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less(Charlie, kind, 3)
Answer:
False
One reasoning:
['Fact0', 'Rule3', ['Default']]
Step reasoning:
Default -> int0: Bob is 0 kind; Fact0 & Rule3 & int0 -> int1: Charlie is 0+3=3 kind
ID: 92
Fact:
0. is(Alexander, generous, 1)
1. is(Alexander, red, 2)
2. chases(Gary, Samuel)
3. needs(Gary, Samuel)
4. needs(Mia, Gary)
5. needs(Mia, Samuel)
Rule:
0. chases(?x, ?y) -> is(?x, generous, 1y+4)
1. is(?x, quiet, 1) -> is(?x, white, 3)
2. is(?x, quiet, 2) -> is(?x, white, 1)
3. is(?x, quiet, 3) -> is(?x, white, 3)
4. chases(?x, ?y) -> is(?x, red, 1y+3)
5. is(?x, red, 2) -> is(?x, quiet, 3)
Assertion:
greater(Gary, red, 2)
Answer:
True
One reasoning:
['Fact2', 'Rule4', ['Default']]
Step reasoning:
Default -> int0: Samuel is 0 red; Fact2 & Rule4 & int0 -> int1: Gary is 0+3=3 red
ID: 93
Fact:
0. hugs(Grace, Mia)
1. visits(Samuel, Dave)
2. hugs(Dave, Samuel)
3. helps(Grace, Samuel)
4. helps(Mia, Samuel)
5. visits(Dave, Grace)
Rule:
0. hugs(?x, ?y) -> is(?x, blue, 1y+1)
1. is(?x, blue, 1) -> is(?x, big, 3)
2. is(?x, big, 3) -> is(?x, furry, 3)
3. is(?x, big, 4) -> is(?x, confident, 3)
4. is(?x, confident, 2) -> is(?x, furry, 1)
5. is(?x, big, 1) -> is(?x, furry, 4)
Assertion:
greater(Grace, blue, 6)
Answer:
False
One reasoning:
['Fact0', 'Rule0', ['Default']]
Step reasoning:
Default -> int0: Mia is 0 blue; Fact0 & Rule0 & int0 -> int1: Grace is 0+1=1 blue
ID: 94
Fact:
0. is(Emily, generous, 4)
1. is(Emily, red, 2)
2. greets(Grace, Emma)
3. likes(Grace, Emily)
4. is(Grace, big, 3)
5. likes(Benjamin, Emma)
Rule:
0. is(?x, reserved, 2) -> is(?x, red, 4)
1. argues(?x, ?y) -> is(?x, big, 1y+2)
2. is(?x, generous, 1) -> is(?x, big, 3)
3. likes(?x, ?y) -> is(?x, reserved, 1y+4)
4. is(?x, red, 3) -> is(?x, generous, 2)
5. is(?x, big, 4) -> is(?x, generous, 3)
Assertion:
greater(Grace, reserved, 9)
Answer:
False
One reasoning:
['Fact3', 'Rule3', ['Default']]
Step reasoning:
Default -> int0: Emily is 0 reserved; Fact3 & Rule3 & int0 -> int1: Grace is 0+4=4 reserved
ID: 95
Fact:
0. meets(Daniel, Grace)
1. meets(Gary, Benjamin)
2. visits(Daniel, Grace)
3. visits(Daniel, Gary)
4. kisses(Grace, Gary)
5. visits(Gary, Grace)
Rule:
0. is(?x, green, 3) -> is(?x, blue, 2)
1. is(?x, green, 4) -> is(?x, generous, 2)
2. is(?x, blue, 2) -> is(?x, red, 4)
3. kisses(?x, ?y) -> is(?x, generous, 2y+4)
4. is(?x, green, 2) -> is(?x, blue, 1)
5. is(?x, red, 3) -> is(?x, blue, 1)
Assertion:
greater(Grace, generous, 2)
Answer:
True
One reasoning: