row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
23,600 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3=5/15 then 2/5=6/15 you then add that together to get 11/15 | True_Correct | null |
23,601 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1/3x5 is 5/15 and 2/5x 3 is 6/15 so 5/15+6/15 is 11/15 | True_Correct | null |
23,602 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 11/15 because 1/3 = 5/15 and 2/5 = 6/15 add them and u get 11/15 | True_Correct | null |
23,603 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 11/15 because 3 x 5 is 15 so thats the denominator and 3 x 2 and 1 x 5 added together is 11 | True_Correct | null |
23,604 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 11/15 because if you make a comman denominater so 5/15+6/15=11/15 | True_Correct | null |
23,605 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 11/15 has the denominator 15, just like i worked out, and the numerator 11. i didn't think it could be b because you have to do the same thing to the numerator as you do to the denominator, so you couldn't have 3/15 as an answer. | True_Correct | null |
23,606 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 11/15 is the answer and because the calculation includes fractions with different denominators, we have to convert them to have the common denominator which would be fifteenths so 1/3 equals 5/15 and 2/5 equals 6/15 so 5/15 plus 6/15 equals 11/15. | True_Correct | null |
23,607 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 11/15 is the answer because 1/3 is equivalent to 5/15 and 2/5 is equivalent to 6/15 so 5/15 + 6/15 = 11/15. | True_Correct | null |
23,608 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 goes into 3 and5 so both denominations are 15 and the first nominator is 5 and the second is 6 | True_Correct | null |
23,609 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is a common multiple of 3 and 5 so which made 1/3 into 5/15 and 6/15 and added together makes 11/15. | True_Correct | null |
23,610 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is a multiple is 5 and 3 so 5+6=11 | True_Neither | null |
23,611 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is in the 3 and 5 times table | True_Neither | null |
23,612 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is in the 5. &3 times tables so that can be the denominator.to get the answer you need to times the numerator by what you timesed the denominator.finally i died them together. | True_Correct | null |
23,613 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is the common denominator and (5x1) +(2x3)=11 | True_Correct | null |
23,614 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is the lcm and you have to multiply up | True_Neither | null |
23,615 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is the lcm of the denominators
so they turn to 5/15 + 6/15 = 11/15 | True_Correct | null |
23,616 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is the lowest common denominator | True_Neither | null |
23,617 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is the lowest common denominator and 5+6 = 11 | True_Correct | null |
23,618 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is the lowest common denominator so 3 x 2 is 6 and 5x1 is 5 | True_Correct | null |
23,619 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 15 is the smallest multiple for 3 and 5 as a denominator. if you get the same denominator it is easier to add them up. 5+6=11 so it must be 11/15 | True_Correct | null |
23,620 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1third is 5 fifthteenths amd 2 fifths are 6 fifthteenths than add then together to make 11 fifthteenths | True_Correct | null |
23,621 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1x5=5 and 2x3=6 add them together and you get 11. 11 is the denominator and you change 15 to be the denominator. | True_Correct | null |
23,622 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1x5=5 and 2x3=6 so since 5+6=11 11/15 it is | True_Neither | null |
23,623 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 1x5=5 so 5 fifteenths + 6 fifteenths is 11 fifteenths | True_Correct | null |
23,624 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 2+2 is 4-1 thats 3 quick maths | True_Neither | null |
23,625 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 2/5 as a 15th is 6/15 and 1/3 is 5/15 add together 11/15 | True_Correct | null |
23,626 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 2/5 is equal to 6/15 and 1/3 is equal to 5/15. add them together and you get 11/15 | True_Correct | null |
23,627 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 * 5 is 15, 1*5 is 5 so 5/15
5*3 is 15, 2*3 is 6 so 6/15
6+5/15 = 11/15 | True_Correct | null |
23,628 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 - 5 = 15 and the rest was a gues | True_Neither | null |
23,629 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 are common factors of 15 so 15÷5=3 so the numerator (2) is multiplied by 3 so 6/15=2/5
15÷3=5 so 5 times 1=5 (5/15 or 1/3 ) then add 5/15 and 6/15 so get 11/15! | True_Correct | null |
23,630 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 are lowest common multiples are 15. | True_Neither | null |
23,631 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 both go equaly into 15 with no remainder
3x5=15
1x5=5
5x3=15
2x3=6
6+5=11 | True_Correct | null |
23,632 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 both go into 15 add the numerators together and it makes 11. | True_Correct | null |
23,633 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 both go into 15 and is the lowest number that they both go into and you have to times 2 by 3=6 and then 1 by 5=5 then add them together to make 11 over 15. | True_Correct | null |
23,634 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 both go into 15 and what ever you do to the bottom you do to the top. | True_Correct | null |
23,635 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 go into 11 5 and 3 times so it would be 6+5 which would 11/15 | True_Correct | null |
23,636 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 go into 15. you times the 1 by 5 and the 2 by 3 which would give you 5 over 15 + 6 over 15 then just add them together. | True_Correct | null |
23,637 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 go up to 15 so must be this answer | True_Neither | null |
23,638 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5 have a common multiple of 15.using this information,you times the denominators by how many times it goes into it.1/3 would become 5/15 as 3 goes into 15 five times.2/5 would become 6/15 because 5 goes into 15 3 times;5+6=11.the answer is:11/15 | True_Correct | null |
23,639 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 and 5's lcm is 15, so i changed both denominators to 15, so i have to do the same to the numerators, and multiplied 1 by 5, giving me 5, and 2 by 3 with gave me 6. 6 + 5 is 11 so it is 11/15 | True_Correct | null |
23,640 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 can be made into the same denominator as 5
which is 15
5/15 + 6/15 =11/15 | True_Correct | null |
23,641 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 goes into 15 5 times so then 1 x 5 equals 5 so the first fraction is 5/15 and 2/5 of is 6 add them together and you get 11/15 | True_Correct | null |
23,642 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 into 5 doesnt go so you have to carry on until 3 goes into 5 | True_Neither | null |
23,643 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 times 5 is 15 and 5 add 6 is 11 | True_Correct | null |
23,644 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 times 5 is 15 so i multyplyd 2 by 3 and 1 by 5 and added 5 and 6 together to get 11 fifteenths | True_Correct | null |
23,645 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 times 5 is 15 so if each one is timed by the opposites denominator it will equal (the same) + that and you will get this answer | True_Correct | null |
23,646 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 times 5 is 15, so the denominator would be 15, and because you have to multiply the numerator with 5 and 3 as well so the answer would be d. | True_Neither | null |
23,647 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 times 5 is 15.
times 3 by2 (6)
times 1 by5(5) add them up to get 11/15 | True_Correct | null |
23,648 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 times 5 is closest number in 5 time table | True_Neither | null |
23,649 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 times 5=15
15 divided 3=5
1 times 5=5
15 divided 5=3
2 times 3=6
5+6/15=11 over 15 | True_Correct | null |
23,650 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 x 5 =15 then multiply the numerators | True_Neither | null |
23,651 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 x 5 is 15 so we can use that as the denominator. so it would be 5/15 + 6/15 which is 11/15 and that number cannot be simplified. | True_Correct | null |
23,652 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3 x 5 is 15 so you times 1 by 5 and 2 by 3 and then add them together | True_Correct | null |
23,653 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3*2=6 1*5=5 add the two 11 denominator is 15 11/15 | True_Neither | null |
23,654 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3*5=15 now i have the denominator and 3*2=6 + 5*1=5 =11 so it has to be 11/15 | True_Correct | null |
23,655 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3*5=15 so the denominators are the same and 5*1=5 and 3*2=6 6+5=11 so it has to be 11/15 because 11 is a prime. | True_Correct | null |
23,656 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 15 and 1x5 and 3x2 is 5 and 6 and 5+6 is 11 so 11/15 | True_Correct | null |
23,657 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 = 15
do the same as what you did to the bottom but don't times them together just do
3x1 =3
5x3 | True_Neither | null |
23,658 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 and then 1 x 5 and then 3x2 and add them all up | True_Correct | null |
23,659 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 equals to 15, and if you multiply to the denominator, you also have to multiply the same number to the numerator, therefore the answer is d. | True_Correct | null |
23,660 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 is 15 so 1x5 is 5 so 3x2 is 6 which
=11/15 | True_Correct | null |
23,661 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 is 15 so multiply 1 by 5 and 2 by 3 then add them together | True_Correct | null |
23,662 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 is 15 so thats the denominator and 3x2 is 6 and 5x1 is 5 and if you add them together its the numerator | True_Correct | null |
23,663 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 is 15 so thats the denominator and you need to do what you do at the bottom to the top 1x5 is 5 and 3x2 is six add them together and you get 11 as the nominator | True_Correct | null |
23,664 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5 is 15 which is the denomiter and 1x5 is 5 and 2x3 is 6 add together is 11 over 15 | True_Correct | null |
23,665 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15
1x5=5 5/15
2x3=6 6/15 now i can add them.
5+6=11. 11/15 | True_Correct | null |
23,666 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15
2x3+1x5= 6 and 5
6+5= 11 therefore the answer is 11 over 15 | True_Correct | null |
23,667 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15
5x3=15
so we multiply both of them so 1/3 = 5/15 and 2/5=6/15 so if you add them together it turns into 11/15 | True_Correct | null |
23,668 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15
1x5=5
which is 5/15
5x3=15
2x3=6
which is 6/15 so you add them together | True_Correct | null |
23,669 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15 and 1x5=5 and 2x3=66+5=11 and he denominator is 15 so the answer is 11/15 | True_Correct | null |
23,670 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15 and 5x3=15 and i converted the into 5/15 and 6/15 and added them | True_Correct | null |
23,671 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15 and whatever you x by the denominator you do to the numerator so you add 5 and 6 | True_Correct | null |
23,672 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15 common denominator /// times-ed the numerator by each original denominator 1x5=5///2x3=6 5+6=11 11/15 | True_Correct | null |
23,673 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 3x5=15=denominator
2x3=6
1x5=5 6+5=11
11/15 cant be simplified | True_Correct | null |
23,674 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5 and 3 both go into 15 5 times 1 is 5 2 times 3 is 6 plus them together is 11/15 | True_Correct | null |
23,675 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5 times 3 is 15 then the top most be 11 | True_Correct | null |
23,676 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5 x 3 is 15
5x1 is 5
3x2 is 6 and 5+6 is 11 | True_Correct | null |
23,677 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5+6 equals 11 and the common denominator is 15 | True_Correct | null |
23,678 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5+6=11 and you have to find the one they both fit in and it is 15 | True_Correct | null |
23,679 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5/15+6/15=11/15 this is the calculation where both have the same denominator | True_Correct | null |
23,680 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5\15 and 6/15 =11/15 and than cannot be made smaller | True_Correct | null |
23,681 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5x3 is 15 and then 5x1 and 2x3 is 6/15 + 5/15 is 11/15 | True_Correct | null |
23,682 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | 5x3=15 the donomanaters=15 5x1=5 so the first fraction is 5/15 2x3=6 so the second fraction is 6/15. add them together to equal 11/15 | True_Correct | null |
23,683 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | a common denominator between 3 and 5 is 15 times both fractions by 5 and 3 and add them up | True_Correct | null |
23,684 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | a common denominator of 3 and 5 is 15. 2 x 3 = 6. 1 x 5 gives you 5. 5/15 + 6/15 = 11/15. | True_Neither | null |
23,685 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | adding 1/3 with 2/5 the answer will be 11/15 | True_Neither | null |
23,686 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | addition after making the denominators the same. | True_Neither | null |
23,687 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | after you find the common denominator which is 15 it is 5 add 6 which means the answer is 11/15 | True_Correct | null |
23,688 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | all i did was find a number that they both go into and that was 15 | True_Neither | null |
23,689 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | all of my working-out is in my homework book. | True_Neither | null |
23,690 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | answer would the answer would be d because if you find the common multiple of 3 and 5 it would be 15 and then when finished converting them your answer would be 11’15 | True_Correct | null |
23,691 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as both fractions must have common denominators so whatever the denominator was timesed by the numerator has to do the same | True_Neither | null |
23,692 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as convert them into 15s and 5+6 =11 | True_Correct | null |
23,693 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as i did the working out on my whiteboard | True_Neither | null |
23,694 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as i found the common denominator, did what i did to the bottom to the top, and added the numerators. | True_Neither | null |
23,695 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as i timed the the denominator together and that made 15, after i saw what number which number went into it and then added those two numbers together | True_Neither | null |
23,696 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as the common denominator is 15 | True_Neither | null |
23,697 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as the lowest common multiple is 15, 1/3 is multiplied by 5 and 2/5 is multiplied by 3. this makes 5/15 + 6/15 making 11/15. | True_Correct | null |
23,698 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | as you have to find a common denominator and then times the numerator by the same as the bottom and then just add | True_Correct | null |
23,699 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{11}{15} \) | becas you convert it into fiftinfs. | True_Neither | null |
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