contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
766 | B | Mahmoud and a Triangle | PROGRAMMING | 1,000 | [
"constructive algorithms",
"geometry",
"greedy",
"math",
"number theory",
"sortings"
] | null | null | Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he can win, so he asked you to tell him if he should accept the challenge. Given the lengths of the line segments... | The first line contains single integer *n* (3<=≤<=*n*<=≤<=105) — the number of line segments Mahmoud has.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the lengths of line segments Mahmoud has. | In the only line print "YES" if he can choose exactly three line segments and form a non-degenerate triangle with them, and "NO" otherwise. | [
"5\n1 5 3 2 4\n",
"3\n4 1 2\n"
] | [
"YES\n",
"NO\n"
] | For the first example, he can use line segments with lengths 2, 4 and 5 to form a non-degenerate triangle. | 1,000 | [
{
"input": "5\n1 5 3 2 4",
"output": "YES"
},
{
"input": "3\n4 1 2",
"output": "NO"
},
{
"input": "30\n197 75 517 39724 7906061 1153471 3 15166 168284 3019844 272293 316 16 24548 42 118 5792 5 9373 1866366 4886214 24 2206 712886 104005 1363 836 64273 440585 3576",
"output": "NO"
},... | 1,661,911,486 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | t=int(input())
a=sorted(list(map(int,input().split())))
def tr(x):
for i in range(t-2):
if x[i]+x[i+1]>x[i+2]
print('YES')
return
print('NO')
return
tr(a) | Title: Mahmoud and a Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud has *n* line segments, the *i*-th of them has length *a**i*. Ehab challenged him to use exactly 3 line segments to form a non-degenerate triangle. Mahmoud doesn't accept challenges unless he is sure he ca... | ```python
t=int(input())
a=sorted(list(map(int,input().split())))
def tr(x):
for i in range(t-2):
if x[i]+x[i+1]>x[i+2]
print('YES')
return
print('NO')
return
tr(a)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
721 | A | One-dimensional Japanese Crossword | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the left of the rows and to the top of the columns, encrypting the corresponding row or column. The number of integers repr... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the row. The second line of the input contains a single string consisting of *n* characters 'B' or 'W', ('B' corresponds to black square, 'W' — to white square in the row that Adaltik drew). | The first line should contain a single integer *k* — the number of integers encrypting the row, e.g. the number of groups of black squares in the row.
The second line should contain *k* integers, encrypting the row, e.g. corresponding to sizes of groups of consecutive black squares in the order from left to right. | [
"3\nBBW\n",
"5\nBWBWB\n",
"4\nWWWW\n",
"4\nBBBB\n",
"13\nWBBBBWWBWBBBW\n"
] | [
"1\n2 ",
"3\n1 1 1 ",
"0\n",
"1\n4 ",
"3\n4 1 3 "
] | The last sample case correspond to the picture in the statement. | 500 | [
{
"input": "3\nBBW",
"output": "1\n2 "
},
{
"input": "5\nBWBWB",
"output": "3\n1 1 1 "
},
{
"input": "4\nWWWW",
"output": "0"
},
{
"input": "4\nBBBB",
"output": "1\n4 "
},
{
"input": "13\nWBBBBWWBWBBBW",
"output": "3\n4 1 3 "
},
{
"input": "1\nB",
... | 1,593,341,016 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 124 | 6,963,200 | n=int(input())
s=input()
count=1
length,l1=[],[]
if len(s)>1:
for i in range(1,len(s)):
if s[i-1]==s[i]:
count+=1
else :
length.append((s[i-1],str(count)))
count=1
length.append((s[i],str(count)))
else:
i=0
length.append((s[i],str(count)))
#pr... | Title: One-dimensional Japanese Crossword
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the... | ```python
n=int(input())
s=input()
count=1
length,l1=[],[]
if len(s)>1:
for i in range(1,len(s)):
if s[i-1]==s[i]:
count+=1
else :
length.append((s[i-1],str(count)))
count=1
length.append((s[i],str(count)))
else:
i=0
length.append((s[i],str(cou... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
792 | A | New Bus Route | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from one city to another only by bus. But all buses and roads are very old, so the Minister of Transport d... | The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). All numbers *a**i* are pairwise distinct. | Print two integer numbers — the minimal distance and the quantity of pairs with this distance. | [
"4\n6 -3 0 4\n",
"3\n-2 0 2\n"
] | [
"2 1\n",
"2 2\n"
] | In the first example the distance between the first city and the fourth city is |4 - 6| = 2, and it is the only pair with this distance. | 0 | [
{
"input": "4\n6 -3 0 4",
"output": "2 1"
},
{
"input": "3\n-2 0 2",
"output": "2 2"
},
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "2\n1000000000 -1000000000",
"output": "2000000000 1"
},
{
"input": "5\n-979619606 -979619602 -979619604 -979619605 -97961960... | 1,608,728,526 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 218 | 2,048,000 | n=int(input())
l=list(map(int,input().split()))
l.sort()
d={}
q=l[-1]
for x in range(n-1):
k=abs(l[x]-l[x+1])
if k in d:d[k]+=1
else:d[k]=1
if k<q:
q=k
print(q,d[q]) | Title: New Bus Route
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from on... | ```python
n=int(input())
l=list(map(int,input().split()))
l.sort()
d={}
q=l[-1]
for x in range(n-1):
k=abs(l[x]-l[x+1])
if k in d:d[k]+=1
else:d[k]=1
if k<q:
q=k
print(q,d[q])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,660,599,700 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 4,403,200 | n,x=map(int,input().rstrip().split())
arr=list(map(int,input().rstrip().split()));o=1;e=0;flag=0
while o<=x:
o=arr[e]+(e+1);e+=1
if o==x:flag+=1;break
if flag:print("YES")
else:print("NO") | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
n,x=map(int,input().rstrip().split())
arr=list(map(int,input().rstrip().split()));o=1;e=0;flag=0
while o<=x:
o=arr[e]+(e+1);e+=1
if o==x:flag+=1;break
if flag:print("YES")
else:print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
505 | B | Mr. Kitayuta's Colorful Graph | PROGRAMMING | 1,400 | [
"dfs and similar",
"dp",
"dsu",
"graphs"
] | null | null | Mr. Kitayuta has just bought an undirected graph consisting of *n* vertices and *m* edges. The vertices of the graph are numbered from 1 to *n*. Each edge, namely edge *i*, has a color *c**i*, connecting vertex *a**i* and *b**i*.
Mr. Kitayuta wants you to process the following *q* queries.
In the *i*-th query, he giv... | The first line of the input contains space-separated two integers — *n* and *m* (2<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=100), denoting the number of the vertices and the number of the edges, respectively.
The next *m* lines contain space-separated three integers — *a**i*, *b**i* (1<=≤<=*a**i*<=<<=*b**i*<=≤<=*n*) and *c*... | For each query, print the answer in a separate line. | [
"4 5\n1 2 1\n1 2 2\n2 3 1\n2 3 3\n2 4 3\n3\n1 2\n3 4\n1 4\n",
"5 7\n1 5 1\n2 5 1\n3 5 1\n4 5 1\n1 2 2\n2 3 2\n3 4 2\n5\n1 5\n5 1\n2 5\n1 5\n1 4\n"
] | [
"2\n1\n0\n",
"1\n1\n1\n1\n2\n"
] | Let's consider the first sample.
- Vertex 1 and vertex 2 are connected by color 1 and 2. - Vertex 3 and vertex 4 are connected by color 3. - Vertex 1 and vertex 4 are not connected by any single color. | 1,000 | [
{
"input": "4 5\n1 2 1\n1 2 2\n2 3 1\n2 3 3\n2 4 3\n3\n1 2\n3 4\n1 4",
"output": "2\n1\n0"
},
{
"input": "5 7\n1 5 1\n2 5 1\n3 5 1\n4 5 1\n1 2 2\n2 3 2\n3 4 2\n5\n1 5\n5 1\n2 5\n1 5\n1 4",
"output": "1\n1\n1\n1\n2"
},
{
"input": "2 1\n1 2 1\n1\n1 2",
"output": "1"
},
{
"input... | 1,607,747,746 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 156 | 2,355,200 | from sys import stdin, stdout
def find(node, color):
x = []
while colors[color][node] > 0:
x.append(node)
node = colors[color][node]
for i in x:
colors[color][i] = node
return node
def union(node1, node2, color):
if node1 != node2:
if colors[color][node... | Title: Mr. Kitayuta's Colorful Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Kitayuta has just bought an undirected graph consisting of *n* vertices and *m* edges. The vertices of the graph are numbered from 1 to *n*. Each edge, namely edge *i*, has a color *c**i*, connecting v... | ```python
from sys import stdin, stdout
def find(node, color):
x = []
while colors[color][node] > 0:
x.append(node)
node = colors[color][node]
for i in x:
colors[color][i] = node
return node
def union(node1, node2, color):
if node1 != node2:
if colors[c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
825 | B | Five-In-a-Row | PROGRAMMING | 1,600 | [
"brute force",
"implementation"
] | null | null | Alice and Bob play 5-in-a-row game. They have a playing field of size 10<=×<=10. In turns they put either crosses or noughts, one at a time. Alice puts crosses and Bob puts noughts.
In current match they have made some turns and now it's Alice's turn. She wonders if she can put cross in such empty cell that she wins i... | You are given matrix 10<=×<=10 (10 lines of 10 characters each) with capital Latin letters 'X' being a cross, letters 'O' being a nought and '.' being an empty cell. The number of 'X' cells is equal to the number of 'O' cells and there is at least one of each type. There is at least one empty cell.
It is guaranteed th... | Print 'YES' if it's possible for Alice to win in one turn by putting cross in some empty cell. Otherwise print 'NO'. | [
"XX.XX.....\n.....OOOO.\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n",
"XXOXX.....\nOO.O......\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n..........\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "O.......O.\n.....O.X..\n......O...\n....X.O...\n.O.O.....X\n.XO.....XX\n...X...X.O\n........O.\n........O.\n.X.X.....X",
"output": "NO"
},
{
"input": "....OX....\n..........\n.O..X...X.\nXXO..XO..O\nO.......X.\n...XX.....\n..O.O...OX\n.........X\n.....X..OO\n........O.",
"output": "N... | 1,508,868,166 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 61 | 5,529,600 | import sys
import math
def check(s):
dot = s.count('.')
# x = s.count('X')
o = s.count('O')
if o != 0:
return False
if dot in [0, 1]:
return True
arr = []
for _ in range(10):
arr.append(sys.stdin.readline().strip())
for i in range(10):
for j in range(6):
st = arr[i][j:j+5]
# print(st)
if check(st):
... | Title: Five-In-a-Row
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice and Bob play 5-in-a-row game. They have a playing field of size 10<=×<=10. In turns they put either crosses or noughts, one at a time. Alice puts crosses and Bob puts noughts.
In current match they have made some t... | ```python
import sys
import math
def check(s):
dot = s.count('.')
# x = s.count('X')
o = s.count('O')
if o != 0:
return False
if dot in [0, 1]:
return True
arr = []
for _ in range(10):
arr.append(sys.stdin.readline().strip())
for i in range(10):
for j in range(6):
st = arr[i][j:j+5]
# print(st)
if c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,582,952,883 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 109 | 307,200 | import sys
import math
#to read string
get_string = lambda: sys.stdin.readline().strip()
#to read list of integers
get_int_list = lambda: list( map(int,sys.stdin.readline().strip().split()) )
#to read non spaced string and elements are integers to list of int
get_intList_from_str = lambda: list(map(int,list(sy... | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
import sys
import math
#to read string
get_string = lambda: sys.stdin.readline().strip()
#to read list of integers
get_int_list = lambda: list( map(int,sys.stdin.readline().strip().split()) )
#to read non spaced string and elements are integers to list of int
get_intList_from_str = lambda: list(map(i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
451 | A | Game With Sticks | PROGRAMMING | 900 | [
"implementation"
] | null | null | After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid show... | The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). | Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. | [
"2 2\n",
"2 3\n",
"3 3\n"
] | [
"Malvika\n",
"Malvika\n",
"Akshat\n"
] | Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remov... | 500 | [
{
"input": "2 2",
"output": "Malvika"
},
{
"input": "2 3",
"output": "Malvika"
},
{
"input": "3 3",
"output": "Akshat"
},
{
"input": "20 68",
"output": "Malvika"
},
{
"input": "1 1",
"output": "Akshat"
},
{
"input": "1 2",
"output": "Akshat"
},
... | 1,683,800,834 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n,m=list(map(int,input().split()))
def gws(n,m):
if n==1:
return 1
if n>=2 and n==m:
return int(n+m-1) + int(gws(n-1,m-1))
elif n>=2 and n!=m:
return int(n+m-1) + int(gws(n-1,m-1)) +1
if gws(n,m)%2==0:
print('Malvika')
else:
print('Akshat') | Title: Game With Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid... | ```python
n,m=list(map(int,input().split()))
def gws(n,m):
if n==1:
return 1
if n>=2 and n==m:
return int(n+m-1) + int(gws(n-1,m-1))
elif n>=2 and n!=m:
return int(n+m-1) + int(gws(n-1,m-1)) +1
if gws(n,m)%2==0:
print('Malvika')
else:
print('Akshat')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
873 | B | Balanced Substring | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | null | null | You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to deter... | The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*. | If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring. | [
"8\n11010111\n",
"3\n111\n"
] | [
"4\n",
"0\n"
] | In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring. | 0 | [
{
"input": "8\n11010111",
"output": "4"
},
{
"input": "3\n111",
"output": "0"
},
{
"input": "11\n00001000100",
"output": "2"
},
{
"input": "10\n0100000000",
"output": "2"
},
{
"input": "13\n0001000011010",
"output": "6"
},
{
"input": "14\n0000010010101... | 1,507,823,863 | 6,763 | Python 3 | OK | TESTS | 53 | 311 | 19,046,400 | # -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
"""
created by shhuan at 2017/10/12 22:12
"""
n = int(input())
s = input()
# n = 100000
# s = ''
# for i in range(n):
# x = random.randint(1, 10)
# if x >= 5:
# s += '1'
... | Title: Balanced Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called... | ```python
# -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
"""
created by shhuan at 2017/10/12 22:12
"""
n = int(input())
s = input()
# n = 100000
# s = ''
# for i in range(n):
# x = random.randint(1, 10)
# if x >= 5:
# ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
558 | B | Amr and The Large Array | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Amr has got a large array of size *n*. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subseg... | The first line contains one number *n* (1<=≤<=*n*<=≤<=105), the size of the array.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106), representing elements of the array. | Output two integers *l*,<=*r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them. | [
"5\n1 1 2 2 1\n",
"5\n1 2 2 3 1\n",
"6\n1 2 2 1 1 2\n"
] | [
"1 5",
"2 3",
"1 5"
] | A subsegment *B* of an array *A* from *l* to *r* is an array of size *r* - *l* + 1 where *B*<sub class="lower-index">*i*</sub> = *A*<sub class="lower-index">*l* + *i* - 1</sub> for all 1 ≤ *i* ≤ *r* - *l* + 1 | 1,000 | [
{
"input": "5\n1 1 2 2 1",
"output": "1 5"
},
{
"input": "5\n1 2 2 3 1",
"output": "2 3"
},
{
"input": "6\n1 2 2 1 1 2",
"output": "1 5"
},
{
"input": "10\n1 1000000 2 1000000 3 2 1000000 1 2 1",
"output": "2 7"
},
{
"input": "10\n1 2 3 4 5 5 1 2 3 4",
"output... | 1,614,854,079 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 218 | 15,360,000 | import math,sys
from collections import defaultdict,deque
import bisect as bi
def yes():print('YES')
def no():print('NO')
def I():return (int(sys.stdin.readline()))
def In():return(map(int,sys.stdin.readline().split()))
def Sn():return sys.stdin.readline().strip()
def Pr(x): sys.stdout.write(str(x)+'\n')
#sys.... | Title: Amr and The Large Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr has got a large array of size *n*. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to... | ```python
import math,sys
from collections import defaultdict,deque
import bisect as bi
def yes():print('YES')
def no():print('NO')
def I():return (int(sys.stdin.readline()))
def In():return(map(int,sys.stdin.readline().split()))
def Sn():return sys.stdin.readline().strip()
def Pr(x): sys.stdout.write(str(x)+'\... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
808 | A | Lucky Year | PROGRAMMING | 900 | [
"implementation"
] | null | null | Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland. | Output amount of years from the current year to the next lucky one. | [
"4\n",
"201\n",
"4000\n"
] | [
"1\n",
"99\n",
"1000\n"
] | In the first example next lucky year is 5. In the second one — 300. In the third — 5000. | 0 | [
{
"input": "4",
"output": "1"
},
{
"input": "201",
"output": "99"
},
{
"input": "4000",
"output": "1000"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "1",
"output": "1"
},
{
"input": "100000000",
"ou... | 1,604,483,440 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 0 | def isLucky(year):
noZero = 0
for num in str(year):
if num != "0":
noZero += 1
return noZero <= 1
current = int(input()) + 1
added = 1
while not isLucky(current):
current += 1
added += 1
print(added)
| Title: Lucky Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 1... | ```python
def isLucky(year):
noZero = 0
for num in str(year):
if num != "0":
noZero += 1
return noZero <= 1
current = int(input()) + 1
added = 1
while not isLucky(current):
current += 1
added += 1
print(added)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,665,070,665 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n = input()
n_ = len(n)
count_lower = 0
count_upper = 0
for i in n:
if i == i.lower():
count_lower += 1
elif i == i.upper():
count_upper += 1
if count_lower > count_upper:
print(n.lower())
elif count_lower < count_upper:
print(n.upper())
else:
print(n.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
n = input()
n_ = len(n)
count_lower = 0
count_upper = 0
for i in n:
if i == i.lower():
count_lower += 1
elif i == i.upper():
count_upper += 1
if count_lower > count_upper:
print(n.lower())
elif count_lower < count_upper:
print(n.upper())
else:
print(n... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
735 | B | Urbanization | PROGRAMMING | 1,100 | [
"greedy",
"number theory",
"sortings"
] | null | null | Local authorities have heard a lot about combinatorial abilities of Ostap Bender so they decided to ask his help in the question of urbanization. There are *n* people who plan to move to the cities. The wealth of the *i* of them is equal to *a**i*. Authorities plan to build two cities, first for *n*1 people and second ... | The first line of the input contains three integers *n*, *n*1 and *n*2 (1<=≤<=*n*,<=*n*1,<=*n*2<=≤<=100<=000, *n*1<=+<=*n*2<=≤<=*n*) — the number of candidates who want to move to the cities, the planned number of residents of the first city and the planned number of residents of the second city.
The second line conta... | Print one real value — the maximum possible sum of arithmetic means of wealth of cities' residents. You answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6.
Namely: let's assume that your answer is *a*, and the answer of the jury is *b*. The checker program will consider your ... | [
"2 1 1\n1 5\n",
"4 2 1\n1 4 2 3\n"
] | [
"6.00000000\n",
"6.50000000\n"
] | In the first sample, one of the optimal solutions is to move candidate 1 to the first city and candidate 2 to the second.
In the second sample, the optimal solution is to pick candidates 3 and 4 for the first city, and candidate 2 for the second one. Thus we obtain (*a*<sub class="lower-index">3</sub> + *a*<sub class=... | 1,000 | [
{
"input": "2 1 1\n1 5",
"output": "6.00000000"
},
{
"input": "4 2 1\n1 4 2 3",
"output": "6.50000000"
},
{
"input": "3 1 2\n1 2 3",
"output": "4.50000000"
},
{
"input": "10 4 6\n3 5 7 9 12 25 67 69 83 96",
"output": "88.91666667"
},
{
"input": "19 7 12\n1 2 4 8 1... | 1,605,579,648 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 187 | 7,782,400 | n, n1, n2 = (int(x) for x in input().split())
a = list(int(x) for x in input().split())
a = sorted(a, reverse=True)
if n1 < n2:
s = 0
for i in range(n1):
s += a[i]
d = 0
for j in range(n1,n1+n2):
d += a[j]
#print(s , d)
s /= n1
d /= n2
else:
s = 0
for i... | Title: Urbanization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Local authorities have heard a lot about combinatorial abilities of Ostap Bender so they decided to ask his help in the question of urbanization. There are *n* people who plan to move to the cities. The wealth of the *i* o... | ```python
n, n1, n2 = (int(x) for x in input().split())
a = list(int(x) for x in input().split())
a = sorted(a, reverse=True)
if n1 < n2:
s = 0
for i in range(n1):
s += a[i]
d = 0
for j in range(n1,n1+n2):
d += a[j]
#print(s , d)
s /= n1
d /= n2
else:
s = 0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,698,839,718 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 122 | 0 | def is_prime(n):#判断n是不是素数
if n < 2:
return False
i = 2
while i*i <= n:
if n % i == 0:
return False
i += 1
return True
n,m = map(int,input().split())
calculate = {}
index = 0
for i in range(n,m+1):
if is_prime(i):
calculate.update({i: index})
index ... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
def is_prime(n):#判断n是不是素数
if n < 2:
return False
i = 2
while i*i <= n:
if n % i == 0:
return False
i += 1
return True
n,m = map(int,input().split())
calculate = {}
index = 0
for i in range(n,m+1):
if is_prime(i):
calculate.update({i: index})
... | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,691,814,490 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 32 | 92 | 0 | from sys import stdin
a = stdin.readline().strip()
b = a.count("4");c = a.count("7")
if b+c == len(list(a)):
print("YES")
else:
for i in range(4,int(a)//2):
if int(a)%i == 0 :
c = str(i)
b = c.count("4");c = c.count("7")
if b+c == len(list(str(i))):
... | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
from sys import stdin
a = stdin.readline().strip()
b = a.count("4");c = a.count("7")
if b+c == len(list(a)):
print("YES")
else:
for i in range(4,int(a)//2):
if int(a)%i == 0 :
c = str(i)
b = c.count("4");c = c.count("7")
if b+c == len(list(st... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,668,420,487 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 22,016,000 | n,m=map(int,input().split())
l=input().split()
for i in range(m):
print(len(set([l[x] for x in range(int(input())-1,n)]))) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
n,m=map(int,input().split())
l=input().split()
for i in range(m):
print(len(set([l[x] for x in range(int(input())-1,n)])))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,678,113,093 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 46 | 0 | s=input()
numRotations=0
starPoint=0
for i in range(len(s)) :
place = ord(s[i])-97
dis = abs(starPoint-place)
if(dis < 13):
numRotations+=dis
else:
numRotations+=26-dis
starPoint=place
print(numRotations) | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
s=input()
numRotations=0
starPoint=0
for i in range(len(s)) :
place = ord(s[i])-97
dis = abs(starPoint-place)
if(dis < 13):
numRotations+=dis
else:
numRotations+=26-dis
starPoint=place
print(numRotations)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the ... | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,683,726,561 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 46 | 0 | n=int(input())
def fib(n):
s1=1
s2=1
s=0
l=[1]
while s<n:
s=s1+s2
s1=s2
s2=s
l.append(s)
return l
l=fib(n)
ch=""
for i in range(1,n+1):
if i in l:
ch+="O"
else:
ch+="o"
print(ch) | Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should o... | ```python
n=int(input())
def fib(n):
s1=1
s2=1
s=0
l=[1]
while s<n:
s=s1+s2
s1=s2
s2=s
l.append(s)
return l
l=fib(n)
ch=""
for i in range(1,n+1):
if i in l:
ch+="O"
else:
ch+="o"
print(ch)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,647,709,418 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | def main():
num = int(input())
score = {}
score2 = {}
for i in range(num):
player, points = input().split()
points = int(points)
if player in score:
if points == 0:
continue
score2[score[player]].remove(player)
score[player] ... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
def main():
num = int(input())
score = {}
score2 = {}
for i in range(num):
player, points = input().split()
points = int(points)
if player in score:
if points == 0:
continue
score2[score[player]].remove(player)
scor... | 0 | MatrixStudio/Codeforces-Python-Submissions |
920 | C | Swap Adjacent Elements | PROGRAMMING | 1,400 | [
"dfs and similar",
"greedy",
"math",
"sortings",
"two pointers"
] | null | null | You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. T... | The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once.
The third line contains a string of *n*<=-<=1 char... | If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO. | [
"6\n1 2 5 3 4 6\n01110\n",
"6\n1 2 5 3 4 6\n01010\n"
] | [
"YES\n",
"NO\n"
] | In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>. | 0 | [
{
"input": "6\n1 2 5 3 4 6\n01110",
"output": "YES"
},
{
"input": "6\n1 2 5 3 4 6\n01010",
"output": "NO"
},
{
"input": "6\n1 6 3 4 5 2\n01101",
"output": "NO"
},
{
"input": "6\n2 3 1 4 5 6\n01111",
"output": "NO"
},
{
"input": "4\n2 3 1 4\n011",
"output": "NO... | 1,517,582,894 | 794 | Python 3 | WRONG_ANSWER | TESTS | 3 | 202 | 19,456,000 | n=int(input())
a=list(map(int,input().split()))
s=input()
b=sorted(a)
#print(a,b)
for i in range(n-1):
if s[i]=='1':
if a[i]>a[i+1]:
a[i],a[i+1]=a[i+1],a[i]
#print(i,a)
if a==b:
print("YES")
else:
print("NO")
| Title: Swap Adjacent Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<... | ```python
n=int(input())
a=list(map(int,input().split()))
s=input()
b=sorted(a)
#print(a,b)
for i in range(n-1):
if s[i]=='1':
if a[i]>a[i+1]:
a[i],a[i+1]=a[i+1],a[i]
#print(i,a)
if a==b:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,629,016,390 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 30 | 109 | 8,806,400 | n = int(input())
s = input().split(' ')
a = [int(i) for i in s]
if a.count(5)!=0:
print('-1')
else:
count_1 = a.count(1)
count_2 = a.count(2)
count_3 = a.count(3)
count_4 = a.count(4)
count_6 = a.count(6)
if count_2 < count_4 or (count_2-count_4)+count_3!=count_6 or count_1!=count_2+count_3:
print(... | Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
n = int(input())
s = input().split(' ')
a = [int(i) for i in s]
if a.count(5)!=0:
print('-1')
else:
count_1 = a.count(1)
count_2 = a.count(2)
count_3 = a.count(3)
count_4 = a.count(4)
count_6 = a.count(6)
if count_2 < count_4 or (count_2-count_4)+count_3!=count_6 or count_1!=count_2+count_3:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,671,758,705 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 21 | 1,000 | 0 | n = int(input(""))
lst = input("").split(" ")
grand = []
numteams = 0
while "1" in lst and "2" in lst and "3" in lst:
team = []
have = []
for i in range(len(lst)):
if lst[i] not in have and lst[i] != "":
have.append(lst[i])
team.append(i+1)
lst[i] = ""
... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n = int(input(""))
lst = input("").split(" ")
grand = []
numteams = 0
while "1" in lst and "2" in lst and "3" in lst:
team = []
have = []
for i in range(len(lst)):
if lst[i] not in have and lst[i] != "":
have.append(lst[i])
team.append(i+1)
ls... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
278 | A | Circle Line | PROGRAMMING | 800 | [
"implementation"
] | null | null | The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) —... | Print a single number — the length of the shortest path between stations number *s* and *t*. | [
"4\n2 3 4 9\n1 3\n",
"4\n5 8 2 100\n4 1\n",
"3\n1 1 1\n3 1\n",
"3\n31 41 59\n1 1\n"
] | [
"5\n",
"15\n",
"1\n",
"0\n"
] | In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13.
In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15.
In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2.
In the fourth sample the numbers of st... | 500 | [
{
"input": "4\n2 3 4 9\n1 3",
"output": "5"
},
{
"input": "4\n5 8 2 100\n4 1",
"output": "15"
},
{
"input": "3\n1 1 1\n3 1",
"output": "1"
},
{
"input": "3\n31 41 59\n1 1",
"output": "0"
},
{
"input": "5\n16 13 10 30 15\n4 2",
"output": "23"
},
{
"inpu... | 1,413,626,010 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 342 | 6,144,000 | import math
import random
import itertools
import collections
import sys
import time
import fractions
import os
import functools
import bisect
def timer(f):
def tmp(*args, **kwargs):
t = time.time()
res = f(*args, **kwargs)
print("Время выполнения функции: %f" % (time.time(... | Title: Circle Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd... | ```python
import math
import random
import itertools
import collections
import sys
import time
import fractions
import os
import functools
import bisect
def timer(f):
def tmp(*args, **kwargs):
t = time.time()
res = f(*args, **kwargs)
print("Время выполнения функции: %f" % (... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | B | Fortune Telling | PROGRAMMING | 1,200 | [
"implementation",
"number theory"
] | B. Fortune Telling | 2 | 256 | Marina loves Sasha. But she keeps wondering whether Sasha loves her. Of course, the best way to know it is fortune telling. There are many ways of telling fortune, but Marina has picked the easiest one. She takes in her hand one or several camomiles and tears off the petals one by one. After each petal she pronounces a... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100), which is the number of flowers growing in the field. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100) which represent the number of petals on a given *i*-th camomile. | Print a single number which is the maximal number of petals in the bouquet, the fortune telling on which would result in "Loves". If there are no such bouquet, print 0 instead. The bouquet may consist of a single flower. | [
"1\n1\n",
"1\n2\n",
"3\n5 6 7\n"
] | [
"1\n",
"0\n",
"13\n"
] | none | 1,000 | [
{
"input": "1\n1",
"output": "1"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "3\n5 6 7",
"output": "13"
},
{
"input": "2\n5 7",
"output": "7"
},
{
"input": "3\n1 2 3",
"output": "5"
},
{
"input": "4\n4 3 1 2",
"output": "9"
},
{
"inpu... | 1,687,900,899 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 14 | 92 | 0 | # Night Vision
# B.Fortune Telling
n = int(input())
a = list(map(int, input().split()))
s = sum(a)
if s % 2 == 1:
print(s)
else:
while s % 2 == 0:
if n == 1:
s = 0
break
else:
if min (a)%2==1:
s -= min(a)
a.remove... | Title: Fortune Telling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Marina loves Sasha. But she keeps wondering whether Sasha loves her. Of course, the best way to know it is fortune telling. There are many ways of telling fortune, but Marina has picked the easiest one. She takes in her han... | ```python
# Night Vision
# B.Fortune Telling
n = int(input())
a = list(map(int, input().split()))
s = sum(a)
if s % 2 == 1:
print(s)
else:
while s % 2 == 0:
if n == 1:
s = 0
break
else:
if min (a)%2==1:
s -= min(a)
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
350 | A | TL | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Valera has also wrote *m* wrong solutions and for each wrong solution he knows its running ... | The first line contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100). The second line contains *n* space-separated positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) — the running time of each of the *n* correct solutions in seconds. The third line contains *m* space-separated positive integers *b*1... | If there is a valid TL value, print it. Otherwise, print -1. | [
"3 6\n4 5 2\n8 9 6 10 7 11\n",
"3 1\n3 4 5\n6\n"
] | [
"5",
"-1\n"
] | none | 500 | [
{
"input": "3 6\n4 5 2\n8 9 6 10 7 11",
"output": "5"
},
{
"input": "3 1\n3 4 5\n6",
"output": "-1"
},
{
"input": "2 5\n45 99\n49 41 77 83 45",
"output": "-1"
},
{
"input": "50 50\n18 13 5 34 10 36 36 12 15 11 16 17 14 36 23 45 32 24 31 18 24 32 7 1 31 3 49 8 16 23 3 39 47 43... | 1,589,571,379 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 310 | 20,172,800 | # It's all about what U BELIEVE
def gint(): return int(input())
def gint_arr(): return list(map(int, input().split()))
def gfloat(): return float(input())
def gfloat_arr(): return list(map(float, input().split()))
def pair_int(): return map(int, input().split())
#########################################################... | Title: TL
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Val... | ```python
# It's all about what U BELIEVE
def gint(): return int(input())
def gint_arr(): return list(map(int, input().split()))
def gfloat(): return float(input())
def gfloat_arr(): return list(map(float, input().split()))
def pair_int(): return map(int, input().split())
###############################################... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
195 | A | Let's Watch Football | PROGRAMMING | 1,000 | [
"binary search",
"brute force",
"math"
] | null | null | Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the si... | The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. T... | Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses. | [
"4 1 1\n",
"10 3 2\n",
"13 12 1\n"
] | [
"3\n",
"5\n",
"1\n"
] | In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watch... | 500 | [
{
"input": "4 1 1",
"output": "3"
},
{
"input": "10 3 2",
"output": "5"
},
{
"input": "13 12 1",
"output": "1"
},
{
"input": "2 1 3",
"output": "3"
},
{
"input": "6 2 4",
"output": "8"
},
{
"input": "5 2 1",
"output": "2"
},
{
"input": "2 1... | 1,596,911,385 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 280 | 20,172,800 | import math
a,b,c=[int(x) for x in input().split()]
t=a*c
k=math.ceil(t/b)
print(k-c) | Title: Let's Watch Football
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn ... | ```python
import math
a,b,c=[int(x) for x in input().split()]
t=a*c
k=math.ceil(t/b)
print(k-c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,697,082,586 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | n=int(input())
s=0
for i in range(n):
b,c,d=map(int,input().split())
if b==1 and c==1:
s=s+1
elif b==1 and d==1:
s=s+1
elif c==1 and d==1:
s=s+1
print(s) | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
n=int(input())
s=0
for i in range(n):
b,c,d=map(int,input().split())
if b==1 and c==1:
s=s+1
elif b==1 and d==1:
s=s+1
elif c==1 and d==1:
s=s+1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,686,847,894 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | L, N = map(int, input().split())
max_dominoes = (L * N) // 2
print(max_dominoes)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
L, N = map(int, input().split())
max_dominoes = (L * N) // 2
print(max_dominoes)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and... | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, ... | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer ... | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,445,766,074 | 2,474 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 0 | l = int(input())
p = int(input())
q = int(input())
"""
dist = (1 - (1 - q / p)) * l
other_dist = l - dist
print(other_dist)
new_l = dist - other_dist
print(new_l)
final_dist = (1 - (1 - q / p)) * new_l
print(final_dist)
"""
print((max(p, q) / (p + q)) * l)
| Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the en... | ```python
l = int(input())
p = int(input())
q = int(input())
"""
dist = (1 - (1 - q / p)) * l
other_dist = l - dist
print(other_dist)
new_l = dist - other_dist
print(new_l)
final_dist = (1 - (1 - q / p)) * new_l
print(final_dist)
"""
print((max(p, q) / (p + q)) * l)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
144 | A | Arrival of the General | PROGRAMMING | 800 | [
"implementation"
] | null | null | A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their... | The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginnin... | Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like. | [
"4\n33 44 11 22\n",
"7\n10 10 58 31 63 40 76\n"
] | [
"2\n",
"10\n"
] | In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76)... | 500 | [
{
"input": "4\n33 44 11 22",
"output": "2"
},
{
"input": "7\n10 10 58 31 63 40 76",
"output": "10"
},
{
"input": "2\n88 89",
"output": "1"
},
{
"input": "5\n100 95 100 100 88",
"output": "0"
},
{
"input": "7\n48 48 48 48 45 45 45",
"output": "0"
},
{
"... | 1,697,302,525 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
a = list(map(int, input().split()))
max_index = a.index(max(a))
min_index = n-a[::-1].index(min(a[::-1]))-1
print(max_index)
print(min_index)
if max_index > min_index:
moves = max_index + (n - 1 - min_index) - 1
else:
moves = max_index + (n - 1 - min_index)
print(moves)
| Title: Arrival of the General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on t... | ```python
n = int(input())
a = list(map(int, input().split()))
max_index = a.index(max(a))
min_index = n-a[::-1].index(min(a[::-1]))-1
print(max_index)
print(min_index)
if max_index > min_index:
moves = max_index + (n - 1 - min_index) - 1
else:
moves = max_index + (n - 1 - min_index)
print(mov... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,543,068,124 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 592 | 204,800 | y, k, n = list(map(int, input().split()))
mx = n - y + 1
fx = (((y // k) + 1) * k) - y
if fx < mx :
for x in range(fx, mx, k) :
print(x, end = ' ')
print()
else :
print(-1) | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
y, k, n = list(map(int, input().split()))
mx = n - y + 1
fx = (((y // k) + 1) * k) - y
if fx < mx :
for x in range(fx, mx, k) :
print(x, end = ' ')
print()
else :
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
63 | A | Sinking Ship | PROGRAMMING | 900 | [
"implementation",
"sortings",
"strings"
] | A. Sinking Ship | 2 | 256 | The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to *n*) and await further instructions. However, one should evacuate the crew properly, in a stri... | The first line contains an integer *n*, which is the number of people in the crew (1<=≤<=*n*<=≤<=100). Then follow *n* lines. The *i*-th of those lines contains two words — the name of the crew member who is *i*-th in line, and his status on the ship. The words are separated by exactly one space. There are no other spa... | Print *n* lines. The *i*-th of them should contain the name of the crew member who must be the *i*-th one to leave the ship. | [
"6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman\n"
] | [
"Teddy\nAlice\nBob\nJulia\nCharlie\nJack\n"
] | none | 500 | [
{
"input": "6\nJack captain\nAlice woman\nCharlie man\nTeddy rat\nBob child\nJulia woman",
"output": "Teddy\nAlice\nBob\nJulia\nCharlie\nJack"
},
{
"input": "1\nA captain",
"output": "A"
},
{
"input": "1\nAbcdefjhij captain",
"output": "Abcdefjhij"
},
{
"input": "5\nA captain... | 1,694,340,361 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 92 | 0 | l1=[]
l2=[]
l3=[]
l4=[]
for _ in range(int(input())):
x,y=map(str,input().split())
if y=="rat":
l1.append(x)
if y=="woman" or y=="child" :
l2.append(x)
if y=="man":
l3.append(x)
if y=="captain":
l4.append(x)
l1=l1+l2+l3+l4
for i in l1:
print(i) | Title: Sinking Ship
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The ship crashed into a reef and is sinking. Now the entire crew must be evacuated. All *n* crew members have already lined up in a row (for convenience let's label them all from left to right with positive integers from 1 to ... | ```python
l1=[]
l2=[]
l3=[]
l4=[]
for _ in range(int(input())):
x,y=map(str,input().split())
if y=="rat":
l1.append(x)
if y=="woman" or y=="child" :
l2.append(x)
if y=="man":
l3.append(x)
if y=="captain":
l4.append(x)
l1=l1+l2+l3+l4
for i in l1:
print(i)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
9 | C | Hexadecimal's Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"math"
] | C. Hexadecimal's Numbers | 1 | 64 | One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural numbers from 1 to *n* to obtain total control over her energy.
But his plan failed. The reason for th... | Input data contains the only number *n* (1<=≤<=*n*<=≤<=109). | Output the only number — answer to the problem. | [
"10\n"
] | [
"2"
] | For *n* = 10 the answer includes numbers 1 and 10. | 0 | [
{
"input": "10",
"output": "2"
},
{
"input": "20",
"output": "3"
},
{
"input": "72",
"output": "3"
},
{
"input": "99",
"output": "3"
},
{
"input": "100",
"output": "4"
},
{
"input": "101",
"output": "5"
},
{
"input": "102",
"output": "5... | 1,589,200,512 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 248 | 20,172,800 | n=input()
count=1
for i in range(1,len(n)):
if(n[i]=='0'):
count=count*1
else:
count=count*2
count+=(pow(2,len(n)-1)-1)
print(count)
| Title: Hexadecimal's Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural ... | ```python
n=input()
count=1
for i in range(1,len(n)):
if(n[i]=='0'):
count=count*1
else:
count=count*2
count+=(pow(2,len(n)-1)-1)
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,586,809,622 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 218 | 0 | a, b = sorted(map(int,input().split()))
if 6-b==0:
print('1/6')
elif 6-b==1:
print('1/3')
elif 6-b==2:
print('1/2')
elif 6-b==3:
print('2/3')
elif 6-b==4:
print('5/6')
elif 6-b==5:
print('1/1') | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
a, b = sorted(map(int,input().split()))
if 6-b==0:
print('1/6')
elif 6-b==1:
print('1/3')
elif 6-b==2:
print('1/2')
elif 6-b==3:
print('2/3')
elif 6-b==4:
print('5/6')
elif 6-b==5:
print('1/1')
``` | 3.891 | MatrixStudio/Codeforces-Python-Submissions |
670 | B | Game of Robots | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | In late autumn evening *n* robots gathered in the cheerful company of friends. Each robot has a unique identifier — an integer from 1 to 109.
At some moment, robots decided to play the game "Snowball". Below there are the rules of this game. First, all robots stand in a row. Then the first robot says his identifier. A... | The first line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*k*<=≤<=*min*(2·109,<=*n*·(*n*<=+<=1)<=/<=2).
The second line contains the sequence *id*1,<=*id*2,<=...,<=*id**n* (1<=≤<=*id**i*<=≤<=109) — identifiers of roborts. It is guaranteed that all identifiers are different. | Print the *k*-th pronounced identifier (assume that the numeration starts from 1). | [
"2 2\n1 2\n",
"4 5\n10 4 18 3\n"
] | [
"1\n",
"4\n"
] | In the first sample identifiers of robots will be pronounced in the following order: 1, 1, 2. As *k* = 2, the answer equals to 1.
In the second test case identifiers of robots will be pronounced in the following order: 10, 10, 4, 10, 4, 18, 10, 4, 18, 3. As *k* = 5, the answer equals to 4. | 750 | [
{
"input": "2 2\n1 2",
"output": "1"
},
{
"input": "4 5\n10 4 18 3",
"output": "4"
},
{
"input": "1 1\n4",
"output": "4"
},
{
"input": "2 1\n5 1",
"output": "5"
},
{
"input": "2 2\n1 4",
"output": "1"
},
{
"input": "2 3\n6 7",
"output": "7"
},
... | 1,607,074,166 | 2,147,483,647 | Python 3 | OK | TESTS | 143 | 140 | 8,806,400 | n,k = map(int,input().split())
idt = list(map(int,input().split()))
t,count =0,0
for i in range(1,n+1):
count+=i;t=i
if count>=k:
break
ans = t-(count-k)
print(idt[ans-1]) | Title: Game of Robots
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In late autumn evening *n* robots gathered in the cheerful company of friends. Each robot has a unique identifier — an integer from 1 to 109.
At some moment, robots decided to play the game "Snowball". Below there are t... | ```python
n,k = map(int,input().split())
idt = list(map(int,input().split()))
t,count =0,0
for i in range(1,n+1):
count+=i;t=i
if count>=k:
break
ans = t-(count-k)
print(idt[ans-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
797 | C | Minimal string | PROGRAMMING | 1,700 | [
"data structures",
"greedy",
"strings"
] | null | null | Petya recieved a gift of a string *s* with length up to 105 characters for his birthday. He took two more empty strings *t* and *u* and decided to play a game. This game has two possible moves:
- Extract the first character of *s* and append *t* with this character. - Extract the last character of *t* and append *u*... | First line contains non-empty string *s* (1<=≤<=|*s*|<=≤<=105), consisting of lowercase English letters. | Print resulting string *u*. | [
"cab\n",
"acdb\n"
] | [
"abc\n",
"abdc\n"
] | none | 0 | [
{
"input": "cab",
"output": "abc"
},
{
"input": "acdb",
"output": "abdc"
},
{
"input": "a",
"output": "a"
},
{
"input": "ab",
"output": "ab"
},
{
"input": "ba",
"output": "ab"
},
{
"input": "dijee",
"output": "deeji"
},
{
"input": "bhrmc",
... | 1,674,888,927 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 10 | 62 | 0 | from collections import deque, defaultdict
S = input()
chars = list(set(list(S)))
chars.sort()
count_s = defaultdict(lambda: 0)
count_t = defaultdict(lambda: 0)
for s in S:
count_s[s] += 1
# for s in count_s.keys(): # O(N)
# print(s, count_s[s])
priority = deque()
for c in chars: # O(26)
priority.append(c)
ou... | Title: Minimal string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya recieved a gift of a string *s* with length up to 105 characters for his birthday. He took two more empty strings *t* and *u* and decided to play a game. This game has two possible moves:
- Extract the first char... | ```python
from collections import deque, defaultdict
S = input()
chars = list(set(list(S)))
chars.sort()
count_s = defaultdict(lambda: 0)
count_t = defaultdict(lambda: 0)
for s in S:
count_s[s] += 1
# for s in count_s.keys(): # O(N)
# print(s, count_s[s])
priority = deque()
for c in chars: # O(26)
priority.app... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,643,753,013 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 31 | 0 | def main():
list = []
num_planes = int(input())
planes = input().split()
for i in range(num_planes):
list.append(int(planes[i]))
found_tri = False
for i in range(num_planes):
if found_tri == False:
start_plane = list[i] - 1
if list[list[(list[s... | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
def main():
list = []
num_planes = int(input())
planes = input().split()
for i in range(num_planes):
list.append(int(planes[i]))
found_tri = False
for i in range(num_planes):
if found_tri == False:
start_plane = list[i] - 1
if list[li... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
548 | A | Mike and Fax | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"strings"
] | null | null | While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly *k* messages ... | The first line of input contains string *s* containing lowercase English letters (1<=≤<=|*s*|<=≤<=1000).
The second line contains integer *k* (1<=≤<=*k*<=≤<=1000). | Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise. | [
"saba\n2\n",
"saddastavvat\n2\n"
] | [
"NO\n",
"YES\n"
] | Palindrome is a string reading the same forward and backward.
In the second sample, the faxes in his back-bag can be "saddas" and "tavvat". | 500 | [
{
"input": "saba\n2",
"output": "NO"
},
{
"input": "saddastavvat\n2",
"output": "YES"
},
{
"input": "aaaaaaaaaa\n3",
"output": "NO"
},
{
"input": "aaaaaa\n3",
"output": "YES"
},
{
"input": "abaacca\n2",
"output": "NO"
},
{
"input": "a\n1",
"output"... | 1,595,254,958 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 20,172,800 | s=str(input())
n=int(input())
d=len(s)//n
z=set(s)
c=0
for i in z:
if(s.count(i)%2!=0):
c=c+1
if(n%2==0 and c==0):
print('YES')
elif(n%2==0 and c!=0):
print('NO')
elif(n%2!=0 and c!=(d)):
print('NO')
elif(n%2!=0 and c==(d)):
print('YES') | Title: Mike and Fax
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure ... | ```python
s=str(input())
n=int(input())
d=len(s)//n
z=set(s)
c=0
for i in z:
if(s.count(i)%2!=0):
c=c+1
if(n%2==0 and c==0):
print('YES')
elif(n%2==0 and c!=0):
print('NO')
elif(n%2!=0 and c!=(d)):
print('NO')
elif(n%2!=0 and c==(d)):
print('YES')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
732 | B | Cormen --- The Best Friend Of a Man | PROGRAMMING | 1,000 | [
"dp",
"greedy"
] | null | null | Recently a dog was bought for Polycarp. The dog's name is Cormen. Now Polycarp has a lot of troubles. For example, Cormen likes going for a walk.
Empirically Polycarp learned that the dog needs at least *k* walks for any two consecutive days in order to feel good. For example, if *k*<==<=5 and yesterday Polycarp went... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=500) — the number of days and the minimum number of walks with Cormen for any two consecutive days.
The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=500) — the number of walks with Cormen on the *i*-th day which Polyca... | In the first line print the smallest number of additional walks that Polycarp should do during the next *n* days so that Cormen will feel good during all days.
In the second line print *n* integers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* — the total number of walks on the *i*-th day according to the found solutions ... | [
"3 5\n2 0 1\n",
"3 1\n0 0 0\n",
"4 6\n2 4 3 5\n"
] | [
"4\n2 3 2\n",
"1\n0 1 0\n",
"0\n2 4 3 5\n"
] | none | 1,000 | [
{
"input": "3 5\n2 0 1",
"output": "4\n2 3 2"
},
{
"input": "3 1\n0 0 0",
"output": "1\n0 1 0"
},
{
"input": "4 6\n2 4 3 5",
"output": "0\n2 4 3 5"
},
{
"input": "5 1\n0 0 0 0 1",
"output": "2\n0 1 0 1 1"
},
{
"input": "10 500\n164 44 238 205 373 249 87 30 239 90"... | 1,676,104,260 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 70 | 61 | 0 | n,k = map(int,input().split())
a = list(map(int,input().split()))
ans = 0
b = []
for i in range(1,n):
j = k - (a[i] + a[i-1])
a[i] += max(j,0)
ans += max(0,j)
print(ans)
print(*a) | Title: Cormen --- The Best Friend Of a Man
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently a dog was bought for Polycarp. The dog's name is Cormen. Now Polycarp has a lot of troubles. For example, Cormen likes going for a walk.
Empirically Polycarp learned that the dog needs at ... | ```python
n,k = map(int,input().split())
a = list(map(int,input().split()))
ans = 0
b = []
for i in range(1,n):
j = k - (a[i] + a[i-1])
a[i] += max(j,0)
ans += max(0,j)
print(ans)
print(*a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,674,837,164 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 46 | 0 | def power_of_2(x):
for i in range(0,33):
if x == 2**i:
return 0
elif (2**i) > x:
return x - (2**(i-1))
x = int(input())
c = 0
while x != 0:
x = power_of_2(x)
c += 1
print(c) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
def power_of_2(x):
for i in range(0,33):
if x == 2**i:
return 0
elif (2**i) > x:
return x - (2**(i-1))
x = int(input())
c = 0
while x != 0:
x = power_of_2(x)
c += 1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
146 | B | Lucky Mask | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a mask of a positive integer *n* the number that is obtained after successive writing ... | The only line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=105). It is guaranteed that number *b* is lucky. | In the only line print a single number — the number *c* that is sought by Petya. | [
"1 7\n",
"100 47\n"
] | [
"7\n",
"147\n"
] | none | 1,000 | [
{
"input": "1 7",
"output": "7"
},
{
"input": "100 47",
"output": "147"
},
{
"input": "458 47",
"output": "467"
},
{
"input": "7 7",
"output": "17"
},
{
"input": "547 47",
"output": "647"
},
{
"input": "77 77",
"output": "177"
},
{
"input":... | 1,383,026,196 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 265 | 307,200 | def readln(): return tuple(map(int, input().split()))
a, b = readln()
def getmask(d):
v = ''.join([_ for _ in list(str(d)) if _ in ['4', '7']])
return 0 if v == '' else int(v)
c = a + 1
while True:
if getmask(c) == b:
break
c += 1
print(c)
| Title: Lucky Mask
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Pe... | ```python
def readln(): return tuple(map(int, input().split()))
a, b = readln()
def getmask(d):
v = ''.join([_ for _ in list(str(d)) if _ in ['4', '7']])
return 0 if v == '' else int(v)
c = a + 1
while True:
if getmask(c) == b:
break
c += 1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
687 | B | Remainders Game | PROGRAMMING | 1,800 | [
"chinese remainder theorem",
"math",
"number theory"
] | null | null | Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*c**n* and Pari has to tell Arya if Arya wants. Given *k* and the ancient values, tell us if Arya has... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<= *k*<=≤<=1<=000<=000) — the number of ancient integers and value *k* that is chosen by Pari.
The second line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=1<=000<=000). | Print "Yes" (without quotes) if Arya has a winning strategy independent of value of *x*, or "No" (without quotes) otherwise. | [
"4 5\n2 3 5 12\n",
"2 7\n2 3\n"
] | [
"Yes\n",
"No\n"
] | In the first sample, Arya can understand <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/d170efffcde0907ee6bcf32de21051bce0677a2c.png" style="max-width: 100.0%;max-height: 100.0%;"/> because 5 is one of the ancient numbers.
In the second sample, Arya can't be sure what <img align="middle" ... | 1,000 | [
{
"input": "4 5\n2 3 5 12",
"output": "Yes"
},
{
"input": "2 7\n2 3",
"output": "No"
},
{
"input": "1 6\n8",
"output": "No"
},
{
"input": "2 3\n9 4",
"output": "Yes"
},
{
"input": "4 16\n19 16 13 9",
"output": "Yes"
},
{
"input": "5 10\n5 16 19 9 17",
... | 1,668,086,647 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 62 | 2,867,200 | s=list(map(int,input().split()))
n=s[0]
k=s[1]
def gcd(a, b):
if(b == 0):
return abs(a)
else:
return gcd(b, a % b)
c=list(map(int,input().split()))
res=(c[0]*c[1])/gcd(c[0],c[1])
for i in range(2,len(c)):
res=(res*c[i])/gcd(res,c[i])
if res%k==0:
print("Yes")
else:
print("No")
... | Title: Remainders Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*... | ```python
s=list(map(int,input().split()))
n=s[0]
k=s[1]
def gcd(a, b):
if(b == 0):
return abs(a)
else:
return gcd(b, a % b)
c=list(map(int,input().split()))
res=(c[0]*c[1])/gcd(c[0],c[1])
for i in range(2,len(c)):
res=(res*c[i])/gcd(res,c[i])
if res%k==0:
print("Yes")
else:
print... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
7 | A | Kalevitch and Chess | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms"
] | A. Kalevitch and Chess | 2 | 64 | A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch decided to put an end to this tradition and to introduce a new attitude to chessboards.
As before, th... | The input file contains 8 lines, each of the lines contains 8 characters. The given matrix describes the client's requirements, W character stands for a white square, and B character — for a square painted black.
It is guaranteed that client's requirments can be fulfilled with a sequence of allowed strokes (vertical/c... | Output the only number — the minimum amount of rows and columns that Kalevitch has to paint on the white chessboard to meet the client's requirements. | [
"WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\n",
"WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\n"
] | [
"3\n",
"1\n"
] | none | 0 | [
{
"input": "WWWBWWBW\nBBBBBBBB\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW\nWWWBWWBW",
"output": "3"
},
{
"input": "WWWWWWWW\nBBBBBBBB\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW",
"output": "1"
},
{
"input": "WWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWWWW\nWWWWWW... | 1,382,617,593 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 307,200 | s, m = 0, 0
for i in range(8):
t = input()
if t == 'BBBBBBBB': s += 1
else: m = max(m, t.count('B'))
print(s + m if m != 8 else s) | Title: Kalevitch and Chess
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A famous Berland's painter Kalevitch likes to shock the public. One of his last obsessions is chess. For more than a thousand years people have been playing this old game on uninteresting, monotonous boards. Kalevitch de... | ```python
s, m = 0, 0
for i in range(8):
t = input()
if t == 'BBBBBBBB': s += 1
else: m = max(m, t.count('B'))
print(s + m if m != 8 else s)
``` | 3.966711 | MatrixStudio/Codeforces-Python-Submissions |
295 | A | Greg and Array | PROGRAMMING | 1,400 | [
"data structures",
"implementation"
] | null | null | Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array elements with numbers *l**i*,<=*l**i*<=+<=1,<=...,<=*r**i* by value *d**i*.
Greg wrote down *k* qu... | The first line contains integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=105). The second line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=105) — the initial array.
Next *m* lines contain operations, the operation number *i* is written as three integers: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=... | On a single line print *n* integers *a*1,<=*a*2,<=...,<=*a**n* — the array after executing all the queries. Separate the printed numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier. | [
"3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3\n",
"1 1 1\n1\n1 1 1\n1 1\n",
"4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3\n"
] | [
"9 18 17\n",
"2\n",
"5 18 31 20\n"
] | none | 500 | [
{
"input": "3 3 3\n1 2 3\n1 2 1\n1 3 2\n2 3 4\n1 2\n1 3\n2 3",
"output": "9 18 17"
},
{
"input": "1 1 1\n1\n1 1 1\n1 1",
"output": "2"
},
{
"input": "4 3 6\n1 2 3 4\n1 2 1\n2 3 2\n3 4 4\n1 2\n1 3\n2 3\n1 2\n1 3\n2 3",
"output": "5 18 31 20"
},
{
"input": "1 1 1\n0\n1 1 0\n1 1... | 1,691,006,791 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 1,247 | 28,160,000 | n, m, k= map(int,input().split())
arr = list(map(int, input().split()))
q = [list(map(int,input().split())) for i in range(m)]
b = [0]*(n+1)
B = [0]*(m+1)
for i in range(k):
x,y = map(int, input().split())
B[x-1]+=1
B[y]-=1
count=0
for i,(x,y,d) in enumerate(q):
count+=B[i]
b[x... | Title: Greg and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg has an array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n* and *m* operations. Each operation looks as: *l**i*, *r**i*, *d**i*, (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). To apply operation *i* to the array means to increase all array... | ```python
n, m, k= map(int,input().split())
arr = list(map(int, input().split()))
q = [list(map(int,input().split())) for i in range(m)]
b = [0]*(n+1)
B = [0]*(m+1)
for i in range(k):
x,y = map(int, input().split())
B[x-1]+=1
B[y]-=1
count=0
for i,(x,y,d) in enumerate(q):
count+=B[i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
168 | A | Wizards and Demonstration | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n*<=-<=*x* people) do not support the wizards and aren't going to go to the demonstration. We know that the city... | The first line contains three space-separated integers, *n*, *x*, *y* (1<=≤<=*n*,<=*x*,<=*y*<=≤<=104,<=*x*<=≤<=*n*) — the number of citizens in the city, the number of wizards and the percentage the administration needs, correspondingly.
Please note that *y* can exceed 100 percent, that is, the administration wants to... | Print a single integer — the answer to the problem, the minimum number of clones to create, so that the demonstration involved no less than *y* percent of *n* (the real total city population). | [
"10 1 14\n",
"20 10 50\n",
"1000 352 146\n"
] | [
"1\n",
"0\n",
"1108\n"
] | In the first sample it is necessary that at least 14% of 10 people came to the demonstration. As the number of people should be integer, then at least two people should come. There is only one wizard living in the city and he is going to come. That isn't enough, so he needs to create one clone.
In the second sample 1... | 500 | [
{
"input": "10 1 14",
"output": "1"
},
{
"input": "20 10 50",
"output": "0"
},
{
"input": "1000 352 146",
"output": "1108"
},
{
"input": "68 65 20",
"output": "0"
},
{
"input": "78 28 27",
"output": "0"
},
{
"input": "78 73 58",
"output": "0"
},
... | 1,632,924,050 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 60 | 0 | import math
n,x,y = [int (x) for x in input().split()]
r = int(math.ceil((y/100)*n))
diff = abs(x-r)
print(diff)
| Title: Wizards and Demonstration
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n... | ```python
import math
n,x,y = [int (x) for x in input().split()]
r = int(math.ceil((y/100)*n))
diff = abs(x-r)
print(diff)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,646,589,043 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 186 | 102,400 | n = input()
i= 0
sum = 0
counter = 0
while len(str(n))>1:
for i in range (0,len(str(n))):
sum = sum + int(str(n[i]))
n = str(sum)
counter = counter+1
sum = 0
print(counter) | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
n = input()
i= 0
sum = 0
counter = 0
while len(str(n))>1:
for i in range (0,len(str(n))):
sum = sum + int(str(n[i]))
n = str(sum)
counter = counter+1
sum = 0
print(counter)
``` | 3.953316 | MatrixStudio/Codeforces-Python-Submissions |
651 | A | Joysticks | PROGRAMMING | 1,100 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if n... | The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively. | Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged. | [
"3 5\n",
"4 4\n"
] | [
"6\n",
"5\n"
] | In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joyst... | 500 | [
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
... | 1,607,430,172 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 124 | 0 | a1, a2 = [int(s) for s in input().split()]
ans = 0
while a1 > 0 and a2 > 0:
ans += 1
if a1 <= a2:
a1 += 1
a2 -= 2
else:
a1 -= 2
a2 += 1
print(ans)
| Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick on... | ```python
a1, a2 = [int(s) for s in input().split()]
ans = 0
while a1 > 0 and a2 > 0:
ans += 1
if a1 <= a2:
a1 += 1
a2 -= 2
else:
a1 -= 2
a2 += 1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
897 | B | Chtholly's request | PROGRAMMING | 1,300 | [
"brute force"
] | null | null | — I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thinking about a problem for days:
If a number is palindrome and length of its decimal representation with... | The first line contains two integers *k* and *p* (1<=≤<=*k*<=≤<=105,<=1<=≤<=*p*<=≤<=109). | Output single integer — answer to the problem. | [
"2 100\n",
"5 30\n"
] | [
"33\n",
"15\n"
] | In the first example, the smallest zcy number is 11, and the second smallest zcy number is 22.
In the second example, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/68fffad54395f7d920ad0384e07c6215ddc64141.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 1,000 | [
{
"input": "2 100",
"output": "33"
},
{
"input": "5 30",
"output": "15"
},
{
"input": "42147 412393322",
"output": "251637727"
},
{
"input": "77809 868097296",
"output": "440411873"
},
{
"input": "5105 443422097",
"output": "363192634"
},
{
"input": "7... | 1,626,034,637 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 6,758,400 | k, p = [int(i) for i in input().split()]
ans = 0
for i in range(1, k+1):
st = str(i)
sz = len(st)
if sz + sz > k: break
num = int( st[::-1] + st ) % p
ans = ans % p + num % p
ans %= p
print(ans % p)
| Title: Chtholly's request
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
— I experienced so many great things.
— You gave me memories like dreams... But I have to leave now...
— One last request, can you...
— Help me solve a Codeforces problem?
— ......
— What?
Chtholly has been thi... | ```python
k, p = [int(i) for i in input().split()]
ans = 0
for i in range(1, k+1):
st = str(i)
sz = len(st)
if sz + sz > k: break
num = int( st[::-1] + st ) % p
ans = ans % p + num % p
ans %= p
print(ans % p)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,585,196,590 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 216 | 0 | import math
a,b,n=map(int,input().split())
temp=a
count=0
while(1):
if n>=(math.gcd(temp,n)):
n=n-math.gcd(temp,n)
count=count+1
temp=b if count%2 else a
else:
break
print ('0' if count%2 else '1') | Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
import math
a,b,n=map(int,input().split())
temp=a
count=0
while(1):
if n>=(math.gcd(temp,n)):
n=n-math.gcd(temp,n)
count=count+1
temp=b if count%2 else a
else:
break
print ('0' if count%2 else '1')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,695,010,147 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 154 | 0 | n = int(input())
x,o = 0,0
for i in range(1,n):
v = [int(n) for n in input().split()]
x -= v[0]
x += v[1]
c = max(o,x)
print(c) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
n = int(input())
x,o = 0,0
for i in range(1,n):
v = [int(n) for n in input().split()]
x -= v[0]
x += v[1]
c = max(o,x)
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,626,779,921 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 77 | 6,758,400 | a=input()
b=input()
s=str(int(a)+int(b))
print('0'*(len(a)-len(s))+s.replace('2','0')) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
a=input()
b=input()
s=str(int(a)+int(b))
print('0'*(len(a)-len(s))+s.replace('2','0'))
``` | 3.968161 | MatrixStudio/Codeforces-Python-Submissions |
919 | A | Supermarket | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation"
] | null | null | We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (You don't need to care about what "yuan" is), the same as $a/b$ yuan for a kilo.
Now imagine you'd... | The first line contains two positive integers $n$ and $m$ ($1 \leq n \leq 5\,000$, $1 \leq m \leq 100$), denoting that there are $n$ supermarkets and you want to buy $m$ kilos of apples.
The following $n$ lines describe the information of the supermarkets. Each line contains two positive integers $a, b$ ($1 \leq a, b ... | The only line, denoting the minimum cost for $m$ kilos of apples. Please make sure that the absolute or relative error between your answer and the correct answer won't exceed $10^{-6}$.
Formally, let your answer be $x$, and the jury's answer be $y$. Your answer is considered correct if $\frac{|x - y|}{\max{(1, |y|)}} ... | [
"3 5\n1 2\n3 4\n1 3\n",
"2 1\n99 100\n98 99\n"
] | [
"1.66666667\n",
"0.98989899\n"
] | In the first sample, you are supposed to buy $5$ kilos of apples in supermarket $3$. The cost is $5/3$ yuan.
In the second sample, you are supposed to buy $1$ kilo of apples in supermarket $2$. The cost is $98/99$ yuan. | 500 | [
{
"input": "3 5\n1 2\n3 4\n1 3",
"output": "1.66666667"
},
{
"input": "2 1\n99 100\n98 99",
"output": "0.98989899"
},
{
"input": "50 37\n78 49\n96 4\n86 62\n28 4\n19 2\n79 43\n79 92\n95 35\n33 60\n54 84\n90 25\n2 25\n53 21\n86 52\n72 25\n6 78\n41 46\n3 68\n42 89\n33 35\n57 43\n99 45\n1 8... | 1,666,329,972 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | n,m=map(int,input().split())
p=1000000000000000000000
for i in range(n):
a,b=map(int,input().split())
if m/b*a<p:
p=m/b*a
print(p) | Title: Supermarket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (Yo... | ```python
n,m=map(int,input().split())
p=1000000000000000000000
for i in range(n):
a,b=map(int,input().split())
if m/b*a<p:
p=m/b*a
print(p)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
246 | B | Increase and Decrease | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | null | null | Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that Polycarpus performs the following operation multiple times:
- he chooses two elements of the array *a**i... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the array size. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=104) — the original array. | Print a single integer — the maximum number of equal array elements he can get if he performs an arbitrary number of the given operation. | [
"2\n2 1\n",
"3\n1 4 1\n"
] | [
"1\n",
"3\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 4 1",
"output": "3"
},
{
"input": "4\n2 -7 -2 -6",
"output": "3"
},
{
"input": "4\n2 0 -2 -1",
"output": "3"
},
{
"input": "6\n-1 1 0 0 -1 -1",
"output": "5"
},
{
"input": "5\n0 0 0 0 0",
"outp... | 1,628,182,772 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 186 | 10,240,000 |
a=input()
b=list(map(int,input().split()))
c=sum(b)
d=c//len(b)
def ok():
if c%len(b)==0:
return len(b)
else:
return len(b)-1
print(ok()) | Title: Increase and Decrease
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has an array, consisting of *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Polycarpus likes it when numbers in an array match. That's why he wants the array to have as many equal numbers as possible. For that... | ```python
a=input()
b=list(map(int,input().split()))
c=sum(b)
d=c//len(b)
def ok():
if c%len(b)==0:
return len(b)
else:
return len(b)-1
print(ok())
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
405 | A | Gravity Flip | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the box arranged in a line. The *i*-th column contains *a**i* cubes. At first, the gravity in the box is... | The first line of input contains an integer *n* (1<=≤<=*n*<=≤<=100), the number of the columns in the box. The next line contains *n* space-separated integer numbers. The *i*-th number *a**i* (1<=≤<=*a**i*<=≤<=100) denotes the number of cubes in the *i*-th column. | Output *n* integer numbers separated by spaces, where the *i*-th number is the amount of cubes in the *i*-th column after the gravity switch. | [
"4\n3 2 1 2\n",
"3\n2 3 8\n"
] | [
"1 2 2 3 \n",
"2 3 8 \n"
] | The first example case is shown on the figure. The top cube of the first column falls to the top of the last column; the top cube of the second column falls to the top of the third column; the middle cube of the first column falls to the top of the second column.
In the second example case the gravity switch does not ... | 500 | [
{
"input": "4\n3 2 1 2",
"output": "1 2 2 3 "
},
{
"input": "3\n2 3 8",
"output": "2 3 8 "
},
{
"input": "5\n2 1 2 1 2",
"output": "1 1 2 2 2 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n4 3",
"output": "3 4 "
},
{
"input": "6\n100 40 60 20... | 1,695,028,657 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | n = int(input())
l1 = list(map(int,input().split()))
l2 = l1.copy()
l2.sort()
for j in range(n):
print(l2[j],end = " ") | Title: Gravity Flip
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Chris is bored during his physics lessons (too easy), so he has built a toy box to keep himself occupied. The box is special, since it has the ability to change gravity.
There are *n* columns of toy cubes in the bo... | ```python
n = int(input())
l1 = list(map(int,input().split()))
l2 = l1.copy()
l2.sort()
for j in range(n):
print(l2[j],end = " ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
359 | C | Prime Number | PROGRAMMING | 1,900 | [
"math",
"number theory"
] | null | null | Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common denominator and summed them up, he got a fraction: , where number *t* equals *x**a*1<=+<=*a*2<=+<=...... | The first line contains two positive integers *n* and *x* (1<=≤<=*n*<=≤<=105, 2<=≤<=*x*<=≤<=109) — the size of the array and the prime number.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*<=≤<=109). | Print a single number — the answer to the problem modulo 1000000007 (109<=+<=7). | [
"2 2\n2 2\n",
"3 3\n1 2 3\n",
"2 2\n29 29\n",
"4 5\n0 0 0 0\n"
] | [
"8\n",
"27\n",
"73741817\n",
"1\n"
] | In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7745f7cc87c6c5f753e3414fad9baa3b1e3fea48.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Thus, the answer to the problem is 8.
In the second sample, <img align="middle" class="tex-formula" src="https://espresso.codef... | 1,500 | [
{
"input": "2 2\n2 2",
"output": "8"
},
{
"input": "3 3\n1 2 3",
"output": "27"
},
{
"input": "2 2\n29 29",
"output": "73741817"
},
{
"input": "4 5\n0 0 0 0",
"output": "1"
},
{
"input": "1 2\n1000000000",
"output": "1"
},
{
"input": "26 2\n0 0 0 0 0 0... | 1,683,846,427 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 93 | 12,800,000 | M=1000000007
def modpow(x, p):
if p==0:
return 1
y=modpow(x, p//2)
if p%2:
return (y*y*x)%M
return (y*y)%M
n,x=[int(e) for e in input().split()]
a=[int(e) for e in input().split()]
asum=sum(a)
a=[asum-e for e in a][::-1]
ans=0
i=0
c=0
while 1:
ans+=a[i]-ans
I=i
... | Title: Prime Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common den... | ```python
M=1000000007
def modpow(x, p):
if p==0:
return 1
y=modpow(x, p//2)
if p%2:
return (y*y*x)%M
return (y*y)%M
n,x=[int(e) for e in input().split()]
a=[int(e) for e in input().split()]
asum=sum(a)
a=[asum-e for e in a][::-1]
ans=0
i=0
c=0
while 1:
ans+=a[i]-ans
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,590,440,204 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 307,200 | n=int(input())
v,m=[],[]
while n:
a,b=[int(y) for y in input().split()]
v.append(a)
m.append(b)
n-=1
menor=100000000000
maior=-1
indice=0
indice1=0
for i in range(len(v)):
if v[i]<=menor:
menor=v[i]
indice=i+1
if m[i]>=maior and v[i]==menor:
maior=m[i]
indice1=i+1... | Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
n=int(input())
v,m=[],[]
while n:
a,b=[int(y) for y in input().split()]
v.append(a)
m.append(b)
n-=1
menor=100000000000
maior=-1
indice=0
indice1=0
for i in range(len(v)):
if v[i]<=menor:
menor=v[i]
indice=i+1
if m[i]>=maior and v[i]==menor:
maior=m[i]
i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
814 | B | An express train to reveries | PROGRAMMING | 1,300 | [
"constructive algorithms"
] | null | null | Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her fancies would be realized.
On that night, Sengoku constructed a permutation *p*1,<=*p*2,<=...,<=*p**n* of intege... | The first line of input contains a positive integer *n* (2<=≤<=*n*<=≤<=1<=000) — the length of Sengoku's permutation, being the length of both meteor outbursts at the same time.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the sequence of colours in the firs... | Output *n* space-separated integers *p*1,<=*p*2,<=...,<=*p**n*, denoting a possible permutation Sengoku could have had. If there are more than one possible answer, output any one of them.
Input guarantees that such permutation exists. | [
"5\n1 2 3 4 3\n1 2 5 4 5\n",
"5\n4 4 2 3 1\n5 4 5 3 1\n",
"4\n1 1 3 4\n1 4 3 4\n"
] | [
"1 2 5 4 3\n",
"5 4 2 3 1\n",
"1 2 3 4\n"
] | In the first sample, both 1, 2, 5, 4, 3 and 1, 2, 3, 4, 5 are acceptable outputs.
In the second sample, 5, 4, 2, 3, 1 is the only permutation to satisfy the constraints. | 1,000 | [
{
"input": "5\n1 2 3 4 3\n1 2 5 4 5",
"output": "1 2 5 4 3"
},
{
"input": "5\n4 4 2 3 1\n5 4 5 3 1",
"output": "5 4 2 3 1"
},
{
"input": "4\n1 1 3 4\n1 4 3 4",
"output": "1 2 3 4"
},
{
"input": "10\n1 2 3 4 7 6 7 8 9 10\n1 2 3 4 5 6 5 8 9 10",
"output": "1 2 3 4 5 6 7 8 9... | 1,496,840,862 | 3,162 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 46 | 0 | n=int(input())
a=[int(x) for x in input().split()]
b=[int(x) for x in input().split()]
c=[0]*n
d=set([x for x in range(1,n+1)])
for x in range(n):
if a[x]==b[x]:
c[x]=a[x]
d.remove(a[x])
elif a.count(a[x])+b.count(a[x])==1:
c[x]=a[x]
d.remove(a[x])
elif a.count(b[... | Title: An express train to reveries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sengoku still remembers the mysterious "colourful meteoroids" she discovered with Lala-chan when they were little. In particular, one of the nights impressed her deeply, giving her the illusion that all her... | ```python
n=int(input())
a=[int(x) for x in input().split()]
b=[int(x) for x in input().split()]
c=[0]*n
d=set([x for x in range(1,n+1)])
for x in range(n):
if a[x]==b[x]:
c[x]=a[x]
d.remove(a[x])
elif a.count(a[x])+b.count(a[x])==1:
c[x]=a[x]
d.remove(a[x])
elif ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
633 | A | Ebony and Ivory | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
For every bullet that hits the shield, Ebony deals *a* units of damage while Ivory deals *b* units of ... | The first line of the input contains three integers *a*, *b*, *c* (1<=≤<=*a*,<=*b*<=≤<=100,<=1<=≤<=*c*<=≤<=10<=000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively. | Print "Yes" (without quotes) if Dante can deal exactly *c* damage to the shield and "No" (without quotes) otherwise. | [
"4 6 15\n",
"3 2 7\n",
"6 11 6\n"
] | [
"No\n",
"Yes\n",
"Yes\n"
] | In the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage. | 250 | [
{
"input": "4 6 15",
"output": "No"
},
{
"input": "3 2 7",
"output": "Yes"
},
{
"input": "6 11 6",
"output": "Yes"
},
{
"input": "3 12 15",
"output": "Yes"
},
{
"input": "5 5 10",
"output": "Yes"
},
{
"input": "6 6 7",
"output": "No"
},
{
"... | 1,593,518,595 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 64 | 140 | 20,172,800 | import math
a,b,c=map(int,input().split())
y=0
while (c-(b*y))>0:
if (c-(b*y))%a==0:
print("Yes")
exit()
y+=1
print("No")
| Title: Ebony and Ivory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
F... | ```python
import math
a,b,c=map(int,input().split())
y=0
while (c-(b*y))>0:
if (c-(b*y))%a==0:
print("Yes")
exit()
y+=1
print("No")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,697,347,316 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n, m = map(int, input().split())
bulbs = [0]*(m+1)
for i in range(n):
x = map(int, input().split())
for j in x[1:]:
bulbs[j] += 1
if all(bulbs[i]>0 for i in bulbs[1:]):
print('YES')
else:
print('NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n, m = map(int, input().split())
bulbs = [0]*(m+1)
for i in range(n):
x = map(int, input().split())
for j in x[1:]:
bulbs[j] += 1
if all(bulbs[i]>0 for i in bulbs[1:]):
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
451 | A | Game With Sticks | PROGRAMMING | 900 | [
"implementation"
] | null | null | After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid show... | The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). | Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. | [
"2 2\n",
"2 3\n",
"3 3\n"
] | [
"Malvika\n",
"Malvika\n",
"Akshat\n"
] | Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remov... | 500 | [
{
"input": "2 2",
"output": "Malvika"
},
{
"input": "2 3",
"output": "Malvika"
},
{
"input": "3 3",
"output": "Akshat"
},
{
"input": "20 68",
"output": "Malvika"
},
{
"input": "1 1",
"output": "Akshat"
},
{
"input": "1 2",
"output": "Akshat"
},
... | 1,689,446,640 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 46 | 0 | m,n=map(int,input().split())
if (min(m,n)%2==0):
print("Malvika")
else:
print("Akshat") | Title: Game With Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid... | ```python
m,n=map(int,input().split())
if (min(m,n)%2==0):
print("Malvika")
else:
print("Akshat")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
552 | B | Vanya and Books | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assigned distinct numbers.
Vanya wants to know how many digits he will have to write down as he labels th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109) — the number of books in the library. | Print the number of digits needed to number all the books. | [
"13\n",
"4\n"
] | [
"17\n",
"4\n"
] | Note to the first test. The books get numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, which totals to 17 digits.
Note to the second sample. The books get numbers 1, 2, 3, 4, which totals to 4 digits. | 1,000 | [
{
"input": "13",
"output": "17"
},
{
"input": "4",
"output": "4"
},
{
"input": "100",
"output": "192"
},
{
"input": "99",
"output": "189"
},
{
"input": "1000000000",
"output": "8888888899"
},
{
"input": "1000000",
"output": "5888896"
},
{
"... | 1,613,583,701 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 77 | 307,200 | n=int(input())
p=n
i=1
l=1
sd=0
s=0
j=1
while(n>9):
n=n/10
i*=10
l+=1
if p>9:
while i!=1:
s=p-i
if j==1:
s+=1
sd+=s*l
p=i
i=i/10
l-=1
p=9
print(p+sd) | Title: Vanya and Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assig... | ```python
n=int(input())
p=n
i=1
l=1
sd=0
s=0
j=1
while(n>9):
n=n/10
i*=10
l+=1
if p>9:
while i!=1:
s=p-i
if j==1:
s+=1
sd+=s*l
p=i
i=i/10
l-=1
p=9
print(p+sd)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
685 | B | Kay and Snowflake | PROGRAMMING | 1,900 | [
"data structures",
"dfs and similar",
"dp",
"trees"
] | null | null | After the piece of a devilish mirror hit the Kay's eye, he is no longer interested in the beauty of the roses. Now he likes to watch snowflakes.
Once upon a time, he found a huge snowflake that has a form of the tree (connected acyclic graph) consisting of *n* nodes. The root of tree has index 1. Kay is very intereste... | The first line of the input contains two integers *n* and *q* (2<=≤<=*n*<=≤<=300<=000, 1<=≤<=*q*<=≤<=300<=000) — the size of the initial tree and the number of queries respectively.
The second line contains *n*<=-<=1 integer *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the indices of the parents of the nodes fr... | For each query print the index of a centroid of the corresponding subtree. If there are many suitable nodes, print any of them. It's guaranteed, that each subtree has at least one centroid. | [
"7 4\n1 1 3 3 5 3\n1\n2\n3\n5\n"
] | [
"3\n2\n3\n6\n"
] | The first query asks for a centroid of the whole tree — this is node 3. If we delete node 3 the tree will split in four components, two of size 1 and two of size 2.
The subtree of the second node consists of this node only, so the answer is 2.
Node 3 is centroid of its own subtree.
The centroids of the subtree of th... | 1,250 | [
{
"input": "7 4\n1 1 3 3 5 3\n1\n2\n3\n5",
"output": "3\n2\n3\n6"
},
{
"input": "2 2\n1\n1\n2",
"output": "2\n2"
}
] | 1,617,049,697 | 2,897 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include "bits/stdc++.h"
using namespace std;
#define _ ios_base::sync_with_stdio(0);cin.tie(0);
#define endl '\n'
#define debug(x) cerr << #x << " == " << (x) << '\n';
#define all(X) begin(X), end(X)
#define size(X) (int)std::size(X)
using ll = long long;
const int INF = 0x3f3f3f3f;
const ll LINF = 0x3f3f3f3f3f3f3... | Title: Kay and Snowflake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the piece of a devilish mirror hit the Kay's eye, he is no longer interested in the beauty of the roses. Now he likes to watch snowflakes.
Once upon a time, he found a huge snowflake that has a form of the tree... | ```python
#include "bits/stdc++.h"
using namespace std;
#define _ ios_base::sync_with_stdio(0);cin.tie(0);
#define endl '\n'
#define debug(x) cerr << #x << " == " << (x) << '\n';
#define all(X) begin(X), end(X)
#define size(X) (int)std::size(X)
using ll = long long;
const int INF = 0x3f3f3f3f;
const ll LINF = 0x3f3... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,556,137,781 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | '''
روزی روزگاری
'''
c = 0
ans=[False]*90
n=int(input())
a = [*map(int,input().split())]
for i in a:
ans[i-1]=True
y=range(90)
for i in y:
if ans[i]==False:
c+=1
else:
c=0
if c==15:
print(i+1)
break | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
'''
روزی روزگاری
'''
c = 0
ans=[False]*90
n=int(input())
a = [*map(int,input().split())]
for i in a:
ans[i-1]=True
y=range(90)
for i in y:
if ans[i]==False:
c+=1
else:
c=0
if c==15:
print(i+1)
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
886 | A | ACM ICPC | PROGRAMMING | 1,000 | [
"brute force"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. ... | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 500 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,653,604,300 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 46 | 0 | from sys import exit
a=list(map(int,input().split()))
a=sorted(a)
sum=0
for i in a:
sum=sum+i
half=sum/2
half=half-a[-1]
a.pop(-1)
for i in a:
x=a.pop(i)
rest=half-x
if rest in a:
print("YES")
exit()
a.insert(i, x)
print("NO") | Title: ACM ICPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build ... | ```python
from sys import exit
a=list(map(int,input().split()))
a=sorted(a)
sum=0
for i in a:
sum=sum+i
half=sum/2
half=half-a[-1]
a.pop(-1)
for i in a:
x=a.pop(i)
rest=half-x
if rest in a:
print("YES")
exit()
a.insert(i, x)
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
803 | B | Distances to Zero | PROGRAMMING | 1,200 | [
"constructive algorithms"
] | null | null | You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the given array. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — length of the array *a*. The second line contains integer elements of the array separated by single spaces (<=-<=109<=≤<=*a**i*<=≤<=109). | Print the sequence *d*0,<=*d*1,<=...,<=*d**n*<=-<=1, where *d**i* is the difference of indices between *i* and nearest *j* such that *a**j*<==<=0. It is possible that *i*<==<=*j*. | [
"9\n2 1 0 3 0 0 3 2 4\n",
"5\n0 1 2 3 4\n",
"7\n5 6 0 1 -2 3 4\n"
] | [
"2 1 0 1 0 0 1 2 3 ",
"0 1 2 3 4 ",
"2 1 0 1 2 3 4 "
] | none | 0 | [
{
"input": "9\n2 1 0 3 0 0 3 2 4",
"output": "2 1 0 1 0 0 1 2 3 "
},
{
"input": "5\n0 1 2 3 4",
"output": "0 1 2 3 4 "
},
{
"input": "7\n5 6 0 1 -2 3 4",
"output": "2 1 0 1 2 3 4 "
},
{
"input": "1\n0",
"output": "0 "
},
{
"input": "2\n0 0",
"output": "0 0 "
... | 1,584,770,574 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 15 | 2,000 | 18,329,600 | t=int(input())
a=list(map(int,input().split()))[:t]
b=[]
for i in range(t):
if a[i]==0:
b.append(i)
for i in range(t):
c=[]
for j in range(len(b)):
c.append(abs(b[j]-i))
print(min(c),end=" ")
| Title: Distances to Zero
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the array of integer numbers *a*0,<=*a*1,<=...,<=*a**n*<=-<=1. For each element find the distance to the nearest zero (to the element which equals to zero). There is at least one zero element in the give... | ```python
t=int(input())
a=list(map(int,input().split()))[:t]
b=[]
for i in range(t):
if a[i]==0:
b.append(i)
for i in range(t):
c=[]
for j in range(len(b)):
c.append(abs(b[j]-i))
print(min(c),end=" ")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
460 | C | Present | PROGRAMMING | 1,700 | [
"binary search",
"data structures",
"greedy"
] | null | null | Little beaver is a beginner programmer, so informatics is his favorite subject. Soon his informatics teacher is going to have a birthday and the beaver has decided to prepare a present for her. He planted *n* flowers in a row on his windowsill and started waiting for them to grow. However, after some time the beaver no... | The first line contains space-separated integers *n*, *m* and *w* (1<=≤<=*w*<=≤<=*n*<=≤<=105; 1<=≤<=*m*<=≤<=105). The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the maximum final height of the smallest flower. | [
"6 2 3\n2 2 2 2 1 1\n",
"2 5 1\n5 8\n"
] | [
"2\n",
"9\n"
] | In the first sample beaver can water the last 3 flowers at the first day. On the next day he may not to water flowers at all. In the end he will get the following heights: [2, 2, 2, 3, 2, 2]. The smallest flower has height equal to 2. It's impossible to get height 3 in this test. | 1,500 | [
{
"input": "6 2 3\n2 2 2 2 1 1",
"output": "2"
},
{
"input": "2 5 1\n5 8",
"output": "9"
},
{
"input": "1 1 1\n1",
"output": "2"
},
{
"input": "3 2 3\n999999998 999999998 999999998",
"output": "1000000000"
},
{
"input": "10 8 3\n499 498 497 497 497 497 497 497 498... | 1,686,114,979 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 62 | 2,457,600 | # 线段树建树
def buildTree(o, l, r):
if l == r:
tree[o] = a[l]
return
mid = (l + r) // 2 # 分割区间的中点,对应左孩子区间结束,右孩子区间开头
left, right = 2 * o, 2 * o + 1
buildTree(left, l, mid)
buildTree(right, mid + 1, r)
tree[o] = min(tree[left],tree[right])
# 查询区间和
def query(o, l, r, ql,... | Title: Present
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little beaver is a beginner programmer, so informatics is his favorite subject. Soon his informatics teacher is going to have a birthday and the beaver has decided to prepare a present for her. He planted *n* flowers in a row o... | ```python
# 线段树建树
def buildTree(o, l, r):
if l == r:
tree[o] = a[l]
return
mid = (l + r) // 2 # 分割区间的中点,对应左孩子区间结束,右孩子区间开头
left, right = 2 * o, 2 * o + 1
buildTree(left, l, mid)
buildTree(right, mid + 1, r)
tree[o] = min(tree[left],tree[right])
# 查询区间和
def query(o,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
680 | B | Bear and Finding Criminals | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city *a*. His job is to catch criminals. It's hard because he doesn't know in which cities criminals are. Though, he... | The first line of the input contains two integers *n* and *a* (1<=≤<=*a*<=≤<=*n*<=≤<=100) — the number of cities and the index of city where Limak lives.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=≤<=1). There are *t**i* criminals in the *i*-th city. | Print the number of criminals Limak will catch. | [
"6 3\n1 1 1 0 1 0\n",
"5 2\n0 0 0 1 0\n"
] | [
"3\n",
"1\n"
] | In the first sample, there are six cities and Limak lives in the third one (blue arrow below). Criminals are in cities marked red.
Using the BCD gives Limak the following information:
- There is one criminal at distance 0 from the third city — Limak is sure that this criminal is exactly in the third city. - There i... | 1,000 | [
{
"input": "6 3\n1 1 1 0 1 0",
"output": "3"
},
{
"input": "5 2\n0 0 0 1 0",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "9 3\n1 1 1 1 1 1 1 1 0",
"output": "8"
},
{
"input": "9 5\n1 0 1 0 1 0... | 1,586,274,125 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 307,200 | import sys
lines = sys.stdin.readlines()
(n, a) = map(int, lines[0].strip().split(" "))
nums = list(map(int, lines[1].strip().split(" ")))
res = 0
if nums[a-1] == 1: res += 1
for i in range(1, min(a-1, n-a) + 1):
if nums[a-i-1] == 1 and nums[a+i-1] == 1:
res += 2
if a * 2 -1 < n:
for i in range(a*2, n)... | Title: Bear and Finding Criminals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city... | ```python
import sys
lines = sys.stdin.readlines()
(n, a) = map(int, lines[0].strip().split(" "))
nums = list(map(int, lines[1].strip().split(" ")))
res = 0
if nums[a-1] == 1: res += 1
for i in range(1, min(a-1, n-a) + 1):
if nums[a-i-1] == 1 and nums[a+i-1] == 1:
res += 2
if a * 2 -1 < n:
for i in ran... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain num... | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,657,140,329 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 93 | 512,000 | s=input().split()
amount=int(s[0])
number=int(s[1])
c=0
def f(y,x):
z=0
for i in range(1,x):
if y%i==0:
z+=1
return z
if f(number,amount)==1:
c+=1
if amount<number:
print(0)
else:
print(2)
if c==0:
print(f(amount,number))
| Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
Y... | ```python
s=input().split()
amount=int(s[0])
number=int(s[1])
c=0
def f(y,x):
z=0
for i in range(1,x):
if y%i==0:
z+=1
return z
if f(number,amount)==1:
c+=1
if amount<number:
print(0)
else:
print(2)
if c==0:
print(f(amount,number))
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for ... | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use al... | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,671,982,436 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | n,k = map(int,input().split())
ar = list(map(int,input().split()))
s = sorted(ar)
x = []
i = 0
while k > 0 and i <n:
idx = ar.index(s[i])
x.append(idx+1)
k-=ar[idx]
ar[idx] = 0
i+=1
if k <0:x.pop()
print(len(x))
if x:print(*x) | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr ... | ```python
n,k = map(int,input().split())
ar = list(map(int,input().split()))
s = sorted(ar)
x = []
i = 0
while k > 0 and i <n:
idx = ar.index(s[i])
x.append(idx+1)
k-=ar[idx]
ar[idx] = 0
i+=1
if k <0:x.pop()
print(len(x))
if x:print(*x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,633,783,581 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 6,758,400 | s = input()
a, b = 0, 0
for i in s:
if i.islower():
a += 1
elif i.isupper():
b += 1
if a >= b:
print(s.lower())
elif a < b:
print(s.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
a, b = 0, 0
for i in s:
if i.islower():
a += 1
elif i.isupper():
b += 1
if a >= b:
print(s.lower())
elif a < b:
print(s.upper())
``` | 3.948911 | MatrixStudio/Codeforces-Python-Submissions |
644 | A | Parliament of Berland | PROGRAMMING | 1,000 | [
"*special",
"constructive algorithms"
] | null | null | There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republicans.
New parliament assembly hall is a rectangle consisting of *a*<=×<=*b* chairs — *a* rows of *b* chair... | The first line of the input contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=10<=000, 1<=≤<=*a*,<=*b*<=≤<=100) — the number of parliamentarians, the number of rows in the assembly hall and the number of seats in each row, respectively. | If there is no way to assigns seats to parliamentarians in a proper way print -1.
Otherwise print the solution in *a* lines, each containing *b* integers. The *j*-th integer of the *i*-th line should be equal to the index of parliamentarian occupying this seat, or 0 if this seat should remain empty. If there are multi... | [
"3 2 2\n",
"8 4 3\n",
"10 2 2\n"
] | [
"0 3\n1 2\n",
"7 8 3\n0 1 4\n6 0 5\n0 2 0\n",
"-1\n"
] | In the first sample there are many other possible solutions. For example,
and
The following assignment
is incorrect, because parliamentarians 1 and 3 are both from Democrats party but will occupy neighbouring seats. | 500 | [
{
"input": "3 2 2",
"output": "1 2 \n0 3 "
},
{
"input": "8 4 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 \n0 0 0 "
},
{
"input": "10 2 2",
"output": "-1"
},
{
"input": "1 1 1",
"output": "1 "
},
{
"input": "8 3 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 "
},
{
"in... | 1,458,247,286 | 128,486 | Python 3 | OK | TESTS | 85 | 93 | 716,800 | n, a, b = map(int, input().split())
if n > a * b:
print(-1)
else:
ch = 2
ne = 1
for y in range(a):
for x in range(b):
if (x + y) % 2:
val = ch if ch <= n else 0
ch += 2
else:
val = ne if ne <= n else 0
... | Title: Parliament of Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republi... | ```python
n, a, b = map(int, input().split())
if n > a * b:
print(-1)
else:
ch = 2
ne = 1
for y in range(a):
for x in range(b):
if (x + y) % 2:
val = ch if ch <= n else 0
ch += 2
else:
val = ne if ne <= n else 0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,520,687,123 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 29 | 1,000 | 5,632,000 | n,k=map(int,input().split())
a=list(map(int,input().split()))
s=sum(a)/n
i=0
while s<(k-0.5):
i+=1
a.append(k)
n+=1
s=sum(a)/n
print(i)
| Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
n,k=map(int,input().split())
a=list(map(int,input().split()))
s=sum(a)/n
i=0
while s<(k-0.5):
i+=1
a.append(k)
n+=1
s=sum(a)/n
print(i)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
520 | B | Two Buttons | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs",
"greedy",
"implementation",
"math",
"shortest paths"
] | null | null | Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by two. After clicking the blue button, device subtracts one from the number on the display. If at so... | The first and the only line of the input contains two distinct integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=104), separated by a space . | Print a single number — the minimum number of times one needs to push the button required to get the number *m* out of number *n*. | [
"4 6\n",
"10 1\n"
] | [
"2\n",
"9\n"
] | In the first example you need to push the blue button once, and then push the red button once.
In the second example, doubling the number is unnecessary, so we need to push the blue button nine times. | 1,000 | [
{
"input": "4 6",
"output": "2"
},
{
"input": "10 1",
"output": "9"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "2 10",
"outpu... | 1,692,334,212 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n,m=map(int,input().split()
count=0
while n!=m:
if n>m:
if n%2==0:
n//=2
else:
n-=1
else:
n*=2
count+=1
print(count) | Title: Two Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by t... | ```python
n,m=map(int,input().split()
count=0
while n!=m:
if n>m:
if n%2==0:
n//=2
else:
n-=1
else:
n*=2
count+=1
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
559 | C | Gerald and Giant Chess | PROGRAMMING | 2,200 | [
"combinatorics",
"dp",
"math",
"number theory"
] | null | null | Giant chess is quite common in Geraldion. We will not delve into the rules of the game, we'll just say that the game takes place on an *h*<=×<=*w* field, and it is painted in two colors, but not like in chess. Almost all cells of the field are white and only some of them are black. Currently Gerald is finishing a game ... | The first line of the input contains three integers: *h*,<=*w*,<=*n* — the sides of the board and the number of black cells (1<=≤<=*h*,<=*w*<=≤<=105,<=1<=≤<=*n*<=≤<=2000).
Next *n* lines contain the description of black cells. The *i*-th of these lines contains numbers *r**i*,<=*c**i* (1<=≤<=*r**i*<=≤<=*h*,<=1<=≤<=*c... | Print a single line — the remainder of the number of ways to move Gerald's pawn from the upper left to the lower right corner modulo 109<=+<=7. | [
"3 4 2\n2 2\n2 3\n",
"100 100 3\n15 16\n16 15\n99 88\n"
] | [
"2\n",
"545732279\n"
] | none | 1,500 | [
{
"input": "3 4 2\n2 2\n2 3",
"output": "2"
},
{
"input": "100 100 3\n15 16\n16 15\n99 88",
"output": "545732279"
},
{
"input": "1000 1000 4\n50 50\n51 50\n50 51\n51 51",
"output": "899660737"
},
{
"input": "100000 100000 4\n50001 50001\n50000 50000\n50000 50001\n50001 50000"... | 1,585,769,250 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | /*
D A R K L _ _ O R D D A
K / | | \ L O R D
A R _ / | | \ _ K L O R
D A R K _ / | _ | \ _... | Title: Gerald and Giant Chess
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giant chess is quite common in Geraldion. We will not delve into the rules of the game, we'll just say that the game takes place on an *h*<=×<=*w* field, and it is painted in two colors, but not like in chess. Al... | ```python
/*
D A R K L _ _ O R D D A
K / | | \ L O R D
A R _ / | | \ _ K L O R
D A R K _ / | _ ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
967 | A | Mind the Gap | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing lasts $1$ minute.
He was asked to insert one takeoff in the schedule. The takeoff takes $1$ minut... | The first line of input contains two integers $n$ and $s$ ($1 \le n \le 100$, $1 \le s \le 60$) — the number of landings on the schedule and the minimum allowed time (in minutes) between a landing and a takeoff.
Each of next $n$ lines contains two integers $h$ and $m$ ($0 \le h \le 23$, $0 \le m \le 59$) — the time, i... | Print two integers $h$ and $m$ — the hour and the minute from the current moment of the earliest time Arkady can insert the takeoff. | [
"6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40\n",
"16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59\n",
"3 17\n0 30\n1 0\n12 0\n"
] | [
"6 1\n",
"24 50\n",
"0 0\n"
] | In the first example note that there is not enough time between 1:20 and 3:21, because each landing and the takeoff take one minute.
In the second example there is no gaps in the schedule, so Arkady can only add takeoff after all landings. Note that it is possible that one should wait more than $24$ hours to insert th... | 500 | [
{
"input": "6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40",
"output": "6 1"
},
{
"input": "16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59",
"output": "24 50"
},
{
"input": "3 17\n0 30\n1 0\n12 0",
"output": "0 0"
},
{
... | 1,699,538,248 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 93 | 0 | n, s = map(int, input().split())
l = []
for i in range(n):
h, m = map(int, input().split())
l.append((h * 60) + m)
if l[0] >= s:
print(0, 0)
else:
for i in range(n - 1):
if l[i + 1] - (l[i] + 1) >= (2 * s) + 1:
print((l[i] + 1 + s) // 60, (l[i] + 1 + s) % 60)
break
if i == n... | Title: Mind the Gap
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing ... | ```python
n, s = map(int, input().split())
l = []
for i in range(n):
h, m = map(int, input().split())
l.append((h * 60) + m)
if l[0] >= s:
print(0, 0)
else:
for i in range(n - 1):
if l[i + 1] - (l[i] + 1) >= (2 * s) + 1:
print((l[i] + 1 + s) // 60, (l[i] + 1 + s) % 60)
break
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
32 | A | Reconnaissance | PROGRAMMING | 800 | [
"brute force"
] | A. Reconnaissance | 2 | 256 | According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob has *n* soldiers in his detachment. Their heights are *a*1,<=*a*2,<=...,<=*a**n* centimeters. Som... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*d*<=≤<=109) — amount of soldiers in Bob's detachment and the maximum allowed height difference respectively. The second line contains *n* space-separated integers — heights of all the soldiers in Bob's detachment. These numbers don't exceed 1... | Output one number — amount of ways to form a reconnaissance unit of two soldiers, whose height difference doesn't exceed *d*. | [
"5 10\n10 20 50 60 65\n",
"5 1\n55 30 29 31 55\n"
] | [
"6\n",
"6\n"
] | none | 500 | [
{
"input": "5 10\n10 20 50 60 65",
"output": "6"
},
{
"input": "5 1\n55 30 29 31 55",
"output": "6"
},
{
"input": "6 10\n4 6 4 1 9 3",
"output": "30"
},
{
"input": "7 100\n19 1694 261 162 1 234 513",
"output": "8"
},
{
"input": "8 42\n37 53 74 187 568 22 5 65",
... | 1,630,172,998 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 498 | 6,963,200 | n, d=[int(i) for i in input().split()]
a=[int(i)for i in input().split()]
count=0
if (n>=1 and n<=1000) and (d>=1 and (d<=10**9)):
for i in range(len(a)):
for j in range(i+1,len(a)):
if abs(a[j]-a[i])<=d:
count+=1
print(count*2) | Title: Reconnaissance
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob h... | ```python
n, d=[int(i) for i in input().split()]
a=[int(i)for i in input().split()]
count=0
if (n>=1 and n<=1000) and (d>=1 and (d<=10**9)):
for i in range(len(a)):
for j in range(i+1,len(a)):
if abs(a[j]-a[i])<=d:
count+=1
print(count*2)
``` | 3.86253 | MatrixStudio/Codeforces-Python-Submissions |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,597,339,849 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 810 | 6,144,000 | n=int(input())
r=0
m=2**20
for _ in range(n):
a,p=map(int,input().split())
m=min(m,p)
r+=a*m
print (r)
| Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
n=int(input())
r=0
m=2**20
for _ in range(n):
a,p=map(int,input().split())
m=min(m,p)
r+=a*m
print (r)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is... | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so ... | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,690,788,001 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 122 | 0 | n = int(input())
cash = 1
sum1 = 0
h1,m1 = map(int , input().split())
sum1 = h1 + m1
if n > 1 :
for i in range(1,n):
h,m = map(int , input().split())
if sum1 == h + m :
cash = cash + 1
sum1 = h + m
else :
cash = 1
print(cash)
| Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends l... | ```python
n = int(input())
cash = 1
sum1 = 0
h1,m1 = map(int , input().split())
sum1 = h1 + m1
if n > 1 :
for i in range(1,n):
h,m = map(int , input().split())
if sum1 == h + m :
cash = cash + 1
sum1 = h + m
else :
cash = 1
print(cash)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
708 | A | Letters Cyclic Shift | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation",
"strings"
] | null | null | You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each character is replaced with the previous character of English alphabet and 'a' is replaced with 'z'.
What is ... | The only line of the input contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) consisting of lowercase English letters. | Print the lexicographically minimum string that can be obtained from *s* by shifting letters of exactly one non-empty substring. | [
"codeforces\n",
"abacaba\n"
] | [
"bncdenqbdr\n",
"aaacaba\n"
] | String *s* is lexicographically smaller than some other string *t* of the same length if there exists some 1 ≤ *i* ≤ |*s*|, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, *s*<sub class="lower-index">2</sub> = *t*<sub class="lower-index">2</sub>, ..., *s*<sub class="lower-index">*i*... | 500 | [
{
"input": "codeforces",
"output": "bncdenqbdr"
},
{
"input": "abacaba",
"output": "aaacaba"
},
{
"input": "babbbabaababbaa",
"output": "aabbbabaababbaa"
},
{
"input": "bcbacaabcababaccccaaaabacbbcbbaa",
"output": "abaacaabcababaccccaaaabacbbcbbaa"
},
{
"input": "... | 1,491,390,176 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 4,608,000 | '''input
codeforces
'''
def lexi_sum(s):
a = "abcdefghijklmnopqrstuvwxyz"
t = 0
for l in s:
t += a.index(l) + 1
return t
def shift(s):
a = "abcdefghijklmnopqrstuvwxyz"
s1 = ""
for l in s:
s1 += a[a.index(l)-1]
return s1
s = input()
s = s.split("a")
m = max(s, key=len)
m1 = s.index(m)
s[m1] = shift(m)
print(... | Title: Letters Cyclic Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each cha... | ```python
'''input
codeforces
'''
def lexi_sum(s):
a = "abcdefghijklmnopqrstuvwxyz"
t = 0
for l in s:
t += a.index(l) + 1
return t
def shift(s):
a = "abcdefghijklmnopqrstuvwxyz"
s1 = ""
for l in s:
s1 += a[a.index(l)-1]
return s1
s = input()
s = s.split("a")
m = max(s, key=len)
m1 = s.index(m)
s[m1] = shift... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,609,354,719 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 216 | 0 | import math
a,b,n=map(int,input().split())
rem=n
flag=0
while(rem>=0):
if flag==0:
g=math.gcd(a,rem)
rem=rem-g
flag=1
print(rem)
elif flag==1:
g=math.gcd(b,rem)
rem=rem-g
flag=0
print(rem)
print(flag)
| Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
import math
a,b,n=map(int,input().split())
rem=n
flag=0
while(rem>=0):
if flag==0:
g=math.gcd(a,rem)
rem=rem-g
flag=1
print(rem)
elif flag==1:
g=math.gcd(b,rem)
rem=rem-g
flag=0
print(rem)
print(flag)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,682,075,647 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 122 | 0 | import math
a,b,n = map(int,input().split())
k = 0
while n>=0:
k +=1
if k%2 == 1:
n -= math.gcd(a,n)
else:
n -= math.gcd(b,n)
if k % 2 != 0:
print("1")
else:
print('0')
| Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
import math
a,b,n = map(int,input().split())
k = 0
while n>=0:
k +=1
if k%2 == 1:
n -= math.gcd(a,n)
else:
n -= math.gcd(b,n)
if k % 2 != 0:
print("1")
else:
print('0')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
600 | B | Queries about less or equal elements | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"sortings",
"two pointers"
] | null | null | You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the sizes of arrays *a* and *b*.
The second line contains *n* integers — the elements of array *a* (<=-<=109<=≤<=*a**i*<=≤<=109).
The third line contains *m* integers — the elements of array *b* (<=-<=109<=≤<=*b**j*<=≤<=109). | Print *m* integers, separated by spaces: the *j*-th of which is equal to the number of such elements in array *a* that are less than or equal to the value *b**j*. | [
"5 4\n1 3 5 7 9\n6 4 2 8\n",
"5 5\n1 2 1 2 5\n3 1 4 1 5\n"
] | [
"3 2 1 4\n",
"4 2 4 2 5\n"
] | none | 0 | [
{
"input": "5 4\n1 3 5 7 9\n6 4 2 8",
"output": "3 2 1 4"
},
{
"input": "5 5\n1 2 1 2 5\n3 1 4 1 5",
"output": "4 2 4 2 5"
},
{
"input": "1 1\n-1\n-2",
"output": "0"
},
{
"input": "1 1\n-80890826\n686519510",
"output": "1"
},
{
"input": "11 11\n237468511 -77918754... | 1,680,514,050 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | a,b = map(int,input().split())
arr1 = list(map(int,input().split()))
arr2 = list(map(int,input().split()))
def binary_search(arr, x):
low = 0
high = len(arr) - 1
mid = 0
if x < arr[0]:
return 0
if x > arr[high]:
return high + 1
while low <= high:
mid = ... | Title: Queries about less or equal elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*.
In... | ```python
a,b = map(int,input().split())
arr1 = list(map(int,input().split()))
arr2 = list(map(int,input().split()))
def binary_search(arr, x):
low = 0
high = len(arr) - 1
mid = 0
if x < arr[0]:
return 0
if x > arr[high]:
return high + 1
while low <= high:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,465,958,207 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 154 | 5,120,000 | import re
helloWord = re.compile(r'.h+.e+.l+.l+.o+.')
text = input()
if helloWord.search(text) == None:
print("NO")
else:
print("YES") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
import re
helloWord = re.compile(r'.h+.e+.l+.l+.o+.')
text = input()
if helloWord.search(text) == None:
print("NO")
else:
print("YES")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
915 | A | Garden | PROGRAMMING | 900 | [
"implementation"
] | null | null | Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't wat... | The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one ... | Print one integer number — the minimum number of hours required to water the garden. | [
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] | [
"2\n",
"7\n"
] | In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | 0 | [
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 5... | 1,534,759,119 | 2,147,483,647 | Python 3 | OK | TESTS | 83 | 124 | 0 | #!/user/bin/python
firstLine = input()
secondLine = input()
if __name__ == '__main__':
_firstLine = firstLine.split(' ')
_secondLine = secondLine.split(' ')
minHours = 10e10
gardenLenght = int(_firstLine[1])
for bucket in _secondLine:
if gardenLenght%(int(bucket)) == 0:
hours = garde... | Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each ... | ```python
#!/user/bin/python
firstLine = input()
secondLine = input()
if __name__ == '__main__':
_firstLine = firstLine.split(' ')
_secondLine = secondLine.split(' ')
minHours = 10e10
gardenLenght = int(_firstLine[1])
for bucket in _secondLine:
if gardenLenght%(int(bucket)) == 0:
hou... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,665,080,291 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 5,529,600 | t = input()
arr = input().split()
q = input()
q_arr = input().split()
c1 = 0
c2 = 0
for j in range(int(q)):
for i in arr:
c1+=1
if i== q_arr[j]:
break
for j in range(int(q)):
for i in range(len(arr)-1,-1,-1):
c2+=1
if arr[i]== q_arr[j]:
brea... | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
t = input()
arr = input().split()
q = input()
q_arr = input().split()
c1 = 0
c2 = 0
for j in range(int(q)):
for i in arr:
c1+=1
if i== q_arr[j]:
break
for j in range(int(q)):
for i in range(len(arr)-1,-1,-1):
c2+=1
if arr[i]== q_arr[j]:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
366 | B | Dima and To-do List | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything he does in her presence. After Inna tells him off for something, she goes to another room, walks there in ... | The first line of the input contains two integers *n*,<=*k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103), where *a**i* is the power Inna tells Dima off with if she is present in the room while he is doing the *i*-th task.
It is guaranteed that *n*... | In a single line print the number of the task Dima should start with to get told off with as little power as possible. If there are multiple solutions, print the one with the minimum number of the first task to do. | [
"6 2\n3 2 1 6 5 4\n",
"10 5\n1 3 5 7 9 9 4 1 8 5\n"
] | [
"1\n",
"3\n"
] | Explanation of the first example.
If Dima starts from the first task, Inna tells him off with power 3, then Dima can do one more task (as *k* = 2), then Inna tells him off for the third task with power 1, then she tells him off for the fifth task with power 5. Thus, Dima gets told off with total power 3 + 1 + 5 = 9. I... | 1,000 | [
{
"input": "6 2\n3 2 1 6 5 4",
"output": "1"
},
{
"input": "10 5\n1 3 5 7 9 9 4 1 8 5",
"output": "3"
},
{
"input": "20 4\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "1"
},
{
"input": "10 10\n8 4 5 7 6 9 2 2 3 5",
"output": "7"
},
{
"input": "50 10\n1 2 3... | 1,559,468,030 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 15 | 1,000 | 6,041,600 | n,k=map(int,input().split())
p=list(map(int,input().split()))
ans=1e9
ans_idx=0
for s in range(k):
x=0
vis=[0]*n
for i in range(s,n,k):
x+=p[i]
if x<ans:
ans=x
ans_idx=s
print(ans_idx+1)
| Title: Dima and To-do List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You helped Dima to have a great weekend, but it's time to work. Naturally, Dima, as all other men who have girlfriends, does everything wrong.
Inna and Dima are now in one room. Inna tells Dima off for everything h... | ```python
n,k=map(int,input().split())
p=list(map(int,input().split()))
ans=1e9
ans_idx=0
for s in range(k):
x=0
vis=[0]*n
for i in range(s,n,k):
x+=p[i]
if x<ans:
ans=x
ans_idx=s
print(ans_idx+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
932 | B | Recursive Queries | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"dfs and similar"
] | null | null | Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x* between *l* and *r* inclusive, such that *g*(*x*)<==<=*k*. | The first line of the input contains an integer *Q* (1<=≤<=*Q*<=≤<=2<=×<=105) representing the number of queries.
*Q* lines follow, each of which contains 3 integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=106,<=1<=≤<=*k*<=≤<=9). | For each query, print a single line containing the answer for that query. | [
"4\n22 73 9\n45 64 6\n47 55 7\n2 62 4\n",
"4\n82 94 6\n56 67 4\n28 59 9\n39 74 4\n"
] | [
"1\n4\n0\n8\n",
"3\n1\n1\n5\n"
] | In the first example:
- *g*(33) = 9 as *g*(33) = *g*(3 × 3) = *g*(9) = 9 - *g*(47) = *g*(48) = *g*(60) = *g*(61) = 6 - There are no such integers between 47 and 55. - *g*(4) = *g*(14) = *g*(22) = *g*(27) = *g*(39) = *g*(40) = *g*(41) = *g*(58) = 4 | 1,000 | [
{
"input": "4\n22 73 9\n45 64 6\n47 55 7\n2 62 4",
"output": "1\n4\n0\n8"
},
{
"input": "4\n82 94 6\n56 67 4\n28 59 9\n39 74 4",
"output": "3\n1\n1\n5"
}
] | 1,519,073,012 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 7,065,600 | from functools import reduce, lru_cache
max = int(10e6 + 5)
def gen(l, r, k):
for i in range(l, r+1):
yield 1 if g(i) == k else 0
def main():
q = int(input())
for _ in range(q):
l, r, k = (int(x) for x in input().split())
s = sum(gen(l, r, k))
print(s)
... | Title: Recursive Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x*... | ```python
from functools import reduce, lru_cache
max = int(10e6 + 5)
def gen(l, r, k):
for i in range(l, r+1):
yield 1 if g(i) == k else 0
def main():
q = int(input())
for _ in range(q):
l, r, k = (int(x) for x in input().split())
s = sum(gen(l, r, k))
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
835 | A | Key races | PROGRAMMING | 800 | [
"math"
] | null | null | Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *... | The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and th... | If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship". | [
"5 1 2 1 2\n",
"3 3 1 1 1\n",
"4 5 3 1 5\n"
] | [
"First\n",
"Second\n",
"Friendship\n"
] | In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, ... | 500 | [
{
"input": "5 1 2 1 2",
"output": "First"
},
{
"input": "3 3 1 1 1",
"output": "Second"
},
{
"input": "4 5 3 1 5",
"output": "Friendship"
},
{
"input": "1000 1000 1000 1000 1000",
"output": "Friendship"
},
{
"input": "1 1 1 1 1",
"output": "Friendship"
},
... | 1,681,390,089 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | bbc=input().split()#кол во символов , скорость первым , скорость текста участником, пинг первого и второго
bbc=list(map(int,bbc))
bbc[2]=1/bbc[2]
bbc[1]=1/bbc[1]
c=bbc[0]/bbc[1]
z=bbc[0]/bbc[2]
if c+bbc[3]>z+bbc[4]:
print('second')
elif c+bbc[3]<z+bbc[4]:
print('first')
else:
print('Draw') | Title: Key races
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t... | ```python
bbc=input().split()#кол во символов , скорость первым , скорость текста участником, пинг первого и второго
bbc=list(map(int,bbc))
bbc[2]=1/bbc[2]
bbc[1]=1/bbc[1]
c=bbc[0]/bbc[1]
z=bbc[0]/bbc[2]
if c+bbc[3]>z+bbc[4]:
print('second')
elif c+bbc[3]<z+bbc[4]:
print('first')
else:
print('D... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,697,121,513 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | from math import sqrt
import random
def is_square(n):
# 检查一个数是否为完全平方数
root = int(sqrt(n))
return root * root == n
def is_prime_miller_rabin(n, k=5):
if n <= 3:
return n == 2 or n == 3
# 将 n - 1 表示为 2^r * d 的形式
r, d = 0, n - 1
while d % 2 == 0:
r += 1
... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
from math import sqrt
import random
def is_square(n):
# 检查一个数是否为完全平方数
root = int(sqrt(n))
return root * root == n
def is_prime_miller_rabin(n, k=5):
if n <= 3:
return n == 2 or n == 3
# 将 n - 1 表示为 2^r * d 的形式
r, d = 0, n - 1
while d % 2 == 0:
r +=... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
622 | C | Not Equal on a Segment | PROGRAMMING | 1,700 | [
"data structures",
"implementation"
] | null | null | You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so that *a**p**i*<=≠<=*x**i*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the number of elements in *a* and the number of queries.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106) — the elements of the array *a*.
Each of the next *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=... | Print *m* lines. On the *i*-th line print integer *p**i* — the position of any number not equal to *x**i* in segment [*l**i*,<=*r**i*] or the value <=-<=1 if there is no such number. | [
"6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2\n"
] | [
"2\n6\n-1\n4\n"
] | none | 0 | [
{
"input": "6 4\n1 2 1 1 3 5\n1 4 1\n2 6 2\n3 4 1\n3 4 2",
"output": "2\n6\n-1\n4"
},
{
"input": "1 1\n1\n1 1 1",
"output": "-1"
},
{
"input": "1 1\n2\n1 1 2",
"output": "-1"
},
{
"input": "1 1\n569888\n1 1 967368",
"output": "1"
},
{
"input": "10 10\n1 1 1 1 1 1 ... | 1,463,549,824 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 19 | 1,000 | 12,697,600 | trans = [int(i) for i in input().split()]
n = trans[0]
m = trans[1]
none = -1
ss = [int(i) for i in input().split()]
sscopy = [0] * n
result = []
for i in range(1, n):
if ss[i] != ss[i-1]:
sscopy[i] = i
else:
sscopy[i] = sscopy[i-1]
for i in range(m):
trans = [int(i) for i in input().split()]
l ... | Title: Not Equal on a Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array *a* with *n* integers and *m* queries. The *i*-th query is given with three integers *l**i*,<=*r**i*,<=*x**i*.
For the *i*-th query find any position *p**i* (*l**i*<=≤<=*p**i*<=≤<=*r**i*) so ... | ```python
trans = [int(i) for i in input().split()]
n = trans[0]
m = trans[1]
none = -1
ss = [int(i) for i in input().split()]
sscopy = [0] * n
result = []
for i in range(1, n):
if ss[i] != ss[i-1]:
sscopy[i] = i
else:
sscopy[i] = sscopy[i-1]
for i in range(m):
trans = [int(i) for i in input().spl... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,678,550,062 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 154 | 102,400 | s = input()
ans = ''
ok = 0
for el in s:
if el == '0' and not ok:
ok = 1
else:
ans += el
if not ok:
print(ans[1:])
else:
print(ans)
| Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
s = input()
ans = ''
ok = 0
for el in s:
if el == '0' and not ok:
ok = 1
else:
ans += el
if not ok:
print(ans[1:])
else:
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,588,153,209 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 140 | 0 | s=input()
ans=0
n=len(s)
for i in range(n-3):
if s[i]=="b":
if s[i+1]=="e" and s[i+2]=="a" and s[i+3]=="r":
ans+=max(i,1)*(n-i-3)
print(ans)
| Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
s=input()
ans=0
n=len(s)
for i in range(n-3):
if s[i]=="b":
if s[i+1]=="e" and s[i+2]=="a" and s[i+3]=="r":
ans+=max(i,1)*(n-i-3)
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,686,916,840 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | word = input() #HoUse
length = len(word)
uppercase = 0
lowercase = 0
for i in range(length):
if word[i-1].islower():
lowercase += 1
else:
uppercase += 1
if uppercase > lowercase:
new_uppercase = word.upper()
print(new_uppercase) #string이라서 ().upper이라고 하는 건가요 ?-?
else:
... | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
word = input() #HoUse
length = len(word)
uppercase = 0
lowercase = 0
for i in range(length):
if word[i-1].islower():
lowercase += 1
else:
uppercase += 1
if uppercase > lowercase:
new_uppercase = word.upper()
print(new_uppercase) #string이라서 ().upper이라고 하는 건가요 ?-?
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
143 | A | Help Vasilisa the Wise 2 | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know what the box's secret is, since she cannot open it again. She hopes that you will help her one more time with tha... | The input contains numbers written on the edges of the lock of the box. The first line contains space-separated integers *r*1 and *r*2 that define the required sums of numbers in the rows of the square. The second line contains space-separated integers *c*1 and *c*2 that define the required sums of numbers in the colum... | Print the scheme of decorating the box with stones: two lines containing two space-separated integers from 1 to 9. The numbers should be pairwise different. If there is no solution for the given lock, then print the single number "-1" (without the quotes).
If there are several solutions, output any. | [
"3 7\n4 6\n5 5\n",
"11 10\n13 8\n5 16\n",
"1 2\n3 4\n5 6\n",
"10 10\n10 10\n10 10\n"
] | [
"1 2\n3 4\n",
"4 7\n9 1\n",
"-1\n",
"-1\n"
] | Pay attention to the last test from the statement: it is impossible to open the box because for that Vasilisa the Wise would need 4 identical gems containing number "5". However, Vasilisa only has one gem with each number from 1 to 9. | 500 | [
{
"input": "3 7\n4 6\n5 5",
"output": "1 2\n3 4"
},
{
"input": "11 10\n13 8\n5 16",
"output": "4 7\n9 1"
},
{
"input": "1 2\n3 4\n5 6",
"output": "-1"
},
{
"input": "10 10\n10 10\n10 10",
"output": "-1"
},
{
"input": "5 13\n8 10\n11 7",
"output": "3 2\n5 8"
... | 1,602,424,579 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 218 | 307,200 | r1, r2 = map(int, input().split())
c1, c2 = map(int, input().split())
d1, d2 = map(int, input().split())
c = False
for a11 in range(1, min(10, r1)):
a12 = r1-a11
if a12!=a11:
for a21 in range(1, min(10, r2)):
a22 = r2-a21
if a21!=a11 and a11+a21==c1 and a12+a22==c2 and a11+a22==... | Title: Help Vasilisa the Wise 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know wha... | ```python
r1, r2 = map(int, input().split())
c1, c2 = map(int, input().split())
d1, d2 = map(int, input().split())
c = False
for a11 in range(1, min(10, r1)):
a12 = r1-a11
if a12!=a11:
for a21 in range(1, min(10, r2)):
a22 = r2-a21
if a21!=a11 and a11+a21==c1 and a12+a22==c2 and... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
400 | B | Inna and New Matrix of Candies | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"schedules"
] | null | null | Inna likes sweets and a game called the "Candy Matrix". Today, she came up with the new game "Candy Matrix 2: Reload".
The field for the new game is a rectangle table of size *n*<=×<=*m*. Each line of the table contains one cell with a dwarf figurine, one cell with a candy, the other cells of the line are empty. The g... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=1000; 2<=≤<=*m*<=≤<=1000).
Next *n* lines each contain *m* characters — the game field for the "Candy Martix 2: Reload". Character "*" represents an empty cell of the field, character "G" represents a dwarf and character "S" represents a can... | In a single line print a single integer — either the minimum number of moves needed to achieve the aim of the game, or -1, if the aim cannot be achieved on the given game field. | [
"3 4\n*G*S\nG**S\n*G*S\n",
"1 3\nS*G\n"
] | [
"2\n",
"-1\n"
] | none | 1,000 | [
{
"input": "3 4\n*G*S\nG**S\n*G*S",
"output": "2"
},
{
"input": "1 3\nS*G",
"output": "-1"
},
{
"input": "10 10\nG********S\n*G*******S\n**G******S\n***G*****S\n****G****S\n*****G***S\n******G**S\n*******G*S\n********GS\nG********S",
"output": "9"
},
{
"input": "5 10\nG***S**... | 1,654,348,211 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n, m = map(int, input().split(" "))
flag = False
array = []
for _ in range(n):
temp = list(input())
if temp.index("S") < temp.index("G"):
flag = True
break
else:
array.append(temp.index("S") - temp.index("G"))
if flag: print(-1)
else: print(max(array)-1)
| Title: Inna and New Matrix of Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Inna likes sweets and a game called the "Candy Matrix". Today, she came up with the new game "Candy Matrix 2: Reload".
The field for the new game is a rectangle table of size *n*<=×<=*m*. Each line of th... | ```python
n, m = map(int, input().split(" "))
flag = False
array = []
for _ in range(n):
temp = list(input())
if temp.index("S") < temp.index("G"):
flag = True
break
else:
array.append(temp.index("S") - temp.index("G"))
if flag: print(-1)
else: print(max(array)-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
637 | B | Chat Order | PROGRAMMING | 1,200 | [
"*special",
"binary search",
"constructive algorithms",
"data structures",
"sortings"
] | null | null | Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The relative order of the other chats doesn't change. If there was no chat with this friend before, then... | The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Polycarpus' messages. Next *n* lines enlist the message recipients in the order in which the messages were sent. The name of each participant is a non-empty sequence of lowercase English letters of length at most 10. | Print all the recipients to who Polycarp talked to in the order of chats with them, from top to bottom. | [
"4\nalex\nivan\nroman\nivan\n",
"8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina\n"
] | [
"ivan\nroman\nalex\n",
"alina\nmaria\nekaterina\ndarya\n"
] | In the first test case Polycarpus first writes to friend by name "alex", and the list looks as follows:
1. alex
Then Polycarpus writes to friend by name "ivan" and the list looks as follows:
1. ivan 1. alex
Polycarpus writes the third message to friend by name "roman" and the list looks as follows:
1. roman 1... | 1,000 | [
{
"input": "4\nalex\nivan\nroman\nivan",
"output": "ivan\nroman\nalex"
},
{
"input": "8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina",
"output": "alina\nmaria\nekaterina\ndarya"
},
{
"input": "1\nwdi",
"output": "wdi"
},
{
"input": "2\nypg\nypg",
"outpu... | 1,457,933,652 | 63,252 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 11 | 3,000 | 1,024,000 | def main():
n = int(input())
arr = ["."] * n
using = [False] * n
for i in range(n):
s = input()
arr[i] = s
using[i] = True
for j in range(i):
if arr[j] == s:
using[j] = False
for i in range(n-1, -1, -1):
if using[i]:
... | Title: Chat Order
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The rela... | ```python
def main():
n = int(input())
arr = ["."] * n
using = [False] * n
for i in range(n):
s = input()
arr[i] = s
using[i] = True
for j in range(i):
if arr[j] == s:
using[j] = False
for i in range(n-1, -1, -1):
if usi... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
787 | A | The Monster | PROGRAMMING | 1,200 | [
"brute force",
"math",
"number theory"
] | null | null | A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams at times *d*,<=*d*<=+<=*c*,<=*d*<=+<=2*c*,<=*d*<=+<=3*c*,<=....
The Monster will catch them if a... | The first line of input contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100).
The second line contains two integers *c* and *d* (1<=≤<=*c*,<=*d*<=≤<=100). | Print the first time Rick and Morty will scream at the same time, or <=-<=1 if they will never scream at the same time. | [
"20 2\n9 19\n",
"2 1\n16 12\n"
] | [
"82\n",
"-1\n"
] | In the first sample testcase, Rick's 5th scream and Morty's 8th time are at time 82.
In the second sample testcase, all Rick's screams will be at odd times and Morty's will be at even times, so they will never scream at the same time. | 500 | [
{
"input": "20 2\n9 19",
"output": "82"
},
{
"input": "2 1\n16 12",
"output": "-1"
},
{
"input": "39 52\n88 78",
"output": "1222"
},
{
"input": "59 96\n34 48",
"output": "1748"
},
{
"input": "87 37\n91 29",
"output": "211"
},
{
"input": "11 81\n49 7",
... | 1,655,199,036 | 2,147,483,647 | PyPy 3 | OK | TESTS | 58 | 92 | 1,228,800 | import sys
input = sys.stdin.readline
a, b = map(int, input().split())
c, d = map(int, input().split())
while b!= d:
if b < d:
b += a
else:
d += c
if b > 20000:
break
if b > 20000:
print(-1)
else:
print(b) | Title: The Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams a... | ```python
import sys
input = sys.stdin.readline
a, b = map(int, input().split())
c, d = map(int, input().split())
while b!= d:
if b < d:
b += a
else:
d += c
if b > 20000:
break
if b > 20000:
print(-1)
else:
print(b)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
83 | A | Magical Array | PROGRAMMING | 1,300 | [
"math"
] | A. Magical Array | 2 | 256 | Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutel... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains an array of original integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator). | [
"4\n2 1 1 4\n",
"5\n-2 -2 -2 0 1\n"
] | [
"5\n",
"8\n"
] | Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3]. | 500 | [
{
"input": "4\n2 1 1 4",
"output": "5"
},
{
"input": "5\n-2 -2 -2 0 1",
"output": "8"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n5 6",
"output": "2"
},
{
"input": "5\n5 5 4 5 5",
"output": "7"
},
{
"input": "8\n1 2 0 0 0 0 3 3",
"output... | 1,522,619,229 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 902 | 42,496,000 | from sys import *
from bisect import *
from collections import *
from itertools import *
from fractions import *
from datetime import *
from math import *
Input = []
#stdin = open('in', 'r')
#stdout = open('out', 'w')
## for i, val in enumerate(array, start_i_value)
def Out(x):
stdout.write(str(... | Title: Magical Array
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a re... | ```python
from sys import *
from bisect import *
from collections import *
from itertools import *
from fractions import *
from datetime import *
from math import *
Input = []
#stdin = open('in', 'r')
#stdout = open('out', 'w')
## for i, val in enumerate(array, start_i_value)
def Out(x):
stdout.... | 3.695345 | MatrixStudio/Codeforces-Python-Submissions |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,693,653,219 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 92 | 0 | n = int(input())
a = [int(i) for i in input().split()]
x , y = input().split()
x = int(x)
y = int(y)
x -= 1
y -= 1
ans = 0
for i in range(x , y):
ans += a[i]
print (ans)
| Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
n = int(input())
a = [int(i) for i in input().split()]
x , y = input().split()
x = int(x)
y = int(y)
x -= 1
y -= 1
ans = 0
for i in range(x , y):
ans += a[i]
print (ans)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
745 | A | Hongcow Learns the Cyclic Shift | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Hongcow is learning to spell! One day, his teacher gives him a word that he needs to learn to spell. Being a dutiful student, he immediately learns how to spell the word.
Hongcow has decided to try to make new words from this one. He starts by taking the word he just learned how to spell, and moves the last character ... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=50), the word Hongcow initially learns how to spell. The string *s* consists only of lowercase English letters ('a'–'z'). | Output a single integer equal to the number of distinct strings that Hongcow can obtain by applying the cyclic shift arbitrarily many times to the given string. | [
"abcd\n",
"bbb\n",
"yzyz\n"
] | [
"4\n",
"1\n",
"2\n"
] | For the first sample, the strings Hongcow can generate are "abcd", "dabc", "cdab", and "bcda".
For the second sample, no matter how many times Hongcow does the cyclic shift, Hongcow can only generate "bbb".
For the third sample, the two strings Hongcow can generate are "yzyz" and "zyzy". | 500 | [
{
"input": "abcd",
"output": "4"
},
{
"input": "bbb",
"output": "1"
},
{
"input": "yzyz",
"output": "2"
},
{
"input": "abcdefghijklmnopqrstuvwxyabcdefghijklmnopqrstuvwxy",
"output": "25"
},
{
"input": "zclkjadoprqronzclkjadoprqronzclkjadoprqron",
"output": "14... | 1,481,992,866 | 366 | Python 3 | OK | TESTS | 28 | 62 | 4,608,000 | s = input()
s1 = s
def transform(s):
return s[-1] + s[:len(s) - 1]
s = transform(s)
count = 1
while s != s1:
s = transform(s)
count += 1
print(count) | Title: Hongcow Learns the Cyclic Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hongcow is learning to spell! One day, his teacher gives him a word that he needs to learn to spell. Being a dutiful student, he immediately learns how to spell the word.
Hongcow has decided to try to m... | ```python
s = input()
s1 = s
def transform(s):
return s[-1] + s[:len(s) - 1]
s = transform(s)
count = 1
while s != s1:
s = transform(s)
count += 1
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions |
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