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less(Emily, nice, 3)
Answer:
False
One reasoning:
['Fact0', 'Rule0', ['Default']]
Step reasoning:
Default -> int0: Liam is 0 nice; Fact0 & Rule0 & int0 -> int1: Emily is 2*0+3=3 nice
ID: 292
Fact:
0. kisses(Grace, Alexander)
1. visits(James, Joseph)
2. kisses(Alexander, Joseph)
3. helps(Joseph, Grace)
4. kisses(James, Joseph)
5. visits(James, Alexander)
Rule:
0. is(?x, gruff, 1) -> is(?x, cold, 1)
1. kisses(?x, ?y) -> is(?x, cold, 1y+1)
2. kisses(?x, ?y) -> is(?x, red, 1y+4)
3. is(?x, red, 1) -> is(?x, rough, 2)
4. kisses(?x, ?y) -> is(?x, rough, 1y+1)
5. is(?x, red, 3) -> is(?x, rough, 1)
Assertion:
less(James, rough, 8)
Answer:
True
One reasoning:
['Fact4', 'Rule4', ['Default']]
Step reasoning:
Default -> int0: Joseph is 0 rough; Fact4 & Rule4 & int0 -> int1: James is 0+1=1 rough
ID: 293
Fact:
0. visits(Chioe, Benjamin)
1. chases(Alice, Chioe)
2. visits(Benjamin, Alice)
3. is(Harry, compassionate, 4)
4. likes(Alice, Chioe)
5. visits(Benjamin, Harry)
Rule:
0. is(?x, compassionate, 2) -> is(?x, cold, 1)
1. chases(?x, ?y) -> is(?x, generous, 1y+3)
2. likes(?x, ?y) -> is(?x, compassionate, 1y+3)
3. is(?x, generous, 4) -> is(?x, quiet, 1)
4. is(?x, compassionate, 3) -> is(?x, quiet, 4)
5. is(?x, compassionate, 1) -> is(?x, cold, 2)
Assertion:
less(Alice, compassionate, 4)
Answer:
True
One reasoning:
['Fact4', 'Rule2', ['Default']]
Step reasoning:
Default -> int0: Chioe is 0 compassionate; Fact4 & Rule2 & int0 -> int1: Alice is 0+3=3 compassionate
ID: 294
Fact:
0. sees(Alice, Michael)
1. meets(Alice, Charlie)
2. is(Alice, friendly, 3)
3. likes(Alice, Michael)
4. meets(Michael, Charlie)
5. likes(Emily, Michael)
Rule:
0. is(?x, friendly, 4) -> is(?x, furry, 2)
1. is(?x, white, 4) -> is(?x, furry, 1)
2. is(?x, white, 2) -> is(?x, friendly, 4)
3. is(?x, round, 4) -> is(?x, friendly, 3)
4. is(?x, furry, 3) -> is(?x, round, 4)
5. likes(?x, ?y) -> is(?x, round, 2y+3)
Assertion:
less(Alice, round, 2)
Answer:
False
One reasoning:
['Fact3', 'Rule5', ['Default']]
Step reasoning:
Default -> int0: Michael is 0 round; Fact3 & Rule5 & int0 -> int1: Alice is 2*0+3=3 round
ID: 295
Fact:
0. sees(William, Harry)
1. is(William, gruff, 2)
2. helps(Sophia, Samuel)
3. helps(William, Sophia)
4. visits(Sophia, Samuel)
5. helps(Sophia, Harry)
Rule:
0. sees(?x, ?y) -> is(?x, compassionate, 2y+4)
1. is(?x, compassionate, 3) -> is(?x, red, 4)
2. sees(?x, ?y) -> is(?x, considerate, 1y+4)
3. visits(?x, ?y) -> is(?x, red, 2y+2)
4. is(?x, red, 2) -> is(?x, compassionate, 1)
5. is(?x, considerate, 1) -> is(?x, red, 2)
Assertion:
greater(William, compassionate, 2)
Answer:
True
One reasoning: