contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
192 | A | Funky Numbers | PROGRAMMING | 1,300 | [
"binary search",
"brute force",
"implementation"
] | null | null | As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.
A well-known hipster Andrew adores everything funky and c... | The first input line contains an integer *n* (1<=≤<=*n*<=≤<=109). | Print "YES" (without the quotes), if *n* can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes). | [
"256\n",
"512\n"
] | [
"YES\n",
"NO\n"
] | In the first sample number <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/92095692c6ea93e9e3b837a0408ba7543549d5b2.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample number 512 can not be represented as a sum of two triangular numbers. | 500 | [
{
"input": "256",
"output": "YES"
},
{
"input": "512",
"output": "NO"
},
{
"input": "80",
"output": "NO"
},
{
"input": "828",
"output": "YES"
},
{
"input": "6035",
"output": "NO"
},
{
"input": "39210",
"output": "YES"
},
{
"input": "79712",... | 1,591,437,091 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 0 | n=int(input( ))
c=[]
for i in range(n):
for j in range(n):
if (i*i+j*j+i+j)/2 ==n:
c.append(1)
if 1 in c:
print("YES")
else:
print("NO") | Title: Funky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are represent... | ```python
n=int(input( ))
c=[]
for i in range(n):
for j in range(n):
if (i*i+j*j+i+j)/2 ==n:
c.append(1)
if 1 in c:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
849 | A | Odds and Ends | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numb... | The first line of input contains a non-negative integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence.
The second line contains *n* space-separated non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100) — the elements of the sequence. | Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower). | [
"3\n1 3 5\n",
"5\n1 0 1 5 1\n",
"3\n4 3 1\n",
"4\n3 9 9 3\n"
] | [
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In ... | 500 | [
{
"input": "3\n1 3 5",
"output": "Yes"
},
{
"input": "5\n1 0 1 5 1",
"output": "Yes"
},
{
"input": "3\n4 3 1",
"output": "No"
},
{
"input": "4\n3 9 9 3",
"output": "No"
},
{
"input": "1\n1",
"output": "Yes"
},
{
"input": "5\n100 99 100 99 99",
"out... | 1,584,380,915 | 2,147,483,647 | PyPy 3 | OK | TESTS | 74 | 140 | 0 | n=int(input())
l=list(map(int,input().split()))
if(n%2==0):
print("NO")
else:
if(l[0]%2==1 and l[-1]%2==1):
print("YES")
else:
print("NO")
| Title: Odds and Ends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd num... | ```python
n=int(input())
l=list(map(int,input().split()))
if(n%2==0):
print("NO")
else:
if(l[0]%2==1 and l[-1]%2==1):
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
982 | C | Cut 'em all! | PROGRAMMING | 1,500 | [
"dfs and similar",
"dp",
"graphs",
"greedy",
"trees"
] | null | null | You're given a tree with $n$ vertices.
Your task is to determine the maximum possible number of edges that can be removed in such a way that all the remaining connected components will have even size. | The first line contains an integer $n$ ($1 \le n \le 10^5$) denoting the size of the tree.
The next $n - 1$ lines contain two integers $u$, $v$ ($1 \le u, v \le n$) each, describing the vertices connected by the $i$-th edge.
It's guaranteed that the given edges form a tree. | Output a single integer $k$ — the maximum number of edges that can be removed to leave all connected components with even size, or $-1$ if it is impossible to remove edges in order to satisfy this property. | [
"4\n2 4\n4 1\n3 1\n",
"3\n1 2\n1 3\n",
"10\n7 1\n8 4\n8 10\n4 7\n6 5\n9 3\n3 5\n2 10\n2 5\n",
"2\n1 2\n"
] | [
"1",
"-1",
"4",
"0"
] | In the first example you can remove the edge between vertices $1$ and $4$. The graph after that will have two connected components with two vertices in each.
In the second example you can't remove edges in such a way that all components have even number of vertices, so the answer is $-1$. | 1,500 | [
{
"input": "4\n2 4\n4 1\n3 1",
"output": "1"
},
{
"input": "3\n1 2\n1 3",
"output": "-1"
},
{
"input": "10\n7 1\n8 4\n8 10\n4 7\n6 5\n9 3\n3 5\n2 10\n2 5",
"output": "4"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "1",
"output": "-1"
},
{
"inpu... | 1,603,575,038 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 409,600 | from sys import stdin, exit, setrecursionlimit
setrecursionlimit(10000000)
from math import *
from bisect import bisect_left
from collections import deque
input = stdin.readline
lmi = lambda: list(map(int, input().split()))
mi = lambda: map(int, input().split())
si = lambda: input().strip('\n')
ssi = lambd... | Title: Cut 'em all!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You're given a tree with $n$ vertices.
Your task is to determine the maximum possible number of edges that can be removed in such a way that all the remaining connected components will have even size.
Input Specification... | ```python
from sys import stdin, exit, setrecursionlimit
setrecursionlimit(10000000)
from math import *
from bisect import bisect_left
from collections import deque
input = stdin.readline
lmi = lambda: list(map(int, input().split()))
mi = lambda: map(int, input().split())
si = lambda: input().strip('\n')
s... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
735 | C | Tennis Championship | PROGRAMMING | 1,600 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are st... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=1018) — the number of players to participate in the tournament. | Print the maximum number of games in which the winner of the tournament can take part. | [
"2\n",
"3\n",
"4\n",
"10\n"
] | [
"1\n",
"2\n",
"2\n",
"4\n"
] | In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't p... | 1,750 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "1000",
"output": "14"
},
{
"input": "2500",
"output": "15"
},
{
"input": "690000",
"output"... | 1,588,084,650 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 93 | 307,200 | def matches(t):
total=[1,2]
i=1
num=2
while(num<t):
total.append(total[num-2]+total[num-1]+1)
num+=1
if(t==1):
return 1
elif(t==2):
return 2
elif(t==3):
return 4
else:
return (total[len(total)-1])
n=int(input())
if(n==2):
... | Title: Tennis Championship
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very firs... | ```python
def matches(t):
total=[1,2]
i=1
num=2
while(num<t):
total.append(total[num-2]+total[num-1]+1)
num+=1
if(t==1):
return 1
elif(t==2):
return 2
elif(t==3):
return 4
else:
return (total[len(total)-1])
n=int(input())
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
939 | B | Hamster Farm | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Dima has a hamsters farm. Soon *N* hamsters will grow up on it and Dima will sell them in a city nearby.
Hamsters should be transported in boxes. If some box is not completely full, the hamsters in it are bored, that's why each box should be completely full with hamsters.
Dima can buy boxes at a factory. The factory ... | The first line contains two integers *N* and *K* (0<=≤<=*N*<=≤<=1018, 1<=≤<=*K*<=≤<=105) — the number of hamsters that will grow up on Dima's farm and the number of types of boxes that the factory produces.
The second line contains *K* integers *a*1, *a*2, ..., *a**K* (1<=≤<=*a**i*<=≤<=1018 for all *i*) — the capaciti... | Output two integers: the type of boxes that Dima should buy and the number of boxes of that type Dima should buy. Types of boxes are numbered from 1 to *K* in the order they are given in input.
If there are many correct answers, output any of them. | [
"19 3\n5 4 10\n",
"28 3\n5 6 30\n"
] | [
"2 4\n",
"1 5\n"
] | none | 1,000 | [
{
"input": "19 3\n5 4 10",
"output": "2 4"
},
{
"input": "28 3\n5 6 30",
"output": "1 5"
},
{
"input": "1 1\n1",
"output": "1 1"
},
{
"input": "0 2\n2 3",
"output": "1 0"
},
{
"input": "30 4\n4 5 5 4",
"output": "2 6"
},
{
"input": "120 7\n109 92 38 38... | 1,662,626,658 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 109 | 9,523,200 | homa, k = map(int, input().split())
type_k = tuple(map(int, input().split()))
if min(type_k) > homa or not homa:
print (1, 0)
elif homa in type_k:
print (type_k.index(homa) + 1, 1)
elif 1 in type_k:
print (type_k.index(1) + 1, homa)
else:
slv = dict()
max_2 = min(type_k)
for_ind = t... | Title: Hamster Farm
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima has a hamsters farm. Soon *N* hamsters will grow up on it and Dima will sell them in a city nearby.
Hamsters should be transported in boxes. If some box is not completely full, the hamsters in it are bored, that's wh... | ```python
homa, k = map(int, input().split())
type_k = tuple(map(int, input().split()))
if min(type_k) > homa or not homa:
print (1, 0)
elif homa in type_k:
print (type_k.index(homa) + 1, 1)
elif 1 in type_k:
print (type_k.index(1) + 1, homa)
else:
slv = dict()
max_2 = min(type_k)
f... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope wi... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,686,010,095 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | import sys
input = sys.stdin.readline
f=int(input())
def q(f):
if f%4==1:
if f<21:
return '-1'
elif f%4==2:
if f<14:
return '-1'
elif f%4==3:
if f<7:
return '-1'
if f%4==0:
g=f//4
return "4"*g
... | Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
import sys
input = sys.stdin.readline
f=int(input())
def q(f):
if f%4==1:
if f<21:
return '-1'
elif f%4==2:
if f<14:
return '-1'
elif f%4==3:
if f<7:
return '-1'
if f%4==0:
g=f//4
ret... | 0 | MatrixStudio/Codeforces-Python-Submissions |
369 | C | Valera and Elections | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | The city Valera lives in is going to hold elections to the city Parliament.
The city has *n* districts and *n*<=-<=1 bidirectional roads. We know that from any district there is a path along the roads to any other district. Let's enumerate all districts in some way by integers from 1 to *n*, inclusive. Furthermore, fo... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of districts in the city.
Then *n*<=-<=1 lines follow. Each line contains the description of a city road as three positive integers *x**i*, *y**i*, *t**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*, 1<=≤<=*t**i*<=≤<=2) — the districts connected by the *... | In the first line print a single non-negative number *k* — the minimum size of the required subset of candidates. Then on the second line print *k* space-separated integers *a*1,<=*a*2,<=... *a**k* — the numbers of the candidates that form the required subset. If there are multiple solutions, you are allowed to print a... | [
"5\n1 2 2\n2 3 2\n3 4 2\n4 5 2\n",
"5\n1 2 1\n2 3 2\n2 4 1\n4 5 1\n",
"5\n1 2 2\n1 3 2\n1 4 2\n1 5 2\n"
] | [
"1\n5 \n",
"1\n3 \n",
"4\n5 4 3 2 \n"
] | none | 1,500 | [
{
"input": "5\n1 2 2\n2 3 2\n3 4 2\n4 5 2",
"output": "1\n5 "
},
{
"input": "5\n1 2 1\n2 3 2\n2 4 1\n4 5 1",
"output": "1\n3 "
},
{
"input": "5\n1 2 2\n1 3 2\n1 4 2\n1 5 2",
"output": "4\n5 4 3 2 "
},
{
"input": "5\n1 5 1\n5 4 2\n4 3 1\n3 2 2",
"output": "1\n2 "
},
{
... | 1,650,047,501 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 158,208,000 | import threading
import sys
from sys import stdin
input=stdin.readline
sys.setrecursionlimit(10**8)
from collections import defaultdict
def main():
n=int(input())
graph=[[] for _ in range(n)]
for _ in range(n-1):
a,b,p=map(int,input().split())
a-=1
b-=1
graph[a... | Title: Valera and Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The city Valera lives in is going to hold elections to the city Parliament.
The city has *n* districts and *n*<=-<=1 bidirectional roads. We know that from any district there is a path along the roads to any other... | ```python
import threading
import sys
from sys import stdin
input=stdin.readline
sys.setrecursionlimit(10**8)
from collections import defaultdict
def main():
n=int(input())
graph=[[] for _ in range(n)]
for _ in range(n-1):
a,b,p=map(int,input().split())
a-=1
b-=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,687,786,360 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | x = int(input())
bacteria = 1
days = 0
while bacteria < x:
bacteria *= 2
days += 1
print(days)
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
x = int(input())
bacteria = 1
days = 0
while bacteria < x:
bacteria *= 2
days += 1
print(days)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,520,062,364 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 5,529,600 | # -*- coding: utf-8 -*-
"""
Created on Fri Mar 2 22:09:34 2018
@author: Xiaohua
"""
def WordCorrection(word):
vowel="aeuioAEUIO"
newword=""
i=0
while(i<len(word)):
newword+=word[i]
if (word[i] in vowel):
j=i+1
while ((j < len(word)) and(word[j]... | Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
# -*- coding: utf-8 -*-
"""
Created on Fri Mar 2 22:09:34 2018
@author: Xiaohua
"""
def WordCorrection(word):
vowel="aeuioAEUIO"
newword=""
i=0
while(i<len(word)):
newword+=word[i]
if (word[i] in vowel):
j=i+1
while ((j < len(word)) a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,604,334,267 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 186 | 0 | string1 =input()
string2=input()
index=0
while(len(string2)!=0):
if(string2[0]==string1[index]):
index+=1
count=index+1
string2=string2[1:len(string2)]
print(count) | Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
string1 =input()
string2=input()
index=0
while(len(string2)!=0):
if(string2[0]==string1[index]):
index+=1
count=index+1
string2=string2[1:len(string2)]
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,643,798,743 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 139 | 4,608,000 | import sys
input = sys.stdin.readline
N, M = map(int, input().split())
DIC_L1, DIC_L2 = {}, {}
for _ in range(M) :
WORD_L1, WORD_L2 = input().rstrip().split()
DIC_L1[WORD_L1] = WORD_L2
DIC_L2[WORD_L2] = WORD_L1
LETURE_WORDS = input().rstrip().split()
noteWords = []
for letureWord in LETURE_WORDS :
if letureWo... | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
import sys
input = sys.stdin.readline
N, M = map(int, input().split())
DIC_L1, DIC_L2 = {}, {}
for _ in range(M) :
WORD_L1, WORD_L2 = input().rstrip().split()
DIC_L1[WORD_L1] = WORD_L2
DIC_L2[WORD_L2] = WORD_L1
LETURE_WORDS = input().rstrip().split()
noteWords = []
for letureWord in LETURE_WORDS :
i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
957 | A | Tritonic Iridescence | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one-dimensional canvas split into *n* consecutive segments, each segment needs to be painted in one of the co... | The first line contains a single positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the canvas.
The second line contains a string *s* of *n* characters, the *i*-th of which is either 'C' (denoting a segment painted in cyan), 'M' (denoting one painted in magenta), 'Y' (one painted in yellow), or '?' (an unpainted... | If there are at least two different ways of painting, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5\nCY??Y\n",
"5\nC?C?Y\n",
"5\n?CYC?\n",
"5\nC??MM\n",
"3\nMMY\n"
] | [
"Yes\n",
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | For the first example, there are exactly two different ways of colouring: CYCMY and CYMCY.
For the second example, there are also exactly two different ways of colouring: CMCMY and CYCMY.
For the third example, there are four ways of colouring: MCYCM, MCYCY, YCYCM, and YCYCY.
For the fourth example, no matter how th... | 500 | [
{
"input": "5\nCY??Y",
"output": "Yes"
},
{
"input": "5\nC?C?Y",
"output": "Yes"
},
{
"input": "5\n?CYC?",
"output": "Yes"
},
{
"input": "5\nC??MM",
"output": "No"
},
{
"input": "3\nMMY",
"output": "No"
},
{
"input": "15\n??YYYYYY??YYYY?",
"output"... | 1,619,340,445 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | import math
#n,k = map(int, input().strip().split(' '))
n=int(input())
#lst = list(map(int, input().strip().split(' ')))
s=input()
if '?' not in s:
print('No')
else:
f=0
c=0
for j in range(n-1):
if s[j]==s[j+1] and s[j]!='?':
print('No')
f=1
brea... | Title: Tritonic Iridescence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one... | ```python
import math
#n,k = map(int, input().strip().split(' '))
n=int(input())
#lst = list(map(int, input().strip().split(' ')))
s=input()
if '?' not in s:
print('No')
else:
f=0
c=0
for j in range(n-1):
if s[j]==s[j+1] and s[j]!='?':
print('No')
f=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
520 | A | Pangram | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
You are given a string consisting of lowercase and uppercase Latin letters. Check whether thi... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of characters in the string.
The second line contains the string. The string consists only of uppercase and lowercase Latin letters. | Output "YES", if the string is a pangram and "NO" otherwise. | [
"12\ntoosmallword\n",
"35\nTheQuickBrownFoxJumpsOverTheLazyDog\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "12\ntoosmallword",
"output": "NO"
},
{
"input": "35\nTheQuickBrownFoxJumpsOverTheLazyDog",
"output": "YES"
},
{
"input": "1\na",
"output": "NO"
},
{
"input": "26\nqwertyuiopasdfghjklzxcvbnm",
"output": "YES"
},
{
"input": "26\nABCDEFGHIJKLMNOPQRSTUVWXY... | 1,699,892,629 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | t = int(input())
s = input()
s2 = s.lower()
s1 = set(s2)
if len(s1) == 26:
print("YES")
else:
print("NO")
| Title: Pangram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
... | ```python
t = int(input())
s = input()
s2 = s.lower()
s1 = set(s2)
if len(s1) == 26:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,698,361,712 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | x=0
line=str()
n = int(input())
for i in range(n):
line = input()
if int(line[0]) + int(line[2]) + int(line [4]) >= 2 :
x = x+1
print( x ) | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
x=0
line=str()
n = int(input())
for i in range(n):
line = input()
if int(line[0]) + int(line[2]) + int(line [4]) >= 2 :
x = x+1
print( x )
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
804 | B | Minimum number of steps | PROGRAMMING | 1,400 | [
"combinatorics",
"greedy",
"implementation",
"math"
] | null | null | We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substring, our job is done. Print the minimum number of steps we should perform to make our job done modulo 109<=+<... | The first line contains the initial string consisting of letters 'a' and 'b' only with length from 1 to 106. | Print the minimum number of steps modulo 109<=+<=7. | [
"ab\n",
"aab\n"
] | [
"1\n",
"3\n"
] | The first example: "ab" → "bba".
The second example: "aab" → "abba" → "bbaba" → "bbbbaa". | 1,000 | [
{
"input": "ab",
"output": "1"
},
{
"input": "aab",
"output": "3"
},
{
"input": "aaaaabaabababaaaaaba",
"output": "17307"
},
{
"input": "abaabaaabbabaabab",
"output": "1795"
},
{
"input": "abbaa",
"output": "2"
},
{
"input": "abbaaabaabaaaaabbbbaababaa... | 1,601,942,743 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 561 | 3,174,400 | modulo = 1000000007
b = 0
saida = 0
entrada = input()
tamanho = len(entrada)
for i in range(tamanho-1,-1,-1):
if(entrada[i] == 'b'):
b = (b+1) % modulo
else:
saida = (saida + b) % modulo
b = (b*2) % modulo
print (saida)
| Title: Minimum number of steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substr... | ```python
modulo = 1000000007
b = 0
saida = 0
entrada = input()
tamanho = len(entrada)
for i in range(tamanho-1,-1,-1):
if(entrada[i] == 'b'):
b = (b+1) % modulo
else:
saida = (saida + b) % modulo
b = (b*2) % modulo
print (saida)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
52 | A | 123-sequence | PROGRAMMING | 900 | [
"implementation"
] | A. 123-sequence | 2 | 256 | There is a given sequence of integers *a*1,<=*a*2,<=...,<=*a**n*, where every number is from 1 to 3 inclusively. You have to replace the minimum number of numbers in it so that all the numbers in the sequence are equal to each other. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106). The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3). | Print the minimum number of replacements needed to be performed to make all the numbers in the sequence equal. | [
"9\n1 3 2 2 2 1 1 2 3\n"
] | [
"5\n"
] | In the example all the numbers equal to 1 and 3 should be replaced by 2. | 500 | [
{
"input": "9\n1 3 2 2 2 1 1 2 3",
"output": "5"
},
{
"input": "6\n3 3 2 2 1 3",
"output": "3"
},
{
"input": "12\n3 1 3 1 2 1 3 2 2 1 2 1",
"output": "7"
},
{
"input": "15\n3 2 1 1 1 1 3 2 2 3 3 1 2 3 2",
"output": "10"
},
{
"input": "2\n2 1",
"output": "1"
... | 1,630,694,392 | 2,147,483,647 | PyPy 3 | OK | TESTS | 23 | 748 | 74,547,200 | n = int(input())
x = list(map(int, input().split()))
data = 3 * [0]
for item in x:
data[item - 1] += 1
print(min(data[0] + data[1], data[0] + data[2], data[1] + data[2]))
| Title: 123-sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a given sequence of integers *a*1,<=*a*2,<=...,<=*a**n*, where every number is from 1 to 3 inclusively. You have to replace the minimum number of numbers in it so that all the numbers in the sequence are equal to each... | ```python
n = int(input())
x = list(map(int, input().split()))
data = 3 * [0]
for item in x:
data[item - 1] += 1
print(min(data[0] + data[1], data[0] + data[2], data[1] + data[2]))
``` | 3.674145 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 0 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,619,050,116 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 82 | 2,000 | 1,433,600 | def isEquivalent(a, b):
if (len(a) % 2 != 0):
return a == b
else:
a1, a2 = [a[0:len(a)//2], a[len(a)//2:len(a)]]
b1, b2 = [b[0:len(b)//2], b[len(b)//2:len(b)]]
return (isEquivalent(a1, b1) and isEquivalent(a2, b2)) or (isEquivalent(a1, b2) and isEquivalent(a2, b1))
a = input()
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into t... | ```python
def isEquivalent(a, b):
if (len(a) % 2 != 0):
return a == b
else:
a1, a2 = [a[0:len(a)//2], a[len(a)//2:len(a)]]
b1, b2 = [b[0:len(b)//2], b[len(b)//2:len(b)]]
return (isEquivalent(a1, b1) and isEquivalent(a2, b2)) or (isEquivalent(a1, b2) and isEquivalent(a2, b1))
a ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,604,633,557 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 310 | 307,200 | n = int(input())
coords = []
for i in range(n):
coords.append(list(map(int, input().split())))
def right(i,j):
return j[0] > i[0] and j[1] == i[1]
def left(i,j):
return j[0] < i[0] and j[1] == i[1]
def lower(i,j):
return j[0] == i[0] and j[1] < i[1]
def upper(i,j):
return j[0] == i[0] a... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
n = int(input())
coords = []
for i in range(n):
coords.append(list(map(int, input().split())))
def right(i,j):
return j[0] > i[0] and j[1] == i[1]
def left(i,j):
return j[0] < i[0] and j[1] == i[1]
def lower(i,j):
return j[0] == i[0] and j[1] < i[1]
def upper(i,j):
return j[0]... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
415 | A | Mashmokh and Lights | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mashmokh works in a factory. At the end of each day he must turn off all of the lights.
The lights on the factory are indexed from 1 to *n*. There are *n* buttons in Mashmokh's room indexed from 1 to *n* as well. If Mashmokh pushes button with index *i*, then each light with index not less than *i* that is still turn... | The first line of the input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), the number of the factory lights and the pushed buttons respectively. The next line contains *m* distinct space-separated integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=*n*).
It is guaranteed that all lights... | Output *n* space-separated integers where the *i*-th number is index of the button that turns the *i*-th light off. | [
"5 4\n4 3 1 2\n",
"5 5\n5 4 3 2 1\n"
] | [
"1 1 3 4 4 \n",
"1 2 3 4 5 \n"
] | In the first sample, after pressing button number 4, lights 4 and 5 are turned off and lights 1, 2 and 3 are still on. Then after pressing button number 3, light number 3 is turned off as well. Pressing button number 1 turns off lights number 1 and 2 as well so pressing button number 2 in the end has no effect. Thus bu... | 500 | [
{
"input": "5 4\n4 3 1 2",
"output": "1 1 3 4 4 "
},
{
"input": "5 5\n5 4 3 2 1",
"output": "1 2 3 4 5 "
},
{
"input": "16 11\n8 5 12 10 14 2 6 3 15 9 1",
"output": "1 2 2 2 5 5 5 8 8 8 8 8 8 8 8 8 "
},
{
"input": "79 22\n76 32 48 28 33 44 58 59 1 51 77 13 15 64 49 72 74 21 6... | 1,653,483,714 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 92 | 0 | n, m = map(int, input().split())
l = [int(i) for i in input().split()]
res = []
for i in range(m):
for j in range(n - l[i] + 1):
if n == 0:
print(res.reverse())
exit()
res.append(l[i])
n -= 1
res.reverse()
for i in res:
print(i, end=" ") | Title: Mashmokh and Lights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mashmokh works in a factory. At the end of each day he must turn off all of the lights.
The lights on the factory are indexed from 1 to *n*. There are *n* buttons in Mashmokh's room indexed from 1 to *n* as well. ... | ```python
n, m = map(int, input().split())
l = [int(i) for i in input().split()]
res = []
for i in range(m):
for j in range(n - l[i] + 1):
if n == 0:
print(res.reverse())
exit()
res.append(l[i])
n -= 1
res.reverse()
for i in res:
print(i, end=" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and... | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, ... | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer ... | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,686,169,317 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 45 | 62 | 0 | def wizard():
n = int(input())
p = int(input())
q = int(input())
rangex = n / (p + q)
distance = rangex * p
print(distance)
wizard()
| Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the en... | ```python
def wizard():
n = int(input())
p = int(input())
q = int(input())
rangex = n / (p + q)
distance = rangex * p
print(distance)
wizard()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
194 | A | Exams | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend too much time and effort to make the sum of his marks strictly more than *k*. That could ha... | The single input line contains space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=250) — the number of exams and the required sum of marks.
It is guaranteed that there exists a way to pass *n* exams in the way that makes the sum of marks equal exactly *k*. | Print the single number — the minimum number of exams that the author will get a 2 for, considering that the sum of marks for all exams must equal *k*. | [
"4 8\n",
"4 10\n",
"1 3\n"
] | [
"4\n",
"2\n",
"0\n"
] | In the first sample the author has to get a 2 for all his exams.
In the second sample he should get a 3 for two exams and a 2 for two more.
In the third sample he should get a 3 for one exam. | 500 | [
{
"input": "4 8",
"output": "4"
},
{
"input": "4 10",
"output": "2"
},
{
"input": "1 3",
"output": "0"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "50 234",
"output": "0"
},
{
"input": "50 100",
"... | 1,535,374,026 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 248 | 0 | import sys
[n,m] = [x for x in map(int,sys.stdin.readline().lstrip('\n').split(' '))]
print(max(0,n - max(0,(m - 2*n)))) | Title: Exams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend ... | ```python
import sys
[n,m] = [x for x in map(int,sys.stdin.readline().lstrip('\n').split(' '))]
print(max(0,n - max(0,(m - 2*n))))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
255 | C | Almost Arithmetical Progression | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | null | null | Gena loves sequences of numbers. Recently, he has discovered a new type of sequences which he called an almost arithmetical progression. A sequence is an almost arithmetical progression, if its elements can be represented as:
- *a*1<==<=*p*, where *p* is some integer; - *a**i*<==<=*a**i*<=-<=1<=+<=(<=-<=1)*i*<=+<=1·... | The first line contains integer *n* (1<=≤<=*n*<=≤<=4000). The next line contains *n* integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=106). | Print a single integer — the length of the required longest subsequence. | [
"2\n3 5\n",
"4\n10 20 10 30\n"
] | [
"2\n",
"3\n"
] | In the first test the sequence actually is the suitable subsequence.
In the second test the following subsequence fits: 10, 20, 10. | 1,500 | [
{
"input": "2\n3 5",
"output": "2"
},
{
"input": "4\n10 20 10 30",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "2"
},
{
"input": "6\n2 3 2 2 1 3",
"output": "4"
},
{
"input": "8\n2 2 5 3 4 3 3 2",
"output": "3"
},
{
"input": "2\n468 335",
... | 1,672,291,577 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 14 | 93 | 1,843,200 | from collections import Counter
def ss(a,x1,x2):
count = 0
term = 0
for i in a:
if count==0:
if i==x1:
count+=1
term = 2
elif i==x2:
count+=1
term = 1
if term==1:
if i==x1:
... | Title: Almost Arithmetical Progression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gena loves sequences of numbers. Recently, he has discovered a new type of sequences which he called an almost arithmetical progression. A sequence is an almost arithmetical progression, if its elements ... | ```python
from collections import Counter
def ss(a,x1,x2):
count = 0
term = 0
for i in a:
if count==0:
if i==x1:
count+=1
term = 2
elif i==x2:
count+=1
term = 1
if term==1:
i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
820 | B | Mister B and Angle in Polygon | PROGRAMMING | 1,300 | [
"constructive algorithms",
"geometry",
"math"
] | null | null | On one quiet day all of sudden Mister B decided to draw angle *a* on his field. Aliens have already visited his field and left many different geometric figures on it. One of the figures is regular convex *n*-gon (regular convex polygon with *n* sides).
That's why Mister B decided to use this polygon. Now Mister B must... | First and only line contains two space-separated integers *n* and *a* (3<=≤<=*n*<=≤<=105, 1<=≤<=*a*<=≤<=180) — the number of vertices in the polygon and the needed angle, in degrees. | Print three space-separated integers: the vertices *v*1, *v*2, *v*3, which form . If there are multiple optimal solutions, print any of them. The vertices are numbered from 1 to *n* in clockwise order. | [
"3 15\n",
"4 67\n",
"4 68\n"
] | [
"1 2 3\n",
"2 1 3\n",
"4 1 2\n"
] | In first sample test vertices of regular triangle can create only angle of 60 degrees, that's why every possible angle is correct.
Vertices of square can create 45 or 90 degrees angles only. That's why in second sample test the angle of 45 degrees was chosen, since |45 - 67| < |90 - 67|. Other correct answers are: ... | 1,000 | [
{
"input": "3 15",
"output": "2 1 3"
},
{
"input": "4 67",
"output": "2 1 3"
},
{
"input": "4 68",
"output": "2 1 4"
},
{
"input": "3 1",
"output": "2 1 3"
},
{
"input": "3 180",
"output": "2 1 3"
},
{
"input": "100000 1",
"output": "2 1 558"
},
... | 1,505,044,812 | 1,812 | Python 3 | OK | TESTS | 46 | 62 | 0 | n, angle = (int(x) for x in input().split())
angle_per = 180 / n
approx = round(angle / angle_per)
if approx == 0:
print(1, n, 2)
elif approx >= n - 2:
print(1, 2, 3)
else:
print(1, n, 1 + approx)
| Title: Mister B and Angle in Polygon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On one quiet day all of sudden Mister B decided to draw angle *a* on his field. Aliens have already visited his field and left many different geometric figures on it. One of the figures is regular convex *... | ```python
n, angle = (int(x) for x in input().split())
angle_per = 180 / n
approx = round(angle / angle_per)
if approx == 0:
print(1, n, 2)
elif approx >= n - 2:
print(1, 2, 3)
else:
print(1, n, 1 + approx)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
369 | A | Valera and Plates | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, he needs exactly one clean plate or bowl. We know that Valera can cook only two types of dishes. He can... | The first line of the input contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=1000) — the number of the planned days, the number of clean bowls and the number of clean plates.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2). If *a**i* equals one, then on day *i* Val... | Print a single integer — the minimum number of times Valera will need to wash a plate/bowl. | [
"3 1 1\n1 2 1\n",
"4 3 1\n1 1 1 1\n",
"3 1 2\n2 2 2\n",
"8 2 2\n1 2 1 2 1 2 1 2\n"
] | [
"1\n",
"1\n",
"0\n",
"4\n"
] | In the first sample Valera will wash a bowl only on the third day, so the answer is one.
In the second sample, Valera will have the first type of the dish during all four days, and since there are only three bowls, he will wash a bowl exactly once.
In the third sample, Valera will have the second type of dish for all... | 500 | [
{
"input": "3 1 1\n1 2 1",
"output": "1"
},
{
"input": "4 3 1\n1 1 1 1",
"output": "1"
},
{
"input": "3 1 2\n2 2 2",
"output": "0"
},
{
"input": "8 2 2\n1 2 1 2 1 2 1 2",
"output": "4"
},
{
"input": "2 100 100\n2 2",
"output": "0"
},
{
"input": "1 1 1\... | 1,409,510,982 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 77 | 0 | n, m, k = (int(x) for x in input().split())
val = 0
for ai in (int(x) for x in input().split()):
if ai == 2 and k > 0:
k -= 1
elif m > 0:
m -= 1
else:
val += 1
print(val)
| Title: Valera and Plates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a lazy student. He has *m* clean bowls and *k* clean plates.
Valera has made an eating plan for the next *n* days. As Valera is lazy, he will eat exactly one dish per day. At that, in order to eat a dish, ... | ```python
n, m, k = (int(x) for x in input().split())
val = 0
for ai in (int(x) for x in input().split()):
if ai == 2 and k > 0:
k -= 1
elif m > 0:
m -= 1
else:
val += 1
print(val)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
550 | C | Divisibility by Eight | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"math"
] | null | null | You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a no... | The single line of the input contains a non-negative integer *n*. The representation of number *n* doesn't contain any leading zeroes and its length doesn't exceed 100 digits. | Print "NO" (without quotes), if there is no such way to remove some digits from number *n*.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number *n* in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any ... | [
"3454\n",
"10\n",
"111111\n"
] | [
"YES\n344\n",
"YES\n0\n",
"NO\n"
] | none | 1,000 | [
{
"input": "3454",
"output": "YES\n344"
},
{
"input": "10",
"output": "YES\n0"
},
{
"input": "111111",
"output": "NO"
},
{
"input": "8996988892",
"output": "YES\n8"
},
{
"input": "5555555555",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
... | 1,699,551,544 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | n=int(input())
s=str(n)
flag=False
for i in range(len(s)):
for j in range(len(s)):
for k in range(len(s)):
if int(s[i]+ s[j] + s[k])%8==0:
print("YES")
print(s[i]+s[j]+s[k])
flag=True
break
if flag==True:
... | Title: Divisibility by Eight
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of t... | ```python
n=int(input())
s=str(n)
flag=False
for i in range(len(s)):
for j in range(len(s)):
for k in range(len(s)):
if int(s[i]+ s[j] + s[k])%8==0:
print("YES")
print(s[i]+s[j]+s[k])
flag=True
break
if flag==True:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
841 | B | Godsend | PROGRAMMING | 1,100 | [
"games",
"math"
] | null | null | Leha somehow found an array consisting of *n* integers. Looking at it, he came up with a task. Two players play the game on the array. Players move one by one. The first player can choose for his move a subsegment of non-zero length with an odd sum of numbers and remove it from the array, after that the remaining parts... | First line of input data contains single integer *n* (1<=≤<=*n*<=≤<=106) — length of the array.
Next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109). | Output answer in single line. "First", if first player wins, and "Second" otherwise (without quotes). | [
"4\n1 3 2 3\n",
"2\n2 2\n"
] | [
"First\n",
"Second\n"
] | In first sample first player remove whole array in one move and win.
In second sample first player can't make a move and lose. | 1,000 | [
{
"input": "4\n1 3 2 3",
"output": "First"
},
{
"input": "2\n2 2",
"output": "Second"
},
{
"input": "4\n2 4 6 8",
"output": "Second"
},
{
"input": "5\n1 1 1 1 1",
"output": "First"
},
{
"input": "4\n720074544 345031254 849487632 80870826",
"output": "Second"
... | 1,629,544,874 | 2,147,483,647 | Python 3 | OK | TESTS | 88 | 576 | 83,558,400 | n=int(input())
a=list(map(int, input().split()))
c=0
for i in a:
if i%2!=0:
c+=1
if c==0:
print("Second")
else:
print("First") | Title: Godsend
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Leha somehow found an array consisting of *n* integers. Looking at it, he came up with a task. Two players play the game on the array. Players move one by one. The first player can choose for his move a subsegment of non-zero l... | ```python
n=int(input())
a=list(map(int, input().split()))
c=0
for i in a:
if i%2!=0:
c+=1
if c==0:
print("Second")
else:
print("First")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,543,219,099 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 109 | 0 | def main():
l, r, k = map(int, input().split())
ans = []
x = 1
while x <= r:
if x >= l:
ans.append(x)
x *= k
if ans:
print(' '.join(map(str, ans)))
else:
print(-1)
if __name__ == '__main__':
main() | Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
def main():
l, r, k = map(int, input().split())
ans = []
x = 1
while x <= r:
if x >= l:
ans.append(x)
x *= k
if ans:
print(' '.join(map(str, ans)))
else:
print(-1)
if __name__ == '__main__':
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
520 | B | Two Buttons | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs",
"greedy",
"implementation",
"math",
"shortest paths"
] | null | null | Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by two. After clicking the blue button, device subtracts one from the number on the display. If at so... | The first and the only line of the input contains two distinct integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=104), separated by a space . | Print a single number — the minimum number of times one needs to push the button required to get the number *m* out of number *n*. | [
"4 6\n",
"10 1\n"
] | [
"2\n",
"9\n"
] | In the first example you need to push the blue button once, and then push the red button once.
In the second example, doubling the number is unnecessary, so we need to push the blue button nine times. | 1,000 | [
{
"input": "4 6",
"output": "2"
},
{
"input": "10 1",
"output": "9"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "2 10",
"outpu... | 1,699,087,400 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 46 | 0 | from math import log2
initial, target = map(int,input().split())
res = 0
while(True):
if (initial >= target):
print(int(initial-target+res))
exit()
if (target%2 == 1):
res+=1
target+=1
if (target%2 == 0):
res+=1
target/=2 | Title: Two Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by t... | ```python
from math import log2
initial, target = map(int,input().split())
res = 0
while(True):
if (initial >= target):
print(int(initial-target+res))
exit()
if (target%2 == 1):
res+=1
target+=1
if (target%2 == 0):
res+=1
target/=2
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
618 | C | Constellation | PROGRAMMING | 1,600 | [
"geometry",
"implementation"
] | null | null | Cat Noku has obtained a map of the night sky. On this map, he found a constellation with *n* stars numbered from 1 to *n*. For each *i*, the *i*-th star is located at coordinates (*x**i*,<=*y**i*). No two stars are located at the same position.
In the evening Noku is going to take a look at the night sky. He would lik... | The first line of the input contains a single integer *n* (3<=≤<=*n*<=≤<=100<=000).
Each of the next *n* lines contains two integers *x**i* and *y**i* (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109).
It is guaranteed that no two stars lie at the same point, and there does not exist a line such that all stars lie on that line. | Print three distinct integers on a single line — the indices of the three points that form a triangle that satisfies the conditions stated in the problem.
If there are multiple possible answers, you may print any of them. | [
"3\n0 1\n1 0\n1 1\n",
"5\n0 0\n0 2\n2 0\n2 2\n1 1\n"
] | [
"1 2 3\n",
"1 3 5\n"
] | In the first sample, we can print the three indices in any order.
In the second sample, we have the following picture.
Note that the triangle formed by starts 1, 4 and 3 doesn't satisfy the conditions stated in the problem, as point 5 is not strictly outside of this triangle (it lies on it's border). | 1,500 | [
{
"input": "3\n0 1\n1 0\n1 1",
"output": "1 2 3"
},
{
"input": "5\n0 0\n0 2\n2 0\n2 2\n1 1",
"output": "1 3 5"
},
{
"input": "3\n819934317 939682125\n487662889 8614219\n-557136619 382982369",
"output": "1 3 2"
},
{
"input": "10\n25280705 121178189\n219147240 -570920213\n-8298... | 1,575,384,582 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 857 | 10,854,400 | n=int(input())
points=[list(map(int,input().split())) for i in range(n)]
from random import randint
i=randint(0,n-2)
j=randint(i+1,n-1)
p1,p2 = points[i],points[j]
def dis(p1,p2):
return (p1[0]-p2[0])**2 + (p1[1]-p2[1])**2
def Area(p1,p2,p3):
return p1[0]*(p2[1]-p3[1])+p2[0]*(p3[1]-p1[1])+p3[0]*(p1[1]-p2[1])... | Title: Constellation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Cat Noku has obtained a map of the night sky. On this map, he found a constellation with *n* stars numbered from 1 to *n*. For each *i*, the *i*-th star is located at coordinates (*x**i*,<=*y**i*). No two stars are locate... | ```python
n=int(input())
points=[list(map(int,input().split())) for i in range(n)]
from random import randint
i=randint(0,n-2)
j=randint(i+1,n-1)
p1,p2 = points[i],points[j]
def dis(p1,p2):
return (p1[0]-p2[0])**2 + (p1[1]-p2[1])**2
def Area(p1,p2,p3):
return p1[0]*(p2[1]-p3[1])+p2[0]*(p3[1]-p1[1])+p3[0]*(p1... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,698,630,881 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 46 | 0 | t = int(input(""))
c = 0
for i in range(t):
y = input("").split(" ")
if abs(int(y[0]) - int(y[1]))>=2:
c = c + 1
print(c) | Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
t = int(input(""))
c = 0
for i in range(t):
y = input("").split(" ")
if abs(int(y[0]) - int(y[1]))>=2:
c = c + 1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
989 | B | A Tide of Riverscape | PROGRAMMING | 1,200 | [
"constructive algorithms",
"strings"
] | null | null | "Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.
Doubtfully, Kanno peeks a... | The first line contains two space-separated integers $n$ and $p$ ($1 \leq p \leq n \leq 2000$) — the length of the given string and the supposed period, respectively.
The second line contains a string $s$ of $n$ characters — Mino's records. $s$ only contains characters '0', '1' and '.', and contains at least one '.' c... | Output one line — if it's possible that $p$ is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)). | [
"10 7\n1.0.1.0.1.\n",
"10 6\n1.0.1.1000\n",
"10 9\n1........1\n"
] | [
"1000100010\n",
"1001101000\n",
"No\n"
] | In the first example, $7$ is not a period of the resulting string because the $1$-st and $8$-th characters of it are different.
In the second example, $6$ is not a period of the resulting string because the $4$-th and $10$-th characters of it are different.
In the third example, $9$ is always a period because the onl... | 1,000 | [
{
"input": "10 7\n1.0.1.0.1.",
"output": "1000100010"
},
{
"input": "10 6\n1.0.1.1000",
"output": "1001101000"
},
{
"input": "10 9\n1........1",
"output": "No"
},
{
"input": "1 1\n.",
"output": "No"
},
{
"input": "5 1\n0...1",
"output": "00001"
},
{
"i... | 1,643,422,543 | 2,147,483,647 | PyPy 3 | OK | TESTS | 59 | 187 | 6,553,600 | import math
import sys
import queue
from heapq import heappop, heappush
import random
def solve():
n, p = map(int, input().split())
s = list(str(input()))
flag = False
for i in range(n - p):
if s[i] != ".":
if s[i + p] == ".":
s[i + p] = str(1 - int(... | Title: A Tide of Riverscape
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its... | ```python
import math
import sys
import queue
from heapq import heappop, heappush
import random
def solve():
n, p = map(int, input().split())
s = list(str(input()))
flag = False
for i in range(n - p):
if s[i] != ".":
if s[i + p] == ".":
s[i + p] = st... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
931 | C | Laboratory Work | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | Anya and Kirill are doing a physics laboratory work. In one of the tasks they have to measure some value *n* times, and then compute the average value to lower the error.
Kirill has already made his measurements, and has got the following integer values: *x*1, *x*2, ..., *x**n*. It is important that the values are clo... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the numeber of measurements made by Kirill.
The second line contains a sequence of integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=100<=000<=≤<=*x**i*<=≤<=100<=000) — the measurements made by Kirill. It is guaranteed that the difference between the maxi... | In the first line print the minimum possible number of equal measurements.
In the second line print *n* integers *y*1,<=*y*2,<=...,<=*y**n* — the values Anya should write. You can print the integers in arbitrary order. Keep in mind that the minimum value among Anya's values should be not less that the minimum among Ki... | [
"6\n-1 1 1 0 0 -1\n",
"3\n100 100 101\n",
"7\n-10 -9 -10 -8 -10 -9 -9\n"
] | [
"2\n0 0 0 0 0 0 \n",
"3\n101 100 100 \n",
"5\n-10 -10 -9 -9 -9 -9 -9 \n"
] | In the first example Anya can write zeros as here measurements results. The average value is then equal to the average value of Kirill's values, and there are only two equal measurements.
In the second example Anya should write two values 100 and one value 101 (in any order), because it is the only possibility to make... | 1,750 | [
{
"input": "6\n-1 1 1 0 0 -1",
"output": "2\n0 0 0 0 0 0 "
},
{
"input": "3\n100 100 101",
"output": "3\n101 100 100 "
},
{
"input": "7\n-10 -9 -10 -8 -10 -9 -9",
"output": "5\n-10 -10 -9 -9 -9 -9 -9 "
},
{
"input": "60\n-8536 -8536 -8536 -8535 -8536 -8536 -8536 -8536 -8536 -... | 1,576,022,744 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 10 | 233 | 14,233,600 | n = int(input())
x = list(map(int, input().strip().split()))
xmin = min(x)
xmax = max(x)
if xmax - xmin < 2:
print(n)
print(' '.join(map(str, x)))
exit(0)
x.sort()
res = list()
cnt = 0
l, r = 0, n-1
while (l < r):
if x[l] + 2 == x[r]:
y = (xmin + xmax) // 2
res.append(... | Title: Laboratory Work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anya and Kirill are doing a physics laboratory work. In one of the tasks they have to measure some value *n* times, and then compute the average value to lower the error.
Kirill has already made his measurements, and h... | ```python
n = int(input())
x = list(map(int, input().strip().split()))
xmin = min(x)
xmax = max(x)
if xmax - xmin < 2:
print(n)
print(' '.join(map(str, x)))
exit(0)
x.sort()
res = list()
cnt = 0
l, r = 0, n-1
while (l < r):
if x[l] + 2 == x[r]:
y = (xmin + xmax) // 2
r... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
653 | B | Bear and Compressing | PROGRAMMING | 1,300 | [
"brute force",
"dfs and similar",
"dp",
"strings"
] | null | null | Limak is a little polar bear. Polar bears hate long strings and thus they like to compress them. You should also know that Limak is so young that he knows only first six letters of the English alphabet: 'a', 'b', 'c', 'd', 'e' and 'f'.
You are given a set of *q* possible operations. Limak can perform them in any order... | The first line contains two integers *n* and *q* (2<=≤<=*n*<=≤<=6, 1<=≤<=*q*<=≤<=36) — the length of the initial string and the number of available operations.
The next *q* lines describe the possible operations. The *i*-th of them contains two strings *a**i* and *b**i* (|*a**i*|<==<=2,<=|*b**i*|<==<=1). It's guarante... | Print the number of strings of length *n* that Limak will be able to transform to string "a" by applying only operations given in the input. | [
"3 5\nab a\ncc c\nca a\nee c\nff d\n",
"2 8\naf e\ndc d\ncc f\nbc b\nda b\neb a\nbb b\nff c\n",
"6 2\nbb a\nba a\n"
] | [
"4\n",
"1\n",
"0\n"
] | In the first sample, we count initial strings of length 3 from which Limak can get a required string "a". There are 4 such strings: "abb", "cab", "cca", "eea". The first one Limak can compress using operation 1 two times (changing "ab" to a single "a"). The first operation would change "abb" to "ab" and the second oper... | 1,000 | [
{
"input": "3 5\nab a\ncc c\nca a\nee c\nff d",
"output": "4"
},
{
"input": "2 8\naf e\ndc d\ncc f\nbc b\nda b\neb a\nbb b\nff c",
"output": "1"
},
{
"input": "6 2\nbb a\nba a",
"output": "0"
},
{
"input": "2 5\nfe b\nbb a\naf b\nfd b\nbf c",
"output": "1"
},
{
"i... | 1,603,459,845 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 0 | n, k = map(int, input().split())
l = []
for _ in range(k):
s1, s2 = input().split()
l.append((s1, s2))
s = 0
def dfs(last, cl):
global s, l, n
if cl == n:
s += 1
return
for item in l:
if item[1] == last:
dfs(item[0][0], cl + 1)
dfs('a', 1)
pr... | Title: Bear and Compressing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. Polar bears hate long strings and thus they like to compress them. You should also know that Limak is so young that he knows only first six letters of the English alphabet: 'a', 'b', '... | ```python
n, k = map(int, input().split())
l = []
for _ in range(k):
s1, s2 = input().split()
l.append((s1, s2))
s = 0
def dfs(last, cl):
global s, l, n
if cl == n:
s += 1
return
for item in l:
if item[1] == last:
dfs(item[0][0], cl + 1)
dfs('... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
789 | B | Masha and geometric depression | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"math"
] | null | null | Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric progression is a sequence of integers *b*1,<=*b*2,<=*b*3,<=..., where for each *i*<=><=1 the respective term satisfi... | The first line of input contains four integers *b*1, *q*, *l*, *m* (-109<=≤<=*b*1,<=*q*<=≤<=109, 1<=≤<=*l*<=≤<=109, 1<=≤<=*m*<=≤<=105) — the initial term and the common ratio of progression, absolute value of maximal number that can be written on the board and the number of "bad" integers, respectively.
The second lin... | Print the only integer, meaning the number of progression terms that will be written on the board if it is finite, or "inf" (without quotes) otherwise. | [
"3 2 30 4\n6 14 25 48\n",
"123 1 2143435 4\n123 11 -5453 141245\n",
"123 1 2143435 4\n54343 -13 6 124\n"
] | [
"3",
"0",
"inf"
] | In the first sample case, Masha will write integers 3, 12, 24. Progression term 6 will be skipped because it is a "bad" integer. Terms bigger than 24 won't be written because they exceed *l* by absolute value.
In the second case, Masha won't write any number because all terms are equal 123 and this is a "bad" integer.... | 1,000 | [
{
"input": "3 2 30 4\n6 14 25 48",
"output": "3"
},
{
"input": "123 1 2143435 4\n123 11 -5453 141245",
"output": "0"
},
{
"input": "123 1 2143435 4\n54343 -13 6 124",
"output": "inf"
},
{
"input": "3 2 25 2\n379195692 -69874783",
"output": "4"
},
{
"input": "3 2 3... | 1,491,547,167 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 46 | 5,529,600 | from math import log
b, q, limit, m = map(int, input().split())
bad = set(map(int, input().split()))
is_inf = ((abs(q) == 1 and abs(b) <= limit) or q == 0 or b == 0)
is_inf_zero = (is_inf and b in bad)
total = int(log(limit/b)/log(q)) + 1
total_bad = 0
for n in bad:
exp = log(n/b)/log(q)
if exp == int(exp) and... | Title: Masha and geometric depression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric pro... | ```python
from math import log
b, q, limit, m = map(int, input().split())
bad = set(map(int, input().split()))
is_inf = ((abs(q) == 1 and abs(b) <= limit) or q == 0 or b == 0)
is_inf_zero = (is_inf and b in bad)
total = int(log(limit/b)/log(q)) + 1
total_bad = 0
for n in bad:
exp = log(n/b)/log(q)
if exp == in... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,693,482,547 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 109 | 0 | def main():
n = int(input())
room = 0
for _ in range(n):
p, q = map(int, input().split())
room += 1 if q - p >= 2 else 0
print(room)
if __name__ == "__main__":
main()
| Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
def main():
n = int(input())
room = 0
for _ in range(n):
p, q = map(int, input().split())
room += 1 if q - p >= 2 else 0
print(room)
if __name__ == "__main__":
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,639,661,996 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 61 | 409,600 | n,m=map(int,input().split())
dic = dict(input().split() for i in range(m))
s1=input().split()
for s in s1:
t = dic[s]
if len(s) <= len(t) :
print(s,end=' ')
else:
print(t,end=' ')
| Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
n,m=map(int,input().split())
dic = dict(input().split() for i in range(m))
s1=input().split()
for s in s1:
t = dic[s]
if len(s) <= len(t) :
print(s,end=' ')
else:
print(t,end=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,632,462,995 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 6,963,200 | input =".-.--"
word = []
r = len(input)
x = 0
while(x<r):
if x == r-1:
break
if input[x] == ".":
word.append("0")
elif input[x] == "-":
if input[x+1] == ".":
word.append("1")
elif input[x+1] == "-":
word.append("2")
x += 1
... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
input =".-.--"
word = []
r = len(input)
x = 0
while(x<r):
if x == r-1:
break
if input[x] == ".":
word.append("0")
elif input[x] == "-":
if input[x+1] == ".":
word.append("1")
elif input[x+1] == "-":
word.append("2")
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
193 | E | Fibonacci Number | PROGRAMMING | 2,900 | [
"brute force",
"math",
"matrices"
] | null | null | John Doe has a list of all Fibonacci numbers modulo 1013. This list is infinite, it starts with numbers 0 and 1. Each number in the list, apart from the first two, is a sum of previous two modulo 1013. That is, John's list is made from the Fibonacci numbers' list by replacing each number there by the remainder when div... | The first line contains the single integer *f* (0<=≤<=*f*<=<<=1013) — the number, which position in the list we should find.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print a single number — the number of the first occurrence of the given number in John's list. If this number doesn't occur in John's list, print -1. | [
"13\n",
"377\n"
] | [
"7\n",
"14\n"
] | none | 2,500 | [
{
"input": "13",
"output": "7"
},
{
"input": "377",
"output": "14"
},
{
"input": "2406684390626",
"output": "999999"
},
{
"input": "1",
"output": "1"
},
{
"input": "3705587146357",
"output": "3224323"
},
{
"input": "2644848607501",
"output": "4999"... | 1,690,495,370 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | print("_RANDOM_GUESS_1690495369.9617267")# 1690495369.9617476 | Title: Fibonacci Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
John Doe has a list of all Fibonacci numbers modulo 1013. This list is infinite, it starts with numbers 0 and 1. Each number in the list, apart from the first two, is a sum of previous two modulo 1013. That is, John's ... | ```python
print("_RANDOM_GUESS_1690495369.9617267")# 1690495369.9617476
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
638 | B | Making Genome in Berland | PROGRAMMING | 1,500 | [
"*special",
"dfs and similar",
"strings"
] | null | null | Berland scientists face a very important task - given the parts of short DNA fragments, restore the dinosaur DNA! The genome of a berland dinosaur has noting in common with the genome that we've used to: it can have 26 distinct nucleotide types, a nucleotide of each type can occur at most once. If we assign distinct En... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of genome fragments.
Each of the next lines contains one descriptions of a fragment. Each fragment is a non-empty string consisting of distinct small letters of the English alphabet. It is not guaranteed that the given fragmen... | In the single line of the output print the genome of the minimum length that contains all the given parts. All the nucleotides in the genome must be distinct. If there are multiple suitable strings, print the string of the minimum length. If there also are multiple suitable strings, you can print any of them. | [
"3\nbcd\nab\ncdef\n",
"4\nx\ny\nz\nw\n"
] | [
"abcdef\n",
"xyzw\n"
] | none | 1,000 | [
{
"input": "3\nbcd\nab\ncdef",
"output": "abcdef"
},
{
"input": "4\nx\ny\nz\nw",
"output": "xyzw"
},
{
"input": "25\nef\nfg\ngh\nhi\nij\njk\nkl\nlm\nmn\nno\nab\nbc\ncd\nde\nop\npq\nqr\nrs\nst\ntu\nuv\nvw\nwx\nxy\nyz",
"output": "abcdefghijklmnopqrstuvwxyz"
},
{
"input": "1\nf... | 1,458,479,420 | 4,220 | PyPy 3 | WRONG_ANSWER | PRETESTS | 9 | 124 | 24,371,200 | n = int(input())
lst = [0] * n
for i in range(n):
lst[i] = input().strip()
i = 0
j = 0
while i < len(lst):
f = 0
for j in range(i + 1, len(lst)):
for h in range(len(lst[j])):
if lst[j][h] == lst[i][0]:
if len(lst[i]) > len(lst[j]) - h:
lst[... | Title: Making Genome in Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland scientists face a very important task - given the parts of short DNA fragments, restore the dinosaur DNA! The genome of a berland dinosaur has noting in common with the genome that we've used to: it can... | ```python
n = int(input())
lst = [0] * n
for i in range(n):
lst[i] = input().strip()
i = 0
j = 0
while i < len(lst):
f = 0
for j in range(i + 1, len(lst)):
for h in range(len(lst[j])):
if lst[j][h] == lst[i][0]:
if len(lst[i]) > len(lst[j]) - h:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
165 | B | Burning Midnight Oil | PROGRAMMING | 1,500 | [
"binary search",
"implementation"
] | null | null | One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of code, drinks a cup of tea, then he writes as much as lines, drinks another cup of tea, then he writes lin... | The input consists of two integers *n* and *k*, separated by spaces — the size of the program in lines and the productivity reduction coefficient, 1<=≤<=*n*<=≤<=109, 2<=≤<=*k*<=≤<=10. | Print the only integer — the minimum value of *v* that lets Vasya write the program in one night. | [
"7 2\n",
"59 9\n"
] | [
"4\n",
"54\n"
] | In the first sample the answer is *v* = 4. Vasya writes the code in the following portions: first 4 lines, then 2, then 1, and then Vasya falls asleep. Thus, he manages to write 4 + 2 + 1 = 7 lines in a night and complete the task.
In the second sample the answer is *v* = 54. Vasya writes the code in the following por... | 1,000 | [
{
"input": "7 2",
"output": "4"
},
{
"input": "59 9",
"output": "54"
},
{
"input": "1 9",
"output": "1"
},
{
"input": "11 2",
"output": "7"
},
{
"input": "747 2",
"output": "376"
},
{
"input": "6578 2",
"output": "3293"
},
{
"input": "37212... | 1,640,202,161 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 62 | 0 | a,b = map(int,input().split())
def work(x,factor,v):
l = 1
total = x
while x // (factor**l) > 0:
total += x // (factor**l)
l += 1
if total >= v:
return True
else:
return False
def bs(A):
left = 1
right = A
while left < right:
... | Title: Burning Midnight Oil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day a highly important task was commissioned to Vasya — writing a program in a night. The program consists of *n* lines of code. Vasya is already exhausted, so he works like that: first he writes *v* lines of c... | ```python
a,b = map(int,input().split())
def work(x,factor,v):
l = 1
total = x
while x // (factor**l) > 0:
total += x // (factor**l)
l += 1
if total >= v:
return True
else:
return False
def bs(A):
left = 1
right = A
while left... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
386 | A | Second-Price Auction | PROGRAMMING | 800 | [
"implementation"
] | null | null | In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is, each bidder secretly informs the organizer of the auction price he is willing to pay. After that, the au... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=1000) — number of bidders. The second line contains *n* distinct integer numbers *p*1,<=*p*2,<=... *p**n*, separated by single spaces (1<=≤<=*p**i*<=≤<=10000), where *p**i* stands for the price offered by the *i*-th bidder. | The single output line should contain two integers: index of the winner and the price he will pay. Indices are 1-based. | [
"2\n5 7\n",
"3\n10 2 8\n",
"6\n3 8 2 9 4 14\n"
] | [
"2 5\n",
"1 8\n",
"6 9\n"
] | none | 500 | [
{
"input": "2\n5 7",
"output": "2 5"
},
{
"input": "3\n10 2 8",
"output": "1 8"
},
{
"input": "6\n3 8 2 9 4 14",
"output": "6 9"
},
{
"input": "4\n4707 7586 4221 5842",
"output": "2 5842"
},
{
"input": "5\n3304 4227 4869 6937 6002",
"output": "4 6002"
},
{... | 1,624,621,229 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 93 | 512,000 |
import builtins
import sys
import math
import re
import itertools
import collections
import random
# with open('testcase.txt', 'r') as stdin:
n = int(input())
bidders = tuple(i for i in map(int, input().split()))
s = set(bidders)
highest = max(s)
winner = bidders.index(highest) + 1
s.remove(highest)
... | Title: Second-Price Auction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is... | ```python
import builtins
import sys
import math
import re
import itertools
import collections
import random
# with open('testcase.txt', 'r') as stdin:
n = int(input())
bidders = tuple(i for i in map(int, input().split()))
s = set(bidders)
highest = max(s)
winner = bidders.index(highest) + 1
s.remove... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
868 | B | Race Against Time | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Have you ever tried to explain to the coordinator, why it is eight hours to the contest and not a single problem has been prepared yet? Misha had. And this time he has a really strong excuse: he faced a space-time paradox! Space and time replaced each other.
The entire universe turned into an enormous clock face with ... | Five integers *h*, *m*, *s*, *t*1, *t*2 (1<=≤<=*h*<=≤<=12, 0<=≤<=*m*,<=*s*<=≤<=59, 1<=≤<=*t*1,<=*t*2<=≤<=12, *t*1<=≠<=*t*2).
Misha's position and the target time do not coincide with the position of any hand. | Print "YES" (quotes for clarity), if Misha can prepare the contest on time, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"12 30 45 3 11\n",
"12 0 1 12 1\n",
"3 47 0 4 9\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | The three examples are shown on the pictures below from left to right. The starting position of Misha is shown with green, the ending position is shown with pink. Note that the positions of the hands on the pictures are not exact, but are close to the exact and the answer is the same. | 500 | [
{
"input": "12 30 45 3 11",
"output": "NO"
},
{
"input": "12 0 1 12 1",
"output": "YES"
},
{
"input": "3 47 0 4 9",
"output": "YES"
},
{
"input": "10 22 59 6 10",
"output": "YES"
},
{
"input": "3 1 13 12 3",
"output": "NO"
},
{
"input": "11 19 28 9 10"... | 1,507,681,842 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 61 | 204,800 | linha = input().split(" ")
horario = False
anti = False
for i in range(5):
linha[i] = int(linha[i])
for i in range(5):
if linha[i] == 12:
linha[i] = 0
hora = (linha[0]*30)
min = (linha[1]*6)
seg = (linha[2]*6)
inicial = (linha[3]*30)
final = (linha[4]*30)
if final > inicial:
if (hora > inicial and ... | Title: Race Against Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Have you ever tried to explain to the coordinator, why it is eight hours to the contest and not a single problem has been prepared yet? Misha had. And this time he has a really strong excuse: he faced a space-time par... | ```python
linha = input().split(" ")
horario = False
anti = False
for i in range(5):
linha[i] = int(linha[i])
for i in range(5):
if linha[i] == 12:
linha[i] = 0
hora = (linha[0]*30)
min = (linha[1]*6)
seg = (linha[2]*6)
inicial = (linha[3]*30)
final = (linha[4]*30)
if final > inicial:
if (hora > in... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations that are powers of three: 1 mark, 3 marks, 9 marks, 27 marks and so on. There are no coins of o... | The single line contains a single integer *n* (1<=≤<=*n*<=≤<=1017).
Please, do not use the %lld specifier to read or write 64 bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | In a single line print an integer: the maximum number of coins the unlucky buyer could have paid with. | [
"1\n",
"4\n"
] | [
"1\n",
"2\n"
] | In the first test case, if a buyer has exactly one coin of at least 3 marks, then, to give Gerald one mark, he will have to give this coin. In this sample, the customer can not have a coin of one mark, as in this case, he will be able to give the money to Gerald without any change.
In the second test case, if the buye... | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "3"
},
{
"input": "10",
"output": "4"
},
{
"input": "100000000000000000",
"output": "33333333333333334"
},
{
"input... | 1,584,516,843 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#define db1(x) cout<<#x<<"="<<x<<'\n'
#define db2(x,y) cout<<#x<<"="<<x<<","<<#y<<"="<<y<<'\n'
#define db3(x,y,z) cout<<#x<<"="<<x<<","<<#y<<"="<<y<<","<<#z<<"="<<z<<'\n'
#define rep(i,n) for(int i=0;i<(n);++i)
#define repA(i,a,n) for(int i=a;i<=(n);++i)
#define repD(i,a,n) for(int i=a;... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations that ... | ```python
#include <bits/stdc++.h>
#define db1(x) cout<<#x<<"="<<x<<'\n'
#define db2(x,y) cout<<#x<<"="<<x<<","<<#y<<"="<<y<<'\n'
#define db3(x,y,z) cout<<#x<<"="<<x<<","<<#y<<"="<<y<<","<<#z<<"="<<z<<'\n'
#define rep(i,n) for(int i=0;i<(n);++i)
#define repA(i,a,n) for(int i=a;i<=(n);++i)
#define repD(i,a,n) fo... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,668,522,112 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n,m=map(int,input().split())
a=(int(i) for i in input().split)
dp=[]
q=()
b=0
for k in reversed(a):
if k not in q:
b+=1
q.add(k)
dp.append(b)
for x in range(m):
print(dp[len(a)-int(input())]) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
n,m=map(int,input().split())
a=(int(i) for i in input().split)
dp=[]
q=()
b=0
for k in reversed(a):
if k not in q:
b+=1
q.add(k)
dp.append(b)
for x in range(m):
print(dp[len(a)-int(input())])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
600 | B | Queries about less or equal elements | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"sortings",
"two pointers"
] | null | null | You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the sizes of arrays *a* and *b*.
The second line contains *n* integers — the elements of array *a* (<=-<=109<=≤<=*a**i*<=≤<=109).
The third line contains *m* integers — the elements of array *b* (<=-<=109<=≤<=*b**j*<=≤<=109). | Print *m* integers, separated by spaces: the *j*-th of which is equal to the number of such elements in array *a* that are less than or equal to the value *b**j*. | [
"5 4\n1 3 5 7 9\n6 4 2 8\n",
"5 5\n1 2 1 2 5\n3 1 4 1 5\n"
] | [
"3 2 1 4\n",
"4 2 4 2 5\n"
] | none | 0 | [
{
"input": "5 4\n1 3 5 7 9\n6 4 2 8",
"output": "3 2 1 4"
},
{
"input": "5 5\n1 2 1 2 5\n3 1 4 1 5",
"output": "4 2 4 2 5"
},
{
"input": "1 1\n-1\n-2",
"output": "0"
},
{
"input": "1 1\n-80890826\n686519510",
"output": "1"
},
{
"input": "11 11\n237468511 -77918754... | 1,628,091,576 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 8,089,600 | a,b=map(int,input().split())
l1=list(map(int,input().split()))
l2=list(map(int,input().split()))
ans=[]
for i in range(len(l2)):
c=0
for j in range(len(l1)):
if l1[j]<=l2[i]:
c=c+1
ans.append(c)
print(*ans)
| Title: Queries about less or equal elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*.
In... | ```python
a,b=map(int,input().split())
l1=list(map(int,input().split()))
l2=list(map(int,input().split()))
ans=[]
for i in range(len(l2)):
c=0
for j in range(len(l1)):
if l1[j]<=l2[i]:
c=c+1
ans.append(c)
print(*ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,653,507,500 | 2,147,483,647 | PyPy 3 | OK | TESTS | 102 | 77 | 0 | # https://codeforces.com/problemset/problem/61/A
a, b = input(), input()
res = [-1 for i in range(len(a))]
for i in range(len(a)):
if a[i] == b[i]:
res[i] = 0
else:
res[i] = 1
print(''.join(map(str, res))) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
# https://codeforces.com/problemset/problem/61/A
a, b = input(), input()
res = [-1 for i in range(len(a))]
for i in range(len(a)):
if a[i] == b[i]:
res[i] = 0
else:
res[i] = 1
print(''.join(map(str, res)))
``` | 3.98075 | MatrixStudio/Codeforces-Python-Submissions |
845 | A | Chess Tourney | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizer... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100).
The second line contains 2·*n* integers *a*1,<=*a*2,<=... *a*2*n* (1<=≤<=*a**i*<=≤<=1000). | If it's possible to divide all 2·*n* players into two teams with *n* people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO". | [
"2\n1 3 2 4\n",
"1\n3 3\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2\n1 3 2 4",
"output": "YES"
},
{
"input": "1\n3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 2 2 3 3 3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 1 2 2 2 2 2",
"output": "YES"
},
{
"input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000... | 1,503,671,706 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 |
def solve():
s = input()
if s == "":
return
n = int(s)
a = list(map(lambda x : int(x), input().split()))
a.sort();
for i in range(0, len(a) - 1):
if a[i] == a[i + 1]:
print("NO")
return
print("YES")
#try:
# while True:
solve()
#except:
# exit(0) | Title: Chess Tourney
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by... | ```python
def solve():
s = input()
if s == "":
return
n = int(s)
a = list(map(lambda x : int(x), input().split()))
a.sort();
for i in range(0, len(a) - 1):
if a[i] == a[i + 1]:
print("NO")
return
print("YES")
#try:
# while True:
solve()
#except:
# exit(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
716 | A | Crazy Computer | PROGRAMMING | 800 | [
"implementation"
] | null | null | ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *b*, then if *b*<=-<=*a*<=≤<=*c*, just the new word is appended to other words on the screen. If *b*<... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*c*<=≤<=109) — the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=...<=<<=*t**n*<=≤<=109), where *t**i* denote... | Print a single positive integer, the number of words that remain on the screen after all *n* words was typed, in other words, at the second *t**n*. | [
"6 5\n1 3 8 14 19 20\n",
"6 1\n1 3 5 7 9 10\n"
] | [
"3",
"2"
] | The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be... | 500 | [
{
"input": "6 5\n1 3 8 14 19 20",
"output": "3"
},
{
"input": "6 1\n1 3 5 7 9 10",
"output": "2"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
"input": "5 5\n1 7 12 13 14",
"output": "4"
},
{
"input": "2 1000000000\n1 1000000000",
"output": "2"
},
{
... | 1,604,676,955 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 171 | 8,806,400 | n,c = map(int,input().split())
arr = list(map(int,input().split()))
count = 1
for i in range(n-1):
if arr[i+1]-arr[i]<=c:
count += 1
else:
count = 1
print(count) | Title: Crazy Computer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *... | ```python
n,c = map(int,input().split())
arr = list(map(int,input().split()))
count = 1
for i in range(n-1):
if arr[i+1]-arr[i]<=c:
count += 1
else:
count = 1
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,681,333,191 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 1,870 | 0 | def sum_of_digits(num):
return sum(int(digit) for digit in str(num))
def magic_transformations(n):
count = 0
while n >= 10:
n = sum_of_digits(n)
count += 1
return count
# Read input
n = int(input().strip())
# Calculate and print the result
result = magic_transformati... | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
def sum_of_digits(num):
return sum(int(digit) for digit in str(num))
def magic_transformations(n):
count = 0
while n >= 10:
n = sum_of_digits(n)
count += 1
return count
# Read input
n = int(input().strip())
# Calculate and print the result
result = magic_tr... | 3.5325 | MatrixStudio/Codeforces-Python-Submissions |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,696,069,922 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | import math
sides = list(map(int, input().strip().split()))
a = math.sqrt(sides[0]*sides[1] / sides[2])
b = math.sqrt(sides[0]*sides[2] / sides[1])
c = math.sqrt(sides[1]*sides[2] / sides[0])
print(int(4 * a + 4 * b + 4 * c)) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
import math
sides = list(map(int, input().strip().split()))
a = math.sqrt(sides[0]*sides[1] / sides[2])
b = math.sqrt(sides[0]*sides[2] / sides[1])
c = math.sqrt(sides[1]*sides[2] / sides[0])
print(int(4 * a + 4 * b + 4 * c))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
618 | A | Slime Combining | PROGRAMMING | 800 | [
"implementation"
] | null | null | Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other *n*<=-<=1 slimes one by one. When you add a slime, you place it at the right of... | The first line of the input will contain a single integer, *n* (1<=≤<=*n*<=≤<=100<=000). | Output a single line with *k* integers, where *k* is the number of slimes in the row after you've finished the procedure described in the problem statement. The *i*-th of these numbers should be the value of the *i*-th slime from the left. | [
"1\n",
"2\n",
"3\n",
"8\n"
] | [
"1\n",
"2\n",
"2 1\n",
"4\n"
] | In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. S... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "8",
"output": "4"
},
{
"input": "100000",
"output": "17 16 11 10 8 6"
},
{
"input": "12345",
"output": "14 13 6 5 4 1"
},
{
"in... | 1,669,546,647 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 108 | 0 | n = int(input())
i = 1
res_board = []
while i <= n:
res_board.append(1)
while True:
if len(res_board)>1:
if res_board[-2] == res_board[-1]:
res_board[-2] += 1
res_board.pop(-1)
else:
break
else:
break
i += 1
res_board = ' '.join([str(x) for x in res_board])
print(res_board) | Title: Slime Combining
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend recently gave you some slimes for your birthday. You have *n* slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, y... | ```python
n = int(input())
i = 1
res_board = []
while i <= n:
res_board.append(1)
while True:
if len(res_board)>1:
if res_board[-2] == res_board[-1]:
res_board[-2] += 1
res_board.pop(-1)
else:
break
else:
break
i += 1
res_board = ' '.join([str(x) for x in res_board])
print(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,687,771,211 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | n = input()
x = n.replace('{','')
y = x.replace('}','')
m = y.split(', ')
if len(m)> 1:
p = set(m)
print(len(p))
else:
print(0) | Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
n = input()
x = n.replace('{','')
y = x.replace('}','')
m = y.split(', ')
if len(m)> 1:
p = set(m)
print(len(p))
else:
print(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset of columns *C**i* are chosen. For each row *r* in *R**i* and each column *c* in *C**i*, the... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and columns of the grid, respectively.
Each of the following *n* lines contains a string of *m* characters, each being either '.' (denoting a white cell) or '#' (denoting a black cell), representing the desir... | If the given grid can be achieved by any valid sequence of operations, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..\n",
"5 5\n..#..\n..#..\n#####\n..#..\n..#..\n",
"5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#\n"
] | [
"Yes\n",
"No\n",
"No\n"
] | For the first example, the desired setup can be produced by 3 operations, as is shown below.
For the second example, the desired setup cannot be produced, since in order to colour the center row, the third row and all columns must be selected in one operation, but after that no column can be selected again, hence it w... | 0 | [
{
"input": "5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..",
"output": "Yes"
},
{
"input": "5 5\n..#..\n..#..\n#####\n..#..\n..#..",
"output": "No"
},
{
"input": "5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#",
"output": "No"
},
{
"input": "1 1\n#",
"o... | 1,521,913,116 | 7,416 | Python 3 | OK | TESTS | 50 | 109 | 7,065,600 | n,m=map(int,input().split())
t=[set(i for i,c in enumerate(input())if c=='#')for _ in [0]*n]
print(['No','Yes'][all(x==y or not x&y for x in t for y in t)]) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset o... | ```python
n,m=map(int,input().split())
t=[set(i for i,c in enumerate(input())if c=='#')for _ in [0]*n]
print(['No','Yes'][all(x==y or not x&y for x in t for y in t)])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,688,765,366 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | n = 3
t = 8
x=10**(n-1)
for i in range (9):
if i==8 and (x+1)%t!=0:
print(-1)
elif x%t!=0:
x+=1
else:
print(x)
break | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n = 3
t = 8
x=10**(n-1)
for i in range (9):
if i==8 and (x+1)%t!=0:
print(-1)
elif x%t!=0:
x+=1
else:
print(x)
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,673,383,356 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 |
n, m = list(map(int, input().split()))
f = list(map(int, input().split()))
nf = list(reversed(sorted(f)))
num = 1001
c = 0
c2 = n -1
print(nf)
if(nf.count(nf[m-n]) >= n or nf.count(nf[0]) >= n):
print(0)
else:
while(c2 < (m-1)):
if((nf[c] - nf[c2]) < num):
num = (nf[c] - nf... | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
n, m = list(map(int, input().split()))
f = list(map(int, input().split()))
nf = list(reversed(sorted(f)))
num = 1001
c = 0
c2 = n -1
print(nf)
if(nf.count(nf[m-n]) >= n or nf.count(nf[0]) >= n):
print(0)
else:
while(c2 < (m-1)):
if((nf[c] - nf[c2]) < num):
num = (... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
291 | A | Spyke Talks | PROGRAMMING | 800 | [
"*special",
"implementation",
"sortings"
] | null | null | Polycarpus is the director of a large corporation. There are *n* secretaries working for the corporation, each of them corresponds via the famous Spyke VoIP system during the day. We know that when two people call each other via Spyke, the Spyke network assigns a unique ID to this call, a positive integer session numbe... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the number of secretaries in Polycarpus's corporation. The next line contains *n* space-separated integers: *id*1,<=*id*2,<=...,<=*id**n* (0<=≤<=*id**i*<=≤<=109). Number *id**i* equals the number of the call session of the *i*-th secretary, if the secretary is t... | Print a single integer — the number of pairs of chatting secretaries, or -1 if Polycarpus's got a mistake in his records and the described situation could not have taken place. | [
"6\n0 1 7 1 7 10\n",
"3\n1 1 1\n",
"1\n0\n"
] | [
"2\n",
"-1\n",
"0\n"
] | In the first test sample there are two Spyke calls between secretaries: secretary 2 and secretary 4, secretary 3 and secretary 5.
In the second test sample the described situation is impossible as conferences aren't allowed. | 500 | [
{
"input": "6\n0 1 7 1 7 10",
"output": "2"
},
{
"input": "3\n1 1 1",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "5\n2 2 1 1 3",
"output": "2"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n4 21 3 21 21 1 1 2 2 3",
"ou... | 1,624,498,861 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 124 | 0 | def check():
n=int(input())
calls=list(map(int,input().split()))
calls.sort()
i,count=0,0
while True:
temp=1
while True:
while i!=len(calls)-1 and calls[i]==calls[i+1]:
temp+=1
i+=1
if temp==2:
co... | Title: Spyke Talks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus is the director of a large corporation. There are *n* secretaries working for the corporation, each of them corresponds via the famous Spyke VoIP system during the day. We know that when two people call each othe... | ```python
def check():
n=int(input())
calls=list(map(int,input().split()))
calls.sort()
i,count=0,0
while True:
temp=1
while True:
while i!=len(calls)-1 and calls[i]==calls[i+1]:
temp+=1
i+=1
if temp==2:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,612,766,732 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | num=list(map(int,input().split(' ')))
num.sort()
print((num[0]+num[1])*2) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
num=list(map(int,input().split(' ')))
num.sort()
print((num[0]+num[1])*2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
622 | F | The Sum of the k-th Powers | PROGRAMMING | 2,600 | [
"math"
] | null | null | There are well-known formulas: , , . Also mathematicians found similar formulas for higher degrees.
Find the value of the sum modulo 109<=+<=7 (so you should find the remainder after dividing the answer by the value 109<=+<=7). | The only line contains two integers *n*,<=*k* (1<=≤<=*n*<=≤<=109,<=0<=≤<=*k*<=≤<=106). | Print the only integer *a* — the remainder after dividing the value of the sum by the value 109<=+<=7. | [
"4 1\n",
"4 2\n",
"4 3\n",
"4 0\n"
] | [
"10\n",
"30\n",
"100\n",
"4\n"
] | none | 0 | [
{
"input": "4 1",
"output": "10"
},
{
"input": "4 2",
"output": "30"
},
{
"input": "4 3",
"output": "100"
},
{
"input": "4 0",
"output": "4"
},
{
"input": "10 0",
"output": "10"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 0",
"o... | 1,598,556,458 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 4,710,400 | def binpo(a,b,m):
a%=m
res = 1
while b>0:
if b &1 ==1:
res*=a%m
a=a*a%m
b>>=1
return res
n,k = map(int,input().split())
x = 0
for i in range(1,n+1):
x+= binpo(i,k,10**9+7)
print(x%(10**9+7)) | Title: The Sum of the k-th Powers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are well-known formulas: , , . Also mathematicians found similar formulas for higher degrees.
Find the value of the sum modulo 109<=+<=7 (so you should find the remainder after dividing the answer by ... | ```python
def binpo(a,b,m):
a%=m
res = 1
while b>0:
if b &1 ==1:
res*=a%m
a=a*a%m
b>>=1
return res
n,k = map(int,input().split())
x = 0
for i in range(1,n+1):
x+= binpo(i,k,10**9+7)
print(x%(10**9+7))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
385 | A | Bear and Raspberry | PROGRAMMING | 1,000 | [
"brute force",
"greedy",
"implementation"
] | null | null | The bear decided to store some raspberry for the winter. He cunningly found out the price for a barrel of honey in kilos of raspberry for each of the following *n* days. According to the bear's data, on the *i*-th (1<=≤<=*i*<=≤<=*n*) day, the price for one barrel of honey is going to is *x**i* kilos of raspberry.
Unfo... | The first line contains two space-separated integers, *n* and *c* (2<=≤<=*n*<=≤<=100,<=0<=≤<=*c*<=≤<=100), — the number of days and the number of kilos of raspberry that the bear should give for borrowing the barrel.
The second line contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x**i*<=≤<=100... | Print a single integer — the answer to the problem. | [
"5 1\n5 10 7 3 20\n",
"6 2\n100 1 10 40 10 40\n",
"3 0\n1 2 3\n"
] | [
"3\n",
"97\n",
"0\n"
] | In the first sample the bear will lend a honey barrel at day 3 and then sell it for 7. Then the bear will buy a barrel for 3 and return it to the friend. So, the profit is (7 - 3 - 1) = 3.
In the second sample bear will lend a honey barrel at day 1 and then sell it for 100. Then the bear buy the barrel for 1 at the da... | 500 | [
{
"input": "5 1\n5 10 7 3 20",
"output": "3"
},
{
"input": "6 2\n100 1 10 40 10 40",
"output": "97"
},
{
"input": "3 0\n1 2 3",
"output": "0"
},
{
"input": "2 0\n2 1",
"output": "1"
},
{
"input": "10 5\n10 1 11 2 12 3 13 4 14 5",
"output": "4"
},
{
"in... | 1,564,124,515 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 109 | 0 | n,c=input().split()
n,c=[int(n),int(c)]
x=list(map(int,input().split()))
num=min(x)
for i in range(n):
if(x[i]==num):
loc=i
break
if(loc==0):
print('0')
else:
res=x[loc-1]-c-x[loc]
print(res) | Title: Bear and Raspberry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear decided to store some raspberry for the winter. He cunningly found out the price for a barrel of honey in kilos of raspberry for each of the following *n* days. According to the bear's data, on the *i*-th (1... | ```python
n,c=input().split()
n,c=[int(n),int(c)]
x=list(map(int,input().split()))
num=min(x)
for i in range(n):
if(x[i]==num):
loc=i
break
if(loc==0):
print('0')
else:
res=x[loc-1]-c-x[loc]
print(res)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
887 | A | Div. 64 | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisi... | In the only line given a non-empty binary string *s* with length up to 100. | Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise. | [
"100010001\n",
"100\n"
] | [
"yes",
"no"
] | In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.
You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system) | 500 | [
{
"input": "100010001",
"output": "yes"
},
{
"input": "100",
"output": "no"
},
{
"input": "0000001000000",
"output": "yes"
},
{
"input": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111",
"output": "no"
},
{
"in... | 1,604,000,213 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a=input()
if len(a)<7:
print("no")
else:
for i n range(len(a)):
if a[i]==1:
a=a[i:]
break
x=a.count('0')
if x>=6:
print("yes")
else:
print("no")
| Title: Div. 64
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some dig... | ```python
a=input()
if len(a)<7:
print("no")
else:
for i n range(len(a)):
if a[i]==1:
a=a[i:]
break
x=a.count('0')
if x>=6:
print("yes")
else:
print("no")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
285 | A | Slightly Decreasing Permutations | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
The ... | The single line contains two space-separated integers: *n*,<=*k* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*k*<=<<=*n*) — the permutation length and the decreasing coefficient. | In a single line print *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* — the permutation of length *n* with decreasing coefficient *k*.
If there are several permutations that meet this condition, print any of them. It is guaranteed that the permutation with the sought parameters exists. | [
"5 2\n",
"3 0\n",
"3 2\n"
] | [
"1 5 2 4 3\n",
"1 2 3\n",
"3 2 1\n"
] | none | 500 | [
{
"input": "5 2",
"output": "1 5 2 4 3"
},
{
"input": "3 0",
"output": "1 2 3"
},
{
"input": "3 2",
"output": "3 2 1"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output": "1 2"
},
{
"input": "2 1",
"output": "2 1"
},
{
"input":... | 1,620,071,117 | 2,147,483,647 | PyPy 3 | OK | TESTS | 28 | 342 | 8,499,200 | n, k = map(int, input().split())
arr = [i for i in range(1, n + 1)]
arr.sort(reverse = True)
if k == n - 1:
arr.sort(reverse = True)
print(*arr)
else:
new_arr = arr[: k] + sorted(arr[k:])
print(*new_arr)
| Title: Slightly Decreasing Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutat... | ```python
n, k = map(int, input().split())
arr = [i for i in range(1, n + 1)]
arr.sort(reverse = True)
if k == n - 1:
arr.sort(reverse = True)
print(*arr)
else:
new_arr = arr[: k] + sorted(arr[k:])
print(*new_arr)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,621,551,023 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 184 | 0 |
n = int(input())
a = [int(x) for x in input().split()]
d = []
for i in range(0,n-1):
d.append(a[i]-a[i+1])
def solve():
for i in range(0, n):
for j in range(0,101):
x = a[i]
a[i] = j
d = []
for k in range(0,n-1):
d.append(a[k]... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
a = [int(x) for x in input().split()]
d = []
for i in range(0,n-1):
d.append(a[i]-a[i+1])
def solve():
for i in range(0, n):
for j in range(0,101):
x = a[i]
a[i] = j
d = []
for k in range(0,n-1):
d.a... | 0 | MatrixStudio/Codeforces-Python-Submissions |
12 | A | Super Agent | PROGRAMMING | 800 | [
"implementation"
] | A. Super Agent | 2 | 256 | There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparing special agent Pearlo for many years. When, finally, Pearlo learned all secrets of espionage... | Input contains the matrix of three rows of three symbols each. Symbol «X» means that the corresponding button was pressed, and «.» means that is was not pressed. The matrix may contain no «X», also it may contain no «.». | Print YES if the password is symmetric with respect to the central button of the terminal and NO otherwise. | [
"XX.\n...\n.XX\n",
"X.X\nX..\n...\n"
] | [
"YES\n",
"NO\n"
] | If you are not familiar with the term «central symmetry», you may look into http://en.wikipedia.org/wiki/Central_symmetry | 0 | [
{
"input": "XX.\n...\n.XX",
"output": "YES"
},
{
"input": ".X.\n.X.\n.X.",
"output": "YES"
},
{
"input": "XXX\nXXX\nXXX",
"output": "YES"
},
{
"input": "XXX\nX.X\nXXX",
"output": "YES"
},
{
"input": "X..\n.X.\n..X",
"output": "YES"
},
{
"input": "...\n... | 1,635,997,831 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 4,300,800 | s = ""
for _ in range(0, 3):
s += input()
print(["NO", "YES"][all([s[i] == s[~i] for i in range(0, 4)])])
| Title: Super Agent
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparin... | ```python
s = ""
for _ in range(0, 3):
s += input()
print(["NO", "YES"][all([s[i] == s[~i] for i in range(0, 4)])])
``` | 3.960989 | MatrixStudio/Codeforces-Python-Submissions |
699 | A | Launch of Collider | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be two or more particles located in the same point. The coordinates of the particles coincide with the dis... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of particles.
The second line contains *n* symbols "L" and "R". If the *i*-th symbol equals "L", then the *i*-th particle will move to the left, otherwise the *i*-th symbol equals "R" and the *i*-th particle will move to the right.... | In the first line print the only integer — the first moment (in microseconds) when two particles are at the same point and there will be an explosion.
Print the only integer -1, if the collision of particles doesn't happen. | [
"4\nRLRL\n2 4 6 10\n",
"3\nLLR\n40 50 60\n"
] | [
"1\n",
"-1\n"
] | In the first sample case the first explosion will happen in 1 microsecond because the particles number 1 and 2 will simultaneously be at the same point with the coordinate 3.
In the second sample case there will be no explosion because there are no particles which will simultaneously be at the same point. | 500 | [
{
"input": "4\nRLRL\n2 4 6 10",
"output": "1"
},
{
"input": "3\nLLR\n40 50 60",
"output": "-1"
},
{
"input": "4\nRLLR\n46 230 264 470",
"output": "92"
},
{
"input": "6\nLLRLLL\n446 492 650 844 930 970",
"output": "97"
},
{
"input": "8\nRRLLLLLL\n338 478 512 574 59... | 1,470,831,394 | 1,294 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 77 | 22,835,200 | n = int(input())
s = input()
x = list(map(int,input().split()))
ans=1e10
lal=-1
lar=-1
for i in range(n-1):
if s[i]=='L':
if lar != -1:
ans = min(ans,x[i]-x[lar])
lal = i
elif s[i]=='R':
if lal != -1:
ans=min(ans,x[i]-x[lal])
lar = i
if ans != 1e10:
pr... | Title: Launch of Collider
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be... | ```python
n = int(input())
s = input()
x = list(map(int,input().split()))
ans=1e10
lal=-1
lar=-1
for i in range(n-1):
if s[i]=='L':
if lar != -1:
ans = min(ans,x[i]-x[lar])
lal = i
elif s[i]=='R':
if lal != -1:
ans=min(ans,x[i]-x[lal])
lar = i
if ans != 1e... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
893 | B | Beautiful Divisors | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Recently Luba learned about a special kind of numbers that she calls beautiful numbers. The number is called beautiful iff its binary representation consists of *k*<=+<=1 consecutive ones, and then *k* consecutive zeroes.
Some examples of beautiful numbers:
- 12 (110); - 1102 (610); - 11110002 (12010); - 1111100... | The only line of input contains one number *n* (1<=≤<=*n*<=≤<=105) — the number Luba has got. | Output one number — the greatest beautiful divisor of Luba's number. It is obvious that the answer always exists. | [
"3\n",
"992\n"
] | [
"1\n",
"496\n"
] | none | 0 | [
{
"input": "3",
"output": "1"
},
{
"input": "992",
"output": "496"
},
{
"input": "81142",
"output": "1"
},
{
"input": "76920",
"output": "120"
},
{
"input": "2016",
"output": "2016"
},
{
"input": "1",
"output": "1"
},
{
"input": "6",
"o... | 1,613,262,670 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 77 | 819,200 |
def STR(): return list(input())
def INT(): return int(input())
def MAP(): return map(int, input().split())
def MAP2():return map(float,input().split())
def LIST(): return list(map(int, input().split()))
def STRING(): return input()
import string
import sys
from heapq import heappop , heappush
from bisect imp... | Title: Beautiful Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba learned about a special kind of numbers that she calls beautiful numbers. The number is called beautiful iff its binary representation consists of *k*<=+<=1 consecutive ones, and then *k* consecutive ze... | ```python
def STR(): return list(input())
def INT(): return int(input())
def MAP(): return map(int, input().split())
def MAP2():return map(float,input().split())
def LIST(): return list(map(int, input().split()))
def STRING(): return input()
import string
import sys
from heapq import heappop , heappush
from ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
703 | A | Mishka and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds *n* is defined.... | The first line of the input contains single integer *n* *n* (1<=≤<=*n*<=≤<=100) — the number of game rounds.
The next *n* lines contains rounds description. *i*-th of them contains pair of integers *m**i* and *c**i* (1<=≤<=*m**i*,<=<=*c**i*<=≤<=6) — values on dice upper face after Mishka's and Chris' throws in *i*-th ... | If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line. | [
"3\n3 5\n2 1\n4 2\n",
"2\n6 1\n1 6\n",
"3\n1 5\n3 3\n2 2\n"
] | [
"Mishka",
"Friendship is magic!^^",
"Chris"
] | In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there... | 500 | [
{
"input": "3\n3 5\n2 1\n4 2",
"output": "Mishka"
},
{
"input": "2\n6 1\n1 6",
"output": "Friendship is magic!^^"
},
{
"input": "3\n1 5\n3 3\n2 2",
"output": "Chris"
},
{
"input": "6\n4 1\n4 2\n5 3\n5 1\n5 3\n4 1",
"output": "Mishka"
},
{
"input": "8\n2 4\n1 4\n1 ... | 1,674,501,644 | 2,147,483,647 | Python 3 | OK | TESTS | 69 | 46 | 0 | n=int(input())
mi=0
ch=0
for i in range(n):
m,c=list(map(int,input().split()))
if(m>c):
mi+=1
elif(m<c):
ch+=1
if(mi>ch):
print("Mishka")
elif(mi<ch):
print("Chris")
else:
print("Friendship is magic!^^")
| Title: Mishka and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they st... | ```python
n=int(input())
mi=0
ch=0
for i in range(n):
m,c=list(map(int,input().split()))
if(m>c):
mi+=1
elif(m<c):
ch+=1
if(mi>ch):
print("Mishka")
elif(mi<ch):
print("Chris")
else:
print("Friendship is magic!^^")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,624,944,264 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 154 | 0 |
'''l,lb=map(int,input().split())
ans=0
while l<=lb:
l,lb=l*3,lb*2
ans+=1
print(ans)
'''
'''q,t=map(int,input().split())
for i in range(t):
if q%10==0:
q=q//10
else:
q=q-1
print(q)'''
'''x=int(input())
if x<=5:
print(1)
else:
if x%5==0:
print(x//5)... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
'''l,lb=map(int,input().split())
ans=0
while l<=lb:
l,lb=l*3,lb*2
ans+=1
print(ans)
'''
'''q,t=map(int,input().split())
for i in range(t):
if q%10==0:
q=q//10
else:
q=q-1
print(q)'''
'''x=int(input())
if x<=5:
print(1)
else:
if x%5==0:
p... | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,690,305,692 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 31 | 0 | a=int(input())
b=bin(a).replace("0b","")
c=[int(x) for x in b]
print(c.count(1)) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
a=int(input())
b=bin(a).replace("0b","")
c=[int(x) for x in b]
print(c.count(1))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
864 | B | Polycarp and Letters | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"strings"
] | null | null | Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if following conditions are met:
- letters on positions from *A* in the string are all distinct and lowerc... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=200) — length of string *s*.
The second line contains a string *s* consisting of lowercase and uppercase Latin letters. | Print maximum number of elements in pretty set of positions for string *s*. | [
"11\naaaaBaabAbA\n",
"12\nzACaAbbaazzC\n",
"3\nABC\n"
] | [
"2\n",
"3\n",
"0\n"
] | In the first example the desired positions might be 6 and 8 or 7 and 8. Positions 6 and 7 contain letters 'a', position 8 contains letter 'b'. The pair of positions 1 and 8 is not suitable because there is an uppercase letter 'B' between these position.
In the second example desired positions can be 7, 8 and 11. There... | 1,000 | [
{
"input": "11\naaaaBaabAbA",
"output": "2"
},
{
"input": "12\nzACaAbbaazzC",
"output": "3"
},
{
"input": "3\nABC",
"output": "0"
},
{
"input": "1\na",
"output": "1"
},
{
"input": "2\naz",
"output": "2"
},
{
"input": "200\nXbTJZqcbpYuZQEoUrbxlPXAPCtVLr... | 1,520,080,566 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 62 | 5,632,000 | def strp(string):
sets = []
s = set()
for c in string:
if c.isupper():
if len(s):
sets.append(s)
s = set()
else:
s.add(c)
if len(s):
sets.append(s)
return max(map(len,sets))
input()
string = input()
print(... | Title: Polycarp and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp loves lowercase letters and dislikes uppercase ones. Once he got a string *s* consisting only of lowercase and uppercase Latin letters.
Let *A* be a set of positions in the string. Let's call it pretty if... | ```python
def strp(string):
sets = []
s = set()
for c in string:
if c.isupper():
if len(s):
sets.append(s)
s = set()
else:
s.add(c)
if len(s):
sets.append(s)
return max(map(len,sets))
input()
string = input... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
787 | A | The Monster | PROGRAMMING | 1,200 | [
"brute force",
"math",
"number theory"
] | null | null | A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams at times *d*,<=*d*<=+<=*c*,<=*d*<=+<=2*c*,<=*d*<=+<=3*c*,<=....
The Monster will catch them if a... | The first line of input contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100).
The second line contains two integers *c* and *d* (1<=≤<=*c*,<=*d*<=≤<=100). | Print the first time Rick and Morty will scream at the same time, or <=-<=1 if they will never scream at the same time. | [
"20 2\n9 19\n",
"2 1\n16 12\n"
] | [
"82\n",
"-1\n"
] | In the first sample testcase, Rick's 5th scream and Morty's 8th time are at time 82.
In the second sample testcase, all Rick's screams will be at odd times and Morty's will be at even times, so they will never scream at the same time. | 500 | [
{
"input": "20 2\n9 19",
"output": "82"
},
{
"input": "2 1\n16 12",
"output": "-1"
},
{
"input": "39 52\n88 78",
"output": "1222"
},
{
"input": "59 96\n34 48",
"output": "1748"
},
{
"input": "87 37\n91 29",
"output": "211"
},
{
"input": "11 81\n49 7",
... | 1,645,520,985 | 2,147,483,647 | PyPy 3 | OK | TESTS | 58 | 77 | 0 | from math import gcd
def main():
a, b = list(map(int, input().split()))
c, d = list(map(int, input().split()))
g = gcd(a, c)
if abs(b - d) % g != 0:
print(-1)
else:
n1, n2 = 0, 0
while True:
value1 = b + a * n1
value2 = d + c * n2
... | Title: The Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams a... | ```python
from math import gcd
def main():
a, b = list(map(int, input().split()))
c, d = list(map(int, input().split()))
g = gcd(a, c)
if abs(b - d) % g != 0:
print(-1)
else:
n1, n2 = 0, 0
while True:
value1 = b + a * n1
value2 = d + ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,674,671,466 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | t=int(input())
if t>1:
for i in range(1,t+1):
print(i,end=' ')
else:
print(-1) | Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
t=int(input())
if t>1:
for i in range(1,t+1):
print(i,end=' ')
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
171 | A | Mysterious numbers - 1 | PROGRAMMING | 1,200 | [
"*special",
"constructive algorithms"
] | null | null | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer. | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space. | Output a single integer. | [
"3 14\n",
"27 12\n",
"100 200\n"
] | [
"44\n",
"48\n",
"102\n"
] | none | 0 | [
{
"input": "3 14",
"output": "44"
},
{
"input": "27 12",
"output": "48"
},
{
"input": "100 200",
"output": "102"
},
{
"input": "0 0",
"output": "0"
},
{
"input": "31415 92653",
"output": "67044"
},
{
"input": "1000000000 0",
"output": "1000000000"
... | 1,567,098,286 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 248 | 0 | a,b = [int(x) for x in input().split()]
c = 0
while b>0:
c = c*10 + b%10
b //= 10
print(a+c) | Title: Mysterious numbers - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer.
Input Specification:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109),... | ```python
a,b = [int(x) for x in input().split()]
c = 0
while b>0:
c = c*10 + b%10
b //= 10
print(a+c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
928 | B | Chat | PROGRAMMING | 1,400 | [
"*special",
"dp"
] | null | null | There are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.
More formal, your message history is a sequence of messages ordered by time sent numbered from 1 to... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*) — the total amount of messages and the number of previous and next messages visible.
The second line features a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*i*), where *a**i* denotes the *i*-th message link... | Print *n* integers with *i*-th denoting the number of distinct messages you can read starting from message *i* and traversing the links while possible. | [
"6 0\n0 1 1 2 3 2\n",
"10 1\n0 1 0 3 4 5 2 3 7 0\n",
"2 2\n0 1\n"
] | [
"1 2 2 3 3 3 \n",
"2 3 3 4 5 6 6 6 8 2 \n",
"2 2 \n"
] | Consider *i* = 6 in sample case one. You will read message 6, then 2, then 1 and then there will be no link to go.
In the second sample case *i* = 6 gives you messages 5, 6, 7 since *k* = 1, then 4, 5, 6, then 2, 3, 4 and then the link sequence breaks. The number of distinct messages here is equal to 6. | 1,250 | [
{
"input": "6 0\n0 1 1 2 3 2",
"output": "1 2 2 3 3 3 "
},
{
"input": "10 1\n0 1 0 3 4 5 2 3 7 0",
"output": "2 3 3 4 5 6 6 6 8 2 "
},
{
"input": "2 2\n0 1",
"output": "2 2 "
},
{
"input": "1 1\n0",
"output": "1 "
},
{
"input": "5 2\n0 1 2 3 1",
"output": "3 4... | 1,519,561,395 | 74,895 | PyPy 3 | WRONG_ANSWER | TESTS | 21 | 295 | 30,924,800 | s = input().split()
n = int(s[0])
k = int(s[1])
a = [int(i) for i in input().split()]
if n < k+2:
print(str(n)+(' ' + str(n))*(n-1))
else:
twok = k*2+1
counts = []
for i in range(1, k+2):
counts.append(i + k)
for i in range(k+2, n-k):
if a[i-1] == 0:
counts.append(twok)... | Title: Chat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.
More form... | ```python
s = input().split()
n = int(s[0])
k = int(s[1])
a = [int(i) for i in input().split()]
if n < k+2:
print(str(n)+(' ' + str(n))*(n-1))
else:
twok = k*2+1
counts = []
for i in range(1, k+2):
counts.append(i + k)
for i in range(k+2, n-k):
if a[i-1] == 0:
counts.ap... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
717 | B | R3D3’s Summer Adventure | PROGRAMMING | 2,700 | [
"dp",
"greedy"
] | null | null | R3D3 spent some time on an internship in MDCS. After earning enough money, he decided to go on a holiday somewhere far, far away. He enjoyed suntanning, drinking alcohol-free cocktails and going to concerts of popular local bands. While listening to "The White Buttons" and their hit song "Dacan the Baker", he met anoth... | The first line of input contains three integers *n* (2<=≤<=*n*<=≤<=108), *c*0 and *c*1 (0<=≤<=*c*0,<=*c*1<=≤<=108) — the number of letters in the alphabet, and costs of '0' and '1', respectively. | Output a single integer — minimum possible total a cost of the whole alphabet. | [
"4 1 2\n"
] | [
"12\n"
] | There are 4 letters in the alphabet. The optimal encoding is "00", "01", "10", "11". There are 4 zeroes and 4 ones used, so the total cost is 4·1 + 4·2 = 12. | 0 | [
{
"input": "4 1 2",
"output": "12"
},
{
"input": "2 1 5",
"output": "6"
},
{
"input": "3 1 1",
"output": "5"
},
{
"input": "5 5 5",
"output": "60"
},
{
"input": "4 0 0",
"output": "0"
},
{
"input": "6 0 6",
"output": "30"
},
{
"input": "6 6... | 1,536,812,300 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 139 | 0 | def get_input_list():
return list(map(int, input().split()))
def factorial(x):
s = 1
for i in range(x):
s = s * (i+1)
return s
def combination(n,k):
return(factorial(n)/(factorial(k)*factorial(n-k)))
def v(cost, c0, c1):
n = int(cost/c0) + 1
l = []
for i in range(n):
if (cost - i*c0)%... | Title: R3D3’s Summer Adventure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
R3D3 spent some time on an internship in MDCS. After earning enough money, he decided to go on a holiday somewhere far, far away. He enjoyed suntanning, drinking alcohol-free cocktails and going to concerts of p... | ```python
def get_input_list():
return list(map(int, input().split()))
def factorial(x):
s = 1
for i in range(x):
s = s * (i+1)
return s
def combination(n,k):
return(factorial(n)/(factorial(k)*factorial(n-k)))
def v(cost, c0, c1):
n = int(cost/c0) + 1
l = []
for i in range(n):
if (cos... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
542 | C | Idempotent functions | PROGRAMMING | 2,000 | [
"constructive algorithms",
"graphs",
"math"
] | null | null | Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1,<=2,<=...,<=*n*} is such function , that for any the formula *g*(*g*(*x*))<==<=*g*(*x*) holds.
Let's denote as *f*(*k*)(*x*) the function *f* applied *k* times to the value *x*. More formally, *f*(1)(*x*)<==<=*f*(*x*),... | In the first line of the input there is a single integer *n* (1<=≤<=*n*<=≤<=200) — the size of function *f* domain.
In the second line follow *f*(1),<=*f*(2),<=...,<=*f*(*n*) (1<=≤<=*f*(*i*)<=≤<=*n* for each 1<=≤<=*i*<=≤<=*n*), the values of a function. | Output minimum *k* such that function *f*(*k*)(*x*) is idempotent. | [
"4\n1 2 2 4\n",
"3\n2 3 3\n",
"3\n2 3 1\n"
] | [
"1\n",
"2\n",
"3\n"
] | In the first sample test function *f*(*x*) = *f*<sup class="upper-index">(1)</sup>(*x*) is already idempotent since *f*(*f*(1)) = *f*(1) = 1, *f*(*f*(2)) = *f*(2) = 2, *f*(*f*(3)) = *f*(3) = 2, *f*(*f*(4)) = *f*(4) = 4.
In the second sample test:
- function *f*(*x*) = *f*<sup class="upper-index">(1)</sup>(*x*) isn'... | 750 | [
{
"input": "4\n1 2 2 4",
"output": "1"
},
{
"input": "3\n2 3 3",
"output": "2"
},
{
"input": "3\n2 3 1",
"output": "3"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "16\n1 4 13 9 11 16 14 6 5 12 7 8 15 2 3 10",
"output": "105"
},
{
"input": "20\n1 ... | 1,430,671,589 | 2,789 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 6 | 1,000 | 0 |
def gcd(a, b):
if b == 0:
return a
return gcd(b, a % b)
n = int(input())
p = [int(x) - 1 for x in input().split()]
was = [0 for i in range(n)]
ans = 1
mx = 0
for i in range(n):
if was[i] != 0:
continue
t = i
l = 1
while was[t] == 0:
was[t] = l
... | Title: Idempotent functions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1,<=2,<=...,<=*n*} is such function , that for any the formula *g*(*g*(*x*))<==<=*g*(*x*) holds.
Let's denote as *... | ```python
def gcd(a, b):
if b == 0:
return a
return gcd(b, a % b)
n = int(input())
p = [int(x) - 1 for x in input().split()]
was = [0 for i in range(n)]
ans = 1
mx = 0
for i in range(n):
if was[i] != 0:
continue
t = i
l = 1
while was[t] == 0:
was[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
508 | A | Pasha and Pixels | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row with *m* pixels in each row. Initially, all the pixels are colored white. In one move, Pasha can choos... | The first line of the input contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=105) — the number of rows, the number of columns and the number of moves that Pasha is going to perform.
The next *k* lines contain Pasha's moves in the order he makes them. Each line contains two integers *i*... | If Pasha loses, print the number of the move when the 2<=×<=2 square consisting of black pixels is formed.
If Pasha doesn't lose, that is, no 2<=×<=2 square consisting of black pixels is formed during the given *k* moves, print 0. | [
"2 2 4\n1 1\n1 2\n2 1\n2 2\n",
"2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1\n",
"5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2\n"
] | [
"4\n",
"5\n",
"0\n"
] | none | 500 | [
{
"input": "2 2 4\n1 1\n1 2\n2 1\n2 2",
"output": "4"
},
{
"input": "2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1",
"output": "5"
},
{
"input": "5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2",
"output": "0"
},
{
"input": "3 3 11\n2 1\n3 1\n1 1\n1 3\n1 2\n2 3\n3 3\n3 2\n2 2\n1 3\n3 3",
... | 1,697,676,843 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 31 | 0 | n, m, k = map(int,input().split())
martix = [(m+2)*[0] for n_i in range(n+2)]
def check(i, j):
if martix[j][i+1]*martix[j+1][i]*martix[j+1][i+1] == 1:
return True
if martix[j][i+1]*martix[j-1][i]*martix[j-1][i+1] == 1:
return True
if martix[j][i-1]*martix[j-1][i]*martix[j-1][i-1] == 1... | Title: Pasha and Pixels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row ... | ```python
n, m, k = map(int,input().split())
martix = [(m+2)*[0] for n_i in range(n+2)]
def check(i, j):
if martix[j][i+1]*martix[j+1][i]*martix[j+1][i+1] == 1:
return True
if martix[j][i+1]*martix[j-1][i]*martix[j-1][i+1] == 1:
return True
if martix[j][i-1]*martix[j-1][i]*martix[j-1]... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
292 | B | Network Topology | PROGRAMMING | 1,200 | [
"graphs",
"implementation"
] | null | null | This problem uses a simplified network topology model, please read the problem statement carefully and use it as a formal document as you develop the solution.
Polycarpus continues working as a system administrator in a large corporation. The computer network of this corporation consists of *n* computers, some of them... | The first line contains two space-separated integers *n* and *m* (4<=≤<=*n*<=≤<=105; 3<=≤<=*m*<=≤<=105) — the number of nodes and edges in the graph, correspondingly. Next *m* lines contain the description of the graph's edges. The *i*-th line contains a space-separated pair of integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*... | In a single line print the network topology name of the given graph. If the answer is the bus, print "bus topology" (without the quotes), if the answer is the ring, print "ring topology" (without the quotes), if the answer is the star, print "star topology" (without the quotes). If no answer fits, print "unknown topolo... | [
"4 3\n1 2\n2 3\n3 4\n",
"4 4\n1 2\n2 3\n3 4\n4 1\n",
"4 3\n1 2\n1 3\n1 4\n",
"4 4\n1 2\n2 3\n3 1\n1 4\n"
] | [
"bus topology\n",
"ring topology\n",
"star topology\n",
"unknown topology\n"
] | none | 1,000 | [
{
"input": "4 3\n1 2\n2 3\n3 4",
"output": "bus topology"
},
{
"input": "4 4\n1 2\n2 3\n3 4\n4 1",
"output": "ring topology"
},
{
"input": "4 3\n1 2\n1 3\n1 4",
"output": "star topology"
},
{
"input": "4 4\n1 2\n2 3\n3 1\n1 4",
"output": "unknown topology"
},
{
"i... | 1,649,810,597 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 1,964 | 12,083,200 | n,m = map(int, input().split())
a = [[] for _ in range(n)]
for i in range(m):
x,y = map(int, input().split())
x -= 1
y -= 1
a[x].append(y)
a[y].append(x)
s1 = 0
s2 = 0
s3 = 0
for i in a:
if len(i) == 1:
s1 += 1
if len(i) == n - 1:
s2 += 1
if len(i)... | Title: Network Topology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem uses a simplified network topology model, please read the problem statement carefully and use it as a formal document as you develop the solution.
Polycarpus continues working as a system administrator in... | ```python
n,m = map(int, input().split())
a = [[] for _ in range(n)]
for i in range(m):
x,y = map(int, input().split())
x -= 1
y -= 1
a[x].append(y)
a[y].append(x)
s1 = 0
s2 = 0
s3 = 0
for i in a:
if len(i) == 1:
s1 += 1
if len(i) == n - 1:
s2 += 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
485 | B | Valuable Resources | PROGRAMMING | 1,300 | [
"brute force",
"greedy"
] | null | null | Many computer strategy games require building cities, recruiting army, conquering tribes, collecting resources. Sometimes it leads to interesting problems.
Let's suppose that your task is to build a square city. The world map uses the Cartesian coordinates. The sides of the city should be parallel to coordinate axes.... | The first line of the input contains number *n* — the number of mines on the map (2<=≤<=*n*<=≤<=1000). Each of the next *n* lines contains a pair of integers *x**i* and *y**i* — the coordinates of the corresponding mine (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109). All points are pairwise distinct. | Print the minimum area of the city that can cover all the mines with valuable resources. | [
"2\n0 0\n2 2\n",
"2\n0 0\n0 3\n"
] | [
"4\n",
"9\n"
] | none | 500 | [
{
"input": "2\n0 0\n2 2",
"output": "4"
},
{
"input": "2\n0 0\n0 3",
"output": "9"
},
{
"input": "2\n0 1\n1 0",
"output": "1"
},
{
"input": "3\n2 2\n1 1\n3 3",
"output": "4"
},
{
"input": "3\n3 1\n1 3\n2 2",
"output": "4"
},
{
"input": "3\n0 1\n1 0\n2 ... | 1,424,598,525 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 77 | 0 | n=int(input())
a=[]
b=[]
for i in range(n):
x,y=list(map(int,input().split()))
a.append(x)
b.append(y)
s=max(a)-min(a)
t=max(b)-min(b)
if s>t:
print(s*s)
else:
print(t*t) | Title: Valuable Resources
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Many computer strategy games require building cities, recruiting army, conquering tribes, collecting resources. Sometimes it leads to interesting problems.
Let's suppose that your task is to build a square city. Th... | ```python
n=int(input())
a=[]
b=[]
for i in range(n):
x,y=list(map(int,input().split()))
a.append(x)
b.append(y)
s=max(a)-min(a)
t=max(b)-min(b)
if s>t:
print(s*s)
else:
print(t*t)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
979 | B | Treasure Hunt | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | After the big birthday party, Katie still wanted Shiro to have some more fun. Later, she came up with a game called treasure hunt. Of course, she invited her best friends Kuro and Shiro to play with her.
The three friends are very smart so they passed all the challenges very quickly and finally reached the destination... | The first line contains an integer $n$ ($0 \leq n \leq 10^{9}$) — the number of turns.
Next 3 lines contain 3 ribbons of Kuro, Shiro and Katie one per line, respectively. Each ribbon is a string which contains no more than $10^{5}$ uppercase and lowercase Latin letters and is not empty. It is guaranteed that the lengt... | Print the name of the winner ("Kuro", "Shiro" or "Katie"). If there are at least two cats that share the maximum beauty, print "Draw". | [
"3\nKuroo\nShiro\nKatie\n",
"7\ntreasurehunt\nthreefriends\nhiCodeforces\n",
"1\nabcabc\ncbabac\nababca\n",
"15\nfoPaErcvJ\nmZaxowpbt\nmkuOlaHRE\n"
] | [
"Kuro\n",
"Shiro\n",
"Katie\n",
"Draw\n"
] | In the first example, after $3$ turns, Kuro can change his ribbon into ooooo, which has the beauty of $5$, while reaching such beauty for Shiro and Katie is impossible (both Shiro and Katie can reach the beauty of at most $4$, for example by changing Shiro's ribbon into SSiSS and changing Katie's ribbon into Kaaaa). Th... | 1,000 | [
{
"input": "3\nKuroo\nShiro\nKatie",
"output": "Kuro"
},
{
"input": "7\ntreasurehunt\nthreefriends\nhiCodeforces",
"output": "Shiro"
},
{
"input": "1\nabcabc\ncbabac\nababca",
"output": "Katie"
},
{
"input": "15\nfoPaErcvJ\nmZaxowpbt\nmkuOlaHRE",
"output": "Draw"
},
{... | 1,526,360,920 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 78 | 7,065,600 | n = int(input())
ku = input()
sh = input()
ka = input()
ku_di = {}
sh_di = {}
ka_di = {}
for ch in ku:
if ku_di.get(ch, 0) == 0:
ku_di[ch] = 1
else:
ku_di[ch] += 1
for ch in sh:
if sh_di.get(ch, 0) == 0:
sh_di[ch] = 1
else:
sh_di[ch] += 1
for ch in ka:
if ka_di.get(ch, 0) == 0:
ka_di[ch] = 1
else:
... | Title: Treasure Hunt
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the big birthday party, Katie still wanted Shiro to have some more fun. Later, she came up with a game called treasure hunt. Of course, she invited her best friends Kuro and Shiro to play with her.
The three friend... | ```python
n = int(input())
ku = input()
sh = input()
ka = input()
ku_di = {}
sh_di = {}
ka_di = {}
for ch in ku:
if ku_di.get(ch, 0) == 0:
ku_di[ch] = 1
else:
ku_di[ch] += 1
for ch in sh:
if sh_di.get(ch, 0) == 0:
sh_di[ch] = 1
else:
sh_di[ch] += 1
for ch in ka:
if ka_di.get(ch, 0) == 0:
ka_di[ch] =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
518 | B | Tanya and Postcard | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"strings"
] | null | null | Little Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string *s* of length *n*, consisting of uppercase and lowercase English letters. Tanya can't write yet, so she found a newspaper and decided to cut out the letters and glue them into the postcard to achieve string *s... | The first line contains line *s* (1<=≤<=|*s*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text of Tanya's message.
The second line contains line *t* (|*s*|<=≤<=|*t*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text written in the newspaper.
Here |*a*| means the ... | Print two integers separated by a space:
- the first number is the number of times Tanya shouts "YAY!" while making the message, - the second number is the number of times Tanya says "WHOOPS" while making the message. | [
"AbC\nDCbA\n",
"ABC\nabc\n",
"abacaba\nAbaCaBA\n"
] | [
"3 0\n",
"0 3\n",
"3 4\n"
] | none | 1,000 | [
{
"input": "AbC\nDCbA",
"output": "3 0"
},
{
"input": "ABC\nabc",
"output": "0 3"
},
{
"input": "abacaba\nAbaCaBA",
"output": "3 4"
},
{
"input": "zzzzz\nZZZZZ",
"output": "0 5"
},
{
"input": "zzzZZZ\nZZZzzZ",
"output": "5 1"
},
{
"input": "abcdefghijk... | 1,570,896,620 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 12,288,000 | alvo = list(input())
jornal = list(input())
s, n = 0, 0
for i in range(len(alvo)):
try:
index1 = jornal.index(alvo[i])
jornal[index1] = '-'
s += 1
except:
if 'a' <= alvo[i] <= 'z':
try:
index1 = jornal.index(alvo[i].upper())
jornal[in... | Title: Tanya and Postcard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string *s* of length *n*, consisting of uppercase and lowercase English letters. Tanya can't write yet, so she f... | ```python
alvo = list(input())
jornal = list(input())
s, n = 0, 0
for i in range(len(alvo)):
try:
index1 = jornal.index(alvo[i])
jornal[index1] = '-'
s += 1
except:
if 'a' <= alvo[i] <= 'z':
try:
index1 = jornal.index(alvo[i].upper())
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
358 | B | Dima and Text Messages | PROGRAMMING | 1,500 | [
"brute force",
"strings"
] | null | null | Seryozha has a very changeable character. This time he refused to leave the room to Dima and his girlfriend (her hame is Inna, by the way). However, the two lovebirds can always find a way to communicate. Today they are writing text messages to each other.
Dima and Inna are using a secret code in their text messages. ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of words in Dima's message. Next *n* lines contain non-empty words, one word per line. The words only consist of small English letters. The total length of all words doesn't exceed 105.
The last line contains non-empty text message that Inna has got... | In a single line, print "yes" (without the quotes), if Dima decoded the text message correctly, and "no" (without the quotes) otherwise. | [
"3\ni\nlove\nyou\n<3i<3love<23you<3\n",
"7\ni\nam\nnot\nmain\nin\nthe\nfamily\n<3i<>3am<3the<3<main<3in<3the<3><3family<3\n"
] | [
"yes\n",
"no\n"
] | Please note that Dima got a good old kick in the pants for the second sample from the statement. | 1,000 | [
{
"input": "3\ni\nlove\nyou\n<3i<3love<23you<3",
"output": "yes"
},
{
"input": "7\ni\nam\nnot\nmain\nin\nthe\nfamily\n<3i<>3am<3the<3<main<3in<3the<3><3family<3",
"output": "no"
},
{
"input": "3\ni\nlove\nyou\n<3i<3lo<3ve<3y<<<<<<<ou3<3",
"output": "yes"
},
{
"input": "4\na\n... | 1,668,112,351 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | """
https://codeforces.com/problemset/problem/358/B
"""
tests = int(input())
texts = []
for _ in range(tests + 1):
texts.append(input())
def trouve_i3(text):
if (v:=text.find('<'))>-1 and text.find('3')>v:
return True
return False
a = texts[-1]
res = []
i = 0
possible = True
#trouve les mots
for c... | Title: Dima and Text Messages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Seryozha has a very changeable character. This time he refused to leave the room to Dima and his girlfriend (her hame is Inna, by the way). However, the two lovebirds can always find a way to communicate. Today t... | ```python
"""
https://codeforces.com/problemset/problem/358/B
"""
tests = int(input())
texts = []
for _ in range(tests + 1):
texts.append(input())
def trouve_i3(text):
if (v:=text.find('<'))>-1 and text.find('3')>v:
return True
return False
a = texts[-1]
res = []
i = 0
possible = True
#trouve les ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,694,964,682 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 46 | 0 | n,k = map(int,input().split())
for i in range(1,n+1):
judge_num = sum(list(range(i+1)))*5
if judge_num > (240 - k):
print(i-1)
break
if sum(list(range(n+1)))*5 + k <= 240:
print(n) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
n,k = map(int,input().split())
for i in range(1,n+1):
judge_num = sum(list(range(i+1)))*5
if judge_num > (240 - k):
print(i-1)
break
if sum(list(range(n+1)))*5 + k <= 240:
print(n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
538 | A | Cutting Banner | PROGRAMMING | 1,400 | [
"brute force",
"implementation"
] | null | null | A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case ... | The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES. | Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes). | [
"CODEWAITFORITFORCES\n",
"BOTTOMCODER\n",
"DECODEFORCES\n",
"DOGEFORCES\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "CODEWAITFORITFORCES",
"output": "YES"
},
{
"input": "BOTTOMCODER",
"output": "NO"
},
{
"input": "DECODEFORCES",
"output": "YES"
},
{
"input": "DOGEFORCES",
"output": "NO"
},
{
"input": "ABACABA",
"output": "NO"
},
{
"input": "CODEFORCE",
... | 1,470,551,476 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 4,608,000 | s=input()
c="CODEFORCES"
for j in range(10):
i=s.find(c[:j])
if i>=0 and s.find(c[j:],i):
print("YES")
break
else:print("NO") | Title: Cutting Banner
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody ... | ```python
s=input()
c="CODEFORCES"
for j in range(10):
i=s.find(c[:j])
if i>=0 and s.find(c[j:],i):
print("YES")
break
else:print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for ... | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use al... | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,689,841,431 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 39 | 62 | 1,536,000 | n,m=map(int,input().split())
parsa=list(map(int,input().split()))
amin=[0]*n
for i in range(0,n,1):
amin[i]=parsa[i]
parsa.sort()
counter=0
s=m
for i in range(0,n,1):
if m==0:
break
else:
if m>=parsa[i]:
m-=parsa[i]
counter+=1
else:
... | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr ... | ```python
n,m=map(int,input().split())
parsa=list(map(int,input().split()))
amin=[0]*n
for i in range(0,n,1):
amin[i]=parsa[i]
parsa.sort()
counter=0
s=m
for i in range(0,n,1):
if m==0:
break
else:
if m>=parsa[i]:
m-=parsa[i]
counter+=1
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
353 | D | Queue | PROGRAMMING | 2,000 | [
"constructive algorithms",
"dp"
] | null | null | There are *n* schoolchildren, boys and girls, lined up in the school canteen in front of the bun stall. The buns aren't ready yet and the line is undergoing some changes.
Each second all boys that stand right in front of girls, simultaneously swap places with the girls (so that the girls could go closer to the beginni... | The first line contains a sequence of letters without spaces *s*1*s*2... *s**n* (1<=≤<=*n*<=≤<=106), consisting of capital English letters M and F. If letter *s**i* equals M, that means that initially, the line had a boy on the *i*-th position. If letter *s**i* equals F, then initially the line had a girl on the *i*-th... | Print a single integer — the number of seconds needed to move all the girls in the line in front of the boys. If the line has only boys or only girls, print 0. | [
"MFM\n",
"MMFF\n",
"FFMMM\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first test case the sequence of changes looks as follows: MFM → FMM.
The second test sample corresponds to the sample from the statement. The sequence of changes is: MMFF → MFMF → FMFM → FFMM. | 2,500 | [
{
"input": "MFM",
"output": "1"
},
{
"input": "MMFF",
"output": "3"
},
{
"input": "FFMMM",
"output": "0"
},
{
"input": "MMFMMFFFFM",
"output": "7"
},
{
"input": "MFFFMMFMFMFMFFFMMMFFMMMMMMFMMFFMMMFMMFMFFFMMFMMMFFMMFFFFFMFMFFFMMMFFFMFMFMFMFFFMMMMFMMFMMFFMMMMMMFFM",... | 1,689,429,615 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1689429615.5541725")# 1689429615.55419 | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* schoolchildren, boys and girls, lined up in the school canteen in front of the bun stall. The buns aren't ready yet and the line is undergoing some changes.
Each second all boys that stand right in front of girls, ... | ```python
print("_RANDOM_GUESS_1689429615.5541725")# 1689429615.55419
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
489 | B | BerSU Ball | PROGRAMMING | 1,200 | [
"dfs and similar",
"dp",
"graph matchings",
"greedy",
"sortings",
"two pointers"
] | null | null | The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in eac... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of boys. The second line contains sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the *i*-th boy's dancing skill.
Similarly, the third line contains an integer *m* (1<=≤<=*m*<=≤<=100) — the number of girls. The fourth l... | Print a single number — the required maximum possible number of pairs. | [
"4\n1 4 6 2\n5\n5 1 5 7 9\n",
"4\n1 2 3 4\n4\n10 11 12 13\n",
"5\n1 1 1 1 1\n3\n1 2 3\n"
] | [
"3\n",
"0\n",
"2\n"
] | none | 1,000 | [
{
"input": "4\n1 4 6 2\n5\n5 1 5 7 9",
"output": "3"
},
{
"input": "4\n1 2 3 4\n4\n10 11 12 13",
"output": "0"
},
{
"input": "5\n1 1 1 1 1\n3\n1 2 3",
"output": "2"
},
{
"input": "1\n1\n1\n1",
"output": "1"
},
{
"input": "2\n1 10\n1\n9",
"output": "1"
},
{... | 1,682,662,020 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | n = int(input())
a = sorted(list(map(int,input().split())))
m = int(input())
b = sorted(list(map(int,input().split())))
i = 0
j = 0
count = 0
while i < n and j < m:
if abs(a[i]-b[j])<=1:
count+=1
i+=1
j+=1
elif b[i] < a[j]:
i+=1
else:
j+=1
print(count)
| Title: BerSU Ball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy... | ```python
n = int(input())
a = sorted(list(map(int,input().split())))
m = int(input())
b = sorted(list(map(int,input().split())))
i = 0
j = 0
count = 0
while i < n and j < m:
if abs(a[i]-b[j])<=1:
count+=1
i+=1
j+=1
elif b[i] < a[j]:
i+=1
else:
j+=1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
551 | C | GukiZ hates Boxes | PROGRAMMING | 2,200 | [
"binary search",
"greedy"
] | null | null | Professor GukiZ is concerned about making his way to school, because massive piles of boxes are blocking his way.
In total there are *n* piles of boxes, arranged in a line, from left to right, *i*-th pile (1<=≤<=*i*<=≤<=*n*) containing *a**i* boxes. Luckily, *m* students are willing to help GukiZ by removing all the ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105), the number of piles of boxes and the number of GukiZ's students.
The second line contains *n* integers *a*1,<=*a*2,<=... *a**n* (0<=≤<=*a**i*<=≤<=109) where *a**i* represents the number of boxes on *i*-th pile. It's guaranteed that at least o... | In a single line, print one number, minimum time needed to remove all the boxes in seconds. | [
"2 1\n1 1\n",
"3 2\n1 0 2\n",
"4 100\n3 4 5 4\n"
] | [
"4\n",
"5\n",
"5\n"
] | First sample: Student will first move to the first pile (1 second), then remove box from first pile (1 second), then move to the second pile (1 second) and finally remove the box from second pile (1 second).
Second sample: One of optimal solutions is to send one student to remove a box from the first pile and a box fr... | 1,750 | [
{
"input": "2 1\n1 1",
"output": "4"
},
{
"input": "3 2\n1 0 2",
"output": "5"
},
{
"input": "4 100\n3 4 5 4",
"output": "5"
},
{
"input": "5 8\n121351 0 13513 0 165454",
"output": "37544"
},
{
"input": "6 6\n0 10 0 0 10 0",
"output": "8"
},
{
"input":... | 1,438,600,020 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 42 | 280 | 11,878,400 | __author__ = '$'
import sys
#sys.stdin = open("in.txt")
val = [0] * 100005
def check(k):
global n, m
sum = 0
cnt = m
for i in range(n):
sum += val[i]
while sum + i + 1 > k:
sum -= k - i - 1
cnt -= 1
if cnt < 0:
return Fals... | Title: GukiZ hates Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ is concerned about making his way to school, because massive piles of boxes are blocking his way.
In total there are *n* piles of boxes, arranged in a line, from left to right, *i*-th pile (1<=≤<=*i*... | ```python
__author__ = '$'
import sys
#sys.stdin = open("in.txt")
val = [0] * 100005
def check(k):
global n, m
sum = 0
cnt = m
for i in range(n):
sum += val[i]
while sum + i + 1 > k:
sum -= k - i - 1
cnt -= 1
if cnt < 0:
r... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,699,213,872 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 52 | 62 | 0 | n,k = map(int,input().split())
t = 4*60
c = 0
for i in range(1,n+1):
t -= i*5
if k > t:
print(c)
break
c += 1
else:
print(n) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
n,k = map(int,input().split())
t = 4*60
c = 0
for i in range(1,n+1):
t -= i*5
if k > t:
print(c)
break
c += 1
else:
print(n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
157 | A | Game Outcome | PROGRAMMING | 800 | [
"brute force"
] | null | null | Sherlock Holmes and Dr. Watson played some game on a checkered board *n*<=×<=*n* in size. During the game they put numbers on the board's squares by some tricky rules we don't know. However, the game is now over and each square of the board contains exactly one number. To understand who has won, they need to count the ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=30). Each of the following *n* lines contain *n* space-separated integers. The *j*-th number on the *i*-th line represents the number on the square that belongs to the *j*-th column and the *i*-th row on the board. All number on the board are integers from 1 to 100. | Print the single number — the number of the winning squares. | [
"1\n1\n",
"2\n1 2\n3 4\n",
"4\n5 7 8 4\n9 5 3 2\n1 6 6 4\n9 5 7 3\n"
] | [
"0\n",
"2\n",
"6\n"
] | In the first example two upper squares are winning.
In the third example three left squares in the both middle rows are winning: | 500 | [
{
"input": "1\n1",
"output": "0"
},
{
"input": "2\n1 2\n3 4",
"output": "2"
},
{
"input": "4\n5 7 8 4\n9 5 3 2\n1 6 6 4\n9 5 7 3",
"output": "6"
},
{
"input": "2\n1 1\n1 1",
"output": "0"
},
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "4"
},
{
"inpu... | 1,645,179,759 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 92 | 0 | n = int(input())
answer = 0
s = [list(map(int, input().split())) for i in range(n)]
for i in range(n):
for j in range(n):
sh = s[i]
sw = [s[k][j] for k in range(n)]
if sum(sw) > sum(sh):
answer+=1
print(answer)
| Title: Game Outcome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sherlock Holmes and Dr. Watson played some game on a checkered board *n*<=×<=*n* in size. During the game they put numbers on the board's squares by some tricky rules we don't know. However, the game is now over and each s... | ```python
n = int(input())
answer = 0
s = [list(map(int, input().split())) for i in range(n)]
for i in range(n):
for j in range(n):
sh = s[i]
sw = [s[k][j] for k in range(n)]
if sum(sw) > sum(sh):
answer+=1
print(answer)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,544,947,332 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 124 | 0 | n,m = map(int, input().split())
x=0
for a in range(n):
win = [int(z)for z in input().split()]
for i in range(m):
if win[2*i]+win[2*i+1]:
x+=1
print(x) | Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
n,m = map(int, input().split())
x=0
for a in range(n):
win = [int(z)for z in input().split()]
for i in range(m):
if win[2*i]+win[2*i+1]:
x+=1
print(x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
496 | B | Secret Combination | PROGRAMMING | 1,500 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | You got a box with a combination lock. The lock has a display showing *n* digits. There are two buttons on the box, each button changes digits on the display. You have quickly discovered that the first button adds 1 to all the digits (all digits 9 become digits 0), and the second button shifts all the digits on the dis... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits on the display.
The second line contains *n* digits — the initial state of the display. | Print a single line containing *n* digits — the desired state of the display containing the smallest possible number. | [
"3\n579\n",
"4\n2014\n"
] | [
"024\n",
"0142\n"
] | none | 1,000 | [
{
"input": "3\n579",
"output": "024"
},
{
"input": "4\n2014",
"output": "0142"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "3\n039",
"output": "014"
},
{
"input": "4\n4444",
"output": "0000"
},
{
"input": "5\n46802",
"output": "02468"
},
... | 1,566,299,772 | 2,147,483,647 | PyPy 3 | OK | TESTS | 28 | 748 | 11,673,600 | class CodeforcesTask496BSolution:
def __init__(self):
self.result = ''
self.n = 0
self.digits = []
def read_input(self):
self.n = int(input())
self.digits = [int(x) for x in input()]
def process_task(self):
nums = []
for x in range(10):
n... | Title: Secret Combination
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You got a box with a combination lock. The lock has a display showing *n* digits. There are two buttons on the box, each button changes digits on the display. You have quickly discovered that the first button adds 1 ... | ```python
class CodeforcesTask496BSolution:
def __init__(self):
self.result = ''
self.n = 0
self.digits = []
def read_input(self):
self.n = int(input())
self.digits = [int(x) for x in input()]
def process_task(self):
nums = []
for x in range(10):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,672,659,432 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 57 | 62 | 0 | vowels='aeiou'
def isvowel(i):
if i in vowels:
return True
else:
return False
t=str(input())
l=(t[-1])
output='YES'
for i in range(len(t)-1):
if isvowel(t[i]) and (isvowel(t[i+1]) or (not isvowel(t[i+1]))):
output='YES'
elif (not isvowel(t[i]) and isvowel(t[i+1])):
output='YES'
e... | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
vowels='aeiou'
def isvowel(i):
if i in vowels:
return True
else:
return False
t=str(input())
l=(t[-1])
output='YES'
for i in range(len(t)-1):
if isvowel(t[i]) and (isvowel(t[i+1]) or (not isvowel(t[i+1]))):
output='YES'
elif (not isvowel(t[i]) and isvowel(t[i+1])):
output=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,629,972,347 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 170 | 18,432,000 | n=int(input())
a=list(map(int, input().split()))[:n]
b=sorted(list(map(int, input().split()))[:n])
s=sum(a)
if s<=b[-1]+b[-2]:
print("YES")
else:
print("NO") | Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
n=int(input())
a=list(map(int, input().split()))[:n]
b=sorted(list(map(int, input().split()))[:n])
s=sum(a)
if s<=b[-1]+b[-2]:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
161 | A | Dress'em in Vests! | PROGRAMMING | 1,300 | [
"binary search",
"brute force",
"greedy",
"two pointers"
] | null | null | The Two-dimensional kingdom is going through hard times... This morning the Three-Dimensional kingdom declared war on the Two-dimensional one. This (possibly armed) conflict will determine the ultimate owner of the straight line.
The Two-dimensional kingdom has a regular army of *n* people. Each soldier registered him... | The first input line contains four integers *n*, *m*, *x* and *y* (1<=≤<=*n*,<=*m*<=≤<=105, 0<=≤<=*x*,<=*y*<=≤<=109) — the number of soldiers, the number of vests and two numbers that specify the soldiers' unpretentiousness, correspondingly.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i... | In the first line print a single integer *k* — the maximum number of soldiers equipped with bulletproof vests.
In the next *k* lines print *k* pairs, one pair per line, as "*u**i* *v**i*" (without the quotes). Pair (*u**i*, *v**i*) means that soldier number *u**i* must wear vest number *v**i*. Soldiers and vests are ... | [
"5 3 0 0\n1 2 3 3 4\n1 3 5\n",
"3 3 2 2\n1 5 9\n3 5 7\n"
] | [
"2\n1 1\n3 2\n",
"3\n1 1\n2 2\n3 3\n"
] | In the first sample you need the vests' sizes to match perfectly: the first soldier gets the first vest (size 1), the third soldier gets the second vest (size 3). This sample allows another answer, which gives the second vest to the fourth soldier instead of the third one.
In the second sample the vest size can differ... | 1,000 | [
{
"input": "5 3 0 0\n1 2 3 3 4\n1 3 5",
"output": "2\n1 1\n3 2"
},
{
"input": "3 3 2 2\n1 5 9\n3 5 7",
"output": "3\n1 1\n2 2\n3 3"
},
{
"input": "1 1 0 0\n1\n1",
"output": "1\n1 1"
},
{
"input": "1 1 0 0\n1\n2",
"output": "0"
},
{
"input": "2 3 1 4\n1 5\n1 2 2",
... | 1,464,565,198 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 122 | 5,120,000 | def main():
n, m, x, y = map(int, input().split())
aa, it, res, b = list(map(int, input().split())), iter(enumerate(map(int, input().split()), 1)), [], -x
try:
for i, a in enumerate(aa, 1):
while b < a - x:
j, b = next(it)
if a >= b - x:
res.ap... | Title: Dress'em in Vests!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Two-dimensional kingdom is going through hard times... This morning the Three-Dimensional kingdom declared war on the Two-dimensional one. This (possibly armed) conflict will determine the ultimate owner of the s... | ```python
def main():
n, m, x, y = map(int, input().split())
aa, it, res, b = list(map(int, input().split())), iter(enumerate(map(int, input().split()), 1)), [], -x
try:
for i, a in enumerate(aa, 1):
while b < a - x:
j, b = next(it)
if a >= b - x:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
755 | A | PolandBall and Hypothesis | PROGRAMMING | 800 | [
"brute force",
"graphs",
"math",
"number theory"
] | null | null | PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is a prime number".
Unfortunately, PolandBall is not experienced yet and doesn't know that his hypothesis is inc... | The only number in the input is *n* (1<=≤<=*n*<=≤<=1000) — number from the PolandBall's hypothesis. | Output such *m* that *n*·*m*<=+<=1 is not a prime number. Your answer will be considered correct if you output any suitable *m* such that 1<=≤<=*m*<=≤<=103. It is guaranteed the the answer exists. | [
"3\n",
"4\n"
] | [
"1",
"2"
] | A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.
For the first sample testcase, 3·1 + 1 = 4. We can output 1.
In the second sample testcase, 4·1 + 1 = 5. We cannot output 1 because 5 is prime. However, *m* = 2 is okay since 4·2 + 1 = 9, which is not... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "2"
},
{
"input": "153",
"output": "1"
},
{
"input": "1000",
"output": "1"
},
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "4"
... | 1,621,822,719 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | n = int(input())
m = 1
flag = 0
count = 0
while flag==0:
n+=m
count +=1
for i in range(2,n):
if n%i==0:
print(count)
flag = 1
break
| Title: PolandBall and Hypothesis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is... | ```python
n = int(input())
m = 1
flag = 0
count = 0
while flag==0:
n+=m
count +=1
for i in range(2,n):
if n%i==0:
print(count)
flag = 1
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,693,990,116 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 124 | 3,072,000 | n = int(input())
m = int(input())
sol = n + m;n = str(n)
m = str(m);sol = str(c)
n = int(n.replace('0', ""))
m = int(m.replace('0', ""))
sol=int(sol.replace("0",""))
if n + m == sol:
print("YES")
else:
print("NO") | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
n = int(input())
m = int(input())
sol = n + m;n = str(n)
m = str(m);sol = str(c)
n = int(n.replace('0', ""))
m = int(m.replace('0', ""))
sol=int(sol.replace("0",""))
if n + m == sol:
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
957 | A | Tritonic Iridescence | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one-dimensional canvas split into *n* consecutive segments, each segment needs to be painted in one of the co... | The first line contains a single positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the canvas.
The second line contains a string *s* of *n* characters, the *i*-th of which is either 'C' (denoting a segment painted in cyan), 'M' (denoting one painted in magenta), 'Y' (one painted in yellow), or '?' (an unpainted... | If there are at least two different ways of painting, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5\nCY??Y\n",
"5\nC?C?Y\n",
"5\n?CYC?\n",
"5\nC??MM\n",
"3\nMMY\n"
] | [
"Yes\n",
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | For the first example, there are exactly two different ways of colouring: CYCMY and CYMCY.
For the second example, there are also exactly two different ways of colouring: CMCMY and CYCMY.
For the third example, there are four ways of colouring: MCYCM, MCYCY, YCYCM, and YCYCY.
For the fourth example, no matter how th... | 500 | [
{
"input": "5\nCY??Y",
"output": "Yes"
},
{
"input": "5\nC?C?Y",
"output": "Yes"
},
{
"input": "5\n?CYC?",
"output": "Yes"
},
{
"input": "5\nC??MM",
"output": "No"
},
{
"input": "3\nMMY",
"output": "No"
},
{
"input": "15\n??YYYYYY??YYYY?",
"output"... | 1,655,540,197 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
s = list(str(input()))
sl = len(s)
cnt = 0
lst = ['']
for i in s:
print(cnt,end=' ')
if cnt == 0 or cnt == sl:
if i == '?':
dum = ['C','M','Y']
if cnt == 0:
vs = s[cnt+1]
if vs != '?':
dum.remove(vs)
... | Title: Tritonic Iridescence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one... | ```python
n = int(input())
s = list(str(input()))
sl = len(s)
cnt = 0
lst = ['']
for i in s:
print(cnt,end=' ')
if cnt == 0 or cnt == sl:
if i == '?':
dum = ['C','M','Y']
if cnt == 0:
vs = s[cnt+1]
if vs != '?':
dum.r... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
879 | B | Table Tennis | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | null | null | *n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. They play until someone wins *k* games in a row. This player becomes the winner.
For each of t... | The first line contains two integers: *n* and *k* (2<=≤<=*n*<=≤<=500, 2<=≤<=*k*<=≤<=1012) — the number of people and the number of wins.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — powers of the player. It's guaranteed that this line contains a valid permutation, i.e. all ... | Output a single integer — power of the winner. | [
"2 2\n1 2\n",
"4 2\n3 1 2 4\n",
"6 2\n6 5 3 1 2 4\n",
"2 10000000000\n2 1\n"
] | [
"2 ",
"3 ",
"6 ",
"2\n"
] | Games in the second sample:
3 plays with 1. 3 wins. 1 goes to the end of the line.
3 plays with 2. 3 wins. He wins twice in a row. He becomes the winner. | 1,000 | [
{
"input": "2 2\n1 2",
"output": "2 "
},
{
"input": "4 2\n3 1 2 4",
"output": "3 "
},
{
"input": "6 2\n6 5 3 1 2 4",
"output": "6 "
},
{
"input": "2 10000000000\n2 1",
"output": "2"
},
{
"input": "4 4\n1 3 4 2",
"output": "4 "
},
{
"input": "2 21474836... | 1,656,871,670 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 102,400 | [n, k] = [int (x) for x in (input().split())]
arr = [int (x) for x in (input().split())]
obj = dict.fromkeys(arr, 0)
def tableTennis(array, k, object, iter):
winner = max(array[:2])
mini = min(array[:2])
object[winner] += 1
if(iter > len(array)):
print(winner)
return
elif... | Title: Table Tennis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so o... | ```python
[n, k] = [int (x) for x in (input().split())]
arr = [int (x) for x in (input().split())]
obj = dict.fromkeys(arr, 0)
def tableTennis(array, k, object, iter):
winner = max(array[:2])
mini = min(array[:2])
object[winner] += 1
if(iter > len(array)):
print(winner)
return... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
466 | C | Number of Ways | PROGRAMMING | 1,700 | [
"binary search",
"brute force",
"data structures",
"dp",
"two pointers"
] | null | null | You've got array *a*[1],<=*a*[2],<=...,<=*a*[*n*], consisting of *n* integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the same.
More formally, you need to find the number of such pairs of indices *i*,<=*j* (2<=≤<=*i*<=≤<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5·105), showing how many numbers are in the array. The second line contains *n* integers *a*[1], *a*[2], ..., *a*[*n*] (|*a*[*i*]|<=≤<=<=109) — the elements of array *a*. | Print a single integer — the number of ways to split the array into three parts with the same sum. | [
"5\n1 2 3 0 3\n",
"4\n0 1 -1 0\n",
"2\n4 1\n"
] | [
"2\n",
"1\n",
"0\n"
] | none | 1,500 | [
{
"input": "5\n1 2 3 0 3",
"output": "2"
},
{
"input": "4\n0 1 -1 0",
"output": "1"
},
{
"input": "2\n4 1",
"output": "0"
},
{
"input": "9\n0 0 0 0 0 0 0 0 0",
"output": "28"
},
{
"input": "10\n2 5 -2 2 -3 -2 3 5 -5 -2",
"output": "0"
},
{
"input": "1\... | 1,699,952,319 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | """
Created on Nov.12 2023
@author: 施广熠 生命科学学院 2300012143
"""
n=int(input())
L=[int(i) for i in input().split()]
su=sum(L)
if su%3!=0:
print(0)
else:
l_su=0
l=0
cou_l=0
r_su=0
r=n-1
cou_r=0
while l<=r:
l_su+=L[l]
r_su+=L[r]
l+=1
r-=1
... | Title: Number of Ways
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got array *a*[1],<=*a*[2],<=...,<=*a*[*n*], consisting of *n* integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the s... | ```python
"""
Created on Nov.12 2023
@author: 施广熠 生命科学学院 2300012143
"""
n=int(input())
L=[int(i) for i in input().split()]
su=sum(L)
if su%3!=0:
print(0)
else:
l_su=0
l=0
cou_l=0
r_su=0
r=n-1
cou_r=0
while l<=r:
l_su+=L[l]
r_su+=L[r]
l+=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
869 | B | The Eternal Immortality | PROGRAMMING | 1,100 | [
"math"
] | null | null | Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like this.
The phoenix has a rather long lifespan, and reincarnates itself once every *a*! years. Here *a*! deno... | The first and only line of input contains two space-separated integers *a* and *b* (0<=≤<=*a*<=≤<=*b*<=≤<=1018). | Output one line containing a single decimal digit — the last digit of the value that interests Koyomi. | [
"2 4\n",
"0 10\n",
"107 109\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first example, the last digit of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/99c47ca8b182f097e38094d12f0c06ce0b081b76.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2;
In the second example, the last digit of <img align="middle" class="tex-formula" src="https://espresso... | 1,000 | [
{
"input": "2 4",
"output": "2"
},
{
"input": "0 10",
"output": "0"
},
{
"input": "107 109",
"output": "2"
},
{
"input": "10 13",
"output": "6"
},
{
"input": "998244355 998244359",
"output": "4"
},
{
"input": "999999999000000000 1000000000000000000",
... | 1,507,701,695 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 20 | 62 | 0 | import sys
def factor(a, b):
s = 1
for i in range(a + 1, b + 1):
s*=i
return s % 10
# sys.stdin = [
# '2 4',
# '0 10',
# '107 109',
# '0 0'
# ]
for line in sys.stdin:
values = line.split()
a = int(values[0])
b = int(values[1])
if (b - a) > 9:
print(0)
... | Title: The Eternal Immortality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like... | ```python
import sys
def factor(a, b):
s = 1
for i in range(a + 1, b + 1):
s*=i
return s % 10
# sys.stdin = [
# '2 4',
# '0 10',
# '107 109',
# '0 0'
# ]
for line in sys.stdin:
values = line.split()
a = int(values[0])
b = int(values[1])
if (b - a) > 9:
pr... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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