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825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 748,029,603,087,384,700 | Yours truly | 02/22/2022 10:16:32 | Yeah | 0 | 1 | null | null | null | null | null | |||||
825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 748,029,603,087,384,700 | Yours truly | 02/22/2022 10:16:34 | I think. | 0 | 1 | null | null | null | null | null | |||||
825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 748,029,603,087,384,700 | Yours truly | 02/22/2022 10:17:17 | But, if some letter were repeated then you'd divide the answer with x! (Where x is the number of times a certain letter is repeated) alright? | 0 | 1 | null | null | null | null | null | |||||
825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 691,652,908,206,522,400 | souii | 02/22/2022 10:17:42 | yes. I have read about that | 1 | 0 | null | null | null | null | null | |||||
825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 748,029,603,087,384,700 | Yours truly | 02/22/2022 10:18:01 | FOOL for example, it would be
(3!×2!)÷2! As there are two O. | 0 | 1 | null | null | null | null | null | |||||
825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 691,652,908,206,522,400 | souii | 02/22/2022 10:18:57 | I see. that makes a lot of sense. thank you :)) | 1 | 0 | null | null | null | null | null | |||||
825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 748,029,603,087,384,700 | Yours truly | 02/22/2022 10:19:14 | Yw. | 0 | 1 | null | null | null | null | null | |||||
825 | help-10 | 727c980b9df24fba9a83ceaa20dda918 | 691,652,908,206,522,400 | souii | 02/22/2022 10:19:24 | .close | 1 | 0 | null | null | null | null | null | |||||
826 | help-10 | 1abb87e9824e4b6aab7a06193abcab66 | 273,579,527,534,280,700 | milly | 02/22/2022 10:26:40 | @s_chanch | 1 | 0 | null | null | null | null | null | |||||
826 | help-10 | 1abb87e9824e4b6aab7a06193abcab66 | 273,579,527,534,280,700 | milly | 02/22/2022 10:34:58 | .close | 1 | 0 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 292,646,273,197,015,040 | X Æ A-12 | 02/22/2022 11:39:53 | if x~ is the median why is the sum minimal? | unknown.png | 1 | 0 | null | null | null | null | null | ||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:46:38 | First you show that sum of absolute values being minimal implies sum of squares being minimal: | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:47:18 | If positive real numbers r_1,…,r_n s_1,…,s_n such that Σr_j<Σs_j | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:47:38 | Then Σs_j^2-Σr_j^2= | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:48:34 | Σ(s_j+r_j)(s_j-r_j)>=M(Σs_j-Σr_j)>0 | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:49:03 | Where M is min{s_j+r_j :j}>0 | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:49:17 | Now sum of square you can calculate its derivative | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:49:20 | The rest is clear | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:50:13 | Wait a second some error | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 292,646,273,197,015,040 | X Æ A-12 | 02/22/2022 11:54:24 | ok thx | 1 | 0 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 11:54:36 | Wait huge error, fixing | 0 | 1 | 701,895,792,763,600,900 | s_chanch | 2633 | s_chanch | false | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 12:07:33 | Oh you let x_1<=x_2<=…<=x_n | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 12:08:23 | |x-x_k|+|x-x_(n-k)| is minimal when x is contained in [x_k, x_(n-k)] | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 12:09:00 | So such x must be contained in the intersection of all [x_k , x_ (n-k)] | 0 | 1 | 292,646,273,197,015,040 | X Æ A-12 | 2866 | X Æ A-12 | false | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 12:11:38 | Median value satisfies that right? I think | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 12:15:47 | Oh yes Any point x such that that sum is smallest must be contained in the intersection of all [x_k, x_ (n-k)] and median value is one of them you can check the details | 0 | 1 | null | null | null | null | null | |||||
827 | help-10 | 4debc02a358c48a7a499a702fe86b0a2 | 292,646,273,197,015,040 | X Æ A-12 | 02/22/2022 12:16:09 | ah ok | 1 | 0 | null | null | null | null | null | |||||
828 | help-10 | b693a1fe26ca4cf897da663fce0739a6 | 349,010,029,686,292,500 | Lil Chris | 02/22/2022 12:41:36 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
828 | help-10 | b693a1fe26ca4cf897da663fce0739a6 | 945,715,302,497,402,900 | mint | 02/22/2022 12:41:36 | can anyone help me understand how to solve this? im so confused | unknown.png | 0 | 1 | null | null | null | null | null | ||||
828 | help-10 | b693a1fe26ca4cf897da663fce0739a6 | 349,010,029,686,292,500 | Lil Chris | 02/22/2022 12:41:58 | Sorry @mint | 1 | 0 | null | null | null | null | null | |||||
828 | help-10 | b693a1fe26ca4cf897da663fce0739a6 | 349,010,029,686,292,500 | Lil Chris | 02/22/2022 12:42:05 | .close | 1 | 0 | null | null | null | null | null | |||||
829 | help-10 | df62cda3204541c08c9702a06212f4a3 | 349,010,029,686,292,500 | Lil Chris | 02/22/2022 12:42:13 | .reopen | 1 | 0 | null | null | null | null | null | |||||
829 | help-10 | df62cda3204541c08c9702a06212f4a3 | 349,010,029,686,292,500 | Lil Chris | 02/22/2022 12:44:15 | Topic: Applied Read Analysis
Does this look accurate for the Fourier coefficient a0? My professor has the denominator as 2pi instead of just pi. | unknown.png | 1 | 0 | null | null | null | null | null | ||||
829 | help-10 | df62cda3204541c08c9702a06212f4a3 | 349,010,029,686,292,500 | Lil Chris | 02/22/2022 12:44:41 | By the way, the screenshot is from a website: https://mathworld.wolfram.com/FourierSeries.html | 1 | 0 | null | null | null | null | null | |||||
829 | help-10 | df62cda3204541c08c9702a06212f4a3 | 349,010,029,686,292,500 | Lil Chris | 02/22/2022 12:50:27 | .close | 1 | 0 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 753,125,620,719,943,700 | Daniel_The_Maniel | 02/22/2022 12:53:05 | IMG_4870.jpg | 1 | 0 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 753,125,620,719,943,700 | Daniel_The_Maniel | 02/22/2022 12:53:44 | So if velocity is displacement over change in time, shouldn’t all racers have an average velocity of 0? | 1 | 0 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 551,269,104,800,104,450 | EndTimes | 02/22/2022 12:53:51 | No | 0 | 1 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 753,125,620,719,943,700 | Daniel_The_Maniel | 02/22/2022 12:53:55 | Since their displacement is all 0 | 1 | 0 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 551,269,104,800,104,450 | EndTimes | 02/22/2022 12:54:10 | Haha | 0 | 1 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 551,269,104,800,104,450 | EndTimes | 02/22/2022 12:54:12 | I agree | 0 | 1 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 551,269,104,800,104,450 | EndTimes | 02/22/2022 12:54:21 | The question should ask for speed not velocity | 0 | 1 | 945,715,302,497,402,900 | mint | 9515 | mint | false | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 800,622,149,903,056,900 | Shen | 02/22/2022 12:55:16 | @Daniel_The_Maniel You're right - you should argue against whoever made it to get points back | 0 | 1 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 800,622,149,903,056,900 | Shen | 02/22/2022 12:55:19 | (If applicable) | 0 | 1 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 753,125,620,719,943,700 | Daniel_The_Maniel | 02/22/2022 12:57:01 | Ok cool thx | 1 | 0 | null | null | null | null | null | |||||
830 | help-10 | fe53065d788142488feda294f5fe4189 | 753,125,620,719,943,700 | Daniel_The_Maniel | 02/22/2022 12:57:03 | .close | 1 | 0 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:11:41 | what does it mean to expand around $z=\pi i$ within a taylor/laurent expansion for $e^z +1$? We've got
\begin{align}
e^z +1 = 1 + \sum_{n=0}^\infty \frac{z^n}{n!}
\end{align}
Does this mean replacing $z$ with the variable $w$ where $w=z-\pi i$? | 1 | 0 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 510,789,298,321,096,700 | TeXit | 02/22/2022 13:12:13 | **madlor** | 163892364681674753.png | 0 | 1 | null | null | null | null | null | ||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 13:13:08 | It means you write e^z+1 in the form Σa_k(z-πi)^k | 0 | 1 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:13:53 | so
\begin{align}
\sum_{n=0}^\infty a_k (z-\pi i)^n
\end{align} | 1 | 0 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 510,789,298,321,096,700 | TeXit | 02/22/2022 13:14:11 | **madlor** | 163892364681674753.png | 0 | 1 | null | null | null | null | null | ||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 13:14:19 | Yes | 0 | 1 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 13:14:35 | Or from negative infinity to positive infinity | 0 | 1 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 826,318,983,413,366,800 | Cogwheels of the mind | 02/22/2022 13:14:53 | Depends on what kind of expansion | 0 | 1 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:14:55 | right | 1 | 0 | 753,125,620,719,943,700 | Daniel_The_Maniel | 9564 | Daniel_The_Maniel | false | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:15:04 | i am looking to do a Laurent expansion specifically yeah | 1 | 0 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:15:41 | quite honestly not sure how to start, but i will try some things | 1 | 0 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:16:44 | but i solve the bottom expression?
\begin{align}
e^{z} + 1 =\sum_{n=-\infty}^\infty c_n (z-\pi i)^n
\end{align} | 1 | 0 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 510,789,298,321,096,700 | TeXit | 02/22/2022 13:16:47 | **madlor** | 163892364681674753.png | 0 | 1 | null | null | null | null | null | ||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:17:56 | oh. i do feel a little bit silly now, ive already done the taylor expansion, but i did it for z_0 = 0. | 1 | 0 | null | null | null | null | null | |||||
831 | help-10 | 413e09ee1ef944c48cfd5743829aa998 | 163,892,364,681,674,750 | madlor | 02/22/2022 13:36:22 | Not resolved but moving on | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 13:38:32 | Hi! I'm working on some arithmetic sequences and noticing factorizing isn't my strong side. In the problem, T2 can be expressed as
T2 = T1 * 0.95 + 600
or upon inserting T1
T2 = (8200 * 0.95 + 600)0.95 + 600
Could someone walk me through how that is factorized into
8200 * 0.95^2 + 600(0.95 + 1)? | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 13:53:45 | If you open brackets, then first you will multiply $8200*0.95*0.095$ then you multiplied 0.95 with 600.
We ddint do anything apart from opening brackets.
And last two terms, 600*0.95 + 600 have 600 as common factor so we took it out. | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 510,789,298,321,096,700 | TeXit | 02/22/2022 13:53:48 | **hoi** | 828645428765523981.png | 0 | 1 | null | null | null | null | null | ||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 13:57:36 | I understand I multiply the two 0.95 and that I can factor out the 600, but what happens to multiplying 8200(0.95)? | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 13:59:17 | Nothing happened here afaik | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 13:59:40 | One more 0.95 is multiplied and hence it's square there | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 14:01:20 | Maybe I'm being really stupid and not seeing something but what I can't wrap my head around is why there's no effect on the 8200 if 0.95 is supposed to multiply with every term. because I see 0.95 is multipled and hence squared as you said and 600 just factored | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 14:03:16 | What effect are you talking about, the only thing that will happen is multiplication of 0.95.
Are you asking why isn't it in calculated form? | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 14:05:03 | Why isn't it
8200(0.95) * 0.95(0.95) + 600(0.95) + 600
8200(0.95) * 0.95^2 + 600(0.95+1)
What mistake am I doing in the above factorization? | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 14:07:16 | Okay you know that we use distributive property while multiplying?
Which is multiplying number outside of brackets, to each term individually and putting ± signs in between | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 14:08:29 | If you know, then you must be knowing there won't be extra 0.95 with 8200×0.95 there | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 14:10:52 | So I percieve 8200 x 0.95 as a unique term basically? | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 14:11:12 | How the fuck did I get so far without being aware of this. | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 14:13:32 | Okay, lemme state again, multiplication is distributive over addition not multiplication itself.
$\implies (a+b)c= ac+ab$ and if you have (ab)c you won't do ac*ab. | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 510,789,298,321,096,700 | TeXit | 02/22/2022 14:13:35 | **hoi** | 828645428765523981.png | 0 | 1 | null | null | null | null | null | ||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 828,645,428,765,524,000 | piang | 02/22/2022 14:14:11 | It will be $abc$ only | 0 | 1 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 510,789,298,321,096,700 | TeXit | 02/22/2022 14:14:13 | **hoi** | 828645428765523981.png | 0 | 1 | 207,967,378,267,439,100 | heisenberg | 8360 | heisenberg | false | ||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 14:15:24 | Alright. I understand now and once again, I'm confused how I did not know this by heart. | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 14:15:26 | Thanks a lot. | 1 | 0 | null | null | null | null | null | |||||
832 | help-10 | c6ed0f4dc2ff40ad9dbede4ffe67f208 | 207,967,378,267,439,100 | heisenberg | 02/22/2022 14:15:29 | .close | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:33:12 | How can I get a non-e number when trying to reduce an imaginary number like i^21 on a ti-84 | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:35:05 | for example our teacher said i can be i, -1, -i, or 1 | 1 | 0 | 207,967,378,267,439,100 | heisenberg | 8360 | heisenberg | false | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:35:11 | but calculator spits back an E number | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 14:35:25 | What's the exact number it spits back? | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 14:35:59 | (idk if I can help you, I'm just curious about this calculator lol) | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:37:25 | $i^{21}$? | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 510,789,298,321,096,700 | TeXit | 02/22/2022 14:37:28 | **madlor** | 163892364681674753.png | 0 | 1 | null | null | null | null | null | ||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:37:48 | -1E-13+i | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:37:52 | is it required to do this on the calculator? | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:37:54 | I'm in a+bi mode | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:38:06 | no but I figure it's easier on a ti-84 | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:38:09 | so this is a numerical error | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:38:19 | -1E-13 is a tiiiiny number | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:38:21 | its basically 0 | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:38:47 | your calculator cant compute things perfectly, i think this one is unavoidable | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:39:16 | does this seem logical? | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:39:52 | $-1E-13 = -1\cdot 10^{-13}$ | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 510,789,298,321,096,700 | TeXit | 02/22/2022 14:40:16 | **madlor** | 163892364681674753.png | 0 | 1 | null | null | null | null | null | ||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:40:47 | our teacher told us to break it in fours so wouldn't it be like i^20 and then whatever i^1 is or something, I forget | 1 | 0 | null | null | null | null | null |
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