contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,617,522,894 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 154 | 0 | from sys import stdin, stdout
m, n = [int(i) for i in stdin.readline().split()]
stdout.write(str(m*n // 2)) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
from sys import stdin, stdout
m, n = [int(i) for i in stdin.readline().split()]
stdout.write(str(m*n // 2))
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,676,645,914 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 11 | 62 | 2,150,400 | n, t = [int(x) for x in input().split()]
ten = 1* (10**(n-1))
if t != 10:
result = ten * t
elif t == 10 and n < 2:
result = -1
print(result) | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n, t = [int(x) for x in input().split()]
ten = 1* (10**(n-1))
if t != 10:
result = ten * t
elif t == 10 and n < 2:
result = -1
print(result)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
52 | A | 123-sequence | PROGRAMMING | 900 | [
"implementation"
] | A. 123-sequence | 2 | 256 | There is a given sequence of integers *a*1,<=*a*2,<=...,<=*a**n*, where every number is from 1 to 3 inclusively. You have to replace the minimum number of numbers in it so that all the numbers in the sequence are equal to each other. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106). The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3). | Print the minimum number of replacements needed to be performed to make all the numbers in the sequence equal. | [
"9\n1 3 2 2 2 1 1 2 3\n"
] | [
"5\n"
] | In the example all the numbers equal to 1 and 3 should be replaced by 2. | 500 | [
{
"input": "9\n1 3 2 2 2 1 1 2 3",
"output": "5"
},
{
"input": "6\n3 3 2 2 1 3",
"output": "3"
},
{
"input": "12\n3 1 3 1 2 1 3 2 2 1 2 1",
"output": "7"
},
{
"input": "15\n3 2 1 1 1 1 3 2 2 3 3 1 2 3 2",
"output": "10"
},
{
"input": "2\n2 1",
"output": "1"
... | 1,642,085,729 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 1,152 | 14,438,400 | n = int(input())
cont = [int(item) for item in input().split(' ')]
count1, count2, count3 = 0, 0, 0
for i in range(n):
if cont[i] == 1:
count1 += 1
elif cont[i] == 2:
count2 += 1
else:
count3 += 1
temp = max(count1,count2,count3)
print(count1+count2+count3-temp)
| Title: 123-sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a given sequence of integers *a*1,<=*a*2,<=...,<=*a**n*, where every number is from 1 to 3 inclusively. You have to replace the minimum number of numbers in it so that all the numbers in the sequence are equal to each... | ```python
n = int(input())
cont = [int(item) for item in input().split(' ')]
count1, count2, count3 = 0, 0, 0
for i in range(n):
if cont[i] == 1:
count1 += 1
elif cont[i] == 2:
count2 += 1
else:
count3 += 1
temp = max(count1,count2,count3)
print(count1+count2+count3-te... | 3.685106 | MatrixStudio/Codeforces-Python-Submissions |
919 | D | Substring | PROGRAMMING | 1,700 | [
"dfs and similar",
"dp",
"graphs"
] | null | null | You are given a graph with $n$ nodes and $m$ directed edges. One lowercase letter is assigned to each node. We define a path's value as the number of the most frequently occurring letter. For example, if letters on a path are "abaca", then the value of that path is $3$. Your task is find a path whose value is the large... | The first line contains two positive integers $n, m$ ($1 \leq n, m \leq 300\,000$), denoting that the graph has $n$ nodes and $m$ directed edges.
The second line contains a string $s$ with only lowercase English letters. The $i$-th character is the letter assigned to the $i$-th node.
Then $m$ lines follow. Each line ... | Output a single line with a single integer denoting the largest value. If the value can be arbitrarily large, output -1 instead. | [
"5 4\nabaca\n1 2\n1 3\n3 4\n4 5\n",
"6 6\nxzyabc\n1 2\n3 1\n2 3\n5 4\n4 3\n6 4\n",
"10 14\nxzyzyzyzqx\n1 2\n2 4\n3 5\n4 5\n2 6\n6 8\n6 5\n2 10\n3 9\n10 9\n4 6\n1 10\n2 8\n3 7\n"
] | [
"3\n",
"-1\n",
"4\n"
] | In the first sample, the path with largest value is $1 \to 3 \to 4 \to 5$. The value is $3$ because the letter 'a' appears $3$ times. | 1,500 | [
{
"input": "5 4\nabaca\n1 2\n1 3\n3 4\n4 5",
"output": "3"
},
{
"input": "6 6\nxzyabc\n1 2\n3 1\n2 3\n5 4\n4 3\n6 4",
"output": "-1"
},
{
"input": "10 14\nxzyzyzyzqx\n1 2\n2 4\n3 5\n4 5\n2 6\n6 8\n6 5\n2 10\n3 9\n10 9\n4 6\n1 10\n2 8\n3 7",
"output": "4"
},
{
"input": "1 1\nf... | 1,672,843,292 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | Copy code
class Graph:
def __init__(self, nodes, edges):
self.nodes = nodes
self.edges = edges
class Edge:
def __init__(self, start, end, weight):
self.start = start
self.end = end
self.weight = weight
def longest_path(graph, start_node):
# Initialize distances to all nodes as i... | Title: Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a graph with $n$ nodes and $m$ directed edges. One lowercase letter is assigned to each node. We define a path's value as the number of the most frequently occurring letter. For example, if letters on a path are... | ```python
Copy code
class Graph:
def __init__(self, nodes, edges):
self.nodes = nodes
self.edges = edges
class Edge:
def __init__(self, start, end, weight):
self.start = start
self.end = end
self.weight = weight
def longest_path(graph, start_node):
# Initialize distances to all ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,647,636,360 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 92 | 0 | n=int(input())
names={}
scores=[]
primeiro=0
max=0
for i in range(n):
entrada=input().split()
name=entrada[0]
score=int(entrada[1])
j=0
if not name in names:
names[name]=score
scores.append(name)
j=len(scores)-2
else:
names[name]+=score
score=names[name]
... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n=int(input())
names={}
scores=[]
primeiro=0
max=0
for i in range(n):
entrada=input().split()
name=entrada[0]
score=int(entrada[1])
j=0
if not name in names:
names[name]=score
scores.append(name)
j=len(scores)-2
else:
names[name]+=score
score=nam... | 0 | MatrixStudio/Codeforces-Python-Submissions |
630 | D | Hexagons! | PROGRAMMING | 1,100 | [
"math"
] | null | null | After a probationary period in the game development company of IT City Petya was included in a group of the programmers that develops a new turn-based strategy game resembling the well known "Heroes of Might & Magic". A part of the game is turn-based fights of big squadrons of enemies on infinite fields where every... | The only line of the input contains one integer *n* (0<=≤<=*n*<=≤<=109). | Output one integer — the number of hexagons situated not farther than *n* cells away from a given cell. | [
"2\n"
] | [
"19"
] | none | 0 | [
{
"input": "2",
"output": "19"
},
{
"input": "0",
"output": "1"
},
{
"input": "1",
"output": "7"
},
{
"input": "3",
"output": "37"
},
{
"input": "749431",
"output": "1684942719577"
},
{
"input": "748629743",
"output": "1681339478558627377"
},
{... | 1,689,451,276 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print("_RANDOM_GUESS_1689451276.5784853")# 1689451276.5785048 | Title: Hexagons!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a probationary period in the game development company of IT City Petya was included in a group of the programmers that develops a new turn-based strategy game resembling the well known "Heroes of Might & Magic". A p... | ```python
print("_RANDOM_GUESS_1689451276.5784853")# 1689451276.5785048
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
631 | B | Print Check | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Kris works in a large company "Blake Technologies". As a best engineer of the company he was assigned a task to develop a printer that will be able to print horizontal and vertical strips. First prototype is already built and Kris wants to tests it. He wants you to implement the program that checks the result of the pr... | The first line of the input contains three integers *n*, *m* and *k* (1<=<=≤<=<=*n*,<=<=*m*<=<=≤<=5000, *n*·*m*<=≤<=100<=000, 1<=≤<=*k*<=≤<=100<=000) — the dimensions of the sheet and the number of operations, respectively.
Each of the next *k* lines contains the description of exactly one query:
- 1 *r**i* *a**i* ... | Print *n* lines containing *m* integers each — the resulting table after all operations are applied. | [
"3 3 3\n1 1 3\n2 2 1\n1 2 2\n",
"5 3 5\n1 1 1\n1 3 1\n1 5 1\n2 1 1\n2 3 1\n"
] | [
"3 1 3 \n2 2 2 \n0 1 0 \n",
"1 1 1 \n1 0 1 \n1 1 1 \n1 0 1 \n1 1 1 \n"
] | The figure below shows all three operations for the first sample step by step. The cells that were painted on the corresponding step are marked gray. | 1,000 | [
{
"input": "3 3 3\n1 1 3\n2 2 1\n1 2 2",
"output": "3 1 3 \n2 2 2 \n0 1 0 "
},
{
"input": "5 3 5\n1 1 1\n1 3 1\n1 5 1\n2 1 1\n2 3 1",
"output": "1 1 1 \n1 0 1 \n1 1 1 \n1 0 1 \n1 1 1 "
},
{
"input": "5 5 4\n1 2 1\n1 4 1\n2 2 1\n2 4 1",
"output": "0 1 0 1 0 \n1 1 1 1 1 \n0 1 0 1 0 \n1... | 1,484,680,063 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <stdio.h>
int main()
{
long int n,m,k,a,b,i,j;
long long int c;
scanf("%ld %ld %ld",&n,&m,&k);
long long int A[n+1][m+1];
for(i=1;i<=n;i++)
{
for(j=1;j<=m;j++)
{
A[i][j]=0;
}
}
while(k--)
{
scanf("%ld %ld %lld",&a,&b,&c);
if(a==1)
{
for(j=1;j<=m;j++)
if(A[... | Title: Print Check
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kris works in a large company "Blake Technologies". As a best engineer of the company he was assigned a task to develop a printer that will be able to print horizontal and vertical strips. First prototype is already built a... | ```python
#include <stdio.h>
int main()
{
long int n,m,k,a,b,i,j;
long long int c;
scanf("%ld %ld %ld",&n,&m,&k);
long long int A[n+1][m+1];
for(i=1;i<=n;i++)
{
for(j=1;j<=m;j++)
{
A[i][j]=0;
}
}
while(k--)
{
scanf("%ld %ld %lld",&a,&b,&c);
if(a==1)
{
for(j=1;j<=m;j++)... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
900 | B | Position in Fraction | PROGRAMMING | 1,300 | [
"math",
"number theory"
] | null | null | You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point. | The first contains three single positive integers *a*, *b*, *c* (1<=≤<=*a*<=<<=*b*<=≤<=105, 0<=≤<=*c*<=≤<=9). | Print position of the first occurrence of digit *c* into the fraction. Positions are numbered from 1 after decimal point. It there is no such position, print -1. | [
"1 2 0\n",
"2 3 7\n"
] | [
"2",
"-1"
] | The fraction in the first example has the following decimal notation: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/896357459a466614a0542f34c9cfb0cef1afc9ed.png" style="max-width: 100.0%;max-height: 100.0%;"/>. The first zero stands on second position.
The fraction in the second example ... | 1,000 | [
{
"input": "1 2 0",
"output": "2"
},
{
"input": "2 3 7",
"output": "-1"
},
{
"input": "1 100000 1",
"output": "5"
},
{
"input": "1 7 7",
"output": "6"
},
{
"input": "99999 100000 8",
"output": "-1"
},
{
"input": "44102 73848 2",
"output": "132"
}... | 1,516,388,541 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 5,632,000 | a,b,c=map(int,input().split())
a=(a%b)
count=0
l=0
m=0
n=0
k=0
while True:
n=k
a*=10
k=a//b
a=(a%b)
count+=1
if k==c:
l+=1
print(count)
break
if a==0 and c!=0 :
m+=1
break
if n==k and c==k:
print(count-1)
break... | Title: Position in Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point.
Input Specification:
The first contains three single positive integers *a*, *b*, ... | ```python
a,b,c=map(int,input().split())
a=(a%b)
count=0
l=0
m=0
n=0
k=0
while True:
n=k
a*=10
k=a//b
a=(a%b)
count+=1
if k==c:
l+=1
print(count)
break
if a==0 and c!=0 :
m+=1
break
if n==k and c==k:
print(count-1)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
994 | B | Knights of a Polygonal Table | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings"
] | null | null | Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power is greater than the power of victim. However, even such a knight will torment his conscience, so he can kill no mo... | The first line contains two integers $n$ and $k$ $(1 \le n \le 10^5, 0 \le k \le \min(n-1,10))$ — the number of knights and the number $k$ from the statement.
The second line contains $n$ integers $p_1, p_2 ,\ldots,p_n$ $(1 \le p_i \le 10^9)$ — powers of the knights. All $p_i$ are distinct.
The third line contains $n... | Print $n$ integers — the maximum number of coins each knight can have it only he kills other knights. | [
"4 2\n4 5 9 7\n1 2 11 33\n",
"5 1\n1 2 3 4 5\n1 2 3 4 5\n",
"1 0\n2\n3\n"
] | [
"1 3 46 36 ",
"1 3 5 7 9 ",
"3 "
] | Consider the first example.
- The first knight is the weakest, so he can't kill anyone. That leaves him with the only coin he initially has. - The second knight can kill the first knight and add his coin to his own two. - The third knight is the strongest, but he can't kill more than $k = 2$ other knights. It is o... | 1,000 | [
{
"input": "4 2\n4 5 9 7\n1 2 11 33",
"output": "1 3 46 36 "
},
{
"input": "5 1\n1 2 3 4 5\n1 2 3 4 5",
"output": "1 3 5 7 9 "
},
{
"input": "1 0\n2\n3",
"output": "3 "
},
{
"input": "7 1\n2 3 4 5 7 8 9\n0 3 7 9 5 8 9",
"output": "0 3 10 16 14 17 18 "
},
{
"input"... | 1,529,227,705 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 77 | 0 | from heapq import heappushpop
n, k = map(int, input().split())
pp = list(map(int, input().split()))
idx = sorted(range(n), key=pp.__getitem__)
cc = list(map(int, input().split()))
r, h, s = [0] * n, [0] * (k + 1), 0
for i in idx:
c = cc[i]
s += c - heappushpop(h, c)
r[i] = s
print(' '.join(map(str, r))) | Title: Knights of a Polygonal Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power ... | ```python
from heapq import heappushpop
n, k = map(int, input().split())
pp = list(map(int, input().split()))
idx = sorted(range(n), key=pp.__getitem__)
cc = list(map(int, input().split()))
r, h, s = [0] * n, [0] * (k + 1), 0
for i in idx:
c = cc[i]
s += c - heappushpop(h, c)
r[i] = s
print(' '.join(map(st... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,652,873,963 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 77 | 18,841,600 | n,k=map(int,input().split())
y=list(map(int,input().split()))
p=5-k
count=0
for i in range(p+1):
count+=y.count(i)
print(int(count/3)) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
n,k=map(int,input().split())
y=list(map(int,input().split()))
p=5-k
count=0
for i in range(p+1):
count+=y.count(i)
print(int(count/3))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,697,002,498 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 2,000 | 79,462,400 | '''程文奇 2100015898'''
def Tprime(x,tprimeset):
if x in tprimeset:
return 'YES'
return 'NO'
n=int(input())
biglist=[1]*1000000
tprimeset=set()
for i in range(2,1000000):
if biglist[i]==1:
tprimeset.add(i**2)
for j in range(i**2,n,i):
biglist[j]=0
answerlist... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
'''程文奇 2100015898'''
def Tprime(x,tprimeset):
if x in tprimeset:
return 'YES'
return 'NO'
n=int(input())
biglist=[1]*1000000
tprimeset=set()
for i in range(2,1000000):
if biglist[i]==1:
tprimeset.add(i**2)
for j in range(i**2,n,i):
biglist[j]=0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and... | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, ... | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer ... | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,446,769,813 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | from sys import stdin, stdout
l = int(raw_input())
speed1 = int(raw_input())
speed2 = int(raw_input())
stdout.write(str(float(l*speed1)/float(speed1+speed2))+"\n")
| Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the en... | ```python
from sys import stdin, stdout
l = int(raw_input())
speed1 = int(raw_input())
speed2 = int(raw_input())
stdout.write(str(float(l*speed1)/float(speed1+speed2))+"\n")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
355 | A | Vasya and Digital Root | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<... | The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9). | In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes. | [
"4 4\n",
"5 1\n",
"1 0\n"
] | [
"5881\n",
"36172\n",
"0\n"
] | For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | 500 | [
{
"input": "4 4",
"output": "5881"
},
{
"input": "5 1",
"output": "36172"
},
{
"input": "1 0",
"output": "0"
},
{
"input": "8 7",
"output": "49722154"
},
{
"input": "487 0",
"output": "No solution"
},
{
"input": "1000 5",
"output": "854193955406789... | 1,621,358,140 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 61 | 0 | k,d = list(map(int,input().split()))
if d == 0 and k!=1:
print("No Solution")
else:
print(int(str(d)+'0'*(k-1))) | Title: Vasya and Digital Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=... | ```python
k,d = list(map(int,input().split()))
if d == 0 and k!=1:
print("No Solution")
else:
print(int(str(d)+'0'*(k-1)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
48 | A | Rock-paper-scissors | PROGRAMMING | 900 | [
"implementation",
"schedules"
] | A. Rock-paper-scissors | 2 | 256 | Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obvio... | The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture. | Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?". | [
"rock\nrock\nrock\n",
"paper\nrock\nrock\n",
"scissors\nrock\nrock\n",
"scissors\npaper\nrock\n"
] | [
"?\n",
"F\n",
"?\n",
"?\n"
] | none | 0 | [
{
"input": "rock\nrock\nrock",
"output": "?"
},
{
"input": "paper\nrock\nrock",
"output": "F"
},
{
"input": "scissors\nrock\nrock",
"output": "?"
},
{
"input": "scissors\npaper\nrock",
"output": "?"
},
{
"input": "paper\npaper\nrock",
"output": "?"
},
{
... | 1,649,095,877 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | def winner(s1, s2):
r, p, s = 'rock', 'paper', 'scissors'
if s1 == r and s2 == s or s1 == p and s2 == r or s1 == s and s2 == p:
return True
def win(s1, s2, s3):
if s1 != s2 and s1 != s3 and s2 == s3:
return True
f, m, s = input(), input(), input()
if win(f, m, s) and winn... | Title: Rock-paper-scissors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case ... | ```python
def winner(s1, s2):
r, p, s = 'rock', 'paper', 'scissors'
if s1 == r and s2 == s or s1 == p and s2 == r or s1 == s and s2 == p:
return True
def win(s1, s2, s3):
if s1 != s2 and s1 != s3 and s2 == s3:
return True
f, m, s = input(), input(), input()
if win(f, m, s... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,620,289,628 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 124 | 6,758,400 | import math
s1,s2,s3 = [*map(int,input().split())]
a = math.sqrt(s1 * s2 / s3)
b = math.sqrt(s3*s1/s2)
c = math.sqrt(s2*s3/s1)
print(int((a+b+c)*4)) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
import math
s1,s2,s3 = [*map(int,input().split())]
a = math.sqrt(s1 * s2 / s3)
b = math.sqrt(s3*s1/s2)
c = math.sqrt(s2*s3/s1)
print(int((a+b+c)*4))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,699,885,151 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 | total = 0
n, h = map(int, input().split())
mans = [int(x) for x in input().split()]
for i in range(n):
if mans[i] <= h:
total += 1
else:
total += 2
print(total) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
total = 0
n, h = map(int, input().split())
mans = [int(x) for x in input().split()]
for i in range(n):
if mans[i] <= h:
total += 1
else:
total += 2
print(total)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
8 | B | Obsession with Robots | PROGRAMMING | 1,400 | [
"constructive algorithms",
"graphs",
"implementation"
] | B. Obsession with Robots | 2 | 64 | The whole world got obsessed with robots,and to keep pace with the progress, great Berland's programmer Draude decided to build his own robot. He was working hard at the robot. He taught it to walk the shortest path from one point to another, to record all its movements, but like in many Draude's programs, there was a ... | The first line of the input file contains the recording of the robot's movements. This recording is a non-empty string, consisting of uppercase Latin letters L, R, U and D, standing for movements left, right, up and down respectively. The length of the string does not exceed 100. | In the first line output the only word OK (if the above described map exists), or BUG (if such a map does not exist). | [
"LLUUUR\n",
"RRUULLDD\n"
] | [
"OK\n",
"BUG\n"
] | none | 0 | [
{
"input": "LLUUUR",
"output": "OK"
},
{
"input": "RRUULLDD",
"output": "BUG"
},
{
"input": "L",
"output": "OK"
},
{
"input": "R",
"output": "OK"
},
{
"input": "R",
"output": "OK"
},
{
"input": "RR",
"output": "OK"
},
{
"input": "DL",
"... | 1,587,940,525 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 248 | 307,200 | def main():
#get the input string
path = input()
#initialise coordinates with 0
coordinate = [[0 for i in range(2)] for j in range(len(path)+1)]
#here we will store the number of moves left, right, up and down
left = 0
right = 0
up = 0
down = 0
#get the number of moves
for direction in... | Title: Obsession with Robots
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
The whole world got obsessed with robots,and to keep pace with the progress, great Berland's programmer Draude decided to build his own robot. He was working hard at the robot. He taught it to walk the shortest path fr... | ```python
def main():
#get the input string
path = input()
#initialise coordinates with 0
coordinate = [[0 for i in range(2)] for j in range(len(path)+1)]
#here we will store the number of moves left, right, up and down
left = 0
right = 0
up = 0
down = 0
#get the number of moves
for di... | 3.935711 | MatrixStudio/Codeforces-Python-Submissions |
797 | A | k-Factorization | PROGRAMMING | 1,100 | [
"implementation",
"math",
"number theory"
] | null | null | Given a positive integer *n*, find *k* integers (not necessary distinct) such that all these integers are strictly greater than 1, and their product is equal to *n*. | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100000, 1<=≤<=*k*<=≤<=20). | If it's impossible to find the representation of *n* as a product of *k* numbers, print -1.
Otherwise, print *k* integers in any order. Their product must be equal to *n*. If there are multiple answers, print any of them. | [
"100000 2\n",
"100000 20\n",
"1024 5\n"
] | [
"2 50000 \n",
"-1\n",
"2 64 2 2 2 \n"
] | none | 0 | [
{
"input": "100000 2",
"output": "2 50000 "
},
{
"input": "100000 20",
"output": "-1"
},
{
"input": "1024 5",
"output": "2 64 2 2 2 "
},
{
"input": "100000 10",
"output": "2 2 2 2 2 5 5 5 5 5 "
},
{
"input": "99999 3",
"output": "3 813 41 "
},
{
"input... | 1,627,454,560 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 109 | 20,172,800 | n, k = map(int, input().split())
arr = []
og = n
i = 2
while i*i <= n:
while n % i == 0:
arr.append(i)
n = n//i
i += 1
if len(arr) >= k-1:
temp = arr[:k-1]
this = 1
for i in temp:
this *= i
print(*arr[:k-1], og//this)
else:
print(-1)
| Title: k-Factorization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Given a positive integer *n*, find *k* integers (not necessary distinct) such that all these integers are strictly greater than 1, and their product is equal to *n*.
Input Specification:
The first line contains two int... | ```python
n, k = map(int, input().split())
arr = []
og = n
i = 2
while i*i <= n:
while n % i == 0:
arr.append(i)
n = n//i
i += 1
if len(arr) >= k-1:
temp = arr[:k-1]
this = 1
for i in temp:
this *= i
print(*arr[:k-1], og//this)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
831 | C | Jury Marks | PROGRAMMING | 1,700 | [
"brute force",
"constructive algorithms"
] | null | null | Polycarp watched TV-show where *k* jury members one by one rated a participant by adding him a certain number of points (may be negative, i. e. points were subtracted). Initially the participant had some score, and each the marks were one by one added to his score. It is known that the *i*-th jury member gave *a**i* po... | The first line contains two integers *k* and *n* (1<=≤<=*n*<=≤<=*k*<=≤<=2<=000) — the number of jury members and the number of scores Polycarp remembers.
The second line contains *k* integers *a*1,<=*a*2,<=...,<=*a**k* (<=-<=2<=000<=≤<=*a**i*<=≤<=2<=000) — jury's marks in chronological order.
The third line contains ... | Print the number of options for the score the participant could have before the judges rated the participant. If Polycarp messes something up and there is no options, print "0" (without quotes). | [
"4 1\n-5 5 0 20\n10\n",
"2 2\n-2000 -2000\n3998000 4000000\n"
] | [
"3\n",
"1\n"
] | The answer for the first example is 3 because initially the participant could have - 10, 10 or 15 points.
In the second example there is only one correct initial score equaling to 4 002 000. | 1,000 | [
{
"input": "4 1\n-5 5 0 20\n10",
"output": "3"
},
{
"input": "2 2\n-2000 -2000\n3998000 4000000",
"output": "1"
},
{
"input": "1 1\n-577\n1273042",
"output": "1"
},
{
"input": "2 1\n614 -1943\n3874445",
"output": "2"
},
{
"input": "3 1\n1416 -1483 1844\n3261895",
... | 1,667,050,991 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 46 | 0 | import sys
input = sys.stdin.readline
k, n = map(int,input().split())
a = list(map(int,input().split()))
b = set(map(int,input().split()))
cumSum = [a[0]]
for i in range(1,k):
cumSum.append(cumSum[i-1]+a[i])
result = 0
second = set()
temp = 0
for i in b:
for j in range(k-1,-1,-1):
i... | Title: Jury Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp watched TV-show where *k* jury members one by one rated a participant by adding him a certain number of points (may be negative, i. e. points were subtracted). Initially the participant had some score, and each the ... | ```python
import sys
input = sys.stdin.readline
k, n = map(int,input().split())
a = list(map(int,input().split()))
b = set(map(int,input().split()))
cumSum = [a[0]]
for i in range(1,k):
cumSum.append(cumSum[i-1]+a[i])
result = 0
second = set()
temp = 0
for i in b:
for j in range(k-1,-1,-1):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
805 | A | Fake NP | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | null | null | Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of their integer divisors except 1. Find the integer that we wrote down the maximum number of times... | The first line contains two integers *l* and *r* (2<=≤<=*l*<=≤<=*r*<=≤<=109). | Print single integer, the integer that appears maximum number of times in the divisors.
If there are multiple answers, print any of them. | [
"19 29\n",
"3 6\n"
] | [
"2\n",
"3\n"
] | Definition of a divisor: [https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html](https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html)
The first example: from 19 to 29 these numbers are divisible by 2: {20, 22, 24, 26, 28}.
The second example: from 3 to 6 these numbers are divisible by 3: {... | 500 | [
{
"input": "19 29",
"output": "2"
},
{
"input": "3 6",
"output": "2"
},
{
"input": "39 91",
"output": "2"
},
{
"input": "76 134",
"output": "2"
},
{
"input": "93 95",
"output": "2"
},
{
"input": "17 35",
"output": "2"
},
{
"input": "94 95",... | 1,575,174,384 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 109 | 0 | a,b=map(int,input().split())
if (a%3==0 and b%3==0 and b-a==3):
print(3)
elif a%3==0 and (b-1)%3==0 and (b%2!=0):
print(3)
else:
print(2) | Title: Fake NP
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of the... | ```python
a,b=map(int,input().split())
if (a%3==0 and b%3==0 and b-a==3):
print(3)
elif a%3==0 and (b-1)%3==0 and (b%2!=0):
print(3)
else:
print(2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
757 | A | Gotta Catch Em' All! | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsession. Since he is too young to go out and catch Bulbasaur, he came up with his own way of catching a Bulbas... | Input contains a single line containing a string *s* (1<=<=≤<=<=|*s*|<=<=≤<=<=105) — the text on the front page of the newspaper without spaces and punctuation marks. |*s*| is the length of the string *s*.
The string *s* contains lowercase and uppercase English letters, i.e. . | Output a single integer, the answer to the problem. | [
"Bulbbasaur\n",
"F\n",
"aBddulbasaurrgndgbualdBdsagaurrgndbb\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first case, you could pick: Bulbbasaur.
In the second case, there is no way to pick even a single Bulbasaur.
In the third case, you can rearrange the string to BulbasaurBulbasauraddrgndgddgargndbb to get two words "Bulbasaur". | 500 | [
{
"input": "Bulbbasaur",
"output": "1"
},
{
"input": "F",
"output": "0"
},
{
"input": "aBddulbasaurrgndgbualdBdsagaurrgndbb",
"output": "2"
},
{
"input": "BBBBBBBBBBbbbbbbbbbbuuuuuuuuuullllllllllssssssssssaaaaaaaaaarrrrrrrrrr",
"output": "5"
},
{
"input": "BBBBBBB... | 1,484,397,503 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 21 | 62 | 4,710,400 | bulba = input()
zavr = [0]*8
zavr[0]=bulba.count('B')
zavr[1]=bulba.count('u')
zavr[2]=bulba.count('l')
zavr[3]=bulba.count('b')
zavr[4]=bulba.count('a')//2
zavr[5]=bulba.count('s')
zavr[6]=bulba.count('u')
zavr[7]=bulba.count('r')
print(min(zavr))
| Title: Gotta Catch Em' All!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsess... | ```python
bulba = input()
zavr = [0]*8
zavr[0]=bulba.count('B')
zavr[1]=bulba.count('u')
zavr[2]=bulba.count('l')
zavr[3]=bulba.count('b')
zavr[4]=bulba.count('a')//2
zavr[5]=bulba.count('s')
zavr[6]=bulba.count('u')
zavr[7]=bulba.count('r')
print(min(zavr))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,696,606,704 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 92 | 0 | number_of_contests = int(input())
scores = input().split()
scores = [int(score) for score in scores]
best_performance, worst_performance, i, amazing_performance = scores[0], scores[0], 1, 0
while i < number_of_contests:
if scores[i] > best_performance:
amazing_performance += 1
best_performanc... | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
number_of_contests = int(input())
scores = input().split()
scores = [int(score) for score in scores]
best_performance, worst_performance, i, amazing_performance = scores[0], scores[0], 1, 0
while i < number_of_contests:
if scores[i] > best_performance:
amazing_performance += 1
best_... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,670,583,740 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | red,blue = map(int,input().strip().split())
pairSocks = min(red,blue)
singleSocks = max(red,blue)
total = singleSocks - pairSocks
print(pairSocks,(total//2)) | Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
red,blue = map(int,input().strip().split())
pairSocks = min(red,blue)
singleSocks = max(red,blue)
total = singleSocks - pairSocks
print(pairSocks,(total//2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,685,103,401 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 0 | # https://codeforces.com/problemset/problem/785/A
figures_num = int(input())
total_num_faces = 0
for figure in range(figures_num):
name = input()
# to be continued
if name == 'Tetrahedron':
total_num_faces += 4
elif name == 'Cube':
total_num_faces += 6
elif name == 'Oct... | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
# https://codeforces.com/problemset/problem/785/A
figures_num = int(input())
total_num_faces = 0
for figure in range(figures_num):
name = input()
# to be continued
if name == 'Tetrahedron':
total_num_faces += 4
elif name == 'Cube':
total_num_faces += 6
elif na... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the numb... | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,689,671,373 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 592 | 9,318,400 | n = int(input())
alex = False
for i in range(n):
a, b = map(int, input().split())
if a < b:
alex = True
if alex:
print("Happy Alex")
else:
print("Poor Alex") | Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the... | ```python
n = int(input())
alex = False
for i in range(n):
a, b = map(int, input().split())
if a < b:
alex = True
if alex:
print("Happy Alex")
else:
print("Poor Alex")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
295 | B | Greg and Graph | PROGRAMMING | 1,700 | [
"dp",
"graphs",
"shortest paths"
] | null | null | Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game:
- The game consists of *n* steps. - On the *i*-th step Greg removes vertex number *x**i* from t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=500) — the number of vertices in the graph.
Next *n* lines contain *n* integers each — the graph adjacency matrix: the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*a**ij*<=≤<=105,<=*a**ii*<==<=0) represents the weight of the edge that goes from vertex *i* to verte... | Print *n* integers — the *i*-th number equals the required sum before the *i*-th step.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams of the %I64d specifier. | [
"1\n0\n1\n",
"2\n0 5\n4 0\n1 2\n",
"4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3\n"
] | [
"0 ",
"9 0 ",
"17 23 404 0 "
] | none | 1,000 | [
{
"input": "1\n0\n1",
"output": "0 "
},
{
"input": "2\n0 5\n4 0\n1 2",
"output": "9 0 "
},
{
"input": "4\n0 3 1 1\n6 0 400 1\n2 4 0 1\n1 1 1 0\n4 1 2 3",
"output": "17 23 404 0 "
},
{
"input": "4\n0 57148 51001 13357\n71125 0 98369 67226\n49388 90852 0 66291\n39573 38165 9700... | 1,599,045,960 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
typedef long long ll;
using namespace std;
#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
const ll N = 502;
ll v[N], z[N], ans[N];
ll l[N][N];
int main()
{
IOS;
#ifndef ONLINE_JUDGE
freopen("input.in", "r", stdin);
freopen("output.txt", "w", stdout);
#endif
ll n... | Title: Greg and Graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg has a weighed directed graph, consisting of *n* vertices. In this graph any pair of distinct vertices has an edge between them in both directions. Greg loves playing with the graph and now he has invented a new game... | ```python
#include <bits/stdc++.h>
typedef long long ll;
using namespace std;
#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
const ll N = 502;
ll v[N], z[N], ans[N];
ll l[N][N];
int main()
{
IOS;
#ifndef ONLINE_JUDGE
freopen("input.in", "r", stdin);
freopen("output.txt", "w", stdout);
#en... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
870 | C | Maximum splitting | PROGRAMMING | 1,300 | [
"dp",
"greedy",
"math",
"number theory"
] | null | null | You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prim... | The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query. | For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings. | [
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] | [
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] | 12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | 1,500 | [
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
... | 1,687,636,599 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | import math
def is_not_prime(n):
limit = int(math.sqrt(n)) + 1
for i in range(2, limit):
if n % i == 0:
return True
return False
def max_op(nums, amount):
dp = [-1] * (amount + 1)
dp[0] = 0
for i in range(1, amount + 1):
for num in nums:
if i - num >= 0:... | Title: Maximum splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, o... | ```python
import math
def is_not_prime(n):
limit = int(math.sqrt(n)) + 1
for i in range(2, limit):
if n % i == 0:
return True
return False
def max_op(nums, amount):
dp = [-1] * (amount + 1)
dp[0] = 0
for i in range(1, amount + 1):
for num in nums:
if i -... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,619,228,470 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s = str(input())
h = "heidi"
c = 0
for i in range(0, len(s)):
if s[i] = h[c]:
c += 1
if c > (len(h) - 1):
print("YES")
else:
print("NO ")
| Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
s = str(input())
h = "heidi"
c = 0
for i in range(0, len(s)):
if s[i] = h[c]:
c += 1
if c > (len(h) - 1):
print("YES")
else:
print("NO ")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,680,807,500 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 61 | 154 | 0 | n = int(input())
a = list(map(int, input().split()))
a_set = set(a)
print(max(a.count(i) for i in a_set), len(a_set))
| Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
n = int(input())
a = list(map(int, input().split()))
a_set = set(a)
print(max(a.count(i) for i in a_set), len(a_set))
``` | 3.9615 | MatrixStudio/Codeforces-Python-Submissions |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,656,559,514 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 62 | 0 | n=int(input())
a=list(map(int,input().split()))
for i in range(len(a)):
f1=a[i]
f2=a[f1-1]
f3=a[f2-1]
if f3-1==i:
print("YES")
break
else:
print("NO") | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
n=int(input())
a=list(map(int,input().split()))
for i in range(len(a)):
f1=a[i]
f2=a[f1-1]
f3=a[f2-1]
if f3-1==i:
print("YES")
break
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
386 | A | Second-Price Auction | PROGRAMMING | 800 | [
"implementation"
] | null | null | In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is, each bidder secretly informs the organizer of the auction price he is willing to pay. After that, the au... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=1000) — number of bidders. The second line contains *n* distinct integer numbers *p*1,<=*p*2,<=... *p**n*, separated by single spaces (1<=≤<=*p**i*<=≤<=10000), where *p**i* stands for the price offered by the *i*-th bidder. | The single output line should contain two integers: index of the winner and the price he will pay. Indices are 1-based. | [
"2\n5 7\n",
"3\n10 2 8\n",
"6\n3 8 2 9 4 14\n"
] | [
"2 5\n",
"1 8\n",
"6 9\n"
] | none | 500 | [
{
"input": "2\n5 7",
"output": "2 5"
},
{
"input": "3\n10 2 8",
"output": "1 8"
},
{
"input": "6\n3 8 2 9 4 14",
"output": "6 9"
},
{
"input": "4\n4707 7586 4221 5842",
"output": "2 5842"
},
{
"input": "5\n3304 4227 4869 6937 6002",
"output": "4 6002"
},
{... | 1,656,733,091 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 46 | 0 | n = int(input())
l = list(map(int,input().split()))
l2=sorted(l)
m1 = l2[-1]
m2 = l2[-2]
pm1 = 0
for i in range(len(l)):
if l[i] == m1:
pm1 = i
print(pm1 + 1,m2) | Title: Second-Price Auction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem we consider a special type of an auction, which is called the second-price auction. As in regular auction *n* bidders place a bid which is price a bidder ready to pay. The auction is closed, that is... | ```python
n = int(input())
l = list(map(int,input().split()))
l2=sorted(l)
m1 = l2[-1]
m2 = l2[-2]
pm1 = 0
for i in range(len(l)):
if l[i] == m1:
pm1 = i
print(pm1 + 1,m2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,594,317,987 | 2,147,483,647 | PyPy 3 | OK | TESTS | 104 | 156 | 20,172,800 | from math import *
m,d = map(int,input().split())
if (m==1 or m==3 or m==5 or m==7 or m==8 or m == 10 or m == 12):
ans = 31
elif (m==2):
ans = 28
else:
ans = 30
ans -=(8-d)
cnt = 1
cnt += (ans + 6)//7
print(cnt) | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
from math import *
m,d = map(int,input().split())
if (m==1 or m==3 or m==5 or m==7 or m==8 or m == 10 or m == 12):
ans = 31
elif (m==2):
ans = 28
else:
ans = 30
ans -=(8-d)
cnt = 1
cnt += (ans + 6)//7
print(cnt)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
299 | B | Ksusha the Squirrel | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to the end of the road, that is, get to sector *n*. Unfortunately, there are some rocks on the road. We know ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=3·105,<=1<=≤<=*k*<=≤<=3·105). The next line contains *n* characters — the description of the road: the *i*-th character equals ".", if the *i*-th sector contains no rocks. Otherwise, it equals "#".
It is guaranteed that the first and the last characters e... | Print "YES" (without the quotes) if Ksusha can reach the end of the road, otherwise print "NO" (without the quotes). | [
"2 1\n..\n",
"5 2\n.#.#.\n",
"7 3\n.#.###.\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 1,000 | [
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "5 2\n.#.#.",
"output": "YES"
},
{
"input": "7 3\n.#.###.",
"output": "NO"
},
{
"input": "2 200\n..",
"output": "YES"
},
{
"input": "2 1\n..",
"output": "YES"
},
{
"input": "2 2\n..",
"output": "Y... | 1,618,945,309 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 |
step_etc = list(map(int, input().split()))
road = list(input())
res = []
for i in road:
stop = road.index(i)
road[stop] = ""
print(stop)
if stop == step_etc[1]:
if i == "#":
res.append("NO")
break
elif i == ".":
res.append("YES")
else:
continue
print(res[0])
| Title: Ksusha the Squirrel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha the Squirrel is standing at the beginning of a straight road, divided into *n* sectors. The sectors are numbered 1 to *n*, from left to right. Initially, Ksusha stands in sector 1.
Ksusha wants to walk to t... | ```python
step_etc = list(map(int, input().split()))
road = list(input())
res = []
for i in road:
stop = road.index(i)
road[stop] = ""
print(stop)
if stop == step_etc[1]:
if i == "#":
res.append("NO")
break
elif i == ".":
res.append("YES")
else:
continue
print(res[0])
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,659,891,398 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | import math
n,k = map(int, input().split())
dis = 0
path = []
past = None
for _ in range(n):
x,y = map(int, input().split())
if past:
dis += math.sqrt((x-past[0])**2 + (y-past[1])**2)
past = [x,y]
print(k*(dis/50))
| Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
import math
n,k = map(int, input().split())
dis = 0
path = []
past = None
for _ in range(n):
x,y = map(int, input().split())
if past:
dis += math.sqrt((x-past[0])**2 + (y-past[1])**2)
past = [x,y]
print(k*(dis/50))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
354 | A | Vasya and Robot | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"math"
] | null | null | Vasya has *n* items lying in a line. The items are consecutively numbered by numbers from 1 to *n* in such a way that the leftmost item has number 1, the rightmost item has number *n*. Each item has a weight, the *i*-th item weights *w**i* kilograms.
Vasya needs to collect all these items, however he won't do it by hi... | The first line contains five integers *n*,<=*l*,<=*r*,<=*Q**l*,<=*Q**r* (1<=≤<=*n*<=≤<=105;<=1<=≤<=*l*,<=*r*<=≤<=100;<=1<=≤<=*Q**l*,<=*Q**r*<=≤<=104).
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=100). | In the single line print a single number — the answer to the problem. | [
"3 4 4 19 1\n42 3 99\n",
"4 7 2 3 9\n1 2 3 4\n"
] | [
"576\n",
"34\n"
] | Consider the first sample. As *l* = *r*, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4·42 + 4·99 + 4·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left a... | 500 | [
{
"input": "3 4 4 19 1\n42 3 99",
"output": "576"
},
{
"input": "4 7 2 3 9\n1 2 3 4",
"output": "34"
},
{
"input": "2 100 100 10000 10000\n100 100",
"output": "20000"
},
{
"input": "2 3 4 5 6\n1 2",
"output": "11"
},
{
"input": "1 78 94 369 10000\n93",
"output... | 1,600,308,106 | 2,147,483,647 | PyPy 3 | OK | TESTS | 23 | 186 | 9,216,000 | if __name__ == '__main__':
n, l, r, ql, qr = map(int, input().split())
weights = [int(x) for x in input().split()]
curr_sum = 0
cum_sum = list()
for i in weights:
curr_sum += i
cum_sum.append(curr_sum)
# print(cum_sum)
min_cost = r*curr_sum + (n-1)*qr
for i in range(1, n+1):
taskl = i
... | Title: Vasya and Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* items lying in a line. The items are consecutively numbered by numbers from 1 to *n* in such a way that the leftmost item has number 1, the rightmost item has number *n*. Each item has a weight, the *i*-th... | ```python
if __name__ == '__main__':
n, l, r, ql, qr = map(int, input().split())
weights = [int(x) for x in input().split()]
curr_sum = 0
cum_sum = list()
for i in weights:
curr_sum += i
cum_sum.append(curr_sum)
# print(cum_sum)
min_cost = r*curr_sum + (n-1)*qr
for i in range(1, n+1):
tas... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
691 | C | Exponential notation | PROGRAMMING | 1,800 | [
"implementation",
"strings"
] | null | null | You are given a positive decimal number *x*.
Your task is to convert it to the "simple exponential notation".
Let *x*<==<=*a*·10*b*, where 1<=≤<=*a*<=<<=10, then in general case the "simple exponential notation" looks like "aEb". If *b* equals to zero, the part "Eb" should be skipped. If *a* is an integer, it shou... | The only line contains the positive decimal number *x*. The length of the line will not exceed 106. Note that you are given too large number, so you can't use standard built-in data types "float", "double" and other. | Print the only line — the "simple exponential notation" of the given number *x*. | [
"16\n",
"01.23400\n",
".100\n",
"100.\n"
] | [
"1.6E1\n",
"1.234\n",
"1E-1\n",
"1E2\n"
] | none | 0 | [
{
"input": "16",
"output": "1.6E1"
},
{
"input": "01.23400",
"output": "1.234"
},
{
"input": ".100",
"output": "1E-1"
},
{
"input": "100.",
"output": "1E2"
},
{
"input": "9000",
"output": "9E3"
},
{
"input": "0.0012",
"output": "1.2E-3"
},
{
... | 1,691,848,388 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | #Jasnah
x=float(input())
ans=''
res=f'{x:.2e}'
# print(res)
if x>1:
a=list(map(float,res.split('e+')))
if int(a[1])==0:
ans=a[0]
else:
ans=res.replace("e+",'E')
else:
a=list(map(float,res.split('e-')))
if int(a[1])==0:
ans=a[0]
else:
ans=res.repl... | Title: Exponential notation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a positive decimal number *x*.
Your task is to convert it to the "simple exponential notation".
Let *x*<==<=*a*·10*b*, where 1<=≤<=*a*<=<<=10, then in general case the "simple exponential notatio... | ```python
#Jasnah
x=float(input())
ans=''
res=f'{x:.2e}'
# print(res)
if x>1:
a=list(map(float,res.split('e+')))
if int(a[1])==0:
ans=a[0]
else:
ans=res.replace("e+",'E')
else:
a=list(map(float,res.split('e-')))
if int(a[1])==0:
ans=a[0]
else:
an... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
559 | B | Equivalent Strings | PROGRAMMING | 1,700 | [
"divide and conquer",
"hashing",
"sortings",
"strings"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 1,000 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,522,889,186 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 88 | 2,000 | 8,089,600 | word1 = input()
word2 = input()
def check_string(word1, word2):
if len(word1) > 0 and len(word2) > 0 and word1 == word2:
return True
elif len(word1) != len(word2):
return False
elif len(word1) % 2 == 1:
return False
mdd = int((len(word1) / 2))
if check_string(word1[0:mdd], word2... | Title: Equivalent Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split str... | ```python
word1 = input()
word2 = input()
def check_string(word1, word2):
if len(word1) > 0 and len(word2) > 0 and word1 == word2:
return True
elif len(word1) != len(word2):
return False
elif len(word1) % 2 == 1:
return False
mdd = int((len(word1) / 2))
if check_string(word1[0:m... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,687,522,240 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | watermelons = input("Please enter the number of watermelons (or 'botumn Esc' to exit): ")
while watermelons != "botumn Esc":
while not watermelons.isdigit :
watermelons = input("Please enter the number of watermelons (or 'botumn Esc' to exit): ")
if (int(watermelons)) % 2 == 0:
print("Yes... | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
watermelons = input("Please enter the number of watermelons (or 'botumn Esc' to exit): ")
while watermelons != "botumn Esc":
while not watermelons.isdigit :
watermelons = input("Please enter the number of watermelons (or 'botumn Esc' to exit): ")
if (int(watermelons)) % 2 == 0:
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,633,529,756 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 62 | 6,758,400 | x,s=input(),input()
x=x.split()
n,k=int(x[0]),int(x[1])
for i in s:
if s.count(i)>k:
print('No')
break
else:
print('Yes')
break | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same colo... | ```python
x,s=input(),input()
x=x.split()
n,k=int(x[0]),int(x[1])
for i in s:
if s.count(i)>k:
print('No')
break
else:
print('Yes')
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
757 | A | Gotta Catch Em' All! | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsession. Since he is too young to go out and catch Bulbasaur, he came up with his own way of catching a Bulbas... | Input contains a single line containing a string *s* (1<=<=≤<=<=|*s*|<=<=≤<=<=105) — the text on the front page of the newspaper without spaces and punctuation marks. |*s*| is the length of the string *s*.
The string *s* contains lowercase and uppercase English letters, i.e. . | Output a single integer, the answer to the problem. | [
"Bulbbasaur\n",
"F\n",
"aBddulbasaurrgndgbualdBdsagaurrgndbb\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first case, you could pick: Bulbbasaur.
In the second case, there is no way to pick even a single Bulbasaur.
In the third case, you can rearrange the string to BulbasaurBulbasauraddrgndgddgargndbb to get two words "Bulbasaur". | 500 | [
{
"input": "Bulbbasaur",
"output": "1"
},
{
"input": "F",
"output": "0"
},
{
"input": "aBddulbasaurrgndgbualdBdsagaurrgndbb",
"output": "2"
},
{
"input": "BBBBBBBBBBbbbbbbbbbbuuuuuuuuuullllllllllssssssssssaaaaaaaaaarrrrrrrrrr",
"output": "5"
},
{
"input": "BBBBBBB... | 1,619,316,997 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 12 | 62 | 0 | s=input()
o="Bulbbasaur"
q={}
for i in o:q[i]=0
for i in s:
if i in q:q[i]+=1
for i in {*o}:
q[i]//=o.count(i)
print(min(q.values())) | Title: Gotta Catch Em' All!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsess... | ```python
s=input()
o="Bulbbasaur"
q={}
for i in o:q[i]=0
for i in s:
if i in q:q[i]+=1
for i in {*o}:
q[i]//=o.count(i)
print(min(q.values()))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
873 | D | Merge Sort | PROGRAMMING | 1,800 | [
"constructive algorithms",
"divide and conquer"
] | null | null | Merge sort is a well-known sorting algorithm. The main function that sorts the elements of array *a* with indices from [*l*,<=*r*) can be implemented as follows:
1. If the segment [*l*,<=*r*) is already sorted in non-descending order (that is, for any *i* such that *l*<=≤<=*i*<=<<=*r*<=-<=1 *a*[*i*]<=≤<=*a*[*i*<=+... | The first line contains two numbers *n* and *k* (1<=≤<=*n*<=≤<=100000, 1<=≤<=*k*<=≤<=200000) — the size of a desired permutation and the number of *mergesort* calls required to sort it. | If a permutation of size *n* such that there will be exactly *k* calls of *mergesort* while sorting it doesn't exist, output <=-<=1. Otherwise output *n* integer numbers *a*[0],<=*a*[1],<=...,<=*a*[*n*<=-<=1] — the elements of a permutation that would meet the required conditions. If there are multiple answers, print a... | [
"3 3\n",
"4 1\n",
"5 6\n"
] | [
"2 1 3 ",
"1 2 3 4 ",
"-1\n"
] | none | 0 | [
{
"input": "3 3",
"output": "2 1 3 "
},
{
"input": "4 1",
"output": "1 2 3 4 "
},
{
"input": "5 6",
"output": "-1"
},
{
"input": "100 100",
"output": "-1"
},
{
"input": "10000 10001",
"output": "3 1 5 2 7 4 8 10 6 12 9 13 15 11 17 14 18 20 16 22 19 23 25 21 27... | 1,646,602,532 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 623 | 3,481,600 | import os
import sys
import copy
num = 0
a = None
# sys.stdin = open(os.path.join(os.path.dirname(__file__),'35.in'))
k = None
def solve():
global k,a
n, k = map(lambda x:int(x), input().split())
savek = copy.deepcopy(k)
# print(a)
a = [_+1 for _ in range(n)]
def mgsort(l, r):
... | Title: Merge Sort
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Merge sort is a well-known sorting algorithm. The main function that sorts the elements of array *a* with indices from [*l*,<=*r*) can be implemented as follows:
1. If the segment [*l*,<=*r*) is already sorted in non-desce... | ```python
import os
import sys
import copy
num = 0
a = None
# sys.stdin = open(os.path.join(os.path.dirname(__file__),'35.in'))
k = None
def solve():
global k,a
n, k = map(lambda x:int(x), input().split())
savek = copy.deepcopy(k)
# print(a)
a = [_+1 for _ in range(n)]
def mgsort... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,695,291,721 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 0 | s=int(input())
count=0
while True:
if s>=100:
count +=s%100
s-=s%100
continue
elif s>=20:
count +=s%20
s-=s%20
continue
elif s>=10:
count +=s%10
s-=s%10
continue
elif s>=5:
count +=s%5
s-=s%5
continue
eli... | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
s=int(input())
count=0
while True:
if s>=100:
count +=s%100
s-=s%100
continue
elif s>=20:
count +=s%20
s-=s%20
continue
elif s>=10:
count +=s%10
s-=s%10
continue
elif s>=5:
count +=s%5
s-=s%5
contin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
487 | A | Fight the Monster | PROGRAMMING | 1,800 | [
"binary search",
"brute force",
"implementation"
] | null | null | A monster is attacking the Cyberland!
Master Yang, a braver, is going to beat the monster. Yang and the monster each have 3 attributes: hitpoints (*HP*), offensive power (*ATK*) and defensive power (*DEF*).
During the battle, every second the monster's HP decrease by *max*(0,<=*ATK**Y*<=-<=*DEF**M*), while Yang's HP ... | The first line contains three integers *HP**Y*,<=*ATK**Y*,<=*DEF**Y*, separated by a space, denoting the initial *HP*, *ATK* and *DEF* of Master Yang.
The second line contains three integers *HP**M*,<=*ATK**M*,<=*DEF**M*, separated by a space, denoting the *HP*, *ATK* and *DEF* of the monster.
The third line contains... | The only output line should contain an integer, denoting the minimum bitcoins Master Yang should spend in order to win. | [
"1 2 1\n1 100 1\n1 100 100\n",
"100 100 100\n1 1 1\n1 1 1\n"
] | [
"99\n",
"0\n"
] | For the first sample, prices for *ATK* and *DEF* are extremely high. Master Yang can buy 99 HP, then he can beat the monster with 1 HP left.
For the second sample, Master Yang is strong enough to beat the monster, so he doesn't need to buy anything. | 500 | [
{
"input": "1 2 1\n1 100 1\n1 100 100",
"output": "99"
},
{
"input": "100 100 100\n1 1 1\n1 1 1",
"output": "0"
},
{
"input": "50 80 92\n41 51 56\n75 93 12",
"output": "0"
},
{
"input": "76 63 14\n89 87 35\n20 15 56",
"output": "915"
},
{
"input": "12 59 66\n43 15... | 1,524,415,241 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 124 | 7,065,600 | import math
hpy, atky, defy = map(int, input().split())
hpm, atkm, defm = map(int, input().split())
h,a,d = map(int, input().split())
ans = math.inf
for i in range(defy, 101):
for j in range(max(atky, defm+1), 201):
xx = math.ceil(hpm / (j - defm)) * max(0,(atkm-i))
hh = max(xx+1, hpy)
... | Title: Fight the Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A monster is attacking the Cyberland!
Master Yang, a braver, is going to beat the monster. Yang and the monster each have 3 attributes: hitpoints (*HP*), offensive power (*ATK*) and defensive power (*DEF*).
During t... | ```python
import math
hpy, atky, defy = map(int, input().split())
hpm, atkm, defm = map(int, input().split())
h,a,d = map(int, input().split())
ans = math.inf
for i in range(defy, 101):
for j in range(max(atky, defm+1), 201):
xx = math.ceil(hpm / (j - defm)) * max(0,(atkm-i))
hh = max(xx... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,662,451,444 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 92 | 0 | n,a,b=map(int,input().split())
x=a
if(n-x<=b):
print(n-x)
else:
print(b+1) | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n,a,b=map(int,input().split())
x=a
if(n-x<=b):
print(n-x)
else:
print(b+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
378 | B | Semifinals | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | Two semifinals have just been in the running tournament. Each semifinal had *n* participants. There are *n* participants advancing to the finals, they are chosen as follows: from each semifinal, we choose *k* people (0<=≤<=2*k*<=≤<=*n*) who showed the best result in their semifinals and all other places in the finals g... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of participants in each semifinal.
Each of the next *n* lines contains two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=109) — the results of the *i*-th participant (the number of milliseconds he needs to cover the semifinals distan... | Print two strings consisting of *n* characters, each equals either "0" or "1". The first line should correspond to the participants of the first semifinal, the second line should correspond to the participants of the second semifinal. The *i*-th character in the *j*-th line should equal "1" if the *i*-th participant of... | [
"4\n9840 9920\n9860 9980\n9930 10020\n10040 10090\n",
"4\n9900 9850\n9940 9930\n10000 10020\n10060 10110\n"
] | [
"1110\n1100\n",
"1100\n1100\n"
] | Consider the first sample. Each semifinal has 4 participants. The results of the first semifinal are 9840, 9860, 9930, 10040. The results of the second semifinal are 9920, 9980, 10020, 10090.
- If *k* = 0, the finalists are determined by the time only, so players 9840, 9860, 9920 and 9930 advance to the finals. - If... | 1,000 | [
{
"input": "4\n9840 9920\n9860 9980\n9930 10020\n10040 10090",
"output": "1110\n1100"
},
{
"input": "4\n9900 9850\n9940 9930\n10000 10020\n10060 10110",
"output": "1100\n1100"
},
{
"input": "1\n1 2",
"output": "1\n0"
},
{
"input": "1\n2 1",
"output": "0\n1"
},
{
"... | 1,672,223,838 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 62 | 0 | n=int(input())
l=[]
for _ in range(n):
a,b=map(int,input().split())
l.append([a,b])
l1=[]
l2=[]
for i in range(n):
l1.append([l[i][0],i])
l2.append([l[i][1],i])
ans1=[0 for i in range(n)]
ans2=[0 for i in range(n)]
cnt=n
i=0
j=0
while(cnt>0):
if(l1[i][0]<=l2[j][0]... | Title: Semifinals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two semifinals have just been in the running tournament. Each semifinal had *n* participants. There are *n* participants advancing to the finals, they are chosen as follows: from each semifinal, we choose *k* people (0<=≤<=2... | ```python
n=int(input())
l=[]
for _ in range(n):
a,b=map(int,input().split())
l.append([a,b])
l1=[]
l2=[]
for i in range(n):
l1.append([l[i][0],i])
l2.append([l[i][1],i])
ans1=[0 for i in range(n)]
ans2=[0 for i in range(n)]
cnt=n
i=0
j=0
while(cnt>0):
if(l1[i][0]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,537,996,262 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | n,p,q = map(int,input().split())
s = input()
def problem6(n,p,q,s):
global string
string = s
size = len(string)
palabras = []
pbool = size<2*p
qbool = size<2*q
if pbool and qbool:
if len(string)==1:
print("1")
print(string)
else:
... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n,p,q = map(int,input().split())
s = input()
def problem6(n,p,q,s):
global string
string = s
size = len(string)
palabras = []
pbool = size<2*p
qbool = size<2*q
if pbool and qbool:
if len(string)==1:
print("1")
print(string)
e... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
609 | A | USB Flash Drives | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives. | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabyt... | Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives. | [
"3\n5\n2\n1\n3\n",
"3\n6\n2\n3\n2\n",
"2\n5\n5\n10\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | 0 | [
{
"input": "3\n5\n2\n1\n3",
"output": "2"
},
{
"input": "3\n6\n2\n3\n2",
"output": "3"
},
{
"input": "2\n5\n5\n10",
"output": "1"
},
{
"input": "5\n16\n8\n1\n3\n4\n9",
"output": "2"
},
{
"input": "10\n121\n10\n37\n74\n56\n42\n39\n6\n68\n8\n100",
"output": "2"
... | 1,541,534,613 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 109 | 0 | import sys
n = int(input())
count = 0
file = int (input())
drives = []
for i in range(n):
drives.append(int(input()))
for k in drives:
if k == file or k > file:
print("1")
sys.exit()
drives.sort(reverse=True)
sum = 0
for l in range(0 , len(drives) , 1):
sum = sum + drives[l... | Title: USB Flash Drives
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of... | ```python
import sys
n = int(input())
count = 0
file = int (input())
drives = []
for i in range(n):
drives.append(int(input()))
for k in drives:
if k == file or k > file:
print("1")
sys.exit()
drives.sort(reverse=True)
sum = 0
for l in range(0 , len(drives) , 1):
sum = sum ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
583 | B | Robot's Task | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to colle... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information. | Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information. | [
"3\n0 2 0\n",
"5\n4 2 3 0 1\n",
"7\n0 3 1 0 5 2 6\n"
] | [
"1\n",
"3\n",
"2\n"
] | In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece.
In the second sample to... | 1,000 | [
{
"input": "3\n0 2 0",
"output": "1"
},
{
"input": "5\n4 2 3 0 1",
"output": "3"
},
{
"input": "7\n0 3 1 0 5 2 6",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "0"
},
{
"input": "10\n0 0 0 0 0 0 0 0 0 0",
"out... | 1,485,864,484 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 108 | 5,734,400 | # 583B
# θ(n*log(n)) time
# θ(n) space
from queue import PriorityQueue
__author__ = 'artyom'
# SOLUTION
def main():
n = read()
a = read(3)
if n == 1:
return 0
ix = []
for i in range(n):
ix.append(i)
ix.sort(key=lambda x: a[x])
l = PriorityQueue()
r... | Title: Robot's Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The compu... | ```python
# 583B
# θ(n*log(n)) time
# θ(n) space
from queue import PriorityQueue
__author__ = 'artyom'
# SOLUTION
def main():
n = read()
a = read(3)
if n == 1:
return 0
ix = []
for i in range(n):
ix.append(i)
ix.sort(key=lambda x: a[x])
l = PriorityQueu... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,666,086,835 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 46 | 0 | n,m=input().split()
n=int(n)
m=int(m)
res=[]
for i in range(n):
nums=[int(num) for num in input().split()[1:]]
res.extend(nums)
flag=0
for i in range(1,m+1):
if i not in res:
flag=1
if flag==1:
print('NO')
else:
print('YES') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n,m=input().split()
n=int(n)
m=int(m)
res=[]
for i in range(n):
nums=[int(num) for num in input().split()[1:]]
res.extend(nums)
flag=0
for i in range(1,m+1):
if i not in res:
flag=1
if flag==1:
print('NO')
else:
print('YES')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,698,384,451 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 | num = input().split(" ")
h = map(int, input().split(" "))
sum = 0
for i in h:
if i>int(num[1]):
sum+=2
else:
sum+=1
print(sum)
| Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
num = input().split(" ")
h = map(int, input().split(" "))
sum = 0
for i in h:
if i>int(num[1]):
sum+=2
else:
sum+=1
print(sum)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
540 | A | Combination Lock | PROGRAMMING | 800 | [
"implementation"
] | null | null | Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of disks on the combination lock.
The second line contains a string of *n* digits — the original state of the disks.
The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock. | Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock. | [
"5\n82195\n64723\n"
] | [
"13\n"
] | In the sample he needs 13 moves:
- 1 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b8967f65a723782358b93eff9ce69f336817cf70.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 2 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/07fa58573ece0d32... | 500 | [
{
"input": "5\n82195\n64723",
"output": "13"
},
{
"input": "12\n102021090898\n010212908089",
"output": "16"
},
{
"input": "1\n8\n1",
"output": "3"
},
{
"input": "2\n83\n57",
"output": "7"
},
{
"input": "10\n0728592530\n1362615763",
"output": "27"
},
{
... | 1,609,983,918 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 155 | 0 | a=int(input())
b=input()
c=input()
s=0
for i in range(a):
if abs(int(c[i])-int(b[i]))>5:
s=s+10-abs(int(c[i])-int(b[i]))
else: s=s+abs(int(c[i])-int(b[i]))
print(s) | Title: Combination Lock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is ... | ```python
a=int(input())
b=input()
c=input()
s=0
for i in range(a):
if abs(int(c[i])-int(b[i]))>5:
s=s+10-abs(int(c[i])-int(b[i]))
else: s=s+abs(int(c[i])-int(b[i]))
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
16 | B | Burglar and Matches | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | B. Burglar and Matches | 0 | 64 | A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* matches. All the matchboxes are of the same size. The burglar's rucksack can hold *n* matchboxes exactl... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2·108) and integer *m* (1<=≤<=*m*<=≤<=20). The *i*<=+<=1-th line contains a pair of numbers *a**i* and *b**i* (1<=≤<=*a**i*<=≤<=108,<=1<=≤<=*b**i*<=≤<=10). All the input numbers are integer. | Output the only number — answer to the problem. | [
"7 3\n5 10\n2 5\n3 6\n",
"3 3\n1 3\n2 2\n3 1\n"
] | [
"62\n",
"7\n"
] | none | 0 | [
{
"input": "7 3\n5 10\n2 5\n3 6",
"output": "62"
},
{
"input": "3 3\n1 3\n2 2\n3 1",
"output": "7"
},
{
"input": "1 1\n1 2",
"output": "2"
},
{
"input": "1 2\n1 9\n1 6",
"output": "9"
},
{
"input": "1 10\n1 1\n1 9\n1 3\n1 9\n1 7\n1 10\n1 4\n1 7\n1 3\n1 1",
"ou... | 1,691,188,415 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 92 | 0 | n, m = map(int, input().split())
w=[]
p=[]
f=0
for i in range(m):
x,v =map(int,input().split())
w.append(x)
p.append(v)
while n>0:
d=max(p)
r=p.index(d)
if n>=w[r]:
f+=(w[r]*d)
else:f+=(n*d)
n=(n-w[r])
p.pop(r)
w.pop(r)
if w ==[]:
break
p... | Title: Burglar and Matches
Time Limit: 0 seconds
Memory Limit: 64 megabytes
Problem Description:
A burglar got into a matches warehouse and wants to steal as many matches as possible. In the warehouse there are *m* containers, in the *i*-th container there are *a**i* matchboxes, and each matchbox contains *b**i* mat... | ```python
n, m = map(int, input().split())
w=[]
p=[]
f=0
for i in range(m):
x,v =map(int,input().split())
w.append(x)
p.append(v)
while n>0:
d=max(p)
r=p.index(d)
if n>=w[r]:
f+=(w[r]*d)
else:f+=(n*d)
n=(n-w[r])
p.pop(r)
w.pop(r)
if w ==[]:
... | 3 | MatrixStudio/Codeforces-Python-Submissions |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,691,794,159 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n=int(input());arr=list(map(int,input().split()));c1=0
l1=[];l2=[];l3=[];l4=[]
for i in arr:
if i>0:
l3.append(i)
if i ==0 :
l2.append(0)
if i<0:
if len(l1)<1:l1.append(i)
if i not in l1:l4.append(i)
print(1,l1[0])
if len(l3)==0:
print(2,l4[1],l4[0])
else:
print(len(l3),l3[0])
print(1,l2[0]... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
n=int(input());arr=list(map(int,input().split()));c1=0
l1=[];l2=[];l3=[];l4=[]
for i in arr:
if i>0:
l3.append(i)
if i ==0 :
l2.append(0)
if i<0:
if len(l1)<1:l1.append(i)
if i not in l1:l4.append(i)
print(1,l1[0])
if len(l3)==0:
print(2,l4[1],l4[0])
else:
print(len(l3),l3[0])
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
215 | B | Olympic Medal | PROGRAMMING | 1,300 | [
"greedy",
"math"
] | null | null | The World Programming Olympics Medal is a metal disk, consisting of two parts: the first part is a ring with outer radius of *r*1 cm, inner radius of *r*2 cm, (0<=<<=*r*2<=<<=*r*1) made of metal with density *p*1 g/cm3. The second part is an inner disk with radius *r*2 cm, it is made of metal with density *p*2 g/... | The first input line contains an integer *n* and a sequence of integers *x*1,<=*x*2,<=...,<=*x**n*. The second input line contains an integer *m* and a sequence of integers *y*1,<=*y*2,<=...,<=*y**m*. The third input line contains an integer *k* and a sequence of integers *z*1,<=*z*2,<=...,<=*z**k*. The last line conta... | Print a single real number — the sought value *r*2 with absolute or relative error of at most 10<=-<=6. It is guaranteed that the solution that meets the problem requirements exists. | [
"3 1 2 3\n1 2\n3 3 2 1\n1 2\n",
"4 2 3 6 4\n2 1 2\n3 10 6 8\n2 1\n"
] | [
"2.683281573000\n",
"2.267786838055\n"
] | In the first sample the jury should choose the following values: *r*<sub class="lower-index">1</sub> = 3, *p*<sub class="lower-index">1</sub> = 2, *p*<sub class="lower-index">2</sub> = 1. | 500 | [
{
"input": "3 1 2 3\n1 2\n3 3 2 1\n1 2",
"output": "2.683281573000"
},
{
"input": "4 2 3 6 4\n2 1 2\n3 10 6 8\n2 1",
"output": "2.267786838055"
},
{
"input": "1 5\n1 3\n1 7\n515 892",
"output": "3.263613058533"
},
{
"input": "2 3 2\n3 2 3 1\n2 2 1\n733 883",
"output": "2.... | 1,580,250,076 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 248 | 614,400 | import math as m
r1=max(list( map(int,input().split() ))[1:])
p1=max(list( map(int,input().split() ))[1:])
p2=min(list( map(int,input().split() ))[1:])
a,b=map(int , input().split())
c=a/b
print(m.sqrt((p1*r1*r1)/(p1+c*p2))) | Title: Olympic Medal
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The World Programming Olympics Medal is a metal disk, consisting of two parts: the first part is a ring with outer radius of *r*1 cm, inner radius of *r*2 cm, (0<=<<=*r*2<=<<=*r*1) made of metal with density *p*1 g/... | ```python
import math as m
r1=max(list( map(int,input().split() ))[1:])
p1=max(list( map(int,input().split() ))[1:])
p2=min(list( map(int,input().split() ))[1:])
a,b=map(int , input().split())
c=a/b
print(m.sqrt((p1*r1*r1)/(p1+c*p2)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
592 | E | BCPC | PROGRAMMING | 2,700 | [
"binary search",
"geometry",
"two pointers"
] | null | null | BCPC stands for Byteforces Collegiate Programming Contest, and is the most famous competition in Byteforces.
BCPC is a team competition. Each team is composed by a coach and three contestants. Blenda is the coach of the Bit State University(BSU), and she is very strict selecting the members of her team.
In BSU there ... | In the first line of the input three integers *n*, *c* and *d* (3<=≤<=*n*<=≤<=345678,<=1<=≤<=*c*,<=*d*<=≤<=109) are written. They denote the number of students Blenda can use to form teams, the value subtracted from all reading speeds and the value subtracted from all writing speeds respectively.
Each of the next *n* ... | Print the number of different teams in BSU, that are good according to Blenda's definition. | [
"5 2 2\n1 1\n4 1\n2 3\n3 2\n3 4\n",
"7 6 6\n3 2\n1 7\n5 7\n3 7\n6 4\n8 9\n8 5\n"
] | [
"4\n",
"11\n"
] | In the first sample the following teams are good: (*i* = 1, *j* = 2, *k* = 3), (*i* = 2, *j* = 5, *k* = 1), (*i* = 1, *j* = 4, *k* = 3), (*i* = 5, *j* = 1, *k* = 4).
Note, that for example the team (*i* = 3, *j* = 1, *k* = 2) is also good, but is considered to be the same as the team (*i* = 1, *j* = 2, *k* = 3). | 3,000 | [] | 1,446,349,050 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 307,200 | import math
n, c, d = map(int, input().split(" "))
def arctan(rise, run):
if run == 0:
if rise > 0:
return (math.pi)/2
elif rise < 0:
return 3*(math.pi)/2
else:
pass
if run > 0:
theta = math.atan(rise/run)
if theta>=0:
... | Title: BCPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
BCPC stands for Byteforces Collegiate Programming Contest, and is the most famous competition in Byteforces.
BCPC is a team competition. Each team is composed by a coach and three contestants. Blenda is the coach of the Bit State... | ```python
import math
n, c, d = map(int, input().split(" "))
def arctan(rise, run):
if run == 0:
if rise > 0:
return (math.pi)/2
elif rise < 0:
return 3*(math.pi)/2
else:
pass
if run > 0:
theta = math.atan(rise/run)
if t... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
14 | A | Letter | PROGRAMMING | 800 | [
"implementation"
] | A. Letter | 1 | 64 | A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brother, who lives in Flatland. Now Bob has to send his picture by post, but because of the w... | The first line of the input data contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50), *n* — amount of lines, and *m* — amount of columns on Bob's sheet. The following *n* lines contain *m* characters each. Character «.» stands for a non-shaded square on the sheet, and «*» — for a shaded square. It is guaranteed that ... | Output the required rectangle of the minimum cost. Study the output data in the sample tests to understand the output format better. | [
"6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..\n",
"3 3\n***\n*.*\n***\n"
] | [
"***\n*..\n***\n*..\n***\n",
"***\n*.*\n***\n"
] | none | 0 | [
{
"input": "6 7\n.......\n..***..\n..*....\n..***..\n..*....\n..***..",
"output": "***\n*..\n***\n*..\n***"
},
{
"input": "3 3\n***\n*.*\n***",
"output": "***\n*.*\n***"
},
{
"input": "1 1\n*",
"output": "*"
},
{
"input": "2 1\n*\n*",
"output": "*\n*"
},
{
"input"... | 1,669,427,531 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 92 | 0 | n, m = list(map(int, input().split()))
grid = []
l = m
r = m
for l in range(n):
line = input()
edge = line.split("*")
if "*" in line:
grid.append(line)
if len(edge[0]) < l:
l = len(edge[0])
if len(edge[-1]) < r:
r = len(edge[-1])
for i in range(le... | Title: Letter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A boy Bob likes to draw. Not long ago he bought a rectangular graph (checked) sheet with *n* rows and *m* columns. Bob shaded some of the squares on the sheet. Having seen his masterpiece, he decided to share it with his elder brothe... | ```python
n, m = list(map(int, input().split()))
grid = []
l = m
r = m
for l in range(n):
line = input()
edge = line.split("*")
if "*" in line:
grid.append(line)
if len(edge[0]) < l:
l = len(edge[0])
if len(edge[-1]) < r:
r = len(edge[-1])
for i i... | 0 | MatrixStudio/Codeforces-Python-Submissions |
670 | D1 | Magic Powder - 1 | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation"
] | null | null | This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too difficult in large constraints, you can write solution to the simplified version only.
Waking up in the ... | The first line of the input contains two positive integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1000) — the number of ingredients and the number of grams of the magic powder.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where the *i*-th number is equal to the number of grams of... | Print the maximum number of cookies, which Apollinaria will be able to bake using the ingredients that she has and the magic powder. | [
"3 1\n2 1 4\n11 3 16\n",
"4 3\n4 3 5 6\n11 12 14 20\n"
] | [
"4\n",
"3\n"
] | In the first sample it is profitably for Apollinaria to make the existing 1 gram of her magic powder to ingredient with the index 2, then Apollinaria will be able to bake 4 cookies.
In the second sample Apollinaria should turn 1 gram of magic powder to ingredient with the index 1 and 1 gram of magic powder to ingredie... | 1,000 | [
{
"input": "3 1\n2 1 4\n11 3 16",
"output": "4"
},
{
"input": "4 3\n4 3 5 6\n11 12 14 20",
"output": "3"
},
{
"input": "10 926\n5 6 8 1 2 5 1 8 4 4\n351 739 998 725 953 970 906 691 707 1000",
"output": "137"
},
{
"input": "20 925\n7 3 1 2 1 3 1 3 1 2 3 1 5 8 1 3 7 3 4 2\n837 ... | 1,693,005,458 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 119 | 77 | 2,457,600 | import sys
input=sys.stdin.readline
ing,sug=map(int,input().split())
wan = list(map(int,input().split()))
have = list(map(int,input().split()))
ingr = [0]*(ing)
for i in range(ing):
ingr[i]=[have[i]//wan[i],wan[i],have[i]%wan[i],have[i]]
def valid(mid,sug):
for i in range(ing):
k = 0
... | Title: Magic Powder - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too dif... | ```python
import sys
input=sys.stdin.readline
ing,sug=map(int,input().split())
wan = list(map(int,input().split()))
have = list(map(int,input().split()))
ingr = [0]*(ing)
for i in range(ing):
ingr[i]=[have[i]//wan[i],wan[i],have[i]%wan[i],have[i]]
def valid(mid,sug):
for i in range(ing):
k = 0... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
777 | A | Shell Game | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | Bomboslav likes to look out of the window in his room and watch lads outside playing famous shell game. The game is played by two persons: operator and player. Operator takes three similar opaque shells and places a ball beneath one of them. Then he shuffles the shells by swapping some pairs and the player has to guess... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=2·109) — the number of movements made by the operator.
The second line contains a single integer *x* (0<=≤<=*x*<=≤<=2) — the index of the shell where the ball was found after *n* movements. | Print one integer from 0 to 2 — the index of the shell where the ball was initially placed. | [
"4\n2\n",
"1\n1\n"
] | [
"1\n",
"0\n"
] | In the first sample, the ball was initially placed beneath the middle shell and the operator completed four movements.
1. During the first move operator swapped the left shell and the middle shell. The ball is now under the left shell. 1. During the second move operator swapped the middle shell and the right one. Th... | 500 | [
{
"input": "4\n2",
"output": "1"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "2\n2",
"output": "0"
},
{
"input": "3\n1",
"output": "1"
},
{
"input": "3\n2",
"output": "0"
},
{
"input": "3\n0",
"output": "2"
},
{
"input": "2000000000\n... | 1,488,062,576 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 500 | 4,608,000 | n = int(input())
x = int(input())
lst = [0,0,0]
lst[x] = 1
for i in range(n,0,-1):
if i % 2 == 0:
lst[1], lst[2] = lst[2], lst[1]
else:
lst[0], lst[1] = lst[1], lst[0]
for i in range(3):
if lst[i] == 1:
print(str(i))
| Title: Shell Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bomboslav likes to look out of the window in his room and watch lads outside playing famous shell game. The game is played by two persons: operator and player. Operator takes three similar opaque shells and places a ball ben... | ```python
n = int(input())
x = int(input())
lst = [0,0,0]
lst[x] = 1
for i in range(n,0,-1):
if i % 2 == 0:
lst[1], lst[2] = lst[2], lst[1]
else:
lst[0], lst[1] = lst[1], lst[0]
for i in range(3):
if lst[i] == 1:
print(str(i))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
915 | C | Permute Digits | PROGRAMMING | 1,700 | [
"dp",
"greedy"
] | null | null | You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allowed to leave *a* as it is. | The first line contains integer *a* (1<=≤<=*a*<=≤<=1018). The second line contains integer *b* (1<=≤<=*b*<=≤<=1018). Numbers don't have leading zeroes. It is guaranteed that answer exists. | Print the maximum possible number that is a permutation of digits of *a* and is not greater than *b*. The answer can't have any leading zeroes. It is guaranteed that the answer exists.
The number in the output should have exactly the same length as number *a*. It should be a permutation of digits of *a*. | [
"123\n222\n",
"3921\n10000\n",
"4940\n5000\n"
] | [
"213\n",
"9321\n",
"4940\n"
] | none | 0 | [
{
"input": "123\n222",
"output": "213"
},
{
"input": "3921\n10000",
"output": "9321"
},
{
"input": "4940\n5000",
"output": "4940"
},
{
"input": "23923472834\n23589234723",
"output": "23498743322"
},
{
"input": "102391019\n491010301",
"output": "399211100"
},... | 1,652,360,672 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 |
# Note: went straight to the tutorial for this problem.
# Problem: 915C codeforces
a = input()
b = int(input())
count = [0,0,0,0,0,0,0,0,0,0]
for digit in a: count[int(digit)] += 1
def minimal_suffix(length):
rtn = ""
i = 0
while length > 0:
rtn += min(length, count[i]) * str(i)
... | Title: Permute Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allow... | ```python
# Note: went straight to the tutorial for this problem.
# Problem: 915C codeforces
a = input()
b = int(input())
count = [0,0,0,0,0,0,0,0,0,0]
for digit in a: count[int(digit)] += 1
def minimal_suffix(length):
rtn = ""
i = 0
while length > 0:
rtn += min(length, count[i]) *... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,688,978,838 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | n = input()
x = int(n)
l = [i for i in n if i!='4' and i!='7']
f = 0
if len(l)==0:
f=1
else:
while x%2==0:
x//=2
l = [i for i in str(x) if i!='4' and i!='7']
if f==1 or len(l)==0:
print("YES")
else:
print("NO") | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = input()
x = int(n)
l = [i for i in n if i!='4' and i!='7']
f = 0
if len(l)==0:
f=1
else:
while x%2==0:
x//=2
l = [i for i in str(x) if i!='4' and i!='7']
if f==1 or len(l)==0:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,695,921,434 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 31 | 0 | n,t=map(int,input().split())
maximum='9'*n
while(len(maximum)>=n):
if(int(maximum)%t==0):
break
maximum=str(int(maximum)-1)
if(len(maximum)<n):
print(-1)
else:
print(maximum)
| Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n,t=map(int,input().split())
maximum='9'*n
while(len(maximum)>=n):
if(int(maximum)%t==0):
break
maximum=str(int(maximum)-1)
if(len(maximum)<n):
print(-1)
else:
print(maximum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
55 | A | Flea travel | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | A. Flea travel | 1 | 256 | A flea is sitting at one of the *n* hassocks, arranged in a circle, at the moment. After minute number *k* the flea jumps through *k*<=-<=1 hassoсks (clockwise). For example, after the first minute the flea jumps to the neighboring hassock. You should answer: will the flea visit all the hassocks or not. We assume that ... | The only line contains single integer: 1<=≤<=*n*<=≤<=1000 — number of hassocks. | Output "YES" if all the hassocks will be visited and "NO" otherwise. | [
"1\n",
"3\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "YES"
},
{
"input": "4",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "NO"
},
{
"input": "7",
"output": "NO... | 1,505,707,326 | 2,147,483,647 | Python 3 | OK | TESTS | 83 | 62 | 5,529,600 | a=int(input())
b=1
while b<=a:
if b==a:
u=1
else:
u=0
b=b*2
if u==1:
print("YES")
else:
print("NO") | Title: Flea travel
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
A flea is sitting at one of the *n* hassocks, arranged in a circle, at the moment. After minute number *k* the flea jumps through *k*<=-<=1 hassoсks (clockwise). For example, after the first minute the flea jumps to the neighbo... | ```python
a=int(input())
b=1
while b<=a:
if b==a:
u=1
else:
u=0
b=b*2
if u==1:
print("YES")
else:
print("NO")
``` | 3.9587 | MatrixStudio/Codeforces-Python-Submissions |
678 | C | Joty and Chocolate | PROGRAMMING | 1,600 | [
"implementation",
"math",
"number theory"
] | null | null | Little Joty has got a task to do. She has a line of *n* tiles indexed from 1 to *n*. She has to paint them in a strange pattern.
An unpainted tile should be painted Red if it's index is divisible by *a* and an unpainted tile should be painted Blue if it's index is divisible by *b*. So the tile with the number divisibl... | The only line contains five integers *n*, *a*, *b*, *p* and *q* (1<=≤<=*n*,<=*a*,<=*b*,<=*p*,<=*q*<=≤<=109). | Print the only integer *s* — the maximum number of chocolates Joty can get.
Note that the answer can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | [
"5 2 3 12 15\n",
"20 2 3 3 5\n"
] | [
"39\n",
"51\n"
] | none | 0 | [
{
"input": "5 2 3 12 15",
"output": "39"
},
{
"input": "20 2 3 3 5",
"output": "51"
},
{
"input": "1 1 1 1 1",
"output": "1"
},
{
"input": "1 2 2 2 2",
"output": "0"
},
{
"input": "2 1 3 3 3",
"output": "6"
},
{
"input": "3 1 1 3 3",
"output": "9"
... | 1,666,007,987 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 185 | 62 | 0 | from math import gcd
n, a, b, p, q=map(int, input().split())
if a!=b:
if q>p: print((n//b)*q+(n//a)*p-p*(n//(a*b//gcd(a, b))))
else: print((n//a)*p+(n//b)*q-q*(n//(a*b//gcd(a, b))))
else:
if q>p: print((n//b)*q)
else: print((n//a)*p)
| Title: Joty and Chocolate
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Joty has got a task to do. She has a line of *n* tiles indexed from 1 to *n*. She has to paint them in a strange pattern.
An unpainted tile should be painted Red if it's index is divisible by *a* and an unpai... | ```python
from math import gcd
n, a, b, p, q=map(int, input().split())
if a!=b:
if q>p: print((n//b)*q+(n//a)*p-p*(n//(a*b//gcd(a, b))))
else: print((n//a)*p+(n//b)*q-q*(n//(a*b//gcd(a, b))))
else:
if q>p: print((n//b)*q)
else: print((n//a)*p)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
157 | B | Trace | PROGRAMMING | 1,000 | [
"geometry",
"sortings"
] | null | null | One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall into several parts. Some parts were painted red and all the other were painted blue. Besides,... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integers *r**i* (1<=≤<=*r**i*<=≤<=1000) — the circles' radii. It is guaranteed that all circles are different. | Print the single real number — total area of the part of the wall that is painted red. The answer is accepted if absolute or relative error doesn't exceed 10<=-<=4. | [
"1\n1\n",
"3\n1 4 2\n"
] | [
"3.1415926536\n",
"40.8407044967\n"
] | In the first sample the picture is just one circle of radius 1. Inner part of the circle is painted red. The area of the red part equals π × 1<sup class="upper-index">2</sup> = π.
In the second sample there are three circles of radii 1, 4 and 2. Outside part of the second circle is painted blue. Part between the secon... | 1,000 | [
{
"input": "1\n1",
"output": "3.1415926536"
},
{
"input": "3\n1 4 2",
"output": "40.8407044967"
},
{
"input": "4\n4 1 3 2",
"output": "31.4159265359"
},
{
"input": "4\n100 10 2 1",
"output": "31111.1920484997"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output"... | 1,620,023,920 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 124 | 0 | input()
l = sorted(int(a)*int(a) for a in input().split())
print(3.1415926536 * (sum(l[::-2])-sum(l[-2::-2])))
| Title: Trace
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall in... | ```python
input()
l = sorted(int(a)*int(a) for a in input().split())
print(3.1415926536 * (sum(l[::-2])-sum(l[-2::-2])))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,669,215,256 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 46 | 0 | n = int(input())
a = (n + 1) // 3
print(n - a) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
n = int(input())
a = (n + 1) // 3
print(n - a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,652,791,675 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 5,632,000 | s1=input()
s2=input()
l1=int(len(s1))
l2=int(len(s2))
l10=int(l1)
l20=int(l2)
i=0
i=int(i)
temp=0
temp=int(temp)
f=0
f=int(f)
if l1>l2:
s1=s1[l1-l2:l1]
temp=temp+l1-l2
elif l1<l2:
s2=s2[l2-l1:l2]
temp=temp+l2-l1
l1=int(len(s1))
l2=int(len(s2))
while(i<l1 and i<l2):
if s1[i:l1]==s2[i:l2]:
tem... | Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
s1=input()
s2=input()
l1=int(len(s1))
l2=int(len(s2))
l10=int(l1)
l20=int(l2)
i=0
i=int(i)
temp=0
temp=int(temp)
f=0
f=int(f)
if l1>l2:
s1=s1[l1-l2:l1]
temp=temp+l1-l2
elif l1<l2:
s2=s2[l2-l1:l2]
temp=temp+l2-l1
l1=int(len(s1))
l2=int(len(s2))
while(i<l1 and i<l2):
if s1[i:l1]==s2[i:l2]:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,657,296,127 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | s = input()
c = 0
d = 0
for i in s:
if i == i.upper():
c = c+1
elif i == i.lower():
d = d+1
else:
print(s.lower())
if c>d:
print(s.upper())
else:
print(s.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
c = 0
d = 0
for i in s:
if i == i.upper():
c = c+1
elif i == i.lower():
d = d+1
else:
print(s.lower())
if c>d:
print(s.upper())
else:
print(s.lower())
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
931 | C | Laboratory Work | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | Anya and Kirill are doing a physics laboratory work. In one of the tasks they have to measure some value *n* times, and then compute the average value to lower the error.
Kirill has already made his measurements, and has got the following integer values: *x*1, *x*2, ..., *x**n*. It is important that the values are clo... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the numeber of measurements made by Kirill.
The second line contains a sequence of integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=100<=000<=≤<=*x**i*<=≤<=100<=000) — the measurements made by Kirill. It is guaranteed that the difference between the maxi... | In the first line print the minimum possible number of equal measurements.
In the second line print *n* integers *y*1,<=*y*2,<=...,<=*y**n* — the values Anya should write. You can print the integers in arbitrary order. Keep in mind that the minimum value among Anya's values should be not less that the minimum among Ki... | [
"6\n-1 1 1 0 0 -1\n",
"3\n100 100 101\n",
"7\n-10 -9 -10 -8 -10 -9 -9\n"
] | [
"2\n0 0 0 0 0 0 \n",
"3\n101 100 100 \n",
"5\n-10 -10 -9 -9 -9 -9 -9 \n"
] | In the first example Anya can write zeros as here measurements results. The average value is then equal to the average value of Kirill's values, and there are only two equal measurements.
In the second example Anya should write two values 100 and one value 101 (in any order), because it is the only possibility to make... | 1,750 | [
{
"input": "6\n-1 1 1 0 0 -1",
"output": "2\n0 0 0 0 0 0 "
},
{
"input": "3\n100 100 101",
"output": "3\n101 100 100 "
},
{
"input": "7\n-10 -9 -10 -8 -10 -9 -9",
"output": "5\n-10 -10 -9 -9 -9 -9 -9 "
},
{
"input": "60\n-8536 -8536 -8536 -8535 -8536 -8536 -8536 -8536 -8536 -... | 1,520,181,881 | 4,181 | Python 3 | WRONG_ANSWER | PRETESTS | 10 | 624 | 13,004,800 | n = int(input())
lst = list(map(int, input().split()))
lst.sort()
l, r = lst[0], lst[-1]
if r - l == 2:
while lst[0] == l and lst[-1] == r:
lst.pop(0)
lst.pop()
print(len(lst))
print(*(lst + [r-1] * (n - len(lst))))
else:
print(n)
print(*lst) | Title: Laboratory Work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anya and Kirill are doing a physics laboratory work. In one of the tasks they have to measure some value *n* times, and then compute the average value to lower the error.
Kirill has already made his measurements, and h... | ```python
n = int(input())
lst = list(map(int, input().split()))
lst.sort()
l, r = lst[0], lst[-1]
if r - l == 2:
while lst[0] == l and lst[-1] == r:
lst.pop(0)
lst.pop()
print(len(lst))
print(*(lst + [r-1] * (n - len(lst))))
else:
print(n)
print(*lst)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
498 | A | Crazy Town | PROGRAMMING | 1,700 | [
"geometry"
] | null | null | Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the plane into connected regions, possibly of infinite space. Let's call each such region a block. We ... | The first line contains two space-separated integers *x*1, *y*1 (<=-<=106<=≤<=*x*1,<=*y*1<=≤<=106) — the coordinates of your home.
The second line contains two integers separated by a space *x*2, *y*2 (<=-<=106<=≤<=*x*2,<=*y*2<=≤<=106) — the coordinates of the university you are studying at.
The third line contains a... | Output the answer to the problem. | [
"1 1\n-1 -1\n2\n0 1 0\n1 0 0\n",
"1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3\n"
] | [
"2\n",
"2\n"
] | Pictures to the samples are presented below (A is the point representing the house; B is the point representing the university, different blocks are filled with different colors): | 500 | [
{
"input": "1 1\n-1 -1\n2\n0 1 0\n1 0 0",
"output": "2"
},
{
"input": "1 1\n-1 -1\n3\n1 0 0\n0 1 0\n1 1 -3",
"output": "2"
},
{
"input": "841746 527518\n595261 331297\n10\n-946901 129987 670374\n-140388 -684770 309555\n-302589 415564 -387435\n-565799 -72069 -395358\n-523453 -511446 85489... | 1,419,771,521 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 77 | 0 | x, y = map(int, input().split())
u, v = map(int, input().split())
s = 0
for i in range(int(input())):
a, b, c = map(int, input().split())
s += (a * x + b * y + c > 0) ^ (a * u + b * v + c > 0)
print(s) | Title: Crazy Town
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Crazy Town is a plane on which there are *n* infinite line roads. Each road is defined by the equation *a**i**x*<=+<=*b**i**y*<=+<=*c**i*<==<=0, where *a**i* and *b**i* are not both equal to the zero. The roads divide the pl... | ```python
x, y = map(int, input().split())
u, v = map(int, input().split())
s = 0
for i in range(int(input())):
a, b, c = map(int, input().split())
s += (a * x + b * y + c > 0) ^ (a * u + b * v + c > 0)
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
653 | E | Bear and Forgotten Tree 2 | PROGRAMMING | 2,400 | [
"dfs and similar",
"dsu",
"graphs",
"trees"
] | null | null | A tree is a connected undirected graph consisting of *n* vertices and *n*<=<=-<=<=1 edges. Vertices are numbered 1 through *n*.
Limak is a little polar bear. He once had a tree with *n* vertices but he lost it. He still remembers something about the lost tree though.
You are given *m* pairs of vertices (*a*1,<=*b*1),... | The first line of the input contains three integers *n*, *m* and *k* () — the number of vertices in Limak's tree, the number of forbidden pairs of vertices, and the degree of vertex 1, respectively.
The *i*-th of next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠... | Print "possible" (without quotes) if there exists at least one tree satisfying the given conditions. Otherwise, print "impossible" (without quotes). | [
"5 4 2\n1 2\n2 3\n4 2\n4 1\n",
"6 5 3\n1 2\n1 3\n1 4\n1 5\n1 6\n"
] | [
"possible\n",
"impossible\n"
] | In the first sample, there are *n* = 5 vertices. The degree of vertex 1 should be *k* = 2. All conditions are satisfied for a tree with edges 1 - 5, 5 - 2, 1 - 3 and 3 - 4.
In the second sample, Limak remembers that none of the following edges existed: 1 - 2, 1 - 3, 1 - 4, 1 - 5 and 1 - 6. Hence, vertex 1 couldn't be ... | 2,500 | [
{
"input": "5 4 2\n1 2\n2 3\n4 2\n4 1",
"output": "possible"
},
{
"input": "6 5 3\n1 2\n1 3\n1 4\n1 5\n1 6",
"output": "impossible"
},
{
"input": "4 3 2\n2 3\n2 4\n3 4",
"output": "impossible"
},
{
"input": "4 2 2\n1 2\n1 3",
"output": "impossible"
},
{
"input": "... | 1,683,117,168 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | #https://codeforces.com/contest/653/problem/E
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return int(input())
def inlt():
return list(map(int,input().split()))
def insr():
s = input()
return list(s[:len(s) - 1])
def invr():
ret... | Title: Bear and Forgotten Tree 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is a connected undirected graph consisting of *n* vertices and *n*<=<=-<=<=1 edges. Vertices are numbered 1 through *n*.
Limak is a little polar bear. He once had a tree with *n* vertices but he lost i... | ```python
#https://codeforces.com/contest/653/problem/E
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return int(input())
def inlt():
return list(map(int,input().split()))
def insr():
s = input()
return list(s[:len(s) - 1])
def invr()... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
644 | C | Hostname Aliases | PROGRAMMING | 2,100 | [
"*special",
"binary search",
"data structures",
"implementation",
"sortings",
"strings"
] | null | null | There are some websites that are accessible through several different addresses. For example, for a long time Codeforces was accessible with two hostnames codeforces.com and codeforces.ru.
You are given a list of page addresses being queried. For simplicity we consider all addresses to have the form http://<hostnam... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of page queries. Then follow *n* lines each containing exactly one address. Each address is of the form http://<hostname>[/<path>], where:
- <hostname> consists of lowercase English letters and dots, ther... | First print *k* — the number of groups of server names that correspond to one website. You should count only groups of size greater than one.
Next *k* lines should contain the description of groups, one group per line. For each group print all server names separated by a single space. You are allowed to print both gro... | [
"10\nhttp://abacaba.ru/test\nhttp://abacaba.ru/\nhttp://abacaba.com\nhttp://abacaba.com/test\nhttp://abacaba.de/\nhttp://abacaba.ru/test\nhttp://abacaba.de/test\nhttp://abacaba.com/\nhttp://abacaba.com/t\nhttp://abacaba.com/test\n",
"14\nhttp://c\nhttp://ccc.bbbb/aba..b\nhttp://cba.com\nhttp://a.c/aba..b/a\nhttp:... | [
"1\nhttp://abacaba.de http://abacaba.ru \n",
"2\nhttp://cba.com http://ccc.bbbb \nhttp://a.a.a http://a.c http://abc \n"
] | none | 1,500 | [
{
"input": "10\nhttp://abacaba.ru/test\nhttp://abacaba.ru/\nhttp://abacaba.com\nhttp://abacaba.com/test\nhttp://abacaba.de/\nhttp://abacaba.ru/test\nhttp://abacaba.de/test\nhttp://abacaba.com/\nhttp://abacaba.com/t\nhttp://abacaba.com/test",
"output": "1\nhttp://abacaba.de http://abacaba.ru "
},
{
"... | 1,458,134,468 | 15,668 | Python 3 | WRONG_ANSWER | TESTS | 51 | 1,419 | 25,804,800 | n = None
d = {}
def add(s):
global d
h = []
ind = 7
for i in s[7:]:
if (i == '/'):
break
else:
h.append(i)
ind += 1
hostname = "".join(h)
path = s[ind:]
if hostname in d:
d[hostname].append(path)
else:
d[hostname] = [pa... | Title: Hostname Aliases
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are some websites that are accessible through several different addresses. For example, for a long time Codeforces was accessible with two hostnames codeforces.com and codeforces.ru.
You are given a list of page... | ```python
n = None
d = {}
def add(s):
global d
h = []
ind = 7
for i in s[7:]:
if (i == '/'):
break
else:
h.append(i)
ind += 1
hostname = "".join(h)
path = s[ind:]
if hostname in d:
d[hostname].append(path)
else:
d[hostn... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
248 | B | Chilly Willy | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected with them.
Chilly Willy wants to find the minimum number of length *n*, such that it is simultaneous... | A single input line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | Print a single integer — the answer to the problem without leading zeroes, or "-1" (without the quotes), if the number that meet the problem condition does not exist. | [
"1\n",
"5\n"
] | [
"-1\n",
"10080"
] | none | 1,000 | [
{
"input": "1",
"output": "-1"
},
{
"input": "5",
"output": "10080"
},
{
"input": "6",
"output": "100170"
},
{
"input": "4",
"output": "1050"
},
{
"input": "15",
"output": "100000000000110"
},
{
"input": "16",
"output": "1000000000000050"
},
{
... | 1,677,917,766 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 124 | 2,867,200 | #****************************************************
#***************Shariar Hasan************************
#**************CSE CU Batch 18***********************
#****************************************************
#import os
import sys
from math import *
#import re
#import random
sys.set_int_max_str_digits... | Title: Chilly Willy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected wit... | ```python
#****************************************************
#***************Shariar Hasan************************
#**************CSE CU Batch 18***********************
#****************************************************
#import os
import sys
from math import *
#import re
#import random
sys.set_int_max_... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,634,545,719 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 154 | 0 | from math import sqrt
a, b, c = map(int, input().split())
x = a *b / c
y = c * b / a
z = c * a / b
val = sqrt(x) + sqrt(y) + sqrt(z)
print(int(val*4)) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
from math import sqrt
a, b, c = map(int, input().split())
x = a *b / c
y = c * b / a
z = c * a / b
val = sqrt(x) + sqrt(y) + sqrt(z)
print(int(val*4))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
884 | A | Book Reading | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of seconds that Luba has to spend working during *i*-th day is *a**i*. If some free time remains, she... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=100, 1<=≤<=*t*<=≤<=106) — the number of days and the time required to read the book.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=86400) — the time Luba has to spend on her work during *i*-th day. | Print the minimum day Luba can finish reading the book.
It is guaranteed that answer doesn't exceed *n*. | [
"2 2\n86400 86398\n",
"2 86400\n0 86400\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "2 2\n86400 86398",
"output": "2"
},
{
"input": "2 86400\n0 86400",
"output": "1"
},
{
"input": "2 86400\n1 86399",
"output": "2"
},
{
"input": "100 1000000\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,509,114,145 | 1,045 | Python 3 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | num_of_days, time_reading = input().split(' ')
times = input().split(' ')
n = 0
for i in range(len(times)):
if int(times[i]) == 86400:
continue
elif int(times[i]) + int(time_reading) <= 86400:
print(i + 1)
n += 1
break
else:
continue
if n == 0... | Title: Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of ... | ```python
num_of_days, time_reading = input().split(' ')
times = input().split(' ')
n = 0
for i in range(len(times)):
if int(times[i]) == 86400:
continue
elif int(times[i]) + int(time_reading) <= 86400:
print(i + 1)
n += 1
break
else:
continue
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,576,748,803 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 109 | 0 | n,v=map(int, input().split())
a=[]
k=0
for _ in range(n):
x=list(map(int, input().rstrip().split()))
for i in range(1,len(x)):
if x[i]<v:
print(_+1,end=" ")
k=1
break
if k==0:
print(0) | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
n,v=map(int, input().split())
a=[]
k=0
for _ in range(n):
x=list(map(int, input().rstrip().split()))
for i in range(1,len(x)):
if x[i]<v:
print(_+1,end=" ")
k=1
break
if k==0:
print(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
604 | A | Uncowed Forces | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challenging tasks, Kevin was uncowed and bulldozed through all of them, distinguishing himself from the herd a... | The first line of the input contains five space-separated integers *m*1, *m*2, *m*3, *m*4, *m*5, where *m**i* (0<=≤<=*m**i*<=≤<=119) is the time of Kevin's last submission for problem *i*. His last submission is always correct and gets accepted.
The second line contains five space-separated integers *w*1, *w*2, *w*3, ... | Print a single integer, the value of Kevin's final score. | [
"20 40 60 80 100\n0 1 2 3 4\n1 0\n",
"119 119 119 119 119\n0 0 0 0 0\n10 0\n"
] | [
"4900\n",
"4930\n"
] | In the second sample, Kevin takes 119 minutes on all of the problems. Therefore, he gets <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/42158dc2bc78cd21fa679530ae9ef8b9ea298d15.png" style="max-width: 100.0%;max-height: 100.0%;"/> of the points on each problem. So his score from solving pro... | 500 | [
{
"input": "20 40 60 80 100\n0 1 2 3 4\n1 0",
"output": "4900"
},
{
"input": "119 119 119 119 119\n0 0 0 0 0\n10 0",
"output": "4930"
},
{
"input": "3 6 13 38 60\n6 10 10 3 8\n9 9",
"output": "5088"
},
{
"input": "21 44 11 68 75\n6 2 4 8 4\n2 8",
"output": "4522"
},
{... | 1,594,558,335 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 6,963,200 | a=list(map(int,input().split()))
b=list(map(int,input().split()))
c,d=map(int,input().split())
e=[500,1000,1500,2000,2500]
f=[]
g=0
for i in range(5):
f.append(max(0.3*e[i],((1-(a[i]//250))*e[i]))-50*b[i])
for j in f:
g+=j
if(c>=0):
g+=c*100
if(d>=0):
g-=d*50
print(g) | Title: Uncowed Forces
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challengin... | ```python
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c,d=map(int,input().split())
e=[500,1000,1500,2000,2500]
f=[]
g=0
for i in range(5):
f.append(max(0.3*e[i],((1-(a[i]//250))*e[i]))-50*b[i])
for j in f:
g+=j
if(c>=0):
g+=c*100
if(d>=0):
g-=d*50
print(g)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,695,717,222 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 62 | 0 | message = input().lower();check = ['a','e','i','o','u']
for i in range(len(message)):
if message[i] in check:
continue
else:
print('.' + message[i],end = "") | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
message = input().lower();check = ['a','e','i','o','u']
for i in range(len(message)):
if message[i] in check:
continue
else:
print('.' + message[i],end = "")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
304 | A | Pythagorean Theorem II | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the s... | The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above. | Print a single integer — the answer to the problem. | [
"5\n",
"74\n"
] | [
"1\n",
"35\n"
] | none | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "74",
"output": "35"
},
{
"input": "1000",
"output": "881"
},
{
"input": "586",
"output": "472"
},
{
"input": "2",
"output": "0"
},
{
"input": "362",
"output": "258"
},
{
"input": "778",
"outp... | 1,547,971,881 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 30 | 3,000 | 0 | n = int(input())
count = 0
for i in range(1, n):
for j in range(i, n):
k = (i*i + j*j)**0.5
if (int(k) == k and k <= n):
count += 1
elif(k > n):
break
print (count) | Title: Pythagorean Theorem II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the squar... | ```python
n = int(input())
count = 0
for i in range(1, n):
for j in range(i, n):
k = (i*i + j*j)**0.5
if (int(k) == k and k <= n):
count += 1
elif(k > n):
break
print (count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
632 | A | Grandma Laura and Apples | PROGRAMMING | 1,200 | [] | null | null | Grandma Laura came to the market to sell some apples. During the day she sold all the apples she had. But grandma is old, so she forgot how many apples she had brought to the market.
She precisely remembers she had *n* buyers and each of them bought exactly half of the apples she had at the moment of the purchase and ... | The first line contains two integers *n* and *p* (1<=≤<=*n*<=≤<=40,<=2<=≤<=*p*<=≤<=1000) — the number of the buyers and the cost of one apple. It is guaranteed that the number *p* is even.
The next *n* lines contains the description of buyers. Each buyer is described with the string half if he simply bought half of th... | Print the only integer *a* — the total money grandma should have at the end of the day.
Note that the answer can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | [
"2 10\nhalf\nhalfplus\n",
"3 10\nhalfplus\nhalfplus\nhalfplus\n"
] | [
"15\n",
"55\n"
] | In the first sample at the start of the day the grandma had two apples. First she sold one apple and then she sold a half of the second apple and gave a half of the second apple as a present to the second buyer. | 0 | [
{
"input": "2 10\nhalf\nhalfplus",
"output": "15"
},
{
"input": "3 10\nhalfplus\nhalfplus\nhalfplus",
"output": "55"
},
{
"input": "10 328\nhalf\nhalfplus\nhalfplus\nhalf\nhalfplus\nhalf\nhalf\nhalf\nhalfplus\nhalfplus",
"output": "258300"
},
{
"input": "1 2\nhalfplus",
"... | 1,561,345,330 | 730 | PyPy 3 | OK | TESTS | 9 | 155 | 0 | #a = list(map(int, input().strip().split()))
# from sys import stdout stdout.flush()
n, p = list(map(int, input().strip().split()))
s = []
for i in range(n):
a = str(input())
if a == "half":
s.append(0)
else:
s.append(1)
s = s[::-1]
m = 1
for i in range(1,n):
m *... | Title: Grandma Laura and Apples
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grandma Laura came to the market to sell some apples. During the day she sold all the apples she had. But grandma is old, so she forgot how many apples she had brought to the market.
She precisely remembers sh... | ```python
#a = list(map(int, input().strip().split()))
# from sys import stdout stdout.flush()
n, p = list(map(int, input().strip().split()))
s = []
for i in range(n):
a = str(input())
if a == "half":
s.append(0)
else:
s.append(1)
s = s[::-1]
m = 1
for i in range(1,n)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
869 | B | The Eternal Immortality | PROGRAMMING | 1,100 | [
"math"
] | null | null | Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like this.
The phoenix has a rather long lifespan, and reincarnates itself once every *a*! years. Here *a*! deno... | The first and only line of input contains two space-separated integers *a* and *b* (0<=≤<=*a*<=≤<=*b*<=≤<=1018). | Output one line containing a single decimal digit — the last digit of the value that interests Koyomi. | [
"2 4\n",
"0 10\n",
"107 109\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first example, the last digit of <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/99c47ca8b182f097e38094d12f0c06ce0b081b76.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2;
In the second example, the last digit of <img align="middle" class="tex-formula" src="https://espresso... | 1,000 | [
{
"input": "2 4",
"output": "2"
},
{
"input": "0 10",
"output": "0"
},
{
"input": "107 109",
"output": "2"
},
{
"input": "10 13",
"output": "6"
},
{
"input": "998244355 998244359",
"output": "4"
},
{
"input": "999999999000000000 1000000000000000000",
... | 1,507,558,950 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 77 | 819,200 |
Read = lambda:map(int, input().split())
from functools import reduce
if __name__ == '__main__':
while True:
try:
a, b = Read()
except:
break
if a == b:
print(1)
else:
print(0 if b > a + 10 else reduce(lambda x, y : x * y,... | Title: The Eternal Immortality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Even if the world is full of counterfeits, I still regard it as wonderful.
Pile up herbs and incense, and arise again from the flames and ashes of its predecessor — as is known to many, the phoenix does it like... | ```python
Read = lambda:map(int, input().split())
from functools import reduce
if __name__ == '__main__':
while True:
try:
a, b = Read()
except:
break
if a == b:
print(1)
else:
print(0 if b > a + 10 else reduce(lambda x, ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
415 | B | Mashmokh and Tokens | PROGRAMMING | 1,500 | [
"binary search",
"greedy",
"implementation",
"math"
] | null | null | Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each worker can give some of his tokens back to get a certain amount of money. The worker can save the rest o... | The first line of input contains three space-separated integers *n*,<=*a*,<=*b* (1<=≤<=*n*<=≤<=105; 1<=≤<=*a*,<=*b*<=≤<=109). The second line of input contains *n* space-separated integers *x*1,<=*x*2,<=...,<=*x**n* (1<=≤<=*x**i*<=≤<=109). | Output *n* space-separated integers. The *i*-th of them is the number of tokens Mashmokh can save on the *i*-th day. | [
"5 1 4\n12 6 11 9 1\n",
"3 1 2\n1 2 3\n",
"1 1 1\n1\n"
] | [
"0 2 3 1 1 ",
"1 0 1 ",
"0 "
] | none | 1,000 | [
{
"input": "5 1 4\n12 6 11 9 1",
"output": "0 2 3 1 1 "
},
{
"input": "3 1 2\n1 2 3",
"output": "1 0 1 "
},
{
"input": "1 1 1\n1",
"output": "0 "
},
{
"input": "1 1 1000000000\n1000000000",
"output": "0 "
},
{
"input": "1 1 1000000000\n999999999",
"output": "9... | 1,658,935,491 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 202 | 9,113,600 | from sys import stdin
def get_data(n,a,b,coins):
for co in coins:
print(((co*a)%b)//a,end=' ')
def main():
[n,a,b] = [int(x) for x in stdin.readline().split()]
coins = [int(x) for x in stdin.readline().split()]
get_data(n,a,b,coins)
main() | Title: Mashmokh and Tokens
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bimokh is Mashmokh's boss. For the following *n* days he decided to pay to his workers in a new way. At the beginning of each day he will give each worker a certain amount of tokens. Then at the end of each day each... | ```python
from sys import stdin
def get_data(n,a,b,coins):
for co in coins:
print(((co*a)%b)//a,end=' ')
def main():
[n,a,b] = [int(x) for x in stdin.readline().split()]
coins = [int(x) for x in stdin.readline().split()]
get_data(n,a,b,coins)
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
285 | A | Slightly Decreasing Permutations | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size or the length of permutation *p*1,<=<=*p*2,<=<=...,<=<=*p**n*.
The ... | The single line contains two space-separated integers: *n*,<=*k* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*k*<=<<=*n*) — the permutation length and the decreasing coefficient. | In a single line print *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* — the permutation of length *n* with decreasing coefficient *k*.
If there are several permutations that meet this condition, print any of them. It is guaranteed that the permutation with the sought parameters exists. | [
"5 2\n",
"3 0\n",
"3 2\n"
] | [
"1 5 2 4 3\n",
"1 2 3\n",
"3 2 1\n"
] | none | 500 | [
{
"input": "5 2",
"output": "1 5 2 4 3"
},
{
"input": "3 0",
"output": "1 2 3"
},
{
"input": "3 2",
"output": "3 2 1"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output": "1 2"
},
{
"input": "2 1",
"output": "2 1"
},
{
"input":... | 1,594,986,119 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 7,987,200 | n,k = map(int,input().split())
permute = []
for i in range(1,n+1):
permute.append(i)
l,r = 0,n-1
ans = []
for i in range(k):
# print(i)
ans.append(permute[r])
r -= 1
for i in permute:
if i not in ans:
ans.append(i)
for i in ans:
print(i, end=' ')
| Title: Slightly Decreasing Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=*p*2,<=<=...,<=<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. We'll denote the *i*-th element of permutat... | ```python
n,k = map(int,input().split())
permute = []
for i in range(1,n+1):
permute.append(i)
l,r = 0,n-1
ans = []
for i in range(k):
# print(i)
ans.append(permute[r])
r -= 1
for i in permute:
if i not in ans:
ans.append(i)
for i in ans:
print(i, end=' ')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
120 | B | Quiz League | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a question and the experts are allowed a minute on brainstorming and finding the right answer to the que... | The first line contains two positive integers *n* and *k* (1<=≤<=*n*<=≤<=1000 and 1<=≤<=*k*<=≤<=*n*) — the numbers of sectors on the table and the number of the sector where the arrow is pointing. The second line contains *n* numbers: *a**i*<==<=0 if the question from sector *i* has already been asked and *a**i*<==<=1 ... | Print the single number — the number of the sector containing the question the experts will be asked. It is guaranteed that the answer exists, that is that not all the questions have already been asked. | [
"5 5\n0 1 0 1 0\n",
"2 1\n1 1\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "5 5\n0 1 0 1 0",
"output": "2"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "3 2\n1 0 0",
"output": "1"
},
{
"input": "3 3\n0 1 0",
"output": "2"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "6 3\n0 0 1 1 0 1",
"output":... | 1,586,351,394 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | n,k = map(int,input().split())
l = list(map(int,input().split()))
k = k - 1
while(1):
if(l[k] == 0):
k = k + 1
k = k % n
if(l[k] == 1):
break
print(k+1)
| Title: Quiz League
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A team quiz game called "What? Where? When?" is very popular in Berland. The game is centered on two teams competing. They are the team of six Experts versus the team of the Audience. A person from the audience asks a quest... | ```python
n,k = map(int,input().split())
l = list(map(int,input().split()))
k = k - 1
while(1):
if(l[k] == 0):
k = k + 1
k = k % n
if(l[k] == 1):
break
print(k+1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,698,316,872 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 122 | 0 | s1, s2, s3 = map(int, input().split())
a = ((s1 * s3) / s2) ** 0.5
b = ((s1 * s2) / s3) ** 0.5
c = ((s2 * s3) / s1) ** 0.5
print(int(4*(a + b + c)))
| Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
s1, s2, s3 = map(int, input().split())
a = ((s1 * s3) / s2) ** 0.5
b = ((s1 * s2) / s3) ** 0.5
c = ((s2 * s3) / s1) ** 0.5
print(int(4*(a + b + c)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,696,652,270 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 124 | 0 | a,b,c,d,e,f,g,h= map(int, input().split())
ans=min(min(b*c //g,d* e),f//h) //a
print(ans)
| Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
a,b,c,d,e,f,g,h= map(int, input().split())
ans=min(min(b*c //g,d* e),f//h) //a
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
915 | A | Garden | PROGRAMMING | 900 | [
"implementation"
] | null | null | Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't wat... | The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one ... | Print one integer number — the minimum number of hours required to water the garden. | [
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] | [
"2\n",
"7\n"
] | In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | 0 | [
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 5... | 1,585,332,135 | 2,147,483,647 | PyPy 3 | OK | TESTS | 83 | 140 | 0 | # Paulo Pacitti
# RA 185447
n, k = list(map(lambda e: int(e), input().split(" ")))
buckets = list(map(lambda e: int(e), input().split(" ")))
alternatives = []
for b in buckets:
mod = k % b
q = k // b
if mod == 0:
alternatives.append(int(k // b))
print(min(alternatives))
... | Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each ... | ```python
# Paulo Pacitti
# RA 185447
n, k = list(map(lambda e: int(e), input().split(" ")))
buckets = list(map(lambda e: int(e), input().split(" ")))
alternatives = []
for b in buckets:
mod = k % b
q = k // b
if mod == 0:
alternatives.append(int(k // b))
print(min(alternatives))
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
287 | A | IQ Test | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and others are painted white. Your task is to repaint at most one cell the other color so that the... | Four lines contain four characters each: the *j*-th character of the *i*-th line equals "." if the cell in the *i*-th row and the *j*-th column of the square is painted white, and "#", if the cell is black. | Print "YES" (without the quotes), if the test can be passed and "NO" (without the quotes) otherwise. | [
"####\n.#..\n####\n....\n",
"####\n....\n####\n....\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample it is enough to repaint the first cell in the second row. After such repainting the required 2 × 2 square is on the intersection of the 1-st and 2-nd row with the 1-st and 2-nd column. | 500 | [
{
"input": "###.\n...#\n###.\n...#",
"output": "NO"
},
{
"input": ".##.\n#..#\n.##.\n#..#",
"output": "NO"
},
{
"input": ".#.#\n#.#.\n.#.#\n#.#.",
"output": "NO"
},
{
"input": "##..\n..##\n##..\n..##",
"output": "NO"
},
{
"input": "#.#.\n#.#.\n.#.#\n.#.#",
"ou... | 1,651,920,424 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 14 | 62 | 0 | s=input()
ss=input()
sss=input()
ssss=input()
l=s+ss+sss+ssss
if l.count('#')==l.count('.'):
print("NO")
else:
print("YES ") | Title: IQ Test
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and o... | ```python
s=input()
ss=input()
sss=input()
ssss=input()
l=s+ss+sss+ssss
if l.count('#')==l.count('.'):
print("NO")
else:
print("YES ")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
672 | B | Different is Good | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are different, he wants all substrings of his string *s* to be distinct. Substring is a string formed by some... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the length of the string *s*.
The second line contains the string *s* of length *n* consisting of only lowercase English letters. | If it's impossible to change the string *s* such that all its substring are distinct print -1. Otherwise print the minimum required number of changes. | [
"2\naa\n",
"4\nkoko\n",
"5\nmurat\n"
] | [
"1\n",
"2\n",
"0\n"
] | In the first sample one of the possible solutions is to change the first character to 'b'.
In the second sample, one may change the first character to 'a' and second character to 'b', so the string becomes "abko". | 1,000 | [
{
"input": "2\naa",
"output": "1"
},
{
"input": "4\nkoko",
"output": "2"
},
{
"input": "5\nmurat",
"output": "0"
},
{
"input": "6\nacbead",
"output": "1"
},
{
"input": "7\ncdaadad",
"output": "4"
},
{
"input": "25\npeoaicnbisdocqofsqdpgobpn",
"outp... | 1,631,321,564 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 62 | 6,963,200 | #672B (70No. Problem B)
n = int(input())
s = input()
t = 0
if (n > 26):
print(-1)
else:
uni = list(set(s))
ans = len(s) - len(uni)
print(ans)
| Title: Different is Good
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A wise man told Kerem "Different is good" once, so Kerem wants all things in his life to be different.
Kerem recently got a string *s* consisting of lowercase English letters. Since Kerem likes it when things are di... | ```python
#672B (70No. Problem B)
n = int(input())
s = input()
t = 0
if (n > 26):
print(-1)
else:
uni = list(set(s))
ans = len(s) - len(uni)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
88 | B | Keyboard | PROGRAMMING | 1,500 | [
"implementation"
] | B. Keyboard | 1 | 256 | Vasya learns to type. He has an unusual keyboard at his disposal: it is rectangular and it has *n* rows of keys containing *m* keys in each row. Besides, the keys are of two types. Some of the keys have lowercase Latin letters on them and some of the keys work like the "Shift" key on standard keyboards, that is, they m... | The first line contains three integers *n*, *m*, *x* (1<=≤<=*n*,<=*m*<=≤<=30,<=1<=≤<=*x*<=≤<=50).
Next *n* lines contain descriptions of all the keyboard keys. Each line contains the descriptions of exactly *m* keys, without spaces. The letter keys are marked with the corresponding lowercase letters. The "Shift" keys ... | If Vasya can type the text, then print the minimum number of times he will have to use his other hand. Otherwise, print "-1" (without the quotes). | [
"2 2 1\nab\ncd\n1\nA\n",
"2 2 1\nab\ncd\n1\ne\n",
"2 2 1\nab\ncS\n5\nabcBA\n",
"3 9 4\nqwertyuio\nasdfghjkl\nSzxcvbnmS\n35\nTheQuIcKbRoWnFOXjummsovertHeLazYDOG\n"
] | [
"-1\n",
"-1\n",
"1\n",
"2\n"
] | In the first sample the symbol "A" is impossible to print as there's no "Shift" key on the keyboard.
In the second sample the symbol "e" is impossible to print as there's no such key on the keyboard.
In the fourth sample the symbols "T", "G" are impossible to print with one hand. The other letters that are on the key... | 1,000 | [
{
"input": "2 2 1\nab\ncd\n1\nA",
"output": "-1"
},
{
"input": "2 2 1\nab\ncd\n1\ne",
"output": "-1"
},
{
"input": "2 2 1\nab\ncS\n5\nabcBA",
"output": "1"
},
{
"input": "3 9 4\nqwertyuio\nasdfghjkl\nSzxcvbnmS\n35\nTheQuIcKbRoWnFOXjummsovertHeLazYDOG",
"output": "2"
},
... | 1,582,425,048 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 109 | 307,200 | my_tap=[]
lst=[]
ans=0
import sys
z=list(map(int,input().split()))
for i in range(z[0]):
v=list(input())
lst.extend(v)
for j in range(v.count('S')):
a=v.index('S')
my_tap.append([i,a])
v[a]='.'
x=input()
for j in input():
w=0
if j.isupper() and j.lower() in lst... | Title: Keyboard
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya learns to type. He has an unusual keyboard at his disposal: it is rectangular and it has *n* rows of keys containing *m* keys in each row. Besides, the keys are of two types. Some of the keys have lowercase Latin letters on ... | ```python
my_tap=[]
lst=[]
ans=0
import sys
z=list(map(int,input().split()))
for i in range(z[0]):
v=list(input())
lst.extend(v)
for j in range(v.count('S')):
a=v.index('S')
my_tap.append([i,a])
v[a]='.'
x=input()
for j in input():
w=0
if j.isupper() and j.lowe... | 0 | MatrixStudio/Codeforces-Python-Submissions |
490 | C | Hacking Cypher | PROGRAMMING | 1,700 | [
"brute force",
"math",
"number theory",
"strings"
] | null | null | Polycarpus participates in a competition for hacking into a new secure messenger. He's almost won.
Having carefully studied the interaction protocol, Polycarpus came to the conclusion that the secret key can be obtained if he properly cuts the public key of the application into two parts. The public key is a long inte... | The first line of the input contains the public key of the messenger — an integer without leading zeroes, its length is in range from 1 to 106 digits. The second line contains a pair of space-separated positive integers *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=108). | In the first line print "YES" (without the quotes), if the method satisfying conditions above exists. In this case, next print two lines — the left and right parts after the cut. These two parts, being concatenated, must be exactly identical to the public key. The left part must be divisible by *a*, and the right part ... | [
"116401024\n97 1024\n",
"284254589153928171911281811000\n1009 1000\n",
"120\n12 1\n"
] | [
"YES\n11640\n1024\n",
"YES\n2842545891539\n28171911281811000\n",
"NO\n"
] | none | 1,500 | [
{
"input": "116401024\n97 1024",
"output": "YES\n11640\n1024"
},
{
"input": "284254589153928171911281811000\n1009 1000",
"output": "YES\n2842545891539\n28171911281811000"
},
{
"input": "120\n12 1",
"output": "NO"
},
{
"input": "604\n6 4",
"output": "YES\n60\n4"
},
{
... | 1,670,330,210 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 35 | 1,000 | 19,660,800 | #Khushal Sindhav
#Indian Institute Of Technology, Jodhpur
# 11 May 2022
def exe():
n=len(s)
sum1,sum2=0,0
l1,l2=[],[0 for i in range(n)]
for i in range(n):
# check*=10
# check+=int(s[i])
sum1*=10
sum1%=a
sum1+=int(s[i])
sum1%=a
l1.app... | Title: Hacking Cypher
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus participates in a competition for hacking into a new secure messenger. He's almost won.
Having carefully studied the interaction protocol, Polycarpus came to the conclusion that the secret key can be obtained... | ```python
#Khushal Sindhav
#Indian Institute Of Technology, Jodhpur
# 11 May 2022
def exe():
n=len(s)
sum1,sum2=0,0
l1,l2=[],[0 for i in range(n)]
for i in range(n):
# check*=10
# check+=int(s[i])
sum1*=10
sum1%=a
sum1+=int(s[i])
sum1%=a
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be sw... | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,602,421,502 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 204,800 | ans=[[1 for i in range(3)] for j in range(3)]
q=[]
for i in range(3):
q.append(list(map(int,input().split())))
for i in range(3):
for j in range(3):
if(q[i][j]%2==1):
ans[i][j]=ans[i][j]^1
if(i-1>=0):
ans[i-1][j]=ans[i-1][j]^1
if(i+1<3):
ans[i+1][j]=ans[i+1][j]^1
if(j-1>=0):
ans... | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the ... | ```python
ans=[[1 for i in range(3)] for j in range(3)]
q=[]
for i in range(3):
q.append(list(map(int,input().split())))
for i in range(3):
for j in range(3):
if(q[i][j]%2==1):
ans[i][j]=ans[i][j]^1
if(i-1>=0):
ans[i-1][j]=ans[i-1][j]^1
if(i+1<3):
ans[i+1][j]=ans[i+1][j]^1
if(j-1>=0)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
219 | A | k-String | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string... | The first input line contains integer *k* (1<=≤<=*k*<=≤<=1000). The second line contains *s*, all characters in *s* are lowercase English letters. The string length *s* satisfies the inequality 1<=≤<=|*s*|<=≤<=1000, where |*s*| is the length of string *s*. | Rearrange the letters in string *s* in such a way that the result is a *k*-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "-1" (without quotes). | [
"2\naazz\n",
"3\nabcabcabz\n"
] | [
"azaz\n",
"-1\n"
] | none | 500 | [
{
"input": "2\naazz",
"output": "azaz"
},
{
"input": "3\nabcabcabz",
"output": "-1"
},
{
"input": "1\na",
"output": "a"
},
{
"input": "2\nabba",
"output": "abab"
},
{
"input": "2\naaab",
"output": "-1"
},
{
"input": "7\nabacaba",
"output": "-1"
}... | 1,632,595,360 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 6,758,400 | k = int(input())
s =input()
x= ''.join(s[::k]*k)
print((-1,x)[sorted(s)==x]) | Title: k-String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is called a *k*-string if it can be represented as *k* concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a ... | ```python
k = int(input())
s =input()
x= ''.join(s[::k]*k)
print((-1,x)[sorted(s)==x])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
678 | D | Iterated Linear Function | PROGRAMMING | 1,700 | [
"math",
"number theory"
] | null | null | Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find the value of *g*(*n*)(*x*) modulo 109<=+<=7. | The only line contains four integers *A*, *B*, *n* and *x* (1<=≤<=*A*,<=*B*,<=*x*<=≤<=109,<=1<=≤<=*n*<=≤<=1018) — the parameters from the problem statement.
Note that the given value *n* can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you c... | Print the only integer *s* — the value *g*(*n*)(*x*) modulo 109<=+<=7. | [
"3 4 1 1\n",
"3 4 2 1\n",
"3 4 3 1\n"
] | [
"7\n",
"25\n",
"79\n"
] | none | 0 | [
{
"input": "3 4 1 1",
"output": "7"
},
{
"input": "3 4 2 1",
"output": "25"
},
{
"input": "3 4 3 1",
"output": "79"
},
{
"input": "1 1 1 1",
"output": "2"
},
{
"input": "3 10 723 6",
"output": "443623217"
},
{
"input": "14 81 51 82",
"output": "908... | 1,476,866,076 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 4,608,000 |
a, b, n, x = map(int, str(input()).split())
if a == 1 and b == 1 and n == 1 and x == 1:
print(2)
else:
mod = 10**9+7
an = pow(a,n ,mod)
print((an * x + b * ((an - 1) // (a - 1))) % mod)
| Title: Iterated Linear Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a linear function *f*(*x*)<==<=*Ax*<=+<=*B*. Let's define *g*(0)(*x*)<==<=*x* and *g*(*n*)(*x*)<==<=*f*(*g*(*n*<=-<=1)(*x*)) for *n*<=><=0. For the given integer values *A*, *B*, *n* and *x* find th... | ```python
a, b, n, x = map(int, str(input()).split())
if a == 1 and b == 1 and n == 1 and x == 1:
print(2)
else:
mod = 10**9+7
an = pow(a,n ,mod)
print((an * x + b * ((an - 1) // (a - 1))) % mod)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
779 | B | Weird Rounding | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For example, if *k*<==<=3, in the number 30020 it is enough to delete a single digit (2). In this case, t... | The only line of the input contains two integer numbers *n* and *k* (0<=≤<=*n*<=≤<=2<=000<=000<=000, 1<=≤<=*k*<=≤<=9).
It is guaranteed that the answer exists. All numbers in the input are written in traditional notation of integers, that is, without any extra leading zeros. | Print *w* — the required minimal number of digits to erase. After removing the appropriate *w* digits from the number *n*, the result should have a value that is divisible by 10*k*. The result can start with digit 0 in the single case (the result is zero and written by exactly the only digit 0). | [
"30020 3\n",
"100 9\n",
"10203049 2\n"
] | [
"1\n",
"2\n",
"3\n"
] | In the example 2 you can remove two digits: 1 and any 0. The result is number 0 which is divisible by any number. | 1,000 | [
{
"input": "30020 3",
"output": "1"
},
{
"input": "100 9",
"output": "2"
},
{
"input": "10203049 2",
"output": "3"
},
{
"input": "0 1",
"output": "0"
},
{
"input": "0 9",
"output": "0"
},
{
"input": "100 2",
"output": "0"
},
{
"input": "102... | 1,488,639,331 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 8 | 62 | 4,608,000 | number,k = input().split(' ')
if(len(number)<=int(k)):
print(len(number)-1)
else:
countZero = 0
countDelete = 0
for i in range(1,int(number)+1):
if(number[-i]=='0'):
countZero+=1
elif(countZero==int(k)):
break
else:
... | Title: Weird Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For e... | ```python
number,k = input().split(' ')
if(len(number)<=int(k)):
print(len(number)-1)
else:
countZero = 0
countDelete = 0
for i in range(1,int(number)+1):
if(number[-i]=='0'):
countZero+=1
elif(countZero==int(k)):
break
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,693,324,383 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 62 | 0 | n,r=map(int,input().split())
ans=10
for i in range(1,10):
if (n*i)%10==0 or (n*i)%10==r:
ans=i
break
print(ans) | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
n,r=map(int,input().split())
ans=10
for i in range(1,10):
if (n*i)%10==0 or (n*i)%10==r:
ans=i
break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
744 | C | Hongcow Buys a Deck of Cards | PROGRAMMING | 2,400 | [
"bitmasks",
"brute force",
"dp"
] | null | null | One day, Hongcow goes to the store and sees a brand new deck of *n* special cards. Each individual card is either red or blue. He decides he wants to buy them immediately. To do this, he needs to play a game with the owner of the store.
This game takes some number of turns to complete. On a turn, Hongcow may do one of... | The first line of input will contain a single integer *n* (1<=≤<=*n*<=≤<=16).
The next *n* lines of input will contain three tokens *c**i*, *r**i* and *b**i*. *c**i* will be 'R' or 'B', denoting the color of the card as red or blue. *r**i* will be an integer denoting the amount of red resources required to obtain the ... | Output a single integer, denoting the minimum number of turns needed to acquire all the cards. | [
"3\nR 0 1\nB 1 0\nR 1 1\n",
"3\nR 3 0\nR 2 0\nR 1 0\n"
] | [
"4\n",
"6\n"
] | For the first sample, Hongcow's four moves are as follows:
1. Collect tokens 1. Buy card 1 1. Buy card 2 1. Buy card 3
For the second sample, one optimal strategy is as follows:
1. Collect tokens 1. Collect tokens 1. Buy card 2 1. Collect tokens 1. Buy card 3 1. Buy card 1 | 1,750 | [
{
"input": "3\nR 0 1\nB 1 0\nR 1 1",
"output": "4"
},
{
"input": "3\nR 3 0\nR 2 0\nR 1 0",
"output": "6"
},
{
"input": "8\nB 0 1\nR 2 3\nB 2 1\nR 4 2\nB 1 3\nB 1 10\nB 3 4\nR 3 4",
"output": "17"
},
{
"input": "16\nR 10000000 10000000\nR 10000000 10000000\nR 10000000 10000000... | 1,482,324,627 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 109 | 23,142,400 | re=0
bl=0
count=0
for i in range(int(input())):
s,r,b=input().split()
r=int(r)
b=int(b)
if(r>b):
if(re<r):
count+=(r-re+1)
re+=r
bl+=r-re
else:
count+=1
else:
if(bl<b):
count+=(r-re+1)
bl... | Title: Hongcow Buys a Deck of Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, Hongcow goes to the store and sees a brand new deck of *n* special cards. Each individual card is either red or blue. He decides he wants to buy them immediately. To do this, he needs to play a gam... | ```python
re=0
bl=0
count=0
for i in range(int(input())):
s,r,b=input().split()
r=int(r)
b=int(b)
if(r>b):
if(re<r):
count+=(r-re+1)
re+=r
bl+=r-re
else:
count+=1
else:
if(bl<b):
count+=(r-re+1)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,651,174,057 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | n=int(input())
l=list(map(int,input().split()))
ans="YES"
c25=0
c50=0
for i in l:
if(i==25):
c+=1
elif(i==50):
if(c25>=1):
c50+=1
else:
ans="NO"
break
else:
if(c25>=3 or(c50>=1 and c25>=1)):
pass
else:
... | Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the bookin... | ```python
n=int(input())
l=list(map(int,input().split()))
ans="YES"
c25=0
c50=0
for i in l:
if(i==25):
c+=1
elif(i==50):
if(c25>=1):
c50+=1
else:
ans="NO"
break
else:
if(c25>=3 or(c50>=1 and c25>=1)):
pass
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
456 | B | Fedya and Maths | PROGRAMMING | 1,200 | [
"math",
"number theory"
] | null | null | Fedya studies in a gymnasium. Fedya's maths hometask is to calculate the following expression:
for given value of *n*. Fedya managed to complete the task. Can you? Note that given number *n* can be extremely large (e.g. it can exceed any integer type of your programming language). | The single line contains a single integer *n* (0<=≤<=*n*<=≤<=10105). The number doesn't contain any leading zeroes. | Print the value of the expression without leading zeros. | [
"4\n",
"124356983594583453458888889\n"
] | [
"4\n",
"0\n"
] | Operation *x* *mod* *y* means taking remainder after division *x* by *y*.
Note to the first sample:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/825f244180bb10323db01645118c3cfdb312fa89.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4",
"output": "4"
},
{
"input": "124356983594583453458888889",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "7854",
"output": "0"
},
{
"input": "584660",
"output": "4"
},
{
"input": "464",
"output": "4"
},
{
"inp... | 1,684,928,791 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 295 | 7,168,000 | n=int(input())
print(4 if n % 4 == 0 else 0) | Title: Fedya and Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fedya studies in a gymnasium. Fedya's maths hometask is to calculate the following expression:
for given value of *n*. Fedya managed to complete the task. Can you? Note that given number *n* can be extremely large (e.g... | ```python
n=int(input())
print(4 if n % 4 == 0 else 0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
630 | A | Again Twenty Five! | PROGRAMMING | 800 | [
"number theory"
] | null | null | The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and get last two digits of the number. Yes, of course, *n* can be rather big, and one cannot find the power us... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·1018) — the power in which you need to raise number 5. | Output the last two digits of 5*n* without spaces between them. | [
"2\n"
] | [
"25"
] | none | 0 | [
{
"input": "2",
"output": "25"
},
{
"input": "7",
"output": "25"
},
{
"input": "1000000000000000000",
"output": "25"
},
{
"input": "2000000000000000000",
"output": "25"
},
{
"input": "987654321012345678",
"output": "25"
}
] | 1,692,534,964 | 2,147,483,647 | Python 3 | OK | TESTS | 5 | 30 | 0 | n = int(input())
if n>=2:
print("25") | Title: Again Twenty Five!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of *n* and ge... | ```python
n = int(input())
if n>=2:
print("25")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and ... | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five l... | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,562,055,659 | 2,147,483,647 | PyPy 3 | OK | TESTS | 79 | 170 | 102,400 | l,r,a = map(int, input().split())
if l>r:
t = l
l = r
r = t
p = r-l;
if p>=a:
l += a
else:
l = r
l+=int((a-p)//2)
print(l*2)
| Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.... | ```python
l,r,a = map(int, input().split())
if l>r:
t = l
l = r
r = t
p = r-l;
if p>=a:
l += a
else:
l = r
l+=int((a-p)//2)
print(l*2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.