row_id int64 0 36.7k | QuestionId int64 31.8k 109k | QuestionText stringclasses 15
values | MC_Answer stringclasses 49
values | StudentExplanation stringlengths 1 586 | Category stringclasses 6
values | Misconception stringclasses 35
values |
|---|---|---|---|---|---|---|
25,600 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to add 1+2 and then x 3+5. | False_Misconception | Denominator-only_change |
25,601 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to add them to gever. | False_Neither | null |
25,602 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to add themm to the gever. | False_Neither | null |
25,603 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to find the bottom number you times the two bottom ones together then you add 1 and 2 together to get 3 | False_Misconception | Adding_across |
25,604 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to get the same denominator which is 15 and then you add he numerators like normal | False_Misconception | Denominator-only_change |
25,605 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to make it with a same demoniter and its 15 and 1 plus 2 is 3 so its 3/15 | False_Misconception | Denominator-only_change |
25,606 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to make the denominators the same 15 and add the numerators together which is 3 | False_Misconception | Denominator-only_change |
25,607 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you need to times three by five as they aren’t in the same times table, you get 15 and then add 1 to 2 | False_Correct | null |
25,608 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you only add the top and times the bottom | False_Misconception | Denominator-only_change |
25,609 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you see which number goes into both of the denominator which is 15 so you do 5x3 which is 15 | False_Neither | null |
25,610 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you times the denominators it makes 15 then add the numerators | False_Misconception | Denominator-only_change |
25,611 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you times the denominators it makes 15 then add the numerators | False_Misconception | Denominator-only_change |
25,612 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you times the denominators to be the same and add the numerators | False_Misconception | Denominator-only_change |
25,613 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you times the denominators to be the same and add the numerators | False_Misconception | Denominator-only_change |
25,614 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you times the top and bottom by 3 | False_Neither | null |
25,615 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | because you times the top and bottom by 3. | False_Neither | null |
25,616 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | becausee 15 is in both timestables | False_Neither | null |
25,617 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | becausee you add them to hadr | False_Neither | null |
25,618 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | becausee you have to make the nemater the same. | False_Neither | null |
25,619 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | becsuse you have to find the cd which is 15 | False_Neither | null |
25,620 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | can't remeber so i think it makes sense | False_Neither | null |
25,621 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | coz 15 is the first number in 3 and 5 time table and 1+2 is 3 | False_Misconception | Denominator-only_change |
25,622 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | find 15 and add 1 on two 2 | False_Misconception | Denominator-only_change |
25,623 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | find 15 and add 1 on two 2 | False_Misconception | Denominator-only_change |
25,624 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | find the least common multiple of each number then multiply the top number by the amount you used to multiply your denominator then add them up. | False_Neither | null |
25,625 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | find the lowest common multiple of each number and multiply the top number by the amount you used to multiply the denominator then add them up | False_Neither | null |
25,626 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | find the multiple which is 15 then add 1 to 2 | False_Misconception | Denominator-only_change |
25,627 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | find the number thst goes with 5 and add it. | False_Neither | null |
25,628 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | find the same number that goes with 5 and add them. | False_Neither | null |
25,629 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | first i made the denominator the same and the highest common multiple was 15 then i added the numerators together | False_Misconception | Denominator-only_change |
25,630 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | firstly you find the common denominator which was 15 because they both go into it then you add the 2 and the 1 together to get 3/15 | False_Misconception | Denominator-only_change |
25,631 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | for the denominator you multiply 3 and 5 to get 15 and add 1 and 2 to get three | False_Misconception | Denominator-only_change |
25,632 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | for this i looked at the 3 and 5 multiples and saw they both had 15 then i just added the numerators together | False_Misconception | Denominator-only_change |
25,633 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i added the top and added a bottom. | False_Neither | null |
25,634 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i added the top and added the bottom | False_Misconception | Adding_across |
25,635 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i am now nit sure. | False_Neither | null |
25,636 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i believe this is the answer because i found the same denominator. | False_Neither | null |
25,637 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i changed the denominator to 15 because 5 and 3 goes into 15 then added 1 and 2 to make 3 | False_Misconception | Denominator-only_change |
25,638 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i changed the denominators to 15 then added them and i got 3. | False_Misconception | Denominator-only_change |
25,639 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i chose b because 3 times 5 is 15 and 2+1=3 | False_Misconception | Denominator-only_change |
25,640 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i chose b because you have to findthe most common denominater. | False_Neither | null |
25,641 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i chose b because you have to findthe most common denominater. | False_Neither | null |
25,642 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i chose b because you have to make the denominator the same number and that number is 15 and then you add 1 and 2 which equals 3 and the answer was 3/15 | False_Misconception | Denominator-only_change |
25,643 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i chose b because you have to make the denominator the same number and that number is 15 and then you add 1 and 2 which equals 3 and the answer was 3/15. | False_Misconception | Denominator-only_change |
25,644 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i did 3 times 5 and i got 15 and then i added the top number together too get the answer | False_Neither | null |
25,645 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i did this because i came to the first number in the times table they were both the same in and added the top | False_Neither | null |
25,646 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i don't know how to explain it | False_Neither | null |
25,647 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i don't think that any of these nswers are right... | False_Neither | null |
25,648 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i don't thunk it's any of them. | False_Neither | null |
25,649 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i found a common denominator which you couldn't do so times them together which equalled 15 and 1 add 2 equals 3. | False_Misconception | Denominator-only_change |
25,650 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i found a number that they both went into,15, thenn you do 1 add 2 which is 3, but you don't change the bottom number. | False_Misconception | Denominator-only_change |
25,651 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i found the common denominator 15 then i added 2 and 3 which gave me 3/15 | False_Misconception | Denominator-only_change |
25,652 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i found the least common denominator and then added the tim numbers. | False_Neither | null |
25,653 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i found the lowest common denominator and then added the tom numbers | False_Misconception | Denominator-only_change |
25,654 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i found what time's tablel the denominator as in then added the numerator. | False_Neither | null |
25,655 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i have a slightest clue but i'm confused because i got 1 whole.
this looks like the most reasonable one
i'm kind of guessing but still not | False_Neither | null |
25,656 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i just see what 5 and 3 both go in to and then just add the top ones | False_Neither | null |
25,657 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i just take the first 5 and 3 and add them together, then just add the top ones. | False_Misconception | Adding_across |
25,658 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i just timesed the bottem and added the top and it came up with one of the answers here. | False_Neither | null |
25,659 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i knew this because you need to do 3 x 5 = 15 and then i remembered that you needed to add 1 and 2=3. | False_Misconception | Denominator-only_change |
25,660 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know i got it wrong accidentally put it | False_Neither | null |
25,661 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know i gott it wrong but i accidentally put it in. | False_Neither | null |
25,662 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know this because 3 goes into 15 so does 5 and 1+2=3 | False_Misconception | Denominator-only_change |
25,663 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know this because times the denominators which is 15 and add 1 and 2 which comes to 3/15. | False_Misconception | Denominator-only_change |
25,664 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know this because times the denominators which is 15 and add 1 and 2 which is 3/15 | False_Misconception | Denominator-only_change |
25,665 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know this because you have to convert the fractions in to the same denominator which would be 15 and then you add the numerators together and the answer is 3/15
i am partly guessing | False_Misconception | Denominator-only_change |
25,666 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know this because you need to do 3 x 5 =15 and then i knew that you needed to do 1+2=3 | False_Misconception | Denominator-only_change |
25,667 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know this because you need to find the cimmon multiple | False_Neither | null |
25,668 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i know this because you need to find the common multiple | False_Neither | null |
25,669 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i looked at the 3 and 5 multiples and saw they both had 15, then i just added the numerators together. | False_Misconception | Denominator-only_change |
25,670 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i multiply 3 and 5 is 15 then add 1 and 2 | False_Misconception | Denominator-only_change |
25,671 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i multiply 3 and 5 is 15 then add 1 and 2. | False_Misconception | Denominator-only_change |
25,672 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i need to do it again. | False_Neither | null |
25,673 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i picked b because first you need to make the danominantor the same 3 times five is fithteen 5 times 3 is fithteen now you can add one add two is three | False_Misconception | Denominator-only_change |
25,674 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i picked b because first you need to make the danominantor the same 3 times five is fithteen 5 times 3 is fiethen now you can add one add two is three | False_Misconception | Denominator-only_change |
25,675 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think 3/15 because the common denominator is 15 and add the numerators 1+2=3. which is 3/15 | False_Misconception | Denominator-only_change |
25,676 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think b because 1+2=3 then you do 3x5=15 | False_Misconception | Denominator-only_change |
25,677 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think b because 3 x 5 is 15 and then 2+1 is 3 | False_Misconception | Denominator-only_change |
25,678 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think b because 3 x 5 is 15 andd then 2 + 1 is 3. | False_Misconception | Denominator-only_change |
25,679 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think b because 3x5 is 15 and 1+2 is 3 but to simplify yiu would get 1/5. | False_Misconception | Denominator-only_change |
25,680 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think b because 3x5 is 15 and 1+2 is 3 but to simplify you would get 1/5 | False_Misconception | Denominator-only_change |
25,681 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think b because ou times the bottom and add the top | False_Neither | null |
25,682 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think because you times the bottom 2 together to get 15 as the common denominator then you add the numerators together to get 8, so it becomes 8/15. | False_Neither | null |
25,683 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is 3/15 because 15 is in both 3 and 5 times table so it is 15 and add 1+2=3 | False_Misconception | Denominator-only_change |
25,684 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is 3/15 because 3 is in both 3 and 5 times table so it must be 15 and add 1+2=3. | False_Misconception | Denominator-only_change |
25,685 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is 3/15 because i converted the bottom to 15 and converted the top to 3 | False_Misconception | Denominator-only_change |
25,686 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is 3/15 because i converted the bottom to 3 and the top to 15. | False_Misconception | Denominator-only_change |
25,687 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is b because 3 and 5 both go into 15. | False_Neither | null |
25,688 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is b because 3 doesn’t go into 5 but 15 goes into 3 and 5 so it has to be 3/15 | False_Misconception | Denominator-only_change |
25,689 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is b because i had to change the denominator to get 15 then i could add them | False_Misconception | Denominator-only_change |
25,690 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is b becausee i had to change the denominator to get 15 then i could add them. | False_Misconception | Denominator-only_change |
25,691 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it is c because you times 3 by 5 and 1 plus2 | False_Misconception | Denominator-only_change |
25,692 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think it's none of them | False_Neither | null |
25,693 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think its b because doesn't go in to 5 so you do is find a common denominator which is 15 .
3x5=15 | False_Neither | null |
25,694 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think its this answer because 3 and 5 goes in to 15 the bottom then 1+2=3 so its 3/15 | False_Misconception | Denominator-only_change |
25,695 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think that it's for this reason: the donuminater should alwayss time up to the same number. | False_Neither | null |
25,696 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think the answer is b because 3/15 15 is 5 times 3 and 2+1=3 | False_Misconception | Denominator-only_change |
25,697 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think the answer is b because if you make them equivilent it would be 15 and you would add 2 and 1 to give you 3 | False_Misconception | Denominator-only_change |
25,698 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think this answer because 3/15 goes into 1/3 and 2/5 | False_Neither | null |
25,699 | 33,472 | \( \frac{1}{3}+\frac{2}{5}= \) | \( \frac{3}{15} \) | i think this because 1+2=3 3 times 5 =15 | False_Misconception | Denominator-only_change |
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