contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
546 | A | Soldier and Bananas | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He has *n* dollars. How many dollars does he have to borrow from his friend soldier to buy *w* bananas? | The first line contains three positive integers *k*,<=*n*,<=*w* (1<=<=≤<=<=*k*,<=*w*<=<=≤<=<=1000, 0<=≤<=*n*<=≤<=109), the cost of the first banana, initial number of dollars the soldier has and number of bananas he wants. | Output one integer — the amount of dollars that the soldier must borrow from his friend. If he doesn't have to borrow money, output 0. | [
"3 17 4\n"
] | [
"13"
] | none | 500 | [
{
"input": "3 17 4",
"output": "13"
},
{
"input": "1 2 1",
"output": "0"
},
{
"input": "1 1 1",
"output": "0"
},
{
"input": "1 5 6",
"output": "16"
},
{
"input": "1 1000000000 1",
"output": "0"
},
{
"input": "1000 0 1000",
"output": "500500000"
}... | 1,694,103,151 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 31 | 0 | case = [int(num) for num in input().split()]
cost = case[2] * case[0] * (case[2] + 1) / 2
if cost > case[1]:
print(int(cost - case[1]))
else:
print(0) | Title: Soldier and Bananas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A soldier wants to buy *w* bananas in the shop. He has to pay *k* dollars for the first banana, 2*k* dollars for the second one and so on (in other words, he has to pay *i*·*k* dollars for the *i*-th banana).
He h... | ```python
case = [int(num) for num in input().split()]
cost = case[2] * case[0] * (case[2] + 1) / 2
if cost > case[1]:
print(int(cost - case[1]))
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
306 | A | Candies | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most equal) manner. He wants to choose such *a**i*, where *a**i* is the number of candies in the *... | The single line of the input contains a pair of space-separated positive integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100;*n*<=≥<=*m*) — the number of candies and the number of Polycarpus's friends. | Print the required sequence *a*1,<=*a*2,<=...,<=*a**m*, where *a**i* is the number of candies in the *i*-th friend's present. All numbers *a**i* must be positive integers, total up to *n*, the maximum one should differ from the minimum one by the smallest possible value. | [
"12 3\n",
"15 4\n",
"18 7\n"
] | [
"4 4 4 ",
"3 4 4 4 ",
"2 2 2 3 3 3 3 "
] | Print *a*<sub class="lower-index">*i*</sub> in any order, separate the numbers by spaces. | 500 | [
{
"input": "12 4",
"output": "3 3 3 3 "
},
{
"input": "15 6",
"output": "2 2 2 3 3 3 "
},
{
"input": "18 8",
"output": "2 2 2 2 2 2 3 3 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "2 1",
"output": "2 "
},
{
"input": "100 1",
"output": "100 ... | 1,631,133,386 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 248 | 20,172,800 | n, m = map(int, input().split())
r = []
bandau = int(n / m)
conlai = n % m
for i in range(0, m - conlai):
r.append(bandau)
for i in range(0, conlai):
r.append(bandau + 1)
print(" ".join(str(x) for x in r))
| Title: Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most ... | ```python
n, m = map(int, input().split())
r = []
bandau = int(n / m)
conlai = n % m
for i in range(0, m - conlai):
r.append(bandau)
for i in range(0, conlai):
r.append(bandau + 1)
print(" ".join(str(x) for x in r))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,694,042,058 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n, h = input().split()
numers = input().split()
total = int(n)
for i in numers:
if i > h:
total += 1
print(total)
| Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n, h = input().split()
numers = input().split()
total = int(n)
for i in numers:
if i > h:
total += 1
print(total)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
297 | A | Parity Game | PROGRAMMING | 1,700 | [
"constructive algorithms"
] | null | null | You are fishing with polar bears Alice and Bob. While waiting for the fish to bite, the polar bears get bored. They come up with a game. First Alice and Bob each writes a 01-string (strings that only contain character "0" and "1") *a* and *b*. Then you try to turn *a* into *b* using two types of operations:
- Write *... | The first line contains the string *a* and the second line contains the string *b* (1<=≤<=|*a*|,<=|*b*|<=≤<=1000). Both strings contain only the characters "0" and "1". Here |*x*| denotes the length of the string *x*. | Print "YES" (without quotes) if it is possible to turn *a* into *b*, and "NO" (without quotes) otherwise. | [
"01011\n0110\n",
"0011\n1110\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the steps are as follows: 01011 → 1011 → 011 → 0110 | 500 | [
{
"input": "01011\n0110",
"output": "YES"
},
{
"input": "0011\n1110",
"output": "NO"
},
{
"input": "11111\n111111",
"output": "YES"
},
{
"input": "0110011\n01100110",
"output": "YES"
},
{
"input": "10000100\n011110",
"output": "NO"
},
{
"input": "1\n0"... | 1,536,065,996 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 307,200 | def zeroEraser(a):
if a.count('0') == len(a):
return ""
x = a[::-1]
for i in range(len(x)):
if x[i] != '0':
y = len(x)-i
break
return a[:y]
def possible(a,b):
x = zeroEraser(a)
y = zeroEraser(b)
if len(x) < len(y):
return "NO"
elif y == x[... | Title: Parity Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are fishing with polar bears Alice and Bob. While waiting for the fish to bite, the polar bears get bored. They come up with a game. First Alice and Bob each writes a 01-string (strings that only contain character "0" a... | ```python
def zeroEraser(a):
if a.count('0') == len(a):
return ""
x = a[::-1]
for i in range(len(x)):
if x[i] != '0':
y = len(x)-i
break
return a[:y]
def possible(a,b):
x = zeroEraser(a)
y = zeroEraser(b)
if len(x) < len(y):
return "NO"
el... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,643,123,612 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 62 | 0 | import math
a, b = map(int, input().split())
s = a // 2 * b
if s > (a * b // 2):
print(s)
else:
print(a * b // 2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
import math
a, b = map(int, input().split())
s = a // 2 * b
if s > (a * b // 2):
print(s)
else:
print(a * b // 2)
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it la... | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on... | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,689,818,532 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | import math
n, m = list(map(int, input().split()))
ans = n
j = n // m
if j >= m:
while j >= m:
ans += j
j = j / m
if type(j) == float:
j = math.ceil(j)
ans += j
else:
ans += j
print(ans) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th... | ```python
import math
n, m = list(map(int, input().split()))
ans = n
j = n // m
if j >= m:
while j >= m:
ans += j
j = j / m
if type(j) == float:
j = math.ceil(j)
ans += j
else:
ans += j
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
40 | E | Number Table | PROGRAMMING | 2,500 | [
"combinatorics"
] | E. Number Table | 2 | 216 | As it has been found out recently, all the Berland's current economical state can be described using a simple table *n*<=×<=*m* in size. *n* — the number of days in each Berland month, *m* — the number of months. Thus, a table cell corresponds to a day and a month of the Berland's year. Each cell will contain either 1,... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000). The second line contains the integer *k* (0<=≤<=*k*<=<<=*max*(*n*,<=*m*)) — the number of cells in which the data had been preserved. The next *k* lines contain the data on the state of the table in the preserved cells. Each line is of the form... | Print the number of different tables that could conform to the preserved data modulo *p*. | [
"2 2\n0\n100\n",
"2 2\n1\n1 1 -1\n100\n"
] | [
"2\n",
"1\n"
] | none | 2,500 | [
{
"input": "2 2\n0\n100",
"output": "2"
},
{
"input": "2 2\n1\n1 1 -1\n100",
"output": "1"
},
{
"input": "7 6\n4\n3 2 -1\n7 1 1\n2 1 1\n3 4 -1\n179460773",
"output": "0"
},
{
"input": "6 2\n3\n5 1 -1\n4 2 1\n1 2 -1\n958300150",
"output": "4"
},
{
"input": "6 9\n3\... | 1,689,635,992 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | print("_RANDOM_GUESS_1689635992.7509944")# 1689635992.7510135 | Title: Number Table
Time Limit: 2 seconds
Memory Limit: 216 megabytes
Problem Description:
As it has been found out recently, all the Berland's current economical state can be described using a simple table *n*<=×<=*m* in size. *n* — the number of days in each Berland month, *m* — the number of months. Thus, a table... | ```python
print("_RANDOM_GUESS_1689635992.7509944")# 1689635992.7510135
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,691,827,908 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | s=input()
t="QAQ"
dp={}
def dfs(i,j):
if j==len(t):
return 1
if i==len(s):
return 0
if (i,j) in dp:
return dp[(i,j)]
if s[i]==t[j]:
dp[(i,j)]=dfs(i+1,j+1)+dfs(i+1,j)
else:
dp[(i,j)]=dfs(i+1,j)
return dp[(i,j)]
print(dfs(0,0)) | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
s=input()
t="QAQ"
dp={}
def dfs(i,j):
if j==len(t):
return 1
if i==len(s):
return 0
if (i,j) in dp:
return dp[(i,j)]
if s[i]==t[j]:
dp[(i,j)]=dfs(i+1,j+1)+dfs(i+1,j)
else:
dp[(i,j)]=dfs(i+1,j)
return dp[(i,j)]
print(dfs(0,0))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
70 | A | Cookies | PROGRAMMING | 1,300 | [
"math"
] | A. Cookies | 1 | 256 | Fangy collects cookies. Once he decided to take a box and put cookies into it in some way. If we take a square *k*<=×<=*k* in size, divided into blocks 1<=×<=1 in size and paint there the main diagonal together with cells, which lie above it, then the painted area will be equal to the area occupied by one cookie *k* in... | The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1000). | Print the single number, equal to the number of empty cells in the box. The answer should be printed modulo 106<=+<=3. | [
"3\n"
] | [
"9"
] | If the box possesses the base of 2<sup class="upper-index">3</sup> × 2<sup class="upper-index">3</sup> (as in the example), then the cookies will be put there in the following manner: | 500 | [
{
"input": "3",
"output": "9"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "27"
},
{
"input": "6",
"output": "243"
},
{
"input": "11",
"output": "59049"
},
{
"input": "14",
"output": "59... | 1,594,381,902 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 93 | 6,656,000 | def f(x):
if x==0 or x==1:
return 1
else:
return 3*f(x-1)
print(3**(int(input())-1)%1000003)
| Title: Cookies
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Fangy collects cookies. Once he decided to take a box and put cookies into it in some way. If we take a square *k*<=×<=*k* in size, divided into blocks 1<=×<=1 in size and paint there the main diagonal together with cells, which li... | ```python
def f(x):
if x==0 or x==1:
return 1
else:
return 3*f(x-1)
print(3**(int(input())-1)%1000003)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* ... | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in ... | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a ... | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,602,790,401 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 108 | 307,200 | n = [int(s) for s in input().split()]
a = list(input())
m = 0
p = True
r = 0
while m!=(n[0]-1) and p:
o = True
for i in range(n[1]):
k=m+n[1]-i
if k<n[0]:
if a[k]=="1" and o:
m=k
r+=1
o = False
if o:
print(-1)
p = False
if m == (n[0]-1):
print(... | Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she c... | ```python
n = [int(s) for s in input().split()]
a = list(input())
m = 0
p = True
r = 0
while m!=(n[0]-1) and p:
o = True
for i in range(n[1]):
k=m+n[1]-i
if k<n[0]:
if a[k]=="1" and o:
m=k
r+=1
o = False
if o:
print(-1)
p = False
if m == (n[0]-1):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
593 | A | 2Char | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | Andrew often reads articles in his favorite magazine 2Char. The main feature of these articles is that each of them uses at most two distinct letters. Andrew decided to send an article to the magazine, but as he hasn't written any article, he just decided to take a random one from magazine 26Char. However, before sendi... | The first line of the input contains number *n* (1<=≤<=*n*<=≤<=100) — the number of words in the article chosen by Andrew. Following are *n* lines, each of them contains one word. All the words consist only of small English letters and their total length doesn't exceed 1000. The words are not guaranteed to be distinct,... | Print a single integer — the maximum possible total length of words in Andrew's article. | [
"4\nabb\ncacc\naaa\nbbb\n",
"5\na\na\nbcbcb\ncdecdecdecdecdecde\naaaa\n"
] | [
"9",
"6"
] | In the first sample the optimal way to choose words is {'abb', 'aaa', 'bbb'}.
In the second sample the word 'cdecdecdecdecdecde' consists of three distinct letters, and thus cannot be used in the article. The optimal answer is {'a', 'a', 'aaaa'}. | 250 | [
{
"input": "4\nabb\ncacc\naaa\nbbb",
"output": "9"
},
{
"input": "5\na\na\nbcbcb\ncdecdecdecdecdecde\naaaa",
"output": "6"
},
{
"input": "1\na",
"output": "1"
},
{
"input": "2\nz\nz",
"output": "2"
},
{
"input": "5\nabcde\nfghij\nklmno\npqrst\nuvwxy",
"output"... | 1,461,264,253 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 61 | 4,812,800 | n = int(input())
strings = []
for i in range(n):
strings.append(input())
data = [[] for i in range(n)]
for i in range(n):
data[i].append(len(strings[i]))
data[i].append('')
for j in range(len(strings[i])):
if strings[i][j] not in data[i][1]:
data[i][1] += strings[i][j... | Title: 2Char
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrew often reads articles in his favorite magazine 2Char. The main feature of these articles is that each of them uses at most two distinct letters. Andrew decided to send an article to the magazine, but as he hasn't written an... | ```python
n = int(input())
strings = []
for i in range(n):
strings.append(input())
data = [[] for i in range(n)]
for i in range(n):
data[i].append(len(strings[i]))
data[i].append('')
for j in range(len(strings[i])):
if strings[i][j] not in data[i][1]:
data[i][1] += st... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least... | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,599,739,226 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 310 | 1,843,200 | from math import *
n,k=map(int,input().split())
l=list(map(int,input().split()))
c=0
for i in range(n-1):
if(l[i]>l[i+1]):
d=abs(l[i+1]-l[i])+1
x=ceil(d/k)
c=c+x
l[i+1]=l[i+1]+(x*k)
elif(l[i]==l[i+1]):
c+=1
l[i+1]=l[i]+k
print(c)
| Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*... | ```python
from math import *
n,k=map(int,input().split())
l=list(map(int,input().split()))
c=0
for i in range(n-1):
if(l[i]>l[i+1]):
d=abs(l[i+1]-l[i])+1
x=ceil(d/k)
c=c+x
l[i+1]=l[i+1]+(x*k)
elif(l[i]==l[i+1]):
c+=1
l[i+1]=l[i]+k
print(c)
``` | 3.831267 | MatrixStudio/Codeforces-Python-Submissions |
7 | B | Memory Manager | PROGRAMMING | 1,600 | [
"implementation"
] | B. Memory Manager | 1 | 64 | There is little time left before the release of the first national operating system BerlOS. Some of its components are not finished yet — the memory manager is among them. According to the developers' plan, in the first release the memory manager will be very simple and rectilinear. It will support three operations:
... | The first line of the input data contains two positive integers *t* and *m* (1<=≤<=*t*<=≤<=100;1<=≤<=*m*<=≤<=100), where *t* — the amount of operations given to the memory manager for processing, and *m* — the available memory size in bytes. Then there follow *t* lines where the operations themselves are given. The fir... | Output the sequence of lines. Each line should contain either the result of alloc operation procession , or ILLEGAL_ERASE_ARGUMENT as a result of failed erase operation procession. Output lines should go in the same order in which the operations are processed. Successful procession of alloc operation should return inte... | [
"6 10\nalloc 5\nalloc 3\nerase 1\nalloc 6\ndefragment\nalloc 6\n"
] | [
"1\n2\nNULL\n3\n"
] | none | 0 | [
{
"input": "6 10\nalloc 5\nalloc 3\nerase 1\nalloc 6\ndefragment\nalloc 6",
"output": "1\n2\nNULL\n3"
},
{
"input": "6 1\ndefragment\nalloc 10\nalloc 1\nerase -1\nerase 1\nerase 1",
"output": "NULL\n1\nILLEGAL_ERASE_ARGUMENT\nILLEGAL_ERASE_ARGUMENT"
},
{
"input": "14 100\nalloc 99\nalloc... | 1,681,581,779 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int d[111],t,m,c,b=0,i,j,k,l;
string s;
int main(){
cin>>t>>m;
for(int k=0; k<t; k++){
cin>>s;
if(s[0]=='a'){
cin>>c;
for(i=0,j=-1; i<m; i++)
if(i-j==c && !d[i]) break;
else if(d[i]) j=i;
if(i-j==c&&i<... | Title: Memory Manager
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
There is little time left before the release of the first national operating system BerlOS. Some of its components are not finished yet — the memory manager is among them. According to the developers' plan, in the first relea... | ```python
#include <bits/stdc++.h>
using namespace std;
int d[111],t,m,c,b=0,i,j,k,l;
string s;
int main(){
cin>>t>>m;
for(int k=0; k<t; k++){
cin>>s;
if(s[0]=='a'){
cin>>c;
for(i=0,j=-1; i<m; i++)
if(i-j==c && !d[i]) break;
else if(d[i]) j=i;
if(... | -1 | MatrixStudio/Codeforces-Python-Submissions |
614 | B | Gena's Code | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from each country, find their product. If it is turns to be too large, then the servers might have not en... | The first line of the input contains the number of countries *n* (1<=≤<=*n*<=≤<=100<=000). The second line contains *n* non-negative integers *a**i* without leading zeroes — the number of tanks of the *i*-th country.
It is guaranteed that the second line contains at least *n*<=-<=1 beautiful numbers and the total leng... | Print a single number without leading zeroes — the product of the number of tanks presented by each country. | [
"3\n5 10 1\n",
"4\n1 1 10 11\n",
"5\n0 3 1 100 1\n"
] | [
"50",
"110",
"0"
] | In sample 1 numbers 10 and 1 are beautiful, number 5 is not not.
In sample 2 number 11 is not beautiful (contains two '1's), all others are beautiful.
In sample 3 number 3 is not beautiful, all others are beautiful. | 1,000 | [
{
"input": "3\n5 10 1",
"output": "50"
},
{
"input": "4\n1 1 10 11",
"output": "110"
},
{
"input": "5\n0 3 1 100 1",
"output": "0"
},
{
"input": "40\n10 100 10 1 10 10 100 10 10 100 10 100 100 10 1824868942 100 100 1 10 100 100 10 100 100 10 100 10 1 10 100 100 100 10 1 10 1 ... | 1,612,286,626 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 124 | 5,427,200 | if __name__ == '__main__':
n = int(input())
a = input().split()
z = False
pr = '1'
count = 0
for k in a:
if k == '0':
z = True
break
elif k == '1' + '0' * (len(k) - 1):
count += len(k) - 1
else :
pr = k
if z:
print(0)
else:
print(pr + '0' * count) | Title: Gena's Code
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from eac... | ```python
if __name__ == '__main__':
n = int(input())
a = input().split()
z = False
pr = '1'
count = 0
for k in a:
if k == '0':
z = True
break
elif k == '1' + '0' * (len(k) - 1):
count += len(k) - 1
else :
pr = k
if z:
print(0)
else:
print(pr + '0' * count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
159 | B | Matchmaker | PROGRAMMING | 1,100 | [
"*special",
"greedy",
"sortings"
] | null | null | Polycarpus has *n* markers and *m* marker caps. Each marker is described by two numbers: *x**i* is the color and *y**i* is the diameter. Correspondingly, each cap is described by two numbers: *a**j* is the color and *b**j* is the diameter. Cap (*a**j*,<=*b**j*) can close marker (*x**i*,<=*y**i*) only if their diameters... | The first input line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of markers and the number of caps, correspondingly.
Next *n* lines describe the markers. The *i*-th line contains two space-separated integers *x**i*, *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the *i*-th mark... | Print two space-separated integers *u*,<=*v*, where *u* is the number of closed markers and *v* is the number of beautifully closed markers in the sought optimal way. Remember that you have to find the way to close the maximum number of markers, and if there are several such ways, you should choose the one where the nu... | [
"3 4\n1 2\n3 4\n2 4\n5 4\n2 4\n1 1\n1 2\n",
"2 2\n1 2\n2 1\n3 4\n5 1\n"
] | [
"3 2\n",
"1 0\n"
] | In the first test sample the first marker should be closed by the fourth cap, the second marker should be closed by the first cap and the third marker should be closed by the second cap. Thus, three markers will be closed, and two of them will be beautifully closed — the first and the third markers. | 1,000 | [
{
"input": "3 4\n1 2\n3 4\n2 4\n5 4\n2 4\n1 1\n1 2",
"output": "3 2"
},
{
"input": "2 2\n1 2\n2 1\n3 4\n5 1",
"output": "1 0"
},
{
"input": "6 7\n2 1\n2 2\n2 1\n1 1\n2 1\n1 2\n2 2\n2 2\n2 2\n1 2\n2 2\n1 1\n1 2",
"output": "3 3"
},
{
"input": "6 7\n2 1\n1 1\n2 2\n1 2\n1 1\n1 2... | 1,669,916,324 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | """
https://codeforces.com/problemset/problem/159/B
"""
n, m = [int(x) for x in input().split()]
markers, caps = [], []
for _ in range(n):
markers.append([int(x) for x in input().split()])
for _ in range(m):
caps.append([int(x) for x in input().split()])
closedbeautifully, closed = 0, 0
indexm, indexc = set(... | Title: Matchmaker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has *n* markers and *m* marker caps. Each marker is described by two numbers: *x**i* is the color and *y**i* is the diameter. Correspondingly, each cap is described by two numbers: *a**j* is the color and *b**j* i... | ```python
"""
https://codeforces.com/problemset/problem/159/B
"""
n, m = [int(x) for x in input().split()]
markers, caps = [], []
for _ in range(n):
markers.append([int(x) for x in input().split()])
for _ in range(m):
caps.append([int(x) for x in input().split()])
closedbeautifully, closed = 0, 0
indexm, ind... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,615,904,410 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 77 | 716,800 | n, m = map(int, input().split())
d = {}
for _ in range(m):
i, j = input().split()
d[i] = j
r = []
for i in input().split():
r.append(d[i] if len(d[i]) < len(i) else i)
print(" ".join(r)) | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
n, m = map(int, input().split())
d = {}
for _ in range(m):
i, j = input().split()
d[i] = j
r = []
for i in input().split():
r.append(d[i] if len(d[i]) < len(i) else i)
print(" ".join(r))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
134 | A | Average Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one). | The first line contains the integer *n* (2<=≤<=*n*<=≤<=2·105). The second line contains elements of the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). All the elements are positive integers. | Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to *n*.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print ... | [
"5\n1 2 3 4 5\n",
"4\n50 50 50 50\n"
] | [
"1\n3 ",
"4\n1 2 3 4 "
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "1\n3 "
},
{
"input": "4\n50 50 50 50",
"output": "4\n1 2 3 4 "
},
{
"input": "3\n2 3 1",
"output": "1\n1 "
},
{
"input": "2\n4 2",
"output": "0"
},
{
"input": "2\n1 1",
"output": "2\n1 2 "
},
{
"input": "10\n3 3 3 ... | 1,673,261,054 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 15 | 0 | n=int(input())
a=[]
a=list(map(int,input().split()))
s=sum(a)
c=[]
for i in a:
q=s-int(i)
q1=int(q/(n-1))
if(q1==i):
c.append(a.index(i)+1)
print(len(c))
for i in c:
print(i, end=" ") | Title: Average Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
... | ```python
n=int(input())
a=[]
a=list(map(int,input().split()))
s=sum(a)
c=[]
for i in a:
q=s-int(i)
q1=int(q/(n-1))
if(q1==i):
c.append(a.index(i)+1)
print(len(c))
for i in c:
print(i, end=" ")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
821 | C | Okabe and Boxes | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"trees"
] | null | null | Okabe and Super Hacker Daru are stacking and removing boxes. There are *n* boxes numbered from 1 to *n*. Initially there are no boxes on the stack.
Okabe, being a control freak, gives Daru 2*n* commands: *n* of which are to add a box to the top of the stack, and *n* of which are to remove a box from the top of the sta... | The first line of input contains the integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of boxes.
Each of the next 2*n* lines of input starts with a string "add" or "remove". If the line starts with the "add", an integer *x* (1<=≤<=*x*<=≤<=*n*) follows, indicating that Daru should add the box with number *x* to the top of... | Print the minimum number of times Daru needs to reorder the boxes to successfully complete all of Okabe's commands. | [
"3\nadd 1\nremove\nadd 2\nadd 3\nremove\nremove\n",
"7\nadd 3\nadd 2\nadd 1\nremove\nadd 4\nremove\nremove\nremove\nadd 6\nadd 7\nadd 5\nremove\nremove\nremove\n"
] | [
"1\n",
"2\n"
] | In the first sample, Daru should reorder the boxes after adding box 3 to the stack.
In the second sample, Daru should reorder the boxes after adding box 4 and box 7 to the stack. | 1,500 | [
{
"input": "3\nadd 1\nremove\nadd 2\nadd 3\nremove\nremove",
"output": "1"
},
{
"input": "7\nadd 3\nadd 2\nadd 1\nremove\nadd 4\nremove\nremove\nremove\nadd 6\nadd 7\nadd 5\nremove\nremove\nremove",
"output": "2"
},
{
"input": "4\nadd 1\nadd 3\nremove\nadd 4\nadd 2\nremove\nremove\nremov... | 1,519,493,625 | 1,725 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 3,000 | 13,209,600 | import sys
n = int(sys.stdin.readline())
stack = list()
mini = 10**9
nb = 0
for loop in range(2*n):
request = sys.stdin.readline().split()
if request[0] == "add":
stack.append(int(request[1]))
mini = min(mini, int(request[1]))
else:
if len(stack) > 0:
if stack[len(stack)-1] == mini:
stack.remove(stack[... | Title: Okabe and Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Okabe and Super Hacker Daru are stacking and removing boxes. There are *n* boxes numbered from 1 to *n*. Initially there are no boxes on the stack.
Okabe, being a control freak, gives Daru 2*n* commands: *n* of which a... | ```python
import sys
n = int(sys.stdin.readline())
stack = list()
mini = 10**9
nb = 0
for loop in range(2*n):
request = sys.stdin.readline().split()
if request[0] == "add":
stack.append(int(request[1]))
mini = min(mini, int(request[1]))
else:
if len(stack) > 0:
if stack[len(stack)-1] == mini:
stack.rem... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,679,681,403 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 18 | 1,000 | 0 | # A. Team Olympiad
n = int(input())
lista = [int(x) for x in input().split(' ')]
contagem = []
prog = lista.count(1)
contagem.append(prog)
math = lista.count(2)
contagem.append(math)
pe = lista.count(3)
contagem.append(pe)
w = min(contagem)
if w == 0:
print(0)
else:
print(w)
for i in range(w):
... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
# A. Team Olympiad
n = int(input())
lista = [int(x) for x in input().split(' ')]
contagem = []
prog = lista.count(1)
contagem.append(prog)
math = lista.count(2)
contagem.append(math)
pe = lista.count(3)
contagem.append(pe)
w = min(contagem)
if w == 0:
print(0)
else:
print(w)
for i in rang... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,573,592,188 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 216 | 0 | a=input()
countup=countlw=0
for walkA in range (0,len(a)):
letter=a[walkA]
if(letter.isupper()):
countup+=1
if(letter.islower()):
countlw+=1
if(countlw>=countup):
print(a.lower())
else:
print(a.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
a=input()
countup=countlw=0
for walkA in range (0,len(a)):
letter=a[walkA]
if(letter.isupper()):
countup+=1
if(letter.islower()):
countlw+=1
if(countlw>=countup):
print(a.lower())
else:
print(a.upper())
``` | 3.946 | MatrixStudio/Codeforces-Python-Submissions |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should b... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right aft... | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,689,404,807 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 265 | 12,390,400 | n = int(input())
inputs = list(map(int,input().split()))
has = [False] * n
current = n
""" Approach 1
for i in range(n):
if inputs[i] == n-i and temp == 0:
print(n-i)
elif inputs[i] == n-i and temp != 0:
print()
elif inputs[i] != n-i and temp == inputs[i]:
for j in rang... | Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents sh... | ```python
n = int(input())
inputs = list(map(int,input().split()))
has = [False] * n
current = n
""" Approach 1
for i in range(n):
if inputs[i] == n-i and temp == 0:
print(n-i)
elif inputs[i] == n-i and temp != 0:
print()
elif inputs[i] != n-i and temp == inputs[i]:
for... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,593,879,873 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 6,656,000 | string = str(input())
small = 0
cap = 0
for i in string:
if 65 <= ord(i) <= 90:
cap += 1
elif 97 <= ord(i) <= 122:
small += 1
if cap > small:
print(string.upper())
else:
print(string.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
string = str(input())
small = 0
cap = 0
for i in string:
if 65 <= ord(i) <= 90:
cap += 1
elif 97 <= ord(i) <= 122:
small += 1
if cap > small:
print(string.upper())
else:
print(string.lower())
``` | 3.933102 | MatrixStudio/Codeforces-Python-Submissions |
791 | A | Bear and Big Brother | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's we... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively. | Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob. | [
"4 7\n",
"4 9\n",
"1 1\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Li... | 500 | [
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output... | 1,698,025,790 | 2,147,483,647 | PyPy 3 | OK | TESTS | 62 | 93 | 0 | limak, bob = [int(f) for f in input().split()]
year = 0
while limak <= bob:
limak *= 3
bob *= 2
year += 1
print(year) | Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or e... | ```python
limak, bob = [int(f) for f in input().split()]
year = 0
while limak <= bob:
limak *= 3
bob *= 2
year += 1
print(year)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
6 | A | Triangle | PROGRAMMING | 900 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allo... | The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks. | Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the s... | [
"4 2 1 3\n",
"7 2 2 4\n",
"3 5 9 1\n"
] | [
"TRIANGLE\n",
"SEGMENT\n",
"IMPOSSIBLE\n"
] | none | 0 | [
{
"input": "4 2 1 3",
"output": "TRIANGLE"
},
{
"input": "7 2 2 4",
"output": "SEGMENT"
},
{
"input": "3 5 9 1",
"output": "IMPOSSIBLE"
},
{
"input": "3 1 5 1",
"output": "IMPOSSIBLE"
},
{
"input": "10 10 10 10",
"output": "TRIANGLE"
},
{
"input": "11 ... | 1,601,138,697 | 297 | PyPy 3 | OK | TESTS | 83 | 342 | 0 | a, b, c, d = sorted([int(p) for p in input().split()])
if a+b > c or b+c > d:
print('TRIANGLE')
elif a+b == c or b+c == d:
print('SEGMENT')
else:
print('IMPOSSIBLE') | Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out o... | ```python
a, b, c, d = sorted([int(p) for p in input().split()])
if a+b > c or b+c > d:
print('TRIANGLE')
elif a+b == c or b+c == d:
print('SEGMENT')
else:
print('IMPOSSIBLE')
``` | 3.9145 | MatrixStudio/Codeforces-Python-Submissions |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<... | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In ... | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,615,743,841 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | $m = (split " ", <>)[1] - 1;
local $/;
$_ = <>;
$i += "acef" eq join '', sort split //, "$1$2$3" while /([face])(?=([face]).{$m}([face]{2}))/sg;
print 0 + $i | Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem a... | ```python
$m = (split " ", <>)[1] - 1;
local $/;
$_ = <>;
$i += "acef" eq join '', sort split //, "$1$2$3" while /([face])(?=([face]).{$m}([face]{2}))/sg;
print 0 + $i
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,644,163,716 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | l=input()
l=l.split()
n=int(l[0])
b=int(l[1])
d=int(l[2])
l=input()
l=l.split()
count=0
waste=0
for i in range(len(l)):
l[i]=int(l[i])
if l[i] <=b:
if l[i]>d or waste>d:
count+=1
else:
waste+=l[i]
if waste >d:
count+1
print(count) | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
l=input()
l=l.split()
n=int(l[0])
b=int(l[1])
d=int(l[2])
l=input()
l=l.split()
count=0
waste=0
for i in range(len(l)):
l[i]=int(l[i])
if l[i] <=b:
if l[i]>d or waste>d:
count+=1
else:
waste+=l[i]
if waste >d:
count+1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
33 | A | What is for dinner? | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | A. What is for dinner? | 2 | 256 | In one little known, but very beautiful country called Waterland, lives a lovely shark Valerie. Like all the sharks, she has several rows of teeth, and feeds on crucians. One of Valerie's distinguishing features is that while eating one crucian she uses only one row of her teeth, the rest of the teeth are "relaxing".
... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*m*<=≤<=*n*<=≤<=1000,<=0<=≤<=*k*<=≤<=106) — total amount of Valerie's teeth, amount of tooth rows and amount of crucians in Valerie's portion for dinner. Then follow *n* lines, each containing two integers: *r* (1<=≤<=*r*<=≤<=*m*) — index of the row, where bel... | In the first line output the maximum amount of crucians that Valerie can consume for dinner. | [
"4 3 18\n2 3\n1 2\n3 6\n2 3\n",
"2 2 13\n1 13\n2 12\n"
] | [
"11\n",
"13\n"
] | none | 500 | [
{
"input": "4 3 18\n2 3\n1 2\n3 6\n2 3",
"output": "11"
},
{
"input": "2 2 13\n1 13\n2 12",
"output": "13"
},
{
"input": "5 4 8\n4 6\n4 5\n1 3\n2 0\n3 3",
"output": "8"
},
{
"input": "1 1 0\n1 3",
"output": "0"
},
{
"input": "7 1 30\n1 8\n1 15\n1 5\n1 17\n1 9\n1 1... | 1,639,202,588 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 2,048,000 | K=int(input())
L=int(input())
M=int(input())
N=int(input())
D=int(input())
ans=0
A=list(map(int,input().split()))
for i in range(D):
if A[i]%K==0 or A[i]%K==0 or A[i]%L==0 or A[i]%M==0 or A[i]%N==0:ans+=1
print(ans) | Title: What is for dinner?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In one little known, but very beautiful country called Waterland, lives a lovely shark Valerie. Like all the sharks, she has several rows of teeth, and feeds on crucians. One of Valerie's distinguishing features is that... | ```python
K=int(input())
L=int(input())
M=int(input())
N=int(input())
D=int(input())
ans=0
A=list(map(int,input().split()))
for i in range(D):
if A[i]%K==0 or A[i]%K==0 or A[i]%L==0 or A[i]%M==0 or A[i]%N==0:ans+=1
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
550 | C | Divisibility by Eight | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"math"
] | null | null | You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a no... | The single line of the input contains a non-negative integer *n*. The representation of number *n* doesn't contain any leading zeroes and its length doesn't exceed 100 digits. | Print "NO" (without quotes), if there is no such way to remove some digits from number *n*.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number *n* in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any ... | [
"3454\n",
"10\n",
"111111\n"
] | [
"YES\n344\n",
"YES\n0\n",
"NO\n"
] | none | 1,000 | [
{
"input": "3454",
"output": "YES\n344"
},
{
"input": "10",
"output": "YES\n0"
},
{
"input": "111111",
"output": "NO"
},
{
"input": "8996988892",
"output": "YES\n8"
},
{
"input": "5555555555",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
... | 1,682,930,845 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n = [int(i)for i in input()]
s = ''
for i in n:
s += str(i)
if int(s) % 8 == 0:
print('YES')
print(f'{n}')
exit()
v = 0
f = 0
while v < len(n):
s = ''
for i in range(len(n)):
if i != v:
s += str(n[i])
if int(s) % 8 == 0:
print('YES')
prin... | Title: Divisibility by Eight
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of t... | ```python
n = [int(i)for i in input()]
s = ''
for i in n:
s += str(i)
if int(s) % 8 == 0:
print('YES')
print(f'{n}')
exit()
v = 0
f = 0
while v < len(n):
s = ''
for i in range(len(n)):
if i != v:
s += str(n[i])
if int(s) % 8 == 0:
print('YES')
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,687,182,748 | 2,147,483,647 | Python 3 | OK | TESTS | 84 | 46 | 0 | a = int(input())
b = int(input())
c = int(input())
k = 0
i = a
while i > 0:
if i * 2 < b + 1 and i * 4 < c + 1:
print(i * 7)
k = 1
break
i -= 1
if k == 0:
print(0) | Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
a = int(input())
b = int(input())
c = int(input())
k = 0
i = a
while i > 0:
if i * 2 < b + 1 and i * 4 < c + 1:
print(i * 7)
k = 1
break
i -= 1
if k == 0:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1 | B | Spreadsheet | PROGRAMMING | 1,600 | [
"implementation",
"math"
] | B. Spreadsheets | 10 | 64 | In the popular spreadsheets systems (for example, in Excel) the following numeration of columns is used. The first column has number A, the second — number B, etc. till column 26 that is marked by Z. Then there are two-letter numbers: column 27 has number AA, 28 — AB, column 52 is marked by AZ. After ZZ there follow th... | The first line of the input contains integer number *n* (1<=≤<=*n*<=≤<=105), the number of coordinates in the test. Then there follow *n* lines, each of them contains coordinates. All the coordinates are correct, there are no cells with the column and/or the row numbers larger than 106 . | Write *n* lines, each line should contain a cell coordinates in the other numeration system. | [
"2\nR23C55\nBC23\n"
] | [
"BC23\nR23C55\n"
] | none | 0 | [
{
"input": "2\nR23C55\nBC23",
"output": "BC23\nR23C55"
},
{
"input": "1\nA1",
"output": "R1C1"
},
{
"input": "5\nR8C3\nD1\nR7C2\nR8C9\nR8C9",
"output": "C8\nR1C4\nB7\nI8\nI8"
},
{
"input": "4\nR4C25\nR90C35\nAP55\nX83",
"output": "Y4\nAI90\nR55C42\nR83C24"
},
{
"i... | 1,679,800,095 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 2,308 | 0 | # LUOGU_RID: 105945841
# LC168
def num2title(n: int) -> str:
s = ""
while n:
n -= 1
s = chr(n % 26 + 65) + s
n //= 26
return s
# LC171
def title2num(s: str) -> int:
n = 0
for c in s:
n = n * 26 + ord(c) - 64
return n
# RxxCxx -> AAxx
def r2e(s: ... | Title: Spreadsheet
Time Limit: 10 seconds
Memory Limit: 64 megabytes
Problem Description:
In the popular spreadsheets systems (for example, in Excel) the following numeration of columns is used. The first column has number A, the second — number B, etc. till column 26 that is marked by Z. Then there are two-letter n... | ```python
# LUOGU_RID: 105945841
# LC168
def num2title(n: int) -> str:
s = ""
while n:
n -= 1
s = chr(n % 26 + 65) + s
n //= 26
return s
# LC171
def title2num(s: str) -> int:
n = 0
for c in s:
n = n * 26 + ord(c) - 64
return n
# RxxCxx -> AAxx
d... | 3.8846 | MatrixStudio/Codeforces-Python-Submissions |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,698,903,260 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | import math
n=int(input())
print(math.cell(n/5))
#abc
| Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
import math
n=int(input())
print(math.cell(n/5))
#abc
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
934 | A | A Compatible Pair | PROGRAMMING | 1,400 | [
"brute force",
"games"
] | null | null | Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cracking noise, all of which frighten the monster out of coming.
Little Tommy has *n* lanterns and Big B... | The first line contains two space-separated integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=50).
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n*.
The third line contains *m* space-separated integers *b*1,<=*b*2,<=...,<=*b**m*.
All the integers range from <=-<=109 to 109. | Print a single integer — the brightness of the chosen pair. | [
"2 2\n20 18\n2 14\n",
"5 3\n-1 0 1 2 3\n-1 0 1\n"
] | [
"252\n",
"2\n"
] | In the first example, Tommy will hide 20 and Banban will choose 18 from Tommy and 14 from himself.
In the second example, Tommy will hide 3 and Banban will choose 2 from Tommy and 1 from himself. | 500 | [
{
"input": "2 2\n20 18\n2 14",
"output": "252"
},
{
"input": "5 3\n-1 0 1 2 3\n-1 0 1",
"output": "2"
},
{
"input": "10 2\n1 6 2 10 2 3 2 10 6 4\n5 7",
"output": "70"
},
{
"input": "50 50\n1 6 2 10 2 3 2 10 6 4 5 0 3 1 7 3 2 4 4 2 1 5 0 6 10 1 8 0 10 9 0 4 10 5 5 7 4 9 9 5 5 ... | 1,601,023,510 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 108 | 0 | x, y = map(int, input().split())
a1 = list(map(int, input().split()))
a1.sort()
a2 = list(map(int, input().split()))
a2.sort()
a1.pop()
print(a1[-1]*a2[-1]) | Title: A Compatible Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cr... | ```python
x, y = map(int, input().split())
a1 = list(map(int, input().split()))
a1.sort()
a2 = list(map(int, input().split()))
a2.sort()
a1.pop()
print(a1[-1]*a2[-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
259 | B | Little Elephant and Magic Square | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table are equal. The figure below shows the magic square, the sum of integers in all its rows, columns and diagonals equals ... | The first three lines of the input contain the Little Elephant's notes. The first line contains elements of the first row of the magic square. The second line contains the elements of the second row, the third line is for the third row. The main diagonal elements that have been forgotten by the Elephant are represented... | Print three lines, in each line print three integers — the Little Elephant's magic square. If there are multiple magic squares, you are allowed to print any of them. Note that all numbers you print must be positive and not exceed 105.
It is guaranteed that there exists at least one magic square that meets the conditio... | [
"0 1 1\n1 0 1\n1 1 0\n",
"0 3 6\n5 0 5\n4 7 0\n"
] | [
"1 1 1\n1 1 1\n1 1 1\n",
"6 3 6\n5 5 5\n4 7 4\n"
] | none | 1,000 | [
{
"input": "0 1 1\n1 0 1\n1 1 0",
"output": "1 1 1\n1 1 1\n1 1 1"
},
{
"input": "0 3 6\n5 0 5\n4 7 0",
"output": "6 3 6\n5 5 5\n4 7 4"
},
{
"input": "0 4 4\n4 0 4\n4 4 0",
"output": "4 4 4\n4 4 4\n4 4 4"
},
{
"input": "0 54 48\n36 0 78\n66 60 0",
"output": "69 54 48\n36 5... | 1,420,349,052 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 122 | 0 | def main():
l = [list(map(int, input().split())) for _ in range(3)]
s = sum(map(sum, l)) // 2
for i, row in enumerate(l):
row[i] = s - sum(row)
print(*row)
if __name__ == '__main__':
main() | Title: Little Elephant and Magic Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Elephant loves magic squares very much.
A magic square is a 3<=×<=3 table, each cell contains some positive integer. At that the sums of integers in all rows, columns and diagonals of the table ... | ```python
def main():
l = [list(map(int, input().split())) for _ in range(3)]
s = sum(map(sum, l)) // 2
for i, row in enumerate(l):
row[i] = s - sum(row)
print(*row)
if __name__ == '__main__':
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
17 | A | Noldbach problem | PROGRAMMING | 1,000 | [
"brute force",
"math",
"number theory"
] | A. Noldbach problem | 2 | 64 | Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a problem of his own and call it Noldbach problem. Since Nick is interested only in prime numbers, Nold... | The first line of the input contains two integers *n* (2<=≤<=*n*<=≤<=1000) and *k* (0<=≤<=*k*<=≤<=1000). | Output YES if at least *k* prime numbers from 2 to *n* inclusively can be expressed as it was described above. Otherwise output NO. | [
"27 2\n",
"45 7\n"
] | [
"YES",
"NO"
] | In the first sample the answer is YES since at least two numbers can be expressed as it was described (for example, 13 and 19). In the second sample the answer is NO since it is impossible to express 7 prime numbers from 2 to 45 in the desired form. | 0 | [
{
"input": "27 2",
"output": "YES"
},
{
"input": "45 7",
"output": "NO"
},
{
"input": "2 0",
"output": "YES"
},
{
"input": "15 1",
"output": "YES"
},
{
"input": "17 1",
"output": "YES"
},
{
"input": "34 5",
"output": "NO"
},
{
"input": "37 ... | 1,620,922,875 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 124 | 6,963,200 | n, k = tuple(map(int, input().split()))
sieve = [0] * n
for x in range(2, n):
if sieve[x]: continue
for u in range(2*x, n, x):
sieve[u] = x
primes = []
for i, j in enumerate(sieve):
if j == 0:
primes.append(i)
primes = primes[2:]
cnt = 0
for i in range(1, len(primes)):
... | Title: Noldbach problem
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nick is interested in prime numbers. Once he read about Goldbach problem. It states that every even integer greater than 2 can be expressed as the sum of two primes. That got Nick's attention and he decided to invent a prob... | ```python
n, k = tuple(map(int, input().split()))
sieve = [0] * n
for x in range(2, n):
if sieve[x]: continue
for u in range(2*x, n, x):
sieve[u] = x
primes = []
for i, j in enumerate(sieve):
if j == 0:
primes.append(i)
primes = primes[2:]
cnt = 0
for i in range(1, len(pr... | 0 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,680,700,219 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s=input()
l=""
m=""
for i in range(0,len(s)):
if(s[i]>='A' and s[i]<='Z'):
l=l+s[i]
else:
m=m+s[i]
if(len(l)>len(m)):
print(s.upper())
elif len(l)<len(m):
print(s.lower())
elif len(l)=len(m):
print(s.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=input()
l=""
m=""
for i in range(0,len(s)):
if(s[i]>='A' and s[i]<='Z'):
l=l+s[i]
else:
m=m+s[i]
if(len(l)>len(m)):
print(s.upper())
elif len(l)<len(m):
print(s.lower())
elif len(l)=len(m):
print(s.lower())
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
917 | A | The Monster | PROGRAMMING | 1,800 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster that took him to the Upside Down will know and relocate him.
Thus, he came up with a puzzle to te... | The first and only line of input contains string *s*, consisting only of characters '(', ')' and '?' (2<=≤<=|*s*|<=≤<=5000). | Print the answer to Will's puzzle in the first and only line of output. | [
"((?))\n",
"??()??\n"
] | [
"4\n",
"7\n"
] | For the first sample testcase, the pretty substrings of *s* are:
1. "(?" which can be transformed to "()". 1. "?)" which can be transformed to "()". 1. "((?)" which can be transformed to "(())". 1. "(?))" which can be transformed to "(())".
For the second sample testcase, the pretty substrings of *s* are:
1. "?... | 500 | [
{
"input": "((?))",
"output": "4"
},
{
"input": "??()??",
"output": "7"
},
{
"input": "?????)(???",
"output": "21"
},
{
"input": "()()((?(()(((()()(())(((()((())))(()))(()(((((())))()))(((()()()))))))(((((()))))))))",
"output": "62"
},
{
"input": "))((()(()((((())... | 1,518,784,050 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 5,529,600 | import os, time
a = []
def show_menu():
os.system('cls')
print("The Current Text Is : ")
for line in range(len(a)):
print(line + 1, ": ", a[line])
print()
print("Choose What You Want To Do")
print("0.Exit")
print("1.Write")
print("2.Copy And Paste")
print("3.C... | Title: The Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As Will is stuck in the Upside Down, he can still communicate with his mom, Joyce, through the Christmas lights (he can turn them on and off with his mind). He can't directly tell his mom where he is, because the monster th... | ```python
import os, time
a = []
def show_menu():
os.system('cls')
print("The Current Text Is : ")
for line in range(len(a)):
print(line + 1, ": ", a[line])
print()
print("Choose What You Want To Do")
print("0.Exit")
print("1.Write")
print("2.Copy And Paste")
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
376 | A | Lever | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar is a segment on the *Ox* axis between points 0 and |*s*|<=-<=1.
The decoding of the lever d... | The first line contains the lever description as a non-empty string *s* (3<=≤<=|*s*|<=≤<=106), consisting of digits (1-9) and characters "^" and "=". It is guaranteed that the line contains exactly one character "^". It is guaranteed that the pivot of the lever isn't located in any end of the lever bar.
To solve the p... | Print "left" if the given lever tilts to the left, "right" if it tilts to the right and "balance", if it is in balance. | [
"=^==\n",
"9===^==1\n",
"2==^7==\n",
"41^52==\n"
] | [
"balance\n",
"left\n",
"right\n",
"balance\n"
] | As you solve the problem, you may find the following link useful to better understand how a lever functions: http://en.wikipedia.org/wiki/Lever.
The pictures to the examples: | 500 | [
{
"input": "=^==",
"output": "balance"
},
{
"input": "9===^==1",
"output": "left"
},
{
"input": "2==^7==",
"output": "right"
},
{
"input": "41^52==",
"output": "balance"
},
{
"input": "=^2=4=1===1=",
"output": "right"
},
{
"input": "9=6===5==3=9=1=1^7=... | 1,696,086,337 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 60 | 77 | 5,427,200 | def lever_balance(s):
pivot_index = s.index("^")
left_torque = 0
right_torque = 0
for i in range(len(s)):
if s[i] == "=":
continue
elif s[i] == "^":
continue
else:
weight = int(s[i])
distance = abs(pivot_... | Title: Lever
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar i... | ```python
def lever_balance(s):
pivot_index = s.index("^")
left_torque = 0
right_torque = 0
for i in range(len(s)):
if s[i] == "=":
continue
elif s[i] == "^":
continue
else:
weight = int(s[i])
distance = ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
6 | C | Alice, Bob and Chocolate | PROGRAMMING | 1,200 | [
"greedy",
"two pointers"
] | C. Alice, Bob and Chocolate | 2 | 64 | Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them wi... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the amount of bars on the table. The second line contains a sequence *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000), where *t**i* is the time (in seconds) needed to consume the *i*-th bar (in the order from left to right). | Print two numbers *a* and *b*, where *a* is the amount of bars consumed by Alice, and *b* is the amount of bars consumed by Bob. | [
"5\n2 9 8 2 7\n"
] | [
"2 3\n"
] | none | 0 | [
{
"input": "5\n2 9 8 2 7",
"output": "2 3"
},
{
"input": "1\n1",
"output": "1 0"
},
{
"input": "2\n1 1",
"output": "1 1"
},
{
"input": "3\n1 1 1",
"output": "2 1"
},
{
"input": "4\n1 1 1 1",
"output": "2 2"
},
{
"input": "1\n6",
"output": "1 0"
}... | 1,694,944,364 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 154 | 13,209,600 | ################################################################################
n=int(input())
c=list(map(int,input().split()))
# n=5
# c=[2,9,8,2,7]
################################################################################
total=sum(c)
a=-1
eata=0
while 1>0:
if eata+c[a+1]<=total/2:
ea... | Title: Alice, Bob and Chocolate
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. Fo... | ```python
################################################################################
n=int(input())
c=list(map(int,input().split()))
# n=5
# c=[2,9,8,2,7]
################################################################################
total=sum(c)
a=-1
eata=0
while 1>0:
if eata+c[a+1]<=total/2:
... | 3.863081 | MatrixStudio/Codeforces-Python-Submissions |
622 | A | Infinite Sequence | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains ... | The only line contains integer *n* (1<=≤<=*n*<=≤<=1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | Print the element in the *n*-th position of the sequence (the elements are numerated from one). | [
"3\n",
"5\n",
"10\n",
"55\n",
"56\n"
] | [
"2\n",
"2\n",
"4\n",
"10\n",
"1\n"
] | none | 0 | [
{
"input": "3",
"output": "2"
},
{
"input": "5",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "55",
"output": "10"
},
{
"input": "56",
"output": "1"
},
{
"input": "1000000000000",
"output": "88209"
},
{
"input": "8471941278... | 1,517,932,653 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 5,632,000 | n = int(input())
k = 1
while n > k:
n = n-k
k+=1
print(n)
| Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider the infinite sequence of integers: 1,<=1,<=2,<=1,<=2,<=3,<=1,<=2,<=3,<=4,<=1,<=2,<=3,<=4,<=5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2,... | ```python
n = int(input())
k = 1
while n > k:
n = n-k
k+=1
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
430 | B | Balls Game | PROGRAMMING | 1,400 | [
"brute force",
"two pointers"
] | null | null | Iahub is training for the IOI. What is a better way to train than playing a Zuma-like game?
There are *n* balls put in a row. Each ball is colored in one of *k* colors. Initially the row doesn't contain three or more contiguous balls with the same color. Iahub has a single ball of color *x*. He can insert his ball at... | The first line of input contains three integers: *n* (1<=≤<=*n*<=≤<=100), *k* (1<=≤<=*k*<=≤<=100) and *x* (1<=≤<=*x*<=≤<=*k*). The next line contains *n* space-separated integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=*k*). Number *c**i* means that the *i*-th ball in the row has color *c**i*.
It is guaranteed th... | Print a single integer — the maximum number of balls Iahub can destroy. | [
"6 2 2\n1 1 2 2 1 1\n",
"1 1 1\n1\n"
] | [
"6\n",
"0\n"
] | none | 1,000 | [
{
"input": "6 2 2\n1 1 2 2 1 1",
"output": "6"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 2 1\n2 1 2 2 1 2 2 1 1 2",
"output": "5"
},
{
"input": "50 2 1\n1 1 2 2 1 2 1 1 2 2 1 2 1 2 1 1 2 2 1 2 1 2 2 1 2 1 2 1 2 2 1 1 2 2 1 1 2 2 1 2 1 1 2 1 1 2 2 1 1 2",
"... | 1,489,684,275 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 4,915,200 | (n, k, x) = map(int, input().split())
balls = list(map(int, input().split()))
c = 0
p = None
pairs = []
matches = []
for b in range(len(balls)):
if(balls[b] is not c):
c = balls[b]
if(c is p):
pairs.append((b - 1, b))
if(c is x):
matches.append((b-1, b))
p = c
max = 0
... | Title: Balls Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub is training for the IOI. What is a better way to train than playing a Zuma-like game?
There are *n* balls put in a row. Each ball is colored in one of *k* colors. Initially the row doesn't contain three or more conti... | ```python
(n, k, x) = map(int, input().split())
balls = list(map(int, input().split()))
c = 0
p = None
pairs = []
matches = []
for b in range(len(balls)):
if(balls[b] is not c):
c = balls[b]
if(c is p):
pairs.append((b - 1, b))
if(c is x):
matches.append((b-1, b))
p = c... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,692,679,839 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 154 | 0 | ans = 1
s = ''
n = int(input())
s += input()
c = 1
for _ in range(n-1):
m = input()
if s[-1] == m[0]:
ans = max(ans, c)
c = 0
else:
c += 1
s += m
print(ans)
| Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
ans = 1
s = ''
n = int(input())
s += input()
c = 1
for _ in range(n-1):
m = input()
if s[-1] == m[0]:
ans = max(ans, c)
c = 0
else:
c += 1
s += m
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x*<=/<=*y*.
Your favorite rational number in the [0;1] range is *p*<=/<=*q*. Now you wonde... | The first line contains a single integer *t* (1<=≤<=*t*<=≤<=1000) — the number of test cases.
Each of the next *t* lines contains four integers *x*, *y*, *p* and *q* (0<=≤<=*x*<=≤<=*y*<=≤<=109; 0<=≤<=*p*<=≤<=*q*<=≤<=109; *y*<=><=0; *q*<=><=0).
It is guaranteed that *p*<=/<=*q* is an irreducible fraction.
Hacks... | For each test case, output a single integer equal to the smallest number of submissions you have to make if you want your success rate to be equal to your favorite rational number, or -1 if this is impossible to achieve. | [
"4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1\n"
] | [
"4\n10\n0\n-1\n"
] | In the first example, you have to make 4 successful submissions. Your success rate will be equal to 7 / 14, or 1 / 2.
In the second example, you have to make 2 successful and 8 unsuccessful submissions. Your success rate will be equal to 9 / 24, or 3 / 8.
In the third example, there is no need to make any new submiss... | 0 | [
{
"input": "4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1",
"output": "4\n10\n0\n-1"
},
{
"input": "8\n0 1 0 1\n0 2 1 2\n0 3 1 1\n1 2 0 1\n1 2 1 1\n2 2 0 1\n3 3 1 2\n4 4 1 1",
"output": "0\n2\n-1\n-1\n-1\n-1\n3\n0"
},
{
"input": "5\n1 1000000000 1 2\n1 1000000000 1 2\n1 1000000000 1 2\n1 100... | 1,494,175,470 | 3,570 | Python 3 | OK | TESTS | 56 | 140 | 102,400 | import sys
input = sys.stdin.readline
t = int(input())
for qq in range(t):
x, y, p, q = map(int, input().split())
if p == q:
if x == y:
print(0)
else:
print(-1)
continue
elif p == 0:
if x == 0:
print(0)
else:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x... | ```python
import sys
input = sys.stdin.readline
t = int(input())
for qq in range(t):
x, y, p, q = map(int, input().split())
if p == q:
if x == y:
print(0)
else:
print(-1)
continue
elif p == 0:
if x == 0:
print(0)
els... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
682 | C | Alyona and the Tree | PROGRAMMING | 1,600 | [
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | Alyona decided to go on a diet and went to the forest to get some apples. There she unexpectedly found a magic rooted tree with root in the vertex 1, every vertex and every edge of which has a number written on.
The girl noticed that some of the tree's vertices are sad, so she decided to play with them. Let's call ver... | In the first line of the input integer *n* (1<=≤<=*n*<=≤<=105) is given — the number of vertices in the tree.
In the second line the sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) is given, where *a**i* is the number written on vertex *i*.
The next *n*<=-<=1 lines describe tree edges: *i**... | Print the only integer — the minimum number of leaves Alyona needs to remove such that there will be no any sad vertex left in the tree. | [
"9\n88 22 83 14 95 91 98 53 11\n3 24\n7 -8\n1 67\n1 64\n9 65\n5 12\n6 -80\n3 8\n"
] | [
"5\n"
] | The following image represents possible process of removing leaves from the tree: | 1,500 | [
{
"input": "9\n88 22 83 14 95 91 98 53 11\n3 24\n7 -8\n1 67\n1 64\n9 65\n5 12\n6 -80\n3 8",
"output": "5"
},
{
"input": "6\n53 82 15 77 71 23\n5 -77\n6 -73\n2 0\n1 26\n4 -92",
"output": "0"
},
{
"input": "10\n99 60 68 46 51 11 96 41 48 99\n4 50\n6 -97\n3 -92\n7 1\n9 99\n2 79\n1 -15\n8 -6... | 1,604,007,525 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 92 | 1,000 | 13,516,800 | from collections import deque
n = int(input())
val = [0] + list(map(int, input().split(" ")))
dists = [0]*(n+1)
g = [ [] for _ in range(n+1)]
for i in range(2,n+1):
a, b = map(int, input().split(" "))
g[a].append((i, b))
res = 0
rem = [False] * (n+1)
stack = deque([1])
while stack:
v = stack.pop()
if rem[v]:
... | Title: Alyona and the Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alyona decided to go on a diet and went to the forest to get some apples. There she unexpectedly found a magic rooted tree with root in the vertex 1, every vertex and every edge of which has a number written on.
Th... | ```python
from collections import deque
n = int(input())
val = [0] + list(map(int, input().split(" ")))
dists = [0]*(n+1)
g = [ [] for _ in range(n+1)]
for i in range(2,n+1):
a, b = map(int, input().split(" "))
g[a].append((i, b))
res = 0
rem = [False] * (n+1)
stack = deque([1])
while stack:
v = stack.pop()
i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
741 | B | Arpa's weak amphitheater and Mehrdad's valuable Hoses | PROGRAMMING | 1,600 | [
"dfs and similar",
"dp",
"dsu"
] | null | null | Just to remind, girls in Arpa's land are really nice.
Mehrdad wants to invite some Hoses to the palace for a dancing party. Each Hos has some weight *w**i* and some beauty *b**i*. Also each Hos may have some friends. Hoses are divided in some friendship groups. Two Hoses *x* and *y* are in the same friendship group if... | The first line contains integers *n*, *m* and *w* (1<=<=≤<=<=*n*<=<=≤<=<=1000, , 1<=≤<=*w*<=≤<=1000) — the number of Hoses, the number of pair of friends and the maximum total weight of those who are invited.
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=1000) — the weights of the ... | Print the maximum possible total beauty of Hoses Mehrdad can invite so that no one gets hurt and the total weight doesn't exceed *w*. | [
"3 1 5\n3 2 5\n2 4 2\n1 2\n",
"4 2 11\n2 4 6 6\n6 4 2 1\n1 2\n2 3\n"
] | [
"6\n",
"7\n"
] | In the first sample there are two friendship groups: Hoses {1, 2} and Hos {3}. The best way is to choose all of Hoses in the first group, sum of their weights is equal to 5 and sum of their beauty is 6.
In the second sample there are two friendship groups: Hoses {1, 2, 3} and Hos {4}. Mehrdad can't invite all the Hose... | 1,000 | [
{
"input": "3 1 5\n3 2 5\n2 4 2\n1 2",
"output": "6"
},
{
"input": "4 2 11\n2 4 6 6\n6 4 2 1\n1 2\n2 3",
"output": "7"
},
{
"input": "10 5 100\n70 67 8 64 28 82 18 61 82 7\n596434 595982 237932 275698 361351 850374 936914 877996 789231 331012\n1 7\n2 4\n3 6\n5 7\n1 5",
"output": "238... | 1,597,163,693 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 155 | 20,582,400 |
class disjoint:
def __init__(self,n):
self.rank=[1]*n
self.parent=[i for i in range(n)]
def find(self,x):
if(self.parent[x]!=x):
self.parent[x]=self.find(self.parent[x])
return self.parent[x];
def union(self,x,y):
... | Title: Arpa's weak amphitheater and Mehrdad's valuable Hoses
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Just to remind, girls in Arpa's land are really nice.
Mehrdad wants to invite some Hoses to the palace for a dancing party. Each Hos has some weight *w**i* and some beauty *b**i*. ... | ```python
class disjoint:
def __init__(self,n):
self.rank=[1]*n
self.parent=[i for i in range(n)]
def find(self,x):
if(self.parent[x]!=x):
self.parent[x]=self.find(self.parent[x])
return self.parent[x];
def union(self,x,y):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,675,799,181 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 46 | 102,400 | n=int(input())
l=list(map(int,input().split()))
d={i: 0 for i in range(1,n+1) }
for i in range(1,n+1):
d[i]=l[i-1]
f=0
for i in range(1,n+1):
if d[d[d[i]]]==i:
print("YES")
f=1
break
if f==0:
print("NO") | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
n=int(input())
l=list(map(int,input().split()))
d={i: 0 for i in range(1,n+1) }
for i in range(1,n+1):
d[i]=l[i-1]
f=0
for i in range(1,n+1):
if d[d[d[i]]]==i:
print("YES")
f=1
break
if f==0:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
510 | A | Fox And Snake | PROGRAMMING | 800 | [
"implementation"
] | null | null | Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body ... | The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number. | Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces. | [
"3 3\n",
"3 4\n",
"5 3\n",
"9 9\n"
] | [
"###\n..#\n###\n",
"####\n...#\n####\n",
"###\n..#\n###\n#..\n###\n",
"#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n"
] | none | 500 | [
{
"input": "3 3",
"output": "###\n..#\n###"
},
{
"input": "3 4",
"output": "####\n...#\n####"
},
{
"input": "5 3",
"output": "###\n..#\n###\n#..\n###"
},
{
"input": "9 9",
"output": "#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#... | 1,678,123,761 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | a = int(input("Enter a no"))
b= int(input("Enter a no"))
for x in range(1):
print("#"*b,end="\n")
y = b-1
z = b-y
print("."*y,"#"*z,end="\n")
print("#"*b,end="\n") | Title: Fox And Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*... | ```python
a = int(input("Enter a no"))
b= int(input("Enter a no"))
for x in range(1):
print("#"*b,end="\n")
y = b-1
z = b-y
print("."*y,"#"*z,end="\n")
print("#"*b,end="\n")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,634,829,930 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 4,505,600 | def solve(k, string):
hashmap = {}
n = len(string)
for i in range(n):
if string[i] not in hashmap.keys():
hashmap[string[i]] = 1
else:
hashmap[string[i]] += 1
count_map = {}
for key in hashmap.keys():
if hashmap[key] % k != 0:
re... | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
def solve(k, string):
hashmap = {}
n = len(string)
for i in range(n):
if string[i] not in hashmap.keys():
hashmap[string[i]] = 1
else:
hashmap[string[i]] += 1
count_map = {}
for key in hashmap.keys():
if hashmap[key] % k != 0:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,683,442,103 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 92 | 0 | n = int(input())
count = 0
def is_almost_prime(n):
factors = set()
d = 2
while d * d <= n:
while n % d == 0:
factors.add(d)
n //= d
d += 1
if n > 1:
factors.add(n)
return len(factors) == 2
for i in range(1, n+1):
count ... | Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
n = int(input())
count = 0
def is_almost_prime(n):
factors = set()
d = 2
while d * d <= n:
while n % d == 0:
factors.add(d)
n //= d
d += 1
if n > 1:
factors.add(n)
return len(factors) == 2
for i in range(1, n+1):
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
931 | B | World Cup | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in the order of their ids, then the first in this order plays with the second, the third — with the ... | The only line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=256, 1<=≤<=*a*,<=*b*<=≤<=*n*) — the total number of teams, and the ids of the teams that Arkady is interested in.
It is guaranteed that *n* is such that in each round an even number of team advance, and that *a* and *b* are not equal. | In the only line print "Final!" (without quotes), if teams *a* and *b* can meet in the Final.
Otherwise, print a single integer — the number of the round in which teams *a* and *b* can meet. The round are enumerated from 1. | [
"4 1 2\n",
"8 2 6\n",
"8 7 5\n"
] | [
"1\n",
"Final!\n",
"2\n"
] | In the first example teams 1 and 2 meet in the first round.
In the second example teams 2 and 6 can only meet in the third round, which is the Final, if they win all their opponents in earlier rounds.
In the third example the teams with ids 7 and 5 can meet in the second round, if they win their opponents in the firs... | 1,000 | [
{
"input": "4 1 2",
"output": "1"
},
{
"input": "8 2 6",
"output": "Final!"
},
{
"input": "8 7 5",
"output": "2"
},
{
"input": "128 30 98",
"output": "Final!"
},
{
"input": "256 128 256",
"output": "Final!"
},
{
"input": "256 2 127",
"output": "7"
... | 1,520,180,305 | 2,605 | Python 3 | OK | TESTS | 64 | 77 | 5,734,400 | from collections import deque
import math
n, a, b = map(int, input().split())
teams = [x for x in range(1, n+1)]
round = 1
good = True
while len(teams) > 2 and good:
temp = []
for i in range(0, len(teams), 2):
t1 = teams[i]
t2 = teams[i+1]
if (t1 == a and t2 == b) or (t1 == b and t2 ==... | Title: World Cup
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in th... | ```python
from collections import deque
import math
n, a, b = map(int, input().split())
teams = [x for x in range(1, n+1)]
round = 1
good = True
while len(teams) > 2 and good:
temp = []
for i in range(0, len(teams), 2):
t1 = teams[i]
t2 = teams[i+1]
if (t1 == a and t2 == b) or (t1 == b... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
361 | A | Levko and Table | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortunately, he doesn't know any such table. Your task is to help him to find at least one of them. | The single line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). | Print any beautiful table. Levko doesn't like too big numbers, so all elements of the table mustn't exceed 1000 in their absolute value.
If there are multiple suitable tables, you are allowed to print any of them. | [
"2 4\n",
"4 7\n"
] | [
"1 3\n3 1\n",
"2 1 0 4\n4 0 2 1\n1 3 3 0\n0 3 2 2\n"
] | In the first sample the sum in the first row is 1 + 3 = 4, in the second row — 3 + 1 = 4, in the first column — 1 + 3 = 4 and in the second column — 3 + 1 = 4. There are other beautiful tables for this sample.
In the second sample the sum of elements in each row and each column equals 7. Besides, there are other table... | 500 | [
{
"input": "2 4",
"output": "4 0 \n0 4 "
},
{
"input": "4 7",
"output": "7 0 0 0 \n0 7 0 0 \n0 0 7 0 \n0 0 0 7 "
},
{
"input": "1 8",
"output": "8 "
},
{
"input": "9 3",
"output": "3 0 0 0 0 0 0 0 0 \n0 3 0 0 0 0 0 0 0 \n0 0 3 0 0 0 0 0 0 \n0 0 0 3 0 0 0 0 0 \n0 0 0 0 3 0... | 1,688,918,416 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | import sys
for _ in range(int(input())):
a,b=map(int,input().split())
for i in range(a):
for j in range(a):
if i==j:
sys.stdout.write(f"{b} ")
else:sys.stdout.write("0 ")
sys.stdout.write("\n")
| Title: Levko and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortun... | ```python
import sys
for _ in range(int(input())):
a,b=map(int,input().split())
for i in range(a):
for j in range(a):
if i==j:
sys.stdout.write(f"{b} ")
else:sys.stdout.write("0 ")
sys.stdout.write("\n")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
567 | C | Geometric Progression | PROGRAMMING | 1,700 | [
"binary search",
"data structures",
"dp"
] | null | null | Polycarp loves geometric progressions very much. Since he was only three years old, he loves only the progressions of length three. He also has a favorite integer *k* and a sequence *a*, consisting of *n* integers.
He wants to know how many subsequences of length three can be selected from *a*, so that they form a geo... | The first line of the input contains two integers, *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=2·105), showing how many numbers Polycarp's sequence has and his favorite number.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109) — elements of the sequence. | Output a single number — the number of ways to choose a subsequence of length three, such that it forms a geometric progression with a common ratio *k*. | [
"5 2\n1 1 2 2 4\n",
"3 1\n1 1 1\n",
"10 3\n1 2 6 2 3 6 9 18 3 9\n"
] | [
"4",
"1",
"6"
] | In the first sample test the answer is four, as any of the two 1s can be chosen as the first element, the second element can be any of the 2s, and the third element of the subsequence must be equal to 4. | 1,500 | [
{
"input": "5 2\n1 1 2 2 4",
"output": "4"
},
{
"input": "3 1\n1 1 1",
"output": "1"
},
{
"input": "10 3\n1 2 6 2 3 6 9 18 3 9",
"output": "6"
},
{
"input": "20 2\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20",
"output": "5"
},
{
"input": "5 3\n5 15 15 15 45... | 1,677,894,948 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 81 | 140 | 31,846,400 | import sys
input = sys.stdin.readline
from math import comb
n, k = map(int, input().split())
q = dict()
w = list(map(int, input().split()))
c, a = 0, 0
for i in w:
if i == 0:
a += 1
else:
if i not in q:
if i % k == 0 and i//k in q:
c += q[i//k][1]
... | Title: Geometric Progression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp loves geometric progressions very much. Since he was only three years old, he loves only the progressions of length three. He also has a favorite integer *k* and a sequence *a*, consisting of *n* integers... | ```python
import sys
input = sys.stdin.readline
from math import comb
n, k = map(int, input().split())
q = dict()
w = list(map(int, input().split()))
c, a = 0, 0
for i in w:
if i == 0:
a += 1
else:
if i not in q:
if i % k == 0 and i//k in q:
c += q[i//k... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
342 | B | Xenia and Spies | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"implementation"
] | null | null | Xenia the vigorous detective faced *n* (*n*<=≥<=2) foreign spies lined up in a row. We'll consider the spies numbered from 1 to *n* from left to right.
Spy *s* has an important note. He has to pass the note to spy *f*. Xenia interrogates the spies in several steps. During one step the spy keeping the important note c... | The first line contains four integers *n*, *m*, *s* and *f* (1<=≤<=*n*,<=*m*<=≤<=105; 1<=≤<=*s*,<=*f*<=≤<=*n*; *s*<=≠<=*f*; *n*<=≥<=2). Each of the following *m* lines contains three integers *t**i*,<=*l**i*,<=*r**i* (1<=≤<=*t**i*<=≤<=109,<=1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). It is guaranteed that *t*1<=<<=*t*2<=<<... | Print *k* characters in a line: the *i*-th character in the line must represent the spies' actions on step *i*. If on step *i* the spy with the note must pass the note to the spy with a lesser number, the *i*-th character should equal "L". If on step *i* the spy with the note must pass it to the spy with a larger numbe... | [
"3 5 1 3\n1 1 2\n2 2 3\n3 3 3\n4 1 1\n10 1 3\n"
] | [
"XXRR\n"
] | none | 1,000 | [
{
"input": "3 5 1 3\n1 1 2\n2 2 3\n3 3 3\n4 1 1\n10 1 3",
"output": "XXRR"
},
{
"input": "2 3 2 1\n1 1 2\n2 1 2\n4 1 2",
"output": "XXL"
},
{
"input": "5 11 1 5\n1 1 5\n2 2 2\n3 1 1\n4 3 3\n5 3 3\n6 1 1\n7 4 4\n8 4 5\n10 1 3\n11 5 5\n13 1 5",
"output": "XXXRXRXXRR"
},
{
"inpu... | 1,626,355,928 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 92 | 20,172,800 | from math import *
#from bisect import *
#from collections import *
#from random import *
#from decimal import *"""
#from heapq import *
#from random import *
import sys
input=sys.stdin.readline
#sys.setrecursionlimit(3*(10**5))
global flag
def inp():
return int(input())
def st():
return input().r... | Title: Xenia and Spies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the vigorous detective faced *n* (*n*<=≥<=2) foreign spies lined up in a row. We'll consider the spies numbered from 1 to *n* from left to right.
Spy *s* has an important note. He has to pass the note to spy *f*... | ```python
from math import *
#from bisect import *
#from collections import *
#from random import *
#from decimal import *"""
#from heapq import *
#from random import *
import sys
input=sys.stdin.readline
#sys.setrecursionlimit(3*(10**5))
global flag
def inp():
return int(input())
def st():
return... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,671,190,590 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 92 | 0 | n = int(input())
time = [int(i) for i in input().split(" ")]
start_end = [int(i) for i in input().split(" ")]
print(sum(time[start_end[0]-1:start_end[1]-1]))
| Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
n = int(input())
time = [int(i) for i in input().split(" ")]
start_end = [int(i) for i in input().split(" ")]
print(sum(time[start_end[0]-1:start_end[1]-1]))
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
448 | A | Rewards | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into two types: medals and cups. Bizon the Champion has *a*1 first prize cups, *a*2 second prize c... | The first line contains integers *a*1, *a*2 and *a*3 (0<=≤<=*a*1,<=*a*2,<=*a*3<=≤<=100). The second line contains integers *b*1, *b*2 and *b*3 (0<=≤<=*b*1,<=*b*2,<=*b*3<=≤<=100). The third line contains integer *n* (1<=≤<=*n*<=≤<=100).
The numbers in the lines are separated by single spaces. | Print "YES" (without the quotes) if all the rewards can be put on the shelves in the described manner. Otherwise, print "NO" (without the quotes). | [
"1 1 1\n1 1 1\n4\n",
"1 1 3\n2 3 4\n2\n",
"1 0 0\n1 0 0\n1\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "1 1 1\n1 1 1\n4",
"output": "YES"
},
{
"input": "1 1 3\n2 3 4\n2",
"output": "YES"
},
{
"input": "1 0 0\n1 0 0\n1",
"output": "NO"
},
{
"input": "0 0 0\n0 0 0\n1",
"output": "YES"
},
{
"input": "100 100 100\n100 100 100\n100",
"output": "YES"
},
... | 1,625,549,437 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 77 | 0 | a1,a2,a3 = [int(x) for x in input().split()]
b1,b2,b3 = [int(x) for x in input().split()]
n = int(input())
a = a1+a2+a3
b = b1+b2+b3
ans = 0
if a%5 == 0:
ans+=int(a/5)
else:
ans+=int(a/5)+1
if b%10 == 0:
ans+=int(b/10)
else:
ans+=int(b/10)+1
if ans<=n:
print("YES")
else:
print("... | Title: Rewards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion is called the Champion for a reason.
Bizon the Champion has recently got a present — a new glass cupboard with *n* shelves and he decided to put all his presents there. All the presents can be divided into ... | ```python
a1,a2,a3 = [int(x) for x in input().split()]
b1,b2,b3 = [int(x) for x in input().split()]
n = int(input())
a = a1+a2+a3
b = b1+b2+b3
ans = 0
if a%5 == 0:
ans+=int(a/5)
else:
ans+=int(a/5)+1
if b%10 == 0:
ans+=int(b/10)
else:
ans+=int(b/10)+1
if ans<=n:
print("YES")
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,691,515,360 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 0 | n=int(input())
if n%2==0 and (n//2)%2==0:
print("YES")
else:
print("NO") | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
n=int(input())
if n%2==0 and (n//2)%2==0:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
445 | A | DZY Loves Chessboard | PROGRAMMING | 1,200 | [
"dfs and similar",
"implementation"
] | null | null | DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with th... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a ... | Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell.
If multiple answers exist, print any of them. It ... | [
"1 1\n.\n",
"2 2\n..\n..\n",
"3 3\n.-.\n---\n--."
] | [
"B\n",
"BW\nWB\n",
"B-B\n---\n--B"
] | In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK.
In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output.
In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are. | 500 | [
{
"input": "1 1\n.",
"output": "B"
},
{
"input": "2 2\n..\n..",
"output": "BW\nWB"
},
{
"input": "3 3\n.-.\n---\n--.",
"output": "B-B\n---\n--B"
},
{
"input": "3 1\n-\n.\n.",
"output": "-\nW\nB"
},
{
"input": "11 11\n-----------\n-----------\n-----------\n--------... | 1,609,645,939 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 93 | 307,200 | n, m = list(map(int, input("").split()))
matrix = [[None if j == '.' else '-' for j in input("")] for i in range(n)]
for i in range(n):
for j in range(m):
if matrix[i][j] == None:
matrix[i][j] = 'W'
if i + 1 < n and matrix[i+1][j] == None:
matrix[i+1][j] = ... | Title: DZY Loves Chessboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. ... | ```python
n, m = list(map(int, input("").split()))
matrix = [[None if j == '.' else '-' for j in input("")] for i in range(n)]
for i in range(n):
for j in range(m):
if matrix[i][j] == None:
matrix[i][j] = 'W'
if i + 1 < n and matrix[i+1][j] == None:
matrix[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
346 | A | Alice and Bob | PROGRAMMING | 1,600 | [
"games",
"math",
"number theory"
] | null | null | It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following moves. During each move, either Alice or Bob (the player whose turn is the current) can choose two ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100) — the initial number of elements in the set. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the set. | Print a single line with the winner's name. If Alice wins print "Alice", otherwise print "Bob" (without quotes). | [
"2\n2 3\n",
"2\n5 3\n",
"3\n5 6 7\n"
] | [
"Alice\n",
"Alice\n",
"Bob\n"
] | Consider the first test sample. Alice moves first, and the only move she can do is to choose 2 and 3, then to add 1 to the set. Next Bob moves, there is no valid move anymore, so the winner is Alice. | 500 | [
{
"input": "2\n2 3",
"output": "Alice"
},
{
"input": "2\n5 3",
"output": "Alice"
},
{
"input": "3\n5 6 7",
"output": "Bob"
},
{
"input": "10\n72 96 24 66 6 18 12 30 60 48",
"output": "Bob"
},
{
"input": "10\n78 66 6 60 18 84 36 96 72 48",
"output": "Bob"
},
... | 1,556,901,032 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 218 | 0 | n=int(input())
l=list(map(int,input().split()))
x=l[0]
from math import gcd
for i in l:
x=gcd(x,i)
x=(max(l)//x)-n
if(x%2==1):
print("Alice")
else:
print("Bob") | Title: Alice and Bob
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following ... | ```python
n=int(input())
l=list(map(int,input().split()))
x=l[0]
from math import gcd
for i in l:
x=gcd(x,i)
x=(max(l)//x)-n
if(x%2==1):
print("Alice")
else:
print("Bob")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,620,043,153 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 216 | 1,331,200 | from fractions import gcd
a,b,n=map(int,input().split())
i=0
while n>0:
if i&1==0:
n-=gcd(n,a)
if n<0:
print("1")
elif n==0:
print("0")
else:
n-=gcd(n,b)
if n<0:
print("0")
elif n==0:
print("1")
i... | Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
from fractions import gcd
a,b,n=map(int,input().split())
i=0
while n>0:
if i&1==0:
n-=gcd(n,a)
if n<0:
print("1")
elif n==0:
print("0")
else:
n-=gcd(n,b)
if n<0:
print("0")
elif n==0:
print("... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,610,353,096 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 108 | 0 | if __name__ == "__main__":
name = "hello"
s = input()
j = 0
for i in range(len(s)):
if s[i] == name[j]:
j += 1
if j == 5:
print("YES")
exit()
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
if __name__ == "__main__":
name = "hello"
s = input()
j = 0
for i in range(len(s)):
if s[i] == name[j]:
j += 1
if j == 5:
print("YES")
exit()
print("NO")
``` | 3.946 | MatrixStudio/Codeforces-Python-Submissions |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,699,267,966 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | lucky_digits = ["4", "7"]
n = int(input())
def is_lucky(n):
a = 0
for i in range(1, n + 1):
if n % i == 0 and all(True if d in lucky_digits else False for d in str(i)):
a = a + 1
if a > 0:
return "YES"
else:
return "NO"
result = is_lucky(n)
print(resu... | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
lucky_digits = ["4", "7"]
n = int(input())
def is_lucky(n):
a = 0
for i in range(1, n + 1):
if n % i == 0 and all(True if d in lucky_digits else False for d in str(i)):
a = a + 1
if a > 0:
return "YES"
else:
return "NO"
result = is_lucky(n)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,581,188,608 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 124 | 0 | s=input()
a=s.find('h')
b=s.rfind('o')
s=s[a:b+1]
h=s.find('h')
e=s.find('e')
l=s.find('l')
o=s.find('o')
l9=s.find('l',l+1)
if(h<e<l<l9<o):
print('YES')
else:
print('NO') | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s=input()
a=s.find('h')
b=s.rfind('o')
s=s[a:b+1]
h=s.find('h')
e=s.find('e')
l=s.find('l')
o=s.find('o')
l9=s.find('l',l+1)
if(h<e<l<l9<o):
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,586,126,252 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 153,804,800 | n,k = map(int,input().split(' '))
a = list(input().split(' '))
k -= 1
seen = dict()
t = 0
end = 1
while True:
end = 1
for x in a:
if x != a[0]:
end = 0
break
if end:
break
if ''.join(a) in seen:
break
seen[''.join(a)] = 1
a = a[1:] + [a[k]]
... | Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
n,k = map(int,input().split(' '))
a = list(input().split(' '))
k -= 1
seen = dict()
t = 0
end = 1
while True:
end = 1
for x in a:
if x != a[0]:
end = 0
break
if end:
break
if ''.join(a) in seen:
break
seen[''.join(a)] = 1
a = a[1:] + ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,474,139,008 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | [n,m]=[int(x) for x in input().split()]
a=[n//5 for i in range(0,5)]
b=[m//5 for i in range(0,5)]
for i in range(1,n%5+1):
a[i]+=1
for i in range(1,m%5+1):
b[i]+=1
c=0
for i in range(0,5):
c+=a[i]*b[4-i]
print(c)
| Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
[n,m]=[int(x) for x in input().split()]
a=[n//5 for i in range(0,5)]
b=[m//5 for i in range(0,5)]
for i in range(1,n%5+1):
a[i]+=1
for i in range(1,m%5+1):
b[i]+=1
c=0
for i in range(0,5):
c+=a[i]*b[4-i]
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
331 | C1 | The Great Julya Calendar | PROGRAMMING | 1,100 | [
"dp"
] | null | null | Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on it. The translation from Old Beaverish is as follows:
"May the Great Beaver bless you! May your chacres open ... | The single line contains the magic integer *n*, 0<=≤<=*n*.
- to get 20 points, you need to solve the problem with constraints: *n*<=≤<=106 (subproblem C1); - to get 40 points, you need to solve the problem with constraints: *n*<=≤<=1012 (subproblems C1+C2); - to get 100 points, you need to solve the problem with co... | Print a single integer — the minimum number of subtractions that turns the magic number to a zero. | [
"24\n"
] | [
"5"
] | In the first test sample the minimum number of operations can be reached by the following sequence of subtractions: | 20 | [
{
"input": "24",
"output": "5"
},
{
"input": "0",
"output": "0"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "1"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "31",
"output": "6"
},
... | 1,677,516,857 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS1 | 0 | 0 | 0 | n = int(input())
count = 0
while n >= 100:
count += 1
n -= max(list(map(int, list(str(n)))))
if n % 10 == 0:
print(((n // 10) * 2)
else:
print((n // 10) * 2 + 1)
| Title: The Great Julya Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on i... | ```python
n = int(input())
count = 0
while n >= 100:
count += 1
n -= max(list(map(int, list(str(n)))))
if n % 10 == 0:
print(((n // 10) * 2)
else:
print((n // 10) * 2 + 1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
637 | C | Promocodes with Mistakes | PROGRAMMING | 1,400 | [
"*special",
"brute force",
"constructive algorithms",
"implementation"
] | null | null | During a New Year special offer the "Sudislavl Bars" offered *n* promo codes. Each promo code consists of exactly six digits and gives right to one free cocktail at the bar "Mosquito Shelter". Of course, all the promocodes differ.
As the "Mosquito Shelter" opens only at 9, and partying in Sudislavl usually begins at a... | The first line of the output contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of promocodes.
Each of the next *n* lines contains a single promocode, consisting of exactly 6 digits. It is guaranteed that all the promocodes are distinct. Promocodes can start from digit "0". | Print the maximum *k* (naturally, not exceeding the length of the promocode), such that any promocode can be uniquely identified if it is typed with at most *k* mistakes. | [
"2\n000000\n999999\n",
"6\n211111\n212111\n222111\n111111\n112111\n121111\n"
] | [
"2\n",
"0\n"
] | In the first sample *k* < 3, so if a bar customer types in value "090909", then it will be impossible to define which promocode exactly corresponds to it. | 1,500 | [
{
"input": "2\n000000\n999999",
"output": "2"
},
{
"input": "6\n211111\n212111\n222111\n111111\n112111\n121111",
"output": "0"
},
{
"input": "1\n123456",
"output": "6"
},
{
"input": "2\n000000\n099999",
"output": "2"
},
{
"input": "2\n000000\n009999",
"output"... | 1,678,253,946 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | def main():
n = eval(input())
t = []
for _ in range(n):
s = input()
t.append(s)
ans = 2
for i in range(1, n):
a = t[i]
for j in range(i):
b = t[j]
k = 0
for c1, c2 in zip(a, b):
if c1 == c2:
... | Title: Promocodes with Mistakes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During a New Year special offer the "Sudislavl Bars" offered *n* promo codes. Each promo code consists of exactly six digits and gives right to one free cocktail at the bar "Mosquito Shelter". Of course, all th... | ```python
def main():
n = eval(input())
t = []
for _ in range(n):
s = input()
t.append(s)
ans = 2
for i in range(1, n):
a = t[i]
for j in range(i):
b = t[j]
k = 0
for c1, c2 in zip(a, b):
if c1 == c2:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
768 | A | Oath of the Night's Watch | PROGRAMMING | 900 | [
"constructive algorithms",
"sortings"
] | null | null | "Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am the sword in the darkness. I am the watcher on the walls. I am the shield that guards the realms of men. I ple... | First line consists of a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of stewards with Jon Snow.
Second line consists of *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) representing the values assigned to the stewards. | Output a single integer representing the number of stewards which Jon will feed. | [
"2\n1 5\n",
"3\n1 2 5\n"
] | [
"0",
"1"
] | In the first sample, Jon Snow cannot support steward with strength 1 because there is no steward with strength less than 1 and he cannot support steward with strength 5 because there is no steward with strength greater than 5.
In the second sample, Jon Snow can support steward with strength 2 because there are steward... | 500 | [
{
"input": "2\n1 5",
"output": "0"
},
{
"input": "3\n1 2 5",
"output": "1"
},
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "8\n7 8 9 4 5 6 1 2",
"output": "6"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n100",
"output": "0"
},
... | 1,698,262,437 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 13 | 93 | 11,264,000 | a = int(input())
b = [int(i) for i in input().split(' ')]
b.sort()
i = 0
mini = b[i]
j = a-1
maxi = b[j]
while(b[i]==mini):
i += 1
while(b[j]==maxi):
j -= 1
print(j-i+1) | Title: Oath of the Night's Watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am... | ```python
a = int(input())
b = [int(i) for i in input().split(' ')]
b.sort()
i = 0
mini = b[i]
j = a-1
maxi = b[j]
while(b[i]==mini):
i += 1
while(b[j]==maxi):
j -= 1
print(j-i+1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
18 | A | Triangle | PROGRAMMING | 1,500 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | At a geometry lesson Bob learnt that a triangle is called right-angled if it is nondegenerate and one of its angles is right. Bob decided to draw such a triangle immediately: on a sheet of paper he drew three points with integer coordinates, and joined them with segments of straight lines, then he showed the triangle t... | The first input line contains 6 space-separated integers *x*1,<=*y*1,<=*x*2,<=*y*2,<=*x*3,<=*y*3 — coordinates of the triangle's vertices. All the coordinates are integer and don't exceed 100 in absolute value. It's guaranteed that the triangle is nondegenerate, i.e. its total area is not zero. | If the given triangle is right-angled, output RIGHT, if it is almost right-angled, output ALMOST, and if it is neither of these, output NEITHER. | [
"0 0 2 0 0 1\n",
"2 3 4 5 6 6\n",
"-1 0 2 0 0 1\n"
] | [
"RIGHT\n",
"NEITHER\n",
"ALMOST\n"
] | none | 0 | [
{
"input": "0 0 2 0 0 1",
"output": "RIGHT"
},
{
"input": "2 3 4 5 6 6",
"output": "NEITHER"
},
{
"input": "-1 0 2 0 0 1",
"output": "ALMOST"
},
{
"input": "27 74 85 23 100 99",
"output": "NEITHER"
},
{
"input": "-97 -19 17 62 30 -76",
"output": "NEITHER"
},... | 1,443,272,394 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 30 | 124 | 0 |
def is_right(l):
a = (l[0]-l[2])**2 + (l[1]-l[3])**2
b = (l[4]-l[2])**2 + (l[5]-l[3])**2
c = (l[0]-l[4])**2 + (l[1]-l[5])**2
return a == b+c\
or b == a+c\
or c==a+b
def is_almost(l):
for i in range(6):
l[i]+=1
res = is_right(l)
l[i]-=1
if r... | Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
At a geometry lesson Bob learnt that a triangle is called right-angled if it is nondegenerate and one of its angles is right. Bob decided to draw such a triangle immediately: on a sheet of paper he drew three points with integer co... | ```python
def is_right(l):
a = (l[0]-l[2])**2 + (l[1]-l[3])**2
b = (l[4]-l[2])**2 + (l[5]-l[3])**2
c = (l[0]-l[4])**2 + (l[1]-l[5])**2
return a == b+c\
or b == a+c\
or c==a+b
def is_almost(l):
for i in range(6):
l[i]+=1
res = is_right(l)
l[i]-=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
177 | A1 | Good Matrix Elements | PROGRAMMING | 800 | [
"implementation"
] | null | null | The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the main diagonal. - Elements of the secondary diagonal. - Elements of the "middle" row — the row which ha... | The first line of input data contains a single odd integer *n*. Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=100) separated by single spaces — the elements of the given matrix.
The input limitations for getting 30 points are:
- 1<=≤<=*n*<=≤<=5
The input limitations for getting 100 po... | Print a single integer — the sum of good matrix elements. | [
"3\n1 2 3\n4 5 6\n7 8 9\n",
"5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n"
] | [
"45\n",
"17\n"
] | In the first sample all matrix elements will be good. Good elements in the second sample are shown on the figure. | 30 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "45"
},
{
"input": "5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1",
"output": "17"
},
{
"input": "1\n3",
"output": "3"
},
{
"input": "5\n27 7 3 11 72\n19 49 68 19 59\n41 25 37 64 65\n8 39 96 62 90\n13 37 43 26 33",
... | 1,566,656,927 | 2,147,483,647 | Python 3 | OK | TESTS1 | 17 | 218 | 0 | n = int(input())
res = 0
for i in range(n):
row = map(int, input().split())
for j, v in enumerate(row):
if i == j or i + j == n - 1 or i == n // 2 or j == n // 2:
res += v
print(res)
| Title: Good Matrix Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the ... | ```python
n = int(input())
res = 0
for i in range(n):
row = map(int, input().split())
for j, v in enumerate(row):
if i == j or i + j == n - 1 or i == n // 2 or j == n // 2:
res += v
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
899 | C | Dividing the numbers | PROGRAMMING | 1,300 | [
"constructive algorithms",
"graphs",
"math"
] | null | null | Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help Petya to split the integers. Each of *n* integers should be exactly in one group. | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=60<=000) — the number of integers Petya has. | Print the smallest possible absolute difference in the first line.
In the second line print the size of the first group, followed by the integers in that group. You can print these integers in arbitrary order. If there are multiple answers, print any of them. | [
"4\n",
"2\n"
] | [
"0\n2 1 4 \n",
"1\n1 1 \n"
] | In the first example you have to put integers 1 and 4 in the first group, and 2 and 3 in the second. This way the sum in each group is 5, and the absolute difference is 0.
In the second example there are only two integers, and since both groups should be non-empty, you have to put one integer in the first group and on... | 1,500 | [
{
"input": "4",
"output": "0\n2 1 4 "
},
{
"input": "2",
"output": "1\n1 1 "
},
{
"input": "3",
"output": "0\n1\n3 "
},
{
"input": "5",
"output": "1\n3\n1 2 5 "
},
{
"input": "59998",
"output": "1\n29999 1 4 5 8 9 12 13 16 17 20 21 24 25 28 29 32 33 36 37 40 4... | 1,625,346,683 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 233 | 10,649,600 | import sys
import math
import collections
import heapq
import decimal
input=sys.stdin.readline
n=int(input())
if(n==2):
print(1)
print(1,1)
elif(n==3):
print(0)
print(2,1,2)
else:
l=[]
for i in range(n,2,-4):
l.append(n-1)
l.append(n-2)
if(n%4==0 or n%4==3):... | Title: Dividing the numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has *n* integers: 1,<=2,<=3,<=...,<=*n*. He wants to split these integers in two non-empty groups in such a way that the absolute difference of sums of integers in each group is as small as possible.
Help P... | ```python
import sys
import math
import collections
import heapq
import decimal
input=sys.stdin.readline
n=int(input())
if(n==2):
print(1)
print(1,1)
elif(n==3):
print(0)
print(2,1,2)
else:
l=[]
for i in range(n,2,-4):
l.append(n-1)
l.append(n-2)
if(n%4==0 o... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
557 | C | Arthur and Table | PROGRAMMING | 1,900 | [
"brute force",
"data structures",
"dp",
"greedy",
"math",
"sortings"
] | null | null | Arthur has bought a beautiful big table into his new flat. When he came home, Arthur noticed that the new table is unstable.
In total the table Arthur bought has *n* legs, the length of the *i*-th leg is *l**i*.
Arthur decided to make the table stable and remove some legs. For each of them Arthur determined number *d... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=105) — the initial number of legs in the table Arthur bought.
The second line of the input contains a sequence of *n* integers *l**i* (1<=≤<=*l**i*<=≤<=105), where *l**i* is equal to the length of the *i*-th leg of the table.
The third line of the input ... | Print a single integer — the minimum number of energy units that Arthur needs to spend in order to make the table stable. | [
"2\n1 5\n3 2\n",
"3\n2 4 4\n1 1 1\n",
"6\n2 2 1 1 3 3\n4 3 5 5 2 1\n"
] | [
"2\n",
"0\n",
"8\n"
] | none | 1,500 | [
{
"input": "2\n1 5\n3 2",
"output": "2"
},
{
"input": "3\n2 4 4\n1 1 1",
"output": "0"
},
{
"input": "6\n2 2 1 1 3 3\n4 3 5 5 2 1",
"output": "8"
},
{
"input": "10\n20 1 15 17 11 2 15 3 16 3\n129 114 183 94 169 16 18 104 49 146",
"output": "652"
},
{
"input": "10\... | 1,436,630,377 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 0 | inpt = input()
h = [int(i) for i in list(input().split())]
e = [int(i) for i in list(input().split())]
def min_cost(h, e):
h1 = h
e1 = e
#print("count:", h1.count(max(h1)))
#print("nesfesh:", len(h1)//2)
if h1.count(max(h1)) > len(h1)//2:
# print(sum(e for e in e1 ))
return ... | Title: Arthur and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arthur has bought a beautiful big table into his new flat. When he came home, Arthur noticed that the new table is unstable.
In total the table Arthur bought has *n* legs, the length of the *i*-th leg is *l**i*.
Arth... | ```python
inpt = input()
h = [int(i) for i in list(input().split())]
e = [int(i) for i in list(input().split())]
def min_cost(h, e):
h1 = h
e1 = e
#print("count:", h1.count(max(h1)))
#print("nesfesh:", len(h1)//2)
if h1.count(max(h1)) > len(h1)//2:
# print(sum(e for e in e1 ))
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,652,523,208 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | #Укладка доминошками
dLen,dWid=list(map(int,input().split(" ")))
fLen,fWid=[2,1]
print(dLen*dWid//(fLen*fWid))
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
#Укладка доминошками
dLen,dWid=list(map(int,input().split(" ")))
fLen,fWid=[2,1]
print(dLen*dWid//(fLen*fWid))
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,681,909,563 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 92 | 0 | s=input()
start='a'
count=0
for i in s:
diff=abs(ord(i)-ord(start))
count+=min(diff,26-diff)
start=i
print(count)
| Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
s=input()
start='a'
count=0
for i in s:
diff=abs(ord(i)-ord(start))
count+=min(diff,26-diff)
start=i
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
412 | B | Network Configuration | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | The R1 company wants to hold a web search championship. There were *n* computers given for the competition, each of them is connected to the Internet. The organizers believe that the data transfer speed directly affects the result. The higher the speed of the Internet is, the faster the participant will find the necess... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100) — the number of computers and the number of participants, respectively. In the second line you have a space-separated sequence consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (16<=≤<=*a**i*<=≤<=32768); number *a**i* deno... | Print a single integer — the maximum Internet speed value. It is guaranteed that the answer to the problem is always an integer. | [
"3 2\n40 20 30\n",
"6 4\n100 20 40 20 50 50\n"
] | [
"30\n",
"40\n"
] | In the first test case the organizers can cut the first computer's speed to 30 kilobits. Then two computers (the first and the third one) will have the same speed of 30 kilobits. They should be used as the participants' computers. This answer is optimal. | 1,000 | [
{
"input": "3 2\n40 20 30",
"output": "30"
},
{
"input": "6 4\n100 20 40 20 50 50",
"output": "40"
},
{
"input": "1 1\n16",
"output": "16"
},
{
"input": "2 1\n10000 17",
"output": "10000"
},
{
"input": "2 2\n200 300",
"output": "200"
},
{
"input": "3 1... | 1,643,131,704 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | def func():
n,m = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
print(a[n-m])
def main():
print('ok or exit: ')
while input() != 'exit':
print('execute.')
func()
print('ok or exit: ')
#main()
func() | Title: Network Configuration
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The R1 company wants to hold a web search championship. There were *n* computers given for the competition, each of them is connected to the Internet. The organizers believe that the data transfer speed directly a... | ```python
def func():
n,m = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
print(a[n-m])
def main():
print('ok or exit: ')
while input() != 'exit':
print('execute.')
func()
print('ok or exit: ')
#main()
func()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
552 | B | Vanya and Books | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assigned distinct numbers.
Vanya wants to know how many digits he will have to write down as he labels th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109) — the number of books in the library. | Print the number of digits needed to number all the books. | [
"13\n",
"4\n"
] | [
"17\n",
"4\n"
] | Note to the first test. The books get numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, which totals to 17 digits.
Note to the second sample. The books get numbers 1, 2, 3, 4, which totals to 4 digits. | 1,000 | [
{
"input": "13",
"output": "17"
},
{
"input": "4",
"output": "4"
},
{
"input": "100",
"output": "192"
},
{
"input": "99",
"output": "189"
},
{
"input": "1000000000",
"output": "8888888899"
},
{
"input": "1000000",
"output": "5888896"
},
{
"... | 1,446,532,109 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n = input()
a = 0
for i in range(1, n + 1):
a += len(str(i))
print a
| Title: Vanya and Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assig... | ```python
n = input()
a = 0
for i in range(1, n + 1):
a += len(str(i))
print a
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,560,401,618 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 0 | n,v=map(int,input().split())
ans=[]
for i in range(n):
l1=list(map(int,input().split()))
for item in l1[1:]:
if item<v:
ans.append(i+1)
break
print(len(ans))
print(' '.join(str(x) for x in ans)) | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
n,v=map(int,input().split())
ans=[]
for i in range(n):
l1=list(map(int,input().split()))
for item in l1[1:]:
if item<v:
ans.append(i+1)
break
print(len(ans))
print(' '.join(str(x) for x in ans))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
336 | A | Vasily the Bear and Triangle | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasily the bear has a favorite rectangle, it has one vertex at point (0,<=0), and the opposite vertex at point (*x*,<=*y*). Of course, the sides of Vasya's favorite rectangle are parallel to the coordinate axes.
Vasya also loves triangles, if the triangles have one vertex at point *B*<==<=(0,<=0). That's why today he... | The first line contains two integers *x*,<=*y* (<=-<=109<=≤<=*x*,<=*y*<=≤<=109,<=*x*<=≠<=0,<=*y*<=≠<=0). | Print in the single line four integers *x*1,<=*y*1,<=*x*2,<=*y*2 — the coordinates of the required points. | [
"10 5\n",
"-10 5\n"
] | [
"0 15 15 0\n",
"-15 0 0 15\n"
] | <img class="tex-graphics" src="https://espresso.codeforces.com/a9ea2088c4294ce8f23801562fda36b830df2c3f.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Figure to the first sample | 500 | [
{
"input": "10 5",
"output": "0 15 15 0"
},
{
"input": "-10 5",
"output": "-15 0 0 15"
},
{
"input": "20 -10",
"output": "0 -30 30 0"
},
{
"input": "-10 -1000000000",
"output": "-1000000010 0 0 -1000000010"
},
{
"input": "-1000000000 -1000000000",
"output": "-... | 1,376,647,619 | 419 | Python 3 | OK | TESTS | 30 | 124 | 0 | x, y = map(int, input().split())
p1, p2 = (0, (-1 if y < 0 else 1) * (abs(x) + abs(y))), ((-1 if x < 0 else 1) * (abs(x) + abs(y)), 0)
if p1[0] > p2[0]:
p1, p2 = p2, p1
print(' '.join(map(str, p1 + p2))) | Title: Vasily the Bear and Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the bear has a favorite rectangle, it has one vertex at point (0,<=0), and the opposite vertex at point (*x*,<=*y*). Of course, the sides of Vasya's favorite rectangle are parallel to the coordinate ... | ```python
x, y = map(int, input().split())
p1, p2 = (0, (-1 if y < 0 else 1) * (abs(x) + abs(y))), ((-1 if x < 0 else 1) * (abs(x) + abs(y)), 0)
if p1[0] > p2[0]:
p1, p2 = p2, p1
print(' '.join(map(str, p1 + p2)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
721 | A | One-dimensional Japanese Crossword | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the left of the rows and to the top of the columns, encrypting the corresponding row or column. The number of integers repr... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the row. The second line of the input contains a single string consisting of *n* characters 'B' or 'W', ('B' corresponds to black square, 'W' — to white square in the row that Adaltik drew). | The first line should contain a single integer *k* — the number of integers encrypting the row, e.g. the number of groups of black squares in the row.
The second line should contain *k* integers, encrypting the row, e.g. corresponding to sizes of groups of consecutive black squares in the order from left to right. | [
"3\nBBW\n",
"5\nBWBWB\n",
"4\nWWWW\n",
"4\nBBBB\n",
"13\nWBBBBWWBWBBBW\n"
] | [
"1\n2 ",
"3\n1 1 1 ",
"0\n",
"1\n4 ",
"3\n4 1 3 "
] | The last sample case correspond to the picture in the statement. | 500 | [
{
"input": "3\nBBW",
"output": "1\n2 "
},
{
"input": "5\nBWBWB",
"output": "3\n1 1 1 "
},
{
"input": "4\nWWWW",
"output": "0"
},
{
"input": "4\nBBBB",
"output": "1\n4 "
},
{
"input": "13\nWBBBBWWBWBBBW",
"output": "3\n4 1 3 "
},
{
"input": "1\nB",
... | 1,678,262,017 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | n =int(input())
seq = input() + 'x'
blakseq = 0
lis_sq_len = []
for i in seq :
if i =="B" :
blakseq +=1
else:
if blakseq == 0 :
continue
else:
lis_sq_len.append(blakseq)
blakseq = 0
print(len(lis_sq_len))
for i in lis_sq_len :
... | Title: One-dimensional Japanese Crossword
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the... | ```python
n =int(input())
seq = input() + 'x'
blakseq = 0
lis_sq_len = []
for i in seq :
if i =="B" :
blakseq +=1
else:
if blakseq == 0 :
continue
else:
lis_sq_len.append(blakseq)
blakseq = 0
print(len(lis_sq_len))
for i in lis_sq_l... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,624,754,845 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | def solve():
n = int(input())
numArray = list(map(int, input().split()))
# n = 6
# numArray = [2, 2, 1, 1, 4, 6]
numArray.sort()
dictionary = {}
found1, found2, found3, found4, found5, found6 = 0
for item in numArray:
if item == 5 or item == 7:
ret... | Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
def solve():
n = int(input())
numArray = list(map(int, input().split()))
# n = 6
# numArray = [2, 2, 1, 1, 4, 6]
numArray.sort()
dictionary = {}
found1, found2, found3, found4, found5, found6 = 0
for item in numArray:
if item == 5 or item == 7:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
493 | B | Vasya and Wrestling | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers are equal, the wrestler whose sequence of points is lexicographically greater, wins.
If the sequences of... | The first line contains number *n* — the number of techniques that the wrestlers have used (1<=≤<=*n*<=≤<=2·105).
The following *n* lines contain integer numbers *a**i* (|*a**i*|<=≤<=109, *a**i*<=≠<=0). If *a**i* is positive, that means that the first wrestler performed the technique that was awarded with *a**i* poin... | If the first wrestler wins, print string "first", otherwise print "second" | [
"5\n1\n2\n-3\n-4\n3\n",
"3\n-1\n-2\n3\n",
"2\n4\n-4\n"
] | [
"second\n",
"first\n",
"second\n"
] | Sequence *x* = *x*<sub class="lower-index">1</sub>*x*<sub class="lower-index">2</sub>... *x*<sub class="lower-index">|*x*|</sub> is lexicographically larger than sequence *y* = *y*<sub class="lower-index">1</sub>*y*<sub class="lower-index">2</sub>... *y*<sub class="lower-index">|*y*|</sub>, if either |*x*| > |... | 1,000 | [
{
"input": "5\n1\n2\n-3\n-4\n3",
"output": "second"
},
{
"input": "3\n-1\n-2\n3",
"output": "first"
},
{
"input": "2\n4\n-4",
"output": "second"
},
{
"input": "7\n1\n2\n-3\n4\n5\n-6\n7",
"output": "first"
},
{
"input": "14\n1\n2\n3\n4\n5\n6\n7\n-8\n-9\n-10\n-11\n-... | 1,417,620,791 | 1,991 | Python 3 | WRONG_ANSWER | TESTS | 37 | 592 | 3,686,400 | n = int(input())
f = ""
s = ""
fsum = 0
ssum = 0
a = 0
for i in range(n):
a = int(input())
if a > 0:
f += str(a)
fsum += a
else:
s += str(-a)
ssum += (-a)
if fsum == ssum:
if f == s:
print("first") if a > 0 else print("second")
else:
... | Title: Vasya and Wrestling
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has become interested in wrestling. In wrestling wrestlers use techniques for which they are awarded points by judges. The wrestler who gets the most points wins.
When the numbers of points of both wrestlers ... | ```python
n = int(input())
f = ""
s = ""
fsum = 0
ssum = 0
a = 0
for i in range(n):
a = int(input())
if a > 0:
f += str(a)
fsum += a
else:
s += str(-a)
ssum += (-a)
if fsum == ssum:
if f == s:
print("first") if a > 0 else print("second")
else:... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
592 | A | PawnChess | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Galois is one of the strongest chess players of Byteforces. He has even invented a new variant of chess, which he named «PawnChess».
This new game is played on a board consisting of 8 rows and 8 columns. At the beginning of every game some black and white pawns are placed on the board. The number of black pawns placed... | The input consists of the board description given in eight lines, each line contains eight characters. Character 'B' is used to denote a black pawn, and character 'W' represents a white pawn. Empty cell is marked with '.'.
It's guaranteed that there will not be white pawns on the first row neither black pawns on the ... | Print 'A' if player A wins the game on the given board, and 'B' if player B will claim the victory. Again, it's guaranteed that there will always be a winner on the given board. | [
"........\n........\n.B....B.\n....W...\n........\n..W.....\n........\n........\n",
"..B.....\n..W.....\n......B.\n........\n.....W..\n......B.\n........\n........\n"
] | [
"A\n",
"B\n"
] | In the first sample player A is able to complete his goal in 3 steps by always moving a pawn initially located at (4, 5). Player B needs at least 5 steps for any of his pawns to reach the row 8. Hence, player A will be the winner. | 500 | [
{
"input": ".BB.B.B.\nB..B..B.\n.B.BB...\nBB.....B\nBBB....B\nB..BB...\nBB.B...B\n....WWW.",
"output": "B"
},
{
"input": "B.B.BB.B\nW.WWW.WW\n.WWWWW.W\nW.BB.WBW\n.W..BBWB\nBB.WWBBB\n.W.W.WWB\nWWW..WW.",
"output": "A"
},
{
"input": "BB..BB..\nBW.W.W.B\n..B.....\n.....BB.\n.B..B..B\n......... | 1,446,310,413 | 1,413 | Python 3 | OK | TESTS | 56 | 62 | 0 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
import time
# = input()
# = int(input())
#() = (i for i in input().split())
# = [i for i in input().split()]
#() = (int(i) for i in input().split())
a = [[ 0 for j in range(8) ] for i in range(8) ]
for i in range(8):
b = input()
for j in range(8):
... | Title: PawnChess
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Galois is one of the strongest chess players of Byteforces. He has even invented a new variant of chess, which he named «PawnChess».
This new game is played on a board consisting of 8 rows and 8 columns. At the beginning of ... | ```python
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import time
# = input()
# = int(input())
#() = (i for i in input().split())
# = [i for i in input().split()]
#() = (int(i) for i in input().split())
a = [[ 0 for j in range(8) ] for i in range(8) ]
for i in range(8):
b = input()
for j in rang... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
845 | A | Chess Tourney | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by BerMobile. Obviously, organizers should guarantee the win for the team of BerOil.
Thus, organizer... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100).
The second line contains 2·*n* integers *a*1,<=*a*2,<=... *a*2*n* (1<=≤<=*a**i*<=≤<=1000). | If it's possible to divide all 2·*n* players into two teams with *n* people each so that the player from the first team in every pair wins regardless of the results of the drawing, then print "YES". Otherwise print "NO". | [
"2\n1 3 2 4\n",
"1\n3 3\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "2\n1 3 2 4",
"output": "YES"
},
{
"input": "1\n3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 2 2 3 3 3 3",
"output": "NO"
},
{
"input": "5\n1 1 1 1 1 2 2 2 2 2",
"output": "YES"
},
{
"input": "10\n1000 1000 1000 1000 1000 1000 1000 1000 1000 1000 1000... | 1,505,815,971 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 61 | 0 | n = int(input())
a = [int(x) for x in input().split()]
if len(a)==n*2:
sumofn = 0
for l in range(len(a)):
sumofn = sumofn + a[l]
val = sumofn/len(a)
v1=v2=0
for r in range(len(a)):
if a[r]>val:
v1=v1+1
else:
v2=v2+1
... | Title: Chess Tourney
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland annual chess tournament is coming!
Organizers have gathered 2·*n* chess players who should be divided into two teams with *n* people each. The first team is sponsored by BerOil and the second team is sponsored by... | ```python
n = int(input())
a = [int(x) for x in input().split()]
if len(a)==n*2:
sumofn = 0
for l in range(len(a)):
sumofn = sumofn + a[l]
val = sumofn/len(a)
v1=v2=0
for r in range(len(a)):
if a[r]>val:
v1=v1+1
else:
v2=v2... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,674,586,135 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | i=input();
print(''.join(01)[a!=b]for a,b in zip(i(),i()))) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
i=input();
print(''.join(01)[a!=b]for a,b in zip(i(),i())))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,691,689,251 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 2,662,400 | if __name__ == '__main__':
_ = input().split()
n = int(_[0])
t = int(_[1])
portals = input().split()
for i in range(0, len(portals)):
portals[i] = int(portals[i]) + i + 1
init = int(1)
while init < t:
# print(init)
init = portals[init]
if init == t:
... | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
if __name__ == '__main__':
_ = input().split()
n = int(_[0])
t = int(_[1])
portals = input().split()
for i in range(0, len(portals)):
portals[i] = int(portals[i]) + i + 1
init = int(1)
while init < t:
# print(init)
init = portals[init]
if i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as large as the size of kangaroo who is held.
Each kangaroo can hold at most one kangaroo, and the kangaroo who i... | The first line contains a single integer — *n* (1<=≤<=*n*<=≤<=5·105). Each of the next *n* lines contains an integer *s**i* — the size of the *i*-th kangaroo (1<=≤<=*s**i*<=≤<=105). | Output a single integer — the optimal number of visible kangaroos. | [
"8\n2\n5\n7\n6\n9\n8\n4\n2\n",
"8\n9\n1\n6\n2\n6\n5\n8\n3\n"
] | [
"5\n",
"5\n"
] | none | 0 | [
{
"input": "8\n2\n5\n7\n6\n9\n8\n4\n2",
"output": "5"
},
{
"input": "8\n9\n1\n6\n2\n6\n5\n8\n3",
"output": "5"
},
{
"input": "12\n3\n99\n24\n46\n75\n63\n57\n55\n10\n62\n34\n52",
"output": "7"
},
{
"input": "12\n55\n75\n1\n98\n63\n64\n9\n39\n82\n18\n47\n9",
"output": "6"
... | 1,682,956,445 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 966 | 14,950,400 | n = int(input())
s = sorted([int(input()) for _ in range(n)])
mid = n // 2
res = 0
i, j = 0, mid
while i < mid and j < n:
if s[i] * 2 <= s[j]:
res += 1
i += 1
j += 1
else:
j += 1
print(n - res)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as large as the size of ... | ```python
n = int(input())
s = sorted([int(input()) for _ in range(n)])
mid = n // 2
res = 0
i, j = 0, mid
while i < mid and j < n:
if s[i] * 2 <= s[j]:
res += 1
i += 1
j += 1
else:
j += 1
print(n - res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,633,362,759 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 6 | 46 | 6,963,200 | # -*- coding: utf-8 -*-
"""
Created on Mon Oct 4 22:05:30 2021
@author: Asus
"""
s=str(input())
liss=list(s[i] for i in range(len(s)))
if 'h' and 'e' and 'l' and 'o' not in liss:
print('NO')
else:
a=int(liss.index('h'))
lisb=liss[a+1:]
b=int(len(liss[:a])+int(lisb.index('e')+1))
li... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
# -*- coding: utf-8 -*-
"""
Created on Mon Oct 4 22:05:30 2021
@author: Asus
"""
s=str(input())
liss=list(s[i] for i in range(len(s)))
if 'h' and 'e' and 'l' and 'o' not in liss:
print('NO')
else:
a=int(liss.index('h'))
lisb=liss[a+1:]
b=int(len(liss[:a])+int(lisb.index('e')+1... | -1 | MatrixStudio/Codeforces-Python-Submissions |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,688,740,365 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 77 | 0 | s=input()
s=s[1:-1]
s=s.replace(',','')
s=s.replace(' ','')
s=set(s)
print(len(s))
| Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
s=input()
s=s[1:-1]
s=s.replace(',','')
s=s.replace(' ','')
s=set(s)
print(len(s))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,658,599,320 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 20 | 186 | 0 | def solve():
s = input()
if not s.startswith('1'):
print("NO")
return
for i in s:
if i != "1" and i != "4":
print("NO")
return
f = 0
mx = 0
for i in s:
if i == "1":
mx = max(mx,f)
f = 0
else:
... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
def solve():
s = input()
if not s.startswith('1'):
print("NO")
return
for i in s:
if i != "1" and i != "4":
print("NO")
return
f = 0
mx = 0
for i in s:
if i == "1":
mx = max(mx,f)
f = 0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,628,466,840 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 124 | 6,963,200 | n=int(input())
res={}
sigma=[]
for i in range(n):
x=input().split()
sigma.append(x)
if x[0] in res:
res[x[0]]+=int(x[1])
else:
res[x[0]]=int(x[1])
y=max(res.values())
w=set()
for j in res.keys():
if res[j]==y:
w.add(j)
res={}
for i in range(n):
x=sigma[i]... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n=int(input())
res={}
sigma=[]
for i in range(n):
x=input().split()
sigma.append(x)
if x[0] in res:
res[x[0]]+=int(x[1])
else:
res[x[0]]=int(x[1])
y=max(res.values())
w=set()
for j in res.keys():
if res[j]==y:
w.add(j)
res={}
for i in range(n):
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
621 | B | Wet Shark and Bishops | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation"
] | null | null | Today, Wet Shark is given *n* bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from 1 to 1000. Rows are numbered from top to bottom, while columns are numbered from left to right.
Wet Shark thinks that two bishops attack each other if they share the same diagonal. Note, that this is the o... | The first line of the input contains *n* (1<=≤<=*n*<=≤<=200<=000) — the number of bishops.
Each of next *n* lines contains two space separated integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the number of row and the number of column where *i*-th bishop is positioned. It's guaranteed that no two bishops ... | Output one integer — the number of pairs of bishops which attack each other. | [
"5\n1 1\n1 5\n3 3\n5 1\n5 5\n",
"3\n1 1\n2 3\n3 5\n"
] | [
"6\n",
"0\n"
] | In the first sample following pairs of bishops attack each other: (1, 3), (1, 5), (2, 3), (2, 4), (3, 4) and (3, 5). Pairs (1, 2), (1, 4), (2, 5) and (4, 5) do not attack each other because they do not share the same diagonal. | 1,000 | [
{
"input": "5\n1 1\n1 5\n3 3\n5 1\n5 5",
"output": "6"
},
{
"input": "3\n1 1\n2 3\n3 5",
"output": "0"
},
{
"input": "3\n859 96\n634 248\n808 72",
"output": "0"
},
{
"input": "3\n987 237\n891 429\n358 145",
"output": "0"
},
{
"input": "3\n411 81\n149 907\n611 114"... | 1,587,231,438 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 1,668 | 9,216,000 | n=int(input())
a=1
b=1
summ=[]
diff=[]
for i in range(n):
x,y=map(int,input().split())
if x+y in summ:
a+=1
else:
summ.append(x+y)
if x-y in diff:
b+=1
else:
diff.append(x-y)
if a==1 and b==1:
print(0)
elif a==1 and b!=1:
print((b*(b-1))//2)
... | Title: Wet Shark and Bishops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, Wet Shark is given *n* bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from 1 to 1000. Rows are numbered from top to bottom, while columns are numbered from left to right.
We... | ```python
n=int(input())
a=1
b=1
summ=[]
diff=[]
for i in range(n):
x,y=map(int,input().split())
if x+y in summ:
a+=1
else:
summ.append(x+y)
if x-y in diff:
b+=1
else:
diff.append(x-y)
if a==1 and b==1:
print(0)
elif a==1 and b!=1:
print((b*(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
342 | A | Xenia and Divisors | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,<=*b*,<=*c* the following conditions held:
- *a*<=<<=*b*<=<<=*c*; - *a* divides *b*, *b* divide... | The first line contains integer *n* (3<=≤<=*n*<=≤<=99999) — the number of elements in the sequence. The next line contains *n* positive integers, each of them is at most 7.
It is guaranteed that *n* is divisible by 3. | If the required partition exists, print groups of three. Print each group as values of the elements it contains. You should print values in increasing order. Separate the groups and integers in groups by whitespaces. If there are multiple solutions, you can print any of them.
If there is no solution, print -1. | [
"6\n1 1 1 2 2 2\n",
"6\n2 2 1 1 4 6\n"
] | [
"-1\n",
"1 2 4\n1 2 6\n"
] | none | 500 | [
{
"input": "6\n1 1 1 2 2 2",
"output": "-1"
},
{
"input": "6\n2 2 1 1 4 6",
"output": "1 2 4\n1 2 6"
},
{
"input": "3\n1 2 3",
"output": "-1"
},
{
"input": "3\n7 5 7",
"output": "-1"
},
{
"input": "3\n1 3 4",
"output": "-1"
},
{
"input": "3\n1 1 1",
... | 1,629,220,127 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 109 | 20,172,800 | n=int(input())
list1=[int(i) for i in input().split()]
dict1=[0]*8
for i in list1:
dict1[i]+=1
if dict1[1]==n//3 and dict1[2]+dict1[3]==n//3 and dict1[4]+dict1[6]==n//3:
print("1 2 4\n"*dict1[4] + "1 3 6\n"*dict1[3]+"1 2 6\n"*(dict1[6]-dict1[3]))
else:
print(-1)
| Title: Xenia and Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the mathematician has a sequence consisting of *n* (*n* is divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that for each group of three *a*,... | ```python
n=int(input())
list1=[int(i) for i in input().split()]
dict1=[0]*8
for i in list1:
dict1[i]+=1
if dict1[1]==n//3 and dict1[2]+dict1[3]==n//3 and dict1[4]+dict1[6]==n//3:
print("1 2 4\n"*dict1[4] + "1 3 6\n"*dict1[3]+"1 2 6\n"*(dict1[6]-dict1[3]))
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
113 | A | Grammar Lessons | PROGRAMMING | 1,600 | [
"implementation",
"strings"
] | A. Grammar Lessons | 5 | 256 | Petya got interested in grammar on his third year in school. He invented his own language called Petya's. Petya wanted to create a maximally simple language that would be enough to chat with friends, that's why all the language's grammar can be described with the following set of rules:
- There are three parts of spee... | The first line contains one or more words consisting of lowercase Latin letters. The overall number of characters (including letters and spaces) does not exceed 105.
It is guaranteed that any two consecutive words are separated by exactly one space and the input data do not contain any other spaces. It is possible tha... | If some word of the given text does not belong to the Petya's language or if the text contains more that one sentence, print "NO" (without the quotes). Otherwise, print "YES" (without the quotes). | [
"petr\n",
"etis atis animatis etis atis amatis\n",
"nataliala kataliala vetra feinites\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "petr",
"output": "YES"
},
{
"input": "etis atis animatis etis atis amatis",
"output": "NO"
},
{
"input": "nataliala kataliala vetra feinites",
"output": "YES"
},
{
"input": "qweasbvflios",
"output": "YES"
},
{
"input": "lios lios petr initis qwe",
... | 1,689,595,040 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | print("_RANDOM_GUESS_1689595040.439736")# 1689595040.4397554 | Title: Grammar Lessons
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya got interested in grammar on his third year in school. He invented his own language called Petya's. Petya wanted to create a maximally simple language that would be enough to chat with friends, that's why all the lang... | ```python
print("_RANDOM_GUESS_1689595040.439736")# 1689595040.4397554
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
168 | A | Wizards and Demonstration | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n*<=-<=*x* people) do not support the wizards and aren't going to go to the demonstration. We know that the city... | The first line contains three space-separated integers, *n*, *x*, *y* (1<=≤<=*n*,<=*x*,<=*y*<=≤<=104,<=*x*<=≤<=*n*) — the number of citizens in the city, the number of wizards and the percentage the administration needs, correspondingly.
Please note that *y* can exceed 100 percent, that is, the administration wants to... | Print a single integer — the answer to the problem, the minimum number of clones to create, so that the demonstration involved no less than *y* percent of *n* (the real total city population). | [
"10 1 14\n",
"20 10 50\n",
"1000 352 146\n"
] | [
"1\n",
"0\n",
"1108\n"
] | In the first sample it is necessary that at least 14% of 10 people came to the demonstration. As the number of people should be integer, then at least two people should come. There is only one wizard living in the city and he is going to come. That isn't enough, so he needs to create one clone.
In the second sample 1... | 500 | [
{
"input": "10 1 14",
"output": "1"
},
{
"input": "20 10 50",
"output": "0"
},
{
"input": "1000 352 146",
"output": "1108"
},
{
"input": "68 65 20",
"output": "0"
},
{
"input": "78 28 27",
"output": "0"
},
{
"input": "78 73 58",
"output": "0"
},
... | 1,600,597,121 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 216 | 0 | from math import ceil
n, x, y = map(int, input().split())
total = n*(y/100)
total = ceil(total)
print(total - x)
| Title: Wizards and Demonstration
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some country is populated by wizards. They want to organize a demonstration.
There are *n* people living in the city, *x* of them are the wizards who will surely go to the demonstration. Other city people (*n... | ```python
from math import ceil
n, x, y = map(int, input().split())
total = n*(y/100)
total = ceil(total)
print(total - x)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,562,357,478 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 109 | 307,200 | import sys
abn=input().split()
a=int(abn[0])
b=int(abn[1])
n=int(abn[2])
for i in range(10):
if (a*10+i)%b==0:
a=a*10+i
break
else:
print(-1)
sys.exit(0)
print(a,'0'*(n-1),sep="") | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
import sys
abn=input().split()
a=int(abn[0])
b=int(abn[1])
n=int(abn[2])
for i in range(10):
if (a*10+i)%b==0:
a=a*10+i
break
else:
print(-1)
sys.exit(0)
print(a,'0'*(n-1),sep="")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
559 | B | Equivalent Strings | PROGRAMMING | 1,700 | [
"divide and conquer",
"hashing",
"sortings",
"strings"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 1,000 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,648,340,530 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 22 | 280 | 1,433,600 |
def divideOrdena(string):
if len(string) == 1:
return string
a = divideOrdena(string[:len(string)//2])
b = divideOrdena(string[len(string)//2:])
if (a < b):
return a + b
else:
return b + a
if __name__ == '__main__':
a = input()
b = input()
if divideOrdena(a) ... | Title: Equivalent Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split str... | ```python
def divideOrdena(string):
if len(string) == 1:
return string
a = divideOrdena(string[:len(string)//2])
b = divideOrdena(string[len(string)//2:])
if (a < b):
return a + b
else:
return b + a
if __name__ == '__main__':
a = input()
b = input()
if divide... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
545 | C | Woodcutters | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described below.
There are *n* trees located along the road at points with coordinates *x*1,<=*x*2,<=...,<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of trees.
Next *n* lines contain pairs of integers *x**i*,<=*h**i* (1<=≤<=*x**i*,<=*h**i*<=≤<=109) — the coordinate and the height of the *і*-th tree.
The pairs are given in the order of ascending *x**i*. No two trees are located at the point with t... | Print a single number — the maximum number of trees that you can cut down by the given rules. | [
"5\n1 2\n2 1\n5 10\n10 9\n19 1\n",
"5\n1 2\n2 1\n5 10\n10 9\n20 1\n"
] | [
"3\n",
"4\n"
] | In the first sample you can fell the trees like that:
- fell the 1-st tree to the left — now it occupies segment [ - 1;1] - fell the 2-nd tree to the right — now it occupies segment [2;3] - leave the 3-rd tree — it occupies point 5 - leave the 4-th tree — it occupies point 10 - fell the 5-th tree to the right — ... | 1,750 | [
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n19 1",
"output": "3"
},
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n20 1",
"output": "4"
},
{
"input": "4\n10 4\n15 1\n19 3\n20 1",
"output": "4"
},
{
"input": "35\n1 7\n3 11\n6 12\n7 6\n8 5\n9 11\n15 3\n16 10\n22 2\n23 3\n25 7\n27 3\n34 5\n35 10... | 1,666,682,567 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n=int(input())
x1=[]
for i in range(n):
x=list(map(int,input().split()))
x1.append(x)
al=2
for i in range(1,len(x1)-1):
if x1[i][1]<=x1[i][0]-x1[i-1][0]-1:
al+=1
elif x1[i][1]<=x1[i+1][0]-x1[i][0]-1:
x1[i][0]+=x1[i][1]
print(al) | Title: Woodcutters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described b... | ```python
n=int(input())
x1=[]
for i in range(n):
x=list(map(int,input().split()))
x1.append(x)
al=2
for i in range(1,len(x1)-1):
if x1[i][1]<=x1[i][0]-x1[i-1][0]-1:
al+=1
elif x1[i][1]<=x1[i+1][0]-x1[i][0]-1:
x1[i][0]+=x1[i][1]
print(al)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
120 | A | Elevator | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through the front door, he goes out through the back one and vice versa. The elevator has two rails n... | The first line indicates the door through which the very important person entered the elevator. It contains "front" if the person enters the elevator through the front door and "back" if he entered the elevator through the back door. The second line contains integer *a* (1<=≤<=*a*<=≤<=2) which denotes the number of the... | Print character "R" if the VIP is right-handed or "L" if he is left-handed. | [
"front\n1\n"
] | [
"L\n"
] | none | 0 | [
{
"input": "front\n1",
"output": "L"
},
{
"input": "back\n1",
"output": "R"
},
{
"input": "front\n2",
"output": "R"
},
{
"input": "back\n2",
"output": "L"
}
] | 1,592,578,065 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 0 | s=input()
a=int(input())
if (s=='front' and a==1) or (s=='back' and a==2):
print('L')
elif (s=='front' and a==2) or (s=='back' and a==1):
print('R') | Title: Elevator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A sky scraper with 1000 floors has been built in the city of N. It has modern superfast elevators to help to travel from one floor to another. Each elevator has two doors, the front one and the back one. If one goes in through... | ```python
s=input()
a=int(input())
if (s=='front' and a==1) or (s=='back' and a==2):
print('L')
elif (s=='front' and a==2) or (s=='back' and a==1):
print('R')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
408 | B | Garland | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Once little Vasya read an article in a magazine on how to make beautiful handmade garland from colored paper. Vasya immediately went to the store and bought *n* colored sheets of paper, the area of each sheet is 1 square meter.
The garland must consist of exactly *m* pieces of colored paper of arbitrary area, each pie... | The first line contains a non-empty sequence of *n* (1<=≤<=*n*<=≤<=1000) small English letters ("a"..."z"). Each letter means that Vasya has a sheet of paper of the corresponding color.
The second line contains a non-empty sequence of *m* (1<=≤<=*m*<=≤<=1000) small English letters that correspond to the colors of the ... | Print an integer that is the maximum possible total area of the pieces of paper in the garland Vasya wants to get or -1, if it is impossible to make the garland from the sheets he's got. It is guaranteed that the answer is always an integer. | [
"aaabbac\naabbccac\n",
"a\nz\n"
] | [
"6\n",
"-1"
] | In the first test sample Vasya can make an garland of area 6: he can use both sheets of color *b*, three (but not four) sheets of color *a* and cut a single sheet of color *c* in three, for example, equal pieces. Vasya can use the resulting pieces to make a garland of area 6.
In the second test sample Vasya cannot mak... | 1,000 | [
{
"input": "aaabbac\naabbccac",
"output": "6"
},
{
"input": "a\nz",
"output": "-1"
},
{
"input": "r\nr",
"output": "1"
},
{
"input": "stnsdn\nndnndsn",
"output": "4"
},
{
"input": "yqfqfp\ntttwtqq",
"output": "-1"
},
{
"input": "zzbbrrtrtzr\ntbbtrrrzr"... | 1,553,325,412 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 124 | 409,600 | """
Oh, Grantors of Dark Disgrace,
Do Not Wake Me Again.
"""
si = lambda: input()
from collections import Counter
r = Counter(si())
g = Counter(si())
a = 0
for i in g.keys():
if r[i] - g[i] >= 0 and (g[i]!=0 and r[i]!=0):
a += g[i]
elif r[i] - g[i] < 0 and (g[i]!=0 and r[i]!=0):
a += 1
prin... | Title: Garland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once little Vasya read an article in a magazine on how to make beautiful handmade garland from colored paper. Vasya immediately went to the store and bought *n* colored sheets of paper, the area of each sheet is 1 square meter.... | ```python
"""
Oh, Grantors of Dark Disgrace,
Do Not Wake Me Again.
"""
si = lambda: input()
from collections import Counter
r = Counter(si())
g = Counter(si())
a = 0
for i in g.keys():
if r[i] - g[i] >= 0 and (g[i]!=0 and r[i]!=0):
a += g[i]
elif r[i] - g[i] < 0 and (g[i]!=0 and r[i]!=0):
a ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | E | 3-cycles | PROGRAMMING | 1,900 | [
"constructive algorithms",
"graphs",
"greedy"
] | E. 3-cycles | 2 | 256 | During a recent research Berland scientists found out that there were *n* cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a well-known tradition, the road network was built so that it would be impossible to choose thr... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of cities in Berland. | On the first line must be printed number *m* — the maximal number of roads in Berland. Then print *m* lines containing two numbers each — the numbers of cities that the given road joins. The cities are numbered with integers from 1 to *n*. If there are several variants of solving the problem, print any of them. | [
"3\n",
"4\n"
] | [
"2\n1 2\n2 3\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | none | 2,500 | [
{
"input": "3",
"output": "2\n1 2\n1 3"
},
{
"input": "4",
"output": "4\n1 3\n1 4\n2 3\n2 4"
},
{
"input": "5",
"output": "6\n1 3\n1 4\n1 5\n2 3\n2 4\n2 5"
},
{
"input": "6",
"output": "9\n1 4\n1 5\n1 6\n2 4\n2 5\n2 6\n3 4\n3 5\n3 6"
},
{
"input": "7",
"output... | 1,542,100,863 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 248 | 409,600 | p = int(input())
print( ( p // 2 ) ** 2 + ( p // 2) * ( p % 2 ) )
for i in range(p//2):
for j in range(p//2, p):
print(i+1, j+1) | Title: 3-cycles
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
During a recent research Berland scientists found out that there were *n* cities in Ancient Berland, joined by two-way paths. Any two cities are joined by no more than one path. No path joins a city with itself. According to a wel... | ```python
p = int(input())
print( ( p // 2 ) ** 2 + ( p // 2) * ( p % 2 ) )
for i in range(p//2):
for j in range(p//2, p):
print(i+1, j+1)
``` | 3.937237 | MatrixStudio/Codeforces-Python-Submissions |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,668,465,110 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 124 | 0 | import math
m, n = [int(i) for i in input().split()]
print(math.floor(m*n / 2)) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
import math
m, n = [int(i) for i in input().split()]
print(math.floor(m*n / 2))
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
8 | D | Two Friends | PROGRAMMING | 2,600 | [
"binary search",
"geometry"
] | D. Two Friends | 1 | 64 | Two neighbours, Alan and Bob, live in the city, where there are three buildings only: a cinema, a shop and the house, where they live. The rest is a big asphalt square.
Once they went to the cinema, and the film impressed them so deeply, that when they left the cinema, they did not want to stop discussing it.
Bob wa... | The first line contains two integers: *t*1,<=*t*2 (0<=≤<=*t*1,<=*t*2<=≤<=100). The second line contains the cinema's coordinates, the third one — the house's, and the last line — the shop's.
All the coordinates are given in meters, are integer, and do not exceed 100 in absolute magnitude. No two given places are in t... | In the only line output one number — the maximum distance that Alan and Bob will cover together, discussing the film. Output the answer accurate to not less than 4 decimal places. | [
"0 2\n0 0\n4 0\n-3 0\n",
"0 0\n0 0\n2 0\n1 0\n"
] | [
"1.0000000000\n",
"2.0000000000\n"
] | none | 0 | [
{
"input": "0 2\n0 0\n4 0\n-3 0",
"output": "1.0000000000"
},
{
"input": "0 0\n0 0\n2 0\n1 0",
"output": "2.0000000000"
},
{
"input": "0 2\n0 0\n40 0\n-31 1",
"output": "1.0002538218"
},
{
"input": "100 2\n0 0\n4 0\n-3 0",
"output": "6.0000000000"
},
{
"input": "2... | 1,572,784,656 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import math
import com
ZERO = 1E-10
def getfloats():
return map(float, input().split())
def inter(complex(A+rA), complex(B+rB)):
u = B - A
l = abs(u)
if abs(rA - rB) - ZERO >= l:
return 1
p = (l * l + rA * rA - rB * rB) / (2 * l)
q = rA * rA - p * p
if q < 0:
... | Title: Two Friends
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Two neighbours, Alan and Bob, live in the city, where there are three buildings only: a cinema, a shop and the house, where they live. The rest is a big asphalt square.
Once they went to the cinema, and the film impressed them... | ```python
import math
import com
ZERO = 1E-10
def getfloats():
return map(float, input().split())
def inter(complex(A+rA), complex(B+rB)):
u = B - A
l = abs(u)
if abs(rA - rB) - ZERO >= l:
return 1
p = (l * l + rA * rA - rB * rB) / (2 * l)
q = rA * rA - p * p
if q... | -1 | MatrixStudio/Codeforces-Python-Submissions |
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