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1ldolmvvn | chemistry | redox-reactions | oxidation-number | <p>Sum of oxidation states of bromine in bromic acid and perbromic acid is ___________.</p> | [] | null | 12 | <p>The sum of the oxidation states of bromine in bromic acid (HBrO<sub>3</sub>) and perbromic acid (HBrO<sub>4</sub>) is +12.</p>
<p>In bromic acid, the oxidation state of bromine is +5, while in perbromic acid, it is +7. The sum of the oxidation states of bromine in both compounds is (+5) + (+7) = +12.</p> | integer | jee-main-2023-online-1st-february-morning-shift | 3,350 |
1lh29uyl4 | chemistry | redox-reactions | oxidation-number | <p>In ammonium - phosphomolybdate, the oxidation state of Mo is + ___________</p> | [] | null | 6 | In ammonium phosphomolybdate, the compound typically found in the reagent used for the quantitative determination of phosphorus, the molybdenum (Mo) atom is in the +6 oxidation state.
| integer | jee-main-2023-online-6th-april-morning-shift | 3,353 |
jaoe38c1lsda2rjf | chemistry | redox-reactions | oxidation-number | <p>In the reaction of potassium dichromate, potassium chloride and sulfuric acid (conc.), the oxidation state of the chromium in the product is $$(+)$$ _________.</p> | [] | null | 6 | <p>$$\begin{aligned}
& \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7(\mathrm{~s})+4 \mathrm{KCl}(\mathrm{s})+6 \mathrm{H}_2 \mathrm{SO}_4 \text { (conc.) } \\
& \rightarrow 2 \mathrm{CrO}_2 \mathrm{Cl}_2(\mathrm{~g})+6 \mathrm{KHSO}_4+3 \mathrm{H}_2 \mathrm{O}
\end{aligned}$$</p>
<p>This reaction is called chromyl chloride t... | integer | jee-main-2024-online-31st-january-evening-shift | 3,354 |
jaoe38c1lsfpnil4 | chemistry | redox-reactions | oxidation-number | <p>The oxidation number of iron in the compound formed during brown ring test for NO$$_3^-$$ iron is ________.</p> | [] | null | 1 | <p>$$\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5(\mathrm{NO})\right]^{2+} \text {, }$$</p>
<p>Oxidation no. of $$\mathrm{Fe}=+1$$</p> | integer | jee-main-2024-online-29th-january-evening-shift | 3,355 |
Nc3KC2d3VAtJyLmgZhERW | chemistry | redox-reactions | redox-titration | 50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount of NaOH in 50 mL of the given sodium hydroxide solution is - | [{"identifier": "A", "content": "20 g "}, {"identifier": "B", "content": "4 g"}, {"identifier": "C", "content": "80 g"}, {"identifier": "D", "content": "10 g"}] | ["B"] | null | <p>The reaction between sodium hydroxide (NaOH) and oxalic acid (H<sub>2</sub>C<sub>2</sub>O<sub>4</sub>) is as follows :</p>
<p>$$ \text{H}_2\text{C}_2\text{O}_4 + 2\text{NaOH} \rightarrow \text{Na}_2\text{C}_2\text{O}_4 + 2\text{H}_2\text{O} $$</p>
<p>We can see that 1 mole of oxalic acid ($\text{H}_2\text{C}_2\text{... | mcq | jee-main-2019-online-12th-january-morning-slot | 3,356 |
fJgmdZRvqRLiiFd7mUjgy2xukevksjwi | chemistry | redox-reactions | redox-titration | While titrating dilute HCl solution with aqueous
NaOH, which of the following will not be
required? | [{"identifier": "A", "content": "Pipette and distilled water\n"}, {"identifier": "B", "content": "Clamp and phenolphthalein"}, {"identifier": "C", "content": "Burette and porcelain tile"}, {"identifier": "D", "content": "Bunsen burner and measuring cylinder"}] | ["D"] | null | Bunsen Burner and measuring cylinder is not
required for titration. | mcq | jee-main-2020-online-2nd-september-morning-slot | 3,357 |
jR6G1U3lIXmR5hprc61klsc56n9 | chemistry | redox-reactions | redox-titration | 0.4 g mixture of NaOH, Na<sub>2</sub>CO<sub>3</sub> and some inert impurities was first titrated with $${N \over {10}}$$ HCl using phenolphthalein as an indicator, 17.5 mL of HCl was required at the end point. After this methyl orange was added and titrated. 1.5 mL of same HCl was required for the next end point. The w... | [] | null | 4 | <b>1<sup>st</sup> end point reaction :</b><br><br>$$NaOH + HCl\buildrel {} \over
\longrightarrow NaCl + {H_2}O$$<br><br>$$nf = 1$$<br><br>$$NaC{O_3} + HCl\buildrel {} \over
\longrightarrow NaHC{O_3}$$<br><br>$$nf = 1$$<br><br>Eq of HCl used $$ = {n_{NaOH}} \times 1 + {n_{N{a_2}C{O_3}}} \times 1$$<br><br>$$17.5 \times... | integer | jee-main-2021-online-25th-february-morning-slot | 3,359 |
1ks1jhofn | chemistry | redox-reactions | redox-titration | 10.0 mL of 0.05 M KMnO<sub>4</sub> solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is _________ $$\times$$ 10<sup>$$-$$2</sup> g/L.<br/><br/>(Round off to the nearest integer) | [] | null | 1575 | n<sub>eq</sub> KMnO<sub>4</sub> = n<sub>eq</sub> H<sub>2</sub>C<sub>2</sub>O<sub>4</sub> . 2H<sub>2</sub>O<br><br>or, $${{10 \times 0.05} \over {1000}} \times 5 = {{10 \times M} \over {1000}} \times 2$$<br><br>$$\therefore$$ Conc. of oxalic acid solution = 0.125 M<br><br>= 0.125 $$\times$$ 125 g/L = 15.75 g/L<br><br>= ... | integer | jee-main-2021-online-27th-july-evening-shift | 3,360 |
1l6rl5zgs | chemistry | redox-reactions | redox-titration | <p>A compound 'X' is a weak acid and it exhibits colour change at pH close to the equivalence point during neutralization of NaOH with $$\mathrm{CH}_{3} \mathrm{COOH}$$. Compound 'X' exists in ionized form in basic medium. The compound 'X' is</p> | [{"identifier": "A", "content": "methyl orange"}, {"identifier": "B", "content": "methyl red"}, {"identifier": "C", "content": "phenolphthalein"}, {"identifier": "D", "content": "erichrome Black T"}] | ["C"] | null | Phenolphthalein is weak acid give colour in basic
medium. | mcq | jee-main-2022-online-29th-july-evening-shift | 3,363 |
1lduligif | chemistry | redox-reactions | redox-titration | <p>The density of a monobasic strong acid (Molar mass 24.2 g/mol) is 1.21 kg/L. The volume of its solution required for the complete neutralization of 25 mL of 0.24 M NaOH is __________ $$\times$$ 10$$^{-2}$$ mL (Nearest integer)</p> | [] | null | 12 | $$
\begin{aligned}
& \text { millimole of } \mathrm{NaOH}=0.24 \times 25 \\\\
& \therefore \text { millimole of acid }=0.24 \times 25 \\\\
& \Rightarrow \text { mass of acid }=0.24 \times 25 \times 24.2 \mathrm{mg} \\\\
& \text { for pure acid, } \\\\
& \mathrm{V}=\frac{\mathrm{w}}{\mathrm{d}} ;(\mathrm{d}=1.21 \mathrm... | integer | jee-main-2023-online-25th-january-morning-shift | 3,364 |
1lgvv7bnc | chemistry | redox-reactions | redox-titration | <p>In alkaline medium, the reduction of permanganate anion involves a gain of __________ electrons.</p> | [] | null | 3 | <p>In alkaline medium, the reduction of permanganate anion involves a gain of <strong>3 electrons</strong>.</p>
<p>The balanced chemical equation for the reduction of permanganate anion in alkaline medium is:</p>
$
\begin{equation}
\ce{MnO4^{-}(aq) + 3 e^{-} + 2 H2O(l) -> MnO2(s) + 4 OH^{-}(aq)}
\end{equation}$<p>In th... | integer | jee-main-2023-online-10th-april-evening-shift | 3,365 |
1lgys8ty2 | chemistry | redox-reactions | redox-titration | <p>Given below are two statements:</p>
<p>Statement I : In redox titration, the indicators used are sensitive to change in $$\mathrm{pH}$$ of the solution.</p>
<p>Statement II : In acid-base titration, the indicators used are sensitive to change in oxidation potential.</p>
<p>In the light of the above statements, choos... | [{"identifier": "A", "content": "Both Statement I and Statement II are incorrect"}, {"identifier": "B", "content": "Statement I is correct but Statement II is incorrect"}, {"identifier": "C", "content": "Statement I is incorrect but Statement II is correct"}, {"identifier": "D", "content": "Both Statement I and Stateme... | ["A"] | null | <p>The correct answer is Option A: Both Statement I and Statement II are incorrect.</p>
<p>Explanation : </p>
<p>In redox titrations, the indicators used are sensitive to a change in oxidation potential, not pH. A redox titration (also called an oxidation-reduction titration) can accurately determine the concentration ... | mcq | jee-main-2023-online-8th-april-evening-shift | 3,366 |
lv0vyra5 | chemistry | redox-reactions | redox-titration | <p>Only $$2 \mathrm{~mL}$$ of $$\mathrm{KMnO}_4$$ solution of unknown molarity is required to reach the end point of a titration of $$20 \mathrm{~mL}$$ of oxalic acid $$(2 \mathrm{M})$$ in acidic medium. The molarity of $$\mathrm{KMnO}_4$$ solution should be ________ M.</p> | [] | null | 8 | <p>$$\begin{aligned}
& \mathrm{(M) \times(2) \times(5)=2 \times 20 \times 2} \\
& \mathrm{M=8}
\end{aligned}
$$</p> | integer | jee-main-2024-online-4th-april-morning-shift | 3,367 |
BsaVZ1wbbWcIJLZwfg3rsa0w2w9jx56tijx | chemistry | redox-reactions | types-of-redox-reactions | An example of a disproportionation reaction is : | [{"identifier": "A", "content": "2NaBr + Cl<sub>2</sub> $$ \\to $$ 2NaCl + Br<sub>2</sub>"}, {"identifier": "B", "content": "2KMnO<sub>4</sub> $$ \\to $$ 2KMnO<sub>4</sub> + MnO<sub>2</sub> + O<sub>2</sub>\n(3) (4)\n"}, {"identifier": "C", "content": "2CuBr $$ \\to $$ CuBr<sub>2</sub> + Cu"}, {"identifier": "D", "cont... | ["C"] | null | In disproportionation reaction one element undergoes both oxidation and reduction.
<picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263499/exam_images/tzgva0nvrqfrga5yabmj.webp"><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264671/exam_images/... | mcq | jee-main-2019-online-12th-april-morning-slot | 3,368 |
1l6gqai21 | chemistry | redox-reactions | types-of-redox-reactions | <p>Which of the given reactions is not an example of disproportionation reaction?</p> | [{"identifier": "A", "content": "$$2 \\mathrm{H}_{2} \\mathrm{O}_{2} \\rightarrow 2 \\mathrm{H}_{2} \\mathrm{O}+\\mathrm{O}_{2}$$"}, {"identifier": "B", "content": "$$2 \\mathrm{NO}_{2}+\\mathrm{H}_{2} \\mathrm{O} \\rightarrow \\mathrm{HNO}_{3}+\\mathrm{HNO}_{2}$$"}, {"identifier": "C", "content": "$$\\mathrm{MnO}_{4}^... | ["C"] | null | $$
\begin{aligned}
& 2 \mathrm{H}_2 \overset{-1}{\mathrm{O}_2} \longrightarrow 2 \mathrm{H}_2 \overset{2-}{\mathrm{O}}+\overset{0}{\mathrm{O}_2}: \text { Disproportionation } \\\\
& 2 \overset{+4}{\mathrm{NO}_2}+\mathrm{H}_2 \mathrm{O} \rightarrow \overset{+5}{\mathrm{HNO}_3}+\overset{+3}{\mathrm{HNO}_2} \text { : Disp... | mcq | jee-main-2022-online-26th-july-morning-shift | 3,370 |
1lh27pci2 | chemistry | redox-reactions | types-of-redox-reactions | <p>Which of the following options are correct for the reaction</p>
<p>$$2\left[\mathrm{Au}(\mathrm{CN})_{2}\right]^{-}(\mathrm{aq})+\mathrm{Zn}(\mathrm{s}) \rightarrow 2 \mathrm{Au}(\mathrm{s})+\left[\mathrm{Zn}(\mathrm{CN})_{4}\right]^{2-}(\mathrm{aq})$$</p>
<p>A. Redox reaction</p>
<p>B. Displacement reaction</p>
<p>... | [{"identifier": "A", "content": "A and B only"}, {"identifier": "B", "content": "C and D only"}, {"identifier": "C", "content": "A only"}, {"identifier": "D", "content": "A and D only"}] | ["A"] | null | $2\left[\stackrel{+1}{\mathrm{Au}}(\mathrm{CN})_2\right]^{-}+\stackrel{0}{\mathrm{Z}} \mathrm{n}(\mathrm{s}) \longrightarrow 2 \stackrel{0}{\mathrm{Au}}+\left[\stackrel{+2}{\mathrm{Zn}}(\mathrm{CN})_4\right]^{-2}$<br/><br/>$\mathrm{Zn}$ displaced $\mathrm{Au}^{+}$<br/><br/>
Reduction and Oxidation both are taking place... | mcq | jee-main-2023-online-6th-april-morning-shift | 3,371 |
lsblv392 | chemistry | redox-reactions | types-of-redox-reactions | Which of the following reactions are disproportionation reactions?<br/><br/>
(A) $\mathrm{Cu}^{+} \rightarrow \mathrm{Cu}^{2+}+\mathrm{Cu}$<br/><br/>
(B) $3 \mathrm{MnO}_4^{2-}+4 \mathrm{H}^{+} \longrightarrow 2 <br/><br/>\mathrm{MnO}_4^{-}+\mathrm{MnO}_2+2 \mathrm{H}_2 \mathrm{O}$<br/><br/>
(C) $2 \mathrm{KMnO}_4 \lon... | [{"identifier": "A", "content": "(A), (B)"}, {"identifier": "B", "content": "(A), (D)"}, {"identifier": "C", "content": "(B), (C), (D)"}, {"identifier": "D", "content": "(A), (B), (C)"}] | ["A"] | null | <p>A disproportionation reaction is a chemical reaction in which a single substance is simultaneously reduced and oxidized, forming two different products. To identify disproportionation reactions, one should look for a specified element in the reactant that gains electrons (reduction) and for the same element that los... | mcq | jee-main-2024-online-1st-february-morning-shift | 3,372 |
1lsg8687o | chemistry | redox-reactions | types-of-redox-reactions | <p>Total number of species from the following which can undergo disproportionation reaction is ________.</p>
<p>$$\mathrm{H}_2 \mathrm{O}_2, \mathrm{ClO}_3^{-}, \mathrm{P}_4, \mathrm{Cl}_2, \mathrm{Ag}, \mathrm{Cu}^{+1}, \mathrm{~F}_2, \mathrm{NO}_2, \mathrm{K}^{+}$$</p> | [] | null | 6 | <p>Intermediate oxidation state of element can undergo disproportionation.</p>
<p>$$\mathrm{H}_2 \mathrm{O}_2, \mathrm{ClO}_3^{-}, \mathrm{P}_4, \mathrm{Cl}_2, \mathrm{Cu}^{+1}, \mathrm{NO}_2$$</p> | integer | jee-main-2024-online-30th-january-evening-shift | 3,373 |
lvb29nmy | chemistry | redox-reactions | types-of-redox-reactions | <p>Match List I with List II.</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;b... | [{"identifier": "A", "content": "(A)-(IV), (B)-(I), (C)-(II), (D)-(III)\n"}, {"identifier": "B", "content": "(A)-(I), (B)-(II), (C)-(III), (D)-(IV)\n"}, {"identifier": "C", "content": "(A)-(II), (B)-(III), (C)-(IV), (D)-(I)\n"}, {"identifier": "D", "content": "(A)-(III), (B)-(II), (C)-(I), (D)-(IV)"}] | ["A"] | null | <p>(A) $$\stackrel{\circ}{\mathrm{N}}_2+\stackrel{\circ}{\mathrm{O}}_2 \longrightarrow 2 \mathrm{NO}_{(\mathrm{g})}$$</p>
<p>Combination reaction</p>
<p>(B) $$2 \mathrm{~Pb}\left(\mathrm{NO}_3\right)_{2(\mathrm{~s})} \longrightarrow 2 \mathrm{PbO}+4 \mathrm{NO}_2+\mathrm{O}_2$$</p>
<p>Decomposition reaction</p>
<p>(C) ... | mcq | jee-main-2024-online-6th-april-evening-shift | 3,374 |
nZxFpwa9Fg4z9Ugm | chemistry | s-block-elements | compounds-of-alkali-metals | KO<sub>2</sub> (potassium super oxide) is used in oxygen cylinders in space and submarines because it : | [{"identifier": "A", "content": "absorbs CO<sub>2</sub> and increases O<sub>2</sub> content"}, {"identifier": "B", "content": "eliminates moisture"}, {"identifier": "C", "content": "absorbs CO<sub>2</sub>"}, {"identifier": "D", "content": "produces ozone"}] | ["A"] | null | $$2K{O_2} + 2{H_2}O$$
<br><br>$$ \to 2KOH + {H_2}{O_2} + {O_2}$$
<br><br>$$K{O_2}$$ is used as an oxidising agent. It is used as air purifier in space capsules. Submarines and breathing masks as it <b>produces oxygen and removes carbon dioxide.</b> | mcq | aieee-2002 | 3,375 |
Qx01cNZKLz1oysG1 | chemistry | s-block-elements | compounds-of-alkali-metals | Which of the following on thermal decomposition yields a basic as well as an acidic oxide? | [{"identifier": "A", "content": "NaNO<sub>3</sub>"}, {"identifier": "B", "content": "KClO<sub>3</sub>"}, {"identifier": "C", "content": "CaCO<sub>3</sub>"}, {"identifier": "D", "content": "NH<sub>4</sub>NO<sub>3</sub>"}] | ["C"] | null | Calcium carbonate on thermal decomposition gives $$CaO$$ (Basic oxide) and $$C{O_2}$$ (Acidic oxide)
<br><br>$$CaC{O_3}\buildrel \Delta \over
\longrightarrow \mathop {\,\,\,\,\,CaO\,\,\,\,\,}\limits_{Basic\,\,oxide} + \,\,\mathop {\,\,\,\,C{O_2} \uparrow }\limits_{Acidic\,\,oxide} $$ | mcq | aieee-2012 | 3,376 |
RLhIav4b1VFGw9o607ijK | chemistry | s-block-elements | compounds-of-alkali-metals | A metal on combustion in excess air forms X. X upon hydrolysis with water yields H<sub>2</sub>O<sub>2</sub> and O<sub>2</sub> along with another product. The metal is : | [{"identifier": "A", "content": "Rb"}, {"identifier": "B", "content": "Mg"}, {"identifier": "C", "content": "Na"}, {"identifier": "D", "content": "Li"}] | ["A"] | null | K, Rb and Cs form super oxides on reaction with excess
air.
<br><br>Rb + O<sub>2</sub> $$ \to $$ RbO<sub>2</sub>
<br><br>2RbO<sub>2</sub>
+ 2H<sub>2</sub>O $$ \to $$ 2RbOH + H<sub>2</sub>O<sub>2</sub>
+ O<sub>2</sub>$$ \uparrow $$ | mcq | jee-main-2019-online-12th-january-morning-slot | 3,377 |
lGXfO6lCgykyXQyZzz3rsa0w2w9jx0w6xqr | chemistry | s-block-elements | compounds-of-alkali-metals | A hydrated solid X on heating initially gives a monohydrated compound Y. Y upon heating above 373 K leads
to an anhydrous white powder Z. X and Z, respectively, are : | [{"identifier": "A", "content": "Baking soda and dead burnt plaster.\n"}, {"identifier": "B", "content": "Washing soda and soda ash"}, {"identifier": "C", "content": "Washing soda and dead burnt plaster."}, {"identifier": "D", "content": "Baking soda and soda as. "}] | ["B"] | null | <picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265619/exam_images/yfm0cybutkxeeu1xoxsp.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266416/exam_images/gkkkwg2olxhnuulsazmq.webp"><img src="https://res.c... | mcq | jee-main-2019-online-10th-april-evening-slot | 3,378 |
1krq5w35n | chemistry | s-block-elements | compounds-of-alkali-metals | A s-block element (M) reacts with oxygen to form an oxide of the formula MO<sub>2</sub>. The oxide is pale yellow in colour and paramagnetic. The element (M) is : | [{"identifier": "A", "content": "Mg"}, {"identifier": "B", "content": "Na"}, {"identifier": "C", "content": "Ca"}, {"identifier": "D", "content": "K"}] | ["D"] | null | <p>The element (M) is potassium (K). It reacts with O<sub>2</sub> to form KO<sub>2</sub>, which is paramagnetic in nature. All other elements form oxides or peroxides which are diamagnetic in nature.</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l2pnip0g/cb7cf53d-8cbe-4afc-adbd-24047297f128/9e... | mcq | jee-main-2021-online-20th-july-morning-shift | 3,380 |
1krx511ei | chemistry | s-block-elements | compounds-of-alkali-metals | Match List I with List II :<br/><br/><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;b... | [{"identifier": "A", "content": "(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)"}, {"identifier": "B", "content": "(a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)"}, {"identifier": "C", "content": "(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)"}, {"identifier": "D", "content": "(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)"}] | ["A"] | null | (a) CsI salt is poor water soluble due to it's low hydration energy<br><br>(b) NaHCO<sub>3</sub> is used in fire extinguisher<br><br>(c) K is most abundant element in cell fluid<br><br>(d) Li<sub>2</sub>CO<sub>3</sub> decomposes easily due to high covalent character caused by small size Li<sup>+</sup> cation. | mcq | jee-main-2021-online-25th-july-evening-shift | 3,381 |
1ks1gxe6d | chemistry | s-block-elements | compounds-of-alkali-metals | Match List - I with List - II :<br/><br/><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:sol... | [{"identifier": "A", "content": "(a) - (v), (b) - (i), (c) - (ii), (d) - (iv)"}, {"identifier": "B", "content": "(a) - (v), (b) - (ii), (c) - (iv), (d) - (i)"}, {"identifier": "C", "content": "(a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)"}, {"identifier": "D", "content": "(a) - (v), (b) - (iii), (c) - (ii), (d) - (i)... | ["D"] | null | Li makes alloy with Lead to make white metal bearings for motor engines<br><br>Liquid Na metal is used s coolant in fast breeder nuclear reactor<br><br>K is a very absorbent of CO<sub>2</sub><br><br>Cs is used in making photoelectric cell | mcq | jee-main-2021-online-27th-july-evening-shift | 3,382 |
1ktfrglym | chemistry | s-block-elements | compounds-of-alkali-metals | Choose the correct statement from the following : | [{"identifier": "A", "content": "The standard enthalpy of formation for alkali metal bromides becomes less negative on descending the group."}, {"identifier": "B", "content": "The low solubility of CsI in water is due to its high lattice enthalpy."}, {"identifier": "C", "content": "Among the alkali metal halides, LiF i... | ["C"] | null | a. Standard enthalpy of formation for alkali metal bromides becomes more negative on descending down the group.<br><br>b. In case of CsI, lattice energy is less, but Cs<sup>+</sup> is having less hydration enthalpy due to which it is less soluble in water.<br><br>c. For alkali metal fluorides, the solubility in water i... | mcq | jee-main-2021-online-27th-august-evening-shift | 3,383 |
1l54ygmwk | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Amongst baking soda, caustic soda and washing soda, carbonate anion is present in :</p> | [{"identifier": "A", "content": "washing soda only."}, {"identifier": "B", "content": "washing soda and caustic soda only."}, {"identifier": "C", "content": "washing soda and baking soda only."}, {"identifier": "D", "content": "baking soda, caustic soda and washing soda. "}] | ["A"] | null | <p>Baking soda $$ \to $$ NaHCO<sub>3</sub></p>
<p>Washing soda $$ \to $$ Na<sub>2</sub>CO<sub>3</sub>.10H<sub>2</sub>O</p>
<p>Caustic soda $$ \to $$ NaOH </p>
<p>$$\text{CO}^{-2}_{3} $$ ion is present only in washing soda.</p> | mcq | jee-main-2022-online-29th-june-evening-shift | 3,384 |
1l5bd8vjo | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Which one of the following compounds is used as a chemical in certain type of fire extinguishers?</p> | [{"identifier": "A", "content": "Baking soda"}, {"identifier": "B", "content": "Soda ash"}, {"identifier": "C", "content": "Washing soda"}, {"identifier": "D", "content": "Caustic soda"}] | ["A"] | null | Baking soda $$\left(\mathrm{NaHCO}_{3}\right)$$ is used in certain type of fire extinguishers because it decomposes at high temperature to produce $$\mathrm{CO}_{2}$$ which extinguishes fire<br/><br/>
$$
2 \mathrm{NaHCO}_{3}(\mathrm{~s}) \stackrel{\Delta}{\longrightarrow} \mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{~s})+\m... | mcq | jee-main-2022-online-24th-june-evening-shift | 3,385 |
1l5w5wxgq | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Correct statement about alkali metal oxides is :</p> | [{"identifier": "A", "content": "peroxides are colored."}, {"identifier": "B", "content": "superoxides are paramagnetic."}, {"identifier": "C", "content": "oxides are paramagnetic."}, {"identifier": "D", "content": "peroxides are both colored and paramagnetic."}] | ["B"] | null | The peroxide and oxides of alkali metals are colourless when pure.
<br/><br/>
Superoxides are paramagnetic while peroxides are diamagnetic. Electronic configuration of $\mathrm{O}_{2}^{2-}$ (peroxide)
<br/><br/>
$\left(\sigma 1 s^{2}\right)\left(\sigma^{*} 1 s^{2}\right)\left(\sigma 2 s^{2}\right)\left(\sigma^{*} 2 s^{... | mcq | jee-main-2022-online-30th-june-morning-shift | 3,386 |
1l6i51di1 | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.</p>
<p>Assertion A: $$\mathrm{LiF}$$ is sparingly soluble in water.</p>
<p>Reason R: The ionic radius of $$\mathrm{Li}^{+}$$ ion is smallest among its group members, hence has least hydration enthalpy.</p>
<p>In the... | [{"identifier": "A", "content": "Both A and R are true and R is the correct explanation of A."}, {"identifier": "B", "content": "Both A and R are true but R is NOT the correct explanation of A."}, {"identifier": "C", "content": "A is true but R is false."}, {"identifier": "D", "content": "A is false but R is true."}] | ["C"] | null | LiF is sparingly soluble in water.
<br/><br/>
The low solubility of LiF in water is due to its high lattice enthalpy (Since $$\mathrm{Li}^{+}$$ and $$\mathrm{F}^{-}$$ are small in size). Also, due to small size of $$\mathrm{Li}^{+}$$, its hydration enthalpy is high.
<br/><br/>
Hence, Assertion is true but Reason is fal... | mcq | jee-main-2022-online-26th-july-evening-shift | 3,387 |
1ldoi309o | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Match List I with List II :</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;... | [{"identifier": "A", "content": "(A) - III, (B) - IV, (C) - II, (D) - I"}, {"identifier": "B", "content": "(A) - III, (B) - II, (C) - IV, (D) - I"}, {"identifier": "C", "content": "(A) - II, (B) - IV, (C) - I, (D) - III"}, {"identifier": "D", "content": "(A) - I, (B) - IV, (C) - II, (D) - III"}] | ["C"] | null | A : Slaked lime $\quad: \mathrm{Ca}(\mathrm{OH})_{2}$
<br/><br/>B : Dead burnt plaster $\quad$: $\mathrm{CaSO}_{4}$
<br/><br/>C : Caustic Soda $\quad$: $\mathrm{NaOH}$
<br/><br/>D : Washing Soda $\quad$: $\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10 \mathrm{H}_{2} \mathrm{O}$ | mcq | jee-main-2023-online-1st-february-morning-shift | 3,389 |
ldqwpq9c | chemistry | s-block-elements | compounds-of-alkali-metals | Which of the following reaction is correct? | [{"identifier": "A", "content": "$4 \\mathrm{LiNO}_{3} \\stackrel{\\Delta}{\\longrightarrow} 2 \\mathrm{Li}_{2} \\mathrm{O}+4 \\mathrm{NO}_{2}+\\mathrm{O}_{2}$"}, {"identifier": "B", "content": "$2 \\mathrm{LiNO}_{3} \\longrightarrow 2 \\mathrm{Li}+2 \\mathrm{NO}_{2}+\\mathrm{O}_{2}$"}, {"identifier": "C", "content": "... | ["A"] | null | <p>$$\mathrm{4LiNO_3}$$ $$\buildrel {\mathrm{Heat}} \over
\longrightarrow $$ $$\mathrm{2Li_2O+4NO_2+O_2}$$</p>
<p>$$\mathrm{LiNO_3}$$ on heating produces $$\mathrm{Li_2O,NO_2}$$ and $$\mathrm{O_2}$$</p> | mcq | jee-main-2023-online-30th-january-evening-shift | 3,390 |
1ldr4kfao | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Lithium aluminium hydride can be prepared from the reaction of :</p> | [{"identifier": "A", "content": "$$\\mathrm{LiCl}$$ and $$\\mathrm{Al_2H_6}$$"}, {"identifier": "B", "content": "$$\\mathrm{LiH}$$ and $$\\mathrm{Al}(\\mathrm{OH})_{3}$$"}, {"identifier": "C", "content": "$$\\mathrm{LiH}$$ and $$\\mathrm{Al}_{2} \\mathrm{Cl}_{6}$$"}, {"identifier": "D", "content": "$$\\mathrm{LiCl}, \\... | ["C"] | null | $$\mathrm{8LiH+Al_2Cl_6\to2LiAlH_4+6LiCl}$$ | mcq | jee-main-2023-online-30th-january-morning-shift | 3,391 |
1ldsdx85d | chemistry | s-block-elements | compounds-of-alkali-metals | <p>On heating, $$\mathrm{LiNO_3}$$ gives how many compounds among the following __________</p>
<p>$$\mathrm{Li_2O,N_2,O_2,LiNO_2,NO_2}$$</p> | [] | null | 3 | <p>$$\mathrm{LiNO_3\buildrel \Delta \over
\longrightarrow Li_2O+NO_2+O_2}$$</p> | integer | jee-main-2023-online-29th-january-evening-shift | 3,392 |
1lgp305w1 | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Identify the correct order of standard enthalpy of formation of sodium halides :</p> | [{"identifier": "A", "content": "$$\\mathrm{NaI}<\\mathrm{NaBr}<\\mathrm{NaCl}<\\mathrm{NaF}$$"}, {"identifier": "B", "content": "$$\\mathrm{NaI}<\\mathrm{NaBr}<\\mathrm{NaF}<\\mathrm{NaCl}$$"}, {"identifier": "C", "content": "$$\\mathrm{NaF}<\\mathrm{NaCl}<\\mathrm{NaBr}<\\mathrm{NaI}$$"}, {"identifier": "D", "content... | ["A"] | null | Lattice energy is directly proportional to the charges of the ions and inversely proportional to the sum of their radii:
<br/><br/>
Lattice energy ∝ (Q₁Q₂) / (r₁ + r₂)
<br/><br/>
As we move down the group, the size of the halide ions increases, resulting in a decrease in lattice energy. This leads to a decrease in the ... | mcq | jee-main-2023-online-13th-april-evening-shift | 3,393 |
1lguzqkuf | chemistry | s-block-elements | compounds-of-alkali-metals | <p>Match List-I with List-II:</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;b... | [{"identifier": "A", "content": "A-IV, B-III, C-I, D-II"}, {"identifier": "B", "content": "A-III, B-II, C-IV, D-I"}, {"identifier": "C", "content": "A-III, B-IV, C-II, D-I"}, {"identifier": "D", "content": "A-IV, B-I, C-III, D-II"}] | ["B"] | null | <p>Let's consider each item in List-I and match it with an appropriate item from List-II:</p>
<p>A. K (Potassium): Potassium ions are crucial for the operation of the sodium-potassium pump in nerve cells. So, A matches with III.</p>
<p>B. KCl (Potassium Chloride): Potassium chloride is widely used in agriculture as... | mcq | jee-main-2023-online-11th-april-morning-shift | 3,394 |
1lh321pgm | chemistry | s-block-elements | compounds-of-alkali-metals | <p>The product, which is not obtained during the electrolysis of brine solution is :</p> | [{"identifier": "A", "content": "NaOH"}, {"identifier": "B", "content": "Cl$$_2$$"}, {"identifier": "C", "content": "H$$_2$$"}, {"identifier": "D", "content": "HCl"}] | ["D"] | null | <p>The electrolysis of brine, which is a solution of sodium chloride (NaCl) in water, involves the migration of ions towards electrodes. When an electric current is passed through the solution, positive sodium ions ($Na^+$) move towards the cathode (negative electrode), and negative chloride ions ($Cl^-$) move towards ... | mcq | jee-main-2023-online-6th-april-evening-shift | 3,396 |
xmLplKAoWrSvtU2v | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The metallic sodium disolves in liquid ammonia to form a deep blue coloured solution. The deep blue colour is due to formation of : | [{"identifier": "A", "content": "solvated electron, $$e(NH_3)^-_x$$"}, {"identifier": "B", "content": "solvated atomic sodium, Na(NH<sub>3</sub>)<sub>y</sub>"}, {"identifier": "C", "content": "(Na<sup>+</sup> + Na<sup>-</sup>)"}, {"identifier": "D", "content": "NaNH<sub>2</sub> + H<sub>2</sub>"}] | ["A"] | null | The alkali metals dissolve in liquid ammonia without evolution of hydrogen. The metal loses electrons and combine with ammonia molecule.
<br><br>$$M \to {M^ + }\,\,$$ (in liquid ammonia) $$\,\, + {E^ - }\,\,$$ (ammoniated)
<br><br>$$\,\,M + (x + y)N{H_3}$$
<br><br>$$ \to {\left[ {M{{(N{H_3})}_x}} \right]^ + }\matho... | mcq | aieee-2002 | 3,398 |
8uVfBltXqgGofLA4 | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | Based on lattice energy and other considerations which one of the following alkali
metal chlorides is expected to have the highest melting point : | [{"identifier": "A", "content": "LiCl"}, {"identifier": "B", "content": "NaCl "}, {"identifier": "C", "content": "KCl"}, {"identifier": "D", "content": "RbCl"}] | ["B"] | null | $$LiCl$$ has partly covalent character. Other halides are ionic in nature. Lattice energy decreases with increases of ionic radius of cation, anion being the same. Larger is the lattice energy, the higher will be $$m.$$ $$pt.$$ hence $$NaCl$$ will have highest lattice energy. | mcq | aieee-2005 | 3,399 |
1nwds6DFEkalJLKm | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | Which of the following atoms has the highest first ionization energy? | [{"identifier": "A", "content": "Na "}, {"identifier": "B", "content": "K"}, {"identifier": "C", "content": "Sc"}, {"identifier": "D", "content": "Rb"}] | ["C"] | null | <p>The first ionization energy is the energy required to remove the most loosely held electron from an atom or a cation. It is measured in units of electron volts (eV) or kilojoules per mole (kJ/mol).</p>
<p>Among the given options, Scandium (Sc) has the highest first ionization energy because it has the smallest atom... | mcq | jee-main-2016-offline | 3,401 |
nMDPHAX75JenhSDN | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The main oxides formed on combustion of Li, Na and K in excess of air are, respectively : | [{"identifier": "A", "content": "LiO<sub>2</sub>, Na<sub>2</sub>O<sub>2</sub> and K<sub>2</sub>O"}, {"identifier": "B", "content": "Li<sub>2</sub>O<sub>2</sub>, Na<sub>2</sub>O<sub>2</sub> and KO<sub>2</sub>"}, {"identifier": "C", "content": "Li<sub>2</sub>O, Na<sub>2</sub>O<sub>2</sub> and KO<sub>2</sub>"}, {"identifi... | ["C"] | null | On heating with excess of air $$Li,$$ $$Na$$ and $$K$$ forms following oxides
<br><br>$$4Li + {O_2}\,\,\buildrel \, \over
\longrightarrow \,\,\mathop {2L{i_2}O\,\,\,\,\,\,\,\,\,\,}\limits_{Lithium\,\,\,\,monoxide} \,$$
<br><br>$$2Na + {O_2}\,\,\buildrel {575\,\,K} \over
\longrightarrow \,\,\mathop {N{a_2}{O_2}\,\,\... | mcq | jee-main-2016-offline | 3,402 |
TgDdM2mmeRLD5wAgr65Ee | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The metal that forms nitride by reacting directly with N<sub>2</sub> of air, is : | [{"identifier": "A", "content": "K"}, {"identifier": "B", "content": "Li"}, {"identifier": "C", "content": "Rb"}, {"identifier": "D", "content": "Cs"}] | ["B"] | null | Only Li react directly with N<sub>2</sub> out of alkali metals
<br><br>6 Li + N<sub>2</sub> $$ \to $$ 2Li<sub>3</sub>N | mcq | jee-main-2019-online-9th-january-evening-slot | 3,404 |
3fIvRcFOUr7RdzK3xtdhl | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | Sodium metal on dissolution in liquid ammonia gives a deep blue solution due to the formation of : | [{"identifier": "A", "content": "ammoniated electrons "}, {"identifier": "B", "content": "sodamide \n"}, {"identifier": "C", "content": "sodium-ammonia complex "}, {"identifier": "D", "content": "sodium ion-ammonia complex "}] | ["A"] | null | Na + (x + y)NH<sub>3</sub>($$l$$) $$ \to $$ [Na(NH<sub>3</sub>)<sub>x</sub>]<sup>+</sup> + [e(NH<sub>3</sub>)<sub>y</sub>]<sup>-</sup>
<br><br>[e(NH<sub>3</sub>)<sub>y</sub>]<sup>-</sup> is called solvated or ammoniated electron. | mcq | jee-main-2019-online-10th-january-evening-slot | 3,405 |
8pFtw7Curi3b8lhQbQxiK | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The correct order of hydration enthapies of alkali metal ions is : | [{"identifier": "A", "content": "Li<sup>+</sup> > Na<sup>+</sup> > Cs<sup>+</sup> > Rb<sup>+</sup>"}, {"identifier": "B", "content": "Na<sup>+</sup> > Li<sup>+</sup> > K<sup>+</sup> > Cs<sup>+</sup> > Rb<sup>+</sup>"}, {"identifier": "C", "content": "Na<sup>+</sup> > Li<sup>+</sup> > K<sup>+<... | ["D"] | null | Hydration energy/enthalpy $$ \propto $$ $${{ch\arg e} \over {size}}$$
<br><br>$$ \therefore $$ Smaller the size more is hydration energy.
<br><br>Li<sup>+</sup> having minimum radius so maximum hydration energy.
<br><br>Correct order is :
<br><br>Li<sup>+</sup> > Na<sup>+</sup> > K<sup>+</sup> > Rb<sup>+</sup>... | mcq | jee-main-2019-online-8th-april-morning-slot | 3,406 |
Md7RnupcKQ9LHk4fmu3rsa0w2w9jx84cpe7 | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The INCORRECT statement is : | [{"identifier": "A", "content": "Lithium is least reactive with water among the alkali metals"}, {"identifier": "B", "content": "LiCl crystallises from aqueous solution as LiCl.2H<sub>2</sub>O"}, {"identifier": "C", "content": "Lithium is the strongest reducing agent among the alkali metals"}, {"identifier": "D", "cont... | ["D"] | null | LiNO<sub>3</sub> $$\buildrel \Delta \over
\longrightarrow $$ Li<sub>2</sub>O + NO<sub>2</sub> + O<sub>2</sub>
<br><br>Ionic potential of Li is high that is why on thermal demoposition of nitrate form of Li will give oxide of Li and NO<sub>2</sub> and O<sub>2</sub>. | mcq | jee-main-2019-online-12th-april-evening-slot | 3,407 |
S59yV4Qjk0ZGs6Qcydjgy2xukevm4nda | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The metal mainly used in devising
photoelectric cells is : | [{"identifier": "A", "content": "Na"}, {"identifier": "B", "content": "Rb"}, {"identifier": "C", "content": "Li"}, {"identifier": "D", "content": "Cs"}] | ["D"] | null | Cs has least work function value because of
less electronegativity thats why it is used in
photoelectric cells. | mcq | jee-main-2020-online-2nd-september-morning-slot | 3,409 |
kG3tUlNLd1J8H7qs8S1kmj7fogs | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The correct order of conductivity of ions in water is : | [{"identifier": "A", "content": "K<sup>+</sup> > Na<sup>+</sup> > Cs<sup>+</sup> > Rb<sup>+</sup>"}, {"identifier": "B", "content": "Cs<sup>+</sup> > Rb<sup>+</sup> > K<sup>+</sup> > Na<sup>+</sup>"}, {"identifier": "C", "content": "Na<sup>+</sup> > K<sup>+</sup> > Rb<sup>+</sup> > Cs<sup>+</... | ["B"] | null | As the size of gaseous ion decreases, it get
more hydrated in water and hence, the size of
aqueous ion increases. When this bulky ion
move in solution, it experience greater
resistance and hence lower conductivity. | mcq | jee-main-2021-online-17th-march-morning-shift | 3,412 |
1krz1p5wh | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | Given below are two statements : One is labelled as Assertion A and the other labelled as Reason R.<br/><br/>Assertion A : Lithium halides are some what covalent in nature.<br/><br/>Reason R : Lithium posses high polarisation capability.<br/><br/>In the light of the above statements, choose the most appropriate answer ... | [{"identifier": "A", "content": "A is true but R is false"}, {"identifier": "B", "content": "A is false but R is true"}, {"identifier": "C", "content": "Both A and R are true but R is NOT the correct explanation of A"}, {"identifier": "D", "content": "Both A and R are true and R is the correct explanation of A"}] | ["D"] | null | Lithium due to small size has very high polarization capability and thus increases covalent nature of Halides. | mcq | jee-main-2021-online-27th-july-morning-shift | 3,413 |
1ktjvo52s | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). <br/><br/>Assertion (A) : Lithium salts are hydrated.<br/><br/>Reason (R) : Lithium has higher polarising power than other alkali metal group members.<br/><br/>In the light of the above statements, choose the most... | [{"identifier": "A", "content": "Both (A) and (R) are correct but (R) is not the correct explanation of (A)"}, {"identifier": "B", "content": "(A) is correct but (R) is not correct."}, {"identifier": "C", "content": "(A) is not correct but (R) is correct."}, {"identifier": "D", "content": "Both (A) and (R) are correct ... | ["A"] | null | Lithium salts are hydrated due to high hydration energy of Li<sup>+</sup><br><br>Li<sup>+</sup> due to smallest size in IA group has highest polarizing power. | mcq | jee-main-2021-online-31st-august-evening-shift | 3,414 |
1l548jryc | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Arrange the following in the decreasing order of their covalent character :</p>
<p>(A) LiCl</p>
<p>(B) NaCl</p>
<p>(C) KCl</p>
<p>(D) CsCl</p>
<p>Choose the most appropriate answer from the options given below :</p> | [{"identifier": "A", "content": "(A) > (C) > (B) > (D)"}, {"identifier": "B", "content": "(B) > (A) > (C) > (D)"}, {"identifier": "C", "content": "(A) > (B) > (C) > (D)"}, {"identifier": "D", "content": "(A) > (B) > (D) > (C)"}] | ["C"] | null | Covalent character $$ \propto $$ polarising power of cation<br/><br/>
Correct decreasing order of covalent character<br/><br/>
LiCl > NaCl > KCl > CsCl | mcq | jee-main-2022-online-29th-june-morning-shift | 3,415 |
1l549ceo4 | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Match List-I with List-II</p>
<p><style type="text/css">
.tg {border-collapse:collapse;border-spacing:0;}
.tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px;
overflow:hidden;padding:10px 5px;word-break:normal;}
.tg th{border-color:black;border-style:solid;bo... | [{"identifier": "A", "content": "(A)-(I), (B)-(II), (C)-(III), (D)-(IV)"}, {"identifier": "B", "content": "(A)-(III), (B)-(II), (C)-(I), (D)-(IV)"}, {"identifier": "C", "content": "(A)-(III), (B)-(I), (C)-(II), (D)-(IV)"}, {"identifier": "D", "content": "(A)-(IV), (B)-(II), (C)-(I), (D)-(III)"}] | ["A"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5itvxgl/85123a1a-1c60-4f89-ae17-a908bdc5c880/af37e550-023d-11ed-82d2-afb4f8196e66/file-1l5itvxgm.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5itvxgl/85123a1a-1c60-4f89-ae17-a908bdc5c880/af37e550-023d-11ed-82d2-afb4f8196e66/fi... | mcq | jee-main-2022-online-29th-june-morning-shift | 3,416 |
1l5bd7ybh | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>In the industrial production of which of the following, molecular hydrogen is obtained as a byproduct?</p> | [{"identifier": "A", "content": "NaOH"}, {"identifier": "B", "content": "NaCl"}, {"identifier": "C", "content": "Na metal"}, {"identifier": "D", "content": "Na<sub>2</sub>CO<sub>3</sub>"}] | ["A"] | null | Molecular hydrogen is produced as a byproduct in the industrial production of $$\mathrm{NaOH}$$ by electrolysis of aq $$\mathrm{NaCl}$$ solution<br/><br/>
$$
\mathrm{NaCl} \rightarrow \mathrm{Na}^{+}+\mathrm{Cl}^{-}
$$<br/><br/>
$$
\begin{aligned}
& \mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{H^{+}}+\mathrm{OH... | mcq | jee-main-2022-online-24th-june-evening-shift | 3,417 |
1l5c6ksxr | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Which of the following statements are correct?</p>
<p>(A) Both LiCl and MgCl<sub>2</sub> are soluble in ethanol.</p>
<p>(B) The oxides Li<sub>2</sub>O and MgO combine with excess of oxygen to give superoxide.</p>
<p>(C) LiF is less soluble in water than other alkali metal fluorides.</p>
<p>(D) Li<sub>2</sub>O is mor... | [{"identifier": "A", "content": "(A) and (C) only"}, {"identifier": "B", "content": "(A), (C) and (D) only"}, {"identifier": "C", "content": "(B) and (C) only"}, {"identifier": "D", "content": "(A) and (D) only"}] | ["A"] | null | (A) Both LiCl and MgCl<sub>2</sub> are soluble in ethanol<br/><br/>
(B) Li and Mg do not form superoxide<br/><br/>
(C) LiF has high lattice energy<br/><br/>
(D) Li<sub>2</sub>O is least soluble in water than another alkali metal oxides | mcq | jee-main-2022-online-24th-june-morning-shift | 3,418 |
1l6e18lqx | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Choose the correct order of density of the alkali metals :</p> | [{"identifier": "A", "content": "Li < K < Na < Rb < Cs"}, {"identifier": "B", "content": "Li < Na < K < Rb < Cs"}, {"identifier": "C", "content": "Cs < Rb < K < Na < Li"}, {"identifier": "D", "content": "Li < Na < K < Cs < Rb"}] | ["A"] | null | The increasing order of density of alkali metals as
<br/><br/>
$$
\underset{0.53}{\mathrm{Li}}<\underset{0.86}{\mathrm{~K}}<\underset{0.97}{\mathrm{Na}}<\underset{1.53}{\mathrm{Rb}}<\underset{1.87}{\mathrm{Cs}} \quad\text { (in } \mathrm{g}{/ \mathrm{dm}^{3} \text { ) }}
$$
<br/><br/>
' $\mathrm{K}$ ' metal has less de... | mcq | jee-main-2022-online-25th-july-morning-shift | 3,419 |
1l6mcnw4r | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Which of the following statement is <b>incorrect</b>?</p> | [{"identifier": "A", "content": "Low solubility of LiF in water is due to its small hydration enthalpy."}, {"identifier": "B", "content": "$$\\mathrm{KO}_{2}$$ is paramagnetic."}, {"identifier": "C", "content": "Solution of sodium in liquid ammonia is conducting in nature."}, {"identifier": "D", "content": "Sodium meta... | ["A"] | null | Low solubility of LiF in water is due to the fact that though $\mathrm{Li}^{+}$ is having high hydration enthalpy but it has higher lattice enthalpy when present in LiF. Due to higher lattice enthalpy its solubility is less. | mcq | jee-main-2022-online-28th-july-morning-shift | 3,420 |
ldo9ucsk | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | The number of alkali metal(s), from $\mathrm{Li}, \mathrm{K}, \mathrm{Cs}$, Rb having ionization enthalpy greater than $400 \mathrm{~kJ}$ $\mathrm{mol}^{-1}$ and forming stable super oxide is _____________. | [] | null | 2 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lecssgjd/16d9b562-4c48-4482-adcb-e3b645d7f48b/a41a5a90-b11a-11ed-8d19-c1418e0c6b67/file-1lecssgje.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lecssgjd/16d9b562-4c48-4482-adcb-e3b645d7f48b/a41a5a90-b11a-11ed-8d19-c1418e0c6b67/fi... | integer | jee-main-2023-online-31st-january-evening-shift | 3,421 |
1ldu04kqa | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Which one among the following metals is the weakest reducing agent?</p> | [{"identifier": "A", "content": "K"}, {"identifier": "B", "content": "Na"}, {"identifier": "C", "content": "Li"}, {"identifier": "D", "content": "Rb"}] | ["B"] | null | Sodium has the lowest oxidation potential in alkali metals. Hence it is the weakest reducing agent among alkali metals. | mcq | jee-main-2023-online-25th-january-evening-shift | 3,422 |
1ldu1d2x5 | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R</p>
<p>Assertion A : The alkali metals and their salts impart characteristic colour to reducing flame.</p>
<p>Reason R : Alkali metals can be detected using flame tests.</p>
<p>In the light of the above statements, c... | [{"identifier": "A", "content": "A is not correct but R is correct"}, {"identifier": "B", "content": "A is correct but R is not correct"}, {"identifier": "C", "content": "Both A and R are correct and R is the correct explanation of A"}, {"identifier": "D", "content": "Both A and R are correct but R is NOT the correct e... | ["A"] | null | Assertion is not correct because alkali metals and
their salts impart characteristic colour to oxidising
part of flame and not reducing part of flame.
Reason is correct because all alkali metals can be
detected by their flame tests. | mcq | jee-main-2023-online-25th-january-evening-shift | 3,423 |
1ldwv6nx1 | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Identify the correct statements about alkali metals.</p>
<p>A. The order of standard reduction potential (M$$^+$$
| M) for alkali metal ions is Na > Rb > Li.</p>
<p>B. CsI is highly soluble in water.</p>
<p>C. Lithium carbonate is highly stable to heat.</p>
<p>D. Potassium dissolved in concentrated liquid am... | [{"identifier": "A", "content": "C and E only"}, {"identifier": "B", "content": "A and E only"}, {"identifier": "C", "content": "A, B, D only"}, {"identifier": "D", "content": "A, B and E only"}] | ["B"] | null | A. The order of standard reduction potential (M<sup>+</sup> | M) for alkali metal ions is Na > Rb > Li. This statement is correct. The standard reduction potential generally increases as we move down the group from Li to Cs so order should be Cs > Rb > K > Na > Li but here Na and K are exception, Na has highest standar... | mcq | jee-main-2023-online-24th-january-evening-shift | 3,424 |
1lgrk21qp | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>The density of alkali metals is in the order :</p> | [{"identifier": "A", "content": "$$\\mathrm{Na}<\\mathrm{K}<\\mathrm{Cs}<\\mathrm{Rb}$$"}, {"identifier": "B", "content": "$$\\mathrm{K}<\\mathrm{Na}<\\mathrm{Rb}<\\mathrm{Cs}$$"}, {"identifier": "C", "content": "$$\\mathrm{K}<\\mathrm{Cs}<\\mathrm{Na}<\\mathrm{Rb}$$"}, {"identifier": "D", "content": "$$\\mathrm{Na}<\\... | ["B"] | null | <p>Alkali metals are part of Group 1 on the periodic table and include lithium (Li), sodium (Na), potassium (K), rubidium (Rb), and cesium (Cs). As you move down the group, the atomic radius increases due to the addition of energy levels (shells). While you might think that the increased atomic mass would correspond to... | mcq | jee-main-2023-online-12th-april-morning-shift | 3,425 |
1lgyrlw06 | chemistry | s-block-elements | physiochemical-trends-in-alkali-metals | <p>Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.</p>
<p>Assertion A : Sodium is about 30 times as abundant as potassium in the oceans.</p>
<p>Reason R : Potassium is bigger in size than sodium.</p>
<p>In the light of the above statements, choose the correct answer... | [{"identifier": "A", "content": "Both A and R are true but R is NOT the correct explanation of A"}, {"identifier": "B", "content": "A is false but R is true"}, {"identifier": "C", "content": "Both A and R are true and R is the correct explanation of A"}, {"identifier": "D", "content": "A is true but R is false"}] | ["C"] | null | Due to bigger size of potassium, it forms more
efficient lattices as compared to sodium with
silicates.<br/><br/>
The abundance of sodium in ocean is more due to
the more soluble nature of salt of sodium as
compared to potassium salts. | mcq | jee-main-2023-online-8th-april-evening-shift | 3,427 |
m7DFC0V1q3ppedgi | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | A metal M readily forms its sulphate MSO<sub>4</sub>, which is water-soluble. It forms its oxide MO which becomes inert on heating. It forms an insoluble hydroxide M(OH)<sub>2</sub> which is soluble in NaOH solution. The M is : | [{"identifier": "A", "content": "Mg"}, {"identifier": "B", "content": "Ba"}, {"identifier": "C", "content": "Ca"}, {"identifier": "D", "content": "Be"}] | ["D"] | null | Sulphate of alkaline earth metal are sparingly soluble or almost not soluble in water whereas $$BeS{O_4}$$ is soluble in water due to high degree of solvation. $$Be{\left( {OH} \right)_2}$$ is insoluble in water but soluble in $$NaOH.$$
<br><br>$$BeO + 2NaOH\,\,$$ $$ \to \,\,N{a_2}Be{O_2} + {H_2}O$$ | mcq | aieee-2002 | 3,428 |
CkTPci39C0Xfl6Cj | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | One mole of magnesium nitride on the reaction with an excess of water gives : | [{"identifier": "A", "content": "one mole of ammonia"}, {"identifier": "B", "content": "two moles of nitric acid "}, {"identifier": "C", "content": "two moles of ammonia "}, {"identifier": "D", "content": "one mole of nitric acid "}] | ["C"] | null | $$M{g_3}{N_2} + 6{H_2}O\,\,\rightleftharpoons\,\,3Mg{\left( {OH} \right)_2} + 2N{H_3}$$
| mcq | aieee-2004 | 3,430 |
K4eHcbFTKpsFqwfS | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | The metal that cannot be obtained by electrolysis of an aqueous solution of its salts is : | [{"identifier": "A", "content": "Cu"}, {"identifier": "B", "content": "Cr"}, {"identifier": "C", "content": "Ag"}, {"identifier": "D", "content": "Ca"}] | ["D"] | null | On electrolysis of aqueous solution of $$s$$-block elements $${H_2}$$ gas discharge at cathode.
<br><br>At cathode: $${H_2}O + {e^ - } \to {1 \over 2}{H_2} + O{H^ - }$$ | mcq | jee-main-2014-offline | 3,431 |
NXhbC551v5SSKO0F | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Which one of the following alkaline earth metal sulphates has its hydration enthalpy greater than its lattice
enthalpy? | [{"identifier": "A", "content": "BeSO<sub>4</sub>"}, {"identifier": "B", "content": "BaSO<sub>4</sub>"}, {"identifier": "C", "content": "SrSO<sub>4</sub>"}, {"identifier": "D", "content": "CaSO<sub>4</sub>"}] | ["A"] | null | In alkaline earth metals, ionic size increases down the group. The lattice energy remains constant because sulphate ion is so large, so that small change in cationic size does not make any difference. On moving down the group the degree of hydration of metal ions decreases very much leading to decrease in solubility.
... | mcq | jee-main-2015-offline | 3,432 |
6b7YOR8lcPINC5urSqZaJ | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | The correct order of the solubility of alkaline-earth metal sulphates in water is : | [{"identifier": "A", "content": "Mg < Ca < Sr < Ba"}, {"identifier": "B", "content": "Mg < Sr < Ca < Ba"}, {"identifier": "C", "content": "Mg > Sr > Ca > Ba"}, {"identifier": "D", "content": "Mg > Ca > Sr > Ba"}] | ["D"] | null | The solubility of the sulphates in water decreases down
the group. Mg > Ca > Sr > Ba. MgSO<sub>4</sub>
is soluble, but
CaSO<sub>4</sub> is sparingly soluble, and the sulphates of Sr, Ba and Ra are virtually insoluble. The significantly high solubility of MgSO4 is due to the high enthalpy of solvation
of the smaller Mg... | mcq | jee-main-2016-online-9th-april-morning-slot | 3,433 |
7OQbAyzGvzLVaGmi | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Both lithium and magnesium display several similar properties due to the diagonal relationship; however,
the one which is incorrect, is : | [{"identifier": "A", "content": "both form soluble bicarbonates"}, {"identifier": "B", "content": "both from nitrides\n"}, {"identifier": "C", "content": "nitrates of both Li and Mg yield NO<sub>2</sub> and O<sub>2</sub> on heating "}, {"identifier": "D", "content": "both form basic carbonates "}] | ["D"] | null | Mg can form basic carbonate like
<br><br>3MgCO<sub>3</sub> . Mg(OH)<sub>2</sub> . 3H<sub>2</sub>O
<br><br>While Li can not. | mcq | jee-main-2017-offline | 3,434 |
g3MNTjqnsbi5rUXXP13rsa0w2w9jwvclt5n | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | The alloy used in the construction of aircrafts is : | [{"identifier": "A", "content": "Mg \u2013 Zn"}, {"identifier": "B", "content": "Mg \u2013 Al "}, {"identifier": "C", "content": "Mg \u2013 Mn"}, {"identifier": "D", "content": "Mg \u2013 Sn"}] | ["B"] | null | An alloy of Mg and Al called magnalium is used
in manufacturing of aircraft due to its light
weight and high strength. | mcq | jee-main-2019-online-10th-april-morning-slot | 3,436 |
UDmTrfxCRp1DXrXcHTbww | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | The metal used for marking X–ray tube window is : | [{"identifier": "A", "content": "Ca"}, {"identifier": "B", "content": "Na"}, {"identifier": "C", "content": "Mg"}, {"identifier": "D", "content": "Be"}] | ["D"] | null | ''Be'' Metal is used in x-ray window is due to transparent to x-rays. | mcq | jee-main-2019-online-10th-january-morning-slot | 3,438 |
x8nHejYs6ywrEWJdhB3Ja | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | The alkaline earth metal nitrate that does not crystallise with water molecules, is : | [{"identifier": "A", "content": "Mg(NO<sub>3</sub>)<sub>2</sub>"}, {"identifier": "B", "content": "Sr(NO<sub>3</sub>)<sub>2</sub>"}, {"identifier": "C", "content": "Ca(NO<sub>3</sub>)<sub>2</sub>"}, {"identifier": "D", "content": "Ba(NO<sub>3</sub>)<sub>2</sub>"}] | ["D"] | null | When central atom size is smaller then more water molecule will crystallize. Ba(NO<sub>3</sub>)<sub>2</sub> does not ctystallize with water as size of Ba<sup>+2</sup> ion is very large. | mcq | jee-main-2019-online-9th-january-morning-slot | 3,439 |
UZbRl56uOuvlI5bb6ojgy2xukey6nndt | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Two elements A and B have similar chemical
properties. They don’t form solid
hydrogencarbonates, but react with nitrogen to
form nitrides. A and B, respectively, are : | [{"identifier": "A", "content": "Li and Mg"}, {"identifier": "B", "content": "Cs and Ba"}, {"identifier": "C", "content": "Na and Rb"}, {"identifier": "D", "content": "Na and Ca"}] | ["A"] | null | Solid hydrogencarbonates are not formed
by lithium and magnesium.
<br><br>– 6Li + N<sub>2</sub> $$ \to $$ 2Li<sub>3</sub>N
<br><br>– 3Mg + N<sub>2</sub> $$ \to $$ Mg<sub>3</sub>N<sub>2</sub> | mcq | jee-main-2020-online-2nd-september-evening-slot | 3,440 |
IHQJW0f6JG7mifzSAIjgy2xukfcedvk5 | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | An alkaline earth metal ‘M’ readily forms water
soluble sulphate and water insoluble hydroxide.
Its oxide MO is very stable to heat and does not
have rock-salt structure. M is : | [{"identifier": "A", "content": "Ca"}, {"identifier": "B", "content": "Mg"}, {"identifier": "C", "content": "Sr"}, {"identifier": "D", "content": "Be"}] | ["D"] | null | BeSO<sub>4</sub>
is water soluble.
<br>Be(OH)<sub>2</sub>
is water insoluble.
<br>BeO is stable to heat. | mcq | jee-main-2020-online-4th-september-evening-slot | 3,441 |
WsmnVOe6nwSecTM36Ujgy2xukftdeo7z | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Among the sulphates of alkaline earth metals,
the solubilities of BeSO<sub>4</sub> and MgSO<sub>4</sub> in water,
respectively, are : | [{"identifier": "A", "content": "poor and poor"}, {"identifier": "B", "content": "poor and high"}, {"identifier": "C", "content": "high and poor"}, {"identifier": "D", "content": "high and high"}] | ["D"] | null | Order of solubility of sulphate of Alkaline earth metals
<br><br>BeSO<sub>4</sub>
> MgSO<sub>4</sub>
> CaSO<sub>4</sub>
> SrSO<sub>4</sub>
> BaSO<sub>4</sub>
<br><br>The greater hydration enthalpies of
Be<sup>2+</sup> and Mg<sup>2+</sup> ions dominate over their lattice
enthalpies and therefore their su... | mcq | jee-main-2020-online-6th-september-morning-slot | 3,442 |
FBEC1Yigj9F7SXOolx1kmhtmrch | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Given below are two statements :<br/><br/>Statement I : Both CaCl<sub>2</sub> . 6H<sub>2</sub>O and MgCl<sub>2</sub> . 8H<sub>2</sub>O undergo dehydration on heating.<br/><br/>Statement II : BeO is amphoteric whereas the oxides of other elements in the same group are acidic.<br/><br/>In the light of the above statement... | [{"identifier": "A", "content": "Both statement I and statement II are false"}, {"identifier": "B", "content": "Statement I is false but statement II is true"}, {"identifier": "C", "content": "Statement I is true but statement II is false"}, {"identifier": "D", "content": "Both statement I and statement II are true"}] | ["A"] | null | CaCl<sub>2</sub>.6H<sub>2</sub>O $$\buildrel \Delta \over
\longrightarrow $$ CaCl<sub>2</sub> + 6H<sub>2</sub>O<br><br>
MgCl<sub>2</sub>.6H<sub>2</sub>O $$\buildrel \Delta \over
\longrightarrow $$ MgCl(OH) + H<sub>2</sub>O<br><br>
Among alkaline earth metal BeO is amphoteric & rest are basic oxide | mcq | jee-main-2021-online-16th-march-morning-shift | 3,443 |
6BsBWGWetlGz7d3oGa1kmki64va | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | The set of elements that differ in mutual relationship from those of the other sets is : | [{"identifier": "A", "content": "Li - Na"}, {"identifier": "B", "content": "Be - Al"}, {"identifier": "C", "content": "B - Si"}, {"identifier": "D", "content": "Li - Mg"}] | ["A"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264651/exam_images/f8e0ml2oibv52mp4tpzq.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 17th March Evening Shift Chemistry - s-Block Elements Question 78 English Explanation"><br>
Li–Mg,... | mcq | jee-main-2021-online-17th-march-evening-shift | 3,444 |
1krussbkk | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Given below are two statements :<br/><br/>Statement I : None of the alkaline earth metal hydroxides dissolve in alkali.<br/><br/>Statement II : Solubility of alkaline earth metal hydroxides in water increases down the group. <br/><br/>In the light of the above statements, choose the most appropriate answer from the opt... | [{"identifier": "A", "content": "Statement I is correct but Statement II is incorrect."}, {"identifier": "B", "content": "Statement I is incorrect but Statement II is correct."}, {"identifier": "C", "content": "Statement I and Statement II both are incorrect."}, {"identifier": "D", "content": "Statement I and Statement... | ["B"] | null | Statement - I is incorrect<br><br>Be(OH)<sub>2</sub> dissolve in alkali due to it's amphoteric nature.<br><br>Statement - II is correct<br><br>Solubility of alkaline earth metal hydroxide in water increases down the group due to rapid decreases in lattice energy as compared to hydration energy. | mcq | jee-main-2021-online-25th-july-morning-shift | 3,447 |
1l58dt92f | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>The correct order of melting point is :</p> | [{"identifier": "A", "content": "Be > Mg > Ca > Sr"}, {"identifier": "B", "content": "Sr > Ca > Mg > Be"}, {"identifier": "C", "content": "Be > Ca > Mg > Sr"}, {"identifier": "D", "content": "Be > Ca > Sr > Mg"}] | ["D"] | null | $$\begin{array}{ll}\text {Element } & \text { M.P. } \\ \mathrm{Be} & 1560 \mathrm{~K} \\ \mathrm{Mg} & 924 \mathrm{~K} \\ \mathrm{Ca} & 1124 \mathrm{~K} \\ \mathrm{Sr} & 1062 \, \text{K}\end{array}$$ | mcq | jee-main-2022-online-26th-june-morning-shift | 3,448 |
1l5alvkoc | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>Which one of the following alkaline earth metal ions has the highest ionic mobility in its aqueous solution?</p> | [{"identifier": "A", "content": "Be<sup>2+</sup>"}, {"identifier": "B", "content": "Mg<sup>2+</sup>"}, {"identifier": "C", "content": "Ca<sup>2+</sup>"}, {"identifier": "D", "content": "Sr<sup>2+</sup>"}] | ["D"] | null | In aqueous solution, the ionic mobility is inversely
proportional to the charge density on the ion. Hence
Sr<sup>2+</sup> has highest ionic mobility in water. | mcq | jee-main-2022-online-25th-june-morning-shift | 3,450 |
1l6f6uoab | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>The correct order of density is :</p> | [{"identifier": "A", "content": "Be > Mg > Ca > Sr"}, {"identifier": "B", "content": "Sr > Ca > Mg > Be"}, {"identifier": "C", "content": "Sr > Be > Mg > Ca"}, {"identifier": "D", "content": "Be > Sr > Mg > Ca"}] | ["C"] | null | Density of $$\mathrm{Sr}=2.63 \mathrm{~g} / \mathrm{cm}^{3}$$
<br/><br/>
Density of $$\mathrm{Be}=1.84 \mathrm{~g} / \mathrm{cm}^{3}$$
<br/><br/>
Density of $$\mathrm{Mg}=1.74 \mathrm{~g} / \mathrm{cm}^{3}$$
<br/><br/>
Density of $$\mathrm{Ca}=1.55 \mathrm{~g} / \mathrm{cm}^{3}$$ | mcq | jee-main-2022-online-25th-july-evening-shift | 3,451 |
1l6i4sc3n | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>The metal that has very low melting point and its periodic position is closer to a metalloid is :</p> | [{"identifier": "A", "content": "Al"}, {"identifier": "B", "content": "Ga"}, {"identifier": "C", "content": "Se"}, {"identifier": "D", "content": "In"}] | ["B"] | null | Among the given elements, Gallium has the lowest
melting point, Gallium is also close to a metalloid | mcq | jee-main-2022-online-26th-july-evening-shift | 3,452 |
1l6kpeypx | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>An element A of group 1 shows similarity to an element B belonging to group 2. If A has maximum hydration enthalpy in group 1 then B is :</p> | [{"identifier": "A", "content": "Mg"}, {"identifier": "B", "content": "Be"}, {"identifier": "C", "content": "Ca"}, {"identifier": "D", "content": "Sr"}] | ["A"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7oihc9m/bdf7ed88-de80-4efb-bbfd-4b02aa3446d5/37c09ba0-2cf6-11ed-a627-29822045a51b/file-1l7oihc9n.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7oihc9m/bdf7ed88-de80-4efb-bbfd-4b02aa3446d5/37c09ba0-2cf6-11ed-a627-29822045a51b/fi... | mcq | jee-main-2022-online-27th-july-evening-shift | 3,453 |
1l6nuhhdy | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>The correct decreasing order for metallic character is :</p> | [{"identifier": "A", "content": "Na > Mg > Be > Si > P"}, {"identifier": "B", "content": "P > Si > Be > Mg > Na"}, {"identifier": "C", "content": "Si > P > Be > Na > Mg"}, {"identifier": "D", "content": "Be > Na > Mg > Si > P"}] | ["A"] | null | Metallic character increases top to bottom in group and decreases left to right in a period.
<br/><br/>
$\mathrm{Mg}$ is from second group it will be less metallic than $\mathrm{Na}$. Be comes above $\mathrm{Mg}$ hence less metallic than Mg. Si is more metallic than phosphorous. | mcq | jee-main-2022-online-28th-july-evening-shift | 3,454 |
1l6nuyuiq | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>Statement I : An alloy of lithium and magnesium is used to make aircraft plates.</p>
<p>Statement II : The magnesium ions are important for cell-membrane integrity.</p>
<p>In the light the above statements, choose the correct answer from the options given below :</p> | [{"identifier": "A", "content": "Both Statement I and Statement II are true"}, {"identifier": "B", "content": "Both Statement I and Statement II are false"}, {"identifier": "C", "content": "Statement I is true but Statement II is false"}, {"identifier": "D", "content": "Statement I is false but Statement II is true"}] | ["B"] | null | Alloy of Li and Mg is used to make armour plates
and not aircraft plates.<br/><br/>
Calcium plays important roles in neuromuscular
function, interneuronal transmission and cell
membrane integrity . | mcq | jee-main-2022-online-28th-july-evening-shift | 3,455 |
ldo8cwum | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | The element playing significant role in neuromuscular function and interneuronal transmission is : | [{"identifier": "A", "content": "Be"}, {"identifier": "B", "content": "$\\mathrm{Ca}$"}, {"identifier": "C", "content": "$\\mathrm{Mg}$"}, {"identifier": "D", "content": "$\\mathrm{Li}$"}] | ["B"] | null | Calcium plays important role in neuromuscular
function, interneuronal transmission, cell
membrane etc. | mcq | jee-main-2023-online-31st-january-evening-shift | 3,456 |
1ldoj5w8f | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>Choose the correct statement(s) :</p>
<p>A. Beryllium oxide is purely acidic in nature.</p>
<p>B. Beryllium carbonate is kept in the atmosphere of $$\mathrm{CO_2}$$.</p>
<p>C. Beryllium sulphate is readily soluble in water.</p>
<p>D. Beryllium shows anomalous behaviour.</p>
<p>Choose the correct answer from the opti... | [{"identifier": "A", "content": "A only"}, {"identifier": "B", "content": "B, C and D only"}, {"identifier": "C", "content": "A, B and C only"}, {"identifier": "D", "content": "A and B only"}] | ["B"] | null | <p>A. Beryllium oxide is amphoteric in nature. </p>
<p> B. Beryllium carbonate is kept in the atmosphere
of CO<sub>2</sub> because it is thermally less stable. </p>
<p> C. Beryllium sulphate is readily soluble in water
due to high degree of hydration. </p>
<p> D. Beryllium shows anomalous behaviour due to
small size... | mcq | jee-main-2023-online-1st-february-morning-shift | 3,457 |
ldqwnz40 | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Chlorides of which metal are soluble in organic solvents : | [{"identifier": "A", "content": "K"}, {"identifier": "B", "content": "Be"}, {"identifier": "C", "content": "Ca"}, {"identifier": "D", "content": "Mg"}] | ["B"] | null | <p>$$\mathrm{BeCl_2}$$ is a covalent molecule</p>
<p>So, it is soluble in organic solvents, rest are ionic compounds.</p> | mcq | jee-main-2023-online-30th-january-evening-shift | 3,458 |
1ldr4n6j4 | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>The alkaline earth metal sulphate(s) which are readily soluble in water is/are :</p>
<p>A. $$\mathrm{BeSO}_{4}$$</p>
<p>B. $$\mathrm{MgSO}_{4}$$</p>
<p>C. $$\mathrm{CaSO}_{4}$$</p>
<p>D. $$\mathrm{SrSO}_{4}$$</p>
<p>E. $$\mathrm{BaSO}_{4}$$</p>
<p>Choose the correct answer from the options given below :</p> | [{"identifier": "A", "content": "A and B"}, {"identifier": "B", "content": "B and C"}, {"identifier": "C", "content": "B only"}, {"identifier": "D", "content": "A only"}] | ["A"] | null | <p>BeSO$$_4$$ and MgSO$$_4$$ are readily soluble in water.</p> | mcq | jee-main-2023-online-30th-january-morning-shift | 3,459 |
1ldsr0jvc | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>The correct order of hydration enthalpies is</p>
<p>(A) K$$^+$$</p>
<p>(B) Rb$$^+$$</p>
<p>(C) Mg$$^{2+}$$</p>
<p>(D) Cs$$^+$$</p>
<p>(E) Ca$$^{2+}$$</p>
<p>Choose the correct answer from the options given below :</p> | [{"identifier": "A", "content": "E > C > A > B > D"}, {"identifier": "B", "content": "C > A > E > B > D"}, {"identifier": "C", "content": "C > E > A > D > B"}, {"identifier": "D", "content": "C > E > A > B > D"}] | ["D"] | null | Hydration enthalpy $\propto$ charge density
<br/><br/>Charge density means $${{Magnitude\,of\,Charge} \over {Ionic\,Radius}}$$.
<br/><br/>
$\therefore$ The correct order of charge density is
<br/><br/>
$$
\mathrm{Mg}^{2+}>\mathrm{Ca}^{2+}>\mathrm{K}^{+}>\mathrm{Rb}^{+}>\mathrm{Cs}^{+}
$$
<br/><br/>
$\therefore$ The or... | mcq | jee-main-2023-online-29th-january-morning-shift | 3,460 |
1ldu0yi9x | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>Which of the following represents the correct order of metallic character of the given elements?</p> | [{"identifier": "A", "content": "K < Mg < Be < Si"}, {"identifier": "B", "content": "Si < Be < Mg < K"}, {"identifier": "C", "content": "Be < Si < Mg < K"}, {"identifier": "D", "content": "Be < Si < K < Mg"}] | ["B"] | null | Metallic character of an element is directly proportional to its electropositivity. Of the given elements silicon is least electro positive and potassium is most electropositive whereas beryllium and magnesium have intermediate values in the increasing order. Therefore, correct order of metallic character is $\mathrm{S... | mcq | jee-main-2023-online-25th-january-evening-shift | 3,461 |
1ldwum0sy | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R</p>
<p>Assertion A : Beryllium has less negative value of reduction potential compared to the other alkaline earth metals.</p>
<p>Reason R : Beryllium has large hydration energy due to small size of Be$$^{2+}$$ but r... | [{"identifier": "A", "content": "Both A and R are correct but R is NOT the correct explanation of A"}, {"identifier": "B", "content": "Both A and R are correct and R is the correct explanation of A"}, {"identifier": "C", "content": "A is correct but R is not correct"}, {"identifier": "D", "content": "A is not correct ... | ["B"] | null | The most appropriate answer is Both A and R are correct and R is the correct explanation of A.
<br/><br/>
<b>Assertion A</b> states that beryllium has a less negative value of reduction potential compared to the other alkaline earth metals. This assertion is correct, as beryllium has higher ionization energy and a smal... | mcq | jee-main-2023-online-24th-january-evening-shift | 3,462 |
lgnzloa4 | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | Given below are two statements : One is labelled as Assertion A and the other is labelled as Reason R :
<br/><br/>
<b>Assertion (A)</b> : $\mathrm{BeCl}_{2}$ and $\mathrm{MgCl}_{2}$ produce characteristic flame<br/><br/>
<b>Reason (R)</b> : The excitation energy is high in $\mathrm{BeCl}_{2}$ and $\mathrm{MgCl}_{2}$
<b... | [{"identifier": "A", "content": "$\\mathrm{(A)}$ is true but $(\\mathrm{R})$ is false"}, {"identifier": "B", "content": "Both (A) and $(\\mathrm{R})$ are true and $(\\mathrm{R})$ is the correct explanation of $(A)$"}, {"identifier": "C", "content": "(A) is false but (R) is true\n"}, {"identifier": "D", "content": "Both... | ["C"] | null | BeCl<sub>2</sub> and MgCl<sub>2</sub> do not produce characteristic
flame because excitation energy is high in BeCl<sub>2</sub>
and MgCl<sub>2</sub>. Hence, the correct answer is option (C). | mcq | jee-main-2023-online-15th-april-morning-shift | 3,463 |
1lgvtszte | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>The correct order of metallic character is :</p> | [{"identifier": "A", "content": "K > Be > Ca"}, {"identifier": "B", "content": "Ca > K > Be"}, {"identifier": "C", "content": "K > Ca > Be"}, {"identifier": "D", "content": "Be > Ca > K"}] | ["C"] | null | <p>As you move from top to bottom in a group (vertical column) on the periodic table, the metallic character increases. This is because elements at the bottom of a group have more electron shells than those at the top. These extra shells shield the outermost electrons from the pull of the nucleus, which makes it easier... | mcq | jee-main-2023-online-10th-april-evening-shift | 3,464 |
1lh32h679 | chemistry | s-block-elements | physiochemical-trends-in-alkaline-earth-metals | <p>Ion having highest hydration enthalpy among the given alkaline earth metal ions is :</p> | [{"identifier": "A", "content": "$$\\mathrm{Sr}^{2+}$$"}, {"identifier": "B", "content": "$$\\mathrm{Ca}^{2+}$$"}, {"identifier": "C", "content": "$$\\mathrm{Be}^{2+}$$"}, {"identifier": "D", "content": "$$\\mathrm{Ba}^{2+}$$"}] | ["C"] | null | <p>Hydration enthalpy is the amount of energy released when one mole of gaseous ions is completely surrounded by water molecules. The process is exothermic, hence the enthalpy change is negative. </p>
<p>Generally, smaller ions and ions with higher charge have larger hydration enthalpies due to the stronger attraction ... | mcq | jee-main-2023-online-6th-april-evening-shift | 3,466 |
K8VVFHuXtvdFkmGb | chemistry | solid-state | close-packing-in-crystals | In a compound atoms of element Y from ccp lattice and those of element X occupy 2/3rd of tetrahedral
voids. The formula of the compound will be : | [{"identifier": "A", "content": "X<sub>4</sub>Y<sub>3</sub>"}, {"identifier": "B", "content": "X<sub>2</sub>Y<sub>3</sub>"}, {"identifier": "C", "content": "X<sub>2</sub>Y"}, {"identifier": "D", "content": "X<sub>3</sub>Y<sub>4</sub>"}] | ["A"] | null | From the given data, we have
<br><br>Number of $$Y$$ atoms in a unit cell
<br><br>$$=4$$
<br><br>Number of $$X$$ atoms in a unit cell
<br><br>$$ = 8 \times {2 \over 3} = {{16} \over 3}$$
<br><br>From the above we get the formula of the compound
<br><br>as $${X_{16/3}}{Y_4}\,\,$$ or $${X_4}{Y_3}$$ | mcq | aieee-2008 | 3,467 |
6xBm9SOvpviBC90u | chemistry | solid-state | close-packing-in-crystals | Percentages of free space in cubic close packed structure and in body centred packed structure are
respectively : | [{"identifier": "A", "content": "30% and 26%"}, {"identifier": "B", "content": "26% and 32%"}, {"identifier": "C", "content": "32% and 48%"}, {"identifier": "D", "content": "48% and 26%"}] | ["B"] | null | Packing fraction is defined as the ratio of the volume of the unit cell that is occupied by the spheres to the volume of the unit cell.
<br><br>P.F. for cpp and bcc are $$0.74$$ and $$0.68$$ respectively.
<br><br>So, the free space in ccp and bcc are $$26\% $$ & $$32\% $$ respectively. | mcq | aieee-2010 | 3,468 |
ya2QzB4oEpOwCfOkCxVnd | chemistry | solid-state | close-packing-in-crystals | A compound of formula A<sub>2</sub>B<sub>3</sub> has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms : | [{"identifier": "A", "content": "hcp lattice - A, $${1 \\over 3}$$ Tetrahedral voids-B"}, {"identifier": "B", "content": "hcp lattice - B, $${1 \\over 3}$$ Tetrahedral voids - A"}, {"identifier": "C", "content": "hcp lattice - A, $${2 \\over 3}$$ Tetrahedral voids - B"}, {"identifier": "D", "content": "hcp lattice - B,... | ["B"] | null | A<sub>2</sub>B<sub>3</sub><sub></sub> has HCP lattice
<br><br>If A form HCP,
<br>then $${{{3^{th}}} \over 4}$$ of THV must occupied by B to form A<sub>2</sub>B<sub>3</sub>
<br><br>If B form HCP, then $${{{1^{th}}} \over 3}$$ of THV must occupied by A to form A<sub>2</sub>B<sub>3</sub> | mcq | jee-main-2019-online-10th-january-evening-slot | 3,469 |
dVbe1ckEgS640O96lN1kmiv0k0d | chemistry | solid-state | close-packing-in-crystals | Ga (atomic mass 70 u) crystallizes in a hexagonal close packed structure. The total number of voids in 0.581 g of Ga is __________ $$\times$$ 10<sup>21</sup>. (Round off to the Nearest Integer). [Given : N<sub>A</sub> = 6.023 $$\times$$ 10<sub>23</sub>] | [] | null | 15 | For HCP structure Z = 6<br><br>Tetrahedral Void = (Z $$\times$$ 2) = 12<br><br>Octahedral Void = [Z $$\times$$ 1] = 6<br><br>No. of void per unit cell = 18<br><br>No. of unit cell = $$\left( {{{0.581 \times {N_A}} \over {70 \times 6}}} \right)$$<br><br>No. of void = $$\left( {{{0.581 \times 6.023 \times {{10}^{23}}} \o... | integer | jee-main-2021-online-16th-march-evening-shift | 3,470 |
FdsRW5NnnN48Z4EMOp1kmlniank | chemistry | solid-state | close-packing-in-crystals | In a binary compound, atoms of element A form a hcp structure and those of element M occupy 2/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is : | [{"identifier": "A", "content": "M<sub>2</sub>A<sub>3</sub>"}, {"identifier": "B", "content": "M<sub>4</sub>A<sub>3</sub>"}, {"identifier": "C", "content": "M<sub>4</sub>A"}, {"identifier": "D", "content": "MA<sub>3</sub>"}] | ["B"] | null | In HCP unit cell,<br><br>Z = 6 so A = 6<br><br>Also we know, in HCP<br><br>Tetrahedral voids = 2Z = 12<br><br>$$ \therefore $$ No. of M = $${2 \over 3}$$ [TV] = $${2 \over 3}$$ $$\times$$ 12 = 8<br><br>$$ \therefore $$ Formula = M<sub>8</sub>A<sub>6</sub> = M<sub>4</sub>A<sub>3</sub> | mcq | jee-main-2021-online-18th-march-morning-shift | 3,471 |
1ktjyki76 | chemistry | solid-state | close-packing-in-crystals | The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites in A<sub>x</sub>B. The value of x is _____________. (Integer answer) | [] | null | 1 | Anions forms CCP or FCC(A<sup>$$-$$</sup>) = 4A<sup>$$-$$</sup> per unit cell Cations occupy all octahedral voids (B<sup>+</sup>) = 4B<sup>+</sup> per unit cell<br><br>cell formula $$\to$$ A<sub>4</sub>B<sub>4</sub><br><br>Empirical formula $$\to$$ AB $$\to$$ (x = 1) | integer | jee-main-2021-online-31st-august-evening-shift | 3,472 |
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