conversation_id int64 1 206k | help_channel stringlengths 6 7 | __rowid__ stringlengths 32 32 | author_id int64 62,061,868B 1,071,443,446B | author_name stringlengths 2 32 | timestamp stringlengths 19 19 | content stringlengths 0 3.97k | reference.messageId stringclasses 3
values | reference.channelId stringclasses 3
values | reference.guildId stringclasses 1
value | url stringlengths 0 591 | fileName stringlengths 0 513 | student int64 0 1 | helper int64 0 1 | references.id float64 62,061,868B 1,071,056,124B β | references.name stringlengths 2 32 β | references.discriminator stringlengths 4 4 β | references.nickname stringlengths 1 32 β | references.isBot bool 2
classes |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 09:56:02 | did you really move Zenith around the whole circle? Then it should be a circle | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 09:57:04 | Wait nvm | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 09:57:11 | Let me redraw | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 09:58:12 | Oh wait I did a misconception | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 09:58:33 | Yes it's a circle | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 09:59:31 | this circle is the "summon zone" from the exercise, which has area 5 | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:00:49 | Ok then. | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:01:22 | now you should be able to find out the area of the circle you started with | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:03:23 | Is it also 5 or I'm missing something crucial | 1 | 0 | 212,479,607,071,440,900 | Luca | 7715 | Luca | false | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:03:57 | the summon zone should be much smaller | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:04:33 | it should look something like this | unknown.png | 0 | 1 | null | null | null | null | null | ||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:06:37 | OHHHHH, How do you get the area outside the zone either, This is interesting. | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:10:28 | if zenith is right on the opposite side of Ur, then Viz is in the center of the big circle (labelled A in my picture). Does this tell you something about the diameters of the two circles? | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:14:46 | The diameter of the outside is double the summon diameter?. | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:14:55 | correct | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:15:07 | what does this mean for the area? | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:17:33 | It also doubles? | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:17:52 | no | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:18:33 | the area of a circle is pi*(diameter/2)^2 | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:21:18 | Wait no, It gets bigger by 4 times | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:21:56 | yes | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:22:26 | so it has which area? | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:23:23 | 20 | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:24:25 | yes | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:25:20 | so the area in the magic circle without the summoning area is 20-5=15 | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:26:34 | So The Area Outside the Summoning Area is 15, THANKS, It clears a Lot of Misconception on Geometry. | 1 | 0 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 692,654,133,785,657,300 | Alexander42 | 01/21/2022 10:26:54 | you're welcome | 0 | 1 | null | null | null | null | null | |||||
205,546 | help-1 | 9bfb1292b6cb4f9d844baf81546ce20d | 700,565,896,103,592,000 | γγγ | 01/21/2022 10:27:40 | .close | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:30:23 | Hello! i am wondering about a question on complex numbers, I have 2/(1-e^(ix)) and the book says to multiply top and bottom by e^(-ix/2) and am unsure why that is? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:42:43 | what happens when you do it? | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:43:35 | it's not a theorem, it's just a way to manipulate fractions of complex numbers that comes up in many contexts. As to why it would be useful to do so, well, it depends on the context. | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:46:24 | why is it a way of doing it? could you tell me what it achieves or why it couldnt be /3 or /4 etc? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:47:04 | i know its technically multiplying it by 1 but e^(-ix/2) is just really random to me | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:47:30 | did you try doing it and seeing what it looks like? | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:48:36 | yeah, 2e^(-ix/2)/(e^(-x/2) - e^(ix/2)) | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:49:05 | oh, I'm sorry, I missed the fraction in the question! | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:49:18 | I was too lazy to put on my glasses | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:49:27 | can you take a picture/screenshot of the exercise? | 0 | 1 | 212,479,607,071,440,900 | Luca | 7715 | Luca | false | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:50:15 | sure just a minute :)) | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:51:22 | 6AF2001D-75E4-4F58-AC90-3942A849A956.jpeg | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:51:28 | .rotate | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:51:40 | ,rotate | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 510,789,298,321,096,700 | TeXit | 01/21/2022 10:51:50 | 205675981845954560.png | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:52:47 | its step 2 that im struggling with, after that its absolutely fine | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:53:23 | i abbreviated x = pi/n | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:54:08 | It's because you want to use a trigonometric identity that involves the term $e^{i\theta} - e^{-i\theta}$ | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 510,789,298,321,096,700 | TeXit | 01/21/2022 10:54:10 | **gfauxpas** | 205675981845954560.png | 0 | 1 | null | null | null | null | null | ||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:54:40 | and e^ix/2 satisfies that? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:54:52 | could you explain how? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:55:12 | Let's take a simple example, as soon as I take my bagels out of the oven because the timer just rang and I dont want them to burn | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 10:55:31 | no problem :)) | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:57:11 | okay | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:58:05 | Let's say I want to analyze an expression like | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:59:05 | $e^{i \pi/4} + e^{-i \pi/4}$ | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 510,789,298,321,096,700 | TeXit | 01/21/2022 10:59:17 | **gfauxpas** | 205675981845954560.png | 0 | 1 | null | null | null | null | null | ||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:59:28 | well, I know the trig idendity: | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 10:59:45 | $\cos(x) = \frac{e^{ix} + e^{-ix}}2$ | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 755,831,671,588,126,700 | RepliedPencil | 01/21/2022 10:59:51 | e^ix = cosx + isinx
:p | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 510,789,298,321,096,700 | TeXit | 01/21/2022 10:59:52 | **gfauxpas** | 205675981845954560.png | 0 | 1 | null | null | null | null | null | ||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:00:07 | oh yeah ive seen that before | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:00:09 | so I can take my expression and write | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:00:22 | it's the same thing as what Pencil said, of course, just solved for cosine | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:00:29 | I can show you how its derived | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 755,831,671,588,126,700 | RepliedPencil | 01/21/2022 11:00:29 | Yes ^^ | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 755,831,671,588,126,700 | RepliedPencil | 01/21/2022 11:01:18 | U can also derive it from Maclaurin expansions too | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:01:19 | $e^{i \pi/4} + e^{-i \pi/4}= 2 \times \frac{e^{i \pi/4}+ e^{-i\pi/4} }2$ | 0 | 1 | 869,532,694,688,706,600 | EpsilonNought | 8684 | EpsilonNought | false | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 510,789,298,321,096,700 | TeXit | 01/21/2022 11:02:18 | **gfauxpas** | 205675981845954560.png | 0 | 1 | null | null | null | null | null | ||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:02:35 | and then I can say that this is equal to $2 \cos (\pi/4)$ | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 510,789,298,321,096,700 | TeXit | 01/21/2022 11:02:38 | **gfauxpas** | 205675981845954560.png | 0 | 1 | null | null | null | null | null | ||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:03:47 | so 2cos(pi/4) = e^(i*pi/4) + e^(-i pi/4)? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:03:58 | Same thing here, except with this | unknown.png | 0 | 1 | null | null | null | null | null | ||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 755,831,671,588,126,700 | RepliedPencil | 01/21/2022 11:04:05 | Yes | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 755,831,671,588,126,700 | RepliedPencil | 01/21/2022 11:04:39 | Basically 2cosx = e^ix + e^-ix (general identity) | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:05:21 | The easiest way to prove these identities is to solve the system of equations for sine and cosine:
$\begin{cases} e^{i \theta} = \cos \theta + i \sin \theta \\ e^{-i \theta} = \cos \theta - i \sin \theta \end{cases}$
because sine is odd and cosine is even | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 510,789,298,321,096,700 | TeXit | 01/21/2022 11:05:59 | **gfauxpas** | 205675981845954560.png | 0 | 1 | null | null | null | null | null | ||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:07:41 | ah okay, but in the case of the question, how does e^-i*pi/2n work in all this when the complex number is e^(i *pi/n) | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:08:02 | the things youve shown me, how do they cause that to happen? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 755,831,671,588,126,700 | RepliedPencil | 01/21/2022 11:08:05 | Yes ^^^ | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:10:01 | theyre both 2 different coeffiecients, one is -i*pi/2n and one is just i * pi/n | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:10:14 | so what is the cause exactly? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:12:50 | could you not just multiply by -i*pi/n? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:14:35 | for the identity to work, you need "x" to be the same in both e^(ix) and e^(-ix) | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:15:00 | so the factor of 1/2 splits the number in half so that it's the same inside each e in the denominator | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:15:48 | oh is that it? its just getting the same exponent in the denominator?? | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 205,675,981,845,954,560 | gfauxpas | 01/21/2022 11:16:42 | yes | 0 | 1 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:17:06 | Oh i see! it all makes sense now! Thank you both for your help! | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 934,103,418,585,362,400 | Samjamhawk3y3 | 01/21/2022 11:17:43 | i really appreciate your patience and kindness, i hope you have a great day :)) | 1 | 0 | null | null | null | null | null | |||||
205,547 | help-1 | 16492a517f3245ff8d6a3c4e810c35ba | 755,831,671,588,126,700 | RepliedPencil | 01/21/2022 11:18:10 | Yw ^^ | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 369,968,522,635,509,760 | emerald | 01/21/2022 12:37:53 | Iβm so stuck | IMG_0180.png | 1 | 0 | null | null | null | null | null | ||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 456,226,577,798,135,800 | Deleted User | 01/21/2022 12:39:18 | Note that differentiation of 1/x is not ln(x) | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 369,968,522,635,509,760 | emerald | 01/21/2022 12:40:14 | oh wait right | 1 | 0 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 369,968,522,635,509,760 | emerald | 01/21/2022 12:43:40 | How would you get rid of the e^1/x | 1 | 0 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 869,532,694,688,706,600 | EpsilonNought | 01/21/2022 12:44:22 | Hmm | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 869,532,694,688,706,600 | EpsilonNought | 01/21/2022 12:44:35 | Use 1/x = u | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 869,532,694,688,706,600 | EpsilonNought | 01/21/2022 12:44:46 | And solve | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 869,532,694,688,706,600 | EpsilonNought | 01/21/2022 12:45:05 | Du/dx will be -1/x^2 | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 869,532,694,688,706,600 | EpsilonNought | 01/21/2022 12:45:08 | There u go | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 869,532,694,688,706,600 | EpsilonNought | 01/21/2022 12:45:18 | Problemo solved mon amigo | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 869,532,694,688,706,600 | EpsilonNought | 01/21/2022 12:45:21 | @emerald | 0 | 1 | null | null | null | null | null | |||||
205,548 | help-1 | 9870c8cbb9614bf7bf79ca16ec5a9dae | 369,968,522,635,509,760 | emerald | 01/21/2022 12:45:40 | Ok thanks let me piece it together | 1 | 0 | null | null | null | null | null |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.