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Now you have to write a function that takes an argument and returns the square of it.
def square(n): pass s = pow(n,2) return s
Now you have to write a function that takes an argument and returns the square of it.
def square(n): res = n*n return res
Now you have to write a function that takes an argument and returns the square of it.
def square(n): a = n ** 2 return a
Now you have to write a function that takes an argument and returns the square of it.
def square(n): return n**2 print(square(5))
Now you have to write a function that takes an argument and returns the square of it.
def square(n): squared = n * n return squared
Now you have to write a function that takes an argument and returns the square of it.
def square(n): return n**2 #self explanatory
Now you have to write a function that takes an argument and returns the square of it.
def square(n): answer = n*n return answer
Now you have to write a function that takes an argument and returns the square of it.
def square(n): sqr = n ** 2 print sqr return sqr
Now you have to write a function that takes an argument and returns the square of it.
def square(n): s = n*n return s
Now you have to write a function that takes an argument and returns the square of it.
def square(n): ans = 0 for i in range(n): for j in range(n): ans += 1 return ans
Now you have to write a function that takes an argument and returns the square of it.
def square(n): import math return math.pow(n, 2)
Now you have to write a function that takes an argument and returns the square of it.
def square(n): i = n * n return i pass
Now you have to write a function that takes an argument and returns the square of it.
def square(n): result = n ** 2 return result
Now you have to write a function that takes an argument and returns the square of it.
def square(n): a=n*n return a
Now you have to write a function that takes an argument and returns the square of it.
def square(n): square = n ** 2 return square
Now you have to write a function that takes an argument and returns the square of it.
def square(n): '''return the square of number''' return n ** 2
Now you have to write a function that takes an argument and returns the square of it.
import math def square(n): return n**(math.sqrt(4))
Now you have to write a function that takes an argument and returns the square of it.
def square(n): """This function return square of number""" return n * n
Now you have to write a function that takes an argument and returns the square of it.
def square(n): return n * sum([1 for x in range(0, n)])
Now you have to write a function that takes an argument and returns the square of it.
import math def __pow(a, b=2): return pow(a, b) math.pow = __pow square = math.pow
Now you have to write a function that takes an argument and returns the square of it.
square = lambda n: pow(n, 2)
Now you have to write a function that takes an argument and returns the square of it.
square = lambda a:a**2
Now you have to write a function that takes an argument and returns the square of it.
def square(n): n = n * n return n
Now you have to write a function that takes an argument and returns the square of it.
import math def square(n): return n**2
Now you have to write a function that takes an argument and returns the square of it.
def square(n): return abs(n*n)
Now you have to write a function that takes an argument and returns the square of it.
def square(n,y=2): if y == 1: return n else: return n * square(n, y - 1)
Now you have to write a function that takes an argument and returns the square of it.
def square(n): sqr = n ** 2 return sqr
Now you have to write a function that takes an argument and returns the square of it.
def square(n): return int(n**2)
Now you have to write a function that takes an argument and returns the square of it.
import math def square(n): return n*n
Now you have to write a function that takes an argument and returns the square of it.
def square(n): sq = n**2 return sq pass
Now you have to write a function that takes an argument and returns the square of it.
def square(n): if type(n) == int or type(n) == float: return n**2 else: return False
Now you have to write a function that takes an argument and returns the square of it.
square=lambda x:x**2
Now you have to write a function that takes an argument and returns the square of it.
def square(n): n = n **2 return n
Now you have to write a function that takes an argument and returns the square of it.
def square(n): ans = n**2 return ans
Now you have to write a function that takes an argument and returns the square of it.
square = lambda x: x*x
Now you have to write a function that takes an argument and returns the square of it.
def square(n): return float(n)*n
Now you have to write a function that takes an argument and returns the square of it.
from math import pow def square(n): return pow(n,2)
Now you have to write a function that takes an argument and returns the square of it.
#def square(n): # pass square = lambda n: n**2
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): width = n * 2 - 1 row = '{{:_^{}}}'.format(width).format return [row(mid(a)) for a in xrange(1, width, 2)] + [width * '#'] def mid(n): return '#' if n == 1 else '#{}#'.format('_' * (n - 2))
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): w, result = 2 * n - 1, [f"{'_' * (2*i-1):#^{2*i+1}}" for i in range(n - 1)] return [f"{l:_^{w}}" for l in result] + ["#" * w]
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
hollow_triangle=lambda n:["".join([['_','#'][k in[n-1-i,n-1+i]]for k in range(n*2-1)])for i in range(n-1)]+[f"{'#'*(n*2-1)}"]
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): return [(f'#{"_" * (2*i-1)}#' if i else '#').center(2*n-1, '_') for i in range(n-1)] + ['#' * (2*n-1)]
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): return ['_' * (n - i - 1) + '#' + '_' * (2 * i - 1) + '#' * (i >= 1) + '_' * (n - i - 1) \ for i in range(n - 1)] + ['#' * (2 * n - 1)]
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): if n == 1: return ['#'] first = ["_"*(n-1)+"#"+"_"*(n-1)] last = ["#"*(2*n-1)] return first +["_"*(n-i-1)+"#"+"_"*(2*i-1)+"#"+"_"*(n-i-1) for i in range(1,n-1)] + last
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): total_width = 2 * n - 1 triangle = ['#'.center(total_width, '_')] for i in range(1, total_width-2, 2): triangle.append('#{}#'.format('_' * i).center(total_width, '_')) triangle.append('#' * total_width) return triangle
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
m,hollow_triangle=lambda s:s[:0:-1]+s,lambda n:[m('_'*i+'#'+'_'*(n-i-1))for i in range(n-1)]+[m(n*'#')]
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): lines = ['_' * (n-i-1) + '#' + '_' * (2*i-1) + '#' + '_' * (n-i-1) for i in range(1, n-1)] return ['_' * (n-1) + '#' + '_' * (n-1)] + lines + ['#' * (2*n-1)] if n > 1 else ['#']
Create a function hollow_triangle(height) that returns a hollow triangle of the correct height. The height is passed through to the function and the function should return a list containing each line of the hollow triangle. ``` hollow_triangle(6) should return : ['_____#_____', '____#_#____', '___#___#___', '__#_____#__', '_#_______#_', '###########'] hollow_triangle(9) should return : ['________#________', '_______#_#_______', '______#___#______', '_____#_____#_____', '____#_______#____', '___#_________#___', '__#___________#__', '_#_____________#_', '#################'] ``` The final idea is for the hollow triangle is to look like this if you decide to print each element of the list: ``` hollow_triangle(6) will result in: _____#_____ 1 ____#_#____ 2 ___#___#___ 3 __#_____#__ 4 _#_______#_ 5 ########### 6 ---- Final Height hollow_triangle(9) will result in: ________#________ 1 _______#_#_______ 2 ______#___#______ 3 _____#_____#_____ 4 ____#_______#____ 5 ___#_________#___ 6 __#___________#__ 7 _#_____________#_ 8 ################# 9 ---- Final Height ``` Pad spaces with underscores i.e _ so each line is the same length.Goodluck and have fun coding !
def hollow_triangle(n): ans = [] for i in range(n-1, 0, -1): x = '_' * i + '#' + '_' * (n-i-1) ans.append(x[:-1] + x[::-1]) return ans + ['#' * (2*n - 1)]
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): return string.endswith(ending)
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
solution = str.endswith
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): return ending in string[-len(ending):]
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): # your code here... string1 = len(string) - len(ending) string2 = len(string) - string1 string3 = string[string1:] if string3 == ending: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
solution=str.endswith # Easy peasy
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): # your code here... return ending == string[len(string)-len(ending):]
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(a,b): return(a.endswith(b))
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
solution = lambda string, ending: string.endswith(ending)
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if ending in string: if ending == '': return True else: str1Arr = string.split(f'{ending}') if str1Arr[-1] == '': return True else: return False else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): pass sol = string.endswith(ending) return sol
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if string.endswith(ending): return True return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if ending in string[-len(ending):]: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): return string[len(string)-len(ending):len(string)] == ending
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if len(ending) > len(string): return False if len(ending) == 0: return True else: # try ending = ending[::-1] string = string[::-1] #ll = -1 * len(ending) #string = string[ll:] for i in range(len(ending)): if i > len(string)-1: break if ending[i] == string[i]: continue else: return False return True
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if string.endswith(ending): return True else: return False print(solution('abc','bc')) print(solution('abc','d'))
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if ending not in string or len(ending) > 0 and string[-1] != ending[-1]: return False else: return True
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): f=len(ending) h=[i for i in ending] r=[] for i in string: r.append(i) r =(r[-f:]) if r == h: return True elif h == []: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if len(ending) > len(string): return False elif ending =='': return True else: for x,y in zip(string[::-1], ending[::-1]): if x!=y: return False return True
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): return True if ending == "" else ending == string[-1*len(ending):]
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
solution = lambda s,e: not e or s[-len(e):] == e
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
from re import search, escape def solution(string, ending): return bool(search(escape(ending)+'\Z',string))
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): return string[len(ending)*-1:] == ending or ending == ''
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): length = len(ending) if string[len(string) - length:] == ending: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): List1 = [] while True: if len(string) == 0: return False if string == ending: return True break else: string = string[1:]
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): # your code here... if(len(ending) == 0): return True if(len(string) == 0): return False last1 = string[-1] last2 = ending[-1] if(last1 == last2): return True and solution(string[:-1],ending[:-1]) else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): l_ending = -(len(ending)) if l_ending == 0: return True elif string[l_ending:] == ending: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): comparison = string[-len(ending):] if len(ending) == 0: return True if comparison == ending: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): ns = len(string) ne = len(ending) if(ne == 0): return True else: if(string[-ne::] == ending): return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): remove = len(string) - len(ending) return string[remove:] == ending
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(str, ending): if len(ending) == 0 or ending == str[-len(ending):]: return True return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(str, end): str = str[::-1] end = end[::-1] end_length = len(end) str_length = len(str) result = 0 if(end_length > str_length): return False else: for i in range(end_length): if(str[i] == end[i]): result +=1 if(result == end_length): return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if ending == "" or string[-int(len(ending)):] == ending: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): """Standalone solution.""" ending_length = len(ending) if ending_length == 0: return True return string[-ending_length:] == ending def solution_endswith(string, ending): """Proper solution using `endswith()`.""" return string.endswith(ending)
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): # your code here... #string = "abc" #ending = "bc" return string.endswith(ending)
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): size = len(ending) if string[-size:] == ending or ending == '': return True else: return False pass
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): e_len = len(ending) s_len = len(string) if e_len == 0: return True elif (s_len >= e_len) and (string[-e_len:] == ending): return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if ending == string[-len(ending):len(string)] or ending == '': return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if ending is "" : return True ln = len(ending) string = string[::-1] str = string[:ln] return str[::-1] == ending
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): var = string.find(ending, (len(string)-len(ending)), (len(string))) if var == -1: return False else: return True
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): a=(string.find(ending,len(string)-len(ending))) if a != -1: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if len(ending) > len(string): return False out = True inc = 0 revString = string[::-1] for i in ending[::-1]: if i != revString[inc]: out = False inc = inc + 1 return out
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): str_len = len(string) end_len = len(ending) return str_len >= end_len and string[str_len - end_len:] == ending
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): start = -len(ending) return True if start == 0 else string[start::] == ending
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): numbs = len(ending) if numbs == 0: return True elif string[-numbs:] == ending: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): newEnding = ending[::-1] newString = string[::-1] stringCount = 0 print (newString, newEnding) for letters in newEnding: if stringCount < len(newString): print (stringCount) if letters != newString[stringCount]: return False stringCount += 1 else: return False return True
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): retval = False if string.endswith(ending): return True return retval pass
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): index = string.rfind(ending) if (index == len(string) - len(ending) or not ending) and index >= 0: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): print(string[-1 * len(ending): None: 1]) if ending == '': return True if ending == string[-1 * len(ending): None: 1]: return True else: return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): for x in range(0,len(string)+1): if string[x:len(string)]==ending: return True return False
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): # your code here... end_len=len(ending) str_len=len(string) actualend=string[str_len-end_len:] if actualend==ending: return(True) else: return(False)
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): if ending not in string: return False for a,b in zip(string[::-1],ending[::-1]): if a!=b: return False return True
Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string). Examples: ```python solution('abc', 'bc') # returns true solution('abc', 'd') # returns false ```
def solution(string, ending): return (True if ending == '' or string[-1 * len(ending):] == ending else False)