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1krz2iayo | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with AgNO<sub>3</sub> [Carius Method], the percentage of chlorine in compound A is ____________ when it forms 0.3849 g of AgCl. (Round off to the Nearest Integer)<br/><br/>(Atomic masses of Ag... | [] | null | 19 | Mass of organic compound = 0.5 gm.<br><br>Mass of formed AgCl = 0.3849 gm<br><br>% of Cl = $${{atomic\,mass\,of\,Cl \times mass\,formed\,AgCl} \over {molecular\,mass\,of\,AgCl \times mass\,of\,organic\,compound}} \times 100$$<br><br>$$ = {{35.5 \times 0.3849} \over {143.37 \times 0.5}} \times 100$$<br><br>= 19.06<br><b... | integer | jee-main-2021-online-27th-july-morning-shift | 3,228 |
1ktb3l6le | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | Which one of the following complexes is violet in colour? | [{"identifier": "A", "content": "[Fe(CN)<sub>6</sub>]<sup>4$$-$$</sup>"}, {"identifier": "B", "content": "[Fe(SCN)<sub>6</sub>]<sup>4$$-$$</sup>"}, {"identifier": "C", "content": "Fe<sub>4</sub>[Fe(CN<sub>6</sub>)]<sub>3</sub> . H<sub>2</sub>O"}, {"identifier": "D", "content": "[Fe(CN)<sub>5</sub>NOS]<sup>4$$-$$</sup>"... | ["D"] | null | (a) [Fe(CN)<sub>6</sub>]<sup>4$$-$$</sup> $$\to$$ Pale yellow solution<br><br>(b) [Fe(SCN)<sub>6</sub>]<sup>4$$-$$</sup> $$\to$$ Blood red colour<br><br>(c) Fe<sub>4</sub>[Fe(CN<sub>6</sub>)]<sub>3</sub> . H<sub>2</sub>O $$\to $$ Prussian blue<br><br>(d) [Fe(CN)<sub>5</sub>NOS]<sup>4$$-$$</sup> $$\to$$ Violet colour | mcq | jee-main-2021-online-26th-august-morning-shift | 3,229 |
1ktcrjxc7 | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | In the sulphur estimation, 0.471 g of an organic compound gave 1.44 g of barium sulphate. The percentage of sulphur in the compound is ____________%. (Nearest integer)<br/><br/>(Atomic Mass of Ba = 137 u) | [] | null | 42 | Molecular mass of BaSO<sub>4</sub> = 233 g<br><br>$$\because$$ 233 BaSO<sub>4</sub> contain $$\to$$ 32 g sulphur<br><br>$$\therefore$$ 1.44 g BaSO<sub>4</sub> contain $$\to$$ $${{32} \over {233}}$$ $$\times$$ 1.44 g sulphur given : 0.471 g of organic compound<br><br>% of S = $${{32 \times 1.44} \over {233 \times 0.471}... | integer | jee-main-2021-online-26th-august-evening-shift | 3,230 |
1l56bwcjk | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>In the estimation of bromine, 0.5 g of an organic compound gave 0.40 g of silver bromide. The percentage of bromine in the given compound is _________ % (nearest integer)</p>
<p>(Relative atomic masses of Ag and Br are 108u and 80u, respectively).</p> | [] | null | 34 | $188 \mathrm{~g} ~ \mathrm{AgBr}$ has $80 \mathrm{~g}$ of $\mathrm{Br}$
<br/><br/>
$$
\therefore 0.4 \mathrm{~g} \mathrm{AgBr}=\frac{80}{188} \times 0.4
$$
<br/><br/>
$\%$ of $\mathrm{Br}$ in given organic compound
<br/><br/>
$$
\begin{aligned}
&=\frac{80 \times 0.4}{188 \times 0.5} \times 100 \\\\
&\approx 34 \%
\end{... | integer | jee-main-2022-online-28th-june-morning-shift | 3,232 |
1l56z33me | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>0.25 g of an organic compound containing chlorine gave 0.40 g of silver chloride in Carius estimation. The percentage of chlorine present in the compound is ___________. [in nearest integer]</p>
<p>(Given : Molar mass of Ag is 108 g mol<sup>$$-$$1</sup> and that of Cl is 35.5 g mol<sup>$$-$$1</sup>)</p> | [] | null | 40 | <p>Given, weight of organic compound = 0.25 g</p>
<p>Moles of AgCl = $${{0.4} \over M}$$</p>
<p>Molecular mass of AgCl (M) = 143.5 gm</p>
<p>$$\therefore$$ Moles of AgCl = $${{0.4} \over 143.5}$$</p>
<p>$$\therefore$$ Mass of Cl = $${{0.4} \over 143.5}$$ $$\times$$ 35.5</p>
<p>Mass % of Cl in the organic compound</p>
<... | integer | jee-main-2022-online-27th-june-evening-shift | 3,233 |
1l5be4gje | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>0.2 g of an organic compound was subjected to estimation of nitrogen by Dumas method in which volume of N<sub>2</sub> evolved (at STP) was found to be 22.400 mL. The percentage of nitrogen in the compound is _________. [nearest integer]</p>
<p>(Given : Molar mass of N<sub>2</sub> is 28 g mol<sup>$$-$$1</sup>. Molar ... | [] | null | 14 | <p>Given volume of N<sub>2</sub> = 22.400 mL</p>
<p>$$\therefore$$ Moles of N<sub>2</sub> = $${{22.400} \over {22400}} = {10^{ - 3}}$$ mole</p>
<p>$$\therefore$$ Moles of N atoms = 2 $$\times$$ 10<sup>$$-$$3</sup> mole</p>
<p>$$\therefore$$ Weigh of N atoms = 14 $$\times$$ 2 $$\times$$ 10<sup>$$-$$3</sup> mole</p>
<p>... | integer | jee-main-2022-online-24th-june-evening-shift | 3,234 |
1l5w6zu0x | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>An organic compound with 51.6% sulfur is heated in a Carius tube. The amount of this compound which will form 0.752 g of barium sulphate is ___________ $$\times$$ 10<sup>$$-$$1</sup> g.</p>
<p>(Given molar mass of barium sulphate 233 g mol<sup>$$-$$1</sup>) (Nearest integer).</p> | [] | null | 2 | $233 \mathrm{~g}\, \mathrm{BaSO}_{4}$ contains $=32 \mathrm{~g}$ sulphur
<br/><br/>
$0.752 \mathrm{~g}\, \mathrm{BaSO}_{4}$ contains $=\frac{32}{233} \times 0.752=0.1005 \mathrm{~g}$
<br/><br/>
Sulfur $\%=\frac{\text { Weight of Sulphur }}{\text { Weight of Compound }} \times 100$
<br/><br/>
$51.6=\frac{0.1005}{\text {... | integer | jee-main-2022-online-30th-june-morning-shift | 3,235 |
1l6kuxpp8 | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p><img src="data:image/png;base64,UklGRnwQAABXRUJQVlA4IHAQAAAw7wCdASoAAzoCP4HA2GW2L6ynIjC5UsAwCWlu8p8dw89CN+fP6P/4n+A7InlLrA8Zf0Xh7+h8+fa78Z/uXoUIqWv/oBef/SNqAfk39D//+o/7/EMlFudFnNf2iSrIy9MUnaTmsZjSPqCH1BD6gh9QQ+oIARcG+VTJuA/W2001y3c1B3uSHVyJ5HQ/tOv69KvTtGavhUMCklWLs3AxNXFeWYR37mVQKQbbvLo+oIfUEPqCH1BD6ahiqj2BcuFO1Gr2E... | [] | null | 530 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7ojs56r/5be453c3-bc7e-4a76-b9db-108541891693/4d503930-2cfb-11ed-9d62-a5035b10641e/file-1l7ojs56u.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7ojs56r/5be453c3-bc7e-4a76-b9db-108541891693/4d503930-2cfb-11ed-9d62-a5035b10641e/fi... | integer | jee-main-2022-online-27th-july-evening-shift | 3,236 |
1l6p95t6z | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>In bromination of Propyne, with Bromine, 1, 1, 2, 2-tetrabromopropane is obtained in 27% yield. The amount of 1, 1, 2, 2-tetrabromopropane obtained from 1 g of Bromine in this reaction is ___________ $$\times$$ 10<sup>$$-$$1</sup> g. (Nearest integer)</p>
<p>(Molar Mass : Bromine = 80 g/mol)</p> | [] | null | 3 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7w0enlg/b9b8cf3c-1570-494c-9291-eabacfc185e9/cdf25b40-3115-11ed-aea7-cb6fb344ee54/file-1l7w0enlh.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7w0enlg/b9b8cf3c-1570-494c-9291-eabacfc185e9/cdf25b40-3115-11ed-aea7-cb6fb344ee54/fi... | integer | jee-main-2022-online-29th-july-morning-shift | 3,237 |
lsbm5rqa | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | In Kjeldahl's method for estimation of nitrogen, $\mathrm{CuSO}_4$ acts as : | [{"identifier": "A", "content": "catalytic agent"}, {"identifier": "B", "content": "hydrolysis agent"}, {"identifier": "C", "content": "reducing agent"}, {"identifier": "D", "content": "oxidising agent"}] | ["A"] | null | <p>The correct option here is :</p>
<p><strong>Option A : catalytic agent</strong></p>
<p>In the Kjeldahl method for the estimation of nitrogen, $\mathrm{CuSO}_4$ or copper sulfate acts as a catalytic agent. The method consists of three main steps: digestion, neutralization, and titration. During the digestion phase, ... | mcq | jee-main-2024-online-1st-february-morning-shift | 3,238 |
jaoe38c1lscqgzqj | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>The technique used for purification of steam volatile water immiscible substances is :</p> | [{"identifier": "A", "content": "Fractional distillation\n"}, {"identifier": "B", "content": "Distillation\n"}, {"identifier": "C", "content": "Fractional distillation under reduced pressure\n"}, {"identifier": "D", "content": "Steam distillation"}] | ["D"] | null | <p>The correct option for the purification of steam volatile water-immiscible substances is Option D, Steam distillation.</p>
<p>Steam distillation is a separation technique used to purify or isolate temperature-sensitive materials, such as natural aromatic compounds, that are volatile in steam at a temperature that i... | mcq | jee-main-2024-online-27th-january-evening-shift | 3,239 |
jaoe38c1lsd9lkhd | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>The fragrance of flowers is due to the presence of some steam volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in vapour phase. A suitable method for the extraction of these oils from the flowers is -</p> | [{"identifier": "A", "content": "distillation\n"}, {"identifier": "B", "content": "steam distillation\n"}, {"identifier": "C", "content": "distillation under reduced pressure\n"}, {"identifier": "D", "content": "crystallisation"}] | ["B"] | null | <p>Steam distillation technique is applied to separate substances which are steam volatile and are immiscible with water.</p> | mcq | jee-main-2024-online-31st-january-evening-shift | 3,240 |
luxwert3 | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>Which of the following compound can give positive iodoform test when treated with aqueous $$\mathrm{KOH}$$ solution followed by potassium hypoiodite.</p> | [{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1luxw4nwr/90745bb1-ee65-4420-a2f5-59a016fa9811/9e984db0-f977-11ee-a5bc-b108889e7d03/file-1luxw4nws.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1luxw4nwr/90745bb1-ee65-4420-a2f5-59a016fa9811/9e9... | ["C"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lw32k836/bd38451f-262b-4944-a820-a04a4b12c807/e8b85d20-101c-11ef-87e8-8d9388b48d3c/file-1lw32k837.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lw32k836/bd38451f-262b-4944-a820-a04a4b12c807/e8b85d20-101c-11ef-87e8-8d9388b48d3c... | mcq | jee-main-2024-online-9th-april-evening-shift | 3,241 |
luxzq9e3 | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>Match List I with List II</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "A-II, B-III, C-IV, D-I\n"}, {"identifier": "B", "content": "A-III, B-IV, C-I, D-II\n"}, {"identifier": "C", "content": "A-I, B-II, C-III, D-IV\n"}, {"identifier": "D", "content": "A-IV, B-I, C-II, D-III"}] | ["A"] | null | <p>Let's match the given tests in List I with the correct observations in List II based on known chemical reactions and their typical outcomes:</p>
<p> List I with List II</p>
<strong>A. $\mathrm{Br_2}$ water test</strong>
<br/><br/><ul>
<li>This test is used to detect unsaturation in organic compounds. If the compo... | mcq | jee-main-2024-online-9th-april-evening-shift | 3,242 |
lvc57nu2 | chemistry | practical-organic-chemistry | chemistry-involved-in-the-preparation-of-organic-and-inorganic-compounds | <p>Which of the following statements are correct?</p>
<p>A. Glycerol is purified by vacuum distillation because it decomposes at its normal boiling point.</p>
<p>B. Aniline can be purified by steam distillation as aniline is miscible in water.</p>
<p>C. Ethanol can be separated from ethanol water mixture by azeotropic ... | [{"identifier": "A", "content": "A, C, D only\n"}, {"identifier": "B", "content": "B, C, D only\n"}, {"identifier": "C", "content": "A, B, D only\n"}, {"identifier": "D", "content": "A, B, C only"}] | ["A"] | null | <p>Statements A, C and D are correct.</p> | mcq | jee-main-2024-online-6th-april-morning-shift | 3,243 |
xTN9Z6PmV9viFCY4Vf974 | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | For standardizing NaOH solution, which of the following is used as a primary standard ? | [{"identifier": "A", "content": "Ferrous Ammonium Sulfate"}, {"identifier": "B", "content": "dil. HCl"}, {"identifier": "C", "content": "Oxalic acid "}, {"identifier": "D", "content": "Sodium tetraborate "}] | ["C"] | null | <p>The solution that can be prepared directly by dissolving an accurately weighed amount of the substance in water and making up the volume to a known amount by water is known as primary standard solution. Oxalic acid is an example of primary standard while NaOH is a secondary standard solution. Hence, strength of NaOH... | mcq | jee-main-2018-online-16th-april-morning-slot | 3,244 |
2z8FqpENQJpTgZzDrzEuU | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | In a complexometric titration of metal ion with ligand
<br/>M(Metal ion) + L(Ligand) $$ \to $$ C(Complex) end point is estimated spectrophoto - metrically (through light absorption). If 'M' and 'C' do not absorb light and only 'L' absorbs, then the titration plot between absorbed light (A) versus volume of ligand '... | [{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1l8g3kx6c/44220a7a-1475-48be-be1d-b187f26c2974/e493eb40-3c21-11ed-8acd-3bfc6080b9d7/file-1l8g3kx6d.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1l8g3kx6c/44220a7a-1475-48be-be1d-b187f26c2974/e49... | ["B"] | null | Ligand concentration is maximum when the reaction has not been initiated. At that point, absorption of light by ligands will be maximum. As the reaction starts, ligand concentration decreases so is the absorption of light till the point where all the metal ions are consumed and further complex formation does not take p... | mcq | jee-main-2018-online-16th-april-morning-slot | 3,245 |
7eI6PFdZ82UWCpGuFN1kltcc74s | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | Consider titration of NaOH solution versus 1.25 M oxalic acid solution. At the end point following burette readings were obtained.<br/><br/>(i) 4.5 mL<br/><br/>(ii) 4.5 mL<br/><br/>(iii) 4.4 mL<br/><br/>(iv) 4.4 mL<br/><br/>(v) 4.4 mL<br/><br/>If the volume of oxalic acid taken was 10.0 mL then the molarity of the NaOH... | [] | null | 6 | <p>Average burette reading = Volume of NaOH solution (V<sub>1</sub>)</p>
<p>$$ = {{4.5 + 4.5 + 4.4 + 4.4 + 4.4} \over 5}$$</p>
<p>= 4.44 mL</p>
<p>Strength of NaOH solution = S<sub>1</sub>(M) (say) = S<sub>1</sub>(N)</p>
<p>Volume of oxalic acid solution (V<sub>2</sub>) = 10 mL</p>
<p>Strength of oxalic acid solution (... | integer | jee-main-2021-online-25th-february-evening-slot | 3,246 |
1kteeq84j | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | When 10 mL of an aqueous solution of KMnO<sub>4</sub> was titrated in acidic medium, equal volume of 0.1 M of an aqueous solution of ferrous sulphate was required for complete discharge of colour. The strength of KMnO<sub>4</sub> in grams per litre is __________ $$\times$$ 10<sup>$$-$$2</sup>. (Nearest integer)<br/><br... | [] | null | 316 | Let molarity of KMnO<sub>4</sub> = x<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265836/exam_images/p9hhzcwijy9z79hapv3x.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 27th August Morning Shift Chemistry - Practical Organi... | integer | jee-main-2021-online-27th-august-morning-shift | 3,247 |
1l56bd1qp | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | <p>A 2.0 g sample containing MnO<sub>2</sub> is treated with HCl liberating Cl<sub>2</sub>. The Cl<sub>2</sub> gas is passed into a solution of KI and 60.0 mL of 0.1 M Na<sub>2</sub>S<sub>2</sub>O<sub>3</sub> is required to titrate the liberated iodine. The percentage of MnO<sub>2</sub> in the sample is _____________. ... | [] | null | 13 | <p>First Step :</p>
<p>MnO<sub>2</sub> + 4HCl $$\to$$ MnCl<sub>2</sub> + Cl<sub>2</sub> + 2H<sub>2</sub>O</p>
<p>Here 1 mol of MnO<sub>2</sub> produce 1 mol of Cl<sub>2</sub></p>
<p>$$\therefore$$ Mole ratio of $${n_{Mn{O_2}}}:{n_{C{l_2}}} = 1:1$$</p>
<p>Second Step :</p>
<p>Cl<sub>2</sub> + 2KI $$\to$$ 2KCl + I<sub>2<... | integer | jee-main-2022-online-28th-june-morning-shift | 3,248 |
1l6f7i5x6 | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | <p>In base vs. acid titration, at the end point methyl orange is present as</p> | [{"identifier": "A", "content": "quinonoid form"}, {"identifier": "B", "content": "heterocyclic form"}, {"identifier": "C", "content": "phenolic form"}, {"identifier": "D", "content": "benzenoid form"}] | ["A"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lc8kl19k/b0d01404-424e-4520-a371-1ad47687a661/fb40b280-872e-11ed-93b3-c381a41bf82e/file-1lc8kl19l.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lc8kl19k/b0d01404-424e-4520-a371-1ad47687a661/fb40b280-872e-11ed-93b3-c381a41bf82e... | mcq | jee-main-2022-online-25th-july-evening-shift | 3,249 |
1lgq4slas | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | <p>$$\mathrm{KMnO}_{4}$$ is titrated with ferrous ammonium sulphate hexahydrate in presence of dilute $$\mathrm{H}_{2} \mathrm{SO}_{4}$$. Number of water molecules produced for 2 molecules of $$\mathrm{KMnO}_{4}$$ is ___________.</p> | [] | null | 68 | The balanced redox equation considering the ferrous ammonium sulfate hexahydrate is as follows:
<br/><br/>
$$
10\left[\mathrm{FeSO}_4 \cdot\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4 \cdot 6 \mathrm{H}_2 \mathrm{O}\right]+2 \mathrm{KMnO}_4+8 \mathrm{H}_2 \mathrm{SO}_4 \rightarrow
$$<br/><br/>
$5 \mathrm{Fe}_2\left... | integer | jee-main-2023-online-13th-april-morning-shift | 3,250 |
1lgysk2xy | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | <p>Given below are two statements:</p>
<p>Statement I : Methyl orange is a weak acid.</p>
<p>Statement II : The benzenoid form of methyl orange is more intense/deeply coloured than the quinonoid form.</p>
<p>In the light of the above statement, choose the most appropriate answer from the options given below:</p> | [{"identifier": "A", "content": "Both Statement I and Statement II are incorrect"}, {"identifier": "B", "content": "Statement $$\\mathrm{I}$$ is incorrect but Statement II is correct"}, {"identifier": "C", "content": "Both statement I and Statement II are correct"}, {"identifier": "D", "content": "Statement I is correc... | ["A"] | null | <p><b>Statement I</b>: Methyl orange is a weak base, not a weak acid.</p>
<p>This is because Methyl orange is actually a pH indicator commonly used in titrations. In its deprotonated form, it appears yellow, and in its protonated form, it appears red. Methyl orange has the ability to accept a proton ($H^+$) from water ... | mcq | jee-main-2023-online-8th-april-evening-shift | 3,252 |
lsapcdp1 | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | Following Kjeldahl's method, $1 \mathrm{~g}$ of organic compound released ammonia, that neutralised $10 \mathrm{~mL}$ of $2 \mathrm{M} ~\mathrm{H}_2 \mathrm{SO}_4$. The percentage of nitrogen in the compound is ___________ $\%$. | [] | null | 56 | <p>To determine the percentage of nitrogen using the Kjeldahl's method, we first need to find out how much ammonia (NH<sub>3</sub>) was produced and then calculate the equivalent amount of nitrogen in the sample.</p>
<p>The ammonia released reacts with sulfuric acid (H<sub>2</sub>SO<sub>4</sub>) in the following stoic... | integer | jee-main-2024-online-1st-february-evening-shift | 3,253 |
lsbm7sp8 | chemistry | practical-organic-chemistry | chemistry-involved-in-titrimetric-experiments | Given below are two statements :<br/><br/>
<b>Statement (I)</b> : Potassium hydrogen phthalate is a primary standard for standardisation of sodium hydroxide solution.
<br/><br/>
<b>Statement (II)</b> : In this titration phenolphthalein can be used as indicator.<br/><br/>
In the light of the above statements, choose the... | [{"identifier": "A", "content": "Both Statement I and Statement II are correct"}, {"identifier": "B", "content": "Statement I is incorrect but Statement II is correct"}, {"identifier": "C", "content": "Both Statement I and Statement II are incorrect"}, {"identifier": "D", "content": "Statement I is correct but Statemen... | ["A"] | null | <p>Let's examine each statement one by one to choose the most appropriate answer :</p>
<p><b>Statement (I) : Potassium hydrogen phthalate is a primary standard for standardisation of sodium hydroxide solution.</b></p>
<p>This statement is correct. Potassium hydrogen phthalate (often abbreviated as KHP, with the chemic... | mcq | jee-main-2024-online-1st-february-morning-shift | 3,254 |
RoaWGv7xoIOnOfUP | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | Which of the following reagents may be used to distinguish between phenol and benzoic acid ? | [{"identifier": "A", "content": "Tollen\u2019s reagent"}, {"identifier": "B", "content": "Molisch reagent"}, {"identifier": "C", "content": "Neutral FeCl<sub>3</sub>"}, {"identifier": "D", "content": "Aqueous NaOH "}] | ["C"] | null | Phenol gives a violet colour with neutral ferric chloride solution whereas benzoic acid does not give this test. | mcq | aieee-2011 | 3,256 |
5SZYObrM7c9kpKCGNPq1U | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | Sodium extract is heated with concentrated HNO<sub>3</sub> before testing for halogens because :
| [{"identifier": "A", "content": "Silver halides are totally insoluble in nitric acid."}, {"identifier": "B", "content": "Ag<sub>2</sub>S and AgCN are soluble in acidic medium."}, {"identifier": "C", "content": "S<sub>2</sub><sup>\u2212</sup> and CN<sup>\u2212</sup>, if present, are\ndecomposed by conc. HNO<sub>3</sub> ... | ["C"] | null | <p>Sodium fusion extract is heated with dilute HNO<sub>3</sub> to decompose NaCN or Na<sub>2</sub>S (if present) to HCN and H<sub>2</sub>S gases, respectively.</p>
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l3y9ip5i/8f361b81-e501-4328-a5e6-8fdaa4707f13/2454e760-e322-11ec-8ab2-698930c131d9/file-1l3... | mcq | jee-main-2016-online-10th-april-morning-slot | 3,257 |
qhRhf5ldY7m4LQoa | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | Which of the following compounds will be suitable for Kjeldahl’s method for nitrogen estimation? | [{"identifier": "A", "content": "<img class=\"question-image\" src=\"https://gateclass.cdn.examgoal.net/fZ7Du03ryLsQEvYhI/7nQoGYsPpTyxCLFJvfnrBqMylWGdJ/eSkuETVAHQo7pa9ccQ7itf/uploadfile.jpg\" loading=\"lazy\" alt=\"JEE Main 2018 (Offline) Chemistry - Practical Organic Chemistry Question 98 English Option 1\">"}, {"iden... | ["C"] | null | In Kjeldahl’s method, ammonium ion or ammonia should generate from a compound.
<br><br>So, those compounds which contain nitrogen in nitro and azo groups and nitrogen in the ring cannot generate ammonium ion or ammonia.
<br><br>Among the given option only aniline can generate NH<sub>3</sub>. So it is suitable far ni... | mcq | jee-main-2018-offline | 3,258 |
zt1pSlBdnxcZnZhd8f84m | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | The correct match between item 'I' and item 'II' is :
<br/><br/><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;width:100%}
.tg td{font-family:Arial, sans-serif;font-size:14px;padding:10px 5px;border-style:solid;border-width:1px;overflow:hidden;word-break:normal;border-color:black;}
.tg th{font... | [{"identifier": "A", "content": "(A) $$ \\to $$ (Q); (B) $$ \\to $$ (R); (C) $$ \\to $$ (S); \n(D) $$ \\to $$ (P)"}, {"identifier": "B", "content": "(A) $$ \\to $$ (Q); &nb... | ["B"] | null | Lysine is an amino acid which gives nindydrin test.
<br><br>Furfural has aldehyde group that is why it reacts with 1-napthol to give purple colouration.
<br><br>Benzyl alcohol undergoes reaction with ceric ammonium nitrate to give pink colouration.
<br><br>Styrene reacts with KMnO<sub>4</sub> and gives benzoic acid and... | mcq | jee-main-2019-online-10th-january-evening-slot | 3,260 |
rOQWGd0iNFCe4rdODLdo2 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | An organic compound neither reacts with neutral ferric chloride solution nor with fehling solution.
it however, reacts with Grignard reagent and gives positive iodoform test. The compound is : | [{"identifier": "A", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734267692/exam_images/cv6r81tkjs2d9sbccimj.webp\" style=\"max-width: 100%; height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Practical Organic Che... | ["D"] | null | (1) The organic compound does not react with natural FeCl<sub>3</sub> solution. It means phenolic group is absent in the organic compound.
<br><br>(2) The organic compound does not give Fehling solution test. It means aldehyde group (- CHO) is absent in the organic compound.
<picture><source media="(max-width: 320px)" ... | mcq | jee-main-2019-online-8th-april-morning-slot | 3,261 |
8KDcveGMs0DDHM85kg7k9k2k5llhweq | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | A, B and C are three biomolecules. The results
of the tests performed on them are given
below:<br/><br/>
$$
\begin{array}{|l|l|l|l|}
\hline & \begin{array}{l}
\text { Molisch's } \\
\text { Test }
\end{array} & \begin{array}{l}
\text { Barfoed } \\
\text { Test }
\end{array} & \begin{array}{l}
\text { Biure... | [{"identifier": "A", "content": "A = Lactose, B = Glucose, C = Albumin"}, {"identifier": "B", "content": "A = Lactose, B = Fructose, C = Alanine"}, {"identifier": "C", "content": "A = Lactose, B = Glucose, C = Alanine"}, {"identifier": "D", "content": "A = Glucose, B = Fructose, C = Albumin"}] | ["A"] | null | <p>The given table provides the results of three tests: Molisch's test, Barfoed's test, and Biuret test for three different biomolecules A, B, and C.</p>
<ol>
<li><p><strong>Molisch's Test</strong>: Detects carbohydrates. Positive results for A and B indicate that they are carbohydrates.</p>
</li><br/>
<li>... | mcq | jee-main-2020-online-9th-january-evening-slot | 3,262 |
zqq0NUXE5kyepMrmXkjgy2xukfuqaifd | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | In an estimation of bromine by Carius method,
1.6 g of an organic compound gave 1.88 g of
AgBr. The mass percentage of bromine in the
compound is _______.
<br/>(Atomic mass, Ag = 108, Br = 80 g mol<sup>–1</sup>) | [] | null | 50 | Mass of organic compound = 1.6 gm
<br><br>Mass of AgBr = 1.88 gm
<br><br>Moles of Br = Moles of AgBr = $${{1.88} \over {188}}$$ = 0.01
<br><br>Mass of Br = 0.01 × 80 = 0.80 gm
<br><br>% of Br = $${{0.80 \times 100} \over {1.60}}$$ = 50 % | integer | jee-main-2020-online-6th-september-morning-slot | 3,264 |
Vs7hwvcmskHCHu42F9jgy2xukg4m6vst | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | Match the following :
<br/><br/><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border... | [{"identifier": "A", "content": "(i)-(b), (ii)-(d), (iii)-(e), (iv)-(a)"}, {"identifier": "B", "content": "(i)-(d), (ii)-(c), (iii)-(e), (iv)-(a)"}, {"identifier": "C", "content": "(i)-(b), (ii)-(a), (iii)-(c), (iv)-(d)"}, {"identifier": "D", "content": "(i)-(d), (ii)-(c), (iii)-(b), (iv)-(e)"}] | ["B"] | null | Lucas reagent – Conc. HCl/ZnCl<sub>2</sub>
<br><br>Dumas method – CuO/CO<sub>2</sub>
<br><br>Kjeldahl’s method – H<sub>2</sub>SO<sub>4</sub>
<br><br>Hinsberg test – C<sub>6</sub>H<sub>5</sub>SO<sub>2</sub>Cl/aq. KOH | mcq | jee-main-2020-online-6th-september-evening-slot | 3,265 |
mqpf3ykQ4mld1gbE2u1kmiuz4c7 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | In Duma's method of estimation of nitrogen, 0.1840 g of an organic compound gave 30 mL of nitrogen collected at 287 K and 758 mm of Hg pressure. The percentage composition of nitrogen in the compound is __________. (Round off to the Nearest Integer). [Given : Aqueous tension at 287 K = 14 mm of Hg] | [] | null | 19 | Aqueous tension at 287 K = 14 mm of Hg.
<br><br>Hence actual pressure = (758 – 14)
<br>= 744 mm of Hg.
<br><br>Moles of $${N_2} = {{\left( {758 - 14} \right)} \over {760}} \times {{30 \times {{10}^{ - 3}}} \over {0.0821 \times 287}}$$<br><br>$$ = 1.246 \times {10^{ - 3}}$$ mol<br><br>mass of $${N_2} = 1.246 \times {10^... | integer | jee-main-2021-online-16th-march-evening-shift | 3,266 |
mDXT6MeV2TIIQ9Uwvw1kmj8ljoh | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <img src="data:image/png;base64,UklGRqAIAABXRUJQVlA4IJQIAADwLgCdASoNAW4APm0ylkgkIqKhJJHqmIANiWlu3WBpKT+kv8g7Tv750m3k8+k/BfzfzL/4H8w8Tfev/O/kB8AXp//AfyDx0f6D9APCWrZ+jvsBeyXzv/M/x3+t/9XzOv5f0O7aX+a/yL0nfBh8i83v+G/gH9S/2f9J9+z+4/kn9L/YD2p/IX+z/lH93/VT7Cv55/Q/9V/Iv7L+xnzC+xH9nfZc/YD/1fxgoWa6LwKezZh9kBTTm70gM0ptM54MsRTNLovA... | [] | null | 80 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264545/exam_images/mykghl4okuu6zlarmt4b.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 17th March Morning Shift Chemistry - Practical Organic Chemistry Question 72 English Explanation">... | integer | jee-main-2021-online-17th-march-morning-shift | 3,267 |
1krxcl7xz | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | 0.8 g of an organic compound was analyzed by Kjeldahl's method for the estimation of nitrogen. If the percentage of nitrogen in the compound was found to be 42%, then ______________ mL of 1 M H<sub>2</sub>SO<sub>4</sub> would have been neutralized by the ammonia evolved during the analysis. | [] | null | 12 | Organic compound : 0.8 gm<br><br>wt. of N = $$\left( {{{42} \over {100}} \times 0.8} \right)$$ gm<br><br>mole of N = $${{{42 \times 0.8} \over {100 \times 14}} = {{2.4} \over {100}}}$$ mol<br><br>moles of NH<sub>3</sub> = $${{{2.4} \over {100}}}$$<br><br> <picture><source media="(max-width: 320px)" srcset="https://res.... | integer | jee-main-2021-online-25th-july-evening-shift | 3,270 |
1ktee351u | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | The number of moles of CuO, that will be utilized in Dumas method for estimation nitrogen in a sample of 57.5 g of N, N-dimethylaminopentane is _____________ $$\times$$ 10<sup>$$-$$2</sup>. (Nearest integer) | [] | null | 1125 | Moles of N in N, N - dimethylaminopentane = $$\left( {{{57.5} \over {115}}} \right)$$ = 0.5 mol<br><br>$$ \Rightarrow {C_7}{H_{17}}N + {{45} \over 2}CuO \to 7C{O_2} + {{17} \over 2}{H_2}O + {1 \over 2}{N_2} + {{45} \over 2}Cu$$<br><br>$${{{n_{CuO}}\,reacted} \over {\left( {{{45} \over 2}} \right)}} = {{{n_{{C_7}{H_{17}... | integer | jee-main-2021-online-27th-august-morning-shift | 3,271 |
1ktfskbwi | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | Which one of the following tests used for the identification of functional groups in organic compounds does not use copper reagent? | [{"identifier": "A", "content": "Barfoed's test"}, {"identifier": "B", "content": "Seliwanoff's test"}, {"identifier": "C", "content": "Benedict's test"}, {"identifier": "D", "content": "Biuret test for peptide bond"}] | ["B"] | null | In Seliwanoff's reagent, Cu is not present.<br><br>In Barfoed, Biuret and in Benediet reagent Cu is present. | mcq | jee-main-2021-online-27th-august-evening-shift | 3,272 |
1ktjzb958 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | The transformation occurring in Duma's method is given below :<br/><br/>$${C_2}{H_7}N + \left( {2x + {y \over 2}} \right)CuO \to xC{O_2} + {y \over 2}{H_2}O + {z \over 2}{N_2} + \left( {2x + {y \over 2}} \right)Cu$$<br/><br/>The value of y is ______________. (Integer answer) | [] | null | 7 | $${C_2}{H_7}N + \left( {2x + {y \over 2}} \right)CuO \to xC{O_2} + {y \over 2}{H_2}O + {z \over 2}{N_2} + \left( {2x + {y \over 2}} \right)Cu$$<br><br>On balancing<br><br>$${C_2}{H_7}N + {{15} \over 2}CuO \to 2C{O_2} + {7 \over 2}{H_2}O + {1 \over 2}{N_2} + {{15} \over 2}Cu$$<br><br>On comparing<br><br>y = 7 | integer | jee-main-2021-online-31st-august-evening-shift | 3,273 |
1l54a8ghz | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>Kjeldahl's method was used for the estimation of nitrogen in an organic compound. The ammonia evolved from 0.55 g of the compound neutralised 12.5 mL of 1 M H<sub>2</sub>SO<sub>4</sub> solution. The percentage of nitrogen in the compound is _____________. (Nearest integer)</p> | [] | null | 64 | Meq. of $\mathrm{H}_2 \mathrm{SO}_4=$ Meq. of $\mathrm{NH}_3$<br/><br/>
12. $5 \times 1 \times 2=25$ meq. of $\mathrm{NH}_3$ $=25$ millimoles of $\mathrm{NH}_3$<br/><br/>
So Millimoles of ${ }^{\prime} \mathrm{N}^{\prime}=25$<br/><br/>
Moles of $\mathrm{N}^{\prime}=25 \times 10^{-3}$<br/><br/>
wt. of $N=14 \times 25 \t... | integer | jee-main-2022-online-29th-june-morning-shift | 3,274 |
1l58e0ehp | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>Given below are two statements :</p>
<p>Statement I : In 'Lassaigne's Test', when both nitrogen and sulphur are present in an organic compound, sodium thiocyanate is formed.</p>
<p>Statement II : If both nitrogen and sulphur are present in an organic compound, then the excess of sodium used in sodium fusion will dec... | [{"identifier": "A", "content": "Both Statement I and Statement II are correct."}, {"identifier": "B", "content": "Both Statement I and Statement II are incorrect."}, {"identifier": "C", "content": "Statement I is correct but Statement II is incorrect."}, {"identifier": "D", "content": "Statement I is incorrect but Sta... | ["A"] | null | Both statement I & statement II are correct<br/><br/>
$\mathrm{NaSCN}+2 \mathrm{Na} \rightarrow \mathrm{NaCN}+\mathrm{Na}_{2} \mathrm{~S}$ | mcq | jee-main-2022-online-26th-june-morning-shift | 3,276 |
1l5w6gv56 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>The reagent neutral ferric chloride is used to detect the presence of ______________</p> | [{"identifier": "A", "content": "sulphide ion and alcoholic $$-$$OH group."}, {"identifier": "B", "content": "acetate ion and phenolic $$-$$OH group."}, {"identifier": "C", "content": "sulphide ion and phenolic $$-$$OH group."}, {"identifier": "D", "content": "acetate ion and alcoholic $$-$$OH group."}] | ["B"] | null | Acetate ions gives deep red colour ppt on reaction with netural ferric chloride solution.
<br/><br/>
$6 \mathrm{CH}_{3} \mathrm{COO}^{-}+3 \mathrm{Fe}^{3+}+2 \mathrm{H}_{2} \mathrm{O} \longrightarrow {\left[\mathrm{Fe}_{3}(\mathrm{OH})_{2}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{6}\right]^{+} + 2 \mathrm{H}^{+}}$
<br... | mcq | jee-main-2022-online-30th-june-morning-shift | 3,277 |
1l6e2geb6 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>While estimating the nitrogen present in an organic compound by Kjeldahl's method, the ammonia evolved from $$0.25 \mathrm{~g}$$ of the compound neutralized $$2.5 \mathrm{~mL}$$ of $$2 \,\mathrm{M} \,\mathrm{H}_{2} \mathrm{SO}_{4}$$. The percentage of nitrogen present in organic compound is ______________.</p> | [] | null | 56 | $$\mathrm{NH}_{3}$$ gas is neutralized by $$2.5 \mathrm{~mL}$$ of $$2 \mathrm{M} \,\,\mathrm{H}_{2} \mathrm{SO}_{4}$$
<br/><br/>
$$\therefore$$ Moles of $$\mathrm{NH}_{3}$$ neutralized $$=2.5 \times 2 \times 2$$ millimole
<br/><br/>
$$
=10 \times 10^{-3} \text { moles }
$$
<br/><br/>
$$\therefore$$ Weight of $$\mathrm{... | integer | jee-main-2022-online-25th-july-morning-shift | 3,278 |
1l6nxx4l6 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>A sample of $$0.125 \mathrm{~g}$$ of an organic compound when analyzed by Duma's method yields $$22.78 \mathrm{~mL}$$ of nitrogen gas collected over $$\mathrm{KOH}$$ solution at $$280 \mathrm{~K}$$ and $$759 \mathrm{~mm}\, \mathrm{Hg}$$. The percentage of nitrogen in the given organic compound is __________. (Neares... | [] | null | 22 | $P_{\text {actual }}=759-14.2=744.8 \,\mathrm{mmHg}$
<br/><br/>
$$
\begin{aligned}
\mathrm{n}_{\mathrm{N}_{2}} &=\frac{744.8 \times 22.78}{760 \times 0.0821 \times 280 \times 1000} \\\\
&=0.000971 \mathrm{~mol}
\end{aligned}
$$
<br/><br/>
Mass of $\mathrm{N}_{2}=0.02719 \,\mathrm{gm}$
<br/><br/>
Percentage of nitrogen
... | integer | jee-main-2022-online-28th-july-evening-shift | 3,279 |
1ldo20ob0 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>Given below are two statements :</p>
<p>Statement I : Sulphanilic acid gives esterification test for carboxyl group.</p>
<p>Statement II : Sulphanilic acid gives red colour in Lassigne's test for extra element detection.</p>
<p>In the light of the above statements, choose the most appropriate answer from the options... | [{"identifier": "A", "content": "Both Statement I and Statement II are correct"}, {"identifier": "B", "content": "Statement I is correct but Statement II is incorrect"}, {"identifier": "C", "content": "Both Statement I and Statement II are incorrect"}, {"identifier": "D", "content": "Statement I is incorrect but Statem... | ["D"] | null | <p>Sulphanilic acid is p-amino benzene sulphonic acid</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1ldx5w5q1/1fa17808-0871-415e-8446-b37b91c38a20/57460e90-a881-11ed-99b3-79cb23978059/file-1ldx5w5q2.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1ldx5w5q1/1fa17808-0871-4... | mcq | jee-main-2023-online-1st-february-evening-shift | 3,280 |
ldo9h8z1 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | In Dumas method for the estimation of $\mathrm{N}_{2}$, the sample is heated with copper oxide and the gas evolved is passed over : | [{"identifier": "A", "content": "Copper oxide"}, {"identifier": "B", "content": "Copper gauze"}, {"identifier": "C", "content": "$\\mathrm{Pd}$"}, {"identifier": "D", "content": "$\\mathrm{Ni}$"}] | ["B"] | null | In dumas method for the estimation of N<sub>2</sub>, the
sample is heated with copper oxide and the gas
evolved is passed over copper gauze. | mcq | jee-main-2023-online-31st-january-evening-shift | 3,281 |
1ldsqs6x7 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>Compound that will give positive Lassaigne's test for both nitrogen and halogen is :</p> | [{"identifier": "A", "content": "$$\\mathrm{NH_2OH.HCl}$$"}, {"identifier": "B", "content": "$$\\mathrm{N_2H_4.HCl}$$"}, {"identifier": "C", "content": "$$\\mathrm{CH_3NH_2.HCl}$$"}, {"identifier": "D", "content": "$$\\mathrm{NH_4Cl}$$"}] | ["C"] | null | $\mathrm{CH}_{3} \mathrm{NH}_{2} \cdot \mathrm{HCl}$ will give positive Lassaigne's test for both nitrogen and halogen. | mcq | jee-main-2023-online-29th-january-morning-shift | 3,282 |
1lgp3frp5 | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>$$0.400 \mathrm{~g}$$ of an organic compound $$(\mathrm{X})$$ gave $$0.376 \mathrm{~g}$$ of $$\mathrm{AgBr}$$ in Carius method for estimation of bromine. $$\%$$ of bromine in the compound $$(\mathrm{X})$$ is ___________.</p>
<p>(Given: Molar mass $$\mathrm{AgBr=188~g~mol^{-1}}$$</p>
<p>$$\mathrm{Br}=80 \mathrm{~g} \... | [] | null | 40 | To calculate the percentage of bromine in the compound X, we first need to determine the moles of AgBr formed and then the moles of bromine present in the compound. Finally, we can find the percentage of bromine by weight.
<br/><br/>
1. Calculate the moles of AgBr formed:
<br/><br/>
Moles of AgBr = mass / molar mass = ... | integer | jee-main-2023-online-13th-april-evening-shift | 3,283 |
1lguzm6th | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>When a solution of mixture having two inorganic salts was treated with freshly prepared ferrous sulphate in acidic medium, a dark brown ring was formed whereas on treatment with neutral $$\mathrm{FeCl}_{3}$$, it gave deep red colour which disppeared on boiling and a brown red ppt was formed. The mixture contains :</... | [{"identifier": "A", "content": "SO$$_3^{2-}$$ & C$$_2$$O$$_4^{2-}$$"}, {"identifier": "B", "content": "$$\\mathrm{CH}_{3} \\mathrm{COO}^{-} \\& ~\\mathrm{NO}_{3}^{-}$$"}, {"identifier": "C", "content": "$$\\mathrm{C}_{2} \\mathrm{O}_{4}{ }^{2-} \\& ~\\mathrm{NO}_{3}^{-}$$"}, {"identifier": "D", "content": "$$\\mathrm{... | ["B"] | null | The mixture of salts gives a dark brown ring when treated with ferrous sulphate in acidic medium. This is a characteristic reaction of nitrate ions (NO$_3^-$). The brown ring is due to the formation of a complex between NO and Fe$^{2+}$.
<br/><br/>Additionally, the mixture gives a deep red color when treated with neut... | mcq | jee-main-2023-online-11th-april-morning-shift | 3,284 |
1lgyrwlgc | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>A compound '$$\mathrm{X}$$' when treated with phthalic anhydride in presence of concentrated $$\mathrm{H}_{2} \mathrm{SO}_{4}$$ yields '$$\mathrm{Y}$$'. '$$\mathrm{Y}$$' is used as an acid/base indicator. '$$\mathrm{X}$$' and '$$\mathrm{Y}$$' are respectively</p> | [{"identifier": "A", "content": "Toludine, Phenolphthalein"}, {"identifier": "B", "content": "Carbolic acid, Phenolphthalein"}, {"identifier": "C", "content": "Salicylaldehyde, Phenolphthalein"}, {"identifier": "D", "content": "Anisole, methyl orange"}] | ["B"] | null | Phenolphthalein is a commonly used acid/base indicator that can be synthesized from phthalic anhydride and phenol (carbolic acid) in the presence of concentrated sulfuric acid (H₂SO₄). Therefore, compound 'X' is phenol and compound 'Y' is phenolphthalein.<br><br>
<img src="https://app-content.cdn.examgoal.net/fly/@widt... | mcq | jee-main-2023-online-8th-april-evening-shift | 3,286 |
1lh29g8bx | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>Match List I with List II</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "A-III, B-I, C-IV, D-II"}, {"identifier": "B", "content": "A-II, B-I, C-IV, D-III"}, {"identifier": "C", "content": "A-IV, B-II, C-I, D-III"}, {"identifier": "D", "content": "A-II, B-IV, C-I, D-III"}] | ["A"] | null | <p><b>Nitrogen Detection (Lassaigne's Test)</b></p>
<p>Nitrogen in organic compounds is detected by converting it into sodium cyanide, which further reacts with iron(II) sulfate to form sodium hexacyanoferrate(II). By reacting this with iron(III) ions, Prussian blue is formed:</p>
<p>$
\begin{aligned}
&\mathrm{Na}+... | mcq | jee-main-2023-online-6th-april-morning-shift | 3,287 |
lv3xmb2m | chemistry | practical-organic-chemistry | detection-of-extra-elements-and-functional-groups | <p>Match List I with List II</p>
<p><style type="text/css">
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.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "(A)-(IV), (B)-(I), (C)-(II), (D)-(III)\n"}, {"identifier": "B", "content": "(A)-(III), (B)-(I), (C)-(IV), (D)-(II)\n"}, {"identifier": "C", "content": "(A)-(II), (B)-(III), (C)-(IV), (D)-(I)\n"}, {"identifier": "D", "content": "(A)-(IV), (B)-(III), (C)-(I), (D)-(II)"}] | ["D"] | null | <p>To match the tests in List I with the corresponding identifications in List II, let's analyze each test:</p>
<p>
<strong>Bayer's test</strong>: This test is used to test for unsaturation in compounds, such as alkenes and alkynes. The presence of unsaturation is indicated by the decolorization of potassium permangan... | mcq | jee-main-2024-online-8th-april-evening-shift | 3,289 |
luxzqkad | chemistry | practical-organic-chemistry | experiments-involving-physical-chemistry | <p><img src="data:image/png;base64,UklGRpALAABXRUJQVlA4IIQLAAAwvACdASpUAgADP4HA12Y2MKwnIHMZYsAwCWlu/CX5bWinZ1/frF2eZJdnh2z74jcohb9voPCU959o+bVx2d8oKDBDvPtHzUbWFR9YVH1hUfWFJyCzhUUC51hAAzr0LC6lJb6rlBgf58YnbxV2dwlqCDYwJNjAk2MCOJv/jTirHS48wnosgOE4VlN30yzzwowuS1IasKj847UEGxgSbFwrjs75ToY5yc9GxfsNzEhM1BnMzIJuBCZqDQb/4lAWLiOb8... | [] | null | 15 | <p>$$\mathrm{R}_{\mathrm{f}}=\frac{\text { Distance moved by substance from base line }}{\text { Distance moved by solvent from base line }}$$</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lw34rhv6/41cdfcc7-ebeb-4bf0-b8bd-9b525abd067c/85321120-1025-11ef-ba0c-0558f6f33b6c/file-1lw34rhv7.png?for... | integer | jee-main-2024-online-9th-april-evening-shift | 3,292 |
C3RKGJ2L0noPtzFd66Pjd | chemistry | practical-organic-chemistry | qualitative-salt-analysis | A solution containing a group-IV cation gives a precipitate on passing H<sub>2</sub>S. A solution of this precipitate in dil.HCl produces a white precipitate with NaOH solution and bluish-white precipitate with basic potassium ferrocyanide. The cation is :
| [{"identifier": "A", "content": "Co<sup>2+</sup>"}, {"identifier": "B", "content": "Ni<sup>2+</sup>"}, {"identifier": "C", "content": "Mn<sup>2+</sup> "}, {"identifier": "D", "content": "Zn<sup>2+</sup>"}] | ["D"] | null | <p>Solution containing Zn<sup>2+</sup> ions forms white precipitate on reaction with H<sub>2</sub>S gas.</p>
<img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l3zxlles/4a58ef58-6e7f-4c0b-86cd-f80449522d60/189e0640-e40d-11ec-9cee-2ba40f085bf5/file-1l3zxllet.png?format=png" data-orsrc="https://app-content.... | mcq | jee-main-2017-online-8th-april-morning-slot | 3,294 |
EyL2l4rWDa200xcC | chemistry | practical-organic-chemistry | qualitative-salt-analysis | Sodium salt of an organic acid ‘X’ produces effervescence with conc. H<sub>2</sub>SO<sub>4</sub>. ‘X’ reacts with the acidified
aqueous CaCl<sub>2</sub> solution to give a white precipitate which decolourises acidic solution of KMnO<sub>4</sub>. ‘X’ is : | [{"identifier": "A", "content": "CH<sub>3</sub>COONa"}, {"identifier": "B", "content": "Na<sub>2</sub>C<sub>2</sub>O<sub>4</sub>"}, {"identifier": "C", "content": "C<sub>6</sub>H<sub>5</sub>COONa"}, {"identifier": "D", "content": "HCOONa"}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267449/exam_images/x1vit74tyod54xnqrtua.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2017 (Offline) Chemistry - Practical Organic Chemistry Question 97 English Explanation"> | mcq | jee-main-2017-offline | 3,295 |
Mj4iu7R0msrjkrddr57k9k2k5dyy2ep | chemistry | practical-organic-chemistry | qualitative-salt-analysis | A solution of m-chloronailimne, m-chlorophenol and m-chlorobenzoic acid in ethyal acetate was extracted initially with a saturated solution of NaHCO<sub>3</sub>
to give fraction A. The left over organic phase
was extracted with dilute NaoH solution tio give fraction B. The final organiic layer was labelled as
fraction... | [{"identifier": "A", "content": "m-chlorobenzoic acid, m-chloroaniline and m-chlorophenol."}, {"identifier": "B", "content": "m-chlorobenzoic acid, m-chlorophenol and m-chloroaniline."}, {"identifier": "C", "content": "m-chlorophenol, m-chlorobenzoic acid and m-chloronailine."}, {"identifier": "D", "content": "m-chloro... | ["B"] | null | m-chlorobenzoic acid dissolves in aq NaHCO<sub>3</sub>
while m-chlorophenol dissolves in aq NaOH. | mcq | jee-main-2020-online-7th-january-morning-slot | 3,296 |
1krq5ta5x | chemistry | practical-organic-chemistry | qualitative-salt-analysis | An inorganic Compound 'X' on treatment with concentrated H<sub>2</sub>SO<sub>4</sub> produces brown fumes and gives dark brown ring with FeSO<sub>4</sub> in presence of concentrated H<sub>2</sub>SO<sub>4</sub>. Also Compound 'X' gives precipitate 'Y', when its solution in dilute HCl is treated with H<sub>2</sub>S gas. ... | [{"identifier": "A", "content": "Co(NO<sub>3</sub>)<sub>2</sub>"}, {"identifier": "B", "content": "Pb(NO<sub>2</sub>)<sub>2</sub>"}, {"identifier": "C", "content": "Cu(NO<sub>3</sub>)<sub>2</sub>"}, {"identifier": "D", "content": "Pb(NO<sub>3</sub>)<sub>2</sub>"}] | ["C"] | null | Compound ‘X’ is copper nitrate, i.e. Cu(NO<sub>3</sub>)<sub>2</sub> is an inorganic
compound. On treatment with concentrated H<sub>2</sub>SO<sub>4</sub> produces brown
fumes and gives dark brown ring with FeSO<sub>4</sub>
in presence of
concentrated H<sub>2</sub>SO<sub>4</sub>. Chemical reaction is as follows
<br><br><... | mcq | jee-main-2021-online-20th-july-morning-shift | 3,298 |
1krrj1xj7 | chemistry | practical-organic-chemistry | qualitative-salt-analysis | Cu<sup>2+</sup> salt reacts with potassium iodide to give | [{"identifier": "A", "content": "Cu<sub>2</sub>I<sub>2</sub>"}, {"identifier": "B", "content": "Cu<sub>2</sub>I<sub>3</sub>"}, {"identifier": "C", "content": "Cul"}, {"identifier": "D", "content": "Cu(I<sub>3</sub>)<sub>2</sub>"}] | ["A"] | null | $$2C{u^{ + 2}} + 4{I^ - }\buildrel {} \over
\longrightarrow C{u_2}{I_2}(s) + {I_2}$$<br><br>$$2C{u^{ + 2}} + 3{I^ - }\buildrel {} \over
\longrightarrow 2CuI + {I_2}$$ | mcq | jee-main-2021-online-20th-july-evening-shift | 3,299 |
1krt4otqi | chemistry | practical-organic-chemistry | qualitative-salt-analysis | When silver nitrate solution is added to potassium iodide solution then the sol produced is : | [{"identifier": "A", "content": "AgI / I<sup>$$-$$</sup>"}, {"identifier": "B", "content": "AgI / Ag<sup>+</sup>"}, {"identifier": "C", "content": "KI / NO$$_3^ - $$"}, {"identifier": "D", "content": "AgNO<sub>3</sub> / NO$$_3^ - $$"}] | ["A"] | null | $$\mathop {AgN{O_3}(aq.)}\limits_{(drop\,by\,drop)} + \mathop {KI(aq.)}\limits_{excess} \buildrel {} \over
\longrightarrow \mathop {AgI/{I^ - }}\limits_{Sol} $$ | mcq | jee-main-2021-online-22th-july-evening-shift | 3,300 |
1ks1hv0hx | chemistry | practical-organic-chemistry | qualitative-salt-analysis | To an aqueous solution containing ions such as Al<sup>3+</sup>, Zn<sup>2+</sup>, Ca<sup>2+</sup>, Fe<sup>3+</sup>, Ni<sup>2+</sup>, Ba<sup>2+</sup> and Cu<sup>2+</sup> was added conc. HCl, followed by H<sub>2</sub>S.<br/><br/>The total number of cations precipitated during this reaction is/are : | [{"identifier": "A", "content": "1"}, {"identifier": "B", "content": "3"}, {"identifier": "C", "content": "4"}, {"identifier": "D", "content": "2"}] | ["A"] | null | Al<sup>3+</sup> and Fe<sup>3+</sup> sulphides hydrolyse in water.<br><br>Ni<sup>2+</sup> and Zn<sup>2+</sup> require basic medium with H<sub>2</sub>S to form ppt<br><br>Ca<sup>2+</sup> and Ba<sup>2+</sup> sulphides are soluble<br><br>hence, we will receive only CuS ppt. | mcq | jee-main-2021-online-27th-july-evening-shift | 3,301 |
1l54yynco | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>A white precipitate was formed when BaCl<sub>2</sub> was added to water extract of an inorganic salt. Further, a gas 'X' with characteristic odour was released when the formed white precipitate was dissolved in dilute HCl. The anion present in the inorganic salt is</p> | [{"identifier": "A", "content": "I<sup>$$-$$</sup>"}, {"identifier": "B", "content": "SO<sub>3</sub><sup>2$$-$$</sup>"}, {"identifier": "C", "content": "S<sup>2$$-$$</sup>"}, {"identifier": "D", "content": "NO<sub>2</sub><sup>$$-$$</sup>"}] | ["B"] | null | Anion is $\mathrm{SO}_{3}^{-2}$
<br/><br/>
$$
\mathrm{BaSO}_{3} \stackrel{\text { dil } \mathrm{HCl}}{\longrightarrow} \underset{x(\text { gas })}{\mathrm{SO}_{2} \uparrow}
$$
<br/><br/>
Gas is released with smell of burning sulphur. | mcq | jee-main-2022-online-29th-june-evening-shift | 3,302 |
1l59r7vgr | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>During halogen test, sodium fusion extract is boiled with concentrated HNO<sub>3</sub> to</p> | [{"identifier": "A", "content": "remove unreacted sodium"}, {"identifier": "B", "content": "decompose cyanide or sulphide of sodium"}, {"identifier": "C", "content": "extract halogen from organic compound"}, {"identifier": "D", "content": "maintain the pH of extract."}] | ["B"] | null | During test for halogen, if nitrogen or sulphur is also
present in the compound, then sodium fusion
extract is first boiled with concentrated nitric acid to
decompose cyanide or sulphide of sodium formed
during Lassaigne's test. | mcq | jee-main-2022-online-25th-june-evening-shift | 3,303 |
1l5bdobmi | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>In the flame test of a mixture of salts, a green flame with blue centre was observed. Which one of the following cations may be present?</p> | [{"identifier": "A", "content": "Cu<sup>2+</sup>"}, {"identifier": "B", "content": "Sr<sup>2+</sup>"}, {"identifier": "C", "content": "Ba<sup>2+</sup>"}, {"identifier": "D", "content": "Ca<sup>2+</sup>"}] | ["A"] | null | Cupric salts give green flame with blue centre. The colour of other salts are
<br/><br/>
$\begin{array}{ll}\mathrm{Sr}^{2+} & \text { Crimson red } \\ \mathrm{Ca}^{2+} & \text { Brick red } \\ \mathrm{Ba}^{2+} & \text { Green }\end{array}$ | mcq | jee-main-2022-online-24th-june-evening-shift | 3,304 |
1l5c6zbel | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>During the qualitative analysis of salt with cation y<sup>2+</sup>, addition of a reagent (X) to alkaline solution of the salt gives a bright red precipitate. The reagent (X) and the cation (y<sup>2+</sup>) present respectively are :</p> | [{"identifier": "A", "content": "Dimethylglyoxime and Ni<sup>2+</sup>"}, {"identifier": "B", "content": "Dimethylglyoxime and Co<sup>2+</sup>"}, {"identifier": "C", "content": "Nessler's reagent and Hg<sup>2+</sup>"}, {"identifier": "D", "content": "Nessler's reagent and Ni<sup>2+</sup>"}] | ["A"] | null | On addition of dimethylglyoxime to alkaline solution of $\mathrm{Ni}^{+2}$, a bright red ppt. is obtained.
<br/><br/>
$\mathrm{Ni}^{+2}+2 \mathrm{dmg} \rightarrow\left[\mathrm{Ni}(\mathrm{dmg})_{2}\right]^{+2}$ (Bright red ppt) | mcq | jee-main-2022-online-24th-june-morning-shift | 3,305 |
1ldr3f16z | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>In the wet tests for identification of various cations by precipitation, which transition element cation doesn't belong to group IV in qualitative inorganic analysis?</p> | [{"identifier": "A", "content": "Co<sup>2+</sup>"}, {"identifier": "B", "content": "Ni<sup>2+</sup>"}, {"identifier": "C", "content": "Zn<sup>2+</sup>"}, {"identifier": "D", "content": "Fe<sup>3+</sup>"}] | ["D"] | null | <p>Fe$$^{3+}$$ belongs to III$$^{rd}$$ group</p> | mcq | jee-main-2023-online-30th-january-morning-shift | 3,306 |
1ldul7hx4 | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>Match the List-I with List-II :</p>
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.tg th{border-color:black;border-style:so... | [{"identifier": "A", "content": "A $$\\to$$ i, B $$\\to$$ iii, C $$\\to$$ iv, D $$\\to$$ ii"}, {"identifier": "B", "content": "A $$\\to$$ i, B $$\\to$$ iii, C $$\\to$$ ii, D $$\\to$$ iv"}, {"identifier": "C", "content": "A $$\\to$$ iii, B $$\\to$$ i, C $$\\to$$ iv, D $$\\to$$ ii"}, {"identifier": "D", "content": "A $$\... | ["A"] | null | <style type="text/css">
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overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family... | mcq | jee-main-2023-online-25th-january-morning-shift | 3,308 |
1lgp2d0he | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>In the wet tests for detection of various cations by precipitation, $$\mathrm{Ba}^{2+}$$ cations are detected by obtaining precipitate of</p> | [{"identifier": "A", "content": "$$\\mathrm{BaSO}_{4}$$"}, {"identifier": "B", "content": "$$\\mathrm{Ba}(\\mathrm{OAc})_{2}$$"}, {"identifier": "C", "content": "$$\\mathrm{BaCO}_{3}$$"}, {"identifier": "D", "content": "$$\\mathrm{Ba}(\\mathrm{ox})$$ : Barium oxalate"}] | ["C"] | null | <p>In the wet test for detection of Group 5 cations, including Ba²⁺, Ca²⁺, and Sr²⁺, ammonium carbonate ((NH₄)₂CO₃) is used as a group reagent. The reaction with barium ions (Ba²⁺) can be written as :</p>
<p>$$\mathrm{Ba}^{2+} + \left(\mathrm{NH}_4\right)_2\mathrm{CO}_3 \rightarrow \underset{\text{(white precipitate)}... | mcq | jee-main-2023-online-13th-april-evening-shift | 3,309 |
jaoe38c1lsfjhjvg | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>In chromyl chloride test for confirmation of $$\mathrm{Cl}^{-}$$ ion, a yellow solution is obtained. Acidification of the solution and addition of amyl alcohol and $$10 \% \mathrm{~H}_2 \mathrm{O}_2$$ turns organic layer blue indicating formation of chromium pentoxide. The oxidation state of chromium in that is</p> | [{"identifier": "A", "content": "+6"}, {"identifier": "B", "content": "+5"}, {"identifier": "C", "content": "+3"}, {"identifier": "D", "content": "+10"}] | ["A"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lt2e99tr/c46ada81-ab0c-4f62-b439-e02d41056910/36ed18f0-d459-11ee-9e2f-8fcdff2fc6a2/file-1lt2e99ts.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lt2e99tr/c46ada81-ab0c-4f62-b439-e02d41056910/36ed18f0-d459-11ee-9e2f-8fcdff2fc6a2... | mcq | jee-main-2024-online-29th-january-morning-shift | 3,310 |
jaoe38c1lsfjwynb | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>Appearance of blood red colour, on treatment of the sodium fusion extract of an organic compound with $$\mathrm{FeSO}_4$$ in presence of concentrated $$\mathrm{H}_2 \mathrm{SO}_4$$ indicates the presence of element/s</p> | [{"identifier": "A", "content": "Br"}, {"identifier": "B", "content": "S"}, {"identifier": "C", "content": "N and S"}, {"identifier": "D", "content": "N"}] | ["C"] | null | <p>$$\begin{aligned}
& \mathrm{Fe}^{2+} \xrightarrow[\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4]{\mathrm{H}^{+}} \mathrm{Fe}^{+3} \\
& \mathrm{Fe}^{+3} \xrightarrow{- \text { SCN }} \mathrm{Fe}(\mathrm{SCN})_3 \text { (blood red colour) }
\end{aligned}$$</p>
<p>Appearance of blood red colour indicates presence of both ... | mcq | jee-main-2024-online-29th-january-morning-shift | 3,311 |
lv0vycfc | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>In the precipitation of the iron group (III) in qualitative analysis, ammonium chloride is added before adding ammonium hydroxide to :</p> | [{"identifier": "A", "content": "decrease concentration of $${ }^{-} \\mathrm{OH}$$ ions\n"}, {"identifier": "B", "content": "increase concentration of $$\\mathrm{Cl}^{-}$$ ions\n"}, {"identifier": "C", "content": "prevent interference by phosphate ions\n"}, {"identifier": "D", "content": "increase concentration of $$\... | ["A"] | null | <p>In qualitative analysis, the precipitation of the iron group (III) requires careful control of conditions to ensure selective precipitation of the desired ions. Ammonium chloride is added before ammonium hydroxide to achieve this control effectively.</p>
<p>Let's analyze the options to understand why ammonium chlor... | mcq | jee-main-2024-online-4th-april-morning-shift | 3,312 |
lv5gt1uq | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>Match List I with List II</p>
<p><style type="text/css">
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.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "A-III, B-I, C-IV, D-II\n"}, {"identifier": "B", "content": "A-III, B-IV, C-I, D-II\n"}, {"identifier": "C", "content": "A-III, B-II, C-IV, D-I\n"}, {"identifier": "D", "content": "A-III, B-I, C-II, D-IV"}] | ["B"] | null | <p>(A) Borax bead test</p>
<p>$$\mathrm{MSO}_4 \xrightarrow[\Delta]{\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7} \mathrm{M}\left(\mathrm{BO}_2\right)_2 \rightarrow \mathrm{MBO}_2 \rightarrow \mathrm{M}$$</p>
<p>(B) Charcoal cavity test</p>
<p>$$\mathrm{MSO}_4 \xrightarrow[\Delta]{\mathrm{Na}_2 \mathrm{CO}_3} \mathrm{MCO}_... | mcq | jee-main-2024-online-8th-april-morning-shift | 3,313 |
lvb29j92 | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>During the detection of acidic radical present in a salt, a student gets a pale yellow precipitate soluble with difficulty in $$\mathrm{NH}_4 \mathrm{OH}$$ solution when sodium carbonate extract was first acidified with dil. $$\mathrm{HNO}_3$$ and then $$\mathrm{AgNO}_3$$ solution was added. This indicates presence ... | [{"identifier": "A", "content": "$$\\mathrm{I}^{-}$$\n"}, {"identifier": "B", "content": "$$\\mathrm{CO}_3{ }^{2-}$$\n"}, {"identifier": "C", "content": "$$\\mathrm{Cl}^{-}$$\n"}, {"identifier": "D", "content": "$$\\mathrm{Br}^{-}$$"}] | ["D"] | null | <p>The $$\mathrm{Br}^{-}$$ ion present in the salt gives pale yellow ppt. of $$\mathrm{AgBr}$$ with $$\mathrm{AgNO}_3$$, insoluble in dil $$\mathrm{HNO}_3$$ but partially soluble in aq. $$\mathrm{NH}_4 \mathrm{OH}$$.</p>
<p>$$\mathrm{Br}^{-}+\mathrm{AgNO}_3 \rightarrow \underset{\text { Pale yellow }}{\mathrm{AgBr} \do... | mcq | jee-main-2024-online-6th-april-evening-shift | 3,314 |
lvc583co | chemistry | practical-organic-chemistry | qualitative-salt-analysis | <p>Match List I with List II</p>
<p><style type="text/css">
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.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "A-III, B-IV, C-I, D-II\n"}, {"identifier": "B", "content": "A-III, B-IV, C-II, D-I\n"}, {"identifier": "C", "content": "A-IV, B-III, C-II, D-I\n"}, {"identifier": "D", "content": "A-IV, B-III, C-I, D-II"}] | ["A"] | null | <p>$$\begin{array}{lll}
\mathrm{A} & \rightarrow \mathrm{Al}^{3+}(\mathrm{III}) \\
\mathrm{B} & \rightarrow \mathrm{Sr}^{2+}(\mathrm{IV}) \\
\mathrm{C} & \rightarrow \mathrm{Mn}^{2+}(\mathrm{I}) \\
\mathrm{D} & \rightarrow \mathrm{Pb}^{2+}(\mathrm{II})
\end{array}$$</p> | mcq | jee-main-2024-online-6th-april-morning-shift | 3,315 |
Ee9Rx5oIInUG5CDx | chemistry | redox-reactions | balancing-of-redox-reactions | Consider the following reaction:<br/><br/>
$$xMnO_4^- + yC_2O_4^{2-}$$ + zH<sup>+</sup> $$\to$$ xMn<sup>2+</sup> + 2yCO<sub>2</sub> + $${z \over 2}{H_2}O$$<br/><br/>
The value's of x, y and z in the reaction are, respectively : | [{"identifier": "A", "content": "5, 2 and 16"}, {"identifier": "B", "content": "2, 5 and 8"}, {"identifier": "C", "content": "2, 5 and 16"}, {"identifier": "D", "content": "5, 2 and 8"}] | ["C"] | null | After balancing the reaction we get
<br><br>$$2MnO_4^- + 5C_2O_4^{2-}$$ + 16H<sup>+</sup> $$\to$$ 2Mn<sup>2+</sup> + 10CO<sub>2</sub> + $$8{H_2}O$$
<br><br>$$\therefore$$ $$x$$ = 2, $$y$$ = 5 and z = 16 | mcq | jee-main-2013-offline | 3,316 |
1lgp3h0ep | chemistry | redox-reactions | balancing-of-redox-reactions | <p>See the following chemical reaction:</p>
<p>$$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+\mathrm{XH}^{+}+6 \mathrm{~F}_{e}^{2+} \rightarrow \mathrm{YCr}^{3+}+6 \mathrm{~F}_{e}^{3+}+\mathrm{Z} \mathrm{H}_{2} \mathrm{O}$$</p>
<p>The sum of $$\mathrm{X}, \mathrm{Y}$$ and $$\mathrm{Z}$$ is ___________</p> | [] | null | 23 | To find the sum of X, Y, and Z, we need to balance the given chemical reaction:
<br/><br/>
$$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} + \mathrm{XH}^{+} + 6 \mathrm{Fe}^{2+} \rightarrow \mathrm{YCr}^{3+} + 6 \mathrm{Fe}^{3+} + \mathrm{ZH}_{2} \mathrm{O}$$
<br/><br/>
Let's balance the reaction step by step:
<br/><br/>
1. Bala... | integer | jee-main-2023-online-13th-april-evening-shift | 3,317 |
1lh031a7t | chemistry | redox-reactions | balancing-of-redox-reactions | <p>$$2 \mathrm{IO}_{3}^{-}+x \mathrm{I}^{-}+12 \mathrm{H}^{+} \rightarrow 6 \mathrm{I}_{2}+6 \mathrm{H}_{2} \mathrm{O}$$</p>
<p>What is the value of $$x$$ ?</p> | [{"identifier": "A", "content": "10"}, {"identifier": "B", "content": "2"}, {"identifier": "C", "content": "12"}, {"identifier": "D", "content": "6"}] | ["A"] | null | <p>The reaction given is a disproportionation reaction where iodine ($\mathrm{I}_2$) undergoes both oxidation and reduction. Disproportionation reactions are a type of redox reaction where an element is simultaneously oxidized and reduced.</p>
<p>In the process, iodine gets oxidized from 0 oxidation state (in $\mathrm{... | mcq | jee-main-2023-online-8th-april-morning-shift | 3,318 |
jaoe38c1lsfjgqcy | chemistry | redox-reactions | balancing-of-redox-reactions | <p>Chlorine undergoes disproportionation in alkaline medium as shown below :</p>
<p>$$\mathrm{aCl}_{2(\mathrm{~g})}+\mathrm{b} \mathrm{OH}_{(\mathrm{aq})}^{-} \rightarrow \mathrm{c} \mathrm{ClO}_{(\mathrm{aq)}}^{-}+\mathrm{d} \mathrm{Cl}_{(\mathrm{aq})}^{-}+\mathrm{e} \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}$$</p>
<p>The... | [{"identifier": "A", "content": "3, 4, 4 and 2"}, {"identifier": "B", "content": "1, 2, 1 and 1"}, {"identifier": "C", "content": "2, 4, 1 and 3"}, {"identifier": "D", "content": "2, 2, 1 and 3"}] | ["B"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lt2nbmm2/d92e9dd7-350f-4f04-a0c3-630a70f852f3/aa9579a0-d47c-11ee-ae81-7f6ed45275c8/file-1lt2nbmm3.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lt2nbmm2/d92e9dd7-350f-4f04-a0c3-630a70f852f3/aa9579a0-d47c-11ee-ae81-7f6ed45275c8... | mcq | jee-main-2024-online-29th-january-morning-shift | 3,321 |
1lsgz3rvm | chemistry | redox-reactions | balancing-of-redox-reactions | <p>$$2 \mathrm{MnO}_4^{-}+\mathrm{bI}^{-}+\mathrm{cH}_2 \mathrm{O} \rightarrow x \mathrm{I}_2+y \mathrm{MnO}_2+z \overline{\mathrm{O}} \mathrm{H}$$</p>
<p>If the above equation is balanced with integer coefficients, the value of $$z$$ is ________.</p> | [] | null | 8 | <p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial,... | integer | jee-main-2024-online-30th-january-morning-shift | 3,322 |
DD98dZed5YgA5ZUouyjgy2xukfchmxk0 | chemistry | redox-reactions | equivalence | A 100 mL solution was made by adding 1.43 g
of Na<sub>2</sub>CO<sub>3</sub>.xH<sub>2</sub>O. The normality of the solution
is 0.1 N. The value of x is _____.
<br/><br/>(The atomic mass of Na is 23 g/mol)
| [] | null | 10 | Molar mass of Na<sub>2</sub>CO<sub>3</sub>.xH<sub>2</sub>O
<br><br>= 23 × 2 + 12 + 48 + 18x
<br><br>= 46 + 12 + 48 + 18x
<br><br>= (106 + 18x)
<br><br>As n<sub>factor</sub> in dissolution will be determined from net cationic or anionic charge; which is 2
<br><br>Eq wt = $${M \over 2}$$ = (53 + 9x)
<br><br>volume = 100 ... | integer | jee-main-2020-online-4th-september-evening-slot | 3,326 |
1l55oahmw | chemistry | redox-reactions | equivalence | <p>0.01 M KMnO<sub>4</sub> solution was added to 20.0 mL of 0.05 M Mohr's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO<sub>4</sub> solution left in the burette after the end point is _____________ mL. (nearest integer)</p> | [] | null | 30 | Meq of oxidizing agent $=$ Meq of reducing agent
<br/><br/>
$\left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}_{\text{F}}\right)_{\mathrm{KMnO}_{4}}=\left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}_{\text{F}}\right)_{\text {Mohr's salt }}$
<br/><br/>
$0.01 \times 20 \times 5=0.05 \times V \times 1$
<br/><br/>
Vo... | integer | jee-main-2022-online-28th-june-evening-shift | 3,327 |
1l59rrtym | chemistry | redox-reactions | equivalence | <p>The neutralization occurs when 10 mL of 0.1M acid 'A' is allowed to react with 30 mL of 0.05 M base M(OH)<sub>2</sub>. The basicity of the acid 'A' is __________.</p>
<p>[M is a metal]</p> | [] | null | 3 | Milieq of acid $A=$ Milieq of base $M(O H)_{2}$
<br/><br/>
$$
\begin{aligned}
& \left(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor }_{A}\right.=(\mathrm{M} \times \mathrm{V} \times \mathrm{n}-\text { Factor })_{\mathrm{M}(\mathrm{OH})_{2}} \\\\
& \left[\mathrm{n}-\text { Factor of } \mathrm{M}(\mathrm{... | integer | jee-main-2022-online-25th-june-evening-shift | 3,328 |
1l6ku767y | chemistry | redox-reactions | equivalence | <p>The normality of $$\mathrm{H}_{2} \mathrm{SO}_{4}$$ in the solution obtained on mixing $$100 \mathrm{~mL}$$ of $$0.1 \,\mathrm{M} \,\mathrm{H}_{2} \mathrm{SO}_{4}$$ with $$50 \mathrm{~mL}$$ of $$0.1 \,\mathrm{M}\, \mathrm{NaOH}$$ is _______________ $$\times 10^{-1} \mathrm{~N}$$. (Nearest Integer)</p> | [] | null | 1 | No. of equivalents of $\mathrm{H}_2 \mathrm{SO}_4=100 \times 0.1 \times 2=20$<br/><br/>
No. of equivalents of $\mathrm{NaOH}=50 \times 0.1=5$<br/><br/>
No. of equivalents of $\mathrm{H}_2 \mathrm{SO}_4$ left $=20-5=15$<br/><br/>
$$
\begin{aligned}
&\Rightarrow 150 \times \mathrm{x}=15 \\\\
&\mathrm{x}=\frac{1}{10}=0.1 ... | integer | jee-main-2022-online-27th-july-evening-shift | 3,329 |
bUz5bDaiqt75drYS | chemistry | redox-reactions | oxidation-and-reduction-reactions | Which of the following is a redox reaction ? | [{"identifier": "A", "content": "NaCl + KNO<sub>3</sub> $$\\to$$ NaNO<sub>3</sub> + KCl"}, {"identifier": "B", "content": "CaC<sub>2</sub>O<sub>4</sub> + 2HCl $$\\to$$ CaCl<sub>2</sub> + H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>"}, {"identifier": "C", "content": "Mg(OH)<sub>2</sub> + 2NH<sub>4</sub>Cl $$\\to$$ MgCl<sub>2... | ["D"] | null | <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263850/exam_images/c9pvrlc19tmt4yqcwxf3.webp" loading="lazy" alt="AIEEE 2002 Chemistry - Redox Reactions Question 57 English Explanation">
<br><br>The oxidation state shows a change only in (d) | mcq | aieee-2002 | 3,330 |
6gt8nqdfhZsoiXTH | chemistry | redox-reactions | oxidation-and-reduction-reactions | In which of the following reactions H<sub>2</sub>O<sub>2</sub> acts as a reducing agent?
<br/>1. H<sub>2</sub>O<sub>2</sub> + 2H<sup>+</sup> + 2e<sup>-</sup> $$\to$$ 2H<sub>2</sub>O
<br/>2. H<sub>2</sub>O<sub>2</sub> - 2e<sup>-</sup> $$\to$$ O<sub>2</sub> + 2H<sup>+</sup>
<br/>3. H<sub>2</sub>O<sub>2</sub> + 2e<sup>-</... | [{"identifier": "A", "content": "1, 2"}, {"identifier": "B", "content": "3, 4"}, {"identifier": "C", "content": "1, 3"}, {"identifier": "D", "content": "2, 4"}] | ["D"] | null | The reducing agent loses electron during redox reaction i.e. oxidises itself.
<br><br>$$\left( 1 \right)\,\,\,\,\,\,{H_2}\mathop {{O_2}}\limits^{ - 1} + 2{H^ + } + 2{e^ - }\,\,\buildrel \, \over
\longrightarrow \,\,2{H_2}\mathop O\limits^{ - 2} \,\,({\mathop{\rm Re}\nolimits} d.)$$
<br><br> $$\left( 2 \right)\,\,\,\... | mcq | jee-main-2014-offline | 3,332 |
AZIQSjpVsC1nOZTE | chemistry | redox-reactions | oxidation-and-reduction-reactions | Which of the following reactions is an example of a redox reaction? | [{"identifier": "A", "content": "$$Xe{F_6}$$ + H<sub>2</sub>O $$\\to$$ $$XeO{F_4}$$ + 2HF"}, {"identifier": "B", "content": "$$Xe{F_6}$$ + 2H<sub>2</sub>O $$\\to$$ $$XeO_2{F_2}$$ + 4HF"}, {"identifier": "C", "content": "$$Xe{F_4}$$ + O<sub>2</sub>F<sub>2</sub> $$\\to$$ $$Xe{F_6}$$ + O<sub>2</sub> "}, {"identifier": "D"... | ["C"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l91qo7ys/d7a37472-ca22-42b1-8af7-9dd448bd7781/a7f2d140-4808-11ed-935b-0fd6c7d272a9/file-1l91qo7yt.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l91qo7ys/d7a37472-ca22-42b1-8af7-9dd448bd7781/a7f2d140-4808-11ed-935b-0fd6c7d272a9/fi... | mcq | jee-main-2017-offline | 3,333 |
dJsK1dnG9eeuqU6h6B1v3 | chemistry | redox-reactions | oxidation-and-reduction-reactions | In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO<sub>2</sub> is : | [{"identifier": "A", "content": "10"}, {"identifier": "B", "content": "2"}, {"identifier": "C", "content": "1"}, {"identifier": "D", "content": "5"}] | ["C"] | null | <p>The balanced reaction of oxalate with permanganate in acidic medium is :</p>
<p>$$5 \, \text{C}_2\text{O}_4^{2-} + 2 \, \text{MnO}_4^- + 16 \, \text{H}^+ \rightarrow 10 \, \text{CO}_2 + 2 \, \text{Mn}^{2+} + 8 \, \text{H}_2\text{O}$$</p>
<p>In this redox reaction, the oxalate ion $\text{C}_2\text{O}_4^{2-}$ is oxidi... | mcq | jee-main-2019-online-10th-january-evening-slot | 3,334 |
uOActAkQoaumecjQJo7k9k2k5epwqeu | chemistry | redox-reactions | oxidation-and-reduction-reactions | The redox reaction among the following is : | [{"identifier": "A", "content": "reaction of H<sub>2</sub>SO<sub>4</sub> with NaOH."}, {"identifier": "B", "content": "formation of ozone form atmosphere oxygen in the presence of sunlight."}, {"identifier": "C", "content": "combination of dinitrogen with dioxygen at 2000 K"}, {"identifier": "D", "content": "reaction o... | ["C"] | null | N<sub>2</sub> + O<sub>2</sub> $$ \to $$ 2NO
<br><br>during the reaction, oxidation of nitrogen take place
from 0 to 2 and reduction of oxygen take place
from 0 to –2. It means this reaction is redox
reaction.
<br><br>3O<sub>2</sub> $$ \to $$ 2O<sub>3</sub> (Non - redox reaction)
<br><br>2NaOH + H<sub>2</sub>SO<sub>4</s... | mcq | jee-main-2020-online-7th-january-evening-slot | 3,335 |
91lPBnmet4BGfbFKjY1kmiunroc | chemistry | redox-reactions | oxidation-and-reduction-reactions | Statement I : Sodium hydride can be used as an oxidising agent.<br/><br/>Statement II : The lone pair of electrons on nitrogen in pyridine makes it basic.<br/><br/>Choose the CORRECT answer from the options given below : | [{"identifier": "A", "content": "Statement I is false but statement II is true"}, {"identifier": "B", "content": "Both statement I and statement II are true"}, {"identifier": "C", "content": "Statement I is true but statement II is false"}, {"identifier": "D", "content": "Both statement I and statement II are false"}] | ["A"] | null | NaH is a strong H<sup>–</sup> (hydride) donor. Hence
cannot be used as an oxidising agent.<br><br>
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263410/exam_images/u8ujyc6ewwg9iw8anna2.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online)... | mcq | jee-main-2021-online-16th-march-evening-shift | 3,336 |
jaoe38c1lscrqpvw | chemistry | redox-reactions | oxidation-and-reduction-reactions | <p>Which of the following cannot function as an oxidising agent?</p> | [{"identifier": "A", "content": "$$\\mathrm{SO}_4^{2-}$$\n"}, {"identifier": "B", "content": "$$\\mathrm{MnO}_4^{-}$$\n"}, {"identifier": "C", "content": "$$\\mathrm{N}^{3-}$$\n"}, {"identifier": "D", "content": "$$\\mathrm{BrO}_3^{-}$$"}] | ["C"] | null | <p>The ability of a species to function as an oxidizing agent depends on its ability to gain electrons (be reduced). For a species to be an oxidizing agent, it must contain an element that has a positive oxidation state and is capable of being reduced (gain electrons), thereby oxidizing another species.</p>
<p>Let's l... | mcq | jee-main-2024-online-27th-january-evening-shift | 3,337 |
jaoe38c1lsfjzybv | chemistry | redox-reactions | oxidation-and-reduction-reactions | <p>In alkaline medium, $$\mathrm{MnO}_4^{-}$$ oxidises $$\mathrm{I}^{-}$$ to </p> | [{"identifier": "A", "content": "$$I_2$$\n"}, {"identifier": "B", "content": "$$\\mathrm{IO}_3^{-}$$\n"}, {"identifier": "C", "content": "$$\\mathrm{IO}^{-}$$\n"}, {"identifier": "D", "content": "$$\\mathrm{IO}_4^{-}$$"}] | ["B"] | null | <p>$$$2 \mathrm{MnO}_4^{-}+\mathrm{H}_2 \mathrm{O}+\mathrm{I}^{-} \xrightarrow{\text { alkaline medium }} 2 \mathrm{MnO}_2+2 \mathrm{OH}^{-}+\mathrm{IO}_3^{-}$$$</p> | mcq | jee-main-2024-online-29th-january-morning-shift | 3,338 |
lv2ers4s | chemistry | redox-reactions | oxidation-and-reduction-reactions | <p>When $$\mathrm{MnO}_2$$ and $$\mathrm{H}_2 \mathrm{SO}_4$$ is added to a salt $$(\mathrm{A})$$, the greenish yellow gas liberated as salt (A) is :</p> | [{"identifier": "A", "content": "$$\\mathrm{NH}_4 \\mathrm{Cl}$$\n"}, {"identifier": "B", "content": "$$\\mathrm{CaI}_2$$\n"}, {"identifier": "C", "content": "$$\\mathrm{KNO}_3$$\n"}, {"identifier": "D", "content": "$$\\mathrm{NaBr}$$"}] | ["A"] | null | <p>When a salt reacts with $$\mathrm{MnO}_2$$ and concentrated $$\mathrm{H}_2 \mathrm{SO}_4$$, the type of gas evolved depends on the anion present in the salt. In this case, a greenish yellow gas is evolved, which indicates the formation of chlorine gas ($$\mathrm{Cl}_2$$). $$\mathrm{Cl}_2$$ gas is greenish-yellow in ... | mcq | jee-main-2024-online-4th-april-evening-shift | 3,339 |
lv5gt1sb | chemistry | redox-reactions | oxidation-and-reduction-reactions | <p>Thiosulphate reacts differently with iodine and bromine in the reactions given below:</p>
<p>$$\begin{aligned}
& 2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+\mathrm{I}_2 \rightarrow \mathrm{S}_4 \mathrm{O}_6^{2-}+2 \mathrm{I}^{-} \\
& \mathrm{S}_2 \mathrm{O}_3^{2-}+5 \mathrm{Br}_2+5 \mathrm{H}_2 \mathrm{O} \rightarrow... | [{"identifier": "A", "content": "Thiosulphate undergoes oxidation by bromine and reduction by iodine in these reactions\n"}, {"identifier": "B", "content": "Bromine is a weaker oxidant than iodine\n"}, {"identifier": "C", "content": "Bromine is a stronger oxidant than iodine\n"}, {"identifier": "D", "content": "Bromine... | ["C"] | null | <p>In the given reactions:</p>
<p>$$\begin{aligned}
& 2 \mathrm{S}_2\mathrm{O}_3^{2-} + \mathrm{I}_2 \rightarrow \mathrm{S}_4\mathrm{O}_6^{2-} + 2 \mathrm{I}^{-} \\\\
& \mathrm{S}_2\mathrm{O}_3^{2-} + 5 \mathrm{Br}_2 + 5 \mathrm{H}_2\mathrm{O} \rightarrow 2 \mathrm{SO}_4^{2-} + 4 \mathrm{Br}^{-} + 10 \mathrm{H}^{+}
\en... | mcq | jee-main-2024-online-8th-april-morning-shift | 3,340 |
ILZMXBbS6Wf9jXCoyj6rP | chemistry | redox-reactions | oxidation-number | The correct order of the oxidation states of
nitrogen in NO, N<sub>2</sub>O, NO<sub>2</sub> and N<sub>2</sub>O<sub>3</sub> is : | [{"identifier": "A", "content": "NO<sub>2</sub> < NO < N<sub>2</sub>O<sub>3</sub> < N<sub>2</sub>O"}, {"identifier": "B", "content": "NO<sub>2</sub> < N<sub>2</sub>O<sub>3</sub> < NO < N<sub>2</sub>O"}, {"identifier": "C", "content": "N<sub>2</sub>O < NO < N<sub>2</sub>O<sub>3</sub> < NO<sub>... | ["C"] | null | In N<sub>2</sub>O oxidation states of
nitrogen = +1
<br><br>In NO oxidation states of
nitrogen = +2
<br><br>In N<sub>2</sub>O<sub>3</sub> oxidation states of
nitrogen = +3
<br><br>In NO<sub>2</sub> oxidation states of
nitrogen = +4 | mcq | jee-main-2019-online-9th-april-morning-slot | 3,342 |
sUGLsiqlV2h6S2Ps2z7k9k2k5dyph0k | chemistry | redox-reactions | oxidation-number | Oxidation number of potassium in K<sub>2</sub>O. K<sub>2</sub>O<sub>2</sub> and KO<sub>2</sub> respectively is : | [{"identifier": "A", "content": "+1, +2 and + 4"}, {"identifier": "B", "content": "+1, +1 and + 1"}, {"identifier": "C", "content": "+2, +1 and $$ + {1 \\over 2}$$"}, {"identifier": "D", "content": "+1, +4, and +2"}] | ["B"] | null | Potasisum has an oxidation of +1 (only) in
combined state. | mcq | jee-main-2020-online-7th-january-morning-slot | 3,343 |
vlhjHX6yKGZg6V7YU07k9k2k5idmyit | chemistry | redox-reactions | oxidation-number | The compound that cannot act both as oxidising
and reducing agent is : | [{"identifier": "A", "content": "H<sub>3</sub>PO<sub>4</sub>"}, {"identifier": "B", "content": "H<sub>2</sub>SO<sub>3</sub>"}, {"identifier": "C", "content": "H<sub>2</sub>O<sub>2</sub>"}, {"identifier": "D", "content": "HNO<sub>2</sub>"}] | ["A"] | null | In H<sub>3</sub>PO<sub>4</sub>, P is present in +5 oxidation state and
it can act as reducing agent only. | mcq | jee-main-2020-online-9th-january-morning-slot | 3,344 |
uNrZvCorxnp4BUjUHOjgy2xukeyh0ywx | chemistry | redox-reactions | oxidation-number | The oxidation states of transition metal atoms
in K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub>, KMnO<sub>4</sub> and K<sub>2</sub>FeO<sub>4</sub>, respectively,
are x, y and z. The sum of x, y and z is _______. | [] | null | 19 | <b>K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub></b>
<br><br>Let oxidation state of Ce
<br><br>2(+1) + 2x + 7(–2) = 0
<br><br>$$ \Rightarrow $$ x = +6
<br><br>In K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub>, Transition metal (Cr) present in +6 oxidation state.
<br><br><b>KMnO<sub>4</sub></b>
<br><br>(+1) + y + 4(–2) = 0
<br>$$ ... | integer | jee-main-2020-online-2nd-september-evening-slot | 3,345 |
9KUPMuqvsxidkPpuBO1klue8sl2 | chemistry | redox-reactions | oxidation-number | Dichromate ion is treated with base, the oxidation number of Cr in the product formed is ___________. | [] | null | 6 | $$C{r_2}O_7^{2 - } + 2O{H^ - }$$ ⇌ $$2CrO_4^{2 - } + {H_2}O$$
<br><br>Let Oxidation state of Cr in $$CrO_4^{2 - }$$ is = x.
<br><br>$$ \therefore $$ x + (–2 × 4) = –2
<br><br>$$ \Rightarrow $$ x = 6 | integer | jee-main-2021-online-26th-february-morning-slot | 3,346 |
9qj8Tm9aeBraxksqGm1kmm1cgbf | chemistry | redox-reactions | oxidation-number | The oxidation states of nitrogen in NO, NO<sub>2</sub>, N<sub>2</sub>O and NO$$_3^ - $$ are in the order of : | [{"identifier": "A", "content": "N<sub>2</sub>O > NO<sub>2</sub> > NO > NO$$_3^ - $$"}, {"identifier": "B", "content": "NO > NO<sub>2</sub> > N<sub>2</sub>O > NO$$_3^ - $$"}, {"identifier": "C", "content": "NO<sub>2</sub> > NO$$_3^ - $$ > NO > N<sub>2</sub>O"}, {"identifier": "D", "content": ... | ["D"] | null | The oxidation states of Nitrogen in following
molecules are as follows<br><br>
$$NO_3^ - \to $$ +5<br><br>
NO<sub>2</sub> $$ \to $$ +4<br><br>
NO $$ \to $$ +2<br><br>
N<sub>2</sub>O $$ \to $$ +1 | mcq | jee-main-2021-online-18th-march-evening-shift | 3,347 |
1krxb954p | chemistry | redox-reactions | oxidation-number | Identify the process in which change in the oxidation state is five : | [{"identifier": "A", "content": "$$C{r_2}O_7^{2 - } \\to 2C{r^{3 + }}$$"}, {"identifier": "B", "content": "$$MnO_4^ - \\to M{n^{2 + }}$$"}, {"identifier": "C", "content": "$$CrO_4^{2 - } \\to C{r^{3 + }}$$"}, {"identifier": "D", "content": "$${C_2}O_4^{2 - } \\to 2C{O_2}$$"}] | ["B"] | null | $$MnO_4^ - + 5e \to M{n^{ + 2}}$$ | mcq | jee-main-2021-online-25th-july-evening-shift | 3,348 |
1krz034xm | chemistry | redox-reactions | oxidation-number | The oxidation states of 'P' in H<sub>4</sub>P<sub>2</sub>O<sub>7</sub>, H<sub>4</sub>P<sub>2</sub>O<sub>5</sub> and H<sub>4</sub>P<sub>2</sub>O<sub>6</sub>, respectively, are : | [{"identifier": "A", "content": "7, 5 and 6"}, {"identifier": "B", "content": "5, 4 and 3"}, {"identifier": "C", "content": "5, 3 and 4"}, {"identifier": "D", "content": "6, 4 and 5"}] | ["C"] | null | Oxidation state of P in H<sub>4</sub>P<sub>2</sub>O<sub>7</sub>, H<sub>4</sub>P<sub>2</sub>O<sub>5</sub> and H<sub>4</sub>P<sub>2</sub>O<sub>6</sub> is 5, 3 & 4 respectively<br><br>H<sub>4</sub>P<sub>2</sub>O<sub>7</sub><br><br>2x + 4(+ 1) + 7 ($$-$$2) = 0<br><br>x = + 5<br><br>$${H_4}\underline {{P_2}} {O_5}$$<br>... | mcq | jee-main-2021-online-27th-july-morning-shift | 3,349 |
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