contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
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value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift.... | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,683,547,194 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 101 | 124 | 0 | import sys
input=sys.stdin.readline
n=int(input())
lst=[*map(int,input().split())]
answer=[0]*n
for i,f in enumerate(lst):
answer[f-1]=i+1
print(' '.join(map(str,answer))) | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on t... | ```python
import sys
input=sys.stdin.readline
n=int(input())
lst=[*map(int,input().split())]
answer=[0]*n
for i,f in enumerate(lst):
answer[f-1]=i+1
print(' '.join(map(str,answer)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,591,125,569 | 2,147,483,647 | Python 3 | OK | TESTS | 104 | 124 | 0 | dc = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
m, d = map(int, input().split())
print((dc[m] + d + 5) // 7)
| Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
dc = [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
m, d = map(int, input().split())
print((dc[m] + d + 5) // 7)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
476 | A | Dreamoon and Stairs | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition? | The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10). | Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead. | [
"10 2\n",
"3 5\n"
] | [
"6\n",
"-1\n"
] | For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | 500 | [
{
"input": "10 2",
"output": "6"
},
{
"input": "3 5",
"output": "-1"
},
{
"input": "29 7",
"output": "21"
},
{
"input": "2 2",
"output": "2"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "10000 2",
"output": "5000"
},
{
"input": "10000 ... | 1,664,854,964 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | n, m = map(int, input().split())
count = 0
if m > n :
count = -1
else:
if (n%2==0):
count = n / 2+1
else:
count = n/2
if(count%m!=0):
count+=1
print(int(count))
| Title: Dreamoon and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb ... | ```python
n, m = map(int, input().split())
count = 0
if m > n :
count = -1
else:
if (n%2==0):
count = n / 2+1
else:
count = n/2
if(count%m!=0):
count+=1
print(int(count))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
755 | A | PolandBall and Hypothesis | PROGRAMMING | 800 | [
"brute force",
"graphs",
"math",
"number theory"
] | null | null | PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is a prime number".
Unfortunately, PolandBall is not experienced yet and doesn't know that his hypothesis is inc... | The only number in the input is *n* (1<=≤<=*n*<=≤<=1000) — number from the PolandBall's hypothesis. | Output such *m* that *n*·*m*<=+<=1 is not a prime number. Your answer will be considered correct if you output any suitable *m* such that 1<=≤<=*m*<=≤<=103. It is guaranteed the the answer exists. | [
"3\n",
"4\n"
] | [
"1",
"2"
] | A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.
For the first sample testcase, 3·1 + 1 = 4. We can output 1.
In the second sample testcase, 4·1 + 1 = 5. We cannot output 1 because 5 is prime. However, *m* = 2 is okay since 4·2 + 1 = 9, which is not... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "2"
},
{
"input": "153",
"output": "1"
},
{
"input": "1000",
"output": "1"
},
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "4"
... | 1,632,508,911 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | n = int(input())
if(n==1):
print(3)
elif(n==2):
print(4)
elif(n%2!=0):
print(1)
else:
print(n)
| Title: PolandBall and Hypothesis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is... | ```python
n = int(input())
if(n==1):
print(3)
elif(n==2):
print(4)
elif(n%2!=0):
print(1)
else:
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,689,828,283 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | p1=int(input())
p2=int(input())
p3=int(input())
ans=p1+p2+p3
ans=min(ans,p1+p1+p2+p2)
ans=min(ans,p1+p3+p3+p2)
ans=min(ans,p2+p3+p3+p2)
print(ans) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
p1=int(input())
p2=int(input())
p3=int(input())
ans=p1+p2+p3
ans=min(ans,p1+p1+p2+p2)
ans=min(ans,p1+p3+p3+p2)
ans=min(ans,p2+p3+p3+p2)
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
844 | A | Diversity | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"strings"
] | null | null | Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too. | First line of input contains string *s*, consisting only of lowercase Latin letters (1<=≤<=|*s*|<=≤<=1000, |*s*| denotes the length of *s*).
Second line of input contains integer *k* (1<=≤<=*k*<=≤<=26). | Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible. | [
"yandex\n6\n",
"yahoo\n5\n",
"google\n7\n"
] | [
"0\n",
"1\n",
"impossible\n"
] | In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'*a*', '*h*', '*o*', '*y*'}. To get 5 different letters it is necessary to change one occurrence of '*o*' to some letter, which doesn't occur in the string, for... | 500 | [
{
"input": "yandex\n6",
"output": "0"
},
{
"input": "yahoo\n5",
"output": "1"
},
{
"input": "google\n7",
"output": "impossible"
},
{
"input": "a\n1",
"output": "0"
},
{
"input": "z\n2",
"output": "impossible"
},
{
"input": "fwgfrwgkuwghfiruhewgirueguhe... | 1,600,177,278 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 140 | 0 | s=input()
k=int(input())
n=len(s)
if k>n:exit(print('impossible'))
print(max(k-len(set(s)),0)) | Title: Diversity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it... | ```python
s=input()
k=int(input())
n=len(s)
if k>n:exit(print('impossible'))
print(max(k-len(set(s)),0))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,586,434,981 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 93 | 307,200 | def maxJokes(n,li,d):
s=0
for i in range(n-1):
s=s+(li[i]+10)
if s+li[n-1]>d:
return -1
else:
temp=[]
i=0
c=0
p=i
j=0
while i<d:
i+=li[j]+10
c+=2
p=i
j+=1
c=c+((d-p)//5)
return c
n,d=input().split()
li = [int(x) for x in input().split()]
print(maxJokes(int(n),li,int(d))) | Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
def maxJokes(n,li,d):
s=0
for i in range(n-1):
s=s+(li[i]+10)
if s+li[n-1]>d:
return -1
else:
temp=[]
i=0
c=0
p=i
j=0
while i<d:
i+=li[j]+10
c+=2
p=i
j+=1
c=c+((d-p)//5)
return c
n,d=input().split()
li = [int(x) for x in input().split()]
print(maxJokes(int(n),li,int(d)... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,644,559,318 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | s = input()
floor = 0
if '8' in s:
print(10)
else:
while True:
s = str(int(s)+1)
floor += 1
if '8' in s:
break
print(floor) | Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
s = input()
floor = 0
if '8' in s:
print(10)
else:
while True:
s = str(int(s)+1)
floor += 1
if '8' in s:
break
print(floor)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,472,993,475 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 0 | y,k,n=map(int,input().split())
l=[]
for x in range(y+1,n+1):
if x%k==0: l+=[str(x-y)]
if len(l)==0: print(-1)
else: print(" ".join(l)) | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
y,k,n=map(int,input().split())
l=[]
for x in range(y+1,n+1):
if x%k==0: l+=[str(x-y)]
if len(l)==0: print(-1)
else: print(" ".join(l))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
408 | A | Line to Cashier | PROGRAMMING | 900 | [
"implementation"
] | null | null | Little Vasya went to the supermarket to get some groceries. He walked about the supermarket for a long time and got a basket full of products. Now he needs to choose the cashier to pay for the products.
There are *n* cashiers at the exit from the supermarket. At the moment the queue for the *i*-th cashier already has ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of cashes in the shop. The second line contains *n* space-separated integers: *k*1,<=*k*2,<=...,<=*k**n* (1<=≤<=*k**i*<=≤<=100), where *k**i* is the number of people in the queue to the *i*-th cashier.
The *i*-th of the next *n* lines contains *k**i*... | Print a single integer — the minimum number of seconds Vasya needs to get to the cashier. | [
"1\n1\n1\n",
"4\n1 4 3 2\n100\n1 2 2 3\n1 9 1\n7 8\n"
] | [
"20\n",
"100\n"
] | In the second test sample, if Vasya goes to the first queue, he gets to the cashier in 100·5 + 15 = 515 seconds. But if he chooses the second queue, he will need 1·5 + 2·5 + 2·5 + 3·5 + 4·15 = 100 seconds. He will need 1·5 + 9·5 + 1·5 + 3·15 = 100 seconds for the third one and 7·5 + 8·5 + 2·15 = 105 seconds for the fou... | 500 | [
{
"input": "1\n1\n1",
"output": "20"
},
{
"input": "4\n1 4 3 2\n100\n1 2 2 3\n1 9 1\n7 8",
"output": "100"
},
{
"input": "4\n5 4 5 5\n3 1 3 1 2\n3 1 1 3\n1 1 1 2 2\n2 2 1 1 3",
"output": "100"
},
{
"input": "5\n5 3 6 6 4\n7 5 3 3 9\n6 8 2\n1 10 8 5 9 2\n9 7 8 5 9 10\n9 8 3 3"... | 1,668,974,531 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 62 | 1,536,000 | from sys import stdin , stdout
input=stdin.readline
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
cashers=int(input()) ; queue=list(map(int,input().split())) ; ans=10**18
for i in range(cashers):
summ=sum(list(map(int,input().split())))
summ*=5
summ... | Title: Line to Cashier
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vasya went to the supermarket to get some groceries. He walked about the supermarket for a long time and got a basket full of products. Now he needs to choose the cashier to pay for the products.
There are *n* c... | ```python
from sys import stdin , stdout
input=stdin.readline
def print(*args, end='\n', sep=' ') -> None:
stdout.write(sep.join(map(str, args)) + end)
cashers=int(input()) ; queue=list(map(int,input().split())) ; ans=10**18
for i in range(cashers):
summ=sum(list(map(int,input().split())))
summ*=5... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
265 | B | Roadside Trees (Simplified Edition) | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | Squirrel Liss loves nuts. There are *n* trees (numbered 1 to *n* from west to east) along a street and there is a delicious nut on the top of each tree. The height of the tree *i* is *h**i*. Liss wants to eat all nuts.
Now Liss is on the root of the tree with the number 1. In one second Liss can perform one of the fol... | The first line contains an integer *n* (1<=<=≤<=<=*n*<=≤<=105) — the number of trees.
Next *n* lines contains the height of trees: *i*-th line contains an integer *h**i* (1<=≤<=*h**i*<=≤<=104) — the height of the tree with the number *i*. | Print a single integer — the minimal time required to eat all nuts in seconds. | [
"2\n1\n2\n",
"5\n2\n1\n2\n1\n1\n"
] | [
"5\n",
"14\n"
] | none | 1,000 | [
{
"input": "2\n1\n2",
"output": "5"
},
{
"input": "5\n2\n1\n2\n1\n1",
"output": "14"
},
{
"input": "1\n1",
"output": "2"
}
] | 1,622,716,241 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 560 | 2,457,600 | # -*- coding: utf-8 -*-
"""Untitled56.ipynb
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1K9zIFsLtcOLH7zehDUTwmMg_CXFRqu9H
"""
n=int(input())
l1=[]
for i in range(0,n):
x=int(input())
l1.append(x)
c=l1[0]+2
for i in range(1,len(l1)):
if l1[i]<... | Title: Roadside Trees (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Squirrel Liss loves nuts. There are *n* trees (numbered 1 to *n* from west to east) along a street and there is a delicious nut on the top of each tree. The height of the tree *i* is *h**i*. Liss wan... | ```python
# -*- coding: utf-8 -*-
"""Untitled56.ipynb
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1K9zIFsLtcOLH7zehDUTwmMg_CXFRqu9H
"""
n=int(input())
l1=[]
for i in range(0,n):
x=int(input())
l1.append(x)
c=l1[0]+2
for i in range(1,len(l1)):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero,... | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,696,905,050 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 11 | 62 | 0 | #initializes initial number and number of operations
numbers = input().split(' ')
number = int(numbers[0])
operations = int(numbers[1])
#performs designated operations per designated amount of times
for x in range(operations):
if number % 10 == 0:
number //= 10
else:
number -= 1
#print final n... | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit ... | ```python
#initializes initial number and number of operations
numbers = input().split(' ')
number = int(numbers[0])
operations = int(numbers[1])
#performs designated operations per designated amount of times
for x in range(operations):
if number % 10 == 0:
number //= 10
else:
number -= 1
#pri... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
672 | B | Different is Good | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are different, he wants all substrings of his string *s* to be distinct. Substring is a string formed by some... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the string *s*.
The second line contains the string *s* of length *n* consisting of only lowercase English letters. | If it's impossible to change the string *s* such that all its substring are distinct print -1. Otherwise print the minimum required number of changes. | [
"2\naa\n",
"4\nkoko\n",
"5\nmurat\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko". | 1,000 | [
{
"input": "2\naa",
"output": "1"
},
{
"input": "4\nkoko",
"output": "2"
},
{
"input": "5\nmurat",
"output": "0"
},
{
"input": "6\nacbead",
"output": "1"
},
{
"input": "7\ncdaadad",
"output": "4"
},
{
"input": "25\npeoaicnbisdocqofsqdpgobpn",
"outp... | 1,609,073,436 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 155 | 1,638,400 | n=int(input())
s1=input()
s2=set(s1)
if(len(s1)>26):
print(-1)
else:
print(len(s1)-len(s2)) | Title: Different is Good
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are di... | ```python
n=int(input())
s1=input()
s2=set(s1)
if(len(s1)>26):
print(-1)
else:
print(len(s1)-len(s2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
225 | A | Dice Tower | PROGRAMMING | 1,100 | [
"constructive algorithms",
"greedy"
] | null | null | A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other) that satisfy the given constraints (both of them are shown on the picture on the left).
Alice... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of dice in the tower.
The second line contains an integer *x* (1<=≤<=*x*<=≤<=6) — the number Bob sees at the top of the tower. Next *n* lines contain two space-separated integers each: the *i*-th line contains numbers *a**i*,<=*b**i* (1<=≤<=... | Print "YES" (without the quotes), if it is possible to to uniquely identify the numbers on the faces of all the dice in the tower. If it is impossible, print "NO" (without the quotes). | [
"3\n6\n3 2\n5 4\n2 4\n",
"3\n3\n2 6\n4 1\n5 3\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "3\n6\n3 2\n5 4\n2 4",
"output": "YES"
},
{
"input": "3\n3\n2 6\n4 1\n5 3",
"output": "NO"
},
{
"input": "1\n3\n2 1",
"output": "YES"
},
{
"input": "2\n2\n3 1\n1 5",
"output": "NO"
},
{
"input": "3\n2\n1 4\n5 3\n6 4",
"output": "NO"
},
{
"in... | 1,610,358,758 | 2,147,483,647 | PyPy 3 | OK | TESTS | 52 | 186 | 0 | n = int(input())
x = int(input())
dice = []
for i in range(n):
dice.append(list(map(int,input().split())))
ans = "YES"
for i in range(n):
dice[i].append(7-dice[i][0])
dice[i].append(7-dice[i][1])
for i in range(n):
if 7-x in dice[i]:
ans = "NO"
break
print(ans) | Title: Dice Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other... | ```python
n = int(input())
x = int(input())
dice = []
for i in range(n):
dice.append(list(map(int,input().split())))
ans = "YES"
for i in range(n):
dice[i].append(7-dice[i][0])
dice[i].append(7-dice[i][1])
for i in range(n):
if 7-x in dice[i]:
ans = "NO"
break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,647,850,006 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 62 | 1,945,600 | n=int(input())
num=0
for i in range(1,n//2+1):
temp=n-i
if temp%i==0:
num+=1
temp=0
print(num) | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
n=int(input())
num=0
for i in range(1,n//2+1):
temp=n-i
if temp%i==0:
num+=1
temp=0
print(num)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
20 | A | BerOS file system | PROGRAMMING | 1,700 | [
"implementation"
] | A. BerOS file system | 2 | 64 | The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of ... | The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty. | The path in normalized form. | [
"//usr///local//nginx/sbin\n"
] | [
"/usr/local/nginx/sbin\n"
] | none | 500 | [
{
"input": "//usr///local//nginx/sbin",
"output": "/usr/local/nginx/sbin"
},
{
"input": "////a//b/////g",
"output": "/a/b/g"
},
{
"input": "/a/b/c",
"output": "/a/b/c"
},
{
"input": "/",
"output": "/"
},
{
"input": "////",
"output": "/"
},
{
"input": "... | 1,641,991,753 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | s=str(input())
while True :
s=s.replace("//","/")
s=s.replace("//","/")
if "//" in s:
continue
else :
break
print(s) | Title: BerOS file system
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/n... | ```python
s=str(input())
while True :
s=s.replace("//","/")
s=s.replace("//","/")
if "//" in s:
continue
else :
break
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,641,480,568 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 92 | 0 | n = int(input())
lst = list(map(int,input().split()))
lst.sort()
count = 0
for i in range(n):
if lst[i] != i+1:
count += 1
print(count) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
n = int(input())
lst = list(map(int,input().split()))
lst.sort()
count = 0
for i in range(n):
if lst[i] != i+1:
count += 1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
804 | A | Find Amir | PROGRAMMING | 1,000 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | A few years ago Sajjad left his school and register to another one due to security reasons. Now he wishes to find Amir, one of his schoolmates and good friends.
There are *n* schools numerated from 1 to *n*. One can travel between each pair of them, to do so, he needs to buy a ticket. The ticker between schools *i* an... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of schools. | Print single integer: the minimum cost of tickets needed to visit all schools. | [
"2\n",
"10\n"
] | [
"0\n",
"4\n"
] | In the first example we can buy a ticket between the schools that costs <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c67d72010e0498bfd065a6a38fdeaec90358507b.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 500 | [
{
"input": "2",
"output": "0"
},
{
"input": "10",
"output": "4"
},
{
"input": "43670",
"output": "21834"
},
{
"input": "4217",
"output": "2108"
},
{
"input": "17879",
"output": "8939"
},
{
"input": "31809",
"output": "15904"
},
{
"input": "... | 1,652,776,186 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 62 | 28,364,800 | n = int(input())
print (int(((n/2) % (n+1))-1))
| Title: Find Amir
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A few years ago Sajjad left his school and register to another one due to security reasons. Now he wishes to find Amir, one of his schoolmates and good friends.
There are *n* schools numerated from 1 to *n*. One can travel b... | ```python
n = int(input())
print (int(((n/2) % (n+1))-1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,591,908,775 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 307,200 | n=int(input())
x=input()
l=x.split(' ')
arr={None:None}
for i in range(len(l)):
p=int(l[i])
if arr.get(p)==None:
arr[p]=1
for j in range(len(l)):
if i!=j and int(l[i])<int(l[j]):
arr[p]+=1
for i in range(len(l)):
print(arr[int(l[i])],end=' ')
... | Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
n=int(input())
x=input()
l=x.split(' ')
arr={None:None}
for i in range(len(l)):
p=int(l[i])
if arr.get(p)==None:
arr[p]=1
for j in range(len(l)):
if i!=j and int(l[i])<int(l[j]):
arr[p]+=1
for i in range(len(l)):
print(arr[int(l[i])],end=' ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,671,109,095 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | def main():
ternary_number = input()
decoding_list = [',','-.', '--']
check = 0
for i in range(len(ternary_number)):
if check == 1:
check = 0
continue
if i == len(ternary_number) - 1:
print(0, end = "")
break
num = terna... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
def main():
ternary_number = input()
decoding_list = [',','-.', '--']
check = 0
for i in range(len(ternary_number)):
if check == 1:
check = 0
continue
if i == len(ternary_number) - 1:
print(0, end = "")
break
n... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
35 | A | Shell Game | PROGRAMMING | 1,000 | [
"implementation"
] | A. Shell Game | 2 | 64 | Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly puts a small ball under one of the cups and starts to shuffle the cups around very quickly so ... | The first input line contains an integer from 1 to 3 — index of the cup which covers the ball before the shuffles. The following three lines describe the shuffles. Each description of a shuffle contains two distinct integers from 1 to 3 — indexes of the cups which the performer shuffled this time. The cups are numbered... | In the first line output an integer from 1 to 3 — index of the cup which will have the ball after all the shuffles. | [
"1\n1 2\n2 1\n2 1\n",
"1\n2 1\n3 1\n1 3\n"
] | [
"2\n",
"2\n"
] | none | 500 | [
{
"input": "1\n1 2\n2 1\n2 1",
"output": "2"
},
{
"input": "1\n2 1\n3 1\n1 3",
"output": "2"
},
{
"input": "3\n3 1\n2 1\n1 2",
"output": "1"
},
{
"input": "1\n1 3\n1 2\n2 3",
"output": "2"
},
{
"input": "3\n3 2\n3 1\n3 1",
"output": "2"
},
{
"input": "... | 1,597,341,516 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 404 | 2,150,400 | ball=int(input())
for i in range(3):
a,b=map(int,input().split())
if(a==ball):
ball=b
elif b==ball:
ball=a
print(ball) | Title: Shell Game
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Today the «Z» city residents enjoy a shell game competition. The residents are gathered on the main square to watch the breath-taking performance. The performer puts 3 non-transparent cups upside down in a row. Then he openly put... | ```python
ball=int(input())
for i in range(3):
a,b=map(int,input().split())
if(a==ball):
ball=b
elif b==ball:
ball=a
print(ball)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,680,278,605 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 92 | 0 | num = int(input())
ans = 0
for i in range(6, num+1):
check = set()
d = 2
temp = i
while d*d <= temp:
while temp % d == 0:
check.add(d)
temp //= d
if d == 2:
d += 1
else:
d += 2
if temp > 1:
check.add(temp)... | Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
num = int(input())
ans = 0
for i in range(6, num+1):
check = set()
d = 2
temp = i
while d*d <= temp:
while temp % d == 0:
check.add(d)
temp //= d
if d == 2:
d += 1
else:
d += 2
if temp > 1:
check... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
722 | C | Destroying Array | PROGRAMMING | 1,600 | [
"data structures",
"dsu"
] | null | null | You are given an array consisting of *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
You are going to destroy integers in the array one by one. Thus, you are given the permutation of integers from 1 to *n* defining the order elements of the array are destroyed.
After each element is destroyed you have to find o... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109).
The third line contains a permutation of integers from 1 to *n* — the order used to destroy elements. | Print *n* lines. The *i*-th line should contain a single integer — the maximum possible sum of elements on the segment containing no destroyed elements, after first *i* operations are performed. | [
"4\n1 3 2 5\n3 4 1 2\n",
"5\n1 2 3 4 5\n4 2 3 5 1\n",
"8\n5 5 4 4 6 6 5 5\n5 2 8 7 1 3 4 6\n"
] | [
"5\n4\n3\n0\n",
"6\n5\n5\n1\n0\n",
"18\n16\n11\n8\n8\n6\n6\n0\n"
] | Consider the first sample:
1. Third element is destroyed. Array is now 1 3 * 5. Segment with maximum sum 5 consists of one integer 5. 1. Fourth element is destroyed. Array is now 1 3 * * . Segment with maximum sum 4 consists of two integers 1 3. 1. First element is destroyed. Array is now * 3 * * . Segme... | 1,000 | [
{
"input": "4\n1 3 2 5\n3 4 1 2",
"output": "5\n4\n3\n0"
},
{
"input": "5\n1 2 3 4 5\n4 2 3 5 1",
"output": "6\n5\n5\n1\n0"
},
{
"input": "8\n5 5 4 4 6 6 5 5\n5 2 8 7 1 3 4 6",
"output": "18\n16\n11\n8\n8\n6\n6\n0"
},
{
"input": "10\n3 3 3 5 6 9 3 1 7 3\n3 4 6 7 5 1 10 9 2 8"... | 1,476,114,272 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 37 | 342 | 18,022,400 | def main():
def f(x):
y = clusters[x]
if y != x:
y = clusters[x] = f(y)
return y
n, aa = int(input()), [0, *map(int, input().split()), 0]
l, clusters, mx = list(map(int, input().split())), [0] * (n + 2), 0
for i in range(n - 1, -1, -1):
a = clusters[a] = l[i]... | Title: Destroying Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array consisting of *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
You are going to destroy integers in the array one by one. Thus, you are given the permutation of integers from 1 to *n* defin... | ```python
def main():
def f(x):
y = clusters[x]
if y != x:
y = clusters[x] = f(y)
return y
n, aa = int(input()), [0, *map(int, input().split()), 0]
l, clusters, mx = list(map(int, input().split())), [0] * (n + 2), 0
for i in range(n - 1, -1, -1):
a = clusters... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
115 | A | Party | PROGRAMMING | 900 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of another employee *B* if at least one of the following is true:
- Employee *A* is the immedi... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of employees.
The next *n* lines contain the integers *p**i* (1<=≤<=*p**i*<=≤<=*n* or *p**i*<==<=-1). Every *p**i* denotes the immediate manager for the *i*-th employee. If *p**i* is -1, that means that the *i*-th employee does not have an immediate... | Print a single integer denoting the minimum number of groups that will be formed in the party. | [
"5\n-1\n1\n2\n1\n-1\n"
] | [
"3\n"
] | For the first example, three groups are sufficient, for example:
- Employee 1 - Employees 2 and 4 - Employees 3 and 5 | 500 | [
{
"input": "5\n-1\n1\n2\n1\n-1",
"output": "3"
},
{
"input": "4\n-1\n1\n2\n3",
"output": "4"
},
{
"input": "12\n-1\n1\n2\n3\n-1\n5\n6\n7\n-1\n9\n10\n11",
"output": "4"
},
{
"input": "6\n-1\n-1\n2\n3\n1\n1",
"output": "3"
},
{
"input": "3\n-1\n1\n1",
"output": ... | 1,675,659,495 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 60 | 0 | n = int(input())
g = 0
managers = []
for i in range(n):
p = int(input())
if p not in managers:
managers.append(p)
g += 1
print(g) | Title: Party
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A company has *n* employees numbered from 1 to *n*. Each employee either has no immediate manager or exactly one immediate manager, who is another employee with a different number. An employee *A* is said to be the superior of an... | ```python
n = int(input())
g = 0
managers = []
for i in range(n):
p = int(input())
if p not in managers:
managers.append(p)
g += 1
print(g)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
928 | A | Login Verification | PROGRAMMING | 1,200 | [
"*special",
"strings"
] | null | null | When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercase latin letters, digits and underline symbols («_»). However, in order to decrease the number of frauds ... | The first line contains a non-empty string *s* consisting of lower and uppercase latin letters, digits and underline symbols («_») with length not exceeding 50 — the login itself.
The second line contains a single integer *n* (1<=≤<=*n*<=≤<=1<=000) — the number of existing logins.
The next *n* lines describe the exi... | Print «Yes» (without quotes), if user can register via this login, i.e. none of the existing logins is similar with it.
Otherwise print «No» (without quotes). | [
"1_wat\n2\n2_wat\nwat_1\n",
"000\n3\n00\nooA\noOo\n",
"_i_\n3\n__i_\n_1_\nI\n",
"La0\n3\n2a0\nLa1\n1a0\n",
"abc\n1\naBc\n",
"0Lil\n2\nLIL0\n0Ril\n"
] | [
"Yes\n",
"No\n",
"No\n",
"No\n",
"No\n",
"Yes\n"
] | In the second sample case the user wants to create a login consisting of three zeros. It's impossible due to collision with the third among the existing.
In the third sample case the new login is similar with the second one. | 500 | [
{
"input": "1_wat\n2\n2_wat\nwat_1",
"output": "Yes"
},
{
"input": "000\n3\n00\nooA\noOo",
"output": "No"
},
{
"input": "_i_\n3\n__i_\n_1_\nI",
"output": "No"
},
{
"input": "La0\n3\n2a0\nLa1\n1a0",
"output": "No"
},
{
"input": "abc\n1\naBc",
"output": "No"
}... | 1,519,487,967 | 1,467 | PyPy 3 | RUNTIME_ERROR | PRETESTS | 0 | 108 | 20,787,200 | from collections import Counter
def corr(s):
z=''
for i in s:
z=z+d[i]
return z
s=input()
n=int(input())
d={}
for i in range(ord('a'),ord('z')+1):
d[chr(i)]=chr(i-ord('a')+ord('A'))
for i in range(ord('A'),ord('Z')+1):
d[chr(i)]=chr(i)
for i in range(10):
d[str(i)]=str(i)
... | Title: Login Verification
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercas... | ```python
from collections import Counter
def corr(s):
z=''
for i in s:
z=z+d[i]
return z
s=input()
n=int(input())
d={}
for i in range(ord('a'),ord('z')+1):
d[chr(i)]=chr(i-ord('a')+ord('A'))
for i in range(ord('A'),ord('Z')+1):
d[chr(i)]=chr(i)
for i in range(10):
d[str(i)... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | The evil Bumbershoot corporation produces clones for gruesome experiments in a vast underground lab. On one occasion, the corp cloned a boy Andryusha who was smarter than his comrades. Immediately Andryusha understood that something fishy was going on there. He rallied fellow clones to go on a feud against the evil cor... | The first line contains three integers *n*, *m*, and *k* (1<=≤<=*n*<=≤<=2·105, *n*<=-<=1<=≤<=*m*<=≤<=2·105, 1<=≤<=*k*<=≤<=*n*) — the number of vertices and edges in the lab, and the number of clones.
Each of the next *m* lines contains two integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — indices of vertice... | You should print *k* lines. *i*-th of these lines must start with an integer *c**i* () — the number of vertices visited by *i*-th clone, followed by *c**i* integers — indices of vertices visited by this clone in the order of visiting. You have to print each vertex every time it is visited, regardless if it was visited ... | [
"3 2 1\n2 1\n3 1\n",
"5 4 2\n1 2\n1 3\n1 4\n1 5\n"
] | [
"3 2 1 3\n",
"3 2 1 3\n3 4 1 5"
] | In the first sample case there is only one clone who may visit vertices in order (2, 1, 3), which fits the constraint of 6 vertices per clone.
In the second sample case the two clones can visited vertices in order (2, 1, 3) and (4, 1, 5), which fits the constraint of 5 vertices per clone. | 0 | [
{
"input": "3 2 1\n2 1\n3 1",
"output": "5 1 2 1 3 1"
},
{
"input": "5 4 2\n1 2\n1 3\n1 4\n1 5",
"output": "5 1 2 1 3 1\n4 4 1 5 1"
},
{
"input": "3 3 2\n1 3\n2 1\n3 2",
"output": "3 1 3 1\n2 2 1"
},
{
"input": "10 30 3\n6 5\n3 2\n7 8\n2 6\n1 9\n3 6\n6 5\n4 7\n3 2\n1 9\n7 8\n... | 1,597,182,783 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 151,449,600 | from math import ceil
import sys
sys.setrecursionlimit(200000)
n,m,k = map(int,sys.stdin.readline().split())
adj = [set() for i in range(n)]
vis = [False for i in range(n)]
deg = [0 for i in range(n)]
for i in range(m):
u,v = map(int,input().split())
if u!=v:
deg[u-1] += 1
deg[v-1] ... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The evil Bumbershoot corporation produces clones for gruesome experiments in a vast underground lab. On one occasion, the corp cloned a boy Andryusha who was smarter than his comrades. Immediately Andryusha understood that somethi... | ```python
from math import ceil
import sys
sys.setrecursionlimit(200000)
n,m,k = map(int,sys.stdin.readline().split())
adj = [set() for i in range(n)]
vis = [False for i in range(n)]
deg = [0 for i in range(n)]
for i in range(m):
u,v = map(int,input().split())
if u!=v:
deg[u-1] += 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
735 | D | Taxes | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not equal to *n*, of course). For example, if *n*<==<=6 then Funt has to pay 3 burles, while fo... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·109) — the total year income of mr. Funt. | Print one integer — minimum possible number of burles that mr. Funt has to pay as a tax. | [
"4\n",
"27\n"
] | [
"2\n",
"3\n"
] | none | 1,750 | [
{
"input": "4",
"output": "2"
},
{
"input": "27",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "2000000000",
"output": "2"
},
{
"input": "26",
"output": ... | 1,562,670,217 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 109 | 0 | from math import sqrt, ceil
def check(x):
for i in range(2, ceil(sqrt(x)) + 1):
if x % i == 0:
return 0
return 1
n = int(input())
if n <= 3 or n % 2 == 0:
print(2)
exit()
if check(n):
print(1)
elif check(n - 2):
print(1)
else:
print(3)
| Title: Taxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not ... | ```python
from math import sqrt, ceil
def check(x):
for i in range(2, ceil(sqrt(x)) + 1):
if x % i == 0:
return 0
return 1
n = int(input())
if n <= 3 or n % 2 == 0:
print(2)
exit()
if check(n):
print(1)
elif check(n - 2):
print(1)
else:
print(3)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
182 | D | Common Divisors | PROGRAMMING | 1,400 | [
"brute force",
"hashing",
"implementation",
"math",
"strings"
] | null | null | Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive integer *x* such that if we write out string *a* consecutively *x* times, we get string *b*. For exam... | The first input line contains a non-empty string *s*1.
The second input line contains a non-empty string *s*2.
Lengths of strings *s*1 and *s*2 are positive and do not exceed 105. The strings only consist of lowercase Latin letters. | Print the number of common divisors of strings *s*1 and *s*2. | [
"abcdabcd\nabcdabcdabcdabcd\n",
"aaa\naa\n"
] | [
"2\n",
"1\n"
] | In first sample the common divisors are strings "abcd" and "abcdabcd".
In the second sample the common divisor is a single string "a". String "aa" isn't included in the answer as it isn't a divisor of string "aaa". | 1,000 | [
{
"input": "abcdabcd\nabcdabcdabcdabcd",
"output": "2"
},
{
"input": "aaa\naa",
"output": "1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaa\naaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "3"
},
{
"input": "aaaaaaaaaaaaaa\naaaaaaaaaaaaaa",
"output": "4"
},
{
"input": "a\nb",
... | 1,605,097,013 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 218 | 1,228,800 | def commondiv(A,B):
front=0
end=1
if len(A)>len(B):
short=B
long=A
else:
short=A
long=B
length=0
while(end<len(short)):
if short[front]==short[end]:
if end==len(short)-1:
length=end-front
else:
temp1=front+1
temp2=end+1
leng=0
while short[temp1]==short[temp2]:
temp... | Title: Common Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive ... | ```python
def commondiv(A,B):
front=0
end=1
if len(A)>len(B):
short=B
long=A
else:
short=A
long=B
length=0
while(end<len(short)):
if short[front]==short[end]:
if end==len(short)-1:
length=end-front
else:
temp1=front+1
temp2=end+1
leng=0
while short[temp1]==short[temp2]:... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
900 | C | Remove Extra One | PROGRAMMING | 1,700 | [
"brute force",
"data structures",
"math"
] | null | null | You are given a permutation *p* of length *n*. Remove one element from permutation to make the number of records the maximum possible.
We remind that in a sequence of numbers *a*1,<=*a*2,<=...,<=*a**k* the element *a**i* is a record if for every integer *j* (1<=≤<=*j*<=<<=*i*) the following holds: *a**j*<=<<=*a*... | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=105) — the length of the permutation.
The second line contains *n* integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the permutation. All the integers are distinct. | Print the only integer — the element that should be removed to make the number of records the maximum possible. If there are multiple such elements, print the smallest one. | [
"1\n1\n",
"5\n5 1 2 3 4\n"
] | [
"1\n",
"5\n"
] | In the first example the only element can be removed. | 1,500 | [
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n5 1 2 3 4",
"output": "5"
},
{
"input": "5\n4 3 5 1 2",
"output": "1"
},
{
"input": "9\n9 5 8 6 3 2 4 1 7",
"output": "9"
},
{
"input": "3\n3 2 1",
"output": "1"
},
{
"input": "7\n1 6 7 4 2 5 3",
"... | 1,555,655,661 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 307,200 | n = int(input())
p = input().split()
p = [int(i) for i in p]
i = 1
a = []
f=0
temp=[p[0]]
temp_ptr=1
while(i<len(p)):
if(p[i]<=p[i-1]):
a.append(temp)
temp = []
temp.append(p[i])
else:
temp.append(p[i])
i+=1
if(temp):
a.append(temp)
# print(a)
i=1
... | Title: Remove Extra One
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a permutation *p* of length *n*. Remove one element from permutation to make the number of records the maximum possible.
We remind that in a sequence of numbers *a*1,<=*a*2,<=...,<=*a**k* the element *a*... | ```python
n = int(input())
p = input().split()
p = [int(i) for i in p]
i = 1
a = []
f=0
temp=[p[0]]
temp_ptr=1
while(i<len(p)):
if(p[i]<=p[i-1]):
a.append(temp)
temp = []
temp.append(p[i])
else:
temp.append(p[i])
i+=1
if(temp):
a.append(temp)
# print(a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,654,253,382 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 498 | 6,144,000 | def sieve():
global spf,adj,MAX
spf[1]=1
for i in range(MAX):
spf[i]=i
for i in range(2,MAX):
if i*i > MAX:
break
if spf[i]==i:
for j in range(i*i,MAX,i):
if spf[j]==j:
spf[j]=i
def distPrime(n):
... | Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
def sieve():
global spf,adj,MAX
spf[1]=1
for i in range(MAX):
spf[i]=i
for i in range(2,MAX):
if i*i > MAX:
break
if spf[i]==i:
for j in range(i*i,MAX,i):
if spf[j]==j:
spf[j]=i
def dist... | 3.864056 | MatrixStudio/Codeforces-Python-Submissions |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,680,617,287 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 8 | 61 | 1,331,200 | n = int(input())
b = 0
while n >= 100:
b += 1
n -= 100
while n >= 20:
b += 1
n -= 20
while n >= 10:
b += 1
n -= 10
while n >= 5:
b += 1
n -= 50
while n >= 1:
b += 1
n -= 1
print(b) | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
n = int(input())
b = 0
while n >= 100:
b += 1
n -= 100
while n >= 20:
b += 1
n -= 20
while n >= 10:
b += 1
n -= 10
while n >= 5:
b += 1
n -= 50
while n >= 1:
b += 1
n -= 1
print(b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,668,137,625 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 10 | 170 | 14,233,600 | global dp
def hj(k):
if dp[k]==0:
if k<a-1:
t=0
if liz[k] not in liz[k+1:]:
t=1
dp[k]= hj(k+1)+t
return dp[k]
else:
return 1
else:
return dp[k]
a,b=map(int,input().split())
dp=[0]*a
liz=list(map... | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
global dp
def hj(k):
if dp[k]==0:
if k<a-1:
t=0
if liz[k] not in liz[k+1:]:
t=1
dp[k]= hj(k+1)+t
return dp[k]
else:
return 1
else:
return dp[k]
a,b=map(int,input().split())
dp=[0]*a
li... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,691,255,273 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 154 | 2,867,200 | n=int(input())
a=map(int,input().split())
mi,ma=a[0],a[0]
ans=0
for x in a:
if x < mi:
ans+=1
mi=x
if x>ma:
ans+= 1
ma=x
print(ans) | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
n=int(input())
a=map(int,input().split())
mi,ma=a[0],a[0]
ans=0
for x in a:
if x < mi:
ans+=1
mi=x
if x>ma:
ans+= 1
ma=x
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resul... | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,694,641,969 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 | a = int(input())
b = int(input())
c = int(input())
result = (a*b*c, a+b*c, (a+b)*c, a+b+c, a*(b+c), a*b+c)
print(max(result)) | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of ... | ```python
a = int(input())
b = int(input())
c = int(input())
result = (a*b*c, a+b*c, (a+b)*c, a+b+c, a*(b+c), a*b+c)
print(max(result))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
859 | B | Lazy Security Guard | PROGRAMMING | 1,000 | [
"brute force",
"geometry",
"math"
] | null | null | Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is, your friend must walk the perimeter of a region whose area is exactly *N* blocks. Your friend is quite ... | Input will consist of a single integer *N* (1<=≤<=*N*<=≤<=106), the number of city blocks that must be enclosed by the route. | Print the minimum perimeter that can be achieved. | [
"4\n",
"11\n",
"22\n"
] | [
"8\n",
"14\n",
"20\n"
] | Here are some possible shapes for the examples:
<img class="tex-graphics" src="https://espresso.codeforces.com/e11bef2cf82b55dd583cfc97d12b5aee5e483a65.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 750 | [
{
"input": "4",
"output": "8"
},
{
"input": "11",
"output": "14"
},
{
"input": "22",
"output": "20"
},
{
"input": "3",
"output": "8"
},
{
"input": "1024",
"output": "128"
},
{
"input": "101",
"output": "42"
},
{
"input": "30",
"output":... | 1,559,037,441 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | n = int(input())
if n == 1:
print(4)
else:
i = 2
while i * i < n:
i += 1
if (i * i > n):
i -= 1
c = 4 * i
d = n - i * i
if (d > 0):
l = d // i
c += (l + 1) * 2
print(c) | Title: Lazy Security Guard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is... | ```python
n = int(input())
if n == 1:
print(4)
else:
i = 2
while i * i < n:
i += 1
if (i * i > n):
i -= 1
c = 4 * i
d = n - i * i
if (d > 0):
l = d // i
c += (l + 1) * 2
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,634,211,426 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 249 | 14,950,400 | n = int(input())
f = list(map(int,input().split()))
s = list(map(int,input().split()))
t = list(map(int,input().split()))
f.sort(); s.sort(); t.sort()
e1=-1; e2=-1
for i in range(len(s)):
if f[i]!=s[i]:
e1=f[i]
break
if e1==-1:
e1=f[-1]
for i in range(len(t)):
if t[i]!=s[i]:
... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
n = int(input())
f = list(map(int,input().split()))
s = list(map(int,input().split()))
t = list(map(int,input().split()))
f.sort(); s.sort(); t.sort()
e1=-1; e2=-1
for i in range(len(s)):
if f[i]!=s[i]:
e1=f[i]
break
if e1==-1:
e1=f[-1]
for i in range(len(t)):
if t[i]!... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,685,789,989 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | print(set("HQ9")&set(input())and"YES"or"NO") | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
print(set("HQ9")&set(input())and"YES"or"NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,683,836,124 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | def main():
bills = [1 , 5, 10, 20, 100]
n = int(input())
cnt = 0
for den in reversed(bills):
cnt += n // den
n %= den
if n == 0:
break
print(cnt)
if __name__ == "__main__":
main()
| Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
def main():
bills = [1 , 5, 10, 20, 100]
n = int(input())
cnt = 0
for den in reversed(bills):
cnt += n // den
n %= den
if n == 0:
break
print(cnt)
if __name__ == "__main__":
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
508 | A | Pasha and Pixels | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row with *m* pixels in each row. Initially, all the pixels are colored white. In one move, Pasha can choos... | The first line of the input contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=105) — the number of rows, the number of columns and the number of moves that Pasha is going to perform.
The next *k* lines contain Pasha's moves in the order he makes them. Each line contains two integers *i*... | If Pasha loses, print the number of the move when the 2<=×<=2 square consisting of black pixels is formed.
If Pasha doesn't lose, that is, no 2<=×<=2 square consisting of black pixels is formed during the given *k* moves, print 0. | [
"2 2 4\n1 1\n1 2\n2 1\n2 2\n",
"2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1\n",
"5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2\n"
] | [
"4\n",
"5\n",
"0\n"
] | none | 500 | [
{
"input": "2 2 4\n1 1\n1 2\n2 1\n2 2",
"output": "4"
},
{
"input": "2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1",
"output": "5"
},
{
"input": "5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2",
"output": "0"
},
{
"input": "3 3 11\n2 1\n3 1\n1 1\n1 3\n1 2\n2 3\n3 3\n3 2\n2 2\n1 3\n3 3",
... | 1,697,592,688 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 8,396,800 | x=[(-1,-1,0),(0,1,1),(-1,-1,0),(0,1,1)]
y=[(-1,0,-1),(-1,-1,0),(0,1,1),(1,0,1)]
step=[]
map_chess=[]
n,m,k=map(int,input().split())
c=0
for i in range(k):
step_x,step_y=map(int,input().split())
step.append((step_x,step_y))
for h in range(k):
if c!=0:
break
for n in range(4):
... | Title: Pasha and Pixels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row ... | ```python
x=[(-1,-1,0),(0,1,1),(-1,-1,0),(0,1,1)]
y=[(-1,0,-1),(-1,-1,0),(0,1,1),(1,0,1)]
step=[]
map_chess=[]
n,m,k=map(int,input().split())
c=0
for i in range(k):
step_x,step_y=map(int,input().split())
step.append((step_x,step_y))
for h in range(k):
if c!=0:
break
for n in range(4)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,634,030,476 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 77 | 21,299,200 | n,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=0
for i in a:
if i not in b:
if i>max(b):
c+=1
else:
if len(b)>1:
b.remove(max(b))
print(c) | Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=0
for i in a:
if i not in b:
if i>max(b):
c+=1
else:
if len(b)>1:
b.remove(max(b))
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
687 | A | NP-Hard Problem | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs"
] | null | null | Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of this graph, if for each edge *uv* there is at least one endpoint of it in this set, i.e. or (or bot... | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — the number of vertices and the number of edges in the prize graph, respectively.
Each of the next *m* lines contains a pair of integers *u**i* and *v**i* (1<=<=≤<=<=*u**i*,<=<=*v**i*<=<=≤<=<=*n*), denoting ... | If it's impossible to split the graph between Pari and Arya as they expect, print "-1" (without quotes).
If there are two disjoint sets of vertices, such that both sets are vertex cover, print their descriptions. Each description must contain two lines. The first line contains a single integer *k* denoting the number ... | [
"4 2\n1 2\n2 3\n",
"3 3\n1 2\n2 3\n1 3\n"
] | [
"1\n2 \n2\n1 3 \n",
"-1\n"
] | In the first sample, you can give the vertex number 2 to Arya and vertices numbered 1 and 3 to Pari and keep vertex number 4 for yourself (or give it someone, if you wish).
In the second sample, there is no way to satisfy both Pari and Arya. | 500 | [
{
"input": "4 2\n1 2\n2 3",
"output": "1\n2 \n2\n1 3 "
},
{
"input": "3 3\n1 2\n2 3\n1 3",
"output": "-1"
},
{
"input": "5 7\n3 2\n5 4\n3 4\n1 3\n1 5\n1 4\n2 5",
"output": "-1"
},
{
"input": "10 11\n4 10\n8 10\n2 3\n2 4\n7 1\n8 5\n2 8\n7 2\n1 2\n2 9\n6 8",
"output": "-1"
... | 1,646,122,111 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 2,000 | 19,660,800 | n,m=map(int,input().split())
g=[[] for i in range(n)]
for i in range(m):
u,v=map(int,input().split())
g[u-1].append(v-1)
g[v-1].append(u-1)
color=[-1 for i in range(n)]
q=[]
def part(g,color,q):
for i in range(n):
if color[i]==-1:
q.append([i,0])
color[i]=0
... | Title: NP-Hard Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of ... | ```python
n,m=map(int,input().split())
g=[[] for i in range(n)]
for i in range(m):
u,v=map(int,input().split())
g[u-1].append(v-1)
g[v-1].append(u-1)
color=[-1 for i in range(n)]
q=[]
def part(g,color,q):
for i in range(n):
if color[i]==-1:
q.append([i,0])
c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,697,034,128 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | stop_num=int(input())
people_num=0
list_people=[0]
for i in range(stop_num):
a,b=[int(x) for x in input().split()]
people_num+=b-a
list_people.append(people_num)
list_people.sort()
print(list_people[-1])
| Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
stop_num=int(input())
people_num=0
list_people=[0]
for i in range(stop_num):
a,b=[int(x) for x in input().split()]
people_num+=b-a
list_people.append(people_num)
list_people.sort()
print(list_people[-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
392 | A | Blocked Points | PROGRAMMING | 0 | [
"math"
] | null | null | Imagine you have an infinite 2D plane with Cartesian coordinate system. Some of the integral points are blocked, and others are not. Two integral points *A* and *B* on the plane are 4-connected if and only if:
- the Euclidean distance between *A* and *B* is one unit and neither *A* nor *B* is blocked; - or there is ... | The first line contains an integer *n* (0<=≤<=*n*<=≤<=4·107). | Print a single integer — the minimum number of points that should be blocked. | [
"1\n",
"2\n",
"3\n"
] | [
"4\n",
"8\n",
"16\n"
] | none | 500 | [
{
"input": "1",
"output": "4"
},
{
"input": "2",
"output": "8"
},
{
"input": "3",
"output": "16"
},
{
"input": "4",
"output": "20"
},
{
"input": "0",
"output": "1"
},
{
"input": "30426905",
"output": "172120564"
},
{
"input": "38450759",
... | 1,554,638,732 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 |
n = int(input())
print(pow(2,n+1)) | Title: Blocked Points
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine you have an infinite 2D plane with Cartesian coordinate system. Some of the integral points are blocked, and others are not. Two integral points *A* and *B* on the plane are 4-connected if and only if:
- the Eu... | ```python
n = int(input())
print(pow(2,n+1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercise... | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the mos... | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,620,885,562 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 154 | 6,963,200 | n = int(input())
data = list(map(int,input().split()))
chest = sum(data[i] for i in range(0,len(data),3))
biceps = sum(data[i] for i in range(1,len(data),3))
back = sum(data[i] for i in range(2,len(data),3))
if max(chest,biceps,back)==chest:
print("chest")
elif max(chest,biceps,back)==biceps:
print("bic... | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg ... | ```python
n = int(input())
data = list(map(int,input().split()))
chest = sum(data[i] for i in range(0,len(data),3))
biceps = sum(data[i] for i in range(1,len(data),3))
back = sum(data[i] for i in range(2,len(data),3))
if max(chest,biceps,back)==chest:
print("chest")
elif max(chest,biceps,back)==biceps:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
284 | A | Cows and Primitive Roots | PROGRAMMING | 1,400 | [
"implementation",
"math",
"number theory"
] | null | null | The cows have just learned what a primitive root is! Given a prime *p*, a primitive root is an integer *x* (1<=≤<=*x*<=<<=*p*) such that none of integers *x*<=-<=1,<=*x*2<=-<=1,<=...,<=*x**p*<=-<=2<=-<=1 are divisible by *p*, but *x**p*<=-<=1<=-<=1 is.
Unfortunately, computing primitive roots can be time consumin... | The input contains a single line containing an integer *p* (2<=≤<=*p*<=<<=2000). It is guaranteed that *p* is a prime. | Output on a single line the number of primitive roots . | [
"3\n",
"5\n"
] | [
"1\n",
"2\n"
] | The only primitive root <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/3722298ba062e95b18705d1253eb4e5d31e3b2d1.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2.
The primitive roots <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1d85c6a17ef1c42b53cf9... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "2"
},
{
"input": "7",
"output": "2"
},
{
"input": "11",
"output": "4"
},
{
"input": "17",
"output": "8"
},
{
"input": "19",
"output": "6"
},
{
"input": "1583",
"output": "672"
... | 1,652,409,087 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | def prime(x):
primes = [2]
for i in range(3, x):
for p in primes:
if i % p == 0: break
else:
primes.append(i)
return primes
print(len(prime(int(input())))) | Title: Cows and Primitive Roots
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The cows have just learned what a primitive root is! Given a prime *p*, a primitive root is an integer *x* (1<=≤<=*x*<=<<=*p*) such that none of integers *x*<=-<=1,<=*x*2<=-<=1,<=...,<=*x**p*<=-<=2<=-<=1 ar... | ```python
def prime(x):
primes = [2]
for i in range(3, x):
for p in primes:
if i % p == 0: break
else:
primes.append(i)
return primes
print(len(prime(int(input()))))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
703 | A | Mishka and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds *n* is defined.... | The first line of the input contains single integer *n* *n* (1<=≤<=*n*<=≤<=100) — the number of game rounds.
The next *n* lines contains rounds description. *i*-th of them contains pair of integers *m**i* and *c**i* (1<=≤<=*m**i*,<=<=*c**i*<=≤<=6) — values on dice upper face after Mishka's and Chris' throws in *i*-th ... | If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line. | [
"3\n3 5\n2 1\n4 2\n",
"2\n6 1\n1 6\n",
"3\n1 5\n3 3\n2 2\n"
] | [
"Mishka",
"Friendship is magic!^^",
"Chris"
] | In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there... | 500 | [
{
"input": "3\n3 5\n2 1\n4 2",
"output": "Mishka"
},
{
"input": "2\n6 1\n1 6",
"output": "Friendship is magic!^^"
},
{
"input": "3\n1 5\n3 3\n2 2",
"output": "Chris"
},
{
"input": "6\n4 1\n4 2\n5 3\n5 1\n5 3\n4 1",
"output": "Mishka"
},
{
"input": "8\n2 4\n1 4\n1 ... | 1,696,000,961 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | n = int(input())
mishkacounter=0
chriscounter=0
while n > 0:
dicerolls = [int(x) for x in input().split()]
if dicerolls[0] > dicerolls[-1]:
mishkacounter +=1
elif dicerolls[-1] > dicerolls[0]:
chriscounter +=1
n-=1
if mishkacounter > chriscounter:
print("Mishka")
elif chr... | Title: Mishka and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they st... | ```python
n = int(input())
mishkacounter=0
chriscounter=0
while n > 0:
dicerolls = [int(x) for x in input().split()]
if dicerolls[0] > dicerolls[-1]:
mishkacounter +=1
elif dicerolls[-1] > dicerolls[0]:
chriscounter +=1
n-=1
if mishkacounter > chriscounter:
print("Mishka")... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin b... | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,591,373,695 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import math
l=list(map(int, input().split()))
r=l[0]
x=l[1]
y=l[2]
a=l[3]
b=l[4]
dist=math.sqrt((x-a)**2+(y-b)**2)
if dist==0:
return 0
return (dist//(2*r))+1
| Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can ... | ```python
import math
l=list(map(int, input().split()))
r=l[0]
x=l[1]
y=l[2]
a=l[3]
b=l[4]
dist=math.sqrt((x-a)**2+(y-b)**2)
if dist==0:
return 0
return (dist//(2*r))+1
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
762 | B | USB vs. PS/2 | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings",
"two pointers"
] | null | null | Due to the increase in the number of students of Berland State University it was decided to equip a new computer room. You were given the task of buying mouses, and you have to spend as little as possible. After all, the country is in crisis!
The computers bought for the room were different. Some of them had only USB ... | The first line contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=105) — the number of computers that only have USB ports, the number of computers, that only have PS/2 ports, and the number of computers, that have both options, respectively.
The next line contains one integer *m* (0<=≤<=*m*<=≤<=3·105... | Output two integers separated by space — the number of equipped computers and the total cost of the mouses you will buy. | [
"2 1 1\n4\n5 USB\n6 PS/2\n3 PS/2\n7 PS/2\n"
] | [
"3 14\n"
] | In the first example you can buy the first three mouses. This way you will equip one of the computers that has only a USB port with a USB mouse, and the two PS/2 mouses you will plug into the computer with PS/2 port and the computer with both ports. | 0 | [
{
"input": "2 1 1\n4\n5 USB\n6 PS/2\n3 PS/2\n7 PS/2",
"output": "3 14"
},
{
"input": "1 4 4\n12\n36949214 USB\n683538043 USB\n595594834 PS/2\n24951774 PS/2\n131512123 USB\n327575645 USB\n30947411 USB\n916758386 PS/2\n474310330 USB\n350512489 USB\n281054887 USB\n875326145 USB",
"output": "8 23453... | 1,688,973,036 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 48 | 1,684 | 16,486,400 | a,b,c=map(int,input().split())
m=int(input())
usb=[]
ps=[]
for i in range(m):
s,x=input().split()
if x=='USB':
usb.append(int(s))
else:
ps.append(int(s))
usb.sort()
ps.sort()
cnt=0
fg=0
if a>=len(usb):
cnt+=sum(usb)
fg+=len(usb)
usb=[]
else:
cnt+=sum(usb[:a... | Title: USB vs. PS/2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Due to the increase in the number of students of Berland State University it was decided to equip a new computer room. You were given the task of buying mouses, and you have to spend as little as possible. After all, the c... | ```python
a,b,c=map(int,input().split())
m=int(input())
usb=[]
ps=[]
for i in range(m):
s,x=input().split()
if x=='USB':
usb.append(int(s))
else:
ps.append(int(s))
usb.sort()
ps.sort()
cnt=0
fg=0
if a>=len(usb):
cnt+=sum(usb)
fg+=len(usb)
usb=[]
else:
cnt+=... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
858 | B | Which floor? | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | In a building where Polycarp lives there are equal number of flats on each floor. Unfortunately, Polycarp don't remember how many flats are on each floor, but he remembers that the flats are numbered from 1 from lower to upper floors. That is, the first several flats are on the first floor, the next several flats are o... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100, 0<=≤<=*m*<=≤<=100), where *n* is the number of the flat you need to restore floor for, and *m* is the number of flats in Polycarp's memory.
*m* lines follow, describing the Polycarp's memory: each of these lines contains a pair of integers *k**i*,<=*... | Print the number of the floor in which the *n*-th flat is located, if it is possible to determine it in a unique way. Print -1 if it is not possible to uniquely restore this floor. | [
"10 3\n6 2\n2 1\n7 3\n",
"8 4\n3 1\n6 2\n5 2\n2 1\n"
] | [
"4\n",
"-1\n"
] | In the first example the 6-th flat is on the 2-nd floor, while the 7-th flat is on the 3-rd, so, the 6-th flat is the last on its floor and there are 3 flats on each floor. Thus, the 10-th flat is on the 4-th floor.
In the second example there can be 3 or 4 flats on each floor, so we can't restore the floor for the 8-... | 750 | [
{
"input": "10 3\n6 2\n2 1\n7 3",
"output": "4"
},
{
"input": "8 4\n3 1\n6 2\n5 2\n2 1",
"output": "-1"
},
{
"input": "8 3\n7 2\n6 2\n1 1",
"output": "2"
},
{
"input": "4 2\n8 3\n3 1",
"output": "2"
},
{
"input": "11 4\n16 4\n11 3\n10 3\n15 4",
"output": "3"
... | 1,505,914,479 | 2,147,483,647 | Python 3 | OK | TESTS | 101 | 62 | 0 | n, m = map(int, input().split())
a = [0] * m
for i in range(m):
a[i] = list(map(int, input().split()))
a[i][0] -= 1
a[i][1] -= 1
n -= 1
canbe = set()
last = 0
for i in range(1, 200):
good = 1
for j in range(m):
k = a[j][0]
f = a[j][1]
if not (i * f <= k <=... | Title: Which floor?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a building where Polycarp lives there are equal number of flats on each floor. Unfortunately, Polycarp don't remember how many flats are on each floor, but he remembers that the flats are numbered from 1 from lower to u... | ```python
n, m = map(int, input().split())
a = [0] * m
for i in range(m):
a[i] = list(map(int, input().split()))
a[i][0] -= 1
a[i][1] -= 1
n -= 1
canbe = set()
last = 0
for i in range(1, 200):
good = 1
for j in range(m):
k = a[j][0]
f = a[j][1]
if not (i *... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,587,819,974 | 2,147,483,647 | Python 3 | OK | TESTS | 8 | 108 | 0 | n = int(input())
for _ in range(n):
pieces=int(input())
ans="NO"
for i in range (0, pieces // 7+1):
if (pieces - i*7)%3==0:
ans="YES"
break
print(ans)
| Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chun... | ```python
n = int(input())
for _ in range(n):
pieces=int(input())
ans="NO"
for i in range (0, pieces // 7+1):
if (pieces - i*7)%3==0:
ans="YES"
break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
960 | A | Check the string | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gi... | The first and only line consists of a string $S$ ($ 1 \le |S| \le 5\,000 $). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'. | Print "YES" or "NO", according to the condition. | [
"aaabccc\n",
"bbacc\n",
"aabc\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'. | 500 | [
{
"input": "aaabccc",
"output": "YES"
},
{
"input": "bbacc",
"output": "NO"
},
{
"input": "aabc",
"output": "YES"
},
{
"input": "aabbcc",
"output": "YES"
},
{
"input": "aaacccbb",
"output": "NO"
},
{
"input": "abc",
"output": "YES"
},
{
"in... | 1,535,362,043 | 1,043 | Python 3 | WRONG_ANSWER | TESTS | 17 | 124 | 0 | a=input()
s=[0]*3
c=1
af=-1
bf=-1
cf=-1
for i in range(len(a)):
if a[i]=='a' and s[0]==0:
af=i
elif a[i]=='b' and s[1]==0:
bf=i
elif s[2]==0:
cf=i
if a[i]=='a':
s[0]+=1
elif a[i]=='b':
s[1]+=1
else:
s[2]+=1
if af<bf and af<cf and... | Title: Check the string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b... | ```python
a=input()
s=[0]*3
c=1
af=-1
bf=-1
cf=-1
for i in range(len(a)):
if a[i]=='a' and s[0]==0:
af=i
elif a[i]=='b' and s[1]==0:
bf=i
elif s[2]==0:
cf=i
if a[i]=='a':
s[0]+=1
elif a[i]=='b':
s[1]+=1
else:
s[2]+=1
if af<bf and... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
84 | A | Toy Army | PROGRAMMING | 900 | [
"math",
"number theory"
] | A. Toy Army | 2 | 256 | The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on the playing field each of which consists of *n* men (*n* is always even). The current playe... | The input data consist of a single integer *n* (2<=≤<=*n*<=≤<=108, *n* is even). Please note that before the game starts there are 2*n* soldiers on the fields. | Print a single number — a maximum total number of soldiers that could be killed in the course of the game in three turns. | [
"2\n",
"4\n"
] | [
"3\n",
"6\n"
] | The first sample test:
1) Valera's soldiers 1 and 2 shoot at Arcady's soldier 1.
2) Arcady's soldier 2 shoots at Valera's soldier 1.
3) Valera's soldier 1 shoots at Arcady's soldier 2.
There are 3 soldiers killed in total: Valera's soldier 1 and Arcady's soldiers 1 and 2. | 500 | [
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "6"
},
{
"input": "6",
"output": "9"
},
{
"input": "8",
"output": "12"
},
{
"input": "10",
"output": "15"
},
{
"input": "140",
"output": "210"
},
{
"input": "500",
"output": "75... | 1,657,623,818 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 92 | 0 | X = int(input())
print(3*X //2)
| Title: Toy Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The hero of our story, Valera, and his best friend Arcady are still in school, and therefore they spend all the free time playing turn-based strategy "GAGA: Go And Go Again". The gameplay is as follows.
There are two armies on t... | ```python
X = int(input())
print(3*X //2)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,621,513,188 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 3,788,800 |
y, k, n = list(map(int, input().split()))
x = n - y
if x < 1:
print(-1)
else:
counter = 0
for i in range(1, n+1):
if i%k ==0:
counter += 1
m = k*counter
if m - y > 0:
print(m - y, end=" ")
if counter == 0:
print(-... | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
y, k, n = list(map(int, input().split()))
x = n - y
if x < 1:
print(-1)
else:
counter = 0
for i in range(1, n+1):
if i%k ==0:
counter += 1
m = k*counter
if m - y > 0:
print(m - y, end=" ")
if counter == 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
476 | A | Dreamoon and Stairs | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition? | The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10). | Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead. | [
"10 2\n",
"3 5\n"
] | [
"6\n",
"-1\n"
] | For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | 500 | [
{
"input": "10 2",
"output": "6"
},
{
"input": "3 5",
"output": "-1"
},
{
"input": "29 7",
"output": "21"
},
{
"input": "2 2",
"output": "2"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "10000 2",
"output": "5000"
},
{
"input": "10000 ... | 1,653,833,630 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 31 | 0 | n,m=map(int,input().split())
if n<m:
print(-1)
elif n==m:
print(n)
elif (n//m)%m==0:
print(n//m)
else:
while n%2==0:
n=n-1
print(((n//m)-1)*m) | Title: Dreamoon and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb ... | ```python
n,m=map(int,input().split())
if n<m:
print(-1)
elif n==m:
print(n)
elif (n//m)%m==0:
print(n//m)
else:
while n%2==0:
n=n-1
print(((n//m)-1)*m)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
331 | C1 | The Great Julya Calendar | PROGRAMMING | 1,100 | [
"dp"
] | null | null | Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on it. The translation from Old Beaverish is as follows:
"May the Great Beaver bless you! May your chacres open ... | The single line contains the magic integer *n*, 0<=≤<=*n*.
- to get 20 points, you need to solve the problem with constraints: *n*<=≤<=106 (subproblem C1); - to get 40 points, you need to solve the problem with constraints: *n*<=≤<=1012 (subproblems C1+C2); - to get 100 points, you need to solve the problem with co... | Print a single integer — the minimum number of subtractions that turns the magic number to a zero. | [
"24\n"
] | [
"5"
] | In the first test sample the minimum number of operations can be reached by the following sequence of subtractions: | 20 | [
{
"input": "24",
"output": "5"
},
{
"input": "0",
"output": "0"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "1"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "31",
"output": "6"
},
... | 1,623,730,486 | 2,147,483,647 | Python 3 | OK | TESTS1 | 24 | 684 | 0 | n = int(input())
ans = 0
while n!= 0:
m = max([int(i) for i in str(n)])
n = n-m
ans+=1
print(ans) | Title: The Great Julya Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on i... | ```python
n = int(input())
ans = 0
while n!= 0:
m = max([int(i) for i in str(n)])
n = n-m
ans+=1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
962 | B | Students in Railway Carriage | PROGRAMMING | 1,300 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | There are $n$ consecutive seat places in a railway carriage. Each place is either empty or occupied by a passenger.
The university team for the Olympiad consists of $a$ student-programmers and $b$ student-athletes. Determine the largest number of students from all $a+b$ students, which you can put in the railway carri... | The first line contain three integers $n$, $a$ and $b$ ($1 \le n \le 2\cdot10^{5}$, $0 \le a, b \le 2\cdot10^{5}$, $a + b > 0$) — total number of seat places in the railway carriage, the number of student-programmers and the number of student-athletes.
The second line contains a string with length $n$, consisting o... | Print the largest number of students, which you can put in the railway carriage so that no student-programmer is sitting next to a student-programmer and no student-athlete is sitting next to a student-athlete. | [
"5 1 1\n*...*\n",
"6 2 3\n*...*.\n",
"11 3 10\n.*....**.*.\n",
"3 2 3\n***\n"
] | [
"2\n",
"4\n",
"7\n",
"0\n"
] | In the first example you can put all student, for example, in the following way: *.AB*
In the second example you can put four students, for example, in the following way: *BAB*B
In the third example you can put seven students, for example, in the following way: B*ABAB**A*B
The letter A means a student-programmer, an... | 0 | [
{
"input": "5 1 1\n*...*",
"output": "2"
},
{
"input": "6 2 3\n*...*.",
"output": "4"
},
{
"input": "11 3 10\n.*....**.*.",
"output": "7"
},
{
"input": "3 2 3\n***",
"output": "0"
},
{
"input": "9 5 3\n*...*...*",
"output": "6"
},
{
"input": "9 2 4\n*.... | 1,554,089,940 | 2,147,483,647 | Python 3 | OK | TESTS | 93 | 186 | 3,481,600 | n, a, b = map(int, input().split())
s = input()
ans = 0
prog = a
ath = b
o = list(map(len, s.split('*')))
for i in o:
if i % 2 == 0:
prog -= i // 2
ath -= i // 2
else:
if prog > ath:
prog -= i // 2 + 1
ath -= i // 2
else:
pro... | Title: Students in Railway Carriage
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are $n$ consecutive seat places in a railway carriage. Each place is either empty or occupied by a passenger.
The university team for the Olympiad consists of $a$ student-programmers and $b$ student-... | ```python
n, a, b = map(int, input().split())
s = input()
ans = 0
prog = a
ath = b
o = list(map(len, s.split('*')))
for i in o:
if i % 2 == 0:
prog -= i // 2
ath -= i // 2
else:
if prog > ath:
prog -= i // 2 + 1
ath -= i // 2
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,572,550,988 | 2,147,483,647 | PyPy 3 | OK | TESTS | 63 | 124 | 0 | #def split(word):
# return [char for char in word]
n, d = map(int,input().split())
word = str(input())
poss = 0
cont = 0
xx = list([int(d) for d in str(word)])
for j in range(d):
xx.append(0)
if d > n:
print(1)
else:
while poss <= n-1:
if poss >= n-1 or cont == -1:
break
... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
#def split(word):
# return [char for char in word]
n, d = map(int,input().split())
word = str(input())
poss = 0
cont = 0
xx = list([int(d) for d in str(word)])
for j in range(d):
xx.append(0)
if d > n:
print(1)
else:
while poss <= n-1:
if poss >= n-1 or cont == -1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
817 | B | Makes And The Product | PROGRAMMING | 1,500 | [
"combinatorics",
"implementation",
"math",
"sortings"
] | null | null | After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular question: how many triples of indices (*i*,<= *j*,<= *k*) (*i*<=<<=*j*<=<<=*k*), such that *a**i*·*a**j*·*a... | The first line of input contains a positive integer number *n* (3<=≤<=*n*<=≤<=105) — the number of elements in array *a*. The second line contains *n* positive integer numbers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of a given array. | Print one number — the quantity of triples (*i*,<= *j*,<= *k*) such that *i*,<= *j* and *k* are pairwise distinct and *a**i*·*a**j*·*a**k* is minimum possible. | [
"4\n1 1 1 1\n",
"5\n1 3 2 3 4\n",
"6\n1 3 3 1 3 2\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first example Makes always chooses three ones out of four, and the number of ways to choose them is 4.
In the second example a triple of numbers (1, 2, 3) is chosen (numbers, not indices). Since there are two ways to choose an element 3, then the answer is 2.
In the third example a triple of numbers (1, 1, 2) ... | 0 | [
{
"input": "4\n1 1 1 1",
"output": "4"
},
{
"input": "5\n1 3 2 3 4",
"output": "2"
},
{
"input": "6\n1 3 3 1 3 2",
"output": "1"
},
{
"input": "3\n1000000000 1000000000 1000000000",
"output": "1"
},
{
"input": "4\n1 1 2 2",
"output": "2"
},
{
"input": ... | 1,497,989,633 | 2,147,483,647 | PyPy 3 | OK | TESTS | 80 | 1,606 | 34,816,000 | from math import factorial
input()
a = sorted(map(int, input().split()))
d = {}
for i in a:
if i in d:
d[i] += 1
else:
d[i] = 1
numbers = set(a[:3])
lN = len(numbers)
def nCr(n,r):
return factorial(n)//(factorial(n - r)*factorial(r))
if lN == 1:
print(nCr(d[a[0]], 3))
elif lN == 2:
... | Title: Makes And The Product
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular questi... | ```python
from math import factorial
input()
a = sorted(map(int, input().split()))
d = {}
for i in a:
if i in d:
d[i] += 1
else:
d[i] = 1
numbers = set(a[:3])
lN = len(numbers)
def nCr(n,r):
return factorial(n)//(factorial(n - r)*factorial(r))
if lN == 1:
print(nCr(d[a[0]], 3))
elif ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,658,595,622 | 2,147,483,647 | PyPy 3 | OK | TESTS | 58 | 93 | 0 | import math
t = input()
ans = ["h", "e", "i", "d", "i"]
for i in t:
if len(ans) == 0:
break
elif ans[0] == i:
ans = ans[1:]
if len(ans):
print("NO")
else:
print("YES") | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
import math
t = input()
ans = ["h", "e", "i", "d", "i"]
for i in t:
if len(ans) == 0:
break
elif ans[0] == i:
ans = ans[1:]
if len(ans):
print("NO")
else:
print("YES")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
922 | C | Cave Painting | PROGRAMMING | 1,600 | [
"brute force",
"number theory"
] | null | null | Imp is watching a documentary about cave painting.
Some numbers, carved in chaotic order, immediately attracted his attention. Imp rapidly proposed a guess that they are the remainders of division of a number *n* by all integers *i* from 1 to *k*. Unfortunately, there are too many integers to analyze for Imp.
Imp wan... | The only line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=1018). | Print "Yes", if all the remainders are distinct, and "No" otherwise.
You can print each letter in arbitrary case (lower or upper). | [
"4 4\n",
"5 3\n"
] | [
"No\n",
"Yes\n"
] | In the first sample remainders modulo 1 and 4 coincide. | 1,250 | [
{
"input": "4 4",
"output": "No"
},
{
"input": "5 3",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "744 18",
"output": "No"
},
{
"input": "47879 10",
"output": "Yes"
},
{
"input": "1000000000000000000 1000000000000000000",
"ou... | 1,647,958,023 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | nk = [int(x) for x in input().split()]
n = nk[0]
k = nk[1]
if n > k or (n == 1 and k == 1):
print('Yes')
else:
print('No')
| Title: Cave Painting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imp is watching a documentary about cave painting.
Some numbers, carved in chaotic order, immediately attracted his attention. Imp rapidly proposed a guess that they are the remainders of division of a number *n* by all ... | ```python
nk = [int(x) for x in input().split()]
n = nk[0]
k = nk[1]
if n > k or (n == 1 and k == 1):
print('Yes')
else:
print('No')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
897 | A | Scarborough Fair | PROGRAMMING | 800 | [
"implementation"
] | null | null | Parsley, sage, rosemary and thyme.
Remember me to one who lives there.
He once was the true love of mine.
Willem is taking the girl to the highest building in island No.28, however, neither of them knows how to get there.
Willem asks his friend, Grick for directions, Grick helped them, and gave them a task.
Althou... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
The second line contains a string *s* of length *n*, consisting of lowercase English letters.
Each of the next *m* lines contains four parameters *l*,<=*r*,<=*c*1,<=*c*2 (1<=≤<=*l*<=≤<=*r*<=≤<=*n*, *c*1,<=*c*2 are lowercase English letters), ... | Output string *s* after performing *m* operations described above. | [
"3 1\nioi\n1 1 i n\n",
"5 3\nwxhak\n3 3 h x\n1 5 x a\n1 3 w g\n"
] | [
"noi",
"gaaak"
] | For the second example:
After the first operation, the string is wxxak.
After the second operation, the string is waaak.
After the third operation, the string is gaaak. | 500 | [
{
"input": "3 1\nioi\n1 1 i n",
"output": "noi"
},
{
"input": "5 3\nwxhak\n3 3 h x\n1 5 x a\n1 3 w g",
"output": "gaaak"
},
{
"input": "9 51\nbhfbdcgff\n2 3 b b\n2 8 e f\n3 8 g f\n5 7 d a\n1 5 e b\n3 4 g b\n6 7 c d\n3 6 e g\n3 6 e h\n5 6 a e\n7 9 a c\n4 9 a h\n3 7 c b\n6 9 b g\n1 7 h b\n... | 1,592,236,154 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 202 | 2,662,400 | n, m = map(int, input().split())
s = list(input())
q = ''
for i in range(m):
l, r, c1, c2 = input().split()
l, r = int(l), int(r)
for j in range(l-1, r):
if s[j] == c1:
s[j] = c2
for k in s:
q += k
print(q) | Title: Scarborough Fair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Parsley, sage, rosemary and thyme.
Remember me to one who lives there.
He once was the true love of mine.
Willem is taking the girl to the highest building in island No.28, however, neither of them knows how to get ... | ```python
n, m = map(int, input().split())
s = list(input())
q = ''
for i in range(m):
l, r, c1, c2 = input().split()
l, r = int(l), int(r)
for j in range(l-1, r):
if s[j] == c1:
s[j] = c2
for k in s:
q += k
print(q)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,511,942,785 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 62 | 5,632,000 | n1 = str(input())
n2 = str(input())
ans = str()
i = 0
for i in range(len(n1)):
if n1[i] == n2[i]:
ans += '0'
else:
ans += '1'
i+=1
print(ans)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
n1 = str(input())
n2 = str(input())
ans = str()
i = 0
for i in range(len(n1)):
if n1[i] == n2[i]:
ans += '0'
else:
ans += '1'
i+=1
print(ans)
``` | 3.97401 | MatrixStudio/Codeforces-Python-Submissions |
814 | B | An express train to reveries | PROGRAMMING | 1,300 | [
"constructive algorithms"
] | null | null | Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her fancies would be realized.
On that night, Sengoku constructed a permutation *p*1,<=*p*2,<=...,<=*p**n* of intege... | The first line of input contains a positive integer *n* (2<=≤<=*n*<=≤<=1<=000) — the length of Sengoku's permutation, being the length of both meteor outbursts at the same time.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the sequence of colours in the firs... | Output *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n*, denoting a possible permutation Sengoku could have had. If there are more than one possible answer, output any one of them.
Input guarantees that such permutation exists. | [
"5\n1 2 3 4 3\n1 2 5 4 5\n",
"5\n4 4 2 3 1\n5 4 5 3 1\n",
"4\n1 1 3 4\n1 4 3 4\n"
] | [
"1 2 5 4 3\n",
"5 4 2 3 1\n",
"1 2 3 4\n"
] | In the first sample, both 1, 2, 5, 4, 3 and 1, 2, 3, 4, 5 are acceptable outputs.
In the second sample, 5, 4, 2, 3, 1 is the only permutation to satisfy the constraints. | 1,000 | [
{
"input": "5\n1 2 3 4 3\n1 2 5 4 5",
"output": "1 2 5 4 3"
},
{
"input": "5\n4 4 2 3 1\n5 4 5 3 1",
"output": "5 4 2 3 1"
},
{
"input": "4\n1 1 3 4\n1 4 3 4",
"output": "1 2 3 4"
},
{
"input": "10\n1 2 3 4 7 6 7 8 9 10\n1 2 3 4 5 6 5 8 9 10",
"output": "1 2 3 4 5 6 7 8 9... | 1,497,008,293 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=[]
for i in range(n):
if(a[i] != b[i]):
c.append(i)
if len(c) == 2:
a[c[0]] = b[c[0]]
else:
s1=set(a)
s2=set(range(1,n+1))
t=s2-s1
a[c[0]] = int(t.pop())
print(a)
| Title: An express train to reveries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her... | ```python
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=[]
for i in range(n):
if(a[i] != b[i]):
c.append(i)
if len(c) == 2:
a[c[0]] = b[c[0]]
else:
s1=set(a)
s2=set(range(1,n+1))
t=s2-s1
a[c[0]] = int(t.pop())
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
929 | A | Прокат велосипедов | PROGRAMMING | 1,400 | [
"*special",
"greedy",
"implementation"
] | null | null | Как известно, в теплую погоду многие жители крупных городов пользуются сервисами городского велопроката. Вот и Аркадий сегодня будет добираться от школы до дома, используя городские велосипеды.
Школа и дом находятся на одной прямой улице, кроме того, на той же улице есть *n* точек, где можно взять велосипед в прокат и... | В первой строке следуют два целых числа *n* и *k* (2<=≤<=*n*<=≤<=1<=000, 1<=≤<=*k*<=≤<=100<=000) — количество велопрокатов и максимальное расстояние, которое Аркадий может проехать на одном велосипеде.
В следующей строке следует последовательность целых чисел *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x*1<=<<=*x*2<=<<=.... | Если Аркадий не сможет добраться от школы до дома только на велосипедах, выведите -1. В противном случае, выведите минимальное количество велосипедов, которые Аркадию нужно взять в точках проката. | [
"4 4\n3 6 8 10\n",
"2 9\n10 20\n",
"12 3\n4 6 7 9 10 11 13 15 17 18 20 21\n"
] | [
"2\n",
"-1\n",
"6\n"
] | В первом примере Аркадий должен взять первый велосипед в первом велопрокате и доехать на нём до второго велопроката. Во втором велопрокате он должен взять новый велосипед, на котором он сможет добраться до четвертого велопроката, рядом с которым и находится его дом. Поэтому Аркадию нужно всего два велосипеда, чтобы доб... | 500 | [
{
"input": "4 4\n3 6 8 10",
"output": "2"
},
{
"input": "2 9\n10 20",
"output": "-1"
},
{
"input": "12 3\n4 6 7 9 10 11 13 15 17 18 20 21",
"output": "6"
},
{
"input": "2 1\n11164 11165",
"output": "1"
},
{
"input": "3 7\n45823 45825 45829",
"output": "1"
},... | 1,677,998,362 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 52 | 46 | 0 | n,k = map(int, input().split())
a = list(map(int, input().split()))
cur_k = k
ans = 0
flg = True
if len(a) == 2:
if a[-1] - a[0] > k:
flg = False
else:
for i in range(1,n-1):
if a[i] - a[i-1] > k:
flg = False
break
if a[i+1] - a[i-1] <= cur_k:
... | Title: Прокат велосипедов
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Как известно, в теплую погоду многие жители крупных городов пользуются сервисами городского велопроката. Вот и Аркадий сегодня будет добираться от школы до дома, используя городские велосипеды.
Школа и дом находятся... | ```python
n,k = map(int, input().split())
a = list(map(int, input().split()))
cur_k = k
ans = 0
flg = True
if len(a) == 2:
if a[-1] - a[0] > k:
flg = False
else:
for i in range(1,n-1):
if a[i] - a[i-1] > k:
flg = False
break
if a[i+1] - a[i-1] <= cur_... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,571,838,491 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 216 | 0 | a,b,n=[int(x) for x in input().split()]
move=0
while n!=0:
if n%a==0:
n-=n/a
move+=1
else:
n-=1
move+=1
if move%2==0:
print(0)
else:
print(1) | Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
a,b,n=[int(x) for x in input().split()]
move=0
while n!=0:
if n%a==0:
n-=n/a
move+=1
else:
n-=1
move+=1
if move%2==0:
print(0)
else:
print(1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
350 | A | TL | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Valera has also wrote *m* wrong solutions and for each wrong solution he knows its running ... | The first line contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100). The second line contains *n* space-separated positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) — the running time of each of the *n* correct solutions in seconds. The third line contains *m* space-separated positive integers *b*1... | If there is a valid TL value, print it. Otherwise, print -1. | [
"3 6\n4 5 2\n8 9 6 10 7 11\n",
"3 1\n3 4 5\n6\n"
] | [
"5",
"-1\n"
] | none | 500 | [
{
"input": "3 6\n4 5 2\n8 9 6 10 7 11",
"output": "5"
},
{
"input": "3 1\n3 4 5\n6",
"output": "-1"
},
{
"input": "2 5\n45 99\n49 41 77 83 45",
"output": "-1"
},
{
"input": "50 50\n18 13 5 34 10 36 36 12 15 11 16 17 14 36 23 45 32 24 31 18 24 32 7 1 31 3 49 8 16 23 3 39 47 43... | 1,381,461,630 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 124 | 0 | n,m = map (int, input().split())
xs = list (map (int, input().split()))
ys = list (map (int, input().split()))
ac = max (2*min(xs), max(xs))
wa = min (ys)
if (ac < wa):
print (ac)
else:
print (-1)
| Title: TL
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Val... | ```python
n,m = map (int, input().split())
xs = list (map (int, input().split()))
ys = list (map (int, input().split()))
ac = max (2*min(xs), max(xs))
wa = min (ys)
if (ac < wa):
print (ac)
else:
print (-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,652,340,094 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 59 | 62 | 0 | from math import factorial
a,b = map(int,input().split())
c = min(a,b)
d = factorial(c)
print(d)
| Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
from math import factorial
a,b = map(int,input().split())
c = min(a,b)
d = factorial(c)
print(d)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,592,337,121 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 155 | 0 | import math
def main():
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
r = []
for i in range(len(arr) - 2):
for j in range(i + 1, len(arr) - 1):
for k in range(j + 1, len(arr)):
if arr[j] % arr[i] == 0 and (arr[k] % arr[j] == 0) and (... | Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
import math
def main():
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
r = []
for i in range(len(arr) - 2):
for j in range(i + 1, len(arr) - 1):
for k in range(j + 1, len(arr)):
if arr[j] % arr[i] == 0 and (arr[k] % arr[j] =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
989 | B | A Tide of Riverscape | PROGRAMMING | 1,200 | [
"constructive algorithms",
"strings"
] | null | null | "Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.
Doubtfully, Kanno peeks a... | The first line contains two space-separated integers $n$ and $p$ ($1 \leq p \leq n \leq 2000$) — the length of the given string and the supposed period, respectively.
The second line contains a string $s$ of $n$ characters — Mino's records. $s$ only contains characters '0', '1' and '.', and contains at least one '.' c... | Output one line — if it's possible that $p$ is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)). | [
"10 7\n1.0.1.0.1.\n",
"10 6\n1.0.1.1000\n",
"10 9\n1........1\n"
] | [
"1000100010\n",
"1001101000\n",
"No\n"
] | In the first example, $7$ is not a period of the resulting string because the $1$-st and $8$-th characters of it are different.
In the second example, $6$ is not a period of the resulting string because the $4$-th and $10$-th characters of it are different.
In the third example, $9$ is always a period because the onl... | 1,000 | [
{
"input": "10 7\n1.0.1.0.1.",
"output": "1000100010"
},
{
"input": "10 6\n1.0.1.1000",
"output": "1001101000"
},
{
"input": "10 9\n1........1",
"output": "No"
},
{
"input": "1 1\n.",
"output": "No"
},
{
"input": "5 1\n0...1",
"output": "00001"
},
{
"i... | 1,617,709,910 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 18 | 77 | 409,600 | import sys
import math
from collections import OrderedDict
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def minput(): return map(int, input().split())
def listinput(): return list(map(int, input().split()))
n,p=minput()
s=input()
s1=s[:(n-p)]
s2=s[p:]
if (s1==s2 ... | Title: A Tide of Riverscape
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its... | ```python
import sys
import math
from collections import OrderedDict
def input(): return sys.stdin.readline().strip()
def iinput(): return int(input())
def minput(): return map(int, input().split())
def listinput(): return list(map(int, input().split()))
n,p=minput()
s=input()
s1=s[:(n-p)]
s2=s[p:]
i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,697,372,622 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 21 | 92 | 12,288,000 | n,k=map(int,input().split())
a=[int(x) for x in input().split()]
ans=True
for i in range(k-1,n-1):
if(a[i]!=a[i+1]):
ans=False
break
if(ans):print(a.index(a[-1]))
else:print(-1) | Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
n,k=map(int,input().split())
a=[int(x) for x in input().split()]
ans=True
for i in range(k-1,n-1):
if(a[i]!=a[i+1]):
ans=False
break
if(ans):print(a.index(a[-1]))
else:print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,548,313,332 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 |
n,m = map(int,input().split())
l1 = list(map(int,input().split()))
l2 = list(map(int,input().split()))
hash = set()
count = 0
for i in range(n):
for j in range(m):
if l2[j]>=l1[i] and j not in set:
hash.add(j)
break
print(n-count)
| Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
n,m = map(int,input().split())
l1 = list(map(int,input().split()))
l2 = list(map(int,input().split()))
hash = set()
count = 0
for i in range(n):
for j in range(m):
if l2[j]>=l1[i] and j not in set:
hash.add(j)
break
print(n-count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
606 | A | Magic Spheres | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible,... | The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal.
The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number o... | If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No". | [
"4 4 0\n2 1 2\n",
"5 6 1\n2 7 2\n",
"3 3 3\n2 2 2\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what... | 500 | [
{
"input": "4 4 0\n2 1 2",
"output": "Yes"
},
{
"input": "5 6 1\n2 7 2",
"output": "No"
},
{
"input": "3 3 3\n2 2 2",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 0",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 1",
"output": "No"
},
{
"input": "0 1 0\n0 0 0... | 1,689,821,377 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | # LUOGU_RID: 116533488
#include<iostream>
using namespace std;
int a,b,c,x,y,z;
int d,g;
int main(){
cin>>a>>b>>c>>x>>y>>z;
if(a>=x) g+=(a-x)/2;
else d+=x-a;
if(b>=y) g+=(b-y)/2;
else d+=y-b;
if(c>=z) g+=(c-z)/2;
else d+=z-c;
if(g>=d) cout<<"Yes";
else cout<<"No";
} | Title: Magic Spheres
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been see... | ```python
# LUOGU_RID: 116533488
#include<iostream>
using namespace std;
int a,b,c,x,y,z;
int d,g;
int main(){
cin>>a>>b>>c>>x>>y>>z;
if(a>=x) g+=(a-x)/2;
else d+=x-a;
if(b>=y) g+=(b-y)/2;
else d+=y-b;
if(c>=z) g+=(c-z)/2;
else d+=z-c;
if(g>=d) cout<<"Yes";
else cout<<"No";
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
980 | A | Links and Pearls | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you l... | The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl. | Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"-o-o--",
"-o---\n",
"-o---o-\n",
"ooo\n"
] | [
"YES",
"YES",
"NO",
"YES\n"
] | none | 500 | [
{
"input": "-o-o--",
"output": "YES"
},
{
"input": "-o---",
"output": "YES"
},
{
"input": "-o---o-",
"output": "NO"
},
{
"input": "ooo",
"output": "YES"
},
{
"input": "---",
"output": "YES"
},
{
"input": "--o-o-----o----o--oo-o-----ooo-oo---o--",
"... | 1,673,707,083 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 31 | 0 | string = input()
e_1 = string.count('-')
e_2 = string.count('o')
if e_1 == e_2 or e_1 % e_2 == 0:
print('YES')
else:
print('NO') | Title: Links and Pearls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearl... | ```python
string = input()
e_1 = string.count('-')
e_2 = string.count('o')
if e_1 == e_2 or e_1 % e_2 == 0:
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
292 | A | SMSC | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Some large corporation where Polycarpus works has its own short message service center (SMSC). The center's task is to send all sorts of crucial information. Polycarpus decided to check the efficiency of the SMSC.
For that, he asked to give him the statistics of the performance of the SMSC for some period of time. In... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=103) — the number of tasks of the SMSC. Next *n* lines contain the tasks' descriptions: the *i*-th line contains two space-separated integers *t**i* and *c**i* (1<=≤<=*t**i*,<=*c**i*<=≤<=106) — the time (the second) when the *i*-th task was received and the nu... | In a single line print two space-separated integers — the time when the last text message was sent and the maximum queue size at a certain moment of time. | [
"2\n1 1\n2 1\n",
"1\n1000000 10\n",
"3\n3 3\n4 3\n5 3\n"
] | [
"3 1\n",
"1000010 10\n",
"12 7\n"
] | In the first test sample:
- second 1: the first message has appeared in the queue, the queue's size is 1; - second 2: the first message is sent, the second message has been received, the queue's size is 1; - second 3: the second message is sent, the queue's size is 0,
Thus, the maximum size of the queue is 1, the... | 1,000 | [
{
"input": "2\n1 1\n2 1",
"output": "3 1"
},
{
"input": "1\n1000000 10",
"output": "1000010 10"
},
{
"input": "3\n3 3\n4 3\n5 3",
"output": "12 7"
},
{
"input": "1\n1 1",
"output": "2 1"
},
{
"input": "2\n1 11\n100 10",
"output": "110 11"
},
{
"input":... | 1,564,550,665 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 218 | 0 | n=int(input())
a,b=map(int,input().split())
l=b
x=a
q=0
m=0
m=max(m,l)
for i in range(n-1):
a,b=map(int,input().split())
l-=(a-x)
l=max(l,0)
l+=b
m=max(m,l)
x=a
print("{} {}".format(x+l,m)) | Title: SMSC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some large corporation where Polycarpus works has its own short message service center (SMSC). The center's task is to send all sorts of crucial information. Polycarpus decided to check the efficiency of the SMSC.
For that, he a... | ```python
n=int(input())
a,b=map(int,input().split())
l=b
x=a
q=0
m=0
m=max(m,l)
for i in range(n-1):
a,b=map(int,input().split())
l-=(a-x)
l=max(l,0)
l+=b
m=max(m,l)
x=a
print("{} {}".format(x+l,m))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | B | Choosing Symbol Pairs | PROGRAMMING | 1,500 | [
"strings"
] | B. Choosing Symbol Pairs | 2 | 256 | There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbol of string *S* is equal to the *j*-th. | The single input line contains *S*, consisting of lowercase Latin letters and digits. It is guaranteed that string *S* in not empty and its length does not exceed 105. | Print a single number which represents the number of pairs *i* and *j* with the needed property. Pairs (*x*,<=*y*) and (*y*,<=*x*) should be considered different, i.e. the ordered pairs count. | [
"great10\n",
"aaaaaaaaaa\n"
] | [
"7\n",
"100\n"
] | none | 1,000 | [
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "great10",
"output": "7"
},
{
"input": "aaaaaaaaaa",
"output": "100"
},
{
"input": "aabb",
"output": "8"
},
{
"input": "w",
"output": "1"
},
{
"in... | 1,652,783,758 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 92 | 28,364,800 | s = str(input())
sum = 0
list1 = []
for i in s:
if s.count(i) > 1 and i not in list1:
sum += (s.count(i)*s.count(i))
list1.append(i)
if sum == 0:
print(len(s))
else:
print(sum) | Title: Choosing Symbol Pairs
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a given string *S* consisting of *N* symbols. Your task is to find the number of ordered pairs of integers *i* and *j* such that
1. 1<=≤<=*i*,<=*j*<=≤<=*N*
2. *S*[*i*]<==<=*S*[*j*], that is the *i*-th symbo... | ```python
s = str(input())
sum = 0
list1 = []
for i in s:
if s.count(i) > 1 and i not in list1:
sum += (s.count(i)*s.count(i))
list1.append(i)
if sum == 0:
print(len(s))
else:
print(sum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
818 | B | Permutation Game | PROGRAMMING | 1,600 | [
"implementation"
] | null | null | *n* children are standing in a circle and playing a game. Children's numbers in clockwise order form a permutation *a*1,<=*a*2,<=...,<=*a**n* of length *n*. It is an integer sequence such that each integer from 1 to *n* appears exactly once in it.
The game consists of *m* steps. On each step the current leader with in... | The first line contains two integer numbers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100).
The second line contains *m* integer numbers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*) — indices of leaders in the beginning of each step. | Print such permutation of *n* numbers *a*1,<=*a*2,<=...,<=*a**n* that leaders in the game will be exactly *l*1,<=*l*2,<=...,<=*l**m* if all the rules are followed. If there are multiple solutions print any of them.
If there is no permutation which satisfies all described conditions print -1. | [
"4 5\n2 3 1 4 4\n",
"3 3\n3 1 2\n"
] | [
"3 1 2 4 \n",
"-1\n"
] | Let's follow leadership in the first example:
- Child 2 starts. - Leadership goes from 2 to 2 + *a*<sub class="lower-index">2</sub> = 3. - Leadership goes from 3 to 3 + *a*<sub class="lower-index">3</sub> = 5. As it's greater than 4, it's going in a circle to 1. - Leadership goes from 1 to 1 + *a*<sub class="lowe... | 0 | [
{
"input": "4 5\n2 3 1 4 4",
"output": "3 1 2 4 "
},
{
"input": "3 3\n3 1 2",
"output": "-1"
},
{
"input": "1 100\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1... | 1,516,856,324 | 3,224 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 5,632,000 | n, m = [int(x) for x in input().split()]
mm = [int(x) for x in input().split()]
a = [0] * (n + 1)
f = False
for i in range(m - 1):
r = mm[i + 1] - mm[i]
if r <= 0:
r += n
if a[mm[i]] == 0:
a[mm[i]] = r
else:
f = True
break
if len(a) != len(set(a)):
f = T... | Title: Permutation Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* children are standing in a circle and playing a game. Children's numbers in clockwise order form a permutation *a*1,<=*a*2,<=...,<=*a**n* of length *n*. It is an integer sequence such that each integer from 1 to *n... | ```python
n, m = [int(x) for x in input().split()]
mm = [int(x) for x in input().split()]
a = [0] * (n + 1)
f = False
for i in range(m - 1):
r = mm[i + 1] - mm[i]
if r <= 0:
r += n
if a[mm[i]] == 0:
a[mm[i]] = r
else:
f = True
break
if len(a) != len(set(a)):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
819 | B | Mister B and PR Shifts | PROGRAMMING | 1,900 | [
"data structures",
"implementation",
"math"
] | null | null | Some time ago Mister B detected a strange signal from the space, which he started to study.
After some transformation the signal turned out to be a permutation *p* of length *n* or its cyclic shift. For the further investigation Mister B need some basis, that's why he decided to choose cyclic shift of this permutation... | First line contains single integer *n* (2<=≤<=*n*<=≤<=106) — the length of the permutation.
The second line contains *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the elements of the permutation. It is guaranteed that all elements are distinct. | Print two integers: the minimum deviation of cyclic shifts of permutation *p* and the id of such shift. If there are multiple solutions, print any of them. | [
"3\n1 2 3\n",
"3\n2 3 1\n",
"3\n3 2 1\n"
] | [
"0 0\n",
"0 1\n",
"2 1\n"
] | In the first sample test the given permutation *p* is the identity permutation, that's why its deviation equals to 0, the shift id equals to 0 as well.
In the second sample test the deviation of *p* equals to 4, the deviation of the 1-st cyclic shift (1, 2, 3) equals to 0, the deviation of the 2-nd cyclic shift (3, 1,... | 1,000 | [
{
"input": "3\n1 2 3",
"output": "0 0"
},
{
"input": "3\n2 3 1",
"output": "0 1"
},
{
"input": "3\n3 2 1",
"output": "2 1"
},
{
"input": "2\n1 2",
"output": "0 0"
},
{
"input": "2\n2 1",
"output": "0 1"
},
{
"input": "10\n10 1 9 2 8 3 7 4 6 5",
"ou... | 1,695,009,558 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 113,356,800 | # Takes a string containing the length of the permutation on the first line and the permutation on the second and returns the length and the list of integers
def parse_input(input_str: str) -> (int, list[int]):
lines = input_str.strip().split('\n')
n = int(lines[0])
p = list(map(int, lines[1].strip().... | Title: Mister B and PR Shifts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some time ago Mister B detected a strange signal from the space, which he started to study.
After some transformation the signal turned out to be a permutation *p* of length *n* or its cyclic shift. For the furt... | ```python
# Takes a string containing the length of the permutation on the first line and the permutation on the second and returns the length and the list of integers
def parse_input(input_str: str) -> (int, list[int]):
lines = input_str.strip().split('\n')
n = int(lines[0])
p = list(map(int, lines[1... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive co... | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,541,593,894 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | def checkCoPrime(nomi,denomi):
if((denomi/nomi)%2==0 or (denomi/nomi)%2==1):
return 0
else:
return 1
sumN=int(input())
maxNomi=sumN//2
storeNomi=0
storeDenomi=0
for i in range(1,(maxNomi)):
denomi=sumN-i
if(i==1):
storeNomi=i
storeDenomi=denomi
else:
if(... | Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is cal... | ```python
def checkCoPrime(nomi,denomi):
if((denomi/nomi)%2==0 or (denomi/nomi)%2==1):
return 0
else:
return 1
sumN=int(input())
maxNomi=sumN//2
storeNomi=0
storeDenomi=0
for i in range(1,(maxNomi)):
denomi=sumN-i
if(i==1):
storeNomi=i
storeDenomi=denomi
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
659 | A | Round House | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance *a* and he decided that during his walk he will move around the house *b* entrances in th... | The single line of the input contains three space-separated integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*a*<=≤<=*n*,<=<=-<=100<=≤<=*b*<=≤<=100) — the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively. | Print a single integer *k* (1<=≤<=*k*<=≤<=*n*) — the number of the entrance where Vasya will be at the end of his walk. | [
"6 2 -5\n",
"5 1 3\n",
"3 2 7\n"
] | [
"3\n",
"4\n",
"3\n"
] | The first example is illustrated by the picture in the statements. | 500 | [
{
"input": "6 2 -5",
"output": "3"
},
{
"input": "5 1 3",
"output": "4"
},
{
"input": "3 2 7",
"output": "3"
},
{
"input": "1 1 0",
"output": "1"
},
{
"input": "1 1 -1",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "100 ... | 1,615,200,447 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 77 | 0 | n, a, b = map(int, input().split())
print(((a+b-1) % n + n) % n+1) | Title: Round House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in e... | ```python
n, a, b = map(int, input().split())
print(((a+b-1) % n + n) % n+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
448 | D | Multiplication Table | PROGRAMMING | 1,800 | [
"binary search",
"brute force"
] | null | null | Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multiplication table, where the element on the intersection of the *i*-th row and *j*-th column equals *i*·*j* ... | The single line contains integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=5·105; 1<=≤<=*k*<=≤<=*n*·*m*). | Print the *k*-th largest number in a *n*<=×<=*m* multiplication table. | [
"2 2 2\n",
"2 3 4\n",
"1 10 5\n"
] | [
"2\n",
"3\n",
"5\n"
] | A 2 × 3 multiplication table looks like this: | 2,000 | [
{
"input": "2 2 2",
"output": "2"
},
{
"input": "2 3 4",
"output": "3"
},
{
"input": "1 10 5",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "10 1 7",
"output": "7"
},
{
"input": "10 10 33",
"output": "14"
},
{
"input": "... | 1,688,784,483 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 6 | 919 | 268,390,400 | n, m, k = tuple(map(int, input().split()))
arr = []
for i in range(1, n+1):
for j in range(1, m+1):
arr += [i*j]
arr.sort()
print(arr[k-1]) | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multi... | ```python
n, m, k = tuple(map(int, input().split()))
arr = []
for i in range(1, n+1):
for j in range(1, m+1):
arr += [i*j]
arr.sort()
print(arr[k-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
331 | A1 | Oh Sweet Beaverette | PROGRAMMING | 1,400 | [
"brute force",
"implementation"
] | null | null | — Oh my sweet Beaverette, would you fancy a walk along a wonderful woodland belt with me?
— Of course, my Smart Beaver! Let us enjoy the splendid view together. How about Friday night?
At this point the Smart Beaver got rushing. Everything should be perfect by Friday, so he needed to prepare the belt to the upcom... | The first line contains a single integer *n* — the initial number of trees in the woodland belt, 2<=≤<=*n*. The second line contains space-separated integers *a**i* — the esthetic appeals of each tree. All esthetic appeals do not exceed 109 in their absolute value.
- to get 30 points, you need to solve the problem wi... | In the first line print two integers — the total esthetic appeal of the woodland belt after the Smart Beaver's intervention and the number of the cut down trees *k*.
In the next line print *k* integers — the numbers of the trees the Beaver needs to cut down. Assume that the trees are numbered from 1 to *n* from left t... | [
"5\n1 2 3 1 2\n",
"5\n1 -2 3 1 -2\n"
] | [
"8 1\n1 ",
"5 2\n2 5 "
] | none | 30 | [
{
"input": "5\n1 2 3 1 2",
"output": "8 1\n1 "
},
{
"input": "5\n1 -2 3 1 -2",
"output": "5 2\n2 5 "
},
{
"input": "2\n0 0",
"output": "0 0"
},
{
"input": "3\n0 -1 0",
"output": "0 1\n2 "
},
{
"input": "3\n1 1 1",
"output": "3 0"
},
{
"input": "4\n-1 1... | 1,375,452,161 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS1 | 4 | 92 | 0 | n = int(input())
l = [int(x) for x in input().split()]
mx = -10**100
k = 0
start = 0
end = 0
for i in range(n):
s=l[i]
for y in range(i+1,n):
if(l[i] == l[y]):
#solo i positivi
neg = i + (n-y-1)
for x in l[i+1:y]:
if x > 0:
... | Title: Oh Sweet Beaverette
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
— Oh my sweet Beaverette, would you fancy a walk along a wonderful woodland belt with me?
— Of course, my Smart Beaver! Let us enjoy the splendid view together. How about Friday night?
At this point the Smart ... | ```python
n = int(input())
l = [int(x) for x in input().split()]
mx = -10**100
k = 0
start = 0
end = 0
for i in range(n):
s=l[i]
for y in range(i+1,n):
if(l[i] == l[y]):
#solo i positivi
neg = i + (n-y-1)
for x in l[i+1:y]:
if x > 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero,... | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,695,307,209 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 11 | 62 | 0 | s=list(map(int, input().split()))
n=s[0]
k=s[1]
del s
while k!=0:
if n%10>=k:
n-=k
k=0
else:
k-=(n%10+1)
n//=10
print(n) | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit ... | ```python
s=list(map(int, input().split()))
n=s[0]
k=s[1]
del s
while k!=0:
if n%10>=k:
n-=k
k=0
else:
k-=(n%10+1)
n//=10
print(n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, al... | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,649,757,682 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | n = int(input())
r = n%4
if(n == 0):
print(1)
elif(r==1):
print(8)
elif(r==2):
print(4)
elif(r==3):
print(2)
else:
print(6) | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one ques... | ```python
n = int(input())
r = n%4
if(n == 0):
print(1)
elif(r==1):
print(8)
elif(r==2):
print(4)
elif(r==3):
print(2)
else:
print(6)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,626,964,065 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 6,758,400 | [L] = map(int, input().split())
[A] = map(int, input().split())
[P] = map(int, input().split())
if L<A<P:
a = min(L,A,P)
print(a*7-7)
else:
print("0") | Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
[L] = map(int, input().split())
[A] = map(int, input().split())
[P] = map(int, input().split())
if L<A<P:
a = min(L,A,P)
print(a*7-7)
else:
print("0")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,656,470,023 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 46 | 0 | [n,m]=map(int,input().split())
x=[]
for i in range(n):
b=input()
if "C" in b or "M" in b or "Y" in b:
x.append(1)
else:x.append(0)
if 1 in x:
print("#Color")
elif 1 not in x:
print("#Black&White") | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
[n,m]=map(int,input().split())
x=[]
for i in range(n):
b=input()
if "C" in b or "M" in b or "Y" in b:
x.append(1)
else:x.append(0)
if 1 in x:
print("#Color")
elif 1 not in x:
print("#Black&White")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
377 | A | Maze | PROGRAMMING | 1,600 | [
"dfs and similar"
] | null | null | Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to a... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=<<=*s*), where *n* and *m* are the maze's height and width, correspondingly, *k* is the number of walls Pavel wants to add and letter *s* represents the number of empty cells in the original maze.
Each of the next *n* lines co... | Print *n* lines containing *m* characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").
It is guaranteed that a solution exists. If there are multiple solutions you can output any of t... | [
"3 4 2\n#..#\n..#.\n#...\n",
"5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#\n"
] | [
"#.X#\nX.#.\n#...\n",
"#XXX\n#X#.\nX#..\n...#\n.#.#\n"
] | none | 500 | [
{
"input": "5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#",
"output": "#XXX\n#X#.\nX#..\n...#\n.#.#"
},
{
"input": "3 3 2\n#.#\n...\n#.#",
"output": "#X#\nX..\n#.#"
},
{
"input": "7 7 18\n#.....#\n..#.#..\n.#...#.\n...#...\n.#...#.\n..#.#..\n#.....#",
"output": "#XXXXX#\nXX#X#X.\nX#XXX#.\nXXX#... | 1,699,456,017 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#define ll long long
using namespace std;
vector<vector<char>>a(505, vector<char>(505));
int dr[] = { 0,0,1,1,1,-1,-1,-1 };
int dc[] = { 1,-1,-1,0,1,-1,0,1 };
int n, m, d,c;
bool valid(int i, int j) { return i > 0 and j > 0 and i <= n and j <= m and a[i][j] == '.'; }
void dfs(int i,... | Title: Maze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze w... | ```python
#include <bits/stdc++.h>
#define ll long long
using namespace std;
vector<vector<char>>a(505, vector<char>(505));
int dr[] = { 0,0,1,1,1,-1,-1,-1 };
int dc[] = { 1,-1,-1,0,1,-1,0,1 };
int n, m, d,c;
bool valid(int i, int j) { return i > 0 and j > 0 and i <= n and j <= m and a[i][j] == '.'; }
void ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
87 | A | Trains | PROGRAMMING | 1,500 | [
"implementation",
"math"
] | A. Trains | 2 | 256 | Vasya the programmer lives in the middle of the Programming subway branch. He has two girlfriends: Dasha and Masha, who live at the different ends of the branch, each one is unaware of the other one's existence.
When Vasya has some free time, he goes to one of his girlfriends. He descends into the subway at some time,... | The first line contains two integers *a* and *b* (*a*<=≠<=*b*,<=1<=≤<=*a*,<=*b*<=≤<=106). | Print "Dasha" if Vasya will go to Dasha more frequently, "Masha" if he will go to Masha more frequently, or "Equal" if he will go to both girlfriends with the same frequency. | [
"3 7\n",
"5 3\n",
"2 3\n"
] | [
"Dasha\n",
"Masha\n",
"Equal\n"
] | Let's take a look at the third sample. Let the trains start to go at the zero moment of time. It is clear that the moments of the trains' arrival will be periodic with period 6. That's why it is enough to show that if Vasya descends to the subway at a moment of time inside the interval (0, 6], he will go to both girls ... | 500 | [
{
"input": "3 7",
"output": "Dasha"
},
{
"input": "5 3",
"output": "Masha"
},
{
"input": "2 3",
"output": "Equal"
},
{
"input": "31 88",
"output": "Dasha"
},
{
"input": "8 75",
"output": "Dasha"
},
{
"input": "32 99",
"output": "Dasha"
},
{
... | 1,642,530,378 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 122 | 0 | import math
a,b = map(int,input().split())
x = math.gcd(a,b)
a = a//x
b = b//x
if abs(a-b) == 1:
print("Equal")
elif a<b:
print("Masha")
else:
print("Dasha")
| Title: Trains
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya the programmer lives in the middle of the Programming subway branch. He has two girlfriends: Dasha and Masha, who live at the different ends of the branch, each one is unaware of the other one's existence.
When Vasya has some... | ```python
import math
a,b = map(int,input().split())
x = math.gcd(a,b)
a = a//x
b = b//x
if abs(a-b) == 1:
print("Equal")
elif a<b:
print("Masha")
else:
print("Dasha")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,692,693,520 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | s = input()
txt = ''
for char in s:
if char.isupper():
txt += char.lower()
else:
txt += char.upper()
print(txt) | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
s = input()
txt = ''
for char in s:
if char.isupper():
txt += char.lower()
else:
txt += char.upper()
print(txt)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
285 | C | Building Permutation | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"sortings"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
You ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the size of the sought permutation. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Print a single number — the minimum number of moves.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"2\n3 0\n",
"3\n-1 -1 2\n"
] | [
"2\n",
"6\n"
] | In the first sample you should decrease the first number by one and then increase the second number by one. The resulting permutation is (2, 1).
In the second sample you need 6 moves to build permutation (1, 3, 2). | 1,500 | [
{
"input": "2\n3 0",
"output": "2"
},
{
"input": "3\n-1 -1 2",
"output": "6"
},
{
"input": "5\n-3 5 -3 3 3",
"output": "10"
},
{
"input": "10\n9 6 -2 4 1 1 1 9 6 2",
"output": "18"
},
{
"input": "9\n2 0 0 6 5 4 1 9 3",
"output": "15"
},
{
"input": "100... | 1,480,686,954 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 966 | 26,009,600 | input()
a = [int(x) for x in input().strip().split(' ')]
a.sort()
ans = 0
for i in range(len(a)):
ans += abs(a[i]-i-1)
print(ans)
| Title: Building Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *... | ```python
input()
a = [int(x) for x in input().strip().split(' ')]
a.sort()
ans = 0
for i in range(len(a)):
ans += abs(a[i]-i-1)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
844 | B | Rectangles | PROGRAMMING | 1,300 | [
"combinatorics",
"math"
] | null | null | You are given *n*<=×<=*m* table. Each cell of the table is colored white or black. Find the number of non-empty sets of cells such that:
1. All cells in a set have the same color. 1. Every two cells in a set share row or column. | The first line of input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and the number of columns correspondingly.
The next *n* lines of input contain descriptions of rows. There are *m* integers, separated by spaces, in each line. The number equals 0 if the corresponding cell is colored wh... | Output single integer — the number of non-empty sets from the problem description. | [
"1 1\n0\n",
"2 3\n1 0 1\n0 1 0\n"
] | [
"1\n",
"8\n"
] | In the second example, there are six one-element sets. Additionally, there are two two-element sets, the first one consists of the first and the third cells of the first row, the second one consists of the first and the third cells of the second row. To sum up, there are 8 sets. | 1,000 | [
{
"input": "1 1\n0",
"output": "1"
},
{
"input": "2 3\n1 0 1\n0 1 0",
"output": "8"
},
{
"input": "2 2\n1 1\n1 1",
"output": "8"
},
{
"input": "1 10\n0 0 0 0 0 0 0 0 0 0",
"output": "1023"
},
{
"input": "11 1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1\n1",
"output": "2047"... | 1,503,594,347 | 1,847 | Python 3 | OK | TESTS | 55 | 77 | 0 | from math import factorial
def c(n, k):
return factorial(n) // (factorial(k) * factorial(n - k))
n, m = map(int, input().split())
ans = 0
a = [list(map(int, input().split())) for i in range(n)]
for i in range(n):
c0, c1 = 0, 0
for j in range(m):
if a[i][j]:
c1 += 1
... | Title: Rectangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n*<=×<=*m* table. Each cell of the table is colored white or black. Find the number of non-empty sets of cells such that:
1. All cells in a set have the same color. 1. Every two cells in a set share row or ... | ```python
from math import factorial
def c(n, k):
return factorial(n) // (factorial(k) * factorial(n - k))
n, m = map(int, input().split())
ans = 0
a = [list(map(int, input().split())) for i in range(n)]
for i in range(n):
c0, c1 = 0, 0
for j in range(m):
if a[i][j]:
c1 +... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
489 | B | BerSU Ball | PROGRAMMING | 1,200 | [
"dfs and similar",
"dp",
"graph matchings",
"greedy",
"sortings",
"two pointers"
] | null | null | The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in eac... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of boys. The second line contains sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is the *i*-th boy's dancing skill.
Similarly, the third line contains an integer *m* (1<=≤<=*m*<=≤<=100) — the number of girls. The fourth l... | Print a single number — the required maximum possible number of pairs. | [
"4\n1 4 6 2\n5\n5 1 5 7 9\n",
"4\n1 2 3 4\n4\n10 11 12 13\n",
"5\n1 1 1 1 1\n3\n1 2 3\n"
] | [
"3\n",
"0\n",
"2\n"
] | none | 1,000 | [
{
"input": "4\n1 4 6 2\n5\n5 1 5 7 9",
"output": "3"
},
{
"input": "4\n1 2 3 4\n4\n10 11 12 13",
"output": "0"
},
{
"input": "5\n1 1 1 1 1\n3\n1 2 3",
"output": "2"
},
{
"input": "1\n1\n1\n1",
"output": "1"
},
{
"input": "2\n1 10\n1\n9",
"output": "1"
},
{... | 1,685,770,510 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 46 | 0 | n = int(input(""))
a = list(map(int, input("").split()))
a.sort()
a.reverse()
m = int(input(""))
b = list(map(int, input("").split()))
b.sort()
b.reverse()
count = 0
for i in range(n+m):
if len(a) == 0 or len(b) == 0:
break
if a[-1] < b[-1]:
if a[-1] == b[-1]-1:
count... | Title: BerSU Ball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! *n* boys and *m* girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy... | ```python
n = int(input(""))
a = list(map(int, input("").split()))
a.sort()
a.reverse()
m = int(input(""))
b = list(map(int, input("").split()))
b.sort()
b.reverse()
count = 0
for i in range(n+m):
if len(a) == 0 or len(b) == 0:
break
if a[-1] < b[-1]:
if a[-1] == b[-1]-1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
653 | A | Bear and Three Balls | PROGRAMMING | 900 | [
"brute force",
"implementation",
"sortings"
] | null | null | Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy:
- No two friends can get balls of the same size. - No two friends can get balls of sizes th... | The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball. | Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes). | [
"4\n18 55 16 17\n",
"6\n40 41 43 44 44 44\n",
"8\n5 972 3 4 1 4 970 971\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17.
In the second sample, there is no way to give gifts to three friends without breaking the rules.
In the third sample, there is even more than one way to choose bal... | 500 | [
{
"input": "4\n18 55 16 17",
"output": "YES"
},
{
"input": "6\n40 41 43 44 44 44",
"output": "NO"
},
{
"input": "8\n5 972 3 4 1 4 970 971",
"output": "YES"
},
{
"input": "3\n959 747 656",
"output": "NO"
},
{
"input": "4\n1 2 2 3",
"output": "YES"
},
{
... | 1,622,186,951 | 2,147,483,647 | PyPy 3 | OK | TESTS | 84 | 108 | 0 | n = int(input())
daf = set(map(int, input().split()))
daf = sorted(daf)
for i in range(len(daf) - 2):
if daf[i+2] - daf[i] == 2:
print("YES")
break
else:
print("NO")
| Title: Bear and Three Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make fri... | ```python
n = int(input())
daf = set(map(int, input().split()))
daf = sorted(daf)
for i in range(len(daf) - 2):
if daf[i+2] - daf[i] == 2:
print("YES")
break
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,617,611,531 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | l,r,k=map(int,input().split())
cnt=int(0)
i=int(0)
while cnt==0:
if k**i>=l and k**i<=r:
print(k**i,end=" ")
i=i+1
else:
break
if cnt==i:
print(-1)
| Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
l,r,k=map(int,input().split())
cnt=int(0)
i=int(0)
while cnt==0:
if k**i>=l and k**i<=r:
print(k**i,end=" ")
i=i+1
else:
break
if cnt==i:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,674,892,240 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 65 | 62 | 0 | n, t = map(int, input().split())
if t == 10 and n == 1:
print(-1)
elif t == 10:
print(10 ** (n-1))
else:
print(str(t) * n) | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n, t = map(int, input().split())
if t == 10 and n == 1:
print(-1)
elif t == 10:
print(10 ** (n-1))
else:
print(str(t) * n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
946 | C | String Transformation | PROGRAMMING | 1,300 | [
"greedy",
"strings"
] | null | null | You are given a string *s* consisting of |*s*| small english letters.
In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be replaced with t, etc.). You cannot replace letter z with any other letter.
Your target is to make some number... | The only one line of the input consisting of the string *s* consisting of |*s*| (1<=≤<=|*s*|<=≤<=105) small english letters. | If you can get a string that can be obtained from the given string and will contain english alphabet as a subsequence, print it. Otherwise print «-1» (without quotes). | [
"aacceeggiikkmmooqqssuuwwyy\n",
"thereisnoanswer\n"
] | [
"abcdefghijklmnopqrstuvwxyz\n",
"-1\n"
] | none | 0 | [
{
"input": "aacceeggiikkmmooqqssuuwwyy",
"output": "abcdefghijklmnopqrstuvwxyz"
},
{
"input": "thereisnoanswer",
"output": "-1"
},
{
"input": "jqcfvsaveaixhioaaeephbmsmfcgdyawscpyioybkgxlcrhaxs",
"output": "-1"
},
{
"input": "rtdacjpsjjmjdhcoprjhaenlwuvpfqzurnrswngmpnkdnunaen... | 1,609,093,176 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 |
t = input()
p=''
for j in t:
p+= str(ord(j)-(ord('a')-1))
if len(p) < 26:
print(-1)
else:
q=1
for j in p:
if int(j) <= q:
q+=1
if q>=26:
print('abcdefghijklmnopqrstuvwxyz')
else:
print(-1)
| Title: String Transformation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting of |*s*| small english letters.
In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be rep... | ```python
t = input()
p=''
for j in t:
p+= str(ord(j)-(ord('a')-1))
if len(p) < 26:
print(-1)
else:
q=1
for j in p:
if int(j) <= q:
q+=1
if q>=26:
print('abcdefghijklmnopqrstuvwxyz')
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,389,424,494 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 92 | 307,200 | test = []
test1 = []
result = {}
n = int(input())
mark = 0
max = 0
for i in range(0, n):
mark = 0
name, scores = map(str, input().split())
score = int(scores)
if len(test) is 0:
test.append((name, score))
continue
for temp in test:
if temp[0] == name:
... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
test = []
test1 = []
result = {}
n = int(input())
mark = 0
max = 0
for i in range(0, n):
mark = 0
name, scores = map(str, input().split())
score = int(scores)
if len(test) is 0:
test.append((name, score))
continue
for temp in test:
if temp[0] == name... | 0 | MatrixStudio/Codeforces-Python-Submissions |
462 | B | Appleman and Card Game | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to lette... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. | Print a single integer – the answer to the problem. | [
"15 10\nDZFDFZDFDDDDDDF\n",
"6 4\nYJSNPI\n"
] | [
"82\n",
"4\n"
] | In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | 1,000 | [
{
"input": "15 10\nDZFDFZDFDDDDDDF",
"output": "82"
},
{
"input": "6 4\nYJSNPI",
"output": "4"
},
{
"input": "5 3\nAOWBY",
"output": "3"
},
{
"input": "1 1\nV",
"output": "1"
},
{
"input": "2 1\nWT",
"output": "1"
},
{
"input": "2 2\nBL",
"output":... | 1,598,248,649 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 109 | 7,065,600 | from collections import Counter
n,k = map(int,input().split(' '))
s = input()
m = Counter(s)
ans = 0
for key,v in m.items():
if v <= k:
k = k-v
#print(k)
ans += v*v
else :
ans += k*k
break
print(ans)
| Title: Appleman and Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally... | ```python
from collections import Counter
n,k = map(int,input().split(' '))
s = input()
m = Counter(s)
ans = 0
for key,v in m.items():
if v <= k:
k = k-v
#print(k)
ans += v*v
else :
ans += k*k
break
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
287 | A | IQ Test | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and others are painted white. Your task is to repaint at most one cell the other color so that the... | Four lines contain four characters each: the *j*-th character of the *i*-th line equals "." if the cell in the *i*-th row and the *j*-th column of the square is painted white, and "#", if the cell is black. | Print "YES" (without the quotes), if the test can be passed and "NO" (without the quotes) otherwise. | [
"####\n.#..\n####\n....\n",
"####\n....\n####\n....\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample it is enough to repaint the first cell in the second row. After such repainting the required 2 × 2 square is on the intersection of the 1-st and 2-nd row with the 1-st and 2-nd column. | 500 | [
{
"input": "###.\n...#\n###.\n...#",
"output": "NO"
},
{
"input": ".##.\n#..#\n.##.\n#..#",
"output": "NO"
},
{
"input": ".#.#\n#.#.\n.#.#\n#.#.",
"output": "NO"
},
{
"input": "##..\n..##\n##..\n..##",
"output": "NO"
},
{
"input": "#.#.\n#.#.\n.#.#\n.#.#",
"ou... | 1,625,570,643 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | a=[]
for i in range(4):
x=input().split()
a.apend(x)
flag=0
for i in range(1,n):
for j in range(n-1):
if a[i-1][j]==a[i-1][j+1]==a[i][j+1]:
flag=1
break
if flag:
print("YES")
else:
print("NO") | Title: IQ Test
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and o... | ```python
a=[]
for i in range(4):
x=input().split()
a.apend(x)
flag=0
for i in range(1,n):
for j in range(n-1):
if a[i-1][j]==a[i-1][j+1]==a[i][j+1]:
flag=1
break
if flag:
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
746 | D | Green and Black Tea | PROGRAMMING | 1,500 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | Innokentiy likes tea very much and today he wants to drink exactly *n* cups of tea. He would be happy to drink more but he had exactly *n* tea bags, *a* of them are green and *b* are black.
Innokentiy doesn't like to drink the same tea (green or black) more than *k* times in a row. Your task is to determine the order ... | The first line contains four integers *n*, *k*, *a* and *b* (1<=≤<=*k*<=≤<=*n*<=≤<=105, 0<=≤<=*a*,<=*b*<=≤<=*n*) — the number of cups of tea Innokentiy wants to drink, the maximum number of cups of same tea he can drink in a row, the number of tea bags of green and black tea. It is guaranteed that *a*<=+<=*b*<==<=*n*. | If it is impossible to drink *n* cups of tea, print "NO" (without quotes).
Otherwise, print the string of the length *n*, which consists of characters 'G' and 'B'. If some character equals 'G', then the corresponding cup of tea should be green. If some character equals 'B', then the corresponding cup of tea should be ... | [
"5 1 3 2\n",
"7 2 2 5\n",
"4 3 4 0\n"
] | [
"GBGBG\n",
"BBGBGBB",
"NO\n"
] | none | 2,000 | [
{
"input": "5 1 3 2",
"output": "GBGBG"
},
{
"input": "7 2 2 5",
"output": "BBGBBGB"
},
{
"input": "4 3 4 0",
"output": "NO"
},
{
"input": "2 2 0 2",
"output": "BB"
},
{
"input": "3 2 0 3",
"output": "NO"
},
{
"input": "1 1 0 1",
"output": "B"
},... | 1,628,819,512 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 93 | 8,192,000 |
def read_int():
return int(input())
def read_ints():
return list(map(int, input().split()))
n,k,a,b = read_ints()
ch = 'GB'
if a < b:
a,b = b,a
ch = 'BG'
result = []
c = min(k,a-b)
result.append(ch[0]*c)
a -= c
while b > 0:
result.append(ch[1])
b -= 1
c = min(k,a-b)
result.append(ch[... | Title: Green and Black Tea
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy likes tea very much and today he wants to drink exactly *n* cups of tea. He would be happy to drink more but he had exactly *n* tea bags, *a* of them are green and *b* are black.
Innokentiy doesn't like ... | ```python
def read_int():
return int(input())
def read_ints():
return list(map(int, input().split()))
n,k,a,b = read_ints()
ch = 'GB'
if a < b:
a,b = b,a
ch = 'BG'
result = []
c = min(k,a-b)
result.append(ch[0]*c)
a -= c
while b > 0:
result.append(ch[1])
b -= 1
c = min(k,a-b)
result.... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Leha decided to move to a quiet town Vičkopolis, because he was tired by living in Bankopolis. Upon arrival he immediately began to expand his network of hacked computers. During the week Leha managed to get access to *n* computers throughout the town. Incidentally all the computers, which were hacked by Leha, lie on t... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3·105) denoting the number of hacked computers.
The second line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109) denoting the coordinates of hacked computers. It is guaranteed that all *x**i* are distinct. | Print a single integer — the required sum modulo 109<=+<=7. | [
"2\n4 7\n",
"3\n4 3 1\n"
] | [
"3\n",
"9\n"
] | There are three non-empty subsets in the first sample test:<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/02b2d12556dad85f1c6c6912786eb87d4be2ea17.png" style="max-width: 100.0%;max-height: 100.0%;"/>, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/22f6a537962c... | 0 | [
{
"input": "2\n4 7",
"output": "3"
},
{
"input": "3\n4 3 1",
"output": "9"
},
{
"input": "20\n8 11 13 19 21 34 36 44 57 58 61 63 76 78 79 81 85 86 90 95",
"output": "83396599"
},
{
"input": "20\n1 8 9 12 15 17 18 24 30 33 36 41 53 54 59 62 64 66 72 73",
"output": "6805914... | 1,587,374,270 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 26,009,600 | from sys import stdin
input = stdin.buffer.readline
n = int(input())
a = sorted(map(int, input().split()))
i, j = 0, n - 1
s = ans = 0
while n - i - 1:
s += a[j] - a[i]
ans += pow(2, n - i - 2) * s
ans %= 1000000007
i += 1
j -= 1
print(ans) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Leha decided to move to a quiet town Vičkopolis, because he was tired by living in Bankopolis. Upon arrival he immediately began to expand his network of hacked computers. During the week Leha managed to get access to *n* computer... | ```python
from sys import stdin
input = stdin.buffer.readline
n = int(input())
a = sorted(map(int, input().split()))
i, j = 0, n - 1
s = ans = 0
while n - i - 1:
s += a[j] - a[i]
ans += pow(2, n - i - 2) * s
ans %= 1000000007
i += 1
j -= 1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
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