contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,696,122,171 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 154 | 614,400 | import sys
import math
from functools import cmp_to_key
from collections import defaultdict
input = sys.stdin.readline
a, b, c = map(int, input().strip().split())
a, b, c = map(round, map(math.sqrt, (a * b / c, a * c / b, b * c / a)))
print(4 * (a + b + c)) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
import sys
import math
from functools import cmp_to_key
from collections import defaultdict
input = sys.stdin.readline
a, b, c = map(int, input().strip().split())
a, b, c = map(round, map(math.sqrt, (a * b / c, a * c / b, b * c / a)))
print(4 * (a + b + c))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,639,190,221 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 77 | 0 | import sys
from math import log
def main():
n, m = map(int, sys.stdin.read().strip().split('\n'))
nm = int(log(m, 2))
if n > nm: return m
return m%2**n
print(main(), sep='\n') | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
import sys
from math import log
def main():
n, m = map(int, sys.stdin.read().strip().split('\n'))
nm = int(log(m, 2))
if n > nm: return m
return m%2**n
print(main(), sep='\n')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
366 | B | Dima and To-do List | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything he does in her presence. After Inna tells him off for something, she goes to another room, walks there in ... | The first line of the input contains two integers *n*,<=*k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103), where *a**i* is the power Inna tells Dima off with if she is present in the room while he is doing the *i*-th task.
It is guaranteed that *n*... | In a single line print the number of the task Dima should start with to get told off with as little power as possible. If there are multiple solutions, print the one with the minimum number of the first task to do. | [
"6 2\n3 2 1 6 5 4\n",
"10 5\n1 3 5 7 9 9 4 1 8 5\n"
] | [
"1\n",
"3\n"
] | Explanation of the first example.
If Dima starts from the first task, Inna tells him off with power 3, then Dima can do one more task (as *k* = 2), then Inna tells him off for the third task with power 1, then she tells him off for the fifth task with power 5. Thus, Dima gets told off with total power 3 + 1 + 5 = 9. I... | 1,000 | [
{
"input": "6 2\n3 2 1 6 5 4",
"output": "1"
},
{
"input": "10 5\n1 3 5 7 9 9 4 1 8 5",
"output": "3"
},
{
"input": "20 4\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "10 10\n8 4 5 7 6 9 2 2 3 5",
"output": "7"
},
{
"input": "50 10\n1 2 3... | 1,533,281,873 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 187 | 6,656,000 |
"""
6 2
3 2 1 6 5 4
"""
n, k = map(int, input().split())
l = [int(x) for x in input().split()]
ans = []
minn = 123456567
key = 0
for i in range(k):
j = i
summ = 0
while j < n:
summ += l[j]
j += k
if(summ < minn):
minn = summ
key = i
print(key + 1) | Title: Dima and To-do List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything h... | ```python
"""
6 2
3 2 1 6 5 4
"""
n, k = map(int, input().split())
l = [int(x) for x in input().split()]
ans = []
minn = 123456567
key = 0
for i in range(k):
j = i
summ = 0
while j < n:
summ += l[j]
j += k
if(summ < minn):
minn = summ
key = i
print(k... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,650,366,219 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 11,468,800 | n = int(input())
a = [0]*(n+1)
d = []
x, y = map(int,input().split())
a[x] = 1
a[y] = -1
for _ in range(n-2) :
x, y = map(int,input().split())
a[x],a[y] = a[x]-a[y],a[y]-a[x]
if a[x] == 0:
d.append((x,y))
while len(d)>0:
s=d
for x,y in s:
a[x],a[y] = a[x]-a[y],a[... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
n = int(input())
a = [0]*(n+1)
d = []
x, y = map(int,input().split())
a[x] = 1
a[y] = -1
for _ in range(n-2) :
x, y = map(int,input().split())
a[x],a[y] = a[x]-a[y],a[y]-a[x]
if a[x] == 0:
d.append((x,y))
while len(d)>0:
s=d
for x,y in s:
a[x],a[y] = a[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
907 | A | Masha and Bears | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 500 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,514,212,507 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 5,529,600 | v1,v2,v3,vm=map(int,input().split())
if vm>2*v3 or 2*vm<v3:
print(-1)
else:
print(2*v1,2*v2,min(2*vm,2*v3)) | Title: Masha and Bears
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son b... | ```python
v1,v2,v3,vm=map(int,input().split())
if vm>2*v3 or 2*vm<v3:
print(-1)
else:
print(2*v1,2*v2,min(2*vm,2*v3))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
845 | A | Chess Tourney | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizer... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100).
The second line contains 2·*n* integers *a*1,<=*a*2,<=... *a*2*n* (1<=≤<=*a**i*<=≤<=1000). | If it's possible to divide all 2·*n* players into two teams with *n* people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO". | [
"2\n1 3 2 4\n",
"1\n3 3\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2\n1 3 2 4",
"output": "YES"
},
{
"input": "1\n3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 2 2 3 3 3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 1 2 2 2 2 2",
"output": "YES"
},
{
"input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000... | 1,503,335,970 | 2,147,483,647 | Python 3 | OK | TESTS | 88 | 77 | 0 | '''
21st august 2017 monday
codeforces 845a
'''
n = int(input())
a = [int(x) for x in input().split(' ')]
a.sort()
out = "NO"
#print(a, i, j)
if max(a[:n]) < min(a[n:]):
out = "YES"
print(out)
| Title: Chess Tourney
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by... | ```python
'''
21st august 2017 monday
codeforces 845a
'''
n = int(input())
a = [int(x) for x in input().split(' ')]
a.sort()
out = "NO"
#print(a, i, j)
if max(a[:n]) < min(a[n:]):
out = "YES"
print(out)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Iahub got lost in a very big desert. The desert can be represented as a *n*<=×<=*n* square matrix, where each cell is a zone of the desert. The cell (*i*,<=*j*) represents the cell at row *i* and column *j* (1<=≤<=*i*,<=*j*<=≤<=*n*). Iahub can go from one cell (*i*,<=*j*) only down or right, that is to cells (*i*<=+<=1... | The first line contains two integers *n* (1<=≤<=*n*<=≤<=109) and *m* (1<=≤<=*m*<=≤<=105). Each of the next *m* lines contains a pair of integers, *x* and *y* (1<=≤<=*x*,<=*y*<=≤<=*n*), representing the coordinates of the volcanoes.
Consider matrix rows are numbered from 1 to *n* from top to bottom, and matrix columns ... | Print one integer, the minimum time in which Iahub can arrive at cell (*n*,<=*n*). If no solution exists (there is no path to the final cell), print -1. | [
"4 2\n1 3\n1 4\n",
"7 8\n1 6\n2 6\n3 5\n3 6\n4 3\n5 1\n5 2\n5 3\n",
"2 2\n1 2\n2 1\n"
] | [
"6\n",
"12\n",
"-1\n"
] | Consider the first sample. A possible road is: (1, 1) → (1, 2) → (2, 2) → (2, 3) → (3, 3) → (3, 4) → (4, 4). | 0 | [] | 1,647,493,090 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 268,390,400 | from collections import deque
def bfs(n, pairs):
queue = deque([(0, 0)])
while queue:
x, y = queue.pop()
if x < n - 1 and (x + 2, y + 1) not in pairs:
queue.append((x + 1, y))
if x + 2 == n and y + 1 == n:
return True
if y < n - 1 ... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub got lost in a very big desert. The desert can be represented as a *n*<=×<=*n* square matrix, where each cell is a zone of the desert. The cell (*i*,<=*j*) represents the cell at row *i* and column *j* (1<=≤<=*i*,<=*j*<=≤<=*n... | ```python
from collections import deque
def bfs(n, pairs):
queue = deque([(0, 0)])
while queue:
x, y = queue.pop()
if x < n - 1 and (x + 2, y + 1) not in pairs:
queue.append((x + 1, y))
if x + 2 == n and y + 1 == n:
return True
if ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
143 | A | Help Vasilisa the Wise 2 | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know what the box's secret is, since she cannot open it again. She hopes that you will help her one more time with tha... | The input contains numbers written on the edges of the lock of the box. The first line contains space-separated integers *r*1 and *r*2 that define the required sums of numbers in the rows of the square. The second line contains space-separated integers *c*1 and *c*2 that define the required sums of numbers in the colum... | Print the scheme of decorating the box with stones: two lines containing two space-separated integers from 1 to 9. The numbers should be pairwise different. If there is no solution for the given lock, then print the single number "-1" (without the quotes).
If there are several solutions, output any. | [
"3 7\n4 6\n5 5\n",
"11 10\n13 8\n5 16\n",
"1 2\n3 4\n5 6\n",
"10 10\n10 10\n10 10\n"
] | [
"1 2\n3 4\n",
"4 7\n9 1\n",
"-1\n",
"-1\n"
] | Pay attention to the last test from the statement: it is impossible to open the box because for that Vasilisa the Wise would need 4 identical gems containing number "5". However, Vasilisa only has one gem with each number from 1 to 9. | 500 | [
{
"input": "3 7\n4 6\n5 5",
"output": "1 2\n3 4"
},
{
"input": "11 10\n13 8\n5 16",
"output": "4 7\n9 1"
},
{
"input": "1 2\n3 4\n5 6",
"output": "-1"
},
{
"input": "10 10\n10 10\n10 10",
"output": "-1"
},
{
"input": "5 13\n8 10\n11 7",
"output": "3 2\n5 8"
... | 1,617,113,659 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 124 | 0 | r1,r2=map(int,input().split(" "))
c1,c2=map(int,input().split(" "))
d1,d2=map(int,input().split(" "))
a=b=c=d=fl=0
li=[1,2,3,4,5,6,7,8,9]
for i in range(1,10):
a=i
b=r1-i
c=c1-a
d=c2-b
#print(a,b,c,d)
if r2<c or r2<d or r2<c+d:
continue
elif a+d!=d1 or b+c!=d2:
... | Title: Help Vasilisa the Wise 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know wha... | ```python
r1,r2=map(int,input().split(" "))
c1,c2=map(int,input().split(" "))
d1,d2=map(int,input().split(" "))
a=b=c=d=fl=0
li=[1,2,3,4,5,6,7,8,9]
for i in range(1,10):
a=i
b=r1-i
c=c1-a
d=c2-b
#print(a,b,c,d)
if r2<c or r2<d or r2<c+d:
continue
elif a+d!=d1 or b+c!=d... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,699,331,629 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | s=input()
s2=s[0].upper()+s[1:]
print(s2) #prints caps letter
| Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
s=input()
s2=s[0].upper()+s[1:]
print(s2) #prints caps letter
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
257 | C | View Angle | PROGRAMMING | 1,800 | [
"brute force",
"geometry",
"math"
] | null | null | Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex at the origin of coordinates and with all mannequins standing inside or on the boarder of this a... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of mannequins.
Next *n* lines contain two space-separated integers each: *x**i*,<=*y**i* (|*x**i*|,<=|*y**i*|<=≤<=1000) — the coordinates of the *i*-th mannequin. It is guaranteed that the origin of the coordinates has no mannequin. It is gu... | Print a single real number — the value of the sought angle in degrees. The answer will be considered valid if the relative or absolute error doesn't exceed 10<=-<=6. | [
"2\n2 0\n0 2\n",
"3\n2 0\n0 2\n-2 2\n",
"4\n2 0\n0 2\n-2 0\n0 -2\n",
"2\n2 1\n1 2\n"
] | [
"90.0000000000\n",
"135.0000000000\n",
"270.0000000000\n",
"36.8698976458\n"
] | Solution for the first sample test is shown below:
Solution for the second sample test is shown below:
Solution for the third sample test is shown below:
Solution for the fourth sample test is shown below: | 1,500 | [
{
"input": "2\n2 0\n0 2",
"output": "90.0000000000"
},
{
"input": "3\n2 0\n0 2\n-2 2",
"output": "135.0000000000"
},
{
"input": "4\n2 0\n0 2\n-2 0\n0 -2",
"output": "270.0000000000"
},
{
"input": "2\n2 1\n1 2",
"output": "36.8698976458"
},
{
"input": "1\n1 1",
... | 1,550,142,896 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 1,060 | 8,704,000 | def fastio():
import sys
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
MOD = 10**9 + 7
I = ... | Title: View Angle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex ... | ```python
def fastio():
import sys
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
MOD = 10**9... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
266 | A | Stones on the Table | PROGRAMMING | 800 | [
"implementation"
] | null | null | There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red... | Print a single integer — the answer to the problem. | [
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] | [
"1\n",
"4\n",
"0\n"
] | none | 500 | [
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "... | 1,694,528,159 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | n = int(input())
x = 0
s = input()
s=str(s)
a = int(len(s))
for i in range(1, a):
if s[i] == s[i-1]:
x+=1
print(x)
| Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row ... | ```python
n = int(input())
x = 0
s = input()
s=str(s)
a = int(len(s))
for i in range(1, a):
if s[i] == s[i-1]:
x+=1
print(x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, al... | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,694,845,498 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 15 | 46 | 0 | dig = [8, 4, 2, 6]
n = int(input())
print(dig[(n%4)-1]) | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one ques... | ```python
dig = [8, 4, 2, 6]
n = int(input())
print(dig[(n%4)-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
771 | A | Bear and Friendship Condition | PROGRAMMING | 1,500 | [
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of members are friends. Of course, a member can't be a friend with themselves.
Let A-B denote that... | The first line of the input contain two integers *n* and *m* (3<=≤<=*n*<=≤<=150<=000, ) — the number of members and the number of pairs of members that are friends.
The *i*-th of the next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*). Members *a**i* and ... | If the given network is reasonable, print "YES" in a single line (without the quotes). Otherwise, print "NO" in a single line (without the quotes). | [
"4 3\n1 3\n3 4\n1 4\n",
"4 4\n3 1\n2 3\n3 4\n1 2\n",
"10 4\n4 3\n5 10\n8 9\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | The drawings below show the situation in the first sample (on the left) and in the second sample (on the right). Each edge represents two members that are friends. The answer is "NO" in the second sample because members (2, 3) are friends and members (3, 4) are friends, while members (2, 4) are not. | 250 | [
{
"input": "4 3\n1 3\n3 4\n1 4",
"output": "YES"
},
{
"input": "4 4\n3 1\n2 3\n3 4\n1 2",
"output": "NO"
},
{
"input": "10 4\n4 3\n5 10\n8 9\n1 2",
"output": "YES"
},
{
"input": "3 2\n1 2\n2 3",
"output": "NO"
},
{
"input": "3 0",
"output": "YES"
},
{
... | 1,610,821,408 | 2,147,483,647 | PyPy 3 | OK | TESTS | 96 | 545 | 44,134,400 | import math,sys,bisect,heapq
from collections import defaultdict,Counter,deque
from itertools import groupby,accumulate
from functools import lru_cache
#sys.setrecursionlimit(200000000)
int1 = lambda x: int(x) - 1
#def input(): return sys.stdin.readline().strip()
input = iter(sys.stdin.buffer.read().decode().spl... | Title: Bear and Friendship Condition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through... | ```python
import math,sys,bisect,heapq
from collections import defaultdict,Counter,deque
from itertools import groupby,accumulate
from functools import lru_cache
#sys.setrecursionlimit(200000000)
int1 = lambda x: int(x) - 1
#def input(): return sys.stdin.readline().strip()
input = iter(sys.stdin.buffer.read().de... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,573,133,029 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | x,y,z=[int(a) for a in input().split()]
n=0
k=0
while (z**(n))>=x and (z**(n))<=y:
k=k+1
print((z**(n)),end=" ")
n=n+1
if k==0:
print("-1") | Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
x,y,z=[int(a) for a in input().split()]
n=0
k=0
while (z**(n))>=x and (z**(n))<=y:
k=k+1
print((z**(n)),end=" ")
n=n+1
if k==0:
print("-1")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
165 | C | Another Problem on Strings | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"dp",
"math",
"strings",
"two pointers"
] | null | null | A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, string "010" has six substrings: "0", "1", "0", "01", "10", "010". Two substrings are considered different if th... | The first line contains the single integer *k* (0<=≤<=*k*<=≤<=106). The second line contains a non-empty binary string *s*. The length of *s* does not exceed 106 characters. | Print the single number — the number of substrings of the given string, containing exactly *k* characters "1".
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"1\n1010\n",
"2\n01010\n",
"100\n01010\n"
] | [
"6\n",
"4\n",
"0\n"
] | In the first sample the sought substrings are: "1", "1", "10", "01", "10", "010".
In the second sample the sought substrings are: "101", "0101", "1010", "01010". | 1,500 | [
{
"input": "1\n1010",
"output": "6"
},
{
"input": "2\n01010",
"output": "4"
},
{
"input": "100\n01010",
"output": "0"
},
{
"input": "0\n01010",
"output": "3"
},
{
"input": "0\n0010100011",
"output": "10"
},
{
"input": "0\n10000",
"output": "10"
}... | 1,618,449,888 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 216 | 0 | k=int(input())
s=input()
n=len(s)
l=[]
cnt=0
for i in range(n):
if s[i]=="1":
l.append(cnt)
cnt=0
else:
cnt+=1
l.append(cnt)
ans=0
for i in range(len(l)):
if i+k<len(l):
ans+=(l[i]+1)*(l[i+k]+1)
print(ans) | Title: Another Problem on Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is binary, if it consists only of characters "0" and "1".
String *v* is a substring of string *w* if it has a non-zero length and can be read starting from some position in string *w*. For example, ... | ```python
k=int(input())
s=input()
n=len(s)
l=[]
cnt=0
for i in range(n):
if s[i]=="1":
l.append(cnt)
cnt=0
else:
cnt+=1
l.append(cnt)
ans=0
for i in range(len(l)):
if i+k<len(l):
ans+=(l[i]+1)*(l[i+k]+1)
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
653 | A | Bear and Three Balls | PROGRAMMING | 900 | [
"brute force",
"implementation",
"sortings"
] | null | null | Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy:
- No two friends can get balls of the same size. - No two friends can get balls of sizes th... | The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball. | Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes). | [
"4\n18 55 16 17\n",
"6\n40 41 43 44 44 44\n",
"8\n5 972 3 4 1 4 970 971\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17.
In the second sample, there is no way to give gifts to three friends without breaking the rules.
In the third sample, there is even more than one way to choose bal... | 500 | [
{
"input": "4\n18 55 16 17",
"output": "YES"
},
{
"input": "6\n40 41 43 44 44 44",
"output": "NO"
},
{
"input": "8\n5 972 3 4 1 4 970 971",
"output": "YES"
},
{
"input": "3\n959 747 656",
"output": "NO"
},
{
"input": "4\n1 2 2 3",
"output": "YES"
},
{
... | 1,651,324,433 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 33 | 93 | 2,252,800 |
def main():
n = int(input())
balls_sizes = [int(x) for x in input().split()]
all_sizes = [False] * 1000
for ball_size in balls_sizes:
all_sizes[ball_size] = True
if ball_size + 1 < 1000 and all_sizes[ball_size + 1]:
if ball_size - 1 >= 0 and all_sizes[ball_size - 1]:
... | Title: Bear and Three Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make fri... | ```python
def main():
n = int(input())
balls_sizes = [int(x) for x in input().split()]
all_sizes = [False] * 1000
for ball_size in balls_sizes:
all_sizes[ball_size] = True
if ball_size + 1 < 1000 and all_sizes[ball_size + 1]:
if ball_size - 1 >= 0 and all_sizes[ball_size ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
886 | A | ACM ICPC | PROGRAMMING | 1,000 | [
"brute force"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 500 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,510,507,772 | 5,072 | Python 3 | OK | TESTS | 53 | 62 | 0 | Q=list(map(int,input().split()))
A=0
for x in range(1,5):
for y in range(x+1,6):
B=0
for i in range(1,6):
if i!=x and i!=y:
B+=Q[i]
if B==Q[0]+Q[x]+Q[y]:
A=1
if A==1:
print('YES')
else:
print('NO')
| Title: ACM ICPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build ... | ```python
Q=list(map(int,input().split()))
A=0
for x in range(1,5):
for y in range(x+1,6):
B=0
for i in range(1,6):
if i!=x and i!=y:
B+=Q[i]
if B==Q[0]+Q[x]+Q[y]:
A=1
if A==1:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
627 | A | XOR Equation | PROGRAMMING | 1,700 | [
"dp",
"math"
] | null | null | Two positive integers *a* and *b* have a sum of *s* and a bitwise XOR of *x*. How many possible values are there for the ordered pair (*a*,<=*b*)? | The first line of the input contains two integers *s* and *x* (2<=≤<=*s*<=≤<=1012, 0<=≤<=*x*<=≤<=1012), the sum and bitwise xor of the pair of positive integers, respectively. | Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0. | [
"9 5\n",
"3 3\n",
"5 2\n"
] | [
"4\n",
"2\n",
"0\n"
] | In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1). | 500 | [
{
"input": "9 5",
"output": "4"
},
{
"input": "3 3",
"output": "2"
},
{
"input": "5 2",
"output": "0"
},
{
"input": "6 0",
"output": "1"
},
{
"input": "549755813887 549755813887",
"output": "549755813886"
},
{
"input": "2 0",
"output": "1"
},
{... | 1,457,175,432 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 0 | def main():
from itertools import product
s, x = map(int, input().split())
res = 0
for astr in product(('0', '1'), repeat=s.bit_length()):
a = int(''.join(astr), 2)
b = s - a
if b > 0 < a and a ^ b == x:
res += 1
print(res)
if __name__ == '__main__':
main()
| Title: XOR Equation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two positive integers *a* and *b* have a sum of *s* and a bitwise XOR of *x*. How many possible values are there for the ordered pair (*a*,<=*b*)?
Input Specification:
The first line of the input contains two integers *s*... | ```python
def main():
from itertools import product
s, x = map(int, input().split())
res = 0
for astr in product(('0', '1'), repeat=s.bit_length()):
a = int(''.join(astr), 2)
b = s - a
if b > 0 < a and a ^ b == x:
res += 1
print(res)
if __name__ == '__main__':
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
552 | B | Vanya and Books | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assigned distinct numbers.
Vanya wants to know how many digits he will have to write down as he labels th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109) — the number of books in the library. | Print the number of digits needed to number all the books. | [
"13\n",
"4\n"
] | [
"17\n",
"4\n"
] | Note to the first test. The books get numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, which totals to 17 digits.
Note to the second sample. The books get numbers 1, 2, 3, 4, which totals to 4 digits. | 1,000 | [
{
"input": "13",
"output": "17"
},
{
"input": "4",
"output": "4"
},
{
"input": "100",
"output": "192"
},
{
"input": "99",
"output": "189"
},
{
"input": "1000000000",
"output": "8888888899"
},
{
"input": "1000000",
"output": "5888896"
},
{
"... | 1,536,521,651 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 109 | 0 | n = int(input())
cont = 0
for c in range(n):
t = str(c)
cont += len(t)
print (cont+1) | Title: Vanya and Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assig... | ```python
n = int(input())
cont = 0
for c in range(n):
t = str(c)
cont += len(t)
print (cont+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,672,324,052 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | num=int(input())
res=list(str(num))
for i,n in enumerate(res):
if 9-int(n)<int(n):
res[i]=9-int(n)
for i,n in enumerate(res):
res[i]=str(n)
print("".join(res))
| Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
num=int(input())
res=list(str(num))
for i,n in enumerate(res):
if 9-int(n)<int(n):
res[i]=9-int(n)
for i,n in enumerate(res):
res[i]=str(n)
print("".join(res))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
842 | B | Gleb And Pizza | PROGRAMMING | 1,100 | [
"geometry"
] | null | null | Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the crust, and he does not really like the crust.
The pizza is a circle of radius *r* and center at the origin. Pizza consists of the main part — circle of radius *r*<=-<=*d* with center at the or... | First string contains two integer numbers *r* and *d* (0<=≤<=*d*<=<<=*r*<=≤<=500) — the radius of pizza and the width of crust.
Next line contains one integer number *n* — the number of pieces of sausage (1<=≤<=*n*<=≤<=105).
Each of next *n* lines contains three integer numbers *x**i*, *y**i* and *r**i* (<=-<=500<... | Output the number of pieces of sausage that lay on the crust. | [
"8 4\n7\n7 8 1\n-7 3 2\n0 2 1\n0 -2 2\n-3 -3 1\n0 6 2\n5 3 1\n",
"10 8\n4\n0 0 9\n0 0 10\n1 0 1\n1 0 2\n"
] | [
"2\n",
"0\n"
] | Below is a picture explaining the first example. Circles of green color denote pieces of sausage lying on the crust. | 1,000 | [
{
"input": "8 4\n7\n7 8 1\n-7 3 2\n0 2 1\n0 -2 2\n-3 -3 1\n0 6 2\n5 3 1",
"output": "2"
},
{
"input": "10 8\n4\n0 0 9\n0 0 10\n1 0 1\n1 0 2",
"output": "0"
},
{
"input": "1 0\n1\n1 1 0",
"output": "0"
},
{
"input": "3 0\n5\n3 0 0\n0 3 0\n-3 0 0\n0 -3 0\n3 0 1",
"output": ... | 1,636,750,502 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 405 | 4,505,600 | import math
rd = list(map(int, input().split(' ')))
r = rd[0]
d = rd[1]
n = int(input())
lista = []
pieces = 0
for idx in range(n):
xyr = list(map(int, input().split(' ')))
x = xyr[0]
y = xyr[1]
rs = xyr[2]
if math.sqrt(x*x+y*y) + rs <= r and math.sqrt(x*x+y*y) - rs >= r-d:
pieces+=1
print(... | Title: Gleb And Pizza
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the crust, and he does not really like the crust.
The pizza is a circle of radius *r* and center... | ```python
import math
rd = list(map(int, input().split(' ')))
r = rd[0]
d = rd[1]
n = int(input())
lista = []
pieces = 0
for idx in range(n):
xyr = list(map(int, input().split(' ')))
x = xyr[0]
y = xyr[1]
rs = xyr[2]
if math.sqrt(x*x+y*y) + rs <= r and math.sqrt(x*x+y*y) - rs >= r-d:
pieces... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,696,399,247 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | str=input()
if len(str) > 1:
if str.upper()==str:
str_final=str.lower()
elif str[1:].upper()==str:
str_final=str.title()
else:
str_final=str
else:
str_final=str
print(str_final)
| Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
str=input()
if len(str) > 1:
if str.upper()==str:
str_final=str.lower()
elif str[1:].upper()==str:
str_final=str.title()
else:
str_final=str
else:
str_final=str
print(str_final)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,692,320,179 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | k, r = map(int, input().split())
c= 1
while True:
if ((c* k) % 10 == 0) or ((c * k) % 10 == r):
break
c += 1
print(c) | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
k, r = map(int, input().split())
c= 1
while True:
if ((c* k) % 10 == 0) or ((c * k) % 10 == r):
break
c += 1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,693,680,953 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 62 | 0 | n = int(input())
count = 0
array = []
array2 = []
for j in range(n):
a, b = map(int, input().split())
array.append(a)
array2.append(b)
for i in range(len(array)):
for k in range(len(array2)):
if array[i] == array2[k]:
count += 1
print(count)
| Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
n = int(input())
count = 0
array = []
array2 = []
for j in range(n):
a, b = map(int, input().split())
array.append(a)
array2.append(b)
for i in range(len(array)):
for k in range(len(array2)):
if array[i] == array2[k]:
count += 1
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
6 | A | Triangle | PROGRAMMING | 900 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allo... | The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks. | Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the s... | [
"4 2 1 3\n",
"7 2 2 4\n",
"3 5 9 1\n"
] | [
"TRIANGLE\n",
"SEGMENT\n",
"IMPOSSIBLE\n"
] | none | 0 | [
{
"input": "4 2 1 3",
"output": "TRIANGLE"
},
{
"input": "7 2 2 4",
"output": "SEGMENT"
},
{
"input": "3 5 9 1",
"output": "IMPOSSIBLE"
},
{
"input": "3 1 5 1",
"output": "IMPOSSIBLE"
},
{
"input": "10 10 10 10",
"output": "TRIANGLE"
},
{
"input": "11 ... | 1,649,826,435 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 512,000 | l=list(map(int,input().split()))
l.sort()
flag=0
for i in range(4):
p=l
a=p[i]
p.remove(p[i])
if p[0]+p[1]>p[2] and p[1]+p[2]>p[0] and p[0]+p[2]>p[1]:
flag=1
break
l.append(a)
l.sort()
if flag==0:
for i in range(2):
if l[i]+l[i+1]==l[i+2]:
f... | Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out o... | ```python
l=list(map(int,input().split()))
l.sort()
flag=0
for i in range(4):
p=l
a=p[i]
p.remove(p[i])
if p[0]+p[1]>p[2] and p[1]+p[2]>p[0] and p[0]+p[2]>p[1]:
flag=1
break
l.append(a)
l.sort()
if flag==0:
for i in range(2):
if l[i]+l[i+1]==l[i+2]:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
909 | C | Python Indentation | PROGRAMMING | 1,800 | [
"dp"
] | null | null | In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An ex... | The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement. | Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7. | [
"4\ns\nf\nf\ns\n",
"4\nf\ns\nf\ns\n"
] | [
"1\n",
"2\n"
] | In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one... | 1,500 | [
{
"input": "4\ns\nf\nf\ns",
"output": "1"
},
{
"input": "4\nf\ns\nf\ns",
"output": "2"
},
{
"input": "156\nf\ns\nf\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\nf\nf\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\ns... | 1,608,972,342 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 307,200 | n=int(input())
lst=[0 for i in range(5005)]
if_f=[0 for i in range(5005)]
f=[0 for i in range(5005)]
mod=10**9+7
c=''
ans=0
mx=0
lst[0]=1
for i in range(1,n+1):
c=input()
if c=='f':
if_f[i]=1
if if_f[i-1]==1:
mx+=1
for j in range(mx,0,-1):
f[j]=lst[j-1]
else:
... | Title: Python Indentation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python... | ```python
n=int(input())
lst=[0 for i in range(5005)]
if_f=[0 for i in range(5005)]
f=[0 for i in range(5005)]
mod=10**9+7
c=''
ans=0
mx=0
lst[0]=1
for i in range(1,n+1):
c=input()
if c=='f':
if_f[i]=1
if if_f[i-1]==1:
mx+=1
for j in range(mx,0,-1):
f[j]=lst[j-1]
else... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
79 | B | Colorful Field | PROGRAMMING | 1,400 | [
"implementation",
"sortings"
] | B. Colorful Field | 2 | 256 | Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
After seeing the field carefully, Ciel found that the crop plants of each cell were planted in f... | In the first line there are four positive integers *n*,<=*m*,<=*k*,<=*t* (1<=≤<=*n*<=≤<=4·104,<=1<=≤<=*m*<=≤<=4·104,<=1<=≤<=*k*<=≤<=103,<=1<=≤<=*t*<=≤<=103), each of which represents the height of the field, the width of the field, the number of waste cells and the number of queries that ask the kind of crop plants in ... | For each query, if the cell is waste, print Waste. Otherwise, print the name of crop plants in the cell: either Carrots or Kiwis or Grapes. | [
"4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1\n"
] | [
"Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots\n"
] | The sample corresponds to the figure in the statement. | 1,000 | [
{
"input": "4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1",
"output": "Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots"
},
{
"input": "2 3 2 2\n1 1\n2 2\n2 1\n2 2",
"output": "Grapes\nWaste"
},
{
"input": "31 31 31 4\n4 9\n16 27\n11 29\n8 28\n11 2\n10 7\n22 6\n1 25\n14 8... | 1,691,694,692 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 92 | 409,600 | # جزرة -> كيوي -> عنب
h,w,waste,qeu = map(int,input().split())
wst = []
clean = ['Carrots','Kiwis','Grapes']
emp = []
for i in range(waste+qeu):
if i<waste:
wst.append(list(map(int,input().split())))
else:
emp.append(list(map(int,input().split())))
wst.sort()
for b in emp:
l,r=0,... | Title: Colorful Field
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
... | ```python
# جزرة -> كيوي -> عنب
h,w,waste,qeu = map(int,input().split())
wst = []
clean = ['Carrots','Kiwis','Grapes']
emp = []
for i in range(waste+qeu):
if i<waste:
wst.append(list(map(int,input().split())))
else:
emp.append(list(map(int,input().split())))
wst.sort()
for b in emp:
... | 3.976237 | MatrixStudio/Codeforces-Python-Submissions |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,658,826,760 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 0 | n = int(input()); m = int(input())
count = 0
k = m
while m != 1:
m//2
count += 1
if count < n:
print(k)
else:
print(k%n) | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
n = int(input()); m = int(input())
count = 0
k = m
while m != 1:
m//2
count += 1
if count < n:
print(k)
else:
print(k%n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
246 | B | Increase and Decrease | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | null | null | Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that Polycarpus performs the following operation multiple times:
- he chooses two elements of the array *a**i... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the array size. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=104) — the original array. | Print a single integer — the maximum number of equal array elements he can get if he performs an arbitrary number of the given operation. | [
"2\n2 1\n",
"3\n1 4 1\n"
] | [
"1\n",
"3\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 4 1",
"output": "3"
},
{
"input": "4\n2 -7 -2 -6",
"output": "3"
},
{
"input": "4\n2 0 -2 -1",
"output": "3"
},
{
"input": "6\n-1 1 0 0 -1 -1",
"output": "5"
},
{
"input": "5\n0 0 0 0 0",
"outp... | 1,671,298,411 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 3,174,400 | n = int(input())
lst = list(map(int, input().split()))
if sum(lst)%n==0:
print(n)
else:
print(n-1) | Title: Increase and Decrease
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that... | ```python
n = int(input())
lst = list(map(int, input().split()))
if sum(lst)%n==0:
print(n)
else:
print(n-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
352 | B | Jeff and Periods | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
- *x* occurs in sequence *a*. - Consider all positions of numbers *x* in the sequence *a* (such *i*, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). The numbers are separated by spaces. | In the first line print integer *t* — the number of valid *x*. On each of the next *t* lines print two integers *x* and *p**x*, where *x* is current suitable value, *p**x* is the common difference between numbers in the progression (if *x* occurs exactly once in the sequence, *p**x* must equal 0). Print the pairs in th... | [
"1\n2\n",
"8\n1 2 1 3 1 2 1 5\n"
] | [
"1\n2 0\n",
"4\n1 2\n2 4\n3 0\n5 0\n"
] | In the first test 2 occurs exactly once in the sequence, ergo *p*<sub class="lower-index">2</sub> = 0. | 1,000 | [
{
"input": "1\n2",
"output": "1\n2 0"
},
{
"input": "8\n1 2 1 3 1 2 1 5",
"output": "4\n1 2\n2 4\n3 0\n5 0"
},
{
"input": "3\n1 10 5",
"output": "3\n1 0\n5 0\n10 0"
},
{
"input": "4\n9 9 3 5",
"output": "3\n3 0\n5 0\n9 1"
},
{
"input": "6\n1 2 2 1 1 2",
"outpu... | 1,630,044,667 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 184 | 20,172,800 | n=int(input())
a=list(map(int,input().split()))
b=sorted(set(a.copy()));dict={};d={}
for x in b:dict[x]=[i for i, y in enumerate(a) if y == x]
for x in dict:
if len(dict[x])>2:
if len(dict[x])//2*(2*dict[x][0]+(len(dict[x])-1)*(dict[x][1]-dict[x][0]))==sum(dict[x]):d[x]=dict[x][1]-dict[x][0]
elif ... | Title: Jeff and Periods
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
-... | ```python
n=int(input())
a=list(map(int,input().split()))
b=sorted(set(a.copy()));dict={};d={}
for x in b:dict[x]=[i for i, y in enumerate(a) if y == x]
for x in dict:
if len(dict[x])>2:
if len(dict[x])//2*(2*dict[x][0]+(len(dict[x])-1)*(dict[x][1]-dict[x][0]))==sum(dict[x]):d[x]=dict[x][1]-dict[x][0]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,647,760,814 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | print(len([i for i in 'QAQ' if i in input()])) | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
print(len([i for i in 'QAQ' if i in input()]))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,466,765,707 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 62 | 0 | inp = input().split()
n = [int(x) for x in inp]
numb = 0
map = {}
mx = 0
for i in n:
if(map.get(i) == None):
map[i] = 1
else:
map[i] += 1
mx = max(mx, map[i])
if(len(map) > 3 or mx < 4):
print(str("Alien"))
else:
if(mx == 6 or len(map) == 2):
print(str("Eleph... | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
inp = input().split()
n = [int(x) for x in inp]
numb = 0
map = {}
mx = 0
for i in n:
if(map.get(i) == None):
map[i] = 1
else:
map[i] += 1
mx = max(mx, map[i])
if(len(map) > 3 or mx < 4):
print(str("Alien"))
else:
if(mx == 6 or len(map) == 2):
print(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | C | Title | PROGRAMMING | 1,600 | [
"expression parsing"
] | C. Title | 2 | 256 | Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a single word containing at least once each of the first *k* Latin letters and not conta... | The first line contains an integer *k* (1<=≤<=*k*<=≤<=26) which is the number of allowed alphabet letters. The second line contains *s* which is the given template. In *s* only the first *k* lowercase letters of Latin alphabet and question marks can be present, the length of *s* is from 1 to 100 characters inclusively. | If there is no solution, print IMPOSSIBLE. Otherwise, a single line should contain the required title, satisfying the given template. The title should be a palindrome and it can only contain the first *k* letters of the Latin alphabet. At that, each of those *k* letters must be present at least once. If there are sever... | [
"3\na?c\n",
"2\na??a\n",
"2\n?b?a\n"
] | [
"IMPOSSIBLE\n",
"abba\n",
"abba\n"
] | none | 1,500 | [
{
"input": "3\na?c",
"output": "IMPOSSIBLE"
},
{
"input": "2\na??a",
"output": "abba"
},
{
"input": "2\n?b?a",
"output": "abba"
},
{
"input": "3\n????",
"output": "IMPOSSIBLE"
},
{
"input": "2\n????",
"output": "abba"
},
{
"input": "1\n?",
"output"... | 1,677,637,693 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | k = int(input())
template = list(input())
l = len(template)
mid = ""
if l % 2 == 1:
l -= 1
mid = template[l // 2]
del template[l // 2]
# x and y is of equal length
def equal(x: list, y: list) -> bool:
for i in range(len(x)):
m = x[i]
n = y[i]
if m == n:
... | Title: Title
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently finished writing a book. Now he faces the problem of giving it the title. Vasya wants the title to be vague and mysterious for his book to be noticeable among others. That's why the title should be represented by a... | ```python
k = int(input())
template = list(input())
l = len(template)
mid = ""
if l % 2 == 1:
l -= 1
mid = template[l // 2]
del template[l // 2]
# x and y is of equal length
def equal(x: list, y: list) -> bool:
for i in range(len(x)):
m = x[i]
n = y[i]
if m == n:... | 0 | MatrixStudio/Codeforces-Python-Submissions |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,685,483,627 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | def f(t):
k = len(t) - min(t.count('1'),t.count('0'))*2
n = int(input())
t = input()
print(f(t)) | Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
def f(t):
k = len(t) - min(t.count('1'),t.count('0'))*2
n = int(input())
t = input()
print(f(t))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,540,290,154 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 307,200 | def miller_rabin_primality_test(n):
def mr_check_one(n):
m = n - 1
n = n - 1
k = 1
while n % 2**k == 0:
m = n // 2**k
k = k + 1
return(m)
def mr_check_two(n, m, a = [2, 3]):
for i in... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
def miller_rabin_primality_test(n):
def mr_check_one(n):
m = n - 1
n = n - 1
k = 1
while n % 2**k == 0:
m = n // 2**k
k = k + 1
return(m)
def mr_check_two(n, m, a = [2, 3]):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morn... | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and ... | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,652,819,463 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 4,300,800 | a,b,c=map(int,input().split())
z=0
for i in range(a,c+1,b):
if i==c or i+1==c:
print('YES')
z=1
break
if z==0:
print('NO')
| Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times... | ```python
a,b,c=map(int,input().split())
z=0
for i in range(a,c+1,b):
if i==c or i+1==c:
print('YES')
z=1
break
if z==0:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,695,385,194 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | import requests
from bs4 import BeautifulSoup
import pandas as pd
# 发送请求获取网页内容
url = 'https://xinghuo.xfyun.cn/desk'
response = requests.get(url)
html = response.text
# 解析网页内容
soup = BeautifulSoup(html, 'html.parser')
table = soup.find('table', {'class': 'table table-striped'})
# 提取表格数据
data = []
for ... | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
import requests
from bs4 import BeautifulSoup
import pandas as pd
# 发送请求获取网页内容
url = 'https://xinghuo.xfyun.cn/desk'
response = requests.get(url)
html = response.text
# 解析网页内容
soup = BeautifulSoup(html, 'html.parser')
table = soup.find('table', {'class': 'table table-striped'})
# 提取表格数据
data ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
285 | A | Slightly Decreasing Permutations | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
The ... | The single line contains two space-separated integers: *n*,<=*k* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*k*<=<<=*n*) — the permutation length and the decreasing coefficient. | In a single line print *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* — the permutation of length *n* with decreasing coefficient *k*.
If there are several permutations that meet this condition, print any of them. It is guaranteed that the permutation with the sought parameters exists. | [
"5 2\n",
"3 0\n",
"3 2\n"
] | [
"1 5 2 4 3\n",
"1 2 3\n",
"3 2 1\n"
] | none | 500 | [
{
"input": "5 2",
"output": "1 5 2 4 3"
},
{
"input": "3 0",
"output": "1 2 3"
},
{
"input": "3 2",
"output": "3 2 1"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output": "1 2"
},
{
"input": "2 1",
"output": "2 1"
},
{
"input":... | 1,689,438,022 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 154 | 9,830,400 | n, k = map(int, input().split())
a = [k + 1]
for i in range(k):
a.append(a[-1] - 1)
if len(a) < n:
a.append(k + 2)
while len(a) < n:
a.append(a[-1] + 1)
print(*a) | Title: Slightly Decreasing Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutat... | ```python
n, k = map(int, input().split())
a = [k + 1]
for i in range(k):
a.append(a[-1] - 1)
if len(a) < n:
a.append(k + 2)
while len(a) < n:
a.append(a[-1] + 1)
print(*a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,559,160,993 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 124 | 0 | import math
n = int(input())
m = int(math.sqrt(2 * n + 0.25) - 0.5)
if n - m*(m+1)//2 == 0:
print(m)
else:
print(n - m*(m+1)//2)
| Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
import math
n = int(input())
m = int(math.sqrt(2 * n + 0.25) - 0.5)
if n - m*(m+1)//2 == 0:
print(m)
else:
print(n - m*(m+1)//2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,691,045,683 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 103 | 1,060 | 16,691,200 | n = int(input())
a = sorted(list(map(int,input().split())))
store = []
for j in range(a[0]):
store.append(0)
i = 1
while i<n:
if a[i] == a[i-1]:
i+=1
else:
for j in range(a[i-1],a[i]):
store.append(i)
i+=1
max_price = len(store) - 1
for _ in range(int(in... | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
n = int(input())
a = sorted(list(map(int,input().split())))
store = []
for j in range(a[0]):
store.append(0)
i = 1
while i<n:
if a[i] == a[i-1]:
i+=1
else:
for j in range(a[i-1],a[i]):
store.append(i)
i+=1
max_price = len(store) - 1
for _ in ra... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
74 | A | Room Leader | PROGRAMMING | 1,000 | [
"implementation"
] | A. Room Leader | 2 | 256 | Let us remind you part of the rules of Codeforces. The given rules slightly simplified, use the problem statement as a formal document.
In the beginning of the round the contestants are divided into rooms. Each room contains exactly *n* participants. During the contest the participants are suggested to solve five prob... | The first line contains an integer *n*, which is the number of contestants in the room (1<=≤<=*n*<=≤<=50). The next *n* lines contain the participants of a given room. The *i*-th line has the format of "*handle**i* *plus**i* *minus**i* *a**i* *b**i* *c**i* *d**i* *e**i*" — it is the handle of a contestant, the number o... | Print on the single line the handle of the room leader. | [
"5\nPetr 3 1 490 920 1000 1200 0\ntourist 2 0 490 950 1100 1400 0\nEgor 7 0 480 900 950 0 1000\nc00lH4x0R 0 10 150 0 0 0 0\nsome_participant 2 1 450 720 900 0 0\n"
] | [
"tourist"
] | The number of points that each participant from the example earns, are as follows:
- Petr — 3860 - tourist — 4140 - Egor — 4030 - c00lH4x0R — - 350 - some_participant — 2220
Thus, the leader of the room is tourist. | 500 | [
{
"input": "5\nPetr 3 1 490 920 1000 1200 0\ntourist 2 0 490 950 1100 1400 0\nEgor 7 0 480 900 950 0 1000\nc00lH4x0R 0 10 150 0 0 0 0\nsome_participant 2 1 450 720 900 0 0",
"output": "tourist"
},
{
"input": "1\nA 0 0 200 0 0 0 0",
"output": "A"
},
{
"input": "2\n12345678901234567890 1 0... | 1,654,625,760 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | n = int(input())
lst = {}
mx = []
for _ in range(n):
nick , plus , minus , a , b , c , d , e = map(str , input().split())
points = (int(a) + int(b) + int(c) + int(d) + int(e) + (int(plus)*100)) - (int(minus)*50)
lst[points] = nick
mx.append(points)
print( lst[max(mx)] ) | Title: Room Leader
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Let us remind you part of the rules of Codeforces. The given rules slightly simplified, use the problem statement as a formal document.
In the beginning of the round the contestants are divided into rooms. Each room contains e... | ```python
n = int(input())
lst = {}
mx = []
for _ in range(n):
nick , plus , minus , a , b , c , d , e = map(str , input().split())
points = (int(a) + int(b) + int(c) + int(d) + int(e) + (int(plus)*100)) - (int(minus)*50)
lst[points] = nick
mx.append(points)
print( lst[max(mx)] )
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,647,425,710 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 62 | 0 | rounds = list()
scores = dict()
maxscr = -1001
for i in range(int(input())):
name, score = input().split()
scores[name] = scores.get(name, 0)+int(score)
rounds.append(name+' '+str(scores[name]))
if maxscr < scores[name]: maxscr = scores[name]
for r in rounds:
name, score = r.split()
if... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
rounds = list()
scores = dict()
maxscr = -1001
for i in range(int(input())):
name, score = input().split()
scores[name] = scores.get(name, 0)+int(score)
rounds.append(name+' '+str(scores[name]))
if maxscr < scores[name]: maxscr = scores[name]
for r in rounds:
name, score = r.split... | 0 | MatrixStudio/Codeforces-Python-Submissions |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,627,076,925 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 6,963,200 | n=int(input(""))
m=list(map(int,input().split()))
for i in range(n-1):
if i == 0:
mi=m[i+1]-m[i]
mx=m[-1]-m[i]
else:
mx=max(abs(m[i]-m[i-1]),abs(m[-1]-m[i]))
mi=min(abs(m[i]-m[i-1]),abs(m[i+1]-m[i]))
print(mi,mx)
print(abs(m[-1]-m[-2]),abs(m[-1]-m[0]))
| Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
n=int(input(""))
m=list(map(int,input().split()))
for i in range(n-1):
if i == 0:
mi=m[i+1]-m[i]
mx=m[-1]-m[i]
else:
mx=max(abs(m[i]-m[i-1]),abs(m[-1]-m[i]))
mi=min(abs(m[i]-m[i-1]),abs(m[i+1]-m[i]))
print(mi,mx)
print(abs(m[-1]-m[-2]),abs(m[-1]-m[0]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
727 | A | Transformation: from A to B | PROGRAMMING | 1,000 | [
"brute force",
"dfs and similar",
"math"
] | null | null | Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - append the digit 1 to the right of current number (that is, replace the number *x* by 10·*x*<=+<=1).
You need to he... | The first line contains two positive integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=109) — the number which Vasily has and the number he wants to have. | If there is no way to get *b* from *a*, print "NO" (without quotes).
Otherwise print three lines. On the first line print "YES" (without quotes). The second line should contain single integer *k* — the length of the transformation sequence. On the third line print the sequence of transformations *x*1,<=*x*2,<=...,<=*x... | [
"2 162\n",
"4 42\n",
"100 40021\n"
] | [
"YES\n5\n2 4 8 81 162 \n",
"NO\n",
"YES\n5\n100 200 2001 4002 40021 \n"
] | none | 1,000 | [
{
"input": "2 162",
"output": "YES\n5\n2 4 8 81 162 "
},
{
"input": "4 42",
"output": "NO"
},
{
"input": "100 40021",
"output": "YES\n5\n100 200 2001 4002 40021 "
},
{
"input": "1 111111111",
"output": "YES\n9\n1 11 111 1111 11111 111111 1111111 11111111 111111111 "
},
... | 1,594,822,775 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 140 | 20,172,800 | a,b=map(int,input().split())
ans=1
ans2=[b]
while b!=a:
if str(b)[-1]=="1":
b=b//10
ans2.append(b)
ans+=1
else:
if b%2==0:
b=b//2
ans2.append(b)
ans+=1
else:
print("NO")
exit()
if b<a:
... | Title: Transformation: from A to B
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - app... | ```python
a,b=map(int,input().split())
ans=1
ans2=[b]
while b!=a:
if str(b)[-1]=="1":
b=b//10
ans2.append(b)
ans+=1
else:
if b%2==0:
b=b//2
ans2.append(b)
ans+=1
else:
print("NO")
exit()
if... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,652,678,375 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 46 | 4,300,800 | s=input()
r=0
p='a'
for i in s:
c=abs(ord(i)-ord(p))
a=26-c
r=r+min(a,c)
p=i
print(r) | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
s=input()
r=0
p='a'
for i in s:
c=abs(ord(i)-ord(p))
a=26-c
r=r+min(a,c)
p=i
print(r)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string *s*.
String *p* is called a substring of string *s* if you can read it starting from some position in the string *s*. For example, string "aba" has six substrings: "a", "b", "a", "ab", "ba", "aba".
Dr. Moriarty plans to take string *s* and c... | The first line contains a non-empty string *s*, consisting of lowercase Latin letters. The second line contains a non-empty string *u*, consisting of lowercase Latin letters. The lengths of both strings are in the range from 1 to 2000, inclusive. | Print the only integer — the minimum number of changes that Dr. Moriarty has to make with the string that you choose. | [
"aaaaa\naaa\n",
"abcabc\nbcd\n",
"abcdef\nklmnopq\n"
] | [
"0\n",
"1\n",
"7\n"
] | In the first sample Moriarty can take any substring of length 3, and it will be equal to the required message *u*, so Moriarty won't have to make any changes.
In the second sample you should take a substring consisting of characters from second to fourth ("bca") or from fifth to sixth ("bc"). Then you will only have t... | 0 | [
{
"input": "aaaaa\naaa",
"output": "0"
},
{
"input": "abcabc\nbcd",
"output": "1"
},
{
"input": "abcdef\nklmnopq",
"output": "7"
},
{
"input": "aaabbbaaa\naba",
"output": "1"
},
{
"input": "a\na",
"output": "0"
},
{
"input": "z\nz",
"output": "0"
... | 1,621,757,652 | 2,532 | Python 3 | RUNTIME_ERROR | TESTS | 11 | 590 | 0 | def question3():
string_we_have = input()
string_to_obtain = input()
max_same = 0
max_at_index = 0
same = 0
for i in range(len(string_we_have)-len(string_to_obtain)+1):
same = 0
for j in range(len(string_to_obtain)):
if string_we_have[i+j] == string_to_obtai... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Moriarty is about to send a message to Sherlock Holmes. He has a string *s*.
String *p* is called a substring of string *s* if you can read it starting from some position in the string *s*. For example, string "aba" has six ... | ```python
def question3():
string_we_have = input()
string_to_obtain = input()
max_same = 0
max_at_index = 0
same = 0
for i in range(len(string_we_have)-len(string_to_obtain)+1):
same = 0
for j in range(len(string_to_obtain)):
if string_we_have[i+j] == strin... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,692,204,373 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 124 | 2,764,800 | x = int(input())
y = input()
array1 = []
array2 = []
array3 = []
one = 0
two = 0
three = 0
count = 1
for c in range(0, len(y), 1):
if y[c] == "1":
one += 1
array1.append(count)
count += 1
if y[c] == "2":
two += 1
array2.append(count)
count += 1
... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
x = int(input())
y = input()
array1 = []
array2 = []
array3 = []
one = 0
two = 0
three = 0
count = 1
for c in range(0, len(y), 1):
if y[c] == "1":
one += 1
array1.append(count)
count += 1
if y[c] == "2":
two += 1
array2.append(count)
cou... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given a tree (a graph with *n* vertices and *n*<=-<=1 edges in which it's possible to reach any vertex from any other vertex using only its edges).
A vertex can be destroyed if this vertex has even degree. If you destroy a vertex, all edges connected to it are also deleted.
Destroy all vertices in the given t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — number of vertices in a tree.
The second line contains *n* integers *p*1,<=*p*2,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=*n*). If *p**i*<=≠<=0 there is an edge between vertices *i* and *p**i*. It is guaranteed that the given graph is a tree. | If it's possible to destroy all vertices, print "YES" (without quotes), otherwise print "NO" (without quotes).
If it's possible to destroy all vertices, in the next *n* lines print the indices of the vertices in order you destroy them. If there are multiple correct answers, print any. | [
"5\n0 1 2 1 2\n",
"4\n0 1 2 3\n"
] | [
"YES\n1\n2\n3\n5\n4\n",
"NO\n"
] | In the first example at first you have to remove the vertex with index 1 (after that, the edges (1, 2) and (1, 4) are removed), then the vertex with index 2 (and edges (2, 3) and (2, 5) are removed). After that there are no edges in the tree, so you can remove remaining vertices in any order. | 0 | [] | 1,524,131,171 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 77 | 7,065,600 | n = int(input())
m = {i: [] for i in range(1, n + 1)}
s = {i: [] for i in range(1, n + 1)}
e = [int(each) for each in input().split()]
def dfs(i):
for e in s[i]:
if (len(s[e]) + len(m[e])) & 1 == 0:
dfs(e)
print(i)
for e in s[i]:
if (len(s[e]) + len(m[e])) & 1 == 1:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a tree (a graph with *n* vertices and *n*<=-<=1 edges in which it's possible to reach any vertex from any other vertex using only its edges).
A vertex can be destroyed if this vertex has even degree. If you destroy ... | ```python
n = int(input())
m = {i: [] for i in range(1, n + 1)}
s = {i: [] for i in range(1, n + 1)}
e = [int(each) for each in input().split()]
def dfs(i):
for e in s[i]:
if (len(s[e]) + len(m[e])) & 1 == 0:
dfs(e)
print(i)
for e in s[i]:
if (len(s[e]) + len(m[e])) & 1 == 1:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
689 | B | Mike and Shortcuts | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"greedy",
"shortest paths"
] | null | null | Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walking from his house located at the intersection number 1 and goes along some sequence of intersections. Wal... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Mike's city intersection.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*i*<=≤<=*a**i*<=≤<=*n* , , describing shortcuts of Mike's city, allowing to walk from intersection *i* to intersection *a**i* using only 1 unit of ... | In the only line print *n* integers *m*1,<=*m*2,<=...,<=*m**n*, where *m**i* denotes the least amount of total energy required to walk from intersection 1 to intersection *i*. | [
"3\n2 2 3\n",
"5\n1 2 3 4 5\n",
"7\n4 4 4 4 7 7 7\n"
] | [
"0 1 2 \n",
"0 1 2 3 4 \n",
"0 1 2 1 2 3 3 \n"
] | In the first sample case desired sequences are:
1: 1; *m*<sub class="lower-index">1</sub> = 0;
2: 1, 2; *m*<sub class="lower-index">2</sub> = 1;
3: 1, 3; *m*<sub class="lower-index">3</sub> = |3 - 1| = 2.
In the second sample case the sequence for any intersection 1 < *i* is always 1, *i* and *m*<sub class="lowe... | 1,000 | [
{
"input": "3\n2 2 3",
"output": "0 1 2 "
},
{
"input": "5\n1 2 3 4 5",
"output": "0 1 2 3 4 "
},
{
"input": "7\n4 4 4 4 7 7 7",
"output": "0 1 2 1 2 3 3 "
},
{
"input": "98\n17 17 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 87 87... | 1,633,281,487 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 483 | 36,249,600 | n = int(input())
x = [int(i) for i in input().split()]
y = [x[i]-1 for i in range(n)]
q = [0]
i = 0
res = [-1] * n
res[0] = 0
while i < len(q):
c = q[i]
i+=1
if c > 0 and res[c-1] == -1:
res[c-1] = res[c] + 1
q.append(c-1)
if c < n-1 and res[c+1] ==- 1:
res[c+... | Title: Mike and Shortcuts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walkin... | ```python
n = int(input())
x = [int(i) for i in input().split()]
y = [x[i]-1 for i in range(n)]
q = [0]
i = 0
res = [-1] * n
res[0] = 0
while i < len(q):
c = q[i]
i+=1
if c > 0 and res[c-1] == -1:
res[c-1] = res[c] + 1
q.append(c-1)
if c < n-1 and res[c+1] ==- 1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
195 | A | Let's Watch Football | PROGRAMMING | 1,000 | [
"binary search",
"brute force",
"math"
] | null | null | Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the si... | The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. T... | Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses. | [
"4 1 1\n",
"10 3 2\n",
"13 12 1\n"
] | [
"3\n",
"5\n",
"1\n"
] | In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watch... | 500 | [
{
"input": "4 1 1",
"output": "3"
},
{
"input": "10 3 2",
"output": "5"
},
{
"input": "13 12 1",
"output": "1"
},
{
"input": "2 1 3",
"output": "3"
},
{
"input": "6 2 4",
"output": "8"
},
{
"input": "5 2 1",
"output": "2"
},
{
"input": "2 1... | 1,573,411,725 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 248 | 0 | a, b, c = map(int, input().split())
l = 0
r = c*a//b
while r-l > 1:
cur = (l+r)//2
if (c+cur)*b >= c*a:
r = cur
else:
l = cur
print(r)
| Title: Let's Watch Football
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn ... | ```python
a, b, c = map(int, input().split())
l = 0
r = c*a//b
while r-l > 1:
cur = (l+r)//2
if (c+cur)*b >= c*a:
r = cur
else:
l = cur
print(r)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
46 | A | Ball Game | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | A. Ball Game | 2 | 256 | A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think of the children as numbered with numbers from 1 to *n* clockwise and the child number 1 is... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) which indicates the number of kids in the circle. | In the single line print *n*<=-<=1 numbers which are the numbers of children who will get the ball after each throw. Separate the numbers by spaces. | [
"10\n",
"3\n"
] | [
"2 4 7 1 6 2 9 7 6\n",
"2 1\n"
] | none | 0 | [
{
"input": "10",
"output": "2 4 7 1 6 2 9 7 6"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "4",
"output": "2 4 3"
},
{
"input": "5",
"output": "2 4 2 1"
},
{
"input": "6",
"output": "2 4 1 5 4"
},
{
"input": "7",
"output": "2 4 7 4 2 1"
},
... | 1,657,375,074 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 186 | 0 | n=int(input())
a=list(range(1,n+1))*(n+1)
t=0
for i in range(1,n):
t+=i
print(a[t],end=' ') | Title: Ball Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think... | ```python
n=int(input())
a=list(range(1,n+1))*(n+1)
t=0
for i in range(1,n):
t+=i
print(a[t],end=' ')
``` | 3.9535 | MatrixStudio/Codeforces-Python-Submissions |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,691,622,045 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 128 | 62 | 0 | import sys
def check(k, n_n, l):
if k > l or k == 0:
return n_n
else:
return n_n + 1
input = sys.stdin.readline
if __name__ == "__main__":
n, m = map(int, input().split())
n_n = n // 5; mm = m // 5
ln = n % 5; lm = m % 5
sum_ = 0
if ln == 0 and lm == 0:
... | Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
import sys
def check(k, n_n, l):
if k > l or k == 0:
return n_n
else:
return n_n + 1
input = sys.stdin.readline
if __name__ == "__main__":
n, m = map(int, input().split())
n_n = n // 5; mm = m // 5
ln = n % 5; lm = m % 5
sum_ = 0
if ln == 0 and... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. O... | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line do... | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,694,270,990 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 92 | 0 | compiedName=input()+input()
pile=input()
if len(compiedName) != len(pile):
print('NO')
else:
for i in range(len(compiedName)):
if pile.find(compiedName[i])>-1:
pile=pile.replace(compiedName[i],'-',1)
if i==len(compiedName)-1:
print('YES')
else:
... | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's nam... | ```python
compiedName=input()+input()
pile=input()
if len(compiedName) != len(pile):
print('NO')
else:
for i in range(len(compiedName)):
if pile.find(compiedName[i])>-1:
pile=pile.replace(compiedName[i],'-',1)
if i==len(compiedName)-1:
print('YES')
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, al... | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,696,639,005 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 24,985,600 | a=int(input())
b=pow(1378,a)
print(b%10) | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one ques... | ```python
a=int(input())
b=pow(1378,a)
print(b%10)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
821 | E | Okabe and El Psy Kongroo | PROGRAMMING | 2,100 | [
"dp",
"matrices"
] | null | null | Okabe likes to take walks but knows that spies from the Organization could be anywhere; that's why he wants to know how many different walks he can take in his city safely. Okabe's city can be represented as all points (*x*,<=*y*) such that *x* and *y* are non-negative. Okabe starts at the origin (point (0,<=0)), and n... | The first line of input contains the integers *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1018) — the number of segments and the destination *x* coordinate.
The next *n* lines contain three space-separated integers *a**i*, *b**i*, and *c**i* (0<=≤<=*a**i*<=<<=*b**i*<=≤<=1018, 0<=≤<=*c**i*<=≤<=15) — the left and r... | Print the number of walks satisfying the conditions, modulo 1000000007 (109<=+<=7). | [
"1 3\n0 3 3\n",
"2 6\n0 3 0\n3 10 2\n"
] | [
"4\n",
"4\n"
] | The graph above corresponds to sample 1. The possible walks are:
- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7fcce410dbd2cf4e427a6b50e0f159b7ce538901.png" style="max-width: 100.0%;max-height: 100.0%;"/> - <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/... | 2,500 | [
{
"input": "1 3\n0 3 3",
"output": "4"
},
{
"input": "2 6\n0 3 0\n3 10 2",
"output": "4"
},
{
"input": "2 3\n0 2 13\n2 3 11",
"output": "4"
},
{
"input": "2 9\n0 8 0\n8 10 10",
"output": "1"
},
{
"input": "1 1\n0 3 9",
"output": "1"
},
{
"input": "3 8\... | 1,692,345,891 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | print("_RANDOM_GUESS_1692345891.186964")# 1692345891.1869802 | Title: Okabe and El Psy Kongroo
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Okabe likes to take walks but knows that spies from the Organization could be anywhere; that's why he wants to know how many different walks he can take in his city safely. Okabe's city can be represented as al... | ```python
print("_RANDOM_GUESS_1692345891.186964")# 1692345891.1869802
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
535 | B | Tavas and SaDDas | PROGRAMMING | 1,100 | [
"bitmasks",
"brute force",
"combinatorics",
"implementation"
] | null | null | Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphones and told him: "If you solve the following problem, I'll return it to you."
The problem is:
You ar... | The first and only line of input contains a lucky number *n* (1<=≤<=*n*<=≤<=109). | Print the index of *n* among all lucky numbers. | [
"4\n",
"7\n",
"77\n"
] | [
"1\n",
"2\n",
"6\n"
] | none | 1,000 | [
{
"input": "4",
"output": "1"
},
{
"input": "7",
"output": "2"
},
{
"input": "77",
"output": "6"
},
{
"input": "4",
"output": "1"
},
{
"input": "474744",
"output": "83"
},
{
"input": "777774",
"output": "125"
},
{
"input": "447",
"outpu... | 1,565,597,744 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 140 | 1,228,800 | n = input()
d = len(n)
m = 1
base = ["4","7"]
l = []
ans = 0
while (m < d):
ans += 2**m
m += 1
for i in range(d-1):
base = list(map(lambda x: "4" + x, base)) + list(map(lambda x: "7" + x, base))
ans += (base.index(str(n)) + 1)
print(ans) | Title: Tavas and SaDDas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphone... | ```python
n = input()
d = len(n)
m = 1
base = ["4","7"]
l = []
ans = 0
while (m < d):
ans += 2**m
m += 1
for i in range(d-1):
base = list(map(lambda x: "4" + x, base)) + list(map(lambda x: "7" + x, base))
ans += (base.index(str(n)) + 1)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | As a German University in Cairo (GUC) student and a basketball player, Herr Wafa was delighted once he heard the news. GUC is finally participating in the Annual Basketball Competition (ABC).
A team is to be formed of *n* players, all of which are GUC students. However, the team might have players belonging to differ... | The first line contains three integers *n*, *m* and *h* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=1000,<=1<=≤<=*h*<=≤<=*m*) — the number of players on the team, the number of departments in GUC and Herr Wafa's department, correspondingly.
The second line contains a single-space-separated list of *m* integers *s**i* (1<=≤<=*... | Print the probability that Herr Wafa will have at least one teammate from his department. If there is not enough basketball players in GUC to participate in ABC, print -1. The answer will be accepted if it has absolute or relative error not exceeding 10<=-<=6. | [
"3 2 1\n2 1\n",
"3 2 1\n1 1\n",
"3 2 1\n2 2\n"
] | [
"1\n",
"-1\n",
"0.666667\n"
] | In the first example all 3 players (2 from department 1 and 1 from department 2) must be chosen for the team. Both players from Wafa's departments will be chosen, so he's guaranteed to have a teammate from his department.
In the second example, there are not enough players.
In the third example, there are three possi... | 0 | [
{
"input": "3 2 1\n2 1",
"output": "1"
},
{
"input": "3 2 1\n1 1",
"output": "-1"
},
{
"input": "3 2 1\n2 2",
"output": "0.666667"
},
{
"input": "3 2 1\n1 2",
"output": "0.000000"
},
{
"input": "6 5 3\n5 2 3 10 5",
"output": "0.380435"
},
{
"input": "7... | 1,676,659,511 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 77 | 2,867,200 | from sys import stdin,stdout
input = stdin.readline
from math import sqrt,gcd
# from collections import Counter
# from heapq import heapify,heappop,heappush
# from time import time
# from bisect import bisect, bisect_left
def NcR(n, r, p):
num = den = 1
for i in range(r):
num = (num *... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As a German University in Cairo (GUC) student and a basketball player, Herr Wafa was delighted once he heard the news. GUC is finally participating in the Annual Basketball Competition (ABC).
A team is to be formed of *n* player... | ```python
from sys import stdin,stdout
input = stdin.readline
from math import sqrt,gcd
# from collections import Counter
# from heapq import heapify,heappop,heappush
# from time import time
# from bisect import bisect, bisect_left
def NcR(n, r, p):
num = den = 1
for i in range(r):
nu... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,587,251,298 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 310 | 1,331,200 | from fractions import Fraction
a,b=map(int,input().strip().split())
if max(a,b)==1:
print('1/1')
elif max(a,b)==6:
print("0/1")
elif max(a,b)==0:
print('0/0')
else:
c=6-max(a,b)+1
print(Fraction(c,6)) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
from fractions import Fraction
a,b=map(int,input().strip().split())
if max(a,b)==1:
print('1/1')
elif max(a,b)==6:
print("0/1")
elif max(a,b)==0:
print('0/0')
else:
c=6-max(a,b)+1
print(Fraction(c,6))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,630,062,278 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 530 | 33,280,000 | n=int(input())
a=list(map(int,input().split()))
m=int(input())
q=list(map(int,input().split()))
s1=s2=0
b={}
for i in range(n):
b[a[i]]=i+1
for i in range(m):
k=b[q[i]]
s1+=k
s2+=n-k+1
print(s1,s2)
| Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
n=int(input())
a=list(map(int,input().split()))
m=int(input())
q=list(map(int,input().split()))
s1=s2=0
b={}
for i in range(n):
b[a[i]]=i+1
for i in range(m):
k=b[q[i]]
s1+=k
s2+=n-k+1
print(s1,s2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,692,358,723 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n=int(input("enter number of friends"))
h=int(input("enter height of fence"))
l=[]
for i in range(n) :
a=int(input("enter height of friend"))
l.append(a)
w=0
for a in l:
if a<=h:
w+=1
else:
w+=2
print(w)
| Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n=int(input("enter number of friends"))
h=int(input("enter height of fence"))
l=[]
for i in range(n) :
a=int(input("enter height of friend"))
l.append(a)
w=0
for a in l:
if a<=h:
w+=1
else:
w+=2
print(w)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
161 | D | Distance in Tree | PROGRAMMING | 1,800 | [
"dfs and similar",
"dp",
"trees"
] | null | null | A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices and a positive number *k*. Find the number of distinct pairs of the vertices which have a distance of ex... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50000, 1<=≤<=*k*<=≤<=500) — the number of vertices and the required distance between the vertices.
Next *n*<=-<=1 lines describe the edges as "*a**i* *b**i*" (without the quotes) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), where *a**i* and *b**i* ... | Print a single integer — the number of distinct pairs of the tree's vertices which have a distance of exactly *k* between them.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"5 2\n1 2\n2 3\n3 4\n2 5\n",
"5 3\n1 2\n2 3\n3 4\n4 5\n"
] | [
"4\n",
"2\n"
] | In the first sample the pairs of vertexes at distance 2 from each other are (1, 3), (1, 5), (3, 5) and (2, 4). | 2,000 | [
{
"input": "5 2\n1 2\n2 3\n3 4\n2 5",
"output": "4"
},
{
"input": "5 3\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10 1\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "9"
},
{
"input": "10 2\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "10"
... | 1,630,944,360 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 107,417,600 | import sys
import threading
from collections import defaultdict
sys.setrecursionlimit(10**6)
def findCountOfNodes(n, k, adj):
dist = [[0]*(k+1) for i in range(n)]
def findDistance(node, par):
dist[node][0] = 1
for ad in adj[node]:
if ad != par:
findDistance(ad, n... | Title: Distance in Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices an... | ```python
import sys
import threading
from collections import defaultdict
sys.setrecursionlimit(10**6)
def findCountOfNodes(n, k, adj):
dist = [[0]*(k+1) for i in range(n)]
def findDistance(node, par):
dist[node][0] = 1
for ad in adj[node]:
if ad != par:
findDist... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
421 | A | Pasha and Hamsters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Pasha has two hamsters: Arthur and Alexander. Pasha put *n* apples in front of them. Pasha knows which apples Arthur likes. Similarly, Pasha knows which apples Alexander likes. Pasha doesn't want any conflict between the hamsters (as they may like the same apple), so he decided to distribute the apples between the hams... | The first line contains integers *n*, *a*, *b* (1<=≤<=*n*<=≤<=100; 1<=≤<=*a*,<=*b*<=≤<=*n*) — the number of apples Pasha has, the number of apples Arthur likes and the number of apples Alexander likes, correspondingly.
The next line contains *a* distinct integers — the numbers of the apples Arthur likes. The next line... | Print *n* characters, each of them equals either 1 or 2. If the *i*-h character equals 1, then the *i*-th apple should be given to Arthur, otherwise it should be given to Alexander. If there are multiple correct answers, you are allowed to print any of them. | [
"4 2 3\n1 2\n2 3 4\n",
"5 5 2\n3 4 1 2 5\n2 3\n"
] | [
"1 1 2 2\n",
"1 1 1 1 1\n"
] | none | 500 | [
{
"input": "4 2 3\n1 2\n2 3 4",
"output": "1 1 2 2"
},
{
"input": "5 5 2\n3 4 1 2 5\n2 3",
"output": "1 1 1 1 1"
},
{
"input": "100 69 31\n1 3 4 5 6 7 8 9 10 11 12 14 15 16 17 18 19 20 21 24 26 27 29 31 37 38 39 40 44 46 48 49 50 51 53 55 56 57 58 59 60 61 63 64 65 66 67 68 69 70 71 72 7... | 1,573,082,172 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 155 | 0 | # cf 421 A 800
n, a, b = map(int, input().split())
Ar = [*map(int, input().split())]
Al = [*map(int, input().split())]
Ar.sort()
Al.sort()
r, l = 0, 0
O = []
for i in range(1, n + 1):
if r < len(Ar) and Ar[r] == i:
O.append(1)
elif l < len(Al) and Al[l] == i:
O.append(2)
while r < len(Ar) a... | Title: Pasha and Hamsters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has two hamsters: Arthur and Alexander. Pasha put *n* apples in front of them. Pasha knows which apples Arthur likes. Similarly, Pasha knows which apples Alexander likes. Pasha doesn't want any conflict between... | ```python
# cf 421 A 800
n, a, b = map(int, input().split())
Ar = [*map(int, input().split())]
Al = [*map(int, input().split())]
Ar.sort()
Al.sort()
r, l = 0, 0
O = []
for i in range(1, n + 1):
if r < len(Ar) and Ar[r] == i:
O.append(1)
elif l < len(Al) and Al[l] == i:
O.append(2)
while r <... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,695,781,813 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 5,632,000 | def check_hello(word):
hello = "hello"
i = 0
j = 0
for i in range(len(word)):
if j < len(hello) and word[i] == hello[j]:
j += 1
return j == len(hello)
word = input()
if check_hello(word):
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def check_hello(word):
hello = "hello"
i = 0
j = 0
for i in range(len(word)):
if j < len(hello) and word[i] == hello[j]:
j += 1
return j == len(hello)
word = input()
if check_hello(word):
print("YES")
else:
print("NO")
``` | 3.96651 | MatrixStudio/Codeforces-Python-Submissions |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should b... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right aft... | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,632,000,124 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 358 | 14,438,400 | n = int(input())
s = list(map(int, input().strip().split()))
tar = n
vis = [0] * (n + 1)
for i in range(n):
vis[s[i]] = 1
f = ""
for j in range(tar, 0, -1):
if vis[j] == 1:
f += (str(j) + " ")
else:
tar = j
break
print(f) | Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents sh... | ```python
n = int(input())
s = list(map(int, input().strip().split()))
tar = n
vis = [0] * (n + 1)
for i in range(n):
vis[s[i]] = 1
f = ""
for j in range(tar, 0, -1):
if vis[j] == 1:
f += (str(j) + " ")
else:
tar = j
break
print(f)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
192 | A | Funky Numbers | PROGRAMMING | 1,300 | [
"binary search",
"brute force",
"implementation"
] | null | null | As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.
A well-known hipster Andrew adores everything funky and c... | The first input line contains an integer *n* (1<=≤<=*n*<=≤<=109). | Print "YES" (without the quotes), if *n* can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes). | [
"256\n",
"512\n"
] | [
"YES\n",
"NO\n"
] | In the first sample number <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/92095692c6ea93e9e3b837a0408ba7543549d5b2.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample number 512 can not be represented as a sum of two triangular numbers. | 500 | [
{
"input": "256",
"output": "YES"
},
{
"input": "512",
"output": "NO"
},
{
"input": "80",
"output": "NO"
},
{
"input": "828",
"output": "YES"
},
{
"input": "6035",
"output": "NO"
},
{
"input": "39210",
"output": "YES"
},
{
"input": "79712",... | 1,628,694,278 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 122 | 9,523,200 | #بِسْمِ ٱللَّٰهِ ٱلرَّحْمَٰنِ ٱلرَّحِيمِ
n=int(input())
st=set([p*(p+1)/2 for p in range(1,55000)]) #adding so called triangular numbers
if(i for i in st if n-i in st):
print("YES")
else:
print("NO") | Title: Funky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are represent... | ```python
#بِسْمِ ٱللَّٰهِ ٱلرَّحْمَٰنِ ٱلرَّحِيمِ
n=int(input())
st=set([p*(p+1)/2 for p in range(1,55000)]) #adding so called triangular numbers
if(i for i in st if n-i in st):
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
1,009 | B | Minimum Ternary String | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa).
For e... | The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). | Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). | [
"100210\n",
"11222121\n",
"20\n"
] | [
"001120\n",
"11112222\n",
"20\n"
] | none | 0 | [
{
"input": "100210",
"output": "001120"
},
{
"input": "11222121",
"output": "11112222"
},
{
"input": "20",
"output": "20"
},
{
"input": "1002",
"output": "0012"
},
{
"input": "10",
"output": "01"
},
{
"input": "000021",
"output": "000012"
},
{
... | 1,531,688,660 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 155 | 512,000 | s = input()
a = ''
b = ''
for i in s:
if i == '1':
a += i
else:
b += i
n = b.find('2')
if n == -1:
ans = b + a
else:
ans = b[:n] + a + b[n:]
print(ans)
| Title: Minimum Ternary String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) ... | ```python
s = input()
a = ''
b = ''
for i in s:
if i == '1':
a += i
else:
b += i
n = b.find('2')
if n == -1:
ans = b + a
else:
ans = b[:n] + a + b[n:]
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,597,008,995 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 171 | 21,606,400 | n,x=[int(i) for i in input().split()]
sad=0
d=x
sad=0
for g in range(n):
l=input().split()
if "+" in l[0]:
d+=int(l[1])
else:
if d>int(l[1]):
d-=int(l[1])
else:
sad+=1
print(d,sad)
| Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n,x=[int(i) for i in input().split()]
sad=0
d=x
sad=0
for g in range(n):
l=input().split()
if "+" in l[0]:
d+=int(l[1])
else:
if d>int(l[1]):
d-=int(l[1])
else:
sad+=1
print(d,sad)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
352 | A | Jeff and Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?
Jeff must make the number without leading zero. At that, we assume that numbe... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (*a**i*<==<=0 or *a**i*<==<=5). Number *a**i* represents the digit that is written on the *i*-th card. | In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1. | [
"4\n5 0 5 0\n",
"11\n5 5 5 5 5 5 5 5 0 5 5\n"
] | [
"0\n",
"5555555550\n"
] | In the first test you can make only one number that is a multiple of 90 — 0.
In the second test you can make number 5555555550, it is a multiple of 90. | 500 | [
{
"input": "4\n5 0 5 0",
"output": "0"
},
{
"input": "11\n5 5 5 5 5 5 5 5 0 5 5",
"output": "5555555550"
},
{
"input": "7\n5 5 5 5 5 5 5",
"output": "-1"
},
{
"input": "1\n5",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "11\n5 0 5 ... | 1,675,686,362 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | input()
a=input()
if a.count('5')//9 and '0' in a: print('5'*((a.count('5')//9)*9)+'0')
elif '0' in a: print(0)
else: print(-1) | Title: Jeff and Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make fr... | ```python
input()
a=input()
if a.count('5')//9 and '0' in a: print('5'*((a.count('5')//9)*9)+'0')
elif '0' in a: print(0)
else: print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero,... | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,696,402,986 | 2,147,483,647 | Python 3 | OK | TESTS | 11 | 46 | 0 | no, k = map(int, input().split())
while k > 0:
if no % 10 == 0:
no //= 10
else:
no -= 1
k -= 1
print(no) | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit ... | ```python
no, k = map(int, input().split())
while k > 0:
if no % 10 == 0:
no //= 10
else:
no -= 1
k -= 1
print(no)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,689,909,529 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 | n, h = map(int,input().split())
friends = list(map(int,input().split()))
ans = 0
for each in friends:
if each>h:
ans+=2
else:
ans+=1
print(ans) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n, h = map(int,input().split())
friends = list(map(int,input().split()))
ans = 0
for each in friends:
if each>h:
ans+=2
else:
ans+=1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
903 | D | Almost Difference | PROGRAMMING | 2,200 | [
"data structures",
"math"
] | null | null | Let's denote a function
You are given an array *a* consisting of *n* integers. You have to calculate the sum of *d*(*a**i*,<=*a**j*) over all pairs (*i*,<=*j*) such that 1<=≤<=*i*<=≤<=*j*<=≤<=*n*. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=200000) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109) — elements of the array. | Print one integer — the sum of *d*(*a**i*,<=*a**j*) over all pairs (*i*,<=*j*) such that 1<=≤<=*i*<=≤<=*j*<=≤<=*n*. | [
"5\n1 2 3 1 3\n",
"4\n6 6 5 5\n",
"4\n6 6 4 4\n"
] | [
"4\n",
"0\n",
"-8\n"
] | In the first example:
1. *d*(*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>) = 0; 1. *d*(*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">3</sub>) = 2; 1. *d*(*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">4</sub>) = 0; 1. *d*(*a*<sub class="lower-index">... | 0 | [
{
"input": "5\n1 2 3 1 3",
"output": "4"
},
{
"input": "4\n6 6 5 5",
"output": "0"
},
{
"input": "4\n6 6 4 4",
"output": "-8"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1000000000",
"output": "0"
},
{
"input": "2\n1 1000000000",
"output"... | 1,633,424,944 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 1 | 124 | 22,220,800 | n = int(input())
a = list(map(int, input().split()))
cnt = {}
for x in range(n):
cnt[x-1] = 0
cnt[x+1] = 0
cnt[x] = 0
ans = 0
for i in range(n):
ans += i*a[i] - (n-i-1)*a[i]
ans -= cnt[a[i]-1]
ans += cnt[a[i]+1]
cnt[a[i]] = cnt[a[i]] + 1
print(ans) | Title: Almost Difference
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's denote a function
You are given an array *a* consisting of *n* integers. You have to calculate the sum of *d*(*a**i*,<=*a**j*) over all pairs (*i*,<=*j*) such that 1<=≤<=*i*<=≤<=*j*<=≤<=*n*.
Input Specifica... | ```python
n = int(input())
a = list(map(int, input().split()))
cnt = {}
for x in range(n):
cnt[x-1] = 0
cnt[x+1] = 0
cnt[x] = 0
ans = 0
for i in range(n):
ans += i*a[i] - (n-i-1)*a[i]
ans -= cnt[a[i]-1]
ans += cnt[a[i]+1]
cnt[a[i]] = cnt[a[i]] + 1
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
126 | B | Password | PROGRAMMING | 1,700 | [
"binary search",
"dp",
"hashing",
"string suffix structures",
"strings"
] | null | null | Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the... | You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters. | Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes. | [
"fixprefixsuffix\n",
"abcdabc\n"
] | [
"fix",
"Just a legend"
] | none | 1,000 | [
{
"input": "fixprefixsuffix",
"output": "fix"
},
{
"input": "abcdabc",
"output": "Just a legend"
},
{
"input": "qwertyqwertyqwerty",
"output": "qwerty"
},
{
"input": "papapapap",
"output": "papap"
},
{
"input": "aaaaaaaaaa",
"output": "aaaaaaaa"
},
{
"... | 1,616,157,656 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 25 | 2,000 | 2,355,200 | s=input()
ans=[]
for i in range(len(s)-2,-1,-1):
if s[i]==s[-1]:
if s[-(i+1):]==s[:i+1]:
ans.append(s[:i+1])
s=s[1:-1]
f=0
#print(ans)
for i in ans:
if i in s:
print(i)
f=1
break
if f==0:
print('Just a legend') | Title: Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carve... | ```python
s=input()
ans=[]
for i in range(len(s)-2,-1,-1):
if s[i]==s[-1]:
if s[-(i+1):]==s[:i+1]:
ans.append(s[:i+1])
s=s[1:-1]
f=0
#print(ans)
for i in ans:
if i in s:
print(i)
f=1
break
if f==0:
print('Just a legend')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
148 | C | Terse princess | PROGRAMMING | 1,700 | [
"constructive algorithms",
"greedy"
] | null | null | «Next please», — the princess called and cast an estimating glance at the next groom.
The princess intends to choose the most worthy groom, this is, the richest one. Whenever she sees a groom who is more rich than each of the previous ones, she says a measured «Oh...». Whenever the groom is richer than all previous on... | The only line of input data contains three integer numbers *n*,<=*a* and *b* (1<=≤<=*n*<=≤<=100,<=0<=≤<=*a*,<=*b*<=≤<=15,<=*n*<=><=*a*<=+<=*b*), separated with single spaces. | Output any sequence of integers *t*1,<=*t*2,<=...,<=*t**n*, where *t**i* (1<=≤<=*t**i*<=≤<=50000) is the fortune of *i*-th groom, that satisfies the given constraints. If no sequence exists that would satisfy all the requirements, output a single number -1. | [
"10 2 3\n",
"5 0 0\n"
] | [
"5 1 3 6 16 35 46 4 200 99",
"10 10 6 6 5"
] | Let's have a closer look at the answer for the first sample test.
- The princess said «Oh...» (highlighted in bold): 5 1 3 6 16 35 46 4 200 99. - The princess exclaimed «Wow!» (highlighted in bold): 5 1 3 6 16 35 46 4 200 99. | 1,000 | [
{
"input": "10 2 3",
"output": "1 2 4 8 9 10 10 10 10 10 "
},
{
"input": "5 0 0",
"output": "1 1 1 1 1 "
},
{
"input": "5 2 2",
"output": "1 2 4 5 6 "
},
{
"input": "6 2 2",
"output": "1 2 4 5 6 6 "
},
{
"input": "10 9 0",
"output": "-1"
},
{
"input": ... | 1,687,874,786 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n, a, b = map(int, input().split())
if (1 << b) + a > 50000 or (n > 1 and a == n - 1):
print("-1")
else:
t = [0] * n
t[0] = 1
sz = 1
for i in range(b):
t[sz] = t[sz-1] * 2 + 1
sz += 1
for i in range(n - a - b - 1):
t[sz] = 1
sz += 1
... | Title: Terse princess
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«Next please», — the princess called and cast an estimating glance at the next groom.
The princess intends to choose the most worthy groom, this is, the richest one. Whenever she sees a groom who is more rich than each ... | ```python
n, a, b = map(int, input().split())
if (1 << b) + a > 50000 or (n > 1 and a == n - 1):
print("-1")
else:
t = [0] * n
t[0] = 1
sz = 1
for i in range(b):
t[sz] = t[sz-1] * 2 + 1
sz += 1
for i in range(n - a - b - 1):
t[sz] = 1
sz ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
769 | C | Cycle In Maze | PROGRAMMING | 1,700 | [
"*special",
"dfs and similar",
"graphs",
"greedy",
"shortest paths"
] | null | null | The Robot is in a rectangular maze of size *n*<=×<=*m*. Each cell of the maze is either empty or occupied by an obstacle. The Robot can move between neighboring cells on the side left (the symbol "L"), right (the symbol "R"), up (the symbol "U") or down (the symbol "D"). The Robot can move to the cell only if it is emp... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=106) — the size of the maze and the length of the cycle.
Each of the following *n* lines contains *m* symbols — the description of the maze. If the symbol equals to "." the current cell is empty. If the symbol equals to "... | Print the lexicographically minimum Robot's way with the length exactly *k*, which starts and ends in the cell where initially Robot is. If there is no such way, print "IMPOSSIBLE"(without quotes). | [
"2 3 2\n.**\nX..\n",
"5 6 14\n..***.\n*...X.\n..*...\n..*.**\n....*.\n",
"3 3 4\n***\n*X*\n***\n"
] | [
"RL\n",
"DLDDLLLRRRUURU\n",
"IMPOSSIBLE\n"
] | In the first sample two cyclic ways for the Robot with the length 2 exist — "UD" and "RL". The second cycle is lexicographically less.
In the second sample the Robot should move in the following way: down, left, down, down, left, left, left, right, right, right, up, up, right, up.
In the third sample the Robot can'... | 1,500 | [
{
"input": "2 3 2\n.**\nX..",
"output": "RL"
},
{
"input": "5 6 14\n..***.\n*...X.\n..*...\n..*.**\n....*.",
"output": "DLDDLLLRRRUURU"
},
{
"input": "3 3 4\n***\n*X*\n***",
"output": "IMPOSSIBLE"
},
{
"input": "1 1 1\nX",
"output": "IMPOSSIBLE"
},
{
"input": "1 2... | 1,597,381,677 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 93 | 307,200 | def bfs(i,j): #x,y
global s,path,k
if s[i+1][j]=="." and [i+1,j] not in path:
path.append([i+1,j])
if len(path)>=(k+1)//2: calpath(path)
bfs(i+1,j)
elif s[i][j-1]=="." and [i,j-1] not in path:
path.append([i,j-1])
if len(path)>=(k+1)//2: calpath(path)
bfs(i,j-1)
elif s[i][j+1]=="." and [i,j+1]... | Title: Cycle In Maze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Robot is in a rectangular maze of size *n*<=×<=*m*. Each cell of the maze is either empty or occupied by an obstacle. The Robot can move between neighboring cells on the side left (the symbol "L"), right (the symbol "... | ```python
def bfs(i,j): #x,y
global s,path,k
if s[i+1][j]=="." and [i+1,j] not in path:
path.append([i+1,j])
if len(path)>=(k+1)//2: calpath(path)
bfs(i+1,j)
elif s[i][j-1]=="." and [i,j-1] not in path:
path.append([i,j-1])
if len(path)>=(k+1)//2: calpath(path)
bfs(i,j-1)
elif s[i][j+1]=="." a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,569,651,463 | 163 | Python 3 | OK | TESTS | 34 | 218 | 0 | #!/usr/bin/python3
n = int(input())
a = []
b = []
for i in range(n):
ap, bp = map(int, input().split())
a.append(ap)
b.append(bp)
ok = [False] * n
for i in range(n):
for j in range(n):
if b[i] == a[j] and i != j:
ok[j] = True
print(ok.count(False))
| Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th... | ```python
#!/usr/bin/python3
n = int(input())
a = []
b = []
for i in range(n):
ap, bp = map(int, input().split())
a.append(ap)
b.append(bp)
ok = [False] * n
for i in range(n):
for j in range(n):
if b[i] == a[j] and i != j:
ok[j] = True
print(ok.count(False))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
578 | B | "Or" Game | PROGRAMMING | 1,700 | [
"brute force",
"greedy"
] | null | null | You are given *n* numbers *a*1,<=*a*2,<=...,<=*a**n*. You can perform at most *k* operations. For each operation you can multiply one of the numbers by *x*. We want to make as large as possible, where denotes the bitwise OR.
Find the maximum possible value of after performing at most *k* operations optimally. | The first line contains three integers *n*, *k* and *x* (1<=≤<=*n*<=≤<=200<=000, 1<=≤<=*k*<=≤<=10, 2<=≤<=*x*<=≤<=8).
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109). | Output the maximum value of a bitwise OR of sequence elements after performing operations. | [
"3 1 2\n1 1 1\n",
"4 2 3\n1 2 4 8\n"
] | [
"3\n",
"79\n"
] | For the first sample, any possible choice of doing one operation will result the same three numbers 1, 1, 2 so the result is <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1ee73b671ed4bc53f2f96ed1a85fd98388e1712b.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
For the second sample... | 500 | [
{
"input": "3 1 2\n1 1 1",
"output": "3"
},
{
"input": "4 2 3\n1 2 4 8",
"output": "79"
},
{
"input": "2 1 2\n12 9",
"output": "30"
},
{
"input": "2 1 2\n12 7",
"output": "31"
},
{
"input": "3 1 3\n3 2 0",
"output": "11"
},
{
"input": "5 10 8\n10000000... | 1,693,745,458 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 12 | 140 | 24,883,200 | import sys
input = lambda: sys.stdin.readline().rstrip()
import math
from heapq import heappush , heappop
from collections import defaultdict,deque,Counter
from bisect import *
N,K,X = map(int, input().split())
A = list(map(int, input().split()))
A.sort()
if K==1:
ans = 0
cnt = [0]*32
for a ... | Title: "Or" Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* numbers *a*1,<=*a*2,<=...,<=*a**n*. You can perform at most *k* operations. For each operation you can multiply one of the numbers by *x*. We want to make as large as possible, where denotes the bitwise OR... | ```python
import sys
input = lambda: sys.stdin.readline().rstrip()
import math
from heapq import heappush , heappop
from collections import defaultdict,deque,Counter
from bisect import *
N,K,X = map(int, input().split())
A = list(map(int, input().split()))
A.sort()
if K==1:
ans = 0
cnt = [0]*32
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many w... | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,622,144,157 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 62 | 0 | a,b=map(int,input().split())
c1=c2=c3=0
for i in range(1,7):
p=abs(a-i)
q=abs(b-i)
if p<q:
c1+=1
elif q<p:
c2+=1
else:
c3+=1
print(c1,c3,c2) | Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same diff... | ```python
a,b=map(int,input().split())
c1=c2=c3=0
for i in range(1,7):
p=abs(a-i)
q=abs(b-i)
if p<q:
c1+=1
elif q<p:
c2+=1
else:
c3+=1
print(c1,c3,c2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,660,070,120 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | import sys
s = sys.stdin.read()
for item in s:
my_list = s.split("\n")
print(my_list[0][::-1]) | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
import sys
s = sys.stdin.read()
for item in s:
my_list = s.split("\n")
print(my_list[0][::-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
597 | B | Restaurant | PROGRAMMING | 1,600 | [
"dp",
"greedy",
"sortings"
] | null | null | A restaurant received *n* orders for the rental. Each rental order reserve the restaurant for a continuous period of time, the *i*-th order is characterized by two time values — the start time *l**i* and the finish time *r**i* (*l**i*<=≤<=*r**i*).
Restaurant management can accept and reject orders. What is the maximal... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=5·105) — number of orders. The following *n* lines contain integer values *l**i* and *r**i* each (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109). | Print the maximal number of orders that can be accepted. | [
"2\n7 11\n4 7\n",
"5\n1 2\n2 3\n3 4\n4 5\n5 6\n",
"6\n4 8\n1 5\n4 7\n2 5\n1 3\n6 8\n"
] | [
"1\n",
"3\n",
"2\n"
] | none | 1,000 | [
{
"input": "2\n7 11\n4 7",
"output": "1"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5\n5 6",
"output": "3"
},
{
"input": "6\n4 8\n1 5\n4 7\n2 5\n1 3\n6 8",
"output": "2"
},
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "2\n4 6\n4 8",
"output": "1"
},
{
"inp... | 1,649,527,698 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 2,401 | 36,966,400 | n = int(input())
l = []
for i in range(n):
a,b = map(int,input().split())
l.append((b,a))
l.sort()
ans = 0
cur = -1
for i in l:
if cur < i[1]:
ans += 1
cur = i[0]
print(ans)
| Title: Restaurant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A restaurant received *n* orders for the rental. Each rental order reserve the restaurant for a continuous period of time, the *i*-th order is characterized by two time values — the start time *l**i* and the finish time *r**... | ```python
n = int(input())
l = []
for i in range(n):
a,b = map(int,input().split())
l.append((b,a))
l.sort()
ans = 0
cur = -1
for i in l:
if cur < i[1]:
ans += 1
cur = i[0]
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,570,886,442 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 109 | 0 | n= int(input())
mat=[]
for i in range(n):
temp= input()
temp= list(temp)
temp.append('0')
mat.append(temp)
mat.append(['0']*(n+1))
count=0
if mat[0][0]=='o':
count+=1
for i in range(n):
for j in range(n):
if i==0:
if mat[i][j+1]=='o':
count+=1... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n= int(input())
mat=[]
for i in range(n):
temp= input()
temp= list(temp)
temp.append('0')
mat.append(temp)
mat.append(['0']*(n+1))
count=0
if mat[0][0]=='o':
count+=1
for i in range(n):
for j in range(n):
if i==0:
if mat[i][j+1]=='o':
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,564,940,091 | 2,147,483,647 | PyPy 3 | OK | TESTS | 21 | 140 | 0 | a = int(input())
b = list(map(int, input().split()))
r = b.count(0)
while r>0:
b.remove(0)
r-=1
t = set(b)
print(len(t))
| Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
a = int(input())
b = list(map(int, input().split()))
r = b.count(0)
while r>0:
b.remove(0)
r-=1
t = set(b)
print(len(t))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
44 | C | Holidays | PROGRAMMING | 1,300 | [
"implementation"
] | C. Holidays | 2 | 256 | School holidays come in Berland. The holidays are going to continue for *n* days. The students of school №*N* are having the time of their lives and the IT teacher Marina Sergeyevna, who has spent all the summer busy checking the BSE (Berland State Examination) results, has finally taken a vacation break! Some people a... | The first input line contains two numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of days in Berland holidays and the number of people in charge of the watering respectively. The next *m* lines contain the description of the duty schedule. Each line contains two integers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=*... | Print "OK" (without quotes), if the schedule does not contain mistakes. Otherwise you have to find the minimal number of a day when the flowers will not be watered or will be watered multiple times, and output two integers — the day number and the number of times the flowers will be watered that day. | [
"10 5\n1 2\n3 3\n4 6\n7 7\n8 10\n",
"10 5\n1 2\n2 3\n4 5\n7 8\n9 10\n",
"10 5\n1 2\n3 3\n5 7\n7 7\n7 10\n"
] | [
"OK\n",
"2 2\n",
"4 0\n"
] | Keep in mind that in the second sample the mistake occurs not only on the second day, but also on the sixth day, when nobody waters the flowers. However, you have to print the second day, i.e. the day with the minimal number. | 0 | [
{
"input": "10 5\n1 2\n3 3\n4 6\n7 7\n8 10",
"output": "OK"
},
{
"input": "10 5\n1 2\n2 3\n4 5\n7 8\n9 10",
"output": "2 2"
},
{
"input": "10 5\n1 2\n3 3\n5 7\n7 7\n7 10",
"output": "4 0"
},
{
"input": "5 4\n1 1\n2 2\n3 3\n4 5",
"output": "OK"
},
{
"input": "100 5... | 1,689,369,267 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | print("_RANDOM_GUESS_1689369267.106425")# 1689369267.106438 | Title: Holidays
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
School holidays come in Berland. The holidays are going to continue for *n* days. The students of school №*N* are having the time of their lives and the IT teacher Marina Sergeyevna, who has spent all the summer busy checking the ... | ```python
print("_RANDOM_GUESS_1689369267.106425")# 1689369267.106438
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
676 | A | Nicholas and Permutation | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Nicholas has an array *a* that contains *n* distinct integers from 1 to *n*. In other words, Nicholas has a permutation of size *n*.
Nicholas want the minimum element (integer 1) and the maximum element (integer *n*) to be as far as possible from each other. He wants to perform exactly one swap in order to maximize th... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100) — the size of the permutation.
The second line of the input contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*), where *a**i* is equal to the element at the *i*-th position. | Print a single integer — the maximum possible distance between the minimum and the maximum elements Nicholas can achieve by performing exactly one swap. | [
"5\n4 5 1 3 2\n",
"7\n1 6 5 3 4 7 2\n",
"6\n6 5 4 3 2 1\n"
] | [
"3\n",
"6\n",
"5\n"
] | In the first sample, one may obtain the optimal answer by swapping elements 1 and 2.
In the second sample, the minimum and the maximum elements will be located in the opposite ends of the array if we swap 7 and 2.
In the third sample, the distance between the minimum and the maximum elements is already maximum possib... | 500 | [
{
"input": "5\n4 5 1 3 2",
"output": "3"
},
{
"input": "7\n1 6 5 3 4 7 2",
"output": "6"
},
{
"input": "6\n6 5 4 3 2 1",
"output": "5"
},
{
"input": "2\n1 2",
"output": "1"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n2 3 1",
"output": "... | 1,676,056,676 | 2,147,483,647 | Python 3 | OK | TESTS | 159 | 46 | 0 | def result(l):
m = l.index(max(l))
n = l.index(min(l))
diff = abs(m-n)
# if (m==0) | (m==len(l)-1) | (n==0) | (n==(len(l)-1)):
# return len(l)-1
if m < n :
if len(l)-m-1 <= n :
temp = l[m]
l[m]= l[0]
l[0] = temp
... | Title: Nicholas and Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nicholas has an array *a* that contains *n* distinct integers from 1 to *n*. In other words, Nicholas has a permutation of size *n*.
Nicholas want the minimum element (integer 1) and the maximum element (integ... | ```python
def result(l):
m = l.index(max(l))
n = l.index(min(l))
diff = abs(m-n)
# if (m==0) | (m==len(l)-1) | (n==0) | (n==(len(l)-1)):
# return len(l)-1
if m < n :
if len(l)-m-1 <= n :
temp = l[m]
l[m]= l[0]
l[... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
132 | C | Logo Turtle | PROGRAMMING | 1,800 | [
"dp"
] | null | null | A lot of people associate Logo programming language with turtle graphics. In this case the turtle moves along the straight line and accepts commands "T" ("turn around") and "F" ("move 1 unit forward").
You are given a list of commands that will be given to the turtle. You have to change exactly *n* commands from the l... | The first line of input contains a string *commands* — the original list of commands. The string *commands* contains between 1 and 100 characters, inclusive, and contains only characters "T" and "F".
The second line contains an integer *n* (1<=≤<=*n*<=≤<=50) — the number of commands you have to change in the list. | Output the maximum distance from the starting point to the ending point of the turtle's path. The ending point of the turtle's path is turtle's coordinate after it follows all the commands of the modified list. | [
"FT\n1\n",
"FFFTFFF\n2\n"
] | [
"2\n",
"6\n"
] | In the first example the best option is to change the second command ("T") to "F" — this way the turtle will cover a distance of 2 units.
In the second example you have to change two commands. One of the ways to cover maximal distance of 6 units is to change the fourth command and first or last one. | 1,500 | [
{
"input": "FT\n1",
"output": "2"
},
{
"input": "FFFTFFF\n2",
"output": "6"
},
{
"input": "F\n1",
"output": "0"
},
{
"input": "FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF\n50",
"output": "100"
},
{
"input": ... | 1,451,873,445 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 122 | 0 | #!/usr/bin/env python3
LMT = 105
def dfs(dre, pos, i, cn):
if cn < 0:
return 0
if i >= len(work):
return 0 if cn > 0 else abs(pos)
if dp[dre][pos + 100][i][cn] != -1:
return dp[dre][pos + 100][i][cn]
mv = 1 if dre else -1
x = dfs(dre, pos + mv, i + 1, cn - (work[i] != "... | Title: Logo Turtle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people associate Logo programming language with turtle graphics. In this case the turtle moves along the straight line and accepts commands "T" ("turn around") and "F" ("move 1 unit forward").
You are given a list... | ```python
#!/usr/bin/env python3
LMT = 105
def dfs(dre, pos, i, cn):
if cn < 0:
return 0
if i >= len(work):
return 0 if cn > 0 else abs(pos)
if dp[dre][pos + 100][i][cn] != -1:
return dp[dre][pos + 100][i][cn]
mv = 1 if dre else -1
x = dfs(dre, pos + mv, i + 1, cn - (wo... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
202 | A | LLPS | PROGRAMMING | 800 | [
"binary search",
"bitmasks",
"brute force",
"greedy",
"implementation",
"strings"
] | null | null | This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string *s* consisting of lowercase English letters only. Find its lexicographically largest palindromic subsequence.
We'll call a non-empty string *s*[*p*1*p*2... *p**k*] = *s**p*1*... | The only input line contains a non-empty string *s* consisting of lowercase English letters only. Its length does not exceed 10. | Print the lexicographically largest palindromic subsequence of string *s*. | [
"radar\n",
"bowwowwow\n",
"codeforces\n",
"mississipp\n"
] | [
"rr\n",
"wwwww\n",
"s\n",
"ssss\n"
] | Among all distinct subsequences of string "radar" the following ones are palindromes: "a", "d", "r", "aa", "rr", "ada", "rar", "rdr", "raar" and "radar". The lexicographically largest of them is "rr". | 500 | [
{
"input": "radar",
"output": "rr"
},
{
"input": "bowwowwow",
"output": "wwwww"
},
{
"input": "codeforces",
"output": "s"
},
{
"input": "mississipp",
"output": "ssss"
},
{
"input": "tourist",
"output": "u"
},
{
"input": "romka",
"output": "r"
},
... | 1,660,327,330 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 92 | 0 | s = list(input())
s.sort()
print(s[len(s)-1]*s.count(s[len(s)-1])) | Title: LLPS
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem's actual name, "Lexicographically Largest Palindromic Subsequence" is too long to fit into the page headline.
You are given string *s* consisting of lowercase English letters only. Find its lexicographically largest ... | ```python
s = list(input())
s.sort()
print(s[len(s)-1]*s.count(s[len(s)-1]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
6 | A | Triangle | PROGRAMMING | 900 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allo... | The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks. | Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the s... | [
"4 2 1 3\n",
"7 2 2 4\n",
"3 5 9 1\n"
] | [
"TRIANGLE\n",
"SEGMENT\n",
"IMPOSSIBLE\n"
] | none | 0 | [
{
"input": "4 2 1 3",
"output": "TRIANGLE"
},
{
"input": "7 2 2 4",
"output": "SEGMENT"
},
{
"input": "3 5 9 1",
"output": "IMPOSSIBLE"
},
{
"input": "3 1 5 1",
"output": "IMPOSSIBLE"
},
{
"input": "10 10 10 10",
"output": "TRIANGLE"
},
{
"input": "11 ... | 1,691,398,092 | 2,147,483,647 | Python 3 | OK | TESTS | 83 | 92 | 0 | l = [int(x) for x in input().split()]
l = l + [l[0]] + [l[1]]
s = 0
t = 0
for i in range(4):
if abs(l[i] - l[i + 1]) < l[i + 2] < (l[i] + l[i + 1]):
t = 1
break
elif abs(l[i] - l[i + 1]) <= l[i + 2] < (l[i] + l[i + 1]) or \
abs(l[i] - l[i + 1]) < l[i + 2] <= (l[i] + l[i + 1]):
... | Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out o... | ```python
l = [int(x) for x in input().split()]
l = l + [l[0]] + [l[1]]
s = 0
t = 0
for i in range(4):
if abs(l[i] - l[i + 1]) < l[i + 2] < (l[i] + l[i + 1]):
t = 1
break
elif abs(l[i] - l[i + 1]) <= l[i + 2] < (l[i] + l[i + 1]) or \
abs(l[i] - l[i + 1]) < l[i + 2] <= (l[i] + l[... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
586 | A | Alena's Schedule | PROGRAMMING | 900 | [
"implementation"
] | null | null | Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic hours (an academic hour is equal to 45 minutes).
The University works in such a way that every day it... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of lessons at the university.
The second line contains *n* numbers *a**i* (0<=≤<=*a**i*<=≤<=1). Number *a**i* equals 0, if Alena doesn't have the *i*-th pairs, otherwise it is equal to 1. Numbers *a*1,<=*a*2,<=...,<=*a**n* ar... | Print a single number — the number of pairs during which Alena stays at the university. | [
"5\n0 1 0 1 1\n",
"7\n1 0 1 0 0 1 0\n",
"1\n0\n"
] | [
"4\n",
"4\n",
"0\n"
] | In the first sample Alena stays at the university from the second to the fifth pair, inclusive, during the third pair she will be it the university waiting for the next pair.
In the last sample Alena doesn't have a single pair, so she spends all the time at home. | 500 | [
{
"input": "5\n0 1 0 1 1",
"output": "4"
},
{
"input": "7\n1 0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "1"
},
{
... | 1,504,210,255 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 62 | 0 | from sys import stdin
x = [int(i) for i in stdin.read().rstrip().split()]
n = x[0]
sch = x[1:]
count = 0
for i in range(n):
if sch[i] == 1:
count += 1
if sch[i] == 0 and i > 0 and i < n-1 and (sch[i-1] == 1 and sch[i+1] == 1):
count += 1
print(count)
| Title: Alena's Schedule
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic ... | ```python
from sys import stdin
x = [int(i) for i in stdin.read().rstrip().split()]
n = x[0]
sch = x[1:]
count = 0
for i in range(n):
if sch[i] == 1:
count += 1
if sch[i] == 0 and i > 0 and i < n-1 and (sch[i-1] == 1 and sch[i+1] == 1):
count += 1
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be part of the square, i.e. if one square is completely inside another, they intersect. If the ... | The input data consists of two lines, one for each square, both containing 4 pairs of integers. Each pair represents coordinates of one vertex of the square. Coordinates within each line are either in clockwise or counterclockwise order.
The first line contains the coordinates of the square with sides parallel to the ... | Print "Yes" if squares intersect, otherwise print "No".
You can print each letter in any case (upper or lower). | [
"0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1\n",
"0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1\n",
"6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the second square lies entirely within the first square, so they do intersect.
In the second sample squares do not have any points in common.
Here are images corresponding to the samples: | 0 | [
{
"input": "0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1",
"output": "NO"
},
{
"input": "6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n8 4 4 8 8 12 12 8",
"output": "YES"
},
... | 1,594,686,403 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 108 | 6,963,200 | # -*- coding: utf-8 -*-
"""
Created on Sun Jul 12 08:50:06 2020
@author: Dark Soul
"""
def isinside(x1,y1,x3,y3,x5,y5):
if (x5>=x1 and x5<=x3) and (y5>=y1 and y5<=y3):
return 1
else:
return 0
def line(x1,y1,x2,y2):
if x1-x2==0:
return ['c',x1]
else:
m=(y... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be pa... | ```python
# -*- coding: utf-8 -*-
"""
Created on Sun Jul 12 08:50:06 2020
@author: Dark Soul
"""
def isinside(x1,y1,x3,y3,x5,y5):
if (x5>=x1 and x5<=x3) and (y5>=y1 and y5<=y3):
return 1
else:
return 0
def line(x1,y1,x2,y2):
if x1-x2==0:
return ['c',x1]
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
864 | A | Fair Game | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | Petya and Vasya decided to play a game. They have *n* cards (*n* is an even number). A single integer is written on each card.
Before the game Petya will choose an integer and after that Vasya will choose another integer (different from the number that Petya chose). During the game each player takes all the cards with... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=100) — number of cards. It is guaranteed that *n* is an even number.
The following *n* lines contain a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (one integer per line, 1<=≤<=*a**i*<=≤<=100) — numbers written on the *n* cards. | If it is impossible for Petya and Vasya to choose numbers in such a way that the game will be fair, print "NO" (without quotes) in the first line. In this case you should not print anything more.
In the other case print "YES" (without quotes) in the first line. In the second line print two distinct integers — number t... | [
"4\n11\n27\n27\n11\n",
"2\n6\n6\n",
"6\n10\n20\n30\n20\n10\n20\n",
"6\n1\n1\n2\n2\n3\n3\n"
] | [
"YES\n11 27\n",
"NO\n",
"NO\n",
"NO\n"
] | In the first example the game will be fair if, for example, Petya chooses number 11, and Vasya chooses number 27. Then the will take all cards — Petya will take cards 1 and 4, and Vasya will take cards 2 and 3. Thus, each of them will take exactly two cards.
In the second example fair game is impossible because the nu... | 500 | [
{
"input": "4\n11\n27\n27\n11",
"output": "YES\n11 27"
},
{
"input": "2\n6\n6",
"output": "NO"
},
{
"input": "6\n10\n20\n30\n20\n10\n20",
"output": "NO"
},
{
"input": "6\n1\n1\n2\n2\n3\n3",
"output": "NO"
},
{
"input": "2\n1\n100",
"output": "YES\n1 100"
},
... | 1,614,921,000 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | t = int(input())
a = []
for _ in range(t):
n = int(input())
a.append(n)
if len(set(a)) == 2:
print('YES')
else:
print('NO') | Title: Fair Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya decided to play a game. They have *n* cards (*n* is an even number). A single integer is written on each card.
Before the game Petya will choose an integer and after that Vasya will choose another integer (di... | ```python
t = int(input())
a = []
for _ in range(t):
n = int(input())
a.append(n)
if len(set(a)) == 2:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
48 | A | Rock-paper-scissors | PROGRAMMING | 900 | [
"implementation",
"schedules"
] | A. Rock-paper-scissors | 2 | 256 | Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obvio... | The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture. | Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?". | [
"rock\nrock\nrock\n",
"paper\nrock\nrock\n",
"scissors\nrock\nrock\n",
"scissors\npaper\nrock\n"
] | [
"?\n",
"F\n",
"?\n",
"?\n"
] | none | 0 | [
{
"input": "rock\nrock\nrock",
"output": "?"
},
{
"input": "paper\nrock\nrock",
"output": "F"
},
{
"input": "scissors\nrock\nrock",
"output": "?"
},
{
"input": "scissors\npaper\nrock",
"output": "?"
},
{
"input": "paper\npaper\nrock",
"output": "?"
},
{
... | 1,634,404,498 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 124 | 0 | jokenpo = ["rock", "paper", 'scissors']
F = input()
M = input()
S = input()
"""
from itertools import cycle
pool = cycle(jokenpo)
"""
contF = 0
contM = 0
contS = 0
for i in range(0, 3):
if(jokenpo[i] == F):
saveF = i
for i in range(0, 3):
if(jokenpo[i] == M):
saveM = i
for i in range(0, 3... | Title: Rock-paper-scissors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case ... | ```python
jokenpo = ["rock", "paper", 'scissors']
F = input()
M = input()
S = input()
"""
from itertools import cycle
pool = cycle(jokenpo)
"""
contF = 0
contM = 0
contS = 0
for i in range(0, 3):
if(jokenpo[i] == F):
saveF = i
for i in range(0, 3):
if(jokenpo[i] == M):
saveM = i
for i in ... | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and ... | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,440,592,111 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | n = int(input())
reposts = [[i for i in input().split(' reposted ')] for j in range(n)]
used = []
for i in reposts:
if i[1] not in used:
used.append(i[1])
print(len(used) + 1) | Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
... | ```python
n = int(input())
reposts = [[i for i in input().split(' reposted ')] for j in range(n)]
used = []
for i in reposts:
if i[1] not in used:
used.append(i[1])
print(len(used) + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
454 | A | Little Pony and Crystal Mine | PROGRAMMING | 800 | [
"implementation"
] | null | null | Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You need to draw a crystal of size *n*. The diamond cells of the matrix should be represented by character "D". All ot... | The only line contains an integer *n* (3<=≤<=*n*<=≤<=101; *n* is odd). | Output a crystal of size *n*. | [
"3\n",
"5\n",
"7\n"
] | [
"*D*\nDDD\n*D*\n",
"**D**\n*DDD*\nDDDDD\n*DDD*\n**D**\n",
"***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***\n"
] | none | 500 | [
{
"input": "3",
"output": "*D*\nDDD\n*D*"
},
{
"input": "5",
"output": "**D**\n*DDD*\nDDDDD\n*DDD*\n**D**"
},
{
"input": "7",
"output": "***D***\n**DDD**\n*DDDDD*\nDDDDDDD\n*DDDDD*\n**DDD**\n***D***"
},
{
"input": "11",
"output": "*****D*****\n****DDD****\n***DDDDD***\n**... | 1,644,322,606 | 2,147,483,647 | Python 3 | OK | TESTS | 12 | 46 | 0 | n = int(input())
s_count, d_count = n//2, 1
for i in range(1, n//2+1):
print((s_count * '*') + (d_count * 'D') + (s_count * '*'))
s_count -= 1
d_count += 2
for i in range(1, n//2+2):
print((s_count * '*') + (d_count * 'D') + (s_count * '*'))
s_count += 1
d_count -= 2 | Title: Little Pony and Crystal Mine
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle once got a crystal from the Crystal Mine. A crystal of size *n* (*n* is odd; *n*<=><=1) is an *n*<=×<=*n* matrix with a diamond inscribed into it.
You are given an odd integer *n*. You ... | ```python
n = int(input())
s_count, d_count = n//2, 1
for i in range(1, n//2+1):
print((s_count * '*') + (d_count * 'D') + (s_count * '*'))
s_count -= 1
d_count += 2
for i in range(1, n//2+2):
print((s_count * '*') + (d_count * 'D') + (s_count * '*'))
s_count += 1
d_count -= 2
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
796 | B | Find The Bone | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Zane the wizard is going to perform a magic show shuffling the cups.
There are *n* cups, numbered from 1 to *n*, placed along the *x*-axis on a table that has *m* holes on it. More precisely, cup *i* is on the table at the position *x*<==<=*i*.
The problematic bone is initially at the position *x*<==<=1. Zane will co... | The first line contains three integers *n*, *m*, and *k* (2<=≤<=*n*<=≤<=106, 1<=≤<=*m*<=≤<=*n*, 1<=≤<=*k*<=≤<=3·105) — the number of cups, the number of holes on the table, and the number of swapping operations, respectively.
The second line contains *m* distinct integers *h*1,<=*h*2,<=...,<=*h**m* (1<=≤<=*h**i*<=≤<=*... | Print one integer — the final position along the *x*-axis of the bone. | [
"7 3 4\n3 4 6\n1 2\n2 5\n5 7\n7 1\n",
"5 1 2\n2\n1 2\n2 4\n"
] | [
"1",
"2"
] | In the first sample, after the operations, the bone becomes at *x* = 2, *x* = 5, *x* = 7, and *x* = 1, respectively.
In the second sample, after the first operation, the bone becomes at *x* = 2, and falls into the hole onto the ground. | 750 | [
{
"input": "7 3 4\n3 4 6\n1 2\n2 5\n5 7\n7 1",
"output": "1"
},
{
"input": "5 1 2\n2\n1 2\n2 4",
"output": "2"
},
{
"input": "10000 1 9\n55\n44 1\n2929 9292\n9999 9998\n44 55\n49 94\n55 53\n100 199\n55 50\n53 11",
"output": "55"
},
{
"input": "100000 3 7\n2 3 4\n1 5\n5 1\n1 5... | 1,664,371,048 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 8 | 545 | 127,180,800 | import sys
input = lambda: sys.stdin.buffer.readline().decode().strip()
print = sys.stdout.write
inl = lambda: list(map(int, input().split()))
n, m, k = inl()
holes = set(inl())
bones_pos = 1
for _ in range(k):
u, v = inl()
if bones_pos == u or bones_pos == v:
bones_pos = u if bones_pos ==... | Title: Find The Bone
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Zane the wizard is going to perform a magic show shuffling the cups.
There are *n* cups, numbered from 1 to *n*, placed along the *x*-axis on a table that has *m* holes on it. More precisely, cup *i* is on the table at t... | ```python
import sys
input = lambda: sys.stdin.buffer.readline().decode().strip()
print = sys.stdout.write
inl = lambda: list(map(int, input().split()))
n, m, k = inl()
holes = set(inl())
bones_pos = 1
for _ in range(k):
u, v = inl()
if bones_pos == u or bones_pos == v:
bones_pos = u if bo... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
359 | C | Prime Number | PROGRAMMING | 1,900 | [
"math",
"number theory"
] | null | null | Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common denominator and summed them up, he got a fraction: , where number *t* equals *x**a*1<=+<=*a*2<=+<=...... | The first line contains two positive integers *n* and *x* (1<=≤<=*n*<=≤<=105, 2<=≤<=*x*<=≤<=109) — the size of the array and the prime number.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*<=≤<=109). | Print a single number — the answer to the problem modulo 1000000007 (109<=+<=7). | [
"2 2\n2 2\n",
"3 3\n1 2 3\n",
"2 2\n29 29\n",
"4 5\n0 0 0 0\n"
] | [
"8\n",
"27\n",
"73741817\n",
"1\n"
] | In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7745f7cc87c6c5f753e3414fad9baa3b1e3fea48.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Thus, the answer to the problem is 8.
In the second sample, <img align="middle" class="tex-formula" src="https://espresso.codef... | 1,500 | [
{
"input": "2 2\n2 2",
"output": "8"
},
{
"input": "3 3\n1 2 3",
"output": "27"
},
{
"input": "2 2\n29 29",
"output": "73741817"
},
{
"input": "4 5\n0 0 0 0",
"output": "1"
},
{
"input": "1 2\n1000000000",
"output": "1"
},
{
"input": "26 2\n0 0 0 0 0 0... | 1,671,907,096 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 0 | from math import gcd
n,x = map(int,input().split())
a = list(map(int,input().split()))
mx = max(a)
r = sum(a)
s = r-mx
b = a.count(mx)
while b%x==0:
mx-=1
s+=1
b+= a.count(mx)
print(pow(x,s,10**9+7)) | Title: Prime Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common den... | ```python
from math import gcd
n,x = map(int,input().split())
a = list(map(int,input().split()))
mx = max(a)
r = sum(a)
s = r-mx
b = a.count(mx)
while b%x==0:
mx-=1
s+=1
b+= a.count(mx)
print(pow(x,s,10**9+7))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
591 | B | Rebranding | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slog... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of *n* lowercase English letters and represents the original name of the corporation.
Next *m* lines contain the descr... | Print the new name of the corporation. | [
"6 1\npolice\np m\n",
"11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b\n"
] | [
"molice\n",
"cdcbcdcfcdc\n"
] | In the second sample the name of the corporation consecutively changes as follows:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c7648432f7138ca53234357d7e08d1d119166055.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.co... | 1,000 | [
{
"input": "6 1\npolice\np m",
"output": "molice"
},
{
"input": "11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b",
"output": "cdcbcdcfcdc"
},
{
"input": "1 1\nf\nz h",
"output": "f"
},
{
"input": "1 1\na\na b",
"output": "b"
},
{
"input": "10 10\nlellelleel\ne l\n... | 1,485,466,326 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 4,608,000 | n,m = [int(_) for _ in input().split()]
s = list(input())
for i in range(m):
x,y = input().split()
for j in range(n):
if s[j] == x:
s[j] = y
elif s[j] == y:
s[j] = x
print(''.join(s))
| Title: Rebranding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand ... | ```python
n,m = [int(_) for _ in input().split()]
s = list(input())
for i in range(m):
x,y = input().split()
for j in range(n):
if s[j] == x:
s[j] = y
elif s[j] == y:
s[j] = x
print(''.join(s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
985 | D | Sand Fortress | PROGRAMMING | 2,100 | [
"binary search",
"constructive algorithms",
"math"
] | null | null | You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars. Spots are numbered 1 through infinity from left to right.
Obviously, there is not enough sand o... | The only line contains two integer numbers *n* and *H* (1<=≤<=*n*,<=*H*<=≤<=1018) — the number of sand packs you have and the height of the fence, respectively. | Print the minimum number of spots you can occupy so the all the castle building conditions hold. | [
"5 2\n",
"6 8\n"
] | [
"3\n",
"3\n"
] | Here are the heights of some valid castles:
- *n* = 5, *H* = 2, [2, 2, 1, 0, ...], [2, 1, 1, 1, 0, ...], [1, 0, 1, 2, 1, 0, ...] - *n* = 6, *H* = 8, [3, 2, 1, 0, ...], [2, 2, 1, 1, 0, ...], [0, 1, 0, 1, 2, 1, 1, 0...] (this one has 5 spots occupied)
The first list for both cases is the optimal answer, 3 spots are ... | 0 | [
{
"input": "5 2",
"output": "3"
},
{
"input": "6 8",
"output": "3"
},
{
"input": "20 4",
"output": "7"
},
{
"input": "1000000000000000000 1000000000000000000",
"output": "1414213562"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 10000000000000000... | 1,527,348,637 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 109 | 0 | def bin(f,l,val,h):
mid = int((f+l)/2)
p = mid*(mid+1) - int(h*(h-1)/2) - mid
if(p <= val and val < ((mid+1)*(mid+2) - int(h*(h-1)/2)- mid -1)):
return mid
elif(val >= p):
f = mid+1
return bin(f,l,val,h)
elif(val < p):
l = mid - 1
return bin(f,l,val,h)
else:
return mid
def binS(f,l,val)... | Title: Sand Fortress
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are going to the beach with the idea to build the greatest sand castle ever in your head! The beach is not as three-dimensional as you could have imagined, it can be decribed as a line of spots to pile up sand pillars... | ```python
def bin(f,l,val,h):
mid = int((f+l)/2)
p = mid*(mid+1) - int(h*(h-1)/2) - mid
if(p <= val and val < ((mid+1)*(mid+2) - int(h*(h-1)/2)- mid -1)):
return mid
elif(val >= p):
f = mid+1
return bin(f,l,val,h)
elif(val < p):
l = mid - 1
return bin(f,l,val,h)
else:
return mid
def bin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,675,623,195 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | k = input();print([k.lower(),k.upper()][sumtot(x'['for x in k)*2>len(k)]) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
k = input();print([k.lower(),k.upper()][sumtot(x'['for x in k)*2>len(k)])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,675,118,304 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 46 | 0 | x=0
n=int(input())
m=list(map(int,input().split()))
summ=sum(m)
c={}
for i in (m):
if i not in c:
c[i]=i
else:
c[i]+=i
d=0
dd=0
v=list(c)
n=len(v)
for j,i in enumerate(v):
if j==0:
d=summ-(c[v[j+1]])
dd=i
elif j==n-1:
if summ-(c[v[j-1]])>d:
... | Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
x=0
n=int(input())
m=list(map(int,input().split()))
summ=sum(m)
c={}
for i in (m):
if i not in c:
c[i]=i
else:
c[i]+=i
d=0
dd=0
v=list(c)
n=len(v)
for j,i in enumerate(v):
if j==0:
d=summ-(c[v[j+1]])
dd=i
elif j==n-1:
if summ-(c[v[j-1]... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
892 | B | Wrath | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the *i*-th person kills the *j*-th person if and only if *j*<=<<=*i* and *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — the number of guilty people.
Second line contains *n* space-separated integers *L*1,<=*L*2,<=...,<=*L**n* (0<=≤<=*L**i*<=≤<=109), where *L**i* is the length of the *i*-th person's claw. | Print one integer — the total number of alive people after the bell rings. | [
"4\n0 1 0 10\n",
"2\n0 0\n",
"10\n1 1 3 0 0 0 2 1 0 3\n"
] | [
"1\n",
"2\n",
"3\n"
] | In first sample the last person kills everyone in front of him. | 1,000 | [
{
"input": "4\n0 1 0 10",
"output": "1"
},
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "10\n1 1 3 0 0 0 2 1 0 3",
"output": "3"
},
{
"input": "10\n0 0 2 0 0 3 3 2 2 0",
"output": "2"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "5\n0 0 0 1 0"... | 1,526,399,564 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 83,456,000 | n=int(input())
a=list(map(int,input().split()))
j=(n-1)
ans=0
b=[1]*n
while j>=0:
x=j-a[j]
if x<0:
x=0
for i in range(x,j,1):
b[i]=0
j-=1
print(b.count(1))
| Title: Wrath
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same ... | ```python
n=int(input())
a=list(map(int,input().split()))
j=(n-1)
ans=0
b=[1]*n
while j>=0:
x=j-a[j]
if x<0:
x=0
for i in range(x,j,1):
b[i]=0
j-=1
print(b.count(1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,509,210,498 | 798 | Python 3 | WRONG_ANSWER | TESTS | 13 | 62 | 0 | k, a, b = [int(i) for i in input().split()]
v = (b - a)//k + 1
print(v)
| Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
k, a, b = [int(i) for i in input().split()]
v = (b - a)//k + 1
print(v)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
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