contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
90 | A | Cableway | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | A. Cableway | 2 | 256 | A group of university students wants to get to the top of a mountain to have a picnic there. For that they decided to use a cableway.
A cableway is represented by some cablecars, hanged onto some cable stations by a cable. A cable is scrolled cyclically between the first and the last cable stations (the first of them ... | The first line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=100). It is guaranteed that *r*<=+<=*g*<=+<=*b*<=><=0, it means that the group consists of at least one student. | Print a single number — the minimal time the students need for the whole group to ascend to the top of the mountain. | [
"1 3 2\n",
"3 2 1\n"
] | [
"34",
"33"
] | Let's analyze the first sample.
At the moment of time 0 a red cablecar comes and one student from the *r* group get on it and ascends to the top at the moment of time 30.
At the moment of time 1 a green cablecar arrives and two students from the *g* group get on it; they get to the top at the moment of time 31.
At t... | 500 | [
{
"input": "1 3 2",
"output": "34"
},
{
"input": "3 2 1",
"output": "33"
},
{
"input": "3 5 2",
"output": "37"
},
{
"input": "10 10 10",
"output": "44"
},
{
"input": "29 7 24",
"output": "72"
},
{
"input": "28 94 13",
"output": "169"
},
{
"... | 1,669,916,712 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 122 | 0 | r, g , b = map(int, input().split())
i = 0
t =30 * max((r// 2), (g//2), (b//2))
while not( (r <=0) and (g <=0) and (b <=0)):
if i % 3 == 0 and r > 0:
r -= 2
elif i % 3 == 1 and g > 0:
g -= 2
elif i % 3 == 2 and b > 0:
b -= 2
#print(r, g, b, i)
if (r <=0) and (g <... | Title: Cableway
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A group of university students wants to get to the top of a mountain to have a picnic there. For that they decided to use a cableway.
A cableway is represented by some cablecars, hanged onto some cable stations by a cable. A cabl... | ```python
r, g , b = map(int, input().split())
i = 0
t =30 * max((r// 2), (g//2), (b//2))
while not( (r <=0) and (g <=0) and (b <=0)):
if i % 3 == 0 and r > 0:
r -= 2
elif i % 3 == 1 and g > 0:
g -= 2
elif i % 3 == 2 and b > 0:
b -= 2
#print(r, g, b, i)
if (r <=0... | 0 | MatrixStudio/Codeforces-Python-Submissions |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,550,602,938 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | n=int(input())
p=int(input())
q=int(input())
ch=input()
i=0
j=0
s=0
for i in range(0,n) :
for j in range(0,n):
if(((i*p)+(q*j))==n):
break
if(((i*p)+(q*j))==n):
break
if(i<n-1 or j<n-1):
print(i+j)
for z in range(0,i):
print(ch[s:s+p])
s=s+p
... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n=int(input())
p=int(input())
q=int(input())
ch=input()
i=0
j=0
s=0
for i in range(0,n) :
for j in range(0,n):
if(((i*p)+(q*j))==n):
break
if(((i*p)+(q*j))==n):
break
if(i<n-1 or j<n-1):
print(i+j)
for z in range(0,i):
print(ch[s:s+p])
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
868 | A | Bark to Unlock | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's p... | The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of words Kashtanka knows.
The next *n* lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to b... | Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"ya\n4\nah\noy\nto\nha\n",
"hp\n2\nht\ntp\n",
"ah\n1\nha\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" produ... | 250 | [
{
"input": "ya\n4\nah\noy\nto\nha",
"output": "YES"
},
{
"input": "hp\n2\nht\ntp",
"output": "NO"
},
{
"input": "ah\n1\nha",
"output": "YES"
},
{
"input": "bb\n4\nba\nab\naa\nbb",
"output": "YES"
},
{
"input": "bc\n4\nca\nba\nbb\ncc",
"output": "YES"
},
{
... | 1,511,329,442 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | pw = input()
n = int(input())
kash = []
for i in range(n):
kash.append(input())
count = 0
for w in kash:
if w[1] == pw[0]:
count += 1
if w[0] == pw[1]:
count += 1
if count == 2:
print('YES')
else:
print('NO') | Title: Bark to Unlock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a passw... | ```python
pw = input()
n = int(input())
kash = []
for i in range(n):
kash.append(input())
count = 0
for w in kash:
if w[1] == pw[0]:
count += 1
if w[0] == pw[1]:
count += 1
if count == 2:
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
981 | A | Antipalindrome | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not.
A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2}... | The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. | If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$.
Note that there can be multiple longest substrings that are not palindromes, but their length is unique. | [
"mew\n",
"wuffuw\n",
"qqqqqqqq\n"
] | [
"3\n",
"5\n",
"0\n"
] | "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$.
The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$.
All sub... | 500 | [
{
"input": "mew",
"output": "3"
},
{
"input": "wuffuw",
"output": "5"
},
{
"input": "qqqqqqqq",
"output": "0"
},
{
"input": "ijvji",
"output": "4"
},
{
"input": "iiiiiii",
"output": "0"
},
{
"input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow"... | 1,639,073,808 | 2,147,483,647 | PyPy 3 | OK | TESTS | 133 | 93 | 0 | s=input()
ans=len(s)
if(s==s[0]*ans):
print(0)
exit()
while(True):
if(s!=s[::-1]):
print(ans)
exit()
s=s[:-1]
ans-=1
print("what") | Title: Antipalindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" ar... | ```python
s=input()
ans=len(s)
if(s==s[0]*ans):
print(0)
exit()
while(True):
if(s!=s[::-1]):
print(ans)
exit()
s=s[:-1]
ans-=1
print("what")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,520,094,361 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 840 | 15,052,800 | import math
if __name__ == "__main__":
n = int(input())
MIN, MAX, segments, answer = math.inf, 0, [], -1
for i in range(n):
[x, y] = [int(i) for i in input().split()]
MIN = MIN if MIN < x else x
MAX = MAX if MAX >= y else y
segments.append([x, y])
for i, s in enumerate(se... | Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
import math
if __name__ == "__main__":
n = int(input())
MIN, MAX, segments, answer = math.inf, 0, [], -1
for i in range(n):
[x, y] = [int(i) for i in input().split()]
MIN = MIN if MIN < x else x
MAX = MAX if MAX >= y else y
segments.append([x, y])
for i, s in en... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
463 | B | Caisa and Pylons | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math"
] | null | null | Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0 has zero height, the pylon with number *i* (*i*<=><=0) has height *h**i*. The goal of the game is ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *h*1, *h*2,<=..., *h**n* (1<=<=≤<=<=*h**i*<=<=≤<=<=105) representing the heights of the pylons. | Print a single number representing the minimum number of dollars paid by Caisa. | [
"5\n3 4 3 2 4\n",
"3\n4 4 4\n"
] | [
"4\n",
"4\n"
] | In the first sample he can pay 4 dollars and increase the height of pylon with number 0 by 4 units. Then he can safely pass to the last pylon. | 1,000 | [
{
"input": "5\n3 4 3 2 4",
"output": "4"
},
{
"input": "3\n4 4 4",
"output": "4"
},
{
"input": "99\n1401 2019 1748 3785 3236 3177 3443 3772 2138 1049 353 908 310 2388 1322 88 2160 2783 435 2248 1471 706 2468 2319 3156 3506 2794 1999 1983 2519 2597 3735 537 344 3519 3772 3872 2961 3895 20... | 1,643,840,817 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 61 | 0 | x = int(input())
ls = list(map(int, input().split()))
sm = 0
for i in range(x - 1):
sm += (ls[i] - ls[i + 1])
print(abs(sm) + ls[0]) | Title: Caisa and Pylons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0... | ```python
x = int(input())
ls = list(map(int, input().split()))
sm = 0
for i in range(x - 1):
sm += (ls[i] - ls[i + 1])
print(abs(sm) + ls[0])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
976 | A | Minimum Binary Number | PROGRAMMING | 800 | [
"implementation"
] | null | null | String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two different operations on this string:
1. swap any pair of adjacent characters (for example, "101" "110"... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=100) — the length of string *s*.
The second line contains the string *s* consisting of characters "0" and "1". It is guaranteed that the string *s* is correct. | Print one string — the minimum correct string that you can obtain from the given one. | [
"4\n1001\n",
"1\n1\n"
] | [
"100\n",
"1\n"
] | In the first example you can obtain the answer by the following sequence of operations: "1001" <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> "1010" <img align="middle" class="tex-formula" src="ht... | 0 | [
{
"input": "4\n1001",
"output": "100"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "100\n1110111100001111011111111010110011111111011110000111101101011100110110001011000000101010110101011100",
"output": "1000000000000000000000000000000000000000"
},
{
"input": "100\n100000... | 1,605,343,026 | 2,147,483,647 | Python 3 | OK | TESTS | 14 | 108 | 0 | # https://codeforces.com/problemset/problem/976/A
n = int(input())
s = input()
total = 0
if n == 1:
print(s)
else:
for i in s:
if i == '0':
total += 1
print('1' + '0' * total)
| Title: Minimum Binary Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
String can be called correct if it consists of characters "0" and "1" and there are no redundant leading zeroes. Here are some examples: "0", "10", "1001".
You are given a correct string *s*.
You can perform two... | ```python
# https://codeforces.com/problemset/problem/976/A
n = int(input())
s = input()
total = 0
if n == 1:
print(s)
else:
for i in s:
if i == '0':
total += 1
print('1' + '0' * total)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
333 | A | Secrets | PROGRAMMING | 1,600 | [
"greedy"
] | null | null | Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations that are powers of three: 1 mark, 3 marks, 9 marks, 27 marks and so on. There are no coins of o... | The single line contains a single integer *n* (1<=≤<=*n*<=≤<=1017).
Please, do not use the %lld specifier to read or write 64 bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | In a single line print an integer: the maximum number of coins the unlucky buyer could have paid with. | [
"1\n",
"4\n"
] | [
"1\n",
"2\n"
] | In the first test case, if a buyer has exactly one coin of at least 3 marks, then, to give Gerald one mark, he will have to give this coin. In this sample, the customer can not have a coin of one mark, as in this case, he will be able to give the money to Gerald without any change.
In the second test case, if the buye... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "3"
},
{
"input": "10",
"output": "4"
},
{
"input": "100000000000000000",
"output": "33333333333333334"
},
{
"input... | 1,681,867,301 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n=input()
while not n%3 : n/=3
print（n/3+1） | Title: Secrets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations th... | ```python
n=input()
while not n%3 : n/=3
print（n/3+1）
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
6 | C | Alice, Bob and Chocolate | PROGRAMMING | 1,200 | [
"greedy",
"two pointers"
] | C. Alice, Bob and Chocolate | 2 | 64 | Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them wi... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the amount of bars on the table. The second line contains a sequence *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000), where *t**i* is the time (in seconds) needed to consume the *i*-th bar (in the order from left to right). | Print two numbers *a* and *b*, where *a* is the amount of bars consumed by Alice, and *b* is the amount of bars consumed by Bob. | [
"5\n2 9 8 2 7\n"
] | [
"2 3\n"
] | none | 0 | [
{
"input": "5\n2 9 8 2 7",
"output": "2 3"
},
{
"input": "1\n1",
"output": "1 0"
},
{
"input": "2\n1 1",
"output": "1 1"
},
{
"input": "3\n1 1 1",
"output": "2 1"
},
{
"input": "4\n1 1 1 1",
"output": "2 2"
},
{
"input": "1\n6",
"output": "1 0"
}... | 1,651,308,498 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | for i in range(int(input())):
a=input()
s=0
if(len(a)>2):
if(a[0]=='B'):
print("NO")
continue
else:
for j in range(len(a)-1):
if(a[j]=='B' and a[j+1]=='B'):
s=s+1
elif(a=="AB"):
print("YES")
... | Title: Alice, Bob and Chocolate
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. Fo... | ```python
for i in range(int(input())):
a=input()
s=0
if(len(a)>2):
if(a[0]=='B'):
print("NO")
continue
else:
for j in range(len(a)-1):
if(a[j]=='B' and a[j+1]=='B'):
s=s+1
elif(a=="AB"):
print("Y... | -1 | MatrixStudio/Codeforces-Python-Submissions |
631 | C | Report | PROGRAMMING | 1,700 | [
"data structures",
"sortings"
] | null | null | Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that denotes corresponding revenue. Before the report gets to Blake, it passes through the hands... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the number of commodities in the report and the number of managers, respectively.
The second line contains *n* integers *a**i* (|*a**i*|<=≤<=109) — the initial report before it gets to the first manager.
Then follow *m* lin... | Print *n* integers — the final report, which will be passed to Blake by manager number *m*. | [
"3 1\n1 2 3\n2 2\n",
"4 2\n1 2 4 3\n2 3\n1 2\n"
] | [
"2 1 3 ",
"2 4 1 3 "
] | In the first sample, the initial report looked like: 1 2 3. After the first manager the first two numbers were transposed: 2 1 3. The report got to Blake in this form.
In the second sample the original report was like this: 1 2 4 3. After the first manager the report changed to: 4 2 1 3. After the second manager the r... | 1,500 | [
{
"input": "3 1\n1 2 3\n2 2",
"output": "2 1 3 "
},
{
"input": "4 2\n1 2 4 3\n2 3\n1 2",
"output": "2 4 1 3 "
},
{
"input": "4 1\n4 3 2 1\n1 4",
"output": "1 2 3 4 "
},
{
"input": "5 1\n1 2 3 4 5\n2 5",
"output": "5 4 3 2 1 "
},
{
"input": "6 2\n3 1 2 6 4 5\n1 6\n... | 1,459,607,268 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 4,608,000 | n,m=input().split()
n=int(n)
m=int(m)
revenue=[int(i) for i in input().split()]
for i in range(m):
operations=[int(j) for j in input().split()]
if operations[0]==1:
b=revenue[0:operations[1]]
b.sort()
revenue=b+revenue[operations[1]:n]
else:
b=revenue[0:operations[... | Title: Report
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that... | ```python
n,m=input().split()
n=int(n)
m=int(m)
revenue=[int(i) for i in input().split()]
for i in range(m):
operations=[int(j) for j in input().split()]
if operations[0]==1:
b=revenue[0:operations[1]]
b.sort()
revenue=b+revenue[operations[1]:n]
else:
b=revenue[0:o... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
612 | C | Replace To Make Regular Bracket Sequence | PROGRAMMING | 1,400 | [
"data structures",
"expression parsing",
"math"
] | null | null | You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another of the same type. For example, you can replace < by the bracket {, but you can't replace it by ) or >.
The following d... | The only line contains a non empty string *s*, consisting of only opening and closing brackets of four kinds. The length of *s* does not exceed 106. | If it's impossible to get RBS from *s* print Impossible.
Otherwise print the least number of replaces needed to get RBS from *s*. | [
"[<}){}\n",
"{()}[]\n",
"]]\n"
] | [
"2",
"0",
"Impossible"
] | none | 0 | [
{
"input": "[<}){}",
"output": "2"
},
{
"input": "{()}[]",
"output": "0"
},
{
"input": "]]",
"output": "Impossible"
},
{
"input": ">",
"output": "Impossible"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{}",
"output": "0"
},
{
"input": ... | 1,585,457,762 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 19 | 155 | 1,126,400 | for ekbaar in range(1):
s=str(input())
while "[]" in s:
s=s[:s.find("[]")]+s[s.find("[]")+2:]
while "()" in s:
s = s[:s.index("()")] + s[s.index("()")+2:]
while "<>" in s:
s = s[:s.index("<>")] + s[s.index("<>") + 2:]
while "{}" in s:
s = s[:s.index("{}")] + ... | Title: Replace To Make Regular Bracket Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another... | ```python
for ekbaar in range(1):
s=str(input())
while "[]" in s:
s=s[:s.find("[]")]+s[s.find("[]")+2:]
while "()" in s:
s = s[:s.index("()")] + s[s.index("()")+2:]
while "<>" in s:
s = s[:s.index("<>")] + s[s.index("<>") + 2:]
while "{}" in s:
s = s[:s.index... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,598,176,789 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 6,963,200 | a,b,n=map(int,input().split())
x=[1,2,3,4,5,6,7,8,9]
for i in range(n):
j=0
while(j<len(x)):
m=a
m=m*10+x[j]
if(m%b==0):
a=m
j=9
j+=1
print(a)
if(len(str(a))==n+1):
print(a)
else:
print(-1)
| Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a,b,n=map(int,input().split())
x=[1,2,3,4,5,6,7,8,9]
for i in range(n):
j=0
while(j<len(x)):
m=a
m=m*10+x[j]
if(m%b==0):
a=m
j=9
j+=1
print(a)
if(len(str(a))==n+1):
print(a)
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
387 | A | George and Sleep | PROGRAMMING | 900 | [
"implementation"
] | null | null | George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when George went to bed. Note that George could have gone to bed yesterday relatively to the current time (see ... | The first line contains current time *s* as a string in the format "hh:mm". The second line contains time *t* in the format "hh:mm" — the duration of George's sleep. It is guaranteed that the input contains the correct time in the 24-hour format, that is, 00<=≤<=*hh*<=≤<=23, 00<=≤<=*mm*<=≤<=59. | In the single line print time *p* — the time George went to bed in the format similar to the format of the time in the input. | [
"05:50\n05:44\n",
"00:00\n01:00\n",
"00:01\n00:00\n"
] | [
"00:06\n",
"23:00\n",
"00:01\n"
] | In the first sample George went to bed at "00:06". Note that you should print the time only in the format "00:06". That's why answers "0:06", "00:6" and others will be considered incorrect.
In the second sample, George went to bed yesterday.
In the third sample, George didn't do to bed at all. | 500 | [
{
"input": "05:50\n05:44",
"output": "00:06"
},
{
"input": "00:00\n01:00",
"output": "23:00"
},
{
"input": "00:01\n00:00",
"output": "00:01"
},
{
"input": "23:59\n23:59",
"output": "00:00"
},
{
"input": "23:44\n23:55",
"output": "23:49"
},
{
"input": "... | 1,664,819,678 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 46 | 0 | hs,ms = map(int,input().split(":"))
ht,mt = map(int,input().split(":"))
if ht <= hs:
hs-=ht
if mt <= ms:
ms-=mt
elif hs > 0:
hs-=1
x = 60 - mt
if x + ms < 60:
ms+=x
else:
hs+=1
ms = (ms+x)-60
elif hs == 0:
... | Title: George and Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when Geor... | ```python
hs,ms = map(int,input().split(":"))
ht,mt = map(int,input().split(":"))
if ht <= hs:
hs-=ht
if mt <= ms:
ms-=mt
elif hs > 0:
hs-=1
x = 60 - mt
if x + ms < 60:
ms+=x
else:
hs+=1
ms = (ms+x)-60
elif hs ==... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
Bu... | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,697,460,814 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | name = input()
string = name
duplicate = []
for letter in name:
if string.count(letter)>1 and letter not in duplicate:
duplicate.append(letter)
l = len(string)-len(duplicate)
if l%2!=0:
print("IGNORE HIM!")
else:
print("CHAT WITH HER!")
| Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he though... | ```python
name = input()
string = name
duplicate = []
for letter in name:
if string.count(letter)>1 and letter not in duplicate:
duplicate.append(letter)
l = len(string)-len(duplicate)
if l%2!=0:
print("IGNORE HIM!")
else:
print("CHAT WITH HER!")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given a set of *n* points on the plane. A line containing the origin is called good, if projection of the given set to this line forms a symmetric multiset of points. Find the total number of good lines.
Multiset is a set where equal elements are allowed.
Multiset is called symmetric, if there is a point *P* ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=2000) — the number of points in the set.
Each of the next *n* lines contains two integers *x**i* and *y**i* (<=-<=106<=<=≤<=<=*x**i*,<=<=*y**i*<=<=≤<=<=106) — the coordinates of the points. It is guaranteed that no two points coincide. | If there are infinitely many good lines, print -1.
Otherwise, print single integer — the number of good lines. | [
"3\n1 2\n2 1\n3 3\n",
"2\n4 3\n1 2\n"
] | [
"3\n",
"-1\n"
] | Picture to the first sample test:
<img class="tex-graphics" src="https://espresso.codeforces.com/eedc60313be8684bd6169b8b23f0f0afd92479a8.png" style="max-width: 100.0%;max-height: 100.0%;"/>
In the second sample, any line containing the origin is good. | 0 | [
{
"input": "3\n1 2\n2 1\n3 3",
"output": "3"
},
{
"input": "2\n4 3\n1 2",
"output": "-1"
},
{
"input": "6\n0 4\n1 5\n2 1\n3 2\n4 3\n5 0",
"output": "5"
},
{
"input": "1\n5 2",
"output": "-1"
},
{
"input": "4\n2 4\n1 2\n0 0\n-2 -4",
"output": "1"
},
{
"... | 1,517,503,043 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <algorithm>
#include <iostream>
#include <complex>
#include <cstdio>
#include <vector>
using namespace std;
#define point complex<double>
#define X real()
#define Y imag()
point p[2010];
bool b[2010];
double dot(point a, point b)
{
return (conj(a)*b).X;
}
double cross(point a, point b)
{
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a set of *n* points on the plane. A line containing the origin is called good, if projection of the given set to this line forms a symmetric multiset of points. Find the total number of good lines.
Multiset is a set... | ```python
#include <algorithm>
#include <iostream>
#include <complex>
#include <cstdio>
#include <vector>
using namespace std;
#define point complex<double>
#define X real()
#define Y imag()
point p[2010];
bool b[2010];
double dot(point a, point b)
{
return (conj(a)*b).X;
}
double cross(point a, poin... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
520 | B | Two Buttons | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs",
"greedy",
"implementation",
"math",
"shortest paths"
] | null | null | Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by two. After clicking the blue button, device subtracts one from the number on the display. If at so... | The first and the only line of the input contains two distinct integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=104), separated by a space . | Print a single number — the minimum number of times one needs to push the button required to get the number *m* out of number *n*. | [
"4 6\n",
"10 1\n"
] | [
"2\n",
"9\n"
] | In the first example you need to push the blue button once, and then push the red button once.
In the second example, doubling the number is unnecessary, so we need to push the blue button nine times. | 1,000 | [
{
"input": "4 6",
"output": "2"
},
{
"input": "10 1",
"output": "9"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "2 10",
"outpu... | 1,696,418,780 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 30 | 0 | from math import ceil
n,m =[int(i) for i in input().split()]
t = 0
while True:
if m==n:
break
elif m<n:
t += n-m
break
elif m>=2*n:
t+=1
n*=2
else:
d = n-ceil(m/2)
t+= d
n-=d
n*=2
t+=1+n-m
break
... | Title: Two Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by t... | ```python
from math import ceil
n,m =[int(i) for i in input().split()]
t = 0
while True:
if m==n:
break
elif m<n:
t += n-m
break
elif m>=2*n:
t+=1
n*=2
else:
d = n-ceil(m/2)
t+= d
n-=d
n*=2
t+=1+n-m
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
765 | C | Table Tennis Game 2 | PROGRAMMING | 1,200 | [
"math"
] | null | null | Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scores exactly *k* points, the score is reset and a new set begins.
Across all the sets Misha scored *a* poi... | The first line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=109, 0<=≤<=*a*,<=*b*<=≤<=109, *a*<=+<=*b*<=><=0). | If the situation is impossible, print a single number -1. Otherwise, print the maximum possible number of sets. | [
"11 11 5\n",
"11 2 3\n"
] | [
"1\n",
"-1\n"
] | Note that the rules of the game in this problem differ from the real table tennis game, for example, the rule of "balance" (the winning player has to be at least two points ahead to win a set) has no power within the present problem. | 1,250 | [
{
"input": "11 11 5",
"output": "1"
},
{
"input": "11 2 3",
"output": "-1"
},
{
"input": "1 5 9",
"output": "14"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "1 1000000000 1000000000",
"output": "2000000000"
},
{
"input": "2 3 5",
"output": "... | 1,487,064,333 | 4,833 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 4 | 2,000 | 406,528,000 | import sys
k, a, b = sys.stdin.readline().strip().split()
k, a, b = int(k), int(a), int(b)
array = [[-1 for x in range(a+1)] for y in range(b+1)]
if k <= b:
for i in range(k):
if i > a:
break
array[k][i] = 1
if k <= a:
for i in range(k):
if i > b:
break
... | Title: Table Tennis Game 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scor... | ```python
import sys
k, a, b = sys.stdin.readline().strip().split()
k, a, b = int(k), int(a), int(b)
array = [[-1 for x in range(a+1)] for y in range(b+1)]
if k <= b:
for i in range(k):
if i > a:
break
array[k][i] = 1
if k <= a:
for i in range(k):
if i > b:
b... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,688,906,225 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 62 | 0 | w=int(input())
print("YES") if (w/2)%2==0 else print("NO") | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
w=int(input())
print("YES") if (w/2)%2==0 else print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
887 | A | Div. 64 | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisi... | In the only line given a non-empty binary string *s* with length up to 100. | Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise. | [
"100010001\n",
"100\n"
] | [
"yes",
"no"
] | In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.
You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system) | 500 | [
{
"input": "100010001",
"output": "yes"
},
{
"input": "100",
"output": "no"
},
{
"input": "0000001000000",
"output": "yes"
},
{
"input": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111",
"output": "no"
},
{
"in... | 1,620,221,175 | 2,147,483,647 | Python 3 | OK | TESTS | 98 | 77 | 0 | n=str(input())
cz=0
for i in range(len(n)):
if n[i]=="0":
cz+=1
for i in range(len(n)):
if n[i]=="0":
cz-=1
if n[i]=="1":
break
if cz>=6:
print("YES")
else:
print("NO") | Title: Div. 64
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some dig... | ```python
n=str(input())
cz=0
for i in range(len(n)):
if n[i]=="0":
cz+=1
for i in range(len(n)):
if n[i]=="0":
cz-=1
if n[i]=="1":
break
if cz>=6:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Arkady decided to buy roses for his girlfriend.
A flower shop has white, orange and red roses, and the total amount of them is *n*. Arkady thinks that red roses are not good together with white roses, so he won't buy a bouquet containing both red and white roses. Also, Arkady won't buy a bouquet where all roses have t... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=200<=000) — the number of roses in the show and the number of roses Arkady wants to buy.
The second line contains a sequence of integers *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=10<=000), where *b**i* equals the beauty of the *i*-th rose.
The... | Print the maximum possible total beauty of a bouquet of *k* roses that satisfies the constraints above. If it is not possible to make a single such bouquet, print -1. | [
"5 3\n4 3 4 1 6\nRROWW\n",
"5 2\n10 20 14 20 11\nRRRRR\n",
"11 5\n5 6 3 2 3 4 7 5 4 5 6\nRWOORWORROW\n"
] | [
"11\n",
"-1\n",
"28\n"
] | In the first example Arkady wants to buy 3 roses. He can, for example, buy both red roses (their indices are 1 and 2, and their total beauty is 7) and the only orange rose (its index is 3, its beauty is 4). This way the total beauty of the bouquet is 11.
In the second example Arkady can not buy a bouquet because all ... | 0 | [
{
"input": "5 3\n4 3 4 1 6\nRROWW",
"output": "11"
},
{
"input": "5 2\n10 20 14 20 11\nRRRRR",
"output": "-1"
},
{
"input": "11 5\n5 6 3 2 3 4 7 5 4 5 6\nRWOORWORROW",
"output": "28"
},
{
"input": "15 10\n8560 6244 9607 5137 7187 3217 5527 9919 282 8748 3529 6110 5767 521 339... | 1,521,304,833 | 3,933 | Python 3 | WRONG_ANSWER | TESTS | 5 | 93 | 7,065,600 | import sys
def main():
n, k = map(int, input().split())
b = list(map(int, input().split()))
bs = [[], [], []]
s = input()
for i in range(n):
ind = -1
if s[i] == 'O':
ind = 0
elif s[i] == 'R':
ind = 1
else:
ind = 2
bs[ind].append(b[i])
bs[0].sort()
bs... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arkady decided to buy roses for his girlfriend.
A flower shop has white, orange and red roses, and the total amount of them is *n*. Arkady thinks that red roses are not good together with white roses, so he won't buy a bouquet co... | ```python
import sys
def main():
n, k = map(int, input().split())
b = list(map(int, input().split()))
bs = [[], [], []]
s = input()
for i in range(n):
ind = -1
if s[i] == 'O':
ind = 0
elif s[i] == 'R':
ind = 1
else:
ind = 2
bs[ind].append(b[i])
bs[0].so... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
31 | A | Worms Evolution | PROGRAMMING | 1,200 | [
"implementation"
] | A. Worms Evolution | 2 | 256 | Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his theory, professor needs to find 3 different forms that the length of the first form is equal to ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of worm's forms. The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=1000) — lengths of worms of each form. | Output 3 distinct integers *i* *j* *k* (1<=≤<=*i*,<=*j*,<=*k*<=≤<=*n*) — such indexes of worm's forms that *a**i*<==<=*a**j*<=+<=*a**k*. If there is no such triple, output -1. If there are several solutions, output any of them. It possible that *a**j*<==<=*a**k*. | [
"5\n1 2 3 5 7\n",
"5\n1 8 1 5 1\n"
] | [
"3 2 1\n",
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 5 7",
"output": "3 2 1"
},
{
"input": "5\n1 8 1 5 1",
"output": "-1"
},
{
"input": "4\n303 872 764 401",
"output": "-1"
},
{
"input": "6\n86 402 133 524 405 610",
"output": "6 4 1"
},
{
"input": "8\n217 779 418 895 996 473 3 22",
"output":... | 1,630,514,794 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 156 | 6,963,200 | n=int(input())
a=list(map(int,input().split()))
c1=0
c2=0
c3=0
for i in range(len(a)):
x=a[i]
for j in range(i+1,len(a)):
y=a[j]
for k in range(j+1,len(a)):
z=a[k]
if(x==y+z):
print(i+1,j+1,k+1)
c1=1
break
... | Title: Worms Evolution
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Professor Vasechkin is studying evolution of worms. Recently he put forward hypotheses that all worms evolve by division. There are *n* forms of worms. Worms of these forms have lengths *a*1, *a*2, ..., *a**n*. To prove his... | ```python
n=int(input())
a=list(map(int,input().split()))
c1=0
c2=0
c3=0
for i in range(len(a)):
x=a[i]
for j in range(i+1,len(a)):
y=a[j]
for k in range(j+1,len(a)):
z=a[k]
if(x==y+z):
print(i+1,j+1,k+1)
c1=1
... | 3.94803 | MatrixStudio/Codeforces-Python-Submissions |
717 | C | Potions Homework | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Harry Water, Ronaldo, Her-my-oh-knee and their friends have started a new school year at their MDCS School of Speechcraft and Misery. At the time, they are very happy to have seen each other after a long time. The sun is shining, birds are singing, flowers are blooming, and their Potions class teacher, professor Snipe ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of tasks. The next *n* lines contain exactly one integer number *a**i* (1<=≤<=*a**i*<=≤<=100<=000) — both the difficulty of the initial task and the laziness of the *i*-th students. | Print the minimum total time to finish all tasks modulo 10<=007. | [
"2\n1\n3\n"
] | [
"6\n"
] | In the first sample, if the students switch their tasks, they will be able to finish them in 3 + 3 = 6 time units. | 0 | [
{
"input": "2\n1\n3",
"output": "6"
}
] | 1,580,887,421 | 2,147,483,647 | PyPy 3 | OK | TESTS | 11 | 826 | 9,113,600 | n = int(input())
l = []
w = []
c = 0
for i in range(n):
a = int(input())
l.append(a)
w.append(a)
l.sort()
w.sort(reverse = True)
for i in range(n):
c += l[i] * w[i]
print(c % 10007) | Title: Potions Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Water, Ronaldo, Her-my-oh-knee and their friends have started a new school year at their MDCS School of Speechcraft and Misery. At the time, they are very happy to have seen each other after a long time. The sun ... | ```python
n = int(input())
l = []
w = []
c = 0
for i in range(n):
a = int(input())
l.append(a)
w.append(a)
l.sort()
w.sort(reverse = True)
for i in range(n):
c += l[i] * w[i]
print(c % 10007)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,603,091,936 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 342 | 1,228,800 | from fractions import Fraction
y,w=map(int,input().split())
n=6
z=max(y,w)
cnt=0
for i in range(z,n+1):
cnt+=1
k=cnt/n
if k==0:
print(Fraction('0/1'))
else:
m=Fraction(k)
if m==1:
print('1'+'/'+'1')
else:
print(Fraction(m)) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
from fractions import Fraction
y,w=map(int,input().split())
n=6
z=max(y,w)
cnt=0
for i in range(z,n+1):
cnt+=1
k=cnt/n
if k==0:
print(Fraction('0/1'))
else:
m=Fraction(k)
if m==1:
print('1'+'/'+'1')
else:
print(Fraction(m))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
176 | A | Trading Business | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | To get money for a new aeonic blaster, ranger Qwerty decided to engage in trade for a while. He wants to buy some number of items (or probably not to buy anything at all) on one of the planets, and then sell the bought items on another planet. Note that this operation is not repeated, that is, the buying and the sellin... | The first line contains three space-separated integers *n*, *m* and *k* (2<=≤<=*n*<=≤<=10, 1<=≤<=*m*,<=*k*<=≤<=100) — the number of planets, the number of question types and the capacity of Qwerty's ship hold, correspondingly.
Then follow *n* blocks describing each planet.
The first line of the *i*-th block has the p... | Print a single number — the maximum profit Qwerty can get. | [
"3 3 10\nVenus\n6 5 3\n7 6 5\n8 6 10\nEarth\n10 9 0\n8 6 4\n10 9 3\nMars\n4 3 0\n8 4 12\n7 2 5\n"
] | [
"16"
] | In the first test case you should fly to planet Venus, take a loan on 74 units of money and buy three items of the first type and 7 items of the third type (3·6 + 7·8 = 74). Then the ranger should fly to planet Earth and sell there all the items he has bought. He gets 3·9 + 7·9 = 90 units of money for the items, he sho... | 500 | [
{
"input": "3 3 10\nVenus\n6 5 3\n7 6 5\n8 6 10\nEarth\n10 9 0\n8 6 4\n10 9 3\nMars\n4 3 0\n8 4 12\n7 2 5",
"output": "16"
},
{
"input": "2 1 5\nA\n6 5 5\nB\n10 9 0",
"output": "15"
},
{
"input": "2 2 5\nAbcdefghij\n20 15 20\n10 5 13\nKlmopqrstu\n19 16 20\n12 7 14",
"output": "0"
}... | 1,627,900,675 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 186 | 7,782,400 | # https://codeforces.com/problemset/problem/176/A
from typing import *
Planet = List[List[int]]
def get_total_profit(profits: List[Tuple[int, int]], total_items: int) -> int:
total_profit = 0
for i in range(len(profits)):
if profits[i][0] < 0:
break
if profits[i][1] < total_items... | Title: Trading Business
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To get money for a new aeonic blaster, ranger Qwerty decided to engage in trade for a while. He wants to buy some number of items (or probably not to buy anything at all) on one of the planets, and then sell the bought... | ```python
# https://codeforces.com/problemset/problem/176/A
from typing import *
Planet = List[List[int]]
def get_total_profit(profits: List[Tuple[int, int]], total_items: int) -> int:
total_profit = 0
for i in range(len(profits)):
if profits[i][0] < 0:
break
if profits[i][1] < t... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should b... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right aft... | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,658,954,236 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 140 | 15,564,800 |
def main():
n = int(fin())
*a, = map(int, fin().split())
b = [False]*(n+1)
c = n
for i in range(0, n):
b[a[i]] = True
while b[c] and c>0:
fout(f"{c} ")
c -= 1
fout("\n")
# FastIO
from sys import stdin, stdout
def fin(): return stdin.... | Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents sh... | ```python
def main():
n = int(fin())
*a, = map(int, fin().split())
b = [False]*(n+1)
c = n
for i in range(0, n):
b[a[i]] = True
while b[c] and c>0:
fout(f"{c} ")
c -= 1
fout("\n")
# FastIO
from sys import stdin, stdout
def fin(): ret... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,559,458,116 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 373 | 6,860,800 | def duff(ls):
s = 0
s = s + (ls[0][0] * ls[0][1])
k = ls[0][1]
for i in range(1, len(ls)):
if(k > ls[i][1]):
k = ls[i][1]
s = s + (ls[i][0] * k)
return s
n = int(input())
ls = []
while(n > 0):
ls1 = [int(i) for i in input().split()]
ls.append(... | Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
def duff(ls):
s = 0
s = s + (ls[0][0] * ls[0][1])
k = ls[0][1]
for i in range(1, len(ls)):
if(k > ls[i][1]):
k = ls[i][1]
s = s + (ls[i][0] * k)
return s
n = int(input())
ls = []
while(n > 0):
ls1 = [int(i) for i in input().split()]
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Limak is a little bear who loves to play. Today he is playing by destroying block towers. He built *n* towers in a row. The *i*-th tower is made of *h**i* identical blocks. For clarification see picture for the first sample.
Limak will repeat the following operation till everything is destroyed.
Block is called inter... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109) — sizes of towers. | Print the number of operations needed to destroy all towers. | [
"6\n2 1 4 6 2 2\n",
"7\n3 3 3 1 3 3 3\n"
] | [
"3\n",
"2\n"
] | The picture below shows all three operations for the first sample test. Each time boundary blocks are marked with red color. | 0 | [
{
"input": "6\n2 1 4 6 2 2",
"output": "3"
},
{
"input": "7\n3 3 3 1 3 3 3",
"output": "2"
},
{
"input": "7\n5128 5672 5805 5452 5882 5567 5032",
"output": "4"
},
{
"input": "10\n1 2 2 3 5 5 5 4 2 1",
"output": "5"
},
{
"input": "14\n20 20 20 20 20 20 3 20 20 20 2... | 1,440,876,023 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 405 | 15,564,800 | n = int(input())
a = [int(x) for x in input().split()]
res = [0] * n
for i in range(n):
res[i] = [0,0,0]
if n < 3:
print(1)
else:
res[0][0] = 1
res[-1][0] = 1
for i in range(1, n - 1):
res[i][0] = min(a[i-1] + 1, a[i+1] + 1, a[i])
cur_min = 0
for i in range(0, n)... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little bear who loves to play. Today he is playing by destroying block towers. He built *n* towers in a row. The *i*-th tower is made of *h**i* identical blocks. For clarification see picture for the first sample.
Lima... | ```python
n = int(input())
a = [int(x) for x in input().split()]
res = [0] * n
for i in range(n):
res[i] = [0,0,0]
if n < 3:
print(1)
else:
res[0][0] = 1
res[-1][0] = 1
for i in range(1, n - 1):
res[i][0] = min(a[i-1] + 1, a[i+1] + 1, a[i])
cur_min = 0
for i in r... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,681,055,443 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 46 | 0 | x1, x2, x3 = sorted(map(int,input().split()))
print(x3-x1)
| Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
x1, x2, x3 = sorted(map(int,input().split()))
print(x3-x1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
362 | B | Petya and Staircases | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump over one or two stairs at a time. But some stairs are too dirty and Petya doesn't want to step on them.
No... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=109, 0<=≤<=*m*<=≤<=3000) — the number of stairs in the staircase and the number of dirty stairs, correspondingly. The second line contains *m* different space-separated integers *d*1,<=*d*2,<=...,<=*d**m* (1<=≤<=*d**i*<=≤<=*n*) — the numbers of the dirty s... | Print "YES" if Petya can reach stair number *n*, stepping only on the clean stairs. Otherwise print "NO". | [
"10 5\n2 4 8 3 6\n",
"10 5\n2 4 5 7 9\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "10 5\n2 4 8 3 6",
"output": "NO"
},
{
"input": "10 5\n2 4 5 7 9",
"output": "YES"
},
{
"input": "10 9\n2 3 4 5 6 7 8 9 10",
"output": "NO"
},
{
"input": "5 2\n4 5",
"output": "NO"
},
{
"input": "123 13\n36 73 111 2 92 5 47 55 48 113 7 78 37",
"outp... | 1,384,711,089 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 204,800 | n, m = [int(x) for x in input().split()]
d = [int(x) for x in input().split()]
d.sort()
if d[0]==1 or d[m-1]==m:
print("NO")
else:
found=False
for i in range(2, m):
if d[i-1]==d[i]-1:
found=True
print("NO")
if not found:
print("YES")
| Title: Petya and Staircases
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little boy Petya loves stairs very much. But he is bored from simple going up and down them — he loves jumping over several stairs at a time. As he stands on some stair, he can either jump to the next one or jump o... | ```python
n, m = [int(x) for x in input().split()]
d = [int(x) for x in input().split()]
d.sort()
if d[0]==1 or d[m-1]==m:
print("NO")
else:
found=False
for i in range(2, m):
if d[i-1]==d[i]-1:
found=True
print("NO")
if not found:
print("YES")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
9 | C | Hexadecimal's Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation",
"math"
] | C. Hexadecimal's Numbers | 1 | 64 | One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural numbers from 1 to *n* to obtain total control over her energy.
But his plan failed. The reason for th... | Input data contains the only number *n* (1<=≤<=*n*<=≤<=109). | Output the only number — answer to the problem. | [
"10\n"
] | [
"2"
] | For *n* = 10 the answer includes numbers 1 and 10. | 0 | [
{
"input": "10",
"output": "2"
},
{
"input": "20",
"output": "3"
},
{
"input": "72",
"output": "3"
},
{
"input": "99",
"output": "3"
},
{
"input": "100",
"output": "4"
},
{
"input": "101",
"output": "5"
},
{
"input": "102",
"output": "5... | 1,674,369,939 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 124 | 0 | n=input()
x=len(n)
y=2**(x)-1
for i in range(x):
if(int(n[i])>1):
break
else :
if(n[i]=='0'):
y-=2**(x-i-1)
print(y)
| Title: Hexadecimal's Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One beautiful July morning a terrible thing happened in Mainframe: a mean virus Megabyte somehow got access to the memory of his not less mean sister Hexadecimal. He loaded there a huge amount of *n* different natural ... | ```python
n=input()
x=len(n)
y=2**(x)-1
for i in range(x):
if(int(n[i])>1):
break
else :
if(n[i]=='0'):
y-=2**(x-i-1)
print(y)
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,694,267,942 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n = int(input())
d = {'D': 12, 'I': 20, 'C': 6, 'T': 4, 'O': 8}
total
for i in range(n):
siii = input()
total += d[siii[0]]
print(total)
| Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
n = int(input())
d = {'D': 12, 'I': 20, 'C': 6, 'T': 4, 'O': 8}
total
for i in range(n):
siii = input()
total += d[siii[0]]
print(total)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
157 | B | Trace | PROGRAMMING | 1,000 | [
"geometry",
"sortings"
] | null | null | One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall into several parts. Some parts were painted red and all the other were painted blue. Besides,... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integers *r**i* (1<=≤<=*r**i*<=≤<=1000) — the circles' radii. It is guaranteed that all circles are different. | Print the single real number — total area of the part of the wall that is painted red. The answer is accepted if absolute or relative error doesn't exceed 10<=-<=4. | [
"1\n1\n",
"3\n1 4 2\n"
] | [
"3.1415926536\n",
"40.8407044967\n"
] | In the first sample the picture is just one circle of radius 1. Inner part of the circle is painted red. The area of the red part equals π × 1<sup class="upper-index">2</sup> = π.
In the second sample there are three circles of radii 1, 4 and 2. Outside part of the second circle is painted blue. Part between the secon... | 1,000 | [
{
"input": "1\n1",
"output": "3.1415926536"
},
{
"input": "3\n1 4 2",
"output": "40.8407044967"
},
{
"input": "4\n4 1 3 2",
"output": "31.4159265359"
},
{
"input": "4\n100 10 2 1",
"output": "31111.1920484997"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output"... | 1,682,314,909 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 44 | 154 | 0 | from math import pi
n=int(input())
r=list(map(int,input().split()))
r.sort()
j=n-1
count_=0
while j>=0:
if j!=0:
count_+=pi*(r[j]**2-r[j-1]**2)
else:
count_+=pi*(r[j]**2)
j-=2
print(count_) | Title: Trace
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall in... | ```python
from math import pi
n=int(input())
r=list(map(int,input().split()))
r.sort()
j=n-1
count_=0
while j>=0:
if j!=0:
count_+=pi*(r[j]**2-r[j-1]**2)
else:
count_+=pi*(r[j]**2)
j-=2
print(count_)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least... | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,689,772,419 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 92 | 0 | n,d=map(int,input().split())
l=list(map(int,input().split()))
mov=0
for i in range(1,n):
if l[i-1]>=l[i]:
dif = l[i-1]-l[i]
if dif+1%d==0:
mov+=((dif+1)//d)
l[i]+=((dif+1)//d)
else:
mov+=((dif+d-(dif%d))//d)
l[i]+=((dif+d-(dif%d))//d... | Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*... | ```python
n,d=map(int,input().split())
l=list(map(int,input().split()))
mov=0
for i in range(1,n):
if l[i-1]>=l[i]:
dif = l[i-1]-l[i]
if dif+1%d==0:
mov+=((dif+1)//d)
l[i]+=((dif+1)//d)
else:
mov+=((dif+d-(dif%d))//d)
l[i]+=((dif+d-(... | 0 | MatrixStudio/Codeforces-Python-Submissions |
284 | B | Cows and Poker Game | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player whose current status is not "FOLDED" may show his/her hand to the table. However, so as not to affect any be... | The first line contains a single integer, *n* (2<=≤<=*n*<=≤<=2·105). The second line contains *n* characters, each either "A", "I", or "F". The *i*-th character is "A" if the *i*-th player's status is "ALLIN", "I" if the *i*-th player's status is "IN", or "F" if the *i*-th player's status is "FOLDED". | The first line should contain a single integer denoting the number of players that can currently show their hands. | [
"6\nAFFAAA\n",
"3\nAFI\n"
] | [
"4\n",
"1\n"
] | In the first sample, cows 1, 4, 5, and 6 can show their hands. In the second sample, only cow 3 can show her hand. | 1,000 | [
{
"input": "6\nAFFAAA",
"output": "4"
},
{
"input": "3\nAFI",
"output": "1"
},
{
"input": "3\nFFF",
"output": "0"
},
{
"input": "3\nFIF",
"output": "1"
},
{
"input": "3\nAAA",
"output": "3"
},
{
"input": "3\nIII",
"output": "0"
},
{
"input"... | 1,612,008,051 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | n=int(input())
a=input()
A=a.count('A')
F=a.count('F')
I=a.count('I')
if A>=1 and F>=1 and I<=1 :
print(A+I)
else:
print(0) | Title: Cows and Poker Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cows playing poker at a table. For the current betting phase, each player's status is either "ALLIN", "IN", or "FOLDED", and does not change throughout the phase. To increase the suspense, a player who... | ```python
n=int(input())
a=input()
A=a.count('A')
F=a.count('F')
I=a.count('I')
if A>=1 and F>=1 and I<=1 :
print(A+I)
else:
print(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
900 | A | Find Extra One | PROGRAMMING | 800 | [
"geometry",
"implementation"
] | null | null | You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis. | The first line contains a single positive integer *n* (2<=≤<=*n*<=≤<=105).
The following *n* lines contain coordinates of the points. The *i*-th of these lines contains two single integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109, *x**i*<=≠<=0). No two points coincide. | Print "Yes" if there is such a point, "No" — otherwise.
You can print every letter in any case (upper or lower). | [
"3\n1 1\n-1 -1\n2 -1\n",
"4\n1 1\n2 2\n-1 1\n-2 2\n",
"3\n1 2\n2 1\n4 60\n"
] | [
"Yes",
"No",
"Yes"
] | In the first example the second point can be removed.
In the second example there is no suitable for the condition point.
In the third example any point can be removed. | 500 | [
{
"input": "3\n1 1\n-1 -1\n2 -1",
"output": "Yes"
},
{
"input": "4\n1 1\n2 2\n-1 1\n-2 2",
"output": "No"
},
{
"input": "3\n1 2\n2 1\n4 60",
"output": "Yes"
},
{
"input": "10\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n7 7\n8 8\n9 9\n-1 -1",
"output": "Yes"
},
{
"input": "2\n1... | 1,594,537,379 | 2,147,483,647 | PyPy 3 | OK | TESTS | 71 | 920 | 30,105,600 | c,d=0,0
for _ in range(int(input())):
l=list(map(int,input().split()))
if(l[0]<0):
c+=1
elif(l[0]>0):
d+=1
if(c==1 or d==1):
print("Yes")
elif(c==0 or d==0):
print("Yes")
else:
print("No") | Title: Find Extra One
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* distinct points on a plane, none of them lie on *OY* axis. Check that there is a point after removal of which the remaining points are located on one side of the *OY* axis.
Input Specification:
The first li... | ```python
c,d=0,0
for _ in range(int(input())):
l=list(map(int,input().split()))
if(l[0]<0):
c+=1
elif(l[0]>0):
d+=1
if(c==1 or d==1):
print("Yes")
elif(c==0 or d==0):
print("Yes")
else:
print("No")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
922 | A | Cloning Toys | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applies the machine to a copied toy, he gets two additional copies.
Initially, Imp has only one origina... | The only line contains two integers *x* and *y* (0<=≤<=*x*,<=*y*<=≤<=109) — the number of copies and the number of original toys Imp wants to get (including the initial one). | Print "Yes", if the desired configuration is possible, and "No" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"6 3\n",
"4 2\n",
"1000 1001\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first example, Imp has to apply the machine twice to original toys and then twice to copies. | 500 | [
{
"input": "6 3",
"output": "Yes"
},
{
"input": "4 2",
"output": "No"
},
{
"input": "1000 1001",
"output": "Yes"
},
{
"input": "1000000000 999999999",
"output": "Yes"
},
{
"input": "81452244 81452247",
"output": "No"
},
{
"input": "188032448 86524683",... | 1,622,646,577 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | c, o = input().split()
c = int(c)
o = int(o)
c_count = 0
if o == 0 c != 0:
print('No')
elif c == 0 and o != 0:
print("No")
elif:
if 0 == 1 and c == 0:
print("yes")
if o > 1:
o_count += (o-1)
c_count += (o-1)
if c_count <= c:
print("Yes")
else:
print("No")
... | Title: Cloning Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applie... | ```python
c, o = input().split()
c = int(c)
o = int(o)
c_count = 0
if o == 0 c != 0:
print('No')
elif c == 0 and o != 0:
print("No")
elif:
if 0 == 1 and c == 0:
print("yes")
if o > 1:
o_count += (o-1)
c_count += (o-1)
if c_count <= c:
print("Yes")
else:
print("No")
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
I... | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**... | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,599,459,628 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 155 | 2,662,400 | a,b=map(int,input().split())
d=[i for i in range(1,b+1)]
for k in range(a):
c=list(map(int,input().split()))
for i in range(1,len(c)):
d[c[i]-1]=0
if sum(d)==0:
print('YES')
else:
print('NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is... | ```python
a,b=map(int,input().split())
d=[i for i in range(1,b+1)]
for k in range(a):
c=list(map(int,input().split()))
for i in range(1,len(c)):
d[c[i]-1]=0
if sum(d)==0:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. O... | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line do... | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,689,775,440 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 307,200 | def can_restore_names(guest_name, host_name, letter_pile):
from collections import Counter
guest_counts = Counter(guest_name)
host_counts = Counter(host_name)
pile_counts = Counter(letter_pile)
for letter in guest_counts:
if letter not in pile_counts or pile_counts[letter] < guest_... | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's nam... | ```python
def can_restore_names(guest_name, host_name, letter_pile):
from collections import Counter
guest_counts = Counter(guest_name)
host_counts = Counter(host_name)
pile_counts = Counter(letter_pile)
for letter in guest_counts:
if letter not in pile_counts or pile_counts[letter... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
462 | B | Appleman and Card Game | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to lette... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. | Print a single integer – the answer to the problem. | [
"15 10\nDZFDFZDFDDDDDDF\n",
"6 4\nYJSNPI\n"
] | [
"82\n",
"4\n"
] | In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | 1,000 | [
{
"input": "15 10\nDZFDFZDFDDDDDDF",
"output": "82"
},
{
"input": "6 4\nYJSNPI",
"output": "4"
},
{
"input": "5 3\nAOWBY",
"output": "3"
},
{
"input": "1 1\nV",
"output": "1"
},
{
"input": "2 1\nWT",
"output": "1"
},
{
"input": "2 2\nBL",
"output":... | 1,698,248,881 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 20 | 92 | 1,843,200 | t = input()
n = (int)(t.split(" ")[0])
k = (int)(t.split(" ")[1])
s = input()
freq = [0]*26
for ch in s :
freq[ord(ch) - 65] = freq[ord(ch)-65]+1
freq.sort()
sum = 0
for i in range(0,25) :
p = freq[25-i]
if (p > k) :
sum = sum + k**2
break
else :
sum = sum + p**2
... | Title: Appleman and Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally... | ```python
t = input()
n = (int)(t.split(" ")[0])
k = (int)(t.split(" ")[1])
s = input()
freq = [0]*26
for ch in s :
freq[ord(ch) - 65] = freq[ord(ch)-65]+1
freq.sort()
sum = 0
for i in range(0,25) :
p = freq[25-i]
if (p > k) :
sum = sum + k**2
break
else :
sum = s... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
152 | A | Marks | PROGRAMMING | 900 | [
"implementation"
] | null | null | Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student got a mark from 1 to 9 (inclusive) for each subject.
Let's consider a student the best at ... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of students and the number of subjects, correspondingly. Next *n* lines each containing *m* characters describe the gradebook. Each character in the gradebook is a number from 1 to 9. Note that the marks in a rows are not sepa... | Print the single number — the number of successful students in the given group. | [
"3 3\n223\n232\n112\n",
"3 5\n91728\n11828\n11111\n"
] | [
"2\n",
"3\n"
] | In the first sample test the student number 1 is the best at subjects 1 and 3, student 2 is the best at subjects 1 and 2, but student 3 isn't the best at any subject.
In the second sample test each student is the best at at least one subject. | 500 | [
{
"input": "3 3\n223\n232\n112",
"output": "2"
},
{
"input": "3 5\n91728\n11828\n11111",
"output": "3"
},
{
"input": "2 2\n48\n27",
"output": "1"
},
{
"input": "2 1\n4\n6",
"output": "1"
},
{
"input": "1 2\n57",
"output": "1"
},
{
"input": "1 1\n5",
... | 1,587,653,884 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 109 | 307,200 | def main():
n,m=[int(x) for x in input().split()]
a=[]
for _ in range(n):
a.append(list(input()))
a=list(zip(*a))
ma=max
d={}
for i in range(m):
highest=ma(a[i])
for j in range(n):
if a[i][j]==highest:
d[j]=1
print(len(d.va... | Title: Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya, or Mr. Vasily Petrov is a dean of a department in a local university. After the winter exams he got his hands on a group's gradebook.
Overall the group has *n* students. They received marks for *m* subjects. Each student ... | ```python
def main():
n,m=[int(x) for x in input().split()]
a=[]
for _ in range(n):
a.append(list(input()))
a=list(zip(*a))
ma=max
d={}
for i in range(m):
highest=ma(a[i])
for j in range(n):
if a[i][j]==highest:
d[j]=1
prin... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
Th... | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,668,438,690 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 61 | 0 | n,k=map(int,input().split(" "))
l=list(map(int,input().split(" ")))
l=sorted(l)
lnew=[]
c=0
split=len(l)//3
for i in range(split):
lnew.append(l[i:i+3])
for j in lnew:
m=j[2]
if m+k<=5:
c+=1
print(c) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. Accordi... | ```python
n,k=map(int,input().split(" "))
l=list(map(int,input().split(" ")))
l=sorted(l)
lnew=[]
c=0
split=len(l)//3
for i in range(split):
lnew.append(l[i:i+3])
for j in lnew:
m=j[2]
if m+k<=5:
c+=1
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
883 | F | Lost in Transliteration | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | There are some ambiguities when one writes Berland names with the letters of the Latin alphabet.
For example, the Berland sound u can be written in the Latin alphabet as "u", and can be written as "oo". For this reason, two words "ulyana" and "oolyana" denote the same name.
The second ambiguity is about the Berland s... | The first line contains integer number *n* (2<=≤<=*n*<=≤<=400) — number of the words in the list.
The following *n* lines contain words, one word per line. Each word consists of only lowercase Latin letters. The length of each word is between 1 and 20 letters inclusive. | Print the minimal number of groups where the words in each group denote the same name. | [
"10\nmihail\noolyana\nkooooper\nhoon\nulyana\nkoouper\nmikhail\nkhun\nkuooper\nkkkhoon\n",
"9\nhariton\nhkariton\nbuoi\nkkkhariton\nboooi\nbui\nkhariton\nboui\nboi\n",
"2\nalex\nalex\n"
] | [
"4\n",
"5\n",
"1\n"
] | There are four groups of words in the first example. Words in each group denote same name:
1. "mihail", "mikhail" 1. "oolyana", "ulyana" 1. "kooooper", "koouper" 1. "hoon", "khun", "kkkhoon"
There are five groups of words in the second example. Words in each group denote same name:
1. "hariton", "kkkhariton", "... | 0 | [
{
"input": "10\nmihail\noolyana\nkooooper\nhoon\nulyana\nkoouper\nmikhail\nkhun\nkuooper\nkkkhoon",
"output": "4"
},
{
"input": "9\nhariton\nhkariton\nbuoi\nkkkhariton\nboooi\nbui\nkhariton\nboui\nboi",
"output": "5"
},
{
"input": "2\nalex\nalex",
"output": "1"
},
{
"input": ... | 1,508,576,744 | 3,644 | PyPy 3 | WRONG_ANSWER | TESTS1 | 3 | 108 | 23,142,400 | import re
n = int(input())
names = set()
for i in range(n):
word = input()
word = re.sub("k*kh", "h", word)
word = word.replace("h", "%").replace("u", "*").replace("oo", "*")
word = word.replace("k", "")
names.add(word)
print(len(names)) | Title: Lost in Transliteration
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are some ambiguities when one writes Berland names with the letters of the Latin alphabet.
For example, the Berland sound u can be written in the Latin alphabet as "u", and can be written as "oo". For thi... | ```python
import re
n = int(input())
names = set()
for i in range(n):
word = input()
word = re.sub("k*kh", "h", word)
word = word.replace("h", "%").replace("u", "*").replace("oo", "*")
word = word.replace("k", "")
names.add(word)
print(len(names))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,563,693,022 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 0 | abc = [int(abc) for abc in input().split()][:3]
a = []
b = []
c = []
for i in range(len(abc)):
for j in range(2,abc[i]//2 + 1):
if abc[i] % j == 0:
if i == 0:
a.append(j)
if i == 1:
b.append(j)
if i == 2:
... | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
abc = [int(abc) for abc in input().split()][:3]
a = []
b = []
c = []
for i in range(len(abc)):
for j in range(2,abc[i]//2 + 1):
if abc[i] % j == 0:
if i == 0:
a.append(j)
if i == 1:
b.append(j)
if i ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given set of *n* points in 5-dimensional space. The points are labeled from 1 to *n*. No two points coincide.
We will call point *a* bad if there are different points *b* and *c*, not equal to *a*, from the given set such that angle between vectors and is acute (i.e. strictly less than ). Otherwise, the poin... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=103) — the number of points.
The next *n* lines of input contain five integers *a**i*,<=*b**i*,<=*c**i*,<=*d**i*,<=*e**i* (|*a**i*|,<=|*b**i*|,<=|*c**i*|,<=|*d**i*|,<=|*e**i*|<=≤<=103) — the coordinates of the i-th point. All points are distinct. | First, print a single integer *k* — the number of good points.
Then, print *k* integers, each on their own line — the indices of the good points in ascending order. | [
"6\n0 0 0 0 0\n1 0 0 0 0\n0 1 0 0 0\n0 0 1 0 0\n0 0 0 1 0\n0 0 0 0 1\n",
"3\n0 0 1 2 0\n0 0 9 2 0\n0 0 5 9 0\n"
] | [
"1\n1\n",
"0\n"
] | In the first sample, the first point forms exactly a <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/362ac8c7a7496dffc06cd0c843287cd822be63c3.png" style="max-width: 100.0%;max-height: 100.0%;"/> angle with all other pairs of points, so it is good.
In the second sample, along the cd plane, ... | 0 | [
{
"input": "6\n0 0 0 0 0\n1 0 0 0 0\n0 1 0 0 0\n0 0 1 0 0\n0 0 0 1 0\n0 0 0 0 1",
"output": "1\n1"
},
{
"input": "3\n0 0 1 2 0\n0 0 9 2 0\n0 0 5 9 0",
"output": "0"
},
{
"input": "1\n0 0 0 0 0",
"output": "1\n1"
},
{
"input": "2\n0 1 2 3 4\n5 6 7 8 9",
"output": "2\n1\n2"... | 1,504,606,678 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 16 | 62 | 307,200 | import math
def check(a, b, c):
ab = [b[i] - a[i] for i in range(5)]
ac = [c[i] - a[i] for i in range(5)]
up = ab[0] * ac[0] + ab[1] * ac[1] + ab[2] * ac[2] + ab[3] * ac[3] + ab[4] * ac[4]
lenab = math.sqrt(ab[0] * ab[0] + ab[1] * ab[1] + ab[2] * ab[2] + ab[3] * ab[3] + ab[4] * ab[4])
l... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given set of *n* points in 5-dimensional space. The points are labeled from 1 to *n*. No two points coincide.
We will call point *a* bad if there are different points *b* and *c*, not equal to *a*, from the given set such... | ```python
import math
def check(a, b, c):
ab = [b[i] - a[i] for i in range(5)]
ac = [c[i] - a[i] for i in range(5)]
up = ab[0] * ac[0] + ab[1] * ac[1] + ab[2] * ac[2] + ab[3] * ac[3] + ab[4] * ac[4]
lenab = math.sqrt(ab[0] * ab[0] + ab[1] * ab[1] + ab[2] * ab[2] + ab[3] * ab[3] + ab[4] * ab[... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,567,942,425 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 109 | 0 | a=int(input())
b=list(map(int,input().split()))
c=set(b)
if 0 in set(c):
c.remove(0)
print(len(c)) | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
a=int(input())
b=list(map(int,input().split()))
c=set(b)
if 0 in set(c):
c.remove(0)
print(len(c))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
525 | A | Vitaliy and Pie | PROGRAMMING | 1,100 | [
"greedy",
"hashing",
"strings"
] | null | null | After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from left to right. You can go from the first room to the second room, from the second room to the third ... | The first line of the input contains a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of rooms in the house.
The second line of the input contains string *s* of length 2·*n*<=-<=2. Let's number the elements of the string from left to right, starting from one.
The odd positions in the given string *s* contain ... | Print the only integer — the minimum number of keys that Vitaly needs to buy to surely get from room one to room *n*. | [
"3\naAbB\n",
"4\naBaCaB\n",
"5\nxYyXzZaZ\n"
] | [
"0\n",
"3\n",
"2\n"
] | none | 250 | [
{
"input": "3\naAbB",
"output": "0"
},
{
"input": "4\naBaCaB",
"output": "3"
},
{
"input": "5\nxYyXzZaZ",
"output": "2"
},
{
"input": "26\naAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyY",
"output": "0"
},
{
"input": "26\nzAyBxCwDvEuFtGsHrIqJpKoLnMmNlOkPjQiRhSg... | 1,646,585,591 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 1,740,800 | n=int(input())
s=input()
lk=[]
ld=[]
c=0
for x in range(len(s)) :
if x%2==0 :
lk.append(s[x])
else :
ld.append(s[x])
for x in range(len(ld)) :
if ld[x].lower() in lk[:x+1] :
for i in lk[:x+1] :
if i==ld[x].lower() :
lk.remove(i)
... | Title: Vitaliy and Pie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a hard day Vitaly got very hungry and he wants to eat his favorite potato pie. But it's not that simple. Vitaly is in the first room of the house with *n* room located in a line and numbered starting from one from... | ```python
n=int(input())
s=input()
lk=[]
ld=[]
c=0
for x in range(len(s)) :
if x%2==0 :
lk.append(s[x])
else :
ld.append(s[x])
for x in range(len(ld)) :
if ld[x].lower() in lk[:x+1] :
for i in lk[:x+1] :
if i==ld[x].lower() :
lk.remove(i)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
499 | A | Watching a movie | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the player automatically proceeds to the next minute of the movie. 1. Skip exactly *x* minutes of the movie... | The first line contains two space-separated integers *n*, *x* (1<=≤<=*n*<=≤<=50, 1<=≤<=*x*<=≤<=105) — the number of the best moments of the movie and the value of *x* for the second button.
The following *n* lines contain the descriptions of the best moments of the movie, the *i*-th line of the description contains tw... | Output a single number — the answer to the problem. | [
"2 3\n5 6\n10 12\n",
"1 1\n1 100000\n"
] | [
"6\n",
"100000\n"
] | In the first sample, the player was initially standing on the first minute. As the minutes from the 1-st to the 4-th one don't contain interesting moments, we press the second button. Now we can not press the second button and skip 3 more minutes, because some of them contain interesting moments. Therefore, we watch th... | 500 | [
{
"input": "2 3\n5 6\n10 12",
"output": "6"
},
{
"input": "1 1\n1 100000",
"output": "100000"
},
{
"input": "10 1\n2156 3497\n4784 7775\n14575 31932\n33447 35902\n36426 47202\n48772 60522\n63982 68417\n78537 79445\n90081 90629\n94325 95728",
"output": "53974"
},
{
"input": "1... | 1,627,830,395 | 2,147,483,647 | PyPy 3 | OK | TESTS | 41 | 109 | 21,401,600 | n,x=map(int,input().split())
arr=[]
for i in range(n):
a,b=map(int,input().split())
arr.append(a)
arr.append(b)
initial=1
count=0
for i in range(len(arr)):
while initial <=arr[i]:
if (arr[i] - initial)/x > 1:
initial+=x
continue
elif (arr[i]... | Title: Watching a movie
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have decided to watch the best moments of some movie. There are two buttons on your player:
1. Watch the current minute of the movie. By pressing this button, you watch the current minute of the movie and the pl... | ```python
n,x=map(int,input().split())
arr=[]
for i in range(n):
a,b=map(int,input().split())
arr.append(a)
arr.append(b)
initial=1
count=0
for i in range(len(arr)):
while initial <=arr[i]:
if (arr[i] - initial)/x > 1:
initial+=x
continue
el... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,665,479,159 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | n=int(input())
num=list(map(int,input().split()))
if num[0]%2==num[1]%2:
for item in num:
if item%2!=num[0]%2:
print(num.index(item)+1)
break
else:
print(2) if num[0]%2==num[2]%2 else print(1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
num=list(map(int,input().split()))
if num[0]%2==num[1]%2:
for item in num:
if item%2!=num[0]%2:
print(num.index(item)+1)
break
else:
print(2) if num[0]%2==num[2]%2 else print(1)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,671,814,256 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import networkx as nx
G = nx.Graph()
# list of edges with weights
edges = (1, 2, 10), (1, 3, 5), (2, 4, 3), (2, 5, 7), (3, 4, 1),(4, 6, 12), (5, 6 , 8)
# adding edges to graph
for edge in edges:
G.addedge(edge[0], edge[1], weight = edge[2])
shortestpath = nx.dijkstrapath(G, 1 ,6) #This m... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
import networkx as nx
G = nx.Graph()
# list of edges with weights
edges = (1, 2, 10), (1, 3, 5), (2, 4, 3), (2, 5, 7), (3, 4, 1),(4, 6, 12), (5, 6 , 8)
# adding edges to graph
for edge in edges:
G.addedge(edge[0], edge[1], weight = edge[2])
shortestpath = nx.dijkstrapath(G, 1 ,6) ... | -1 | MatrixStudio/Codeforces-Python-Submissions |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab'... | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mah... | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,652,358,448 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def simple_multiplication(number) :
if number % 2 == 0:
return "Mahmod"
else:
return "Ehab" | Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a*... | ```python
def simple_multiplication(number) :
if number % 2 == 0:
return "Mahmod"
else:
return "Ehab"
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
322 | B | Ciel and Flowers | PROGRAMMING | 1,600 | [
"combinatorics",
"math"
] | null | null | Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red flowers. - To make a "green bouquet", it needs 3 green flowers. - To make a "blue bouquet", it needs 3... | The first line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=109) — the number of red, green and blue flowers. | Print the maximal number of bouquets Fox Ciel can make. | [
"3 6 9\n",
"4 4 4\n",
"0 0 0\n"
] | [
"6\n",
"4\n",
"0\n"
] | In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.
In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet. | 1,000 | [
{
"input": "3 6 9",
"output": "6"
},
{
"input": "4 4 4",
"output": "4"
},
{
"input": "0 0 0",
"output": "0"
},
{
"input": "0 3 6",
"output": "3"
},
{
"input": "7 8 9",
"output": "7"
},
{
"input": "8 8 9",
"output": "8"
},
{
"input": "15 3 9... | 1,583,424,526 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 218 | 512,000 | import math
#q=int(input())
q=1
for _ in range(q):
l=list(map(int,input().split()))
l.sort()
a=l[0]
b=l[1]
c=l[2]
ans2=0
ans3=0
ans1=a//3+b//3+c//3
if a>0 and b>0 and c>0:
ans2=1
a1=max(0,a-1)
b1=max(0,b-1)
c1=max(0,c-1)
an... | Title: Ciel and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red fl... | ```python
import math
#q=int(input())
q=1
for _ in range(q):
l=list(map(int,input().split()))
l.sort()
a=l[0]
b=l[1]
c=l[2]
ans2=0
ans3=0
ans1=a//3+b//3+c//3
if a>0 and b>0 and c>0:
ans2=1
a1=max(0,a-1)
b1=max(0,b-1)
c1=max(0,c-1)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
787 | A | The Monster | PROGRAMMING | 1,200 | [
"brute force",
"math",
"number theory"
] | null | null | A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams at times *d*,<=*d*<=+<=*c*,<=*d*<=+<=2*c*,<=*d*<=+<=3*c*,<=....
The Monster will catch them if a... | The first line of input contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100).
The second line contains two integers *c* and *d* (1<=≤<=*c*,<=*d*<=≤<=100). | Print the first time Rick and Morty will scream at the same time, or <=-<=1 if they will never scream at the same time. | [
"20 2\n9 19\n",
"2 1\n16 12\n"
] | [
"82\n",
"-1\n"
] | In the first sample testcase, Rick's 5th scream and Morty's 8th time are at time 82.
In the second sample testcase, all Rick's screams will be at odd times and Morty's will be at even times, so they will never scream at the same time. | 500 | [
{
"input": "20 2\n9 19",
"output": "82"
},
{
"input": "2 1\n16 12",
"output": "-1"
},
{
"input": "39 52\n88 78",
"output": "1222"
},
{
"input": "59 96\n34 48",
"output": "1748"
},
{
"input": "87 37\n91 29",
"output": "211"
},
{
"input": "11 81\n49 7",
... | 1,689,255,077 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | import math
def the_monster():
a, b= map(int, input().split())
c, d= map(int, input().split())
if b==d:
print(b)
elif a == c:
print(-1)
elif (b<d and a<c) or (b>d and a>c):
print(-1)
elif (a%2==0 and c%2==0) and ((b%2==1 and a%2==0) or (b%2==0 and a%2==1)):
print... | Title: The Monster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A monster is chasing after Rick and Morty on another planet. They're so frightened that sometimes they scream. More accurately, Rick screams at times *b*,<=*b*<=+<=*a*,<=*b*<=+<=2*a*,<=*b*<=+<=3*a*,<=... and Morty screams a... | ```python
import math
def the_monster():
a, b= map(int, input().split())
c, d= map(int, input().split())
if b==d:
print(b)
elif a == c:
print(-1)
elif (b<d and a<c) or (b>d and a>c):
print(-1)
elif (a%2==0 and c%2==0) and ((b%2==1 and a%2==0) or (b%2==0 and a%2==1)):
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
46 | C | Hamsters and Tigers | PROGRAMMING | 1,600 | [
"two pointers"
] | C. Hamsters and Tigers | 2 | 256 | Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap the animals' positions so that all the hamsters stood together and all the tigers also stood together... | The first line contains number *n* (2<=≤<=*n*<=≤<=1000) which indicates the total number of animals in the arena. The second line contains the description of the animals' positions. The line consists of *n* symbols "H" and "T". The "H"s correspond to hamsters and the "T"s correspond to tigers. It is guaranteed that at ... | Print the single number which is the minimal number of swaps that let the trainer to achieve his goal. | [
"3\nHTH\n",
"9\nHTHTHTHHT\n"
] | [
"0\n",
"2\n"
] | In the first example we shouldn't move anybody because the animals of each species already stand apart from the other species. In the second example you may swap, for example, the tiger in position 2 with the hamster in position 5 and then — the tiger in position 9 with the hamster in position 7. | 0 | [
{
"input": "3\nHTH",
"output": "0"
},
{
"input": "9\nHTHTHTHHT",
"output": "2"
},
{
"input": "2\nTH",
"output": "0"
},
{
"input": "4\nHTTH",
"output": "0"
},
{
"input": "4\nHTHT",
"output": "1"
},
{
"input": "7\nTTTHTTT",
"output": "0"
},
{
... | 1,691,913,477 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 218 | 0 | def min_swaps(n, positions):
hamster_count = positions.count('H')
tiger_count = n - hamster_count
min_swaps = float('inf')
for i in range(n):
hamster_swaps = 0
tiger_swaps = 0
for j in range(i, i + hamster_count):
if positions[j % n] == 'T':
... | Title: Hamsters and Tigers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Today there is going to be an unusual performance at the circus — hamsters and tigers will perform together! All of them stand in circle along the arena edge and now the trainer faces a difficult task: he wants to swap ... | ```python
def min_swaps(n, positions):
hamster_count = positions.count('H')
tiger_count = n - hamster_count
min_swaps = float('inf')
for i in range(n):
hamster_swaps = 0
tiger_swaps = 0
for j in range(i, i + hamster_count):
if positions[j % n] == 'T... | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,694,715,141 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 342 | 14,848,000 | import sys, io, os
import math
import bisect
import heapq
import string
import re
from decimal import *
from collections import defaultdict,Counter,deque
input = sys.stdin.readline
def I():
return input()
def II():
return int(input())
def MII():
return map(int, input().split())
de... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
import sys, io, os
import math
import bisect
import heapq
import string
import re
from decimal import *
from collections import defaultdict,Counter,deque
input = sys.stdin.readline
def I():
return input()
def II():
return int(input())
def MII():
return map(int, input().split... | 0 | MatrixStudio/Codeforces-Python-Submissions |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,686,160,095 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 61 | 0 | import random
n = int(input())
x = random.randrange(2, (n - 1))
y = n - x
print(f'{x} {y}') | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
import random
n = int(input())
x = random.randrange(2, (n - 1))
y = n - x
print(f'{x} {y}')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
789 | A | Anastasia and pebbles | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has only two pockets. She can put at most *k* pebbles in each pocket at the same tim... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 1<=≤<=*k*<=≤<=109) — the number of different pebble types and number of pebbles Anastasia can place in one pocket.
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=104) — number of pebbles of each type. | The only line of output contains one integer — the minimum number of days Anastasia needs to collect all the pebbles. | [
"3 2\n2 3 4\n",
"5 4\n3 1 8 9 7\n"
] | [
"3\n",
"5\n"
] | In the first sample case, Anastasia can collect all pebbles of the first type on the first day, of second type — on the second day, and of third type — on the third day.
Optimal sequence of actions in the second sample case:
- In the first day Anastasia collects 8 pebbles of the third type. - In the second day she... | 500 | [
{
"input": "3 2\n2 3 4",
"output": "3"
},
{
"input": "5 4\n3 1 8 9 7",
"output": "5"
},
{
"input": "1 22\n1",
"output": "1"
},
{
"input": "3 57\n78 165 54",
"output": "3"
},
{
"input": "5 72\n74 10 146 189 184",
"output": "6"
},
{
"input": "9 13\n132 8... | 1,490,817,758 | 2,147,483,647 | PyPy 3 | IDLENESS_LIMIT_EXCEEDED | TESTS | 5 | 109 | 28,672,000 | from sys import stdin, stdout
n, k = map(int, stdin.readline().split())
values = list(map(int, stdin.readline().split()))
cnt = 0
for i in range(n):
cnt += values[i] // k + (values[i] % k != 0)
stdout.write(str(cnt // 2 + (cnt % 2 != 0))) | Title: Anastasia and pebbles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could ... | ```python
from sys import stdin, stdout
n, k = map(int, stdin.readline().split())
values = list(map(int, stdin.readline().split()))
cnt = 0
for i in range(n):
cnt += values[i] // k + (values[i] % k != 0)
stdout.write(str(cnt // 2 + (cnt % 2 != 0)))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
257 | B | Playing Cubes | PROGRAMMING | 1,300 | [
"games",
"greedy",
"implementation"
] | null | null | Petya and Vasya decided to play a little. They found *n* red cubes and *m* blue cubes. The game goes like that: the players take turns to choose a cube of some color (red or blue) and put it in a line from left to right (overall the line will have *n*<=+<=*m* cubes). Petya moves first. Petya's task is to get as many pa... | The only line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of red and blue cubes, correspondingly. | On a single line print two space-separated integers — the number of Petya's and Vasya's points correspondingly provided that both players play optimally well. | [
"3 1\n",
"2 4\n"
] | [
"2 1\n",
"3 2\n"
] | In the first test sample the optimal strategy for Petya is to put the blue cube in the line. After that there will be only red cubes left, so by the end of the game the line of cubes from left to right will look as [blue, red, red, red]. So, Petya gets 2 points and Vasya gets 1 point.
If Petya would choose the red cu... | 500 | [
{
"input": "3 1",
"output": "2 1"
},
{
"input": "2 4",
"output": "3 2"
},
{
"input": "1 1",
"output": "0 1"
},
{
"input": "2 1",
"output": "1 1"
},
{
"input": "4 4",
"output": "3 4"
},
{
"input": "10 7",
"output": "9 7"
},
{
"input": "5 13"... | 1,540,128,469 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 0 | n=int(input())
m=int(input())
print(max(n,m),min(n,m)) | Title: Playing Cubes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya decided to play a little. They found *n* red cubes and *m* blue cubes. The game goes like that: the players take turns to choose a cube of some color (red or blue) and put it in a line from left to right (... | ```python
n=int(input())
m=int(input())
print(max(n,m),min(n,m))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,643,264,338 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 92 | 0 | N = input()
while N != '' and N[0:1] == '1' or N[0:2] == '14' or N[0:3] == '144':
if N[0:3] == '144':
N = N[3:]
else:
if N[0:2] == '14':
N = N[2:]
else:
if N[0:1] == '1':
N = N[1:]
if N == '':
print('YES')
else:
print('NO') | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
N = input()
while N != '' and N[0:1] == '1' or N[0:2] == '14' or N[0:3] == '144':
if N[0:3] == '144':
N = N[3:]
else:
if N[0:2] == '14':
N = N[2:]
else:
if N[0:1] == '1':
N = N[1:]
if N == '':
print('YES')
else:
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
957 | A | Tritonic Iridescence | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one-dimensional canvas split into *n* consecutive segments, each segment needs to be painted in one of the co... | The first line contains a single positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the canvas.
The second line contains a string *s* of *n* characters, the *i*-th of which is either 'C' (denoting a segment painted in cyan), 'M' (denoting one painted in magenta), 'Y' (one painted in yellow), or '?' (an unpainted... | If there are at least two different ways of painting, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5\nCY??Y\n",
"5\nC?C?Y\n",
"5\n?CYC?\n",
"5\nC??MM\n",
"3\nMMY\n"
] | [
"Yes\n",
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | For the first example, there are exactly two different ways of colouring: CYCMY and CYMCY.
For the second example, there are also exactly two different ways of colouring: CMCMY and CYCMY.
For the third example, there are four ways of colouring: MCYCM, MCYCY, YCYCM, and YCYCY.
For the fourth example, no matter how th... | 500 | [
{
"input": "5\nCY??Y",
"output": "Yes"
},
{
"input": "5\nC?C?Y",
"output": "Yes"
},
{
"input": "5\n?CYC?",
"output": "Yes"
},
{
"input": "5\nC??MM",
"output": "No"
},
{
"input": "3\nMMY",
"output": "No"
},
{
"input": "15\n??YYYYYY??YYYY?",
"output"... | 1,521,906,670 | 970 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 77 | 7,372,800 | n = int(input())
s = input()
x = False
dup = False
for i in range(0,n-1):
if s[i]==s[i+1]:
dup = True
break
for i in range(0,n):
if x:
break
if s[i]=='?':
if i==0:
x = True
continue
elif i==n-1:
x = True
continue
... | Title: Tritonic Iridescence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Overlooking the captivating blend of myriads of vernal hues, Arkady the painter lays out a long, long canvas.
Arkady has a sufficiently large amount of paint of three colours: cyan, magenta, and yellow. On the one... | ```python
n = int(input())
s = input()
x = False
dup = False
for i in range(0,n-1):
if s[i]==s[i+1]:
dup = True
break
for i in range(0,n):
if x:
break
if s[i]=='?':
if i==0:
x = True
continue
elif i==n-1:
x = True
contin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* em... | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,669,682,525 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | n = int(input())
n1 = n // 2
counter = 0
for i in range(1, n1):
sum1 = n - i
if sum1 % i == 0:
counter += 1
print(counter + 1) | Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the emp... | ```python
n = int(input())
n1 = n // 2
counter = 0
for i in range(1, n1):
sum1 = n - i
if sum1 % i == 0:
counter += 1
print(counter + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,674,410,596 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | p=input()
q=input()
r=list(p)
s=list(q)
t=len(p)
i=0
c=[]
while t>0:
if p[i]==q[i]:
c.append(0)
elif p[i]!=q[i]:
c.append(1)
i=i+1
t=t-1
print(c)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
p=input()
q=input()
r=list(p)
s=list(q)
t=len(p)
i=0
c=[]
while t>0:
if p[i]==q[i]:
c.append(0)
elif p[i]!=q[i]:
c.append(1)
i=i+1
t=t-1
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,626,432,191 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 154 | 6,963,200 | n=int(input())
a=input().split()
counteven=0
poseven=0
posodd=0
for i in range(n):
a[i]=int(a[i])
for i in range(n):
if a[i]%2==0:
poseven=i
counteven+=1
else:
posodd=i
if counteven==(n-1):
print(posodd+1)
else:
print(poseven+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
a=input().split()
counteven=0
poseven=0
posodd=0
for i in range(n):
a[i]=int(a[i])
for i in range(n):
if a[i]%2==0:
poseven=i
counteven+=1
else:
posodd=i
if counteven==(n-1):
print(posodd+1)
else:
print(poseven+1)
``` | 3.94853 | MatrixStudio/Codeforces-Python-Submissions |
960 | B | Minimize the error | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one operation, you have to choose one element of the array and increase or decrease it by 1.
Output the min... | The first line contains three space-separated integers *n* (1<=≤<=*n*<=≤<=103), *k*1 and *k*2 (0<=≤<=*k*1<=+<=*k*2<=≤<=103, *k*1 and *k*2 are non-negative) — size of arrays and number of operations to perform on *A* and *B* respectively.
Second line contains *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (<=-... | Output a single integer — the minimum possible value of after doing exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. | [
"2 0 0\n1 2\n2 3\n",
"2 1 0\n1 2\n2 2\n",
"2 5 7\n3 4\n14 4\n"
] | [
"2",
"0",
"1"
] | In the first sample case, we cannot perform any operations on *A* or *B*. Therefore the minimum possible error *E* = (1 - 2)<sup class="upper-index">2</sup> + (2 - 3)<sup class="upper-index">2</sup> = 2.
In the second sample case, we are required to perform exactly one operation on *A*. In order to minimize error, we... | 1,000 | [
{
"input": "2 0 0\n1 2\n2 3",
"output": "2"
},
{
"input": "2 1 0\n1 2\n2 2",
"output": "0"
},
{
"input": "2 5 7\n3 4\n14 4",
"output": "1"
},
{
"input": "2 0 1\n1 2\n2 2",
"output": "0"
},
{
"input": "2 1 1\n0 0\n1 1",
"output": "0"
},
{
"input": "5 5 ... | 1,614,200,349 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
int n,k1,k2;
scanf("%d %d %d",&n,&k1,&k2);
int k=k1+k2;
vector <int> a(n),b(n), c;
for (int i=0;i<n;i++) {
scanf("%d", &a[i]);
}
for (int i=0;i<n;i++) {
scanf("%d", &b... | Title: Minimize the error
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one ... | ```python
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
int n,k1,k2;
scanf("%d %d %d",&n,&k1,&k2);
int k=k1+k2;
vector <int> a(n),b(n), c;
for (int i=0;i<n;i++) {
scanf("%d", &a[i]);
}
for (int i=0;i<n;i++) {
scan... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
424 | C | Magic Formulas | PROGRAMMING | 1,600 | [
"math"
] | null | null | People in the Tomskaya region like magic formulas very much. You can see some of them below.
Imagine you are given a sequence of positive integer numbers *p*1, *p*2, ..., *p**n*. Lets write down some magic formulas:
Here, "mod" means the operation of taking the residue after dividing.
The expression means applying ... | The first line of the input contains the only integer *n* (1<=≤<=*n*<=≤<=106). The next line contains *n* integers: *p*1,<=*p*2,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=2·109). | The only line of output should contain a single integer — the value of *Q*. | [
"3\n1 2 3\n"
] | [
"3\n"
] | none | 1,500 | [
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n65535 0",
"output": "65534"
},
{
"input": "10\n1356106972 165139648 978829595 410669403 873711167 287346624 117863440 228957745 835903650 1575323015",
"output": "948506286"
},
{... | 1,617,104,941 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 1,871 | 73,216,000 | n,p,l,k,q=int(input()),list(map(int,input().split())),[],0,0
for i in range(n):k^=i;l+=[k]
for i in range(n):r=i+1;q^=p[i]^l[i]*(n//r%2)^l[n%r]
print(q) | Title: Magic Formulas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
People in the Tomskaya region like magic formulas very much. You can see some of them below.
Imagine you are given a sequence of positive integer numbers *p*1, *p*2, ..., *p**n*. Lets write down some magic formulas:
He... | ```python
n,p,l,k,q=int(input()),list(map(int,input().split())),[],0,0
for i in range(n):k^=i;l+=[k]
for i in range(n):r=i+1;q^=p[i]^l[i]*(n//r%2)^l[n%r]
print(q)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
779 | A | Pupils Redistribution | PROGRAMMING | 1,000 | [
"constructive algorithms",
"math"
] | null | null | In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consists of exactly *n* students. An academic performance of each student is known — integer value between 1 and ... | The first line of the input contains integer number *n* (1<=≤<=*n*<=≤<=100) — number of students in both groups.
The second line contains sequence of integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=5), where *a**i* is academic performance of the *i*-th student of the group *A*.
The third line contains se... | Print the required minimum number of exchanges or -1, if the desired distribution of students can not be obtained. | [
"4\n5 4 4 4\n5 5 4 5\n",
"6\n1 1 1 1 1 1\n5 5 5 5 5 5\n",
"1\n5\n3\n",
"9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1\n"
] | [
"1\n",
"3\n",
"-1\n",
"4\n"
] | none | 500 | [
{
"input": "4\n5 4 4 4\n5 5 4 5",
"output": "1"
},
{
"input": "6\n1 1 1 1 1 1\n5 5 5 5 5 5",
"output": "3"
},
{
"input": "1\n5\n3",
"output": "-1"
},
{
"input": "9\n3 2 5 5 2 3 3 3 2\n4 1 4 1 1 2 4 4 1",
"output": "4"
},
{
"input": "1\n1\n2",
"output": "-1"
... | 1,638,454,876 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | n = int(input())
a = list(map(int, input().split(maxsplit = n)))
b = list(map(int, input().split(maxsplit = n)))
sum_1=sum(a)
sum_2=sum(b)
ball=(sum(a)+sum(b))//2
if n==1:
print('-1')
elif sum_1==sum_2:
print('0')
elif sum_1<sum_2:
print(ball//(sum_1%sum_2))
elif sum_1>sum_2:
print(ball//(s... | Title: Pupils Redistribution
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland each high school student is characterized by academic performance — integer value between 1 and 5.
In high school 0xFF there are two groups of pupils: the group *A* and the group *B*. Each group consis... | ```python
n = int(input())
a = list(map(int, input().split(maxsplit = n)))
b = list(map(int, input().split(maxsplit = n)))
sum_1=sum(a)
sum_2=sum(b)
ball=(sum(a)+sum(b))//2
if n==1:
print('-1')
elif sum_1==sum_2:
print('0')
elif sum_1<sum_2:
print(ball//(sum_1%sum_2))
elif sum_1>sum_2:
prin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,618,062,024 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 124 | 7,168,000 | n, b, d = map(int, input().split())
summa = 0
ans = 0
a = [int(i) for i in input().split()]
for i in a:
if i < b:
summa += i
if summa >= d:
summa -= d
ans += 1
print(ans)
| Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
n, b, d = map(int, input().split())
summa = 0
ans = 0
a = [int(i) for i in input().split()]
for i in a:
if i < b:
summa += i
if summa >= d:
summa -= d
ans += 1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x*<=/<=*y*.
Your favorite rational number in the [0;1] range is *p*<=/<=*q*. Now you wonde... | The first line contains a single integer *t* (1<=≤<=*t*<=≤<=1000) — the number of test cases.
Each of the next *t* lines contains four integers *x*, *y*, *p* and *q* (0<=≤<=*x*<=≤<=*y*<=≤<=109; 0<=≤<=*p*<=≤<=*q*<=≤<=109; *y*<=><=0; *q*<=><=0).
It is guaranteed that *p*<=/<=*q* is an irreducible fraction.
Hacks... | For each test case, output a single integer equal to the smallest number of submissions you have to make if you want your success rate to be equal to your favorite rational number, or -1 if this is impossible to achieve. | [
"4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1\n"
] | [
"4\n10\n0\n-1\n"
] | In the first example, you have to make 4 successful submissions. Your success rate will be equal to 7 / 14, or 1 / 2.
In the second example, you have to make 2 successful and 8 unsuccessful submissions. Your success rate will be equal to 9 / 24, or 3 / 8.
In the third example, there is no need to make any new submiss... | 0 | [
{
"input": "4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1",
"output": "4\n10\n0\n-1"
},
{
"input": "8\n0 1 0 1\n0 2 1 2\n0 3 1 1\n1 2 0 1\n1 2 1 1\n2 2 0 1\n3 3 1 2\n4 4 1 1",
"output": "0\n2\n-1\n-1\n-1\n-1\n3\n0"
},
{
"input": "5\n1 1000000000 1 2\n1 1000000000 1 2\n1 1000000000 1 2\n1 100... | 1,494,216,867 | 1,167 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 1 | 2,000 | 0 | import sys
N = int(input())
for i in range(N):
x, y, p, q = map(int,input().split())
y=y-x
q=q-p
if q==0:
print(-1)
else:
p1=p
q1=q
j=1
while (x>p1) | (y>q1):
p1=p1+p
q1=q1+q
print(p1+q1-x-y)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x... | ```python
import sys
N = int(input())
for i in range(N):
x, y, p, q = map(int,input().split())
y=y-x
q=q-p
if q==0:
print(-1)
else:
p1=p
q1=q
j=1
while (x>p1) | (y>q1):
p1=p1+p
q1=q1+q
print(p1+q1-x-y)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
508 | A | Pasha and Pixels | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row with *m* pixels in each row. Initially, all the pixels are colored white. In one move, Pasha can choos... | The first line of the input contains three integers *n*,<=*m*,<=*k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=105) — the number of rows, the number of columns and the number of moves that Pasha is going to perform.
The next *k* lines contain Pasha's moves in the order he makes them. Each line contains two integers *i*... | If Pasha loses, print the number of the move when the 2<=×<=2 square consisting of black pixels is formed.
If Pasha doesn't lose, that is, no 2<=×<=2 square consisting of black pixels is formed during the given *k* moves, print 0. | [
"2 2 4\n1 1\n1 2\n2 1\n2 2\n",
"2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1\n",
"5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2\n"
] | [
"4\n",
"5\n",
"0\n"
] | none | 500 | [
{
"input": "2 2 4\n1 1\n1 2\n2 1\n2 2",
"output": "4"
},
{
"input": "2 3 6\n2 3\n2 2\n1 3\n2 2\n1 2\n1 1",
"output": "5"
},
{
"input": "5 3 7\n2 3\n1 2\n1 1\n4 1\n3 1\n5 3\n3 2",
"output": "0"
},
{
"input": "3 3 11\n2 1\n3 1\n1 1\n1 3\n1 2\n2 3\n3 3\n3 2\n2 2\n1 3\n3 3",
... | 1,697,862,198 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n, m, k = map(int, input().split())
actions = [list(map(int, input().split())) for _ in range(k)]
grid = [[0] * m for _ in range(n)]
dx = [0, 0, 1, 1]
dy = [0, 1, 0, 1]
def check(x, y):
if x < n-1 and y < m-1:
if grid[x][y] and grid[x+dx[1]][y+dy[1]] and grid[x+dx[2]][y+dy[2]] and grid[x+dx[3]][y+d... | Title: Pasha and Pixels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha loves his phone and also putting his hair up... But the hair is now irrelevant.
Pasha has installed a new game to his phone. The goal of the game is following. There is a rectangular field consisting of *n* row ... | ```python
n, m, k = map(int, input().split())
actions = [list(map(int, input().split())) for _ in range(k)]
grid = [[0] * m for _ in range(n)]
dx = [0, 0, 1, 1]
dy = [0, 1, 0, 1]
def check(x, y):
if x < n-1 and y < m-1:
if grid[x][y] and grid[x+dx[1]][y+dy[1]] and grid[x+dx[2]][y+dy[2]] and grid[x+... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
331 | C1 | The Great Julya Calendar | PROGRAMMING | 1,100 | [
"dp"
] | null | null | Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on it. The translation from Old Beaverish is as follows:
"May the Great Beaver bless you! May your chacres open ... | The single line contains the magic integer *n*, 0<=≤<=*n*.
- to get 20 points, you need to solve the problem with constraints: *n*<=≤<=106 (subproblem C1); - to get 40 points, you need to solve the problem with constraints: *n*<=≤<=1012 (subproblems C1+C2); - to get 100 points, you need to solve the problem with co... | Print a single integer — the minimum number of subtractions that turns the magic number to a zero. | [
"24\n"
] | [
"5"
] | In the first test sample the minimum number of operations can be reached by the following sequence of subtractions: | 20 | [
{
"input": "24",
"output": "5"
},
{
"input": "0",
"output": "0"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "1"
},
{
"input": "9",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "31",
"output": "6"
},
... | 1,608,833,155 | 2,147,483,647 | Python 3 | OK | TESTS1 | 24 | 404 | 0 | n,c=int(input()),0
while n:n-=int(max(str(n)));c+=1
print(c) | Title: The Great Julya Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yet another Armageddon is coming! This time the culprit is the Julya tribe calendar.
The beavers in this tribe knew math very well. Smart Beaver, an archaeologist, got a sacred plate with a magic integer on i... | ```python
n,c=int(input()),0
while n:n-=int(max(str(n)));c+=1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given set of *n* points in 5-dimensional space. The points are labeled from 1 to *n*. No two points coincide.
We will call point *a* bad if there are different points *b* and *c*, not equal to *a*, from the given set such that angle between vectors and is acute (i.e. strictly less than ). Otherwise, the poin... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=103) — the number of points.
The next *n* lines of input contain five integers *a**i*,<=*b**i*,<=*c**i*,<=*d**i*,<=*e**i* (|*a**i*|,<=|*b**i*|,<=|*c**i*|,<=|*d**i*|,<=|*e**i*|<=≤<=103) — the coordinates of the i-th point. All points are distinct. | First, print a single integer *k* — the number of good points.
Then, print *k* integers, each on their own line — the indices of the good points in ascending order. | [
"6\n0 0 0 0 0\n1 0 0 0 0\n0 1 0 0 0\n0 0 1 0 0\n0 0 0 1 0\n0 0 0 0 1\n",
"3\n0 0 1 2 0\n0 0 9 2 0\n0 0 5 9 0\n"
] | [
"1\n1\n",
"0\n"
] | In the first sample, the first point forms exactly a <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/362ac8c7a7496dffc06cd0c843287cd822be63c3.png" style="max-width: 100.0%;max-height: 100.0%;"/> angle with all other pairs of points, so it is good.
In the second sample, along the cd plane, ... | 0 | [
{
"input": "6\n0 0 0 0 0\n1 0 0 0 0\n0 1 0 0 0\n0 0 1 0 0\n0 0 0 1 0\n0 0 0 0 1",
"output": "1\n1"
},
{
"input": "3\n0 0 1 2 0\n0 0 9 2 0\n0 0 5 9 0",
"output": "0"
},
{
"input": "1\n0 0 0 0 0",
"output": "1\n1"
},
{
"input": "2\n0 1 2 3 4\n5 6 7 8 9",
"output": "2\n1\n2"... | 1,504,542,365 | 6,665 | Python 3 | COMPILATION_ERROR | PRETESTS | 0 | 0 | 0 | #include <stdio.h>
#include <math.h>
double get_angle(int* vec1, int* vec2){
int count=0;
for(int i=0;i<5; i++)
count+=vec1[i]*vec2[i];
int len1=0;
for(int i=0;i<5; i++)
len1+=vec1[i]*vec1[i];
int len2=0;
for(int i=0;i<5; i++)
len2+=vec2[i]*vec2[i];
//printf("%d %f\n", count, sqrt(len1*len2));
return(aco... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given set of *n* points in 5-dimensional space. The points are labeled from 1 to *n*. No two points coincide.
We will call point *a* bad if there are different points *b* and *c*, not equal to *a*, from the given set such... | ```python
#include <stdio.h>
#include <math.h>
double get_angle(int* vec1, int* vec2){
int count=0;
for(int i=0;i<5; i++)
count+=vec1[i]*vec2[i];
int len1=0;
for(int i=0;i<5; i++)
len1+=vec1[i]*vec1[i];
int len2=0;
for(int i=0;i<5; i++)
len2+=vec2[i]*vec2[i];
//printf("%d %f\n", count, sqrt(len1*len2));
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,411,905,835 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | numbers = input().split()
amounts = sorted(set(numbers.count(x) for x in numbers))
if amounts == [1,4]: print('Bear')
elif amounts == [2,4]: print('Elephant')
else: print('Alien'); | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
numbers = input().split()
amounts = sorted(set(numbers.count(x) for x in numbers))
if amounts == [1,4]: print('Bear')
elif amounts == [2,4]: print('Elephant')
else: print('Alien');
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,696,655,611 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n=int(input("enter number of friends"))
h=int(input("enter hieght of hence"))
m_w=0
for m_w in range(n):
friend=int(input())
if friend>h:
m_w+=2
else:
m_w+=1
print(m_w) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n=int(input("enter number of friends"))
h=int(input("enter hieght of hence"))
m_w=0
for m_w in range(n):
friend=int(input())
if friend>h:
m_w+=2
else:
m_w+=1
print(m_w)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
932 | F | Escape Through Leaf | PROGRAMMING | 2,700 | [
"data structures",
"dp",
"geometry"
] | null | null | You are given a tree with *n* nodes (numbered from 1 to *n*) rooted at node 1. Also, each node has two values associated with it. The values for *i*-th node are *a**i* and *b**i*.
You can jump from a node to any node in its subtree. The cost of one jump from node *x* to node *y* is the product of *a**x* and *b**y*. Th... | The first line of input contains an integer *n* (2<=≤<=*n*<=≤<=105) — the number of nodes in the tree.
The second line contains *n* space-separated integers *a*1,<=<=*a*2,<=<=...,<=<=*a**n*(<=-<=105<=<=≤<=<=*a**i*<=<=≤<=<=105).
The third line contains *n* space-separated integers *b*1,<=<=*b*2,<=<=...,<=<=*b**n*(<=-<... | Output *n* space-separated integers, *i*-th of which denotes the minimum cost of a path from node *i* to reach any leaf. | [
"3\n2 10 -1\n7 -7 5\n2 3\n2 1\n",
"4\n5 -10 5 7\n-8 -80 -3 -10\n2 1\n2 4\n1 3\n"
] | [
"10 50 0 ",
"-300 100 0 0 "
] | In the first example, node 3 is already a leaf, so the cost is 0. For node 2, jump to node 3 with cost *a*<sub class="lower-index">2</sub> × *b*<sub class="lower-index">3</sub> = 50. For node 1, jump directly to node 3 with cost *a*<sub class="lower-index">1</sub> × *b*<sub class="lower-index">3</sub> = 10.
In the sec... | 2,500 | [
{
"input": "3\n2 10 -1\n7 -7 5\n2 3\n2 1",
"output": "10 50 0 "
},
{
"input": "4\n5 -10 5 7\n-8 -80 -3 -10\n2 1\n2 4\n1 3",
"output": "-300 100 0 0 "
},
{
"input": "5\n7 -8 -8 -3 -10\n6 1 -6 7 5\n3 1\n2 5\n1 4\n4 5",
"output": "-42 0 0 -25 -10 "
},
{
"input": "6\n4 -8 9 -1 -2... | 1,518,710,445 | 5,145 | Python 3 | RUNTIME_ERROR | PRETESTS | 5 | 529 | 15,974,400 | n = int(input())
avals = [int(x) for x in input().split(' ')]
bvals = [int(x) for x in input().split(' ')]
neighbors = [[] for i in range(n)]
for i in range(n-1):
raw = [int(x) for x in input().split(' ')]
neighbors[raw[0]-1].append(raw[1]-1)
neighbors[raw[1]-1].append(raw[0]-1)
def subtree(index,parent):
... | Title: Escape Through Leaf
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a tree with *n* nodes (numbered from 1 to *n*) rooted at node 1. Also, each node has two values associated with it. The values for *i*-th node are *a**i* and *b**i*.
You can jump from a node to any no... | ```python
n = int(input())
avals = [int(x) for x in input().split(' ')]
bvals = [int(x) for x in input().split(' ')]
neighbors = [[] for i in range(n)]
for i in range(n-1):
raw = [int(x) for x in input().split(' ')]
neighbors[raw[0]-1].append(raw[1]-1)
neighbors[raw[1]-1].append(raw[0]-1)
def subtree(index... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,590,763,367 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 390 | 10,752,000 | from collections import *
from bisect import *
from math import *
from heapq import *
from fractions import *
import sys
input=sys.stdin.readline
t=1
def r(a):
return ((a*(a-1))//2)
while(t):
t-=1
n,m=map(int,input().split())
f={}
for i in range(m):
a=input().split()
... | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
from collections import *
from bisect import *
from math import *
from heapq import *
from fractions import *
import sys
input=sys.stdin.readline
t=1
def r(a):
return ((a*(a-1))//2)
while(t):
t-=1
n,m=map(int,input().split())
f={}
for i in range(m):
a=input().split()... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,696,006,665 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | t = int(input())
ls = list(map(int,input().split()))
odd =0
even =0
for i in ls:
if i%2==0:
even+=1
else:
odd+=1
stor1 =0
if even>odd:
for i in ls:
if i %2 !=0:
stor1 = i
else:
for i in ls:
if i %2 ==0:
stor1 = i
print(s... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
t = int(input())
ls = list(map(int,input().split()))
odd =0
even =0
for i in ls:
if i%2==0:
even+=1
else:
odd+=1
stor1 =0
if even>odd:
for i in ls:
if i %2 !=0:
stor1 = i
else:
for i in ls:
if i %2 ==0:
stor1 = i
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant... | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,637,170,151 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s = input()
vowel = 'aeiouAEIOU'
n = len(s)
if n == 1 and s[0] not in vowel and s[0] !='n':
result = 'NO'
elif n == 1 and s[0] == 'n' or s[0] in vowel :
result = 'YES'
for i in range(n-1):
if s[i] not in vowel and s[i+1] in vowel:
result = 'YES'
elif s[i] == 'n':
result = 'YES... | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after eve... | ```python
s = input()
vowel = 'aeiouAEIOU'
n = len(s)
if n == 1 and s[0] not in vowel and s[0] !='n':
result = 'NO'
elif n == 1 and s[0] == 'n' or s[0] in vowel :
result = 'YES'
for i in range(n-1):
if s[i] not in vowel and s[i+1] in vowel:
result = 'YES'
elif s[i] == 'n':
res... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
311 | B | Cats Transport | PROGRAMMING | 2,400 | [
"data structures",
"dp"
] | null | null | Zxr960115 is owner of a large farm. He feeds *m* cute cats and employs *p* feeders. There's a straight road across the farm and *n* hills along the road, numbered from 1 to *n* from left to right. The distance between hill *i* and (*i*<=-<=1) is *d**i* meters. The feeders live in hill 1.
One day, the cats went out to ... | The first line of the input contains three integers *n*,<=*m*,<=*p* (2<=≤<=*n*<=≤<=105,<=1<=≤<=*m*<=≤<=105,<=1<=≤<=*p*<=≤<=100).
The second line contains *n*<=-<=1 positive integers *d*2,<=*d*3,<=...,<=*d**n* (1<=≤<=*d**i*<=<<=104).
Each of the next *m* lines contains two integers *h**i* and *t**i* (1<=≤<=*h**i*<=... | Output an integer, the minimum sum of waiting time of all cats.
Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 6 2\n1 3 5\n1 0\n2 1\n4 9\n1 10\n2 10\n3 12\n"
] | [
"3\n"
] | none | 1,000 | [
{
"input": "4 6 2\n1 3 5\n1 0\n2 1\n4 9\n1 10\n2 10\n3 12",
"output": "3"
}
] | 1,693,418,614 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1693418614.6411917")# 1693418614.6412075 | Title: Cats Transport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Zxr960115 is owner of a large farm. He feeds *m* cute cats and employs *p* feeders. There's a straight road across the farm and *n* hills along the road, numbered from 1 to *n* from left to right. The distance between hi... | ```python
print("_RANDOM_GUESS_1693418614.6411917")# 1693418614.6412075
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
679 | B | Bear and Tower of Cubes | PROGRAMMING | 2,200 | [
"binary search",
"dp",
"greedy"
] | null | null | Limak is a little polar bear. He plays by building towers from blocks. Every block is a cube with positive integer length of side. Limak has infinitely many blocks of each side length.
A block with side *a* has volume *a*3. A tower consisting of blocks with sides *a*1,<=*a*2,<=...,<=*a**k* has the total volume *a*13<=... | The only line of the input contains one integer *m* (1<=≤<=*m*<=≤<=1015), meaning that Limak wants you to choose *X* between 1 and *m*, inclusive. | Print two integers — the maximum number of blocks in the tower and the maximum required total volume *X*, resulting in the maximum number of blocks. | [
"48\n",
"6\n"
] | [
"9 42\n",
"6 6\n"
] | In the first sample test, there will be 9 blocks if you choose *X* = 23 or *X* = 42. Limak wants to maximize *X* secondarily so you should choose 42.
In more detail, after choosing *X* = 42 the process of building a tower is:
- Limak takes a block with side 3 because it's the biggest block with volume not greater th... | 1,250 | [
{
"input": "48",
"output": "9 42"
},
{
"input": "6",
"output": "6 6"
},
{
"input": "1",
"output": "1 1"
},
{
"input": "994",
"output": "12 941"
},
{
"input": "567000123",
"output": "16 566998782"
},
{
"input": "123830583943",
"output": "17 12383056... | 1,611,459,374 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 307,200 | import math
if __name__ == "__main__":
m = int(input())
total_blocks_used = 0
total_vol = 0
steps_dct = {}
while (m > 0):
x = math.floor(m ** (1/3))
if steps(m, steps_dct) == 1 + steps(m - x**3):
m -= x**3
total_vol += x**3
else:
... | Title: Bear and Tower of Cubes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He plays by building towers from blocks. Every block is a cube with positive integer length of side. Limak has infinitely many blocks of each side length.
A block with side *a* has... | ```python
import math
if __name__ == "__main__":
m = int(input())
total_blocks_used = 0
total_vol = 0
steps_dct = {}
while (m > 0):
x = math.floor(m ** (1/3))
if steps(m, steps_dct) == 1 + steps(m - x**3):
m -= x**3
total_vol += x**3
else:... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,605,538,996 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | a = int(input())
b = list(map(int, input().split()))
c = max(b)
d = list()
for e in range(1, c + 1):
f = b.index(e)
d.append(f+1)
print(*d)
| Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
a = int(input())
b = list(map(int, input().split()))
c = max(b)
d = list()
for e in range(1, c + 1):
f = b.index(e)
d.append(f+1)
print(*d)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive co... | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,507,239,585 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 62 | 0 | # print("Input n")
n = int(input())
if n%2 == 0:
if (n//2-1)%2 != 0:
print(str(n//2 - 1) + " " + str(n//2 + 1))
else:
print(str(n//2 - 2) + " " + str(n//2 + 2))
else:
print(str(n//2) + " " + str(n//2 + 1))
| Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is cal... | ```python
# print("Input n")
n = int(input())
if n%2 == 0:
if (n//2-1)%2 != 0:
print(str(n//2 - 1) + " " + str(n//2 + 1))
else:
print(str(n//2 - 2) + " " + str(n//2 + 2))
else:
print(str(n//2) + " " + str(n//2 + 1))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
651 | A | Joysticks | PROGRAMMING | 1,100 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if n... | The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively. | Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged. | [
"3 5\n",
"4 4\n"
] | [
"6\n",
"5\n"
] | In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joyst... | 500 | [
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
... | 1,631,556,921 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 77 | 20,172,800 | a, b = list(map(int,input().split()))
count = 0
while True:
a, b = max(a,b), min(a, b)
a -= 2
b += 1
if a < 0 or b < 0:
break
count += 1
print(count) | Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick on... | ```python
a, b = list(map(int,input().split()))
count = 0
while True:
a, b = max(a,b), min(a, b)
a -= 2
b += 1
if a < 0 or b < 0:
break
count += 1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
86 | A | Reflection | PROGRAMMING | 1,600 | [
"math"
] | A. Reflection | 2 | 256 | For each positive integer *n* consider the integer ψ(*n*) which is obtained from *n* by replacing every digit *a* in the decimal notation of *n* with the digit (9<=<=-<=<=*a*). We say that ψ(*n*) is the reflection of *n*. For example, reflection of 192 equals 807. Note that leading zeros (if any) should be omitted. So ... | Input contains two space-separated integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=109) — bounds of the range. | Output should contain single integer number: maximum value of the product *n*·ψ(*n*), where *l*<=≤<=*n*<=≤<=*r*.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preferred to use cout (also you may use %I64d). | [
"3 7\n",
"1 1\n",
"8 10\n"
] | [
"20",
"8",
"890"
] | In the third sample weight of 8 equals 8·1 = 8, weight of 9 equals 9·0 = 0, weight of 10 equals 890.
Thus, maximum value of the product is equal to 890. | 500 | [
{
"input": "3 7",
"output": "20"
},
{
"input": "1 1",
"output": "8"
},
{
"input": "8 10",
"output": "890"
},
{
"input": "4 6",
"output": "20"
},
{
"input": "10 100",
"output": "89900"
},
{
"input": "1 999",
"output": "249500"
},
{
"input": ... | 1,456,172,670 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 2,000 | 9,420,800 | inp1, inp2 = [int(i) for i in input().split()]
lista = list()
def reverse(n):
newStr = ""
for c in str(n):
newC = 9 - int(c)
newStr += str(newC)
return int(newStr)
for i in range(inp1,inp2 +1):
w = reverse(i) * i
lista.append(w)
print(max(lista)) | Title: Reflection
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
For each positive integer *n* consider the integer ψ(*n*) which is obtained from *n* by replacing every digit *a* in the decimal notation of *n* with the digit (9<=<=-<=<=*a*). We say that ψ(*n*) is the reflection of *n*. For ex... | ```python
inp1, inp2 = [int(i) for i in input().split()]
lista = list()
def reverse(n):
newStr = ""
for c in str(n):
newC = 9 - int(c)
newStr += str(newC)
return int(newStr)
for i in range(inp1,inp2 +1):
w = reverse(i) * i
lista.append(w)
print(max(lista))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
10 | A | Power Consumption Calculation | PROGRAMMING | 900 | [
"implementation"
] | A. Power Consumption Calculation | 1 | 256 | Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T... | The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<... | Output the answer to the problem. | [
"1 3 2 1 5 10\n0 10\n",
"2 8 4 2 5 10\n20 30\n50 100\n"
] | [
"30",
"570"
] | none | 0 | [
{
"input": "1 3 2 1 5 10\n0 10",
"output": "30"
},
{
"input": "2 8 4 2 5 10\n20 30\n50 100",
"output": "570"
},
{
"input": "3 15 9 95 39 19\n873 989\n1003 1137\n1172 1436",
"output": "8445"
},
{
"input": "4 73 2 53 58 16\n51 52\n209 242\n281 407\n904 945",
"output": "5287... | 1,591,944,981 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 280 | 0 | n,p1,p2,p3,t1,t2 = map(int, input().split())
data = []
result = 0
for i in range(n):
data.append(list(map(int, input().split())))
result += p1*(data[i][1]-data[i][0])
for i in range(1,n):
gap = data[i][0]-data[i-1][1]
if gap>t1+t2:
result += (gap-(t1+t2))*p3
gap = t1+t2
... | Title: Power Consumption Calculation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard f... | ```python
n,p1,p2,p3,t1,t2 = map(int, input().split())
data = []
result = 0
for i in range(n):
data.append(list(map(int, input().split())))
result += p1*(data[i][1]-data[i][0])
for i in range(1,n):
gap = data[i][0]-data[i-1][1]
if gap>t1+t2:
result += (gap-(t1+t2))*p3
gap = t... | 3.86 | MatrixStudio/Codeforces-Python-Submissions |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the numb... | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,678,724,703 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 307,200 | a = []
b = []
for y in range(int(input())):
m, n = [int(x) for x in input().split()]
a.append(m)
b.append(n)
c = min(a)
i = a.index(c)
d = max(b)
if (b[i]==d):
print("Happy Alex")
else :
print("Poor Alex") | Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the... | ```python
a = []
b = []
for y in range(int(input())):
m, n = [int(x) for x in input().split()]
a.append(m)
b.append(n)
c = min(a)
i = a.index(c)
d = max(b)
if (b[i]==d):
print("Happy Alex")
else :
print("Poor Alex")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
143 | A | Help Vasilisa the Wise 2 | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know what the box's secret is, since she cannot open it again. She hopes that you will help her one more time with tha... | The input contains numbers written on the edges of the lock of the box. The first line contains space-separated integers *r*1 and *r*2 that define the required sums of numbers in the rows of the square. The second line contains space-separated integers *c*1 and *c*2 that define the required sums of numbers in the colum... | Print the scheme of decorating the box with stones: two lines containing two space-separated integers from 1 to 9. The numbers should be pairwise different. If there is no solution for the given lock, then print the single number "-1" (without the quotes).
If there are several solutions, output any. | [
"3 7\n4 6\n5 5\n",
"11 10\n13 8\n5 16\n",
"1 2\n3 4\n5 6\n",
"10 10\n10 10\n10 10\n"
] | [
"1 2\n3 4\n",
"4 7\n9 1\n",
"-1\n",
"-1\n"
] | Pay attention to the last test from the statement: it is impossible to open the box because for that Vasilisa the Wise would need 4 identical gems containing number "5". However, Vasilisa only has one gem with each number from 1 to 9. | 500 | [
{
"input": "3 7\n4 6\n5 5",
"output": "1 2\n3 4"
},
{
"input": "11 10\n13 8\n5 16",
"output": "4 7\n9 1"
},
{
"input": "1 2\n3 4\n5 6",
"output": "-1"
},
{
"input": "10 10\n10 10\n10 10",
"output": "-1"
},
{
"input": "5 13\n8 10\n11 7",
"output": "3 2\n5 8"
... | 1,585,729,068 | 2,147,483,647 | PyPy 3 | OK | TESTS | 52 | 280 | 0 | from sys import stdin,stdout
i1 = lambda : int(stdin.readline())
iia = lambda : map(int, stdin.readline().split())
isa = lambda: stdin.readline().split()
r1, r2 = iia()
c1, c2 = iia()
d1, d2 = iia()
if (c2 + r2 - d2) % 2 == 0:
d = (c2 + r2 - d2) // 2
c = r2 - d
b = c2 - d
a = r1 - b
te... | Title: Help Vasilisa the Wise 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasilisa the Wise from the Kingdom of Far Far Away got a magic box with a secret as a present from her friend Hellawisa the Wise from the Kingdom of A Little Closer. However, Vasilisa the Wise does not know wha... | ```python
from sys import stdin,stdout
i1 = lambda : int(stdin.readline())
iia = lambda : map(int, stdin.readline().split())
isa = lambda: stdin.readline().split()
r1, r2 = iia()
c1, c2 = iia()
d1, d2 = iia()
if (c2 + r2 - d2) % 2 == 0:
d = (c2 + r2 - d2) // 2
c = r2 - d
b = c2 - d
a = r1 -... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,682,765,349 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 483 | 0 | n=int(input())
a=list(map(int,input().split()))
b=[]
if a.count(1)<0 or a.count(2)<0 or a.count(3)<0:
print(0)
exit()
q=(min(a.count(1), a.count(2), a.count(3)))
print(q)
for i in range(q):
w=[a.index(1)+1, a.index(2)+1, a.index(3)+1]
z=a.index(1)
x=a.index(2)
c=a.index(3)
b.app... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n=int(input())
a=list(map(int,input().split()))
b=[]
if a.count(1)<0 or a.count(2)<0 or a.count(3)<0:
print(0)
exit()
q=(min(a.count(1), a.count(2), a.count(3)))
print(q)
for i in range(q):
w=[a.index(1)+1, a.index(2)+1, a.index(3)+1]
z=a.index(1)
x=a.index(2)
c=a.index(3)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
222 | B | Cosmic Tables | PROGRAMMING | 1,300 | [
"data structures",
"implementation"
] | null | null | The Free Meteor Association (FMA) has got a problem: as meteors are moving, the Universal Cosmic Descriptive Humorous Program (UCDHP) needs to add a special module that would analyze this movement.
UCDHP stores some secret information about meteors as an *n*<=×<=*m* table with integers in its cells. The order of mete... | The first line contains three space-separated integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=1000, 1<=≤<=*k*<=≤<=500000) — the number of table columns and rows and the number of queries, correspondingly.
Next *n* lines contain *m* space-separated numbers each — the initial state of the table. Each number *p* in the ta... | For each query to obtain a number (*s**i* = "g") print the required number. Print the answers to the queries in the order of the queries in the input. | [
"3 3 5\n1 2 3\n4 5 6\n7 8 9\ng 3 2\nr 3 2\nc 2 3\ng 2 2\ng 3 2\n",
"2 3 3\n1 2 4\n3 1 5\nc 2 1\nr 1 2\ng 1 3\n"
] | [
"8\n9\n6\n",
"5\n"
] | Let's see how the table changes in the second test case.
After the first operation is fulfilled, the table looks like that:
2 1 4
1 3 5
After the second operation is fulfilled, the table looks like that:
1 3 5
2 1 4
So the answer to the third query (the number located in the first row and in the third column) wi... | 1,000 | [
{
"input": "3 3 5\n1 2 3\n4 5 6\n7 8 9\ng 3 2\nr 3 2\nc 2 3\ng 2 2\ng 3 2",
"output": "8\n9\n6"
},
{
"input": "2 3 3\n1 2 4\n3 1 5\nc 2 1\nr 1 2\ng 1 3",
"output": "5"
},
{
"input": "1 1 15\n1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1 1\ng 1... | 1,626,367,707 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 3,000 | 28,876,800 | n, m, k = map(int, input().split())
grid = []
for _ in range(n):
grid.append(list(map(int, input().split())))
col = {i: i-1 for i in range(1,m+1)}
row = {i: i-1 for i in range(1,n+1)}
for _ in range(k):
q, x,y = input().split()
if q == "g":
print(grid[row[int(x)]][col[int(y)]])
elif q... | Title: Cosmic Tables
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Free Meteor Association (FMA) has got a problem: as meteors are moving, the Universal Cosmic Descriptive Humorous Program (UCDHP) needs to add a special module that would analyze this movement.
UCDHP stores some sec... | ```python
n, m, k = map(int, input().split())
grid = []
for _ in range(n):
grid.append(list(map(int, input().split())))
col = {i: i-1 for i in range(1,m+1)}
row = {i: i-1 for i in range(1,n+1)}
for _ in range(k):
q, x,y = input().split()
if q == "g":
print(grid[row[int(x)]][col[int(y)]])
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
777 | B | Game of Credit Cards | PROGRAMMING | 1,300 | [
"data structures",
"dp",
"greedy",
"sortings"
] | null | null | After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simple: each player bring his favourite *n*-digit credit card. Then both players name the digits written on the... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits in the cards Sherlock and Moriarty are going to use.
The second line contains *n* digits — Sherlock's credit card number.
The third line contains *n* digits — Moriarty's credit card number. | First print the minimum possible number of flicks Moriarty will get. Then print the maximum possible number of flicks that Sherlock can get from Moriarty. | [
"3\n123\n321\n",
"2\n88\n00\n"
] | [
"0\n2\n",
"2\n0\n"
] | First sample is elaborated in the problem statement. In the second sample, there is no way Moriarty can avoid getting two flicks. | 1,000 | [
{
"input": "3\n123\n321",
"output": "0\n2"
},
{
"input": "2\n88\n00",
"output": "2\n0"
},
{
"input": "1\n4\n5",
"output": "0\n1"
},
{
"input": "1\n8\n7",
"output": "1\n0"
},
{
"input": "2\n55\n55",
"output": "0\n0"
},
{
"input": "3\n534\n432",
"out... | 1,488,734,543 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 61 | 4,608,000 | n = int(input())
a = list(sorted(input()))
b = list(sorted(input()))
ans1 = ans2 = 0
for i in range(n):
if b[i] >= a[ans1]:
ans1 += 1
if b[i] > a[ans2]:
ans2 += 1
print(n - ans1)
print(ans2) | Title: Game of Credit Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simpl... | ```python
n = int(input())
a = list(sorted(input()))
b = list(sorted(input()))
ans1 = ans2 = 0
for i in range(n):
if b[i] >= a[ans1]:
ans1 += 1
if b[i] > a[ans2]:
ans2 += 1
print(n - ans1)
print(ans2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
355 | A | Vasya and Digital Root | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<... | The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9). | In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes. | [
"4 4\n",
"5 1\n",
"1 0\n"
] | [
"5881\n",
"36172\n",
"0\n"
] | For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | 500 | [
{
"input": "4 4",
"output": "5881"
},
{
"input": "5 1",
"output": "36172"
},
{
"input": "1 0",
"output": "0"
},
{
"input": "8 7",
"output": "49722154"
},
{
"input": "487 0",
"output": "No solution"
},
{
"input": "1000 5",
"output": "854193955406789... | 1,381,789,660 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | k,d=raw_input().split()
k=int(k)
d=int(d)
if d==0:
if k==1:
print 0
else:
print 'No solution'
else:
a = pow(10,k-1)*d
print str(a)
| Title: Vasya and Digital Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=... | ```python
k,d=raw_input().split()
k=int(k)
d=int(d)
if d==0:
if k==1:
print 0
else:
print 'No solution'
else:
a = pow(10,k-1)*d
print str(a)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
13 | A | Numbers | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Numbers | 1 | 64 | Little Petya likes numbers a lot. He found that number 123 in base 16 consists of two digits: the first is 7 and the second is 11. So the sum of digits of 123 in base 16 is equal to 18.
Now he wonders what is an average value of sum of digits of the number *A* written in all bases from 2 to *A*<=-<=1.
Note that all c... | Input contains one integer number *A* (3<=≤<=*A*<=≤<=1000). | Output should contain required average value in format «X/Y», where X is the numerator and Y is the denominator. | [
"5\n",
"3\n"
] | [
"7/3\n",
"2/1\n"
] | In the first sample number 5 written in all bases from 2 to 4 looks so: 101, 12, 11. Sums of digits are 2, 3 and 2, respectively. | 0 | [
{
"input": "5",
"output": "7/3"
},
{
"input": "3",
"output": "2/1"
},
{
"input": "1000",
"output": "90132/499"
},
{
"input": "927",
"output": "155449/925"
},
{
"input": "260",
"output": "6265/129"
},
{
"input": "131",
"output": "3370/129"
},
{
... | 1,650,799,406 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 99 | 124 | 2,150,400 | def sumOfBaseDigits(n, base):
suma = 0
while n:
suma += n%base
n = n//base
return suma
A = int(input())
num = 0
den = A-2
for i in range(2, A):
num += sumOfBaseDigits(A,i)
i = 2
while i < min(num, den):
while num%i == 0 and den%i == 0:
num = num // i
den = den // i... | Title: Numbers
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Little Petya likes numbers a lot. He found that number 123 in base 16 consists of two digits: the first is 7 and the second is 11. So the sum of digits of 123 in base 16 is equal to 18.
Now he wonders what is an average value of su... | ```python
def sumOfBaseDigits(n, base):
suma = 0
while n:
suma += n%base
n = n//base
return suma
A = int(input())
num = 0
den = A-2
for i in range(2, A):
num += sumOfBaseDigits(A,i)
i = 2
while i < min(num, den):
while num%i == 0 and den%i == 0:
num = num // i
den ... | 3.921978 | MatrixStudio/Codeforces-Python-Submissions |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,606,110,954 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 3,000 | 6,758,400 | n=int(input())
a=b=0
l=[int(x) for x in input().split()]
for x in l:
k=[]
for y in l:
if x==y:
continue
k.append(abs(y-x))
print(min(k),max(k)) | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
n=int(input())
a=b=0
l=[int(x) for x in input().split()]
for x in l:
k=[]
for y in l:
if x==y:
continue
k.append(abs(y-x))
print(min(k),max(k))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,678,462,233 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 436 | 4,300,800 | n = int(input())
cnt = 0
board = ''
for i in range(n):
for j in range(n):
if i % 2:
if j % 2:
board += 'C'
cnt += 1
else: board += '.'
else:
if j % 2: board += '.'
else:
board += 'C'
cnt... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
n = int(input())
cnt = 0
board = ''
for i in range(n):
for j in range(n):
if i % 2:
if j % 2:
board += 'C'
cnt += 1
else: board += '.'
else:
if j % 2: board += '.'
else:
board += 'C'
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
933 | C | A Colourful Prospect | PROGRAMMING | 2,700 | [
"geometry",
"graphs"
] | null | null | Firecrackers scare Nian the monster, but they're wayyyyy too noisy! Maybe fireworks make a nice complement.
Little Tommy is watching a firework show. As circular shapes spread across the sky, a splendid view unfolds on the night of Lunar New Year's eve.
A wonder strikes Tommy. How many regions are formed by the circl... | The first line of input contains one integer *n* (1<=≤<=*n*<=≤<=3), denoting the number of circles.
The following *n* lines each contains three space-separated integers *x*, *y* and *r* (<=-<=10<=≤<=*x*,<=*y*<=≤<=10, 1<=≤<=*r*<=≤<=10), describing a circle whose center is (*x*,<=*y*) and the radius is *r*. No two circl... | Print a single integer — the number of regions on the plane. | [
"3\n0 0 1\n2 0 1\n4 0 1\n",
"3\n0 0 2\n3 0 2\n6 0 2\n",
"3\n0 0 2\n2 0 2\n1 1 2\n"
] | [
"4\n",
"6\n",
"8\n"
] | For the first example,
For the second example,
For the third example, | 1,500 | [
{
"input": "3\n0 0 1\n2 0 1\n4 0 1",
"output": "4"
},
{
"input": "3\n0 0 2\n3 0 2\n6 0 2",
"output": "6"
},
{
"input": "3\n0 0 2\n2 0 2\n1 1 2",
"output": "8"
},
{
"input": "1\n0 0 10",
"output": "2"
},
{
"input": "2\n-10 10 1\n10 -10 1",
"output": "3"
},
... | 1,568,720,211 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 561 | 512,000 | import random
n = int(input())
a = [tuple(map(int, input().split())) for _ in range(n)]
def inside(x, y, r, x1, y1):
return (x - x1) ** 2 + (y - y1) ** 2 <= r * r
s = set()
for _ in range(10 ** 5):
x1, y1 = random.uniform(-25, 25), random.uniform(-25, 25)
s.add(tuple(inside(x, y, r, x1, y1) fo... | Title: A Colourful Prospect
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Firecrackers scare Nian the monster, but they're wayyyyy too noisy! Maybe fireworks make a nice complement.
Little Tommy is watching a firework show. As circular shapes spread across the sky, a splendid view unfol... | ```python
import random
n = int(input())
a = [tuple(map(int, input().split())) for _ in range(n)]
def inside(x, y, r, x1, y1):
return (x - x1) ** 2 + (y - y1) ** 2 <= r * r
s = set()
for _ in range(10 ** 5):
x1, y1 = random.uniform(-25, 25), random.uniform(-25, 25)
s.add(tuple(inside(x, y, r, ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
281 | A | Word Capitalization | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged. | A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103. | Output the given word after capitalization. | [
"ApPLe\n",
"konjac\n"
] | [
"ApPLe\n",
"Konjac\n"
] | none | 500 | [
{
"input": "ApPLe",
"output": "ApPLe"
},
{
"input": "konjac",
"output": "Konjac"
},
{
"input": "a",
"output": "A"
},
{
"input": "A",
"output": "A"
},
{
"input": "z",
"output": "Z"
},
{
"input": "ABACABA",
"output": "ABACABA"
},
{
"input": "... | 1,697,083,215 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | #Word Capitalization problem on codeforces.com
word = input()
word_out = word[0].upper() + word[1:]
print(word_out)
| Title: Word Capitalization
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input... | ```python
#Word Capitalization problem on codeforces.com
word = input()
word_out = word[0].upper() + word[1:]
print(word_out)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
667 | A | Pouring Rain | PROGRAMMING | 1,100 | [
"geometry",
"math"
] | null | null | A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.
Today everything ... | The only line of the input contains four integer numbers *d*,<=*h*,<=*v*,<=*e* (1<=≤<=*d*,<=*h*,<=*v*,<=*e*<=≤<=104), where:
- *d* — the diameter of your cylindrical cup, - *h* — the initial level of water in the cup, - *v* — the speed of drinking process from the cup in milliliters per second, - *e* — the growth ... | If it is impossible to make the cup empty, print "NO" (without quotes).
Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=4. It is... | [
"1 2 3 100\n",
"1 1 1 1\n"
] | [
"NO\n",
"YES\n3.659792366325\n"
] | In the first example the water fills the cup faster than you can drink from it.
In the second example area of the cup's bottom equals to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/419dc74dcd7bc392019c9fe748fe1fdb08ab521a.png" style="max-width: 100.0%;max-height: 100.0%;"/>, thus we ca... | 500 | [
{
"input": "1 2 3 100",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "YES\n3.659792366325"
},
{
"input": "48 7946 7992 72",
"output": "NO"
},
{
"input": "72 6791 8546 46",
"output": "NO"
},
{
"input": "100 5635 9099 23",
"output": "NO"
},
{
"input... | 1,624,288,003 | 1,303 | Python 3 | OK | TESTS | 23 | 62 | 0 | import math
pi=math.pi
d,h,v,e=map(int,input().split())
d=d/2
gr=pi*d*d*e
if gr>v:
print("NO")
else:
dec=v-gr
print("YES")
tot=pi*d*d*h
print(tot/dec)
| Title: Pouring Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, cont... | ```python
import math
pi=math.pi
d,h,v,e=map(int,input().split())
d=d/2
gr=pi*d*d*e
if gr>v:
print("NO")
else:
dec=v-gr
print("YES")
tot=pi*d*d*h
print(tot/dec)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works... | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,693,638,490 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | m=int(input())
a=[m]+list(range(1,m))
a=" ".join(a)
print(a) | Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the perm... | ```python
m=int(input())
a=[m]+list(range(1,m))
a=" ".join(a)
print(a)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
99 | B | Help Chef Gerasim | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | B. Help Chef Gerasim | 0 | 256 | In a far away kingdom young pages help to set the table for the King. As they are terribly mischievous, one needs to keep an eye on the control whether they have set everything correctly. This time the royal chef Gerasim had the impression that the pages have played a prank again: they had poured the juice from one cup... | The first line contains integer *n* — the number of cups on the royal table (1<=≤<=*n*<=≤<=1000). Next *n* lines contain volumes of juice in each cup — non-negative integers, not exceeding 104. | If the pages didn't pour the juice, print "Exemplary pages." (without the quotes). If you can determine the volume of juice poured during exactly one juice pouring, print "*v* ml. from cup #*a* to cup #*b*." (without the quotes), where *v* represents the volume of poured juice, *a* represents the number of the cup from... | [
"5\n270\n250\n250\n230\n250\n",
"5\n250\n250\n250\n250\n250\n",
"5\n270\n250\n249\n230\n250\n"
] | [
"20 ml. from cup #4 to cup #1.\n",
"Exemplary pages.\n",
"Unrecoverable configuration.\n"
] | none | 1,000 | [
{
"input": "5\n270\n250\n250\n230\n250",
"output": "20 ml. from cup #4 to cup #1."
},
{
"input": "5\n250\n250\n250\n250\n250",
"output": "Exemplary pages."
},
{
"input": "5\n270\n250\n249\n230\n250",
"output": "Unrecoverable configuration."
},
{
"input": "4\n200\n190\n210\n20... | 1,626,259,270 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 109 | 20,172,800 | n = int(input())
X = [int(input()) for i in range(n)]
if n == 1:
print('Exemplary pages.')
exit()
if n == 2:
if X[0] == X[1]:
print('Exemplary pages.')
else:
if (X[0]+X[1])%2 == 0:
x = (X[0]+X[1])//2-min(X)
x = str(x)
if X[0] > X[1]:
... | Title: Help Chef Gerasim
Time Limit: 0 seconds
Memory Limit: 256 megabytes
Problem Description:
In a far away kingdom young pages help to set the table for the King. As they are terribly mischievous, one needs to keep an eye on the control whether they have set everything correctly. This time the royal chef Gerasim ... | ```python
n = int(input())
X = [int(input()) for i in range(n)]
if n == 1:
print('Exemplary pages.')
exit()
if n == 2:
if X[0] == X[1]:
print('Exemplary pages.')
else:
if (X[0]+X[1])%2 == 0:
x = (X[0]+X[1])//2-min(X)
x = str(x)
if X[0]... | 0 | MatrixStudio/Codeforces-Python-Submissions |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,692,908,562 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 374 | 13,516,800 |
n_testcases = int(input())
cities = [int(x) for x in input().split(' ')]
n = len(cities)
for i, city in enumerate(cities):
# if i == 0:
# pass
# elif i == n-1:
# pass
max_cost = max(abs(city-cities[0]), abs(city-cities[n-1]))
li = (i - 1) % n
ri = (i + 1) % n
min_cost = min(ab... | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
n_testcases = int(input())
cities = [int(x) for x in input().split(' ')]
n = len(cities)
for i, city in enumerate(cities):
# if i == 0:
# pass
# elif i == n-1:
# pass
max_cost = max(abs(city-cities[0]), abs(city-cities[n-1]))
li = (i - 1) % n
ri = (i + 1) % n
min_cos... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,488,373,654 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 4,505,600 | m,d=map(int,input().split())
if m==2:
ans=4+[0,1][d!=1]
elif m in [4,6,9,11]:
ans=5+[0,1][d>6]
else:
ans=5+[0,1][d>5] | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
m,d=map(int,input().split())
if m==2:
ans=4+[0,1][d!=1]
elif m in [4,6,9,11]:
ans=5+[0,1][d>6]
else:
ans=5+[0,1][d>5]
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
747 | B | Mammoth's Genome Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, *s... | The first line contains the integer *n* (4<=≤<=*n*<=≤<=255) — the length of the genome.
The second line contains the string *s* of length *n* — the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'. | If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes). | [
"8\nAG?C??CT\n",
"4\nAGCT\n",
"6\n????G?\n",
"4\nAA??\n"
] | [
"AGACGTCT\n",
"AGCT\n",
"===\n",
"===\n"
] | In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is ... | 1,000 | [
{
"input": "8\nAG?C??CT",
"output": "AGACGTCT"
},
{
"input": "4\nAGCT",
"output": "AGCT"
},
{
"input": "6\n????G?",
"output": "==="
},
{
"input": "4\nAA??",
"output": "==="
},
{
"input": "4\n????",
"output": "ACGT"
},
{
"input": "252\n???????GCG??T??TT... | 1,486,067,217 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | letters = set('Bulbasaur')
string = input()
counts = []
for i in letters:
if i in ['a', 'u']:
counts.append(string.count(i)//2)
else:
counts.append(string.count(i))
print(min(counts))letters = set('Bulbasaur')
string = input()
counts = []
for i in letters:
if i in ['a', 'u']:
counts.append(stri... | Title: Mammoth's Genome Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter... | ```python
letters = set('Bulbasaur')
string = input()
counts = []
for i in letters:
if i in ['a', 'u']:
counts.append(string.count(i)//2)
else:
counts.append(string.count(i))
print(min(counts))letters = set('Bulbasaur')
string = input()
counts = []
for i in letters:
if i in ['a', 'u']:
counts.a... | -1 | MatrixStudio/Codeforces-Python-Submissions |
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