contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
724 | A | Checking the Calendar | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the first day of the next month was equal to the second day of the week you are given. Both months should belong t... | The input consists of two lines, each of them containing the name of exactly one day of the week. It's guaranteed that each string in the input is from the set "monday", "tuesday", "wednesday", "thursday", "friday", "saturday", "sunday". | Print "YES" (without quotes) if such situation is possible during some non-leap year. Otherwise, print "NO" (without quotes). | [
"monday\ntuesday\n",
"sunday\nsunday\n",
"saturday\ntuesday\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | In the second sample, one can consider February 1 and March 1 of year 2015. Both these days were Sundays.
In the third sample, one can consider July 1 and August 1 of year 2017. First of these two days is Saturday, while the second one is Tuesday. | 500 | [
{
"input": "monday\ntuesday",
"output": "NO"
},
{
"input": "sunday\nsunday",
"output": "YES"
},
{
"input": "saturday\ntuesday",
"output": "YES"
},
{
"input": "tuesday\nthursday",
"output": "YES"
},
{
"input": "friday\nwednesday",
"output": "NO"
},
{
"i... | 1,621,736,697 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | f = input()
s = input()
l = ['monday','tuesday','wednesday','thursday','friday','saturday','sunday']
ind_f = l.index(f)
ind_s = l.index(s)
if ind_s - ind_f == 2 or 3:
print("YES")
else:
print("NO")
| Title: Checking the Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given names of two days of the week.
Please, determine whether it is possible that during some non-leap year the first day of some month was equal to the first day of the week you are given, while the fir... | ```python
f = input()
s = input()
l = ['monday','tuesday','wednesday','thursday','friday','saturday','sunday']
ind_f = l.index(f)
ind_s = l.index(s)
if ind_s - ind_f == 2 or 3:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,631,971,246 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 154 | 6,656,000 | s=input()
l=0
u=0
for i in s:
if i.islower():
l=l+1
elif i.isupper():
u=u+1
if l==u:
s=s.lower()
print(s)
if l<u:
s=s.upper()
print(s)
else:
s=s.lower()
print(s) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=input()
l=0
u=0
for i in s:
if i.islower():
l=l+1
elif i.isupper():
u=u+1
if l==u:
s=s.lower()
print(s)
if l<u:
s=s.upper()
print(s)
else:
s=s.lower()
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,646,545,512 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 92 | 0 | x = input()
result = 0
while True:
if x == "0" or len(str(x)) == 1:
print(result)
break
x = sum((map(int, x)))
x = str(x)
result +=1
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
x = input()
result = 0
while True:
if x == "0" or len(str(x)) == 1:
print(result)
break
x = sum((map(int, x)))
x = str(x)
result +=1
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
599 | B | Spongebob and Joke | PROGRAMMING | 1,500 | [
"implementation"
] | null | null | While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Patrick's personal stuff and found a sequence *a*1,<=*a*2,<=...,<=*a**m* of length *m*, consisting of integers from 1 to *n*, not necessarily distinct. Then he picked some sequence *f*1,<=*f*2,<=.... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100<=000) — the lengths of sequences *f**i* and *b**i* respectively.
The second line contains *n* integers, determining sequence *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*).
The last line contains *m* integers, determining sequen... | Print "Possible" if there is exactly one sequence *a**i*, such that *b**i*<==<=*f**a**i* for all *i* from 1 to *m*. Then print *m* integers *a*1,<=*a*2,<=...,<=*a**m*.
If there are multiple suitable sequences *a**i*, print "Ambiguity".
If Spongebob has made a mistake in his calculations and no suitable sequence *a**i... | [
"3 3\n3 2 1\n1 2 3\n",
"3 3\n1 1 1\n1 1 1\n",
"3 3\n1 2 1\n3 3 3\n"
] | [
"Possible\n3 2 1 \n",
"Ambiguity\n",
"Impossible\n"
] | In the first sample 3 is replaced by 1 and vice versa, while 2 never changes. The answer exists and is unique.
In the second sample all numbers are replaced by 1, so it is impossible to unambiguously restore the original sequence.
In the third sample *f*<sub class="lower-index">*i*</sub> ≠ 3 for all *i*, so no sequen... | 1,000 | [
{
"input": "3 3\n3 2 1\n1 2 3",
"output": "Possible\n3 2 1 "
},
{
"input": "3 3\n1 1 1\n1 1 1",
"output": "Ambiguity"
},
{
"input": "3 3\n1 2 1\n3 3 3",
"output": "Impossible"
},
{
"input": "2 100\n2 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1... | 1,593,781,171 | 571 | PyPy 3 | WRONG_ANSWER | TESTS | 19 | 295 | 14,950,400 | import sys
n,m=map(int,input().split())
f=list(map(int,input().split()))
a=list(map(int,input().split()))
dic={}
for i in range(n):
if f[i] in dic:
dic[f[i]]=-1
else:
dic[f[i]]=i
ans=[]
for i in range(m):
if not a[i] in dic:
print('Impossible')
sys.exit()
i... | Title: Spongebob and Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Patrick was gone shopping, Spongebob decided to play a little trick on his friend. The naughty Sponge browsed through Patrick's personal stuff and found a sequence *a*1,<=*a*2,<=...,<=*a**m* of length *m*, cons... | ```python
import sys
n,m=map(int,input().split())
f=list(map(int,input().split()))
a=list(map(int,input().split()))
dic={}
for i in range(n):
if f[i] in dic:
dic[f[i]]=-1
else:
dic[f[i]]=i
ans=[]
for i in range(m):
if not a[i] in dic:
print('Impossible')
sys.exi... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
670 | D1 | Magic Powder - 1 | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation"
] | null | null | This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too difficult in large constraints, you can write solution to the simplified version only.
Waking up in the ... | The first line of the input contains two positive integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1000) — the number of ingredients and the number of grams of the magic powder.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where the *i*-th number is equal to the number of grams of... | Print the maximum number of cookies, which Apollinaria will be able to bake using the ingredients that she has and the magic powder. | [
"3 1\n2 1 4\n11 3 16\n",
"4 3\n4 3 5 6\n11 12 14 20\n"
] | [
"4\n",
"3\n"
] | In the first sample it is profitably for Apollinaria to make the existing 1 gram of her magic powder to ingredient with the index 2, then Apollinaria will be able to bake 4 cookies.
In the second sample Apollinaria should turn 1 gram of magic powder to ingredient with the index 1 and 1 gram of magic powder to ingredie... | 1,000 | [
{
"input": "3 1\n2 1 4\n11 3 16",
"output": "4"
},
{
"input": "4 3\n4 3 5 6\n11 12 14 20",
"output": "3"
},
{
"input": "10 926\n5 6 8 1 2 5 1 8 4 4\n351 739 998 725 953 970 906 691 707 1000",
"output": "137"
},
{
"input": "20 925\n7 3 1 2 1 3 1 3 1 2 3 1 5 8 1 3 7 3 4 2\n837 ... | 1,685,194,972 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 119 | 77 | 3,276,800 | n, k = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
l = 0
h = 1000 + k
flagged = True
while l <= h:
m = (l + h) // 2
need = 0
for ind in range(n):
need += max(a[ind] * m - b[ind], 0)
if need == k:
print(m)
flagged ... | Title: Magic Powder - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too dif... | ```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
l = 0
h = 1000 + k
flagged = True
while l <= h:
m = (l + h) // 2
need = 0
for ind in range(n):
need += max(a[ind] * m - b[ind], 0)
if need == k:
print(m)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
608 | A | Saitama Destroys Hotel | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only move down, and has infinite capacity. Floors are numbered from 0 to *s* and elevator initially starts on floor... | The first line of input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=100, 1<=≤<=*s*<=≤<=1000) — the number of passengers and the number of the top floor respectively.
The next *n* lines each contain two space-separated integers *f**i* and *t**i* (1<=≤<=*f**i*<=≤<=*s*, 1<=≤<=*t**i*<=≤<=1000) — the floor and the tim... | Print a single integer — the minimum amount of time in seconds needed to bring all the passengers to floor 0. | [
"3 7\n2 1\n3 8\n5 2\n",
"5 10\n2 77\n3 33\n8 21\n9 12\n10 64\n"
] | [
"11\n",
"79\n"
] | In the first sample, it takes at least 11 seconds to bring all passengers to floor 0. Here is how this could be done:
1. Move to floor 5: takes 2 seconds.
2. Pick up passenger 3.
3. Move to floor 3: takes 2 seconds.
4. Wait for passenger 2 to arrive: takes 4 seconds.
5. Pick up passenger 2.
6. Go to floor 2: take... | 500 | [
{
"input": "3 7\n2 1\n3 8\n5 2",
"output": "11"
},
{
"input": "5 10\n2 77\n3 33\n8 21\n9 12\n10 64",
"output": "79"
},
{
"input": "1 1000\n1000 1000",
"output": "2000"
},
{
"input": "1 1\n1 1",
"output": "2"
},
{
"input": "1 1000\n1 1",
"output": "1000"
},
... | 1,684,616,306 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n, s = map(int, input().split())
mx = 0
ans = 0
for i in range(n):
f, t = map(int, input().split())
if mx < t:
mx = t
ans += t + f
if s - (ans - mx) > mx:
ans = s
print(ans) | Title: Saitama Destroys Hotel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only mo... | ```python
n, s = map(int, input().split())
mx = 0
ans = 0
for i in range(n):
f, t = map(int, input().split())
if mx < t:
mx = t
ans += t + f
if s - (ans - mx) > mx:
ans = s
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
285 | B | Find Marble | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not.
First Petya puts a marble under the glass in position *s*. Then he performs som... | The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaran... | If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1. | [
"4 2 1\n2 3 4 1\n",
"4 3 3\n4 1 3 2\n",
"4 3 4\n1 2 3 4\n",
"3 1 3\n2 1 3\n"
] | [
"3\n",
"0\n",
"-1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "4 2 1\n2 3 4 1",
"output": "3"
},
{
"input": "4 3 3\n4 1 3 2",
"output": "0"
},
{
"input": "4 3 4\n1 2 3 4",
"output": "-1"
},
{
"input": "3 1 3\n2 1 3",
"output": "-1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 6 7\n10 7 8 1... | 1,638,262,603 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 154 | 7,270,400 | n, s, t = map(int, input().split())
p = list(map(int, input().split()))
c = 0
stemp = s
while s!=t:
c+=1
s = p[s-1]
if s == stemp:
print(-1)
exit()
print(c)
| Title: Find Marble
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the ... | ```python
n, s, t = map(int, input().split())
p = list(map(int, input().split()))
c = 0
stemp = s
while s!=t:
c+=1
s = p[s-1]
if s == stemp:
print(-1)
exit()
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,626,508,017 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 124 | 6,963,200 | s=input()
if all(i=="1" or i=="4" for i in s):
if "144" in s:
s=s.replace("144","0")
if "14" in s:
s=s.replace("14","0")
if "1" in s:
s=s.replace("1","0")
if all(j=="0" for j in s):
print("YES")
else:
print("NO")
else:
print("NO")
| Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
s=input()
if all(i=="1" or i=="4" for i in s):
if "144" in s:
s=s.replace("144","0")
if "14" in s:
s=s.replace("14","0")
if "1" in s:
s=s.replace("1","0")
if all(j=="0" for j in s):
print("YES")
else:
print("NO")
else:
print("NO")
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,646,163,274 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 92 | 0 | import math
x= input()
while len(x)>=3:
if x[0:3]=="114":
x=x.replace(x[0],"",1)
elif x[0:3]=="111":
x = x.replace(x[0:2], "",1)
elif x[0:3]=="141":
x = x.replace(x[0:2], "",1)
elif x[0:3]=="144":
x = x.replace(x[0:3], "",1)
else:
print("... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
import math
x= input()
while len(x)>=3:
if x[0:3]=="114":
x=x.replace(x[0],"",1)
elif x[0:3]=="111":
x = x.replace(x[0:2], "",1)
elif x[0:3]=="141":
x = x.replace(x[0:2], "",1)
elif x[0:3]=="144":
x = x.replace(x[0:3], "",1)
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
745 | A | Hongcow Learns the Cyclic Shift | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Hongcow is learning to spell! One day, his teacher gives him a word that he needs to learn to spell. Being a dutiful student, he immediately learns how to spell the word.
Hongcow has decided to try to make new words from this one. He starts by taking the word he just learned how to spell, and moves the last character ... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=50), the word Hongcow initially learns how to spell. The string *s* consists only of lowercase English letters ('a'–'z'). | Output a single integer equal to the number of distinct strings that Hongcow can obtain by applying the cyclic shift arbitrarily many times to the given string. | [
"abcd\n",
"bbb\n",
"yzyz\n"
] | [
"4\n",
"1\n",
"2\n"
] | For the first sample, the strings Hongcow can generate are "abcd", "dabc", "cdab", and "bcda".
For the second sample, no matter how many times Hongcow does the cyclic shift, Hongcow can only generate "bbb".
For the third sample, the two strings Hongcow can generate are "yzyz" and "zyzy". | 500 | [
{
"input": "abcd",
"output": "4"
},
{
"input": "bbb",
"output": "1"
},
{
"input": "yzyz",
"output": "2"
},
{
"input": "abcdefghijklmnopqrstuvwxyabcdefghijklmnopqrstuvwxy",
"output": "25"
},
{
"input": "zclkjadoprqronzclkjadoprqronzclkjadoprqron",
"output": "14... | 1,590,090,355 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 109 | 0 | s = input()
o = set()
for i in range(len(s)):
o.add(s)
s = s[-1] + s[:-1]
#print(s) #it will give the cyclic order
print(len(o)) | Title: Hongcow Learns the Cyclic Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hongcow is learning to spell! One day, his teacher gives him a word that he needs to learn to spell. Being a dutiful student, he immediately learns how to spell the word.
Hongcow has decided to try to m... | ```python
s = input()
o = set()
for i in range(len(s)):
o.add(s)
s = s[-1] + s[:-1]
#print(s) #it will give the cyclic order
print(len(o))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,695,784,201 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 92 | 17,715,200 | a=int(input())
d=a/2
if d-d==0:
print("YES")
else:
print('NO')
| Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
a=int(input())
d=a/2
if d-d==0:
print("YES")
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | In Arcady's garden there grows a peculiar apple-tree that fruits one time per year. Its peculiarity can be explained in following way: there are *n* inflorescences, numbered from 1 to *n*. Inflorescence number 1 is situated near base of tree and any other inflorescence with number *i* (*i*<=><=1) is situated at the ... | First line of input contains single integer number *n* (2<=≤<=*n*<=≤<=100<=000) — number of inflorescences.
Second line of input contains sequence of *n*<=-<=1 integer numbers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* is number of inflorescence into which the apple from *i*-th inflorescence r... | Single line of output should contain one integer number: amount of apples that Arcady will be able to collect from first inflorescence during one harvest. | [
"3\n1 1\n",
"5\n1 2 2 2\n",
"18\n1 1 1 4 4 3 2 2 2 10 8 9 9 9 10 10 4\n"
] | [
"1\n",
"3\n",
"4\n"
] | In first example Arcady will be able to collect only one apple, initially situated in 1st inflorescence. In next second apples from 2nd and 3rd inflorescences will roll down and annihilate, and Arcady won't be able to collect them.
In the second example Arcady will be able to collect 3 apples. First one is one initial... | 0 | [
{
"input": "3\n1 1",
"output": "1"
},
{
"input": "5\n1 2 2 2",
"output": "3"
},
{
"input": "18\n1 1 1 4 4 3 2 2 2 10 8 9 9 9 10 10 4",
"output": "4"
},
{
"input": "2\n1",
"output": "2"
},
{
"input": "3\n1 2",
"output": "3"
},
{
"input": "20\n1 1 1 1 1 ... | 1,520,183,514 | 5,814 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 10 | 1,000 | 13,004,800 | n = int(input())
a = list(map(int, input().split()))
app = [1] * (n + 1)
dop = [0] * (n + 1)
ans = 0
a = [0, 0] + a
while 1 in app:
for i in range(2, n + 1):
if app[i] == 1:
dop[a[i]] += 1
for i in range(len(dop)):
app[i] = dop[i] % 2
ans += app[1]
app[1] = 0
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Arcady's garden there grows a peculiar apple-tree that fruits one time per year. Its peculiarity can be explained in following way: there are *n* inflorescences, numbered from 1 to *n*. Inflorescence number 1 is situated near b... | ```python
n = int(input())
a = list(map(int, input().split()))
app = [1] * (n + 1)
dop = [0] * (n + 1)
ans = 0
a = [0, 0] + a
while 1 in app:
for i in range(2, n + 1):
if app[i] == 1:
dop[a[i]] += 1
for i in range(len(dop)):
app[i] = dop[i] % 2
ans += app[1]
app[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain nu... | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the son... | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE... | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,674,664,072 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | p=input()
p=p.replace("WUB", " ")
print(p)
| Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consist... | ```python
p=input()
p=p.replace("WUB", " ")
print(p)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,680,839,065 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 52 | 93 | 0 | d, b = map(int, input().split()); c = [b + 5 * (a) * (a+1) / 2 <= 240 for a in range(1,d+1)]; print((c.index(False) if not c[-1] else d)) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
d, b = map(int, input().split()); c = [b + 5 * (a) * (a+1) / 2 <= 240 for a in range(1,d+1)]; print((c.index(False) if not c[-1] else d))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
797 | D | Broken BST | PROGRAMMING | 2,100 | [
"data structures",
"dfs and similar"
] | null | null | Let *T* be arbitrary binary tree — tree, every vertex of which has no more than two children. Given tree is rooted, so there exists only one vertex which doesn't have a parent — it's the root of a tree. Every vertex has an integer number written on it. Following algorithm is run on every value from the tree *T*:
1. S... | First line contains integer number *n* (1<=≤<=*n*<=≤<=105) — number of vertices in the tree.
Each of the next *n* lines contains 3 numbers *v*, *l*, *r* (0<=≤<=*v*<=≤<=109) — value on current vertex, index of the left child of the vertex and index of the right child of the vertex, respectively. If some child doesn't e... | Print number of times when search algorithm will fail. | [
"3\n15 -1 -1\n10 1 3\n5 -1 -1\n",
"8\n6 2 3\n3 4 5\n12 6 7\n1 -1 8\n4 -1 -1\n5 -1 -1\n14 -1 -1\n2 -1 -1\n"
] | [
"2\n",
"1\n"
] | In the example the root of the tree in vertex 2. Search of numbers 5 and 15 will return fail because on the first step algorithm will choose the subtree which doesn't contain numbers you are looking for. | 0 | [
{
"input": "3\n15 -1 -1\n10 1 3\n5 -1 -1",
"output": "2"
},
{
"input": "8\n6 2 3\n3 4 5\n12 6 7\n1 -1 8\n4 -1 -1\n5 -1 -1\n14 -1 -1\n2 -1 -1",
"output": "1"
},
{
"input": "1\n493041212 -1 -1",
"output": "0"
},
{
"input": "10\n921294733 5 9\n341281094 -1 -1\n35060484 10 -1\n36... | 1,676,305,782 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | mport sys
from collections import Counter
n = int(sys.stdin.buffer.readline().decode('utf-8'))
p = [-1]*n
value = [0]*n
left, right = [-1]*n, [-1]*n
for i, (v, l, r) in enumerate(map(int, line.decode('utf-8').split()) for line in sys.stdin.buffer):
value[i] = v
if l != -1:
left[i] = l-1
... | Title: Broken BST
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let *T* be arbitrary binary tree — tree, every vertex of which has no more than two children. Given tree is rooted, so there exists only one vertex which doesn't have a parent — it's the root of a tree. Every vertex has an i... | ```python
mport sys
from collections import Counter
n = int(sys.stdin.buffer.readline().decode('utf-8'))
p = [-1]*n
value = [0]*n
left, right = [-1]*n, [-1]*n
for i, (v, l, r) in enumerate(map(int, line.decode('utf-8').split()) for line in sys.stdin.buffer):
value[i] = v
if l != -1:
left[... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
834 | B | The Festive Evening | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here are not supposed to be disclosed to the general public: the information can cause discord in the kingdom... | Two integers are given in the first string: the number of guests *n* and the number of guards *k* (1<=≤<=*n*<=≤<=106, 1<=≤<=*k*<=≤<=26).
In the second string, *n* uppercase English letters *s*1*s*2... *s**n* are given, where *s**i* is the entrance used by the *i*-th guest. | Output «YES» if at least one door was unguarded during some time, and «NO» otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"5 1\nAABBB\n",
"5 1\nABABB\n"
] | [
"NO\n",
"YES\n"
] | In the first sample case, the door A is opened right before the first guest's arrival and closed when the second guest enters the castle. The door B is opened right before the arrival of the third guest, and closed after the fifth one arrives. One guard can handle both doors, as the first one is closed before the secon... | 1,000 | [
{
"input": "5 1\nAABBB",
"output": "NO"
},
{
"input": "5 1\nABABB",
"output": "YES"
},
{
"input": "26 1\nABCDEFGHIJKLMNOPQRSTUVWXYZ",
"output": "NO"
},
{
"input": "27 1\nABCDEFGHIJKLMNOPQRSTUVWXYZA",
"output": "YES"
},
{
"input": "5 2\nABACA",
"output": "NO"
... | 1,633,621,199 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 92 | 20,172,800 | from sys import stdin
input=stdin.readline
def answer():
count = [0]*(26)
for i in s:
x = ord(i)
count[x - 65] += 1
done = [False]*(26)
ans = 0
for i in range(n):
x = ord(s[i])
if(done[x - 65] == False):
done[x - 65] = True
ans += 1
... | Title: The Festive Evening
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here... | ```python
from sys import stdin
input=stdin.readline
def answer():
count = [0]*(26)
for i in s:
x = ord(i)
count[x - 65] += 1
done = [False]*(26)
ans = 0
for i in range(n):
x = ord(s[i])
if(done[x - 65] == False):
done[x - 65] = True
an... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
710 | D | Two Arithmetic Progressions | PROGRAMMING | 2,500 | [
"math",
"number theory"
] | null | null | You are given two arithmetic progressions: *a*1*k*<=+<=*b*1 and *a*2*l*<=+<=*b*2. Find the number of integers *x* such that *L*<=≤<=*x*<=≤<=*R* and *x*<==<=*a*1*k*'<=+<=*b*1<==<=*a*2*l*'<=+<=*b*2, for some integers *k*',<=*l*'<=≥<=0. | The only line contains six integers *a*1,<=*b*1,<=*a*2,<=*b*2,<=*L*,<=*R* (0<=<<=*a*1,<=*a*2<=≤<=2·109,<=<=-<=2·109<=≤<=*b*1,<=*b*2,<=*L*,<=*R*<=≤<=2·109,<=*L*<=≤<=*R*). | Print the desired number of integers *x*. | [
"2 0 3 3 5 21\n",
"2 4 3 0 6 17\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "2 0 3 3 5 21",
"output": "3"
},
{
"input": "2 4 3 0 6 17",
"output": "2"
},
{
"input": "2 0 4 2 -39 -37",
"output": "0"
},
{
"input": "1 9 3 11 49 109",
"output": "20"
},
{
"input": "3 81 5 72 -1761 501",
"output": "28"
},
{
"input": "8 -89... | 1,472,039,279 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 5,120,000 | from collections import defaultdict
import sys, os, math
def gcd(a1, a2):
if a2 == 0:
return a1
else:
return gcd(a2, a1 % a2)
# return (g, x, y) a*x + b*y = gcd(x, y)
def egcd(a, b):
if a == 0:
return (b, 0, 1)
else:
g, x, y = egcd(b % a, a)
... | Title: Two Arithmetic Progressions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arithmetic progressions: *a*1*k*<=+<=*b*1 and *a*2*l*<=+<=*b*2. Find the number of integers *x* such that *L*<=≤<=*x*<=≤<=*R* and *x*<==<=*a*1*k*'<=+<=*b*1<==<=*a*2*l*'<=+<=*b*2, for some i... | ```python
from collections import defaultdict
import sys, os, math
def gcd(a1, a2):
if a2 == 0:
return a1
else:
return gcd(a2, a1 % a2)
# return (g, x, y) a*x + b*y = gcd(x, y)
def egcd(a, b):
if a == 0:
return (b, 0, 1)
else:
g, x, y = egcd(b % a,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at ... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepa... | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,621,342,034 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | x,y=list(map(int,input().split()))
s=set()
nums=[]
for i in range(x):
nums.append(input())
for i in nums:
x=max(i)
if x not in s:
s.add(x)
print(len(s)) | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student ... | ```python
x,y=list(map(int,input().split()))
s=set()
nums=[]
for i in range(x):
nums.append(input())
for i in nums:
x=max(i)
if x not in s:
s.add(x)
print(len(s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,573,588,696 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 109 | 0 | n=int(input())
if (n%10)<=5:
print(n-n%10)
else:
print((n+10)-(n+10)%10) | Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
n=int(input())
if (n%10)<=5:
print(n-n%10)
else:
print((n+10)-(n+10)%10)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,645,852,195 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 512,000 |
N, K = list(map(int, input().split(" ")))
A = {}
for i in range(K):
X, Y = input().split(" ")
x = len(X)
y = len(Y)
if x <= y:
A[X] = X
A[Y] = X
else:
A[X] = Y
A[Y] = Y
S = input().split(" ")
for i in range(N):
S[i] = A[S[i]]
print(" ".join(S)) | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
N, K = list(map(int, input().split(" ")))
A = {}
for i in range(K):
X, Y = input().split(" ")
x = len(X)
y = len(Y)
if x <= y:
A[X] = X
A[Y] = X
else:
A[X] = Y
A[Y] = Y
S = input().split(" ")
for i in range(N):
S[i] = A[S[i]]
print(" ".j... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
135 | A | Replacement | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little Petya very much likes arrays consisting of *n* integers, where each of them is in the range from 1 to 109, inclusive. Recently he has received one such array as a gift from his mother. Petya didn't like it at once. He decided to choose exactly one element from the array and replace it with another integer that a... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), which represents how many numbers the array has. The next line contains *n* space-separated integers — the array's description. All elements of the array lie in the range from 1 to 109, inclusive. | Print *n* space-separated integers — the minimum possible values of each array element after one replacement and the sorting are performed. | [
"5\n1 2 3 4 5\n",
"5\n2 3 4 5 6\n",
"3\n2 2 2\n"
] | [
"1 1 2 3 4\n",
"1 2 3 4 5\n",
"1 2 2\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "1 1 2 3 4"
},
{
"input": "5\n2 3 4 5 6",
"output": "1 2 3 4 5"
},
{
"input": "3\n2 2 2",
"output": "1 2 2"
},
{
"input": "4\n1 1 2 3",
"output": "1 1 1 2"
},
{
"input": "3\n1 1 1",
"output": "1 1 2"
},
{
"input": "... | 1,661,531,399 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 122 | 0 | def miis():
return map(int, input().split())
n = int(input())
a = list(miis())
a[a.index(max(a))] = 1
a.sort()
print(*a)
| Title: Replacement
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes arrays consisting of *n* integers, where each of them is in the range from 1 to 109, inclusive. Recently he has received one such array as a gift from his mother. Petya didn't like it at once. H... | ```python
def miis():
return map(int, input().split())
n = int(input())
a = list(miis())
a[a.index(max(a))] = 1
a.sort()
print(*a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,589,657,279 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 140 | 21,606,400 |
if __name__ == "__main__":
s = str(input())
n = len(s)
vec = list()
for i in range(n - 3):
if s[i] == 'b' and s[i + 1] == 'e' and s[i + 2] == 'a' and s[i + 3] == 'r':
vec.append(i + 1)
size = len(vec)
x = 1
ans = 0
for i in range(size):
y = n - vec[i] - 2
if i:
x = vec[i - 1] + 1
x... | Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
if __name__ == "__main__":
s = str(input())
n = len(s)
vec = list()
for i in range(n - 3):
if s[i] == 'b' and s[i + 1] == 'e' and s[i + 2] == 'a' and s[i + 3] == 'r':
vec.append(i + 1)
size = len(vec)
x = 1
ans = 0
for i in range(size):
y = n - vec[i] - 2
if i:
x = vec[i - 1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
298 | A | Snow Footprints | PROGRAMMING | 1,300 | [
"greedy",
"implementation"
] | null | null | There is a straight snowy road, divided into *n* blocks. The blocks are numbered from 1 to *n* from left to right. If one moves from the *i*-th block to the (*i*<=+<=1)-th block, he will leave a right footprint on the *i*-th block. Similarly, if one moves from the *i*-th block to the (*i*<=-<=1)-th block, he will leave... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=1000).
The second line contains the description of the road — the string that consists of *n* characters. Each character will be either "." (a block without footprint), or "L" (a block with a left footprint), "R" (a block with a right footprint).
It's gu... | Print two space-separated integers — the values of *s* and *t*. If there are several possible solutions you can print any of them. | [
"9\n..RRLL...\n",
"11\n.RRRLLLLL..\n"
] | [
"3 4\n",
"7 5\n"
] | The first test sample is the one in the picture. | 500 | [
{
"input": "11\n.RRRLLLLL..",
"output": "7 5"
},
{
"input": "4\n.RL.",
"output": "3 2"
},
{
"input": "3\n.L.",
"output": "2 1"
},
{
"input": "3\n.R.",
"output": "2 3"
}
] | 1,656,092,253 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 498 | 9,523,200 | from unittest.util import strclass
n = int(input())
str = input()
t = 0
s = 0
r1 = str.index("R")
l1 = str.index("L")
if "R" in str and "L" in str:
s = r1
t = str.rfind("R")
if not "R" in str and "L" in str:
t = l1 -1
s = str.rfind("L")
if not "L" in str and "R" in str:
s = r1
... | Title: Snow Footprints
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a straight snowy road, divided into *n* blocks. The blocks are numbered from 1 to *n* from left to right. If one moves from the *i*-th block to the (*i*<=+<=1)-th block, he will leave a right footprint on the *... | ```python
from unittest.util import strclass
n = int(input())
str = input()
t = 0
s = 0
r1 = str.index("R")
l1 = str.index("L")
if "R" in str and "L" in str:
s = r1
t = str.rfind("R")
if not "R" in str and "L" in str:
t = l1 -1
s = str.rfind("L")
if not "L" in str and "R" in str:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
92 | A | Chips | PROGRAMMING | 800 | [
"implementation",
"math"
] | A. Chips | 2 | 256 | There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus number 1 sits to the left of the walrus number *n*.
The presenter has *m* chips. The pre... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=50, 1<=≤<=*m*<=≤<=104) — the number of walruses and the number of chips correspondingly. | Print the number of chips the presenter ended up with. | [
"4 11\n",
"17 107\n",
"3 8\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first sample the presenter gives one chip to the walrus number 1, two chips to the walrus number 2, three chips to the walrus number 3, four chips to the walrus number 4, then again one chip to the walrus number 1. After that the presenter runs out of chips. He can't give anything to the walrus number 2 and the ... | 500 | [
{
"input": "4 11",
"output": "0"
},
{
"input": "17 107",
"output": "2"
},
{
"input": "3 8",
"output": "1"
},
{
"input": "46 7262",
"output": "35"
},
{
"input": "32 6864",
"output": "0"
},
{
"input": "36 6218",
"output": "14"
},
{
"input": "... | 1,649,775,341 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n, m = list(map(int, input().split()))
a, b = 0, 0
d = []
while a < n:
a += 1
b += a
d.append(b)
c = m % d[-1]
print(c, d)
if c == 0:
print(0)
else:
for i in range(n):
if c < d[i]:
if c!= d[i-1]:
print(c-d[i-1])
else:
... | Title: Chips
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus nu... | ```python
n, m = list(map(int, input().split()))
a, b = 0, 0
d = []
while a < n:
a += 1
b += a
d.append(b)
c = m % d[-1]
print(c, d)
if c == 0:
print(0)
else:
for i in range(n):
if c < d[i]:
if c!= d[i-1]:
print(c-d[i-1])
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
53 | C | Little Frog | PROGRAMMING | 1,200 | [
"constructive algorithms"
] | C. Little Frog | 2 | 256 | Once upon a time a little frog whose name was Vasya decided to travel around his home swamp. Overall there are *n* mounds on the swamp, located on one line. The distance between the neighboring mounds is one meter. Vasya wants to visit all the mounds in one day; besides, he wants to visit each one exactly once. For tha... | The single line contains a number *n* (1<=≤<=*n*<=≤<=104) which is the number of mounds. | Print *n* integers *p**i* (1<=≤<=*p**i*<=≤<=*n*) which are the frog's route plan.
- All the *p**i*'s should be mutually different. - All the |*p**i*–*p**i*<=+<=1|'s should be mutually different (1<=≤<=*i*<=≤<=*n*<=-<=1).
If there are several solutions, output any. | [
"2\n",
"3\n"
] | [
"1 2 ",
"1 3 2 "
] | none | 1,500 | [
{
"input": "2",
"output": "1 2 "
},
{
"input": "3",
"output": "1 3 2 "
},
{
"input": "4",
"output": "1 4 2 3 "
},
{
"input": "5",
"output": "1 5 2 4 3 "
},
{
"input": "6",
"output": "1 6 2 5 3 4 "
},
{
"input": "1",
"output": "1 "
},
{
"inp... | 1,677,523,274 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | number_of_mound=int(input())
mound_distance=1
while mound_distance<=number_of_mound:
if number_of_mound!=mound_distance:
print(mound_distance)
else:
print(mound_distance)
mound_distance+=1
number_of_mound-=1 | Title: Little Frog
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once upon a time a little frog whose name was Vasya decided to travel around his home swamp. Overall there are *n* mounds on the swamp, located on one line. The distance between the neighboring mounds is one meter. Vasya wants ... | ```python
number_of_mound=int(input())
mound_distance=1
while mound_distance<=number_of_mound:
if number_of_mound!=mound_distance:
print(mound_distance)
else:
print(mound_distance)
mound_distance+=1
number_of_mound-=1
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
733 | A | Grasshopper And the String | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of ... | The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. | Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. | [
"ABABBBACFEYUKOTT\n",
"AAA\n"
] | [
"4",
"1"
] | none | 500 | [
{
"input": "ABABBBACFEYUKOTT",
"output": "4"
},
{
"input": "AAA",
"output": "1"
},
{
"input": "A",
"output": "1"
},
{
"input": "B",
"output": "2"
},
{
"input": "AEYUIOAEIYAEOUIYOEIUYEAOIUEOEAYOEIUYAEOUIYEOIKLMJNHGTRWSDZXCVBNMHGFDSXVWRTPPPLKMNBXIUOIUOIUOIUOOIU",
... | 1,661,583,124 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 46 | 0 | s = input()
convert_to_list_and_append_2_vowels_to_s = ['A'] + list(s) + ['A']
vowels = ['A', 'E', 'I', 'O', 'U', 'Y']
jumps = []
j = 0
k = 0
while j < len(convert_to_list_and_append_2_vowels_to_s):
if convert_to_list_and_append_2_vowels_to_s[j] in vowels:
jumps.append(j - k)
k = j
j += 1
pri... | Title: Grasshopper And the String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far en... | ```python
s = input()
convert_to_list_and_append_2_vowels_to_s = ['A'] + list(s) + ['A']
vowels = ['A', 'E', 'I', 'O', 'U', 'Y']
jumps = []
j = 0
k = 0
while j < len(convert_to_list_and_append_2_vowels_to_s):
if convert_to_list_and_append_2_vowels_to_s[j] in vowels:
jumps.append(j - k)
k = j
j... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
779 | A | Pupils Redistribution | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consists of exactly *n* students. An academic performance of each student is known — integer value between 1 and ... | The first line of the input contains integer number *n* (1<=≤<=*n*<=≤<=100) — number of students in both groups.
The second line contains sequence of integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=5), where *a**i* is academic performance of the *i*-th student of the group *A*.
The third line contains se... | Print the required minimum number of exchanges or -1, if the desired distribution of students can not be obtained. | [
"4\n5 4 4 4\n5 5 4 5\n",
"6\n1 1 1 1 1 1\n5 5 5 5 5 5\n",
"1\n5\n3\n",
"9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1\n"
] | [
"1\n",
"3\n",
"-1\n",
"4\n"
] | none | 500 | [
{
"input": "4\n5 4 4 4\n5 5 4 5",
"output": "1"
},
{
"input": "6\n1 1 1 1 1 1\n5 5 5 5 5 5",
"output": "3"
},
{
"input": "1\n5\n3",
"output": "-1"
},
{
"input": "9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1",
"output": "4"
},
{
"input": "1\n1\n2",
"output": "-1"
... | 1,611,530,749 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
do = True
cnt = [0]*5
ans = 0
for i in range(n):
cnt[a[i]-1] += 1
cnt[b[i]-1] -= 1
for i in range(5):
if cnt[i] % 2 == 1:
do = False
break
if not do:
print('-1')
else:
for i... | Title: Pupils Redistribution
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consis... | ```python
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
do = True
cnt = [0]*5
ans = 0
for i in range(n):
cnt[a[i]-1] += 1
cnt[b[i]-1] -= 1
for i in range(5):
if cnt[i] % 2 == 1:
do = False
break
if not do:
print('-1')
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,669,348,829 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 0 | txt = input().split()
n = int(txt[0])
t = int(txt[1])
value = 10**(n-1)
limit = 10**n-1
found = False
while value <= limit:
if value // t == value / t and value >= t:
print(value)
found = True
break
else:
value = value + 1
if not found:
print(-1) | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
txt = input().split()
n = int(txt[0])
t = int(txt[1])
value = 10**(n-1)
limit = 10**n-1
found = False
while value <= limit:
if value // t == value / t and value >= t:
print(value)
found = True
break
else:
value = value + 1
if not found:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,582,988,755 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 109 | 0 | a = input()
b = str(int(input()) + int(a))
b = b.replace('2', '0', b.count('2'))
print('0' * (len(a) - len(b)) + b) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
a = input()
b = str(int(input()) + int(a))
b = b.replace('2', '0', b.count('2'))
print('0' * (len(a) - len(b)) + b)
``` | 3.97275 | MatrixStudio/Codeforces-Python-Submissions |
550 | A | Two Substrings | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"greedy",
"implementation",
"strings"
] | null | null | You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order). | The only line of input contains a string *s* of length between 1 and 105 consisting of uppercase Latin letters. | Print "YES" (without the quotes), if string *s* contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise. | [
"ABA\n",
"BACFAB\n",
"AXBYBXA\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".
In the second sample test there are the following occurrences of the substrings: BACFAB.
In the third sample test there is no substring "AB" nor substring "BA". | 1,000 | [
{
"input": "ABA",
"output": "NO"
},
{
"input": "BACFAB",
"output": "YES"
},
{
"input": "AXBYBXA",
"output": "NO"
},
{
"input": "ABABAB",
"output": "YES"
},
{
"input": "BBBBBBBBBB",
"output": "NO"
},
{
"input": "ABBA",
"output": "YES"
},
{
"... | 1,679,959,636 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 34 | 46 | 204,800 | s=input()
a=''
b=''
x=''
if len(s)<=3:
print('NO')
a=0
b=0
else:
a=s.find('AB')
b=s.find('BA')
c=s.find('A', a+1)
d=s.find('B',b+1)
if 'BABA' in s and s!='BABA':
x='ABBA'
else:
if (b-1!=a or a-1!=b or c!=b+1 or d!=a+1):
x=s[a:a+2]+s[b:b+2]
if x in ['BAAB','ABBA']:
... | Title: Two Substrings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s*. Your task is to determine if the given string *s* contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order).
Input Specification:
The only line of input contain... | ```python
s=input()
a=''
b=''
x=''
if len(s)<=3:
print('NO')
a=0
b=0
else:
a=s.find('AB')
b=s.find('BA')
c=s.find('A', a+1)
d=s.find('B',b+1)
if 'BABA' in s and s!='BABA':
x='ABBA'
else:
if (b-1!=a or a-1!=b or c!=b+1 or d!=a+1):
x=s[a:a+2]+s[b:b+2]
if x in ['BAAB','A... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,693,160,433 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | def get_correct(s) :
upper,lower = 0,0
for char in s :
if 97 <= ord(char) :
lower += 1
else :
upper += 1
res = ''
if upper <= lower :
for char in s :
res += char.lower()
else :
for char in s :
res += char.up... | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
def get_correct(s) :
upper,lower = 0,0
for char in s :
if 97 <= ord(char) :
lower += 1
else :
upper += 1
res = ''
if upper <= lower :
for char in s :
res += char.lower()
else :
for char in s :
res ... | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
592 | B | The Monster and the Squirrel | PROGRAMMING | 1,100 | [
"math"
] | null | null | Ari the monster always wakes up very early with the first ray of the sun and the first thing she does is feeding her squirrel.
Ari draws a regular convex polygon on the floor and numbers it's vertices 1,<=2,<=...,<=*n* in clockwise order. Then starting from the vertex 1 she draws a ray in the direction of each other v... | The first and only line of the input contains a single integer *n* (3<=≤<=*n*<=≤<=54321) - the number of vertices of the regular polygon drawn by Ari. | Print the minimum number of jumps Ada should make to collect all the walnuts. Note, that she doesn't need to leave the polygon after. | [
"5\n",
"3\n"
] | [
"9\n",
"1\n"
] | One of the possible solutions for the first sample is shown on the picture above. | 1,000 | [
{
"input": "5",
"output": "9"
},
{
"input": "3",
"output": "1"
},
{
"input": "54321",
"output": "2950553761"
},
{
"input": "4",
"output": "4"
},
{
"input": "6",
"output": "16"
},
{
"input": "7",
"output": "25"
},
{
"input": "8",
"output... | 1,446,406,037 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n = raw_input().split()
n = int(n)
print ((n-2) * (n-2)) | Title: The Monster and the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ari the monster always wakes up very early with the first ray of the sun and the first thing she does is feeding her squirrel.
Ari draws a regular convex polygon on the floor and numbers it's vertices 1,<=... | ```python
n = raw_input().split()
n = int(n)
print ((n-2) * (n-2))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Limak is a little polar bear. He loves connecting with other bears via social networks. He has *n* friends and his relation with the *i*-th of them is described by a unique integer *t**i*. The bigger this value is, the better the friendship is. No two friends have the same value *t**i*.
Spring is starting and the Wint... | The first line contains three integers *n*, *k* and *q* (1<=≤<=*n*,<=*q*<=≤<=150<=000,<=1<=≤<=*k*<=≤<=*min*(6,<=*n*)) — the number of friends, the maximum number of displayed online friends and the number of queries, respectively.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=109) ... | For each query of the second type print one line with the answer — "YES" (without quotes) if the given friend is displayed and "NO" (without quotes) otherwise. | [
"4 2 8\n300 950 500 200\n1 3\n2 4\n2 3\n1 1\n1 2\n2 1\n2 2\n2 3\n",
"6 3 9\n50 20 51 17 99 24\n1 3\n1 4\n1 5\n1 2\n2 4\n2 2\n1 1\n2 4\n2 3\n"
] | [
"NO\nYES\nNO\nYES\nYES\n",
"NO\nYES\nNO\nYES\n"
] | In the first sample, Limak has 4 friends who all sleep initially. At first, the system displays nobody because nobody is online. There are the following 8 queries:
1. "1 3" — Friend 3 becomes online. 1. "2 4" — We should check if friend 4 is displayed. He isn't even online and thus we print "NO". 1. "2 3" — We shou... | 0 | [
{
"input": "4 2 8\n300 950 500 200\n1 3\n2 4\n2 3\n1 1\n1 2\n2 1\n2 2\n2 3",
"output": "NO\nYES\nNO\nYES\nYES"
},
{
"input": "6 3 9\n50 20 51 17 99 24\n1 3\n1 4\n1 5\n1 2\n2 4\n2 2\n1 1\n2 4\n2 3",
"output": "NO\nYES\nNO\nYES"
},
{
"input": "6 3 10\n62417580 78150524 410053501 582708235 ... | 1,680,977,608 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 1,092 | 12,492,800 | friends, displays, queries = map(int, input().split())
lst = list(map(int, input().split()))
screen = []
awakes = []
for j in range(queries):
t, indx = map(int, input().split())
if(t == 1):
indxTemp = indx - 1
temp = lst[indxTemp]
if(len(awakes) < displays):
awakes.... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He loves connecting with other bears via social networks. He has *n* friends and his relation with the *i*-th of them is described by a unique integer *t**i*. The bigger this value is, the better the ... | ```python
friends, displays, queries = map(int, input().split())
lst = list(map(int, input().split()))
screen = []
awakes = []
for j in range(queries):
t, indx = map(int, input().split())
if(t == 1):
indxTemp = indx - 1
temp = lst[indxTemp]
if(len(awakes) < displays):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
7 | D | Palindrome Degree | PROGRAMMING | 2,200 | [
"hashing",
"strings"
] | D. Palindrome Degree | 1 | 256 | String *s* of length *n* is called *k*-palindrome, if it is a palindrome itself, and its prefix and suffix of length are (*k*<=-<=1)-palindromes. By definition, any string (even empty) is 0-palindrome.
Let's call the palindrome degree of string *s* such a maximum number *k*, for which *s* is *k*-palindrome. For examp... | The first line of the input data contains a non-empty string, consisting of Latin letters and digits. The length of the string does not exceed 5·106. The string is case-sensitive. | Output the only number — the sum of the polindrome degrees of all the string's prefixes. | [
"a2A\n",
"abacaba\n"
] | [
"1",
"6"
] | none | 0 | [
{
"input": "a2A",
"output": "1"
},
{
"input": "abacaba",
"output": "6"
},
{
"input": "CCeCeCCCee",
"output": "4"
},
{
"input": "opooppppopppopoppopoooppopopooopopppooopppoppoppoppppoooppooooooopppoopoopooooppooooppppppppooopooop",
"output": "3"
},
{
"input": "odri... | 1,526,318,091 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 7,577,600 | myStr = input()
hash1 = [[0 for i in range(114)]for i in range(1013)]
hashVal1 = 0
auxHashVal1 = 0
hashVal2 = 0
auxHashVal2 = 0
for i in range(len(myStr)):
hashVal1 = (((hashVal1 * 127) % 113) + (ord(myStr[i]) % 113)) % 113
hashVal2 = (hashVal2 + ((ord(myStr[i]) * ( 127 ** (i % 112))) % 113)) % 113
... | Title: Palindrome Degree
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
String *s* of length *n* is called *k*-palindrome, if it is a palindrome itself, and its prefix and suffix of length are (*k*<=-<=1)-palindromes. By definition, any string (even empty) is 0-palindrome.
Let's call the pa... | ```python
myStr = input()
hash1 = [[0 for i in range(114)]for i in range(1013)]
hashVal1 = 0
auxHashVal1 = 0
hashVal2 = 0
auxHashVal2 = 0
for i in range(len(myStr)):
hashVal1 = (((hashVal1 * 127) % 113) + (ord(myStr[i]) % 113)) % 113
hashVal2 = (hashVal2 + ((ord(myStr[i]) * ( 127 ** (i % 112))) % 113)) ... | 0 | MatrixStudio/Codeforces-Python-Submissions |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,668,019,573 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | n = input().lower()
str = ''
for i in range(len(n)):
if n[i] == 'h' and 'h' not in str:
str += 'h'
if n[i] == 'e' and 'e' not in str:
str += 'e'
if n[i] == 'l' and 'l' not in str:
str += 'll'
if n[i] == 'o' and 'o' not in str:
str += 'o'
if str == 'hello':
... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
n = input().lower()
str = ''
for i in range(len(n)):
if n[i] == 'h' and 'h' not in str:
str += 'h'
if n[i] == 'e' and 'e' not in str:
str += 'e'
if n[i] == 'l' and 'l' not in str:
str += 'll'
if n[i] == 'o' and 'o' not in str:
str += 'o'
if str == 'he... | 0 | MatrixStudio/Codeforces-Python-Submissions |
667 | A | Pouring Rain | PROGRAMMING | 1,100 | [
"geometry",
"math"
] | null | null | A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.
Today everything ... | The only line of the input contains four integer numbers *d*,<=*h*,<=*v*,<=*e* (1<=≤<=*d*,<=*h*,<=*v*,<=*e*<=≤<=104), where:
- *d* — the diameter of your cylindrical cup, - *h* — the initial level of water in the cup, - *v* — the speed of drinking process from the cup in milliliters per second, - *e* — the growth ... | If it is impossible to make the cup empty, print "NO" (without quotes).
Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=4. It is... | [
"1 2 3 100\n",
"1 1 1 1\n"
] | [
"NO\n",
"YES\n3.659792366325\n"
] | In the first example the water fills the cup faster than you can drink from it.
In the second example area of the cup's bottom equals to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/419dc74dcd7bc392019c9fe748fe1fdb08ab521a.png" style="max-width: 100.0%;max-height: 100.0%;"/>, thus we ca... | 500 | [
{
"input": "1 2 3 100",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "YES\n3.659792366325"
},
{
"input": "48 7946 7992 72",
"output": "NO"
},
{
"input": "72 6791 8546 46",
"output": "NO"
},
{
"input": "100 5635 9099 23",
"output": "NO"
},
{
"input... | 1,626,029,101 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 77 | 6,758,400 | from math import pi
d, h, v, e = map(int, input().split())
if(e * pi * d * d / 4 >= v):
print('NO')
else:
print("YES")
print(h*pi*d*d/4/(v-e * pi * d * d / 4)) | Title: Pouring Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, cont... | ```python
from math import pi
d, h, v, e = map(int, input().split())
if(e * pi * d * d / 4 >= v):
print('NO')
else:
print("YES")
print(h*pi*d*d/4/(v-e * pi * d * d / 4))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works... | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,679,762,433 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 154 | 1,740,800 | n = int(input())
a=[]
for i in range(1,n+1):
a.append(i)
b=[]
b.append(a[n-1])
for i in range(n-1):
b.append(a[i])
for i in range(n):
print(b[i],end=" ") | Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the perm... | ```python
n = int(input())
a=[]
for i in range(1,n+1):
a.append(i)
b=[]
b.append(a[n-1])
for i in range(n-1):
b.append(a[i])
for i in range(n):
print(b[i],end=" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
784 | A | Numbers Joke | PROGRAMMING | 1,700 | [
"*special"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=30).
Output a single integer. | The input contains a single integer *a* (1<=≤<=*a*<=≤<=30). | Output a single integer. | [
"3\n"
] | [
"27\n"
] | none | 0 | [
{
"input": "3",
"output": "27"
},
{
"input": "1",
"output": "4"
},
{
"input": "2",
"output": "22"
},
{
"input": "4",
"output": "58"
},
{
"input": "5",
"output": "85"
},
{
"input": "6",
"output": "94"
},
{
"input": "7",
"output": "121"
... | 1,585,297,526 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | n=int(input())
c=1
print(n*n*n) | Title: Numbers Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=30).
Output a single integer.
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=30).
Output Specification:
Output a single integer.
Demo ... | ```python
n=int(input())
c=1
print(n*n*n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,695,301,220 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | # -*- coding: utf-8 -*-
"""
Created on Thu Sep 21 20:36:39 2023
@author: 2300011314
"""
y=int(input())
n=y+1
def judge(year):
for i in range(10):
if year.count(str(i))>1:
return False
return True
while n>y:
if judge(str(n))==True:
break
n+=1
print(n... | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
# -*- coding: utf-8 -*-
"""
Created on Thu Sep 21 20:36:39 2023
@author: 2300011314
"""
y=int(input())
n=y+1
def judge(year):
for i in range(10):
if year.count(str(i))>1:
return False
return True
while n>y:
if judge(str(n))==True:
break
n+=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, inf... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word bec... | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,678,888,342 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 |
def decode(encoded_word):
decoded_word = [""] * len(encoded_word)
left, right = 0, len(encoded_word) - 1
for i, letter in enumerate(encoded_word):
if (len(encoded_word) - 1) % 2 == i % 2:
decoded_word[left] = letter
left += 1
else:
decoded_word[r... | Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the... | ```python
def decode(encoded_word):
decoded_word = [""] * len(encoded_word)
left, right = 0, len(encoded_word) - 1
for i, letter in enumerate(encoded_word):
if (len(encoded_word) - 1) % 2 == i % 2:
decoded_word[left] = letter
left += 1
else:
deco... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,698,118,459 | 2,147,483,647 | PyPy 3 | OK | TESTS | 103 | 1,419 | 10,752,000 | n = int(input())
price = input().split()
prices = [int(i) for i in price]
prices.sort()
days = int(input())
for i in range(days):
coin = int(input())
count = n
low = 0
high = n - 1
while low <= high:
mid = (low + high) // 2
if coin >= prices[mid]:
low = mid + 1
else:
high = mid - 1
count = mid
p... | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
n = int(input())
price = input().split()
prices = [int(i) for i in price]
prices.sort()
days = int(input())
for i in range(days):
coin = int(input())
count = n
low = 0
high = n - 1
while low <= high:
mid = (low + high) // 2
if coin >= prices[mid]:
low = mid + 1
else:
high = mid - 1
count ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,689,851,196 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | a=list(map(str,input().split()))
if int(a[0])==30 and a[2]=="month":
print(11)
elif a[2]=="month" and int(a[0])==31:
print(4)
elif a[2]=="month":
print(12)
else:
print(366//7)
print(a) | Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
a=list(map(str,input().split()))
if int(a[0])==30 and a[2]=="month":
print(11)
elif a[2]=="month" and int(a[0])==31:
print(4)
elif a[2]=="month":
print(12)
else:
print(366//7)
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
900 | A | Find Extra One | PROGRAMMING | 800 | [
"geometry",
"implementation"
] | null | null | You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis. | The first line contains a single positive integer *n* (2<=≤<=*n*<=≤<=105).
The following *n* lines contain coordinates of the points. The *i*-th of these lines contains two single integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109, *x**i*<=≠<=0). No two points coincide. | Print "Yes" if there is such a point, "No" — otherwise.
You can print every letter in any case (upper or lower). | [
"3\n1 1\n-1 -1\n2 -1\n",
"4\n1 1\n2 2\n-1 1\n-2 2\n",
"3\n1 2\n2 1\n4 60\n"
] | [
"Yes",
"No",
"Yes"
] | In the first example the second point can be removed.
In the second example there is no suitable for the condition point.
In the third example any point can be removed. | 500 | [
{
"input": "3\n1 1\n-1 -1\n2 -1",
"output": "Yes"
},
{
"input": "4\n1 1\n2 2\n-1 1\n-2 2",
"output": "No"
},
{
"input": "3\n1 2\n2 1\n4 60",
"output": "Yes"
},
{
"input": "10\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n-1 -1",
"output": "Yes"
},
{
"input": "2\n1... | 1,656,707,271 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 218 | 2,457,600 | n = int(input())
positive_x_coordinates = []
negative_x_coordinates = []
for i in range(n):
(x, y) = map(int, input().split(' '))
if x > 0:
positive_x_coordinates.append(x)
elif x < 0:
negative_x_coordinates.append(x)
if len(positive_x_coordinates) > 1 and len(negative_x_coordinates) > 1:... | Title: Find Extra One
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis.
Input Specification:
The first li... | ```python
n = int(input())
positive_x_coordinates = []
negative_x_coordinates = []
for i in range(n):
(x, y) = map(int, input().split(' '))
if x > 0:
positive_x_coordinates.append(x)
elif x < 0:
negative_x_coordinates.append(x)
if len(positive_x_coordinates) > 1 and len(negative_x_coordin... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
569 | A | Music | PROGRAMMING | 1,500 | [
"implementation",
"math"
] | null | null | Little Lesha loves listening to music via his smartphone. But the smartphone doesn't have much memory, so Lesha listens to his favorite songs in a well-known social network InTalk.
Unfortunately, internet is not that fast in the city of Ekaterinozavodsk and the song takes a lot of time to download. But Lesha is quite ... | The single line contains three integers *T*,<=*S*,<=*q* (2<=≤<=*q*<=≤<=104, 1<=≤<=*S*<=<<=*T*<=≤<=105). | Print a single integer — the number of times the song will be restarted. | [
"5 2 2\n",
"5 4 7\n",
"6 2 3\n"
] | [
"2\n",
"1\n",
"1\n"
] | In the first test, the song is played twice faster than it is downloaded, which means that during four first seconds Lesha reaches the moment that has not been downloaded, and starts the song again. After another two seconds, the song is downloaded completely, and thus, Lesha starts the song twice.
In the second test,... | 500 | [
{
"input": "5 2 2",
"output": "2"
},
{
"input": "5 4 7",
"output": "1"
},
{
"input": "6 2 3",
"output": "1"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "2 1 3",
"output": "1"
},
{
"input": "2 1 10000",
"output": "1"
},
{
"input": "12... | 1,439,226,489 | 2,289 | Python 3 | OK | TESTS | 33 | 77 | 0 | info=list(map(int,input().split()))
t=info[0]
s=info[1]
q=info[2]
q=(q-1)/q
p=s
ans=0
while p<t:
p=p/(1-q)
if ((int(p)+1)-p)<.005:
p=int(p)+1
ans+=1
print(ans)
| Title: Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Lesha loves listening to music via his smartphone. But the smartphone doesn't have much memory, so Lesha listens to his favorite songs in a well-known social network InTalk.
Unfortunately, internet is not that fast in the... | ```python
info=list(map(int,input().split()))
t=info[0]
s=info[1]
q=info[2]
q=(q-1)/q
p=s
ans=0
while p<t:
p=p/(1-q)
if ((int(p)+1)-p)<.005:
p=int(p)+1
ans+=1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,696,617,437 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 46 | 102,400 | x = int(input())
y = input()
z = y.count('D')
if z > x//2:
print('Danik')
elif z < x//2:
print('Anton')
else:
print('Friendship') | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
x = int(input())
y = input()
z = y.count('D')
if z > x//2:
print('Danik')
elif z < x//2:
print('Anton')
else:
print('Friendship')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
676 | C | Vasya and String | PROGRAMMING | 1,500 | [
"binary search",
"dp",
"strings",
"two pointers"
] | null | null | High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequence) consisting of equal letters.
Vasya can change no more than *k* characters of the original strin... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000,<=0<=≤<=*k*<=≤<=*n*) — the length of the string and the maximum number of characters to change.
The second line contains the string, consisting of letters 'a' and 'b' only. | Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than *k* characters. | [
"4 2\nabba\n",
"8 1\naabaabaa\n"
] | [
"4\n",
"5\n"
] | In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".
In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa". | 1,500 | [
{
"input": "4 2\nabba",
"output": "4"
},
{
"input": "8 1\naabaabaa",
"output": "5"
},
{
"input": "1 0\na",
"output": "1"
},
{
"input": "1 1\nb",
"output": "1"
},
{
"input": "1 0\nb",
"output": "1"
},
{
"input": "1 1\na",
"output": "1"
},
{
... | 1,603,769,936 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 343 | 9,830,400 | from collections import Counter
import string
import math
import sys
from fractions import Fraction
def array_int():
return [int(i) for i in sys.stdin.readline().split()]
def vary(arrber_of_variables):
if arrber_of_variables==1:
return int(sys.stdin.readline())
if arrber_of_variables>=2:
... | Title: Vasya and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequ... | ```python
from collections import Counter
import string
import math
import sys
from fractions import Fraction
def array_int():
return [int(i) for i in sys.stdin.readline().split()]
def vary(arrber_of_variables):
if arrber_of_variables==1:
return int(sys.stdin.readline())
if arrber_of_varia... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,676,949,260 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | s = input()
for ch in s:
if ch == "h" or ch == "e" or ch == "i" or ch == "d":
continue
else:
s = s.replace(ch,"")
if s == "heidi":
print("YES")
else:
print("NO") | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
s = input()
for ch in s:
if ch == "h" or ch == "e" or ch == "i" or ch == "d":
continue
else:
s = s.replace(ch,"")
if s == "heidi":
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
216 | B | Forming Teams | PROGRAMMING | 1,700 | [
"dfs and similar",
"implementation"
] | null | null | One day *n* students come to the stadium. They want to play football, and for that they need to split into teams, the teams must have an equal number of people.
We know that this group of people has archenemies. Each student has at most two archenemies. Besides, if student *A* is an archenemy to student *B*, then stud... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100, 1<=≤<=*m*<=≤<=100) — the number of students and the number of pairs of archenemies correspondingly.
Next *m* lines describe enmity between students. Each enmity is described as two numbers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=... | Print a single integer — the minimum number of students you will have to send to the bench in order to start the game. | [
"5 4\n1 2\n2 4\n5 3\n1 4\n",
"6 2\n1 4\n3 4\n",
"6 6\n1 2\n2 3\n3 1\n4 5\n5 6\n6 4\n"
] | [
"1",
"0",
"2"
] | none | 1,500 | [
{
"input": "5 4\n1 2\n2 4\n5 3\n1 4",
"output": "1"
},
{
"input": "6 2\n1 4\n3 4",
"output": "0"
},
{
"input": "6 6\n1 2\n2 3\n3 1\n4 5\n5 6\n6 4",
"output": "2"
},
{
"input": "5 1\n1 2",
"output": "1"
},
{
"input": "8 8\n1 2\n2 3\n3 4\n4 5\n5 6\n6 7\n7 8\n8 1",
... | 1,578,940,407 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 310 | 512,000 | def arr_inp():
return [int(x) for x in stdin.readline().split()]
class graph:
# initialize graph
def __init__(self, gdict=None):
if gdict is None:
gdict = defaultdict(list)
self.gdict = gdict
# get edges
def edges(self):
return self.find_edges()
... | Title: Forming Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* students come to the stadium. They want to play football, and for that they need to split into teams, the teams must have an equal number of people.
We know that this group of people has archenemies. Each stu... | ```python
def arr_inp():
return [int(x) for x in stdin.readline().split()]
class graph:
# initialize graph
def __init__(self, gdict=None):
if gdict is None:
gdict = defaultdict(list)
self.gdict = gdict
# get edges
def edges(self):
return self.find_... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
1,010 | B | Rocket | PROGRAMMING | 1,800 | [
"binary search",
"interactive"
] | null | null | This is an interactive problem.
Natasha is going to fly to Mars. Finally, Natasha sat in the rocket. She flies, flies... but gets bored. She wishes to arrive to Mars already! So she decides to find something to occupy herself. She couldn't think of anything better to do than to calculate the distance to the red planet... | The first line contains two integers $m$ and $n$ ($1 \le m \le 10^9$, $1 \le n \le 30$) — the maximum distance to Mars and the number of elements in the sequence $p$. | none | [
"5 2\n1\n-1\n-1\n1\n0\n"
] | [
"1\n2\n4\n5\n3\n"
] | In the example, hacking would look like this:
5 2 3
1 0
This means that the current distance to Mars is equal to $3$, Natasha knows that it does not exceed $5$, and the rocket answers in order: correctly, incorrectly, correctly, incorrectly ...
Really:
on the first query ($1$) the correct answer is $1$, the rocket... | 750 | [
{
"input": "5 2 3\n1 0",
"output": "3 queries, x=3"
},
{
"input": "1 1 1\n1",
"output": "1 queries, x=1"
},
{
"input": "3 2 3\n1 0",
"output": "4 queries, x=3"
},
{
"input": "6 3 5\n1 1 1",
"output": "5 queries, x=5"
},
{
"input": "10 4 3\n0 0 1 0",
"output": ... | 1,688,985,774 | 2,147,483,647 | PyPy 3-64 | IDLENESS_LIMIT_EXCEEDED | TESTS | 0 | 0 | 0 | import math
import random
import time
from decimal import *
from collections import defaultdict
from bisect import bisect_left as lower_bound
from bisect import bisect_right as upper_bound
def printare_matrice(matricea):
coloane=len(matricea[0])
randuri=len(matricea)
#print("r=",randuri)
#print... | Title: Rocket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This is an interactive problem.
Natasha is going to fly to Mars. Finally, Natasha sat in the rocket. She flies, flies... but gets bored. She wishes to arrive to Mars already! So she decides to find something to occupy herself. ... | ```python
import math
import random
import time
from decimal import *
from collections import defaultdict
from bisect import bisect_left as lower_bound
from bisect import bisect_right as upper_bound
def printare_matrice(matricea):
coloane=len(matricea[0])
randuri=len(matricea)
#print("r=",randuri... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
262 | B | Roma and Changing Signs | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of s... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made.
The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104).
The numbers in the lines are separated by single spaces... | In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes. | [
"3 2\n-1 -1 1\n",
"3 1\n-1 -1 1\n"
] | [
"3\n",
"1\n"
] | In the first sample we can get sequence [1, 1, 1], thus the total income equals 3.
In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1. | 1,000 | [
{
"input": "3 2\n-1 -1 1",
"output": "3"
},
{
"input": "3 1\n-1 -1 1",
"output": "1"
},
{
"input": "17 27\n257 320 676 1136 2068 2505 2639 4225 4951 5786 7677 7697 7851 8337 8429 8469 9343",
"output": "81852"
},
{
"input": "69 28\n-9822 -9264 -9253 -9221 -9139 -9126 -9096 -89... | 1,613,216,946 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 122 | 0 | n, k=map(int,input().split())
arr=list(map(int, input().split()))
arr.sort()
curr=0
sum=0
for i in range(n):
if(arr[i]<0 and curr<k):
sum+=abs(arr[i])
curr+=1
else:
sum+=abs(arr[i])
print(sum) | Title: Roma and Changing Signs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of ... | ```python
n, k=map(int,input().split())
arr=list(map(int, input().split()))
arr.sort()
curr=0
sum=0
for i in range(n):
if(arr[i]<0 and curr<k):
sum+=abs(arr[i])
curr+=1
else:
sum+=abs(arr[i])
print(sum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
475 | B | Strongly Connected City | PROGRAMMING | 1,400 | [
"brute force",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Imagine a city with *n* horizontal streets crossing *m* vertical streets, forming an (*n*<=-<=1)<=×<=(*m*<=-<=1) grid. In order to increase the traffic flow, mayor of the city has decided to make each street one way. This means in each horizontal street, the traffic moves only from west to east or only from east to wes... | The first line of input contains two integers *n* and *m*, (2<=≤<=*n*,<=*m*<=≤<=20), denoting the number of horizontal streets and the number of vertical streets.
The second line contains a string of length *n*, made of characters '<' and '>', denoting direction of each horizontal street. If the *i*-th character... | If the given pattern meets the mayor's criteria, print a single line containing "YES", otherwise print a single line containing "NO". | [
"3 3\n><>\nv^v\n",
"4 6\n<><>\nv^v^v^\n"
] | [
"NO\n",
"YES\n"
] | The figure above shows street directions in the second sample test case. | 1,000 | [
{
"input": "3 3\n><>\nv^v",
"output": "NO"
},
{
"input": "4 6\n<><>\nv^v^v^",
"output": "YES"
},
{
"input": "2 2\n<>\nv^",
"output": "YES"
},
{
"input": "2 2\n>>\n^v",
"output": "NO"
},
{
"input": "3 3\n>><\n^^v",
"output": "YES"
},
{
"input": "3 4\n>>... | 1,659,019,331 | 2,147,483,647 | PyPy 3 | OK | TESTS | 81 | 77 | 0 |
n, m = map(int, input().split())
s1 = input()
s2 = input()
if s1[0] == '>' and s1[-1] == '<' and s2[0] == '^' and s2[-1] == 'v':
print("YES")
elif s1[0] == '<' and s1[-1] == '>' and s2[0] == 'v' and s2[-1] == '^':
print("YES")
else:
print("NO")
| Title: Strongly Connected City
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine a city with *n* horizontal streets crossing *m* vertical streets, forming an (*n*<=-<=1)<=×<=(*m*<=-<=1) grid. In order to increase the traffic flow, mayor of the city has decided to make each street one... | ```python
n, m = map(int, input().split())
s1 = input()
s2 = input()
if s1[0] == '>' and s1[-1] == '<' and s2[0] == '^' and s2[-1] == 'v':
print("YES")
elif s1[0] == '<' and s1[-1] == '>' and s2[0] == 'v' and s2[-1] == '^':
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morn... | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and ... | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,697,299,030 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | t,s,x=map(int,input().split())
y=t
z=t
while y<=x:
if x==y or x==z:
print("yes")
else:
print("no")
y=y+s
z=z+s+1
| Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times... | ```python
t,s,x=map(int,input().split())
y=t
z=t
while y<=x:
if x==y or x==z:
print("yes")
else:
print("no")
y=y+s
z=z+s+1
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
572 | B | Order Book | PROGRAMMING | 1,300 | [
"data structures",
"greedy",
"implementation",
"sortings"
] | null | null | In this task you need to process a set of stock exchange orders and use them to create order book.
An order is an instruction of some participant to buy or sell stocks on stock exchange. The order number *i* has price *p**i*, direction *d**i* — buy or sell, and integer *q**i*. This means that the participant is ready ... | The input starts with two positive integers *n* and *s* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*s*<=≤<=50), the number of orders and the book depth.
Next *n* lines contains a letter *d**i* (either 'B' or 'S'), an integer *p**i* (0<=≤<=*p**i*<=≤<=105) and an integer *q**i* (1<=≤<=*q**i*<=≤<=104) — direction, price and volume resp... | Print no more than 2*s* lines with aggregated orders from order book of depth *s*. The output format for orders should be the same as in input. | [
"6 2\nB 10 3\nS 50 2\nS 40 1\nS 50 6\nB 20 4\nB 25 10\n"
] | [
"S 50 8\nS 40 1\nB 25 10\nB 20 4\n"
] | Denote (x, y) an order with price *x* and volume *y*. There are 3 aggregated buy orders (10, 3), (20, 4), (25, 10) and two sell orders (50, 8), (40, 1) in the sample.
You need to print no more than two best orders for each direction, so you shouldn't print the order (10 3) having the worst price among buy orders. | 1,000 | [
{
"input": "6 2\nB 10 3\nS 50 2\nS 40 1\nS 50 6\nB 20 4\nB 25 10",
"output": "S 50 8\nS 40 1\nB 25 10\nB 20 4"
},
{
"input": "2 1\nB 7523 5589\nS 69799 1711",
"output": "S 69799 1711\nB 7523 5589"
},
{
"input": "1 1\nB 48259 991",
"output": "B 48259 991"
},
{
"input": "1 50\n... | 1,697,978,578 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n, s = map(int, input().split())
dictB = {}
dictS = {}
for i in range(n):
c, p, q = input().split()
if c == "B":
if dictB.get(int(p)) is None:
dictB[int(p)] = int(q)
else:
dictB[int(p)] += int(q)
else:
if dictS.get(int(p)) is None:
dict... | Title: Order Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this task you need to process a set of stock exchange orders and use them to create order book.
An order is an instruction of some participant to buy or sell stocks on stock exchange. The order number *i* has price *p**i... | ```python
n, s = map(int, input().split())
dictB = {}
dictS = {}
for i in range(n):
c, p, q = input().split()
if c == "B":
if dictB.get(int(p)) is None:
dictB[int(p)] = int(q)
else:
dictB[int(p)] += int(q)
else:
if dictS.get(int(p)) is None:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
47 | A | Triangular numbers | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Triangular numbers | 2 | 256 | A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers fr... | The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer. | If the given integer is a triangular number output YES, otherwise output NO. | [
"1\n",
"2\n",
"3\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "2",
"output": "NO"
},
{
"input": "3",
"output": "YES"
},
{
"input": "4",
"output": "NO"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "YES"
},
{
"input": "7",
"output": "NO... | 1,607,976,410 | 2,147,483,647 | PyPy 3 | OK | TESTS | 71 | 280 | 0 | # A. Triangular numbers
n = int(input())
s = 0
for i in range(1, n+1):
s += i
if s == n:
print('YES')
break
elif s > n:
print('NO')
break
| Title: Triangular numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is t... | ```python
# A. Triangular numbers
n = int(input())
s = 0
for i in range(1, n+1):
s += i
if s == n:
print('YES')
break
elif s > n:
print('NO')
break
``` | 3.93 | MatrixStudio/Codeforces-Python-Submissions |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,562,863,440 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 0 | #!/usr/bin/python3
n = int(input())
string = input()
s = string.count("SF")
f = string.count("FS")
r = "YES" if s > f else "NO"
print(r)
'''
https://codeforces.com/problemset/problem/867/A
'''
| Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
#!/usr/bin/python3
n = int(input())
string = input()
s = string.count("SF")
f = string.count("FS")
r = "YES" if s > f else "NO"
print(r)
'''
https://codeforces.com/problemset/problem/867/A
'''
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
710 | A | King Moves | PROGRAMMING | 800 | [
"implementation"
] | null | null | The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check the king's moves here [https://en.wikipedia.org/wiki/King_(chess)](https://en.wikipedia.org/wik... | The only line contains the king's position in the format "cd", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'. | Print the only integer *x* — the number of moves permitted for the king. | [
"e4\n"
] | [
"8\n"
] | none | 0 | [
{
"input": "e4",
"output": "8"
},
{
"input": "a1",
"output": "3"
},
{
"input": "h8",
"output": "3"
},
{
"input": "a4",
"output": "5"
},
{
"input": "g7",
"output": "8"
},
{
"input": "e1",
"output": "5"
},
{
"input": "b2",
"output": "8"
... | 1,676,030,015 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | pos = input()
column = pos[0]
row = pos[1]
ans = 0
if(row == 1 or row == 8):
if(column == 'a' or column == 'h'):
ans = 3
else:
ans = 5
elif(column == 'a' or column == 'h'):
if(row == 1 or row == 8):
ans = 3
else:
ans = 5
else:
ans = 8
print(ans) | Title: King Moves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check... | ```python
pos = input()
column = pos[0]
row = pos[1]
ans = 0
if(row == 1 or row == 8):
if(column == 'a' or column == 'h'):
ans = 3
else:
ans = 5
elif(column == 'a' or column == 'h'):
if(row == 1 or row == 8):
ans = 3
else:
ans = 5
else:
ans = 8
print... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
816 | B | Karen and Coffee | PROGRAMMING | 1,400 | [
"binary search",
"data structures",
"implementation"
] | null | null | To stay woke and attentive during classes, Karen needs some coffee!
Karen, a coffee aficionado, wants to know the optimal temperature for brewing the perfect cup of coffee. Indeed, she has spent some time reading several recipe books, including the universally acclaimed "The Art of the Covfefe".
She knows *n* coffee ... | The first line of input contains three integers, *n*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=200000), and *q* (1<=≤<=*q*<=≤<=200000), the number of recipes, the minimum number of recipes a certain temperature must be recommended by to be admissible, and the number of questions Karen has, respectively.
The next *n* lines describe ... | For each question, output a single integer on a line by itself, the number of admissible integer temperatures between *a* and *b* degrees, inclusive. | [
"3 2 4\n91 94\n92 97\n97 99\n92 94\n93 97\n95 96\n90 100\n",
"2 1 1\n1 1\n200000 200000\n90 100\n"
] | [
"3\n3\n0\n4\n",
"0\n"
] | In the first test case, Karen knows 3 recipes.
1. The first one recommends brewing the coffee between 91 and 94 degrees, inclusive. 1. The second one recommends brewing the coffee between 92 and 97 degrees, inclusive. 1. The third one recommends brewing the coffee between 97 and 99 degrees, inclusive.
A temperatur... | 1,000 | [
{
"input": "3 2 4\n91 94\n92 97\n97 99\n92 94\n93 97\n95 96\n90 100",
"output": "3\n3\n0\n4"
},
{
"input": "2 1 1\n1 1\n200000 200000\n90 100",
"output": "0"
},
{
"input": "1 1 1\n1 1\n1 1",
"output": "1"
},
{
"input": "1 1 1\n200000 200000\n200000 200000",
"output": "1"
... | 1,615,624,661 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,500 | 2,662,400 | n,k,q=map(int,input().split())
recomended = []
for i in range(n):
recomended.append(list(map(int,input().split())))
query = []
for i in range(q):
query.append(list(map(int,input().split())))
arr = [0 for i in range(200002)]
for i in recomended:
a = i[0]
b = i[1]
arr[a]+=1
arr[b+1]-=1
for i in ra... | Title: Karen and Coffee
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To stay woke and attentive during classes, Karen needs some coffee!
Karen, a coffee aficionado, wants to know the optimal temperature for brewing the perfect cup of coffee. Indeed, she has spent some time reading seve... | ```python
n,k,q=map(int,input().split())
recomended = []
for i in range(n):
recomended.append(list(map(int,input().split())))
query = []
for i in range(q):
query.append(list(map(int,input().split())))
arr = [0 for i in range(200002)]
for i in recomended:
a = i[0]
b = i[1]
arr[a]+=1
arr[b+1]-=1
f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
454 | B | Little Pony and Sort by Shift | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. That is, she can move the last element of the sequence to its beginning:
Help Twilight Sparkle to calculate: what ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=105). The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | If it's impossible to sort the sequence output -1. Otherwise output the minimum number of operations Twilight Sparkle needs to sort it. | [
"2\n2 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"1\n",
"-1\n",
"0\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 3 2",
"output": "-1"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "6\n3 4 5 6 3 2",
"output": "-1"
},
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n1 1 2 1 1",
"output": "2"
}... | 1,594,717,331 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 21 | 202 | 30,617,600 | n=int(input())
l=[int(i) for i in input().split()]
k=l.index(min(l))
if(k==0):
if(l==sorted(l)):
print(0)
else:
print(-1)
else:
if(l[:k]==sorted(l[:k]) and l[k:]==sorted(l[k:]) and l[n-1]<=l[0]):
print(n-k)
else:
print(-1) | Title: Little Pony and Sort by Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. ... | ```python
n=int(input())
l=[int(i) for i in input().split()]
k=l.index(min(l))
if(k==0):
if(l==sorted(l)):
print(0)
else:
print(-1)
else:
if(l[:k]==sorted(l[:k]) and l[k:]==sorted(l[k:]) and l[n-1]<=l[0]):
print(n-k)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
117 | A | Elevator | PROGRAMMING | 1,300 | [
"implementation",
"math"
] | null | null | And now the numerous qualifying tournaments for one of the most prestigious Russian contests Russian Codec Cup are over. All *n* participants who have made it to the finals found themselves in a huge *m*-floored 108-star hotel. Of course the first thought to come in a place like this is "How about checking out the elev... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*<=≤<=105,<=2<=≤<=*m*<=≤<=108).
Next *n* lines contain information about the participants in the form of three space-separated integers *s**i* *f**i* *t**i* (1<=≤<=*s**i*,<=*f**i*<=≤<=*m*,<=0<=≤<=*t**i*<=≤<=108), described in the problem statem... | Print *n* lines each containing one integer — the time of the arrival for each participant to the required floor. | [
"7 4\n2 4 3\n1 2 0\n2 2 0\n1 2 1\n4 3 5\n1 2 2\n4 2 0\n",
"5 5\n1 5 4\n1 3 1\n1 3 4\n3 1 5\n4 2 5\n"
] | [
"9\n1\n0\n7\n10\n7\n5\n",
"12\n10\n10\n8\n7\n"
] | Let's consider the first sample. The first participant starts at floor *s* = 2 by the time equal to *t* = 3. To get to the floor *f* = 4, he has to wait until the time equals 7, that's the time when the elevator will go upwards for the second time. Then the first participant should get on the elevator and go two floors... | 500 | [
{
"input": "7 4\n2 4 3\n1 2 0\n2 2 0\n1 2 1\n4 3 5\n1 2 2\n4 2 0",
"output": "9\n1\n0\n7\n10\n7\n5"
},
{
"input": "5 5\n1 5 4\n1 3 1\n1 3 4\n3 1 5\n4 2 5",
"output": "12\n10\n10\n8\n7"
},
{
"input": "5 5\n1 3 4\n4 4 2\n3 2 1\n2 4 0\n1 5 3",
"output": "10\n2\n7\n3\n12"
},
{
"i... | 1,678,048,164 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 358 | 7,475,200 | n, m = map(int, input().split())
k = 2 * (m - 1)
p = [0] * n
for i in range(n):
s, f, t = map(int, input().split())
d = t % k
if s < f: p[i] = (k if s <= d else 0) + f - 1 + t - d
elif f < s: p[i] = (k if d + s > k + 1 else 0) + k + 1 - f + t - d
else: p[i] = t
print('\n'.join(map(str, p))... | Title: Elevator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
And now the numerous qualifying tournaments for one of the most prestigious Russian contests Russian Codec Cup are over. All *n* participants who have made it to the finals found themselves in a huge *m*-floored 108-star hotel... | ```python
n, m = map(int, input().split())
k = 2 * (m - 1)
p = [0] * n
for i in range(n):
s, f, t = map(int, input().split())
d = t % k
if s < f: p[i] = (k if s <= d else 0) + f - 1 + t - d
elif f < s: p[i] = (k if d + s > k + 1 else 0) + k + 1 - f + t - d
else: p[i] = t
print('\n'.join(ma... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
583 | B | Robot's Task | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to colle... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information. | Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information. | [
"3\n0 2 0\n",
"5\n4 2 3 0 1\n",
"7\n0 3 1 0 5 2 6\n"
] | [
"1\n",
"3\n",
"2\n"
] | In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece.
In the second sample to... | 1,000 | [
{
"input": "3\n0 2 0",
"output": "1"
},
{
"input": "5\n4 2 3 0 1",
"output": "3"
},
{
"input": "7\n0 3 1 0 5 2 6",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "0"
},
{
"input": "10\n0 0 0 0 0 0 0 0 0 0",
"out... | 1,443,891,793 | 1,093 | Python 3 | OK | TESTS | 56 | 202 | 0 | n = int(input())
a = list(map(int, input().split(' ')[:n]))
n_infos = 0
direction = 1
res = 0
while True:
if direction == 1:
r = range(n)
else:
r = range(n-1, -1, -1)
for i in r:
if n_infos >= a[i]:
a[i] = float("inf")
n_infos += 1
if n... | Title: Robot's Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The compu... | ```python
n = int(input())
a = list(map(int, input().split(' ')[:n]))
n_infos = 0
direction = 1
res = 0
while True:
if direction == 1:
r = range(n)
else:
r = range(n-1, -1, -1)
for i in r:
if n_infos >= a[i]:
a[i] = float("inf")
n_infos += 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | In mathematical terms, the sequence *F**n* of Fibonacci numbers is defined by the recurrence relation
DZY loves Fibonacci numbers very much. Today DZY gives you an array consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. Moreover, there are *m* queries, each query has one of the two types:
1. Format of the que... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=300000). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — initial array *a*.
Then, *m* lines follow. A single line describes a single query in the format given in the statement. It is guaranteed ... | For each query of the second type, print the value of the sum on a single line. | [
"4 4\n1 2 3 4\n1 1 4\n2 1 4\n1 2 4\n2 1 3\n"
] | [
"17\n12\n"
] | After the first query, *a* = [2, 3, 5, 7].
For the second query, *sum* = 2 + 3 + 5 + 7 = 17.
After the third query, *a* = [2, 4, 6, 9].
For the fourth query, *sum* = 2 + 4 + 6 = 12. | 0 | [] | 1,690,495,494 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print("_RANDOM_GUESS_1690495493.0716913")# 1690495493.0717115 | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematical terms, the sequence *F**n* of Fibonacci numbers is defined by the recurrence relation
DZY loves Fibonacci numbers very much. Today DZY gives you an array consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. Mo... | ```python
print("_RANDOM_GUESS_1690495493.0716913")# 1690495493.0717115
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,689,184,160 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689184159.822846")# 1689184159.82286 | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
print("_RANDOM_GUESS_1689184159.822846")# 1689184159.82286
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works... | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,697,964,242 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 60 | 0 | a = int(input())
mas = []
for i in range(1, a+1):
mas.append(i)
print(*(mas)[::-1]) | Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the perm... | ```python
a = int(input())
mas = []
for i in range(1, a+1):
mas.append(i)
print(*(mas)[::-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,698,339,527 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | c,x,n,y=int(input()),list(map(int,input().split())),int(input()),list(map(int,input().split()))
a=b=0
d,z={},{}
for i in y:
if i not in d: d[i]=x.index(i)+1
z[i]=z[i]+1 if i in z else 1
for i in z: a,b=a+z[i]*d[i],b+z[i]*(c-d[i]+1)
print(d,z)
print(a,b) | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
c,x,n,y=int(input()),list(map(int,input().split())),int(input()),list(map(int,input().split()))
a=b=0
d,z={},{}
for i in y:
if i not in d: d[i]=x.index(i)+1
z[i]=z[i]+1 if i in z else 1
for i in z: a,b=a+z[i]*d[i],b+z[i]*(c-d[i]+1)
print(d,z)
print(a,b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
572 | B | Order Book | PROGRAMMING | 1,300 | [
"data structures",
"greedy",
"implementation",
"sortings"
] | null | null | In this task you need to process a set of stock exchange orders and use them to create order book.
An order is an instruction of some participant to buy or sell stocks on stock exchange. The order number *i* has price *p**i*, direction *d**i* — buy or sell, and integer *q**i*. This means that the participant is ready ... | The input starts with two positive integers *n* and *s* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*s*<=≤<=50), the number of orders and the book depth.
Next *n* lines contains a letter *d**i* (either 'B' or 'S'), an integer *p**i* (0<=≤<=*p**i*<=≤<=105) and an integer *q**i* (1<=≤<=*q**i*<=≤<=104) — direction, price and volume resp... | Print no more than 2*s* lines with aggregated orders from order book of depth *s*. The output format for orders should be the same as in input. | [
"6 2\nB 10 3\nS 50 2\nS 40 1\nS 50 6\nB 20 4\nB 25 10\n"
] | [
"S 50 8\nS 40 1\nB 25 10\nB 20 4\n"
] | Denote (x, y) an order with price *x* and volume *y*. There are 3 aggregated buy orders (10, 3), (20, 4), (25, 10) and two sell orders (50, 8), (40, 1) in the sample.
You need to print no more than two best orders for each direction, so you shouldn't print the order (10 3) having the worst price among buy orders. | 1,000 | [
{
"input": "6 2\nB 10 3\nS 50 2\nS 40 1\nS 50 6\nB 20 4\nB 25 10",
"output": "S 50 8\nS 40 1\nB 25 10\nB 20 4"
},
{
"input": "2 1\nB 7523 5589\nS 69799 1711",
"output": "S 69799 1711\nB 7523 5589"
},
{
"input": "1 1\nB 48259 991",
"output": "B 48259 991"
},
{
"input": "1 50\n... | 1,440,270,003 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 46 | 0 | n,s = map(int,input().split())
a = [[-1,-1] for i in range(100) ]
b = [[-1,-1] for i in range(100) ]
for i in range(n):
s1 = list(map(str,input().split()))
p = int(s1[1])
depth = int(s1[2])
if (s1[0] == 'B'):
if (b[p][0] == -1):
b[p][0] = 0
b[p][1] = p
... | Title: Order Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this task you need to process a set of stock exchange orders and use them to create order book.
An order is an instruction of some participant to buy or sell stocks on stock exchange. The order number *i* has price *p**i... | ```python
n,s = map(int,input().split())
a = [[-1,-1] for i in range(100) ]
b = [[-1,-1] for i in range(100) ]
for i in range(n):
s1 = list(map(str,input().split()))
p = int(s1[1])
depth = int(s1[2])
if (s1[0] == 'B'):
if (b[p][0] == -1):
b[p][0] = 0
b[p][1] = p... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,651,734,412 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | str1=input()
i=0
l1=[]
str2=""
for i in str1:
if i not in l1:
l1.append(i)
if i=='l' and l1.count('l')==1:
l1.append(i)
for i in l1:
str2+=i
print(str2)
if "hello" in str2:
print("YES")
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
str1=input()
i=0
l1=[]
str2=""
for i in str1:
if i not in l1:
l1.append(i)
if i=='l' and l1.count('l')==1:
l1.append(i)
for i in l1:
str2+=i
print(str2)
if "hello" in str2:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,589,464,865 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 7,270,400 | data = input().split(" ")
i = int(data[0])
j = int(data[1])
n = int(data[2])
result = ""
for e in range(0,j):
r = n**e
if (r >= i and r <= j):
result += (str(r) + " ")
if (result == ''):
print(-1)
else:
print(result[:-1])
| Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
data = input().split(" ")
i = int(data[0])
j = int(data[1])
n = int(data[2])
result = ""
for e in range(0,j):
r = n**e
if (r >= i and r <= j):
result += (str(r) + " ")
if (result == ''):
print(-1)
else:
print(result[:-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,661,321,040 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 62 | 1,638,400 | from sys import stdin
def input(): return stdin.readline()[:-1]
# list(map(int,input().split()))
def solve():
energy = 0
x = input().split()
for number in input():
energy += int(x[int(number)-1])
return energy
print(solve())
| Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
from sys import stdin
def input(): return stdin.readline()[:-1]
# list(map(int,input().split()))
def solve():
energy = 0
x = input().split()
for number in input():
energy += int(x[int(number)-1])
return energy
print(solve())
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
633 | A | Ebony and Ivory | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
For every bullet that hits the shield, Ebony deals *a* units of damage while Ivory deals *b* units of ... | The first line of the input contains three integers *a*, *b*, *c* (1<=≤<=*a*,<=*b*<=≤<=100,<=1<=≤<=*c*<=≤<=10<=000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively. | Print "Yes" (without quotes) if Dante can deal exactly *c* damage to the shield and "No" (without quotes) otherwise. | [
"4 6 15\n",
"3 2 7\n",
"6 11 6\n"
] | [
"No\n",
"Yes\n",
"Yes\n"
] | In the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage. | 250 | [
{
"input": "4 6 15",
"output": "No"
},
{
"input": "3 2 7",
"output": "Yes"
},
{
"input": "6 11 6",
"output": "Yes"
},
{
"input": "3 12 15",
"output": "Yes"
},
{
"input": "5 5 10",
"output": "Yes"
},
{
"input": "6 6 7",
"output": "No"
},
{
"... | 1,538,727,435 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<iostream>
#include<stdio.h>
using namespace std;
#pragma GCC optimize(2)
#pragma GCC optimize(3)
int input()
{
int re=0;char c=getchar();
while(c<'0' or c>'9') c=getchar();
while(c>='0' and c<='9') re=(re<<3)+(re<<1)+(c^48),c=getchar();
return re;
}
int main()
{
int a,b,c;
// scanf("%d%d... | Title: Ebony and Ivory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
F... | ```python
#include<iostream>
#include<stdio.h>
using namespace std;
#pragma GCC optimize(2)
#pragma GCC optimize(3)
int input()
{
int re=0;char c=getchar();
while(c<'0' or c>'9') c=getchar();
while(c>='0' and c<='9') re=(re<<3)+(re<<1)+(c^48),c=getchar();
return re;
}
int main()
{
int a,b,c;
// s... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
934 | B | A Prosperous Lot | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to approach them, it will be driven away by the fairies inside.
Big Banban is hesitating over the amount ... | The first and only line contains an integer *k* (1<=≤<=*k*<=≤<=106) — the desired number of loops. | Output an integer — if no such *n* exists, output -1; otherwise output any such *n*. In the latter case, your output should be a positive decimal integer not exceeding 1018. | [
"2\n",
"6\n"
] | [
"462",
"8080"
] | none | 1,000 | [
{
"input": "2",
"output": "8"
},
{
"input": "6",
"output": "888"
},
{
"input": "3",
"output": "86"
},
{
"input": "4",
"output": "88"
},
{
"input": "5",
"output": "886"
},
{
"input": "1000000",
"output": "-1"
},
{
"input": "1",
"output":... | 1,666,241,829 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
k = int(input())
if k >= 37:
ans = -1
else:
ans = 0
k -= 1
while k:
ans += 8
k -= 1
if not k:
break
ans *= 10
k -= 1
print(ans) | Title: A Prosperous Lot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to a... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
k = int(input())
if k >= 37:
ans = -1
else:
ans = 0
k -= 1
while k:
ans += 8
k -= 1
if not k:
break
ans *= 10
k -= 1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,588,966,831 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 124 | 6,963,200 | def bin_search(b,k):
ans = 0
# print(k)
l,r=0,len(b)-1
while l<=r:
mid =(l+r)//2
if b[mid]<=k:
ans = mid
l=mid+1
else:
r = mid-1
return ans
n,d = [int(n) for n in input().split()]
s = input()
b = []
for i in range(len(s)):
if s[i]=="1":
b.append(i)
# c =0
f =0
i =0
x = 0
c =0
bl = 0
for i in rang... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
def bin_search(b,k):
ans = 0
# print(k)
l,r=0,len(b)-1
while l<=r:
mid =(l+r)//2
if b[mid]<=k:
ans = mid
l=mid+1
else:
r = mid-1
return ans
n,d = [int(n) for n in input().split()]
s = input()
b = []
for i in range(len(s)):
if s[i]=="1":
b.append(i)
# c =0
f =0
i =0
x = 0
c =0
bl = 0
for... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,680,283,284 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
print("Alice" if n % 2 != 0 else "Bob")
| Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
n = int(input())
print("Alice" if n % 2 != 0 else "Bob")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,511,095,936 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 5,529,600 | n=int(input())
rem=[int(x) for x in input().split()]
cap=[int(x) for x in input().split()]
rems=0
cap2=[0,0]
for i in range(n):
rems+=rem[i]
if cap[i]>cap2[0]:
cap2[1]=cap2[0]
cap2[0]=cap[i]
elif cap[i]>cap2[1]:
cap2[1]=cap[i]
caps=cap[0]+cap[1]
if caps>=rems:
pri... | Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
n=int(input())
rem=[int(x) for x in input().split()]
cap=[int(x) for x in input().split()]
rems=0
cap2=[0,0]
for i in range(n):
rems+=rem[i]
if cap[i]>cap2[0]:
cap2[1]=cap2[0]
cap2[0]=cap[i]
elif cap[i]>cap2[1]:
cap2[1]=cap[i]
caps=cap[0]+cap[1]
if caps>=rems... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
515 | C | Drazil and Factorial | PROGRAMMING | 1,400 | [
"greedy",
"math",
"sortings"
] | null | null | Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they shoul... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=15) — the number of digits in *a*.
The second line contains *n* digits of *a*. There is at least one digit in *a* that is larger than 1. Number *a* may possibly contain leading zeroes. | Output a maximum possible integer satisfying the conditions above. There should be no zeroes and ones in this number decimal representation. | [
"4\n1234\n",
"3\n555\n"
] | [
"33222\n",
"555\n"
] | In the first case, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f5a4207f23215fddce977ab5ea9e9d2e7578fb52.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4\n1234",
"output": "33222"
},
{
"input": "3\n555",
"output": "555"
},
{
"input": "15\n012345781234578",
"output": "7777553333222222222222"
},
{
"input": "1\n8",
"output": "7222"
},
{
"input": "10\n1413472614",
"output": "75333332222222"
},
{
... | 1,591,270,265 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 109 | 307,200 | n = int(input())
v = [0] * 8
for i in range (n):
digit = int(input())
if digit == 2:
v[int(digit)] += 1
if digit == 3:
v[int(digit)] += 1
if digit == 4:
v[3] += 1
v[2] += 2
if digit == 5:
v[int(digit)] += 1
if digit == 6:
v[5] += 1
... | Title: Drazil and Factorial
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that cont... | ```python
n = int(input())
v = [0] * 8
for i in range (n):
digit = int(input())
if digit == 2:
v[int(digit)] += 1
if digit == 3:
v[int(digit)] += 1
if digit == 4:
v[3] += 1
v[2] += 2
if digit == 5:
v[int(digit)] += 1
if digit == 6:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,694,390,123 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 46 | 0 | a, b, c = input().split()
result = 0
for i in range(1 , int(c)+1):
result += (i*int(a))
if(result - int(b)) >= 0:
print(result - int(b))
else:
print(0)
| Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
a, b, c = input().split()
result = 0
for i in range(1 , int(c)+1):
result += (i*int(a))
if(result - int(b)) >= 0:
print(result - int(b))
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
369 | A | Valera and Plates | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, he needs exactly one clean plate or bowl. We know that Valera can cook only two types of dishes. He can... | The first line of the input contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=1000) — the number of the planned days, the number of clean bowls and the number of clean plates.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2). If *a**i* equals one, then on day *i* Val... | Print a single integer — the minimum number of times Valera will need to wash a plate/bowl. | [
"3 1 1\n1 2 1\n",
"4 3 1\n1 1 1 1\n",
"3 1 2\n2 2 2\n",
"8 2 2\n1 2 1 2 1 2 1 2\n"
] | [
"1\n",
"1\n",
"0\n",
"4\n"
] | In the first sample Valera will wash a bowl only on the third day, so the answer is one.
In the second sample, Valera will have the first type of the dish during all four days, and since there are only three bowls, he will wash a bowl exactly once.
In the third sample, Valera will have the second type of dish for all... | 500 | [
{
"input": "3 1 1\n1 2 1",
"output": "1"
},
{
"input": "4 3 1\n1 1 1 1",
"output": "1"
},
{
"input": "3 1 2\n2 2 2",
"output": "0"
},
{
"input": "8 2 2\n1 2 1 2 1 2 1 2",
"output": "4"
},
{
"input": "2 100 100\n2 2",
"output": "0"
},
{
"input": "1 1 1\... | 1,683,704,556 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 46 | 0 | n, m, k = map(int, input().split())
a = list(map(int, input().split()))
washing = 0
for dish in a:
if dish == 1:
if m > 0:
m -= 1
else:
washing += 1
else:
if k > 0:
k -= 1
elif m > 0:
m -= 1
else:
... | Title: Valera and Plates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, ... | ```python
n, m, k = map(int, input().split())
a = list(map(int, input().split()))
washing = 0
for dish in a:
if dish == 1:
if m > 0:
m -= 1
else:
washing += 1
else:
if k > 0:
k -= 1
elif m > 0:
m -= 1
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,483,633,671 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #define TASK_NAME string("sweets")
#define SAMPLE string("1")
#define DIR string("cf-t13")
#define REMOTE_FIO 0
//-------------------------
#ifndef DEV
#define DEV 0
#endif //!DEV
//include "../../htk-src/min_queue.cpp"
//include "../../htk-src/geom.cpp"
#include "../../htk-src/math.cpp"
#include <bits/std... | Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
#define TASK_NAME string("sweets")
#define SAMPLE string("1")
#define DIR string("cf-t13")
#define REMOTE_FIO 0
//-------------------------
#ifndef DEV
#define DEV 0
#endif //!DEV
//include "../../htk-src/min_queue.cpp"
//include "../../htk-src/geom.cpp"
#include "../../htk-src/math.cpp"
#include... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
710 | B | Optimal Point on a Line | PROGRAMMING | 1,400 | [
"brute force",
"sortings"
] | null | null | You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal. | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of points on the line.
The second line contains *n* integers *x**i* (<=-<=109<=≤<=*x**i*<=≤<=109) — the coordinates of the given *n* points. | Print the only integer *x* — the position of the optimal point on the line. If there are several optimal points print the position of the leftmost one. It is guaranteed that the answer is always the integer. | [
"4\n1 2 3 4\n"
] | [
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "5\n-1 -10 2 6 7",
"output": "2"
},
{
"input": "10\n-68 10 87 22 30 89 82 -97 -52 25",
"output": "22"
},
{
"input": "100\n457 827 807 17 871 935 907 -415 536 170 551 -988 865 758 -457 -892 -875 -488 684 19 0 555 -807 -624 -... | 1,640,911,466 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | n = int(input())
a = [int(x) for x in input().split()]
def quicksort(a, left, right):
i = left
j = right
m = int((i + j) / 2)
while i <= j:
while a[i] < a[m]: i += 1
while a[j] > a[m]: j -= 1
if(i <= j):
a[i], a[j] = a[j], a[i]
i += 1
j -= 1
... | Title: Optimal Point on a Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=... | ```python
n = int(input())
a = [int(x) for x in input().split()]
def quicksort(a, left, right):
i = left
j = right
m = int((i + j) / 2)
while i <= j:
while a[i] < a[m]: i += 1
while a[j] > a[m]: j -= 1
if(i <= j):
a[i], a[j] = a[j], a[i]
i += 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,649,395,793 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | def main():
str1=input()
str2=input()
str3=str1[::-1]
if str3==str2:
print('YES')
else:
print('NO')
if __name__ == "__main__":
main() | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
def main():
str1=input()
str2=input()
str3=str1[::-1]
if str3==str2:
print('YES')
else:
print('NO')
if __name__ == "__main__":
main()
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,597,499,865 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 186 | 2,764,800 | n=int(input())
s=input()
col={}
ans=0
for i in range(1,n):
key=s[2*i-2]
if key in col:
col[key]+=1
else:
col[key]=1
room=s[2*i-1]
if room.lower() in col:
if(col[room.lower()]==0):
ans+=1
else:
col[room.lower()]-=1
else:
... | Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
n=int(input())
s=input()
col={}
ans=0
for i in range(1,n):
key=s[2*i-2]
if key in col:
col[key]+=1
else:
col[key]=1
room=s[2*i-1]
if room.lower() in col:
if(col[room.lower()]==0):
ans+=1
else:
col[room.lower()]-=1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
680 | B | Bear and Finding Criminals | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city *a*. His job is to catch criminals. It's hard because he doesn't know in which cities criminals are. Though, he... | The first line of the input contains two integers *n* and *a* (1<=≤<=*a*<=≤<=*n*<=≤<=100) — the number of cities and the index of city where Limak lives.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=≤<=1). There are *t**i* criminals in the *i*-th city. | Print the number of criminals Limak will catch. | [
"6 3\n1 1 1 0 1 0\n",
"5 2\n0 0 0 1 0\n"
] | [
"3\n",
"1\n"
] | In the first sample, there are six cities and Limak lives in the third one (blue arrow below). Criminals are in cities marked red.
Using the BCD gives Limak the following information:
- There is one criminal at distance 0 from the third city — Limak is sure that this criminal is exactly in the third city. - There i... | 1,000 | [
{
"input": "6 3\n1 1 1 0 1 0",
"output": "3"
},
{
"input": "5 2\n0 0 0 1 0",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "9 3\n1 1 1 1 1 1 1 1 0",
"output": "8"
},
{
"input": "9 5\n1 0 1 0 1 0... | 1,657,557,513 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 24 | 187 | 10,649,600 | # If you win, you live. You cannot win unless you fight.
from sys import stdin,setrecursionlimit
input=stdin.readline
import heapq
import string
rd=lambda: map(lambda s: int(s), input().strip().split())
ri=lambda: int(input())
rs=lambda :input().strip()
from collections import defaultdict,deque,Counter
from bisect im... | Title: Bear and Finding Criminals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city... | ```python
# If you win, you live. You cannot win unless you fight.
from sys import stdin,setrecursionlimit
input=stdin.readline
import heapq
import string
rd=lambda: map(lambda s: int(s), input().strip().split())
ri=lambda: int(input())
rs=lambda :input().strip()
from collections import defaultdict,deque,Counter
from... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,631,540,920 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 46 | 6,963,200 | a_size, b_size = map(int, input().split())
k, m = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
a_array = A[0:k]
b_array = []
for i in range(m):
b_array.append(B[~i])
def is_less_(number_in_a_array: int, b_array: list) -> bool:
for num in b_ar... | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
a_size, b_size = map(int, input().split())
k, m = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
a_array = A[0:k]
b_array = []
for i in range(m):
b_array.append(B[~i])
def is_less_(number_in_a_array: int, b_array: list) -> bool:
for n... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
393 | A | Nineteen | PROGRAMMING | 0 | [] | null | null | Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) ... | The first line contains a non-empty string *s*, consisting only of lowercase English letters. The length of string *s* doesn't exceed 100. | Print a single integer — the maximum number of "nineteen"s that she can get in her string. | [
"nniinneetteeeenn\n",
"nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii\n",
"nineteenineteen\n"
] | [
"2",
"2",
"2"
] | none | 500 | [
{
"input": "nniinneetteeeenn",
"output": "2"
},
{
"input": "nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii",
"output": "2"
},
{
"input": "nineteenineteen",
"output": "2"
},
{
"input": "nssemsnnsitjtihtthij",
"output": "0"
},
{
"input": "eehihnttehtherjsihihn... | 1,581,442,922 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | def nine(s):
d={'e':0,'n':0,'t':0,'i':0}
for e in s:
if e in ['e','n','i','t']:
d[e]+=1
return min(d['e']//3,d['t'],d['n']//3,d['i'])
print(nine(input()))
| Title: Nineteen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiinetee... | ```python
def nine(s):
d={'e':0,'n':0,'t':0,'i':0}
for e in s:
if e in ['e','n','i','t']:
d[e]+=1
return min(d['e']//3,d['t'],d['n']//3,d['i'])
print(nine(input()))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,690,101,059 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 62 | 0 | x = list(map(int,input().split()))
sum = 1
first = x[0]
while (x[0]%10 != 0) and (x[0]%10 != x[1]):
x[0] += first
sum += 1
print(sum) | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
x = list(map(int,input().split()))
sum = 1
first = x[0]
while (x[0]%10 != 0) and (x[0]%10 != x[1]):
x[0] += first
sum += 1
print(sum)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,673,395,771 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | num_teams = int(input())
home_colors = list()
guest_colors = list()
num_swaps = 0
for _ in range(num_teams):
home_color, guest_color = map(int, input().split())
home_colors.append(home_color), guest_colors.append(guest_color)
for home_index in range(num_teams):
for guest_index in range(num_teams... | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
num_teams = int(input())
home_colors = list()
guest_colors = list()
num_swaps = 0
for _ in range(num_teams):
home_color, guest_color = map(int, input().split())
home_colors.append(home_color), guest_colors.append(guest_color)
for home_index in range(num_teams):
for guest_index in range... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
79 | B | Colorful Field | PROGRAMMING | 1,400 | [
"implementation",
"sortings"
] | B. Colorful Field | 2 | 256 | Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
After seeing the field carefully, Ciel found that the crop plants of each cell were planted in f... | In the first line there are four positive integers *n*,<=*m*,<=*k*,<=*t* (1<=≤<=*n*<=≤<=4·104,<=1<=≤<=*m*<=≤<=4·104,<=1<=≤<=*k*<=≤<=103,<=1<=≤<=*t*<=≤<=103), each of which represents the height of the field, the width of the field, the number of waste cells and the number of queries that ask the kind of crop plants in ... | For each query, if the cell is waste, print Waste. Otherwise, print the name of crop plants in the cell: either Carrots or Kiwis or Grapes. | [
"4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1\n"
] | [
"Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots\n"
] | The sample corresponds to the figure in the statement. | 1,000 | [
{
"input": "4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1",
"output": "Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots"
},
{
"input": "2 3 2 2\n1 1\n2 2\n2 1\n2 2",
"output": "Grapes\nWaste"
},
{
"input": "31 31 31 4\n4 9\n16 27\n11 29\n8 28\n11 2\n10 7\n22 6\n1 25\n14 8... | 1,577,524,312 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 280 | 307,200 | import bisect
from operator import itemgetter
n,m,k,t = map(int,input().split())
waste = []
q = []
for i in range(k):
waste.append(tuple(map(int,input().split())))
waste.sort(key = itemgetter(0,1))
# print(waste)
for i in range(t):
q.append(tuple(map(int,input().split())))
# print(q)
# print(waste)
... | Title: Colorful Field
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
... | ```python
import bisect
from operator import itemgetter
n,m,k,t = map(int,input().split())
waste = []
q = []
for i in range(k):
waste.append(tuple(map(int,input().split())))
waste.sort(key = itemgetter(0,1))
# print(waste)
for i in range(t):
q.append(tuple(map(int,input().split())))
# print(q)
# pri... | 3.929428 | MatrixStudio/Codeforces-Python-Submissions |
784 | F | Crunching Numbers Just for You | PROGRAMMING | 1,900 | [
"*special",
"implementation"
] | null | null | You are developing a new feature for the website which sells airline tickets: being able to sort tickets by price! You have already extracted the tickets' prices, so there's just the last step to be done...
You are given an array of integers. Sort it in non-descending order. | The input consists of a single line of space-separated integers. The first number is *n* (1<=≤<=*n*<=≤<=10) — the size of the array. The following *n* numbers are the elements of the array (1<=≤<=*a**i*<=≤<=100). | Output space-separated elements of the sorted array. | [
"3 3 1 2\n"
] | [
"1 2 3 \n"
] | Remember, this is a very important feature, and you have to make sure the customers appreciate it! | 0 | [
{
"input": "3 3 1 2",
"output": "1 2 3 "
},
{
"input": "10 54 100 27 1 33 27 80 49 27 6",
"output": "1 6 27 27 27 33 49 54 80 100 "
}
] | 1,617,285,165 | 5,505 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | a = input().split(' ')
b = [int(x) for x in a]
for x in sorted(b):
print(x, end=' ') | Title: Crunching Numbers Just for You
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are developing a new feature for the website which sells airline tickets: being able to sort tickets by price! You have already extracted the tickets' prices, so there's just the last step to be done.... | ```python
a = input().split(' ')
b = [int(x) for x in a]
for x in sorted(b):
print(x, end=' ')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
266 | B | Queue at the School | PROGRAMMING | 800 | [
"constructive algorithms",
"graph matchings",
"implementation",
"shortest paths"
] | null | null | During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling awkward for standing in front of the girls in the queue and they started letting the girls move forward ea... | The first line contains two integers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=50), which represent the number of children in the queue and the time after which the queue will transform into the arrangement you need to find.
The next line contains string *s*, which represents the schoolchildren's initial arrangement. If the *... | Print string *a*, which describes the arrangement after *t* seconds. If the *i*-th position has a boy after the needed time, then the *i*-th character *a* must equal "B", otherwise it must equal "G". | [
"5 1\nBGGBG\n",
"5 2\nBGGBG\n",
"4 1\nGGGB\n"
] | [
"GBGGB\n",
"GGBGB\n",
"GGGB\n"
] | none | 500 | [
{
"input": "5 1\nBGGBG",
"output": "GBGGB"
},
{
"input": "5 2\nBGGBG",
"output": "GGBGB"
},
{
"input": "4 1\nGGGB",
"output": "GGGB"
},
{
"input": "2 1\nBB",
"output": "BB"
},
{
"input": "2 1\nBG",
"output": "GB"
},
{
"input": "6 2\nBBGBBG",
"outpu... | 1,699,244,836 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n,t = map(int,input().split())
s=input()
while t>0:
t=t-1
for i in range(1,n):
if s[i]=='G' and s[i-1]=='B':
s = s[:i-1] + 'G' + 'B' + s[i+1:]
i += 1
print(s)
| Title: Queue at the School
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling a... | ```python
n,t = map(int,input().split())
s=input()
while t>0:
t=t-1
for i in range(1,n):
if s[i]=='G' and s[i-1]=='B':
s = s[:i-1] + 'G' + 'B' + s[i+1:]
i += 1
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,697,380,947 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | n = int(input())
count = 0
for _ in range(n):
P, V, T = map(int, input().split())
if P + V + T >= 2:
count += 1
print(count)
# Sun Oct 15 2023 17:42:24 GMT+0300 (Moscow Standard Time)
| Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
n = int(input())
count = 0
for _ in range(n):
P, V, T = map(int, input().split())
if P + V + T >= 2:
count += 1
print(count)
# Sun Oct 15 2023 17:42:24 GMT+0300 (Moscow Standard Time)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
791 | A | Bear and Big Brother | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's we... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively. | Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob. | [
"4 7\n",
"4 9\n",
"1 1\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Li... | 500 | [
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output... | 1,696,160,919 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 62 | 62 | 0 | s=input().split()
a=int(s[0])
b=int(s[1])
y=0
while a<=b:
a*=3
b*=2
y+=1
print(y)
| Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or e... | ```python
s=input().split()
a=int(s[0])
b=int(s[1])
y=0
while a<=b:
a*=3
b*=2
y+=1
print(y)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,698,637,296 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | def d_s():
ortak = sum(k) // 2
k.sort(reverse= True)
counter = 0
total = 0
for c in k:
total += c
counter += 1
if total < ortak:
break
return counter
n = int(input())
k = list(map(int, input().split()))
print(d_s()) | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
def d_s():
ortak = sum(k) // 2
k.sort(reverse= True)
counter = 0
total = 0
for c in k:
total += c
counter += 1
if total < ortak:
break
return counter
n = int(input())
k = list(map(int, input().split()))
print(d_s())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
554 | B | Ohana Cleans Up | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"strings"
] | null | null | Ohana Matsumae is trying to clean a room, which is divided up into an *n* by *n* grid of squares. Each square is initially either clean or dirty. Ohana can sweep her broom over columns of the grid. Her broom is very strange: if she sweeps over a clean square, it will become dirty, and if she sweeps over a dirty square,... | The first line of input will be a single integer *n* (1<=≤<=*n*<=≤<=100).
The next *n* lines will describe the state of the room. The *i*-th line will contain a binary string with *n* characters denoting the state of the *i*-th row of the room. The *j*-th character on this line is '1' if the *j*-th square in the *i*-t... | The output should be a single line containing an integer equal to a maximum possible number of rows that are completely clean. | [
"4\n0101\n1000\n1111\n0101\n",
"3\n111\n111\n111\n"
] | [
"2\n",
"3\n"
] | In the first sample, Ohana can sweep the 1st and 3rd columns. This will make the 1st and 4th row be completely clean.
In the second sample, everything is already clean, so Ohana doesn't need to do anything. | 500 | [
{
"input": "4\n0101\n1000\n1111\n0101",
"output": "2"
},
{
"input": "3\n111\n111\n111",
"output": "3"
},
{
"input": "10\n0100000000\n0000000000\n0000000000\n0000000000\n0000000000\n0000000000\n0000000000\n0000000000\n0000000000\n0000000000",
"output": "9"
},
{
"input": "1\n1"... | 1,596,856,621 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 109 | 6,963,200 | a=int(input())
d={}
for _ in " "*a:
z=input()
t=()
for i in range(a):
if z[i]=='0':t+=(i,)
d[t]=d.get(t,0)+1
print(max(d.values())) | Title: Ohana Cleans Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ohana Matsumae is trying to clean a room, which is divided up into an *n* by *n* grid of squares. Each square is initially either clean or dirty. Ohana can sweep her broom over columns of the grid. Her broom is very str... | ```python
a=int(input())
d={}
for _ in " "*a:
z=input()
t=()
for i in range(a):
if z[i]=='0':t+=(i,)
d[t]=d.get(t,0)+1
print(max(d.values()))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a**i* — add non-negative integer *a**i* to the multiset. Note, that she has a multiset, thus there may b... | The first line of the input contains an integer *t* (1<=≤<=*t*<=≤<=100<=000) — the number of operation Sonya has to perform.
Next *t* lines provide the descriptions of the queries in order they appear in the input file. The *i*-th row starts with a character *c**i* — the type of the corresponding operation. If *c**i* ... | For each query of the third type print the number of integers matching the given pattern. Each integer is counted as many times, as it appears in the multiset at this moment of time. | [
"12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0\n",
"4\n+ 200\n+ 200\n- 200\n? 0\n"
] | [
"2\n1\n2\n1\n1\n",
"1\n"
] | Consider the integers matching the patterns from the queries of the third type. Queries are numbered in the order they appear in the input.
1. 1 and 241. 1. 361. 1. 101 and 361. 1. 361. 1. 4000. | 0 | [
{
"input": "12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0",
"output": "2\n1\n2\n1\n1"
},
{
"input": "4\n+ 200\n+ 200\n- 200\n? 0",
"output": "1"
},
{
"input": "20\n+ 61\n+ 99\n+ 51\n+ 70\n+ 7\n+ 34\n+ 71\n+ 86\n+ 68\n+ 39\n+ 78\n+ 81\n+ 89\n? 10\n? 00... | 1,618,649,761 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 409,600 | def is_correct_for_pattern(pattern, number):
number = str(number)
pattern = str(pattern)
padding = len(number) - len(pattern)
if padding < 0:
padding = -padding
for _ in range(padding):
number = "2" + number
else:
for _ in range(padding):
pattern = "0"... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a**i* — add no... | ```python
def is_correct_for_pattern(pattern, number):
number = str(number)
pattern = str(pattern)
padding = len(number) - len(pattern)
if padding < 0:
padding = -padding
for _ in range(padding):
number = "2" + number
else:
for _ in range(padding):
pat... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,501,503,433 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 4,608,000 | s = input()
a = len(s)
q = 0
n = 0
for x in range(a - 3):
if s[x:x + 4] == "bear":
p = a - x - 3
if x - q > 0:
p = (a - x - 3) * (x - q)
q = x
print(n) | Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
s = input()
a = len(s)
q = 0
n = 0
for x in range(a - 3):
if s[x:x + 4] == "bear":
p = a - x - 3
if x - q > 0:
p = (a - x - 3) * (x - q)
q = x
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,680,869,886 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | def main():
n = int(input())
home_uniforms = []
away_uniforms = {}
for _ in range(n):
home, away = map(int, input().split())
home_uniforms.append(home)
away_uniforms[away] = away_uniforms.get(away, 0) + 1
clashes = 0
for home in home_uniforms:
clashes += away_... | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
def main():
n = int(input())
home_uniforms = []
away_uniforms = {}
for _ in range(n):
home, away = map(int, input().split())
home_uniforms.append(home)
away_uniforms[away] = away_uniforms.get(away, 0) + 1
clashes = 0
for home in home_uniforms:
clashe... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
460 | C | Present | PROGRAMMING | 1,700 | [
"binary search",
"data structures",
"greedy"
] | null | null | Little beaver is a beginner programmer, so informatics is his favorite subject. Soon his informatics teacher is going to have a birthday and the beaver has decided to prepare a present for her. He planted *n* flowers in a row on his windowsill and started waiting for them to grow. However, after some time the beaver no... | The first line contains space-separated integers *n*, *m* and *w* (1<=≤<=*w*<=≤<=*n*<=≤<=105; 1<=≤<=*m*<=≤<=105). The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the maximum final height of the smallest flower. | [
"6 2 3\n2 2 2 2 1 1\n",
"2 5 1\n5 8\n"
] | [
"2\n",
"9\n"
] | In the first sample beaver can water the last 3 flowers at the first day. On the next day he may not to water flowers at all. In the end he will get the following heights: [2, 2, 2, 3, 2, 2]. The smallest flower has height equal to 2. It's impossible to get height 3 in this test. | 1,500 | [
{
"input": "6 2 3\n2 2 2 2 1 1",
"output": "2"
},
{
"input": "2 5 1\n5 8",
"output": "9"
},
{
"input": "1 1 1\n1",
"output": "2"
},
{
"input": "3 2 3\n999999998 999999998 999999998",
"output": "1000000000"
},
{
"input": "10 8 3\n499 498 497 497 497 497 497 497 498... | 1,690,442,106 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 1,185 | 13,721,600 | import sys
#import threading
#sys.setrecursionlimit(10**8)
#threading.stack_size(10**8)
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:l... | Title: Present
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little beaver is a beginner programmer, so informatics is his favorite subject. Soon his informatics teacher is going to have a birthday and the beaver has decided to prepare a present for her. He planted *n* flowers in a row o... | ```python
import sys
#import threading
#sys.setrecursionlimit(10**8)
#threading.stack_size(10**8)
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
352 | B | Jeff and Periods | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
- *x* occurs in sequence *a*. - Consider all positions of numbers *x* in the sequence *a* (such *i*, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). The numbers are separated by spaces. | In the first line print integer *t* — the number of valid *x*. On each of the next *t* lines print two integers *x* and *p**x*, where *x* is current suitable value, *p**x* is the common difference between numbers in the progression (if *x* occurs exactly once in the sequence, *p**x* must equal 0). Print the pairs in th... | [
"1\n2\n",
"8\n1 2 1 3 1 2 1 5\n"
] | [
"1\n2 0\n",
"4\n1 2\n2 4\n3 0\n5 0\n"
] | In the first test 2 occurs exactly once in the sequence, ergo *p*<sub class="lower-index">2</sub> = 0. | 1,000 | [
{
"input": "1\n2",
"output": "1\n2 0"
},
{
"input": "8\n1 2 1 3 1 2 1 5",
"output": "4\n1 2\n2 4\n3 0\n5 0"
},
{
"input": "3\n1 10 5",
"output": "3\n1 0\n5 0\n10 0"
},
{
"input": "4\n9 9 3 5",
"output": "3\n3 0\n5 0\n9 1"
},
{
"input": "6\n1 2 2 1 1 2",
"outpu... | 1,638,489,508 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 154 | 0 | n = int(input())
seq = input().split()
occurences = {}
pairs = []
for i in range(n):
if seq[i] in occurences:
occurences[seq[i]].append(i)
else:
occurences[seq[i]] = [i]
for num in occurences:
if len(occurences[num]) > 1:
pairs.append((int(num), occurences[num][1] - occu... | Title: Jeff and Periods
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
-... | ```python
n = int(input())
seq = input().split()
occurences = {}
pairs = []
for i in range(n):
if seq[i] in occurences:
occurences[seq[i]].append(i)
else:
occurences[seq[i]] = [i]
for num in occurences:
if len(occurences[num]) > 1:
pairs.append((int(num), occurences[num]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,647,718,101 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | str1=str(input())
count=0
for char in str1:
if char.isupper():
count += 1
else:
count -= 1
if count > 0:
print(str1.upper())
else:
print(str1.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
str1=str(input())
count=0
for char in str1:
if char.isupper():
count += 1
else:
count -= 1
if count > 0:
print(str1.upper())
else:
print(str1.lower())
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
884 | A | Book Reading | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of seconds that Luba has to spend working during *i*-th day is *a**i*. If some free time remains, she... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=100, 1<=≤<=*t*<=≤<=106) — the number of days and the time required to read the book.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=86400) — the time Luba has to spend on her work during *i*-th day. | Print the minimum day Luba can finish reading the book.
It is guaranteed that answer doesn't exceed *n*. | [
"2 2\n86400 86398\n",
"2 86400\n0 86400\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "2 2\n86400 86398",
"output": "2"
},
{
"input": "2 86400\n0 86400",
"output": "1"
},
{
"input": "2 86400\n1 86399",
"output": "2"
},
{
"input": "100 1000000\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,511,341,609 | 949 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | a = [int(i) for i in input().split()]
b = [int(i) for i in input().split()]
for i in range(len(b)):
if 86400 - b[i] >= a[1]:
print(i + 1)
break | Title: Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of ... | ```python
a = [int(i) for i in input().split()]
b = [int(i) for i in input().split()]
for i in range(len(b)):
if 86400 - b[i] >= a[1]:
print(i + 1)
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
801 | A | Vicious Keyboard | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maxi... | The first line will contain a string *s* consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100. | Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character. | [
"VK\n",
"VV\n",
"V\n",
"VKKKKKKKKKVVVVVVVVVK\n",
"KVKV\n"
] | [
"1\n",
"1\n",
"0\n",
"3\n",
"1\n"
] | For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.
For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.
For the fourth case, we ... | 500 | [
{
"input": "VK",
"output": "1"
},
{
"input": "VV",
"output": "1"
},
{
"input": "V",
"output": "0"
},
{
"input": "VKKKKKKKKKVVVVVVVVVK",
"output": "3"
},
{
"input": "KVKV",
"output": "1"
},
{
"input": "VKKVVVKVKVK",
"output": "5"
},
{
"input... | 1,492,466,926 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 62 | 5,529,600 | s = input()
res = max((s[:i] + j + s[i+1:]).count('VK') for j in 'VK' for i in range(len(s)))
print(res)
| Title: Vicious Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter i... | ```python
s = input()
res = max((s[:i] + j + s[i+1:]).count('VK') for j in 'VK' for i in range(len(s)))
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions |
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