contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
229 | B | Planets | PROGRAMMING | 1,700 | [
"binary search",
"data structures",
"graphs",
"shortest paths"
] | null | null | Goa'uld Apophis captured Jack O'Neill's team again! Jack himself was able to escape, but by that time Apophis's ship had already jumped to hyperspace. But Jack knows on what planet will Apophis land. In order to save his friends, Jack must repeatedly go through stargates to get to this planet.
Overall the galaxy has *... | The first line contains two space-separated integers: *n* (2<=≤<=*n*<=≤<=105), the number of planets in the galaxy, and *m* (0<=≤<=*m*<=≤<=105) — the number of pairs of planets between which Jack can travel using stargates. Then *m* lines follow, containing three integers each: the *i*-th line contains numbers of plane... | Print a single number — the least amount of time Jack needs to get from planet 1 to planet *n*. If Jack can't get to planet *n* in any amount of time, print number -1. | [
"4 6\n1 2 2\n1 3 3\n1 4 8\n2 3 4\n2 4 5\n3 4 3\n0\n1 3\n2 3 4\n0\n",
"3 1\n1 2 3\n0\n1 3\n0\n"
] | [
"7\n",
"-1\n"
] | In the first sample Jack has three ways to go from planet 1. If he moves to planet 4 at once, he spends 8 seconds. If he transfers to planet 3, he spends 3 seconds, but as other travellers arrive to planet 3 at time 3 and 4, he can travel to planet 4 only at time 5, thus spending 8 seconds in total. But if Jack moves t... | 500 | [
{
"input": "4 6\n1 2 2\n1 3 3\n1 4 8\n2 3 4\n2 4 5\n3 4 3\n0\n1 3\n2 3 4\n0",
"output": "7"
},
{
"input": "3 1\n1 2 3\n0\n1 3\n0",
"output": "-1"
},
{
"input": "2 1\n1 2 3\n0\n1 3",
"output": "3"
},
{
"input": "2 1\n1 2 3\n1 0\n0",
"output": "4"
},
{
"input": "3 3... | 1,654,780,804 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 154 | 409,600 | def inlt():
return(list(map(int,input().split())))
import sys
from collections import defaultdict
from math import sqrt, ceil,floor,factorial,log
from bisect import bisect_left , bisect_right
from io import BytesIO, IOBase, StringIO
MYPC = False
if MYPC :
sys.stdin = open('in.txt' , 'r')
sys.std... | Title: Planets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Goa'uld Apophis captured Jack O'Neill's team again! Jack himself was able to escape, but by that time Apophis's ship had already jumped to hyperspace. But Jack knows on what planet will Apophis land. In order to save his friend... | ```python
def inlt():
return(list(map(int,input().split())))
import sys
from collections import defaultdict
from math import sqrt, ceil,floor,factorial,log
from bisect import bisect_left , bisect_right
from io import BytesIO, IOBase, StringIO
MYPC = False
if MYPC :
sys.stdin = open('in.txt' , 'r')
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,671,086,546 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 93 | 7,372,800 | n = int(input())
l = list(map(int, input().split()))
s = set([])
for i in l:
if i != 0:
s.add(i)
print(len(s)) | Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
n = int(input())
l = list(map(int, input().split()))
s = set([])
for i in l:
if i != 0:
s.add(i)
print(len(s))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
714 | A | Meeting of Old Friends | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to ... | The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks. | Print one integer — the number of minutes Sonya and Filya will be able to spend together. | [
"1 10 9 20 1\n",
"1 100 50 200 75\n"
] | [
"2\n",
"50\n"
] | In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100. | 500 | [
{
"input": "1 10 9 20 1",
"output": "2"
},
{
"input": "1 100 50 200 75",
"output": "50"
},
{
"input": "6 6 5 8 9",
"output": "1"
},
{
"input": "1 1000000000 1 1000000000 1",
"output": "999999999"
},
{
"input": "5 100 8 8 8",
"output": "0"
},
{
"input":... | 1,539,283,661 | 460 | PyPy 3 | OK | TESTS | 96 | 140 | 0 | l1,r1,l2,r2,k=map(int,input().split())
if l2<l1:
if r2<l1:
print(0)
else:
if r2<r1:
start=l1
end=r2
else:
start=l1
end=r1
if k>=start and k<=end:
print(end-start)
else:
print(end-start... | Title: Meeting of Old Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusi... | ```python
l1,r1,l2,r2,k=map(int,input().split())
if l2<l1:
if r2<l1:
print(0)
else:
if r2<r1:
start=l1
end=r2
else:
start=l1
end=r1
if k>=start and k<=end:
print(end-start)
else:
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
757 | B | Bash's Big Day | PROGRAMMING | 1,400 | [
"greedy",
"math",
"number theory"
] | null | null | Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon from his lab as he pleases.
But Zulu warns him that a group of *k*<=><=1 Pokemon with strengths {*... | The input consists of two lines.
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105), the number of Pokemon in the lab.
The next line contains *n* space separated integers, where the *i*-th of them denotes *s**i* (1<=≤<=*s**i*<=≤<=105), the strength of the *i*-th Pokemon. | Print single integer — the maximum number of Pokemons Bash can take. | [
"3\n2 3 4\n",
"5\n2 3 4 6 7\n"
] | [
"2\n",
"3\n"
] | *gcd* (greatest common divisor) of positive integers set {*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub>} is the maximum positive integer that divides all the integers {*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a... | 1,000 | [
{
"input": "3\n2 3 4",
"output": "2"
},
{
"input": "5\n2 3 4 6 7",
"output": "3"
},
{
"input": "3\n5 6 4",
"output": "2"
},
{
"input": "8\n41 74 4 27 85 39 100 36",
"output": "4"
},
{
"input": "6\n89 20 86 81 62 23",
"output": "3"
},
{
"input": "71\n23... | 1,484,299,306 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 77 | 5,120,000 | from collections import Counter
def primes1(n):
""" Returns a list of primes < n """
sieve = [True] * (n//2)
for i in range(3,int(n**0.5)+1,2):
if sieve[i//2]:
sieve[i*i//2::i] = [False] * ((n-i*i-1)//(2*i)+1)
return [2] + [2*i+1 for i in range(1,n//2) if sieve[i]]
def factors(n... | Title: Bash's Big Day
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bash has set out on a journey to become the greatest Pokemon master. To get his first Pokemon, he went to Professor Zulu's Lab. Since Bash is Professor Zulu's favourite student, Zulu allows him to take as many Pokemon fr... | ```python
from collections import Counter
def primes1(n):
""" Returns a list of primes < n """
sieve = [True] * (n//2)
for i in range(3,int(n**0.5)+1,2):
if sieve[i//2]:
sieve[i*i//2::i] = [False] * ((n-i*i-1)//(2*i)+1)
return [2] + [2*i+1 for i in range(1,n//2) if sieve[i]]
def... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
180 | E | Cubes | PROGRAMMING | 1,800 | [
"binary search",
"dp",
"two pointers"
] | null | null | Let's imagine that you're playing the following simple computer game. The screen displays *n* lined-up cubes. Each cube is painted one of *m* colors. You are allowed to delete not more than *k* cubes (that do not necessarily go one after another). After that, the remaining cubes join together (so that the gaps are clos... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=2·105,<=1<=≤<=*m*<=≤<=105,<=0<=≤<=*k*<=<<=*n*). The second line contains *n* integers from 1 to *m* — the numbers of cube colors. The numbers of colors are separated by single spaces. | Print the maximum possible number of points you can score. | [
"10 3 2\n1 2 1 1 3 2 1 1 2 2\n",
"10 2 2\n1 2 1 2 1 1 2 1 1 2\n",
"3 1 2\n1 1 1\n"
] | [
"4\n",
"5\n",
"3\n"
] | In the first sample you should delete the fifth and the sixth cubes.
In the second sample you should delete the fourth and the seventh cubes.
In the third sample you shouldn't delete any cubes. | 0 | [
{
"input": "10 3 2\n1 2 1 1 3 2 1 1 2 2",
"output": "4"
},
{
"input": "10 2 2\n1 2 1 2 1 1 2 1 1 2",
"output": "5"
},
{
"input": "3 1 2\n1 1 1",
"output": "3"
},
{
"input": "10 2 2\n1 1 1 2 1 2 1 2 1 1",
"output": "5"
},
{
"input": "1 1 0\n1",
"output": "1"
... | 1,596,767,637 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 342 | 20,275,200 | n,m,k = map(int,input().split())
a = list(map(int,input().split()))
from collections import defaultdict
mp = defaultdict(list)
for i in range(n):
mp[a[i]].append(i)
res = 0
for i in range(n):
val = a[i]
st = 0
tmp = 0
ll =0
rr = len(mp[val])-1
while rr-ll>=0:
m = rr+ll>... | Title: Cubes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's imagine that you're playing the following simple computer game. The screen displays *n* lined-up cubes. Each cube is painted one of *m* colors. You are allowed to delete not more than *k* cubes (that do not necessarily go o... | ```python
n,m,k = map(int,input().split())
a = list(map(int,input().split()))
from collections import defaultdict
mp = defaultdict(list)
for i in range(n):
mp[a[i]].append(i)
res = 0
for i in range(n):
val = a[i]
st = 0
tmp = 0
ll =0
rr = len(mp[val])-1
while rr-ll>=0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
961 | B | Lecture Sleep | PROGRAMMING | 1,200 | [
"data structures",
"dp",
"implementation",
"two pointers"
] | null | null | Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for all the time of lecture. You are given an array *t* of Mishka's behavior. If Mishka is asleep during ... | The first line of the input contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105) — the duration of the lecture in minutes and the number of minutes you can keep Mishka awake.
The second line of the input contains *n* integer numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=104) — the number of theore... | Print only one integer — the maximum number of theorems Mishka will be able to write down if you use your technique only once to wake him up. | [
"6 3\n1 3 5 2 5 4\n1 1 0 1 0 0\n"
] | [
"16\n"
] | In the sample case the better way is to use the secret technique at the beginning of the third minute. Then the number of theorems Mishka will be able to write down will be equal to 16. | 0 | [
{
"input": "6 3\n1 3 5 2 5 4\n1 1 0 1 0 0",
"output": "16"
},
{
"input": "5 3\n1 9999 10000 10000 10000\n0 0 0 0 0",
"output": "30000"
},
{
"input": "3 3\n10 10 10\n1 1 0",
"output": "30"
},
{
"input": "1 1\n423\n0",
"output": "423"
},
{
"input": "6 6\n1 3 5 2 5 4... | 1,600,389,535 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 108 | 0 | n, k = input().split()
n, k = int(n), int(k)
a = list(map(int, input().split()))
t = list(map(int, input().split()))
somaAll = [0 for i in range(n+1)]
somaF = [0 for i in range(n+1)]
for i in range(1, n+1):
somaAll[i] = somaAll[i-1] + a[i-1]
somaF[i] = somaF[i-1] if t[i-1] == 0 else somaF[i-1] + a[i-1]
"""... | Title: Lecture Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for al... | ```python
n, k = input().split()
n, k = int(n), int(k)
a = list(map(int, input().split()))
t = list(map(int, input().split()))
somaAll = [0 for i in range(n+1)]
somaF = [0 for i in range(n+1)]
for i in range(1, n+1):
somaAll[i] = somaAll[i-1] + a[i-1]
somaF[i] = somaF[i-1] if t[i-1] == 0 else somaF[i-1] + a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
888 | B | Buggy Robot | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — mo... | The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R. | Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell. | [
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] | [
"4\n",
"0\n",
"4\n"
] | none | 0 | [
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDL... | 1,582,822,318 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 307,200 | from sys import stdin, stdout
n = int(stdin.readline().strip())
ls = stdin.readline().strip()
ans = 0
pos = [0, 0]
dydx = {
"L": [-1, 0],
"D": [0, 1],
"U": [0, -1],
"R": [1, 0],
}
count = 0
for l in ls:
count += 1
pos[0] += dydx[l][0]
pos[1] += dydx[l][0]
if pos[0] == 0... | Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the ce... | ```python
from sys import stdin, stdout
n = int(stdin.readline().strip())
ls = stdin.readline().strip()
ans = 0
pos = [0, 0]
dydx = {
"L": [-1, 0],
"D": [0, 1],
"U": [0, -1],
"R": [1, 0],
}
count = 0
for l in ls:
count += 1
pos[0] += dydx[l][0]
pos[1] += dydx[l][0]
if p... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,639,540,351 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 46 | 0 | #!/usr/bin/env python
import math, sys, itertools
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
d1,d2,d3 = map(int, wtf[0].split())
print(min(d1+d2+d3, 2*d1 + 2*d2, 2*d1 + 2*d3, 2*d2 + 2*d3)) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
#!/usr/bin/env python
import math, sys, itertools
if __name__ == '__main__':
wtf = sys.stdin.read()
wtf = wtf.strip().split('\n')
d1,d2,d3 = map(int, wtf[0].split())
print(min(d1+d2+d3, 2*d1 + 2*d2, 2*d1 + 2*d3, 2*d2 + 2*d3))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,690,641,947 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 716,800 | import fileinput
inputLine = []
for line in fileinput.input():
inputLine.append(line)
if inputLine[0]%2 == 0:
print("YES")
else:
print("NO")
| Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
import fileinput
inputLine = []
for line in fileinput.input():
inputLine.append(line)
if inputLine[0]%2 == 0:
print("YES")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,599,068,265 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import math
a=list(map(int,input().split()))
ui=a[0]
u=0
if(type(math.log(a[0],10))==int and type(math.log(a[1],10))==int):
yu=''
for i in range(a[2]):
if(i==0):
yu=yu+str(a[0])
else:
yu=yu+str(a[1])
print(yu)
else:
for j in range(1,a[2]+1):
... | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
import math
a=list(map(int,input().split()))
ui=a[0]
u=0
if(type(math.log(a[0],10))==int and type(math.log(a[1],10))==int):
yu=''
for i in range(a[2]):
if(i==0):
yu=yu+str(a[0])
else:
yu=yu+str(a[1])
print(yu)
else:
for j in range(1... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,551,135,391 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 124 | 0 | n,p,q= map(int,input().split())
word = input()
def estcomb(n , p , q):
l = n//p
for i in range (0,l):
k=i*p
a=i
j=0
while (k<n):
k+=q
j+=1
if ( k==n):
return( 1 , a , j)
return (0 , a , j)
c,i,j= estcomb(n,p,q)
d=... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n,p,q= map(int,input().split())
word = input()
def estcomb(n , p , q):
l = n//p
for i in range (0,l):
k=i*p
a=i
j=0
while (k<n):
k+=q
j+=1
if ( k==n):
return( 1 , a , j)
return (0 , a , j)
c,i,j= estcomb(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,617,814,932 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 248 | 8,192,000 | from sys import stdin
from bisect import bisect_right as br
input = stdin.readline
n = int(input())
lst = list(map(int, input().strip().split()))
arr = sorted(lst)
ind = br(arr, arr[0]) - 1
if ind == 0:
print(lst.index(arr[0]) + 1)
else:
print('Still Rozdil')
| Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
from sys import stdin
from bisect import bisect_right as br
input = stdin.readline
n = int(input())
lst = list(map(int, input().strip().split()))
arr = sorted(lst)
ind = br(arr, arr[0]) - 1
if ind == 0:
print(lst.index(arr[0]) + 1)
else:
print('Still Rozdil')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of t... | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell ... | Print one integer — the number of good positions for placing the spotlight. | [
"2 4\n0 1 0 0\n1 0 1 0\n",
"4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n"
] | [
"9\n",
"20\n"
] | In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and... | 0 | [
{
"input": "2 4\n0 1 0 0\n1 0 1 0",
"output": "9"
},
{
"input": "4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0",
"output": "20"
},
{
"input": "1 5\n1 1 0 0 0",
"output": "3"
},
{
"input": "2 10\n0 0 0 0 0 0 0 1 0 0\n1 0 0 0 0 0 0 0 0 0",
"output": "20"
},
{
"input": "3 ... | 1,479,637,075 | 4,375 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 6 | 1,000 | 10,752,000 | s=input().split(" ")
m=int(s[1])
n=int(s[0])
A=[]
C=[]
for i in range(n):
B=input().split(" ")
A.append(B)
A1=[]
for i in range(n):
B1=[]
for j in range(m):
B1.append(0)
A1.append(B1)
ans=0
for i in range(n):
for j in range(m):
if A[i][j]=='1':
ic=i+... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a ... | ```python
s=input().split(" ")
m=int(s[1])
n=int(s[0])
A=[]
C=[]
for i in range(n):
B=input().split(" ")
A.append(B)
A1=[]
for i in range(n):
B1=[]
for j in range(m):
B1.append(0)
A1.append(B1)
ans=0
for i in range(n):
for j in range(m):
if A[i][j]=='1':
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the numb... | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,670,665,435 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 873 | 9,625,600 | s = int(input())
cnt = 0
for _ in range(s):
a, b = list(map(int, input().split()))
if a == b:
cnt += 1
else:
continue
if cnt < s:
print('Happy Alex')
else:
print('Poor Alex') | Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the... | ```python
s = int(input())
cnt = 0
for _ in range(s):
a, b = list(map(int, input().split()))
if a == b:
cnt += 1
else:
continue
if cnt < s:
print('Happy Alex')
else:
print('Poor Alex')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
313 | A | Ilya and Bank Account | PROGRAMMING | 900 | [
"implementation",
"number theory"
] | null | null | Ilya is a very clever lion, he lives in an unusual city ZooVille. In this city all the animals have their rights and obligations. Moreover, they even have their own bank accounts. The state of a bank account is an integer. The state of a bank account can be a negative number. This means that the owner of the account ow... | The single line contains integer *n* (10<=≤<=|*n*|<=≤<=109) — the state of Ilya's bank account. | In a single line print an integer — the maximum state of the bank account that Ilya can get. | [
"2230\n",
"-10\n",
"-100003\n"
] | [
"2230\n",
"0\n",
"-10000\n"
] | In the first test sample Ilya doesn't profit from using the present.
In the second test sample you can delete digit 1 and get the state of the account equal to 0. | 500 | [
{
"input": "2230",
"output": "2230"
},
{
"input": "-10",
"output": "0"
},
{
"input": "-100003",
"output": "-10000"
},
{
"input": "544883178",
"output": "544883178"
},
{
"input": "-847251738",
"output": "-84725173"
},
{
"input": "423654797",
"output... | 1,689,863,628 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | def maximize_bank_account(n):
account = str(n)
max_balance = max(int(account[:-1]), int(account[:-2] + account[-1]))
return max_balance
if __name__ == "__main__":
n = int(input())
result = maximize_bank_account(n)
print(result)
| Title: Ilya and Bank Account
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya is a very clever lion, he lives in an unusual city ZooVille. In this city all the animals have their rights and obligations. Moreover, they even have their own bank accounts. The state of a bank account is an... | ```python
def maximize_bank_account(n):
account = str(n)
max_balance = max(int(account[:-1]), int(account[:-2] + account[-1]))
return max_balance
if __name__ == "__main__":
n = int(input())
result = maximize_bank_account(n)
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,678,348,548 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | s= input()
t= input()
f= s[::-1]
if f==t:
print('YES')
else:
print('NO')
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s= input()
t= input()
f= s[::-1]
if f==t:
print('YES')
else:
print('NO')
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
573 | A | Bear and Poker | PROGRAMMING | 1,300 | [
"implementation",
"math",
"number theory"
] | null | null | Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid with size *a**i* dollars.
Each player can double his bid any number of times and triple his bid any nu... | First line of input contains an integer *n* (2<=≤<=*n*<=≤<=105), the number of players.
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the bids of players. | Print "Yes" (without the quotes) if players can make their bids become equal, or "No" otherwise. | [
"4\n75 150 75 50\n",
"3\n100 150 250\n"
] | [
"Yes\n",
"No\n"
] | In the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid.
It can be shown that in the second sample test there is no way to make all bids equal. | 500 | [
{
"input": "4\n75 150 75 50",
"output": "Yes"
},
{
"input": "3\n100 150 250",
"output": "No"
},
{
"input": "7\n34 34 68 34 34 68 34",
"output": "Yes"
},
{
"input": "10\n72 96 12 18 81 20 6 2 54 1",
"output": "No"
},
{
"input": "20\n958692492 954966768 77387000 724... | 1,481,031,672 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 546 | 9,011,200 | import sys
n = int(input())
a = list(map(int, sys.stdin.readline().split()))
def pgcd(a,b):
while b:
a,b = b,a%b
return a
def test2and3(n):
while n%2 == 0:
n = n//2
while n%3 == 0:
n = n//3
return n
p = a[0]
for ai in a[1:]:
p = pgcd(p,ai)
for ai in a:
if test2and3(ai//p) > 1:
print('No... | Title: Bear and Poker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid wit... | ```python
import sys
n = int(input())
a = list(map(int, sys.stdin.readline().split()))
def pgcd(a,b):
while b:
a,b = b,a%b
return a
def test2and3(n):
while n%2 == 0:
n = n//2
while n%3 == 0:
n = n//3
return n
p = a[0]
for ai in a[1:]:
p = pgcd(p,ai)
for ai in a:
if test2and3(ai//p) > 1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,676,974,216 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 109 | 307,200 | t=input().split()
s=list(input())
k=0
for i in s:
k+=int(t[int(i)-1])
print(k) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
t=input().split()
s=list(input())
k=0
for i in s:
k+=int(t[int(i)-1])
print(k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,673,352,375 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | def max_dominoes(M: int, N: int) -> int:
squares = M * N
if (M*N) % 2 == 0:
return squares // 2
else:
return (squares // 2) + (min(M, N) % 2)
if __name__ == '__main__':
m, n = map(int, input("Enter the size of the board (M N): ").split())
result = max_dominoes(m, n)
... | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
def max_dominoes(M: int, N: int) -> int:
squares = M * N
if (M*N) % 2 == 0:
return squares // 2
else:
return (squares // 2) + (min(M, N) % 2)
if __name__ == '__main__':
m, n = map(int, input("Enter the size of the board (M N): ").split())
result = max_dominoes(m... | 0 | MatrixStudio/Codeforces-Python-Submissions |
373 | A | Collecting Beats is Fun | PROGRAMMING | 900 | [
"implementation"
] | null | null | Cucumber boy is fan of Kyubeat, a famous music game.
Kyubeat has 16 panels for playing arranged in 4<=×<=4 table. When a panel lights up, he has to press that panel.
Each panel has a timing to press (the preffered time when a player should press it), and Cucumber boy is able to press at most *k* panels in a time with... | The first line contains a single integer *k* (1<=≤<=*k*<=≤<=5) — the number of panels Cucumber boy can press with his one hand.
Next 4 lines contain 4 characters each (digits from 1 to 9, or period) — table of panels. If a digit *i* was written on the panel, it means the boy has to press that panel in time *i*. If per... | Output "YES" (without quotes), if he is able to press all the panels in perfect timing. If not, output "NO" (without quotes). | [
"1\n.135\n1247\n3468\n5789\n",
"5\n..1.\n1111\n..1.\n..1.\n",
"1\n....\n12.1\n.2..\n.2..\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the third sample boy cannot press all panels in perfect timing. He can press all the panels in timing in time 1, but he cannot press the panels in time 2 in timing with his two hands. | 500 | [
{
"input": "1\n.135\n1247\n3468\n5789",
"output": "YES"
},
{
"input": "5\n..1.\n1111\n..1.\n..1.",
"output": "YES"
},
{
"input": "1\n....\n12.1\n.2..\n.2..",
"output": "NO"
},
{
"input": "1\n6981\n.527\n4163\n2345",
"output": "YES"
},
{
"input": "5\n9999\n9999\n99... | 1,680,224,470 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 46 | 0 | n = int(input())
panel = []
ans = "YES"
for i in range(0,4):
s = input()
arr = [ch for ch in s if ch != "."]
panel += arr
for i in range(1,int(max(panel))+1):
if panel.count(str(i)) > 2*n:
ans = "NO"
break
print(ans) | Title: Collecting Beats is Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Cucumber boy is fan of Kyubeat, a famous music game.
Kyubeat has 16 panels for playing arranged in 4<=×<=4 table. When a panel lights up, he has to press that panel.
Each panel has a timing to press (the preff... | ```python
n = int(input())
panel = []
ans = "YES"
for i in range(0,4):
s = input()
arr = [ch for ch in s if ch != "."]
panel += arr
for i in range(1,int(max(panel))+1):
if panel.count(str(i)) > 2*n:
ans = "NO"
break
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,651,972,390 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 92 | 0 | def remove0(s):
res = ""
for ch in s:
if ch != "0":
res += ch
return res
if __name__ == '__main__':
a = int(input())
b = int(input())
c = a + b
newA, newB, newC = remove0(str(a)), remove0(str(b)), remove0(str(c))
if int(newA) + int(newB) == int(newC):
... | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
def remove0(s):
res = ""
for ch in s:
if ch != "0":
res += ch
return res
if __name__ == '__main__':
a = int(input())
b = int(input())
c = a + b
newA, newB, newC = remove0(str(a)), remove0(str(b)), remove0(str(c))
if int(newA) + int(newB) == int(ne... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
960 | B | Minimize the error | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one operation, you have to choose one element of the array and increase or decrease it by 1.
Output the min... | The first line contains three space-separated integers *n* (1<=≤<=*n*<=≤<=103), *k*1 and *k*2 (0<=≤<=*k*1<=+<=*k*2<=≤<=103, *k*1 and *k*2 are non-negative) — size of arrays and number of operations to perform on *A* and *B* respectively.
Second line contains *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (<=-... | Output a single integer — the minimum possible value of after doing exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. | [
"2 0 0\n1 2\n2 3\n",
"2 1 0\n1 2\n2 2\n",
"2 5 7\n3 4\n14 4\n"
] | [
"2",
"0",
"1"
] | In the first sample case, we cannot perform any operations on *A* or *B*. Therefore the minimum possible error *E* = (1 - 2)<sup class="upper-index">2</sup> + (2 - 3)<sup class="upper-index">2</sup> = 2.
In the second sample case, we are required to perform exactly one operation on *A*. In order to minimize error, we... | 1,000 | [
{
"input": "2 0 0\n1 2\n2 3",
"output": "2"
},
{
"input": "2 1 0\n1 2\n2 2",
"output": "0"
},
{
"input": "2 5 7\n3 4\n14 4",
"output": "1"
},
{
"input": "2 0 1\n1 2\n2 2",
"output": "0"
},
{
"input": "2 1 1\n0 0\n1 1",
"output": "0"
},
{
"input": "5 5 ... | 1,601,487,383 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 124 | 0 | n,c1,c2=[int(n) for n in input().split()]
arr=[int(item) for item in input().split()]
brr=[int(item) for item in input().split()]
c=c1+c2
count=0
for i in range(n):
if(i!=n-1):
a=arr[i]
b=brr[i]
d=abs(a-b)
if(d<=c):
c=c-d
else:
count=count... | Title: Minimize the error
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one ... | ```python
n,c1,c2=[int(n) for n in input().split()]
arr=[int(item) for item in input().split()]
brr=[int(item) for item in input().split()]
c=c1+c2
count=0
for i in range(n):
if(i!=n-1):
a=arr[i]
b=brr[i]
d=abs(a-b)
if(d<=c):
c=c-d
else:
c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,447,153,502 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 62 | 204,800 | data=input().strip().split()
mas=[]
col=0
for i in range(int(data[0])):
mas.append(input().strip().split())
for j in range(1,len(mas[i]),2):
if mas[i][j]=="1" or mas[i][j-1]=="1":
col+=1
print(col) | Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
data=input().strip().split()
mas=[]
col=0
for i in range(int(data[0])):
mas.append(input().strip().split())
for j in range(1,len(mas[i]),2):
if mas[i][j]=="1" or mas[i][j-1]=="1":
col+=1
print(col)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
520 | B | Two Buttons | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs",
"greedy",
"implementation",
"math",
"shortest paths"
] | null | null | Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by two. After clicking the blue button, device subtracts one from the number on the display. If at so... | The first and the only line of the input contains two distinct integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=104), separated by a space . | Print a single number — the minimum number of times one needs to push the button required to get the number *m* out of number *n*. | [
"4 6\n",
"10 1\n"
] | [
"2\n",
"9\n"
] | In the first example you need to push the blue button once, and then push the red button once.
In the second example, doubling the number is unnecessary, so we need to push the blue button nine times. | 1,000 | [
{
"input": "4 6",
"output": "2"
},
{
"input": "10 1",
"output": "9"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "2 10",
"outpu... | 1,693,833,074 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 46 | 614,400 | from collections import deque
n, m = map(int, input().split())
def min_button_clicks(n, m):
visited = [False] * 10001 # Assuming a maximum value of 10,000
queue = deque([(n, 0)]) # (number, clicks)
while queue:
current, clicks = queue.popleft()
if current == m:
... | Title: Two Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by t... | ```python
from collections import deque
n, m = map(int, input().split())
def min_button_clicks(n, m):
visited = [False] * 10001 # Assuming a maximum value of 10,000
queue = deque([(n, 0)]) # (number, clicks)
while queue:
current, clicks = queue.popleft()
if current == m:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
821 | A | Okabe and Future Gadget Laboratory | PROGRAMMING | 800 | [
"implementation"
] | null | null | Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in which every number not equal to 1 can be expressed as the sum of a number in the same row and a number in the same column. ... | The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=50) — the size of the lab.
The next *n* lines contain *n* space-separated integers denoting a row of the grid. The *j*-th integer in the *i*-th row is *a**i*,<=*j* (1<=≤<=*a**i*,<=*j*<=≤<=105). | Print "Yes" if the given lab is good and "No" otherwise.
You can output each letter in upper or lower case. | [
"3\n1 1 2\n2 3 1\n6 4 1\n",
"3\n1 5 2\n1 1 1\n1 2 3\n"
] | [
"Yes\n",
"No\n"
] | In the first sample test, the 6 in the bottom left corner is valid because it is the sum of the 2 above it and the 4 on the right. The same holds for every number not equal to 1 in this table, so the answer is "Yes".
In the second sample test, the 5 cannot be formed as the sum of an integer in the same row and an inte... | 500 | [
{
"input": "3\n1 1 2\n2 3 1\n6 4 1",
"output": "Yes"
},
{
"input": "3\n1 5 2\n1 1 1\n1 2 3",
"output": "No"
},
{
"input": "1\n1",
"output": "Yes"
},
{
"input": "4\n1 1 1 1\n1 11 1 2\n2 5 1 4\n3 9 4 1",
"output": "Yes"
},
{
"input": "4\n1 1 1 1\n1 7 1 1\n1 3 1 2\n2... | 1,502,817,583 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 62 | 4,608,000 | n=int(input())
a=[list(map(int, input().split())) for i in range(n)]
#print(a)
for i in range(n):
for j in range(n):
val=0
if(a[i][j]==1):
continue
for k in range(n):
for l in range(n):
if(a[i][j]==a[i][k]+a[l][j]):
val=1... | Title: Okabe and Future Gadget Laboratory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Okabe needs to renovate the Future Gadget Laboratory after he tried doing some crazy experiments! The lab is represented as an *n* by *n* square grid of integers. A good lab is defined as a lab in whi... | ```python
n=int(input())
a=[list(map(int, input().split())) for i in range(n)]
#print(a)
for i in range(n):
for j in range(n):
val=0
if(a[i][j]==1):
continue
for k in range(n):
for l in range(n):
if(a[i][j]==a[i][k]+a[l][j]):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
952 | A | Quirky Quantifiers | PROGRAMMING | 800 | [
"math"
] | null | null | The input contains a single integer *a* (10<=≤<=*a*<=≤<=999).
Output 0 or 1. | The input contains a single integer *a* (10<=≤<=*a*<=≤<=999). | Output 0 or 1. | [
"13\n",
"927\n",
"48\n"
] | [
"1\n",
"1\n",
"0\n"
] | none | 0 | [
{
"input": "13",
"output": "1"
},
{
"input": "927",
"output": "1"
},
{
"input": "48",
"output": "0"
},
{
"input": "10",
"output": "0"
},
{
"input": "999",
"output": "1"
},
{
"input": "142",
"output": "0"
},
{
"input": "309",
"output": "... | 1,628,757,778 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | t = int(input())
s = input()
n, k = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
for _ in range(t):
s = input()
n = int(input())
n, k = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]] | Title: Quirky Quantifiers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (10<=≤<=*a*<=≤<=999).
Output 0 or 1.
Input Specification:
The input contains a single integer *a* (10<=≤<=*a*<=≤<=999).
Output Specification:
Output 0 or 1.
Demo Input:
['1... | ```python
t = int(input())
s = input()
n, k = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
for _ in range(t):
s = input()
n = int(input())
n, k = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]]
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
859 | B | Lazy Security Guard | PROGRAMMING | 1,000 | [
"brute force",
"geometry",
"math"
] | null | null | Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is, your friend must walk the perimeter of a region whose area is exactly *N* blocks. Your friend is quite ... | Input will consist of a single integer *N* (1<=≤<=*N*<=≤<=106), the number of city blocks that must be enclosed by the route. | Print the minimum perimeter that can be achieved. | [
"4\n",
"11\n",
"22\n"
] | [
"8\n",
"14\n",
"20\n"
] | Here are some possible shapes for the examples:
<img class="tex-graphics" src="https://espresso.codeforces.com/e11bef2cf82b55dd583cfc97d12b5aee5e483a65.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 750 | [
{
"input": "4",
"output": "8"
},
{
"input": "11",
"output": "14"
},
{
"input": "22",
"output": "20"
},
{
"input": "3",
"output": "8"
},
{
"input": "1024",
"output": "128"
},
{
"input": "101",
"output": "42"
},
{
"input": "30",
"output":... | 1,505,749,916 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 61 | 4,608,000 | from math import *
N = int(input())
print(2*ceil(2*sqrt(N))) | Title: Lazy Security Guard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is... | ```python
from math import *
N = int(input())
print(2*ceil(2*sqrt(N)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
486 | B | OR in Matrix | PROGRAMMING | 1,300 | [
"greedy",
"hashing",
"implementation"
] | null | null | Let's define logical *OR* as an operation on two logical values (i. e. values that belong to the set {0,<=1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical *OR* of three or more logical values in the same manner:
where is equal to 1 if some *a**i*<==... | The first line contains two integer *m* and *n* (1<=≤<=*m*,<=*n*<=≤<=100), number of rows and number of columns of matrices respectively.
The next *m* lines each contain *n* integers separated by spaces describing rows of matrix *B* (each element of *B* is either 0 or 1). | In the first line, print "NO" if Nam has made a mistake when calculating *B*, otherwise print "YES". If the first line is "YES", then also print *m* rows consisting of *n* integers representing matrix *A* that can produce given matrix *B*. If there are several solutions print any one. | [
"2 2\n1 0\n0 0\n",
"2 3\n1 1 1\n1 1 1\n",
"2 3\n0 1 0\n1 1 1\n"
] | [
"NO\n",
"YES\n1 1 1\n1 1 1\n",
"YES\n0 0 0\n0 1 0\n"
] | none | 1,000 | [
{
"input": "2 2\n1 0\n0 0",
"output": "NO"
},
{
"input": "2 3\n1 1 1\n1 1 1",
"output": "YES\n1 1 1\n1 1 1"
},
{
"input": "2 3\n0 1 0\n1 1 1",
"output": "YES\n0 0 0\n0 1 0"
},
{
"input": "5 5\n1 1 1 1 1\n1 0 0 0 0\n1 0 0 0 0\n1 0 0 0 0\n1 0 0 0 0",
"output": "YES\n1 0 0 0... | 1,697,113,031 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 155 | 614,400 | x = []
xx = []
r, c = map(int, input().split())
ans = [[1]*c] * r
for _ in range(r):
a = list(map(int, input().split()))
xx.extend(a)
x.append(a)
f = True
for R in range(r):
for C in range(c):
if x[R][C] == 0:
f = False
v = [0] * c
ans[R] = v
... | Title: OR in Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's define logical *OR* as an operation on two logical values (i. e. values that belong to the set {0,<=1}) that is equal to 1 if either or both of the logical values is set to 1, otherwise it is 0. We can define logical... | ```python
x = []
xx = []
r, c = map(int, input().split())
ans = [[1]*c] * r
for _ in range(r):
a = list(map(int, input().split()))
xx.extend(a)
x.append(a)
f = True
for R in range(r):
for C in range(c):
if x[R][C] == 0:
f = False
v = [0] * c
ans[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many w... | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,680,798,254 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 2,048,000 | a=int(input())
b=int(input())
wins_a = 0
draws = 0
wins_b = 0
for i in range(1, 7):
diff_a = abs(a - i)
diff_b = abs(b - i)
if diff_a == diff_b:
draws += 1
elif diff_a < diff_b:
wins_a += 1
else:
wins_b += 1
print(wins_a,end=' ')
print(draws,end=' ')
print(wins_b,end=' ')
... | Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same diff... | ```python
a=int(input())
b=int(input())
wins_a = 0
draws = 0
wins_b = 0
for i in range(1, 7):
diff_a = abs(a - i)
diff_b = abs(b - i)
if diff_a == diff_b:
draws += 1
elif diff_a < diff_b:
wins_a += 1
else:
wins_b += 1
print(wins_a,end=' ')
print(draws,end=' ')
print(wins_b,... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,625,727,467 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 216 | 0 | a = input(); a = a.split(" "); x = int(a[0]); y = int(a[1]); print((x*y)//2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
a = input(); a = a.split(" "); x = int(a[0]); y = int(a[1]); print((x*y)//2)
``` | 3.946 | MatrixStudio/Codeforces-Python-Submissions |
710 | A | King Moves | PROGRAMMING | 800 | [
"implementation"
] | null | null | The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check the king's moves here [https://en.wikipedia.org/wiki/King_(chess)](https://en.wikipedia.org/wik... | The only line contains the king's position in the format "cd", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'. | Print the only integer *x* — the number of moves permitted for the king. | [
"e4\n"
] | [
"8\n"
] | none | 0 | [
{
"input": "e4",
"output": "8"
},
{
"input": "a1",
"output": "3"
},
{
"input": "h8",
"output": "3"
},
{
"input": "a4",
"output": "5"
},
{
"input": "g7",
"output": "8"
},
{
"input": "e1",
"output": "5"
},
{
"input": "b2",
"output": "8"
... | 1,610,102,605 | 2,147,483,647 | PyPy 3 | OK | TESTS | 24 | 155 | 0 | s=input()
c=0
if (s[0]=='a' or s[0]=='h'):
c+=1
if (s[1]=='1' or s[1]=='8'):
c+=1
if c==0:
print(8)
elif c==1:
print(5)
else:
print(3) | Title: King Moves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check... | ```python
s=input()
c=0
if (s[0]=='a' or s[0]=='h'):
c+=1
if (s[1]=='1' or s[1]=='8'):
c+=1
if c==0:
print(8)
elif c==1:
print(5)
else:
print(3)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,699,789,361 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 85 | 124 | 0 | meno, uz_boli, tot = input().strip(), [], 0
for pismeno in meno:
if pismeno not in uz_boli:
uz_boli.append(pismeno)
tot += 1
if tot % 2 == 0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
| Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
meno, uz_boli, tot = input().strip(), [], 0
for pismeno in meno:
if pismeno not in uz_boli:
uz_boli.append(pismeno)
tot += 1
if tot % 2 == 0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,558,281,471 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 0 | y = input().lower()
a = y.find('h')
b = y.find('e', a + 1)
c = y.find('l', b + 1)
d = y.find('l', c + 1)
e = y.find('o', d + 1)
if e > d > c > b > a:
print('YES')
else:
print('NO') | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
y = input().lower()
a = y.find('h')
b = y.find('e', a + 1)
c = y.find('l', b + 1)
d = y.find('l', c + 1)
e = y.find('o', d + 1)
if e > d > c > b > a:
print('YES')
else:
print('NO')
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
722 | B | Verse Pattern | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowel... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the text.
The second line contains integers *p*1,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=100) — the verse pattern.
Next *n* lines contain the text itself. Text consists of lowercase English letters and spaces. It's guarant... | If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes). | [
"3\n2 2 3\nintel\ncode\nch allenge\n",
"4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz\n",
"4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageous fortune\nor to take arms against a sea of troubles\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, one can split words into syllables in the following way:
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one. | 500 | [
{
"input": "3\n2 2 3\nintel\ncode\nch allenge",
"output": "YES"
},
{
"input": "4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz",
"output": "NO"
},
{
"input": "4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageo... | 1,557,778,194 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 109 | 0 | n=int(input())
x=list(map(int,input().split()))
l=[]
for i in range(n):
s=input()
ans=s.count('a')+s.count('e')+s.count('i')+s.count('o')+s.count('u')
l.append(ans)
if l==x:
print('YES')
else:
print('NO')
| Title: Verse Pattern
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary num... | ```python
n=int(input())
x=list(map(int,input().split()))
l=[]
for i in range(n):
s=input()
ans=s.count('a')+s.count('e')+s.count('i')+s.count('o')+s.count('u')
l.append(ans)
if l==x:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,558,534,456 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 218 | 0 |
n, m = map(int, input().split())
t = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53]
if m in t and t.index(n) + 1 == t.index(m):
print('YES')
else:
print('NO')
# UBCF
# CodeForcesian
# ♥
# هی | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
n, m = map(int, input().split())
t = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53]
if m in t and t.index(n) + 1 == t.index(m):
print('YES')
else:
print('NO')
# UBCF
# CodeForcesian
# ♥
# هی
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
387 | A | George and Sleep | PROGRAMMING | 900 | [
"implementation"
] | null | null | George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when George went to bed. Note that George could have gone to bed yesterday relatively to the current time (see ... | The first line contains current time *s* as a string in the format "hh:mm". The second line contains time *t* in the format "hh:mm" — the duration of George's sleep. It is guaranteed that the input contains the correct time in the 24-hour format, that is, 00<=≤<=*hh*<=≤<=23, 00<=≤<=*mm*<=≤<=59. | In the single line print time *p* — the time George went to bed in the format similar to the format of the time in the input. | [
"05:50\n05:44\n",
"00:00\n01:00\n",
"00:01\n00:00\n"
] | [
"00:06\n",
"23:00\n",
"00:01\n"
] | In the first sample George went to bed at "00:06". Note that you should print the time only in the format "00:06". That's why answers "0:06", "00:6" and others will be considered incorrect.
In the second sample, George went to bed yesterday.
In the third sample, George didn't do to bed at all. | 500 | [
{
"input": "05:50\n05:44",
"output": "00:06"
},
{
"input": "00:00\n01:00",
"output": "23:00"
},
{
"input": "00:01\n00:00",
"output": "00:01"
},
{
"input": "23:59\n23:59",
"output": "00:00"
},
{
"input": "23:44\n23:55",
"output": "23:49"
},
{
"input": "... | 1,663,295,353 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 46 | 0 | h=[]
m=[]
for _ in range(2):
x,y = list(map(int, input().split(':')))
h.append(x)
m.append(y)
h[0]=h[0]-h[1]
m[0]=m[0]-m[1]
if m[0]<0:
h[0]-=1
m[0]+=60
if h[0]<0:
h[0]+=24
if h[0]>=0 and h[0]<=9:
h[0]='0'+str(h[0])
if m[0]>=0 and m[0]<=9:
m[0]=... | Title: George and Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when Geor... | ```python
h=[]
m=[]
for _ in range(2):
x,y = list(map(int, input().split(':')))
h.append(x)
m.append(y)
h[0]=h[0]-h[1]
m[0]=m[0]-m[1]
if m[0]<0:
h[0]-=1
m[0]+=60
if h[0]<0:
h[0]+=24
if h[0]>=0 and h[0]<=9:
h[0]='0'+str(h[0])
if m[0]>=0 and m[0]<=9:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
475 | B | Strongly Connected City | PROGRAMMING | 1,400 | [
"brute force",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Imagine a city with *n* horizontal streets crossing *m* vertical streets, forming an (*n*<=-<=1)<=×<=(*m*<=-<=1) grid. In order to increase the traffic flow, mayor of the city has decided to make each street one way. This means in each horizontal street, the traffic moves only from west to east or only from east to wes... | The first line of input contains two integers *n* and *m*, (2<=≤<=*n*,<=*m*<=≤<=20), denoting the number of horizontal streets and the number of vertical streets.
The second line contains a string of length *n*, made of characters '<' and '>', denoting direction of each horizontal street. If the *i*-th character... | If the given pattern meets the mayor's criteria, print a single line containing "YES", otherwise print a single line containing "NO". | [
"3 3\n><>\nv^v\n",
"4 6\n<><>\nv^v^v^\n"
] | [
"NO\n",
"YES\n"
] | The figure above shows street directions in the second sample test case. | 1,000 | [
{
"input": "3 3\n><>\nv^v",
"output": "NO"
},
{
"input": "4 6\n<><>\nv^v^v^",
"output": "YES"
},
{
"input": "2 2\n<>\nv^",
"output": "YES"
},
{
"input": "2 2\n>>\n^v",
"output": "NO"
},
{
"input": "3 3\n>><\n^^v",
"output": "YES"
},
{
"input": "3 4\n>>... | 1,683,768,492 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n,m=list(map(int,input().split()))
di=[*input()]
dj=[*input()]
mj=[1,-1,0,0]
mi=[0,0,1,-1]
def canMove(i,j,xi,xj):
test=False
if di[i]=='>' and xj==1 and xi==0:
test=True
elif di[i]=='<'and xj==-1 and xi==0:
test=True
elif dj[j]=='^' and xi==1 and xj==0:
test=True
elif dj[j]=='v' and ... | Title: Strongly Connected City
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine a city with *n* horizontal streets crossing *m* vertical streets, forming an (*n*<=-<=1)<=×<=(*m*<=-<=1) grid. In order to increase the traffic flow, mayor of the city has decided to make each street one... | ```python
n,m=list(map(int,input().split()))
di=[*input()]
dj=[*input()]
mj=[1,-1,0,0]
mi=[0,0,1,-1]
def canMove(i,j,xi,xj):
test=False
if di[i]=='>' and xj==1 and xi==0:
test=True
elif di[i]=='<'and xj==-1 and xi==0:
test=True
elif dj[j]=='^' and xi==1 and xj==0:
test=True
elif dj[j]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,665,823,967 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 155 | 11,161,600 | t=int(input())
a=list(map(int,input().split(" ")))
b=list(map(int,input().split(" ")))
sum1=sum(a)
b.sort()
for i in range(t):
sum2=b[i]+b[i-1]
if sum1<=sum2:
print("YES")
else:
print("NO")
| Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
t=int(input())
a=list(map(int,input().split(" ")))
b=list(map(int,input().split(" ")))
sum1=sum(a)
b.sort()
for i in range(t):
sum2=b[i]+b[i-1]
if sum1<=sum2:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,650,989,471 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 124 | 0 | def convert_to_sum_digits(string):
sum_digits = 0
for i in string:
sum_digits += int(i)
return str(sum_digits)
string = input()
spells= 0
while len(string)>1:
spells +=1
string = convert_to_sum_digits(string)
print(spells)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
def convert_to_sum_digits(string):
sum_digits = 0
for i in string:
sum_digits += int(i)
return str(sum_digits)
string = input()
spells= 0
while len(string)>1:
spells +=1
string = convert_to_sum_digits(string)
print(spells)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
189 | B | Counting Rhombi | PROGRAMMING | 1,300 | [
"brute force",
"math"
] | null | null | You have two positive integers *w* and *h*. Your task is to count the number of rhombi which have the following properties:
- Have positive area. - With vertices at integer points. - All vertices of the rhombi are located inside or on the border of the rectangle with vertices at points (0,<=0), (*w*,<=0), (*w*,<=*... | The first line contains two integers *w* and *h* (1<=≤<=*w*,<=*h*<=≤<=4000) — the rectangle's sizes. | Print a single number — the number of sought rhombi.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2 2\n",
"1 2\n"
] | [
"1\n",
"0\n"
] | In the first example there exists only one such rhombus. Its vertices are located at points (1, 0), (2, 1), (1, 2), (0, 1). | 1,000 | [
{
"input": "2 2",
"output": "1"
},
{
"input": "1 2",
"output": "0"
},
{
"input": "1 4000",
"output": "0"
},
{
"input": "4000 1",
"output": "0"
},
{
"input": "4000 4000",
"output": "16000000000000"
},
{
"input": "15 10",
"output": "1400"
},
{
... | 1,691,854,116 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 26 | 154 | 0 | x, y = map(int, input().split())
while True:
if x == -1 and y == -1:
break
c, d = x // 2, y // 2
e, f = x % 2, y % 2
if c > 0 and d > 0:
ans = c * d * (c + e) * (d + f)
print(ans)
break
else:
print(0)
... | Title: Counting Rhombi
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have two positive integers *w* and *h*. Your task is to count the number of rhombi which have the following properties:
- Have positive area. - With vertices at integer points. - All vertices of the rhombi are ... | ```python
x, y = map(int, input().split())
while True:
if x == -1 and y == -1:
break
c, d = x // 2, y // 2
e, f = x % 2, y % 2
if c > 0 and d > 0:
ans = c * d * (c + e) * (d + f)
print(ans)
break
else:
print(0... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
556 | A | Case of the Zeros and Ones | PROGRAMMING | 900 | [
"greedy"
] | null | null | Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Consider the following operation: we choose any two adjacent positions in the string, and if one them contains 0, an... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=2·105), the length of the string that Andreid has.
The second line contains the string of length *n* consisting only from zeros and ones. | Output the minimum length of the string that may remain after applying the described operations several times. | [
"4\n1100\n",
"5\n01010\n",
"8\n11101111\n"
] | [
"0\n",
"1\n",
"6\n"
] | In the first sample test it is possible to change the string like the following: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/10df55364c21c6e8d5da31b6ab6f6294c4fc26b3.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample test it is possible to change the string like... | 250 | [
{
"input": "4\n1100",
"output": "0"
},
{
"input": "5\n01010",
"output": "1"
},
{
"input": "8\n11101111",
"output": "6"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n00",
"output": "2"
},
{
"input"... | 1,657,701,411 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 512,000 | n = int(input())
s = input()
ones = s.count("1")
zeros = s.count("0")
print(len(s)-min(ones , zeros) * 2)
| Title: Case of the Zeros and Ones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrewid the Android is a galaxy-famous detective. In his free time he likes to think about strings containing zeros and ones.
Once he thought about a string of length *n* consisting of zeroes and ones. Cons... | ```python
n = int(input())
s = input()
ones = s.count("1")
zeros = s.count("0")
print(len(s)-min(ones , zeros) * 2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,663,919,849 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 46 | 0 | if __name__ == "__main__":
n = int(input())
table = []
for _ in range(n):
table.append([])
max_value_in_table = 1
for i in range(n):
for j in range(n):
total = 0
if i == 0:
table[i].append(1)
else:
if... | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
if __name__ == "__main__":
n = int(input())
table = []
for _ in range(n):
table.append([])
max_value_in_table = 1
for i in range(n):
for j in range(n):
total = 0
if i == 0:
table[i].append(1)
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,633,239,577 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 154 | 6,758,400 | n=int(input())
d=list(map(int,input().split(' ')))
a,b=map(int,input().split(' '))
o=0
for i in range(a-1,b-1):
o+=d[i]
print(o) | Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
n=int(input())
d=list(map(int,input().split(' ')))
a,b=map(int,input().split(' '))
o=0
for i in range(a-1,b-1):
o+=d[i]
print(o)
``` | 3.948911 | MatrixStudio/Codeforces-Python-Submissions |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,598,785,258 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 278 | 20,172,800 | def f(l):
n = len(l)
cl = [0]*1001
for i in l:
cl[i] += 1
return max(cl) << (n+1)//2
q = int(input())
l = list(map(int,input().split()))
print('YES' if f(l) else 'NO')
| Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
def f(l):
n = len(l)
cl = [0]*1001
for i in l:
cl[i] += 1
return max(cl) << (n+1)//2
q = int(input())
l = list(map(int,input().split()))
print('YES' if f(l) else 'NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
573 | A | Bear and Poker | PROGRAMMING | 1,300 | [
"implementation",
"math",
"number theory"
] | null | null | Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid with size *a**i* dollars.
Each player can double his bid any number of times and triple his bid any nu... | First line of input contains an integer *n* (2<=≤<=*n*<=≤<=105), the number of players.
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the bids of players. | Print "Yes" (without the quotes) if players can make their bids become equal, or "No" otherwise. | [
"4\n75 150 75 50\n",
"3\n100 150 250\n"
] | [
"Yes\n",
"No\n"
] | In the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid.
It can be shown that in the second sample test there is no way to make all bids equal. | 500 | [
{
"input": "4\n75 150 75 50",
"output": "Yes"
},
{
"input": "3\n100 150 250",
"output": "No"
},
{
"input": "7\n34 34 68 34 34 68 34",
"output": "Yes"
},
{
"input": "10\n72 96 12 18 81 20 6 2 54 1",
"output": "No"
},
{
"input": "20\n958692492 954966768 77387000 724... | 1,649,076,661 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 61 | 7,372,800 | n = int(input())
a = list(map(int, input().split()))
p = 0
for num in a:
if max(a)%num == 0 and max(a)!=num:
ans = max(a)/num
if ans%3==0:
continue
elif ans%2==0:
continue
else:
p+=1
break
elif p==0 and max(a)==num:
... | Title: Bear and Poker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid wit... | ```python
n = int(input())
a = list(map(int, input().split()))
p = 0
for num in a:
if max(a)%num == 0 and max(a)!=num:
ans = max(a)/num
if ans%3==0:
continue
elif ans%2==0:
continue
else:
p+=1
break
elif p==0 and max(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
888 | A | Local Extrema | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given an array *a*. Some element of this array *a**i* is a local minimum iff it is strictly less than both of its neighbours (that is, *a**i*<=<<=*a**i*<=-<=1 and *a**i*<=<<=*a**i*<=+<=1). Also the element can be called local maximum iff it is strictly greater than its neighbours (that is, *a**i*<=><=*... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in array *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=1000) — the elements of array *a*. | Print the number of local extrema in the given array. | [
"3\n1 2 3\n",
"4\n1 5 2 5\n"
] | [
"0\n",
"2\n"
] | none | 0 | [
{
"input": "3\n1 2 3",
"output": "0"
},
{
"input": "4\n1 5 2 5",
"output": "2"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n548",
"output": "0"
},
{
"input": "2\n1 1",
"output": "0"
},
{
"input": "3\n3 2 3",
"output": "1"
},
{
"inp... | 1,591,085,376 | 2,147,483,647 | PyPy 3 | OK | TESTS | 14 | 140 | 0 | n=int(input())
#n,t=map(int,input().split())
l=list(map(int, input().split()))
s=0
for i in range(1,n-1):
if l[i-1]<l[i]>l[i+1] or l[i-1]>l[i]<l[i+1]:
s+=1
print(s)
| Title: Local Extrema
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a*. Some element of this array *a**i* is a local minimum iff it is strictly less than both of its neighbours (that is, *a**i*<=<<=*a**i*<=-<=1 and *a**i*<=<<=*a**i*<=+<=1). Also the element c... | ```python
n=int(input())
#n,t=map(int,input().split())
l=list(map(int, input().split()))
s=0
for i in range(1,n-1):
if l[i-1]<l[i]>l[i+1] or l[i-1]>l[i]<l[i+1]:
s+=1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
899 | D | Shovel Sale | PROGRAMMING | 1,800 | [
"constructive algorithms",
"math"
] | null | null | There are *n* shovels in Polycarp's shop. The *i*-th shovel costs *i* burles, that is, the first shovel costs 1 burle, the second shovel costs 2 burles, the third shovel costs 3 burles, and so on. Polycarps wants to sell shovels in pairs.
Visitors are more likely to buy a pair of shovels if their total cost ends with ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=109) — the number of shovels in Polycarp's shop. | Print the number of pairs of shovels such that their total cost ends with maximum possible number of nines.
Note that it is possible that the largest number of 9s at the end is 0, then you should count all such ways.
It is guaranteed that for every *n*<=≤<=109 the answer doesn't exceed 2·109. | [
"7\n",
"14\n",
"50\n"
] | [
"3\n",
"9\n",
"1\n"
] | In the first example the maximum possible number of nines at the end is one. Polycarp cah choose the following pairs of shovels for that purpose:
- 2 and 7; - 3 and 6; - 4 and 5.
In the second example the maximum number of nines at the end of total cost of two shovels is one. The following pairs of shovels suit Po... | 1,750 | [
{
"input": "7",
"output": "3"
},
{
"input": "14",
"output": "9"
},
{
"input": "50",
"output": "1"
},
{
"input": "999999999",
"output": "499999999"
},
{
"input": "15",
"output": "11"
},
{
"input": "3",
"output": "3"
},
{
"input": "6500",
... | 1,513,588,587 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 61 | 5,529,600 | from sys import stdin, stdout
INF = float('inf')
n = int(stdin.readline())
count = [0, 5, 50, 500, 5000, 50000, 500000, 5000000, 50000000, 500000000, INF]
for label in range(len(count)):
if count[label + 1] > n:
break
pref = 0
value = int(str(pref) + '9' * label)
ans = 0
while value <= n -... | Title: Shovel Sale
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* shovels in Polycarp's shop. The *i*-th shovel costs *i* burles, that is, the first shovel costs 1 burle, the second shovel costs 2 burles, the third shovel costs 3 burles, and so on. Polycarps wants to sell sh... | ```python
from sys import stdin, stdout
INF = float('inf')
n = int(stdin.readline())
count = [0, 5, 50, 500, 5000, 50000, 500000, 5000000, 50000000, 500000000, INF]
for label in range(len(count)):
if count[label + 1] > n:
break
pref = 0
value = int(str(pref) + '9' * label)
ans = 0
while va... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
342 | E | Xenia and Tree | PROGRAMMING | 2,400 | [
"data structures",
"divide and conquer",
"trees"
] | null | null | Xenia the programmer has a tree consisting of *n* nodes. We will consider the tree nodes indexed from 1 to *n*. We will also consider the first node to be initially painted red, and the other nodes — to be painted blue.
The distance between two tree nodes *v* and *u* is the number of edges in the shortest path between... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=1<=≤<=*m*<=≤<=105) — the number of nodes in the tree and the number of queries. Next *n*<=-<=1 lines contain the tree edges, the *i*-th line contains a pair of integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*) — an edge of ... | For each second type query print the reply in a single line. | [
"5 4\n1 2\n2 3\n2 4\n4 5\n2 1\n2 5\n1 2\n2 5\n"
] | [
"0\n3\n2\n"
] | none | 2,500 | [
{
"input": "5 4\n1 2\n2 3\n2 4\n4 5\n2 1\n2 5\n1 2\n2 5",
"output": "0\n3\n2"
}
] | 1,689,184,269 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689184269.366092")# 1689184269.366105 | Title: Xenia and Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the programmer has a tree consisting of *n* nodes. We will consider the tree nodes indexed from 1 to *n*. We will also consider the first node to be initially painted red, and the other nodes — to be painted blue.
... | ```python
print("_RANDOM_GUESS_1689184269.366092")# 1689184269.366105
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
370 | A | Rook, Bishop and King | PROGRAMMING | 1,100 | [
"graphs",
"math",
"shortest paths"
] | null | null | Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=8 table. A field is represented by a pair of integers (*r*,<=*c*) — the number of the row and the number of... | The input contains four integers *r*1,<=*c*1,<=*r*2,<=*c*2 (1<=≤<=*r*1,<=*c*1,<=*r*2,<=*c*2<=≤<=8) — the coordinates of the starting and the final field. The starting field doesn't coincide with the final one.
You can assume that the chessboard rows are numbered from top to bottom 1 through 8, and the columns are numb... | Print three space-separated integers: the minimum number of moves the rook, the bishop and the king (in this order) is needed to move from field (*r*1,<=*c*1) to field (*r*2,<=*c*2). If a piece cannot make such a move, print a 0 instead of the corresponding number. | [
"4 3 1 6\n",
"5 5 5 6\n"
] | [
"2 1 3\n",
"1 0 1\n"
] | none | 500 | [
{
"input": "4 3 1 6",
"output": "2 1 3"
},
{
"input": "5 5 5 6",
"output": "1 0 1"
},
{
"input": "1 1 8 8",
"output": "2 1 7"
},
{
"input": "1 1 8 1",
"output": "1 0 7"
},
{
"input": "1 1 1 8",
"output": "1 0 7"
},
{
"input": "8 1 1 1",
"output": "... | 1,588,503,873 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 124 | 307,200 | x1,y1,x2,y2=list(map(int,input().split()))
a,b,c=0,0,0
if x1==x2 or y1==y2:
a=1
else:
a=2
c=max(abs(x1-x2),abs(y1-y2))
if (abs(x1-x2)+abs(y1-y2))%2!=0:
b=0
else:
if abs(x1-x2)==abs(y1-y2):
b=1
else:
b=2
print(a,b,c)
| Title: Rook, Bishop and King
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=... | ```python
x1,y1,x2,y2=list(map(int,input().split()))
a,b,c=0,0,0
if x1==x2 or y1==y2:
a=1
else:
a=2
c=max(abs(x1-x2),abs(y1-y2))
if (abs(x1-x2)+abs(y1-y2))%2!=0:
b=0
else:
if abs(x1-x2)==abs(y1-y2):
b=1
else:
b=2
print(a,b,c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,672,288,308 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | x,y=map(int,input().split())
if x>y:
x,y=y,x
print(x,y)
if y<1 or x<1:
print(0)
else:
s=y*(x//2)
if x>2:
s=s+y//2
print(s)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
x,y=map(int,input().split())
if x>y:
x,y=y,x
print(x,y)
if y<1 or x<1:
print(0)
else:
s=y*(x//2)
if x>2:
s=s+y//2
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,592,205,351 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 307,200 | n=int(input())
list=[int(i) for i in input().split()]
neg,pos,zero=0,0,0
negarr,posarr=[],[]
for i in range(n):
if(list[i]==0):
zero+=1
elif(list[i]<0):
neg+=1
elif(list[i]>0):
pos+=1
if(zero+neg==n):
flag=True
for i in range(n):
if(list[i]<0 and flag):
... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
n=int(input())
list=[int(i) for i in input().split()]
neg,pos,zero=0,0,0
negarr,posarr=[],[]
for i in range(n):
if(list[i]==0):
zero+=1
elif(list[i]<0):
neg+=1
elif(list[i]>0):
pos+=1
if(zero+neg==n):
flag=True
for i in range(n):
if(list[i]<0 a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the ... | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,553,664,211 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 93 | 0 | # print("Input n")
n = int(input())
fiblist = [1, 1]
currentfib = 1
oneback = 1
twoback = 1
while currentfib < 2000:
currentfib = oneback + twoback
fiblist.append(currentfib)
twoback = oneback
oneback = currentfib
answer = ''
for i in range(1, n+1):
if i in fiblist:
answer += "O"
else... | Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should o... | ```python
# print("Input n")
n = int(input())
fiblist = [1, 1]
currentfib = 1
oneback = 1
twoback = 1
while currentfib < 2000:
currentfib = oneback + twoback
fiblist.append(currentfib)
twoback = oneback
oneback = currentfib
answer = ''
for i in range(1, n+1):
if i in fiblist:
answer += "O... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
903 | A | Hungry Student Problem | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chunks; a large one — 7 chunks. Ivan wants to eat exactly *x* chunks. Now he wonders whether he can buy exactly ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of testcases.
The *i*-th of the following *n* lines contains one integer *x**i* (1<=≤<=*x**i*<=≤<=100) — the number of chicken chunks Ivan wants to eat. | Print *n* lines, in *i*-th line output YES if Ivan can buy exactly *x**i* chunks. Otherwise, print NO. | [
"2\n6\n5\n"
] | [
"YES\nNO\n"
] | In the first example Ivan can buy two small portions.
In the second example Ivan cannot buy exactly 5 chunks, since one small portion is not enough, but two small portions or one large is too much. | 0 | [
{
"input": "2\n6\n5",
"output": "YES\nNO"
},
{
"input": "100\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13\n14\n15\n16\n17\n18\n19\n20\n21\n22\n23\n24\n25\n26\n27\n28\n29\n30\n31\n32\n33\n34\n35\n36\n37\n38\n39\n40\n41\n42\n43\n44\n45\n46\n47\n48\n49\n50\n51\n52\n53\n54\n55\n56\n57\n58\n59\n60\n61\n62\... | 1,618,477,970 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<stdio.h>
int main()
{
int t;
scanf("%d",&t);
while(t--){
int n;
scanf("%d",&n);
while(n!=0)
if(n%3 == 0 || n%7 == 0){
printf("YES\n");
continue;
}
else{
... | Title: Hungry Student Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan's classes at the university have just finished, and now he wants to go to the local CFK cafe and eat some fried chicken.
CFK sells chicken chunks in small and large portions. A small portion contains 3 chun... | ```python
#include<stdio.h>
int main()
{
int t;
scanf("%d",&t);
while(t--){
int n;
scanf("%d",&n);
while(n!=0)
if(n%3 == 0 || n%7 == 0){
printf("YES\n");
continue;
}
else{
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
766 | A | Mahmoud and Longest Uncommon Subsequence | PROGRAMMING | 1,000 | [
"constructive algorithms",
"strings"
] | null | null | While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two strings *a* and *b*, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence ... | The first line contains string *a*, and the second line — string *b*. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than 105 characters. | If there's no uncommon subsequence, print "-1". Otherwise print the length of the longest uncommon subsequence of *a* and *b*. | [
"abcd\ndefgh\n",
"a\na\n"
] | [
"5\n",
"-1\n"
] | In the first example: you can choose "defgh" from string *b* as it is the longest subsequence of string *b* that doesn't appear as a subsequence of string *a*. | 500 | [
{
"input": "abcd\ndefgh",
"output": "5"
},
{
"input": "a\na",
"output": "-1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaacccccccccccccccccccccccccccccccccccccccccccccccccc\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaadddddddddddddddddddddddddddddddddddddddddddd... | 1,678,134,264 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | a = 'abcd'
b = 'defgh'
len_a = len(a)
len_b = len(b)
if a != b:
print(max(len_b, len_b))
else:
print(-1) | Title: Mahmoud and Longest Uncommon Subsequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two ... | ```python
a = 'abcd'
b = 'defgh'
len_a = len(a)
len_b = len(b)
if a != b:
print(max(len_b, len_b))
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
359 | A | Table | PROGRAMMING | 1,000 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | Simon has a rectangular table consisting of *n* rows and *m* columns. Simon numbered the rows of the table from top to bottom starting from one and the columns — from left to right starting from one. We'll represent the cell on the *x*-th row and the *y*-th column as a pair of numbers (*x*,<=*y*). The table corners are... | The first line contains exactly two integers *n*, *m* (3<=≤<=*n*,<=*m*<=≤<=50).
Next *n* lines contain the description of the table cells. Specifically, the *i*-th line contains *m* space-separated integers *a**i*1,<=*a**i*2,<=...,<=*a**im*. If *a**ij* equals zero, then cell (*i*,<=*j*) isn't good. Otherwise *a**ij* e... | Print a single number — the minimum number of operations Simon needs to carry out his idea. | [
"3 3\n0 0 0\n0 1 0\n0 0 0\n",
"4 3\n0 0 0\n0 0 1\n1 0 0\n0 0 0\n"
] | [
"4\n",
"2\n"
] | In the first sample, the sequence of operations can be like this:
- For the first time you need to choose cell (2, 2) and corner (1, 1). - For the second time you need to choose cell (2, 2) and corner (3, 3). - For the third time you need to choose cell (2, 2) and corner (3, 1). - For the fourth time you need to c... | 500 | [
{
"input": "3 3\n0 0 0\n0 1 0\n0 0 0",
"output": "4"
},
{
"input": "4 3\n0 0 0\n0 0 1\n1 0 0\n0 0 0",
"output": "2"
},
{
"input": "50 4\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 1 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0\n0 0 0 0... | 1,607,580,519 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 109 | 0 | n,m = map(int,input().split())
check = 0
for i in range(n):
s = input()
if i==0 or i==n-1:
if '1' in s:
check = 1
break
elif s[0]=='1' or s[-1]=='1':
check = 1
break
if check:
print(2)
else:
print(4) | Title: Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon has a rectangular table consisting of *n* rows and *m* columns. Simon numbered the rows of the table from top to bottom starting from one and the columns — from left to right starting from one. We'll represent the cell on t... | ```python
n,m = map(int,input().split())
check = 0
for i in range(n):
s = input()
if i==0 or i==n-1:
if '1' in s:
check = 1
break
elif s[0]=='1' or s[-1]=='1':
check = 1
break
if check:
print(2)
else:
print(4)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,675,877,822 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 61 | 1,740,800 | testNum,inputNum=map(int,input().split())
sumcolor=""
for i in range(testNum):
colorName=str(input().split())
sumcolor+=colorName
if("W" in sumcolor or "B" in sumcolor or "G" in sumcolor):
print("#Black&White")
else:
print("#Color")
| Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
testNum,inputNum=map(int,input().split())
sumcolor=""
for i in range(testNum):
colorName=str(input().split())
sumcolor+=colorName
if("W" in sumcolor or "B" in sumcolor or "G" in sumcolor):
print("#Black&White")
else:
print("#Color")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be part of the square, i.e. if one square is completely inside another, they intersect. If the ... | The input data consists of two lines, one for each square, both containing 4 pairs of integers. Each pair represents coordinates of one vertex of the square. Coordinates within each line are either in clockwise or counterclockwise order.
The first line contains the coordinates of the square with sides parallel to the ... | Print "Yes" if squares intersect, otherwise print "No".
You can print each letter in any case (upper or lower). | [
"0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1\n",
"0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1\n",
"6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the second square lies entirely within the first square, so they do intersect.
In the second sample squares do not have any points in common.
Here are images corresponding to the samples: | 0 | [
{
"input": "0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1",
"output": "NO"
},
{
"input": "6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n8 4 4 8 8 12 12 8",
"output": "YES"
},
... | 1,529,564,336 | 5,036 | Python 3 | OK | TESTS | 124 | 93 | 0 | from sys import stdin,exit
def listinput():
return list(map(int,stdin.readline().rstrip().split()))
a = listinput()
b = listinput()
x1,y1,x2,y2 = min(a[0],a[2],a[4],a[6]),min(a[1],a[3],a[5],a[7]),max(a[0],a[2],a[4],a[6]),max(a[1],a[3],a[5],a[7])
lx,rx = min(b[0],b[2],b[4],b[6]),max(b[0],b[2],b[4],b[6])
ty,by = ... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be pa... | ```python
from sys import stdin,exit
def listinput():
return list(map(int,stdin.readline().rstrip().split()))
a = listinput()
b = listinput()
x1,y1,x2,y2 = min(a[0],a[2],a[4],a[6]),min(a[1],a[3],a[5],a[7]),max(a[0],a[2],a[4],a[6]),max(a[1],a[3],a[5],a[7])
lx,rx = min(b[0],b[2],b[4],b[6]),max(b[0],b[2],b[4],b[6])... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
287 | A | IQ Test | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and others are painted white. Your task is to repaint at most one cell the other color so that the... | Four lines contain four characters each: the *j*-th character of the *i*-th line equals "." if the cell in the *i*-th row and the *j*-th column of the square is painted white, and "#", if the cell is black. | Print "YES" (without the quotes), if the test can be passed and "NO" (without the quotes) otherwise. | [
"####\n.#..\n####\n....\n",
"####\n....\n####\n....\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample it is enough to repaint the first cell in the second row. After such repainting the required 2 × 2 square is on the intersection of the 1-st and 2-nd row with the 1-st and 2-nd column. | 500 | [
{
"input": "###.\n...#\n###.\n...#",
"output": "NO"
},
{
"input": ".##.\n#..#\n.##.\n#..#",
"output": "NO"
},
{
"input": ".#.#\n#.#.\n.#.#\n#.#.",
"output": "NO"
},
{
"input": "##..\n..##\n##..\n..##",
"output": "NO"
},
{
"input": "#.#.\n#.#.\n.#.#\n.#.#",
"ou... | 1,587,482,942 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 140 | 0 | s=str(input())
s1=str(input())
s2=str(input())
s3=str(input())
l=[]
flag=0
l.append(s[0])
l.append(s[1])
l.append(s1[0])
l.append(s1[1])
for i in range(0,len(l)):
if(l.count("#")>2 or l.count(".")>2):
flag=1
l1=[]
l1.append(s[1])
l1.append(s[2])
l1.append(s1[1])
l1.append(s1[2]... | Title: IQ Test
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and o... | ```python
s=str(input())
s1=str(input())
s2=str(input())
s3=str(input())
l=[]
flag=0
l.append(s[0])
l.append(s[1])
l.append(s1[0])
l.append(s1[1])
for i in range(0,len(l)):
if(l.count("#")>2 or l.count(".")>2):
flag=1
l1=[]
l1.append(s[1])
l1.append(s[2])
l1.append(s1[1])
l1.ap... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
336 | B | Vasily the Bear and Fly | PROGRAMMING | 1,900 | [
"math"
] | null | null | One beautiful day Vasily the bear painted 2*m* circles of the same radius *R* on a coordinate plane. Circles with numbers from 1 to *m* had centers at points (2*R*<=-<=*R*,<=0), (4*R*<=-<=*R*,<=0), ..., (2*Rm*<=-<=*R*,<=0), respectively. Circles with numbers from *m*<=+<=1 to 2*m* had centers at points (2*R*<=-<=*R*,<=... | The first line contains two integers *m*,<=*R* (1<=≤<=*m*<=≤<=105, 1<=≤<=*R*<=≤<=10). | In a single line print a single real number — the answer to the problem. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=6. | [
"1 1\n",
"2 2\n"
] | [
"2.0000000000\n",
"5.4142135624\n"
] | <img class="tex-graphics" src="https://espresso.codeforces.com/9fe384073741e20965ddc4bf162afd3a604b6b39.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Figure to the second sample | 1,000 | [
{
"input": "1 1",
"output": "2.0000000000"
},
{
"input": "2 2",
"output": "5.4142135624"
},
{
"input": "100000 3",
"output": "200002.4853316681"
},
{
"input": "2344 5",
"output": "7817.4790439982"
},
{
"input": "999 10",
"output": "6668.3010410807"
},
{
... | 1,376,068,872 | 6,672 | Python 3 | COMPILATION_ERROR | PRETESTS | 0 | 0 | 0 | #include <iostream>
#include <string>
#include <algorithm>
#include <vector>
#include <cstdio>
#include <iomanip>
#include <cmath>
using namespace std;
int main() {
int n,m;
double f;
scanf("%d %d",&n,&m);
if(m==1) printf("%d.0000000000000\n",2*n);
else {
f=4*n;
f+=sqr... | Title: Vasily the Bear and Fly
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One beautiful day Vasily the bear painted 2*m* circles of the same radius *R* on a coordinate plane. Circles with numbers from 1 to *m* had centers at points (2*R*<=-<=*R*,<=0), (4*R*<=-<=*R*,<=0), ..., (2*Rm*<=... | ```python
#include <iostream>
#include <string>
#include <algorithm>
#include <vector>
#include <cstdio>
#include <iomanip>
#include <cmath>
using namespace std;
int main() {
int n,m;
double f;
scanf("%d %d",&n,&m);
if(m==1) printf("%d.0000000000000\n",2*n);
else {
f=4*n;
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | A flower shop has got *n* bouquets, and the *i*-th bouquet consists of *a**i* flowers. Vasya, the manager of the shop, decided to make large bouquets from these bouquets.
Vasya thinks that a bouquet is large if it is made of two or more initial bouquets, and there is a constraint: the total number of flowers in a lar... | The first line contains a single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of initial bouquets.
The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the number of flowers in each of the initial bouquets. | Print the maximum number of large bouquets Vasya can make. | [
"5\n2 3 4 2 7\n",
"6\n2 2 6 8 6 12\n",
"3\n11 4 10\n"
] | [
"2\n",
"0\n",
"1\n"
] | In the first example Vasya can make 2 large bouquets. For example, the first bouquet can contain the first and the fifth initial bouquets (the total number of flowers is then equal to 9), and the second bouquet can consist of the second and the third initial bouquets (the total number of flowers is then equal to 7). Th... | 0 | [
{
"input": "5\n2 3 4 2 7",
"output": "2"
},
{
"input": "6\n2 2 6 8 6 12",
"output": "0"
},
{
"input": "3\n11 4 10",
"output": "1"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "1\n999999",
"output": "0"
},
... | 1,521,307,231 | 6,331 | Python 3 | WRONG_ANSWER | TESTS | 3 | 77 | 7,065,600 | n = int(input())
ans = 0
a = input().split(' ')
for i in range(0, n):
b = int(a[i])
if (b % 2 == 1):
ans = ans + 1
print(ans)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A flower shop has got *n* bouquets, and the *i*-th bouquet consists of *a**i* flowers. Vasya, the manager of the shop, decided to make large bouquets from these bouquets.
Vasya thinks that a bouquet is large if it is made of two... | ```python
n = int(input())
ans = 0
a = input().split(' ')
for i in range(0, n):
b = int(a[i])
if (b % 2 == 1):
ans = ans + 1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
672 | B | Different is Good | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are different, he wants all substrings of his string *s* to be distinct. Substring is a string formed by some... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the string *s*.
The second line contains the string *s* of length *n* consisting of only lowercase English letters. | If it's impossible to change the string *s* such that all its substring are distinct print -1. Otherwise print the minimum required number of changes. | [
"2\naa\n",
"4\nkoko\n",
"5\nmurat\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko". | 1,000 | [
{
"input": "2\naa",
"output": "1"
},
{
"input": "4\nkoko",
"output": "2"
},
{
"input": "5\nmurat",
"output": "0"
},
{
"input": "6\nacbead",
"output": "1"
},
{
"input": "7\ncdaadad",
"output": "4"
},
{
"input": "25\npeoaicnbisdocqofsqdpgobpn",
"outp... | 1,593,749,204 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 155 | 512,000 | n = int(input())
s = input()
if n>26:
print(-1)
else:
dist = len(set(list(s)))
print(n-dist)
| Title: Different is Good
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are di... | ```python
n = int(input())
s = input()
if n>26:
print(-1)
else:
dist = len(set(list(s)))
print(n-dist)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
217 | A | Ice Skating | PROGRAMMING | 1,200 | [
"brute force",
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed that in this way it's impossible to get from some snow drifts to some other by any sequence of moves... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of snow drifts. Each of the following *n* lines contains two integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the coordinates of the *i*-th snow drift.
Note that the north direction coinсides with the direction of *Oy* ... | Output the minimal number of snow drifts that need to be created in order for Bajtek to be able to reach any snow drift from any other one. | [
"2\n2 1\n1 2\n",
"2\n2 1\n4 1\n"
] | [
"1\n",
"0\n"
] | none | 500 | [
{
"input": "2\n2 1\n1 2",
"output": "1"
},
{
"input": "2\n2 1\n4 1",
"output": "0"
},
{
"input": "24\n171 35\n261 20\n4 206\n501 446\n961 912\n581 748\n946 978\n463 514\n841 889\n341 466\n842 967\n54 102\n235 261\n925 889\n682 672\n623 636\n268 94\n635 710\n474 510\n697 794\n586 663\n182... | 1,635,886,498 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 4,505,600 | n = int(input())
xList = []
yList = []
for i in range(n):
x, y = map(int, input().split())
xList.append(x)
yList.append(y)
xList.sort()
yList.sort()
mnX = 1000
mnY = 1000
for i in range(n-1):
if xList[i+1] - xList[i] < mnX:
mnX = xList[i+1] - xList[i]
if yList[i+1] - yList[i] <... | Title: Ice Skating
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed tha... | ```python
n = int(input())
xList = []
yList = []
for i in range(n):
x, y = map(int, input().split())
xList.append(x)
yList.append(y)
xList.sort()
yList.sort()
mnX = 1000
mnY = 1000
for i in range(n-1):
if xList[i+1] - xList[i] < mnX:
mnX = xList[i+1] - xList[i]
if yList[i+1] - ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
451 | B | Sort the Array | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | Being a programmer, you like arrays a lot. For your birthday, your friends have given you an array *a* consisting of *n* distinct integers.
Unfortunately, the size of *a* is too small. You want a bigger array! Your friends agree to give you a bigger array, but only if you are able to answer the following question corr... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=105) — the size of array *a*.
The second line contains *n* distinct space-separated integers: *a*[1],<=*a*[2],<=...,<=*a*[*n*] (1<=≤<=*a*[*i*]<=≤<=109). | Print "yes" or "no" (without quotes), depending on the answer.
If your answer is "yes", then also print two space-separated integers denoting start and end (start must not be greater than end) indices of the segment to be reversed. If there are multiple ways of selecting these indices, print any of them. | [
"3\n3 2 1\n",
"4\n2 1 3 4\n",
"4\n3 1 2 4\n",
"2\n1 2\n"
] | [
"yes\n1 3\n",
"yes\n1 2\n",
"no\n",
"yes\n1 1\n"
] | Sample 1. You can reverse the entire array to get [1, 2, 3], which is sorted.
Sample 3. No segment can be reversed such that the array will be sorted.
Definitions
A segment [*l*, *r*] of array *a* is the sequence *a*[*l*], *a*[*l* + 1], ..., *a*[*r*].
If you have an array *a* of size *n* and you reverse its segment... | 1,000 | [
{
"input": "3\n3 2 1",
"output": "yes\n1 3"
},
{
"input": "4\n2 1 3 4",
"output": "yes\n1 2"
},
{
"input": "4\n3 1 2 4",
"output": "no"
},
{
"input": "2\n1 2",
"output": "yes\n1 1"
},
{
"input": "2\n58 4",
"output": "yes\n1 2"
},
{
"input": "5\n69 37 2... | 1,674,342,442 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 25 | 311 | 8,192,000 | var1 = int(input())
var2 = input().split(" ")
if var1 == 1:
print("yes")
print(str(var2[0]))
else:
for i in range(var1):
var2[i] = int(var2[i])
difTable = []
for i in range(var1-1):
if (var2[i]) > (var2[i+1]):
difTable.append(-1)
elif var2[i] <... | Title: Sort the Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Being a programmer, you like arrays a lot. For your birthday, your friends have given you an array *a* consisting of *n* distinct integers.
Unfortunately, the size of *a* is too small. You want a bigger array! Your frie... | ```python
var1 = int(input())
var2 = input().split(" ")
if var1 == 1:
print("yes")
print(str(var2[0]))
else:
for i in range(var1):
var2[i] = int(var2[i])
difTable = []
for i in range(var1-1):
if (var2[i]) > (var2[i+1]):
difTable.append(-1)
elif... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
31 | B | Sysadmin Bob | PROGRAMMING | 1,500 | [
"greedy",
"implementation",
"strings"
] | B. Sysadmin Bob | 0 | 256 | Email address in Berland is a string of the form *A*@*B*, where *A* and *B* are arbitrary strings consisting of small Latin letters.
Bob is a system administrator in «Bersoft» company. He keeps a list of email addresses of the company's staff. This list is as a large string, where all addresses are written in arbitra... | The first line contains the list of addresses without separators. The length of this string is between 1 and 200, inclusive. The string consists only from small Latin letters and characters «@». | If there is no list of the valid (according to the Berland rules) email addresses such that after removing all commas it coincides with the given string, output No solution. In the other case, output the list. The same address can be written in this list more than once. If there are several solutions, output any of the... | [
"a@aa@a\n",
"a@a@a\n",
"@aa@a\n"
] | [
"a@a,a@a\n",
"No solution\n",
"No solution\n"
] | none | 1,000 | [
{
"input": "a@aa@a",
"output": "a@a,a@a"
},
{
"input": "a@a@a",
"output": "No solution"
},
{
"input": "@aa@a",
"output": "No solution"
},
{
"input": "aba@caba@daba",
"output": "aba@c,aba@daba"
},
{
"input": "asd@qwasd@qwasd@qwasd@qwasd@qw",
"output": "asd@q,wa... | 1,643,799,198 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 46 | 0 | s=input().split('@'); n=len(s)-1
for i in range(1,n):
if len(s[i])<2: print('No solution'); exit()
else: s[i]=s[i][0]+','+s[i][1:]
if n>0 and s and s[0] and s[n]: print('@'.join(s))
else: print('No solution') | Title: Sysadmin Bob
Time Limit: 0 seconds
Memory Limit: 256 megabytes
Problem Description:
Email address in Berland is a string of the form *A*@*B*, where *A* and *B* are arbitrary strings consisting of small Latin letters.
Bob is a system administrator in «Bersoft» company. He keeps a list of email addresses of t... | ```python
s=input().split('@'); n=len(s)-1
for i in range(1,n):
if len(s[i])<2: print('No solution'); exit()
else: s[i]=s[i][0]+','+s[i][1:]
if n>0 and s and s[0] and s[n]: print('@'.join(s))
else: print('No solution')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,596,383,236 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 22,323,200 | t=int(input())
l=[]
x=list(map(int,input().split()))
k=set(int (f) for f in x)
if 0 in s:
k.remove(0)
print(len(k))
else:
print(len(k))
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
t=int(input())
l=[]
x=list(map(int,input().split()))
k=set(int (f) for f in x)
if 0 in s:
k.remove(0)
print(len(k))
else:
print(len(k))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
266 | A | Stones on the Table | PROGRAMMING | 800 | [
"implementation"
] | null | null | There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red... | Print a single integer — the answer to the problem. | [
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] | [
"1\n",
"4\n",
"0\n"
] | none | 500 | [
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "... | 1,696,176,052 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | # Read the number of stones
n = int(input())
# Read the string representing the colors of the stones
colors = input()
# Initialize a variable to count the number of stones to remove
stones_to_remove = 0
# Iterate through the colors starting from the second stone
for i in range(1, n):
if colors[i] == c... | Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row ... | ```python
# Read the number of stones
n = int(input())
# Read the string representing the colors of the stones
colors = input()
# Initialize a variable to count the number of stones to remove
stones_to_remove = 0
# Iterate through the colors starting from the second stone
for i in range(1, n):
if colo... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
57 | A | Square Earth? | PROGRAMMING | 1,300 | [
"dfs and similar",
"greedy",
"implementation"
] | A. Square Earth? | 2 | 256 | Meg the Rabbit decided to do something nice, specifically — to determine the shortest distance between two points on the surface of our planet. But Meg... what can you say, she wants everything simple. So, she already regards our planet as a two-dimensional circle. No, wait, it's even worse — as a square of side *n*. T... | The single line contains 5 space-separated integers: *n*,<=*x*1,<=*y*1,<=*x*2,<=*y*2 (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=*n*) which correspondingly represent a side of the square, the coordinates of the first point and the coordinates of the second point. It is guaranteed that the points lie on th... | You must print on a single line the shortest distance between the points. | [
"2 0 0 1 0\n",
"2 0 1 2 1\n",
"100 0 0 100 100\n"
] | [
"1\n",
"4\n",
"200\n"
] | none | 500 | [
{
"input": "2 0 0 1 0",
"output": "1"
},
{
"input": "2 0 1 2 1",
"output": "4"
},
{
"input": "100 0 0 100 100",
"output": "200"
},
{
"input": "4 0 3 1 4",
"output": "2"
},
{
"input": "10 8 10 10 0",
"output": "12"
},
{
"input": "26 21 0 26 14",
"ou... | 1,643,721,635 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | arr,ans = [int(item) for item in input().split(' ')],0
if arr[1] <= arr[3] and arr[2] <= arr[4] or arr[1] >= arr[3] and arr[2] >= arr[4]:
ans += min(abs(arr[1] - arr[3]) ,abs(arr[2]- arr[4]))
else:
ans += min((arr[1] + arr[2]+arr[3]+arr[4]),(4*arr[0]) - (arr[1] + arr[2]+arr[3]+arr[4]))
print(ans) | Title: Square Earth?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Meg the Rabbit decided to do something nice, specifically — to determine the shortest distance between two points on the surface of our planet. But Meg... what can you say, she wants everything simple. So, she already regards... | ```python
arr,ans = [int(item) for item in input().split(' ')],0
if arr[1] <= arr[3] and arr[2] <= arr[4] or arr[1] >= arr[3] and arr[2] >= arr[4]:
ans += min(abs(arr[1] - arr[3]) ,abs(arr[2]- arr[4]))
else:
ans += min((arr[1] + arr[2]+arr[3]+arr[4]),(4*arr[0]) - (arr[1] + arr[2]+arr[3]+arr[4]))
print... | 0 | MatrixStudio/Codeforces-Python-Submissions |
1 | C | Ancient Berland Circus | PROGRAMMING | 2,100 | [
"geometry",
"math"
] | C. Ancient Berland Circus | 2 | 64 | Nowadays all circuses in Berland have a round arena with diameter 13 meters, but in the past things were different.
In Ancient Berland arenas in circuses were shaped as a regular (equiangular) polygon, the size and the number of angles could vary from one circus to another. In each corner of the arena there was a spec... | The input file consists of three lines, each of them contains a pair of numbers –– coordinates of the pillar. Any coordinate doesn't exceed 1000 by absolute value, and is given with at most six digits after decimal point. | Output the smallest possible area of the ancient arena. This number should be accurate to at least 6 digits after the decimal point. It's guaranteed that the number of angles in the optimal polygon is not larger than 100. | [
"0.000000 0.000000\n1.000000 1.000000\n0.000000 1.000000\n"
] | [
"1.00000000\n"
] | 0 | [
{
"input": "0.000000 0.000000\n1.000000 1.000000\n0.000000 1.000000",
"output": "1.00000000"
},
{
"input": "71.756151 7.532275\n-48.634784 100.159986\n91.778633 158.107739",
"output": "9991.27897663"
},
{
"input": "18.716839 40.852752\n66.147248 -4.083161\n111.083161 43.347248",
"out... | 1,671,050,356 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 50 | 124 | 0 | from itertools import count
from math import atan2, cos, hypot, inf, sin, tau
def circumcenter(x1, y1, x2, y2, x3, y3):
assert not (y1 == y2 == y3) and not (x1 == x2 == x3)
if y1 == y2:
return circumcenter(x1, y1, x3, y3, x2, y2)
if y3 == y2:
return circumcenter(x2, y2, x1, y1, x3, y3)
... | Title: Ancient Berland Circus
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nowadays all circuses in Berland have a round arena with diameter 13 meters, but in the past things were different.
In Ancient Berland arenas in circuses were shaped as a regular (equiangular) polygon, the size and t... | ```python
from itertools import count
from math import atan2, cos, hypot, inf, sin, tau
def circumcenter(x1, y1, x2, y2, x3, y3):
assert not (y1 == y2 == y3) and not (x1 == x2 == x3)
if y1 == y2:
return circumcenter(x1, y1, x3, y3, x2, y2)
if y3 == y2:
return circumcenter(x2, y2, x1, y1, x... | 3.969 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,669,193,079 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 154 | 0 | n=int(input())
b=[int(i)for i in input().split()]
a=[]
for i in b:
if i not in a:
a=a+[i]
a.sort()
if len(a)==1:
print("NO")
else:
print(a[1])
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n=int(input())
b=[int(i)for i in input().split()]
a=[]
for i in b:
if i not in a:
a=a+[i]
a.sort()
if len(a)==1:
print("NO")
else:
print(a[1])
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,643,560,770 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 31 | 0 | n = int(input())
a = list(map(int, input().split()))
if 0 not in a:
print(len(set(a)))
else:
print(len(set(a))-1) | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n = int(input())
a = list(map(int, input().split()))
if 0 not in a:
print(len(set(a)))
else:
print(len(set(a))-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,618,940,703 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | a=input()
i=0
while i<len(a):
if a[i]=='h':
while i<len(a):
if a[i]=='e':
while i<len(a):
if a[i]=='i':
while i<len(a):
if a[i]=='d':
while i<len(a):
... | Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
a=input()
i=0
while i<len(a):
if a[i]=='h':
while i<len(a):
if a[i]=='e':
while i<len(a):
if a[i]=='i':
while i<len(a):
if a[i]=='d':
while i<len(a):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
977 | B | Two-gram | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to find any two-gram contained in the given string as a substring (i.e. two consecutive characters... | The first line of the input contains integer number $n$ ($2 \le n \le 100$) — the length of string $s$. The second line of the input contains the string $s$ consisting of $n$ capital Latin letters. | Print the only line containing exactly two capital Latin letters — any two-gram contained in the given string $s$ as a substring (i.e. two consecutive characters of the string) maximal number of times. | [
"7\nABACABA\n",
"5\nZZZAA\n"
] | [
"AB\n",
"ZZ\n"
] | In the first example "BA" is also valid answer.
In the second example the only two-gram "ZZ" can be printed because it contained in the string "ZZZAA" two times. | 0 | [
{
"input": "7\nABACABA",
"output": "AB"
},
{
"input": "5\nZZZAA",
"output": "ZZ"
},
{
"input": "26\nQWERTYUIOPASDFGHJKLZXCVBNM",
"output": "AS"
},
{
"input": "2\nQA",
"output": "QA"
},
{
"input": "2\nWW",
"output": "WW"
},
{
"input": "11\nGGRRAATTZZZ",... | 1,694,358,652 | 952 | PyPy 3-64 | OK | TESTS | 22 | 62 | 0 | n = int(input())
string = input()
d ={}
for i in range(1, len(string)):
bi = string[i-1: i+1]
if bi not in d.keys():
d[bi] = 1
else:
d[bi]+=1
max= 0
result = ""
for key in d.keys():
if d[key] > max:
result = key
max = d[key]
print(result) | Title: Two-gram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to f... | ```python
n = int(input())
string = input()
d ={}
for i in range(1, len(string)):
bi = string[i-1: i+1]
if bi not in d.keys():
d[bi] = 1
else:
d[bi]+=1
max= 0
result = ""
for key in d.keys():
if d[key] > max:
result = key
max = d[key]
print(result)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
590 | C | Three States | PROGRAMMING | 2,200 | [
"dfs and similar",
"graphs",
"shortest paths"
] | null | null | The famous global economic crisis is approaching rapidly, so the states of Berman, Berance and Bertaly formed an alliance and allowed the residents of all member states to freely pass through the territory of any of them. In addition, it was decided that a road between the states should be built to guarantee so that on... | The first line of the input contains the dimensions of the map *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and columns respectively.
Each of the next *n* lines contain *m* characters, describing the rows of the map. Digits from 1 to 3 represent the accessory to the corresponding state. The character '.... | Print a single integer — the minimum number of cells you need to build a road inside in order to connect all the cells of all states. If such a goal is unachievable, print -1. | [
"4 5\n11..2\n#..22\n#.323\n.#333",
"1 5\n1#2#3\n"
] | [
"2",
"-1\n"
] | none | 1,250 | [
{
"input": "4 5\n11..2\n#..22\n#.323\n.#333",
"output": "2"
},
{
"input": "1 5\n1#2#3",
"output": "-1"
},
{
"input": "3 4\n.2..\n...3\n.1#.",
"output": "2"
},
{
"input": "10 10\n##.#..#.#2\n...###....\n#..#....##\n.....#....\n.#........\n.....#####\n...#..#...\n....###...\n##... | 1,692,898,719 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 307,200 | import sys
# sys.setrecursionlimit(1000000)
input=lambda:sys.stdin.readline().strip()
write=lambda x:sys.stdout.write(str(x)+'\n')
# from decimal import Decimal
# from random import randint
# from copy import deepcopy
from collections import deque,Counter
from heapq import heapify,heappush,heappop
# from bis... | Title: Three States
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The famous global economic crisis is approaching rapidly, so the states of Berman, Berance and Bertaly formed an alliance and allowed the residents of all member states to freely pass through the territory of any of them. ... | ```python
import sys
# sys.setrecursionlimit(1000000)
input=lambda:sys.stdin.readline().strip()
write=lambda x:sys.stdout.write(str(x)+'\n')
# from decimal import Decimal
# from random import randint
# from copy import deepcopy
from collections import deque,Counter
from heapq import heapify,heappush,heappop
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
157 | B | Trace | PROGRAMMING | 1,000 | [
"geometry",
"sortings"
] | null | null | One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall into several parts. Some parts were painted red and all the other were painted blue. Besides,... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integers *r**i* (1<=≤<=*r**i*<=≤<=1000) — the circles' radii. It is guaranteed that all circles are different. | Print the single real number — total area of the part of the wall that is painted red. The answer is accepted if absolute or relative error doesn't exceed 10<=-<=4. | [
"1\n1\n",
"3\n1 4 2\n"
] | [
"3.1415926536\n",
"40.8407044967\n"
] | In the first sample the picture is just one circle of radius 1. Inner part of the circle is painted red. The area of the red part equals π × 1<sup class="upper-index">2</sup> = π.
In the second sample there are three circles of radii 1, 4 and 2. Outside part of the second circle is painted blue. Part between the secon... | 1,000 | [
{
"input": "1\n1",
"output": "3.1415926536"
},
{
"input": "3\n1 4 2",
"output": "40.8407044967"
},
{
"input": "4\n4 1 3 2",
"output": "31.4159265359"
},
{
"input": "4\n100 10 2 1",
"output": "31111.1920484997"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output"... | 1,587,563,592 | 2,147,483,647 | PyPy 3 | OK | TESTS | 44 | 312 | 0 | import math
a = int(input())
v = [int(i) for i in input().split()]
res1 = 0
res2 = 0
for i in range(a):
v = sorted(v, reverse=True)
if i%2 == 0:
res1 += v[i]*v[i]
else:
res2 += v[i]*v[i]
res = res1 - res2
# print(res1, res2)
print(res*math.pi)
| Title: Trace
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall in... | ```python
import math
a = int(input())
v = [int(i) for i in input().split()]
res1 = 0
res2 = 0
for i in range(a):
v = sorted(v, reverse=True)
if i%2 == 0:
res1 += v[i]*v[i]
else:
res2 += v[i]*v[i]
res = res1 - res2
# print(res1, res2)
print(res*math.pi)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,667,058,427 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 |
num = [int(n) for n in list(input())]
for i in range(len(num)):
temp = 9-num[i]
if(num[i]>temp):
num[i]= temp
num[i]= str(num[i])
print(''.join(num)) | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
num = [int(n) for n in list(input())]
for i in range(len(num)):
temp = 9-num[i]
if(num[i]>temp):
num[i]= temp
num[i]= str(num[i])
print(''.join(num))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
862 | B | Mahmoud and Ehab and the bipartiteness | PROGRAMMING | 1,300 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a graph, whose vertices can be partitioned into 2 sets in such a way, that for each edge (*u*,<=*v*) that belongs to the graph, *... | The first line of input contains an integer *n* — the number of nodes in the tree (1<=≤<=*n*<=≤<=105).
The next *n*<=-<=1 lines contain integers *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*) — the description of the edges of the tree.
It's guaranteed that the given graph is a tree. | Output one integer — the maximum number of edges that Mahmoud and Ehab can add to the tree while fulfilling the conditions. | [
"3\n1 2\n1 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n"
] | [
"0\n",
"2\n"
] | Tree definition: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory))
Bipartite graph definition: [https://en.wikipedia.org/wiki/Bipartite_graph](https://en.wikipedia.org/wiki/Bipartite_graph)
In the first test case the only edge that can be added in such a way, that ... | 1,000 | [
{
"input": "3\n1 2\n1 3",
"output": "0"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10\n3 8\n6 2\n9 7\n10 1\n3 5\n1 3\n6 7\n5 4\n3 6",
"output": "16"
},
{
"input": "10\n7 6\n2 7\n4 1\n8 5\n9 4\n5 3\n8 7\n10 8\n10 4",
"output": "16"
},
{
"in... | 1,594,316,654 | 2,147,483,647 | PyPy 3 | OK | TESTS | 36 | 997 | 38,092,800 |
from collections import deque, Counter, OrderedDict,defaultdict
def is_bipartite(graph):
n = len(graph)
color = [-1] *(n+1)
for start in range(1,n+1):
if color[start] == -1:
color[start] = 0
stack = [start]
while stack:
parent ... | Title: Mahmoud and Ehab and the bipartiteness
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab continue their adventures! As everybody in the evil land knows, Dr. Evil likes bipartite graphs, especially trees.
A tree is a connected acyclic graph. A bipartite graph is a gra... | ```python
from collections import deque, Counter, OrderedDict,defaultdict
def is_bipartite(graph):
n = len(graph)
color = [-1] *(n+1)
for start in range(1,n+1):
if color[start] == -1:
color[start] = 0
stack = [start]
while stack:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
435 | B | Pasha Maximizes | PROGRAMMING | 1,400 | [
"greedy"
] | null | null | Pasha has a positive integer *a* without leading zeroes. Today he decided that the number is too small and he should make it larger. Unfortunately, the only operation Pasha can do is to swap two adjacent decimal digits of the integer.
Help Pasha count the maximum number he can get if he has the time to make at most *k... | The single line contains two integers *a* and *k* (1<=≤<=*a*<=≤<=1018; 0<=≤<=*k*<=≤<=100). | Print the maximum number that Pasha can get if he makes at most *k* swaps. | [
"1990 1\n",
"300 0\n",
"1034 2\n",
"9090000078001234 6\n"
] | [
"9190\n",
"300\n",
"3104\n",
"9907000008001234\n"
] | none | 1,000 | [
{
"input": "1990 1",
"output": "9190"
},
{
"input": "300 0",
"output": "300"
},
{
"input": "1034 2",
"output": "3104"
},
{
"input": "9090000078001234 6",
"output": "9907000008001234"
},
{
"input": "1234 3",
"output": "4123"
},
{
"input": "5 100",
"... | 1,641,019,727 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 93 | 0 | s,k =input().split()
s = list(s)
k = int(k)
for _ in range(k):
for i in range(len(s)-1):
if s[i] < s[i+1]:
s[i],s[i+1]=s[i+1],s[i]
break
print(''.join(s)) | Title: Pasha Maximizes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a positive integer *a* without leading zeroes. Today he decided that the number is too small and he should make it larger. Unfortunately, the only operation Pasha can do is to swap two adjacent decimal digits ... | ```python
s,k =input().split()
s = list(s)
k = int(k)
for _ in range(k):
for i in range(len(s)-1):
if s[i] < s[i+1]:
s[i],s[i+1]=s[i+1],s[i]
break
print(''.join(s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
114 | A | Cifera | PROGRAMMING | 1,000 | [
"math"
] | null | null | When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousand and "tma tmyschaya" (which literally means "the tma of tmas") used to stand for a million... | The first input line contains integer number *k*, the second line contains integer number *l* (2<=≤<=*k*,<=*l*<=≤<=231<=-<=1). | You should print in the first line of the output "YES", if the number belongs to the set petriciumus cifera and otherwise print "NO". If the number belongs to the set, then print on the seconds line the only number — the importance of number *l*. | [
"5\n25\n",
"3\n8\n"
] | [
"YES\n1\n",
"NO\n"
] | none | 500 | [
{
"input": "5\n25",
"output": "YES\n1"
},
{
"input": "3\n8",
"output": "NO"
},
{
"input": "123\n123",
"output": "YES\n0"
},
{
"input": "99\n970300",
"output": "NO"
},
{
"input": "1000\n6666666",
"output": "NO"
},
{
"input": "59\n3571",
"output": "N... | 1,603,177,960 | 2,147,483,647 | PyPy 3 | OK | TESTS | 64 | 280 | 0 | from sys import stdin,stdout
n=int(stdin.readline())
m=int(stdin.readline())
test=n
ans=0
while m>test:
test*=n
ans+=1
if m==test:
stdout.write('YES'+'\n')
stdout.write(str(ans)+'\n')
else:
stdout.write('NO'+'\n')
| Title: Cifera
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Petya went to school, he got interested in large numbers and what they were called in ancient times. For instance, he learned that the Russian word "tma" (which now means "too much to be counted") used to stand for a thousa... | ```python
from sys import stdin,stdout
n=int(stdin.readline())
m=int(stdin.readline())
test=n
ans=0
while m>test:
test*=n
ans+=1
if m==test:
stdout.write('YES'+'\n')
stdout.write(str(ans)+'\n')
else:
stdout.write('NO'+'\n')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
322 | B | Ciel and Flowers | PROGRAMMING | 1,600 | [
"combinatorics",
"math"
] | null | null | Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red flowers. - To make a "green bouquet", it needs 3 green flowers. - To make a "blue bouquet", it needs 3... | The first line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=109) — the number of red, green and blue flowers. | Print the maximal number of bouquets Fox Ciel can make. | [
"3 6 9\n",
"4 4 4\n",
"0 0 0\n"
] | [
"6\n",
"4\n",
"0\n"
] | In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.
In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet. | 1,000 | [
{
"input": "3 6 9",
"output": "6"
},
{
"input": "4 4 4",
"output": "4"
},
{
"input": "0 0 0",
"output": "0"
},
{
"input": "0 3 6",
"output": "3"
},
{
"input": "7 8 9",
"output": "7"
},
{
"input": "8 8 9",
"output": "8"
},
{
"input": "15 3 9... | 1,610,355,929 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 186 | 0 | a, b, c = map(int, input().split())
ans = 0
for i in range(3):
k = min(i, a, b, c)
x, y, z = a-k, b-k, c-k
ans = max(ans, (x//3)+(y//3)+(z//3) + k)
print(ans) | Title: Ciel and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red fl... | ```python
a, b, c = map(int, input().split())
ans = 0
for i in range(3):
k = min(i, a, b, c)
x, y, z = a-k, b-k, c-k
ans = max(ans, (x//3)+(y//3)+(z//3) + k)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
631 | C | Report | PROGRAMMING | 1,700 | [
"data structures",
"sortings"
] | null | null | Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that denotes corresponding revenue. Before the report gets to Blake, it passes through the hands... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the number of commodities in the report and the number of managers, respectively.
The second line contains *n* integers *a**i* (|*a**i*|<=≤<=109) — the initial report before it gets to the first manager.
Then follow *m* lin... | Print *n* integers — the final report, which will be passed to Blake by manager number *m*. | [
"3 1\n1 2 3\n2 2\n",
"4 2\n1 2 4 3\n2 3\n1 2\n"
] | [
"2 1 3 ",
"2 4 1 3 "
] | In the first sample, the initial report looked like: 1 2 3. After the first manager the first two numbers were transposed: 2 1 3. The report got to Blake in this form.
In the second sample the original report was like this: 1 2 4 3. After the first manager the report changed to: 4 2 1 3. After the second manager the r... | 1,500 | [
{
"input": "3 1\n1 2 3\n2 2",
"output": "2 1 3 "
},
{
"input": "4 2\n1 2 4 3\n2 3\n1 2",
"output": "2 4 1 3 "
},
{
"input": "4 1\n4 3 2 1\n1 4",
"output": "1 2 3 4 "
},
{
"input": "5 1\n1 2 3 4 5\n2 5",
"output": "5 4 3 2 1 "
},
{
"input": "6 2\n3 1 2 6 4 5\n1 6\n... | 1,459,827,600 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 31,846,400 | n,m = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
manager = []
for i in range(m):
t = [int(j) for j in input().split()]
manager.append(t)
manager.sort(key = lambda manager:manager[1],reverse = True)
result = []
if manager[0][1] < len(a):
result.extend(a[manager[0][1]:])
... | Title: Report
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that... | ```python
n,m = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
manager = []
for i in range(m):
t = [int(j) for j in input().split()]
manager.append(t)
manager.sort(key = lambda manager:manager[1],reverse = True)
result = []
if manager[0][1] < len(a):
result.extend(a[manager... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
44 | B | Cola | PROGRAMMING | 1,500 | [
"implementation"
] | B. Cola | 2 | 256 | To celebrate the opening of the Winter Computer School the organizers decided to buy in *n* liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly *a* bottles 0.5 in volume, *b* one-liter bottles and *c... | The first line contains four integers — *n*, *a*, *b*, *c* (1<=≤<=*n*<=≤<=10000, 0<=≤<=*a*,<=*b*,<=*c*<=≤<=5000). | Print the unique number — the solution to the problem. If it is impossible to buy exactly *n* liters of cola, print 0. | [
"10 5 5 5\n",
"3 0 0 2\n"
] | [
"9\n",
"0\n"
] | none | 0 | [
{
"input": "10 5 5 5",
"output": "9"
},
{
"input": "3 0 0 2",
"output": "0"
},
{
"input": "1 0 0 0",
"output": "0"
},
{
"input": "1 1 0 0",
"output": "0"
},
{
"input": "1 2 0 0",
"output": "1"
},
{
"input": "1 0 1 0",
"output": "1"
},
{
"in... | 1,665,485,479 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | import sys
input = sys.stdin.readline
n, a, b, c = map(int, input().split())
M = 2 << 30
x = min(c, n//2)
y = min(b, a//2)
y1 = max(b, a//2)
z = b + a//2
ew = 0
while x >= 0:
s = n - x*2
if s > z:
break
ew += min(s, y, z - s) + 1
x -= 1
print(ew) | Title: Cola
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
To celebrate the opening of the Winter Computer School the organizers decided to buy in *n* liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volu... | ```python
import sys
input = sys.stdin.readline
n, a, b, c = map(int, input().split())
M = 2 << 30
x = min(c, n//2)
y = min(b, a//2)
y1 = max(b, a//2)
z = b + a//2
ew = 0
while x >= 0:
s = n - x*2
if s > z:
break
ew += min(s, y, z - s) + 1
x -= 1
print(ew)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
820 | A | Mister B and Book Reading | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, starting from the second, he read *a* pages more than on the previous day (at first day he read *v*0 pages, at ... | First and only line contains five space-separated integers: *c*, *v*0, *v*1, *a* and *l* (1<=≤<=*c*<=≤<=1000, 0<=≤<=*l*<=<<=*v*0<=≤<=*v*1<=≤<=1000, 0<=≤<=*a*<=≤<=1000) — the length of the book in pages, the initial reading speed, the maximum reading speed, the acceleration in reading speed and the number of pages fo... | Print one integer — the number of days Mister B needed to finish the book. | [
"5 5 10 5 4\n",
"12 4 12 4 1\n",
"15 1 100 0 0\n"
] | [
"1\n",
"3\n",
"15\n"
] | In the first sample test the book contains 5 pages, so Mister B read it right at the first day.
In the second sample test at first day Mister B read pages number 1 - 4, at second day — 4 - 11, at third day — 11 - 12 and finished the book.
In third sample test every day Mister B read 1 page of the book, so he finished... | 500 | [
{
"input": "5 5 10 5 4",
"output": "1"
},
{
"input": "12 4 12 4 1",
"output": "3"
},
{
"input": "15 1 100 0 0",
"output": "15"
},
{
"input": "1 1 1 0 0",
"output": "1"
},
{
"input": "1000 999 1000 1000 998",
"output": "2"
},
{
"input": "1000 2 2 5 1",
... | 1,498,574,676 | 576 | Python 3 | OK | TESTS | 110 | 93 | 5,529,600 | c, v0, v1, a, l = map(int, input().split())
v = v0
p = 0
ans = 0
while p < c:
if p != 0:
p -= l
p += v
v = min(v + a, v1)
ans += 1
print(ans)
| Title: Mister B and Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mister B once received a gift: it was a book about aliens, which he started read immediately. This book had *c* pages.
At first day Mister B read *v*0 pages, but after that he started to speed up. Every day, ... | ```python
c, v0, v1, a, l = map(int, input().split())
v = v0
p = 0
ans = 0
while p < c:
if p != 0:
p -= l
p += v
v = min(v + a, v1)
ans += 1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
792 | A | New Bus Route | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from one city to another only by bus. But all buses and roads are very old, so the Minister of Transport d... | The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). All numbers *a**i* are pairwise distinct. | Print two integer numbers — the minimal distance and the quantity of pairs with this distance. | [
"4\n6 -3 0 4\n",
"3\n-2 0 2\n"
] | [
"2 1\n",
"2 2\n"
] | In the first example the distance between the first city and the fourth city is |4 - 6| = 2, and it is the only pair with this distance. | 0 | [
{
"input": "4\n6 -3 0 4",
"output": "2 1"
},
{
"input": "3\n-2 0 2",
"output": "2 2"
},
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "2\n1000000000 -1000000000",
"output": "2000000000 1"
},
{
"input": "5\n-979619606 -979619602 -979619604 -979619605 -97961960... | 1,671,376,101 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 45 | 155 | 27,545,600 | n=int(input())
a=list(map(int,input().split()))
a.sort()
b=[]
for i in range(1,n):
b.append(a[i]-a[i-1])
b.sort()
c=b[0]
d=b.count(c)
print(c,d) | Title: New Bus Route
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from on... | ```python
n=int(input())
a=list(map(int,input().split()))
a.sort()
b=[]
for i in range(1,n):
b.append(a[i]-a[i-1])
b.sort()
c=b[0]
d=b.count(c)
print(c,d)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
498 | A | Crazy Town | PROGRAMMING | 1,700 | [
"geometry"
] | null | null | Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the plane into connected regions, possibly of infinite space. Let's call each such region a block. We ... | The first line contains two space-separated integers *x*1, *y*1 (<=-<=106<=≤<=*x*1,<=*y*1<=≤<=106) — the coordinates of your home.
The second line contains two integers separated by a space *x*2, *y*2 (<=-<=106<=≤<=*x*2,<=*y*2<=≤<=106) — the coordinates of the university you are studying at.
The third line contains a... | Output the answer to the problem. | [
"1 1\n-1 -1\n2\n0 1 0\n1 0 0\n",
"1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3\n"
] | [
"2\n",
"2\n"
] | Pictures to the samples are presented below (A is the point representing the house; B is the point representing the university, different blocks are filled with different colors): | 500 | [
{
"input": "1 1\n-1 -1\n2\n0 1 0\n1 0 0",
"output": "2"
},
{
"input": "1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3",
"output": "2"
},
{
"input": "841746 527518\n595261 331297\n10\n-946901 129987 670374\n-140388 -684770 309555\n-302589 415564 -387435\n-565799 -72069 -395358\n-523453 -511446 85489... | 1,553,618,810 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 108 | 0 | x,y=input().split()
x,y=[int(x),int(y)]
a,b=input().split()
a,b=[int(a),int(b)]
n=int(input())
counter=0
for i in range(n):
p,q,r=input().split()
p,q,r=[int(p),int(q),int(r)]
q1=p*x+q*y+r
q2=p*a+q*b+r
if q1>0 and q2<0 or q1<0 and q2>0:
counter+=1
print(counter)
| Title: Crazy Town
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the pl... | ```python
x,y=input().split()
x,y=[int(x),int(y)]
a,b=input().split()
a,b=[int(a),int(b)]
n=int(input())
counter=0
for i in range(n):
p,q,r=input().split()
p,q,r=[int(p),int(q),int(r)]
q1=p*x+q*y+r
q2=p*a+q*b+r
if q1>0 and q2<0 or q1<0 and q2>0:
counter+=1
print(counter)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
895 | A | Pizza Separation | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | Students Vasya and Petya are studying at the BSU (Byteland State University). At one of the breaks they decided to order a pizza. In this problem pizza is a circle of some radius. The pizza was delivered already cut into *n* pieces. The *i*-th piece is a sector of angle equal to *a**i*. Vasya and Petya want to divide a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=360) — the number of pieces into which the delivered pizza was cut.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=360) — the angles of the sectors into which the pizza was cut. The sum of all *a**i* is 360. | Print one integer — the minimal difference between angles of sectors that will go to Vasya and Petya. | [
"4\n90 90 90 90\n",
"3\n100 100 160\n",
"1\n360\n",
"4\n170 30 150 10\n"
] | [
"0\n",
"40\n",
"360\n",
"0\n"
] | In first sample Vasya can take 1 and 2 pieces, Petya can take 3 and 4 pieces. Then the answer is |(90 + 90) - (90 + 90)| = 0.
In third sample there is only one piece of pizza that can be taken by only one from Vasya and Petya. So the answer is |360 - 0| = 360.
In fourth sample Vasya can take 1 and 4 pieces, then Pety... | 500 | [
{
"input": "4\n90 90 90 90",
"output": "0"
},
{
"input": "3\n100 100 160",
"output": "40"
},
{
"input": "1\n360",
"output": "360"
},
{
"input": "4\n170 30 150 10",
"output": "0"
},
{
"input": "5\n10 10 10 10 320",
"output": "280"
},
{
"input": "8\n45 4... | 1,511,718,143 | 5,843 | Python 3 | RUNTIME_ERROR | PRETESTS | 0 | 77 | 6,041,600 | import random
n = int(input())
while(n>360 and n<0):
n = int(input('Enter n: '))
arr = []
sum1 = 0
while(len(arr)<(n-1)):
arr=int(input())
if(arr<=(360-sum1)):
sum1 += arr
arr.append(arr)
arr.append(360-sum1)
def quicksort(first,last):
f = first
l = last
piv = arr... | Title: Pizza Separation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Students Vasya and Petya are studying at the BSU (Byteland State University). At one of the breaks they decided to order a pizza. In this problem pizza is a circle of some radius. The pizza was delivered already cut in... | ```python
import random
n = int(input())
while(n>360 and n<0):
n = int(input('Enter n: '))
arr = []
sum1 = 0
while(len(arr)<(n-1)):
arr=int(input())
if(arr<=(360-sum1)):
sum1 += arr
arr.append(arr)
arr.append(360-sum1)
def quicksort(first,last):
f = first
l = last
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
259 | B | Little Elephant and Magic Square | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals ... | The first three lines of the input contain the Little Elephant's notes. The first line contains elements of the first row of the magic square. The second line contains the elements of the second row, the third line is for the third row. The main diagonal elements that have been forgotten by the Elephant are represented... | Print three lines, in each line print three integers — the Little Elephant's magic square. If there are multiple magic squares, you are allowed to print any of them. Note that all numbers you print must be positive and not exceed 105.
It is guaranteed that there exists at least one magic square that meets the conditio... | [
"0 1 1\n1 0 1\n1 1 0\n",
"0 3 6\n5 0 5\n4 7 0\n"
] | [
"1 1 1\n1 1 1\n1 1 1\n",
"6 3 6\n5 5 5\n4 7 4\n"
] | none | 1,000 | [
{
"input": "0 1 1\n1 0 1\n1 1 0",
"output": "1 1 1\n1 1 1\n1 1 1"
},
{
"input": "0 3 6\n5 0 5\n4 7 0",
"output": "6 3 6\n5 5 5\n4 7 4"
},
{
"input": "0 4 4\n4 0 4\n4 4 0",
"output": "4 4 4\n4 4 4\n4 4 4"
},
{
"input": "0 54 48\n36 0 78\n66 60 0",
"output": "69 54 48\n36 5... | 1,610,944,868 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 124 | 0 | if __name__ == '__main__':
ans = [[int(i) for i in input().split()] for _ in range(3)]
s = sum([sum(i) for i in ans]) // 2
for i in range(3):
ans[i][i] = s - sum(ans[i])
print("\n".join([" ".join(["{}".format(i) for i in row]) for row in ans])) | Title: Little Elephant and Magic Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table ... | ```python
if __name__ == '__main__':
ans = [[int(i) for i in input().split()] for _ in range(3)]
s = sum([sum(i) for i in ans]) // 2
for i in range(3):
ans[i][i] = s - sum(ans[i])
print("\n".join([" ".join(["{}".format(i) for i in row]) for row in ans]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
834 | B | The Festive Evening | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here are not supposed to be disclosed to the general public: the information can cause discord in the kingdom... | Two integers are given in the first string: the number of guests *n* and the number of guards *k* (1<=≤<=*n*<=≤<=106, 1<=≤<=*k*<=≤<=26).
In the second string, *n* uppercase English letters *s*1*s*2... *s**n* are given, where *s**i* is the entrance used by the *i*-th guest. | Output «YES» if at least one door was unguarded during some time, and «NO» otherwise.
You can output each letter in arbitrary case (upper or lower). | [
"5 1\nAABBB\n",
"5 1\nABABB\n"
] | [
"NO\n",
"YES\n"
] | In the first sample case, the door A is opened right before the first guest's arrival and closed when the second guest enters the castle. The door B is opened right before the arrival of the third guest, and closed after the fifth one arrives. One guard can handle both doors, as the first one is closed before the secon... | 1,000 | [
{
"input": "5 1\nAABBB",
"output": "NO"
},
{
"input": "5 1\nABABB",
"output": "YES"
},
{
"input": "26 1\nABCDEFGHIJKLMNOPQRSTUVWXYZ",
"output": "NO"
},
{
"input": "27 1\nABCDEFGHIJKLMNOPQRSTUVWXYZA",
"output": "YES"
},
{
"input": "5 2\nABACA",
"output": "NO"
... | 1,610,118,835 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 343 | 7,577,600 | n, k = map(int,input().split())
A = input()
D = dict()
B = [0] * len(A)
for i in range(len(A)):
if A[i] not in D:
D[A[i]] = [i,i]
else:
D[A[i]][1] = i
#print(D)
flag = 0
for elem in D:
t = D[elem][0]
p = D[elem][1]
for i in range(t,p+1):
B[i] += 1
#print(B)
f... | Title: The Festive Evening
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the end of July – the time when a festive evening is held at Jelly Castle! Guests from all over the kingdom gather here to discuss new trends in the world of confectionery. Yet some of the things discussed here... | ```python
n, k = map(int,input().split())
A = input()
D = dict()
B = [0] * len(A)
for i in range(len(A)):
if A[i] not in D:
D[A[i]] = [i,i]
else:
D[A[i]][1] = i
#print(D)
flag = 0
for elem in D:
t = D[elem][0]
p = D[elem][1]
for i in range(t,p+1):
B[i] += 1
#p... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,603,892,385 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 307,200 | n, x = map(int,input().split(' '))
print(n + x)
n = int(n)
x = int(x)
icVal = x
dCount = 0
while n > 0:
a, b = input().split(' ')
print(a + b)
b = int(b)
if a == '-':
b = b * -1
if (icVal + b) > 0:
icVal = icVal + b
else:
dCount = dCount + 1
n = n ... | Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
n, x = map(int,input().split(' '))
print(n + x)
n = int(n)
x = int(x)
icVal = x
dCount = 0
while n > 0:
a, b = input().split(' ')
print(a + b)
b = int(b)
if a == '-':
b = b * -1
if (icVal + b) > 0:
icVal = icVal + b
else:
dCount = dCount + 1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,697,271,771 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 35 | 2,000 | 14,233,600 | import random
def is_prime(n, k=5):
if n <= 1:
return False
if n <= 3:
return True
def witness(a, n):
t = n - 1
s = 0
while t % 2 == 0:
t //= 2
s += 1
x = pow(a, t, n)
if x == 1 or x == n - 1:
ret... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
import random
def is_prime(n, k=5):
if n <= 1:
return False
if n <= 3:
return True
def witness(a, n):
t = n - 1
s = 0
while t % 2 == 0:
t //= 2
s += 1
x = pow(a, t, n)
if x == 1 or x == n - 1:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,634,405,232 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | a,b,c=sorted(map(int,input().split))
if a+b>c:
print(0)
else:
print(c+1-a-b) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
a,b,c=sorted(map(int,input().split))
if a+b>c:
print(0)
else:
print(c+1-a-b)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
606 | A | Magic Spheres | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible,... | The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal.
The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number o... | If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No". | [
"4 4 0\n2 1 2\n",
"5 6 1\n2 7 2\n",
"3 3 3\n2 2 2\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what... | 500 | [
{
"input": "4 4 0\n2 1 2",
"output": "Yes"
},
{
"input": "5 6 1\n2 7 2",
"output": "No"
},
{
"input": "3 3 3\n2 2 2",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 0",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 1",
"output": "No"
},
{
"input": "0 1 0\n0 0 0... | 1,655,551,031 | 2,147,483,647 | PyPy 3 | OK | TESTS | 79 | 93 | 0 | import sys
input = sys.stdin.readline
a, b, c = map(int, input().split())
x, y, z = map(int, input().split())
a1 = a-x
b1 = b-y
c1 = c-z
x = 0
y = 0
for i in [a1,b1,c1]:
if i > 0:
x += i//2
else:
y -= i
if x >= y:
print('Yes')
else:
print('No') | Title: Magic Spheres
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been see... | ```python
import sys
input = sys.stdin.readline
a, b, c = map(int, input().split())
x, y, z = map(int, input().split())
a1 = a-x
b1 = b-y
c1 = c-z
x = 0
y = 0
for i in [a1,b1,c1]:
if i > 0:
x += i//2
else:
y -= i
if x >= y:
print('Yes')
else:
print('No')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,574,999,847 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | import math
n = int(input())
p = math.floor(math.log2(0.25*n+1))
print(math.ceil((n-4*(2**p-1))/2**p)) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
import math
n = int(input())
p = math.floor(math.log2(0.25*n+1))
print(math.ceil((n-4*(2**p-1))/2**p))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
747 | E | Comments | PROGRAMMING | 1,700 | [
"dfs and similar",
"expression parsing",
"implementation",
"strings"
] | null | null | A rare article in the Internet is posted without a possibility to comment it. On a Polycarp's website each article has comments feed.
Each comment on Polycarp's website is a non-empty string consisting of uppercase and lowercase letters of English alphabet. Comments have tree-like structure, that means each comment ex... | The first line contains non-empty comments feed in the described format. It consists of uppercase and lowercase letters of English alphabet, digits and commas.
It is guaranteed that each comment is a non-empty string consisting of uppercase and lowercase English characters. Each of the number of comments is integer (... | Print comments in a format that is given in the statement. For each level of nesting, comments should be printed in the order they are given in the input. | [
"hello,2,ok,0,bye,0,test,0,one,1,two,2,a,0,b,0\n",
"a,5,A,0,a,0,A,0,a,0,A,0\n",
"A,3,B,2,C,0,D,1,E,0,F,1,G,0,H,1,I,1,J,0,K,1,L,0,M,2,N,0,O,1,P,0\n"
] | [
"3\nhello test one \nok bye two \na b \n",
"2\na \nA a A a A \n",
"4\nA K M \nB F H L N O \nC D G I P \nE J \n"
] | The first example is explained in the statements. | 2,000 | [
{
"input": "hello,2,ok,0,bye,0,test,0,one,1,two,2,a,0,b,0",
"output": "3\nhello test one \nok bye two \na b "
},
{
"input": "a,5,A,0,a,0,A,0,a,0,A,0",
"output": "2\na \nA a A a A "
},
{
"input": "A,3,B,2,C,0,D,1,E,0,F,1,G,0,H,1,I,1,J,0,K,1,L,0,M,2,N,0,O,1,P,0",
"output": "4\nA K M \n... | 1,562,733,292 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 218 | 2,560,000 | import psyco
psyco.full()
import sys
Rcomments = list(sys.stdin.readline().strip().split(","))
comments=[]
for i in range(0,len(Rcomments),2):
comments.append([Rcomments[i],int(Rcomments[i+1])])
cind=0
ans = ["" for i in range(len(comments))]
def assign(val):
global cind
ans[val] += (comments[cind][0]+... | Title: Comments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A rare article in the Internet is posted without a possibility to comment it. On a Polycarp's website each article has comments feed.
Each comment on Polycarp's website is a non-empty string consisting of uppercase and lowerc... | ```python
import psyco
psyco.full()
import sys
Rcomments = list(sys.stdin.readline().strip().split(","))
comments=[]
for i in range(0,len(Rcomments),2):
comments.append([Rcomments[i],int(Rcomments[i+1])])
cind=0
ans = ["" for i in range(len(comments))]
def assign(val):
global cind
ans[val] += (comments... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
120 | B | Quiz League | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a question and the experts are allowed a minute on brainstorming and finding the right answer to the que... | The first line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=1000 and 1<=≤<=*k*<=≤<=*n*) — the numbers of sectors on the table and the number of the sector where the arrow is pointing. The second line contains *n* numbers: *a**i*<==<=0 if the question from sector *i* has already been asked and *a**i*<==<=1 ... | Print the single number — the number of the sector containing the question the experts will be asked. It is guaranteed that the answer exists, that is that not all the questions have already been asked. | [
"5 5\n0 1 0 1 0\n",
"2 1\n1 1\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "5 5\n0 1 0 1 0",
"output": "2"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "3 2\n1 0 0",
"output": "1"
},
{
"input": "3 3\n0 1 0",
"output": "2"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "6 3\n0 0 1 1 0 1",
"output":... | 1,611,496,816 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | import sys
sys.stdin = open(r'input.txt', 'r')
sys.stdout = open(r'output.txt', 'w')
n, k = map(int, input().split())
arr = list(map(int, input().split()))
for i in range(k-1,2*n):
pos=i%n
if arr[pos]==1:
print(pos+1)
break | Title: Quiz League
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a quest... | ```python
import sys
sys.stdin = open(r'input.txt', 'r')
sys.stdout = open(r'output.txt', 'w')
n, k = map(int, input().split())
arr = list(map(int, input().split()))
for i in range(k-1,2*n):
pos=i%n
if arr[pos]==1:
print(pos+1)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,618,371,238 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 32 | 622 | 5,222,400 | n=int(input())
sa=[]
sb=[]
for i in range(n):
a,b=map(int,input().split())
sa.append(a)
sb.append(b)
mi=100000000
ma=-1
f=0
for i in range(n):
if sa[i]<mi:
mi=sa[i]
if sb[i]>ma:
ma=sb[i]
for i in range(n):
if sa[i]==mi and sb[i]==ma:
f=1
break
... | Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
n=int(input())
sa=[]
sb=[]
for i in range(n):
a,b=map(int,input().split())
sa.append(a)
sb.append(b)
mi=100000000
ma=-1
f=0
for i in range(n):
if sa[i]<mi:
mi=sa[i]
if sb[i]>ma:
ma=sb[i]
for i in range(n):
if sa[i]==mi and sb[i]==ma:
f=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
632 | E | Thief in a Shop | PROGRAMMING | 2,400 | [
"divide and conquer",
"dp",
"fft",
"math"
] | null | null | A thief made his way to a shop.
As usual he has his lucky knapsack with him. The knapsack can contain *k* objects. There are *n* kinds of products in the shop and an infinite number of products of each kind. The cost of one product of kind *i* is *a**i*.
The thief is greedy, so he will take exactly *k* products (it's... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1000) — the number of kinds of products and the number of products the thief will take.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=1000) — the costs of products for kinds from 1 to *n*. | Print the only line with all the possible total costs of stolen products, separated by a space. The numbers should be printed in the ascending order. | [
"3 2\n1 2 3\n",
"5 5\n1 1 1 1 1\n",
"3 3\n3 5 11\n"
] | [
"2 3 4 5 6\n",
"5\n",
"9 11 13 15 17 19 21 25 27 33\n"
] | none | 0 | [
{
"input": "3 2\n1 2 3",
"output": "2 3 4 5 6"
},
{
"input": "5 5\n1 1 1 1 1",
"output": "5"
},
{
"input": "3 3\n3 5 11",
"output": "9 11 13 15 17 19 21 25 27 33"
},
{
"input": "10 3\n3 4 12 5 7 13 5 6 1 6",
"output": "3 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23... | 1,539,927,988 | 6,448 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 5,000 | 921,600 | #import sys
#sys.stdin = open('in', 'r')
#n = int(input())
#a = [int(x) for x in input().split()]
n,k = map(int, input().split())
a = [int(x) for x in input().split()]
hss = [set() for i in range(k)]
hsprev = set()
hscur = set()
for ai in a:
hscur.add(ai)
for level in range(1, k):
hsprev = hscur
... | Title: Thief in a Shop
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A thief made his way to a shop.
As usual he has his lucky knapsack with him. The knapsack can contain *k* objects. There are *n* kinds of products in the shop and an infinite number of products of each kind. The cost o... | ```python
#import sys
#sys.stdin = open('in', 'r')
#n = int(input())
#a = [int(x) for x in input().split()]
n,k = map(int, input().split())
a = [int(x) for x in input().split()]
hss = [set() for i in range(k)]
hsprev = set()
hscur = set()
for ai in a:
hscur.add(ai)
for level in range(1, k):
hsprev... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,600,797,655 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 0 | n, v = map(int, input().split())
ans = []
for i in range(n):
a = list(map(int, input().split()))[1:]
if v > min(a):
ans.append(i + 1)
print(len(ans))
print(*ans)
| Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
n, v = map(int, input().split())
ans = []
for i in range(n):
a = list(map(int, input().split()))[1:]
if v > min(a):
ans.append(i + 1)
print(len(ans))
print(*ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
382 | C | Arithmetic Progression | PROGRAMMING | 1,700 | [
"implementation",
"sortings"
] | null | null | Everybody knows what an arithmetic progression is. Let us remind you just in case that an arithmetic progression is such sequence of numbers *a*1,<=*a*2,<=...,<=*a**n* of length *n*, that the following condition fulfills:
For example, sequences [1, 5], [10], [5, 4, 3] are arithmetic progressions and sequences [1, 3, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of cards. The next line contains the sequence of integers — the numbers on Alexander's cards. The numbers are positive integers, each of them doesn't exceed 108. | If Arthur can write infinitely many distinct integers on the card, print on a single line -1.
Otherwise, print on the first line the number of integers that suit you. In the second line, print the numbers in the increasing order. Note that the numbers in the answer can exceed 108 or even be negative (see test samples)... | [
"3\n4 1 7\n",
"1\n10\n",
"4\n1 3 5 9\n",
"4\n4 3 4 5\n",
"2\n2 4\n"
] | [
"2\n-2 10\n",
"-1\n",
"1\n7\n",
"0\n",
"3\n0 3 6\n"
] | none | 1,500 | [
{
"input": "3\n4 1 7",
"output": "2\n-2 10"
},
{
"input": "1\n10",
"output": "-1"
},
{
"input": "4\n1 3 5 9",
"output": "1\n7"
},
{
"input": "4\n4 3 4 5",
"output": "0"
},
{
"input": "2\n2 4",
"output": "3\n0 3 6"
},
{
"input": "4\n1 3 4 5",
"outpu... | 1,590,434,288 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 204,800 | n=int(input())
temp=[]
list=[int(i) for i in input().split()]
list.sort()
if(n==1):
print("-1")
exit()
for i in range(n-1):
temp.append(list[i+1]-list[i])
if(min(temp)!=max(temp)):
print("0")
exit()
else:
print("1")
print(list[n-1]+(list[1]-list[0])) | Title: Arithmetic Progression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Everybody knows what an arithmetic progression is. Let us remind you just in case that an arithmetic progression is such sequence of numbers *a*1,<=*a*2,<=...,<=*a**n* of length *n*, that the following condition ... | ```python
n=int(input())
temp=[]
list=[int(i) for i in input().split()]
list.sort()
if(n==1):
print("-1")
exit()
for i in range(n-1):
temp.append(list[i+1]-list[i])
if(min(temp)!=max(temp)):
print("0")
exit()
else:
print("1")
print(list[n-1]+(list[1]-list[0]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,378,541,607 | 807 | Python 3 | OK | TESTS | 45 | 780 | 1,638,400 |
if __name__=='__main__':
N = int(input())
L = [0,0,0,0,0,0,0,0]
inp = input()
for i in inp.split(' '):
L[int(i)]+=1
it = N//3
fnd = True
ans = []
for ic in range(it):
Tl = []
for el in range(len(L)):
if L[el]!=0:
if len(Tl)==0:
... | Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
if __name__=='__main__':
N = int(input())
L = [0,0,0,0,0,0,0,0]
inp = input()
for i in inp.split(' '):
L[int(i)]+=1
it = N//3
fnd = True
ans = []
for ic in range(it):
Tl = []
for el in range(len(L)):
if L[el]!=0:
if len(Tl)==... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,698,492,169 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | # A. Team - https://codeforces.com/contest/231/problem/A
def solve():
n = int(input())
res = 0
for _ in (range(n)):
arr = list(map(int, input().split()))
answer = arr.count(1)
if answer >=2:
res+=1
return res
print(solve())
| Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
# A. Team - https://codeforces.com/contest/231/problem/A
def solve():
n = int(input())
res = 0
for _ in (range(n)):
arr = list(map(int, input().split()))
answer = arr.count(1)
if answer >=2:
res+=1
return res
print(solve())
``` | 3 | MatrixStudio/Codeforces-Python-Submissions |
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