contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
864 | B | Polycarp and Letters | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if following conditions are met:
- letters on positions from *A* in the string are all distinct and lowerc... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=200) — length of string *s*.
The second line contains a string *s* consisting of lowercase and uppercase Latin letters. | Print maximum number of elements in pretty set of positions for string *s*. | [
"11\naaaaBaabAbA\n",
"12\nzACaAbbaazzC\n",
"3\nABC\n"
] | [
"2\n",
"3\n",
"0\n"
] | In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6 and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1 and 8 is not suitable because there is an uppercase letter 'B' between these position.
In the second example desired positions can be 7, 8 and 11. There... | 1,000 | [
{
"input": "11\naaaaBaabAbA",
"output": "2"
},
{
"input": "12\nzACaAbbaazzC",
"output": "3"
},
{
"input": "3\nABC",
"output": "0"
},
{
"input": "1\na",
"output": "1"
},
{
"input": "2\naz",
"output": "2"
},
{
"input": "200\nXbTJZqcbpYuZQEoUrbxlPXAPCtVLr... | 1,522,005,358 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 93 | 7,065,600 | ans = 0
combo = set()
pre = -1
input()
for c in input():
if c.isupper():
ans = max(ans, len(combo))
combo = set()
pre = -1
elif c != pre:
combo.add(c)
pre = c
print(max(ans, len(combo)))
| Title: Polycarp and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if... | ```python
ans = 0
combo = set()
pre = -1
input()
for c in input():
if c.isupper():
ans = max(ans, len(combo))
combo = set()
pre = -1
elif c != pre:
combo.add(c)
pre = c
print(max(ans, len(combo)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
496 | A | Minimum Difficulty | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 for all *i* from 1 to *n*<=-<=1; we will call such sequence a track. Mike thinks that the track *a*1, ...,... | The first line contains a single integer *n* (3<=≤<=*n*<=≤<=100) — the number of holds.
The next line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000), where *a**i* is the height where the hold number *i* hangs. The sequence *a**i* is increasing (i.e. each element except for the first one is strict... | Print a single number — the minimum difficulty of the track after removing a single hold. | [
"3\n1 4 6\n",
"5\n1 2 3 4 5\n",
"5\n1 2 3 7 8\n"
] | [
"5\n",
"2\n",
"4\n"
] | In the first sample you can remove only the second hold, then the sequence looks like (1, 6), the maximum difference of the neighboring elements equals 5.
In the second test after removing every hold the difficulty equals 2.
In the third test you can obtain sequences (1, 3, 7, 8), (1, 2, 7, 8), (1, 2, 3, 8), for whic... | 500 | [
{
"input": "3\n1 4 6",
"output": "5"
},
{
"input": "5\n1 2 3 4 5",
"output": "2"
},
{
"input": "5\n1 2 3 7 8",
"output": "4"
},
{
"input": "3\n1 500 1000",
"output": "999"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "2"
},
{
"input": "10\n1 4 9... | 1,540,732,417 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 109 | 0 | n=int(input())
a=list(map(int,input().split()))
mn_darmion=a[2]-a[0]
for i in range(n-2):
mn_darmion=min(mn_darmion,a[i+2]-a[i])
mx=a[1]-a[0]
for i in range(n-1):
mx=max(mx,a[i+1]-a[i])
print(max(mx,mn_darmion)) | Title: Minimum Difficulty
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 fo... | ```python
n=int(input())
a=list(map(int,input().split()))
mn_darmion=a[2]-a[0]
for i in range(n-2):
mn_darmion=min(mn_darmion,a[i+2]-a[i])
mx=a[1]-a[0]
for i in range(n-1):
mx=max(mx,a[i+1]-a[i])
print(max(mx,mn_darmion))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
250 | B | Restoring IPv6 | PROGRAMMING | 1,500 | [
"implementation",
"strings"
] | null | null | An IPv6-address is a 128-bit number. For convenience, this number is recorded in blocks of 16 bits in hexadecimal record, the blocks are separated by colons — 8 blocks in total, each block has four hexadecimal digits. Here is an example of the correct record of a IPv6 address: "0124:5678:90ab:cdef:0124:5678:90ab:cdef".... | The first line contains a single integer *n* — the number of records to restore (1<=≤<=*n*<=≤<=100).
Each of the following *n* lines contains a string — the short IPv6 addresses. Each string only consists of string characters "0123456789abcdef:".
It is guaranteed that each short address is obtained by the way that is... | For each short IPv6 address from the input print its full record on a separate line. Print the full records for the short IPv6 addresses in the order, in which the short records follow in the input. | [
"6\na56f:d3:0:0124:01:f19a:1000:00\na56f:00d3:0000:0124:0001::\na56f::0124:0001:0000:1234:0ff0\na56f:0000::0000:0001:0000:1234:0ff0\n::\n0ea::4d:f4:6:0\n"
] | [
"a56f:00d3:0000:0124:0001:f19a:1000:0000\na56f:00d3:0000:0124:0001:0000:0000:0000\na56f:0000:0000:0124:0001:0000:1234:0ff0\na56f:0000:0000:0000:0001:0000:1234:0ff0\n0000:0000:0000:0000:0000:0000:0000:0000\n00ea:0000:0000:0000:004d:00f4:0006:0000\n"
] | none | 1,000 | [
{
"input": "6\na56f:d3:0:0124:01:f19a:1000:00\na56f:00d3:0000:0124:0001::\na56f::0124:0001:0000:1234:0ff0\na56f:0000::0000:0001:0000:1234:0ff0\n::\n0ea::4d:f4:6:0",
"output": "a56f:00d3:0000:0124:0001:f19a:1000:0000\na56f:00d3:0000:0124:0001:0000:0000:0000\na56f:0000:0000:0124:0001:0000:1234:0ff0\na56f:0000... | 1,658,770,915 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | for i in range(int(input())):
S = input()
for i in range(1, len(S)):
if S[i] == ':' and S[i - 1] == ':':
z = ('0000:' * (9 - S.count(':')))
S = S[:i - 1] + z + S[i + 1:]
a = S.split(':')
for j in range(8):
a[j] = '0' * (4 - len(a[j])) + a[j]
print(*a,... | Title: Restoring IPv6
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An IPv6-address is a 128-bit number. For convenience, this number is recorded in blocks of 16 bits in hexadecimal record, the blocks are separated by colons — 8 blocks in total, each block has four hexadecimal digits. He... | ```python
for i in range(int(input())):
S = input()
for i in range(1, len(S)):
if S[i] == ':' and S[i - 1] == ':':
z = ('0000:' * (9 - S.count(':')))
S = S[:i - 1] + z + S[i + 1:]
a = S.split(':')
for j in range(8):
a[j] = '0' * (4 - len(a[j])) + a[j]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,623,001,844 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 109 | 0 | def check(grid,n):
for i in range(n):
for j in range(n):
count=0
if i!=n-1:
if grid[i+1][j]=='o':
count+=1
if j!=n-1:
if grid[i][j+1]=='o':
count+=1
if i!=0:
if ... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
def check(grid,n):
for i in range(n):
for j in range(n):
count=0
if i!=n-1:
if grid[i+1][j]=='o':
count+=1
if j!=n-1:
if grid[i][j+1]=='o':
count+=1
if i!=0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,513,979,171 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 5,529,600 | n,d = map(int,input().split())
s = input()
w = [0]*n
w[0]=1
for i in range(1,n):
if s[i]=='1':
if i<=d:
for j in range(i):
w[i]+=w[j]
else:
for j in range(i-d,i):
w[i]+=w[j]
#print(w)
if w[n-1]==0:
print(-1)
else:
print(w[n-1])
| Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
n,d = map(int,input().split())
s = input()
w = [0]*n
w[0]=1
for i in range(1,n):
if s[i]=='1':
if i<=d:
for j in range(i):
w[i]+=w[j]
else:
for j in range(i-d,i):
w[i]+=w[j]
#print(w)
if w[n-1]==0:
print(-1)
else:
print(w[n-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
534 | A | Exam | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and became friends and if they take an exam sitting next to each other, they will help each other... | A single line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of students at an exam. | In the first line print integer *k* — the maximum number of students who can be seated so that no two students with adjacent numbers sit next to each other.
In the second line print *k* distinct integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=*n*), where *a**i* is the number of the student on the *i*-th position... | [
"6",
"3\n"
] | [
"6\n1 5 3 6 2 4",
"2\n1 3"
] | none | 500 | [
{
"input": "6",
"output": "6\n5 3 1 6 4 2 "
},
{
"input": "3",
"output": "2\n1 3"
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "2",
"output": "1\n1"
},
{
"input": "4",
"output": "4\n3 1 4 2 "
},
{
"input": "5",
"output": "5\n5 3 1 4 2 "
},
... | 1,655,665,822 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 46 | 0 | n=int(input())
li=[i+1 for i in range(n)]
e=[i for i in li if i%2==0]
o=[i for i in li if i%2]
if n%2:e.pop()
print(n-1 if n%2 else n)
print(*o,*e) | Title: Exam
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and bec... | ```python
n=int(input())
li=[i+1 for i in range(n)]
e=[i for i in li if i%2==0]
o=[i for i in li if i%2]
if n%2:e.pop()
print(n-1 if n%2 else n)
print(*o,*e)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,664,643,971 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | A,B = map(int, input().split())
C = max(A,B)
print((C-1)/6)
| Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
A,B = map(int, input().split())
C = max(A,B)
print((C-1)/6)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
851 | A | Arpa and a research in Mexican wave | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Arpa is researching the Mexican wave.
There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0.
- At time 1, the first spectator stands. - At time 2, the second spectator stands. - ... - At time *k*, the *k*-th spectator stands. - At time *k*<=+<=1, the (*k*<=+<=1)-t... | The first line contains three integers *n*, *k*, *t* (1<=≤<=*n*<=≤<=109, 1<=≤<=*k*<=≤<=*n*, 1<=≤<=*t*<=<<=*n*<=+<=*k*). | Print single integer: how many spectators are standing at time *t*. | [
"10 5 3\n",
"10 5 7\n",
"10 5 12\n"
] | [
"3\n",
"5\n",
"3\n"
] | In the following a sitting spectator is represented as -, a standing spectator is represented as ^.
- At *t* = 0 ---------- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4d97e684117250a9afe9be022ab8a63653dd15aa.png" style="max-width: 100.0%;max-height: 100.0%;"/> number of standing spe... | 500 | [
{
"input": "10 5 3",
"output": "3"
},
{
"input": "10 5 7",
"output": "5"
},
{
"input": "10 5 12",
"output": "3"
},
{
"input": "840585600 770678331 788528791",
"output": "770678331"
},
{
"input": "25462281 23343504 8024619",
"output": "8024619"
},
{
"in... | 1,618,720,564 | 2,147,483,647 | PyPy 3 | OK | TESTS | 166 | 108 | 0 | n,k,t=map(int,input().strip().split())
#print(n,k,t)
k2=k+k
if t<k:
ans=t
elif t>n:
# print("here")
ans=n+k-t
else:
ans=k
print(ans)
| Title: Arpa and a research in Mexican wave
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arpa is researching the Mexican wave.
There are *n* spectators in the stadium, labeled from 1 to *n*. They start the Mexican wave at time 0.
- At time 1, the first spectator stands. - At time 2,... | ```python
n,k,t=map(int,input().strip().split())
#print(n,k,t)
k2=k+k
if t<k:
ans=t
elif t>n:
# print("here")
ans=n+k-t
else:
ans=k
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,583,330,563 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 467 | 3,276,800 | n=int(input())
n=2*(n-1)
a=input()
ans=0
b=[i for i in a]
for i in range(n-1,-1,-2):
if chr((ord(a[i])+32)) not in b:
ans+=1
else:
d=a.find(chr((ord(a[i])+32)))
if(d<i):
b[d]='0'
b[i],b[i-1]='0','0'
print(ans)
| Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
n=int(input())
n=2*(n-1)
a=input()
ans=0
b=[i for i in a]
for i in range(n-1,-1,-2):
if chr((ord(a[i])+32)) not in b:
ans+=1
else:
d=a.find(chr((ord(a[i])+32)))
if(d<i):
b[d]='0'
b[i],b[i-1]='0','0'
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,663,964,443 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 93 | 0 | n = input().split(" ")
s = input().strip()
ans = 0
for i in s :
ans = ans + int( n[ int(i) - 1 ] )
print(ans) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
n = input().split(" ")
s = input().strip()
ans = 0
for i in s :
ans = ans + int( n[ int(i) - 1 ] )
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
609 | E | Minimum spanning tree for each edge | PROGRAMMING | 2,100 | [
"data structures",
"dfs and similar",
"dsu",
"graphs",
"trees"
] | null | null | Connected undirected weighted graph without self-loops and multiple edges is given. Graph contains *n* vertices and *m* edges.
For each edge (*u*,<=*v*) find the minimal possible weight of the spanning tree that contains the edge (*u*,<=*v*).
The weight of the spanning tree is the sum of weights of all edges included... | First line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=2·105,<=*n*<=-<=1<=≤<=*m*<=≤<=2·105) — the number of vertices and edges in graph.
Each of the next *m* lines contains three integers *u**i*,<=*v**i*,<=*w**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*,<=*u**i*<=≠<=*v**i*,<=1<=≤<=*w**i*<=≤<=109) — the endpoints of the *i*... | Print *m* lines. *i*-th line should contain the minimal possible weight of the spanning tree that contains *i*-th edge.
The edges are numbered from 1 to *m* in order of their appearing in input. | [
"5 7\n1 2 3\n1 3 1\n1 4 5\n2 3 2\n2 5 3\n3 4 2\n4 5 4\n"
] | [
"9\n8\n11\n8\n8\n8\n9\n"
] | none | 0 | [
{
"input": "5 7\n1 2 3\n1 3 1\n1 4 5\n2 3 2\n2 5 3\n3 4 2\n4 5 4",
"output": "9\n8\n11\n8\n8\n8\n9"
},
{
"input": "2 1\n1 2 42",
"output": "42"
},
{
"input": "3 3\n1 2 10\n2 3 20\n3 1 40",
"output": "30\n30\n50"
},
{
"input": "4 6\n1 2 999999001\n1 3 999999003\n1 4 999999009\... | 1,642,449,974 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 176,128,000 | from collections import defaultdict
import io, os, sys
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
I = lambda: [int(i) for i in input().split()]
################################################
from types import GeneratorType
def bootstrap(f, stack=[]):
def wrappedfunc(*args, **kwargs):
... | Title: Minimum spanning tree for each edge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Connected undirected weighted graph without self-loops and multiple edges is given. Graph contains *n* vertices and *m* edges.
For each edge (*u*,<=*v*) find the minimal possible weight of the spann... | ```python
from collections import defaultdict
import io, os, sys
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
I = lambda: [int(i) for i in input().split()]
################################################
from types import GeneratorType
def bootstrap(f, stack=[]):
def wrappedfunc(*args, **kw... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,625,601,906 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | a,b = map(int,input().split())
auction= {}
ans =[]
for i in range(a):
c = [int(i) for i in input().split()]
auction[c[0]] = c[1:]
print(auction)
for i,j in auction.items():
for x in j:
if b > x:
print(a,x)
ans.append(i)
break
if ans:
print(" ... | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
a,b = map(int,input().split())
auction= {}
ans =[]
for i in range(a):
c = [int(i) for i in input().split()]
auction[c[0]] = c[1:]
print(auction)
for i,j in auction.items():
for x in j:
if b > x:
print(a,x)
ans.append(i)
break
if ans:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
804 | B | Minimum number of steps | PROGRAMMING | 1,400 | [
"combinatorics",
"greedy",
"implementation",
"math"
] | null | null | We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substring, our job is done. Print the minimum number of steps we should perform to make our job done modulo 109<=+<... | The first line contains the initial string consisting of letters 'a' and 'b' only with length from 1 to 106. | Print the minimum number of steps modulo 109<=+<=7. | [
"ab\n",
"aab\n"
] | [
"1\n",
"3\n"
] | The first example: "ab" → "bba".
The second example: "aab" → "abba" → "bbaba" → "bbbbaa". | 1,000 | [
{
"input": "ab",
"output": "1"
},
{
"input": "aab",
"output": "3"
},
{
"input": "aaaaabaabababaaaaaba",
"output": "17307"
},
{
"input": "abaabaaabbabaabab",
"output": "1795"
},
{
"input": "abbaa",
"output": "2"
},
{
"input": "abbaaabaabaaaaabbbbaababaa... | 1,677,388,422 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 701 | 8,806,400 | import sys
input = sys.stdin.readline
z = input().strip()
ans = 0
while 'ab' in z:
z =z.replace('ab', 'bba')
ans+=1
print(ans)
| Title: Minimum number of steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substr... | ```python
import sys
input = sys.stdin.readline
z = input().strip()
ans = 0
while 'ab' in z:
z =z.replace('ab', 'bba')
ans+=1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,641,701,391 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n=list(input())
array=sorted(list(map(int,input().split())))
print("1 "+str(array[0]))
array=array[1:]
if array[-1]==0:
print("2 "+str(array[0])+" "+str(array[1]))
array=array[2:]
else:
positive=[elem for elem in array if elem>0]
print(str(len(positive)),end=" ")
print(*positive)
if len(a... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
n=list(input())
array=sorted(list(map(int,input().split())))
print("1 "+str(array[0]))
array=array[1:]
if array[-1]==0:
print("2 "+str(array[0])+" "+str(array[1]))
array=array[2:]
else:
positive=[elem for elem in array if elem>0]
print(str(len(positive)),end=" ")
print(*positive)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
899 | A | Splitting in Teams | PROGRAMMING | 800 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The coach decided to form teams of exactly three people for this training. Determine the maximum number of tea... | The first line contains single integer *n* (2<=≤<=*n*<=≤<=2·105) — the number of groups.
The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), where *a**i* is the number of people in group *i*. | Print the maximum number of teams of three people the coach can form. | [
"4\n1 1 2 1\n",
"2\n2 2\n",
"7\n2 2 2 1 1 1 1\n",
"3\n1 1 1\n"
] | [
"1\n",
"0\n",
"3\n",
"1\n"
] | In the first example the coach can form one team. For example, he can take students from the first, second and fourth groups.
In the second example he can't make a single team.
In the third example the coach can form three teams. For example, he can do this in the following way:
- The first group (of two people) an... | 500 | [
{
"input": "4\n1 1 2 1",
"output": "1"
},
{
"input": "2\n2 2",
"output": "0"
},
{
"input": "7\n2 2 2 1 1 1 1",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "3\n2 2 2",
"output": "0"
},
{
"input": "3\n1 2 1",
"output": "1"
}... | 1,513,516,667 | 2,147,483,647 | Python 3 | OK | TESTS | 67 | 108 | 9,523,200 | n=int(input())
l=list(map(int,input().split()))
if l.count(1)==0:
print(0)
elif l.count(2)>=l.count(1) :
print(l.count(1))
else :
print(l.count(2)+(l.count(1)-l.count(2))//3) | Title: Splitting in Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The co... | ```python
n=int(input())
l=list(map(int,input().split()))
if l.count(1)==0:
print(0)
elif l.count(2)>=l.count(1) :
print(l.count(1))
else :
print(l.count(2)+(l.count(1)-l.count(2))//3)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
515 | D | Drazil and Tiles | PROGRAMMING | 2,000 | [
"constructive algorithms",
"greedy"
] | null | null | Drazil created a following problem about putting 1<=×<=2 tiles into an *n*<=×<=*m* grid:
"There is a grid with some cells that are empty and some cells that are occupied. You should use 1<=×<=2 tiles to cover all empty cells and no two tiles should cover each other. And you should print a solution about how to do it."... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2000).
The following *n* lines describe the grid rows. Character '.' denotes an empty cell, and the character '*' denotes a cell that is occupied. | If there is no solution or the solution is not unique, you should print the string "Not unique".
Otherwise you should print how to cover all empty cells with 1<=×<=2 tiles. Use characters "<>" to denote horizontal tiles and characters "^v" to denote vertical tiles. Refer to the sample test for the output format ... | [
"3 3\n...\n.*.\n...\n",
"4 4\n..**\n*...\n*.**\n....\n",
"2 4\n*..*\n....\n",
"1 1\n.\n",
"1 1\n*\n"
] | [
"Not unique\n",
"<>**\n*^<>\n*v**\n<><>\n",
"*<>*\n<><>\n",
"Not unique\n",
"*\n"
] | In the first case, there are indeed two solutions:
and
so the answer is "Not unique". | 3,000 | [] | 1,585,912,323 | 2,147,483,647 | PyPy 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 17 | 1,543 | 268,390,400 | from sys import stdin, gettrace
if not gettrace():
def input():
return next(stdin)[:-1]
# def input():
# return stdin.buffer.readline()
def main():
n,m = map(int, input().split())
grid = [['*']*(m+2)]
for _ in range(n):
grid.append(['*'] + list(input()) + ['*'])
grid.append([... | Title: Drazil and Tiles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil created a following problem about putting 1<=×<=2 tiles into an *n*<=×<=*m* grid:
"There is a grid with some cells that are empty and some cells that are occupied. You should use 1<=×<=2 tiles to cover all empt... | ```python
from sys import stdin, gettrace
if not gettrace():
def input():
return next(stdin)[:-1]
# def input():
# return stdin.buffer.readline()
def main():
n,m = map(int, input().split())
grid = [['*']*(m+2)]
for _ in range(n):
grid.append(['*'] + list(input()) + ['*'])
gri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
940 | A | Points on the line | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"sortings"
] | null | null | We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1,<=3,<=2,<=1} is 2.
D... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=100,<=0<=≤<=*d*<=≤<=100) — the amount of points and the maximum allowed diameter respectively.
The second line contains *n* space separated integers (1<=≤<=*x**i*<=≤<=100) — the coordinates of the points. | Output a single integer — the minimum number of points you have to remove. | [
"3 1\n2 1 4\n",
"3 0\n7 7 7\n",
"6 3\n1 3 4 6 9 10\n"
] | [
"1\n",
"0\n",
"3\n"
] | In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal stra... | 500 | [
{
"input": "3 1\n2 1 4",
"output": "1"
},
{
"input": "3 0\n7 7 7",
"output": "0"
},
{
"input": "6 3\n1 3 4 6 9 10",
"output": "3"
},
{
"input": "11 5\n10 11 12 13 14 15 16 17 18 19 20",
"output": "5"
},
{
"input": "1 100\n1",
"output": "0"
},
{
"input"... | 1,521,474,082 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 93 | 7,065,600 | def main():
n,d = map(int,input().split())
x = list(map(int,input().split()))
x.sort()
ans = n
for i in range(n):
j = i
while j<n and x[j]-x[i]<=d:
j += 1
ans = min(ans, n-(j-i))
print(ans)
if __name__ == '__main__':
main()
| Title: Points on the line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest dista... | ```python
def main():
n,d = map(int,input().split())
x = list(map(int,input().split()))
x.sort()
ans = n
for i in range(n):
j = i
while j<n and x[j]-x[i]<=d:
j += 1
ans = min(ans, n-(j-i))
print(ans)
if __name__ == '__main__':
main()
``... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,694,667,777 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 46 | 0 | knw = input()
k_n_w = knw.split()
k = int(k_n_w[0])
n = int(k_n_w[1])
w = int(k_n_w[2])
cost = 0
for i in range(1,w+1):
cost += i*k
borrow = cost - n
if borrow > 0:
print(borrow)
else:
print(0)
| Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
knw = input()
k_n_w = knw.split()
k = int(k_n_w[0])
n = int(k_n_w[1])
w = int(k_n_w[2])
cost = 0
for i in range(1,w+1):
cost += i*k
borrow = cost - n
if borrow > 0:
print(borrow)
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,589,737,332 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 109 | 6,656,000 | s = input()
a = 0
n = len(s)
for i in range(n):
if s[i] == "A":
a += s[:i].count("Q") * s[i:].count("Q")
print(a)
| Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
s = input()
a = 0
n = len(s)
for i in range(n):
if s[i] == "A":
a += s[:i].count("Q") * s[i:].count("Q")
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
803 | C | Maximal GCD | PROGRAMMING | 1,900 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Greatest common divisor of sequence is maximum of such numbers that every element of sequence is divi... | The first line consists of two numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1010). | If the answer exists then output *k* numbers — resulting sequence. Otherwise output -1. If there are multiple answers, print any of them. | [
"6 3\n",
"8 2\n",
"5 3\n"
] | [
"1 2 3\n",
"2 6\n",
"-1\n"
] | none | 0 | [
{
"input": "6 3",
"output": "1 2 3"
},
{
"input": "8 2",
"output": "2 6"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "2 10000000... | 1,700,307,367 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 138 | 93 | 11,468,800 | import math
n,k=map(int,input().split())
u=k*(k+1)//2
if n<u:
print(-1)
else:
d=[]
for i in range(1,int(math.sqrt(n))+1):
if n%i==0:
d.append(i)
if n//i!=i:
d.append(n//i)
d=sorted(d,reverse=True)
res=[]
for p in d:
if n//p<u... | Title: Maximal GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Grea... | ```python
import math
n,k=map(int,input().split())
u=k*(k+1)//2
if n<u:
print(-1)
else:
d=[]
for i in range(1,int(math.sqrt(n))+1):
if n%i==0:
d.append(i)
if n//i!=i:
d.append(n//i)
d=sorted(d,reverse=True)
res=[]
for p in d:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
439 | B | Devu, the Dumb Guy | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Devu is a dumb guy, his learning curve is very slow. You are supposed to teach him *n* subjects, the *i**th* subject has *c**i* chapters. When you teach him, you are supposed to teach all the chapters of a subject continuously.
Let us say that his initial per chapter learning power of a subject is *x* hours. In other ... | The first line will contain two space separated integers *n*, *x* (1<=≤<=*n*,<=*x*<=≤<=105). The next line will contain *n* space separated integers: *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=105). | Output a single integer representing the answer to the problem. | [
"2 3\n4 1\n",
"4 2\n5 1 2 1\n",
"3 3\n1 1 1\n"
] | [
"11\n",
"10\n",
"6\n"
] | Look at the first example. Consider the order of subjects: 1, 2. When you teach Devu the first subject, it will take him 3 hours per chapter, so it will take 12 hours to teach first subject. After teaching first subject, his per chapter learning time will be 2 hours. Now teaching him second subject will take 2 × 1 = 2 ... | 1,000 | [
{
"input": "2 3\n4 1",
"output": "11"
},
{
"input": "4 2\n5 1 2 1",
"output": "10"
},
{
"input": "3 3\n1 1 1",
"output": "6"
},
{
"input": "20 4\n1 1 3 5 5 1 3 4 2 5 2 4 3 1 3 3 3 3 4 3",
"output": "65"
},
{
"input": "20 10\n6 6 1 2 6 4 5 3 6 5 4 5 6 5 4 6 6 2 3 3... | 1,581,830,853 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 218 | 10,547,200 | subject,hour=map(int,input().split())
chapter=list(map(int,input().split()))
global sum
sum=0
chapter.sort()
for i in range(subject):
if hour==1:
sum+=chapter[i]
else:
sum+=chapter[i]*hour
hour-=1
print(sum) | Title: Devu, the Dumb Guy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a dumb guy, his learning curve is very slow. You are supposed to teach him *n* subjects, the *i**th* subject has *c**i* chapters. When you teach him, you are supposed to teach all the chapters of a subject co... | ```python
subject,hour=map(int,input().split())
chapter=list(map(int,input().split()))
global sum
sum=0
chapter.sort()
for i in range(subject):
if hour==1:
sum+=chapter[i]
else:
sum+=chapter[i]*hour
hour-=1
print(sum)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,671,176,920 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 93 | 1,024,000 | # This is a sample Python script.
# Press Shift+F10 to execute it or replace it with your code.
# Press Double Shift to search everywhere for classes, files, tool windows, actions, and settings.
from string import ascii_uppercase
from collections import Counter
import itertools
import sys
from dataclasses im... | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
# This is a sample Python script.
# Press Shift+F10 to execute it or replace it with your code.
# Press Double Shift to search everywhere for classes, files, tool windows, actions, and settings.
from string import ascii_uppercase
from collections import Counter
import itertools
import sys
from data... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,470,930,753 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 122 | 4,608,000 | n = int(input())
q = 0
s = [0] + list(map(int,input().split()))
a, b = map(int, input().split())
for i in range(a-1, b):
q+=s[i]
print(q) | Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
n = int(input())
q = 0
s = [0] + list(map(int,input().split()))
a, b = map(int, input().split())
for i in range(a-1, b):
q+=s[i]
print(q)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
827 | B | High Load | PROGRAMMING | 1,800 | [
"constructive algorithms",
"greedy",
"implementation",
"trees"
] | null | null | Arkady needs your help again! This time he decided to build his own high-speed Internet exchange point. It should consist of *n* nodes connected with minimum possible number of wires into one network (a wire directly connects two nodes). Exactly *k* of the nodes should be exit-nodes, that means that each of them should... | The first line contains two integers *n* and *k* (3<=≤<=*n*<=≤<=2·105, 2<=≤<=*k*<=≤<=*n*<=-<=1) — the total number of nodes and the number of exit-nodes.
Note that it is always possible to build at least one network with *n* nodes and *k* exit-nodes within the given constraints. | In the first line print the minimum possible distance between the two most distant exit-nodes. In each of the next *n*<=-<=1 lines print two integers: the ids of the nodes connected by a wire. The description of each wire should be printed exactly once. You can print wires and wires' ends in arbitrary order. The nodes ... | [
"3 2\n",
"5 3\n"
] | [
"2\n1 2\n2 3\n",
"3\n1 2\n2 3\n3 4\n3 5\n"
] | In the first example the only network is shown on the left picture.
In the second example one of optimal networks is shown on the right picture.
Exit-nodes are highlighted. | 750 | [
{
"input": "3 2",
"output": "2\n1 2\n2 3"
},
{
"input": "5 3",
"output": "3\n1 2\n2 3\n3 4\n3 5"
},
{
"input": "4 2",
"output": "3\n1 2\n2 3\n3 4"
},
{
"input": "4 3",
"output": "2\n1 2\n2 3\n2 4"
},
{
"input": "5 2",
"output": "4\n1 2\n2 3\n3 4\n4 5"
},
{... | 1,624,548,504 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 77 | 0 | def f(n,k):
points=[i for i in range(1,k+1)]
mid=[i for i in range(k+1,n+1)]
l=mid[0]
r=mid[-1]
ans=[]
print(len(mid)+1)
ans.append((l,points[0]))
for i in points[1:]:
ans.append((r,i))
for i in range(0,len(mid)-1):
ans.append((mid[i],mid[i+1]))
for i in ans:
print(*i)
n,k=map(int,input(... | Title: High Load
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arkady needs your help again! This time he decided to build his own high-speed Internet exchange point. It should consist of *n* nodes connected with minimum possible number of wires into one network (a wire directly connects... | ```python
def f(n,k):
points=[i for i in range(1,k+1)]
mid=[i for i in range(k+1,n+1)]
l=mid[0]
r=mid[-1]
ans=[]
print(len(mid)+1)
ans.append((l,points[0]))
for i in points[1:]:
ans.append((r,i))
for i in range(0,len(mid)-1):
ans.append((mid[i],mid[i+1]))
for i in ans:
print(*i)
n,k=map(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
687 | A | NP-Hard Problem | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs"
] | null | null | Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of this graph, if for each edge *uv* there is at least one endpoint of it in this set, i.e. or (or bot... | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — the number of vertices and the number of edges in the prize graph, respectively.
Each of the next *m* lines contains a pair of integers *u**i* and *v**i* (1<=<=≤<=<=*u**i*,<=<=*v**i*<=<=≤<=<=*n*), denoting ... | If it's impossible to split the graph between Pari and Arya as they expect, print "-1" (without quotes).
If there are two disjoint sets of vertices, such that both sets are vertex cover, print their descriptions. Each description must contain two lines. The first line contains a single integer *k* denoting the number ... | [
"4 2\n1 2\n2 3\n",
"3 3\n1 2\n2 3\n1 3\n"
] | [
"1\n2 \n2\n1 3 \n",
"-1\n"
] | In the first sample, you can give the vertex number 2 to Arya and vertices numbered 1 and 3 to Pari and keep vertex number 4 for yourself (or give it someone, if you wish).
In the second sample, there is no way to satisfy both Pari and Arya. | 500 | [
{
"input": "4 2\n1 2\n2 3",
"output": "1\n2 \n2\n1 3 "
},
{
"input": "3 3\n1 2\n2 3\n1 3",
"output": "-1"
},
{
"input": "5 7\n3 2\n5 4\n3 4\n1 3\n1 5\n1 4\n2 5",
"output": "-1"
},
{
"input": "10 11\n4 10\n8 10\n2 3\n2 4\n7 1\n8 5\n2 8\n7 2\n1 2\n2 9\n6 8",
"output": "-1"
... | 1,540,419,193 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 14 | 732 | 12,390,400 | n, m = map(int, input().split())
g = [[] for i in range(n)]
color = [-1] * n
for i in range(m):
f, t = map(int, input().split())
f -= 1
t -= 1
g[f].append(t)
g[t].append(f)
def dfs(v, c):
color[v] = c
for to in g[v]:
if(color[to] == -1):
dfs(to, c ^ 1)
... | Title: NP-Hard Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of ... | ```python
n, m = map(int, input().split())
g = [[] for i in range(n)]
color = [-1] * n
for i in range(m):
f, t = map(int, input().split())
f -= 1
t -= 1
g[f].append(t)
g[t].append(f)
def dfs(v, c):
color[v] = c
for to in g[v]:
if(color[to] == -1):
dfs(t... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,665,333,170 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 46 | 0 | st = input()
ans = (len(st)+1)*25
print(ans+1) | Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
st = input()
ans = (len(st)+1)*25
print(ans+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,699,957,680 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | input()
a = list(map(int, input().split()))
mn = min(a.count(1), a.count(2), a.count(3))
print(mn)
a2 = [[], [], []]
for i in range(len(a)):
a2[a[i]-1].append(i)
for i in range(mn):
print(a2[0][i], a2[1][i], a2[2][i]) | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
input()
a = list(map(int, input().split()))
mn = min(a.count(1), a.count(2), a.count(3))
print(mn)
a2 = [[], [], []]
for i in range(len(a)):
a2[a[i]-1].append(i)
for i in range(mn):
print(a2[0][i], a2[1][i], a2[2][i])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,560,840,635 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 248 | 0 | N = int(input())
A = list(map(int, input().split()))
even = 0
odd = 0
for i in range(0, N):
if A[i]%2 == 0: even += 1
else: odd += 1
print(abs(even-odd)) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
N = int(input())
A = list(map(int, input().split()))
even = 0
odd = 0
for i in range(0, N):
if A[i]%2 == 0: even += 1
else: odd += 1
print(abs(even-odd))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
501 | B | Misha and Changing Handles | PROGRAMMING | 1,100 | [
"data structures",
"dsu",
"strings"
] | null | null | Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is already used or that was used at some point.
Misha has a list of handle change requests. After completing the re... | The first line contains integer *q* (1<=≤<=*q*<=≤<=1000), the number of handle change requests.
Next *q* lines contain the descriptions of the requests, one per line.
Each query consists of two non-empty strings *old* and *new*, separated by a space. The strings consist of lowercase and uppercase Latin letters and di... | In the first line output the integer *n* — the number of users that changed their handles at least once.
In the next *n* lines print the mapping between the old and the new handles of the users. Each of them must contain two strings, *old* and *new*, separated by a space, meaning that before the user had handle *old*,... | [
"5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov\n"
] | [
"3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123\n"
] | none | 500 | [
{
"input": "5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov",
"output": "3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123"
},
{
"input": "1\nMisha Vasya",
"output": "1\nMisha Vasya"
},
{
"input": "10\na b\nb c\nc d\nd... | 1,617,386,541 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 109 | 0 | q = int(input())
users = []
for k in range(q):
old, new = input().split()
if len(users) == 0:
users.append([old, new])
else:
encontrou = False
for i in users:
if i[-1] == old:
i.append(new)
encontrou = True
if not encontrou:
users.append([old, new])
print(len(users))
... | Title: Misha and Changing Handles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is a... | ```python
q = int(input())
users = []
for k in range(q):
old, new = input().split()
if len(users) == 0:
users.append([old, new])
else:
encontrou = False
for i in users:
if i[-1] == old:
i.append(new)
encontrou = True
if not encontrou:
users.append([old, new])
print(le... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
553 | A | Kyoya and Colored Balls | PROGRAMMING | 1,500 | [
"combinatorics",
"dp",
"math"
] | null | null | Kyoya Ootori has a bag with *n* colored balls that are colored with *k* different colors. The colors are labeled from 1 to *k*. Balls of the same color are indistinguishable. He draws balls from the bag one by one until the bag is empty. He noticed that he drew the last ball of color *i* before drawing the last ball of... | The first line of input will have one integer *k* (1<=≤<=*k*<=≤<=1000) the number of colors.
Then, *k* lines will follow. The *i*-th line will contain *c**i*, the number of balls of the *i*-th color (1<=≤<=*c**i*<=≤<=1000).
The total number of balls doesn't exceed 1000. | A single integer, the number of ways that Kyoya can draw the balls from the bag as described in the statement, modulo 1<=000<=000<=007. | [
"3\n2\n2\n1\n",
"4\n1\n2\n3\n4\n"
] | [
"3\n",
"1680\n"
] | In the first sample, we have 2 balls of color 1, 2 balls of color 2, and 1 ball of color 3. The three ways for Kyoya are: | 250 | [
{
"input": "3\n2\n2\n1",
"output": "3"
},
{
"input": "4\n1\n2\n3\n4",
"output": "1680"
},
{
"input": "10\n100\n100\n100\n100\n100\n100\n100\n100\n100\n100",
"output": "12520708"
},
{
"input": "5\n10\n10\n10\n10\n10",
"output": "425711769"
},
{
"input": "11\n291\n3... | 1,695,531,355 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 62 | 0 | import sys
#sys.setrecursionlimit(20000)
#from collections import deque #Counter
#from itertools import accumulate, product
#from functools import reduce
#from math import gcd #sqrt
import math
def rall():
return [x.strip() for x in sys.stdin.readlines()]
def rl():
return sys.stdin.readline().strip()
def rl_t... | Title: Kyoya and Colored Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori has a bag with *n* colored balls that are colored with *k* different colors. The colors are labeled from 1 to *k*. Balls of the same color are indistinguishable. He draws balls from the bag one by o... | ```python
import sys
#sys.setrecursionlimit(20000)
#from collections import deque #Counter
#from itertools import accumulate, product
#from functools import reduce
#from math import gcd #sqrt
import math
def rall():
return [x.strip() for x in sys.stdin.readlines()]
def rl():
return sys.stdin.readline().strip(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
716 | A | Crazy Computer | PROGRAMMING | 800 | [
"implementation"
] | null | null | ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *b*, then if *b*<=-<=*a*<=≤<=*c*, just the new word is appended to other words on the screen. If *b*<... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*c*<=≤<=109) — the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=...<=<<=*t**n*<=≤<=109), where *t**i* denote... | Print a single positive integer, the number of words that remain on the screen after all *n* words was typed, in other words, at the second *t**n*. | [
"6 5\n1 3 8 14 19 20\n",
"6 1\n1 3 5 7 9 10\n"
] | [
"3",
"2"
] | The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be... | 500 | [
{
"input": "6 5\n1 3 8 14 19 20",
"output": "3"
},
{
"input": "6 1\n1 3 5 7 9 10",
"output": "2"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
"input": "5 5\n1 7 12 13 14",
"output": "4"
},
{
"input": "2 1000000000\n1 1000000000",
"output": "2"
},
{
... | 1,553,627,996 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | # import sys
# import time
# sys.stdin=open("utest.in","r")
# sys.stdout=open("utest.out","w")
# n=list(map(int,(input().split())))
# q=""
# for j in range(1,n[1]+1):
# q+="#"
# w=""
# for u in range(1,n[1]):
# w+="."
# w+="#"
# e=""
# for t in range(1,n[1]+1):
# e+="#"
# r="#"
# for i in range(1,n[1]):
# r+="."
... | Title: Crazy Computer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *... | ```python
# import sys
# import time
# sys.stdin=open("utest.in","r")
# sys.stdout=open("utest.out","w")
# n=list(map(int,(input().split())))
# q=""
# for j in range(1,n[1]+1):
# q+="#"
# w=""
# for u in range(1,n[1]):
# w+="."
# w+="#"
# e=""
# for t in range(1,n[1]+1):
# e+="#"
# r="#"
# for i in range(1,n[1]):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,637,591,042 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def check(s:str):
countbig, countsmall = 0, 0
for letter in s:
if letter.isupper():
countbig+=1
continue
countsmall
if countbig > countsmall:
return s.upper()
return s.lower(),len(s)
print(check(input())) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
def check(s:str):
countbig, countsmall = 0, 0
for letter in s:
if letter.isupper():
countbig+=1
continue
countsmall
if countbig > countsmall:
return s.upper()
return s.lower(),len(s)
print(check(input()))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,642,736,297 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | import math
a,b=input().split()
a=int(a)
b=int(b)
num=a+math.floor((a-1)/(b-1))
print(num) | Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
import math
a,b=input().split()
a=int(a)
b=int(b)
num=a+math.floor((a-1)/(b-1))
print(num)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,681,564,112 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | t=input()
t.lower()
print(t) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
t=input()
t.lower()
print(t)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
907 | A | Masha and Bears | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 500 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,676,441,055 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | size_father, size_mother, size_baby, size_masha = [int(x) for x in input().strip().split()]
car_father = size_father
car_mother = size_mother
car_baby = size_baby
if car_baby < size_masha:
diff = size_masha - car_baby
car_baby += diff
if car_baby > 2*size_masha:
diff = car_baby - (2*size_masha)
size_... | Title: Masha and Bears
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son b... | ```python
size_father, size_mother, size_baby, size_masha = [int(x) for x in input().strip().split()]
car_father = size_father
car_mother = size_mother
car_baby = size_baby
if car_baby < size_masha:
diff = size_masha - car_baby
car_baby += diff
if car_baby > 2*size_masha:
diff = car_baby - (2*size_masha)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,586,157,121 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 218 | 0 | #----Kuzlyaev-Nikita-Codeforces-----
#------------06.04.2020-------------
alph="abcdefghijklmnopqrstuvwxyz"
#-----------------------------------
n,k=map(int,input().split())
E=0;x,y=map(int,input().split())
for i in range(n-1):
a,b=map(int,input().split())
r=((x-a)**2+(y-b)**2)**0.5
E+=r;x,y=... | Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
#----Kuzlyaev-Nikita-Codeforces-----
#------------06.04.2020-------------
alph="abcdefghijklmnopqrstuvwxyz"
#-----------------------------------
n,k=map(int,input().split())
E=0;x,y=map(int,input().split())
for i in range(n-1):
a,b=map(int,input().split())
r=((x-a)**2+(y-b)**2)**0.5
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
494 | A | Treasure | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string *s* written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that th... | The first line of the input contains a string *s* (1<=≤<=|*s*|<=≤<=105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that *s* contains at least one '#' character. | If there is no way of replacing '#' characters which leads to a beautiful string print <=-<=1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them. | [
"(((#)((#)\n",
"()((#((#(#()\n",
"#\n",
"(#)\n"
] | [
"1\n2\n",
"2\n2\n1",
"-1\n",
"-1\n"
] | |*s*| denotes the length of the string *s*. | 500 | [
{
"input": "(((#)((#)",
"output": "1\n2"
},
{
"input": "()((#((#(#()",
"output": "1\n1\n3"
},
{
"input": "#",
"output": "-1"
},
{
"input": "(#)",
"output": "-1"
},
{
"input": "(((((#(#(#(#()",
"output": "1\n1\n1\n5"
},
{
"input": "#))))",
"output":... | 1,698,064,614 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 93 | 8,908,800 | import sys
s = input()
x = 0
y = 0
v = []
for _ in s:
if _ == "(":
x += 1
elif _ == ")":
x -= 1
elif _ == "#":
x -= 1
v.append(1)
if x < 0:
print(-1)
sys.exit()
v[-1] += x
i = 0
x = 0
for _ in s:
if _ == "(":
x += 1
el... | Title: Treasure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string *s* written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open... | ```python
import sys
s = input()
x = 0
y = 0
v = []
for _ in s:
if _ == "(":
x += 1
elif _ == ")":
x -= 1
elif _ == "#":
x -= 1
v.append(1)
if x < 0:
print(-1)
sys.exit()
v[-1] += x
i = 0
x = 0
for _ in s:
if _ == "(":
x +=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
817 | B | Makes And The Product | PROGRAMMING | 1,500 | [
"combinatorics",
"implementation",
"math",
"sortings"
] | null | null | After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular question: how many triples of indices (*i*,<= *j*,<= *k*) (*i*<=<<=*j*<=<<=*k*), such that *a**i*·*a**j*·*a... | The first line of input contains a positive integer number *n* (3<=≤<=*n*<=≤<=105) — the number of elements in array *a*. The second line contains *n* positive integer numbers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of a given array. | Print one number — the quantity of triples (*i*,<= *j*,<= *k*) such that *i*,<= *j* and *k* are pairwise distinct and *a**i*·*a**j*·*a**k* is minimum possible. | [
"4\n1 1 1 1\n",
"5\n1 3 2 3 4\n",
"6\n1 3 3 1 3 2\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first example Makes always chooses three ones out of four, and the number of ways to choose them is 4.
In the second example a triple of numbers (1, 2, 3) is chosen (numbers, not indices). Since there are two ways to choose an element 3, then the answer is 2.
In the third example a triple of numbers (1, 1, 2) ... | 0 | [
{
"input": "4\n1 1 1 1",
"output": "4"
},
{
"input": "5\n1 3 2 3 4",
"output": "2"
},
{
"input": "6\n1 3 3 1 3 2",
"output": "1"
},
{
"input": "3\n1000000000 1000000000 1000000000",
"output": "1"
},
{
"input": "4\n1 1 2 2",
"output": "2"
},
{
"input": ... | 1,689,743,422 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 14,438,400 | import math
def ccc(n,r):
return math.factorial(n)/(math.factorial(r)*math.factorial(n-r))
n=int(input())
ls=list(map(int,input().split()))
ls.sort()
lz=[ls[0],ls[1],ls[2]]
z={}
for i in lz:
z[i]=lz.count(i)
cnt=1
for i in range(3,n):
if ls[i] in lz:
if z[ls[i]]>1:
cnt=cnt+... | Title: Makes And The Product
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular questi... | ```python
import math
def ccc(n,r):
return math.factorial(n)/(math.factorial(r)*math.factorial(n-r))
n=int(input())
ls=list(map(int,input().split()))
ls.sort()
lz=[ls[0],ls[1],ls[2]]
z={}
for i in lz:
z[i]=lz.count(i)
cnt=1
for i in range(3,n):
if ls[i] in lz:
if z[ls[i]]>1:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,684,433,842 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 62 | 0 | import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
############ --... | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
#####... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,696,608,030 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 92 | 0 | n = int(input())
points = []
for _ in range(n):
x, y = map(int, input().split())
points.append((x, y))
supercentral_count = 0
for x, y in points:
has_upper = False
has_lower = False
has_left = False
has_right = False
for x2, y2 in points:
if x2 == x and y2 > y... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
n = int(input())
points = []
for _ in range(n):
x, y = map(int, input().split())
points.append((x, y))
supercentral_count = 0
for x, y in points:
has_upper = False
has_lower = False
has_left = False
has_right = False
for x2, y2 in points:
if x2 == x ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
924 | C | Riverside Curio | PROGRAMMING | 1,700 | [
"data structures",
"dp",
"greedy"
] | null | null | Arkady decides to observe a river for *n* consecutive days. The river's water level on each day is equal to some real value.
Arkady goes to the riverside each day and makes a mark on the side of the channel at the height of the water level, but if it coincides with a mark made before, no new mark is created. The water... | The first line contains a single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of days.
The second line contains *n* space-separated integers *m*1,<=*m*2,<=...,<=*m**n* (0<=≤<=*m**i*<=<<=*i*) — the number of marks strictly above the water on each day. | Output one single integer — the minimum possible sum of the number of marks strictly below the water level among all days. | [
"6\n0 1 0 3 0 2\n",
"5\n0 1 2 1 2\n",
"5\n0 1 1 2 2\n"
] | [
"6\n",
"1\n",
"0\n"
] | In the first example, the following figure shows an optimal case.
Note that on day 3, a new mark should be created because if not, there cannot be 3 marks above water on day 4. The total number of marks underwater is 0 + 0 + 2 + 0 + 3 + 1 = 6.
In the second example, the following figure shows an optimal case. | 1,250 | [
{
"input": "6\n0 1 0 3 0 2",
"output": "6"
},
{
"input": "5\n0 1 2 1 2",
"output": "1"
},
{
"input": "5\n0 1 1 2 2",
"output": "0"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "100\n0 1 2 2 3 0 1 5 6 6 0 0 8 7 1 9 9 4 10 11 12 2 12 12 12 12 9 13 14 8 15 15 15... | 1,522,755,590 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 6,963,200 | n = int(input())
m = input().split()
for i in range(n):
m[i] = int(m[i])
marks = []
s = 0
x = max(m)+1
for i in range(n):
if i == 0:
marks.append(10.0)
else:
if m[i] == len(marks):
marks.insert(0, min(marks)-0.000001)
else:
if i != n-1 and m[i+1]... | Title: Riverside Curio
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arkady decides to observe a river for *n* consecutive days. The river's water level on each day is equal to some real value.
Arkady goes to the riverside each day and makes a mark on the side of the channel at the heig... | ```python
n = int(input())
m = input().split()
for i in range(n):
m[i] = int(m[i])
marks = []
s = 0
x = max(m)+1
for i in range(n):
if i == 0:
marks.append(10.0)
else:
if m[i] == len(marks):
marks.insert(0, min(marks)-0.000001)
else:
if i != n-1 ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, al... | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,700,146,326 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 175,616,000 | def last_digit_of_1378n(n):
return (8 ** n) % 10
n=int(input())
print(last_digit_of_1378n(n)) | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one ques... | ```python
def last_digit_of_1378n(n):
return (8 ** n) % 10
n=int(input())
print(last_digit_of_1378n(n))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,585,334,278 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 307,200 | length = int(input())
list_num = list(map(int, input().split()))
even1 = list_num[0] % 2
even2 = list_num[1] % 2
even3 = list_num[2] % 2
found = False
if even1 == even2:
if even1 == even3:
evenness = even1
else:
found = True
print("3")
else:
if even1 == even3:
found = True
... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
length = int(input())
list_num = list(map(int, input().split()))
even1 = list_num[0] % 2
even2 = list_num[1] % 2
even3 = list_num[2] % 2
found = False
if even1 == even2:
if even1 == even3:
evenness = even1
else:
found = True
print("3")
else:
if even1 == even3:
fou... | 3.944928 | MatrixStudio/Codeforces-Python-Submissions |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,658,959,575 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 154 | 0 | n,m=[int(i) for i in input().split()]
a=[int(i) for i in input().split()]
a1=sorted(a)
maxpr,minpr=0,0
pas=n
for i in range(m):
while(a1[i]>0 and pas>0):
minpr+=a1[i]
a1[i]-=1
pas-=1
for j in range(n):
x=max(a)
maxpr+=x
a[a.index(x)]=a[a.index(x)]-1
print(str(maxpr)... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n,m=[int(i) for i in input().split()]
a=[int(i) for i in input().split()]
a1=sorted(a)
maxpr,minpr=0,0
pas=n
for i in range(m):
while(a1[i]>0 and pas>0):
minpr+=a1[i]
a1[i]-=1
pas-=1
for j in range(n):
x=max(a)
maxpr+=x
a[a.index(x)]=a[a.index(x)]-1
print(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,632,605,476 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 6,758,400 | '''
Author : Youssef Abbas
Date : 25/9/2021
Link : https://codeforces.com/problemset/problem/41/A
About : Translation
'''
str1 = input('First String : ')
str2 = input('Second String : ')
str2_r = str2[::-1]
if str1 ==str2_r:
print("YES")
else :
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
'''
Author : Youssef Abbas
Date : 25/9/2021
Link : https://codeforces.com/problemset/problem/41/A
About : Translation
'''
str1 = input('First String : ')
str2 = input('Second String : ')
str2_r = str2[::-1]
if str1 ==str2_r:
print("YES")
else :
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
405 | A | Gravity Flip | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the box arranged in a line. The *i*-th column contains *a**i* cubes. At first, the gravity in the box is... | The first line of input contains an integer *n* (1<=≤<=*n*<=≤<=100), the number of the columns in the box. The next line contains *n* space-separated integer numbers. The *i*-th number *a**i* (1<=≤<=*a**i*<=≤<=100) denotes the number of cubes in the *i*-th column. | Output *n* integer numbers separated by spaces, where the *i*-th number is the amount of cubes in the *i*-th column after the gravity switch. | [
"4\n3 2 1 2\n",
"3\n2 3 8\n"
] | [
"1 2 2 3 \n",
"2 3 8 \n"
] | The first example case is shown on the figure. The top cube of the first column falls to the top of the last column; the top cube of the second column falls to the top of the third column; the middle cube of the first column falls to the top of the second column.
In the second example case the gravity switch does not ... | 500 | [
{
"input": "4\n3 2 1 2",
"output": "1 2 2 3 "
},
{
"input": "3\n2 3 8",
"output": "2 3 8 "
},
{
"input": "5\n2 1 2 1 2",
"output": "1 1 2 2 2 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n4 3",
"output": "3 4 "
},
{
"input": "6\n100 40 60 20... | 1,691,506,078 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | n=int(input())
ls=list(map(int,input().split()))
print(ls.sort()) | Title: Gravity Flip
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the bo... | ```python
n=int(input())
ls=list(map(int,input().split()))
print(ls.sort())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,695,581,775 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | n = int(input())
k = 0
for c in [100, 20, 10, 5, 1]:
k += n // c
n %= c
print(k)
| Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
n = int(input())
k = 0
for c in [100, 20, 10, 5, 1]:
k += n // c
n %= c
print(k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,638,878,979 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 1,000 | 0 | n=int(input())
str1=str(input())
while '01' in str1:
str1=str1.replace('01','')
while '10' in str1:
str1=str1.replace('10','')
print(len(str1))
| Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
n=int(input())
str1=str(input())
while '01' in str1:
str1=str1.replace('01','')
while '10' in str1:
str1=str1.replace('10','')
print(len(str1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, inf... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word bec... | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,683,982,400 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 77 | 2,252,800 | import collections
import sys
input = sys.stdin.readline
n = int(input())
data = list(input().rstrip())
f = collections.deque()
s = collections.deque()
chk = True
for i in range(n - 1, -1, -1):
if chk:
s.appendleft(data[i])
else:
f.append(data[i])
chk = not chk
prin... | Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the... | ```python
import collections
import sys
input = sys.stdin.readline
n = int(input())
data = list(input().rstrip())
f = collections.deque()
s = collections.deque()
chk = True
for i in range(n - 1, -1, -1):
if chk:
s.appendleft(data[i])
else:
f.append(data[i])
chk = not c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it la... | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on... | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,662,471,456 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | import math
def get():
return list(map(int, input().split()))
def intput():
return int(input())
def rec(i,w):
if (i==0):
return 0
return i+rec(i//w,w)
def main():
arr=get()
l=arr[0]
r=arr[0]//arr[1]+arr[0]
while l <r:
if (l %arr[1]==... | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th... | ```python
import math
def get():
return list(map(int, input().split()))
def intput():
return int(input())
def rec(i,w):
if (i==0):
return 0
return i+rec(i//w,w)
def main():
arr=get()
l=arr[0]
r=arr[0]//arr[1]+arr[0]
while l <r:
if (l... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
630 | C | Lucky Numbers | PROGRAMMING | 1,100 | [
"combinatorics",
"math"
] | null | null | The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than *n* digits. | The only line of input contains one integer *n* (1<=≤<=*n*<=≤<=55) — the maximum length of a number that a door-plate can hold. | Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than *n* digits. | [
"2\n"
] | [
"6"
] | none | 0 | [
{
"input": "2",
"output": "6"
},
{
"input": "1",
"output": "2"
},
{
"input": "3",
"output": "14"
},
{
"input": "5",
"output": "62"
},
{
"input": "12",
"output": "8190"
},
{
"input": "34",
"output": "34359738366"
},
{
"input": "43",
"out... | 1,694,892,643 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 |
a=int(input())
print(2**a+2) | Title: Lucky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building o... | ```python
a=int(input())
print(2**a+2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,618,618,585 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 154 | 0 | number = int(input())
lengths = [int(i) for i in input().split()]
repeated = []
for i in lengths:
repeated.append(lengths.count(i))
height = max(repeated)
length1 = len(set(lengths))
print(height, length1) | Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
number = int(input())
lengths = [int(i) for i in input().split()]
repeated = []
for i in lengths:
repeated.append(lengths.count(i))
height = max(repeated)
length1 = len(set(lengths))
print(height, length1)
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,641,942,613 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 122 | 0 | def transpose(board):
n = len(board)
m = len(board[0])
ans = [['.'] * n for _ in range(m)]
for i in range(n):
for j in range(m):
ans[j][i] = board[i][j]
return ans
def whittle(board):
target = []
n = len(board)
m = len(board[0])
for i in range(n):
if board[i]... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
def transpose(board):
n = len(board)
m = len(board[0])
ans = [['.'] * n for _ in range(m)]
for i in range(n):
for j in range(m):
ans[j][i] = board[i][j]
return ans
def whittle(board):
target = []
n = len(board)
m = len(board[0])
for i in range(n):
i... | 0 | MatrixStudio/Codeforces-Python-Submissions |
884 | A | Book Reading | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of seconds that Luba has to spend working during *i*-th day is *a**i*. If some free time remains, she... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=100, 1<=≤<=*t*<=≤<=106) — the number of days and the time required to read the book.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=86400) — the time Luba has to spend on her work during *i*-th day. | Print the minimum day Luba can finish reading the book.
It is guaranteed that answer doesn't exceed *n*. | [
"2 2\n86400 86398\n",
"2 86400\n0 86400\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "2 2\n86400 86398",
"output": "2"
},
{
"input": "2 86400\n0 86400",
"output": "1"
},
{
"input": "2 86400\n1 86399",
"output": "2"
},
{
"input": "100 1000000\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,685,580,173 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | t = list(input())
a = input()
print((86400-a[-1])) | Title: Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of ... | ```python
t = list(input())
a = input()
print((86400-a[-1]))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
955 | A | Feed the cat | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without food increases his hunger by *D* points.
At any time Andrew can visit the store where tasty buns are... | The first line contains two integers *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59) — the time of Andrew's awakening.
The second line contains four integers *H*, *D*, *C* and *N* (1<=≤<=*H*<=≤<=105,<=1<=≤<=*D*,<=*C*,<=*N*<=≤<=102). | Output the minimum amount of money to within three decimal digits. You answer is considered correct, if its absolute or relative error does not exceed 10<=-<=4.
Formally, let your answer be *a*, and the jury's answer be *b*. Your answer is considered correct if . | [
"19 00\n255 1 100 1\n",
"17 41\n1000 6 15 11\n"
] | [
"25200.0000\n",
"1365.0000\n"
] | In the first sample Andrew can visit the store at exactly 20:00. The cat's hunger will be equal to 315, hence it will be necessary to purchase 315 buns. The discount makes the final answer 25200 roubles.
In the second sample it's optimal to visit the store right after he wakes up. Then he'll have to buy 91 bins per 15... | 500 | [
{
"input": "19 00\n255 1 100 1",
"output": "25200.0000"
},
{
"input": "17 41\n1000 6 15 11",
"output": "1365.0000"
},
{
"input": "16 34\n61066 14 50 59",
"output": "43360.0000"
},
{
"input": "18 18\n23331 86 87 41",
"output": "49590.0000"
},
{
"input": "10 48\n684... | 1,521,829,475 | 6,575 | Python 3 | OK | TESTS | 34 | 93 | 7,065,600 | # Standard Input
import sys
def main():
file = sys.stdin # we can read the input from this file
line1 = file.readline()
line2 = file.readline() # get the two lines
hour, minute = line1.split()
H, D, C, N = line2.split()
hour, minute = int(hour), int(minute)
H, D, C, N = in... | Title: Feed the cat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without foo... | ```python
# Standard Input
import sys
def main():
file = sys.stdin # we can read the input from this file
line1 = file.readline()
line2 = file.readline() # get the two lines
hour, minute = line1.split()
H, D, C, N = line2.split()
hour, minute = int(hour), int(minute)
H, D,... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
35 | A | Shell Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Shell Game | 2 | 64 | Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly puts a small ball under one of the cups and starts to shuffle the cups around very quickly so ... | The first input line contains an integer from 1 to 3 — index of the cup which covers the ball before the shuffles. The following three lines describe the shuffles. Each description of a shuffle contains two distinct integers from 1 to 3 — indexes of the cups which the performer shuffled this time. The cups are numbered... | In the first line output an integer from 1 to 3 — index of the cup which will have the ball after all the shuffles. | [
"1\n1 2\n2 1\n2 1\n",
"1\n2 1\n3 1\n1 3\n"
] | [
"2\n",
"2\n"
] | none | 500 | [
{
"input": "1\n1 2\n2 1\n2 1",
"output": "2"
},
{
"input": "1\n2 1\n3 1\n1 3",
"output": "2"
},
{
"input": "3\n3 1\n2 1\n1 2",
"output": "1"
},
{
"input": "1\n1 3\n1 2\n2 3",
"output": "2"
},
{
"input": "3\n3 2\n3 1\n3 1",
"output": "2"
},
{
"input": "... | 1,459,966,874 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 4,608,000 | fhand = open("input.txt")
i = 0
position = 0
lst = [1,2,3]
for line in fhand:
if i == 0:
p = int(line)
i = 1
else:
f, s = map(int, line.split())
if p == f:
position = s
elif p == s:
position = s
else:
continue
fh... | Title: Shell Game
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly put... | ```python
fhand = open("input.txt")
i = 0
position = 0
lst = [1,2,3]
for line in fhand:
if i == 0:
p = int(line)
i = 1
else:
f, s = map(int, line.split())
if p == f:
position = s
elif p == s:
position = s
else:
co... | 0 | MatrixStudio/Codeforces-Python-Submissions |
883 | E | Field of Wonders | PROGRAMMING | 1,500 | [
"implementation",
"strings"
] | null | null | Polycarpus takes part in the "Field of Wonders" TV show. The participants of the show have to guess a hidden word as fast as possible. Initially all the letters of the word are hidden.
The game consists of several turns. At each turn the participant tells a letter and the TV show host responds if there is such letter ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=50) — the length of the hidden word.
The following line describes already revealed letters. It contains the string of length *n*, which consists of lowercase Latin letters and symbols "*". If there is a letter at some position, then this letter was already reveale... | Output the single integer — the number of letters Polycarpus can tell so that the TV show host definitely reveals at least one more letter. It is possible that this number is zero. | [
"4\na**d\n2\nabcd\nacbd\n",
"5\nlo*er\n2\nlover\nloser\n",
"3\na*a\n2\naaa\naba\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first example Polycarpus can tell letters "b" and "c", which assuredly will be revealed.
The second example contains no letters which can be told as it is not clear, which of the letters "v" or "s" is located at the third position of the hidden word.
In the third example Polycarpus exactly knows that the hidde... | 0 | [
{
"input": "4\na**d\n2\nabcd\nacbd",
"output": "2"
},
{
"input": "5\nlo*er\n2\nlover\nloser",
"output": "0"
},
{
"input": "3\na*a\n2\naaa\naba",
"output": "1"
},
{
"input": "1\n*\n1\na",
"output": "1"
},
{
"input": "1\n*\n1\nz",
"output": "1"
},
{
"inp... | 1,508,575,325 | 2,225 | Python 3 | WRONG_ANSWER | TESTS1 | 11 | 77 | 6,451,200 | from string import ascii_lowercase as lower
char = int(input())
s = input()
new = [input() for k in range(int(input()))]
used = set()
can_be_said = set(lower)
indices = []
for index in range(char):
if s[index] != '*':
used.add(s[index])
else:
indices.append(index)
for word ... | Title: Field of Wonders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus takes part in the "Field of Wonders" TV show. The participants of the show have to guess a hidden word as fast as possible. Initially all the letters of the word are hidden.
The game consists of several tur... | ```python
from string import ascii_lowercase as lower
char = int(input())
s = input()
new = [input() for k in range(int(input()))]
used = set()
can_be_said = set(lower)
indices = []
for index in range(char):
if s[index] != '*':
used.add(s[index])
else:
indices.append(index)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,651,660,490 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n=int(input())
lst=list(map(int,input().split()))
neg=0;zero=0;bst=[];z=[]
for num in lst:
if num==0:z.append(0);continue
elif num<0 and neg==0: neg=num
else : bst.append(num)
print(1,neg)
print(len(bst),end=' ')
for num in bst : print(num,end=' ')
print()
print(len(z),end=' ')
for num in z : print(num,end=... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
n=int(input())
lst=list(map(int,input().split()))
neg=0;zero=0;bst=[];z=[]
for num in lst:
if num==0:z.append(0);continue
elif num<0 and neg==0: neg=num
else : bst.append(num)
print(1,neg)
print(len(bst),end=' ')
for num in bst : print(num,end=' ')
print()
print(len(z),end=' ')
for num in z : prin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,575,209,746 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 124 | 0 | n=int(input())
if n%3==0:print((n//3)*2)
else:print(2*(n//3)+1) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
n=int(input())
if n%3==0:print((n//3)*2)
else:print(2*(n//3)+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
523 | A | Rotate, Flip and Zoom | PROGRAMMING | 1,200 | [
"*special",
"implementation"
] | null | null | Polycarp is writing the prototype of a graphic editor. He has already made up his mind that the basic image transformations in his editor will be: rotate the image 90 degrees clockwise, flip the image horizontally (symmetry relative to the vertical line, that is, the right part of the image moves to the left, and vice ... | The first line contains two integers, *w* and *h* (1<=≤<=*w*,<=*h*<=≤<=100) — the width and height of an image in pixels. The picture is given in *h* lines, each line contains *w* characters — each character encodes the color of the corresponding pixel of the image. The line consists only of characters "." and "*", as ... | Print 2*w* lines, each containing 2*h* characters — the result of consecutive implementing of the three transformations, described above. | [
"3 2\n.*.\n.*.\n",
"9 20\n**.......\n****.....\n******...\n*******..\n..******.\n....****.\n......***\n*.....***\n*********\n*********\n*********\n*********\n....**...\n...****..\n..******.\n.********\n****..***\n***...***\n**.....**\n*.......*\n"
] | [
"....\n....\n****\n****\n....\n....\n",
"********......**********........********\n********......**********........********\n********........********......********..\n********........********......********..\n..********......********....********....\n..********......********....********....\n..********......*****... | none | 500 | [
{
"input": "3 2\n.*.\n.*.",
"output": "....\n....\n****\n****\n....\n...."
},
{
"input": "9 20\n**.......\n****.....\n******...\n*******..\n..******.\n....****.\n......***\n*.....***\n*********\n*********\n*********\n*********\n....**...\n...****..\n..******.\n.********\n****..***\n***...***\n**....... | 1,426,372,086 | 26,886 | PyPy 3 | OK | TESTS | 24 | 109 | 1,638,400 | import sys
w, h = map(int, sys.stdin.readline().split())
grid = []
for i in range(h):
grid.append(sys.stdin.readline().strip())
for j in range(w):
res = []
for i in range(h):
res.append(grid[i][j] * 2)
sys.stdout.write(''.join(res) + '\n')
sys.stdout.write(''.join(res) + '\n')
| Title: Rotate, Flip and Zoom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is writing the prototype of a graphic editor. He has already made up his mind that the basic image transformations in his editor will be: rotate the image 90 degrees clockwise, flip the image horizontally... | ```python
import sys
w, h = map(int, sys.stdin.readline().split())
grid = []
for i in range(h):
grid.append(sys.stdin.readline().strip())
for j in range(w):
res = []
for i in range(h):
res.append(grid[i][j] * 2)
sys.stdout.write(''.join(res) + '\n')
sys.stdout.write(''.join(res) + '\n')
`... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,659,306,116 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 102,400 | import sys
sys.setrecursionlimit(4000)
import math
from collections import Counter
from collections import defaultdict
from collections import deque
input = sys.stdin.readline
import heapq
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(ma... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
import sys
sys.setrecursionlimit(4000)
import math
from collections import Counter
from collections import defaultdict
from collections import deque
input = sys.stdin.readline
import heapq
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
retu... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
5 | B | Center Alignment | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | B. Center Alignment | 1 | 64 | Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.
You are to implement the alignment in the shortest possible time. Good luck! | The input file consists of one or more lines, each of the lines contains Latin letters, digits and/or spaces. The lines cannot start or end with a space. It is guaranteed that at least one of the lines has positive length. The length of each line and the total amount of the lines do not exceed 1000. | Format the given text, aligning it center. Frame the whole text with characters «*» of the minimum size. If a line cannot be aligned perfectly (for example, the line has even length, while the width of the block is uneven), you should place such lines rounding down the distance to the left or to the right edge and brin... | [
"This is\n\nCodeforces\nBeta\nRound\n5\n",
"welcome to the\nCodeforces\nBeta\nRound 5\n\nand\ngood luck\n"
] | [
"************\n* This is *\n* *\n*Codeforces*\n* Beta *\n* Round *\n* 5 *\n************\n",
"****************\n*welcome to the*\n* Codeforces *\n* Beta *\n* Round 5 *\n* *\n* and *\n* good luck *\n****************\n"
] | none | 0 | [
{
"input": "This is\n\nCodeforces\nBeta\nRound\n5",
"output": "************\n* This is *\n* *\n*Codeforces*\n* Beta *\n* Round *\n* 5 *\n************"
},
{
"input": "welcome to the\nCodeforces\nBeta\nRound 5\n\nand\ngood luck",
"output": "****************\n*welcome to th... | 1,629,573,306 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import sys
lines=sys.stdin.readlines()
l_arr=[]
ss
def sstrs(max_len){
for i in range(max_len):
ss=ss+'*'
print(ss)
}
for i in lines:
i=i.replce('\n','')
l_arr.append(len(i))
outp=[]
for i in lines:
while nn<max(lines)-len(i):
if nn%2==0:
i=" "+i
else:
i=i+" "
nn+=1
sstrs(max(l_a... | Title: Center Alignment
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.
You ... | ```python
import sys
lines=sys.stdin.readlines()
l_arr=[]
ss
def sstrs(max_len){
for i in range(max_len):
ss=ss+'*'
print(ss)
}
for i in lines:
i=i.replce('\n','')
l_arr.append(len(i))
outp=[]
for i in lines:
while nn<max(lines)-len(i):
if nn%2==0:
i=" "+i
else:
i=i+" "
nn+=1
sst... | -1 | MatrixStudio/Codeforces-Python-Submissions |
560 | A | Currency System in Geraldion | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of ea... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes. | Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1. | [
"5\n1 2 3 4 5\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "10\n371054 506438 397130 1 766759 208409 769264 549213 641270 771837",
"output": "-1"
},
{
"input": "10\n635370 154890 909382 220996 276501 716105 538714 140162 171960 271264",
"o... | 1,685,199,652 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | def f(n):
s=list(map(int,input().split()))
s.sort()
for a in range(1,3):
if a not in s:
return a
else:
return -1
z=2*max(s)
l=len(s)
i=l
# for j in range(z+1,2*z+1):
print(f(int(input())))
| Title: Currency System in Geraldion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cann... | ```python
def f(n):
s=list(map(int,input().split()))
s.sort()
for a in range(1,3):
if a not in s:
return a
else:
return -1
z=2*max(s)
l=len(s)
i=l
# for j in range(z+1,2*z+1):
print(f(int(input())))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,547,618,612 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 124 | 0 | a=int(input())
q=1
while a//((5*(2**q))-5)>1:
q=q+1
x=a%((5*(2**q))-5)
y=(2**q)-1
if x==0:
print("Howard")
else:
if x<=(2**q)-1:
print("Sheldon")
elif y<x<=2*y:
print("Leonard")
elif 2*y<x<=3*y:
print("Penny")
elif 3*y<x<=4*y:
print("Rajesh")
... | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
a=int(input())
q=1
while a//((5*(2**q))-5)>1:
q=q+1
x=a%((5*(2**q))-5)
y=(2**q)-1
if x==0:
print("Howard")
else:
if x<=(2**q)-1:
print("Sheldon")
elif y<x<=2*y:
print("Leonard")
elif 2*y<x<=3*y:
print("Penny")
elif 3*y<x<=4*y:
print("Raje... | 0 | MatrixStudio/Codeforces-Python-Submissions |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,561,467,562 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 109 | 0 | n, m, z =[int(i) for i in input().split()]
a, b = n, m
while n!=0 and m!=0:
if n>m:
n%=m
else:
m%=n
if n==0:
d=m
else:
d=n
print(z//((a*b)//d)) | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
n, m, z =[int(i) for i in input().split()]
a, b = n, m
while n!=0 and m!=0:
if n>m:
n%=m
else:
m%=n
if n==0:
d=m
else:
d=n
print(z//((a*b)//d))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
807 | A | Is it rated? | PROGRAMMING | 900 | [
"implementation",
"sortings"
] | null | null | Is it rated?
Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to answer it.
Another Codeforces round has been conducted. No two participants have the same number of points. For each participant, from the top to the bottom of the standings, their rating before ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of round participants.
Each of the next *n* lines contains two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=4126) — the rating of the *i*-th participant before and after the round, respectively. The participants are listed in order... | If the round is rated for sure, print "rated". If the round is unrated for sure, print "unrated". If it's impossible to determine whether the round is rated or not, print "maybe". | [
"6\n3060 3060\n2194 2194\n2876 2903\n2624 2624\n3007 2991\n2884 2884\n",
"4\n1500 1500\n1300 1300\n1200 1200\n1400 1400\n",
"5\n3123 3123\n2777 2777\n2246 2246\n2246 2246\n1699 1699\n"
] | [
"rated\n",
"unrated\n",
"maybe\n"
] | In the first example, the ratings of the participants in the third and fifth places have changed, therefore, the round was rated.
In the second example, no one's rating has changed, but the participant in the second place has lower rating than the participant in the fourth place. Therefore, if the round was rated, som... | 500 | [
{
"input": "6\n3060 3060\n2194 2194\n2876 2903\n2624 2624\n3007 2991\n2884 2884",
"output": "rated"
},
{
"input": "4\n1500 1500\n1300 1300\n1200 1200\n1400 1400",
"output": "unrated"
},
{
"input": "5\n3123 3123\n2777 2777\n2246 2246\n2246 2246\n1699 1699",
"output": "maybe"
},
{
... | 1,622,624,084 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 78 | 0 | n = int(input())
a = []
b = []
for i in range(n):
temp = [int(x) for x in input().split()]
a.append(temp[0])
b.append(temp[1])
print(a, b)
b1 = False
for i in range(n):
if a[i] != b[i]:
print('rated')
bool = True
break
b2 = False
if not b1:
for i in range(1, n... | Title: Is it rated?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Is it rated?
Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to answer it.
Another Codeforces round has been conducted. No two participants have the same number ... | ```python
n = int(input())
a = []
b = []
for i in range(n):
temp = [int(x) for x in input().split()]
a.append(temp[0])
b.append(temp[1])
print(a, b)
b1 = False
for i in range(n):
if a[i] != b[i]:
print('rated')
bool = True
break
b2 = False
if not b1:
for i in ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
955 | C | Sad powers | PROGRAMMING | 2,100 | [
"binary search",
"math",
"number theory"
] | null | null | You're given *Q* queries of the form (*L*,<=*R*).
For each query you have to find the number of such *x* that *L*<=≤<=*x*<=≤<=*R* and there exist integer numbers *a*<=><=0, *p*<=><=1 such that *x*<==<=*a**p*. | The first line contains the number of queries *Q* (1<=≤<=*Q*<=≤<=105).
The next *Q* lines contains two integers *L*, *R* each (1<=≤<=*L*<=≤<=*R*<=≤<=1018). | Output *Q* lines — the answers to the queries. | [
"6\n1 4\n9 9\n5 7\n12 29\n137 591\n1 1000000\n"
] | [
"2\n1\n0\n3\n17\n1111\n"
] | In query one the suitable numbers are 1 and 4. | 1,500 | [
{
"input": "6\n1 4\n9 9\n5 7\n12 29\n137 591\n1 1000000",
"output": "2\n1\n0\n3\n17\n1111"
},
{
"input": "20\n862 928\n758 964\n541 789\n622 943\n328 900\n14 764\n217 972\n461 847\n442 468\n900 986\n518 529\n938 993\n549 851\n690 944\n484 601\n320 910\n98 868\n816 915\n765 880\n551 770",
"output... | 1,521,829,022 | 6,122 | Python 3 | WRONG_ANSWER | PRETESTS | 1 | 77 | 7,065,600 | coof = [0, 0, -1, -1, 0, -1, 1, -1, 0, 0, 1, -1, 0, -1, 1, 1, 0, -1, 0, -1, 0, 1, 1, -1, 0, 0, 1, 0, 0, -1, -1, -1, 0, 1, 1, 1, 0, -1, 1, 1, 0, -1, -1, -1, 0, 0, 1, -1, 0, 0, 0, 1, 0, -1, 0, 1, 0, 1, 1, -1, 0, -1, 1, 0, 0]
def get_prefix(m):
f = [0, 0] + [int(pow(m, (1 / i))) for i in range(2, 65)]
ans =... | Title: Sad powers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You're given *Q* queries of the form (*L*,<=*R*).
For each query you have to find the number of such *x* that *L*<=≤<=*x*<=≤<=*R* and there exist integer numbers *a*<=><=0, *p*<=><=1 such that *x*<==<=*a**p*.
Input ... | ```python
coof = [0, 0, -1, -1, 0, -1, 1, -1, 0, 0, 1, -1, 0, -1, 1, 1, 0, -1, 0, -1, 0, 1, 1, -1, 0, 0, 1, 0, 0, -1, -1, -1, 0, 1, 1, 1, 0, -1, 1, 1, 0, -1, -1, -1, 0, 0, 1, -1, 0, 0, 0, 1, 0, -1, 0, 1, 0, 1, 1, -1, 0, -1, 1, 0, 0]
def get_prefix(m):
f = [0, 0] + [int(pow(m, (1 / i))) for i in range(2, 65)]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
446 | A | DZY Loves Sequences | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"two pointers"
] | null | null | DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | In a single line print the answer to the problem — the maximum length of the required subsegment. | [
"6\n7 2 3 1 5 6\n"
] | [
"5\n"
] | You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | 500 | [
{
"input": "6\n7 2 3 1 5 6",
"output": "5"
},
{
"input": "10\n424238336 649760493 681692778 714636916 719885387 804289384 846930887 957747794 596516650 189641422",
"output": "9"
},
{
"input": "50\n804289384 846930887 681692778 714636916 957747794 424238336 719885387 649760493 596516650 1... | 1,599,641,379 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 140 | 0 | n = int(input())
arr = list(map(int, input().split()))
def dzy(n, arr):
dp = {}
Max = 1
for i in range(n):
dp[i] = {0: 1, 1: 1}
if i == 0: continue
elif i == 1:
if arr[i] > arr[i - 1]:
dp[i][0], dp[i][1] = 2, 2
... | Title: DZY Loves Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the... | ```python
n = int(input())
arr = list(map(int, input().split()))
def dzy(n, arr):
dp = {}
Max = 1
for i in range(n):
dp[i] = {0: 1, 1: 1}
if i == 0: continue
elif i == 1:
if arr[i] > arr[i - 1]:
dp[i][0], dp[i][... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and... | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, ... | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer ... | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,445,764,578 | 978 | Python 3 | OK | TESTS | 45 | 77 | 0 | l=int(input().strip())
p=int(input().strip())
q=int(input().strip())
ans=(l*p)/(p+q)
print(ans)
| Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the en... | ```python
l=int(input().strip())
p=int(input().strip())
q=int(input().strip())
ans=(l*p)/(p+q)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
899 | A | Splitting in Teams | PROGRAMMING | 800 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The coach decided to form teams of exactly three people for this training. Determine the maximum number of tea... | The first line contains single integer *n* (2<=≤<=*n*<=≤<=2·105) — the number of groups.
The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), where *a**i* is the number of people in group *i*. | Print the maximum number of teams of three people the coach can form. | [
"4\n1 1 2 1\n",
"2\n2 2\n",
"7\n2 2 2 1 1 1 1\n",
"3\n1 1 1\n"
] | [
"1\n",
"0\n",
"3\n",
"1\n"
] | In the first example the coach can form one team. For example, he can take students from the first, second and fourth groups.
In the second example he can't make a single team.
In the third example the coach can form three teams. For example, he can do this in the following way:
- The first group (of two people) an... | 500 | [
{
"input": "4\n1 1 2 1",
"output": "1"
},
{
"input": "2\n2 2",
"output": "0"
},
{
"input": "7\n2 2 2 1 1 1 1",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "3\n2 2 2",
"output": "0"
},
{
"input": "3\n1 2 1",
"output": "1"
}... | 1,588,831,667 | 2,147,483,647 | Python 3 | OK | TESTS | 67 | 139 | 10,649,600 | """
https://codeforces.com/problemset/problem/899/A
"""
n = int(input())
people = list(map(int, input().split()))
ones = people.count(1)
twos = people.count(2)
if ones < twos:
print(ones)
else:
print(twos + (ones - twos) // 3) | Title: Splitting in Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The co... | ```python
"""
https://codeforces.com/problemset/problem/899/A
"""
n = int(input())
people = list(map(int, input().split()))
ones = people.count(1)
twos = people.count(2)
if ones < twos:
print(ones)
else:
print(twos + (ones - twos) // 3)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
916 | A | Jamie and Alarm Snooze | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every *x* minutes until *hh*:<=*mm* is reached, and only then he will wake up. He ... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=60).
The second line contains two two-digit integers, *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59). | Print the minimum number of times he needs to press the button. | [
"3\n11 23\n",
"5\n01 07\n"
] | [
"2\n",
"0\n"
] | In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.
In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky. | 500 | [
{
"input": "3\n11 23",
"output": "2"
},
{
"input": "5\n01 07",
"output": "0"
},
{
"input": "34\n09 24",
"output": "3"
},
{
"input": "2\n14 37",
"output": "0"
},
{
"input": "14\n19 54",
"output": "9"
},
{
"input": "42\n15 44",
"output": "12"
},
... | 1,516,828,316 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 5,529,600 | x=int(input())
h=int(input())
m=int(input())
count=0
while(m%10!=7):
count=count+1
m=m-x
if(m<0):
h=h-1
m=60+m;
print (count) | Title: Jamie and Alarm Snooze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will the... | ```python
x=int(input())
h=int(input())
m=int(input())
count=0
while(m%10!=7):
count=count+1
m=m-x
if(m<0):
h=h-1
m=60+m;
print (count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
285 | A | Slightly Decreasing Permutations | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
The ... | The single line contains two space-separated integers: *n*,<=*k* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*k*<=<<=*n*) — the permutation length and the decreasing coefficient. | In a single line print *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* — the permutation of length *n* with decreasing coefficient *k*.
If there are several permutations that meet this condition, print any of them. It is guaranteed that the permutation with the sought parameters exists. | [
"5 2\n",
"3 0\n",
"3 2\n"
] | [
"1 5 2 4 3\n",
"1 2 3\n",
"3 2 1\n"
] | none | 500 | [
{
"input": "5 2",
"output": "1 5 2 4 3"
},
{
"input": "3 0",
"output": "1 2 3"
},
{
"input": "3 2",
"output": "3 2 1"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output": "1 2"
},
{
"input": "2 1",
"output": "2 1"
},
{
"input":... | 1,657,983,247 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 342 | 0 | def miis():
return map(int, input().split())
n, k = miis()
for i in range(k):
print(n-i, end=' ')
for i in range(n-k):
print(i+1, end=' ')
| Title: Slightly Decreasing Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutat... | ```python
def miis():
return map(int, input().split())
n, k = miis()
for i in range(k):
print(n-i, end=' ')
for i in range(n-k):
print(i+1, end=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,598,627,550 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | n = int(input())
i = 1
a = []
while(n < i *2):
n -= i
a.append(i)
i += 1
a.append(n)
print(len(a))
print(''.join(map(str, a))) | Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
n = int(input())
i = 1
a = []
while(n < i *2):
n -= i
a.append(i)
i += 1
a.append(n)
print(len(a))
print(''.join(map(str, a)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
662 | C | Binary Table | PROGRAMMING | 2,600 | [
"bitmasks",
"brute force",
"divide and conquer",
"dp",
"fft",
"math"
] | null | null | You are given a table consisting of *n* rows and *m* columns. Each cell of the table contains either 0 or 1. In one move, you are allowed to pick any row or any column and invert all values, that is, replace 0 by 1 and vice versa.
What is the minimum number of cells with value 1 you can get after applying some number ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=20, 1<=≤<=*m*<=≤<=100<=000) — the number of rows and the number of columns, respectively.
Then *n* lines follows with the descriptions of the rows. Each line has length *m* and contains only digits '0' and '1'. | Output a single integer — the minimum possible number of ones you can get after applying some sequence of operations. | [
"3 4\n0110\n1010\n0111\n"
] | [
"2\n"
] | none | 2,250 | [
{
"input": "3 4\n0110\n1010\n0111",
"output": "2"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n0\n1",
"output": "0"
},
{
"input": "1 2\n10",
"output": "0"
},
{
"input": "2 2\n01\n10",
"output": "0"... | 1,679,548,999 | 499 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | m.n=map(int,input().split(" "))
c=[]
for i in range(m):
k=list(map(int,input().split(" ")))
c.append(k)
k=[sum(i) for i in c]
x=max(k)
print(n-x)
| Title: Binary Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a table consisting of *n* rows and *m* columns. Each cell of the table contains either 0 or 1. In one move, you are allowed to pick any row or any column and invert all values, that is, replace 0 by 1 and vic... | ```python
m.n=map(int,input().split(" "))
c=[]
for i in range(m):
k=list(map(int,input().split(" ")))
c.append(k)
k=[sum(i) for i in c]
x=max(k)
print(n-x)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
103 | B | Cthulhu | PROGRAMMING | 1,500 | [
"dfs and similar",
"dsu",
"graphs"
] | B. Cthulhu | 2 | 256 | ...Once upon a time a man came to the sea. The sea was stormy and dark. The man started to call for the little mermaid to appear but alas, he only woke up Cthulhu...
Whereas on the other end of the world Pentagon is actively collecting information trying to predict the monster's behavior and preparing the secret super... | The first line contains two integers — the number of vertices *n* and the number of edges *m* of the graph (1<=≤<=*n*<=≤<=100, 0<=≤<=*m*<=≤<=).
Each of the following *m* lines contains a pair of integers *x* and *y*, that show that an edge exists between vertices *x* and *y* (1<=≤<=*x*,<=*y*<=≤<=*n*,<=*x*<=≠<=*y*). Fo... | Print "NO", if the graph is not Cthulhu and "FHTAGN!" if it is. | [
"6 6\n6 3\n6 4\n5 1\n2 5\n1 4\n5 4\n",
"6 5\n5 6\n4 6\n3 1\n5 1\n1 2\n"
] | [
"FHTAGN!",
"NO"
] | Let us denote as a simple cycle a set of *v* vertices that can be numbered so that the edges will only exist between vertices number 1 and 2, 2 and 3, ..., *v* - 1 and *v*, *v* and 1.
A tree is a connected undirected graph consisting of *n* vertices and *n* - 1 edges (*n* > 0).
A rooted tree is a tree where one ve... | 1,000 | [
{
"input": "6 6\n6 3\n6 4\n5 1\n2 5\n1 4\n5 4",
"output": "FHTAGN!"
},
{
"input": "6 5\n5 6\n4 6\n3 1\n5 1\n1 2",
"output": "NO"
},
{
"input": "10 10\n4 10\n8 5\n2 8\n4 9\n9 3\n2 7\n10 6\n10 2\n9 8\n1 8",
"output": "FHTAGN!"
},
{
"input": "5 4\n1 5\n1 3\n1 4\n3 2",
"outpu... | 1,539,744,791 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 280 | 102,400 | MAX = 101
parent = []
def makeSet():
global parent
parent = [i for i in range(MAX + 1)]
def findSet(u):
while u != parent[u]:
u = parent[u]
return u
def unionSet(u, v):
up = findSet(u)
vp = findSet(v)
parent[up] = vp
makeSet()
n, m = map(int, input().split())
... | Title: Cthulhu
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
...Once upon a time a man came to the sea. The sea was stormy and dark. The man started to call for the little mermaid to appear but alas, he only woke up Cthulhu...
Whereas on the other end of the world Pentagon is actively colle... | ```python
MAX = 101
parent = []
def makeSet():
global parent
parent = [i for i in range(MAX + 1)]
def findSet(u):
while u != parent[u]:
u = parent[u]
return u
def unionSet(u, v):
up = findSet(u)
vp = findSet(v)
parent[up] = vp
makeSet()
n, m = map(int, input().s... | 3.929809 | MatrixStudio/Codeforces-Python-Submissions |
821 | C | Okabe and Boxes | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"trees"
] | null | null | Okabe and Super Hacker Daru are stacking and removing boxes. There are *n* boxes numbered from 1 to *n*. Initially there are no boxes on the stack.
Okabe, being a control freak, gives Daru 2*n* commands: *n* of which are to add a box to the top of the stack, and *n* of which are to remove a box from the top of the sta... | The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of boxes.
Each of the next 2*n* lines of input starts with a string "add" or "remove". If the line starts with the "add", an integer *x* (1<=≤<=*x*<=≤<=*n*) follows, indicating that Daru should add the box with number *x* to the top of... | Print the minimum number of times Daru needs to reorder the boxes to successfully complete all of Okabe's commands. | [
"3\nadd 1\nremove\nadd 2\nadd 3\nremove\nremove\n",
"7\nadd 3\nadd 2\nadd 1\nremove\nadd 4\nremove\nremove\nremove\nadd 6\nadd 7\nadd 5\nremove\nremove\nremove\n"
] | [
"1\n",
"2\n"
] | In the first sample, Daru should reorder the boxes after adding box 3 to the stack.
In the second sample, Daru should reorder the boxes after adding box 4 and box 7 to the stack. | 1,500 | [
{
"input": "3\nadd 1\nremove\nadd 2\nadd 3\nremove\nremove",
"output": "1"
},
{
"input": "7\nadd 3\nadd 2\nadd 1\nremove\nadd 4\nremove\nremove\nremove\nadd 6\nadd 7\nadd 5\nremove\nremove\nremove",
"output": "2"
},
{
"input": "4\nadd 1\nadd 3\nremove\nadd 4\nadd 2\nremove\nremove\nremov... | 1,499,155,465 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
#define ll long long
#define Add_Speed ios_base::sync_with_stdio(0);cin.tie(NULL);
#define pb push_back
#define mp make_pair
#define sz size()
#define f first
#define pii pair<int, int>
#define s second
#define ppi pair<int, pair<int, int> >
#define all(s) s.begin(), s.end()
#define... | Title: Okabe and Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Okabe and Super Hacker Daru are stacking and removing boxes. There are *n* boxes numbered from 1 to *n*. Initially there are no boxes on the stack.
Okabe, being a control freak, gives Daru 2*n* commands: *n* of which a... | ```python
#include<bits/stdc++.h>
#define ll long long
#define Add_Speed ios_base::sync_with_stdio(0);cin.tie(NULL);
#define pb push_back
#define mp make_pair
#define sz size()
#define f first
#define pii pair<int, int>
#define s second
#define ppi pair<int, pair<int, int> >
#define all(s) s.begin(), s.end(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=2,<=2] and [1,<=2,<=3] is not.
A permutation triple of permutations of length *n* (*a*,<=... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If no Lucky Permutation Triple of length *n* exists print -1.
Otherwise, you need to print three lines. Each line contains *n* space-seperated integers. The first line must contain permutation *a*, the second line — permutation *b*, the third — permutation *c*.
If there are multiple solutions, print any of them. | [
"5\n",
"2\n"
] | [
"1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3\n",
"-1\n"
] | In Sample 1, the permutation triple ([1, 4, 3, 2, 0], [1, 0, 2, 4, 3], [2, 4, 0, 1, 3]) is Lucky Permutation Triple, as following holds:
- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a6bf1b9b57809dbec5021f65f89616f259587c07.png" style="max-width: 100.0%;max-height: 100.0%;"/>; - <img... | 0 | [
{
"input": "5",
"output": "1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3"
},
{
"input": "2",
"output": "-1"
},
{
"input": "8",
"output": "-1"
},
{
"input": "9",
"output": "0 1 2 3 4 5 6 7 8 \n0 1 2 3 4 5 6 7 8 \n0 2 4 6 8 1 3 5 7 "
},
{
"input": "2",
"output": "-1"
},
{... | 1,508,230,433 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 122 | 5,529,600 | n = int(input())
if n == 3 or n == 5:
a, b, c = [], [], []
for i in range(n):
a.append(i)
b.append(i)
c.append((i+i)%n)
print(*a)
print(*b)
print(*c)
else:
print(-1)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=... | ```python
n = int(input())
if n == 3 or n == 5:
a, b, c = [], [], []
for i in range(n):
a.append(i)
b.append(i)
c.append((i+i)%n)
print(*a)
print(*b)
print(*c)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,686,406,341 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 92 | 0 | n=int(input())
ne=[] ; po=[] ; z=[] ... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
n=int(input())
ne=[] ; po=[] ; z=[] ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,691,985,827 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 62 | 0 | word = input()
if word[0].islower() and word[1:].isupper():
print(word.title())
elif word.isupper():
print(word.lower())
elif len(word) == 1 and word.islower():
print(word.upper())
else:
print(word) | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
word = input()
if word[0].islower() and word[1:].isupper():
print(word.title())
elif word.isupper():
print(word.lower())
elif len(word) == 1 and word.islower():
print(word.upper())
else:
print(word)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
468 | A | 24 Game | PROGRAMMING | 1,500 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of *n* integers: 1,<=2,<=...,<=*n*. In a single step, you can pick two of them, let's denote them *a* and *b*, erase them from the sequence, and append to the sequence eit... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following *n*<=-<=1 lines print the required operations an operation per line. Each operation should be in form: "*a* *op* *b* = *c*". Where *a* and *b* are the numbe... | [
"1\n",
"8\n"
] | [
"NO\n",
"YES\n8 * 7 = 56\n6 * 5 = 30\n3 - 4 = -1\n1 - 2 = -1\n30 - -1 = 31\n56 - 31 = 25\n25 + -1 = 24\n"
] | none | 500 | [
{
"input": "1",
"output": "NO"
},
{
"input": "8",
"output": "YES\n8 * 7 = 56\n6 * 5 = 30\n3 - 4 = -1\n1 - 2 = -1\n30 - -1 = 31\n56 - 31 = 25\n25 + -1 = 24"
},
{
"input": "12",
"output": "YES\n3 * 4 = 12\n2 * 1 = 2\n12 * 2 = 24\n6 - 5 = 1\n24 * 1 = 24\n8 - 7 = 1\n24 * 1 = 24\n10 - 9 =... | 1,566,869,654 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 124 | 102,400 | import sys
n = int(input())
variable = n
resultado = 12
contador=0
if n>=4:
print("YES")
else:
print("NO")
sys.exit
if n%2==0:
contador=1
for i in range(n-1):
if(variable>4):
print(""+str(variable)+" - "+str(variable-1)+" = 1")
variable-=2
contador+=1
else:
resultado = variable*... | Title: 24 Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of *n* integers: 1,<=2,<=...,<=*n*. In a single step, you can pick two of them... | ```python
import sys
n = int(input())
variable = n
resultado = 12
contador=0
if n>=4:
print("YES")
else:
print("NO")
sys.exit
if n%2==0:
contador=1
for i in range(n-1):
if(variable>4):
print(""+str(variable)+" - "+str(variable-1)+" = 1")
variable-=2
contador+=1
else:
resultado =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
919 | D | Substring | PROGRAMMING | 1,700 | [
"dfs and similar",
"dp",
"graphs"
] | null | null | You are given a graph with $n$ nodes and $m$ directed edges. One lowercase letter is assigned to each node. We define a path's value as the number of the most frequently occurring letter. For example, if letters on a path are "abaca", then the value of that path is $3$. Your task is find a path whose value is the large... | The first line contains two positive integers $n, m$ ($1 \leq n, m \leq 300\,000$), denoting that the graph has $n$ nodes and $m$ directed edges.
The second line contains a string $s$ with only lowercase English letters. The $i$-th character is the letter assigned to the $i$-th node.
Then $m$ lines follow. Each line ... | Output a single line with a single integer denoting the largest value. If the value can be arbitrarily large, output -1 instead. | [
"5 4\nabaca\n1 2\n1 3\n3 4\n4 5\n",
"6 6\nxzyabc\n1 2\n3 1\n2 3\n5 4\n4 3\n6 4\n",
"10 14\nxzyzyzyzqx\n1 2\n2 4\n3 5\n4 5\n2 6\n6 8\n6 5\n2 10\n3 9\n10 9\n4 6\n1 10\n2 8\n3 7\n"
] | [
"3\n",
"-1\n",
"4\n"
] | In the first sample, the path with largest value is $1 \to 3 \to 4 \to 5$. The value is $3$ because the letter 'a' appears $3$ times. | 1,500 | [
{
"input": "5 4\nabaca\n1 2\n1 3\n3 4\n4 5",
"output": "3"
},
{
"input": "6 6\nxzyabc\n1 2\n3 1\n2 3\n5 4\n4 3\n6 4",
"output": "-1"
},
{
"input": "10 14\nxzyzyzyzqx\n1 2\n2 4\n3 5\n4 5\n2 6\n6 8\n6 5\n2 10\n3 9\n10 9\n4 6\n1 10\n2 8\n3 7",
"output": "4"
},
{
"input": "1 1\nf... | 1,622,615,770 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | n=int(input())
m=int(input())
s=input()
l={}
x=list(map(int,input().split()))
y=list(map(int,input().split()))
for i in range(0,len(x)):
l[x[i]]=l.get(x[i],[])
l[x[i]].append(y[i])
def f(n,z):
if n in l.keys() and n not in vis:
j=0
vis.append(n)
#print(vis)
for ... | Title: Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a graph with $n$ nodes and $m$ directed edges. One lowercase letter is assigned to each node. We define a path's value as the number of the most frequently occurring letter. For example, if letters on a path are... | ```python
n=int(input())
m=int(input())
s=input()
l={}
x=list(map(int,input().split()))
y=list(map(int,input().split()))
for i in range(0,len(x)):
l[x[i]]=l.get(x[i],[])
l[x[i]].append(y[i])
def f(n,z):
if n in l.keys() and n not in vis:
j=0
vis.append(n)
#print(vis)
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
808 | A | Lucky Year | PROGRAMMING | 900 | [
"implementation"
] | null | null | Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland. | Output amount of years from the current year to the next lucky one. | [
"4\n",
"201\n",
"4000\n"
] | [
"1\n",
"99\n",
"1000\n"
] | In the first example next lucky year is 5. In the second one — 300. In the third — 5000. | 0 | [
{
"input": "4",
"output": "1"
},
{
"input": "201",
"output": "99"
},
{
"input": "4000",
"output": "1000"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "1",
"output": "1"
},
{
"input": "100000000",
"ou... | 1,678,451,867 | 2,147,483,647 | Python 3 | OK | TESTS | 271 | 46 | 0 | def lucky_year(n):
if 0<n<10:
return 1
a,i,p = n,0,1
while a>0:
i+=1
a//=10
p *=10
p//=10
return (n//p+1)*p-n
n = int(input())
print(lucky_year(n)) | Title: Lucky Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 1... | ```python
def lucky_year(n):
if 0<n<10:
return 1
a,i,p = n,0,1
while a>0:
i+=1
a//=10
p *=10
p//=10
return (n//p+1)*p-n
n = int(input())
print(lucky_year(n))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,582,008,886 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | n = int(input())
arr = list(map(int,input().split()))
# arr = [7, 20, 88]
def minMinute(arr):
t = 0
for i in range (len(arr)):
if arr[i] - t >= t +15:
return t+15
else:
t = arr[i]
print(minMinute(arr)) | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int(input())
arr = list(map(int,input().split()))
# arr = [7, 20, 88]
def minMinute(arr):
t = 0
for i in range (len(arr)):
if arr[i] - t >= t +15:
return t+15
else:
t = arr[i]
print(minMinute(arr))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,677,950,965 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | a,b=map(int,input().split())
k=min(a,b)
ans1=k
ans2=(max(a,b)-k)//2
print(ans1,ans2)
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
a,b=map(int,input().split())
k=min(a,b)
ans1=k
ans2=(max(a,b)-k)//2
print(ans1,ans2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope wi... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,587,891,040 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 622 | 307,200 | import sys
n=int(input())
x1,x2=0,0
for i in range(n,-1,-1):
x=n-7*i
if x<0:
continue
else:
if x%4==0:
x1=i
x2=int(x/4)
break
else :
x1=0
x2=0
print(-1) if x1==0 and x2==0 else print('4'*x2 +'7'*x1)
| Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
import sys
n=int(input())
x1,x2=0,0
for i in range(n,-1,-1):
x=n-7*i
if x<0:
continue
else:
if x%4==0:
x1=i
x2=int(x/4)
break
else :
x1=0
x2=0
print(-1) if x1==0 and x2==0 else print('4'*x2 +'7... | 3.843928 | MatrixStudio/Codeforces-Python-Submissions |
520 | A | Pangram | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
You are given a string consisting of lowercase and uppercase Latin letters. Check whether thi... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of characters in the string.
The second line contains the string. The string consists only of uppercase and lowercase Latin letters. | Output "YES", if the string is a pangram and "NO" otherwise. | [
"12\ntoosmallword\n",
"35\nTheQuickBrownFoxJumpsOverTheLazyDog\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "12\ntoosmallword",
"output": "NO"
},
{
"input": "35\nTheQuickBrownFoxJumpsOverTheLazyDog",
"output": "YES"
},
{
"input": "1\na",
"output": "NO"
},
{
"input": "26\nqwertyuiopasdfghjklzxcvbnm",
"output": "YES"
},
{
"input": "26\nABCDEFGHIJKLMNOPQRSTUVWXY... | 1,696,423,765 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | def pangrams(s):
s=s.lower()
alphabet="abcdefghijklmnopqrstuvwxyz"
for i in alphabet:
if i not in s:
return "NO"
return "YES"
n=int(input())
k=input()
if n<26:
print("NO")
else:
print(pangrams(k))
| Title: Pangram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
... | ```python
def pangrams(s):
s=s.lower()
alphabet="abcdefghijklmnopqrstuvwxyz"
for i in alphabet:
if i not in s:
return "NO"
return "YES"
n=int(input())
k=input()
if n<26:
print("NO")
else:
print(pangrams(k))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,493,549,929 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 77 | 5,529,600 | import math
n = int(input())
print([math.ceil(n/4) - 1, 0][n % 2 != 0])
| Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
import math
n = int(input())
print([math.ceil(n/4) - 1, 0][n % 2 != 0])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
616 | D | Longest k-Good Segment | PROGRAMMING | 1,600 | [
"binary search",
"data structures",
"two pointers"
] | null | null | The array *a* with *n* integers is given. Let's call the sequence of one or more consecutive elements in *a* segment. Also let's call the segment k-good if it contains no more than *k* different values.
Find any longest k-good segment.
As the input/output can reach huge size it is recommended to use fast input/output... | The first line contains two integers *n*,<=*k* (1<=≤<=*k*<=≤<=*n*<=≤<=5·105) — the number of elements in *a* and the parameter *k*.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=106) — the elements of the array *a*. | Print two integers *l*,<=*r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in *a* are numbered from 1 to *n* from left to right. | [
"5 5\n1 2 3 4 5\n",
"9 3\n6 5 1 2 3 2 1 4 5\n",
"3 1\n1 2 3\n"
] | [
"1 5\n",
"3 7\n",
"1 1\n"
] | none | 0 | [
{
"input": "5 5\n1 2 3 4 5",
"output": "1 5"
},
{
"input": "9 3\n6 5 1 2 3 2 1 4 5",
"output": "3 7"
},
{
"input": "3 1\n1 2 3",
"output": "1 1"
},
{
"input": "1 1\n747391",
"output": "1 1"
},
{
"input": "5 2\n171230 171230 171230 171230 171230",
"output": "1 ... | 1,697,667,196 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 77 | 0 | from collections import defaultdict
def solve(n, m, a):
freq = defaultdict(int)
q = []
un = 0
res = 0
l = 0
r = 0
for i in range(n):
if freq[a[i]] == 0:
un += 1
q.append(a[i])
freq[a[i]] += 1
while q and un > m:
if freq[q.pop(0)] == 1:
un -= 1
if res < len(q):... | Title: Longest k-Good Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The array *a* with *n* integers is given. Let's call the sequence of one or more consecutive elements in *a* segment. Also let's call the segment k-good if it contains no more than *k* different values.
Find any... | ```python
from collections import defaultdict
def solve(n, m, a):
freq = defaultdict(int)
q = []
un = 0
res = 0
l = 0
r = 0
for i in range(n):
if freq[a[i]] == 0:
un += 1
q.append(a[i])
freq[a[i]] += 1
while q and un > m:
if freq[q.pop(0)] == 1:
un -= 1
if res... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,696,006,272 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a= int(input())
n=int(input())
w=int(input())
if a-2n=2w
print("YES")
else:
print("NO") | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
a= int(input())
n=int(input())
w=int(input())
if a-2n=2w
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
484 | B | Maximum Value | PROGRAMMING | 2,100 | [
"binary search",
"math",
"sortings",
"two pointers"
] | null | null | You are given a sequence *a* consisting of *n* integers. Find the maximum possible value of (integer remainder of *a**i* divided by *a**j*), where 1<=≤<=*i*,<=*j*<=≤<=*n* and *a**i*<=≥<=*a**j*. | The first line contains integer *n* — the length of the sequence (1<=≤<=*n*<=≤<=2·105).
The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=106). | Print the answer to the problem. | [
"3\n3 4 5\n"
] | [
"2\n"
] | none | 1,000 | [
{
"input": "3\n3 4 5",
"output": "2"
},
{
"input": "3\n1 2 4",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1000000",
"output": "0"
},
{
"input": "2\n1000000 999999",
"output": "1"
},
{
"input": "12\n4 4 10 13 28 30 41 43 58 61 7... | 1,419,148,691 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 38 | 1,000 | 18,329,600 | def main():
n = int(input())
aa = sorted(set(map(int, input().split())))
x = x2 = i = 0
for ai in reversed(aa):
if ai < x2:
break
while aa[i] < x:
i += 1
j = i
while aa[j] + x < ai:
t = ai % aa[j]
if x < t:
x... | Title: Maximum Value
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. Find the maximum possible value of (integer remainder of *a**i* divided by *a**j*), where 1<=≤<=*i*,<=*j*<=≤<=*n* and *a**i*<=≥<=*a**j*.
Input Specification:
The ... | ```python
def main():
n = int(input())
aa = sorted(set(map(int, input().split())))
x = x2 = i = 0
for ai in reversed(aa):
if ai < x2:
break
while aa[i] < x:
i += 1
j = i
while aa[j] + x < ai:
t = ai % aa[j]
if x < t:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,659,627,130 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 154 | 1,536,000 | b = input()
num0 = 0
i = 0
for char in b:
if char == '0':
num0 += 1
b = b[0:i] + b[i+1:]
break
i += 1
if num0 == 1:
print(b)
else:
# print()
if b == '1':
print(0)
else:
print(b[1:])
| Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
b = input()
num0 = 0
i = 0
for char in b:
if char == '0':
num0 += 1
b = b[0:i] + b[i+1:]
break
i += 1
if num0 == 1:
print(b)
else:
# print()
if b == '1':
print(0)
else:
print(b[1:])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,497,172,204 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 307,200 | import sys
import math
inf = 100000000
n = int(input())
a = [int(e) for e in input().split()]
f = [[0, 0, 0] for i in range(n)]
m = inf
f[0][0] = 1
if a[0] == 1 or a[0] == 3:
f[0][1] = 0
else:
f[0][1] = inf
if a[0] == 2 or a[0] == 3:
f[0][2] = 0
else:
f[0][2] = inf
if a[0] == 3:
f[0][1] = f[0][2] = inf
for i in ... | Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Int... | ```python
import sys
import math
inf = 100000000
n = int(input())
a = [int(e) for e in input().split()]
f = [[0, 0, 0] for i in range(n)]
m = inf
f[0][0] = 1
if a[0] == 1 or a[0] == 3:
f[0][1] = 0
else:
f[0][1] = inf
if a[0] == 2 or a[0] == 3:
f[0][2] = 0
else:
f[0][2] = inf
if a[0] == 3:
f[0][1] = f[0][2] = inf... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
50 | B | Choosing Symbol Pairs | PROGRAMMING | 1,500 | [
"strings"
] | B. Choosing Symbol Pairs | 2 | 256 | There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbol of string *S* is equal to the *j*-th. | The single input line contains *S*, consisting of lowercase Latin letters and digits. It is guaranteed that string *S* in not empty and its length does not exceed 105. | Print a single number which represents the number of pairs *i* and *j* with the needed property. Pairs (*x*,<=*y*) and (*y*,<=*x*) should be considered different, i.e. the ordered pairs count. | [
"great10\n",
"aaaaaaaaaa\n"
] | [
"7\n",
"100\n"
] | none | 1,000 | [
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "aabb",
"output": "8"
},
{
"input": "w",
"output": "1"
},
{
"in... | 1,616,568,823 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 124 | 0 | s=input()
d={}
cnt=0
k=0
for c in s:
d[c]=d.get(c,0)+1
ls=list(d.values())
for i in ls:
if i>1:
cnt+=i
elif i==1:
k+=1
else:
break
if sum(ls)>len(ls):
print(cnt**2)
else:
print(k)
| Title: Choosing Symbol Pairs
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbo... | ```python
s=input()
d={}
cnt=0
k=0
for c in s:
d[c]=d.get(c,0)+1
ls=list(d.values())
for i in ls:
if i>1:
cnt+=i
elif i==1:
k+=1
else:
break
if sum(ls)>len(ls):
print(cnt**2)
else:
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,618,748,618 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 6 | 622 | 8,089,600 | number = int(input())
def f(num):
res =0
while num !=0:
res +=num%10
num = int(num / 10)
return res
num_of_iter =0
while True :
if number >=10:
num_of_iter+=1
number = f(number)
else :
break
print(num_of_iter) | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
number = int(input())
def f(num):
res =0
while num !=0:
res +=num%10
num = int(num / 10)
return res
num_of_iter =0
while True :
if number >=10:
num_of_iter+=1
number = f(number)
else :
break
print(num_of_iter)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
437 | A | The Child and Homework | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Once upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D. Each choice has a description, and the child should find out the only one that is correct.
Fortunately the child knows how to solve such complicated test. The chi... | The first line starts with "A." (without quotes), then followed the description of choice A. The next three lines contains the descriptions of the other choices in the same format. They are given in order: B, C, D. Please note, that the description goes after prefix "X.", so the prefix mustn't be counted in description... | Print a single line with the child's choice: "A", "B", "C" or "D" (without quotes). | [
"A.VFleaKing_is_the_author_of_this_problem\nB.Picks_is_the_author_of_this_problem\nC.Picking_is_the_author_of_this_problem\nD.Ftiasch_is_cute\n",
"A.ab\nB.abcde\nC.ab\nD.abc\n",
"A.c\nB.cc\nC.c\nD.c\n"
] | [
"D\n",
"C\n",
"B\n"
] | In the first sample, the first choice has length 39, the second one has length 35, the third one has length 37, and the last one has length 15. The choice D (length 15) is twice shorter than all other choices', so it is great choice. There is no other great choices so the child will choose D.
In the second sample, no ... | 500 | [
{
"input": "A.VFleaKing_is_the_author_of_this_problem\nB.Picks_is_the_author_of_this_problem\nC.Picking_is_the_author_of_this_problem\nD.Ftiasch_is_cute",
"output": "D"
},
{
"input": "A.ab\nB.abcde\nC.ab\nD.abc",
"output": "C"
},
{
"input": "A.c\nB.cc\nC.c\nD.c",
"output": "B"
},
... | 1,685,524,199 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 27 | 62 | 0 | #Cypher
#Indian Institute Of Technology, Jodhpur
import sys
input = lambda: sys.stdin.readline().rstrip()
mod= 10**9+7
l=[]
lund=[]
for i in range(4):
l.append(input())
a=len(l[0])-2
b=len(l[1])-2
c=len(l[2])-2
d=len(l[3])-2
lund.append(a)
lund.append(b)
lund.append(c)
lund.append(d)
lund.sort()
i... | Title: The Child and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D. Each choice has a description, and the child should fin... | ```python
#Cypher
#Indian Institute Of Technology, Jodhpur
import sys
input = lambda: sys.stdin.readline().rstrip()
mod= 10**9+7
l=[]
lund=[]
for i in range(4):
l.append(input())
a=len(l[0])-2
b=len(l[1])-2
c=len(l[2])-2
d=len(l[3])-2
lund.append(a)
lund.append(b)
lund.append(c)
lund.append(d)
lund... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
765 | A | Neverending competitions | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.
Jinotega's best friends, team ... | In the first line of input there is a single integer *n*: the number of Jinotega's flights (1<=≤<=*n*<=≤<=100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next *n* lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX"... | If Jinotega is now at home, print "home" (without quotes), otherwise print "contest". | [
"4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO\n",
"3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP\n"
] | [
"home\n",
"contest\n"
] | In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list. | 500 | [
{
"input": "4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO",
"output": "home"
},
{
"input": "3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP",
"output": "contest"
},
{
"input": "1\nESJ\nESJ->TSJ",
"output": "contest"
},
{
"input": "2\nXMR\nFAJ->XMR\nXMR->FAJ",
"output": "home"
},
... | 1,637,201,300 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | n = int(input())
home = input().strip()
isHome = True
count = 0
for _ in range(n):
src, dest = input().split("->")
if dest == home:
count += 1
if (count == n // 2):
print("home")
else:
print("contest")
| Title: Neverending competitions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from thei... | ```python
n = int(input())
home = input().strip()
isHome = True
count = 0
for _ in range(n):
src, dest = input().split("->")
if dest == home:
count += 1
if (count == n // 2):
print("home")
else:
print("contest")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
548 | A | Mike and Fax | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"strings"
] | null | null | While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly *k* messages ... | The first line of input contains string *s* containing lowercase English letters (1<=≤<=|*s*|<=≤<=1000).
The second line contains integer *k* (1<=≤<=*k*<=≤<=1000). | Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise. | [
"saba\n2\n",
"saddastavvat\n2\n"
] | [
"NO\n",
"YES\n"
] | Palindrome is a string reading the same forward and backward.
In the second sample, the faxes in his back-bag can be "saddas" and "tavvat". | 500 | [
{
"input": "saba\n2",
"output": "NO"
},
{
"input": "saddastavvat\n2",
"output": "YES"
},
{
"input": "aaaaaaaaaa\n3",
"output": "NO"
},
{
"input": "aaaaaa\n3",
"output": "YES"
},
{
"input": "abaacca\n2",
"output": "NO"
},
{
"input": "a\n1",
"output"... | 1,587,998,699 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 124 | 0 | s=input()
k=int(input())
n=len(s)
c=0
kk=n//k
for i in range(0,n,kk):
x=s[i:i+kk]
if(x==x[::-1]):
c=c+1
if(c==k):
print('YES')
else:
print('NO')
| Title: Mike and Fax
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure ... | ```python
s=input()
k=int(input())
n=len(s)
c=0
kk=n//k
for i in range(0,n,kk):
x=s[i:i+kk]
if(x==x[::-1]):
c=c+1
if(c==k):
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,694,783,004 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | def min_steps(x):
return (x + 4) // 5 # 加4是为了实现向上取整
# 示例
print(min_steps(5)) # 输出：1
| Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
def min_steps(x):
return (x + 4) // 5 # 加4是为了实现向上取整
# 示例
print(min_steps(5)) # 输出：1
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,570,536,622 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 280 | 0 | n,m = map(int,input().split())
l = list(map(int,input().split()))
min =0
max =0
temp = sorted(l)
for i in range(n):
if len(l) >0:
l.sort(reverse = True)
max += l[0]
l[0] -= 1
if 0 in l:
l.remove(0)
min += temp[0]
temp[0] -= 1
if 0 in ... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n,m = map(int,input().split())
l = list(map(int,input().split()))
min =0
max =0
temp = sorted(l)
for i in range(n):
if len(l) >0:
l.sort(reverse = True)
max += l[0]
l[0] -= 1
if 0 in l:
l.remove(0)
min += temp[0]
temp[0] -= 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,660,553,584 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | for t in range(int(input())):
n=int(input())
if(n%2==1):
print(-1)
else:
arr=[i for i in range(1,n+1)]
for i in range(1,n,2):
arr[i],arr[i-1]=arr[i-1],arr[i]
print(*arr,sep=' ') | Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
for t in range(int(input())):
n=int(input())
if(n%2==1):
print(-1)
else:
arr=[i for i in range(1,n+1)]
for i in range(1,n,2):
arr[i],arr[i-1]=arr[i-1],arr[i]
print(*arr,sep=' ')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
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