row_id
int64
0
36.7k
QuestionId
int64
31.8k
109k
QuestionText
stringclasses
15 values
MC_Answer
stringclasses
49 values
StudentExplanation
stringlengths
1
586
Category
stringclasses
6 values
Misconception
stringclasses
35 values
25,800
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
make the denominateors the same and add the numorators
False_Misconception
Denominator-only_change
25,801
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
multiply the bottom and add the top
False_Misconception
Denominator-only_change
25,802
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
now that the denominators are not the same you have to multiply them which would be 15 and then you add the numerators which is 3 so you get 3/15
False_Misconception
Denominator-only_change
25,803
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
since 3 x 1=3 then 3 + 5 both go in 15 snd 3 = 3 so it's 3/15.
False_Misconception
Denominator-only_change
25,804
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
since 3 x 5 = 15 so 15 is the denominator and 1 + 2 = 3 so the answer would be 3/15.
False_Misconception
Denominator-only_change
25,805
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
since the smallest common denominator of 3 and 5 is 15, and 1+2=3, then the least common multiple of those two numbers is 15.
False_Misconception
Denominator-only_change
25,806
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
so the denominator would have to be the same as the multiple, so in this case, 3 and 5, the common multiple was 15, so the answer would be 3/15.
False_Misconception
Denominator-only_change
25,807
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
so you have to get the denominators the same so 15 so x the first by 5 and the second by 3 so 6 and 6+5=11.
False_Correct
null
25,808
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
so you just add the numerators which is 3 and 5, and then you add 3 because the number that goess into 3 is 5, then 5.
False_Neither
null
25,809
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
so you need to find the lcm whichh is 15 and then add one and two which equals three.
False_Misconception
Denominator-only_change
25,810
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
so you need to get the same denomernatier and u times them together and then add 1+2 then thats the numeratour
False_Misconception
Denominator-only_change
25,811
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
so you would times 3 and 5 times each other which is 15 and 15 would be your denominater.
False_Neither
null
25,812
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
spit will be the denominator and then u just add the top numbers
False_Neither
null
25,813
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the bottom would make 15 and then you add 1 and 2
False_Misconception
Denominator-only_change
25,814
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the common denominator is 15 so 1/15 plus 2/15 is going to be 3/15
False_Misconception
Denominator-only_change
25,815
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the common denominator of 3 and 5 is 15 and 2 and 1 is 3 so its 3 over 15
False_Misconception
Denominator-only_change
25,816
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the common denomitor is 15 and 2+1 is 3
False_Misconception
Denominator-only_change
25,817
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the common factor of 3 and 5 is 15 then add the top
False_Misconception
Denominator-only_change
25,818
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the denominator is 15 because 3 and 5s common multipul is 15
False_Neither
null
25,819
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the denominators have to be the same so you can add the numorators. i did 3x5 which is 15. now you can add the numorators so it is 3/15
False_Misconception
Denominator-only_change
25,820
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the denominators have to be the same so youu can add the numorators. i did 3x5 which is 15. now you have 3/15.
False_Misconception
Denominator-only_change
25,821
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the dominaner is not in the times tables
False_Neither
null
25,822
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the dominotars both go into 15 and 1plus2 equals 3
False_Misconception
Denominator-only_change
25,823
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the first common denominator is 15 and 1/3 x 5 =5/15 and 2/5 x 3 = 6/15 3x1/15 = 3/15
False_Misconception
Denominator-only_change
25,824
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lcm of 3&5 is 15. then you just add the numerators together to get 3. therefore it's 3/5
False_Misconception
Denominator-only_change
25,825
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lowest common denominator for 3 & 5 is 15. 1/15+2/15=3/15
False_Misconception
Denominator-only_change
25,826
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lowest common denominator is 15 1+2 =3
False_Misconception
Denominator-only_change
25,827
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lowest common multiple is 15 1+2 is 3 3/15 is your answer
False_Misconception
Denominator-only_change
25,828
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lowest common multiple of 3 and 5 is 15 so the denominator is 15. 1+2=3 so the answer is three fifteenths
False_Misconception
Denominator-only_change
25,829
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lowest common multiple of 3 and 5 is 15, so the snswer is 3/15.
False_Misconception
Denominator-only_change
25,830
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lowest commonn denomanator is 15 and 2+1=3.
False_Misconception
Denominator-only_change
25,831
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the lowest multiple of 3 and 5 is 15 so that means denominater is 15
False_Neither
null
25,832
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the method i use is this: you need to convert the fractions in to the same denominator, which would be 15, then add the numerators together to get the answer, a bit of which i can't exactly remember, but i think the value is 3/15.
False_Misconception
Denominator-only_change
25,833
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the number that is in both times tables of three and five are 15 so the bottom number is 15 and then 1+2=3 so that top number would be 3.
False_Misconception
Denominator-only_change
25,834
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the number that is in both times tables of three and five are 15 so the bottom number is 15 and then 1+2=3 so the top number is 3.
False_Misconception
Denominator-only_change
25,835
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the smallest common denominator of 3 and 5 is 15 and 1+2=3
False_Misconception
Denominator-only_change
25,836
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
the to dimnominators have to be the same 5 x 3 thatll make it 15 and you don the top off it
False_Neither
null
25,837
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
then, multiply the bottom by 2, and add the top.
False_Neither
null
25,838
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
they both go into 15
False_Neither
null
25,839
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
this is because you can add the 1 and 2 but the bottom numbers are not the same so you have to change it to a common number, in this case 15.
False_Misconception
Denominator-only_change
25,840
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
this is because you find a multiple of both 3 and 5 , which is 15 , and add the numerators to get the answer 3 over 15
False_Misconception
Denominator-only_change
25,841
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
this is the denominator and you add the top ones together.
False_Neither
null
25,842
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
thr least multiple of 3 and 5 is 15, so that means denominater is 15.
False_Neither
null
25,843
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
three and five both go in 15 and 3 x 1=3 so it's 3/15.
False_Misconception
Denominator-only_change
25,844
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
times 3 x 5 and 5x3 and add the numerators
False_Neither
null
25,845
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
times by the bottom add by by.
False_Neither
null
25,846
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
times by the bottom add by the top
False_Neither
null
25,847
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
to do the calculation you must make the dominate the same and then and the numerater
False_Neither
null
25,848
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
to do this you need a number that is in the three and five times table and fifteen is one of them so you add one and two together which is three which equals three fiteenths
False_Misconception
Denominator-only_change
25,849
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
to do this, you needd to find a common denominator.
False_Neither
null
25,850
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
to find out the denominator you have to find a multiply of 3 and 5 which the closest one is 15, and then or the numerator, you need to add them together
False_Neither
null
25,851
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
to find the denominator, which the closest one is 15, and then or the numerator you need to add them together.
False_Neither
null
25,852
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
to get to 15 you make the denominators the same, then do 2 + 1 timess the numbers to get 16.
False_Neither
null
25,853
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
to get to 15, you make the denominators the same, so you end up with 2 + 1
False_Misconception
Denominator-only_change
25,854
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
two divided by six is three
False_Neither
null
25,855
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
two divided by six is three.
False_Neither
null
25,856
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
well you do 3 times 5 which is 15 then you add 1 and 2 which is 3 therefore that gives you the answer 3/15
False_Misconception
Denominator-only_change
25,857
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
when you add with fractions, the denominator must be the same, so the common multiple of 3 and 5 was 15 so that would be the denominator. 1 + 2 equals 3. answer: 3/15.
False_Misconception
Denominator-only_change
25,858
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
when you are adding fractions the denominater needs to be the same so you would times 3 and 5 together which is 15 and 15 would be your denominater
False_Neither
null
25,859
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
x the denominators add the numorators
False_Neither
null
25,860
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
x the drnominators add the numorators
False_Neither
null
25,861
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you convert 3 and 5 into 15 as it is rhe nearest number
False_Neither
null
25,862
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you find the common denominator and ad nominations
False_Neither
null
25,863
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you find the common denominator and the ad nominations
False_Neither
null
25,864
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you find the common denominator which was 15 and then add the numerators.
False_Neither
null
25,865
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you find the lcm of 3 and 5 what is 15 then add 1 and 2 together
False_Misconception
Denominator-only_change
25,866
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have 3 and 5 so 15 both goes into them so 15 would be the denominator
False_Neither
null
25,867
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to change the bottom because you cant add them when they are diffrent so u have to change it to 15
False_Neither
null
25,868
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to change the bottom because youu can't add it when they are different so you have change it to 15.
False_Neither
null
25,869
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to convert the fractions to a equelent fraction
False_Neither
null
25,870
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to convert the fractions to the equivalent fraction.
False_Neither
null
25,871
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to convert them denominater into a multiple that both 3 and 5 go into (15) and then add the numerators.
False_Misconception
Denominator-only_change
25,872
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to get the fractions with the same denominator
False_Neither
null
25,873
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to make both denominators the same so..... 3x5=15 1x5=5 2x5=10 so it would be 5/15+10/15 i don't think that any of these nswers are right...
False_Neither
null
25,874
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to make it with a same demoniter and it is 15 and 1 plus 2 is 3, so its 3/15
False_Misconception
Denominator-only_change
25,875
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you have to make the bottom numbers the same , 3 doesn't go into 5 exactly so i found a number that they both went into ,15, then you do 1 add 2 which is 3 but you don't change the bottom number.
False_Misconception
Denominator-only_change
25,876
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you just add up the top ones because 3 times 5 is 15 and then you just multiply that by 3 because that is 3 * 5 = 15 so you add that up.
False_Neither
null
25,877
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you make them into 15 and 1+2=3 so the answer is 3/15
False_Misconception
Denominator-only_change
25,878
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you need to add at the top and times at he bottom.
False_Misconception
Denominator-only_change
25,879
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you need to add at the top and times at the bottom
False_Misconception
Denominator-only_change
25,880
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you need to change the denominators to a number they both go into and they both go into 15
False_Neither
null
25,881
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you need to find a common denominator
False_Neither
null
25,882
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you need to find the common denominator
False_Neither
null
25,883
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you need to have the same integer at the bottom and add the top
False_Misconception
Denominator-only_change
25,884
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you times the bottom and add the top
False_Misconception
Denominator-only_change
25,885
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you wood add boafe of numerator and times boaf of the denominator and you get the answers
False_Misconception
Adding_across
25,886
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you wood add boafe of numerator and times boarf of the denominator you get the answers
False_Misconception
Adding_across
25,887
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{15} \)
you x because you cant find the lcm
False_Neither
null
25,888
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 + 2 = 3 and 3 + 5 = 8 so the answer is 3/8
False_Misconception
Adding_across
25,889
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 + 2 = 3 and 3+5=8 so in a fraction that would be 3 over 8.
False_Misconception
Adding_across
25,890
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 + 2 = 3 thenn 3 + 5 = 8.
False_Misconception
Adding_across
25,891
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 + 2 is 3 + 5 is 8 which gives the answer 3 over 8.
False_Misconception
Adding_across
25,892
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 + 2 is 3 and 3 plus five is 8 so 3 over eightt is the fraction.
False_Misconception
Adding_across
25,893
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 + 2 is 3 andd 3 + 5 is 8.
False_Misconception
Adding_across
25,894
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 / 3 + 2 /5 = what a is
False_Neither
null
25,895
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 / 3 + 5 1/ 3 = 1 1 8th
False_Neither
null
25,896
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 add 2 is 3 3 add 5 is 8 which gives the answer three over eight
False_Misconception
Adding_across
25,897
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 add 2 is 3 and 3 add 5 is 8
False_Misconception
Adding_across
25,898
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 add 2 is 3 and 3 add 5 equals 8
False_Misconception
Adding_across
25,899
33,472
\( \frac{1}{3}+\frac{2}{5}= \)
\( \frac{3}{8} \)
1 add 2 is 3 and 3 add 5 is 8
False_Misconception
Adding_across