contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
270 | A | Fancy Fence | PROGRAMMING | 1,100 | [
"geometry",
"implementation",
"math"
] | null | null | Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuska... | The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees. | For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible. | [
"3\n30\n60\n90\n"
] | [
"NO\nYES\nYES\n"
] | In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a r... | 500 | [
{
"input": "3\n30\n60\n90",
"output": "NO\nYES\nYES"
},
{
"input": "6\n1\n2\n3\n170\n179\n25",
"output": "NO\nNO\nNO\nYES\nYES\nNO"
}
] | 1,665,468,043 | 2,147,483,647 | Python 3 | OK | TESTS | 3 | 62 | 0 | for x in range(int(input())):
angle=int(input())
N=360/(180-angle)
print(["NO","YES"][int(N)==N]) | Title: Fancy Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can... | ```python
for x in range(int(input())):
angle=int(input())
N=360/(180-angle)
print(["NO","YES"][int(N)==N])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
952 | G | Puzzling Language | PROGRAMMING | 2,200 | [
"constructive algorithms"
] | null | null | In this problem you will write a simple code generator for a 2D programming language derived from [Brainfuck](https://en.wikipedia.org/wiki/Brainfuck).
The code in this language is a rectangular grid of characters '.' and 'X'. The code is converted to a Brainfuck program as follows: the characters are read in the usua... | The input consists of a single string of characters with ASCII codes between 33 ('!') and 122 ('z'), inclusive. The length of the string is between 1 and 10 characters, inclusive. | Output a program in the described language which, when executed, will print the given message. | [
"$$$"
] | [
".......X.......\n......XXX......\n.....XXXXX.....\n....XXXXXXX....\n...XXXXXXXXX...\n..XXXXXXXXXXX..\n.XXXXXXXXXXXXX.\n...............\nX.............X\nX..............\nX..............\nX..............\n"
] | The example corresponds to the following Brainfuck program:
The triangular block decrements the first memory cell and sets the value of the second memory cell to 36 - the ASCII code of '$' character. The next line after the triangular block moves the memory pointer to the second memory cell, and the next three lines p... | 0 | [
{
"input": "$$$",
"output": "..\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\n.X\nX.\... | 1,656,924,381 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 31 | 0 | for i in map(ord, input()) : print("..\n.X\n" * (256 - i) + ".X\n" + "..\n.X\n" * i, end = "") | Title: Puzzling Language
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you will write a simple code generator for a 2D programming language derived from [Brainfuck](https://en.wikipedia.org/wiki/Brainfuck).
The code in this language is a rectangular grid of characters '.... | ```python
for i in map(ord, input()) : print("..\n.X\n" * (256 - i) + ".X\n" + "..\n.X\n" * i, end = "")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,650,895,435 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 154 | 2,150,400 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
a = list(map(int, input().split()))
cnt = [0] * (n + 1)
for i in a:
cnt[i] += 1
ans = 0
for i in range(1, n + 1):
if not cnt[i]:
ans += 1
print(ans) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
a = list(map(int, input().split()))
cnt = [0] * (n + 1)
for i in a:
cnt[i] += 1
ans = 0
for i in range(1, n + 1):
if not cnt[i]:
ans += 1
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
938 | B | Run For Your Prize | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are distinct. You start at position 1, your friend — at position 106 (and there is no prize in any of these tw... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the number of prizes.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (2<=≤<=*a**i*<=≤<=106<=-<=1) — the positions of the prizes. No two prizes are located at the same position. Positions are given in ascending order. | Print one integer — the minimum number of seconds it will take to collect all prizes. | [
"3\n2 3 9\n",
"2\n2 999995\n"
] | [
"8\n",
"5\n"
] | In the first example you take all the prizes: take the first at 1, the second at 2 and the third at 8.
In the second example you take the first prize in 1 second and your friend takes the other in 5 seconds, you do this simultaneously, so the total time is 5. | 0 | [
{
"input": "3\n2 3 9",
"output": "8"
},
{
"input": "2\n2 999995",
"output": "5"
},
{
"input": "1\n20",
"output": "19"
},
{
"input": "6\n2 3 500000 999997 999998 999999",
"output": "499999"
},
{
"input": "1\n999999",
"output": "1"
},
{
"input": "1\n5100... | 1,629,290,910 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 140 | 14,438,400 | n=int(input())
a=list(map(int,input().split()))
c=10000000
for i in range(n-1):
c=min(max(a[i]-1,1000000-a[i+1]),c)
print(min(a[-1]-1,1000000-a[1],c))
| Title: Run For Your Prize
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are di... | ```python
n=int(input())
a=list(map(int,input().split()))
c=10000000
for i in range(n-1):
c=min(max(a[i]-1,1000000-a[i+1]),c)
print(min(a[-1]-1,1000000-a[1],c))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,564,763,730 | 2,147,483,647 | PyPy 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 16 | 280 | 67,072,000 | import sys
input = sys.stdin.readline
def grafAdd(n, m):
matrix = [[-1]*n for _ in range(n)]
for i in range(m):
u, v, l = map(int, input().split())
u-=1
v-=1
if matrix[u][v] == -1:
matrix[u][v] = l
matrix[v][u] = l
else:
m... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
import sys
input = sys.stdin.readline
def grafAdd(n, m):
matrix = [[-1]*n for _ in range(n)]
for i in range(m):
u, v, l = map(int, input().split())
u-=1
v-=1
if matrix[u][v] == -1:
matrix[u][v] = l
matrix[v][u] = l
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
838 | A | Binary Blocks | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | You are given an image, that can be represented with a 2-d *n* by *m* grid of pixels. Each pixel of the image is either on or off, denoted by the characters "0" or "1", respectively. You would like to compress this image. You want to choose an integer *k*<=><=1 and split the image into *k* by *k* blocks. If *n* and ... | The first line of input will contain two integers *n*,<=*m* (2<=≤<=*n*,<=*m*<=≤<=2<=500), the dimensions of the image.
The next *n* lines of input will contain a binary string with exactly *m* characters, representing the image. | Print a single integer, the minimum number of pixels needed to toggle to make the image compressible. | [
"3 5\n00100\n10110\n11001\n"
] | [
"5\n"
] | We first choose *k* = 2.
The image is padded as follows:
We can toggle the image to look as follows:
We can see that this image is compressible for *k* = 2. | 0 | [
{
"input": "3 5\n00100\n10110\n11001",
"output": "5"
}
] | 1,631,857,330 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 37,888,000 | # _838a
#####################################################################################################################
def main():
return nPixelsToToggleMin([list(map(int, input())) for _ in range(int(input().split()[0]))])
def nPixelsToToggleMin(image):
nOnes2, nOnes3 = [0]*4, [0]*9
bloc... | Title: Binary Blocks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an image, that can be represented with a 2-d *n* by *m* grid of pixels. Each pixel of the image is either on or off, denoted by the characters "0" or "1", respectively. You would like to compress this image.... | ```python
# _838a
#####################################################################################################################
def main():
return nPixelsToToggleMin([list(map(int, input())) for _ in range(int(input().split()[0]))])
def nPixelsToToggleMin(image):
nOnes2, nOnes3 = [0]*4, [0]*9... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift.... | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,688,651,854 | 2,147,483,647 | Python 3 | OK | TESTS | 101 | 92 | 0 | n= int(input())
x=input().split()
s=''
for i in range(1,n+1):
c=0
a=str(i)
for j in x:
if j==a:
c+=1
break
else:
c+=1
s+=str(c)+' '
print(s) | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on t... | ```python
n= int(input())
x=input().split()
s=''
for i in range(1,n+1):
c=0
a=str(i)
for j in x:
if j==a:
c+=1
break
else:
c+=1
s+=str(c)+' '
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,638,905,213 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 46 | 0 | s=input()
n=''
for i in s:
if i=='h'and n=='':
n+=i
if i=='e' and n=='h':
n+=i
if i=='i' and n=='he':
n+=i
if i=='d' and n=='hei':
n+=i
if i=='i' and n=='heid':
n+=i
if n=='heidi':
print("YES")
else:
print("NO")
| Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
s=input()
n=''
for i in s:
if i=='h'and n=='':
n+=i
if i=='e' and n=='h':
n+=i
if i=='i' and n=='he':
n+=i
if i=='d' and n=='hei':
n+=i
if i=='i' and n=='heid':
n+=i
if n=='heidi':
print("YES")
else:
print("NO")
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
733 | B | Parade | PROGRAMMING | 1,100 | [
"math"
] | null | null | Very soon there will be a parade of victory over alien invaders in Berland. Unfortunately, all soldiers died in the war and now the army consists of entirely new recruits, many of whom do not even know from which leg they should begin to march. The civilian population also poorly understands from which leg recruits beg... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=105) — the number of columns.
The next *n* lines contain the pairs of integers *l**i* and *r**i* (1<=≤<=*l**i*,<=*r**i*<=≤<=500) — the number of soldiers in the *i*-th column which start to march from the left or the right leg respectively. | Print single integer *k* — the number of the column in which soldiers need to change the leg from which they start to march, or 0 if the maximum beauty is already reached.
Consider that columns are numbered from 1 to *n* in the order they are given in the input data.
If there are several answers, print any of them. | [
"3\n5 6\n8 9\n10 3\n",
"2\n6 5\n5 6\n",
"6\n5 9\n1 3\n4 8\n4 5\n23 54\n12 32\n"
] | [
"3\n",
"1\n",
"0\n"
] | In the first example if you don't give the order to change the leg, the number of soldiers, who start to march from the left leg, would equal 5 + 8 + 10 = 23, and from the right leg — 6 + 9 + 3 = 18. In this case the beauty of the parade will equal |23 - 18| = 5.
If you give the order to change the leg to the third co... | 1,000 | [
{
"input": "3\n5 6\n8 9\n10 3",
"output": "3"
},
{
"input": "2\n6 5\n5 6",
"output": "1"
},
{
"input": "6\n5 9\n1 3\n4 8\n4 5\n23 54\n12 32",
"output": "0"
},
{
"input": "2\n500 499\n500 500",
"output": "0"
},
{
"input": "1\n139 252",
"output": "0"
},
{
... | 1,583,476,226 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 4 | 779 | 268,390,400 | a = eval('map(int, input().split()),' * int(input()))
b = [i - j for i, j in a]
mn, mx = min(b), max(b)
m = b.index((mx, mn)[-mn > mx])
now = sum(b)
future = now - (b[m] * 2)
print((0, m + 1)[abs(future) > abs(now)]) | Title: Parade
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Very soon there will be a parade of victory over alien invaders in Berland. Unfortunately, all soldiers died in the war and now the army consists of entirely new recruits, many of whom do not even know from which leg they should... | ```python
a = eval('map(int, input().split()),' * int(input()))
b = [i - j for i, j in a]
mn, mx = min(b), max(b)
m = b.index((mx, mn)[-mn > mx])
now = sum(b)
future = now - (b[m] * 2)
print((0, m + 1)[abs(future) > abs(now)])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
450 | A | Jzzhu and Children | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of... | The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). | Output a single integer, representing the number of the last child. | [
"5 2\n1 3 1 4 2\n",
"6 4\n1 1 2 2 3 3\n"
] | [
"4\n",
"6\n"
] | Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the en... | 500 | [
{
"input": "5 2\n1 3 1 4 2",
"output": "4"
},
{
"input": "6 4\n1 1 2 2 3 3",
"output": "6"
},
{
"input": "7 3\n6 1 5 4 2 3 1",
"output": "4"
},
{
"input": "10 5\n2 7 3 6 2 5 1 3 4 5",
"output": "4"
},
{
"input": "100 1\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18... | 1,680,181,582 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | def juzzuAndChildren(n,m,c):
ans = 0
k = -1
for i in range(n):
if c[i]>=k:
k = c[i]
ans = i+1
return ans
if __name__ == "__main__":
n,m = [int(i) for i in input().split()]
c = [int(i) for i in input().split()]
ans = juzzuAndChi... | Title: Jzzhu and Children
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line ... | ```python
def juzzuAndChildren(n,m,c):
ans = 0
k = -1
for i in range(n):
if c[i]>=k:
k = c[i]
ans = i+1
return ans
if __name__ == "__main__":
n,m = [int(i) for i in input().split()]
c = [int(i) for i in input().split()]
ans = j... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
343 | B | Alternating Current | PROGRAMMING | 1,600 | [
"data structures",
"greedy",
"implementation"
] | null | null | Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it a proper glance and started experimenting right away. After a while Mike observed that the wires ended u... | The single line of the input contains a sequence of characters "+" and "-" of length *n* (1<=≤<=*n*<=≤<=100000). The *i*-th (1<=≤<=*i*<=≤<=*n*) position of the sequence contains the character "+", if on the *i*-th step from the wall the "plus" wire runs above the "minus" wire, and the character "-" otherwise. | Print either "Yes" (without the quotes) if the wires can be untangled or "No" (without the quotes) if the wires cannot be untangled. | [
"-++-\n",
"+-\n",
"++\n",
"-\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"No\n"
] | The first testcase corresponds to the picture in the statement. To untangle the wires, one can first move the "plus" wire lower, thus eliminating the two crosses in the middle, and then draw it under the "minus" wire, eliminating also the remaining two crosses.
In the second testcase the "plus" wire makes one full rev... | 1,000 | [
{
"input": "-++-",
"output": "Yes"
},
{
"input": "+-",
"output": "No"
},
{
"input": "++",
"output": "Yes"
},
{
"input": "-",
"output": "No"
},
{
"input": "+-+-",
"output": "No"
},
{
"input": "-+-",
"output": "No"
},
{
"input": "-++-+--+",
... | 1,549,107,551 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 24 | 1,000 | 716,800 | from heapq import heappush, heappop
import random
input = input()
n = len(input)
while True:
test = "++" in input
test2 = "--" in input
if test:
input = input.replace("++", "")
if test2:
input = input.replace("--", "")
if not test and not test2:
break
... | Title: Alternating Current
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike has just finished constructing a new device to search for extraterrestrial intelligence! He was in such a hurry to launch it for the first time that he plugged in the power wires without giving it... | ```python
from heapq import heappush, heappop
import random
input = input()
n = len(input)
while True:
test = "++" in input
test2 = "--" in input
if test:
input = input.replace("++", "")
if test2:
input = input.replace("--", "")
if not test and not test2:
br... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
732 | B | Cormen --- The Best Friend Of a Man | PROGRAMMING | 1,000 | [
"dp",
"greedy"
] | null | null | Recently a dog was bought for Polycarp. The dog's name is Cormen. Now Polycarp has a lot of troubles. For example, Cormen likes going for a walk.
Empirically Polycarp learned that the dog needs at least *k* walks for any two consecutive days in order to feel good. For example, if *k*<==<=5 and yesterday Polycarp went... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=500) — the number of days and the minimum number of walks with Cormen for any two consecutive days.
The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=500) — the number of walks with Cormen on the *i*-th day which Polyca... | In the first line print the smallest number of additional walks that Polycarp should do during the next *n* days so that Cormen will feel good during all days.
In the second line print *n* integers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* — the total number of walks on the *i*-th day according to the found solutions ... | [
"3 5\n2 0 1\n",
"3 1\n0 0 0\n",
"4 6\n2 4 3 5\n"
] | [
"4\n2 3 2\n",
"1\n0 1 0\n",
"0\n2 4 3 5\n"
] | none | 1,000 | [
{
"input": "3 5\n2 0 1",
"output": "4\n2 3 2"
},
{
"input": "3 1\n0 0 0",
"output": "1\n0 1 0"
},
{
"input": "4 6\n2 4 3 5",
"output": "0\n2 4 3 5"
},
{
"input": "5 1\n0 0 0 0 1",
"output": "2\n0 1 0 1 1"
},
{
"input": "10 500\n164 44 238 205 373 249 87 30 239 90"... | 1,694,379,533 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 46 | 0 | n, k = map(int, input().split())
a = list(map(int, input().split()))
m = 0
for i in range(1, n):
if a[i-1] + a[i] < k:
m += k - a[i] - a[i-1]
a[i] = k - a[i-1]
print(m)
print(*a) | Title: Cormen --- The Best Friend Of a Man
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently a dog was bought for Polycarp. The dog's name is Cormen. Now Polycarp has a lot of troubles. For example, Cormen likes going for a walk.
Empirically Polycarp learned that the dog needs at ... | ```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
m = 0
for i in range(1, n):
if a[i-1] + a[i] < k:
m += k - a[i] - a[i-1]
a[i] = k - a[i-1]
print(m)
print(*a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
281 | B | Nearest Fraction | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"two pointers"
] | null | null | You are given three positive integers *x*,<=*y*,<=*n*. Your task is to find the nearest fraction to fraction whose denominator is no more than *n*.
Formally, you should find such pair of integers *a*,<=*b* (1<=≤<=*b*<=≤<=*n*; 0<=≤<=*a*) that the value is as minimal as possible.
If there are multiple "nearest" frac... | A single line contains three integers *x*,<=*y*,<=*n* (1<=≤<=*x*,<=*y*,<=*n*<=≤<=105). | Print the required fraction in the format "*a*/*b*" (without quotes). | [
"3 7 6\n",
"7 2 4\n"
] | [
"2/5\n",
"7/2\n"
] | none | 1,000 | [] | 1,696,378,826 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | #Fraccion mas cercana
def fraccion_cercana(x, y, n):
minimo = float('inf')
a, b = 0, 1
for i in range(1, n+1):
j = int(x*i/y)
for k in range(j-1, j+2):
if abs(x/y - k/i) < minimo:
minimo = abs(x/y - k/i)
... | Title: Nearest Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given three positive integers *x*,<=*y*,<=*n*. Your task is to find the nearest fraction to fraction whose denominator is no more than *n*.
Formally, you should find such pair of integers *a*,<=*b* (1<=≤<=*b... | ```python
#Fraccion mas cercana
def fraccion_cercana(x, y, n):
minimo = float('inf')
a, b = 0, 1
for i in range(1, n+1):
j = int(x*i/y)
for k in range(j-1, j+2):
if abs(x/y - k/i) < minimo:
minimo = abs(x/y - k/i)
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
535 | B | Tavas and SaDDas | PROGRAMMING | 1,100 | [
"bitmasks",
"brute force",
"combinatorics",
"implementation"
] | null | null | Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphones and told him: "If you solve the following problem, I'll return it to you."
The problem is:
You ar... | The first and only line of input contains a lucky number *n* (1<=≤<=*n*<=≤<=109). | Print the index of *n* among all lucky numbers. | [
"4\n",
"7\n",
"77\n"
] | [
"1\n",
"2\n",
"6\n"
] | none | 1,000 | [
{
"input": "4",
"output": "1"
},
{
"input": "7",
"output": "2"
},
{
"input": "77",
"output": "6"
},
{
"input": "4",
"output": "1"
},
{
"input": "474744",
"output": "83"
},
{
"input": "777774",
"output": "125"
},
{
"input": "447",
"outpu... | 1,567,002,555 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 29 | 1,000 | 2,048,000 | n=int(input())
ans=0
for i in range(n+1):
b=True
x=str(i)
for j in range(len(x)):
if x[j]!="4" and x[j]!="7":
b=False
break
if b==True:
ans+=1
print(ans) | Title: Tavas and SaDDas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphone... | ```python
n=int(input())
ans=0
for i in range(n+1):
b=True
x=str(i)
for j in range(len(x)):
if x[j]!="4" and x[j]!="7":
b=False
break
if b==True:
ans+=1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,453,594,343 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 62 | 0 | n = int(input())
if n%2 == 0:
if n%4 == 0:
print(int(n/4-1))
else:
print(int((n-2)/4))
else:
print(0) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n = int(input())
if n%2 == 0:
if n%4 == 0:
print(int(n/4-1))
else:
print(int((n-2)/4))
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
117 | C | Cycle | PROGRAMMING | 2,000 | [
"dfs and similar",
"graphs"
] | null | null | A tournament is a directed graph without self-loops in which every pair of vertexes is connected by exactly one directed edge. That is, for any two vertexes *u* and *v* (*u*<=≠<=*v*) exists either an edge going from *u* to *v*, or an edge from *v* to *u*.
You are given a tournament consisting of *n* vertexes. Your tas... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=5000). Next *n* lines contain the adjacency matrix *A* of the graph (without spaces). *A**i*,<=*j*<==<=1 if the graph has an edge going from vertex *i* to vertex *j*, otherwise *A**i*,<=*j*<==<=0. *A**i*,<=*j* stands for the *j*-th character in the *i*-th line.
It ... | Print three distinct vertexes of the graph *a*1, *a*2, *a*3 (1<=≤<=*a**i*<=≤<=*n*), such that *A**a*1,<=*a*2<==<=*A**a*2,<=*a*3<==<=*A**a*3,<=*a*1<==<=1, or "-1", if a cycle whose length equals three does not exist.
If there are several solutions, print any of them. | [
"5\n00100\n10000\n01001\n11101\n11000\n",
"5\n01111\n00000\n01000\n01100\n01110\n"
] | [
"1 3 2 ",
"-1\n"
] | none | 1,500 | [
{
"input": "5\n00100\n10000\n01001\n11101\n11000",
"output": "1 3 2 "
},
{
"input": "5\n01111\n00000\n01000\n01100\n01110",
"output": "-1"
},
{
"input": "5\n01000\n00101\n10010\n11001\n10100",
"output": "1 2 3 "
},
{
"input": "5\n00110\n10110\n00011\n00000\n11010",
"outpu... | 1,493,710,506 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#define dbg(x) cerr<<#x": "<<x<<"\n"
#define dbg_v(x, n) do{cerr<<#x"[]: ";for(int _=0;_<n;++_)cerr<<x[_]<<" ";cerr<<'\n';}while(0)
#define dbg_ok cerr<<"OK!\n"
using namespace std;
int n, use[5001], mat[5001][5001], prv[5001];
std::vector<int> v;
int dfs(int k)
{
use[k] = 1... | Title: Cycle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tournament is a directed graph without self-loops in which every pair of vertexes is connected by exactly one directed edge. That is, for any two vertexes *u* and *v* (*u*<=≠<=*v*) exists either an edge going from *u* to *v*, o... | ```python
#include <bits/stdc++.h>
#define dbg(x) cerr<<#x": "<<x<<"\n"
#define dbg_v(x, n) do{cerr<<#x"[]: ";for(int _=0;_<n;++_)cerr<<x[_]<<" ";cerr<<'\n';}while(0)
#define dbg_ok cerr<<"OK!\n"
using namespace std;
int n, use[5001], mat[5001][5001], prv[5001];
std::vector<int> v;
int dfs(int k)
{
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
622 | D | Optimal Number Permutation | PROGRAMMING | 1,900 | [
"constructive algorithms"
] | null | null | You have array *a* that contains all integers from 1 to *n* twice. You can arbitrary permute any numbers in *a*.
Let number *i* be in positions *x**i*,<=*y**i* (*x**i*<=<<=*y**i*) in the permuted array *a*. Let's define the value *d**i*<==<=*y**i*<=-<=*x**i* — the distance between the positions of the number *i*. P... | The only line contains integer *n* (1<=≤<=*n*<=≤<=5·105). | Print 2*n* integers — the permuted array *a* that minimizes the value of the sum *s*. | [
"2\n",
"1\n"
] | [
"1 1 2 2\n",
"1 1\n"
] | none | 0 | [
{
"input": "2",
"output": "1 1 2 2"
},
{
"input": "1",
"output": "1 1"
},
{
"input": "3",
"output": "1 3 1 2 2 3"
},
{
"input": "4",
"output": "1 3 3 1 2 4 2 4"
},
{
"input": "10",
"output": "1 3 5 7 9 9 7 5 3 1 2 4 6 8 10 8 6 4 2 10"
},
{
"input": "10... | 1,684,845,974 | 2,174 | PyPy 3-64 | OK | TESTS | 16 | 374 | 112,435,200 | import sys
input = sys.stdin.readline
from collections import defaultdict, deque, Counter
from heapq import heappop, heappush
from bisect import bisect_left, bisect_right
from math import gcd
n = int(input())
odd = []
even = []
for i in range(n):
if i % 2 == 0:
even.append(n-i)
else:
... | Title: Optimal Number Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have array *a* that contains all integers from 1 to *n* twice. You can arbitrary permute any numbers in *a*.
Let number *i* be in positions *x**i*,<=*y**i* (*x**i*<=<<=*y**i*) in the permuted array *a... | ```python
import sys
input = sys.stdin.readline
from collections import defaultdict, deque, Counter
from heapq import heappop, heappush
from bisect import bisect_left, bisect_right
from math import gcd
n = int(input())
odd = []
even = []
for i in range(n):
if i % 2 == 0:
even.append(n-i)
e... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
946 | D | Timetable | PROGRAMMING | 1,800 | [
"dp"
] | null | null | Ivan is a student at Berland State University (BSU). There are *n* days in Berland week, and each of these days Ivan might have some classes at the university.
There are *m* working hours during each Berland day, and each lesson at the university lasts exactly one hour. If at some day Ivan's first lesson is during *i*... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=≤<=500) — the number of days in the Berland week, the number of working hours during each day, and the number of lessons Ivan can skip, respectively.
Then *n* lines follow, *i*-th line containing a binary string of *m* charact... | Print the minimum number of hours Ivan has to spend in the university during the week if he skips not more than *k* lessons. | [
"2 5 1\n01001\n10110\n",
"2 5 0\n01001\n10110\n"
] | [
"5\n",
"8\n"
] | In the first example Ivan can skip any of two lessons during the first day, so he spends 1 hour during the first day and 4 hours during the second day.
In the second example Ivan can't skip any lessons, so he spends 4 hours every day. | 0 | [
{
"input": "2 5 1\n01001\n10110",
"output": "5"
},
{
"input": "2 5 0\n01001\n10110",
"output": "8"
},
{
"input": "3 4 0\n0000\n0000\n0000",
"output": "0"
},
{
"input": "3 4 12\n1111\n1111\n1111",
"output": "0"
},
{
"input": "3 4 6\n1111\n1111\n1111",
"output":... | 1,662,343,608 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 15 | 140 | 5,734,400 | I,G=input,range;n,m,k=map(int,I().split());f=[0]*(k+1)
for i in G(n):
r=[j for j,c in enumerate(I())if c=='1']
n1=len(r);cur=[n*m]*(k+1)
if n1==0:continue
for j in G(k+1):
for l in G(min(j,n1),-1,-1):#skip first or last l lessons
on1=on2=0
if l<n1:on1,on2=r[-1]-r[l]+1,r[n1-l-1]-r[0]+1
... | Title: Timetable
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan is a student at Berland State University (BSU). There are *n* days in Berland week, and each of these days Ivan might have some classes at the university.
There are *m* working hours during each Berland day, and each le... | ```python
I,G=input,range;n,m,k=map(int,I().split());f=[0]*(k+1)
for i in G(n):
r=[j for j,c in enumerate(I())if c=='1']
n1=len(r);cur=[n*m]*(k+1)
if n1==0:continue
for j in G(k+1):
for l in G(min(j,n1),-1,-1):#skip first or last l lessons
on1=on2=0
if l<n1:on1,on2=r[-1]-r[l]+1,r[n1-l-1]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,645,317,524 | 2,147,483,647 | Python 3 | OK | TESTS | 88 | 62 | 409,600 | from functools import lru_cache
@lru_cache(maxsize=400)
def solve(nums, i, prev):
if i >= len(nums):
return 0
if nums[i] == 0:
return 1 + solve(nums, i+1, 0)
if nums[i] != 3:
if prev == nums[i]:
return 1 + solve(nums, i+1, 0)
else:
return solve(... | Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Int... | ```python
from functools import lru_cache
@lru_cache(maxsize=400)
def solve(nums, i, prev):
if i >= len(nums):
return 0
if nums[i] == 0:
return 1 + solve(nums, i+1, 0)
if nums[i] != 3:
if prev == nums[i]:
return 1 + solve(nums, i+1, 0)
else:
ret... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,686,380,385 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
l = [int(x) for x in range(1,(n+1))]
l2 = []
for i in range(len(l)):
if (l[i]%2 == 0) and (l[i]!=2):
continue
elif (l[i]%3 == 0) and (l[i]!=3):
continue
elif (l[i]%5 == 0) and (l[i]!=5):
continue
elif (l[i]%7 == 0) and (l[i]!=7):
continue
... | Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
n = int(input())
l = [int(x) for x in range(1,(n+1))]
l2 = []
for i in range(len(l)):
if (l[i]%2 == 0) and (l[i]!=2):
continue
elif (l[i]%3 == 0) and (l[i]!=3):
continue
elif (l[i]%5 == 0) and (l[i]!=5):
continue
elif (l[i]%7 == 0) and (l[i]!=7):
cont... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
686 | B | Little Robber Girl's Zoo | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation",
"sortings"
] | null | null | Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — number of animals in the robber girl's zoo.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the height of the animal occupying the *i*-th place. | Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, *i*-th of the lines should contain two space-separated integers *l**i* and *r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*) — descriptions of segments the robber girl should name. The segments... | [
"4\n2 1 4 3\n",
"7\n36 28 57 39 66 69 68\n",
"5\n1 2 1 2 1\n"
] | [
"1 4\n",
"1 4\n6 7\n",
"2 5\n3 4\n1 4\n1 4\n"
] | Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed. | 1,000 | [
{
"input": "4\n2 1 4 3",
"output": "1 2\n3 4"
},
{
"input": "7\n36 28 57 39 66 69 68",
"output": "1 2\n3 4\n6 7"
},
{
"input": "5\n1 2 1 2 1",
"output": "2 3\n4 5\n3 4"
},
{
"input": "78\n7 3 8 8 9 8 10 9 12 11 16 14 17 17 18 18 20 20 25 22 27 26 29 27 35 35 36 36 37 37 38 38... | 1,691,995,708 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 102,400 | # LUOGU_RID: 120814999
n = int(input())
a = list(map(int, input().split()))
for i in range(1, n):
for j in range(n - 1, i - 1, -1):
if a[j] < a[j - 1]:
a[j], a[j - 1] = a[j - 1], a[j]
print(j, j + 1)
| Title: Little Robber Girl's Zoo
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in th... | ```python
# LUOGU_RID: 120814999
n = int(input())
a = list(map(int, input().split()))
for i in range(1, n):
for j in range(n - 1, i - 1, -1):
if a[j] < a[j - 1]:
a[j], a[j - 1] = a[j - 1], a[j]
print(j, j + 1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,663,598,468 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | ch=str(input())
l=ch.split(' ')
while (int(l[0])<1 ) or (int(l[0])>int(l[1])) or (int(l[1])<1) or (int(l[1])>16) or (len(l)!=2) or ch[len(l[0])]!=' ' :
ch=str(input())
l=ch.split(' ')
m,n=int(l[0]),int(l[1])
if m%2==0:
print((m*n)/2)
else:
s=((m-1)*n)/2
s+=n//2
print(s) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
ch=str(input())
l=ch.split(' ')
while (int(l[0])<1 ) or (int(l[0])>int(l[1])) or (int(l[1])<1) or (int(l[1])>16) or (len(l)!=2) or ch[len(l[0])]!=' ' :
ch=str(input())
l=ch.split(' ')
m,n=int(l[0]),int(l[1])
if m%2==0:
print((m*n)/2)
else:
s=((m-1)*n)/2
s+=n//2
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
918 | B | Radio Station | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server has a name and an ip (names aren't necessarily unique, but ips are). Dustin knows the ip and name o... | The first line of input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000).
The next *n* lines contain the names and ips of the servers. Each line contains a string name, name of the server and a string ip, ip of the server, separated by space (1<=≤<=|*name*|<=≤<=10, *name* only consists of English lowercase... | Print *m* lines, the commands in the configuration file after Dustin did his task. | [
"2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;\n",
"3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.33.27;\nunblock 8.8.8.8;\ncheck 138.197.64.57;\n"
] | [
"block 192.168.0.1; #replica\nproxy 192.168.0.2; #main\n",
"redirect 138.197.64.57; #server\nblock 8.8.8.8; #google\ncf 212.193.33.27; #codeforces\nunblock 8.8.8.8; #google\ncheck 138.197.64.57; #server\n"
] | none | 1,000 | [
{
"input": "2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;",
"output": "block 192.168.0.1; #replica\nproxy 192.168.0.2; #main"
},
{
"input": "3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.3... | 1,558,654,595 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 124 | 307,200 | a = input().split()
for i in range(2):
a[i]=int(a[i])
dic = {}
for i in range(a[0]):
ls = input().split()
dic[ls[1]]=ls[0]
for i in range(a[1]):
ls1= input().split()
b = ""
d=""
c= ""
b = ls1[1]
c=b[:len(b)-1]
d = dic[c]
print(ls1[0]+" " +ls1[1] + " #" + d )
| Title: Radio Station
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server ... | ```python
a = input().split()
for i in range(2):
a[i]=int(a[i])
dic = {}
for i in range(a[0]):
ls = input().split()
dic[ls[1]]=ls[0]
for i in range(a[1]):
ls1= input().split()
b = ""
d=""
c= ""
b = ls1[1]
c=b[:len(b)-1]
d = dic[c]
print(ls1[0]+" " +ls1[1] + " #" + d )
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero,... | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,700,502,026 | 2,147,483,647 | Python 3 | OK | TESTS | 11 | 31 | 0 | x = list(map(int, input().split()))
num = x[0]
times = x[1]
while times > 0:
if num % 10 > 0:
num = num - 1
times = times - 1
else:
num = num // 10
times = times - 1
print(num) | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit ... | ```python
x = list(map(int, input().split()))
num = x[0]
times = x[1]
while times > 0:
if num % 10 > 0:
num = num - 1
times = times - 1
else:
num = num // 10
times = times - 1
print(num)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
56 | A | Bar | PROGRAMMING | 1,000 | [
"implementation"
] | A. Bar | 2 | 256 | According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya happened to determine either the age or the drink the person is having. Vasya can chec... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of the bar's clients. Then follow *n* lines, each describing one visitor. A line either contains his age (an integer from 0 to 1000) or his drink (a string of capital Latin letters from 1 to 100 in length). It is guaranteed that the input da... | Print a single number which is the number of people Vasya should check to guarantee the law enforcement. | [
"5\n18\nVODKA\nCOKE\n19\n17\n"
] | [
"2\n"
] | In the sample test the second and fifth clients should be checked. | 500 | [
{
"input": "5\n18\nVODKA\nCOKE\n19\n17",
"output": "2"
},
{
"input": "2\n2\nGIN",
"output": "2"
},
{
"input": "3\nWHISKEY\n3\nGIN",
"output": "3"
},
{
"input": "4\n813\nIORBQITQXMPTFAEMEQDQIKFGKGOTNKTOSZCBRPXJLUKVLVHJYNRUJXK\nRUM\nRHVRWGODYWWTYZFLFYKCVUFFRTQDINKNWPKFHZBFWBHWI... | 1,584,560,640 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 216 | 0 | # -*- coding: utf-8 -*-
"""
Created on Wed Mar 18 21:37:04 2020
@author: DELL
"""
str=["ABSINTH", "BEER", "BRANDY","CHAMPAGNE","GIN","RUM","SAKE","TEQUILA","VODKA","WHISKEY","WINE"]
n=int(input())
l=[]
for i in range(n):
h=input()
l+=[h]
c=0
for i in l:
if i.isalpha():
if not i in st... | Title: Bar
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to Berland laws it is only allowed to sell alcohol to people not younger than 18 years. Vasya's job is to monitor the law's enforcement. Tonight he entered a bar and saw *n* people sitting there. For every one of them Vasya h... | ```python
# -*- coding: utf-8 -*-
"""
Created on Wed Mar 18 21:37:04 2020
@author: DELL
"""
str=["ABSINTH", "BEER", "BRANDY","CHAMPAGNE","GIN","RUM","SAKE","TEQUILA","VODKA","WHISKEY","WINE"]
n=int(input())
l=[]
for i in range(n):
h=input()
l+=[h]
c=0
for i in l:
if i.isalpha():
if n... | 0 | MatrixStudio/Codeforces-Python-Submissions |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,647,438,022 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 186 | 8,396,800 | y, k, n = [int(item) for item in input().split(" ")]
m = []
sum = 0
while sum <= n:
if sum > y:
l = (sum - y)
m.append(l)
sum = sum + k
if m == []:
print(-1)
print(" ".join(map(str, m))) | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
y, k, n = [int(item) for item in input().split(" ")]
m = []
sum = 0
while sum <= n:
if sum > y:
l = (sum - y)
m.append(l)
sum = sum + k
if m == []:
print(-1)
print(" ".join(map(str, m)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,585,330,861 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 124 | 0 | def isVowel(c):
return c == 'a' or c == 'e' or c == 'i' or c == 'o' or c == 'u' or c == 'y'
n = int(input())
s = input()
new_s = ""
i = 0
while i < n:
c = s[i]
new_s += c
if (isVowel(c)):
while (i+1 < n and isVowel(s[i+1])):
i += 1
i += 1
print(new_s)
... | Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
def isVowel(c):
return c == 'a' or c == 'e' or c == 'i' or c == 'o' or c == 'u' or c == 'y'
n = int(input())
s = input()
new_s = ""
i = 0
while i < n:
c = s[i]
new_s += c
if (isVowel(c)):
while (i+1 < n and isVowel(s[i+1])):
i += 1
i += 1
print(new_s)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,622,542,375 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 342 | 307,200 | import sys
import math
import collections
import heapq
input=sys.stdin.readline
n,m=(int(i) for i in input().split())
d={}
for i in range(m):
a,b=(int(i) for i in input().split())
d[b]=a
d1=collections.OrderedDict(sorted(d.items(),reverse=True))
c=0
c1=0
for i in d1:
if(c1+d1[i]<=n):
... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
import sys
import math
import collections
import heapq
input=sys.stdin.readline
n,m=(int(i) for i in input().split())
d={}
for i in range(m):
a,b=(int(i) for i in input().split())
d[b]=a
d1=collections.OrderedDict(sorted(d.items(),reverse=True))
c=0
c1=0
for i in d1:
if(c1+d1[i]<=n):... | 0 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Есть *n*-подъездный дом, в каждом подъезде по *m* этажей, и на каждом этаже каждого подъезда ровно *k* квартир. Таким образом, в доме всего *n*·*m*·*k* квартир. Они пронумерованы естественным образом от 1 до *n*·*m*·*k*, то есть первая квартира на первом этаже в первом подъезде имеет номер 1, первая квартира на втором ... | В первой строке входных данных следуют три числа *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=1000) — количество подъездов в доме, количество этажей в каждом подъезде и количество квартир на каждом этаже каждого подъезда соответственно.
Во второй строке входных данных записаны два числа *a* и *b* (1<=≤<=*a*,<=*b*<=≤<=*n*·... | Выведите единственное целое число — минимальное время (в секундах), за которое Эдвард сможет добраться от своей квартиры до квартиры Наташи. | [
"4 10 5\n200 6\n",
"3 1 5\n7 2\n"
] | [
"39\n",
"15\n"
] | В первом тестовом примере Эдвард находится в 4 подъезде на 10 этаже, а Наташа находится в 1 подъезде на 2 этаже. Поэтому Эдварду выгодно сначала спуститься на лифте на первый этаж (на это он потратит 19 секунд, из которых 10 — на ожидание и 9 — на поездку на лифте), затем обойти дом против часовой стрелки до подъезда н... | 0 | [
{
"input": "4 10 5\n200 6",
"output": "39"
},
{
"input": "3 1 5\n7 2",
"output": "15"
},
{
"input": "100 100 100\n1 1000000",
"output": "124"
},
{
"input": "1000 1000 1000\n1 1000000000",
"output": "1024"
},
{
"input": "125 577 124\n7716799 6501425",
"output":... | 1,458,979,401 | 3,801 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 46 | 4,812,800 | x = list(map(int, input().split()))
a, b = map(int, input().split())
n = x[0]
m = x[1]
k = x[2]
l1 = 0
p1 = 0
l2 = 0
p2 = 0
t = 0
if a < m * k:
p1 = 1
else:
if a % (m * k) == 0:
p1 = a // (m * k)
else:
p1 = a // (m * k) + 1
if (a - (p1 - 1) * m * k) < k:
l1 = 1
else:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Есть *n*-подъездный дом, в каждом подъезде по *m* этажей, и на каждом этаже каждого подъезда ровно *k* квартир. Таким образом, в доме всего *n*·*m*·*k* квартир. Они пронумерованы естественным образом от 1 до *n*·*m*·*k*, то есть п... | ```python
x = list(map(int, input().split()))
a, b = map(int, input().split())
n = x[0]
m = x[1]
k = x[2]
l1 = 0
p1 = 0
l2 = 0
p2 = 0
t = 0
if a < m * k:
p1 = 1
else:
if a % (m * k) == 0:
p1 = a // (m * k)
else:
p1 = a // (m * k) + 1
if (a - (p1 - 1) * m * k) < k:
l1 = ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
259 | B | Little Elephant and Magic Square | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals ... | The first three lines of the input contain the Little Elephant's notes. The first line contains elements of the first row of the magic square. The second line contains the elements of the second row, the third line is for the third row. The main diagonal elements that have been forgotten by the Elephant are represented... | Print three lines, in each line print three integers — the Little Elephant's magic square. If there are multiple magic squares, you are allowed to print any of them. Note that all numbers you print must be positive and not exceed 105.
It is guaranteed that there exists at least one magic square that meets the conditio... | [
"0 1 1\n1 0 1\n1 1 0\n",
"0 3 6\n5 0 5\n4 7 0\n"
] | [
"1 1 1\n1 1 1\n1 1 1\n",
"6 3 6\n5 5 5\n4 7 4\n"
] | none | 1,000 | [
{
"input": "0 1 1\n1 0 1\n1 1 0",
"output": "1 1 1\n1 1 1\n1 1 1"
},
{
"input": "0 3 6\n5 0 5\n4 7 0",
"output": "6 3 6\n5 5 5\n4 7 4"
},
{
"input": "0 4 4\n4 0 4\n4 4 0",
"output": "4 4 4\n4 4 4\n4 4 4"
},
{
"input": "0 54 48\n36 0 78\n66 60 0",
"output": "69 54 48\n36 5... | 1,619,275,188 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 124 | 204,800 | x=[]
s=0
for i in range(3):
y=list(map(int,input().split()))
s+=sum(y)
x.append(y)
s=s//2
x[0][0]=s-sum(x[0])
x[1][1]=s-sum(x[1])
x[2][2]=s-sum(x[2])
for i in x:
for j in i:
print(j,end=" ")
print("")
| Title: Little Elephant and Magic Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table ... | ```python
x=[]
s=0
for i in range(3):
y=list(map(int,input().split()))
s+=sum(y)
x.append(y)
s=s//2
x[0][0]=s-sum(x[0])
x[1][1]=s-sum(x[1])
x[2][2]=s-sum(x[2])
for i in x:
for j in i:
print(j,end=" ")
print("")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,685,449,359 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 154 | 0 | mylist = list(map(int,input().split()))
from collections import Counter
count=Counter(mylist)
count=sorted(count.items(),key= lambda x:x[1],reverse=True)
q=0
for c in count:
if c[1]>1:
x = c[1]
while x > 1:
q+=1
x-=1
print(q) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
mylist = list(map(int,input().split()))
from collections import Counter
count=Counter(mylist)
count=sorted(count.items(),key= lambda x:x[1],reverse=True)
q=0
for c in count:
if c[1]>1:
x = c[1]
while x > 1:
q+=1
x-=1
print(q)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
215 | B | Olympic Medal | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | null | null | The World Programming Olympics Medal is a metal disk, consisting of two parts: the first part is a ring with outer radius of *r*1 cm, inner radius of *r*2 cm, (0<=<<=*r*2<=<<=*r*1) made of metal with density *p*1 g/cm3. The second part is an inner disk with radius *r*2 cm, it is made of metal with density *p*2 g/... | The first input line contains an integer *n* and a sequence of integers *x*1,<=*x*2,<=...,<=*x**n*. The second input line contains an integer *m* and a sequence of integers *y*1,<=*y*2,<=...,<=*y**m*. The third input line contains an integer *k* and a sequence of integers *z*1,<=*z*2,<=...,<=*z**k*. The last line conta... | Print a single real number — the sought value *r*2 with absolute or relative error of at most 10<=-<=6. It is guaranteed that the solution that meets the problem requirements exists. | [
"3 1 2 3\n1 2\n3 3 2 1\n1 2\n",
"4 2 3 6 4\n2 1 2\n3 10 6 8\n2 1\n"
] | [
"2.683281573000\n",
"2.267786838055\n"
] | In the first sample the jury should choose the following values: *r*<sub class="lower-index">1</sub> = 3, *p*<sub class="lower-index">1</sub> = 2, *p*<sub class="lower-index">2</sub> = 1. | 500 | [
{
"input": "3 1 2 3\n1 2\n3 3 2 1\n1 2",
"output": "2.683281573000"
},
{
"input": "4 2 3 6 4\n2 1 2\n3 10 6 8\n2 1",
"output": "2.267786838055"
},
{
"input": "1 5\n1 3\n1 7\n515 892",
"output": "3.263613058533"
},
{
"input": "2 3 2\n3 2 3 1\n2 2 1\n733 883",
"output": "2.... | 1,591,168,274 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 218 | 921,600 | def compare(original_ratio, new_ratio):
if original_ratio == new_ratio:
return True
return False
import math
def solve():
# posible r1
n, *x = list(map(int, input().split()))
# posible p1
m, *y = list(map(int, input().split()))
# possible p2
k, *z = list(map(in... | Title: Olympic Medal
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The World Programming Olympics Medal is a metal disk, consisting of two parts: the first part is a ring with outer radius of *r*1 cm, inner radius of *r*2 cm, (0<=<<=*r*2<=<<=*r*1) made of metal with density *p*1 g/... | ```python
def compare(original_ratio, new_ratio):
if original_ratio == new_ratio:
return True
return False
import math
def solve():
# posible r1
n, *x = list(map(int, input().split()))
# posible p1
m, *y = list(map(int, input().split()))
# possible p2
k, *z = l... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
144 | A | Arrival of the General | PROGRAMMING | 800 | [
"implementation"
] | null | null | A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their... | The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginnin... | Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like. | [
"4\n33 44 11 22\n",
"7\n10 10 58 31 63 40 76\n"
] | [
"2\n",
"10\n"
] | In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76)... | 500 | [
{
"input": "4\n33 44 11 22",
"output": "2"
},
{
"input": "7\n10 10 58 31 63 40 76",
"output": "10"
},
{
"input": "2\n88 89",
"output": "1"
},
{
"input": "5\n100 95 100 100 88",
"output": "0"
},
{
"input": "7\n48 48 48 48 45 45 45",
"output": "0"
},
{
"... | 1,684,901,352 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 92 | 0 |
n = int(input())
arr = list(map(int, input().split()))
min_val = arr[0]
max_val = arr[0]
index_min = 0
index_max = 0
for i in range(n):
if arr[i] > max_val:
max_val = arr[i]
index_max = i
if arr[i] <= min_val:
min_val = arr[i]
index_min = i
if index_max > ind... | Title: Arrival of the General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on t... | ```python
n = int(input())
arr = list(map(int, input().split()))
min_val = arr[0]
max_val = arr[0]
index_min = 0
index_max = 0
for i in range(n):
if arr[i] > max_val:
max_val = arr[i]
index_max = i
if arr[i] <= min_val:
min_val = arr[i]
index_min = i
if index... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
115 | B | Lawnmower | PROGRAMMING | 1,500 | [
"greedy",
"sortings"
] | null | null | You have a garden consisting entirely of grass and weeds. Your garden is described by an *n*<=×<=*m* grid, with rows numbered 1 to *n* from top to bottom, and columns 1 to *m* from left to right. Each cell is identified by a pair (*r*,<=*c*) which means that the cell is located at row *r* and column *c*. Each cell may ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=150) — the number of rows and columns respectively. Then follow *n* lines containing *m* characters each — the content of the grid. "G" means that this cell contains grass. "W" means that this cell contains weeds.
It is guaranteed that the top-left... | Print a single number — the minimum number of moves required to mow all the weeds. | [
"4 5\nGWGGW\nGGWGG\nGWGGG\nWGGGG\n",
"3 3\nGWW\nWWW\nWWG\n",
"1 1\nG\n"
] | [
"11\n",
"7\n",
"0\n"
] | For the first example, this is the picture of the initial state of the grid:
A possible solution is by mowing the weeds as illustrated below: | 1,000 | [
{
"input": "4 5\nGWGGW\nGGWGG\nGWGGG\nWGGGG",
"output": "11"
},
{
"input": "3 3\nGWW\nWWW\nWWG",
"output": "7"
},
{
"input": "1 1\nG",
"output": "0"
},
{
"input": "4 3\nGWW\nWWW\nWWW\nWWG",
"output": "11"
},
{
"input": "6 5\nGWWWW\nWWWWW\nWWWWW\nWWWWW\nWWWWW\nWWWW... | 1,665,652,138 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | import sys
input = sys.stdin.readline
n, m = map(int, input().split())
t = [(p.find('W'), p.rfind('W')) for p in [input()[:-1] for i in range(n)]]
print(t)
c, s, k = 0, n - 1, True
while s > 0 and t[s][0] == -1:
s -= 1
for a, b in t[: s + 1]:
if a != -1:
if k:
s += abs(a - c) ... | Title: Lawnmower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a garden consisting entirely of grass and weeds. Your garden is described by an *n*<=×<=*m* grid, with rows numbered 1 to *n* from top to bottom, and columns 1 to *m* from left to right. Each cell is identified by a ... | ```python
import sys
input = sys.stdin.readline
n, m = map(int, input().split())
t = [(p.find('W'), p.rfind('W')) for p in [input()[:-1] for i in range(n)]]
print(t)
c, s, k = 0, n - 1, True
while s > 0 and t[s][0] == -1:
s -= 1
for a, b in t[: s + 1]:
if a != -1:
if k:
s += a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
484 | A | Bits | PROGRAMMING | 1,700 | [
"bitmasks",
"constructive algorithms"
] | null | null | Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that *l*<=≤<=*x*<=≤<=*r*, and is maximum possible. If there are multiple such numbers find the... | The first line contains integer *n* — the number of queries (1<=≤<=*n*<=≤<=10000).
Each of the following *n* lines contain two integers *l**i*,<=*r**i* — the arguments for the corresponding query (0<=≤<=*l**i*<=≤<=*r**i*<=≤<=1018). | For each query print the answer in a separate line. | [
"3\n1 2\n2 4\n1 10\n"
] | [
"1\n3\n7\n"
] | The binary representations of numbers from 1 to 10 are listed below:
1<sub class="lower-index">10</sub> = 1<sub class="lower-index">2</sub>
2<sub class="lower-index">10</sub> = 10<sub class="lower-index">2</sub>
3<sub class="lower-index">10</sub> = 11<sub class="lower-index">2</sub>
4<sub class="lower-index">10</su... | 500 | [
{
"input": "3\n1 2\n2 4\n1 10",
"output": "1\n3\n7"
},
{
"input": "55\n1 1\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n2 2\n2 3\n2 4\n2 5\n2 6\n2 7\n2 8\n2 9\n2 10\n3 3\n3 4\n3 5\n3 6\n3 7\n3 8\n3 9\n3 10\n4 4\n4 5\n4 6\n4 7\n4 8\n4 9\n4 10\n5 5\n5 6\n5 7\n5 8\n5 9\n5 10\n6 6\n6 7\n6 8\n6 9\n6 10... | 1,602,809,347 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 327 | 9,318,400 | import os
import sys
from io import BytesIO, IOBase
import heapq as h
from bisect import bisect_left
from types import GeneratorType
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
import os
self.os = os
self._fd = file.fileno()
self... | Title: Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that ... | ```python
import os
import sys
from io import BytesIO, IOBase
import heapq as h
from bisect import bisect_left
from types import GeneratorType
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
import os
self.os = os
self._fd = file.fileno()
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
485 | A | Factory | PROGRAMMING | 1,400 | [
"implementation",
"math",
"matrices"
] | null | null | One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the factory has to produce (remainder after dividing *x* by *m*) more details. Unfortunately, no cu... | The first line contains two integers *a* and *m* (1<=≤<=*a*,<=*m*<=≤<=105). | Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No". | [
"1 5\n",
"3 6\n"
] | [
"No\n",
"Yes\n"
] | none | 1,000 | [
{
"input": "1 5",
"output": "No"
},
{
"input": "3 6",
"output": "Yes"
},
{
"input": "1 8",
"output": "Yes"
},
{
"input": "2 3",
"output": "No"
},
{
"input": "3 24",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "100000 ... | 1,587,556,280 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n,m = map(int,input().split())
x=[]
for i in range(m):
s=n%m
if s in x:
break
else:
x.append(s)
n=n+s
if n%m==0:
print("YES")
exit()
print("NO") | Title: Factory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the fac... | ```python
n,m = map(int,input().split())
x=[]
for i in range(m):
s=n%m
if s in x:
break
else:
x.append(s)
n=n+s
if n%m==0:
print("YES")
exit()
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
424 | A | Squats | PROGRAMMING | 900 | [
"implementation"
] | null | null | Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to stand up and the other hamsters to sit down. In one minute, Pasha can make some hamster ethe... | The first line contains integer *n* (2<=≤<=*n*<=≤<=200; *n* is even). The next line contains *n* characters without spaces. These characters describe the hamsters' position: the *i*-th character equals 'X', if the *i*-th hamster in the row is standing, and 'x', if he is sitting. | In the first line, print a single integer — the minimum required number of minutes. In the second line, print a string that describes the hamsters' position after Pasha makes the required changes. If there are multiple optimal positions, print any of them. | [
"4\nxxXx\n",
"2\nXX\n",
"6\nxXXxXx\n"
] | [
"1\nXxXx\n",
"1\nxX\n",
"0\nxXXxXx\n"
] | none | 500 | [
{
"input": "4\nxxXx",
"output": "1\nXxXx"
},
{
"input": "2\nXX",
"output": "1\nxX"
},
{
"input": "6\nxXXxXx",
"output": "0\nxXXxXx"
},
{
"input": "4\nxXXX",
"output": "1\nxxXX"
},
{
"input": "2\nXx",
"output": "0\nXx"
},
{
"input": "22\nXXxXXxxXxXxXXXX... | 1,398,905,842 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | n=int(input())
s=input()
print(abs((s.count('X')-s.count('x')))//2)
print('Xx'*(len(s)//2))
| Title: Squats
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to ... | ```python
n=int(input())
s=input()
print(abs((s.count('X')-s.count('x')))//2)
print('Xx'*(len(s)//2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
909 | B | Segments | PROGRAMMING | 1,300 | [
"constructive algorithms",
"math"
] | null | null | You are given an integer *N*. Consider all possible segments on the coordinate axis with endpoints at integer points with coordinates between 0 and *N*, inclusive; there will be of them.
You want to draw these segments in several layers so that in each layer the segments don't overlap (they might touch at the endpoin... | The only input line contains a single integer *N* (1<=≤<=*N*<=≤<=100). | Output a single integer - the minimal number of layers required to draw the segments for the given *N*. | [
"2\n",
"3\n",
"4\n"
] | [
"2\n",
"4\n",
"6\n"
] | As an example, here are the segments and their optimal arrangement into layers for *N* = 4. | 1,000 | [
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "4"
},
{
"input": "4",
"output": "6"
},
{
"input": "21",
"output": "121"
},
{
"input": "100",
"output": "2550"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "9"
... | 1,514,394,451 | 1,951 | Python 3 | OK | TESTS | 102 | 93 | 5,529,600 | n = int(input())
l = [0]*n
for i in range(n):
for j in range(n-i):
for k in range(j,j+i+1):l[k]+=1
print(max(l))
| Title: Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an integer *N*. Consider all possible segments on the coordinate axis with endpoints at integer points with coordinates between 0 and *N*, inclusive; there will be of them.
You want to draw these segments in se... | ```python
n = int(input())
l = [0]*n
for i in range(n):
for j in range(n-i):
for k in range(j,j+i+1):l[k]+=1
print(max(l))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
369 | A | Valera and Plates | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, he needs exactly one clean plate or bowl. We know that Valera can cook only two types of dishes. He can... | The first line of the input contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=1000) — the number of the planned days, the number of clean bowls and the number of clean plates.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2). If *a**i* equals one, then on day *i* Val... | Print a single integer — the minimum number of times Valera will need to wash a plate/bowl. | [
"3 1 1\n1 2 1\n",
"4 3 1\n1 1 1 1\n",
"3 1 2\n2 2 2\n",
"8 2 2\n1 2 1 2 1 2 1 2\n"
] | [
"1\n",
"1\n",
"0\n",
"4\n"
] | In the first sample Valera will wash a bowl only on the third day, so the answer is one.
In the second sample, Valera will have the first type of the dish during all four days, and since there are only three bowls, he will wash a bowl exactly once.
In the third sample, Valera will have the second type of dish for all... | 500 | [
{
"input": "3 1 1\n1 2 1",
"output": "1"
},
{
"input": "4 3 1\n1 1 1 1",
"output": "1"
},
{
"input": "3 1 2\n2 2 2",
"output": "0"
},
{
"input": "8 2 2\n1 2 1 2 1 2 1 2",
"output": "4"
},
{
"input": "2 100 100\n2 2",
"output": "0"
},
{
"input": "1 1 1\... | 1,385,739,237 | 237 | Python 3 | OK | TESTS | 63 | 62 | 0 | n,m,k=map(int,input().split())
L=list(map(int,input().split()))
ans=0
for item in L:
if(item==1):
if(m==0):
ans+=1
m+=1
m-=1
else:
if(k>0):
k-=1
continue
if(m>0):
m-=1
continue
ans+=1
print(ans)
| Title: Valera and Plates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, ... | ```python
n,m,k=map(int,input().split())
L=list(map(int,input().split()))
ans=0
for item in L:
if(item==1):
if(m==0):
ans+=1
m+=1
m-=1
else:
if(k>0):
k-=1
continue
if(m>0):
m-=1
continue
ans+=1
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,700,048,955 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 140 | 13,721,600 | '''
2300015897
吴杰稀
光华管理学院
'''
n = int(input())
num_list = list(map(int,input().split()))
dp = [0] * (max(num_list) + 2)
times = [0] * (max(num_list) + 2)
for _ in num_list:
times[_] += _
dp[1] = times[1]
for i in range(2,max(num_list) + 2):
dp[i] = max(dp[i - 1],dp[i - 2] + times[i])
print(dp[-1]) | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
'''
2300015897
吴杰稀
光华管理学院
'''
n = int(input())
num_list = list(map(int,input().split()))
dp = [0] * (max(num_list) + 2)
times = [0] * (max(num_list) + 2)
for _ in num_list:
times[_] += _
dp[1] = times[1]
for i in range(2,max(num_list) + 2):
dp[i] = max(dp[i - 1],dp[i - 2] + times[i])
pri... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
926 | B | Add Points | PROGRAMMING | 1,800 | [] | null | null | There are *n* points on a straight line, and the *i*-th point among them is located at *x**i*. All these coordinates are distinct.
Determine the number *m* — the smallest number of points you should add on the line to make the distances between all neighboring points equal. | The first line contains a single integer *n* (3<=≤<=*n*<=≤<=100<=000) — the number of points.
The second line contains a sequence of integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109) — the coordinates of the points. All these coordinates are distinct. The points can be given in an arbitrary order. | Print a single integer *m* — the smallest number of points you should add on the line to make the distances between all neighboring points equal. | [
"3\n-5 10 5\n",
"6\n100 200 400 300 600 500\n",
"4\n10 9 0 -1\n"
] | [
"1\n",
"0\n",
"8\n"
] | In the first example you can add one point with coordinate 0.
In the second example the distances between all neighboring points are already equal, so you shouldn't add anything. | 0 | [
{
"input": "3\n-5 10 5",
"output": "1"
},
{
"input": "6\n100 200 400 300 600 500",
"output": "0"
},
{
"input": "4\n10 9 0 -1",
"output": "8"
},
{
"input": "3\n1 4 7",
"output": "0"
},
{
"input": "3\n1 4 6",
"output": "3"
},
{
"input": "3\n1 2 6",
"... | 1,521,303,007 | 2,107 | Python 3 | WRONG_ANSWER | TESTS | 4 | 78 | 7,065,600 | def nod(n, m):
if(m==0):
return n;
if(n>m):
return nod(m,n-m);
else:
return nod(n,m-n);
n=input();
x = sorted(list(map(int, input().split())))
m = min(x)
nnod=0
for i in range(len(x)):
if(i>1):
if(i==2):
nnod=nod(x[i]-x[i-1], x[i-1]-x[i-1])
... | Title: Add Points
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* points on a straight line, and the *i*-th point among them is located at *x**i*. All these coordinates are distinct.
Determine the number *m* — the smallest number of points you should add on the line to make ... | ```python
def nod(n, m):
if(m==0):
return n;
if(n>m):
return nod(m,n-m);
else:
return nod(n,m-n);
n=input();
x = sorted(list(map(int, input().split())))
m = min(x)
nnod=0
for i in range(len(x)):
if(i>1):
if(i==2):
nnod=nod(x[i]-x[i-1], x[i-1]-x... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
120 | A | Elevator | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through the front door, he goes out through the back one and vice versa. The elevator has two rails n... | The first line indicates the door through which the very important person entered the elevator. It contains "front" if the person enters the elevator through the front door and "back" if he entered the elevator through the back door. The second line contains integer *a* (1<=≤<=*a*<=≤<=2) which denotes the number of the... | Print character "R" if the VIP is right-handed or "L" if he is left-handed. | [
"front\n1\n"
] | [
"L\n"
] | none | 0 | [
{
"input": "front\n1",
"output": "L"
},
{
"input": "back\n1",
"output": "R"
},
{
"input": "front\n2",
"output": "R"
},
{
"input": "back\n2",
"output": "L"
}
] | 1,558,283,806 | 2,147,483,647 | Python 3 | OK | TESTS | 4 | 218 | 0 | f = open('input.txt', 'r')
s = []
for line in f:
s.append(line)
f.close()
g = open('output.txt', 'w')
if s[0] == 'front\n' and s[1] == '1\n' or s[0] == 'back\n' and s[1] == '2\n':
g.write('L')
else:
g.write('R')
g.close()
| Title: Elevator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through... | ```python
f = open('input.txt', 'r')
s = []
for line in f:
s.append(line)
f.close()
g = open('output.txt', 'w')
if s[0] == 'front\n' and s[1] == '1\n' or s[0] == 'back\n' and s[1] == '2\n':
g.write('L')
else:
g.write('R')
g.close()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
7 | A | Kalevitch and Chess | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms"
] | A. Kalevitch and Chess | 2 | 64 | A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch decided to put an end to this tradition and to introduce a new attitude to chessboards.
As before, th... | The input file contains 8 lines, each of the lines contains 8 characters. The given matrix describes the client's requirements, W character stands for a white square, and B character — for a square painted black.
It is guaranteed that client's requirments can be fulfilled with a sequence of allowed strokes (vertical/c... | Output the only number — the minimum amount of rows and columns that Kalevitch has to paint on the white chessboard to meet the client's requirements. | [
"WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\n",
"WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\n"
] | [
"3\n",
"1\n"
] | none | 0 | [
{
"input": "WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW",
"output": "3"
},
{
"input": "WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW",
"output": "1"
},
{
"input": "WWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWW... | 1,582,988,975 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 307,200 | m=0
rows=[]
columns=[]
c1=''
c2=''
c3=''
c4=''
c5=''
c6=''
c7=''
c8=''
for i in range(8):
row=input()
rows.append(row)
c1=c1+row[0]
c2=c2+row[1]
c3=c3+row[2]
c4=c4+row[3]
c5=c5+row[4]
c6=c6+row[5]
c7=c7+row[6]
c8=c8+row[7]
columns=[c1,c2,c3,c4,c5,c6,c7,c8]
... | Title: Kalevitch and Chess
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch de... | ```python
m=0
rows=[]
columns=[]
c1=''
c2=''
c3=''
c4=''
c5=''
c6=''
c7=''
c8=''
for i in range(8):
row=input()
rows.append(row)
c1=c1+row[0]
c2=c2+row[1]
c3=c3+row[2]
c4=c4+row[3]
c5=c5+row[4]
c6=c6+row[5]
c7=c7+row[6]
c8=c8+row[7]
columns=[c1,c2,c3,c4,c5,c... | 0 | MatrixStudio/Codeforces-Python-Submissions |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,660,651,322 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 93 | 3,788,800 | n,t=map(int,input().split())
a=list(map(int,input().split()))
i=0
arr=[]
pos=0
while i<len(a):
arr.append(i+1)
i+=a[i]
arr.append(i+1)
if t in arr:
print("YES")
else:
print("NO") | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
n,t=map(int,input().split())
a=list(map(int,input().split()))
i=0
arr=[]
pos=0
while i<len(a):
arr.append(i+1)
i+=a[i]
arr.append(i+1)
if t in arr:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
75 | B | Facetook Priority Wall | PROGRAMMING | 1,500 | [
"expression parsing",
"implementation",
"strings"
] | B. Facetook Priority Wall | 2 | 256 | Facetook is a well known social network website, and it will launch a new feature called Facetook Priority Wall. This feature will sort all posts from your friends according to the priority factor (it will be described).
This priority factor will be affected by three types of actions:
- 1. "*X* posted on *Y*'s wall... | The first line contains your name. The second line contains an integer *n*, which is the number of actions (1<=≤<=*n*<=≤<=100). Then *n* lines follow, it is guaranteed that each one contains exactly 1 action in the format given above. There is exactly one space between each two words in a line, and there are no extra s... | Print *m* lines, where *m* is the number of distinct names in the input (excluding yourself). Each line should contain just 1 name. The names should be sorted according to the priority factor with you in the descending order (the highest priority factor should come first). If two or more names have the same priority fa... | [
"ahmed\n3\nahmed posted on fatma's wall\nfatma commented on ahmed's post\nmona likes ahmed's post\n",
"aba\n1\nlikes likes posted's post\n"
] | [
"fatma\nmona\n",
"likes\nposted\n"
] | none | 1,000 | [
{
"input": "ahmed\n3\nahmed posted on fatma's wall\nfatma commented on ahmed's post\nmona likes ahmed's post",
"output": "fatma\nmona"
},
{
"input": "aba\n1\nlikes likes posted's post",
"output": "likes\nposted"
},
{
"input": "nu\n5\ng commented on pwyndmh's post\nqv posted on g's wall\n... | 1,653,098,671 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 216 | 8,192,000 | from pickle import TRUE
me=input()
n=int(input())
d=dict()
for _ in range(n):
s=input().split(' ')
x, y=s[0], s[-2].split('\'')[0]
if x not in d: d[x]=0
if y not in d: d[y]=0
if s[1]=='posted':
d[x]+=15
d[y]+=15
elif s[1]=='commented':
d[x]+=10
d... | Title: Facetook Priority Wall
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Facetook is a well known social network website, and it will launch a new feature called Facetook Priority Wall. This feature will sort all posts from your friends according to the priority factor (it will be describ... | ```python
from pickle import TRUE
me=input()
n=int(input())
d=dict()
for _ in range(n):
s=input().split(' ')
x, y=s[0], s[-2].split('\'')[0]
if x not in d: d[x]=0
if y not in d: d[y]=0
if s[1]=='posted':
d[x]+=15
d[y]+=15
elif s[1]=='commented':
d[x]+=10
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
44 | C | Holidays | PROGRAMMING | 1,300 | [
"implementation"
] | C. Holidays | 2 | 256 | School holidays come in Berland. The holidays are going to continue for *n* days. The students of school №*N* are having the time of their lives and the IT teacher Marina Sergeyevna, who has spent all the summer busy checking the BSE (Berland State Examination) results, has finally taken a vacation break! Some people a... | The first input line contains two numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of days in Berland holidays and the number of people in charge of the watering respectively. The next *m* lines contain the description of the duty schedule. Each line contains two integers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=*... | Print "OK" (without quotes), if the schedule does not contain mistakes. Otherwise you have to find the minimal number of a day when the flowers will not be watered or will be watered multiple times, and output two integers — the day number and the number of times the flowers will be watered that day. | [
"10 5\n1 2\n3 3\n4 6\n7 7\n8 10\n",
"10 5\n1 2\n2 3\n4 5\n7 8\n9 10\n",
"10 5\n1 2\n3 3\n5 7\n7 7\n7 10\n"
] | [
"OK\n",
"2 2\n",
"4 0\n"
] | Keep in mind that in the second sample the mistake occurs not only on the second day, but also on the sixth day, when nobody waters the flowers. However, you have to print the second day, i.e. the day with the minimal number. | 0 | [
{
"input": "10 5\n1 2\n3 3\n4 6\n7 7\n8 10",
"output": "OK"
},
{
"input": "10 5\n1 2\n2 3\n4 5\n7 8\n9 10",
"output": "2 2"
},
{
"input": "10 5\n1 2\n3 3\n5 7\n7 7\n7 10",
"output": "4 0"
},
{
"input": "5 4\n1 1\n2 2\n3 3\n4 5",
"output": "OK"
},
{
"input": "100 5... | 1,400,760,668 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 33 | 124 | 0 | n, m = map(int, input().split())
hols = []
for i in range(m):
hols.append(list(map(int, input().split())))
days = []
for (a, b) in hols:
days.append(list(range(a, b+1)))
days = sum(days, [])
res = []
for x in days:
if days.count(x) > 1:
res.append(x)
break
for i in r... | Title: Holidays
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
School holidays come in Berland. The holidays are going to continue for *n* days. The students of school №*N* are having the time of their lives and the IT teacher Marina Sergeyevna, who has spent all the summer busy checking the ... | ```python
n, m = map(int, input().split())
hols = []
for i in range(m):
hols.append(list(map(int, input().split())))
days = []
for (a, b) in hols:
days.append(list(range(a, b+1)))
days = sum(days, [])
res = []
for x in days:
if days.count(x) > 1:
res.append(x)
break
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
401 | A | Vanya and Cards | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time p... | The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their a... | Print a single number — the answer to the problem. | [
"3 2\n-1 1 2\n",
"2 3\n-2 -2\n"
] | [
"1\n",
"2\n"
] | In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | 500 | [
{
"input": "3 2\n-1 1 2",
"output": "1"
},
{
"input": "2 3\n-2 -2",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
},
{
"input": "2 2\n-1 -1",
"output": "1"
},
{
"input": "15 5\n-2 -1 2 -4 -3 4 -4 -2 -2 2 -2 -1 1 -4 -2",
"output": "4"
},
{
"... | 1,583,409,215 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 124 | 307,200 | import math
a, b = map(int, input().split())
c = list(map(int, input().split()))
print(math.ceil(abs(sum(c)/b))) | Title: Vanya and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each... | ```python
import math
a, b = map(int, input().split())
c = list(map(int, input().split()))
print(math.ceil(abs(sum(c)/b)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
306 | D | Polygon | PROGRAMMING | 2,300 | [
"constructive algorithms",
"geometry"
] | null | null | Polycarpus loves convex polygons, especially if all their angles are the same and all their sides are different. Draw for him any such polygon with the given number of vertexes. | The input contains a single integer *n* (3<=≤<=*n*<=≤<=100) — the number of the polygon vertexes. | Print *n* lines, containing the coordinates of the vertexes of the *n*-gon "*x**i* *y**i*" in the counter clockwise order. The coordinates of the vertexes shouldn't exceed 106 in their absolute value. The side lengths should fit within limits [1,<=1000] (not necessarily integer). Mutual comparing sides and angles of yo... | [
"8\n"
] | [
"1.000 0.000\n7.000 0.000\n9.000 2.000\n9.000 3.000\n5.000 7.000\n3.000 7.000\n0.000 4.000\n0.000 1.000\n"
] | none | 2,000 | [] | 1,689,431,910 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1689431910.878837")# 1689431910.8788562 | Title: Polygon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus loves convex polygons, especially if all their angles are the same and all their sides are different. Draw for him any such polygon with the given number of vertexes.
Input Specification:
The input contains a single... | ```python
print("_RANDOM_GUESS_1689431910.878837")# 1689431910.8788562
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,582,439,854 | 2,147,483,647 | PyPy 3 | OK | TESTS | 63 | 156 | 0 | #910A
n, d = map(int, input().split())
s = input()
if '0'*d in s:
print(-1)
else:
jump = 0
i = 0
while i < n-1:
if s[i] == "1":
i += d
jump += 1
else:
i -= 1
print(jump)
| Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
#910A
n, d = map(int, input().split())
s = input()
if '0'*d in s:
print(-1)
else:
jump = 0
i = 0
while i < n-1:
if s[i] == "1":
i += d
jump += 1
else:
i -= 1
print(jump)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
234 | B | Reading | PROGRAMMING | 1,000 | [
"sortings"
] | null | null | Vasya is going to the Olympics in the city Ntown by train. The boy wants to read the textbook to prepare for the Olympics. He counted that he needed *k* hours for this. He also found that the light in the train changes every hour. The light is measured on a scale from 0 to 100, where 0 is very dark, and 100 is very lig... | The first input line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*k*<=≤<=*n*) — the number of hours on the train and the number of hours to read, correspondingly. The second line contains *n* space-separated integers *a**i* (0<=≤<=*a**i*<=≤<=100), *a**i* is the light level at the *i*-th hour. | In the first output line print the minimum light level Vasya will read at. In the second line print *k* distinct space-separated integers *b*1,<=*b*2,<=...,<=*b**k*, — the indexes of hours Vasya will read at (1<=≤<=*b**i*<=≤<=*n*). The hours are indexed starting from 1. If there are multiple optimal solutions, print an... | [
"5 3\n20 10 30 40 10\n",
"6 5\n90 20 35 40 60 100\n"
] | [
"20\n1 3 4 \n",
"35\n1 3 4 5 6 \n"
] | In the first sample Vasya should read at the first hour (light 20), third hour (light 30) and at the fourth hour (light 40). The minimum light Vasya will have to read at is 20. | 0 | [
{
"input": "5 3\n20 10 30 40 10",
"output": "20\n1 3 4 "
},
{
"input": "6 5\n90 20 35 40 60 100",
"output": "35\n1 3 4 5 6 "
},
{
"input": "100 7\n85 66 9 91 50 46 61 12 55 65 95 1 25 97 95 4 59 59 52 34 94 30 60 11 68 36 17 84 87 68 72 87 46 99 24 66 75 77 75 2 19 3 33 19 7 20 22 3 71 2... | 1,620,469,759 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 6,963,200 | with open("input.txt", "r") as g:
n, k = map(int, g.readline().split())
lights = list(map(int, g.readline().split()))
for i, l in enumerate(lights):
lights[i] = [l, i]
lights.sort()
with open("output.txt", "w") as h:
h.write(str(lights[n - k][0]) + "\n")
for i in range(n - k, n):
h.write(str... | Title: Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is going to the Olympics in the city Ntown by train. The boy wants to read the textbook to prepare for the Olympics. He counted that he needed *k* hours for this. He also found that the light in the train changes every ho... | ```python
with open("input.txt", "r") as g:
n, k = map(int, g.readline().split())
lights = list(map(int, g.readline().split()))
for i, l in enumerate(lights):
lights[i] = [l, i]
lights.sort()
with open("output.txt", "w") as h:
h.write(str(lights[n - k][0]) + "\n")
for i in range(n - k, n):
h... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
469 | A | I Wanna Be the Guy | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the game. And Little Y can pass only *q* levels of the game. You are given the indices of levels Little X can... | The first line contains a single integer *n* (1<=≤<=<=*n*<=≤<=100).
The next line contains an integer *p* (0<=≤<=*p*<=≤<=*n*) at first, then follows *p* distinct integers *a*1,<=*a*2,<=...,<=*a**p* (1<=≤<=*a**i*<=≤<=*n*). These integers denote the indices of levels Little X can pass. The next line contains the levels... | If they can pass all the levels, print "I become the guy.". If it's impossible, print "Oh, my keyboard!" (without the quotes). | [
"4\n3 1 2 3\n2 2 4\n",
"4\n3 1 2 3\n2 2 3\n"
] | [
"I become the guy.\n",
"Oh, my keyboard!\n"
] | In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.
In the second sample, no one can pass level 4. | 500 | [
{
"input": "4\n3 1 2 3\n2 2 4",
"output": "I become the guy."
},
{
"input": "4\n3 1 2 3\n2 2 3",
"output": "Oh, my keyboard!"
},
{
"input": "10\n5 8 6 1 5 4\n6 1 3 2 9 4 6",
"output": "Oh, my keyboard!"
},
{
"input": "10\n8 8 10 7 3 1 4 2 6\n8 9 5 10 3 7 2 4 8",
"output":... | 1,698,528,449 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 31 | 0 | n=int(input())
l1=[int(x) for x in input().split()]
l2=[int(x) for x in input().split()]
flag=''
for i in range(1,n+1):
if i in l1[1:] or i in l2[1:]:
flag='True'
else:
flag='False'
if flag=='True':
print('I become the guy.')
else:
print('Oh, my keyboard!') | Title: I Wanna Be the Guy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a game called "I Wanna Be the Guy", consisting of *n* levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game.
Little X can pass only *p* levels of the g... | ```python
n=int(input())
l1=[int(x) for x in input().split()]
l2=[int(x) for x in input().split()]
flag=''
for i in range(1,n+1):
if i in l1[1:] or i in l2[1:]:
flag='True'
else:
flag='False'
if flag=='True':
print('I become the guy.')
else:
print('Oh, my keyboard!')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,691,657,363 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | t = int(input())
c1 = 0
c2=0
for _ in range(t):
a, b = map(int, input().split())
c1 = c1 + b
c2 = c1 - a
print(c2) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
t = int(input())
c1 = 0
c2=0
for _ in range(t):
a, b = map(int, input().split())
c1 = c1 + b
c2 = c1 - a
print(c2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
864 | B | Polycarp and Letters | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if following conditions are met:
- letters on positions from *A* in the string are all distinct and lowerc... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=200) — length of string *s*.
The second line contains a string *s* consisting of lowercase and uppercase Latin letters. | Print maximum number of elements in pretty set of positions for string *s*. | [
"11\naaaaBaabAbA\n",
"12\nzACaAbbaazzC\n",
"3\nABC\n"
] | [
"2\n",
"3\n",
"0\n"
] | In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6 and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1 and 8 is not suitable because there is an uppercase letter 'B' between these position.
In the second example desired positions can be 7, 8 and 11. There... | 1,000 | [
{
"input": "11\naaaaBaabAbA",
"output": "2"
},
{
"input": "12\nzACaAbbaazzC",
"output": "3"
},
{
"input": "3\nABC",
"output": "0"
},
{
"input": "1\na",
"output": "1"
},
{
"input": "2\naz",
"output": "2"
},
{
"input": "200\nXbTJZqcbpYuZQEoUrbxlPXAPCtVLr... | 1,607,768,922 | 2,147,483,647 | PyPy 3 | OK | TESTS | 55 | 218 | 2,150,400 | import re
input()
print(max(map(lambda w: len(set(w)), re.split('[A-Z]', input())))) | Title: Polycarp and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if... | ```python
import re
input()
print(max(map(lambda w: len(set(w)), re.split('[A-Z]', input()))))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Vasya the programmer lives in the middle of the Programming subway branch. He has two girlfriends: Dasha and Masha, who live at the different ends of the branch, each one is unaware of the other one's existence.
When Vasya has some free time, he goes to one of his girlfriends. He descends into the subway at some time,... | The first line contains two integers *a* and *b* (*a*<=≠<=*b*,<=1<=≤<=*a*,<=*b*<=≤<=106). | Print "Dasha" if Vasya will go to Dasha more frequently, "Masha" if he will go to Masha more frequently, or "Equal" if he will go to both girlfriends with the same frequency. | [
"3 7\n",
"5 3\n",
"2 3\n"
] | [
"Dasha\n",
"Masha\n",
"Equal\n"
] | Let's take a look at the third sample. Let the trains start to go at the zero moment of time. It is clear that the moments of the trains' arrival will be periodic with period 6. That's why it is enough to show that if Vasya descends to the subway at a moment of time inside the interval (0, 6], he will go to both girls ... | 0 | [
{
"input": "3 7",
"output": "Dasha"
},
{
"input": "5 3",
"output": "Masha"
},
{
"input": "2 3",
"output": "Equal"
},
{
"input": "31 88",
"output": "Dasha"
},
{
"input": "8 75",
"output": "Dasha"
},
{
"input": "32 99",
"output": "Dasha"
},
{
... | 1,646,567,946 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 41 | 2,000 | 92,057,600 | a,b=map(int,input().split())
q,w=0,0
import math
t=1
if a>b:
a,b=b,a
t=0
l=(a*b)//math.gcd(a,b)
p={l}
k=a
y=b
while a<=l:
p.add(a)
a+=k
while b<=l:
p.add(b)
b+=y
p=[0]+sorted(p)
for i in range(1,len(p)):
if p[i]%y==0:w+=p[i]-p[i-1]
else:q+=p[i]-p[i-1]
if t==0:q,w=w,q... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya the programmer lives in the middle of the Programming subway branch. He has two girlfriends: Dasha and Masha, who live at the different ends of the branch, each one is unaware of the other one's existence.
When Vasya has so... | ```python
a,b=map(int,input().split())
q,w=0,0
import math
t=1
if a>b:
a,b=b,a
t=0
l=(a*b)//math.gcd(a,b)
p={l}
k=a
y=b
while a<=l:
p.add(a)
a+=k
while b<=l:
p.add(b)
b+=y
p=[0]+sorted(p)
for i in range(1,len(p)):
if p[i]%y==0:w+=p[i]-p[i-1]
else:q+=p[i]-p[i-1]
if t=... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,677,353,606 | 2,147,483,647 | Python 3 | OK | TESTS | 8 | 31 | 0 | for i in range(int(input())):
a = int(input())
if a <=11:
if a % 3 == 0 or a % 7 == 0 or a % 10 == 0:
print("YES")
else:
print("NO")
else:
print("YES")
| Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chun... | ```python
for i in range(int(input())):
a = int(input())
if a <=11:
if a % 3 == 0 or a % 7 == 0 or a % 10 == 0:
print("YES")
else:
print("NO")
else:
print("YES")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
251 | A | Points on Line | PROGRAMMING | 1,300 | [
"binary search",
"combinatorics",
"two pointers"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen... | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input stri... | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 500 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,678,636,978 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 1,310 | 8,089,600 | def p(a,b):
o=-1
l,h=0,len(a)-1
while l<=h:
mid=l+(h-l)//2
if a[mid]<=b:
o=mid
l=mid+1
else:
h=mid-1
return o
a,b=map(int,input().split())
c=list(map(int,input().split()))
def sum(n):
n-=1
if n%2==0:
return n//2*... | Title: Points on Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two fart... | ```python
def p(a,b):
o=-1
l,h=0,len(a)-1
while l<=h:
mid=l+(h-l)//2
if a[mid]<=b:
o=mid
l=mid+1
else:
h=mid-1
return o
a,b=map(int,input().split())
c=list(map(int,input().split()))
def sum(n):
n-=1
if n%2==0:
re... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
143 | B | Help Kingdom of Far Far Away 2 | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as time went by, the economy of the Far Far Away developed and the scale of operatio... | The input contains a number that needs to be converted into financial format. The number's notation length does not exceed 100 characters, including (possible) signs "-" (minus) and "." (decimal point). The number's notation is correct, that is:
- The number's notation only contains characters from the set {"0" – "9... | Print the number given in the input in the financial format by the rules described in the problem statement. | [
"2012\n",
"0.000\n",
"-0.00987654321\n",
"-12345678.9\n"
] | [
"$2,012.00",
"$0.00",
"($0.00)",
"($12,345,678.90)"
] | Pay attention to the second and third sample tests. They show that the sign of a number in the financial format (and consequently, the presence or absence of brackets) is determined solely by the sign of the initial number. It does not depend on the sign of the number you got after translating the number to the financi... | 1,000 | [
{
"input": "2012",
"output": "$2,012.00"
},
{
"input": "0.000",
"output": "$0.00"
},
{
"input": "-0.00987654321",
"output": "($0.00)"
},
{
"input": "-12345678.9",
"output": "($12,345,678.90)"
},
{
"input": "0.99999999999999999999",
"output": "$0.99"
},
{
... | 1,660,823,556 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 124 | 2,867,200 | import collections
import heapq
import sys
import math
import itertools
import bisect
from io import BytesIO, IOBase
import os
# sys.setrecursionlimit(10000)
def values(): return tuple(map(int, sys.stdin.readline().split()))
def inlst(): return [int(i) for i in sys.stdin.readline().split()]
def inp(): re... | Title: Help Kingdom of Far Far Away 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more e... | ```python
import collections
import heapq
import sys
import math
import itertools
import bisect
from io import BytesIO, IOBase
import os
# sys.setrecursionlimit(10000)
def values(): return tuple(map(int, sys.stdin.readline().split()))
def inlst(): return [int(i) for i in sys.stdin.readline().split()]
def... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
498 | A | Crazy Town | PROGRAMMING | 1,700 | [
"geometry"
] | null | null | Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the plane into connected regions, possibly of infinite space. Let's call each such region a block. We ... | The first line contains two space-separated integers *x*1, *y*1 (<=-<=106<=≤<=*x*1,<=*y*1<=≤<=106) — the coordinates of your home.
The second line contains two integers separated by a space *x*2, *y*2 (<=-<=106<=≤<=*x*2,<=*y*2<=≤<=106) — the coordinates of the university you are studying at.
The third line contains a... | Output the answer to the problem. | [
"1 1\n-1 -1\n2\n0 1 0\n1 0 0\n",
"1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3\n"
] | [
"2\n",
"2\n"
] | Pictures to the samples are presented below (A is the point representing the house; B is the point representing the university, different blocks are filled with different colors): | 500 | [
{
"input": "1 1\n-1 -1\n2\n0 1 0\n1 0 0",
"output": "2"
},
{
"input": "1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3",
"output": "2"
},
{
"input": "841746 527518\n595261 331297\n10\n-946901 129987 670374\n-140388 -684770 309555\n-302589 415564 -387435\n-565799 -72069 -395358\n-523453 -511446 85489... | 1,458,852,802 | 2,147,483,647 | PyPy 3 | OK | TESTS | 51 | 155 | 23,142,400 | #!/usr/bin/env python3
import collections, itertools, functools, math
def value(a, b, c, x, y):
return a*x + b*y + c
def sign(x):
if x < 0:
return -1
if x == 0:
return 0
if x > 0:
return 1
def solve():
x1, y1 = map(int, input().split())
x2, y2 = map(int, input().split(... | Title: Crazy Town
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the pl... | ```python
#!/usr/bin/env python3
import collections, itertools, functools, math
def value(a, b, c, x, y):
return a*x + b*y + c
def sign(x):
if x < 0:
return -1
if x == 0:
return 0
if x > 0:
return 1
def solve():
x1, y1 = map(int, input().split())
x2, y2 = map(int, inpu... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
348 | A | Mafia | PROGRAMMING | 1,600 | [
"binary search",
"math",
"sortings"
] | null | null | One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the *i*-th person wants to play *a**i* rounds. What is the min... | The first line contains integer *n* (3<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the *i*-th number in the list is the number of rounds the *i*-th person wants to play. | In a single line print a single integer — the minimum number of game rounds the friends need to let the *i*-th person play at least *a**i* rounds.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3\n3 2 2\n",
"4\n2 2 2 2\n"
] | [
"4\n",
"3\n"
] | You don't need to know the rules of "Mafia" to solve this problem. If you're curious, it's a game Russia got from the Soviet times: http://en.wikipedia.org/wiki/Mafia_(party_game). | 500 | [
{
"input": "3\n3 2 2",
"output": "4"
},
{
"input": "4\n2 2 2 2",
"output": "3"
},
{
"input": "7\n9 7 7 8 8 7 8",
"output": "9"
},
{
"input": "10\n13 12 10 13 13 14 10 10 12 12",
"output": "14"
},
{
"input": "10\n94 96 91 95 99 94 96 92 95 99",
"output": "106"
... | 1,564,065,608 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 154 | 0 | import math
n=int(input())
a=list(map(int,input().split()))
m=sum(a)
r=math.ceil(m/(n-1))
r=int(r)
print(max(a),r)
| Title: Mafia
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a... | ```python
import math
n=int(input())
a=list(map(int,input().split()))
m=sum(a)
r=math.ceil(m/(n-1))
r=int(r)
print(max(a),r)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at ... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepa... | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,613,122,651 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 77 | 307,200 | try:
a,b=map(int,input().split())
l=[]
for i in range(a):
k=input()
l.append(k)
f=[]
for i in range(b):
g=[]
for j in range(a):
g.append(l[j][i])
f.append(g)
final=[]
for i in range(b):
... | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student ... | ```python
try:
a,b=map(int,input().split())
l=[]
for i in range(a):
k=input()
l.append(k)
f=[]
for i in range(b):
g=[]
for j in range(a):
g.append(l[j][i])
f.append(g)
final=[]
for i in range(b... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
552 | D | Vanya and Triangles | PROGRAMMING | 1,900 | [
"brute force",
"combinatorics",
"data structures",
"geometry",
"math",
"sortings"
] | null | null | Vanya got bored and he painted *n* distinct points on the plane. After that he connected all the points pairwise and saw that as a result many triangles were formed with vertices in the painted points. He asks you to count the number of the formed triangles with the non-zero area. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of the points painted on the plane.
Next *n* lines contain two integers each *x**i*,<=*y**i* (<=-<=100<=≤<=*x**i*,<=*y**i*<=≤<=100) — the coordinates of the *i*-th point. It is guaranteed that no two given points coincide. | In the first line print an integer — the number of triangles with the non-zero area among the painted points. | [
"4\n0 0\n1 1\n2 0\n2 2\n",
"3\n0 0\n1 1\n2 0\n",
"1\n1 1\n"
] | [
"3\n",
"1\n",
"0\n"
] | Note to the first sample test. There are 3 triangles formed: (0, 0) - (1, 1) - (2, 0); (0, 0) - (2, 2) - (2, 0); (1, 1) - (2, 2) - (2, 0).
Note to the second sample test. There is 1 triangle formed: (0, 0) - (1, 1) - (2, 0).
Note to the third sample test. A single point doesn't form a single triangle. | 2,000 | [
{
"input": "4\n0 0\n1 1\n2 0\n2 2",
"output": "3"
},
{
"input": "3\n0 0\n1 1\n2 0",
"output": "1"
},
{
"input": "1\n1 1",
"output": "0"
},
{
"input": "5\n0 0\n1 1\n2 2\n3 3\n4 4",
"output": "0"
},
{
"input": "5\n0 0\n1 1\n2 3\n3 6\n4 10",
"output": "10"
},
... | 1,579,463,790 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 307,200 | def main():
n = map(int, input().split())
total = 0
x = []
y = []
lines = {}
for i in range(n):
x[i], y[i] = map(int, input().split())
for j in range(n - 2):
for k in range(n - 1):
for m in range(n):
test = x[j] * (y[k] - y[m]) + x... | Title: Vanya and Triangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got bored and he painted *n* distinct points on the plane. After that he connected all the points pairwise and saw that as a result many triangles were formed with vertices in the painted points. He asks you t... | ```python
def main():
n = map(int, input().split())
total = 0
x = []
y = []
lines = {}
for i in range(n):
x[i], y[i] = map(int, input().split())
for j in range(n - 2):
for k in range(n - 1):
for m in range(n):
test = x[j] * (y[k] -... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,693,655,311 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | x = str(input())
z = str(input())
v=0
c=0
for i in range(len(x)):
c += ord(x[i])
v += ord(z[-i])
if c==v:
print('YES')
else:
print('NO') | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
x = str(input())
z = str(input())
v=0
c=0
for i in range(len(x)):
c += ord(x[i])
v += ord(z[-i])
if c==v:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,636,870,280 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 4,505,600 | s = input()
a = len(s)
vow = ('a', 'e', 'i', 'o', 'u')
for i in range(0,a-1) :
if s[i] not in vow :
if s[i+1] in vow :
result = "YES"
else :
result = "NO"
print(result) | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
s = input()
a = len(s)
vow = ('a', 'e', 'i', 'o', 'u')
for i in range(0,a-1) :
if s[i] not in vow :
if s[i+1] in vow :
result = "YES"
else :
result = "NO"
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
3 | C | Tic-tac-toe | PROGRAMMING | 1,800 | [
"brute force",
"games",
"implementation"
] | C. Tic-tac-toe | 1 | 64 | Certainly, everyone is familiar with tic-tac-toe game. The rules are very simple indeed. Two players take turns marking the cells in a 3<=×<=3 grid (one player always draws crosses, the other — noughts). The player who succeeds first in placing three of his marks in a horizontal, vertical or diagonal line wins, and the... | The input consists of three lines, each of the lines contains characters ".", "X" or "0" (a period, a capital letter X, or a digit zero). | Print one of the six verdicts: first, second, illegal, the first player won, the second player won or draw. | [
"X0X\n.0.\n.X.\n"
] | [
"second\n"
] | none | 0 | [
{
"input": "X0X\n.0.\n.X.",
"output": "second"
},
{
"input": "0.X\nXX.\n000",
"output": "illegal"
},
{
"input": "XXX\n.0.\n000",
"output": "illegal"
},
{
"input": "XXX\n...\n000",
"output": "illegal"
},
{
"input": "X.X\nX..\n00.",
"output": "second"
},
{
... | 1,684,795,575 | 2,147,483,647 | Python 3 | OK | TESTS | 175 | 92 | 102,400 | def winState(w, matrix):
if matrix[0][0] == w and matrix[0][1] == w and matrix[0][2] == w:
return True
if matrix[1][0] == w and matrix[1][1] == w and matrix[1][2] == w:
return True
if matrix[2][0] == w and matrix[2][1] == w and matrix[2][2] == w:
return True
if matrix[0][0... | Title: Tic-tac-toe
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Certainly, everyone is familiar with tic-tac-toe game. The rules are very simple indeed. Two players take turns marking the cells in a 3<=×<=3 grid (one player always draws crosses, the other — noughts). The player who succeeds ... | ```python
def winState(w, matrix):
if matrix[0][0] == w and matrix[0][1] == w and matrix[0][2] == w:
return True
if matrix[1][0] == w and matrix[1][1] == w and matrix[1][2] == w:
return True
if matrix[2][0] == w and matrix[2][1] == w and matrix[2][2] == w:
return True
if m... | 3.953237 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Sasha has an array of integers *a*1,<=*a*2,<=...,<=*a**n*. You have to perform *m* queries. There might be queries of two types:
1. 1 l r x — increase all integers on the segment from *l* to *r* by values *x*; 1. 2 l r — find , where *f*(*x*) is the *x*-th Fibonacci number. As this number may be large, you only have... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — the number of elements in the array and the number of queries respectively.
The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Then follow *m* lines with queries descrip... | For each query of the second type print the answer modulo 109<=+<=7. | [
"5 4\n1 1 2 1 1\n2 1 5\n1 2 4 2\n2 2 4\n2 1 5\n"
] | [
"5\n7\n9\n"
] | Initially, array *a* is equal to 1, 1, 2, 1, 1.
The answer for the first query of the second type is *f*(1) + *f*(1) + *f*(2) + *f*(1) + *f*(1) = 1 + 1 + 1 + 1 + 1 = 5.
After the query 1 2 4 2 array *a* is equal to 1, 3, 4, 3, 1.
The answer for the second query of the second type is *f*(3) + *f*(4) + *f*(3) = 2 + 3... | 0 | [
{
"input": "5 4\n1 1 2 1 1\n2 1 5\n1 2 4 2\n2 2 4\n2 1 5",
"output": "5\n7\n9"
},
{
"input": "2 3\n1 3\n2 1 1\n1 1 2 3\n1 1 2 2",
"output": "1"
},
{
"input": "7 4\n2 2 1 1 3 3 2\n2 1 5\n2 6 7\n1 3 4 3\n2 6 6",
"output": "6\n3\n2"
},
{
"input": "9 4\n2 1 2 3 3 3 2 1 3\n2 1 8\n... | 1,585,407,767 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 109 | 716,800 | def fib(num, x = 0, y = 1):
if num == 1:
return y
else:
return fib(num - 1, y, x + y)
n, m = [int(num) for num in input().split()]
a = [int(elem) for elem in input().split()]
out = []
for rep in range(m):
summ = 0
zapros = [int(i) for i in input().split()]
if len(zapr... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sasha has an array of integers *a*1,<=*a*2,<=...,<=*a**n*. You have to perform *m* queries. There might be queries of two types:
1. 1 l r x — increase all integers on the segment from *l* to *r* by values *x*; 1. 2 l r — find ,... | ```python
def fib(num, x = 0, y = 1):
if num == 1:
return y
else:
return fib(num - 1, y, x + y)
n, m = [int(num) for num in input().split()]
a = [int(elem) for elem in input().split()]
out = []
for rep in range(m):
summ = 0
zapros = [int(i) for i in input().split()]
i... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,695,987,291 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 |
def solve():
n = int(input())
ans = []
sm = 0
for i in range(1,n+1):
sm+=i
ans.append(i)
if sm>=n:
break
# print(ans)
# total =
if sm==n:
print(len(ans))
print(*ans)
else:
sm = sum(ans)-n
ans... | Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
def solve():
n = int(input())
ans = []
sm = 0
for i in range(1,n+1):
sm+=i
ans.append(i)
if sm>=n:
break
# print(ans)
# total =
if sm==n:
print(len(ans))
print(*ans)
else:
sm = sum(ans)-n
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
652 | C | Foe Pairs | PROGRAMMING | 1,800 | [
"combinatorics",
"sortings",
"two pointers"
] | null | null | You are given a permutation *p* of length *n*. Also you are given *m* foe pairs (*a**i*,<=*b**i*) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*).
Your task is to count the number of different intervals (*x*,<=*y*) (1<=≤<=*x*<=≤<=*y*<=≤<=*n*) that do not contain any foe pairs. So you shouldn't count intervals (*x... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3·105) — the length of the permutation *p* and the number of foe pairs.
The second line contains *n* distinct integers *p**i* (1<=≤<=*p**i*<=≤<=*n*) — the elements of the permutation *p*.
Each of the next *m* lines contains two integers (*a**i*,<=*... | Print the only integer *c* — the number of different intervals (*x*,<=*y*) that does not contain any foe pairs.
Note that the answer can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | [
"4 2\n1 3 2 4\n3 2\n2 4\n",
"9 5\n9 7 2 3 1 4 6 5 8\n1 6\n4 5\n2 7\n7 2\n2 7\n"
] | [
"5\n",
"20\n"
] | In the first example the intervals from the answer are (1, 1), (1, 2), (2, 2), (3, 3) and (4, 4). | 0 | [
{
"input": "4 2\n1 3 2 4\n3 2\n2 4",
"output": "5"
},
{
"input": "9 5\n9 7 2 3 1 4 6 5 8\n1 6\n4 5\n2 7\n7 2\n2 7",
"output": "20"
},
{
"input": "2 1\n1 2\n1 2",
"output": "2"
},
{
"input": "10 3\n4 10 5 1 6 8 9 2 3 7\n10 5\n2 10\n4 1",
"output": "39"
},
{
"input"... | 1,574,701,029 | 2,147,483,647 | PyPy 3 | OK | TESTS | 24 | 732 | 41,574,400 | #!/usr/bin/env python3
from __future__ import division, print_function
def solver():
import sys
blob = sys.stdin.read().split()
it = map(int, blob)
n, m = next(it), next(it)
revp = [0, ] * (n+1)
for i in range(n):
revp[next(it)] = i
pairs = [-1] * (n+1)
pairs[-1] = n-1
fo... | Title: Foe Pairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a permutation *p* of length *n*. Also you are given *m* foe pairs (*a**i*,<=*b**i*) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*).
Your task is to count the number of different intervals (*x*,<=*y*) (1<=... | ```python
#!/usr/bin/env python3
from __future__ import division, print_function
def solver():
import sys
blob = sys.stdin.read().split()
it = map(int, blob)
n, m = next(it), next(it)
revp = [0, ] * (n+1)
for i in range(n):
revp[next(it)] = i
pairs = [-1] * (n+1)
pairs[-1] = ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
940 | B | Our Tanya is Crying Out Loud | PROGRAMMING | 1,400 | [
"dp",
"greedy"
] | null | null | Right now she actually isn't. But she will be, if you don't solve this problem.
You are given integers *n*, *k*, *A* and *B*. There is a number *x*, which is initially equal to *n*. You are allowed to perform two types of operations:
1. Subtract 1 from *x*. This operation costs you *A* coins. 1. Divide *x* by *k*.... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=2·109).
The second line contains a single integer *k* (1<=≤<=*k*<=≤<=2·109).
The third line contains a single integer *A* (1<=≤<=*A*<=≤<=2·109).
The fourth line contains a single integer *B* (1<=≤<=*B*<=≤<=2·109). | Output a single integer — the minimum amount of coins you have to pay to make *x* equal to 1. | [
"9\n2\n3\n1\n",
"5\n5\n2\n20\n",
"19\n3\n4\n2\n"
] | [
"6\n",
"8\n",
"12\n"
] | In the first testcase, the optimal strategy is as follows:
- Subtract 1 from *x* (9 → 8) paying 3 coins. - Divide *x* by 2 (8 → 4) paying 1 coin. - Divide *x* by 2 (4 → 2) paying 1 coin. - Divide *x* by 2 (2 → 1) paying 1 coin.
The total cost is 6 coins.
In the second test case the optimal strategy is to subtra... | 1,250 | [
{
"input": "9\n2\n3\n1",
"output": "6"
},
{
"input": "5\n5\n2\n20",
"output": "8"
},
{
"input": "19\n3\n4\n2",
"output": "12"
},
{
"input": "1845999546\n999435865\n1234234\n2323423",
"output": "1044857680578777"
},
{
"input": "1604353664\n1604353665\n9993432\n1",
... | 1,561,724,090 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 109 | 0 | n,k,a,b=[int(input()) for i in range(4)]
sm=0
x=n
while x!=1:
if x%k==0:
x//=k
sm+=b
else:
x-=1
sm+=a
print(sm) | Title: Our Tanya is Crying Out Loud
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Right now she actually isn't. But she will be, if you don't solve this problem.
You are given integers *n*, *k*, *A* and *B*. There is a number *x*, which is initially equal to *n*. You are allowed to perf... | ```python
n,k,a,b=[int(input()) for i in range(4)]
sm=0
x=n
while x!=1:
if x%k==0:
x//=k
sm+=b
else:
x-=1
sm+=a
print(sm)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,689,973,293 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 0 | 0 | word = input()
def shouldGetFix(word):
for i in range (1,len(word)):
print(word[i])
if word[i].islower():
return False
return True
if len(word) == 1:
print(word.upper())
elif shouldGetFix(word):
print(word.lower().capitalize())
else:
print(word) | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
word = input()
def shouldGetFix(word):
for i in range (1,len(word)):
print(word[i])
if word[i].islower():
return False
return True
if len(word) == 1:
print(word.upper())
elif shouldGetFix(word):
print(word.lower().capitalize())
else:
print(word)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
336 | A | Vasily the Bear and Triangle | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasily the bear has a favorite rectangle, it has one vertex at point (0,<=0), and the opposite vertex at point (*x*,<=*y*). Of course, the sides of Vasya's favorite rectangle are parallel to the coordinate axes.
Vasya also loves triangles, if the triangles have one vertex at point *B*<==<=(0,<=0). That's why today he... | The first line contains two integers *x*,<=*y* (<=-<=109<=≤<=*x*,<=*y*<=≤<=109,<=*x*<=≠<=0,<=*y*<=≠<=0). | Print in the single line four integers *x*1,<=*y*1,<=*x*2,<=*y*2 — the coordinates of the required points. | [
"10 5\n",
"-10 5\n"
] | [
"0 15 15 0\n",
"-15 0 0 15\n"
] | <img class="tex-graphics" src="https://espresso.codeforces.com/a9ea2088c4294ce8f23801562fda36b830df2c3f.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Figure to the first sample | 500 | [
{
"input": "10 5",
"output": "0 15 15 0"
},
{
"input": "-10 5",
"output": "-15 0 0 15"
},
{
"input": "20 -10",
"output": "0 -30 30 0"
},
{
"input": "-10 -1000000000",
"output": "-1000000010 0 0 -1000000010"
},
{
"input": "-1000000000 -1000000000",
"output": "-... | 1,586,121,476 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 307,200 | l=list(map(int,input().split()))
x=l[0]
y=l[1]
if (x>0 and y>0):
print("0 ",x+y," ",x+y," 0")
elif(x<0 and y<0):
print(x+y," 0 0 ",x+y)
elif(x<0 and y>0):
print(x-y," 0 0 ",y-x)
else:
print("0 ",y-x," ",x-y," 0")
| Title: Vasily the Bear and Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the bear has a favorite rectangle, it has one vertex at point (0,<=0), and the opposite vertex at point (*x*,<=*y*). Of course, the sides of Vasya's favorite rectangle are parallel to the coordinate ... | ```python
l=list(map(int,input().split()))
x=l[0]
y=l[1]
if (x>0 and y>0):
print("0 ",x+y," ",x+y," 0")
elif(x<0 and y<0):
print(x+y," 0 0 ",x+y)
elif(x<0 and y>0):
print(x-y," 0 0 ",y-x)
else:
print("0 ",y-x," ",x-y," 0")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
169 | A | Chores | PROGRAMMING | 800 | [
"sortings"
] | null | null | Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*.
As Petya is older, he wants to take the chores with complexit... | The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores.
The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* ... | Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. | [
"5 2 3\n6 2 3 100 1\n",
"7 3 4\n1 1 9 1 1 1 1\n"
] | [
"3\n",
"0\n"
] | In the first sample the possible values of *x* are 3, 4 or 5.
In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4. | 500 | [
{
"input": "5 2 3\n6 2 3 100 1",
"output": "3"
},
{
"input": "7 3 4\n1 1 9 1 1 1 1",
"output": "0"
},
{
"input": "2 1 1\n10 2",
"output": "8"
},
{
"input": "2 1 1\n7 7",
"output": "0"
},
{
"input": "2 1 1\n1 1000000000",
"output": "999999999"
},
{
"inp... | 1,540,991,587 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 108 | 0 | # http://codeforces.com/problemset/problem/169/A?fbclid=IwAR2qjWxrKeECIDX3IvTsI-DC7jeJEtGIqj2vePzXa8OLBjqKkkMjcWpwm7Y
number_of_jobs, petya_jobs, vasya_jobs = map(int, input().split(' '))
job_complexities = list(map(int, input().split(' ')))
job_complexities.sort(reverse=True)
m = job_complexities[vasya_jobs - 1]
cou... | Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of th... | ```python
# http://codeforces.com/problemset/problem/169/A?fbclid=IwAR2qjWxrKeECIDX3IvTsI-DC7jeJEtGIqj2vePzXa8OLBjqKkkMjcWpwm7Y
number_of_jobs, petya_jobs, vasya_jobs = map(int, input().split(' '))
job_complexities = list(map(int, input().split(' ')))
job_complexities.sort(reverse=True)
m = job_complexities[vasya_job... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
915 | A | Garden | PROGRAMMING | 900 | [
"implementation"
] | null | null | Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't wat... | The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one ... | Print one integer number — the minimum number of hours required to water the garden. | [
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] | [
"2\n",
"7\n"
] | In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | 0 | [
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 5... | 1,585,337,628 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | line = input().split()
num_buckets = int(line[0])
length = int(line[1])
ans = 0
line = input().split()
for bucket in line:
bucket_size = int(bucket)
if length % bucket_size == 0:
ans = max(ans, bucket_size)
print(ans)
| Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each ... | ```python
line = input().split()
num_buckets = int(line[0])
length = int(line[1])
ans = 0
line = input().split()
for bucket in line:
bucket_size = int(bucket)
if length % bucket_size == 0:
ans = max(ans, bucket_size)
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,674,057,641 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 186 | 7,987,200 | n = int(input())
a = input().split(' ')
b = [int(i) for i in a]
e = min(b)
if b.count(e) == 1:
print(b.index(e)+1)
else:
print('Still Rozdil') | Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
n = int(input())
a = input().split(' ')
b = [int(i) for i in a]
e = min(b)
if b.count(e) == 1:
print(b.index(e)+1)
else:
print('Still Rozdil')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
24 | A | Ring road | PROGRAMMING | 1,400 | [
"graphs"
] | A. Ring road | 2 | 256 | Nowadays the one-way traffic is introduced all over the world in order to improve driving safety and reduce traffic jams. The government of Berland decided to keep up with new trends. Formerly all *n* cities of Berland were connected by *n* two-way roads in the ring, i. e. each city was connected directly to exactly tw... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of cities (and roads) in Berland. Next *n* lines contain description of roads. Each road is described by three integers *a**i*, *b**i*, *c**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*,<=1<=≤<=*c**i*<=≤<=100) — road is directed from city *a**i* t... | Output single integer — the smallest amount of money the government should spend on the redirecting of roads so that from every city you can get to any other. | [
"3\n1 3 1\n1 2 1\n3 2 1\n",
"3\n1 3 1\n1 2 5\n3 2 1\n",
"6\n1 5 4\n5 3 8\n2 4 15\n1 6 16\n2 3 23\n4 6 42\n",
"4\n1 2 9\n2 3 8\n3 4 7\n4 1 5\n"
] | [
"1\n",
"2\n",
"39\n",
"0\n"
] | none | 0 | [
{
"input": "3\n1 3 1\n1 2 1\n3 2 1",
"output": "1"
},
{
"input": "3\n1 3 1\n1 2 5\n3 2 1",
"output": "2"
},
{
"input": "6\n1 5 4\n5 3 8\n2 4 15\n1 6 16\n2 3 23\n4 6 42",
"output": "39"
},
{
"input": "4\n1 2 9\n2 3 8\n3 4 7\n4 1 5",
"output": "0"
},
{
"input": "5\n... | 1,658,655,349 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | def findNextPath(cont, path, ind):
for i in range(len(cont)):
if cont[ind][i] != 0 and i not in path or \
cont[i][ind] != 0 and i not in path:
return i
return -1
N = int(input())
cont = [[0] * N for i in range(N)]
for i in range(N):
city1, city2, price = [int... | Title: Ring road
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Nowadays the one-way traffic is introduced all over the world in order to improve driving safety and reduce traffic jams. The government of Berland decided to keep up with new trends. Formerly all *n* cities of Berland were conne... | ```python
def findNextPath(cont, path, ind):
for i in range(len(cont)):
if cont[ind][i] != 0 and i not in path or \
cont[i][ind] != 0 and i not in path:
return i
return -1
N = int(input())
cont = [[0] * N for i in range(N)]
for i in range(N):
city1, city2, pr... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
766 | B | Mahmoud and a Triangle | PROGRAMMING | 1,000 | [
"constructive algorithms",
"geometry",
"greedy",
"math",
"number theory",
"sortings"
] | null | null | Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he can win, so he asked you to tell him if he should accept the challenge. Given the lengths of the line segments... | The first line contains single integer *n* (3<=≤<=*n*<=≤<=105) — the number of line segments Mahmoud has.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the lengths of line segments Mahmoud has. | In the only line print "YES" if he can choose exactly three line segments and form a non-degenerate triangle with them, and "NO" otherwise. | [
"5\n1 5 3 2 4\n",
"3\n4 1 2\n"
] | [
"YES\n",
"NO\n"
] | For the first example, he can use line segments with lengths 2, 4 and 5 to form a non-degenerate triangle. | 1,000 | [
{
"input": "5\n1 5 3 2 4",
"output": "YES"
},
{
"input": "3\n4 1 2",
"output": "NO"
},
{
"input": "30\n197 75 517 39724 7906061 1153471 3 15166 168284 3019844 272293 316 16 24548 42 118 5792 5 9373 1866366 4886214 24 2206 712886 104005 1363 836 64273 440585 3576",
"output": "NO"
},... | 1,695,720,790 | 2,147,483,647 | Python 3 | OK | TESTS | 87 | 77 | 13,619,200 | def is_triangle_possible(arr):
n = len(arr)
if n < 3:
return False
arr.sort()
for i in range(n - 2):
if arr[i] + arr[i + 1] > arr[i + 2]:
return True
return False
n = int(input())
t = list(map(int, input().split()))
if is_triangle_possible(t) == False:
... | Title: Mahmoud and a Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he ca... | ```python
def is_triangle_possible(arr):
n = len(arr)
if n < 3:
return False
arr.sort()
for i in range(n - 2):
if arr[i] + arr[i + 1] > arr[i + 2]:
return True
return False
n = int(input())
t = list(map(int, input().split()))
if is_triangle_possible(t) == F... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<... | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In ... | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,620,409,108 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 124 | 21,504,000 | def numberOfFaces(n, m, image):
ans = 0
for i in range(n - 1):
for j in range(m - 1):
lists = [image[i][j], image[i + 1][j], image[i][j + 1], image[i + 1][j + 1]]
if set(lists) == set("face"):
ans += 1
return ans
n, m = [int(i) for i in input().split()]
image = [list(input()) for i in ran... | Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem a... | ```python
def numberOfFaces(n, m, image):
ans = 0
for i in range(n - 1):
for j in range(m - 1):
lists = [image[i][j], image[i + 1][j], image[i][j + 1], image[i + 1][j + 1]]
if set(lists) == set("face"):
ans += 1
return ans
n, m = [int(i) for i in input().split()]
image = [list(input()) fo... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
992 | C | Nastya and a Wardrobe | PROGRAMMING | 1,600 | [
"math"
] | null | null | Nastya received a gift on New Year — a magic wardrobe. It is magic because in the end of each month the number of dresses in it doubles (i.e. the number of dresses becomes twice as large as it is in the beginning of the month).
Unfortunately, right after the doubling the wardrobe eats one of the dresses (if any) with ... | The only line contains two integers *x* and *k* (0<=≤<=*x*,<=*k*<=≤<=1018), where *x* is the initial number of dresses and *k*<=+<=1 is the number of months in a year in Byteland. | In the only line print a single integer — the expected number of dresses Nastya will own one year later modulo 109<=+<=7. | [
"2 0\n",
"2 1\n",
"3 2\n"
] | [
"4\n",
"7\n",
"21\n"
] | In the first example a year consists on only one month, so the wardrobe does not eat dresses at all.
In the second example after the first month there are 3 dresses with 50% probability and 4 dresses with 50% probability. Thus, in the end of the year there are 6 dresses with 50% probability and 8 dresses with 50% prob... | 1,500 | [
{
"input": "2 0",
"output": "4"
},
{
"input": "2 1",
"output": "7"
},
{
"input": "3 2",
"output": "21"
},
{
"input": "1 411",
"output": "485514976"
},
{
"input": "1 692",
"output": "860080936"
},
{
"input": "16 8",
"output": "7937"
},
{
"in... | 1,604,502,705 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | # (x^y)%p in O(log y)
def power(x, y, p) :
res = 1 # Initialize result
# Update x if it is more
# than or equal to p
x = x % p
if (x == 0) :
return 0
while (y > 0) :
# If y is odd, multiply
# x with result
if ... | Title: Nastya and a Wardrobe
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya received a gift on New Year — a magic wardrobe. It is magic because in the end of each month the number of dresses in it doubles (i.e. the number of dresses becomes twice as large as it is in the beginning ... | ```python
# (x^y)%p in O(log y)
def power(x, y, p) :
res = 1 # Initialize result
# Update x if it is more
# than or equal to p
x = x % p
if (x == 0) :
return 0
while (y > 0) :
# If y is odd, multiply
# x with result
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
445 | B | DZY Loves Chemistry | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu",
"greedy"
] | null | null | DZY loves chemistry, and he enjoys mixing chemicals.
DZY has *n* chemicals, and *m* pairs of them will react. He wants to pour these chemicals into a test tube, and he needs to pour them in one by one, in any order.
Let's consider the danger of a test tube. Danger of an empty test tube is 1. And every time when DZY ... | The first line contains two space-separated integers *n* and *m* .
Each of the next *m* lines contains two space-separated integers *x**i* and *y**i* (1<=≤<=*x**i*<=<<=*y**i*<=≤<=*n*). These integers mean that the chemical *x**i* will react with the chemical *y**i*. Each pair of chemicals will appear at most once i... | Print a single integer — the maximum possible danger. | [
"1 0\n",
"2 1\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first sample, there's only one way to pour, and the danger won't increase.
In the second sample, no matter we pour the 1st chemical first, or pour the 2nd chemical first, the answer is always 2.
In the third sample, there are four ways to achieve the maximum possible danger: 2-1-3, 2-3-1, 1-2-3 and 3-2-1 (that... | 1,000 | [
{
"input": "1 0",
"output": "1"
},
{
"input": "2 1\n1 2",
"output": "2"
},
{
"input": "3 2\n1 2\n2 3",
"output": "4"
},
{
"input": "10 10\n1 8\n4 10\n4 6\n5 10\n2 3\n1 7\n3 4\n3 6\n6 9\n3 7",
"output": "512"
},
{
"input": "20 20\n6 8\n13 20\n7 13\n6 17\n5 15\n1 12... | 1,643,034,479 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 62 | 0 | # -*- coding: utf-8 -*-
"""
Created on Mon Jan 24 21:16:11 2022
@author: Lai Phuc
problem 445B - codeforce
"""
n, m = map(int, input().split(" "))
root = list(range(n+1))
def find_root(u):
if u == root[u]:
return u
else:
return find_root(root[u])
def disSet(u, v):
rootu = fin... | Title: DZY Loves Chemistry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chemistry, and he enjoys mixing chemicals.
DZY has *n* chemicals, and *m* pairs of them will react. He wants to pour these chemicals into a test tube, and he needs to pour them in one by one, in any order... | ```python
# -*- coding: utf-8 -*-
"""
Created on Mon Jan 24 21:16:11 2022
@author: Lai Phuc
problem 445B - codeforce
"""
n, m = map(int, input().split(" "))
root = list(range(n+1))
def find_root(u):
if u == root[u]:
return u
else:
return find_root(root[u])
def disSet(u, v):
r... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,612,634,008 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 9,011,200 | try:
a,b,n=list(map(int,input().split(" ")))
s=str(a)
k=len(s)
kl=0
while kl!=2 and len(s)!=k+n:
for i in range(0,9):
if int(s+str(i))%b==0:
s+=str(i)
kl=1
break
elif kl==0:
kl=2
if len(s... | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
try:
a,b,n=list(map(int,input().split(" ")))
s=str(a)
k=len(s)
kl=0
while kl!=2 and len(s)!=k+n:
for i in range(0,9):
if int(s+str(i))%b==0:
s+=str(i)
kl=1
break
elif kl==0:
kl=2
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
724 | B | Batch Sort | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | You are given a table consisting of *n* rows and *m* columns.
Numbers in each row form a permutation of integers from 1 to *m*.
You are allowed to pick two elements in one row and swap them, but no more than once for each row. Also, no more than once you are allowed to pick two columns and swap them. Thus, you are al... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=20) — the number of rows and the number of columns in the given table.
Each of next *n* lines contains *m* integers — elements of the table. It's guaranteed that numbers in each line form a permutation of integers from 1 to *m*. | If there is a way to obtain the identity permutation in each row by following the given rules, print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes). | [
"2 4\n1 3 2 4\n1 3 4 2\n",
"4 4\n1 2 3 4\n2 3 4 1\n3 4 1 2\n4 1 2 3\n",
"3 6\n2 1 3 4 5 6\n1 2 4 3 5 6\n1 2 3 4 6 5\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, one can act in the following way:
1. Swap second and third columns. Now the table is <center class="tex-equation">1 2 3 4</center> <center class="tex-equation">1 4 3 2</center> 1. In the second row, swap the second and the fourth elements. Now the table is <center class="tex-equation">1 2 3 4</... | 1,000 | [
{
"input": "2 4\n1 3 2 4\n1 3 4 2",
"output": "YES"
},
{
"input": "4 4\n1 2 3 4\n2 3 4 1\n3 4 1 2\n4 1 2 3",
"output": "NO"
},
{
"input": "3 6\n2 1 3 4 5 6\n1 2 4 3 5 6\n1 2 3 4 6 5",
"output": "YES"
},
{
"input": "3 10\n1 2 3 4 5 6 7 10 9 8\n5 2 3 4 1 6 7 8 9 10\n1 2 3 4 5 6... | 1,475,935,812 | 6,912 | Python 3 | OK | TESTS | 86 | 92 | 4,915,200 | def difference(ln, k, l):
count = 0
line2 = ln[:]
line2[k], line2[l] = ln[l], ln[k]
for i in range(len(ln)):
if line2[i] != i + 1:
count += 1
return count
def difference2(ln):
count = 0
for i in range(len(ln)):
if ln[i] != i + 1:
coun... | Title: Batch Sort
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a table consisting of *n* rows and *m* columns.
Numbers in each row form a permutation of integers from 1 to *m*.
You are allowed to pick two elements in one row and swap them, but no more than once for each ... | ```python
def difference(ln, k, l):
count = 0
line2 = ln[:]
line2[k], line2[l] = ln[l], ln[k]
for i in range(len(ln)):
if line2[i] != i + 1:
count += 1
return count
def difference2(ln):
count = 0
for i in range(len(ln)):
if ln[i] != i + 1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,605,104,046 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | x = input().split()
res = []
for i in range(int(x[2])+1):
if (i+int(x[0])) % int(x[1]) ==0 and i+int(x[0]) < int(x[2]):
res.append(i)
if len(res)==0:
print(-1)
else:
print(" ".join(map(str, res))) | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
x = input().split()
res = []
for i in range(int(x[2])+1):
if (i+int(x[0])) % int(x[1]) ==0 and i+int(x[0]) < int(x[2]):
res.append(i)
if len(res)==0:
print(-1)
else:
print(" ".join(map(str, res)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
612 | B | HDD is Outdated Technology | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the problems of HDD hard drives is the following: the magnetic head should move from one sector to another to read s... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of fragments.
The second line contains *n* different integers *f**i* (1<=≤<=*f**i*<=≤<=*n*) — the number of the fragment written in the *i*-th sector. | Print the only integer — the number of time units needed to read the file. | [
"3\n3 1 2\n",
"5\n1 3 5 4 2\n"
] | [
"3\n",
"10\n"
] | In the second example the head moves in the following way:
- 1->2 means movement from the sector 1 to the sector 5, i.e. it takes 4 time units - 2->3 means movement from the sector 5 to the sector 2, i.e. it takes 3 time units - 3->4 means movement from the sector 2 to the sector 4, i.e. it takes 2 time un... | 0 | [
{
"input": "3\n3 1 2",
"output": "3"
},
{
"input": "5\n1 3 5 4 2",
"output": "10"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n8 2 10 3 4 6 1 7 9 5",
"output": "40"
... | 1,451,068,143 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 514 | 27,750,400 | import sys
if False:
inp = open('A.txt', 'r')
else:
inp = sys.stdin
n = int(inp.readline())
sectors = list(zip(map(int, inp.readline().split()), [x+1 for x in range(n)]))
sectors.sort(key = lambda x: x[0])
ans = 0
for i in range(n-1):
ans += max(sectors[i][1]-sectors[i+1][1], sectors[i+1][1] - sectors[... | Title: HDD is Outdated Technology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the ... | ```python
import sys
if False:
inp = open('A.txt', 'r')
else:
inp = sys.stdin
n = int(inp.readline())
sectors = list(zip(map(int, inp.readline().split()), [x+1 for x in range(n)]))
sectors.sort(key = lambda x: x[0])
ans = 0
for i in range(n-1):
ans += max(sectors[i][1]-sectors[i+1][1], sectors[i+1][1] ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
920 | A | Water The Garden | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the bed *x**i*), which, if turned on, start delivering water to neighbouring beds. If the tap on the bed *... | The first line contains one integer *t* — the number of test cases to solve (1<=≤<=*t*<=≤<=200).
Then *t* test cases follow. The first line of each test case contains two integers *n* and *k* (1<=≤<=*n*<=≤<=200, 1<=≤<=*k*<=≤<=*n*) — the number of garden beds and water taps, respectively.
Next line contains *k* intege... | For each test case print one integer — the minimum number of seconds that have to pass after Max turns on some of the water taps, until the whole garden is watered. | [
"3\n5 1\n3\n3 3\n1 2 3\n4 1\n1\n"
] | [
"3\n1\n4\n"
] | The first example consists of 3 tests:
1. There are 5 garden beds, and a water tap in the bed 3. If we turn it on, then after 1 second passes, only bed 3 will be watered; after 2 seconds pass, beds [1, 3] will be watered, and after 3 seconds pass, everything will be watered. 1. There are 3 garden beds, and there is ... | 0 | [
{
"input": "3\n5 1\n3\n3 3\n1 2 3\n4 1\n1",
"output": "3\n1\n4"
},
{
"input": "26\n1 1\n1\n2 1\n2\n2 1\n1\n2 2\n1 2\n3 1\n3\n3 1\n2\n3 2\n2 3\n3 1\n1\n3 2\n1 3\n3 2\n1 2\n3 3\n1 2 3\n4 1\n4\n4 1\n3\n4 2\n3 4\n4 1\n2\n4 2\n2 4\n4 2\n2 3\n4 3\n2 3 4\n4 1\n1\n4 2\n1 4\n4 2\n1 3\n4 3\n1 3 4\n4 2\n1 2\n4... | 1,609,427,247 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 124 | 716,800 | import math
import os
import random
import re
import sys
import functools
from operator import itemgetter, attrgetter
from collections import Counter
if __name__ == '__main__':
Y = lambda: list(map(int, input().split()))
P = lambda: map(int, input().split())
N = lambda: int(input())
t = ... | Title: Water The Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the ... | ```python
import math
import os
import random
import re
import sys
import functools
from operator import itemgetter, attrgetter
from collections import Counter
if __name__ == '__main__':
Y = lambda: list(map(int, input().split()))
P = lambda: map(int, input().split())
N = lambda: int(input())
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
405 | A | Gravity Flip | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the box arranged in a line. The *i*-th column contains *a**i* cubes. At first, the gravity in the box is... | The first line of input contains an integer *n* (1<=≤<=*n*<=≤<=100), the number of the columns in the box. The next line contains *n* space-separated integer numbers. The *i*-th number *a**i* (1<=≤<=*a**i*<=≤<=100) denotes the number of cubes in the *i*-th column. | Output *n* integer numbers separated by spaces, where the *i*-th number is the amount of cubes in the *i*-th column after the gravity switch. | [
"4\n3 2 1 2\n",
"3\n2 3 8\n"
] | [
"1 2 2 3 \n",
"2 3 8 \n"
] | The first example case is shown on the figure. The top cube of the first column falls to the top of the last column; the top cube of the second column falls to the top of the third column; the middle cube of the first column falls to the top of the second column.
In the second example case the gravity switch does not ... | 500 | [
{
"input": "4\n3 2 1 2",
"output": "1 2 2 3 "
},
{
"input": "3\n2 3 8",
"output": "2 3 8 "
},
{
"input": "5\n2 1 2 1 2",
"output": "1 1 2 2 2 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n4 3",
"output": "3 4 "
},
{
"input": "6\n100 40 60 20... | 1,694,678,557 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | n = int(input())
cube_counts = list(map(int, input().split()))
cube_counts.sort()
for count in cube_counts:
print(count, end=' ') | Title: Gravity Flip
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the bo... | ```python
n = int(input())
cube_counts = list(map(int, input().split()))
cube_counts.sort()
for count in cube_counts:
print(count, end=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,673,090,881 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 140 | 10,035,200 |
(n, b, d) = (int(x) for x in input().split(" "))
ol = [int(x) for x in input().split(" ")]
juicer = 0
cnt = 0
for i in range(n):
orange = ol[i]
if(orange < b):
juicer += orange
else:
continue
if(juicer > d):
cnt += 1
juicer = 0
print... | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
(n, b, d) = (int(x) for x in input().split(" "))
ol = [int(x) for x in input().split(" ")]
juicer = 0
cnt = 0
for i in range(n):
orange = ol[i]
if(orange < b):
juicer += orange
else:
continue
if(juicer > d):
cnt += 1
juicer = 0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
760 | B | Frodo and pillows | PROGRAMMING | 1,500 | [
"binary search",
"greedy"
] | null | null | *n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as many pillows as possible. Of course, it's not always possible to share pillows equally, but any hobbit ge... | The only line contain three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=*m*<=≤<=109, 1<=≤<=*k*<=≤<=*n*) — the number of hobbits, the number of pillows and the number of Frodo's bed. | Print single integer — the maximum number of pillows Frodo can have so that no one is hurt. | [
"4 6 2\n",
"3 10 3\n",
"3 6 1\n"
] | [
"2\n",
"4\n",
"3\n"
] | In the first example Frodo can have at most two pillows. In this case, he can give two pillows to the hobbit on the first bed, and one pillow to each of the hobbits on the third and the fourth beds.
In the second example Frodo can take at most four pillows, giving three pillows to each of the others.
In the third exa... | 1,000 | [
{
"input": "4 6 2",
"output": "2"
},
{
"input": "3 10 3",
"output": "4"
},
{
"input": "3 6 1",
"output": "3"
},
{
"input": "3 3 3",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 1000000000 1",
"output": "1000000000"
},
{
... | 1,580,449,628 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 124 | 0 | n, m, k = [int(i) for i in input().strip().split(" ")]
def check(t):
a = t - k + 1
b = t - n + k
pillows = t
if a > 1:
pillows += (t - a) * (a + t - 1) // 2
else:
pillows += k - t + t * (t - 1) // 2
if b > 1:
pillows += (t - b) * (a + t - 1) // 2
else:
... | Title: Frodo and pillows
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as ma... | ```python
n, m, k = [int(i) for i in input().strip().split(" ")]
def check(t):
a = t - k + 1
b = t - n + k
pillows = t
if a > 1:
pillows += (t - a) * (a + t - 1) // 2
else:
pillows += k - t + t * (t - 1) // 2
if b > 1:
pillows += (t - b) * (a + t - 1) // 2
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,667,994,307 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 77 | 0 | from collections import Counter
def main():
n = get_int()
nums = get_list_int()
num_counter = Counter(nums)
num_groups = n // 3
if (
num_counter[1] != num_groups
or num_counter[2] != num_groups
or (num_counter[4] + num_counter[6] != num_groups)
):
... | Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
from collections import Counter
def main():
n = get_int()
nums = get_list_int()
num_counter = Counter(nums)
num_groups = n // 3
if (
num_counter[1] != num_groups
or num_counter[2] != num_groups
or (num_counter[4] + num_counter[6] != num_groups)
)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,675,979,990 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | def ts(x):
return "YES" if x else "NO"
def si(x):
return [int(z) for z in x.split()]
def prime(x):
if x < 2:
return False
i = 2
while i * i <= x:
if x % i == 0:
return False
i += 1
return True
def case(data):
a, b = si(data)
if a >= b:
return "NO"
return ts(prime(a) and prime(... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
def ts(x):
return "YES" if x else "NO"
def si(x):
return [int(z) for z in x.split()]
def prime(x):
if x < 2:
return False
i = 2
while i * i <= x:
if x % i == 0:
return False
i += 1
return True
def case(data):
a, b = si(data)
if a >= b:
return "NO"
return ts(prime(a) ... | -1 | MatrixStudio/Codeforces-Python-Submissions |
982 | C | Cut 'em all! | PROGRAMMING | 1,500 | [
"dfs and similar",
"dp",
"graphs",
"greedy",
"trees"
] | null | null | You're given a tree with $n$ vertices.
Your task is to determine the maximum possible number of edges that can be removed in such a way that all the remaining connected components will have even size. | The first line contains an integer $n$ ($1 \le n \le 10^5$) denoting the size of the tree.
The next $n - 1$ lines contain two integers $u$, $v$ ($1 \le u, v \le n$) each, describing the vertices connected by the $i$-th edge.
It's guaranteed that the given edges form a tree. | Output a single integer $k$ — the maximum number of edges that can be removed to leave all connected components with even size, or $-1$ if it is impossible to remove edges in order to satisfy this property. | [
"4\n2 4\n4 1\n3 1\n",
"3\n1 2\n1 3\n",
"10\n7 1\n8 4\n8 10\n4 7\n6 5\n9 3\n3 5\n2 10\n2 5\n",
"2\n1 2\n"
] | [
"1",
"-1",
"4",
"0"
] | In the first example you can remove the edge between vertices $1$ and $4$. The graph after that will have two connected components with two vertices in each.
In the second example you can't remove edges in such a way that all components have even number of vertices, so the answer is $-1$. | 1,500 | [
{
"input": "4\n2 4\n4 1\n3 1",
"output": "1"
},
{
"input": "3\n1 2\n1 3",
"output": "-1"
},
{
"input": "10\n7 1\n8 4\n8 10\n4 7\n6 5\n9 3\n3 5\n2 10\n2 5",
"output": "4"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "1",
"output": "-1"
},
{
"inpu... | 1,551,171,480 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | from sys import stdin
n = int(input())
g = [[] for _ in range(n)]
def dfs(v, p=-1):
res = 1
for to in g[v]:
if to != p:
res += dfs(to, v)
return res
for line in stdin:
if line == '': break
u, v = (int(x)-1 for x in line.split())
g[v].append(u)
g[u].appe... | Title: Cut 'em all!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You're given a tree with $n$ vertices.
Your task is to determine the maximum possible number of edges that can be removed in such a way that all the remaining connected components will have even size.
Input Specification... | ```python
from sys import stdin
n = int(input())
g = [[] for _ in range(n)]
def dfs(v, p=-1):
res = 1
for to in g[v]:
if to != p:
res += dfs(to, v)
return res
for line in stdin:
if line == '': break
u, v = (int(x)-1 for x in line.split())
g[v].append(u)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
825 | A | Binary Protocol | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Polycarp has just invented a new binary protocol for data transmission. He is encoding positive integer decimal number to binary string using following algorithm:
- Each digit is represented with number of '1' characters equal to the value of that digit (for 0 it is zero ones). - Digits are written one by one in ord... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=89) — length of the string *s*.
The second line contains string *s* — sequence of '0' and '1' characters, number in its encoded format. It is guaranteed that the number corresponding to the string is positive and doesn't exceed 109. The string always starts... | Print the decoded number. | [
"3\n111\n",
"9\n110011101\n"
] | [
"3\n",
"2031\n"
] | none | 0 | [
{
"input": "3\n111",
"output": "3"
},
{
"input": "9\n110011101",
"output": "2031"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "3\n100",
"output": "100"
},
{
"input": "5\n10001",
"output": "1001"
},
{
"input": "14\n11001100011000",
"output": "... | 1,500,219,010 | 1,510 | Python 3 | OK | TESTS | 13 | 46 | 4,608,000 | n = int(input())
string = input()
number = ""
count = 0
for i in range(0, n):
if string[i] == "1":
count += 1
elif string[i] == "0" and i > 0 and string[i-1] == "1":
number += str(count)
count = 0
else:
number += "0"
number += str(count)
print(number)
| Title: Binary Protocol
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has just invented a new binary protocol for data transmission. He is encoding positive integer decimal number to binary string using following algorithm:
- Each digit is represented with number of '1' charact... | ```python
n = int(input())
string = input()
number = ""
count = 0
for i in range(0, n):
if string[i] == "1":
count += 1
elif string[i] == "0" and i > 0 and string[i-1] == "1":
number += str(count)
count = 0
else:
number += "0"
number += str(count)
print(number)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,612,010,217 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n=int(input())
li=[int(x) for x in input().split()]
ev=0
od=0
for i in range(len(li)):
if(li[i]%2==0):
ev=ev+1
ind=i+1
else:
od=od+1
ind1=i+1
if(ev>od):
print(ind)
else:
print(ind1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
li=[int(x) for x in input().split()]
ev=0
od=0
for i in range(len(li)):
if(li[i]%2==0):
ev=ev+1
ind=i+1
else:
od=od+1
ind1=i+1
if(ev>od):
print(ind)
else:
print(ind1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,583,218,887 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 5,734,400 | from math import sqrt
a, b, n = [int(x) for x in input().split(" ")]
while n > 0:
flag = False
for i in range(10):
if ((a * 10) + i) % b == 0:
a = a * 10 + i
flag = True
n -= 1
break
if not flag:
break
if n != 0:
... | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
from math import sqrt
a, b, n = [int(x) for x in input().split(" ")]
while n > 0:
flag = False
for i in range(10):
if ((a * 10) + i) % b == 0:
a = a * 10 + i
flag = True
n -= 1
break
if not flag:
break
if n... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,648,582,025 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 93 | 6,656,000 | n,b,d = map(int, input().split())
arr = list(map(int, input().split()[:n]))
counter = 0
k = 0
for i in range(len(arr)):
if arr[i] <= b and counter <= d:
counter += arr[i]
if counter > d:
counter = 0
k += 1
print(k) | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
n,b,d = map(int, input().split())
arr = list(map(int, input().split()[:n]))
counter = 0
k = 0
for i in range(len(arr)):
if arr[i] <= b and counter <= d:
counter += arr[i]
if counter > d:
counter = 0
k += 1
print(k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
454 | A | Little Pony and Crystal Mine | PROGRAMMING | 800 | [
"implementation"
] | null | null | Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You need to draw a crystal of size *n*. The diamond cells of the matrix should be represented by character "D". All ot... | The only line contains an integer *n* (3<=≤<=*n*<=≤<=101; *n* is odd). | Output a crystal of size *n*. | [
"3\n",
"5\n",
"7\n"
] | [
"*D*\nDDD\n*D*\n",
"**D**\n*DDD*\nDDDDD\n*DDD*\n**D**\n",
"***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***\n"
] | none | 500 | [
{
"input": "3",
"output": "*D*\nDDD\n*D*"
},
{
"input": "5",
"output": "**D**\n*DDD*\nDDDDD\n*DDD*\n**D**"
},
{
"input": "7",
"output": "***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***"
},
{
"input": "11",
"output": "*****D*****\n****DDD****\n***DDDDD***\n**... | 1,625,139,068 | 2,147,483,647 | PyPy 3 | OK | TESTS | 12 | 109 | 102,400 | # for testCase in range(int(input())):
n = int(input())
ans = ""
for i in range(1 ,(n+1)//2+1):
cur = i*2-1
ans += '*'*((n-cur)//2) + 'D'*(cur) + '*'*((n-cur)//2)
ans += '\n'
for i in range(1 ,(n+1)//2):
cur = n-i*2
ans += '*'*i + 'D'*cur + '*'*i + '\n'
print(ans)
| Title: Little Pony and Crystal Mine
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You ... | ```python
# for testCase in range(int(input())):
n = int(input())
ans = ""
for i in range(1 ,(n+1)//2+1):
cur = i*2-1
ans += '*'*((n-cur)//2) + 'D'*(cur) + '*'*((n-cur)//2)
ans += '\n'
for i in range(1 ,(n+1)//2):
cur = n-i*2
ans += '*'*i + 'D'*cur + '*'*i + '\n'
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,695,569,645 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 62 | 1,331,200 | n = int(input())
def prime(n):
for i in range(2,n//2+1):
if(n%i==0):
return False
return True
for i in range(4, n):
if not prime(i) and not prime(n-i):
print(i, n-i)
break | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n = int(input())
def prime(n):
for i in range(2,n//2+1):
if(n%i==0):
return False
return True
for i in range(4, n):
if not prime(i) and not prime(n-i):
print(i, n-i)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,615,611,445 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 77 | 307,200 | n,d = map(int, input().split())
li = list(map(int, input()))
dist = [10000]*n
dist[0] = 0
for i in range(n):
if li[i] == 1:
for j in range(d+1):
if i+j < n and li[i+j] == 1:
dist[i+j] = min(dist[i+j],dist[i]+1)
if dist[n-1] == 10000:
print(-1)
else:
print(dist... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
n,d = map(int, input().split())
li = list(map(int, input()))
dist = [10000]*n
dist[0] = 0
for i in range(n):
if li[i] == 1:
for j in range(d+1):
if i+j < n and li[i+j] == 1:
dist[i+j] = min(dist[i+j],dist[i]+1)
if dist[n-1] == 10000:
print(-1)
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
777 | C | Alyona and Spreadsheet | PROGRAMMING | 1,600 | [
"binary search",
"data structures",
"dp",
"greedy",
"implementation",
"two pointers"
] | null | null | During the lesson small girl Alyona works with one famous spreadsheet computer program and learns how to edit tables.
Now she has a table filled with integers. The table consists of *n* rows and *m* columns. By *a**i*,<=*j* we will denote the integer located at the *i*-th row and the *j*-th column. We say that the tab... | The first line of the input contains two positive integers *n* and *m* (1<=≤<=*n*·*m*<=≤<=100<=000) — the number of rows and the number of columns in the table respectively. Note that your are given a constraint that bound the product of these two integers, i.e. the number of elements in the table.
Each of the followi... | Print "Yes" to the *i*-th line of the output if the table consisting of rows from *l**i* to *r**i* inclusive is sorted in non-decreasing order in at least one column. Otherwise, print "No". | [
"5 4\n1 2 3 5\n3 1 3 2\n4 5 2 3\n5 5 3 2\n4 4 3 4\n6\n1 1\n2 5\n4 5\n3 5\n1 3\n1 5\n"
] | [
"Yes\nNo\nYes\nYes\nYes\nNo\n"
] | In the sample, the whole table is not sorted in any column. However, rows 1–3 are sorted in column 1, while rows 4–5 are sorted in column 3. | 1,500 | [
{
"input": "5 4\n1 2 3 5\n3 1 3 2\n4 5 2 3\n5 5 3 2\n4 4 3 4\n6\n1 1\n2 5\n4 5\n3 5\n1 3\n1 5",
"output": "Yes\nNo\nYes\nYes\nYes\nNo"
},
{
"input": "1 1\n1\n1\n1 1",
"output": "Yes"
},
{
"input": "10 1\n523130301\n127101624\n15573616\n703140639\n628818570\n957494759\n161270109\n38686565... | 1,589,458,396 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 187 | 22,220,800 | from sys import stdin
input = stdin.readline
n, m = map(int, input().split())
arr = list(list(map(int, input().split())) for _ in range(n))
dp = [[1 for i in range(m)] for j in range(n)]
for i in range(1, n):
for j in range(m):
if arr[i][j] >= arr[i-1][j]:
dp[i][j] = dp[i-1][j] + 1
... | Title: Alyona and Spreadsheet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the lesson small girl Alyona works with one famous spreadsheet computer program and learns how to edit tables.
Now she has a table filled with integers. The table consists of *n* rows and *m* columns. By ... | ```python
from sys import stdin
input = stdin.readline
n, m = map(int, input().split())
arr = list(list(map(int, input().split())) for _ in range(n))
dp = [[1 for i in range(m)] for j in range(n)]
for i in range(1, n):
for j in range(m):
if arr[i][j] >= arr[i-1][j]:
dp[i][j] = dp[i-1]... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,639,075,776 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | import numpy as np
n = int(input())
m = int(input())
print(m % np.power(2, n)) | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
import numpy as np
n = int(input())
m = int(input())
print(m % np.power(2, n))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,617,690,311 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 0 | x = input()
y = x.split(' ')
print(int((int(y[0]) * int(y[1]))/2))
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
x = input()
y = x.split(' ')
print(int((int(y[0]) * int(y[1]))/2))
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
559 | B | Equivalent Strings | PROGRAMMING | 1,700 | [
"divide and conquer",
"hashing",
"sortings",
"strings"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 1,000 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,608,815,351 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 18 | 217 | 4,198,400 | from collections import Counter
s=str(input())
t=str(input())
n,m=len(s),len(t)
if n!=m:
print("NO")
elif n%2!=0:
if s==t:
print("YES")
else:
print("NO")
else:
v1=Counter(s[:n//2])
v2=Counter(s[n//2:])
v3=Counter(t[:n//2])
v4=Counter(t[n//2:])
if v1==v3 an... | Title: Equivalent Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split str... | ```python
from collections import Counter
s=str(input())
t=str(input())
n,m=len(s),len(t)
if n!=m:
print("NO")
elif n%2!=0:
if s==t:
print("YES")
else:
print("NO")
else:
v1=Counter(s[:n//2])
v2=Counter(s[n//2:])
v3=Counter(t[:n//2])
v4=Counter(t[n//2:])
if... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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