contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
934 | A | A Compatible Pair | PROGRAMMING | 1,400 | [
"brute force",
"games"
] | null | null | Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cracking noise, all of which frighten the monster out of coming.
Little Tommy has *n* lanterns and Big B... | The first line contains two space-separated integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=50).
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n*.
The third line contains *m* space-separated integers *b*1,<=*b*2,<=...,<=*b**m*.
All the integers range from <=-<=109 to 109. | Print a single integer — the brightness of the chosen pair. | [
"2 2\n20 18\n2 14\n",
"5 3\n-1 0 1 2 3\n-1 0 1\n"
] | [
"252\n",
"2\n"
] | In the first example, Tommy will hide 20 and Banban will choose 18 from Tommy and 14 from himself.
In the second example, Tommy will hide 3 and Banban will choose 2 from Tommy and 1 from himself. | 500 | [
{
"input": "2 2\n20 18\n2 14",
"output": "252"
},
{
"input": "5 3\n-1 0 1 2 3\n-1 0 1",
"output": "2"
},
{
"input": "10 2\n1 6 2 10 2 3 2 10 6 4\n5 7",
"output": "70"
},
{
"input": "50 50\n1 6 2 10 2 3 2 10 6 4 5 0 3 1 7 3 2 4 4 2 1 5 0 6 10 1 8 0 10 9 0 4 10 5 5 7 4 9 9 5 5 ... | 1,519,214,763 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 77 | 5,632,000 | x,y = [int(x) for x in input().split()]
a=[int(x) for x in input().split()]
b=[int(x) for x in input().split()]
choice1= max(a)*max(b)
choice2= min(a)*min(b)
if choice1 > choice2:
a.remove(max(a))
else:
a.remove(min(a))
choice1= max(a)*max(b)
choice2= min(a)*min(b)
if choice1 > choice2:
print(choice1)
e... | Title: A Compatible Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cr... | ```python
x,y = [int(x) for x in input().split()]
a=[int(x) for x in input().split()]
b=[int(x) for x in input().split()]
choice1= max(a)*max(b)
choice2= min(a)*min(b)
if choice1 > choice2:
a.remove(max(a))
else:
a.remove(min(a))
choice1= max(a)*max(b)
choice2= min(a)*min(b)
if choice1 > choice2:
print(c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
989 | B | A Tide of Riverscape | PROGRAMMING | 1,200 | [
"constructive algorithms",
"strings"
] | null | null | "Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.
Doubtfully, Kanno peeks a... | The first line contains two space-separated integers $n$ and $p$ ($1 \leq p \leq n \leq 2000$) — the length of the given string and the supposed period, respectively.
The second line contains a string $s$ of $n$ characters — Mino's records. $s$ only contains characters '0', '1' and '.', and contains at least one '.' c... | Output one line — if it's possible that $p$ is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)). | [
"10 7\n1.0.1.0.1.\n",
"10 6\n1.0.1.1000\n",
"10 9\n1........1\n"
] | [
"1000100010\n",
"1001101000\n",
"No\n"
] | In the first example, $7$ is not a period of the resulting string because the $1$-st and $8$-th characters of it are different.
In the second example, $6$ is not a period of the resulting string because the $4$-th and $10$-th characters of it are different.
In the third example, $9$ is always a period because the onl... | 1,000 | [
{
"input": "10 7\n1.0.1.0.1.",
"output": "1000100010"
},
{
"input": "10 6\n1.0.1.1000",
"output": "1001101000"
},
{
"input": "10 9\n1........1",
"output": "No"
},
{
"input": "1 1\n.",
"output": "No"
},
{
"input": "5 1\n0...1",
"output": "00001"
},
{
"i... | 1,528,725,386 | 1,286 | Python 3 | WRONG_ANSWER | PRETESTS | 1 | 77 | 0 | n, p = map(int, input().split())
a = list(input())
flag = 0
for i in range(n-p):
if flag:
break
if a[i]!=a[i+p]:
flag = 1
else:
if '.' in [ a[i], a[i+p] ]:
if a[i]=='.' and a[i+p]=='.':
a[i] = '1'
a[i+p] = '0'
flag = 1
elif a[i]=='.':
if a[i+p]=='0':
a[i] = '1'
... | Title: A Tide of Riverscape
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its... | ```python
n, p = map(int, input().split())
a = list(input())
flag = 0
for i in range(n-p):
if flag:
break
if a[i]!=a[i+p]:
flag = 1
else:
if '.' in [ a[i], a[i+p] ]:
if a[i]=='.' and a[i+p]=='.':
a[i] = '1'
a[i+p] = '0'
flag = 1
elif a[i]=='.':
if a[i+p]=='0':
a[i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
765 | B | Code obfuscation | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"strings"
] | null | null | Kostya likes Codeforces contests very much. However, he is very disappointed that his solutions are frequently hacked. That's why he decided to obfuscate (intentionally make less readable) his code before upcoming contest.
To obfuscate the code, Kostya first looks at the first variable name used in his program and rep... | In the only line of input there is a string *S* of lowercase English letters (1<=≤<=|*S*|<=≤<=500) — the identifiers of a program with removed whitespace characters. | If this program can be a result of Kostya's obfuscation, print "YES" (without quotes), otherwise print "NO". | [
"abacaba\n",
"jinotega\n"
] | [
"YES\n",
"NO\n"
] | In the first sample case, one possible list of identifiers would be "number string number character number string number". Here how Kostya would obfuscate the program:
- replace all occurences of number with a, the result would be "a string a character a string a",- replace all occurences of string with b, the result... | 1,000 | [
{
"input": "abacaba",
"output": "YES"
},
{
"input": "jinotega",
"output": "NO"
},
{
"input": "aaaaaaaaaaa",
"output": "YES"
},
{
"input": "aba",
"output": "YES"
},
{
"input": "bab",
"output": "NO"
},
{
"input": "a",
"output": "YES"
},
{
"in... | 1,524,654,615 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 77 | 7,065,600 | s = input()
alphabet = 'abcdefghijklmnopqrstuvwxyz'
unique_char = set(s)
print('YES' if ''.join(sorted(unique_char)) == alphabet[:len(unique_char)] else 'NO')
| Title: Code obfuscation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kostya likes Codeforces contests very much. However, he is very disappointed that his solutions are frequently hacked. That's why he decided to obfuscate (intentionally make less readable) his code before upcoming cont... | ```python
s = input()
alphabet = 'abcdefghijklmnopqrstuvwxyz'
unique_char = set(s)
print('YES' if ''.join(sorted(unique_char)) == alphabet[:len(unique_char)] else 'NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,649,939,670 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 124 | 5,734,400 | def checkSize(max_size, size):
if max_size < size:
return False
return True
n, max_size, d = [int(i) for i in input().split()]
inJucier = 0
result = 0
sizeList = input().split()
for i in range(n):
size = int(sizeList[i])
if checkSize(max_size, size):
if inJucier + size > d:
... | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
def checkSize(max_size, size):
if max_size < size:
return False
return True
n, max_size, d = [int(i) for i in input().split()]
inJucier = 0
result = 0
sizeList = input().split()
for i in range(n):
size = int(sizeList[i])
if checkSize(max_size, size):
if inJucier + size > d:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,523,282,335 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 78 | 7,065,600 | n = int(input())
arr = list(map(int, input().split()))
def minWatchingGame(arr):
if (arr[0] > 15):
return 15
for i in range(len(arr) - 1):
if (arr[i] + 15 < arr[i+1]):
return arr[i] + 15
return 90
print(minWatchingGame(arr))
| Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int(input())
arr = list(map(int, input().split()))
def minWatchingGame(arr):
if (arr[0] > 15):
return 15
for i in range(len(arr) - 1):
if (arr[i] + 15 < arr[i+1]):
return arr[i] + 15
return 90
print(minWatchingGame(arr))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,692,817,266 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 62 | 0 | e=int(input())
r=0
for i in [100,20,10,5,1]:
if e>=i:
r+=(e//i)
e=e-(e//i)*i
print(r) | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
e=int(input())
r=0
for i in [100,20,10,5,1]:
if e>=i:
r+=(e//i)
e=e-(e//i)*i
print(r)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,691,687,355 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 46 | 2,867,200 | t=int(input())
a=input()
c=0
c1=0
for i in range(a):
if i=='A':
c=c+1
elif i=='D':
c1=c1+1
if c==c1:
print("Friendship")
elif c>c1:
print("Anton")
else:
print("Danik") | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
t=int(input())
a=input()
c=0
c1=0
for i in range(a):
if i=='A':
c=c+1
elif i=='D':
c1=c1+1
if c==c1:
print("Friendship")
elif c>c1:
print("Anton")
else:
print("Danik")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
220 | B | Little Elephant and Array | PROGRAMMING | 1,800 | [
"constructive algorithms",
"data structures"
] | null | null | The Little Elephant loves playing with arrays. He has array *a*, consisting of *n* positive integers, indexed from 1 to *n*. Let's denote the number with index *i* as *a**i*.
Additionally the Little Elephant has *m* queries to the array, each query is characterised by a pair of integers *l**j* and *r**j* (1<=≤<=*l**j... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the size of array *a* and the number of queries to it. The next line contains *n* space-separated positive integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109). Next *m* lines contain descriptions of queries, one per line. T... | In *m* lines print *m* integers — the answers to the queries. The *j*-th line should contain the answer to the *j*-th query. | [
"7 2\n3 1 2 2 3 3 7\n1 7\n3 4\n"
] | [
"3\n1\n"
] | none | 1,000 | [
{
"input": "7 2\n3 1 2 2 3 3 7\n1 7\n3 4",
"output": "3\n1"
},
{
"input": "6 6\n1 2 2 3 3 3\n1 2\n2 2\n1 3\n2 4\n4 6\n1 6",
"output": "1\n0\n2\n1\n1\n3"
},
{
"input": "1 2\n1\n1 1\n1 1",
"output": "1\n1"
},
{
"input": "1 1\n1000000000\n1 1",
"output": "0"
}
] | 1,525,314,436 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 4,000 | 37,580,800 | from sys import stdin, stdout
from bisect import bisect_left
n, m = stdin.readline().split()
n = int(n)
m = int(m)
idx = {}
for i, a in enumerate(stdin.readline().split()):
a = int(a)
if a <= n:
v = idx.setdefault(a, [])
v.append(i)
nope = set()
for a, v in idx.items():
if a > len(v):
... | Title: Little Elephant and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves playing with arrays. He has array *a*, consisting of *n* positive integers, indexed from 1 to *n*. Let's denote the number with index *i* as *a**i*.
Additionally the Little Elephant... | ```python
from sys import stdin, stdout
from bisect import bisect_left
n, m = stdin.readline().split()
n = int(n)
m = int(m)
idx = {}
for i, a in enumerate(stdin.readline().split()):
a = int(a)
if a <= n:
v = idx.setdefault(a, [])
v.append(i)
nope = set()
for a, v in idx.items():
if a >... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
650 | A | Watchmen | PROGRAMMING | 1,400 | [
"data structures",
"geometry",
"math"
] | null | null | Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manha... | The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide. | Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel. | [
"3\n1 1\n7 5\n1 5\n",
"6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n"
] | [
"2\n",
"11\n"
] | In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs... | 500 | [
{
"input": "3\n1 1\n7 5\n1 5",
"output": "2"
},
{
"input": "6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1",
"output": "11"
},
{
"input": "10\n46 -55\n46 45\n46 45\n83 -55\n46 45\n83 -55\n46 45\n83 45\n83 45\n46 -55",
"output": "33"
},
{
"input": "1\n-5 -90",
"output": "0"
},
{
... | 1,578,390,066 | 2,147,483,647 | PyPy 3 | OK | TESTS | 71 | 2,090 | 34,508,800 | from collections import Counter
n = int(input())
x_c = Counter()
y_c = Counter()
coords_c = Counter()
ans = 0
for _ in range(n):
x, y = map(int, input().split())
ans += x_c[x]
ans += y_c[y]
ans -= coords_c[(x, y)]
x_c[x] += 1
y_c[y] += 1
coords_c[(x, y)] += 1
print(ans) | Title: Watchmen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They n... | ```python
from collections import Counter
n = int(input())
x_c = Counter()
y_c = Counter()
coords_c = Counter()
ans = 0
for _ in range(n):
x, y = map(int, input().split())
ans += x_c[x]
ans += y_c[y]
ans -= coords_c[(x, y)]
x_c[x] += 1
y_c[y] += 1
coords_c[(x, y)] += 1
print(an... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,633,981,650 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 92 | 0 | a = list(map(int , input('').split()))
dat = sorted(list(map(int , input('').split())))
while dat[a[1]] > 0:
a[1] -= 1
print(abs(sum(dat[0:a[1]])))
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
a = list(map(int , input('').split()))
dat = sorted(list(map(int , input('').split())))
while dat[a[1]] > 0:
a[1] -= 1
print(abs(sum(dat[0:a[1]])))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,679,380,313 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 50 | 62 | 1,843,200 | n,m=map(int,input().split())
l=[]
ans="#Black&White"
for i in range(n):
s=list(input().split())
for k in s:
if k=="C" or k=="M" or k=="Y":
ans="#Color"
print(ans)
| Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
n,m=map(int,input().split())
l=[]
ans="#Black&White"
for i in range(n):
s=list(input().split())
for k in s:
if k=="C" or k=="M" or k=="Y":
ans="#Color"
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,649,001,954 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | def solve(lemons, apples, pears):
oneCompote = 1 + 2 + 4
l = lemons/1
a = apples/2
p = pears/4
return min(l,a,p) * oneCompote
lemons = int(input())
apples = int(input())
pears = int(input())
print(solve(lemons, apples, pears)) | Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
def solve(lemons, apples, pears):
oneCompote = 1 + 2 + 4
l = lemons/1
a = apples/2
p = pears/4
return min(l,a,p) * oneCompote
lemons = int(input())
apples = int(input())
pears = int(input())
print(solve(lemons, apples, pears))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
955 | A | Feed the cat | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without food increases his hunger by *D* points.
At any time Andrew can visit the store where tasty buns are... | The first line contains two integers *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59) — the time of Andrew's awakening.
The second line contains four integers *H*, *D*, *C* and *N* (1<=≤<=*H*<=≤<=105,<=1<=≤<=*D*,<=*C*,<=*N*<=≤<=102). | Output the minimum amount of money to within three decimal digits. You answer is considered correct, if its absolute or relative error does not exceed 10<=-<=4.
Formally, let your answer be *a*, and the jury's answer be *b*. Your answer is considered correct if . | [
"19 00\n255 1 100 1\n",
"17 41\n1000 6 15 11\n"
] | [
"25200.0000\n",
"1365.0000\n"
] | In the first sample Andrew can visit the store at exactly 20:00. The cat's hunger will be equal to 315, hence it will be necessary to purchase 315 buns. The discount makes the final answer 25200 roubles.
In the second sample it's optimal to visit the store right after he wakes up. Then he'll have to buy 91 bins per 15... | 500 | [
{
"input": "19 00\n255 1 100 1",
"output": "25200.0000"
},
{
"input": "17 41\n1000 6 15 11",
"output": "1365.0000"
},
{
"input": "16 34\n61066 14 50 59",
"output": "43360.0000"
},
{
"input": "18 18\n23331 86 87 41",
"output": "49590.0000"
},
{
"input": "10 48\n684... | 1,521,827,667 | 4,767 | Python 3 | WRONG_ANSWER | PRETESTS | 7 | 124 | 8,192,000 | #author:@karngyan
FMT='%H:%M'
from datetime import datetime
import math
def calc(hh,mm,h,d,c,n,s,s2):
a=1000000000000.0
b=(math.ceil(h/n)*c)
if(hh<20):
extra=datetime.strptime(s2,FMT)-datetime.strptime(s,FMT)
extra=extra.seconds
extra/=60
h+=(d*extra)
a=... | Title: Feed the cat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without foo... | ```python
#author:@karngyan
FMT='%H:%M'
from datetime import datetime
import math
def calc(hh,mm,h,d,c,n,s,s2):
a=1000000000000.0
b=(math.ceil(h/n)*c)
if(hh<20):
extra=datetime.strptime(s2,FMT)-datetime.strptime(s,FMT)
extra=extra.seconds
extra/=60
h+=(d*extra)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
317 | A | Perfect Pair | PROGRAMMING | 1,600 | [
"brute force"
] | null | null | Let us call a pair of integer numbers *m*-perfect, if at least one number in the pair is greater than or equal to *m*. Thus, the pairs (3, 3) and (0, 2) are 2-perfect while the pair (-1, 1) is not.
Two integers *x*, *y* are written on the blackboard. It is allowed to erase one of them and replace it with the sum of th... | Single line of the input contains three integers *x*, *y* and *m* (<=-<=1018<=≤<=*x*, *y*, *m*<=≤<=1018).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preffered to use the cin, cout streams or the %I64d specifier. | Print the minimum number of operations or "-1" (without quotes), if it is impossible to transform the given pair to the *m*-perfect one. | [
"1 2 5\n",
"-1 4 15\n",
"0 -1 5\n"
] | [
"2\n",
"4\n",
"-1\n"
] | In the first sample the following sequence of operations is suitable: (1, 2) <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> (3, 2) <img align="middle" class="tex-formula" src="https://espresso.cod... | 500 | [
{
"input": "1 2 5",
"output": "2"
},
{
"input": "-1 4 15",
"output": "4"
},
{
"input": "0 -1 5",
"output": "-1"
},
{
"input": "0 1 8",
"output": "5"
},
{
"input": "-134 -345 -134",
"output": "0"
},
{
"input": "-134 -345 -133",
"output": "-1"
},
... | 1,371,229,333 | 5,533 | Python 3 | WRONG_ANSWER | TESTS | 54 | 93 | 102,400 | A, B, C = map(int, input().split())
ans = 0
if A > B:
temp = A
A = B
B = temp
if B >= C:
print(0)
exit(0)
if A <= 0 and B <= 0:
print(-1)
exit(0)
if A < 0:
ans = (-A) // B
A = A + ans * B
for i in range(1, 1000000000):
if A + B >= C:
print(ans + i);
exit(0)
temp = A + B
A = B
B... | Title: Perfect Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let us call a pair of integer numbers *m*-perfect, if at least one number in the pair is greater than or equal to *m*. Thus, the pairs (3, 3) and (0, 2) are 2-perfect while the pair (-1, 1) is not.
Two integers *x*, *y* a... | ```python
A, B, C = map(int, input().split())
ans = 0
if A > B:
temp = A
A = B
B = temp
if B >= C:
print(0)
exit(0)
if A <= 0 and B <= 0:
print(-1)
exit(0)
if A < 0:
ans = (-A) // B
A = A + ans * B
for i in range(1, 1000000000):
if A + B >= C:
print(ans + i);
exit(0)
temp = A + B
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
676 | C | Vasya and String | PROGRAMMING | 1,500 | [
"binary search",
"dp",
"strings",
"two pointers"
] | null | null | High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequence) consisting of equal letters.
Vasya can change no more than *k* characters of the original strin... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000,<=0<=≤<=*k*<=≤<=*n*) — the length of the string and the maximum number of characters to change.
The second line contains the string, consisting of letters 'a' and 'b' only. | Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than *k* characters. | [
"4 2\nabba\n",
"8 1\naabaabaa\n"
] | [
"4\n",
"5\n"
] | In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".
In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa". | 1,500 | [
{
"input": "4 2\nabba",
"output": "4"
},
{
"input": "8 1\naabaabaa",
"output": "5"
},
{
"input": "1 0\na",
"output": "1"
},
{
"input": "1 1\nb",
"output": "1"
},
{
"input": "1 0\nb",
"output": "1"
},
{
"input": "1 1\na",
"output": "1"
},
{
... | 1,676,608,289 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | inputs = [int(num) for num in input().split()]
n = inputs[0]
k = inputs[1]
s = input()
i=0
j=0
c=0
max1=0
Temp =k
while(j<len(s)):
if(s[j]=="a"):
c+=1
else:
if(Temp>0):
Temp -= 1
c += 1
else:
while(s[i]!="b"):
i += 1
c -... | Title: Vasya and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequ... | ```python
inputs = [int(num) for num in input().split()]
n = inputs[0]
k = inputs[1]
s = input()
i=0
j=0
c=0
max1=0
Temp =k
while(j<len(s)):
if(s[j]=="a"):
c+=1
else:
if(Temp>0):
Temp -= 1
c += 1
else:
while(s[i]!="b"):
i += 1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
6 | C | Alice, Bob and Chocolate | PROGRAMMING | 1,200 | [
"greedy",
"two pointers"
] | C. Alice, Bob and Chocolate | 2 | 64 | Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them wi... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the amount of bars on the table. The second line contains a sequence *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000), where *t**i* is the time (in seconds) needed to consume the *i*-th bar (in the order from left to right). | Print two numbers *a* and *b*, where *a* is the amount of bars consumed by Alice, and *b* is the amount of bars consumed by Bob. | [
"5\n2 9 8 2 7\n"
] | [
"2 3\n"
] | none | 0 | [
{
"input": "5\n2 9 8 2 7",
"output": "2 3"
},
{
"input": "1\n1",
"output": "1 0"
},
{
"input": "2\n1 1",
"output": "1 1"
},
{
"input": "3\n1 1 1",
"output": "2 1"
},
{
"input": "4\n1 1 1 1",
"output": "2 2"
},
{
"input": "1\n6",
"output": "1 0"
}... | 1,674,752,504 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 1 | 154 | 3,481,600 | n = int(input())
arr = list(map(int, input().split()))
a, b = 0 , 0
start, end = 0, n-1
c_a, c_b = 0, 0
while start < end:
if a <= b:
a += arr[start]
c_a += 1
start+=1
here = True
else:
b += arr[end]
c_b += 1
end -= 1
here = Fals... | Title: Alice, Bob and Chocolate
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. Fo... | ```python
n = int(input())
arr = list(map(int, input().split()))
a, b = 0 , 0
start, end = 0, n-1
c_a, c_b = 0, 0
while start < end:
if a <= b:
a += arr[start]
c_a += 1
start+=1
here = True
else:
b += arr[end]
c_b += 1
end -= 1
h... | -1 | MatrixStudio/Codeforces-Python-Submissions |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of int... | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,656,800,124 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | import sys
res=0
n,m=map(int,input().split())
for i in 1000:
for j in 1000:
if i**2 + j ==n and i + j**2 ==m:
res+=1
sys.stdout.write(str(res)) | Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immedi... | ```python
import sys
res=0
n,m=map(int,input().split())
for i in 1000:
for j in 1000:
if i**2 + j ==n and i + j**2 ==m:
res+=1
sys.stdout.write(str(res))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
808 | A | Lucky Year | PROGRAMMING | 900 | [
"implementation"
] | null | null | Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland. | Output amount of years from the current year to the next lucky one. | [
"4\n",
"201\n",
"4000\n"
] | [
"1\n",
"99\n",
"1000\n"
] | In the first example next lucky year is 5. In the second one — 300. In the third — 5000. | 0 | [
{
"input": "4",
"output": "1"
},
{
"input": "201",
"output": "99"
},
{
"input": "4000",
"output": "1000"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "1",
"output": "1"
},
{
"input": "100000000",
"ou... | 1,646,251,941 | 2,147,483,647 | PyPy 3 | OK | TESTS | 271 | 78 | 0 | s = input()
print(int(str(int(s[0]) + 1) + '0' * (len(s) - 1)) - int(s))
| Title: Lucky Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 1... | ```python
s = input()
print(int(str(int(s[0]) + 1) + '0' * (len(s) - 1)) - int(s))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,598,499,968 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 26 | 500 | 1,433,600 | def Sort(sub_li):
sub_li.sort(key = lambda x: x[1])
return sub_li
n , m = map(int,input().split())
mapped =[]
for i in range(m):
mapped.append(list(map(int,input().split(" "))))
mapped = Sort(mapped)
mapped.reverse()
result =0
for a,b in mapped:
for i in range(a):
if n>0:... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
def Sort(sub_li):
sub_li.sort(key = lambda x: x[1])
return sub_li
n , m = map(int,input().split())
mapped =[]
for i in range(m):
mapped.append(list(map(int,input().split(" "))))
mapped = Sort(mapped)
mapped.reverse()
result =0
for a,b in mapped:
for i in range(a):
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,585,707,698 | 2,147,483,647 | PyPy 3 | OK | TESTS | 8 | 155 | 0 | #-------------Program--------------
#----Kuzlyaev-Nikita-Codeforces----
#-------------Training-------------
#----------------------------------
n=int(input())
for i in range(n):
x=int(input())
for j in range(15):
if 7*j>x:
print("NO")
break
if (x-7*j)%3==0:
... | Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chun... | ```python
#-------------Program--------------
#----Kuzlyaev-Nikita-Codeforces----
#-------------Training-------------
#----------------------------------
n=int(input())
for i in range(n):
x=int(input())
for j in range(15):
if 7*j>x:
print("NO")
break
if (x-7*... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
117 | A | Elevator | PROGRAMMING | 1,300 | [
"implementation",
"math"
] | null | null | And now the numerous qualifying tournaments for one of the most prestigious Russian contests Russian Codec Cup are over. All *n* participants who have made it to the finals found themselves in a huge *m*-floored 108-star hotel. Of course the first thought to come in a place like this is "How about checking out the elev... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*<=≤<=105,<=2<=≤<=*m*<=≤<=108).
Next *n* lines contain information about the participants in the form of three space-separated integers *s**i* *f**i* *t**i* (1<=≤<=*s**i*,<=*f**i*<=≤<=*m*,<=0<=≤<=*t**i*<=≤<=108), described in the problem statem... | Print *n* lines each containing one integer — the time of the arrival for each participant to the required floor. | [
"7 4\n2 4 3\n1 2 0\n2 2 0\n1 2 1\n4 3 5\n1 2 2\n4 2 0\n",
"5 5\n1 5 4\n1 3 1\n1 3 4\n3 1 5\n4 2 5\n"
] | [
"9\n1\n0\n7\n10\n7\n5\n",
"12\n10\n10\n8\n7\n"
] | Let's consider the first sample. The first participant starts at floor *s* = 2 by the time equal to *t* = 3. To get to the floor *f* = 4, he has to wait until the time equals 7, that's the time when the elevator will go upwards for the second time. Then the first participant should get on the elevator and go two floors... | 500 | [
{
"input": "7 4\n2 4 3\n1 2 0\n2 2 0\n1 2 1\n4 3 5\n1 2 2\n4 2 0",
"output": "9\n1\n0\n7\n10\n7\n5"
},
{
"input": "5 5\n1 5 4\n1 3 1\n1 3 4\n3 1 5\n4 2 5",
"output": "12\n10\n10\n8\n7"
},
{
"input": "5 5\n1 3 4\n4 4 2\n3 2 1\n2 4 0\n1 5 3",
"output": "10\n2\n7\n3\n12"
},
{
"i... | 1,454,933,215 | 1,915 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 |
n, m = map(int, input().split())
for _ in range(n):
s, f, t = map(int, input().split())
result = t
t_cut = t % (2 * (m - 1))
if s == f:
result = t
elif t_cut >= (m - 1):
if 2 * (m - 1) - t_cut < (s - 1):
result += 2 * (m - 1) - ((s - 1) - (2 * (m - 1) - t_cut))
... | Title: Elevator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
And now the numerous qualifying tournaments for one of the most prestigious Russian contests Russian Codec Cup are over. All *n* participants who have made it to the finals found themselves in a huge *m*-floored 108-star hotel... | ```python
n, m = map(int, input().split())
for _ in range(n):
s, f, t = map(int, input().split())
result = t
t_cut = t % (2 * (m - 1))
if s == f:
result = t
elif t_cut >= (m - 1):
if 2 * (m - 1) - t_cut < (s - 1):
result += 2 * (m - 1) - ((s - 1) - (2 * (m - 1) - t_cut... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
377 | A | Maze | PROGRAMMING | 1,600 | [
"dfs and similar"
] | null | null | Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to a... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=<<=*s*), where *n* and *m* are the maze's height and width, correspondingly, *k* is the number of walls Pavel wants to add and letter *s* represents the number of empty cells in the original maze.
Each of the next *n* lines co... | Print *n* lines containing *m* characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").
It is guaranteed that a solution exists. If there are multiple solutions you can output any of t... | [
"3 4 2\n#..#\n..#.\n#...\n",
"5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#\n"
] | [
"#.X#\nX.#.\n#...\n",
"#XXX\n#X#.\nX#..\n...#\n.#.#\n"
] | none | 500 | [
{
"input": "5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#",
"output": "#XXX\n#X#.\nX#..\n...#\n.#.#"
},
{
"input": "3 3 2\n#.#\n...\n#.#",
"output": "#X#\nX..\n#.#"
},
{
"input": "7 7 18\n#.....#\n..#.#..\n.#...#.\n...#...\n.#...#.\n..#.#..\n#.....#",
"output": "#XXXXX#\nXX#X#X.\nX#XXX#.\nXXX#... | 1,654,139,249 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 217 | 12,492,800 | import math
from collections import Counter, deque
from sys import stdout
import time
from math import factorial, log, gcd
import sys
def S():
return sys.stdin.readline().split()
def I():
return [int(i) for i in sys.stdin.readline().split()]
def II():
return int(sys.stdin.readline())
... | Title: Maze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze w... | ```python
import math
from collections import Counter, deque
from sys import stdout
import time
from math import factorial, log, gcd
import sys
def S():
return sys.stdin.readline().split()
def I():
return [int(i) for i in sys.stdin.readline().split()]
def II():
return int(sys.stdin.re... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,604,946,930 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 93 | 307,200 | l=list(map(int,input().split()))
d={}
for i in l:
if not i in d:
d[i]=0
d[i]+=1
flag = None
for (k, v) in d.items():
if v >= 4:
flag = k
break
if not flag:
print('Alien')
else:
if d[k] == 4:
d.pop(k)
else:
d[k] -= 4
i... | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
l=list(map(int,input().split()))
d={}
for i in l:
if not i in d:
d[i]=0
d[i]+=1
flag = None
for (k, v) in d.items():
if v >= 4:
flag = k
break
if not flag:
print('Alien')
else:
if d[k] == 4:
d.pop(k)
else:
d[k] -=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Три брата договорились о встрече. Пронумеруем братьев следующим образом: пусть старший брат имеет номер 1, средний брат имеет номер 2, а младший брат — номер 3.
Когда пришло время встречи, один из братьев опоздал. По заданным номерам двух братьев, которые пришли вовремя, вам предстоит определить номер опоздавшего бра... | В первой строке входных данных следуют два различных целых числа *a* и *b* (1<=≤<=*a*,<=*b*<=≤<=3, *a*<=≠<=*b*) — номера братьев, которые пришли на встречу вовремя. Номера даны в произвольном порядке. | Выведите единственное целое число — номер брата, который опоздал на встречу. | [
"3 1\n"
] | [
"2\n"
] | none | 0 | [
{
"input": "3 1",
"output": "2"
},
{
"input": "2 1",
"output": "3"
},
{
"input": "2 3",
"output": "1"
},
{
"input": "1 2",
"output": "3"
},
{
"input": "1 3",
"output": "2"
},
{
"input": "3 2",
"output": "1"
}
] | 1,458,733,394 | 164,593 | PyPy 3 | OK | TESTS | 6 | 124 | 23,040,000 | a, b = map(int, input().split())
p = [1, 2, 3]
p.remove(a)
p.remove(b)
print(p[0])
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Три брата договорились о встрече. Пронумеруем братьев следующим образом: пусть старший брат имеет номер 1, средний брат имеет номер 2, а младший брат — номер 3.
Когда пришло время встречи, один из братьев опоздал. По заданным но... | ```python
a, b = map(int, input().split())
p = [1, 2, 3]
p.remove(a)
p.remove(b)
print(p[0])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given two integers $a$ and $b$. Moreover, you are given a sequence $s_0, s_1, \dots, s_{n}$. All values in $s$ are integers $1$ or $-1$. It's known that sequence is $k$-periodic and $k$ divides $n+1$. In other words, for each $k \leq i \leq n$ it's satisfied that $s_{i} = s_{i - k}$.
Find out the non-negative ... | The first line contains four integers $n, a, b$ and $k$ $(1 \leq n \leq 10^{9}, 1 \leq a, b \leq 10^{9}, 1 \leq k \leq 10^{5})$.
The second line contains a sequence of length $k$ consisting of characters '+' and '-'.
If the $i$-th character (0-indexed) is '+', then $s_{i} = 1$, otherwise $s_{i} = -1$.
Note that onl... | Output a single integer — value of given expression modulo $10^{9} + 9$. | [
"2 2 3 3\n+-+\n",
"4 1 5 1\n-\n"
] | [
"7\n",
"999999228\n"
] | In the first example:
$(\sum \limits_{i=0}^{n} s_{i} a^{n - i} b^{i})$ = $2^{2} 3^{0} - 2^{1} 3^{1} + 2^{0} 3^{2}$ = 7
In the second example:
$(\sum \limits_{i=0}^{n} s_{i} a^{n - i} b^{i}) = -1^{4} 5^{0} - 1^{3} 5^{1} - 1^{2} 5^{2} - 1^{1} 5^{3} - 1^{0} 5^{4} = -781 \equiv 999999228 \pmod{10^{9} + 9}$. | 0 | [
{
"input": "2 2 3 3\n+-+",
"output": "7"
},
{
"input": "4 1 5 1\n-",
"output": "999999228"
},
{
"input": "1 1 4 2\n-+",
"output": "3"
},
{
"input": "3 1 4 4\n+--+",
"output": "45"
},
{
"input": "5 1 1 6\n++---+",
"output": "0"
},
{
"input": "5 2 2 6\n+... | 1,523,977,007 | 3,107 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 6 | 1,000 | 7,168,000 | def val(c):
if c == '+':
return 1
else:
return -1
def calculate(seq, n, a, b):
total = 0
for i in range(n + 1):
v = val(seq[i % k]) * (a ** (n - i)) * (b ** i)
total += v
return total
[n, a, b, k] = [int(x) for x in input().split(' ')]
sequence =... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers $a$ and $b$. Moreover, you are given a sequence $s_0, s_1, \dots, s_{n}$. All values in $s$ are integers $1$ or $-1$. It's known that sequence is $k$-periodic and $k$ divides $n+1$. In other words, for e... | ```python
def val(c):
if c == '+':
return 1
else:
return -1
def calculate(seq, n, a, b):
total = 0
for i in range(n + 1):
v = val(seq[i % k]) * (a ** (n - i)) * (b ** i)
total += v
return total
[n, a, b, k] = [int(x) for x in input().split(' ')]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works... | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,604,232,603 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 186 | 307,200 | n=int(input())
print(n,end=' ')
for i in range(0,n-1):
print(i+1,sep=' ')
| Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the perm... | ```python
n=int(input())
print(n,end=' ')
for i in range(0,n-1):
print(i+1,sep=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
5 | C | Longest Regular Bracket Sequence | PROGRAMMING | 1,900 | [
"constructive algorithms",
"data structures",
"dp",
"greedy",
"sortings",
"strings"
] | C. Longest Regular Bracket Sequence | 2 | 256 | This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical expression. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.... | The first line of the input file contains a non-empty string, consisting of «(» and «)» characters. Its length does not exceed 106. | Print the length of the longest substring that is a regular bracket sequence, and the number of such substrings. If there are no such substrings, write the only line containing "0 1". | [
")((())))(()())\n",
"))(\n"
] | [
"6 2\n",
"0 1\n"
] | none | 0 | [
{
"input": ")((())))(()())",
"output": "6 2"
},
{
"input": "))(",
"output": "0 1"
},
{
"input": "()(())()",
"output": "8 1"
},
{
"input": "((((()(((",
"output": "2 1"
},
{
"input": "))))()())))",
"output": "4 1"
},
{
"input": "(()())()(())()()())())()(... | 1,385,051,090 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | t = [-1] + [[-1, 1][i == '('] for i in input()] + [1]
s, n = t[:], len(t)
for i in range(n - 1): s[i + 1] += s[i]
a, b = min(s), max(s)
p = [-1] * (b - a + 1)
k = l = 0
for i in range(n - 1):
x, y, j = t[i], t[i + 1], s[i] - a
if x < 0:
if p[j] >= 0:
d = i - p[j]
if d ... | Title: Longest Regular Bracket Sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical exp... | ```python
t = [-1] + [[-1, 1][i == '('] for i in input()] + [1]
s, n = t[:], len(t)
for i in range(n - 1): s[i + 1] += s[i]
a, b = min(s), max(s)
p = [-1] * (b - a + 1)
k = l = 0
for i in range(n - 1):
x, y, j = t[i], t[i + 1], s[i] - a
if x < 0:
if p[j] >= 0:
d = i - p[j]
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,641,495,400 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | l = int(input('L : '))
temp = []
for i in range(l):
n = int(input('n : '))
if n not in temp and n != 0:
temp.append(n)
print(len(temp))
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
l = int(input('L : '))
temp = []
for i in range(l):
n = int(input('n : '))
if n not in temp and n != 0:
temp.append(n)
print(len(temp))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
566 | A | Matching Names | PROGRAMMING | 2,300 | [
"dfs and similar",
"strings",
"trees"
] | null | null | Teachers of one programming summer school decided to make a surprise for the students by giving them names in the style of the "Hobbit" movie. Each student must get a pseudonym maximally similar to his own name. The pseudonym must be a name of some character of the popular saga and now the teachers are busy matching ps... | The first line contains number *n* (1<=≤<=*n*<=≤<=100<=000) — the number of students in the summer school.
Next *n* lines contain the name of the students. Each name is a non-empty word consisting of lowercase English letters. Some names can be repeating.
The last *n* lines contain the given pseudonyms. Each pseudony... | In the first line print the maximum possible quality of matching pseudonyms to students.
In the next *n* lines describe the optimal matching. Each line must have the form *a* *b* (1<=≤<=*a*,<=*b*<=≤<=*n*), that means that the student who was number *a* in the input, must match to the pseudonym number *b* in the input.... | [
"5\ngennady\ngalya\nboris\nbill\ntoshik\nbilbo\ntorin\ngendalf\nsmaug\ngaladriel\n"
] | [
"11\n4 1\n2 5\n1 3\n5 2\n3 4\n"
] | The first test from the statement the match looks as follows:
- bill → bilbo (lcp = 3) - galya → galadriel (lcp = 3) - gennady → gendalf (lcp = 3) - toshik → torin (lcp = 2) - boris → smaug (lcp = 0) | 1,750 | [
{
"input": "5\ngennady\ngalya\nboris\nbill\ntoshik\nbilbo\ntorin\ngendalf\nsmaug\ngaladriel",
"output": "11\n4 1\n2 5\n1 3\n5 2\n3 4"
},
{
"input": "1\na\na",
"output": "1\n1 1"
},
{
"input": "2\na\na\na\na",
"output": "2\n1 1\n2 2"
},
{
"input": "2\na\nb\na\na",
"output"... | 1,586,839,173 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | s = int(input())
n = str(input())
nol = n.count("0")
satu = n.count("1")
while True:
if satu == 0 or nol ==0:
break
nol -= 1
satu -=1
if satu == 0 or nol == 0:
break
if nol == 0:
print(satu)
elif satu ==0 :
print(nol)
print (nol)
else :
print("0")
| Title: Matching Names
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Teachers of one programming summer school decided to make a surprise for the students by giving them names in the style of the "Hobbit" movie. Each student must get a pseudonym maximally similar to his own name. The pseu... | ```python
s = int(input())
n = str(input())
nol = n.count("0")
satu = n.count("1")
while True:
if satu == 0 or nol ==0:
break
nol -= 1
satu -=1
if satu == 0 or nol == 0:
break
if nol == 0:
print(satu)
elif satu ==0 :
print(nol)
print (nol)
else :
print("0")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercise... | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the mos... | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,645,088,782 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 92 | 0 | n = int(input())
s = input()
s = s.split()
c = 0
b = 0
p = 0
for i in range(0,n,3):
c = c + int(s[i])
for i in range(1,n,3):
p = p + int(s[i])
for i in range(2,n,3):
b = b + int(s[i])
if c > p and c > b:
print("chest")
elif p > c and p > b:
print("biceps")
elif b > c and b > p:
... | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg ... | ```python
n = int(input())
s = input()
s = s.split()
c = 0
b = 0
p = 0
for i in range(0,n,3):
c = c + int(s[i])
for i in range(1,n,3):
p = p + int(s[i])
for i in range(2,n,3):
b = b + int(s[i])
if c > p and c > b:
print("chest")
elif p > c and p > b:
print("biceps")
elif b > c and b ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,691,378,814 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | a = int(input())
b = list(map(int,input().split()))
c = list(map(int,input().split()))
d = list(map(int,input().split()))
b.sort()
c.sort()
d.sort()
tmp = 0
for i in range(a-1):
if b[i]!=c[i]:
print(b[i])
tmp = 1
break
if tmp == 0:
print(b[-1])
tmp = 0
for i in range(a-2)... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
a = int(input())
b = list(map(int,input().split()))
c = list(map(int,input().split()))
d = list(map(int,input().split()))
b.sort()
c.sort()
d.sort()
tmp = 0
for i in range(a-1):
if b[i]!=c[i]:
print(b[i])
tmp = 1
break
if tmp == 0:
print(b[-1])
tmp = 0
for i in ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,605,455,047 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 109 | 0 | a = input()
b = input()
ans = ''
for i,j in zip(a,b):
ans += str(int(i)^int(j))
print(ans)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
a = input()
b = input()
ans = ''
for i,j in zip(a,b):
ans += str(int(i)^int(j))
print(ans)
``` | 3.97275 | MatrixStudio/Codeforces-Python-Submissions |
936 | C | Lock Puzzle | PROGRAMMING | 2,300 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | Welcome to another task about breaking the code lock! Explorers Whitfield and Martin came across an unusual safe, inside of which, according to rumors, there are untold riches, among which one can find the solution of the problem of discrete logarithm!
Of course, there is a code lock is installed on the safe. The lock... | The first line contains an integer *n*, the length of the strings *s* and *t* (1<=≤<=*n*<=≤<=2<=000).
After that, there are two strings *s* and *t*, consisting of *n* lowercase Latin letters each. | If it is impossible to get string *t* from string *s* using no more than 6100 operations «shift», print a single number <=-<=1.
Otherwise, in the first line output the number of operations *k* (0<=≤<=*k*<=≤<=6100). In the next line output *k* numbers *x**i* corresponding to the operations «shift *x**i*» (0<=≤<=*x**i*<... | [
"6\nabacbb\nbabcba\n",
"3\naba\nbba\n"
] | [
"4\n6 3 2 3\n",
"-1\n"
] | none | 1,500 | [
{
"input": "6\nabacbb\nbabcba",
"output": "13\n2 6 1 4 0 3 6 3 1 1 1 5 6 "
},
{
"input": "3\naba\nbba",
"output": "-1"
},
{
"input": "1\nw\nw",
"output": "2\n0 1 "
},
{
"input": "2\nvb\nvb",
"output": "2\n1 1 "
},
{
"input": "7\nvhypflg\nvprhfly",
"output": "-... | 1,556,365,268 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 109 | 0 | def shift(x, s):
lens = len(s)
s1 = s[0:lens-x]
s2 = s[lens-x:lens]
s2= s2[::-1]
s=s2+s1
def get():
len = int(input())
s=input()
t=input()
list_out = []
out = 0
suma = 0
sumb = 0
for item in s:
suma +=ord(item)
for item in t:
sumb +=ord(item)
... | Title: Lock Puzzle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Welcome to another task about breaking the code lock! Explorers Whitfield and Martin came across an unusual safe, inside of which, according to rumors, there are untold riches, among which one can find the solution of the p... | ```python
def shift(x, s):
lens = len(s)
s1 = s[0:lens-x]
s2 = s[lens-x:lens]
s2= s2[::-1]
s=s2+s1
def get():
len = int(input())
s=input()
t=input()
list_out = []
out = 0
suma = 0
sumb = 0
for item in s:
suma +=ord(item)
for item in t:
sumb +=ord... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,602,958,279 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | def checkword(newword):
i=0
try:
while newword[i] != None:
if newword[i] not in "hello":
newword = newword.replace(newword[i],"0")
i+=1
except:
if newword[0:4] == "hell" and newword[-1] == "o":
return "YES"
else:
re... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def checkword(newword):
i=0
try:
while newword[i] != None:
if newword[i] not in "hello":
newword = newword.replace(newword[i],"0")
i+=1
except:
if newword[0:4] == "hell" and newword[-1] == "o":
return "YES"
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,682,508,125 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n=input();a=(n%2*5+4);print a,n-a | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n=input();a=(n%2*5+4);print a,n-a
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,612,718,718 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 109 | 1,433,600 | a,b = map(int,input().split())
s = b
ctr = 0
for i in range(a):
k,t = input().split()
if k == "+":
s+=int(t)
elif k == "-" and s-int(t) > 0:
s-=int(t)
elif k =="-" and s-int(t) < 0:
ctr+=1
print(s,ctr,end=" ")
| Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
a,b = map(int,input().split())
s = b
ctr = 0
for i in range(a):
k,t = input().split()
if k == "+":
s+=int(t)
elif k == "-" and s-int(t) > 0:
s-=int(t)
elif k =="-" and s-int(t) < 0:
ctr+=1
print(s,ctr,end=" ")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
495 | B | Modular Equations | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Last week, Hamed learned about a new type of equations in his math class called Modular Equations. Lets define *i* modulo *j* as the remainder of division of *i* by *j* and denote it by . A Modular Equation, as Hamed's teacher described, is an equation of the form in which *a* and *b* are two non-negative integers and... | In the only line of the input two space-separated integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=109) are given. | If there is an infinite number of answers to our equation, print "infinity" (without the quotes). Otherwise print the number of solutions of the Modular Equation . | [
"21 5\n",
"9435152 272\n",
"10 10\n"
] | [
"2\n",
"282\n",
"infinity\n"
] | In the first sample the answers of the Modular Equation are 8 and 16 since <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/6f5ff39ebd209bf990adaf91f4b82f9687097224.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "21 5",
"output": "2"
},
{
"input": "9435152 272",
"output": "282"
},
{
"input": "10 10",
"output": "infinity"
},
{
"input": "0 1000000000",
"output": "0"
},
{
"input": "11 2",
"output": "2"
},
{
"input": "1 0",
"output": "1"
},
{
... | 1,602,014,580 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 202 | 2,150,400 | a = int(input())
b = int(input())
if a==b:
print("infinity")
else:
resp = 0;
n = a - b
m = a - b
while n*n >= m and n > b:
if m % n == 0:
resp+=1
if (m/n > b and m/n != n):
resp+=1
n-=1
print(resp)
| Title: Modular Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Last week, Hamed learned about a new type of equations in his math class called Modular Equations. Lets define *i* modulo *j* as the remainder of division of *i* by *j* and denote it by . A Modular Equation, as Hamed'... | ```python
a = int(input())
b = int(input())
if a==b:
print("infinity")
else:
resp = 0;
n = a - b
m = a - b
while n*n >= m and n > b:
if m % n == 0:
resp+=1
if (m/n > b and m/n != n):
resp+=1
n-=1
print(resp)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
608 | A | Saitama Destroys Hotel | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only move down, and has infinite capacity. Floors are numbered from 0 to *s* and elevator initially starts on floor... | The first line of input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=100, 1<=≤<=*s*<=≤<=1000) — the number of passengers and the number of the top floor respectively.
The next *n* lines each contain two space-separated integers *f**i* and *t**i* (1<=≤<=*f**i*<=≤<=*s*, 1<=≤<=*t**i*<=≤<=1000) — the floor and the tim... | Print a single integer — the minimum amount of time in seconds needed to bring all the passengers to floor 0. | [
"3 7\n2 1\n3 8\n5 2\n",
"5 10\n2 77\n3 33\n8 21\n9 12\n10 64\n"
] | [
"11\n",
"79\n"
] | In the first sample, it takes at least 11 seconds to bring all passengers to floor 0. Here is how this could be done:
1. Move to floor 5: takes 2 seconds.
2. Pick up passenger 3.
3. Move to floor 3: takes 2 seconds.
4. Wait for passenger 2 to arrive: takes 4 seconds.
5. Pick up passenger 2.
6. Go to floor 2: take... | 500 | [
{
"input": "3 7\n2 1\n3 8\n5 2",
"output": "11"
},
{
"input": "5 10\n2 77\n3 33\n8 21\n9 12\n10 64",
"output": "79"
},
{
"input": "1 1000\n1000 1000",
"output": "2000"
},
{
"input": "1 1\n1 1",
"output": "2"
},
{
"input": "1 1000\n1 1",
"output": "1000"
},
... | 1,627,996,739 | 2,147,483,647 | PyPy 3 | OK | TESTS | 39 | 109 | 20,172,800 | n,m = map(int,input().split())
l=[]
for _ in range(n):
a,b = map(int,input().split())
l.append([a,b])
for i in range(len(l)):
l.sort(reverse=True)
c=0
h=0
for i in range(len(l)):
c+=m-l[i][0]
m = l[i][0]
if(c<=l[i][1]):
c+=l[i][1]-c
print(c+l[-1][0])
... | Title: Saitama Destroys Hotel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only mo... | ```python
n,m = map(int,input().split())
l=[]
for _ in range(n):
a,b = map(int,input().split())
l.append([a,b])
for i in range(len(l)):
l.sort(reverse=True)
c=0
h=0
for i in range(len(l)):
c+=m-l[i][0]
m = l[i][0]
if(c<=l[i][1]):
c+=l[i][1]-c
print(c+l[-1][0])
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
952 | B | A Map of the Cat | PROGRAMMING | 1,900 | [
"brute force",
"interactive"
] | null | null | If you have ever interacted with a cat, you have probably noticed that they are quite particular about how to pet them. Here is an approximate map of a normal cat.
However, some cats won't tolerate this nonsense from the humans. Here is a map of a grumpy cat.
You have met a cat. Can you figure out whether it's normal... | none | none | [] | [] | Please make sure to use the stream flushing operation after each query in order not to leave part of your output in some buffer. | 0 | [
{
"input": "5 0 1 2 5 3 5 4 5 5",
"output": "Correct answer 'normal'"
},
{
"input": "5 5 5 6 6 7 8 9 10 11",
"output": "Correct answer 'grumpy'"
},
{
"input": "10 6 5 7 5 6 11 5 8 9",
"output": "Correct answer 'grumpy'"
},
{
"input": "7 10 8 9 6 5 5 11 5 6",
"output": "Co... | 1,585,746,319 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 202 | 2,048,000 | import sys
def sendLine(sstr):
print(sstr)
sys.stdout.flush()
MP1 = ['are you serious','worse','terrible','go die in a hole','no way']
MP2 = ['great!',"don't think so","don't touch me!",'not bad','cool']
for i in range(10):
sendLine(i)
sta = int(input())
sys.stdin.flush()
if ... | Title: A Map of the Cat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
If you have ever interacted with a cat, you have probably noticed that they are quite particular about how to pet them. Here is an approximate map of a normal cat.
However, some cats won't tolerate this nonsense from ... | ```python
import sys
def sendLine(sstr):
print(sstr)
sys.stdout.flush()
MP1 = ['are you serious','worse','terrible','go die in a hole','no way']
MP2 = ['great!',"don't think so","don't touch me!",'not bad','cool']
for i in range(10):
sendLine(i)
sta = int(input())
sys.stdin.flush()
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
689 | B | Mike and Shortcuts | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"greedy",
"shortest paths"
] | null | null | Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walking from his house located at the intersection number 1 and goes along some sequence of intersections. Wal... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Mike's city intersection.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*i*<=≤<=*a**i*<=≤<=*n* , , describing shortcuts of Mike's city, allowing to walk from intersection *i* to intersection *a**i* using only 1 unit of ... | In the only line print *n* integers *m*1,<=*m*2,<=...,<=*m**n*, where *m**i* denotes the least amount of total energy required to walk from intersection 1 to intersection *i*. | [
"3\n2 2 3\n",
"5\n1 2 3 4 5\n",
"7\n4 4 4 4 7 7 7\n"
] | [
"0 1 2 \n",
"0 1 2 3 4 \n",
"0 1 2 1 2 3 3 \n"
] | In the first sample case desired sequences are:
1: 1; *m*<sub class="lower-index">1</sub> = 0;
2: 1, 2; *m*<sub class="lower-index">2</sub> = 1;
3: 1, 3; *m*<sub class="lower-index">3</sub> = |3 - 1| = 2.
In the second sample case the sequence for any intersection 1 < *i* is always 1, *i* and *m*<sub class="lowe... | 1,000 | [
{
"input": "3\n2 2 3",
"output": "0 1 2 "
},
{
"input": "5\n1 2 3 4 5",
"output": "0 1 2 3 4 "
},
{
"input": "7\n4 4 4 4 7 7 7",
"output": "0 1 2 1 2 3 3 "
},
{
"input": "98\n17 17 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 87 87... | 1,624,785,966 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 3,000 | 6,041,600 | from queue import PriorityQueue
n = int(input())
shortcuts = [0] + [int(nb) for nb in input().split()]
dst = [float("inf")] * (n+1)
dst[1] = 0
q = PriorityQueue()
q.put((0, 1))
while not q.empty():
node = q.get()[1]
for adj in range(1, n+1):
if dst[node] + abs(node - adj) < dst[adj]:
... | Title: Mike and Shortcuts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walkin... | ```python
from queue import PriorityQueue
n = int(input())
shortcuts = [0] + [int(nb) for nb in input().split()]
dst = [float("inf")] * (n+1)
dst[1] = 0
q = PriorityQueue()
q.put((0, 1))
while not q.empty():
node = q.get()[1]
for adj in range(1, n+1):
if dst[node] + abs(node - adj) < dst[adj]:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,689,131,762 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 103 | 686 | 13,824,000 | import bisect
n = int(input())
prices = [int(x) for x in input().split()]
q = int(input())
allowances = []
for i in range(q):
allowances.append(int(input()))
num_shops = [0 for i in range(q)]
i = 0
prices.sort()
for allowance in allowances:
index = bisect.bisect_left(prices, allowance + 1)
if in... | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
import bisect
n = int(input())
prices = [int(x) for x in input().split()]
q = int(input())
allowances = []
for i in range(q):
allowances.append(int(input()))
num_shops = [0 for i in range(q)]
i = 0
prices.sort()
for allowance in allowances:
index = bisect.bisect_left(prices, allowance + 1)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Be... | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands ... | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,689,623,661 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 124 | 0 | a, b = map(int, input().split())
flag = [input() for i in range(a)]
def flag_check(flag, length):
for i in range(length):
row = flag[i]
if i > 0 and row == flag[i-1]:
return 'No'
if len(set(row)) != 1:
return 'No'
return 'Yes'
print(flag_check(flag, a)) | Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of... | ```python
a, b = map(int, input().split())
flag = [input() for i in range(a)]
def flag_check(flag, length):
for i in range(length):
row = flag[i]
if i > 0 and row == flag[i-1]:
return 'No'
if len(set(row)) != 1:
return 'No'
return 'Yes'
print(flag_check(flag, ... | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
828 | B | Black Square | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Polycarp has a checkered sheet of paper of size *n*<=×<=*m*. Polycarp painted some of cells with black, the others remained white. Inspired by Malevich's "Black Square", Polycarp wants to paint minimum possible number of white cells with black so that all black cells form a square.
You are to determine the minimum pos... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the sizes of the sheet.
The next *n* lines contain *m* letters 'B' or 'W' each — the description of initial cells' colors. If a letter is 'B', then the corresponding cell is painted black, otherwise it is painted white. | Print the minimum number of cells needed to be painted black so that the black cells form a black square with sides parallel to the painting's sides. All the cells that do not belong to the square should be white. If it is impossible, print -1. | [
"5 4\nWWWW\nWWWB\nWWWB\nWWBB\nWWWW\n",
"1 2\nBB\n",
"3 3\nWWW\nWWW\nWWW\n"
] | [
"5\n",
"-1\n",
"1\n"
] | In the first example it is needed to paint 5 cells — (2, 2), (2, 3), (3, 2), (3, 3) and (4, 2). Then there will be a square with side equal to three, and the upper left corner in (2, 2).
In the second example all the cells are painted black and form a rectangle, so it's impossible to get a square.
In the third exampl... | 750 | [
{
"input": "5 4\nWWWW\nWWWB\nWWWB\nWWBB\nWWWW",
"output": "5"
},
{
"input": "1 2\nBB",
"output": "-1"
},
{
"input": "3 3\nWWW\nWWW\nWWW",
"output": "1"
},
{
"input": "100 1\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nB\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\n... | 1,578,987,547 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 139 | 0 | a,b = map(int,input().split())
mas = []
for i in range(0,a):
n = str(input())
mas.append(n)
k=-1
n = -1
i = 1
d = 0
for i in range(0,a):
if mas[i-1].find('B')>-1:
if k<0:
k = i
else:
n = i
m = b
p = 0
for i in range(0,a):
if (mas[i].find('B')<m)a... | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has a checkered sheet of paper of size *n*<=×<=*m*. Polycarp painted some of cells with black, the others remained white. Inspired by Malevich's "Black Square", Polycarp wants to paint minimum possible number of w... | ```python
a,b = map(int,input().split())
mas = []
for i in range(0,a):
n = str(input())
mas.append(n)
k=-1
n = -1
i = 1
d = 0
for i in range(0,a):
if mas[i-1].find('B')>-1:
if k<0:
k = i
else:
n = i
m = b
p = 0
for i in range(0,a):
if (mas[i].fin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
670 | A | Holidays | PROGRAMMING | 900 | [
"brute force",
"constructive algorithms",
"greedy",
"math"
] | null | null | On the planet Mars a year lasts exactly *n* days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars. | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=1<=000<=000) — the number of days in a year on Mars. | Print two integers — the minimum possible and the maximum possible number of days off per year on Mars. | [
"14\n",
"2\n"
] | [
"4 4\n",
"0 2\n"
] | In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .
In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off. | 500 | [
{
"input": "14",
"output": "4 4"
},
{
"input": "2",
"output": "0 2"
},
{
"input": "1",
"output": "0 1"
},
{
"input": "3",
"output": "0 2"
},
{
"input": "4",
"output": "0 2"
},
{
"input": "5",
"output": "0 2"
},
{
"input": "6",
"output":... | 1,654,305,179 | 2,147,483,647 | Python 3 | OK | TESTS | 198 | 46 | 0 | n = int(input())
cycle = n // 7
remain = n % 7
if remain <= 2:
min_offdays = cycle * 2
max_offdays = cycle * 2 + remain
elif 2 < remain <= 5:
min_offdays = cycle * 2
max_offdays = cycle * 2 + 2
else:
min_offdays = cycle * 2 + 1
max_offdays = cycle * 2 + 2
print(min_offdays, max_offdays)
... | Title: Holidays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On the planet Mars a year lasts exactly *n* days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maxim... | ```python
n = int(input())
cycle = n // 7
remain = n % 7
if remain <= 2:
min_offdays = cycle * 2
max_offdays = cycle * 2 + remain
elif 2 < remain <= 5:
min_offdays = cycle * 2
max_offdays = cycle * 2 + 2
else:
min_offdays = cycle * 2 + 1
max_offdays = cycle * 2 + 2
print(min_offdays, max_offdays... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
450 | A | Jzzhu and Children | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of... | The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). | Output a single integer, representing the number of the last child. | [
"5 2\n1 3 1 4 2\n",
"6 4\n1 1 2 2 3 3\n"
] | [
"4\n",
"6\n"
] | Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the en... | 500 | [
{
"input": "5 2\n1 3 1 4 2",
"output": "4"
},
{
"input": "6 4\n1 1 2 2 3 3",
"output": "6"
},
{
"input": "7 3\n6 1 5 4 2 3 1",
"output": "4"
},
{
"input": "10 5\n2 7 3 6 2 5 1 3 4 5",
"output": "4"
},
{
"input": "100 1\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18... | 1,657,396,831 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 102,400 | import collections
d = collections.deque()
nm = list(map(int, input().split()))
a = list(map(int, input().split()))
z = d
for i in range(nm[0]):
d.append(a[i])
z.append(i+1)
dop = 0
dops = 0
while len(d) > 1:
dop = d.popleft()
dops = z.popleft()
if dop > nm[1]:
dop -= nm[1]
... | Title: Jzzhu and Children
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line ... | ```python
import collections
d = collections.deque()
nm = list(map(int, input().split()))
a = list(map(int, input().split()))
z = d
for i in range(nm[0]):
d.append(a[i])
z.append(i+1)
dop = 0
dops = 0
while len(d) > 1:
dop = d.popleft()
dops = z.popleft()
if dop > nm[1]:
dop -=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
106 | A | Card Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Card Game | 2 | 256 | There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselves if you want.
To play durak you need a pack of 36 cards. Each card has a suit ("S", "H", ... | The first line contains the tramp suit. It is "S", "H", "D" or "C".
The second line contains the description of the two different cards. Each card is described by one word consisting of two symbols. The first symbol stands for the rank ("6", "7", "8", "9", "T", "J", "Q", "K" and "A"), and the second one stands for the... | Print "YES" (without the quotes) if the first cards beats the second one. Otherwise, print "NO" (also without the quotes). | [
"H\nQH 9S\n",
"S\n8D 6D\n",
"C\n7H AS\n"
] | [
"YES\n",
"YES",
"NO"
] | none | 500 | [
{
"input": "H\nQH 9S",
"output": "YES"
},
{
"input": "S\n8D 6D",
"output": "YES"
},
{
"input": "C\n7H AS",
"output": "NO"
},
{
"input": "C\nKC 9C",
"output": "YES"
},
{
"input": "D\n7D KD",
"output": "NO"
},
{
"input": "H\n7H KD",
"output": "YES"
... | 1,606,681,264 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 47 | 342 | 409,600 | import math,sys,bisect,heapq
from collections import defaultdict,Counter,deque
from itertools import groupby,accumulate
#sys.setrecursionlimit(200000000)
int1 = lambda x: int(x) - 1
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
ilele = lambda: map(int,input().split())
alele = lambda: list(... | Title: Card Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a card game called "Durak", which means "Fool" in Russian. The game is quite popular in the countries that used to form USSR. The problem does not state all the game's rules explicitly — you can find them later yourselve... | ```python
import math,sys,bisect,heapq
from collections import defaultdict,Counter,deque
from itertools import groupby,accumulate
#sys.setrecursionlimit(200000000)
int1 = lambda x: int(x) - 1
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
ilele = lambda: map(int,input().split())
alele = lam... | 0 | MatrixStudio/Codeforces-Python-Submissions |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,544,451,033 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 155 | 409,600 | import re
string = input()
pattern = re.findall(r'h+e+l+l+o+',string)
#print(pattern)
value = len(pattern)
if value:
print('YES')
else:
print('NO')
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
import re
string = input()
pattern = re.findall(r'h+e+l+l+o+',string)
#print(pattern)
value = len(pattern)
if value:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
772 | A | Voltage Keepsake | PROGRAMMING | 1,800 | [
"binary search",
"math"
] | null | null | You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-th device currently has *b**i* units of power stored. All devices can store an arbitrary amount of pow... | The first line contains two integers, *n* and *p* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*p*<=≤<=109) — the number of devices and the power of the charger.
This is followed by *n* lines which contain two integers each. Line *i* contains the integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=100<=000) — the power of the dev... | If you can use the devices indefinitely, print -1. Otherwise, print the maximum amount of time before any one device hits 0 power.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=4.
Namely, let's assume that your answer is *a* and the answer of the jury is *b*. The chec... | [
"2 1\n2 2\n2 1000\n",
"1 100\n1 1\n",
"3 5\n4 3\n5 2\n6 1\n"
] | [
"2.0000000000",
"-1\n",
"0.5000000000"
] | In sample test 1, you can charge the first device for the entire time until it hits zero power. The second device has enough power to last this time without being charged.
In sample test 2, you can use the device indefinitely.
In sample test 3, we can charge the third device for 2 / 5 of a second, then switch to char... | 500 | [
{
"input": "2 1\n2 2\n2 1000",
"output": "2.0000000000"
},
{
"input": "1 100\n1 1",
"output": "-1"
},
{
"input": "3 5\n4 3\n5 2\n6 1",
"output": "0.5000000000"
},
{
"input": "1 1\n1 87",
"output": "-1"
},
{
"input": "1 1\n100 77",
"output": "0.7777777778"
},... | 1,692,203,002 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main() {
int n, p;
cin >> n >> p;
vector<pair<int, int>> s(n);
int x = -p, y = 0;
for (int i = 0; i < n; ++i) {
int a, b;
cin >> a >> b;
x += a;
y += b;
s[i] = make_pair(a,... | Title: Voltage Keepsake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-... | ```python
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main() {
int n, p;
cin >> n >> p;
vector<pair<int, int>> s(n);
int x = -p, y = 0;
for (int i = 0; i < n; ++i) {
int a, b;
cin >> a >> b;
x += a;
y += b;
s[i] = ma... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
799 | A | Carrot Cakes | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he currently don't have any. However, he has infinitely many ingredients and one oven. Moreover, Arkady... | The only line contains four integers *n*, *t*, *k*, *d* (1<=≤<=*n*,<=*t*,<=*k*,<=*d*<=≤<=1<=000) — the number of cakes needed, the time needed for one oven to bake *k* cakes, the number of cakes baked at the same time, the time needed to build the second oven. | If it is reasonable to build the second oven, print "YES". Otherwise print "NO". | [
"8 6 4 5\n",
"8 6 4 6\n",
"10 3 11 4\n",
"4 2 1 4\n"
] | [
"YES\n",
"NO\n",
"NO\n",
"YES\n"
] | In the first example it is possible to get 8 cakes in 12 minutes using one oven. The second oven can be built in 5 minutes, so after 6 minutes the first oven bakes 4 cakes, the second oven bakes 4 more ovens after 11 minutes. Thus, it is reasonable to build the second oven.
In the second example it doesn't matter whe... | 500 | [
{
"input": "8 6 4 5",
"output": "YES"
},
{
"input": "8 6 4 6",
"output": "NO"
},
{
"input": "10 3 11 4",
"output": "NO"
},
{
"input": "4 2 1 4",
"output": "YES"
},
{
"input": "28 17 16 26",
"output": "NO"
},
{
"input": "60 69 9 438",
"output": "NO"... | 1,689,748,818 | 2,147,483,647 | Python 3 | OK | TESTS | 93 | 46 | 0 | import math
n,t,k,d=map(int,input().split())
batch=math.ceil(n/k)
if (batch*t)>(t+d):
print('YES')
else:
print('NO') | Title: Carrot Cakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he cu... | ```python
import math
n,t,k,d=map(int,input().split())
batch=math.ceil(n/k)
if (batch*t)>(t+d):
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,584,650,937 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 171 | 2,048,000 | vals = [int(x) for x in input().split()]
n = vals[0]
m = vals[1]
problemRound = [int(x) for x in input().split()]
problemSet = [int(x) for x in input().split()]
i = 0
j = 0
while i < n and j < m:
if problemRound[i] <= problemSet[j]:
i += 1
j += 1
print(n-i) | Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
vals = [int(x) for x in input().split()]
n = vals[0]
m = vals[1]
problemRound = [int(x) for x in input().split()]
problemSet = [int(x) for x in input().split()]
i = 0
j = 0
while i < n and j < m:
if problemRound[i] <= problemSet[j]:
i += 1
j += 1
print(n-i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,588,251,907 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 0 | n=int(input())
a=[int(i) for i in input().split()]
b=[]
c=[]
for i in a:
if i%2!=0:
b.append(i)
else:
c.append(i)
if len(b)==1:
print(a.index(b[0])+1)
elif len(c)==1:
print(a.index(c[0])+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
a=[int(i) for i in input().split()]
b=[]
c=[]
for i in a:
if i%2!=0:
b.append(i)
else:
c.append(i)
if len(b)==1:
print(a.index(b[0])+1)
elif len(c)==1:
print(a.index(c[0])+1)
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,688,964,495 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | lines=int(input())
text=""
for i in range(1,lines+1):
if i==1:
text+=" I hate it"
elif i%2==0:
text+=" that I love it"
elif i%2!=0:
text+=" that I hate it"
print(text)
| Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
lines=int(input())
text=""
for i in range(1,lines+1):
if i==1:
text+=" I hate it"
elif i%2==0:
text+=" that I love it"
elif i%2!=0:
text+=" that I hate it"
print(text)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,634,819,920 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 4,505,600 | names=["Sheldon","Leonard","Penny","Rajesh","Howard",]
n= int(input())
turns=[0,1,2,3]
for i in range(n):
if(i != n-1):
for j in "12":
turns.append(turns[i])
else:
print(names[turns[n]-1]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
names=["Sheldon","Leonard","Penny","Rajesh","Howard",]
n= int(input())
turns=[0,1,2,3]
for i in range(n):
if(i != n-1):
for j in "12":
turns.append(turns[i])
else:
print(names[turns[n]-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,699,300,846 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | n = [int(i) for i in input().split()]
m = [0,0,0,0]
n.sort()
b,s,ss = '',0,0
for i in n:
if ss==0:
b = i
m[s]+=1
elif i == b:
m[s]+=1
else:
b = i
s+=1
m[s]+=1
ss+=1
if m[0]==0:
m[0]=1
if m[1]==0:
m[1]=1
if m[2]==0:
m[2]=1
i... | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
n = [int(i) for i in input().split()]
m = [0,0,0,0]
n.sort()
b,s,ss = '',0,0
for i in n:
if ss==0:
b = i
m[s]+=1
elif i == b:
m[s]+=1
else:
b = i
s+=1
m[s]+=1
ss+=1
if m[0]==0:
m[0]=1
if m[1]==0:
m[1]=1
if m[2]==0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
985 | C | Liebig's Barrels | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to exactly one barrel.
Let volume *v**j* of barrel *j* be equal to the length of the minimal stave in it.
... | The first line contains three space-separated integers *n*, *k* and *l* (1<=≤<=*n*,<=*k*<=≤<=105, 1<=≤<=*n*·*k*<=≤<=105, 0<=≤<=*l*<=≤<=109).
The second line contains *m*<==<=*n*·*k* space-separated integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=109) — lengths of staves. | Print single integer — maximal total sum of the volumes of barrels or 0 if it's impossible to construct exactly *n* barrels satisfying the condition |*v**x*<=-<=*v**y*|<=≤<=*l* for any 1<=≤<=*x*<=≤<=*n* and 1<=≤<=*y*<=≤<=*n*. | [
"4 2 1\n2 2 1 2 3 2 2 3\n",
"2 1 0\n10 10\n",
"1 2 1\n5 2\n",
"3 2 1\n1 2 3 4 5 6\n"
] | [
"7\n",
"20\n",
"2\n",
"0\n"
] | In the first example you can form the following barrels: [1, 2], [2, 2], [2, 3], [2, 3].
In the second example you can form the following barrels: [10], [10].
In the third example you can form the following barrels: [2, 5].
In the fourth example difference between volumes of barrels in any partition is at least 2 so... | 0 | [
{
"input": "4 2 1\n2 2 1 2 3 2 2 3",
"output": "7"
},
{
"input": "2 1 0\n10 10",
"output": "20"
},
{
"input": "1 2 1\n5 2",
"output": "2"
},
{
"input": "3 2 1\n1 2 3 4 5 6",
"output": "0"
},
{
"input": "10 3 189\n267 697 667 4 52 128 85 616 142 344 413 660 962 194... | 1,584,602,413 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 233 | 8,704,000 |
from bisect import bisect_right as right
n,k,l=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
x = right(a, a[0]+l)
if x<n:
print(0)
else:
ans = 0
i = 0
while n > 0:
ans += a[i]
i = min(i+k, x-n+1)
n -= 1
print(ans) | Title: Liebig's Barrels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *m*<==<=*n*·*k* wooden staves. The *i*-th stave has length *a**i*. You have to assemble *n* barrels consisting of *k* staves each, you can use any *k* staves to construct a barrel. Each stave must belong to ex... | ```python
from bisect import bisect_right as right
n,k,l=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
x = right(a, a[0]+l)
if x<n:
print(0)
else:
ans = 0
i = 0
while n > 0:
ans += a[i]
i = min(i+k, x-n+1)
n -= 1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
38 | B | Chess | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"math"
] | B. Chess | 2 | 256 | Two chess pieces, a rook and a knight, stand on a standard chessboard 8<=×<=8 in size. The positions in which they are situated are known. It is guaranteed that none of them beats the other one.
Your task is to find the number of ways to place another knight on the board so that none of the three pieces on the board b... | The first input line contains the description of the rook's position on the board. This description is a line which is 2 in length. Its first symbol is a lower-case Latin letter from a to h, and its second symbol is a number from 1 to 8. The second line contains the description of the knight's position in a similar way... | Print a single number which is the required number of ways. | [
"a1\nb2\n",
"a8\nd4\n"
] | [
"44\n",
"38\n"
] | none | 0 | [
{
"input": "a1\nb2",
"output": "44"
},
{
"input": "a8\nd4",
"output": "38"
},
{
"input": "a8\nf1",
"output": "42"
},
{
"input": "f8\nh3",
"output": "42"
},
{
"input": "g8\nb7",
"output": "42"
},
{
"input": "h1\ng5",
"output": "42"
},
{
"inp... | 1,485,339,344 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 372 | 23,142,400 | def check_rook(r1, c1, r2, c2):
if r1 == r2 or c1 == c2:
return 0
elif (abs(r1 - r2) == 2 and abs(c1 - c2) == 1) or (abs(r1 - r2) == 1 and abs(c1 - c2) == 2):
return 0
else:
return 1
def check_knight(r1, c1, r2, c2):
if (abs(r1 - r2) == 2 and abs(c1 - c2) == 1) or (abs(r1 - r2) ... | Title: Chess
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Two chess pieces, a rook and a knight, stand on a standard chessboard 8<=×<=8 in size. The positions in which they are situated are known. It is guaranteed that none of them beats the other one.
Your task is to find the number of wa... | ```python
def check_rook(r1, c1, r2, c2):
if r1 == r2 or c1 == c2:
return 0
elif (abs(r1 - r2) == 2 and abs(c1 - c2) == 1) or (abs(r1 - r2) == 1 and abs(c1 - c2) == 2):
return 0
else:
return 1
def check_knight(r1, c1, r2, c2):
if (abs(r1 - r2) == 2 and abs(c1 - c2) == 1) or (abs... | 3.863894 | MatrixStudio/Codeforces-Python-Submissions |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,676,519,630 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 1,060 | 9,113,600 | a=int(input())
s=0
for i in range(a):
x=input()
if x=="Tetrahedron":
s=s+4
if x=="Cube":
s=s+6
if x=="Octahedron":
s=s+8
if x=="Dodecahedron":
s=s+12
if x=="Icosahedron":
s=s+20
print(s)
| Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
a=int(input())
s=0
for i in range(a):
x=input()
if x=="Tetrahedron":
s=s+4
if x=="Cube":
s=s+6
if x=="Octahedron":
s=s+8
if x=="Dodecahedron":
s=s+12
if x=="Icosahedron":
s=s+20
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,673,369,148 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
s = input()
vowels = "aeiouy"
for i in range(len(s)-1):
if s[i] in vowels and s[i+1] in vowels:
s = s[:i] + s[i+1:]
print(s) | Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
n = int(input())
s = input()
vowels = "aeiouy"
for i in range(len(s)-1):
if s[i] in vowels and s[i+1] in vowels:
s = s[:i] + s[i+1:]
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,539,170,732 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 109 | 0 | input()
a=list(map(int,input().split()))
a=list(set(a))
s=0
for i in a:
if i!=0:s=s+1
print(s) | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
input()
a=list(map(int,input().split()))
a=list(set(a))
s=0
for i in a:
if i!=0:s=s+1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
48 | A | Rock-paper-scissors | PROGRAMMING | 900 | [
"implementation",
"schedules"
] | A. Rock-paper-scissors | 2 | 256 | Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obvio... | The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture. | Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?". | [
"rock\nrock\nrock\n",
"paper\nrock\nrock\n",
"scissors\nrock\nrock\n",
"scissors\npaper\nrock\n"
] | [
"?\n",
"F\n",
"?\n",
"?\n"
] | none | 0 | [
{
"input": "rock\nrock\nrock",
"output": "?"
},
{
"input": "paper\nrock\nrock",
"output": "F"
},
{
"input": "scissors\nrock\nrock",
"output": "?"
},
{
"input": "scissors\npaper\nrock",
"output": "?"
},
{
"input": "paper\npaper\nrock",
"output": "?"
},
{
... | 1,658,282,352 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 124 | 0 | def esMejor(yo, otro):
if yo == "rock" and otro == "scissors":
return True
if yo == "scissors" and otro == "paper":
return True
if yo == "paper" and otro == "rock":
return True
return False
if __name__ == "__main__":
a = input()
b = input()
c = ... | Title: Rock-paper-scissors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case ... | ```python
def esMejor(yo, otro):
if yo == "rock" and otro == "scissors":
return True
if yo == "scissors" and otro == "paper":
return True
if yo == "paper" and otro == "rock":
return True
return False
if __name__ == "__main__":
a = input()
b = input()... | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
420 | A | Start Up | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of the company should be identical to its reflection in a mirror! In other words, if we write out... | The first line contains a non-empty name that needs to be checked. The name contains at most 105 large English letters. The name will be written with the next sans serif font: | Print 'YES' (without the quotes), if the given name matches its mirror reflection. Otherwise, print 'NO' (without the quotes). | [
"AHA\n",
"Z\n",
"XO\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "AHA",
"output": "YES"
},
{
"input": "Z",
"output": "NO"
},
{
"input": "XO",
"output": "NO"
},
{
"input": "AAA",
"output": "YES"
},
{
"input": "AHHA",
"output": "YES"
},
{
"input": "BAB",
"output": "NO"
},
{
"input": "OMMMAAMMMO"... | 1,404,583,613 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | var
s:ansistring;
i:longint;
begin
readln(s);
for i := 1 to length(s) do
begin
if s[i] in ['C','D','E','F','G','J','K','L','N','P','Q','R','S','Z'] then
begin
write('NO');
exit();
end;
if s[i] <> s[length(s) - i + 1] then
begin
... | Title: Start Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of ... | ```python
var
s:ansistring;
i:longint;
begin
readln(s);
for i := 1 to length(s) do
begin
if s[i] in ['C','D','E','F','G','J','K','L','N','P','Q','R','S','Z'] then
begin
write('NO');
exit();
end;
if s[i] <> s[length(s) - i + 1] then
begin
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,598,644,072 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | x ,y = map(int,input().split())
x1 , y1 = map(int,input().split())
listX = list(map(int,input().split()))
listY = list(map(int,input().split()))
for i in range(y):
if x==len(listX) or y == len(listY):
print("NO")
break
elif listX[0]<listY[i]:
print("YES")
break
... | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
x ,y = map(int,input().split())
x1 , y1 = map(int,input().split())
listX = list(map(int,input().split()))
listY = list(map(int,input().split()))
for i in range(y):
if x==len(listX) or y == len(listY):
print("NO")
break
elif listX[0]<listY[i]:
print("YES")
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,614,427,245 | 2,147,483,647 | PyPy 3 | OK | TESTS | 79 | 108 | 0 | l,r,a=map(int,input().split())
m=2*min(l,r)
x=abs(l-r)
k=min(x,a)
z=2*k
a=max(0,a-k)//2
m=2*a+m+z
print(m) | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
l,r,a=map(int,input().split())
m=2*min(l,r)
x=abs(l-r)
k=min(x,a)
z=2*k
a=max(0,a-k)//2
m=2*a+m+z
print(m)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,668,598,522 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 6,144,000 | def bs(x,l):
low=0
high=len(l)-1
while low<=high:
mid=(low+high)//2
if l[mid]>x:
high=mid-1
else:
low=mid+1
if low<len(l) and l[low]==x:
return low
else:
return low-1
n=int(input())
nums=[int(x) for x in input().split(... | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
def bs(x,l):
low=0
high=len(l)-1
while low<=high:
mid=(low+high)//2
if l[mid]>x:
high=mid-1
else:
low=mid+1
if low<len(l) and l[low]==x:
return low
else:
return low-1
n=int(input())
nums=[int(x) for x in inpu... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
766 | A | Mahmoud and Longest Uncommon Subsequence | PROGRAMMING | 1,000 | [
"constructive algorithms",
"strings"
] | null | null | While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two strings *a* and *b*, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence ... | The first line contains string *a*, and the second line — string *b*. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than 105 characters. | If there's no uncommon subsequence, print "-1". Otherwise print the length of the longest uncommon subsequence of *a* and *b*. | [
"abcd\ndefgh\n",
"a\na\n"
] | [
"5\n",
"-1\n"
] | In the first example: you can choose "defgh" from string *b* as it is the longest subsequence of string *b* that doesn't appear as a subsequence of string *a*. | 500 | [
{
"input": "abcd\ndefgh",
"output": "5"
},
{
"input": "a\na",
"output": "-1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaacccccccccccccccccccccccccccccccccccccccccccccccccc\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaadddddddddddddddddddddddddddddddddddddddddddd... | 1,672,589,154 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | a=input()
b=input()
n=min([len(a),len(b)])
N=max([len(a),len(b)])
i=0
Uncommon_number=0
Common_number=0
while i<n:
if a==b:
print(-1)
elif a[i]!=b[i]:
Uncommon_number=Uncommon_number+1
elif a[i]==b[i]:
Common_number=Common_number+1
i=i+1
if Uncommon_number>0:
... | Title: Mahmoud and Longest Uncommon Subsequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two ... | ```python
a=input()
b=input()
n=min([len(a),len(b)])
N=max([len(a),len(b)])
i=0
Uncommon_number=0
Common_number=0
while i<n:
if a==b:
print(-1)
elif a[i]!=b[i]:
Uncommon_number=Uncommon_number+1
elif a[i]==b[i]:
Common_number=Common_number+1
i=i+1
if Uncommon_numbe... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
350 | A | TL | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Valera has also wrote *m* wrong solutions and for each wrong solution he knows its running ... | The first line contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100). The second line contains *n* space-separated positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) — the running time of each of the *n* correct solutions in seconds. The third line contains *m* space-separated positive integers *b*1... | If there is a valid TL value, print it. Otherwise, print -1. | [
"3 6\n4 5 2\n8 9 6 10 7 11\n",
"3 1\n3 4 5\n6\n"
] | [
"5",
"-1\n"
] | none | 500 | [
{
"input": "3 6\n4 5 2\n8 9 6 10 7 11",
"output": "5"
},
{
"input": "3 1\n3 4 5\n6",
"output": "-1"
},
{
"input": "2 5\n45 99\n49 41 77 83 45",
"output": "-1"
},
{
"input": "50 50\n18 13 5 34 10 36 36 12 15 11 16 17 14 36 23 45 32 24 31 18 24 32 7 1 31 3 49 8 16 23 3 39 47 43... | 1,595,999,311 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 216 | 6,656,000 | from sys import stdin,stdout
import math
n,m=map(int,stdin.readline().split())
AC=list(map(int,stdin.readline().split()))
WA=list(map(int,stdin.readline().split()))
x,y,z=min(AC),max(AC),min(WA)
if y>=z or 2*x>=z:
print(-1)
else:
print(max(2*x,y)) | Title: TL
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Val... | ```python
from sys import stdin,stdout
import math
n,m=map(int,stdin.readline().split())
AC=list(map(int,stdin.readline().split()))
WA=list(map(int,stdin.readline().split()))
x,y,z=min(AC),max(AC),min(WA)
if y>=z or 2*x>=z:
print(-1)
else:
print(max(2*x,y))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
622 | C | Not Equal on a Segment | PROGRAMMING | 1,700 | [
"data structures",
"implementation"
] | null | null | You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so that *a**p**i*<=≠<=*x**i*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the number of elements in *a* and the number of queries.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106) — the elements of the array *a*.
Each of the next *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=... | Print *m* lines. On the *i*-th line print integer *p**i* — the position of any number not equal to *x**i* in segment [*l**i*,<=*r**i*] or the value <=-<=1 if there is no such number. | [
"6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2\n"
] | [
"2\n6\n-1\n4\n"
] | none | 0 | [
{
"input": "6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2",
"output": "2\n6\n-1\n4"
},
{
"input": "1 1\n1\n1 1 1",
"output": "-1"
},
{
"input": "1 1\n2\n1 1 2",
"output": "-1"
},
{
"input": "1 1\n569888\n1 1 967368",
"output": "1"
},
{
"input": "10 10\n1 1 1 1 1 1 ... | 1,542,989,855 | 2,147,483,647 | PyPy 3 | OK | TESTS | 63 | 780 | 59,289,600 | #!/usr/bin/env python3
import io
import sys
def solver(ifs):
n, m = list(map(int, ifs.readline().split()))
a = list(map(int, ifs.readline().split()))
b = [0,] * len(a)
c = [0,] * len(a)
for i in range(1, n):
if a[i] == a[i-1]:
b[i] = b[i-1] + 1
for i in range(n-2, -1, -1):
... | Title: Not Equal on a Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so ... | ```python
#!/usr/bin/env python3
import io
import sys
def solver(ifs):
n, m = list(map(int, ifs.readline().split()))
a = list(map(int, ifs.readline().split()))
b = [0,] * len(a)
c = [0,] * len(a)
for i in range(1, n):
if a[i] == a[i-1]:
b[i] = b[i-1] + 1
for i in range(n-2,... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
361 | B | Levko and Permutation | PROGRAMMING | 1,200 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | Levko loves permutations very much. A permutation of length *n* is a sequence of distinct positive integers, each is at most *n*.
Let’s assume that value *gcd*(*a*,<=*b*) shows the greatest common divisor of numbers *a* and *b*. Levko assumes that element *p**i* of permutation *p*1,<=*p*2,<=... ,<=*p**n* is good if *g... | The single line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*). | In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.
If there are multiple suitable permutations, you are allowed to print any of them. | [
"4 2\n",
"1 1\n"
] | [
"2 4 3 1",
"-1\n"
] | In the first sample elements 4 and 3 are good because *gcd*(2, 4) = 2 > 1 and *gcd*(3, 3) = 3 > 1. Elements 2 and 1 are not good because *gcd*(1, 2) = 1 and *gcd*(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.
The second sample has no beautiful permutations. | 1,000 | [
{
"input": "4 2",
"output": "2 1 3 4 "
},
{
"input": "1 1",
"output": "-1"
},
{
"input": "7 4",
"output": "3 1 2 4 5 6 7 "
},
{
"input": "10 9",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "10000 5000",
"output": "5000 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1... | 1,613,627,593 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 170 | 7,987,200 | n,k=map(int,input().split())
if n==k:
print(-1)
else:
arr=[i for i in range(1,n+1)]
var=n-k
arr.remove(var)
arr.insert(0,var)
print(*arr)
| Title: Levko and Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves permutations very much. A permutation of length *n* is a sequence of distinct positive integers, each is at most *n*.
Let’s assume that value *gcd*(*a*,<=*b*) shows the greatest common divisor of numb... | ```python
n,k=map(int,input().split())
if n==k:
print(-1)
else:
arr=[i for i in range(1,n+1)]
var=n-k
arr.remove(var)
arr.insert(0,var)
print(*arr)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
85 | A | Domino | PROGRAMMING | 1,300 | [
"constructive algorithms",
"implementation"
] | A. Domino | 1 | 256 | We all know the problem about the number of ways one can tile a 2<=×<=*n* field by 1<=×<=2 dominoes. You probably remember that it goes down to Fibonacci numbers. We will talk about some other problem below, there you also are going to deal with tiling a rectangular field with dominoes.
You are given a 4<=×<=*n* recta... | The input contains one positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of the field's columns. | If there's no solution, print "-1" (without the quotes). Otherwise, print four lines containing *n* characters each — that's the description of tiling, where each vertical cut intersects at least one domino. You should print the tiling, having painted the field in no more than 26 colors. Each domino should be painted a... | [
"4\n"
] | [
"yyzz\nbccd\nbxxd\nyyaa\n"
] | none | 500 | [
{
"input": "4",
"output": "aacc\nbbdd\nzkkz\nzllz"
},
{
"input": "2",
"output": "aa\nbb\naa\nbb"
},
{
"input": "3",
"output": "aab\nccb\nbaa\nbcc"
},
{
"input": "5",
"output": "aaccz\nbbddz\nzkkmm\nzllnn"
},
{
"input": "1",
"output": "a\na\nb\nb"
},
{
... | 1,572,505,131 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 436 | 2,150,400 | n=int(input())
if n%3==2:
print("-1")
else:
ans=["."*n for i in range(4)]
for i in range(n):
if i%2==0:
ans[i][0]="a"
ans[i][1]="a"
ans[i][2]="b"
ans[i][3]="b"
else:
ans[i][0]="b"
ans[i][1]="b"
... | Title: Domino
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
We all know the problem about the number of ways one can tile a 2<=×<=*n* field by 1<=×<=2 dominoes. You probably remember that it goes down to Fibonacci numbers. We will talk about some other problem below, there you also are going... | ```python
n=int(input())
if n%3==2:
print("-1")
else:
ans=["."*n for i in range(4)]
for i in range(n):
if i%2==0:
ans[i][0]="a"
ans[i][1]="a"
ans[i][2]="b"
ans[i][3]="b"
else:
ans[i][0]="b"
ans[i][1]="b"
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,665,643,181 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 62 | 0 | def countSet(n):
if n==0:
return 0
count = 0
while n:
n&=(n-1)
count+=1
return count
n = int(input())
print(countSet(n))
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
def countSet(n):
if n==0:
return 0
count = 0
while n:
n&=(n-1)
count+=1
return count
n = int(input())
print(countSet(n))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
550 | C | Divisibility by Eight | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"math"
] | null | null | You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a no... | The single line of the input contains a non-negative integer *n*. The representation of number *n* doesn't contain any leading zeroes and its length doesn't exceed 100 digits. | Print "NO" (without quotes), if there is no such way to remove some digits from number *n*.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number *n* in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any ... | [
"3454\n",
"10\n",
"111111\n"
] | [
"YES\n344\n",
"YES\n0\n",
"NO\n"
] | none | 1,000 | [
{
"input": "3454",
"output": "YES\n344"
},
{
"input": "10",
"output": "YES\n0"
},
{
"input": "111111",
"output": "NO"
},
{
"input": "8996988892",
"output": "YES\n8"
},
{
"input": "5555555555",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
... | 1,672,877,319 | 2,147,483,647 | Python 3 | OK | TESTS | 73 | 156 | 0 | s=input()
t=0
for i in range(len(s)):
out=s[i]
if int(out)%8==0:
t=1
if t!=1:
for j in range(i+1,len(s)):
out=out+s[j]
if int(out)%8==0:
t=1
if t!=1:
for k in range(j+1,len(s)):
out=out+s[k]
... | Title: Divisibility by Eight
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of t... | ```python
s=input()
t=0
for i in range(len(s)):
out=s[i]
if int(out)%8==0:
t=1
if t!=1:
for j in range(i+1,len(s)):
out=out+s[j]
if int(out)%8==0:
t=1
if t!=1:
for k in range(j+1,len(s)):
out... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,666,219,042 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 30 | 0 | n,a,b=map(int,input().split())
if a!=0 and b!=0:
print(a+1)
elif a==0 or b==0:
print(1) | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n,a,b=map(int,input().split())
if a!=0 and b!=0:
print(a+1)
elif a==0 or b==0:
print(1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,630,772,692 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 16 | 607 | 25,804,800 | from collections import defaultdict
AL = defaultdict(list) #initalize AL
notvisited=[]
side=[]
def dfs(u,s):
side[s]+=1
notvisited[u] = 0
for v,w in AL[u]:
if(notvisited[v]):
dfs(v,1-s)
side=[0]*2
n= int(input())
notvisited=[1]*(n+1)
for i in range(1,n):
u,v=[int(i) for i in input().split()]
AL[... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
from collections import defaultdict
AL = defaultdict(list) #initalize AL
notvisited=[]
side=[]
def dfs(u,s):
side[s]+=1
notvisited[u] = 0
for v,w in AL[u]:
if(notvisited[v]):
dfs(v,1-s)
side=[0]*2
n= int(input())
notvisited=[1]*(n+1)
for i in range(1,n):
u,v=[int(i) for i in input().split(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,637,076,837 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 19 | 122 | 0 | import sys
string1 = sys.stdin.readline()
string2 = sys.stdin.readline()
pos = 0
for i in string2 :
if i == string1[pos] :
pos += 1
print(pos+1) | Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
import sys
string1 = sys.stdin.readline()
string2 = sys.stdin.readline()
pos = 0
for i in string2 :
if i == string1[pos] :
pos += 1
print(pos+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
466 | A | Cheap Travel | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubles. Ann did the math; she will need to use subway *n* times. Help Ann, tell her what is the minimu... | The single line contains four space-separated integers *n*, *m*, *a*, *b* (1<=≤<=*n*,<=*m*,<=*a*,<=*b*<=≤<=1000) — the number of rides Ann has planned, the number of rides covered by the *m* ride ticket, the price of a one ride ticket and the price of an *m* ride ticket. | Print a single integer — the minimum sum in rubles that Ann will need to spend. | [
"6 2 1 2\n",
"5 2 2 3\n"
] | [
"6\n",
"8\n"
] | In the first sample one of the optimal solutions is: each time buy a one ride ticket. There are other optimal solutions. For example, buy three *m* ride tickets. | 500 | [
{
"input": "6 2 1 2",
"output": "6"
},
{
"input": "5 2 2 3",
"output": "8"
},
{
"input": "10 3 5 1",
"output": "4"
},
{
"input": "1000 1 1000 1000",
"output": "1000000"
},
{
"input": "1000 3 1000 1000",
"output": "334000"
},
{
"input": "1 1 1 1",
"... | 1,687,170,082 | 2,147,483,647 | PyPy 3 | OK | TESTS | 19 | 93 | 0 | n, m, a, b = map(int, input().split())
print(min((a*n), (n//m * b + min(n%m * a, b)))) | Title: Cheap Travel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubl... | ```python
n, m, a, b = map(int, input().split())
print(min((a*n), (n//m * b + min(n%m * a, b))))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
659 | A | Round House | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance *a* and he decided that during his walk he will move around the house *b* entrances in th... | The single line of the input contains three space-separated integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*a*<=≤<=*n*,<=<=-<=100<=≤<=*b*<=≤<=100) — the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively. | Print a single integer *k* (1<=≤<=*k*<=≤<=*n*) — the number of the entrance where Vasya will be at the end of his walk. | [
"6 2 -5\n",
"5 1 3\n",
"3 2 7\n"
] | [
"3\n",
"4\n",
"3\n"
] | The first example is illustrated by the picture in the statements. | 500 | [
{
"input": "6 2 -5",
"output": "3"
},
{
"input": "5 1 3",
"output": "4"
},
{
"input": "3 2 7",
"output": "3"
},
{
"input": "1 1 0",
"output": "1"
},
{
"input": "1 1 -1",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "100 ... | 1,507,389,785 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 18 | 61 | 0 | n = list(map(int, input().split()))
k = abs(n[1]+n[2]%n[0])
print(k)
| Title: Round House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in e... | ```python
n = list(map(int, input().split()))
k = abs(n[1]+n[2]%n[0])
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
262 | A | Roma and Lucky Numbers | PROGRAMMING | 800 | [
"implementation"
] | null | null | Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integer... | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces. | In a single line print a single integer — the answer to the problem. | [
"3 4\n1 2 4\n",
"3 2\n447 44 77\n"
] | [
"3\n",
"2\n"
] | In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | 500 | [
{
"input": "3 4\n1 2 4",
"output": "3"
},
{
"input": "3 2\n447 44 77",
"output": "2"
},
{
"input": "2 2\n507978501 180480073",
"output": "2"
},
{
"input": "9 6\n655243746 167613748 1470546 57644035 176077477 56984809 44677 215706823 369042089",
"output": "9"
},
{
... | 1,624,733,896 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 154 | 0 | n,k = [*map(int, input().split())]
a = [*map(int, input().split())]
print(sum(sum(c in '47' for c in str(x))<=k for x in a))
| Title: Roma and Lucky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits... | ```python
n,k = [*map(int, input().split())]
a = [*map(int, input().split())]
print(sum(sum(c in '47' for c in str(x))<=k for x in a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
18 | C | Stripe | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | C. Stripe | 2 | 64 | Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece, ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=105) — amount of squares in the stripe. The second line contains *n* space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. | Output the amount of ways to cut the stripe into two non-empty pieces so that the sum of numbers from one piece is equal to the sum of numbers from the other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. | [
"9\n1 5 -6 7 9 -16 0 -2 2\n",
"3\n1 1 1\n",
"2\n0 0\n"
] | [
"3\n",
"0\n",
"1\n"
] | none | 0 | [
{
"input": "9\n1 5 -6 7 9 -16 0 -2 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "0"
},
{
"input": "2\n0 0",
"output": "1"
},
{
"input": "4\n100 1 10 111",
"output": "1"
},
{
"input": "10\n0 4 -3 0 -2 2 -3 -3 2 5",
"output": "3"
},
{
"input": "... | 1,691,412,787 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 156 | 12,800,000 | class Solve:
def __init__(self) -> None:
self.n = 0;
self.stripePaper = [];
def vao(self) -> None:
self.n = int(input());
self.stripePaper = [int(item) for item in input().split(" ")];
def tong(self) -> int:
tong = 0;
for i in self.stripePaper:
... | Title: Stripe
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Once Bob took a paper stripe of *n* squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into two pieces so that ... | ```python
class Solve:
def __init__(self) -> None:
self.n = 0;
self.stripePaper = [];
def vao(self) -> None:
self.n = int(input());
self.stripePaper = [int(item) for item in input().split(" ")];
def tong(self) -> int:
tong = 0;
for i in self.str... | 3.865633 | MatrixStudio/Codeforces-Python-Submissions |
846 | E | Chemistry in Berland | PROGRAMMING | 2,300 | [
"dfs and similar",
"greedy",
"trees"
] | null | null | Igor is a post-graduate student of chemistry faculty in Berland State University (BerSU). He needs to conduct a complicated experiment to write his thesis, but laboratory of BerSU doesn't contain all the materials required for this experiment.
Fortunately, chemical laws allow material transformations (yes, chemistry i... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=105) — the number of materials discovered by Berland chemists.
The second line contains *n* integer numbers *b*1,<=*b*2... *b**n* (1<=≤<=*b**i*<=≤<=1012) — supplies of BerSU laboratory.
The third line contains *n* integer numbers *a*1,<=*a*2... *a**n* (1<=... | Print YES if it is possible to conduct an experiment. Otherwise print NO. | [
"3\n1 2 3\n3 2 1\n1 1\n1 1\n",
"3\n3 2 1\n1 2 3\n1 1\n1 2\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 2 3\n3 2 1\n1 1\n1 1",
"output": "YES"
},
{
"input": "3\n3 2 1\n1 2 3\n1 1\n1 2",
"output": "NO"
},
{
"input": "5\n2 1 1 2 3\n1 2 2 2 1\n1 2\n1 3\n2 4\n1 4",
"output": "NO"
},
{
"input": "10\n2 8 6 1 2 7 6 9 2 8\n4 9 4 3 5 2 9 3 7 3\n1 8\n2 8\n3 8\n4 10\n5 1\... | 1,679,390,875 | 4,075 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 16 | 2,000 | 16,384,000 | import sys
N = int(input())
B = list(map(int, input().split()))
A = list(map(int, input().split()))
X = [0] * N
K = [0] * N
for i in range(N - 1):
X[i + 1], K[i + 1] = map(int, input().split())
X[i + 1] -= 1
for x in range(N - 1, 0, -1):
if B[x] < A[x]:
B[X[x]] -= (A[x] - B[x]) * K[... | Title: Chemistry in Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor is a post-graduate student of chemistry faculty in Berland State University (BerSU). He needs to conduct a complicated experiment to write his thesis, but laboratory of BerSU doesn't contain all the materials ... | ```python
import sys
N = int(input())
B = list(map(int, input().split()))
A = list(map(int, input().split()))
X = [0] * N
K = [0] * N
for i in range(N - 1):
X[i + 1], K[i + 1] = map(int, input().split())
X[i + 1] -= 1
for x in range(N - 1, 0, -1):
if B[x] < A[x]:
B[X[x]] -= (A[x] - ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,696,862,383 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n, m = map(int, input().split())
min_row, max_row, min_col, max_col = n, -1, m, -1 # Initialize boundaries
for i in range(n):
row = input()
for j in range(m):
if row[j] == '*':
min_row = min(min_row, i)
max_row = max(max_row, i)
min_col = min(min_col, j)
... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
n, m = map(int, input().split())
min_row, max_row, min_col, max_col = n, -1, m, -1 # Initialize boundaries
for i in range(n):
row = input()
for j in range(m):
if row[j] == '*':
min_row = min(min_row, i)
max_row = max(max_row, i)
min_col = min(min_... | 0 | MatrixStudio/Codeforces-Python-Submissions |
877 | B | Nikita and string | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | null | null | One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st and the 3-rd one contain only letters "a" and the 2-nd contains only letters "b".
Nikita wants to make... | The first line contains a non-empty string of length not greater than 5<=000 containing only lowercase English letters "a" and "b". | Print a single integer — the maximum possible size of beautiful string Nikita can get. | [
"abba\n",
"bab\n"
] | [
"4",
"2"
] | It the first sample the string is already beautiful.
In the second sample he needs to delete one of "b" to make it beautiful. | 1,000 | [
{
"input": "abba",
"output": "4"
},
{
"input": "bab",
"output": "2"
},
{
"input": "bbabbbaabbbb",
"output": "9"
},
{
"input": "bbabbbbbaaba",
"output": "10"
},
{
"input": "bbabbbababaa",
"output": "9"
},
{
"input": "aabbaababbab",
"output": "8"
}... | 1,604,228,154 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 307,200 | s=input()
k=s.index('a')
m=k
for i in range(k+1,len(s)):
if s[i]=='a':
m=max(m,i-k)
k=i
if s[0]==s[-1]=='a':
print(max(m+1,s.count('b')+2))
elif (s[-1]=='a' and s[0]!='a') or (s[-1]!='a' and s[0]=='a'):
print(max((m+1),s.count('b')+1))
else:
print(max(m+1,s.count('b'))) | Title: Nikita and string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st ... | ```python
s=input()
k=s.index('a')
m=k
for i in range(k+1,len(s)):
if s[i]=='a':
m=max(m,i-k)
k=i
if s[0]==s[-1]=='a':
print(max(m+1,s.count('b')+2))
elif (s[-1]=='a' and s[0]!='a') or (s[-1]!='a' and s[0]=='a'):
print(max((m+1),s.count('b')+1))
else:
print(max(m+1,s.count('... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,491,038,438 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 5,529,600 | s=input()
n=len(s)
com='hello'
j=0
if n<5:
print('NO')
else:
for i in s:
if com[j]==i:
j+=1
if j>=4:
break;
if j>4:
print('YES')
else:
print('NO')
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s=input()
n=len(s)
com='hello'
j=0
if n<5:
print('NO')
else:
for i in s:
if com[j]==i:
j+=1
if j>=4:
break;
if j>4:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
292 | B | Network Topology | PROGRAMMING | 1,200 | [
"graphs",
"implementation"
] | null | null | This problem uses a simplified network topology model, please read the problem statement carefully and use it as a formal document as you develop the solution.
Polycarpus continues working as a system administrator in a large corporation. The computer network of this corporation consists of *n* computers, some of them... | The first line contains two space-separated integers *n* and *m* (4<=≤<=*n*<=≤<=105; 3<=≤<=*m*<=≤<=105) — the number of nodes and edges in the graph, correspondingly. Next *m* lines contain the description of the graph's edges. The *i*-th line contains a space-separated pair of integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*... | In a single line print the network topology name of the given graph. If the answer is the bus, print "bus topology" (without the quotes), if the answer is the ring, print "ring topology" (without the quotes), if the answer is the star, print "star topology" (without the quotes). If no answer fits, print "unknown topolo... | [
"4 3\n1 2\n2 3\n3 4\n",
"4 4\n1 2\n2 3\n3 4\n4 1\n",
"4 3\n1 2\n1 3\n1 4\n",
"4 4\n1 2\n2 3\n3 1\n1 4\n"
] | [
"bus topology\n",
"ring topology\n",
"star topology\n",
"unknown topology\n"
] | none | 1,000 | [
{
"input": "4 3\n1 2\n2 3\n3 4",
"output": "bus topology"
},
{
"input": "4 4\n1 2\n2 3\n3 4\n4 1",
"output": "ring topology"
},
{
"input": "4 3\n1 2\n1 3\n1 4",
"output": "star topology"
},
{
"input": "4 4\n1 2\n2 3\n3 1\n1 4",
"output": "unknown topology"
},
{
"i... | 1,561,945,904 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 808 | 819,200 | N = 1e5+5
M = 1e5+5
n,m = map(int,input().split(' '))
d=[]
for i in range(0,n+1):
d.append(0)
for i in range(0,m):
u,v = map(int,input().split(' '))
d[u]+=1
d[v]+=1
flag1=1
flag2=1
flag3=1
d1=0
d2=0
star_cent = 0
for i in range(1,n+1):
if(d[i]==1): d1+=1
if(d[i]==2): d2+=1
else: flag2=0
... | Title: Network Topology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem uses a simplified network topology model, please read the problem statement carefully and use it as a formal document as you develop the solution.
Polycarpus continues working as a system administrator in... | ```python
N = 1e5+5
M = 1e5+5
n,m = map(int,input().split(' '))
d=[]
for i in range(0,n+1):
d.append(0)
for i in range(0,m):
u,v = map(int,input().split(' '))
d[u]+=1
d[v]+=1
flag1=1
flag2=1
flag3=1
d1=0
d2=0
star_cent = 0
for i in range(1,n+1):
if(d[i]==1): d1+=1
if(d[i]==2): d2+=1
else: fl... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | A remote island chain contains *n* islands, labeled 1 through *n*. Bidirectional bridges connect the islands to form a simple cycle — a bridge connects islands 1 and 2, islands 2 and 3, and so on, and additionally a bridge connects islands *n* and 1. The center of each island contains an identical pedestal, and all but... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=200<=000) — the total number of islands.
The second line contains *n* space-separated integers *a**i* (0<=≤<=*a**i*<=≤<=*n*<=-<=1) — the statue currently placed on the *i*-th island. If *a**i*<==<=0, then the island has no statue. It is guaranteed that the *a... | Print "YES" (without quotes) if the rearrangement can be done in the existing network, and "NO" otherwise. | [
"3\n1 0 2\n2 0 1\n",
"2\n1 0\n0 1\n",
"4\n1 2 3 0\n0 3 2 1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample, the islanders can first move statue 1 from island 1 to island 2, then move statue 2 from island 3 to island 1, and finally move statue 1 from island 2 to island 3.
In the second sample, the islanders can simply move statue 1 from island 1 to island 2.
In the third sample, no sequence of movements... | 0 | [
{
"input": "3\n1 0 2\n2 0 1",
"output": "YES"
},
{
"input": "2\n1 0\n0 1",
"output": "YES"
},
{
"input": "4\n1 2 3 0\n0 3 2 1",
"output": "NO"
},
{
"input": "9\n3 8 4 6 7 1 5 2 0\n6 4 8 5 3 1 2 0 7",
"output": "NO"
},
{
"input": "4\n2 3 1 0\n2 0 1 3",
"output"... | 1,456,687,330 | 4,329 | Python 3 | OK | TESTS | 61 | 358 | 21,606,400 | #!/usr/bin/python3
def main():
number_islands = int(input())
current_order = tuple(map(int, input().split()))
desired_order = tuple(map(int, input().split()))
print("YES" if rotation_of(current_order, desired_order) else "NO")
def rotation_of(seq1, seq2):
if len(seq1) != len(seq2):
return... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A remote island chain contains *n* islands, labeled 1 through *n*. Bidirectional bridges connect the islands to form a simple cycle — a bridge connects islands 1 and 2, islands 2 and 3, and so on, and additionally a bridge connect... | ```python
#!/usr/bin/python3
def main():
number_islands = int(input())
current_order = tuple(map(int, input().split()))
desired_order = tuple(map(int, input().split()))
print("YES" if rotation_of(current_order, desired_order) else "NO")
def rotation_of(seq1, seq2):
if len(seq1) != len(seq2):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
3 | B | Lorry | PROGRAMMING | 1,900 | [
"greedy",
"sortings"
] | B. Lorry | 2 | 64 | A group of tourists is going to kayak and catamaran tour. A rented lorry has arrived to the boat depot to take kayaks and catamarans to the point of departure. It's known that all kayaks are of the same size (and each of them occupies the space of 1 cubic metre), and all catamarans are of the same size, but two times b... | The first line contains a pair of integer numbers *n* and *v* (1<=≤<=*n*<=≤<=105; 1<=≤<=*v*<=≤<=109), where *n* is the number of waterborne vehicles in the boat depot, and *v* is the truck body volume of the lorry in cubic metres. The following *n* lines contain the information about the waterborne vehicles, that is a ... | In the first line print the maximum possible carrying capacity of the set. In the second line print a string consisting of the numbers of the vehicles that make the optimal set. If the answer is not unique, print any of them. | [
"3 2\n1 2\n2 7\n1 3\n"
] | [
"7\n2\n"
] | none | 0 | [
{
"input": "3 2\n1 2\n2 7\n1 3",
"output": "7\n2"
},
{
"input": "5 3\n1 9\n2 9\n1 9\n2 10\n1 6",
"output": "24\n3 1 5"
},
{
"input": "10 10\n1 14\n2 15\n2 11\n2 12\n2 9\n1 14\n2 15\n1 9\n2 11\n2 6",
"output": "81\n6 1 7 2 4 9"
},
{
"input": "20 19\n2 47\n1 37\n1 48\n2 42\n2 4... | 1,542,347,474 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 342 | 1,024,000 | n, v = map(int, input().split())
tp = []
for i in range(n):
ti, pi = map(int, input().split())
tp.append((ti, pi, i))
sort(tp, key=lambda _: - _[1] / _[0])
numbers, v_current, quality = [], 0, 0
for tpi in tp:
if v_current + tpi[0] <= v:
v_current += tpi[0]
quality += tpi[1]
numbers.append(t... | Title: Lorry
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A group of tourists is going to kayak and catamaran tour. A rented lorry has arrived to the boat depot to take kayaks and catamarans to the point of departure. It's known that all kayaks are of the same size (and each of them occupies... | ```python
n, v = map(int, input().split())
tp = []
for i in range(n):
ti, pi = map(int, input().split())
tp.append((ti, pi, i))
sort(tp, key=lambda _: - _[1] / _[0])
numbers, v_current, quality = [], 0, 0
for tpi in tp:
if v_current + tpi[0] <= v:
v_current += tpi[0]
quality += tpi[1]
number... | -1 | MatrixStudio/Codeforces-Python-Submissions |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,637,674,278 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | z=input()
m=[]
for i in z:
m.append(int(i))
a=[4,1]
q=[1]
s=[4]
m=list(set(m))
if m==a or m==q or m==s:
print("YES")
else:
print("NO")
| Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
z=input()
m=[]
for i in z:
m.append(int(i))
a=[4,1]
q=[1]
s=[4]
m=list(set(m))
if m==a or m==q or m==s:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,668,916,232 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 186 | 7,372,800 | n = int(input())
lst = [0] + list(map(int,input().split()))
cnt = [0]*7**6
dp = [0]*7**6
for i in lst:
cnt[i] += 1
dp[1] = cnt[1]
for i in range(2,len(dp)):
dp[i] = max(dp[i-1],dp[i-2] + i*cnt[i])
print(max(dp)) | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
n = int(input())
lst = [0] + list(map(int,input().split()))
cnt = [0]*7**6
dp = [0]*7**6
for i in lst:
cnt[i] += 1
dp[1] = cnt[1]
for i in range(2,len(dp)):
dp[i] = max(dp[i-1],dp[i-2] + i*cnt[i])
print(max(dp))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,662,392,516 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n,m = map(int,input().split())
if m<=n:
print("NO")
else:
for i in range(n+1,m+1):
for j in range(2, int(i**0.5)+2):
print("printing i and j",i,j)
if i%j ==0:
if i==m:
print("NO")
break
if j>=int(i**0.5)+1:
... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
n,m = map(int,input().split())
if m<=n:
print("NO")
else:
for i in range(n+1,m+1):
for j in range(2, int(i**0.5)+2):
print("printing i and j",i,j)
if i%j ==0:
if i==m:
print("NO")
break
if j>=int(i... | 0 | MatrixStudio/Codeforces-Python-Submissions |
729 | C | Road to Cinema | PROGRAMMING | 1,700 | [
"binary search",
"greedy",
"sortings"
] | null | null | Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in *t* minutes. There is a straight road of length *s* from the service to the cinema. Let's introduce a coordinate system so that the car rental service is at the point 0, and the cinema is at the point... | The first line contains four positive integers *n*, *k*, *s* and *t* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*k*<=≤<=2·105, 2<=≤<=*s*<=≤<=109, 1<=≤<=*t*<=≤<=2·109) — the number of cars at the car rental service, the number of gas stations along the road, the length of the road and the time in which the film starts.
Each of the n... | Print the minimum rent price of an appropriate car, i.e. such car that Vasya will be able to reach the cinema before the film starts (not later than in *t* minutes). If there is no appropriate car, print -1. | [
"3 1 8 10\n10 8\n5 7\n11 9\n3\n",
"2 2 10 18\n10 4\n20 6\n5 3\n"
] | [
"10\n",
"20\n"
] | In the first sample, Vasya can reach the cinema in time using the first or the third cars, but it would be cheaper to choose the first one. Its price is equal to 10, and the capacity of its fuel tank is 8. Then Vasya can drive to the first gas station in the accelerated mode in 3 minutes, spending 6 liters of fuel. Aft... | 1,750 | [
{
"input": "3 1 8 10\n10 8\n5 7\n11 9\n3",
"output": "10"
},
{
"input": "2 2 10 18\n10 4\n20 6\n5 3",
"output": "20"
},
{
"input": "2 1 1000000000 2000000000\n111 1000000000\n101 1000000000\n5",
"output": "101"
},
{
"input": "2 1 1000000000 2000000000\n111 999999998\n101 9999... | 1,479,637,313 | 4,613 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 8 | 1,000 | 37,785,600 | def tru(a):
ans = 0
for j in range(1,k):
x = B[j] - B[j-1]
if a >= 2 * x:
ans += x
elif a < x:
return False
else:
x1 = 2*x - a
x2 = x - x1
ans += (x2 + 2 * x1)
if ans <= t:
return True
else... | Title: Road to Cinema
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is currently at a car rental service, and he wants to reach cinema. The film he has bought a ticket for starts in *t* minutes. There is a straight road of length *s* from the service to the cinema. Let's introduce ... | ```python
def tru(a):
ans = 0
for j in range(1,k):
x = B[j] - B[j-1]
if a >= 2 * x:
ans += x
elif a < x:
return False
else:
x1 = 2*x - a
x2 = x - x1
ans += (x2 + 2 * x1)
if ans <= t:
return True... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
225 | A | Dice Tower | PROGRAMMING | 1,100 | [
"constructive algorithms",
"greedy"
] | null | null | A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other) that satisfy the given constraints (both of them are shown on the picture on the left).
Alice... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of dice in the tower.
The second line contains an integer *x* (1<=≤<=*x*<=≤<=6) — the number Bob sees at the top of the tower. Next *n* lines contain two space-separated integers each: the *i*-th line contains numbers *a**i*,<=*b**i* (1<=≤<=... | Print "YES" (without the quotes), if it is possible to to uniquely identify the numbers on the faces of all the dice in the tower. If it is impossible, print "NO" (without the quotes). | [
"3\n6\n3 2\n5 4\n2 4\n",
"3\n3\n2 6\n4 1\n5 3\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "3\n6\n3 2\n5 4\n2 4",
"output": "YES"
},
{
"input": "3\n3\n2 6\n4 1\n5 3",
"output": "NO"
},
{
"input": "1\n3\n2 1",
"output": "YES"
},
{
"input": "2\n2\n3 1\n1 5",
"output": "NO"
},
{
"input": "3\n2\n1 4\n5 3\n6 4",
"output": "NO"
},
{
"in... | 1,670,848,836 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 52 | 124 | 0 | def main():
n = int(input())
x = int(input())
y = 7-x
while n:
n -= 1
m,k = map(int, input().split())
if (m == x or m ==y) or (k == x or k ==y):
print("NO")
return
print("YES")
main() | Title: Dice Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other... | ```python
def main():
n = int(input())
x = int(input())
y = 7-x
while n:
n -= 1
m,k = map(int, input().split())
if (m == x or m ==y) or (k == x or k ==y):
print("NO")
return
print("YES")
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
772 | A | Voltage Keepsake | PROGRAMMING | 1,800 | [
"binary search",
"math"
] | null | null | You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-th device currently has *b**i* units of power stored. All devices can store an arbitrary amount of pow... | The first line contains two integers, *n* and *p* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*p*<=≤<=109) — the number of devices and the power of the charger.
This is followed by *n* lines which contain two integers each. Line *i* contains the integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=100<=000) — the power of the dev... | If you can use the devices indefinitely, print -1. Otherwise, print the maximum amount of time before any one device hits 0 power.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=4.
Namely, let's assume that your answer is *a* and the answer of the jury is *b*. The chec... | [
"2 1\n2 2\n2 1000\n",
"1 100\n1 1\n",
"3 5\n4 3\n5 2\n6 1\n"
] | [
"2.0000000000",
"-1\n",
"0.5000000000"
] | In sample test 1, you can charge the first device for the entire time until it hits zero power. The second device has enough power to last this time without being charged.
In sample test 2, you can use the device indefinitely.
In sample test 3, we can charge the third device for 2 / 5 of a second, then switch to char... | 500 | [
{
"input": "2 1\n2 2\n2 1000",
"output": "2.0000000000"
},
{
"input": "1 100\n1 1",
"output": "-1"
},
{
"input": "3 5\n4 3\n5 2\n6 1",
"output": "0.5000000000"
},
{
"input": "1 1\n1 87",
"output": "-1"
},
{
"input": "1 1\n100 77",
"output": "0.7777777778"
},... | 1,696,438,272 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 8,806,400 | import sys
MAXN = 10**5 + 4
MAXV = 1e18
def f(imid):
needsum = 0
for i in range(n):
need = max(0.0, (imid - exhaust[i]) * a[i])
needsum += need
supply = imid * P
return supply >= needsum
if __name__ == "__main__":
n, P = map(int, input().split())
a = [0] * MAXN
b = [0] * M... | Title: Voltage Keepsake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-... | ```python
import sys
MAXN = 10**5 + 4
MAXV = 1e18
def f(imid):
needsum = 0
for i in range(n):
need = max(0.0, (imid - exhaust[i]) * a[i])
needsum += need
supply = imid * P
return supply >= needsum
if __name__ == "__main__":
n, P = map(int, input().split())
a = [0] * MAXN
b... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,698,814,973 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | def beautiful_year(s):
for i in range(0, len(s)):
if n[i] in n[i+1:]:
return False
else:
return True
n=str(input())
n=str(int(n)+1)
ans=None
while ans==False:
ans=beautiful_year(n)
n=str(int(n)+1)
print(n)
| Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
def beautiful_year(s):
for i in range(0, len(s)):
if n[i] in n[i+1:]:
return False
else:
return True
n=str(input())
n=str(int(n)+1)
ans=None
while ans==False:
ans=beautiful_year(n)
n=str(int(n)+1)
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,690,428,762 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 11 | 46 | 0 | n = input()
lis = ["h",'e','l','l','o']
count = 0
if len(n) > len(lis):
for i in n:
if i in lis:
count += 1
if count > len(lis)+1:
print("YES")
else:
print("NO")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
n = input()
lis = ["h",'e','l','l','o']
count = 0
if len(n) > len(lis):
for i in n:
if i in lis:
count += 1
if count > len(lis)+1:
print("YES")
else:
print("NO")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the ... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs.
The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha ... | Print single integer — the maximum number of socks that were on the table at the same time. | [
"1\n1 1\n",
"3\n2 1 1 3 2 3\n"
] | [
"1\n",
"2\n"
] | In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time.
In the second example Andryusha behaved as follows:
- ... | 0 | [
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "3\n2 1 1 3 2 3",
"output": "2"
},
{
"input": "5\n5 1 3 2 4 3 1 2 4 5",
"output": "5"
},
{
"input": "10\n4 2 6 3 4 8 7 1 1 5 2 10 6 8 3 5 10 9 9 7",
"output": "6"
},
{
"input": "50\n30 47 31 38 37 50 36 43 9 23 2 2 ... | 1,623,072,743 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 280 | 14,131,200 | n = int(input())
st = set()
m = 0
c = 0
for i in list(map(int, input().split())):
if i in st:
c -= 1
else:
c += 1
st.add(i)
m = max(m, c)
print(m)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*... | ```python
n = int(input())
st = set()
m = 0
c = 0
for i in list(map(int, input().split())):
if i in st:
c -= 1
else:
c += 1
st.add(i)
m = max(m, c)
print(m)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,571,018,369 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 278 | 0 | from math import gcd
(Y,W) = map(int,input().split())
A = (6-max(Y,W))+1
print(str(A//gcd(A,6))+'/'+str(6//gcd(A,6))) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
from math import gcd
(Y,W) = map(int,input().split())
A = (6-max(Y,W))+1
print(str(A//gcd(A,6))+'/'+str(6//gcd(A,6)))
``` | 3.861 | MatrixStudio/Codeforces-Python-Submissions |
808 | A | Lucky Year | PROGRAMMING | 900 | [
"implementation"
] | null | null | Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland. | Output amount of years from the current year to the next lucky one. | [
"4\n",
"201\n",
"4000\n"
] | [
"1\n",
"99\n",
"1000\n"
] | In the first example next lucky year is 5. In the second one — 300. In the third — 5000. | 0 | [
{
"input": "4",
"output": "1"
},
{
"input": "201",
"output": "99"
},
{
"input": "4000",
"output": "1000"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "1",
"output": "1"
},
{
"input": "100000000",
"ou... | 1,689,771,326 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | def lucky(a):
flag = False
while a>0:
x = a%10
if x!=0 :
if flag:
return False
else:
flag = True
a//=10
return True
n = int(input())+1
while not lucky(n):
n+=1
print(n) | Title: Lucky Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 1... | ```python
def lucky(a):
flag = False
while a>0:
x = a%10
if x!=0 :
if flag:
return False
else:
flag = True
a//=10
return True
n = int(input())+1
while not lucky(n):
n+=1
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,666,731,638 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | numbers = list(map(int ,input().split()))
x1 = min(numbers[0] , numbers[1])
which = 0 if x1 == numbers[0] else 1
x2 = min(numbers[0]+numbers[1] , numbers[2])
x3 = min(numbers[1 if which == 0 else 1] , numbers[2] + numbers[1 if which == 0 else 0])
print(x2 + x3 + x1) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
numbers = list(map(int ,input().split()))
x1 = min(numbers[0] , numbers[1])
which = 0 if x1 == numbers[0] else 1
x2 = min(numbers[0]+numbers[1] , numbers[2])
x3 = min(numbers[1 if which == 0 else 1] , numbers[2] + numbers[1 if which == 0 else 0])
print(x2 + x3 + x1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,507,609,036 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | def inp():
return map(int, input().split(' '))
def compare(a, b):
return a.mark > b.mark
class Student:
def __init__(self, id, mark):
self.id = id
self.mark = mark
n = int(input())
v = inp()
students = []
for i in range(0, n):
temp = Student(i, v[i])
... | Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
def inp():
return map(int, input().split(' '))
def compare(a, b):
return a.mark > b.mark
class Student:
def __init__(self, id, mark):
self.id = id
self.mark = mark
n = int(input())
v = inp()
students = []
for i in range(0, n):
temp = Student(i, v... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
989 | A | A Blend of Springtime | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | "What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimistic.
The landscape can be expressed as a row of consecutive cells, each of which either contains a flower o... | The first and only line of input contains a non-empty string $s$ consisting of uppercase English letters 'A', 'B', 'C' and characters '.' (dots) only ($\lvert s \rvert \leq 100$) — denoting cells containing an amber flower, a buff one, a canary yellow one, and no flowers, respectively. | Output "Yes" if it's possible that all three colours appear in some cell, and "No" otherwise.
You can print each letter in any case (upper or lower). | [
".BAC.\n",
"AA..CB\n"
] | [
"Yes\n",
"No\n"
] | In the first example, the buff and canary yellow flowers can leave their petals in the central cell, blending all three colours in it.
In the second example, it's impossible to satisfy the requirement because there is no way that amber and buff meet in any cell. | 500 | [
{
"input": ".BAC.",
"output": "Yes"
},
{
"input": "AA..CB",
"output": "No"
},
{
"input": ".",
"output": "No"
},
{
"input": "ACB.AAAAAA",
"output": "Yes"
},
{
"input": "B.BC.BBBCA",
"output": "Yes"
},
{
"input": "BA..CAB..B",
"output": "Yes"
},
... | 1,618,829,157 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 109 | 0 | S = input()
poss = ["ABC", "CBA", "BAC", "CAB", "BCA", "ACB"]
present = False
for i in poss:
if i in S:
present = True
break
if present == True:
print("Yes")
else:
print("No")
| Title: A Blend of Springtime
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimisti... | ```python
S = input()
poss = ["ABC", "CBA", "BAC", "CAB", "BCA", "ACB"]
present = False
for i in poss:
if i in S:
present = True
break
if present == True:
print("Yes")
else:
print("No")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
487 | A | Fight the Monster | PROGRAMMING | 1,800 | [
"binary search",
"brute force",
"implementation"
] | null | null | A monster is attacking the Cyberland!
Master Yang, a braver, is going to beat the monster. Yang and the monster each have 3 attributes: hitpoints (*HP*), offensive power (*ATK*) and defensive power (*DEF*).
During the battle, every second the monster's HP decrease by *max*(0,<=*ATK**Y*<=-<=*DEF**M*), while Yang's HP ... | The first line contains three integers *HP**Y*,<=*ATK**Y*,<=*DEF**Y*, separated by a space, denoting the initial *HP*, *ATK* and *DEF* of Master Yang.
The second line contains three integers *HP**M*,<=*ATK**M*,<=*DEF**M*, separated by a space, denoting the *HP*, *ATK* and *DEF* of the monster.
The third line contains... | The only output line should contain an integer, denoting the minimum bitcoins Master Yang should spend in order to win. | [
"1 2 1\n1 100 1\n1 100 100\n",
"100 100 100\n1 1 1\n1 1 1\n"
] | [
"99\n",
"0\n"
] | For the first sample, prices for *ATK* and *DEF* are extremely high. Master Yang can buy 99 HP, then he can beat the monster with 1 HP left.
For the second sample, Master Yang is strong enough to beat the monster, so he doesn't need to buy anything. | 500 | [
{
"input": "1 2 1\n1 100 1\n1 100 100",
"output": "99"
},
{
"input": "100 100 100\n1 1 1\n1 1 1",
"output": "0"
},
{
"input": "50 80 92\n41 51 56\n75 93 12",
"output": "0"
},
{
"input": "76 63 14\n89 87 35\n20 15 56",
"output": "915"
},
{
"input": "12 59 66\n43 15... | 1,504,506,591 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 204,800 | import math
hpy, aty, defy = map(int, input().split())
hpm, atm, defm = map(int, input().split())
h, a, d = map(int, input().split())
init_cost = hpy*h + aty*a + defy*d
def feasible(hpy, aty, defy):
if aty <= defm:
return False
if atm <= defy:
return True
return math.ceil(hpm /... | Title: Fight the Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A monster is attacking the Cyberland!
Master Yang, a braver, is going to beat the monster. Yang and the monster each have 3 attributes: hitpoints (*HP*), offensive power (*ATK*) and defensive power (*DEF*).
During t... | ```python
import math
hpy, aty, defy = map(int, input().split())
hpm, atm, defm = map(int, input().split())
h, a, d = map(int, input().split())
init_cost = hpy*h + aty*a + defy*d
def feasible(hpy, aty, defy):
if aty <= defm:
return False
if atm <= defy:
return True
return math.... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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