contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
707 | C | Pythagorean Triples | PROGRAMMING | 1,500 | [
"math",
"number theory"
] | null | null | Katya studies in a fifth grade. Recently her class studied right triangles and the Pythagorean theorem. It appeared, that there are triples of positive integers such that you can construct a right triangle with segments of lengths corresponding to triple. Such triples are called Pythagorean triples.
For example, tripl... | The only line of the input contains single integer *n* (1<=≤<=*n*<=≤<=109) — the length of some side of a right triangle. | Print two integers *m* and *k* (1<=≤<=*m*,<=*k*<=≤<=1018), such that *n*, *m* and *k* form a Pythagorean triple, in the only line.
In case if there is no any Pythagorean triple containing integer *n*, print <=-<=1 in the only line. If there are many answers, print any of them. | [
"3\n",
"6\n",
"1\n",
"17\n",
"67\n"
] | [
"4 5",
"8 10",
"-1",
"144 145",
"2244 2245"
] | Illustration for the first sample. | 1,500 | [
{
"input": "3",
"output": "4 5"
},
{
"input": "6",
"output": "8 10"
},
{
"input": "1",
"output": "-1"
},
{
"input": "17",
"output": "144 145"
},
{
"input": "67",
"output": "2244 2245"
},
{
"input": "10",
"output": "24 26"
},
{
"input": "14"... | 1,659,689,630 | 2,147,483,647 | Python 3 | OK | TESTS | 90 | 61 | 0 | a = int(input())
if a<3: ans = [-1]
elif(a%2): ans = [a**2//2,a**2//2+1]
else: ans = [a**2//4-1,a**2//4+1]
print(*ans) | Title: Pythagorean Triples
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Katya studies in a fifth grade. Recently her class studied right triangles and the Pythagorean theorem. It appeared, that there are triples of positive integers such that you can construct a right triangle with segm... | ```python
a = int(input())
if a<3: ans = [-1]
elif(a%2): ans = [a**2//2,a**2//2+1]
else: ans = [a**2//4-1,a**2//4+1]
print(*ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,689,150,989 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 46 | 0 | a = int(input())
n = 0
while n != a:
n += 1
if n % 2 == 0 and n == a:
print("I love it")
break
elif n % 2 == 1 and n == a:
print("I hate it")
break
if n % 2 == 0:
print("I love that", end = " ")
else:
print("I hate that", end = " ")
# Wed ... | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
a = int(input())
n = 0
while n != a:
n += 1
if n % 2 == 0 and n == a:
print("I love it")
break
elif n % 2 == 1 and n == a:
print("I hate it")
break
if n % 2 == 0:
print("I love that", end = " ")
else:
print("I hate that", end = "... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
18 | A | Triangle | PROGRAMMING | 1,500 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | At a geometry lesson Bob learnt that a triangle is called right-angled if it is nondegenerate and one of its angles is right. Bob decided to draw such a triangle immediately: on a sheet of paper he drew three points with integer coordinates, and joined them with segments of straight lines, then he showed the triangle t... | The first input line contains 6 space-separated integers *x*1,<=*y*1,<=*x*2,<=*y*2,<=*x*3,<=*y*3 — coordinates of the triangle's vertices. All the coordinates are integer and don't exceed 100 in absolute value. It's guaranteed that the triangle is nondegenerate, i.e. its total area is not zero. | If the given triangle is right-angled, output RIGHT, if it is almost right-angled, output ALMOST, and if it is neither of these, output NEITHER. | [
"0 0 2 0 0 1\n",
"2 3 4 5 6 6\n",
"-1 0 2 0 0 1\n"
] | [
"RIGHT\n",
"NEITHER\n",
"ALMOST\n"
] | none | 0 | [
{
"input": "0 0 2 0 0 1",
"output": "RIGHT"
},
{
"input": "2 3 4 5 6 6",
"output": "NEITHER"
},
{
"input": "-1 0 2 0 0 1",
"output": "ALMOST"
},
{
"input": "27 74 85 23 100 99",
"output": "NEITHER"
},
{
"input": "-97 -19 17 62 30 -76",
"output": "NEITHER"
},... | 1,693,826,250 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 30 | 92 | 102,400 | z = []
z[0:] = map(int,input().split())
lst = []
lst.append((z[0] - z[2])**2+((z[1] - z[3])**2))
lst.append((z[0] - z[4])**2+((z[1] - z[5])**2))
lst.append((z[2] - z[4])**2+((z[3] - z[5])**2))
lst.sort()
#print(lst)
lst_1 = list(z)
new = []
lst_1[0] = lst_1[0] - 1
#print(lst_1)
lst_1[0] = lst_1[0]+ 1
#prin... | Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
At a geometry lesson Bob learnt that a triangle is called right-angled if it is nondegenerate and one of its angles is right. Bob decided to draw such a triangle immediately: on a sheet of paper he drew three points with integer co... | ```python
z = []
z[0:] = map(int,input().split())
lst = []
lst.append((z[0] - z[2])**2+((z[1] - z[3])**2))
lst.append((z[0] - z[4])**2+((z[1] - z[5])**2))
lst.append((z[2] - z[4])**2+((z[3] - z[5])**2))
lst.sort()
#print(lst)
lst_1 = list(z)
new = []
lst_1[0] = lst_1[0] - 1
#print(lst_1)
lst_1[0] = lst_1[0]... | 0 | MatrixStudio/Codeforces-Python-Submissions |
801 | A | Vicious Keyboard | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maxi... | The first line will contain a string *s* consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100. | Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character. | [
"VK\n",
"VV\n",
"V\n",
"VKKKKKKKKKVVVVVVVVVK\n",
"KVKV\n"
] | [
"1\n",
"1\n",
"0\n",
"3\n",
"1\n"
] | For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.
For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.
For the fourth case, we ... | 500 | [
{
"input": "VK",
"output": "1"
},
{
"input": "VV",
"output": "1"
},
{
"input": "V",
"output": "0"
},
{
"input": "VKKKKKKKKKVVVVVVVVVK",
"output": "3"
},
{
"input": "KVKV",
"output": "1"
},
{
"input": "VKKVVVKVKVK",
"output": "5"
},
{
"input... | 1,683,083,237 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | a=input()
b=0
for i in range(len(a)):
c=list(a)
c[i]='K'
if c.count('VK')>b:
b=c.count('VK')
for i in range(len(a)):
c=list(a)
c[i]='V'
if c.count('VK')>b:
b=c.count('VK')
print(b) | Title: Vicious Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter i... | ```python
a=input()
b=0
for i in range(len(a)):
c=list(a)
c[i]='K'
if c.count('VK')>b:
b=c.count('VK')
for i in range(len(a)):
c=list(a)
c[i]='V'
if c.count('VK')>b:
b=c.count('VK')
print(b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
967 | A | Mind the Gap | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing lasts $1$ minute.
He was asked to insert one takeoff in the schedule. The takeoff takes $1$ minut... | The first line of input contains two integers $n$ and $s$ ($1 \le n \le 100$, $1 \le s \le 60$) — the number of landings on the schedule and the minimum allowed time (in minutes) between a landing and a takeoff.
Each of next $n$ lines contains two integers $h$ and $m$ ($0 \le h \le 23$, $0 \le m \le 59$) — the time, i... | Print two integers $h$ and $m$ — the hour and the minute from the current moment of the earliest time Arkady can insert the takeoff. | [
"6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40\n",
"16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59\n",
"3 17\n0 30\n1 0\n12 0\n"
] | [
"6 1\n",
"24 50\n",
"0 0\n"
] | In the first example note that there is not enough time between 1:20 and 3:21, because each landing and the takeoff take one minute.
In the second example there is no gaps in the schedule, so Arkady can only add takeoff after all landings. Note that it is possible that one should wait more than $24$ hours to insert th... | 500 | [
{
"input": "6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40",
"output": "6 1"
},
{
"input": "16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59",
"output": "24 50"
},
{
"input": "3 17\n0 30\n1 0\n12 0",
"output": "0 0"
},
{
... | 1,531,834,556 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 109 | 0 | n, s = (int(x) for x in input().split())
h, m = [], []
for i in range(n):
h1, m1 = (int(x) for x in input().split())
h.append(h1)
m.append(m1)
flag = True
if h[0] * 60 + m[0] - s >= 1:
flag = False
print(0, 0)
else:
for i in range(n-1):
z = h[i] * 60 + m[i] + s + 1
... | Title: Mind the Gap
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing ... | ```python
n, s = (int(x) for x in input().split())
h, m = [], []
for i in range(n):
h1, m1 = (int(x) for x in input().split())
h.append(h1)
m.append(m1)
flag = True
if h[0] * 60 + m[0] - s >= 1:
flag = False
print(0, 0)
else:
for i in range(n-1):
z = h[i] * 60 + m[i] + s + ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
426 | B | Sereja and Mirroring | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Let's assume that we are given a matrix *b* of size *x*<=×<=*y*, let's determine the operation of mirroring matrix *b*. The mirroring of matrix *b* is a 2*x*<=×<=*y* matrix *c* which has the following properties:
- the upper half of matrix *c* (rows with numbers from 1 to *x*) exactly matches *b*; - the lower half o... | The first line contains two integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Each of the next *n* lines contains *m* integers — the elements of matrix *a*. The *i*-th line contains integers *a**i*1,<=*a**i*2,<=...,<=*a**im* (0<=≤<=*a**ij*<=≤<=1) — the *i*-th row of the matrix *a*. | In the single line, print the answer to the problem — the minimum number of rows of matrix *b*. | [
"4 3\n0 0 1\n1 1 0\n1 1 0\n0 0 1\n",
"3 3\n0 0 0\n0 0 0\n0 0 0\n",
"8 1\n0\n1\n1\n0\n0\n1\n1\n0\n"
] | [
"2\n",
"3\n",
"2\n"
] | In the first test sample the answer is a 2 × 3 matrix *b*:
If we perform a mirroring operation with this matrix, we get the matrix *a* that is given in the input: | 1,000 | [
{
"input": "4 3\n0 0 1\n1 1 0\n1 1 0\n0 0 1",
"output": "2"
},
{
"input": "3 3\n0 0 0\n0 0 0\n0 0 0",
"output": "3"
},
{
"input": "8 1\n0\n1\n1\n0\n0\n1\n1\n0",
"output": "2"
},
{
"input": "10 4\n0 0 1 0\n0 0 1 0\n1 1 0 1\n0 0 1 1\n1 0 1 0\n1 0 1 0\n0 0 1 1\n1 1 0 1\n0 0 1 0\... | 1,679,128,836 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 1,331,200 | x,y=input().split()
x=int(x)
y=int(y)
lst=[[0]*y]*x
for i in range(x):
lst[i]=list(map(int,input().split()))
if x%2==1:
print(x)
else:
k=0
while 1:
for i in range(int(x)):
if lst[i]!=lst[int(x)-1-i]:
print(int(x))
k=1
break
if k... | Title: Sereja and Mirroring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's assume that we are given a matrix *b* of size *x*<=×<=*y*, let's determine the operation of mirroring matrix *b*. The mirroring of matrix *b* is a 2*x*<=×<=*y* matrix *c* which has the following properties:
... | ```python
x,y=input().split()
x=int(x)
y=int(y)
lst=[[0]*y]*x
for i in range(x):
lst[i]=list(map(int,input().split()))
if x%2==1:
print(x)
else:
k=0
while 1:
for i in range(int(x)):
if lst[i]!=lst[int(x)-1-i]:
print(int(x))
k=1
break
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
803 | B | Distances to Zero | PROGRAMMING | 1,200 | [
"constructive algorithms"
] | null | null | You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the given array. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — length of the array *a*. The second line contains integer elements of the array separated by single spaces (<=-<=109<=≤<=*a**i*<=≤<=109). | Print the sequence *d*0,<=*d*1,<=...,<=*d**n*<=-<=1, where *d**i* is the difference of indices between *i* and nearest *j* such that *a**j*<==<=0. It is possible that *i*<==<=*j*. | [
"9\n2 1 0 3 0 0 3 2 4\n",
"5\n0 1 2 3 4\n",
"7\n5 6 0 1 -2 3 4\n"
] | [
"2 1 0 1 0 0 1 2 3 ",
"0 1 2 3 4 ",
"2 1 0 1 2 3 4 "
] | none | 0 | [
{
"input": "9\n2 1 0 3 0 0 3 2 4",
"output": "2 1 0 1 0 0 1 2 3 "
},
{
"input": "5\n0 1 2 3 4",
"output": "0 1 2 3 4 "
},
{
"input": "7\n5 6 0 1 -2 3 4",
"output": "2 1 0 1 2 3 4 "
},
{
"input": "1\n0",
"output": "0 "
},
{
"input": "2\n0 0",
"output": "0 0 "
... | 1,652,106,822 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
a = list(map(int, input().split()))
d = len(a)
for i in range(len(a)):
if 0 == a[i]:
d = 0
a[i] = d
d += 1
d = len(a)
for i in range(len(a)-1, -1, -1):
if 0 == a[i]:
d = 0
a[i] = min(a[i], d)
d += 1
print(" ".join(a))
| Title: Distances to Zero
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the give... | ```python
n = int(input())
a = list(map(int, input().split()))
d = len(a)
for i in range(len(a)):
if 0 == a[i]:
d = 0
a[i] = d
d += 1
d = len(a)
for i in range(len(a)-1, -1, -1):
if 0 == a[i]:
d = 0
a[i] = min(a[i], d)
d += 1
print(" ".join(a))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,588,818,712 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 1,000 | 45,772,800 | list=["Sheldon","Leonard", "Penny", "Rajesh", "Howard"]
n = int(input())
i=0
while len(list) <= n:
list.append(list[i])
list.append(list[i])
i+=1
print(list[n-1]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
list=["Sheldon","Leonard", "Penny", "Rajesh", "Howard"]
n = int(input())
i=0
while len(list) <= n:
list.append(list[i])
list.append(list[i])
i+=1
print(list[n-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,637,848,414 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 2,000 | 0 | def sushu(m):
cnt=0
for j in range(2,int(m/2)+1):
if m%j==0:
cnt+=1
return cnt
n=int(input())
cn=0
for i in range(n+1):
lis1 = [j for j in range(2, i + 1) if sushu(j) == 0 and i%j==0]
if len(lis1) == 2:
cn += 1
print(cn)
| Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
def sushu(m):
cnt=0
for j in range(2,int(m/2)+1):
if m%j==0:
cnt+=1
return cnt
n=int(input())
cn=0
for i in range(n+1):
lis1 = [j for j in range(2, i + 1) if sushu(j) == 0 and i%j==0]
if len(lis1) == 2:
cn += 1
print(cn)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
679 | A | Bear and Prime 100 | PROGRAMMING | 1,400 | [
"constructive algorithms",
"interactive",
"math"
] | null | null | This is an interactive problem. In the output section below you will see the information about flushing the output.
Bear Limak thinks of some hidden number — an integer from interval [2,<=100]. Your task is to say if the hidden number is prime or composite.
Integer *x*<=><=1 is called prime if it has exactly two d... | After each query you should read one string from the input. It will be "yes" if the printed integer is a divisor of the hidden number, and "no" otherwise. | Up to 20 times you can ask a query — print an integer from interval [2,<=100] in one line. You have to both print the end-of-line character and flush the output. After flushing you should read a response from the input.
In any moment you can print the answer "prime" or "composite" (without the quotes). After that, flu... | [
"yes\nno\nyes\n",
"no\nyes\nno\nno\nno\n"
] | [
"2\n80\n5\ncomposite\n",
"58\n59\n78\n78\n2\nprime\n"
] | The hidden number in the first query is 30. In a table below you can see a better form of the provided example of the communication process.
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ea790051c34ea7d2761cd9b096412ca7c647a173.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The hi... | 750 | [
{
"input": "30",
"output": "composite 4"
},
{
"input": "59",
"output": "prime 15"
},
{
"input": "2",
"output": "prime 16"
},
{
"input": "7",
"output": "prime 16"
},
{
"input": "9",
"output": "composite 3"
},
{
"input": "13",
"output": "prime 15"
... | 1,622,581,869 | 2,147,483,647 | PyPy 3 | OK | TESTS | 59 | 155 | 0 | prime=[1 for i in range(101)]
prime[0]=0
prime[1]=0
for i in range(2,101):
if prime[i]==1:
for j in range(i*i,101,i):
prime[j]=0
ans=[]
for i in range(2,101):
if prime[i]:
ans.append(i)
ans=ans[:-9]
ans.append(4)
ans.append(9)
ans.append(25)
ans.append(49)
#print(len(... | Title: Bear and Prime 100
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This is an interactive problem. In the output section below you will see the information about flushing the output.
Bear Limak thinks of some hidden number — an integer from interval [2,<=100]. Your task is to say i... | ```python
prime=[1 for i in range(101)]
prime[0]=0
prime[1]=0
for i in range(2,101):
if prime[i]==1:
for j in range(i*i,101,i):
prime[j]=0
ans=[]
for i in range(2,101):
if prime[i]:
ans.append(i)
ans=ans[:-9]
ans.append(4)
ans.append(9)
ans.append(25)
ans.append(49)
#... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,699,123,348 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n=eval(input(""))
b=eval(input(""))
d=eval(input(""))
sum=0
q=0
for i in range(0,n):
a=eval(input(""))
if a>b:
continue
sum+=a
if sum>d:
q+=1
sum=0
print(q)
| Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
n=eval(input(""))
b=eval(input(""))
d=eval(input(""))
sum=0
q=0
for i in range(0,n):
a=eval(input(""))
if a>b:
continue
sum+=a
if sum>d:
q+=1
sum=0
print(q)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
12 | B | Correct Solution? | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | B. Correct Solution? | 2 | 256 | One cold winter evening Alice and her older brother Bob was sitting at home near the fireplace and giving each other interesting problems to solve. When it was Alice's turn, she told the number *n* to Bob and said:
—Shuffle the digits in this number in order to obtain the smallest possible number without leading zeroe... | The first line contains one integer *n* (0<=≤<=*n*<=≤<=109) without leading zeroes. The second lines contains one integer *m* (0<=≤<=*m*<=≤<=109) — Bob's answer, possibly with leading zeroes. | Print OK if Bob's answer is correct and WRONG_ANSWER otherwise. | [
"3310\n1033\n",
"4\n5\n"
] | [
"OK\n",
"WRONG_ANSWER\n"
] | none | 0 | [
{
"input": "3310\n1033",
"output": "OK"
},
{
"input": "4\n5",
"output": "WRONG_ANSWER"
},
{
"input": "40\n04",
"output": "WRONG_ANSWER"
},
{
"input": "12\n12",
"output": "OK"
},
{
"input": "432\n234",
"output": "OK"
},
{
"input": "17109\n01179",
"o... | 1,580,527,430 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 278 | 0 | from itertools import permutations
n=list(input())
ele=list(permutations(n,len(n)))
ans=[]
for i in range(0,len(ele)):
m=int("".join(ele[i]))
if len(list(str(m)))==len(n):
ans.append(m)
n=int(input())
if min(ans)==n:
print("OK")
else:
print("WRONG_ANSWER")
| Title: Correct Solution?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One cold winter evening Alice and her older brother Bob was sitting at home near the fireplace and giving each other interesting problems to solve. When it was Alice's turn, she told the number *n* to Bob and said:
—Shuf... | ```python
from itertools import permutations
n=list(input())
ele=list(permutations(n,len(n)))
ans=[]
for i in range(0,len(ele)):
m=int("".join(ele[i]))
if len(list(str(m)))==len(n):
ans.append(m)
n=int(input())
if min(ans)==n:
print("OK")
else:
print("WRONG_ANSWER")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,629,114,520 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 6,758,400 | import sys
x = "".join(sys.stdin.readlines())
up_c = 0
l_c = 0
for c in x:
if c.islower():
l_c +=1
else:
up_c+=1
if l_c >= up_c:
x = x.lower()
else:
x = x.upper()
print(x)
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
import sys
x = "".join(sys.stdin.readlines())
up_c = 0
l_c = 0
for c in x:
if c.islower():
l_c +=1
else:
up_c+=1
if l_c >= up_c:
x = x.lower()
else:
x = x.upper()
print(x)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
352 | B | Jeff and Periods | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
- *x* occurs in sequence *a*. - Consider all positions of numbers *x* in the sequence *a* (such *i*, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). The numbers are separated by spaces. | In the first line print integer *t* — the number of valid *x*. On each of the next *t* lines print two integers *x* and *p**x*, where *x* is current suitable value, *p**x* is the common difference between numbers in the progression (if *x* occurs exactly once in the sequence, *p**x* must equal 0). Print the pairs in th... | [
"1\n2\n",
"8\n1 2 1 3 1 2 1 5\n"
] | [
"1\n2 0\n",
"4\n1 2\n2 4\n3 0\n5 0\n"
] | In the first test 2 occurs exactly once in the sequence, ergo *p*<sub class="lower-index">2</sub> = 0. | 1,000 | [
{
"input": "1\n2",
"output": "1\n2 0"
},
{
"input": "8\n1 2 1 3 1 2 1 5",
"output": "4\n1 2\n2 4\n3 0\n5 0"
},
{
"input": "3\n1 10 5",
"output": "3\n1 0\n5 0\n10 0"
},
{
"input": "4\n9 9 3 5",
"output": "3\n3 0\n5 0\n9 1"
},
{
"input": "6\n1 2 2 1 1 2",
"outpu... | 1,631,611,599 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 122 | 20,172,800 | n=int(input())
l=list(map(int,input().split()))
t=[[0,0,0] for i in range(max(l)+1)] #[element,current_value,common difference]
for i in range(len(l)):
if t[l[i]][0]==0:
t[l[i]][0]=l[i]
t[l[i]][1]=i+1
else:
if t[l[i]][2]==0:
t[l[i]][2]=(i+1)-t[l[i]][1]
... | Title: Jeff and Periods
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
-... | ```python
n=int(input())
l=list(map(int,input().split()))
t=[[0,0,0] for i in range(max(l)+1)] #[element,current_value,common difference]
for i in range(len(l)):
if t[l[i]][0]==0:
t[l[i]][0]=l[i]
t[l[i]][1]=i+1
else:
if t[l[i]][2]==0:
t[l[i]][2]=(i+1)-t[l[i]][1]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
820 | A | Mister B and Book Reading | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, starting from the second, he read *a* pages more than on the previous day (at first day he read *v*0 pages, at ... | First and only line contains five space-separated integers: *c*, *v*0, *v*1, *a* and *l* (1<=≤<=*c*<=≤<=1000, 0<=≤<=*l*<=<<=*v*0<=≤<=*v*1<=≤<=1000, 0<=≤<=*a*<=≤<=1000) — the length of the book in pages, the initial reading speed, the maximum reading speed, the acceleration in reading speed and the number of pages fo... | Print one integer — the number of days Mister B needed to finish the book. | [
"5 5 10 5 4\n",
"12 4 12 4 1\n",
"15 1 100 0 0\n"
] | [
"1\n",
"3\n",
"15\n"
] | In the first sample test the book contains 5 pages, so Mister B read it right at the first day.
In the second sample test at first day Mister B read pages number 1 - 4, at second day — 4 - 11, at third day — 11 - 12 and finished the book.
In third sample test every day Mister B read 1 page of the book, so he finished... | 500 | [
{
"input": "5 5 10 5 4",
"output": "1"
},
{
"input": "12 4 12 4 1",
"output": "3"
},
{
"input": "15 1 100 0 0",
"output": "15"
},
{
"input": "1 1 1 0 0",
"output": "1"
},
{
"input": "1000 999 1000 1000 998",
"output": "2"
},
{
"input": "1000 2 2 5 1",
... | 1,498,574,878 | 778 | Python 3 | OK | TESTS | 110 | 77 | 5,529,600 | numList=input().split(" ")
c=int(numList[0])
v0=int(numList[1])
v1=int(numList[2])
a=int(numList[3])
l=int(numList[4])
iPage=0
iDay=0
while iPage<c:
iDay+=1
iAddPage=v0+(iDay-1)*a
if iAddPage>v1:
iAddPage=v1
if iDay==1:
iPage+=iAddPage
else:
iPage+=iAddPage-l
print(iDay) | Title: Mister B and Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, ... | ```python
numList=input().split(" ")
c=int(numList[0])
v0=int(numList[1])
v1=int(numList[2])
a=int(numList[3])
l=int(numList[4])
iPage=0
iDay=0
while iPage<c:
iDay+=1
iAddPage=v0+(iDay-1)*a
if iAddPage>v1:
iAddPage=v1
if iDay==1:
iPage+=iAddPage
else:
iPage+=iAddPage-l
print(iDay)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,652,796,212 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 46 | 4,505,600 | n = str(input())
m = str(input())
l = []
j = str()
n = ' '.join(str(n)).split()
m = ' '.join(str(m)).split()
for i in range(len(n)):
if n[i] == "1" and m[i] == "1":
l.append("0")
elif n[i] == "0" and m[i] == "0":
l.append("0")
elif n[i] == "0" and m[i] == "1":
l.a... | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
n = str(input())
m = str(input())
l = []
j = str()
n = ' '.join(str(n)).split()
m = ' '.join(str(m)).split()
for i in range(len(n)):
if n[i] == "1" and m[i] == "1":
l.append("0")
elif n[i] == "0" and m[i] == "0":
l.append("0")
elif n[i] == "0" and m[i] == "1":
... | 3.980108 | MatrixStudio/Codeforces-Python-Submissions |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,676,426,510 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 77 | 4,403,200 | # t = int(input())
t = 1
from math import log2
def cp():
# code here
n,t = tuple(map(int,input().split()))
arr = list(map(int,input().split()))
start = 1
while start < t:
start += arr[start-1]
if start == t:
print('YES')
else:
print('NO')
for i in range(t):
cp()
| Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
# t = int(input())
t = 1
from math import log2
def cp():
# code here
n,t = tuple(map(int,input().split()))
arr = list(map(int,input().split()))
start = 1
while start < t:
start += arr[start-1]
if start == t:
print('YES')
else:
print('NO')
for i in range(t):
cp()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
602 | B | Approximating a Constant Range | PROGRAMMING | 1,400 | [
"dp",
"implementation",
"two pointers"
] | null | null | When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choosing a sufficiently large number of consecutive data points that seems as constant as possible and taking their aver... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of data points.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100<=000). | Print a single number — the maximum length of an almost constant range of the given sequence. | [
"5\n1 2 3 3 2\n",
"11\n5 4 5 5 6 7 8 8 8 7 6\n"
] | [
"4\n",
"5\n"
] | In the first sample, the longest almost constant range is [2, 5]; its length (the number of data points in it) is 4.
In the second sample, there are three almost constant ranges of length 4: [1, 4], [6, 9] and [7, 10]; the only almost constant range of the maximum length 5 is [6, 10]. | 1,000 | [
{
"input": "5\n1 2 3 3 2",
"output": "4"
},
{
"input": "11\n5 4 5 5 6 7 8 8 8 7 6",
"output": "5"
},
{
"input": "2\n3 2",
"output": "2"
},
{
"input": "4\n1001 1000 1000 1001",
"output": "4"
},
{
"input": "4\n1 1 2 3",
"output": "3"
},
{
"input": "3\n1 ... | 1,632,385,830 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 21 | 530 | 38,604,800 |
def getLongestLength(currentIdx, currentMin, currentMax, cache):
if (currentIdx, currentMin, currentMax) in cache:
return cache[(currentIdx, currentMin, currentMax)]
if currentIdx == len(array):
return 0
currentMin = min(currentMin, array[currentIdx])
currentMax = max(currentMax,... | Title: Approximating a Constant Range
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choo... | ```python
def getLongestLength(currentIdx, currentMin, currentMax, cache):
if (currentIdx, currentMin, currentMax) in cache:
return cache[(currentIdx, currentMin, currentMax)]
if currentIdx == len(array):
return 0
currentMin = min(currentMin, array[currentIdx])
currentMax = max(c... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,672,630,209 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 61 | 108 | 20,275,200 | # Queue
n = int(input())
s = list(map(int,input().split(" ")))
s.sort()
x = [0]
count = 0
z = []
for i in range(n):
if s[i] < x[i]:
x.append(x[i])
z.append(s[i])
else:
count += 1
x.append(x[i]+s[i])
print(count) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
# Queue
n = int(input())
s = list(map(int,input().split(" ")))
s.sort()
x = [0]
count = 0
z = []
for i in range(n):
if s[i] < x[i]:
x.append(x[i])
z.append(s[i])
else:
count += 1
x.append(x[i]+s[i])
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
869 | B | The Eternal Immortality | PROGRAMMING | 1,100 | [
"math"
] | null | null | Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like this.
The phoenix has a rather long lifespan, and reincarnates itself once every *a*! years. Here *a*! deno... | The first and only line of input contains two space-separated integers *a* and *b* (0<=≤<=*a*<=≤<=*b*<=≤<=1018). | Output one line containing a single decimal digit — the last digit of the value that interests Koyomi. | [
"2 4\n",
"0 10\n",
"107 109\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first example, the last digit of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/99c47ca8b182f097e38094d12f0c06ce0b081b76.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2;
In the second example, the last digit of <img align="middle" class="tex-formula" src="https://espresso... | 1,000 | [
{
"input": "2 4",
"output": "2"
},
{
"input": "0 10",
"output": "0"
},
{
"input": "107 109",
"output": "2"
},
{
"input": "10 13",
"output": "6"
},
{
"input": "998244355 998244359",
"output": "4"
},
{
"input": "999999999000000000 1000000000000000000",
... | 1,697,631,058 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a, b = map(int, input().split())
# Initialize a variable to keep track of the number of trailing zeros
trailing_zeros = 0
# Count the number of trailing zeros in b!
while b > 0:
b //= 10
trailing_zeros += b
# Subtract the number of trailing zeros in a! to find the last digit
result = trailing_zero... | Title: The Eternal Immortality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like... | ```python
a, b = map(int, input().split())
# Initialize a variable to keep track of the number of trailing zeros
trailing_zeros = 0
# Count the number of trailing zeros in b!
while b > 0:
b //= 10
trailing_zeros += b
# Subtract the number of trailing zeros in a! to find the last digit
result = tra... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
789 | A | Anastasia and pebbles | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has only two pockets. She can put at most *k* pebbles in each pocket at the same tim... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 1<=≤<=*k*<=≤<=109) — the number of different pebble types and number of pebbles Anastasia can place in one pocket.
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=104) — number of pebbles of each type. | The only line of output contains one integer — the minimum number of days Anastasia needs to collect all the pebbles. | [
"3 2\n2 3 4\n",
"5 4\n3 1 8 9 7\n"
] | [
"3\n",
"5\n"
] | In the first sample case, Anastasia can collect all pebbles of the first type on the first day, of second type — on the second day, and of third type — on the third day.
Optimal sequence of actions in the second sample case:
- In the first day Anastasia collects 8 pebbles of the third type. - In the second day she... | 500 | [
{
"input": "3 2\n2 3 4",
"output": "3"
},
{
"input": "5 4\n3 1 8 9 7",
"output": "5"
},
{
"input": "1 22\n1",
"output": "1"
},
{
"input": "3 57\n78 165 54",
"output": "3"
},
{
"input": "5 72\n74 10 146 189 184",
"output": "6"
},
{
"input": "9 13\n132 8... | 1,490,805,560 | 2,060 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 61 | 5,529,600 | a,b=map(int,input().split())
f=list(map(int,input().split()))
s=1
for i in range(1,len(f)):
if f[i-1]<=b:
f[i]=f[i]-b
s=s+1
else:
if f[i]%(b*2)>0:
s=s+f[i]//(b*2)+1
else:
s=s+f[i]//(b*2)
print(s)
| Title: Anastasia and pebbles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could ... | ```python
a,b=map(int,input().split())
f=list(map(int,input().split()))
s=1
for i in range(1,len(f)):
if f[i-1]<=b:
f[i]=f[i]-b
s=s+1
else:
if f[i]%(b*2)>0:
s=s+f[i]//(b*2)+1
else:
s=s+f[i]//(b*2)
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
765 | A | Neverending competitions | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.
Jinotega's best friends, team ... | In the first line of input there is a single integer *n*: the number of Jinotega's flights (1<=≤<=*n*<=≤<=100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next *n* lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX"... | If Jinotega is now at home, print "home" (without quotes), otherwise print "contest". | [
"4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO\n",
"3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP\n"
] | [
"home\n",
"contest\n"
] | In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list. | 500 | [
{
"input": "4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO",
"output": "home"
},
{
"input": "3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP",
"output": "contest"
},
{
"input": "1\nESJ\nESJ->TSJ",
"output": "contest"
},
{
"input": "2\nXMR\nFAJ->XMR\nXMR->FAJ",
"output": "home"
},
... | 1,487,061,955 | 2,455 | Python 3 | RUNTIME_ERROR | PRETESTS | 0 | 93 | 6,144,000 | import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time
sys.setrecursionlimit(10**7)
inf = 10**20
mod = 10**9 + 7
def LI(): return list(map(int, input().split()))
def II(): return int(input())
def LS(): return input().split()
def S(): return input()
def main():
n = LI()
if n... | Title: Neverending competitions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from thei... | ```python
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time
sys.setrecursionlimit(10**7)
inf = 10**20
mod = 10**9 + 7
def LI(): return list(map(int, input().split()))
def II(): return int(input())
def LS(): return input().split()
def S(): return input()
def main():
n = LI(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,592,488,137 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 248 | 921,600 | n = int(input())
a = set(list(map(int,input().split())))
print(len(set(range(1,n+1))-a)) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
n = int(input())
a = set(list(map(int,input().split())))
print(len(set(range(1,n+1))-a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,643,688,238 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 122 | 0 | def greater(a, b):
if a>=b:
return a
else:
return b
x, y = input().split()
x = int(x)
y = int(y)
z = greater(x, y)
if ((6-z)==2):
print("1/3")
elif((6-z)==3):
print("1/2")
elif((6-z)==0):
print("0/1")
elif((6-z)==6):
print("1/1")
else:
print(f"{6-z}/6") | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
def greater(a, b):
if a>=b:
return a
else:
return b
x, y = input().split()
x = int(x)
y = int(y)
z = greater(x, y)
if ((6-z)==2):
print("1/3")
elif((6-z)==3):
print("1/2")
elif((6-z)==0):
print("0/1")
elif((6-z)==6):
print("1/1")
else:
print(f"... | 0 | MatrixStudio/Codeforces-Python-Submissions |
412 | A | Poster | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | The R1 company has recently bought a high rise building in the centre of Moscow for its main office. It's time to decorate the new office, and the first thing to do is to write the company's slogan above the main entrance to the building.
The slogan of the company consists of *n* characters, so the decorators hung a l... | The first line contains two integers, *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100) — the number of characters in the slogan and the initial position of the ladder, correspondingly. The next line contains the slogan as *n* characters written without spaces. Each character of the slogan is either a large English letter, or di... | In *t* lines, print the actions the programmers need to make. In the *i*-th line print:
- "LEFT" (without the quotes), if the *i*-th action was "move the ladder to the left"; - "RIGHT" (without the quotes), if the *i*-th action was "move the ladder to the right"; - "PRINT *x*" (without the quotes), if the *i*-th ac... | [
"2 2\nR1\n",
"2 1\nR1\n",
"6 4\nGO?GO!\n"
] | [
"PRINT 1\nLEFT\nPRINT R\n",
"PRINT R\nRIGHT\nPRINT 1\n",
"RIGHT\nRIGHT\nPRINT !\nLEFT\nPRINT O\nLEFT\nPRINT G\nLEFT\nPRINT ?\nLEFT\nPRINT O\nLEFT\nPRINT G\n"
] | Note that the ladder cannot be shifted by less than one meter. The ladder can only stand in front of some square of the poster. For example, you cannot shift a ladder by half a meter and position it between two squares. Then go up and paint the first character and the second character. | 500 | [
{
"input": "2 2\nR1",
"output": "PRINT 1\nLEFT\nPRINT R"
},
{
"input": "2 1\nR1",
"output": "PRINT R\nRIGHT\nPRINT 1"
},
{
"input": "6 4\nGO?GO!",
"output": "RIGHT\nRIGHT\nPRINT !\nLEFT\nPRINT O\nLEFT\nPRINT G\nLEFT\nPRINT ?\nLEFT\nPRINT O\nLEFT\nPRINT G"
},
{
"input": "7 3\n... | 1,397,838,726 | 1,326 | Python 3 | OK | TESTS | 43 | 77 | 0 | a=input().split()
lozung=input()
n=int(a[0])
k=int(a[1])
tol=k-1
tor=n-k
if tol>tor:
for i in range(tor):
print('RIGHT')
for i in range(1,n):
print('PRINT '+lozung[n-i])
print('LEFT')
print('PRINT '+lozung[0])
else:
for i in range(tol):
print('LEFT')
f... | Title: Poster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The R1 company has recently bought a high rise building in the centre of Moscow for its main office. It's time to decorate the new office, and the first thing to do is to write the company's slogan above the main entrance to the... | ```python
a=input().split()
lozung=input()
n=int(a[0])
k=int(a[1])
tol=k-1
tor=n-k
if tol>tor:
for i in range(tor):
print('RIGHT')
for i in range(1,n):
print('PRINT '+lozung[n-i])
print('LEFT')
print('PRINT '+lozung[0])
else:
for i in range(tol):
print('LEF... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,667,054,583 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | room = int(input())
key = input()
count = 0
for i in range(0, len(key), 2):
if (room[i].upper() != room[i+1]):
count += 1
print(count) | Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
room = int(input())
key = input()
count = 0
for i in range(0, len(key), 2):
if (room[i].upper() != room[i+1]):
count += 1
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,623,572,097 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 62 | 102,400 | def bach_gold(n):
count = 0
if n % 2 == 0:
count += n / 2
print(int(count))
print(str("2 " * int(count)))
else:
count += (n - 1) / 2
print(int(count))
print(str("2 ") * int(count - 1) + str("3"))
n = int(input())
bach_gold(n)
| Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
def bach_gold(n):
count = 0
if n % 2 == 0:
count += n / 2
print(int(count))
print(str("2 " * int(count)))
else:
count += (n - 1) / 2
print(int(count))
print(str("2 ") * int(count - 1) + str("3"))
n = int(input())
bach_gold(n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
748 | A | Santa Claus and a Place in a Class | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are *n* lanes of *m* desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to *n* from the left to the right, the desks in a lane ar... | The only line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=10<=000, 1<=≤<=*k*<=≤<=2*nm*) — the number of lanes, the number of desks in each lane and the number of Santa Claus' place. | Print two integers: the number of lane *r*, the number of desk *d*, and a character *s*, which stands for the side of the desk Santa Claus. The character *s* should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right. | [
"4 3 9\n",
"4 3 24\n",
"2 4 4\n"
] | [
"2 2 L\n",
"4 3 R\n",
"1 2 R\n"
] | The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his pla... | 500 | [
{
"input": "4 3 9",
"output": "2 2 L"
},
{
"input": "4 3 24",
"output": "4 3 R"
},
{
"input": "2 4 4",
"output": "1 2 R"
},
{
"input": "3 10 24",
"output": "2 2 R"
},
{
"input": "10 3 59",
"output": "10 3 L"
},
{
"input": "10000 10000 160845880",
"... | 1,482,657,298 | 598 | Python 3 | OK | TESTS | 46 | 77 | 4,608,000 | n, m, k = map(int, input().split())
row = (k + m * 2 - 1) // (m * 2)
table = (k - ((m * 2) * (row - 1) + 1)) // 2 + 1
place = ''
if k % 2 == 0:
place = 'R'
else:
place = 'L'
print(row, table, place) | Title: Santa Claus and a Place in a Class
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are *n* lanes of *m* desks each, and there are two work... | ```python
n, m, k = map(int, input().split())
row = (k + m * 2 - 1) // (m * 2)
table = (k - ((m * 2) * (row - 1) + 1)) // 2 + 1
place = ''
if k % 2 == 0:
place = 'R'
else:
place = 'L'
print(row, table, place)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
779 | A | Pupils Redistribution | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consists of exactly *n* students. An academic performance of each student is known — integer value between 1 and ... | The first line of the input contains integer number *n* (1<=≤<=*n*<=≤<=100) — number of students in both groups.
The second line contains sequence of integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=5), where *a**i* is academic performance of the *i*-th student of the group *A*.
The third line contains se... | Print the required minimum number of exchanges or -1, if the desired distribution of students can not be obtained. | [
"4\n5 4 4 4\n5 5 4 5\n",
"6\n1 1 1 1 1 1\n5 5 5 5 5 5\n",
"1\n5\n3\n",
"9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1\n"
] | [
"1\n",
"3\n",
"-1\n",
"4\n"
] | none | 500 | [
{
"input": "4\n5 4 4 4\n5 5 4 5",
"output": "1"
},
{
"input": "6\n1 1 1 1 1 1\n5 5 5 5 5 5",
"output": "3"
},
{
"input": "1\n5\n3",
"output": "-1"
},
{
"input": "9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1",
"output": "4"
},
{
"input": "1\n1\n2",
"output": "-1"
... | 1,489,190,281 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 62 | 4,608,000 | n = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
ma = [0] * 5
mb = [0] * 5
for a, b in zip(A, B):
ma[a - 1] += 1
mb[b - 1] += 1
ca = 0
cb = 0
for a, b in zip(ma, mb):
if (a + b)% 2 != 0:
print(-1)
exit()
if a - b > 0:
ca += (... | Title: Pupils Redistribution
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consis... | ```python
n = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
ma = [0] * 5
mb = [0] * 5
for a, b in zip(A, B):
ma[a - 1] += 1
mb[b - 1] += 1
ca = 0
cb = 0
for a, b in zip(ma, mb):
if (a + b)% 2 != 0:
print(-1)
exit()
if a - b > 0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,666,158,510 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | #byerainkaporababu
a,b=map(int,input().split())
sum1=(a*b)//2
print(sum1)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
#byerainkaporababu
a,b=map(int,input().split())
sum1=(a*b)//2
print(sum1)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
957 | A | Tritonic Iridescence | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one-dimensional canvas split into *n* consecutive segments, each segment needs to be painted in one of the co... | The first line contains a single positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the canvas.
The second line contains a string *s* of *n* characters, the *i*-th of which is either 'C' (denoting a segment painted in cyan), 'M' (denoting one painted in magenta), 'Y' (one painted in yellow), or '?' (an unpainted... | If there are at least two different ways of painting, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5\nCY??Y\n",
"5\nC?C?Y\n",
"5\n?CYC?\n",
"5\nC??MM\n",
"3\nMMY\n"
] | [
"Yes\n",
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | For the first example, there are exactly two different ways of colouring: CYCMY and CYMCY.
For the second example, there are also exactly two different ways of colouring: CMCMY and CYCMY.
For the third example, there are four ways of colouring: MCYCM, MCYCY, YCYCM, and YCYCY.
For the fourth example, no matter how th... | 500 | [
{
"input": "5\nCY??Y",
"output": "Yes"
},
{
"input": "5\nC?C?Y",
"output": "Yes"
},
{
"input": "5\n?CYC?",
"output": "Yes"
},
{
"input": "5\nC??MM",
"output": "No"
},
{
"input": "3\nMMY",
"output": "No"
},
{
"input": "15\n??YYYYYY??YYYY?",
"output"... | 1,632,245,518 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 62 | 6,758,400 | n, s = int(input()), input()
if (("??" in s or "C?C" in s or "M?M" in s or "Y?Y" in s or s[0] == "?" or s[-1] == "?")
and not("CC" in s or "YY" in s or "MM" in s)):
print("YES")
else:
print("NO") | Title: Tritonic Iridescence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one... | ```python
n, s = int(input()), input()
if (("??" in s or "C?C" in s or "M?M" in s or "Y?Y" in s or s[0] == "?" or s[-1] == "?")
and not("CC" in s or "YY" in s or "MM" in s)):
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is... | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so ... | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,631,801,207 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 6,963,200 | n=int(input())
l=[]
c=1
ans=[]
for i in range(n):
s,a=input().split()
if [s,a] not in l:
l.append([s,a])
ans.append(c)
c=1
else:
c=c+1
ans.append(c)
print(max(ans)) | Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends l... | ```python
n=int(input())
l=[]
c=1
ans=[]
for i in range(n):
s,a=input().split()
if [s,a] not in l:
l.append([s,a])
ans.append(c)
c=1
else:
c=c+1
ans.append(c)
print(max(ans))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
868 | A | Bark to Unlock | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's p... | The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of words Kashtanka knows.
The next *n* lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to b... | Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"ya\n4\nah\noy\nto\nha\n",
"hp\n2\nht\ntp\n",
"ah\n1\nha\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" produ... | 250 | [
{
"input": "ya\n4\nah\noy\nto\nha",
"output": "YES"
},
{
"input": "hp\n2\nht\ntp",
"output": "NO"
},
{
"input": "ah\n1\nha",
"output": "YES"
},
{
"input": "bb\n4\nba\nab\naa\nbb",
"output": "YES"
},
{
"input": "bc\n4\nca\nba\nbb\ncc",
"output": "YES"
},
{
... | 1,599,444,970 | 2,147,483,647 | PyPy 3 | OK | TESTS | 90 | 156 | 0 | pas = input()
l = []
for i in range(int(input())):
l.append(input())
for i in l:
if i==pas:
print("YES")
exit(0)
knt1= 0
knt2 = 0
for i in l:
if i[1] == pas[0]:
knt1=1
if i[0] == pas[1]:
knt2=1
if knt1+knt2==2:
print("YES")
exit(0)
... | Title: Bark to Unlock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a passw... | ```python
pas = input()
l = []
for i in range(int(input())):
l.append(input())
for i in l:
if i==pas:
print("YES")
exit(0)
knt1= 0
knt2 = 0
for i in l:
if i[1] == pas[0]:
knt1=1
if i[0] == pas[1]:
knt2=1
if knt1+knt2==2:
print("YES")
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,564,662,690 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | m = int(input("Enter any number "))
m+=1
print (i[m+1]) | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
m = int(input("Enter any number "))
m+=1
print (i[m+1])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
596 | A | Wilbur and Swimming Pool | PROGRAMMING | 1,100 | [
"geometry",
"implementation"
] | null | null | After making bad dives into swimming pools, Wilbur wants to build a swimming pool in the shape of a rectangle in his backyard. He has set up coordinate axes, and he wants the sides of the rectangle to be parallel to them. Of course, the area of the rectangle must be positive. Wilbur had all four vertices of the planned... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=4) — the number of vertices that were not erased by Wilbur's friend.
Each of the following *n* lines contains two integers *x**i* and *y**i* (<=-<=1000<=≤<=*x**i*,<=*y**i*<=≤<=1000) —the coordinates of the *i*-th vertex that remains. Vertices are... | Print the area of the initial rectangle if it could be uniquely determined by the points remaining. Otherwise, print <=-<=1. | [
"2\n0 0\n1 1\n",
"1\n1 1\n"
] | [
"1\n",
"-1\n"
] | In the first sample, two opposite corners of the initial rectangle are given, and that gives enough information to say that the rectangle is actually a unit square.
In the second sample there is only one vertex left and this is definitely not enough to uniquely define the area. | 500 | [
{
"input": "2\n0 0\n1 1",
"output": "1"
},
{
"input": "1\n1 1",
"output": "-1"
},
{
"input": "1\n-188 17",
"output": "-1"
},
{
"input": "1\n71 -740",
"output": "-1"
},
{
"input": "4\n-56 -858\n-56 -174\n778 -858\n778 -174",
"output": "570456"
},
{
"inp... | 1,653,142,087 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 17 | 46 | 0 | import sys
input = sys.stdin.readline
n = int(input())
g = sorted([list(map(int, input().split())) for _ in range(n)])
if n == 1:
print(-1)
elif n == 2:
if g[0][0] == g[1][0] or g[0][1] == g[1][1]:
print(-1)
else:
print(abs(g[0][0] - g[1][0]) * abs(g[0][1] - g[1][1]))
else:
... | Title: Wilbur and Swimming Pool
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After making bad dives into swimming pools, Wilbur wants to build a swimming pool in the shape of a rectangle in his backyard. He has set up coordinate axes, and he wants the sides of the rectangle to be parall... | ```python
import sys
input = sys.stdin.readline
n = int(input())
g = sorted([list(map(int, input().split())) for _ in range(n)])
if n == 1:
print(-1)
elif n == 2:
if g[0][0] == g[1][0] or g[0][1] == g[1][1]:
print(-1)
else:
print(abs(g[0][0] - g[1][0]) * abs(g[0][1] - g[1][1]))... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,684,822,286 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 0 | 0 | x=input()
print(x)
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
x=input()
print(x)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,697,866,243 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 0 | n = int(input())
s = 0
for i in range(1,n+1):
if i%2 ==0:
s+=i
else:
s-=i
print(s) | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
n = int(input())
s = 0
for i in range(1,n+1):
if i%2 ==0:
s+=i
else:
s-=i
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
474 | A | Keyboard | PROGRAMMING | 900 | [
"implementation"
] | null | null | Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That mean... | First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).
Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain ... | Print a line that contains the original message. | [
"R\ns;;upimrrfod;pbr\n"
] | [
"allyouneedislove\n"
] | none | 500 | [
{
"input": "R\ns;;upimrrfod;pbr",
"output": "allyouneedislove"
},
{
"input": "R\nwertyuiop;lkjhgfdsxcvbnm,.",
"output": "qwertyuiolkjhgfdsazxcvbnm,"
},
{
"input": "L\nzxcvbnm,kjhgfdsaqwertyuio",
"output": "xcvbnm,.lkjhgfdswertyuiop"
},
{
"input": "R\nbubbuduppudup",
"outp... | 1,675,016,750 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 46 | 0 | d = -1 if input() == "R" else 1
s = input()
k = "0qwertyuiop0asdfghjkl;0zxcvbnm,./0"
res = ""
for l in s:
res += k[k.index(l) + d] if k[k.index(l) + d] != "0" else ""
print(res) | Title: Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately.... | ```python
d = -1 if input() == "R" else 1
s = input()
k = "0qwertyuiop0asdfghjkl;0zxcvbnm,./0"
res = ""
for l in s:
res += k[k.index(l) + d] if k[k.index(l) + d] != "0" else ""
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,642,607,874 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | from math import *
n = int(input())
if n % 2 != 0:
print(n * (n - 1) * (n - 2))
else:
ans = (n - 2) * (n - 1) * (n - 3)
k = n - 3
while k >= 1:
if gcd(k, n) >= 2:
break
ans = max(n * (n - 1) * k, ans)
k -= 2
print(ans)
| Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
from math import *
n = int(input())
if n % 2 != 0:
print(n * (n - 1) * (n - 2))
else:
ans = (n - 2) * (n - 1) * (n - 3)
k = n - 3
while k >= 1:
if gcd(k, n) >= 2:
break
ans = max(n * (n - 1) * k, ans)
k -= 2
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
876 | B | Divisiblity of Differences | PROGRAMMING | 1,300 | [
"implementation",
"math",
"number theory"
] | null | null | You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be repeated in the original multiset and in the multiset of selected numbers, but number of occurrences of any number... | First line contains three integers *n*, *k* and *m* (2<=≤<=*k*<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — number of integers in the multiset, number of integers you should select and the required divisor of any pair of selected integers.
Second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=... | If it is not possible to select *k* numbers in the desired way, output «No» (without the quotes).
Otherwise, in the first line of output print «Yes» (without the quotes). In the second line print *k* integers *b*1,<=*b*2,<=...,<=*b**k* — the selected numbers. If there are multiple possible solutions, print any of them... | [
"3 2 3\n1 8 4\n",
"3 3 3\n1 8 4\n",
"4 3 5\n2 7 7 7\n"
] | [
"Yes\n1 4 ",
"No",
"Yes\n2 7 7 "
] | none | 1,000 | [
{
"input": "3 2 3\n1 8 4",
"output": "Yes\n1 4 "
},
{
"input": "3 3 3\n1 8 4",
"output": "No"
},
{
"input": "4 3 5\n2 7 7 7",
"output": "Yes\n2 7 7 "
},
{
"input": "9 9 5\n389149775 833127990 969340400 364457730 48649145 316121525 640054660 924273385 973207825",
"output":... | 1,519,548,804 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 202 | 19,968,000 | n, k, m = map(int, input().split())
a = list(map(int, input().split()))
rec = [[] for i in range(m)]
for i in range(n):
rec[a[i] % m].append(a[i])
flag = False
for i in range(m):
if len(rec[i]) >= k:
print("Yes")
print(" ".join(map(str, rec[i][:k])))
flag = True
brea... | Title: Divisiblity of Differences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be re... | ```python
n, k, m = map(int, input().split())
a = list(map(int, input().split()))
rec = [[] for i in range(m)]
for i in range(n):
rec[a[i] % m].append(a[i])
flag = False
for i in range(m):
if len(rec[i]) >= k:
print("Yes")
print(" ".join(map(str, rec[i][:k])))
flag = True
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
262 | B | Roma and Changing Signs | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of s... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made.
The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104).
The numbers in the lines are separated by single spaces... | In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes. | [
"3 2\n-1 -1 1\n",
"3 1\n-1 -1 1\n"
] | [
"3\n",
"1\n"
] | In the first sample we can get sequence [1, 1, 1], thus the total income equals 3.
In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1. | 1,000 | [
{
"input": "3 2\n-1 -1 1",
"output": "3"
},
{
"input": "3 1\n-1 -1 1",
"output": "1"
},
{
"input": "17 27\n257 320 676 1136 2068 2505 2639 4225 4951 5786 7677 7697 7851 8337 8429 8469 9343",
"output": "81852"
},
{
"input": "69 28\n-9822 -9264 -9253 -9221 -9139 -9126 -9096 -89... | 1,664,667,801 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 60 | 0 | numbers = list(map(int , input().split()))
arr = list(map(int , input().split()))
arr.sort()
sum = 0
for i in range(0 , 2) :
if arr[i] < 0 and numbers[1] != 0:
arr[i] = arr[i] * -1
numbers[1] -= 1
for i in arr :
sum += i
print(sum) | Title: Roma and Changing Signs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of ... | ```python
numbers = list(map(int , input().split()))
arr = list(map(int , input().split()))
arr.sort()
sum = 0
for i in range(0 , 2) :
if arr[i] < 0 and numbers[1] != 0:
arr[i] = arr[i] * -1
numbers[1] -= 1
for i in arr :
sum += i
print(sum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
277 | A | Learning Languages | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu"
] | null | null | The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have the list of languages, which he knows. This list could be empty, i. e. an employee may know no official la... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=100) — the number of employees and the number of languages.
Then *n* lines follow — each employee's language list. At the beginning of the *i*-th line is integer *k**i* (0<=≤<=*k**i*<=≤<=*m*) — the number of languages the *i*-th employee knows. Next... | Print a single integer — the minimum amount of money to pay so that in the end every employee could write a letter to every other one (other employees can help out translating). | [
"5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5\n",
"8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1\n",
"2 2\n1 2\n0\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the second sample the employee 1 can learn language 2, and employee 8 can learn language 4.
In the third sample employee 2 must learn language 2. | 500 | [
{
"input": "5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5",
"output": "0"
},
{
"input": "8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1",
"output": "2"
},
{
"input": "2 2\n1 2\n0",
"output": "1"
},
{
"input": "2 2\n0\n0",
"output": "2"
},
{
"input": "5 5\n1 3\n0\n0\n2 4... | 1,664,619,161 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 10 | 186 | 2,150,400 | from collections import defaultdict
class UnionFind:
def __init__(self, size):
self.root = [i for i in range(size)]
self.rank = [1] * size
def find(self, x):
while x != self.root[x]:
x = self.root[x]
return x
def union(self, x, y):
rootX = self.find(x)... | Title: Learning Languages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have th... | ```python
from collections import defaultdict
class UnionFind:
def __init__(self, size):
self.root = [i for i in range(size)]
self.rank = [1] * size
def find(self, x):
while x != self.root[x]:
x = self.root[x]
return x
def union(self, x, y):
rootX = se... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
908 | A | New Year and Counting Cards | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a c... | The first and only line of input will contain a string *s* (1<=≤<=|*s*|<=≤<=50), denoting the sides of the cards that you can see on the table currently. Each character of *s* is either a lowercase English letter or a digit. | Print a single integer, the minimum number of cards you must turn over to verify your claim. | [
"ee\n",
"z\n",
"0ay1\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on th... | 500 | [
{
"input": "ee",
"output": "2"
},
{
"input": "z",
"output": "0"
},
{
"input": "0ay1",
"output": "2"
},
{
"input": "0abcdefghijklmnopqrstuvwxyz1234567896",
"output": "10"
},
{
"input": "0a0a9e9e2i2i9o9o6u6u9z9z4x4x9b9b",
"output": "18"
},
{
"input": "01... | 1,599,699,912 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 108 | 0 | entrada = input()
x = list(entrada)
pares = ['0','2','4','6','8']
vogais = ['a','e','i','o','u']
cont = 0
for i in x:
if (i in vogais) or (i in pares):
cont += 1
print(cont)
| Title: New Year and Counting Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each car... | ```python
entrada = input()
x = list(entrada)
pares = ['0','2','4','6','8']
vogais = ['a','e','i','o','u']
cont = 0
for i in x:
if (i in vogais) or (i in pares):
cont += 1
print(cont)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
197 | A | Plate Game | PROGRAMMING | 1,600 | [
"constructive algorithms",
"games",
"math"
] | null | null | You've got a rectangular table with length *a* and width *b* and the infinite number of plates of radius *r*. Two players play the following game: they take turns to put the plates on the table so that the plates don't lie on each other (but they can touch each other), and so that any point on any plate is located with... | A single line contains three space-separated integers *a*, *b*, *r* (1<=≤<=*a*,<=*b*,<=*r*<=≤<=100) — the table sides and the plates' radius, correspondingly. | If wins the player who moves first, print "First" (without the quotes). Otherwise print "Second" (without the quotes). | [
"5 5 2\n",
"6 7 4\n"
] | [
"First\n",
"Second\n"
] | In the first sample the table has place for only one plate. The first player puts a plate on the table, the second player can't do that and loses.
In the second sample the table is so small that it doesn't have enough place even for one plate. So the first player loses without making a single move. | 1,000 | [
{
"input": "5 5 2",
"output": "First"
},
{
"input": "6 7 4",
"output": "Second"
},
{
"input": "100 100 1",
"output": "First"
},
{
"input": "1 1 100",
"output": "Second"
},
{
"input": "13 7 3",
"output": "First"
},
{
"input": "23 7 3",
"output": "Fi... | 1,507,162,289 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 307,200 | a,b,r=list(map(int,input().split()))
from math import *
c=round((a*b)/(pi*r**2)+1)
for i in range(c):
if r<a and r<b:
a+=-r
b+=-r
else:
if i%2==0:
print('First')
else:
print('Second') | Title: Plate Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular table with length *a* and width *b* and the infinite number of plates of radius *r*. Two players play the following game: they take turns to put the plates on the table so that the plates don't lie o... | ```python
a,b,r=list(map(int,input().split()))
from math import *
c=round((a*b)/(pi*r**2)+1)
for i in range(c):
if r<a and r<b:
a+=-r
b+=-r
else:
if i%2==0:
print('First')
else:
print('Second')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
711 | C | Coloring Trees | PROGRAMMING | 1,700 | [
"dp"
] | null | null | ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where *n* trees grow. They decided to be naughty and color the trees in the park. The trees are numbered with integers from 1 to *n* from left to right.
Initially, tree *i* has color *c**i*. ZS the Coder and Chris the Baboon recognizes ... | The first line contains three integers, *n*, *m* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100, 1<=≤<=*m*<=≤<=100) — the number of trees, number of colors and beauty of the resulting coloring respectively.
The second line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (0<=≤<=*c**i*<=≤<=*m*), the initial colors of the trees. *c... | Print a single integer, the minimum amount of paint needed to color the trees. If there are no valid tree colorings of beauty *k*, print <=-<=1. | [
"3 2 2\n0 0 0\n1 2\n3 4\n5 6\n",
"3 2 2\n2 1 2\n1 3\n2 4\n3 5\n",
"3 2 2\n2 0 0\n1 3\n2 4\n3 5\n",
"3 2 3\n2 1 2\n1 3\n2 4\n3 5\n"
] | [
"10",
"-1",
"5",
"0"
] | In the first sample case, coloring the trees with colors 2, 1, 1 minimizes the amount of paint used, which equals to 2 + 3 + 5 = 10. Note that 1, 1, 1 would not be valid because the beauty of such coloring equals to 1 ({1, 1, 1} is a way to group the trees into a single group of the same color).
In the second sample c... | 1,500 | [
{
"input": "3 2 2\n0 0 0\n1 2\n3 4\n5 6",
"output": "10"
},
{
"input": "3 2 2\n2 1 2\n1 3\n2 4\n3 5",
"output": "-1"
},
{
"input": "3 2 2\n2 0 0\n1 3\n2 4\n3 5",
"output": "5"
},
{
"input": "3 2 3\n2 1 2\n1 3\n2 4\n3 5",
"output": "0"
},
{
"input": "3 2 3\n0 0 0\n... | 1,597,863,514 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 89 | 2,000 | 23,040,000 |
def ans(n,c,t):
if c>k:
return float('inf')
if dp[n][c][t] != -1:
return dp[n][c][t]
gg = float('inf')
if n == act_n:
if c == k:
return 0
else:
return float('inf')
if a[n]!=0:
dp[n][c][t] = ans(n+1,c+(a[n]!=t),a[n]... | Title: Coloring Trees
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where *n* trees grow. They decided to be naughty and color the trees in the park. The trees are numbered with integers from 1 to *n* from... | ```python
def ans(n,c,t):
if c>k:
return float('inf')
if dp[n][c][t] != -1:
return dp[n][c][t]
gg = float('inf')
if n == act_n:
if c == k:
return 0
else:
return float('inf')
if a[n]!=0:
dp[n][c][t] = ans(n+1,c+(a[n... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
780 | A | Andryusha and Socks | PROGRAMMING | 800 | [
"implementation"
] | null | null | Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the ... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs.
The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha ... | Print single integer — the maximum number of socks that were on the table at the same time. | [
"1\n1 1\n",
"3\n2 1 1 3 2 3\n"
] | [
"1\n",
"2\n"
] | In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time.
In the second example Andryusha behaved as follows:
- ... | 500 | [
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "3\n2 1 1 3 2 3",
"output": "2"
},
{
"input": "5\n5 1 3 2 4 3 1 2 4 5",
"output": "5"
},
{
"input": "10\n4 2 6 3 4 8 7 1 1 5 2 10 6 8 3 5 10 9 9 7",
"output": "6"
},
{
"input": "50\n30 47 31 38 37 50 36 43 9 23 2 2 ... | 1,610,284,266 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 14,336,000 | # import os
n = int(input())
a = list(map(int,input().split()))
r = 0
rr = []
for sock in a:
if sock not in rr:
rr.append(sock)
r = len(rr) if len(rr) > r else r
else:
rr.remove(sock)
print(r)
| Title: Andryusha and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbere... | ```python
# import os
n = int(input())
a = list(map(int,input().split()))
r = 0
rr = []
for sock in a:
if sock not in rr:
rr.append(sock)
r = len(rr) if len(rr) > r else r
else:
rr.remove(sock)
print(r)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
474 | F | Ant colony | PROGRAMMING | 2,100 | [
"data structures",
"math",
"number theory"
] | null | null | Mole is hungry again. He found one ant colony, consisting of *n* ants, ordered in a row. Each ant *i* (1<=≤<=*i*<=≤<=*n*) has a strength *s**i*.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) and each... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105), the size of the ant colony.
The second line contains *n* integers *s*1,<=*s*2,<=...,<=*s**n* (1<=≤<=*s**i*<=≤<=109), the strengths of the ants.
The third line contains one integer *t* (1<=≤<=*t*<=≤<=105), the number of test cases.
Each of the next *t* l... | Print to the standard output *t* lines. The *i*-th line contains number of ants that Mole eats from the segment [*l**i*,<=*r**i*]. | [
"5\n1 3 2 4 2\n4\n1 5\n2 5\n3 5\n4 5\n"
] | [
"4\n4\n1\n1\n"
] | In the first test battle points for each ant are *v* = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are *v* = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are *v* = [2, 0, 2], so ants number ... | 3,000 | [
{
"input": "5\n1 3 2 4 2\n4\n1 5\n2 5\n3 5\n4 5",
"output": "4\n4\n1\n1"
}
] | 1,693,556,114 | 1,814 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | t = input()
ar = list(map(int,input().split(' ')))
i = int(input())
for j in range(i):
a = list(map(int,input().split(' ')))
print(a)
sub = ar[a[0]-1:a[1]]
print(sub)
c = 0
for k,l in enumerate(sub):
o = True
for m in sub:
if m%l!=0:
o = F... | Title: Ant colony
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mole is hungry again. He found one ant colony, consisting of *n* ants, ordered in a row. Each ant *i* (1<=≤<=*i*<=≤<=*n*) has a strength *s**i*.
In order to make his dinner more interesting, Mole organizes a version of «Hun... | ```python
t = input()
ar = list(map(int,input().split(' ')))
i = int(input())
for j in range(i):
a = list(map(int,input().split(' ')))
print(a)
sub = ar[a[0]-1:a[1]]
print(sub)
c = 0
for k,l in enumerate(sub):
o = True
for m in sub:
if m%l!=0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
523 | D | Statistics of Recompressing Videos | PROGRAMMING | 1,600 | [
"*special",
"data structures",
"implementation"
] | null | null | A social network for dogs called DH (DogHouse) has *k* special servers to recompress uploaded videos of cute cats. After each video is uploaded, it should be recompressed on one (any) of the servers, and only after that it can be saved in the social network.
We know that each server takes one second to recompress a on... | The first line of the input contains integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=5·105) — the number of videos and servers, respectively.
Next *n* lines contain the descriptions of the videos as pairs of integers *s**i*,<=*m**i* (1<=≤<=*s**i*,<=*m**i*<=≤<=109), where *s**i* is the time in seconds when the *i*-th video a... | Print *n* numbers *e*1,<=*e*2,<=...,<=*e**n*, where *e**i* is the time in seconds after the servers start working, when the *i*-th video will be recompressed. | [
"3 2\n1 5\n2 5\n3 5\n",
"6 1\n1 1000000000\n2 1000000000\n3 1000000000\n4 1000000000\n5 1000000000\n6 3\n"
] | [
"6\n7\n11\n",
"1000000001\n2000000001\n3000000001\n4000000001\n5000000001\n5000000004\n"
] | none | 2,000 | [
{
"input": "3 2\n1 5\n2 5\n3 5",
"output": "6\n7\n11"
},
{
"input": "6 1\n1 1000000000\n2 1000000000\n3 1000000000\n4 1000000000\n5 1000000000\n6 3",
"output": "1000000001\n2000000001\n3000000001\n4000000001\n5000000001\n5000000004"
},
{
"input": "1 1\n1 1",
"output": "2"
},
{
... | 1,426,427,259 | 82,059 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 12 | 3,000 | 819,200 | n,k = map(int,input().split())
a = [0]*k
for i in range(n):
s,m = map(int, input().split())
j = a.index(min(a))
if(a[j] > s):
a[j] += m
else:
a[j] = s + m
print(a[j])
| Title: Statistics of Recompressing Videos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A social network for dogs called DH (DogHouse) has *k* special servers to recompress uploaded videos of cute cats. After each video is uploaded, it should be recompressed on one (any) of the servers, ... | ```python
n,k = map(int,input().split())
a = [0]*k
for i in range(n):
s,m = map(int, input().split())
j = a.index(min(a))
if(a[j] > s):
a[j] += m
else:
a[j] = s + m
print(a[j])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
190 | D | Non-Secret Cypher | PROGRAMMING | 1,900 | [
"two pointers"
] | null | null | Berland starts to seize the initiative on the war with Flatland. To drive the enemy from their native land, the berlanders need to know exactly how many more flatland soldiers are left in the enemy's reserve. Fortunately, the scouts captured an enemy in the morning, who had a secret encrypted message with the informati... | The first line contains two space-separated integers *n*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=4·105), showing how many numbers an array has and how many equal numbers the subarrays are required to have, correspondingly.
The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=109) — elements of the array... | Print the single number — the number of such subarrays of array *a*, that they have at least *k* equal integers.
Please do not use the %lld specifier to read or write 64-bit integers in С++. In is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 2\n1 2 1 2\n",
"5 3\n1 2 1 1 3\n",
"3 1\n1 1 1\n"
] | [
"3",
"2",
"6"
] | In the first sample are three subarrays, containing at least two equal numbers: (1,2,1), (2,1,2) and (1,2,1,2).
In the second sample are two subarrays, containing three equal numbers: (1,2,1,1,3) and (1,2,1,1).
In the third sample any subarray contains at least one 1 number. Overall they are 6: (1), (1), (1), (1,1), ... | 2,000 | [
{
"input": "4 2\n1 2 1 2",
"output": "3"
},
{
"input": "5 3\n1 2 1 1 3",
"output": "2"
},
{
"input": "3 1\n1 1 1",
"output": "6"
},
{
"input": "20 2\n6 7 2 4 6 8 4 3 10 5 3 5 7 9 1 2 8 1 9 10",
"output": "131"
},
{
"input": "63 2\n1 2 1 2 4 5 1 1 1 1 1 2 3 1 2 3 3... | 1,637,482,430 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | '''
# left - указатель на первый элемент списка, равный val
# right - указатель на последний элемент списка, не равный val
# элементы nums[right] nums[left] меняются местами, ненужные элементы оказываются в конце
# в конце возвращается указатель на последний элемент равный val
class Solution:
def removeElem... | Title: Non-Secret Cypher
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland starts to seize the initiative on the war with Flatland. To drive the enemy from their native land, the berlanders need to know exactly how many more flatland soldiers are left in the enemy's reserve. Fortunat... | ```python
'''
# left - указатель на первый элемент списка, равный val
# right - указатель на последний элемент списка, не равный val
# элементы nums[right] nums[left] меняются местами, ненужные элементы оказываются в конце
# в конце возвращается указатель на последний элемент равный val
class Solution:
def ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab'... | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mah... | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,671,369,577 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 61 | 2,867,200 | # -*- coding: utf-8 -*-
"""
Created on Sun Dec 18 18:21:15 2022
@author: rohan
"""
import math
t = int(input())
for _ in range(t):
n, x = map(int, input().split(" "))
print(1 if n <= 2 else math.ceil((n-2)/x) + 1) | Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a*... | ```python
# -*- coding: utf-8 -*-
"""
Created on Sun Dec 18 18:21:15 2022
@author: rohan
"""
import math
t = int(input())
for _ in range(t):
n, x = map(int, input().split(" "))
print(1 if n <= 2 else math.ceil((n-2)/x) + 1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
76 | A | Gift | PROGRAMMING | 2,200 | [
"dsu",
"graphs",
"sortings",
"trees"
] | A. Gift | 2 | 256 | The kingdom of Olympia consists of *N* cities and *M* bidirectional roads. Each road connects exactly two cities and two cities can be connected with more than one road. Also it possible that some roads connect city with itself making a loop.
All roads are constantly plundered with bandits. After a while bandits becam... | The first line of the input contains two integers *N* and *M* (2<=≤<=*N*<=≤<=200, 1<=≤<=*M*<=≤<=50<=000) — the number of cities and the number of roads, respectively. The second line contains two integers *G* and *S* (1<=≤<=*G*,<=*S*<=≤<=109) — the prices of gold and silver coins in tugriks. The following *M* lines con... | The output should contain the minimal cost of the gift in Olympian tugriks. If there is no gift that satisfies the given requirements output . | [
"3 3\n2 1\n1 2 10 15\n1 2 4 20\n1 3 5 1\n"
] | [
"30\n"
] | none | 0 | [
{
"input": "3 3\n2 1\n1 2 10 15\n1 2 4 20\n1 3 5 1",
"output": "30"
}
] | 1,639,494,741 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | class DSU:
def __init__(self, size: int, initializer: int = 0):
self.init = initializer
self.parent = list(range(initializer, size + initializer))
self.rank = [0] * size
def union(self, a, b):
a = self.find(a)
b = self.find(b)
if a != b:
... | Title: Gift
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The kingdom of Olympia consists of *N* cities and *M* bidirectional roads. Each road connects exactly two cities and two cities can be connected with more than one road. Also it possible that some roads connect city with itself making... | ```python
class DSU:
def __init__(self, size: int, initializer: int = 0):
self.init = initializer
self.parent = list(range(initializer, size + initializer))
self.rank = [0] * size
def union(self, a, b):
a = self.find(a)
b = self.find(b)
if a != b:
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
192 | A | Funky Numbers | PROGRAMMING | 1,300 | [
"binary search",
"brute force",
"implementation"
] | null | null | As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.
A well-known hipster Andrew adores everything funky and c... | The first input line contains an integer *n* (1<=≤<=*n*<=≤<=109). | Print "YES" (without the quotes), if *n* can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes). | [
"256\n",
"512\n"
] | [
"YES\n",
"NO\n"
] | In the first sample number <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/92095692c6ea93e9e3b837a0408ba7543549d5b2.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample number 512 can not be represented as a sum of two triangular numbers. | 500 | [
{
"input": "256",
"output": "YES"
},
{
"input": "512",
"output": "NO"
},
{
"input": "80",
"output": "NO"
},
{
"input": "828",
"output": "YES"
},
{
"input": "6035",
"output": "NO"
},
{
"input": "39210",
"output": "YES"
},
{
"input": "79712",... | 1,591,456,183 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 528 | 614,400 | def binary_search(arr, low, high, x):
# Check base case
if high >= low:
mid = (high + low) // 2
if arr[mid] == x:
return mid
elif arr[mid] > x:
return binary_search(arr, low, mid - 1, x)
else:
return binary_search(arr, mid + 1,... | Title: Funky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are represent... | ```python
def binary_search(arr, low, high, x):
# Check base case
if high >= low:
mid = (high + low) // 2
if arr[mid] == x:
return mid
elif arr[mid] > x:
return binary_search(arr, low, mid - 1, x)
else:
return binary_search(arr... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
190 | A | Vasya and the Bus | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant and he loves counting money. So he wondered what maximum and minimum sum of money these passengers cou... | The input file consists of a single line containing two space-separated numbers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=105) — the number of the grown-ups and the number of the children in the bus, correspondingly. | If *n* grown-ups and *m* children could have ridden in the bus, then print on a single line two space-separated integers — the minimum and the maximum possible total bus fare, correspondingly.
Otherwise, print "Impossible" (without the quotes). | [
"1 2\n",
"0 5\n",
"2 2\n"
] | [
"2 2",
"Impossible",
"2 3"
] | In the first sample a grown-up rides with two children and pays two rubles.
In the second sample there are only children in the bus, so the situation is impossible.
In the third sample there are two cases: - Each of the two grown-ups rides with one children and pays one ruble for the tickets. In this case the passen... | 500 | [
{
"input": "1 2",
"output": "2 2"
},
{
"input": "0 5",
"output": "Impossible"
},
{
"input": "2 2",
"output": "2 3"
},
{
"input": "2 7",
"output": "7 8"
},
{
"input": "4 10",
"output": "10 13"
},
{
"input": "6 0",
"output": "6 6"
},
{
"input... | 1,648,267,864 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | p,c=map(int, input().split())
if p==0:
print("Impossible" )
else:
if c==0:
print(p,end=" ")
else:
print(c,end=" ")
print(p-1+c)
| Title: Vasya and the Bus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant... | ```python
p,c=map(int, input().split())
if p==0:
print("Impossible" )
else:
if c==0:
print(p,end=" ")
else:
print(c,end=" ")
print(p-1+c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Mike has a frog and a flower. His frog is named Xaniar and his flower is named Abol. Initially(at time 0), height of Xaniar is *h*1 and height of Abol is *h*2. Each second, Mike waters Abol and Xaniar.
So, if height of Xaniar is *h*1 and height of Abol is *h*2, after one second height of Xaniar will become and height... | The first line of input contains integer *m* (2<=≤<=*m*<=≤<=106).
The second line of input contains integers *h*1 and *a*1 (0<=≤<=*h*1,<=*a*1<=<<=*m*).
The third line of input contains integers *x*1 and *y*1 (0<=≤<=*x*1,<=*y*1<=<<=*m*).
The fourth line of input contains integers *h*2 and *a*2 (0<=≤<=*h*2,<=*a*... | Print the minimum number of seconds until Xaniar reaches height *a*1 and Abol reaches height *a*2 or print -1 otherwise. | [
"5\n4 2\n1 1\n0 1\n2 3\n",
"1023\n1 2\n1 0\n1 2\n1 1\n"
] | [
"3\n",
"-1\n"
] | In the first sample, heights sequences are following:
Xaniar: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/85da629b05969e7a8a6636d995b8fe7a0494e8f4.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Abol: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ea... | 0 | [
{
"input": "5\n4 2\n1 1\n0 1\n2 3",
"output": "3"
},
{
"input": "1023\n1 2\n1 0\n1 2\n1 1",
"output": "-1"
},
{
"input": "1023\n1 2\n1 2\n1 2\n1 2",
"output": "512"
},
{
"input": "2\n0 1\n1 0\n1 0\n0 1",
"output": "-1"
},
{
"input": "17\n15 12\n15 12\n12 14\n1 11"... | 1,451,332,354 | 1,594 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | import sys
m = int(input())
h1, a1 = [int(i) for i in input().split()]
x1, y1 = [int(i) for i in input().split()]
h2, a2 = [int(i) for i in input().split()]
x2, y2 = [int(i) for i in input().split()]
last = 0
h1_now = h1
h2_now = h2
while last < m + 1:
if h1_now == a1 and h2_now == a2:
print(last... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike has a frog and a flower. His frog is named Xaniar and his flower is named Abol. Initially(at time 0), height of Xaniar is *h*1 and height of Abol is *h*2. Each second, Mike waters Abol and Xaniar.
So, if height of Xaniar is ... | ```python
import sys
m = int(input())
h1, a1 = [int(i) for i in input().split()]
x1, y1 = [int(i) for i in input().split()]
h2, a2 = [int(i) for i in input().split()]
x2, y2 = [int(i) for i in input().split()]
last = 0
h1_now = h1
h2_now = h2
while last < m + 1:
if h1_now == a1 and h2_now == a2:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,599,131,879 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 280 | 0 | s={"A","E","I","O","U","Y"}
string=list(map(str,input().split()))
if string[-1]=="?":
if (string[-2][-1]).upper() in s:
print("YES")
else:
print("NO")
else:
if string[-1][-2].upper() in s:
print("YES")
else:
print("NO") | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
s={"A","E","I","O","U","Y"}
string=list(map(str,input().split()))
if string[-1]=="?":
if (string[-2][-1]).upper() in s:
print("YES")
else:
print("NO")
else:
if string[-1][-2].upper() in s:
print("YES")
else:
print("NO")
``` | 3.93 | MatrixStudio/Codeforces-Python-Submissions |
714 | B | Filya and Homework | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. First, he pick an integer *x* and then he adds *x* to some elements of the array (no more than onc... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of integers in the Filya's array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — elements of the array. | If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes). | [
"5\n1 3 3 2 1\n",
"5\n1 2 3 4 5\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Filya should select *x* = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements. | 1,000 | [
{
"input": "5\n1 3 3 2 1",
"output": "YES"
},
{
"input": "5\n1 2 3 4 5",
"output": "NO"
},
{
"input": "2\n1 2",
"output": "YES"
},
{
"input": "3\n1 2 3",
"output": "YES"
},
{
"input": "3\n1 1 1",
"output": "YES"
},
{
"input": "2\n1 1000000000",
"ou... | 1,501,683,913 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 4,608,000 | import sys
n = int(input())
arr = sorted(list(map(int,input().split())))
if len(set(arr)) <= 2:
print('YES')
elif len(set(arr)) >= 4:
print('NO')
else:
arr2 = sorted(list(set(arr)))
if arr[1] - arr[0] == arr[2] - arr[1] :
print('YES')
else:
print('NO')
| Title: Filya and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a... | ```python
import sys
n = int(input())
arr = sorted(list(map(int,input().split())))
if len(set(arr)) <= 2:
print('YES')
elif len(set(arr)) >= 4:
print('NO')
else:
arr2 = sorted(list(set(arr)))
if arr[1] - arr[0] == arr[2] - arr[1] :
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
670 | A | Holidays | PROGRAMMING | 900 | [
"brute force",
"constructive algorithms",
"greedy",
"math"
] | null | null | On the planet Mars a year lasts exactly *n* days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars. | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=1<=000<=000) — the number of days in a year on Mars. | Print two integers — the minimum possible and the maximum possible number of days off per year on Mars. | [
"14\n",
"2\n"
] | [
"4 4\n",
"0 2\n"
] | In the first sample there are 14 days in a year on Mars, and therefore independently of the day a year starts with there will be exactly 4 days off .
In the second sample there are only 2 days in a year on Mars, and they can both be either work days or days off. | 500 | [
{
"input": "14",
"output": "4 4"
},
{
"input": "2",
"output": "0 2"
},
{
"input": "1",
"output": "0 1"
},
{
"input": "3",
"output": "0 2"
},
{
"input": "4",
"output": "0 2"
},
{
"input": "5",
"output": "0 2"
},
{
"input": "6",
"output":... | 1,694,829,369 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 1 | 77 | 2,867,200 | n = int(input())
if n%7 == 6:
min = ((n/7)*2) + 1
else:
min = (n/7) * 2
if n % 7 == 1:
max = min + 1
elif n % 7 >= 2:
if n % 7 == 6:
max = min + 1
else:
max = min + 2
if n % 7 == 0:
max = min
print(round(min),round(max)) | Title: Holidays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On the planet Mars a year lasts exactly *n* days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maxim... | ```python
n = int(input())
if n%7 == 6:
min = ((n/7)*2) + 1
else:
min = (n/7) * 2
if n % 7 == 1:
max = min + 1
elif n % 7 >= 2:
if n % 7 == 6:
max = min + 1
else:
max = min + 2
if n % 7 == 0:
max = min
print(round(min),round(max))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
729 | B | Spotlights | PROGRAMMING | 1,200 | [
"dp",
"implementation"
] | null | null | Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of t... | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell ... | Print one integer — the number of good positions for placing the spotlight. | [
"2 4\n0 1 0 0\n1 0 1 0\n",
"4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n"
] | [
"9\n",
"20\n"
] | In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and... | 1,000 | [
{
"input": "2 4\n0 1 0 0\n1 0 1 0",
"output": "9"
},
{
"input": "4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0",
"output": "20"
},
{
"input": "1 5\n1 1 0 0 0",
"output": "3"
},
{
"input": "2 10\n0 0 0 0 0 0 0 1 0 0\n1 0 0 0 0 0 0 0 0 0",
"output": "20"
},
{
"input": "3 ... | 1,651,654,071 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 72 | 326 | 18,227,200 | import sys,io,os
#input = io.BytesIO(os.read(0,fstat(st_size(0))).readline
n, m = map(int,input().split())
p = []
vis = [0] * m
vis1 = [0] * n
mn = [-1] * m
mx = [-1] * m
w = []
for i in range(n):
d = list(map(int,input().split()))
p += [d]
e = 1001
e1 = -1
if 1 in d:
for j in range... | Title: Spotlights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to pl... | ```python
import sys,io,os
#input = io.BytesIO(os.read(0,fstat(st_size(0))).readline
n, m = map(int,input().split())
p = []
vis = [0] * m
vis1 = [0] * n
mn = [-1] * m
mx = [-1] * m
w = []
for i in range(n):
d = list(map(int,input().split()))
p += [d]
e = 1001
e1 = -1
if 1 in d:
for ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
120 | A | Elevator | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through the front door, he goes out through the back one and vice versa. The elevator has two rails n... | The first line indicates the door through which the very important person entered the elevator. It contains "front" if the person enters the elevator through the front door and "back" if he entered the elevator through the back door. The second line contains integer *a* (1<=≤<=*a*<=≤<=2) which denotes the number of the... | Print character "R" if the VIP is right-handed or "L" if he is left-handed. | [
"front\n1\n"
] | [
"L\n"
] | none | 0 | [
{
"input": "front\n1",
"output": "L"
},
{
"input": "back\n1",
"output": "R"
},
{
"input": "front\n2",
"output": "R"
},
{
"input": "back\n2",
"output": "L"
}
] | 1,638,301,866 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | side = input()
rail = int(input())
if side == "front":
side = 2
else:
side = 1
if rail == side:
print("R")
else:
print("L") | Title: Elevator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through... | ```python
side = input()
rail = int(input())
if side == "front":
side = 2
else:
side = 1
if rail == side:
print("R")
else:
print("L")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
508 | A | Pasha and Pixels | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row with *m* pixels in each row. Initially, all the pixels are colored white. In one move, Pasha can choos... | The first line of the input contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=105) — the number of rows, the number of columns and the number of moves that Pasha is going to perform.
The next *k* lines contain Pasha's moves in the order he makes them. Each line contains two integers *i*... | If Pasha loses, print the number of the move when the 2<=×<=2 square consisting of black pixels is formed.
If Pasha doesn't lose, that is, no 2<=×<=2 square consisting of black pixels is formed during the given *k* moves, print 0. | [
"2 2 4\n1 1\n1 2\n2 1\n2 2\n",
"2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1\n",
"5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2\n"
] | [
"4\n",
"5\n",
"0\n"
] | none | 500 | [
{
"input": "2 2 4\n1 1\n1 2\n2 1\n2 2",
"output": "4"
},
{
"input": "2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1",
"output": "5"
},
{
"input": "5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2",
"output": "0"
},
{
"input": "3 3 11\n2 1\n3 1\n1 1\n1 3\n1 2\n2 3\n3 3\n3 2\n2 2\n1 3\n3 3",
... | 1,697,706,183 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 0 | # -*- coding: utf-8 -*-
"""
Created on Thu Oct 19 16:18:10 2023
@author: 苏柔德 2300011012
"""
n,m,k=map(int,input().split())
x=[[0]*m for __ in range(n)]
flag=0
for _ in range(k):
i,j=map(int,input().split())
x[i-1][j-1]=1
for row in range(n-1):
for con in range (m-1):
if ... | Title: Pasha and Pixels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row ... | ```python
# -*- coding: utf-8 -*-
"""
Created on Thu Oct 19 16:18:10 2023
@author: 苏柔德 2300011012
"""
n,m,k=map(int,input().split())
x=[[0]*m for __ in range(n)]
flag=0
for _ in range(k):
i,j=map(int,input().split())
x[i-1][j-1]=1
for row in range(n-1):
for con in range (m-1):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
837 | D | Round Subset | PROGRAMMING | 2,100 | [
"dp",
"math"
] | null | null | Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected numbers will be maximum possible. | The first line contains two integer numbers *n* and *k* (1<=≤<=*n*<=≤<=200,<=1<=≤<=*k*<=≤<=*n*).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018). | Print maximal roundness of product of the chosen subset of length *k*. | [
"3 2\n50 4 20\n",
"5 3\n15 16 3 25 9\n",
"3 3\n9 77 13\n"
] | [
"3\n",
"3\n",
"0\n"
] | In the first example there are 3 subsets of 2 numbers. [50, 4] has product 200 with roundness 2, [4, 20] — product 80, roundness 1, [50, 20] — product 1000, roundness 3.
In the second example subset [15, 16, 25] has product 6000, roundness 3.
In the third example all subsets has product with roundness 0. | 0 | [
{
"input": "3 2\n50 4 20",
"output": "3"
},
{
"input": "5 3\n15 16 3 25 9",
"output": "3"
},
{
"input": "3 3\n9 77 13",
"output": "0"
},
{
"input": "1 1\n200000000",
"output": "8"
},
{
"input": "1 1\n3",
"output": "0"
},
{
"input": "3 1\n10000000000000... | 1,658,602,696 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 23 | 170 | 16,691,200 | n,p = map(int,input().split())
nums = []
for z in map(int,input().split()):
x = z
c2 = 0
while x%2==0:
x//=2
c2+=1
x = z
c5 = 0
while x%5==0:
x//=5
c5+=1
nums.append([c2,c5])
aids = [[[-1 for i in range(61)] for i in range(p+1)] for i in range(... | Title: Round Subset
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected number... | ```python
n,p = map(int,input().split())
nums = []
for z in map(int,input().split()):
x = z
c2 = 0
while x%2==0:
x//=2
c2+=1
x = z
c5 = 0
while x%5==0:
x//=5
c5+=1
nums.append([c2,c5])
aids = [[[-1 for i in range(61)] for i in range(p+1)] for i... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,664,432,873 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | n,m = map(int,input().split())
a = [n//5 for i in range(5)]
for i in range(1,n%5+1):
a[i]+=1
# print(a)
b = [m//5 for i in range(5)]
for i in range(1,m%5+1):
b[i]+=1
r = 0
for i in range(5):
r+= a[i]*b[4-i]
print(r)
| Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
n,m = map(int,input().split())
a = [n//5 for i in range(5)]
for i in range(1,n%5+1):
a[i]+=1
# print(a)
b = [m//5 for i in range(5)]
for i in range(1,m%5+1):
b[i]+=1
r = 0
for i in range(5):
r+= a[i]*b[4-i]
print(r)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,587,017,725 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 307,200 | tse = input().split()
st = input()
x, y = int(tse[1])- int(tse[3]), int(tse[2])-int(tse[4])
cx = 'E' if x > 0 else 'W'
cy = 'N' if y > 0 else 'S'
x, y = abs(x), abs(y)
cnt = 0
for test in st:
if test == cx:
x -= 1
elif test == cy:
y -= 1
if x<=0 and y<=0:
break
cnt += 1
i... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
tse = input().split()
st = input()
x, y = int(tse[1])- int(tse[3]), int(tse[2])-int(tse[4])
cx = 'E' if x > 0 else 'W'
cy = 'N' if y > 0 else 'S'
x, y = abs(x), abs(y)
cnt = 0
for test in st:
if test == cx:
x -= 1
elif test == cy:
y -= 1
if x<=0 and y<=0:
break
c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
794 | B | Cutting Carrot | PROGRAMMING | 1,200 | [
"geometry",
"math"
] | null | null | Igor the analyst has adopted *n* little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cut the carrot into *n* pieces of equal area.
Formally, the carrot can be viewed as an isosceles tri... | The first and only line of input contains two space-separated integers, *n* and *h* (2<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=105). | The output should contain *n*<=-<=1 real numbers *x*1,<=*x*2,<=...,<=*x**n*<=-<=1. The number *x**i* denotes that the *i*-th cut must be made *x**i* units away from the apex of the carrot. In addition, 0<=<<=*x*1<=<<=*x*2<=<<=...<=<<=*x**n*<=-<=1<=<<=*h* must hold.
Your output will be considered correc... | [
"3 2\n",
"2 100000\n"
] | [
"1.154700538379 1.632993161855\n",
"70710.678118654752\n"
] | Definition of isosceles triangle: [https://en.wikipedia.org/wiki/Isosceles_triangle](https://en.wikipedia.org/wiki/Isosceles_triangle). | 1,000 | [
{
"input": "3 2",
"output": "1.154700538379 1.632993161855"
},
{
"input": "2 100000",
"output": "70710.678118654752"
},
{
"input": "1000 100000",
"output": "3162.277660168379 4472.135954999579 5477.225575051661 6324.555320336759 7071.067811865475 7745.966692414834 8366.600265340755 8... | 1,494,669,604 | 1,504 | Python 3 | OK | TESTS | 31 | 62 | 102,400 | from math import sqrt
n, h = map(int, input().split())
for i in range(1, n):
print(sqrt(i/n)*h, end=' ')
print()
| Title: Cutting Carrot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor the analyst has adopted *n* little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cu... | ```python
from math import sqrt
n, h = map(int, input().split())
for i in range(1, n):
print(sqrt(i/n)*h, end=' ')
print()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
177 | A1 | Good Matrix Elements | PROGRAMMING | 800 | [
"implementation"
] | null | null | The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the main diagonal. - Elements of the secondary diagonal. - Elements of the "middle" row — the row which ha... | The first line of input data contains a single odd integer *n*. Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=100) separated by single spaces — the elements of the given matrix.
The input limitations for getting 30 points are:
- 1<=≤<=*n*<=≤<=5
The input limitations for getting 100 po... | Print a single integer — the sum of good matrix elements. | [
"3\n1 2 3\n4 5 6\n7 8 9\n",
"5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n"
] | [
"45\n",
"17\n"
] | In the first sample all matrix elements will be good. Good elements in the second sample are shown on the figure. | 30 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "45"
},
{
"input": "5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1",
"output": "17"
},
{
"input": "1\n3",
"output": "3"
},
{
"input": "5\n27 7 3 11 72\n19 49 68 19 59\n41 25 37 64 65\n8 39 96 62 90\n13 37 43 26 33",
... | 1,551,532,007 | 2,147,483,647 | Python 3 | OK | TESTS1 | 17 | 186 | 0 | x = int(input())
a = []
b = []
for i in range(x):
b.append(list(map(int, input().split(" "))))
c = b[x//2][x//2]
b[x//2][x//2] = 0
a = a + b[x//2]
for i in b:
a.append(i[x//2])
for i in range(x):
for j in range(x):
if i == j:
a.append(b[i][j])
else:
... | Title: Good Matrix Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the ... | ```python
x = int(input())
a = []
b = []
for i in range(x):
b.append(list(map(int, input().split(" "))))
c = b[x//2][x//2]
b[x//2][x//2] = 0
a = a + b[x//2]
for i in b:
a.append(i[x//2])
for i in range(x):
for j in range(x):
if i == j:
a.append(b[i][j])
el... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
416 | B | Art Union | PROGRAMMING | 1,300 | [
"brute force",
"dp",
"implementation"
] | null | null | A well-known art union called "Kalevich is Alive!" manufactures objects d'art (pictures). The union consists of *n* painters who decided to organize their work as follows.
Each painter uses only the color that was assigned to him. The colors are distinct for all painters. Let's assume that the first painter uses color... | The first line of the input contains integers *m*,<=*n* (1<=≤<=*m*<=≤<=50000,<=1<=≤<=*n*<=≤<=5), where *m* is the number of pictures and *n* is the number of painters. Then follow the descriptions of the pictures, one per line. Each line contains *n* integers *t**i*1,<=*t**i*2,<=...,<=*t**in* (1<=≤<=*t**ij*<=≤<=1000), ... | Print the sequence of *m* integers *r*1,<=*r*2,<=...,<=*r**m*, where *r**i* is the moment when the *n*-th painter stopped working on the *i*-th picture. | [
"5 1\n1\n2\n3\n4\n5\n",
"4 2\n2 5\n3 1\n5 3\n10 1\n"
] | [
"1 3 6 10 15 ",
"7 8 13 21 "
] | none | 1,000 | [
{
"input": "5 1\n1\n2\n3\n4\n5",
"output": "1 3 6 10 15 "
},
{
"input": "4 2\n2 5\n3 1\n5 3\n10 1",
"output": "7 8 13 21 "
},
{
"input": "1 1\n66",
"output": "66 "
},
{
"input": "2 2\n1 1\n1 1",
"output": "2 3 "
},
{
"input": "2 2\n10 1\n10 1",
"output": "11 2... | 1,423,111,984 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 686 | 13,824,000 |
m , n = map(int, input().split())
t = list()
for i in range(m):
t.append(list(map(int, input().split())))
for col in range(n):
for row in range(m):
left = 0 if col == 0 else t[row][col-1]
up = 0 if row == 0 else t[row-1][col]
start = max(left, up)
t[row][col] = start+t[row][col... | Title: Art Union
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A well-known art union called "Kalevich is Alive!" manufactures objects d'art (pictures). The union consists of *n* painters who decided to organize their work as follows.
Each painter uses only the color that was assigned t... | ```python
m , n = map(int, input().split())
t = list()
for i in range(m):
t.append(list(map(int, input().split())))
for col in range(n):
for row in range(m):
left = 0 if col == 0 else t[row][col-1]
up = 0 if row == 0 else t[row-1][col]
start = max(left, up)
t[row][col] = start+... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
940 | F | Machine Learning | PROGRAMMING | 2,600 | [
"brute force",
"data structures"
] | null | null | You come home and fell some unpleasant smell. Where is it coming from?
You are given an array *a*. You have to answer the following queries:
1. You are given two integers *l* and *r*. Let *c**i* be the number of occurrences of *i* in *a**l*:<=*r*, where *a**l*:<=*r* is the subarray of *a* from *l*-th element to *r*... | The first line of input contains two integers *n* and *q* (1<=≤<=*n*,<=*q*<=≤<=100<=000) — the length of the array and the number of queries respectively.
The second line of input contains *n* integers — *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109).
Each of the next *q* lines describes a single query.
The first ty... | For each query of the first type output a single integer — the Mex of {*c*0,<=*c*1,<=...,<=*c*109}. | [
"10 4\n1 2 3 1 1 2 2 2 9 9\n1 1 1\n1 2 8\n2 7 1\n1 2 8\n"
] | [
"2\n3\n2\n"
] | The subarray of the first query consists of the single element — 1.
The subarray of the second query consists of four 2s, one 3 and two 1s.
The subarray of the fourth query consists of three 1s, three 2s and one 3. | 2,750 | [
{
"input": "10 4\n1 2 3 1 1 2 2 2 9 9\n1 1 1\n1 2 8\n2 7 1\n1 2 8",
"output": "2\n3\n2"
}
] | 1,693,178,710 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1693178709.92125")# 1693178709.9212663 | Title: Machine Learning
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You come home and fell some unpleasant smell. Where is it coming from?
You are given an array *a*. You have to answer the following queries:
1. You are given two integers *l* and *r*. Let *c**i* be the number of oc... | ```python
print("_RANDOM_GUESS_1693178709.92125")# 1693178709.9212663
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,592,519,302 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 278 | 0 | n = int(input())
arr = list(map(int, input().split()))
mx = 1
for i in range(1, n):
count = 1
l = i - 1
r = i+1
print(i, l, r)
while l - 1 >= -1 and arr[l] <= arr[l+1]:
count += 1
print('left', l)
l -= 1
while r + 1 < n and arr[r] <= arr[... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
n = int(input())
arr = list(map(int, input().split()))
mx = 1
for i in range(1, n):
count = 1
l = i - 1
r = i+1
print(i, l, r)
while l - 1 >= -1 and arr[l] <= arr[l+1]:
count += 1
print('left', l)
l -= 1
while r + 1 < n and arr[... | 0 | MatrixStudio/Codeforces-Python-Submissions |
756 | B | Travel Card | PROGRAMMING | 1,600 | [
"binary search",
"dp"
] | null | null | A new innovative ticketing systems for public transport is introduced in Bytesburg. Now there is a single travel card for all transport. To make a trip a passenger scan his card and then he is charged according to the fare.
The fare is constructed in the following manner. There are three types of tickets:
1. a tick... | The first line of input contains integer number *n* (1<=≤<=*n*<=≤<=105) — the number of trips made by passenger.
Each of the following *n* lines contains the time of trip *t**i* (0<=≤<=*t**i*<=≤<=109), measured in minutes from the time of starting the system. All *t**i* are different, given in ascending order, i. e. *... | Output *n* integers. For each trip, print the sum the passenger is charged after it. | [
"3\n10\n20\n30\n",
"10\n13\n45\n46\n60\n103\n115\n126\n150\n256\n516\n"
] | [
"20\n20\n10\n",
"20\n20\n10\n0\n20\n0\n0\n20\n20\n10\n"
] | In the first example, the system works as follows: for the first and second trips it is cheaper to pay for two one-trip tickets, so each time 20 rubles is charged, after the third trip the system understands that it would be cheaper to buy a ticket for 90 minutes. This ticket costs 50 rubles, and the passenger had alre... | 1,000 | [
{
"input": "3\n10\n20\n30",
"output": "20\n20\n10"
},
{
"input": "10\n13\n45\n46\n60\n103\n115\n126\n150\n256\n516",
"output": "20\n20\n10\n0\n20\n0\n0\n20\n20\n10"
},
{
"input": "7\n100\n138\n279\n308\n396\n412\n821",
"output": "20\n20\n20\n20\n20\n20\n0"
},
{
"input": "8\n0... | 1,601,109,007 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 436 | 12,390,400 | from bisect import bisect_left as bl
from bisect import bisect_right as br
from heapq import heappush,heappop,heapify
import math
from collections import *
from functools import reduce,cmp_to_key
import sys
input = sys.stdin.readline
from itertools import accumulate
from functools import lru_cache
M = mod = 998244353... | Title: Travel Card
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A new innovative ticketing systems for public transport is introduced in Bytesburg. Now there is a single travel card for all transport. To make a trip a passenger scan his card and then he is charged according to the fare.... | ```python
from bisect import bisect_left as bl
from bisect import bisect_right as br
from heapq import heappush,heappop,heapify
import math
from collections import *
from functools import reduce,cmp_to_key
import sys
input = sys.stdin.readline
from itertools import accumulate
from functools import lru_cache
M = mod =... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
280 | A | Rectangle Puzzle | PROGRAMMING | 2,000 | [
"geometry"
] | null | null | You are given two rectangles on a plane. The centers of both rectangles are located in the origin of coordinates (meaning the center of the rectangle's symmetry). The first rectangle's sides are parallel to the coordinate axes: the length of the side that is parallel to the *Ox* axis, equals *w*, the length of the side... | The first line contains three integers *w*,<=*h*,<=α (1<=≤<=*w*,<=*h*<=≤<=106; 0<=≤<=α<=≤<=180). Angle α is given in degrees. | In a single line print a real number — the area of the region which belongs to both given rectangles.
The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=6. | [
"1 1 45\n",
"6 4 30\n"
] | [
"0.828427125\n",
"19.668384925\n"
] | The second sample has been drawn on the picture above. | 500 | [
{
"input": "1 1 45",
"output": "0.828427125"
},
{
"input": "6 4 30",
"output": "19.668384925"
},
{
"input": "100 100 0",
"output": "10000.000000000"
},
{
"input": "100 100 30",
"output": "8452.994616207"
},
{
"input": "303304 904227 3",
"output": "262706079399... | 1,585,693,534 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 248 | 0 | from math import *
from sys import stdin, stdout
io = stdin.readline().split()
w = float(io[0])
h = float(io[1])
a = float(io[2])
if (a > 90): a = 180 - a
if (a == 0) :
print(w * h)
else :
a = a * pi / 180.0
corner_x = cos(a) * (w / 2.0) + sin(a) * (h / 2.0)
if (corner_x >= w / 2 ) :
x0 = w... | Title: Rectangle Puzzle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two rectangles on a plane. The centers of both rectangles are located in the origin of coordinates (meaning the center of the rectangle's symmetry). The first rectangle's sides are parallel to the coordin... | ```python
from math import *
from sys import stdin, stdout
io = stdin.readline().split()
w = float(io[0])
h = float(io[1])
a = float(io[2])
if (a > 90): a = 180 - a
if (a == 0) :
print(w * h)
else :
a = a * pi / 180.0
corner_x = cos(a) * (w / 2.0) + sin(a) * (h / 2.0)
if (corner_x >= w / 2 ) :
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,677,498,382 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int main() {
int a, b; cin >> a >> b;
int prob = 6 - max(a, b) + 1;
if(prob == 1) cout << "1/6";
else if(prob == 2) cout << "1/3";
else if(prob == 3) cout << "1/2";
else if(prob == 4) cout << "2/3";
else if(prob == 5) cout << "5/6";
... | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
#include <bits/stdc++.h>
using namespace std;
int main() {
int a, b; cin >> a >> b;
int prob = 6 - max(a, b) + 1;
if(prob == 1) cout << "1/6";
else if(prob == 2) cout << "1/3";
else if(prob == 3) cout << "1/2";
else if(prob == 4) cout << "2/3";
else if(prob == 5) cout <<... | -1 | MatrixStudio/Codeforces-Python-Submissions |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,543,919,392 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 0 | def f(x):
x = str(x)
if "8" in x: return 1
else: return 0
k = int(input())
n = k
while not f(n+1):
n += 1
print(n-k+1) | Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
def f(x):
x = str(x)
if "8" in x: return 1
else: return 0
k = int(input())
n = k
while not f(n+1):
n += 1
print(n-k+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,661,190,292 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 92 | 0 | n=int(input())
a=list(map(int,input().split()))
val=sum(a)
cnt=0
for i in range(1,6):
if (val+i)%(n+1)==1:
cnt+=1
print(5-cnt) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n=int(input())
a=list(map(int,input().split()))
val=sum(a)
cnt=0
for i in range(1,6):
if (val+i)%(n+1)==1:
cnt+=1
print(5-cnt)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,638,992,079 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | if __name__ == '__main__':
m, n = input().split()
print(divmod(int(m) * int(n), 2)[0])
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
if __name__ == '__main__':
m, n = input().split()
print(divmod(int(m) * int(n), 2)[0])
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,677,898,889 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 62 | 0 | def solve():
shovel_cost , coins = map(int,input().split())
for i in range(1,10):
rem = (i * shovel_cost) % 10
if rem == coins or rem == 0 :
print(i)
break
solve() | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
def solve():
shovel_cost , coins = map(int,input().split())
for i in range(1,10):
rem = (i * shovel_cost) % 10
if rem == coins or rem == 0 :
print(i)
break
solve()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
825 | A | Binary Protocol | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Polycarp has just invented a new binary protocol for data transmission. He is encoding positive integer decimal number to binary string using following algorithm:
- Each digit is represented with number of '1' characters equal to the value of that digit (for 0 it is zero ones). - Digits are written one by one in ord... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=89) — length of the string *s*.
The second line contains string *s* — sequence of '0' and '1' characters, number in its encoded format. It is guaranteed that the number corresponding to the string is positive and doesn't exceed 109. The string always starts... | Print the decoded number. | [
"3\n111\n",
"9\n110011101\n"
] | [
"3\n",
"2031\n"
] | none | 0 | [
{
"input": "3\n111",
"output": "3"
},
{
"input": "9\n110011101",
"output": "2031"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "3\n100",
"output": "100"
},
{
"input": "5\n10001",
"output": "1001"
},
{
"input": "14\n11001100011000",
"output": "... | 1,500,234,811 | 2,147,483,647 | Python 3 | OK | TESTS | 13 | 61 | 4,608,000 | import sys
input()
s = input().split('0')
def main(argv):
ans = 0
for c in s:
# print('print do tamanho de ' + s + str(len(s)))
ans *= 10
ans += len(c)
print(ans)
if __name__ == "__main__":
main(sys.argv)
| Title: Binary Protocol
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has just invented a new binary protocol for data transmission. He is encoding positive integer decimal number to binary string using following algorithm:
- Each digit is represented with number of '1' charact... | ```python
import sys
input()
s = input().split('0')
def main(argv):
ans = 0
for c in s:
# print('print do tamanho de ' + s + str(len(s)))
ans *= 10
ans += len(c)
print(ans)
if __name__ == "__main__":
main(sys.argv)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,486,104,042 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 61 | 4,608,000 | n, m, z = map(int, input().split())
if n == m:
print(z // n)
else:
kol = 0
for i in range(1, z+1):
if not i % n and not i % m:
kol += 1
print(kol) | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
n, m, z = map(int, input().split())
if n == m:
print(z // n)
else:
kol = 0
for i in range(1, z+1):
if not i % n and not i % m:
kol += 1
print(kol)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
306 | A | Candies | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most equal) manner. He wants to choose such *a**i*, where *a**i* is the number of candies in the *... | The single line of the input contains a pair of space-separated positive integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100;*n*<=≥<=*m*) — the number of candies and the number of Polycarpus's friends. | Print the required sequence *a*1,<=*a*2,<=...,<=*a**m*, where *a**i* is the number of candies in the *i*-th friend's present. All numbers *a**i* must be positive integers, total up to *n*, the maximum one should differ from the minimum one by the smallest possible value. | [
"12 3\n",
"15 4\n",
"18 7\n"
] | [
"4 4 4 ",
"3 4 4 4 ",
"2 2 2 3 3 3 3 "
] | Print *a*<sub class="lower-index">*i*</sub> in any order, separate the numbers by spaces. | 500 | [
{
"input": "12 4",
"output": "3 3 3 3 "
},
{
"input": "15 6",
"output": "2 2 2 3 3 3 "
},
{
"input": "18 8",
"output": "2 2 2 2 2 2 3 3 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "2 1",
"output": "2 "
},
{
"input": "100 1",
"output": "100 ... | 1,588,182,217 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 218 | 0 | n,m = map(int, input().split())
if n%m==0:
n //= m
s = str(n) + ' '
print(s*m)
else:
t = n%m
n //= m
s = ''
for i in range(t):
s += str(n+1) + ' '
for i in range(m-t):
s += str(n) + ' '
print(s) | Title: Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most ... | ```python
n,m = map(int, input().split())
if n%m==0:
n //= m
s = str(n) + ' '
print(s*m)
else:
t = n%m
n //= m
s = ''
for i in range(t):
s += str(n+1) + ' '
for i in range(m-t):
s += str(n) + ' '
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,616,849,753 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 0 | # -*- coding: utf-8 -*-
"""
Created on Sat Mar 27 20:52:17 2021
@author: nagan
"""
s = input()
c = 0
x = True
ans = ""
while x == True:
if c < len(s):
if s[c] == ".":
ans += "0"
c += 1
elif s[c] == "-":
if s[c + 1] == ".":
ans +... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
# -*- coding: utf-8 -*-
"""
Created on Sat Mar 27 20:52:17 2021
@author: nagan
"""
s = input()
c = 0
x = True
ans = ""
while x == True:
if c < len(s):
if s[c] == ".":
ans += "0"
c += 1
elif s[c] == "-":
if s[c + 1] == ".":
... | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,619,197,373 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 186 | 0 | d = {}
n = int(input())
for _ in range(n):
s = input()
if not s in d: d[s] = 0
d[s] += 1
mv = -1
mi = ''
for i in d:
if d[i] > mv:
mi, mv = i, d[i]
print(mi) | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
d = {}
n = int(input())
for _ in range(n):
s = input()
if not s in d: d[s] = 0
d[s] += 1
mv = -1
mi = ''
for i in d:
if d[i] > mv:
mi, mv = i, d[i]
print(mi)
``` | 3.9535 | MatrixStudio/Codeforces-Python-Submissions |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,691,841,720 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n,k = list(map(int,input().split()))
counter = 0
for i in range(n):
num = input()
if len(set(num)) == k+1 and int(max(list(num),key=int)) == k:
counter += 1
print(counter) | Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number eve... | ```python
n,k = list(map(int,input().split()))
counter = 0
for i in range(n):
num = input()
if len(set(num)) == k+1 and int(max(list(num),key=int)) == k:
counter += 1
print(counter)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,640,316,476 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | t = input() + ' '
nums = []
m = {
'.': 0,
'-.': 1,
'--': 2
}
if len(t) == 1:
nums.append(0)
else:
i = 0
while i < len(t) - 1:
if t[i] + t[i + 1] in m:
nums.append(str(m[t[i] + t[i + 1]]))
i += 2
else:
nums.append(str(m[t[i]]))
i += ... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
t = input() + ' '
nums = []
m = {
'.': 0,
'-.': 1,
'--': 2
}
if len(t) == 1:
nums.append(0)
else:
i = 0
while i < len(t) - 1:
if t[i] + t[i + 1] in m:
nums.append(str(m[t[i] + t[i + 1]]))
i += 2
else:
nums.append(str(m[t[i]]))
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
651 | B | Beautiful Paintings | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | There are *n* pictures delivered for the new exhibition. The *i*-th painting has beauty *a**i*. We know that a visitor becomes happy every time he passes from a painting to a more beautiful one.
We are allowed to arranged pictures in any order. What is the maximum possible number of times the visitor may become happy ... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of painting.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where *a**i* means the beauty of the *i*-th painting. | Print one integer — the maximum possible number of neighbouring pairs, such that *a**i*<=+<=1<=><=*a**i*, after the optimal rearrangement. | [
"5\n20 30 10 50 40\n",
"4\n200 100 100 200\n"
] | [
"4\n",
"2\n"
] | In the first sample, the optimal order is: 10, 20, 30, 40, 50.
In the second sample, the optimal order is: 100, 200, 100, 200. | 1,000 | [
{
"input": "5\n20 30 10 50 40",
"output": "4"
},
{
"input": "4\n200 100 100 200",
"output": "2"
},
{
"input": "10\n2 2 2 2 2 2 2 2 2 2",
"output": "0"
},
{
"input": "1\n1000",
"output": "0"
},
{
"input": "2\n444 333",
"output": "1"
},
{
"input": "100\n... | 1,561,991,047 | 3,847 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 124 | 1,126,400 | n = int(input())
a = list(map(int,input().split()))
a = sorted(a)
l = len(a)
ans =0
for i in range(0,l-1):
if a[i]!=-1:
for j in range(i+1,l):
if a[i]<a[j]:
ans+=1
a[j]=-1
print(ans)
| Title: Beautiful Paintings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* pictures delivered for the new exhibition. The *i*-th painting has beauty *a**i*. We know that a visitor becomes happy every time he passes from a painting to a more beautiful one.
We are allowed to a... | ```python
n = int(input())
a = list(map(int,input().split()))
a = sorted(a)
l = len(a)
ans =0
for i in range(0,l-1):
if a[i]!=-1:
for j in range(i+1,l):
if a[i]<a[j]:
ans+=1
a[j]=-1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,698,766,721 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n=int(input())
l=[4,7,44,77,474,747,777,444,447,774];
lucky=False
for i in l:
if(n%i==0):
lucky=True
break
if lucky:
print("Yes")
else:
print("No"); | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n=int(input())
l=[4,7,44,77,474,747,777,444,447,774];
lucky=False
for i in l:
if(n%i==0):
lucky=True
break
if lucky:
print("Yes")
else:
print("No");
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,686,824,110 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 60 | 0 | n=input()
c=0
s='HQ9+'
for i in n:
if i in s:
c=1
break
if c:
print('YES')
else:
print('NO') | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
n=input()
c=0
s='HQ9+'
for i in n:
if i in s:
c=1
break
if c:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,687,837,888 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | l=list(map(int,input().split())
if((len(set(l)))==len(l)):
print("0")
else:
print((len(l))-len(set(l))) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
l=list(map(int,input().split())
if((len(set(l)))==len(l)):
print("0")
else:
print((len(l))-len(set(l)))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
748 | C | Santa Claus and Robot | PROGRAMMING | 1,400 | [
"constructive algorithms",
"math"
] | null | null | Santa Claus has Robot which lives on the infinite grid and can move along its lines. He can also, having a sequence of *m* points *p*1,<=*p*2,<=...,<=*p**m* with integer coordinates, do the following: denote its initial location by *p*0. First, the robot will move from *p*0 to *p*1 along one of the shortest paths betwe... | The first line of input contains the only positive integer *n* (1<=≤<=*n*<=≤<=2·105) which equals the number of unit segments the robot traveled. The second line contains the movements protocol, which consists of *n* letters, each being equal either L, or R, or U, or D. *k*-th letter stands for the direction which Robo... | The only line of input should contain the minimum possible length of the sequence. | [
"4\nRURD\n",
"6\nRRULDD\n",
"26\nRRRULURURUULULLLDLDDRDRDLD\n",
"3\nRLL\n",
"4\nLRLR\n"
] | [
"2\n",
"2\n",
"7\n",
"2\n",
"4\n"
] | The illustrations to the first three tests are given below.
<img class="tex-graphics" src="https://espresso.codeforces.com/832fb8f97a482be815e0f87edde26c9791a0d330.png" style="max-width: 100.0%;max-height: 100.0%;"/> <img class="tex-graphics" src="https://espresso.codeforces.com/119a8ba68772b2c2bf76f2acdc58027f6c5cde1... | 1,500 | [
{
"input": "4\nRURD",
"output": "2"
},
{
"input": "6\nRRULDD",
"output": "2"
},
{
"input": "26\nRRRULURURUULULLLDLDDRDRDLD",
"output": "7"
},
{
"input": "3\nRLL",
"output": "2"
},
{
"input": "4\nLRLR",
"output": "4"
},
{
"input": "5\nLRDLR",
"outpu... | 1,482,684,575 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 4,608,000 | #N = int(input())
protokol = input().lower()
protokol = list(protokol)
#protokol.append(protokol[len(protokol)-1])
print(protokol)
t_pr = []
k = 0
for i in range(len(protokol)):
if not protokol[i] in t_pr and (len(t_pr) != 2):
t_pr.append(protokol[i])
if len(t_pr) == 2 and ((t_pr[0] == 'r'... | Title: Santa Claus and Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has Robot which lives on the infinite grid and can move along its lines. He can also, having a sequence of *m* points *p*1,<=*p*2,<=...,<=*p**m* with integer coordinates, do the following: denote its i... | ```python
#N = int(input())
protokol = input().lower()
protokol = list(protokol)
#protokol.append(protokol[len(protokol)-1])
print(protokol)
t_pr = []
k = 0
for i in range(len(protokol)):
if not protokol[i] in t_pr and (len(t_pr) != 2):
t_pr.append(protokol[i])
if len(t_pr) == 2 and ((t_pr... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
868 | B | Race Against Time | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Have you ever tried to explain to the coordinator, why it is eight hours to the contest and not a single problem has been prepared yet? Misha had. And this time he has a really strong excuse: he faced a space-time paradox! Space and time replaced each other.
The entire universe turned into an enormous clock face with ... | Five integers *h*, *m*, *s*, *t*1, *t*2 (1<=≤<=*h*<=≤<=12, 0<=≤<=*m*,<=*s*<=≤<=59, 1<=≤<=*t*1,<=*t*2<=≤<=12, *t*1<=≠<=*t*2).
Misha's position and the target time do not coincide with the position of any hand. | Print "YES" (quotes for clarity), if Misha can prepare the contest on time, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"12 30 45 3 11\n",
"12 0 1 12 1\n",
"3 47 0 4 9\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | The three examples are shown on the pictures below from left to right. The starting position of Misha is shown with green, the ending position is shown with pink. Note that the positions of the hands on the pictures are not exact, but are close to the exact and the answer is the same. | 500 | [
{
"input": "12 30 45 3 11",
"output": "NO"
},
{
"input": "12 0 1 12 1",
"output": "YES"
},
{
"input": "3 47 0 4 9",
"output": "YES"
},
{
"input": "10 22 59 6 10",
"output": "YES"
},
{
"input": "3 1 13 12 3",
"output": "NO"
},
{
"input": "11 19 28 9 10"... | 1,509,016,313 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <stdio.h>
void swap(double * t1, double * t2)
{
if (*t1 > *t2)
{
double temp = *t1;
*t1 = *t2;
*t2 = temp;
}
return;
}
int main(void)
{
int h, m, s, t1, t2, f = 0;
double posh, posm, poss, post1, post2;
scanf("%d %d %d %d %d", &h, &m, &s, &t1, &t2);
h = h % 12;
t1 = t1 % 12;... | Title: Race Against Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Have you ever tried to explain to the coordinator, why it is eight hours to the contest and not a single problem has been prepared yet? Misha had. And this time he has a really strong excuse: he faced a space-time par... | ```python
#include <stdio.h>
void swap(double * t1, double * t2)
{
if (*t1 > *t2)
{
double temp = *t1;
*t1 = *t2;
*t2 = temp;
}
return;
}
int main(void)
{
int h, m, s, t1, t2, f = 0;
double posh, posm, poss, post1, post2;
scanf("%d %d %d %d %d", &h, &m, &s, &t1, &t2);
h = h % 12;
t1 ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
616 | A | Comparing Two Long Integers | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can r... | The first line contains a non-negative integer *a*.
The second line contains a non-negative integer *b*.
The numbers *a*,<=*b* may contain leading zeroes. Each of them contains no more than 106 digits. | Print the symbol "<" if *a*<=<<=*b* and the symbol ">" if *a*<=><=*b*. If the numbers are equal print the symbol "=". | [
"9\n10\n",
"11\n10\n",
"00012345\n12345\n",
"0123\n9\n",
"0123\n111\n"
] | [
"<\n",
">\n",
"=\n",
">\n",
">\n"
] | none | 0 | [
{
"input": "9\n10",
"output": "<"
},
{
"input": "11\n10",
"output": ">"
},
{
"input": "00012345\n12345",
"output": "="
},
{
"input": "0123\n9",
"output": ">"
},
{
"input": "0123\n111",
"output": ">"
},
{
"input": "9\n9",
"output": "="
},
{
... | 1,674,312,529 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 2,000 | 3,584,000 | num= input()
num1= input()
if int(num)>int(num1):
print(">")
elif int(num)==int(num1):
print("=")
elif int(num)<int(num1):
print("<")
| Title: Comparing Two Long Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use th... | ```python
num= input()
num1= input()
if int(num)>int(num1):
print(">")
elif int(num)==int(num1):
print("=")
elif int(num)<int(num1):
print("<")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,689,326,265 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 9,728,000 | n, t = [int(j) for j in input().split()]
s = [int(j) for j in input().split()]
m = 0
for i in range(n):
summa = 0
count = 0
j = i
while True:
summa+=s[j]
if summa>t:
break
count+=1
j+=1
if j>(n-1):
break
if count>m:
... | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
n, t = [int(j) for j in input().split()]
s = [int(j) for j in input().split()]
m = 0
for i in range(n):
summa = 0
count = 0
j = i
while True:
summa+=s[j]
if summa>t:
break
count+=1
j+=1
if j>(n-1):
break
if coun... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,610,927,951 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 216 | 0 | n,m=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
ans=0
for i in range(m):
ans+=min(0,a[i])
print(-ans)
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
ans=0
for i in range(m):
ans+=min(0,a[i])
print(-ans)
``` | 3.946 | MatrixStudio/Codeforces-Python-Submissions |
656 | B | Scrambled | PROGRAMMING | 1,700 | [
"*special",
"implementation"
] | null | null | Btoh yuo adn yuor roomatme lhoate wianshg disehs, btu stlil sdmoeboy msut peorrfm tihs cohre dialy. Oen dya yuo decdie to idourtcne smoe syestm. Yuor rmmotaoe sstgegus teh fooniwllg dael. Yuo argee on tow arayrs of ientgres M adn R, nmebur upmicnog dyas (induiclng teh cunrret oen) wtih sicsescuve irnegets (teh ceurrnt ... | The first line of input contains a single integer N (1<=≤<=*N*<=≤<=16).
The second and third lines of input contain N integers each, all between 0 and 16, inclusive, and represent arrays M and R, respectively. All *M*[*i*] are positive, for each *i* *R*[*i*]<=<<=*M*[*i*]. | Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10<=-<=4. | [
"1\n2\n0\n",
"2\n2 3\n1 0\n"
] | [
"0.500000\n",
"0.666667\n"
] | none | 0 | [
{
"input": "1\n2\n0",
"output": "0.500000"
},
{
"input": "2\n2 3\n1 0",
"output": "0.666667"
},
{
"input": "3\n2 4 4\n0 1 3",
"output": "1.000000"
},
{
"input": "1\n16\n15",
"output": "0.062500"
},
{
"input": "16\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16\n0 1 2 3 4 ... | 1,489,512,002 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 4,608,000 | n = int(input())
m = list(map(int, input().split()))
r = list(map(int, input().split()))
maxM = max(m)
count = 0
for i in range(0, maxM):
found = False
for j in range(0,len(m)):
if(i % m[j] is r[j]):
found = True
if(found):
count += 1
percent = round(count / maxM, 3)
if(per... | Title: Scrambled
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Btoh yuo adn yuor roomatme lhoate wianshg disehs, btu stlil sdmoeboy msut peorrfm tihs cohre dialy. Oen dya yuo decdie to idourtcne smoe syestm. Yuor rmmotaoe sstgegus teh fooniwllg dael. Yuo argee on tow arayrs of ientgres M... | ```python
n = int(input())
m = list(map(int, input().split()))
r = list(map(int, input().split()))
maxM = max(m)
count = 0
for i in range(0, maxM):
found = False
for j in range(0,len(m)):
if(i % m[j] is r[j]):
found = True
if(found):
count += 1
percent = round(count / maxM,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,574,775,530 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | word = input()
count = 0
for a in 'holle':
if a in word:
b = word.find(a)
word = word[b:]
count += 1
if count >= 5:
print('YES')
else:
print('NO') | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
word = input()
count = 0
for a in 'holle':
if a in word:
b = word.find(a)
word = word[b:]
count += 1
if count >= 5:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,694,783,525 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | import math
x = input("")
x = int(x)
if x > 5:
y = math.ceil(x / 5)
else:
y = 1
print(y) | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
import math
x = input("")
x = int(x)
if x > 5:
y = math.ceil(x / 5)
else:
y = 1
print(y)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Nikita has a stack. A stack in this problem is a data structure that supports two operations. Operation push(x) puts an integer *x* on the top of the stack, and operation pop() deletes the top integer from the stack, i. e. the last added. If the stack is empty, then the operation pop() does nothing.
Nikita made *m* op... | The first line contains the integer *m* (1<=≤<=*m*<=≤<=105) — the number of operations Nikita made.
The next *m* lines contain the operations Nikita remembers. The *i*-th line starts with two integers *p**i* and *t**i* (1<=≤<=*p**i*<=≤<=*m*, *t**i*<==<=0 or *t**i*<==<=1) — the index of operation he remembers on the st... | Print *m* integers. The integer *i* should equal the number on the top of the stack after performing all the operations Nikita remembered on the steps from 1 to *i*. If the stack is empty after performing all these operations, print -1. | [
"2\n2 1 2\n1 0\n",
"3\n1 1 2\n2 1 3\n3 0\n",
"5\n5 0\n4 0\n3 1 1\n2 1 1\n1 1 2\n"
] | [
"2\n2\n",
"2\n3\n2\n",
"-1\n-1\n-1\n-1\n2\n"
] | In the first example, after Nikita remembers the operation on the first step, the operation push(2) is the only operation, so the answer is 2. After he remembers the operation pop() which was done before push(2), answer stays the same.
In the second example, the operations are push(2), push(3) and pop(). Nikita rememb... | 0 | [] | 1,691,215,684 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1691215684.8674812")# 1691215684.8674994 | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikita has a stack. A stack in this problem is a data structure that supports two operations. Operation push(x) puts an integer *x* on the top of the stack, and operation pop() deletes the top integer from the stack, i. e. the las... | ```python
print("_RANDOM_GUESS_1691215684.8674812")# 1691215684.8674994
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,612,421,757 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 204,800 | points = int(input())
cords = []
for i in range(points):
cords.append( [x for x in input().split()])
count = 0
for x, y in cords:
flag = []
## print(x, y)
for i, j in cords:
## print(i, j)
if (x > i and y == j) and ('r' not in flag):
flag.append('r')
... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
points = int(input())
cords = []
for i in range(points):
cords.append( [x for x in input().split()])
count = 0
for x, y in cords:
flag = []
## print(x, y)
for i, j in cords:
## print(i, j)
if (x > i and y == j) and ('r' not in flag):
flag.append('... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
765 | C | Table Tennis Game 2 | PROGRAMMING | 1,200 | [
"math"
] | null | null | Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scores exactly *k* points, the score is reset and a new set begins.
Across all the sets Misha scored *a* poi... | The first line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=109, 0<=≤<=*a*,<=*b*<=≤<=109, *a*<=+<=*b*<=><=0). | If the situation is impossible, print a single number -1. Otherwise, print the maximum possible number of sets. | [
"11 11 5\n",
"11 2 3\n"
] | [
"1\n",
"-1\n"
] | Note that the rules of the game in this problem differ from the real table tennis game, for example, the rule of "balance" (the winning player has to be at least two points ahead to win a set) has no power within the present problem. | 1,250 | [
{
"input": "11 11 5",
"output": "1"
},
{
"input": "11 2 3",
"output": "-1"
},
{
"input": "1 5 9",
"output": "14"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "1 1000000000 1000000000",
"output": "2000000000"
},
{
"input": "2 3 5",
"output": "... | 1,494,239,216 | 1,436 | Python 3 | OK | TESTS | 279 | 62 | 0 | k, a, b = [int(i) for i in input().split()]
resa = a // k
resb = b // k
osta = a % k
ostb = b % k
res = resa + resb
if (res == 0) or (resa == 0 and ostb != 0) or (resb == 0 and osta != 0):
print(-1)
else:
print(res)
| Title: Table Tennis Game 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scor... | ```python
k, a, b = [int(i) for i in input().split()]
resa = a // k
resb = b // k
osta = a % k
ostb = b % k
res = resa + resb
if (res == 0) or (resa == 0 and ostb != 0) or (resb == 0 and osta != 0):
print(-1)
else:
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
628 | B | New Skateboard | PROGRAMMING | 1,300 | [
"dp"
] | null | null | Max wants to buy a new skateboard. He has calculated the amount of money that is needed to buy a new skateboard. He left a calculator on the floor and went to ask some money from his parents. Meanwhile his little brother Yusuf came and started to press the keys randomly. Unfortunately Max has forgotten the number which... | The only line contains string *s* (1<=≤<=|*s*|<=≤<=3·105). The string *s* contains only digits from 0 to 9. | Print integer *a* — the number of substrings of the string *s* that are divisible by 4.
Note that the answer can be huge, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | [
"124\n",
"04\n",
"5810438174\n"
] | [
"4\n",
"3\n",
"9\n"
] | none | 0 | [
{
"input": "124",
"output": "4"
},
{
"input": "04",
"output": "3"
},
{
"input": "5810438174",
"output": "9"
},
{
"input": "1",
"output": "0"
},
{
"input": "039",
"output": "1"
},
{
"input": "97247",
"output": "6"
},
{
"input": "5810438174",... | 1,697,484,355 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 22 | 77 | 2,867,200 | s = input()
ans = 0
for i in range(len(s)):
if s[i] == '0' or s[i] == '4' or s[i] == '8':
ans += 1
if i > 0 and int(s[i-1:i+1]) % 4 == 0:
ans += i
print(ans) | Title: New Skateboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Max wants to buy a new skateboard. He has calculated the amount of money that is needed to buy a new skateboard. He left a calculator on the floor and went to ask some money from his parents. Meanwhile his little brother... | ```python
s = input()
ans = 0
for i in range(len(s)):
if s[i] == '0' or s[i] == '4' or s[i] == '8':
ans += 1
if i > 0 and int(s[i-1:i+1]) % 4 == 0:
ans += i
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
376 | A | Lever | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar is a segment on the *Ox* axis between points 0 and |*s*|<=-<=1.
The decoding of the lever d... | The first line contains the lever description as a non-empty string *s* (3<=≤<=|*s*|<=≤<=106), consisting of digits (1-9) and characters "^" and "=". It is guaranteed that the line contains exactly one character "^". It is guaranteed that the pivot of the lever isn't located in any end of the lever bar.
To solve the p... | Print "left" if the given lever tilts to the left, "right" if it tilts to the right and "balance", if it is in balance. | [
"=^==\n",
"9===^==1\n",
"2==^7==\n",
"41^52==\n"
] | [
"balance\n",
"left\n",
"right\n",
"balance\n"
] | As you solve the problem, you may find the following link useful to better understand how a lever functions: http://en.wikipedia.org/wiki/Lever.
The pictures to the examples: | 500 | [
{
"input": "=^==",
"output": "balance"
},
{
"input": "9===^==1",
"output": "left"
},
{
"input": "2==^7==",
"output": "right"
},
{
"input": "41^52==",
"output": "balance"
},
{
"input": "=^2=4=1===1=",
"output": "right"
},
{
"input": "9=6===5==3=9=1=1^7=... | 1,640,590,864 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 436 | 6,144,000 | lever=list(input())
pivot=lever.index("^")
left,right=0,0
for i in range(len(lever)):
if i<pivot and lever[i]!="=":left+=int(lever[i])*(pivot-i)
elif i>pivot and lever[i]!="=":right+=int(lever[i])*(i-pivot)
if left<right:print("right")
elif right<left:print("left")
else:print("balance") | Title: Lever
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar i... | ```python
lever=list(input())
pivot=lever.index("^")
left,right=0,0
for i in range(len(lever)):
if i<pivot and lever[i]!="=":left+=int(lever[i])*(pivot-i)
elif i>pivot and lever[i]!="=":right+=int(lever[i])*(i-pivot)
if left<right:print("right")
elif right<left:print("left")
else:print("balance")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
797 | B | Odd sum | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains subsequence with odd sum.
Subsequence is a sequence that can be derived from another sequen... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=104<=≤<=*a**i*<=≤<=104). The sequence contains at least one subsequence with odd sum. | Print sum of resulting subseqeuence. | [
"4\n-2 2 -3 1\n",
"3\n2 -5 -3\n"
] | [
"3\n",
"-1\n"
] | In the first example sum of the second and the fourth elements is 3. | 0 | [
{
"input": "4\n-2 2 -3 1",
"output": "3"
},
{
"input": "3\n2 -5 -3",
"output": "-1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "1\n-1",
"output": "-1"
},
{
"input": "15\n-6004 4882 9052 413 6056 4306 9946 -4616 -6135 906 -1718 5252 -2866 9061 4046",
"ou... | 1,686,746,125 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | t = int(input())
for i in range(t):
n = int(input())
cnt = 0
for j in range(2 * n):
x = int(input())
cnt += x % 2
print("Yes" if cnt == n else "No")
| Title: Odd sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains... | ```python
t = int(input())
for i in range(t):
n = int(input())
cnt = 0
for j in range(2 * n):
x = int(input())
cnt += x % 2
print("Yes" if cnt == n else "No")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
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