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1ktmw4fvn | physics | current-electricity | electric-power-and-heating-effect-of-current | A uniform heating wire of resistance 36$$\Omega$$ is connected across a potential difference of 240 V. The wire is then cut into half and potential difference of 240V is applied across each half separately. The ratio of power dissipation in first case to the total power dissipation in the second case would be 1 : x, wh... | [] | null | 4 | <b>For Case I,</b><br/><br/>The potential difference of the uniform wire, V = 240 V<br/><br/>The resistance of the uniform wire, R<sub>1</sub> = 36 $$\Omega$$<br/><br/>The power dissipation in the first case,<br/><br/>$${P_1} = {{{V^2}} \over {{R_1}}} = {{{{(240)}^2}} \over {36}}$$<br/><br/><b>For Case II,</b><br/><br/... | integer | jee-main-2021-online-1st-september-evening-shift | 9,785 |
1l55k5jwd | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>Resistance of the wire is measured as 2 $$\Omega$$ and 3 $$\Omega$$ at 10$$^\circ$$C and 30$$^\circ$$C respectively. Temperature co-efficient of resistance of the material of the wire is :</p> | [{"identifier": "A", "content": "0.033 $$^\\circ$$C<sup>$$-$$1</sup>"}, {"identifier": "B", "content": "$$-$$0.033 $$^\\circ$$C<sup>$$-$$1</sup>"}, {"identifier": "C", "content": "0.011 $$^\\circ$$C<sup>$$-$$1</sup>"}, {"identifier": "D", "content": "0.055 $$^\\circ$$C<sup>$$-$$1</sup>"}] | ["A"] | null | <p>R<sub>10</sub> = 2 = R<sub>0</sub>(1 + $$\alpha$$ $$\times$$ 10)</p>
<p>R<sub>30</sub> = 3 = R<sub>0</sub>(1 + $$\alpha$$ $$\times$$ 30)</p>
<p>On solving</p>
<p>$$\alpha$$ = 0.033/$$^\circ$$C | mcq | jee-main-2022-online-28th-june-evening-shift | 9,786 |
1l5alepo2 | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>A resistor develops 300 J of thermal energy in 15 s, when a current of 2 A is passed through it. If the current increases to 3 A, the energy developed in 10 s is ____________ J.</p> | [] | null | 450 | <p>$$300 = {I^2}R \times 15$$</p>
<p>$$ \Rightarrow R = 5\,\Omega $$</p>
<p>Now $$I_2^2R{t_2}$$</p>
<p>$$ = 9 \times 5 \times 10$$</p>
<p>$$ = 450\,J$$</p> | integer | jee-main-2022-online-25th-june-morning-shift | 9,787 |
1l6nsjma0 | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>Given below are two statements :</p>
<p>Statement I : A uniform wire of resistance $$80 \,\Omega$$ is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be $$5 \,\Omega$$.</p>
<p>Statement II: Two resistances 2R and 3R are connected in parallel in ... | [{"identifier": "A", "content": "Both statement I and statement II are correct"}, {"identifier": "B", "content": "Both statement I and statement II are incorrect"}, {"identifier": "C", "content": "Statement I is correct but statement II is incorrect"}, {"identifier": "D", "content": "Statement I is incorrect but statem... | ["C"] | null | <p>Statement I : $${R_{1\,part}} = {{80} \over 4} = 20\,\Omega $$</p>
<p>$$ \Rightarrow {R_{eff}} = {{20} \over 4} = 5\,\Omega $$</p>
<p>Statement II : Ratio $$ = {{{{{{(\Delta V)}^2}} \over {3R}}} \over {{{{{(\Delta V)}^2}} \over {2R}}}}$$</p>
<p>$$ = {2 \over 3}$$</p> | mcq | jee-main-2022-online-28th-july-evening-shift | 9,788 |
1l6ntyjpv | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>An electrical bulb rated 220 V, 100 W, is connected in series with another bulb rated 220 V, 60 W. If the voltage across combination is 220 V, the power consumed by the 100 W bulb will be about _______ W.</p> | [] | null | 14 | <p>$${P_{100}} = {{{V^2}} \over {{R_{100}}}} \Rightarrow {R_{100}} = {{{V^2}} \over {{P_{100}}}}$$</p>
<p>$${P_{60}} = {{{V^2}} \over {{R_{60}}}} \Rightarrow {R_{60}} = {{{V^2}} \over {{P_{60}}}}$$</p>
<p>$${P_{net}} = {{{V^2}} \over {{R_{60}} + {R_{100}}}} = {{{P_{60}}{P_{100}}} \over {{P_{60}} + {P_{100}}}} = {{60 \t... | integer | jee-main-2022-online-28th-july-evening-shift | 9,789 |
ldo6lxz4 | physics | current-electricity | electric-power-and-heating-effect-of-current | The $\mathrm{H}$ amount of thermal energy is developed by a resistor in $10 \mathrm{~s}$ when a current of $4 \mathrm{~A}$ is passed through it. If the current is increased to $16 \mathrm{~A}$, the thermal energy developed by the resistor in $10 \mathrm{~s}$ will be : | [{"identifier": "A", "content": "$\\frac{\\mathrm{H}}{4}$"}, {"identifier": "B", "content": "$16 \\mathrm{H}$"}, {"identifier": "C", "content": "H"}, {"identifier": "D", "content": "$4 \\mathrm{H}$"}] | ["B"] | null | $H \propto i^{2}$ for $t=$ constant
<br/><br/>$$ \Rightarrow $$ $$
\frac{H}{H^{\prime}}=\left(\frac{4}{16}\right)^{2}
$$
<br/><br/>$$ \Rightarrow $$ $H^{\prime}=16 H$ | mcq | jee-main-2023-online-31st-january-evening-shift | 9,790 |
1lgq2otjb | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>Different combination of 3 resistors of equal resistance $$\mathrm{R}$$ are shown in the figures. The increasing order for power dissipation is:</p>
<p><img src="data:image/png;base64,UklGRnoRAABXRUJQVlA4IG4RAACQAwGdASqMAgADP4HA2mU2MTqnIdR5U1AwCWlu+/O7S+xGVs5leHpH/ZWu9n9/d+NP7j36/WCgE+uiuH/zj/vZH/99Zf3+HxtqKVRm2opVG... | [{"identifier": "A", "content": "$$\\mathrm{P}_{\\mathrm{B}}<\\mathrm{P}_{\\mathrm{C}}<\\mathrm{P}_{\\mathrm{D}}<\\mathrm{P}_{\\mathrm{A}}$$"}, {"identifier": "B", "content": "$$\\mathrm{P}_{\\mathrm{C}}<\\mathrm{P}_{\\mathrm{B}}<\\mathrm{P}_{\\mathrm{A}}<\\mathrm{P}_{\\mathrm{D}}$$"}, {"identifier": "C", "content": "$... | ["B"] | null | $\mathrm{P}=\mathrm{I}^2 \mathrm{R}$<br/><br/>
$$
\mathrm{R}_1=\frac{3 \mathrm{R}}{2}, \mathrm{R}_2=\frac{2 \mathrm{R}}{3}, \mathrm{R}_3=\frac{\mathrm{R}}{3}, \mathrm{R}_4=3 \mathrm{R}
$$<br/><br/>
Since $\mathrm{i}$ is same, hence $\mathrm{P} \propto \mathrm{R}$ so options (B) is correct | mcq | jee-main-2023-online-13th-april-morning-shift | 9,792 |
1lgq3c0ja | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>A potential $$\mathrm{V}_{0}$$ is applied across a uniform wire of resistance $$R$$. The power dissipation is $$P_{1}$$. The wire is then cut into two equal halves and a potential of $$V_{0}$$ is applied across the length of each half. The total power dissipation across two wires is $$P_{2}$$. The ratio $$P_{2}: \ma... | [] | null | 16 | Let's analyze the initial situation where the potential $$V_0$$ is applied across the entire length of the wire with resistance $$R$$.
<br/><br/>
The power dissipation, $$P_1$$, can be calculated using the formula:
<br/><br/>
$$P_1 = \frac{V_0^2}{R}$$
<br/><br/>
Now, let's consider the case where the wire is cut into t... | integer | jee-main-2023-online-13th-april-morning-shift | 9,793 |
1lgrjqg3o | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>The current flowing through a conductor connected across a source is $$2 \mathrm{~A}$$ and 1.2 $$\mathrm{A}$$ at $$0^{\circ} \mathrm{C}$$ and $$100^{\circ} \mathrm{C}$$ respectively. The current flowing through the conductor at $$50^{\circ} \mathrm{C}$$ will be ___________ $$\times 10^{2} \mathrm{~mA}$$.</p> | [] | null | 15 | Our approach to this problem uses the fact that the voltage across the conductor remains constant as it is connected to the same source. By analyzing the relation between the currents and resistances at different temperatures, you can find the current flowing through the conductor at $$50^{\circ} \mathrm{C}$$.
<br/><br... | integer | jee-main-2023-online-12th-april-morning-shift | 9,794 |
1lguy6qmk | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>Two identical heater filaments are connected first in parallel and then in series. At the same applied voltage, the ratio of heat produced in same time for parallel to series will be:</p> | [{"identifier": "A", "content": "4 : 1"}, {"identifier": "B", "content": "1 : 4"}, {"identifier": "C", "content": "2 : 1"}, {"identifier": "D", "content": "1 : 2"}] | ["A"] | null | Let's consider the power $$P$$ dissipated by a single heater filament with resistance $$R$$ when connected to a voltage $$V$$.
<br/><br/>
The power dissipated by the heater filament is given by:
<br/><br/>
$$P = \frac{V^2}{R}$$
<br/><br/>
When the two identical heater filaments are connected in parallel, the equivalent... | mcq | jee-main-2023-online-11th-april-morning-shift | 9,795 |
jaoe38c1lsd5tt5u | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>By what percentage will the illumination of the lamp decrease if the current drops by 20%?</p> | [{"identifier": "A", "content": "26%"}, {"identifier": "B", "content": "36%"}, {"identifier": "C", "content": "46%"}, {"identifier": "D", "content": "56%"}] | ["B"] | null | <p>$$\begin{aligned}
& \mathrm{P}=\mathrm{i}^2 \mathrm{R} \\
& \mathrm{P}_{\text {int }}=\mathrm{I}_{\text {int }}^2 \mathrm{R} \\
& \mathrm{P}_{\text {final }}=\left(0.8 \mathrm{I}_{\text {int }}\right)^2 \mathrm{R}
\end{aligned}$$</p>
<p>% change in power $$=$$</p>
<p>$$\frac{P_{\text {final }}-P_{\text {int }}}{P_{\... | mcq | jee-main-2024-online-31st-january-evening-shift | 9,796 |
jaoe38c1lsd8fgeo | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>In the following circuit, the battery has an emf of $$2 \mathrm{~V}$$ and an internal resistance of $$\frac{2}{3} \Omega$$. The power consumption in the entire circuit is _________ W.</p>
<p><img src="data:image/png;base64,UklGRngSAABXRUJQVlA4IGwSAADQAwGdASorAgADP4HA2GQ2MKymoxJZwsAwCWlu+++ZC+pkzs5lc3p7cnsurffcnih4lC... | [] | null | 3 | <p>$$\begin{aligned}
& \mathrm{R}_{\text {eq }}=\frac{4}{3} \Omega \\
& \therefore \mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{R}_{\text {eq }}}=\frac{4}{4 / 3}=3 \mathrm{~W}
\end{aligned}$$</p> | integer | jee-main-2024-online-31st-january-evening-shift | 9,797 |
1lsg5t1zl | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>When a potential difference $$V$$ is applied across a wire of resistance $$R$$, it dissipates energy at a rate $$W$$. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the energy dissipation rate will become:</p> | [{"identifier": "A", "content": "1/2W"}, {"identifier": "B", "content": "4W"}, {"identifier": "C", "content": "1/4W"}, {"identifier": "D", "content": "2W"}] | ["B"] | null | <p>$$\begin{aligned}
& \frac{\mathrm{v}^2}{\mathrm{R}}=\mathrm{W} \qquad \text{.... (i)}\\
& \frac{\mathrm{v}^2}{\frac{1}{2}\left(\frac{\mathrm{R}}{2}\right)}=\mathrm{W}^{\prime} \quad \text{.... (ii)}
\end{aligned}$$</p>
<p>From (i) & (ii), we get</p>
<p>$$W^{\prime}=4 W$$</p> | mcq | jee-main-2024-online-30th-january-evening-shift | 9,798 |
lv2es2na | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>An electric bulb rated $$50 \mathrm{~W}-200 \mathrm{~V}$$ is connected across a $$100 \mathrm{~V}$$ supply. The power dissipation of the bulb is:</p> | [{"identifier": "A", "content": "100 W"}, {"identifier": "B", "content": "50 W"}, {"identifier": "C", "content": "12.5 W"}, {"identifier": "D", "content": "25 W"}] | ["C"] | null | <p>To find the power dissipation of the bulb when it's connected to a $$100 \mathrm{V}$$ supply instead of its rated $$200 \mathrm{V}$$ supply, we can use the relation between power (P), voltage (V), and resistance (R), which is given by $$P = \frac{V^2}{R}$$. The resistance of the bulb can be considered constant in th... | mcq | jee-main-2024-online-4th-april-evening-shift | 9,800 |
lv3vegqg | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>A heater is designed to operate with a power of $$1000 \mathrm{~W}$$ in a $$100 \mathrm{~V}$$ line. It is connected in combination with a resistance of $$10 \Omega$$ and a resistance $$R$$, to a $$100 \mathrm{~V}$$ mains as shown in figure. For the heater to operate at $$62.5 \mathrm{~W}$$, the value of $$\mathrm{R}... | [] | null | 5 | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lw50aedd/976d6b3a-15ff-493c-9ab6-71cf1b3d6b45/9685db10-112d-11ef-8ba2-25ca10491422/file-1lw50aede.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lw50aedd/976d6b3a-15ff-493c-9ab6-71cf1b3d6b45/9685db10-112d-11ef-8ba2-25ca10491422... | integer | jee-main-2024-online-8th-april-evening-shift | 9,802 |
lvb295ad | physics | current-electricity | electric-power-and-heating-effect-of-current | <p>The number of electrons flowing per second in the filament of a $$110 \mathrm{~W}$$ bulb operating at $$220 \mathrm{~V}$$ is : (Given $$\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$$)</p> | [{"identifier": "A", "content": "$$1.25 \\times 10^{19}$$\n"}, {"identifier": "B", "content": "$$31.25 \\times 10^{17}$$\n"}, {"identifier": "C", "content": "$$6.25 \\times 10^{18}$$\n"}, {"identifier": "D", "content": "$$6.25 \\times 10^{17}$$"}] | ["B"] | null | <p>$$\begin{aligned}
& P=v \times i \Rightarrow i=\frac{110}{220}=\frac{1}{2} \mathrm{~A} \\
& i=n e \Rightarrow n=\frac{1}{2 \times 1.6 \times 10^{-19}}=31.25 \times 10^{17}
\end{aligned}$$</p> | mcq | jee-main-2024-online-6th-april-evening-shift | 9,804 |
uiLFmxxbPDGgE81u | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | If an ammeter is to be used in place of a voltmeter, then we must connect with the ammeter a | [{"identifier": "A", "content": "low resistance in parallel "}, {"identifier": "B", "content": "high resistance in parallel "}, {"identifier": "C", "content": "high resistance in series "}, {"identifier": "D", "content": "low resistance in series "}] | ["C"] | null | <b>KEY CONCEPT :</b> To convert a galvanometer into a voltmeter we connect a high resistance in series with the galvanometer.
<br><br>The same procedure needs to be done if ammeter is to be used as a voltmeter. | mcq | aieee-2002 | 9,805 |
oCfPjGdX87Zk9NBi | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | The thermo $$e.m.f.$$ of a thermo -couple is $$25$$ $$\mu V/{}^ \circ C$$ at room temperature. A galvanometer of $$40$$ $$ohm$$ resistance, capable of detecting current as low as $${10^{ - 5}}\,A,$$ is connected with the thermo couple. The smallest temperature difference that can be detected by this system is | [{"identifier": "A", "content": "$${16^0}C$$ "}, {"identifier": "B", "content": "$${12^0}C$$"}, {"identifier": "C", "content": "$${8^0}C$$"}, {"identifier": "D", "content": "$${20^0}C$$"}] | ["A"] | null | Let $$\theta $$ be the smallest temperature difference that can be detected by the thermocouple, then
<br><br>$$I \times R = \left( {25 \times {{10}^{ - 6}}} \right)\theta $$
<br><br>where $${\rm I}$$ is the smallest current which can be detected by the galvanometer of resistance $$R.$$
<br><br>$$\therefore$$ $${10^{ -... | mcq | aieee-2003 | 9,806 |
cpZym95vLWxghTMx | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A moving coil galvanometer has $$150$$ equal divisions. Its current sensitivity is $$10$$- divisions per milliampere and voltage sensitivity is $$2$$ divisions per millivolt. In order that each division reads $$1$$ volt, the resistance in $$ohms$$ needed to be connected in series with the coil will be - | [{"identifier": "A", "content": "$${10^5}$$ "}, {"identifier": "B", "content": "$${10^3}$$"}, {"identifier": "C", "content": "$$9995$$ "}, {"identifier": "D", "content": "$$99995$$ "}] | ["C"] | null | <b>KEY CONCEPT :</b> Resistance of Galvanometer,
<br><br>$$G = {{Current\,\,\,sensitivity} \over {Voltage\,\,\,sensityvity}} \Rightarrow G = {{10} \over 2} = 5\Omega $$
<br><br>Here $${i_g} = $$ Full scale deflection current $$ = {{150} \over {10}} = 15\,\,mA$$
<br><br>$$V=$$ voltage to be measured $$=150$$ volts
<br... | mcq | aieee-2005 | 9,809 |
6SoJA5XIwlMKlyVQ | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | Two voltmeters, one of copper and another of silver, are joined in parallel. When a total charge $$q$$ flows through the voltmeters, equal amount of metals are deposited. If the electrochemical equivalents of copper and silver are $${Z_1}$$ and $${Z_2}$$ respectively the charge which flows through the silver voltmeter ... | [{"identifier": "A", "content": "$${q \\over {1 + {{{Z_2}} \\over {{Z_1}}}}}$$ "}, {"identifier": "B", "content": "$${q \\over {1 + {{{Z_1}} \\over {{Z_2}}}}}$$ "}, {"identifier": "C", "content": "$$q{{{Z_2}} \\over {{Z_1}}}$$ "}, {"identifier": "D", "content": "$$q{{{Z_1}} \\over {{Z_2}}}$$ "}] | ["A"] | null | Mass deposited
<br><br>$$m = Zq \Rightarrow Z \propto {1 \over q} \Rightarrow {{{Z_1}} \over {{Z_2}}} = {{{q_2}} \over {{q_1}}}\,\,\,\,\,\,\,\,\,\,\,...\left( i \right)$$
<br><br>Also $$q = {q_1} + {q_2}\,\,\,\,\,\,\,\,\,\,...\left( {ii} \right)$$
<br><br>$$ \Rightarrow {q \over {{q_2}}} = {{{q_1}} \over {{q_2}}} + 1\... | mcq | aieee-2005 | 9,810 |
ztgSr6Loh3Y9B6B4 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | Shown in the figure below is a meter-bridge set up with null deflection in the galvanometer.
<img src="data:image/png;base64,UklGRjgQAABXRUJQVlA4ICwQAABQiACdASrdAYIBP4G812O2L6wmo3LqKsAwCWlu/EtoVtOo7Imi6n9S/tH9m62HL0bp2Eeeyot/qu+HgI+rf/3vkIA+9qmZfjctv4N9ADynu9V+9b3Iep6nJ3BXAs54zeuzPy4hWhA7ChtzjAEx+Y3C09TkhdVthPeOtvBl4OT... | [{"identifier": "A", "content": "$$13.75\\Omega $$ "}, {"identifier": "B", "content": "$$220\\Omega $$ "}, {"identifier": "C", "content": "$$110\\Omega $$"}, {"identifier": "D", "content": "$$55\\Omega $$"}] | ["B"] | null | According to the condition of balancing
<br><br>$${{55} \over {20}} = {R \over {80}} \Rightarrow R = 220\Omega $$ | mcq | aieee-2008 | 9,811 |
EMaCvdCkcJFexPVY | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | This questions has Statement - $${\rm I}$$ and Statement - $${\rm I}$$$${\rm I}$$. Of the four choices given after the Statements, choose the one that best describes into two Statements.
<p><b>Statement - $${\rm I}$$ : </b> Higher the range, greater is the resistance of ammeter.
<br/><b>Statement - $${\rm I}$$$${\rm I... | [{"identifier": "A", "content": "Statement - $${\\rm I}$$ is true, Statement - $${\\rm II}$$ is true, Statement - $${\\rm II}$$ is the correct explanation of statement - $${\\rm I}$$."}, {"identifier": "B", "content": "Statement - $${\\rm I}$$ is true, Statement - $${\\rm II}$$ is true, Statement - $${\\rm II}$$ is not... | ["D"] | null | Statements $${\rm I}$$ is false and Statement $${\rm I}$$$${\rm I}$$ is true
<br><br>For ammeter, shunt resistance, $$S = {{{{\rm I}_g}G} \over {{\rm I} - {{\rm I}_g}}}$$
<br><br>Therefore for $${\rm I}$$ to increase, $$S$$ should decrease, So additional $$S$$ can be connected across it. | mcq | jee-main-2013-offline | 9,812 |
V9o4nKvXVSLkC19r9Kkcf | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer has a 50 division scale. Battery has no internal resistance. It is found that there is deflection of 40 divisions when R = 2400 $$\Omega $$. Deflection becomes 20 divisions when resistance taken from resistance box is 4900 $$\Omega $$. Then we can conclude :
<br/><br/><img src="data:image/png;base64,UklG... | [{"identifier": "A", "content": "Resistance of galvanometer is 200 $$\\Omega $$"}, {"identifier": "B", "content": "Full scale deflection current is 2 mA.\n"}, {"identifier": "C", "content": "Current sensitivity of galvanometer is 20 $$\\mu $$A/division."}, {"identifier": "D", "content": "Resistance required on R.B. for... | ["C"] | null | Let full scale deflection of current = I
<br><br>In case 1, when R = 2400 $$\Omega $$ and deflection of 40 divisions present.
<br><br>$$ \therefore $$ $${{40} \over {50}}{\rm I} = {V \over {G + R}}$$
<br><br>$$ \Rightarrow $$ $${4 \over 5}{\rm I}$$ = $${2 \over {G + 2400}}$$ &nbs... | mcq | jee-main-2016-online-10th-april-morning-slot | 9,813 |
OJAkST2XymZYeR9P | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer having a coil resistance of $$100\,\Omega $$ gives a full scale deflection, when a currect of $$1$$ $$mA$$ is passed through it. The value of the resistance, which can convert this galvanometer into ammeter giving a full scale deflection for a current of $$10$$ $$A,$$ is : | [{"identifier": "A", "content": "$$0.1\\,\\Omega $$ "}, {"identifier": "B", "content": "$$3\\,\\Omega $$ "}, {"identifier": "C", "content": "$$0.01\\,\\Omega $$"}, {"identifier": "D", "content": "$$2\\,\\Omega $$"}] | ["C"] | null | $${\rm I}gG = \left( {{\rm I} - {\rm I}g} \right)s$$
<br><br>$$\therefore$$ $${10^{ - 3}} \times 100 = \left( {10 - {{10}^{ - 3}}} \right) \times S$$
<br><br>$$\therefore$$ $$S \approx 0.01\,\,\Omega $$ | mcq | jee-main-2016-offline | 9,815 |
5aT5yJbIhnIdc8J8 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | When a current of 5 mA is passed through a galvanometer having a coil of resistance 15$$\Omega $$, it shows full
scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a
voltmeter of range 0 – 10V is: | [{"identifier": "A", "content": "4.005 \u00d7 10<sup>3</sup> $$\\Omega $$"}, {"identifier": "B", "content": "1.985 \u00d7 10<sup>3</sup> $$\\Omega $$"}, {"identifier": "C", "content": "2.535 \u00d7 10<sup>3</sup> $$\\Omega $$"}, {"identifier": "D", "content": "2.045 \u00d7 10<sup>3</sup> $$\\Omega $$"}] | ["B"] | null | Given : Current through the galvanometer,
<br><br>i<sub>g</sub> = 5 × 10<sup>–3</sup> A
<br><br>Galvanometer resistance, G = 15 $$\Omega $$
<br><br>Let resistance R to be put in series with the galvanometer to
convert it into a voltmeter.
<br><br>V = i<sub>g</sub> (R + G)
<br><br>10 = 5 × 10<sup>–3</sup> (R + 15)
<br><... | mcq | jee-main-2017-offline | 9,817 |
vzQHFuKMH5gDmq87s6WNr | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer with its coil resistance 25 $$\Omega $$ requires a current of 1 mA for its full deflection. In order to construct an ammeter to read upto a current of 2 A, the approximate value of the shunt resistance should be : | [{"identifier": "A", "content": "$$2.5 \\times {10^{ - 3}}\\,\\Omega $$ "}, {"identifier": "B", "content": "$$1.25 \\times {10^{ - 2}}\\Omega $$"}, {"identifier": "C", "content": "$$1.25 \\times {10^{ - 3}}\\Omega $$"}, {"identifier": "D", "content": "$$2.5 \\times {10^{ - 2}}\\Omega $$"}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264358/exam_images/ywczrpvunyf45azc53kd.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Online) 16th April Morning Slot Physics - Current Electricity Question 273 English Explanation">
<br><br... | mcq | jee-main-2018-online-16th-april-morning-slot | 9,819 |
SSiE5nee84TR580txzma9 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A moving coil galvanometer has resistance 50$$\Omega $$
and it indicates full deflection at 4mA current.
A voltmeter is made using this galvanometer
and a 5 k$$\Omega $$ resistance. The maximum voltage,
that can be measured using this voltmeter, will
be close to : | [{"identifier": "A", "content": "15 V"}, {"identifier": "B", "content": "10 V"}, {"identifier": "C", "content": "40 V"}, {"identifier": "D", "content": "20 V"}] | ["D"] | null | G = 50 $$\Omega $$<br><br/>
S = 5000 $$\Omega $$<br><br/>
I<sub>g</sub> = 4 × 10<sup>–3</sup><br><br/>
V = i<sub>g</sub> (G + S)<br><br/>
V = 4 × 10<sup>–3</sup> (50 + 5000)<br><br/>
= 4 × 10<sup>–3</sup> (5050) = 20.2 volt | mcq | jee-main-2019-online-9th-april-morning-slot | 9,820 |
R9SAZKwXxdLWzsVBun3rsa0w2w9jx7g1ya9 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A moving coil galvanometer, having a resistance G, produces full scale deflection when a current Ig flows
through it. This galvanometer can be converted into (i) an ammeter of range 0 to I<sub>0</sub>(I<sub>0</sub> > I<sub>g</sub>) by connecting a
shunt resistance R<sub>A</sub> to it and (ii) into a voltmeter of ran... | [{"identifier": "A", "content": "$${R_A}{R_V} = {G^2}$$ and $${{{R_A}} \\over {{R_V}}} = {{{I_g}} \\over {\\left( {{I_0} - {I_g}} \\right)}}$$"}, {"identifier": "B", "content": "$${R_A}{R_V} = {G^2}\\left( {{{{I_g}} \\over {{I_0} - {I_g}}}} \\right)$$ and $${{{R_A}} \\over {{R_V}}} = {\\left( {{{{I_0} - {I_g}} \\over {... | ["D"] | null | Galvanometer is converted into ammeter of range 0 to I<sub>0</sub> :
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266264/exam_images/vxnh6e6twqsuiy6jmfoq.webp" alt="JEE Main 2019 (Online) 12th April Evening Slot Physics - Current Electricity Question 219 English Explanation 1" style="max-width: 100%... | mcq | jee-main-2019-online-12th-april-evening-slot | 9,821 |
OZGlkEmOIAFO7PiXJx3rsa0w2w9jx3ogfe3 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The
measured voltage is plotted as a function of the current, and the following graph is obtained :
<img src="data:image/png;base64,UklGRgoOAABXRUJQVlA4IP4NAAAQewCdASoCApkBP4HA2mS2MS0nIhR5esAwCWlu/EsYaDlnZ1+frNaD2c3Y3KbBc8... | [{"identifier": "A", "content": "The value of the resistance R is 1.5 $$\\Omega $$"}, {"identifier": "B", "content": "The emf of the battery is l.5 V and its internal resistance is 1.5 $$\\Omega $$"}, {"identifier": "C", "content": "The emf of the battery is l.5 V and the value of R is 1.5 $$\\Omega $$"}, {"identifier"... | ["B"] | null | V = E – Ir<br><br>
When V = V<sub>0</sub> = 0 $$ \Rightarrow $$ 0 = E – Ir<br><br>
$$ \therefore $$ E = r<br><br>
When I = 0, V = E = 1.5 V<br><br>
$$ \therefore $$ r = 1.5 $$\Omega $$ | mcq | jee-main-2019-online-12th-april-morning-slot | 9,822 |
UcTqW9EwawMGoCyEpj3rsa0w2w9jx3mwfob | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer of resistance 100 $$\Omega $$ has 50 divisions on its scale and has sensitivitv of 20 $$\mu $$A/division. It is
to be converted to a voltmeter with three ranges of 0-2V, 0-10 V and 0-20 V. The appropriate circuit to do so
is | [{"identifier": "A", "content": "<picture><source media=\"(max-width: 320px)\" srcset=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734267530/exam_images/rsvg8poa6l1g8veob6bo.webp\"><source media=\"(max-width: 500px)\" srcset=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734264939/exam_images/ufrvfpzyun... | ["C"] | null | 20 × 50 × 10<sup>–6</sup> = 10<sup>–3</sup> Amp<br><br>
$${V_1} = {2 \over {{{10}^{ - 3}}}} = 100 + {R_1}$$<br><br>
$$1900 = {R_1}$$<br><br>
$${V_2} = {{10} \over {{{10}^{ - 3}}}} = \left( {2000 + {R_2}} \right)$$<br><br>
$${R_2} = 8000$$<br><br>
$${V_3} = {{20} \over {{{10}^{ - 3}}}} = 10 \times {10^3} + {R_3} = 10 \t... | mcq | jee-main-2019-online-12th-april-morning-slot | 9,823 |
YT7RwK5Ja7WshBqG1L18hoxe66ijvztisa7 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | In the given circuit, an ideal voltmeter
connected across the 10$$\Omega $$ resistance reads 2V.
The internal resistance r, of each cell is:
<img src="data:image/png;base64,UklGRuYOAABXRUJQVlA4INoOAACQWwCdASo0AQUBPm02lkikIqKhIbHqoIANiWlu/Eb44OtQx/0k/mf4oeCX9q/Jvz5/FPl37D/Tv2P/tHrhVsn9J/APVP+afUH7h/I/6R/kfzY+B/69/Rv28/w... | [{"identifier": "A", "content": "1.5 $$\\Omega $$"}, {"identifier": "B", "content": "1 $$\\Omega $$"}, {"identifier": "C", "content": "0.5 $$\\Omega $$"}, {"identifier": "D", "content": "0 $$\\Omega $$"}] | ["C"] | null | For the given circuit<br><br>
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266465/exam_images/kdnwvltaafy9dcz3cz2v.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 10th April Morning Slot Physics - Current Electricity Question 224 E... | mcq | jee-main-2019-online-10th-april-morning-slot | 9,824 |
Zo4UwXxVxxd17xakDSp73 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | The resistance of a galvanometer is 50 ohm and
the maximum current which can be passed
through it is 0.002 A. What resistance must be
connected to it in order to convert it into an
ammeter of range 0 – 0.5 A ? | [{"identifier": "A", "content": "0.02 ohm"}, {"identifier": "B", "content": "0.2 ohm"}, {"identifier": "C", "content": "0.002 ohm"}, {"identifier": "D", "content": "0.5 ohm"}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264080/exam_images/neabkssdo9r8ikvqvdeg.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 9th April Evening Slot Physics - Current Electricity Question 230 English Explanation"><br><br>
We... | mcq | jee-main-2019-online-9th-april-evening-slot | 9,826 |
jOqz53VZQQm7z1S2BiHUc | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 $$ \times $$ 10<sup>–4</sup> A passes through it, its needle ( pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of : | [{"identifier": "A", "content": "200 ohm"}, {"identifier": "B", "content": "250 ohm"}, {"identifier": "C", "content": "6200 ohm"}, {"identifier": "D", "content": "6250 ohm"}] | ["A"] | null | I<sub>g</sub> = 4 $$ \times $$ 10<sup>$$-$$4</sup> $$ \times $$ 25 = 10<sup>$$-$$2</sup> A
<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263293/exam_images/ircp5doxcaunxz6jbmqc.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Onlin... | mcq | jee-main-2019-online-12th-january-evening-slot | 9,827 |
fmuzQlhzjKN6UggNrS6xP | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | The galvanometer deflection, when key K<sub>1</sub> is closed but K<sub>2</sub> is open, equals $$\theta $$<sub>0</sub> (see figure). On closing K<sub>2</sub> also and adjusting R<sub>2</sub> to 5$$\Omega $$, the deflection in galvanometer becomes $${{{\theta _0}} \over 5}.$$ . The resistance of the galvanometer is, th... | [{"identifier": "A", "content": "5 $$\\Omega $$"}, {"identifier": "B", "content": "25 $$\\Omega $$"}, {"identifier": "C", "content": "12 $$\\Omega $$"}, {"identifier": "D", "content": "22 $$\\Omega $$"}] | ["D"] | null | <b>case I :</b>
<br><br>i<sub>g</sub> = $${E \over {220 + {R_g}}}$$ = C$$\theta $$<sub>0</sub> . . .(i)
<br><br><b>Case II :</b>
<br><br>i<sub>g</sub> = $$\left( {{E \over {220 + {{5{R_g}} \over {5 + {R_g}}}}}} \right)$$ $$ \times $$ $${5 \over {\left( {{R_g} + 5} \right)}}$$ = $${{C{\theta _0}} \ove... | mcq | jee-main-2019-online-12th-january-morning-slot | 9,828 |
73cGZSdMnYzbD7YcVxFVC | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | The actual value of resistance R, shown in the figure is 30$$\Omega $$. This is measuered in an experiment as shown
using the standard formula R = $${V \over {\rm I}}$$, where V and I are the readings of the voltmeter and ammeter, respectively. If the measured value of R is 5% less, then the internal resistance of the ... | [{"identifier": "A", "content": "570 $$\\Omega $$"}, {"identifier": "B", "content": "600 $$\\Omega $$"}, {"identifier": "C", "content": "350 $$\\Omega $$"}, {"identifier": "D", "content": "35 $$\\Omega $$"}] | ["A"] | null | 0.95 R = $${{R{R_v}} \over {R + {R_v}}}$$
<br><br>0.95 $$ \times $$ 30 = 0.05 R<sub>v</sub>
<br><br>R<sub>v</sub> = 19 $$ \times $$ 30 = 570 $$\Omega $$ | mcq | jee-main-2019-online-10th-january-evening-slot | 9,830 |
DAnXq686VdMsqgXco0jgy2xukfl4e626 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer is used in laboratory for
detecting the null point in electrical
experiments. If, on passing a current of 6 mA it
produces a deflection of 2<sup>o</sup>, its figure of merit
is close to : | [{"identifier": "A", "content": "6 $$ \\times $$ 10<sup>\u20133</sup> A/div"}, {"identifier": "B", "content": "666<sup>o</sup> A/div"}, {"identifier": "C", "content": "3 $$ \\times $$ 10<sup>\u20133</sup> A/div"}, {"identifier": "D", "content": "333<sup>o</sup> A/div"}] | ["C"] | null | figure of merit = $${I \over \theta }$$
<br><br>= $${{6 \times {{10}^{ - 3}}} \over 2}$$
<br><br>= 3 $$ \times $$ 10<sup>–3</sup> A/div | mcq | jee-main-2020-online-5th-september-evening-slot | 9,832 |
2iPRjBl8dAyZejKwENjgy2xukf3uaadv | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | Two resistors 400$$\Omega $$ and 800$$\Omega $$ are connected in series across a 6 V battery. The potential difference measured by a voltmeter of 10 k$$\Omega $$ across 400 $$\Omega $$ resistor is close to :
| [{"identifier": "A", "content": "2.05 V"}, {"identifier": "B", "content": "1.95 V"}, {"identifier": "C", "content": "2 V"}, {"identifier": "D", "content": "1.8 V"}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266174/exam_images/imyxmqkvtiuxojy8nxgb.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 3rd September Evening Slot Physics - Current Electricity Question 205 English Explanation">
<br><b... | mcq | jee-main-2020-online-3rd-september-evening-slot | 9,833 |
1yNqnTCFDtdFg02BWMjgy2xukfg9wky8 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer of resistance G is converted
into a voltmeter of range 0 – 1 V by connecting
a resistance R<sub>1</sub> in series with it. The additional
resistance that should be connected in series
with R<sub>1</sub> to increase the range of the voltmeter
to 0 – 2 V will be : | [{"identifier": "A", "content": "G"}, {"identifier": "B", "content": "R<sub>1</sub>"}, {"identifier": "C", "content": "R<sub>1</sub> + G"}, {"identifier": "D", "content": "R<sub>1</sub> - G"}] | ["C"] | null | 1 = i<sub>g</sub>(G + R<sub>1</sub>) ....(1)
<br><br>2 = i<sub>g</sub>(R<sub>1</sub> + R<sub>2</sub> + G) ....(2)
<br><br>Doing (1) $$ \div $$ (2), we get
<br><br>$${1 \over 2} = {{{i_g}\left( {G + {R_1}} \right)} \over {{i_g}\left( {G + {R_1} + {R_2}} \right)}}$$
<br><br>$$ \Rightarrow $$ R<sub>1</sub>
+ R<sub>2</su... | mcq | jee-main-2020-online-5th-september-morning-slot | 9,834 |
uFiuD4Rks8JQ2Ghhra7k9k2k5hgpxmr | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer having a coil resistance
100 $$\Omega $$ gives a full scale deflection when a
current of 1 mA is passed through it. What is
the value of the resistance which can convert
this galvanometer into a voltmeter giving full
scale deflection for a potential difference of
10 V? | [{"identifier": "A", "content": "8.9 k$$\\Omega $$"}, {"identifier": "B", "content": "10 k$$\\Omega $$"}, {"identifier": "C", "content": "9.9 k$$\\Omega $$"}, {"identifier": "D", "content": "7.9 k$$\\Omega $$"}] | ["C"] | null | i<sub>g</sub> = 1 mA , R<sub>g</sub> = 100 $$\Omega $$
<br><br>V = i<sub>g</sub>(R + R<sub>g</sub>)
<br><br>$$ \Rightarrow $$10 = 1 × 10<sup>–3</sup> (R + 100)
<br><br>$$ \Rightarrow $$R = 9.9 k$$\Omega $$ | mcq | jee-main-2020-online-8th-january-evening-slot | 9,835 |
hCuMKiJ47eNOxB05jb1kmlwlddc | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | Consider a 72 cm long wire AB as shown in the figure. The galvanometer jockey is placed at P on AB at a distance x cm from A. The galvanometer shows zero deflection.<br/><br/><img src="data:image/png;base64,UklGRqwJAABXRUJQVlA4IKAJAACwPgCdASoWAcYAPm00lkikIqKhIjILCIANiWlu6B/I6SLZbEeD/5f2sf3HoxvCfST8LDL395/l/8+/33x8/Zv71... | [] | null | 48 | As galvanometer shows zero deflection so it act's as balanced wheatstone bridge.<br><br>$$ \therefore $$ $${{12} \over 6} = {x \over {72 - x}}$$<br><br>$$ \Rightarrow $$ 14 $$-$$ 2x = x<br><br>$$ \Rightarrow $$ 3x = 144<br><br>$$ \Rightarrow $$ x = 48 cm | integer | jee-main-2021-online-18th-march-evening-shift | 9,836 |
1kth5jj8l | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | Consider a galvanometer shunted with 5$$\Omega$$ resistance and 2% of current passes through it. What is the resistance of the given galvanometer ? | [{"identifier": "A", "content": "300 $$\\Omega$$"}, {"identifier": "B", "content": "344 $$\\Omega$$"}, {"identifier": "C", "content": "245 $$\\Omega$$"}, {"identifier": "D", "content": "226 $$\\Omega$$"}] | ["C"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266900/exam_images/mrj18lewipk8cejnns6s.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 31st August Morning Shift Physics - Current Electricity Question 153 English Explanation"><br>0.02... | mcq | jee-main-2021-online-31st-august-morning-shift | 9,838 |
1l54voy1n | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>Two resistors are connected in series across a battery as shown in figure. If a voltmeter of resistance 2000 $$\Omega$$ is used to measure the potential difference across 500 $$\Omega$$ resistor, the reading of the voltmeter will be ___________ V.</p>
<p><img src="data:image/png;base64,UklGRhgKAABXRUJQVlA4IAwKAADQvg... | [] | null | 8 | <p>New $${R_{eff}} = {{2000 \times 500} \over {2500}} + 600\,\Omega = 1000\,\Omega $$</p>
<p>$$\Rightarrow$$ Reading of voltmeter $$ = {{400} \over {1000}} \times 20 = 8$$ volts</p> | integer | jee-main-2022-online-29th-june-evening-shift | 9,839 |
1l56a5oww | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>Current measured by the ammeter (A) in the reported circuit when no current flows through 10 $$\Omega$$ resistance, will be ________________ A.</p>
<p><img src="data:image/png;base64,UklGRtYSAABXRUJQVlA4IMoSAADwGgGdASoAA3ECP4HA2WU2MKynIhGJcsAwCWlu8n1dp00CN+fD6e/4vrBu+WBmINn/284m6HSr3573//rR/QXsd//+pL77EUUlTz0/LGIGKS... | [] | null | 10 | <p>For $${I_{10}} = 0$$</p>
<p>$${R \over 3} = {4 \over 6}$$</p>
<p>$$ \Rightarrow R = 2\,\Omega $$</p>
<p>$$ \Rightarrow {I_A} = {{36 \times (6 + 9)} \over {6 \times 9}}$$</p>
<p>$$ = {{36 \times 15} \over {6 \times 9}} = 10$$ A</p> | integer | jee-main-2022-online-28th-june-morning-shift | 9,840 |
1l57prg1l | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>A 72 $$\Omega$$ galvanometer is shunted by a resistance of 8 $$\Omega$$. The percentage of the total current which passes through the galvanometer is :</p> | [{"identifier": "A", "content": "0.1%"}, {"identifier": "B", "content": "10%"}, {"identifier": "C", "content": "25%"}, {"identifier": "D", "content": "0.25%"}] | ["B"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5jqemdq/c70f58cd-41c8-412b-8e71-6f5c0feb722d/db2a8ee0-02bc-11ed-95db-c3fa9a0f41ba/file-1l5jqemdr.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5jqemdq/c70f58cd-41c8-412b-8e71-6f5c0feb722d/db2a8ee0-02bc-11ed-95db-c3fa9a0f41ba... | mcq | jee-main-2022-online-27th-june-morning-shift | 9,841 |
1l59poesd | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be:</p> | [{"identifier": "A", "content": "$${{KS} \\over {(S + G)}}$$"}, {"identifier": "B", "content": "$${{(G + S)} \\over {nKS}}$$"}, {"identifier": "C", "content": "$${{nKS} \\over {(G + S)}}$$"}, {"identifier": "D", "content": "$${{nK(G + S)} \\over S}$$"}] | ["D"] | null | <p>According to the information, current through galvanometer = nK</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5kpt3dk/2d747c27-da40-45f5-81ac-b01f5f127587/4d249d80-0347-11ed-8429-27c3de0e24ff/file-1l5kpt3dl.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5kpt3dk/2d... | mcq | jee-main-2022-online-25th-june-evening-shift | 9,842 |
1l5al5y8m | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>A teacher in his physics laboratory allotted an experiment to determine the resistance (G) of a galvanometer. Students took the observations for $${1 \over 3}$$ deflection in the galvanometer. Which of the below is true for measuring value of G?</p> | [{"identifier": "A", "content": "$${1 \\over 3}$$ deflection method cannot be used for determining the resistance of the galvanometer."}, {"identifier": "B", "content": "$${1 \\over 3}$$ deflection method can be used and in this case the G equals to twice the value of shunt resistances."}, {"identifier": "C", "content"... | ["B"] | null | <p>The circuit for the given situation is:</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5ky536y/839f6d87-1d8b-48ef-b90e-58dc536e3270/e3be5590-0367-11ed-af51-374257f3e209/file-1l5ky536z.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5ky536y/839f6d87-1d8b-48ef-b90e-58... | mcq | jee-main-2022-online-25th-june-morning-shift | 9,843 |
1l5c2qi47 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>Two identical cells each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20 $$\Omega$$. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell is :</p> | [{"identifier": "A", "content": "2.5 $$\\Omega$$"}, {"identifier": "B", "content": "4 $$\\Omega$$"}, {"identifier": "C", "content": "5 $$\\Omega$$"}, {"identifier": "D", "content": "10 $$\\Omega$$"}] | ["C"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5le9d7o/bb316064-5929-4f7d-9df2-1a7193aea921/ecc98e40-03a6-11ed-b731-675fd498ca49/file-1l5le9d7p.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5le9d7o/bb316064-5929-4f7d-9df2-1a7193aea921/ecc98e40-03a6-11ed-b731-675fd498ca49... | mcq | jee-main-2022-online-24th-june-morning-shift | 9,844 |
1ldnw0rsa | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>Given below are two statements : One is labelled as Assertion $$\mathbf{A}$$ and the other is labelled as Reason $$\mathbf{R}$$.</p>
<p>Assertion A : For measuring the potential difference across a resistance of $$600 \Omega$$, the voltmeter with resistance $$1000 \Omega$$ will be preferred over voltmeter with resis... | [{"identifier": "A", "content": "$$\\mathbf{A}$$ is not correct but $$\\mathbf{R}$$ is correct"}, {"identifier": "B", "content": "Both $$\\mathbf{A}$$ and $$\\mathbf{R}$$ are correct and $$\\mathbf{R}$$ is the correct explanation of $$\\mathbf{A}$$"}, {"identifier": "C", "content": "$$\\mathbf{A}$$ is correct but $$\\m... | ["A"] | null | <p>Assertion A is incorrect because the preferred voltmeter for measuring the potential difference across a resistance of 600 ohm is actually the voltmeter with a higher resistance, not a lower resistance. The reason for this is that when a voltmeter is connected in parallel with the resistance being measured, it will ... | mcq | jee-main-2023-online-1st-february-evening-shift | 9,845 |
ldo69h0d | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | The number of turns of the coil of a moving coil galvanometer is increased in order to increase current sensitivity by $50 \%$. The percentage change in voltage sensitivity of the galvanometer will be : | [{"identifier": "A", "content": "$0 \\%$"}, {"identifier": "B", "content": "$75 \\%$"}, {"identifier": "C", "content": "$100 \\%$"}, {"identifier": "D", "content": "$50 \\%$"}] | ["A"] | null | Current sensitivity $=$ Voltage sensitivity $\times R$
<br/><br/>Current sensitivity is made $1.5$ times.
<br/><br/>$R$ also increase $1.5$ times.
<br/><br/>Hence voltage sensitivity $=\frac{1.5 \times \text { current sensitivity }}{1.5 \times R}$
<br/><br/>$$
=\text { no change }
$$ | mcq | jee-main-2023-online-31st-january-evening-shift | 9,846 |
1ldwqp8xy | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>A cell of emf 90 V is connected across series combination of two resistors each of 100$$\Omega$$ resistance. A voltmeter of resistance 400$$\Omega$$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be :</p> | [{"identifier": "A", "content": "40 V"}, {"identifier": "B", "content": "90 V"}, {"identifier": "C", "content": "45 V"}, {"identifier": "D", "content": "80 V"}] | ["A"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1le4beg6w/f8e46281-d0b4-4633-967d-41b176518f4c/5e1dcf80-ac70-11ed-a551-772121b6ed7f/file-1le4beg6x.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1le4beg6w/f8e46281-d0b4-4633-967d-41b176518f4c/5e1dcf80-ac70-11ed-a551-772121b6ed7f/fi... | mcq | jee-main-2023-online-24th-january-evening-shift | 9,847 |
lgnyj1w1 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | For designing a voltmeter of range $50 \mathrm{~V}$ and an ammeter of range $10 \mathrm{~mA}$ using a galvanometer which has a coil of resistance $54 \Omega$ showing a full scale deflection for $1 \mathrm{~mA}$ as in figure.<br/><br/>
<img src="data:image/png;base64,UklGRkwRAABXRUJQVlA4IEARAABwFAGdASoAA8ECP4HA2mS2MT+nI... | [{"identifier": "A", "content": "$(\\mathrm{A})$ and $(\\mathrm{C})$"}, {"identifier": "B", "content": "(A) and (B)"}, {"identifier": "C", "content": "(C) and (E)"}, {"identifier": "D", "content": "(C) and (D)"}] | ["A"] | null | For voltmeter<br/><br/>
$$
\begin{aligned}
& \mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}_{\mathrm{g}}}-\mathrm{G} \\\\
& =\frac{50}{10^{-3}}-54 \approx 50 \mathrm{k} \Omega~(\mathrm{A})
\end{aligned}
$$<br/><br/>
For ammeter<br/><br/>
$$
\mathrm{S}=\frac{\mathrm{I}_{\mathrm{g}} \mathrm{G}}{\mathrm{I}-\mathrm{I}_{\mathrm{g}... | mcq | jee-main-2023-online-15th-april-morning-shift | 9,848 |
1lgq2vwpw | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>When a resistance of $$5 ~\Omega$$ is shunted with a moving coil galvanometer, it shows a full scale deflection for a current of $$250 \mathrm{~mA}$$, however when $$1050 ~\Omega$$ resistance is connected with it in series, it gives full scale deflection for 25 volt. The resistance of galvanometer is ____________ $$... | [] | null | 50 | Given:
<br/><br/>
$$\frac{250 \ \text{mA} \times 5}{5 + R_G} = i$$
<br/><br/>
$$i = \frac{25}{1050 + R_G}$$
<br/><br/>
Equating the two expressions for current, $$i$$:
<br/><br/>
$$\frac{250 \ \text{mA} \times 5}{5 + R_G} = \frac{25}{1050 + R_G}$$
<br/><br/>
This equation simplifies to:
<br/><br/>
$$100(5 + R_G) = 1050... | integer | jee-main-2023-online-13th-april-morning-shift | 9,849 |
1lgsxtlu7 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>Two identical cells each of emf $$1.5 \mathrm{~V}$$ are connected in series across a $$10 ~\Omega$$ resistance. An ideal voltmeter connected across $$10 ~\Omega$$ resistance reads $$1.5 \mathrm{~V}$$. The internal resistance of each cell is __________ $$\Omega$$.</p> | [] | null | 5 | Let the internal resistance of each cell be $$r$$.
<br/><br/>Since the two cells are connected in series, their internal resistances add up, and the total internal resistance of the series combination is $$2r$$. The total EMF of the series combination of cells is $$1.5\,\text{V} + 1.5\,\text{V} = 3\,\text{V}$$.
<br/... | integer | jee-main-2023-online-11th-april-evening-shift | 9,850 |
1lh30oygz | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>A student is provided with a variable voltage source $$\mathrm{V}$$, a test resistor $$R_{T}=10 ~\Omega$$, two identical galvanometers $$G_{1}$$ and $$G_{2}$$ and two additional resistors, $$R_{1}=10 ~M \Omega$$ and $$R_{2}=0.001 ~\Omega$$. For conducting an experiment to verify ohm's law, the most suitable circuit ... | [{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1lh5oh0dv/48e35e77-3614-4a62-8ebb-fff9e1263f6a/eacc8830-e894-11ed-8179-292e62481b94/file-1lh5oh0dw.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1lh5oh0dv/48e35e77-3614-4a62-8ebb-fff9e1263f6a/eac... | ["C"] | null | For voltage measurement across $R_T$<br/><br/> Voltmeter should have very high resistance <br/><br/>$\Rightarrow R_1$ should be in series with $G_1$ and Ammeter should be having very less resistance<br/><br/> $\Rightarrow R_2$ should be in parallel with $G_2$ | mcq | jee-main-2023-online-6th-april-evening-shift | 9,852 |
1lh31jio0 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>As shown in the figure, the voltmeter reads $$2 \mathrm{~V}$$ across $$5 ~\Omega$$ resistor. The resistance of the voltmeter is _________ $$\Omega$$.</p>
<p><img src="data:image/png;base64,UklGRvwJAABXRUJQVlA4IPAJAADwsgCdASoAAxQCP4HA22U2MS2nIVNZUsAwCWlu4W8CVmNwvx6ijefb6pVqqX//9Wf9GHBe8L3he4v1NWTIykVXJuYF+2nCU6mGYQzC... | [] | null | 20 | $$
i_1=\frac{2 V}{5 \Omega}=\frac{2}{5} \mathrm{~A}
$$<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lmjxha88/dbca81e0-fad9-423b-a82c-f2d110479be3/328d0170-5368-11ee-a24f-c39988942e14/file-6y3zli1lmjxha89.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lmjxh... | integer | jee-main-2023-online-6th-april-evening-shift | 9,853 |
lsan7lov | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | In an ammeter, $5 \%$ of the main current passes through the galvanometer. If resistance of the galvanometer is $\mathrm{G}$, the resistance of ammeter will be : | [{"identifier": "A", "content": "$199 \\mathrm{~G}$"}, {"identifier": "B", "content": "$200 \\mathrm{~G}$"}, {"identifier": "C", "content": "$\\frac{G}{20}$"}, {"identifier": "D", "content": "$\\frac{\\mathrm{G}}{199}$"}] | ["C"] | null | <p>When an ammeter is designed, a shunt resistor ($R_s$) is placed in parallel with the galvanometer to ensure that only a small fraction of the total current passes through the galvanometer itself. This is done because the galvanometer is usually a sensitive instrument designed to measure small currents, and passing a... | mcq | jee-main-2024-online-1st-february-evening-shift | 9,854 |
lsbkwr5w | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | A galvanometer has a resistance of $50 ~\Omega$ and it allows maximum current of $5 \mathrm{~mA}$. It can be converted into voltmeter to measure upto $100 \mathrm{~V}$ by connecting in series a resistor of resistance : | [{"identifier": "A", "content": "$19500 \\Omega$"}, {"identifier": "B", "content": "$5975 \\Omega$"}, {"identifier": "C", "content": "$20050 \\Omega$"}, {"identifier": "D", "content": "$19950 \\Omega$"}] | ["D"] | null | <p>To convert a galvanometer into a voltmeter to measure higher voltages, you need to add a series resistance to it. Let's figure out the required resistance value.</p>
<p>First, let's find the maximum voltage that can be directly measured by the galvanometer without any additional resistance. We know the maximum curr... | mcq | jee-main-2024-online-1st-february-morning-shift | 9,855 |
jaoe38c1lscpoor2 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>A current of $$200 \mu \mathrm{A}$$ deflects the coil of a moving coil galvanometer through $$60^{\circ}$$. The current to cause deflection through $$\frac{\pi}{10}$$ radian is :</p> | [{"identifier": "A", "content": "120 $$\\mu$$A"}, {"identifier": "B", "content": "180 $$\\mu$$A"}, {"identifier": "C", "content": "30 $$\\mu$$A"}, {"identifier": "D", "content": "60 $$\\mu$$A"}] | ["D"] | null | <p>$$\mathrm{i} \propto \theta$$ (angle of deflection)</p>
<p>$$\begin{aligned}
& \therefore \frac{\mathrm{i}_2}{\mathrm{i}_1}=\frac{\theta_2}{\theta_1} \Rightarrow \frac{\mathrm{i}_2}{200 \mu \mathrm{A}}=\frac{\pi / 10}{\pi / 3}=\frac{3}{10} \\
& \Rightarrow \mathrm{i}_2=60 \mu \mathrm{A}
\end{aligned}$$</p> | mcq | jee-main-2024-online-27th-january-evening-shift | 9,856 |
jaoe38c1lsf144o3 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>The deflection in moving coil galvanometer falls from 25 divisions to 5 division when a shunt of $$24 \Omega$$ is applied. The resistance of galvanometer coil will be :</p> | [{"identifier": "A", "content": "$$48 \\Omega$$\n"}, {"identifier": "B", "content": "$$100 \\Omega$$\n"}, {"identifier": "C", "content": "$$96 \\Omega$$\n"}, {"identifier": "D", "content": "$$12 \\Omega$$"}] | ["C"] | null | <p>Let x = current/division</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lt2toclz/fdc1cef0-c338-481f-b621-896a016be062/8326ae70-d495-11ee-a613-e11ae62575eb/file-1lt2tocm0.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lt2toclz/fdc1cef0-c338-481f-b621-896a016be062/8326... | mcq | jee-main-2024-online-29th-january-morning-shift | 9,857 |
jaoe38c1lsf18uwe | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>A galvanometer having coil resistance $$10 \Omega$$ shows a full scale deflection for a current of $$3 \mathrm{~mA}$$. For it to measure a current of $$8 \mathrm{~A}$$, the value of the shunt should be:</p> | [{"identifier": "A", "content": "$$3.75 \\times 10^{-3} \\Omega$$\n"}, {"identifier": "B", "content": "$$3 \\times 10^{-3} \\Omega$$\n"}, {"identifier": "C", "content": "$$4.85 \\times 10^{-3} \\Omega$$\n"}, {"identifier": "D", "content": "$$2.75 \\times 10^{-3} \\Omega$$"}] | ["A"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lt2thne5/2f5730dc-195f-4232-8eab-2f5be126e174/c8d0f5d0-d494-11ee-a613-e11ae62575eb/file-1lt2thne6.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lt2thne5/2f5730dc-195f-4232-8eab-2f5be126e174/c8d0f5d0-d494-11ee-a613-e11ae62575eb... | mcq | jee-main-2024-online-29th-january-morning-shift | 9,858 |
luxwer61 | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>To determine the resistance (R) of a wire, a circuit is designed below. The $$V$$-$$I$$ characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of $R$ is _________ $$\Omega$$.</p>
<p><img src="data:image/png;base64,UklGRtgNAABXRUJQVlA4IMwNAAAQtwCdASrE... | [] | null | 2500 | <p>$$\begin{aligned}
& R_{\text {net }}=\frac{1}{\text { Slope }}=\frac{8}{4} \times 10^3=2 \times 10^3 \\
& \Rightarrow 2=\frac{10 R}{10+R} \\
& \Rightarrow 20+2 R=10 R \\
& \Rightarrow 8 R=20 \\
& \Rightarrow R=2.5 \mathrm{k} \Omega \\
& \quad=2500 ~\Omega
\end{aligned}$$</p> | integer | jee-main-2024-online-9th-april-evening-shift | 9,860 |
luy9clvj | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>A galvanometer has a coil of resistance $$200 \Omega$$ with a full scale deflection at $$20 \mu \mathrm{A}$$. The value of resistance to be added to use it as an ammeter of range $$(0-20) \mathrm{mA}$$ is :</p> | [{"identifier": "A", "content": "$$0.40\\Omega$$"}, {"identifier": "B", "content": "$$0.10\\Omega$$"}, {"identifier": "C", "content": "$$0.20\\Omega$$"}, {"identifier": "D", "content": "$$0.50\\Omega$$"}] | ["C"] | null | <p>To convert a galvanometer into an ammeter, we need to add a shunt resistance in parallel with the galvanometer's coil. The purpose of the shunt resistance is to bypass the majority of the current while allowing only a small fraction of it to pass through the galvanometer, thereby preventing it from being damaged by ... | mcq | jee-main-2024-online-9th-april-morning-shift | 9,861 |
lv7v4rep | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>In the experiment to determine the galvanometer resistance by half-deflection method, the plot of $$1 / \theta$$ vs the resistance (R) of the resistance box is shown in the figure. The figure of merit of the galvanometer is _________ $$\times 10^{-1} \mathrm{~A} /$$ division. [The source has emf $$2 \mathrm{~V}$$]</... | [] | null | 5 | <p>$$\frac{1}{3} \mathrm{~A} \longrightarrow \frac{1}{2} \mathrm{div}$$</p>
<p>$$\frac{1}{2} \mathrm{~A} \longrightarrow \frac{2}{3} \mathrm{div}$$</p>
<p>$$\text { Figure of merit }=\frac{\Delta i}{\Delta \theta} \quad \begin{aligned}
& \frac{\frac{1}{2}--}{\frac{2}{3}-\frac{1}{2}} \\
&=0.5 \\
&=5 \times 10^{-1} \math... | integer | jee-main-2024-online-5th-april-morning-shift | 9,862 |
lvb2acqd | physics | current-electricity | galvanometer,-voltmeter-and-ammeter | <p>In the given figure an ammeter A consists of a $$240 \Omega$$ coil connected in parallel to a $$10 \Omega$$ shunt. The reading of the ammeter is ________ $$\mathrm{mA}$$.</p>
<p><img src="data:image/png;base64,UklGRswIAABXRUJQVlA4IMAIAAAwlwCdASoAA90BP4HA22W2MK2poVJpIsAwCWlu4XJyQmNwvV6jtQbO7uNxRkKnzlVOf/3rJI/TBHkSU0J... | [] | null | 160 | <p>$$\begin{aligned}
& i=\frac{24}{140 \cdot 4+r_A}=\frac{24}{140 \cdot 4+9 \cdot 6}=0.16 \mathrm{~A} \\
& i=160 \mathrm{~mA}
\end{aligned}$$</p> | integer | jee-main-2024-online-6th-april-evening-shift | 9,864 |
bk5sv78J3L0z0cRc | physics | current-electricity | kirchhoff's-circuit-laws | A $$3$$ volt battery with negligible internal resistance is connected in a circuit as shown in the figure. The current $${\rm I}$$, in the circuit will be
<img src="data:image/png;base64,UklGRmINAABXRUJQVlA4IFYNAADQhACdASpOAqIBP4G81mY2LqwnIbFZWsAwCWlu4XExG/P58vdpWNjaD9hf7jxtz2hwFhd4HffTWUzzXfd/cf/pwFRIBmqTJDLxtqKVTG2o... | [{"identifier": "A", "content": "$$1$$ $$A$$ "}, {"identifier": "B", "content": "$$1.5$$ $$A$$ "}, {"identifier": "C", "content": "$$2$$ $$A$$ "}, {"identifier": "D", "content": "$$1/3$$ $$A$$ "}] | ["B"] | null | <img class="question-image" src="https://imagex.cdn.examgoal.net/WDpUoLOV1yODn3cHp/gkAzIxmP1qLqw8qxt7HOmTSYya4pF/wozCWi0bu2kWOTn6cRTc1r/image.svg" loading="lazy" alt="AIEEE 2003 Physics - Current Electricity Question 322 English Explanation">
<br><br>$${R_p} = {{3 \times 6} \over {3 + 6}} = {{18} \over 9} = 2\Omega $$
... | mcq | aieee-2003 | 9,865 |
BjQ6wonD4UOIAkoa | physics | current-electricity | kirchhoff's-circuit-laws | An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengths and radii are in the ratio of $${4 \over 3}$$ and $${2 \over 3}$$, then the ratio of the current passing through the wires will be | [{"identifier": "A", "content": "$$8/9$$ "}, {"identifier": "B", "content": "$$1/3$$ "}, {"identifier": "C", "content": "$$3$$ "}, {"identifier": "D", "content": "$$2$$ "}] | ["B"] | null | <img class="question-image" src="https://imagex.cdn.examgoal.net/jr80KlmMStRLVuRaq/YUFjVqeck4OZIBsyzblcm0nH7RhKK/nheUeoJQOmHkvoJmCI3rct/image.svg" loading="lazy" alt="AIEEE 2004 Physics - Current Electricity Question 318 English Explanation">
<br><br>$${i_1}{R_1} = {i_2}{R_2}\,\,\,\,\,\,\,\,\,\,$$ (same potential diffe... | mcq | aieee-2004 | 9,866 |
wQpXFlq3svQh5PjV | physics | current-electricity | kirchhoff's-circuit-laws | The total current supplied to the circuit by the battery is
<img src="data:image/png;base64,UklGRiYRAABXRUJQVlA4IBoRAAAQgQCdASrzAWsBP4HA12U2MCsnItMZgsAwCWlu/HyY4OtQ2v1M/1HcV4M6xu720i7EeAE6rtAsSvBL+51o889/6eT/94/93AwFzvkwqL8mFRfkwqL8mFRfkwqL8mFRfkwqL8mFRfkwqL8mFRfkpTE8b/8Df+rLsq9G7EPNB7b5VzybrNK/tsNhlusO1UkUA8IwqL8mBEJ... | [{"identifier": "A", "content": "$$4A$$ "}, {"identifier": "B", "content": "$$2A$$ "}, {"identifier": "C", "content": "$$1A$$ "}, {"identifier": "D", "content": "$$6A$$ "}] | ["A"] | null | <img class="question-image" src="https://imagex.cdn.examgoal.net/MeHEGOc0Be3TDbNru/K3Lobapl9WCmadFJ4SR4Vi1NgVNvW/D26kkCzPXrnrAAOSLjSKGv/image.svg" loading="lazy" alt="AIEEE 2004 Physics - Current Electricity Question 320 English Explanation">
<br><br>hence $${{\mathop{\rm R}\nolimits} _{eq}} = 3/2;$$
<br><br>$$\theref... | mcq | aieee-2004 | 9,868 |
kZl0WVkqCMamH0EY | physics | current-electricity | kirchhoff's-circuit-laws | Two sources of equal $$emf$$ are connected to an external resistance $$R.$$ The internal resistance of the two sources are $${R_1}$$ and $${R_2}\left( {{R_1} > {R_1}} \right).$$ If the potential difference across the source having internal resistance $${R_2}$$ is zero, then | [{"identifier": "A", "content": "$$R = {R_2} - {R_1}$$ "}, {"identifier": "B", "content": "$$R = {R_2} \\times \\left( {{R_1} + {R_2}} \\right)/\\left( {{R_2} - {R_1}} \\right)$$ "}, {"identifier": "C", "content": "$$R = {R_1}{R_2}/\\left( {{R_2} - {R_1}} \\right)$$ "}, {"identifier": "D", "content": "$$R = {R_1}{R_2}/... | ["A"] | null | <img class="question-image" src="https://imagex.cdn.examgoal.net/0RRrcFySZ6JcNyEdf/1H3KDfGLejP8HICSLTHRp6q7v3uW4/qrXU67CSqnnQhJWBuZMeWj/image.svg" loading="lazy" alt="AIEEE 2005 Physics - Current Electricity Question 310 English Explanation">
<br><br>$${\rm I} = {{2\varepsilon } \over {R + {R_1} + {R_2}}}$$
<br><br>Pot... | mcq | aieee-2005 | 9,869 |
WTMNsN9U9rwTubZG | physics | current-electricity | kirchhoff's-circuit-laws | A $$5V$$ battery with internal resistance $$2\Omega $$ and a $$2V$$ battery with internal resistance $$1\Omega $$ are connected to a $$10\Omega $$ resistor as shown in the figure.
<img src="data:image/png;base64,UklGRmIIAABXRUJQVlA4IFYIAACQXwCdASoaAmoBP4G+12Y2LywnITOZSsAwCWlu4XMlEmNwvj5A/0e4HYKF1d+spEG+yJlYE8f3zv3Tfdh... | [{"identifier": "A", "content": "$$0.27A{P_2}\\,\\,to\\,\\,{P_1}$$ "}, {"identifier": "B", "content": "$$0.03A{P_1}\\,\\,to\\,\\,{P_2}$$ "}, {"identifier": "C", "content": "$$0.03A{P_2}\\,\\,to\\,\\,{P_1}$$ "}, {"identifier": "D", "content": "$$0.27A{P_1}\\,\\,to\\,\\,{P_2}$$ "}] | ["C"] | null | Applying kirchoff's loop law in $$AB\,{P_2}{P_1}A$$ we get
<br><br>$$ - 2i + 5 - 10\,{i_1} = 0\,\,\,\,\,\,\,\,...\left( i \right)$$
<br><br><picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264461/exam_images/zs697mtdzjwfucbnooao.webp"><source media="(max-width:... | mcq | aieee-2008 | 9,870 |
fYVSRq9Yd8YfaqJO | physics | current-electricity | kirchhoff's-circuit-laws | <img src="data:image/png;base64,UklGRpALAABXRUJQVlA4IIQLAAAwtwCdASoAA9gBP4HA22U2MK2nIhLpOsAwCWlu/FuY3HYnZ1+fsvuZ2WNu7ufxMkJv0VVJf//rJK2Htl/vupw1QVODpYxHbgnr9v9BT2zAHdP2/0FPbMAd048pJVbBjUripLuU0/GrqqY98jCYKl2AurxSSq3jVe0XlJKreNV7ReUkqt8opJVbvqnf46dK7eag8YjwiQeyAtNjhZ63KSVW72aUo0vOhcH+Tii7tuhemCGrRS5uZTm9c6GywDFKreNV7ReU... | [{"identifier": "A", "content": "$$0.13$$ $$A,$$ from $$Q$$ to $$P$$ "}, {"identifier": "B", "content": "$$0.13$$ $$A$$, from $$P$$ to $$Q$$ "}, {"identifier": "C", "content": "$$1.3A$$ from $$P$$ to $$Q$$ "}, {"identifier": "D", "content": "$$0A$$ "}] | ["A"] | null | From $$KVL$$
<br><br>$$ - 6 + 3{{\rm I}_1} + {\rm 1}\left( {{{\rm I}_1} - {{\rm I}_2}} \right) = 0$$
<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l91f47um/350b1501-6062-49f3-9f33-e2d7cbb1899a/77416de0-47db-11ed-8284-6d7e98c66709/file-1l91f47un.png?format=png" data-orsrc="https://app-content.... | mcq | jee-main-2015-offline | 9,871 |
q6enrJemho3wyLDd | physics | current-electricity | kirchhoff's-circuit-laws | <img src="data:image/png;base64,UklGRmwJAABXRUJQVlA4IGAJAACQfwCdASoAAx8BP4HA12O2MTimohT6exAwCWlu8oU9lEHCN+fP5qtB8fr21dqcvy3/59slF5/4/YytPNlU+OvUSB5cZ6X2OtEpy/yPsGTlxklfHHyb4S+BdWBOnAwDjjHTjIeyyzQN+Tlxs1gWmyRsZtZ5FhTpiApbOUGeQfgLCCxoG/JvT6VA5N2hasHHkMDAlgcoFj8vJ8aChT/VBgCK8Mm88VKCrccBUSYqJL9A3yS95OtEWNkkrY2V4saBvycuM3yL... | [{"identifier": "A", "content": "0 A"}, {"identifier": "B", "content": "1 A"}, {"identifier": "C", "content": "0.25 A"}, {"identifier": "D", "content": "0.5 A "}] | ["A"] | null | The potential difference in each loop is zero.
<br><br>$$ \therefore $$ No current will flow or current in each resistance is
Zero. | mcq | jee-main-2017-offline | 9,873 |
5NHEvSOiSFvXpiKu | physics | current-electricity | kirchhoff's-circuit-laws | Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10 $$\Omega $$. The
internal resistances of the two batteries are 1 $$\Omega $$ and 2 $$\Omega $$ respectively. The voltage across the load lies between : | [{"identifier": "A", "content": "11.7 V and 11.8 V"}, {"identifier": "B", "content": "11.6 V and 11.7 V"}, {"identifier": "C", "content": "11.5 V and 11.6 V"}, {"identifier": "D", "content": "11.4 V and 11.5 V"}] | ["C"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265437/exam_images/f6vvbufkzrapliec7lo3.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Offline) Physics - Current Electricity Question 284 English Explanation">
<br><br>Let potential at S, T,... | mcq | jee-main-2018-offline | 9,874 |
zRg9MTlDllqP6aOUQKNiO | physics | current-electricity | kirchhoff's-circuit-laws | In the given circuit the cells have zero internal resistance. The currents (in Amperes) passing through resistance R<sub>1</sub> and R<sub>2</sub> respectively, are -
<br/><br/><img src="data:image/png;base64,UklGRrYPAABXRUJQVlA4IKoPAACQvgCdASoAA8oBP4G+1mW2L6wnIbJJwsAwCWlu/HyY+UpHZ19/rF/qe5baBsOfy25l7K/mmoZuCPa3Orw2/oN... | [{"identifier": "A", "content": "0.5, 0"}, {"identifier": "B", "content": "0, 1"}, {"identifier": "C", "content": "1, 2"}, {"identifier": "D", "content": "2, 2"}] | ["A"] | null | i<sub>1</sub> = $${{10} \over {20}}$$ = 0.5A
<br><br>i<sub>2</sub> = 0 | mcq | jee-main-2019-online-10th-january-morning-slot | 9,875 |
BCgVi1aNjcgze3ip7BOFl | physics | current-electricity | kirchhoff's-circuit-laws | In the figure shown, what is the current
(in Ampere) drawn from the battery ?<br/> You are
given:
R<sub>1</sub> = 15$$\Omega $$, R<sub>2</sub> = 10 $$\Omega $$, R<sub>3</sub> = 20 $$\Omega $$, R<sub>4</sub> = 5$$\Omega $$,
R<sub>5</sub> = 25$$\Omega $$, R<sub>6</sub> = 30 $$\Omega $$, E = 15 V
<img src="data:image/png;... | [{"identifier": "A", "content": "13/24"}, {"identifier": "B", "content": "7/18"}, {"identifier": "C", "content": "9/32"}, {"identifier": "D", "content": "20/3"}] | ["C"] | null | Equivalent resistance of the given circuit<br><br>
$${R_{eq}} = 45 + {{10 \times 50} \over {10 + 50}} = \left( {45 + {{50} \over 6}} \right)\Omega $$<br><br>
$$ \Rightarrow $$ $${{160} \over 3}\Omega $$<br><br>
$$ \therefore $$ $$I = {{15} \over {{{160} \over 3}}} = {9 \over {32}}A$$ | mcq | jee-main-2019-online-8th-april-evening-slot | 9,876 |
kgAMpEEtwe7r04rGmKKYn | physics | current-electricity | kirchhoff's-circuit-laws | In the given circuit diagram, the currents, I<sub>1</sub> = – 0.3 A, I<sub>4</sub> = 0.8 A and I<sub>5</sub> = 0.4 A, are flowing as shown. The currents I<sub>2</sub>, I<sub>3</sub> and I<sub>6</sub>, respectively, are :
<br/><br/><img src="data:image/png;base64,UklGRsAUAABXRUJQVlA4ILQUAACQ0QCdASoAA7EBP4G+12U2MCwnIjPJ... | [{"identifier": "A", "content": "1.1 A, \u2013 0.4 A, 0.4 A"}, {"identifier": "B", "content": "$$-$$ 0.4 A, 0.4 A, 1.1 A"}, {"identifier": "C", "content": "0.4 A, 1.1 A, 0.4 A"}, {"identifier": "D", "content": "1.1 A, 0.4 A, 0.4 A"}] | ["D"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265548/exam_images/od8nvktmqs5vrljqzgfa.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 12th January Evening Slot Physics - Current Electricity Question 239 English Explanation">
<br><... | mcq | jee-main-2019-online-12th-january-evening-slot | 9,877 |
M8TdbxuObbPsPtHBaZJhg | physics | current-electricity | kirchhoff's-circuit-laws | In the given circuit the the internal resistance of the 18 V cell is negligible. If R<sub>1</sub> = 400 $$\Omega $$, R<sub>3</sub> = 100 $$\Omega $$ and R<sub>4</sub> = 500 $$\Omega $$ and the reading of an ideal voltmeter across R<sub>4</sub> is 5V, then the value of R<sub>2</sub> will be :
<br/><br/><img src="data:i... | [{"identifier": "A", "content": "300 $$\\Omega $$"}, {"identifier": "B", "content": "450 $$\\Omega $$"}, {"identifier": "C", "content": "550 $$\\Omega $$"}, {"identifier": "D", "content": "230 $$\\Omega $$"}] | ["A"] | null | Voltage accross resistance R<sub>4</sub> = 5 V
<br><br>$$ \therefore $$ IR<sub>4</sub> = 5 V
<br><br>$$ \Rightarrow $$ 500 $$ \times $$ I = 5
<br><br>$$ \Rightarrow $$ I = $${1 \over {100}}$$ A
<br><br>$$ \therefore $$ Voltage across resistor R<sub>3</... | mcq | jee-main-2019-online-9th-january-evening-slot | 9,878 |
VN4FR7NapTMf20BEkmKKp | physics | current-electricity | kirchhoff's-circuit-laws | When the switch S, in the circuit shown, is closed, then the value of current i will be :
<br/><br/><img src="data:image/png;base64,UklGRn4MAABXRUJQVlA4IHIMAACwsgCdASoAA80BP4HA3GW2MK2nIbRo+sAwCWlu6B/I3KLZb4+g/9JHZ+4fdk30IYrdJ//nqWIg1qTkXF70uSQlld0NZk7bm7OSifyAHqlldzq+iPPMdvjKQWAg7T6OFeiWFrvUhPf3POv5+t8RDD1mGVgb8KQLC... | [{"identifier": "A", "content": "3A "}, {"identifier": "B", "content": "5A"}, {"identifier": "C", "content": "4A"}, {"identifier": "D", "content": "2A"}] | ["B"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l8mgbjaf/b19e2c43-c07e-46de-97fd-b3e0e3d8c1fd/6a24d770-3fa0-11ed-835d-8b6c97a43374/file-1l8mgbjag.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l8mgbjaf/b19e2c43-c07e-46de-97fd-b3e0e3d8c1fd/6a24d770-3fa0-11ed-835d-8b6c97a43374/fi... | mcq | jee-main-2019-online-9th-january-morning-slot | 9,879 |
8ypOZGsRiLM86zl85D7k9k2k5if4zch | physics | current-electricity | kirchhoff's-circuit-laws | In the given circuit diagram, a wire is joining
points B and D. The current in this wire is :
<img src="data:image/png;base64,UklGRvIJAABXRUJQVlA4IOYJAAAwPQCdASr6AK0APm00lkikIqIhIdM7OIANiWlu3WBpBKv5x+KHgX/a/tX7Kr1N+o/tHtqvbe+8/y/+of8D+q+zn+H8K+AR6p/zv8k/pflp/wH8A/pvh3Vu9AL25+if6P+T/zfx4P7H+Tf2H2U+oHmUf7f+T/1z0hP9v5QHin... | [{"identifier": "A", "content": "4 A"}, {"identifier": "B", "content": "2 A"}, {"identifier": "C", "content": "zero"}, {"identifier": "D", "content": "0.4 A"}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263424/exam_images/yihidsxipwypbj70617k.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 9th January Morning Slot Physics - Current Electricity Question 211 English Explanation 1">
<img s... | mcq | jee-main-2020-online-9th-january-morning-slot | 9,881 |
y6HsW4H9jYlQ4ErzREjgy2xukfl3bysw | physics | current-electricity | kirchhoff's-circuit-laws | In the circuit, given in the figure currents in
different branches and value of one resistor are
shown. Then potential at point B with respect to
the point A is :
<img src="data:image/png;base64,UklGRkARAABXRUJQVlA4IDQRAACQXwCdASqMAcQAPm00lkikIqIhIxEagIANiWlu4WsBG/OB8I/xf8gvMV+w/1z+nfsp/YfUP8V+WfrX9V/Z7+x/+L/LfAD/IdG7/... | [{"identifier": "A", "content": "+2 V"}, {"identifier": "B", "content": "-2 V"}, {"identifier": "C", "content": "+1 V"}, {"identifier": "D", "content": "-1 V"}] | ["C"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266844/exam_images/bx3ccwgybqqdlckekmw7.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 5th September Evening Slot Physics - Current Electricity Question 200 English Explanation">
<br>Le... | mcq | jee-main-2020-online-5th-september-evening-slot | 9,883 |
xagL93oSnBFOeei4jV1klt3taxm | physics | current-electricity | kirchhoff's-circuit-laws | A current of 6A enters one corner P of an equilateral triangle PQR having 3 wires of resistance 2$$\Omega$$ each and leaves by the corner R. The currents i<sub>1</sub> in ampere is _________.<br/><br/><img src="data:image/png;base64,UklGRiwMAABXRUJQVlA4ICAMAABwQACdASq4AN4APm00lkikIqIhIdHK6IANiWlu3WBpKV+hv8u/GDwP/tX5EeJ... | [] | null | 2 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267809/exam_images/szhgdj0dmv77ozjkyvlb.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 25th February Evening Shift Physics - Current Electricity Question 192 English Explanation">
<br>T... | integer | jee-main-2021-online-25th-february-evening-slot | 9,885 |
xr971ORaNsOaj5Pm4z1kmhpddrb | physics | current-electricity | kirchhoff's-circuit-laws | In the figure given, the electric current flowing through the 5 k$$\Omega$$ resistor is 'x' mA.<br/><br/><img src="data:image/png;base64,UklGRhALAABXRUJQVlA4IAQLAACQRACdASocAcIAPm02lkikIqIhIfW6mIANiWlu4XHhG/OZ8IfyH8e/Db+xfkz56/h/zL+C/K/0wv4DaP/V/7Z/Qf3D/sfz7/UP8B4T+63UC9Y/47+S/0/yc/67+bd2LT7/L+oR3E/0n8m/tn/L/pnnwfunoB9... | [] | null | 3 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263933/exam_images/yshfkjb3v5zdojpssvpp.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 16th March Morning Shift Physics - Current Electricity Question 187 English Explanation">
<br>$$I ... | integer | jee-main-2021-online-16th-march-morning-shift | 9,886 |
1krsxt8cy | physics | current-electricity | kirchhoff's-circuit-laws | In an electric circuit, a cell of certain emf provides a potential difference of 1.25 V across a load resistance of 5$$\Omega$$. However, it provides a potential difference of 1 V across a load resistance of 2$$\Omega$$. The emf of the cell is given by $${x \over {10}}V$$. Then the value of x is ______________. | [] | null | 15 | <picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263888/exam_images/mbbgq51yxtx3fimfnotd.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265429/exam_images/h1outmndt9p0lthtipky.webp"><source media="(max-wid... | integer | jee-main-2021-online-22th-july-evening-shift | 9,888 |
1krwcbx8s | physics | current-electricity | kirchhoff's-circuit-laws | A 16 $$\Omega$$ wire is bend to form a square loop. A 9V supply having internal resistance of 1$$\Omega$$ is connected across one of its sides. The potential drop across the diagonals of the square loop is _______________ $$\times$$ 10<sup>$$-$$1</sup> V | [] | null | 45 | Here assume current as<br><br> <picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267592/exam_images/kavkafnakbtq1jptaxkw.webp"><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266691/exam_images/e2bxfllirpxwwrddn7d... | integer | jee-main-2021-online-25th-july-evening-shift | 9,889 |
1ks1ancr3 | physics | current-electricity | kirchhoff's-circuit-laws | For the circuit shown, the value of current at time t = 3.2 s will be _________ A.<br/><br/><picture><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266759/exam_images/gj2advbatxo5ds6g0eu3.webp"/><source media="(max-width: 500px)" srcset="https://res.cloudinary.com/dckx... | [] | null | 1 | From graph voltage at t = 3.2 sec is 6 volt.<br><br><img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263513/exam_images/k7lnmksbxbdee3bzsoli.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 27th July Evening Shift Physics - Current Elec... | integer | jee-main-2021-online-27th-july-evening-shift | 9,890 |
1l55m2mrd | physics | current-electricity | kirchhoff's-circuit-laws | <p>All resistances in figure are 1 $$\Omega$$ each. The value of current 'I' is $${a \over 5}$$ A. The value of a is _________.</p>
<p> <img src="data:image/png;base64,UklGRiQSAABXRUJQVlA4IBgSAADw1ACdASoAA5wBP4G61WU2LiunIbFKisAwCWlu4W5RymNwur85/wve+1l2/X9P3cO2V3S7sG/sEE3eenXyVTyv/36okN7/RYwDflj36Pf5u1TWwaOEpVQMDnAoJheE... | [] | null | 8 | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5hwixco/671ee0f8-017a-426d-9d9e-8ad7a9480443/385a7d80-01bb-11ed-85a8-43d162d2b7e8/file-1l5hwixcp.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5hwixco/671ee0f8-017a-426d-9d9e-8ad7a9480443/385a7d80-01bb-11ed-85a8-43d162d2b7e8... | integer | jee-main-2022-online-28th-june-evening-shift | 9,892 |
1l6e0745z | physics | current-electricity | kirchhoff's-circuit-laws | <p>In the given figure, the value of V<sub>o</sub> will be _____________ V.</p>
<p><img src="data:image/png;base64,UklGRiQPAABXRUJQVlA4IBgPAADw6wCdASoAA3ACP4HA22U2ML+nIjMJM/AwCWlu/BV3DDKnZ1+/sPan493uE/qO5J34fXNgPeuo9POn/+7/97P///rwK/+B12uWIUNcrJRj15wntSEqHmxFsj+WvRAyjGTW2HKT0FRbLymzqkko3NQjq2HXJMhmX1KUy2dJAOWC4slgPzQJ/... | [] | null | 4 | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l6td2rja/87f2855f-5c1e-4f75-9c47-f345314cf779/c8a1d860-1bd4-11ed-bd9f-71db3a4811b2/file-1l6td2rjb.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l6td2rja/87f2855f-5c1e-4f75-9c47-f345314cf779/c8a1d860-1bd4-11ed-bd9f-71db3a4811b2... | integer | jee-main-2022-online-25th-july-morning-shift | 9,893 |
1l6f4y8xg | physics | current-electricity | kirchhoff's-circuit-laws | <p>A current of 15 mA flows in the circuit as shown in figure. The value of potential difference between the points A and B will be:</p>
<p><img src="data:image/png;base64,UklGRiYRAABXRUJQVlA4IBoRAADQHQGdASrwAgADP4HA22U2MT+nIdIZI/AwCWlu/DRcEVlKSY3C9Xqb0R3S+/Xu33WvW0hKq/+dgZOf//rMJ/tWRLRbfY5UhLB4EERW26XzYx3GL/IEJT1yWlot... | [{"identifier": "A", "content": "50 V"}, {"identifier": "B", "content": "75 V"}, {"identifier": "C", "content": "150 V"}, {"identifier": "D", "content": "275 V"}] | ["D"] | null | <p>Effective $$R = \left[ {5 + {{5 \times 10} \over {5 + 10}} + 10} \right]\,k\Omega $$</p>
<p>$$ = {{275} \over {15}}k\Omega $$</p>
<p>$$ \Rightarrow \Delta {V_{AB}} = 15\,mA \times {{275} \over {15}}k\Omega $$</p>
<p>$$ = 275$$ V</p> | mcq | jee-main-2022-online-25th-july-evening-shift | 9,894 |
1ldnzxarl | physics | current-electricity | kirchhoff's-circuit-laws | <p>In the given circuit, the value of $$\left| {{{{\mathrm{I_1}} + {\mathrm{I_3}}} \over {{\mathrm{I_2}}}}} \right|$$ is _____________</p>
<p><img src="data:image/png;base64,UklGRoYOAABXRUJQVlA4IHoOAAAQ6ACdASoAA1oCP4HA2WS2MKynIXMqAsAwCWlu8n63gMr+XARTnUNz9mvRlcHcfuI+6fdg9XOCB3yqmf//1nmwLP6Ydy5jfLWRbyUKtv4kWt4+zEB4V0E6DB... | [] | null | 2 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1le4aptpb/234a3036-645b-46ab-98c0-49b5318c7850/b1531be0-ac6d-11ed-9df5-039d8e7e7857/file-1le4aptpc.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1le4aptpb/234a3036-645b-46ab-98c0-49b5318c7850/b1531be0-ac6d-11ed-9df5-039d8e7e7857/fi... | integer | jee-main-2023-online-1st-february-evening-shift | 9,895 |
1ldr2sbbw | physics | current-electricity | kirchhoff's-circuit-laws | <p>In the following circuit, the magnitude of current I<sub>1</sub>, is ___________ A.</p>
<p><img src="data:image/png;base64,UklGRrAQAABXRUJQVlA4IKQQAACwEQGdASrlAgADP4HA2mS2MLqnIfP5k1AwCWlu/AeM8LOFxMbher0f/sN3Nh67e5hxvr0MjJL//9VBmD986WS3nTxS8BUi7YjKB/Fj987H752P3zsfvnY/fOx+9ckkkkZ/w9L4AZMeY+j79f4WMlXeavstE8iSNheqlnwZLz... | [] | null | 1.5 | <p>The indicated diagram shows current flow diagram loops for writing Kirchhoff's law are also indicated, writing the equation</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lepyfbx7/6158c940-46b9-4c24-ad40-fefcef25913e/de3c5eb0-b856-11ed-8195-4f3c56fa1eb5/file-1lepyfbx8.png?format=png" data-or... | integer | jee-main-2023-online-30th-january-morning-shift | 9,896 |
lgnz2zq1 | physics | current-electricity | kirchhoff's-circuit-laws | A network of four resistances is connected to $9 \mathrm{~V}$ battery, as shown in figure. The magnitude of voltage difference between the points $\mathrm{A}$ and $\mathrm{B}$ is __________ $V$.<br/><br/>
<img src="data:image/png;base64,UklGRpANAABXRUJQVlA4IIQNAADQ0wCdASriAQADP4HA2mQ2MS0moxVpmsAwCWlu/DJY+Y3HZ19/tR6IDDs... | [] | null | 3 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lgrdm9cf/08e4a3ff-8d6f-460f-be72-94bbe178f739/7f410d00-e0b7-11ed-88f5-253292a46f70/file-1lgrdm9cg.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lgrdm9cf/08e4a3ff-8d6f-460f-be72-94bbe178f739/7f410d00-e0b7-11ed-88f5-253292a46f70/fi... | integer | jee-main-2023-online-15th-april-morning-shift | 9,898 |
1lh2zzm8f | physics | current-electricity | kirchhoff's-circuit-laws | <p>Figure shows a part of an electric circuit. The potentials at points $$a, b$$ and $$c$$ are $$30 \mathrm{~V}, 12 \mathrm{~V}$$ and $$2 \mathrm{~V}$$ respectively. The current through the $$20 ~\Omega$$ resistor will be,</p>
<p><img src="data:image/png;base64,UklGRuwKAABXRUJQVlA4IOAKAAAwngCdASoAA2gBP4G812W2LqwnIfCJYs... | [{"identifier": "A", "content": "0.2 A"}, {"identifier": "B", "content": "0.6 A"}, {"identifier": "C", "content": "0.4 A"}, {"identifier": "D", "content": "1.0 A"}] | ["C"] | null | Sum of current at junction point will be zero :<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lmjxkccx/e1890d4f-c278-4268-9a68-a01932ce13fc/879fe010-5368-11ee-a24f-c39988942e14/file-6y3zli1lmjxkccy.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lmjxkccx/e18... | mcq | jee-main-2023-online-6th-april-evening-shift | 9,901 |
jaoe38c1lscpfh6i | physics | current-electricity | kirchhoff's-circuit-laws | <p>Three voltmeters, all having different internal resistances are joined as shown in figure. When some potential difference is applied across $$A$$ and $$B$$, their readings are $$V_1, V_2$$ and $$V_3$$. Choose the correct option.</p>
<p><img src="data:image/png;base64,UklGRjQHAABXRUJQVlA4ICgHAABwdACdASoAAzoBP4HA3GU2M... | [{"identifier": "A", "content": "$$V_1=V_2$$\n"}, {"identifier": "B", "content": "$$V_1 \\neq V_3-V_2$$\n"}, {"identifier": "C", "content": "$$V_1+V_2=V_3$$\n"}, {"identifier": "D", "content": "$$V_1+V_2>V_3$$"}] | ["C"] | null | <p>From KVL,</p>
<p>$$\mathbf{V}_{\mathbf{1}}+\mathbf{V}_{\mathbf{2}}-\mathbf{V}_{\mathbf{3}}=\mathbf{0} \Rightarrow \mathrm{V}_1+\mathrm{V}_2=\mathrm{V}_3$$</p> | mcq | jee-main-2024-online-27th-january-evening-shift | 9,903 |
jaoe38c1lsfli46g | physics | current-electricity | kirchhoff's-circuit-laws | <p>In the given circuit, the current in resistance R$$_3$$ is :</p>
<p><img src="data:image/png;base64,UklGRsAKAABXRUJQVlA4ILQKAAAQnACdASoAA4wBP4HA2mU2MS0nIdNZUsAwCWlu/HyYhVsnZ1+/rVaM2dvbPu4eqXBP9nFz9v/swpG6ilUZtqKVRm2nudUNaUNHH3MwCSZIYjNtRSqMy3XuGBzWz4nl+4YHNEJ2xR7jY90eeS59pFuvcMDmtnxPL9wwPAV7hgc1s+J5fuGBxojJMiRZ9Ttjy... | [{"identifier": "A", "content": "2 A"}, {"identifier": "B", "content": "1.5 A"}, {"identifier": "C", "content": "1 A"}, {"identifier": "D", "content": "2.5 A"}] | ["C"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lsr7uyt9/4b73df87-350d-47ad-801f-19687c4f7fd8/932c1de0-ce33-11ee-9412-cd4f9c6f2c40/file-6y3zli1lsr7uyta.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lsr7uyt9/4b73df87-350d-47ad-801f-19687c4f7fd8/932c1de0-ce33-11ee... | mcq | jee-main-2024-online-29th-january-evening-shift | 9,904 |
jaoe38c1lsfm4cdp | physics | current-electricity | kirchhoff's-circuit-laws | <p>In the given circuit, the current flowing through the resistance $$20 \Omega$$ is $$0.3 \mathrm{~A}$$, while the ammeter reads $$0.9 \mathrm{~A}$$. The value of $$\mathrm{R}_1$$ is _________ $$\Omega$$.</p>
<p><img src="data:image/png;base64,UklGRjwMAABXRUJQVlA4IDAMAACw1ACdASoAA0YCP4HA2WW2MCynIXG5QsAwCWlu4XMkcmNwvj6... | [] | null | 30 | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lsr7jd2i/9643e284-f016-4b1f-b6df-6acde3e54568/5079a4a0-ce32-11ee-9412-cd4f9c6f2c40/file-6y3zli1lsr7jd2j.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lsr7jd2i/9643e284-f016-4b1f-b6df-6acde3e54568/5079a4a0-ce32-11ee... | integer | jee-main-2024-online-29th-january-evening-shift | 9,905 |
1lsgx8rwq | physics | current-electricity | kirchhoff's-circuit-laws | <p>Two cells are connected in opposition as shown. Cell $$\mathrm{E}_1$$ is of $$8 \mathrm{~V}$$ emf and $$2 \Omega$$ internal resistance; the cell $$\mathrm{E}_2$$ is of $$2 \mathrm{~V}$$ emf and $$4 \Omega$$ internal resistance. The terminal potential difference of cell $$\mathrm{E}_2$$ is __________ V.</p>
<p><img s... | [] | null | 6 | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lsqm6ziy/c382890f-e59d-4125-a0e6-8a4831a0b0e8/d8976ba0-cdde-11ee-a0d3-7b75c4537559/file-6y3zli1lsqm6ziz.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lsqm6ziy/c382890f-e59d-4125-a0e6-8a4831a0b0e8/d8976ba0-cdde-11ee... | integer | jee-main-2024-online-30th-january-morning-shift | 9,906 |
EMCCdeYAXjPF8mlv | physics | current-electricity | meter-bridge | In a meter bridge experiment null point is obtained at $$20$$ $$cm$$, from one end of the wire when resistance $$X$$ is balanced against another resistance $$Y.$$ If $$X < Y$$, then where will be the new position of the null point from the same end, if one decides to balance a resistance of $$4$$ $$X$$ against $$Y$... | [{"identifier": "A", "content": "$$40$$ $$cm$$ "}, {"identifier": "B", "content": "$$80$$ $$cm$$ "}, {"identifier": "C", "content": "$$50$$ $$cm$$ "}, {"identifier": "D", "content": "$$70$$ $$cm$$ "}] | ["C"] | null | In the first case $${X \over Y} = {{20} \over {80}} = {1 \over 4}$$
<br><br>In the second case $${{4X} \over Y} = {\ell \over {100 - \ell }} \Rightarrow \ell = 50$$ | mcq | aieee-2004 | 9,908 |
W2uKMuQzeFdnSIwQs5NGI | physics | current-electricity | meter-bridge | In a meter bridge experiment resistances are connected as shown in the figure. Initially resistance P = 4 $$\Omega $$ and the neutral point N is at 60 cm from A. Now an unknown resistance R is connected in series to P and the new position of the neutral point is at 80 cm from A. The value of unknown resistance R is :
<... | [{"identifier": "A", "content": "$${{33} \\over 5}\\,\\Omega $$ "}, {"identifier": "B", "content": "6 $$\\,\\Omega $$"}, {"identifier": "C", "content": "7 $$\\,\\Omega $$"}, {"identifier": "D", "content": "$${{20} \\over 3}\\,\\Omega $$"}] | ["D"] | null | <p>Initially, the resistance P = 4 $$\Omega$$ and the neutral point N is at 60 cm from A. Therefore,</p>
<p>$${4 \over {60}} = {Q \over {40}} \Rightarrow Q = {{160} \over {60}} = \left( {{8 \over 3}} \right)\Omega $$</p>
<p>When an unknown resistance R is connected in series to P and the new position of the neutral poi... | mcq | jee-main-2017-online-9th-april-morning-slot | 9,909 |
hcIg5KV9z1Xl432I | physics | current-electricity | meter-bridge | On interchanging the resistances, the balance point of a meter bridge shifts to the left by 10 cm. The
resistance of their series combination is 1 k$$\Omega $$. How much was the resistance on the left slot before
interchanging the resistances? | [{"identifier": "A", "content": "910 $$\\Omega $$"}, {"identifier": "B", "content": "990 $$\\Omega $$"}, {"identifier": "C", "content": "505 $$\\Omega $$"}, {"identifier": "D", "content": "550 $$\\Omega $$"}] | ["D"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266981/exam_images/vk2z5nfou4fbv2hwae5b.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2018 (Offline) Physics - Current Electricity Question 283 English Explanation 1">
<br><br>$${X \over l}$$ = $$... | mcq | jee-main-2018-offline | 9,910 |
nIT3xB7IJNluJWldJ3MuW | physics | current-electricity | meter-bridge | The resistance of the meter bridge AB in given figure is 4 $$\Omega $$. With a cell of emf $$\varepsilon $$ = 0.5 V and rheostat
resistance R<sub>h</sub> = 2 $$\Omega $$ the null point is obtained at some point J. When the cell is replaced by another one of emf $$\varepsilon $$ = $$\varepsilon $$<sub>2</sub> the same n... | [{"identifier": "A", "content": "0.3 V"}, {"identifier": "B", "content": "0.6 V"}, {"identifier": "C", "content": "0.5 V"}, {"identifier": "D", "content": "0.4 V"}] | ["A"] | null | Potential gradient with R<sub>h</sub> = 2$$\Omega $$
<br><br>is $$\left( {{6 \over {2 + 4}}} \right) \times {4 \over L} = {{dV} \over {dL}};$$ L $$=$$ 100 cm
<br><br>Let null point be at $$\ell $$ cm
<br><br>thus $$\varepsilon $$<sub>1</sub> $$=$$ 0.5V $$=$$ $$\left( {{6 \over {2 + 4}}} \right) \times {4 \o... | mcq | jee-main-2019-online-11th-january-morning-slot | 9,912 |
ZnjBgSYUjkQIMaaI9RdpC | physics | current-electricity | meter-bridge | In the experimental set up of metre bridge shown in the figure, the null point is obtained at a distance of 40 cm from A. If a 10 $$\Omega $$ resistor is connected in series with R<sub>1</sub>, the null point shifts by 10 cm. The resistance that should be connected in parallel with (R<sub>1</sub> + 10) $$\Omega $$ such... | [{"identifier": "A", "content": "40 $$\\Omega $$"}, {"identifier": "B", "content": "30 $$\\Omega $$"}, {"identifier": "C", "content": "20 $$\\Omega $$"}, {"identifier": "D", "content": "60 $$\\Omega $$"}] | ["D"] | null | $${{{R_1}} \over {{R_2}}} = {2 \over 3}\,\,$$ . . .(i)
<br><br>$${{{R_1} + 10} \over {{R_2}}}... | mcq | jee-main-2019-online-11th-january-evening-slot | 9,913 |
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