contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
981 | A | Antipalindrome | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not.
A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2}... | The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. | If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$.
Note that there can be multiple longest substrings that are not palindromes, but their length is unique. | [
"mew\n",
"wuffuw\n",
"qqqqqqqq\n"
] | [
"3\n",
"5\n",
"0\n"
] | "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$.
The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$.
All sub... | 500 | [
{
"input": "mew",
"output": "3"
},
{
"input": "wuffuw",
"output": "5"
},
{
"input": "qqqqqqqq",
"output": "0"
},
{
"input": "ijvji",
"output": "4"
},
{
"input": "iiiiiii",
"output": "0"
},
{
"input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow"... | 1,527,600,756 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | s = input()
s1 = s
if s == s[::-1]:
print(len(s)-1)
else:
print(len(s)) | Title: Antipalindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" ar... | ```python
s = input()
s1 = s
if s == s[::-1]:
print(len(s)-1)
else:
print(len(s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon piece... | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,697,214,747 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 61 | 0 | n, a, b, c = map(int, input().split())
lst = [(a, a), (a, b), (a, c), (b, b), (b, c), (c, c)]
s = [n]
f = True
while f:
for j in range(len(s)):
h = False
for i in lst:
if (i[0] + i[1]) == s[j]:
s.pop(j)
s.append(i[0])
s.append(... | Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the... | ```python
n, a, b, c = map(int, input().split())
lst = [(a, a), (a, b), (a, c), (b, b), (b, c), (c, c)]
s = [n]
f = True
while f:
for j in range(len(s)):
h = False
for i in lst:
if (i[0] + i[1]) == s[j]:
s.pop(j)
s.append(i[0])
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,696,956,085 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | n = int(input())
d = ''
for i in str(n):
if int(i) < 5:
d += str(i)
else:
d += str(9-int(i))
print(d) | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
n = int(input())
d = ''
for i in str(n):
if int(i) < 5:
d += str(i)
else:
d += str(9-int(i))
print(d)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
676 | C | Vasya and String | PROGRAMMING | 1,500 | [
"binary search",
"dp",
"strings",
"two pointers"
] | null | null | High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequence) consisting of equal letters.
Vasya can change no more than *k* characters of the original strin... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000,<=0<=≤<=*k*<=≤<=*n*) — the length of the string and the maximum number of characters to change.
The second line contains the string, consisting of letters 'a' and 'b' only. | Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than *k* characters. | [
"4 2\nabba\n",
"8 1\naabaabaa\n"
] | [
"4\n",
"5\n"
] | In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".
In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa". | 1,500 | [
{
"input": "4 2\nabba",
"output": "4"
},
{
"input": "8 1\naabaabaa",
"output": "5"
},
{
"input": "1 0\na",
"output": "1"
},
{
"input": "1 1\nb",
"output": "1"
},
{
"input": "1 0\nb",
"output": "1"
},
{
"input": "1 1\na",
"output": "1"
},
{
... | 1,621,427,493 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 62 | 0 | def string(n,k,s):
i=0
j=0
ans=1
while j<n and i<n:
if j<n and s[j]=="a":
ans=max(ans,(j-i+1))
j+=1
# print(j,ans)
if j<n and s[j]=="b" and k>0:
ans=max(ans,(j-i+1))
j+=1
k-=1
# print(j,k,ans)
if j<n and i<n and s[j]=="b" and k==0:
i+=1
ans=max(ans,(j... | Title: Vasya and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequ... | ```python
def string(n,k,s):
i=0
j=0
ans=1
while j<n and i<n:
if j<n and s[j]=="a":
ans=max(ans,(j-i+1))
j+=1
# print(j,ans)
if j<n and s[j]=="b" and k>0:
ans=max(ans,(j-i+1))
j+=1
k-=1
# print(j,k,ans)
if j<n and i<n and s[j]=="b" and k==0:
i+=1
ans=... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
614 | B | Gena's Code | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from each country, find their product. If it is turns to be too large, then the servers might have not en... | The first line of the input contains the number of countries *n* (1<=≤<=*n*<=≤<=100<=000). The second line contains *n* non-negative integers *a**i* without leading zeroes — the number of tanks of the *i*-th country.
It is guaranteed that the second line contains at least *n*<=-<=1 beautiful numbers and the total leng... | Print a single number without leading zeroes — the product of the number of tanks presented by each country. | [
"3\n5 10 1\n",
"4\n1 1 10 11\n",
"5\n0 3 1 100 1\n"
] | [
"50",
"110",
"0"
] | In sample 1 numbers 10 and 1 are beautiful, number 5 is not not.
In sample 2 number 11 is not beautiful (contains two '1's), all others are beautiful.
In sample 3 number 3 is not beautiful, all others are beautiful. | 1,000 | [
{
"input": "3\n5 10 1",
"output": "50"
},
{
"input": "4\n1 1 10 11",
"output": "110"
},
{
"input": "5\n0 3 1 100 1",
"output": "0"
},
{
"input": "40\n10 100 10 1 10 10 100 10 10 100 10 100 100 10 1824868942 100 100 1 10 100 100 10 100 100 10 100 10 1 10 100 100 100 10 1 10 1 ... | 1,601,218,128 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 500 | 13,107,200 | def c(a):
k1 = 0
for i in a:
if i == '1':
k1 += 1
if i != '1' and i != '0':
return True
return k1 > 1
n = int(input())
a = input().split()
f1 = True
f2 = True
for i in range(n):
if a[i] == '0':
f1 = False
if a[i] != '1':
f... | Title: Gena's Code
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from eac... | ```python
def c(a):
k1 = 0
for i in a:
if i == '1':
k1 += 1
if i != '1' and i != '0':
return True
return k1 > 1
n = int(input())
a = input().split()
f1 = True
f2 = True
for i in range(n):
if a[i] == '0':
f1 = False
if a[i] != '1':
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,631,312,283 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 62 | 6,963,200 | arr=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
p=input()
posi,aux=0,0
for i in p:
if arr.index(i) > posi:
if ((26 - arr.index(i)) + posi) < (arr.index(i) - posi): aux += ((26 - arr.index(i)) + posi)
else: aux += (arr.index(i) - pos... | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
arr=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
p=input()
posi,aux=0,0
for i in p:
if arr.index(i) > posi:
if ((26 - arr.index(i)) + posi) < (arr.index(i) - posi): aux += ((26 - arr.index(i)) + posi)
else: aux += (arr.inde... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
799 | A | Carrot Cakes | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he currently don't have any. However, he has infinitely many ingredients and one oven. Moreover, Arkady... | The only line contains four integers *n*, *t*, *k*, *d* (1<=≤<=*n*,<=*t*,<=*k*,<=*d*<=≤<=1<=000) — the number of cakes needed, the time needed for one oven to bake *k* cakes, the number of cakes baked at the same time, the time needed to build the second oven. | If it is reasonable to build the second oven, print "YES". Otherwise print "NO". | [
"8 6 4 5\n",
"8 6 4 6\n",
"10 3 11 4\n",
"4 2 1 4\n"
] | [
"YES\n",
"NO\n",
"NO\n",
"YES\n"
] | In the first example it is possible to get 8 cakes in 12 minutes using one oven. The second oven can be built in 5 minutes, so after 6 minutes the first oven bakes 4 cakes, the second oven bakes 4 more ovens after 11 minutes. Thus, it is reasonable to build the second oven.
In the second example it doesn't matter whe... | 500 | [
{
"input": "8 6 4 5",
"output": "YES"
},
{
"input": "8 6 4 6",
"output": "NO"
},
{
"input": "10 3 11 4",
"output": "NO"
},
{
"input": "4 2 1 4",
"output": "YES"
},
{
"input": "28 17 16 26",
"output": "NO"
},
{
"input": "60 69 9 438",
"output": "NO"... | 1,628,896,129 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 61 | 6,963,200 | from math import ceil
ip = list(map(int, input().strip().split()))[:]
total1 = ceil(ip[0]/ip[2]) * ip[1]
g = ceil(ip[0]/ip[2])
o1 = 0
o2 = ip[3]
for i in range(g):
if o1 <= o2:
o1 += ip[2]
else:
o2 += ip[2]
total2 = max(o1, o2)
if total1 <= total2:
print("NO")
else:
pri... | Title: Carrot Cakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some game by Playrix it takes *t* minutes for an oven to bake *k* carrot cakes, all cakes are ready at the same moment *t* minutes after they started baking. Arkady needs at least *n* cakes to complete a task, but he cu... | ```python
from math import ceil
ip = list(map(int, input().strip().split()))[:]
total1 = ceil(ip[0]/ip[2]) * ip[1]
g = ceil(ip[0]/ip[2])
o1 = 0
o2 = ip[3]
for i in range(g):
if o1 <= o2:
o1 += ip[2]
else:
o2 += ip[2]
total2 = max(o1, o2)
if total1 <= total2:
print("NO")
else... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,682,596,088 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 186 | 0 | k=int(input())
s=input()
newstr=""
d={}
for x in s:
if x in d:
d[x]+=1
else:
d[x]=1
flag=0
for y in d:
if(d[y]%k!=0):
print(-1)
flag=-1
break
if(flag!=-1):
for z in d:
newstr=newstr+z*int(d[z]/k)
print(k*newstr) | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
k=int(input())
s=input()
newstr=""
d={}
for x in s:
if x in d:
d[x]+=1
else:
d[x]=1
flag=0
for y in d:
if(d[y]%k!=0):
print(-1)
flag=-1
break
if(flag!=-1):
for z in d:
newstr=newstr+z*int(d[z]/k)
print(k*newstr)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,681,298,768 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 171 | 25,907,200 | #Ram
from sys import stdin,stdout
input = stdin.readline
def print(n):
stdout.write(str(n)+"\n")
def printl(l):
for i in l:
stdout.write(str(i)+" ")
n=int(input())
l1=list(map(int,input().split()))
l2=list(map(int,input().split()))
l3=list(map(int,input().split()))
d1={}
d2={}... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
#Ram
from sys import stdin,stdout
input = stdin.readline
def print(n):
stdout.write(str(n)+"\n")
def printl(l):
for i in l:
stdout.write(str(i)+" ")
n=int(input())
l1=list(map(int,input().split()))
l2=list(map(int,input().split()))
l3=list(map(int,input().split()))
d1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,664,197,568 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
list = [int(x) for x in input().split(" ")]
result = []
def foo(list, result):
set = {1,2,3}
arr = []
dict = {}
if not set.issubset(list):
return result
for i in range(len(list)):
if list[i] != 0:
dict.setdefault(list[i], 0)
dict[list[i]] = i
if set.issubset(map(int,... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n = int(input())
list = [int(x) for x in input().split(" ")]
result = []
def foo(list, result):
set = {1,2,3}
arr = []
dict = {}
if not set.issubset(list):
return result
for i in range(len(list)):
if list[i] != 0:
dict.setdefault(list[i], 0)
dict[list[i]] = i
if set.issubse... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,643,343,727 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 60 | 0 | inp1 = input()
inp1 = inp1.replace("?","")
inp1 = inp1.lower()
a = "aeiouy"
if inp1[-1] in a:
print("YES")
else:
print("NO")
| Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
inp1 = input()
inp1 = inp1.replace("?","")
inp1 = inp1.lower()
a = "aeiouy"
if inp1[-1] in a:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
390 | A | Inna and Alarm Clock | PROGRAMMING | 0 | [
"implementation"
] | null | null | Inna loves sleeping very much, so she needs *n* alarm clocks in total to wake up. Let's suppose that Inna's room is a 100<=×<=100 square with the lower left corner at point (0,<=0) and with the upper right corner at point (100,<=100). Then the alarm clocks are points with integer coordinates in this square.
The mornin... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of the alarm clocks. The next *n* lines describe the clocks: the *i*-th line contains two integers *x**i*, *y**i* — the coordinates of the *i*-th alarm clock (0<=≤<=*x**i*,<=*y**i*<=≤<=100).
Note that a single point in the room can conta... | In a single line print a single integer — the minimum number of segments Inna will have to draw if she acts optimally. | [
"4\n0 0\n0 1\n0 2\n1 0\n",
"4\n0 0\n0 1\n1 0\n1 1\n",
"4\n1 1\n1 2\n2 3\n3 3\n"
] | [
"2\n",
"2\n",
"3\n"
] | In the first sample, Inna first chooses type "vertical segments", and then she makes segments with ends at : (0, 0), (0, 2); and, for example, (1, 0), (1, 1). If she paints horizontal segments, she will need at least 3 segments.
In the third sample it is important to note that Inna doesn't have the right to change the... | 500 | [
{
"input": "4\n0 0\n0 1\n0 2\n1 0",
"output": "2"
},
{
"input": "4\n0 0\n0 1\n1 0\n1 1",
"output": "2"
},
{
"input": "4\n1 1\n1 2\n2 3\n3 3",
"output": "3"
},
{
"input": "1\n0 0",
"output": "1"
},
{
"input": "42\n28 87\n26 16\n59 90\n47 61\n28 83\n36 30\n67 10\n6 ... | 1,545,336,722 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 405 | 11,366,400 |
n = int(input())
hashrows= {}
hashcolumns = {}
for i in range(n):
a,b = map(int,input().split())
if a not in hashrows.keys() :
hashrows[a] = [[a,b]]
else:
hashrows[a].append([a,b])
if b not in hashcolumns.keys() :
hashcolumns[b] = [[a,b]]
else:
hashcolumns[b].appe... | Title: Inna and Alarm Clock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Inna loves sleeping very much, so she needs *n* alarm clocks in total to wake up. Let's suppose that Inna's room is a 100<=×<=100 square with the lower left corner at point (0,<=0) and with the upper right corner a... | ```python
n = int(input())
hashrows= {}
hashcolumns = {}
for i in range(n):
a,b = map(int,input().split())
if a not in hashrows.keys() :
hashrows[a] = [[a,b]]
else:
hashrows[a].append([a,b])
if b not in hashcolumns.keys() :
hashcolumns[b] = [[a,b]]
else:
hashcolum... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,506,023,768 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | k, a, b = [int(x) for x in input().split(' ')]
print((b - a) / k + 1)
| Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
k, a, b = [int(x) for x in input().split(' ')]
print((b - a) / k + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,692,461,443 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 46 | 0 | exhibit_name = input().strip()
total_rotations = 0
current_position = 0
for char in exhibit_name:
target_position = ord(char) - ord('a')
clockwise = (target_position - current_position + 26) % 26
counterclockwise = (current_position - target_position + 26) % 26
rotations_needed = min(clockwis... | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
exhibit_name = input().strip()
total_rotations = 0
current_position = 0
for char in exhibit_name:
target_position = ord(char) - ord('a')
clockwise = (target_position - current_position + 26) % 26
counterclockwise = (current_position - target_position + 26) % 26
rotations_needed = mi... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,678,485,473 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 92 | 0 | n, m = map(int, input().split())
costs = list(map(int, input().split()))
costs.sort()
counter = 0
result = 0
for i in range(n):
if counter < m:
if costs[i] < 0:
result += costs[i]
print(result*-1)
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n, m = map(int, input().split())
costs = list(map(int, input().split()))
costs.sort()
counter = 0
result = 0
for i in range(n):
if counter < m:
if costs[i] < 0:
result += costs[i]
print(result*-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
454 | B | Little Pony and Sort by Shift | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. That is, she can move the last element of the sequence to its beginning:
Help Twilight Sparkle to calculate: what ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=105). The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | If it's impossible to sort the sequence output -1. Otherwise output the minimum number of operations Twilight Sparkle needs to sort it. | [
"2\n2 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"1\n",
"-1\n",
"0\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 3 2",
"output": "-1"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "6\n3 4 5 6 3 2",
"output": "-1"
},
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n1 1 2 1 1",
"output": "2"
}... | 1,591,093,539 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 7,680,000 | n=int(input())
a=[int(i) for i in input().split()]
b=a.copy()
b.sort()
t=n
f=0
c=0
while(t>=1):
if a==b:
f=1
break
a.insert(0,a[n-1])
a.pop()
c+=1
t-=1
if f==1:
print(c)
else:
print(-1) | Title: Little Pony and Sort by Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. ... | ```python
n=int(input())
a=[int(i) for i in input().split()]
b=a.copy()
b.sort()
t=n
f=0
c=0
while(t>=1):
if a==b:
f=1
break
a.insert(0,a[n-1])
a.pop()
c+=1
t-=1
if f==1:
print(c)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain nu... | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the son... | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE... | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,698,322,990 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 71 | 124 | 0 | s = input()
s = s.replace('WUB','~').split('~')
d = []
for i in s:
if i!= '':
d.append(i)
print(' '.join(d)) | Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consist... | ```python
s = input()
s = s.replace('WUB','~').split('~')
d = []
for i in s:
if i!= '':
d.append(i)
print(' '.join(d))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
515 | A | Drazil and Date | PROGRAMMING | 1,000 | [
"math"
] | null | null | Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit distance in horizontal or vertical direction. In other words, from position (*x*,<=*y*) he can go to ... | You are given three integers *a*, *b*, and *s* (<=-<=109<=≤<=*a*,<=*b*<=≤<=109, 1<=≤<=*s*<=≤<=2·109) in a single line. | If you think Drazil made a mistake and it is impossible to take exactly *s* steps and get from his home to Varda's home, print "No" (without quotes).
Otherwise, print "Yes". | [
"5 5 11\n",
"10 15 25\n",
"0 5 1\n",
"0 0 2\n"
] | [
"No\n",
"Yes\n",
"No\n",
"Yes\n"
] | In fourth sample case one possible route is: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/0d30660ddf6eb6c64ffd071055a4e8ddd016cde5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 500 | [
{
"input": "5 5 11",
"output": "No"
},
{
"input": "10 15 25",
"output": "Yes"
},
{
"input": "0 5 1",
"output": "No"
},
{
"input": "0 0 2",
"output": "Yes"
},
{
"input": "999999999 999999999 2000000000",
"output": "Yes"
},
{
"input": "-606037695 9983201... | 1,585,897,484 | 284 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 140 | 0 | a, b, s = [int(i) for i in input().split(" ")]
if (a+b+s)%2 == 1 or a+b > s:
print("No")
else:
print("Yes")
| Title: Drazil and Date
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit ... | ```python
a, b, s = [int(i) for i in input().split(" ")]
if (a+b+s)%2 == 1 or a+b > s:
print("No")
else:
print("Yes")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,674,469,939 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | w=input()
lower=0
upper=0
for char in w:
if char.isupper():
upper+=1
else:
lower+=1
if upper>lower:
w=w.upper()
else:
w=w.lower()
print(w) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
w=input()
lower=0
upper=0
for char in w:
if char.isupper():
upper+=1
else:
lower+=1
if upper>lower:
w=w.upper()
else:
w=w.lower()
print(w)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
147 | A | Punctuation | PROGRAMMING | 1,300 | [
"implementation",
"strings"
] | null | null | You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the text by the following rules:
- if there is no punctuation mark between two word... | The input data contains of a single non-empty line — the text whose length is no more than 10000 characters. | Print the text, edited according to the rules. In this problem you should follow the output format very strictly. For example, extra space at the end of the output line is considered as wrong answer. Note that a newline character at the end of the line doesn't matter. | [
"galileo galilei was an italian physicist ,mathematician,astronomer\n",
"galileo was born in pisa\n"
] | [
"galileo galilei was an italian physicist, mathematician, astronomer\n",
"galileo was born in pisa\n"
] | none | 500 | [
{
"input": "galileo galilei was an italian physicist ,mathematician,astronomer",
"output": "galileo galilei was an italian physicist, mathematician, astronomer"
},
{
"input": "galileo was born in pisa",
"output": "galileo was born in pisa"
},
{
"input": "jkhksdfhsdfsf",
"outpu... | 1,684,241,831 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 124 | 0 | a=input()
for i in range(len(a)):
if a[i]==',':
print(a[i],end=' ')
if a[i]!=' ' and a[i]!=',':
print(a[i],end='')
if a[i]==' ' and a[i+1]!=',':
if a[i+1]!=' ':
print(a[i],end='')
i+=1;
| Title: Punctuation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to ad... | ```python
a=input()
for i in range(len(a)):
if a[i]==',':
print(a[i],end=' ')
if a[i]!=' ' and a[i]!=',':
print(a[i],end='')
if a[i]==' ' and a[i+1]!=',':
if a[i+1]!=' ':
print(a[i],end='')
i+=1;
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
150 | A | Win or Freeze | PROGRAMMING | 1,400 | [
"games",
"math",
"number theory"
] | null | null | You can't possibly imagine how cold our friends are this winter in Nvodsk! Two of them play the following game to warm up: initially a piece of paper has an integer *q*. During a move a player should write any integer number that is a non-trivial divisor of the last written number. Then he should run this number of cir... | The first line contains the only integer *q* (1<=≤<=*q*<=≤<=1013).
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. | In the first line print the number of the winning player (1 or 2). If the first player wins then the second line should contain another integer — his first move (if the first player can't even make the first move, print 0). If there are multiple solutions, print any of them. | [
"6\n",
"30\n",
"1\n"
] | [
"2\n",
"1\n6\n",
"1\n0\n"
] | Number 6 has only two non-trivial divisors: 2 and 3. It is impossible to make a move after the numbers 2 and 3 are written, so both of them are winning, thus, number 6 is the losing number. A player can make a move and write number 6 after number 30; 6, as we know, is a losing number. Thus, this move will bring us the ... | 500 | [
{
"input": "6",
"output": "2"
},
{
"input": "30",
"output": "1\n6"
},
{
"input": "1",
"output": "1\n0"
},
{
"input": "2",
"output": "1\n0"
},
{
"input": "3",
"output": "1\n0"
},
{
"input": "5",
"output": "1\n0"
},
{
"input": "445538663413",... | 1,600,310,286 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 202 | 2,048,000 | import math
if __name__ == '__main__':
n = int(input())
sqrtn = int(math.sqrt(n))
factors = list()
for i in range(2, sqrtn+1):
while n%i == 0:
factors.append(i)
n = n//i
if len(factors) == 2:
print(2)
exit()
else:
print(1)
if len(factors) == 0:
print(0)
else:
print... | Title: Win or Freeze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You can't possibly imagine how cold our friends are this winter in Nvodsk! Two of them play the following game to warm up: initially a piece of paper has an integer *q*. During a move a player should write any integer num... | ```python
import math
if __name__ == '__main__':
n = int(input())
sqrtn = int(math.sqrt(n))
factors = list()
for i in range(2, sqrtn+1):
while n%i == 0:
factors.append(i)
n = n//i
if len(factors) == 2:
print(2)
exit()
else:
print(1)
if len(factors) == 0:
print(0)
else:... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,687,218,669 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 15 | 0 | def minimum_bacteria(x):
bacteria_count = 1
days = 0
while bacteria_count < x:
bacteria_count *= 2
days += 1
return days - 1
x = int(input())
min_bacteria = minimum_bacteria(x)
print(min_bacteria)
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
def minimum_bacteria(x):
bacteria_count = 1
days = 0
while bacteria_count < x:
bacteria_count *= 2
days += 1
return days - 1
x = int(input())
min_bacteria = minimum_bacteria(x)
print(min_bacteria)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
932 | F | Escape Through Leaf | PROGRAMMING | 2,700 | [
"data structures",
"dp",
"geometry"
] | null | null | You are given a tree with *n* nodes (numbered from 1 to *n*) rooted at node 1. Also, each node has two values associated with it. The values for *i*-th node are *a**i* and *b**i*.
You can jump from a node to any node in its subtree. The cost of one jump from node *x* to node *y* is the product of *a**x* and *b**y*. Th... | The first line of input contains an integer *n* (2<=≤<=*n*<=≤<=105) — the number of nodes in the tree.
The second line contains *n* space-separated integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n*(<=-<=105<=<=≤<=<=*a**i*<=<=≤<=<=105).
The third line contains *n* space-separated integers *b*1,<=<=*b*2,<=<=...,<=<=*b**n*(<=-<... | Output *n* space-separated integers, *i*-th of which denotes the minimum cost of a path from node *i* to reach any leaf. | [
"3\n2 10 -1\n7 -7 5\n2 3\n2 1\n",
"4\n5 -10 5 7\n-8 -80 -3 -10\n2 1\n2 4\n1 3\n"
] | [
"10 50 0 ",
"-300 100 0 0 "
] | In the first example, node 3 is already a leaf, so the cost is 0. For node 2, jump to node 3 with cost *a*<sub class="lower-index">2</sub> × *b*<sub class="lower-index">3</sub> = 50. For node 1, jump directly to node 3 with cost *a*<sub class="lower-index">1</sub> × *b*<sub class="lower-index">3</sub> = 10.
In the sec... | 2,500 | [
{
"input": "3\n2 10 -1\n7 -7 5\n2 3\n2 1",
"output": "10 50 0 "
},
{
"input": "4\n5 -10 5 7\n-8 -80 -3 -10\n2 1\n2 4\n1 3",
"output": "-300 100 0 0 "
},
{
"input": "5\n7 -8 -8 -3 -10\n6 1 -6 7 5\n3 1\n2 5\n1 4\n4 5",
"output": "-42 0 0 -25 -10 "
},
{
"input": "6\n4 -8 9 -1 -2... | 1,631,002,335 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
using namespace std;
#define ll long long
struct edge{
int ne,to;
}a[200010];
struct node{
int ls,rs,v;
}t[100010];
struct emm{
ll k,b;
}qwq[100010];
int n,num,head[100010],rt[100010],A[100010],B[100010];
ll f[100010];
inline void add(int u,int v){
a[++num].ne=head[u];
a[num... | Title: Escape Through Leaf
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a tree with *n* nodes (numbered from 1 to *n*) rooted at node 1. Also, each node has two values associated with it. The values for *i*-th node are *a**i* and *b**i*.
You can jump from a node to any no... | ```python
#include<bits/stdc++.h>
using namespace std;
#define ll long long
struct edge{
int ne,to;
}a[200010];
struct node{
int ls,rs,v;
}t[100010];
struct emm{
ll k,b;
}qwq[100010];
int n,num,head[100010],rt[100010],A[100010],B[100010];
ll f[100010];
inline void add(int u,int v){
a[++num].ne=head[u... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,599,515,793 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 0 | text = input('')
count_upper = 0
for l in text:
if l.isupper():
count_upper += 1
print(text.upper() if count_upper > (len(text)//2) else text.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
text = input('')
count_upper = 0
for l in text:
if l.isupper():
count_upper += 1
print(text.upper() if count_upper > (len(text)//2) else text.lower())
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,596,354,459 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 186 | 6,656,000 | input()
print(sorted(list(set(input().split(' '))))[1])
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
input()
print(sorted(list(set(input().split(' '))))[1])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
735 | C | Tennis Championship | PROGRAMMING | 1,600 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are st... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=1018) — the number of players to participate in the tournament. | Print the maximum number of games in which the winner of the tournament can take part. | [
"2\n",
"3\n",
"4\n",
"10\n"
] | [
"1\n",
"2\n",
"2\n",
"4\n"
] | In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't p... | 1,750 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "1000",
"output": "14"
},
{
"input": "2500",
"output": "15"
},
{
"input": "690000",
"output"... | 1,628,687,372 | 2,147,483,647 | PyPy 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 7 | 1,263 | 268,390,400 |
def findMaxGame(N):
if(N == 1):
return "MATCH NOT POSSIBLE"
if(N == 2):
return 1
if(N == 3):
return 2
dp = [0 for i in range(N)]
dp[0] = 1
dp[1] = 2
i = 1
while dp[i] <= N:
i = i + 1
dp[i] = dp[i - 1] + dp[i - 2]
return (i - 1)
... | Title: Tennis Championship
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very firs... | ```python
def findMaxGame(N):
if(N == 1):
return "MATCH NOT POSSIBLE"
if(N == 2):
return 1
if(N == 3):
return 2
dp = [0 for i in range(N)]
dp[0] = 1
dp[1] = 2
i = 1
while dp[i] <= N:
i = i + 1
dp[i] = dp[i - 1] + dp[i - 2]
retur... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,590,188,357 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | a,b,c,d=map(int,input().split())
p1=max(3*a/10,a*c/250)
p2=max(3*b/10,b*d/250)
if p1>p2:
print("Misha")
elif p1<p2:
print("Vasya")
else:
print("Tie") | Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
a,b,c,d=map(int,input().split())
p1=max(3*a/10,a*c/250)
p2=max(3*b/10,b*d/250)
if p1>p2:
print("Misha")
elif p1<p2:
print("Vasya")
else:
print("Tie")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,699,108,779 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | k , n , w = map(int , input().split())
z = w*(w+1)*k//2
print(z-n)
| Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
k , n , w = map(int , input().split())
z = w*(w+1)*k//2
print(z-n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,678,363,097 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 0 | def is_translation(word1: str, word2: str) -> bool:
return word1 == word2[::-1]
if __name__ == "__main__":
w1 = input()
w2 = input()
if (is_translation(w1, w2)):
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
def is_translation(word1: str, word2: str) -> bool:
return word1 == word2[::-1]
if __name__ == "__main__":
w1 = input()
w2 = input()
if (is_translation(w1, w2)):
print("YES")
else:
print("NO")
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
169 | A | Chores | PROGRAMMING | 800 | [
"sortings"
] | null | null | Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*.
As Petya is older, he wants to take the chores with complexit... | The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores.
The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* ... | Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. | [
"5 2 3\n6 2 3 100 1\n",
"7 3 4\n1 1 9 1 1 1 1\n"
] | [
"3\n",
"0\n"
] | In the first sample the possible values of *x* are 3, 4 or 5.
In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4. | 500 | [
{
"input": "5 2 3\n6 2 3 100 1",
"output": "3"
},
{
"input": "7 3 4\n1 1 9 1 1 1 1",
"output": "0"
},
{
"input": "2 1 1\n10 2",
"output": "8"
},
{
"input": "2 1 1\n7 7",
"output": "0"
},
{
"input": "2 1 1\n1 1000000000",
"output": "999999999"
},
{
"inp... | 1,680,589,345 | 145 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n, a, b = map(int, input().split())
tasks = sorted(map(int, input().split()))
min_A_task = tasks[-a]
max_B_task = tasks[b-1]
possible_x = min_A_task - max_B_task - 1
print(max(possible_x, 0)) | Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of th... | ```python
n, a, b = map(int, input().split())
tasks = sorted(map(int, input().split()))
min_A_task = tasks[-a]
max_B_task = tasks[b-1]
possible_x = min_A_task - max_B_task - 1
print(max(possible_x, 0))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,616,565,691 | 2,147,483,647 | PyPy 3 | OK | TESTS | 64 | 109 | 0 | n=input()
if n[-1]=='0':
print(n)
elif n[-1]<='5':
s=int(n[-1])
n=int(n)
print(n-s)
else:
s=10-int(n[-1])
print(int(n)+s)
| Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
n=input()
if n[-1]=='0':
print(n)
elif n[-1]<='5':
s=int(n[-1])
n=int(n)
print(n-s)
else:
s=10-int(n[-1])
print(int(n)+s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
552 | B | Vanya and Books | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assigned distinct numbers.
Vanya wants to know how many digits he will have to write down as he labels th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109) — the number of books in the library. | Print the number of digits needed to number all the books. | [
"13\n",
"4\n"
] | [
"17\n",
"4\n"
] | Note to the first test. The books get numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, which totals to 17 digits.
Note to the second sample. The books get numbers 1, 2, 3, 4, which totals to 4 digits. | 1,000 | [
{
"input": "13",
"output": "17"
},
{
"input": "4",
"output": "4"
},
{
"input": "100",
"output": "192"
},
{
"input": "99",
"output": "189"
},
{
"input": "1000000000",
"output": "8888888899"
},
{
"input": "1000000",
"output": "5888896"
},
{
"... | 1,593,157,580 | 2,147,483,647 | PyPy 3 | OK | TESTS | 55 | 155 | 20,172,800 | import math
n=input()
a=[]
for i in range(0,10):
k=9*math.pow(10,i)*(i+1)
a.append(int(k))
print(sum(a[:len(n)-1])+int((int(n)-(math.pow(10,len(n)-1))+1)*len(n)))
| Title: Vanya and Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assig... | ```python
import math
n=input()
a=[]
for i in range(0,10):
k=9*math.pow(10,i)*(i+1)
a.append(int(k))
print(sum(a[:len(n)-1])+int((int(n)-(math.pow(10,len(n)-1))+1)*len(n)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
908 | A | New Year and Counting Cards | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a c... | The first and only line of input will contain a string *s* (1<=≤<=|*s*|<=≤<=50), denoting the sides of the cards that you can see on the table currently. Each character of *s* is either a lowercase English letter or a digit. | Print a single integer, the minimum number of cards you must turn over to verify your claim. | [
"ee\n",
"z\n",
"0ay1\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on th... | 500 | [
{
"input": "ee",
"output": "2"
},
{
"input": "z",
"output": "0"
},
{
"input": "0ay1",
"output": "2"
},
{
"input": "0abcdefghijklmnopqrstuvwxyz1234567896",
"output": "10"
},
{
"input": "0a0a9e9e2i2i9o9o6u6u9z9z4x4x9b9b",
"output": "18"
},
{
"input": "01... | 1,602,178,822 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | numbers = '02468'
vowels = 'aeiou'
count = 0
cards = input()
for card in cards:
if card in vowels or card in numbers:
count += 1
print(count)
| Title: New Year and Counting Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each car... | ```python
numbers = '02468'
vowels = 'aeiou'
count = 0
cards = input()
for card in cards:
if card in vowels or card in numbers:
count += 1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,685,518,241 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 62 | 0 | s = input()
a, b = int(s.split()[0]), int(s.split()[1])
prime = [True for i in range(b + 1)]
p = 2
while p*p <= b:
if prime[p] == True:
for i in range(p*p, b + 1, p):
prime[i] = False
p += 1
for i in range(1, b - a + 1):
if prime[a + i] == True and a + i == b:
print(... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
s = input()
a, b = int(s.split()[0]), int(s.split()[1])
prime = [True for i in range(b + 1)]
p = 2
while p*p <= b:
if prime[p] == True:
for i in range(p*p, b + 1, p):
prime[i] = False
p += 1
for i in range(1, b - a + 1):
if prime[a + i] == True and a + i == b:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
476 | A | Dreamoon and Stairs | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition? | The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10). | Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead. | [
"10 2\n",
"3 5\n"
] | [
"6\n",
"-1\n"
] | For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | 500 | [
{
"input": "10 2",
"output": "6"
},
{
"input": "3 5",
"output": "-1"
},
{
"input": "29 7",
"output": "21"
},
{
"input": "2 2",
"output": "2"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "10000 2",
"output": "5000"
},
{
"input": "10000 ... | 1,654,347,678 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | x,y=map(int,input().split())
if y>x:
print(-1)
else:
print(((((x+1)//2)+(y-1))//y)*y) | Title: Dreamoon and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb ... | ```python
x,y=map(int,input().split())
if y>x:
print(-1)
else:
print(((((x+1)//2)+(y-1))//y)*y)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,699,193,830 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 12,595,200 | n = int(input())
a = sorted([int(i) for i in input().split()])
for i in range(int(input())):
b = int(input())
ans = 0
for j in range(n):
if a[j] <= b:
ans += 1
else:
break
print(ans) | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
n = int(input())
a = sorted([int(i) for i in input().split()])
for i in range(int(input())):
b = int(input())
ans = 0
for j in range(n):
if a[j] <= b:
ans += 1
else:
break
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
270 | A | Fancy Fence | PROGRAMMING | 1,100 | [
"geometry",
"implementation",
"math"
] | null | null | Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuska... | The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees. | For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible. | [
"3\n30\n60\n90\n"
] | [
"NO\nYES\nYES\n"
] | In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a r... | 500 | [
{
"input": "3\n30\n60\n90",
"output": "NO\nYES\nYES"
},
{
"input": "6\n1\n2\n3\n170\n179\n25",
"output": "NO\nNO\nNO\nYES\nYES\nNO"
}
] | 1,696,942,474 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | t=int(input())
while t>0:
t-=1
a=int(input())
if (2/(180/a-1)+2)-int(2/(180/a-1)+2)<pow(10,-5):
print("YES")
else:
print("NO") | Title: Fancy Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can... | ```python
t=int(input())
while t>0:
t-=1
a=int(input())
if (2/(180/a-1)+2)-int(2/(180/a-1)+2)<pow(10,-5):
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
476 | A | Dreamoon and Stairs | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition? | The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10). | Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead. | [
"10 2\n",
"3 5\n"
] | [
"6\n",
"-1\n"
] | For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | 500 | [
{
"input": "10 2",
"output": "6"
},
{
"input": "3 5",
"output": "-1"
},
{
"input": "29 7",
"output": "21"
},
{
"input": "2 2",
"output": "2"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "10000 2",
"output": "5000"
},
{
"input": "10000 ... | 1,671,812,942 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define fast ios_base::sync_with_stdio(false);cin.tie(NULL);
#define yes cout<<"YES"<<endl
#define no cout<<"NO"<<endl
using namespace std;
const ll M... | Title: Dreamoon and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb ... | ```python
#include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define fast ios_base::sync_with_stdio(false);cin.tie(NULL);
#define yes cout<<"YES"<<endl
#define no cout<<"NO"<<endl
using namespace std;
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,630,164,850 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 6,963,200 |
def chat(s):
if len(s) < 5:
return 'NO'
s1 = ''
k = 0
for i in 'hello':
index = s.find(i,k,len(s))
s1 = s1 + s[index]
k = index + 1
print(s1)
if s1 == 'hello':
return 'YES'
return 'NO'
s = input()
print(chat(s)) | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def chat(s):
if len(s) < 5:
return 'NO'
s1 = ''
k = 0
for i in 'hello':
index = s.find(i,k,len(s))
s1 = s1 + s[index]
k = index + 1
print(s1)
if s1 == 'hello':
return 'YES'
return 'NO'
s = input()
print(chat(s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,621,324,057 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 16 | 967 | 21,913,600 | de=[0]*1000000
adjlist=list()
visited=[0]*1000000
even, odd=0, 0
def dfs(s, depth):
global even
global odd
de[s]=depth
visited[s]=1
if depth%2==0:
even=even+1
else:
odd=odd+1
for i in range(0, len(adjlist[s])):
v=adjlist[s][i]
if visited[v]==0:
dfs(v, depth+1)
n=int(input())
for i in... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
de=[0]*1000000
adjlist=list()
visited=[0]*1000000
even, odd=0, 0
def dfs(s, depth):
global even
global odd
de[s]=depth
visited[s]=1
if depth%2==0:
even=even+1
else:
odd=odd+1
for i in range(0, len(adjlist[s])):
v=adjlist[s][i]
if visited[v]==0:
dfs(v, depth+1)
n=int(input())... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
250 | A | Paper Work | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Polycarpus has been working in the analytic department of the "F.R.A.U.D." company for as much as *n* days. Right now his task is to make a series of reports about the company's performance for the last *n* days. We know that the main information in a day report is value *a**i*, the company's profit on the *i*-th day. ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), *n* is the number of days. The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=100), where *a**i* means the company profit on the *i*-th day. It is possible that the company has no days with the negative *a**i*. | Print an integer *k* — the required minimum number of folders. In the second line print a sequence of integers *b*1, *b*2, ..., *b**k*, where *b**j* is the number of day reports in the *j*-th folder.
If there are multiple ways to sort the reports into *k* days, print any of them. | [
"11\n1 2 3 -4 -5 -6 5 -5 -6 -7 6\n",
"5\n0 -1 100 -1 0\n"
] | [
"3\n5 3 3 ",
"1\n5 "
] | Here goes a way to sort the reports from the first sample into three folders:
In the second sample you can put all five reports in one folder. | 500 | [
{
"input": "11\n1 2 3 -4 -5 -6 5 -5 -6 -7 6",
"output": "3\n5 3 3 "
},
{
"input": "5\n0 -1 100 -1 0",
"output": "1\n5 "
},
{
"input": "1\n0",
"output": "1\n1 "
},
{
"input": "1\n-1",
"output": "1\n1 "
},
{
"input": "2\n0 0",
"output": "1\n2 "
},
{
"inp... | 1,615,227,243 | 2,147,483,647 | PyPy 3 | OK | TESTS | 69 | 216 | 0 | input()
days = map(int, input().split())
folders = []
fc = 0
c = 0
for i in days:
if i < 0:
if c < 2:
c += 1
else:
fc += 1
c = 1
if len(folders) <= fc:
folders.append(0)
folders[fc] += 1
print(fc + 1)
print(*folders) | Title: Paper Work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has been working in the analytic department of the "F.R.A.U.D." company for as much as *n* days. Right now his task is to make a series of reports about the company's performance for the last *n* days. We know tha... | ```python
input()
days = map(int, input().split())
folders = []
fc = 0
c = 0
for i in days:
if i < 0:
if c < 2:
c += 1
else:
fc += 1
c = 1
if len(folders) <= fc:
folders.append(0)
folders[fc] += 1
print(fc + 1)
print(*folders)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
680 | B | Bear and Finding Criminals | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city *a*. His job is to catch criminals. It's hard because he doesn't know in which cities criminals are. Though, he... | The first line of the input contains two integers *n* and *a* (1<=≤<=*a*<=≤<=*n*<=≤<=100) — the number of cities and the index of city where Limak lives.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=≤<=1). There are *t**i* criminals in the *i*-th city. | Print the number of criminals Limak will catch. | [
"6 3\n1 1 1 0 1 0\n",
"5 2\n0 0 0 1 0\n"
] | [
"3\n",
"1\n"
] | In the first sample, there are six cities and Limak lives in the third one (blue arrow below). Criminals are in cities marked red.
Using the BCD gives Limak the following information:
- There is one criminal at distance 0 from the third city — Limak is sure that this criminal is exactly in the third city. - There i... | 1,000 | [
{
"input": "6 3\n1 1 1 0 1 0",
"output": "3"
},
{
"input": "5 2\n0 0 0 1 0",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "9 3\n1 1 1 1 1 1 1 1 0",
"output": "8"
},
{
"input": "9 5\n1 0 1 0 1 0... | 1,657,632,390 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 31 | 0 | n, a = map(int, input().split())
gcd = list(map(int, input().split()))
a = a-1
l = a - 1
r = a + 1
if gcd[a] == 1:
ctr = 1
else:
ctr = 0
while (l>=0 and r < n):
if gcd[l] == 1 and gcd[r] == 1:
ctr += 2
l -= 1
r += 1
while l >= 0:
if gcd[l] == 1:
ctr += 1
l -=... | Title: Bear and Finding Criminals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city... | ```python
n, a = map(int, input().split())
gcd = list(map(int, input().split()))
a = a-1
l = a - 1
r = a + 1
if gcd[a] == 1:
ctr = 1
else:
ctr = 0
while (l>=0 and r < n):
if gcd[l] == 1 and gcd[r] == 1:
ctr += 2
l -= 1
r += 1
while l >= 0:
if gcd[l] == 1:
ctr += 1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,657,923,499 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | def main():
n, k = [int(i) for i in input().split()]
team = [int(i) for i in input().split()]
# Loop and compute
count = 0
for member in team:
tmp = member + k
if tmp <= 5:
count += 1
print(count // 3)
main() | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
def main():
n, k = [int(i) for i in input().split()]
team = [int(i) for i in input().split()]
# Loop and compute
count = 0
for member in team:
tmp = member + k
if tmp <= 5:
count += 1
print(count // 3)
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
496 | A | Minimum Difficulty | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 for all *i* from 1 to *n*<=-<=1; we will call such sequence a track. Mike thinks that the track *a*1, ...,... | The first line contains a single integer *n* (3<=≤<=*n*<=≤<=100) — the number of holds.
The next line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000), where *a**i* is the height where the hold number *i* hangs. The sequence *a**i* is increasing (i.e. each element except for the first one is strict... | Print a single number — the minimum difficulty of the track after removing a single hold. | [
"3\n1 4 6\n",
"5\n1 2 3 4 5\n",
"5\n1 2 3 7 8\n"
] | [
"5\n",
"2\n",
"4\n"
] | In the first sample you can remove only the second hold, then the sequence looks like (1, 6), the maximum difference of the neighboring elements equals 5.
In the second test after removing every hold the difficulty equals 2.
In the third test you can obtain sequences (1, 3, 7, 8), (1, 2, 7, 8), (1, 2, 3, 8), for whic... | 500 | [
{
"input": "3\n1 4 6",
"output": "5"
},
{
"input": "5\n1 2 3 4 5",
"output": "2"
},
{
"input": "5\n1 2 3 7 8",
"output": "4"
},
{
"input": "3\n1 500 1000",
"output": "999"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "2"
},
{
"input": "10\n1 4 9... | 1,545,725,524 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 108 | 0 | n=int(input())
a = [int(i) for i in input().split()]
maxi=0
mini=a[n-1]-a[0]
for i in range(1,n-1):
for j in range(1,n):
if j==i:
maxi=max(maxi,a[j+1]-a[j-1])
else:
maxi=max(maxi,a[j]-a[j-1])
mini=min(maxi,mini)
print(mini)
| Title: Minimum Difficulty
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike is trying rock climbing but he is awful at it.
There are *n* holds on the wall, *i*-th hold is at height *a**i* off the ground. Besides, let the sequence *a**i* increase, that is, *a**i*<=<<=*a**i*<=+<=1 fo... | ```python
n=int(input())
a = [int(i) for i in input().split()]
maxi=0
mini=a[n-1]-a[0]
for i in range(1,n-1):
for j in range(1,n):
if j==i:
maxi=max(maxi,a[j+1]-a[j-1])
else:
maxi=max(maxi,a[j]-a[j-1])
mini=min(maxi,mini)
print(mini)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
14 | B | Young Photographer | PROGRAMMING | 1,000 | [
"implementation"
] | B. Young Photographer | 2 | 64 | Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. But the problem was that not all the runners passed him. The total amount of sportsmen, training at t... | The first line of the input file contains integers *n* and *x*0 (1<=≤<=*n*<=≤<=100; 0<=≤<=*x*0<=≤<=1000). The following *n* lines contain pairs of integers *a**i*,<=*b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000; *a**i*<=≠<=*b**i*). | Output the required minimum distance in the same units as the positions on the racetrack. If there is no such a position, output -1. | [
"3 3\n0 7\n14 2\n4 6\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "3 3\n0 7\n14 2\n4 6",
"output": "1"
},
{
"input": "1 1\n0 10",
"output": "0"
},
{
"input": "2 2\n1 2\n3 2",
"output": "0"
},
{
"input": "3 2\n1 2\n2 3\n3 4",
"output": "-1"
},
{
"input": "2 4\n10 4\n1 5",
"output": "0"
},
{
"input": "1 10\n... | 1,694,169,680 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | def read_int():
return int(input().strip())
def read_ints():
return list(map(int, input().strip().split()))
def read_str():
return input().strip()
def read_strs():
return input().strip().split()
def result(n, x0, a, b):
borders = [(i, +1) for i in a] + [(i, -1) for i in b]
borders.sort()
... | Title: Young Photographer
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. Bu... | ```python
def read_int():
return int(input().strip())
def read_ints():
return list(map(int, input().strip().split()))
def read_str():
return input().strip()
def read_strs():
return input().strip().split()
def result(n, x0, a, b):
borders = [(i, +1) for i in a] + [(i, -1) for i in b]
borders.... | 0 | MatrixStudio/Codeforces-Python-Submissions |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,693,605,851 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 122 | 2,764,800 | import math
n=int(input("Number of Friends: "))
k=int(input("Number of Cans: "))
l=int(input("Mililiter of Drink: "))
nl=int(input("Drink In Each Bottle: "))
totalmil=k*l
totalto=totalmil//nl
c=int(input("Number of Limes: "))
d=int(input("Number of Slices for Each Lime: "))
totalimeslices=c*d
p=int(input("Grams of ... | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
import math
n=int(input("Number of Friends: "))
k=int(input("Number of Cans: "))
l=int(input("Mililiter of Drink: "))
nl=int(input("Drink In Each Bottle: "))
totalmil=k*l
totalto=totalmil//nl
c=int(input("Number of Limes: "))
d=int(input("Number of Slices for Each Lime: "))
totalimeslices=c*d
p=int(input(... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,541,837,327 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 109 | 0 | #!/usr/bin/env python3
s = input()
hello = []
if s.count("l") >= 2:
for c in s:
if c not in hello and c in "helo":
hello.append(c)
if ''.join(hello) == "helo":
print("YES")
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
#!/usr/bin/env python3
s = input()
hello = []
if s.count("l") >= 2:
for c in s:
if c not in hello and c in "helo":
hello.append(c)
if ''.join(hello) == "helo":
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
985 | B | Switches and Lamps | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | You are given *n* switches and *m* lamps. The *i*-th switch turns on some subset of the lamps. This information is given as the matrix *a* consisting of *n* rows and *m* columns where *a**i*,<=*j*<==<=1 if the *i*-th switch turns on the *j*-th lamp and *a**i*,<=*j*<==<=0 if the *i*-th switch is not connected to the *j*... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2000) — the number of the switches and the number of the lamps.
The following *n* lines contain *m* characters each. The character *a**i*,<=*j* is equal to '1' if the *i*-th switch turns on the *j*-th lamp and '0' otherwise.
It is guar... | Print "YES" if there is a switch that if you will ignore it and press all the other *n*<=-<=1 switches then all *m* lamps will be turned on. Print "NO" if there is no such switch. | [
"4 5\n10101\n01000\n00111\n10000\n",
"4 5\n10100\n01000\n00110\n00101\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "4 5\n10101\n01000\n00111\n10000",
"output": "YES"
},
{
"input": "4 5\n10100\n01000\n00110\n00101",
"output": "NO"
},
{
"input": "1 5\n11111",
"output": "NO"
},
{
"input": "10 1\n1\n0\n0\n0\n0\n0\n0\n0\n0\n1",
"output": "YES"
},
{
"input": "1 1\n1",
... | 1,607,258,576 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 1,621 | 20,172,800 | s, l= list(map(int,input().split()))
sig = []
utp = []
for i in range(s):
sig.append(list(map(int,input())))
for i in range(0,s):
out = 0
for x in range(0,l-1):
out+=sig[x][i]
utp.append(out)
for i in range(0,s):
for x in range(0,l-1):
if utp[x]-sig[i][x] <=0:
... | Title: Switches and Lamps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* switches and *m* lamps. The *i*-th switch turns on some subset of the lamps. This information is given as the matrix *a* consisting of *n* rows and *m* columns where *a**i*,<=*j*<==<=1 if the *i*-th... | ```python
s, l= list(map(int,input().split()))
sig = []
utp = []
for i in range(s):
sig.append(list(map(int,input())))
for i in range(0,s):
out = 0
for x in range(0,l-1):
out+=sig[x][i]
utp.append(out)
for i in range(0,s):
for x in range(0,l-1):
if utp[x]-sig[i][x] <=0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it la... | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on... | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,667,898,627 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 46 | 0 | n,m=map(int,input().split(' '))
s=0
x=0
a=n
while(a>=m):
x=a%m
a=int(a/m)
s=s+a+x
print(s+n) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th... | ```python
n,m=map(int,input().split(' '))
s=0
x=0
a=n
while(a>=m):
x=a%m
a=int(a/m)
s=s+a+x
print(s+n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 0 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,409,068,596 | 6,996 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 61 | 0 | def yabl(b):
if len(b) == 1:
False
else:
x = len(b) // 2
tost(b[x:])
tost(b[:x])
def tost(a):
global cnt
cnt += sum(a)
yabl(a)
cnt = 0
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
tost(arr)
print(cnt) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and ... | ```python
def yabl(b):
if len(b) == 1:
False
else:
x = len(b) // 2
tost(b[x:])
tost(b[:x])
def tost(a):
global cnt
cnt += sum(a)
yabl(a)
cnt = 0
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
tost(arr)
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
27 | B | Tournament | PROGRAMMING | 1,300 | [
"bitmasks",
"brute force",
"dfs and similar",
"greedy"
] | B. Tournament | 2 | 256 | The tournament «Sleepyhead-2010» in the rapid falling asleep has just finished in Berland. *n* best participants from the country have participated in it. The tournament consists of games, each of them is a match between two participants. *n*·(*n*<=-<=1)<=/<=2 games were played during the tournament, and each participa... | The first line contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of participants. The following *n*·(*n*<=-<=1)<=/<=2<=-<=1 lines contain the results of the games. Each game is described in a single line by two integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*,<=*x**i*<=≠<=*y**i*), where *x**i* и *y**i* ar... | Output two integers *x* and *y* — the missing record. If there are several solutions, output any of them. | [
"4\n4 2\n4 1\n2 3\n2 1\n3 1\n"
] | [
"4 3\n"
] | none | 1,000 | [
{
"input": "3\n3 2\n1 2",
"output": "1 3"
},
{
"input": "4\n2 4\n3 4\n1 2\n1 4\n1 3",
"output": "2 3"
},
{
"input": "5\n3 5\n2 5\n1 5\n1 4\n4 3\n1 3\n2 3\n4 5\n4 2",
"output": "1 2"
},
{
"input": "6\n3 4\n3 5\n5 4\n1 2\n5 6\n2 6\n5 2\n3 6\n3 2\n4 6\n2 4\n1 3\n1 5\n1 4",
"... | 1,544,378,275 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 216 | 0 | elements = []
sayac = []
n = int(input())
sayi = (n * (n-1))/2
sayi = int(sayi)
for i in range(60):
elements.append([])
sayac.append(0)
for i in range(1,sayi):
winner,loser = map(int,input().split())
elements[winner].append(loser)
sayac[winner] +=1
sayac[loser] += 1
s1,s2 = 0,0
for i in range(... | Title: Tournament
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The tournament «Sleepyhead-2010» in the rapid falling asleep has just finished in Berland. *n* best participants from the country have participated in it. The tournament consists of games, each of them is a match between two par... | ```python
elements = []
sayac = []
n = int(input())
sayi = (n * (n-1))/2
sayi = int(sayi)
for i in range(60):
elements.append([])
sayac.append(0)
for i in range(1,sayi):
winner,loser = map(int,input().split())
elements[winner].append(loser)
sayac[winner] +=1
sayac[loser] += 1
s1,s2 = 0,0
for i... | -1 | MatrixStudio/Codeforces-Python-Submissions |
284 | B | Cows and Poker Game | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any be... | The first line contains a single integer, *n* (2<=≤<=*n*<=≤<=2·105). The second line contains *n* characters, each either "A", "I", or "F". The *i*-th character is "A" if the *i*-th player's status is "ALLIN", "I" if the *i*-th player's status is "IN", or "F" if the *i*-th player's status is "FOLDED". | The first line should contain a single integer denoting the number of players that can currently show their hands. | [
"6\nAFFAAA\n",
"3\nAFI\n"
] | [
"4\n",
"1\n"
] | In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | 1,000 | [
{
"input": "6\nAFFAAA",
"output": "4"
},
{
"input": "3\nAFI",
"output": "1"
},
{
"input": "3\nFFF",
"output": "0"
},
{
"input": "3\nFIF",
"output": "1"
},
{
"input": "3\nAAA",
"output": "3"
},
{
"input": "3\nIII",
"output": "0"
},
{
"input"... | 1,635,409,402 | 2,147,483,647 | Python 3 | OK | TESTS | 66 | 124 | 5,632,000 | n=int(input())
l=list(input())
ca=l.count("A")
ci=l.count("I")
if ci==0:
print(ca)
elif ci==1:
print(1)
else:
print(0) | Title: Cows and Poker Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player who... | ```python
n=int(input())
l=list(input())
ca=l.count("A")
ci=l.count("I")
if ci==0:
print(ca)
elif ci==1:
print(1)
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,645,627,094 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | def factorial(x):
if x == 0:
return 1
return x*factorial(x-1)
a, b = map(int, input().split())
print(factorial(min(a, b))) | Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
def factorial(x):
if x == 0:
return 1
return x*factorial(x-1)
a, b = map(int, input().split())
print(factorial(min(a, b)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,632,782,672 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 93 | 20,172,800 | state = 0
for i in input():
if i == "h" and state == 0:
state = 1
elif i == "e" and state == 1:
state = 2
elif i == "l" and state == 2:
state = 3
elif i == "l" and state == 3:
state = 4
elif i == "o" and state == 4:
state = 5
if state == 5:
print("YES")
el... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
state = 0
for i in input():
if i == "h" and state == 0:
state = 1
elif i == "e" and state == 1:
state = 2
elif i == "l" and state == 2:
state = 3
elif i == "l" and state == 3:
state = 4
elif i == "o" and state == 4:
state = 5
if state == 5:
print... | 3.915925 | MatrixStudio/Codeforces-Python-Submissions |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,662,979,459 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 109 | 307,200 | n = int(input())
prime = []
if n % 2 == 1:
prime.append(3)
n -= 3
for _ in range(n, 0, -2):
prime.append(2)
print(len(prime))
for i in range(len(prime)):
print(prime[i], end =" ")
| Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
n = int(input())
prime = []
if n % 2 == 1:
prime.append(3)
n -= 3
for _ in range(n, 0, -2):
prime.append(2)
print(len(prime))
for i in range(len(prime)):
print(prime[i], end =" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,690,459,987 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | x=input().lower()
if x[0]==h or x[0]==q:
print('YES')
else:
print('NO') | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
x=input().lower()
if x[0]==h or x[0]==q:
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
234 | A | Lefthanders and Righthanders | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One fine October day a mathematics teacher Vasily Petrov went to a class and saw there *n* pupils who sat at the desks, two people at each desk. Vasily quickly realized that number *n* is even. Like all true mathematicians, Vasily has all students numbered from 1 to *n*.
But Vasily Petrov did not like the way the chi... | The first input line contains a single even integer *n* (4<=≤<=*n*<=≤<=100) — the number of students in the class. The second line contains exactly *n* capital English letters "L" and "R". If the *i*-th letter at the second line equals "L", then the student number *i* is a lefthander, otherwise he is a righthander. | Print integer pairs, one pair per line. In the *i*-th line print the numbers of students that will sit at the *i*-th desk. The first number in the pair stands for the student who is sitting to the left, and the second number stands for the student who is sitting to the right. Separate the numbers in the pairs by space... | [
"6\nLLRLLL\n",
"4\nRRLL\n"
] | [
"1 4\n2 5\n6 3\n",
"3 1\n4 2\n"
] | none | 0 | [
{
"input": "6\nLLRLLL",
"output": "1 4\n2 5\n6 3"
},
{
"input": "4\nRRLL",
"output": "3 1\n4 2"
},
{
"input": "4\nLLRR",
"output": "1 3\n2 4"
},
{
"input": "6\nRLLRRL",
"output": "1 4\n2 5\n3 6"
},
{
"input": "8\nLRLRLLLR",
"output": "1 5\n6 2\n3 7\n4 8"
},
... | 1,620,389,926 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 109 | 22,323,200 | my_file = open("input.txt", "r")
outputFile = open("output.txt", "a")
n = int(my_file.readline())
s = my_file.readline()
s = s.strip()
if len(s)==n:
i = 0
while i < n//2:
if s[i] == s[i + n//2]:
outputFile.write(str(i+1) + ' ' + str(i+n//2+1) + '\n')
else:
if students[i]=... | Title: Lefthanders and Righthanders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One fine October day a mathematics teacher Vasily Petrov went to a class and saw there *n* pupils who sat at the desks, two people at each desk. Vasily quickly realized that number *n* is even. Like all t... | ```python
my_file = open("input.txt", "r")
outputFile = open("output.txt", "a")
n = int(my_file.readline())
s = my_file.readline()
s = s.strip()
if len(s)==n:
i = 0
while i < n//2:
if s[i] == s[i + n//2]:
outputFile.write(str(i+1) + ' ' + str(i+n//2+1) + '\n')
else:
if st... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
842 | D | Vitya and Strange Lesson | PROGRAMMING | 2,000 | [
"binary search",
"data structures"
] | null | null | Today at the lesson Vitya learned a very interesting function — mex. Mex of a sequence of numbers is the minimum non-negative number that is not present in the sequence as element. For example, *mex*([4,<=33,<=0,<=1,<=1,<=5])<==<=2 and *mex*([1,<=2,<=3])<==<=0.
Vitya quickly understood all tasks of the teacher, but ca... | First line contains two integer numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3·105) — number of elements in array and number of queries.
Next line contains *n* integer numbers *a**i* (0<=≤<=*a**i*<=≤<=3·105) — elements of then array.
Each of next *m* lines contains query — one integer number *x* (0<=≤<=*x*<=≤<=3·105). | For each query print the answer on a separate line. | [
"2 2\n1 3\n1\n3\n",
"4 3\n0 1 5 6\n1\n2\n4\n",
"5 4\n0 1 5 6 7\n1\n1\n4\n5\n"
] | [
"1\n0\n",
"2\n0\n0\n",
"2\n2\n0\n2\n"
] | none | 2,000 | [
{
"input": "2 2\n1 3\n1\n3",
"output": "1\n0"
},
{
"input": "4 3\n0 1 5 6\n1\n2\n4",
"output": "2\n0\n0"
},
{
"input": "5 4\n0 1 5 6 7\n1\n1\n4\n5",
"output": "2\n2\n0\n2"
},
{
"input": "5 5\n1 2 3 4 5\n1\n2\n3\n4\n5",
"output": "1\n3\n0\n2\n1"
},
{
"input": "9 3\... | 1,685,637,401 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 47,308,800 | NUMBEROFNODES = 140005
LG = 18
class Trie:
class Node:
def __init__(self):
self.child = [-1, -1]
self.cnt = 0
def __init__(self):
self.nodes = [self.Node() for _ in range(NUMBEROFNODES)]
self.cur = 0
self.nodes[0].child = [-1, -1]
se... | Title: Vitya and Strange Lesson
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today at the lesson Vitya learned a very interesting function — mex. Mex of a sequence of numbers is the minimum non-negative number that is not present in the sequence as element. For example, *mex*([4,<=33,<=... | ```python
NUMBEROFNODES = 140005
LG = 18
class Trie:
class Node:
def __init__(self):
self.child = [-1, -1]
self.cnt = 0
def __init__(self):
self.nodes = [self.Node() for _ in range(NUMBEROFNODES)]
self.cur = 0
self.nodes[0].child = [-1, -1]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,672,324,726 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 62 | 0 | num=int(input())
res=list(str(num))
for i,n in enumerate(res):
if i==0 and n=="9":
continue
if 9-int(n)<int(n):
res[i]=9-int(n)
for i,n in enumerate(res):
res[i]=str(n)
if num==9:
print(9)
else:
print(int("".join(res)))
| Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
num=int(input())
res=list(str(num))
for i,n in enumerate(res):
if i==0 and n=="9":
continue
if 9-int(n)<int(n):
res[i]=9-int(n)
for i,n in enumerate(res):
res[i]=str(n)
if num==9:
print(9)
else:
print(int("".join(res)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,697,012,186 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 62 | 0 | number = int(input())
count = 0
while number != 0:
if number % 2 == 1:
number -= 1
count += 1
else:
number = number // 2
print(count) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
number = int(input())
count = 0
while number != 0:
if number % 2 == 1:
number -= 1
count += 1
else:
number = number // 2
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,672,903,530 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n=int(input())
for i in range(4,n//2+1):
f=0
for j in range(2,i):
if i%j==0 and (n-i)%j==0:
f=1
break
if f==1:
print(i,n-i,sep=' ')
break | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n=int(input())
for i in range(4,n//2+1):
f=0
for j in range(2,i):
if i%j==0 and (n-i)%j==0:
f=1
break
if f==1:
print(i,n-i,sep=' ')
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,380,973,102 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | a, b = map(int, input().split())
c = 7 - max(a, b)
d = gcd(6, c)
print(str(c // d) + '/' + str(6 // d)) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
a, b = map(int, input().split())
c = 7 - max(a, b)
d = gcd(6, c)
print(str(c // d) + '/' + str(6 // d))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
454 | A | Little Pony and Crystal Mine | PROGRAMMING | 800 | [
"implementation"
] | null | null | Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You need to draw a crystal of size *n*. The diamond cells of the matrix should be represented by character "D". All ot... | The only line contains an integer *n* (3<=≤<=*n*<=≤<=101; *n* is odd). | Output a crystal of size *n*. | [
"3\n",
"5\n",
"7\n"
] | [
"*D*\nDDD\n*D*\n",
"**D**\n*DDD*\nDDDDD\n*DDD*\n**D**\n",
"***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***\n"
] | none | 500 | [
{
"input": "3",
"output": "*D*\nDDD\n*D*"
},
{
"input": "5",
"output": "**D**\n*DDD*\nDDDDD\n*DDD*\n**D**"
},
{
"input": "7",
"output": "***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***"
},
{
"input": "11",
"output": "*****D*****\n****DDD****\n***DDDDD***\n**... | 1,576,491,850 | 2,147,483,647 | Python 3 | OK | TESTS | 12 | 108 | 0 | n=int(input())
for i in range(n//2+1):
x=(2*i)+1
print("*"*((n//2)-i),end='')
print("D"*x,end='')
print("*"*((n//2)-i))
for i in range(n//2-1,-1,-1):
x=(2*i)+1
print("*"*((n//2)-i),end='')
print("D"*x,end='')
print("*"*((n//2)-i)) | Title: Little Pony and Crystal Mine
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You ... | ```python
n=int(input())
for i in range(n//2+1):
x=(2*i)+1
print("*"*((n//2)-i),end='')
print("D"*x,end='')
print("*"*((n//2)-i))
for i in range(n//2-1,-1,-1):
x=(2*i)+1
print("*"*((n//2)-i),end='')
print("D"*x,end='')
print("*"*((n//2)-i))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million... | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,642,566,943 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 64 | 186 | 0 | k = int(input())
l = int(input())
arr = []
for x in range(1,32):
arr.append(k**x)
for i in range(31):
if arr[i] == l:
print("YES")
print(i)
break
else:
print("NO") | Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousa... | ```python
k = int(input())
l = int(input())
arr = []
for x in range(1,32):
arr.append(k**x)
for i in range(31):
if arr[i] == l:
print("YES")
print(i)
break
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
883 | A | Automatic Door | PROGRAMMING | 2,200 | [
"implementation"
] | null | null | There is an automatic door at the entrance of a factory. The door works in the following way:
- when one or several people come to the door and it is closed, the door immediately opens automatically and all people immediately come inside, - when one or several people come to the door and it is open, all people immed... | The first line contains four integers *n*, *m*, *a* and *d* (1<=≤<=*n*,<=*a*<=≤<=109, 1<=≤<=*m*<=≤<=105, 1<=≤<=*d*<=≤<=1018) — the number of the employees, the number of the clients, the moment of time when the first employee will come and the period of time in which the door closes.
The second line contains integer s... | Print the number of times the door will open. | [
"1 1 3 4\n7\n",
"4 3 4 2\n7 9 11\n"
] | [
"1\n",
"4\n"
] | In the first example the only employee will come at moment 3. At this moment the door will open and will stay open until the moment 7. At the same moment of time the client will come, so at first he will enter and only after it the door will close. Thus the door will open one time. | 0 | [
{
"input": "1 1 3 4\n7",
"output": "1"
},
{
"input": "4 3 4 2\n7 9 11",
"output": "4"
},
{
"input": "10 10 51 69\n154 170 170 183 251 337 412 426 445 452",
"output": "6"
},
{
"input": "70 10 26 17\n361 371 579 585 629 872 944 1017 1048 1541",
"output": "70"
},
{
"... | 1,509,368,416 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | # http://codeforces.com/problemset/problem/883/A
n, m, a, d = [int(x) for x in input().split()]
q = [int(x) for x in input().split()]
i = 1
curr = 0
j = 0
ans = 1
while( (i <= n) or (j < len(q)) ):
if j < len(q):
temp = q[j]
curr = min(curr+d, i*a, temp)
else:
curr = min(curr+d, i*a)
# prin... | Title: Automatic Door
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is an automatic door at the entrance of a factory. The door works in the following way:
- when one or several people come to the door and it is closed, the door immediately opens automatically and all people imme... | ```python
# http://codeforces.com/problemset/problem/883/A
n, m, a, d = [int(x) for x in input().split()]
q = [int(x) for x in input().split()]
i = 1
curr = 0
j = 0
ans = 1
while( (i <= n) or (j < len(q)) ):
if j < len(q):
temp = q[j]
curr = min(curr+d, i*a, temp)
else:
curr = min(curr+d, i*a)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,696,097,397 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 265 | 102,400 | a = int(input())
if a % 2 == 1:
print(a ** 2 // 2 + 1)
else:
print(a ** 2 // 2)
for i in range(a):
b = ''
if i % 2 == 0:
for g in range(a):
if g % 2 == 0:
b += 'C'
else:
b += '.'
else:
for g in range(a):
... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
a = int(input())
if a % 2 == 1:
print(a ** 2 // 2 + 1)
else:
print(a ** 2 // 2)
for i in range(a):
b = ''
if i % 2 == 0:
for g in range(a):
if g % 2 == 0:
b += 'C'
else:
b += '.'
else:
for g in range(a):... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
863 | B | Kayaking | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"sortings"
] | null | null | Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they have to choose kayaks. There are 2·*n* people in the group (including Vadim), and they have exact... | The first line contains one number *n* (2<=≤<=*n*<=≤<=50).
The second line contains 2·*n* integer numbers *w*1, *w*2, ..., *w*2*n*, where *w**i* is weight of person *i* (1<=≤<=*w**i*<=≤<=1000). | Print minimum possible total instability. | [
"2\n1 2 3 4\n",
"4\n1 3 4 6 3 4 100 200\n"
] | [
"1\n",
"5\n"
] | none | 0 | [
{
"input": "2\n1 2 3 4",
"output": "1"
},
{
"input": "4\n1 3 4 6 3 4 100 200",
"output": "5"
},
{
"input": "3\n305 139 205 406 530 206",
"output": "102"
},
{
"input": "3\n610 750 778 6 361 407",
"output": "74"
},
{
"input": "5\n97 166 126 164 154 98 221 7 51 47",
... | 1,680,038,245 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 61 | 1,536,000 | n = int(input())
arr = list(map(int, input().split()))
ans = []
while (len(arr) > 2) :
arr.sort()
m = 1e9
a = -1
for i in range(1, len(arr)) :
if arr[i] - arr[i-1] < m :
m = arr[i] - arr[i-1]
a = i-1
ans.append(m)
arr.pop(a); arr.pop(a)
print(... | Title: Kayaking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they hav... | ```python
n = int(input())
arr = list(map(int, input().split()))
ans = []
while (len(arr) > 2) :
arr.sort()
m = 1e9
a = -1
for i in range(1, len(arr)) :
if arr[i] - arr[i-1] < m :
m = arr[i] - arr[i-1]
a = i-1
ans.append(m)
arr.pop(a); arr.pop(a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,646,464,471 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 92 | 0 | n = input()
i=0
check = True
count=0
if(n[0]!="1"):
print("NO")
else:
while(i<len(n)):
if(n[i]=="1"):
count = 0
pass
elif(n[i]=="4" and count<2):
count+=1
else:
check = False
break
i+=1
if check:
... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
n = input()
i=0
check = True
count=0
if(n[0]!="1"):
print("NO")
else:
while(i<len(n)):
if(n[i]=="1"):
count = 0
pass
elif(n[i]=="4" and count<2):
count+=1
else:
check = False
break
i+=1
if ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
257 | A | Sockets | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"sortings"
] | null | null | Vasya has got many devices that work on electricity. He's got *n* supply-line filters to plug the devices, the *i*-th supply-line filter has *a**i* sockets.
Overall Vasya has got *m* devices and *k* electrical sockets in his flat, he can plug the devices or supply-line filters directly. Of course, he can plug the supp... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=50) — the number of supply-line filters, the number of devices and the number of sockets that he can plug to directly, correspondingly. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=50) —... | Print a single number — the minimum number of supply-line filters that is needed to plug all the devices to electricity. If it is impossible to plug all the devices even using all the supply-line filters, print -1. | [
"3 5 3\n3 1 2\n",
"4 7 2\n3 3 2 4\n",
"5 5 1\n1 3 1 2 1\n"
] | [
"1\n",
"2\n",
"-1\n"
] | In the first test case he can plug the first supply-line filter directly to electricity. After he plug it, he get 5 (3 on the supply-line filter and 2 remaining sockets for direct plugging) available sockets to plug. Thus, one filter is enough to plug 5 devices.
One of the optimal ways in the second test sample is to ... | 500 | [
{
"input": "3 5 3\n3 1 2",
"output": "1"
},
{
"input": "4 7 2\n3 3 2 4",
"output": "2"
},
{
"input": "5 5 1\n1 3 1 2 1",
"output": "-1"
},
{
"input": "4 5 8\n3 2 4 3",
"output": "0"
},
{
"input": "5 10 1\n4 3 4 2 4",
"output": "3"
},
{
"input": "7 13 2... | 1,694,801,227 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 31 | 124 | 0 | n,m,k = map(int,input().split())
a = sorted(list(map(int,input().split())), reverse= True)
if m <= k:
print(0)
else:
s = 0
for i in range(1,n):
s += a[i-1]
if s + (k-i) >= m:
print(i)
exit()
print(-1) | Title: Sockets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got many devices that work on electricity. He's got *n* supply-line filters to plug the devices, the *i*-th supply-line filter has *a**i* sockets.
Overall Vasya has got *m* devices and *k* electrical sockets in his f... | ```python
n,m,k = map(int,input().split())
a = sorted(list(map(int,input().split())), reverse= True)
if m <= k:
print(0)
else:
s = 0
for i in range(1,n):
s += a[i-1]
if s + (k-i) >= m:
print(i)
exit()
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
452 | B | 4-point polyline | PROGRAMMING | 1,800 | [
"brute force",
"constructive algorithms",
"geometry",
"trees"
] | null | null | You are given a rectangular grid of lattice points from (0,<=0) to (*n*,<=*m*) inclusive. You have to choose exactly 4 different points to build a polyline possibly with self-intersections and self-touching. This polyline should be as long as possible.
A polyline defined by points *p*1,<=*p*2,<=*p*3,<=*p*4 consists of... | The only line of the input contains two integers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=1000). It is guaranteed that grid contains at least 4 different points. | Print 4 lines with two integers per line separated by space — coordinates of points *p*1,<=*p*2,<=*p*3,<=*p*4 in order which represent the longest possible polyline.
Judge program compares your answer and jury's answer with 10<=-<=6 precision. | [
"1 1\n",
"0 10\n"
] | [
"1 1\n0 0\n1 0\n0 1\n",
"0 1\n0 10\n0 0\n0 9\n"
] | none | 1,000 | [
{
"input": "1 1",
"output": "0 0\n1 1\n0 1\n1 0"
},
{
"input": "0 10",
"output": "0 1\n0 10\n0 0\n0 9"
},
{
"input": "10 10",
"output": "10 9\n0 0\n10 10\n1 0"
},
{
"input": "100 100",
"output": "0 1\n100 100\n0 0\n99 100"
},
{
"input": "10 100",
"output": "9 ... | 1,648,707,888 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | from math import sqrt
def solv(n,m):
print(0,0)
print(n,m)
if not n:
print(0,1)
print(0,m-1)
return
if not m:
print(1,0)
print(n-1,0)
return
r2nm = sqrt((n-1)**2 + m**2)
u2nm = sqrt(n**2 + (m-1)**2)
l00r = sqrt((n-2)**2 + m**2)
... | Title: 4-point polyline
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular grid of lattice points from (0,<=0) to (*n*,<=*m*) inclusive. You have to choose exactly 4 different points to build a polyline possibly with self-intersections and self-touching. This polyl... | ```python
from math import sqrt
def solv(n,m):
print(0,0)
print(n,m)
if not n:
print(0,1)
print(0,m-1)
return
if not m:
print(1,0)
print(n-1,0)
return
r2nm = sqrt((n-1)**2 + m**2)
u2nm = sqrt(n**2 + (m-1)**2)
l00r = sqrt((n-2)**... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,680,938,823 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 77 | 1,945,600 | def it(): return int(input())
def pr(a): return print(a)
def li(): return list(map(int, input().split()))
def ls(): return [str(i) for i in input()]
def no(): return print('NO')
def yes(): return print('YES')
def mapa(): return map(int, input().split())
#''' ????????????????????????????????????? '''#
#''' ?????... | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
def it(): return int(input())
def pr(a): return print(a)
def li(): return list(map(int, input().split()))
def ls(): return [str(i) for i in input()]
def no(): return print('NO')
def yes(): return print('YES')
def mapa(): return map(int, input().split())
#''' ????????????????????????????????????? '''#
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,610,355,111 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 186 | 0 | w = input()
lCount = 0
uCount = 0
for i in w:
if ord(i)<97:
uCount+=1
else:
lCount+=1
print(w.lower() if lCount>=uCount else w.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
w = input()
lCount = 0
uCount = 0
for i in w:
if ord(i)<97:
uCount+=1
else:
lCount+=1
print(w.lower() if lCount>=uCount else w.upper())
``` | 3.9535 | MatrixStudio/Codeforces-Python-Submissions |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,581,532,969 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 0 | #Yakko, Wakko and Dot,
y = int(input())
w = int(input())
max_num = y
if y > 6 and w <= 6:
max_num = w
if w > y and w <= 6:
max_num = w
result = (6-(max_num-1)) / 6
result = float(result).as_integer_ratio()
print(f'{result[0]}/{result[1]}')
| Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
#Yakko, Wakko and Dot,
y = int(input())
w = int(input())
max_num = y
if y > 6 and w <= 6:
max_num = w
if w > y and w <= 6:
max_num = w
result = (6-(max_num-1)) / 6
result = float(result).as_integer_ratio()
print(f'{result[0]}/{result[1]}')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
659 | A | Round House | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance *a* and he decided that during his walk he will move around the house *b* entrances in th... | The single line of the input contains three space-separated integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*a*<=≤<=*n*,<=<=-<=100<=≤<=*b*<=≤<=100) — the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively. | Print a single integer *k* (1<=≤<=*k*<=≤<=*n*) — the number of the entrance where Vasya will be at the end of his walk. | [
"6 2 -5\n",
"5 1 3\n",
"3 2 7\n"
] | [
"3\n",
"4\n",
"3\n"
] | The first example is illustrated by the picture in the statements. | 500 | [
{
"input": "6 2 -5",
"output": "3"
},
{
"input": "5 1 3",
"output": "4"
},
{
"input": "3 2 7",
"output": "3"
},
{
"input": "1 1 0",
"output": "1"
},
{
"input": "1 1 -1",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "100 ... | 1,675,435,837 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 28,774,400 | n , a , b = list(map(int , input().split()))
if(b > 0):
while b > 0 :
if(a == n):
a = 1
b -= 1
else:
b -= 1
a += 1
print(a)
elif(b == 0):
print(a)
else:
b = abs(b)
while b < 0:
if(a == 1):
a = ... | Title: Round House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in e... | ```python
n , a , b = list(map(int , input().split()))
if(b > 0):
while b > 0 :
if(a == n):
a = 1
b -= 1
else:
b -= 1
a += 1
print(a)
elif(b == 0):
print(a)
else:
b = abs(b)
while b < 0:
if(a == 1):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
611 | D | New Year and Ancient Prophecy | PROGRAMMING | 2,000 | [
"dp",
"hashing",
"strings"
] | null | null | Limak is a little polar bear. In the snow he found a scroll with the ancient prophecy. Limak doesn't know any ancient languages and thus is unable to understand the prophecy. But he knows digits!
One fragment of the prophecy is a sequence of *n* digits. The first digit isn't zero. Limak thinks that it's a list of some... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=5000) — the number of digits.
The second line contains a string of digits and has length equal to *n*. It's guaranteed that the first digit is not '0'. | Print the number of ways to correctly split the given sequence modulo 109<=+<=7. | [
"6\n123434\n",
"8\n20152016\n"
] | [
"8\n",
"4\n"
] | In the first sample there are 8 ways to split the sequence:
- "123434" = "123434" (maybe the given sequence is just one big number) - "123434" = "1" + "23434" - "123434" = "12" + "3434" - "123434" = "123" + "434" - "123434" = "1" + "23" + "434" - "123434" = "1" + "2" + "3434" - "123434" = "1" + "2" + "3" + "434... | 1,750 | [] | 1,463,870,375 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 8,806,400 | from collections import OrderedDict
from collections import deque
import time
import random
import sys
import re
def sizeof(t):
return sys.getsizeof(t)
def pr(x):
print(x)
def ti():
return time.time()
#Function profiler. Sorting options: 0-by call number, 1-by function inner time, 2-by ... | Title: New Year and Ancient Prophecy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. In the snow he found a scroll with the ancient prophecy. Limak doesn't know any ancient languages and thus is unable to understand the prophecy. But he knows digits!
One frag... | ```python
from collections import OrderedDict
from collections import deque
import time
import random
import sys
import re
def sizeof(t):
return sys.getsizeof(t)
def pr(x):
print(x)
def ti():
return time.time()
#Function profiler. Sorting options: 0-by call number, 1-by function inner t... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
293 | A | Weird Game | PROGRAMMING | 1,500 | [
"games",
"greedy"
] | null | null | Yaroslav, Andrey and Roman can play cubes for hours and hours. But the game is for three, so when Roman doesn't show up, Yaroslav and Andrey play another game.
Roman leaves a word for each of them. Each word consists of 2·*n* binary characters "0" or "1". After that the players start moving in turns. Yaroslav moves f... | The first line contains integer *n* (1<=≤<=*n*<=≤<=106). The second line contains string *s* — Yaroslav's word. The third line contains string *t* — Andrey's word.
It is guaranteed that both words consist of 2·*n* characters "0" and "1". | Print "First", if both players play optimally well and Yaroslav wins. If Andrey wins, print "Second" and if the game ends with a draw, print "Draw". Print the words without the quotes. | [
"2\n0111\n0001\n",
"3\n110110\n001001\n",
"3\n111000\n000111\n",
"4\n01010110\n00101101\n",
"4\n01100000\n10010011\n"
] | [
"First\n",
"First\n",
"Draw\n",
"First\n",
"Second\n"
] | none | 500 | [
{
"input": "2\n0111\n0001",
"output": "First"
},
{
"input": "3\n110110\n001001",
"output": "First"
},
{
"input": "3\n111000\n000111",
"output": "Draw"
},
{
"input": "4\n01010110\n00101101",
"output": "First"
},
{
"input": "4\n01100000\n10010011",
"output": "Se... | 1,695,115,212 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 51 | 654 | 64,204,800 | # https://codeforces.com/problemset/problem/293/A
n = int(input())
S = list(map(int, input()))
T = list(map(int, input()))
types = [0] * 4
for s, t in zip(S, T):
types[s * 2 + t] += 1
yaroslav = 0
andrey = 0
for turn in range(2 * n):
'''
1. Always optimal to take 3 (11) first so you benefit and make the... | Title: Weird Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav, Andrey and Roman can play cubes for hours and hours. But the game is for three, so when Roman doesn't show up, Yaroslav and Andrey play another game.
Roman leaves a word for each of them. Each word consists of 2·... | ```python
# https://codeforces.com/problemset/problem/293/A
n = int(input())
S = list(map(int, input()))
T = list(map(int, input()))
types = [0] * 4
for s, t in zip(S, T):
types[s * 2 + t] += 1
yaroslav = 0
andrey = 0
for turn in range(2 * n):
'''
1. Always optimal to take 3 (11) first so you benefit an... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
318 | B | Strings of Power | PROGRAMMING | 1,300 | [
"implementation",
"strings",
"two pointers"
] | null | null | Volodya likes listening to heavy metal and (occasionally) reading. No wonder Volodya is especially interested in texts concerning his favourite music style.
Volodya calls a string powerful if it starts with "heavy" and ends with "metal". Finding all powerful substrings (by substring Volodya means a subsequence of cons... | Input contains a single non-empty string consisting of the lowercase Latin alphabet letters. Length of this string will not be greater than 106 characters. | Print exactly one number — the number of powerful substrings of the given string.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"heavymetalisheavymetal\n",
"heavymetalismetal\n",
"trueheavymetalissotruewellitisalsosoheavythatyoucanalmostfeeltheweightofmetalonyou\n"
] | [
"3",
"2",
"3"
] | In the first sample the string "heavymetalisheavymetal" contains powerful substring "heavymetal" twice, also the whole string "heavymetalisheavymetal" is certainly powerful.
In the second sample the string "heavymetalismetal" contains two powerful substrings: "heavymetal" and "heavymetalismetal". | 500 | [
{
"input": "heavymetalisheavymetal",
"output": "3"
},
{
"input": "heavymetalismetal",
"output": "2"
},
{
"input": "trueheavymetalissotruewellitisalsosoheavythatyoucanalmostfeeltheweightofmetalonyou",
"output": "3"
},
{
"input": "fpgzbvhheavymheheavyzmheavyavyebknkhheavyhsbqmm... | 1,693,748,905 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 11,059,200 | from collections import deque
def ndxsFor(w, tgt):
cur, res = -1, []
while tgt in w[cur+1:]:
cur = w.index(tgt, cur+1)
res.append(cur)
return res
w = input()
hNdxs = ndxsFor(w, 'heavy')
mNdxs = ndxsFor(w, 'metal')
d = deque(mNdxs)
res = 0
for h in hNdxs:
while len(d) >... | Title: Strings of Power
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Volodya likes listening to heavy metal and (occasionally) reading. No wonder Volodya is especially interested in texts concerning his favourite music style.
Volodya calls a string powerful if it starts with "heavy" an... | ```python
from collections import deque
def ndxsFor(w, tgt):
cur, res = -1, []
while tgt in w[cur+1:]:
cur = w.index(tgt, cur+1)
res.append(cur)
return res
w = input()
hNdxs = ndxsFor(w, 'heavy')
mNdxs = ndxsFor(w, 'metal')
d = deque(mNdxs)
res = 0
for h in hNdxs:
whil... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
21 | C | Stripe 2 | PROGRAMMING | 2,000 | [
"binary search",
"dp",
"sortings"
] | C. Stripe 2 | 1 | 64 | Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into three pieces so that the sum of numbers from each piece is equal to the sum of numbers from any other piece,... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=105) — amount of squares in the stripe. The second line contains n space-separated numbers — they are the numbers written in the squares of the stripe. These numbers are integer and do not exceed 10000 in absolute value. | Output the amount of ways to cut the stripe into three non-empty pieces so that the sum of numbers from each piece is equal to the sum of numbers from any other piece. Don't forget that it's allowed to cut the stripe along the squares' borders only. | [
"4\n1 2 3 3\n",
"5\n1 2 3 4 5\n"
] | [
"1\n",
"0\n"
] | none | 1,500 | [
{
"input": "1\n-3",
"output": "0"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "3\n0 0 0",
"output": "1"
},
{
"input": "4\n-2 3 3 2",
"output": "0"
},
{
"input": "5\n-6 3 -1 2 -7",
"output": "0"
},
{
"input": "6\n2 3 -3 0 -3 1",
"output": "0... | 1,510,766,824 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 1,000 | 0 | # 21C
k = int(input())
X = []
sum0 = 0
for i in input().strip().split():
X.append(int(i))
for i in range(0, k):
sum0 = sum0 + X[i]
if ((sum0 % 3 != 0) or (k < 3)):
print(0)
quit()
i=0
b=1
sum1=0
while b< (k-1):
b1= b+ 1
sum2= 0
sum1+= X[b-1]
while b1< k:
... | Title: Stripe 2
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Once Bob took a paper stripe of n squares (the height of the stripe is 1 square). In each square he wrote an integer number, possibly negative. He became interested in how many ways exist to cut this stripe into three pieces so tha... | ```python
# 21C
k = int(input())
X = []
sum0 = 0
for i in input().strip().split():
X.append(int(i))
for i in range(0, k):
sum0 = sum0 + X[i]
if ((sum0 % 3 != 0) or (k < 3)):
print(0)
quit()
i=0
b=1
sum1=0
while b< (k-1):
b1= b+ 1
sum2= 0
sum1+= X[b-1]
while b1< k:... | 0 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,585,337,510 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 0 | if __name__ == '__main__':
s=input()
l=u=0
for i in s:
if(i.islower()):
l += 1
else:
u += 1
if(l<u):
print(s.upper())
else:
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
if __name__ == '__main__':
s=input()
l=u=0
for i in s:
if(i.islower()):
l += 1
else:
u += 1
if(l<u):
print(s.upper())
else:
print(s.lower())
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
748 | B | Santa Claus and Keyboard Check | PROGRAMMING | 1,500 | [
"implementation",
"strings"
] | null | null | Santa Claus decided to disassemble his keyboard to clean it. After he returned all the keys back, he suddenly realized that some pairs of keys took each other's place! That is, Santa suspects that each key is either on its place, or on the place of another key, which is located exactly where the first key should be.
... | The input consists of only two strings *s* and *t* denoting the favorite Santa's patter and the resulting string. *s* and *t* are not empty and have the same length, which is at most 1000. Both strings consist only of lowercase English letters. | If Santa is wrong, and there is no way to divide some of keys into pairs and swap keys in each pair so that the keyboard will be fixed, print «-1» (without quotes).
Otherwise, the first line of output should contain the only integer *k* (*k*<=≥<=0) — the number of pairs of keys that should be swapped. The following *k... | [
"helloworld\nehoolwlroz\n",
"hastalavistababy\nhastalavistababy\n",
"merrychristmas\nchristmasmerry\n"
] | [
"3\nh e\nl o\nd z\n",
"0\n",
"-1\n"
] | none | 1,000 | [
{
"input": "helloworld\nehoolwlroz",
"output": "3\nh e\nl o\nd z"
},
{
"input": "hastalavistababy\nhastalavistababy",
"output": "0"
},
{
"input": "merrychristmas\nchristmasmerry",
"output": "-1"
},
{
"input": "kusyvdgccw\nkusyvdgccw",
"output": "0"
},
{
"input": "... | 1,482,659,359 | 2,659 | Python 3 | CHALLENGED | CHALLENGES | 8 | 62 | 4,608,000 | s = input()
t = input()
let = {}
f = True
ans = 0
if s == t:
print(0)
else:
for i in range(len(s)):
if s[i] in let:
if t[i] != let[s[i]]:
print(-1)
f = False
break
elif t[i] in let:
if s[i] != let[t[i]]:
... | Title: Santa Claus and Keyboard Check
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus decided to disassemble his keyboard to clean it. After he returned all the keys back, he suddenly realized that some pairs of keys took each other's place! That is, Santa suspects that each ke... | ```python
s = input()
t = input()
let = {}
f = True
ans = 0
if s == t:
print(0)
else:
for i in range(len(s)):
if s[i] in let:
if t[i] != let[s[i]]:
print(-1)
f = False
break
elif t[i] in let:
if s[i] != let[t[... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,641,025,119 | 4,719 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 93 | 102,400 | import sys
from collections import defaultdict,deque
nodes_size, edges_size = map(int,sys.stdin.readline().split())
graph = {i: defaultdict(lambda: float('inf'))
for i in range(1,nodes_size+1)
}
for _ in range(edges_size):
e1,e2,w = map(int, sys.stdin.readline().split())
graph[e1][e2] = min(graph[e1][e2]... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
import sys
from collections import defaultdict,deque
nodes_size, edges_size = map(int,sys.stdin.readline().split())
graph = {i: defaultdict(lambda: float('inf'))
for i in range(1,nodes_size+1)
}
for _ in range(edges_size):
e1,e2,w = map(int, sys.stdin.readline().split())
graph[e1][e2] = min(gra... | 0 | MatrixStudio/Codeforces-Python-Submissions |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,610,353,348 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 307,200 | meat = []
price = []
total = 0
for day in range(int(input())):
m, p = map(int, input().split()[:2])
meat.append(m)
price.append(p)
start = 0
cheap = min(price)
for i,j in zip(meat, price):
if j == cheap:
break
else:
total += i * j
start += 1
total += cheap * su... | Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
meat = []
price = []
total = 0
for day in range(int(input())):
m, p = map(int, input().split()[:2])
meat.append(m)
price.append(p)
start = 0
cheap = min(price)
for i,j in zip(meat, price):
if j == cheap:
break
else:
total += i * j
start += 1
total += ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
97 | E | Leaders | PROGRAMMING | 2,200 | [
"dfs and similar",
"dsu",
"graphs",
"trees"
] | E. Leaders | 2 | 256 | After a revolution in Berland the new dictator faced an unexpected challenge: the country has to be somehow ruled. The dictator is a very efficient manager, yet he can't personally give orders to each and every citizen. That's why he decided to pick some set of leaders he would control. Those leaders will directly orde... | The first line contains integers *n* and *m* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105) — the number of vertices and edges in the relationship graph correspondingly. Next *m* lines contain pairs of integers *a* and *b* which mean that there is an edge between the *a*-th and the *b*-th vertices (the vertices are numbered s... | For each query print on a single line "Yes" if there's a simple odd path between the pair of people; otherwise, print "No". | [
"7 7\n1 3\n1 4\n2 3\n2 4\n5 6\n6 7\n7 5\n8\n1 2\n1 3\n1 4\n2 4\n1 5\n5 6\n5 7\n6 7\n"
] | [
"No\nYes\nYes\nYes\nNo\nYes\nYes\nYes\n"
] | Notes to the samples:
1) Between vertices 1 and 2 there are 2 different simple paths in total: 1-3-2 and 1-4-2. Both of them consist of an even number of edges.
2) Vertices 1 and 3 are connected by an edge, that's why a simple odd path for them is 1-3.
5) Vertices 1 and 5 are located in different connected componen... | 2,500 | [] | 1,692,374,888 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1692374888.078645")# 1692374888.0786622 | Title: Leaders
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
After a revolution in Berland the new dictator faced an unexpected challenge: the country has to be somehow ruled. The dictator is a very efficient manager, yet he can't personally give orders to each and every citizen. That's why ... | ```python
print("_RANDOM_GUESS_1692374888.078645")# 1692374888.0786622
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,655,828,973 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 46 | 0 | l,r,k=map(int,input().split())
arr=[]
p=0
x=k
k=1
while k<=r:
if k>=l:
arr.append(k)
p+=1
k*=x
if len(arr)==0:
print(-1)
else:
for ele in arr:
print(ele,end=" ")
print() | Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
l,r,k=map(int,input().split())
arr=[]
p=0
x=k
k=1
while k<=r:
if k>=l:
arr.append(k)
p+=1
k*=x
if len(arr)==0:
print(-1)
else:
for ele in arr:
print(ele,end=" ")
print()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,692,739,984 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 62 | 0 | word = input()
if len(word) == 1 and word.lower() == word:
word = word.upper()
elif word.upper() == word:
word = word.lower()
elif word[0].lower()+word[1:].upper() == word:
word = word[0].upper() + word[1:].lower()
print(word)
| Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
word = input()
if len(word) == 1 and word.lower() == word:
word = word.upper()
elif word.upper() == word:
word = word.lower()
elif word[0].lower()+word[1:].upper() == word:
word = word[0].upper() + word[1:].lower()
print(word)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,661,444,548 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 62 | 0 | n , k = map(int,input().split())
print(n + (k-n%k)) | Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *... | ```python
n , k = map(int,input().split())
print(n + (k-n%k))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
10 | B | Cinema Cashier | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | B. Cinema Cashier | 1 | 256 | All cinema halls in Berland are rectangles with *K* rows of *K* seats each, and *K* is an odd number. Rows and seats are numbered from 1 to *K*. For safety reasons people, who come to the box office to buy tickets, are not allowed to choose seats themselves. Formerly the choice was made by a cashier, but now this is th... | The first line contains two integers *N* and *K* (1<=≤<=*N*<=≤<=1000,<=1<=≤<=*K*<=≤<=99) — the amount of requests and the hall size respectively. The second line contains *N* space-separated integers *M**i* from the range [1,<=*K*] — requests to the program. | Output *N* lines. In the *i*-th line output «-1» (without quotes), if it is impossible to find *M**i* successive seats in one row, otherwise output three numbers *x*,<=*y**l*,<=*y**r*. Separate the numbers with a space. | [
"2 1\n1 1\n",
"4 3\n1 2 3 1\n"
] | [
"1 1 1\n-1\n",
"2 2 2\n1 1 2\n3 1 3\n2 1 1\n"
] | none | 0 | [
{
"input": "2 1\n1 1",
"output": "1 1 1\n-1"
},
{
"input": "4 3\n1 2 3 1",
"output": "2 2 2\n1 1 2\n3 1 3\n2 1 1"
},
{
"input": "1 3\n1",
"output": "2 2 2"
},
{
"input": "2 3\n3 3",
"output": "2 1 3\n1 1 3"
},
{
"input": "3 3\n3 2 3",
"output": "2 1 3\n1 1 2\n... | 1,682,701,920 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n, k = map(int, raw_input().split())
M = map(int, raw_input().split())
xc = yc = k / 2
taken = [[False for i in xrange(k)] for i in xrange(k)]
v = [[0 for i in xrange(k + 1)] for i in xrange(k)]
for x in xrange(k):
for y in xrange(k):
v[x][y + 1] = abs(x - xc) + abs(y - yc)
#v is prefix sum of cos... | Title: Cinema Cashier
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
All cinema halls in Berland are rectangles with *K* rows of *K* seats each, and *K* is an odd number. Rows and seats are numbered from 1 to *K*. For safety reasons people, who come to the box office to buy tickets, are not a... | ```python
n, k = map(int, raw_input().split())
M = map(int, raw_input().split())
xc = yc = k / 2
taken = [[False for i in xrange(k)] for i in xrange(k)]
v = [[0 for i in xrange(k + 1)] for i in xrange(k)]
for x in xrange(k):
for y in xrange(k):
v[x][y + 1] = abs(x - xc) + abs(y - yc)
#v is prefix ... | -1 | MatrixStudio/Codeforces-Python-Submissions |
779 | B | Weird Rounding | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For example, if *k*<==<=3, in the number 30020 it is enough to delete a single digit (2). In this case, t... | The only line of the input contains two integer numbers *n* and *k* (0<=≤<=*n*<=≤<=2<=000<=000<=000, 1<=≤<=*k*<=≤<=9).
It is guaranteed that the answer exists. All numbers in the input are written in traditional notation of integers, that is, without any extra leading zeros. | Print *w* — the required minimal number of digits to erase. After removing the appropriate *w* digits from the number *n*, the result should have a value that is divisible by 10*k*. The result can start with digit 0 in the single case (the result is zero and written by exactly the only digit 0). | [
"30020 3\n",
"100 9\n",
"10203049 2\n"
] | [
"1\n",
"2\n",
"3\n"
] | In the example 2 you can remove two digits: 1 and any 0. The result is number 0 which is divisible by any number. | 1,000 | [
{
"input": "30020 3",
"output": "1"
},
{
"input": "100 9",
"output": "2"
},
{
"input": "10203049 2",
"output": "3"
},
{
"input": "0 1",
"output": "0"
},
{
"input": "0 9",
"output": "0"
},
{
"input": "100 2",
"output": "0"
},
{
"input": "102... | 1,628,925,017 | 2,147,483,647 | PyPy 3 | OK | TESTS | 161 | 124 | 20,172,800 | n,k=map(int,input().split())
l=list(str(n))
q=0
if(n%10**k==0):
print(0)
else:
i=len(l)-1
c=0
while(i>0):
s=''
if(l[i]!='0'):
l.pop(i)
c+=1
if(int(s.join(l))%(10**k)==0):
q=1
break
... | Title: Weird Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For e... | ```python
n,k=map(int,input().split())
l=list(str(n))
q=0
if(n%10**k==0):
print(0)
else:
i=len(l)-1
c=0
while(i>0):
s=''
if(l[i]!='0'):
l.pop(i)
c+=1
if(int(s.join(l))%(10**k)==0):
q=1
break
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
535 | A | Tavas and Nafas | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.
He ate coffee mix without... | The first and only line of input contains an integer *s* (0<=≤<=*s*<=≤<=99), Tavas's score. | In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces. | [
"6\n",
"99\n",
"20\n"
] | [
"six\n",
"ninety-nine\n",
"twenty\n"
] | You can find all you need to know about English numerals in [http://en.wikipedia.org/wiki/English_numerals](https://en.wikipedia.org/wiki/English_numerals) . | 500 | [
{
"input": "6",
"output": "six"
},
{
"input": "99",
"output": "ninety-nine"
},
{
"input": "20",
"output": "twenty"
},
{
"input": "10",
"output": "ten"
},
{
"input": "15",
"output": "fifteen"
},
{
"input": "27",
"output": "twenty-seven"
},
{
... | 1,590,003,688 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 108 | 307,200 | k = ['one','two','three','four','five','six','seven','eigth','nine']
p=['one','two','three','four','five','six','seven','eigth','nine','ten','eleven','twelve','thirteen','fourteen','fifteen','sixteen','seventeen','eighteen','nineteen']
r = ['twenty','thirty','forty','fifty','sixty','seventy','eighty','ninety']
for s i... | Title: Tavas and Nafas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score wit... | ```python
k = ['one','two','three','four','five','six','seven','eigth','nine']
p=['one','two','three','four','five','six','seven','eigth','nine','ten','eleven','twelve','thirteen','fourteen','fifteen','sixteen','seventeen','eighteen','nineteen']
r = ['twenty','thirty','forty','fifty','sixty','seventy','eighty','ninety'... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
701 | B | Cells Not Under Attack | PROGRAMMING | 1,200 | [
"data structures",
"math"
] | null | null | Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=*min*(100<=000,<=*n*2)) — the size of the board and the number of rooks.
Each of the next *m* lines contains integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the number of the row and the number of the col... | Print *m* integer, the *i*-th of them should be equal to the number of cells that are not under attack after first *i* rooks are put. | [
"3 3\n1 1\n3 1\n2 2\n",
"5 2\n1 5\n5 1\n",
"100000 1\n300 400\n"
] | [
"4 2 0 \n",
"16 9 \n",
"9999800001 \n"
] | On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | 750 | [
{
"input": "3 3\n1 1\n3 1\n2 2",
"output": "4 2 0 "
},
{
"input": "5 2\n1 5\n5 1",
"output": "16 9 "
},
{
"input": "100000 1\n300 400",
"output": "9999800001 "
},
{
"input": "10 4\n2 8\n1 8\n9 8\n6 9",
"output": "81 72 63 48 "
},
{
"input": "30 30\n3 13\n27 23\n18... | 1,661,206,555 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 2 | 498 | 268,390,400 | n, m = input().split()
n = int(n)
m = int(m)
array = [[1]*n for i in range(n)]
l = []
for i in range(m):
a, b = [int(i) for i in input().split()]
array[a-1] = [0] * n
for j in range(n):
array[j][b-1] = 0
c = 0
for j in range(n):
for k in range(n):
if arra... | Title: Cells Not Under Attack
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's a... | ```python
n, m = input().split()
n = int(n)
m = int(m)
array = [[1]*n for i in range(n)]
l = []
for i in range(m):
a, b = [int(i) for i in input().split()]
array[a-1] = [0] * n
for j in range(n):
array[j][b-1] = 0
c = 0
for j in range(n):
for k in range(n):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
451 | A | Game With Sticks | PROGRAMMING | 900 | [
"implementation"
] | null | null | After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid show... | The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). | Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. | [
"2 2\n",
"2 3\n",
"3 3\n"
] | [
"Malvika\n",
"Malvika\n",
"Akshat\n"
] | Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remov... | 500 | [
{
"input": "2 2",
"output": "Malvika"
},
{
"input": "2 3",
"output": "Malvika"
},
{
"input": "3 3",
"output": "Akshat"
},
{
"input": "20 68",
"output": "Malvika"
},
{
"input": "1 1",
"output": "Akshat"
},
{
"input": "1 2",
"output": "Akshat"
},
... | 1,693,929,105 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 46 | 0 | line = [int(n) for n in input().split()]
intercion = line[0]*line[1]
if intercion !=2:
if intercion %2 ==0:
print("Malvika")
else:
print("Akshat")
else:
print("Akshat") | Title: Game With Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid... | ```python
line = [int(n) for n in input().split()]
intercion = line[0]*line[1]
if intercion !=2:
if intercion %2 ==0:
print("Malvika")
else:
print("Akshat")
else:
print("Akshat")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
404 | A | Valera and X | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the... | The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper. | Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes. | [
"5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n",
"3\nwsw\nsws\nwsw\n",
"3\nxpx\npxp\nxpe\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox",
"output": "NO"
},
{
"input": "3\nwsw\nsws\nwsw",
"output": "YES"
},
{
"input": "3\nxpx\npxp\nxpe",
"output": "NO"
},
{
"input": "5\nliiil\nilili\niilii\nilili\nliiil",
"output": "YES"
},
{
"input": "7\nbwccccb\nck... | 1,676,557,437 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | a=[]
n=int(input())
ans='YES'
for _ in range(n): a.append(input())
i=h=0
j=n-1
d={}
while j:
if a[h][i]!=a[h][j]:
ans='NO'
break
if i<=n//2:
for x in a[h][:i]: d[x]=1
for x in a[h][j+1:]: d[x]=1
else:
for x in a[h][i+1:]: d[x]=1
for x in a[h][:... | Title: Valera and X
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a... | ```python
a=[]
n=int(input())
ans='YES'
for _ in range(n): a.append(input())
i=h=0
j=n-1
d={}
while j:
if a[h][i]!=a[h][j]:
ans='NO'
break
if i<=n//2:
for x in a[h][:i]: d[x]=1
for x in a[h][j+1:]: d[x]=1
else:
for x in a[h][i+1:]: d[x]=1
for x... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,695,912,546 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | n = int(input())
a = list(i for i in input().split())
burles = 0
for i in range(n):
a[i]=int(a[i])
maximum = max(a)
for i in a:
burles = burles + (maximum-i)
print(burles)
| Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n = int(input())
a = list(i for i in input().split())
burles = 0
for i in range(n):
a[i]=int(a[i])
maximum = max(a)
for i in a:
burles = burles + (maximum-i)
print(burles)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,664,967,969 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | def main() -> None:
# with open("test.txt") as test_file:
# _, numbers = test_file.readline(), list(map(int, test_file.readline().split()))
_ = input()
numbers = list(map(int, input().split()))
# last_number = None
# for i, num in enumerate(numbers):
# endianness = num & 1
# ... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
def main() -> None:
# with open("test.txt") as test_file:
# _, numbers = test_file.readline(), list(map(int, test_file.readline().split()))
_ = input()
numbers = list(map(int, input().split()))
# last_number = None
# for i, num in enumerate(numbers):
# endianness = num & 1
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of int... | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,663,517,477 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 124 | 0 | m,n=map(int,input().split())
a=0
c=0
while a*a<=m and a<=n:
b=m-a*a
if a+(b*b)==n:
c+=1
a+=1
print(c) | Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immedi... | ```python
m,n=map(int,input().split())
a=0
c=0
while a*a<=m and a<=n:
b=m-a*a
if a+(b*b)==n:
c+=1
a+=1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,622,308,772 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | l,r,a=map(int,input().split())
if l==0 or r==0:
print(0)
else:
if l==r:
print(2*l+(a//2 * 2))
else:
if l>r:
l,r=r,l
print(l+(r-l)+(a//2 *2)) | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
l,r,a=map(int,input().split())
if l==0 or r==0:
print(0)
else:
if l==r:
print(2*l+(a//2 * 2))
else:
if l>r:
l,r=r,l
print(l+(r-l)+(a//2 *2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,525,103,942 | 4,742 | Python 3 | OK | TESTS | 14 | 93 | 7,065,600 | n = int(input())
s = input() # The binary string
o = 0
z = 0
for c in s:
if(c=="0"):z+=1
else:o+=1
if(s=="0"):print("0")
elif(s=="1"):print("1")
else:print("1" + "0"*z) | Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
n = int(input())
s = input() # The binary string
o = 0
z = 0
for c in s:
if(c=="0"):z+=1
else:o+=1
if(s=="0"):print("0")
elif(s=="1"):print("1")
else:print("1" + "0"*z)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
185 | A | Plant | PROGRAMMING | 1,300 | [
"math"
] | null | null | Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will point "upwards" and one will point "downwards". After another year, each triangle plant divide... | The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1018) — the number of full years when the plant grew.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | Print a single integer — the remainder of dividing the number of plants that will point "upwards" in *n* years by 1000000007 (109<=+<=7). | [
"1\n",
"2\n"
] | [
"3\n",
"10\n"
] | The first test sample corresponds to the second triangle on the figure in the statement. The second test sample corresponds to the third one. | 500 | [
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "10"
},
{
"input": "385599124",
"output": "493875375"
},
{
"input": "989464295",
"output": "31966163"
},
{
"input": "376367012",
"output": "523204186"
},
{
"input": "529357306",
"output": "... | 1,560,496,598 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | n = int(input())
if n != 0:
print( n*(2*n + 1) % 1000000007 )
elif n == 0:
print(1)
| Title: Plant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will poi... | ```python
n = int(input())
if n != 0:
print( n*(2*n + 1) % 1000000007 )
elif n == 0:
print(1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,691,218,122 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s=list(input())
ans=0
pred='a'
for i in range(len(s)):
c=abs(ord(s[i])-ord(pred))
a=26-c
ans+=min(a,c)
pred=s[i]
print(ans | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
s=list(input())
ans=0
pred='a'
for i in range(len(s)):
c=abs(ord(s[i])-ord(pred))
a=26-c
ans+=min(a,c)
pred=s[i]
print(ans
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,686,967,412 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | n = int(input())
m = [int(x) for x in input().split()]
for i in range(n):
m[i]%=2
y = m.count(1)
z = m.count(0)
if (y>z):
for i in range(n):
if (m[i]==0):
print(i+1)
break
else :
for i in range(n):
if (m[i]==1):
print(i+1)
break
... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
m = [int(x) for x in input().split()]
for i in range(n):
m[i]%=2
y = m.count(1)
z = m.count(0)
if (y>z):
for i in range(n):
if (m[i]==0):
print(i+1)
break
else :
for i in range(n):
if (m[i]==1):
print(i+1)
break
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
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