text
stringlengths
0
418
greater(Bob, friendly, 2)
Answer:
True
One reasoning:
['Fact3', 'Rule1', ['Default']]
Step reasoning:
Default -> int0: Emily is 0 friendly; Fact3 & Rule1 & int0 -> int1: Bob is 0+4=4 friendly
ID: 117
Fact:
0. meets(Emily, Samuel)
1. visits(Emily, Emma)
2. is(Emily, nice, 3)
3. meets(Emily, Gary)
4. meets(Samuel, Emma)
5. needs(Gary, Emily)
Rule:
0. is(?x, nice, 3) -> is(?x, kind, 4)
1. is(?x, nice, 2) -> is(?x, big, 1)
2. is(?x, nice, 1) -> is(?x, generous, 4)
3. is(?x, generous, 2) -> is(?x, kind, 2)
4. needs(?x, ?y) -> is(?x, nice, 2y+1)
5. is(?x, generous, 3) -> is(?x, nice, 3)
Assertion:
greater(Gary, nice, 8)
Answer:
False
One reasoning:
['Fact5', 'Rule4', ['Fact2']]
Step reasoning:
Fact2 -> int0: Emily is 3 nice; Fact5 & Rule4 & int0 -> int1: Gary is 2*3+1=7 nice
ID: 118
Fact:
0. eats(Mia, Gary)
1. interacts(Mia, Gary)
2. eats(Gary, Benjamin)
3. is(Benjamin, furry, 2)
4. interacts(Benjamin, Mia)
5. interacts(Chioe, Mia)
Rule:
0. interacts(?x, ?y) -> is(?x, young, 1y+3)
1. is(?x, young, 4) -> is(?x, smart, 3)
2. is(?x, furry, 2) -> is(?x, rough, 2)
3. is(?x, rough, 1) -> is(?x, smart, 2)
4. visits(?x, ?y) -> is(?x, smart, 1y+3)
5. eats(?x, ?y) -> is(?x, furry, 2y+3)
Assertion:
greater(Gary, furry, 1)
Answer:
True
One reasoning:
['Fact2', 'Rule5', ['Fact3']]
Step reasoning:
Fact3 -> int0: Benjamin is 2 furry; Fact2 & Rule5 & int0 -> int1: Gary is 2*2+3=7 furry
ID: 119
Fact:
0. kisses(Harry, Chioe)
1. hugs(Alice, Harry)
2. kisses(Alice, Harry)
3. hugs(Chioe, Bob)
4. needs(Chioe, Bob)
5. needs(Harry, Alice)
Rule:
0. hugs(?x, ?y) -> is(?x, cold, 2y+1)
1. is(?x, green, 1) -> is(?x, cold, 2)
2. is(?x, compassionate, 2) -> is(?x, generous, 1)
3. is(?x, compassionate, 4) -> is(?x, green, 1)
4. kisses(?x, ?y) -> is(?x, compassionate, 2y+4)
5. is(?x, cold, 1) -> is(?x, generous, 3)
Assertion:
less(Harry, compassionate, 5)
Answer:
True
One reasoning:
['Fact0', 'Rule4', ['Default']]
Step reasoning:
Default -> int0: Chioe is 0 compassionate; Fact0 & Rule4 & int0 -> int1: Harry is 2*0+4=4 compassionate
ID: 120
Fact:
0. hugs(Liam, Bob)
1. interacts(Michael, Bob)
2. sees(Liam, Michael)
3. interacts(Charlie, Liam)
4. is(Bob, young, 3)
5. sees(Charlie, Bob)
Rule:
0. is(?x, young, 2) -> is(?x, red, 4)
1. is(?x, young, 4) -> is(?x, kind, 1)
2. sees(?x, ?y) -> is(?x, kind, 1y+2)
3. is(?x, furry, 2) -> is(?x, young, 3)
4. sees(?x, ?y) -> is(?x, young, 2y+1)
5. is(?x, kind, 2) -> is(?x, red, 2)
Assertion:
greater(Liam, young, 8)
Answer:
False
One reasoning: