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values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
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values | memory-limit stringclasses 8
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value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,696,353,266 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 20 | 122 | 0 | # n, m = map(int, input().split())
# descr = [list(map(int, input().split())) for _ in range(n)]
# d = [0] * (m + 1)
# for w, p in descr:
# for oldsum in range(m - w, -1, -1):
# d[oldsum + w] = max(d[oldsum + w], d[oldsum] + p)
# print(oldsum, end=" ")
# print()
# for elem in d:
# print(ele... | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
# n, m = map(int, input().split())
# descr = [list(map(int, input().split())) for _ in range(n)]
# d = [0] * (m + 1)
# for w, p in descr:
# for oldsum in range(m - w, -1, -1):
# d[oldsum + w] = max(d[oldsum + w], d[oldsum] + p)
# print(oldsum, end=" ")
# print()
# for elem in d:
# ... | 3.939 | MatrixStudio/Codeforces-Python-Submissions |
570 | B | Simple Game | PROGRAMMING | 1,300 | [
"constructive algorithms",
"games",
"greedy",
"implementation",
"math"
] | null | null | One day Misha and Andrew were playing a very simple game. First, each player chooses an integer in the range from 1 to *n*. Let's assume that Misha chose number *m*, and Andrew chose number *a*.
Then, by using a random generator they choose a random integer *c* in the range between 1 and *n* (any integer from 1 to *n*... | The first line contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the range of numbers in the game, and the number selected by Misha respectively. | Print a single number — such value *a*, that probability that Andrew wins is the highest. If there are multiple such values, print the minimum of them. | [
"3 1\n",
"4 3\n"
] | [
"2",
"2"
] | In the first sample test: Andrew wins if *c* is equal to 2 or 3. The probability that Andrew wins is 2 / 3. If Andrew chooses *a* = 3, the probability of winning will be 1 / 3. If *a* = 1, the probability of winning is 0.
In the second sample test: Andrew wins if *c* is equal to 1 and 2. The probability that Andrew wi... | 1,000 | [
{
"input": "3 1",
"output": "2"
},
{
"input": "4 3",
"output": "2"
},
{
"input": "5 5",
"output": "4"
},
{
"input": "10 5",
"output": "6"
},
{
"input": "20 13",
"output": "12"
},
{
"input": "51 1",
"output": "2"
},
{
"input": "100 50",
... | 1,569,487,718 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 0 | def main():
n, m = map(int, input().split())
if 1 <= m - 1 <= n:
print(m-1)
elif 1 <= m + 1 <= n:
print(m+1)
else:
print(m)
if __name__ == "__main__":
main() | Title: Simple Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Misha and Andrew were playing a very simple game. First, each player chooses an integer in the range from 1 to *n*. Let's assume that Misha chose number *m*, and Andrew chose number *a*.
Then, by using a random gen... | ```python
def main():
n, m = map(int, input().split())
if 1 <= m - 1 <= n:
print(m-1)
elif 1 <= m + 1 <= n:
print(m+1)
else:
print(m)
if __name__ == "__main__":
main()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
934 | A | A Compatible Pair | PROGRAMMING | 1,400 | [
"brute force",
"games"
] | null | null | Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cracking noise, all of which frighten the monster out of coming.
Little Tommy has *n* lanterns and Big B... | The first line contains two space-separated integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=50).
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n*.
The third line contains *m* space-separated integers *b*1,<=*b*2,<=...,<=*b**m*.
All the integers range from <=-<=109 to 109. | Print a single integer — the brightness of the chosen pair. | [
"2 2\n20 18\n2 14\n",
"5 3\n-1 0 1 2 3\n-1 0 1\n"
] | [
"252\n",
"2\n"
] | In the first example, Tommy will hide 20 and Banban will choose 18 from Tommy and 14 from himself.
In the second example, Tommy will hide 3 and Banban will choose 2 from Tommy and 1 from himself. | 500 | [
{
"input": "2 2\n20 18\n2 14",
"output": "252"
},
{
"input": "5 3\n-1 0 1 2 3\n-1 0 1",
"output": "2"
},
{
"input": "10 2\n1 6 2 10 2 3 2 10 6 4\n5 7",
"output": "70"
},
{
"input": "50 50\n1 6 2 10 2 3 2 10 6 4 5 0 3 1 7 3 2 4 4 2 1 5 0 6 10 1 8 0 10 9 0 4 10 5 5 7 4 9 9 5 5 ... | 1,670,580,324 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 77 | 0 | n,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
a.sort(),b.sort()
if(a[0]>=0 and b[0]>=0):
print(a[-2]*b[-1])
elif(a[0]<0 and b[0]>=0 or a[0]>=0 and b[0]<0):
print(a[-2]*b[-1])
else:
ans=1000000001
for i in range(n):
ans1=-1000000001
for j in range(n):
... | Title: A Compatible Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cr... | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
a.sort(),b.sort()
if(a[0]>=0 and b[0]>=0):
print(a[-2]*b[-1])
elif(a[0]<0 and b[0]>=0 or a[0]>=0 and b[0]<0):
print(a[-2]*b[-1])
else:
ans=1000000001
for i in range(n):
ans1=-1000000001
for j in ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
794 | A | Bank Robbery | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and steal some money from the safes. There are many safes arranged in a line, where the *i*-th safe f... | The first line of input contains three space-separated integers, *a*, *b* and *c* (1<=≤<=*b*<=<<=*a*<=<<=*c*<=≤<=109), denoting the positions of Oleg, the first security guard and the second security guard, respectively.
The next line of input contains a single integer *n* (1<=≤<=*n*<=≤<=105), denoting the numbe... | Output a single integer: the maximum number of banknotes Oleg can take. | [
"5 3 7\n8\n4 7 5 5 3 6 2 8\n",
"6 5 7\n5\n1 5 7 92 3\n"
] | [
"4\n",
"0\n"
] | In the first example Oleg can take the banknotes in positions 4, 5, 6 (note that there are 2 banknotes at position 5). Oleg can't take the banknotes in safes 7 and 8 because he can't run into the second security guard. Similarly, Oleg cannot take the banknotes at positions 3 and 2 because he can't run into the first se... | 500 | [
{
"input": "5 3 7\n8\n4 7 5 5 3 6 2 8",
"output": "4"
},
{
"input": "6 5 7\n5\n1 5 7 92 3",
"output": "0"
},
{
"input": "3 2 4\n1\n3",
"output": "1"
},
{
"input": "5 3 8\n12\n8 3 4 5 7 6 8 3 5 4 7 6",
"output": "8"
},
{
"input": "7 3 10\n5\n3 3 3 3 3",
"output... | 1,678,459,843 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define fbo find_by_order
#define ook order_of_key
typedef long long ll;
... | Title: Bank Robbery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and... | ```python
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define fbo find_by_order
#define ook order_of_key
typedef long ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
801 | B | Valued Keys | PROGRAMMING | 900 | [
"constructive algorithms",
"greedy",
"strings"
] | null | null | You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th cha... | The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100. | If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters. | [
"ab\naa\n",
"nzwzl\nniwel\n",
"ab\nba\n"
] | [
"ba\n",
"xiyez\n",
"-1\n"
] | The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba". | 1,000 | [
{
"input": "ab\naa",
"output": "ba"
},
{
"input": "nzwzl\nniwel",
"output": "xiyez"
},
{
"input": "ab\nba",
"output": "-1"
},
{
"input": "r\nl",
"output": "l"
},
{
"input": "d\ny",
"output": "-1"
},
{
"input": "yvowz\ncajav",
"output": "cajav"
},... | 1,492,358,055 | 1,155 | Python 3 | OK | TESTS | 35 | 62 | 5,529,600 | x = input()
y = input()
z = ''
st = False
for i in range(len(x)):
if x[i] < y[i]:
st = True
break
elif x[i] >= y[i]:
z += y[i]
if not st:
print(z)
else:
print(-1) | Title: Valued Keys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string... | ```python
x = input()
y = input()
z = ''
st = False
for i in range(len(x)):
if x[i] < y[i]:
st = True
break
elif x[i] >= y[i]:
z += y[i]
if not st:
print(z)
else:
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,390,579,103 | 1,403 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 46 | 307,200 | s = input()
n = len(s)
ans = 0
lb = 0
for i in range(n - 3):
if s[i:i + 4] == 'bear':
ans += (i-lb)*(n - 1-i)
lb = i+1
print(ans) | Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
s = input()
n = len(s)
ans = 0
lb = 0
for i in range(n - 3):
if s[i:i + 4] == 'bear':
ans += (i-lb)*(n - 1-i)
lb = i+1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
20 | B | Equation | PROGRAMMING | 2,000 | [
"math"
] | B. Equation | 1 | 256 | You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order. | The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=105<=≤<=*A*,<=*B*,<=*C*<=≤<=105). Any coefficient may be equal to 0. | In case of infinite root count print the only integer -1. In case of no roots print the only integer 0. In other cases print the number of root on the first line and the roots on the following lines in the ascending order. Print roots with at least 5 digits after the decimal point. | [
"1 -5 6\n"
] | [
"2\n2.0000000000\n3.0000000000"
] | none | 1,000 | [
{
"input": "1 -5 6",
"output": "2\n2.0000000000\n3.0000000000"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 2 1",
"output": "1\n-1.0000000000"
},
{
"input": "0 0 0",
"output": "-1"
},
{
"input": "0 -2 1",
"output": "1\n0.5000000000"
},
{
"inpu... | 1,682,891,880 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 46 | 0 | import math
def verifyPossibility():
if (A == 0 and B == 0 and C == 0):
return -1
elif (A == 0 and B == 0):
return 0
elif (A == 0):
return 1
else:
return 2
def delta():
return math.pow(B, 2) - 4 * (A) * (C)
def resolveRoots():
roots = set()
roots.add((... | Title: Equation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given an equation:
Your task is to find the number of distinct roots of the equation and print all of them in ascending order.
Input Specification:
The first line contains three integer numbers *A*,<=*B* and *C* (<=-<=1... | ```python
import math
def verifyPossibility():
if (A == 0 and B == 0 and C == 0):
return -1
elif (A == 0 and B == 0):
return 0
elif (A == 0):
return 1
else:
return 2
def delta():
return math.pow(B, 2) - 4 * (A) * (C)
def resolveRoots():
roots = set()
r... | 0 | MatrixStudio/Codeforces-Python-Submissions |
409 | H | A + B Strikes Back | PROGRAMMING | 1,500 | [
"*special",
"brute force",
"constructive algorithms",
"dsu",
"implementation"
] | null | null | A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try? | The input contains two integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=103), separated by a single space. | Output the sum of the given integers. | [
"5 14\n",
"381 492\n"
] | [
"19\n",
"873\n"
] | none | 0 | [
{
"input": "5 14",
"output": "19"
},
{
"input": "381 492",
"output": "873"
},
{
"input": "536 298",
"output": "834"
},
{
"input": "143 522",
"output": "665"
},
{
"input": "433 126",
"output": "559"
},
{
"input": "723 350",
"output": "1073"
},
{... | 1,688,362,014 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | # LUOGU_RID: 113829936
print(sum([int(_) for _ in input().split(" ")])) | Title: A + B Strikes Back
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input ... | ```python
# LUOGU_RID: 113829936
print(sum([int(_) for _ in input().split(" ")]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
261 | B | Maxim and Restaurant | PROGRAMMING | 1,900 | [
"dp",
"math",
"probabilities"
] | null | null | Maxim has opened his own restaurant! The restaurant has got a huge table, the table's length is *p* meters.
Maxim has got a dinner party tonight, *n* guests will come to him. Let's index the guests of Maxim's restaurant from 1 to *n*. Maxim knows the sizes of all guests that are going to come to him. The *i*-th guest'... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of guests in the restaurant. The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=50) — the guests' sizes in meters. The third line contains integer *p* (1<=≤<=*p*<=≤<=50) — the table's length in meters.
The numbers in the lines ... | In a single line print a real number — the answer to the problem. The answer will be considered correct, if the absolute or relative error doesn't exceed 10<=-<=4. | [
"3\n1 2 3\n3\n"
] | [
"1.3333333333\n"
] | In the first sample the people will come in the following orders:
- (1, 2, 3) — there will be two people in the restaurant; - (1, 3, 2) — there will be one person in the restaurant; - (2, 1, 3) — there will be two people in the restaurant; - (2, 3, 1) — there will be one person in the restaurant; - (3, 1, 2) — t... | 1,000 | [
{
"input": "3\n1 2 3\n3",
"output": "1.3333333333"
},
{
"input": "9\n2 2 2 2 2 2 2 1 2\n9",
"output": "4.5555555556"
},
{
"input": "7\n2 1 1 2 1 1 2\n2",
"output": "1.2857142857"
},
{
"input": "8\n3 1 5 6 1 5 4 4\n7",
"output": "1.6250000000"
},
{
"input": "2\n1 3... | 1,686,484,841 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 55 | 186 | 4,608,000 | n = int(input())
a = list(map(int, input().split()))
p = int(input())
f = [1]
for i in range(1, 101):
f.append(f[-1] * i)
dp = [[[0 for _ in range(p + 1)] for __ in range(n + 1)] for ___ in range(n + 1)]
dp[0][0][0] = 1
for i in range(n):
for j in range(i + 1):
for k in range(p + 1):
... | Title: Maxim and Restaurant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maxim has opened his own restaurant! The restaurant has got a huge table, the table's length is *p* meters.
Maxim has got a dinner party tonight, *n* guests will come to him. Let's index the guests of Maxim's rest... | ```python
n = int(input())
a = list(map(int, input().split()))
p = int(input())
f = [1]
for i in range(1, 101):
f.append(f[-1] * i)
dp = [[[0 for _ in range(p + 1)] for __ in range(n + 1)] for ___ in range(n + 1)]
dp[0][0][0] = 1
for i in range(n):
for j in range(i + 1):
for k in range(p + 1):... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,678,893,228 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 967 | 17,305,600 | n,m=map(int,input().split())
a=[int(i)for i in input().split()]
d=set()
s=[]
for i in reversed(a):
d.add(i)
s.append(len(d))
for i in range(m): print(s[-int(input())]) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
n,m=map(int,input().split())
a=[int(i)for i in input().split()]
d=set()
s=[]
for i in reversed(a):
d.add(i)
s.append(len(d))
for i in range(m): print(s[-int(input())])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,689,835,019 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | l=input()
s=""
i=0
n=len(l)
while(i<len(l)):
if(l[i:i+2]=="--"):
s=s+"2"
i=i+2
elif(l[i:i+2]=="-."):
s=s+"1"
i=i+2
elif(l[i]=="."):
s=s+"0"
i=i+1
else:
i=i+1
print(s)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
l=input()
s=""
i=0
n=len(l)
while(i<len(l)):
if(l[i:i+2]=="--"):
s=s+"2"
i=i+2
elif(l[i:i+2]=="-."):
s=s+"1"
i=i+2
elif(l[i]=="."):
s=s+"0"
i=i+1
else:
i=i+1
print(s)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
166 | A | Rank List | PROGRAMMING | 1,100 | [
"binary search",
"implementation",
"sortings"
] | null | null | Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for no team we are shown its final place.
You know the rules of comparing the results of two give... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=50). Then *n* lines contain the description of the teams: the *i*-th line contains two integers *p**i* and *t**i* (1<=≤<=*p**i*,<=*t**i*<=≤<=50) — the number of solved problems and the total penalty time of the *i*-th team, correspondingly. All num... | In the only line print the sought number of teams that got the *k*-th place in the final results' table. | [
"7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10\n",
"5 4\n3 1\n3 1\n5 3\n3 1\n3 1\n"
] | [
"3\n",
"4\n"
] | The final results' table for the first sample is:
- 1-3 places — 4 solved problems, the penalty time equals 10 - 4 place — 3 solved problems, the penalty time equals 20 - 5-6 places — 2 solved problems, the penalty time equals 1 - 7 place — 1 solved problem, the penalty time equals 10
The table shows that the se... | 500 | [
{
"input": "7 2\n4 10\n4 10\n4 10\n3 20\n2 1\n2 1\n1 10",
"output": "3"
},
{
"input": "5 4\n3 1\n3 1\n5 3\n3 1\n3 1",
"output": "4"
},
{
"input": "5 1\n2 2\n1 1\n1 1\n1 1\n2 2",
"output": "2"
},
{
"input": "6 3\n2 2\n3 1\n2 2\n4 5\n2 2\n4 5",
"output": "1"
},
{
"i... | 1,667,600,350 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 184 | 3,072,000 | n, k = [int(j) for j in input().split()]
s = []
for _ in range(n):
s.append([int(j) for j in el.split()])
def contest(arr, k):
arr.sort(key=lambda a: (-a[0], a[1]))
print(s_tup)
res = []
for tup in arr:
if len(res) and res[-1][0] == tup:
res[-1][1] += 1
... | Title: Rank List
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Another programming contest is over. You got hold of the contest's final results table. The table has the following data. For each team we are shown two numbers: the number of problems and the total penalty time. However, for... | ```python
n, k = [int(j) for j in input().split()]
s = []
for _ in range(n):
s.append([int(j) for j in el.split()])
def contest(arr, k):
arr.sort(key=lambda a: (-a[0], a[1]))
print(s_tup)
res = []
for tup in arr:
if len(res) and res[-1][0] == tup:
res[-1][1] += ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
493 | B | Vasya and Wrestling | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of... | The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* poin... | If the first wrestler wins, print string "first", otherwise print "second" | [
"5\n1\n2\n-3\n-4\n3\n",
"3\n-1\n-2\n3\n",
"2\n4\n-4\n"
] | [
"second\n",
"first\n",
"second\n"
] | Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |... | 1,000 | [
{
"input": "5\n1\n2\n-3\n-4\n3",
"output": "second"
},
{
"input": "3\n-1\n-2\n3",
"output": "first"
},
{
"input": "2\n4\n-4",
"output": "second"
},
{
"input": "7\n1\n2\n-3\n4\n5\n-6\n7",
"output": "first"
},
{
"input": "14\n1\n2\n3\n4\n5\n6\n7\n-8\n-9\n-10\n-11\n-... | 1,417,620,734 | 1,934 | Python 3 | OK | TESTS | 57 | 436 | 6,041,600 | n = int(input())
first = []
second = []
last = 0
for i in range(n):
a = int(input())
if a>0:
first.append(a)
else:
second.append(abs(a))
if i==n-1:
last = a
if abs(sum(first))>abs(sum(second)):
print('first')
quit()
if abs(sum(first))<abs(sum(second)):
... | Title: Vasya and Wrestling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers ... | ```python
n = int(input())
first = []
second = []
last = 0
for i in range(n):
a = int(input())
if a>0:
first.append(a)
else:
second.append(abs(a))
if i==n-1:
last = a
if abs(sum(first))>abs(sum(second)):
print('first')
quit()
if abs(sum(first))<abs(sum(seco... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
55 | C | Pie or die | PROGRAMMING | 1,900 | [
"games"
] | C. Pie or die | 2 | 256 | Volodya and Vlad play the following game. There are *k* pies at the cells of *n*<=<=×<=<=*m* board. Each turn Volodya moves one pie to the neighbouring (by side) cell. If the pie lies at the border of the board then Volodya can move it outside the board, get the pie and win. After Volodya's move, Vlad bans some edge at... | First line contains 3 integers, separated by space: 1<=≤<=*n*,<=*m*<=≤<=100 — dimensions of the board and 0<=≤<=*k*<=≤<=100 — the number of pies. Each of the next *k* lines contains 2 integers, separated by space: 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* — coordinates of the corresponding pie. There could be more than one ... | Output only one word: "YES" — if Volodya wins, "NO" — otherwise. | [
"2 2 1\n1 2\n",
"3 4 0\n",
"100 50 2\n50 25\n50 25\n"
] | [
"YES",
"NO",
"NO"
] | none | 1,500 | [
{
"input": "2 2 1\n1 2",
"output": "YES"
},
{
"input": "3 4 0",
"output": "NO"
},
{
"input": "100 50 2\n50 25\n50 25",
"output": "NO"
},
{
"input": "20 20 4\n10 10\n10 10\n10 10\n10 10",
"output": "NO"
},
{
"input": "15 15 1\n8 8",
"output": "NO"
},
{
... | 1,620,761,999 | 2,147,483,647 | PyPy 3 | OK | TESTS | 75 | 218 | 20,172,800 | n,m,k=list(map(int,input().split()))
for i in range(k):
x,y=list(map(int,input().split()))
if min(x,n-x+1,y,m-y+1)<6:
print('YES')
break
else:
print('NO') | Title: Pie or die
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Volodya and Vlad play the following game. There are *k* pies at the cells of *n*<=<=×<=<=*m* board. Each turn Volodya moves one pie to the neighbouring (by side) cell. If the pie lies at the border of the board then Volodya can ... | ```python
n,m,k=list(map(int,input().split()))
for i in range(k):
x,y=list(map(int,input().split()))
if min(x,n-x+1,y,m-y+1)<6:
print('YES')
break
else:
print('NO')
``` | 3.907925 | MatrixStudio/Codeforces-Python-Submissions |
922 | A | Cloning Toys | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applies the machine to a copied toy, he gets two additional copies.
Initially, Imp has only one origina... | The only line contains two integers *x* and *y* (0<=≤<=*x*,<=*y*<=≤<=109) — the number of copies and the number of original toys Imp wants to get (including the initial one). | Print "Yes", if the desired configuration is possible, and "No" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"6 3\n",
"4 2\n",
"1000 1001\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first example, Imp has to apply the machine twice to original toys and then twice to copies. | 500 | [
{
"input": "6 3",
"output": "Yes"
},
{
"input": "4 2",
"output": "No"
},
{
"input": "1000 1001",
"output": "Yes"
},
{
"input": "1000000000 999999999",
"output": "Yes"
},
{
"input": "81452244 81452247",
"output": "No"
},
{
"input": "188032448 86524683",... | 1,573,569,277 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 109 | 0 | lst=list(map(int,input().split()))
if((lst[1]-1)<=0):
print("no")
if((lst[1]-1)>(lst[0])):
print("no")
if((lst[1]-1)<=(lst[0])):
if((lst[1]-1)%2==0):
if((lst[0])%2==0):
print("yes")
else:
print("no")
if((lst[1]-1)%2!=0):
if((lst[0])%2!=0):
... | Title: Cloning Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applie... | ```python
lst=list(map(int,input().split()))
if((lst[1]-1)<=0):
print("no")
if((lst[1]-1)>(lst[0])):
print("no")
if((lst[1]-1)<=(lst[0])):
if((lst[1]-1)%2==0):
if((lst[0])%2==0):
print("yes")
else:
print("no")
if((lst[1]-1)%2!=0):
if((lst[0])... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
869 | B | The Eternal Immortality | PROGRAMMING | 1,100 | [
"math"
] | null | null | Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like this.
The phoenix has a rather long lifespan, and reincarnates itself once every *a*! years. Here *a*! deno... | The first and only line of input contains two space-separated integers *a* and *b* (0<=≤<=*a*<=≤<=*b*<=≤<=1018). | Output one line containing a single decimal digit — the last digit of the value that interests Koyomi. | [
"2 4\n",
"0 10\n",
"107 109\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first example, the last digit of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/99c47ca8b182f097e38094d12f0c06ce0b081b76.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2;
In the second example, the last digit of <img align="middle" class="tex-formula" src="https://espresso... | 1,000 | [
{
"input": "2 4",
"output": "2"
},
{
"input": "0 10",
"output": "0"
},
{
"input": "107 109",
"output": "2"
},
{
"input": "10 13",
"output": "6"
},
{
"input": "998244355 998244359",
"output": "4"
},
{
"input": "999999999000000000 1000000000000000000",
... | 1,636,894,385 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 1,000 | 5,836,800 | from math import factorial
a = list(map(int, input().split()))
print(int(factorial(a[1])/factorial(a[0])) % 10)
| Title: The Eternal Immortality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like... | ```python
from math import factorial
a = list(map(int, input().split()))
print(int(factorial(a[1])/factorial(a[0])) % 10)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,609,850,139 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 20 | 2,000 | 10,240,000 | s = input()
f = 0
ans=""
for i in s:
if f==0 and i=='0':
f=1
else:
ans+=i
if len(s)==len(ans):
ans=ans[:-1]
print(ans) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
s = input()
f = 0
ans=""
for i in s:
if f==0 and i=='0':
f=1
else:
ans+=i
if len(s)==len(ans):
ans=ans[:-1]
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
45 | A | Codecraft III | PROGRAMMING | 900 | [
"implementation"
] | A. Codecraft III | 2 | 256 | Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly *k* months. He looked at the calendar and learned that at the moment is the month number *s*. Vasya immediately got interested in what month Codecraft III will appear. Help him understa... | The first input line contains the name of the current month. It is guaranteed that it is a proper English name of one of twelve months. The first letter is uppercase, the rest are lowercase. The second line contains integer *k* (0<=≤<=*k*<=≤<=100) — the number of months left till the appearance of Codecraft III. | Print starting from an uppercase letter the name of the month in which the continuation of Codeforces II will appear. The printed name must be contained in the list January, February, March, April, May, June, July, August, September, October, November, December. | [
"November\n3\n",
"May\n24\n"
] | [
"February\n",
"May\n"
] | none | 0 | [
{
"input": "November\n3",
"output": "February"
},
{
"input": "May\n24",
"output": "May"
},
{
"input": "April\n0",
"output": "April"
},
{
"input": "September\n0",
"output": "September"
},
{
"input": "August\n0",
"output": "August"
},
{
"input": "June\n1... | 1,609,062,361 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 248 | 0 | a = ["January", "February", "March", "April", "May", "June", "July", "August"," September", "October", "November", "December"]
s = input()
n = int(input())
n %= 12
x = a.index(s) + n
if (x > 11):
tmp = 11 - x
n -= tmp
print(a[n - 1])
else:
print(a[x])
| Title: Codecraft III
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Today Vasya visited a widely known site and learned that the continuation of his favourite game Codecraft II will appear after exactly *k* months. He looked at the calendar and learned that at the moment is the month number *... | ```python
a = ["January", "February", "March", "April", "May", "June", "July", "August"," September", "October", "November", "December"]
s = input()
n = int(input())
n %= 12
x = a.index(s) + n
if (x > 11):
tmp = 11 - x
n -= tmp
print(a[n - 1])
else:
print(a[x])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,567,014,795 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 218 | 716,800 | def little_elephant_and_bits(a):
if "0" not in a:
a.pop(a.index("1"))
else:
a.pop(a.index("0"))
return "".join(a)
if __name__ == "__main__":
a = list(input())
print(little_elephant_and_bits(a))
| Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
def little_elephant_and_bits(a):
if "0" not in a:
a.pop(a.index("1"))
else:
a.pop(a.index("0"))
return "".join(a)
if __name__ == "__main__":
a = list(input())
print(little_elephant_and_bits(a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
900 | A | Find Extra One | PROGRAMMING | 800 | [
"geometry",
"implementation"
] | null | null | You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis. | The first line contains a single positive integer *n* (2<=≤<=*n*<=≤<=105).
The following *n* lines contain coordinates of the points. The *i*-th of these lines contains two single integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109, *x**i*<=≠<=0). No two points coincide. | Print "Yes" if there is such a point, "No" — otherwise.
You can print every letter in any case (upper or lower). | [
"3\n1 1\n-1 -1\n2 -1\n",
"4\n1 1\n2 2\n-1 1\n-2 2\n",
"3\n1 2\n2 1\n4 60\n"
] | [
"Yes",
"No",
"Yes"
] | In the first example the second point can be removed.
In the second example there is no suitable for the condition point.
In the third example any point can be removed. | 500 | [
{
"input": "3\n1 1\n-1 -1\n2 -1",
"output": "Yes"
},
{
"input": "4\n1 1\n2 2\n-1 1\n-2 2",
"output": "No"
},
{
"input": "3\n1 2\n2 1\n4 60",
"output": "Yes"
},
{
"input": "10\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n-1 -1",
"output": "Yes"
},
{
"input": "2\n1... | 1,564,141,368 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 109 | 0 | q=int(input())
e=0
r=0
for i in range(q):
w=input().split()
if int(w[0])<0:
e+=1
else:
r+=1
if e==1 or r==1:
print('Yes')
else:
print('No') | Title: Find Extra One
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis.
Input Specification:
The first li... | ```python
q=int(input())
e=0
r=0
for i in range(q):
w=input().split()
if int(w[0])<0:
e+=1
else:
r+=1
if e==1 or r==1:
print('Yes')
else:
print('No')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
515 | B | Drazil and His Happy Friends | PROGRAMMING | 1,300 | [
"brute force",
"dsu",
"meet-in-the-middle",
"number theory"
] | null | null | Drazil has many friends. Some of them are happy and some of them are unhappy. Drazil wants to make all his friends become happy. So he invented the following plan.
There are *n* boys and *m* girls among his friends. Let's number them from 0 to *n*<=-<=1 and 0 to *m*<=-<=1 separately. In *i*-th day, Drazil invites -th ... | The first line contains two integer *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
The second line contains integer *b* (0<=≤<=*b*<=≤<=*n*), denoting the number of happy boys among friends of Drazil, and then follow *b* distinct integers *x*1,<=*x*2,<=...,<=*x**b* (0<=≤<=*x**i*<=<<=*n*), denoting the list of indices of hap... | If Drazil can make all his friends become happy by this plan, print "Yes". Otherwise, print "No". | [
"2 3\n0\n1 0\n",
"2 4\n1 0\n1 2\n",
"2 3\n1 0\n1 1\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | By <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/169ade208e6eb4f9263c57aaff716529d59c3288.png" style="max-width: 100.0%;max-height: 100.0%;"/> we define the remainder of integer division of *i* by *k*.
In first sample case:
- On the 0-th day, Drazil invites 0-th boy and 0-th girl. Bec... | 1,000 | [
{
"input": "2 3\n0\n1 0",
"output": "Yes"
},
{
"input": "2 4\n1 0\n1 2",
"output": "No"
},
{
"input": "2 3\n1 0\n1 1",
"output": "Yes"
},
{
"input": "16 88\n6 5 14 2 0 12 7\n30 21 64 35 79 74 39 63 44 81 73 0 27 33 69 12 86 46 20 25 55 52 7 58 23 5 60 32 41 50 82",
"outpu... | 1,625,300,246 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 77 | 307,200 | #!/usr/bin/env python3
# from typing import *
import sys
import io
import math
import collections
import decimal
import itertools
import bisect
import heapq
def input():
return sys.stdin.readline()[:-1]
# sys.setrecursionlimit(1000000)
# _INPUT = """100 50
# 30 50 54 7 8 59 60 61 62 63 64 ... | Title: Drazil and His Happy Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil has many friends. Some of them are happy and some of them are unhappy. Drazil wants to make all his friends become happy. So he invented the following plan.
There are *n* boys and *m* girls among hi... | ```python
#!/usr/bin/env python3
# from typing import *
import sys
import io
import math
import collections
import decimal
import itertools
import bisect
import heapq
def input():
return sys.stdin.readline()[:-1]
# sys.setrecursionlimit(1000000)
# _INPUT = """100 50
# 30 50 54 7 8 59 60 61... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
808 | A | Lucky Year | PROGRAMMING | 900 | [
"implementation"
] | null | null | Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 12, 3001 and 12345 are not.
You are given current year in Berland. Your task is to find how long... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=109) — current year in Berland. | Output amount of years from the current year to the next lucky one. | [
"4\n",
"201\n",
"4000\n"
] | [
"1\n",
"99\n",
"1000\n"
] | In the first example next lucky year is 5. In the second one — 300. In the third — 5000. | 0 | [
{
"input": "4",
"output": "1"
},
{
"input": "201",
"output": "99"
},
{
"input": "4000",
"output": "1000"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "10"
},
{
"input": "1",
"output": "1"
},
{
"input": "100000000",
"ou... | 1,671,058,826 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | def is_lucky(x):
the_list= []
str_x = str(x)
for item in str_x:
if int(item) >= 1:
the_list.append(item)
if len(the_list) == 1:
return True
if len(the_list)>1:
return False
user_input= int(input("Enter a year: "))
the_remaining = 0
while True:
... | Title: Lucky Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from having lots of holidays throughout the year, residents of Berland also have whole lucky years. Year is considered lucky if it has no more than 1 non-zero digit in its number. So years 100, 40000, 5 are lucky and 1... | ```python
def is_lucky(x):
the_list= []
str_x = str(x)
for item in str_x:
if int(item) >= 1:
the_list.append(item)
if len(the_list) == 1:
return True
if len(the_list)>1:
return False
user_input= int(input("Enter a year: "))
the_remaining = 0
while ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,562,770,386 | 2,147,483,647 | PyPy 3 | OK | TESTS | 15 | 623 | 9,728,000 | import math
n = int(input())
print(math.ceil(n**2/2))
for i in range(n):
for j in range(n):
k = i+j
if k %2 == 0:
print('C',end='')
else:
print('.',end='')
print() | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
import math
n = int(input())
print(math.ceil(n**2/2))
for i in range(n):
for j in range(n):
k = i+j
if k %2 == 0:
print('C',end='')
else:
print('.',end='')
print()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for ... | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use al... | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,639,583,476 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | n,k=map(int,input().split())
a=list(map(int,input().split()))
a1=[]
for i in range(n):
a1.append((a[i],i+1))
a1.sort()
a=[]
for i in range(n):
if (k-a1[i][0]>=0):
k-=a1[i][0];
a.append(a1[i][1])
else:
break
print(len(a))
print(*a) | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr ... | ```python
n,k=map(int,input().split())
a=list(map(int,input().split()))
a1=[]
for i in range(n):
a1.append((a[i],i+1))
a1.sort()
a=[]
for i in range(n):
if (k-a1[i][0]>=0):
k-=a1[i][0];
a.append(a1[i][1])
else:
break
print(len(a))
print(*a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,650,395,058 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 61 | 307,200 | a, b, n = map(int, input().split())
a *= 10
flag = False
for i in range(10):
if (a+i) % b == 0:
print(a+i, end = "")
flag = True
break
if(flag):
s = "0" * (n-1)
print(s)
else:
print(-1)
| Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a, b, n = map(int, input().split())
a *= 10
flag = False
for i in range(10):
if (a+i) % b == 0:
print(a+i, end = "")
flag = True
break
if(flag):
s = "0" * (n-1)
print(s)
else:
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
792 | C | Divide by Three | PROGRAMMING | 2,000 | [
"dp",
"greedy",
"math",
"number theory"
] | null | null | A positive integer number *n* is written on a blackboard. It consists of not more than 105 digits. You have to transform it into a beautiful number by erasing some of the digits, and you want to erase as few digits as possible.
The number is called beautiful if it consists of at least one digit, doesn't have leading z... | The first line of input contains *n* — a positive integer number without leading zeroes (1<=≤<=*n*<=<<=10100000). | Print one number — any beautiful number obtained by erasing as few as possible digits. If there is no answer, print <=-<=1. | [
"1033\n",
"10\n",
"11\n"
] | [
"33\n",
"0\n",
"-1\n"
] | In the first example it is enough to erase only the first digit to obtain a multiple of 3. But if we erase the first digit, then we obtain a number with a leading zero. So the minimum number of digits to be erased is two. | 0 | [
{
"input": "1033",
"output": "33"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "-1"
},
{
"input": "3",
"output": "3"
},
{
"input": "1",
"output": "-1"
},
{
"input": "117",
"output": "117"
},
{
"input": "518",
"output"... | 1,490,627,197 | 1,897 | Python 3 | WRONG_ANSWER | TESTS | 9 | 46 | 4,608,000 | import sys
def CalNum(sNum,iLen):
if iLen>=len(sNum):
iNum=int(sNum)
if iNum%3==0:
return iNum
else:
return -1
iNum=int(sNum[iLen:])
if iNum%3==0:
return iNum
elif iNum<10:
return -1
else:
return CalNum(str(iNum),iLen+1)
def Main():
sNum=input()
if int(sNum)%3==0:
print(... | Title: Divide by Three
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A positive integer number *n* is written on a blackboard. It consists of not more than 105 digits. You have to transform it into a beautiful number by erasing some of the digits, and you want to erase as few digits as p... | ```python
import sys
def CalNum(sNum,iLen):
if iLen>=len(sNum):
iNum=int(sNum)
if iNum%3==0:
return iNum
else:
return -1
iNum=int(sNum[iLen:])
if iNum%3==0:
return iNum
elif iNum<10:
return -1
else:
return CalNum(str(iNum),iLen+1)
def Main():
sNum=input()
if int(sNum)%3==0:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
266 | A | Stones on the Table | PROGRAMMING | 800 | [
"implementation"
] | null | null | There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red... | Print a single integer — the answer to the problem. | [
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] | [
"1\n",
"4\n",
"0\n"
] | none | 500 | [
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "... | 1,699,166,081 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | number_of_colors = int(input())
colors = input()
count = 0
num = colors.count(colors[0])
for i in range(number_of_colors):
if num != number_of_colors:
if (i > 0 and i < number_of_colors-1) and colors[i+1] == colors[i] or colors[i] == colors[i-1]:
count += 1
if num != number_of_colors:
... | Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row ... | ```python
number_of_colors = int(input())
colors = input()
count = 0
num = colors.count(colors[0])
for i in range(number_of_colors):
if num != number_of_colors:
if (i > 0 and i < number_of_colors-1) and colors[i+1] == colors[i] or colors[i] == colors[i-1]:
count += 1
if num != number_o... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,680,977,989 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | S = input()
from collections import deque
ans = deque(["h","e","l","l","o"])
for s in S:
if s == ans[0]:
ans.popleft()
else:
print("NO")
exit()
print("YES") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
S = input()
from collections import deque
ans = deque(["h","e","l","l","o"])
for s in S:
if s == ans[0]:
ans.popleft()
else:
print("NO")
exit()
print("YES")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,672,130,248 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 186 | 2,355,200 | import re
string = input()
upper = len(re.findall(r'[A-Z]', string))
lower = len(re.findall(r'[a-z]', string))
if lower >= upper :
print(string.lower())
else:
print(string.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
import re
string = input()
upper = len(re.findall(r'[A-Z]', string))
lower = len(re.findall(r'[a-z]', string))
if lower >= upper :
print(string.lower())
else:
print(string.upper())
``` | 3.949113 | MatrixStudio/Codeforces-Python-Submissions |
159 | B | Matchmaker | PROGRAMMING | 1,100 | [
"*special",
"greedy",
"sortings"
] | null | null | Polycarpus has *n* markers and *m* marker caps. Each marker is described by two numbers: *x**i* is the color and *y**i* is the diameter. Correspondingly, each cap is described by two numbers: *a**j* is the color and *b**j* is the diameter. Cap (*a**j*,<=*b**j*) can close marker (*x**i*,<=*y**i*) only if their diameters... | The first input line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of markers and the number of caps, correspondingly.
Next *n* lines describe the markers. The *i*-th line contains two space-separated integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the *i*-th mark... | Print two space-separated integers *u*,<=*v*, where *u* is the number of closed markers and *v* is the number of beautifully closed markers in the sought optimal way. Remember that you have to find the way to close the maximum number of markers, and if there are several such ways, you should choose the one where the nu... | [
"3 4\n1 2\n3 4\n2 4\n5 4\n2 4\n1 1\n1 2\n",
"2 2\n1 2\n2 1\n3 4\n5 1\n"
] | [
"3 2\n",
"1 0\n"
] | In the first test sample the first marker should be closed by the fourth cap, the second marker should be closed by the first cap and the third marker should be closed by the second cap. Thus, three markers will be closed, and two of them will be beautifully closed — the first and the third markers. | 1,000 | [
{
"input": "3 4\n1 2\n3 4\n2 4\n5 4\n2 4\n1 1\n1 2",
"output": "3 2"
},
{
"input": "2 2\n1 2\n2 1\n3 4\n5 1",
"output": "1 0"
},
{
"input": "6 7\n2 1\n2 2\n2 1\n1 1\n2 1\n1 2\n2 2\n2 2\n2 2\n1 2\n2 2\n1 1\n1 2",
"output": "3 3"
},
{
"input": "6 7\n2 1\n1 1\n2 2\n1 2\n1 1\n1 2... | 1,669,919,317 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 2,588 | 27,545,600 | """
https://codeforces.com/problemset/problem/159/B
"""
closedbeautifully, closed = 0, 0
n, m = [int(x) for x in input().split()]
markers, caps = dict(), dict()
for _ in range(n):
zz = tuple(int(x) for x in input().split())
markers[zz] = markers.get(zz, 0) + 1
for _ in range(m):
(x, y) = [int(x) for x in ... | Title: Matchmaker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has *n* markers and *m* marker caps. Each marker is described by two numbers: *x**i* is the color and *y**i* is the diameter. Correspondingly, each cap is described by two numbers: *a**j* is the color and *b**j* i... | ```python
"""
https://codeforces.com/problemset/problem/159/B
"""
closedbeautifully, closed = 0, 0
n, m = [int(x) for x in input().split()]
markers, caps = dict(), dict()
for _ in range(n):
zz = tuple(int(x) for x in input().split())
markers[zz] = markers.get(zz, 0) + 1
for _ in range(m):
(x, y) = [int(x)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
47 | A | Triangular numbers | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Triangular numbers | 2 | 256 | A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers fr... | The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer. | If the given integer is a triangular number output YES, otherwise output NO. | [
"1\n",
"2\n",
"3\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "2",
"output": "NO"
},
{
"input": "3",
"output": "YES"
},
{
"input": "4",
"output": "NO"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "YES"
},
{
"input": "7",
"output": "NO... | 1,632,517,103 | 2,147,483,647 | PyPy 3 | OK | TESTS | 71 | 218 | 20,172,800 | print(["NO","YES"][((-1+(1+8*int(input()))**0.5)/2)%1==0]) | Title: Triangular numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is t... | ```python
print(["NO","YES"][((-1+(1+8*int(input()))**0.5)/2)%1==0])
``` | 3.907925 | MatrixStudio/Codeforces-Python-Submissions |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,694,303,817 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
using namespace std;
int main()
{
int num, rooms = 0;
cin>>num;
for (int i = 1; i <=num; i++)
{
int p, q;
cin>>p>>q;
if(q-p >=2)
rooms++;
}
cout<<rooms;
return 0;
}
| Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
#include <iostream>
using namespace std;
int main()
{
int num, rooms = 0;
cin>>num;
for (int i = 1; i <=num; i++)
{
int p, q;
cin>>p>>q;
if(q-p >=2)
rooms++;
}
cout<<rooms;
return 0;
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
656 | D | Rosetta Problem | PROGRAMMING | 2,100 | [
"*special"
] | null | null | The input contains a single integer *a* (0<=≤<=*a*<=≤<=1<=000<=000). | Output a single integer. | [
"129\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "129",
"output": "1"
},
{
"input": "0",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "6",
"output": "0"
},
{
"input": "16",
"output": "0"
},
{
"input": "299593",
"output": "7"
},
{
"input": "398929",
"output":... | 1,459,533,394 | 6,994 | Python 3 | WRONG_ANSWER | TESTS | 0 | 61 | 4,608,000 | s = input()
print(all('0' <= c <= '7' for c in s)) | Title: Rosetta Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Input Specification:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=1<=000<=000).
Output Specification:
Output a single integer.
Demo Input:
['129\n']
Demo Output:
['1\n']
Note:
none | ```python
s = input()
print(all('0' <= c <= '7' for c in s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | ||
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,695,327,570 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n, h = [int(i) for i in input().split()]
max_width = 0
for i in input().split():
if i > h:
max_width += 2
else:
max_width += 1
print(max_width) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n, h = [int(i) for i in input().split()]
max_width = 0
for i in input().split():
if i > h:
max_width += 2
else:
max_width += 1
print(max_width)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
852 | A | Digits | PROGRAMMING | 2,500 | [
"brute force",
"implementation",
"math"
] | null | null | John gave Jack a very hard problem. He wrote a very big positive integer *A*0 on a piece of paper. The number is less than 10200000 . In each step, Jack is allowed to put '<=+<=' signs in between some of the digits (maybe none) of the current number and calculate the sum of the expression. He can perform the same proce... | First line contains a positive integer *N* (1<=≤<=*N*<=≤<=200000), representing the number of digits of *A*0.
Second line contains a string of length *N* representing positive integer number *A*0. Each character is digit. There will be no leading zeros. | Output exactly three lines, the steps Jack needs to perform to solve the problem. You can output any sequence of steps which results in a single digit number (and is logically consistent).
Every step consists of digits and '<=+<=' signs. Steps should not contain several '<=+<=' signs in a row, whitespaces, or '<=+<=' ... | [
"1\n1\n",
"4\n5806\n"
] | [
"1\n1\n1\n",
"5+8+0+6\n1+9\n1+0\n"
] | In the first sample, Jack can't put ' + ' signs anywhere, so he just writes 1 in each line and solves the problem. Here, solution is unique.
In the second sample, Jack first puts ' + ' between every two consecutive digits, thus getting the result 5 + 8 + 0 + 6 = 19. He does the same on the second step, getting 1 + 9 =... | 0 | [] | 1,504,750,672 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 9,728,000 | from sys import stdin
def concatena(y):
cont=0
cad=''
for i in range(len(y)):
cont+=int(y[i])
if (len(y)-1)==i:
cad+=y[i]
else:
cad=cad+y[i]+'+'
return str(cont), cad
def main():
x=int(stdin.readline())
y=stdin.readline().strip()
cont=0
w... | Title: Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
John gave Jack a very hard problem. He wrote a very big positive integer *A*0 on a piece of paper. The number is less than 10200000 . In each step, Jack is allowed to put '<=+<=' signs in between some of the digits (maybe none) ... | ```python
from sys import stdin
def concatena(y):
cont=0
cad=''
for i in range(len(y)):
cont+=int(y[i])
if (len(y)-1)==i:
cad+=y[i]
else:
cad=cad+y[i]+'+'
return str(cont), cad
def main():
x=int(stdin.readline())
y=stdin.readline().strip()
co... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,662,377,686 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 204,800 | import math as m
x = ""
n = int(input(""))
print(m.floor(n/2))
if n%2 == 0:
for i in range(int(n/2)):
x += "2 "
else:
for i in range(int((n-3)/2)):
x += "2 "
x += "3"
print(x) | Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
import math as m
x = ""
n = int(input(""))
print(m.floor(n/2))
if n%2 == 0:
for i in range(int(n/2)):
x += "2 "
else:
for i in range(int((n-3)/2)):
x += "2 "
x += "3"
print(x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
165 | E | Compatible Numbers | PROGRAMMING | 2,200 | [
"bitmasks",
"brute force",
"dfs and similar",
"dp"
] | null | null | Two integers *x* and *y* are compatible, if the result of their bitwise "AND" equals zero, that is, *a* & *b*<==<=0. For example, numbers 90 (10110102) and 36 (1001002) are compatible, as 10110102 & 1001002<==<=02, and numbers 3 (112) and 6 (1102) are not compatible, as 112 & 1102<==<=102.
You are given an... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the number of elements in the given array. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=4·106) — the elements of the given array. The numbers in the array can coincide. | Print *n* integers *ans**i*. If *a**i* isn't compatible with any other element of the given array *a*1,<=*a*2,<=...,<=*a**n*, then *ans**i* should be equal to -1. Otherwise *ans**i* is any such number, that *a**i* & *ans**i*<==<=0, and also *ans**i* occurs in the array *a*1,<=*a*2,<=...,<=*a**n*. | [
"2\n90 36\n",
"4\n3 6 3 6\n",
"5\n10 6 9 8 2\n"
] | [
"36 90",
"-1 -1 -1 -1",
"-1 8 2 2 8"
] | none | 2,500 | [
{
"input": "2\n90 36",
"output": "36 90"
},
{
"input": "4\n3 6 3 6",
"output": "-1 -1 -1 -1"
},
{
"input": "5\n10 6 9 8 2",
"output": "-1 8 2 2 8"
},
{
"input": "10\n4 9 8 3 2 6 8 2 9 7",
"output": "8 4 4 8 8 8 4 8 4 8"
},
{
"input": "10\n3 5 18 12 4 20 11 19 15 6... | 1,630,153,244 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 69 | 4,000 | 116,121,600 | from collections import defaultdict, Counter,deque
from math import sqrt, log10, log, floor, factorial,gcd
from bisect import bisect_left, bisect_right
from itertools import permutations,combinations
import sys, io, os
input = sys.stdin.readline
# input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
# sys.s... | Title: Compatible Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two integers *x* and *y* are compatible, if the result of their bitwise "AND" equals zero, that is, *a* & *b*<==<=0. For example, numbers 90 (10110102) and 36 (1001002) are compatible, as 10110102 & 1001002<=... | ```python
from collections import defaultdict, Counter,deque
from math import sqrt, log10, log, floor, factorial,gcd
from bisect import bisect_left, bisect_right
from itertools import permutations,combinations
import sys, io, os
input = sys.stdin.readline
# input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readlin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
95 | B | Lucky Numbers | PROGRAMMING | 1,800 | [
"dp",
"greedy"
] | B. Lucky Numbers | 2 | 256 | Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Lucky number is super lucky if it's decimal representation contains equal amount of digits 4 and 7. Fo... | The only line contains a positive integer *n* (1<=≤<=*n*<=≤<=10100000). This number doesn't have leading zeroes. | Output the least super lucky number that is more than or equal to *n*. | [
"4500\n",
"47\n"
] | [
"4747\n",
"47\n"
] | none | 1,000 | [
{
"input": "4500",
"output": "4747"
},
{
"input": "47",
"output": "47"
},
{
"input": "1",
"output": "47"
},
{
"input": "12",
"output": "47"
},
{
"input": "4587",
"output": "4747"
},
{
"input": "100",
"output": "4477"
},
{
"input": "1007",
... | 1,584,378,289 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 248 | 0 |
n=int(input())
s=[0]
while 1:
f=1
for i in s:
i=10*i
if i+4>=n and str(i+4).count('4')==str(4+i).count('7'):
print(i+4)
f=0
break
elif i+4>=n and str(i+7).count('4')==str(7+i).count('7'):
print(i+7)
f=0
break
... | Title: Lucky Numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Lucky n... | ```python
n=int(input())
s=[0]
while 1:
f=1
for i in s:
i=10*i
if i+4>=n and str(i+4).count('4')==str(4+i).count('7'):
print(i+4)
f=0
break
elif i+4>=n and str(i+7).count('4')==str(7+i).count('7'):
print(i+7)
f=0
br... | 0 | MatrixStudio/Codeforces-Python-Submissions |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,699,389,630 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | def solve(n,s,cnt):
v=[]
for i in s:
v.append(i)
if v.count("1")>1:
cnt+=1
return cnt
n=int(input())
cnt=0
for i in range(n):
s=input()
print(solve(n,s,cnt))
| Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
def solve(n,s,cnt):
v=[]
for i in s:
v.append(i)
if v.count("1")>1:
cnt+=1
return cnt
n=int(input())
cnt=0
for i in range(n):
s=input()
print(solve(n,s,cnt))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,688,474,538 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 43 | 46 | 0 | k=int(input())
j=str(k)
l=""
for i in range (len(j)):
if(i==0):
if(int(j[0])==9 or int(j[0])<=4):
l=l+j[0]
else:
l=l+str(9-int(j[0]))
else:
if(int(j[i])>4):
l=l+str(9-int(j[i]))
else:
l=l+j[i]
print(int(l)) ... | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
k=int(input())
j=str(k)
l=""
for i in range (len(j)):
if(i==0):
if(int(j[0])==9 or int(j[0])<=4):
l=l+j[0]
else:
l=l+str(9-int(j[0]))
else:
if(int(j[i])>4):
l=l+str(9-int(j[i]))
else:
l=l+j[i]
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,690,203,506 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | year = int(input())
def check(year):
lst = [int(x) for x in str(year)]
count = 0
for i in range (0, 3):
for j in range(i+1, 4):
if lst[i] == lst[j]:
count += 1
if count != 0:
year += 1
check(year)
else:
print(year)
check(year +... | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
year = int(input())
def check(year):
lst = [int(x) for x in str(year)]
count = 0
for i in range (0, 3):
for j in range(i+1, 4):
if lst[i] == lst[j]:
count += 1
if count != 0:
year += 1
check(year)
else:
print(year)
ch... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,688,930,478 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 62 | 0 | n=0
for i in range(int(input())):
a, b = map(int, input().split())
if abs(a-b) > 1:
n +=1
print(n) | Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
n=0
for i in range(int(input())):
a, b = map(int, input().split())
if abs(a-b) > 1:
n +=1
print(n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,693,720,697 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | n=int(input())
s=input().split()
d=[]
for i in range(n):
d.append(int(s[i]))
c=max(d)
c1=0
for i in d:
c1+=abs(c-i)
print(c1) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n=int(input())
s=input().split()
d=[]
for i in range(n):
d.append(int(s[i]))
c=max(d)
c1=0
for i in d:
c1+=abs(c-i)
print(c1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
220 | B | Little Elephant and Array | PROGRAMMING | 1,800 | [
"constructive algorithms",
"data structures"
] | null | null | The Little Elephant loves playing with arrays. He has array *a*, consisting of *n* positive integers, indexed from 1 to *n*. Let's denote the number with index *i* as *a**i*.
Additionally the Little Elephant has *m* queries to the array, each query is characterised by a pair of integers *l**j* and *r**j* (1<=≤<=*l**j... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the size of array *a* and the number of queries to it. The next line contains *n* space-separated positive integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109). Next *m* lines contain descriptions of queries, one per line. T... | In *m* lines print *m* integers — the answers to the queries. The *j*-th line should contain the answer to the *j*-th query. | [
"7 2\n3 1 2 2 3 3 7\n1 7\n3 4\n"
] | [
"3\n1\n"
] | none | 1,000 | [
{
"input": "7 2\n3 1 2 2 3 3 7\n1 7\n3 4",
"output": "3\n1"
},
{
"input": "6 6\n1 2 2 3 3 3\n1 2\n2 2\n1 3\n2 4\n4 6\n1 6",
"output": "1\n0\n2\n1\n1\n3"
},
{
"input": "1 2\n1\n1 1\n1 1",
"output": "1\n1"
},
{
"input": "1 1\n1000000000\n1 1",
"output": "0"
}
] | 1,601,521,699 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 4,000 | 8,908,800 | n,m=map(int,input().split())
arr=list(map(int,input().split()))
arr=[0]+arr
summ=[0]*(100001)
freq=[0]*(100001)
#print(l)
l=[0]*(100001)
r=[0]*(100001)
for ii in arr:
if ii<=n:freq[ii]+=1
for i in range(1,m+1):
x,y=map(int,input().split())
l[i]=x
r[i]=y
ans=[0]*(m+1)
for i in range(1,n+1):
if ... | Title: Little Elephant and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves playing with arrays. He has array *a*, consisting of *n* positive integers, indexed from 1 to *n*. Let's denote the number with index *i* as *a**i*.
Additionally the Little Elephant... | ```python
n,m=map(int,input().split())
arr=list(map(int,input().split()))
arr=[0]+arr
summ=[0]*(100001)
freq=[0]*(100001)
#print(l)
l=[0]*(100001)
r=[0]*(100001)
for ii in arr:
if ii<=n:freq[ii]+=1
for i in range(1,m+1):
x,y=map(int,input().split())
l[i]=x
r[i]=y
ans=[0]*(m+1)
for i in range(1,n+... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
934 | A | A Compatible Pair | PROGRAMMING | 1,400 | [
"brute force",
"games"
] | null | null | Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cracking noise, all of which frighten the monster out of coming.
Little Tommy has *n* lanterns and Big B... | The first line contains two space-separated integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=50).
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n*.
The third line contains *m* space-separated integers *b*1,<=*b*2,<=...,<=*b**m*.
All the integers range from <=-<=109 to 109. | Print a single integer — the brightness of the chosen pair. | [
"2 2\n20 18\n2 14\n",
"5 3\n-1 0 1 2 3\n-1 0 1\n"
] | [
"252\n",
"2\n"
] | In the first example, Tommy will hide 20 and Banban will choose 18 from Tommy and 14 from himself.
In the second example, Tommy will hide 3 and Banban will choose 2 from Tommy and 1 from himself. | 500 | [
{
"input": "2 2\n20 18\n2 14",
"output": "252"
},
{
"input": "5 3\n-1 0 1 2 3\n-1 0 1",
"output": "2"
},
{
"input": "10 2\n1 6 2 10 2 3 2 10 6 4\n5 7",
"output": "70"
},
{
"input": "50 50\n1 6 2 10 2 3 2 10 6 4 5 0 3 1 7 3 2 4 4 2 1 5 0 6 10 1 8 0 10 9 0 4 10 5 5 7 4 9 9 5 5 ... | 1,560,757,042 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 109 | 0 | n,m=map(int,input().split())
a = list(map(int,input().split()))
a.sort()
b = list(map(int,input().split()))
x,y = max(b),min(b)
if a[1]*y>a[n-2]*x:print(a[1]*y)
else:print(a[n-2]*x) | Title: A Compatible Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cr... | ```python
n,m=map(int,input().split())
a = list(map(int,input().split()))
a.sort()
b = list(map(int,input().split()))
x,y = max(b),min(b)
if a[1]*y>a[n-2]*x:print(a[1]*y)
else:print(a[n-2]*x)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,614,609,734 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 77 | 0 | a = int(input())
cp_a = a + 1
while '8' not in str(cp_a): cp_a += 1
print(cp_a - a) | Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
a = int(input())
cp_a = a + 1
while '8' not in str(cp_a): cp_a += 1
print(cp_a - a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
622 | B | The Time | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedi... | The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes... | The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format. | [
"23:59\n10\n",
"20:20\n121\n",
"10:10\n0\n"
] | [
"00:09\n",
"22:21\n",
"10:10\n"
] | none | 0 | [
{
"input": "23:59\n10",
"output": "00:09"
},
{
"input": "20:20\n121",
"output": "22:21"
},
{
"input": "10:10\n0",
"output": "10:10"
},
{
"input": "12:34\n10000",
"output": "11:14"
},
{
"input": "00:00\n10000",
"output": "22:40"
},
{
"input": "00:00\n14... | 1,608,650,552 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 108 | 0 |
h,m=map(int,input().split(":"))
x=int(input())
ho,mi=divmod(x,60)
h+=ho
if m+mi>=60:
a,b=divmod(m+mi,60)
h+=a
m+=b
if h>=24:
h-=24
if len(str(h))==1:
h="0"+str(h)
if m>=60:
m-=59
if len(str(m))==1:
m="0"+str(m)
print(str(h)+":"+str(m))
| Title: The Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read mo... | ```python
h,m=map(int,input().split(":"))
x=int(input())
ho,mi=divmod(x,60)
h+=ho
if m+mi>=60:
a,b=divmod(m+mi,60)
h+=a
m+=b
if h>=24:
h-=24
if len(str(h))==1:
h="0"+str(h)
if m>=60:
m-=59
if len(str(m))==1:
m="0"+str(m)
print(str(h)+":"+str(m))
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
691 | A | Fashion in Berland | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | According to rules of the Berland fashion, a jacket should be fastened by all the buttons except only one, but not necessarily it should be the last one. Also if the jacket has only one button, it should be fastened, so the jacket will not swinging open.
You are given a jacket with *n* buttons. Determine if it is fast... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of buttons on the jacket.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=1). The number *a**i*<==<=0 if the *i*-th button is not fastened. Otherwise *a**i*<==<=1. | In the only line print the word "YES" if the jacket is fastened in a right way. Otherwise print the word "NO". | [
"3\n1 0 1\n",
"3\n1 0 0\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 0 1",
"output": "YES"
},
{
"input": "3\n1 0 0",
"output": "NO"
},
{
"input": "3\n1 1 0",
"output": "YES"
},
{
"input": "3\n1 1 1",
"output": "NO"
},
{
"input": "3\n0 0 1",
"output": "NO"
},
{
"input": "3\n0 0 0",
"output": "NO"
}... | 1,689,593,240 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689593240.6433547")# 1689593240.6433737 | Title: Fashion in Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to rules of the Berland fashion, a jacket should be fastened by all the buttons except only one, but not necessarily it should be the last one. Also if the jacket has only one button, it should be fastened,... | ```python
print("_RANDOM_GUESS_1689593240.6433547")# 1689593240.6433737
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,683,364,327 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | n , m = input().split()
ni = int(n)
mi = int(m)
total = 0
while(ni > 1 and mi > 0):
total += mi
ni -= 2
while(mi > 1 and ni>0) :
total += ni
mi -= 2
print(total) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
n , m = input().split()
ni = int(n)
mi = int(m)
total = 0
while(ni > 1 and mi > 0):
total += mi
ni -= 2
while(mi > 1 and ni>0) :
total += ni
mi -= 2
print(total)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
624 | B | Making a String | PROGRAMMING | 1,100 | [
"greedy",
"sortings"
] | null | null | You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than *a**i* times; - the number of occurrences of each letter in the string must be distinct for all the ... | The first line of the input contains a single integer *n* (2<=<=≤<=<=*n*<=<=≤<=<=26) — the number of letters in the alphabet.
The next line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — *i*-th of these integers gives the limitation on the number of occurrences of the *i*-th character in the string. | Print a single integer — the maximum length of the string that meets all the requirements. | [
"3\n2 5 5\n",
"3\n1 1 2\n"
] | [
"11\n",
"3\n"
] | For convenience let's consider an alphabet consisting of three letters: "a", "b", "c". In the first sample, some of the optimal strings are: "cccaabbccbb", "aabcbcbcbcb". In the second sample some of the optimal strings are: "acc", "cbc". | 1,000 | [
{
"input": "3\n2 5 5",
"output": "11"
},
{
"input": "3\n1 1 2",
"output": "3"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "3\n1 1000000000 2",
"output": "1000000003"
},
{
"input": "26\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 10000... | 1,454,607,306 | 1,806 | Python 3 | WRONG_ANSWER | TESTS | 8 | 62 | 0 | y = int(input())
x = input()
x = x.split()
x = list(map(int, x))
x.sort()
x_uni = list(set(x))
ans = 0
for i in x_uni:
num = x.count(i)
for j in range(num):
if i-j>0:
ans = ans+i-j
print(ans) | Title: Making a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than ... | ```python
y = int(input())
x = input()
x = x.split()
x = list(map(int, x))
x.sort()
x_uni = list(set(x))
ans = 0
for i in x_uni:
num = x.count(i)
for j in range(num):
if i-j>0:
ans = ans+i-j
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
855 | B | Marvolo Gaunt's Ring | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"dp"
] | null | null | Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he... | First line of input contains 4 integers *n*,<=*p*,<=*q*,<=*r* (<=-<=109<=≤<=*p*,<=*q*,<=*r*<=≤<=109,<=1<=≤<=*n*<=≤<=105).
Next line of input contains *n* space separated integers *a*1,<=*a*2,<=... *a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Output a single integer the maximum value of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* that can be obtained provided 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. | [
"5 1 2 3\n1 2 3 4 5\n",
"5 1 2 -3\n-1 -2 -3 -4 -5\n"
] | [
"30\n",
"12\n"
] | In the first sample case, we can take *i* = *j* = *k* = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.
In second sample case, selecting *i* = *j* = 1 and *k* = 5 gives the answer 12. | 1,000 | [
{
"input": "5 1 2 3\n1 2 3 4 5",
"output": "30"
},
{
"input": "5 1 2 -3\n-1 -2 -3 -4 -5",
"output": "12"
},
{
"input": "5 886327859 82309257 -68295239\n-731225382 354766539 -48222231 -474691998 360965777",
"output": "376059240645059046"
},
{
"input": "4 -96405765 -495906217 6... | 1,598,065,657 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 20,172,800 | n,p,q,r = map(int,input().split())
List = [int(x) for x in input().split()]
Max = max(List)
Min = min(List)
Neg = []
Pos = []
if(p<0):
Neg.append(p)
else:
Pos.append(p)
if(q<0):
Neg.append(q)
else:
Pos.append(q)
if(r<0):
Neg.append(r)
else:
Pos.append(r)
Ans = 0
if(Min<0):
... | Title: Marvolo Gaunt's Ring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed i... | ```python
n,p,q,r = map(int,input().split())
List = [int(x) for x in input().split()]
Max = max(List)
Min = min(List)
Neg = []
Pos = []
if(p<0):
Neg.append(p)
else:
Pos.append(p)
if(q<0):
Neg.append(q)
else:
Pos.append(q)
if(r<0):
Neg.append(r)
else:
Pos.append(r)
Ans = 0
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,663,650,766 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 124 | 1,433,600 | n,m=map(int,input().split())
l=list(map(int,input().split()))
p1=sorted(l)
p2=sorted(l)
c1,c2=0,0
for i in range(n):
c1=c1+p1[-1]
p1[-1]=p1[-1]-1
p1.sort()
i=0
x=0
while i!=n:
if p2[x]!=0:
c2+=p2[x]
p2[x]-=1
i+=1
else:
x+=1
print(c1,end=" ")
... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n,m=map(int,input().split())
l=list(map(int,input().split()))
p1=sorted(l)
p2=sorted(l)
c1,c2=0,0
for i in range(n):
c1=c1+p1[-1]
p1[-1]=p1[-1]-1
p1.sort()
i=0
x=0
while i!=n:
if p2[x]!=0:
c2+=p2[x]
p2[x]-=1
i+=1
else:
x+=1
print(c1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
721 | B | Passwords | PROGRAMMING | 1,100 | [
"implementation",
"math",
"sortings",
"strings"
] | null | null | Vanya is managed to enter his favourite site Codehorses. Vanya uses *n* distinct passwords for sites at all, however he can't remember which one exactly he specified during Codehorses registration.
Vanya will enter passwords in order of non-decreasing their lengths, and he will enter passwords of same length in arbitr... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of Vanya's passwords and the number of failed tries, after which the access to the site is blocked for 5 seconds.
The next *n* lines contains passwords, one per line — pairwise distinct non-empty strings consisting of ... | Print two integers — time (in seconds), Vanya needs to be authorized to Codehorses in the best case for him and in the worst case respectively. | [
"5 2\ncba\nabc\nbb1\nabC\nABC\nabc\n",
"4 100\n11\n22\n1\n2\n22\n"
] | [
"1 15\n",
"3 4\n"
] | Consider the first sample case. As soon as all passwords have the same length, Vanya can enter the right password at the first try as well as at the last try. If he enters it at the first try, he spends exactly 1 second. Thus in the best case the answer is 1. If, at the other hand, he enters it at the last try, he ente... | 1,000 | [
{
"input": "5 2\ncba\nabc\nbb1\nabC\nABC\nabc",
"output": "1 15"
},
{
"input": "4 100\n11\n22\n1\n2\n22",
"output": "3 4"
},
{
"input": "1 1\na1\na1",
"output": "1 1"
},
{
"input": "1 100\na1\na1",
"output": "1 1"
},
{
"input": "2 1\nabc\nAbc\nAbc",
"output": ... | 1,652,373,953 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | N, K = list(map(int, input().split()))
X = []
for i in range(N): X.append(input())
P = len(input())
X.sort()
x, y = 0, 0
for i in range(N):
if len(X[i]) > P: break
elif len(X[i]) == P: y+=1
else:
y+=1
x+=1
x+=1
print(x+((x//K)*5),y+((y//K)*5)) | Title: Passwords
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya is managed to enter his favourite site Codehorses. Vanya uses *n* distinct passwords for sites at all, however he can't remember which one exactly he specified during Codehorses registration.
Vanya will enter passwords... | ```python
N, K = list(map(int, input().split()))
X = []
for i in range(N): X.append(input())
P = len(input())
X.sort()
x, y = 0, 0
for i in range(N):
if len(X[i]) > P: break
elif len(X[i]) == P: y+=1
else:
y+=1
x+=1
x+=1
print(x+((x//K)*5),y+((y//K)*5))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
169 | A | Chores | PROGRAMMING | 800 | [
"sortings"
] | null | null | Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*.
As Petya is older, he wants to take the chores with complexit... | The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores.
The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* ... | Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. | [
"5 2 3\n6 2 3 100 1\n",
"7 3 4\n1 1 9 1 1 1 1\n"
] | [
"3\n",
"0\n"
] | In the first sample the possible values of *x* are 3, 4 or 5.
In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4. | 500 | [
{
"input": "5 2 3\n6 2 3 100 1",
"output": "3"
},
{
"input": "7 3 4\n1 1 9 1 1 1 1",
"output": "0"
},
{
"input": "2 1 1\n10 2",
"output": "8"
},
{
"input": "2 1 1\n7 7",
"output": "0"
},
{
"input": "2 1 1\n1 1000000000",
"output": "999999999"
},
{
"inp... | 1,625,140,568 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n,a,b=map(int,input().split())
li = [*map(int,input().split())]
li.sort()
print(li[b]-li[a]) | Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of th... | ```python
n,a,b=map(int,input().split())
li = [*map(int,input().split())]
li.sort()
print(li[b]-li[a])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
107 | A | Dorm Water Supply | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs"
] | A. Dorm Water Supply | 1 | 256 | The German University in Cairo (GUC) dorm houses are numbered from 1 to *n*. Underground water pipes connect these houses together. Each pipe has certain direction (water can flow only in this direction and not vice versa), and diameter (which characterizes the maximal amount of water it can handle).
For each house, t... | The first line contains two space-separated integers *n* and *p* (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*p*<=≤<=*n*) — the number of houses and the number of pipes correspondingly.
Then *p* lines follow — the description of *p* pipes. The *i*-th line contains three integers *a**i* *b**i* *d**i*, indicating a pipe of diameter *d... | Print integer *t* in the first line — the number of tank-tap pairs of houses.
For the next *t* lines, print 3 integers per line, separated by spaces: *tank**i*, *tap**i*, and *diameter**i*, where *tank**i*<=≠<=*tap**i* (1<=≤<=*i*<=≤<=*t*). Here *tank**i* and *tap**i* are indexes of tank and tap houses respectively, an... | [
"3 2\n1 2 10\n2 3 20\n",
"3 3\n1 2 20\n2 3 10\n3 1 5\n",
"4 2\n1 2 60\n3 4 50\n"
] | [
"1\n1 3 10\n",
"0\n",
"2\n1 2 60\n3 4 50\n"
] | none | 500 | [
{
"input": "3 2\n1 2 10\n2 3 20",
"output": "1\n1 3 10"
},
{
"input": "3 3\n1 2 20\n2 3 10\n3 1 5",
"output": "0"
},
{
"input": "4 2\n1 2 60\n3 4 50",
"output": "2\n1 2 60\n3 4 50"
},
{
"input": "10 10\n10 3 70\n1 9 98\n9 10 67\n5 2 78\n8 6 71\n4 8 95\n7 1 10\n2 5 73\n6 7 94\... | 1,423,852,850 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print("x") | Title: Dorm Water Supply
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
The German University in Cairo (GUC) dorm houses are numbered from 1 to *n*. Underground water pipes connect these houses together. Each pipe has certain direction (water can flow only in this direction and not vice versa... | ```python
print("x")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
877 | B | Nikita and string | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | null | null | One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st and the 3-rd one contain only letters "a" and the 2-nd contains only letters "b".
Nikita wants to make... | The first line contains a non-empty string of length not greater than 5<=000 containing only lowercase English letters "a" and "b". | Print a single integer — the maximum possible size of beautiful string Nikita can get. | [
"abba\n",
"bab\n"
] | [
"4",
"2"
] | It the first sample the string is already beautiful.
In the second sample he needs to delete one of "b" to make it beautiful. | 1,000 | [
{
"input": "abba",
"output": "4"
},
{
"input": "bab",
"output": "2"
},
{
"input": "bbabbbaabbbb",
"output": "9"
},
{
"input": "bbabbbbbaaba",
"output": "10"
},
{
"input": "bbabbbababaa",
"output": "9"
},
{
"input": "aabbaababbab",
"output": "8"
}... | 1,509,334,930 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 93 | 1,228,800 | # -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
import itertools
import sys
"""
created by shhuan at 2017/10/30 11:20
"""
S = input()
N = len(S)
dp = [[0 for _ in range(5)] for _ in range((N+1))]
for i in range(1, N+1):
a = 1 ... | Title: Nikita and string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st ... | ```python
# -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
import itertools
import sys
"""
created by shhuan at 2017/10/30 11:20
"""
S = input()
N = len(S)
dp = [[0 for _ in range(5)] for _ in range((N+1))]
for i in range(1, N+1):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,690,640,531 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 122 | 0 | def is_lucky(num):
lucky_numbers = [4, 7, 44, 47, 74, 77, 444, 447, 474, 477]
for lucky in lucky_numbers:
if num % lucky == 0:
return True
return False
# Input reading
n = int(input())
# Check if the number is almost lucky and output the result
if is_lucky(n):
print("YE... | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
def is_lucky(num):
lucky_numbers = [4, 7, 44, 47, 74, 77, 444, 447, 474, 477]
for lucky in lucky_numbers:
if num % lucky == 0:
return True
return False
# Input reading
n = int(input())
# Check if the number is almost lucky and output the result
if is_lucky(n):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
53 | A | Autocomplete | PROGRAMMING | 1,100 | [
"implementation"
] | A. Autocomplete | 2 | 256 | Autocomplete is a program function that enables inputting the text (in editors, command line shells, browsers etc.) completing the text by its inputted part. Vasya is busy working on a new browser called 'BERowser'. He happens to be working on the autocomplete function in the address line at this very moment. A list co... | The first line contains the *s* line which is the inputted part. The second line contains an integer *n* (1<=≤<=*n*<=≤<=100) which is the number of visited pages. Then follow *n* lines which are the visited pages, one on each line. All the lines have lengths of from 1 to 100 symbols inclusively and consist of lowercase... | If *s* is not the beginning of any of *n* addresses of the visited pages, print *s*. Otherwise, print the lexicographically minimal address of one of the visited pages starting from *s*.
The lexicographical order is the order of words in a dictionary. The lexicographical comparison of lines is realized by the '<' o... | [
"next\n2\nnextpermutation\nnextelement\n",
"find\n4\nfind\nfindfirstof\nfindit\nfand\n",
"find\n4\nfondfind\nfondfirstof\nfondit\nfand\n"
] | [
"nextelement\n",
"find\n",
"find\n"
] | none | 500 | [
{
"input": "next\n2\nnextpermutation\nnextelement",
"output": "nextelement"
},
{
"input": "find\n4\nfind\nfindfirstof\nfindit\nfand",
"output": "find"
},
{
"input": "find\n4\nfondfind\nfondfirstof\nfondit\nfand",
"output": "find"
},
{
"input": "kudljmxcse\n4\nkudljmxcse\nszje... | 1,660,386,828 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 10 | 124 | 0 | s = input()
short = " "*200
for i in range(int(input())):
l = input()
if l.startswith(s) and len(l) < len(short):
short = l
if short == " "*200:
print(s)
else: print(short) | Title: Autocomplete
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Autocomplete is a program function that enables inputting the text (in editors, command line shells, browsers etc.) completing the text by its inputted part. Vasya is busy working on a new browser called 'BERowser'. He happens... | ```python
s = input()
short = " "*200
for i in range(int(input())):
l = input()
if l.startswith(s) and len(l) < len(short):
short = l
if short == " "*200:
print(s)
else: print(short)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
949 | A | Zebras | PROGRAMMING | 1,600 | [
"greedy"
] | null | null | Oleg writes down the history of the days he lived. For each day he decides if it was good or bad. Oleg calls a non-empty sequence of days a zebra, if it starts with a bad day, ends with a bad day, and good and bad days are alternating in it. Let us denote bad days as 0 and good days as 1. Then, for example, sequences o... | In the only line of input data there is a non-empty string *s* consisting of characters 0 and 1, which describes the history of Oleg's life. Its length (denoted as |*s*|) does not exceed 200<=000 characters. | If there is a way to divide history into zebra subsequences, in the first line of output you should print an integer *k* (1<=≤<=*k*<=≤<=|*s*|), the resulting number of subsequences. In the *i*-th of following *k* lines first print the integer *l**i* (1<=≤<=*l**i*<=≤<=|*s*|), which is the length of the *i*-th subsequenc... | [
"0010100\n",
"111\n"
] | [
"3\n3 1 3 4\n3 2 5 6\n1 7\n",
"-1\n"
] | none | 500 | [
{
"input": "0010100",
"output": "3\n1 1\n5 2 3 4 5 6\n1 7"
},
{
"input": "111",
"output": "-1"
},
{
"input": "0",
"output": "1\n1 1"
},
{
"input": "1",
"output": "-1"
},
{
"input": "0101010101",
"output": "-1"
},
{
"input": "010100001",
"output": "... | 1,672,030,556 | 2,147,483,647 | PyPy 3 | OK | TESTS | 71 | 420 | 26,214,400 | from sys import stdin
input = stdin.readline
s = input().strip()
n = len(s)
ans = [[] for _ in range(200005)]
cnt = 0; mx = 0
for i in range(n):
if s[i] == '0':
ans[cnt].append(i+1)
cnt += 1
else:
cnt -= 1
if cnt < 0: print(-1); quit()
ans[cnt].append(i+1)
... | Title: Zebras
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Oleg writes down the history of the days he lived. For each day he decides if it was good or bad. Oleg calls a non-empty sequence of days a zebra, if it starts with a bad day, ends with a bad day, and good and bad days are alter... | ```python
from sys import stdin
input = stdin.readline
s = input().strip()
n = len(s)
ans = [[] for _ in range(200005)]
cnt = 0; mx = 0
for i in range(n):
if s[i] == '0':
ans[cnt].append(i+1)
cnt += 1
else:
cnt -= 1
if cnt < 0: print(-1); quit()
ans[cnt].ap... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,688,433,652 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | n,m=map(int,input().split())
a=[int(i) for i in input().split()]
a.sort()
m=1000
for i in range(m-n+1):
m=min(m,a[i+(n-1)]-a[i])
print(m) | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
n,m=map(int,input().split())
a=[int(i) for i in input().split()]
a.sort()
m=1000
for i in range(m-n+1):
m=min(m,a[i+(n-1)]-a[i])
print(m)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
268 | B | Buttons | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Manao is trying to open a rather challenging lock. The lock has *n* buttons on it and to open it, you should press the buttons in a certain order to open the lock. When you push some button, it either stays pressed into the lock (that means that you've guessed correctly and pushed the button that goes next in the seque... | A single line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of buttons the lock has. | In a single line print the number of times Manao has to push a button in the worst-case scenario. | [
"2\n",
"3\n"
] | [
"3\n",
"7\n"
] | Consider the first test sample. Manao can fail his first push and push the wrong button. In this case he will already be able to guess the right one with his second push. And his third push will push the second right button. Thus, in the worst-case scenario he will only need 3 pushes. | 1,000 | [
{
"input": "2",
"output": "3"
},
{
"input": "3",
"output": "7"
},
{
"input": "4",
"output": "14"
},
{
"input": "1",
"output": "1"
},
{
"input": "10",
"output": "175"
},
{
"input": "2000",
"output": "1333335000"
},
{
"input": "1747",
"ou... | 1,683,008,260 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | def main():
number = int(input())
print((number - i) * i + number)
if __name__ == '__main__':
main() | Title: Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao is trying to open a rather challenging lock. The lock has *n* buttons on it and to open it, you should press the buttons in a certain order to open the lock. When you push some button, it either stays pressed into the loc... | ```python
def main():
number = int(input())
print((number - i) * i + number)
if __name__ == '__main__':
main()
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,680,082,812 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n = int(input())
a = list(map(int,input()))
k1 = 0
k2 = 0
e = 0
o = 0
for i in range(n):
if a[i]%2==0:
e+ = 1
k1 = i
else:
o+ = 1
k2 = i
if e<o:
print(k1)
else:
print(k2) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
a = list(map(int,input()))
k1 = 0
k2 = 0
e = 0
o = 0
for i in range(n):
if a[i]%2==0:
e+ = 1
k1 = i
else:
o+ = 1
k2 = i
if e<o:
print(k1)
else:
print(k2)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,682,117,434 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 216 | 0 | n = int(input())
arr = [int(num) for num in input().split(' ')]
lastOdd = -1
lastEven = -1
for i in range(len(arr)):
if arr[i] % 2==0:
lastEven = i
else:
lastOdd = i
for i in range(len(arr)):
if arr[i]%2==0 and lastEven!=i:
print(lastOdd+1)
break
if arr[i]%2=... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
arr = [int(num) for num in input().split(' ')]
lastOdd = -1
lastEven = -1
for i in range(len(arr)):
if arr[i] % 2==0:
lastEven = i
else:
lastOdd = i
for i in range(len(arr)):
if arr[i]%2==0 and lastEven!=i:
print(lastOdd+1)
break
if... | 3.946 | MatrixStudio/Codeforces-Python-Submissions |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,596,382,890 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 6,963,200 | word=str(input()).lower()
index=word.find('l')
letter_l=word.count('l',index,index+2)
if letter_l>=2:
index0=word.find('h',0,index+1)
letter_h=word.count('h',index0,index+1)
if letter_h>=1:
index1=word.find('e',index0,index+1)
letter_e=word.count('e',index1,index+1)
if lette... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
word=str(input()).lower()
index=word.find('l')
letter_l=word.count('l',index,index+2)
if letter_l>=2:
index0=word.find('h',0,index+1)
letter_h=word.count('h',index0,index+1)
if letter_h>=1:
index1=word.find('e',index0,index+1)
letter_e=word.count('e',index1,index+1)
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
277 | A | Learning Languages | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu"
] | null | null | The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have the list of languages, which he knows. This list could be empty, i. e. an employee may know no official la... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=100) — the number of employees and the number of languages.
Then *n* lines follow — each employee's language list. At the beginning of the *i*-th line is integer *k**i* (0<=≤<=*k**i*<=≤<=*m*) — the number of languages the *i*-th employee knows. Next... | Print a single integer — the minimum amount of money to pay so that in the end every employee could write a letter to every other one (other employees can help out translating). | [
"5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5\n",
"8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1\n",
"2 2\n1 2\n0\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the second sample the employee 1 can learn language 2, and employee 8 can learn language 4.
In the third sample employee 2 must learn language 2. | 500 | [
{
"input": "5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5",
"output": "0"
},
{
"input": "8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1",
"output": "2"
},
{
"input": "2 2\n1 2\n0",
"output": "1"
},
{
"input": "2 2\n0\n0",
"output": "2"
},
{
"input": "5 5\n1 3\n0\n0\n2 4... | 1,624,553,217 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 218 | 1,638,400 | a = [[] for _ in range(205)]
vis = [0 for _ in range(205)]
def dfs(v):
vis[v] = 1
for i in range(len(a[v])):
if vis[a[v][i]] == 0:
dfs(a[v][i])
n, m = map(int, input().split())
x = 0
for i in range(n):
xx, *yy = map(int, input().split())
x += xx
for y in yy:
a[i+1].appe... | Title: Learning Languages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have th... | ```python
a = [[] for _ in range(205)]
vis = [0 for _ in range(205)]
def dfs(v):
vis[v] = 1
for i in range(len(a[v])):
if vis[a[v][i]] == 0:
dfs(a[v][i])
n, m = map(int, input().split())
x = 0
for i in range(n):
xx, *yy = map(int, input().split())
x += xx
for y in yy:
a... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
543 | B | Destroying Roads | PROGRAMMING | 2,100 | [
"constructive algorithms",
"graphs",
"shortest paths"
] | null | null | In some country there are exactly *n* cities and *m* bidirectional roads connecting the cities. Cities are numbered with integers from 1 to *n*. If cities *a* and *b* are connected by a road, then in an hour you can go along this road either from city *a* to city *b*, or from city *b* to city *a*. The road network is s... | The first line contains two integers *n*, *m* (1<=≤<=*n*<=≤<=3000, ) — the number of cities and roads in the country, respectively.
Next *m* lines contain the descriptions of the roads as pairs of integers *a**i*, *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*). It is guaranteed that the roads that are give... | Print a single number — the answer to the problem. If the it is impossible to meet the conditions, print -1. | [
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 2\n",
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n2 4 2\n",
"5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 1\n"
] | [
"0\n",
"1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 2",
"output": "0"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n2 4 2",
"output": "1"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n4 5\n1 3 2\n3 5 1",
"output": "-1"
},
{
"input": "9 9\n1 2\n2 3\n2 4\n4 5\n5 7\n5 6\n3 8\n8 9\n9 6\n1 7 4\... | 1,605,512,677 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 108 | 409,600 | # region My classes and methods
import copy
from collections import deque
class Queue:
def __init__(self):
self.items = deque([])
self.visited = False
def enqueue(self, item):
self.items.append(item)
def dequeue(self):
if self.items:
return self... | Title: Destroying Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In some country there are exactly *n* cities and *m* bidirectional roads connecting the cities. Cities are numbered with integers from 1 to *n*. If cities *a* and *b* are connected by a road, then in an hour you can go... | ```python
# region My classes and methods
import copy
from collections import deque
class Queue:
def __init__(self):
self.items = deque([])
self.visited = False
def enqueue(self, item):
self.items.append(item)
def dequeue(self):
if self.items:
r... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
573 | A | Bear and Poker | PROGRAMMING | 1,300 | [
"implementation",
"math",
"number theory"
] | null | null | Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid with size *a**i* dollars.
Each player can double his bid any number of times and triple his bid any nu... | First line of input contains an integer *n* (2<=≤<=*n*<=≤<=105), the number of players.
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the bids of players. | Print "Yes" (without the quotes) if players can make their bids become equal, or "No" otherwise. | [
"4\n75 150 75 50\n",
"3\n100 150 250\n"
] | [
"Yes\n",
"No\n"
] | In the first sample test first and third players should double their bids twice, second player should double his bid once and fourth player should both double and triple his bid.
It can be shown that in the second sample test there is no way to make all bids equal. | 500 | [
{
"input": "4\n75 150 75 50",
"output": "Yes"
},
{
"input": "3\n100 150 250",
"output": "No"
},
{
"input": "7\n34 34 68 34 34 68 34",
"output": "Yes"
},
{
"input": "10\n72 96 12 18 81 20 6 2 54 1",
"output": "No"
},
{
"input": "20\n958692492 954966768 77387000 724... | 1,631,653,541 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 61 | 6,963,200 | n = int(input())
temp=0
arr = map(int,input().split())
bol = True
for i in arr:
while i%2==0:
i = i //2
while i%3==0:
i = i // 3
if not temp:
temp=i
elif temp!=i:
print('No')
bol = False
if bol:
print('Yes')
| Title: Bear and Poker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is an old brown bear. He often plays poker with his friends. Today they went to a casino. There are *n* players (including Limak himself) and right now all of them have bids on the table. *i*-th of them has bid wit... | ```python
n = int(input())
temp=0
arr = map(int,input().split())
bol = True
for i in arr:
while i%2==0:
i = i //2
while i%3==0:
i = i // 3
if not temp:
temp=i
elif temp!=i:
print('No')
bol = False
if bol:
print('Yes')
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
992 | C | Nastya and a Wardrobe | PROGRAMMING | 1,600 | [
"math"
] | null | null | Nastya received a gift on New Year — a magic wardrobe. It is magic because in the end of each month the number of dresses in it doubles (i.e. the number of dresses becomes twice as large as it is in the beginning of the month).
Unfortunately, right after the doubling the wardrobe eats one of the dresses (if any) with ... | The only line contains two integers *x* and *k* (0<=≤<=*x*,<=*k*<=≤<=1018), where *x* is the initial number of dresses and *k*<=+<=1 is the number of months in a year in Byteland. | In the only line print a single integer — the expected number of dresses Nastya will own one year later modulo 109<=+<=7. | [
"2 0\n",
"2 1\n",
"3 2\n"
] | [
"4\n",
"7\n",
"21\n"
] | In the first example a year consists on only one month, so the wardrobe does not eat dresses at all.
In the second example after the first month there are 3 dresses with 50% probability and 4 dresses with 50% probability. Thus, in the end of the year there are 6 dresses with 50% probability and 8 dresses with 50% prob... | 1,500 | [
{
"input": "2 0",
"output": "4"
},
{
"input": "2 1",
"output": "7"
},
{
"input": "3 2",
"output": "21"
},
{
"input": "1 411",
"output": "485514976"
},
{
"input": "1 692",
"output": "860080936"
},
{
"input": "16 8",
"output": "7937"
},
{
"in... | 1,540,295,978 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 108 | 0 | s = input().split()
x = int(s[0])
k = int(s[1])
y = x - 0.5
print(int(pow(2, k + 1) * y + 1)) | Title: Nastya and a Wardrobe
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya received a gift on New Year — a magic wardrobe. It is magic because in the end of each month the number of dresses in it doubles (i.e. the number of dresses becomes twice as large as it is in the beginning ... | ```python
s = input().split()
x = int(s[0])
k = int(s[1])
y = x - 0.5
print(int(pow(2, k + 1) * y + 1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,618,203,774 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 409,600 | from collections import Counter
def solve():
string=input()
i=0
resStr=""
while i<len(string):
if string[i]=="-":
if string[i+1]=="-":
resStr+="2"
else:
resStr+="1"
i+=1
else:
resStr+="0"
... | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
from collections import Counter
def solve():
string=input()
i=0
resStr=""
while i<len(string):
if string[i]=="-":
if string[i+1]=="-":
resStr+="2"
else:
resStr+="1"
i+=1
else:
res... | 3.960737 | MatrixStudio/Codeforces-Python-Submissions |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,679,913,603 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | import math
l = input().split()
l[0] = int(l[0])
l[1] = int(l[1])
if int(math.sqrt(2*(240-l[1])/5)) >= l[0]:
print(l[0])
else:
print(int(math.sqrt(2*(240-l[1])/5)))
| Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
import math
l = input().split()
l[0] = int(l[0])
l[1] = int(l[1])
if int(math.sqrt(2*(240-l[1])/5)) >= l[0]:
print(l[0])
else:
print(int(math.sqrt(2*(240-l[1])/5)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,690,644,383 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | a = int(input())
if ( a >= 1 and a <= 100 and a % 2 and a != 2):
print('YES')
else:
print('NO') | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
a = int(input())
if ( a >= 1 and a <= 100 and a % 2 and a != 2):
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
631 | E | Product Sum | PROGRAMMING | 2,600 | [
"data structures",
"dp",
"geometry"
] | null | null | Blake is the boss of Kris, however, this doesn't spoil their friendship. They often gather at the bar to talk about intriguing problems about maximising some values. This time the problem is really special.
You are given an array *a* of length *n*. The characteristic of this array is the value — the sum of the produc... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=200<=000) — the size of the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*i*<=≤<=*n*, |*a**i*|<=≤<=1<=000<=000) — the elements of the array *a*. | Print a single integer — the maximum possible value of characteristic of *a* that can be obtained by performing no more than one move. | [
"4\n4 3 2 5\n",
"5\n1 1 2 7 1\n",
"3\n1 1 2\n"
] | [
"39",
"49",
"9"
] | In the first sample, one may pick the first element and place it before the third (before 5). Thus, the answer will be 3·1 + 2·2 + 4·3 + 5·4 = 39.
In the second sample, one may pick the fifth element of the array and place it before the third. The answer will be 1·1 + 1·2 + 1·3 + 2·4 + 7·5 = 49. | 2,500 | [
{
"input": "4\n4 3 2 5",
"output": "39"
},
{
"input": "5\n1 1 2 7 1",
"output": "49"
},
{
"input": "3\n1 1 2",
"output": "9"
},
{
"input": "5\n1 2 3 4 5",
"output": "55"
},
{
"input": "5\n-1 -2 -3 -4 -5",
"output": "-45"
},
{
"input": "4\n0 0 0 0",
... | 1,629,352,460 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 62 | 6,963,200 | import bisect
n=int(input())
a=[*map(int,input().split())]
q,l,r=0,[a[0]],sorted(a)
for i in range(n):q+=(i+1)*a[i]
for i in range(1,n):l+=[l[i-1]+a[i]]
l,x=[0]+l+[0],q
for i in range(1,n+1):
m=bisect.bisect(r,a[i-1])
if m>i:v=x+a[i-1]*(m-i)-l[m]+l[i]
elif m<i:v=x+a[i-1]*(m-i)+l[i-1]-l[m-1]
q... | Title: Product Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Blake is the boss of Kris, however, this doesn't spoil their friendship. They often gather at the bar to talk about intriguing problems about maximising some values. This time the problem is really special.
You are given a... | ```python
import bisect
n=int(input())
a=[*map(int,input().split())]
q,l,r=0,[a[0]],sorted(a)
for i in range(n):q+=(i+1)*a[i]
for i in range(1,n):l+=[l[i-1]+a[i]]
l,x=[0]+l+[0],q
for i in range(1,n+1):
m=bisect.bisect(r,a[i-1])
if m>i:v=x+a[i-1]*(m-i)-l[m]+l[i]
elif m<i:v=x+a[i-1]*(m-i)+l[i-1]-l[m... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,663,349,402 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n = int(input())
arr = list(map(int,input().split()))
val = max(arr)
for i in range(0,n+1):
if(val == arr[i]):
print(i+1)
break
# TODO: write code... | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n = int(input())
arr = list(map(int,input().split()))
val = max(arr)
for i in range(0,n+1):
if(val == arr[i]):
print(i+1)
break
# TODO: write code...
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-th device currently has *b**i* units of power stored. All devices can store an arbitrary amount of pow... | The first line contains two integers, *n* and *p* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*p*<=≤<=109) — the number of devices and the power of the charger.
This is followed by *n* lines which contain two integers each. Line *i* contains the integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=100<=000) — the power of the dev... | If you can use the devices indefinitely, print -1. Otherwise, print the maximum amount of time before any one device hits 0 power.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=4.
Namely, let's assume that your answer is *a* and the answer of the jury is *b*. The chec... | [
"2 1\n2 2\n2 1000\n",
"1 100\n1 1\n",
"3 5\n4 3\n5 2\n6 1\n"
] | [
"2.0000000000",
"-1\n",
"0.5000000000"
] | In sample test 1, you can charge the first device for the entire time until it hits zero power. The second device has enough power to last this time without being charged.
In sample test 2, you can use the device indefinitely.
In sample test 3, we can charge the third device for 2 / 5 of a second, then switch to char... | 0 | [
{
"input": "2 1\n2 2\n2 1000",
"output": "2.0000000000"
},
{
"input": "1 100\n1 1",
"output": "-1"
},
{
"input": "3 5\n4 3\n5 2\n6 1",
"output": "0.5000000000"
},
{
"input": "1 1\n1 87",
"output": "-1"
},
{
"input": "1 1\n100 77",
"output": "0.7777777778"
},... | 1,586,930,436 | 4,536 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 499 | 11,980,800 | import math as mt
import sys,string,bisect
input=sys.stdin.readline
import random
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
d=defaultdict(int)
n,p=M()
la=[]
s=0
for _ in r... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-th device cu... | ```python
import math as mt
import sys,string,bisect
input=sys.stdin.readline
import random
from collections import deque,defaultdict
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
d=defaultdict(int)
n,p=M()
la=[]
s=0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,536,924,492 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 218 | 0 | def isSolved(x,k):
for i in range(k-1, len(x)-1):
if(x[i] != x[i+1]):
return False
return True
def findTotal(x):
for i in range(len(x)-1, 0, -1):
if(x[i] != x[i-1]):
return i
def main():
inps = list(map(int, input().rstrip().split()))
n,k,total ... | Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
def isSolved(x,k):
for i in range(k-1, len(x)-1):
if(x[i] != x[i+1]):
return False
return True
def findTotal(x):
for i in range(len(x)-1, 0, -1):
if(x[i] != x[i-1]):
return i
def main():
inps = list(map(int, input().rstrip().split()))
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,587,746,360 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 109 | 0 | d1,d2,d3=map(int,input().split())
z1=d1+d2+d3
z2=(d1*2)+(d2*2)
z3=(d1*2)+(d3*2)
z4=(d2*2)+(d3*2)
ans=min(z1,z2,z3,z4)
print(ans) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
d1,d2,d3=map(int,input().split())
z1=d1+d2+d3
z2=(d1*2)+(d2*2)
z3=(d1*2)+(d3*2)
z4=(d2*2)+(d3*2)
ans=min(z1,z2,z3,z4)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
632 | D | Longest Subsequence | PROGRAMMING | 2,100 | [
"brute force",
"math",
"number theory"
] | null | null | You are given array *a* with *n* elements and the number *m*. Consider some subsequence of *a* and the value of least common multiple (LCM) of its elements. Denote LCM as *l*. Find any longest subsequence of *a* with the value *l*<=≤<=*m*.
A subsequence of *a* is an array we can get by erasing some elements of *a*. It... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=106) — the size of the array *a* and the parameter from the problem statement.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of *a*. | In the first line print two integers *l* and *k**max* (1<=≤<=*l*<=≤<=*m*,<=0<=≤<=*k**max*<=≤<=*n*) — the value of LCM and the number of elements in optimal subsequence.
In the second line print *k**max* integers — the positions of the elements from the optimal subsequence in the ascending order.
Note that you can fin... | [
"7 8\n6 2 9 2 7 2 3\n",
"6 4\n2 2 2 3 3 3\n"
] | [
"6 5\n1 2 4 6 7\n",
"2 3\n1 2 3\n"
] | none | 0 | [
{
"input": "7 8\n6 2 9 2 7 2 3",
"output": "6 5\n1 2 4 6 7"
},
{
"input": "6 4\n2 2 2 3 3 3",
"output": "2 3\n1 2 3"
},
{
"input": "10 50\n39 22 60 88 11 65 41 85 65 100",
"output": "22 2\n2 5"
},
{
"input": "100 343\n999 284 486 785 176 742 856 415 992 601 600 122 460 214 33... | 1,648,969,321 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | import sys
input = sys.stdin.readline
n, m = map(int, input().split())
a = [int(x) for x in input().split()]
arr=[0]*(m+1)
for x in a:
if x <= m:
arr[x] += 1
for i in range(m//2, 0, -1):
for j in range(i*2, m+1, i):
arr[j] += arr[x]
ind = arr.index(max(arr))
print(ind, arr[ind])
for i, x in enumerate(a):
if ind... | Title: Longest Subsequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array *a* with *n* elements and the number *m*. Consider some subsequence of *a* and the value of least common multiple (LCM) of its elements. Denote LCM as *l*. Find any longest subsequence of *a* wit... | ```python
import sys
input = sys.stdin.readline
n, m = map(int, input().split())
a = [int(x) for x in input().split()]
arr=[0]*(m+1)
for x in a:
if x <= m:
arr[x] += 1
for i in range(m//2, 0, -1):
for j in range(i*2, m+1, i):
arr[j] += arr[x]
ind = arr.index(max(arr))
print(ind, arr[ind])
for i, x in enumerate(a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
534 | C | Polycarpus' Dice | PROGRAMMING | 1,600 | [
"math"
] | null | null | Polycarp has *n* dice *d*1,<=*d*2,<=...,<=*d**n*. The *i*-th dice shows numbers from 1 to *d**i*. Polycarp rolled all the dice and the sum of numbers they showed is *A*. Agrippina didn't see which dice showed what number, she knows only the sum *A* and the values *d*1,<=*d*2,<=...,<=*d**n*. However, she finds it enough... | The first line contains two integers *n*,<=*A* (1<=≤<=*n*<=≤<=2·105,<=*n*<=≤<=*A*<=≤<=*s*) — the number of dice and the sum of shown values where *s*<==<=*d*1<=+<=*d*2<=+<=...<=+<=*d**n*.
The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=106), where *d**i* is the maximum value that the... | Print *n* integers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* is the number of values for which it is guaranteed that the *i*-th dice couldn't show them. | [
"2 8\n4 4\n",
"1 3\n5\n",
"2 3\n2 3\n"
] | [
"3 3 ",
"4 ",
"0 1 "
] | In the first sample from the statement *A* equal to 8 could be obtained in the only case when both the first and the second dice show 4. Correspondingly, both dice couldn't show values 1, 2 or 3.
In the second sample from the statement *A* equal to 3 could be obtained when the single dice shows 3. Correspondingly, it ... | 1,500 | [
{
"input": "2 8\n4 4",
"output": "3 3 "
},
{
"input": "1 3\n5",
"output": "4 "
},
{
"input": "2 3\n2 3",
"output": "0 1 "
},
{
"input": "1 1\n3",
"output": "2 "
},
{
"input": "1 2\n3",
"output": "2 "
},
{
"input": "2 2\n2 3",
"output": "1 2 "
},
... | 1,670,962,887 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 99 | 202 | 28,774,400 | from bisect import *
from collections import *
import sys
import io, os
import math
import random
from heapq import *
gcd = math.gcd
sqrt = math.sqrt
maxint=10**21
def ceil(a, b):
if(b==0):
return maxint
a = -a
k = a // b
k = -k
return k
# n,m=map(int,input().split())
# a... | Title: Polycarpus' Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has *n* dice *d*1,<=*d*2,<=...,<=*d**n*. The *i*-th dice shows numbers from 1 to *d**i*. Polycarp rolled all the dice and the sum of numbers they showed is *A*. Agrippina didn't see which dice showed what numb... | ```python
from bisect import *
from collections import *
import sys
import io, os
import math
import random
from heapq import *
gcd = math.gcd
sqrt = math.sqrt
maxint=10**21
def ceil(a, b):
if(b==0):
return maxint
a = -a
k = a // b
k = -k
return k
# n,m=map(int,input().spl... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | A tree is an undirected connected graph without cycles.
Let's consider a rooted undirected tree with *n* vertices, numbered 1 through *n*. There are many ways to represent such a tree. One way is to create an array with *n* integers *p*1,<=*p*2,<=...,<=*p**n*, where *p**i* denotes a parent of vertex *i* (here, for con... | The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=200<=000) — the number of vertices in the tree.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*). | In the first line print the minimum number of elements to change, in order to get a valid sequence.
In the second line, print any valid sequence possible to get from (*a*1,<=*a*2,<=...,<=*a**n*) in the minimum number of changes. If there are many such sequences, any of them will be accepted. | [
"4\n2 3 3 4\n",
"5\n3 2 2 5 3\n",
"8\n2 3 5 4 1 6 6 7\n"
] | [
"1\n2 3 4 4 \n",
"0\n3 2 2 5 3 \n",
"2\n2 3 7 8 1 6 6 7\n"
] | In the first sample, it's enough to change one element. In the provided output, a sequence represents a tree rooted in a vertex 4 (because *p*<sub class="lower-index">4</sub> = 4), which you can see on the left drawing below. One of other correct solutions would be a sequence 2 3 3 2, representing a tree rooted in vert... | 0 | [
{
"input": "4\n2 3 3 4",
"output": "1\n2 3 4 4 "
},
{
"input": "5\n3 2 2 5 3",
"output": "0\n3 2 2 5 3 "
},
{
"input": "8\n2 3 5 4 1 6 6 7",
"output": "2\n2 3 7 8 1 6 6 7"
},
{
"input": "2\n1 2",
"output": "1\n2 2 "
},
{
"input": "7\n4 3 2 6 3 5 2",
"output": ... | 1,598,269,195 | 2,147,483,647 | PyPy 3 | OK | TESTS | 101 | 436 | 40,448,000 | import math,sys,bisect,heapq
from collections import defaultdict,Counter,deque
from itertools import groupby,accumulate
#sys.setrecursionlimit(200000000)
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
ilele = lambda: map(int,input().split())
alele = lambda: list(map(int, input().split()))
f... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is an undirected connected graph without cycles.
Let's consider a rooted undirected tree with *n* vertices, numbered 1 through *n*. There are many ways to represent such a tree. One way is to create an array with *n* integ... | ```python
import math,sys,bisect,heapq
from collections import defaultdict,Counter,deque
from itertools import groupby,accumulate
#sys.setrecursionlimit(200000000)
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
ilele = lambda: map(int,input().split())
alele = lambda: list(map(int, input().sp... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
78 | A | Haiku | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Haiku | 2 | 256 | Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syll... | The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The *i*-th line contains the *i*-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailin... | Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes). | [
"on codeforces \nbeta round is running\n a rustling of keys \n",
"how many gallons\nof edo s rain did you drink\n cuckoo\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "on codeforces \nbeta round is running\n a rustling of keys ",
"output": "YES"
},
{
"input": "how many gallons\nof edo s rain did you drink\n cuckoo",
"output": "NO"
},
{
"input": " hatsu shigure\n saru mo komino wo\nhoshige nari",
... | 1,657,842,070 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | a = str(input())
b = str(input())
c = str(input())
def fun(f):
x = 0
for i in range(0, len(f)):
if f[i] == 'a'or f[i] == 'e' or f[i] == 'i'or f[i] == 'o' or f[i] == 'u':
x+=1
return x
if fun(a) == 5 and fun(b) == 7 and fun(c) == 5:
print("YES")
else:
print("NO")
| Title: Haiku
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase... | ```python
a = str(input())
b = str(input())
c = str(input())
def fun(f):
x = 0
for i in range(0, len(f)):
if f[i] == 'a'or f[i] == 'e' or f[i] == 'i'or f[i] == 'o' or f[i] == 'u':
x+=1
return x
if fun(a) == 5 and fun(b) == 7 and fun(c) == 5:
print("YES")
else:
print("... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
864 | A | Fair Game | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | Petya and Vasya decided to play a game. They have *n* cards (*n* is an even number). A single integer is written on each card.
Before the game Petya will choose an integer and after that Vasya will choose another integer (different from the number that Petya chose). During the game each player takes all the cards with... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=100) — number of cards. It is guaranteed that *n* is an even number.
The following *n* lines contain a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (one integer per line, 1<=≤<=*a**i*<=≤<=100) — numbers written on the *n* cards. | If it is impossible for Petya and Vasya to choose numbers in such a way that the game will be fair, print "NO" (without quotes) in the first line. In this case you should not print anything more.
In the other case print "YES" (without quotes) in the first line. In the second line print two distinct integers — number t... | [
"4\n11\n27\n27\n11\n",
"2\n6\n6\n",
"6\n10\n20\n30\n20\n10\n20\n",
"6\n1\n1\n2\n2\n3\n3\n"
] | [
"YES\n11 27\n",
"NO\n",
"NO\n",
"NO\n"
] | In the first example the game will be fair if, for example, Petya chooses number 11, and Vasya chooses number 27. Then the will take all cards — Petya will take cards 1 and 4, and Vasya will take cards 2 and 3. Thus, each of them will take exactly two cards.
In the second example fair game is impossible because the nu... | 500 | [
{
"input": "4\n11\n27\n27\n11",
"output": "YES\n11 27"
},
{
"input": "2\n6\n6",
"output": "NO"
},
{
"input": "6\n10\n20\n30\n20\n10\n20",
"output": "NO"
},
{
"input": "6\n1\n1\n2\n2\n3\n3",
"output": "NO"
},
{
"input": "2\n1\n100",
"output": "YES\n1 100"
},
... | 1,520,881,786 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 5,632,000 | n = int(input())
a = [int(input()) for i in range(n)]
a = [[i, a.count(i)] for i in sorted(set(a))]
for p in a:
for q in a:
if p!=q and p[1]==q[1]:
print("YES")
print(p[0], q[0])
quit()
print("NO")
| Title: Fair Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya decided to play a game. They have *n* cards (*n* is an even number). A single integer is written on each card.
Before the game Petya will choose an integer and after that Vasya will choose another integer (di... | ```python
n = int(input())
a = [int(input()) for i in range(n)]
a = [[i, a.count(i)] for i in sorted(set(a))]
for p in a:
for q in a:
if p!=q and p[1]==q[1]:
print("YES")
print(p[0], q[0])
quit()
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,696,241,888 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | sentence = input()
sentence = sentence.replace(sentence[0],sentence[0].upper(),1)
print(sentence) | Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
sentence = input()
sentence = sentence.replace(sentence[0],sentence[0].upper(),1)
print(sentence)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to a... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=<<=*s*), where *n* and *m* are the maze's height and width, correspondingly, *k* is the number of walls Pavel wants to add and letter *s* represents the number of empty cells in the original maze.
Each of the next *n* lines co... | Print *n* lines containing *m* characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").
It is guaranteed that a solution exists. If there are multiple solutions you can output any of t... | [
"3 4 2\n#..#\n..#.\n#...\n",
"5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#\n"
] | [
"#.X#\nX.#.\n#...\n",
"#XXX\n#X#.\nX#..\n...#\n.#.#\n"
] | none | 0 | [
{
"input": "5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#",
"output": "#XXX\n#X#.\nX#..\n...#\n.#.#"
},
{
"input": "3 3 2\n#.#\n...\n#.#",
"output": "#X#\nX..\n#.#"
},
{
"input": "7 7 18\n#.....#\n..#.#..\n.#...#.\n...#...\n.#...#.\n..#.#..\n#.....#",
"output": "#XXXXX#\nXX#X#X.\nX#XXX#.\nXXX#... | 1,650,600,273 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 6 | 170 | 20,172,800 | dx = [0,1,0,-1]
dy = [1,0,-1,0]
def PRINT(maze):
for i in range(len(maze)):
print(*maze[i],sep='')
def dfs(maze, visited, cnt, i, j):
if cnt[0]<=0:
return
n,m = len(maze),len(maze[0])
for ii in range(4):
if cnt[0]<=0:
return
x,y = dx[ii]+i,dy... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze w... | ```python
dx = [0,1,0,-1]
dy = [1,0,-1,0]
def PRINT(maze):
for i in range(len(maze)):
print(*maze[i],sep='')
def dfs(maze, visited, cnt, i, j):
if cnt[0]<=0:
return
n,m = len(maze),len(maze[0])
for ii in range(4):
if cnt[0]<=0:
return
x,y = d... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
570 | A | Elections | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusual. At the first stage of elections the votes are counted for each city: it is assumed that in ... | The first line of the input contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of candidates and of cities, respectively.
Each of the next *m* lines contains *n* non-negative integers, the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*j*<=≤<=*n*, 1<=≤<=*i*<=≤<=*m*, 0<=≤<=*a**ij*<=≤<=109) denotes ... | Print a single number — the index of the candidate who won the elections. The candidates are indexed starting from one. | [
"3 3\n1 2 3\n2 3 1\n1 2 1\n",
"3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7\n"
] | [
"2",
"1"
] | Note to the first sample test. At the first stage city 1 chosen candidate 3, city 2 chosen candidate 2, city 3 chosen candidate 2. The winner is candidate 2, he gained 2 votes.
Note to the second sample test. At the first stage in city 1 candidates 1 and 2 got the same maximum number of votes, but candidate 1 has a sm... | 500 | [
{
"input": "3 3\n1 2 3\n2 3 1\n1 2 1",
"output": "2"
},
{
"input": "3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7",
"output": "1"
},
{
"input": "1 3\n5\n3\n2",
"output": "1"
},
{
"input": "3 1\n1 2 3",
"output": "3"
},
{
"input": "3 1\n100 100 100",
"output": "1"
},
{... | 1,649,219,801 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 62 | 102,400 | from collections import defaultdict
n,m=map(int,input().split())
d=defaultdict(int)
for _ in range(m):
a=list(map(int,input().strip().split()))
mx=max(a)
for i in range(n):
if a[i]==mx:break
d[i+1]+=1
mx=0
for x in d:
if d[x]>mx:mx=d[x]
b=[]
for x in d:
if d[x]==mx:b.append... | Title: Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusu... | ```python
from collections import defaultdict
n,m=map(int,input().split())
d=defaultdict(int)
for _ in range(m):
a=list(map(int,input().strip().split()))
mx=max(a)
for i in range(n):
if a[i]==mx:break
d[i+1]+=1
mx=0
for x in d:
if d[x]>mx:mx=d[x]
b=[]
for x in d:
if d[x]==m... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,691,400,026 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | x=input()
y=input()
s=''.join(sorted(x))
if s==y:
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
x=input()
y=input()
s=''.join(sorted(x))
if s==y:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
559 | A | Gerald's Hexagon | PROGRAMMING | 1,600 | [
"brute force",
"geometry",
"math"
] | null | null | Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to . Then he measured the length of its sides, and found that each of them is equal to an integer number of centimeters. There the properties of the hexagon ended and Gerald decided to draw on it.
He pain... | The first and the single line of the input contains 6 space-separated integers *a*1,<=*a*2,<=*a*3,<=*a*4,<=*a*5 and *a*6 (1<=≤<=*a**i*<=≤<=1000) — the lengths of the sides of the hexagons in centimeters in the clockwise order. It is guaranteed that the hexagon with the indicated properties and the exactly such sides ex... | Print a single integer — the number of triangles with the sides of one 1 centimeter, into which the hexagon is split. | [
"1 1 1 1 1 1\n",
"1 2 1 2 1 2\n"
] | [
"6\n",
"13\n"
] | This is what Gerald's hexagon looks like in the first sample:
<img class="tex-graphics" src="https://espresso.codeforces.com/84d193e27b02c38eb1eadc536602a2ec0b9f9519.png" style="max-width: 100.0%;max-height: 100.0%;"/>
And that's what it looks like in the second sample:
<img class="tex-graphics" src="https://espress... | 500 | [
{
"input": "1 1 1 1 1 1",
"output": "6"
},
{
"input": "1 2 1 2 1 2",
"output": "13"
},
{
"input": "2 4 5 3 3 6",
"output": "83"
},
{
"input": "45 19 48 18 46 21",
"output": "6099"
},
{
"input": "66 6 65 6 66 5",
"output": "5832"
},
{
"input": "7 5 4 8 ... | 1,597,937,290 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 93 | 0 | # from decimal import *
# getcontext().prec=16
# from math import sqrt
# from scipy.special import binom
# from collections import defaultdict
# from math import sin,pi,sqrt
liste=list(map(int,input().split(' ')))
number=(liste[0]+liste[1]+liste[2])**2-liste[0]**2-liste[2]**2-liste[4]**2
print(number) | Title: Gerald's Hexagon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to . Then he measured the length of its sides, and found that each of them is equal to an integer numbe... | ```python
# from decimal import *
# getcontext().prec=16
# from math import sqrt
# from scipy.special import binom
# from collections import defaultdict
# from math import sin,pi,sqrt
liste=list(map(int,input().split(' ')))
number=(liste[0]+liste[1]+liste[2])**2-liste[0]**2-liste[2]**2-liste[4]**2
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,690,199,857 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | m = list(map (int , input() . split()))
for i in range(1,11):
x = m[0]*i-m[1]
y = m[0]*i
if x % 10 == 0 or y % 10 == 0 :
print(i)
break
| Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
m = list(map (int , input() . split()))
for i in range(1,11):
x = m[0]*i-m[1]
y = m[0]*i
if x % 10 == 0 or y % 10 == 0 :
print(i)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,674,579,382 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n=int(input())
l=[]
a=[]
for i in range(0,n):
p,q=map(int,input().split())
l.append(p)
a.append(q)
t=0
for i in range(0,n):
for j in range(0,n):
if l[i]==a[j]:
t=t+1
print(t) | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
n=int(input())
l=[]
a=[]
for i in range(0,n):
p,q=map(int,input().split())
l.append(p)
a.append(q)
t=0
for i in range(0,n):
for j in range(0,n):
if l[i]==a[j]:
t=t+1
print(t)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,539,525,499 | 2,147,483,647 | PyPy 3 | OK | TESTS | 36 | 280 | 0 | a,b = map(int,input().split())
c = 7 - max(a,b)
if c == 1: print("1/6")
elif c == 2: print("1/3")
elif c == 3: print("1/2")
elif c == 4: print("2/3")
elif c == 5: print("5/6")
elif c == 6: print("1/1") | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
a,b = map(int,input().split())
c = 7 - max(a,b)
if c == 1: print("1/6")
elif c == 2: print("1/3")
elif c == 3: print("1/2")
elif c == 4: print("2/3")
elif c == 5: print("5/6")
elif c == 6: print("1/1")
``` | 3.86 | MatrixStudio/Codeforces-Python-Submissions |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,573,961,495 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 216 | 307,200 | n = int(input())
rank = []
rank1 = []
name = []
name2 = []
max1 = 0
for i in range(n):
name1, score1 = input().split()
score1 = int(score1)
if name1 in name :
x = name.index(name1)
rank[x] = rank[x] + score1
while x > 0 and rank[x-1] < rank[x]:
rank[x - 1], r... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n = int(input())
rank = []
rank1 = []
name = []
name2 = []
max1 = 0
for i in range(n):
name1, score1 = input().split()
score1 = int(score1)
if name1 in name :
x = name.index(name1)
rank[x] = rank[x] + score1
while x > 0 and rank[x-1] < rank[x]:
rank... | -1 | MatrixStudio/Codeforces-Python-Submissions |
398 | A | Cards | PROGRAMMING | 0 | [
"constructive algorithms",
"implementation"
] | null | null | User ainta loves to play with cards. He has *a* cards containing letter "o" and *b* cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0. 1. For each block of contiguous "o"s with length *x* the score increases by *x*2. 1.... | The first line contains two space-separated integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=105; *a*<=+<=*b*<=≥<=1) — the number of "o" cards and the number of "x" cards. | In the first line print a single integer *v* — the maximum score that ainta can obtain.
In the second line print *a*<=+<=*b* characters describing the deck. If the *k*-th card of the deck contains "o", the *k*-th character must be "o". If the *k*-th card of the deck contains "x", the *k*-th character must be "x". The ... | [
"2 3\n",
"4 0\n",
"0 4\n"
] | [
"-1\nxoxox\n",
"16\noooo",
"-16\nxxxx"
] | none | 500 | [
{
"input": "2 3",
"output": "-1\nxoxox"
},
{
"input": "4 0",
"output": "16\noooo"
},
{
"input": "0 4",
"output": "-16\nxxxx"
},
{
"input": "8 6",
"output": "46\nxxxooooooooxxx"
},
{
"input": "28691 28312",
"output": "809737773\nxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx... | 1,548,477,004 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 108 | 0 | import math
inp = input().split()
a = int(inp[0])
b = int(inp[1])
if a > b:
st = int(math.floor(b/2))
ed = int(math.ceil(b/2))
print(str(a**2 - int(st)**2 - int(ed)**2))
out = "x" * st + "o" * a + "x" * ed
print(out)
elif a < b:
mi = b - a + 1
st = int(math.floor(mi/2))
ed = int(math.c... | Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
User ainta loves to play with cards. He has *a* cards containing letter "o" and *b* cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score ... | ```python
import math
inp = input().split()
a = int(inp[0])
b = int(inp[1])
if a > b:
st = int(math.floor(b/2))
ed = int(math.ceil(b/2))
print(str(a**2 - int(st)**2 - int(ed)**2))
out = "x" * st + "o" * a + "x" * ed
print(out)
elif a < b:
mi = b - a + 1
st = int(math.floor(mi/2))
ed = ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,572,345,850 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 216 | 0 | a=input()
b=list(a)
c=len(b)
n=0
for i in range(c):
if b[i]<a:
n=n+1
d="".join(b)
if 2*n>c:
e=d.upper()
else:
e=d.lower()
print(e)
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
a=input()
b=list(a)
c=len(b)
n=0
for i in range(c):
if b[i]<a:
n=n+1
d="".join(b)
if 2*n>c:
e=d.upper()
else:
e=d.lower()
print(e)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
274 | A | k-Multiple Free Set | PROGRAMMING | 1,500 | [
"binary search",
"greedy",
"sortings"
] | null | null | A *k*-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by *k*. That is, there are no two integers *x* and *y* (*x*<=<<=*y*) from the set, such that *y*<==<=*x*·*k*.
You're given a set of *n* distinct positive integers. Your task is to find th... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=109). The next line contains a list of *n* distinct positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
All the numbers in the lines are separated by single spaces. | On the only line of the output print the size of the largest *k*-multiple free subset of {*a*1,<=*a*2,<=...,<=*a**n*}. | [
"6 2\n2 3 6 5 4 10\n"
] | [
"3\n"
] | In the sample input one of the possible maximum 2-multiple free subsets is {4, 5, 6}. | 500 | [
{
"input": "6 2\n2 3 6 5 4 10",
"output": "3"
},
{
"input": "10 2\n1 2 3 4 5 6 7 8 9 10",
"output": "6"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "100 2\n191 17 61 40 77 95 128 88 26 69 79 10 131 106 142 152 68 39 182 53 83 81 6 89 65 148 33 22 5 47 107 121 52 163 1... | 1,414,094,850 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | n, k=int(input()), int(input())
a=list(input())
t=0
for i in range(0,len(a)):
a[i]=int(a[i])
for i in a:
for j in a:
if k*i==j:
t=t+1
print(t)
| Title: k-Multiple Free Set
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A *k*-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by *k*. That is, there are no two integers *x* and *y* (*x*<=<<=*y*) from the set, ... | ```python
n, k=int(input()), int(input())
a=list(input())
t=0
for i in range(0,len(a)):
a[i]=int(a[i])
for i in a:
for j in a:
if k*i==j:
t=t+1
print(t)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
879 | B | Table Tennis | PROGRAMMING | 1,200 | [
"data structures",
"implementation"
] | null | null | *n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. They play until someone wins *k* games in a row. This player becomes the winner.
For each of t... | The first line contains two integers: *n* and *k* (2<=≤<=*n*<=≤<=500, 2<=≤<=*k*<=≤<=1012) — the number of people and the number of wins.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — powers of the player. It's guaranteed that this line contains a valid permutation, i.e. all ... | Output a single integer — power of the winner. | [
"2 2\n1 2\n",
"4 2\n3 1 2 4\n",
"6 2\n6 5 3 1 2 4\n",
"2 10000000000\n2 1\n"
] | [
"2 ",
"3 ",
"6 ",
"2\n"
] | Games in the second sample:
3 plays with 1. 3 wins. 1 goes to the end of the line.
3 plays with 2. 3 wins. He wins twice in a row. He becomes the winner. | 1,000 | [
{
"input": "2 2\n1 2",
"output": "2 "
},
{
"input": "4 2\n3 1 2 4",
"output": "3 "
},
{
"input": "6 2\n6 5 3 1 2 4",
"output": "6 "
},
{
"input": "2 10000000000\n2 1",
"output": "2"
},
{
"input": "4 4\n1 3 4 2",
"output": "4 "
},
{
"input": "2 21474836... | 1,573,051,145 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 124 | 0 | n, k = map(int, input().rstrip().split(' '))
player = list(map(int, input().rstrip().split(' ')))
if n <= k:
k = n - 1
playWin = 0
count = 0
for i in range(1, n):
tempComp = max(player[i], player[playWin])
if player[playWin] == tempComp:
count += 1
else:
count = 1
playWin = i
if count == ... | Title: Table Tennis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so o... | ```python
n, k = map(int, input().rstrip().split(' '))
player = list(map(int, input().rstrip().split(' ')))
if n <= k:
k = n - 1
playWin = 0
count = 0
for i in range(1, n):
tempComp = max(player[i], player[playWin])
if player[playWin] == tempComp:
count += 1
else:
count = 1
playWin = i
if... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
484 | D | Kindergarten | PROGRAMMING | 2,400 | [
"data structures",
"dp",
"greedy"
] | null | null | In a kindergarten, the children are being divided into groups. The teacher put the children in a line and associated each child with his or her integer charisma value. Each child should go to exactly one group. Each group should be a nonempty segment of consecutive children of a line. A group's sociability is the maxim... | The first line contains integer *n* — the number of children in the line (1<=≤<=*n*<=≤<=106).
The second line contains *n* integers *a**i* — the charisma of the *i*-th child (<=-<=109<=≤<=*a**i*<=≤<=109). | Print the maximum possible total sociability of all groups. | [
"5\n1 2 3 1 2\n",
"3\n3 3 3\n"
] | [
"3\n",
"0\n"
] | In the first test sample one of the possible variants of an division is following: the first three children form a group with sociability 2, and the two remaining children form a group with sociability 1.
In the second test sample any division leads to the same result, the sociability will be equal to 0 in each group. | 2,000 | [
{
"input": "5\n1 2 3 1 2",
"output": "3"
},
{
"input": "3\n3 3 3",
"output": "0"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n-1000000000 1000000000",
"output": "2000000000"
},
{
"input": "4\n1 4 2 3",
"output": "4"
},
{
"input": "4\n23 5 7 1"... | 1,596,009,441 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include<bits/stdc++.h>
#define _ ;
#define __ (
#define ___ )
#define ____ [
#define _____ ]
#define ______ ,
#define _______ {
#define ________ }
#define _________ <=
#define __________ =
#define ___________ +
#define ____________ -
#define _____________ >>
#define ______________ <<
#define ___________... | Title: Kindergarten
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a kindergarten, the children are being divided into groups. The teacher put the children in a line and associated each child with his or her integer charisma value. Each child should go to exactly one group. Each group ... | ```python
#include<bits/stdc++.h>
#define _ ;
#define __ (
#define ___ )
#define ____ [
#define _____ ]
#define ______ ,
#define _______ {
#define ________ }
#define _________ <=
#define __________ =
#define ___________ +
#define ____________ -
#define _____________ >>
#define ______________ <<
#define _... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
847 | G | University Classes | PROGRAMMING | 900 | [
"implementation"
] | null | null | There are *n* student groups at the university. During the study day, each group can take no more than 7 classes. Seven time slots numbered from 1 to 7 are allocated for the classes.
The schedule on Monday is known for each group, i. e. time slots when group will have classes are known.
Your task is to determine the ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of groups.
Each of the following *n* lines contains a sequence consisting of 7 zeroes and ones — the schedule of classes on Monday for a group. If the symbol in a position equals to 1 then the group has class in the corresponding time slot... | Print minimum number of rooms needed to hold all groups classes on Monday. | [
"2\n0101010\n1010101\n",
"3\n0101011\n0011001\n0110111\n"
] | [
"1\n",
"3\n"
] | In the first example one room is enough. It will be occupied in each of the seven time slot by the first group or by the second group.
In the second example three rooms is enough, because in the seventh time slot all three groups have classes. | 0 | [
{
"input": "2\n0101010\n1010101",
"output": "1"
},
{
"input": "3\n0101011\n0011001\n0110111",
"output": "3"
},
{
"input": "1\n0111000",
"output": "1"
},
{
"input": "1\n0000000",
"output": "0"
},
{
"input": "1\n1111111",
"output": "1"
},
{
"input": "2\n... | 1,689,258,776 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print("_RANDOM_GUESS_1689258775.838717")# 1689258775.838737 | Title: University Classes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* student groups at the university. During the study day, each group can take no more than 7 classes. Seven time slots numbered from 1 to 7 are allocated for the classes.
The schedule on Monday is known ... | ```python
print("_RANDOM_GUESS_1689258775.838717")# 1689258775.838737
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
430 | B | Balls Game | PROGRAMMING | 1,400 | [
"brute force",
"two pointers"
] | null | null | Iahub is training for the IOI. What is a better way to train than playing a Zuma-like game?
There are *n* balls put in a row. Each ball is colored in one of *k* colors. Initially the row doesn't contain three or more contiguous balls with the same color. Iahub has a single ball of color *x*. He can insert his ball at... | The first line of input contains three integers: *n* (1<=≤<=*n*<=≤<=100), *k* (1<=≤<=*k*<=≤<=100) and *x* (1<=≤<=*x*<=≤<=*k*). The next line contains *n* space-separated integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=*k*). Number *c**i* means that the *i*-th ball in the row has color *c**i*.
It is guaranteed th... | Print a single integer — the maximum number of balls Iahub can destroy. | [
"6 2 2\n1 1 2 2 1 1\n",
"1 1 1\n1\n"
] | [
"6\n",
"0\n"
] | none | 1,000 | [
{
"input": "6 2 2\n1 1 2 2 1 1",
"output": "6"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 2 1\n2 1 2 2 1 2 2 1 1 2",
"output": "5"
},
{
"input": "50 2 1\n1 1 2 2 1 2 1 1 2 2 1 2 1 2 1 1 2 2 1 2 1 2 2 1 2 1 2 1 2 2 1 1 2 2 1 1 2 2 1 2 1 1 2 1 1 2 2 1 1 2",
"... | 1,680,292,307 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 46 | 0 | numero_bolas, limite_cores, bola_inserida = input().split()
numero_bolas = int(numero_bolas)
limite_cores = int(limite_cores)
# lendo as bolas e atribuindo à lista lista_bolas
lista_bolas = input().split()
# inicializando a variável resposta
resposta = 0
# iterando sobre as posições possíveis para inserir ... | Title: Balls Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub is training for the IOI. What is a better way to train than playing a Zuma-like game?
There are *n* balls put in a row. Each ball is colored in one of *k* colors. Initially the row doesn't contain three or more conti... | ```python
numero_bolas, limite_cores, bola_inserida = input().split()
numero_bolas = int(numero_bolas)
limite_cores = int(limite_cores)
# lendo as bolas e atribuindo à lista lista_bolas
lista_bolas = input().split()
# inicializando a variável resposta
resposta = 0
# iterando sobre as posições possíveis par... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
909 | A | Generate Login | PROGRAMMING | 1,000 | [
"brute force",
"greedy",
"sortings"
] | null | null | The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the full name. Typically there are multiple possible logins for each person.
You are given the first and ... | The input consists of a single line containing two space-separated strings: the first and the last names. Each character of each string is a lowercase English letter. The length of each string is between 1 and 10, inclusive. | Output a single string — alphabetically earliest possible login formed from these names. The output should be given in lowercase as well. | [
"harry potter\n",
"tom riddle\n"
] | [
"hap\n",
"tomr\n"
] | none | 500 | [
{
"input": "harry potter",
"output": "hap"
},
{
"input": "tom riddle",
"output": "tomr"
},
{
"input": "a qdpinbmcrf",
"output": "aq"
},
{
"input": "wixjzniiub ssdfodfgap",
"output": "wis"
},
{
"input": "z z",
"output": "zz"
},
{
"input": "ertuyivhfg v"... | 1,514,396,526 | 4,026 | Python 3 | COMPILATION_ERROR | PRETESTS | 0 | 0 | 0 | f,l = input().split()
ans = ''
if len(f) > 3
ans = f[:3] + l[0]
else:
ans = f[:2] + l[0]
print(ans)
| Title: Generate Login
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the fu... | ```python
f,l = input().split()
ans = ''
if len(f) > 3
ans = f[:3] + l[0]
else:
ans = f[:2] + l[0]
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
884 | A | Book Reading | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of seconds that Luba has to spend working during *i*-th day is *a**i*. If some free time remains, she... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=100, 1<=≤<=*t*<=≤<=106) — the number of days and the time required to read the book.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=86400) — the time Luba has to spend on her work during *i*-th day. | Print the minimum day Luba can finish reading the book.
It is guaranteed that answer doesn't exceed *n*. | [
"2 2\n86400 86398\n",
"2 86400\n0 86400\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "2 2\n86400 86398",
"output": "2"
},
{
"input": "2 86400\n0 86400",
"output": "1"
},
{
"input": "2 86400\n1 86399",
"output": "2"
},
{
"input": "100 1000000\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,618,645,272 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | n,t=map(int,input().split())
s,d=0,0
a=list(map(int,input().split()))
for i in range(0,n):
if s<t:
s=s(86400-a[i])
d+=1
else:
print(d)
break
| Title: Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of ... | ```python
n,t=map(int,input().split())
s,d=0,0
a=list(map(int,input().split()))
for i in range(0,n):
if s<t:
s=s(86400-a[i])
d+=1
else:
print(d)
break
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
697 | B | Barnicle | PROGRAMMING | 1,400 | [
"brute force",
"implementation",
"math",
"strings"
] | null | null | Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl about this distance value, but Carl was so busy talking to the customers so he wrote the distance ... | The first and only line of input contains a single string of form *a*.*deb* where *a*, *d* and *b* are integers and *e* is usual character 'e' (0<=≤<=*a*<=≤<=9,<=0<=≤<=*d*<=<<=10100,<=0<=≤<=*b*<=≤<=100) — the scientific notation of the desired distance value.
*a* and *b* contain no leading zeros and *d* contains no... | Print the only real number *x* (the desired distance value) in the only line in its decimal notation.
Thus if *x* is an integer, print it's integer value without decimal part and decimal point and without leading zeroes.
Otherwise print *x* in a form of *p*.*q* such that *p* is an integer that have no leading zeroe... | [
"8.549e2\n",
"8.549e3\n",
"0.33e0\n"
] | [
"854.9\n",
"8549\n",
"0.33\n"
] | none | 1,000 | [
{
"input": "8.549e2",
"output": "854.9"
},
{
"input": "8.549e3",
"output": "8549"
},
{
"input": "0.33e0",
"output": "0.33"
},
{
"input": "1.31e1",
"output": "13.1"
},
{
"input": "1.038e0",
"output": "1.038"
},
{
"input": "8.25983e5",
"output": "825... | 1,475,915,694 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 62 | 4,608,000 | s=input()
i=len(s)-1
while s[i]!='e':
i-=1
b=int(s[i+1:len(s)])
j=0
while s[j]!='.':
j+=1
p=""
if s[i-1]=='0':
p=s[0:j]
for i in range(b):
p=p+'0'
elif i-j>b+1:
p=s[0:j]+s[j+1:j+b+1]+'.'+s[j+b+1:i]
else:
p=s[0:j]+s[j+1:i]+s[j+b+1:i]
for i in range(b-(i-j-1)):
... | Title: Barnicle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl abou... | ```python
s=input()
i=len(s)-1
while s[i]!='e':
i-=1
b=int(s[i+1:len(s)])
j=0
while s[j]!='.':
j+=1
p=""
if s[i-1]=='0':
p=s[0:j]
for i in range(b):
p=p+'0'
elif i-j>b+1:
p=s[0:j]+s[j+1:j+b+1]+'.'+s[j+b+1:i]
else:
p=s[0:j]+s[j+1:i]+s[j+b+1:i]
for i in range(b-(i-j-1)... | 3 | MatrixStudio/Codeforces-Python-Submissions |
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