contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
644 | A | Parliament of Berland | PROGRAMMING | 1,000 | [
"*special",
"constructive algorithms"
] | null | null | There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republicans.
New parliament assembly hall is a rectangle consisting of *a*<=×<=*b* chairs — *a* rows of *b* chair... | The first line of the input contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=10<=000, 1<=≤<=*a*,<=*b*<=≤<=100) — the number of parliamentarians, the number of rows in the assembly hall and the number of seats in each row, respectively. | If there is no way to assigns seats to parliamentarians in a proper way print -1.
Otherwise print the solution in *a* lines, each containing *b* integers. The *j*-th integer of the *i*-th line should be equal to the index of parliamentarian occupying this seat, or 0 if this seat should remain empty. If there are multi... | [
"3 2 2\n",
"8 4 3\n",
"10 2 2\n"
] | [
"0 3\n1 2\n",
"7 8 3\n0 1 4\n6 0 5\n0 2 0\n",
"-1\n"
] | In the first sample there are many other possible solutions. For example,
and
The following assignment
is incorrect, because parliamentarians 1 and 3 are both from Democrats party but will occupy neighbouring seats. | 500 | [
{
"input": "3 2 2",
"output": "1 2 \n0 3 "
},
{
"input": "8 4 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 \n0 0 0 "
},
{
"input": "10 2 2",
"output": "-1"
},
{
"input": "1 1 1",
"output": "1 "
},
{
"input": "8 3 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 "
},
{
"in... | 1,458,121,865 | 3,065 | Python 3 | WRONG_ANSWER | TESTS | 16 | 78 | 512,000 | n,a,b = map(int,input().split())
if n > a * b:
print(-1)
else:
z = 0
if a % 2 != 0:
for i in range(a):
for j in range(1,b+1):
if z == n:
print(0,end = " ")
else:
print(i*(b)+j,end=" ")
... | Title: Parliament of Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republi... | ```python
n,a,b = map(int,input().split())
if n > a * b:
print(-1)
else:
z = 0
if a % 2 != 0:
for i in range(a):
for j in range(1,b+1):
if z == n:
print(0,end = " ")
else:
print(i*(b)+j,end=" ")
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
355 | A | Vasya and Digital Root | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<... | The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9). | In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes. | [
"4 4\n",
"5 1\n",
"1 0\n"
] | [
"5881\n",
"36172\n",
"0\n"
] | For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | 500 | [
{
"input": "4 4",
"output": "5881"
},
{
"input": "5 1",
"output": "36172"
},
{
"input": "1 0",
"output": "0"
},
{
"input": "8 7",
"output": "49722154"
},
{
"input": "487 0",
"output": "No solution"
},
{
"input": "1000 5",
"output": "854193955406789... | 1,567,662,650 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 139 | 512,000 | ######################################################################
# Write your code here
import sys
from math import *
input = sys.stdin.readline
#import resource
#resource.setrlimit(resource.RLIMIT_STACK, [0x10000000, resource.RLIM_INFINITY])
#sys.setrecursionlimit(0x100000)
# Write your code here
RI = l... | Title: Vasya and Digital Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=... | ```python
######################################################################
# Write your code here
import sys
from math import *
input = sys.stdin.readline
#import resource
#resource.setrlimit(resource.RLIMIT_STACK, [0x10000000, resource.RLIM_INFINITY])
#sys.setrecursionlimit(0x100000)
# Write your code he... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
999 | B | Reversing Encryption | PROGRAMMING | 900 | [
"implementation"
] | null | null | A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$ (i.e. the substring which starts at position $1$ and ends at position $d$).
For example, the above algor... | The first line of input consists of a single integer $n$ ($1 \le n \le 100$) — the length of the string $t$. The second line of input consists of the string $t$. The length of $t$ is $n$, and it consists only of lowercase Latin letters. | Print a string $s$ such that the above algorithm results in $t$. | [
"10\nrocesfedoc\n",
"16\nplmaetwoxesisiht\n",
"1\nz\n"
] | [
"codeforces\n",
"thisisexampletwo\n",
"z\n"
] | The first example is described in the problem statement. | 0 | [
{
"input": "10\nrocesfedoc",
"output": "codeforces"
},
{
"input": "16\nplmaetwoxesisiht",
"output": "thisisexampletwo"
},
{
"input": "1\nz",
"output": "z"
},
{
"input": "2\nir",
"output": "ri"
},
{
"input": "3\nilj",
"output": "jli"
},
{
"input": "4\nj... | 1,673,534,847 | 2,727 | PyPy 3-64 | OK | TESTS | 20 | 61 | 0 | n = int(input())
a = input()
for i in range(n):
if n % (i+1) == 0:
tmp = a[:i+1]
tmp = tmp[::-1]
a = tmp + a[i + 1:]
print(a) | Title: Reversing Encryption
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string $s$ of length $n$ can be encrypted by the following algorithm:
- iterate over all divisors of $n$ in decreasing order (i.e. from $n$ to $1$), - for each divisor $d$, reverse the substring $s[1 \dots d]$... | ```python
n = int(input())
a = input()
for i in range(n):
if n % (i+1) == 0:
tmp = a[:i+1]
tmp = tmp[::-1]
a = tmp + a[i + 1:]
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
128 | B | String | PROGRAMMING | 2,100 | [
"brute force",
"constructive algorithms",
"hashing",
"implementation",
"string suffix structures",
"strings"
] | null | null | One day in the IT lesson Anna and Maria learned about the lexicographic order.
String *x* is lexicographically less than string *y*, if either *x* is a prefix of *y* (and *x*<=≠<=*y*), or there exists such *i* (1<=≤<=*i*<=≤<=*min*(|*x*|,<=|*y*|)), that *x**i*<=<<=*y**i*, and for any *j* (1<=≤<=*j*<=<<=*i*) *x**j... | The first line contains a non-empty string that only consists of small Latin letters ("a"-"z"), whose length does not exceed 105. The second line contains the only integer *k* (1<=≤<=*k*<=≤<=105). | Print the string Anna and Maria need — the *k*-th (in the lexicographical order) substring of the given string. If the total number of substrings is less than *k*, print a string saying "No such line." (without the quotes). | [
"aa\n2\n",
"abc\n5\n",
"abab\n7\n"
] | [
"a\n",
"bc\n",
"b\n"
] | In the second sample before string "bc" follow strings "a", "ab", "abc", "b". | 1,500 | [
{
"input": "aa\n2",
"output": "a"
},
{
"input": "abc\n5",
"output": "bc"
},
{
"input": "abab\n7",
"output": "b"
},
{
"input": "codeforces\n1",
"output": "c"
},
{
"input": "cccc\n8",
"output": "ccc"
},
{
"input": "abcdefghijklmnopqrstuvwxyz\n27",
"o... | 1,462,933,211 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 154 | 5,017,600 | import math
from collections import *
from heapq import *
s=input()
k=int(input())
h=[]
l=0
n=len(s)
if k>(n*(n+1)/2):
print("No such line.")
else:
k0=k
while l<len(s) and k0>0:
for i in range(len(s)-l):
h.append(s[i:i+l+1])
l+=1
k0-=len(s)-l
h.sort... | Title: String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day in the IT lesson Anna and Maria learned about the lexicographic order.
String *x* is lexicographically less than string *y*, if either *x* is a prefix of *y* (and *x*<=≠<=*y*), or there exists such *i* (1<=≤<=*i*<=≤<=*m... | ```python
import math
from collections import *
from heapq import *
s=input()
k=int(input())
h=[]
l=0
n=len(s)
if k>(n*(n+1)/2):
print("No such line.")
else:
k0=k
while l<len(s) and k0>0:
for i in range(len(s)-l):
h.append(s[i:i+l+1])
l+=1
k0-=len(s)-l
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
31 | A | Worms Evolution | PROGRAMMING | 1,200 | [
"implementation"
] | A. Worms Evolution | 2 | 256 | Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his theory, professor needs to find 3 different forms that the length of the first form is equal to ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of worm's forms. The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000) — lengths of worms of each form. | Output 3 distinct integers *i* *j* *k* (1<=≤<=*i*,<=*j*,<=*k*<=≤<=*n*) — such indexes of worm's forms that *a**i*<==<=*a**j*<=+<=*a**k*. If there is no such triple, output -1. If there are several solutions, output any of them. It possible that *a**j*<==<=*a**k*. | [
"5\n1 2 3 5 7\n",
"5\n1 8 1 5 1\n"
] | [
"3 2 1\n",
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 5 7",
"output": "3 2 1"
},
{
"input": "5\n1 8 1 5 1",
"output": "-1"
},
{
"input": "4\n303 872 764 401",
"output": "-1"
},
{
"input": "6\n86 402 133 524 405 610",
"output": "6 4 1"
},
{
"input": "8\n217 779 418 895 996 473 3 22",
"output":... | 1,662,614,986 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n = int(input())
a = list(map(int, input().split()))
found = False
for i in range(n):
if found:
break
for j in range(n):
if found:
break
if j == i:
continue
for k in range(n):
if k == j or k == i:
continue
if a[i] =... | Title: Worms Evolution
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his... | ```python
n = int(input())
a = list(map(int, input().split()))
found = False
for i in range(n):
if found:
break
for j in range(n):
if found:
break
if j == i:
continue
for k in range(n):
if k == j or k == i:
continue
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
518 | B | Tanya and Postcard | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"strings"
] | null | null | Little Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string *s* of length *n*, consisting of uppercase and lowercase English letters. Tanya can't write yet, so she found a newspaper and decided to cut out the letters and glue them into the postcard to achieve string *s... | The first line contains line *s* (1<=≤<=|*s*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text of Tanya's message.
The second line contains line *t* (|*s*|<=≤<=|*t*|<=≤<=2·105), consisting of uppercase and lowercase English letters — the text written in the newspaper.
Here |*a*| means the ... | Print two integers separated by a space:
- the first number is the number of times Tanya shouts "YAY!" while making the message, - the second number is the number of times Tanya says "WHOOPS" while making the message. | [
"AbC\nDCbA\n",
"ABC\nabc\n",
"abacaba\nAbaCaBA\n"
] | [
"3 0\n",
"0 3\n",
"3 4\n"
] | none | 1,000 | [
{
"input": "AbC\nDCbA",
"output": "3 0"
},
{
"input": "ABC\nabc",
"output": "0 3"
},
{
"input": "abacaba\nAbaCaBA",
"output": "3 4"
},
{
"input": "zzzzz\nZZZZZ",
"output": "0 5"
},
{
"input": "zzzZZZ\nZZZzzZ",
"output": "5 1"
},
{
"input": "abcdefghijk... | 1,627,389,391 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 54,886,400 | from functools import cmp_to_key
from string import ascii_lowercase as al
def mycmp(a, b):
if al.index(a.lower()) < al.index(b.lower()):
return -1
if al.index(a.lower()) > al.index(b.lower()):
return 1
if a == b:
return 0
if a.upper() == a:
return -1
return... | Title: Tanya and Postcard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string *s* of length *n*, consisting of uppercase and lowercase English letters. Tanya can't write yet, so she f... | ```python
from functools import cmp_to_key
from string import ascii_lowercase as al
def mycmp(a, b):
if al.index(a.lower()) < al.index(b.lower()):
return -1
if al.index(a.lower()) > al.index(b.lower()):
return 1
if a == b:
return 0
if a.upper() == a:
return -1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,685,073,197 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | s=input()
t=input()
is_rev=True
for c,d in zip(s,reversed(t)):
if c!=d:
is_rev=False
break
if is_rev:
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s=input()
t=input()
is_rev=True
for c,d in zip(s,reversed(t)):
if c!=d:
is_rev=False
break
if is_rev:
print("YES")
else:
print("NO")
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,647,149,973 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a=str(input())
b=""
for i in range (0,len(a)-1):
if (a[i]=="."):
b=b+str(0)
elif(a[i]=="-"):
if(a[i+1]=="."):
b=b+str(1)
if(a[i+1]=="-"):
b=b+str(2)
if(a[len(a)-1]=="." and a[len(a)-2]!="-"):
b=b+str(0)
print(b)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
a=str(input())
b=""
for i in range (0,len(a)-1):
if (a[i]=="."):
b=b+str(0)
elif(a[i]=="-"):
if(a[i+1]=="."):
b=b+str(1)
if(a[i+1]=="-"):
b=b+str(2)
if(a[len(a)-1]=="." and a[len(a)-2]!="-"):
b=b+str(0)
print(b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many w... | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,589,441,715 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 108 | 6,656,000 | a,b = map(int,input().split())
a1 = 0
t = 0
b1 = 0
for i in range(1,7):
if abs(a-i)<abs(b-i):
a1 = a1+1
elif abs(a-i)>abs(b-i):
b1 = b1+1
else:
t = t+1
print(a1,t,b1)
| Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same diff... | ```python
a,b = map(int,input().split())
a1 = 0
t = 0
b1 = 0
for i in range(1,7):
if abs(a-i)<abs(b-i):
a1 = a1+1
elif abs(a-i)>abs(b-i):
b1 = b1+1
else:
t = t+1
print(a1,t,b1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,644,199,448 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
a = set([int(i) for i in input().split()])
a.remove(0)
print(len(a) if len(a) > 1 else 1) | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n = int(input())
a = set([int(i) for i in input().split()])
a.remove(0)
print(len(a) if len(a) > 1 else 1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
954 | A | Diagonal Walking | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace an... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence. The second line contains the sequence consisting of *n* characters U and R. | Print the minimum possible length of the sequence of moves after all replacements are done. | [
"5\nRUURU\n",
"17\nUUURRRRRUUURURUUU\n"
] | [
"3\n",
"13\n"
] | In the first test the shortened sequence of moves may be DUD (its length is 3).
In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13). | 0 | [
{
"input": "5\nRUURU",
"output": "3"
},
{
"input": "17\nUUURRRRRUUURURUUU",
"output": "13"
},
{
"input": "100\nUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU",
"output": "100"
},
{
"input": "100\nRRURRUUUURURRRURRRRURRRRRR... | 1,677,950,373 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n = int(input())
moves = input()
num_pairs = moves.count("RU") + moves.count("UR")
shortest_length = n - num_pairs
print(shortest_length)
| Title: Diagonal Walking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence movi... | ```python
n = int(input())
moves = input()
num_pairs = moves.count("RU") + moves.count("UR")
shortest_length = n - num_pairs
print(shortest_length)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
686 | A | Free Ice Cream | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, people start standing in the queue before Kay and Gerda's house even in the night. Each person in the... | The first line contains two space-separated integers *n* and *x* (1<=≤<=*n*<=≤<=1000, 0<=≤<=*x*<=≤<=109).
Each of the next *n* lines contains a character '+' or '-', and an integer *d**i*, separated by a space (1<=≤<=*d**i*<=≤<=109). Record "+ *d**i*" in *i*-th line means that a carrier with *d**i* ice cream packs occ... | Print two space-separated integers — number of ice cream packs left after all operations, and number of kids that left the house in distress. | [
"5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20\n",
"5 17\n- 16\n- 2\n- 98\n+ 100\n- 98\n"
] | [
"22 1\n",
"3 2\n"
] | Consider the first sample.
1. Initially Kay and Gerda have 7 packs of ice cream. 1. Carrier brings 5 more, so now they have 12 packs. 1. A kid asks for 10 packs and receives them. There are only 2 packs remaining. 1. Another kid asks for 20 packs. Kay and Gerda do not have them, so the kid goes away distressed. 1.... | 500 | [
{
"input": "5 7\n+ 5\n- 10\n- 20\n+ 40\n- 20",
"output": "22 1"
},
{
"input": "5 17\n- 16\n- 2\n- 98\n+ 100\n- 98",
"output": "3 2"
},
{
"input": "6 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000\n+ 1000000000",
"output": "7000000000 0"
},
{
... | 1,645,997,943 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | people, packs = map(int, input().split())
sad = 0
for i in range(people):
state, amount = map(str, input().split())
if state == "+":
packs += int(amount)
else:
if packs >= int(amount):
packs -= int(amount)
else:
sad += 1
print(packs, sad)
| Title: Free Ice Cream
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After their adventure with the magic mirror Kay and Gerda have returned home and sometimes give free ice cream to kids in the summer.
At the start of the day they have *x* ice cream packs. Since the ice cream is free, p... | ```python
people, packs = map(int, input().split())
sad = 0
for i in range(people):
state, amount = map(str, input().split())
if state == "+":
packs += int(amount)
else:
if packs >= int(amount):
packs -= int(amount)
else:
sad += 1
print(packs, sad)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
485 | A | Factory | PROGRAMMING | 1,400 | [
"implementation",
"math",
"matrices"
] | null | null | One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the factory has to produce (remainder after dividing *x* by *m*) more details. Unfortunately, no cu... | The first line contains two integers *a* and *m* (1<=≤<=*a*,<=*m*<=≤<=105). | Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No". | [
"1 5\n",
"3 6\n"
] | [
"No\n",
"Yes\n"
] | none | 1,000 | [
{
"input": "1 5",
"output": "No"
},
{
"input": "3 6",
"output": "Yes"
},
{
"input": "1 8",
"output": "Yes"
},
{
"input": "2 3",
"output": "No"
},
{
"input": "3 24",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "100000 ... | 1,589,217,096 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 109 | 6,656,000 | n,m=map(int,input().split())
if m%2==0:
while m%2==0:
m=m//2
if n%m==0:
print("Yes")
else:
print("No") | Title: Factory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the fac... | ```python
n,m=map(int,input().split())
if m%2==0:
while m%2==0:
m=m//2
if n%m==0:
print("Yes")
else:
print("No")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
876 | A | Trip For Meal | PROGRAMMING | 900 | [
"math"
] | null | null | Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is *a* meters, between Rabbit's ... | First line contains an integer *n* (1<=≤<=*n*<=≤<=100) — number of visits.
Second line contains an integer *a* (1<=≤<=*a*<=≤<=100) — distance between Rabbit's and Owl's houses.
Third line contains an integer *b* (1<=≤<=*b*<=≤<=100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer *c* ... | Output one number — minimum distance in meters Winnie must go through to have a meal *n* times. | [
"3\n2\n3\n1\n",
"1\n2\n3\n5\n"
] | [
"3\n",
"0\n"
] | In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | 500 | [
{
"input": "3\n2\n3\n1",
"output": "3"
},
{
"input": "1\n2\n3\n5",
"output": "0"
},
{
"input": "10\n1\n8\n3",
"output": "9"
},
{
"input": "7\n10\n5\n6",
"output": "30"
},
{
"input": "9\n9\n7\n5",
"output": "42"
},
{
"input": "9\n37\n85\n76",
"outpu... | 1,508,152,383 | 483 | PyPy 3 | OK | TESTS | 48 | 139 | 23,142,400 | n = int(input())
a = int(input())
b = int(input())
c = int(input())
if n == 1:
print(0)
else:
ans = min(a, b)
n -= 2
if a <= b:
ans = ans + n * min(a, c)
else:
ans = ans + n * min(b, c)
print(ans)
| Title: Trip For Meal
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair... | ```python
n = int(input())
a = int(input())
b = int(input())
c = int(input())
if n == 1:
print(0)
else:
ans = min(a, b)
n -= 2
if a <= b:
ans = ans + n * min(a, c)
else:
ans = ans + n * min(b, c)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following moves. During each move, either Alice or Bob (the player whose turn is the current) can choose two ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100) — the initial number of elements in the set. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the set. | Print a single line with the winner's name. If Alice wins print "Alice", otherwise print "Bob" (without quotes). | [
"2\n2 3\n",
"2\n5 3\n",
"3\n5 6 7\n"
] | [
"Alice\n",
"Alice\n",
"Bob\n"
] | Consider the first test sample. Alice moves first, and the only move she can do is to choose 2 and 3, then to add 1 to the set. Next Bob moves, there is no valid move anymore, so the winner is Alice. | 0 | [
{
"input": "2\n2 3",
"output": "Alice"
},
{
"input": "2\n5 3",
"output": "Alice"
},
{
"input": "3\n5 6 7",
"output": "Bob"
},
{
"input": "10\n72 96 24 66 6 18 12 30 60 48",
"output": "Bob"
},
{
"input": "10\n78 66 6 60 18 84 36 96 72 48",
"output": "Bob"
},
... | 1,379,692,896 | 1,896 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 92 | 0 | n = int(input())
input()
print('Alice' * (1 - n % 2) + 'Bob' * (n % 2))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following moves. Du... | ```python
n = int(input())
input()
print('Alice' * (1 - n % 2) + 'Bob' * (n % 2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
291 | A | Spyke Talks | PROGRAMMING | 800 | [
"*special",
"implementation",
"sortings"
] | null | null | Polycarpus is the director of a large corporation. There are *n* secretaries working for the corporation, each of them corresponds via the famous Spyke VoIP system during the day. We know that when two people call each other via Spyke, the Spyke network assigns a unique ID to this call, a positive integer session numbe... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the number of secretaries in Polycarpus's corporation. The next line contains *n* space-separated integers: *id*1,<=*id*2,<=...,<=*id**n* (0<=≤<=*id**i*<=≤<=109). Number *id**i* equals the number of the call session of the *i*-th secretary, if the secretary is t... | Print a single integer — the number of pairs of chatting secretaries, or -1 if Polycarpus's got a mistake in his records and the described situation could not have taken place. | [
"6\n0 1 7 1 7 10\n",
"3\n1 1 1\n",
"1\n0\n"
] | [
"2\n",
"-1\n",
"0\n"
] | In the first test sample there are two Spyke calls between secretaries: secretary 2 and secretary 4, secretary 3 and secretary 5.
In the second test sample the described situation is impossible as conferences aren't allowed. | 500 | [
{
"input": "6\n0 1 7 1 7 10",
"output": "2"
},
{
"input": "3\n1 1 1",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "5\n2 2 1 1 3",
"output": "2"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n4 21 3 21 21 1 1 2 2 3",
"ou... | 1,600,075,763 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 186 | 307,200 | n=int(input())
arr=list(map(int,input().strip().split()))
seta=set(arr)
zero=arr.count(0)
count=0
flag=0
if(zero==n):
print(count)
exit()
else:
for i in range(zero):
arr.remove(0)
if(i==0):
seta.remove(0)
for i in seta:
if(arr.count(i)==2):
... | Title: Spyke Talks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus is the director of a large corporation. There are *n* secretaries working for the corporation, each of them corresponds via the famous Spyke VoIP system during the day. We know that when two people call each othe... | ```python
n=int(input())
arr=list(map(int,input().strip().split()))
seta=set(arr)
zero=arr.count(0)
count=0
flag=0
if(zero==n):
print(count)
exit()
else:
for i in range(zero):
arr.remove(0)
if(i==0):
seta.remove(0)
for i in seta:
if(arr.count(i)==2):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,659,441,149 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 78 | 0 | b = list(map(int, input().split()))#first string
n=input()
sums = 0# summ
for n in n:
sums += b[int(n)-1]
print(sums)
| Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
b = list(map(int, input().split()))#first string
n=input()
sums = 0# summ
for n in n:
sums += b[int(n)-1]
print(sums)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
743 | A | Vladik and flights | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | Vladik is a competitive programmer. This year he is going to win the International Olympiad in Informatics. But it is not as easy as it sounds: the question Vladik face now is to find the cheapest way to get to the olympiad.
Vladik knows *n* airports. All the airports are located on a straight line. Each airport has u... | The first line contains three integers *n*, *a*, and *b* (1<=≤<=*n*<=≤<=105, 1<=≤<=*a*,<=*b*<=≤<=*n*) — the number of airports, the id of the airport from which Vladik starts his route and the id of the airport which he has to reach.
The second line contains a string with length *n*, which consists only of characters... | Print single integer — the minimum cost Vladik has to pay to get to the olympiad. | [
"4 1 4\n1010\n",
"5 5 2\n10110\n"
] | [
"1",
"0"
] | In the first example Vladik can fly to the airport 2 at first and pay |1 - 2| = 1 (because the airports belong to different companies), and then fly from the airport 2 to the airport 4 for free (because the airports belong to the same company). So the cost of the whole flight is equal to 1. It's impossible to get to th... | 500 | [
{
"input": "4 1 4\n1010",
"output": "1"
},
{
"input": "5 5 2\n10110",
"output": "0"
},
{
"input": "10 9 5\n1011111001",
"output": "1"
},
{
"input": "7 3 7\n1110111",
"output": "0"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 3 3\n100101101... | 1,558,531,767 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | n, a, b = map(int, input().strip().split())
s = input().strip()
a -= 1
b -= 1
if s[a] == s[b]:
print(0)
quit()
a1 = 1e5+1
for i in range(b, n):
if s[i] == s[a]:
a1 = i-b
break
a2 = 1e5+1
for i in range(b-1, -1, -1):
if s[i] == s[a]:
a2 = b-i
break
print(min(a1, a2, abs(b-a))) | Title: Vladik and flights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vladik is a competitive programmer. This year he is going to win the International Olympiad in Informatics. But it is not as easy as it sounds: the question Vladik face now is to find the cheapest way to get to the o... | ```python
n, a, b = map(int, input().strip().split())
s = input().strip()
a -= 1
b -= 1
if s[a] == s[b]:
print(0)
quit()
a1 = 1e5+1
for i in range(b, n):
if s[i] == s[a]:
a1 = i-b
break
a2 = 1e5+1
for i in range(b-1, -1, -1):
if s[i] == s[a]:
a2 = b-i
break
print(min(a1, a2, abs(b-a)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
394 | A | Counting Sticks | PROGRAMMING | 0 | [
"brute force",
"implementation"
] | null | null | When new students come to the Specialized Educational and Scientific Centre (SESC) they need to start many things from the beginning. Sometimes the teachers say (not always unfairly) that we cannot even count. So our teachers decided to teach us arithmetics from the start. And what is the best way to teach students add... | The single line contains the initial expression. It is guaranteed that the expression looks like *A*<=+<=*B*<==<=*C*, where 1<=≤<=*A*,<=*B*,<=*C*<=≤<=100. | If there isn't a way to shift the stick so the expression becomes correct, print on a single line "Impossible" (without the quotes). If there is a way, print the resulting expression. Follow the format of the output from the test samples. Don't print extra space characters.
If there are multiple correct answers, print... | [
"||+|=|||||\n",
"|||||+||=||\n",
"|+|=||||||\n",
"||||+||=||||||\n"
] | [
"|||+|=||||\n",
"Impossible\n",
"Impossible\n",
"||||+||=||||||\n"
] | In the first sample we can shift stick from the third group of sticks to the first one.
In the second sample we cannot shift vertical stick from + sign to the second group of sticks. So we cannot make a - sign.
There is no answer in the third sample because we cannot remove sticks from the expression.
In the forth s... | 500 | [
{
"input": "||+|=|||||",
"output": "|||+|=||||"
},
{
"input": "|||||+||=||",
"output": "Impossible"
},
{
"input": "|+|=||||||",
"output": "Impossible"
},
{
"input": "||||+||=||||||",
"output": "||||+||=||||||"
},
{
"input": "||||||||||||+|||||||||||=||||||||||||||... | 1,679,564,663 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 21 | 46 | 0 | s = input()
# find the indices of the sticks and the equality sign
plus_idx = s.index('+')
equal_idx = s.index('=')
# count the number of sticks before the plus sign, after the plus sign, and after the equality sign
a = plus_idx
b = equal_idx - plus_idx - 1
c = len(s) - equal_idx - 1
# check if A + B = C
... | Title: Counting Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When new students come to the Specialized Educational and Scientific Centre (SESC) they need to start many things from the beginning. Sometimes the teachers say (not always unfairly) that we cannot even count. So our te... | ```python
s = input()
# find the indices of the sticks and the equality sign
plus_idx = s.index('+')
equal_idx = s.index('=')
# count the number of sticks before the plus sign, after the plus sign, and after the equality sign
a = plus_idx
b = equal_idx - plus_idx - 1
c = len(s) - equal_idx - 1
# check if ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
245 | B | Internet Address | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
where:
- <protocol> can equal either "http" (without the quotes) or "ftp" (without the quotes), - <domain> is a no... | The first line contains a non-empty string that Vasya wrote out in his notebook. This line consists of lowercase English letters only.
It is guaranteed that the given string contains at most 50 letters. It is guaranteed that the given string can be obtained from some correct Internet resource address, described above... | Print a single line — the address of the Internet resource that Vasya liked. If there are several addresses that meet the problem limitations, you are allowed to print any of them. | [
"httpsunrux\n",
"ftphttprururu\n"
] | [
"http://sun.ru/x\n",
"ftp://http.ru/ruru\n"
] | In the second sample there are two more possible answers: "ftp://httpruru.ru" and "ftp://httpru.ru/ru". | 0 | [
{
"input": "httpsunrux",
"output": "http://sun.ru/x"
},
{
"input": "ftphttprururu",
"output": "ftp://http.ru/ruru"
},
{
"input": "httpuururrururruruurururrrrrurrurrurruruuruuu",
"output": "http://uu.ru/rrururruruurururrrrrurrurrurruruuruuu"
},
{
"input": "httpabuaruauabbaruru... | 1,679,368,698 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | #F
# <protocol>://<domain>.ru[/<context>]
# httpsunrux ---> http://sun.ru/x
# ftphttprururu --> ftp://http.ru/ruru
import networkx as nx
s = input()
ans = ""
if s[0] == 'h':
ans += s[0:4]
else:
ans += s[0:3]
x = len(ans)
ans += "://"
for i in range(len(s)-1):
if(s[i] == 'r' and s[i+1] == 'u'):
... | Title: Internet Address
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is an active Internet user. One day he came across an Internet resource he liked, so he wrote its address in the notebook. We know that the address of the written resource has format:
where:
- <protocol>... | ```python
#F
# <protocol>://<domain>.ru[/<context>]
# httpsunrux ---> http://sun.ru/x
# ftphttprururu --> ftp://http.ru/ruru
import networkx as nx
s = input()
ans = ""
if s[0] == 'h':
ans += s[0:4]
else:
ans += s[0:3]
x = len(ans)
ans += "://"
for i in range(len(s)-1):
if(s[i] == 'r' and s[i+1] ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,676,811,479 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 46 | 0 | problems, time = [int(s) for s in input().split()]
count = 0
for i in range(1, problems + 1):
# adds the time it takes to complete the problem to the time to arrive
time += 5 * i
# if the total time is more than or equal to 4 hours (240 minutes)
if time > 240:
# breaks
break
... | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
problems, time = [int(s) for s in input().split()]
count = 0
for i in range(1, problems + 1):
# adds the time it takes to complete the problem to the time to arrive
time += 5 * i
# if the total time is more than or equal to 4 hours (240 minutes)
if time > 240:
# breaks
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
651 | A | Joysticks | PROGRAMMING | 1,100 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if n... | The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively. | Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged. | [
"3 5\n",
"4 4\n"
] | [
"6\n",
"5\n"
] | In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joyst... | 500 | [
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
... | 1,628,591,260 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 6,963,200 | a = list(map(int, input().split()))
c = a.index(min(a))
m = 0
while a[0] > 0 and a[1] > 0:
if c == 0:
a[0] += 1
a[1] -= 2
else:
a[0] -= 2
a[1] += 1
c = a.index(min(a))
m += 1
print(m)
| Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick on... | ```python
a = list(map(int, input().split()))
c = a.index(min(a))
m = 0
while a[0] > 0 and a[1] > 0:
if c == 0:
a[0] += 1
a[1] -= 2
else:
a[0] -= 2
a[1] += 1
c = a.index(min(a))
m += 1
print(m)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
835 | A | Key races | PROGRAMMING | 800 | [
"math"
] | null | null | Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *... | The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and th... | If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship". | [
"5 1 2 1 2\n",
"3 3 1 1 1\n",
"4 5 3 1 5\n"
] | [
"First\n",
"Second\n",
"Friendship\n"
] | In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, ... | 500 | [
{
"input": "5 1 2 1 2",
"output": "First"
},
{
"input": "3 3 1 1 1",
"output": "Second"
},
{
"input": "4 5 3 1 5",
"output": "Friendship"
},
{
"input": "1000 1000 1000 1000 1000",
"output": "Friendship"
},
{
"input": "1 1 1 1 1",
"output": "Friendship"
},
... | 1,609,848,994 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s,v1,v2,t1,t2 = [int(x) for x in input().split()]
k1 = v1*s+2*t1
k2 = v2*s +2*t2
if(k1 < k2):
print("First")
else if(k1 == k2):
print("Second")
else:
print("Friendship") | Title: Key races
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t... | ```python
s,v1,v2,t1,t2 = [int(x) for x in input().split()]
k1 = v1*s+2*t1
k2 = v2*s +2*t2
if(k1 < k2):
print("First")
else if(k1 == k2):
print("Second")
else:
print("Friendship")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,610,043,137 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 218 | 0 | n,m=map(int,input().split())
li = list(map(int,input().split()))
li.sort()
i,su = int(),0
while True:
if i < m and li[i] < 0:su += li[i]
else:break
i+=1
print(abs(su)) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m=map(int,input().split())
li = list(map(int,input().split()))
li.sort()
i,su = int(),0
while True:
if i < m and li[i] < 0:su += li[i]
else:break
i+=1
print(abs(su))
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,627,487,106 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 62 | 6,758,400 | n, m = [int(x) for x in input().split()]
s = set()
for _ in range(n):
a = [int(x) for x in input().split()]
for x in a[1: ]:
s.add(x)
print("YES" if len(s) == m else "NO")
| Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
n, m = [int(x) for x in input().split()]
s = set()
for _ in range(n):
a = [int(x) for x in input().split()]
for x in a[1: ]:
s.add(x)
print("YES" if len(s) == m else "NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
92 | B | Binary Number | PROGRAMMING | 1,300 | [
"greedy"
] | B. Binary Number | 1 | 256 | Little walrus Fangy loves math very much. That's why when he is bored he plays with a number performing some operations.
Fangy takes some positive integer *x* and wants to get a number one from it. While *x* is not equal to 1, Fangy repeats the following action: if *x* is odd, then he adds 1 to it, otherwise he divide... | The first line contains a positive integer *x* in a binary system. It is guaranteed that the first digit of *x* is different from a zero and the number of its digits does not exceed 106. | Print the required number of actions. | [
"1\n",
"1001001\n",
"101110\n"
] | [
"0\n",
"12\n",
"8\n"
] | Let's consider the third sample. Number 101110 is even, which means that we should divide it by 2. After the dividing Fangy gets an odd number 10111 and adds one to it. Number 11000 can be divided by 2 three times in a row and get number 11. All that's left is to increase the number by one (we get 100), and then divide... | 1,000 | [
{
"input": "1",
"output": "0"
},
{
"input": "1001001",
"output": "12"
},
{
"input": "101110",
"output": "8"
},
{
"input": "11",
"output": "3"
},
{
"input": "11110001101",
"output": "16"
},
{
"input": "101010100100111100011111001111100001010101111110101... | 1,517,807,903 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 46 | 19,660,800 | n,res = int(input()),0;
while(n>1):
if(n%2==0): n/=2;
else: n+=1;
res+=1;
print(res); | Title: Binary Number
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Little walrus Fangy loves math very much. That's why when he is bored he plays with a number performing some operations.
Fangy takes some positive integer *x* and wants to get a number one from it. While *x* is not equal to ... | ```python
n,res = int(input()),0;
while(n>1):
if(n%2==0): n/=2;
else: n+=1;
res+=1;
print(res);
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
722 | B | Verse Pattern | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowel... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the text.
The second line contains integers *p*1,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=100) — the verse pattern.
Next *n* lines contain the text itself. Text consists of lowercase English letters and spaces. It's guarant... | If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes). | [
"3\n2 2 3\nintel\ncode\nch allenge\n",
"4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz\n",
"4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageous fortune\nor to take arms against a sea of troubles\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, one can split words into syllables in the following way:
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one. | 500 | [
{
"input": "3\n2 2 3\nintel\ncode\nch allenge",
"output": "YES"
},
{
"input": "4\n1 2 3 1\na\nbcdefghi\njklmnopqrstu\nvwxyz",
"output": "NO"
},
{
"input": "4\n13 11 15 15\nto be or not to be that is the question\nwhether tis nobler in the mind to suffer\nthe slings and arrows of outrageo... | 1,580,490,399 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 109 | 307,200 | N = int(input())
X = list(map(int, input().split()))
for i in range(N):
Temp = input()
Count = len([i for i in Temp if i in 'aeiouy'])
if Count != X[i]:
print("NO")
exit()
print("YES")
# Show you deserve being the best to whom doesn't believe in you.
# Location: At home in Mashha... | Title: Verse Pattern
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text consisting of *n* lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary num... | ```python
N = int(input())
X = list(map(int, input().split()))
for i in range(N):
Temp = input()
Count = len([i for i in Temp if i in 'aeiouy'])
if Count != X[i]:
print("NO")
exit()
print("YES")
# Show you deserve being the best to whom doesn't believe in you.
# Location: At home... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
331 | C1 | The Great Julya Calendar | PROGRAMMING | 1,100 | [
"dp"
] | null | null | Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on it. The translation from Old Beaverish is as follows:
"May the Great Beaver bless you! May your chacres open ... | The single line contains the magic integer *n*, 0<=≤<=*n*.
- to get 20 points, you need to solve the problem with constraints: *n*<=≤<=106 (subproblem C1); - to get 40 points, you need to solve the problem with constraints: *n*<=≤<=1012 (subproblems C1+C2); - to get 100 points, you need to solve the problem with co... | Print a single integer — the minimum number of subtractions that turns the magic number to a zero. | [
"24\n"
] | [
"5"
] | In the first test sample the minimum number of operations can be reached by the following sequence of subtractions: | 20 | [
{
"input": "24",
"output": "5"
},
{
"input": "0",
"output": "0"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "1"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "31",
"output": "6"
},
... | 1,644,644,007 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS1 | 6 | 62 | 0 | n=int(input())
if n==0:print(0)
elif len(str(n))==1:print(1)
else:
if n%10==0:
print(n//5)
else:
n-=(n%10)
print(1+n//5) | Title: The Great Julya Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on i... | ```python
n=int(input())
if n==0:print(0)
elif len(str(n))==1:print(1)
else:
if n%10==0:
print(n//5)
else:
n-=(n%10)
print(1+n//5)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
289 | B | Polo the Penguin and Matrix | PROGRAMMING | 1,400 | [
"brute force",
"dp",
"implementation",
"sortings",
"ternary search"
] | null | null | Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represent the matrix element on the intersection of row *i* and column *j* as *a**ij*.
In one move the penguin can add ... | The first line contains three integers *n*, *m* and *d* (1<=≤<=*n*,<=*m*<=≤<=100,<=1<=≤<=*d*<=≤<=104) — the matrix sizes and the *d* parameter. Next *n* lines contain the matrix: the *j*-th integer in the *i*-th row is the matrix element *a**ij* (1<=≤<=*a**ij*<=≤<=104). | In a single line print a single integer — the minimum number of moves the penguin needs to make all matrix elements equal. If that is impossible, print "-1" (without the quotes). | [
"2 2 2\n2 4\n6 8\n",
"1 2 7\n6 7\n"
] | [
"4\n",
"-1\n"
] | none | 1,000 | [
{
"input": "2 2 2\n2 4\n6 8",
"output": "4"
},
{
"input": "1 2 7\n6 7",
"output": "-1"
},
{
"input": "3 2 1\n5 7\n1 2\n5 100",
"output": "104"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 2",
"output": "12"
},
{
"input": "3 3 3\n5 8 5\n11 11 17\n14 5 3",
"outpu... | 1,623,923,579 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 122 | 0 | n,m,d=map(int,input().split())
l=[]
for i in range(n):
x=(list(map(int,input().split())))
for j in x:
l.append(j)
l.sort()
s=0
value=l[len(l)//2]
for i in range(n//2+1):
s+=abs(value-l[i])/d + abs(value-l[-i-1])/d
if not s.is_integer():
print(-1)
exit()
print(int(s)... | Title: Polo the Penguin and Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little penguin Polo has an *n*<=×<=*m* matrix, consisting of integers. Let's index the matrix rows from 1 to *n* from top to bottom and let's index the columns from 1 to *m* from left to right. Let's represe... | ```python
n,m,d=map(int,input().split())
l=[]
for i in range(n):
x=(list(map(int,input().split())))
for j in x:
l.append(j)
l.sort()
s=0
value=l[len(l)//2]
for i in range(n//2+1):
s+=abs(value-l[i])/d + abs(value-l[-i-1])/d
if not s.is_integer():
print(-1)
exit()
pr... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
886 | C | Petya and Catacombs | PROGRAMMING | 1,300 | [
"dsu",
"greedy",
"implementation",
"trees"
] | null | null | A very brave explorer Petya once decided to explore Paris catacombs. Since Petya is not really experienced, his exploration is just walking through the catacombs.
Catacombs consist of several rooms and bidirectional passages between some pairs of them. Some passages can connect a room to itself and since the passages ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=2·105) — then number of notes in Petya's logbook.
The second line contains *n* non-negative integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=<<=*i*) — notes in the logbook. | In the only line print a single integer — the minimum possible number of rooms in Paris catacombs. | [
"2\n0 0\n",
"5\n0 1 0 1 3\n"
] | [
"2\n",
"3\n"
] | In the first sample, sequence of rooms Petya visited could be, for example 1 → 1 → 2, 1 → 2 → 1 or 1 → 2 → 3. The minimum possible number of rooms is 2.
In the second sample, the sequence could be 1 → 2 → 3 → 1 → 2 → 1. | 1,500 | [
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "5\n0 1 0 1 3",
"output": "3"
},
{
"input": "7\n0 1 0 0 0 0 0",
"output": "6"
},
{
"input": "100\n0 0 0 0 0 0 1 4 4 0 2 2 4 1 7 1 11 0 8 4 12 12 3 0 3 2 2 4 3 9 1 5 4 6 9 14 6 2 4 18 7 7 19 11 20 13 17 16 0 34 2 6 12 27 9 4 29 ... | 1,631,950,699 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 218 | 21,299,200 | import sys
sys.setrecursionlimit(10**6);
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
n=int(input())+1;
a=[-1]+list(map(int,input().split(" ")));
i=1;c=0;s=set();
while(i<n):
if(a[i] in s):
s.remove(a[i]);
else:c+=1;
s.add(i);i+=1;
print(c);
| Title: Petya and Catacombs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A very brave explorer Petya once decided to explore Paris catacombs. Since Petya is not really experienced, his exploration is just walking through the catacombs.
Catacombs consist of several rooms and bidirectiona... | ```python
import sys
sys.setrecursionlimit(10**6);
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
n=int(input())+1;
a=[-1]+list(map(int,input().split(" ")));
i=1;c=0;s=set();
while(i<n):
if(a[i] in s):
s.remove(a[i]);
else:c+=1;
s.add(i);i+=1;
print(c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
768 | A | Oath of the Night's Watch | PROGRAMMING | 900 | [
"constructive algorithms",
"sortings"
] | null | null | "Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am the sword in the darkness. I am the watcher on the walls. I am the shield that guards the realms of men. I ple... | First line consists of a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of stewards with Jon Snow.
Second line consists of *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) representing the values assigned to the stewards. | Output a single integer representing the number of stewards which Jon will feed. | [
"2\n1 5\n",
"3\n1 2 5\n"
] | [
"0",
"1"
] | In the first sample, Jon Snow cannot support steward with strength 1 because there is no steward with strength less than 1 and he cannot support steward with strength 5 because there is no steward with strength greater than 5.
In the second sample, Jon Snow can support steward with strength 2 because there are steward... | 500 | [
{
"input": "2\n1 5",
"output": "0"
},
{
"input": "3\n1 2 5",
"output": "1"
},
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "8\n7 8 9 4 5 6 1 2",
"output": "6"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n100",
"output": "0"
},
... | 1,656,996,953 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 7,987,200 | n = int(input())
a = list(map(int, input().split()))
a.sort()
b = list({i for i in a})
b.remove(b[0])
b.remove(b[len(b)-1])
c = 0
for i in a:
if i in b:
c += 1
print(c) | Title: Oath of the Night's Watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am... | ```python
n = int(input())
a = list(map(int, input().split()))
a.sort()
b = list({i for i in a})
b.remove(b[0])
b.remove(b[len(b)-1])
c = 0
for i in a:
if i in b:
c += 1
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,697,813,477 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 109 | 18,432,000 | a_len, b_len = list(map(int, input().split()))
k, m = list(map(int, input().split()))
list_a = list(map(int, input().split()))
list_b = list(map(int, input().split()))
if list_a[k - 1] < list_b[-m]:
print("YES")
else:
print("NO") | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
a_len, b_len = list(map(int, input().split()))
k, m = list(map(int, input().split()))
list_a = list(map(int, input().split()))
list_b = list(map(int, input().split()))
if list_a[k - 1] < list_b[-m]:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
146 | A | Lucky Ticket | PROGRAMMING | 800 | [
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya loves tickets very much. As we know, each ticket has a number that is a positive integer. It... | The first line contains an even integer *n* (2<=≤<=*n*<=≤<=50) — the length of the ticket number that needs to be checked. The second line contains an integer whose length equals exactly *n* — the ticket number. The number may contain leading zeros. | On the first line print "YES" if the given ticket number is lucky. Otherwise, print "NO" (without the quotes). | [
"2\n47\n",
"4\n4738\n",
"4\n4774\n"
] | [
"NO\n",
"NO\n",
"YES\n"
] | In the first sample the sum of digits in the first half does not equal the sum of digits in the second half (4 ≠ 7).
In the second sample the ticket number is not the lucky number. | 500 | [
{
"input": "2\n47",
"output": "NO"
},
{
"input": "4\n4738",
"output": "NO"
},
{
"input": "4\n4774",
"output": "YES"
},
{
"input": "4\n4570",
"output": "NO"
},
{
"input": "6\n477477",
"output": "YES"
},
{
"input": "6\n777777",
"output": "YES"
},
... | 1,652,332,828 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | n = int(input())
a=int(input())
b=a//100000
c=((a//10000)%100)%10
d=((a//1000)%100)%10
e=((a//100)%100)%10
f=((a//10)%100)%10
g=((a//1)%100)%10
if b+c+d==e+f+g:
print('YES')
else:
print('NO') | Title: Lucky Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n = int(input())
a=int(input())
b=a//100000
c=((a//10000)%100)%10
d=((a//1000)%100)%10
e=((a//100)%100)%10
f=((a//10)%100)%10
g=((a//1)%100)%10
if b+c+d==e+f+g:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,670,825,219 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 7 | 77 | 2,764,800 | n, t = map(int, input().split())
nine = ''
for i in range(n-1):
nine+='9'
print(int(nine)*t) | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n, t = map(int, input().split())
nine = ''
for i in range(n-1):
nine+='9'
print(int(nine)*t)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,633,836,704 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | def factorial(num):
factorial = 1
if num == 0:
return 1
else:
for i in range(1,num + 1):
factorial = factorial*i
return factorial
def gcd(a,b):
i = 1
while(i <= a and i <= b):
if(a % i == 0 and b % i == 0):
gcd = i
i = i + ... | Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
def factorial(num):
factorial = 1
if num == 0:
return 1
else:
for i in range(1,num + 1):
factorial = factorial*i
return factorial
def gcd(a,b):
i = 1
while(i <= a and i <= b):
if(a % i == 0 and b % i == 0):
gcd = i
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
907 | A | Masha and Bears | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 500 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,514,038,896 | 996 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 5,529,600 | v = list( map( int, input().split() ) )
ans = []
for i in range( 0, 3 ):
for b in range( 1, 101 ):
if v[i] <= b and v[-1] <= b and 2*v[i] >= b:
if i == 2:
if 2*v[-1] >= b:
ans.append( b )
break
else:
... | Title: Masha and Bears
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son b... | ```python
v = list( map( int, input().split() ) )
ans = []
for i in range( 0, 3 ):
for b in range( 1, 101 ):
if v[i] <= b and v[-1] <= b and 2*v[i] >= b:
if i == 2:
if 2*v[-1] >= b:
ans.append( b )
break
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,541,688,614 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 109 | 0 | h = list(input())
t = ['h','e','l','l','o']
a = 0
b = "NO"
for i in h:
if i == t[a]:
a+=1
if a<4:
a+=1
else:
a = 4
else:
continue
if a>=len(t)-1:
b = "YES"
print(b) | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
h = list(input())
t = ['h','e','l','l','o']
a = 0
b = "NO"
for i in h:
if i == t[a]:
a+=1
if a<4:
a+=1
else:
a = 4
else:
continue
if a>=len(t)-1:
b = "YES"
print(b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,676,062,098 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | def main():
n = int(input().strip());
good_performance = False;
for i in range(n):
name, before, after = input().strip().split()
before, after = int(before), int(after);
if before >= 2400 and after < before:
good_performance = True;
break;
if good_performa... | Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
def main():
n = int(input().strip());
good_performance = False;
for i in range(n):
name, before, after = input().strip().split()
before, after = int(before), int(after);
if before >= 2400 and after < before:
good_performance = True;
break;
if goo... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
558 | A | Lala Land and Apple Trees | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"sortings"
] | null | null | Amr lives in Lala Land. Lala Land is a very beautiful country that is located on a coordinate line. Lala Land is famous with its apple trees growing everywhere.
Lala Land has exactly *n* apple trees. Tree number *i* is located in a position *x**i* and has *a**i* apples growing on it. Amr wants to collect apples from t... | The first line contains one number *n* (1<=≤<=*n*<=≤<=100), the number of apple trees in Lala Land.
The following *n* lines contains two integers each *x**i*, *a**i* (<=-<=105<=≤<=*x**i*<=≤<=105, *x**i*<=≠<=0, 1<=≤<=*a**i*<=≤<=105), representing the position of the *i*-th tree and number of apples on it.
It's guarant... | Output the maximum number of apples Amr can collect. | [
"2\n-1 5\n1 5\n",
"3\n-2 2\n1 4\n-1 3\n",
"3\n1 9\n3 5\n7 10\n"
] | [
"10",
"9",
"9"
] | In the first sample test it doesn't matter if Amr chose at first to go left or right. In both cases he'll get all the apples.
In the second sample test the optimal solution is to go left to *x* = - 1, collect apples from there, then the direction will be reversed, Amr has to go to *x* = 1, collect apples from there, ... | 500 | [
{
"input": "2\n-1 5\n1 5",
"output": "10"
},
{
"input": "3\n-2 2\n1 4\n-1 3",
"output": "9"
},
{
"input": "3\n1 9\n3 5\n7 10",
"output": "9"
},
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "4\n10000 100000\n-1000 100000\n-2 100000\n-1 100000",
"output": "3... | 1,613,603,054 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 62 | 307,200 | x=int(input())
lst=[[int(j) for j in input().split()] for i in range(x)]
total_negative,total_positive=0,0
eksi_tree,arti_tree=0,0
lst.sort(key=lambda y: y[0])
for i in range(x):
if lst[i][0]>0:
eksi_tree=i
arti_tree=x-i
break
toplam=0
az=min(arti_tree,eksi_tree)
if eksi_tr... | Title: Lala Land and Apple Trees
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr lives in Lala Land. Lala Land is a very beautiful country that is located on a coordinate line. Lala Land is famous with its apple trees growing everywhere.
Lala Land has exactly *n* apple trees. Tree num... | ```python
x=int(input())
lst=[[int(j) for j in input().split()] for i in range(x)]
total_negative,total_positive=0,0
eksi_tree,arti_tree=0,0
lst.sort(key=lambda y: y[0])
for i in range(x):
if lst[i][0]>0:
eksi_tree=i
arti_tree=x-i
break
toplam=0
az=min(arti_tree,eksi_tree)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
664 | A | Complicated GCD | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest in... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100). | Output one integer — greatest common divisor of all integers from *a* to *b* inclusive. | [
"1 2\n",
"61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n"
] | [
"1\n",
"61803398874989484820458683436563811772030917980576\n"
] | none | 500 | [
{
"input": "1 2",
"output": "1"
},
{
"input": "61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576",
"output": "61803398874989484820458683436563811772030917980576"
},
{
"input": "1 100",
"output": "1"
},
{
"input": "100 100000... | 1,635,248,754 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 46 | 4,300,800 | n=input().split(" ")
def gcd(a,b):
if a==b:
print(a)
else:
print(1)
gcd(int(n[0]),int(n[1]))
| Title: Complicated GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find gre... | ```python
n=input().split(" ")
def gcd(a,b):
if a==b:
print(a)
else:
print(1)
gcd(int(n[0]),int(n[1]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin b... | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,695,846,074 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 62 | 0 | import math
r, x, y, nx, ny = map(int,input().split())
step = 2*r
d = math.sqrt((nx-x)**2 + (ny-y)**2)
if (d//step)*step < d :
print(int(d//step)+1)
else :
print(int(d//step)) | Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can ... | ```python
import math
r, x, y, nx, ny = map(int,input().split())
step = 2*r
d = math.sqrt((nx-x)**2 + (ny-y)**2)
if (d//step)*step < d :
print(int(d//step)+1)
else :
print(int(d//step))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,680,028,801 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 61 | 1,331,200 | n = int(input())
c= 0
for i in range(1, n+1):
a = n - i
b = a // i
if b*i == a and n % i == 0:
c += 1
d=c-1
print(d) | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
n = int(input())
c= 0
for i in range(1, n+1):
a = n - i
b = a // i
if b*i == a and n % i == 0:
c += 1
d=c-1
print(d)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
574 | A | Bear and Elections | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Limak is a grizzly bear who desires power and adoration. He wants to win in upcoming elections and rule over the Bearland.
There are *n* candidates, including Limak. We know how many citizens are going to vote for each candidate. Now *i*-th candidate would get *a**i* votes. Limak is candidate number 1. To win in elect... | The first line contains single integer *n* (2<=≤<=*n*<=≤<=100) - number of candidates.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) - number of votes for each candidate. Limak is candidate number 1.
Note that after bribing number of votes for some candidate ... | Print the minimum number of citizens Limak must bribe to have strictly more votes than any other candidate. | [
"5\n5 1 11 2 8\n",
"4\n1 8 8 8\n",
"2\n7 6\n"
] | [
"4\n",
"6\n",
"0\n"
] | In the first sample Limak has 5 votes. One of the ways to achieve victory is to bribe 4 citizens who want to vote for the third candidate. Then numbers of votes would be 9, 1, 7, 2, 8 (Limak would have 9 votes). Alternatively, Limak could steal only 3 votes from the third candidate and 1 vote from the second candidate ... | 500 | [
{
"input": "5\n5 1 11 2 8",
"output": "4"
},
{
"input": "4\n1 8 8 8",
"output": "6"
},
{
"input": "2\n7 6",
"output": "0"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "10\n100 200 57 99 1 1000 200 200 200 500",
"output": "451"
},
{
"input": "16\... | 1,440,869,471 | 3,671 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 0 | n = int(input())
a = input().split()
for i in range(len(a)):
a[i] = int(a[i])
ans = 0
run = True
a1 = a.copy()
del a1[0]
if not (max(a) == a[0] and not a[0] in a1):
del a1
while run:
for i in range(len(a)):
if a[i] == max(a):
a[i] -= 1
a[0] +... | Title: Bear and Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a grizzly bear who desires power and adoration. He wants to win in upcoming elections and rule over the Bearland.
There are *n* candidates, including Limak. We know how many citizens are going to vote for e... | ```python
n = int(input())
a = input().split()
for i in range(len(a)):
a[i] = int(a[i])
ans = 0
run = True
a1 = a.copy()
del a1[0]
if not (max(a) == a[0] and not a[0] in a1):
del a1
while run:
for i in range(len(a)):
if a[i] == max(a):
a[i] -= 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
699 | A | Launch of Collider | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be two or more particles located in the same point. The coordinates of the particles coincide with the dis... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of particles.
The second line contains *n* symbols "L" and "R". If the *i*-th symbol equals "L", then the *i*-th particle will move to the left, otherwise the *i*-th symbol equals "R" and the *i*-th particle will move to the right.... | In the first line print the only integer — the first moment (in microseconds) when two particles are at the same point and there will be an explosion.
Print the only integer -1, if the collision of particles doesn't happen. | [
"4\nRLRL\n2 4 6 10\n",
"3\nLLR\n40 50 60\n"
] | [
"1\n",
"-1\n"
] | In the first sample case the first explosion will happen in 1 microsecond because the particles number 1 and 2 will simultaneously be at the same point with the coordinate 3.
In the second sample case there will be no explosion because there are no particles which will simultaneously be at the same point. | 500 | [
{
"input": "4\nRLRL\n2 4 6 10",
"output": "1"
},
{
"input": "3\nLLR\n40 50 60",
"output": "-1"
},
{
"input": "4\nRLLR\n46 230 264 470",
"output": "92"
},
{
"input": "6\nLLRLLL\n446 492 650 844 930 970",
"output": "97"
},
{
"input": "8\nRRLLLLLL\n338 478 512 574 59... | 1,689,552,625 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | n = int(input())
pos = input()
x = list(map(int, input().split()))
for i in range(len(x)-1):
if x[i+1] - x[i] == 2:
print(1)
exit()
print(-1)
| Title: Launch of Collider
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be... | ```python
n = int(input())
pos = input()
x = list(map(int, input().split()))
for i in range(len(x)-1):
if x[i+1] - x[i] == 2:
print(1)
exit()
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,699,331,784 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | n=intput()
s2=n[0].upper()+n[1:]
print(s2)
| Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
n=intput()
s2=n[0].upper()+n[1:]
print(s2)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
204 | B | Little Elephant and Cards | PROGRAMMING | 1,500 | [
"binary search",
"data structures"
] | null | null | The Little Elephant loves to play with color cards.
He has *n* cards, each has exactly two colors (the color of the front side and the color of the back side). Initially, all the cards lay on the table with the front side up. In one move the Little Elephant can turn any card to the other side. The Little Elephant thin... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of the cards. The following *n* lines contain the description of all cards, one card per line. The cards are described by a pair of positive integers not exceeding 109 — colors of both sides. The first number in a line is the color of the fro... | On a single line print a single integer — the sought minimum number of moves. If it is impossible to make the set funny, print -1. | [
"3\n4 7\n4 7\n7 4\n",
"5\n4 7\n7 4\n2 11\n9 7\n1 1\n"
] | [
"0\n",
"2\n"
] | In the first sample there initially are three cards lying with colors 4, 4, 7. Since two of the three cards are of the same color 4, you do not need to change anything, so the answer is 0.
In the second sample, you can turn the first and the fourth cards. After that three of the five cards will be of color 7. | 500 | [
{
"input": "3\n4 7\n4 7\n7 4",
"output": "0"
},
{
"input": "5\n4 7\n7 4\n2 11\n9 7\n1 1",
"output": "2"
},
{
"input": "1\n1 1",
"output": "0"
},
{
"input": "2\n1 1\n1 1",
"output": "0"
},
{
"input": "7\n1 2\n2 3\n3 4\n4 5\n5 6\n6 7\n7 8",
"output": "-1"
},
... | 1,528,191,002 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 186 | 7,168,000 | from collections import defaultdict
temp_n = n = int(input())
front = defaultdict(int)
back = defaultdict(int)
while temp_n > 0:
temp_n -= 1
f, b = map(int, input().split())
front[f] += 1
back[b] += 1
target = (n + 1) // 2
for count, num in sorted(((_count, _num) for _num, _count in front.items()), ... | Title: Little Elephant and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves to play with color cards.
He has *n* cards, each has exactly two colors (the color of the front side and the color of the back side). Initially, all the cards lay on the table with t... | ```python
from collections import defaultdict
temp_n = n = int(input())
front = defaultdict(int)
back = defaultdict(int)
while temp_n > 0:
temp_n -= 1
f, b = map(int, input().split())
front[f] += 1
back[b] += 1
target = (n + 1) // 2
for count, num in sorted(((_count, _num) for _num, _count in front.... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
255 | A | Greg's Workout | PROGRAMMING | 800 | [
"implementation"
] | null | null | Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg should repeat the *i*-th in order exercise *a**i* times.
Greg now only does three types of exercise... | The first line contains integer *n* (1<=≤<=*n*<=≤<=20). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=25) — the number of times Greg repeats the exercises. | Print word "chest" (without the quotes), if the chest gets the most exercise, "biceps" (without the quotes), if the biceps gets the most exercise and print "back" (without the quotes) if the back gets the most exercise.
It is guaranteed that the input is such that the answer to the problem is unambiguous. | [
"2\n2 8\n",
"3\n5 1 10\n",
"7\n3 3 2 7 9 6 8\n"
] | [
"biceps\n",
"back\n",
"chest\n"
] | In the first sample Greg does 2 chest, 8 biceps and zero back exercises, so the biceps gets the most exercises.
In the second sample Greg does 5 chest, 1 biceps and 10 back exercises, so the back gets the most exercises.
In the third sample Greg does 18 chest, 12 biceps and 8 back exercises, so the chest gets the mos... | 500 | [
{
"input": "2\n2 8",
"output": "biceps"
},
{
"input": "3\n5 1 10",
"output": "back"
},
{
"input": "7\n3 3 2 7 9 6 8",
"output": "chest"
},
{
"input": "4\n5 6 6 2",
"output": "chest"
},
{
"input": "5\n8 2 2 6 3",
"output": "chest"
},
{
"input": "6\n8 7 ... | 1,618,477,910 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 154 | 0 | n = int(input())
exercise = list(map(int, input().split()))
chest = 0
biceps = 0
back = 0
for i in range(0,len(exercise),3):
# print("i=",i)
chest+=exercise[i]
for j in range(1, len(exercise), 3):
#print("j=",j)
biceps+=exercise[j]
for k in range(2, len(exercise),3):
#print("k=", k)
... | Title: Greg's Workout
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greg is a beginner bodybuilder. Today the gym coach gave him the training plan. All it had was *n* integers *a*1,<=*a*2,<=...,<=*a**n*. These numbers mean that Greg needs to do exactly *n* exercises today. Besides, Greg ... | ```python
n = int(input())
exercise = list(map(int, input().split()))
chest = 0
biceps = 0
back = 0
for i in range(0,len(exercise),3):
# print("i=",i)
chest+=exercise[i]
for j in range(1, len(exercise), 3):
#print("j=",j)
biceps+=exercise[j]
for k in range(2, len(exercise),3):
#print("k="... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,639,379,932 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | text = "hello"
def chatroom():
count = 0
s = input()
for i in range(len(s)):
if s[i] ==text[x]:
count += 1
if count == 5:
return "YES"
return "NO"
print(chatroom()) | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
text = "hello"
def chatroom():
count = 0
s = input()
for i in range(len(s)):
if s[i] ==text[x]:
count += 1
if count == 5:
return "YES"
return "NO"
print(chatroom())
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,672,331,492 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | a,b = map(int,input().split())
c = list(map(int,input().split()))
c.sort()
print(max(c[:a])-min(c[:a])) | Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
a,b = map(int,input().split())
c = list(map(int,input().split()))
c.sort()
print(max(c[:a])-min(c[:a]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
993 | A | Two Squares | PROGRAMMING | 1,600 | [
"geometry",
"implementation"
] | null | null | You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be part of the square, i.e. if one square is completely inside another, they intersect. If the ... | The input data consists of two lines, one for each square, both containing 4 pairs of integers. Each pair represents coordinates of one vertex of the square. Coordinates within each line are either in clockwise or counterclockwise order.
The first line contains the coordinates of the square with sides parallel to the ... | Print "Yes" if squares intersect, otherwise print "No".
You can print each letter in any case (upper or lower). | [
"0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1\n",
"0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1\n",
"6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the second square lies entirely within the first square, so they do intersect.
In the second sample squares do not have any points in common.
Here are images corresponding to the samples: | 500 | [
{
"input": "0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1",
"output": "NO"
},
{
"input": "6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n8 4 4 8 8 12 12 8",
"output": "YES"
},
... | 1,545,853,591 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | import sys
I =lambda : map(int, sys.stdin.readline().split())
l1 = list(I())
l2 = list(I())
x1,y1 = l1[0],l1[1]
x2,y2 = l1[2],l1[3]
x3,y3 = l1[4],l1[5]
x4,y4 = l1[6],l1[7]
y=[];x=[];
if x1==x2 :
x.append(x1)
x.append(x3)
y.append(y2)
y.append(y1)
else :
x.append(x1)
x.append(x2)
... | Title: Two Squares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered t... | ```python
import sys
I =lambda : map(int, sys.stdin.readline().split())
l1 = list(I())
l2 = list(I())
x1,y1 = l1[0],l1[1]
x2,y2 = l1[2],l1[3]
x3,y3 = l1[4],l1[5]
x4,y4 = l1[6],l1[7]
y=[];x=[];
if x1==x2 :
x.append(x1)
x.append(x3)
y.append(y2)
y.append(y1)
else :
x.append(x1)
x.a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,691,395,070 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | '''
list(map(int,input().split()))
'''
n=int(input());h,a=[],[]
for _ in range(n):
g=list(map(int,input().split()))
h.append(g[0])
a.append(g[1])
matches=0
for col in h:
if col in a:matches+=a.count(col)
print(matches)
| Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
'''
list(map(int,input().split()))
'''
n=int(input());h,a=[],[]
for _ in range(n):
g=list(map(int,input().split()))
h.append(g[0])
a.append(g[1])
matches=0
for col in h:
if col in a:matches+=a.count(col)
print(matches)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,462,173,375 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 78 | 4,608,000 | n=int(input())
x=(n//3)*2
if n%3!=0:
x+=1
print(x) | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
n=int(input())
x=(n//3)*2
if n%3!=0:
x+=1
print(x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,688,394,300 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 31 | 0 | n = int(input())
a="I hate"
for i in range(2,n+1):
if i%2==0:
a+=" that I love"
else:
a+=" that I hate"
a+=" it"
print(a) | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
n = int(input())
a="I hate"
for i in range(2,n+1):
if i%2==0:
a+=" that I love"
else:
a+=" that I hate"
a+=" it"
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
186 | A | Comparing Strings | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Mish... | The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that co... | Print "YES", if the dwarves belong to the same race. Otherwise, print "NO". | [
"ab\nba\n",
"aa\nab\n"
] | [
"YES\n",
"NO\n"
] | - First example: you can simply swap two letters in string "ab". So we get "ba". - Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b". | 500 | [
{
"input": "ab\nba",
"output": "YES"
},
{
"input": "aa\nab",
"output": "NO"
},
{
"input": "a\nza",
"output": "NO"
},
{
"input": "vvea\nvvae",
"output": "YES"
},
{
"input": "rtfabanpc\natfabrnpc",
"output": "YES"
},
{
"input": "mt\ntm",
"output": "Y... | 1,616,524,805 | 2,147,483,647 | Python 3 | OK | TESTS | 53 | 156 | 614,400 | #from collections import Counter
#n = int(input())
#n,m = map(int,input().split())
#l = list(map(int,input().split()))
l = []
s = input()
t = input()
c = 0
if len(t) == len(s):
for i in range(len(t)):
if t[i] != s[i]:
l.append((t[i],s[i]))
c+=1
if c>2:
... | Title: Comparing Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome ... | ```python
#from collections import Counter
#n = int(input())
#n,m = map(int,input().split())
#l = list(map(int,input().split()))
l = []
s = input()
t = input()
c = 0
if len(t) == len(s):
for i in range(len(t)):
if t[i] != s[i]:
l.append((t[i],s[i]))
c+=1
if c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,588,112,963 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 280 | 0 | import math
x, y, z = map(int,input().split())
b = int(math.sqrt(x*y//z))
a = int(math.sqrt(x*z//y))
c = int(math.sqrt(z*y//x))
ma = max(a,b,c)
mi = min(a,b,c)
md = sum([a,b,c]) - ma -mi
print(ma*4 + mi*4 + md*4)
| Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
import math
x, y, z = map(int,input().split())
b = int(math.sqrt(x*y//z))
a = int(math.sqrt(x*z//y))
c = int(math.sqrt(z*y//x))
ma = max(a,b,c)
mi = min(a,b,c)
md = sum([a,b,c]) - ma -mi
print(ma*4 + mi*4 + md*4)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,480,935,153 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 6,758,400 | n=int(input())
s=list(map(int,input().split()))
output=sum(s)
while len(s)>1:
output+=min(s)
s.remove(min(s))
output+=sum(s)
print(output) | Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
n=int(input())
s=list(map(int,input().split()))
output=sum(s)
while len(s)>1:
output+=min(s)
s.remove(min(s))
output+=sum(s)
print(output)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
534 | B | Covered Path | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"math"
] | null | null | The on-board computer on Polycarp's car measured that the car speed at the beginning of some section of the path equals *v*1 meters per second, and in the end it is *v*2 meters per second. We know that this section of the route took exactly *t* seconds to pass.
Assuming that at each of the seconds the speed is constan... | The first line contains two integers *v*1 and *v*2 (1<=≤<=*v*1,<=*v*2<=≤<=100) — the speeds in meters per second at the beginning of the segment and at the end of the segment, respectively.
The second line contains two integers *t* (2<=≤<=*t*<=≤<=100) — the time when the car moves along the segment in seconds, *d* (0<... | Print the maximum possible length of the path segment in meters. | [
"5 6\n4 2\n",
"10 10\n10 0\n"
] | [
"26",
"100"
] | In the first sample the sequence of speeds of Polycarpus' car can look as follows: 5, 7, 8, 6. Thus, the total path is 5 + 7 + 8 + 6 = 26 meters.
In the second sample, as *d* = 0, the car covers the whole segment at constant speed *v* = 10. In *t* = 10 seconds it covers the distance of 100 meters. | 1,000 | [
{
"input": "5 6\n4 2",
"output": "26"
},
{
"input": "10 10\n10 0",
"output": "100"
},
{
"input": "87 87\n2 10",
"output": "174"
},
{
"input": "1 11\n6 2",
"output": "36"
},
{
"input": "100 10\n10 10",
"output": "550"
},
{
"input": "1 1\n100 10",
"o... | 1,594,291,715 | 2,147,483,647 | PyPy 3 | OK | TESTS | 64 | 155 | 20,172,800 | v1,v2 =map(int,input().split())
t,d =map(int,input().split())
ans = 0
for i in range(t):
ans += min(v1 + i * d, v2 + (t - i - 1) * d)
print(ans) | Title: Covered Path
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The on-board computer on Polycarp's car measured that the car speed at the beginning of some section of the path equals *v*1 meters per second, and in the end it is *v*2 meters per second. We know that this section of the ... | ```python
v1,v2 =map(int,input().split())
t,d =map(int,input().split())
ans = 0
for i in range(t):
ans += min(v1 + i * d, v2 + (t - i - 1) * d)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,617,018,987 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 312 | 5,632,000 | n=int(input())
a=[int(i) for i in input().split()]
d={}
flag=True
for i in a:
k=i-25
if k>0:
if k>=50 and d.get(50,0)>0:
r=k//50
k=k-r*50
d[50]-=r
if k>=25 :
if d.get(25,0)>0:
r=k//25
s=k%25
... | Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the bookin... | ```python
n=int(input())
a=[int(i) for i in input().split()]
d={}
flag=True
for i in a:
k=i-25
if k>0:
if k>=50 and d.get(50,0)>0:
r=k//50
k=k-r*50
d[50]-=r
if k>=25 :
if d.get(25,0)>0:
r=k//25
s=k%25
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
612 | C | Replace To Make Regular Bracket Sequence | PROGRAMMING | 1,400 | [
"data structures",
"expression parsing",
"math"
] | null | null | You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another of the same type. For example, you can replace < by the bracket {, but you can't replace it by ) or >.
The following d... | The only line contains a non empty string *s*, consisting of only opening and closing brackets of four kinds. The length of *s* does not exceed 106. | If it's impossible to get RBS from *s* print Impossible.
Otherwise print the least number of replaces needed to get RBS from *s*. | [
"[<}){}\n",
"{()}[]\n",
"]]\n"
] | [
"2",
"0",
"Impossible"
] | none | 0 | [
{
"input": "[<}){}",
"output": "2"
},
{
"input": "{()}[]",
"output": "0"
},
{
"input": "]]",
"output": "Impossible"
},
{
"input": ">",
"output": "Impossible"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{}",
"output": "0"
},
{
"input": ... | 1,633,967,547 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 62 | 6,963,200 | s = input()
stk = []
count = 0
for i in range(len(s)): #<>, {}, [], ().
if(s[i] == "<"):
stk.append(s[i])
elif(s[i] == "{"):
stk.append(s[i])
elif(s[i] == "["):
stk.append(s[i])
elif(s[i] == "("):
stk.append(s[i])
elif(s[i] == ">"):
if(stk[-1] == "<"):
stk.pop()
else:
count += 1
stk.pop()
... | Title: Replace To Make Regular Bracket Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another... | ```python
s = input()
stk = []
count = 0
for i in range(len(s)): #<>, {}, [], ().
if(s[i] == "<"):
stk.append(s[i])
elif(s[i] == "{"):
stk.append(s[i])
elif(s[i] == "["):
stk.append(s[i])
elif(s[i] == "("):
stk.append(s[i])
elif(s[i] == ">"):
if(stk[-1] == "<"):
stk.pop()
else:
count += 1
stk.... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
192 | B | Walking in the Rain | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start walking on the tile number 1 and the finish on the tile number *n*. During the walk it is allowed to move... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the boulevard's length in tiles.
The second line contains *n* space-separated integers *a**i* — the number of days after which the *i*-th tile gets destroyed (1<=≤<=*a**i*<=≤<=103). | Print a single number — the sought number of days. | [
"4\n10 3 5 10\n",
"5\n10 2 8 3 5\n"
] | [
"5\n",
"5\n"
] | In the first sample the second tile gets destroyed after day three, and the only path left is 1 → 3 → 4. After day five there is a two-tile gap between the first and the last tile, you can't jump over it.
In the second sample path 1 → 3 → 5 is available up to day five, inclusive. On day six the last tile is destroyed ... | 1,000 | [
{
"input": "4\n10 3 5 10",
"output": "5"
},
{
"input": "5\n10 2 8 3 5",
"output": "5"
},
{
"input": "10\n10 3 1 6 7 1 3 3 8 1",
"output": "1"
},
{
"input": "10\n26 72 10 52 2 5 61 2 39 64",
"output": "5"
},
{
"input": "100\n8 2 1 2 8 3 5 8 5 1 9 3 4 1 5 6 4 2 9 10... | 1,578,655,544 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 280 | 0 | n = int(input())
a = list(map(int, input().split()))
ans = min(a[0], a[n-1])
i = 0
t = 1001
while i < n:
if i+2 < n:
if a[i+1] > a[i+2]:
i = i+1
t = a[i]
else:
i = i+2
t = a[i]
ans = min(ans, t)
else:
if i+1 == n-1... | Title: Walking in the Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start ... | ```python
n = int(input())
a = list(map(int, input().split()))
ans = min(a[0], a[n-1])
i = 0
t = 1001
while i < n:
if i+2 < n:
if a[i+1] > a[i+2]:
i = i+1
t = a[i]
else:
i = i+2
t = a[i]
ans = min(ans, t)
else:
if ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
126 | B | Password | PROGRAMMING | 1,700 | [
"binary search",
"dp",
"hashing",
"string suffix structures",
"strings"
] | null | null | Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carved on a rock below the temple's gates. Asterix supposed that that's the password that opens the... | You are given the string *s* whose length can vary from 1 to 106 (inclusive), consisting of small Latin letters. | Print the string *t*. If a suitable *t* string does not exist, then print "Just a legend" without the quotes. | [
"fixprefixsuffix\n",
"abcdabc\n"
] | [
"fix",
"Just a legend"
] | none | 1,000 | [
{
"input": "fixprefixsuffix",
"output": "fix"
},
{
"input": "abcdabc",
"output": "Just a legend"
},
{
"input": "qwertyqwertyqwerty",
"output": "qwerty"
},
{
"input": "papapapap",
"output": "papap"
},
{
"input": "aaaaaaaaaa",
"output": "aaaaaaaa"
},
{
"... | 1,670,443,958 | 2,147,483,647 | Python 3 | OK | TESTS | 97 | 1,372 | 32,051,200 | s = input()
n = len(s)
def prefix_F(s):
n = len(s)
pi = [0] * n
for i in range(1, n):
cur = pi[i - 1]
while cur > 0 and s[i] != s[cur]:
cur = pi[cur - 1]
if s[i] == s[cur]:
cur += 1
pi[i] = cur
return pi
def end():
print("Just a legend")
exit(0)
def inside(pi, x):
n = l... | Title: Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Asterix, Obelix and their temporary buddies Suffix and Prefix has finally found the Harmony temple. However, its doors were firmly locked and even Obelix had no luck opening them.
A little later they found a string *s*, carve... | ```python
s = input()
n = len(s)
def prefix_F(s):
n = len(s)
pi = [0] * n
for i in range(1, n):
cur = pi[i - 1]
while cur > 0 and s[i] != s[cur]:
cur = pi[cur - 1]
if s[i] == s[cur]:
cur += 1
pi[i] = cur
return pi
def end():
print("Just a legend")
exit(0)
def inside(pi, x... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
15 | A | Cottage Village | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Cottage Village | 2 | 64 | A new cottage village called «Flatville» is being built in Flatland. By now they have already built in «Flatville» *n* square houses with the centres on the *Оx*-axis. The houses' sides are parallel to the coordinate axes. It's known that no two houses overlap, but they can touch each other.
The architect bureau, wher... | The first line of the input data contains numbers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=1000). Then there follow *n* lines, each of them contains two space-separated integer numbers: *x**i* *a**i*, where *x**i* — *x*-coordinate of the centre of the *i*-th house, and *a**i* — length of its side (<=-<=1000<=≤<=*x**i*<=≤<=1000... | Output the amount of possible positions of the new house. | [
"2 2\n0 4\n6 2\n",
"2 2\n0 4\n5 2\n",
"2 3\n0 4\n5 2\n"
] | [
"4\n",
"3\n",
"2\n"
] | It is possible for the *x*-coordinate of the new house to have non-integer value. | 0 | [
{
"input": "2 2\n0 4\n6 2",
"output": "4"
},
{
"input": "2 2\n0 4\n5 2",
"output": "3"
},
{
"input": "2 3\n0 4\n5 2",
"output": "2"
},
{
"input": "1 1\n1 1",
"output": "2"
},
{
"input": "1 2\n2 1",
"output": "2"
},
{
"input": "2 1\n2 1\n1 1",
"outp... | 1,508,432,704 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 122 | 5,529,600 | n,t=map(int,input().split())
t=t*2
f=list()
k=2
for i in range(n):
x,y=map(int,input().split())
f.append(x*2-y)
f.append(x*2+y)
f.sort()
for i in range(2,len(f)-1,2):
if f[i]-f[i-1]>t:
k+=2
if f[i]-f[i-1]==t:
k+=1
print(k)
| Title: Cottage Village
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A new cottage village called «Flatville» is being built in Flatland. By now they have already built in «Flatville» *n* square houses with the centres on the *Оx*-axis. The houses' sides are parallel to the coordinate axes. I... | ```python
n,t=map(int,input().split())
t=t*2
f=list()
k=2
for i in range(n):
x,y=map(int,input().split())
f.append(x*2-y)
f.append(x*2+y)
f.sort()
for i in range(2,len(f)-1,2):
if f[i]-f[i-1]>t:
k+=2
if f[i]-f[i-1]==t:
k+=1
print(k)
``` | 3.928301 | MatrixStudio/Codeforces-Python-Submissions |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,583,401,367 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 307,200 | n=input()
l=list(n.strip().split())
if l[-1]=='week':
if l[0]=='1' or l[0]=='2' or l[0]=='3' or l[0]=='4' or l[0]=='7':
print(52)
elif l[0]=='5' or l[0]=='6':
print(53)
if l[-1]=='month':
if l[0] in range(1,30):
print(12)
elif l[0]=='30':
print(11)
elif l[... | Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
n=input()
l=list(n.strip().split())
if l[-1]=='week':
if l[0]=='1' or l[0]=='2' or l[0]=='3' or l[0]=='4' or l[0]=='7':
print(52)
elif l[0]=='5' or l[0]=='6':
print(53)
if l[-1]=='month':
if l[0] in range(1,30):
print(12)
elif l[0]=='30':
print(11)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
508 | A | Pasha and Pixels | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row with *m* pixels in each row. Initially, all the pixels are colored white. In one move, Pasha can choos... | The first line of the input contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=105) — the number of rows, the number of columns and the number of moves that Pasha is going to perform.
The next *k* lines contain Pasha's moves in the order he makes them. Each line contains two integers *i*... | If Pasha loses, print the number of the move when the 2<=×<=2 square consisting of black pixels is formed.
If Pasha doesn't lose, that is, no 2<=×<=2 square consisting of black pixels is formed during the given *k* moves, print 0. | [
"2 2 4\n1 1\n1 2\n2 1\n2 2\n",
"2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1\n",
"5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2\n"
] | [
"4\n",
"5\n",
"0\n"
] | none | 500 | [
{
"input": "2 2 4\n1 1\n1 2\n2 1\n2 2",
"output": "4"
},
{
"input": "2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1",
"output": "5"
},
{
"input": "5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2",
"output": "0"
},
{
"input": "3 3 11\n2 1\n3 1\n1 1\n1 3\n1 2\n2 3\n3 3\n3 2\n2 2\n1 3\n3 3",
... | 1,668,169,382 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n, m, k = map(int, input().split())
a = [[] for h in range(n)]
for s in range(n):
for t in range(m):
a[s].append(0)
if k <= 3:
print(0)
else:
for _ in range(1, k + 1):
f = 1
i, j = map(int, input().split())
i -= 1
j -= 1
a[i][j] = 1
print... | Title: Pasha and Pixels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row ... | ```python
n, m, k = map(int, input().split())
a = [[] for h in range(n)]
for s in range(n):
for t in range(m):
a[s].append(0)
if k <= 3:
print(0)
else:
for _ in range(1, k + 1):
f = 1
i, j = map(int, input().split())
i -= 1
j -= 1
a[i][j] = 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | B | The least round way | PROGRAMMING | 2,000 | [
"dp",
"math"
] | B. The least round way | 2 | 64 | There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down from the current cell; - the way ends in the bottom right cell.
Moreover, if we multiply together all... | The first line contains an integer number *n* (2<=≤<=*n*<=≤<=1000), *n* is the size of the matrix. Then follow *n* lines containing the matrix elements (non-negative integer numbers not exceeding 109). | In the first line print the least number of trailing zeros. In the second line print the correspondent way itself. | [
"3\n1 2 3\n4 5 6\n7 8 9\n"
] | [
"0\nDDRR\n"
] | none | 0 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "0\nDDRR"
},
{
"input": "2\n7 6\n3 8",
"output": "0\nDR"
},
{
"input": "3\n4 10 5\n10 9 4\n6 5 3",
"output": "1\nDRRD"
},
{
"input": "4\n1 1 9 9\n3 4 7 3\n7 9 1 7\n1 7 1 5",
"output": "0\nDDDRRR"
},
{
"input": "5\n8 3... | 1,569,788,018 | 2,147,483,647 | Python 3 | MEMORY_LIMIT_EXCEEDED | TESTS | 15 | 1,996 | 67,072,000 | import sys
sys.setrecursionlimit(30000)
def pw(n,p):
m=0
while n>0 and n%p==0:
n/=p
m+=1
return m
t2,t5=[],[]
d2,d5=[],[]
n=-1
INF=1000000
def gen(i,j):
global n, INF
if i>=n or j>=n: return INF,INF
if d2[i][j][0]>=0: return d2[i][j][0],d5[i][j][0]
o2,o5=t2[i][j],t5[i][j]
D... | Title: The least round way
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
There is a square matrix *n*<=×<=*n*, consisting of non-negative integer numbers. You should find such a way on it that
- starts in the upper left cell of the matrix; - each following cell is to the right or down fro... | ```python
import sys
sys.setrecursionlimit(30000)
def pw(n,p):
m=0
while n>0 and n%p==0:
n/=p
m+=1
return m
t2,t5=[],[]
d2,d5=[],[]
n=-1
INF=1000000
def gen(i,j):
global n, INF
if i>=n or j>=n: return INF,INF
if d2[i][j][0]>=0: return d2[i][j][0],d5[i][j][0]
o2,o5=t2[i][j],t5[... | 0 | MatrixStudio/Codeforces-Python-Submissions |
515 | A | Drazil and Date | PROGRAMMING | 1,000 | [
"math"
] | null | null | Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit distance in horizontal or vertical direction. In other words, from position (*x*,<=*y*) he can go to ... | You are given three integers *a*, *b*, and *s* (<=-<=109<=≤<=*a*,<=*b*<=≤<=109, 1<=≤<=*s*<=≤<=2·109) in a single line. | If you think Drazil made a mistake and it is impossible to take exactly *s* steps and get from his home to Varda's home, print "No" (without quotes).
Otherwise, print "Yes". | [
"5 5 11\n",
"10 15 25\n",
"0 5 1\n",
"0 0 2\n"
] | [
"No\n",
"Yes\n",
"No\n",
"Yes\n"
] | In fourth sample case one possible route is: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/0d30660ddf6eb6c64ffd071055a4e8ddd016cde5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. | 500 | [
{
"input": "5 5 11",
"output": "No"
},
{
"input": "10 15 25",
"output": "Yes"
},
{
"input": "0 5 1",
"output": "No"
},
{
"input": "0 0 2",
"output": "Yes"
},
{
"input": "999999999 999999999 2000000000",
"output": "Yes"
},
{
"input": "-606037695 9983201... | 1,640,332,033 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 77 | 0 | import math
a,b,s=map(int,input().split(' '))
bl=False
if(s>=(abs(a)+abs(b))):
v=abs(a)+abs(b)
if(v%2==0 and s%2==0):
bl=True
if(v%2!=0 and s%2!=0):
bl=True
if(bl):
print("Yes")
else:
print("No")
| Title: Drazil and Date
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil's home is located in point (0,<=0) and Varda's home is located in point (*a*,<=*b*). In each step, he can move in a unit ... | ```python
import math
a,b,s=map(int,input().split(' '))
bl=False
if(s>=(abs(a)+abs(b))):
v=abs(a)+abs(b)
if(v%2==0 and s%2==0):
bl=True
if(v%2!=0 and s%2!=0):
bl=True
if(bl):
print("Yes")
else:
print("No")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
876 | A | Trip For Meal | PROGRAMMING | 900 | [
"math"
] | null | null | Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is *a* meters, between Rabbit's ... | First line contains an integer *n* (1<=≤<=*n*<=≤<=100) — number of visits.
Second line contains an integer *a* (1<=≤<=*a*<=≤<=100) — distance between Rabbit's and Owl's houses.
Third line contains an integer *b* (1<=≤<=*b*<=≤<=100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer *c* ... | Output one number — minimum distance in meters Winnie must go through to have a meal *n* times. | [
"3\n2\n3\n1\n",
"1\n2\n3\n5\n"
] | [
"3\n",
"0\n"
] | In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | 500 | [
{
"input": "3\n2\n3\n1",
"output": "3"
},
{
"input": "1\n2\n3\n5",
"output": "0"
},
{
"input": "10\n1\n8\n3",
"output": "9"
},
{
"input": "7\n10\n5\n6",
"output": "30"
},
{
"input": "9\n9\n7\n5",
"output": "42"
},
{
"input": "9\n37\n85\n76",
"outpu... | 1,655,542,809 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n = int(input())
a = int(input())
b = int(input())
c = int(input())
print(min(min(a, b) * (n - 1), min(a, b) + c * (n - 2)))
| Title: Trip For Meal
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair... | ```python
n = int(input())
a = int(input())
b = int(input())
c = int(input())
print(min(min(a, b) * (n - 1), min(a, b) + c * (n - 2)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
192 | B | Walking in the Rain | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start walking on the tile number 1 and the finish on the tile number *n*. During the walk it is allowed to move... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the boulevard's length in tiles.
The second line contains *n* space-separated integers *a**i* — the number of days after which the *i*-th tile gets destroyed (1<=≤<=*a**i*<=≤<=103). | Print a single number — the sought number of days. | [
"4\n10 3 5 10\n",
"5\n10 2 8 3 5\n"
] | [
"5\n",
"5\n"
] | In the first sample the second tile gets destroyed after day three, and the only path left is 1 → 3 → 4. After day five there is a two-tile gap between the first and the last tile, you can't jump over it.
In the second sample path 1 → 3 → 5 is available up to day five, inclusive. On day six the last tile is destroyed ... | 1,000 | [
{
"input": "4\n10 3 5 10",
"output": "5"
},
{
"input": "5\n10 2 8 3 5",
"output": "5"
},
{
"input": "10\n10 3 1 6 7 1 3 3 8 1",
"output": "1"
},
{
"input": "10\n26 72 10 52 2 5 61 2 39 64",
"output": "5"
},
{
"input": "100\n8 2 1 2 8 3 5 8 5 1 9 3 4 1 5 6 4 2 9 10... | 1,554,808,487 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 310 | 512,000 | # Author Kmoussai
import sys
import math
import random
'''
i = 0
while i < n:
i += 1
map(int, input().split())
def pgcd(a, b):
if b == 0:
return a
return pgcd(b, a%b)
'''
if len(sys.argv) >= 2:
if sys.argv[1] == 'LOCAL':
sys.stdin = open('input.in', 'r')
def check(l, n):
... | Title: Walking in the Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland the opposition is going to arrange mass walking on the boulevard. The boulevard consists of *n* tiles that are lain in a row and are numbered from 1 to *n* from right to left. The opposition should start ... | ```python
# Author Kmoussai
import sys
import math
import random
'''
i = 0
while i < n:
i += 1
map(int, input().split())
def pgcd(a, b):
if b == 0:
return a
return pgcd(b, a%b)
'''
if len(sys.argv) >= 2:
if sys.argv[1] == 'LOCAL':
sys.stdin = open('input.in', 'r')
def check(l... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,686,127,753 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 122 | 0 | n,a,b=map(int,input().strip().split())
print(n-max(n-b,a+1)+1) | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n,a,b=map(int,input().strip().split())
print(n-max(n-b,a+1)+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
334 | A | Candy Bags | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from 1 to *n*2 he has exactly one bag with *k* candies.
Help him give *n* bags of candies to each b... | The single line contains a single integer *n* (*n* is even, 2<=≤<=*n*<=≤<=100) — the number of Gerald's brothers. | Let's assume that Gerald indexes his brothers with numbers from 1 to *n*. You need to print *n* lines, on the *i*-th line print *n* integers — the numbers of candies in the bags for the *i*-th brother. Naturally, all these numbers should be distinct and be within limits from 1 to *n*2. You can print the numbers in the ... | [
"2\n"
] | [
"1 4\n2 3\n"
] | The sample shows Gerald's actions if he has two brothers. In this case, his bags contain 1, 2, 3 and 4 candies. He can give the bags with 1 and 4 candies to one brother and the bags with 2 and 3 to the other brother. | 500 | [
{
"input": "2",
"output": "1 4\n2 3"
},
{
"input": "4",
"output": "1 16 2 15\n3 14 4 13\n5 12 6 11\n7 10 8 9"
},
{
"input": "6",
"output": "1 36 2 35 3 34\n4 33 5 32 6 31\n7 30 8 29 9 28\n10 27 11 26 12 25\n13 24 14 23 15 22\n16 21 17 20 18 19"
},
{
"input": "8",
"output"... | 1,473,158,573 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 124 | 102,400 | x = int(input())
buffer=2
for i in range(1, int(x**2/2)+1):
print("{:d} {:d} ".format(i, (x**2)+1-i), end="")
if buffer%x == 0:
print()
buffer += 2
| Title: Candy Bags
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from ... | ```python
x = int(input())
buffer=2
for i in range(1, int(x**2/2)+1):
print("{:d} {:d} ".format(i, (x**2)+1-i), end="")
if buffer%x == 0:
print()
buffer += 2
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
302 | A | Eugeny and Array | PROGRAMMING | 800 | [
"implementation"
] | null | null | Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of a... | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). | Print *m* integers — the responses to Eugene's queries in the order they occur in the input. | [
"2 3\n1 -1\n1 1\n1 2\n2 2\n",
"5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n"
] | [
"0\n1\n0\n",
"0\n1\n0\n1\n0\n"
] | none | 500 | [
{
"input": "2 3\n1 -1\n1 1\n1 2\n2 2",
"output": "0\n1\n0"
},
{
"input": "5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5",
"output": "0\n1\n0\n1\n0"
},
{
"input": "3 3\n1 1 1\n2 2\n1 1\n1 1",
"output": "0\n0\n0"
},
{
"input": "4 4\n-1 -1 -1 -1\n1 3\n1 2\n1 2\n1 1",
"output": "... | 1,615,299,556 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 10 | 77 | 3,891,200 | def sum_of_subset(idx, sm, count):
if sm == 0:
lst.append(count)
if idx == n:
return
sum_of_subset(idx+1, sm + arr[idx+1], count+1)
sum_of_subset(idx+1, sm, count)
n, m = map(int, input().split())
arr = [int(i) for i in input().split()]
arr.append(-9999999999999999)
arr... | Title: Eugeny and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (... | ```python
def sum_of_subset(idx, sm, count):
if sm == 0:
lst.append(count)
if idx == n:
return
sum_of_subset(idx+1, sm + arr[idx+1], count+1)
sum_of_subset(idx+1, sm, count)
n, m = map(int, input().split())
arr = [int(i) for i in input().split()]
arr.append(-999999999999... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,695,560,531 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 154 | 0 |
def is_even(weight):
if weight % 2 == 0:
return True
else:
return False
weight = int(input())
if is_even(weight):
print('Yes')
else:
print('No') | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
def is_even(weight):
if weight % 2 == 0:
return True
else:
return False
weight = int(input())
if is_even(weight):
print('Yes')
else:
print('No')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
96 | B | Lucky Numbers (easy) | PROGRAMMING | 1,300 | [
"binary search",
"bitmasks",
"brute force"
] | B. Lucky Numbers (easy) | 2 | 256 | Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Lucky number is super lucky if it's decimal representation contains equal amount of digits 4 and 7. Fo... | The only line contains a positive integer *n* (1<=≤<=*n*<=≤<=109). This number doesn't have leading zeroes. | Output the least super lucky number that is more than or equal to *n*.
Please, do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"4500\n",
"47\n"
] | [
"4747\n",
"47\n"
] | none | 1,000 | [
{
"input": "4500",
"output": "4747"
},
{
"input": "47",
"output": "47"
},
{
"input": "1",
"output": "47"
},
{
"input": "12",
"output": "47"
},
{
"input": "4587",
"output": "4747"
},
{
"input": "100",
"output": "4477"
},
{
"input": "1007",
... | 1,692,549,765 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | # https://codeforces.com/problemset/problem/96/B
n = int(input())
def superLucky(n):
if str(n).count("4") == str(n).count("7") and (str(n).count("4") + str(n).count("7") == len(str(n))):
return True
def findN(n):
s = n
while True:
if superLucky(s):
return s
s ... | Title: Lucky Numbers (easy)
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that positive integers are lucky if their decimal representation doesn't contain digits other than 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
# https://codeforces.com/problemset/problem/96/B
n = int(input())
def superLucky(n):
if str(n).count("4") == str(n).count("7") and (str(n).count("4") + str(n).count("7") == len(str(n))):
return True
def findN(n):
s = n
while True:
if superLucky(s):
return s
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
888 | C | K-Dominant Character | PROGRAMMING | 1,400 | [
"binary search",
"implementation",
"two pointers"
] | null | null | You are given a string *s* consisting of lowercase Latin letters. Character *c* is called *k*-dominant iff each substring of *s* with length at least *k* contains this character *c*.
You have to find minimum *k* such that there exists at least one *k*-dominant character. | The first line contains string *s* consisting of lowercase Latin letters (1<=≤<=|*s*|<=≤<=100000). | Print one number — the minimum value of *k* such that there exists at least one *k*-dominant character. | [
"abacaba\n",
"zzzzz\n",
"abcde\n"
] | [
"2\n",
"1\n",
"3\n"
] | none | 0 | [
{
"input": "abacaba",
"output": "2"
},
{
"input": "zzzzz",
"output": "1"
},
{
"input": "abcde",
"output": "3"
},
{
"input": "bcaccacaaabaacaabaaabcbbcbcaacacbcbaaaacccacbbcbaabcbacaacbabacacacaccbbccbcbacbbbbccccabcabaaab",
"output": "8"
},
{
"input": "daabcdabbab... | 1,691,558,111 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 10,956,800 | def in_between(s, char):
a = []
idx1 = None
idx2 = None
for i, c in enumerate(s):
if c == char:
if idx1 is None:
idx1 = i
idx2 = i
a.append(i)
a.insert(0, -1)
a.append(len(s) - 1)
return max(a[i + 1] - a[i] for i in rang... | Title: K-Dominant Character
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting of lowercase Latin letters. Character *c* is called *k*-dominant iff each substring of *s* with length at least *k* contains this character *c*.
You have to find minimum *k* s... | ```python
def in_between(s, char):
a = []
idx1 = None
idx2 = None
for i, c in enumerate(s):
if c == char:
if idx1 is None:
idx1 = i
idx2 = i
a.append(i)
a.insert(0, -1)
a.append(len(s) - 1)
return max(a[i + 1] - a[i] for... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,611,427,767 | 2,147,483,647 | PyPy 3 | OK | TESTS | 51 | 248 | 3,584,000 | n = list(map(int, input()))
i = 0
while True:
if len(n) == 1:
print(i)
break
n = str(sum(n))
n = list(map(int, n))
i += 1 | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
n = list(map(int, input()))
i = 0
while True:
if len(n) == 1:
print(i)
break
n = str(sum(n))
n = list(map(int, n))
i += 1
``` | 3.931551 | MatrixStudio/Codeforces-Python-Submissions |
630 | J | Divisibility | PROGRAMMING | 1,100 | [
"math",
"number theory"
] | null | null | IT City company developing computer games invented a new way to reward its employees. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. Every time when the next number of sales is divisible by all numbers from 2 to 10 every developer ... | The only line of the input contains one integer *n* (1<=≤<=*n*<=≤<=1018) — the prediction on the number of people who will buy the game. | Output one integer showing how many numbers from 1 to *n* are divisible by all numbers from 2 to 10. | [
"3000\n"
] | [
"1"
] | none | 0 | [
{
"input": "3000",
"output": "1"
},
{
"input": "2520",
"output": "1"
},
{
"input": "2519",
"output": "0"
},
{
"input": "2521",
"output": "1"
},
{
"input": "1",
"output": "0"
},
{
"input": "314159265",
"output": "124666"
},
{
"input": "71828... | 1,694,261,209 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | a = int(input())
b = 0
for i in range(3,10):
if a%i==0:
b+=1
print(b) | Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
IT City company developing computer games invented a new way to reward its employees. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. ... | ```python
a = int(input())
b = 0
for i in range(3,10):
if a%i==0:
b+=1
print(b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,628,093,927 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 62 | 6,963,200 | num = int(input())
string = str(input())
strlist = string.split(' ')
counter = list()
length = len(strlist)
for x in range(length) :
counter.append(0)
for x in range(length):
for y in (strlist[x]):
element = strlist[x]
if y.isupper():
a = counter[x]
a = a+1
c... | Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
num = int(input())
string = str(input())
strlist = string.split(' ')
counter = list()
length = len(strlist)
for x in range(length) :
counter.append(0)
for x in range(length):
for y in (strlist[x]):
element = strlist[x]
if y.isupper():
a = counter[x]
a = a+1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,532,732,738 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 248 | 0 | n = int(input())
values = [int(k) for k in input().split()]
values.sort()
spaces = [True]*3002
spaces[0] = False
for i in values:
spaces[i] = False
print(spaces.index(True)) | Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the... | ```python
n = int(input())
values = [int(k) for k in input().split()]
values.sort()
spaces = [True]*3002
spaces[0] = False
for i in values:
spaces[i] = False
print(spaces.index(True))
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
825 | C | Multi-judge Solving | PROGRAMMING | 1,600 | [
"greedy",
"implementation"
] | null | null | Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the problem with difficulty *d* on Decoforces is as hard as the problem with difficulty *d* on any other judge).... | The first line contains two integer numbers *n*, *k* (1<=≤<=*n*<=≤<=103, 1<=≤<=*k*<=≤<=109).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print minimum number of problems Makes should solve on other judges in order to solve all chosen problems on Decoforces. | [
"3 3\n2 1 9\n",
"4 20\n10 3 6 3\n"
] | [
"1\n",
"0\n"
] | In the first example Makes at first solves problems 1 and 2. Then in order to solve the problem with difficulty 9, he should solve problem with difficulty no less than 5. The only available are difficulties 5 and 6 on some other judge. Solving any of these will give Makes opportunity to solve problem 3.
In the second ... | 0 | [
{
"input": "3 3\n2 1 9",
"output": "1"
},
{
"input": "4 20\n10 3 6 3",
"output": "0"
},
{
"input": "1 1000000000\n1",
"output": "0"
},
{
"input": "1 1\n3",
"output": "1"
},
{
"input": "50 100\n74 55 33 5 83 24 75 59 30 36 13 4 62 28 96 17 6 35 45 53 33 11 37 93 34... | 1,510,765,543 | 6,043 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | c = [int(i) for i in input().split()]
x = [int(f) for f in input().split()]
n = 0
for t in x:
if (t / 2) >= (c[1] / 2):
n = n + 1
print(n)
| Title: Multi-judge Solving
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the pro... | ```python
c = [int(i) for i in input().split()]
x = [int(f) for f in input().split()]
n = 0
for t in x:
if (t / 2) >= (c[1] / 2):
n = n + 1
print(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | A dragon symbolizes wisdom, power and wealth. On Lunar New Year's Day, people model a dragon with bamboo strips and clothes, raise them with rods, and hold the rods high and low to resemble a flying dragon.
A performer holding the rod low is represented by a 1, while one holding it high is represented by a 2. Thus, th... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=2000), denoting the length of the original sequence.
The second line contains *n* space-separated integers, describing the original sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2,<=*i*<==<=1,<=2,<=...,<=*n*). | Print a single integer, which means the maximum possible length of the longest non-decreasing subsequence of the new sequence. | [
"4\n1 2 1 2\n",
"10\n1 1 2 2 2 1 1 2 2 1\n"
] | [
"4\n",
"9\n"
] | In the first example, after reversing [2, 3], the array will become [1, 1, 2, 2], where the length of the longest non-decreasing subsequence is 4.
In the second example, after reversing [3, 7], the array will become [1, 1, 1, 1, 2, 2, 2, 2, 2, 1], where the length of the longest non-decreasing subsequence is 9. | 0 | [
{
"input": "4\n1 2 1 2",
"output": "4"
},
{
"input": "10\n1 1 2 2 2 1 1 2 2 1",
"output": "9"
},
{
"input": "200\n2 1 1 2 1 2 2 2 2 2 1 2 2 1 1 2 2 1 1 1 2 1 1 2 2 2 2 2 1 1 2 1 2 1 1 2 1 1 1 1 2 1 2 2 1 2 1 1 1 2 1 1 1 2 2 2 1 1 1 1 2 2 2 1 2 2 2 1 2 2 2 1 2 1 2 1 2 1 1 1 1 2 2 2 1 1 2 ... | 1,518,617,056 | 7,156 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 2 | 1,000 | 5,632,000 | R=lambda:map(int,input().split())
n = R()
a = list(R())
ones = a.count(1)
twos = a.count(2)
def solve(a):
ones_right = ones
twos_right = twos
ones_left = 0
twos_left = 0
ans = 0
for i in range(len(a)):
if a[i] == 1:
ans = max(ans, ones_left + twos_right)
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A dragon symbolizes wisdom, power and wealth. On Lunar New Year's Day, people model a dragon with bamboo strips and clothes, raise them with rods, and hold the rods high and low to resemble a flying dragon.
A performer holding th... | ```python
R=lambda:map(int,input().split())
n = R()
a = list(R())
ones = a.count(1)
twos = a.count(2)
def solve(a):
ones_right = ones
twos_right = twos
ones_left = 0
twos_left = 0
ans = 0
for i in range(len(a)):
if a[i] == 1:
ans = max(ans, ones_left + twos... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for ... | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use al... | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,683,639,561 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | a=list(map(int,input().split()))
f=1
for i in range(a[0]):
if i%2==0:
print("#"*a[1])
else:
if f:
print('.'*(a[1]-1)+'#')
f=0
else:
print('#'+'.'*(a[1]-1))
f=1 | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr ... | ```python
a=list(map(int,input().split()))
f=1
for i in range(a[0]):
if i%2==0:
print("#"*a[1])
else:
if f:
print('.'*(a[1]-1)+'#')
f=0
else:
print('#'+'.'*(a[1]-1))
f=1
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,622,662,408 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 155 | 0 | """Copyright © 2021 Rishabh Rao.
All Rights Reserved."""
import sys
MOD = 1000000007
inp = sys.stdin.readline
def ii(): return int(inp())
def iis(): return [int(i) for i in inp().split()]
s = inp()
hello = "hello"
j = 0
for i in range(len(s)):
if s[i] == hello[j]:
j += 1
if j == 5:
... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
"""Copyright © 2021 Rishabh Rao.
All Rights Reserved."""
import sys
MOD = 1000000007
inp = sys.stdin.readline
def ii(): return int(inp())
def iis(): return [int(i) for i in inp().split()]
s = inp()
hello = "hello"
j = 0
for i in range(len(s)):
if s[i] == hello[j]:
j += 1
if ... | 3.9225 | MatrixStudio/Codeforces-Python-Submissions |
863 | B | Kayaking | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"sortings"
] | null | null | Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they have to choose kayaks. There are 2·*n* people in the group (including Vadim), and they have exact... | The first line contains one number *n* (2<=≤<=*n*<=≤<=50).
The second line contains 2·*n* integer numbers *w*1, *w*2, ..., *w*2*n*, where *w**i* is weight of person *i* (1<=≤<=*w**i*<=≤<=1000). | Print minimum possible total instability. | [
"2\n1 2 3 4\n",
"4\n1 3 4 6 3 4 100 200\n"
] | [
"1\n",
"5\n"
] | none | 0 | [
{
"input": "2\n1 2 3 4",
"output": "1"
},
{
"input": "4\n1 3 4 6 3 4 100 200",
"output": "5"
},
{
"input": "3\n305 139 205 406 530 206",
"output": "102"
},
{
"input": "3\n610 750 778 6 361 407",
"output": "74"
},
{
"input": "5\n97 166 126 164 154 98 221 7 51 47",
... | 1,665,100,091 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | import math
n = int(input())
k = list(map(int, input().split(" ")))
k.sort()
instability = 0
linst = 0
#pair and get instability
for i in range(len(k)):
if i%2 != 0: continue
inst = int(math.fabs(k[i+1]-k[i]))
instability += inst
if inst > linst:
linst = inst
instability -= linst
pri... | Title: Kayaking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vadim is really keen on travelling. Recently he heard about kayaking activity near his town and became very excited about it, so he joined a party of kayakers.
Now the party is ready to start its journey, but firstly they hav... | ```python
import math
n = int(input())
k = list(map(int, input().split(" ")))
k.sort()
instability = 0
linst = 0
#pair and get instability
for i in range(len(k)):
if i%2 != 0: continue
inst = int(math.fabs(k[i+1]-k[i]))
instability += inst
if inst > linst:
linst = inst
instability -= li... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, inf... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word bec... | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,693,138,162 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 614,400 | n=int(input())
encoded_word=str(input())
decoded_word=encoded_word[0]
for i in range(1,n):
if n%2>0:
if i%2>0:
decoded_word=encoded_word[i]+decoded_word
else:
decoded_word=decoded_word+encoded_word[i]
else:
if i%2==0:
decoded_word=encoded_word[i]+decod... | Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the... | ```python
n=int(input())
encoded_word=str(input())
decoded_word=encoded_word[0]
for i in range(1,n):
if n%2>0:
if i%2>0:
decoded_word=encoded_word[i]+decoded_word
else:
decoded_word=decoded_word+encoded_word[i]
else:
if i%2==0:
decoded_word=encoded_wor... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
456 | B | Fedya and Maths | PROGRAMMING | 1,200 | [
"math",
"number theory"
] | null | null | Fedya studies in a gymnasium. Fedya's maths hometask is to calculate the following expression:
for given value of *n*. Fedya managed to complete the task. Can you? Note that given number *n* can be extremely large (e.g. it can exceed any integer type of your programming language). | The single line contains a single integer *n* (0<=≤<=*n*<=≤<=10105). The number doesn't contain any leading zeroes. | Print the value of the expression without leading zeros. | [
"4\n",
"124356983594583453458888889\n"
] | [
"4\n",
"0\n"
] | Operation *x* *mod* *y* means taking remainder after division *x* by *y*.
Note to the first sample:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/825f244180bb10323db01645118c3cfdb312fa89.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4",
"output": "4"
},
{
"input": "124356983594583453458888889",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "7854",
"output": "0"
},
{
"input": "584660",
"output": "4"
},
{
"input": "464",
"output": "4"
},
{
"inp... | 1,690,916,579 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 342 | 19,148,800 | from decimal import Decimal
import math
n = int(input())
num = Decimal(n)
print((1 + pow(2, n%4) + pow(3, n%4) + pow(4, n%4)) % 5) | Title: Fedya and Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fedya studies in a gymnasium. Fedya's maths hometask is to calculate the following expression:
for given value of *n*. Fedya managed to complete the task. Can you? Note that given number *n* can be extremely large (e.g... | ```python
from decimal import Decimal
import math
n = int(input())
num = Decimal(n)
print((1 + pow(2, n%4) + pow(3, n%4) + pow(4, n%4)) % 5)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
222 | A | Shooshuns and Sequence | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the current sequence and add the same number to the end of the sequence; 1. Delete the first number of the current ... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the sequence that the shooshuns found. | Print the minimum number of operations, required for all numbers on the blackboard to become the same. If it is impossible to achieve, print -1. | [
"3 2\n3 1 1\n",
"3 1\n3 1 1\n"
] | [
"1\n",
"-1\n"
] | In the first test case after the first operation the blackboard will have sequence [1, 1, 1]. So, one operation is enough to make all numbers the same. Thus, the answer equals one.
In the second test case the sequence will never consist of the same numbers. It will always contain at least two distinct numbers 3 and 1.... | 500 | [
{
"input": "3 2\n3 1 1",
"output": "1"
},
{
"input": "3 1\n3 1 1",
"output": "-1"
},
{
"input": "1 1\n1",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "0"
},
{
"input": "2 1\n2 1",
"output": "-1"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
}... | 1,493,329,317 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 186 | 11,878,400 | '''input
3 2
3 1 1
'''
n, k = map(int, input().split())
a = list(map(int, input().split()))
if k > 1 and k % 2 == 0:
for x in range(n-1, -1, -1):
if a[x] != a[k-1]:
break
print(x+1)
elif len(set(a)) == 1:
print(0)
else:
print(-1) | Title: Shooshuns and Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day shooshuns found a sequence of *n* integers, written on a blackboard. The shooshuns can perform one operation with it, the operation consists of two steps:
1. Find the number that goes *k*-th in the cur... | ```python
'''input
3 2
3 1 1
'''
n, k = map(int, input().split())
a = list(map(int, input().split()))
if k > 1 and k % 2 == 0:
for x in range(n-1, -1, -1):
if a[x] != a[k-1]:
break
print(x+1)
elif len(set(a)) == 1:
print(0)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
306 | A | Candies | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most equal) manner. He wants to choose such *a**i*, where *a**i* is the number of candies in the *... | The single line of the input contains a pair of space-separated positive integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100;*n*<=≥<=*m*) — the number of candies and the number of Polycarpus's friends. | Print the required sequence *a*1,<=*a*2,<=...,<=*a**m*, where *a**i* is the number of candies in the *i*-th friend's present. All numbers *a**i* must be positive integers, total up to *n*, the maximum one should differ from the minimum one by the smallest possible value. | [
"12 3\n",
"15 4\n",
"18 7\n"
] | [
"4 4 4 ",
"3 4 4 4 ",
"2 2 2 3 3 3 3 "
] | Print *a*<sub class="lower-index">*i*</sub> in any order, separate the numbers by spaces. | 500 | [
{
"input": "12 4",
"output": "3 3 3 3 "
},
{
"input": "15 6",
"output": "2 2 2 3 3 3 "
},
{
"input": "18 8",
"output": "2 2 2 2 2 2 3 3 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "2 1",
"output": "2 "
},
{
"input": "100 1",
"output": "100 ... | 1,647,140,252 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 62 | 0 | n,m=map(int,input().split())
print(f'{n//m+1} '*(n%m)+f'{n//m} '*(m-n%m)) | Title: Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most ... | ```python
n,m=map(int,input().split())
print(f'{n//m+1} '*(n%m)+f'{n//m} '*(m-n%m))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,691,563,698 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | b = input()
t = b.replace("--", "2").replace("-.", "1").replace(".", "0")
print(t) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
b = input()
t = b.replace("--", "2").replace("-.", "1").replace(".", "0")
print(t)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,596,787,928 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 6,963,200 | n,m=map(int,input().split())
d={}
for i in range(m):
a,b=map(int,input().split())
if a>b:
d[b]=a
elif b>a:
d[a]=b
else:
d[a]=a
s=input()
for i in s:
if i!=" ":
if i in d.keys():
print(d[i],end="")
else:
print(i,end="")
... | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
n,m=map(int,input().split())
d={}
for i in range(m):
a,b=map(int,input().split())
if a>b:
d[b]=a
elif b>a:
d[a]=b
else:
d[a]=a
s=input()
for i in s:
if i!=" ":
if i in d.keys():
print(d[i],end="")
else:
print(i... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
652 | B | z-sort | PROGRAMMING | 1,000 | [
"sortings"
] | null | null | A student of *z*-school found a kind of sorting called *z*-sort. The array *a* with *n* elements are *z*-sorted if two conditions hold:
1. *a**i*<=≥<=*a**i*<=-<=1 for all even *i*, 1. *a**i*<=≤<=*a**i*<=-<=1 for all odd *i*<=><=1.
For example the arrays [1,2,1,2] and [1,1,1,1] are *z*-sorted while the array [1,2... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | If it's possible to make the array *a* *z*-sorted print *n* space separated integers *a**i* — the elements after *z*-sort. Otherwise print the only word "Impossible". | [
"4\n1 2 2 1\n",
"5\n1 3 2 2 5\n"
] | [
"1 2 1 2\n",
"1 5 2 3 2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 1",
"output": "1 2 1 2"
},
{
"input": "5\n1 3 2 2 5",
"output": "1 5 2 3 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "1 1 1 1 1 1 1 1 1 1"
},
{
"input": "10\n1 9 7 6 2 4 7 8 1 3",
"output": "1 ... | 1,459,022,612 | 2,147,483,647 | Python 3 | OK | TESTS | 16 | 61 | 5,120,000 | #!/usr/bin/python3
n = int(input())
a = sorted([int(i) for i in input().split()])
i = 0
d = 1
s = n-1
while s >= 0:
print(a[i], end=' ')
i += d * s
s -= 1
d *= -1
| Title: z-sort
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A student of *z*-school found a kind of sorting called *z*-sort. The array *a* with *n* elements are *z*-sorted if two conditions hold:
1. *a**i*<=≥<=*a**i*<=-<=1 for all even *i*, 1. *a**i*<=≤<=*a**i*<=-<=1 for all odd *i*<=... | ```python
#!/usr/bin/python3
n = int(input())
a = sorted([int(i) for i in input().split()])
i = 0
d = 1
s = n-1
while s >= 0:
print(a[i], end=' ')
i += d * s
s -= 1
d *= -1
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,011 | A | Stages | PROGRAMMING | 900 | [
"greedy",
"implementation",
"sortings"
] | null | null | Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.
There are $n$ stages available. The ro... | The first line of input contains two integers — $n$ and $k$ ($1 \le k \le n \le 50$) – the number of available stages and the number of stages to use in the rocket.
The second line contains string $s$, which consists of exactly $n$ lowercase Latin letters. Each letter defines a new stage, which can be used to build th... | Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all. | [
"5 3\nxyabd\n",
"7 4\nproblem\n",
"2 2\nab\n",
"12 1\nabaabbaaabbb\n"
] | [
"29",
"34",
"-1",
"1"
] | In the first example, the following rockets satisfy the condition:
- "adx" (weight is $1+4+24=29$);- "ady" (weight is $1+4+25=30$);- "bdx" (weight is $2+4+24=30$);- "bdy" (weight is $2+4+25=31$).
Rocket "adx" has the minimal weight, so the answer is $29$.
In the second example, target rocket is "belo". Its weight ... | 500 | [
{
"input": "5 3\nxyabd",
"output": "29"
},
{
"input": "7 4\nproblem",
"output": "34"
},
{
"input": "2 2\nab",
"output": "-1"
},
{
"input": "12 1\nabaabbaaabbb",
"output": "1"
},
{
"input": "50 13\nqwertyuiopasdfghjklzxcvbnmaaaaaaaaaaaaaaaaaaaaaaaa",
"output": ... | 1,565,725,065 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 108 | 0 | n,k=map(int,input().split())
s=sorted(list(map(ord,input())))
c=[]
y=0
for i in range(n-1):
if s[i]-y>1:
c.append(s[i])
y=s[i]
if len(c)==k:
break
x=[c[i]-96 for i in range(len(c))]
if len(x)==k:
print(sum(x))
else:
print(-1) | Title: Stages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — conca... | ```python
n,k=map(int,input().split())
s=sorted(list(map(ord,input())))
c=[]
y=0
for i in range(n-1):
if s[i]-y>1:
c.append(s[i])
y=s[i]
if len(c)==k:
break
x=[c[i]-96 for i in range(len(c))]
if len(x)==k:
print(sum(x))
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
545 | C | Woodcutters | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described below.
There are *n* trees located along the road at points with coordinates *x*1,<=*x*2,<=...,<=... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of trees.
Next *n* lines contain pairs of integers *x**i*,<=*h**i* (1<=≤<=*x**i*,<=*h**i*<=≤<=109) — the coordinate and the height of the *і*-th tree.
The pairs are given in the order of ascending *x**i*. No two trees are located at the point with t... | Print a single number — the maximum number of trees that you can cut down by the given rules. | [
"5\n1 2\n2 1\n5 10\n10 9\n19 1\n",
"5\n1 2\n2 1\n5 10\n10 9\n20 1\n"
] | [
"3\n",
"4\n"
] | In the first sample you can fell the trees like that:
- fell the 1-st tree to the left — now it occupies segment [ - 1;1] - fell the 2-nd tree to the right — now it occupies segment [2;3] - leave the 3-rd tree — it occupies point 5 - leave the 4-th tree — it occupies point 10 - fell the 5-th tree to the right — ... | 1,750 | [
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n19 1",
"output": "3"
},
{
"input": "5\n1 2\n2 1\n5 10\n10 9\n20 1",
"output": "4"
},
{
"input": "4\n10 4\n15 1\n19 3\n20 1",
"output": "4"
},
{
"input": "35\n1 7\n3 11\n6 12\n7 6\n8 5\n9 11\n15 3\n16 10\n22 2\n23 3\n25 7\n27 3\n34 5\n35 10... | 1,698,309,462 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 218 | 8,192,000 | n = int(input())
pos = [0 for i in range(n+1)]
height = [0 for i in range(n+1)]
answer = 2
for i in range(n):
pos[i+1],height[i+1] = map(int,input().split())
for i in range(2,n):
if pos[i]-height[i] > pos[i-1]:
answer += 1
elif pos[i]+height[i] < pos[i+1]:
answer += 1
pos[... | Title: Woodcutters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Susie listens to fairy tales before bed every day. Today's fairy tale was about wood cutters and the little girl immediately started imagining the choppers cutting wood. She imagined the situation that is described b... | ```python
n = int(input())
pos = [0 for i in range(n+1)]
height = [0 for i in range(n+1)]
answer = 2
for i in range(n):
pos[i+1],height[i+1] = map(int,input().split())
for i in range(2,n):
if pos[i]-height[i] > pos[i-1]:
answer += 1
elif pos[i]+height[i] < pos[i+1]:
answer += 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
993 | A | Two Squares | PROGRAMMING | 1,600 | [
"geometry",
"implementation"
] | null | null | You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered to be part of the square, i.e. if one square is completely inside another, they intersect. If the ... | The input data consists of two lines, one for each square, both containing 4 pairs of integers. Each pair represents coordinates of one vertex of the square. Coordinates within each line are either in clockwise or counterclockwise order.
The first line contains the coordinates of the square with sides parallel to the ... | Print "Yes" if squares intersect, otherwise print "No".
You can print each letter in any case (upper or lower). | [
"0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1\n",
"0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1\n",
"6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the second square lies entirely within the first square, so they do intersect.
In the second sample squares do not have any points in common.
Here are images corresponding to the samples: | 500 | [
{
"input": "0 0 6 0 6 6 0 6\n1 3 3 5 5 3 3 1",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n7 3 9 5 11 3 9 1",
"output": "NO"
},
{
"input": "6 0 6 6 0 6 0 0\n7 4 4 7 7 10 10 7",
"output": "YES"
},
{
"input": "0 0 6 0 6 6 0 6\n8 4 4 8 8 12 12 8",
"output": "YES"
},
... | 1,599,186,511 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 93 | 307,200 | import math
x1,y1,x2,y2,x3,y3,x4,y4=map(int,input().split())
a1,b1,a2,b2,a3,b3,a4,b4=map(int,input().split())
cx1=(x1+x3)/2
l1=abs(x1-x2)+abs(y1-y2)
l2=abs(a1-a2)+abs(b1-b2)
cy1=(y1+y3)/2
ax1=(a1+a3)/2
ay1=(b1+b3)/2
if(math.dist([cx1,cy1],[ax1,ay1])>l1/2+l2/math.sqrt(2)):
print("NO")
else:
print("YE... | Title: Two Squares
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two squares, one with sides parallel to the coordinate axes, and another one with sides at 45 degrees to the coordinate axes. Find whether the two squares intersect.
The interior of the square is considered t... | ```python
import math
x1,y1,x2,y2,x3,y3,x4,y4=map(int,input().split())
a1,b1,a2,b2,a3,b3,a4,b4=map(int,input().split())
cx1=(x1+x3)/2
l1=abs(x1-x2)+abs(y1-y2)
l2=abs(a1-a2)+abs(b1-b2)
cy1=(y1+y3)/2
ax1=(a1+a3)/2
ay1=(b1+b3)/2
if(math.dist([cx1,cy1],[ax1,ay1])>l1/2+l2/math.sqrt(2)):
print("NO")
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
650 | A | Watchmen | PROGRAMMING | 1,400 | [
"data structures",
"geometry",
"math"
] | null | null | Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manha... | The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide. | Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel. | [
"3\n1 1\n7 5\n1 5\n",
"6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n"
] | [
"2\n",
"11\n"
] | In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs... | 500 | [
{
"input": "3\n1 1\n7 5\n1 5",
"output": "2"
},
{
"input": "6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1",
"output": "11"
},
{
"input": "10\n46 -55\n46 45\n46 45\n83 -55\n46 45\n83 -55\n46 45\n83 45\n83 45\n46 -55",
"output": "33"
},
{
"input": "1\n-5 -90",
"output": "0"
},
{
... | 1,591,709,772 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | n = int(input())
A = {}
B = {}
C = {}
for i in range(n):
s = input().split()
if s[0] not in A:
A[s[0]] = 0
A[s[0]] += 1
if s[1] not in B:
B[s[1]] = 0
B[s[1]] += 1
if s[0] not in C:
C[s[0]] = {}
C[s[0]][s[1]] = 0
elif s[1] not in C[s[0]]:
... | Title: Watchmen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They n... | ```python
n = int(input())
A = {}
B = {}
C = {}
for i in range(n):
s = input().split()
if s[0] not in A:
A[s[0]] = 0
A[s[0]] += 1
if s[1] not in B:
B[s[1]] = 0
B[s[1]] += 1
if s[0] not in C:
C[s[0]] = {}
C[s[0]][s[1]] = 0
elif s[1] not in C[s[0]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
365 | A | Good Number | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number every time it occurs in array *a*). | The first line contains integers *n* and *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=9). The *i*-th of the following *n* lines contains integer *a**i* without leading zeroes (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the number of *k*-good numbers in *a*. | [
"10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n",
"2 1\n1\n10\n"
] | [
"10\n",
"1\n"
] | none | 500 | [
{
"input": "10 6\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560\n1234560",
"output": "10"
},
{
"input": "2 1\n1\n10",
"output": "1"
},
{
"input": "1 0\n1000000000",
"output": "1"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
... | 1,638,885,113 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n,k=map(int,input().split())
count=0
start=0
a=[]
for i in range(k+1):
a+=str(i)
if k=0:
start=1
for i in range(n):
t=input()
l=a.copy()
for i in range(start,len(t)):
if t[i] in l:
l.remove(t[i])
if l==[]:
count+=1
print(count) | Title: Good Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a number *k*-good if it contains all digits not exceeding *k* (0,<=...,<=*k*). You've got a number *k* and an array *a* containing *n* numbers. Find out how many *k*-good numbers are in *a* (count each number eve... | ```python
n,k=map(int,input().split())
count=0
start=0
a=[]
for i in range(k+1):
a+=str(i)
if k=0:
start=1
for i in range(n):
t=input()
l=a.copy()
for i in range(start,len(t)):
if t[i] in l:
l.remove(t[i])
if l==[]:
count+=1
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,693,492,492 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 62 | 0 | string1, string2 = input(), input()
lst = []
for i in range(len(string1)):
if string1[i] == string2[i]:
lst.append('0')
else:
lst.append('1')
print(''.join(lst)) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
string1, string2 = input(), input()
lst = []
for i in range(len(string1)):
if string1[i] == string2[i]:
lst.append('0')
else:
lst.append('1')
print(''.join(lst))
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
864 | E | Fire | PROGRAMMING | 2,000 | [
"dp",
"sortings"
] | null | null | Polycarp is in really serious trouble — his house is on fire! It's time to save the most valuable items. Polycarp estimated that it would take *t**i* seconds to save *i*-th item. In addition, for each item, he estimated the value of *d**i* — the moment after which the item *i* will be completely burned and will no long... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of items in Polycarp's house.
Each of the following *n* lines contains three integers *t**i*,<=*d**i*,<=*p**i* (1<=≤<=*t**i*<=≤<=20, 1<=≤<=*d**i*<=≤<=2<=000, 1<=≤<=*p**i*<=≤<=20) — the time needed to save the item *i*, the time after which t... | In the first line print the maximum possible total value of the set of saved items. In the second line print one integer *m* — the number of items in the desired set. In the third line print *m* distinct integers — numbers of the saved items in the order Polycarp saves them. Items are 1-indexed in the same order in whi... | [
"3\n3 7 4\n2 6 5\n3 7 6\n",
"2\n5 6 1\n3 3 5\n"
] | [
"11\n2\n2 3 \n",
"1\n1\n1 \n"
] | In the first example Polycarp will have time to save any two items, but in order to maximize the total value of the saved items, he must save the second and the third item. For example, he can firstly save the third item in 3 seconds, and then save the second item in another 2 seconds. Thus, the total value of the save... | 2,500 | [
{
"input": "3\n3 7 4\n2 6 5\n3 7 6",
"output": "11\n2\n2 3 "
},
{
"input": "2\n5 6 1\n3 3 5",
"output": "1\n1\n1 "
},
{
"input": "9\n13 18 14\n8 59 20\n9 51 2\n18 32 15\n1 70 18\n14 81 14\n10 88 16\n18 52 3\n1 50 6",
"output": "106\n8\n1 4 9 8 2 5 6 7 "
},
{
"input": "5\n12 4... | 1,632,380,590 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 78 | 10,649,600 | import copy
n = int(input().strip())
v = []
t = []
d = []
for i in range(n):
line = input().strip()
tt, dd, vv = list(map(int, line.split()))
v.append(vv)
t.append(tt)
d.append(dd)
data = [[0, 0, 0, 0] for i in range(n)]
for i in range(n):
data[i] = [v[i], t[i], d[i], i+1]
data... | Title: Fire
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is in really serious trouble — his house is on fire! It's time to save the most valuable items. Polycarp estimated that it would take *t**i* seconds to save *i*-th item. In addition, for each item, he estimated the value ... | ```python
import copy
n = int(input().strip())
v = []
t = []
d = []
for i in range(n):
line = input().strip()
tt, dd, vv = list(map(int, line.split()))
v.append(vv)
t.append(tt)
d.append(dd)
data = [[0, 0, 0, 0] for i in range(n)]
for i in range(n):
data[i] = [v[i], t[i], d[i], i+... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,567,318,351 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 9 | 216 | 0 | s=input()
t=input()
c=0
for i in range(len(s)):
if s[i]==t[-i-1]:
c+=1
if c==len(s):
print('YES')
else:
print('NO')
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
s=input()
t=input()
c=0
for i in range(len(s)):
if s[i]==t[-i-1]:
c+=1
if c==len(s):
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,539,879,415 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 202 | 11,571,200 | n = int(input())
cola , can = list(map(int,input().split())) , list(map(int,input().split()))
can.sort(reverse = True)
if sum(cola) <= can[0]+can[1]:
print("YES")
else:
print("NO") | Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
n = int(input())
cola , can = list(map(int,input().split())) , list(map(int,input().split()))
can.sort(reverse = True)
if sum(cola) <= can[0]+can[1]:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
744 | A | Hongcow Builds A Nation | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs"
] | null | null | Hongcow is ruler of the world. As ruler of the world, he wants to make it easier for people to travel by road within their own countries.
The world can be modeled as an undirected graph with *n* nodes and *m* edges. *k* of the nodes are home to the governments of the *k* countries that make up the world.
There is at ... | The first line of input will contain three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=1<=000, 0<=≤<=*m*<=≤<=100<=000, 1<=≤<=*k*<=≤<=*n*) — the number of vertices and edges in the graph, and the number of vertices that are homes of the government.
The next line of input will contain *k* integers *c*1,<=*c*2,<=...,<=*c**... | Output a single integer, the maximum number of edges Hongcow can add to the graph while keeping it stable. | [
"4 1 2\n1 3\n1 2\n",
"3 3 1\n2\n1 2\n1 3\n2 3\n"
] | [
"2\n",
"0\n"
] | For the first sample test, the graph looks like this:
For the second sample test, the graph looks like this: | 500 | [
{
"input": "4 1 2\n1 3\n1 2",
"output": "2"
},
{
"input": "3 3 1\n2\n1 2\n1 3\n2 3",
"output": "0"
},
{
"input": "10 3 2\n1 10\n1 2\n1 3\n4 5",
"output": "33"
},
{
"input": "1 0 1\n1",
"output": "0"
},
{
"input": "1000 0 1\n72",
"output": "499500"
},
{
... | 1,699,088,355 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 61 | 639 | 14,336,000 | num_nodes, num_edges, num_queries = map(int, input().split())
color_list = list(map(int, input().split()))
adjacency_matrix = [[0] * (num_nodes + 1) for _ in range(num_nodes + 1)]
for _ in range(num_edges):
node_a, node_b = map(int, input().split())
adjacency_matrix[node_a][node_b] = adjacency_matrix[nod... | Title: Hongcow Builds A Nation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hongcow is ruler of the world. As ruler of the world, he wants to make it easier for people to travel by road within their own countries.
The world can be modeled as an undirected graph with *n* nodes and *m* e... | ```python
num_nodes, num_edges, num_queries = map(int, input().split())
color_list = list(map(int, input().split()))
adjacency_matrix = [[0] * (num_nodes + 1) for _ in range(num_nodes + 1)]
for _ in range(num_edges):
node_a, node_b = map(int, input().split())
adjacency_matrix[node_a][node_b] = adjacency_... | 3 | MatrixStudio/Codeforces-Python-Submissions |
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