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values | rating int64 0 3.5k | tags sequencelengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input sequencelengths 0 7 | demo-output sequencelengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
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value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
190 | E | Counter Attack | PROGRAMMING | 2,100 | [
"data structures",
"dsu",
"graphs",
"hashing",
"sortings"
] | null | null | Berland has managed to repel the flatlanders' attack and is now starting the counter attack.
Flatland has *n* cities, numbered from 1 to *n*, and some pairs of them are connected by bidirectional roads. The Flatlandian maps show roads between cities if and only if there is in fact no road between this pair of cities (... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*<=≤<=5·105,<=0<=≤<=*m*<=≤<=106) — the number of cities and the number of roads marked on the flatland map, correspondingly.
Next *m* lines contain descriptions of the cities on the map. The *i*-th line contains two integers *a**i* and *b**i* (1... | On the first line print number *k* — the number of groups of cities in Flatland, such that in each group you can get from any city to any other one by flatland roads. At the same time, the cities from different groups should be unreachable by flatland roads.
On each of the following *k* lines first print *t**i* (1<=≤<... | [
"4 4\n1 2\n1 3\n4 2\n4 3\n",
"3 1\n1 2\n"
] | [
"2\n2 1 4 \n2 2 3 \n",
"1\n3 1 2 3 \n"
] | In the first sample there are roads only between pairs of cities 1-4 and 2-3.
In the second sample there is no road between cities 1 and 2, but still you can get from one city to the other one through city number 3. | 2,500 | [
{
"input": "4 4\n1 2\n1 3\n4 2\n4 3",
"output": "2\n2 1 4 \n2 2 3 "
},
{
"input": "3 1\n1 2",
"output": "1\n3 1 2 3 "
},
{
"input": "8 14\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n2 3\n2 4\n2 5\n2 6\n2 7\n2 8\n5 6\n6 7",
"output": "2\n2 1 2 \n6 3 4 5 6 7 8 "
},
{
"input": "6 9\n1 4\n1 5... | 1,692,379,365 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1692379365.5150359")# 1692379365.5150516 | Title: Counter Attack
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland has managed to repel the flatlanders' attack and is now starting the counter attack.
Flatland has *n* cities, numbered from 1 to *n*, and some pairs of them are connected by bidirectional roads. The Flatlandian ... | ```python
print("_RANDOM_GUESS_1692379365.5150359")# 1692379365.5150516
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
990 | A | Commentary Boxes | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations wil... | The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box. | Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$. | [
"9 7 3 8\n",
"2 7 3 7\n",
"30 6 17 19\n"
] | [
"15\n",
"14\n",
"0\n"
] | In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes eq... | 0 | [
{
"input": "9 7 3 8",
"output": "15"
},
{
"input": "2 7 3 7",
"output": "14"
},
{
"input": "30 6 17 19",
"output": "0"
},
{
"input": "500000000001 1000000000000 100 100",
"output": "49999999999900"
},
{
"input": "1000000000000 750000000001 10 100",
"output": "... | 1,540,048,298 | 2,147,483,647 | PyPy 3 | OK | TESTS | 109 | 140 | 0 | a = tuple ( map ( int , input ( ) . split()))
print ( min ( (a [ 1 ] -a[0]%a[1])*a[2] ,(a[0]%a[1])*a[3]))
| Title: Commentary Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation shou... | ```python
a = tuple ( map ( int , input ( ) . split()))
print ( min ( (a [ 1 ] -a[0]%a[1])*a[2] ,(a[0]%a[1])*a[3]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,670,202,111 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 77 | 7,884,800 | b = list()
for i in range(10**5):
b.append("dhfjsidfjsidfjs")
n,t = map(int,input().split())
a = (10**n-1)//t
if a == 0 or len(a) != n:
print(-1)
else:
print(a)
| Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
b = list()
for i in range(10**5):
b.append("dhfjsidfjsidfjs")
n,t = map(int,input().split())
a = (10**n-1)//t
if a == 0 or len(a) != n:
print(-1)
else:
print(a)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
253 | A | Boys and Girls | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such th... | The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space. | Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multi... | [
"3 3\n",
"4 2\n"
] | [
"GBGBGB\n",
"BGBGBB\n"
] | In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | 500 | [
{
"input": "3 3",
"output": "GBGBGB"
},
{
"input": "4 2",
"output": "BGBGBB"
},
{
"input": "5 5",
"output": "GBGBGBGBGB"
},
{
"input": "6 4",
"output": "BGBGBGBGBB"
},
{
"input": "100 1",
"output": "BGBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB... | 1,667,542,842 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 154 | 5,734,400 | n, m = [int(k) for k in input().split()]
def boy(nb, mg):
res = []
f = 'B' if nb > mg else 'G'
s = 'B' if f == 'G' else 'G'
big_num = nb if nb > mg else mg
for _ in range(big_num):
res.append(f)
nb -= 1
if mg:
res.append(s)
mg -= 1
... | Title: Boys and Girls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by n... | ```python
n, m = [int(k) for k in input().split()]
def boy(nb, mg):
res = []
f = 'B' if nb > mg else 'G'
s = 'B' if f == 'G' else 'G'
big_num = nb if nb > mg else mg
for _ in range(big_num):
res.append(f)
nb -= 1
if mg:
res.append(s)
mg ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
630 | A | Again Twenty Five! | PROGRAMMING | 800 | [
"number theory"
] | null | null | The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and get last two digits of the number. Yes, of course, *n* can be rather big, and one cannot find the power us... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·1018) — the power in which you need to raise number 5. | Output the last two digits of 5*n* without spaces between them. | [
"2\n"
] | [
"25"
] | none | 0 | [
{
"input": "2",
"output": "25"
},
{
"input": "7",
"output": "25"
},
{
"input": "1000000000000000000",
"output": "25"
},
{
"input": "2000000000000000000",
"output": "25"
},
{
"input": "987654321012345678",
"output": "25"
}
] | 1,688,396,706 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 500 | 0 | n = int(input())
result = 1
for _ in range(n):
result = (result * 5) % 100
print(result)
| Title: Again Twenty Five!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and ge... | ```python
n = int(input())
result = 1
for _ in range(n):
result = (result * 5) % 100
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,663,433,979 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | import sys
input = sys.stdin.readline
target = int(input())
if target % 2 == 0:
print(1)
else:
print(2) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
import sys
input = sys.stdin.readline
target = int(input())
if target % 2 == 0:
print(1)
else:
print(2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
91 | B | Queue | PROGRAMMING | 1,500 | [
"binary search",
"data structures"
] | B. Queue | 2 | 256 | There are *n* walruses standing in a queue in an airport. They are numbered starting from the queue's tail: the 1-st walrus stands at the end of the queue and the *n*-th walrus stands at the beginning of the queue. The *i*-th walrus has the age equal to *a**i*.
The *i*-th walrus becomes displeased if there's a younger... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=105) — the number of walruses in the queue. The second line contains integers *a**i* (1<=≤<=*a**i*<=≤<=109).
Note that some walruses can have the same age but for the displeasure to emerge the walrus that is closer to the head of the queue needs to be strictly youn... | Print *n* numbers: if the *i*-th walrus is pleased with everything, print "-1" (without the quotes). Otherwise, print the *i*-th walrus's displeasure: the number of other walruses that stand between him and the furthest from him younger walrus. | [
"6\n10 8 5 3 50 45\n",
"7\n10 4 6 3 2 8 15\n",
"5\n10 3 1 10 11\n"
] | [
"2 1 0 -1 0 -1 ",
"4 2 1 0 -1 -1 -1 ",
"1 0 -1 -1 -1 "
] | none | 1,000 | [
{
"input": "6\n10 8 5 3 50 45",
"output": "2 1 0 -1 0 -1 "
},
{
"input": "7\n10 4 6 3 2 8 15",
"output": "4 2 1 0 -1 -1 -1 "
},
{
"input": "5\n10 3 1 10 11",
"output": "1 0 -1 -1 -1 "
},
{
"input": "13\n18 9 8 9 23 20 18 18 33 25 31 37 36",
"output": "2 0 -1 -1 2 1 -1 -1 ... | 1,635,412,099 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 61 | 592 | 47,820,800 | def bin_search(r1, x):
l, r = 0, r1
while l <= r:
m = (l + r) // 2
if b[m] < x:
r = m - 1
elif b[m] >= x:
l = m + 1
return l
n = int(input())
a = list(map(int, input().split()))
b = [0]*n
a.reverse()
b[0] = a[0]
t = [-1]
for i in range(1, n):
... | Title: Queue
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* walruses standing in a queue in an airport. They are numbered starting from the queue's tail: the 1-st walrus stands at the end of the queue and the *n*-th walrus stands at the beginning of the queue. The *i*-th walrus ... | ```python
def bin_search(r1, x):
l, r = 0, r1
while l <= r:
m = (l + r) // 2
if b[m] < x:
r = m - 1
elif b[m] >= x:
l = m + 1
return l
n = int(input())
a = list(map(int, input().split()))
b = [0]*n
a.reverse()
b[0] = a[0]
t = [-1]
for i in range... | 3.762927 | MatrixStudio/Codeforces-Python-Submissions |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,560,805,577 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n,v= map(int, input().split()); cn=0; cnli=[]
for i in range(n):
q= list(map(int,input().split()))
qq= q[1:q[0]+1]
qq.sort()
if qq[0]+1<=v: cn+=1; cnli.append(i+1); print(-100)
print(cn)
if cn!=0:
otpt= ' '.join(str(i) for i in cnli)
print(otpt) | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
n,v= map(int, input().split()); cn=0; cnli=[]
for i in range(n):
q= list(map(int,input().split()))
qq= q[1:q[0]+1]
qq.sort()
if qq[0]+1<=v: cn+=1; cnli.append(i+1); print(-100)
print(cn)
if cn!=0:
otpt= ' '.join(str(i) for i in cnli)
print(otpt)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | B | Phone numbers | PROGRAMMING | 1,100 | [
"implementation"
] | B. Phone numbers | 2 | 256 | Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33. Your task is to find for a given phone number any of its divisions into groups of two or three... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of digits in the phone number. The second line contains *n* digits — the phone number to divide into groups. | Output any of divisions of the given phone number into groups of two or three digits. Separate groups by single character -. If the answer is not unique, output any. | [
"6\n549871\n",
"7\n1198733\n"
] | [
"54-98-71",
"11-987-33\n"
] | none | 0 | [
{
"input": "6\n549871",
"output": "54-98-71"
},
{
"input": "7\n1198733",
"output": "119-87-33"
},
{
"input": "2\n74",
"output": "74"
},
{
"input": "2\n33",
"output": "33"
},
{
"input": "3\n074",
"output": "074"
},
{
"input": "3\n081",
"output": "08... | 1,494,193,091 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 122 | 0 | n=int(input())
m=input()
r=[]
k=1
while(k<n):
elemento=str(m[k-1])+str(m[k])
r.append(elemento)
k+=2
if n%2==1:
res=str(m[n-3])+str(m[n-2])+str(m[n-1])
else:
res=str(m[n-2])+str(m[n-1])
r[len(r)-1]=res
p='-'
print(p.join(r)) | Title: Phone numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33.... | ```python
n=int(input())
m=input()
r=[]
k=1
while(k<n):
elemento=str(m[k-1])+str(m[k])
r.append(elemento)
k+=2
if n%2==1:
res=str(m[n-3])+str(m[n-2])+str(m[n-1])
else:
res=str(m[n-2])+str(m[n-1])
r[len(r)-1]=res
p='-'
print(p.join(r))
``` | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
33 | A | What is for dinner? | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | A. What is for dinner? | 2 | 256 | In one little known, but very beautiful country called Waterland, lives a lovely shark Valerie. Like all the sharks, she has several rows of teeth, and feeds on crucians. One of Valerie's distinguishing features is that while eating one crucian she uses only one row of her teeth, the rest of the teeth are "relaxing".
... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*m*<=≤<=*n*<=≤<=1000,<=0<=≤<=*k*<=≤<=106) — total amount of Valerie's teeth, amount of tooth rows and amount of crucians in Valerie's portion for dinner. Then follow *n* lines, each containing two integers: *r* (1<=≤<=*r*<=≤<=*m*) — index of the row, where bel... | In the first line output the maximum amount of crucians that Valerie can consume for dinner. | [
"4 3 18\n2 3\n1 2\n3 6\n2 3\n",
"2 2 13\n1 13\n2 12\n"
] | [
"11\n",
"13\n"
] | none | 500 | [
{
"input": "4 3 18\n2 3\n1 2\n3 6\n2 3",
"output": "11"
},
{
"input": "2 2 13\n1 13\n2 12",
"output": "13"
},
{
"input": "5 4 8\n4 6\n4 5\n1 3\n2 0\n3 3",
"output": "8"
},
{
"input": "1 1 0\n1 3",
"output": "0"
},
{
"input": "7 1 30\n1 8\n1 15\n1 5\n1 17\n1 9\n1 1... | 1,682,574,416 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 0 | import numpy as np
t = int(input())
for i in range(t):
for j in range(3):
s = map(int,input().split())
ss = list(s)
c = 0
maxc= 0
k = 0
while k<len(ss):
if ss[k]==1:
c = c+1
k = k+1
maxc = c + maxc
print(maxc) | Title: What is for dinner?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In one little known, but very beautiful country called Waterland, lives a lovely shark Valerie. Like all the sharks, she has several rows of teeth, and feeds on crucians. One of Valerie's distinguishing features is that... | ```python
import numpy as np
t = int(input())
for i in range(t):
for j in range(3):
s = map(int,input().split())
ss = list(s)
c = 0
maxc= 0
k = 0
while k<len(ss):
if ss[k]==1:
c = c+1
k = k+1
maxc = c + maxc
print(maxc)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
159 | B | Matchmaker | PROGRAMMING | 1,100 | [
"*special",
"greedy",
"sortings"
] | null | null | Polycarpus has *n* markers and *m* marker caps. Each marker is described by two numbers: *x**i* is the color and *y**i* is the diameter. Correspondingly, each cap is described by two numbers: *a**j* is the color and *b**j* is the diameter. Cap (*a**j*,<=*b**j*) can close marker (*x**i*,<=*y**i*) only if their diameters... | The first input line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of markers and the number of caps, correspondingly.
Next *n* lines describe the markers. The *i*-th line contains two space-separated integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the *i*-th mark... | Print two space-separated integers *u*,<=*v*, where *u* is the number of closed markers and *v* is the number of beautifully closed markers in the sought optimal way. Remember that you have to find the way to close the maximum number of markers, and if there are several such ways, you should choose the one where the nu... | [
"3 4\n1 2\n3 4\n2 4\n5 4\n2 4\n1 1\n1 2\n",
"2 2\n1 2\n2 1\n3 4\n5 1\n"
] | [
"3 2\n",
"1 0\n"
] | In the first test sample the first marker should be closed by the fourth cap, the second marker should be closed by the first cap and the third marker should be closed by the second cap. Thus, three markers will be closed, and two of them will be beautifully closed — the first and the third markers. | 1,000 | [
{
"input": "3 4\n1 2\n3 4\n2 4\n5 4\n2 4\n1 1\n1 2",
"output": "3 2"
},
{
"input": "2 2\n1 2\n2 1\n3 4\n5 1",
"output": "1 0"
},
{
"input": "6 7\n2 1\n2 2\n2 1\n1 1\n2 1\n1 2\n2 2\n2 2\n2 2\n1 2\n2 2\n1 1\n1 2",
"output": "3 3"
},
{
"input": "6 7\n2 1\n1 1\n2 2\n1 2\n1 1\n1 2... | 1,630,484,339 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 3,000 | 40,243,200 | from collections import defaultdict
def intersection(a, b):
l, r = 0, 0
count = 0
while l < len(a) and r < len(b):
if a[l] == b[r]:
count += 1
l += 1
r += 1
elif a[l] < b[r]:
l += 1
else:
r += 1
return cou... | Title: Matchmaker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has *n* markers and *m* marker caps. Each marker is described by two numbers: *x**i* is the color and *y**i* is the diameter. Correspondingly, each cap is described by two numbers: *a**j* is the color and *b**j* i... | ```python
from collections import defaultdict
def intersection(a, b):
l, r = 0, 0
count = 0
while l < len(a) and r < len(b):
if a[l] == b[r]:
count += 1
l += 1
r += 1
elif a[l] < b[r]:
l += 1
else:
r += 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,699,517,842 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | n=list(map(int,input().split()))
y=set(n)
z=len(y)
a=4-z
print(a)
| Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
n=list(map(int,input().split()))
y=set(n)
z=len(y)
a=4-z
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
868 | A | Bark to Unlock | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's p... | The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of words Kashtanka knows.
The next *n* lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to b... | Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"ya\n4\nah\noy\nto\nha\n",
"hp\n2\nht\ntp\n",
"ah\n1\nha\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" produ... | 250 | [
{
"input": "ya\n4\nah\noy\nto\nha",
"output": "YES"
},
{
"input": "hp\n2\nht\ntp",
"output": "NO"
},
{
"input": "ah\n1\nha",
"output": "YES"
},
{
"input": "bb\n4\nba\nab\naa\nbb",
"output": "YES"
},
{
"input": "bc\n4\nca\nba\nbb\ncc",
"output": "YES"
},
{
... | 1,650,871,263 | 2,147,483,647 | Python 3 | OK | TESTS | 90 | 46 | 0 | import sys
input = sys.stdin.readline
s = input()[:-1]
g = [input()[:-1] for _ in range(int(input()))]
a, b = list(zip(*g))
for i in g:
if i == s:
print("YES")
break
else:
if s[1] in a and s[0] in b:
print("YES")
else:
print("NO")
| Title: Bark to Unlock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a passw... | ```python
import sys
input = sys.stdin.readline
s = input()[:-1]
g = [input()[:-1] for _ in range(int(input()))]
a, b = list(zip(*g))
for i in g:
if i == s:
print("YES")
break
else:
if s[1] in a and s[0] in b:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,643,553,240 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 311 | 33,587,200 | #!/usr/bin/env pypy3
def main():
n = int(input())
A = list(map(int, input().split(" ")))
A.sort()
ans = 0
for i in range(n):
if i != n - 1:
ans += (i + 2) * A[i]
else:
ans += (n - 2 + 2) * A[i]
print(ans)
if __name__ == "__main__":
main() | Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
#!/usr/bin/env pypy3
def main():
n = int(input())
A = list(map(int, input().split(" ")))
A.sort()
ans = 0
for i in range(n):
if i != n - 1:
ans += (i + 2) * A[i]
else:
ans += (n - 2 + 2) * A[i]
print(ans)
if __name__ == "__main__":
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,688,497,449 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | n = int(input())
ans = -1
total = 0
for i in range(n):
a , b = input().split()
a = int(a)
b = int(b)
total -= a
total += b
ans = max(ans , total)
print(ans)
| Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
n = int(input())
ans = -1
total = 0
for i in range(n):
a , b = input().split()
a = int(a)
b = int(b)
total -= a
total += b
ans = max(ans , total)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
382 | A | Ksenia and Pan Scales | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium ... | The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially ... | If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them. | [
"AC|T\nL\n",
"|ABC\nXYZ\n",
"W|T\nF\n",
"ABC|\nD\n"
] | [
"AC|TL\n",
"XYZ|ABC\n",
"Impossible\n",
"Impossible\n"
] | none | 500 | [
{
"input": "AC|T\nL",
"output": "AC|TL"
},
{
"input": "|ABC\nXYZ",
"output": "XYZ|ABC"
},
{
"input": "W|T\nF",
"output": "Impossible"
},
{
"input": "ABC|\nD",
"output": "Impossible"
},
{
"input": "A|BC\nDEF",
"output": "ADF|BCE"
},
{
"input": "|\nABC",... | 1,693,422,705 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 39 | 62 | 0 | l,r = input().split("|")
other = input()
a = len(other) - abs(len(l) - len(r))
if not (a > -1 and a % 2 == 0):
print("Impossible")
exit()
ind = 0
t = 0
if len(l) > len(r):
t = len(l) - len(r)
r += other[:t]
else:
t = len(r) - len(l)
l += other[:t]
x = len(other) - t
l +=... | Title: Ksenia and Pan Scales
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all ... | ```python
l,r = input().split("|")
other = input()
a = len(other) - abs(len(l) - len(r))
if not (a > -1 and a % 2 == 0):
print("Impossible")
exit()
ind = 0
t = 0
if len(l) > len(r):
t = len(l) - len(r)
r += other[:t]
else:
t = len(r) - len(l)
l += other[:t]
x = len(other)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
525 | B | Pasha and String | PROGRAMMING | 1,400 | [
"constructive algorithms",
"greedy",
"math",
"strings"
] | null | null | Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given string.
Pasha didn't like his present very much so he decided to change it. After his birthday Pasha ... | The first line of the input contains Pasha's string *s* of length from 2 to 2·105 characters, consisting of lowercase Latin letters.
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=105) — the number of days when Pasha changed his string.
The third line contains *m* space-separated elements *a**i* (1<=≤<... | In the first line of the output print what Pasha's string *s* will look like after *m* days. | [
"abcdef\n1\n2\n",
"vwxyz\n2\n2 2\n",
"abcdef\n3\n1 2 3\n"
] | [
"aedcbf\n",
"vwxyz\n",
"fbdcea\n"
] | none | 750 | [
{
"input": "abcdef\n1\n2",
"output": "aedcbf"
},
{
"input": "vwxyz\n2\n2 2",
"output": "vwxyz"
},
{
"input": "abcdef\n3\n1 2 3",
"output": "fbdcea"
},
{
"input": "jc\n5\n1 1 1 1 1",
"output": "cj"
},
{
"input": "wljqgdlxyc\n13\n3 4 3 3 5 4 4 2 4 4 5 3 3",
"out... | 1,455,349,633 | 4,333 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 7,577,600 | def get_new_idx(s, i, j):
end = len(s) - 1 - i
if j < i or j > end:
return j
return end - (j - i)
def l2s(l):
s = ''
for i in l:
s += i
return s
s = input()
days = int(input())
indices = [int(i) - 1 for i in input().split()]
result = ['0'] * len(s)
for i in range(len(s)):
... | Title: Pasha and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given ... | ```python
def get_new_idx(s, i, j):
end = len(s) - 1 - i
if j < i or j > end:
return j
return end - (j - i)
def l2s(l):
s = ''
for i in l:
s += i
return s
s = input()
days = int(input())
indices = [int(i) - 1 for i in input().split()]
result = ['0'] * len(s)
for i in range(len... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
505 | C | Mr. Kitayuta, the Treasure Hunter | PROGRAMMING | 1,900 | [
"dfs and similar",
"dp",
"two pointers"
] | null | null | The Shuseki Islands are an archipelago of 30001 small islands in the Yutampo Sea. The islands are evenly spaced along a line, numbered from 0 to 30000 from the west to the east. These islands are known to contain many treasures. There are *n* gems in the Shuseki Islands in total, and the *i*-th gem is located on island... | The first line of the input contains two space-separated integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=30000), denoting the number of the gems in the Shuseki Islands and the length of the Mr. Kitayuta's first jump, respectively.
The next *n* lines describe the location of the gems. The *i*-th of them (1<=≤<=*i*<=≤<=*n*) c... | Print the maximum number of gems that Mr. Kitayuta can collect. | [
"4 10\n10\n21\n27\n27\n",
"8 8\n9\n19\n28\n36\n45\n55\n66\n78\n",
"13 7\n8\n8\n9\n16\n17\n17\n18\n21\n23\n24\n24\n26\n30\n"
] | [
"3\n",
"6\n",
"4\n"
] | In the first sample, the optimal route is 0 → 10 (+1 gem) → 19 → 27 (+2 gems) → ...
In the second sample, the optimal route is 0 → 8 → 15 → 21 → 28 (+1 gem) → 36 (+1 gem) → 45 (+1 gem) → 55 (+1 gem) → 66 (+1 gem) → 78 (+1 gem) → ...
In the third sample, the optimal route is 0 → 7 → 13 → ... | 1,500 | [
{
"input": "4 10\n10\n21\n27\n27",
"output": "3"
},
{
"input": "8 8\n9\n19\n28\n36\n45\n55\n66\n78",
"output": "6"
},
{
"input": "13 7\n8\n8\n9\n16\n17\n17\n18\n21\n23\n24\n24\n26\n30",
"output": "4"
},
{
"input": "8 4\n9\n15\n15\n16\n22\n25\n25\n28",
"output": "8"
},
... | 1,655,346,051 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 4 | 935 | 35,942,400 | N = 30000
a = [0]*(N+1)
line = input().split()
n = int(line[0])
d = int(line[1])
max_p = 0
memo = {}
def dp(i, l):
if (i, l) in memo:
return memo[i, l]
if i > max_p:
return 0
ans = 0
for step in [l - 1, l, l + 1]:
if step > 0 and i + step <= max_p:
... | Title: Mr. Kitayuta, the Treasure Hunter
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Shuseki Islands are an archipelago of 30001 small islands in the Yutampo Sea. The islands are evenly spaced along a line, numbered from 0 to 30000 from the west to the east. These islands are known... | ```python
N = 30000
a = [0]*(N+1)
line = input().split()
n = int(line[0])
d = int(line[1])
max_p = 0
memo = {}
def dp(i, l):
if (i, l) in memo:
return memo[i, l]
if i > max_p:
return 0
ans = 0
for step in [l - 1, l, l + 1]:
if step > 0 and i + step <... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
834 | B | The Festive Evening | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here are not supposed to be disclosed to the general public: the information can cause discord in the kingdom... | Two integers are given in the first string: the number of guests *n* and the number of guards *k* (1<=≤<=*n*<=≤<=106, 1<=≤<=*k*<=≤<=26).
In the second string, *n* uppercase English letters *s*1*s*2... *s**n* are given, where *s**i* is the entrance used by the *i*-th guest. | Output «YES» if at least one door was unguarded during some time, and «NO» otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"5 1\nAABBB\n",
"5 1\nABABB\n"
] | [
"NO\n",
"YES\n"
] | In the first sample case, the door A is opened right before the first guest's arrival and closed when the second guest enters the castle. The door B is opened right before the arrival of the third guest, and closed after the fifth one arrives. One guard can handle both doors, as the first one is closed before the secon... | 1,000 | [
{
"input": "5 1\nAABBB",
"output": "NO"
},
{
"input": "5 1\nABABB",
"output": "YES"
},
{
"input": "26 1\nABCDEFGHIJKLMNOPQRSTUVWXYZ",
"output": "NO"
},
{
"input": "27 1\nABCDEFGHIJKLMNOPQRSTUVWXYZA",
"output": "YES"
},
{
"input": "5 2\nABACA",
"output": "NO"
... | 1,501,497,215 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 78 | 7,884,800 | n, k = [int(x) for x in input().split()]
s = input()
all_bad= 'NO'
alphabet = set(s)
doors = []
for letter in alphabet:
doors.append((s.find(letter), s.rfind(letter)))
starts = [doors[i][0] for i in range(len(alphabet))]
stops = [doors[i][1] for i in range(len(alphabet))]
for elem in starts:
... | Title: The Festive Evening
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here... | ```python
n, k = [int(x) for x in input().split()]
s = input()
all_bad= 'NO'
alphabet = set(s)
doors = []
for letter in alphabet:
doors.append((s.find(letter), s.rfind(letter)))
starts = [doors[i][0] for i in range(len(alphabet))]
stops = [doors[i][1] for i in range(len(alphabet))]
for elem in st... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
913 | B | Christmas Spruce | PROGRAMMING | 1,200 | [
"implementation",
"trees"
] | null | null | Consider a rooted tree. A rooted tree has one special vertex called the root. All edges are directed from the root. Vertex *u* is called a child of vertex *v* and vertex *v* is called a parent of vertex *u* if there exists a directed edge from *v* to *u*. A vertex is called a leaf if it doesn't have children and has a ... | The first line contains one integer *n* — the number of vertices in the tree (3<=≤<=*n*<=≤<=1<=000). Each of the next *n*<=-<=1 lines contains one integer *p**i* (1<=≤<=*i*<=≤<=*n*<=-<=1) — the index of the parent of the *i*<=+<=1-th vertex (1<=≤<=*p**i*<=≤<=*i*).
Vertex 1 is the root. It's guaranteed that the root ha... | Print "Yes" if the tree is a spruce and "No" otherwise. | [
"4\n1\n1\n1\n",
"7\n1\n1\n1\n2\n2\n2\n",
"8\n1\n1\n1\n1\n3\n3\n3\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | The first example:
<img class="tex-graphics" src="https://espresso.codeforces.com/8dd976913226df83d535dfa66193f5525f8471bc.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The second example:
<img class="tex-graphics" src="https://espresso.codeforces.com/44dad5804f5290a2e026c9c41a15151562df8682.png" style="max-w... | 750 | [
{
"input": "4\n1\n1\n1",
"output": "Yes"
},
{
"input": "7\n1\n1\n1\n2\n2\n2",
"output": "No"
},
{
"input": "8\n1\n1\n1\n1\n3\n3\n3",
"output": "Yes"
},
{
"input": "3\n1\n1",
"output": "No"
},
{
"input": "13\n1\n2\n2\n2\n1\n6\n6\n6\n1\n10\n10\n10",
"output": "N... | 1,598,835,534 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 24 | 155 | 21,811,200 | n = int(input())
a = [0,0]+[int(input()) for _ in range(n-1)]
isleaf = [0,0]+[1 for _ in range(n)]
chleaf = [0,0]+[1 for _ in range(n)]
for i in range(2,n+1):
isleaf[a[i]] = 0
for i in range(2,n+1):
if isleaf[i]:
chleaf[a[i]] += 1
ans = "Yes"
for i in range(1, n+1):
if not isleaf[i] a... | Title: Christmas Spruce
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a rooted tree. A rooted tree has one special vertex called the root. All edges are directed from the root. Vertex *u* is called a child of vertex *v* and vertex *v* is called a parent of vertex *u* if there ex... | ```python
n = int(input())
a = [0,0]+[int(input()) for _ in range(n-1)]
isleaf = [0,0]+[1 for _ in range(n)]
chleaf = [0,0]+[1 for _ in range(n)]
for i in range(2,n+1):
isleaf[a[i]] = 0
for i in range(2,n+1):
if isleaf[i]:
chleaf[a[i]] += 1
ans = "Yes"
for i in range(1, n+1):
if not i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
89 | C | Chip Play | PROGRAMMING | 2,300 | [
"brute force",
"data structures",
"implementation"
] | C. Chip Play | 4 | 256 | Let's consider the following game. We have a rectangular field *n*<=×<=*m* in size. Some squares of the field contain chips.
Each chip has an arrow painted on it. Thus, each chip on the field points in one of the following directions: up, down, left or right.
The player may choose a chip and make a move with it.
The... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*,<=*n*<=×<=*m*<=≤<=5000). Then follow *n* lines containing *m* characters each — that is the game field description. "." means that this square is empty. "L", "R", "U", "D" mean that this square contains a chip and an arrow on it says left, right, up or d... | Print two numbers — the maximal number of points a player can get after a move and the number of moves that allow receiving this maximum number of points. | [
"4 4\nDRLD\nU.UL\n.UUR\nRDDL\n",
"3 5\n.D...\nRRRLL\n.U...\n"
] | [
"10 1",
"6 2"
] | In the first sample the maximum number of points is earned by the chip in the position (3, 3). You can see its progress at the following picture:
All other chips earn fewer points. | 1,000 | [
{
"input": "4 4\nDRLD\nU.UL\n.UUR\nRDDL",
"output": "10 1"
},
{
"input": "2 2\nRD\nUL",
"output": "4 4"
},
{
"input": "5 5\nUD..L\nRRD..\n..RDD\nUUL..\nDDLRR",
"output": "8 3"
},
{
"input": "10 10\n.L.....R..\n.........U\n..D....D..\n.R......L.\n....L.....\n.........D\n......... | 1,689,415,145 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print("_RANDOM_GUESS_1689415145.1069593")# 1689415145.1069796 | Title: Chip Play
Time Limit: 4 seconds
Memory Limit: 256 megabytes
Problem Description:
Let's consider the following game. We have a rectangular field *n*<=×<=*m* in size. Some squares of the field contain chips.
Each chip has an arrow painted on it. Thus, each chip on the field points in one of the following direc... | ```python
print("_RANDOM_GUESS_1689415145.1069593")# 1689415145.1069796
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,696,268,402 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 48 | 61 | 0 | c = list(map(int, input().split()))
print(max(c) - min(c))
| Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
c = list(map(int, input().split()))
print(max(c) - min(c))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
631 | A | Interview | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function *f*(*x*,<=*l*,<=*r*) as a bitwise OR of integers *x... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the length of the arrays.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=109).
The third line contains *n* integers *b**i* (0<=≤<=*b**i*<=≤<=109). | Print a single integer — the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. | [
"5\n1 2 4 3 2\n2 3 3 12 1\n",
"10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6\n"
] | [
"22",
"46"
] | Bitwise OR of two non-negative integers *a* and *b* is the number *c* = *a* *OR* *b*, such that each of its digits in binary notation is 1 if and only if at least one of *a* or *b* have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is *l* = 2 and *r* = 4, because *... | 500 | [
{
"input": "5\n1 2 4 3 2\n2 3 3 12 1",
"output": "22"
},
{
"input": "10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6",
"output": "46"
},
{
"input": "25\n12 30 38 109 81 124 80 33 38 48 29 78 96 48 96 27 80 77 102 65 80 113 31 118 35\n25 64 95 13 12 6 111 80 85 16 61 119 23 65 73 65 20 9... | 1,524,625,688 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a=int(input())
x=1
y=1
l1=list(map(int,input()))
l2=list(map(int,input()))
for e1 in l1:
x | =e1
for e2 in l2:
y | =e2
print(x+y)
| Title: Interview
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of... | ```python
a=int(input())
x=1
y=1
l1=list(map(int,input()))
l2=list(map(int,input()))
for e1 in l1:
x | =e1
for e2 in l2:
y | =e2
print(x+y)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
689 | C | Mike and Chocolate Thieves | PROGRAMMING | 1,700 | [
"binary search",
"combinatorics",
"math"
] | null | null | Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly *k* times more than the previous... | The single line of input contains the integer *m* (1<=≤<=*m*<=≤<=1015) — the number of ways the thieves might steal the chocolates, as rumours say. | Print the only integer *n* — the maximum amount of chocolates that thieves' bags can carry. If there are more than one *n* satisfying the rumors, print the smallest one.
If there is no such *n* for a false-rumoured *m*, print <=-<=1. | [
"1\n",
"8\n",
"10\n"
] | [
"8\n",
"54\n",
"-1\n"
] | In the first sample case the smallest *n* that leads to exactly one way of stealing chocolates is *n* = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest *n* that leads to exactly 8 ways is *n* = 54 with the po... | 1,500 | [
{
"input": "1",
"output": "8"
},
{
"input": "8",
"output": "54"
},
{
"input": "10",
"output": "-1"
},
{
"input": "27",
"output": "152"
},
{
"input": "28206",
"output": "139840"
},
{
"input": "32",
"output": "184"
},
{
"input": "115",
"o... | 1,468,246,710 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 2,000 | 0 | m = int(input())
def judge(x):
base = 2
cnt = 0
while x >= base ** 3 and cnt <= m:
cnt += x // base ** 3
base += 1
return cnt
l = 1
r = 10000000000000000
ans = -1
while l <= r:
mid = l + (r - l) // 2
tmp = judge(mid)
if(tmp >= m):
if(tmp == m):
... | Title: Mike and Chocolate Thieves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thi... | ```python
m = int(input())
def judge(x):
base = 2
cnt = 0
while x >= base ** 3 and cnt <= m:
cnt += x // base ** 3
base += 1
return cnt
l = 1
r = 10000000000000000
ans = -1
while l <= r:
mid = l + (r - l) // 2
tmp = judge(mid)
if(tmp >= m):
if(tm... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
154 | B | Colliders | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | By 2312 there were *n* Large Hadron Colliders in the inhabited part of the universe. Each of them corresponded to a single natural number from 1 to *n*. However, scientists did not know what activating several colliders simultaneously could cause, so the colliders were deactivated.
In 2312 there was a startling discov... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of colliders and the number of requests, correspondingly.
Next *m* lines contain numbers of requests, one per line, in the form of either "+ i" (without the quotes) — activate the *i*-th collider, or "- i" (without ... | Print *m* lines — the results of executing requests in the above given format. The requests should be processed in the order, in which they are given in the input. Don't forget that the responses to the requests should be printed without quotes. | [
"10 10\n+ 6\n+ 10\n+ 5\n- 10\n- 5\n- 6\n+ 10\n+ 3\n+ 6\n+ 3\n"
] | [
"Success\nConflict with 6\nSuccess\nAlready off\nSuccess\nSuccess\nSuccess\nSuccess\nConflict with 10\nAlready on\n"
] | Note that in the sample the colliders don't turn on after the second and ninth requests. The ninth request could also receive response "Conflict with 3". | 1,000 | [
{
"input": "10 10\n+ 6\n+ 10\n+ 5\n- 10\n- 5\n- 6\n+ 10\n+ 3\n+ 6\n+ 3",
"output": "Success\nConflict with 6\nSuccess\nAlready off\nSuccess\nSuccess\nSuccess\nSuccess\nConflict with 10\nAlready on"
},
{
"input": "7 5\n+ 7\n+ 6\n+ 4\n+ 3\n- 7",
"output": "Success\nSuccess\nConflict with 6\nConfli... | 1,675,996,471 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n,m=list(map(int,input().split()))
onset=set()
for _ in range(m):
a,b=list(map(str,input().split()))
b=int(b)
if a=="-":
if b not in onset:
print("Already off")
else:
print("Success")
onset.remove(b)
... | Title: Colliders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
By 2312 there were *n* Large Hadron Colliders in the inhabited part of the universe. Each of them corresponded to a single natural number from 1 to *n*. However, scientists did not know what activating several colliders simul... | ```python
n,m=list(map(int,input().split()))
onset=set()
for _ in range(m):
a,b=list(map(str,input().split()))
b=int(b)
if a=="-":
if b not in onset:
print("Already off")
else:
print("Success")
onset.remove... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
548 | A | Mike and Fax | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"strings"
] | null | null | While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly *k* messages ... | The first line of input contains string *s* containing lowercase English letters (1<=≤<=|*s*|<=≤<=1000).
The second line contains integer *k* (1<=≤<=*k*<=≤<=1000). | Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise. | [
"saba\n2\n",
"saddastavvat\n2\n"
] | [
"NO\n",
"YES\n"
] | Palindrome is a string reading the same forward and backward.
In the second sample, the faxes in his back-bag can be "saddas" and "tavvat". | 500 | [
{
"input": "saba\n2",
"output": "NO"
},
{
"input": "saddastavvat\n2",
"output": "YES"
},
{
"input": "aaaaaaaaaa\n3",
"output": "NO"
},
{
"input": "aaaaaa\n3",
"output": "YES"
},
{
"input": "abaacca\n2",
"output": "NO"
},
{
"input": "a\n1",
"output"... | 1,594,316,279 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 11 | 186 | 22,220,800 | from collections import *
s = input()
k = int(input())
n = len(s)//k
for i in range(0,len(s),n):
t = s[i:i+n]
if(t != t[::-1]):
print("NO")
break
else:
if(len(s)%k == 0): print("YES")
else: print("NO") | Title: Mike and Fax
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure ... | ```python
from collections import *
s = input()
k = int(input())
n = len(s)//k
for i in range(0,len(s),n):
t = s[i:i+n]
if(t != t[::-1]):
print("NO")
break
else:
if(len(s)%k == 0): print("YES")
else: print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
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