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3. is(?x, blue, 4) -> is(?x, generous, 4)
4. meets(?x, ?y) -> is(?x, blue, 2y+3)
5. is(?x, kind, 3) -> is(?x, blue, 2)
Assertion:
greater(Mia, kind, 3)
Answer:
False
One reasoning:
['Rule1', ['Fact0']]
Step reasoning:
Fact0 -> int0: Mia is 3 considerate; Rule1 & int0 -> int1: Mia is 1 kind
ID: 188
Fact:
0. kisses(Alice, Amelia)
1. kisses(Emily, Olivia)
2. meets(Amelia, Olivia)
3. meets(Emily, Olivia)
4. meets(Amelia, Emily)
5. argues(Alice, Olivia)
Rule:
0. argues(?x, ?y) -> is(?x, white, 1y+2)
1. is(?x, considerate, 2) -> is(?x, generous, 4)
2. is(?x, nice, 4) -> is(?x, considerate, 1)
3. argues(?x, ?y) -> is(?x, nice, 1y+3)
4. argues(?x, ?y) -> is(?x, generous, 2y+2)
5. is(?x, white, 4) -> is(?x, generous, 2)
Assertion:
greater(Alice, nice, 9)
Answer:
False
One reasoning:
['Fact5', 'Rule3', ['Default']]
Step reasoning:
Default -> int0: Olivia is 0 nice; Fact5 & Rule3 & int0 -> int1: Alice is 0+3=3 nice
ID: 189
Fact:
0. is(Erin, friendly, 1)
1. meets(Hannah, Erin)
2. hugs(Erin, Alexander)
3. helps(Olivia, Erin)
4. helps(Hannah, Erin)
5. hugs(Erin, Olivia)
Rule:
0. meets(?x, ?y) -> is(?x, friendly, 1y+3)
1. is(?x, reserved, 3) -> is(?x, furry, 3)
2. meets(?x, ?y) -> is(?x, rough, 1y+3)
3. is(?x, furry, 2) -> is(?x, rough, 1)
4. is(?x, rough, 4) -> is(?x, furry, 3)
5. meets(?x, ?y) -> is(?x, furry, 1y+4)
Assertion:
less(Hannah, furry, 7)
Answer:
True
One reasoning:
['Fact1', 'Rule5', ['Default']]
Step reasoning:
Default -> int0: Erin is 0 furry; Fact1 & Rule5 & int0 -> int1: Hannah is 0+4=4 furry
ID: 190
Fact:
0. visits(Emma, Emily)
1. greets(Michael, Gary)
2. is(Gary, rough, 2)
3. needs(Emma, Michael)
4. visits(Michael, Emma)
5. visits(Michael, Gary)
Rule:
0. is(?x, rough, 1) -> is(?x, white, 3)
1. is(?x, rough, 2) -> is(?x, round, 3)
2. needs(?x, ?y) -> is(?x, gruff, 1y+1)
3. needs(?x, ?y) -> is(?x, white, 1y+4)
4. is(?x, round, 2) -> is(?x, gruff, 2)
5. needs(?x, ?y) -> is(?x, rough, 1y+3)
Assertion:
less(Gary, round, 3)
Answer:
False
One reasoning:
['Rule1', ['Fact2']]
Step reasoning:
Fact2 -> int0: Gary is 2 rough; Rule1 & int0 -> int1: Gary is 3 round
ID: 191
Fact:
0. meets(Fiona, Dave)
1. chases(Fiona, Benjamin)
2. meets(Benjamin, Fiona)
3. is(James, white, 1)
4. kisses(Fiona, Dave)
5. chases(Dave, Fiona)
Rule:
0. is(?x, big, 1) -> is(?x, young, 4)
1. is(?x, cold, 1) -> is(?x, big, 1)
2. is(?x, white, 4) -> is(?x, cold, 3)
3. is(?x, young, 3) -> is(?x, white, 1)
4. chases(?x, ?y) -> is(?x, young, 1y+2)
5. is(?x, big, 3) -> is(?x, cold, 4)
Assertion: