contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
15 | A | Cottage Village | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Cottage Village | 2 | 64 | A new cottage village called «Flatville» is being built in Flatland. By now they have already built in «Flatville» *n* square houses with the centres on the *Оx*-axis. The houses' sides are parallel to the coordinate axes. It's known that no two houses overlap, but they can touch each other.
The architect bureau, wher... | The first line of the input data contains numbers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=1000). Then there follow *n* lines, each of them contains two space-separated integer numbers: *x**i* *a**i*, where *x**i* — *x*-coordinate of the centre of the *i*-th house, and *a**i* — length of its side (<=-<=1000<=≤<=*x**i*<=≤<=1000... | Output the amount of possible positions of the new house. | [
"2 2\n0 4\n6 2\n",
"2 2\n0 4\n5 2\n",
"2 3\n0 4\n5 2\n"
] | [
"4\n",
"3\n",
"2\n"
] | It is possible for the *x*-coordinate of the new house to have non-integer value. | 0 | [
{
"input": "2 2\n0 4\n6 2",
"output": "4"
},
{
"input": "2 2\n0 4\n5 2",
"output": "3"
},
{
"input": "2 3\n0 4\n5 2",
"output": "2"
},
{
"input": "1 1\n1 1",
"output": "2"
},
{
"input": "1 2\n2 1",
"output": "2"
},
{
"input": "2 1\n2 1\n1 1",
"outp... | 1,587,643,244 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 310 | 1,638,400 | n, t = map(int, input().split())
center_length = []
for i in range(n):
center, length = map(int, input().split())
center_length.append([center, length])
center_length = sorted(center_length, key=lambda x: x[0])
answer = 2
for i in range(len(center_length)-1):
dist = abs(center_length[i+1][0] - cen... | Title: Cottage Village
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A new cottage village called «Flatville» is being built in Flatland. By now they have already built in «Flatville» *n* square houses with the centres on the *Оx*-axis. The houses' sides are parallel to the coordinate axes. I... | ```python
n, t = map(int, input().split())
center_length = []
for i in range(n):
center, length = map(int, input().split())
center_length.append([center, length])
center_length = sorted(center_length, key=lambda x: x[0])
answer = 2
for i in range(len(center_length)-1):
dist = abs(center_length[i+1... | 3.910293 | MatrixStudio/Codeforces-Python-Submissions |
682 | B | Alyona and Mex | PROGRAMMING | 1,200 | [
"sortings"
] | null | null | Someone gave Alyona an array containing *n* positive integers *a*1,<=*a*2,<=...,<=*a**n*. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer that is smaller than the current one. Alyona can repeat this operation as many times as she wants. In particular,... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of elements in the Alyona's array.
The second line of the input contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the array. | Print one positive integer — the maximum possible value of mex of the array after Alyona applies some (possibly none) operations. | [
"5\n1 3 3 3 6\n",
"2\n2 1\n"
] | [
"5\n",
"3\n"
] | In the first sample case if one will decrease the second element value to 2 and the fifth element value to 4 then the mex value of resulting array 1 2 3 3 4 will be equal to 5.
To reach the answer to the second sample case one must not decrease any of the array elements. | 1,000 | [
{
"input": "5\n1 3 3 3 6",
"output": "5"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "1\n1",
"output": "2"
},
{
"input": "1\n1000000000",
"output": "2"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n1 1",
"output": "2"
},
{
"... | 1,636,307,380 | 2,147,483,647 | Python 3 | OK | TESTS | 127 | 109 | 13,926,400 | n = int(input())
a=input().split()
a = [int(i) for i in a]
a.sort()
k=0
for j in range(n):
if a[j]<j+1-k:
k=k+1
print(n+1-k) | Title: Alyona and Mex
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someone gave Alyona an array containing *n* positive integers *a*1,<=*a*2,<=...,<=*a**n*. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer that is small... | ```python
n = int(input())
a=input().split()
a = [int(i) for i in a]
a.sort()
k=0
for j in range(n):
if a[j]<j+1-k:
k=k+1
print(n+1-k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,629,447,274 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 186 | 20,172,800 | s='44'+input()
print('YNEOS'[any(i in s for i in'02356789')or'444'in s::2]) | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
s='44'+input()
print('YNEOS'[any(i in s for i in'02356789')or'444'in s::2])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | C | Roads in Berland | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Roads in Berland | 2 | 256 | There are *n* cities numbered from 1 to *n* in Berland. Some of them are connected by two-way roads. Each road has its own length — an integer number from 1 to 1000. It is known that from each city it is possible to get to any other city by existing roads. Also for each pair of cities it is known the shortest distance ... | The first line contains integer *n* (2<=≤<=*n*<=≤<=300) — amount of cities in Berland. Then there follow *n* lines with *n* integer numbers each — the matrix of shortest distances. *j*-th integer in the *i*-th row — *d**i*,<=*j*, the shortest distance between cities *i* and *j*. It is guaranteed that *d**i*,<=*i*<==<=0... | Output *k* space-separated integers *q**i* (1<=≤<=*i*<=≤<=*k*). *q**i* should be equal to the sum of shortest distances between all pairs of cities after the construction of roads with indexes from 1 to *i*. Roads are numbered from 1 in the input order. Each pair of cities should be taken into account in the sum exactl... | [
"2\n0 5\n5 0\n1\n1 2 3\n",
"3\n0 4 5\n4 0 9\n5 9 0\n2\n2 3 8\n1 2 1\n"
] | [
"3 ",
"17 12 "
] | none | 0 | [
{
"input": "2\n0 5\n5 0\n1\n1 2 3",
"output": "3 "
},
{
"input": "3\n0 4 5\n4 0 9\n5 9 0\n2\n2 3 8\n1 2 1",
"output": "17 12 "
},
{
"input": "3\n0 983 173\n983 0 810\n173 810 0\n3\n3 2 567\n2 3 767\n1 2 763",
"output": "1480 1480 1480 "
},
{
"input": "4\n0 537 1064 656\n537 0... | 1,521,671,532 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 186 | 21,401,600 | dic,thesum = {},0
for rownr in range(int(input())):
row = list(map(int, input().split(" ")))
for i in range(rownr):
dic[(i, rownr)] = row[i]
thesum +=row[i]
#print(dic)
result = []
roads = int(input())
for notused in range(roads):
a,b,c = list(map(int, input().split(" ")))
if a > b: a,b = b,a
a -=1
b-=1
if d... | Title: Roads in Berland
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* cities numbered from 1 to *n* in Berland. Some of them are connected by two-way roads. Each road has its own length — an integer number from 1 to 1000. It is known that from each city it is possible to get to... | ```python
dic,thesum = {},0
for rownr in range(int(input())):
row = list(map(int, input().split(" ")))
for i in range(rownr):
dic[(i, rownr)] = row[i]
thesum +=row[i]
#print(dic)
result = []
roads = int(input())
for notused in range(roads):
a,b,c = list(map(int, input().split(" ")))
if a > b: a,b = b,a
a -=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
616 | E | Sum of Remainders | PROGRAMMING | 2,200 | [
"implementation",
"math",
"number theory"
] | null | null | Calculate the value of the sum: *n* mod 1 + *n* mod 2 + *n* mod 3 + ... + *n* mod *m*. As the result can be very large, you should print the value modulo 109<=+<=7 (the remainder when divided by 109<=+<=7).
The modulo operator *a* mod *b* stands for the remainder after dividing *a* by *b*. For example 10 mod 3 = 1. | The only line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1013) — the parameters of the sum. | Print integer *s* — the value of the required sum modulo 109<=+<=7. | [
"3 4\n",
"4 4\n",
"1 1\n"
] | [
"4\n",
"1\n",
"0\n"
] | none | 0 | [
{
"input": "3 4",
"output": "4"
},
{
"input": "4 4",
"output": "1"
},
{
"input": "1 1",
"output": "0"
},
{
"input": "20000000 10000000",
"output": "176305083"
},
{
"input": "10000000000000 10000000000000",
"output": "869957328"
},
{
"input": "1 1000000... | 1,644,927,426 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | def solve(n, m):
if m > n:
return solve(n, n) + n * (m - n)
if m <= 7:
return sum([n % i for i in range(1, m+1)])
# Arithmetic progression
v = solve(n, 7)
num = m - 7
a0 = n - 8
delta = (2 * a0 - num + 1) * num // 2
return v + delta
M = 20
def stri... | Title: Sum of Remainders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calculate the value of the sum: *n* mod 1 + *n* mod 2 + *n* mod 3 + ... + *n* mod *m*. As the result can be very large, you should print the value modulo 109<=+<=7 (the remainder when divided by 109<=+<=7).
The modul... | ```python
def solve(n, m):
if m > n:
return solve(n, n) + n * (m - n)
if m <= 7:
return sum([n % i for i in range(1, m+1)])
# Arithmetic progression
v = solve(n, 7)
num = m - 7
a0 = n - 8
delta = (2 * a0 - num + 1) * num // 2
return v + delta
M = 20
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
592 | C | The Big Race | PROGRAMMING | 1,800 | [
"math"
] | null | null | Vector Willman and Array Bolt are the two most famous athletes of Byteforces. They are going to compete in a race with a distance of *L* meters today.
Willman and Bolt have exactly the same speed, so when they compete the result is always a tie. That is a problem for the organizers because they want a winner.
While ... | The first line of the input contains three integers *t*, *w* and *b* (1<=≤<=*t*,<=*w*,<=*b*<=≤<=5·1018) — the maximum possible length of the racetrack, the length of Willman's steps and the length of Bolt's steps respectively. | Print the answer to the problem as an irreducible fraction . Follow the format of the samples output.
The fraction (*p* and *q* are integers, and both *p*<=≥<=0 and *q*<=><=0 holds) is called irreducible, if there is no such integer *d*<=><=1, that both *p* and *q* are divisible by *d*. | [
"10 3 2\n",
"7 1 2\n"
] | [
"3/10\n",
"3/7\n"
] | In the first sample Willman and Bolt will tie in case 1, 6 or 7 are chosen as the length of the racetrack. | 1,500 | [
{
"input": "10 3 2",
"output": "3/10"
},
{
"input": "7 1 2",
"output": "3/7"
},
{
"input": "1 1 1",
"output": "1/1"
},
{
"input": "5814 31 7",
"output": "94/2907"
},
{
"input": "94268 813 766",
"output": "765/94268"
},
{
"input": "262610 5583 4717",
... | 1,446,315,001 | 6,001 | Python 3 | WRONG_ANSWER | PRETESTS | 7 | 46 | 0 | import math
def gcd(a,b):
if(b==0):
return a
else:
return gcd(b,a%b)
a,b,c=map(int,input().split())
mv=min(b,c);
ans=mv-1
lcm=int(b*c/gcd(b,c))
cnt=math.floor(a/lcm)
ans += cnt*mv
gcd2 = gcd(ans,a)
print("%d/%d" % (ans/gcd2,a/gcd2))
| Title: The Big Race
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vector Willman and Array Bolt are the two most famous athletes of Byteforces. They are going to compete in a race with a distance of *L* meters today.
Willman and Bolt have exactly the same speed, so when they compete the... | ```python
import math
def gcd(a,b):
if(b==0):
return a
else:
return gcd(b,a%b)
a,b,c=map(int,input().split())
mv=min(b,c);
ans=mv-1
lcm=int(b*c/gcd(b,c))
cnt=math.floor(a/lcm)
ans += cnt*mv
gcd2 = gcd(ans,a)
print("%d/%d" % (ans/gcd2,a/gcd2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
825 | B | Five-In-a-Row | PROGRAMMING | 1,600 | [
"brute force",
"implementation"
] | null | null | Alice and Bob play 5-in-a-row game. They have a playing field of size 10<=×<=10. In turns they put either crosses or noughts, one at a time. Alice puts crosses and Bob puts noughts.
In current match they have made some turns and now it's Alice's turn. She wonders if she can put cross in such empty cell that she wins i... | You are given matrix 10<=×<=10 (10 lines of 10 characters each) with capital Latin letters 'X' being a cross, letters 'O' being a nought and '.' being an empty cell. The number of 'X' cells is equal to the number of 'O' cells and there is at least one of each type. There is at least one empty cell.
It is guaranteed th... | Print 'YES' if it's possible for Alice to win in one turn by putting cross in some empty cell. Otherwise print 'NO'. | [
"XX.XX.....\n.....OOOO.\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n",
"XXOXX.....\nOO.O......\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "O.......O.\n.....O.X..\n......O...\n....X.O...\n.O.O.....X\n.XO.....XX\n...X...X.O\n........O.\n........O.\n.X.X.....X",
"output": "NO"
},
{
"input": "....OX....\n..........\n.O..X...X.\nXXO..XO..O\nO.......X.\n...XX.....\n..O.O...OX\n.........X\n.....X..OO\n........O.",
"output": "N... | 1,500,305,300 | 2,147,483,647 | Python 3 | OK | TESTS | 156 | 77 | 4,915,200 | a=[]
for i in range(10):
a.append(input())
for i in range(6):
for j in range(6):
k,z=0,0
for x in range(5):
if a[i+x][j+x]=="X":
k+=1
else:
if a[i+x][j+x]==".":
z+=1
if k==5 or k==4 and z==1:
... | Title: Five-In-a-Row
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice and Bob play 5-in-a-row game. They have a playing field of size 10<=×<=10. In turns they put either crosses or noughts, one at a time. Alice puts crosses and Bob puts noughts.
In current match they have made some t... | ```python
a=[]
for i in range(10):
a.append(input())
for i in range(6):
for j in range(6):
k,z=0,0
for x in range(5):
if a[i+x][j+x]=="X":
k+=1
else:
if a[i+x][j+x]==".":
z+=1
if k==5 or k==4 and z==... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,689,579,136 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 31 | 0 | n = int(input())
sugar = ""
odd = "I hate that "
even = "I love that "
for i in range(1,n+1):
if i%2==0:
sugar+= even
else:
sugar+= odd
if i==n:
pp = sugar.split(" ")
pp[-2] = "it"
sugar = " ".join(pp)
print(sugar) | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
n = int(input())
sugar = ""
odd = "I hate that "
even = "I love that "
for i in range(1,n+1):
if i%2==0:
sugar+= even
else:
sugar+= odd
if i==n:
pp = sugar.split(" ")
pp[-2] = "it"
sugar = " ".join(pp)
print(sugar)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | As behooves any intelligent schoolboy, Kevin Sun is studying psycowlogy, cowculus, and cryptcowgraphy at the Bovinia State University (BGU) under Farmer Ivan. During his Mathematics of Olympiads (MoO) class, Kevin was confronted with a weird functional equation and needs your help. For two fixed integers *k* and *p*, w... | The input consists of two space-separated integers *p* and *k* (3<=≤<=*p*<=≤<=1<=000<=000, 0<=≤<=*k*<=≤<=*p*<=-<=1) on a single line. It is guaranteed that *p* is an odd prime number. | Print a single integer, the number of distinct functions *f* modulo 109<=+<=7. | [
"3 2\n",
"5 4\n"
] | [
"3\n",
"25\n"
] | In the first sample, *p* = 3 and *k* = 2. The following functions work:
1. *f*(0) = 0, *f*(1) = 1, *f*(2) = 2. 1. *f*(0) = 0, *f*(1) = 2, *f*(2) = 1. 1. *f*(0) = *f*(1) = *f*(2) = 0. | 0 | [
{
"input": "3 2",
"output": "3"
},
{
"input": "5 4",
"output": "25"
},
{
"input": "7 2",
"output": "49"
},
{
"input": "7 6",
"output": "343"
},
{
"input": "10007 25",
"output": "100140049"
},
{
"input": "40037 4",
"output": "602961362"
},
{
... | 1,520,628,406 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 33 | 1,000 | 9,113,600 | from sys import stdin
p, k = stdin.readline().rstrip().split(' ')
p = int(p); k = int(k)
if k==0:
print(((p)**(p-1)) % (10**9+7))
elif k==1:
print((p**p) % (10**9+7))
else:
n = k
order = 1
while n != 1:
n = (n*k) % p
order += 1
loops = (p-1) // order
print(pow(p, loops, 10**9+7))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As behooves any intelligent schoolboy, Kevin Sun is studying psycowlogy, cowculus, and cryptcowgraphy at the Bovinia State University (BGU) under Farmer Ivan. During his Mathematics of Olympiads (MoO) class, Kevin was confronted w... | ```python
from sys import stdin
p, k = stdin.readline().rstrip().split(' ')
p = int(p); k = int(k)
if k==0:
print(((p)**(p-1)) % (10**9+7))
elif k==1:
print((p**p) % (10**9+7))
else:
n = k
order = 1
while n != 1:
n = (n*k) % p
order += 1
loops = (p-1) // order
print(pow(p, loops, 10**9+7))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,637,370,589 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 62 | 0 | def solution(user_input):
s = 'hello'
for ch in s:
if user_input.find(ch) == -1:
return 'NO'
else:
user_input = user_input[user_input.find(ch)+1:]
return 'YES'
print(solution(input()))
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def solution(user_input):
s = 'hello'
for ch in s:
if user_input.find(ch) == -1:
return 'NO'
else:
user_input = user_input[user_input.find(ch)+1:]
return 'YES'
print(solution(input()))
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
276 | B | Little Girl and Game | PROGRAMMING | 1,300 | [
"games",
"greedy"
] | null | null | The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string *s*, consisting of lowercase English letters. They play a game that is described by the following rules:
- The players move in turns; In one move the player can remove an arbitrary letter from string *s*. - If the p... | The input contains a single line, containing string *s* (1<=≤<=|*s*|<=<=≤<=<=103). String *s* consists of lowercase English letters. | In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes. | [
"aba\n",
"abca\n"
] | [
"First\n",
"Second\n"
] | none | 1,000 | [
{
"input": "aba",
"output": "First"
},
{
"input": "abca",
"output": "Second"
},
{
"input": "aabb",
"output": "First"
},
{
"input": "ctjxzuimsxnarlciuynqeoqmmbqtagszuo",
"output": "Second"
},
{
"input": "gevqgtaorjixsxnbcoybr",
"output": "First"
},
{
"i... | 1,684,938,908 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 307,200 | from collections import Counter
s= input();c=0;c1=True
d=Counter(s)
while c1:
if s== s[::-1]:
c1=False
else:
s=list(s)
for i in s:
s.remove(str(d.most_common()[-1][0]))
s=''.join(s)
d[str(d.most_common()[-1][0])]-=1
... | Title: Little Girl and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string *s*, consisting of lowercase English letters. They play a game that is described by the following rules:
- The... | ```python
from collections import Counter
s= input();c=0;c1=True
d=Counter(s)
while c1:
if s== s[::-1]:
c1=False
else:
s=list(s)
for i in s:
s.remove(str(d.most_common()[-1][0]))
s=''.join(s)
d[str(d.most_common()[-1][0])]-=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,598,174,520 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 342 | 20,172,800 | n=input()
l=list(map(int,input().split()))
a=set(l)
f=list(a)
f.sort()
n=len(f)
print(f[n-2],end="")
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n=input()
l=list(map(int,input().split()))
a=set(l)
f=list(a)
f.sort()
n=len(f)
print(f[n-2],end="")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Emuskald is a well-known illusionist. One of his trademark tricks involves a set of magical boxes. The essence of the trick is in packing the boxes inside other boxes.
From the top view each magical box looks like a square with side length equal to 2*k* (*k* is an integer, *k*<=≥<=0) units. A magical box *v* can be pu... | The first line of input contains an integer *n* (1<=≤<=*n*<=≤<=105), the number of different sizes of boxes Emuskald has. Each of following *n* lines contains two integers *k**i* and *a**i* (0<=≤<=*k**i*<=≤<=109, 1<=≤<=*a**i*<=≤<=109), which means that Emuskald has *a**i* boxes with side length 2*k**i*. It is guarantee... | Output a single integer *p*, such that the smallest magical box that can contain all of Emuskald’s boxes has side length 2*p*. | [
"2\n0 3\n1 5\n",
"1\n0 4\n",
"2\n1 10\n2 2\n"
] | [
"3\n",
"1\n",
"3\n"
] | Picture explanation. If we have 3 boxes with side length 2 and 5 boxes with side length 1, then we can put all these boxes inside a box with side length 4, for example, as shown in the picture.
In the second test case, we can put all four small boxes into a box with side length 2. | 0 | [
{
"input": "2\n0 3\n1 5",
"output": "3"
},
{
"input": "1\n0 4",
"output": "1"
},
{
"input": "2\n1 10\n2 2",
"output": "3"
},
{
"input": "1\n0 1",
"output": "1"
},
{
"input": "1\n1000000000 1000000000",
"output": "1000000015"
},
{
"input": "1\n0 16",
... | 1,655,894,855 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | from cv2 import sort
def countbox(size, num):
if num <= 4 :
return size+1, 0
return size+1, num/4
line = int(input())
num = 0
size = 0
temp =[]
for l in range(line):
temp.append(tuple(map(int, input().split())))
tem = sorted(temp, key=lambda x: x[0])
# print(tem)
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald is a well-known illusionist. One of his trademark tricks involves a set of magical boxes. The essence of the trick is in packing the boxes inside other boxes.
From the top view each magical box looks like a square with s... | ```python
from cv2 import sort
def countbox(size, num):
if num <= 4 :
return size+1, 0
return size+1, num/4
line = int(input())
num = 0
size = 0
temp =[]
for l in range(line):
temp.append(tuple(map(int, input().split())))
tem = sorted(temp, key=lambda x: x[0])
# print(te... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope wi... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,679,526,334 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | entrada = int(input())
num4 = entrada // 4
num7 = entrada // 7
soma = 0
list = []
qntDigits4 = 0
i = 0
bol = False
while i < num4 + 1:
soma = i*4
if(i != 0):
qntDigits4 +=1
qntDigits7 = 0
if(soma == entrada):
print(qntDigits4)
print(qntDigits7)
... | Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
entrada = int(input())
num4 = entrada // 4
num7 = entrada // 7
soma = 0
list = []
qntDigits4 = 0
i = 0
bol = False
while i < num4 + 1:
soma = i*4
if(i != 0):
qntDigits4 +=1
qntDigits7 = 0
if(soma == entrada):
print(qntDigits4)
print(qntDigits7... | 0 | MatrixStudio/Codeforces-Python-Submissions |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,695,039,069 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | s = input()
s2 = ""
len_s = len(s)
for i in range(len_s):
if s[i] == '.':
s2 += '0'
if s[i] == '-' and s[i+1] == '.':
s2 += '1'
i += 1
if s[i] == '-' and s[i+1] == '-':
s2 += '2'
i += 1
print(s2) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s = input()
s2 = ""
len_s = len(s)
for i in range(len_s):
if s[i] == '.':
s2 += '0'
if s[i] == '-' and s[i+1] == '.':
s2 += '1'
i += 1
if s[i] == '-' and s[i+1] == '-':
s2 += '2'
i += 1
print(s2)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
814 | B | An express train to reveries | PROGRAMMING | 1,300 | [
"constructive algorithms"
] | null | null | Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her fancies would be realized.
On that night, Sengoku constructed a permutation *p*1,<=*p*2,<=...,<=*p**n* of intege... | The first line of input contains a positive integer *n* (2<=≤<=*n*<=≤<=1<=000) — the length of Sengoku's permutation, being the length of both meteor outbursts at the same time.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the sequence of colours in the firs... | Output *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n*, denoting a possible permutation Sengoku could have had. If there are more than one possible answer, output any one of them.
Input guarantees that such permutation exists. | [
"5\n1 2 3 4 3\n1 2 5 4 5\n",
"5\n4 4 2 3 1\n5 4 5 3 1\n",
"4\n1 1 3 4\n1 4 3 4\n"
] | [
"1 2 5 4 3\n",
"5 4 2 3 1\n",
"1 2 3 4\n"
] | In the first sample, both 1, 2, 5, 4, 3 and 1, 2, 3, 4, 5 are acceptable outputs.
In the second sample, 5, 4, 2, 3, 1 is the only permutation to satisfy the constraints. | 1,000 | [
{
"input": "5\n1 2 3 4 3\n1 2 5 4 5",
"output": "1 2 5 4 3"
},
{
"input": "5\n4 4 2 3 1\n5 4 5 3 1",
"output": "5 4 2 3 1"
},
{
"input": "4\n1 1 3 4\n1 4 3 4",
"output": "1 2 3 4"
},
{
"input": "10\n1 2 3 4 7 6 7 8 9 10\n1 2 3 4 5 6 5 8 9 10",
"output": "1 2 3 4 5 6 7 8 9... | 1,496,842,461 | 4,761 | Python 3 | WRONG_ANSWER | PRETESTS | 4 | 46 | 204,800 | n=int(input())
l = input()
l=[int(i) for i in l.split()]
x= input()
x=[int(i) for i in x.split()]
t=0
a=set(range(1,n+1)) - set(x)
for i in range(n):
if l[i]==x[i]:
t+=1
if t==n-1:
s=""
for i in range(n):
if l[i]==x[i]:
s=s+str(l[i])+" "
else:
... | Title: An express train to reveries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her... | ```python
n=int(input())
l = input()
l=[int(i) for i in l.split()]
x= input()
x=[int(i) for i in x.split()]
t=0
a=set(range(1,n+1)) - set(x)
for i in range(n):
if l[i]==x[i]:
t+=1
if t==n-1:
s=""
for i in range(n):
if l[i]==x[i]:
s=s+str(l[i])+" "
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
90 | B | African Crossword | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | B. African Crossword | 2 | 256 | An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To solve the crossword you should cross out all repeated letters in rows and columns. In other words, a... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Next *n* lines contain *m* lowercase Latin letters each. That is the crossword grid. | Print the encrypted word on a single line. It is guaranteed that the answer consists of at least one letter. | [
"3 3\ncba\nbcd\ncbc\n",
"5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf\n"
] | [
"abcd",
"codeforces"
] | none | 1,000 | [
{
"input": "3 3\ncba\nbcd\ncbc",
"output": "abcd"
},
{
"input": "5 5\nfcofd\nooedo\nafaoa\nrdcdf\neofsf",
"output": "codeforces"
},
{
"input": "4 4\nusah\nusha\nhasu\nsuha",
"output": "ahhasusu"
},
{
"input": "7 5\naabcd\neffgh\niijkk\nlmnoo\npqqrs\nttuvw\nxxyyz",
"output... | 1,676,982,803 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 92 | 204,800 | from collections import *
n, m = map(int, input().split())
arr = []
for i in range(n):
arr.append(input())
transed = defaultdict(str)
for row in arr:
for ind, ltr in enumerate(row):
transed[ind] += ltr
trs = []
for key in transed.keys():
trs.append(transed[key])
rowD = defaultdict(... | Title: African Crossword
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
An African crossword is a rectangular table *n*<=×<=*m* in size. Each cell of the table contains exactly one letter. This table (it is also referred to as grid) contains some encrypted word that needs to be decoded.
To s... | ```python
from collections import *
n, m = map(int, input().split())
arr = []
for i in range(n):
arr.append(input())
transed = defaultdict(str)
for row in arr:
for ind, ltr in enumerate(row):
transed[ind] += ltr
trs = []
for key in transed.keys():
trs.append(transed[key])
rowD = de... | 3.976619 | MatrixStudio/Codeforces-Python-Submissions |
908 | C | New Year and Curling | PROGRAMMING | 1,500 | [
"brute force",
"geometry",
"implementation",
"math"
] | null | null | Carol is currently curling.
She has *n* disks each with radius *r* on the 2D plane.
Initially she has all these disks above the line *y*<==<=10100.
She then will slide the disks towards the line *y*<==<=0 one by one in order from 1 to *n*.
When she slides the *i*-th disk, she will place its center at the point (*... | The first line will contain two integers *n* and *r* (1<=≤<=*n*,<=*r*<=≤<=1<=000), the number of disks, and the radius of the disks, respectively.
The next line will contain *n* integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=1<=000) — the *x*-coordinates of the disks. | Print a single line with *n* numbers. The *i*-th number denotes the *y*-coordinate of the center of the *i*-th disk. The output will be accepted if it has absolute or relative error at most 10<=-<=6.
Namely, let's assume that your answer for a particular value of a coordinate is *a* and the answer of the jury is *b*. ... | [
"6 2\n5 5 6 8 3 12\n"
] | [
"2 6.0 9.87298334621 13.3370849613 12.5187346573 13.3370849613\n"
] | The final positions of the disks will look as follows:
In particular, note the position of the last disk. | 1,000 | [
{
"input": "6 2\n5 5 6 8 3 12",
"output": "2 6.0 9.87298334621 13.3370849613 12.5187346573 13.3370849613"
},
{
"input": "1 1\n5",
"output": "1"
},
{
"input": "5 300\n939 465 129 611 532",
"output": "300 667.864105343 1164.9596696 1522.27745533 2117.05388391"
},
{
"input": "5 ... | 1,514,601,610 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 717 | 5,734,400 | n, r = map(int, input().split())
discs = {}
s = list(map(int, input().split()))
discs[s[0]] = r
print(r, end=" ")
b = lambda x, y: (4 * (r ** 2) - (x - y) ** 2) ** 0.5
for i in range(1, n):
xi = s[i]
found = False
to_app = []
for x in discs:
res = b(x, xi)
if type(r... | Title: New Year and Curling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Carol is currently curling.
She has *n* disks each with radius *r* on the 2D plane.
Initially she has all these disks above the line *y*<==<=10100.
She then will slide the disks towards the line *y*<==<=0 one b... | ```python
n, r = map(int, input().split())
discs = {}
s = list(map(int, input().split()))
discs[s[0]] = r
print(r, end=" ")
b = lambda x, y: (4 * (r ** 2) - (x - y) ** 2) ** 0.5
for i in range(1, n):
xi = s[i]
found = False
to_app = []
for x in discs:
res = b(x, xi)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
902 | A | Visiting a Friend | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Pig is visiting a friend.
Pig's house is located at point 0, and his friend's house is located at point *m* on an axis.
Pig can use teleports to move along the axis.
To use a teleport, Pig should come to a certain point (where the teleport is located) and choose where to move: for each teleport there is the rightmos... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=100) — the number of teleports and the location of the friend's house.
The next *n* lines contain information about teleports.
The *i*-th of these lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=*b**i*<=≤<=*m*), where ... | Print "YES" if there is a path from Pig's house to his friend's house that uses only teleports, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"3 5\n0 2\n2 4\n3 5\n",
"3 7\n0 4\n2 5\n6 7\n"
] | [
"YES\n",
"NO\n"
] | The first example is shown on the picture below:
Pig can use the first teleport from his house (point 0) to reach point 2, then using the second teleport go from point 2 to point 3, then using the third teleport go from point 3 to point 5, where his friend lives.
The second example is shown on the picture below:
You... | 500 | [
{
"input": "3 5\n0 2\n2 4\n3 5",
"output": "YES"
},
{
"input": "3 7\n0 4\n2 5\n6 7",
"output": "NO"
},
{
"input": "1 1\n0 0",
"output": "NO"
},
{
"input": "30 10\n0 7\n1 2\n1 2\n1 4\n1 4\n1 3\n2 2\n2 4\n2 6\n2 9\n2 2\n3 5\n3 8\n4 8\n4 5\n4 6\n5 6\n5 7\n6 6\n6 9\n6 7\n6 9\n7 7... | 1,593,749,727 | 3,207 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 268,390,400 | n,m = map(int,input().split())
flag = True
st = []
for i in range(n):
a,b = map(int,input().split())
st.append([a,b])
st2 = []
for i in range(n):
a,b = st[i][0],st[i][1]
if i == 0:
if a != 0:
flag = False
else:
if n == 1:
if b<m:
... | Title: Visiting a Friend
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pig is visiting a friend.
Pig's house is located at point 0, and his friend's house is located at point *m* on an axis.
Pig can use teleports to move along the axis.
To use a teleport, Pig should come to a certain ... | ```python
n,m = map(int,input().split())
flag = True
st = []
for i in range(n):
a,b = map(int,input().split())
st.append([a,b])
st2 = []
for i in range(n):
a,b = st[i][0],st[i][1]
if i == 0:
if a != 0:
flag = False
else:
if n == 1:
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,592,056,396 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 156 | 0 | d=[chr(i) for i in range(97,123)]
n,k=map(int,input().split())
s=''.join(map(str,d[:k]))
s=s*(n//k)+s[:n%k]
print(s)
| Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
d=[chr(i) for i in range(97,123)]
n,k=map(int,input().split())
s=''.join(map(str,d[:k]))
s=s*(n//k)+s[:n%k]
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,594,986,864 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 280 | 20,172,800 | s = list(map(str, input().split()))
S = ['A', 'E', 'I', 'O', 'U','Y', 'a', 'e', 'i', 'o', 'u', 'y']
S = set(S)
if s[-1] == '?':
if s[-2][-1] in S:
print('YES')
else:
print('NO')
else:
if s[-1][-2] in S:
print('YES')
else:
print('NO')
| Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
s = list(map(str, input().split()))
S = ['A', 'E', 'I', 'O', 'U','Y', 'a', 'e', 'i', 'o', 'u', 'y']
S = set(S)
if s[-1] == '?':
if s[-2][-1] in S:
print('YES')
else:
print('NO')
else:
if s[-1][-2] in S:
print('YES')
else:
print('NO')
``` | 3.892425 | MatrixStudio/Codeforces-Python-Submissions |
262 | A | Roma and Lucky Numbers | PROGRAMMING | 800 | [
"implementation"
] | null | null | Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integer... | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces. | In a single line print a single integer — the answer to the problem. | [
"3 4\n1 2 4\n",
"3 2\n447 44 77\n"
] | [
"3\n",
"2\n"
] | In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | 500 | [
{
"input": "3 4\n1 2 4",
"output": "3"
},
{
"input": "3 2\n447 44 77",
"output": "2"
},
{
"input": "2 2\n507978501 180480073",
"output": "2"
},
{
"input": "9 6\n655243746 167613748 1470546 57644035 176077477 56984809 44677 215706823 369042089",
"output": "9"
},
{
... | 1,589,383,726 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 216 | 6,656,000 | n,k=input().split()
a=list(map(str,input().split()))
l=[]
for i in a:
if i.count('4')+i.count('7')<=int(k):l.append(i)
print(len(l))
| Title: Roma and Lucky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits... | ```python
n,k=input().split()
a=list(map(str,input().split()))
l=[]
for i in a:
if i.count('4')+i.count('7')<=int(k):l.append(i)
print(len(l))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
107 | B | Basketball Team | PROGRAMMING | 1,600 | [
"combinatorics",
"dp",
"math",
"probabilities"
] | B. Basketball Team | 1 | 256 | As a German University in Cairo (GUC) student and a basketball player, Herr Wafa was delighted once he heard the news. GUC is finally participating in the Annual Basketball Competition (ABC).
A team is to be formed of *n* players, all of which are GUC students. However, the team might have players belonging to differ... | The first line contains three integers *n*, *m* and *h* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=1000,<=1<=≤<=*h*<=≤<=*m*) — the number of players on the team, the number of departments in GUC and Herr Wafa's department, correspondingly.
The second line contains a single-space-separated list of *m* integers *s**i* (1<=≤<=*... | Print the probability that Herr Wafa will have at least one teammate from his department. If there is not enough basketball players in GUC to participate in ABC, print -1. The answer will be accepted if it has absolute or relative error not exceeding 10<=-<=6. | [
"3 2 1\n2 1\n",
"3 2 1\n1 1\n",
"3 2 1\n2 2\n"
] | [
"1\n",
"-1\n",
"0.666667\n"
] | In the first example all 3 players (2 from department 1 and 1 from department 2) must be chosen for the team. Both players from Wafa's departments will be chosen, so he's guaranteed to have a teammate from his department.
In the second example, there are not enough players.
In the third example, there are three possi... | 1,000 | [
{
"input": "3 2 1\n2 1",
"output": "1"
},
{
"input": "3 2 1\n1 1",
"output": "-1"
},
{
"input": "3 2 1\n2 2",
"output": "0.666667"
},
{
"input": "3 2 1\n1 2",
"output": "0.000000"
},
{
"input": "6 5 3\n5 2 3 10 5",
"output": "0.380435"
},
{
"input": "7... | 1,679,689,797 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 42 | 62 | 0 | def nCr(n, r):
s = 1
for i in range(1, r+1):
s = s * (n - r + i) / i
return s
def sol():
n, m, h = map(int, input().split())
a = list(map(int, input().split()))
n -= 1
a[h - 1] -= 1
total = sum(a)
if total < n:
print(-1)
return
totalM = total - a[h - 1]
... | Title: Basketball Team
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
As a German University in Cairo (GUC) student and a basketball player, Herr Wafa was delighted once he heard the news. GUC is finally participating in the Annual Basketball Competition (ABC).
A team is to be formed of *n*... | ```python
def nCr(n, r):
s = 1
for i in range(1, r+1):
s = s * (n - r + i) / i
return s
def sol():
n, m, h = map(int, input().split())
a = list(map(int, input().split()))
n -= 1
a[h - 1] -= 1
total = sum(a)
if total < n:
print(-1)
return
totalM = total - a... | 0 | MatrixStudio/Codeforces-Python-Submissions |
977 | B | Two-gram | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to find any two-gram contained in the given string as a substring (i.e. two consecutive characters... | The first line of the input contains integer number $n$ ($2 \le n \le 100$) — the length of string $s$. The second line of the input contains the string $s$ consisting of $n$ capital Latin letters. | Print the only line containing exactly two capital Latin letters — any two-gram contained in the given string $s$ as a substring (i.e. two consecutive characters of the string) maximal number of times. | [
"7\nABACABA\n",
"5\nZZZAA\n"
] | [
"AB\n",
"ZZ\n"
] | In the first example "BA" is also valid answer.
In the second example the only two-gram "ZZ" can be printed because it contained in the string "ZZZAA" two times. | 0 | [
{
"input": "7\nABACABA",
"output": "AB"
},
{
"input": "5\nZZZAA",
"output": "ZZ"
},
{
"input": "26\nQWERTYUIOPASDFGHJKLZXCVBNM",
"output": "AS"
},
{
"input": "2\nQA",
"output": "QA"
},
{
"input": "2\nWW",
"output": "WW"
},
{
"input": "11\nGGRRAATTZZZ",... | 1,694,267,891 | 1,991 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | input()
s = input()
co_dv = dict()
for i in range(0, len(s)-2):
if s[i:i+2] not in co_dv.keys():
co_dv[s[i:i+2]] = 1
else:
co_dv[s[i:i+2]] = co_dv[s[i:i+2]] + 1
result = str()
result_count = 0
for k, v in co_dv.items():
if v > result_count:
result = k
result_... | Title: Two-gram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to f... | ```python
input()
s = input()
co_dv = dict()
for i in range(0, len(s)-2):
if s[i:i+2] not in co_dv.keys():
co_dv[s[i:i+2]] = 1
else:
co_dv[s[i:i+2]] = co_dv[s[i:i+2]] + 1
result = str()
result_count = 0
for k, v in co_dv.items():
if v > result_count:
result = k
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
560 | B | Gerald is into Art | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of an *a*1<=×<=*b*1 rectangle, the paintings have shape of a *a*2<=×<=*b*2 and *a*3<=×<=*b*3 rec... | The first line contains two space-separated numbers *a*1 and *b*1 — the sides of the board. Next two lines contain numbers *a*2,<=*b*2,<=*a*3 and *b*3 — the sides of the paintings. All numbers *a**i*,<=*b**i* in the input are integers and fit into the range from 1 to 1000. | If the paintings can be placed on the wall, print "YES" (without the quotes), and if they cannot, print "NO" (without the quotes). | [
"3 2\n1 3\n2 1\n",
"5 5\n3 3\n3 3\n",
"4 2\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | That's how we can place the pictures in the first test:
<img class="tex-graphics" src="https://espresso.codeforces.com/b41bf40c649073c6d3dd62eb7ae7adfc4bd131bd.png" style="max-width: 100.0%;max-height: 100.0%;"/>
And that's how we can do it in the third one.
<img class="tex-graphics" src="https://espresso.codeforces... | 1,000 | [
{
"input": "3 2\n1 3\n2 1",
"output": "YES"
},
{
"input": "5 5\n3 3\n3 3",
"output": "NO"
},
{
"input": "4 2\n2 3\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 1",
"output": "YES"
},
{
"input": "1000 1000\n999 999\n1 1000",
"output": "YES"
},
{
"in... | 1,448,268,441 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | from sys import stdin
a1, b1 = map(int, stdin.readline().split())
a2, b2 = map(int, stdin.readline().split())
a3, b3 = map(int, stdin.readline().split())
z1 = min(a3, b3) + a2
z2 = max(max(a3, b3), b2)
if max(z1, z2) == max(a1, b1) and min(z1, z2) == min(a1, b1):
print("YES")
exit()
z1 = mi... | Title: Gerald is into Art
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board ha... | ```python
from sys import stdin
a1, b1 = map(int, stdin.readline().split())
a2, b2 = map(int, stdin.readline().split())
a3, b3 = map(int, stdin.readline().split())
z1 = min(a3, b3) + a2
z2 = max(max(a3, b3), b2)
if max(z1, z2) == max(a1, b1) and min(z1, z2) == min(a1, b1):
print("YES")
exit()
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
478 | B | Random Teams | PROGRAMMING | 1,300 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | *n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is to write a program that will find the minimum and the maximum number of pairs of friends that coul... | The only line of input contains two integers *n* and *m*, separated by a single space (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the number of participants and the number of teams respectively. | The only line of the output should contain two integers *k**min* and *k**max* — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively. | [
"5 1\n",
"3 2\n",
"6 3\n"
] | [
"10 10\n",
"1 1\n",
"3 6\n"
] | In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.
In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.
... | 1,000 | [
{
"input": "5 1",
"output": "10 10"
},
{
"input": "3 2",
"output": "1 1"
},
{
"input": "6 3",
"output": "3 6"
},
{
"input": "5 3",
"output": "2 3"
},
{
"input": "10 2",
"output": "20 36"
},
{
"input": "10 6",
"output": "4 10"
},
{
"input": ... | 1,675,359,657 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 46 | 0 | def pairs(n):
return int(n*(n-1)/2)
def max_pairs(players,team):
players = players - (team-1)
return pairs(players)
def min_pairs(players,team):
left = players%team
left_team = team-left
player_per_team = players//team
sum = 0
sum += left*pairs((player_per_team+1))
sum += left_team... | Title: Random Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is ... | ```python
def pairs(n):
return int(n*(n-1)/2)
def max_pairs(players,team):
players = players - (team-1)
return pairs(players)
def min_pairs(players,team):
left = players%team
left_team = team-left
player_per_team = players//team
sum = 0
sum += left*pairs((player_per_team+1))
sum +=... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
665 | B | Shopping | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Ayush is a cashier at the shopping center. Recently his department has started a ''click and collect" service which allows users to shop online.
The store contains *k* items. *n* customers have already used the above service. Each user paid for *m* items. Let *a**ij* denote the *j*-th item in the *i*-th person's orde... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*k*<=≤<=100,<=1<=≤<=*m*<=≤<=*k*) — the number of users, the number of items each user wants to buy and the total number of items at the market.
The next line contains *k* distinct integers *p**l* (1<=≤<=*p**l*<=≤<=*k*) denoting the initial positions ... | Print the only integer *t* — the total time needed for Ayush to process all the orders. | [
"2 2 5\n3 4 1 2 5\n1 5\n3 1\n"
] | [
"14\n"
] | Customer 1 wants the items 1 and 5.
*pos*(1) = 3, so the new positions are: [1, 3, 4, 2, 5].
*pos*(5) = 5, so the new positions are: [5, 1, 3, 4, 2].
Time taken for the first customer is 3 + 5 = 8.
Customer 2 wants the items 3 and 1.
*pos*(3) = 3, so the new positions are: [3, 5, 1, 4, 2].
*pos*(1) = 3, so the ne... | 0 | [
{
"input": "2 2 5\n3 4 1 2 5\n1 5\n3 1",
"output": "14"
},
{
"input": "4 4 4\n1 2 3 4\n3 4 2 1\n4 3 2 1\n4 1 2 3\n4 1 2 3",
"output": "59"
},
{
"input": "1 1 1\n1\n1",
"output": "1"
},
{
"input": "10 1 100\n1 55 67 75 40 86 24 84 82 26 81 23 70 79 51 54 21 78 31 98 68 93 66 8... | 1,621,224,947 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<char> vc;
typedef pair<int, int> pii;
typedef map<int, int> dictii;
typedef map<string, int> dictsi;
typedef map<string, string> dictss;
typedef pair<string, string> pss;
t... | Title: Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ayush is a cashier at the shopping center. Recently his department has started a ''click and collect" service which allows users to shop online.
The store contains *k* items. *n* customers have already used the above service... | ```python
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<string> vs;
typedef vector<char> vc;
typedef pair<int, int> pii;
typedef map<int, int> dictii;
typedef map<string, int> dictsi;
typedef map<string, string> dictss;
typedef pair<string, strin... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | B | Phone numbers | PROGRAMMING | 1,100 | [
"implementation"
] | B. Phone numbers | 2 | 256 | Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33. Your task is to find for a given phone number any of its divisions into groups of two or three... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of digits in the phone number. The second line contains *n* digits — the phone number to divide into groups. | Output any of divisions of the given phone number into groups of two or three digits. Separate groups by single character -. If the answer is not unique, output any. | [
"6\n549871\n",
"7\n1198733\n"
] | [
"54-98-71",
"11-987-33\n"
] | none | 0 | [
{
"input": "6\n549871",
"output": "54-98-71"
},
{
"input": "7\n1198733",
"output": "119-87-33"
},
{
"input": "2\n74",
"output": "74"
},
{
"input": "2\n33",
"output": "33"
},
{
"input": "3\n074",
"output": "074"
},
{
"input": "3\n081",
"output": "08... | 1,586,652,579 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 280 | 307,200 | def string2list(x):
x=x.split()
i=0
#print(hi)
for i in range(len(x)):
x[i]=int(x[i])
return x
#def list2string(x)
# (' '.join(state.rem[0:states.total]))
n=int(input())
number=input()
k=0
current=0
output=['']*(3*n)
if n % 2==0:
while k<n:
#print('The value of k is')
#... | Title: Phone numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33.... | ```python
def string2list(x):
x=x.split()
i=0
#print(hi)
for i in range(len(x)):
x[i]=int(x[i])
return x
#def list2string(x)
# (' '.join(state.rem[0:states.total]))
n=int(input())
number=input()
k=0
current=0
output=['']*(3*n)
if n % 2==0:
while k<n:
#print('The value of k is')... | 3.929428 | MatrixStudio/Codeforces-Python-Submissions |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,686,582,460 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 124 | 0 | n = int(input())
mem = {}
for _ in range(n):
s = input()
mem[s] = 1 + mem.get(s, 0)
km, vm = None, None
for k, v in mem.items():
if km is None and vm is None:
km, vm = k, v
else:
if vm < v:
km, vm = k, v
print(km)
| Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
n = int(input())
mem = {}
for _ in range(n):
s = input()
mem[s] = 1 + mem.get(s, 0)
km, vm = None, None
for k, v in mem.items():
if km is None and vm is None:
km, vm = k, v
else:
if vm < v:
km, vm = k, v
print(km)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the ... | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,683,727,121 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 31 | 0 | n=int(input())
L=[1,1]
for i in range(2,n):
s =L[i-1]+L[i-2]
L.append(s)
ch=""
for i in range(1,n+1):
if(i in L):
ch=ch+'O'
else:
ch=ch+'o'
print (ch) | Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should o... | ```python
n=int(input())
L=[1,1]
for i in range(2,n):
s =L[i-1]+L[i-2]
L.append(s)
ch=""
for i in range(1,n+1):
if(i in L):
ch=ch+'O'
else:
ch=ch+'o'
print (ch)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,598,500,136 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 26 | 500 | 1,433,600 |
n , m = map(int,input().split())
mapped =[]
for i in range(m):
mapped.append(list(map(int,input().split(" "))))
mapped.sort(key = lambda x:x[1] , reverse =True)
result =0
for a,b in mapped:
for i in range(a):
if n>0:
result+=b
n-=1
print(result) | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
n , m = map(int,input().split())
mapped =[]
for i in range(m):
mapped.append(list(map(int,input().split(" "))))
mapped.sort(key = lambda x:x[1] , reverse =True)
result =0
for a,b in mapped:
for i in range(a):
if n>0:
result+=b
n-=1
print(re... | 0 | MatrixStudio/Codeforces-Python-Submissions |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,699,364,587 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | n = list(map(int, input()))
luckies = [4, 7, 47, 74, 444, 447, 474, 477, 744, 747, 774, 777]
n_joined = int(''.join(map(str, n)))
for i in range(len(n)):
if n[i] == 4 or n[i] == 7:
Lucky = True
else:
Lucky = False
for i in luckies:
if n_joined % i == 0:
print('YES... | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = list(map(int, input()))
luckies = [4, 7, 47, 74, 444, 447, 474, 477, 744, 747, 774, 777]
n_joined = int(''.join(map(str, n)))
for i in range(len(n)):
if n[i] == 4 or n[i] == 7:
Lucky = True
else:
Lucky = False
for i in luckies:
if n_joined % i == 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
710 | B | Optimal Point on a Line | PROGRAMMING | 1,400 | [
"brute force",
"sortings"
] | null | null | You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal. | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of points on the line.
The second line contains *n* integers *x**i* (<=-<=109<=≤<=*x**i*<=≤<=109) — the coordinates of the given *n* points. | Print the only integer *x* — the position of the optimal point on the line. If there are several optimal points print the position of the leftmost one. It is guaranteed that the answer is always the integer. | [
"4\n1 2 3 4\n"
] | [
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "5\n-1 -10 2 6 7",
"output": "2"
},
{
"input": "10\n-68 10 87 22 30 89 82 -97 -52 25",
"output": "22"
},
{
"input": "100\n457 827 807 17 871 935 907 -415 536 170 551 -988 865 758 -457 -892 -875 -488 684 19 0 555 -807 -624 -... | 1,495,241,188 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | #!/usr/bin/env python3
n=int(input())
a=list(map(int,input().split()))
a.sort()
print(a[math.ceil((n-1)/2)])
| Title: Optimal Point on a Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on a line with their coordinates *x**i*. Find the point *x* so the sum of distances to the given points is minimal.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=... | ```python
#!/usr/bin/env python3
n=int(input())
a=list(map(int,input().split()))
a.sort()
print(a[math.ceil((n-1)/2)])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
868 | A | Bark to Unlock | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's p... | The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of words Kashtanka knows.
The next *n* lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to b... | Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"ya\n4\nah\noy\nto\nha\n",
"hp\n2\nht\ntp\n",
"ah\n1\nha\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" produ... | 250 | [
{
"input": "ya\n4\nah\noy\nto\nha",
"output": "YES"
},
{
"input": "hp\n2\nht\ntp",
"output": "NO"
},
{
"input": "ah\n1\nha",
"output": "YES"
},
{
"input": "bb\n4\nba\nab\naa\nbb",
"output": "YES"
},
{
"input": "bc\n4\nca\nba\nbb\ncc",
"output": "YES"
},
{
... | 1,621,023,858 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 61 | 0 | arr = ['a', 'b', 'c', 'd', 'e', 'f', 'j', 'h', 'i']
print(arr[2:])
for _ in range(int(input())):
count = 0
password = input()
n = int(input())
for i in range(n):
podstr = input()
if podstr == password:
print('YES')
elif podstr[1] == password[0]:
... | Title: Bark to Unlock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a passw... | ```python
arr = ['a', 'b', 'c', 'd', 'e', 'f', 'j', 'h', 'i']
print(arr[2:])
for _ in range(int(input())):
count = 0
password = input()
n = int(input())
for i in range(n):
podstr = input()
if podstr == password:
print('YES')
elif podstr[1] == password[0]:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,614,053,517 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | d1, d2, d3 = [int(i) for i in input().split()]
first = (2 * d1) + (2 * d2)
second = d1 + d3 + d2
print(min(first,second)) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
d1, d2, d3 = [int(i) for i in input().split()]
first = (2 * d1) + (2 * d2)
second = d1 + d3 + d2
print(min(first,second))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,692,693,113 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | n = int(input())
ans = "NO"
for i in range(1, n+1):
if n%i == 0:
if i in [4, 7, 44, 47, 74, 77, 444, 447, 474, 744, 747, 477, 774, 777]:
ans = "YES"
break
print(ans) | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
ans = "NO"
for i in range(1, n+1):
if n%i == 0:
if i in [4, 7, 44, 47, 74, 77, 444, 447, 474, 744, 747, 477, 774, 777]:
ans = "YES"
break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
358 | A | Dima and Continuous Line | PROGRAMMING | 1,400 | [
"brute force",
"implementation"
] | null | null | Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher gave Seryozha the coordinates of *n* distinct points on the abscissa axis and asked to consecutively connect th... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=103). The second line contains *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=106<=≤<=*x**i*<=≤<=106) — the *i*-th point has coordinates (*x**i*,<=0). The points are not necessarily sorted by their *x* coordinate. | In the single line print "yes" (without the quotes), if the line has self-intersections. Otherwise, print "no" (without the quotes). | [
"4\n0 10 5 15\n",
"4\n0 15 5 10\n"
] | [
"yes\n",
"no\n"
] | The first test from the statement is on the picture to the left, the second test is on the picture to the right. | 500 | [
{
"input": "4\n0 10 5 15",
"output": "yes"
},
{
"input": "4\n0 15 5 10",
"output": "no"
},
{
"input": "5\n0 1000 2000 3000 1500",
"output": "yes"
},
{
"input": "5\n-724093 710736 -383722 -359011 439613",
"output": "no"
},
{
"input": "50\n384672 661179 -775591 -989... | 1,585,195,945 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 140 | 0 | n = int(input())
A = [int(i) for i in input().split()]
res = "no"
lo, hi = min(A[0], A[1]), max(A[0], A[1])
for i in range(1, len(A)-1):
# arc between x1, x2
# x1, x2 = min(A[i], A[i+1]), max(A[i], A[i+1])
# x3, x4 = min(A[i+2], A[i+3]), max(A[i+2], A[i+3])
# print(x1, x2, x3, x4)
# if x1<x3<x2<x4 ... | Title: Dima and Continuous Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher g... | ```python
n = int(input())
A = [int(i) for i in input().split()]
res = "no"
lo, hi = min(A[0], A[1]), max(A[0], A[1])
for i in range(1, len(A)-1):
# arc between x1, x2
# x1, x2 = min(A[i], A[i+1]), max(A[i], A[i+1])
# x3, x4 = min(A[i+2], A[i+3]), max(A[i+2], A[i+3])
# print(x1, x2, x3, x4)
# if x1... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,615,581,964 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 122 | 0 | n,k = map(int,input().split(" "))
array = [int(num) for num in input().split(" ")]
x = 0
for i in range(n - 1,0,-1):
if array[i] != array[n - 1]:
break
x += 1
if n == 1: print(0)
elif (k - 1) < (n - x): print(-1)
else: print(n - x)
'''
k = 4
1 1 1 1 1 1
Ans: 0
Your answer: 2 (len(arr)... | Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
n,k = map(int,input().split(" "))
array = [int(num) for num in input().split(" ")]
x = 0
for i in range(n - 1,0,-1):
if array[i] != array[n - 1]:
break
x += 1
if n == 1: print(0)
elif (k - 1) < (n - x): print(-1)
else: print(n - x)
'''
k = 4
1 1 1 1 1 1
Ans: 0
Your answer: 2... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
651 | A | Joysticks | PROGRAMMING | 1,100 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if n... | The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively. | Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged. | [
"3 5\n",
"4 4\n"
] | [
"6\n",
"5\n"
] | In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joyst... | 500 | [
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
... | 1,572,244,207 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 93 | 0 | list=input().split(' ')
a=int(list[0])
b=int(list[1])
c=0
while(a!=0 and b!=0):
c+=1
if a>=b:
a-=2
b+=1
else:
b-=2
a+=1
print(c) | Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick on... | ```python
list=input().split(' ')
a=int(list[0])
b=int(list[1])
c=0
while(a!=0 and b!=0):
c+=1
if a>=b:
a-=2
b+=1
else:
b-=2
a+=1
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,700,435,165 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | import math
arr = input().split(" ")
a = int(arr[0])
b = int(arr[1])
print(math.factorial(min(a,b))) | Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
import math
arr = input().split(" ")
a = int(arr[0])
b = int(arr[1])
print(math.factorial(min(a,b)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,638,692,441 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n = int(input())
arr =[]
if n % 2 == 0:
for i in range(1, n+1):
if i % 2 != 0:
arr.append(i+1)
else:
arr.append(i-1)
for i in arr:
print(i, end=' ')
else:
print(-1)
| Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
n = int(input())
arr =[]
if n % 2 == 0:
for i in range(1, n+1):
if i % 2 != 0:
arr.append(i+1)
else:
arr.append(i-1)
for i in arr:
print(i, end=' ')
else:
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,594,819,323 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 109 | 6,656,000 | num1 = input()
num2 = input()
li = []
for k,j in zip(num1,num2):
if k!=j:
li.append('1')
else:
li.append('0')
print(''.join(li)) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
num1 = input()
num2 = input()
li = []
for k,j in zip(num1,num2):
if k!=j:
li.append('1')
else:
li.append('0')
print(''.join(li))
``` | 3.960352 | MatrixStudio/Codeforces-Python-Submissions |
448 | A | Rewards | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has *a*1 first prize cups, *a*2 second prize c... | The first line contains integers *a*1, *a*2 and *a*3 (0<=≤<=*a*1,<=*a*2,<=*a*3<=≤<=100). The second line contains integers *b*1, *b*2 and *b*3 (0<=≤<=*b*1,<=*b*2,<=*b*3<=≤<=100). The third line contains integer *n* (1<=≤<=*n*<=≤<=100).
The numbers in the lines are separated by single spaces. | Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO" (without the quotes). | [
"1 1 1\n1 1 1\n4\n",
"1 1 3\n2 3 4\n2\n",
"1 0 0\n1 0 0\n1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "1 1 1\n1 1 1\n4",
"output": "YES"
},
{
"input": "1 1 3\n2 3 4\n2",
"output": "YES"
},
{
"input": "1 0 0\n1 0 0\n1",
"output": "NO"
},
{
"input": "0 0 0\n0 0 0\n1",
"output": "YES"
},
{
"input": "100 100 100\n100 100 100\n100",
"output": "YES"
},
... | 1,692,703,028 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 46 | 0 | # Read input
cups = list(map(int, input().split()))
medals = list(map(int, input().split()))
n = int(input())
# Calculate the total number of shelves required for cups and medals
total_shelves = (sum(cups) + 4) // 5 + (sum(medals) + 9) // 10
# Check if the total shelves required are less than or equal to n
i... | Title: Rewards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into ... | ```python
# Read input
cups = list(map(int, input().split()))
medals = list(map(int, input().split()))
n = int(input())
# Calculate the total number of shelves required for cups and medals
total_shelves = (sum(cups) + 4) // 5 + (sum(medals) + 9) // 10
# Check if the total shelves required are less than or equ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
601 | A | The Two Routes | PROGRAMMING | 1,600 | [
"graphs",
"shortest paths"
] | null | null | In Absurdistan, there are *n* towns (numbered 1 through *n*) and *m* bidirectional railways. There is also an absurdly simple road network — for each pair of different towns *x* and *y*, there is a bidirectional road between towns *x* and *y* if and only if there is no railway between them. Travelling to a different to... | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=400, 0<=≤<=*m*<=≤<=*n*(*n*<=-<=1)<=/<=2) — the number of towns and the number of railways respectively.
Each of the next *m* lines contains two integers *u* and *v*, denoting a railway between towns *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=... | Output one integer — the smallest possible time of the later vehicle's arrival in town *n*. If it's impossible for at least one of the vehicles to reach town *n*, output <=-<=1. | [
"4 2\n1 3\n3 4\n",
"4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4\n",
"5 5\n4 2\n3 5\n4 5\n5 1\n1 2\n"
] | [
"2\n",
"-1\n",
"3\n"
] | In the first sample, the train can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c0aa60a06309ef607b7159fd7f3687ea0d943ce.png" style="max-width: 100.0%;max-height: 100.0%;"/> and the bus can take the route <img align="middle" class="tex-formula" src="https://espresso.codefo... | 500 | [
{
"input": "4 2\n1 3\n3 4",
"output": "2"
},
{
"input": "4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4",
"output": "-1"
},
{
"input": "5 5\n4 2\n3 5\n4 5\n5 1\n1 2",
"output": "3"
},
{
"input": "5 4\n1 2\n3 2\n3 4\n5 4",
"output": "4"
},
{
"input": "3 1\n1 2",
"output": "... | 1,623,717,765 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 3,481,600 | # there is always a railway or a road connecting 1 and n
# so we just need to figure out the shortest route of the other transport
n,m = map(int,input().split())
railways = [[False]*n for _ in range(n)]
railways_list = [[] for _ in range(n)]
for _ in range(m):
u,v = map(int,input().split())
u,v = u-1,v-1
r... | Title: The Two Routes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Absurdistan, there are *n* towns (numbered 1 through *n*) and *m* bidirectional railways. There is also an absurdly simple road network — for each pair of different towns *x* and *y*, there is a bidirectional road bet... | ```python
# there is always a railway or a road connecting 1 and n
# so we just need to figure out the shortest route of the other transport
n,m = map(int,input().split())
railways = [[False]*n for _ in range(n)]
railways_list = [[] for _ in range(n)]
for _ in range(m):
u,v = map(int,input().split())
u,v = u... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
916 | A | Jamie and Alarm Snooze | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will then press the snooze button every *x* minutes until *hh*:<=*mm* is reached, and only then he will wake up. He ... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=60).
The second line contains two two-digit integers, *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59). | Print the minimum number of times he needs to press the button. | [
"3\n11 23\n",
"5\n01 07\n"
] | [
"2\n",
"0\n"
] | In the first sample, Jamie needs to wake up at 11:23. So, he can set his alarm at 11:17. He would press the snooze button when the alarm rings at 11:17 and at 11:20.
In the second sample, Jamie can set his alarm at exactly at 01:07 which is lucky. | 500 | [
{
"input": "3\n11 23",
"output": "2"
},
{
"input": "5\n01 07",
"output": "0"
},
{
"input": "34\n09 24",
"output": "3"
},
{
"input": "2\n14 37",
"output": "0"
},
{
"input": "14\n19 54",
"output": "9"
},
{
"input": "42\n15 44",
"output": "12"
},
... | 1,517,549,703 | 2,147,483,647 | Python 3 | OK | TESTS | 254 | 62 | 5,632,000 | # Min Zhang
# cf916a
# Feb 2, 2018
def isLucky(h,m):
return ('7' in str(h)) or ('7' in str(m))
# return number of minutes
# time1 is later than time2
def distance(h1,m1,h2,m2):
return 60 * (h1 - h2) + (m1 - m2)
def addTime(h, m, snooze):
if m + snooze >= 60:
m2 = m + snooze - 60
h2 = h ... | Title: Jamie and Alarm Snooze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jamie loves sleeping. One day, he decides that he needs to wake up at exactly *hh*:<=*mm*. However, he hates waking up, so he wants to make waking up less painful by setting the alarm at a lucky time. He will the... | ```python
# Min Zhang
# cf916a
# Feb 2, 2018
def isLucky(h,m):
return ('7' in str(h)) or ('7' in str(m))
# return number of minutes
# time1 is later than time2
def distance(h1,m1,h2,m2):
return 60 * (h1 - h2) + (m1 - m2)
def addTime(h, m, snooze):
if m + snooze >= 60:
m2 = m + snooze - 60
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,664,084,073 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 46 | 0 | values = []
for a in range(2):
imp = list(input().split())
values.append(imp)
for i in range (len(values[0][0])):
if values[0][0][i] == values[1][0][i]:
print("0",end="")
else:
print("1",end="") | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
values = []
for a in range(2):
imp = list(input().split())
values.append(imp)
for i in range (len(values[0][0])):
if values[0][0][i] == values[1][0][i]:
print("0",end="")
else:
print("1",end="")
``` | 3.9885 | MatrixStudio/Codeforces-Python-Submissions |
978 | B | File Name | PROGRAMMING | 800 | [
"greedy",
"strings"
] | null | null | You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin letters "x") in a row, the system considers that the file content does not correspond to the socia... | The first line contains integer $n$ $(3 \le n \le 100)$ — the length of the file name.
The second line contains a string of length $n$ consisting of lowercase Latin letters only — the file name. | Print the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. If initially the file name dost not contain a forbidden substring "xxx", print 0. | [
"6\nxxxiii\n",
"5\nxxoxx\n",
"10\nxxxxxxxxxx\n"
] | [
"1\n",
"0\n",
"8\n"
] | In the first example Polycarp tried to send a file with name contains number $33$, written in Roman numerals. But he can not just send the file, because it name contains three letters "x" in a row. To send the file he needs to remove any one of this letters. | 0 | [
{
"input": "6\nxxxiii",
"output": "1"
},
{
"input": "5\nxxoxx",
"output": "0"
},
{
"input": "10\nxxxxxxxxxx",
"output": "8"
},
{
"input": "100\nxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx",
"output": "98"
},
{
... | 1,680,141,388 | 2,147,483,647 | Python 3 | OK | TESTS | 13 | 46 | 0 | a= int(input())
nombre = input()
contar = 0
for i in range(a-2):
if nombre [i:i+3] == "xxx":
contar += 1
print(contar)
T=467474747467467475677656756
| Title: File Name
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin let... | ```python
a= int(input())
nombre = input()
contar = 0
for i in range(a-2):
if nombre [i:i+3] == "xxx":
contar += 1
print(contar)
T=467474747467467475677656756
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
448 | A | Rewards | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has *a*1 first prize cups, *a*2 second prize c... | The first line contains integers *a*1, *a*2 and *a*3 (0<=≤<=*a*1,<=*a*2,<=*a*3<=≤<=100). The second line contains integers *b*1, *b*2 and *b*3 (0<=≤<=*b*1,<=*b*2,<=*b*3<=≤<=100). The third line contains integer *n* (1<=≤<=*n*<=≤<=100).
The numbers in the lines are separated by single spaces. | Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO" (without the quotes). | [
"1 1 1\n1 1 1\n4\n",
"1 1 3\n2 3 4\n2\n",
"1 0 0\n1 0 0\n1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "1 1 1\n1 1 1\n4",
"output": "YES"
},
{
"input": "1 1 3\n2 3 4\n2",
"output": "YES"
},
{
"input": "1 0 0\n1 0 0\n1",
"output": "NO"
},
{
"input": "0 0 0\n0 0 0\n1",
"output": "YES"
},
{
"input": "100 100 100\n100 100 100\n100",
"output": "YES"
},
... | 1,633,850,026 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | #بسم الله الرحمن الرحيم
import numpy as np
cup = [int(i) for i in input().split()]
medal = [int(i) for i in input().split()]
shaves = int(input())
x = sum(cup)
x=np.ceil(x/5)
z = sum(medal)
z=np.ceil(z/10)
if x+z<=shaves:
print("YES")
else:
print("NO") | Title: Rewards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into ... | ```python
#بسم الله الرحمن الرحيم
import numpy as np
cup = [int(i) for i in input().split()]
medal = [int(i) for i in input().split()]
shaves = int(input())
x = sum(cup)
x=np.ceil(x/5)
z = sum(medal)
z=np.ceil(z/10)
if x+z<=shaves:
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
567 | B | Berland National Library | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Berland National Library has recently been built in the capital of Berland. In addition, in the library you can take any of the collected works of Berland leaders, the library has a reading room.
Today was the pilot launch of an automated reading room visitors' accounting system! The scanner of the system is installed... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of records in the system log. Next follow *n* events from the system journal in the order in which the were made. Each event was written on a single line and looks as "+ *r**i*" or "- *r**i*", where *r**i* is an integer from 1 to 106, the r... | Print a single integer — the minimum possible capacity of the reading room. | [
"6\n+ 12001\n- 12001\n- 1\n- 1200\n+ 1\n+ 7\n",
"2\n- 1\n- 2\n",
"2\n+ 1\n- 1\n"
] | [
"3",
"2",
"1"
] | In the first sample test, the system log will ensure that at some point in the reading room were visitors with registration numbers 1, 1200 and 12001. More people were not in the room at the same time based on the log. Therefore, the answer to the test is 3. | 1,000 | [
{
"input": "6\n+ 12001\n- 12001\n- 1\n- 1200\n+ 1\n+ 7",
"output": "3"
},
{
"input": "2\n- 1\n- 2",
"output": "2"
},
{
"input": "2\n+ 1\n- 1",
"output": "1"
},
{
"input": "5\n+ 1\n- 1\n+ 2\n+ 3\n- 4",
"output": "3"
},
{
"input": "3\n- 1\n- 2\n- 3",
"output": "... | 1,638,252,411 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 77 | 0 | ht = {}
room_capacity = 0
maxx = 0
for _ in range(int(input())):
op, idd = list(map(str, input().split()))
if op == "-" and (idd not in ht or ht[idd] == 0):
maxx += 1
elif op == "-" and idd in ht and ht[idd] == 1:
room_capacity -= 1
ht[idd] = 0
elif op == "+" and room_capacity ==... | Title: Berland National Library
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland National Library has recently been built in the capital of Berland. In addition, in the library you can take any of the collected works of Berland leaders, the library has a reading room.
Today was the... | ```python
ht = {}
room_capacity = 0
maxx = 0
for _ in range(int(input())):
op, idd = list(map(str, input().split()))
if op == "-" and (idd not in ht or ht[idd] == 0):
maxx += 1
elif op == "-" and idd in ht and ht[idd] == 1:
room_capacity -= 1
ht[idd] = 0
elif op == "+" and room_c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
266 | B | Queue at the School | PROGRAMMING | 800 | [
"constructive algorithms",
"graph matchings",
"implementation",
"shortest paths"
] | null | null | During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling awkward for standing in front of the girls in the queue and they started letting the girls move forward ea... | The first line contains two integers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=50), which represent the number of children in the queue and the time after which the queue will transform into the arrangement you need to find.
The next line contains string *s*, which represents the schoolchildren's initial arrangement. If the *... | Print string *a*, which describes the arrangement after *t* seconds. If the *i*-th position has a boy after the needed time, then the *i*-th character *a* must equal "B", otherwise it must equal "G". | [
"5 1\nBGGBG\n",
"5 2\nBGGBG\n",
"4 1\nGGGB\n"
] | [
"GBGGB\n",
"GGBGB\n",
"GGGB\n"
] | none | 500 | [
{
"input": "5 1\nBGGBG",
"output": "GBGGB"
},
{
"input": "5 2\nBGGBG",
"output": "GGBGB"
},
{
"input": "4 1\nGGGB",
"output": "GGGB"
},
{
"input": "2 1\nBB",
"output": "BB"
},
{
"input": "2 1\nBG",
"output": "GB"
},
{
"input": "6 2\nBBGBBG",
"outpu... | 1,696,771,104 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 92 | 0 | n,t = map(int,input().split())
que = list(input())
for j in range(t):
check = 0
for i in range(len(que)-1):
if que[i+1] =="G" and que[i] == "B" and i >= check:
que[i],que[i+1] = que[i+1],que[i]
check = i + 2
print("".join(que)) | Title: Queue at the School
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling a... | ```python
n,t = map(int,input().split())
que = list(input())
for j in range(t):
check = 0
for i in range(len(que)-1):
if que[i+1] =="G" and que[i] == "B" and i >= check:
que[i],que[i+1] = que[i+1],que[i]
check = i + 2
print("".join(que))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
174 | B | File List | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each file name has a form "name.ext", where:
- name is a string consisting of lowercase Latin lette... | The input data consists of a single string *s*, its length is from 1 to 4·105 characters. The string can contain only lowercase Latin letters ('a' - 'z') and periods ('.'). | In the first line print "YES" (without the quotes), if it is possible to divide *s* into parts as required. In this case, the following lines should contain the parts of the required partition, one per line in the order in which they appear in *s*. The required partition can contain the same file names. If there are mu... | [
"read.meexample.txtb.cpp\n",
"version.infontldrcontestdata.zip\n"
] | [
"YES\nread.m\neexample.t\nxtb.cpp\n",
"NO\n"
] | none | 1,000 | [
{
"input": "read.meexample.txtb.cpp",
"output": "YES\nread.m\neexample.t\nxtb.cpp"
},
{
"input": "version.infontldrcontestdata.zip",
"output": "NO"
},
{
"input": "thisis.text.txt",
"output": "YES\nthisis.t\next.txt"
},
{
"input": "oops.t",
"output": "YES\noops.t"
},
{... | 1,589,865,732 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 248 | 0 | s = input()
s = s.split('.')
f = 0
if len(s[0])>8 and len(s[-1])>3:
f = 1
for i in range(1,len(s)-1):
if len(s[i])>11 and len(s[i])>1:
f = 1
if f==1:
print("NO")
else:
print("YES")
prev = 0
last = s[0]+'.'
for i in range(1,len(s)-1):
if len(s[i])>=9:
... | Title: File List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eudokimus, a system administrator is in trouble again. As a result of an error in some script, a list of names of very important files has been damaged. Since they were files in the BerFS file system, it is known that each fi... | ```python
s = input()
s = s.split('.')
f = 0
if len(s[0])>8 and len(s[-1])>3:
f = 1
for i in range(1,len(s)-1):
if len(s[i])>11 and len(s[i])>1:
f = 1
if f==1:
print("NO")
else:
print("YES")
prev = 0
last = s[0]+'.'
for i in range(1,len(s)-1):
if len(s[i])>=9:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,662,816,510 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | import itertools
import math
from itertools import permutations,combinations
def iint():
return int(input())
def iarr():
return list(map(int,input().split()))
def gcd(a,b):
if a % b == 0:
return b
else:
return gcd(b,a % b)
def lcm(a,b):
return a * b //gcd(a,b)
def binpo... | Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
import itertools
import math
from itertools import permutations,combinations
def iint():
return int(input())
def iarr():
return list(map(int,input().split()))
def gcd(a,b):
if a % b == 0:
return b
else:
return gcd(b,a % b)
def lcm(a,b):
return a * b //gcd(a,b)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,599,388,313 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 16 | 2,000 | 23,961,600 | def main():
n = int(input())
a, b = set(), set()
task = []
for i in range(n-1):
x, y = map(int, input().split())
task.append((x, y))
a.add(task[0][0])
b.add(task[0][1])
to_do = []
while task:
for i, j in task:
if i in a or j in b:
... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
def main():
n = int(input())
a, b = set(), set()
task = []
for i in range(n-1):
x, y = map(int, input().split())
task.append((x, y))
a.add(task[0][0])
b.add(task[0][1])
to_do = []
while task:
for i, j in task:
if i in a or j in b:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
961 | A | Tetris | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bottom row. Otherwise a square will appear at the top of the highest square of this column.
... | The first line of input contain 2 integer numbers $n$ and $m$ ($1 \le n, m \le 1000$) — the length of the platform and the number of the squares.
The next line contain $m$ integer numbers $c_1, c_2, \dots, c_m$ ($1 \le c_i \le n$) — column in which $i$-th square will appear. | Print one integer — the amount of points you will receive. | [
"3 9\n1 1 2 2 2 3 1 2 3\n"
] | [
"2\n"
] | In the sample case the answer will be equal to $2$ because after the appearing of $6$-th square will be removed one row (counts of the squares on the platform will look like $[2~ 3~ 1]$, and after removing one row will be $[1~ 2~ 0]$).
After the appearing of $9$-th square counts will be $[2~ 3~ 1]$, and after removing... | 0 | [
{
"input": "3 9\n1 1 2 2 2 3 1 2 3",
"output": "2"
},
{
"input": "1 7\n1 1 1 1 1 1 1",
"output": "7"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "3 5\n1 1 1 2 3",
"output": "1"
},
{
"input": "4 6\n4 4 4 4 4 4",
"output": "0"
},
{
"input": "4 6\... | 1,552,477,495 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 124 | 0 | rong,sl=map(int, input().split())
play=list(map(int, input().split()))
rs=sl
for i in range(1,rong+1):
dem=play.count(i)
if dem<rs:
rs=dem
print(rs) | Title: Tetris
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bo... | ```python
rong,sl=map(int, input().split())
play=list(map(int, input().split()))
rs=sl
for i in range(1,rong+1):
dem=play.count(i)
if dem<rs:
rs=dem
print(rs)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
962 | B | Students in Railway Carriage | PROGRAMMING | 1,300 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | There are $n$ consecutive seat places in a railway carriage. Each place is either empty or occupied by a passenger.
The university team for the Olympiad consists of $a$ student-programmers and $b$ student-athletes. Determine the largest number of students from all $a+b$ students, which you can put in the railway carri... | The first line contain three integers $n$, $a$ and $b$ ($1 \le n \le 2\cdot10^{5}$, $0 \le a, b \le 2\cdot10^{5}$, $a + b > 0$) — total number of seat places in the railway carriage, the number of student-programmers and the number of student-athletes.
The second line contains a string with length $n$, consisting o... | Print the largest number of students, which you can put in the railway carriage so that no student-programmer is sitting next to a student-programmer and no student-athlete is sitting next to a student-athlete. | [
"5 1 1\n*...*\n",
"6 2 3\n*...*.\n",
"11 3 10\n.*....**.*.\n",
"3 2 3\n***\n"
] | [
"2\n",
"4\n",
"7\n",
"0\n"
] | In the first example you can put all student, for example, in the following way: *.AB*
In the second example you can put four students, for example, in the following way: *BAB*B
In the third example you can put seven students, for example, in the following way: B*ABAB**A*B
The letter A means a student-programmer, an... | 0 | [
{
"input": "5 1 1\n*...*",
"output": "2"
},
{
"input": "6 2 3\n*...*.",
"output": "4"
},
{
"input": "11 3 10\n.*....**.*.",
"output": "7"
},
{
"input": "3 2 3\n***",
"output": "0"
},
{
"input": "9 5 3\n*...*...*",
"output": "6"
},
{
"input": "9 2 4\n*.... | 1,535,634,190 | 2,350 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 171 | 2,662,400 | #autogenerated (:'D)
read_numbers = lambda: list(map(int, input().split()))
INF = 1 << 64
#main
(n, a, b), ans = read_numbers(), 0
s = input()
m, j = [a, b], 0
for p in (len(place) for place in s.split('*') if len(place)):
if p & 1: j = 0 if a > b else 1
for i in range(p):
if m[0] == m[1... | Title: Students in Railway Carriage
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are $n$ consecutive seat places in a railway carriage. Each place is either empty or occupied by a passenger.
The university team for the Olympiad consists of $a$ student-programmers and $b$ student-... | ```python
#autogenerated (:'D)
read_numbers = lambda: list(map(int, input().split()))
INF = 1 << 64
#main
(n, a, b), ans = read_numbers(), 0
s = input()
m, j = [a, b], 0
for p in (len(place) for place in s.split('*') if len(place)):
if p & 1: j = 0 if a > b else 1
for i in range(p):
if m... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
166 | E | Tetrahedron | PROGRAMMING | 1,500 | [
"dp",
"math",
"matrices"
] | null | null | You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each moment of time he makes a step from one vertex to another one along some edge of the tetrahedron. ... | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=107) — the required length of the cyclic path. | Print the only integer — the required number of ways modulo 1000000007 (109<=+<=7). | [
"2\n",
"4\n"
] | [
"3\n",
"21\n"
] | The required paths in the first sample are:
- *D* - *A* - *D* - *D* - *B* - *D* - *D* - *C* - *D* | 1,000 | [
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "21"
},
{
"input": "1",
"output": "0"
},
{
"input": "3",
"output": "6"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "183"
},
{
"input": "7",
"output": "546"
... | 1,682,935,181 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 2,048,000 | n=int(input())
y=(pow(3,n)+3*pow(-1,n))//4
print(y%(10**9+7)) | Title: Tetrahedron
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each m... | ```python
n=int(input())
y=(pow(3,n)+3*pow(-1,n))//4
print(y%(10**9+7))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,625,757,758 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 184 | 0 | hh,mm=map(int,input().split(':'))
mm+=1
if mm == 60:
hh+=1
mm = 0
if hh == 24:
hh = 0
while hh % 10 * 10 + hh // 10 != mm:
mm+=1
if mm == 60:
hh+=1
mm = 0
if hh == 24:
hh = 0
if hh==0 and mm==0:
print("00:00")
elif hh==0:
print("00:",mm,sep="")
e... | Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
hh,mm=map(int,input().split(':'))
mm+=1
if mm == 60:
hh+=1
mm = 0
if hh == 24:
hh = 0
while hh % 10 * 10 + hh // 10 != mm:
mm+=1
if mm == 60:
hh+=1
mm = 0
if hh == 24:
hh = 0
if hh==0 and mm==0:
print("00:00")
elif hh==0:
print("00:",mm,... | 0 | MatrixStudio/Codeforces-Python-Submissions |
272 | D | Dima and Two Sequences | PROGRAMMING | 1,600 | [
"combinatorics",
"math",
"sortings"
] | null | null | Little Dima has two sequences of points with integer coordinates: sequence (*a*1,<=1),<=(*a*2,<=2),<=...,<=(*a**n*,<=*n*) and sequence (*b*1,<=1),<=(*b*2,<=2),<=...,<=(*b**n*,<=*n*).
Now Dima wants to count the number of distinct sequences of points of length 2·*n* that can be assembled from these sequences, such that... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). The third line contains *n* integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=109). The numbers in the lines are separated by spaces.
The last line contains integer *m* ... | In the single line print the remainder after dividing the answer to the problem by number *m*. | [
"1\n1\n2\n7\n",
"2\n1 2\n2 3\n11\n"
] | [
"1\n",
"2\n"
] | In the first sample you can get only one sequence: (1, 1), (2, 1).
In the second sample you can get such sequences : (1, 1), (2, 2), (2, 1), (3, 2); (1, 1), (2, 1), (2, 2), (3, 2). Thus, the answer is 2. | 2,000 | [
{
"input": "1\n1\n2\n7",
"output": "1"
},
{
"input": "2\n1 2\n2 3\n11",
"output": "2"
},
{
"input": "100\n1 8 10 6 5 3 2 3 4 2 3 7 1 1 5 1 4 1 8 1 5 5 6 5 3 7 4 5 5 3 8 7 8 6 8 9 10 7 8 5 8 9 1 3 7 2 6 1 7 7 2 8 1 5 4 2 10 4 9 8 1 10 1 5 9 8 1 9 5 1 5 7 1 6 7 8 8 2 2 3 3 7 2 10 6 3 6 3 5... | 1,649,934,371 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 16,588,800 | import collections
import math
import sys
def main():
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
d = collections.defaultdict(int)
div = 1
for x, y in zip(a, b):
d[x] += 1
d[y] += 1
if x == y:
div *= ... | Title: Dima and Two Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Dima has two sequences of points with integer coordinates: sequence (*a*1,<=1),<=(*a*2,<=2),<=...,<=(*a**n*,<=*n*) and sequence (*b*1,<=1),<=(*b*2,<=2),<=...,<=(*b**n*,<=*n*).
Now Dima wants to count the ... | ```python
import collections
import math
import sys
def main():
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
d = collections.defaultdict(int)
div = 1
for x, y in zip(a, b):
d[x] += 1
d[y] += 1
if x == y:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
844 | A | Diversity | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"strings"
] | null | null | Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too. | First line of input contains string *s*, consisting only of lowercase Latin letters (1<=≤<=|*s*|<=≤<=1000, |*s*| denotes the length of *s*).
Second line of input contains integer *k* (1<=≤<=*k*<=≤<=26). | Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible. | [
"yandex\n6\n",
"yahoo\n5\n",
"google\n7\n"
] | [
"0\n",
"1\n",
"impossible\n"
] | In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'*a*', '*h*', '*o*', '*y*'}. To get 5 different letters it is necessary to change one occurrence of '*o*' to some letter, which doesn't occur in the string, for... | 500 | [
{
"input": "yandex\n6",
"output": "0"
},
{
"input": "yahoo\n5",
"output": "1"
},
{
"input": "google\n7",
"output": "impossible"
},
{
"input": "a\n1",
"output": "0"
},
{
"input": "z\n2",
"output": "impossible"
},
{
"input": "fwgfrwgkuwghfiruhewgirueguhe... | 1,683,696,398 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | s = input().strip()
k = int(input())
if k > len(s):
print("impossible")
else:
freq = [0] * 26
for c in s:
freq[ord(c) - ord('a')] += 1
distinct_chars = sum([1 for f in freq if f > 0])
if distinct_chars >= k:
print(0)
else:
print(k - distinct_chars)
| Title: Diversity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it... | ```python
s = input().strip()
k = int(input())
if k > len(s):
print("impossible")
else:
freq = [0] * 26
for c in s:
freq[ord(c) - ord('a')] += 1
distinct_chars = sum([1 for f in freq if f > 0])
if distinct_chars >= k:
print(0)
else:
print(k - distinct_chars)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,690,478,980 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | s = int(input()) + 1
while len(set(str(s)))<4:s+=1
print(s) | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
s = int(input()) + 1
while len(set(str(s)))<4:s+=1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,687,374,952 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 15 | 0 | import math
t = 1#int(input())
for q in range(0, t):
# lenght = int(input())
# # lenght = 2
# s = input().split(" ")
#chislo, delit = map(int, input().split(' '))
n = int(input())
# s2 = input().split(' ')
# for i in range(0, len(s2)):
# s2[i] = int(s2[i])
for i in... | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
import math
t = 1#int(input())
for q in range(0, t):
# lenght = int(input())
# # lenght = 2
# s = input().split(" ")
#chislo, delit = map(int, input().split(' '))
n = int(input())
# s2 = input().split(' ')
# for i in range(0, len(s2)):
# s2[i] = int(s2[i])
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
722 | B | Verse Pattern | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowel... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the text.
The second line contains integers *p*1,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=100) — the verse pattern.
Next *n* lines contain the text itself. Text consists of lowercase English letters and spaces. It's guarant... | If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes). | [
"3\n2 2 3\nintel\ncode\nch allenge\n",
"4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz\n",
"4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageous fortune\nor to take arms against a sea of troubles\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, one can split words into syllables in the following way:
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one. | 500 | [
{
"input": "3\n2 2 3\nintel\ncode\nch allenge",
"output": "YES"
},
{
"input": "4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz",
"output": "NO"
},
{
"input": "4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageo... | 1,475,331,441 | 741 | Python 3 | OK | TESTS | 54 | 77 | 0 | import sys
n = int(input())
L = list(map(int, input().split()))
H = ['a', 'e', 'i', 'o', 'u', 'y']
a = "YES"
for i in range(n):
ss = input().split()
s = ""
ans = 0
for item in ss:
for x in item:
if (x in H):
ans += 1
if (ans != L[i]):
a =... | Title: Verse Pattern
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary num... | ```python
import sys
n = int(input())
L = list(map(int, input().split()))
H = ['a', 'e', 'i', 'o', 'u', 'y']
a = "YES"
for i in range(n):
ss = input().split()
s = ""
ans = 0
for item in ss:
for x in item:
if (x in H):
ans += 1
if (ans != L[i]):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,645,030,662 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | answer=''
data=input().split('.')
for item in data:
if item=='':
answer=answer+str(0)
elif item=='-':
answer=answer+str(1)
else:
answer=answer+str(2)
print(answer)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
answer=''
data=input().split('.')
for item in data:
if item=='':
answer=answer+str(0)
elif item=='-':
answer=answer+str(1)
else:
answer=answer+str(2)
print(answer)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
234 | C | Weather | PROGRAMMING | 1,300 | [
"dp",
"implementation"
] | null | null | Scientists say a lot about the problems of global warming and cooling of the Earth. Indeed, such natural phenomena strongly influence all life on our planet.
Our hero Vasya is quite concerned about the problems. He decided to try a little experiment and observe how outside daily temperature changes. He hung out a ther... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of days for which Vasya has been measuring the temperature.
The second line contains a sequence of *n* integers *t*1,<=*t*2,<=...,<=*t**n* (|*t**i*|<=≤<=109) — the sequence of temperature values. Numbers *t**i* are separated by single space... | Print a single integer — the answer to the given task. | [
"4\n-1 1 -2 1\n",
"5\n0 -1 1 2 -5\n"
] | [
"1\n",
"2\n"
] | Note to the first sample: there are two ways to change exactly one number so that the sequence met Vasya's condition. You can either replace the first number 1 by any negative number or replace the number -2 by any positive number. | 0 | [
{
"input": "4\n-1 1 -2 1",
"output": "1"
},
{
"input": "5\n0 -1 1 2 -5",
"output": "2"
},
{
"input": "6\n0 0 0 0 0 0",
"output": "6"
},
{
"input": "6\n-1 -2 -3 -4 5 6",
"output": "0"
},
{
"input": "8\n1 2 -1 0 10 2 12 13",
"output": "3"
},
{
"input": "... | 1,620,682,048 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 6,656,000 | f=open("input.txt","r")
a=list(map(int,f.readline().split()))
b=min(a)
o=open("output.txt","w")
c=a[0]-a[1]
if c==0:
o.write("BG"*b)
if c>0:
o.write("BG"*b+"B"*c)
if c<0:
o.write("GB"*b+"G"*(-c))
#assist from friend
| Title: Weather
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scientists say a lot about the problems of global warming and cooling of the Earth. Indeed, such natural phenomena strongly influence all life on our planet.
Our hero Vasya is quite concerned about the problems. He decided to ... | ```python
f=open("input.txt","r")
a=list(map(int,f.readline().split()))
b=min(a)
o=open("output.txt","w")
c=a[0]-a[1]
if c==0:
o.write("BG"*b)
if c>0:
o.write("BG"*b+"B"*c)
if c<0:
o.write("GB"*b+"G"*(-c))
#assist from friend
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
560 | A | Currency System in Geraldion | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of ea... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes. | Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1. | [
"5\n1 2 3 4 5\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "10\n371054 506438 397130 1 766759 208409 769264 549213 641270 771837",
"output": "-1"
},
{
"input": "10\n635370 154890 909382 220996 276501 716105 538714 140162 171960 271264",
"o... | 1,459,242,905 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 62 | 4,915,200 | n=int(input())
l=sorted(map(int,input().split()))
if l[0]!=1: print(1)
else: print(-1) | Title: Currency System in Geraldion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cann... | ```python
n=int(input())
l=sorted(map(int,input().split()))
if l[0]!=1: print(1)
else: print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You already know that Valery's favorite sport is biathlon. Due to your help, he learned to shoot without missing, and his skills are unmatched at the shooting range. But now a smaller task is to be performed, he should learn to complete the path fastest.
The track's map is represented by a rectangle *n*<=×<=*m* in siz... | The first input line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=50,<=*n*·*m*<=≥<=2,<=1<=≤<=*k*<=≤<=4). Then *n* lines contain the map. Each line has the length of exactly *m* characters and consists of lowercase Latin letters and characters *S* and *T*. It is guaranteed that the map contains exactly ... | If there is a path that satisfies the condition, print it as a sequence of letters — the plot types. Otherwise, print "-1" (without quotes). You shouldn't print the character *S* in the beginning and *T* in the end.
Note that this sequence may be empty. This case is present in pretests. You can just print nothing or p... | [
"5 3 2\nSba\nccc\naac\nccc\nabT\n",
"3 4 1\nSxyy\nyxxx\nyyyT\n",
"1 3 3\nTyS\n",
"1 4 1\nSxyT\n"
] | [
"bcccc\n",
"xxxx\n",
"y\n",
"-1\n"
] | none | 0 | [
{
"input": "5 3 2\nSba\nccc\naac\nccc\nabT",
"output": "bcccc"
},
{
"input": "3 4 1\nSxyy\nyxxx\nyyyT",
"output": "xxxx"
},
{
"input": "1 3 3\nTyS",
"output": "y"
},
{
"input": "1 4 1\nSxyT",
"output": "-1"
},
{
"input": "1 3 3\nSaT",
"output": "a"
},
{
... | 1,692,462,547 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1692462546.5911705")# 1692462546.5911868 | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You already know that Valery's favorite sport is biathlon. Due to your help, he learned to shoot without missing, and his skills are unmatched at the shooting range. But now a smaller task is to be performed, he should learn to co... | ```python
print("_RANDOM_GUESS_1692462546.5911705")# 1692462546.5911868
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,668,332,544 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | Slovo=input()
reversedSlovo=input()
Slovo=Slovo[::-1]
if Slovo==reversedSlovo:
print('YES')
else:
print('NO') | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
Slovo=input()
reversedSlovo=input()
Slovo=Slovo[::-1]
if Slovo==reversedSlovo:
print('YES')
else:
print('NO')
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,679,998,441 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n, x, y = map(int, input().split())
L, R = 0, (n - 1) * max(x, y)
while R > L + 1:
M = (R + L) // 2
if (M // x + M // y) < n - 1:
L = M
else:
R = Mprint(R + min(x, y))
# Tue Mar 28 2023 13:14:00 GMT+0300 (Moscow Standard Time)
| Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
n, x, y = map(int, input().split())
L, R = 0, (n - 1) * max(x, y)
while R > L + 1:
M = (R + L) // 2
if (M // x + M // y) < n - 1:
L = M
else:
R = Mprint(R + min(x, y))
# Tue Mar 28 2023 13:14:00 GMT+0300 (Moscow Standard Time)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,679,595,172 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 2,048,000 | n, k = map(int, input().split())
divisors = []
for i in range(1, n+1):
if n % i == 0:
divisors.append(i)
if len(divisors) >= k:
print(divisors[k-1])
else:
print(-1) | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
n, k = map(int, input().split())
divisors = []
for i in range(1, n+1):
if n % i == 0:
divisors.append(i)
if len(divisors) >= k:
print(divisors[k-1])
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,427,371,019 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 62 | 0 | # coding: utf-8
a = int(input())
b = 0
while True:
b += 1
for ch in str(a+b):
if ch == '8':
print(b)
exit()
| Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
# coding: utf-8
a = int(input())
b = 0
while True:
b += 1
for ch in str(a+b):
if ch == '8':
print(b)
exit()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,619,703,223 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | n = int(input())
a = sum(list(map(int,input().split())))
m = a+5+1
b = [i for i in range(1,m,n+1)]
c=0
for i in range(1,6):
if(a+i not in b):
c+=1
print(c) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n = int(input())
a = sum(list(map(int,input().split())))
m = a+5+1
b = [i for i in range(1,m,n+1)]
c=0
for i in range(1,6):
if(a+i not in b):
c+=1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
799 | A | Carrot Cakes | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he currently don't have any. However, he has infinitely many ingredients and one oven. Moreover, Arkady... | The only line contains four integers *n*, *t*, *k*, *d* (1<=≤<=*n*,<=*t*,<=*k*,<=*d*<=≤<=1<=000) — the number of cakes needed, the time needed for one oven to bake *k* cakes, the number of cakes baked at the same time, the time needed to build the second oven. | If it is reasonable to build the second oven, print "YES". Otherwise print "NO". | [
"8 6 4 5\n",
"8 6 4 6\n",
"10 3 11 4\n",
"4 2 1 4\n"
] | [
"YES\n",
"NO\n",
"NO\n",
"YES\n"
] | In the first example it is possible to get 8 cakes in 12 minutes using one oven. The second oven can be built in 5 minutes, so after 6 minutes the first oven bakes 4 cakes, the second oven bakes 4 more ovens after 11 minutes. Thus, it is reasonable to build the second oven.
In the second example it doesn't matter whe... | 500 | [
{
"input": "8 6 4 5",
"output": "YES"
},
{
"input": "8 6 4 6",
"output": "NO"
},
{
"input": "10 3 11 4",
"output": "NO"
},
{
"input": "4 2 1 4",
"output": "YES"
},
{
"input": "28 17 16 26",
"output": "NO"
},
{
"input": "60 69 9 438",
"output": "NO"... | 1,610,907,656 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n, t, k, d = map(int, input().split())
using_1oven = int(round((t/k)*n))
using_2oven = d + using_1oven/2
if using_2oven < using_1oven:
print('YES')
else: print('NO') | Title: Carrot Cakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he cu... | ```python
n, t, k, d = map(int, input().split())
using_1oven = int(round((t/k)*n))
using_2oven = d + using_1oven/2
if using_2oven < using_1oven:
print('YES')
else: print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
688 | A | Opponents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of them all. That means if one day at least one of Arya's opponents is absent at the school, then Ar... | The first line of the input contains two integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=100) — the number of opponents and the number of days, respectively.
The *i*-th of the following *d* lines contains a string of length *n* consisting of characters '0' and '1'. The *j*-th character of this string is '0' if the *j*-th op... | Print the only integer — the maximum number of consecutive days that Arya will beat all present opponents. | [
"2 2\n10\n00\n",
"4 1\n0100\n",
"4 5\n1101\n1111\n0110\n1011\n1111\n"
] | [
"2\n",
"1\n",
"2\n"
] | In the first and the second samples, Arya will beat all present opponents each of the *d* days.
In the third sample, Arya will beat his opponents on days 1, 3 and 4 and his opponents will beat him on days 2 and 5. Thus, the maximum number of consecutive winning days is 2, which happens on days 3 and 4. | 500 | [
{
"input": "2 2\n10\n00",
"output": "2"
},
{
"input": "4 1\n0100",
"output": "1"
},
{
"input": "4 5\n1101\n1111\n0110\n1011\n1111",
"output": "2"
},
{
"input": "3 2\n110\n110",
"output": "2"
},
{
"input": "10 6\n1111111111\n0100110101\n1111111111\n0000011010\n1111... | 1,639,391,118 | 918 | PyPy 3-64 | OK | TESTS | 56 | 109 | 1,945,600 | n, d = [int(i) for i in input().split()]
m = 0
now = 0
for i in range(d):
if not all([bool(int(j)) for j in list(input())]):
now += 1
else:
m = max(m, now)
now = 0
m = max(m, now)
print(m)
| Title: Opponents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of th... | ```python
n, d = [int(i) for i in input().split()]
m = 0
now = 0
for i in range(d):
if not all([bool(int(j)) for j in list(input())]):
now += 1
else:
m = max(m, now)
now = 0
m = max(m, now)
print(m)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,610,829,885 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 20 | 62 | 307,200 | import math
def maximumToys(q):
# arr=q[:3]
# n=q[0]
# if(n%min(arr)==0):
# return int(n/min(arr))
# else:
# val= math.floor(n/min(arr))-1
# val_1= val* min(arr)
# val_1
q= q+" "
max_W = 0
temp =0
for i in range (0,len(q)... | Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
import math
def maximumToys(q):
# arr=q[:3]
# n=q[0]
# if(n%min(arr)==0):
# return int(n/min(arr))
# else:
# val= math.floor(n/min(arr))-1
# val_1= val* min(arr)
# val_1
q= q+" "
max_W = 0
temp =0
for i in range... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,592,840,462 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 140 | 1,536,000 | A = input()
n = len(A)
ans = 0
for i in range(n-2):
if A[i] == 'Q':
for j in range(i+1,n-1):
if A[j] == 'A':
for m in range(j+1,n):
if A[m] == 'Q':
ans += 1
print(ans) | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
A = input()
n = len(A)
ans = 0
for i in range(n-2):
if A[i] == 'Q':
for j in range(i+1,n-1):
if A[j] == 'A':
for m in range(j+1,n):
if A[m] == 'Q':
ans += 1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,568,556,588 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 248 | 0 | n = int(input())
i = 0
teams = list()
while i < n:
teams.append(input())
i += 1
teams.sort()
count = 1
if len(teams) == 1:
print(teams[0])
else:
for i in range(len(teams)-1):
if teams[i] == teams[i+1]:
count += 1
else:
if count > len(teams) - count:
... | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
n = int(input())
i = 0
teams = list()
while i < n:
teams.append(input())
i += 1
teams.sort()
count = 1
if len(teams) == 1:
print(teams[0])
else:
for i in range(len(teams)-1):
if teams[i] == teams[i+1]:
count += 1
else:
if count > len(teams) - count:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
690 | C2 | Brain Network (medium) | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Further research on zombie thought processes yielded interesting results. As we know from the previous problem, the nervous system of a zombie consists of *n* brains and *m* brain connectors joining some pairs of brains together. It was observed that the intellectual abilities of a zombie depend mainly on the topology ... | The first line of the input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100000) denoting the number of brains (which are conveniently numbered from 1 to *n*) and the number of brain connectors in the nervous system, respectively. In the next *m* lines, descriptions of brain connectors follow.... | Print one number – the brain latency. | [
"4 3\n1 2\n1 3\n1 4\n",
"5 4\n1 2\n2 3\n3 4\n3 5\n"
] | [
"2",
"3"
] | none | 0 | [
{
"input": "2 1\n1 2",
"output": "1"
},
{
"input": "3 2\n2 1\n3 2",
"output": "2"
},
{
"input": "10 9\n5 1\n1 2\n9 3\n10 5\n6 3\n8 5\n2 7\n2 3\n9 4",
"output": "6"
},
{
"input": "4 3\n1 2\n1 3\n1 4",
"output": "2"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n3 5",
"outp... | 1,582,113,333 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 7 | 452 | 16,486,400 | import sys
input=sys.stdin.readline
t=1
import math
def dfs(a,i,dis):
vis[i]=1
for j in a[i]:
if vis[j]==0:
dis[j]=dis[i]+1
dfs(a,j,dis)
while t>0:
t-=1
n,m=map(int,input().split())
a=[[] for i in range(n+1)]
for i in range(m):
x,y=map(i... | Title: Brain Network (medium)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Further research on zombie thought processes yielded interesting results. As we know from the previous problem, the nervous system of a zombie consists of *n* brains and *m* brain connectors joining some pairs of... | ```python
import sys
input=sys.stdin.readline
t=1
import math
def dfs(a,i,dis):
vis[i]=1
for j in a[i]:
if vis[j]==0:
dis[j]=dis[i]+1
dfs(a,j,dis)
while t>0:
t-=1
n,m=map(int,input().split())
a=[[] for i in range(n+1)]
for i in range(m):
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,641,820,586 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 109 | 0 | k=int(input())
for i in range(1,21):
if "8" in str(k+i) :
print(i)
exit() | Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
k=int(input())
for i in range(1,21):
if "8" in str(k+i) :
print(i)
exit()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
493 | B | Vasya and Wrestling | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of... | The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* poin... | If the first wrestler wins, print string "first", otherwise print "second" | [
"5\n1\n2\n-3\n-4\n3\n",
"3\n-1\n-2\n3\n",
"2\n4\n-4\n"
] | [
"second\n",
"first\n",
"second\n"
] | Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |... | 1,000 | [
{
"input": "5\n1\n2\n-3\n-4\n3",
"output": "second"
},
{
"input": "3\n-1\n-2\n3",
"output": "first"
},
{
"input": "2\n4\n-4",
"output": "second"
},
{
"input": "7\n1\n2\n-3\n4\n5\n-6\n7",
"output": "first"
},
{
"input": "14\n1\n2\n3\n4\n5\n6\n7\n-8\n-9\n-10\n-11\n-... | 1,609,930,021 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 389 | 6,451,200 | def wrestler(one,two):
s1=sum(one)
s2=sum(two)
if s1>s2:
return "first"
if s2>s1:
return "second"
else:
if two>one:
return ("second")
else:
return ("first")
ls=[]
ls2=[]
flag=True
for i in range(int(input())):
a=int(input(... | Title: Vasya and Wrestling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers ... | ```python
def wrestler(one,two):
s1=sum(one)
s2=sum(two)
if s1>s2:
return "first"
if s2>s1:
return "second"
else:
if two>one:
return ("second")
else:
return ("first")
ls=[]
ls2=[]
flag=True
for i in range(int(input())):
a=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
981 | A | Antipalindrome | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not.
A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2}... | The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. | If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$.
Note that there can be multiple longest substrings that are not palindromes, but their length is unique. | [
"mew\n",
"wuffuw\n",
"qqqqqqqq\n"
] | [
"3\n",
"5\n",
"0\n"
] | "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$.
The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$.
All sub... | 500 | [
{
"input": "mew",
"output": "3"
},
{
"input": "wuffuw",
"output": "5"
},
{
"input": "qqqqqqqq",
"output": "0"
},
{
"input": "ijvji",
"output": "4"
},
{
"input": "iiiiiii",
"output": "0"
},
{
"input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow"... | 1,694,986,879 | 2,147,483,647 | Python 3 | OK | TESTS | 133 | 46 | 0 | def isPalindrome(s):
isPalindrome = True
for i in range(len(s)//2):
if(s[i] != s[-i-1]):
isPalindrome = False
return isPalindrome;
def getBiggest(s):
best = 0
for i in range(len(s)):
temp = s[i]
for j in range(i + 1, len(s)):
temp += s[j]
if not isPalindrome(temp... | Title: Antipalindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" ar... | ```python
def isPalindrome(s):
isPalindrome = True
for i in range(len(s)//2):
if(s[i] != s[-i-1]):
isPalindrome = False
return isPalindrome;
def getBiggest(s):
best = 0
for i in range(len(s)):
temp = s[i]
for j in range(i + 1, len(s)):
temp += s[j]
if not isPalin... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at ... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepa... | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,593,898,002 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 6,963,200 | n, m = [int(i) for i in input().split()]
grades = []
res = 0
for i in range(n):
g = input()
sub = []
for j in g:
sub.append(int(j))
grades.append(sub)
pos = 0
while pos < len(grades[0]):
subj = []
for student in grades:
subj.append(student[pos])
sub = []
... | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student ... | ```python
n, m = [int(i) for i in input().split()]
grades = []
res = 0
for i in range(n):
g = input()
sub = []
for j in g:
sub.append(int(j))
grades.append(sub)
pos = 0
while pos < len(grades[0]):
subj = []
for student in grades:
subj.append(student[pos])
sub ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
499 | A | Watching a movie | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the player automatically proceeds to the next minute of the movie. 1. Skip exactly *x* minutes of the movie... | The first line contains two space-separated integers *n*, *x* (1<=≤<=*n*<=≤<=50, 1<=≤<=*x*<=≤<=105) — the number of the best moments of the movie and the value of *x* for the second button.
The following *n* lines contain the descriptions of the best moments of the movie, the *i*-th line of the description contains tw... | Output a single number — the answer to the problem. | [
"2 3\n5 6\n10 12\n",
"1 1\n1 100000\n"
] | [
"6\n",
"100000\n"
] | In the first sample, the player was initially standing on the first minute. As the minutes from the 1-st to the 4-th one don't contain interesting moments, we press the second button. Now we can not press the second button and skip 3 more minutes, because some of them contain interesting moments. Therefore, we watch th... | 500 | [
{
"input": "2 3\n5 6\n10 12",
"output": "6"
},
{
"input": "1 1\n1 100000",
"output": "100000"
},
{
"input": "10 1\n2156 3497\n4784 7775\n14575 31932\n33447 35902\n36426 47202\n48772 60522\n63982 68417\n78537 79445\n90081 90629\n94325 95728",
"output": "53974"
},
{
"input": "1... | 1,597,128,987 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 109 | 6,656,000 | n,x =[int(x) for x in input("").split()]
sum=0
prev=0
for i in range(n):
a,b=[int(x) for x in input("").split()]
sum=sum+((a-prev)%x) +(b-a)
prev=b
if(x==1):
print(sum+1)
else:
print(sum) | Title: Watching a movie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the pl... | ```python
n,x =[int(x) for x in input("").split()]
sum=0
prev=0
for i in range(n):
a,b=[int(x) for x in input("").split()]
sum=sum+((a-prev)%x) +(b-a)
prev=b
if(x==1):
print(sum+1)
else:
print(sum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
285 | B | Find Marble | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not.
First Petya puts a marble under the glass in position *s*. Then he performs som... | The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaran... | If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1. | [
"4 2 1\n2 3 4 1\n",
"4 3 3\n4 1 3 2\n",
"4 3 4\n1 2 3 4\n",
"3 1 3\n2 1 3\n"
] | [
"3\n",
"0\n",
"-1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "4 2 1\n2 3 4 1",
"output": "3"
},
{
"input": "4 3 3\n4 1 3 2",
"output": "0"
},
{
"input": "4 3 4\n1 2 3 4",
"output": "-1"
},
{
"input": "3 1 3\n2 1 3",
"output": "-1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 6 7\n10 7 8 1... | 1,564,467,308 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 404 | 10,547,200 | n,s,e = list(map(int,input().split()))
s-=1
e-=1
a = list(map(int,input().split()))
a = [x-1 for x in a]
i =s
found = False
if s==e:
print(0)
found=True
count = 0
#print(s,e,"start",a)
while (not (i==s and count>0)) and (not found) :
i = a[i]
count+=1
#print(i,count)
if i==e:
... | Title: Find Marble
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the ... | ```python
n,s,e = list(map(int,input().split()))
s-=1
e-=1
a = list(map(int,input().split()))
a = [x-1 for x in a]
i =s
found = False
if s==e:
print(0)
found=True
count = 0
#print(s,e,"start",a)
while (not (i==s and count>0)) and (not found) :
i = a[i]
count+=1
#print(i,count)
i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
87 | D | Beautiful Road | PROGRAMMING | 2,300 | [
"dfs and similar",
"dp",
"dsu",
"graphs",
"implementation",
"sortings",
"trees"
] | D. Beautiful Road | 1 | 256 | A long time ago in some country in Asia were civil wars.
Each of *n* cities wanted to seize power. That's why sometimes one city gathered an army and sent it to campaign against another city.
Road making was difficult, so the country had few roads, exactly *n*<=-<=1. Also you could reach any city from any other city ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=105), which represents the number of cities. Next *n*<=-<=1 lines contain three integers each: the numbers of cities *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), connected by the *i*-th road and the number of days *d**i* the army spends to go on it (1<=≤<=*d**i*... | Print on the first line two integers — the number of beautiful trees on the most beautiful road and the number of the most beautiful roads. Print on the second line the list of the most beautiful roads in the sorted order by the numbers' increasing. The roads are numbered from 1 to *n*<=-<=1 in the order in which they ... | [
"2\n2 1 5\n",
"6\n1 2 1\n1 3 5\n3 4 2\n3 5 3\n3 6 4\n"
] | [
"2 1\n1 \n",
"16 1\n2 \n"
] | none | 2,000 | [
{
"input": "2\n2 1 5",
"output": "2 1\n1 "
},
{
"input": "6\n1 2 1\n1 3 5\n3 4 2\n3 5 3\n3 6 4",
"output": "16 1\n2 "
},
{
"input": "10\n10 6 43981\n4 2 6730\n1 2 35174\n5 3 61951\n8 7 43981\n7 1 6730\n5 8 6730\n9 3 52479\n6 4 18138",
"output": "32 1\n4 "
},
{
"input": "9\n6 ... | 1,605,092,706 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 1,000 | 50,176,000 |
class DisjoinSet:
def __init__(self, n):
self.padre = [x for x in range(0, n)]
self.cantidad_vertices = [1]*n
def Padre(self, x):
if x == self.padre[x]:
return x
self.padre[x] = self.Padre(self.padre[x])
return self.padre[x]
def Union(self, ... | Title: Beautiful Road
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
A long time ago in some country in Asia were civil wars.
Each of *n* cities wanted to seize power. That's why sometimes one city gathered an army and sent it to campaign against another city.
Road making was difficult, so ... | ```python
class DisjoinSet:
def __init__(self, n):
self.padre = [x for x in range(0, n)]
self.cantidad_vertices = [1]*n
def Padre(self, x):
if x == self.padre[x]:
return x
self.padre[x] = self.Padre(self.padre[x])
return self.padre[x]
def Un... | 0 | MatrixStudio/Codeforces-Python-Submissions |
185 | A | Plant | PROGRAMMING | 1,300 | [
"math"
] | null | null | Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will point "upwards" and one will point "downwards". After another year, each triangle plant divide... | The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1018) — the number of full years when the plant grew.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | Print a single integer — the remainder of dividing the number of plants that will point "upwards" in *n* years by 1000000007 (109<=+<=7). | [
"1\n",
"2\n"
] | [
"3\n",
"10\n"
] | The first test sample corresponds to the second triangle on the figure in the statement. The second test sample corresponds to the third one. | 500 | [
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "10"
},
{
"input": "385599124",
"output": "493875375"
},
{
"input": "989464295",
"output": "31966163"
},
{
"input": "376367012",
"output": "523204186"
},
{
"input": "529357306",
"output": "... | 1,401,436,980 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | n = int(input())
res = pow(2, n, 1000000007)
print((res+1)*res//2) | Title: Plant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will poi... | ```python
n = int(input())
res = pow(2, n, 1000000007)
print((res+1)*res//2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
620 | C | Pearls in a Row | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | There are *n* pearls in a row. Let's enumerate them with integers from 1 to *n* from the left to the right. The pearl number *i* has the type *a**i*.
Let's call a sequence of consecutive pearls a segment. Let's call a segment good if it contains two pearls of the same type.
Split the row of the pearls to the maximal ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of pearls in a row.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) – the type of the *i*-th pearl. | On the first line print integer *k* — the maximal number of segments in a partition of the row.
Each of the next *k* lines should contain two integers *l**j*,<=*r**j* (1<=≤<=*l**j*<=≤<=*r**j*<=≤<=*n*) — the number of the leftmost and the rightmost pearls in the *j*-th segment.
Note you should print the correct partit... | [
"5\n1 2 3 4 1\n",
"5\n1 2 3 4 5\n",
"7\n1 2 1 3 1 2 1\n"
] | [
"1\n1 5\n",
"-1\n",
"2\n1 3\n4 7\n"
] | none | 0 | [
{
"input": "5\n1 2 3 4 1",
"output": "1\n1 5"
},
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "7\n1 2 1 3 1 2 1",
"output": "2\n1 3\n4 7"
},
{
"input": "9\n1 2 1 2 1 2 1 2 1",
"output": "3\n1 3\n4 6\n7 9"
},
{
"input": "11\n1 1 2 1 2 1 2 1 2 1 1",
"... | 1,620,156,123 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 124 | 3,276,800 | import re
import sys
exit=sys.exit
from bisect import bisect_left as bsl,bisect_right as bsr
from collections import Counter,defaultdict as ddict,deque
from functools import lru_cache
cache=lru_cache(None)
from heapq import *
from itertools import *
from math import inf
from pprint import pprint as pp
enum=e... | Title: Pearls in a Row
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* pearls in a row. Let's enumerate them with integers from 1 to *n* from the left to the right. The pearl number *i* has the type *a**i*.
Let's call a sequence of consecutive pearls a segment. Let's call a ... | ```python
import re
import sys
exit=sys.exit
from bisect import bisect_left as bsl,bisect_right as bsr
from collections import Counter,defaultdict as ddict,deque
from functools import lru_cache
cache=lru_cache(None)
from heapq import *
from itertools import *
from math import inf
from pprint import pprint as ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
302 | A | Eugeny and Array | PROGRAMMING | 800 | [
"implementation"
] | null | null | Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of a... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). | Print *m* integers — the responses to Eugene's queries in the order they occur in the input. | [
"2 3\n1 -1\n1 1\n1 2\n2 2\n",
"5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n"
] | [
"0\n1\n0\n",
"0\n1\n0\n1\n0\n"
] | none | 500 | [
{
"input": "2 3\n1 -1\n1 1\n1 2\n2 2",
"output": "0\n1\n0"
},
{
"input": "5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5",
"output": "0\n1\n0\n1\n0"
},
{
"input": "3 3\n1 1 1\n2 2\n1 1\n1 1",
"output": "0\n0\n0"
},
{
"input": "4 4\n-1 -1 -1 -1\n1 3\n1 2\n1 2\n1 1",
"output": "... | 1,593,509,120 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 155 | 22,220,800 | n,m=map(int,input().split())
list1=[0]*((2*100000)+1)
list2=list(map(int,input().split()))
j=0
for i in range(n):
list1[j]=list2[i]
j+=1
for i in range(1,2*100000+1):
list1[i]=list1[i]+list1[i-1]
for i in range(m):
x,y=map(int,input().split())
if(abs(x-y)>0):
if(list1[x]-li... | Title: Eugeny and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (... | ```python
n,m=map(int,input().split())
list1=[0]*((2*100000)+1)
list2=list(map(int,input().split()))
j=0
for i in range(n):
list1[j]=list2[i]
j+=1
for i in range(1,2*100000+1):
list1[i]=list1[i]+list1[i-1]
for i in range(m):
x,y=map(int,input().split())
if(abs(x-y)>0):
if(l... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,693,332,138 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 13,619,200 | n, b, d = list(map(int, input().split()))
oranges = list(map(int, input().split()))
oranges = list(filter(lambda x: x <= b, oranges))
answer = 0 if len(oranges) == 0 or sum(oranges) - d == 0 else sum(oranges) // d
print(answer) | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
n, b, d = list(map(int, input().split()))
oranges = list(map(int, input().split()))
oranges = list(filter(lambda x: x <= b, oranges))
answer = 0 if len(oranges) == 0 or sum(oranges) - d == 0 else sum(oranges) // d
print(answer)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
45 | A | Codecraft III | PROGRAMMING | 900 | [
"implementation"
] | A. Codecraft III | 2 | 256 | Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly *k* months. He looked at the calendar and learned that at the moment is the month number *s*. Vasya immediately got interested in what month Codecraft III will appear. Help him understa... | The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer *k* (0<=≤<=*k*<=≤<=100) — the number of months left till the appearance of Codecraft III. | Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December. | [
"November\n3\n",
"May\n24\n"
] | [
"February\n",
"May\n"
] | none | 0 | [
{
"input": "November\n3",
"output": "February"
},
{
"input": "May\n24",
"output": "May"
},
{
"input": "April\n0",
"output": "April"
},
{
"input": "September\n0",
"output": "September"
},
{
"input": "August\n0",
"output": "August"
},
{
"input": "June\n1... | 1,653,084,647 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | first_month = input()
n = int(input())
months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
initial = months.index(first_month)
final_month = (initial + n) % 12
print(months[final_month])
| Title: Codecraft III
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly *k* months. He looked at the calendar and learned that at the moment is the month number *... | ```python
first_month = input()
n = int(input())
months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
initial = months.index(first_month)
final_month = (initial + n) % 12
print(months[final_month])
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
299 | B | Ksusha the Squirrel | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to the end of the road, that is, get to sector *n*. Unfortunately, there are some rocks on the road. We know ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=3·105,<=1<=≤<=*k*<=≤<=3·105). The next line contains *n* characters — the description of the road: the *i*-th character equals ".", if the *i*-th sector contains no rocks. Otherwise, it equals "#".
It is guaranteed that the first and the last characters e... | Print "YES" (without the quotes) if Ksusha can reach the end of the road, otherwise print "NO" (without the quotes). | [
"2 1\n..\n",
"5 2\n.#.#.\n",
"7 3\n.#.###.\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 1,000 | [
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "5 2\n.#.#.",
"output": "YES"
},
{
"input": "7 3\n.#.###.",
"output": "NO"
},
{
"input": "2 200\n..",
"output": "YES"
},
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "2 2\n..",
"output": "Y... | 1,557,740,522 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 310 | 2,867,200 | def main():
from re import findall
[__, k] = [int(_) for _ in input().split()]
road = input()
print('YES' if '#' not in road or max(len(s) for s in findall(r'#+', road)) < k else
'NO')
if __name__ == '__main__':
main()
| Title: Ksusha the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to t... | ```python
def main():
from re import findall
[__, k] = [int(_) for _ in input().split()]
road = input()
print('YES' if '#' not in road or max(len(s) for s in findall(r'#+', road)) < k else
'NO')
if __name__ == '__main__':
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
797 | B | Odd sum | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains subsequence with odd sum.
Subsequence is a sequence that can be derived from another sequen... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=104<=≤<=*a**i*<=≤<=104). The sequence contains at least one subsequence with odd sum. | Print sum of resulting subseqeuence. | [
"4\n-2 2 -3 1\n",
"3\n2 -5 -3\n"
] | [
"3\n",
"-1\n"
] | In the first example sum of the second and the fourth elements is 3. | 0 | [
{
"input": "4\n-2 2 -3 1",
"output": "3"
},
{
"input": "3\n2 -5 -3",
"output": "-1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "1\n-1",
"output": "-1"
},
{
"input": "15\n-6004 4882 9052 413 6056 4306 9946 -4616 -6135 906 -1718 5252 -2866 9061 4046",
"ou... | 1,683,186,341 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 126 | 93 | 13,107,200 | n = int(input())
a = list(map(int, input().split()))
count_nech = 0
prev_nech = None
ans = 0
a.sort(reverse=True)
for i in a:
if i > 0:
if i % 2 == 0:
ans += i
else:
if count_nech == 0:
ans += i
elif count_nech % 2 == 0:
... | Title: Odd sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains... | ```python
n = int(input())
a = list(map(int, input().split()))
count_nech = 0
prev_nech = None
ans = 0
a.sort(reverse=True)
for i in a:
if i > 0:
if i % 2 == 0:
ans += i
else:
if count_nech == 0:
ans += i
elif count_nech % 2 == 0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,696,569,657 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 124 | 0 | test=int(input())
n=0
list1= []
list2= []
i=0
while i<test:
a,b= map(int, input().split())
list1.append(a)
list2.append(b)
i+=1
for i in range(test):
for j in range(i):
if list1[i] ==list2[j]:
n+= 1
if list2[i] ==list1[j]:
n+= 1
print(n)
| Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
test=int(input())
n=0
list1= []
list2= []
i=0
while i<test:
a,b= map(int, input().split())
list1.append(a)
list2.append(b)
i+=1
for i in range(test):
for j in range(i):
if list1[i] ==list2[j]:
n+= 1
if list2[i] ==list1[j]:
n+= 1
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
834 | B | The Festive Evening | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here are not supposed to be disclosed to the general public: the information can cause discord in the kingdom... | Two integers are given in the first string: the number of guests *n* and the number of guards *k* (1<=≤<=*n*<=≤<=106, 1<=≤<=*k*<=≤<=26).
In the second string, *n* uppercase English letters *s*1*s*2... *s**n* are given, where *s**i* is the entrance used by the *i*-th guest. | Output «YES» if at least one door was unguarded during some time, and «NO» otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"5 1\nAABBB\n",
"5 1\nABABB\n"
] | [
"NO\n",
"YES\n"
] | In the first sample case, the door A is opened right before the first guest's arrival and closed when the second guest enters the castle. The door B is opened right before the arrival of the third guest, and closed after the fifth one arrives. One guard can handle both doors, as the first one is closed before the secon... | 1,000 | [
{
"input": "5 1\nAABBB",
"output": "NO"
},
{
"input": "5 1\nABABB",
"output": "YES"
},
{
"input": "26 1\nABCDEFGHIJKLMNOPQRSTUVWXYZ",
"output": "NO"
},
{
"input": "27 1\nABCDEFGHIJKLMNOPQRSTUVWXYZA",
"output": "YES"
},
{
"input": "5 2\nABACA",
"output": "NO"
... | 1,503,253,430 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 3,072,000 | def solution():
n, k = (int(x) for x in input().split())
tmp = k
open_doors = set()
prev = ' '
s = input()
while len(s):
if s.count(s[0]) == 1 and s[0] not in open_doors and tmp >= 1:
pass
elif s.count(s[0]) > 1 and s[0] not in open_doors:
tm... | Title: The Festive Evening
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here... | ```python
def solution():
n, k = (int(x) for x in input().split())
tmp = k
open_doors = set()
prev = ' '
s = input()
while len(s):
if s.count(s[0]) == 1 and s[0] not in open_doors and tmp >= 1:
pass
elif s.count(s[0]) > 1 and s[0] not in open_doors:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
246 | B | Increase and Decrease | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | null | null | Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that Polycarpus performs the following operation multiple times:
- he chooses two elements of the array *a**i... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the array size. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=104) — the original array. | Print a single integer — the maximum number of equal array elements he can get if he performs an arbitrary number of the given operation. | [
"2\n2 1\n",
"3\n1 4 1\n"
] | [
"1\n",
"3\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 4 1",
"output": "3"
},
{
"input": "4\n2 -7 -2 -6",
"output": "3"
},
{
"input": "4\n2 0 -2 -1",
"output": "3"
},
{
"input": "6\n-1 1 0 0 -1 -1",
"output": "5"
},
{
"input": "5\n0 0 0 0 0",
"outp... | 1,597,620,316 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 307,200 | n=int(input())
a=list(map(int,input().split()))
s=sum(a)//n
a.sort()
b=[]
flag="not done"
for i in range(n):
x=a[i]-s
if(x>=0 and flag=="not done"):
flag="done"
f=i
b.append(x)
l=sum(b[:f])*(-1)
r=sum(b[f:])
if(l<r):
print(2*f+1)
else:
print(2*(... | Title: Increase and Decrease
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that... | ```python
n=int(input())
a=list(map(int,input().split()))
s=sum(a)//n
a.sort()
b=[]
flag="not done"
for i in range(n):
x=a[i]-s
if(x>=0 and flag=="not done"):
flag="done"
f=i
b.append(x)
l=sum(b[:f])*(-1)
r=sum(b[f:])
if(l<r):
print(2*f+1)
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain num... | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,694,882,456 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 46 | 0 | n, x = map(int, input().split())
print(sum(x%i == 0 and x//i <= n for i in range(1, n+1))) | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
Y... | ```python
n, x = map(int, input().split())
print(sum(x%i == 0 and x//i <= n for i in range(1, n+1)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
748 | A | Santa Claus and a Place in a Class | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are *n* lanes of *m* desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to *n* from the left to the right, the desks in a lane ar... | The only line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=10<=000, 1<=≤<=*k*<=≤<=2*nm*) — the number of lanes, the number of desks in each lane and the number of Santa Claus' place. | Print two integers: the number of lane *r*, the number of desk *d*, and a character *s*, which stands for the side of the desk Santa Claus. The character *s* should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right. | [
"4 3 9\n",
"4 3 24\n",
"2 4 4\n"
] | [
"2 2 L\n",
"4 3 R\n",
"1 2 R\n"
] | The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his pla... | 500 | [
{
"input": "4 3 9",
"output": "2 2 L"
},
{
"input": "4 3 24",
"output": "4 3 R"
},
{
"input": "2 4 4",
"output": "1 2 R"
},
{
"input": "3 10 24",
"output": "2 2 R"
},
{
"input": "10 3 59",
"output": "10 3 L"
},
{
"input": "10000 10000 160845880",
"... | 1,482,739,911 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 62 | 4,608,000 | n, m, k = map(int, input().split())
k -= 1
print(1 + k // 2 // m, 1 + k % (2 * m) // 2, end = ' ')
if k % 2:
print('R')
else:
print('L')
| Title: Santa Claus and a Place in a Class
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are *n* lanes of *m* desks each, and there are two work... | ```python
n, m, k = map(int, input().split())
k -= 1
print(1 + k // 2 // m, 1 + k % (2 * m) // 2, end = ' ')
if k % 2:
print('R')
else:
print('L')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
993 | A | Two Squares | PROGRAMMING | 1,600 | [
"geometry",
"implementation"
] | null | null | You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be part of the square, i.e. if one square is completely inside another, they intersect. If the ... | The input data consists of two lines, one for each square, both containing 4 pairs of integers. Each pair represents coordinates of one vertex of the square. Coordinates within each line are either in clockwise or counterclockwise order.
The first line contains the coordinates of the square with sides parallel to the ... | Print "Yes" if squares intersect, otherwise print "No".
You can print each letter in any case (upper or lower). | [
"0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1\n",
"0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1\n",
"6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the second square lies entirely within the first square, so they do intersect.
In the second sample squares do not have any points in common.
Here are images corresponding to the samples: | 500 | [
{
"input": "0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1",
"output": "NO"
},
{
"input": "6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n8 4 4 8 8 12 12 8",
"output": "YES"
},
... | 1,529,750,544 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | text=input()
l=text.split()
a=[((int(l[i]),int(l[i+1]))) for i in range(0,7,2)]
text2=input()
l2=text2.split()
b=[((int(l2[i]),int(l2[i+1]))) for i in range(0,7,2)]
def maxmin(a):
abmax=a[0][0]
abmin=a[0][0]
for i in range(1,4):
if a[i][0]>abmax:abmax=a[i][0]
if a[i][0]<abmin:... | Title: Two Squares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered t... | ```python
text=input()
l=text.split()
a=[((int(l[i]),int(l[i+1]))) for i in range(0,7,2)]
text2=input()
l2=text2.split()
b=[((int(l2[i]),int(l2[i+1]))) for i in range(0,7,2)]
def maxmin(a):
abmax=a[0][0]
abmin=a[0][0]
for i in range(1,4):
if a[i][0]>abmax:abmax=a[i][0]
if a[i]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
989 | A | A Blend of Springtime | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | "What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimistic.
The landscape can be expressed as a row of consecutive cells, each of which either contains a flower o... | The first and only line of input contains a non-empty string $s$ consisting of uppercase English letters 'A', 'B', 'C' and characters '.' (dots) only ($\lvert s \rvert \leq 100$) — denoting cells containing an amber flower, a buff one, a canary yellow one, and no flowers, respectively. | Output "Yes" if it's possible that all three colours appear in some cell, and "No" otherwise.
You can print each letter in any case (upper or lower). | [
".BAC.\n",
"AA..CB\n"
] | [
"Yes\n",
"No\n"
] | In the first example, the buff and canary yellow flowers can leave their petals in the central cell, blending all three colours in it.
In the second example, it's impossible to satisfy the requirement because there is no way that amber and buff meet in any cell. | 500 | [
{
"input": ".BAC.",
"output": "Yes"
},
{
"input": "AA..CB",
"output": "No"
},
{
"input": ".",
"output": "No"
},
{
"input": "ACB.AAAAAA",
"output": "Yes"
},
{
"input": "B.BC.BBBCA",
"output": "Yes"
},
{
"input": "BA..CAB..B",
"output": "Yes"
},
... | 1,641,410,663 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 62 | 0 | s = input()
n = len(s)
ans = "NO"
if n < 3:
print(ans)
else:
for i in range(1, n - 1):
if len(set(s[i-1:i+2].replace(".", ""))) == 3:
ans = "YES"
break
print(ans) | Title: A Blend of Springtime
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimisti... | ```python
s = input()
n = len(s)
ans = "NO"
if n < 3:
print(ans)
else:
for i in range(1, n - 1):
if len(set(s[i-1:i+2].replace(".", ""))) == 3:
ans = "YES"
break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<... | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In ... | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,433,595,850 | 250 | Python 3 | OK | TESTS | 37 | 62 | 0 | import sys
def main():
# fin = open("input.txt", "r")
fin = sys.stdin
n, m = map(int, fin.readline().split())
A = []
for i in range(n):
A.append(fin.readline().rstrip())
cnt = 0
for i in range(n - 1):
for j in range(m - 1):
S = {A[i][j], A[i][j + 1], A[i + ... | Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem a... | ```python
import sys
def main():
# fin = open("input.txt", "r")
fin = sys.stdin
n, m = map(int, fin.readline().split())
A = []
for i in range(n):
A.append(fin.readline().rstrip())
cnt = 0
for i in range(n - 1):
for j in range(m - 1):
S = {A[i][j], A[i][j + ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
813 | C | The Tag Game | PROGRAMMING | 1,700 | [
"dfs and similar",
"graphs"
] | null | null | Alice got tired of playing the tag game by the usual rules so she offered Bob a little modification to it. Now the game should be played on an undirected rooted tree of *n* vertices. Vertex 1 is the root of the tree.
Alice starts at vertex 1 and Bob starts at vertex *x* (*x*<=≠<=1). The moves are made in turns, Bob go... | The first line contains two integer numbers *n* and *x* (2<=≤<=*n*<=≤<=2·105, 2<=≤<=*x*<=≤<=*n*).
Each of the next *n*<=-<=1 lines contains two integer numbers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=*n*) — edges of the tree. It is guaranteed that the edges form a valid tree. | Print the total number of moves Alice and Bob will make. | [
"4 3\n1 2\n2 3\n2 4\n",
"5 2\n1 2\n2 3\n3 4\n2 5\n"
] | [
"4\n",
"6\n"
] | In the first example the tree looks like this:
The red vertex is Alice's starting position, the blue one is Bob's. Bob will make the game run the longest by standing at the vertex 3 during all the game. So here are the moves:
B: stay at vertex 3
A: go to vertex 2
B: stay at vertex 3
A: go to vertex 3
In the secon... | 0 | [
{
"input": "4 3\n1 2\n2 3\n2 4",
"output": "4"
},
{
"input": "5 2\n1 2\n2 3\n3 4\n2 5",
"output": "6"
},
{
"input": "2 2\n2 1",
"output": "2"
},
{
"input": "3 3\n2 1\n3 1",
"output": "2"
},
{
"input": "3 3\n1 2\n3 2",
"output": "4"
},
{
"input": "10 4\... | 1,496,755,416 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 1,000 | 30,515,200 | n, x = map(int, input().split())
s = [[[], -1, -1] for i in range(n + 1)]
for i in range(n - 1):
a, b = map(int, input().split())
s[a][0].append(b)
s[b][0].append(a)
s[1][1] = 0
q = [1]
while len(q):
a = q.pop(0)
for i in range(len(s[a][0])):
if s[s[a][0][i]][1] == -1:
... | Title: The Tag Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice got tired of playing the tag game by the usual rules so she offered Bob a little modification to it. Now the game should be played on an undirected rooted tree of *n* vertices. Vertex 1 is the root of the tree.
Alic... | ```python
n, x = map(int, input().split())
s = [[[], -1, -1] for i in range(n + 1)]
for i in range(n - 1):
a, b = map(int, input().split())
s[a][0].append(b)
s[b][0].append(a)
s[1][1] = 0
q = [1]
while len(q):
a = q.pop(0)
for i in range(len(s[a][0])):
if s[s[a][0][i]][1] == -... | 0 | MatrixStudio/Codeforces-Python-Submissions |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.