contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
0 | none | none | none | 0 | [
"none"
] | null | null | Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a**i* — add non-negative integer *a**i* to the multiset. Note, that she has a multiset, thus there may b... | The first line of the input contains an integer *t* (1<=≤<=*t*<=≤<=100<=000) — the number of operation Sonya has to perform.
Next *t* lines provide the descriptions of the queries in order they appear in the input file. The *i*-th row starts with a character *c**i* — the type of the corresponding operation. If *c**i* ... | For each query of the third type print the number of integers matching the given pattern. Each integer is counted as many times, as it appears in the multiset at this moment of time. | [
"12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0\n",
"4\n+ 200\n+ 200\n- 200\n? 0\n"
] | [
"2\n1\n2\n1\n1\n",
"1\n"
] | Consider the integers matching the patterns from the queries of the third type. Queries are numbered in the order they appear in the input.
1. 1 and 241. 1. 361. 1. 101 and 361. 1. 361. 1. 4000. | 0 | [
{
"input": "12\n+ 1\n+ 241\n? 1\n+ 361\n- 241\n? 0101\n+ 101\n? 101\n- 101\n? 101\n+ 4000\n? 0",
"output": "2\n1\n2\n1\n1"
},
{
"input": "4\n+ 200\n+ 200\n- 200\n? 0",
"output": "1"
},
{
"input": "20\n+ 61\n+ 99\n+ 51\n+ 70\n+ 7\n+ 34\n+ 71\n+ 86\n+ 68\n+ 39\n+ 78\n+ 81\n+ 89\n? 10\n? 00... | 1,475,239,206 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 545 | 9,728,000 | from sys import stdin, stdout
from collections import defaultdict
input()
d = defaultdict(int)
regex = str.maketrans("0123456789","0101010101")
for line in stdin.readlines():
typ, val = line.split()
if typ == "?":
print(d[int(val,2)])
else:
val = int(val.translate(regex), 2)
if typ =... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Sonya learned about long integers and invited all her friends to share the fun. Sonya has an initially empty multiset with integers. Friends give her *t* queries, each of one of the following type:
1. <=+<= *a**i* — add no... | ```python
from sys import stdin, stdout
from collections import defaultdict
input()
d = defaultdict(int)
regex = str.maketrans("0123456789","0101010101")
for line in stdin.readlines():
typ, val = line.split()
if typ == "?":
print(d[int(val,2)])
else:
val = int(val.translate(regex), 2)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
299 | A | Ksusha and Array | PROGRAMMING | 1,000 | [
"brute force",
"number theory",
"sortings"
] | null | null | Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that all array elements are divisible by it. Help her and find the number! | The first line contains integer *n* (1<=≤<=*n*<=≤<=105), showing how many numbers the array has. The next line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the array elements. | Print a single integer — the number from the array, such that all array elements are divisible by it. If such number doesn't exist, print -1.
If there are multiple answers, you are allowed to print any of them. | [
"3\n2 2 4\n",
"5\n2 1 3 1 6\n",
"3\n2 3 5\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 500 | [
{
"input": "3\n2 2 4",
"output": "2"
},
{
"input": "5\n2 1 3 1 6",
"output": "1"
},
{
"input": "3\n2 3 5",
"output": "-1"
},
{
"input": "1\n331358794",
"output": "331358794"
},
{
"input": "5\n506904227 214303304 136194869 838256937 183952885",
"output": "-1"
... | 1,571,356,386 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 312 | 8,192,000 | n=int(input())
L=list(map(int,input().split()))
a=min(L)
for i in range(len(L)):
if L[i]%a :
i-=1
break
if i < len(L)-1:
print(-1)
else:
print(a) | Title: Ksusha and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that ... | ```python
n=int(input())
L=list(map(int,input().split()))
a=min(L)
for i in range(len(L)):
if L[i]%a :
i-=1
break
if i < len(L)-1:
print(-1)
else:
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the numb... | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,674,283,089 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | # from [smt] import [smt]
# import sys
# sys.setrecursionlimit(2000)
# from collections import defaultdict
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s)]))
def invr():
return(map(int,input().split()))
... | Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the... | ```python
# from [smt] import [smt]
# import sys
# sys.setrecursionlimit(2000)
# from collections import defaultdict
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s)]))
def invr():
return(map(int,input().s... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,634,549,646 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | question = input()
size = len(question)
if question[ size -2] == "A" or "E" or "I" or "O" or "U" or "Y":
print("YES")
else:
print("NO") | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
question = input()
size = len(question)
if question[ size -2] == "A" or "E" or "I" or "O" or "U" or "Y":
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,686,577,282 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | n=int(input())
a=0
b=0
max=0
sit=0
for i in range(n):
a,b=map(int,input().split())
sit=sit-a
sit=sit+b
if(max<sit):
max=sit
print(max) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
n=int(input())
a=0
b=0
max=0
sit=0
for i in range(n):
a,b=map(int,input().split())
sit=sit-a
sit=sit+b
if(max<sit):
max=sit
print(max)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are st... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=1018) — the number of players to participate in the tournament. | Print the maximum number of games in which the winner of the tournament can take part. | [
"2\n",
"3\n",
"4\n",
"10\n"
] | [
"1\n",
"2\n",
"2\n",
"4\n"
] | In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't p... | 0 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "1000",
"output": "14"
},
{
"input": "2500",
"output": "15"
},
{
"input": "690000",
"output"... | 1,672,389,322 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | import math
print(int(math.log(pow(int(input()),2))))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very first game. That me... | ```python
import math
print(int(math.log(pow(int(input()),2))))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
334 | B | Eight Point Sets | PROGRAMMING | 1,400 | [
"sortings"
] | null | null | Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizontal straight lines, except for the average of these nine points. In other words, there must be three int... | The input consists of eight lines, the *i*-th line contains two space-separated integers *x**i* and *y**i* (0<=≤<=*x**i*,<=*y**i*<=≤<=106). You do not have any other conditions for these points. | In a single line print word "respectable", if the given set of points corresponds to Gerald's decency rules, and "ugly" otherwise. | [
"0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2\n",
"0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0\n",
"1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n"
] | [
"respectable\n",
"ugly\n",
"ugly\n"
] | none | 1,000 | [
{
"input": "0 0\n0 1\n0 2\n1 0\n1 2\n2 0\n2 1\n2 2",
"output": "respectable"
},
{
"input": "0 0\n1 0\n2 0\n3 0\n4 0\n5 0\n6 0\n7 0",
"output": "ugly"
},
{
"input": "1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2",
"output": "ugly"
},
{
"input": "0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0\n0 0... | 1,551,775,258 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import java.util.Scanner;
import java.util.ArrayList;
import java.util.Collections;
public class Main {
static final int MAX = (int)1e6 + 5;
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
ArrayList<Integer> unique_x = new ArrayList<>(), unique_y = new Arra... | Title: Eight Point Sets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald is very particular to eight point sets. He thinks that any decent eight point set must consist of all pairwise intersections of three distinct integer vertical straight lines and three distinct integer horizonta... | ```python
import java.util.Scanner;
import java.util.ArrayList;
import java.util.Collections;
public class Main {
static final int MAX = (int)1e6 + 5;
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
ArrayList<Integer> unique_x = new ArrayList<>(), unique_y ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,576,933,347 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 109 | 0 | '''input
12 3
101111100101
'''
n,d = map(int,input().split())
s = input()
i = 0
count = 0
possible = True
while i<n-1:
for c in range(min(i+d,n-1),i,-1):
if s[c]=='1':
count += 1
i = c
break
else:
possible = False
# print('Not possible')
break
if possible:
print(count)
els... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
'''input
12 3
101111100101
'''
n,d = map(int,input().split())
s = input()
i = 0
count = 0
possible = True
while i<n-1:
for c in range(min(i+d,n-1),i,-1):
if s[c]=='1':
count += 1
i = c
break
else:
possible = False
# print('Not possible')
break
if possible:
print(c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,695,986,848 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | user_name = input().strip()
# Count the number of distinct characters
distinct_characters = set(user_name)
# Determine the gender based on the count of distinct characters
if len(distinct_characters) % 2 == 0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
| Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
user_name = input().strip()
# Count the number of distinct characters
distinct_characters = set(user_name)
# Determine the gender based on the count of distinct characters
if len(distinct_characters) % 2 == 0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
624 | B | Making a String | PROGRAMMING | 1,100 | [
"greedy",
"sortings"
] | null | null | You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than *a**i* times; - the number of occurrences of each letter in the string must be distinct for all the ... | The first line of the input contains a single integer *n* (2<=<=≤<=<=*n*<=<=≤<=<=26) — the number of letters in the alphabet.
The next line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — *i*-th of these integers gives the limitation on the number of occurrences of the *i*-th character in the string. | Print a single integer — the maximum length of the string that meets all the requirements. | [
"3\n2 5 5\n",
"3\n1 1 2\n"
] | [
"11\n",
"3\n"
] | For convenience let's consider an alphabet consisting of three letters: "a", "b", "c". In the first sample, some of the optimal strings are: "cccaabbccbb", "aabcbcbcbcb". In the second sample some of the optimal strings are: "acc", "cbc". | 1,000 | [
{
"input": "3\n2 5 5",
"output": "11"
},
{
"input": "3\n1 1 2",
"output": "3"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "3\n1 1000000000 2",
"output": "1000000003"
},
{
"input": "26\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 10000... | 1,616,401,236 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 77 | 307,200 | def solution():
n = int(input())
limits = [int(each) for each in input().split()]
limits.sort(reverse=True)
res = []
i = 0
while i < n:
times = limits[i]
for j in range(limits.count(limits[i])):
while times in res:
times -= 1
res.append(tim... | Title: Making a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than ... | ```python
def solution():
n = int(input())
limits = [int(each) for each in input().split()]
limits.sort(reverse=True)
res = []
i = 0
while i < n:
times = limits[i]
for j in range(limits.count(limits[i])):
while times in res:
times -= 1
res.... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,618,135,130 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 154 | 0 | r, c = map(int, input().split())
mas = list(input() for i in range(r))
summ = r * c
row = column = count = 0
for i in range(r):
if 'S' not in mas[i]:
row += c
if row+column == summ:
print(row + column - count)
else:
for i in range(c):
tru = True
for j in range(r):
... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
r, c = map(int, input().split())
mas = list(input() for i in range(r))
summ = r * c
row = column = count = 0
for i in range(r):
if 'S' not in mas[i]:
row += c
if row+column == summ:
print(row + column - count)
else:
for i in range(c):
tru = True
for j in range... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
967 | A | Mind the Gap | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing lasts $1$ minute.
He was asked to insert one takeoff in the schedule. The takeoff takes $1$ minut... | The first line of input contains two integers $n$ and $s$ ($1 \le n \le 100$, $1 \le s \le 60$) — the number of landings on the schedule and the minimum allowed time (in minutes) between a landing and a takeoff.
Each of next $n$ lines contains two integers $h$ and $m$ ($0 \le h \le 23$, $0 \le m \le 59$) — the time, i... | Print two integers $h$ and $m$ — the hour and the minute from the current moment of the earliest time Arkady can insert the takeoff. | [
"6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40\n",
"16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59\n",
"3 17\n0 30\n1 0\n12 0\n"
] | [
"6 1\n",
"24 50\n",
"0 0\n"
] | In the first example note that there is not enough time between 1:20 and 3:21, because each landing and the takeoff take one minute.
In the second example there is no gaps in the schedule, so Arkady can only add takeoff after all landings. Note that it is possible that one should wait more than $24$ hours to insert th... | 500 | [
{
"input": "6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40",
"output": "6 1"
},
{
"input": "16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59",
"output": "24 50"
},
{
"input": "3 17\n0 30\n1 0\n12 0",
"output": "0 0"
},
{
... | 1,601,679,293 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 155 | 0 | n, k = map(int, input().split())
h, m = map(int, input().split())
if 60 * h + m >= k + 1:
print(0, 0)
else:
prev_hours, prev_minutes = h, m + 1
flag = 0
for _ in range(n - 1):
h, m = map(int, input().split())
if 60 * prev_hours + prev_minutes + k + 1 + k <= 60 * h + m:
... | Title: Mind the Gap
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing ... | ```python
n, k = map(int, input().split())
h, m = map(int, input().split())
if 60 * h + m >= k + 1:
print(0, 0)
else:
prev_hours, prev_minutes = h, m + 1
flag = 0
for _ in range(n - 1):
h, m = map(int, input().split())
if 60 * prev_hours + prev_minutes + k + 1 + k <= 60 * h + m:... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,601,153,284 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 280 | 614,400 | t, sx, sy, ex, ey = map(int, input().split())
st = input()
if sx < ex:
e = ex - sx
if sy < ey:
n = ey - sy
ind = 0
while ind < t:
if e <= 0 and n <= 0:
break
if st[ind] == 'E':
e-=1
if st[ind] == 'N':
n-=1
ind+=1
if e <= 0 and n <= 0:
print(ind)
else:
print(-1... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
t, sx, sy, ex, ey = map(int, input().split())
st = input()
if sx < ex:
e = ex - sx
if sy < ey:
n = ey - sy
ind = 0
while ind < t:
if e <= 0 and n <= 0:
break
if st[ind] == 'E':
e-=1
if st[ind] == 'N':
n-=1
ind+=1
if e <= 0 and n <= 0:
print(ind)
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
688 | B | Lovely Palindromes | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is trying to love them too, but only very special and gifted people can understand the beauty behind palindro... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10100<=000). | Print the *n*-th even-length palindrome number. | [
"1\n",
"10\n"
] | [
"11\n",
"1001\n"
] | The first 10 even-length palindrome numbers are 11, 22, 33, ... , 88, 99 and 1001. | 1,000 | [
{
"input": "1",
"output": "11"
},
{
"input": "10",
"output": "1001"
},
{
"input": "11",
"output": "1111"
},
{
"input": "12",
"output": "1221"
},
{
"input": "100",
"output": "100001"
},
{
"input": "1321",
"output": "13211231"
},
{
"input": "... | 1,622,129,583 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 170 | 9,420,800 |
# https://codeforces.com/contest/688/problem/B
def split(word):
return [char for char in word]
def listToString(s):
# initialize an empty string
str1 = ""
# traverse in the string
for ele in s:
str1 += ele
# return string
return str1
x = input()
print(x,e... | Title: Lovely Palindromes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pari has a friend who loves palindrome numbers. A palindrome number is a number that reads the same forward or backward. For example 12321, 100001 and 1 are palindrome numbers, while 112 and 1021 are not.
Pari is tr... | ```python
# https://codeforces.com/contest/688/problem/B
def split(word):
return [char for char in word]
def listToString(s):
# initialize an empty string
str1 = ""
# traverse in the string
for ele in s:
str1 += ele
# return string
return str1
x = input()... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
835 | B | The number on the board | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that the length of the number didn't change.
You have to find the minimum number of digits in which these two numbe... | The first line contains integer *k* (1<=≤<=*k*<=≤<=109).
The second line contains integer *n* (1<=≤<=*n*<=<<=10100000).
There are no leading zeros in *n*. It's guaranteed that this situation is possible. | Print the minimum number of digits in which the initial number and *n* can differ. | [
"3\n11\n",
"3\n99\n"
] | [
"1\n",
"0\n"
] | In the first example, the initial number could be 12.
In the second example the sum of the digits of *n* is not less than *k*. The initial number could be equal to *n*. | 750 | [
{
"input": "3\n11",
"output": "1"
},
{
"input": "3\n99",
"output": "0"
},
{
"input": "10\n5205602270",
"output": "0"
},
{
"input": "70\n3326631213",
"output": "6"
},
{
"input": "200\n100000001000000000000000000001000000000000000100000100000000000000000000000000000... | 1,655,178,289 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 48 | 93 | 10,137,600 | k = int(input())
n = list(input())
s = sum([int(i) for i in n])
n.sort()
c = 0
i = 0
while(i < len(n) and s < k):
s += 9 - int(n[i])
i += 1
c += 1
print(i) | Title: The number on the board
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some natural number was written on the board. Its sum of digits was not less than *k*. But you were distracted a bit, and someone changed this number to *n*, replacing some digits with others. It's known that th... | ```python
k = int(input())
n = list(input())
s = sum([int(i) for i in n])
n.sort()
c = 0
i = 0
while(i < len(n) and s < k):
s += 9 - int(n[i])
i += 1
c += 1
print(i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
787 | A | The Monster | PROGRAMMING | 1,200 | [
"brute force",
"math",
"number theory"
] | null | null | A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams at times *d*,<=*d*<=+<=*c*,<=*d*<=+<=2*c*,<=*d*<=+<=3*c*,<=....
The Monster will catch them if a... | The first line of input contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100).
The second line contains two integers *c* and *d* (1<=≤<=*c*,<=*d*<=≤<=100). | Print the first time Rick and Morty will scream at the same time, or <=-<=1 if they will never scream at the same time. | [
"20 2\n9 19\n",
"2 1\n16 12\n"
] | [
"82\n",
"-1\n"
] | In the first sample testcase, Rick's 5th scream and Morty's 8th time are at time 82.
In the second sample testcase, all Rick's screams will be at odd times and Morty's will be at even times, so they will never scream at the same time. | 500 | [
{
"input": "20 2\n9 19",
"output": "82"
},
{
"input": "2 1\n16 12",
"output": "-1"
},
{
"input": "39 52\n88 78",
"output": "1222"
},
{
"input": "59 96\n34 48",
"output": "1748"
},
{
"input": "87 37\n91 29",
"output": "211"
},
{
"input": "11 81\n49 7",
... | 1,490,282,684 | 1,184 | Python 3 | RUNTIME_ERROR | TESTS | 9 | 46 | 4,608,000 | def gcd(m, n):
while n:
m, n = n, m % n
return m
b, a = map(int, input().split())
d, c = map(int, input().split())
if a == c:
print(a)
else:
g = gcd(b,d)
if abs(a-b) % g:
print(-1)
else:
print(min([a+i*b for i in range(100) if a+i*b - c > 0 and (a+i*b - c) % d == 0]))
| Title: The Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams a... | ```python
def gcd(m, n):
while n:
m, n = n, m % n
return m
b, a = map(int, input().split())
d, c = map(int, input().split())
if a == c:
print(a)
else:
g = gcd(b,d)
if abs(a-b) % g:
print(-1)
else:
print(min([a+i*b for i in range(100) if a+i*b - c > 0 and (a+i*b - c) % d == 0])... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,604,447,904 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | n, k = map(int, input().split())
l = []
s = input()
for i in s:
l.append(i)
mn = set(s)
for i in mn:
r = l.count(i)
if k % r == 0:
continue
elif k % r != 0:
print('NO')
break
else:
print('YES')
| Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
n, k = map(int, input().split())
l = []
s = input()
for i in s:
l.append(i)
mn = set(s)
for i in mn:
r = l.count(i)
if k % r == 0:
continue
elif k % r != 0:
print('NO')
break
else:
print('YES')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,695,231,589 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | # Input
word = input()
# Capitalize the word
capitalized_word = word[0].upper() + word[1:]
# Output the capitalized word
print(capitalized_word)
| Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
# Input
word = input()
# Capitalize the word
capitalized_word = word[0].upper() + word[1:]
# Output the capitalized word
print(capitalized_word)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
545 | C | Woodcutters | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described below.
There are *n* trees located along the road at points with coordinates *x*1,<=*x*2,<=...,<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of trees.
Next *n* lines contain pairs of integers *x**i*,<=*h**i* (1<=≤<=*x**i*,<=*h**i*<=≤<=109) — the coordinate and the height of the *і*-th tree.
The pairs are given in the order of ascending *x**i*. No two trees are located at the point with t... | Print a single number — the maximum number of trees that you can cut down by the given rules. | [
"5\n1 2\n2 1\n5 10\n10 9\n19 1\n",
"5\n1 2\n2 1\n5 10\n10 9\n20 1\n"
] | [
"3\n",
"4\n"
] | In the first sample you can fell the trees like that:
- fell the 1-st tree to the left — now it occupies segment [ - 1;1] - fell the 2-nd tree to the right — now it occupies segment [2;3] - leave the 3-rd tree — it occupies point 5 - leave the 4-th tree — it occupies point 10 - fell the 5-th tree to the right — ... | 1,750 | [
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n19 1",
"output": "3"
},
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n20 1",
"output": "4"
},
{
"input": "4\n10 4\n15 1\n19 3\n20 1",
"output": "4"
},
{
"input": "35\n1 7\n3 11\n6 12\n7 6\n8 5\n9 11\n15 3\n16 10\n22 2\n23 3\n25 7\n27 3\n34 5\n35 10... | 1,680,262,811 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 264 | 10,547,200 | import sys
n = int(input())
list = []
for i in range(n):
a, b = sys.stdin.readline().split()
list.append([int(a), int(b)])
list.sort()
num = 2
pending = list[0][0]
for i in range(1, n-1):
prev = list[i-1][0]
curr = list[i][0]
next = list[i+1][0]
point = list[i][1]
if point < curr-prev: #... | Title: Woodcutters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described b... | ```python
import sys
n = int(input())
list = []
for i in range(n):
a, b = sys.stdin.readline().split()
list.append([int(a), int(b)])
list.sort()
num = 2
pending = list[0][0]
for i in range(1, n-1):
prev = list[i-1][0]
curr = list[i][0]
next = list[i+1][0]
point = list[i][1]
if point < cu... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
748 | A | Santa Claus and a Place in a Class | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are *n* lanes of *m* desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to *n* from the left to the right, the desks in a lane ar... | The only line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=10<=000, 1<=≤<=*k*<=≤<=2*nm*) — the number of lanes, the number of desks in each lane and the number of Santa Claus' place. | Print two integers: the number of lane *r*, the number of desk *d*, and a character *s*, which stands for the side of the desk Santa Claus. The character *s* should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right. | [
"4 3 9\n",
"4 3 24\n",
"2 4 4\n"
] | [
"2 2 L\n",
"4 3 R\n",
"1 2 R\n"
] | The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his pla... | 500 | [
{
"input": "4 3 9",
"output": "2 2 L"
},
{
"input": "4 3 24",
"output": "4 3 R"
},
{
"input": "2 4 4",
"output": "1 2 R"
},
{
"input": "3 10 24",
"output": "2 2 R"
},
{
"input": "10 3 59",
"output": "10 3 L"
},
{
"input": "10000 10000 160845880",
"... | 1,680,304,652 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 61 | 0 | n,m,k=map(int,input().split())
p,c,r=0,0,0
if k%2==0:
p=k//2
else:
p=(k//2)+1
if p%m==0:
c=p//m
else:
c=(p//m)+1
if p%m==0:
r=m
else:
r=p%m
if k%2==0:
print(c,r,"R")
else:
print(c,r,"L") | Title: Santa Claus and a Place in a Class
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are *n* lanes of *m* desks each, and there are two work... | ```python
n,m,k=map(int,input().split())
p,c,r=0,0,0
if k%2==0:
p=k//2
else:
p=(k//2)+1
if p%m==0:
c=p//m
else:
c=(p//m)+1
if p%m==0:
r=m
else:
r=p%m
if k%2==0:
print(c,r,"R")
else:
print(c,r,"L")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,570,130,664 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 218 | 0 | print('YES' if input()[:-1].strip()[-1].upper() in ['A', 'E', 'I', 'O', 'U', 'Y'] else 'NO')
| Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
print('YES' if input()[:-1].strip()[-1].upper() in ['A', 'E', 'I', 'O', 'U', 'Y'] else 'NO')
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
126 | B | Password | PROGRAMMING | 1,700 | [
"binary search",
"dp",
"hashing",
"string suffix structures",
"strings"
] | null | null | Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the... | You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters. | Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes. | [
"fixprefixsuffix\n",
"abcdabc\n"
] | [
"fix",
"Just a legend"
] | none | 1,000 | [
{
"input": "fixprefixsuffix",
"output": "fix"
},
{
"input": "abcdabc",
"output": "Just a legend"
},
{
"input": "qwertyqwertyqwerty",
"output": "qwerty"
},
{
"input": "papapapap",
"output": "papap"
},
{
"input": "aaaaaaaaaa",
"output": "aaaaaaaa"
},
{
"... | 1,552,397,646 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 218 | 0 | '''input
abcdabc
'''
# KMP prefix structure
from sys import stdin
def prefix_calculator(string):
p = [0] * len(string)
j = 0
for i in range(1, len(string)):
while j > 0 and string[i] != string[j]:
j = p[j - 1]
if string[i] == string[j]:
j += 1
p[i] = j
return p
# main starts
string = stdin.readl... | Title: Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carve... | ```python
'''input
abcdabc
'''
# KMP prefix structure
from sys import stdin
def prefix_calculator(string):
p = [0] * len(string)
j = 0
for i in range(1, len(string)):
while j > 0 and string[i] != string[j]:
j = p[j - 1]
if string[i] == string[j]:
j += 1
p[i] = j
return p
# main starts
string = s... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,616,568,224 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | a=input()
b=input()//2
c=input()//4
print(min(a,b,c)*7) | Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
a=input()
b=input()//2
c=input()//4
print(min(a,b,c)*7)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
484 | A | Bits | PROGRAMMING | 1,700 | [
"bitmasks",
"constructive algorithms"
] | null | null | Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that *l*<=≤<=*x*<=≤<=*r*, and is maximum possible. If there are multiple such numbers find the... | The first line contains integer *n* — the number of queries (1<=≤<=*n*<=≤<=10000).
Each of the following *n* lines contain two integers *l**i*,<=*r**i* — the arguments for the corresponding query (0<=≤<=*l**i*<=≤<=*r**i*<=≤<=1018). | For each query print the answer in a separate line. | [
"3\n1 2\n2 4\n1 10\n"
] | [
"1\n3\n7\n"
] | The binary representations of numbers from 1 to 10 are listed below:
1<sub class="lower-index">10</sub> = 1<sub class="lower-index">2</sub>
2<sub class="lower-index">10</sub> = 10<sub class="lower-index">2</sub>
3<sub class="lower-index">10</sub> = 11<sub class="lower-index">2</sub>
4<sub class="lower-index">10</su... | 500 | [
{
"input": "3\n1 2\n2 4\n1 10",
"output": "1\n3\n7"
},
{
"input": "55\n1 1\n1 2\n1 3\n1 4\n1 5\n1 6\n1 7\n1 8\n1 9\n1 10\n2 2\n2 3\n2 4\n2 5\n2 6\n2 7\n2 8\n2 9\n2 10\n3 3\n3 4\n3 5\n3 6\n3 7\n3 8\n3 9\n3 10\n4 4\n4 5\n4 6\n4 7\n4 8\n4 9\n4 10\n5 5\n5 6\n5 7\n5 8\n5 9\n5 10\n6 6\n6 7\n6 8\n6 9\n6 10... | 1,564,666,113 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 8,499,200 | from sys import stdin
#stdin = open("sum.in", 'r')
hat = stdin.readlines()
number = int(hat[0])
bigger = 0
def change(num, idx):
return num & ~(1 << idx)
def popcount(n):
ba = 0
while n:
if n & 1:
ba += 1
n >>= 1
return ba
def helaha(a, b):
if pop... | Title: Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's denote as the number of bits set ('1' bits) in the binary representation of the non-negative integer *x*.
You are given multiple queries consisting of pairs of integers *l* and *r*. For each query, find the *x*, such that ... | ```python
from sys import stdin
#stdin = open("sum.in", 'r')
hat = stdin.readlines()
number = int(hat[0])
bigger = 0
def change(num, idx):
return num & ~(1 << idx)
def popcount(n):
ba = 0
while n:
if n & 1:
ba += 1
n >>= 1
return ba
def helaha(a, b):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
278 | A | Circle Line | PROGRAMMING | 800 | [
"implementation"
] | null | null | The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) —... | Print a single number — the length of the shortest path between stations number *s* and *t*. | [
"4\n2 3 4 9\n1 3\n",
"4\n5 8 2 100\n4 1\n",
"3\n1 1 1\n3 1\n",
"3\n31 41 59\n1 1\n"
] | [
"5\n",
"15\n",
"1\n",
"0\n"
] | In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13.
In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15.
In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2.
In the fourth sample the numbers of st... | 500 | [
{
"input": "4\n2 3 4 9\n1 3",
"output": "5"
},
{
"input": "4\n5 8 2 100\n4 1",
"output": "15"
},
{
"input": "3\n1 1 1\n3 1",
"output": "1"
},
{
"input": "3\n31 41 59\n1 1",
"output": "0"
},
{
"input": "5\n16 13 10 30 15\n4 2",
"output": "23"
},
{
"inpu... | 1,607,972,646 | 2,147,483,647 | PyPy 3 | OK | TESTS | 23 | 248 | 0 | # A. Circle Line
n = int(input())
d = list(map(int, input().split()))
s, t = map(int, input().split())
s -= 1
t -= 1
if s > t:
s, t = t, s
s1 = sum(d[s:t])
s2 = sum(d[t:]) + sum(d[:s])
print(min(s1, s2))
| Title: Circle Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd... | ```python
# A. Circle Line
n = int(input())
d = list(map(int, input().split()))
s, t = map(int, input().split())
s -= 1
t -= 1
if s > t:
s, t = t, s
s1 = sum(d[s:t])
s2 = sum(d[t:]) + sum(d[:s])
print(min(s1, s2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
474 | B | Worms | PROGRAMMING | 1,200 | [
"binary search",
"implementation"
] | null | null | It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled w... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (... | Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is. | [
"5\n2 7 3 4 9\n3\n1 25 11\n"
] | [
"1\n5\n3\n"
] | For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the f... | 1,000 | [
{
"input": "5\n2 7 3 4 9\n3\n1 25 11",
"output": "1\n5\n3"
}
] | 1,696,734,327 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 614,400 | pile=int(input())
piles=list(map(int,input().split()))
worm=int(input())
worms=list(map(int,input().split()))
answers=[]
for i in worms:
digit=0
while i > 0:
i-=piles[digit]
digit+=1
answers.append(digit)
for ans in answers:
print(ans) | Title: Worms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers:... | ```python
pile=int(input())
piles=list(map(int,input().split()))
worm=int(input())
worms=list(map(int,input().split()))
answers=[]
for i in worms:
digit=0
while i > 0:
i-=piles[digit]
digit+=1
answers.append(digit)
for ans in answers:
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,662,787,668 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 41 | 62 | 0 | n = int (input ())
wealth = tuple (map (int, input ().split (' ')))
new = max (wealth)
cost = new * len (wealth) - sum (wealth)
print (cost) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n = int (input ())
wealth = tuple (map (int, input ().split (' ')))
new = max (wealth)
cost = new * len (wealth) - sum (wealth)
print (cost)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
355 | A | Vasya and Digital Root | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<... | The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9). | In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes. | [
"4 4\n",
"5 1\n",
"1 0\n"
] | [
"5881\n",
"36172\n",
"0\n"
] | For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | 500 | [
{
"input": "4 4",
"output": "5881"
},
{
"input": "5 1",
"output": "36172"
},
{
"input": "1 0",
"output": "0"
},
{
"input": "8 7",
"output": "49722154"
},
{
"input": "487 0",
"output": "No solution"
},
{
"input": "1000 5",
"output": "854193955406789... | 1,629,761,353 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 109 | 20,172,800 | def vas_dig_root(k, d):
if d == 0:
return -1
res = 0
dig_sum = 0
while k > 1:
res = (res*10)+1
k-=1
dig_sum+=1
res = (res*10)+d-dig_sum
return res
k,d = map(int, input().split())
print(vas_dig_root(k,d))
| Title: Vasya and Digital Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=... | ```python
def vas_dig_root(k, d):
if d == 0:
return -1
res = 0
dig_sum = 0
while k > 1:
res = (res*10)+1
k-=1
dig_sum+=1
res = (res*10)+d-dig_sum
return res
k,d = map(int, input().split())
print(vas_dig_root(k,d))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,680,740,295 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | from bisect import bisect_right
n, k = list(map(input().strip().split(''),int))
cost = [5*i for i in range(1,n+1)]
total_time = 0
time = [total_time := total_time + t for t in cost]
print(bisect_right(time, x=240-k, lo=0, hi=n)) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
from bisect import bisect_right
n, k = list(map(input().strip().split(''),int))
cost = [5*i for i in range(1,n+1)]
total_time = 0
time = [total_time := total_time + t for t in cost]
print(bisect_right(time, x=240-k, lo=0, hi=n))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,683,142,913 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 46 | 2,764,800 |
a = input()
print(max(a)-min(a))
| Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
a = input()
print(max(a)-min(a))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
183 | B | Zoo | PROGRAMMING | 1,700 | [
"brute force",
"geometry"
] | null | null | The Zoo in the Grid Kingdom is represented by an infinite grid. The Zoo has *n* observation binoculars located at the *OX* axis. For each *i* between 1 and *n*, inclusive, there exists a single binocular located at the point with coordinates (*i*,<=0). There are *m* flamingos in the Zoo, located at points with positive... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*<=≤<=106,<=1<=≤<=*m*<=≤<=250), denoting the number of binoculars and the number of flamingos, respectively.
Then *m* lines follow, the *i*-th line will contain two space-separated integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=109), whic... | Print a single integer denoting the maximum total number of flamingos that can be seen by all the binoculars. | [
"5 5\n2 1\n4 1\n3 2\n4 3\n4 4\n"
] | [
"11\n"
] | This picture shows the answer to the example test case. | 1,000 | [
{
"input": "5 5\n2 1\n4 1\n3 2\n4 3\n4 4",
"output": "11"
},
{
"input": "3 3\n1 1\n2 10\n3 100",
"output": "3"
},
{
"input": "1 2\n450000001 500000000\n900000001 1000000000",
"output": "2"
},
{
"input": "3 6\n1 1\n1 2\n1 3\n2 1\n2 2\n3 1",
"output": "7"
},
{
"inpu... | 1,674,398,430 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 248 | 13,209,600 | import math
from math import sqrt, inf, gcd, ceil, tan, pi, sin, cos
import queue
# -------- info --------
# https://codeforces.com/profile/Wolxy
# -------- sys --------
def next_int() -> int:
return int(input())
def next_ints() -> map:
return map(int, input().split(' '))
def next_li... | Title: Zoo
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Zoo in the Grid Kingdom is represented by an infinite grid. The Zoo has *n* observation binoculars located at the *OX* axis. For each *i* between 1 and *n*, inclusive, there exists a single binocular located at the point with c... | ```python
import math
from math import sqrt, inf, gcd, ceil, tan, pi, sin, cos
import queue
# -------- info --------
# https://codeforces.com/profile/Wolxy
# -------- sys --------
def next_int() -> int:
return int(input())
def next_ints() -> map:
return map(int, input().split(' '))
d... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,604,738,057 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 202 | 2,048,000 | buttons, bulbs = map(int, input().split())
bulb = [False] * bulbs
for _ in range(bulbs):
button = list(map(int, input().split()))
for b in button[1:]:
bulb[b-1] = True
if bulb[:] == [True] * bulbs:
print("YES")
else:
print('NO')
| Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
buttons, bulbs = map(int, input().split())
bulb = [False] * bulbs
for _ in range(bulbs):
button = list(map(int, input().split()))
for b in button[1:]:
bulb[b-1] = True
if bulb[:] == [True] * bulbs:
print("YES")
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
875 | A | Classroom Watch | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | Eighth-grader Vova is on duty today in the class. After classes, he went into the office to wash the board, and found on it the number *n*. He asked what is this number and the teacher of mathematics Inna Petrovna answered Vova that *n* is the answer to the arithmetic task for first-graders. In the textbook, a certain ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109). | In the first line print one integer *k* — number of different values of *x* satisfying the condition.
In next *k* lines print these values in ascending order. | [
"21\n",
"20\n"
] | [
"1\n15\n",
"0\n"
] | In the first test case *x* = 15 there is only one variant: 15 + 1 + 5 = 21.
In the second test case there are no such *x*. | 500 | [
{
"input": "21",
"output": "1\n15"
},
{
"input": "20",
"output": "0"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "1\n1"
},
{
"input": "3",
"output": "0"
},
{
"input": "100000001",
"output": "2\n99999937\n100000000"
},
{
"i... | 1,644,202,726 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | x = int(input())
m = x - 9 * (len(str(x)))
array = []
x = 0
def digito(v):
r = 0
while v > 0:
r += v % 10
v //= 10
return r
for i in range(max(m,0),x):
v = i + digito(i)
if v == x:
array.append(i)
x = x + 1
print(x)
for j in array:
print(j)
#Isaias Martins
#118... | Title: Classroom Watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eighth-grader Vova is on duty today in the class. After classes, he went into the office to wash the board, and found on it the number *n*. He asked what is this number and the teacher of mathematics Inna Petrovna answe... | ```python
x = int(input())
m = x - 9 * (len(str(x)))
array = []
x = 0
def digito(v):
r = 0
while v > 0:
r += v % 10
v //= 10
return r
for i in range(max(m,0),x):
v = i + digito(i)
if v == x:
array.append(i)
x = x + 1
print(x)
for j in array:
print(j)
#Isaias Ma... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Young Teodor enjoys drawing. His favourite hobby is drawing segments with integer borders inside his huge [1;*m*] segment. One day Teodor noticed that picture he just drawn has one interesting feature: there doesn't exist an integer point, that belongs each of segments in the picture. Having discovered this fact, Teodo... | First line of input contains two integer numbers: *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100<=000) — amount of segments of Teodor's picture and maximal coordinate of point that Sasha can ask about.
*i*th of next *n* lines contains two integer numbers *l**i* and *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*m*) — left and right ends ... | Single line of output should contain one integer number *k* – size of largest set (*x**i*,<=*cnt*(*x**i*)) where all *x**i* are different, 1<=≤<=*x**i*<=≤<=*m*, and *cnt*(*x**i*) is amount of segments, containing point with coordinate *x**i*, such that one can't be sure that there doesn't exist point, belonging to all ... | [
"2 4\n1 2\n3 4\n",
"4 6\n1 3\n2 3\n4 6\n5 6\n"
] | [
"4\n",
"5\n"
] | First example shows situation where Sasha can never be sure that Teodor isn't lying to him, because even if one knows *cnt*(*x*<sub class="lower-index">*i*</sub>) for each point in segment [1;4], he can't distinguish this case from situation Teodor has drawn whole [1;4] segment.
In second example Sasha can ask about 5... | 0 | [
{
"input": "2 4\n1 2\n3 4",
"output": "4"
},
{
"input": "4 6\n1 3\n2 3\n4 6\n5 6",
"output": "5"
},
{
"input": "43 1319\n750 1030\n857 946\n941 1203\n407 1034\n947 1290\n546 585\n630 1201\n72 342\n693 1315\n34 719\n176 1097\n36 931\n198 973\n5 1025\n892 1054\n461 1287\n195 1273\n832 1039... | 1,690,727,514 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 22 | 1,000 | 15,769,600 | import sys
def get_int():
return int(sys.stdin.readline().strip())
def get_int_list():
return list(map(int, sys.stdin.readline().split()))
class ST:
def __init__(self):
self.tree = []
self.sz = 0
def build(self, n):
self.sz = 1
while self.sz < n:
s... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Young Teodor enjoys drawing. His favourite hobby is drawing segments with integer borders inside his huge [1;*m*] segment. One day Teodor noticed that picture he just drawn has one interesting feature: there doesn't exist an integ... | ```python
import sys
def get_int():
return int(sys.stdin.readline().strip())
def get_int_list():
return list(map(int, sys.stdin.readline().split()))
class ST:
def __init__(self):
self.tree = []
self.sz = 0
def build(self, n):
self.sz = 1
while self.sz < n:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
285 | C | Building Permutation | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"sortings"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
You ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the size of the sought permutation. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Print a single number — the minimum number of moves.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"2\n3 0\n",
"3\n-1 -1 2\n"
] | [
"2\n",
"6\n"
] | In the first sample you should decrease the first number by one and then increase the second number by one. The resulting permutation is (2, 1).
In the second sample you need 6 moves to build permutation (1, 3, 2). | 1,500 | [
{
"input": "2\n3 0",
"output": "2"
},
{
"input": "3\n-1 -1 2",
"output": "6"
},
{
"input": "5\n-3 5 -3 3 3",
"output": "10"
},
{
"input": "10\n9 6 -2 4 1 1 1 9 6 2",
"output": "18"
},
{
"input": "9\n2 0 0 6 5 4 1 9 3",
"output": "15"
},
{
"input": "100... | 1,600,017,861 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | length=int(input())
arr=[int(i) for i in input().split()]
arr.sort()
print(arr)
tot=0
for i in range(len(arr)):
tot+=abs(arr[i]-i-1)
print(tot) | Title: Building Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *... | ```python
length=int(input())
arr=[int(i) for i in input().split()]
arr.sort()
print(arr)
tot=0
for i in range(len(arr)):
tot+=abs(arr[i]-i-1)
print(tot)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,687,061,716 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 93 | 0 | a,b,c=map(int,input().split())
x1=a*2+b*2
x2=a+c+b
x3=a*2+c*2
x4=b*2+c*2
print(min(x1,x2,x3,x4))
| Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
a,b,c=map(int,input().split())
x1=a*2+b*2
x2=a+c+b
x3=a*2+c*2
x4=b*2+c*2
print(min(x1,x2,x3,x4))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,626,983,499 | 2,147,483,647 | Python 3 | OK | TESTS | 84 | 77 | 6,758,400 | L = int(input())
A = int(input())
P = int(input())
x = min(L, A//2, P//4)
print(x*7) | Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
L = int(input())
A = int(input())
P = int(input())
x = min(L, A//2, P//4)
print(x*7)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
180 | C | Letter | PROGRAMMING | 1,400 | [
"dp"
] | null | null | Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them were uppercase.
Patrick believes that a message is fancy if any uppercase letter stands to... | The only line of the input contains a non-empty string consisting of uppercase and lowercase letters. The string's length does not exceed 105. | Print a single number — the least number of actions needed to make the message fancy. | [
"PRuvetSTAaYA\n",
"OYPROSTIYAOPECHATALSYAPRIVETSTASYA\n",
"helloworld\n"
] | [
"5\n",
"0\n",
"0\n"
] | none | 0 | [
{
"input": "PRuvetSTAaYA",
"output": "5"
},
{
"input": "OYPROSTIYAOPECHATALSYAPRIVETSTASYA",
"output": "0"
},
{
"input": "helloworld",
"output": "0"
},
{
"input": "P",
"output": "0"
},
{
"input": "t",
"output": "0"
},
{
"input": "XdJ",
"output": "1... | 1,586,097,830 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 310 | 2,457,600 | from sys import stdin,stdout
Pi = lambda x: stdout.write(str(x) + '\n')
Ps = lambda x: stdout.write(str(x))
S = lambda x: x*(x+1) // 2
I = lambda x: 1+(2*x)
R = lambda:stdin.readline()
Ri = lambda x:map(int,x.split())
Rs = lambda x:map(str,x.split())
Rf = lambda x:map(float,x.split())
def main():
# t = i... | Title: Letter
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Patrick has just finished writing a message to his sweetheart Stacey when he noticed that the message didn't look fancy. Patrick was nervous while writing the message, so some of the letters there were lowercase and some of them... | ```python
from sys import stdin,stdout
Pi = lambda x: stdout.write(str(x) + '\n')
Ps = lambda x: stdout.write(str(x))
S = lambda x: x*(x+1) // 2
I = lambda x: 1+(2*x)
R = lambda:stdin.readline()
Ri = lambda x:map(int,x.split())
Rs = lambda x:map(str,x.split())
Rf = lambda x:map(float,x.split())
def main(): ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
817 | C | Really Big Numbers | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"dp",
"math"
] | null | null | Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number *x* is really big if the difference between *x* and the sum of its digits (in decimal representation) is not less than *s*. To prove that these numbers may have different... | The first (and the only) line contains two integers *n* and *s* (1<=≤<=*n*,<=*s*<=≤<=1018). | Print one integer — the quantity of really big numbers that are not greater than *n*. | [
"12 1\n",
"25 20\n",
"10 9\n"
] | [
"3\n",
"0\n",
"1\n"
] | In the first example numbers 10, 11 and 12 are really big.
In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 ≥ 20).
In the third example 10 is the only really big number (10 - 1 ≥ 9). | 0 | [
{
"input": "12 1",
"output": "3"
},
{
"input": "25 20",
"output": "0"
},
{
"input": "10 9",
"output": "1"
},
{
"input": "300 1000",
"output": "0"
},
{
"input": "500 1000",
"output": "0"
},
{
"input": "1000 2000",
"output": "0"
},
{
"input":... | 1,497,545,272 | 6,172 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import java.util.*;
import java.lang.*;
public class exam {
private static short d;
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
long n = scan.nextLong();
long s = scan.nextLong();
long d = getD(s);
long t;
if... | Title: Really Big Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number *x* is really big if the difference between *x* and the sum of its... | ```python
import java.util.*;
import java.lang.*;
public class exam {
private static short d;
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
long n = scan.nextLong();
long s = scan.nextLong();
long d = getD(s);
long t;
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards ... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print... | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,629,094,689 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 6,963,200 | n = int(input())
arr = [int(i) for i in input().split()]
suma = sum(arr)//n * 2
v = []
for i in range(n):
for j in range(i+1,n):
if arr[i]+arr[j] == suma and j not in v and i not in v:
v.append(j)
print(i+1,v[-1]+1)
break
| Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one p... | ```python
n = int(input())
arr = [int(i) for i in input().split()]
suma = sum(arr)//n * 2
v = []
for i in range(n):
for j in range(i+1,n):
if arr[i]+arr[j] == suma and j not in v and i not in v:
v.append(j)
print(i+1,v[-1]+1)
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
44 | A | Indian Summer | PROGRAMMING | 900 | [
"implementation"
] | A. Indian Summer | 2 | 256 | Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the species of the tree of one of the leaves she already has. Find out how many leaves Alyona has picked. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of leaves Alyona has found. The next *n* lines contain the leaves' descriptions. Each leaf is characterized by the species of the tree it has fallen from and by the color. The species of the trees and colors are given in names, consisting of no mor... | Output the single number — the number of Alyona's leaves. | [
"5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green\n",
"3\noak yellow\noak yellow\noak yellow\n"
] | [
"4\n",
"1\n"
] | none | 0 | [
{
"input": "5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green",
"output": "4"
},
{
"input": "3\noak yellow\noak yellow\noak yellow",
"output": "1"
},
{
"input": "5\nxbnbkzn hp\nkaqkl vrgzbvqstu\nj aqidx\nhos gyul\nwefxmh tygpluae",
"output": "5"
},
{
"input"... | 1,592,568,449 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 310 | 0 | n=int(input())
l=[]
c=0
for i in range(n):
l.append(input())
for i in range(1,n):
if(l[0]==l[i]):
c+=1
print(n-c) | Title: Indian Summer
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the specie... | ```python
n=int(input())
l=[]
c=0
for i in range(n):
l.append(input())
for i in range(1,n):
if(l[0]==l[i]):
c+=1
print(n-c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
144 | A | Arrival of the General | PROGRAMMING | 800 | [
"implementation"
] | null | null | A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their... | The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginnin... | Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like. | [
"4\n33 44 11 22\n",
"7\n10 10 58 31 63 40 76\n"
] | [
"2\n",
"10\n"
] | In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76)... | 500 | [
{
"input": "4\n33 44 11 22",
"output": "2"
},
{
"input": "7\n10 10 58 31 63 40 76",
"output": "10"
},
{
"input": "2\n88 89",
"output": "1"
},
{
"input": "5\n100 95 100 100 88",
"output": "0"
},
{
"input": "7\n48 48 48 48 45 45 45",
"output": "0"
},
{
"... | 1,696,418,099 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n = int(input())
h = list(map(int, input().split()))
max_h = max(h)
min_h = min(h)
count_s = 0
count_e = 0
for i in range(n):
if h[i] != max_h:
break
count_s += 1
for i in range(n - 1, -1, -1):
if h[i] != min_h:
break
count_e += 1
seconds = max(count_s, count_e)
print(sec... | Title: Arrival of the General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on t... | ```python
n = int(input())
h = list(map(int, input().split()))
max_h = max(h)
min_h = min(h)
count_s = 0
count_e = 0
for i in range(n):
if h[i] != max_h:
break
count_s += 1
for i in range(n - 1, -1, -1):
if h[i] != min_h:
break
count_e += 1
seconds = max(count_s, count_e)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
666 | A | Reberland Linguistics | PROGRAMMING | 1,800 | [
"dp",
"implementation",
"strings"
] | null | null | First-rate specialists graduate from Berland State Institute of Peace and Friendship. You are one of the most talented students in this university. The education is not easy because you need to have fundamental knowledge in different areas, which sometimes are not related to each other.
For example, you should know l... | The only line contains a string *s* (5<=≤<=|*s*|<=≤<=104) consisting of lowercase English letters. | On the first line print integer *k* — a number of distinct possible suffixes. On the next *k* lines print suffixes.
Print suffixes in lexicographical (alphabetical) order. | [
"abacabaca\n",
"abaca\n"
] | [
"3\naca\nba\nca\n",
"0\n"
] | The first test was analysed in the problem statement.
In the second example the length of the string equals 5. The length of the root equals 5, so no string can be used as a suffix. | 500 | [
{
"input": "abacabaca",
"output": "3\naca\nba\nca"
},
{
"input": "abaca",
"output": "0"
},
{
"input": "gzqgchv",
"output": "1\nhv"
},
{
"input": "iosdwvzerqfi",
"output": "9\ner\nerq\nfi\nqfi\nrq\nvz\nvze\nze\nzer"
},
{
"input": "oawtxikrpvfuzugjweki",
"output... | 1,480,185,532 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 92 | 1,126,400 | def main():
s = input()[5:]
n = len(s)
if n < 2:
print(0)
return
res2, res3 = set(), set()
dp2 = [False] * (n + 1)
dp3 = [False] * (n + 1)
dp2[-1] = dp3[-1] = True
for i in range(n, 1, -1):
if dp3[i] or dp2[i] and s[i - 2:i] != s[i:i + 2]:
res2.add(s[i... | Title: Reberland Linguistics
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
First-rate specialists graduate from Berland State Institute of Peace and Friendship. You are one of the most talented students in this university. The education is not easy because you need to have fundamental kn... | ```python
def main():
s = input()[5:]
n = len(s)
if n < 2:
print(0)
return
res2, res3 = set(), set()
dp2 = [False] * (n + 1)
dp3 = [False] * (n + 1)
dp2[-1] = dp3[-1] = True
for i in range(n, 1, -1):
if dp3[i] or dp2[i] and s[i - 2:i] != s[i:i + 2]:
re... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
424 | B | Megacity | PROGRAMMING | 1,200 | [
"binary search",
"greedy",
"implementation",
"sortings"
] | null | null | The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding the boundaries of the city.
The city of Tomsk can be represented as point on the plane with ... | The first line of the input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=103; 1<=≤<=*s*<=<<=106) — the number of locatons around Tomsk city and the population of the city. Then *n* lines follow. The *i*-th line contains three integers — the *x**i* and *y**i* coordinate values of the *i*-th location and the numbe... | In the output, print "-1" (without the quotes), if Tomsk won't be able to become a megacity. Otherwise, in the first line print a single real number — the minimum radius of the circle that the city needs to expand to in order to become a megacity.
The answer is considered correct if the absolute or relative error don'... | [
"4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1\n",
"4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1\n",
"2 1\n1 1 999997\n2 2 1\n"
] | [
"2.8284271\n",
"1.4142136\n",
"-1"
] | none | 1,000 | [
{
"input": "4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1",
"output": "2.8284271"
},
{
"input": "4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1",
"output": "1.4142136"
},
{
"input": "2 1\n1 1 999997\n2 2 1",
"output": "-1"
},
{
"input": "4 999998\n3 3 10\n-3 3 10\n3 -3 10\n-3 -3 10",
"out... | 1,569,877,447 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 124 | 307,200 | #Megacity
import math
n, s = map(int, input().split())
class Boundary:
def __init__(self,x,y,population):
self.radius = round(math.sqrt(x*x + y*y),7)
self.population = population
def __lt__(self, other):
return self.radius < other.radius
arr = []
for i in range(n):
x, ... | Title: Megacity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding... | ```python
#Megacity
import math
n, s = map(int, input().split())
class Boundary:
def __init__(self,x,y,population):
self.radius = round(math.sqrt(x*x + y*y),7)
self.population = population
def __lt__(self, other):
return self.radius < other.radius
arr = []
for i in range(n)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
3 | D | Least Cost Bracket Sequence | PROGRAMMING | 2,600 | [
"greedy"
] | D. Least Cost Bracket Sequence | 1 | 64 | This is yet another problem on regular bracket sequences.
A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()" and "(()(()))" are regular, while ")(", "(()" and "(()))(" are not. You have a pattern of a bracket sequenc... | The first line contains a non-empty pattern of even length, consisting of characters "(", ")" and "?". Its length doesn't exceed 5·104. Then there follow *m* lines, where *m* is the number of characters "?" in the pattern. Each line contains two integer numbers *a**i* and *b**i* (1<=≤<=*a**i*,<=<=*b**i*<=≤<=106), where... | Print the cost of the optimal regular bracket sequence in the first line, and the required sequence in the second.
Print -1, if there is no answer. If the answer is not unique, print any of them. | [
"(??)\n1 2\n2 8\n"
] | [
"4\n()()\n"
] | none | 0 | [
{
"input": "(??)\n1 2\n2 8",
"output": "4\n()()"
},
{
"input": "??\n1 1\n1 1",
"output": "2\n()"
},
{
"input": "(???\n1 1\n1 1\n1 1",
"output": "3\n(())"
},
{
"input": "(??)\n2 1\n1 1",
"output": "2\n()()"
},
{
"input": "(???)?\n3 3\n3 1\n3 3\n2 3",
"output": ... | 1,498,482,893 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 124 | 4,608,000 | t = list(input())
b = 0
m = 0
d1 = []
d2 = []
for i in range(len(t)):
if t[i] == "(":
b += 1
elif t[i] == ")":
b -= 1
else:
c = list(map(int, input().split()))
t[i] = ")"
d1.append(i)
d2.append(c[0] - c[1])
b -=1
m += c[1]
... | Title: Least Cost Bracket Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
This is yet another problem on regular bracket sequences.
A bracket sequence is called regular, if by inserting "+" and "1" into it we get a correct mathematical expression. For example, sequences "(())()", "()"... | ```python
t = list(input())
b = 0
m = 0
d1 = []
d2 = []
for i in range(len(t)):
if t[i] == "(":
b += 1
elif t[i] == ")":
b -= 1
else:
c = list(map(int, input().split()))
t[i] = ")"
d1.append(i)
d2.append(c[0] - c[1])
b -=1
m +... | 0 | MatrixStudio/Codeforces-Python-Submissions |
845 | E | Fire in the City | PROGRAMMING | 2,400 | [
"binary search",
"data structures"
] | null | null | The capital of Berland looks like a rectangle of size *n*<=×<=*m* of the square blocks of same size.
Fire!
It is known that *k*<=+<=1 blocks got caught on fire (*k*<=+<=1<=≤<=*n*·*m*). Those blocks are centers of ignition. Moreover positions of *k* of these centers are known and one of these stays unknown. All *k*<=+... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=109, 1<=≤<=*k*<=≤<=500).
Each of the next *k* lines contain two integers *x**i* and *y**i* (1<=≤<=*x**i*<=≤<=*n*, 1<=≤<=*y**i*<=≤<=*m*) — coordinates of the *i*-th center of ignition. It is guaranteed that the locations of all centers of igni... | Print the minimal time it takes the fire to lighten up the whole city (in minutes). | [
"7 7 3\n1 2\n2 1\n5 5\n",
"10 5 1\n3 3\n"
] | [
"3\n",
"2\n"
] | In the first example the last block can have coordinates (4, 4).
In the second example the last block can have coordinates (8, 3). | 0 | [
{
"input": "7 7 3\n1 2\n2 1\n5 5",
"output": "3"
},
{
"input": "10 5 1\n3 3",
"output": "2"
},
{
"input": "4 5 19\n1 1\n1 2\n1 3\n1 4\n1 5\n2 1\n2 2\n2 3\n2 5\n3 1\n3 2\n3 3\n3 4\n3 5\n4 1\n4 2\n4 3\n4 4\n4 5",
"output": "0"
},
{
"input": "5 5 24\n1 2\n1 3\n1 4\n1 5\n2 1\n2 2... | 1,642,174,392 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 77 | 1,331,200 | import sys
input = sys.stdin.readline
def binary_search(c1, c2):
c = (c1 + c2 + 1) // 2
while abs(c1 - c2) > 1:
c = (c1 + c2 + 1) // 2
if ok(c):
c2 = c
else:
c1 = c
c += 2
while ok(c):
c -= 1
return c + 1
def ok(c):
if c ... | Title: Fire in the City
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The capital of Berland looks like a rectangle of size *n*<=×<=*m* of the square blocks of same size.
Fire!
It is known that *k*<=+<=1 blocks got caught on fire (*k*<=+<=1<=≤<=*n*·*m*). Those blocks are centers of ign... | ```python
import sys
input = sys.stdin.readline
def binary_search(c1, c2):
c = (c1 + c2 + 1) // 2
while abs(c1 - c2) > 1:
c = (c1 + c2 + 1) // 2
if ok(c):
c2 = c
else:
c1 = c
c += 2
while ok(c):
c -= 1
return c + 1
def ok(c):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,598,359,950 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 109 | 0 | n=int(input())
l=list(map(int,input().split()))
l=set(l)
count=0
for i in l:
if i!=0:
count+=1
print(count) | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n=int(input())
l=list(map(int,input().split()))
l=set(l)
count=0
for i in l:
if i!=0:
count+=1
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,009 | B | Minimum Ternary String | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa).
For e... | The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). | Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). | [
"100210\n",
"11222121\n",
"20\n"
] | [
"001120\n",
"11112222\n",
"20\n"
] | none | 0 | [
{
"input": "100210",
"output": "001120"
},
{
"input": "11222121",
"output": "11112222"
},
{
"input": "20",
"output": "20"
},
{
"input": "1002",
"output": "0012"
},
{
"input": "10",
"output": "01"
},
{
"input": "000021",
"output": "000012"
},
{
... | 1,614,017,069 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 280 | 11,673,600 | import sys, os, io
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(sys.stdin.readline())
def ria(): return list(map(int, sys.stdin.readline().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x in a]) + ... | Title: Minimum Ternary String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) ... | ```python
import sys, os, io
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(sys.stdin.readline())
def ria(): return list(map(int, sys.stdin.readline().split()))
def ws(s): sys.stdout.write(s + '\n')
def wi(n): sys.stdout.write(str(n) + '\n')
def wia(a): sys.stdout.write(' '.join([str(x) for x... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least... | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,676,537,593 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | (n,d)=map(int,str(input()).split())
l=list(map(int,str(input()).split()))
s=0
for i in range(len(l)-1):
while l[i+1]<=l[i]:
l[i+1]+=d
s+=1
print(l,s) | Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*... | ```python
(n,d)=map(int,str(input()).split())
l=list(map(int,str(input()).split()))
s=0
for i in range(len(l)-1):
while l[i+1]<=l[i]:
l[i+1]+=d
s+=1
print(l,s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
897 | A | Scarborough Fair | PROGRAMMING | 800 | [
"implementation"
] | null | null | Parsley, sage, rosemary and thyme.
Remember me to one who lives there.
He once was the true love of mine.
Willem is taking the girl to the highest building in island No.28, however, neither of them knows how to get there.
Willem asks his friend, Grick for directions, Grick helped them, and gave them a task.
Althou... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
The second line contains a string *s* of length *n*, consisting of lowercase English letters.
Each of the next *m* lines contains four parameters *l*,<=*r*,<=*c*1,<=*c*2 (1<=≤<=*l*<=≤<=*r*<=≤<=*n*, *c*1,<=*c*2 are lowercase English letters), ... | Output string *s* after performing *m* operations described above. | [
"3 1\nioi\n1 1 i n\n",
"5 3\nwxhak\n3 3 h x\n1 5 x a\n1 3 w g\n"
] | [
"noi",
"gaaak"
] | For the second example:
After the first operation, the string is wxxak.
After the second operation, the string is waaak.
After the third operation, the string is gaaak. | 500 | [
{
"input": "3 1\nioi\n1 1 i n",
"output": "noi"
},
{
"input": "5 3\nwxhak\n3 3 h x\n1 5 x a\n1 3 w g",
"output": "gaaak"
},
{
"input": "9 51\nbhfbdcgff\n2 3 b b\n2 8 e f\n3 8 g f\n5 7 d a\n1 5 e b\n3 4 g b\n6 7 c d\n3 6 e g\n3 6 e h\n5 6 a e\n7 9 a c\n4 9 a h\n3 7 c b\n6 9 b g\n1 7 h b\n... | 1,567,111,101 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 124 | 0 | n,m=map(int,input().split())
s=input()
for _ in range(m):
l, r, c1, c2 = input().split()
for i in range(int(l)-1,int(r),1):
if(s[i]==c1):
s=s[0:i]+c2+s[i+1:len(s)]
print(s,end="") | Title: Scarborough Fair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Parsley, sage, rosemary and thyme.
Remember me to one who lives there.
He once was the true love of mine.
Willem is taking the girl to the highest building in island No.28, however, neither of them knows how to get ... | ```python
n,m=map(int,input().split())
s=input()
for _ in range(m):
l, r, c1, c2 = input().split()
for i in range(int(l)-1,int(r),1):
if(s[i]==c1):
s=s[0:i]+c2+s[i+1:len(s)]
print(s,end="")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
808 | B | Average Sleep Time | PROGRAMMING | 1,300 | [
"data structures",
"implementation",
"math"
] | null | null | It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts *k* days!
When Polycarp went to a doctor with his problem, the doctor asked him about his sleeping schedule (more specifically, the average amount of hours of sleep per week). Luckily, Polycarp k... | The first line contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | Output average sleeping time over all weeks.
The answer is considered to be correct if its absolute or relative error does not exceed 10<=-<=6. In particular, it is enough to output real number with at least 6 digits after the decimal point. | [
"3 2\n3 4 7\n",
"1 1\n10\n",
"8 2\n1 2 4 100000 123 456 789 1\n"
] | [
"9.0000000000\n",
"10.0000000000\n",
"28964.2857142857\n"
] | In the third example there are *n* - *k* + 1 = 7 weeks, so the answer is sums of all weeks divided by 7. | 0 | [
{
"input": "3 2\n3 4 7",
"output": "9.0000000000"
},
{
"input": "1 1\n10",
"output": "10.0000000000"
},
{
"input": "8 2\n1 2 4 100000 123 456 789 1",
"output": "28964.2857142857"
},
{
"input": "1 1\n1",
"output": "1.0000000000"
},
{
"input": "1 1\n100000",
"ou... | 1,590,768,738 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 139 | 0 | import sys,math
Tests=1
for _ in range(Tests):
n,k=map(int,sys.stdin.readline().split())
arr=list(map(int,sys.stdin.readline().split()))
ans=0
for i in range(n):
b=min(n-k+1,i)
a=max(i-k+1,1)
if(a<=b):
ans+=arr[i]*(b-a+1)
print(ans/(n-k+1)) | Title: Average Sleep Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts *k* days!
When Polycarp went to a doctor with his problem, the doctor asked him about his s... | ```python
import sys,math
Tests=1
for _ in range(Tests):
n,k=map(int,sys.stdin.readline().split())
arr=list(map(int,sys.stdin.readline().split()))
ans=0
for i in range(n):
b=min(n-k+1,i)
a=max(i-k+1,1)
if(a<=b):
ans+=arr[i]*(b-a+1)
print(ans/(n-k+1)) ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,599,299,998 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 139 | 0 | s=input()
n=len("hello")
if(n>len(s)):
print("NO")
exit()
s1=""
count=0
for c in s:
if(c=='l'):
count+=1
if(c=='h' or c=='e' or c=='l' or c=='o'):
if((c not in s1) or (c=='l' and count<=2)):
s1=s1+c
# print(s1)
if(s1=="hello"):
p... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s=input()
n=len("hello")
if(n>len(s)):
print("NO")
exit()
s1=""
count=0
for c in s:
if(c=='l'):
count+=1
if(c=='h' or c=='e' or c=='l' or c=='o'):
if((c not in s1) or (c=='l' and count<=2)):
s1=s1+c
# print(s1)
if(s1=="hello"):
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
284 | B | Cows and Poker Game | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any be... | The first line contains a single integer, *n* (2<=≤<=*n*<=≤<=2·105). The second line contains *n* characters, each either "A", "I", or "F". The *i*-th character is "A" if the *i*-th player's status is "ALLIN", "I" if the *i*-th player's status is "IN", or "F" if the *i*-th player's status is "FOLDED". | The first line should contain a single integer denoting the number of players that can currently show their hands. | [
"6\nAFFAAA\n",
"3\nAFI\n"
] | [
"4\n",
"1\n"
] | In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | 1,000 | [
{
"input": "6\nAFFAAA",
"output": "4"
},
{
"input": "3\nAFI",
"output": "1"
},
{
"input": "3\nFFF",
"output": "0"
},
{
"input": "3\nFIF",
"output": "1"
},
{
"input": "3\nAAA",
"output": "3"
},
{
"input": "3\nIII",
"output": "0"
},
{
"input"... | 1,672,675,253 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 124 | 2,867,200 | N = int(input())
S = input()
hashmap = {}
for i in S:
if i not in hashmap:
hashmap[i] = 1
else:
hashmap[i] += 1
if 'I' in hashmap:
if hashmap['I'] == 1:
print(1)
else:
print(0)
else:
print(hashmap['A']) | Title: Cows and Poker Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player who... | ```python
N = int(input())
S = input()
hashmap = {}
for i in S:
if i not in hashmap:
hashmap[i] = 1
else:
hashmap[i] += 1
if 'I' in hashmap:
if hashmap['I'] == 1:
print(1)
else:
print(0)
else:
print(hashmap['A'])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Be... | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands ... | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,371,406,532 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 78 | 102,400 | n,m=input().split()
x='a'
n=int(n)
m=int(m)
k=True
for i in range(n):
s=input()
if(s.count(s[0])==m and s[0]!=x and k):
x=s[0]
continue
k=False
if(k):
print("YES")
else:
print("NO")
| Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of... | ```python
n,m=input().split()
x='a'
n=int(n)
m=int(m)
k=True
for i in range(n):
s=input()
if(s.count(s[0])==m and s[0]!=x and k):
x=s[0]
continue
k=False
if(k):
print("YES")
else:
print("NO")
``` | 3.979737 | MatrixStudio/Codeforces-Python-Submissions |
159 | D | Palindrome pairs | PROGRAMMING | 1,500 | [
"*special",
"brute force",
"dp",
"strings"
] | null | null | You are given a non-empty string *s* consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string.
In a more formal way, you have to find the quantity of tuples (*a*,<=*b*,<=*x*,<=*y*) such that 1<=≤<=*a*<=≤<=*b*<=<<=*x*<=≤<=*y*<=≤<=|*s*| and substrings *s*[*a*.... | The first line of input contains a non-empty string *s* which consists of lowercase letters ('a'...'z'), *s* contains at most 2000 characters. | Output a single number — the quantity of pairs of non-overlapping palindromic substrings of *s*.
Please do not use the %lld format specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d format specifier. | [
"aa\n",
"aaa\n",
"abacaba\n"
] | [
"1\n",
"5\n",
"36\n"
] | none | 2,000 | [
{
"input": "aa",
"output": "1"
},
{
"input": "aaa",
"output": "5"
},
{
"input": "abacaba",
"output": "36"
},
{
"input": "aaaaaaaaaa",
"output": "495"
},
{
"input": "aabbb",
"output": "24"
},
{
"input": "abbaa",
"output": "18"
},
{
"input": ... | 1,670,166,145 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 50 | 186 | 3,891,200 | s = input()
n = len(s)
beg = [0] * n
end = [0] * n
for i in range(n):
for j in range(n):
if i-j < 0 or i+j >= n: break
if s[i-j] != s[i+j]: break
beg[i-j] += 1
end[i+j] += 1
for j in range(n):
if i-j < 0 or i+j+1 >= n: break
if s[i-j] != s[i+j+1]... | Title: Palindrome pairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-empty string *s* consisting of lowercase letters. Find the number of pairs of non-overlapping palindromic substrings of this string.
In a more formal way, you have to find the quantity of tuples (*... | ```python
s = input()
n = len(s)
beg = [0] * n
end = [0] * n
for i in range(n):
for j in range(n):
if i-j < 0 or i+j >= n: break
if s[i-j] != s[i+j]: break
beg[i-j] += 1
end[i+j] += 1
for j in range(n):
if i-j < 0 or i+j+1 >= n: break
if s[i-j] !... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
792 | A | New Bus Route | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from one city to another only by bus. But all buses and roads are very old, so the Minister of Transport d... | The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). All numbers *a**i* are pairwise distinct. | Print two integer numbers — the minimal distance and the quantity of pairs with this distance. | [
"4\n6 -3 0 4\n",
"3\n-2 0 2\n"
] | [
"2 1\n",
"2 2\n"
] | In the first example the distance between the first city and the fourth city is |4 - 6| = 2, and it is the only pair with this distance. | 0 | [
{
"input": "4\n6 -3 0 4",
"output": "2 1"
},
{
"input": "3\n-2 0 2",
"output": "2 2"
},
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "2\n1000000000 -1000000000",
"output": "2000000000 1"
},
{
"input": "5\n-979619606 -979619602 -979619604 -979619605 -97961960... | 1,601,529,632 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 296 | 16,793,600 | n = int(input())
L = list(map(int,input().split()))
L.sort()
d = [ abs(L[i] - L[i-1]) for i in range(1, n)]
a = min(d)
print(a, d.count(a))
| Title: New Bus Route
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from on... | ```python
n = int(input())
L = list(map(int,input().split()))
L.sort()
d = [ abs(L[i] - L[i-1]) for i in range(1, n)]
a = min(d)
print(a, d.count(a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
854 | B | Maxim Buys an Apartment | PROGRAMMING | 1,200 | [
"constructive algorithms",
"math"
] | null | null | Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices differ by 1. Some of the apartments can already be inhabited, others are available for sale.
Maxim often visi... | The only line of the input contains two integers: *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=*n*). | Print the minimum possible and the maximum possible number of apartments good for Maxim. | [
"6 3\n"
] | [
"1 3\n"
] | In the sample test, the number of good apartments could be minimum possible if, for example, apartments with indices 1, 2 and 3 were inhabited. In this case only apartment 4 is good. The maximum possible number could be, for example, if apartments with indices 1, 3 and 5 were inhabited. In this case all other apartment... | 1,000 | [
{
"input": "6 3",
"output": "1 3"
},
{
"input": "10 1",
"output": "1 2"
},
{
"input": "10 9",
"output": "1 1"
},
{
"input": "8 0",
"output": "0 0"
},
{
"input": "8 8",
"output": "0 0"
},
{
"input": "966871928 890926970",
"output": "1 75944958"
},... | 1,505,924,916 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | nk = input()
n, k = [int(i) for i in nk.split(' ')]
if n == 1:
print(0, min(2 * k, n - k))
else:
print(1, min(2 * k, n - k))
| Title: Maxim Buys an Apartment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices d... | ```python
nk = input()
n, k = [int(i) for i in nk.split(' ')]
if n == 1:
print(0, min(2 * k, n - k))
else:
print(1, min(2 * k, n - k))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
143 | A | Help Vasilisa the Wise 2 | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know what the box's secret is, since she cannot open it again. She hopes that you will help her one more time with tha... | The input contains numbers written on the edges of the lock of the box. The first line contains space-separated integers *r*1 and *r*2 that define the required sums of numbers in the rows of the square. The second line contains space-separated integers *c*1 and *c*2 that define the required sums of numbers in the colum... | Print the scheme of decorating the box with stones: two lines containing two space-separated integers from 1 to 9. The numbers should be pairwise different. If there is no solution for the given lock, then print the single number "-1" (without the quotes).
If there are several solutions, output any. | [
"3 7\n4 6\n5 5\n",
"11 10\n13 8\n5 16\n",
"1 2\n3 4\n5 6\n",
"10 10\n10 10\n10 10\n"
] | [
"1 2\n3 4\n",
"4 7\n9 1\n",
"-1\n",
"-1\n"
] | Pay attention to the last test from the statement: it is impossible to open the box because for that Vasilisa the Wise would need 4 identical gems containing number "5". However, Vasilisa only has one gem with each number from 1 to 9. | 500 | [
{
"input": "3 7\n4 6\n5 5",
"output": "1 2\n3 4"
},
{
"input": "11 10\n13 8\n5 16",
"output": "4 7\n9 1"
},
{
"input": "1 2\n3 4\n5 6",
"output": "-1"
},
{
"input": "10 10\n10 10\n10 10",
"output": "-1"
},
{
"input": "5 13\n8 10\n11 7",
"output": "3 2\n5 8"
... | 1,602,836,743 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 154 | 0 | a = input()
keys = []
rings = []
for i in a:
if a in keys:
for x in range(len(keys)-1):
if keys[x] == a:
rings[x] += 1
break
else:
keys.append(i)
n = 0
for i in range(len(rings)-1):
if rings[i] % 2 == 1:
n += 1
if n < 2 or n... | Title: Help Vasilisa the Wise 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know wha... | ```python
a = input()
keys = []
rings = []
for i in a:
if a in keys:
for x in range(len(keys)-1):
if keys[x] == a:
rings[x] += 1
break
else:
keys.append(i)
n = 0
for i in range(len(rings)-1):
if rings[i] % 2 == 1:
n += 1
if ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,597,673,450 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 46,387,200 | x = int(input())
y = int(input())
result = y % 2 ** x
print(result) | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
x = int(input())
y = int(input())
result = y % 2 ** x
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
909 | C | Python Indentation | PROGRAMMING | 1,800 | [
"dp"
] | null | null | In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An ex... | The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement. | Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7. | [
"4\ns\nf\nf\ns\n",
"4\nf\ns\nf\ns\n"
] | [
"1\n",
"2\n"
] | In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one... | 1,500 | [
{
"input": "4\ns\nf\nf\ns",
"output": "1"
},
{
"input": "4\nf\ns\nf\ns",
"output": "2"
},
{
"input": "156\nf\ns\nf\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\nf\nf\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\ns... | 1,515,503,566 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 5,632,000 | n=int(input())
k=0
p=0
for i in range(n) :
b=input()
if b=='f' and p==0 :
k=k+1
p=1
if b=='s' :
p=0
print(2**(k-1))
| Title: Python Indentation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python... | ```python
n=int(input())
k=0
p=0
for i in range(n) :
b=input()
if b=='f' and p==0 :
k=k+1
p=1
if b=='s' :
p=0
print(2**(k-1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
144 | A | Arrival of the General | PROGRAMMING | 800 | [
"implementation"
] | null | null | A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on the parade ground.
By the military charter the soldiers should stand in the order of non-increasing of their... | The first input line contains the only integer *n* (2<=≤<=*n*<=≤<=100) which represents the number of soldiers in the line. The second line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) the values of the soldiers' heights in the order of soldiers' heights' increasing in the order from the beginnin... | Print the only integer — the minimum number of seconds the colonel will need to form a line-up the general will like. | [
"4\n33 44 11 22\n",
"7\n10 10 58 31 63 40 76\n"
] | [
"2\n",
"10\n"
] | In the first sample the colonel will need to swap the first and second soldier and then the third and fourth soldier. That will take 2 seconds. The resulting position of the soldiers is (44, 33, 22, 11).
In the second sample the colonel may swap the soldiers in the following sequence:
1. (10, 10, 58, 31, 63, 40, 76)... | 500 | [
{
"input": "4\n33 44 11 22",
"output": "2"
},
{
"input": "7\n10 10 58 31 63 40 76",
"output": "10"
},
{
"input": "2\n88 89",
"output": "1"
},
{
"input": "5\n100 95 100 100 88",
"output": "0"
},
{
"input": "7\n48 48 48 48 45 45 45",
"output": "0"
},
{
"... | 1,694,157,581 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | n=int(input())
x=input().split()
z=[int(i) for i in x]
sf,sl=max(z),min(z)
check1,check2=[],[]
lswap,rswap=z.index(sf),(len(z)-z.index(sl))+1
for i in z:
if z.count(sl)>=2:
check2.append(z.index(sl))
rswap=max(check2)
elif z.count(sf)>=2:
check1.append(z.index(sf))
ls... | Title: Arrival of the General
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A Ministry for Defense sent a general to inspect the Super Secret Military Squad under the command of the Colonel SuperDuper. Having learned the news, the colonel ordered to all *n* squad soldiers to line up on t... | ```python
n=int(input())
x=input().split()
z=[int(i) for i in x]
sf,sl=max(z),min(z)
check1,check2=[],[]
lswap,rswap=z.index(sf),(len(z)-z.index(sl))+1
for i in z:
if z.count(sl)>=2:
check2.append(z.index(sl))
rswap=max(check2)
elif z.count(sf)>=2:
check1.append(z.index(sf))
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,650,737,618 | 2,147,483,647 | Python 3 | OK | TESTS | 80 | 92 | 0 | #!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
import math
import bisect
from math import gcd, floor, sqrt, log
from bisect import bisect_left as bl, bisect_right as br
sys.setrecursionlimit(100000000)
inp = lambda: int(input())
strng = lambda: input()
jn = lambda x, l: x.join(map(str, l))... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
import math
import bisect
from math import gcd, floor, sqrt, log
from bisect import bisect_left as bl, bisect_right as br
sys.setrecursionlimit(100000000)
inp = lambda: int(input())
strng = lambda: input()
jn = lambda x, l: x.join(ma... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,647,290,459 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 5,222,400 | e=True
n=int(input())
line=input().split()
a=0
b=0
for person in line:
if person=="25":
a+=1
elif person=="50":
a-=1
b+=1
elif person=="100":
if a>=3 and b<=0:
a-=3
elif a>=1 and b>=1:
a-=1
b-=1
else:
... | Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the bookin... | ```python
e=True
n=int(input())
line=input().split()
a=0
b=0
for person in line:
if person=="25":
a+=1
elif person=="50":
a-=1
b+=1
elif person=="100":
if a>=3 and b<=0:
a-=3
elif a>=1 and b>=1:
a-=1
b-=1
el... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
687 | A | NP-Hard Problem | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs"
] | null | null | Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of this graph, if for each edge *uv* there is at least one endpoint of it in this set, i.e. or (or bot... | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — the number of vertices and the number of edges in the prize graph, respectively.
Each of the next *m* lines contains a pair of integers *u**i* and *v**i* (1<=<=≤<=<=*u**i*,<=<=*v**i*<=<=≤<=<=*n*), denoting ... | If it's impossible to split the graph between Pari and Arya as they expect, print "-1" (without quotes).
If there are two disjoint sets of vertices, such that both sets are vertex cover, print their descriptions. Each description must contain two lines. The first line contains a single integer *k* denoting the number ... | [
"4 2\n1 2\n2 3\n",
"3 3\n1 2\n2 3\n1 3\n"
] | [
"1\n2 \n2\n1 3 \n",
"-1\n"
] | In the first sample, you can give the vertex number 2 to Arya and vertices numbered 1 and 3 to Pari and keep vertex number 4 for yourself (or give it someone, if you wish).
In the second sample, there is no way to satisfy both Pari and Arya. | 500 | [
{
"input": "4 2\n1 2\n2 3",
"output": "1\n2 \n2\n1 3 "
},
{
"input": "3 3\n1 2\n2 3\n1 3",
"output": "-1"
},
{
"input": "5 7\n3 2\n5 4\n3 4\n1 3\n1 5\n1 4\n2 5",
"output": "-1"
},
{
"input": "10 11\n4 10\n8 10\n2 3\n2 4\n7 1\n8 5\n2 8\n7 2\n1 2\n2 9\n6 8",
"output": "-1"
... | 1,606,695,765 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 2,000 | 16,896,000 | n, m = list(map(int, input().split()))
from types import GeneratorType
def bootstrap(f, stack=[]):
def wrappedfunc(*args, **kwargs):
if stack:
return f(*args, **kwargs)
else:
to = f(*args, **kwargs)
while True:
if type(to) is Generator... | Title: NP-Hard Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of ... | ```python
n, m = list(map(int, input().split()))
from types import GeneratorType
def bootstrap(f, stack=[]):
def wrappedfunc(*args, **kwargs):
if stack:
return f(*args, **kwargs)
else:
to = f(*args, **kwargs)
while True:
if type(to) is... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
168 | B | Wizards and Minimal Spell | PROGRAMMING | 1,700 | [
"implementation",
"strings"
] | null | null | Let's dive into one of the most interesting areas of magic — writing spells. Learning this exciting but challenging science is very troublesome, so now you will not learn the magic words, but only get to know the basic rules of writing spells.
Each spell consists of several lines. The line, whose first non-space chara... | The input contains multiple lines. All characters in the lines have codes from 32 to 127 (inclusive). Please note that the lines may begin with or end with one or more spaces. The size of the input does not exceed 1048576 (<==<=220) bytes. Newlines are included in this size.
In the Windows operating system used on the... | Print the text of the spell where all extra characters are deleted. Please note that each output line should be followed by a newline.
Please be careful: your answers will be validated by comparing them to the jury's answer byte-by-byte. So, all spaces and newlines matter. | [
"# include <cstdio>\n\nusing namespace std;\n\nint main ( ){\nputs(\"Hello # World\"); #\n#\n}\n",
"#\n\n#\n"
] | [
"# include <cstdio>\nusingnamespacestd;intmain(){puts(\"Hello#World\");#\n#\n}\n",
"#\n\n#\n"
] | In the first sample the amplifying lines are lines 1 and 7. So, lines 2 to 6 are concatenated to each other, all spaces are deleted from them.
In the second sample the amplifying lines are lines 1 and 3. So, no lines are concatenated to each other. | 1,000 | [
{
"input": " # include <cstdio>\n\nusing namespace std;\n\nint main ( ){\nputs(\"Hello # World\"); #\n#\n}",
"output": " # include <cstdio>\nusingnamespacestd;intmain(){puts(\"Hello#World\");#\n#\n}"
},
{
"input": "#\n\n#",
"output": "#\n\n#"
},
{
"input": "#\n \n#",
"... | 1,600,669,246 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 156 | 0 | import sys
code = sys.stdin.readlines()
ans_code = []
for line in code:
ans_code.append(line)
print(ans_code) | Title: Wizards and Minimal Spell
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's dive into one of the most interesting areas of magic — writing spells. Learning this exciting but challenging science is very troublesome, so now you will not learn the magic words, but only get to know ... | ```python
import sys
code = sys.stdin.readlines()
ans_code = []
for line in code:
ans_code.append(line)
print(ans_code)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
842 | B | Gleb And Pizza | PROGRAMMING | 1,100 | [
"geometry"
] | null | null | Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the crust, and he does not really like the crust.
The pizza is a circle of radius *r* and center at the origin. Pizza consists of the main part — circle of radius *r*<=-<=*d* with center at the or... | First string contains two integer numbers *r* and *d* (0<=≤<=*d*<=<<=*r*<=≤<=500) — the radius of pizza and the width of crust.
Next line contains one integer number *n* — the number of pieces of sausage (1<=≤<=*n*<=≤<=105).
Each of next *n* lines contains three integer numbers *x**i*, *y**i* and *r**i* (<=-<=500<... | Output the number of pieces of sausage that lay on the crust. | [
"8 4\n7\n7 8 1\n-7 3 2\n0 2 1\n0 -2 2\n-3 -3 1\n0 6 2\n5 3 1\n",
"10 8\n4\n0 0 9\n0 0 10\n1 0 1\n1 0 2\n"
] | [
"2\n",
"0\n"
] | Below is a picture explaining the first example. Circles of green color denote pieces of sausage lying on the crust. | 1,000 | [
{
"input": "8 4\n7\n7 8 1\n-7 3 2\n0 2 1\n0 -2 2\n-3 -3 1\n0 6 2\n5 3 1",
"output": "2"
},
{
"input": "10 8\n4\n0 0 9\n0 0 10\n1 0 1\n1 0 2",
"output": "0"
},
{
"input": "1 0\n1\n1 1 0",
"output": "0"
},
{
"input": "3 0\n5\n3 0 0\n0 3 0\n-3 0 0\n0 -3 0\n3 0 1",
"output": ... | 1,504,021,908 | 2,808 | Python 3 | WRONG_ANSWER | PRETESTS | 4 | 46 | 0 | # cook your dish here
r,d=map(int,input().strip().split(' '))
n=int(input())
k=0
for i in range(n):
x,y,r1=map(int,input().strip().split(' '))
dis=pow(x*x+y*y,.5)
if(dis+r1<=r and dis-r1>=d):
k+=1
print(k) | Title: Gleb And Pizza
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gleb ordered pizza home. When the courier delivered the pizza, he was very upset, because several pieces of sausage lay on the crust, and he does not really like the crust.
The pizza is a circle of radius *r* and center... | ```python
# cook your dish here
r,d=map(int,input().strip().split(' '))
n=int(input())
k=0
for i in range(n):
x,y,r1=map(int,input().strip().split(' '))
dis=pow(x*x+y*y,.5)
if(dis+r1<=r and dis-r1>=d):
k+=1
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
385 | C | Bear and Prime Numbers | PROGRAMMING | 1,700 | [
"binary search",
"brute force",
"data structures",
"dp",
"implementation",
"math",
"number theory"
] | null | null | Recently, the bear started studying data structures and faced the following problem.
You are given a sequence of integers *x*1,<=*x*2,<=...,<=*x**n* of length *n* and *m* queries, each of them is characterized by two integers *l**i*,<=*r**i*. Let's introduce *f*(*p*) to represent the number of such indexes *k*, that *... | The first line contains integer *n* (1<=≤<=*n*<=≤<=106). The second line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* (2<=≤<=*x**i*<=≤<=107). The numbers are not necessarily distinct.
The third line contains integer *m* (1<=≤<=*m*<=≤<=50000). Each of the following *m* lines contains a pair of space-separated integ... | Print *m* integers — the answers to the queries on the order the queries appear in the input. | [
"6\n5 5 7 10 14 15\n3\n2 11\n3 12\n4 4\n",
"7\n2 3 5 7 11 4 8\n2\n8 10\n2 123\n"
] | [
"9\n7\n0\n",
"0\n7\n"
] | Consider the first sample. Overall, the first sample has 3 queries.
1. The first query *l* = 2, *r* = 11 comes. You need to count *f*(2) + *f*(3) + *f*(5) + *f*(7) + *f*(11) = 2 + 1 + 4 + 2 + 0 = 9. 1. The second query comes *l* = 3, *r* = 12. You need to count *f*(3) + *f*(5) + *f*(7) + *f*(11) = 1 + 4 + 2 + 0 = 7.... | 1,500 | [
{
"input": "6\n5 5 7 10 14 15\n3\n2 11\n3 12\n4 4",
"output": "9\n7\n0"
},
{
"input": "7\n2 3 5 7 11 4 8\n2\n8 10\n2 123",
"output": "0\n7"
},
{
"input": "9\n50 50 50 50 50 50 50 50 50\n7\n20 20\n8 13\n13 13\n6 14\n3 5\n15 17\n341 1792",
"output": "0\n0\n0\n0\n9\n0\n0"
},
{
"... | 1,599,834,846 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 155 | 1,536,000 | import math
limit = 40000
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
prime[0],prime[1] = False,False
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prim... | Title: Bear and Prime Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, the bear started studying data structures and faced the following problem.
You are given a sequence of integers *x*1,<=*x*2,<=...,<=*x**n* of length *n* and *m* queries, each of them is characterized b... | ```python
import math
limit = 40000
def SieveOfEratosthenes(n):
prime = [True for i in range(n+1)]
prime[0],prime[1] = False,False
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
r... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,671,599,568 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | import math
n = int(input())
print(f'{math.ceil(n/2)} {math.floor(n/2)}') | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
import math
n = int(input())
print(f'{math.ceil(n/2)} {math.floor(n/2)}')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
252 | B | Unsorting Array | PROGRAMMING | 1,800 | [
"brute force",
"sortings"
] | null | null | Little Petya likes arrays of integers a lot. Recently his mother has presented him one such array consisting of *n* elements. Petya is now wondering whether he can swap any two distinct integers in the array so that the array got unsorted. Please note that Petya can not swap equal integers even if they are in distinct ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* non-negative space-separated integers *a*1,<=*a*2,<=...,<=*a**n* — the elements of the array that Petya's mother presented him. All integers in the input do not exceed 109. | If there is a pair of positions that make the array unsorted if swapped, then print the numbers of these positions separated by a space. If there are several pairs of positions, print any of them. If such pair does not exist, print -1. The positions in the array are numbered with integers from 1 to *n*. | [
"1\n1\n",
"2\n1 2\n",
"4\n1 2 3 4\n",
"3\n1 1 1\n"
] | [
"-1\n",
"-1\n",
"1 2\n",
"-1\n"
] | In the first two samples the required pairs obviously don't exist.
In the third sample you can swap the first two elements. After that the array will look like this: 2 1 3 4. This array is unsorted. | 1,000 | [
{
"input": "1\n1",
"output": "-1"
},
{
"input": "2\n1 2",
"output": "-1"
},
{
"input": "4\n1 2 3 4",
"output": "1 2"
},
{
"input": "3\n1 1 1",
"output": "-1"
},
{
"input": "3\n1 2 2",
"output": "1 2"
},
{
"input": "5\n1 1 1 1 2",
"output": "2 5"
... | 1,690,501,673 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | print("_RANDOM_GUESS_1690501673.4088113")# 1690501673.4088318 | Title: Unsorting Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes arrays of integers a lot. Recently his mother has presented him one such array consisting of *n* elements. Petya is now wondering whether he can swap any two distinct integers in the array so that the... | ```python
print("_RANDOM_GUESS_1690501673.4088113")# 1690501673.4088318
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,688,610,852 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 46 | 0 | g=0
n=int(input())
for i in range(n):
x,y=map(int,input().split())
if y-x >=2:
g+=1
print(g) | Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
g=0
n=int(input())
for i in range(n):
x,y=map(int,input().split())
if y-x >=2:
g+=1
print(g)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
762 | E | Radio stations | PROGRAMMING | 2,200 | [
"binary search",
"data structures"
] | null | null | In the lattice points of the coordinate line there are *n* radio stations, the *i*-th of which is described by three integers:
- *x**i* — the coordinate of the *i*-th station on the line, - *r**i* — the broadcasting range of the *i*-th station, - *f**i* — the broadcasting frequency of the *i*-th station.
We will s... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=10) — the number of radio stations and the maximum difference in the frequencies for the pair of stations that reach each other to be considered bad.
In the next *n* lines follow the descriptions of radio stations. Each line contains th... | Output the number of bad pairs of radio stations. | [
"3 2\n1 3 10\n3 2 5\n4 10 8\n",
"3 3\n1 3 10\n3 2 5\n4 10 8\n",
"5 1\n1 3 2\n2 2 4\n3 2 1\n4 2 1\n5 3 3\n",
"5 1\n1 5 2\n2 5 4\n3 5 1\n4 5 1\n5 5 3\n"
] | [
"1\n",
"2\n",
"2\n",
"5\n"
] | none | 0 | [
{
"input": "3 2\n1 3 10\n3 2 5\n4 10 8",
"output": "1"
},
{
"input": "3 3\n1 3 10\n3 2 5\n4 10 8",
"output": "2"
},
{
"input": "5 1\n1 3 2\n2 2 4\n3 2 1\n4 2 1\n5 3 3",
"output": "2"
},
{
"input": "5 1\n1 5 2\n2 5 4\n3 5 1\n4 5 1\n5 5 3",
"output": "5"
},
{
"input... | 1,491,164,669 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 5,529,600 | class stn:
def __init__(self, x, r, f):
self.x = x
self.r = r
self.f = f
stantions = []
n, k = map(int, input().split())
for i in range(n):
x, r, f = map(int, input().split())
stantions.append(stn(x, r, f))
result = 0
for stn1 in stantions:
for stn2 in stantions:
... | Title: Radio stations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the lattice points of the coordinate line there are *n* radio stations, the *i*-th of which is described by three integers:
- *x**i* — the coordinate of the *i*-th station on the line, - *r**i* — the broadcasting r... | ```python
class stn:
def __init__(self, x, r, f):
self.x = x
self.r = r
self.f = f
stantions = []
n, k = map(int, input().split())
for i in range(n):
x, r, f = map(int, input().split())
stantions.append(stn(x, r, f))
result = 0
for stn1 in stantions:
for stn2 in sta... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
633 | A | Ebony and Ivory | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
For every bullet that hits the shield, Ebony deals *a* units of damage while Ivory deals *b* units of ... | The first line of the input contains three integers *a*, *b*, *c* (1<=≤<=*a*,<=*b*<=≤<=100,<=1<=≤<=*c*<=≤<=10<=000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively. | Print "Yes" (without quotes) if Dante can deal exactly *c* damage to the shield and "No" (without quotes) otherwise. | [
"4 6 15\n",
"3 2 7\n",
"6 11 6\n"
] | [
"No\n",
"Yes\n",
"Yes\n"
] | In the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage. | 250 | [
{
"input": "4 6 15",
"output": "No"
},
{
"input": "3 2 7",
"output": "Yes"
},
{
"input": "6 11 6",
"output": "Yes"
},
{
"input": "3 12 15",
"output": "Yes"
},
{
"input": "5 5 10",
"output": "Yes"
},
{
"input": "6 6 7",
"output": "No"
},
{
"... | 1,600,933,125 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 117 | 156 | 1,331,200 | from math import gcd
import sys
a,b,c=map(int,input().split())
if c%gcd(a,b)==0:
for i in range(0,101):
for j in range(0,101):
if a*i+b*j==c:
print("Yes")
sys.exit()
print("No")
else:
print("No") | Title: Ebony and Ivory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
F... | ```python
from math import gcd
import sys
a,b,c=map(int,input().split())
if c%gcd(a,b)==0:
for i in range(0,101):
for j in range(0,101):
if a*i+b*j==c:
print("Yes")
sys.exit()
print("No")
else:
print("No")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
493 | B | Vasya and Wrestling | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of... | The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* poin... | If the first wrestler wins, print string "first", otherwise print "second" | [
"5\n1\n2\n-3\n-4\n3\n",
"3\n-1\n-2\n3\n",
"2\n4\n-4\n"
] | [
"second\n",
"first\n",
"second\n"
] | Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |... | 1,000 | [
{
"input": "5\n1\n2\n-3\n-4\n3",
"output": "second"
},
{
"input": "3\n-1\n-2\n3",
"output": "first"
},
{
"input": "2\n4\n-4",
"output": "second"
},
{
"input": "7\n1\n2\n-3\n4\n5\n-6\n7",
"output": "first"
},
{
"input": "14\n1\n2\n3\n4\n5\n6\n7\n-8\n-9\n-10\n-11\n-... | 1,608,620,997 | 2,147,483,647 | PyPy 3 | OK | TESTS | 57 | 1,466 | 10,649,600 | arr = []
brr = []
for _ in range(int(input())):
n = int(input())
#print(n)
if n > 0:
arr.append(n)
else:
brr.append(-1*n)
#print(arr,brr,n)
if sum(arr) > sum(brr):
print("first")
elif sum(arr) < sum(brr):
print("second")
else:
if arr > brr:
print... | Title: Vasya and Wrestling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers ... | ```python
arr = []
brr = []
for _ in range(int(input())):
n = int(input())
#print(n)
if n > 0:
arr.append(n)
else:
brr.append(-1*n)
#print(arr,brr,n)
if sum(arr) > sum(brr):
print("first")
elif sum(arr) < sum(brr):
print("second")
else:
if arr > brr:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
501 | C | Misha and Forest | PROGRAMMING | 1,500 | [
"constructive algorithms",
"data structures",
"greedy",
"sortings",
"trees"
] | null | null | Let's define a forest as a non-directed acyclic graph (also without loops and parallel edges). One day Misha played with the forest consisting of *n* vertices. For each vertex *v* from 0 to *n*<=-<=1 he wrote down two integers, *degree**v* and *s**v*, were the first integer is the number of vertices adjacent to vertex ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=216), the number of vertices in the graph.
The *i*-th of the next lines contains numbers *degree**i* and *s**i* (0<=≤<=*degree**i*<=≤<=*n*<=-<=1, 0<=≤<=*s**i*<=<<=216), separated by a space. | In the first line print number *m*, the number of edges of the graph.
Next print *m* lines, each containing two distinct numbers, *a* and *b* (0<=≤<=*a*<=≤<=*n*<=-<=1, 0<=≤<=*b*<=≤<=*n*<=-<=1), corresponding to edge (*a*,<=*b*).
Edges can be printed in any order; vertices of the edge can also be printed in any order. | [
"3\n2 3\n1 0\n1 0\n",
"2\n1 1\n1 0\n"
] | [
"2\n1 0\n2 0\n",
"1\n0 1\n"
] | The XOR sum of numbers is the result of bitwise adding numbers modulo 2. This operation exists in many modern programming languages. For example, in languages C++, Java and Python it is represented as "^", and in Pascal — as "xor". | 1,500 | [
{
"input": "3\n2 3\n1 0\n1 0",
"output": "2\n1 0\n2 0"
},
{
"input": "2\n1 1\n1 0",
"output": "1\n0 1"
},
{
"input": "10\n3 13\n2 6\n1 5\n3 5\n1 3\n2 2\n2 6\n1 6\n1 3\n2 3",
"output": "9\n2 5\n4 3\n7 6\n8 3\n5 0\n6 1\n3 9\n1 0\n9 0"
},
{
"input": "10\n1 2\n1 7\n1 0\n1 8\n0 0\... | 1,666,985,806 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | n=int(input())
w=[]
eta=[]
for j in range(n):
w.append([int(k) for k in input().split()])
for j in range(n):
if w[j][0]==1:
eta.append([j, w[j][1]])
w[w[j][1]][1]=w[w[j][1]][1]^j
w[w[j][1]][0]-=1
w[j][0]=0
w[j][1]=0
iota=w[j][1]
while w[iota][... | Title: Misha and Forest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's define a forest as a non-directed acyclic graph (also without loops and parallel edges). One day Misha played with the forest consisting of *n* vertices. For each vertex *v* from 0 to *n*<=-<=1 he wrote down two ... | ```python
n=int(input())
w=[]
eta=[]
for j in range(n):
w.append([int(k) for k in input().split()])
for j in range(n):
if w[j][0]==1:
eta.append([j, w[j][1]])
w[w[j][1]][1]=w[w[j][1]][1]^j
w[w[j][1]][0]-=1
w[j][0]=0
w[j][1]=0
iota=w[j][1]
whil... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
982 | B | Bus of Characters | PROGRAMMING | 1,300 | [
"data structures",
"greedy",
"implementation"
] | null | null | In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$ stops one passenger enters the bus. There are two types of passengers:
- an introvert always choose... | The first line contains a single integer $n$ ($1 \le n \le 200\,000$) — the number of rows in the bus.
The second line contains the sequence of integers $w_1, w_2, \dots, w_n$ ($1 \le w_i \le 10^{9}$), where $w_i$ is the width of each of the seats in the $i$-th row. It is guaranteed that all $w_i$ are distinct.
The t... | Print $2n$ integers — the rows the passengers will take. The order of passengers should be the same as in input. | [
"2\n3 1\n0011\n",
"6\n10 8 9 11 13 5\n010010011101\n"
] | [
"2 1 1 2 \n",
"6 6 2 3 3 1 4 4 1 2 5 5 \n"
] | In the first example the first passenger (introvert) chooses the row $2$, because it has the seats with smallest width. The second passenger (introvert) chooses the row $1$, because it is the only empty row now. The third passenger (extrovert) chooses the row $1$, because it has exactly one occupied seat and the seat w... | 1,000 | [
{
"input": "2\n3 1\n0011",
"output": "2 1 1 2 "
},
{
"input": "6\n10 8 9 11 13 5\n010010011101",
"output": "6 6 2 3 3 1 4 4 1 2 5 5 "
},
{
"input": "1\n1\n01",
"output": "1 1 "
},
{
"input": "1\n1000000\n01",
"output": "1 1 "
},
{
"input": "2\n1 1000000\n0011",
... | 1,585,824,103 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 2,000 | 27,136,000 | MyDict = {}
N, Ans = int(input()), []
Width = list(map(int, input().split()))
Passengers = input()
for i in range(N):
MyDict[Width[i]] = [0, i + 1]
Keys = sorted(Width)
Index = 0
for j in Passengers:
if j == "0":
MyDict[Keys[Index]][0] += 1
print(MyDict[Keys[Index]][1], end=" ")
... | Title: Bus of Characters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the Bus of Characters there are $n$ rows of seat, each having $2$ seats. The width of both seats in the $i$-th row is $w_i$ centimeters. All integers $w_i$ are distinct.
Initially the bus is empty. On each of $2n$... | ```python
MyDict = {}
N, Ans = int(input()), []
Width = list(map(int, input().split()))
Passengers = input()
for i in range(N):
MyDict[Width[i]] = [0, i + 1]
Keys = sorted(Width)
Index = 0
for j in Passengers:
if j == "0":
MyDict[Keys[Index]][0] += 1
print(MyDict[Keys[Index]][1], end=... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
989 | B | A Tide of Riverscape | PROGRAMMING | 1,200 | [
"constructive algorithms",
"strings"
] | null | null | "Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.
Doubtfully, Kanno peeks a... | The first line contains two space-separated integers $n$ and $p$ ($1 \leq p \leq n \leq 2000$) — the length of the given string and the supposed period, respectively.
The second line contains a string $s$ of $n$ characters — Mino's records. $s$ only contains characters '0', '1' and '.', and contains at least one '.' c... | Output one line — if it's possible that $p$ is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)). | [
"10 7\n1.0.1.0.1.\n",
"10 6\n1.0.1.1000\n",
"10 9\n1........1\n"
] | [
"1000100010\n",
"1001101000\n",
"No\n"
] | In the first example, $7$ is not a period of the resulting string because the $1$-st and $8$-th characters of it are different.
In the second example, $6$ is not a period of the resulting string because the $4$-th and $10$-th characters of it are different.
In the third example, $9$ is always a period because the onl... | 1,000 | [
{
"input": "10 7\n1.0.1.0.1.",
"output": "1000100010"
},
{
"input": "10 6\n1.0.1.1000",
"output": "1001101000"
},
{
"input": "10 9\n1........1",
"output": "No"
},
{
"input": "1 1\n.",
"output": "No"
},
{
"input": "5 1\n0...1",
"output": "00001"
},
{
"i... | 1,528,798,757 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 78 | 0 | n, p = map(int, input().split(' '))
line = list(input())
possible = False
if p <= n/2:
possible = True
if not possible and p > n / 2:
for i in range(n):
if line[i] == '.':
if i - p >= 0 and line[i - p] != '.':
possible = True
elif i + p < n and line[i... | Title: A Tide of Riverscape
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its... | ```python
n, p = map(int, input().split(' '))
line = list(input())
possible = False
if p <= n/2:
possible = True
if not possible and p > n / 2:
for i in range(n):
if line[i] == '.':
if i - p >= 0 and line[i - p] != '.':
possible = True
elif i + p < n ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
845 | A | Chess Tourney | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizer... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100).
The second line contains 2·*n* integers *a*1,<=*a*2,<=... *a*2*n* (1<=≤<=*a**i*<=≤<=1000). | If it's possible to divide all 2·*n* players into two teams with *n* people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO". | [
"2\n1 3 2 4\n",
"1\n3 3\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2\n1 3 2 4",
"output": "YES"
},
{
"input": "1\n3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 2 2 3 3 3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 1 2 2 2 2 2",
"output": "YES"
},
{
"input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000... | 1,562,103,806 | 206 | PyPy 3 | OK | TESTS | 88 | 155 | 102,400 | n = int(input())
a = [int(i) for i in input().split()]
a.sort()
if(a[n] > a[n-1]):
print('YES')
else:
print('NO') | Title: Chess Tourney
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by... | ```python
n = int(input())
a = [int(i) for i in input().split()]
a.sort()
if(a[n] > a[n-1]):
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
754 | A | Lesha and array splitting | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | One spring day on his way to university Lesha found an array *A*. Lesha likes to split arrays into several parts. This time Lesha decided to split the array *A* into several, possibly one, new arrays so that the sum of elements in each of the new arrays is not zero. One more condition is that if we place the new arrays... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array *A*.
The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=103<=≤<=*a**i*<=≤<=103) — the elements of the array *A*. | If it is not possible to split the array *A* and satisfy all the constraints, print single line containing "NO" (without quotes).
Otherwise in the first line print "YES" (without quotes). In the next line print single integer *k* — the number of new arrays. In each of the next *k* lines print two integers *l**i* and *... | [
"3\n1 2 -3\n",
"8\n9 -12 3 4 -4 -10 7 3\n",
"1\n0\n",
"4\n1 2 3 -5\n"
] | [
"YES\n2\n1 2\n3 3\n",
"YES\n2\n1 2\n3 8\n",
"NO\n",
"YES\n4\n1 1\n2 2\n3 3\n4 4\n"
] | none | 500 | [
{
"input": "3\n1 2 -3",
"output": "YES\n3\n1 1\n2 2\n3 3"
},
{
"input": "8\n9 -12 3 4 -4 -10 7 3",
"output": "YES\n8\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8"
},
{
"input": "1\n0",
"output": "NO"
},
{
"input": "4\n1 2 3 -5",
"output": "YES\n4\n1 1\n2 2\n3 3\n4 4"
},
{
... | 1,596,166,100 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 93 | 6,656,000 | a=int(input())
z=list(map(int,input().split()))
for i in range(a-1):
if sum(z[:i+1])!=0 and sum(z[i+1:])!=0:
print("YES")
print(2)
print(1,i+1)
print(i+2,a)
exit()
print("NO") | Title: Lesha and array splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One spring day on his way to university Lesha found an array *A*. Lesha likes to split arrays into several parts. This time Lesha decided to split the array *A* into several, possibly one, new arrays so that t... | ```python
a=int(input())
z=list(map(int,input().split()))
for i in range(a-1):
if sum(z[:i+1])!=0 and sum(z[i+1:])!=0:
print("YES")
print(2)
print(1,i+1)
print(i+2,a)
exit()
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,634,916,093 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 4,505,600 | n,m=map(int,input().split())
b=[]
for i in range (n):
x=list(input())
p=x[0]
b=b.append(x[1,p])
q=1
while q<m:
if q in b :
q+=1
if q not in b:
break
if q==m:
print('YES')
else:
print('NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n,m=map(int,input().split())
b=[]
for i in range (n):
x=list(input())
p=x[0]
b=b.append(x[1,p])
q=1
while q<m:
if q in b :
q+=1
if q not in b:
break
if q==m:
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
255 | B | Code Parsing | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Little Vitaly loves different algorithms. Today he has invented a new algorithm just for you. Vitaly's algorithm works with string *s*, consisting of characters "x" and "y", and uses two following operations at runtime:
1. Find two consecutive characters in the string, such that the first of them equals "y", and the ... | The first line contains a non-empty string *s*.
It is guaranteed that the string only consists of characters "x" and "y". It is guaranteed that the string consists of at most 106 characters. It is guaranteed that as the result of the algorithm's execution won't be an empty string. | In the only line print the string that is printed as the result of the algorithm's work, if the input of the algorithm input receives string *s*. | [
"x\n",
"yxyxy\n",
"xxxxxy\n"
] | [
"x\n",
"y\n",
"xxxx\n"
] | In the first test the algorithm will end after the first step of the algorithm, as it is impossible to apply any operation. Thus, the string won't change.
In the second test the transformation will be like this:
1. string "yxyxy" transforms into string "xyyxy"; 1. string "xyyxy" transforms into string "xyxyy"; 1. ... | 1,000 | [
{
"input": "x",
"output": "x"
},
{
"input": "yxyxy",
"output": "y"
},
{
"input": "xxxxxy",
"output": "xxxx"
},
{
"input": "yxyyxyyx",
"output": "yy"
},
{
"input": "yxxyxyx",
"output": "x"
},
{
"input": "xxx",
"output": "xxx"
},
{
"input": "... | 1,679,994,242 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 92 | 3,891,200 | a=input()
x=a.count('x')
y=len(a)-x
print(('yx'[x>y])*abs(x-y))
| Title: Code Parsing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vitaly loves different algorithms. Today he has invented a new algorithm just for you. Vitaly's algorithm works with string *s*, consisting of characters "x" and "y", and uses two following operations at runtime:
1... | ```python
a=input()
x=a.count('x')
y=len(a)-x
print(('yx'[x>y])*abs(x-y))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,652,459,625 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | s=input()
l=['h','e','i','d','i']
i=0
r=0
sett=0
try:
while i<len(s):
while i<len(s) and s[i]!=l[r]:
print(s[i],l[r])
i+=1
if s[i]==l[r]:
sett+=1
r+=1
if sett==5:
break
except:
print('NO')
else:
print('YES')
| Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
s=input()
l=['h','e','i','d','i']
i=0
r=0
sett=0
try:
while i<len(s):
while i<len(s) and s[i]!=l[r]:
print(s[i],l[r])
i+=1
if s[i]==l[r]:
sett+=1
r+=1
if sett==5:
break
except:
print('NO')
else:
print... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,643,548,452 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 46 | 0 | n,d=map(int,input().split())
s=input()
f=1
c=0
i=0
while(i<n-1):
if(i+d<n):
j=i+d
else:
j=n-1
while(s[j]!='1' and j>=i):
j-=1
if(j<=i):
f=0
break
else:
i=j
c+=1
if(f==1):
print(c)
else:
print(-1) | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
n,d=map(int,input().split())
s=input()
f=1
c=0
i=0
while(i<n-1):
if(i+d<n):
j=i+d
else:
j=n-1
while(s[j]!='1' and j>=i):
j-=1
if(j<=i):
f=0
break
else:
i=j
c+=1
if(f==1):
print(c)
else:
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,587,920,121 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 49 | 124 | 0 | n, k = map(int, input().split())
s = list(input())
colors = set(s)
result = 'YES' if n >= k else 'NO'
if result == 'YES':
for color in colors:
if s.count(color) > k:
result = 'NO'
break
print(result) | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
n, k = map(int, input().split())
s = list(input())
colors = set(s)
result = 'YES' if n >= k else 'NO'
if result == 'YES':
for color in colors:
if s.count(color) > k:
result = 'NO'
break
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,676,065,288 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 41 | 109 | 5,529,600 | n = int(input())
a = list(map(int, input().split()))
prom = a.count(1)
math = a.count(2)
fiz = a.count(3)
count = 0
while prom >= 1 and math >= 1 and fiz >= 1:
count += 1
prom -= 1
math -= 1
fiz -= 1
print(count)
for i in range(count):
print(a.index(1) + 1, a.index(2) + 1, a.index(3) + ... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n = int(input())
a = list(map(int, input().split()))
prom = a.count(1)
math = a.count(2)
fiz = a.count(3)
count = 0
while prom >= 1 and math >= 1 and fiz >= 1:
count += 1
prom -= 1
math -= 1
fiz -= 1
print(count)
for i in range(count):
print(a.index(1) + 1, a.index(2) + 1, a.i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
186 | A | Comparing Strings | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Mish... | The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that co... | Print "YES", if the dwarves belong to the same race. Otherwise, print "NO". | [
"ab\nba\n",
"aa\nab\n"
] | [
"YES\n",
"NO\n"
] | - First example: you can simply swap two letters in string "ab". So we get "ba". - Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b". | 500 | [
{
"input": "ab\nba",
"output": "YES"
},
{
"input": "aa\nab",
"output": "NO"
},
{
"input": "a\nza",
"output": "NO"
},
{
"input": "vvea\nvvae",
"output": "YES"
},
{
"input": "rtfabanpc\natfabrnpc",
"output": "YES"
},
{
"input": "mt\ntm",
"output": "Y... | 1,686,527,819 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 31 | 154 | 5,427,200 | first = input()
second = input()
if len(first) != len(second):
print("NO")
else:
differences = []
for i in range(len(first)):
if first[i] != second[i]:
differences.append(i)
if len(differences) != 2 and len(differences) != 0:
print('NO')
else:
prin... | Title: Comparing Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome ... | ```python
first = input()
second = input()
if len(first) != len(second):
print("NO")
else:
differences = []
for i in range(len(first)):
if first[i] != second[i]:
differences.append(i)
if len(differences) != 2 and len(differences) != 0:
print('NO')
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,611,142,085 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | word = input()
control = 'hello'
final = []
for char in word:
if char in control and (char not in final or (char=='l' and final.count('l')==1)):
final.append(char)
print(final)
elif char in final:
final.remove(char)
final.append(char)
if ''.join(final)==control:
print('YES')
... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
word = input()
control = 'hello'
final = []
for char in word:
if char in control and (char not in final or (char=='l' and final.count('l')==1)):
final.append(char)
print(final)
elif char in final:
final.remove(char)
final.append(char)
if ''.join(final)==control:
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,619,264,935 | 2,147,483,647 | PyPy 3 | OK | TESTS | 26 | 93 | 0 | no_of_songs, max_duration = map(int, input().split())
song_time_list = list(map(int, input().split()))
max_jokes = 0
waiting_time = (len(song_time_list) - 1) * 10
song_performance_time = 0
for song_time in song_time_list:
song_performance_time += song_time
if waiting_time+song_performance_time > max_d... | Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
no_of_songs, max_duration = map(int, input().split())
song_time_list = list(map(int, input().split()))
max_jokes = 0
waiting_time = (len(song_time_list) - 1) * 10
song_performance_time = 0
for song_time in song_time_list:
song_performance_time += song_time
if waiting_time+song_performance_ti... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
596 | A | Wilbur and Swimming Pool | PROGRAMMING | 1,100 | [
"geometry",
"implementation"
] | null | null | After making bad dives into swimming pools, Wilbur wants to build a swimming pool in the shape of a rectangle in his backyard. He has set up coordinate axes, and he wants the sides of the rectangle to be parallel to them. Of course, the area of the rectangle must be positive. Wilbur had all four vertices of the planned... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=4) — the number of vertices that were not erased by Wilbur's friend.
Each of the following *n* lines contains two integers *x**i* and *y**i* (<=-<=1000<=≤<=*x**i*,<=*y**i*<=≤<=1000) —the coordinates of the *i*-th vertex that remains. Vertices are... | Print the area of the initial rectangle if it could be uniquely determined by the points remaining. Otherwise, print <=-<=1. | [
"2\n0 0\n1 1\n",
"1\n1 1\n"
] | [
"1\n",
"-1\n"
] | In the first sample, two opposite corners of the initial rectangle are given, and that gives enough information to say that the rectangle is actually a unit square.
In the second sample there is only one vertex left and this is definitely not enough to uniquely define the area. | 500 | [
{
"input": "2\n0 0\n1 1",
"output": "1"
},
{
"input": "1\n1 1",
"output": "-1"
},
{
"input": "1\n-188 17",
"output": "-1"
},
{
"input": "1\n71 -740",
"output": "-1"
},
{
"input": "4\n-56 -858\n-56 -174\n778 -858\n778 -174",
"output": "570456"
},
{
"inp... | 1,516,823,426 | 326 | Python 3 | OK | TESTS | 121 | 62 | 5,632,000 | n = int(input())
R = lambda : map(int, input().split())
xs = set()
ys = set()
for _ in range(n):
x,y = R()
xs.add(x)
ys.add(y)
if len(xs)==len(ys)==2:
y = max(ys)-min(ys)
x = max(xs)-min(xs)
print (y*x)
else:
print(-1) | Title: Wilbur and Swimming Pool
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After making bad dives into swimming pools, Wilbur wants to build a swimming pool in the shape of a rectangle in his backyard. He has set up coordinate axes, and he wants the sides of the rectangle to be parall... | ```python
n = int(input())
R = lambda : map(int, input().split())
xs = set()
ys = set()
for _ in range(n):
x,y = R()
xs.add(x)
ys.add(y)
if len(xs)==len(ys)==2:
y = max(ys)-min(ys)
x = max(xs)-min(xs)
print (y*x)
else:
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,697,529,172 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | x=input()
y=input()
if len(x)>=len(y):
big=x
low=y
else
big=y
low=x
count=0
for i in range(len(l)):
if big[len(low)-1:]==low:
print(len(big[len(low)-1:])+count)
break
else
low=low[1:]
count=count+1
| Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
x=input()
y=input()
if len(x)>=len(y):
big=x
low=y
else
big=y
low=x
count=0
for i in range(len(l)):
if big[len(low)-1:]==low:
print(len(big[len(low)-1:])+count)
break
else
low=low[1:]
count=count+1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is... | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so ... | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,638,457,393 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 3,993,600 | #!/usr/bin/env python
# coding=utf-8
'''
Author: Deean
Date: 2021-11-29 23:17:57
LastEditTime: 2021-12-02 23:01:45
Description: Free Cash
FilePath: CF237A.py
'''
def func():
n = int(input())
times, count = [], []
for _ in range(n):
times.append(input().strip())
for item in list(set(times)):
... | Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends l... | ```python
#!/usr/bin/env python
# coding=utf-8
'''
Author: Deean
Date: 2021-11-29 23:17:57
LastEditTime: 2021-12-02 23:01:45
Description: Free Cash
FilePath: CF237A.py
'''
def func():
n = int(input())
times, count = [], []
for _ in range(n):
times.append(input().strip())
for item in list(set(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
404 | A | Valera and X | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the... | The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper. | Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes. | [
"5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n",
"3\nwsw\nsws\nwsw\n",
"3\nxpx\npxp\nxpe\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox",
"output": "NO"
},
{
"input": "3\nwsw\nsws\nwsw",
"output": "YES"
},
{
"input": "3\nxpx\npxp\nxpe",
"output": "NO"
},
{
"input": "5\nliiil\nilili\niilii\nilili\nliiil",
"output": "YES"
},
{
"input": "7\nbwccccb\nck... | 1,600,357,046 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 18 | 156 | 2,048,000 |
n=int(input())
d1=''
d2=''
l=[]
flag=1
for i in range(n):
a=input()
l.append(a)
d1+=a[i]
d2+=a[n-1-i]
s=set(list(d1))
if(d1==d2):
for j in range(n):
b=l[j]
b=list(b)
c=[]
#b=b[]
for k in range(n):
if(k==j or k==n-1-j):
... | Title: Valera and X
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a... | ```python
n=int(input())
d1=''
d2=''
l=[]
flag=1
for i in range(n):
a=input()
l.append(a)
d1+=a[i]
d2+=a[n-1-i]
s=set(list(d1))
if(d1==d2):
for j in range(n):
b=l[j]
b=list(b)
c=[]
#b=b[]
for k in range(n):
if(k==j or k==n-1-j... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
78 | B | Easter Eggs | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | B. Easter Eggs | 2 | 256 | The Easter Rabbit laid *n* eggs in a circle and is about to paint them.
Each egg should be painted one color out of 7: red, orange, yellow, green, blue, indigo or violet. Also, the following conditions should be satisfied:
- Each of the seven colors should be used to paint at least one egg. - Any four eggs lying s... | The only line contains an integer *n* — the amount of eggs (7<=≤<=*n*<=≤<=100). | Print one line consisting of *n* characters. The *i*-th character should describe the color of the *i*-th egg in the order they lie in the circle. The colors should be represented as follows: "R" stands for red, "O" stands for orange, "Y" stands for yellow, "G" stands for green, "B" stands for blue, "I" stands for indi... | [
"8\n",
"13\n"
] | [
"ROYGRBIV\n",
"ROYGBIVGBIVYG\n"
] | The way the eggs will be painted in the first sample is shown on the picture: | 1,000 | [
{
"input": "8",
"output": "ROYGBIVG"
},
{
"input": "13",
"output": "ROYGBIVOYGBIV"
},
{
"input": "7",
"output": "ROYGBIV"
},
{
"input": "10",
"output": "ROYGBIVYGB"
},
{
"input": "14",
"output": "ROYGBIVROYGBIV"
},
{
"input": "50",
"output": "ROYGB... | 1,579,603,531 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 248 | 0 | n=int(input())
c=['R','O','Y','G','B','I','V']
x=n//7
y=n%7
arr=[]
arr+=c*x
n=n-x*7
for i in range(0,n):
arr.insert(-3,c[i])
print(*arr,sep='')
| Title: Easter Eggs
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Easter Rabbit laid *n* eggs in a circle and is about to paint them.
Each egg should be painted one color out of 7: red, orange, yellow, green, blue, indigo or violet. Also, the following conditions should be satisfied:
-... | ```python
n=int(input())
c=['R','O','Y','G','B','I','V']
x=n//7
y=n%7
arr=[]
arr+=c*x
n=n-x*7
for i in range(0,n):
arr.insert(-3,c[i])
print(*arr,sep='')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
424 | B | Megacity | PROGRAMMING | 1,200 | [
"binary search",
"greedy",
"implementation",
"sortings"
] | null | null | The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding the boundaries of the city.
The city of Tomsk can be represented as point on the plane with ... | The first line of the input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=103; 1<=≤<=*s*<=<<=106) — the number of locatons around Tomsk city and the population of the city. Then *n* lines follow. The *i*-th line contains three integers — the *x**i* and *y**i* coordinate values of the *i*-th location and the numbe... | In the output, print "-1" (without the quotes), if Tomsk won't be able to become a megacity. Otherwise, in the first line print a single real number — the minimum radius of the circle that the city needs to expand to in order to become a megacity.
The answer is considered correct if the absolute or relative error don'... | [
"4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1\n",
"4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1\n",
"2 1\n1 1 999997\n2 2 1\n"
] | [
"2.8284271\n",
"1.4142136\n",
"-1"
] | none | 1,000 | [
{
"input": "4 999998\n1 1 1\n2 2 1\n3 3 1\n2 -2 1",
"output": "2.8284271"
},
{
"input": "4 999998\n1 1 2\n2 2 1\n3 3 1\n2 -2 1",
"output": "1.4142136"
},
{
"input": "2 1\n1 1 999997\n2 2 1",
"output": "-1"
},
{
"input": "4 999998\n3 3 10\n-3 3 10\n3 -3 10\n-3 -3 10",
"out... | 1,398,433,824 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 93 | 102,400 | n, k = map(int, input().split())
if k >= 1000000:
print('0')
exit(0)
def f():
x, y, d = map(int, input().split())
return (x * x + y * y, d)
t = [f() for i in range(n)]
t.sort()
for r, d in t:
k += d
if k >= 1000000:
print(r ** 0.5)
break
else: print('-1') | Title: Megacity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The administration of the Tomsk Region firmly believes that it's time to become a megacity (that is, get population of one million). Instead of improving the demographic situation, they decided to achieve its goal by expanding... | ```python
n, k = map(int, input().split())
if k >= 1000000:
print('0')
exit(0)
def f():
x, y, d = map(int, input().split())
return (x * x + y * y, d)
t = [f() for i in range(n)]
t.sort()
for r, d in t:
k += d
if k >= 1000000:
print(r ** 0.5)
break
else: print('-1')
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of members are friends. Of course, a member can't be a friend with themselves.
Let A-B denote that... | The first line of the input contain two integers *n* and *m* (3<=≤<=*n*<=≤<=150<=000, ) — the number of members and the number of pairs of members that are friends.
The *i*-th of the next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*). Members *a**i* and ... | If the given network is reasonable, print "YES" in a single line (without the quotes). Otherwise, print "NO" in a single line (without the quotes). | [
"4 3\n1 3\n3 4\n1 4\n",
"4 4\n3 1\n2 3\n3 4\n1 2\n",
"10 4\n4 3\n5 10\n8 9\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | The drawings below show the situation in the first sample (on the left) and in the second sample (on the right). Each edge represents two members that are friends. The answer is "NO" in the second sample because members (2, 3) are friends and members (3, 4) are friends, while members (2, 4) are not. | 0 | [
{
"input": "4 3\n1 3\n3 4\n1 4",
"output": "YES"
},
{
"input": "4 4\n3 1\n2 3\n3 4\n1 2",
"output": "NO"
},
{
"input": "10 4\n4 3\n5 10\n8 9\n1 2",
"output": "YES"
},
{
"input": "3 2\n1 2\n2 3",
"output": "NO"
},
{
"input": "3 0",
"output": "YES"
},
{
... | 1,697,333,681 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def is_network_reasonable(n, friendships):
# Create a set to store friendships
friend_set = set()
# Populate the set with friendships
for a, b in friendships:
friend_set.add((a, b))
friend_set.add((b, a))
for i in range(1, n + 1):
for j in range(i + 1, n + 1):
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of member... | ```python
def is_network_reasonable(n, friendships):
# Create a set to store friendships
friend_set = set()
# Populate the set with friendships
for a, b in friendships:
friend_set.add((a, b))
friend_set.add((b, a))
for i in range(1, n + 1):
for j in range(i + 1, n +... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,650,802,937 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 0 | s = input()
string = []
for l in s:
string.append(l)
comp = ["h","e","l","l","o"]
pointer = 0
for letter in string:
if pointer == 4 and letter == "o":
print("YES")
break
if comp[pointer] == letter:
pointer += 1
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = input()
string = []
for l in s:
string.append(l)
comp = ["h","e","l","l","o"]
pointer = 0
for letter in string:
if pointer == 4 and letter == "o":
print("YES")
break
if comp[pointer] == letter:
pointer += 1
else:
print("NO")
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,617,210,618 | 2,147,483,647 | Python 3 | OK | TESTS | 84 | 77 | 0 | lemon = int(input())
apple = int(input())
pear = int(input())
a, b, c = 0, 0, 0
if lemon<1 or apple<2 or pear<4:
print("0")
else:
while lemon>=1 and apple>=2 and pear>=4:
a, b, c = a+1, b+2, c+4
lemon, apple, pear = lemon-1, apple-2, pear-4
print(a+b+c) | Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
lemon = int(input())
apple = int(input())
pear = int(input())
a, b, c = 0, 0, 0
if lemon<1 or apple<2 or pear<4:
print("0")
else:
while lemon>=1 and apple>=2 and pear>=4:
a, b, c = a+1, b+2, c+4
lemon, apple, pear = lemon-1, apple-2, pear-4
print(a+b+c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
361 | A | Levko and Table | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortunately, he doesn't know any such table. Your task is to help him to find at least one of them. | The single line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). | Print any beautiful table. Levko doesn't like too big numbers, so all elements of the table mustn't exceed 1000 in their absolute value.
If there are multiple suitable tables, you are allowed to print any of them. | [
"2 4\n",
"4 7\n"
] | [
"1 3\n3 1\n",
"2 1 0 4\n4 0 2 1\n1 3 3 0\n0 3 2 2\n"
] | In the first sample the sum in the first row is 1 + 3 = 4, in the second row — 3 + 1 = 4, in the first column — 1 + 3 = 4 and in the second column — 3 + 1 = 4. There are other beautiful tables for this sample.
In the second sample the sum of elements in each row and each column equals 7. Besides, there are other table... | 500 | [
{
"input": "2 4",
"output": "4 0 \n0 4 "
},
{
"input": "4 7",
"output": "7 0 0 0 \n0 7 0 0 \n0 0 7 0 \n0 0 0 7 "
},
{
"input": "1 8",
"output": "8 "
},
{
"input": "9 3",
"output": "3 0 0 0 0 0 0 0 0 \n0 3 0 0 0 0 0 0 0 \n0 0 3 0 0 0 0 0 0 \n0 0 0 3 0 0 0 0 0 \n0 0 0 0 3 0... | 1,565,295,181 | 2,147,483,647 | Python 3 | OK | TESTS | 22 | 139 | 716,800 | a,b=input().split()
a,b=int(a),int(b)
for i in range(a):
for j in range(a):
if i==j:
print(b,end=' ')
else:
print(0,end=' ')
print('') | Title: Levko and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortun... | ```python
a,b=input().split()
a,b=int(a),int(b)
for i in range(a):
for j in range(a):
if i==j:
print(b,end=' ')
else:
print(0,end=' ')
print('')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,598,337,725 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 187 | 2,150,400 | import re
message = input()
print("YES") if re.search(r"h+e+ll+o+", message) else print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
import re
message = input()
print("YES") if re.search(r"h+e+ll+o+", message) else print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
524 | B | Фото на память - 2 (round version) | PROGRAMMING | 1,700 | [
"dp",
"greedy"
] | null | null | Прошло много лет, и на вечеринке снова встретились *n* друзей. С момента последней встречи техника шагнула далеко вперёд, появились фотоаппараты с автоспуском, и теперь не требуется, чтобы один из друзей стоял с фотоаппаратом, и, тем самым, оказывался не запечатлённым на снимке.
Упрощенно процесс фотографирования можн... | В первой строке следует целое число *n* (1<=≤<=*n*<=≤<=1000) — количество друзей.
В последующих *n* строках следуют по два целых числа *w**i*,<=*h**i* (1<=≤<=*w**i*,<=*h**i*<=≤<=1000), обозначающие размеры прямоугольника, соответствующего *i*-му из друзей. | Выведите единственное целое число, равное минимальной возможной площади фотографии, вмещающей всех друзей. | [
"3\n10 1\n20 2\n30 3\n",
"3\n3 1\n2 2\n4 3\n",
"1\n5 10\n"
] | [
"180\n",
"21\n",
"50\n"
] | none | 500 | [
{
"input": "3\n10 1\n20 2\n30 3",
"output": "180"
},
{
"input": "3\n3 1\n2 2\n4 3",
"output": "21"
},
{
"input": "1\n5 10",
"output": "50"
},
{
"input": "10\n168 538\n836 439\n190 873\n206 47\n891 591\n939 481\n399 898\n859 466\n701 777\n629 222",
"output": "3478056"
},... | 1,426,950,328 | 3,928 | PyPy 3 | WRONG_ANSWER | PRETESTS | 7 | 109 | 307,200 | n = int(input())
w = 0
h = 0
arr = []
for _ in range(n):
x, y = map(int, input().split())
arr.append((x, y))
w += x
h = max(h, y)
for i in arr:
if (w - i[0] + i[1]) * max(h, i[0]) < w * h:
w, h = (w - i[0] + i[1]), max(h, i[0])
print(w * h) | Title: Фото на память - 2 (round version)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Прошло много лет, и на вечеринке снова встретились *n* друзей. С момента последней встречи техника шагнула далеко вперёд, появились фотоаппараты с автоспуском, и теперь не требуется, чтобы один из дру... | ```python
n = int(input())
w = 0
h = 0
arr = []
for _ in range(n):
x, y = map(int, input().split())
arr.append((x, y))
w += x
h = max(h, y)
for i in arr:
if (w - i[0] + i[1]) * max(h, i[0]) < w * h:
w, h = (w - i[0] + i[1]), max(h, i[0])
print(w * h)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
515 | C | Drazil and Factorial | PROGRAMMING | 1,400 | [
"greedy",
"math",
"sortings"
] | null | null | Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they shoul... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=15) — the number of digits in *a*.
The second line contains *n* digits of *a*. There is at least one digit in *a* that is larger than 1. Number *a* may possibly contain leading zeroes. | Output a maximum possible integer satisfying the conditions above. There should be no zeroes and ones in this number decimal representation. | [
"4\n1234\n",
"3\n555\n"
] | [
"33222\n",
"555\n"
] | In the first case, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f5a4207f23215fddce977ab5ea9e9d2e7578fb52.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4\n1234",
"output": "33222"
},
{
"input": "3\n555",
"output": "555"
},
{
"input": "15\n012345781234578",
"output": "7777553333222222222222"
},
{
"input": "1\n8",
"output": "7222"
},
{
"input": "10\n1413472614",
"output": "75333332222222"
},
{
... | 1,588,776,979 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 20,172,800 | n=int(input())
a=list(input())
x=[]
for i in range(n):
a[i]=int(a[i])
for i in range(n):
if a[i]<=3:
x.append(a[i])
else:
if a[i]%2!=0:
x.append(a[i])
else:
if a[i]==4:
x.append(2)
x.append(2)
x.ap... | Title: Drazil and Factorial
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that cont... | ```python
n=int(input())
a=list(input())
x=[]
for i in range(n):
a[i]=int(a[i])
for i in range(n):
if a[i]<=3:
x.append(a[i])
else:
if a[i]%2!=0:
x.append(a[i])
else:
if a[i]==4:
x.append(2)
x.append(2)
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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