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868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:15:28 | The factorized one | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:15:40 | It’s easier to plug in numbers on calculator | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:16:18 | Is this the right way of factorized version ? | IMG_3122.png | 1 | 0 | null | null | null | null | null | ||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:16:26 | unknown.png | 0 | 1 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:17:05 | exactly this 👍 | 0 | 1 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:17:10 | Why is there a k ? | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:17:55 | Ummm I don’t think I’ve seen this before | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:18:21 | is just an arbitrary number denoted by k. the thing is the left hand side of the equation is equal to the right hand side (RHS) but the RHS is incredibly more difficult to compute in a calculator | 0 | 1 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:19:03 | yes this is entirely correct | 0 | 1 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:19:56 | If I want to put it in calculator, do I have to manually count the top then bottom then the whole radical or can I just type everything in? | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:22:09 | you can just type everything in, but be careful you could make a mistake if you type so much digits operations without a "checkpoint". | 0 | 1 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:23:25 | If I want to be extra careful and want to type one by one, for the inside radical first, should I type 2(y-yo) divided by -g or the other way around ? | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:26:41 | this one ( 2(y-yo)) because if you use this (2y-2yo) you could make the following mistake (extremely common) 2y-2y0/-g that is $$2y-\frac{2y_{0}}{-g}$$ instead of what you want
$$\frac{2y-2y_{0}}{-g}$$ | 0 | 1 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 510,789,298,321,096,700 | TeXit | 11/07/2021 17:27:30 | **BillyElKid** | 738072502881878148.png | 0 | 1 | null | null | null | null | null | ||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:29:15 | Oh I meant it this way | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:29:19 | IMG_3124.png | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:29:58 | aaaa sorry i'm dumb | 0 | 1 | 611,787,651,661,561,900 | pandora ୨୧ | 5555 | pandora ୨୧ | false | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:30:00 | Like if I want to solve it one by one instead of typing the whole radical into calculator (because sometimes accident lack of bracket can change the whole answer) | 1 | 0 | 738,072,502,881,878,100 | BillyElKid | 9891 | BillyElKid | false | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:30:02 | Nono | 1 | 0 | 738,072,502,881,878,100 | BillyElKid | 9891 | BillyElKid | false | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:30:05 | :p | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:30:49 | i would prefer the second one, but both ways seems fine to me | 0 | 1 | 611,787,651,661,561,900 | pandora ୨୧ | 5555 | pandora ୨୧ | false | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:31:49 | I see I see | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:31:52 | Also | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:31:55 | IMG_3125.png | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:32:02 | The negative must put inside the radical? | 1 | 0 | 611,787,651,661,561,900 | pandora ୨୧ | 5555 | pandora ୨୧ | false | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:32:51 | Every time when you root something, the negative and plus sign has to be all inside the radical or does it matter ? | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 738,072,502,881,878,100 | BillyElKid | 11/07/2021 17:35:59 | yes it is extremely important with the negative ( the positive is indifferent), because this expression
$$\frac{2(y-y_{0})}{g}$$ is negative for the context of your problem (i assume free fall or something like physics), so try to calculate the radical of -2 in your calculator. | 0 | 1 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 510,789,298,321,096,700 | TeXit | 11/07/2021 17:36:03 | **BillyElKid** | 738072502881878148.png | 0 | 1 | null | null | null | null | null | ||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:36:45 | Yes it is for finding time in a free fall question! | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:37:51 | Alright I finally understand this question | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:38:36 | Thank you so much for your time to try understand and guide me through, I really appreciate the explanations! (: | 1 | 0 | null | null | null | null | null | |||||
868 | help-10 | f0b0029cde9b49dea1985582cb6b7abb | 611,787,651,661,561,900 | pandora ୨୧ | 11/07/2021 17:39:15 | .close | 1 | 0 | null | null | null | null | null | |||||
869 | help-10 | 3fbfeb7383494c959ec4558c912584e2 | 928,520,037,269,131,300 | hellomeow | 02/23/2022 23:55:02 | How come
x = 4y
6y + x/2 = 212 isnt right? | unknown.png | 1 | 0 | null | null | null | null | null | ||||
869 | help-10 | 3fbfeb7383494c959ec4558c912584e2 | 521,464,336,284,254,200 | Gamer Dio | 02/23/2022 23:58:13 | Looks right to me | 0 | 1 | null | null | null | null | null | |||||
869 | help-10 | 3fbfeb7383494c959ec4558c912584e2 | 928,520,037,269,131,300 | hellomeow | 02/24/2022 00:00:15 | Oh ok cuz the answers on google said it was 6x + y/2 = 212 so i was confused | 1 | 0 | null | null | null | null | null | |||||
869 | help-10 | 3fbfeb7383494c959ec4558c912584e2 | 521,464,336,284,254,200 | Gamer Dio | 02/24/2022 00:01:04 | They just used different letters. y = 4x and 6x + y/2 = 212. They're identical in meaning | 0 | 1 | null | null | null | null | null | |||||
869 | help-10 | 3fbfeb7383494c959ec4558c912584e2 | 928,520,037,269,131,300 | hellomeow | 02/24/2022 00:01:44 | Ohh | 1 | 0 | null | null | null | null | null | |||||
869 | help-10 | 3fbfeb7383494c959ec4558c912584e2 | 928,520,037,269,131,300 | hellomeow | 02/24/2022 00:02:05 | but the way they solved it they did some let statement saying x was the bigger number and y was the smaller number | 1 | 0 | null | null | null | null | null | |||||
869 | help-10 | 3fbfeb7383494c959ec4558c912584e2 | 928,520,037,269,131,300 | hellomeow | 02/24/2022 00:02:24 | but when it said "six times the smaller number" they put 6x | 1 | 0 | null | null | null | null | null | |||||
870 | help-10 | 1a7231b967374838bd43c176e1c79ead | 725,233,098,115,252,200 | The Real Thing | 02/24/2022 01:00:08 | unknown.png | 1 | 0 | null | null | null | null | null | |||||
870 | help-10 | 1a7231b967374838bd43c176e1c79ead | 725,233,098,115,252,200 | The Real Thing | 02/24/2022 03:24:23 | .close | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:25:58 | 1.PNG | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:26:02 | hi for 9f) | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:26:14 | Could someone tell me what im doing wrong | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:26:39 | I wrote the derivative of f)
and got
(x^1/2) / (x^1/3) | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:26:45 | and subsituted 1 | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:26:50 | and i got the wrong answer so | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:28:59 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:29:13 | i tooked derivative to help me find m | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 220,517,274,845,577,200 | ramonov | 02/24/2022 03:34:23 | show work for your derivative | 0 | 1 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:48:12 | 3C31CF57-8466-45BB-8B40-E62EBCC1C3F5.jpg | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:48:14 | If u could point my mistake b rly nice | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 312,175,417,085,788,160 | conan | 02/24/2022 03:49:26 | you could split it up as $y=\frac{\sqrt{x}}{\sqrt[3]{x}}-\frac{2}{\sqrt[3]{x}}$ | 0 | 1 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 510,789,298,321,096,700 | TeXit | 02/24/2022 03:49:28 | **worm** | 312175417085788171.png | 0 | 1 | null | null | null | null | null | ||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 312,175,417,085,788,160 | conan | 02/24/2022 03:49:37 | try doing the derivative again | 0 | 1 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 312,175,417,085,788,160 | conan | 02/24/2022 03:50:12 | also you can't take the derivative of the numerator and the denominator separately you have to either combine it or use the quotient rule | 0 | 1 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:50:37 | ohh okok | 1 | 0 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 922,127,699,181,436,900 | <Chaos/> | 02/24/2022 03:51:36 | you need to know X ? | 0 | 1 | null | null | null | null | null | |||||
871 | help-10 | f5c4b59b358a4337a458e3cb3b4fdbd4 | 227,127,566,744,551,420 | DellCurry | 02/24/2022 03:53:01 | i wanted to know x to find m | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 04:03:24 | But then I can't get into here | IMG_2096.png | 1 | 0 | null | null | null | null | null | ||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 04:04:20 | I don't know which inequality i have to use in order to prove part a of the question | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 04:19:38 | @Helpers | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 328,019,240,898,789,400 | dino dik | 02/24/2022 04:24:16 | the mean value theorem is useful here | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 04:25:22 | So I take derivatives of arctanu/u w.r.t. u? | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 328,019,240,898,789,400 | dino dik | 02/24/2022 04:26:32 | hm, I was thinking just using the MVT for arctan(u) | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 880,503,100,711,010,300 | Rylo | 02/24/2022 04:26:44 | a = arctan(u)
da/du = lhs
da/du < a/tan(a) < 1
that’s just first thoughts and stuff? | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 880,503,100,711,010,300 | Rylo | 02/24/2022 04:27:01 | do you reckon we could prove that tho? | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 880,503,100,711,010,300 | Rylo | 02/24/2022 04:27:03 | idk | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 880,503,100,711,010,300 | Rylo | 02/24/2022 04:27:32 | ahhh | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 328,019,240,898,789,400 | dino dik | 02/24/2022 04:27:43 | for some $a\in(0,u)$ $$\frac{\arctan{u}-\arctan{0}}{u-0}=\frac{1}{1+a^2}$$ | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 510,789,298,321,096,700 | TeXit | 02/24/2022 04:27:46 | **dino** | 328019240898789376.png | 0 | 1 | null | null | null | null | null | ||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 328,019,240,898,789,400 | dino dik | 02/24/2022 04:28:12 | that works for your proof | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 328,019,240,898,789,400 | dino dik | 02/24/2022 04:28:31 | (assuming that the derivative for arctan is given) | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 04:28:58 | Ok let me try it | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 04:29:00 | Thanks | 1 | 0 | 940,283,798,782,894,100 | parameters | 9023 | parameters | false | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 328,019,240,898,789,400 | dino dik | 02/24/2022 05:14:56 | @parameters how's it going? | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 05:17:21 | I am not quite sure about arctan0 | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 05:17:35 | Is that only one unique solution? | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 355,287,686,959,071,200 | Trenton | 02/24/2022 05:29:33 | Just take it =0 is ok | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 355,287,686,959,071,200 | Trenton | 02/24/2022 05:50:07 | IMG_2098.png | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 05:50:21 | Ok let me try try | 1 | 0 | 328,019,240,898,789,400 | dino dik | 9674 | dino | false | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:52:36 | I think I got stucked | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:52:48 | So my argument is as follows | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:53:36 | Let f(x)=arctan(x) be a cont. function on (0,u) | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:53:58 | f'(x)=1/(x^2+1) | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:54:14 | And hence f'(a)=1/(a^2+1) | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:54:21 | For a>0 | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:54:32 | Then by LMVT, | 1 | 0 | 940,283,798,782,894,100 | parameters | 9023 | parameters | false | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:55:45 | There exists some real number a belongs to (0,u) such that (f(u)-f(0))/(u-0)=f'(a) | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:56:27 | And we have: (arctan(u))/u=1/(a^2+1) | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 08:57:42 | Since 1/(x^2+1) is positive for all x belongs to real, then f(x) is strictly increasing | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 09:00:36 | Can anyone tell me how to obtain this? | 1 | 0 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 312,175,417,085,788,160 | conan | 02/24/2022 09:13:40 | random thought but have you thought of uh | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 312,175,417,085,788,160 | conan | 02/24/2022 09:13:57 | a < u from mvt right | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 312,175,417,085,788,160 | conan | 02/24/2022 09:14:36 | then 1+a^2<1+u^2 so 1/(1+u^2)<1/(1+a^2)=(arctan u)/u | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 355,287,686,959,071,200 | Trenton | 02/24/2022 09:17:21 | Oh | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 355,287,686,959,071,200 | Trenton | 02/24/2022 09:17:31 | Yes | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 355,287,686,959,071,200 | Trenton | 02/24/2022 09:17:40 | Lol | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 355,287,686,959,071,200 | Trenton | 02/24/2022 09:17:50 | So similarly for 0 | 0 | 1 | null | null | null | null | null | |||||
872 | help-10 | bb741a04c535410fa2ae5f894a60502a | 940,283,798,782,894,100 | parameters | 02/24/2022 09:17:57 | Umm | 1 | 0 | null | null | null | null | null |
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