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833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:41:03 | i agree that sounds like a good idea | 0 | 1 | 740,938,819,125,248,100 | idioticbaka1824 | 9340 | idioticbaka1824 | false | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:41:16 | if you're comfortable with power rules, it shouldnt be too bad | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:42:23 | feel free to ping me if unsure how to go about that | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:43:08 | which way do you think is the easiest idea to solve | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:43:21 | obviously after like i^4 the numbers repeat | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:43:33 | but if you get a number like i^800 you can't just write it 800 times | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:43:43 | you can but you'll be there all day | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:44:03 | i think it would be handy to do utilize $a^{bc} =(a^{b})^c$ for instance | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 510,789,298,321,096,700 | TeXit | 02/22/2022 14:44:23 | **madlor** | 163892364681674753.png | 0 | 1 | null | null | null | null | null | ||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:44:35 | but 21 is an akward number | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:45:06 | so id advise making it so that the power is 20 instead of 21 by utilizing $a^{b+c}=a^b a^c$ | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 510,789,298,321,096,700 | TeXit | 02/22/2022 14:45:09 | **madlor** | 163892364681674753.png | 0 | 1 | null | null | null | null | null | ||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:45:23 | let me know how it goes | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 163,892,364,681,674,750 | madlor | 02/22/2022 14:45:36 | should simplify quite quickly | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 14:48:43 | You can group it into groups of 4. Like writing i 800 times is like writing iiii 200 times, right? But iiii is just 1 | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:53:36 | ok so I just skimmed thru a video from another professor | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:53:53 | her method was if you have say i^302, get the remainder of 302/4 | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:54:12 | the remainder of that is 2
so: i^302 = i^2
i^2 = -1 | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:54:47 | to me that seems like the easiest way, no? | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 14:55:44 | That is indeed TheBest way | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:58:17 | so that means to solve
i^21 sqrt -8
remainder of 21/4 = 1, i^1 = I
i sqrt -8 | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 14:59:18 | I get a decimal of -2.828 for i sqrt -8 | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 15:00:30 | is the final answer suppose to be a decimal? | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 15:01:09 | Yeah | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 15:01:20 | It's basically -2root2 | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 15:01:32 | So it's definitely going to have plenty of decimals | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 15:04:07 | yeah that's what the internet shows me -2root2 | 1 | 0 | 415,684,042,235,576,300 | TheBest | 4188 | TheBest | false | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 15:04:11 | how did you get that | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 15:04:17 | like how's you convert that decimal to that | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 15:05:48 | Root(8)=root(4*2) | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 15:05:55 | =root4*root2 | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 740,938,819,125,248,100 | idioticbaka1824 | 02/22/2022 15:05:59 | =2root2 | 0 | 1 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 15:19:48 | ok thanks yeah I figured out how to do that now | 1 | 0 | null | null | null | null | null | |||||
833 | help-10 | d73dc8857847475b9fcd0d6f7c55fd03 | 415,684,042,235,576,300 | TheBest | 02/22/2022 15:19:55 | good for now I guess until harder problems come up | 1 | 0 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 692,635,975,678,951,400 | Michal | 02/22/2022 15:21:48 | how to get inverse element for this operation ? | Screenshot_2022-02-22_at_20.33.21.png | 1 | 0 | null | null | null | null | null | ||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 692,635,975,678,951,400 | Michal | 02/22/2022 15:22:30 | i ended up with these equations: suppose (c,d) is inverse | 1 | 0 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 692,635,975,678,951,400 | Michal | 02/22/2022 15:22:48 | ac + 5bd = 1
ad + bc = 0 | 1 | 0 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 692,635,975,678,951,400 | Michal | 02/22/2022 15:29:09 | how to get inverse element for this operation ? | 1 | 0 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 706,934,233,012,371,600 | Ansh_ | 02/22/2022 15:29:40 | . | 0 | 1 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 706,934,233,012,371,600 | Ansh_ | 02/22/2022 15:29:48 | I suppose Ann helped you with this one? | 0 | 1 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 706,934,233,012,371,600 | Ansh_ | 02/22/2022 15:30:11 | it's literally solving the simultaneous equations in
e_1, e_2 | 0 | 1 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 692,635,975,678,951,400 | Michal | 02/22/2022 15:31:17 | with identity | 1 | 0 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 692,635,975,678,951,400 | Michal | 02/22/2022 15:33:48 | i have tried but unsuccessfully | 1 | 0 | null | null | null | null | null | |||||
834 | help-10 | 8ccd98e608614eeb8c379240c0fc5302 | 692,635,975,678,951,400 | Michal | 02/22/2022 15:39:04 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:32:17 | Could someone please explain how we get the last expression? | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:32:18 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 186,109,587,366,215,680 | Omegabet_ | 11/07/2021 14:35:30 | it's a geometric series | 0 | 1 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:37:09 | Yes | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:37:11 | 🤔 | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 186,109,587,366,215,680 | Omegabet_ | 11/07/2021 14:37:44 | so... they used the formula for finite geometric series | 0 | 1 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:40:54 | Im sorry if this is a really stupid question but because the numbers are inversed here, where r^n is meant to be applied, we would have 1 instead and the signs seem to be wrong if we apply this one? | maxresdefault.png | 1 | 0 | null | null | null | null | null | ||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:41:32 | :sad: | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 186,109,587,366,215,680 | Omegabet_ | 11/07/2021 14:45:00 | they're equivalent | 0 | 1 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:45:14 | I dont see how | 1 | 0 | 706,934,233,012,371,600 | Ansh_ | 3502 | Arya | false | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:45:17 | :sad: | 1 | 0 | 706,934,233,012,371,600 | Ansh_ | 3502 | Arya | false | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 186,109,587,366,215,680 | Omegabet_ | 11/07/2021 14:45:23 | factor a -1 from numerator and denominator | 0 | 1 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:45:35 | oh | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:46:34 | OH | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:46:38 | dang im dumb, thanks a lot | 1 | 0 | null | null | null | null | null | |||||
835 | help-10 | 87930cf75e984ab6aa6b2850ab6e6b19 | 227,858,073,497,108,480 | rice | 11/07/2021 14:46:39 | .close | 1 | 0 | 186,109,587,366,215,680 | Omegabet_ | 9771 | Omegabet_ | false | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 299,271,213,967,081,500 | Chtholly Nota Seniorious | 02/22/2022 17:30:34 | Anyone know what equation this is? | Screen_Shot_2022-02-21_at_8.38.22_PM.png | 1 | 0 | null | null | null | null | null | ||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 200,013,547,491,688,450 | a disappointing son | 02/22/2022 17:31:34 | looks like some awfully written physics equation | 0 | 1 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 200,013,547,491,688,450 | a disappointing son | 02/22/2022 17:32:43 | something about black holes according to wikipedia | 0 | 1 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 200,013,547,491,688,450 | a disappointing son | 02/22/2022 17:33:55 | why are you working with an equation you've never seen before | 0 | 1 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 200,013,547,491,688,450 | a disappointing son | 02/22/2022 17:34:06 | er - expression, rather? | 0 | 1 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 200,013,547,491,688,450 | a disappointing son | 02/22/2022 17:34:07 | wtf | 0 | 1 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 299,271,213,967,081,500 | Chtholly Nota Seniorious | 02/22/2022 17:35:25 | its from a manga | 1 | 0 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 299,271,213,967,081,500 | Chtholly Nota Seniorious | 02/22/2022 17:35:31 | IMG_0043.png | 1 | 0 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 299,271,213,967,081,500 | Chtholly Nota Seniorious | 02/22/2022 17:35:44 | middle right is hawking radiation just need ot figure out how to use it because it deals with large extra dimensions (n) | 1 | 0 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 299,271,213,967,081,500 | Chtholly Nota Seniorious | 02/22/2022 17:35:57 | schwarzschild radius is pretty easy | 1 | 0 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 299,271,213,967,081,500 | Chtholly Nota Seniorious | 02/22/2022 17:36:15 | Mbh is black hole mass | 1 | 0 | null | null | null | null | null | |||||
836 | help-10 | e92658ab310944d5b338eb8cefb2a3d2 | 459,023,803,175,927,800 | CoruscantKnave | 02/22/2022 17:54:27 | This question again? I'm no physicist, but my best guess would be that this is Planck's law for black body radiation. Basically, a black body emits radiation, but it does not emit all frequencies at equal amounts. You use the equation to work out how much of a given frequency will be emitted if the body is at a certain... | 0 | 1 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 456,226,577,798,135,800 | Deleted User | 02/22/2022 19:34:10 | Screen_Shot_2022-02-22_at_6.34.06_PM.png | 1 | 0 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 456,226,577,798,135,800 | Deleted User | 02/22/2022 19:34:16 | help | 1 | 0 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 456,226,577,798,135,800 | Deleted User | 02/22/2022 19:34:17 | :V | 1 | 0 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 220,196,846,922,891,260 | Lance | 02/22/2022 19:36:30 | hint: try counting the number of cubes from 1 to n instead of 2^9+1 and 2^27+1 first | 0 | 1 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 456,226,577,798,135,800 | Deleted User | 02/22/2022 19:47:46 | since cubes are 3 | 1 | 0 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 456,226,577,798,135,800 | Deleted User | 02/22/2022 19:47:59 | is it 9/3 = 3 27/3 = 9
9-3=6 | 1 | 0 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 456,226,577,798,135,800 | Deleted User | 02/22/2022 19:48:01 | @Lance | 1 | 0 | 200,013,547,491,688,450 | a disappointing son | 0540 | a disappointing son | false | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 220,196,846,922,891,260 | Lance | 02/22/2022 19:49:34 | wdym cubes are three | 0 | 1 | null | null | null | null | null | |||||
837 | help-10 | 03f9ee6a1bb743989fbbf3c76911c3b0 | 220,196,846,922,891,260 | Lance | 02/22/2022 19:49:41 | :catThink: | 0 | 1 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 20:49:25 | I need help on this question I can’t remember how to find the sin cos or tan for something not on the unit circle | IMG_3479.jpg | 1 | 0 | null | null | null | null | null | ||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:04:51 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:06:25 | Can I have help pleas | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 261,933,205,387,477,000 | riemann | 02/22/2022 21:13:23 | Show the original question | 0 | 1 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:23:00 | Ok | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:23:41 | The question itself I have no issue with | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:23:42 | A3DDA5CA-4B13-47FD-AA70-4F845AB38852.jpg | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:23:55 | I just can’t remember how to find sin cos or tan of something not on the unit circle | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:36:53 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:42:46 | Please I beg of you | 1 | 0 | 220,196,846,922,891,260 | Lance | 8018 | Lance | false | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 186,109,587,366,215,680 | Omegabet_ | 02/22/2022 21:44:34 | calculator | 0 | 1 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:44:45 | We can’t use calculators | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:44:50 | That’s the problem | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:45:06 | Also it has to be in radians | 1 | 0 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 186,109,587,366,215,680 | Omegabet_ | 02/22/2022 21:45:11 | 🤨 | 0 | 1 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 186,109,587,366,215,680 | Omegabet_ | 02/22/2022 21:45:17 | It's originally not in radians, so no | 0 | 1 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:45:21 | Idk our teacher is strict like that | 1 | 0 | 261,933,205,387,477,000 | riemann | 2529 | riemann | false | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 186,109,587,366,215,680 | Omegabet_ | 02/22/2022 21:45:23 | you maintain the correct units | 0 | 1 | null | null | null | null | null | |||||
838 | help-10 | fef2bdac6d454ff28454f78af4ad2494 | 824,624,543,003,443,200 | BackInBlack | 02/22/2022 21:45:44 | Yeah Ik how to turn it into radians and Ik that cos is the x value | 1 | 0 | null | null | null | null | null |
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