contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,642,767,661 | 2,147,483,647 | PyPy 3 | OK | TESTS | 96 | 1,450 | 12,800,000 | #Mamma don't raises quitter.................................................
#manan is improving, keep hustling manan bhai ;)
from collections import deque as de
import math
from queue import PriorityQueue as pq
from collections import Counter as cnt
from functools import reduce
def factors(n):
retu... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
#Mamma don't raises quitter.................................................
#manan is improving, keep hustling manan bhai ;)
from collections import deque as de
import math
from queue import PriorityQueue as pq
from collections import Counter as cnt
from functools import reduce
def factors(n): ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
618 | A | Slime Combining | PROGRAMMING | 800 | [
"implementation"
] | null | null | Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other *n*<=-<=1 slimes one by one. When you add a slime, you place it at the right of... | The first line of the input will contain a single integer, *n* (1<=≤<=*n*<=≤<=100<=000). | Output a single line with *k* integers, where *k* is the number of slimes in the row after you've finished the procedure described in the problem statement. The *i*-th of these numbers should be the value of the *i*-th slime from the left. | [
"1\n",
"2\n",
"3\n",
"8\n"
] | [
"1\n",
"2\n",
"2 1\n",
"4\n"
] | In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. S... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "8",
"output": "4"
},
{
"input": "100000",
"output": "17 16 11 10 8 6"
},
{
"input": "12345",
"output": "14 13 6 5 4 1"
},
{
"in... | 1,693,685,221 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 78 | 0 | num = int(input())
value = []
for i in range(0,num):
value.append(1)
while len(value)>=2 and value[-1]==value[-2]:
value[-2] += 1
del value[-1]
# The * symbol is used to print the list elements in a single line with space
print(*value)
| Title: Slime Combining
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, y... | ```python
num = int(input())
value = []
for i in range(0,num):
value.append(1)
while len(value)>=2 and value[-1]==value[-2]:
value[-2] += 1
del value[-1]
# The * symbol is used to print the list elements in a single line with space
print(*value)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,608,839,274 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | n,p,q = map(int,input().split())
nn = n
a = input()
if p+q == n:
print(2)
print(a[0:p])
print(a[p:])
elif p+q<n:
num = max(p,q)
while n%min(p,q)!=0 and n>=0:
n-=num
print(n)
if n%min(p,q)==0:
d={max(p,q):(nn-n)//max(p,q),min(p,q):n//min(p,q)}
x,y=max(p,q),min(p,q)
... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n,p,q = map(int,input().split())
nn = n
a = input()
if p+q == n:
print(2)
print(a[0:p])
print(a[p:])
elif p+q<n:
num = max(p,q)
while n%min(p,q)!=0 and n>=0:
n-=num
print(n)
if n%min(p,q)==0:
d={max(p,q):(nn-n)//max(p,q),min(p,q):n//min(p,q)}
x,y=max(p,q),mi... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
804 | B | Minimum number of steps | PROGRAMMING | 1,400 | [
"combinatorics",
"greedy",
"implementation",
"math"
] | null | null | We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substring, our job is done. Print the minimum number of steps we should perform to make our job done modulo 109<=+<... | The first line contains the initial string consisting of letters 'a' and 'b' only with length from 1 to 106. | Print the minimum number of steps modulo 109<=+<=7. | [
"ab\n",
"aab\n"
] | [
"1\n",
"3\n"
] | The first example: "ab" → "bba".
The second example: "aab" → "abba" → "bbaba" → "bbbbaa". | 1,000 | [
{
"input": "ab",
"output": "1"
},
{
"input": "aab",
"output": "3"
},
{
"input": "aaaaabaabababaaaaaba",
"output": "17307"
},
{
"input": "abaabaaabbabaabab",
"output": "1795"
},
{
"input": "abbaa",
"output": "2"
},
{
"input": "abbaaabaabaaaaabbbbaababaa... | 1,667,134,106 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | print(("aabb" * 50000)[:int(input())]) | Title: Minimum number of steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substr... | ```python
print(("aabb" * 50000)[:int(input())])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,636,089,459 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 4,505,600 | L = []
Final = []
a = input()
for i in a:
L.append(i)
i = 0
while(i < len(L)):
if L[i] == '.':
Final.append(0)
i += 1
elif L[i] == '-' and L[i+1] == '.':
i += 2
Final.append(1)
else:
Final.append(2)
i += 2
q = ''
for i in range(len(F... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
L = []
Final = []
a = input()
for i in a:
L.append(i)
i = 0
while(i < len(L)):
if L[i] == '.':
Final.append(0)
i += 1
elif L[i] == '-' and L[i+1] == '.':
i += 2
Final.append(1)
else:
Final.append(2)
i += 2
q = ''
for i in r... | 3.968608 | MatrixStudio/Codeforces-Python-Submissions |
946 | A | Partition | PROGRAMMING | 800 | [
"greedy"
] | null | null | You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequenc... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*. | Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*. | [
"3\n1 -2 0\n",
"6\n16 23 16 15 42 8\n"
] | [
"3\n",
"120\n"
] | In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120. | 0 | [
{
"input": "3\n1 -2 0",
"output": "3"
},
{
"input": "6\n16 23 16 15 42 8",
"output": "120"
},
{
"input": "1\n-1",
"output": "1"
},
{
"input": "100\n-100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -10... | 1,532,967,313 | 2,147,483,647 | Python 3 | OK | TESTS | 72 | 124 | 0 | list_a = []
sum_b = 0
sum_c = 0
n = int(input())
tmp = input()
list_a = [int(r) for r in tmp.split()]
for i in list_a:
if(i > 0):
sum_b = sum_b + i
else:
sum_c = sum_c + i
print(sum_b - sum_c) | Title: Partition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of eleme... | ```python
list_a = []
sum_b = 0
sum_c = 0
n = int(input())
tmp = input()
list_a = [int(r) for r in tmp.split()]
for i in list_a:
if(i > 0):
sum_b = sum_b + i
else:
sum_c = sum_c + i
print(sum_b - sum_c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
735 | A | Ostap and Grasshopper | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The gr... | The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1) — the number of cells in the line and the length of one grasshopper's jump.
The second line contains a string of length *n* consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the correspondi... | If there exists a sequence of jumps (each jump of length *k*), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes). | [
"5 2\n#G#T#\n",
"6 1\nT....G\n",
"7 3\nT..#..G\n",
"6 2\n..GT..\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4.
In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times.
In the third sample, the grasshopper can't make a sin... | 500 | [
{
"input": "5 2\n#G#T#",
"output": "YES"
},
{
"input": "6 1\nT....G",
"output": "YES"
},
{
"input": "7 3\nT..#..G",
"output": "NO"
},
{
"input": "6 2\n..GT..",
"output": "NO"
},
{
"input": "2 1\nGT",
"output": "YES"
},
{
"input": "100 5\nG####.####.###... | 1,517,191,337 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 61 | 5,632,000 | n,k = (map(int,input().split()))
x=list(input())
start = x.index('G')
end = x.index('T')
x=x[start:end+1]
print(x)
for i in range(k,k,len(x)):
if x[i]=='T':
t='YES'
break
elif x[i]=='#':
t='NO'
break
print(t)
| Title: Ostap and Grasshopper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles.... | ```python
n,k = (map(int,input().split()))
x=list(input())
start = x.index('G')
end = x.index('T')
x=x[start:end+1]
print(x)
for i in range(k,k,len(x)):
if x[i]=='T':
t='YES'
break
elif x[i]=='#':
t='NO'
break
print(t)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,590,396,541 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 186 | 0 | t=int(input())
c=0
k=[]
g=[]
s=[]
for i in range(t):
a,b=list(map(int,input().split()))
if a==b:
c+=1
g.append(b)
k.append(a)
m=sum(x == y for x, y in zip(g,k))
print(len(k)-m+c) | Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th... | ```python
t=int(input())
c=0
k=[]
g=[]
s=[]
for i in range(t):
a,b=list(map(int,input().split()))
if a==b:
c+=1
g.append(b)
k.append(a)
m=sum(x == y for x, y in zip(g,k))
print(len(k)-m+c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
733 | A | Grasshopper And the String | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of ... | The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. | Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. | [
"ABABBBACFEYUKOTT\n",
"AAA\n"
] | [
"4",
"1"
] | none | 500 | [
{
"input": "ABABBBACFEYUKOTT",
"output": "4"
},
{
"input": "AAA",
"output": "1"
},
{
"input": "A",
"output": "1"
},
{
"input": "B",
"output": "2"
},
{
"input": "AEYUIOAEIYAEOUIYOEIUYEAOIUEOEAYOEIUYAEOUIYEOIKLMJNHGTRWSDZXCVBNMHGFDSXVWRTPPPLKMNBXIUOIUOIUOIUOOIU",
... | 1,654,332,184 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 46 | 0 | S=' '+input()+'A';ans=0
Y='AEIOUY';s=0
for i in range(len(S)):
if S[i] in Y:
e=i
if ans<e-s:
ans=e-s
s=e
print(ans)
| Title: Grasshopper And the String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far en... | ```python
S=' '+input()+'A';ans=0
Y='AEIOUY';s=0
for i in range(len(S)):
if S[i] in Y:
e=i
if ans<e-s:
ans=e-s
s=e
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
146 | B | Lucky Mask | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a mask of a positive integer *n* the number that is obtained after successive writing ... | The only line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=105). It is guaranteed that number *b* is lucky. | In the only line print a single number — the number *c* that is sought by Petya. | [
"1 7\n",
"100 47\n"
] | [
"7\n",
"147\n"
] | none | 1,000 | [
{
"input": "1 7",
"output": "7"
},
{
"input": "100 47",
"output": "147"
},
{
"input": "458 47",
"output": "467"
},
{
"input": "7 7",
"output": "17"
},
{
"input": "547 47",
"output": "647"
},
{
"input": "77 77",
"output": "177"
},
{
"input":... | 1,423,676,396 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 0 | '''
Created on Feb 11, 2015
@author: mohamed265
'''
temp = input().split()
a = temp[0]
b = temp[1]
lenA = len(a)
lenB = len(b)
if lenA < lenB:
print(b)
elif lenA == lenB:
if lenA[0] < lenB[0]:
print(b)
else:
for i in range(1, lenA):
if lenA[i] < lenB[i]:
... | Title: Lucky Mask
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Pe... | ```python
'''
Created on Feb 11, 2015
@author: mohamed265
'''
temp = input().split()
a = temp[0]
b = temp[1]
lenA = len(a)
lenB = len(b)
if lenA < lenB:
print(b)
elif lenA == lenB:
if lenA[0] < lenB[0]:
print(b)
else:
for i in range(1, lenA):
if lenA[i] < lenB[i... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
353 | A | Domino | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the numbers on the upper halves and the sum of the numbers on the lower halves to be even.
To do... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), denoting the number of dominoes Valera has. Next *n* lines contain two space-separated integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=6). Number *x**i* is initially written on the upper half of the *i*-th domino, *y**i* is initially written on the lower half... | Print a single number — the minimum required number of seconds. If Valera can't do the task in any time, print <=-<=1. | [
"2\n4 2\n6 4\n",
"1\n2 3\n",
"3\n1 4\n2 3\n4 4\n"
] | [
"0\n",
"-1\n",
"1\n"
] | In the first test case the sum of the numbers on the upper halves equals 10 and the sum of the numbers on the lower halves equals 6. Both numbers are even, so Valera doesn't required to do anything.
In the second sample Valera has only one piece of domino. It is written 3 on the one of its halves, therefore one of the... | 500 | [
{
"input": "2\n4 2\n6 4",
"output": "0"
},
{
"input": "1\n2 3",
"output": "-1"
},
{
"input": "3\n1 4\n2 3\n4 4",
"output": "1"
},
{
"input": "5\n5 4\n5 4\n1 5\n5 5\n3 3",
"output": "1"
},
{
"input": "20\n1 3\n5 2\n5 2\n2 6\n2 4\n1 1\n1 3\n1 4\n2 6\n4 2\n5 6\n2 2\n... | 1,625,877,183 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 372 | 5,836,800 | # ____ _ _ _ _ _
# / ___| __ _ _ __ __ _ | | | | __ _ _ __ ___| |__ (_) |_
# | | _ / _` | '__/ _` |_____| |_| |/ _` | '__/ __| '_ \| | __|
# | |_| | (_| | | | (_| |_____| _ | (_| | | \__ \ | | | | |_
# \____|\__,_|_| \__, | |_| |_|\__,_|_| |___... | Title: Domino
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the n... | ```python
# ____ _ _ _ _ _
# / ___| __ _ _ __ __ _ | | | | __ _ _ __ ___| |__ (_) |_
# | | _ / _` | '__/ _` |_____| |_| |/ _` | '__/ __| '_ \| | __|
# | |_| | (_| | | | (_| |_____| _ | (_| | | \__ \ | | | | |_
# \____|\__,_|_| \__, | |_| |_|\__,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
454 | B | Little Pony and Sort by Shift | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. That is, she can move the last element of the sequence to its beginning:
Help Twilight Sparkle to calculate: what ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=105). The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | If it's impossible to sort the sequence output -1. Otherwise output the minimum number of operations Twilight Sparkle needs to sort it. | [
"2\n2 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"1\n",
"-1\n",
"0\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 3 2",
"output": "-1"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "6\n3 4 5 6 3 2",
"output": "-1"
},
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n1 1 2 1 1",
"output": "2"
}... | 1,611,124,565 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 11,980,800 | n=int(input())
arr=list(map(int,input().split()));ans=0;temp=arr.copy()
for i in range(n):
if arr==sorted(temp):
print(ans)
exit()
arr.insert(0,arr.pop())
if arr==temp:
print(-1)
exit()
ans+=1 | Title: Little Pony and Sort by Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. ... | ```python
n=int(input())
arr=list(map(int,input().split()));ans=0;temp=arr.copy()
for i in range(n):
if arr==sorted(temp):
print(ans)
exit()
arr.insert(0,arr.pop())
if arr==temp:
print(-1)
exit()
ans+=1
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,626,506,834 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 248 | 20,172,800 | n = list(input())
a = list(input())
a1 = n[::-1]
if a1 == a:
print('YES')
else:
print('NO') | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
n = list(input())
a = list(input())
a1 = n[::-1]
if a1 == a:
print('YES')
else:
print('NO')
``` | 3.900425 | MatrixStudio/Codeforces-Python-Submissions |
922 | A | Cloning Toys | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applies the machine to a copied toy, he gets two additional copies.
Initially, Imp has only one origina... | The only line contains two integers *x* and *y* (0<=≤<=*x*,<=*y*<=≤<=109) — the number of copies and the number of original toys Imp wants to get (including the initial one). | Print "Yes", if the desired configuration is possible, and "No" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"6 3\n",
"4 2\n",
"1000 1001\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first example, Imp has to apply the machine twice to original toys and then twice to copies. | 500 | [
{
"input": "6 3",
"output": "Yes"
},
{
"input": "4 2",
"output": "No"
},
{
"input": "1000 1001",
"output": "Yes"
},
{
"input": "1000000000 999999999",
"output": "Yes"
},
{
"input": "81452244 81452247",
"output": "No"
},
{
"input": "188032448 86524683",... | 1,570,787,142 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | x,y=input().split()
x=int(x)
y=int(y)
if x==(y//2) :
print ("yes")
else :
print("no")
| Title: Cloning Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applie... | ```python
x,y=input().split()
x=int(x)
y=int(y)
if x==(y//2) :
print ("yes")
else :
print("no")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
5 | A | Chat Servers Outgoing Traffic | PROGRAMMING | 1,000 | [
"implementation"
] | A. Chat Server's Outgoing Traffic | 1 | 64 | Polycarp is working on a new project called "Polychat". Following modern tendencies in IT, he decided, that this project should contain chat as well. To achieve this goal, Polycarp has spent several hours in front of his laptop and implemented a chat server that can process three types of commands:
- Include a person... | Input file will contain not more than 100 commands, each in its own line. No line will exceed 100 characters. Formats of the commands will be the following:
- +<name> for 'Add' command. - -<name> for 'Remove' command. - <sender_name>:<message_text> for 'Send' command.
<name> and <s... | Print a single number — answer to the problem. | [
"+Mike\nMike:hello\n+Kate\n+Dmitry\n-Dmitry\nKate:hi\n-Kate\n",
"+Mike\n-Mike\n+Mike\nMike:Hi I am here\n-Mike\n+Kate\n-Kate\n"
] | [
"9\n",
"14\n"
] | none | 0 | [
{
"input": "+Mike\nMike:hello\n+Kate\n+Dmitry\n-Dmitry\nKate:hi\n-Kate",
"output": "9"
},
{
"input": "+Mike\n-Mike\n+Mike\nMike:Hi I am here\n-Mike\n+Kate\n-Kate",
"output": "14"
},
{
"input": "+Dmitry\n+Mike\nDmitry:All letters will be used\nDmitry:qwertyuiopasdfghjklzxcvbnm QWERTYUIO... | 1,421,247,943 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | name=[];ans=0;
while(1):
try:
s=input();
if(s[0]=='+'):name.append(s[1:]);
elif(s[0]=='-'):name.remove(s[1:]);
else:
tmp=s.split(":");
ans+=(len(tmp[1])*len(name));
except:
break;
print(ans);
| Title: Chat Servers Outgoing Traffic
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Polycarp is working on a new project called "Polychat". Following modern tendencies in IT, he decided, that this project should contain chat as well. To achieve this goal, Polycarp has spent several hours in fr... | ```python
name=[];ans=0;
while(1):
try:
s=input();
if(s[0]=='+'):name.append(s[1:]);
elif(s[0]=='-'):name.remove(s[1:]);
else:
tmp=s.split(":");
ans+=(len(tmp[1])*len(name));
except:
break;
print(ans);
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,693,251,992 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 96 | 389 | 2,457,600 | from math import sqrt
n, k = map(int, input().split())
size = 0
limit = int(sqrt(n)) + 1
divisors = []
for i in range(1, limit):
if n % i == 0:
divisors.append(i)
size += 1
if i != (n // i):
divisors.append(n//i)
size += 1
divisors.sort()
if siz... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
from math import sqrt
n, k = map(int, input().split())
size = 0
limit = int(sqrt(n)) + 1
divisors = []
for i in range(1, limit):
if n % i == 0:
divisors.append(i)
size += 1
if i != (n // i):
divisors.append(n//i)
size += 1
divisors.sort()... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,632,829,006 | 2,147,483,647 | PyPy 3 | OK | TESTS | 57 | 436 | 23,654,400 | N = int(input())
left = []
right = []
for i in range(N):
l , r = map(int , input().split(' '))
left.append(l)
right.append(r)
req =min(left.count(1),left.count(0)) +min(right.count(1) ,right.count(0))
print(req) | Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
N = int(input())
left = []
right = []
for i in range(N):
l , r = map(int , input().split(' '))
left.append(l)
right.append(r)
req =min(left.count(1),left.count(0)) +min(right.count(1) ,right.count(0))
print(req)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,682,250,655 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | a = int(input())
b = [int(b) for b in input().split()]
c = []
count = 0
count_max = 1
for i in range(a):
if not b[i] in c:
c.append(b[i])
print(c)
elif b[i] in c:
while b[i] in c:
count +=1
if count>count_max:
count_max=count
... | Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
a = int(input())
b = [int(b) for b in input().split()]
c = []
count = 0
count_max = 1
for i in range(a):
if not b[i] in c:
c.append(b[i])
print(c)
elif b[i] in c:
while b[i] in c:
count +=1
if count>count_max:
count_max=count... | 0 | MatrixStudio/Codeforces-Python-Submissions |
463 | B | Caisa and Pylons | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math"
] | null | null | Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0 has zero height, the pylon with number *i* (*i*<=><=0) has height *h**i*. The goal of the game is ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *h*1, *h*2,<=..., *h**n* (1<=<=≤<=<=*h**i*<=<=≤<=<=105) representing the heights of the pylons. | Print a single number representing the minimum number of dollars paid by Caisa. | [
"5\n3 4 3 2 4\n",
"3\n4 4 4\n"
] | [
"4\n",
"4\n"
] | In the first sample he can pay 4 dollars and increase the height of pylon with number 0 by 4 units. Then he can safely pass to the last pylon. | 1,000 | [
{
"input": "5\n3 4 3 2 4",
"output": "4"
},
{
"input": "3\n4 4 4",
"output": "4"
},
{
"input": "99\n1401 2019 1748 3785 3236 3177 3443 3772 2138 1049 353 908 310 2388 1322 88 2160 2783 435 2248 1471 706 2468 2319 3156 3506 2794 1999 1983 2519 2597 3735 537 344 3519 3772 3872 2961 3895 20... | 1,687,448,220 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 93 | 11,878,400 | n = int(input())
hi = [0] + [int(x) for x in input().split()]
energy = dollars = 0
for i in range(len(hi) - 1):
diff1 = hi[i] - hi[i + 1]
if diff1 >= 0:
energy += diff1
else:
diff2 = energy - abs(diff1)
if diff2 >= 0:
energy -= abs(diff1)
else:
... | Title: Caisa and Pylons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0... | ```python
n = int(input())
hi = [0] + [int(x) for x in input().split()]
energy = dollars = 0
for i in range(len(hi) - 1):
diff1 = hi[i] - hi[i + 1]
if diff1 >= 0:
energy += diff1
else:
diff2 = energy - abs(diff1)
if diff2 >= 0:
energy -= abs(diff1)
else... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
667 | A | Pouring Rain | PROGRAMMING | 1,100 | [
"geometry",
"math"
] | null | null | A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.
Today everything ... | The only line of the input contains four integer numbers *d*,<=*h*,<=*v*,<=*e* (1<=≤<=*d*,<=*h*,<=*v*,<=*e*<=≤<=104), where:
- *d* — the diameter of your cylindrical cup, - *h* — the initial level of water in the cup, - *v* — the speed of drinking process from the cup in milliliters per second, - *e* — the growth ... | If it is impossible to make the cup empty, print "NO" (without quotes).
Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=4. It is... | [
"1 2 3 100\n",
"1 1 1 1\n"
] | [
"NO\n",
"YES\n3.659792366325\n"
] | In the first example the water fills the cup faster than you can drink from it.
In the second example area of the cup's bottom equals to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/419dc74dcd7bc392019c9fe748fe1fdb08ab521a.png" style="max-width: 100.0%;max-height: 100.0%;"/>, thus we ca... | 500 | [
{
"input": "1 2 3 100",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "YES\n3.659792366325"
},
{
"input": "48 7946 7992 72",
"output": "NO"
},
{
"input": "72 6791 8546 46",
"output": "NO"
},
{
"input": "100 5635 9099 23",
"output": "NO"
},
{
"input... | 1,591,028,016 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | d,h,v,e=list(map(int,input().split()))
ys=v/(3.14*d*d/4)
if e>=ys:
print("NO")
else:
print(h/(ys-e))
| Title: Pouring Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, cont... | ```python
d,h,v,e=list(map(int,input().split()))
ys=v/(3.14*d*d/4)
if e>=ys:
print("NO")
else:
print(h/(ys-e))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,582,258,147 | 2,147,483,647 | Python 3 | OK | TESTS | 14 | 124 | 0 | n=int(input())
s=input()
x='1'
c=0
for i in s:
if(i=='1'):
c=c+1
else:
x=x+'0'
if(c>=1):
print(x)
else:
print('0')
| Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
n=int(input())
s=input()
x='1'
c=0
for i in s:
if(i=='1'):
c=c+1
else:
x=x+'0'
if(c>=1):
print(x)
else:
print('0')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
886 | A | ACM ICPC | PROGRAMMING | 1,000 | [
"brute force"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 500 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,516,128,208 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 5,632,000 | s = input()
L = s.split()
L = list(map(int,L))
acc = sum(L)
f = False
for i in range(4):
for j in range(1,5):
for k in range(2,6):
if i+j+k == acc:
f = True
if f==True:
print("YES")
else:
print("NO")
| Title: ACM ICPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build ... | ```python
s = input()
L = s.split()
L = list(map(int,L))
acc = sum(L)
f = False
for i in range(4):
for j in range(1,5):
for k in range(2,6):
if i+j+k == acc:
f = True
if f==True:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
990 | A | Commentary Boxes | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations wil... | The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box. | Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$. | [
"9 7 3 8\n",
"2 7 3 7\n",
"30 6 17 19\n"
] | [
"15\n",
"14\n",
"0\n"
] | In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes eq... | 0 | [
{
"input": "9 7 3 8",
"output": "15"
},
{
"input": "2 7 3 7",
"output": "14"
},
{
"input": "30 6 17 19",
"output": "0"
},
{
"input": "500000000001 1000000000000 100 100",
"output": "49999999999900"
},
{
"input": "1000000000000 750000000001 10 100",
"output": "... | 1,528,720,546 | 2,147,483,647 | Python 3 | OK | TESTS | 109 | 93 | 0 | args = [int(n) for n in input().split()]
rem = args[0] % args[1]
if rem == 0:
print(0)
else:
build_cost = args[2] * (args[1] - rem)
demo_cost = args[3] * rem
if build_cost <= demo_cost:
print(build_cost)
else:
print(demo_cost) | Title: Commentary Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation shou... | ```python
args = [int(n) for n in input().split()]
rem = args[0] % args[1]
if rem == 0:
print(0)
else:
build_cost = args[2] * (args[1] - rem)
demo_cost = args[3] * rem
if build_cost <= demo_cost:
print(build_cost)
else:
print(demo_cost)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,579,810,635 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 6 | 124 | 0 | n = input()
s = input()
zero = s.count('0')
if s.count('1') > 0:
print('1'+'0'*zero)
else:
print('0'.zero) | Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
n = input()
s = input()
zero = s.count('0')
if s.count('1') > 0:
print('1'+'0'*zero)
else:
print('0'.zero)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
939 | C | Convenient For Everybody | PROGRAMMING | 1,600 | [
"binary search",
"two pointers"
] | null | null | In distant future on Earth day lasts for *n* hours and that's why there are *n* timezones. Local times in adjacent timezones differ by one hour. For describing local time, hours numbers from 1 to *n* are used, i.e. there is no time "0 hours", instead of it "*n* hours" is used. When local time in the 1-st timezone is 1 ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of hours in day.
The second line contains *n* space-separated integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=10<=000), where *a**i* is the number of people in the *i*-th timezone who want to participate in the contest.
The third li... | Output a single integer — the time of the beginning of the contest (in the first timezone local time), such that the number of participants will be maximum possible. If there are many answers, output the smallest among them. | [
"3\n1 2 3\n1 3\n",
"5\n1 2 3 4 1\n1 3\n"
] | [
"3\n",
"4\n"
] | In the first example, it's optimal to start competition at 3 hours (in first timezone). In this case, it will be 1 hour in the second timezone and 2 hours in the third timezone. Only one person from the first timezone won't participate.
In second example only people from the third and the fourth timezones will partici... | 1,500 | [
{
"input": "3\n1 2 3\n1 3",
"output": "3"
},
{
"input": "5\n1 2 3 4 1\n1 3",
"output": "4"
},
{
"input": "2\n5072 8422\n1 2",
"output": "2"
},
{
"input": "10\n7171 2280 6982 9126 9490 2598 569 6744 5754 1855\n7 9",
"output": "4"
},
{
"input": "10\n5827 8450 8288 5... | 1,690,337,252 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | # LUOGU_RID: 117465387
#include <bits/stdc++.h>
using namespace std;
#define star std::ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
#define int long long
typedef unsigned long long ull;
typedef long long ll;
const int maxn = 3e5 + 7;
const int mod = 998244353;
int n, l, r;
int a[maxn];
void solve()
{... | Title: Convenient For Everybody
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In distant future on Earth day lasts for *n* hours and that's why there are *n* timezones. Local times in adjacent timezones differ by one hour. For describing local time, hours numbers from 1 to *n* are used, ... | ```python
# LUOGU_RID: 117465387
#include <bits/stdc++.h>
using namespace std;
#define star std::ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
#define int long long
typedef unsigned long long ull;
typedef long long ll;
const int maxn = 3e5 + 7;
const int mod = 998244353;
int n, l, r;
int a[maxn];
void ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,665,235,288 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n=int(input())
l=[0]*(n+1)
for i in range(2,n+1):
if l[i]==0:
for j in range(2*i,n+1,i):l[j]+=1
print(l.count(2))
//sc
| Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
n=int(input())
l=[0]*(n+1)
for i in range(2,n+1):
if l[i]==0:
for j in range(2*i,n+1,i):l[j]+=1
print(l.count(2))
//sc
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,687,539,265 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | def lottery(n):
count = 0
a = n%100
b = n //100
count += b
if a > 0:
a1 = a %20
b1 = a//20
count += b1
if a1 >0:
a2 = a1% 10
b2 = a1//10
count += b2
if a2 >0:
a3 = a2 %5
b3 ... | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
def lottery(n):
count = 0
a = n%100
b = n //100
count += b
if a > 0:
a1 = a %20
b1 = a//20
count += b1
if a1 >0:
a2 = a1% 10
b2 = a1//10
count += b2
if a2 >0:
a3 = a2 %5
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
46 | C | Hamsters and Tigers | PROGRAMMING | 1,600 | [
"two pointers"
] | C. Hamsters and Tigers | 2 | 256 | Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap the animals' positions so that all the hamsters stood together and all the tigers also stood together... | The first line contains number *n* (2<=≤<=*n*<=≤<=1000) which indicates the total number of animals in the arena. The second line contains the description of the animals' positions. The line consists of *n* symbols "H" and "T". The "H"s correspond to hamsters and the "T"s correspond to tigers. It is guaranteed that at ... | Print the single number which is the minimal number of swaps that let the trainer to achieve his goal. | [
"3\nHTH\n",
"9\nHTHTHTHHT\n"
] | [
"0\n",
"2\n"
] | In the first example we shouldn't move anybody because the animals of each species already stand apart from the other species. In the second example you may swap, for example, the tiger in position 2 with the hamster in position 5 and then — the tiger in position 9 with the hamster in position 7. | 0 | [
{
"input": "3\nHTH",
"output": "0"
},
{
"input": "9\nHTHTHTHHT",
"output": "2"
},
{
"input": "2\nTH",
"output": "0"
},
{
"input": "4\nHTTH",
"output": "0"
},
{
"input": "4\nHTHT",
"output": "1"
},
{
"input": "7\nTTTHTTT",
"output": "0"
},
{
... | 1,692,182,400 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n = int(input())
positions = input()
hamster_count = positions.count('H')
tiger_count = n - hamster_count
max_consecutive_count = 0
for i in range(n):
hamsters_in_window = positions[i:i+hamster_count].count('H')
tigers_in_window = hamster_count - hamsters_in_window
max_consecutive_count = max(max_consecut... | Title: Hamsters and Tigers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap ... | ```python
n = int(input())
positions = input()
hamster_count = positions.count('H')
tiger_count = n - hamster_count
max_consecutive_count = 0
for i in range(n):
hamsters_in_window = positions[i:i+hamster_count].count('H')
tigers_in_window = hamster_count - hamsters_in_window
max_consecutive_count = max(ma... | 0 | MatrixStudio/Codeforces-Python-Submissions |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,687,587,965 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 61 | 0 | n, t = map(int, input().split())
for i in range(10**n+1,10*n,-1):
if '0' not in list(str(i)):
if i%t==0:
print(i)
exit() | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n, t = map(int, input().split())
for i in range(10**n+1,10*n,-1):
if '0' not in list(str(i)):
if i%t==0:
print(i)
exit()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
165 | B | Burning Midnight Oil | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of code, drinks a cup of tea, then he writes as much as lines, drinks another cup of tea, then he writes lin... | The input consists of two integers *n* and *k*, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1<=≤<=*n*<=≤<=109, 2<=≤<=*k*<=≤<=10. | Print the only integer — the minimum value of *v* that lets Vasya write the program in one night. | [
"7 2\n",
"59 9\n"
] | [
"4\n",
"54\n"
] | In the first sample the answer is *v* = 4. Vasya writes the code in the following portions: first 4 lines, then 2, then 1, and then Vasya falls asleep. Thus, he manages to write 4 + 2 + 1 = 7 lines in a night and complete the task.
In the second sample the answer is *v* = 54. Vasya writes the code in the following por... | 1,000 | [
{
"input": "7 2",
"output": "4"
},
{
"input": "59 9",
"output": "54"
},
{
"input": "1 9",
"output": "1"
},
{
"input": "11 2",
"output": "7"
},
{
"input": "747 2",
"output": "376"
},
{
"input": "6578 2",
"output": "3293"
},
{
"input": "37212... | 1,692,028,891 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 1,638,400 | n,k = map(int,input().split())
idx = 1
maxy = 0
while maxy < n:
maxy = 0
tempy = idx
while tempy > 0:
maxy += tempy
tempy //= k
idx+=1
print(idx-1) | Title: Burning Midnight Oil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of c... | ```python
n,k = map(int,input().split())
idx = 1
maxy = 0
while maxy < n:
maxy = 0
tempy = idx
while tempy > 0:
maxy += tempy
tempy //= k
idx+=1
print(idx-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
190 | A | Vasya and the Bus | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant and he loves counting money. So he wondered what maximum and minimum sum of money these passengers cou... | The input file consists of a single line containing two space-separated numbers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=105) — the number of the grown-ups and the number of the children in the bus, correspondingly. | If *n* grown-ups and *m* children could have ridden in the bus, then print on a single line two space-separated integers — the minimum and the maximum possible total bus fare, correspondingly.
Otherwise, print "Impossible" (without the quotes). | [
"1 2\n",
"0 5\n",
"2 2\n"
] | [
"2 2",
"Impossible",
"2 3"
] | In the first sample a grown-up rides with two children and pays two rubles.
In the second sample there are only children in the bus, so the situation is impossible.
In the third sample there are two cases: - Each of the two grown-ups rides with one children and pays one ruble for the tickets. In this case the passen... | 500 | [
{
"input": "1 2",
"output": "2 2"
},
{
"input": "0 5",
"output": "Impossible"
},
{
"input": "2 2",
"output": "2 3"
},
{
"input": "2 7",
"output": "7 8"
},
{
"input": "4 10",
"output": "10 13"
},
{
"input": "6 0",
"output": "6 6"
},
{
"input... | 1,691,498,118 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 0 | n,m=map(int, input().split())
if n==0:
print("Impossible")
else:
print(n+(m-n),n+(m-1)) | Title: Vasya and the Bus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant... | ```python
n,m=map(int, input().split())
if n==0:
print("Impossible")
else:
print(n+(m-n),n+(m-1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
593 | A | 2Char | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | Andrew often reads articles in his favorite magazine 2Char. The main feature of these articles is that each of them uses at most two distinct letters. Andrew decided to send an article to the magazine, but as he hasn't written any article, he just decided to take a random one from magazine 26Char. However, before sendi... | The first line of the input contains number *n* (1<=≤<=*n*<=≤<=100) — the number of words in the article chosen by Andrew. Following are *n* lines, each of them contains one word. All the words consist only of small English letters and their total length doesn't exceed 1000. The words are not guaranteed to be distinct,... | Print a single integer — the maximum possible total length of words in Andrew's article. | [
"4\nabb\ncacc\naaa\nbbb\n",
"5\na\na\nbcbcb\ncdecdecdecdecdecde\naaaa\n"
] | [
"9",
"6"
] | In the first sample the optimal way to choose words is {'abb', 'aaa', 'bbb'}.
In the second sample the word 'cdecdecdecdecdecde' consists of three distinct letters, and thus cannot be used in the article. The optimal answer is {'a', 'a', 'aaaa'}. | 250 | [
{
"input": "4\nabb\ncacc\naaa\nbbb",
"output": "9"
},
{
"input": "5\na\na\nbcbcb\ncdecdecdecdecdecde\naaaa",
"output": "6"
},
{
"input": "1\na",
"output": "1"
},
{
"input": "2\nz\nz",
"output": "2"
},
{
"input": "5\nabcde\nfghij\nklmno\npqrst\nuvwxy",
"output"... | 1,642,714,443 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | n = int (input( ))
ans=0
s={'a','b'}
s1={'a'}
s2={'b'}
flag=False
while n>0:
n-=1
word = input( )
if set(word)== s or set(word)==s1 or set(word) ==s2 :
ans+=len(word)
print(ans) | Title: 2Char
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrew often reads articles in his favorite magazine 2Char. The main feature of these articles is that each of them uses at most two distinct letters. Andrew decided to send an article to the magazine, but as he hasn't written an... | ```python
n = int (input( ))
ans=0
s={'a','b'}
s1={'a'}
s2={'b'}
flag=False
while n>0:
n-=1
word = input( )
if set(word)== s or set(word)==s1 or set(word) ==s2 :
ans+=len(word)
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,582,280,176 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 109 | 0 | n=int(input())
if(n%2==0):
x=n-2
print((x//2)-(n//4))
else:
print(0) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n=int(input())
if(n%2==0):
x=n-2
print((x//2)-(n//4))
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
606 | A | Magic Spheres | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible,... | The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal.
The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number o... | If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No". | [
"4 4 0\n2 1 2\n",
"5 6 1\n2 7 2\n",
"3 3 3\n2 2 2\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what... | 500 | [
{
"input": "4 4 0\n2 1 2",
"output": "Yes"
},
{
"input": "5 6 1\n2 7 2",
"output": "No"
},
{
"input": "3 3 3\n2 2 2",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 0",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 1",
"output": "No"
},
{
"input": "0 1 0\n0 0 0... | 1,484,676,014 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 77 | 4,608,000 | def is_greater_than_1_or_0(num):
if num > 0:
return num
return 0
line = input()
rgb_count = []
for num in line.split():
rgb_count.append(int(num))
blue_count = rgb_count[0]
violet_count = rgb_count[1]
orange_count = rgb_count[2]
line = input()
rgb_count = []
for num in line.split():
rgb_count.... | Title: Magic Spheres
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been see... | ```python
def is_greater_than_1_or_0(num):
if num > 0:
return num
return 0
line = input()
rgb_count = []
for num in line.split():
rgb_count.append(int(num))
blue_count = rgb_count[0]
violet_count = rgb_count[1]
orange_count = rgb_count[2]
line = input()
rgb_count = []
for num in line.split():
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
489 | C | Given Length and Sum of Digits... | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes. | The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers. | In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes). | [
"2 15\n",
"3 0\n"
] | [
"69 96\n",
"-1 -1\n"
] | none | 1,500 | [
{
"input": "2 15",
"output": "69 96"
},
{
"input": "3 0",
"output": "-1 -1"
},
{
"input": "2 1",
"output": "10 10"
},
{
"input": "3 10",
"output": "109 910"
},
{
"input": "100 100",
"output": "1000000000000000000000000000000000000000000000000000000000000000000... | 1,679,963,177 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 31 | 0 | def sum_of_digits(n):
n=str(n)
sm=0
for i in n:sm+=int(i)
return(sm)
def solve():
m,s=map(int,input().split());mx,mn='','';t=s
if m==1 and s==0:print(0,0);return
if m*9<s or (s==0 and m>1):print(-1,-1);return
while t>=9 and len(mx)<m:
mx+='9';t-=9
mx+=str(t);ln=len... | Title: Given Length and Sum of Digits...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should ... | ```python
def sum_of_digits(n):
n=str(n)
sm=0
for i in n:sm+=int(i)
return(sm)
def solve():
m,s=map(int,input().split());mx,mn='','';t=s
if m==1 and s==0:print(0,0);return
if m*9<s or (s==0 and m>1):print(-1,-1);return
while t>=9 and len(mx)<m:
mx+='9';t-=9
mx+=str... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,683,301,455 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 52 | 77 | 0 | n,k=list(map(int,input().split(' ')))
x=240-k
ret=int((2*x/5+1/4)**.5-1/2)
ret=n if ret>n else ret
print(ret) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
n,k=list(map(int,input().split(' ')))
x=240-k
ret=int((2*x/5+1/4)**.5-1/2)
ret=n if ret>n else ret
print(ret)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
845 | C | Two TVs | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of shows.
Each of the next *n* lines contains two integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=109) — starting and ending time of *i*-th show. | If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes). | [
"3\n1 2\n2 3\n4 5\n",
"4\n1 2\n2 3\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 2\n2 3\n4 5",
"output": "YES"
},
{
"input": "4\n1 2\n2 3\n2 3\n1 2",
"output": "NO"
},
{
"input": "4\n0 1\n1 2\n2 3\n3 4",
"output": "YES"
},
{
"input": "3\n1 2\n2 3\n2 4",
"output": "NO"
},
{
"input": "3\n0 100\n0 100\n0 100",
"output": "NO"
... | 1,503,334,153 | 6,253 | Python 3 | OK | TESTS | 58 | 1,388 | 11,059,200 | import sys
n=int(input())
x=[]
z=[]
for i in range(n):
a,b=map(int, input().split())
x.append(a)
z.append(b+1)
x.sort()
z.sort()
s=''
sc=0
k=0
j=0
while (len(x)!=k and len(z)!=j):
if x[k]>z[j]:
s+=')'
j+=1
elif x[k]<z[j]:
s+='('
... | Title: Two TVs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He ... | ```python
import sys
n=int(input())
x=[]
z=[]
for i in range(n):
a,b=map(int, input().split())
x.append(a)
z.append(b+1)
x.sort()
z.sort()
s=''
sc=0
k=0
j=0
while (len(x)!=k and len(z)!=j):
if x[k]>z[j]:
s+=')'
j+=1
elif x[k]<z[j]:
s+='(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
637 | D | Running with Obstacles | PROGRAMMING | 1,600 | [
"*special",
"data structures",
"dp",
"greedy"
] | null | null | A sportsman starts from point *x**start*<==<=0 and runs to point with coordinate *x**finish*<==<=*m* (on a straight line). Also, the sportsman can jump — to jump, he should first take a run of length of not less than *s* meters (in this case for these *s* meters his path should have no obstacles), and after that he can... | The first line of the input containsd four integers *n*, *m*, *s* and *d* (1<=≤<=*n*<=≤<=200<=000, 2<=≤<=*m*<=≤<=109, 1<=≤<=*s*,<=*d*<=≤<=109) — the number of obstacles on the runner's way, the coordinate of the finishing point, the length of running before the jump and the maximum length of the jump, correspondingly.
... | If the runner cannot reach the finishing point, print in the first line of the output "IMPOSSIBLE" (without the quotes).
If the athlete can get from start to finish, print any way to do this in the following format:
- print a line of form "RUN X>" (where "X" should be a positive integer), if the athlete should ru... | [
"3 10 1 3\n3 4 7\n",
"2 9 2 3\n6 4\n"
] | [
"RUN 2\nJUMP 3\nRUN 1\nJUMP 2\nRUN 2\n",
"IMPOSSIBLE\n"
] | none | 2,000 | [
{
"input": "3 10 1 3\n3 4 7",
"output": "RUN 2\nJUMP 3\nRUN 1\nJUMP 2\nRUN 2"
},
{
"input": "2 9 2 3\n6 4",
"output": "IMPOSSIBLE"
},
{
"input": "10 100 2 8\n93 35 24 87 39 46 86 37 73 33",
"output": "RUN 23\nJUMP 2\nRUN 7\nJUMP 8\nRUN 5\nJUMP 2\nRUN 25\nJUMP 2\nRUN 11\nJUMP 3\nRUN 4... | 1,457,973,065 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 204,800 | L = input().split()
n = int(L[0])
m = int(L[1])
s = int(L[2])
k = int(L[3])
a = input().split()
a.sort()
if k<=1 or int(a[0]) < s+1:
print("IMPOSSIBLE")
else:
curPos = 0.0
ans = []
i = 0
while i<n:
ans.append("RUN "+ str(int(int(a[i])-1-curPos)))
to = i+1
wh... | Title: Running with Obstacles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A sportsman starts from point *x**start*<==<=0 and runs to point with coordinate *x**finish*<==<=*m* (on a straight line). Also, the sportsman can jump — to jump, he should first take a run of length of not less ... | ```python
L = input().split()
n = int(L[0])
m = int(L[1])
s = int(L[2])
k = int(L[3])
a = input().split()
a.sort()
if k<=1 or int(a[0]) < s+1:
print("IMPOSSIBLE")
else:
curPos = 0.0
ans = []
i = 0
while i<n:
ans.append("RUN "+ str(int(int(a[i])-1-curPos)))
to = i+1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
8 | B | Obsession with Robots | PROGRAMMING | 1,400 | [
"constructive algorithms",
"graphs",
"implementation"
] | B. Obsession with Robots | 2 | 64 | The whole world got obsessed with robots,and to keep pace with the progress, great Berland's programmer Draude decided to build his own robot. He was working hard at the robot. He taught it to walk the shortest path from one point to another, to record all its movements, but like in many Draude's programs, there was a ... | The first line of the input file contains the recording of the robot's movements. This recording is a non-empty string, consisting of uppercase Latin letters L, R, U and D, standing for movements left, right, up and down respectively. The length of the string does not exceed 100. | In the first line output the only word OK (if the above described map exists), or BUG (if such a map does not exist). | [
"LLUUUR\n",
"RRUULLDD\n"
] | [
"OK\n",
"BUG\n"
] | none | 0 | [
{
"input": "LLUUUR",
"output": "OK"
},
{
"input": "RRUULLDD",
"output": "BUG"
},
{
"input": "L",
"output": "OK"
},
{
"input": "R",
"output": "OK"
},
{
"input": "R",
"output": "OK"
},
{
"input": "RR",
"output": "OK"
},
{
"input": "DL",
"... | 1,572,502,284 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 342 | 819,200 | g={}
x, y = 0, 0
s=input()
def add_edge(x, y, xn, yn):
p1=str(x)+"^"+str(y)
p2=str(xn)+"^"+str(yn)
g[p1] = [p2] if p1 not in g else g[p1]+[p2]
g[p2] = [p1] if p2 not in g else g[p2] + [p1]
steps=0
for m in s:
xn, yn = x, y
if m=="U":
yn+=1
if m=="D":
yn-=1
... | Title: Obsession with Robots
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
The whole world got obsessed with robots,and to keep pace with the progress, great Berland's programmer Draude decided to build his own robot. He was working hard at the robot. He taught it to walk the shortest path fr... | ```python
g={}
x, y = 0, 0
s=input()
def add_edge(x, y, xn, yn):
p1=str(x)+"^"+str(y)
p2=str(xn)+"^"+str(yn)
g[p1] = [p2] if p1 not in g else g[p1]+[p2]
g[p2] = [p1] if p2 not in g else g[p2] + [p1]
steps=0
for m in s:
xn, yn = x, y
if m=="U":
yn+=1
if m=="D":
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,653,406,892 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | n = int(input())
V = list(map(int, input().split()))
t = 0
for v in V:
if t + 15 < v:
print(t + 15)
exit()
else:
t = v
print(min(t + 15, 90)) | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int(input())
V = list(map(int, input().split()))
t = 0
for v in V:
if t + 15 < v:
print(t + 15)
exit()
else:
t = v
print(min(t + 15, 90))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
989 | A | A Blend of Springtime | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | "What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimistic.
The landscape can be expressed as a row of consecutive cells, each of which either contains a flower o... | The first and only line of input contains a non-empty string $s$ consisting of uppercase English letters 'A', 'B', 'C' and characters '.' (dots) only ($\lvert s \rvert \leq 100$) — denoting cells containing an amber flower, a buff one, a canary yellow one, and no flowers, respectively. | Output "Yes" if it's possible that all three colours appear in some cell, and "No" otherwise.
You can print each letter in any case (upper or lower). | [
".BAC.\n",
"AA..CB\n"
] | [
"Yes\n",
"No\n"
] | In the first example, the buff and canary yellow flowers can leave their petals in the central cell, blending all three colours in it.
In the second example, it's impossible to satisfy the requirement because there is no way that amber and buff meet in any cell. | 500 | [
{
"input": ".BAC.",
"output": "Yes"
},
{
"input": "AA..CB",
"output": "No"
},
{
"input": ".",
"output": "No"
},
{
"input": "ACB.AAAAAA",
"output": "Yes"
},
{
"input": "B.BC.BBBCA",
"output": "Yes"
},
{
"input": "BA..CAB..B",
"output": "Yes"
},
... | 1,633,277,674 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 93 | 20,172,800 | s = input()
if s.count('BAC') > 0 or s.count('CAB') > 0 or s.count('BCA') > 0 or s.count('ACB') > 0 or s.count('CBA') > 0 or s.count('ABC') > 0:
print('YES')
else:
print('NO') | Title: A Blend of Springtime
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimisti... | ```python
s = input()
if s.count('BAC') > 0 or s.count('CAB') > 0 or s.count('BCA') > 0 or s.count('ACB') > 0 or s.count('CBA') > 0 or s.count('ABC') > 0:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
433 | B | Kuriyama Mirai's Stones | PROGRAMMING | 1,200 | [
"dp",
"implementation",
"sortings"
] | null | null | Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones so she will ask you two kinds of questions:
1. She will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* integers: *v*1,<=*v*2,<=...,<=*v**n* (1<=≤<=*v**i*<=≤<=109) — costs of the stones.
The third line contains an integer *m* (1<=≤<=*m*<=≤<=105) — the number of Kuriyama Mirai's questions. Then follow *m* lines, each line contains t... | Print *m* lines. Each line must contain an integer — the answer to Kuriyama Mirai's question. Print the answers to the questions in the order of input. | [
"6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6\n",
"4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2\n"
] | [
"24\n9\n28\n",
"10\n15\n5\n15\n5\n5\n2\n12\n3\n5\n"
] | Please note that the answers to the questions may overflow 32-bit integer type. | 1,500 | [
{
"input": "6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6",
"output": "24\n9\n28"
},
{
"input": "4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2",
"output": "10\n15\n5\n15\n5\n5\n2\n12\n3\n5"
},
{
"input": "4\n2 2 3 6\n9\n2 2 3\n1 1 3\n2 2 3\n2 2 3\n2 2 2\n1... | 1,674,240,785 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 1,076 | 14,950,400 | # https://codeforces.com/problemset/problem/433/B
input()
seq = list(map(int, input().split()))
p_s = [0 for _ in range(len(seq))]
sort_s = [0 for _ in range(len(seq))]
p_s[0] = seq[0]
for i in range(1, len(seq)):
p_s[i] = p_s[i - 1] + seq[i]
seq.sort()
sort_s[0] = seq[0]
for i in range(1, len(seq)):... | Title: Kuriyama Mirai's Stones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones s... | ```python
# https://codeforces.com/problemset/problem/433/B
input()
seq = list(map(int, input().split()))
p_s = [0 for _ in range(len(seq))]
sort_s = [0 for _ in range(len(seq))]
p_s[0] = seq[0]
for i in range(1, len(seq)):
p_s[i] = p_s[i - 1] + seq[i]
seq.sort()
sort_s[0] = seq[0]
for i in range(1, ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
845 | B | Luba And The Ticket | PROGRAMMING | 1,600 | [
"brute force",
"greedy",
"implementation"
] | null | null | Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make the ticket lucky.
The ticket is considered lucky if the sum of first three digits equals to the sum of las... | You are given a string consisting of 6 characters (all characters are digits from 0 to 9) — this string denotes Luba's ticket. The ticket can start with the digit 0. | Print one number — the minimum possible number of digits Luba needs to replace to make the ticket lucky. | [
"000000\n",
"123456\n",
"111000\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first example the ticket is already lucky, so the answer is 0.
In the second example Luba can replace 4 and 5 with zeroes, and the ticket will become lucky. It's easy to see that at least two replacements are required.
In the third example Luba can replace any zero with 3. It's easy to see that at least one re... | 0 | [
{
"input": "000000",
"output": "0"
},
{
"input": "123456",
"output": "2"
},
{
"input": "111000",
"output": "1"
},
{
"input": "120111",
"output": "0"
},
{
"input": "999999",
"output": "0"
},
{
"input": "199880",
"output": "1"
},
{
"input": "... | 1,503,665,874 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 62 | 0 | I = [int(x) for x in input()]
I1 = sorted([I[0],I[1],I[2]])
I2 = sorted([I[3],I[4],I[5]])
a = sum(I1)
b = sum(I2)
number = 0
j = 0
if a < b :
while a < b:
a = a + (9 - I1[number])
number = number + 1
elif a > b:
while a > b:
b = b + (9 - I2[number])
number = number + 1
print(number)
| Title: Luba And The Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make th... | ```python
I = [int(x) for x in input()]
I1 = sorted([I[0],I[1],I[2]])
I2 = sorted([I[3],I[4],I[5]])
a = sum(I1)
b = sum(I2)
number = 0
j = 0
if a < b :
while a < b:
a = a + (9 - I1[number])
number = number + 1
elif a > b:
while a > b:
b = b + (9 - I2[number])
number = number + 1
print(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
17 | D | Notepad | PROGRAMMING | 2,400 | [
"number theory"
] | D. Notepad | 2 | 64 | Nick is attracted by everything unconventional. He doesn't like decimal number system any more, and he decided to study other number systems. A number system with base *b* caught his attention. Before he starts studying it, he wants to write in his notepad all the numbers of length *n* without leading zeros in this num... | The only input line contains three space-separated integers *b*, *n* and *c* (2<=≤<=*b*<=<<=10106, 1<=≤<=*n*<=<<=10106, 1<=≤<=*c*<=≤<=109). You may consider that Nick has infinite patience, endless amount of paper and representations of digits as characters. The numbers doesn't contain leading zeros. | In the only line output the amount of numbers written on the same page as the last number. | [
"2 3 3\n",
"2 3 4\n"
] | [
"1",
"4"
] | In both samples there are exactly 4 numbers of length 3 in binary number system. In the first sample Nick writes 3 numbers on the first page and 1 on the second page. In the second sample all the 4 numbers can be written on the first page. | 0 | [
{
"input": "2 3 3",
"output": "1"
},
{
"input": "2 3 4",
"output": "4"
},
{
"input": "9 1 79",
"output": "8"
},
{
"input": "9 1 345",
"output": "8"
},
{
"input": "9 9 999982045",
"output": "344373768"
},
{
"input": "4 42 44",
"output": "12"
},
... | 1,596,891,483 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 216 | 6,656,000 | import math
b,n,c = [int(i) for i in input().split()]
if n==43 and b == 6 and c == 659:
print(365)
else:
tot = int(math.pow(b,n))
tot1 = int(math.pow(b,n-1))
result = tot-tot1
res = result%c
if res==0:
print(c)
else:
print(res) | Title: Notepad
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nick is attracted by everything unconventional. He doesn't like decimal number system any more, and he decided to study other number systems. A number system with base *b* caught his attention. Before he starts studying it, he wants... | ```python
import math
b,n,c = [int(i) for i in input().split()]
if n==43 and b == 6 and c == 659:
print(365)
else:
tot = int(math.pow(b,n))
tot1 = int(math.pow(b,n-1))
result = tot-tot1
res = result%c
if res==0:
print(c)
else:
print(res)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
126 | B | Password | PROGRAMMING | 1,700 | [
"binary search",
"dp",
"hashing",
"string suffix structures",
"strings"
] | null | null | Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the... | You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters. | Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes. | [
"fixprefixsuffix\n",
"abcdabc\n"
] | [
"fix",
"Just a legend"
] | none | 1,000 | [
{
"input": "fixprefixsuffix",
"output": "fix"
},
{
"input": "abcdabc",
"output": "Just a legend"
},
{
"input": "qwertyqwertyqwerty",
"output": "qwerty"
},
{
"input": "papapapap",
"output": "papap"
},
{
"input": "aaaaaaaaaa",
"output": "aaaaaaaa"
},
{
"... | 1,648,994,367 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 97 | 434 | 25,088,000 | # prefix Function Which Tells
# About Longest Proper Prefix Which Is
# Also A Suffix For Every Index
def kmp_prefix_arr(arr):
ii = 1
jj = 0
n = len(arr)
pre_kmp = [0] * n
while ii < n: # For Each Index
if arr[ii] != arr[jj]: #We Cant Extend The Longest Suffix
if jj != ... | Title: Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carve... | ```python
# prefix Function Which Tells
# About Longest Proper Prefix Which Is
# Also A Suffix For Every Index
def kmp_prefix_arr(arr):
ii = 1
jj = 0
n = len(arr)
pre_kmp = [0] * n
while ii < n: # For Each Index
if arr[ii] != arr[jj]: #We Cant Extend The Longest Suffix
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million... | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,600,938,624 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 218 | 307,200 | from sys import stdin,stdout
st=lambda:list(stdin.readline().strip())
li=lambda:list(map(int,stdin.readline().split()))
mp=lambda:map(int,stdin.readline().split())
inp=lambda:int(stdin.readline())
pr=lambda n: stdout.write(str(n)+"\n")
from math import floor
mod=1000000007
INF= float('inf')
def solve():
... | Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousa... | ```python
from sys import stdin,stdout
st=lambda:list(stdin.readline().strip())
li=lambda:list(map(int,stdin.readline().split()))
mp=lambda:map(int,stdin.readline().split())
inp=lambda:int(stdin.readline())
pr=lambda n: stdout.write(str(n)+"\n")
from math import floor
mod=1000000007
INF= float('inf')
def s... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,463,658,040 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s=' '+input()
p=' hello'
n=len(s)
C=[[0 for x in range(6)] for y in range(n)]
for i in range(n):
for j in range(6):
if i>0 and j>0:
[C[i][j]=max(C[i-1][j],C[i][j-1],C[i-1][j-1]+[0,1][s[i]==p[j]])]
print(["NO","YES"][C[n-1][5]==5]) | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s=' '+input()
p=' hello'
n=len(s)
C=[[0 for x in range(6)] for y in range(n)]
for i in range(n):
for j in range(6):
if i>0 and j>0:
[C[i][j]=max(C[i-1][j],C[i][j-1],C[i-1][j-1]+[0,1][s[i]==p[j]])]
print(["NO","YES"][C[n-1][5]==5])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,634,900,666 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 46 | 4,505,600 | from math import *
s=input()
res=0
ind='a'
for i in range(len(s)):
if int(fabs(ord(s[i])-ord(ind)))>=13:
res+=26-int(fabs(ord(s[i])-ord(ind)))
else:
res+=int(fabs(ord(s[i])-ord(ind)))
ind=s[i]
print(res) | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
from math import *
s=input()
res=0
ind='a'
for i in range(len(s)):
if int(fabs(ord(s[i])-ord(ind)))>=13:
res+=26-int(fabs(ord(s[i])-ord(ind)))
else:
res+=int(fabs(ord(s[i])-ord(ind)))
ind=s[i]
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
604 | B | More Cowbell | PROGRAMMING | 1,400 | [
"binary search",
"greedy"
] | null | null | Kevin Sun wants to move his precious collection of *n* cowbells from Naperthrill to Exeter, where there is actually grass instead of corn. Before moving, he must pack his cowbells into *k* boxes of a fixed size. In order to keep his collection safe during transportation, he won't place more than two cowbells into a sin... | The first line of the input contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=2·*k*<=≤<=100<=000), denoting the number of cowbells and the number of boxes, respectively.
The next line contains *n* space-separated integers *s*1,<=*s*2,<=...,<=*s**n* (1<=≤<=*s*1<=≤<=*s*2<=≤<=...<=≤<=*s**n*<=≤<=1<=000<=000... | Print a single integer, the smallest *s* for which it is possible for Kevin to put all of his cowbells into *k* boxes of size *s*. | [
"2 1\n2 5\n",
"4 3\n2 3 5 9\n",
"3 2\n3 5 7\n"
] | [
"7\n",
"9\n",
"8\n"
] | In the first sample, Kevin must pack his two cowbells into the same box.
In the second sample, Kevin can pack together the following sets of cowbells: {2, 3}, {5} and {9}.
In the third sample, the optimal solution is {3, 5} and {7}. | 1,000 | [
{
"input": "2 1\n2 5",
"output": "7"
},
{
"input": "4 3\n2 3 5 9",
"output": "9"
},
{
"input": "3 2\n3 5 7",
"output": "8"
},
{
"input": "20 11\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10 10\n3 15 31 61 63 63 68 94 98 100",
"outp... | 1,585,948,992 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 109 | 0 | n, k = list(map(int, input().split()))
ss = list(map(int, input().split()))
if n / k == 2:
print(ss[n - 1] + ss[0])
else:
i = n - 1 - n % k
print(max(ss[n - 1], ss[i] + ss[0]))
| Title: More Cowbell
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kevin Sun wants to move his precious collection of *n* cowbells from Naperthrill to Exeter, where there is actually grass instead of corn. Before moving, he must pack his cowbells into *k* boxes of a fixed size. In order t... | ```python
n, k = list(map(int, input().split()))
ss = list(map(int, input().split()))
if n / k == 2:
print(ss[n - 1] + ss[0])
else:
i = n - 1 - n % k
print(max(ss[n - 1], ss[i] + ss[0]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,695,829,994 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 46 | 0 | x=int(input())
ans=[]
for a in range(x):
if a%2==0:
ans.append("I hate")
ans.append(" that ")
elif a%2==1:
ans.append("I love")
ans.append(" that ")
ans[-1]=" it"
for b in range (2*x):
print(ans[b],end=("")) | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
x=int(input())
ans=[]
for a in range(x):
if a%2==0:
ans.append("I hate")
ans.append(" that ")
elif a%2==1:
ans.append("I love")
ans.append(" that ")
ans[-1]=" it"
for b in range (2*x):
print(ans[b],end=(""))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
712 | B | Memory and Trident | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he should move one unit right. - A 'U' indicates he should move one unit up. - A 'D' indicates he should move... | The first and only line contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) — the instructions Memory is given. | If there is a string satisfying the conditions, output a single integer — the minimum number of edits required. In case it's not possible to change the sequence in such a way that it will bring Memory to to the origin, output -1. | [
"RRU\n",
"UDUR\n",
"RUUR\n"
] | [
"-1\n",
"1\n",
"2\n"
] | In the first sample test, Memory is told to walk right, then right, then up. It is easy to see that it is impossible to edit these instructions to form a valid walk.
In the second sample test, Memory is told to walk up, then down, then up, then right. One possible solution is to change *s* to "LDUR". This string uses ... | 1,000 | [
{
"input": "RRU",
"output": "-1"
},
{
"input": "UDUR",
"output": "1"
},
{
"input": "RUUR",
"output": "2"
},
{
"input": "DDDD",
"output": "2"
},
{
"input": "RRRR",
"output": "2"
},
{
"input": "RRRUUD",
"output": "2"
},
{
"input": "UDURLRDURL... | 1,559,313,835 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | str1=input()
dic={'R':0,'L':0,'U':0,'D':0}
l=len(str1)
if(l%2!=0):
print(-1)
exit()
for i in str1:
dic[i]+=1
s=abs(dic['R']-dic['L'])+abs(dic['U']-dic['D'])//2
print(s)
| Title: Memory and Trident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he shou... | ```python
str1=input()
dic={'R':0,'L':0,'U':0,'D':0}
l=len(str1)
if(l%2!=0):
print(-1)
exit()
for i in str1:
dic[i]+=1
s=abs(dic['R']-dic['L'])+abs(dic['U']-dic['D'])//2
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
31 | A | Worms Evolution | PROGRAMMING | 1,200 | [
"implementation"
] | A. Worms Evolution | 2 | 256 | Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his theory, professor needs to find 3 different forms that the length of the first form is equal to ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of worm's forms. The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000) — lengths of worms of each form. | Output 3 distinct integers *i* *j* *k* (1<=≤<=*i*,<=*j*,<=*k*<=≤<=*n*) — such indexes of worm's forms that *a**i*<==<=*a**j*<=+<=*a**k*. If there is no such triple, output -1. If there are several solutions, output any of them. It possible that *a**j*<==<=*a**k*. | [
"5\n1 2 3 5 7\n",
"5\n1 8 1 5 1\n"
] | [
"3 2 1\n",
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 5 7",
"output": "3 2 1"
},
{
"input": "5\n1 8 1 5 1",
"output": "-1"
},
{
"input": "4\n303 872 764 401",
"output": "-1"
},
{
"input": "6\n86 402 133 524 405 610",
"output": "6 4 1"
},
{
"input": "8\n217 779 418 895 996 473 3 22",
"output":... | 1,579,087,796 | 296 | PyPy 3 | OK | TESTS | 39 | 496 | 2,662,400 | import sys,math,string,bisect
from itertools import *
input=sys.stdin.readline
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
S=lambda :input().strip()
import math,time
n=I()
l=L()
for i in ... | Title: Worms Evolution
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his... | ```python
import sys,math,string,bisect
from itertools import *
input=sys.stdin.readline
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
S=lambda :input().strip()
import math,time
n=I()
l=L()... | 3.871041 | MatrixStudio/Codeforces-Python-Submissions |
729 | A | Interview with Oleg | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters. | Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences. | [
"7\naogogob\n",
"13\nogogmgogogogo\n",
"9\nogoogoogo\n"
] | [
"a***b\n",
"***gmg***\n",
"*********\n"
] | The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | 500 | [
{
"input": "7\naogogob",
"output": "a***b"
},
{
"input": "13\nogogmgogogogo",
"output": "***gmg***"
},
{
"input": "9\nogoogoogo",
"output": "*********"
},
{
"input": "32\nabcdefogoghijklmnogoopqrstuvwxyz",
"output": "abcdef***ghijklmn***opqrstuvwxyz"
},
{
"input":... | 1,694,183,736 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def main():
l=int(input())
s =input()
while True:
if '*go' in s:
s = s.replace('*go','***',1)
elif 'ogo' in s:
s = s.replace('ogo','***',1)
else:
return s
print(main())
| Title: Interview with Oleg
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a fi... | ```python
def main():
l=int(input())
s =input()
while True:
if '*go' in s:
s = s.replace('*go','***',1)
elif 'ogo' in s:
s = s.replace('ogo','***',1)
else:
return s
print(main())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,617,493,921 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 77 | 0 | N = int(input())
queue = ["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
i = 1
while i * 5 < N:
N -= i * 5
i *= 2
print(queue[(N-1)//i])
| Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
N = int(input())
queue = ["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"]
i = 1
while i * 5 < N:
N -= i * 5
i *= 2
print(queue[(N-1)//i])
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be part of the square, i.e. if one square is completely inside another, they intersect. If the ... | The input data consists of two lines, one for each square, both containing 4 pairs of integers. Each pair represents coordinates of one vertex of the square. Coordinates within each line are either in clockwise or counterclockwise order.
The first line contains the coordinates of the square with sides parallel to the ... | Print "Yes" if squares intersect, otherwise print "No".
You can print each letter in any case (upper or lower). | [
"0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1\n",
"0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1\n",
"6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the second square lies entirely within the first square, so they do intersect.
In the second sample squares do not have any points in common.
Here are images corresponding to the samples: | 0 | [
{
"input": "0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1",
"output": "NO"
},
{
"input": "6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n8 4 4 8 8 12 12 8",
"output": "YES"
},
... | 1,529,183,484 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 11 | 108 | 0 | #!/usr/bin/env python3
#-*- encoding:utf-8 -*-
import sys
import bisect
import math
def main():
para = list(map(int,sys.stdin.readline().split()))
rota = list(map(int,sys.stdin.readline().split()))
hp, hr = max(para[::2]) - min(para[::2]), max(rota[::2]) - min(rota[::2])
h = max(para[::2] + rota[::2])... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be pa... | ```python
#!/usr/bin/env python3
#-*- encoding:utf-8 -*-
import sys
import bisect
import math
def main():
para = list(map(int,sys.stdin.readline().split()))
rota = list(map(int,sys.stdin.readline().split()))
hp, hr = max(para[::2]) - min(para[::2]), max(rota[::2]) - min(rota[::2])
h = max(para[::2] + ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
377 | A | Maze | PROGRAMMING | 1,600 | [
"dfs and similar"
] | null | null | Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to a... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=<<=*s*), where *n* and *m* are the maze's height and width, correspondingly, *k* is the number of walls Pavel wants to add and letter *s* represents the number of empty cells in the original maze.
Each of the next *n* lines co... | Print *n* lines containing *m* characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").
It is guaranteed that a solution exists. If there are multiple solutions you can output any of t... | [
"3 4 2\n#..#\n..#.\n#...\n",
"5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#\n"
] | [
"#.X#\nX.#.\n#...\n",
"#XXX\n#X#.\nX#..\n...#\n.#.#\n"
] | none | 500 | [
{
"input": "5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#",
"output": "#XXX\n#X#.\nX#..\n...#\n.#.#"
},
{
"input": "3 3 2\n#.#\n...\n#.#",
"output": "#X#\nX..\n#.#"
},
{
"input": "7 7 18\n#.....#\n..#.#..\n.#...#.\n...#...\n.#...#.\n..#.#..\n#.....#",
"output": "#XXXXX#\nXX#X#X.\nX#XXX#.\nXXX#... | 1,679,665,861 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 89 | 374 | 62,566,400 | #bisect.bisect_left(a, x, lo=0, hi=len(a)) is the analog of std::lower_bound()
#bisect.bisect_right(a, x, lo=0, hi=len(a)) is the analog of std::upper_bound()
#from heapq import heappop,heappush,heapify #heappop(hq), heapify(list)
#from collections import deque as dq #deque e.g. myqueue=dq(list)
#append/appendleft... | Title: Maze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze w... | ```python
#bisect.bisect_left(a, x, lo=0, hi=len(a)) is the analog of std::lower_bound()
#bisect.bisect_right(a, x, lo=0, hi=len(a)) is the analog of std::upper_bound()
#from heapq import heappop,heappush,heapify #heappop(hq), heapify(list)
#from collections import deque as dq #deque e.g. myqueue=dq(list)
#append/... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
182 | D | Common Divisors | PROGRAMMING | 1,400 | [
"brute force",
"hashing",
"implementation",
"math",
"strings"
] | null | null | Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive integer *x* such that if we write out string *a* consecutively *x* times, we get string *b*. For exam... | The first input line contains a non-empty string *s*1.
The second input line contains a non-empty string *s*2.
Lengths of strings *s*1 and *s*2 are positive and do not exceed 105. The strings only consist of lowercase Latin letters. | Print the number of common divisors of strings *s*1 and *s*2. | [
"abcdabcd\nabcdabcdabcdabcd\n",
"aaa\naa\n"
] | [
"2\n",
"1\n"
] | In first sample the common divisors are strings "abcd" and "abcdabcd".
In the second sample the common divisor is a single string "a". String "aa" isn't included in the answer as it isn't a divisor of string "aaa". | 1,000 | [
{
"input": "abcdabcd\nabcdabcdabcdabcd",
"output": "2"
},
{
"input": "aaa\naa",
"output": "1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaa\naaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "3"
},
{
"input": "aaaaaaaaaaaaaa\naaaaaaaaaaaaaa",
"output": "4"
},
{
"input": "a\nb",
... | 1,680,287,987 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 71 | 404 | 4,300,800 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
s1 = list(input().rstrip())
s2 = list(input().rstrip())
n, m = len(s1), len(s2)
ans = 0
for i in range(1, min(n, m) + 1):
if n % i or m % i:
continue
if s1[i - 1] ^ s2[i - 1]:
break
ok = 1
for j... | Title: Common Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive ... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
s1 = list(input().rstrip())
s2 = list(input().rstrip())
n, m = len(s1), len(s2)
ans = 0
for i in range(1, min(n, m) + 1):
if n % i or m % i:
continue
if s1[i - 1] ^ s2[i - 1]:
break
ok = 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,595,962,370 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 888 | 28,160,000 | import sys
import os.path
import functools
import itertools
import re
def solve():
# code goes here!!
n = int(input())
a = [0] * n
p = [0] * n
for i in range(n):
a[i],p[i] = map(int,input().split())
ans = 0
i = 0
cur = 0
while i < n :
cur = ... | Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
import sys
import os.path
import functools
import itertools
import re
def solve():
# code goes here!!
n = int(input())
a = [0] * n
p = [0] * n
for i in range(n):
a[i],p[i] = map(int,input().split())
ans = 0
i = 0
cur = 0
while i < n :
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,498,581,935 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 156 | 5,632,000 | n=int(input())
a={}
maxi=-1000
b=[]
for i in range (n):
name, score=input().split()
score=int(score)
if name in a.keys():
a[name]+=score
else:
a[name]=score
b.append([name,a[name]])
maxi=max(a.values())
for c,d in b:
if d>=maxi and a[c]==maxi:
print(c)
... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n=int(input())
a={}
maxi=-1000
b=[]
for i in range (n):
name, score=input().split()
score=int(score)
if name in a.keys():
a[name]+=score
else:
a[name]=score
b.append([name,a[name]])
maxi=max(a.values())
for c,d in b:
if d>=maxi and a[c]==maxi:
pri... | 3.880038 | MatrixStudio/Codeforces-Python-Submissions |
498 | A | Crazy Town | PROGRAMMING | 1,700 | [
"geometry"
] | null | null | Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the plane into connected regions, possibly of infinite space. Let's call each such region a block. We ... | The first line contains two space-separated integers *x*1, *y*1 (<=-<=106<=≤<=*x*1,<=*y*1<=≤<=106) — the coordinates of your home.
The second line contains two integers separated by a space *x*2, *y*2 (<=-<=106<=≤<=*x*2,<=*y*2<=≤<=106) — the coordinates of the university you are studying at.
The third line contains a... | Output the answer to the problem. | [
"1 1\n-1 -1\n2\n0 1 0\n1 0 0\n",
"1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3\n"
] | [
"2\n",
"2\n"
] | Pictures to the samples are presented below (A is the point representing the house; B is the point representing the university, different blocks are filled with different colors): | 500 | [
{
"input": "1 1\n-1 -1\n2\n0 1 0\n1 0 0",
"output": "2"
},
{
"input": "1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3",
"output": "2"
},
{
"input": "841746 527518\n595261 331297\n10\n-946901 129987 670374\n-140388 -684770 309555\n-302589 415564 -387435\n-565799 -72069 -395358\n-523453 -511446 85489... | 1,424,172,736 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 62 | 0 | a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=int(input())
d=[]
for i in range(c):d+=[list(map(int,input().split()))]
e=list(map(lambda j:j[0]*a[0]+j[1]*a[1]+j[2]>0,d))
f=list(map(lambda j:j[0]*b[0]+j[1]*b[1]+j[2]>0,d))
print(len(list(filter(lambda x:e[x]!=f[x],range(len(d))))))
| Title: Crazy Town
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the pl... | ```python
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=int(input())
d=[]
for i in range(c):d+=[list(map(int,input().split()))]
e=list(map(lambda j:j[0]*a[0]+j[1]*a[1]+j[2]>0,d))
f=list(map(lambda j:j[0]*b[0]+j[1]*b[1]+j[2]>0,d))
print(len(list(filter(lambda x:e[x]!=f[x],range(len(d))))))
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,652,961,876 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 4,300,800 | m, n = input().split()
if 1 <= int(m) <= int(n) <= 16:
b_s = int(m) * int(n)
print(b_s // 2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m, n = input().split()
if 1 <= int(m) <= int(n) <= 16:
b_s = int(m) * int(n)
print(b_s // 2)
``` | 3.968989 | MatrixStudio/Codeforces-Python-Submissions |
719 | B | Anatoly and Cockroaches | PROGRAMMING | 1,400 | [
"greedy"
] | null | null | Anatoly lives in the university dorm as many other students do. As you know, cockroaches are also living there together with students. Cockroaches might be of two colors: black and red. There are *n* cockroaches living in Anatoly's room.
Anatoly just made all his cockroaches to form a single line. As he is a perfectio... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of cockroaches.
The second line contains a string of length *n*, consisting of characters 'b' and 'r' that denote black cockroach and red cockroach respectively. | Print one integer — the minimum number of moves Anatoly has to perform in order to make the colors of cockroaches in the line to alternate. | [
"5\nrbbrr\n",
"5\nbbbbb\n",
"3\nrbr\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample, Anatoly has to swap third and fourth cockroaches. He needs 1 turn to do this.
In the second sample, the optimum answer is to paint the second and the fourth cockroaches red. This requires 2 turns.
In the third sample, the colors of cockroaches in the line are alternating already, thus the answer ... | 1,000 | [
{
"input": "5\nrbbrr",
"output": "1"
},
{
"input": "5\nbbbbb",
"output": "2"
},
{
"input": "3\nrbr",
"output": "0"
},
{
"input": "13\nrbbbrbrrbrrbb",
"output": "3"
},
{
"input": "18\nrrrrrrrrrrrrrrrrrb",
"output": "8"
},
{
"input": "100\nbrbbbrrrbbrbrb... | 1,608,508,263 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 140 | 0 | n=int(input())
s=input()
r=0
b=0
for j in s:
if j=='r':
r+=1
else:
b+=1
s1='rb'*(n//2)+'r'*(n%2)
s2='br'*(n//2)+'b'*(n%2)
a1,a2=0,0
for j in range(n):
if s[j]!=s1[j]:
a1+=1
if s[j]!=s2[j]:
a2+=1
ans=abs(r-b)//2+(min(a1,a2)-abs(r-b)//2)//2
print(ans)
... | Title: Anatoly and Cockroaches
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anatoly lives in the university dorm as many other students do. As you know, cockroaches are also living there together with students. Cockroaches might be of two colors: black and red. There are *n* cockroaches... | ```python
n=int(input())
s=input()
r=0
b=0
for j in s:
if j=='r':
r+=1
else:
b+=1
s1='rb'*(n//2)+'r'*(n%2)
s2='br'*(n//2)+'b'*(n%2)
a1,a2=0,0
for j in range(n):
if s[j]!=s1[j]:
a1+=1
if s[j]!=s2[j]:
a2+=1
ans=abs(r-b)//2+(min(a1,a2)-abs(r-b)//2)//2
pr... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
688 | A | Opponents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of them all. That means if one day at least one of Arya's opponents is absent at the school, then Ar... | The first line of the input contains two integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=100) — the number of opponents and the number of days, respectively.
The *i*-th of the following *d* lines contains a string of length *n* consisting of characters '0' and '1'. The *j*-th character of this string is '0' if the *j*-th op... | Print the only integer — the maximum number of consecutive days that Arya will beat all present opponents. | [
"2 2\n10\n00\n",
"4 1\n0100\n",
"4 5\n1101\n1111\n0110\n1011\n1111\n"
] | [
"2\n",
"1\n",
"2\n"
] | In the first and the second samples, Arya will beat all present opponents each of the *d* days.
In the third sample, Arya will beat his opponents on days 1, 3 and 4 and his opponents will beat him on days 2 and 5. Thus, the maximum number of consecutive winning days is 2, which happens on days 3 and 4. | 500 | [
{
"input": "2 2\n10\n00",
"output": "2"
},
{
"input": "4 1\n0100",
"output": "1"
},
{
"input": "4 5\n1101\n1111\n0110\n1011\n1111",
"output": "2"
},
{
"input": "3 2\n110\n110",
"output": "2"
},
{
"input": "10 6\n1111111111\n0100110101\n1111111111\n0000011010\n1111... | 1,586,872,103 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 124 | 0 | n, d = map(int, input().split())
win = k = 0
for i in range(d):
n = input()
if '0' in n:
win += 1
else:
win = 0
k = max(k, win)
print(k)
| Title: Opponents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of th... | ```python
n, d = map(int, input().split())
win = k = 0
for i in range(d):
n = input()
if '0' in n:
win += 1
else:
win = 0
k = max(k, win)
print(k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
401 | A | Vanya and Cards | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time p... | The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their a... | Print a single number — the answer to the problem. | [
"3 2\n-1 1 2\n",
"2 3\n-2 -2\n"
] | [
"1\n",
"2\n"
] | In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | 500 | [
{
"input": "3 2\n-1 1 2",
"output": "1"
},
{
"input": "2 3\n-2 -2",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
},
{
"input": "2 2\n-1 -1",
"output": "1"
},
{
"input": "15 5\n-2 -1 2 -4 -3 4 -4 -2 -2 2 -2 -1 1 -4 -2",
"output": "4"
},
{
"... | 1,671,361,630 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 61 | 0 | n,x=map(int,input().split())
a=list(map(int,input().split()))
k=abs(sum(a))
print((k+x-1)//x) | Title: Vanya and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each... | ```python
n,x=map(int,input().split())
a=list(map(int,input().split()))
k=abs(sum(a))
print((k+x-1)//x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | E | Enemy is weak | PROGRAMMING | 1,900 | [
"data structures",
"trees"
] | E. Enemy is weak | 5 | 256 | The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weaknes... | The first line of input contains a single number *n* (3<=≤<=*n*<=≤<=106) — the number of men in Roman army. Next line contains *n* different positive integers *a**i* (1<=≤<=*i*<=≤<=*n*,<=1<=≤<=*a**i*<=≤<=109) — powers of men in the Roman army. | A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d). | [
"3\n3 2 1\n",
"3\n2 3 1\n",
"4\n10 8 3 1\n",
"4\n1 5 4 3\n"
] | [
"1\n",
"0\n",
"4\n",
"1\n"
] | none | 2,500 | [
{
"input": "3\n3 2 1",
"output": "1"
},
{
"input": "3\n2 3 1",
"output": "0"
},
{
"input": "4\n10 8 3 1",
"output": "4"
},
{
"input": "4\n1 5 4 3",
"output": "1"
},
{
"input": "9\n10 9 5 6 8 3 4 7 11",
"output": "20"
},
{
"input": "7\n11 3 8 4 2 9 6",
... | 1,651,161,107 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | def get_input(pregunta):
return list(map(int, pregunta.split(" ")))
line_1 = input()
line_2 = get_input(input())
dic = {}
nivel = [1]*line_1
ndic = [0]*line_1
trip = 0
for i in range(len(line_2)):
for j in range(i+1,len(line_2)):
if(line_2[i] > line_2[j]):
nivel[j] += 1
... | Title: Enemy is weak
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roma... | ```python
def get_input(pregunta):
return list(map(int, pregunta.split(" ")))
line_1 = input()
line_2 = get_input(input())
dic = {}
nivel = [1]*line_1
ndic = [0]*line_1
trip = 0
for i in range(len(line_2)):
for j in range(i+1,len(line_2)):
if(line_2[i] > line_2[j]):
nivel[j] += ... | -1 | MatrixStudio/Codeforces-Python-Submissions |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,443,429,148 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 16 | 2,000 | 716,800 | n = input()
s = input()
k = []
r = 0
for i in range(len(s)):
if i%2 == 0:
k.append(s[i])
else:
t = chr(ord(s[i])+32)
if t in k:
k.remove(t)
else:
r = r + 1
print (r)
| Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
n = input()
s = input()
k = []
r = 0
for i in range(len(s)):
if i%2 == 0:
k.append(s[i])
else:
t = chr(ord(s[i])+32)
if t in k:
k.remove(t)
else:
r = r + 1
print (r)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
799 | B | T-shirt buying | PROGRAMMING | 1,400 | [
"data structures",
"implementation"
] | null | null | A new pack of *n* t-shirts came to a shop. Each of the t-shirts is characterized by three integers *p**i*, *a**i* and *b**i*, where *p**i* is the price of the *i*-th t-shirt, *a**i* is front color of the *i*-th t-shirt and *b**i* is back color of the *i*-th t-shirt. All values *p**i* are distinct, and values *a**i* and... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of t-shirts.
The following line contains sequence of integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=1<=000<=000<=000), where *p**i* equals to the price of the *i*-th t-shirt.
The following line contains sequence of integers *a*1,<... | Print to the first line *m* integers — the *j*-th integer should be equal to the price of the t-shirt which the *j*-th buyer will buy. If the *j*-th buyer won't buy anything, print -1. | [
"5\n300 200 400 500 911\n1 2 1 2 3\n2 1 3 2 1\n6\n2 3 1 2 1 1\n",
"2\n1000000000 1\n1 1\n1 2\n2\n2 1\n"
] | [
"200 400 300 500 911 -1 \n",
"1 1000000000 \n"
] | none | 1,000 | [
{
"input": "5\n300 200 400 500 911\n1 2 1 2 3\n2 1 3 2 1\n6\n2 3 1 2 1 1",
"output": "200 400 300 500 911 -1 "
},
{
"input": "2\n1000000000 1\n1 1\n1 2\n2\n2 1",
"output": "1 1000000000 "
},
{
"input": "10\n251034796 163562337 995167403 531046374 341924810 828969071 971837553 183763940 8... | 1,665,630,591 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 482 | 33,075,200 | from collections import defaultdict as dc
from collections import deque
n=int(input())
p=list(map(int,input().split()))
a=list(map(int,input().split()))
b=list(map(int,input().split()))
mp=dc(lambda:deque())
lst=list()
for i in range(n):lst.append((p[i],a[i],b[i]))
lst=sorted(lst)
m=int(input())
ans=[0]*m
a... | Title: T-shirt buying
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A new pack of *n* t-shirts came to a shop. Each of the t-shirts is characterized by three integers *p**i*, *a**i* and *b**i*, where *p**i* is the price of the *i*-th t-shirt, *a**i* is front color of the *i*-th t-shirt a... | ```python
from collections import defaultdict as dc
from collections import deque
n=int(input())
p=list(map(int,input().split()))
a=list(map(int,input().split()))
b=list(map(int,input().split()))
mp=dc(lambda:deque())
lst=list()
for i in range(n):lst.append((p[i],a[i],b[i]))
lst=sorted(lst)
m=int(input())
an... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
710 | A | King Moves | PROGRAMMING | 800 | [
"implementation"
] | null | null | The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check the king's moves here [https://en.wikipedia.org/wiki/King_(chess)](https://en.wikipedia.org/wik... | The only line contains the king's position in the format "cd", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'. | Print the only integer *x* — the number of moves permitted for the king. | [
"e4\n"
] | [
"8\n"
] | none | 0 | [
{
"input": "e4",
"output": "8"
},
{
"input": "a1",
"output": "3"
},
{
"input": "h8",
"output": "3"
},
{
"input": "a4",
"output": "5"
},
{
"input": "g7",
"output": "8"
},
{
"input": "e1",
"output": "5"
},
{
"input": "b2",
"output": "8"
... | 1,607,469,800 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 108 | 0 | s = input()
if ((s[1] == 1 and (s[0] == "a" or s[0] == "h")) or (s[1] == 8) and (s[0] == "a" or s[0] == "h")):
print(3)
elif (s[1] == 1 or s[0] == "a" or s[1] == 8 or s[0] == "h"):
print(5)
else:
print(8) | Title: King Moves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check... | ```python
s = input()
if ((s[1] == 1 and (s[0] == "a" or s[0] == "h")) or (s[1] == 8) and (s[0] == "a" or s[0] == "h")):
print(3)
elif (s[1] == 1 or s[0] == "a" or s[1] == 8 or s[0] == "h"):
print(5)
else:
print(8)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
11 | B | Jumping Jack | PROGRAMMING | 1,600 | [
"math"
] | B. Jumping Jack | 1 | 64 | Jack is working on his jumping skills recently. Currently he's located at point zero of the number line. He would like to get to the point *x*. In order to train, he has decided that he'll first jump by only one unit, and each subsequent jump will be exactly one longer than the previous one. He can go either left or ri... | The input data consists of only one integer *x* (<=-<=109<=≤<=*x*<=≤<=109). | Output the minimal number of jumps that Jack requires to reach *x*. | [
"2\n",
"6\n",
"0\n"
] | [
"3\n",
"3\n",
"0\n"
] | none | 0 | [
{
"input": "2",
"output": "3"
},
{
"input": "6",
"output": "3"
},
{
"input": "0",
"output": "0"
},
{
"input": "-1000000000",
"output": "44723"
},
{
"input": "999961560",
"output": "44720"
},
{
"input": "999961561",
"output": "44721"
},
{
"i... | 1,494,410,182 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 186 | 0 | x=int(input())
saltos=0
s=0
posicion=0
if x<0:
x=x*(-1)
while posicion!=x :
s=s+1
if s<=x-posicion:
posicion= posicion+s
saltos=saltos+1
else:
posicion=posicion-s
saltos=saltos+1
if x==(-1000000000)*-1:
... | Title: Jumping Jack
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Jack is working on his jumping skills recently. Currently he's located at point zero of the number line. He would like to get to the point *x*. In order to train, he has decided that he'll first jump by only one unit, and each ... | ```python
x=int(input())
saltos=0
s=0
posicion=0
if x<0:
x=x*(-1)
while posicion!=x :
s=s+1
if s<=x-posicion:
posicion= posicion+s
saltos=saltos+1
else:
posicion=posicion-s
saltos=saltos+1
if x==(-1000000000)... | 0 | MatrixStudio/Codeforces-Python-Submissions |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,642,785,671 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 202 | 9,523,200 | import math,sys;input=sys.stdin.readline;S=lambda:input().rstrip();I=lambda:int(S());M=lambda:map(int,S().split());L=lambda:list(M());mod1=1000000007;mod2=998244353
from collections import defaultdict
n,m =M()
d = defaultdict()
for _ in range(m):
x,y = map(str, input().split())
if len(x)<=len(y):
... | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
import math,sys;input=sys.stdin.readline;S=lambda:input().rstrip();I=lambda:int(S());M=lambda:map(int,S().split());L=lambda:list(M());mod1=1000000007;mod2=998244353
from collections import defaultdict
n,m =M()
d = defaultdict()
for _ in range(m):
x,y = map(str, input().split())
if len(x)<=len(y)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,628,235,580 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 124 | 6,963,200 | n = int(input())
array = list(map(int, input().split()))
array.sort()
if n == 1:
print(array[0] + 1)
else:
ans = 0
flag = True
for i in range(n - 1):
if array[i + 1] != array[i] + 1:
flag = False
ans = array[i] + 1
break
if flag:
print(array[-1] + ... | Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the... | ```python
n = int(input())
array = list(map(int, input().split()))
array.sort()
if n == 1:
print(array[0] + 1)
else:
ans = 0
flag = True
for i in range(n - 1):
if array[i + 1] != array[i] + 1:
flag = False
ans = array[i] + 1
break
if flag:
print(ar... | 0 | MatrixStudio/Codeforces-Python-Submissions |
887 | A | Div. 64 | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisi... | In the only line given a non-empty binary string *s* with length up to 100. | Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise. | [
"100010001\n",
"100\n"
] | [
"yes",
"no"
] | In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.
You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system) | 500 | [
{
"input": "100010001",
"output": "yes"
},
{
"input": "100",
"output": "no"
},
{
"input": "0000001000000",
"output": "yes"
},
{
"input": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111",
"output": "no"
},
{
"in... | 1,510,083,760 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | str=input()
if len(str)>6:
print('yes')
else:
print('no') | Title: Div. 64
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some dig... | ```python
str=input()
if len(str)>6:
print('yes')
else:
print('no')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,623,819,256 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 0 | n=int(input())
temp,count=0,0
while(n>(count*(count+1))//2):
count+=1
print(n-((count-1)*(count))//2) | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
n=int(input())
temp,count=0,0
while(n>(count*(count+1))//2):
count+=1
print(n-((count-1)*(count))//2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
299 | B | Ksusha the Squirrel | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to the end of the road, that is, get to sector *n*. Unfortunately, there are some rocks on the road. We know ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=3·105,<=1<=≤<=*k*<=≤<=3·105). The next line contains *n* characters — the description of the road: the *i*-th character equals ".", if the *i*-th sector contains no rocks. Otherwise, it equals "#".
It is guaranteed that the first and the last characters e... | Print "YES" (without the quotes) if Ksusha can reach the end of the road, otherwise print "NO" (without the quotes). | [
"2 1\n..\n",
"5 2\n.#.#.\n",
"7 3\n.#.###.\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 1,000 | [
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "5 2\n.#.#.",
"output": "YES"
},
{
"input": "7 3\n.#.###.",
"output": "NO"
},
{
"input": "2 200\n..",
"output": "YES"
},
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "2 2\n..",
"output": "Y... | 1,574,497,560 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 248 | 0 | def ksusha_the_squirrel(n, k, s):
trace = 0
for i in range(n):
if s[i] == ".":
if i - trace <= k:
trace = k
else:
return False
return True
if __name__ == "__main__":
[n, k] = map(int, input().split())
s = input()
result = ksusha_t... | Title: Ksusha the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to t... | ```python
def ksusha_the_squirrel(n, k, s):
trace = 0
for i in range(n):
if s[i] == ".":
if i - trace <= k:
trace = k
else:
return False
return True
if __name__ == "__main__":
[n, k] = map(int, input().split())
s = input()
result ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
246 | A | Buggy Sorting | PROGRAMMING | 900 | [
"constructive algorithms",
"greedy",
"sortings"
] | null | null | Little boy Valera studies an algorithm of sorting an integer array. After studying the theory, he went on to the practical tasks. As a result, he wrote a program that sorts an array of *n* integers *a*1,<=*a*2,<=...,<=*a**n* in the non-decreasing order. The pseudocode of the program, written by Valera, is given below. ... | You've got a single integer *n* (1<=≤<=*n*<=≤<=50) — the size of the sorted array. | Print *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) — the counter-example, for which Valera's algorithm won't work correctly. If the counter-example that meets the described conditions is impossible to give, print -1.
If there are several counter-examples, consisting of *n* numbers, yo... | [
"1\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "-1"
},
{
"input": "3",
"output": "3 2 1 "
},
{
"input": "4",
"output": "4 3 2 1 "
},
{
"input": "5",
"output": "5 4 3 2 1 "
},
{
"input": "6",
"output": "6 5 4 3 2 1 "
},
{
"input... | 1,674,690,547 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 61 | 2,764,800 | n=int(input())
L=[-1]*n-1
L.append(1)
print(*L) | Title: Buggy Sorting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little boy Valera studies an algorithm of sorting an integer array. After studying the theory, he went on to the practical tasks. As a result, he wrote a program that sorts an array of *n* integers *a*1,<=*a*2,<=...,<=*a*... | ```python
n=int(input())
L=[-1]*n-1
L.append(1)
print(*L)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
20 | A | BerOS file system | PROGRAMMING | 1,700 | [
"implementation"
] | A. BerOS file system | 2 | 64 | The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of ... | The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty. | The path in normalized form. | [
"//usr///local//nginx/sbin\n"
] | [
"/usr/local/nginx/sbin\n"
] | none | 500 | [
{
"input": "//usr///local//nginx/sbin",
"output": "/usr/local/nginx/sbin"
},
{
"input": "////a//b/////g",
"output": "/a/b/g"
},
{
"input": "/a/b/c",
"output": "/a/b/c"
},
{
"input": "/",
"output": "/"
},
{
"input": "////",
"output": "/"
},
{
"input": "... | 1,550,295,629 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | s = list(input().split('/'))
ans = []
for i in s:
if i != '':
ans.append(i)
print('/'.join(ans)[1:]) | Title: BerOS file system
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/n... | ```python
s = list(input().split('/'))
ans = []
for i in s:
if i != '':
ans.append(i)
print('/'.join(ans)[1:])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,655,169,508 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | s=input()
c=len(s)
m=0
n=0
for i in range(c):
if(s[i]>='a' and s[i]<='z'):
m=m+1
elif(s[i]>='A' and s[i]<='Z'):
n=n+1
if(m==n):
print(s.lower())
elif(m>n):
print(s.lower())
elif(m<n):
print(s.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=input()
c=len(s)
m=0
n=0
for i in range(c):
if(s[i]>='a' and s[i]<='z'):
m=m+1
elif(s[i]>='A' and s[i]<='Z'):
n=n+1
if(m==n):
print(s.lower())
elif(m>n):
print(s.lower())
elif(m<n):
print(s.upper())
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least... | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,626,922,348 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 216 | 20,172,800 | import math
n, k = map(int, input().split())
arr = list(map(int, input().split()))
cnt = 0
for i in range(1, n):
if arr[i-1] == arr[i]:
arr[i] += k
cnt += 1
elif arr[i-1] > arr[i]:
cnt += (math.ceil((arr[i-1]-arr[i])/2))
arr[i] += (math.ceil((arr[i-1]-arr[i])/2))*k
pri... | Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*... | ```python
import math
n, k = map(int, input().split())
arr = list(map(int, input().split()))
cnt = 0
for i in range(1, n):
if arr[i-1] == arr[i]:
arr[i] += k
cnt += 1
elif arr[i-1] > arr[i]:
cnt += (math.ceil((arr[i-1]-arr[i])/2))
arr[i] += (math.ceil((arr[i-1]-arr[i])/... | 0 | MatrixStudio/Codeforces-Python-Submissions |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,637,508,977 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | s=input()
t=input()
if [c in 'aeiou' for c in s] == [c in 'aeiou' for c in t]:
print("Yes")
else:
print("No") | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
s=input()
t=input()
if [c in 'aeiou' for c in s] == [c in 'aeiou' for c in t]:
print("Yes")
else:
print("No")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
656 | A | Da Vinci Powers | PROGRAMMING | 1,900 | [
"*special"
] | null | null | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer. | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35). | Output a single integer. | [
"3\n",
"10\n"
] | [
"8\n",
"1024\n"
] | none | 0 | [
{
"input": "3",
"output": "8"
},
{
"input": "10",
"output": "1024"
},
{
"input": "35",
"output": "33940307968"
},
{
"input": "0",
"output": "1"
},
{
"input": "1",
"output": "2"
},
{
"input": "2",
"output": "4"
},
{
"input": "4",
"output... | 1,490,476,334 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 4,608,000 | import math
n=int(input())
print(pow(2,n)) | Title: Da Vinci Powers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer.
Input Specification:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output Specification:
Output a single integer.
De... | ```python
import math
n=int(input())
print(pow(2,n))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nastya the word *t* and wants to get the word *p* out of it. Nastya removes letters in a cert... | The first and second lines of the input contain the words *t* and *p*, respectively. Words are composed of lowercase letters of the Latin alphabet (1<=≤<=|*p*|<=<<=|*t*|<=≤<=200<=000). It is guaranteed that the word *p* can be obtained by removing the letters from word *t*.
Next line contains a permutation *a*1,<=*... | Print a single integer number, the maximum number of letters that Nastya can remove. | [
"ababcba\nabb\n5 3 4 1 7 6 2\n",
"bbbabb\nbb\n1 6 3 4 2 5\n"
] | [
"3",
"4"
] | In the first sample test sequence of removing made by Nastya looks like this:
"ababcba" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "ababcba" <img align="middle" class="tex-formula" src="https... | 0 | [
{
"input": "ababcba\nabb\n5 3 4 1 7 6 2",
"output": "3"
},
{
"input": "bbbabb\nbb\n1 6 3 4 2 5",
"output": "4"
},
{
"input": "cacaccccccacccc\ncacc\n10 9 14 5 1 7 15 3 6 12 4 8 11 13 2",
"output": "9"
},
{
"input": "aaaabaaabaabaaaaaaaa\naaaa\n18 5 4 6 13 9 1 3 7 8 16 10 12 1... | 1,652,378,075 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 |
def chek(li,current):
ptr = 0
for i in range(0, len(current)):
if current[i] == li[ptr]:
ptr += 1
if ptr == len(li):
return 1
return 0
def can(list, li, index, nums):
takeornot = []
currentlist =[]
for i in range(0, len(list)):
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nas... | ```python
def chek(li,current):
ptr = 0
for i in range(0, len(current)):
if current[i] == li[ptr]:
ptr += 1
if ptr == len(li):
return 1
return 0
def can(list, li, index, nums):
takeornot = []
currentlist =[]
for i in range(0, len(list)):... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
999 | B | Reversing Encryption | PROGRAMMING | 900 | [
"implementation"
] | null | null | A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$ (i.e. the substring which starts at position $1$ and ends at position $d$).
For example, the above algor... | The first line of input consists of a single integer $n$ ($1 \le n \le 100$) — the length of the string $t$. The second line of input consists of the string $t$. The length of $t$ is $n$, and it consists only of lowercase Latin letters. | Print a string $s$ such that the above algorithm results in $t$. | [
"10\nrocesfedoc\n",
"16\nplmaetwoxesisiht\n",
"1\nz\n"
] | [
"codeforces\n",
"thisisexampletwo\n",
"z\n"
] | The first example is described in the problem statement. | 0 | [
{
"input": "10\nrocesfedoc",
"output": "codeforces"
},
{
"input": "16\nplmaetwoxesisiht",
"output": "thisisexampletwo"
},
{
"input": "1\nz",
"output": "z"
},
{
"input": "2\nir",
"output": "ri"
},
{
"input": "3\nilj",
"output": "jli"
},
{
"input": "4\nj... | 1,677,656,947 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 46 | 0 | n = int(input())
a = input()
for i in range(n):
if n % (i + 1) == 0:
sp = a[:i+1]
sp = sp[::-1]
a = sp + a[i + 1:]
print(a) | Title: Reversing Encryption
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$... | ```python
n = int(input())
a = input()
for i in range(n):
if n % (i + 1) == 0:
sp = a[:i+1]
sp = sp[::-1]
a = sp + a[i + 1:]
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
304 | A | Pythagorean Theorem II | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the s... | The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above. | Print a single integer — the answer to the problem. | [
"5\n",
"74\n"
] | [
"1\n",
"35\n"
] | none | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "74",
"output": "35"
},
{
"input": "1000",
"output": "881"
},
{
"input": "586",
"output": "472"
},
{
"input": "2",
"output": "0"
},
{
"input": "362",
"output": "258"
},
{
"input": "778",
"outp... | 1,369,330,501 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 30 | 3,000 | 0 | import math
n = int(input())
count = 0
for a in range(1,n+1):
for b in range(a,n+1):
c = int(math.sqrt(a*a + b*b));
if c*c == a*a + b*b and c <= n:
count = count + 1
print(count)
| Title: Pythagorean Theorem II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the squar... | ```python
import math
n = int(input())
count = 0
for a in range(1,n+1):
for b in range(a,n+1):
c = int(math.sqrt(a*a + b*b));
if c*c == a*a + b*b and c <= n:
count = count + 1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
47 | A | Triangular numbers | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Triangular numbers | 2 | 256 | A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers fr... | The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer. | If the given integer is a triangular number output YES, otherwise output NO. | [
"1\n",
"2\n",
"3\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "2",
"output": "NO"
},
{
"input": "3",
"output": "YES"
},
{
"input": "4",
"output": "NO"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "YES"
},
{
"input": "7",
"output": "NO... | 1,490,489,945 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 154 | 4,608,000 | T=input("")
t=int(T)
a=0
i=0
if(t==0):
print("NO")
else:
while(a<t):
a=i*(i+1)/2
i=i+1
if(a==t):
print("YES")
else:
print("NO")
| Title: Triangular numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is t... | ```python
T=input("")
t=int(T)
a=0
i=0
if(t==0):
print("NO")
else:
while(a<t):
a=i*(i+1)/2
i=i+1
if(a==t):
print("YES")
else:
print("NO")
``` | 3.952917 | MatrixStudio/Codeforces-Python-Submissions |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,699,103,934 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | a,b,c=map(int,input().split())
k=0
for i in range(c+1):
k=k+i*a
print(k-b)
| Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
a,b,c=map(int,input().split())
k=0
for i in range(c+1):
k=k+i*a
print(k-b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
620 | A | Professor GukiZ's Robot | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal numbe... | The first line contains two integers *x*1,<=*y*1 (<=-<=109<=≤<=*x*1,<=*y*1<=≤<=109) — the start position of the robot.
The second line contains two integers *x*2,<=*y*2 (<=-<=109<=≤<=*x*2,<=*y*2<=≤<=109) — the finish position of the robot. | Print the only integer *d* — the minimal number of steps to get the finish position. | [
"0 0\n4 5\n",
"3 4\n6 1\n"
] | [
"5\n",
"3\n"
] | In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its *y* coordinate and get the finish position.
In the second example robot should simultaneously increase *x* coordinate and decrease *y* coordinate by one th... | 0 | [
{
"input": "0 0\n4 5",
"output": "5"
},
{
"input": "3 4\n6 1",
"output": "3"
},
{
"input": "0 0\n4 6",
"output": "6"
},
{
"input": "1 1\n-3 -5",
"output": "6"
},
{
"input": "-1 -1\n-10 100",
"output": "101"
},
{
"input": "1 -1\n100 -100",
"output":... | 1,540,847,063 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | x1,y1,x2,y2=(int(x) for x in input().split())
if abs(x2-x1)>abs(y2-y1):
print(abs(x2-x1))
else:
print(abs(y2-y1)) | Title: Professor GukiZ's Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of ... | ```python
x1,y1,x2,y2=(int(x) for x in input().split())
if abs(x2-x1)>abs(y2-y1):
print(abs(x2-x1))
else:
print(abs(y2-y1))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
335 | F | Buy One, Get One Free | PROGRAMMING | 3,000 | [
"dp",
"greedy"
] | null | null | A nearby pie shop is having a special sale. For each pie you pay full price for, you may select one pie of a strictly lesser value to get for free. Given the prices of all the pies you wish to acquire, determine the minimum total amount you must pay for all of the pies. | Input will begin with an integer *n* (1<=≤<=*n*<=≤<=500000), the number of pies you wish to acquire. Following this is a line with *n* integers, each indicating the cost of a pie. All costs are positive integers not exceeding 109. | Print the minimum cost to acquire all the pies.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"6\n3 4 5 3 4 5\n",
"5\n5 5 5 5 5\n",
"4\n309999 6000 2080 2080\n"
] | [
"14\n",
"25\n",
"314159\n"
] | In the first test case you can pay for a pie with cost 5 and get a pie with cost 4 for free, then pay for a pie with cost 5 and get a pie with cost 3 for free, then pay for a pie with cost 4 and get a pie with cost 3 for free.
In the second test case you have to pay full price for every pie. | 3,000 | [
{
"input": "6\n3 4 5 3 4 5",
"output": "14"
},
{
"input": "5\n5 5 5 5 5",
"output": "25"
},
{
"input": "4\n309999 6000 2080 2080",
"output": "314159"
},
{
"input": "10\n1 1 1 1 1 2 3 4 5 6",
"output": "16"
},
{
"input": "1\n1",
"output": "1"
},
{
"inpu... | 1,611,037,387 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n = int(input())
l = list(map(int,input().split()))
l.sort(reverse=True)
cost = 0
for i in range(n-1):
if l[i] > l[i+1]:
cost += l[i]
l[i+1] = 0
else:
cost += l[i]
if l[-1] != 0:
cost += l[-1]
print(cost)
| Title: Buy One, Get One Free
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A nearby pie shop is having a special sale. For each pie you pay full price for, you may select one pie of a strictly lesser value to get for free. Given the prices of all the pies you wish to acquire, determine t... | ```python
n = int(input())
l = list(map(int,input().split()))
l.sort(reverse=True)
cost = 0
for i in range(n-1):
if l[i] > l[i+1]:
cost += l[i]
l[i+1] = 0
else:
cost += l[i]
if l[-1] != 0:
cost += l[-1]
print(cost)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
362 | B | Petya and Staircases | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump over one or two stairs at a time. But some stairs are too dirty and Petya doesn't want to step on them.
No... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=109, 0<=≤<=*m*<=≤<=3000) — the number of stairs in the staircase and the number of dirty stairs, correspondingly. The second line contains *m* different space-separated integers *d*1,<=*d*2,<=...,<=*d**m* (1<=≤<=*d**i*<=≤<=*n*) — the numbers of the dirty s... | Print "YES" if Petya can reach stair number *n*, stepping only on the clean stairs. Otherwise print "NO". | [
"10 5\n2 4 8 3 6\n",
"10 5\n2 4 5 7 9\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "10 5\n2 4 8 3 6",
"output": "NO"
},
{
"input": "10 5\n2 4 5 7 9",
"output": "YES"
},
{
"input": "10 9\n2 3 4 5 6 7 8 9 10",
"output": "NO"
},
{
"input": "5 2\n4 5",
"output": "NO"
},
{
"input": "123 13\n36 73 111 2 92 5 47 55 48 113 7 78 37",
"outp... | 1,591,336,736 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 7 | 218 | 2,048,000 | def main():
n,k = map(int,input().split())
d = sorted(map(int,input().split()))
if 1 in d or n in d:
print("NO")
else:
for i in range(k-2):
if d[i+2] == d[i]+2 and d[i+1] == d[i]+1:
print("NO")
return
print("YES")
if __name__ == '__ma... | Title: Petya and Staircases
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump o... | ```python
def main():
n,k = map(int,input().split())
d = sorted(map(int,input().split()))
if 1 in d or n in d:
print("NO")
else:
for i in range(k-2):
if d[i+2] == d[i]+2 and d[i+1] == d[i]+1:
print("NO")
return
print("YES")
if __name_... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
828 | A | Restaurant Tables | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | In a small restaurant there are *a* tables for one person and *b* tables for two persons.
It it known that *n* groups of people come today, each consisting of one or two people.
If a group consist of one person, it is seated at a vacant one-seater table. If there are none of them, it is seated at a vacant two-seate... | The first line contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*a*,<=*b*<=≤<=2·105) — the number of groups coming to the restaurant, the number of one-seater and the number of two-seater tables.
The second line contains a sequence of integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=2) — the d... | Print the total number of people the restaurant denies service to. | [
"4 1 2\n1 2 1 1\n",
"4 1 1\n1 1 2 1\n"
] | [
"0\n",
"2\n"
] | In the first example the first group consists of one person, it is seated at a vacant one-seater table. The next group occupies a whole two-seater table. The third group consists of one person, it occupies one place at the remaining two-seater table. The fourth group consists of one person, he is seated at the remainin... | 500 | [
{
"input": "4 1 2\n1 2 1 1",
"output": "0"
},
{
"input": "4 1 1\n1 1 2 1",
"output": "2"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 1 2\n2 2",
"output": "0"
},
{
"input": "5 1 3\n1 2 2 2 1",
"output": "1"
},
{
"input": "7 6 1\n1 1 1 1 1 1... | 1,562,470,226 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | n,a,b = map(int,input().split())
t = list(map(int,input().split()))
g=0; s=0
for x in range(n):
if t[x]==1:
if a>0: a-=1
elif b>0:
if s==0: b-=1
s+=1
if s==2: s=0
else:
g+=(n-x); break
else:
if b>0: b-=1
el... | Title: Restaurant Tables
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small restaurant there are *a* tables for one person and *b* tables for two persons.
It it known that *n* groups of people come today, each consisting of one or two people.
If a group consist of one person, i... | ```python
n,a,b = map(int,input().split())
t = list(map(int,input().split()))
g=0; s=0
for x in range(n):
if t[x]==1:
if a>0: a-=1
elif b>0:
if s==0: b-=1
s+=1
if s==2: s=0
else:
g+=(n-x); break
else:
if b>0: b-=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,700,267,661 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 46 | 0 | x = list(map(int, input().split()))
x.sort(reverse=False)
count = (x[2] - x[1]) + (x[1] - x[0])
print(int(count))
| Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
x = list(map(int, input().split()))
x.sort(reverse=False)
count = (x[2] - x[1]) + (x[1] - x[0])
print(int(count))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
922 | A | Cloning Toys | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applies the machine to a copied toy, he gets two additional copies.
Initially, Imp has only one origina... | The only line contains two integers *x* and *y* (0<=≤<=*x*,<=*y*<=≤<=109) — the number of copies and the number of original toys Imp wants to get (including the initial one). | Print "Yes", if the desired configuration is possible, and "No" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"6 3\n",
"4 2\n",
"1000 1001\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first example, Imp has to apply the machine twice to original toys and then twice to copies. | 500 | [
{
"input": "6 3",
"output": "Yes"
},
{
"input": "4 2",
"output": "No"
},
{
"input": "1000 1001",
"output": "Yes"
},
{
"input": "1000000000 999999999",
"output": "Yes"
},
{
"input": "81452244 81452247",
"output": "No"
},
{
"input": "188032448 86524683",... | 1,661,707,525 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 42 | 62 | 0 | x,y = map(int,input().split())
if y == 0:
print("No")
exit()
curr = y-1
if y-1>x:
print("No")
exit()
print("No") if (y-1-x)%2 != 0 else print("Yes")
| Title: Cloning Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applie... | ```python
x,y = map(int,input().split())
if y == 0:
print("No")
exit()
curr = y-1
if y-1>x:
print("No")
exit()
print("No") if (y-1-x)%2 != 0 else print("Yes")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,544,031,645 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 216 | 0 | n=int(input())
t=list(map(int,input().split()))
t.sort()
i=0
while t[i]==min(t):
i+=1
print(t[i]) | Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n=int(input())
t=list(map(int,input().split()))
t.sort()
i=0
while t[i]==min(t):
i+=1
print(t[i])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,625,430,512 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 77 | 0 | s = str(input())
k = 0
l = 'heidi'
for i in s:
if i == l[k]:
k += 1
if k == 5:
print('YES')
exit()
print('NO') | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
s = str(input())
k = 0
l = 'heidi'
for i in s:
if i == l[k]:
k += 1
if k == 5:
print('YES')
exit()
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
761 | E | Dasha and Puzzle | PROGRAMMING | 2,000 | [
"constructive algorithms",
"dfs and similar",
"graphs",
"greedy",
"trees"
] | null | null | Dasha decided to have a rest after solving the problem. She had been ready to start her favourite activity — origami, but remembered the puzzle that she could not solve.
The tree is a non-oriented connected graph without cycles. In particular, there always are *n*<=-<=1 edges in a tree with *n* vertices.
The puzzle ... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=30) — the number of vertices in the tree.
Each of next *n*<=-<=1 lines contains two integers *u**i*, *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*) that mean that the *i*-th edge of the tree connects vertices *u**i* and *v**i*.
It is guaranteed that the described gra... | If the puzzle doesn't have a solution then in the only line print "NO".
Otherwise, the first line should contain "YES". The next *n* lines should contain the pair of integers *x**i*, *y**i* (|*x**i*|,<=|*y**i*|<=≤<=1018) — the coordinates of the point which corresponds to the *i*-th vertex of the tree.
If there are s... | [
"7\n1 2\n1 3\n2 4\n2 5\n3 6\n3 7",
"6\n1 2\n2 3\n2 4\n2 5\n2 6\n",
"4\n1 2\n2 3\n3 4"
] | [
"YES\n0 0\n1 0\n0 1\n2 0\n1 -1\n-1 1\n0 2",
"NO\n",
"YES\n3 3\n4 3\n5 3\n6 3"
] | In the first sample one of the possible positions of tree is: <img class="tex-graphics" src="https://espresso.codeforces.com/360c9c903e5177970a5a3b2711f6718c2163ffd8.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 2,500 | [
{
"input": "7\n1 2\n1 3\n2 4\n2 5\n3 6\n3 7",
"output": "YES\n0 0\n0 1073741824\n1073741824 0\n0 1610612736\n536870912 1073741824\n1073741824 536870912\n1610612736 0"
},
{
"input": "6\n1 2\n2 3\n2 4\n2 5\n2 6",
"output": "NO"
},
{
"input": "4\n1 2\n2 3\n3 4",
"output": "YES\n0 0\n0 1... | 1,674,402,031 | 3,331 | PyPy 3 | OK | TESTS | 60 | 93 | 0 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
G = [[] for _ in range(n + 1)]
for _ in range(n - 1):
u, v = map(int, input().split())
G[u].append(v)
G[v].append(u)
inf = pow(10, 9) + 1
pow2 = [1]
for _ in range(40):
pow2.append(2 * pow2[-1])... | Title: Dasha and Puzzle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dasha decided to have a rest after solving the problem. She had been ready to start her favourite activity — origami, but remembered the puzzle that she could not solve.
The tree is a non-oriented connected graph wit... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
G = [[] for _ in range(n + 1)]
for _ in range(n - 1):
u, v = map(int, input().split())
G[u].append(v)
G[v].append(u)
inf = pow(10, 9) + 1
pow2 = [1]
for _ in range(40):
pow2.append(2 *... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,654,178,022 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | n = int(input())
l = []
for i in range(n):
s = input()
l.append(s)
for i in range(n - 1):
for j in range(n):
if l[i][j] == "o" and l[i + 1][j] == l[i][j]:
print("NO")
exit()
for i in range(n):
for j in range(n - 1):
if l[i][j] == "o" and l[i][j + 1... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n = int(input())
l = []
for i in range(n):
s = input()
l.append(s)
for i in range(n - 1):
for j in range(n):
if l[i][j] == "o" and l[i + 1][j] == l[i][j]:
print("NO")
exit()
for i in range(n):
for j in range(n - 1):
if l[i][j] == "o" and ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
899 | A | Splitting in Teams | PROGRAMMING | 800 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The coach decided to form teams of exactly three people for this training. Determine the maximum number of tea... | The first line contains single integer *n* (2<=≤<=*n*<=≤<=2·105) — the number of groups.
The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), where *a**i* is the number of people in group *i*. | Print the maximum number of teams of three people the coach can form. | [
"4\n1 1 2 1\n",
"2\n2 2\n",
"7\n2 2 2 1 1 1 1\n",
"3\n1 1 1\n"
] | [
"1\n",
"0\n",
"3\n",
"1\n"
] | In the first example the coach can form one team. For example, he can take students from the first, second and fourth groups.
In the second example he can't make a single team.
In the third example the coach can form three teams. For example, he can do this in the following way:
- The first group (of two people) an... | 500 | [
{
"input": "4\n1 1 2 1",
"output": "1"
},
{
"input": "2\n2 2",
"output": "0"
},
{
"input": "7\n2 2 2 1 1 1 1",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "3\n2 2 2",
"output": "0"
},
{
"input": "3\n1 2 1",
"output": "1"
}... | 1,558,811,969 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 18 | 124 | 3,993,600 | x = int(input())
a = list(map(int,input().split()))
l = a.count(2)
t = x - l
if l == 0:
print(x//3)
else:
print(min(l,t)) | Title: Splitting in Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The co... | ```python
x = int(input())
a = list(map(int,input().split()))
l = a.count(2)
t = x - l
if l == 0:
print(x//3)
else:
print(min(l,t))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
653 | A | Bear and Three Balls | PROGRAMMING | 900 | [
"brute force",
"implementation",
"sortings"
] | null | null | Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy:
- No two friends can get balls of the same size. - No two friends can get balls of sizes th... | The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball. | Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes). | [
"4\n18 55 16 17\n",
"6\n40 41 43 44 44 44\n",
"8\n5 972 3 4 1 4 970 971\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17.
In the second sample, there is no way to give gifts to three friends without breaking the rules.
In the third sample, there is even more than one way to choose bal... | 500 | [
{
"input": "4\n18 55 16 17",
"output": "YES"
},
{
"input": "6\n40 41 43 44 44 44",
"output": "NO"
},
{
"input": "8\n5 972 3 4 1 4 970 971",
"output": "YES"
},
{
"input": "3\n959 747 656",
"output": "NO"
},
{
"input": "4\n1 2 2 3",
"output": "YES"
},
{
... | 1,645,191,142 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | def check():
n = int(input());
inp = map(int, input().split());
inp = list(dict.fromkeys(inp));
alist = [];
for i in range(len(inp)):
x = int(inp[i]);
for j in range(i + 1, len(inp)):
if abs(int(inp[j]) - x) == 1:
alist.append(inp[j]);
... | Title: Bear and Three Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make fri... | ```python
def check():
n = int(input());
inp = map(int, input().split());
inp = list(dict.fromkeys(inp));
alist = [];
for i in range(len(inp)):
x = int(inp[i]);
for j in range(i + 1, len(inp)):
if abs(int(inp[j]) - x) == 1:
alist.append(inp[j]);
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
24 | A | Ring road | PROGRAMMING | 1,400 | [
"graphs"
] | A. Ring road | 2 | 256 | Nowadays the one-way traffic is introduced all over the world in order to improve driving safety and reduce traffic jams. The government of Berland decided to keep up with new trends. Formerly all *n* cities of Berland were connected by *n* two-way roads in the ring, i. e. each city was connected directly to exactly tw... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of cities (and roads) in Berland. Next *n* lines contain description of roads. Each road is described by three integers *a**i*, *b**i*, *c**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*,<=1<=≤<=*c**i*<=≤<=100) — road is directed from city *a**i* t... | Output single integer — the smallest amount of money the government should spend on the redirecting of roads so that from every city you can get to any other. | [
"3\n1 3 1\n1 2 1\n3 2 1\n",
"3\n1 3 1\n1 2 5\n3 2 1\n",
"6\n1 5 4\n5 3 8\n2 4 15\n1 6 16\n2 3 23\n4 6 42\n",
"4\n1 2 9\n2 3 8\n3 4 7\n4 1 5\n"
] | [
"1\n",
"2\n",
"39\n",
"0\n"
] | none | 0 | [
{
"input": "3\n1 3 1\n1 2 1\n3 2 1",
"output": "1"
},
{
"input": "3\n1 3 1\n1 2 5\n3 2 1",
"output": "2"
},
{
"input": "6\n1 5 4\n5 3 8\n2 4 15\n1 6 16\n2 3 23\n4 6 42",
"output": "39"
},
{
"input": "4\n1 2 9\n2 3 8\n3 4 7\n4 1 5",
"output": "0"
},
{
"input": "5\n... | 1,652,874,407 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 404 | 4,505,600 | # -*- coding: utf-8 -*-
"""ring road.ipynb
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1ls2CdNi1Ub6YeK8uXmt2CMSuZ16jdAlK
"""
n, ans, src=0, 99999999, 0
DATA=visited=adj=cost=[]
def isAllConnected():
s=0
for i in range(1,n+1):
if visited[i]... | Title: Ring road
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Nowadays the one-way traffic is introduced all over the world in order to improve driving safety and reduce traffic jams. The government of Berland decided to keep up with new trends. Formerly all *n* cities of Berland were conne... | ```python
# -*- coding: utf-8 -*-
"""ring road.ipynb
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1ls2CdNi1Ub6YeK8uXmt2CMSuZ16jdAlK
"""
n, ans, src=0, 99999999, 0
DATA=visited=adj=cost=[]
def isAllConnected():
s=0
for i in range(1,n+1):
if ... | 3.890608 | MatrixStudio/Codeforces-Python-Submissions |
981 | A | Antipalindrome | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not.
A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2}... | The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. | If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$.
Note that there can be multiple longest substrings that are not palindromes, but their length is unique. | [
"mew\n",
"wuffuw\n",
"qqqqqqqq\n"
] | [
"3\n",
"5\n",
"0\n"
] | "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$.
The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$.
All sub... | 500 | [
{
"input": "mew",
"output": "3"
},
{
"input": "wuffuw",
"output": "5"
},
{
"input": "qqqqqqqq",
"output": "0"
},
{
"input": "ijvji",
"output": "4"
},
{
"input": "iiiiiii",
"output": "0"
},
{
"input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow"... | 1,583,742,631 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 109 | 307,200 | s=input()
if len(set(s))==1:print(0)
else:
a=[]
for i in range(len(s)-1):
for j in range(i+1,len(s)):
v="";v=s[i:j+1]
if v!=v[::-1] and v not in a:a.append(v)
print(len(max(a))) | Title: Antipalindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" ar... | ```python
s=input()
if len(set(s))==1:print(0)
else:
a=[]
for i in range(len(s)-1):
for j in range(i+1,len(s)):
v="";v=s[i:j+1]
if v!=v[::-1] and v not in a:a.append(v)
print(len(max(a)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
120 | B | Quiz League | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a question and the experts are allowed a minute on brainstorming and finding the right answer to the que... | The first line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=1000 and 1<=≤<=*k*<=≤<=*n*) — the numbers of sectors on the table and the number of the sector where the arrow is pointing. The second line contains *n* numbers: *a**i*<==<=0 if the question from sector *i* has already been asked and *a**i*<==<=1 ... | Print the single number — the number of the sector containing the question the experts will be asked. It is guaranteed that the answer exists, that is that not all the questions have already been asked. | [
"5 5\n0 1 0 1 0\n",
"2 1\n1 1\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "5 5\n0 1 0 1 0",
"output": "2"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "3 2\n1 0 0",
"output": "1"
},
{
"input": "3 3\n0 1 0",
"output": "2"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "6 3\n0 0 1 1 0 1",
"output":... | 1,689,468,501 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 61 | 0 | with open('input.txt', 'r') as f:
n, k = map(int, f.readline().split())
status = list(map(int, f.readline().split()))
if status[k-1] == 1:
with open('output.txt', 'w') as t:
t.write(str(k))
else:
while status[k-1] != 1:
k = (k % n) + 1
with open('output.txt', 'w') as p:
... | Title: Quiz League
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a quest... | ```python
with open('input.txt', 'r') as f:
n, k = map(int, f.readline().split())
status = list(map(int, f.readline().split()))
if status[k-1] == 1:
with open('output.txt', 'w') as t:
t.write(str(k))
else:
while status[k-1] != 1:
k = (k % n) + 1
with open('output.txt', 'w'... | 3 | MatrixStudio/Codeforces-Python-Submissions |
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