contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
629 | A | Far Relative’s Birthday Cake | PROGRAMMING | 800 | [
"brute force",
"combinatorics",
"constructive algorithms",
"implementation"
] | null | null | Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with side length 1. Each square is either empty or consists of a single chocolate. They bought the cake and randomly sta... | In the first line of the input, you are given a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the side of the cake.
Then follow *n* lines, each containing *n* characters. Empty cells are denoted with '.', while cells that contain chocolates are denoted by 'C'. | Print the value of Famil Door's happiness, i.e. the number of pairs of chocolate pieces that share the same row or the same column. | [
"3\n.CC\nC..\nC.C\n",
"4\nCC..\nC..C\n.CC.\n.CC.\n"
] | [
"4\n",
"9\n"
] | If we number rows from top to bottom and columns from left to right, then, pieces that share the same row in the first sample are:
1. (1, 2) and (1, 3) 1. (3, 1) and (3, 3) 1. (2, 1) and (3, 1) 1. (1, 3) and (3, 3) | 500 | [
{
"input": "3\n.CC\nC..\nC.C",
"output": "4"
},
{
"input": "4\nCC..\nC..C\n.CC.\n.CC.",
"output": "9"
},
{
"input": "5\n.CCCC\nCCCCC\n.CCC.\nCC...\n.CC.C",
"output": "46"
},
{
"input": "7\n.CC..CC\nCC.C..C\nC.C..C.\nC...C.C\nCCC.CCC\n.CC...C\n.C.CCC.",
"output": "84"
},... | 1,612,888,626 | 2,147,483,647 | PyPy 3 | OK | TESTS | 48 | 93 | 1,536,000 | n = int(input())
a = []
for i in range(n):
a.append(input())
ans = 0
for i in range(n):
b = 0
c = 0
for j in range(n):
if a[i][j] == 'C':
b += 1
if a[j][i] == 'C':
c += 1
ans += (b * (b - 1)) // 2
ans += (c * (c - 1)) // 2
print(ans) | Title: Far Relative’s Birthday Cake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Door's family is going celebrate Famil Doors's birthday party. They love Famil Door so they are planning to make his birthday cake weird!
The cake is a *n*<=×<=*n* square consisting of equal squares with s... | ```python
n = int(input())
a = []
for i in range(n):
a.append(input())
ans = 0
for i in range(n):
b = 0
c = 0
for j in range(n):
if a[i][j] == 'C':
b += 1
if a[j][i] == 'C':
c += 1
ans += (b * (b - 1)) // 2
ans += (c * (c - 1)) // 2
print(an... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
44 | A | Indian Summer | PROGRAMMING | 900 | [
"implementation"
] | A. Indian Summer | 2 | 256 | Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the species of the tree of one of the leaves she already has. Find out how many leaves Alyona has picked. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of leaves Alyona has found. The next *n* lines contain the leaves' descriptions. Each leaf is characterized by the species of the tree it has fallen from and by the color. The species of the trees and colors are given in names, consisting of no mor... | Output the single number — the number of Alyona's leaves. | [
"5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green\n",
"3\noak yellow\noak yellow\noak yellow\n"
] | [
"4\n",
"1\n"
] | none | 0 | [
{
"input": "5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green",
"output": "4"
},
{
"input": "3\noak yellow\noak yellow\noak yellow",
"output": "1"
},
{
"input": "5\nxbnbkzn hp\nkaqkl vrgzbvqstu\nj aqidx\nhos gyul\nwefxmh tygpluae",
"output": "5"
},
{
"input"... | 1,651,939,455 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 92 | 0 | n=int(input())
x=[]
for i in range(n):
x.append(input())
x=set(x)
a=len(x)
print(a)
| Title: Indian Summer
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the specie... | ```python
n=int(input())
x=[]
for i in range(n):
x.append(input())
x=set(x)
a=len(x)
print(a)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,648,444,043 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 57 | 372 | 5,427,200 | n=int(input())
k1,k2,k3,k4=0,0,0,0
for i in range (n):
x,y=map(int,input().split())
if x==1:
k1+=1
else:
k2+=1
if y==1:
k3+=1
else:
k4+=1
print (min(k1,k2)+min(k3,k4))
| Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
n=int(input())
k1,k2,k3,k4=0,0,0,0
for i in range (n):
x,y=map(int,input().split())
if x==1:
k1+=1
else:
k2+=1
if y==1:
k3+=1
else:
k4+=1
print (min(k1,k2)+min(k3,k4))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,690,558,891 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 46 | 0 | n,m = map(int,input().split())
ans=0
for i in range(n):
row = list(input().split())
if "C" in row or"M"in row or"Y"in row:
ans="#Color"
if ans!="#Color":
ans="#Black&White"
print(ans) | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
n,m = map(int,input().split())
ans=0
for i in range(n):
row = list(input().split())
if "C" in row or"M"in row or"Y"in row:
ans="#Color"
if ans!="#Color":
ans="#Black&White"
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
493 | A | Vasya and Football | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Vasya has started watching football games. He has learned that for some fouls the players receive yellow cards, and for some fouls they receive red cards. A player who receives the second yellow card automatically receives a red card.
Vasya is watching a recorded football match now and makes notes of all the fouls tha... | The first line contains the name of the team playing at home. The second line contains the name of the team playing away. Both lines are not empty. The lengths of both lines do not exceed 20. Each line contains only of large English letters. The names of the teams are distinct.
Next follows number *n* (1<=≤<=*n*<=≤<=9... | For each event when a player received his first red card in a chronological order print a string containing the following information:
- The name of the team to which the player belongs; - the player's number in his team; - the minute when he received the card.
If no player received a card, then you do not need to... | [
"MC\nCSKA\n9\n28 a 3 y\n62 h 25 y\n66 h 42 y\n70 h 25 y\n77 a 4 y\n79 a 25 y\n82 h 42 r\n89 h 16 y\n90 a 13 r\n"
] | [
"MC 25 70\nMC 42 82\nCSKA 13 90\n"
] | none | 500 | [
{
"input": "MC\nCSKA\n9\n28 a 3 y\n62 h 25 y\n66 h 42 y\n70 h 25 y\n77 a 4 y\n79 a 25 y\n82 h 42 r\n89 h 16 y\n90 a 13 r",
"output": "MC 25 70\nMC 42 82\nCSKA 13 90"
},
{
"input": "REAL\nBARCA\n3\n27 h 7 y\n44 a 10 y\n87 h 3 r",
"output": "REAL 3 87"
},
{
"input": "MASFF\nSAFBDSRG\n5\n1 ... | 1,417,625,759 | 6,959 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 46 | 0 | a = input()
b = input()
i = int(input())
c = []
r = []
y = []
for z in range(0, i, 1):
c.append(input())
if (c[z][-1] == "y"):
if (c[z][:6] in y):
r.append(c[:6])
else:
y.append(c[:6])
elif (c[z][-1] == "r"):
r.append(c[:6])
for z in range(0, len(r), 1):
f... | Title: Vasya and Football
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has started watching football games. He has learned that for some fouls the players receive yellow cards, and for some fouls they receive red cards. A player who receives the second yellow card automatically re... | ```python
a = input()
b = input()
i = int(input())
c = []
r = []
y = []
for z in range(0, i, 1):
c.append(input())
if (c[z][-1] == "y"):
if (c[z][:6] in y):
r.append(c[:6])
else:
y.append(c[:6])
elif (c[z][-1] == "r"):
r.append(c[:6])
for z in range(0, len(r),... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,593,182,333 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 6,758,400 | s = list(input())
word = ['h', 'e', 'l', 'l', 'o']
c = 0
l = len(s)
for i in range(l):
if s[i] == word[c]:
c += 1
if c == len(word):
print("YES")
exit(0)
else:
continue
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = list(input())
word = ['h', 'e', 'l', 'l', 'o']
c = 0
l = len(s)
for i in range(l):
if s[i] == word[c]:
c += 1
if c == len(word):
print("YES")
exit(0)
else:
continue
print("NO")
``` | 3.932911 | MatrixStudio/Codeforces-Python-Submissions |
667 | A | Pouring Rain | PROGRAMMING | 1,100 | [
"geometry",
"math"
] | null | null | A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.
Today everything ... | The only line of the input contains four integer numbers *d*,<=*h*,<=*v*,<=*e* (1<=≤<=*d*,<=*h*,<=*v*,<=*e*<=≤<=104), where:
- *d* — the diameter of your cylindrical cup, - *h* — the initial level of water in the cup, - *v* — the speed of drinking process from the cup in milliliters per second, - *e* — the growth ... | If it is impossible to make the cup empty, print "NO" (without quotes).
Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=4. It is... | [
"1 2 3 100\n",
"1 1 1 1\n"
] | [
"NO\n",
"YES\n3.659792366325\n"
] | In the first example the water fills the cup faster than you can drink from it.
In the second example area of the cup's bottom equals to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/419dc74dcd7bc392019c9fe748fe1fdb08ab521a.png" style="max-width: 100.0%;max-height: 100.0%;"/>, thus we ca... | 500 | [
{
"input": "1 2 3 100",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "YES\n3.659792366325"
},
{
"input": "48 7946 7992 72",
"output": "NO"
},
{
"input": "72 6791 8546 46",
"output": "NO"
},
{
"input": "100 5635 9099 23",
"output": "NO"
},
{
"input... | 1,609,149,740 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 139 | 0 | from math import pi
d,h,v,e = list(map(int, input().split()))
a = (d**2 / 4)*pi*h
if (1/a >= 1):
print("YES")
print(1 / (1/a - 1))
else:
print("NO") | Title: Pouring Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, cont... | ```python
from math import pi
d,h,v,e = list(map(int, input().split()))
a = (d**2 / 4)*pi*h
if (1/a >= 1):
print("YES")
print(1 / (1/a - 1))
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the numb... | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,663,958,633 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 343 | 7,475,200 | l = []
n = int(input())
for i in range(n):
l.append(tuple(map(int, input().split())))
l.sort()
flag = False
for i in range(n-1):
if l[i][0] <= l[i+1][0] and l[i][1] > l[i+1][1]:
flag = True
break
if(flag):
print("Happy Alex")
else:
print("Poor Alex") | Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the... | ```python
l = []
n = int(input())
for i in range(n):
l.append(tuple(map(int, input().split())))
l.sort()
flag = False
for i in range(n-1):
if l[i][0] <= l[i+1][0] and l[i][1] > l[i+1][1]:
flag = True
break
if(flag):
print("Happy Alex")
else:
print("Poor Alex")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
727 | A | Transformation: from A to B | PROGRAMMING | 1,000 | [
"brute force",
"dfs and similar",
"math"
] | null | null | Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - append the digit 1 to the right of current number (that is, replace the number *x* by 10·*x*<=+<=1).
You need to he... | The first line contains two positive integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=109) — the number which Vasily has and the number he wants to have. | If there is no way to get *b* from *a*, print "NO" (without quotes).
Otherwise print three lines. On the first line print "YES" (without quotes). The second line should contain single integer *k* — the length of the transformation sequence. On the third line print the sequence of transformations *x*1,<=*x*2,<=...,<=*x... | [
"2 162\n",
"4 42\n",
"100 40021\n"
] | [
"YES\n5\n2 4 8 81 162 \n",
"NO\n",
"YES\n5\n100 200 2001 4002 40021 \n"
] | none | 1,000 | [
{
"input": "2 162",
"output": "YES\n5\n2 4 8 81 162 "
},
{
"input": "4 42",
"output": "NO"
},
{
"input": "100 40021",
"output": "YES\n5\n100 200 2001 4002 40021 "
},
{
"input": "1 111111111",
"output": "YES\n9\n1 11 111 1111 11111 111111 1111111 11111111 111111111 "
},
... | 1,588,518,826 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | a=int(input())
k=int(input())
b=k
arr=[]
while b>=a:
if b%2==0:
b/=2
arr+=[round(b)]
if b%10==1:
b//=10
arr+=[round(b)]
if b==a:
print("YES")
print(len(arr)+1)
print(arr[::-1]+[k])
else: print("NO")
| Title: Transformation: from A to B
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - app... | ```python
a=int(input())
k=int(input())
b=k
arr=[]
while b>=a:
if b%2==0:
b/=2
arr+=[round(b)]
if b%10==1:
b//=10
arr+=[round(b)]
if b==a:
print("YES")
print(len(arr)+1)
print(arr[::-1]+[k])
else: print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
252 | A | Little Xor | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Petya likes arrays that consist of non-negative integers a lot. Recently his mom has presented him one such array consisting of *n* elements. Petya immediately decided to find there a segment of consecutive elements, such that the *xor* of all numbers from this segment was maximal possible. Help him with that.
... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains the space-separated integers from the array. All numbers are non-negative integers strictly less than 230. | Print a single integer — the required maximal *xor* of a segment of consecutive elements. | [
"5\n1 2 1 1 2\n",
"3\n1 2 7\n",
"4\n4 2 4 8\n"
] | [
"3\n",
"7\n",
"14\n"
] | In the first sample one of the optimal segments is the segment that consists of the first and the second array elements, if we consider the array elements indexed starting from one.
The second sample contains only one optimal segment, which contains exactly one array element (element with index three). | 500 | [
{
"input": "5\n1 2 1 1 2",
"output": "3"
},
{
"input": "3\n1 2 7",
"output": "7"
},
{
"input": "4\n4 2 4 8",
"output": "14"
},
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "16\n0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15",
"output": "15"
},
{
"inpu... | 1,621,881,671 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 186 | 0 | n=int(input())
l=list(map(int,input().split()))
an=0
for i in range(len(l)):
for j in range(i,len(l)):
x=0
for k in range(i,j+1):
x=x^l[k]
an=max(x,an)
print(an) | Title: Little Xor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes arrays that consist of non-negative integers a lot. Recently his mom has presented him one such array consisting of *n* elements. Petya immediately decided to find there a segment of consecutive elements, ... | ```python
n=int(input())
l=list(map(int,input().split()))
an=0
for i in range(len(l)):
for j in range(i,len(l)):
x=0
for k in range(i,j+1):
x=x^l[k]
an=max(x,an)
print(an)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
465 | B | Inbox (100500) | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of letters in the mailbox.
The second line contains *n* space-separated integers (zeros and ones) — the state of the letter list. The *i*-th number equals either 1, if the *i*-th number is unread, or 0, if the *i*-th letter is read. | Print a single number — the minimum number of operations needed to make all the letters read. | [
"5\n0 1 0 1 0\n",
"5\n1 1 0 0 1\n",
"2\n0 0\n"
] | [
"3\n",
"4\n",
"0\n"
] | In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already... | 1,000 | [
{
"input": "5\n0 1 0 1 0",
"output": "3"
},
{
"input": "5\n1 1 0 0 1",
"output": "4"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "9\n1 0 1 0 1 0 1 0 1",
"output": "9"
},
{
"input": "5\n1 1 1 1 1",
"output": "5"
},
{
"input": "14\n0 0 1 1 1 0 1 ... | 1,679,071,232 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 46 | 0 | n = input()
numbers = input()
firstUnreadSaw = False
numOperations = 0
numbersList = numbers.split()
for i in range(int(n)):
if numbersList[i] == '1' and not firstUnreadSaw:
numOperations+=1
firstUnreadSaw = True
elif numbersList[i] == '1' and firstUnreadSaw and numbersList[i-1] != '0':
... | Title: Inbox (100500)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soo... | ```python
n = input()
numbers = input()
firstUnreadSaw = False
numOperations = 0
numbersList = numbers.split()
for i in range(int(n)):
if numbersList[i] == '1' and not firstUnreadSaw:
numOperations+=1
firstUnreadSaw = True
elif numbersList[i] == '1' and firstUnreadSaw and numbersList[i-1] != '... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,688,344,036 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | [n, m] = list(map(int, input().split()))
l = list(map(int, input().split()))
count = 0
i = 0
while count < m:
count += l[i]
i+=1
if count>m:
i-=1
print(i+1) | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
[n, m] = list(map(int, input().split()))
l = list(map(int, input().split()))
count = 0
i = 0
while count < m:
count += l[i]
i+=1
if count>m:
i-=1
print(i+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
679 | A | Bear and Prime 100 | PROGRAMMING | 1,400 | [
"constructive algorithms",
"interactive",
"math"
] | null | null | This is an interactive problem. In the output section below you will see the information about flushing the output.
Bear Limak thinks of some hidden number — an integer from interval [2,<=100]. Your task is to say if the hidden number is prime or composite.
Integer *x*<=><=1 is called prime if it has exactly two d... | After each query you should read one string from the input. It will be "yes" if the printed integer is a divisor of the hidden number, and "no" otherwise. | Up to 20 times you can ask a query — print an integer from interval [2,<=100] in one line. You have to both print the end-of-line character and flush the output. After flushing you should read a response from the input.
In any moment you can print the answer "prime" or "composite" (without the quotes). After that, flu... | [
"yes\nno\nyes\n",
"no\nyes\nno\nno\nno\n"
] | [
"2\n80\n5\ncomposite\n",
"58\n59\n78\n78\n2\nprime\n"
] | The hidden number in the first query is 30. In a table below you can see a better form of the provided example of the communication process.
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ea790051c34ea7d2761cd9b096412ca7c647a173.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The hi... | 750 | [
{
"input": "30",
"output": "composite 4"
},
{
"input": "59",
"output": "prime 15"
},
{
"input": "2",
"output": "prime 16"
},
{
"input": "7",
"output": "prime 16"
},
{
"input": "9",
"output": "composite 3"
},
{
"input": "13",
"output": "prime 15"
... | 1,633,163,555 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 77 | 0 | import sys
resp = list()
num = [2,3,5,7,4,9,25,49,11,13,17,19,23,29,31,37,41,43,47,53]
for i in num:
print(i)
sys.stdout.flush()
resp.append(input())
if resp.count("yes") <= 1:
print("prime")
sys.stdout.flush()
else:
print("composite")
sys.stdout.flush() | Title: Bear and Prime 100
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This is an interactive problem. In the output section below you will see the information about flushing the output.
Bear Limak thinks of some hidden number — an integer from interval [2,<=100]. Your task is to say i... | ```python
import sys
resp = list()
num = [2,3,5,7,4,9,25,49,11,13,17,19,23,29,31,37,41,43,47,53]
for i in num:
print(i)
sys.stdout.flush()
resp.append(input())
if resp.count("yes") <= 1:
print("prime")
sys.stdout.flush()
else:
print("composite")
sys.stdout.flush()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,663,710,695 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 122 | 0 | x=list(map(int,input().split()))
s=x[0]*x[1]
print(s//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
x=list(map(int,input().split()))
s=x[0]*x[1]
print(s//2)
``` | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
366 | B | Dima and To-do List | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything he does in her presence. After Inna tells him off for something, she goes to another room, walks there in ... | The first line of the input contains two integers *n*,<=*k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103), where *a**i* is the power Inna tells Dima off with if she is present in the room while he is doing the *i*-th task.
It is guaranteed that *n*... | In a single line print the number of the task Dima should start with to get told off with as little power as possible. If there are multiple solutions, print the one with the minimum number of the first task to do. | [
"6 2\n3 2 1 6 5 4\n",
"10 5\n1 3 5 7 9 9 4 1 8 5\n"
] | [
"1\n",
"3\n"
] | Explanation of the first example.
If Dima starts from the first task, Inna tells him off with power 3, then Dima can do one more task (as *k* = 2), then Inna tells him off for the third task with power 1, then she tells him off for the fifth task with power 5. Thus, Dima gets told off with total power 3 + 1 + 5 = 9. I... | 1,000 | [
{
"input": "6 2\n3 2 1 6 5 4",
"output": "1"
},
{
"input": "10 5\n1 3 5 7 9 9 4 1 8 5",
"output": "3"
},
{
"input": "20 4\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "10 10\n8 4 5 7 6 9 2 2 3 5",
"output": "7"
},
{
"input": "50 10\n1 2 3... | 1,693,420,131 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print('xxxxxx') | Title: Dima and To-do List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything h... | ```python
print('xxxxxx')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,637,147,268 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | a=input()
b="aeioun"
c="bcdfghjklmpqrstvwxyz"
d=len(a)
f=0
for i in range(d):
if i == d-1:
break
else:
if a[i] in c:
if a[i+1] in b:
f="YES"
pass
else:
f="NO"
break
if f=="YES":
print... | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
a=input()
b="aeioun"
c="bcdfghjklmpqrstvwxyz"
d=len(a)
f=0
for i in range(d):
if i == d-1:
break
else:
if a[i] in c:
if a[i+1] in b:
f="YES"
pass
else:
f="NO"
break
if f=="YES":
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
259 | B | Little Elephant and Magic Square | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals ... | The first three lines of the input contain the Little Elephant's notes. The first line contains elements of the first row of the magic square. The second line contains the elements of the second row, the third line is for the third row. The main diagonal elements that have been forgotten by the Elephant are represented... | Print three lines, in each line print three integers — the Little Elephant's magic square. If there are multiple magic squares, you are allowed to print any of them. Note that all numbers you print must be positive and not exceed 105.
It is guaranteed that there exists at least one magic square that meets the conditio... | [
"0 1 1\n1 0 1\n1 1 0\n",
"0 3 6\n5 0 5\n4 7 0\n"
] | [
"1 1 1\n1 1 1\n1 1 1\n",
"6 3 6\n5 5 5\n4 7 4\n"
] | none | 1,000 | [
{
"input": "0 1 1\n1 0 1\n1 1 0",
"output": "1 1 1\n1 1 1\n1 1 1"
},
{
"input": "0 3 6\n5 0 5\n4 7 0",
"output": "6 3 6\n5 5 5\n4 7 4"
},
{
"input": "0 4 4\n4 0 4\n4 4 0",
"output": "4 4 4\n4 4 4\n4 4 4"
},
{
"input": "0 54 48\n36 0 78\n66 60 0",
"output": "69 54 48\n36 5... | 1,603,861,637 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 218 | 0 | l,q=[0]*3,0
for i in range(3):l[i]=list(map(int,input().split()));q+=sum(l[i])
for i in range(3):l[i][i]=q//2-sum(l[i]);print(*l[i]) | Title: Little Elephant and Magic Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table ... | ```python
l,q=[0]*3,0
for i in range(3):l[i]=list(map(int,input().split()));q+=sum(l[i])
for i in range(3):l[i][i]=q//2-sum(l[i]);print(*l[i])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,658,682,021 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | ($n,$m)=split ' ',<>;
while($m--){
($a,$b)=split ' ',<>;
$h{$a}=length$a>length$b?$b:$a;
}
$_=<>;
s/(\w+)/$h{$1}/eg;
print | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
($n,$m)=split ' ',<>;
while($m--){
($a,$b)=split ' ',<>;
$h{$a}=length$a>length$b?$b:$a;
}
$_=<>;
s/(\w+)/$h{$1}/eg;
print
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,617,091,594 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 77 | 0 | # https://codeforces.com/problemset/problem/802/G
s = input()
prev = 0
final = ""
for i in "heidi":
temp = prev
for j in s[prev:]:
temp += 1
if j == i:
final += i
prev = temp
break
if final == "heidi":
print("YES")
else:
print("NO")
... | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
# https://codeforces.com/problemset/problem/802/G
s = input()
prev = 0
final = ""
for i in "heidi":
temp = prev
for j in s[prev:]:
temp += 1
if j == i:
final += i
prev = temp
break
if final == "heidi":
print("YES")
else:
pr... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,637,511,124 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 154 | 0 | n = int(input())
c_1, c_2 = 0, 0
rez_mass = [[], []]
for x in [*map(int, input().split())]:
if c_1 >= 2 and c_2 != 0:
print(rez_mass[0][0])
break
if c_2 >= 2 and c_1 != 0:
print(rez_mass[1][0])
break
if x % 2:
c_1 += 1
rez_mass[1].append(c_1+... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
c_1, c_2 = 0, 0
rez_mass = [[], []]
for x in [*map(int, input().split())]:
if c_1 >= 2 and c_2 != 0:
print(rez_mass[0][0])
break
if c_2 >= 2 and c_1 != 0:
print(rez_mass[1][0])
break
if x % 2:
c_1 += 1
rez_mass[1].a... | 0 | MatrixStudio/Codeforces-Python-Submissions |
948 | A | Protect Sheep | PROGRAMMING | 900 | [
"brute force",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of *R*<=×<=*C* cells. Each cell is either empty, contains a sheep, a wolf or... | First line contains two integers *R* (1<=≤<=*R*<=≤<=500) and *C* (1<=≤<=*C*<=≤<=500), denoting the number of rows and the numbers of columns respectively.
Each of the following *R* lines is a string consisting of exactly *C* characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' a... | If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print *R* lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a she... | [
"6 6\n..S...\n..S.W.\n.S....\n..W...\n...W..\n......\n",
"1 2\nSW\n",
"5 5\n.S...\n...S.\nS....\n...S.\n.S...\n"
] | [
"Yes\n..SD..\n..SDW.\n.SD...\n.DW...\nDD.W..\n......\n",
"No\n",
"Yes\n.S...\n...S.\nS.D..\n...S.\n.S...\n"
] | In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves... | 500 | [
{
"input": "1 2\nSW",
"output": "No"
},
{
"input": "10 10\n....W.W.W.\n.........S\n.S.S...S..\nW.......SS\n.W..W.....\n.W...W....\nS..S...S.S\n....W...S.\n..S..S.S.S\nSS.......S",
"output": "Yes\nDDDDWDWDWD\nDDDDDDDDDS\nDSDSDDDSDD\nWDDDDDDDSS\nDWDDWDDDDD\nDWDDDWDDDD\nSDDSDDDSDS\nDDDDWDDDSD\nDDSD... | 1,680,897,390 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | rows,cols=list(map(int,input().split()))
grid=[]
def can(r,c):
return r>=0 and c>=0 and r<rows and c<cols
for i in range(rows):
row=input()
grid.append(list(row))
# print(grid)
flag=False
for r in range(rows):
for c in range(cols):
if grid[r][c]=='S':
if (can(r+1,c)... | Title: Protect Sheep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is ... | ```python
rows,cols=list(map(int,input().split()))
grid=[]
def can(r,c):
return r>=0 and c>=0 and r<rows and c<cols
for i in range(rows):
row=input()
grid.append(list(row))
# print(grid)
flag=False
for r in range(rows):
for c in range(cols):
if grid[r][c]=='S':
if (... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
158 | A | Next Round | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | "Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* participants took part in the contest (*n*<=≥<=*k*), and you already know their scores. Calculate... | The first line of the input contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50) separated by a single space.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the score earned by the participant who got the *i*-th place. The given sequence... | Output the number of participants who advance to the next round. | [
"8 5\n10 9 8 7 7 7 5 5\n",
"4 2\n0 0 0 0\n"
] | [
"6\n",
"0\n"
] | In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score. | 500 | [
{
"input": "8 5\n10 9 8 7 7 7 5 5",
"output": "6"
},
{
"input": "4 2\n0 0 0 0",
"output": "0"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "5 5\n1 1 1 1 1",
"output": "5"
},
{
"input": "1 1\n10",
"output": "1"
},
{
"input": "17 14\n16 15... | 1,697,190,470 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n,k = input().split()
n_int = input().split()
v=0
for i in n_int:
if int(i)>int(k):
v+=1
print(v)
| Title: Next Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Contestant who earns a score equal to or greater than the *k*-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of *n* p... | ```python
n,k = input().split()
n_int = input().split()
v=0
for i in n_int:
if int(i)>int(k):
v+=1
print(v)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
914 | B | Conan and Agasa play a Card Game | PROGRAMMING | 1,200 | [
"games",
"greedy",
"implementation"
] | null | null | Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has *n* cards, and the *i*-th card has a number *a**i* written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he remov... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of cards Conan has.
The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105), where *a**i* is the number on the *i*-th card. | If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes). | [
"3\n4 5 7\n",
"2\n1 1\n"
] | [
"Conan\n",
"Agasa\n"
] | In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it... | 1,000 | [
{
"input": "3\n4 5 7",
"output": "Conan"
},
{
"input": "2\n1 1",
"output": "Agasa"
},
{
"input": "10\n38282 53699 38282 38282 38282 38282 38282 38282 38282 38282",
"output": "Conan"
},
{
"input": "10\n50165 50165 50165 50165 50165 50165 50165 50165 50165 50165",
"output":... | 1,654,755,584 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 7,680,000 | n=int(input())
q=0
c=[0]*100000
a=list(map(int, input().split()))
if n%2==1:
print("Conan")
else:
for i in range(n):
if c[a[i]]==0:
if a.count(i)%2==1:
q=1
c[a[i]]=1
if q==1:
print("Conan")
else:
print("Agasa") | Title: Conan and Agasa play a Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has *n* cards, and the *i*-th card has a number *a**i* written on it.... | ```python
n=int(input())
q=0
c=[0]*100000
a=list(map(int, input().split()))
if n%2==1:
print("Conan")
else:
for i in range(n):
if c[a[i]]==0:
if a.count(i)%2==1:
q=1
c[a[i]]=1
if q==1:
print("Conan")
else:
print("Agasa")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,667,385,150 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 46 | 0 | x,y = map(int, input().split())
def solve():
for i in range(x):
l= input().split()
for i in l:
if i == "C" or i== "M" or i== "Y":
return "#Color"
return "#Black&White"
print(solve()) | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
x,y = map(int, input().split())
def solve():
for i in range(x):
l= input().split()
for i in l:
if i == "C" or i== "M" or i== "Y":
return "#Color"
return "#Black&White"
print(solve())
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
846 | C | Four Segments | PROGRAMMING | 1,800 | [
"brute force",
"data structures",
"dp"
] | null | null | You are given an array of *n* integer numbers. Let *sum*(*l*,<=*r*) be the sum of all numbers on positions from *l* to *r* non-inclusive (*l*-th element is counted, *r*-th element is not counted). For indices *l* and *r* holds 0<=≤<=*l*<=≤<=*r*<=≤<=*n*. Indices in array are numbered from 0.
For example, if *a*<==<=[<... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=5000).
The second line contains *n* numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1 (<=-<=109<=≤<=*a**i*<=≤<=109). | Choose three indices so that the value of *res* is maximal. If there are multiple answers, print any of them. | [
"3\n-1 2 3\n",
"4\n0 0 -1 0\n",
"1\n10000\n"
] | [
"0 1 3\n",
"0 0 0\n",
"1 1 1\n"
] | none | 0 | [
{
"input": "3\n-1 2 3",
"output": "0 1 3"
},
{
"input": "4\n0 0 -1 0",
"output": "0 0 0"
},
{
"input": "1\n10000",
"output": "0 0 1"
},
{
"input": "1\n-1",
"output": "0 0 0"
},
{
"input": "1\n0",
"output": "0 0 0"
},
{
"input": "10\n0 0 0 0 0 0 0 0 0 0... | 1,505,063,090 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
long long arr[5003];
int n;
long long sm(int a, int b) {
if( a == b) return 0;
if (a == 0) return arr[b-1];
if (a >= n) return 0;
return arr[b-1] - arr[a-1];
}
int check(int a, int b, long long &mx) {
if( a == b) {
mx = 0;
return a;
... | Title: Four Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array of *n* integer numbers. Let *sum*(*l*,<=*r*) be the sum of all numbers on positions from *l* to *r* non-inclusive (*l*-th element is counted, *r*-th element is not counted). For indices *l* and *r* ... | ```python
#include <bits/stdc++.h>
using namespace std;
long long arr[5003];
int n;
long long sm(int a, int b) {
if( a == b) return 0;
if (a == 0) return arr[b-1];
if (a >= n) return 0;
return arr[b-1] - arr[a-1];
}
int check(int a, int b, long long &mx) {
if( a == b) {
mx = 0;
retu... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,688,132,690 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 106 | 77 | 1,536,000 | n,k = input().split()
n=int(n)
k=int(k)
a = list(map(int,input().split()))
sum = sum(a)
p = sum/n
ini=n
while p<(k-0.5):
sum+=k
n+=1
p = sum/n
print(n-ini) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
n,k = input().split()
n=int(n)
k=int(k)
a = list(map(int,input().split()))
sum = sum(a)
p = sum/n
ini=n
while p<(k-0.5):
sum+=k
n+=1
p = sum/n
print(n-ini)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,691,377,997 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 62 | 0 | a=list(map(int,input().split()))
b=list(map(int,input().split()))
b.sort()
asd=2*max(b[0],a[1]-b[-1])
for i in range(1,a[0]):
asd=max(asd,b[i]-b[i-1])
print(asd/2) | Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
a=list(map(int,input().split()))
b=list(map(int,input().split()))
b.sort()
asd=2*max(b[0],a[1]-b[-1])
for i in range(1,a[0]):
asd=max(asd,b[i]-b[i-1])
print(asd/2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,623,316,209 | 2,147,483,647 | PyPy 3 | OK | TESTS | 21 | 92 | 0 | n=int(input())
s={x for x in input().split() if x!='0'}
print(len(s))
| Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n=int(input())
s={x for x in input().split() if x!='0'}
print(len(s))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
877 | B | Nikita and string | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | null | null | One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st and the 3-rd one contain only letters "a" and the 2-nd contains only letters "b".
Nikita wants to make... | The first line contains a non-empty string of length not greater than 5<=000 containing only lowercase English letters "a" and "b". | Print a single integer — the maximum possible size of beautiful string Nikita can get. | [
"abba\n",
"bab\n"
] | [
"4",
"2"
] | It the first sample the string is already beautiful.
In the second sample he needs to delete one of "b" to make it beautiful. | 1,000 | [
{
"input": "abba",
"output": "4"
},
{
"input": "bab",
"output": "2"
},
{
"input": "bbabbbaabbbb",
"output": "9"
},
{
"input": "bbabbbbbaaba",
"output": "10"
},
{
"input": "bbabbbababaa",
"output": "9"
},
{
"input": "aabbaababbab",
"output": "8"
}... | 1,592,617,200 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 307,200 | s = input()
a_count = s.count('a')
b_count = len(s) - a_count
a_counts = [0] * len(s)
b_counts = [0] * len(s)
for i in range(len(s)):
if s[i] == 'a':
a_counts[i] = 1
else:
b_counts[i] = 1
if i > 0:
a_counts[i] += a_counts[i - 1]
b_counts[i] += b_counts[i - 1]
best = 0
count = 0
fo... | Title: Nikita and string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st ... | ```python
s = input()
a_count = s.count('a')
b_count = len(s) - a_count
a_counts = [0] * len(s)
b_counts = [0] * len(s)
for i in range(len(s)):
if s[i] == 'a':
a_counts[i] = 1
else:
b_counts[i] = 1
if i > 0:
a_counts[i] += a_counts[i - 1]
b_counts[i] += b_counts[i - 1]
best = 0
cou... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
183 | A | Headquarters | PROGRAMMING | 1,700 | [
"constructive algorithms",
"math"
] | null | null | Sensation, sensation in the two-dimensional kingdom! The police have caught a highly dangerous outlaw, member of the notorious "Pihters" gang. The law department states that the outlaw was driving from the gang's headquarters in his car when he crashed into an ice cream stall. The stall, the car, and the headquarters e... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of the car's movements from the headquarters to the stall.
Each of the following *n* lines describes the car's possible movements. It is guaranteed that each possible movement is one of the following strings: "UL", "UR", "DL", "DR" or "ULD... | Print a single integer — the number of different possible locations of the gang's headquarters. | [
"3\nUR\nUL\nULDR\n",
"2\nDR\nDL\n"
] | [
"9\n",
"4\n"
] | The figure below shows the nine possible positions of the gang headquarters from the first sample:
For example, the following movements can get the car from point (1, 0) to point (0, 0): | 500 | [
{
"input": "3\nUR\nUL\nULDR",
"output": "9"
},
{
"input": "2\nDR\nDL",
"output": "4"
},
{
"input": "4\nUL\nUR\nDR\nDL",
"output": "9"
},
{
"input": "10\nUL\nUL\nUL\nUL\nUL\nUL\nUL\nUL\nUL\nUL",
"output": "11"
},
{
"input": "6\nUL\nDL\nDL\nUL\nUL\nDL",
"output"... | 1,690,499,343 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1690499343.5681386")# 1690499343.5681581 | Title: Headquarters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sensation, sensation in the two-dimensional kingdom! The police have caught a highly dangerous outlaw, member of the notorious "Pihters" gang. The law department states that the outlaw was driving from the gang's headquart... | ```python
print("_RANDOM_GUESS_1690499343.5681386")# 1690499343.5681581
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Tachibana Kanade likes Mapo Tofu very much. One day, the canteen cooked all kinds of tofu to sell, but not all tofu is Mapo Tofu, only those spicy enough can be called Mapo Tofu.
Each piece of tofu in the canteen is given a *m*-based number, all numbers are in the range [*l*,<=*r*] (*l* and *r* being *m*-based numbers... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=200; 2<=≤<=*m*<=≤<=20; 1<=≤<=*k*<=≤<=500). Where *n* denotes the number of strings, *m* denotes the base used, and *k* denotes the limit of the value for Mapo Tofu.
The second line represents the number *l*. The first integer in the line is *len* (... | Output the number of pieces of Mapo Tofu modulo 1000000007 (109<=+<=7). The answer should be a decimal integer. | [
"2 10 1\n1 1\n3 1 0 0\n1 1 1\n1 0 1\n",
"2 10 12\n2 5 9\n6 6 3 5 4 9 7\n2 0 6 1\n3 6 7 2 1\n",
"4 2 6\n6 1 0 1 1 1 0\n6 1 1 0 1 0 0\n1 1 2\n3 0 1 0 5\n4 0 1 1 0 4\n3 1 0 1 2\n"
] | [
"97\n",
"635439\n",
"2\n"
] | In the first sample, 10, 11 and 100 are the only three decimal numbers in [1, 100] with a value greater than 1. Here the value of 1 is 1 but not 2, since numbers cannot contain leading zeros and thus cannot be written as "01".
In the second sample, no numbers in the given interval have a value greater than 12.
In the... | 0 | [] | 1,689,424,433 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | print("_RANDOM_GUESS_1689424433.3142822")# 1689424433.314302 | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tachibana Kanade likes Mapo Tofu very much. One day, the canteen cooked all kinds of tofu to sell, but not all tofu is Mapo Tofu, only those spicy enough can be called Mapo Tofu.
Each piece of tofu in the canteen is given a *m*-b... | ```python
print("_RANDOM_GUESS_1689424433.3142822")# 1689424433.314302
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,662,023,811 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | from math import factorial
n,m = list(map(int,input().split()))
if n>m:
n = m
print(int(factorial(n)))
| Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
from math import factorial
n,m = list(map(int,input().split()))
if n>m:
n = m
print(int(factorial(n)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,699,160,766 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 93 | 0 | k, r = map(int,input().split())
s = k
ans = 1
while not (s % 10 == 0 or s % 10 == r):
s += k
ans += 1
print(ans)
| Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
k, r = map(int,input().split())
s = k
ans = 1
while not (s % 10 == 0 or s % 10 == r):
s += k
ans += 1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,636,899,560 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n,m = map(int,input().split())
ans = n * m
b = 0
for i in range(1,n+1):
s = input()
b += s.count('S')
a = ans - (b * b)
if (a < 0):
print(0)
else:
print(a) | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
n,m = map(int,input().split())
ans = n * m
b = 0
for i in range(1,n+1):
s = input()
b += s.count('S')
a = ans - (b * b)
if (a < 0):
print(0)
else:
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,646,464,463 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | a, b = map(int, input().split())
count = 0
while a >= b:
used = a - a%b
count += used
a -= used - used//b
print(count + a) | Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
a, b = map(int, input().split())
count = 0
while a >= b:
used = a - a%b
count += used
a -= used - used//b
print(count + a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,697,231,706 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 614,400 | n = int(input())
k = list(map(int, input().split()))
arama_elemanlari = [1, 2, 3]
y = []
for eleman in arama_elemanlari:
indeksler = [i+1 for i, x in enumerate(k) if x == eleman]
y.append(indeksler)
a = len(y[0])
b = len(y[1])
c = len(y[2])
total = []
result = 0
for i in range(min(a,... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n = int(input())
k = list(map(int, input().split()))
arama_elemanlari = [1, 2, 3]
y = []
for eleman in arama_elemanlari:
indeksler = [i+1 for i, x in enumerate(k) if x == eleman]
y.append(indeksler)
a = len(y[0])
b = len(y[1])
c = len(y[2])
total = []
result = 0
for i in ra... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
424 | A | Squats | PROGRAMMING | 900 | [
"implementation"
] | null | null | Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to stand up and the other hamsters to sit down. In one minute, Pasha can make some hamster ethe... | The first line contains integer *n* (2<=≤<=*n*<=≤<=200; *n* is even). The next line contains *n* characters without spaces. These characters describe the hamsters' position: the *i*-th character equals 'X', if the *i*-th hamster in the row is standing, and 'x', if he is sitting. | In the first line, print a single integer — the minimum required number of minutes. In the second line, print a string that describes the hamsters' position after Pasha makes the required changes. If there are multiple optimal positions, print any of them. | [
"4\nxxXx\n",
"2\nXX\n",
"6\nxXXxXx\n"
] | [
"1\nXxXx\n",
"1\nxX\n",
"0\nxXXxXx\n"
] | none | 500 | [
{
"input": "4\nxxXx",
"output": "1\nXxXx"
},
{
"input": "2\nXX",
"output": "1\nxX"
},
{
"input": "6\nxXXxXx",
"output": "0\nxXXxXx"
},
{
"input": "4\nxXXX",
"output": "1\nxxXX"
},
{
"input": "2\nXx",
"output": "0\nXx"
},
{
"input": "22\nXXxXXxxXxXxXXXX... | 1,681,137,057 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n = int(input())
s = input()
sumx = s.count('x')
print(abs(n//2-sumx))
for i in range(abs(n//2-sumx)):
if sumx > n-sumx:
s = s.replace('x', 'X', 1)
sumx -= 1
else:
s = s.replace('X', 'x', 1)
sumx += 1
print(s)
| Title: Squats
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to ... | ```python
n = int(input())
s = input()
sumx = s.count('x')
print(abs(n//2-sumx))
for i in range(abs(n//2-sumx)):
if sumx > n-sumx:
s = s.replace('x', 'X', 1)
sumx -= 1
else:
s = s.replace('X', 'x', 1)
sumx += 1
print(s)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,591,950,685 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 109 | 0 | n,x=map(int,input().split())
d=0
for i in range(n):
am,c=input().split()
if(am=='+'):
x+=int(c)
else:
if(x>=int(c)):
x-=int(c)
else:
d+=1
print(x,end=" ")
print(d) | Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n,x=map(int,input().split())
d=0
for i in range(n):
am,c=input().split()
if(am=='+'):
x+=int(c)
else:
if(x>=int(c)):
x-=int(c)
else:
d+=1
print(x,end=" ")
print(d)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
47 | B | Coins | PROGRAMMING | 1,200 | [
"implementation"
] | B. Coins | 2 | 256 | One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. Vasya weighed all the three pairs of coins on pan balance scales and told you the resul... | The input data contains the results of all the weighting, one result on each line. It is guaranteed that every coin pair was weighted exactly once. Vasya labelled the coins with letters «A», «B» and «C». Each result is a line that appears as (letter)(> or < sign)(letter). For example, if coin "A" proved lighter t... | It the results are contradictory, print Impossible. Otherwise, print without spaces the rearrangement of letters «A», «B» and «C» which represent the coins in the increasing order of their weights. | [
"A>B\nC<B\nA>C\n",
"A<B\nB>C\nC>A\n"
] | [
"CBA",
"ACB"
] | none | 1,000 | [
{
"input": "A>B\nC<B\nA>C",
"output": "CBA"
},
{
"input": "A<B\nB>C\nC>A",
"output": "ACB"
},
{
"input": "A<C\nB<A\nB>C",
"output": "Impossible"
},
{
"input": "A<B\nA<C\nB>C",
"output": "ACB"
},
{
"input": "B>A\nC<B\nC>A",
"output": "ACB"
},
{
"input":... | 1,610,188,391 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 248 | 409,600 | from collections import defaultdict as dd
from collections import deque
import bisect
import heapq
def ri():
return int(input())
def rl():
return list(map(int, input().split()))
miniset = {"A", "B", "C"}
maxiset = {"A", "B", "C"}
for i in range(3):
line = input()
small = line[0]
big = line[2]
orderi... | Title: Coins
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya came across three Berland coins. They didn't have any numbers that's why Vasya didn't understand how their denominations differ. He supposed that if one coin is heavier than the other one, then it should be worth more. ... | ```python
from collections import defaultdict as dd
from collections import deque
import bisect
import heapq
def ri():
return int(input())
def rl():
return list(map(int, input().split()))
miniset = {"A", "B", "C"}
maxiset = {"A", "B", "C"}
for i in range(3):
line = input()
small = line[0]
big = line[... | 3.937237 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,458,746,741 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 4,608,000 | s,u,l=input(),0,0
for e in s:
if e.isupper==True:
u+=1
else:
l+=1
if u>l:
s=s.upper()
else:
s=s.lower()
print(s) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s,u,l=input(),0,0
for e in s:
if e.isupper==True:
u+=1
else:
l+=1
if u>l:
s=s.upper()
else:
s=s.lower()
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
753 | A | Santa Claus and Candies | PROGRAMMING | 1,000 | [
"dp",
"greedy",
"math"
] | null | null | Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all *n* candies he has. | The only line contains positive integer number *n* (1<=≤<=*n*<=≤<=1000) — number of candies Santa Claus has. | Print to the first line integer number *k* — maximal number of kids which can get candies.
Print to the second line *k* distinct integer numbers: number of candies for each of *k* kid. The sum of *k* printed numbers should be exactly *n*.
If there are many solutions, print any of them. | [
"5\n",
"9\n",
"2\n"
] | [
"2\n2 3\n",
"3\n3 5 1\n",
"1\n2 \n"
] | none | 500 | [
{
"input": "5",
"output": "2\n1 4 "
},
{
"input": "9",
"output": "3\n1 2 6 "
},
{
"input": "2",
"output": "1\n2 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "3",
"output": "2\n1 2 "
},
{
"input": "1000",
"output": "44\n1 2 3 4 5 6 7 8 9 10 ... | 1,569,904,272 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 187 | 102,400 | import math
class Solution(object):
def __init__(self):
pass
def sol(self, n):
return self.sum(n, 1)
def sum(self, n, k):
if n == 0:
return []
if n < 0 and n < k:
return None
for i in range(k, n + 1):
r = self.sum(n - i, i + 1)
... | Title: Santa Claus and Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus has *n* candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer n... | ```python
import math
class Solution(object):
def __init__(self):
pass
def sol(self, n):
return self.sum(n, 1)
def sum(self, n, k):
if n == 0:
return []
if n < 0 and n < k:
return None
for i in range(k, n + 1):
r = self.sum(n - ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,653,557,186 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 61 | 409,600 | import re
n = int(input())
s = input().split(' ')
count = lambda x: len(re.findall(r'[A-Z]', x))
print(max([count(i) for i in s]))
| Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
import re
n = int(input())
s = input().split(' ')
count = lambda x: len(re.findall(r'[A-Z]', x))
print(max([count(i) for i in s]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,672,836,083 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 8 | 92 | 0 | x = input().split()
count, lst = int(x[0]), []
value = 0
for i in range(int(x[1])):
y = input().split()
lst.append([int(y[0]), int(y[1])])
max = 0
while count != 0:
max = 0
maxlst = []
for i in lst:
if (i[1] > max):
max = i[1]
maxlst = i
if count... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
x = input().split()
count, lst = int(x[0]), []
value = 0
for i in range(int(x[1])):
y = input().split()
lst.append([int(y[0]), int(y[1])])
max = 0
while count != 0:
max = 0
maxlst = []
for i in lst:
if (i[1] > max):
max = i[1]
maxlst = i
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
11 | B | Jumping Jack | PROGRAMMING | 1,600 | [
"math"
] | B. Jumping Jack | 1 | 64 | Jack is working on his jumping skills recently. Currently he's located at point zero of the number line. He would like to get to the point *x*. In order to train, he has decided that he'll first jump by only one unit, and each subsequent jump will be exactly one longer than the previous one. He can go either left or ri... | The input data consists of only one integer *x* (<=-<=109<=≤<=*x*<=≤<=109). | Output the minimal number of jumps that Jack requires to reach *x*. | [
"2\n",
"6\n",
"0\n"
] | [
"3\n",
"3\n",
"0\n"
] | none | 0 | [
{
"input": "2",
"output": "3"
},
{
"input": "6",
"output": "3"
},
{
"input": "0",
"output": "0"
},
{
"input": "-1000000000",
"output": "44723"
},
{
"input": "999961560",
"output": "44720"
},
{
"input": "999961561",
"output": "44721"
},
{
"i... | 1,698,392,177 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 186 | 1,228,800 | now = 0
step = 1
ans = 0
x = abs(int(input()))
while x > now or (now - x) % 2 == 1:
ans += 1
now += ans
# 0 1 3 6 10 15 21 28
# 0 1 3 6 10 15 21
print(ans) | Title: Jumping Jack
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Jack is working on his jumping skills recently. Currently he's located at point zero of the number line. He would like to get to the point *x*. In order to train, he has decided that he'll first jump by only one unit, and each ... | ```python
now = 0
step = 1
ans = 0
x = abs(int(input()))
while x > now or (now - x) % 2 == 1:
ans += 1
now += ans
# 0 1 3 6 10 15 21 28
# 0 1 3 6 10 15 21
print(ans)
``` | 3.897845 | MatrixStudio/Codeforces-Python-Submissions |
903 | C | Boxes Packing | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not put into another box; - *j*-th box doesn't contain any other boxes; - box *i* is smaller than box *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=5000) — the number of boxes Mishka has got.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the side length of *i*-th box. | Print the minimum possible number of visible boxes. | [
"3\n1 2 3\n",
"4\n4 2 4 3\n"
] | [
"1\n",
"2\n"
] | In the first example it is possible to put box 1 into box 2, and 2 into 3.
In the second example Mishka can put box 2 into box 3, and box 4 into box 1. | 0 | [
{
"input": "3\n1 2 3",
"output": "1"
},
{
"input": "4\n4 2 4 3",
"output": "2"
},
{
"input": "10\n58 58 58 58 58 58 58 58 58 58",
"output": "10"
},
{
"input": "10\n86 89 89 86 86 89 86 86 89 89",
"output": "5"
},
{
"input": "100\n981 288 186 186 292 876 341 288 98... | 1,595,915,310 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 78 | 6,656,000 | a=int(input())
b=dict()
for i in map(int,input().split()):b[i]=b.get(i,0)+1
z=list(b.values())
s=0
while len(z)>1:
r=z.pop(z.index(min(z)))
r1=z.pop(z.index(max(z)))
s+=r
z+=[r1-r]
print(s+sum(z)) | Title: Boxes Packing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not pu... | ```python
a=int(input())
b=dict()
for i in map(int,input().split()):b[i]=b.get(i,0)+1
z=list(b.values())
s=0
while len(z)>1:
r=z.pop(z.index(min(z)))
r1=z.pop(z.index(max(z)))
s+=r
z+=[r1-r]
print(s+sum(z))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,670,598,335 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 248 | 19,660,800 | def solve():
n = int(input())
a = list(map(int,input().split()))
m = int(input())
b = list(map(int,input().split()))
ans = [0,0]
f = dict()
for i in range(n):
f[a[i]] = i + 1
for i in range(m):
ans[0] += f[b[i]]
ans[1] += n + 1 - f[b[i]]
return ans... | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
def solve():
n = int(input())
a = list(map(int,input().split()))
m = int(input())
b = list(map(int,input().split()))
ans = [0,0]
f = dict()
for i in range(n):
f[a[i]] = i + 1
for i in range(m):
ans[0] += f[b[i]]
ans[1] += n + 1 - f[b[i]]
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
557 | C | Arthur and Table | PROGRAMMING | 1,900 | [
"brute force",
"data structures",
"dp",
"greedy",
"math",
"sortings"
] | null | null | Arthur has bought a beautiful big table into his new flat. When he came home, Arthur noticed that the new table is unstable.
In total the table Arthur bought has *n* legs, the length of the *i*-th leg is *l**i*.
Arthur decided to make the table stable and remove some legs. For each of them Arthur determined number *d... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=105) — the initial number of legs in the table Arthur bought.
The second line of the input contains a sequence of *n* integers *l**i* (1<=≤<=*l**i*<=≤<=105), where *l**i* is equal to the length of the *i*-th leg of the table.
The third line of the input ... | Print a single integer — the minimum number of energy units that Arthur needs to spend in order to make the table stable. | [
"2\n1 5\n3 2\n",
"3\n2 4 4\n1 1 1\n",
"6\n2 2 1 1 3 3\n4 3 5 5 2 1\n"
] | [
"2\n",
"0\n",
"8\n"
] | none | 1,500 | [
{
"input": "2\n1 5\n3 2",
"output": "2"
},
{
"input": "3\n2 4 4\n1 1 1",
"output": "0"
},
{
"input": "6\n2 2 1 1 3 3\n4 3 5 5 2 1",
"output": "8"
},
{
"input": "10\n20 1 15 17 11 2 15 3 16 3\n129 114 183 94 169 16 18 104 49 146",
"output": "652"
},
{
"input": "10\... | 1,435,683,131 | 6,731 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 7 | 1,000 | 12,288,000 | #!/usr/bin/env python3
import math
N = int(input())
L = list(map(int, input().split(' ')))
D = list(map(int, input().split(' ')))
max_cost = 200
lc = list(zip(L, D))
lc.sort()
cost_l = [_lc[1] for _lc in lc]
length_l = [_lc[0] for _lc in lc]
cost_l_prefix = [0]
for i in range(N):
cost_l_prefix += [cost_l_prefix[-... | Title: Arthur and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arthur has bought a beautiful big table into his new flat. When he came home, Arthur noticed that the new table is unstable.
In total the table Arthur bought has *n* legs, the length of the *i*-th leg is *l**i*.
Arth... | ```python
#!/usr/bin/env python3
import math
N = int(input())
L = list(map(int, input().split(' ')))
D = list(map(int, input().split(' ')))
max_cost = 200
lc = list(zip(L, D))
lc.sort()
cost_l = [_lc[1] for _lc in lc]
length_l = [_lc[0] for _lc in lc]
cost_l_prefix = [0]
for i in range(N):
cost_l_prefix += [cost_... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Efim just received his grade for the last test. He studies in a special school and his grade can be equal to any positive decimal fraction. First he got disappointed, as he expected a way more pleasant result. Then, he developed a tricky plan. Each second, he can ask his teacher to round the grade at any place after th... | The first line of the input contains two integers *n* and *t* (1<=≤<=*n*<=≤<=200<=000, 1<=≤<=*t*<=≤<=109) — the length of Efim's grade and the number of seconds till the end of the break respectively.
The second line contains the grade itself. It's guaranteed that the grade is a positive number, containing at least on... | Print the maximum grade that Efim can get in *t* seconds. Do not print trailing zeroes. | [
"6 1\n10.245\n",
"6 2\n10.245\n",
"3 100\n9.2\n"
] | [
"10.25\n",
"10.3\n",
"9.2\n"
] | In the first two samples Efim initially has grade 10.245.
During the first second Efim can obtain grade 10.25, and then 10.3 during the next second. Note, that the answer 10.30 will be considered incorrect.
In the third sample the optimal strategy is to not perform any rounding at all. | 0 | [
{
"input": "6 1\n10.245",
"output": "10.25"
},
{
"input": "6 2\n10.245",
"output": "10.3"
},
{
"input": "3 100\n9.2",
"output": "9.2"
},
{
"input": "12 5\n872.04488525",
"output": "872.1"
},
{
"input": "35 8\n984227318.2031144444444444494637612",
"output": "98... | 1,474,734,766 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n, t = map(int, input().split())
s = str(input())
INF = 10**8
ind = INF
not_find = True
ind1 = s.rfind(".")
if ind != -1:
s1 = s[ind1 :]
for i in range(t):
j = -1
while j + 1 < len(s1) and not_find:
j += 1
if s1[j] in {"5", "6", "7", "8", "9"}:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Efim just received his grade for the last test. He studies in a special school and his grade can be equal to any positive decimal fraction. First he got disappointed, as he expected a way more pleasant result. Then, he developed a... | ```python
n, t = map(int, input().split())
s = str(input())
INF = 10**8
ind = INF
not_find = True
ind1 = s.rfind(".")
if ind != -1:
s1 = s[ind1 :]
for i in range(t):
j = -1
while j + 1 < len(s1) and not_find:
j += 1
if s1[j] in {"5", "6", "7", "8", "9"... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
302 | A | Eugeny and Array | PROGRAMMING | 800 | [
"implementation"
] | null | null | Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of a... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). | Print *m* integers — the responses to Eugene's queries in the order they occur in the input. | [
"2 3\n1 -1\n1 1\n1 2\n2 2\n",
"5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n"
] | [
"0\n1\n0\n",
"0\n1\n0\n1\n0\n"
] | none | 500 | [
{
"input": "2 3\n1 -1\n1 1\n1 2\n2 2",
"output": "0\n1\n0"
},
{
"input": "5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5",
"output": "0\n1\n0\n1\n0"
},
{
"input": "3 3\n1 1 1\n2 2\n1 1\n1 1",
"output": "0\n0\n0"
},
{
"input": "4 4\n-1 -1 -1 -1\n1 3\n1 2\n1 2\n1 1",
"output": "... | 1,567,231,828 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 11,264,000 | n,m = map(int,input().split())
x = list(map(int,input().split()))
c = x.count(-1)
k = min(n-c,c)
for _ in range(m):
a,b = map(int,input().split())
l = b-a+1
if l&1:
print(0)
else:
if l<=2*k:
print(1)
else:
print(0)
| Title: Eugeny and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (... | ```python
n,m = map(int,input().split())
x = list(map(int,input().split()))
c = x.count(-1)
k = min(n-c,c)
for _ in range(m):
a,b = map(int,input().split())
l = b-a+1
if l&1:
print(0)
else:
if l<=2*k:
print(1)
else:
print(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,684,945,059 | 1,059 | PyPy 3 | OK | TESTS | 61 | 124 | 9,318,400 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
t = list(map(int, input().split()))
t.sort()
s = 0
ans = 0
for i in t:
if s <= i:
s += i
ans += 1
print(ans) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n = int(input())
t = list(map(int, input().split()))
t.sort()
s = 0
ans = 0
for i in t:
if s <= i:
s += i
ans += 1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
863 | B | Kayaking | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"sortings"
] | null | null | Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they have to choose kayaks. There are 2·*n* people in the group (including Vadim), and they have exact... | The first line contains one number *n* (2<=≤<=*n*<=≤<=50).
The second line contains 2·*n* integer numbers *w*1, *w*2, ..., *w*2*n*, where *w**i* is weight of person *i* (1<=≤<=*w**i*<=≤<=1000). | Print minimum possible total instability. | [
"2\n1 2 3 4\n",
"4\n1 3 4 6 3 4 100 200\n"
] | [
"1\n",
"5\n"
] | none | 0 | [
{
"input": "2\n1 2 3 4",
"output": "1"
},
{
"input": "4\n1 3 4 6 3 4 100 200",
"output": "5"
},
{
"input": "3\n305 139 205 406 530 206",
"output": "102"
},
{
"input": "3\n610 750 778 6 361 407",
"output": "74"
},
{
"input": "5\n97 166 126 164 154 98 221 7 51 47",
... | 1,664,381,799 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | #!/usr/bin/env python3
import math
import sys
def test_case():
n = int(input())
w = list(map(int, input().split()))
w.sort()
ans = float("inf")
for i in range(2*n):
for j in range(i+1, 2*n):
a = w[:i] + w[i+1:j] + w[j+1:]
s = 0
for k in... | Title: Kayaking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they hav... | ```python
#!/usr/bin/env python3
import math
import sys
def test_case():
n = int(input())
w = list(map(int, input().split()))
w.sort()
ans = float("inf")
for i in range(2*n):
for j in range(i+1, 2*n):
a = w[:i] + w[i+1:j] + w[j+1:]
s = 0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
44 | J | Triminoes | PROGRAMMING | 2,000 | [
"constructive algorithms",
"greedy"
] | J. Triminoes | 2 | 256 | There are many interesting tasks on domino tilings. For example, an interesting fact is known. Let us take a standard chessboard (8<=×<=8) and cut exactly two squares out of it. It turns out that the resulting board can always be tiled using dominoes 1<=×<=2, if the two cut out squares are of the same color, otherwise ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the board size. Next *n* lines contain *m* symbols each and represent the board description. If some position contains ".", then the square in this position has been cut out. Symbol "w" stands for a white square, "b" stands for a black square... | If at least one correct tiling exists, in the first line print "YES" (without quotes), and then — the tiling description. The description must contain *n* lines, *m* symbols in each. The cut out squares, as well as in the input data, are marked by ".". To denote triminoes symbols "a", "b", "c", "d" can be used, and all... | [
"6 10\n.w.wbw.wbw\nwbwbw.w.w.\nbw.wbwbwbw\nw.wbw.wbwb\n...wbw.w.w\n..wbw.wbw.\n",
"2 2\nwb\nbw\n",
"1 3\nwbw\n",
"1 3\n...\n"
] | [
"YES\n.a.aaa.ccc\nbaccc.c.a.\nba.dddcbab\nb.aaa.cbab\n...bbb.b.b\n..ccc.ddd.",
"NO\n",
"YES\nbbb\n",
"YES\n...\n"
] | none | 0 | [
{
"input": "6 10\n.w.wbw.wbw\nwbwbw.w.w.\nbw.wbwbwbw\nw.wbw.wbwb\n...wbw.w.w\n..wbw.wbw.",
"output": "YES\n.a.aaa.aaa\nbabbb.a.b.\nba.cccacba\nb.aaa.acba\n...bbb.c.a\n..aaa.aaa."
},
{
"input": "2 2\nwb\nbw",
"output": "NO"
},
{
"input": "1 3\nwbw",
"output": "YES\naaa"
},
{
"... | 1,689,350,536 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | print("_RANDOM_GUESS_1689350535.794174")# 1689350535.7942212 | Title: Triminoes
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are many interesting tasks on domino tilings. For example, an interesting fact is known. Let us take a standard chessboard (8<=×<=8) and cut exactly two squares out of it. It turns out that the resulting board can always be... | ```python
print("_RANDOM_GUESS_1689350535.794174")# 1689350535.7942212
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive co... | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,602,801,187 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 93 | 307,200 | n = int(input())
if n % 2 == 0:
a = int(n/2) - 1
b = int(n/2) + 1
elif n % 2 == 1:
a = int(n//2)
b = int(n//2) + 1
while True:
listaA = []
listaB = []
cont = 1
while cont <= (a//2):
if a % cont == 0:
listaA.append(cont)
cont += 1
listaA.appe... | Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is cal... | ```python
n = int(input())
if n % 2 == 0:
a = int(n/2) - 1
b = int(n/2) + 1
elif n % 2 == 1:
a = int(n//2)
b = int(n//2) + 1
while True:
listaA = []
listaB = []
cont = 1
while cont <= (a//2):
if a % cont == 0:
listaA.append(cont)
cont += 1
l... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,697,670,988 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | from math import *
x = input()
x = int(x)
x1 = x / 5
print(ceil(x1))
| Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
from math import *
x = input()
x = int(x)
x1 = x / 5
print(ceil(x1))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,636,626,332 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 4,505,600 | n=int(input())
b=0
a=[int(x) for x in input().split()]
for i in range(n):
if a[i]%2==0:
b+=1
if b==1:
for i in range(n):
if a[i]%2==0:
print(i+1);break
else:
for i in range(n):
if a[i]%2!=0:
print(i+1);break | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
b=0
a=[int(x) for x in input().split()]
for i in range(n):
if a[i]%2==0:
b+=1
if b==1:
for i in range(n):
if a[i]%2==0:
print(i+1);break
else:
for i in range(n):
if a[i]%2!=0:
print(i+1);break
``` | 3.968608 | MatrixStudio/Codeforces-Python-Submissions |
274 | A | k-Multiple Free Set | PROGRAMMING | 1,500 | [
"binary search",
"greedy",
"sortings"
] | null | null | A *k*-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by *k*. That is, there are no two integers *x* and *y* (*x*<=<<=*y*) from the set, such that *y*<==<=*x*·*k*.
You're given a set of *n* distinct positive integers. Your task is to find th... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=109). The next line contains a list of *n* distinct positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
All the numbers in the lines are separated by single spaces. | On the only line of the output print the size of the largest *k*-multiple free subset of {*a*1,<=*a*2,<=...,<=*a**n*}. | [
"6 2\n2 3 6 5 4 10\n"
] | [
"3\n"
] | In the sample input one of the possible maximum 2-multiple free subsets is {4, 5, 6}. | 500 | [
{
"input": "6 2\n2 3 6 5 4 10",
"output": "3"
},
{
"input": "10 2\n1 2 3 4 5 6 7 8 9 10",
"output": "6"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "100 2\n191 17 61 40 77 95 128 88 26 69 79 10 131 106 142 152 68 39 182 53 83 81 6 89 65 148 33 22 5 47 107 121 52 163 1... | 1,585,039,774 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 1,964 | 12,083,200 | n, k = map(int,input().split())
a = sorted(list(map(int,input().split())))
ans= []
for i in range(n) :
if a[i] % k != 0 :
ans.append(a[i])
else :
if a[i] // k not in ans :
ans.append(a[i])
print(len(ans)) | Title: k-Multiple Free Set
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A *k*-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by *k*. That is, there are no two integers *x* and *y* (*x*<=<<=*y*) from the set, ... | ```python
n, k = map(int,input().split())
a = sorted(list(map(int,input().split())))
ans= []
for i in range(n) :
if a[i] % k != 0 :
ans.append(a[i])
else :
if a[i] // k not in ans :
ans.append(a[i])
print(len(ans))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
622 | C | Not Equal on a Segment | PROGRAMMING | 1,700 | [
"data structures",
"implementation"
] | null | null | You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so that *a**p**i*<=≠<=*x**i*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the number of elements in *a* and the number of queries.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106) — the elements of the array *a*.
Each of the next *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=... | Print *m* lines. On the *i*-th line print integer *p**i* — the position of any number not equal to *x**i* in segment [*l**i*,<=*r**i*] or the value <=-<=1 if there is no such number. | [
"6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2\n"
] | [
"2\n6\n-1\n4\n"
] | none | 0 | [
{
"input": "6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2",
"output": "2\n6\n-1\n4"
},
{
"input": "1 1\n1\n1 1 1",
"output": "-1"
},
{
"input": "1 1\n2\n1 1 2",
"output": "-1"
},
{
"input": "1 1\n569888\n1 1 967368",
"output": "1"
},
{
"input": "10 10\n1 1 1 1 1 1 ... | 1,463,051,390 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 19 | 1,000 | 16,384,000 | n,m=list(map(int,input().split()))
a=list(map(int,input().split()))
pre=[]
t,index=a[0],0
for i in range(n) :
index=index if a[i]==t else i
t=a[i]
pre.append(index)
prt=[]
for i in range(m) :
l,r,x=list(map(int,input().split()))
L=pre[r-1]
J=True
while l<=r and a[r-1]==x :
... | Title: Not Equal on a Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so ... | ```python
n,m=list(map(int,input().split()))
a=list(map(int,input().split()))
pre=[]
t,index=a[0],0
for i in range(n) :
index=index if a[i]==t else i
t=a[i]
pre.append(index)
prt=[]
for i in range(m) :
l,r,x=list(map(int,input().split()))
L=pre[r-1]
J=True
while l<=r and a[r... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,664,013,065 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n=int(input())
l=list(map(int,input().split()))
l=set(l)
l.remove(0)
print(len(l))
| Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n=int(input())
l=list(map(int,input().split()))
l=set(l)
l.remove(0)
print(len(l))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain nu... | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the son... | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE... | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,689,167,528 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | def restore(m):
w=m.split("WUB")
w=[word for word in w if word]
o=" ".join(w)
return o
m=input().strip()
print(restore(m)) | Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consist... | ```python
def restore(m):
w=m.split("WUB")
w=[word for word in w if word]
o=" ".join(w)
return o
m=input().strip()
print(restore(m))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,615,214,396 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 154 | 0 | n=int(input())
a,b=0,0
for i in range(n):
l, r = map(int, input().split())
a+=l
b+=r
print(min(a,n-a)+min(b,n-b)) | Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
n=int(input())
a,b=0,0
for i in range(n):
l, r = map(int, input().split())
a+=l
b+=r
print(min(a,n-a)+min(b,n-b))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,669,538,683 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | import math
a=list(map(int,input().split()))
b=a[0]
c=a[1]
if b<c:
print(math.factorial(b))
else:
print(math.factorial(c))
| Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
import math
a=list(map(int,input().split()))
b=a[0]
c=a[1]
if b<c:
print(math.factorial(b))
else:
print(math.factorial(c))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,565,520,304 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 30 | 278 | 0 | n = int(input())
q = []
tmp = set()
cnt = dict()
for _ in range(n):
a , b = map(int,input().split())
if a in cnt : cnt[a] = cnt[a] + 1
else : cnt[a] = 1
if a != b:
tmp.add(b)
ans = 0
for i in tmp:
if i in cnt :
del cnt[i]
for u in cnt:
ans += cnt[u]
... | Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th... | ```python
n = int(input())
q = []
tmp = set()
cnt = dict()
for _ in range(n):
a , b = map(int,input().split())
if a in cnt : cnt[a] = cnt[a] + 1
else : cnt[a] = 1
if a != b:
tmp.add(b)
ans = 0
for i in tmp:
if i in cnt :
del cnt[i]
for u in cnt:
ans ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,640,783,243 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 62 | 0 | n, x = input().split()
n, x = int(n), int(x)
g = 0
for i in range(n):
s = input()
c = int(s[2:])
if '+' in s:
x += c
else:
if x < c:
g += 1
else:
x -= c
print(x, g)
| Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n, x = input().split()
n, x = int(n), int(x)
g = 0
for i in range(n):
s = input()
c = int(s[2:])
if '+' in s:
x += c
else:
if x < c:
g += 1
else:
x -= c
print(x, g)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
334 | A | Candy Bags | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from 1 to *n*2 he has exactly one bag with *k* candies.
Help him give *n* bags of candies to each b... | The single line contains a single integer *n* (*n* is even, 2<=≤<=*n*<=≤<=100) — the number of Gerald's brothers. | Let's assume that Gerald indexes his brothers with numbers from 1 to *n*. You need to print *n* lines, on the *i*-th line print *n* integers — the numbers of candies in the bags for the *i*-th brother. Naturally, all these numbers should be distinct and be within limits from 1 to *n*2. You can print the numbers in the ... | [
"2\n"
] | [
"1 4\n2 3\n"
] | The sample shows Gerald's actions if he has two brothers. In this case, his bags contain 1, 2, 3 and 4 candies. He can give the bags with 1 and 4 candies to one brother and the bags with 2 and 3 to the other brother. | 500 | [
{
"input": "2",
"output": "1 4\n2 3"
},
{
"input": "4",
"output": "1 16 2 15\n3 14 4 13\n5 12 6 11\n7 10 8 9"
},
{
"input": "6",
"output": "1 36 2 35 3 34\n4 33 5 32 6 31\n7 30 8 29 9 28\n10 27 11 26 12 25\n13 24 14 23 15 22\n16 21 17 20 18 19"
},
{
"input": "8",
"output"... | 1,622,295,417 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 124 | 102,400 | from collections import deque
num = int(input())
arr = deque(i for i in range(1, num**2+1))
cases = len(arr)//2
pairs = []
while cases:
cases -= 1
pairs.append([arr.popleft(), arr.pop()])
for i in range(num):
temp = []
while len(temp) < num:
temp.extend(pairs.pop())
print(temp)
... | Title: Candy Bags
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from ... | ```python
from collections import deque
num = int(input())
arr = deque(i for i in range(1, num**2+1))
cases = len(arr)//2
pairs = []
while cases:
cases -= 1
pairs.append([arr.popleft(), arr.pop()])
for i in range(num):
temp = []
while len(temp) < num:
temp.extend(pairs.pop())
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,624,770,083 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 0 | a = input()
i = 0
while(i < len(a)):
if(a[i] == "-" and a[i + 1] == "-"):
i += 1
print(2, end = "")
elif(a[i] == "-" and a[i + 1] == "."):
i += 1
print(1, end = "")
elif(a[i] == "."):
print(0, end = "")
i += 1
# Sun Jun 27 2021 08:01:22 GMT+0300 (Москва, стандартное время)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
a = input()
i = 0
while(i < len(a)):
if(a[i] == "-" and a[i + 1] == "-"):
i += 1
print(2, end = "")
elif(a[i] == "-" and a[i + 1] == "."):
i += 1
print(1, end = "")
elif(a[i] == "."):
print(0, end = "")
i += 1
# Sun Jun 27 2021 08:01:22 GMT+0300 (Москва, стандартное время)
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
358 | A | Dima and Continuous Line | PROGRAMMING | 1,400 | [
"brute force",
"implementation"
] | null | null | Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher gave Seryozha the coordinates of *n* distinct points on the abscissa axis and asked to consecutively connect th... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=103). The second line contains *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=106<=≤<=*x**i*<=≤<=106) — the *i*-th point has coordinates (*x**i*,<=0). The points are not necessarily sorted by their *x* coordinate. | In the single line print "yes" (without the quotes), if the line has self-intersections. Otherwise, print "no" (without the quotes). | [
"4\n0 10 5 15\n",
"4\n0 15 5 10\n"
] | [
"yes\n",
"no\n"
] | The first test from the statement is on the picture to the left, the second test is on the picture to the right. | 500 | [
{
"input": "4\n0 10 5 15",
"output": "yes"
},
{
"input": "4\n0 15 5 10",
"output": "no"
},
{
"input": "5\n0 1000 2000 3000 1500",
"output": "yes"
},
{
"input": "5\n-724093 710736 -383722 -359011 439613",
"output": "no"
},
{
"input": "50\n384672 661179 -775591 -989... | 1,541,022,027 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 20 | 951 | 0 |
n = int(input())
k = list(map(int,input().split()))
for i in range(len(k)-1):
temp = 0
m = min(k[i],k[i+1])
n = max(k[i],k[i+1])
for j in range(len(k) - 1):
a = min(k[j],k[j+1])
b = max(k[j],k[j+1])
if m < a < n and b >n:
print('yes')
temp = 1
... | Title: Dima and Continuous Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and Seryozha live in an ordinary dormitory room for two. One day Dima had a date with his girl and he asked Seryozha to leave the room. As a compensation, Seryozha made Dima do his homework.
The teacher g... | ```python
n = int(input())
k = list(map(int,input().split()))
for i in range(len(k)-1):
temp = 0
m = min(k[i],k[i+1])
n = max(k[i],k[i+1])
for j in range(len(k) - 1):
a = min(k[j],k[j+1])
b = max(k[j],k[j+1])
if m < a < n and b >n:
print('yes')
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,693,909,498 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n=int(input())
if n==1987:
print('2013')
else:
a=n+1
print(a)
| Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
n=int(input())
if n==1987:
print('2013')
else:
a=n+1
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
574 | B | Bear and Three Musketeers | PROGRAMMING | 1,500 | [
"brute force",
"dfs and similar",
"graphs",
"hashing"
] | null | null | Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three brave warriors to help him to fight against bad guys.
There are *n* warriors. Richelimakieu wants to choose thre... | The first line contains two space-separated integers, *n* and *m* (3<=≤<=*n*<=≤<=4000, 0<=≤<=*m*<=≤<=4000) — respectively number of warriors and number of pairs of warriors knowing each other.
*i*-th of the following *m* lines contains two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**... | If Richelimakieu can choose three musketeers, print the minimum possible sum of their recognitions. Otherwise, print "-1" (without the quotes). | [
"5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5\n",
"7 4\n2 1\n3 6\n5 1\n1 7\n"
] | [
"2\n",
"-1\n"
] | In the first sample Richelimakieu should choose a triple 1, 2, 3. The first musketeer doesn't know anyone except other two musketeers so his recognition is 0. The second musketeer has recognition 1 because he knows warrior number 4. The third musketeer also has recognition 1 because he knows warrior 4. Sum of recogniti... | 1,000 | [
{
"input": "5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5",
"output": "2"
},
{
"input": "7 4\n2 1\n3 6\n5 1\n1 7",
"output": "-1"
},
{
"input": "5 0",
"output": "-1"
},
{
"input": "7 14\n3 6\n2 3\n5 2\n5 6\n7 5\n7 4\n6 2\n3 5\n7 1\n4 1\n6 1\n7 6\n6 4\n5 4",
"output": "5"
},
{
... | 1,613,697,525 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 19 | 2,000 | 819,200 | # K - 2, Assignment 4, bd2255
# contributions to the solution: Daniel Perez
triangles = []
def helper(graph, streak, start, key, tempTrio):
if streak == 3:
if key == start:
tempTrio.sort()
if not tempTrio in triangles:
triangles.append(tempTrio)
return
... | Title: Bear and Three Musketeers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three br... | ```python
# K - 2, Assignment 4, bd2255
# contributions to the solution: Daniel Perez
triangles = []
def helper(graph, streak, start, key, tempTrio):
if streak == 3:
if key == start:
tempTrio.sort()
if not tempTrio in triangles:
triangles.append(tempTrio)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
820 | B | Mister B and Angle in Polygon | PROGRAMMING | 1,300 | [
"constructive algorithms",
"geometry",
"math"
] | null | null | On one quiet day all of sudden Mister B decided to draw angle *a* on his field. Aliens have already visited his field and left many different geometric figures on it. One of the figures is regular convex *n*-gon (regular convex polygon with *n* sides).
That's why Mister B decided to use this polygon. Now Mister B must... | First and only line contains two space-separated integers *n* and *a* (3<=≤<=*n*<=≤<=105, 1<=≤<=*a*<=≤<=180) — the number of vertices in the polygon and the needed angle, in degrees. | Print three space-separated integers: the vertices *v*1, *v*2, *v*3, which form . If there are multiple optimal solutions, print any of them. The vertices are numbered from 1 to *n* in clockwise order. | [
"3 15\n",
"4 67\n",
"4 68\n"
] | [
"1 2 3\n",
"2 1 3\n",
"4 1 2\n"
] | In first sample test vertices of regular triangle can create only angle of 60 degrees, that's why every possible angle is correct.
Vertices of square can create 45 or 90 degrees angles only. That's why in second sample test the angle of 45 degrees was chosen, since |45 - 67| < |90 - 67|. Other correct answers are: ... | 1,000 | [
{
"input": "3 15",
"output": "2 1 3"
},
{
"input": "4 67",
"output": "2 1 3"
},
{
"input": "4 68",
"output": "2 1 4"
},
{
"input": "3 1",
"output": "2 1 3"
},
{
"input": "3 180",
"output": "2 1 3"
},
{
"input": "100000 1",
"output": "2 1 558"
},
... | 1,627,527,947 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 77 | 6,758,400 | # _
#####################################################################################################################
def main():
return bestAngle_sVertices(*map(int, input().split()))
def bestAngle_sVertices(nVertices, angle):
angle *= nVertices
if angle < 180:
return '2 1 3'
... | Title: Mister B and Angle in Polygon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On one quiet day all of sudden Mister B decided to draw angle *a* on his field. Aliens have already visited his field and left many different geometric figures on it. One of the figures is regular convex *... | ```python
# _
#####################################################################################################################
def main():
return bestAngle_sVertices(*map(int, input().split()))
def bestAngle_sVertices(nVertices, angle):
angle *= nVertices
if angle < 180:
return '2 ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,673,627,813 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 124 | 0 | import sys,math
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
def get_string(): return sys.stdin.readline().strip()
a = input()
b = input()
c = str(int(a)+int(b))
an,bn,cn="","",""
for x in a:
if x!='0':
... | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
import sys,math
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
def get_string(): return sys.stdin.readline().strip()
a = input()
b = input()
c = str(int(a)+int(b))
an,bn,cn="","",""
for x in a:
if x... | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
696 | C | PLEASE | PROGRAMMING | 2,000 | [
"combinatorics",
"dp",
"implementation",
"math",
"matrices"
] | null | null | As we all know Barney's job is "PLEASE" and he has not much to do at work. That's why he started playing "cups and key". In this game there are three identical cups arranged in a line from left to right. Initially key to Barney's heart is under the middle cup.
Then at one turn Barney swaps the cup in the middle with a... | The first line of input contains a single integer *k* (1<=≤<=*k*<=≤<=105) — the number of elements in array Barney gave you.
The second line contains *k* integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=1018) — the elements of the array. | In the only line of output print a single string *x*<=/<=*y* where *x* is the remainder of dividing *p* by 109<=+<=7 and *y* is the remainder of dividing *q* by 109<=+<=7. | [
"1\n2\n",
"3\n1 1 1\n"
] | [
"1/2\n",
"0/1\n"
] | none | 1,500 | [
{
"input": "1\n2",
"output": "1/2"
},
{
"input": "3\n1 1 1",
"output": "0/1"
},
{
"input": "1\n983155795040951739",
"output": "145599903/436799710"
},
{
"input": "2\n467131402341701583 956277077729692725",
"output": "63467752/190403257"
},
{
"input": "10\n21767322... | 1,522,393,085 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 17,510,400 | from functools import reduce
MOD = 10 ** 9 + 7
n, a = int(input()), list(map(int, input().split()))
def pw():
res = 2
for k in a:
res = pow(res, k, MOD)
return res
# 333333336 * 3 = 1
# 500000004 * 2 = 1
k = reduce(lambda x,y:(x*y)%2, a, 1)
q = (pw() * 500000004) % MOD
if k == 0:
p = ((q + 1) * 33333... | Title: PLEASE
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As we all know Barney's job is "PLEASE" and he has not much to do at work. That's why he started playing "cups and key". In this game there are three identical cups arranged in a line from left to right. Initially key to Barney'... | ```python
from functools import reduce
MOD = 10 ** 9 + 7
n, a = int(input()), list(map(int, input().split()))
def pw():
res = 2
for k in a:
res = pow(res, k, MOD)
return res
# 333333336 * 3 = 1
# 500000004 * 2 = 1
k = reduce(lambda x,y:(x*y)%2, a, 1)
q = (pw() * 500000004) % MOD
if k == 0:
p = ((q + ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,503,190,227 | 327 | Python 3 | OK | TESTS | 29 | 77 | 0 | a=input()
a=input().split()
best=0
for i in a:
ans=0
for l in i:
if l>='A' and l<='Z':
ans+=1
if ans>best:
best=ans
print(best) | Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
a=input()
a=input().split()
best=0
for i in a:
ans=0
for l in i:
if l>='A' and l<='Z':
ans+=1
if ans>best:
best=ans
print(best)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
691 | B | s-palindrome | PROGRAMMING | 1,600 | [
"implementation",
"strings"
] | null | null | Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
You are given a string *s*. Check if the ... | The only line contains the string *s* (1<=≤<=|*s*|<=≤<=1000) which consists of only English letters. | Print "TAK" if the string *s* is "s-palindrome" and "NIE" otherwise. | [
"oXoxoXo\n",
"bod\n",
"ER\n"
] | [
"TAK\n",
"TAK\n",
"NIE\n"
] | none | 0 | [
{
"input": "oXoxoXo",
"output": "TAK"
},
{
"input": "bod",
"output": "TAK"
},
{
"input": "ER",
"output": "NIE"
},
{
"input": "o",
"output": "TAK"
},
{
"input": "a",
"output": "NIE"
},
{
"input": "opo",
"output": "NIE"
},
{
"input": "HCMoxkg... | 1,671,030,065 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | def start():
a = input()
s = ['A','b','X', 'x', 'O', 'o','H','i','I','M','T',"U",'V','v','W','w','Y']
if len(a)%2==0:
a1=list(a[:len(a)//2])
a2=list(a[len(a)//2:])
else:
a1 = list(a[:(len(a) // 2)])
a2 = list(a[(len(a) // 2)+1:])
for i in range(len(a)//2):
... | Title: s-palindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second h... | ```python
def start():
a = input()
s = ['A','b','X', 'x', 'O', 'o','H','i','I','M','T',"U",'V','v','W','w','Y']
if len(a)%2==0:
a1=list(a[:len(a)//2])
a2=list(a[len(a)//2:])
else:
a1 = list(a[:(len(a) // 2)])
a2 = list(a[(len(a) // 2)+1:])
for i in range(len(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,661,636,655 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | a = input("enter first number: ")
b = input("enter second number: ")
a2 = (a.replace('0',''))
b2 = (b.replace('0',''))
c = int(a)+int(b)
c2 = int(str(c).replace('0',''))
c3 = int(a2)+int(b2)
if c2 == c3:
print("yes")
else:
print("no")
| Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
a = input("enter first number: ")
b = input("enter second number: ")
a2 = (a.replace('0',''))
b2 = (b.replace('0',''))
c = int(a)+int(b)
c2 = int(str(c).replace('0',''))
c3 = int(a2)+int(b2)
if c2 == c3:
print("yes")
else:
print("no")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
828 | A | Restaurant Tables | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | In a small restaurant there are *a* tables for one person and *b* tables for two persons.
It it known that *n* groups of people come today, each consisting of one or two people.
If a group consist of one person, it is seated at a vacant one-seater table. If there are none of them, it is seated at a vacant two-seate... | The first line contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=2·105, 1<=≤<=*a*,<=*b*<=≤<=2·105) — the number of groups coming to the restaurant, the number of one-seater and the number of two-seater tables.
The second line contains a sequence of integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=2) — the d... | Print the total number of people the restaurant denies service to. | [
"4 1 2\n1 2 1 1\n",
"4 1 1\n1 1 2 1\n"
] | [
"0\n",
"2\n"
] | In the first example the first group consists of one person, it is seated at a vacant one-seater table. The next group occupies a whole two-seater table. The third group consists of one person, it occupies one place at the remaining two-seater table. The fourth group consists of one person, he is seated at the remainin... | 500 | [
{
"input": "4 1 2\n1 2 1 1",
"output": "0"
},
{
"input": "4 1 1\n1 1 2 1",
"output": "2"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 1 2\n2 2",
"output": "0"
},
{
"input": "5 1 3\n1 2 2 2 1",
"output": "1"
},
{
"input": "7 6 1\n1 1 1 1 1 1... | 1,499,875,345 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 139 | 8,192,000 | n, a, b = list(map(int, input().split()))
times = list(map(int, input().split()))
cur_a = 0
cur_b_1 = [b - 1, 0]
cur_b_2 = 0
denied = 0
for time in times:
if time == 1:
if cur_a != a:
cur_a += 1
else:
if cur_b_1[0] != cur_b_2 - 1:
if cur_b_1[1] == ... | Title: Restaurant Tables
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small restaurant there are *a* tables for one person and *b* tables for two persons.
It it known that *n* groups of people come today, each consisting of one or two people.
If a group consist of one person, i... | ```python
n, a, b = list(map(int, input().split()))
times = list(map(int, input().split()))
cur_a = 0
cur_b_1 = [b - 1, 0]
cur_b_2 = 0
denied = 0
for time in times:
if time == 1:
if cur_a != a:
cur_a += 1
else:
if cur_b_1[0] != cur_b_2 - 1:
if cur_... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
920 | A | Water The Garden | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the bed *x**i*), which, if turned on, start delivering water to neighbouring beds. If the tap on the bed *... | The first line contains one integer *t* — the number of test cases to solve (1<=≤<=*t*<=≤<=200).
Then *t* test cases follow. The first line of each test case contains two integers *n* and *k* (1<=≤<=*n*<=≤<=200, 1<=≤<=*k*<=≤<=*n*) — the number of garden beds and water taps, respectively.
Next line contains *k* intege... | For each test case print one integer — the minimum number of seconds that have to pass after Max turns on some of the water taps, until the whole garden is watered. | [
"3\n5 1\n3\n3 3\n1 2 3\n4 1\n1\n"
] | [
"3\n1\n4\n"
] | The first example consists of 3 tests:
1. There are 5 garden beds, and a water tap in the bed 3. If we turn it on, then after 1 second passes, only bed 3 will be watered; after 2 seconds pass, beds [1, 3] will be watered, and after 3 seconds pass, everything will be watered. 1. There are 3 garden beds, and there is ... | 0 | [
{
"input": "3\n5 1\n3\n3 3\n1 2 3\n4 1\n1",
"output": "3\n1\n4"
},
{
"input": "26\n1 1\n1\n2 1\n2\n2 1\n1\n2 2\n1 2\n3 1\n3\n3 1\n2\n3 2\n2 3\n3 1\n1\n3 2\n1 3\n3 2\n1 2\n3 3\n1 2 3\n4 1\n4\n4 1\n3\n4 2\n3 4\n4 1\n2\n4 2\n2 4\n4 2\n2 3\n4 3\n2 3 4\n4 1\n1\n4 2\n1 4\n4 2\n1 3\n4 3\n1 3 4\n4 2\n1 2\n4... | 1,595,697,805 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 109 | 6,963,200 | for _ in range(int(input())):
n,k=map(int,input().split())
arr=list(map(int,input().split()))
water=[0]*n
ans,j=1,0
for i in range(k):
water[arr[i]-1]=1
while(sum(water)<n):
ans+=1
j+=1
for i in range(k):
if(arr[i]-1+j<n):
w... | Title: Water The Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the ... | ```python
for _ in range(int(input())):
n,k=map(int,input().split())
arr=list(map(int,input().split()))
water=[0]*n
ans,j=1,0
for i in range(k):
water[arr[i]-1]=1
while(sum(water)<n):
ans+=1
j+=1
for i in range(k):
if(arr[i]-1+j<n):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
999 | E | Reachability from the Capital | PROGRAMMING | 2,000 | [
"dfs and similar",
"graphs",
"greedy"
] | null | null | There are $n$ cities and $m$ roads in Berland. Each road connects a pair of cities. The roads in Berland are one-way.
What is the minimum number of new roads that need to be built to make all the cities reachable from the capital?
New roads will also be one-way. | The first line of input consists of three integers $n$, $m$ and $s$ ($1 \le n \le 5000, 0 \le m \le 5000, 1 \le s \le n$) — the number of cities, the number of roads and the index of the capital. Cities are indexed from $1$ to $n$.
The following $m$ lines contain roads: road $i$ is given as a pair of cities $u_i$, $v_... | Print one integer — the minimum number of extra roads needed to make all the cities reachable from city $s$. If all the cities are already reachable from $s$, print 0. | [
"9 9 1\n1 2\n1 3\n2 3\n1 5\n5 6\n6 1\n1 8\n9 8\n7 1\n",
"5 4 5\n1 2\n2 3\n3 4\n4 1\n"
] | [
"3\n",
"1\n"
] | The first example is illustrated by the following:
For example, you can add roads ($6, 4$), ($7, 9$), ($1, 7$) to make all the cities reachable from $s = 1$.
The second example is illustrated by the following:
In this example, you can add any one of the roads ($5, 1$), ($5, 2$), ($5, 3$), ($5, 4$) to make all the ci... | 0 | [
{
"input": "9 9 1\n1 2\n1 3\n2 3\n1 5\n5 6\n6 1\n1 8\n9 8\n7 1",
"output": "3"
},
{
"input": "5 4 5\n1 2\n2 3\n3 4\n4 1",
"output": "1"
},
{
"input": "5000 0 2956",
"output": "4999"
},
{
"input": "2 0 2",
"output": "1"
},
{
"input": "2 1 1\n1 2",
"output": "0"... | 1,653,737,525 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n,m,c = map(int,input().split())
dc = []
for i in range(m):
dc.append(i)
for i in range(m):
dc[i] = []
for i in range(m):
a,b = list(map(int,input().split()))
dc[i].append(a)
dc[i].append(b)
x = 1
ch = []
ch1 = []
for i in dc:
if i[0] == c:
x += 1
ch.append(i)
else:
... | Title: Reachability from the Capital
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are $n$ cities and $m$ roads in Berland. Each road connects a pair of cities. The roads in Berland are one-way.
What is the minimum number of new roads that need to be built to make all the cities r... | ```python
n,m,c = map(int,input().split())
dc = []
for i in range(m):
dc.append(i)
for i in range(m):
dc[i] = []
for i in range(m):
a,b = list(map(int,input().split()))
dc[i].append(a)
dc[i].append(b)
x = 1
ch = []
ch1 = []
for i in dc:
if i[0] == c:
x += 1
ch.append(i)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,695,461,332 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n=int(input())
c=0
while(n>0):
if(n//100>0):
c+=n//100
n=n-(n//100)
elif(n>=20):
c+=n//20
n=n-(n//20)
elif(n>=10):
c+=n//10
n=n-(n//10)
elif(n>=5):
c+=n//5
n=n-(n//5)
else:
c+=n//1
n=n-(n//1)
print(c)
... | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
n=int(input())
c=0
while(n>0):
if(n//100>0):
c+=n//100
n=n-(n//100)
elif(n>=20):
c+=n//20
n=n-(n//20)
elif(n>=10):
c+=n//10
n=n-(n//10)
elif(n>=5):
c+=n//5
n=n-(n//5)
else:
c+=n//1
n=n-(n//1)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,690,626,255 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 93 | 1,945,600 | n,x = map(int,input().split())
m = 0
for _ in range(n):
b, c = input().split()
if b == "+":
x+=int(c)
elif b == "-":
if int(c) > x :
m += 1
else :
x-=int(c)
print(x,m) | Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n,x = map(int,input().split())
m = 0
for _ in range(n):
b, c = input().split()
if b == "+":
x+=int(c)
elif b == "-":
if int(c) > x :
m += 1
else :
x-=int(c)
print(x,m)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given an array *a*1,<=*a*2,<=...,<=*a**n* consisting of *n* integers, and an integer *k*. You have to split the array into exactly *k* non-empty subsegments. You'll then compute the minimum integer on each subsegment, and take the maximum integer over the *k* obtained minimums. What is the maximum possible inte... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=<=105) — the size of the array *a* and the number of subsegments you have to split the array to.
The second line contains *n* integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n* (<=-<=109<=<=≤<=<=*a**i*<=≤<=<=109). | Print single integer — the maximum possible integer you can get if you split the array into *k* non-empty subsegments and take maximum of minimums on the subsegments. | [
"5 2\n1 2 3 4 5\n",
"5 1\n-4 -5 -3 -2 -1\n"
] | [
"5\n",
"-5\n"
] | A subsegment [*l*, *r*] (*l* ≤ *r*) of array *a* is the sequence *a*<sub class="lower-index">*l*</sub>, *a*<sub class="lower-index">*l* + 1</sub>, ..., *a*<sub class="lower-index">*r*</sub>.
Splitting of array *a* of *n* elements into *k* subsegments [*l*<sub class="lower-index">1</sub>, *r*<sub class="lower-index... | 0 | [
{
"input": "5 2\n1 2 3 4 5",
"output": "5"
},
{
"input": "5 1\n-4 -5 -3 -2 -1",
"output": "-5"
},
{
"input": "10 2\n10 9 1 -9 -7 -9 3 8 -10 5",
"output": "10"
},
{
"input": "10 4\n-8 -1 2 -3 9 -8 4 -3 5 9",
"output": "9"
},
{
"input": "1 1\n504262064",
"output... | 1,512,664,519 | 919 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 1,000 | 13,721,600 | (n,k) = (int(i) for i in input().split())
a = [int(i) for i in input().split()]
if k==1:
print(min(a))
elif k==2:
mx = a[0]
for i in range(1, n):
v = max(min(a[:i]), min(a[i:]))
if v>mx:
mx = v
print(mx)
else:
print(max(a)) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a*1,<=*a*2,<=...,<=*a**n* consisting of *n* integers, and an integer *k*. You have to split the array into exactly *k* non-empty subsegments. You'll then compute the minimum integer on each subsegment, and ... | ```python
(n,k) = (int(i) for i in input().split())
a = [int(i) for i in input().split()]
if k==1:
print(min(a))
elif k==2:
mx = a[0]
for i in range(1, n):
v = max(min(a[:i]), min(a[i:]))
if v>mx:
mx = v
print(mx)
else:
print(max(a))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,652,680,878 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 4,300,800 |
s =input()
t =input()
x = 0
for i in range(len(t)):
if t[i] == s[i]:
x = x+1
print(x+1)
| Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
s =input()
t =input()
x = 0
for i in range(len(t)):
if t[i] == s[i]:
x = x+1
print(x+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,685,033,425 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | k,a,b=map(int,input().split())
bb = b // k
aa = (a-1) // k
if a == 0 and k != 0:
print (bb - aa + 1)
else:
print (bb - aa ) | Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
k,a,b=map(int,input().split())
bb = b // k
aa = (a-1) // k
if a == 0 and k != 0:
print (bb - aa + 1)
else:
print (bb - aa )
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
907 | A | Masha and Bears | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 500 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,514,112,539 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 5,529,600 | v1, v2, v3, v4=map(int, input().split())
if min(v1, v2)<=v4 or 2*v3<v4:
print(-1)
else:
print (v1)
print (v2)
print (v4)
| Title: Masha and Bears
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son b... | ```python
v1, v2, v3, v4=map(int, input().split())
if min(v1, v2)<=v4 or 2*v3<v4:
print(-1)
else:
print (v1)
print (v2)
print (v4)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
820 | A | Mister B and Book Reading | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, starting from the second, he read *a* pages more than on the previous day (at first day he read *v*0 pages, at ... | First and only line contains five space-separated integers: *c*, *v*0, *v*1, *a* and *l* (1<=≤<=*c*<=≤<=1000, 0<=≤<=*l*<=<<=*v*0<=≤<=*v*1<=≤<=1000, 0<=≤<=*a*<=≤<=1000) — the length of the book in pages, the initial reading speed, the maximum reading speed, the acceleration in reading speed and the number of pages fo... | Print one integer — the number of days Mister B needed to finish the book. | [
"5 5 10 5 4\n",
"12 4 12 4 1\n",
"15 1 100 0 0\n"
] | [
"1\n",
"3\n",
"15\n"
] | In the first sample test the book contains 5 pages, so Mister B read it right at the first day.
In the second sample test at first day Mister B read pages number 1 - 4, at second day — 4 - 11, at third day — 11 - 12 and finished the book.
In third sample test every day Mister B read 1 page of the book, so he finished... | 500 | [
{
"input": "5 5 10 5 4",
"output": "1"
},
{
"input": "12 4 12 4 1",
"output": "3"
},
{
"input": "15 1 100 0 0",
"output": "15"
},
{
"input": "1 1 1 0 0",
"output": "1"
},
{
"input": "1000 999 1000 1000 998",
"output": "2"
},
{
"input": "1000 2 2 5 1",
... | 1,603,298,600 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 1,536,000 | c,v0,v1,a,l=map(int,input().split())
page=v0
page1=a
count=1
while page < c:
page+=page1
page-=l
if (page1+a) < v1:
page1+=a
count+=1
print(count) | Title: Mister B and Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, ... | ```python
c,v0,v1,a,l=map(int,input().split())
page=v0
page1=a
count=1
while page < c:
page+=page1
page-=l
if (page1+a) < v1:
page1+=a
count+=1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
892 | B | Wrath | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the *i*-th person kills the *j*-th person if and only if *j*<=<<=*i* and *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — the number of guilty people.
Second line contains *n* space-separated integers *L*1,<=*L*2,<=...,<=*L**n* (0<=≤<=*L**i*<=≤<=109), where *L**i* is the length of the *i*-th person's claw. | Print one integer — the total number of alive people after the bell rings. | [
"4\n0 1 0 10\n",
"2\n0 0\n",
"10\n1 1 3 0 0 0 2 1 0 3\n"
] | [
"1\n",
"2\n",
"3\n"
] | In first sample the last person kills everyone in front of him. | 1,000 | [
{
"input": "4\n0 1 0 10",
"output": "1"
},
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "10\n1 1 3 0 0 0 2 1 0 3",
"output": "3"
},
{
"input": "10\n0 0 2 0 0 3 3 2 2 0",
"output": "2"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "5\n0 0 0 1 0"... | 1,510,935,512 | 6,212 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 34 | 2,000 | 76,492,800 | n = int(input())
a = list(map(int,input().split()))
o = []
p = [1]*n
kol = 0
for i in range(len(a)):
o.append(i - a[i])
for t in range(1,len(a)):
if o[len(a) - t] > 0:
for u in range(o[len(a)-t],len(a)-t):
if p[u] == 0:
break
else:
p[u... | Title: Wrath
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same ... | ```python
n = int(input())
a = list(map(int,input().split()))
o = []
p = [1]*n
kol = 0
for i in range(len(a)):
o.append(i - a[i])
for t in range(1,len(a)):
if o[len(a) - t] > 0:
for u in range(o[len(a)-t],len(a)-t):
if p[u] == 0:
break
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
631 | A | Interview | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function *f*(*x*,<=*l*,<=*r*) as a bitwise OR of integers *x... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the length of the arrays.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=109).
The third line contains *n* integers *b**i* (0<=≤<=*b**i*<=≤<=109). | Print a single integer — the maximum value of sum *f*(*a*,<=*l*,<=*r*)<=+<=*f*(*b*,<=*l*,<=*r*) among all possible 1<=≤<=*l*<=≤<=*r*<=≤<=*n*. | [
"5\n1 2 4 3 2\n2 3 3 12 1\n",
"10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6\n"
] | [
"22",
"46"
] | Bitwise OR of two non-negative integers *a* and *b* is the number *c* = *a* *OR* *b*, such that each of its digits in binary notation is 1 if and only if at least one of *a* or *b* have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is *l* = 2 and *r* = 4, because *... | 500 | [
{
"input": "5\n1 2 4 3 2\n2 3 3 12 1",
"output": "22"
},
{
"input": "10\n13 2 7 11 8 4 9 8 5 1\n5 7 18 9 2 3 0 11 8 6",
"output": "46"
},
{
"input": "25\n12 30 38 109 81 124 80 33 38 48 29 78 96 48 96 27 80 77 102 65 80 113 31 118 35\n25 64 95 13 12 6 111 80 85 16 61 119 23 65 73 65 20 9... | 1,618,098,953 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 409,600 | from functools import reduce
def solve(n,a,b):
l = 0
r = l+3
max_val = 0
for i in range(n-2):
val = reduce(lambda x,y: x | y , a[l:r])+reduce(lambda x,y: x | y , b[l:r])
if val > max_val:
max_val = val
l = i+1
r = l+3
return max_val
def main() :
# na,nb = list(map(int, in... | Title: Interview
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of... | ```python
from functools import reduce
def solve(n,a,b):
l = 0
r = l+3
max_val = 0
for i in range(n-2):
val = reduce(lambda x,y: x | y , a[l:r])+reduce(lambda x,y: x | y , b[l:r])
if val > max_val:
max_val = val
l = i+1
r = l+3
return max_val
def main() :
# na,nb = list(m... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
520 | B | Two Buttons | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs",
"greedy",
"implementation",
"math",
"shortest paths"
] | null | null | Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by two. After clicking the blue button, device subtracts one from the number on the display. If at so... | The first and the only line of the input contains two distinct integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=104), separated by a space . | Print a single number — the minimum number of times one needs to push the button required to get the number *m* out of number *n*. | [
"4 6\n",
"10 1\n"
] | [
"2\n",
"9\n"
] | In the first example you need to push the blue button once, and then push the red button once.
In the second example, doubling the number is unnecessary, so we need to push the blue button nine times. | 1,000 | [
{
"input": "4 6",
"output": "2"
},
{
"input": "10 1",
"output": "9"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "2 10",
"outpu... | 1,698,332,996 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 46 | 0 | n, m = map(int, input().split())
res = 0
while n < m:
if m % 2 == 0:
m //= 2
else:
m += 1
res += 1
print(res+ n - m)
| Title: Two Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by t... | ```python
n, m = map(int, input().split())
res = 0
while n < m:
if m % 2 == 0:
m //= 2
else:
m += 1
res += 1
print(res+ n - m)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
74 | A | Room Leader | PROGRAMMING | 1,000 | [
"implementation"
] | A. Room Leader | 2 | 256 | Let us remind you part of the rules of Codeforces. The given rules slightly simplified, use the problem statement as a formal document.
In the beginning of the round the contestants are divided into rooms. Each room contains exactly *n* participants. During the contest the participants are suggested to solve five prob... | The first line contains an integer *n*, which is the number of contestants in the room (1<=≤<=*n*<=≤<=50). The next *n* lines contain the participants of a given room. The *i*-th line has the format of "*handle**i* *plus**i* *minus**i* *a**i* *b**i* *c**i* *d**i* *e**i*" — it is the handle of a contestant, the number o... | Print on the single line the handle of the room leader. | [
"5\nPetr 3 1 490 920 1000 1200 0\ntourist 2 0 490 950 1100 1400 0\nEgor 7 0 480 900 950 0 1000\nc00lH4x0R 0 10 150 0 0 0 0\nsome_participant 2 1 450 720 900 0 0\n"
] | [
"tourist"
] | The number of points that each participant from the example earns, are as follows:
- Petr — 3860 - tourist — 4140 - Egor — 4030 - c00lH4x0R — - 350 - some_participant — 2220
Thus, the leader of the room is tourist. | 500 | [
{
"input": "5\nPetr 3 1 490 920 1000 1200 0\ntourist 2 0 490 950 1100 1400 0\nEgor 7 0 480 900 950 0 1000\nc00lH4x0R 0 10 150 0 0 0 0\nsome_participant 2 1 450 720 900 0 0",
"output": "tourist"
},
{
"input": "1\nA 0 0 200 0 0 0 0",
"output": "A"
},
{
"input": "2\n12345678901234567890 1 0... | 1,589,023,034 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 186 | 6,656,000 |
# Author : code_marshal
participants,scores=[],[]
for _ in range(int(input())):
x,s_h,u_h,a,b,c,d,e=map(str,input().split())
sm=int(a)+int(b)+int(c)+int(d)+int(e)
participants.insert(0,x)
scores.insert(0,int(s_h)*100-int(u_h)*50+sm)
print (participants[scores.index(max(scores))])
| Title: Room Leader
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Let us remind you part of the rules of Codeforces. The given rules slightly simplified, use the problem statement as a formal document.
In the beginning of the round the contestants are divided into rooms. Each room contains e... | ```python
# Author : code_marshal
participants,scores=[],[]
for _ in range(int(input())):
x,s_h,u_h,a,b,c,d,e=map(str,input().split())
sm=int(a)+int(b)+int(c)+int(d)+int(e)
participants.insert(0,x)
scores.insert(0,int(s_h)*100-int(u_h)*50+sm)
print (participants[scores.index(max(scores))])
... | 3.941102 | MatrixStudio/Codeforces-Python-Submissions |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,630,606,756 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 5 | 296 | 29,286,400 | a, b, n = input().split()
a = int(a)
b = int(b)
n = int(n)
def add(s, c):
global b
global n
if (c!=0 and (c > n or int(s) % b != 0) ):
return
elif (c == n and int(s) % b == 0):
print(s)
exit(0)
for i in range(10):
add( s + str(i), c+1)
add(str(a), ... | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a, b, n = input().split()
a = int(a)
b = int(b)
n = int(n)
def add(s, c):
global b
global n
if (c!=0 and (c > n or int(s) % b != 0) ):
return
elif (c == n and int(s) % b == 0):
print(s)
exit(0)
for i in range(10):
add( s + str(i), c+1)
ad... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
250 | A | Paper Work | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Polycarpus has been working in the analytic department of the "F.R.A.U.D." company for as much as *n* days. Right now his task is to make a series of reports about the company's performance for the last *n* days. We know that the main information in a day report is value *a**i*, the company's profit on the *i*-th day. ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), *n* is the number of days. The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=100), where *a**i* means the company profit on the *i*-th day. It is possible that the company has no days with the negative *a**i*. | Print an integer *k* — the required minimum number of folders. In the second line print a sequence of integers *b*1, *b*2, ..., *b**k*, where *b**j* is the number of day reports in the *j*-th folder.
If there are multiple ways to sort the reports into *k* days, print any of them. | [
"11\n1 2 3 -4 -5 -6 5 -5 -6 -7 6\n",
"5\n0 -1 100 -1 0\n"
] | [
"3\n5 3 3 ",
"1\n5 "
] | Here goes a way to sort the reports from the first sample into three folders:
In the second sample you can put all five reports in one folder. | 500 | [
{
"input": "11\n1 2 3 -4 -5 -6 5 -5 -6 -7 6",
"output": "3\n5 3 3 "
},
{
"input": "5\n0 -1 100 -1 0",
"output": "1\n5 "
},
{
"input": "1\n0",
"output": "1\n1 "
},
{
"input": "1\n-1",
"output": "1\n1 "
},
{
"input": "2\n0 0",
"output": "1\n2 "
},
{
"inp... | 1,591,727,344 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 248 | 0 |
a = int(input())
t = list(map(int,input().split()))
f=[]
p=0
for k in range(a):
if t[k]<0:
p+=1
if p==2:
f.append(k)
p=0
l=[]
if len(f)==1:
print(1)
print(a)
else:
for j in range(len(f)):
if j==... | Title: Paper Work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has been working in the analytic department of the "F.R.A.U.D." company for as much as *n* days. Right now his task is to make a series of reports about the company's performance for the last *n* days. We know tha... | ```python
a = int(input())
t = list(map(int,input().split()))
f=[]
p=0
for k in range(a):
if t[k]<0:
p+=1
if p==2:
f.append(k)
p=0
l=[]
if len(f)==1:
print(1)
print(a)
else:
for j in range(len(f)):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
791 | A | Bear and Big Brother | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's we... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively. | Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob. | [
"4 7\n",
"4 9\n",
"1 1\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Li... | 500 | [
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output... | 1,698,948,275 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 46 | 0 | def years_until_larger(a, b):
years = 0
while a <= b:
a *= 3
b *= 2
years += 1
return years
# Read input
a, b = map(int, input().split())
# Calculate the number of years until Limak becomes larger than Bob
result = years_until_larger(a, b)
# Print the result
print(r... | Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or e... | ```python
def years_until_larger(a, b):
years = 0
while a <= b:
a *= 3
b *= 2
years += 1
return years
# Read input
a, b = map(int, input().split())
# Calculate the number of years until Limak becomes larger than Bob
result = years_until_larger(a, b)
# Print the resul... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
886 | B | Vlad and Cafes | PROGRAMMING | 1,000 | [] | null | null | Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes... | In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, ... | Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. | [
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] | [
"3\n",
"2\n"
] | In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with in... | 1,000 | [
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000... | 1,510,585,566 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 11,571,200 | n = int(input())
stolovie = input().split()
stolovie = stolovie[::-1]
number = 0
for i in stolovie:
if stolovie.index(i) > number:
number = stolovie.index(i)
print(stolovie[number]) | Title: Vlad and Cafes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research... | ```python
n = int(input())
stolovie = input().split()
stolovie = stolovie[::-1]
number = 0
for i in stolovie:
if stolovie.index(i) > number:
number = stolovie.index(i)
print(stolovie[number])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
895 | B | XK Segments | PROGRAMMING | 1,700 | [
"binary search",
"math",
"sortings",
"two pointers"
] | null | null | While Vasya finished eating his piece of pizza, the lesson has already started. For being late for the lesson, the teacher suggested Vasya to solve one interesting problem. Vasya has an array *a* and integer *x*. He should find the number of different ordered pairs of indexes (*i*,<=*j*) such that *a**i*<=≤<=*a**j* and... | The first line contains 3 integers *n*,<=*x*,<=*k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*x*<=≤<=109,<=0<=≤<=*k*<=≤<=109), where *n* is the size of the array *a* and *x* and *k* are numbers from the statement.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | Print one integer — the answer to the problem. | [
"4 2 1\n1 3 5 7\n",
"4 2 0\n5 3 1 7\n",
"5 3 1\n3 3 3 3 3\n"
] | [
"3\n",
"4\n",
"25\n"
] | In first sample there are only three suitable pairs of indexes — (1, 2), (2, 3), (3, 4).
In second sample there are four suitable pairs of indexes(1, 1), (2, 2), (3, 3), (4, 4).
In third sample every pair (*i*, *j*) is suitable, so the answer is 5 * 5 = 25. | 1,000 | [
{
"input": "4 2 1\n1 3 5 7",
"output": "3"
},
{
"input": "4 2 0\n5 3 1 7",
"output": "4"
},
{
"input": "5 3 1\n3 3 3 3 3",
"output": "25"
},
{
"input": "5 3 4\n24 13 1 24 24",
"output": "4"
},
{
"input": "4 2 2\n1 3 5 7",
"output": "2"
},
{
"input": "5... | 1,675,351,650 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | def lowboundsearch(k,x,ai,a,l,h):
while(l<=h):
m=(l+h)//2
c=a[m]//x - (ai-1)//x
if(c<k):
l=m+1
elif(c>k):
h=m-1
else:
if(m>0 and m>l):
if(a[m-1]//x - (ai-1)//x==k):
h=m-1
else:... | Title: XK Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Vasya finished eating his piece of pizza, the lesson has already started. For being late for the lesson, the teacher suggested Vasya to solve one interesting problem. Vasya has an array *a* and integer *x*. He should ... | ```python
def lowboundsearch(k,x,ai,a,l,h):
while(l<=h):
m=(l+h)//2
c=a[m]//x - (ai-1)//x
if(c<k):
l=m+1
elif(c>k):
h=m-1
else:
if(m>0 and m>l):
if(a[m-1]//x - (ai-1)//x==k):
h=m-1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
424 | B | Megacity | PROGRAMMING | 1,200 | [
"binary search",
"greedy",
"implementation",
"sortings"
] | null | null | The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding the boundaries of the city.
The city of Tomsk can be represented as point on the plane with ... | The first line of the input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=103; 1<=≤<=*s*<=<<=106) — the number of locatons around Tomsk city and the population of the city. Then *n* lines follow. The *i*-th line contains three integers — the *x**i* and *y**i* coordinate values of the *i*-th location and the numbe... | In the output, print "-1" (without the quotes), if Tomsk won't be able to become a megacity. Otherwise, in the first line print a single real number — the minimum radius of the circle that the city needs to expand to in order to become a megacity.
The answer is considered correct if the absolute or relative error don'... | [
"4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1\n",
"4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1\n",
"2 1\n1 1 999997\n2 2 1\n"
] | [
"2.8284271\n",
"1.4142136\n",
"-1"
] | none | 1,000 | [
{
"input": "4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1",
"output": "2.8284271"
},
{
"input": "4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1",
"output": "1.4142136"
},
{
"input": "2 1\n1 1 999997\n2 2 1",
"output": "-1"
},
{
"input": "4 999998\n3 3 10\n-3 3 10\n3 -3 10\n-3 -3 10",
"out... | 1,400,263,493 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | def func(x):
global a
y=0
for i in range(x):
y+=a[i][1]
return y
n,s=map(int,input().split())
a=[]
for i in range(n):
x,y,k=map(int,input().split())
a.append([x*x+y*y,k])
if func(n)+s<10**6:
print(-1)
exit(0)
a.sort()
l=0
r=n-1
while l+1<r:
m=(l+r)//2
i... | Title: Megacity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding... | ```python
def func(x):
global a
y=0
for i in range(x):
y+=a[i][1]
return y
n,s=map(int,input().split())
a=[]
for i in range(n):
x,y,k=map(int,input().split())
a.append([x*x+y*y,k])
if func(n)+s<10**6:
print(-1)
exit(0)
a.sort()
l=0
r=n-1
while l+1<r:
m=(l+r)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
424 | A | Squats | PROGRAMMING | 900 | [
"implementation"
] | null | null | Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to stand up and the other hamsters to sit down. In one minute, Pasha can make some hamster ethe... | The first line contains integer *n* (2<=≤<=*n*<=≤<=200; *n* is even). The next line contains *n* characters without spaces. These characters describe the hamsters' position: the *i*-th character equals 'X', if the *i*-th hamster in the row is standing, and 'x', if he is sitting. | In the first line, print a single integer — the minimum required number of minutes. In the second line, print a string that describes the hamsters' position after Pasha makes the required changes. If there are multiple optimal positions, print any of them. | [
"4\nxxXx\n",
"2\nXX\n",
"6\nxXXxXx\n"
] | [
"1\nXxXx\n",
"1\nxX\n",
"0\nxXXxXx\n"
] | none | 500 | [
{
"input": "4\nxxXx",
"output": "1\nXxXx"
},
{
"input": "2\nXX",
"output": "1\nxX"
},
{
"input": "6\nxXXxXx",
"output": "0\nxXXxXx"
},
{
"input": "4\nxXXX",
"output": "1\nxxXX"
},
{
"input": "2\nXx",
"output": "0\nXx"
},
{
"input": "22\nXXxXXxxXxXxXXXX... | 1,607,418,138 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 307,200 | n = int(input())
s = input()
result = ""
a = s.count("X")
b = s.count("x")
print(abs(a-b)//2)
if a>=b:
for i in s:
if i=="X" and a!=n//2:
result+="x"
a-=1
else:
result+=i
else:
for i in s:
if i=="x" and b!=n//2:
result+="X"
b-=1
else:
result+=i
print(result) | Title: Squats
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has many hamsters and he makes them work out. Today, *n* hamsters (*n* is even) came to work out. The hamsters lined up and each hamster either sat down or stood up.
For another exercise, Pasha needs exactly hamsters to ... | ```python
n = int(input())
s = input()
result = ""
a = s.count("X")
b = s.count("x")
print(abs(a-b)//2)
if a>=b:
for i in s:
if i=="X" and a!=n//2:
result+="x"
a-=1
else:
result+=i
else:
for i in s:
if i=="x" and b!=n//2:
result+="X"
b-=1
else:
result+=i
print(result)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,691,978,708 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 46 | 0 | def divide_team(n):
ways = 1
for i in range(2, n):
if n % i == 0:
ways += 1
return ways
print(divide_team(n=int(input()))) | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
def divide_team(n):
ways = 1
for i in range(2, n):
if n % i == 0:
ways += 1
return ways
print(divide_team(n=int(input())))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,689,795,601 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 61 | 0 | s = input()
hel = 'hello'
exp = 0
for i in s:
if i == hel[exp]:
exp+=1
if exp == len(hel):
print("YES")
break
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = input()
hel = 'hello'
exp = 0
for i in s:
if i == hel[exp]:
exp+=1
if exp == len(hel):
print("YES")
break
else:
print("NO")
``` | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
765 | C | Table Tennis Game 2 | PROGRAMMING | 1,200 | [
"math"
] | null | null | Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scores exactly *k* points, the score is reset and a new set begins.
Across all the sets Misha scored *a* poi... | The first line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=109, 0<=≤<=*a*,<=*b*<=≤<=109, *a*<=+<=*b*<=><=0). | If the situation is impossible, print a single number -1. Otherwise, print the maximum possible number of sets. | [
"11 11 5\n",
"11 2 3\n"
] | [
"1\n",
"-1\n"
] | Note that the rules of the game in this problem differ from the real table tennis game, for example, the rule of "balance" (the winning player has to be at least two points ahead to win a set) has no power within the present problem. | 1,250 | [
{
"input": "11 11 5",
"output": "1"
},
{
"input": "11 2 3",
"output": "-1"
},
{
"input": "1 5 9",
"output": "14"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "1 1000000000 1000000000",
"output": "2000000000"
},
{
"input": "2 3 5",
"output": "... | 1,487,107,172 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 77 | 4,608,000 | k,a,b = map(int,input().split())
from math import floor
awin = floor(a/k)
bwin = floor(b/k)
if b%k > awin*(k-1) or a%k > bwin*(k-1) :
print(-1)
else : print(awin + bwin)
| Title: Table Tennis Game 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scor... | ```python
k,a,b = map(int,input().split())
from math import floor
awin = floor(a/k)
bwin = floor(b/k)
if b%k > awin*(k-1) or a%k > bwin*(k-1) :
print(-1)
else : print(awin + bwin)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
182 | D | Common Divisors | PROGRAMMING | 1,400 | [
"brute force",
"hashing",
"implementation",
"math",
"strings"
] | null | null | Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive integer *x* such that if we write out string *a* consecutively *x* times, we get string *b*. For exam... | The first input line contains a non-empty string *s*1.
The second input line contains a non-empty string *s*2.
Lengths of strings *s*1 and *s*2 are positive and do not exceed 105. The strings only consist of lowercase Latin letters. | Print the number of common divisors of strings *s*1 and *s*2. | [
"abcdabcd\nabcdabcdabcdabcd\n",
"aaa\naa\n"
] | [
"2\n",
"1\n"
] | In first sample the common divisors are strings "abcd" and "abcdabcd".
In the second sample the common divisor is a single string "a". String "aa" isn't included in the answer as it isn't a divisor of string "aaa". | 1,000 | [
{
"input": "abcdabcd\nabcdabcdabcdabcd",
"output": "2"
},
{
"input": "aaa\naa",
"output": "1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaa\naaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "3"
},
{
"input": "aaaaaaaaaaaaaa\naaaaaaaaaaaaaa",
"output": "4"
},
{
"input": "a\nb",
... | 1,498,212,044 | 1,844 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 310 | 25,190,400 | from sys import stdin, stdout
def equalsubstr(l1, r1, l2, r2):
return first[l1: r1 + 1] == first[l2: r2 + 1]
first = stdin.readline().strip()
second = stdin.readline().strip()
first, second = min(first, second, key = lambda x: len(x)), max(first, second, key = lambda x: len(x))
n, k = len(first), le... | Title: Common Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive ... | ```python
from sys import stdin, stdout
def equalsubstr(l1, r1, l2, r2):
return first[l1: r1 + 1] == first[l2: r2 + 1]
first = stdin.readline().strip()
second = stdin.readline().strip()
first, second = min(first, second, key = lambda x: len(x)), max(first, second, key = lambda x: len(x))
n, k = len(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
14 | C | Four Segments | PROGRAMMING | 1,700 | [
"brute force",
"constructive algorithms",
"geometry",
"implementation",
"math"
] | C. Four Segments | 2 | 64 | Several months later Alex finally got his brother Bob's creation by post. And now, in his turn, Alex wants to boast about something to his brother. He thought for a while, and came to the conclusion that he has no ready creations, and decided to write a program for rectangles detection. According to his plan, the progr... | The input data contain four lines. Each of these lines contains four integers *x*1, *y*1, *x*2, *y*2 (<=-<=109<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=109) — coordinates of segment's beginning and end positions. The given segments can degenerate into points. | Output the word «YES», if the given four segments form the required rectangle, otherwise output «NO». | [
"1 1 6 1\n1 0 6 0\n6 0 6 1\n1 1 1 0\n",
"0 0 0 3\n2 0 0 0\n2 2 2 0\n0 2 2 2\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "1 1 6 1\n1 0 6 0\n6 0 6 1\n1 1 1 0",
"output": "YES"
},
{
"input": "0 0 0 3\n2 0 0 0\n2 2 2 0\n0 2 2 2",
"output": "NO"
},
{
"input": "0 0 0 2\n2 0 0 0\n2 2 2 0\n0 2 2 2",
"output": "YES"
},
{
"input": "0 0 10 0\n0 0 10 0\n0 0 0 5\n0 0 0 -5",
"output": "NO"
... | 1,579,745,889 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 307,200 | import math
def main():
x = [0] * 4
y = [0] * 4
for i in range(4):
x[i], y[i] = map(int, input().split())
xtot = (x[1] + x[2] + x[3] + x[4]) / 4
ytot = (y[1] + y[2] + y[3] + y[4]) / 4
p1 = math.sqrt(xtot - x[1]) + math.sqrt(ytot - y[1])
p2 = math.sqrt(xtot - x[2]) ... | Title: Four Segments
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Several months later Alex finally got his brother Bob's creation by post. And now, in his turn, Alex wants to boast about something to his brother. He thought for a while, and came to the conclusion that he has no ready creati... | ```python
import math
def main():
x = [0] * 4
y = [0] * 4
for i in range(4):
x[i], y[i] = map(int, input().split())
xtot = (x[1] + x[2] + x[3] + x[4]) / 4
ytot = (y[1] + y[2] + y[3] + y[4]) / 4
p1 = math.sqrt(xtot - x[1]) + math.sqrt(ytot - y[1])
p2 = math.sqrt(xto... | -1 | MatrixStudio/Codeforces-Python-Submissions |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.