contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
393 | A | Nineteen | PROGRAMMING | 0 | [] | null | null | Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) ... | The first line contains a non-empty string *s*, consisting only of lowercase English letters. The length of string *s* doesn't exceed 100. | Print a single integer — the maximum number of "nineteen"s that she can get in her string. | [
"nniinneetteeeenn\n",
"nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii\n",
"nineteenineteen\n"
] | [
"2",
"2",
"2"
] | none | 500 | [
{
"input": "nniinneetteeeenn",
"output": "2"
},
{
"input": "nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii",
"output": "2"
},
{
"input": "nineteenineteen",
"output": "2"
},
{
"input": "nssemsnnsitjtihtthij",
"output": "0"
},
{
"input": "eehihnttehtherjsihihn... | 1,566,487,460 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 140 | 819,200 | import re
print(re.findall("nineteen","nineteenineteen")) | Title: Nineteen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiinetee... | ```python
import re
print(re.findall("nineteen","nineteenineteen"))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,601,496,502 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | n,k=map(int,input().split())
s=input()
d={}
if n%k==0 or k%n==0:
for i in s:
d[i]=d.get(i,0)+1
f=0
for i in sorted(d.values()):
if i%k!=0:
f+=1
if f>0:
print('NO')
else:
print('YES')
| Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
n,k=map(int,input().split())
s=input()
d={}
if n%k==0 or k%n==0:
for i in s:
d[i]=d.get(i,0)+1
f=0
for i in sorted(d.values()):
if i%k!=0:
f+=1
if f>0:
print('NO')
else:
print('YES')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million... | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,678,729,942 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 92 | 0 |
ni = int(input())
ki = int(input())
ti = -1
while ki != 1 and ki % ni == 0:
ki //= ni
ti += 1
if ki == 1:
print("YES\n" + str(ti))
else:
print("NO") | Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousa... | ```python
ni = int(input())
ki = int(input())
ti = -1
while ki != 1 and ki % ni == 0:
ki //= ni
ti += 1
if ki == 1:
print("YES\n" + str(ti))
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
900 | A | Find Extra One | PROGRAMMING | 800 | [
"geometry",
"implementation"
] | null | null | You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis. | The first line contains a single positive integer *n* (2<=≤<=*n*<=≤<=105).
The following *n* lines contain coordinates of the points. The *i*-th of these lines contains two single integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109, *x**i*<=≠<=0). No two points coincide. | Print "Yes" if there is such a point, "No" — otherwise.
You can print every letter in any case (upper or lower). | [
"3\n1 1\n-1 -1\n2 -1\n",
"4\n1 1\n2 2\n-1 1\n-2 2\n",
"3\n1 2\n2 1\n4 60\n"
] | [
"Yes",
"No",
"Yes"
] | In the first example the second point can be removed.
In the second example there is no suitable for the condition point.
In the third example any point can be removed. | 500 | [
{
"input": "3\n1 1\n-1 -1\n2 -1",
"output": "Yes"
},
{
"input": "4\n1 1\n2 2\n-1 1\n-2 2",
"output": "No"
},
{
"input": "3\n1 2\n2 1\n4 60",
"output": "Yes"
},
{
"input": "10\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n-1 -1",
"output": "Yes"
},
{
"input": "2\n1... | 1,568,346,137 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | n=int(input())
x1=0
x2=0
for q in range(n):
x,y=map(int,input().split())
if x>0:
x1=x1+1
elif x1<0:
x2=x2+1
if(x2<=1 or x1<=1):
print("Yes")
else:
print("No")
| Title: Find Extra One
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis.
Input Specification:
The first li... | ```python
n=int(input())
x1=0
x2=0
for q in range(n):
x,y=map(int,input().split())
if x>0:
x1=x1+1
elif x1<0:
x2=x2+1
if(x2<=1 or x1<=1):
print("Yes")
else:
print("No")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,603,020,177 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 307,200 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Sun Oct 18 19:14:57 2020
@author: apple
"""
n=int(input())
a=list(map(int,input().split(' ')))
b=c=0
d=[]
e=[]
for i in range(n):
if a[i]%2==0:
b+=1
d.append(i+1)
elif a[i]%2==1:
c+=1
e.append(i+1)
if b==1:
print... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Sun Oct 18 19:14:57 2020
@author: apple
"""
n=int(input())
a=list(map(int,input().split(' ')))
b=c=0
d=[]
e=[]
for i in range(n):
if a[i]%2==0:
b+=1
d.append(i+1)
elif a[i]%2==1:
c+=1
e.append(i+1)
if b==1:... | 3.944928 | MatrixStudio/Codeforces-Python-Submissions |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,622,957,816 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | n,m=map(int,input().split())
lsta=list(map(int,input().split()))
lstb=list(map(int,input().split()))
b=list(set(lstb))
cnt=0
for i in b:
if i in lsta:
cnt+=1
print(n-cnt) | Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
n,m=map(int,input().split())
lsta=list(map(int,input().split()))
lstb=list(map(int,input().split()))
b=list(set(lstb))
cnt=0
for i in b:
if i in lsta:
cnt+=1
print(n-cnt)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
659 | C | Tanya and Toys | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the *i*-th type costs *i* bourles.
Tania has managed to collect *n* different types of toys *a*1,<=*a*2,<=...,<=*a**n* from the new collection... | The first line contains two integers *n* (1<=≤<=*n*<=≤<=100<=000) and *m* (1<=≤<=*m*<=≤<=109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109... | In the first line print a single integer *k* — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed *m*.
In the second line print *k* distinct space-separated ... | [
"3 7\n1 3 4\n",
"4 14\n4 6 12 8\n"
] | [
"2\n2 5 \n",
"4\n7 2 3 1\n"
] | In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | 1,000 | [
{
"input": "3 7\n1 3 4",
"output": "2\n2 5 "
},
{
"input": "4 14\n4 6 12 8",
"output": "4\n1 2 3 5 "
},
{
"input": "5 6\n97746 64770 31551 96547 65684",
"output": "3\n1 2 3 "
},
{
"input": "10 10\n94125 56116 29758 94024 29289 31663 99794 35076 25328 58656",
"output": "4\... | 1,679,409,726 | 726 | PyPy 3 | OK | TESTS | 61 | 140 | 12,185,600 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n, m = map(int, input().split())
a = list(map(int, input().split()))
s = set(sorted(a))
t = []
for i in range(1, pow(10, 6)):
if i > m:
break
if not i in s:
t.append(i)
m -= i
k = len(t)
print(... | Title: Tanya and Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the *i*-th type costs *i* bourles.
Tania h... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n, m = map(int, input().split())
a = list(map(int, input().split()))
s = set(sorted(a))
t = []
for i in range(1, pow(10, 6)):
if i > m:
break
if not i in s:
t.append(i)
m -= i
k = len(... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
979 | B | Treasure Hunt | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | After the big birthday party, Katie still wanted Shiro to have some more fun. Later, she came up with a game called treasure hunt. Of course, she invited her best friends Kuro and Shiro to play with her.
The three friends are very smart so they passed all the challenges very quickly and finally reached the destination... | The first line contains an integer $n$ ($0 \leq n \leq 10^{9}$) — the number of turns.
Next 3 lines contain 3 ribbons of Kuro, Shiro and Katie one per line, respectively. Each ribbon is a string which contains no more than $10^{5}$ uppercase and lowercase Latin letters and is not empty. It is guaranteed that the lengt... | Print the name of the winner ("Kuro", "Shiro" or "Katie"). If there are at least two cats that share the maximum beauty, print "Draw". | [
"3\nKuroo\nShiro\nKatie\n",
"7\ntreasurehunt\nthreefriends\nhiCodeforces\n",
"1\nabcabc\ncbabac\nababca\n",
"15\nfoPaErcvJ\nmZaxowpbt\nmkuOlaHRE\n"
] | [
"Kuro\n",
"Shiro\n",
"Katie\n",
"Draw\n"
] | In the first example, after $3$ turns, Kuro can change his ribbon into ooooo, which has the beauty of $5$, while reaching such beauty for Shiro and Katie is impossible (both Shiro and Katie can reach the beauty of at most $4$, for example by changing Shiro's ribbon into SSiSS and changing Katie's ribbon into Kaaaa). Th... | 1,000 | [
{
"input": "3\nKuroo\nShiro\nKatie",
"output": "Kuro"
},
{
"input": "7\ntreasurehunt\nthreefriends\nhiCodeforces",
"output": "Shiro"
},
{
"input": "1\nabcabc\ncbabac\nababca",
"output": "Katie"
},
{
"input": "15\nfoPaErcvJ\nmZaxowpbt\nmkuOlaHRE",
"output": "Draw"
},
{... | 1,676,727,514 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 102,400 | from sys import stdin ,stdout
input=stdin.readline
from collections import Counter , defaultdict
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
n= int(input()) ; ku=sh=ka=n ; a=input().strip() ; lenth=len(a) ; c1=Counter(a) ; c2=Counter(input().strip()) ; c3=Cou... | Title: Treasure Hunt
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the big birthday party, Katie still wanted Shiro to have some more fun. Later, she came up with a game called treasure hunt. Of course, she invited her best friends Kuro and Shiro to play with her.
The three friend... | ```python
from sys import stdin ,stdout
input=stdin.readline
from collections import Counter , defaultdict
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
n= int(input()) ; ku=sh=ka=n ; a=input().strip() ; lenth=len(a) ; c1=Counter(a) ; c2=Counter(input().strip()... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,683,440,392 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 31 | 0 | n=int(input())
c=0
while True:
if n==1:
print(c+1)
break
else:
if n%2==1:
c+=1
n=n-1
else:
n=n//2
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
n=int(input())
c=0
while True:
if n==1:
print(c+1)
break
else:
if n%2==1:
c+=1
n=n-1
else:
n=n//2
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,643,033,361 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 104 | 109 | 0 | from math import ceil
n,m=map(int,input().split())
if n in {1,3,5,7,8,10,12}:
days=31
c=1
days-=8-m
c+=ceil(days/7)
elif n in {4,6,9,11}:
days=30
c=1
days-=8-m
c+=ceil(days/7)
else :
days=28
c=1
days-=8-m
c+=ceil(days/7)
print(c) | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
from math import ceil
n,m=map(int,input().split())
if n in {1,3,5,7,8,10,12}:
days=31
c=1
days-=8-m
c+=ceil(days/7)
elif n in {4,6,9,11}:
days=30
c=1
days-=8-m
c+=ceil(days/7)
else :
days=28
c=1
days-=8-m
c+=ceil(days/7)
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,675,221,635 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 46 | 0 | a,b=input(),input()
for i in range(len(a)):
if a[i]==b[i]:
c='0'
else:
c='1'
print(c,end='') | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
a,b=input(),input()
for i in range(len(a)):
if a[i]==b[i]:
c='0'
else:
c='1'
print(c,end='')
``` | 3.9885 | MatrixStudio/Codeforces-Python-Submissions |
757 | B | Bash's Big Day | PROGRAMMING | 1,400 | [
"greedy",
"math",
"number theory"
] | null | null | Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases.
But Zulu warns him that a group of *k*<=><=1 Pokemon with strengths {*... | The input consists of two lines.
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105), the number of Pokemon in the lab.
The next line contains *n* space separated integers, where the *i*-th of them denotes *s**i* (1<=≤<=*s**i*<=≤<=105), the strength of the *i*-th Pokemon. | Print single integer — the maximum number of Pokemons Bash can take. | [
"3\n2 3 4\n",
"5\n2 3 4 6 7\n"
] | [
"2\n",
"3\n"
] | *gcd* (greatest common divisor) of positive integers set {*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>} is the maximum positive integer that divides all the integers {*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a... | 1,000 | [
{
"input": "3\n2 3 4",
"output": "2"
},
{
"input": "5\n2 3 4 6 7",
"output": "3"
},
{
"input": "3\n5 6 4",
"output": "2"
},
{
"input": "8\n41 74 4 27 85 39 100 36",
"output": "4"
},
{
"input": "6\n89 20 86 81 62 23",
"output": "3"
},
{
"input": "71\n23... | 1,541,917,737 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 124 | 307,200 | import sys
from math import sqrt
n = int(input())
a = sys.stdin.readline().split()
s = [0]*100001
for i in range(n):
s[int(a[i])] = int(a[i])
mx= -1
q = 0
for i in range(2, 100001):
if s[i] != 0:
q = 0
for j in range(i, 100001, i):
if s[j] != 0:
... | Title: Bash's Big Day
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon fr... | ```python
import sys
from math import sqrt
n = int(input())
a = sys.stdin.readline().split()
s = [0]*100001
for i in range(n):
s[int(a[i])] = int(a[i])
mx= -1
q = 0
for i in range(2, 100001):
if s[i] != 0:
q = 0
for j in range(i, 100001, i):
if s[j] != 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
560 | A | Currency System in Geraldion | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of ea... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes. | Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1. | [
"5\n1 2 3 4 5\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "10\n371054 506438 397130 1 766759 208409 769264 549213 641270 771837",
"output": "-1"
},
{
"input": "10\n635370 154890 909382 220996 276501 716105 538714 140162 171960 271264",
"o... | 1,689,396,678 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 16 | 62 | 0 | _ = input()
lst = list(map(int, input().split()))
print(-1 if 1 in lst else 1) | Title: Currency System in Geraldion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cann... | ```python
_ = input()
lst = list(map(int, input().split()))
print(-1 if 1 in lst else 1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
707 | B | Bakery | PROGRAMMING | 1,300 | [
"graphs"
] | null | null | Masha wants to open her own bakery and bake muffins in one of the *n* cities numbered from 1 to *n*. There are *m* bidirectional roads, each of whose connects some pair of cities.
To bake muffins in her bakery, Masha needs to establish flour supply from some storage. There are only *k* storages, located in different c... | The first line of the input contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=105, 0<=≤<=*k*<=≤<=*n*) — the number of cities in country Masha lives in, the number of roads between them and the number of flour storages respectively.
Then *m* lines follow. Each of them contains three integers *u*, *v* and *l... | Print the minimum possible amount of rubles Masha should pay for flour delivery in the only line.
If the bakery can not be opened (while satisfying conditions) in any of the *n* cities, print <=-<=1 in the only line. | [
"5 4 2\n1 2 5\n1 2 3\n2 3 4\n1 4 10\n1 5\n",
"3 1 1\n1 2 3\n3\n"
] | [
"3",
"-1"
] | Image illustrates the first sample case. Cities with storage located in and the road representing the answer are darkened. | 1,000 | [
{
"input": "5 4 2\n1 2 5\n1 2 3\n2 3 4\n1 4 10\n1 5",
"output": "3"
},
{
"input": "3 1 1\n1 2 3\n3",
"output": "-1"
},
{
"input": "2 3 1\n1 2 3\n1 2 18\n1 2 13\n2",
"output": "3"
},
{
"input": "3 7 0\n1 3 9\n1 2 5\n1 2 21\n1 2 12\n1 2 13\n2 3 19\n2 3 8",
"output": "-1"
... | 1,681,666,082 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 499 | 15,257,600 | n,m,k = map(int,input().split())
l = []
for i in range(m):
a,b,c = map(int,input().split())
l.append((a,b,c))
seen = set()
if k>0:
l1 = list(map(int,input().split()))
for i in l1:
seen.add(i)
mn = float('inf')
f = -1
for a,b,c in l:
if (a in seen and b not in seen) or (b in s... | Title: Bakery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Masha wants to open her own bakery and bake muffins in one of the *n* cities numbered from 1 to *n*. There are *m* bidirectional roads, each of whose connects some pair of cities.
To bake muffins in her bakery, Masha needs to e... | ```python
n,m,k = map(int,input().split())
l = []
for i in range(m):
a,b,c = map(int,input().split())
l.append((a,b,c))
seen = set()
if k>0:
l1 = list(map(int,input().split()))
for i in l1:
seen.add(i)
mn = float('inf')
f = -1
for a,b,c in l:
if (a in seen and b not in seen) ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | B | Hard Work | PROGRAMMING | 1,300 | [
"strings"
] | B. Hard Work | 2 | 256 | After the contest in comparing numbers, Shapur's teacher found out that he is a real genius and that no one could possibly do the calculations faster than him even using a super computer!
Some days before the contest, the teacher took a very simple-looking exam and all his *n* students took part in the exam. The teach... | The first three lines contain a string each. These are the initial strings. They consists only of lowercase and uppercase Latin letters and signs ("-", ";" and "_"). All the initial strings have length from 1 to 100, inclusively.
In the fourth line there is a single integer *n* (0<=≤<=*n*<=≤<=1000), the number of stud... | For each student write in a different line. Print "WA" if his answer is wrong or "ACC" if his answer is OK. | [
"Iran_\nPersian;\nW_o;n;d;e;r;f;u;l;\n7\nWonderfulPersianIran\nwonderful_PersIAN_IRAN;;_\nWONDERFUL___IRAN__PERSIAN__;;\nIra__Persiann__Wonderful\nWonder;;fulPersian___;I;r;a;n;\n__________IranPersianWonderful__________\nPersianIran_is_Wonderful\n",
"Shapur;;\nis___\na_genius\n3\nShapur__a_is___geniUs\nis___shapu... | [
"ACC\nACC\nACC\nWA\nACC\nACC\nWA\n",
"WA\nACC\nACC\n"
] | none | 1,000 | [
{
"input": "Iran_\nPersian;\nW_o;n;d;e;r;f;u;l;\n7\nWonderfulPersianIran\nwonderful_PersIAN_IRAN;;_\nWONDERFUL___IRAN__PERSIAN__;;\nIra__Persiann__Wonderful\nWonder;;fulPersian___;I;r;a;n;\n__________IranPersianWonderful__________\nPersianIran_is_Wonderful",
"output": "ACC\nACC\nACC\nWA\nACC\nACC\nWA"
},
... | 1,642,636,100 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 218 | 11,878,400 | #! /usr/bin/env python3
import sys
import re
import itertools
def main():
inpt = []
str_list = []
answers = []
for line in sys.stdin:
inpt.append(line.rstrip("\n"))
str_list = [re.sub("[-_;]", "", word).lower() for word in inpt[:3]]
answers = [re.sub("[-_;]", "", word).lower() for wor... | Title: Hard Work
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
After the contest in comparing numbers, Shapur's teacher found out that he is a real genius and that no one could possibly do the calculations faster than him even using a super computer!
Some days before the contest, the teache... | ```python
#! /usr/bin/env python3
import sys
import re
import itertools
def main():
inpt = []
str_list = []
answers = []
for line in sys.stdin:
inpt.append(line.rstrip("\n"))
str_list = [re.sub("[-_;]", "", word).lower() for word in inpt[:3]]
answers = [re.sub("[-_;]", "", word).lower... | 3.923375 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,601,279,082 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 216 | 0 | # -*- coding: utf-8 -*-
"""
Created on Mon Sep 28 13:11:51 2020
@author: PREET MODH
"""
s=input()
countl=0
countu=0
for i in s:
if(i.islower()):
countl=countl+1
elif(i.isupper()):
countu=countu+1
if countu>countl:
print(s.upper())
else:
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
# -*- coding: utf-8 -*-
"""
Created on Mon Sep 28 13:11:51 2020
@author: PREET MODH
"""
s=input()
countl=0
countu=0
for i in s:
if(i.islower()):
countl=countl+1
elif(i.isupper()):
countu=countu+1
if countu>countl:
print(s.upper())
else:
print(s... | 3.946 | MatrixStudio/Codeforces-Python-Submissions |
37 | D | Lesson Timetable | PROGRAMMING | 2,300 | [
"combinatorics",
"dp",
"math"
] | D. Lesson Timetable | 1 | 256 | When Petya has free from computer games time, he attends university classes. Every day the lessons on Petya’s faculty consist of two double classes. The floor where the lessons take place is a long corridor with *M* classrooms numbered from 1 to *M*, situated along it.
All the students of Petya’s year are divided into... | The first line contains one integer *M* (1<=≤<=*M*<=≤<=100) — the number of classrooms.
The second line contains *M* space-separated integers — *X**i* (0<=≤<=*X**i*<=≤<=100) the amount of groups present in classroom *i* during the first lesson.
The third line contains *M* space-separated integers — *Y**i* (0<=≤<=*Y**... | In the single line output the answer to the problem modulo 109<=+<=7. | [
"3\n1 1 1\n1 2 3\n",
"3\n1 1 1\n1 1 1\n"
] | [
"36\n",
"6\n"
] | In the second sample test the first and the second lessons of each group must take place in the same classroom, that’s why the timetables will only be different in the rearrangement of the classrooms’ numbers for each group, e.g. 3! = 6. | 2,000 | [
{
"input": "3\n1 1 1\n1 2 3",
"output": "36"
},
{
"input": "3\n1 1 1\n1 1 1",
"output": "6"
},
{
"input": "3\n2 1 1\n5 1 2",
"output": "72"
},
{
"input": "5\n2 1 1 1 1\n5 3 1 1 3",
"output": "49320"
},
{
"input": "5\n1 3 15 3 18\n2 6 18 5 19",
"output": "92148... | 1,691,285,686 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | print("_RANDOM_GUESS_1691285685.9755578")# 1691285685.9755776 | Title: Lesson Timetable
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
When Petya has free from computer games time, he attends university classes. Every day the lessons on Petya’s faculty consist of two double classes. The floor where the lessons take place is a long corridor with *M* classr... | ```python
print("_RANDOM_GUESS_1691285685.9755578")# 1691285685.9755776
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should b... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right aft... | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,650,306,283 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 6,963,200 | n = int(input())
guardar = []
respostas = []
l = [int(value) for value in input().split()]
base = n
for i in range(n):
if l[i] == base:
guardar.append(l[i])
guardar = sorted(guardar, reverse=True)
base_aux = base
guardar_aux = []
j = guardar[0]
whi... | Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents sh... | ```python
n = int(input())
guardar = []
respostas = []
l = [int(value) for value in input().split()]
base = n
for i in range(n):
if l[i] == base:
guardar.append(l[i])
guardar = sorted(guardar, reverse=True)
base_aux = base
guardar_aux = []
j = guardar[0]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
14 | B | Young Photographer | PROGRAMMING | 1,000 | [
"implementation"
] | B. Young Photographer | 2 | 64 | Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. But the problem was that not all the runners passed him. The total amount of sportsmen, training at t... | The first line of the input file contains integers *n* and *x*0 (1<=≤<=*n*<=≤<=100; 0<=≤<=*x*0<=≤<=1000). The following *n* lines contain pairs of integers *a**i*,<=*b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000; *a**i*<=≠<=*b**i*). | Output the required minimum distance in the same units as the positions on the racetrack. If there is no such a position, output -1. | [
"3 3\n0 7\n14 2\n4 6\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "3 3\n0 7\n14 2\n4 6",
"output": "1"
},
{
"input": "1 1\n0 10",
"output": "0"
},
{
"input": "2 2\n1 2\n3 2",
"output": "0"
},
{
"input": "3 2\n1 2\n2 3\n3 4",
"output": "-1"
},
{
"input": "2 4\n10 4\n1 5",
"output": "0"
},
{
"input": "1 10\n... | 1,682,805,986 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 154 | 0 | alpha = input().split()
n = int(alpha[0])
x = int(alpha[1])
s = []
r = -1
flag = False
true_list = ""
for i in range(n):
beta = input().split()
beta = [int(c) for c in beta]
s.append([i for i in range(min(beta), max(beta) + 1)])
print(s)
for c in range(len(s)):
if x not in s[c]:
tr... | Title: Young Photographer
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. Bu... | ```python
alpha = input().split()
n = int(alpha[0])
x = int(alpha[1])
s = []
r = -1
flag = False
true_list = ""
for i in range(n):
beta = input().split()
beta = [int(c) for c in beta]
s.append([i for i in range(min(beta), max(beta) + 1)])
print(s)
for c in range(len(s)):
if x not in s[c]:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,641,584,851 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n = int(input())
if n == 1:
print(-1)
else:
x = [2]
i = 1
while i<n:
if i%2 == 0:
x.append(i+2)
else:
x.append(i)
i+=1
for i in x:
print(i, end = " ") | Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
n = int(input())
if n == 1:
print(-1)
else:
x = [2]
i = 1
while i<n:
if i%2 == 0:
x.append(i+2)
else:
x.append(i)
i+=1
for i in x:
print(i, end = " ")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,616,953,669 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 10,240,000 | import sys
inp = sys.stdin.readlines(); ii = 0
out = []
n, k = map(int, inp[ii].split())
ii += 1
nums = [int(bruh) for bruh in inp[ii].split()]
ii += 1
times = 0
if len(set(nums)) == 1:
print(times)
exit()
for sim in range(n):
nums.append(nums[k-1])
del nums[0]
times += 1
... | Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
import sys
inp = sys.stdin.readlines(); ii = 0
out = []
n, k = map(int, inp[ii].split())
ii += 1
nums = [int(bruh) for bruh in inp[ii].split()]
ii += 1
times = 0
if len(set(nums)) == 1:
print(times)
exit()
for sim in range(n):
nums.append(nums[k-1])
del nums[0]
ti... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
134 | B | Pairs of Numbers | PROGRAMMING | 1,900 | [
"brute force",
"dfs and similar",
"math",
"number theory"
] | null | null | Let's assume that we have a pair of numbers (*a*,<=*b*). We can get a new pair (*a*<=+<=*b*,<=*b*) or (*a*,<=*a*<=+<=*b*) from the given pair in a single step.
Let the initial pair of numbers be (1,1). Your task is to find number *k*, that is, the least number of steps needed to transform (1,1) into the pair where at ... | The input contains the only integer *n* (1<=≤<=*n*<=≤<=106). | Print the only integer *k*. | [
"5\n",
"1\n"
] | [
"3\n",
"0\n"
] | The pair (1,1) can be transformed into a pair containing 5 in three moves: (1,1) → (1,2) → (3,2) → (5,2). | 1,000 | [
{
"input": "5",
"output": "3"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "10",
"output": "5"
},
{
"input": "1009",
"output": "15"
}... | 1,378,398,645 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n = input()
H = dict()
inf = 10000000
def number (n,b):
s = 0
while b>1:
s += n/b
n,b = b,n%b
if b==1: return s+n-1
else: return inf
m = inf
for b in range(1,(n+1)/2+1):
m = min (number(n,b),m)
print m
| Title: Pairs of Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's assume that we have a pair of numbers (*a*,<=*b*). We can get a new pair (*a*<=+<=*b*,<=*b*) or (*a*,<=*a*<=+<=*b*) from the given pair in a single step.
Let the initial pair of numbers be (1,1). Your task is to... | ```python
n = input()
H = dict()
inf = 10000000
def number (n,b):
s = 0
while b>1:
s += n/b
n,b = b,n%b
if b==1: return s+n-1
else: return inf
m = inf
for b in range(1,(n+1)/2+1):
m = min (number(n,b),m)
print m
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
787 | A | The Monster | PROGRAMMING | 1,200 | [
"brute force",
"math",
"number theory"
] | null | null | A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams at times *d*,<=*d*<=+<=*c*,<=*d*<=+<=2*c*,<=*d*<=+<=3*c*,<=....
The Monster will catch them if a... | The first line of input contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100).
The second line contains two integers *c* and *d* (1<=≤<=*c*,<=*d*<=≤<=100). | Print the first time Rick and Morty will scream at the same time, or <=-<=1 if they will never scream at the same time. | [
"20 2\n9 19\n",
"2 1\n16 12\n"
] | [
"82\n",
"-1\n"
] | In the first sample testcase, Rick's 5th scream and Morty's 8th time are at time 82.
In the second sample testcase, all Rick's screams will be at odd times and Morty's will be at even times, so they will never scream at the same time. | 500 | [
{
"input": "20 2\n9 19",
"output": "82"
},
{
"input": "2 1\n16 12",
"output": "-1"
},
{
"input": "39 52\n88 78",
"output": "1222"
},
{
"input": "59 96\n34 48",
"output": "1748"
},
{
"input": "87 37\n91 29",
"output": "211"
},
{
"input": "11 81\n49 7",
... | 1,675,949,537 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 46 | 0 | a,b = list(map(int, input().split()))
c,d = list(map(int, input().split()))
for i in range(101):
j = (b + a*i - d) *1.0/c
if j>=0 and j==int(j):
print(b + a*i)
exit()
print(-1) | Title: The Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams a... | ```python
a,b = list(map(int, input().split()))
c,d = list(map(int, input().split()))
for i in range(101):
j = (b + a*i - d) *1.0/c
if j>=0 and j==int(j):
print(b + a*i)
exit()
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
593 | B | Anton and Lines | PROGRAMMING | 1,600 | [
"geometry",
"sortings"
] | null | null | The teacher gave Anton a large geometry homework, but he didn't do it (as usual) as he participated in a regular round on Codeforces. In the task he was given a set of *n* lines defined by the equations *y*<==<=*k**i*·*x*<=+<=*b**i*. It was necessary to determine whether there is at least one point of intersection of t... | The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of lines in the task given to Anton. The second line contains integers *x*1 and *x*2 (<=-<=1<=000<=000<=≤<=*x*1<=<<=*x*2<=≤<=1<=000<=000) defining the strip inside which you need to find a point of intersection of at least two ... | Print "Yes" (without quotes), if there is at least one intersection of two distinct lines, located strictly inside the strip. Otherwise print "No" (without quotes). | [
"4\n1 2\n1 2\n1 0\n0 1\n0 2\n",
"2\n1 3\n1 0\n-1 3\n",
"2\n1 3\n1 0\n0 2\n",
"2\n1 3\n1 0\n0 3\n"
] | [
"NO",
"YES",
"YES",
"NO"
] | In the first sample there are intersections located on the border of the strip, but there are no intersections located strictly inside it. | 1,000 | [
{
"input": "4\n1 2\n1 2\n1 0\n0 1\n0 2",
"output": "NO"
},
{
"input": "2\n1 3\n1 0\n-1 3",
"output": "YES"
},
{
"input": "2\n1 3\n1 0\n0 2",
"output": "YES"
},
{
"input": "2\n1 3\n1 0\n0 3",
"output": "NO"
},
{
"input": "2\n0 1\n-1000000 1000000\n1000000 -1000000"... | 1,536,067,764 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 15 | 998 | 268,390,400 | from itertools import combinations
ada=False
def intersect(k1, k2, b1, b2):
global x1, x2
if(k1==k2):
if(b2==b1):
return True
else:
return False
if((b2-b1)/(k1-k2)>x1) and ((b2-b1)/(k1-k2)<x2):
return True
n=int(input())
apapun=input().split()
x1=int(apapun[0])
x2=int(apapun[1])
k=[]
b=[]
dummy=[]
for i... | Title: Anton and Lines
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The teacher gave Anton a large geometry homework, but he didn't do it (as usual) as he participated in a regular round on Codeforces. In the task he was given a set of *n* lines defined by the equations *y*<==<=*k**i*·*... | ```python
from itertools import combinations
ada=False
def intersect(k1, k2, b1, b2):
global x1, x2
if(k1==k2):
if(b2==b1):
return True
else:
return False
if((b2-b1)/(k1-k2)>x1) and ((b2-b1)/(k1-k2)<x2):
return True
n=int(input())
apapun=input().split()
x1=int(apapun[0])
x2=int(apapun[1])
k=[]
b=[]
dumm... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
672 | A | Summer Camp | PROGRAMMING | 800 | [
"implementation"
] | null | null | Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1 are written in one line. The prefix of these line is "123456789101112131415...". Your task is to... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the position of the digit you need to print. | Print the *n*-th digit of the line. | [
"3\n",
"11\n"
] | [
"3\n",
"0\n"
] | In the first sample the digit at position 3 is '3', as both integers 1 and 2 consist on one digit.
In the second sample, the digit at position 11 is '0', it belongs to the integer 10. | 500 | [
{
"input": "3",
"output": "3"
},
{
"input": "11",
"output": "0"
},
{
"input": "12",
"output": "1"
},
{
"input": "13",
"output": "1"
},
{
"input": "29",
"output": "9"
},
{
"input": "30",
"output": "2"
},
{
"input": "1000",
"output": "3"
... | 1,592,503,768 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 124 | 0 | a=int(input())
fin=""
for i in range(1,a+1):
fin+=str(i)
print(fin[a-1]) | Title: Summer Camp
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1... | ```python
a=int(input())
fin=""
for i in range(1,a+1):
fin+=str(i)
print(fin[a-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
496 | B | Secret Combination | PROGRAMMING | 1,500 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | You got a box with a combination lock. The lock has a display showing *n* digits. There are two buttons on the box, each button changes digits on the display. You have quickly discovered that the first button adds 1 to all the digits (all digits 9 become digits 0), and the second button shifts all the digits on the dis... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits on the display.
The second line contains *n* digits — the initial state of the display. | Print a single line containing *n* digits — the desired state of the display containing the smallest possible number. | [
"3\n579\n",
"4\n2014\n"
] | [
"024\n",
"0142\n"
] | none | 1,000 | [
{
"input": "3\n579",
"output": "024"
},
{
"input": "4\n2014",
"output": "0142"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "3\n039",
"output": "014"
},
{
"input": "4\n4444",
"output": "0000"
},
{
"input": "5\n46802",
"output": "02468"
},
... | 1,636,096,795 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 4,505,600 | a=input()
i=10000
t=[]
if int(a[1])==0:
i=int(a[1:]+a[0])
for j in range(0,len(a)):
t.append((a[j]))
while 1:
if int(t[0])==0:
break
for j in range(len(a)):
if int(t[j])+1==10:
t[j]=str(0)
else:
t[j]=str(int(t[j])+1)
g="".join(t)
prin... | Title: Secret Combination
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You got a box with a combination lock. The lock has a display showing *n* digits. There are two buttons on the box, each button changes digits on the display. You have quickly discovered that the first button adds 1 ... | ```python
a=input()
i=10000
t=[]
if int(a[1])==0:
i=int(a[1:]+a[0])
for j in range(0,len(a)):
t.append((a[j]))
while 1:
if int(t[0])==0:
break
for j in range(len(a)):
if int(t[j])+1==10:
t[j]=str(0)
else:
t[j]=str(int(t[j])+1)
g="".joi... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
352 | B | Jeff and Periods | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
- *x* occurs in sequence *a*. - Consider all positions of numbers *x* in the sequence *a* (such *i*, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). The numbers are separated by spaces. | In the first line print integer *t* — the number of valid *x*. On each of the next *t* lines print two integers *x* and *p**x*, where *x* is current suitable value, *p**x* is the common difference between numbers in the progression (if *x* occurs exactly once in the sequence, *p**x* must equal 0). Print the pairs in th... | [
"1\n2\n",
"8\n1 2 1 3 1 2 1 5\n"
] | [
"1\n2 0\n",
"4\n1 2\n2 4\n3 0\n5 0\n"
] | In the first test 2 occurs exactly once in the sequence, ergo *p*<sub class="lower-index">2</sub> = 0. | 1,000 | [
{
"input": "1\n2",
"output": "1\n2 0"
},
{
"input": "8\n1 2 1 3 1 2 1 5",
"output": "4\n1 2\n2 4\n3 0\n5 0"
},
{
"input": "3\n1 10 5",
"output": "3\n1 0\n5 0\n10 0"
},
{
"input": "4\n9 9 3 5",
"output": "3\n3 0\n5 0\n9 1"
},
{
"input": "6\n1 2 2 1 1 2",
"outpu... | 1,655,377,654 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | n=int(input())
lst=[int(x) for x in input().split()]
dic={}
for i in range(n):
m=lst[i]
if m in dic:
if dic[m][1]==0:
dic[m][1]=i-dic[m][0]
dic[m][0]=i
elif dic[m][1]>0:
if (i-dic[m][0])!=dic[m][1]:dic[m][1]=-1
else:dic[m][0]=i
else... | Title: Jeff and Periods
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
-... | ```python
n=int(input())
lst=[int(x) for x in input().split()]
dic={}
for i in range(n):
m=lst[i]
if m in dic:
if dic[m][1]==0:
dic[m][1]=i-dic[m][0]
dic[m][0]=i
elif dic[m][1]>0:
if (i-dic[m][0])!=dic[m][1]:dic[m][1]=-1
else:dic[m][0]=i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
190 | A | Vasya and the Bus | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant and he loves counting money. So he wondered what maximum and minimum sum of money these passengers cou... | The input file consists of a single line containing two space-separated numbers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=105) — the number of the grown-ups and the number of the children in the bus, correspondingly. | If *n* grown-ups and *m* children could have ridden in the bus, then print on a single line two space-separated integers — the minimum and the maximum possible total bus fare, correspondingly.
Otherwise, print "Impossible" (without the quotes). | [
"1 2\n",
"0 5\n",
"2 2\n"
] | [
"2 2",
"Impossible",
"2 3"
] | In the first sample a grown-up rides with two children and pays two rubles.
In the second sample there are only children in the bus, so the situation is impossible.
In the third sample there are two cases: - Each of the two grown-ups rides with one children and pays one ruble for the tickets. In this case the passen... | 500 | [
{
"input": "1 2",
"output": "2 2"
},
{
"input": "0 5",
"output": "Impossible"
},
{
"input": "2 2",
"output": "2 3"
},
{
"input": "2 7",
"output": "7 8"
},
{
"input": "4 10",
"output": "10 13"
},
{
"input": "6 0",
"output": "6 6"
},
{
"input... | 1,591,298,619 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 216 | 0 | g,c=map(int,input().split())
if g==0:
print('Impossible')
else:
print(max(c,g), g+c-1)
| Title: Vasya and the Bus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant... | ```python
g,c=map(int,input().split())
if g==0:
print('Impossible')
else:
print(max(c,g), g+c-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Alyona's mother wants to present an array of *n* non-negative integers to Alyona. The array should be special.
Alyona is a capricious girl so after she gets the array, she inspects *m* of its subarrays. Subarray is a set of some subsequent elements of the array. The *i*-th subarray is described with two integers *l**... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105).
The next *m* lines contain information about the subarrays chosen by Alyona. The *i*-th of these lines contains two integers *l**i* and *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*), that describe the subarray *a*[*l**i*],<=*a*[*l**i*<=+<=1],<=...,... | In the first line print single integer — the maximum possible minimum mex.
In the second line print *n* integers — the array *a*. All the elements in *a* should be between 0 and 109.
It is guaranteed that there is an optimal answer in which all the elements in *a* are between 0 and 109.
If there are multiple solutio... | [
"5 3\n1 3\n2 5\n4 5\n",
"4 2\n1 4\n2 4\n"
] | [
"2\n1 0 2 1 0\n",
"3\n5 2 0 1"
] | The first example: the mex of the subarray (1, 3) is equal to 3, the mex of the subarray (2, 5) is equal to 3, the mex of the subarray (4, 5) is equal to 2 as well, thus the minumal mex among the subarrays chosen by Alyona is equal to 2. | 0 | [
{
"input": "5 3\n1 3\n2 5\n4 5",
"output": "2\n0 1 0 1 0"
},
{
"input": "4 2\n1 4\n2 4",
"output": "3\n0 1 2 0"
},
{
"input": "1 1\n1 1",
"output": "1\n0"
},
{
"input": "2 1\n2 2",
"output": "1\n0 0"
},
{
"input": "5 6\n2 4\n2 3\n1 4\n3 4\n2 5\n1 3",
"output":... | 1,679,435,756 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | nm = input()
nmnew = nm.split(' ')
n = int(nmnew[0])
m = int(nmnew[1])
lr = []
for i in range(m):
new = input()
aaa = new
aaa = new.split(' ')
newl = int(aaa[0])
newr = int(aaa[1])
bbb = [newl, newr]
lr.append(bbb)
largo = 20*n
answer = ""
for j in lr:
L =... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alyona's mother wants to present an array of *n* non-negative integers to Alyona. The array should be special.
Alyona is a capricious girl so after she gets the array, she inspects *m* of its subarrays. Subarray is a set of some... | ```python
nm = input()
nmnew = nm.split(' ')
n = int(nmnew[0])
m = int(nmnew[1])
lr = []
for i in range(m):
new = input()
aaa = new
aaa = new.split(' ')
newl = int(aaa[0])
newr = int(aaa[1])
bbb = [newl, newr]
lr.append(bbb)
largo = 20*n
answer = ""
for j in lr... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
120 | C | Winnie-the-Pooh and honey | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | As we all know, Winnie-the-Pooh just adores honey. Ones he and the Piglet found out that the Rabbit has recently gotten hold of an impressive amount of this sweet and healthy snack. As you may guess, Winnie and the Piglet asked to come at the Rabbit's place. Thus, there are *n* jars of honey lined up in front of Winnie... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100). The second line contains *n* integers *a*1, *a*2, ..., *a**n*, separated by spaces (1<=≤<=*a**i*<=≤<=100). | Print a single number — how many kilos of honey gets Piglet. | [
"3 3\n15 8 10\n"
] | [
"9\n"
] | none | 0 | [
{
"input": "3 3\n15 8 10",
"output": "9"
},
{
"input": "1 3\n3",
"output": "0"
},
{
"input": "3 4\n3 8 2",
"output": "5"
},
{
"input": "3 2\n95 25 49",
"output": "151"
},
{
"input": "3 1\n8 3 2",
"output": "5"
},
{
"input": "5 1\n4 7 9 5 7",
"outpu... | 1,675,112,740 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 122 | 2,764,800 | n,k=map(int,input().split())
ll=list(map(int,input().split()))
count=sum(ll)
for _ in ll:
for t in range(3,0,-1):
if _>=t*k:
count-=t*k
break
print(count) | Title: Winnie-the-Pooh and honey
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As we all know, Winnie-the-Pooh just adores honey. Ones he and the Piglet found out that the Rabbit has recently gotten hold of an impressive amount of this sweet and healthy snack. As you may guess, Winnie an... | ```python
n,k=map(int,input().split())
ll=list(map(int,input().split()))
count=sum(ll)
for _ in ll:
for t in range(3,0,-1):
if _>=t*k:
count-=t*k
break
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
629 | A | Far Relative’s Birthday Cake | PROGRAMMING | 800 | [
"brute force",
"combinatorics",
"constructive algorithms",
"implementation"
] | null | null | Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with side length 1. Each square is either empty or consists of a single chocolate. They bought the cake and randomly sta... | In the first line of the input, you are given a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the side of the cake.
Then follow *n* lines, each containing *n* characters. Empty cells are denoted with '.', while cells that contain chocolates are denoted by 'C'. | Print the value of Famil Door's happiness, i.e. the number of pairs of chocolate pieces that share the same row or the same column. | [
"3\n.CC\nC..\nC.C\n",
"4\nCC..\nC..C\n.CC.\n.CC.\n"
] | [
"4\n",
"9\n"
] | If we number rows from top to bottom and columns from left to right, then, pieces that share the same row in the first sample are:
1. (1, 2) and (1, 3) 1. (3, 1) and (3, 3) 1. (2, 1) and (3, 1) 1. (1, 3) and (3, 3) | 500 | [
{
"input": "3\n.CC\nC..\nC.C",
"output": "4"
},
{
"input": "4\nCC..\nC..C\n.CC.\n.CC.",
"output": "9"
},
{
"input": "5\n.CCCC\nCCCCC\n.CCC.\nCC...\n.CC.C",
"output": "46"
},
{
"input": "7\n.CC..CC\nCC.C..C\nC.C..C.\nC...C.C\nCCC.CCC\n.CC...C\n.C.CCC.",
"output": "84"
},... | 1,666,778,304 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 156 | 0 | import math
case= int(input())
ll=[]
for i in range(case):
row=list(input())
ll.append(row)
r=0
for i in ll:
if i.count("C")>1:
r+=math.comb(i.count("C"),2)
v=0
for i in range(case-1):
for t in range(i+1,case):
for a in range(case):
if ll[i][a]=="C" and ll[i][... | Title: Far Relative’s Birthday Cake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with s... | ```python
import math
case= int(input())
ll=[]
for i in range(case):
row=list(input())
ll.append(row)
r=0
for i in ll:
if i.count("C")>1:
r+=math.comb(i.count("C"),2)
v=0
for i in range(case-1):
for t in range(i+1,case):
for a in range(case):
if ll[i][a]=="C" ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,692,644,945 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 92 | 0 | n = int(input())
elements = input().split()
elements = [int(x) for x in elements]
elements.sort(reverse=True)
res = 0
temp = 0
for k,e in enumerate(elements):
temp += e
res += 1
if temp > sum(elements[k+1:]):
break
print(res) | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
n = int(input())
elements = input().split()
elements = [int(x) for x in elements]
elements.sort(reverse=True)
res = 0
temp = 0
for k,e in enumerate(elements):
temp += e
res += 1
if temp > sum(elements[k+1:]):
break
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
607 | A | Chain Reaction | PROGRAMMING | 1,600 | [
"binary search",
"dp"
] | null | null | There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of decreasing coordinates) within distance *b**i* inclusive. The beacon itself is not destroyed however.... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the initial number of beacons.
The *i*-th of next *n* lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=1<=000<=000, 1<=≤<=*b**i*<=≤<=1<=000<=000) — the position and power level of the *i*-th beacon respectively. No two beac... | Print a single integer — the minimum number of beacons that could be destroyed if exactly one beacon is added. | [
"4\n1 9\n3 1\n6 1\n7 4\n",
"7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1\n"
] | [
"1\n",
"3\n"
] | For the first sample case, the minimum number of beacons destroyed is 1. One way to achieve this is to place a beacon at position 9 with power level 2.
For the second sample case, the minimum number of beacons destroyed is 3. One way to achieve this is to place a beacon at position 1337 with power level 42. | 500 | [
{
"input": "4\n1 9\n3 1\n6 1\n7 4",
"output": "1"
},
{
"input": "7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1",
"output": "3"
},
{
"input": "1\n0 1",
"output": "0"
},
{
"input": "1\n0 1000000",
"output": "0"
},
{
"input": "1\n1000000 1000000",
"output": "0"
},
{
... | 1,549,044,062 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 1,091 | 14,131,200 | from operator import itemgetter
n = int(input())
abi = [[-10**9,0]] + [list(map(int,input().split())) for i in range(n)]
abi.sort(key = itemgetter(0))
ar = [0] * (n+1)
ar[0] = 0
def check(pos,num):
#print(pos,num)
if abi[pos][0] < num:
return True
else:
return False
def binsearch... | Title: Chain Reaction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of d... | ```python
from operator import itemgetter
n = int(input())
abi = [[-10**9,0]] + [list(map(int,input().split())) for i in range(n)]
abi.sort(key = itemgetter(0))
ar = [0] * (n+1)
ar[0] = 0
def check(pos,num):
#print(pos,num)
if abi[pos][0] < num:
return True
else:
return False
def... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes acco... | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, an... | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,562,652,875 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 0 | n1=int(input())
n2=int(input())
if n1>n2:
c=n1
n1=n2
n2=c
c=0
p1=0
p2=0
s=0
while n1<n2:
if c%2==0:
n1+=1
p1+=1
s=s+p1
else:
n2-=1
p2+=1
s=s+p2
c+=1
print(s) | Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in... | ```python
n1=int(input())
n2=int(input())
if n1>n2:
c=n1
n1=n2
n2=c
c=0
p1=0
p2=0
s=0
while n1<n2:
if c%2==0:
n1+=1
p1+=1
s=s+p1
else:
n2-=1
p2+=1
s=s+p2
c+=1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,658,049,056 | 2,147,483,647 | Python 3 | OK | TESTS | 114 | 46 | 0 | b=int(input().split()[1]);c=input();print(["YES","NO"][max(c.count(i) for i in set(c))>b]) | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
b=int(input().split()[1]);c=input();print(["YES","NO"][max(c.count(i) for i in set(c))>b])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,692,174,106 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 12,697,600 | def maxSubArraySum(a,size):
max_so_far =a[0]
curr_max = a[0]
for i in range(1,size):
curr_max = max(a[i], curr_max + a[i])
max_so_far = max(max_so_far,curr_max)
return max_so_far
n, t = map(int, input().split())
arr = list(map(int, input().split()))
max_books = 0
for i in range(n):
... | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
def maxSubArraySum(a,size):
max_so_far =a[0]
curr_max = a[0]
for i in range(1,size):
curr_max = max(a[i], curr_max + a[i])
max_so_far = max(max_so_far,curr_max)
return max_so_far
n, t = map(int, input().split())
arr = list(map(int, input().split()))
max_books = 0
for i in rang... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,591,003,876 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | t=input()
s=""
for i in t:
if(i!=" "):
s+=i
k=list(s)
d=k[-2]
x={"aeiouyAEIOUY")
if(d not in x):
print("NO")
else:
print("YES") | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
t=input()
s=""
for i in t:
if(i!=" "):
s+=i
k=list(s)
d=k[-2]
x={"aeiouyAEIOUY")
if(d not in x):
print("NO")
else:
print("YES")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,690,901,817 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 248 | 7,884,800 | def count_groups_of_magnets(n, magnets):
count = 1
for i in range(1, n):
if magnets[i] != magnets[i - 1]:
count += 1
return count
n = int(input())
magnets = [input() for _ in range(n)]
result = count_groups_of_magnets(n, magnets)
print(result)
| Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
def count_groups_of_magnets(n, magnets):
count = 1
for i in range(1, n):
if magnets[i] != magnets[i - 1]:
count += 1
return count
n = int(input())
magnets = [input() for _ in range(n)]
result = count_groups_of_magnets(n, magnets)
print(result)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,513,952,538 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 154 | 5,632,000 | n,m=[int(i) for i in input().split()]
price=[int(i)*(-1) for i in input().split()]
lst=[]
for i in price:
if i>0:
lst.append(i)
lst.sort(reverse=True)
s=0
for i in range(min(len(lst),m)):
s+=lst[i]
print(s)
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m=[int(i) for i in input().split()]
price=[int(i)*(-1) for i in input().split()]
lst=[]
for i in price:
if i>0:
lst.append(i)
lst.sort(reverse=True)
s=0
for i in range(min(len(lst),m)):
s+=lst[i]
print(s)
``` | 3.95101 | MatrixStudio/Codeforces-Python-Submissions |
672 | B | Different is Good | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are different, he wants all substrings of his string *s* to be distinct. Substring is a string formed by some... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the string *s*.
The second line contains the string *s* of length *n* consisting of only lowercase English letters. | If it's impossible to change the string *s* such that all its substring are distinct print -1. Otherwise print the minimum required number of changes. | [
"2\naa\n",
"4\nkoko\n",
"5\nmurat\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko". | 1,000 | [
{
"input": "2\naa",
"output": "1"
},
{
"input": "4\nkoko",
"output": "2"
},
{
"input": "5\nmurat",
"output": "0"
},
{
"input": "6\nacbead",
"output": "1"
},
{
"input": "7\ncdaadad",
"output": "4"
},
{
"input": "25\npeoaicnbisdocqofsqdpgobpn",
"outp... | 1,631,320,876 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 61 | 6,758,400 | #672B (70No. Problem B)
n = int(input())
s = input()
t = 0
if (n > 26):
print(-1)
else:
for i in range(n):
for j in range(i+1,n):
if (s[i] == s[j]):
t+=1
print(t)
| Title: Different is Good
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are di... | ```python
#672B (70No. Problem B)
n = int(input())
s = input()
t = 0
if (n > 26):
print(-1)
else:
for i in range(n):
for j in range(i+1,n):
if (s[i] == s[j]):
t+=1
print(t)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
361 | A | Levko and Table | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortunately, he doesn't know any such table. Your task is to help him to find at least one of them. | The single line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). | Print any beautiful table. Levko doesn't like too big numbers, so all elements of the table mustn't exceed 1000 in their absolute value.
If there are multiple suitable tables, you are allowed to print any of them. | [
"2 4\n",
"4 7\n"
] | [
"1 3\n3 1\n",
"2 1 0 4\n4 0 2 1\n1 3 3 0\n0 3 2 2\n"
] | In the first sample the sum in the first row is 1 + 3 = 4, in the second row — 3 + 1 = 4, in the first column — 1 + 3 = 4 and in the second column — 3 + 1 = 4. There are other beautiful tables for this sample.
In the second sample the sum of elements in each row and each column equals 7. Besides, there are other table... | 500 | [
{
"input": "2 4",
"output": "4 0 \n0 4 "
},
{
"input": "4 7",
"output": "7 0 0 0 \n0 7 0 0 \n0 0 7 0 \n0 0 0 7 "
},
{
"input": "1 8",
"output": "8 "
},
{
"input": "9 3",
"output": "3 0 0 0 0 0 0 0 0 \n0 3 0 0 0 0 0 0 0 \n0 0 3 0 0 0 0 0 0 \n0 0 0 3 0 0 0 0 0 \n0 0 0 0 3 0... | 1,683,364,620 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n, k = map(int, input().split())
num = k//n
rem = k%n+1
ans = [[str(rem) if i==j else str(num) for j in range(n)] for i in range(n)]
for i in range(n):
print(" ".join(ans[i]))
| Title: Levko and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortun... | ```python
n, k = map(int, input().split())
num = k//n
rem = k%n+1
ans = [[str(rem) if i==j else str(num) for j in range(n)] for i in range(n)]
for i in range(n):
print(" ".join(ans[i]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
664 | A | Complicated GCD | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest in... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100). | Output one integer — greatest common divisor of all integers from *a* to *b* inclusive. | [
"1 2\n",
"61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n"
] | [
"1\n",
"61803398874989484820458683436563811772030917980576\n"
] | none | 500 | [
{
"input": "1 2",
"output": "1"
},
{
"input": "61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576",
"output": "61803398874989484820458683436563811772030917980576"
},
{
"input": "1 100",
"output": "1"
},
{
"input": "100 100000... | 1,635,920,685 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 1,000 | 4,505,600 | def nod_mod(a, b):
if b == 0:
return a
return nod_mod(b, a % b)
a, b = map(int, input().split())
if a != b:
for i in range(a + 1, b + 1):
ans = nod_mod(i, nod_mod(i, i - 1))
print(ans)
else:
print(a)
| Title: Complicated GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find gre... | ```python
def nod_mod(a, b):
if b == 0:
return a
return nod_mod(b, a % b)
a, b = map(int, input().split())
if a != b:
for i in range(a + 1, b + 1):
ans = nod_mod(i, nod_mod(i, i - 1))
print(ans)
else:
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
385 | C | Bear and Prime Numbers | PROGRAMMING | 1,700 | [
"binary search",
"brute force",
"data structures",
"dp",
"implementation",
"math",
"number theory"
] | null | null | Recently, the bear started studying data structures and faced the following problem.
You are given a sequence of integers *x*1,<=*x*2,<=...,<=*x**n* of length *n* and *m* queries, each of them is characterized by two integers *l**i*,<=*r**i*. Let's introduce *f*(*p*) to represent the number of such indexes *k*, that *... | The first line contains integer *n* (1<=≤<=*n*<=≤<=106). The second line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* (2<=≤<=*x**i*<=≤<=107). The numbers are not necessarily distinct.
The third line contains integer *m* (1<=≤<=*m*<=≤<=50000). Each of the following *m* lines contains a pair of space-separated integ... | Print *m* integers — the answers to the queries on the order the queries appear in the input. | [
"6\n5 5 7 10 14 15\n3\n2 11\n3 12\n4 4\n",
"7\n2 3 5 7 11 4 8\n2\n8 10\n2 123\n"
] | [
"9\n7\n0\n",
"0\n7\n"
] | Consider the first sample. Overall, the first sample has 3 queries.
1. The first query *l* = 2, *r* = 11 comes. You need to count *f*(2) + *f*(3) + *f*(5) + *f*(7) + *f*(11) = 2 + 1 + 4 + 2 + 0 = 9. 1. The second query comes *l* = 3, *r* = 12. You need to count *f*(3) + *f*(5) + *f*(7) + *f*(11) = 1 + 4 + 2 + 0 = 7.... | 1,500 | [
{
"input": "6\n5 5 7 10 14 15\n3\n2 11\n3 12\n4 4",
"output": "9\n7\n0"
},
{
"input": "7\n2 3 5 7 11 4 8\n2\n8 10\n2 123",
"output": "0\n7"
},
{
"input": "9\n50 50 50 50 50 50 50 50 50\n7\n20 20\n8 13\n13 13\n6 14\n3 5\n15 17\n341 1792",
"output": "0\n0\n0\n0\n9\n0\n0"
},
{
"... | 1,607,441,974 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 389 | 10,240,000 | import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right as br, bi... | Title: Bear and Prime Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, the bear started studying data structures and faced the following problem.
You are given a sequence of integers *x*1,<=*x*2,<=...,<=*x**n* of length *n* and *m* queries, each of them is characterized b... | ```python
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
356 | A | Knight Tournament | PROGRAMMING | 1,500 | [
"data structures",
"dsu"
] | null | null | Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tourname... | The first line contains two integers *n*, *m* (2<=≤<=*n*<=≤<=3·105; 1<=≤<=*m*<=≤<=3·105) — the number of knights and the number of fights. Each of the following *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*; *l**i*<=≤<=*x**i*<=≤<=*r**i*) — the description of the *i*-th f... | Print *n* integers. If the *i*-th knight lost, then the *i*-th number should equal the number of the knight that beat the knight number *i*. If the *i*-th knight is the winner, then the *i*-th number must equal 0. | [
"4 3\n1 2 1\n1 3 3\n1 4 4\n",
"8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1\n"
] | [
"3 1 4 0 ",
"0 8 4 6 4 8 6 1 "
] | Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won. | 500 | [
{
"input": "4 3\n1 2 1\n1 3 3\n1 4 4",
"output": "3 1 4 0 "
},
{
"input": "8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1",
"output": "0 8 4 6 4 8 6 1 "
},
{
"input": "2 1\n1 2 1",
"output": "0 1 "
},
{
"input": "2 1\n1 2 2",
"output": "2 0 "
},
{
"input": "3 1\n1 3 1",
"out... | 1,652,629,528 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 3,000 | 57,753,600 | knight,fight = map(int,input().split())
import math
number_nodes = 4*(knight)+1
seg_tree = [-1]*(number_nodes)
def SegmentTree (l,r,seg_tree,qleft,qright,vals,dic): # building segment tree
if l >= qleft and r<= qright:
if l==r :
if l == vals: return
if dic[l] == -1 :
... | Title: Knight Tournament
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're j... | ```python
knight,fight = map(int,input().split())
import math
number_nodes = 4*(knight)+1
seg_tree = [-1]*(number_nodes)
def SegmentTree (l,r,seg_tree,qleft,qright,vals,dic): # building segment tree
if l >= qleft and r<= qright:
if l==r :
if l == vals: return
if dic[l] == -... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
954 | D | Fight Against Traffic | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"shortest paths"
] | null | null | Little town Nsk consists of *n* junctions connected by *m* bidirectional roads. Each road connects two distinct junctions and no two roads connect the same pair of junctions. It is possible to get from any junction to any other junction by these roads. The distance between two junctions is equal to the minimum possible... | The firt line of the input contains integers *n*, *m*, *s* and *t* (2<=≤<=*n*<=≤<=1000, 1<=≤<=*m*<=≤<=1000, 1<=≤<=*s*,<=*t*<=≤<=*n*, *s*<=≠<=*t*) — the number of junctions and the number of roads in Nsk, as well as the indices of junctions where mayors home and work are located respectively. The *i*-th of the following... | Print one integer — the number of pairs of junctions not connected by a direct road, such that building a road between these two junctions won't decrease the distance between junctions *s* and *t*. | [
"5 4 1 5\n1 2\n2 3\n3 4\n4 5\n",
"5 4 3 5\n1 2\n2 3\n3 4\n4 5\n",
"5 6 1 5\n1 2\n1 3\n1 4\n4 5\n3 5\n2 5\n"
] | [
"0\n",
"5\n",
"3\n"
] | none | 0 | [
{
"input": "5 4 1 5\n1 2\n2 3\n3 4\n4 5",
"output": "0"
},
{
"input": "5 4 3 5\n1 2\n2 3\n3 4\n4 5",
"output": "5"
},
{
"input": "5 6 1 5\n1 2\n1 3\n1 4\n4 5\n3 5\n2 5",
"output": "3"
},
{
"input": "2 1 2 1\n1 2",
"output": "0"
},
{
"input": "3 2 2 3\n1 2\n2 3",
... | 1,638,106,276 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 998 | 57,139,200 | import sys
import math
from bisect import bisect_right as br
from collections import deque
#from decimal import Decimal
#from statistics import mode
from itertools import combinations as cb
def int_arr(): return list(map(int, sys.stdin.readline().strip().split()))
def str_arr(): return list(map(str... | Title: Fight Against Traffic
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little town Nsk consists of *n* junctions connected by *m* bidirectional roads. Each road connects two distinct junctions and no two roads connect the same pair of junctions. It is possible to get from any junctio... | ```python
import sys
import math
from bisect import bisect_right as br
from collections import deque
#from decimal import Decimal
#from statistics import mode
from itertools import combinations as cb
def int_arr(): return list(map(int, sys.stdin.readline().strip().split()))
def str_arr(): return li... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
417 | A | Elimination | PROGRAMMING | 1,500 | [
"dp",
"implementation",
"math"
] | null | null | The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination rounds consists of *c* problems, the winners of the round are the first *n* people in the rating list.... | The first line contains two integers *c* and *d* (1<=≤<=*c*,<=*d*<=≤<=100) — the number of problems in the main and additional rounds, correspondingly. The second line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Finally, the third line contains an integer *k* (1<=≤<=*k*<=≤<=100) — the number of the pre... | In the first line, print a single integer — the minimum number of problems the jury needs to prepare. | [
"1 10\n7 2\n1\n",
"2 2\n2 1\n2\n"
] | [
"2\n",
"0\n"
] | none | 500 | [
{
"input": "1 10\n7 2\n1",
"output": "2"
},
{
"input": "2 2\n2 1\n2",
"output": "0"
},
{
"input": "8 9\n2 2\n3",
"output": "8"
},
{
"input": "5 5\n8 8\n7",
"output": "40"
},
{
"input": "1 8\n8 10\n8",
"output": "9"
},
{
"input": "5 7\n9 1\n8",
"out... | 1,397,752,815 | 3,615 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 61 | 0 | c, d = map(int, input().split())
n, m = map(int, input().split())
p = 0
k = int(input())
if m*n <= k:
print(0)
else:
a = [0]*(m*n+1)
#a[k+1] = min(c,d)
for i in range(k+1,m*n+1):
if p == 0:
if d > c:
a[i] = a[i-1]+c
p = n-1
el... | Title: Elimination
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The finalists of the "Russian Code Cup" competition in 2214 will be the participants who win in one of the elimination rounds.
The elimination rounds are divided into main and additional. Each of the main elimination round... | ```python
c, d = map(int, input().split())
n, m = map(int, input().split())
p = 0
k = int(input())
if m*n <= k:
print(0)
else:
a = [0]*(m*n+1)
#a[k+1] = min(c,d)
for i in range(k+1,m*n+1):
if p == 0:
if d > c:
a[i] = a[i-1]+c
p = n-1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,586,153,619 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 0 | n,m=map(int,input().split())
r=(n+m)%5
mx=n+m-r
c=0
for i in range(1,n+1):
for j in range(5,mx+1,+5):
if j-i<=m and j-i>0:
c+=1
print(c) | Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
n,m=map(int,input().split())
r=(n+m)%5
mx=n+m-r
c=0
for i in range(1,n+1):
for j in range(5,mx+1,+5):
if j-i<=m and j-i>0:
c+=1
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
325 | A | Square and Rectangles | PROGRAMMING | 1,500 | [
"implementation"
] | null | null | You are given *n* rectangles. The corners of rectangles have integer coordinates and their edges are parallel to the *Ox* and *Oy* axes. The rectangles may touch each other, but they do not overlap (that is, there are no points that belong to the interior of more than one rectangle).
Your task is to determine if the ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=5). Next *n* lines contain four integers each, describing a single rectangle: *x*1, *y*1, *x*2, *y*2 (0<=≤<=*x*1<=<<=*x*2<=≤<=31400,<=0<=≤<=*y*1<=<<=*y*2<=≤<=31400) — *x*1 and *x*2 are *x*-coordinates of the left and right edges of the rectangle, and *y*... | In a single line print "YES", if the given rectangles form a square, or "NO" otherwise. | [
"5\n0 0 2 3\n0 3 3 5\n2 0 5 2\n3 2 5 5\n2 2 3 3\n",
"4\n0 0 2 3\n0 3 3 5\n2 0 5 2\n3 2 5 5\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n0 0 2 3\n0 3 3 5\n2 0 5 2\n3 2 5 5\n2 2 3 3",
"output": "YES"
},
{
"input": "4\n0 0 2 3\n0 3 3 5\n2 0 5 2\n3 2 5 5",
"output": "NO"
},
{
"input": "5\n0 0 10000 20000\n10000 0 15000 19999\n10000 19999 14999 20000\n0 20000 15000 31400\n15000 0 31400 31400",
"output": "NO... | 1,650,830,449 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | from itertools import *
n = int(input())
R = [list(map(int, input().split())) for _ in range(n)]
sx, sy, mx, my = 1e5, 1e5, 0, 0
for x1, y1, x2, y2 in R:
sx = min(sx, x1)
sy = min(sy, y1)
mx = max(mx, x2)
my = max(my, y2)
if mx-sx!=my-sy:
print("NO")
exit(0)
A = (mx-sx)*(my-sy)
for x1, y1, x2, y2 in R:
A -= (x... | Title: Square and Rectangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* rectangles. The corners of rectangles have integer coordinates and their edges are parallel to the *Ox* and *Oy* axes. The rectangles may touch each other, but they do not overlap (that is, there... | ```python
from itertools import *
n = int(input())
R = [list(map(int, input().split())) for _ in range(n)]
sx, sy, mx, my = 1e5, 1e5, 0, 0
for x1, y1, x2, y2 in R:
sx = min(sx, x1)
sy = min(sy, y1)
mx = max(mx, x2)
my = max(my, y2)
if mx-sx!=my-sy:
print("NO")
exit(0)
A = (mx-sx)*(my-sy)
for x1, y1, x2, y2 in R... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,579,604,473 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 0 | s = input()
if s[5:] == 'week':
if s[0] == '5':
print(53)
else:
print(52)
else:
if int(s[:2]) == 30:
print(11)
elif int(s[:2]) == 31:
print(7)
else:
print(12) | Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
s = input()
if s[5:] == 'week':
if s[0] == '5':
print(53)
else:
print(52)
else:
if int(s[:2]) == 30:
print(11)
elif int(s[:2]) == 31:
print(7)
else:
print(12)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,605,466,244 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 109 | 0 | def XOR(num1, num2):
out = ''
for n1, n2 in zip(num1, num2):
if n1 != n2:
out += '1'
else:
out += '0'
print(out)
num1 = input()
num2 = input()
XOR(num1, num2) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
def XOR(num1, num2):
out = ''
for n1, n2 in zip(num1, num2):
if n1 != n2:
out += '1'
else:
out += '0'
print(out)
num1 = input()
num2 = input()
XOR(num1, num2)
``` | 3.97275 | MatrixStudio/Codeforces-Python-Submissions |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,664,785,411 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 154 | 0 | m, n = map(int, input().split())
if m % 2 == 0:
print(m // 2 * n)
elif n % 2 == 0:
print(n // 2 * m)
elif n%2==0 and m%2!=0:
print(m//2*n + n//2)
elif n%2!=0 and m%2==0:
print(n//2*n)
elif n%2!=0 and m%2!=0:
print(m*n//2)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m, n = map(int, input().split())
if m % 2 == 0:
print(m // 2 * n)
elif n % 2 == 0:
print(n // 2 * m)
elif n%2==0 and m%2!=0:
print(m//2*n + n//2)
elif n%2!=0 and m%2==0:
print(n//2*n)
elif n%2!=0 and m%2!=0:
print(m*n//2)
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
379 | C | New Year Ratings Change | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | One very well-known internet resource site (let's call it X) has come up with a New Year adventure. Specifically, they decided to give ratings to all visitors.
There are *n* users on the site, for each user we know the rating value he wants to get as a New Year Present. We know that user *i* wants to get at least *a**... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of users on the site. The next line contains integer sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print a sequence of integers *b*1,<=*b*2,<=...,<=*b**n*. Number *b**i* means that user *i* gets *b**i* of rating as a present. The printed sequence must meet the problem conditions.
If there are multiple optimal solutions, print any of them. | [
"3\n5 1 1\n",
"1\n1000000000\n"
] | [
"5 1 2\n",
"1000000000\n"
] | none | 1,500 | [
{
"input": "3\n5 1 1",
"output": "5 1 2"
},
{
"input": "1\n1000000000",
"output": "1000000000"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "1 2 3 4 5 6 7 8 9 10"
},
{
"input": "10\n1 10 1 10 1 1 7 8 6 7",
"output": "1 10 2 11 3 4 7 9 6 8"
},
{
"input": "10\... | 1,672,510,706 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n=int(input())
a=list(map(int,input().split()))
t=0
a.sort()
for i in range(n):
a[i]=max(t+1,a[i])
t=a[i]
print(*a)
| Title: New Year Ratings Change
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One very well-known internet resource site (let's call it X) has come up with a New Year adventure. Specifically, they decided to give ratings to all visitors.
There are *n* users on the site, for each user we ... | ```python
n=int(input())
a=list(map(int,input().split()))
t=0
a.sort()
for i in range(n):
a[i]=max(t+1,a[i])
t=a[i]
print(*a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,506,453,575 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 62 | 0 | from math import sqrt
n=int(input())
k=int((sqrt(1+8*n)-1)/2)
x=int(n-k*(k+1)/2)
if x==0:
print(k)
else:
print(x)
| Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
from math import sqrt
n=int(input())
k=int((sqrt(1+8*n)-1)/2)
x=int(n-k*(k+1)/2)
if x==0:
print(k)
else:
print(x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
879 | B | Table Tennis | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | null | null | *n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. They play until someone wins *k* games in a row. This player becomes the winner.
For each of t... | The first line contains two integers: *n* and *k* (2<=≤<=*n*<=≤<=500, 2<=≤<=*k*<=≤<=1012) — the number of people and the number of wins.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — powers of the player. It's guaranteed that this line contains a valid permutation, i.e. all ... | Output a single integer — power of the winner. | [
"2 2\n1 2\n",
"4 2\n3 1 2 4\n",
"6 2\n6 5 3 1 2 4\n",
"2 10000000000\n2 1\n"
] | [
"2 ",
"3 ",
"6 ",
"2\n"
] | Games in the second sample:
3 plays with 1. 3 wins. 1 goes to the end of the line.
3 plays with 2. 3 wins. He wins twice in a row. He becomes the winner. | 1,000 | [
{
"input": "2 2\n1 2",
"output": "2 "
},
{
"input": "4 2\n3 1 2 4",
"output": "3 "
},
{
"input": "6 2\n6 5 3 1 2 4",
"output": "6 "
},
{
"input": "2 10000000000\n2 1",
"output": "2"
},
{
"input": "4 4\n1 3 4 2",
"output": "4 "
},
{
"input": "2 21474836... | 1,657,896,244 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 15 | 2,000 | 0 |
str1 = input()
str1 = str1.split(" ")
n = int(str1[0])
v = int(str1[1])
list1 = []
str2 = input()
str2 = str2.split(" ")
for i in range(n):
pow = int(str2[i])
list1.append(pow)
# print(list1)
a = list1[0]
vic =0
while vic < v:
j = 1
b = list1[j]
if a > b:
list1.remove(b)
list1.appen... | Title: Table Tennis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so o... | ```python
str1 = input()
str1 = str1.split(" ")
n = int(str1[0])
v = int(str1[1])
list1 = []
str2 = input()
str2 = str2.split(" ")
for i in range(n):
pow = int(str2[i])
list1.append(pow)
# print(list1)
a = list1[0]
vic =0
while vic < v:
j = 1
b = list1[j]
if a > b:
list1.remove(b)
l... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,578,058,519 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 77 | 0 | for x in range(int(input())):
a=int(input())
if a%7==0 or a%3==0 or a%10==0 or (a-7>0 and ((a-7)%10==0 or (a-7)%3==0)) or (a-3>0 and ((a-3)%7==0 or (a-3)%10==0)):print("YES")
else:print("NO") | Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chun... | ```python
for x in range(int(input())):
a=int(input())
if a%7==0 or a%3==0 or a%10==0 or (a-7>0 and ((a-7)%10==0 or (a-7)%3==0)) or (a-3>0 and ((a-3)%7==0 or (a-3)%10==0)):print("YES")
else:print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,676,550,512 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 0 | x = str(input())
out = []
ll = 0
for i in x:
if i == "h":
if len(out) == 0:
out.append(i)
elif i == "e":
if len(out) == 1:
out.append(i)
elif i == 'l':
if len(out) == 2 or len(out) == 3:
out.append(i)
elif i == "o":
if len... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
x = str(input())
out = []
ll = 0
for i in x:
if i == "h":
if len(out) == 0:
out.append(i)
elif i == "e":
if len(out) == 1:
out.append(i)
elif i == 'l':
if len(out) == 2 or len(out) == 3:
out.append(i)
elif i == "o":
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
932 | B | Recursive Queries | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"dfs and similar"
] | null | null | Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x* between *l* and *r* inclusive, such that *g*(*x*)<==<=*k*. | The first line of the input contains an integer *Q* (1<=≤<=*Q*<=≤<=2<=×<=105) representing the number of queries.
*Q* lines follow, each of which contains 3 integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=106,<=1<=≤<=*k*<=≤<=9). | For each query, print a single line containing the answer for that query. | [
"4\n22 73 9\n45 64 6\n47 55 7\n2 62 4\n",
"4\n82 94 6\n56 67 4\n28 59 9\n39 74 4\n"
] | [
"1\n4\n0\n8\n",
"3\n1\n1\n5\n"
] | In the first example:
- *g*(33) = 9 as *g*(33) = *g*(3 × 3) = *g*(9) = 9 - *g*(47) = *g*(48) = *g*(60) = *g*(61) = 6 - There are no such integers between 47 and 55. - *g*(4) = *g*(14) = *g*(22) = *g*(27) = *g*(39) = *g*(40) = *g*(41) = *g*(58) = 4 | 1,000 | [
{
"input": "4\n22 73 9\n45 64 6\n47 55 7\n2 62 4",
"output": "1\n4\n0\n8"
},
{
"input": "4\n82 94 6\n56 67 4\n28 59 9\n39 74 4",
"output": "3\n1\n1\n5"
}
] | 1,657,291,661 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 139 | 4,403,200 |
# problem O
def getMultiplicationOf(num):
pro = 1
while num != 0:
pro = pro * (num % 10)
num = int(num / 10)
return pro
def isContain0(num):
result = [int(x) for x in str(num)]
result = [i for i in result if i != 0]
s = [str(i) for i in result]
num = int("".join(s))
r... | Title: Recursive Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x*... | ```python
# problem O
def getMultiplicationOf(num):
pro = 1
while num != 0:
pro = pro * (num % 10)
num = int(num / 10)
return pro
def isContain0(num):
result = [int(x) for x in str(num)]
result = [i for i in result if i != 0]
s = [str(i) for i in result]
num = int("".join(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,636,352,278 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 19,968,000 | int(input())
for i in range(1,int(n/2)+1):
print(i) | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
int(input())
for i in range(1,int(n/2)+1):
print(i)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Iahub is so happy about inventing bubble sort graphs that he's staying all day long at the office and writing permutations. Iahubina is angry that she is no more important for Iahub. When Iahub goes away, Iahubina comes to his office and sabotage his research work.
The girl finds an important permutation for the resea... | The first line contains integer *n* (2<=≤<=*n*<=≤<=2000). On the second line, there are *n* integers, representing Iahub's important permutation after Iahubina replaces some values with -1.
It's guaranteed that there are no fixed points in the given permutation. Also, the given sequence contains at least two numbers ... | Output a single integer, the number of ways Iahub could recover his permutation, modulo 1000000007 (109<=+<=7). | [
"5\n-1 -1 4 3 -1\n"
] | [
"2\n"
] | For the first test example there are two permutations with no fixed points are [2, 5, 4, 3, 1] and [5, 1, 4, 3, 2]. Any other permutation would have at least one fixed point. | 0 | [
{
"input": "5\n-1 -1 4 3 -1",
"output": "2"
},
{
"input": "8\n2 4 5 3 -1 8 -1 6",
"output": "1"
},
{
"input": "7\n-1 -1 4 -1 7 1 6",
"output": "4"
},
{
"input": "6\n-1 -1 -1 -1 -1 -1",
"output": "265"
},
{
"input": "2\n-1 -1",
"output": "1"
},
{
"input... | 1,594,121,838 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 186 | 7,577,600 | def main():
mod = (10 ** 9) + 7
lim = 20200
fct = [0] * lim
inv_f = [0] * lim
fct[0] = 1
for i in range(1, lim):
fct[i] = fct[i - 1] * i % mod
inv_f[lim - 1] = pow(fct[lim - 1], mod - 2, mod)
for i in range(lim - 1, 0, -1):
inv_f[i - 1] = inv_f[i] * i % ... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub is so happy about inventing bubble sort graphs that he's staying all day long at the office and writing permutations. Iahubina is angry that she is no more important for Iahub. When Iahub goes away, Iahubina comes to his off... | ```python
def main():
mod = (10 ** 9) + 7
lim = 20200
fct = [0] * lim
inv_f = [0] * lim
fct[0] = 1
for i in range(1, lim):
fct[i] = fct[i - 1] * i % mod
inv_f[lim - 1] = pow(fct[lim - 1], mod - 2, mod)
for i in range(lim - 1, 0, -1):
inv_f[i - 1] = inv_f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,582,996,458 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 186 | 307,200 | name = input('')
lower = name.lower()
upper = name.upper()
p_low =0
q_up = 0
l = list(map(chr,range(97,123)))
t = [chr(x) for x in range(ord('A'), ord('Z')+1 )]
for k in range(0, len(name)):
if name[k] == any(l):
p_low = p_low +1
elif name[k] == any(t):
q_up = q_up +1
if q_up>p_low:
... | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
name = input('')
lower = name.lower()
upper = name.upper()
p_low =0
q_up = 0
l = list(map(chr,range(97,123)))
t = [chr(x) for x in range(ord('A'), ord('Z')+1 )]
for k in range(0, len(name)):
if name[k] == any(l):
p_low = p_low +1
elif name[k] == any(t):
q_up = q_up +1
if q_... | 0 | MatrixStudio/Codeforces-Python-Submissions |
803 | C | Maximal GCD | PROGRAMMING | 1,900 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Greatest common divisor of sequence is maximum of such numbers that every element of sequence is divi... | The first line consists of two numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1010). | If the answer exists then output *k* numbers — resulting sequence. Otherwise output -1. If there are multiple answers, print any of them. | [
"6 3\n",
"8 2\n",
"5 3\n"
] | [
"1 2 3\n",
"2 6\n",
"-1\n"
] | none | 0 | [
{
"input": "6 3",
"output": "1 2 3"
},
{
"input": "8 2",
"output": "2 6"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "2 10000000... | 1,622,267,762 | 2,147,483,647 | PyPy 3 | OK | TESTS | 138 | 248 | 9,318,400 | n, k = map(int, input().rstrip().split())
i = 1
ans = -1
while i * i <= n:
if n % i != 0:
i += 1
continue
t = (k * k + k) * i // 2
if(t > n):
i += 1
continue
ans = max(ans, i)
j = n // i
t = (k * k + k) * j // 2
if(t > n):
i += 1
continue
ans = max(ans, j)
i += 1
if ans == -1:
print(an... | Title: Maximal GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Grea... | ```python
n, k = map(int, input().rstrip().split())
i = 1
ans = -1
while i * i <= n:
if n % i != 0:
i += 1
continue
t = (k * k + k) * i // 2
if(t > n):
i += 1
continue
ans = max(ans, i)
j = n // i
t = (k * k + k) * j // 2
if(t > n):
i += 1
continue
ans = max(ans, j)
i += 1
if ans == -1:... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,686,839,647 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | def calculate_final_power(p1, p2, p3):
powers = [p1, p2, p3]
while len(powers) > 1:
powers.sort()
powers[2] -= powers[0]
powers.pop(0)
return powers[0]
p1, p2, p3 = map(int, input().split())
print(calculate_final_power(p1, p2, p3))
| Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
def calculate_final_power(p1, p2, p3):
powers = [p1, p2, p3]
while len(powers) > 1:
powers.sort()
powers[2] -= powers[0]
powers.pop(0)
return powers[0]
p1, p2, p3 = map(int, input().split())
print(calculate_final_power(p1, p2, p3))
`... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,684,870,034 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 77 | 26,112,000 | # Wadea #
n = int(input())
m = int(input())
print( m% (2**n))
| Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
# Wadea #
n = int(input())
m = int(input())
print( m% (2**n))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,695,581,917 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | word=input()
x=""
if word[0].islower()==True and word[1:len(word)].isupper()==True:
x=(word[0].upper()+word[1:len(word)].lower())
print(x)
elif word[0:len(word)].isupper==True:
x=word[0].upper()
x+=word[1:len(word)].lower()
print(x)
else:
print(word)
| Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
word=input()
x=""
if word[0].islower()==True and word[1:len(word)].isupper()==True:
x=(word[0].upper()+word[1:len(word)].lower())
print(x)
elif word[0:len(word)].isupper==True:
x=word[0].upper()
x+=word[1:len(word)].lower()
print(x)
else:
print(word)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
510 | B | Fox And Two Dots | PROGRAMMING | 1,500 | [
"dfs and similar"
] | null | null | Fox Ciel is playing a mobile puzzle game called "Two Dots". The basic levels are played on a board of size *n*<=×<=*m* cells, like this:
Each cell contains a dot that has some color. We will use different uppercase Latin characters to express different colors.
The key of this game is to find a cycle that contain dots... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=50): the number of rows and columns of the board.
Then *n* lines follow, each line contains a string consisting of *m* characters, expressing colors of dots in each line. Each character is an uppercase Latin letter. | Output "Yes" if there exists a cycle, and "No" otherwise. | [
"3 4\nAAAA\nABCA\nAAAA\n",
"3 4\nAAAA\nABCA\nAADA\n",
"4 4\nYYYR\nBYBY\nBBBY\nBBBY\n",
"7 6\nAAAAAB\nABBBAB\nABAAAB\nABABBB\nABAAAB\nABBBAB\nAAAAAB\n",
"2 13\nABCDEFGHIJKLM\nNOPQRSTUVWXYZ\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"Yes\n",
"No\n"
] | In first sample test all 'A' form a cycle.
In second sample there is no such cycle.
The third sample is displayed on the picture above ('Y' = Yellow, 'B' = Blue, 'R' = Red). | 1,000 | [
{
"input": "3 4\nAAAA\nABCA\nAAAA",
"output": "Yes"
},
{
"input": "3 4\nAAAA\nABCA\nAADA",
"output": "No"
},
{
"input": "4 4\nYYYR\nBYBY\nBBBY\nBBBY",
"output": "Yes"
},
{
"input": "7 6\nAAAAAB\nABBBAB\nABAAAB\nABABBB\nABAAAB\nABBBAB\nAAAAAB",
"output": "Yes"
},
{
... | 1,682,074,249 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n,m=map(int,input().split())
g=[]
for i in range(n):
c=input()
d=[]
for j in c:
d.append(j)
g.append(d)
di=[1,-1,0,0]
dj=[0,0,1,-1]
visited=[]
def reset():
for i in range(n):
c=[]
for j in range(m):
c.append(False)
visited.appen... | Title: Fox And Two Dots
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel is playing a mobile puzzle game called "Two Dots". The basic levels are played on a board of size *n*<=×<=*m* cells, like this:
Each cell contains a dot that has some color. We will use different uppercase La... | ```python
n,m=map(int,input().split())
g=[]
for i in range(n):
c=input()
d=[]
for j in c:
d.append(j)
g.append(d)
di=[1,-1,0,0]
dj=[0,0,1,-1]
visited=[]
def reset():
for i in range(n):
c=[]
for j in range(m):
c.append(False)
vis... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
698 | A | Vacations | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Internet on that day. For the *i*-th day there are four options:
1. on this day the gym is close... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of days of Vasya's vacations.
The second line contains the sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=3) separated by space, where:
- *a**i* equals 0, if on the *i*-th day of vacations the gym is closed and the co... | Print the minimum possible number of days on which Vasya will have a rest. Remember that Vasya refuses:
- to do sport on any two consecutive days, - to write the contest on any two consecutive days. | [
"4\n1 3 2 0\n",
"7\n1 3 3 2 1 2 3\n",
"2\n2 2\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first test Vasya can write the contest on the day number 1 and do sport on the day number 3. Thus, he will have a rest for only 2 days.
In the second test Vasya should write contests on days number 1, 3, 5 and 7, in other days do sport. Thus, he will not have a rest for a single day.
In the third test Vasya ca... | 500 | [
{
"input": "4\n1 3 2 0",
"output": "2"
},
{
"input": "7\n1 3 3 2 1 2 3",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "10\n0 0 1 1 0 0 0 0 1 0",
"output": "8"
},
{
"input": "100\n3 2 3 3 3 2 3 1 ... | 1,684,881,521 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 61 | 1,536,000 | # ﷽
import sys
input = sys.stdin.readline
def f(n,prev):
if n > length :
return 0
if (n,arr[n],prev) in memo :
return memo[n,arr[n],prev]
if arr[n] == 3:
x = 1
y = 2
dx = 1 if prev == 1 else 0
dy = 1 if prev == 2 else 0
memo[n,x,prev] = ... | Title: Vacations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* days of vacations! So he decided to improve his IT skills and do sport. Vasya knows the following information about each of this *n* days: whether that gym opened and whether a contest was carried out in the Int... | ```python
# ﷽
import sys
input = sys.stdin.readline
def f(n,prev):
if n > length :
return 0
if (n,arr[n],prev) in memo :
return memo[n,arr[n],prev]
if arr[n] == 3:
x = 1
y = 2
dx = 1 if prev == 1 else 0
dy = 1 if prev == 2 else 0
memo[n,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
131 | B | Opposites Attract | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Everybody knows that opposites attract. That is the key principle of the "Perfect Matching" dating agency. The "Perfect Matching" matchmakers have classified each registered customer by his interests and assigned to the *i*-th client number *t**i* (<=-<=10<=≤<=*t**i*<=≤<=10). Of course, one number can be assigned to an... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=105) which represents the number of registered clients of the "Couple Matching". The second line contains a sequence of integers *t*1,<=*t*2,<=...,<=*t**n* (<=-<=10<=≤<=*t**i*<=≤<=10), *t**i* — is the parameter of the *i*-th customer that has been ... | Print the number of couples of customs with opposite *t*. The opposite number for *x* is number <=-<=*x* (0 is opposite to itself). Couples that only differ in the clients' order are considered the same.
Note that the answer to the problem can be large enough, so you must use the 64-bit integer type for calculations. ... | [
"5\n-3 3 0 0 3\n",
"3\n0 0 0\n"
] | [
"3\n",
"3\n"
] | In the first sample the couples of opposite clients are: (1,2), (1,5) и (3,4).
In the second sample any couple of clients is opposite. | 1,000 | [
{
"input": "5\n-3 3 0 0 3",
"output": "3"
},
{
"input": "3\n0 0 0",
"output": "3"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n5",
"output": "0"
},
{
"input": "2\n0 0",
"output": "1"
},
{
"input": "2\n-3 3",
"output": "1"
},
{
"inp... | 1,694,567,200 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n = int(input())
nums = map(int, input().split())
ans = 0
freq_map = [0] * 21
for n in nums:
freq_map[n + 10] += 1
for i in range(-10, 0):
ans += freq_map[i + 10] * freq_map[-i + 10]
if 0 in freq_map:
x = freq_map[0]
ans += x * (x - 1) // 2
print(ans)
| Title: Opposites Attract
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Everybody knows that opposites attract. That is the key principle of the "Perfect Matching" dating agency. The "Perfect Matching" matchmakers have classified each registered customer by his interests and assigned to t... | ```python
n = int(input())
nums = map(int, input().split())
ans = 0
freq_map = [0] * 21
for n in nums:
freq_map[n + 10] += 1
for i in range(-10, 0):
ans += freq_map[i + 10] * freq_map[-i + 10]
if 0 in freq_map:
x = freq_map[0]
ans += x * (x - 1) // 2
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
789 | B | Masha and geometric depression | PROGRAMMING | 1,700 | [
"brute force",
"implementation",
"math"
] | null | null | Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric progression is a sequence of integers *b*1,<=*b*2,<=*b*3,<=..., where for each *i*<=><=1 the respective term satisfi... | The first line of input contains four integers *b*1, *q*, *l*, *m* (-109<=≤<=*b*1,<=*q*<=≤<=109, 1<=≤<=*l*<=≤<=109, 1<=≤<=*m*<=≤<=105) — the initial term and the common ratio of progression, absolute value of maximal number that can be written on the board and the number of "bad" integers, respectively.
The second lin... | Print the only integer, meaning the number of progression terms that will be written on the board if it is finite, or "inf" (without quotes) otherwise. | [
"3 2 30 4\n6 14 25 48\n",
"123 1 2143435 4\n123 11 -5453 141245\n",
"123 1 2143435 4\n54343 -13 6 124\n"
] | [
"3",
"0",
"inf"
] | In the first sample case, Masha will write integers 3, 12, 24. Progression term 6 will be skipped because it is a "bad" integer. Terms bigger than 24 won't be written because they exceed *l* by absolute value.
In the second case, Masha won't write any number because all terms are equal 123 and this is a "bad" integer.... | 1,000 | [
{
"input": "3 2 30 4\n6 14 25 48",
"output": "3"
},
{
"input": "123 1 2143435 4\n123 11 -5453 141245",
"output": "0"
},
{
"input": "123 1 2143435 4\n54343 -13 6 124",
"output": "inf"
},
{
"input": "3 2 25 2\n379195692 -69874783",
"output": "4"
},
{
"input": "3 2 3... | 1,490,805,122 | 1,622 | Python 3 | WRONG_ANSWER | PRETESTS | 7 | 92 | 16,281,600 |
s, r, m, n = map(int, input().split())
bad = set(map(int, input().split()))
cnt = 0
if m < s:
print(0)
elif r == 1:
if s in bad:
print(0)
else:
print('inf')
elif r <= 1:
print('inf')
else:
while s <= m:
if s not in bad:
cnt += 1
s *= r
print(cnt) | Title: Masha and geometric depression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Masha really loves algebra. On the last lesson, her strict teacher Dvastan gave she new exercise.
You are given geometric progression *b* defined by two integers *b*1 and *q*. Remind that a geometric pro... | ```python
s, r, m, n = map(int, input().split())
bad = set(map(int, input().split()))
cnt = 0
if m < s:
print(0)
elif r == 1:
if s in bad:
print(0)
else:
print('inf')
elif r <= 1:
print('inf')
else:
while s <= m:
if s not in bad:
cnt += 1
s *= r
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
63 | A | Sinking Ship | PROGRAMMING | 900 | [
"implementation",
"sortings",
"strings"
] | A. Sinking Ship | 2 | 256 | The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to *n*) and await further instructions. However, one should evacuate the crew properly, in a stri... | The first line contains an integer *n*, which is the number of people in the crew (1<=≤<=*n*<=≤<=100). Then follow *n* lines. The *i*-th of those lines contains two words — the name of the crew member who is *i*-th in line, and his status on the ship. The words are separated by exactly one space. There are no other spa... | Print *n* lines. The *i*-th of them should contain the name of the crew member who must be the *i*-th one to leave the ship. | [
"6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman\n"
] | [
"Teddy\nAlice\nBob\nJulia\nCharlie\nJack\n"
] | none | 500 | [
{
"input": "6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman",
"output": "Teddy\nAlice\nBob\nJulia\nCharlie\nJack"
},
{
"input": "1\nA captain",
"output": "A"
},
{
"input": "1\nAbcdefjhij captain",
"output": "Abcdefjhij"
},
{
"input": "5\nA captain... | 1,573,327,863 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 218 | 0 | def inp():
return map(str, input().split())
hash = dict({'captain': 4, 'man': 3, 'woman': 2, 'child': 2, 'rat': 1})
arr = []
n = int(input())
for i in range(n):
s1, s2 = inp()
arr.append([s1, hash[s2]])
arr.sort(key=lambda x: x[1])
for i in range(n):
print(arr[i][0])
| Title: Sinking Ship
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to ... | ```python
def inp():
return map(str, input().split())
hash = dict({'captain': 4, 'man': 3, 'woman': 2, 'child': 2, 'rat': 1})
arr = []
n = int(input())
for i in range(n):
s1, s2 = inp()
arr.append([s1, hash[s2]])
arr.sort(key=lambda x: x[1])
for i in range(n):
print(arr[i][0])
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,653,560,000 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 31 | 0 | n = int(input())
f = list(map(int, input().split()))
can = False
for i in range(n):
a = i+1
b = f[i]
c = f[b-1]
if (a == f[c-1]):
can = True
break
if (can):
print("YES")
else:
print("NO") | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
n = int(input())
f = list(map(int, input().split()))
can = False
for i in range(n):
a = i+1
b = f[i]
c = f[b-1]
if (a == f[c-1]):
can = True
break
if (can):
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and... | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, ... | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer ... | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,464,870,488 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 77 | 4,812,800 | # coding=utf-8
if __name__ == '__main__':
n = int(input())
p = int(input())
q = int(input())
print(n * p / (p + q))
| Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the en... | ```python
# coding=utf-8
if __name__ == '__main__':
n = int(input())
p = int(input())
q = int(input())
print(n * p / (p + q))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it la... | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on... | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,682,246,188 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | w=[int(i) for i in input().split()]
n,m=w[0],w[1]
ans=n
poss_days=n//m
ans+=poss_days
print(ans+1 if not ans%m else ans) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th... | ```python
w=[int(i) for i in input().split()]
n,m=w[0],w[1]
ans=n
poss_days=n//m
ans+=poss_days
print(ans+1 if not ans%m else ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,571,507,859 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 0 | n, k = list(map(int,input().split()))
k1 = 1
c = 1
for i in range(2,n // 2 + 1):
if k == k1:
break
if n % i == 0:
k1 += 1
c = i
if k == k1:
print(c)
else:
print(-1)
| Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
n, k = list(map(int,input().split()))
k1 = 1
c = 1
for i in range(2,n // 2 + 1):
if k == k1:
break
if n % i == 0:
k1 += 1
c = i
if k == k1:
print(c)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,695,476,512 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 62 | 0 | n, k, l, c, d, p, nl, np = map(int, input().split())
t1 = (k*l)//nl
t2 = c*d
t3 = p//np
toast = [t1, t2, t3]
t = min(toast)//n
print(t)
| Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
n, k, l, c, d, p, nl, np = map(int, input().split())
t1 = (k*l)//nl
t2 = c*d
t3 = p//np
toast = [t1, t2, t3]
t = min(toast)//n
print(t)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
474 | A | Keyboard | PROGRAMMING | 900 | [
"implementation"
] | null | null | Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That mean... | First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).
Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain ... | Print a line that contains the original message. | [
"R\ns;;upimrrfod;pbr\n"
] | [
"allyouneedislove\n"
] | none | 500 | [
{
"input": "R\ns;;upimrrfod;pbr",
"output": "allyouneedislove"
},
{
"input": "R\nwertyuiop;lkjhgfdsxcvbnm,.",
"output": "qwertyuiolkjhgfdsazxcvbnm,"
},
{
"input": "L\nzxcvbnm,kjhgfdsaqwertyuio",
"output": "xcvbnm,.lkjhgfdswertyuiop"
},
{
"input": "R\nbubbuduppudup",
"outp... | 1,676,939,874 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 61 | 0 | #it's my code my name is Abduaziz
string = input()
keyboard = input()
array = ['qwertyuiop', 'asdfghjkl;', 'zxcvbnm,./']
answer = ''
for key in keyboard:
if key in array[0]:
if string == "R":
if array[0].index(key) == 0:
answer += 'q'
else:
... | Title: Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:
Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately.... | ```python
#it's my code my name is Abduaziz
string = input()
keyboard = input()
array = ['qwertyuiop', 'asdfghjkl;', 'zxcvbnm,./']
answer = ''
for key in keyboard:
if key in array[0]:
if string == "R":
if array[0].index(key) == 0:
answer += 'q'
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,687,496,536 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 44 | 62 | 0 | s = str(input())
cur = ord('a')
ans = 0
for i in range(0, len(s)):
diff = abs(cur - ord(s[i]))
ans += min(diff, 26 - diff)
cur = ord(s[i])
print(ans) | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
s = str(input())
cur = ord('a')
ans = 0
for i in range(0, len(s)):
diff = abs(cur - ord(s[i]))
ans += min(diff, 26 - diff)
cur = ord(s[i])
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,555,083,552 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 109 | 0 | n = int(input())
if n%10 == 0:
print(n)
elif n%10<6:
print(n-n%10)
else:
print(n+10-n%10)
| Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
n = int(input())
if n%10 == 0:
print(n)
elif n%10<6:
print(n-n%10)
else:
print(n+10-n%10)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
625 | A | Guest From the Past | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much more complicated.
Kolya is hungry, so he went to the nearest milk shop. In 2084 you may buy kefir in a plas... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1018) — the number of rubles Kolya has at the beginning.
Then follow three lines containing integers *a*, *b* and *c* (1<=≤<=*a*<=≤<=1018, 1<=≤<=*c*<=<<=*b*<=≤<=1018) — the cost of one plastic liter bottle, the cost of one glass liter bottle and t... | Print the only integer — maximum number of liters of kefir, that Kolya can drink. | [
"10\n11\n9\n8\n",
"10\n5\n6\n1\n"
] | [
"2\n",
"2\n"
] | In the first sample, Kolya can buy one glass bottle, then return it and buy one more glass bottle. Thus he will drink 2 liters of kefir.
In the second sample, Kolya can buy two plastic bottle and get two liters of kefir, or he can buy one liter glass bottle, then return it and buy one plastic bottle. In both cases he ... | 750 | [
{
"input": "10\n11\n9\n8",
"output": "2"
},
{
"input": "10\n5\n6\n1",
"output": "2"
},
{
"input": "2\n2\n2\n1",
"output": "1"
},
{
"input": "10\n3\n3\n1",
"output": "4"
},
{
"input": "10\n1\n2\n1",
"output": "10"
},
{
"input": "10\n2\n3\n1",
"outpu... | 1,455,007,214 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 62 | 0 | n=int(input())
a=int(input())
b=int(input())
c=int(input())
if a<b-c:
ans=n//a
elif a>b:
ans=(n-b)//(b-c)+1
else:
ans=(n-a)//(b-c)+1
print(ans)
| Title: Guest From the Past
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much mor... | ```python
n=int(input())
a=int(input())
b=int(input())
c=int(input())
if a<b-c:
ans=n//a
elif a>b:
ans=(n-b)//(b-c)+1
else:
ans=(n-a)//(b-c)+1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,568,740,747 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | asd=input()
'''while vstup[0]!='h':
del vstup[0]
while vstup[1]!='e':
del vstup[1]
print(vstup)
while vstup[2]!='l' or vstup[3]!='l':
if vstup[2]!='l':
del vstup[2]
else:
del vstup[3]
if len(vstup) == 3:
break
print(vstup)
try:
while vstup[4]!='o':
del vstup[4]
except:
x=1
vstup =''... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
asd=input()
'''while vstup[0]!='h':
del vstup[0]
while vstup[1]!='e':
del vstup[1]
print(vstup)
while vstup[2]!='l' or vstup[3]!='l':
if vstup[2]!='l':
del vstup[2]
else:
del vstup[3]
if len(vstup) == 3:
break
print(vstup)
try:
while vstup[4]!='o':
del vstup[4]
except:
x=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
811 | B | Vladik and Complicated Book | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Vladik had started reading a complicated book about algorithms containing *n* pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation *P*<==<=[*p*1,<=*p*2,<=...,<=*p**n*], where *p**i* denotes the number of page that should be read *i*-th in turn.
So... | First line contains two space-separated integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — permutation *P*. Note that elements in p... | For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise. | [
"5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3\n",
"6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3\n"
] | [
"Yes\nNo\nYes\nYes\nNo\n",
"Yes\nNo\nYes\nNo\nYes\n"
] | Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes". 1. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No". 1. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Ye... | 1,000 | [
{
"input": "5 5\n5 4 3 2 1\n1 5 3\n1 3 1\n2 4 3\n4 4 4\n2 5 3",
"output": "Yes\nNo\nYes\nYes\nNo"
},
{
"input": "6 5\n1 4 3 2 5 6\n2 4 3\n1 6 2\n4 5 4\n1 3 3\n2 6 3",
"output": "Yes\nNo\nYes\nNo\nYes"
},
{
"input": "10 10\n10 1 6 7 9 8 4 3 5 2\n1 1 1\n4 4 4\n7 7 7\n3 3 3\n1 6 5\n2 6 2\n6... | 1,497,617,382 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | #http://codeforces.com/problemset/problem/811/B
import sys
sys.stdin = open('input2','r')
n,m = map(int,input().split())
arr = sys.stdin.readline().split()
pos = 0
for i in range(m):
l,r,x = map(int,input().split())
arr3 = arr[l-1:r]
arr2 = [int(i) for i in arr3]
arr2 = sorted(arr2)
#prin... | Title: Vladik and Complicated Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vladik had started reading a complicated book about algorithms containing *n* pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation *P*<... | ```python
#http://codeforces.com/problemset/problem/811/B
import sys
sys.stdin = open('input2','r')
n,m = map(int,input().split())
arr = sys.stdin.readline().split()
pos = 0
for i in range(m):
l,r,x = map(int,input().split())
arr3 = arr[l-1:r]
arr2 = [int(i) for i in arr3]
arr2 = sorted(arr2)
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
909 | C | Python Indentation | PROGRAMMING | 1,800 | [
"dp"
] | null | null | In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An ex... | The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement. | Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7. | [
"4\ns\nf\nf\ns\n",
"4\nf\ns\nf\ns\n"
] | [
"1\n",
"2\n"
] | In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one... | 1,500 | [
{
"input": "4\ns\nf\nf\ns",
"output": "1"
},
{
"input": "4\nf\ns\nf\ns",
"output": "2"
},
{
"input": "156\nf\ns\nf\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\nf\nf\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\ns... | 1,670,754,949 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 70 | 545 | 205,209,600 | n = int(input())
a = ['' for i in range(n+1)]
for i in range(1, n+1):
a[i] = input()
dp = [[1 for i in range(n + 2)] for j in range(n + 1)]
for i in range(n):
dp[i][i] = 1
for i in reversed(range(1, n)):
sum = 0
for j in range(n):
sum += dp[i+1][j]
sum %= 1000000007
if a[i] == 'f... | Title: Python Indentation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python... | ```python
n = int(input())
a = ['' for i in range(n+1)]
for i in range(1, n+1):
a[i] = input()
dp = [[1 for i in range(n + 2)] for j in range(n + 1)]
for i in range(n):
dp[i][i] = 1
for i in reversed(range(1, n)):
sum = 0
for j in range(n):
sum += dp[i+1][j]
sum %= 1000000007
if ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
468 | A | 24 Game | PROGRAMMING | 1,500 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of *n* integers: 1,<=2,<=...,<=*n*. In a single step, you can pick two of them, let's denote them *a* and *b*, erase them from the sequence, and append to the sequence eit... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following *n*<=-<=1 lines print the required operations an operation per line. Each operation should be in form: "*a* *op* *b* = *c*". Where *a* and *b* are the numbe... | [
"1\n",
"8\n"
] | [
"NO\n",
"YES\n8 * 7 = 56\n6 * 5 = 30\n3 - 4 = -1\n1 - 2 = -1\n30 - -1 = 31\n56 - 31 = 25\n25 + -1 = 24\n"
] | none | 500 | [
{
"input": "1",
"output": "NO"
},
{
"input": "8",
"output": "YES\n8 * 7 = 56\n6 * 5 = 30\n3 - 4 = -1\n1 - 2 = -1\n30 - -1 = 31\n56 - 31 = 25\n25 + -1 = 24"
},
{
"input": "12",
"output": "YES\n3 * 4 = 12\n2 * 1 = 2\n12 * 2 = 24\n6 - 5 = 1\n24 * 1 = 24\n8 - 7 = 1\n24 * 1 = 24\n10 - 9 =... | 1,615,213,798 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 62 | 307,200 | n = int(input())
x = n*(n+1)//2
if x%2:
print("NO")
else:
if x>=24:
print("YES")
s = 0
z = (x-24)//2
lst = [1]*(n+1)
for i in range(n,0,-1):
if s+i<=z:
if s!=0:
print(s," + ",i," = ",s+i)
s += i... | Title: 24 Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of *n* integers: 1,<=2,<=...,<=*n*. In a single step, you can pick two of them... | ```python
n = int(input())
x = n*(n+1)//2
if x%2:
print("NO")
else:
if x>=24:
print("YES")
s = 0
z = (x-24)//2
lst = [1]*(n+1)
for i in range(n,0,-1):
if s+i<=z:
if s!=0:
print(s," + ",i," = ",s+i)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
299 | A | Ksusha and Array | PROGRAMMING | 1,000 | [
"brute force",
"number theory",
"sortings"
] | null | null | Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that all array elements are divisible by it. Help her and find the number! | The first line contains integer *n* (1<=≤<=*n*<=≤<=105), showing how many numbers the array has. The next line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the array elements. | Print a single integer — the number from the array, such that all array elements are divisible by it. If such number doesn't exist, print -1.
If there are multiple answers, you are allowed to print any of them. | [
"3\n2 2 4\n",
"5\n2 1 3 1 6\n",
"3\n2 3 5\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 500 | [
{
"input": "3\n2 2 4",
"output": "2"
},
{
"input": "5\n2 1 3 1 6",
"output": "1"
},
{
"input": "3\n2 3 5",
"output": "-1"
},
{
"input": "1\n331358794",
"output": "331358794"
},
{
"input": "5\n506904227 214303304 136194869 838256937 183952885",
"output": "-1"
... | 1,449,907,294 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 216 | 8,499,200 | n = int(input())
data = list(map(int, input().split()))
small = min(data)
for x in data:
if x % small != 0:
print(-1)
import sys; sys.exit()
print(small)
| Title: Ksusha and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that ... | ```python
n = int(input())
data = list(map(int, input().split()))
small = min(data)
for x in data:
if x % small != 0:
print(-1)
import sys; sys.exit()
print(small)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
672 | A | Summer Camp | PROGRAMMING | 800 | [
"implementation"
] | null | null | Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1 are written in one line. The prefix of these line is "123456789101112131415...". Your task is to... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the position of the digit you need to print. | Print the *n*-th digit of the line. | [
"3\n",
"11\n"
] | [
"3\n",
"0\n"
] | In the first sample the digit at position 3 is '3', as both integers 1 and 2 consist on one digit.
In the second sample, the digit at position 11 is '0', it belongs to the integer 10. | 500 | [
{
"input": "3",
"output": "3"
},
{
"input": "11",
"output": "0"
},
{
"input": "12",
"output": "1"
},
{
"input": "13",
"output": "1"
},
{
"input": "29",
"output": "9"
},
{
"input": "30",
"output": "2"
},
{
"input": "1000",
"output": "3"
... | 1,604,224,424 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 124 | 0 | n = int(input())
def get_dig(n):
d = n - ((n-10)/2)
return int(d/10),int(d%10)
if n < 10:
print(n)
else:
if n%2 == 0:
print(get_dig(n)[0])
else:
print(get_dig(n-1)[1]) | Title: Summer Camp
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Every year, hundreds of people come to summer camps, they learn new algorithms and solve hard problems.
This is your first year at summer camp, and you are asked to solve the following problem. All integers starting with 1... | ```python
n = int(input())
def get_dig(n):
d = n - ((n-10)/2)
return int(d/10),int(d%10)
if n < 10:
print(n)
else:
if n%2 == 0:
print(get_dig(n)[0])
else:
print(get_dig(n-1)[1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,695,728,967 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | x = input()
y = ''
for i in x:
if i not in y:
y += i
if len(y) % 2 == 0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
| Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
x = input()
y = ''
for i in x:
if i not in y:
y += i
if len(y) % 2 == 0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
463 | A | Caisa and Sugar | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | Caisa is going to have a party and he needs to buy the ingredients for a big chocolate cake. For that he is going to the biggest supermarket in town.
Unfortunately, he has just *s* dollars for sugar. But that's not a reason to be sad, because there are *n* types of sugar in the supermarket, maybe he able to buy one. B... | The first line contains two space-separated integers *n*,<=*s* (1<=≤<=*n*,<=*s*<=≤<=100).
The *i*-th of the next *n* lines contains two integers *x**i*, *y**i* (1<=≤<=*x**i*<=≤<=100; 0<=≤<=*y**i*<=<<=100), where *x**i* represents the number of dollars and *y**i* the number of cents needed in order to buy the *i*-th... | Print a single integer representing the maximum number of sweets he can buy, or -1 if he can't buy any type of sugar. | [
"5 10\n3 90\n12 0\n9 70\n5 50\n7 0\n",
"5 5\n10 10\n20 20\n30 30\n40 40\n50 50\n"
] | [
"50\n",
"-1\n"
] | In the first test sample Caisa can buy the fourth type of sugar, in such a case he will take 50 sweets as a change. | 500 | [
{
"input": "5 10\n3 90\n12 0\n9 70\n5 50\n7 0",
"output": "50"
},
{
"input": "5 5\n10 10\n20 20\n30 30\n40 40\n50 50",
"output": "-1"
},
{
"input": "1 2\n1 0",
"output": "0"
},
{
"input": "2 10\n20 99\n30 99",
"output": "-1"
},
{
"input": "15 21\n16 51\n33 44\n32 ... | 1,612,277,208 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | if __name__ == '__main__':
cin = input
n, s = map(int, cin().split())
mx = -1
for i in range(n):
x, y = map(int, cin().split())
if x <= s:
mx = max(mx, 100 - y) if y and x + 1 <= s else mx
print(mx)
| Title: Caisa and Sugar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Caisa is going to have a party and he needs to buy the ingredients for a big chocolate cake. For that he is going to the biggest supermarket in town.
Unfortunately, he has just *s* dollars for sugar. But that's not a r... | ```python
if __name__ == '__main__':
cin = input
n, s = map(int, cin().split())
mx = -1
for i in range(n):
x, y = map(int, cin().split())
if x <= s:
mx = max(mx, 100 - y) if y and x + 1 <= s else mx
print(mx)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
404 | A | Valera and X | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the... | The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper. | Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes. | [
"5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n",
"3\nwsw\nsws\nwsw\n",
"3\nxpx\npxp\nxpe\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox",
"output": "NO"
},
{
"input": "3\nwsw\nsws\nwsw",
"output": "YES"
},
{
"input": "3\nxpx\npxp\nxpe",
"output": "NO"
},
{
"input": "5\nliiil\nilili\niilii\nilili\nliiil",
"output": "YES"
},
{
"input": "7\nbwccccb\nck... | 1,695,105,022 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 31 | 46 | 0 | n = int(input())
pat = []
flag = True
for _ in range(n):
temp = input()
if not 3 > len(list(set(temp))) > 1:
flag = False
pat.append(temp)
if flag:
x = pat[0][0]
for i in range(n):
if i == n // 2:
if pat[i].count(x) != 1:
flag = False
print("NO")
break
... | Title: Valera and X
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a... | ```python
n = int(input())
pat = []
flag = True
for _ in range(n):
temp = input()
if not 3 > len(list(set(temp))) > 1:
flag = False
pat.append(temp)
if flag:
x = pat[0][0]
for i in range(n):
if i == n // 2:
if pat[i].count(x) != 1:
flag = False
print("NO")
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
147 | A | Punctuation | PROGRAMMING | 1,300 | [
"implementation",
"strings"
] | null | null | You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to add spaces to the text by the following rules:
- if there is no punctuation mark between two word... | The input data contains of a single non-empty line — the text whose length is no more than 10000 characters. | Print the text, edited according to the rules. In this problem you should follow the output format very strictly. For example, extra space at the end of the output line is considered as wrong answer. Note that a newline character at the end of the line doesn't matter. | [
"galileo galilei was an italian physicist ,mathematician,astronomer\n",
"galileo was born in pisa\n"
] | [
"galileo galilei was an italian physicist, mathematician, astronomer\n",
"galileo was born in pisa\n"
] | none | 500 | [
{
"input": "galileo galilei was an italian physicist ,mathematician,astronomer",
"output": "galileo galilei was an italian physicist, mathematician, astronomer"
},
{
"input": "galileo was born in pisa",
"output": "galileo was born in pisa"
},
{
"input": "jkhksdfhsdfsf",
"outpu... | 1,674,061,022 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | s= input()#Abir . kumar . raj
a = ",.?!"
for i in a:
s = s.replace(i,i+" ")#Abir . kumar . raj
s = ' '.join(s.split()) #Abir . kumar . raj
for i in a:
s = s.replace(" "+i,i) #Abir. kumar. raj
print(s) | Title: Punctuation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text that consists of lowercase Latin letters, spaces and punctuation marks (dot, comma, exclamation mark and question mark). A word is defined as a sequence of consecutive Latin letters.
Your task is to ad... | ```python
s= input()#Abir . kumar . raj
a = ",.?!"
for i in a:
s = s.replace(i,i+" ")#Abir . kumar . raj
s = ' '.join(s.split()) #Abir . kumar . raj
for i in a:
s = s.replace(" "+i,i) #Abir. kumar. raj
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
463 | B | Caisa and Pylons | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math"
] | null | null | Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0 has zero height, the pylon with number *i* (*i*<=><=0) has height *h**i*. The goal of the game is ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *h*1, *h*2,<=..., *h**n* (1<=<=≤<=<=*h**i*<=<=≤<=<=105) representing the heights of the pylons. | Print a single number representing the minimum number of dollars paid by Caisa. | [
"5\n3 4 3 2 4\n",
"3\n4 4 4\n"
] | [
"4\n",
"4\n"
] | In the first sample he can pay 4 dollars and increase the height of pylon with number 0 by 4 units. Then he can safely pass to the last pylon. | 1,000 | [
{
"input": "5\n3 4 3 2 4",
"output": "4"
},
{
"input": "3\n4 4 4",
"output": "4"
},
{
"input": "99\n1401 2019 1748 3785 3236 3177 3443 3772 2138 1049 353 908 310 2388 1322 88 2160 2783 435 2248 1471 706 2468 2319 3156 3506 2794 1999 1983 2519 2597 3735 537 344 3519 3772 3872 2961 3895 20... | 1,676,653,775 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 77 | 10,649,600 | input()
print(max(map(int, str.split(input()))))
| Title: Caisa and Pylons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0... | ```python
input()
print(max(map(int, str.split(input()))))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,590,408,575 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 280 | 0 | a,b,c = map(int, input().rstrip().split(" "))
z = (a*b*c)**0.5
n1 = z/b
n2 = z/c
n3= z/a
print(int((4*(n1+n2+n3)))) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
a,b,c = map(int, input().rstrip().split(" "))
z = (a*b*c)**0.5
n1 = z/b
n2 = z/c
n3= z/a
print(int((4*(n1+n2+n3))))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
426 | B | Sereja and Mirroring | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Let's assume that we are given a matrix *b* of size *x*<=×<=*y*, let's determine the operation of mirroring matrix *b*. The mirroring of matrix *b* is a 2*x*<=×<=*y* matrix *c* which has the following properties:
- the upper half of matrix *c* (rows with numbers from 1 to *x*) exactly matches *b*; - the lower half o... | The first line contains two integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). Each of the next *n* lines contains *m* integers — the elements of matrix *a*. The *i*-th line contains integers *a**i*1,<=*a**i*2,<=...,<=*a**im* (0<=≤<=*a**ij*<=≤<=1) — the *i*-th row of the matrix *a*. | In the single line, print the answer to the problem — the minimum number of rows of matrix *b*. | [
"4 3\n0 0 1\n1 1 0\n1 1 0\n0 0 1\n",
"3 3\n0 0 0\n0 0 0\n0 0 0\n",
"8 1\n0\n1\n1\n0\n0\n1\n1\n0\n"
] | [
"2\n",
"3\n",
"2\n"
] | In the first test sample the answer is a 2 × 3 matrix *b*:
If we perform a mirroring operation with this matrix, we get the matrix *a* that is given in the input: | 1,000 | [
{
"input": "4 3\n0 0 1\n1 1 0\n1 1 0\n0 0 1",
"output": "2"
},
{
"input": "3 3\n0 0 0\n0 0 0\n0 0 0",
"output": "3"
},
{
"input": "8 1\n0\n1\n1\n0\n0\n1\n1\n0",
"output": "2"
},
{
"input": "10 4\n0 0 1 0\n0 0 1 0\n1 1 0 1\n0 0 1 1\n1 0 1 0\n1 0 1 0\n0 0 1 1\n1 1 0 1\n0 0 1 0\... | 1,398,613,939 | 1,339 | Python 3 | OK | TESTS | 65 | 77 | 0 | n, m = map(int, input().split())
ans = n
arr = []
for i in range(n):
arr.append(input())
while True:
if n & 1:
print(ans)
break
else:
k = n // 2
for i in range(k):
if arr[i] != arr[n - i - 1]:
print(ans)
exit(0)
... | Title: Sereja and Mirroring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's assume that we are given a matrix *b* of size *x*<=×<=*y*, let's determine the operation of mirroring matrix *b*. The mirroring of matrix *b* is a 2*x*<=×<=*y* matrix *c* which has the following properties:
... | ```python
n, m = map(int, input().split())
ans = n
arr = []
for i in range(n):
arr.append(input())
while True:
if n & 1:
print(ans)
break
else:
k = n // 2
for i in range(k):
if arr[i] != arr[n - i - 1]:
print(ans)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,610,851,342 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 218 | 0 | import math as m
#from math import comb as nCr
t=input
'''
for _ in range(int(t())):
n=int(t())
a,b=map(int,t().split())
a=list(map(int,t().split()))
'''
r,c=map(int,t().split())
k=[t() for y in range(r)]
rr,cc=0,0
for i in k:
cnt=i.count('S')
rr+=cnt;cc+=cnt
print(r*c - rr*cc) | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
import math as m
#from math import comb as nCr
t=input
'''
for _ in range(int(t())):
n=int(t())
a,b=map(int,t().split())
a=list(map(int,t().split()))
'''
r,c=map(int,t().split())
k=[t() for y in range(r)]
rr,cc=0,0
for i in k:
cnt=i.count('S')
rr+=cnt;cc+=cnt
print(r*c - r... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,665,750,203 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 46 | 102,400 | n, m = map(int, input().split())
x = ''
for i in range(n):
x += input()[1:].replace(' ', '')
y = [int(i) for i in x]
if set(y) == set(range(1, m+1)):
print('YES')
else:
print('NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n, m = map(int, input().split())
x = ''
for i in range(n):
x += input()[1:].replace(' ', '')
y = [int(i) for i in x]
if set(y) == set(range(1, m+1)):
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
733 | D | Kostya the Sculptor | PROGRAMMING | 1,600 | [
"data structures",
"hashing"
] | null | null | Kostya is a genial sculptor, he has an idea: to carve a marble sculpture in the shape of a sphere. Kostya has a friend Zahar who works at a career. Zahar knows about Kostya's idea and wants to present him a rectangular parallelepiped of marble from which he can carve the sphere.
Zahar has *n* stones which are rectang... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=105).
*n* lines follow, in the *i*-th of which there are three integers *a**i*,<=*b**i* and *c**i* (1<=≤<=*a**i*,<=*b**i*,<=*c**i*<=≤<=109) — the lengths of edges of the *i*-th stone. Note, that two stones may have exactly the same sizes, but they still will be co... | In the first line print *k* (1<=≤<=*k*<=≤<=2) the number of stones which Zahar has chosen. In the second line print *k* distinct integers from 1 to *n* — the numbers of stones which Zahar needs to choose. Consider that stones are numbered from 1 to *n* in the order as they are given in the input data.
You can print th... | [
"6\n5 5 5\n3 2 4\n1 4 1\n2 1 3\n3 2 4\n3 3 4\n",
"7\n10 7 8\n5 10 3\n4 2 6\n5 5 5\n10 2 8\n4 2 1\n7 7 7\n"
] | [
"1\n1\n",
"2\n1 5\n"
] | In the first example we can connect the pairs of stones:
- 2 and 4, the size of the parallelepiped: 3 × 2 × 5, the radius of the inscribed sphere 1 - 2 and 5, the size of the parallelepiped: 3 × 2 × 8 or 6 × 2 × 4 or 3 × 4 × 4, the radius of the inscribed sphere 1, or 1, or 1.5 respectively. - 2 and 6, the size of ... | 2,000 | [
{
"input": "6\n5 5 5\n3 2 4\n1 4 1\n2 1 3\n3 2 4\n3 3 4",
"output": "1\n1"
},
{
"input": "7\n10 7 8\n5 10 3\n4 2 6\n5 5 5\n10 2 8\n4 2 1\n7 7 7",
"output": "2\n1 5"
},
{
"input": "1\n1 1 1",
"output": "1\n1"
},
{
"input": "2\n2 3 1\n2 2 3",
"output": "2\n2 1"
},
{
... | 1,669,101,133 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 204,800 | #z=int(input())
import math
from itertools import combinations
import time
import random
alfabet = {'a': 1, 'b': 2,'c': 3,'d': 4,'e': 5,'f': 6,'g': 7,'h': 8,'i': 9,'j': 10,'k': 11,'l': 12,'m': 13,'n': 14,'o': 15,'p': 16,'q': 17,'r': 18,'s': 19,'t': 20,'u': 21,'v': 22,'w': 23,'x': 24,'y': 25,'z': 26}
a... | Title: Kostya the Sculptor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kostya is a genial sculptor, he has an idea: to carve a marble sculpture in the shape of a sphere. Kostya has a friend Zahar who works at a career. Zahar knows about Kostya's idea and wants to present him a rectangu... | ```python
#z=int(input())
import math
from itertools import combinations
import time
import random
alfabet = {'a': 1, 'b': 2,'c': 3,'d': 4,'e': 5,'f': 6,'g': 7,'h': 8,'i': 9,'j': 10,'k': 11,'l': 12,'m': 13,'n': 14,'o': 15,'p': 16,'q': 17,'r': 18,'s': 19,'t': 20,'u': 21,'v': 22,'w': 23,'x': 24,'y': 25,'... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
29 | C | Mail Stamps | PROGRAMMING | 1,700 | [
"data structures",
"dfs and similar",
"graphs",
"implementation"
] | C. Mail Stamps | 2 | 256 | One day Bob got a letter in an envelope. Bob knows that when Berland's post officers send a letter directly from city «A» to city «B», they stamp it with «A B», or «B A». Unfortunately, often it is impossible to send a letter directly from the city of the sender to the city of the receiver, that's why the letter is sen... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — amount of mail stamps on the envelope. Then there follow *n* lines with two integers each — description of the stamps. Each stamp is described with indexes of the cities between which a letter is sent. The indexes of cities are integers from 1 to 109. Indexes of... | Output *n*<=+<=1 numbers — indexes of cities in one of the two possible routes of the letter. | [
"2\n1 100\n100 2\n",
"3\n3 1\n100 2\n3 2\n"
] | [
"2 100 1 ",
"100 2 3 1 "
] | none | 1,500 | [
{
"input": "2\n1 100\n100 2",
"output": "2 100 1 "
},
{
"input": "3\n3 1\n100 2\n3 2",
"output": "100 2 3 1 "
},
{
"input": "3\n458744979 589655889\n248228386 824699605\n458744979 824699605",
"output": "589655889 458744979 824699605 248228386 "
},
{
"input": "4\n90104473 2210... | 1,539,430,373 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 8 | 248 | 0 | d1 = {}
d2 = {}
n = int(input())
for i in range(n):
a,b = map(int,input().split())
if a in d1.keys(): d1[a] += 1
else: d1[a] = 1
if b in d1.keys(): d1[b] += 1
else: d1[b] = 1
if a in d2.keys():
if b in d2.keys():
m = d2[a]
n = d2[b]
if m not in d2.k... | Title: Mail Stamps
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Bob got a letter in an envelope. Bob knows that when Berland's post officers send a letter directly from city «A» to city «B», they stamp it with «A B», or «B A». Unfortunately, often it is impossible to send a letter d... | ```python
d1 = {}
d2 = {}
n = int(input())
for i in range(n):
a,b = map(int,input().split())
if a in d1.keys(): d1[a] += 1
else: d1[a] = 1
if b in d1.keys(): d1[b] += 1
else: d1[b] = 1
if a in d2.keys():
if b in d2.keys():
m = d2[a]
n = d2[b]
if m n... | -1 | MatrixStudio/Codeforces-Python-Submissions |
493 | D | Vasya and Chess | PROGRAMMING | 1,700 | [
"constructive algorithms",
"games",
"math"
] | null | null | Vasya decided to learn to play chess. Classic chess doesn't seem interesting to him, so he plays his own sort of chess.
The queen is the piece that captures all squares on its vertical, horizontal and diagonal lines. If the cell is located on the same vertical, horizontal or diagonal line with queen, and the cell cont... | The input contains a single number *n* (2<=≤<=*n*<=≤<=109) — the size of the board. | On the first line print the answer to problem — string "white" or string "black", depending on who wins if the both players play optimally.
If the answer is "white", then you should also print two integers *r* and *c* representing the cell (*r*,<=*c*), where the first player should make his first move to win. If ther... | [
"2\n",
"3\n"
] | [
"white\n1 2\n",
"black\n"
] | In the first sample test the white queen can capture the black queen at the first move, so the white player wins.
In the second test from the statement if the white queen captures the green pawn located on the central vertical line, then it will be captured by the black queen during the next move. So the only move for... | 1,500 | [
{
"input": "2",
"output": "white\n1 2"
},
{
"input": "3",
"output": "black"
},
{
"input": "4",
"output": "white\n1 2"
},
{
"input": "6",
"output": "white\n1 2"
},
{
"input": "10",
"output": "white\n1 2"
},
{
"input": "16",
"output": "white\n1 2"
... | 1,549,345,132 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 264 | 6,041,600 | import sys
from math import *
from fractions import gcd
readints=lambda:map(int, input().strip('\n').split())
n=int(input())
if n==2:
print('white')
print('1 2')
elif n==3:
print('black')
else:
print('white')
print('2 1')
| Title: Vasya and Chess
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya decided to learn to play chess. Classic chess doesn't seem interesting to him, so he plays his own sort of chess.
The queen is the piece that captures all squares on its vertical, horizontal and diagonal lines. I... | ```python
import sys
from math import *
from fractions import gcd
readints=lambda:map(int, input().strip('\n').split())
n=int(input())
if n==2:
print('white')
print('1 2')
elif n==3:
print('black')
else:
print('white')
print('2 1')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
779 | B | Weird Rounding | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For example, if *k*<==<=3, in the number 30020 it is enough to delete a single digit (2). In this case, t... | The only line of the input contains two integer numbers *n* and *k* (0<=≤<=*n*<=≤<=2<=000<=000<=000, 1<=≤<=*k*<=≤<=9).
It is guaranteed that the answer exists. All numbers in the input are written in traditional notation of integers, that is, without any extra leading zeros. | Print *w* — the required minimal number of digits to erase. After removing the appropriate *w* digits from the number *n*, the result should have a value that is divisible by 10*k*. The result can start with digit 0 in the single case (the result is zero and written by exactly the only digit 0). | [
"30020 3\n",
"100 9\n",
"10203049 2\n"
] | [
"1\n",
"2\n",
"3\n"
] | In the example 2 you can remove two digits: 1 and any 0. The result is number 0 which is divisible by any number. | 1,000 | [
{
"input": "30020 3",
"output": "1"
},
{
"input": "100 9",
"output": "2"
},
{
"input": "10203049 2",
"output": "3"
},
{
"input": "0 1",
"output": "0"
},
{
"input": "0 9",
"output": "0"
},
{
"input": "100 2",
"output": "0"
},
{
"input": "102... | 1,611,476,662 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | if __name__ == "__main__":
n, k = [int(x) for x in input().split()]
digits = list(str(n))
n, k = [int(x) for x in input().split()]
digits = list(str(n))
zero_count = digits.count('0')
if zero_count < k:
print(len(str(n)) - 1)
exit()
zero_count = digits.count('0')
if zero_coun... | Title: Weird Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For e... | ```python
if __name__ == "__main__":
n, k = [int(x) for x in input().split()]
digits = list(str(n))
n, k = [int(x) for x in input().split()]
digits = list(str(n))
zero_count = digits.count('0')
if zero_count < k:
print(len(str(n)) - 1)
exit()
zero_count = digits.count('0')
if... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
797 | B | Odd sum | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains subsequence with odd sum.
Subsequence is a sequence that can be derived from another sequen... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=104<=≤<=*a**i*<=≤<=104). The sequence contains at least one subsequence with odd sum. | Print sum of resulting subseqeuence. | [
"4\n-2 2 -3 1\n",
"3\n2 -5 -3\n"
] | [
"3\n",
"-1\n"
] | In the first example sum of the second and the fourth elements is 3. | 0 | [
{
"input": "4\n-2 2 -3 1",
"output": "3"
},
{
"input": "3\n2 -5 -3",
"output": "-1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "1\n-1",
"output": "-1"
},
{
"input": "15\n-6004 4882 9052 413 6056 4306 9946 -4616 -6135 906 -1718 5252 -2866 9061 4046",
"ou... | 1,649,428,155 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
arr = [int(x) for x in input().split()]
inf = float('inf')
ans = -inf
dp = [False for i in range(n+1)]
def solver(ind, cursum):
global n, arr, ans
# print(ans)
# print(ind, cursum)
if ind == n :
if cursum %2:
ans = max(ans, cursum)
... | Title: Odd sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains... | ```python
n = int(input())
arr = [int(x) for x in input().split()]
inf = float('inf')
ans = -inf
dp = [False for i in range(n+1)]
def solver(ind, cursum):
global n, arr, ans
# print(ans)
# print(ind, cursum)
if ind == n :
if cursum %2:
ans = max(ans, cursum)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,475,694,466 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | n = int(input())
arr = sum(list(map(int,input().split())))
cnt=0
for i in range(1,6):
if ((arr+i)%(n+1) )!=1:
cnt+=1
print(cnt)
| Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n = int(input())
arr = sum(list(map(int,input().split())))
cnt=0
for i in range(1,6):
if ((arr+i)%(n+1) )!=1:
cnt+=1
print(cnt)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,609,196,463 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 249 | 4,710,400 | from collections import defaultdict
#from colections import Counter
def solution():
dictionary = defaultdict(str)
n,m = map(int,input().split())
for _ in range(m):
w1,w2 = input().split()
dictionary[w1] = w2
lecture = list(input().split())
for i in range(n):
word = ... | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
from collections import defaultdict
#from colections import Counter
def solution():
dictionary = defaultdict(str)
n,m = map(int,input().split())
for _ in range(m):
w1,w2 = input().split()
dictionary[w1] = w2
lecture = list(input().split())
for i in range(n):
... | 3 | MatrixStudio/Codeforces-Python-Submissions |
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