contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
612 | C | Replace To Make Regular Bracket Sequence | PROGRAMMING | 1,400 | [
"data structures",
"expression parsing",
"math"
] | null | null | You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another of the same type. For example, you can replace < by the bracket {, but you can't replace it by ) or >.
The following d... | The only line contains a non empty string *s*, consisting of only opening and closing brackets of four kinds. The length of *s* does not exceed 106. | If it's impossible to get RBS from *s* print Impossible.
Otherwise print the least number of replaces needed to get RBS from *s*. | [
"[<}){}\n",
"{()}[]\n",
"]]\n"
] | [
"2",
"0",
"Impossible"
] | none | 0 | [
{
"input": "[<}){}",
"output": "2"
},
{
"input": "{()}[]",
"output": "0"
},
{
"input": "]]",
"output": "Impossible"
},
{
"input": ">",
"output": "Impossible"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{}",
"output": "0"
},
{
"input": ... | 1,472,742,031 | 1,531 | Python 3 | OK | TESTS | 52 | 561 | 10,649,600 | s = input()
open = {'(', '{', '[', '<'}
res = 0
our = []
for elem in s:
if elem in open:
our.append(elem)
else:
if our:
res += (abs(ord(elem) - ord(our[-1])) > 2)
our.pop()
else:
print('Impossible')
exit()
if our:
print('Impossible')
el... | Title: Replace To Make Regular Bracket Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given string *s* consists of opening and closing brackets of four kinds <>, {}, [], (). There are two types of brackets: opening and closing. You can replace any bracket by another... | ```python
s = input()
open = {'(', '{', '[', '<'}
res = 0
our = []
for elem in s:
if elem in open:
our.append(elem)
else:
if our:
res += (abs(ord(elem) - ord(our[-1])) > 2)
our.pop()
else:
print('Impossible')
exit()
if our:
print('Impos... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,480,523,856 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n=int(input())
l=[int(i) for i in input().split()]
a=1
s=sum(l)
while 2**(a)<n:
s=s+sum(l)
if len(l)%(2**a)==0:
s=s+sum(l)
elif len(l)%(2**a)!=0:
k=l[:]
for i in range(len(l)%(2**a)):
k.remove(min(k))
s=s+sum(k)
a=a+1
print(s) | Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
n=int(input())
l=[int(i) for i in input().split()]
a=1
s=sum(l)
while 2**(a)<n:
s=s+sum(l)
if len(l)%(2**a)==0:
s=s+sum(l)
elif len(l)%(2**a)!=0:
k=l[:]
for i in range(len(l)%(2**a)):
k.remove(min(k))
s=s+sum(k)
a=a+1
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
699 | A | Launch of Collider | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be two or more particles located in the same point. The coordinates of the particles coincide with the dis... | The first line contains the positive integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of particles.
The second line contains *n* symbols "L" and "R". If the *i*-th symbol equals "L", then the *i*-th particle will move to the left, otherwise the *i*-th symbol equals "R" and the *i*-th particle will move to the right.... | In the first line print the only integer — the first moment (in microseconds) when two particles are at the same point and there will be an explosion.
Print the only integer -1, if the collision of particles doesn't happen. | [
"4\nRLRL\n2 4 6 10\n",
"3\nLLR\n40 50 60\n"
] | [
"1\n",
"-1\n"
] | In the first sample case the first explosion will happen in 1 microsecond because the particles number 1 and 2 will simultaneously be at the same point with the coordinate 3.
In the second sample case there will be no explosion because there are no particles which will simultaneously be at the same point. | 500 | [
{
"input": "4\nRLRL\n2 4 6 10",
"output": "1"
},
{
"input": "3\nLLR\n40 50 60",
"output": "-1"
},
{
"input": "4\nRLLR\n46 230 264 470",
"output": "92"
},
{
"input": "6\nLLRLLL\n446 492 650 844 930 970",
"output": "97"
},
{
"input": "8\nRRLLLLLL\n338 478 512 574 59... | 1,470,415,592 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 22,835,200 | from sys import stdin, stdout
n = int(stdin.readline())
route = stdin.readline().split()
coordinates = stdin.readline().split()
ans = float('inf')
coordinate = -1
for i in range(n):
if route[i] == 'R':
coordinate = coordinates[i]
elif coordinate != -1 and route[i] == 'L':
ans = min((co... | Title: Launch of Collider
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There will be a launch of a new, powerful and unusual collider very soon, which located along a straight line. *n* particles will be launched inside it. All of them are located in a straight line and there can not be... | ```python
from sys import stdin, stdout
n = int(stdin.readline())
route = stdin.readline().split()
coordinates = stdin.readline().split()
ans = float('inf')
coordinate = -1
for i in range(n):
if route[i] == 'R':
coordinate = coordinates[i]
elif coordinate != -1 and route[i] == 'L':
ans... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,692,441,037 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 124 | 0 | dumbs = input()
input_line = input()
input_components = input_line.split()
list = []
for _ in input_components :
list.append(int(_))
max_temp = list[0]
min_temp = list[0]
count = 0
for i in list :
if i > max_temp :
max_temp = i
count += 1
if i < min_temp:
min_temp... | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
dumbs = input()
input_line = input()
input_components = input_line.split()
list = []
for _ in input_components :
list.append(int(_))
max_temp = list[0]
min_temp = list[0]
count = 0
for i in list :
if i > max_temp :
max_temp = i
count += 1
if i < min_temp:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,697,467,750 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | vowels = ['A','O','E','I','U','Y']
def process(c: chr) -> str:
if c.upper() in vowels:
return ''
return "." + c.lower()
ss = input()
res = ''.join(process(c) for c in ss)
print(res) | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
vowels = ['A','O','E','I','U','Y']
def process(c: chr) -> str:
if c.upper() in vowels:
return ''
return "." + c.lower()
ss = input()
res = ''.join(process(c) for c in ss)
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,599,751,258 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 109 | 0 | first = input()
second = input()
answer = []
for f, s in zip(first, second):
if f != s:
answer.append('1')
else:
answer.append('0')
for i in answer:
print(i, end='')
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
first = input()
second = input()
answer = []
for f, s in zip(first, second):
if f != s:
answer.append('1')
else:
answer.append('0')
for i in answer:
print(i, end='')
``` | 3.97275 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,657,369,672 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 0 | string= str(input())
F={"UPPER_CASE":0, "LOWER_CASE":0}
for s in string:
if s.isupper():
F["UPPER_CASE"]+=1
elif s.islower():
F["LOWER_CASE"]+=1
else:
pass
l=len(string)
if(F["UPPER_CASE"]>l/2):
print(string.upper())
else:
print(string.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
string= str(input())
F={"UPPER_CASE":0, "LOWER_CASE":0}
for s in string:
if s.isupper():
F["UPPER_CASE"]+=1
elif s.islower():
F["LOWER_CASE"]+=1
else:
pass
l=len(string)
if(F["UPPER_CASE"]>l/2):
print(string.upper())
else:
print(string.lower())
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
608 | A | Saitama Destroys Hotel | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only move down, and has infinite capacity. Floors are numbered from 0 to *s* and elevator initially starts on floor... | The first line of input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=100, 1<=≤<=*s*<=≤<=1000) — the number of passengers and the number of the top floor respectively.
The next *n* lines each contain two space-separated integers *f**i* and *t**i* (1<=≤<=*f**i*<=≤<=*s*, 1<=≤<=*t**i*<=≤<=1000) — the floor and the tim... | Print a single integer — the minimum amount of time in seconds needed to bring all the passengers to floor 0. | [
"3 7\n2 1\n3 8\n5 2\n",
"5 10\n2 77\n3 33\n8 21\n9 12\n10 64\n"
] | [
"11\n",
"79\n"
] | In the first sample, it takes at least 11 seconds to bring all passengers to floor 0. Here is how this could be done:
1. Move to floor 5: takes 2 seconds.
2. Pick up passenger 3.
3. Move to floor 3: takes 2 seconds.
4. Wait for passenger 2 to arrive: takes 4 seconds.
5. Pick up passenger 2.
6. Go to floor 2: take... | 500 | [
{
"input": "3 7\n2 1\n3 8\n5 2",
"output": "11"
},
{
"input": "5 10\n2 77\n3 33\n8 21\n9 12\n10 64",
"output": "79"
},
{
"input": "1 1000\n1000 1000",
"output": "2000"
},
{
"input": "1 1\n1 1",
"output": "2"
},
{
"input": "1 1000\n1 1",
"output": "1000"
},
... | 1,615,228,036 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 307,200 | a,b=map(int,input().split())
floort=[]
time=[];tot=[];ans1=0;ans2=0
for m in range(a):
c,d=map(int,input().split())
floort.append(c)
time.append(d)
floort.append(b)
so=sorted(floort)
for s in sorted(range(1,len(so)),reverse=True):
m=floort[s]-floort[s-1]
tot.append(m)
ans1=abs(sum(tot))
... | Title: Saitama Destroys Hotel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only mo... | ```python
a,b=map(int,input().split())
floort=[]
time=[];tot=[];ans1=0;ans2=0
for m in range(a):
c,d=map(int,input().split())
floort.append(c)
time.append(d)
floort.append(b)
so=sorted(floort)
for s in sorted(range(1,len(so)),reverse=True):
m=floort[s]-floort[s-1]
tot.append(m)
ans1=abs(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
701 | C | They Are Everywhere | PROGRAMMING | 1,500 | [
"binary search",
"strings",
"two pointers"
] | null | null | Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is ... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*. | Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house. | [
"3\nAaA\n",
"7\nbcAAcbc\n",
"6\naaBCCe\n"
] | [
"2\n",
"3\n",
"5\n"
] | In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | 1,000 | [
{
"input": "3\nAaA",
"output": "2"
},
{
"input": "7\nbcAAcbc",
"output": "3"
},
{
"input": "6\naaBCCe",
"output": "5"
},
{
"input": "1\nA",
"output": "1"
},
{
"input": "1\ng",
"output": "1"
},
{
"input": "52\nabcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQ... | 1,600,851,846 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | n,s=int(input()),input()
dis = len(set(s))
mp = {}
l,r,m,cnt=0,0,99999999,0
for c in s:
if c not in mp:
mp[c]=0
cnt+=1
mp[c]+=1
print(cnt)
if cnt == dis:
while mp[s[l]]>1:
mp[s[l]]-=1
l+=1
m = min(m,r-l+1)
r+=1
print(m)
| Title: They Are Everywhere
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each ... | ```python
n,s=int(input()),input()
dis = len(set(s))
mp = {}
l,r,m,cnt=0,0,99999999,0
for c in s:
if c not in mp:
mp[c]=0
cnt+=1
mp[c]+=1
print(cnt)
if cnt == dis:
while mp[s[l]]>1:
mp[s[l]]-=1
l+=1
m = min(m,r-l+1)
r+=1
prin... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,642,254,955 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 46 | 0 | s1=input()
s2=input()
list1=list(s1)
list2=list(s2)
for i in range(len(s1)):
if(list1[i]==list2[i]):
list1[i]='0'
else:
list1[i]='1'
for i in range(len(s1)):
print(list1[i],end='')
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
s1=input()
s2=input()
list1=list(s1)
list2=list(s2)
for i in range(len(s1)):
if(list1[i]==list2[i]):
list1[i]='0'
else:
list1[i]='1'
for i in range(len(s1)):
print(list1[i],end='')
``` | 3.9885 | MatrixStudio/Codeforces-Python-Submissions |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,685,021,673 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | x=list(map(int,input().split()))
con = 1
while True:
if (x[0]*con)%10==x[1] or (x[0]*con)%10==0:
print(con)
break
else:
con+=1 | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
x=list(map(int,input().split()))
con = 1
while True:
if (x[0]*con)%10==x[1] or (x[0]*con)%10==0:
print(con)
break
else:
con+=1
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,594,123,690 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 248 | 20,172,800 | n=int(input())
s=0
while(n > 0 or s>9):
if(n == 0):
n = s
s = 0
s += n % 10
n //= 10
print(s) | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
n=int(input())
s=0
while(n > 0 or s>9):
if(n == 0):
n = s
s = 0
s += n % 10
n //= 10
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,696,438,878 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | user_set = input()
user_set = user_set[1:-1]
user_set = user_set.split(",")
letters_arr = []
for let in user_set:
letters_arr.append(let.strip())
unique_arr = set(letters_arr)
print(len(unique_arr))
| Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
user_set = input()
user_set = user_set[1:-1]
user_set = user_set.split(",")
letters_arr = []
for let in user_set:
letters_arr.append(let.strip())
unique_arr = set(letters_arr)
print(len(unique_arr))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
377 | C | Captains Mode | PROGRAMMING | 2,200 | [
"bitmasks",
"dp",
"games"
] | null | null | Kostya is a progamer specializing in the discipline of Dota 2. Valve Corporation, the developer of this game, has recently released a new patch which turned the balance of the game upside down. Kostya, as the captain of the team, realizes that the greatest responsibility lies on him, so he wants to resort to the analys... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=100) — the number of heroes in Dota 2.
The second line contains *n* integers *s*1, *s*2, ..., *s**n* (1<=≤<=*s**i*<=≤<=106) — the strengths of all the heroes.
The third line contains a single integer *m* (2<=≤<=*m*<=≤<=*min*(*n*,<=20)) — the number of action... | Print a single integer — the difference between the strength of the first team and the strength of the second team if the captains of both teams will act optimally well. | [
"2\n2 1\n2\np 1\np 2\n",
"6\n6 4 5 4 5 5\n4\nb 2\np 1\nb 1\np 2\n",
"4\n1 2 3 4\n4\np 2\nb 2\np 1\nb 1\n"
] | [
"1\n",
"0\n",
"-2\n"
] | none | 1,000 | [
{
"input": "2\n2 1\n2\np 1\np 2",
"output": "1"
},
{
"input": "6\n6 4 5 4 5 5\n4\nb 2\np 1\nb 1\np 2",
"output": "0"
},
{
"input": "4\n1 2 3 4\n4\np 2\nb 2\np 1\nb 1",
"output": "-2"
},
{
"input": "4\n1 2 3 5\n4\nb 2\np 1\np 2\nb 1",
"output": "1"
},
{
"input": "6... | 1,678,761,412 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 11 | 46 | 0 | import sys
#input functions
readint = lambda: int(sys.stdin.readline())
readints = lambda: map(int,sys.stdin.readline().split())
readar = lambda: list(map(int,sys.stdin.readline().split()))
flush = lambda: sys.stdout.flush()
n = readint()
ar = readar()
ar.sort()
x = readint()
a,b = input().split()
t = int(b)
pick,ban... | Title: Captains Mode
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kostya is a progamer specializing in the discipline of Dota 2. Valve Corporation, the developer of this game, has recently released a new patch which turned the balance of the game upside down. Kostya, as the captain of t... | ```python
import sys
#input functions
readint = lambda: int(sys.stdin.readline())
readints = lambda: map(int,sys.stdin.readline().split())
readar = lambda: list(map(int,sys.stdin.readline().split()))
flush = lambda: sys.stdout.flush()
n = readint()
ar = readar()
ar.sort()
x = readint()
a,b = input().split()
t = int(b... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
508 | B | Anton and currency you all know | PROGRAMMING | 1,300 | [
"greedy",
"math",
"strings"
] | null | null | Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of... | The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes. | If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained fro... | [
"527\n",
"4573\n",
"1357997531\n"
] | [
"572\n",
"3574\n",
"-1\n"
] | none | 1,000 | [
{
"input": "527",
"output": "572"
},
{
"input": "4573",
"output": "3574"
},
{
"input": "1357997531",
"output": "-1"
},
{
"input": "444443",
"output": "444434"
},
{
"input": "22227",
"output": "72222"
},
{
"input": "24683",
"output": "34682"
},
... | 1,635,271,273 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 186 | 13,926,400 | n = str(input())
n = [x for x in n]
even = {}
for i in range(len(n)):
if int(n[i]) % 2 == 0:
even[i] = int(n[i])
if not even:
print(-1)
exit()
el = list(even.items())
max_el = (0, 0)
for i in el:
if i[1] > max_el[1]:
max_el = i
j = 0
for key, value in even.items():... | Title: Anton and currency you all know
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed... | ```python
n = str(input())
n = [x for x in n]
even = {}
for i in range(len(n)):
if int(n[i]) % 2 == 0:
even[i] = int(n[i])
if not even:
print(-1)
exit()
el = list(even.items())
max_el = (0, 0)
for i in el:
if i[1] > max_el[1]:
max_el = i
j = 0
for key, value in eve... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
772 | A | Voltage Keepsake | PROGRAMMING | 1,800 | [
"binary search",
"math"
] | null | null | You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-th device currently has *b**i* units of power stored. All devices can store an arbitrary amount of pow... | The first line contains two integers, *n* and *p* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*p*<=≤<=109) — the number of devices and the power of the charger.
This is followed by *n* lines which contain two integers each. Line *i* contains the integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=100<=000) — the power of the dev... | If you can use the devices indefinitely, print -1. Otherwise, print the maximum amount of time before any one device hits 0 power.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=4.
Namely, let's assume that your answer is *a* and the answer of the jury is *b*. The chec... | [
"2 1\n2 2\n2 1000\n",
"1 100\n1 1\n",
"3 5\n4 3\n5 2\n6 1\n"
] | [
"2.0000000000",
"-1\n",
"0.5000000000"
] | In sample test 1, you can charge the first device for the entire time until it hits zero power. The second device has enough power to last this time without being charged.
In sample test 2, you can use the device indefinitely.
In sample test 3, we can charge the third device for 2 / 5 of a second, then switch to char... | 500 | [
{
"input": "2 1\n2 2\n2 1000",
"output": "2.0000000000"
},
{
"input": "1 100\n1 1",
"output": "-1"
},
{
"input": "3 5\n4 3\n5 2\n6 1",
"output": "0.5000000000"
},
{
"input": "1 1\n1 87",
"output": "-1"
},
{
"input": "1 1\n100 77",
"output": "0.7777777778"
},... | 1,696,441,688 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 11,776,000 | import sys
from decimal import Decimal
def main():
n, p = map(int, input().split())
arr = []
for _ in range(n):
a, b = map(int, input().split())
arr.append((a, b))
lo = Decimal(0)
hi = Decimal(1e10)
epsilon = Decimal('0.00001')
while hi - lo >= epsilon:
mid... | Title: Voltage Keepsake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *n* devices that you want to use simultaneously.
The *i*-th device uses *a**i* units of power per second. This usage is continuous. That is, in λ seconds, the device will use λ·*a**i* units of power. The *i*-... | ```python
import sys
from decimal import Decimal
def main():
n, p = map(int, input().split())
arr = []
for _ in range(n):
a, b = map(int, input().split())
arr.append((a, b))
lo = Decimal(0)
hi = Decimal(1e10)
epsilon = Decimal('0.00001')
while hi - lo >= epsilon:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
792 | B | Counting-out Rhyme | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | *n* children are standing in a circle and playing the counting-out game. Children are numbered clockwise from 1 to *n*. In the beginning, the first child is considered the leader. The game is played in *k* steps. In the *i*-th step the leader counts out *a**i* people in clockwise order, starting from the next person. T... | The first line contains two integer numbers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1).
The next line contains *k* integer numbers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=109). | Print *k* numbers, the *i*-th one corresponds to the number of child to be eliminated at the *i*-th step. | [
"7 5\n10 4 11 4 1\n",
"3 2\n2 5\n"
] | [
"4 2 5 6 1 \n",
"3 2 \n"
] | Let's consider first example:
- In the first step child 4 is eliminated, child 5 becomes the leader. - In the second step child 2 is eliminated, child 3 becomes the leader. - In the third step child 5 is eliminated, child 6 becomes the leader. - In the fourth step child 6 is eliminated, child 7 becomes the leader... | 0 | [
{
"input": "7 5\n10 4 11 4 1",
"output": "4 2 5 6 1 "
},
{
"input": "3 2\n2 5",
"output": "3 2 "
},
{
"input": "2 1\n1",
"output": "2 "
},
{
"input": "2 1\n2",
"output": "1 "
},
{
"input": "2 1\n3",
"output": "2 "
},
{
"input": "10 7\n5 10 4 3 8 10 6",... | 1,689,427,250 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689427250.6612241")# 1689427250.6612434 | Title: Counting-out Rhyme
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* children are standing in a circle and playing the counting-out game. Children are numbered clockwise from 1 to *n*. In the beginning, the first child is considered the leader. The game is played in *k* steps. In ... | ```python
print("_RANDOM_GUESS_1689427250.6612241")# 1689427250.6612434
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
996 | A | Hit the Lottery | PROGRAMMING | 800 | [
"dp",
"greedy"
] | null | null | Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$. What is the minimum number of bills Allen could receive after withdrawing his entire balance? | The first and only line of input contains a single integer $n$ ($1 \le n \le 10^9$). | Output the minimum number of bills that Allen could receive. | [
"125\n",
"43\n",
"1000000000\n"
] | [
"3\n",
"5\n",
"10000000\n"
] | In the first sample case, Allen can withdraw this with a $100$ dollar bill, a $20$ dollar bill, and a $5$ dollar bill. There is no way for Allen to receive $125$ dollars in one or two bills.
In the second sample case, Allen can withdraw two $20$ dollar bills and three $1$ dollar bills.
In the third sample case, Allen... | 500 | [
{
"input": "125",
"output": "3"
},
{
"input": "43",
"output": "5"
},
{
"input": "1000000000",
"output": "10000000"
},
{
"input": "4",
"output": "4"
},
{
"input": "5",
"output": "1"
},
{
"input": "1",
"output": "1"
},
{
"input": "74",
"o... | 1,698,600,912 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 810 | 0 | def dr(n):
counter = 0
while n > 0:
if n >= 100:
counter += 1
n -= 100
elif n >= 20:
counter += 1
n -= 20
elif n >= 10:
counter += 1
n -= 10
elif n >= 5:
counter += 1
n -... | Title: Hit the Lottery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Allen has a LOT of money. He has $n$ dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are $1$, $5$, $10$, $20$, $100$... | ```python
def dr(n):
counter = 0
while n > 0:
if n >= 100:
counter += 1
n -= 100
elif n >= 20:
counter += 1
n -= 20
elif n >= 10:
counter += 1
n -= 10
elif n >= 5:
counter += 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
667 | A | Pouring Rain | PROGRAMMING | 1,100 | [
"geometry",
"math"
] | null | null | A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, contemplate all around you, enjoy freshness, think about big deeds you have to do.
Today everything ... | The only line of the input contains four integer numbers *d*,<=*h*,<=*v*,<=*e* (1<=≤<=*d*,<=*h*,<=*v*,<=*e*<=≤<=104), where:
- *d* — the diameter of your cylindrical cup, - *h* — the initial level of water in the cup, - *v* — the speed of drinking process from the cup in milliliters per second, - *e* — the growth ... | If it is impossible to make the cup empty, print "NO" (without quotes).
Otherwise print "YES" (without quotes) in the first line. In the second line print a real number — time in seconds needed the cup will be empty. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=-<=4. It is... | [
"1 2 3 100\n",
"1 1 1 1\n"
] | [
"NO\n",
"YES\n3.659792366325\n"
] | In the first example the water fills the cup faster than you can drink from it.
In the second example area of the cup's bottom equals to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/419dc74dcd7bc392019c9fe748fe1fdb08ab521a.png" style="max-width: 100.0%;max-height: 100.0%;"/>, thus we ca... | 500 | [
{
"input": "1 2 3 100",
"output": "NO"
},
{
"input": "1 1 1 1",
"output": "YES\n3.659792366325"
},
{
"input": "48 7946 7992 72",
"output": "NO"
},
{
"input": "72 6791 8546 46",
"output": "NO"
},
{
"input": "100 5635 9099 23",
"output": "NO"
},
{
"input... | 1,461,948,345 | 645 | Python 3 | COMPILATION_ERROR | PRETESTS | 0 | 0 | 0 | // {{{
#include <memory.h>
#include <cstdint>
#include <algorithm>
#include <bitset>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <ctime>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#i... | Title: Pouring Rain
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of people in Berland hates rain, but you do not. Rain pacifies, puts your thoughts in order. By these years you have developed a good tradition — when it rains, you go on the street and stay silent for a moment, cont... | ```python
// {{{
#include <memory.h>
#include <cstdint>
#include <algorithm>
#include <bitset>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <ctime>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#includ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
652 | A | Gabriel and Caterpillar | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | The 9-th grade student Gabriel noticed a caterpillar on a tree when walking around in a forest after the classes. The caterpillar was on the height *h*1 cm from the ground. On the height *h*2 cm (*h*2<=><=*h*1) on the same tree hung an apple and the caterpillar was crawling to the apple.
Gabriel is interested when ... | The first line contains two integers *h*1,<=*h*2 (1<=≤<=*h*1<=<<=*h*2<=≤<=105) — the heights of the position of the caterpillar and the apple in centimeters.
The second line contains two integers *a*,<=*b* (1<=≤<=*a*,<=*b*<=≤<=105) — the distance the caterpillar goes up by day and slips down by night, in centimeter... | Print the only integer *k* — the number of days Gabriel should wait to return to the forest and see the caterpillar getting the apple.
If the caterpillar can't get the apple print the only integer <=-<=1. | [
"10 30\n2 1\n",
"10 13\n1 1\n",
"10 19\n1 2\n",
"1 50\n5 4\n"
] | [
"1\n",
"0\n",
"-1\n",
"1\n"
] | In the first example at 10 pm of the first day the caterpillar gets the height 26. At 10 am of the next day it slips down to the height 14. And finally at 6 pm of the same day the caterpillar gets the apple.
Note that in the last example the caterpillar was slipping down under the ground and getting the apple on the n... | 0 | [
{
"input": "10 30\n2 1",
"output": "1"
},
{
"input": "10 13\n1 1",
"output": "0"
},
{
"input": "10 19\n1 2",
"output": "-1"
},
{
"input": "1 50\n5 4",
"output": "1"
},
{
"input": "1 1000\n2 1",
"output": "82"
},
{
"input": "999 1000\n1 1",
"output"... | 1,459,210,299 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 62 | 4,608,000 | h1, h2 = map(int, input().split())
a, b = map(int, input().split())
d = 0
r = h1
while(True):
h1 += 8 * a
if h1 >= h2:
print(d)
exit(0)
d += 1
h1 = max(0, h1 - 12 * b) + 4 * a
if d > 1 and h1 <= r:
print("-1")
exit(0) | Title: Gabriel and Caterpillar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The 9-th grade student Gabriel noticed a caterpillar on a tree when walking around in a forest after the classes. The caterpillar was on the height *h*1 cm from the ground. On the height *h*2 cm (*h*2<=><=*h*... | ```python
h1, h2 = map(int, input().split())
a, b = map(int, input().split())
d = 0
r = h1
while(True):
h1 += 8 * a
if h1 >= h2:
print(d)
exit(0)
d += 1
h1 = max(0, h1 - 12 * b) + 4 * a
if d > 1 and h1 <= r:
print("-1")
exit(0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,587,723,974 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 93 | 307,200 | n=int(input())
k=1
l=0
if n>5:
while 5*k<n:
cola=5*k
k=k*2
l=l+1
cal=n-cola
cal2=cal/(k/2)
else:
cal2=n
if cal2<=1:
print('Sheldon')
if 1<cal2<=2:
print('Leonard')
if 2<cal2 <= 3:
print('Penny')
if 3<cal2 <= 4:
print('Rajesh')
if 4< cal2 <... | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
n=int(input())
k=1
l=0
if n>5:
while 5*k<n:
cola=5*k
k=k*2
l=l+1
cal=n-cola
cal2=cal/(k/2)
else:
cal2=n
if cal2<=1:
print('Sheldon')
if 1<cal2<=2:
print('Leonard')
if 2<cal2 <= 3:
print('Penny')
if 3<cal2 <= 4:
print('Rajesh')
if... | 0 | MatrixStudio/Codeforces-Python-Submissions |
299 | A | Ksusha and Array | PROGRAMMING | 1,000 | [
"brute force",
"number theory",
"sortings"
] | null | null | Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that all array elements are divisible by it. Help her and find the number! | The first line contains integer *n* (1<=≤<=*n*<=≤<=105), showing how many numbers the array has. The next line contains integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the array elements. | Print a single integer — the number from the array, such that all array elements are divisible by it. If such number doesn't exist, print -1.
If there are multiple answers, you are allowed to print any of them. | [
"3\n2 2 4\n",
"5\n2 1 3 1 6\n",
"3\n2 3 5\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 500 | [
{
"input": "3\n2 2 4",
"output": "2"
},
{
"input": "5\n2 1 3 1 6",
"output": "1"
},
{
"input": "3\n2 3 5",
"output": "-1"
},
{
"input": "1\n331358794",
"output": "331358794"
},
{
"input": "5\n506904227 214303304 136194869 838256937 183952885",
"output": "-1"
... | 1,612,158,662 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 307,200 | def gcd(a,b):
if b==0:
return a
else:
return gcd(b,a%b)
n=int(input())
list1=[]
str1=input()
list2=str1.split(" ")
list2_length=len(list2)
i=0
while i<=list2_length-1:
list1.append(int(list2.pop()))
i+=1
list1.reverse()
g=list1[0]
pan=0
for x in range(1,n):
g=gcd(g,... | Title: Ksusha and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ksusha is a beginner coder. Today she starts studying arrays. She has array *a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* positive integers.
Her university teacher gave her a task. Find such number in the array, that ... | ```python
def gcd(a,b):
if b==0:
return a
else:
return gcd(b,a%b)
n=int(input())
list1=[]
str1=input()
list2=str1.split(" ")
list2_length=len(list2)
i=0
while i<=list2_length-1:
list1.append(int(list2.pop()))
i+=1
list1.reverse()
g=list1[0]
pan=0
for x in range(1,n):
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,609,397,266 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 109 | 0 | n = int(input())
x = 0
l = 0
y = 0
for i in range(100):
x += 5*2**i
if (x>=n):
l = i
y = x-n
break
names = ["Howard", "Rajesh", "Penny", "Leonard", "Sheldon"]
print(names[int(y/(2**l))])
| Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
n = int(input())
x = 0
l = 0
y = 0
for i in range(100):
x += 5*2**i
if (x>=n):
l = i
y = x-n
break
names = ["Howard", "Rajesh", "Penny", "Leonard", "Sheldon"]
print(names[int(y/(2**l))])
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,589,999,880 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 307,200 | n=int(input())
arr=input().split()
for i in range(len(arr)):
arr[i]=int(arr[i])
c=1000
l=1000
count=0
for i in range(len(arr)):
if arr[i]%2==0:
count+=1
c=min(c,i)
else :
l=min(l,i)
if count==1:
print(c+1)
else:
print(l+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
arr=input().split()
for i in range(len(arr)):
arr[i]=int(arr[i])
c=1000
l=1000
count=0
for i in range(len(arr)):
if arr[i]%2==0:
count+=1
c=min(c,i)
else :
l=min(l,i)
if count==1:
print(c+1)
else:
print(l+1)
``` | 3.944928 | MatrixStudio/Codeforces-Python-Submissions |
522 | B | Photo to Remember | PROGRAMMING | 1,100 | [
"*special",
"data structures",
"dp",
"implementation"
] | null | null | One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together.
Simply speaking, the process of taking photos can be described as follows. On the photo, each photographed friend occupies a rectangle of pixels: the *i*-th of them occupies the rectangl... | The first line contains integer *n* (2<=≤<=*n*<=≤<=200<=000) — the number of friends.
Then *n* lines follow: the *i*-th line contains information about the *i*-th friend. The line contains a pair of integers *w**i*,<=*h**i* (1<=≤<=*w**i*<=≤<=10,<=1<=≤<=*h**i*<=≤<=1000) — the width and height in pixels of the correspo... | Print *n* space-separated numbers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* — the total number of pixels on the minimum photo containing all friends expect for the *i*-th one. | [
"3\n1 10\n5 5\n10 1\n",
"3\n2 1\n1 2\n2 1\n"
] | [
"75 110 60 ",
"6 4 6 "
] | none | 1,000 | [
{
"input": "3\n1 10\n5 5\n10 1",
"output": "75 110 60 "
},
{
"input": "3\n2 1\n1 2\n2 1",
"output": "6 4 6 "
},
{
"input": "2\n1 5\n2 3",
"output": "6 5 "
},
{
"input": "2\n2 3\n1 1",
"output": "1 6 "
},
{
"input": "3\n1 10\n2 10\n3 10",
"output": "50 40 30 "
... | 1,653,288,742 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n=eval(input())
s=0
for i in range(1,n+1):
s+=len(str(i))
print(s) | Title: Photo to Remember
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together.
Simply speaking, the process of taking photos can be described as follows. On the p... | ```python
n=eval(input())
s=0
for i in range(1,n+1):
s+=len(str(i))
print(s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,519,400,896 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 5,632,000 | n=int(input())
name=list(input())
vowels=['a','e','o','u','y','i']
for i in range(n-1) :
if name[i] in vowels and name[i+1] in vowels :
name[i]='~'
for i in name :
if i!='~' :
print(i,end='')
| Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
n=int(input())
name=list(input())
vowels=['a','e','o','u','y','i']
for i in range(n-1) :
if name[i] in vowels and name[i+1] in vowels :
name[i]='~'
for i in name :
if i!='~' :
print(i,end='')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,653,845,194 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | a,b,n=map(int,input().split())
k=str(a)
a=str(a)
for x in range(0,10):
a+=str(x)
if int(a)%b==0:
break
a=k
if len(str(a))==1:
print(-1)
else:
print(str(a)+'0'*(n-1))
| Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a,b,n=map(int,input().split())
k=str(a)
a=str(a)
for x in range(0,10):
a+=str(x)
if int(a)%b==0:
break
a=k
if len(str(a))==1:
print(-1)
else:
print(str(a)+'0'*(n-1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,692,729,522 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 46 | 0 | from math import log
for i in range(int(input())):
n=int(input())
x=int(log(n,2))
s=(1<<(x+1))
s-=1
s*=2
sum=((n*(n+1))//2)-s
print(sum) | Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, be... | ```python
from math import log
for i in range(int(input())):
n=int(input())
x=int(log(n,2))
s=(1<<(x+1))
s-=1
s*=2
sum=((n*(n+1))//2)-s
print(sum)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,666,803,610 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 154 | 2,048,000 | n, m = map(int, input().split())
a = list(map(int, input().split()))
min_profit = 0
max_profit = 0
free_places = a.copy()
for _ in range(n):
mins = 1001
for i in free_places:
if i < mins and i != 0:
mins = i
min_id = free_places.index(mins)
min_profit += mins
fr... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n, m = map(int, input().split())
a = list(map(int, input().split()))
min_profit = 0
max_profit = 0
free_places = a.copy()
for _ in range(n):
mins = 1001
for i in free_places:
if i < mins and i != 0:
mins = i
min_id = free_places.index(mins)
min_profit += mi... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
554 | A | Kyoya and Photobooks | PROGRAMMING | 900 | [
"brute force",
"math",
"strings"
] | null | null | Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos being duplicated). A photo booklet can be described as a string of lowercase letters, consisting of the pho... | The first line of input will be a single string *s* (1<=≤<=|*s*|<=≤<=20). String *s* consists only of lowercase English letters. | Output a single integer equal to the number of distinct photobooks Kyoya Ootori can make. | [
"a\n",
"hi\n"
] | [
"51\n",
"76\n"
] | In the first case, we can make 'ab','ac',...,'az','ba','ca',...,'za', and 'aa', producing a total of 51 distinct photo booklets. | 250 | [
{
"input": "a",
"output": "51"
},
{
"input": "hi",
"output": "76"
},
{
"input": "y",
"output": "51"
},
{
"input": "kgan",
"output": "126"
},
{
"input": "zoabkyuvus",
"output": "276"
},
{
"input": "spyemhyznjieyhhbk",
"output": "451"
},
{
"i... | 1,439,831,197 | 1,297 | Python 3 | OK | TESTS | 33 | 62 | 512,000 | #!/usr/bin/env python3
"""
Codeforces Round #309 (Div. 2)
Problem 554 A. Kyoya and Photobooks
@author yamaton
@date 2015-08-17
"""
import itertools as it
import functools
import operator
import collections
import math
import sys
def solve(s):
letters = set(s)
letter_count = len(letters)
size = len(s)
... | Title: Kyoya and Photobooks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kyoya Ootori is selling photobooks of the Ouran High School Host Club. He has 26 photos, labeled "a" to "z", and he has compiled them into a photo booklet with some photos in some order (possibly with some photos b... | ```python
#!/usr/bin/env python3
"""
Codeforces Round #309 (Div. 2)
Problem 554 A. Kyoya and Photobooks
@author yamaton
@date 2015-08-17
"""
import itertools as it
import functools
import operator
import collections
import math
import sys
def solve(s):
letters = set(s)
letter_count = len(letters)
size ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
955 | A | Feed the cat | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without food increases his hunger by *D* points.
At any time Andrew can visit the store where tasty buns are... | The first line contains two integers *hh* and *mm* (00<=≤<=*hh*<=≤<=23,<=00<=≤<=*mm*<=≤<=59) — the time of Andrew's awakening.
The second line contains four integers *H*, *D*, *C* and *N* (1<=≤<=*H*<=≤<=105,<=1<=≤<=*D*,<=*C*,<=*N*<=≤<=102). | Output the minimum amount of money to within three decimal digits. You answer is considered correct, if its absolute or relative error does not exceed 10<=-<=4.
Formally, let your answer be *a*, and the jury's answer be *b*. Your answer is considered correct if . | [
"19 00\n255 1 100 1\n",
"17 41\n1000 6 15 11\n"
] | [
"25200.0000\n",
"1365.0000\n"
] | In the first sample Andrew can visit the store at exactly 20:00. The cat's hunger will be equal to 315, hence it will be necessary to purchase 315 buns. The discount makes the final answer 25200 roubles.
In the second sample it's optimal to visit the store right after he wakes up. Then he'll have to buy 91 bins per 15... | 500 | [
{
"input": "19 00\n255 1 100 1",
"output": "25200.0000"
},
{
"input": "17 41\n1000 6 15 11",
"output": "1365.0000"
},
{
"input": "16 34\n61066 14 50 59",
"output": "43360.0000"
},
{
"input": "18 18\n23331 86 87 41",
"output": "49590.0000"
},
{
"input": "10 48\n684... | 1,523,132,800 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 93 | 7,065,600 | hh,mm=map(int,input().split())
h,d,c,n=map(int,input().split())
hh=hh*60+mm
mm=max(20*60,hh)
print(min(c*((h+n-1)//n),c*0.8*(((mm-hh)*d+h+n-1)//n)))
| Title: Feed the cat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After waking up at *hh*:*mm*, Andrew realised that he had forgotten to feed his only cat for yet another time (guess why there's only one cat). The cat's current hunger level is *H* points, moreover each minute without foo... | ```python
hh,mm=map(int,input().split())
h,d,c,n=map(int,input().split())
hh=hh*60+mm
mm=max(20*60,hh)
print(min(c*((h+n-1)//n),c*0.8*(((mm-hh)*d+h+n-1)//n)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,587,574,618 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
#define ll long long
using namespace std;
int main(){
ll n;
cin >> n;
n = n / 2;
if(n & 1)
n++;
cout << max((n / 2) - 1, 0ll) << "\n";
return 0;
}
| Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
#include <bits/stdc++.h>
#define ll long long
using namespace std;
int main(){
ll n;
cin >> n;
n = n / 2;
if(n & 1)
n++;
cout << max((n / 2) - 1, 0ll) << "\n";
return 0;
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
845 | C | Two TVs | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of shows.
Each of the next *n* lines contains two integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=109) — starting and ending time of *i*-th show. | If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes). | [
"3\n1 2\n2 3\n4 5\n",
"4\n1 2\n2 3\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 2\n2 3\n4 5",
"output": "YES"
},
{
"input": "4\n1 2\n2 3\n2 3\n1 2",
"output": "NO"
},
{
"input": "4\n0 1\n1 2\n2 3\n3 4",
"output": "YES"
},
{
"input": "3\n1 2\n2 3\n2 4",
"output": "NO"
},
{
"input": "3\n0 100\n0 100\n0 100",
"output": "NO"
... | 1,504,105,141 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | n=int(input())
a=[]
for i in range(n):
aa=list(map(int,input().split()))
a.append(aa)
a=sorted(a)
t=True
if n>2:
for i in range(n-2):
if n[i][1]==n[i+1][0]==n[i+2][0]:
t=False
break
if t:
print("YES")
else:
print("NO")
else:
print(... | Title: Two TVs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He ... | ```python
n=int(input())
a=[]
for i in range(n):
aa=list(map(int,input().split()))
a.append(aa)
a=sorted(a)
t=True
if n>2:
for i in range(n-2):
if n[i][1]==n[i+1][0]==n[i+2][0]:
t=False
break
if t:
print("YES")
else:
print("NO")
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
727 | A | Transformation: from A to B | PROGRAMMING | 1,000 | [
"brute force",
"dfs and similar",
"math"
] | null | null | Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - append the digit 1 to the right of current number (that is, replace the number *x* by 10·*x*<=+<=1).
You need to he... | The first line contains two positive integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=109) — the number which Vasily has and the number he wants to have. | If there is no way to get *b* from *a*, print "NO" (without quotes).
Otherwise print three lines. On the first line print "YES" (without quotes). The second line should contain single integer *k* — the length of the transformation sequence. On the third line print the sequence of transformations *x*1,<=*x*2,<=...,<=*x... | [
"2 162\n",
"4 42\n",
"100 40021\n"
] | [
"YES\n5\n2 4 8 81 162 \n",
"NO\n",
"YES\n5\n100 200 2001 4002 40021 \n"
] | none | 1,000 | [
{
"input": "2 162",
"output": "YES\n5\n2 4 8 81 162 "
},
{
"input": "4 42",
"output": "NO"
},
{
"input": "100 40021",
"output": "YES\n5\n100 200 2001 4002 40021 "
},
{
"input": "1 111111111",
"output": "YES\n9\n1 11 111 1111 11111 111111 1111111 11111111 111111111 "
},
... | 1,683,265,907 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 46 | 0 | a, b = map(int, input().split())
v = [b]
while b > a:
if b % 2 == 0:
b //= 2
elif (b - 1) % 10 == 0:
b = (b - 1) // 10
else:
break
v.append(b)
if v[-1] != a:
print("NO")
else:
print("YES")
print(len(v))
print(*reversed(v))
| Title: Transformation: from A to B
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily has a number *a*, which he wants to turn into a number *b*. For this purpose, he can do two types of operations:
- multiply the current number by 2 (that is, replace the number *x* by 2·*x*); - app... | ```python
a, b = map(int, input().split())
v = [b]
while b > a:
if b % 2 == 0:
b //= 2
elif (b - 1) % 10 == 0:
b = (b - 1) // 10
else:
break
v.append(b)
if v[-1] != a:
print("NO")
else:
print("YES")
print(len(v))
print(*reversed(v))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
270 | A | Fancy Fence | PROGRAMMING | 1,100 | [
"geometry",
"implementation",
"math"
] | null | null | Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuska... | The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees. | For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible. | [
"3\n30\n60\n90\n"
] | [
"NO\nYES\nYES\n"
] | In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a r... | 500 | [
{
"input": "3\n30\n60\n90",
"output": "NO\nYES\nYES"
},
{
"input": "6\n1\n2\n3\n170\n179\n25",
"output": "NO\nNO\nNO\nYES\nYES\nNO"
}
] | 1,696,930,826 | 2,147,483,647 | Python 3 | OK | TESTS | 3 | 62 | 0 | angle=[]
for i in range(1,361):
if 360%i==0:
angle.append((i-2)*180/i)
n=int(input())
for i in range(n):
if int(input()) in angle:
print("YES")
else:
print("NO")
| Title: Fancy Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can... | ```python
angle=[]
for i in range(1,361):
if 360%i==0:
angle.append((i-2)*180/i)
n=int(input())
for i in range(n):
if int(input()) in angle:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
620 | B | Grandfather Dovlet’s calculator | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Once Max found an electronic calculator from his grandfather Dovlet's chest. He noticed that the numbers were written with seven-segment indicators ([https://en.wikipedia.org/wiki/Seven-segment_display](https://en.wikipedia.org/wiki/Seven-segment_display)).
Max starts to type all the values from *a* to *b*. After typi... | The only line contains two integers *a*,<=*b* (1<=≤<=*a*<=≤<=*b*<=≤<=106) — the first and the last number typed by Max. | Print the only integer *a* — the total number of printed segments. | [
"1 3\n",
"10 15\n"
] | [
"12\n",
"39\n"
] | none | 0 | [
{
"input": "1 3",
"output": "12"
},
{
"input": "10 15",
"output": "39"
},
{
"input": "1 100",
"output": "928"
},
{
"input": "100 10000",
"output": "188446"
},
{
"input": "213 221442",
"output": "5645356"
},
{
"input": "1 1000000",
"output": "287333... | 1,672,414,537 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | m = [6,2,5,5,4,5,6,3,7,6]
a,b = map(int,input().split())
n = str(list(range(a,b+1)))
ans = 0
for k in range(len(m)):
ans+=d[i]*n.count(str(k))
print(ans) | Title: Grandfather Dovlet’s calculator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once Max found an electronic calculator from his grandfather Dovlet's chest. He noticed that the numbers were written with seven-segment indicators ([https://en.wikipedia.org/wiki/Seven-segment_display](... | ```python
m = [6,2,5,5,4,5,6,3,7,6]
a,b = map(int,input().split())
n = str(list(range(a,b+1)))
ans = 0
for k in range(len(m)):
ans+=d[i]*n.count(str(k))
print(ans)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
448 | C | Painting Fence | PROGRAMMING | 1,900 | [
"divide and conquer",
"dp",
"greedy"
] | null | null | Bizon the Champion isn't just attentive, he also is very hardworking.
Bizon the Champion decided to paint his old fence his favorite color, orange. The fence is represented as *n* vertical planks, put in a row. Adjacent planks have no gap between them. The planks are numbered from the left to the right starting from o... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of fence planks. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print a single integer — the minimum number of strokes needed to paint the whole fence. | [
"5\n2 2 1 2 1\n",
"2\n2 2\n",
"1\n5\n"
] | [
"3\n",
"2\n",
"1\n"
] | In the first sample you need to paint the fence in three strokes with the brush: the first stroke goes on height 1 horizontally along all the planks. The second stroke goes on height 2 horizontally and paints the first and second planks and the third stroke (it can be horizontal and vertical) finishes painting the four... | 2,500 | [
{
"input": "5\n2 2 1 2 1",
"output": "3"
},
{
"input": "2\n2 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n2 2 1 2 2",
"output": "3"
},
{
"input": "5\n2 2 1 5 1",
"output": "3"
},
{
"input": "1\n1",
"output": "1"
},
{
... | 1,673,514,681 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 716,800 | import gc
import heapq
import itertools
import math
from collections import Counter, deque, defaultdict
from sys import stdout
import time
from math import factorial, log, gcd
import sys
from decimal import Decimal
import threading
from heapq import *
from fractions import Fraction
import bisect
def S... | Title: Painting Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion isn't just attentive, he also is very hardworking.
Bizon the Champion decided to paint his old fence his favorite color, orange. The fence is represented as *n* vertical planks, put in a row. Adjacent... | ```python
import gc
import heapq
import itertools
import math
from collections import Counter, deque, defaultdict
from sys import stdout
import time
from math import factorial, log, gcd
import sys
from decimal import Decimal
import threading
from heapq import *
from fractions import Fraction
import bisect
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
660 | D | Number of Parallelograms | PROGRAMMING | 1,900 | [
"geometry"
] | null | null | You are given *n* points on a plane. All the points are distinct and no three of them lie on the same line. Find the number of parallelograms with the vertices at the given points. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of points.
Each of the next *n* lines contains two integers (*x**i*,<=*y**i*) (0<=≤<=*x**i*,<=*y**i*<=≤<=109) — the coordinates of the *i*-th point. | Print the only integer *c* — the number of parallelograms with the vertices at the given points. | [
"4\n0 1\n1 0\n1 1\n2 0\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "4\n0 1\n1 0\n1 1\n2 0",
"output": "1"
},
{
"input": "1\n0 0",
"output": "0"
},
{
"input": "1\n6 6",
"output": "0"
},
{
"input": "5\n1 5\n4 2\n4 4\n8 1\n8 2",
"output": "0"
},
{
"input": "10\n1 7\n2 14\n3 7\n3 13\n5 13\n13 10\n15 12\n17 1\n18 8\n19 0",
... | 1,629,873,536 | 1,736 | PyPy 3 | OK | TESTS | 72 | 1,294 | 199,782,400 | from collections import defaultdict
import sys
input = sys.stdin.readline
n = int(input())
xy = []
for _ in range(n):
x, y = map(int, input().split())
xy.append((x, y))
cnt = defaultdict(lambda : 0)
for i in range(n):
xi, yi = xy[i]
for j in range(i + 1, n):
xj, yj = xy[j]
... | Title: Number of Parallelograms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* points on a plane. All the points are distinct and no three of them lie on the same line. Find the number of parallelograms with the vertices at the given points.
Input Specification:
The fir... | ```python
from collections import defaultdict
import sys
input = sys.stdin.readline
n = int(input())
xy = []
for _ in range(n):
x, y = map(int, input().split())
xy.append((x, y))
cnt = defaultdict(lambda : 0)
for i in range(n):
xi, yi = xy[i]
for j in range(i + 1, n):
xj, yj = xy[j... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,595,985,023 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 155 | 20,172,800 | from sys import stdin
line = stdin.readline()
flage = 0
for x in line:
if flage == 0 and x == 'h' : flage = 1
elif flage == 1 and x == 'e' : flage = 2
elif flage == 2 and x == 'l' : flage = 3
elif flage == 3 and x == 'l' : flage = 4
elif flage == 4 and x == 'o' : flage = 5
if flage == ... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
from sys import stdin
line = stdin.readline()
flage = 0
for x in line:
if flage == 0 and x == 'h' : flage = 1
elif flage == 1 and x == 'e' : flage = 2
elif flage == 2 and x == 'l' : flage = 3
elif flage == 3 and x == 'l' : flage = 4
elif flage == 4 and x == 'o' : flage = 5
if... | 3.884925 | MatrixStudio/Codeforces-Python-Submissions |
352 | B | Jeff and Periods | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
- *x* occurs in sequence *a*. - Consider all positions of numbers *x* in the sequence *a* (such *i*, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). The numbers are separated by spaces. | In the first line print integer *t* — the number of valid *x*. On each of the next *t* lines print two integers *x* and *p**x*, where *x* is current suitable value, *p**x* is the common difference between numbers in the progression (if *x* occurs exactly once in the sequence, *p**x* must equal 0). Print the pairs in th... | [
"1\n2\n",
"8\n1 2 1 3 1 2 1 5\n"
] | [
"1\n2 0\n",
"4\n1 2\n2 4\n3 0\n5 0\n"
] | In the first test 2 occurs exactly once in the sequence, ergo *p*<sub class="lower-index">2</sub> = 0. | 1,000 | [
{
"input": "1\n2",
"output": "1\n2 0"
},
{
"input": "8\n1 2 1 3 1 2 1 5",
"output": "4\n1 2\n2 4\n3 0\n5 0"
},
{
"input": "3\n1 10 5",
"output": "3\n1 0\n5 0\n10 0"
},
{
"input": "4\n9 9 3 5",
"output": "3\n3 0\n5 0\n9 1"
},
{
"input": "6\n1 2 2 1 1 2",
"outpu... | 1,694,841,857 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | n = int(input())
arr = list(map(int,input().split()))
dit = {}
for i in range(n):
if arr[i] not in dit.keys():
dit[arr[i]]=[]
dit[arr[i]].append(i)
ans = []
for i in sorted(list(dit.keys())):
a = dit[i]
if len(a)==1:
ans.append([i,0])
else:
o=a[1]-a[0]
... | Title: Jeff and Periods
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
-... | ```python
n = int(input())
arr = list(map(int,input().split()))
dit = {}
for i in range(n):
if arr[i] not in dit.keys():
dit[arr[i]]=[]
dit[arr[i]].append(i)
ans = []
for i in sorted(list(dit.keys())):
a = dit[i]
if len(a)==1:
ans.append([i,0])
else:
o=a[1]-a[0... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
660 | B | Seating On Bus | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Consider 2*n* rows of the seats in a bus. *n* rows of the seats on the left and *n* rows of the seats on the right. Each row can be filled by two people. So the total capacity of the bus is 4*n*.
Consider that *m* (*m*<=≤<=4*n*) people occupy the seats in the bus. The passengers entering the bus are numbered from 1 to... | The only line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=4*n*) — the number of pairs of rows and the number of passengers. | Print *m* distinct integers from 1 to *m* — the order in which the passengers will get off the bus. | [
"2 7\n",
"9 36\n"
] | [
"5 1 6 2 7 3 4\n",
"19 1 20 2 21 3 22 4 23 5 24 6 25 7 26 8 27 9 28 10 29 11 30 12 31 13 32 14 33 15 34 16 35 17 36 18\n"
] | none | 0 | [
{
"input": "2 7",
"output": "5 1 6 2 7 3 4"
},
{
"input": "9 36",
"output": "19 1 20 2 21 3 22 4 23 5 24 6 25 7 26 8 27 9 28 10 29 11 30 12 31 13 32 14 33 15 34 16 35 17 36 18"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 4",
"output": "3 1 4 2"
},
{
"input... | 1,651,213,632 | 2,147,483,647 | PyPy 3 | OK | TESTS | 23 | 77 | 0 | n, m = [int(i) for i in input().split()]
wl, wr, nwl, nwr = [], [] , [], []
visited = set()
for i in range(2*n+1, m+1, 2):
if i not in visited : nwl.append(i); visited.add(i)
for i in range(1, m+1, 2):
if i not in visited : wl.append(i); visited.add(i)
for i in range(2*n+2, m+1, 2):
if i not in vis... | Title: Seating On Bus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider 2*n* rows of the seats in a bus. *n* rows of the seats on the left and *n* rows of the seats on the right. Each row can be filled by two people. So the total capacity of the bus is 4*n*.
Consider that *m* (*m*<... | ```python
n, m = [int(i) for i in input().split()]
wl, wr, nwl, nwr = [], [] , [], []
visited = set()
for i in range(2*n+1, m+1, 2):
if i not in visited : nwl.append(i); visited.add(i)
for i in range(1, m+1, 2):
if i not in visited : wl.append(i); visited.add(i)
for i in range(2*n+2, m+1, 2):
if i ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
409 | H | A + B Strikes Back | PROGRAMMING | 1,500 | [
"*special",
"brute force",
"constructive algorithms",
"dsu",
"implementation"
] | null | null | A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try? | The input contains two integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=103), separated by a single space. | Output the sum of the given integers. | [
"5 14\n",
"381 492\n"
] | [
"19\n",
"873\n"
] | none | 0 | [
{
"input": "5 14",
"output": "19"
},
{
"input": "381 492",
"output": "873"
},
{
"input": "536 298",
"output": "834"
},
{
"input": "143 522",
"output": "665"
},
{
"input": "433 126",
"output": "559"
},
{
"input": "723 350",
"output": "1073"
},
{... | 1,628,881,792 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 0 | 0 | a, b = map(int, input.split())
print(a + b) | Title: A + B Strikes Back
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input ... | ```python
a, b = map(int, input.split())
print(a + b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,652,631,274 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 60 | 4,505,600 | n = int(input())
linea=input()
arreglo = linea.split(" ")
arreglo.sort()
conjunto = set()
menor=101
for elem in arreglo:
conjunto.add(elem)
conjunto.remove(arreglo[0])
for e in conjunto:
if int(e) < menor:
menor = int(e)
print(menor)
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n = int(input())
linea=input()
arreglo = linea.split(" ")
arreglo.sort()
conjunto = set()
menor=101
for elem in arreglo:
conjunto.add(elem)
conjunto.remove(arreglo[0])
for e in conjunto:
if int(e) < menor:
menor = int(e)
print(menor)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,689,317,990 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 31 | 0 | S = input()
if S.isupper() :
print(S[0] + S[1:].lower())
elif (S[0].islower() and S[1:].isupper()):
print(S[0].upper()+ S[1:].lower())
else:
print(S) | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
S = input()
if S.isupper() :
print(S[0] + S[1:].lower())
elif (S[0].islower() and S[1:].isupper()):
print(S[0].upper()+ S[1:].lower())
else:
print(S)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
245 | A | System Administrator | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping command sends exactly ten packets to the server specified in the argument of the command. Executing a progra... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=1000) — the number of commands Polycarpus has fulfilled. Each of the following *n* lines contains three integers — the description of the commands. The *i*-th of these lines contains three space-separated integers *t**i*, *x**i*, *y**i* (1<=≤<=*t**i*<=≤<=2; *x... | In the first line print string "LIVE" (without the quotes) if server *a* is "alive", otherwise print "DEAD" (without the quotes).
In the second line print the state of server *b* in the similar format. | [
"2\n1 5 5\n2 6 4\n",
"3\n1 0 10\n2 0 10\n1 10 0\n"
] | [
"LIVE\nLIVE\n",
"LIVE\nDEAD\n"
] | Consider the first test case. There 10 packets were sent to server *a*, 5 of them reached it. Therefore, at least half of all packets sent to this server successfully reached it through the network. Overall there were 10 packets sent to server *b*, 6 of them reached it. Therefore, at least half of all packets sent to t... | 0 | [
{
"input": "2\n1 5 5\n2 6 4",
"output": "LIVE\nLIVE"
},
{
"input": "3\n1 0 10\n2 0 10\n1 10 0",
"output": "LIVE\nDEAD"
},
{
"input": "10\n1 3 7\n2 4 6\n1 2 8\n2 5 5\n2 10 0\n2 10 0\n1 8 2\n2 2 8\n2 10 0\n1 1 9",
"output": "DEAD\nLIVE"
},
{
"input": "11\n1 8 2\n1 6 4\n1 9 1\n1... | 1,574,413,728 | 2,147,483,647 | Python 3 | OK | TESTS | 13 | 248 | 307,200 | def server_status(packets):
first_delta = 0
second_delta = 0
for packet in packets:
if packet[0] == 1:
first_delta += packet[1] - packet[2]
else:
second_delta += packet[1] - packet[2]
print("LIVE" if first_delta >= 0 else "DEAD")
print("LIVE" if secon... | Title: System Administrator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus is a system administrator. There are two servers under his strict guidance — *a* and *b*. To stay informed about the servers' performance, Polycarpus executes commands "ping a" and "ping b". Each ping co... | ```python
def server_status(packets):
first_delta = 0
second_delta = 0
for packet in packets:
if packet[0] == 1:
first_delta += packet[1] - packet[2]
else:
second_delta += packet[1] - packet[2]
print("LIVE" if first_delta >= 0 else "DEAD")
print("LIVE... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
495 | A | Digital Counter | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Malek lives in an apartment block with 100 floors numbered from 0 to 99. The apartment has an elevator with a digital counter showing the floor that the elevator is currently on. The elevator shows each digit of a number with 7 light sticks by turning them on or off. The picture below shows how the elevator shows each ... | The only line of input contains exactly two digits representing number *n* (0<=≤<=*n*<=≤<=99). Note that *n* may have a leading zero. | In the only line of the output print the number of good integers. | [
"89\n",
"00\n",
"73\n"
] | [
"2\n",
"4\n",
"15\n"
] | In the first sample the counter may be supposed to show 88 or 89.
In the second sample the good integers are 00, 08, 80 and 88.
In the third sample the good integers are 03, 08, 09, 33, 38, 39, 73, 78, 79, 83, 88, 89, 93, 98, 99. | 500 | [
{
"input": "89",
"output": "2"
},
{
"input": "00",
"output": "4"
},
{
"input": "73",
"output": "15"
},
{
"input": "08",
"output": "2"
},
{
"input": "26",
"output": "4"
},
{
"input": "49",
"output": "6"
},
{
"input": "88",
"output": "1"
... | 1,418,489,508 | 1,308 | Python 3 | OK | TESTS | 29 | 62 | 0 | s = str(input())
x1 = int(s[0])
x2 = int(s[1])
y = [[0] * 7 for i in range(10)]
y[0] = [1, 1, 1, 0, 1, 1, 1]
y[1] = [0, 0, 0, 0, 0, 1, 1]
y[2] = [0, 1, 1, 1, 1, 1, 0]
y[3] = [0, 0, 1, 1, 1, 1, 1]
y[4] = [1, 0, 0, 1, 0, 1, 1]
y[5] = [1, 0, 1, 1, 1, 0, 1]
y[6] = [1, 1, 1, 1, 1, 0, 1]
y[7] = [0, 0, 1, 0, 0, 1, ... | Title: Digital Counter
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Malek lives in an apartment block with 100 floors numbered from 0 to 99. The apartment has an elevator with a digital counter showing the floor that the elevator is currently on. The elevator shows each digit of a numbe... | ```python
s = str(input())
x1 = int(s[0])
x2 = int(s[1])
y = [[0] * 7 for i in range(10)]
y[0] = [1, 1, 1, 0, 1, 1, 1]
y[1] = [0, 0, 0, 0, 0, 1, 1]
y[2] = [0, 1, 1, 1, 1, 1, 0]
y[3] = [0, 0, 1, 1, 1, 1, 1]
y[4] = [1, 0, 0, 1, 0, 1, 1]
y[5] = [1, 0, 1, 1, 1, 0, 1]
y[6] = [1, 1, 1, 1, 1, 0, 1]
y[7] = [0, 0, 1,... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
171 | B | Star | PROGRAMMING | 1,300 | [
"*special",
"combinatorics"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257). | Print a single integer *output* (1<=≤<=*output*<=≤<=2·109). | [
"2\n"
] | [
"13"
] | none | 0 | [
{
"input": "2",
"output": "13"
},
{
"input": "1",
"output": "1"
},
{
"input": "3",
"output": "37"
},
{
"input": "4",
"output": "73"
},
{
"input": "5",
"output": "121"
},
{
"input": "6",
"output": "181"
},
{
"input": "7",
"output": "253"... | 1,585,629,920 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 186 | 0 | a=int(input())
print((a*6)+1) | Title: Star
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257).
Output Specification:
Print a single integer *output* (1<=≤<=*output*<=≤<=2·109).
Demo Input:
['2\n']
Demo Output:
['13']
Note:
none | ```python
a=int(input())
print((a*6)+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | ||
765 | A | Neverending competitions | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.
Jinotega's best friends, team ... | In the first line of input there is a single integer *n*: the number of Jinotega's flights (1<=≤<=*n*<=≤<=100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next *n* lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX"... | If Jinotega is now at home, print "home" (without quotes), otherwise print "contest". | [
"4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO\n",
"3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP\n"
] | [
"home\n",
"contest\n"
] | In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list. | 500 | [
{
"input": "4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO",
"output": "home"
},
{
"input": "3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP",
"output": "contest"
},
{
"input": "1\nESJ\nESJ->TSJ",
"output": "contest"
},
{
"input": "2\nXMR\nFAJ->XMR\nXMR->FAJ",
"output": "home"
},
... | 1,644,651,167 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | n=int(input())
st=input()
for i in range(n):
str=input()
if str[5:]==st:
print("home")
else:
print("contest")
| Title: Neverending competitions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from thei... | ```python
n=int(input())
st=input()
for i in range(n):
str=input()
if str[5:]==st:
print("home")
else:
print("contest")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
893 | B | Beautiful Divisors | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Recently Luba learned about a special kind of numbers that she calls beautiful numbers. The number is called beautiful iff its binary representation consists of *k*<=+<=1 consecutive ones, and then *k* consecutive zeroes.
Some examples of beautiful numbers:
- 12 (110); - 1102 (610); - 11110002 (12010); - 1111100... | The only line of input contains one number *n* (1<=≤<=*n*<=≤<=105) — the number Luba has got. | Output one number — the greatest beautiful divisor of Luba's number. It is obvious that the answer always exists. | [
"3\n",
"992\n"
] | [
"1\n",
"496\n"
] | none | 0 | [
{
"input": "3",
"output": "1"
},
{
"input": "992",
"output": "496"
},
{
"input": "81142",
"output": "1"
},
{
"input": "76920",
"output": "120"
},
{
"input": "2016",
"output": "2016"
},
{
"input": "1",
"output": "1"
},
{
"input": "6",
"o... | 1,603,693,956 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 78 | 0 | from math import log,ceil
n = int(input())
a = log(n,2)
a = ceil(a)//2
result = (2**(2*a)-2**a)//2
print(result)
| Title: Beautiful Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba learned about a special kind of numbers that she calls beautiful numbers. The number is called beautiful iff its binary representation consists of *k*<=+<=1 consecutive ones, and then *k* consecutive ze... | ```python
from math import log,ceil
n = int(input())
a = log(n,2)
a = ceil(a)//2
result = (2**(2*a)-2**a)//2
print(result)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,644,043,806 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | a=input()
b=''
##def chat(name):
## prov=[]
## b=''
## for i in range(len(a)):
## if a[i] not in prov:
## b+=a[i]
## prov+=a[i]
## return b
##b=chat(a)
##if 'h'in b and b.index('h')<b.index('e') and b.index('e')<b.index('l') and b.index('l')<b.index('o'):
## pri... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
a=input()
b=''
##def chat(name):
## prov=[]
## b=''
## for i in range(len(a)):
## if a[i] not in prov:
## b+=a[i]
## prov+=a[i]
## return b
##b=chat(a)
##if 'h'in b and b.index('h')<b.index('e') and b.index('e')<b.index('l') and b.index('l')<b.index('o'):
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,639,563,917 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | a = int(input())
lst = input().split(" ")
lst = list(map(int, lst))
b = True
lst.sort()
for x in range(len(lst) - 1):
if(lst[x] != lst[x+1] and b):
print(lst[x+1])
b = False
if(b):
print("NO")
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
a = int(input())
lst = input().split(" ")
lst = list(map(int, lst))
b = True
lst.sort()
for x in range(len(lst) - 1):
if(lst[x] != lst[x+1] and b):
print(lst[x+1])
b = False
if(b):
print("NO")
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,555,072,754 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | def coders(n):
solution = []
for i in range(n):
inner = []
f = (i % 2 == 0)
for j in range(n):
f1 = (j % 2 == 0)
if f:
if f1:
inner.append("C")
else:
inner.append(".")
... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
def coders(n):
solution = []
for i in range(n):
inner = []
f = (i % 2 == 0)
for j in range(n):
f1 = (j % 2 == 0)
if f:
if f1:
inner.append("C")
else:
inner.append(".... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,651,415,878 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | n=input()
s = input().split()
v = [int(x) for x in s]
maxv=0
for x in v:
if (x>maxv):
maxv=x
res=0
for x in v:
res=res+maxv-x
print (res) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n=input()
s = input().split()
v = [int(x) for x in s]
maxv=0
for x in v:
if (x>maxv):
maxv=x
res=0
for x in v:
res=res+maxv-x
print (res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
899 | A | Splitting in Teams | PROGRAMMING | 800 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The coach decided to form teams of exactly three people for this training. Determine the maximum number of tea... | The first line contains single integer *n* (2<=≤<=*n*<=≤<=2·105) — the number of groups.
The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2), where *a**i* is the number of people in group *i*. | Print the maximum number of teams of three people the coach can form. | [
"4\n1 1 2 1\n",
"2\n2 2\n",
"7\n2 2 2 1 1 1 1\n",
"3\n1 1 1\n"
] | [
"1\n",
"0\n",
"3\n",
"1\n"
] | In the first example the coach can form one team. For example, he can take students from the first, second and fourth groups.
In the second example he can't make a single team.
In the third example the coach can form three teams. For example, he can do this in the following way:
- The first group (of two people) an... | 500 | [
{
"input": "4\n1 1 2 1",
"output": "1"
},
{
"input": "2\n2 2",
"output": "0"
},
{
"input": "7\n2 2 2 1 1 1 1",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "3\n2 2 2",
"output": "0"
},
{
"input": "3\n1 2 1",
"output": "1"
}... | 1,608,309,804 | 2,147,483,647 | PyPy 3 | OK | TESTS | 67 | 202 | 12,595,200 | # A. Splitting in Teams
n = int(input())
a = list(map(int, input().split()))
ones = a.count(1)
twos = a.count(2)
ans = min(twos, ones)
if ones > twos:
ans += (ones - twos) // 3
print(ans)
| Title: Splitting in Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There were *n* groups of students which came to write a training contest. A group is either one person who can write the contest with anyone else, or two people who want to write the contest in the same team.
The co... | ```python
# A. Splitting in Teams
n = int(input())
a = list(map(int, input().split()))
ones = a.count(1)
twos = a.count(2)
ans = min(twos, ones)
if ones > twos:
ans += (ones - twos) // 3
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,696,244,260 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | m,n = map(int,input().split())
a = list(map(int,input().split()))
a.sort()
c = 0
for i in range(n) :
c += abs(a[i])
print(c) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
m,n = map(int,input().split())
a = list(map(int,input().split()))
a.sort()
c = 0
for i in range(n) :
c += abs(a[i])
print(c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,608,530,114 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 218 | 0 | n,x=map(int, input().split())
a=([i for i in range(2,x+1) if all([i%j for j in range(2,i)])])
for i in range(len(a)):
if a[i-1]==n:
if a[i]==x:
print('YES')
else:
print('NO') | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
n,x=map(int, input().split())
a=([i for i in range(2,x+1) if all([i%j for j in range(2,i)])])
for i in range(len(a)):
if a[i-1]==n:
if a[i]==x:
print('YES')
else:
print('NO')
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,668,534,168 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 4 | 77 | 3,379,200 | strArrInput = list(input())
if "5" <= strArrInput[0] < "9":
strArrInput[idx] = str(ord("9") - ord(strArrInput[idx]))
for idx in range(1, len(strArrInput)):
if strArrInput[idx] >= "5":
strArrInput[idx] = str(ord("9") - ord(strArrInput[idx]))
x = ''.join(strArrInput)
print(x) | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
strArrInput = list(input())
if "5" <= strArrInput[0] < "9":
strArrInput[idx] = str(ord("9") - ord(strArrInput[idx]))
for idx in range(1, len(strArrInput)):
if strArrInput[idx] >= "5":
strArrInput[idx] = str(ord("9") - ord(strArrInput[idx]))
x = ''.join(strArrInput)
print(x)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
755 | A | PolandBall and Hypothesis | PROGRAMMING | 800 | [
"brute force",
"graphs",
"math",
"number theory"
] | null | null | PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is a prime number".
Unfortunately, PolandBall is not experienced yet and doesn't know that his hypothesis is inc... | The only number in the input is *n* (1<=≤<=*n*<=≤<=1000) — number from the PolandBall's hypothesis. | Output such *m* that *n*·*m*<=+<=1 is not a prime number. Your answer will be considered correct if you output any suitable *m* such that 1<=≤<=*m*<=≤<=103. It is guaranteed the the answer exists. | [
"3\n",
"4\n"
] | [
"1",
"2"
] | A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.
For the first sample testcase, 3·1 + 1 = 4. We can output 1.
In the second sample testcase, 4·1 + 1 = 5. We cannot output 1 because 5 is prime. However, *m* = 2 is okay since 4·2 + 1 = 9, which is not... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "2"
},
{
"input": "153",
"output": "1"
},
{
"input": "1000",
"output": "1"
},
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "4"
... | 1,632,507,206 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 61 | 6,758,400 | import math
def isPrime(num):
if num%2 == 0:
return False
else:
div = 3
while div <= math.sqrt(num):
if num%div == 0:
return False
div += 2
return True
n = int(input())
m = 1
while m <= 1000:
num = n*m + 1
if not isPrime(num)... | Title: PolandBall and Hypothesis
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is a young, clever Ball. He is interested in prime numbers. He has stated a following hypothesis: "There exists such a positive integer *n* that for each positive integer *m* number *n*·*m*<=+<=1 is... | ```python
import math
def isPrime(num):
if num%2 == 0:
return False
else:
div = 3
while div <= math.sqrt(num):
if num%div == 0:
return False
div += 2
return True
n = int(input())
m = 1
while m <= 1000:
num = n*m + 1
if not is... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
805 | A | Fake NP | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | null | null | Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of their integer divisors except 1. Find the integer that we wrote down the maximum number of times... | The first line contains two integers *l* and *r* (2<=≤<=*l*<=≤<=*r*<=≤<=109). | Print single integer, the integer that appears maximum number of times in the divisors.
If there are multiple answers, print any of them. | [
"19 29\n",
"3 6\n"
] | [
"2\n",
"3\n"
] | Definition of a divisor: [https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html](https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html)
The first example: from 19 to 29 these numbers are divisible by 2: {20, 22, 24, 26, 28}.
The second example: from 3 to 6 these numbers are divisible by 3: {... | 500 | [
{
"input": "19 29",
"output": "2"
},
{
"input": "3 6",
"output": "2"
},
{
"input": "39 91",
"output": "2"
},
{
"input": "76 134",
"output": "2"
},
{
"input": "93 95",
"output": "2"
},
{
"input": "17 35",
"output": "2"
},
{
"input": "94 95",... | 1,574,137,656 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 24 | 140 | 0 | a,b = map(int,input().split())
two_count = 0
three_count = 0
two_count = (b//2) - (a//2)
three_count = (b//3) - (a//3)
if a%2 == 0:
two_count += 1
if a%3 == 0:
three_count += 1
if two_count > three_count:
print("2")
else:
print("3")
| Title: Fake NP
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of the... | ```python
a,b = map(int,input().split())
two_count = 0
three_count = 0
two_count = (b//2) - (a//2)
three_count = (b//3) - (a//3)
if a%2 == 0:
two_count += 1
if a%3 == 0:
three_count += 1
if two_count > three_count:
print("2")
else:
print("3")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
620 | B | Grandfather Dovlet’s calculator | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Once Max found an electronic calculator from his grandfather Dovlet's chest. He noticed that the numbers were written with seven-segment indicators ([https://en.wikipedia.org/wiki/Seven-segment_display](https://en.wikipedia.org/wiki/Seven-segment_display)).
Max starts to type all the values from *a* to *b*. After typi... | The only line contains two integers *a*,<=*b* (1<=≤<=*a*<=≤<=*b*<=≤<=106) — the first and the last number typed by Max. | Print the only integer *a* — the total number of printed segments. | [
"1 3\n",
"10 15\n"
] | [
"12\n",
"39\n"
] | none | 0 | [
{
"input": "1 3",
"output": "12"
},
{
"input": "10 15",
"output": "39"
},
{
"input": "1 100",
"output": "928"
},
{
"input": "100 10000",
"output": "188446"
},
{
"input": "213 221442",
"output": "5645356"
},
{
"input": "1 1000000",
"output": "287333... | 1,453,550,443 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 0 | seg={}
seg[0]=6
seg[1]=2
seg[2]=5
seg[3]=5
seg[4]=4
seg[5]=5
seg[6]=6
seg[7]=3
seg[8]=7
seg[9]=6
a,b=map(int,input().split(' '))
cc=0
for i in range(a,b+1):
x=i
while x:
cc+=seg[x%10]
x//=10
print(cc) | Title: Grandfather Dovlet’s calculator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once Max found an electronic calculator from his grandfather Dovlet's chest. He noticed that the numbers were written with seven-segment indicators ([https://en.wikipedia.org/wiki/Seven-segment_display](... | ```python
seg={}
seg[0]=6
seg[1]=2
seg[2]=5
seg[3]=5
seg[4]=4
seg[5]=5
seg[6]=6
seg[7]=3
seg[8]=7
seg[9]=6
a,b=map(int,input().split(' '))
cc=0
for i in range(a,b+1):
x=i
while x:
cc+=seg[x%10]
x//=10
print(cc)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,605,283,494 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 280 | 0 | n = int(input())
l = list(map(int,input().split()))
a,b = map(int,input().split())
y = b-a
sum1 = 0
for i in range(y):
sum1 = sum1 + l[i]
print(sum1)
| Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
n = int(input())
l = list(map(int,input().split()))
a,b = map(int,input().split())
y = b-a
sum1 = 0
for i in range(y):
sum1 = sum1 + l[i]
print(sum1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain num... | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,666,732,547 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | import numpy as np
n=int(input())
x=int(input())
M=np.zeros((n,n))
nb=0
for i in range(n):
for j in range(n):
M[i,j]=(i+1)*(j+1)
if M[i,j]==x:
nb+=1
print(nb) | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
Y... | ```python
import numpy as np
n=int(input())
x=int(input())
M=np.zeros((n,n))
nb=0
for i in range(n):
for j in range(n):
M[i,j]=(i+1)*(j+1)
if M[i,j]==x:
nb+=1
print(nb)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,513,223,337 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 77 | 5,529,600 | x = input()
y = input()
s = ''
for i in range(len(x)):
s += '0' if x[i] == y[i] else '1'
print(s)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
x = input()
y = input()
s = ''
for i in range(len(x)):
s += '0' if x[i] == y[i] else '1'
print(s)
``` | 3.97045 | MatrixStudio/Codeforces-Python-Submissions |
476 | A | Dreamoon and Stairs | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition? | The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10). | Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead. | [
"10 2\n",
"3 5\n"
] | [
"6\n",
"-1\n"
] | For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | 500 | [
{
"input": "10 2",
"output": "6"
},
{
"input": "3 5",
"output": "-1"
},
{
"input": "29 7",
"output": "21"
},
{
"input": "2 2",
"output": "2"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "10000 2",
"output": "5000"
},
{
"input": "10000 ... | 1,652,392,909 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n, m = map(float, input().split())
status = True
c1=0#количесто 2
c2=0#количество 1
sum=0
if n%2==0:
c1=n//2
else:
c1=n//2
c2=n%2
if m>n:
print("-1")
else:
while not (c1+c2)%m==0:# 20 3 c1=8 c2=4
c1-=1
c2+=2
print(c1 + c2) | Title: Dreamoon and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb ... | ```python
n, m = map(float, input().split())
status = True
c1=0#количесто 2
c2=0#количество 1
sum=0
if n%2==0:
c1=n//2
else:
c1=n//2
c2=n%2
if m>n:
print("-1")
else:
while not (c1+c2)%m==0:# 20 3 c1=8 c2=4
c1-=1
c2+=2
print(c1 + c2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,684,044,504 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | n,l=map(int,input().split())
x=list(map(int,input().split()))
x.sort()
d1=x[0]-0
d2=l-x[n-1]
z=[]
for i in range(0,n-1):
d=abs(x[i]-x[i+1])
z.append(d)
z.sort()
if len(z)==0:
print(max(d1,d2))
else:
y=z[len(z)-1]/2
print(max(d1,d2,y))
| Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
n,l=map(int,input().split())
x=list(map(int,input().split()))
x.sort()
d1=x[0]-0
d2=l-x[n-1]
z=[]
for i in range(0,n-1):
d=abs(x[i]-x[i+1])
z.append(d)
z.sort()
if len(z)==0:
print(max(d1,d2))
else:
y=z[len(z)-1]/2
print(max(d1,d2,y))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You've got string *s*, consisting of only lowercase English letters. Find its lexicographically maximum subsequence.
We'll call a non-empty string *s*[*p*1*p*2... *p**k*]<==<=*s**p*1*s**p*2... *s**p**k*(1<=≤<=*p*1<=<<=*p*2<=<<=...<=<<=*p**k*<=≤<=|*s*|) a subsequence of string *s*<==<=*s*1*s*2... *s*|*s*|.
St... | The single line contains a non-empty string *s*, consisting only of lowercase English letters. The string's length doesn't exceed 105. | Print the lexicographically maximum subsequence of string *s*. | [
"ababba\n",
"abbcbccacbbcbaaba\n"
] | [
"bbba\n",
"cccccbba\n"
] | Let's look at samples and see what the sought subsequences look like (they are marked with uppercase bold letters).
The first sample: aBaBBA
The second sample: abbCbCCaCbbCBaaBA | 0 | [
{
"input": "ababba",
"output": "bbba"
},
{
"input": "abbcbccacbbcbaaba",
"output": "cccccbba"
},
{
"input": "thankstosamarasauteddybearsforthiscontest",
"output": "yttt"
},
{
"input": "cantouristsolveitlessthaninoneminute",
"output": "vute"
},
{
"input": "areprete... | 1,670,484,022 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 156 | 0 | s = input()
s = s[::-1]
n = len(s)
maxi = s[0]
for i in range(1,n):
if s[i]>=maxi[-1]:
maxi += s[i]
print(maxi[::-1])
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got string *s*, consisting of only lowercase English letters. Find its lexicographically maximum subsequence.
We'll call a non-empty string *s*[*p*1*p*2... *p**k*]<==<=*s**p*1*s**p*2... *s**p**k*(1<=≤<=*p*1<=<<=*p*2<=&l... | ```python
s = input()
s = s[::-1]
n = len(s)
maxi = s[0]
for i in range(1,n):
if s[i]>=maxi[-1]:
maxi += s[i]
print(maxi[::-1])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
898 | A | Rounding | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5 Vasya can round it to 0 or to 10. Both ways are correct.
For given *n* find out to which int... | The first line contains single integer *n* (0<=≤<=*n*<=≤<=109) — number that Vasya has. | Print result of rounding *n*. Pay attention that in some cases answer isn't unique. In that case print any correct answer. | [
"5\n",
"113\n",
"1000000000\n",
"5432359\n"
] | [
"0\n",
"110\n",
"1000000000\n",
"5432360\n"
] | In the first example *n* = 5. Nearest integers, that ends up with zero are 0 and 10. Any of these answers is correct, so you can print 0 or 10. | 500 | [
{
"input": "5",
"output": "0"
},
{
"input": "113",
"output": "110"
},
{
"input": "1000000000",
"output": "1000000000"
},
{
"input": "5432359",
"output": "5432360"
},
{
"input": "999999994",
"output": "999999990"
},
{
"input": "10",
"output": "10"
... | 1,590,058,181 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 109 | 0 | from math import ceil
def solve():
n = int(input())
if n % 10 == 0:
print(n)
elif n % 10 < 5:
print(n//10*10)
else:
print(int(ceil(n/10))*10)
if __name__ == "__main__":
solve() | Title: Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has a non-negative integer *n*. He wants to round it to nearest integer, which ends up with 0. If *n* already ends up with 0, Vasya considers it already rounded.
For example, if *n*<==<=4722 answer is 4720. If *n*<==<=5... | ```python
from math import ceil
def solve():
n = int(input())
if n % 10 == 0:
print(n)
elif n % 10 < 5:
print(n//10*10)
else:
print(int(ceil(n/10))*10)
if __name__ == "__main__":
solve()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
23 | A | You're Given a String... | PROGRAMMING | 1,200 | [
"brute force",
"greedy"
] | A. You're Given a String... | 2 | 256 | You're given a string of lower-case Latin letters. Your task is to find the length of its longest substring that can be met in the string at least twice. These occurrences can overlap (see sample test 2). | The first input line contains the string. It's guaranteed, that the string is non-empty, consists of lower-case Latin letters, and its length doesn't exceed 100. | Output one number — length of the longest substring that can be met in the string at least twice. | [
"abcd\n",
"ababa\n",
"zzz\n"
] | [
"0",
"3",
"2"
] | none | 0 | [
{
"input": "abcd",
"output": "0"
},
{
"input": "ababa",
"output": "3"
},
{
"input": "zzz",
"output": "2"
},
{
"input": "kmmm",
"output": "2"
},
{
"input": "wzznz",
"output": "1"
},
{
"input": "qlzazaaqll",
"output": "2"
},
{
"input": "lzggg... | 1,541,825,129 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 218 | 0 | x = input().strip()
maxx = -1
i = 0
while i < len(x):
j = 1
#print(x.find(x[i:i+j],i+1))
while x.find(x[i:i+j],i+1)>0:
if maxx < i+j:
maxx = i+j
j+=1
i+=1
print(maxx)
| Title: You're Given a String...
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You're given a string of lower-case Latin letters. Your task is to find the length of its longest substring that can be met in the string at least twice. These occurrences can overlap (see sample test 2).
Input Sp... | ```python
x = input().strip()
maxx = -1
i = 0
while i < len(x):
j = 1
#print(x.find(x[i:i+j],i+1))
while x.find(x[i:i+j],i+1)>0:
if maxx < i+j:
maxx = i+j
j+=1
i+=1
print(maxx)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,699,986,821 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 1,122 | 23,142,400 | num = int(input())
fig = {"Icosahedron":20,
"Cube":6,
"Tetrahedron" : 4,
"Octahedron" : 8,
"Dodecahedron": 12
}
odp = 0
figury = [0] * num
for i in range(num):
figury[i] = input()
for j in figury:
if j in fig:
odp+= fig[j]
print(odp) | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
num = int(input())
fig = {"Icosahedron":20,
"Cube":6,
"Tetrahedron" : 4,
"Octahedron" : 8,
"Dodecahedron": 12
}
odp = 0
figury = [0] * num
for i in range(num):
figury[i] = input()
for j in figury:
if j in fig:
odp+= fig[j]
print(odp)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
372 | A | Counting Kangaroos is Fun | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"sortings",
"two pointers"
] | null | null | There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as large as the size of kangaroo who is held.
Each kangaroo can hold at most one kangaroo, and the kangaroo who i... | The first line contains a single integer — *n* (1<=≤<=*n*<=≤<=5·105). Each of the next *n* lines contains an integer *s**i* — the size of the *i*-th kangaroo (1<=≤<=*s**i*<=≤<=105). | Output a single integer — the optimal number of visible kangaroos. | [
"8\n2\n5\n7\n6\n9\n8\n4\n2\n",
"8\n9\n1\n6\n2\n6\n5\n8\n3\n"
] | [
"5\n",
"5\n"
] | none | 500 | [
{
"input": "8\n2\n5\n7\n6\n9\n8\n4\n2",
"output": "5"
},
{
"input": "8\n9\n1\n6\n2\n6\n5\n8\n3",
"output": "5"
},
{
"input": "12\n3\n99\n24\n46\n75\n63\n57\n55\n10\n62\n34\n52",
"output": "7"
},
{
"input": "12\n55\n75\n1\n98\n63\n64\n9\n39\n82\n18\n47\n9",
"output": "6"
... | 1,588,240,546 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 124 | 307,200 | import bisect
m=int(input())
l=[]
while m>0:
t=int(input())
l.append(t)
m-=1
l.sort()
k=l[m-1]//2
s=bisect.bisect_right(l,k)
n=len(l)
c=0
while(s>=0):
if 2*l[s]<=l[n-1]:
c+=1
n-=1
s-=1
print(len(l)-c) | Title: Counting Kangaroos is Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as ... | ```python
import bisect
m=int(input())
l=[]
while m>0:
t=int(input())
l.append(t)
m-=1
l.sort()
k=l[m-1]//2
s=bisect.bisect_right(l,k)
n=len(l)
c=0
while(s>=0):
if 2*l[s]<=l[n-1]:
c+=1
n-=1
s-=1
print(len(l)-c)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
574 | B | Bear and Three Musketeers | PROGRAMMING | 1,500 | [
"brute force",
"dfs and similar",
"graphs",
"hashing"
] | null | null | Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three brave warriors to help him to fight against bad guys.
There are *n* warriors. Richelimakieu wants to choose thre... | The first line contains two space-separated integers, *n* and *m* (3<=≤<=*n*<=≤<=4000, 0<=≤<=*m*<=≤<=4000) — respectively number of warriors and number of pairs of warriors knowing each other.
*i*-th of the following *m* lines contains two space-separated integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**... | If Richelimakieu can choose three musketeers, print the minimum possible sum of their recognitions. Otherwise, print "-1" (without the quotes). | [
"5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5\n",
"7 4\n2 1\n3 6\n5 1\n1 7\n"
] | [
"2\n",
"-1\n"
] | In the first sample Richelimakieu should choose a triple 1, 2, 3. The first musketeer doesn't know anyone except other two musketeers so his recognition is 0. The second musketeer has recognition 1 because he knows warrior number 4. The third musketeer also has recognition 1 because he knows warrior 4. Sum of recogniti... | 1,000 | [
{
"input": "5 6\n1 2\n1 3\n2 3\n2 4\n3 4\n4 5",
"output": "2"
},
{
"input": "7 4\n2 1\n3 6\n5 1\n1 7",
"output": "-1"
},
{
"input": "5 0",
"output": "-1"
},
{
"input": "7 14\n3 6\n2 3\n5 2\n5 6\n7 5\n7 4\n6 2\n3 5\n7 1\n4 1\n6 1\n7 6\n6 4\n5 4",
"output": "5"
},
{
... | 1,441,205,210 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 264 | 1,126,400 | def main():
M = int(1e12) # $$ +\infty $$
n, m = map(int, input().split())
graph = [set() for _ in range(n + 1)]
edges = []
for _ in range(m):
a, b = map(int, input().split())
edges += [(a, b)]
graph[a] |= {b}
graph[b] |= {a}
res = M
for a, b i... | Title: Bear and Three Musketeers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Do you know a story about the three musketeers? Anyway, you will learn about its origins now.
Richelimakieu is a cardinal in the city of Bearis. He is tired of dealing with crime by himself. He needs three br... | ```python
def main():
M = int(1e12) # $$ +\infty $$
n, m = map(int, input().split())
graph = [set() for _ in range(n + 1)]
edges = []
for _ in range(m):
a, b = map(int, input().split())
edges += [(a, b)]
graph[a] |= {b}
graph[b] |= {a}
res = M
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,484,517,765 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 186 | 9,830,400 | l = list(map(int, input()))
try:
l.remove(0)
print("".join(map(str, l)))
except:
l.remove(1)
print("".join(map(str, l)))
| Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
l = list(map(int, input()))
try:
l.remove(0)
print("".join(map(str, l)))
except:
l.remove(1)
print("".join(map(str, l)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,665,650,038 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 202 | 4,096,000 | # -*- coding: utf-8 -*-
"""
Created on Thu Oct 13 16:24:41 2022
@author: lenovo
"""
n,t=map(int, input().split())
s=list(map(int, input().split()))
v=[s[0]]
for i in s:
v.append(s.index(i)+1+i)
print('YES' if t in v else 'NO') | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
# -*- coding: utf-8 -*-
"""
Created on Thu Oct 13 16:24:41 2022
@author: lenovo
"""
n,t=map(int, input().split())
s=list(map(int, input().split()))
v=[s[0]]
for i in s:
v.append(s.index(i)+1+i)
print('YES' if t in v else 'NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
393 | A | Nineteen | PROGRAMMING | 0 | [] | null | null | Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) ... | The first line contains a non-empty string *s*, consisting only of lowercase English letters. The length of string *s* doesn't exceed 100. | Print a single integer — the maximum number of "nineteen"s that she can get in her string. | [
"nniinneetteeeenn\n",
"nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii\n",
"nineteenineteen\n"
] | [
"2",
"2",
"2"
] | none | 500 | [
{
"input": "nniinneetteeeenn",
"output": "2"
},
{
"input": "nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii",
"output": "2"
},
{
"input": "nineteenineteen",
"output": "2"
},
{
"input": "nssemsnnsitjtihtthij",
"output": "0"
},
{
"input": "eehihnttehtherjsihihn... | 1,676,889,704 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 62 | 0 | s = input().strip()
n = s.count('n')
e = s.count('e')
i = s.count('i')
t = s.count('t')
n=int((n-1)/2)
e=int(e/3)
print(min(n,e,i,t)) | Title: Nineteen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiinetee... | ```python
s = input().strip()
n = s.count('n')
e = s.count('e')
i = s.count('i')
t = s.count('t')
n=int((n-1)/2)
e=int(e/3)
print(min(n,e,i,t))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,696,782,343 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 124 | 3,072,000 | for _ in range(int(input())):
a = str(input())
d += a[0]
t = 1
q = d.count('0')
if q==0:
q = 1000000
o = d.count("1")
if o==0:
o = 1000000
v = min(q,o)
if v==q:
v = '0'
else:
v = '1'
p = (d.split(str(v)))
for i in range(len(p)):
if (p[i] != ''):
t += 1
print (t)
... | Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
for _ in range(int(input())):
a = str(input())
d += a[0]
t = 1
q = d.count('0')
if q==0:
q = 1000000
o = d.count("1")
if o==0:
o = 1000000
v = min(q,o)
if v==q:
v = '0'
else:
v = '1'
p = (d.split(str(v)))
for i in range(len(p)):
if (p[i] != ''):
t += 1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
5 | C | Longest Regular Bracket Sequence | PROGRAMMING | 1,900 | [
"constructive algorithms",
"data structures",
"dp",
"greedy",
"sortings",
"strings"
] | C. Longest Regular Bracket Sequence | 2 | 256 | This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical expression. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.... | The first line of the input file contains a non-empty string, consisting of «(» and «)» characters. Its length does not exceed 106. | Print the length of the longest substring that is a regular bracket sequence, and the number of such substrings. If there are no such substrings, write the only line containing "0 1". | [
")((())))(()())\n",
"))(\n"
] | [
"6 2\n",
"0 1\n"
] | none | 0 | [
{
"input": ")((())))(()())",
"output": "6 2"
},
{
"input": "))(",
"output": "0 1"
},
{
"input": "()(())()",
"output": "8 1"
},
{
"input": "((((()(((",
"output": "2 1"
},
{
"input": "))))()())))",
"output": "4 1"
},
{
"input": "(()())()(())()()())())()(... | 1,578,142,262 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 840 | 62,668,800 | s = input()
dp, m, c, mx = [0], {0:-1}, 0, 0
for i in range(len(s)):
if s[i] == '(':
dp.append(0)
c += 1
else:
c -= 1
j = m.get(c, -2)
if j == -2:
dp.append(0)
else:
dp.append(dp[j + 1] + i - j)
mx = max(mx, dp[-1])
... | Title: Longest Regular Bracket Sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical exp... | ```python
s = input()
dp, m, c, mx = [0], {0:-1}, 0, 0
for i in range(len(s)):
if s[i] == '(':
dp.append(0)
c += 1
else:
c -= 1
j = m.get(c, -2)
if j == -2:
dp.append(0)
else:
dp.append(dp[j + 1] + i - j)
mx = max(mx, d... | 3.67327 | MatrixStudio/Codeforces-Python-Submissions |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,678,476,550 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 11 | 46 | 0 | n,m = list(map(int,input().split()))
x = str(m%10) * n
print(-1) if x == '0' else print(x) | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
n,m = list(map(int,input().split()))
x = str(m%10) * n
print(-1) if x == '0' else print(x)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
992 | A | Nastya and an Array | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second we can add an arbitrary (possibly negative) integer to all elements of the array that are not equal to ze... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the size of the array.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=105<=≤<=*a**i*<=≤<=105) — the elements of the array. | Print a single integer — the minimum number of seconds needed to make all elements of the array equal to zero. | [
"5\n1 1 1 1 1\n",
"3\n2 0 -1\n",
"4\n5 -6 -5 1\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first example you can add - 1 to all non-zero elements in one second and make them equal to zero.
In the second example you can add - 2 on the first second, then the array becomes equal to [0, 0, - 3]. On the second second you can add 3 to the third (the only non-zero) element. | 500 | [
{
"input": "5\n1 1 1 1 1",
"output": "1"
},
{
"input": "3\n2 0 -1",
"output": "2"
},
{
"input": "4\n5 -6 -5 1",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n21794 -79194",
"output": "2"
},
{
"input": "3\n-63526 95085 -5239",
... | 1,606,726,706 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 140 | 7,782,400 | num=input()
a=list(map(int,input().split()))
a=list(filter(lambda x:x!=0,a))
a=len(list(set(a)))
print(a)
| Title: Nastya and an Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nastya owns too many arrays now, so she wants to delete the least important of them. However, she discovered that this array is magic! Nastya now knows that the array has the following properties:
- In one second ... | ```python
num=input()
a=list(map(int,input().split()))
a=list(filter(lambda x:x!=0,a))
a=len(list(set(a)))
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
466 | A | Cheap Travel | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubles. Ann did the math; she will need to use subway *n* times. Help Ann, tell her what is the minimu... | The single line contains four space-separated integers *n*, *m*, *a*, *b* (1<=≤<=*n*,<=*m*,<=*a*,<=*b*<=≤<=1000) — the number of rides Ann has planned, the number of rides covered by the *m* ride ticket, the price of a one ride ticket and the price of an *m* ride ticket. | Print a single integer — the minimum sum in rubles that Ann will need to spend. | [
"6 2 1 2\n",
"5 2 2 3\n"
] | [
"6\n",
"8\n"
] | In the first sample one of the optimal solutions is: each time buy a one ride ticket. There are other optimal solutions. For example, buy three *m* ride tickets. | 500 | [
{
"input": "6 2 1 2",
"output": "6"
},
{
"input": "5 2 2 3",
"output": "8"
},
{
"input": "10 3 5 1",
"output": "4"
},
{
"input": "1000 1 1000 1000",
"output": "1000000"
},
{
"input": "1000 3 1000 1000",
"output": "334000"
},
{
"input": "1 1 1 1",
"... | 1,693,591,168 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n, m, a, b = map(int, input().split())
x1 = m / n
l = 0
l1 = 0
price = 0
price1 = 0
if b * m < a:
while l * m < n:
l += 1
price = l * b
if b < a * n:
while l1 * m < n:
l1 += 1
price1 = l1 * b
while l1 * m < n:
price1 += a
if price < price1:
print(price)
else:
print... | Title: Cheap Travel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ann has recently started commuting by subway. We know that a one ride subway ticket costs *a* rubles. Besides, Ann found out that she can buy a special ticket for *m* rides (she can buy it several times). It costs *b* rubl... | ```python
n, m, a, b = map(int, input().split())
x1 = m / n
l = 0
l1 = 0
price = 0
price1 = 0
if b * m < a:
while l * m < n:
l += 1
price = l * b
if b < a * n:
while l1 * m < n:
l1 += 1
price1 = l1 * b
while l1 * m < n:
price1 += a
if price < price1:
print(price)
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
842 | C | Ilya And The Tree | PROGRAMMING | 2,000 | [
"dfs and similar",
"graphs",
"math",
"number theory",
"trees"
] | null | null | Ilya is very fond of graphs, especially trees. During his last trip to the forest Ilya found a very interesting tree rooted at vertex 1. There is an integer number written on each vertex of the tree; the number written on vertex *i* is equal to *a**i*.
Ilya believes that the beauty of the vertex *x* is the greatest co... | First line contains one integer number *n* — the number of vertices in tree (1<=≤<=*n*<=≤<=2·105).
Next line contains *n* integer numbers *a**i* (1<=≤<=*i*<=≤<=*n*, 1<=≤<=*a**i*<=≤<=2·105).
Each of next *n*<=-<=1 lines contains two integer numbers *x* and *y* (1<=≤<=*x*,<=*y*<=≤<=*n*, *x*<=≠<=*y*), which means that t... | Output *n* numbers separated by spaces, where *i*-th number equals to maximum possible beauty of vertex *i*. | [
"2\n6 2\n1 2\n",
"3\n6 2 3\n1 2\n1 3\n",
"1\n10\n"
] | [
"6 6 \n",
"6 6 6 \n",
"10 \n"
] | none | 1,500 | [
{
"input": "2\n6 2\n1 2",
"output": "6 6 "
},
{
"input": "3\n6 2 3\n1 2\n1 3",
"output": "6 6 6 "
},
{
"input": "1\n10",
"output": "10 "
},
{
"input": "10\n2 3 4 5 6 7 8 9 10 11\n1 2\n2 3\n3 4\n4 5\n5 6\n6 7\n4 8\n8 9\n9 10",
"output": "2 3 2 1 1 1 1 1 1 1 "
},
{
... | 1,697,923,540 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 716,800 | # for I/O for local system
import sys
from os import path
if(path.exists('Input.txt')):
sys.stdin = open('Input.txt','r')
sys.stdout = open('Output.txt','w')
# For fast I/O
input = sys.stdin.buffer.readline
# input = sys.stdin.readline
print = sys.stdout.write
# Import libraries here whenever required
from ... | Title: Ilya And The Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya is very fond of graphs, especially trees. During his last trip to the forest Ilya found a very interesting tree rooted at vertex 1. There is an integer number written on each vertex of the tree; the number writte... | ```python
# for I/O for local system
import sys
from os import path
if(path.exists('Input.txt')):
sys.stdin = open('Input.txt','r')
sys.stdout = open('Output.txt','w')
# For fast I/O
input = sys.stdin.buffer.readline
# input = sys.stdin.readline
print = sys.stdout.write
# Import libraries here whenever requ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for ... | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use al... | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,569,349,120 | 2,147,483,647 | PyPy 3 | OK | TESTS | 39 | 140 | 0 | n,k = map(int,input().split())
a = list(map(int,input().split()))
dist = [0]*n
l = []
pos = 0
aux = 0
for i in range(n):
dist[i] = a[i],i+1
dist = sorted(dist)
soma = dist[0][0]
while(soma <= k):
pos+=1
aux+=1
if(pos >= n):
break
soma += dist[pos][0]
for i in range(aux):
l.append(str(dist[i][1]))
l = sorted(l... | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr ... | ```python
n,k = map(int,input().split())
a = list(map(int,input().split()))
dist = [0]*n
l = []
pos = 0
aux = 0
for i in range(n):
dist[i] = a[i],i+1
dist = sorted(dist)
soma = dist[0][0]
while(soma <= k):
pos+=1
aux+=1
if(pos >= n):
break
soma += dist[pos][0]
for i in range(aux):
l.append(str(dist[i][1]))
l ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
334 | A | Candy Bags | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from 1 to *n*2 he has exactly one bag with *k* candies.
Help him give *n* bags of candies to each b... | The single line contains a single integer *n* (*n* is even, 2<=≤<=*n*<=≤<=100) — the number of Gerald's brothers. | Let's assume that Gerald indexes his brothers with numbers from 1 to *n*. You need to print *n* lines, on the *i*-th line print *n* integers — the numbers of candies in the bags for the *i*-th brother. Naturally, all these numbers should be distinct and be within limits from 1 to *n*2. You can print the numbers in the ... | [
"2\n"
] | [
"1 4\n2 3\n"
] | The sample shows Gerald's actions if he has two brothers. In this case, his bags contain 1, 2, 3 and 4 candies. He can give the bags with 1 and 4 candies to one brother and the bags with 2 and 3 to the other brother. | 500 | [
{
"input": "2",
"output": "1 4\n2 3"
},
{
"input": "4",
"output": "1 16 2 15\n3 14 4 13\n5 12 6 11\n7 10 8 9"
},
{
"input": "6",
"output": "1 36 2 35 3 34\n4 33 5 32 6 31\n7 30 8 29 9 28\n10 27 11 26 12 25\n13 24 14 23 15 22\n16 21 17 20 18 19"
},
{
"input": "8",
"output"... | 1,667,485,160 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | n=int(input())
for i in range(1,int(n**2/2+1)):
print('%d %d'%(i,n**2-i+1)) | Title: Candy Bags
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from ... | ```python
n=int(input())
for i in range(1,int(n**2/2+1)):
print('%d %d'%(i,n**2-i+1))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
171 | B | Star | PROGRAMMING | 1,300 | [
"*special",
"combinatorics"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257). | Print a single integer *output* (1<=≤<=*output*<=≤<=2·109). | [
"2\n"
] | [
"13"
] | none | 0 | [
{
"input": "2",
"output": "13"
},
{
"input": "1",
"output": "1"
},
{
"input": "3",
"output": "37"
},
{
"input": "4",
"output": "73"
},
{
"input": "5",
"output": "121"
},
{
"input": "6",
"output": "181"
},
{
"input": "7",
"output": "253"... | 1,585,568,773 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 0 | a = input()
s = []
for i in a:
s.append(i-1,i+1)
z = ''.join(s)
print(z) | Title: Star
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257).
Output Specification:
Print a single integer *output* (1<=≤<=*output*<=≤<=2·109).
Demo Input:
['2\n']
Demo Output:
['13']
Note:
none | ```python
a = input()
s = []
for i in a:
s.append(i-1,i+1)
z = ''.join(s)
print(z)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | ||
251 | A | Points on Line | PROGRAMMING | 1,300 | [
"binary search",
"combinatorics",
"two pointers"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen... | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input stri... | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 500 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,598,924,911 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 154 | 307,200 | def comb(a, b):
return a & (1<<b)
def valido(lista, l, h, d):
#print(str(l) + " " + str(h) + " " + str(d))
if lista[h] - lista[l] <= d:
print(*lista, sep=" - ")
return True
return False
def points(v, n, d):
cont = 0
lista = []
for i in range(1<<n):
for j in range(n):
if comb(i, j) > 0:
lista.appe... | Title: Points on Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two fart... | ```python
def comb(a, b):
return a & (1<<b)
def valido(lista, l, h, d):
#print(str(l) + " " + str(h) + " " + str(d))
if lista[h] - lista[l] <= d:
print(*lista, sep=" - ")
return True
return False
def points(v, n, d):
cont = 0
lista = []
for i in range(1<<n):
for j in range(n):
if comb(i, j) > 0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,679,237,728 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 46 | 0 | n=input().split()
k=int(n[0])
r=int(n[1])
i=1
count=0
while True:
count+=1
if k%10==0:
break
elif (k*i)%10==0:
break
elif ((k*i)-r)%10==0:
break
i+=1
print(count)
| Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
n=input().split()
k=int(n[0])
r=int(n[1])
i=1
count=0
while True:
count+=1
if k%10==0:
break
elif (k*i)%10==0:
break
elif ((k*i)-r)%10==0:
break
i+=1
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,648,324,950 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a=[int(i) for i in input()]
c=0
while len(a)>1:
x=str(sum(a))
y=[int(i) for in x]
c+=1
print(c)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
a=[int(i) for i in input()]
c=0
while len(a)>1:
x=str(sum(a))
y=[int(i) for in x]
c+=1
print(c)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,561,572,818 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 218 | 0 | l=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,0]
n=(input()).split()
# print(n)
m=int(n[1])
n=int(n[0])
# print(n,m)
# m=int(input())
if l[l.index((n))+1] == m:
print('YES')
else:
print('NO') | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
l=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,0]
n=(input()).split()
# print(n)
m=int(n[1])
n=int(n[0])
# print(n,m)
# m=int(input())
if l[l.index((n))+1] == m:
print('YES')
else:
print('NO')
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,629,142,687 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 218 | 20,172,800 | a , b = input().split(' ')
m = int(a)
n = int(b)
s = m*n
f = int(s/2)
print(f) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
a , b = input().split(' ')
m = int(a)
n = int(b)
s = m*n
f = int(s/2)
print(f)
``` | 3.907925 | MatrixStudio/Codeforces-Python-Submissions |
929 | A | Прокат велосипедов | PROGRAMMING | 1,400 | [
"*special",
"greedy",
"implementation"
] | null | null | Как известно, в теплую погоду многие жители крупных городов пользуются сервисами городского велопроката. Вот и Аркадий сегодня будет добираться от школы до дома, используя городские велосипеды.
Школа и дом находятся на одной прямой улице, кроме того, на той же улице есть *n* точек, где можно взять велосипед в прокат и... | В первой строке следуют два целых числа *n* и *k* (2<=≤<=*n*<=≤<=1<=000, 1<=≤<=*k*<=≤<=100<=000) — количество велопрокатов и максимальное расстояние, которое Аркадий может проехать на одном велосипеде.
В следующей строке следует последовательность целых чисел *x*1,<=*x*2,<=...,<=*x**n* (0<=≤<=*x*1<=<<=*x*2<=<<=.... | Если Аркадий не сможет добраться от школы до дома только на велосипедах, выведите -1. В противном случае, выведите минимальное количество велосипедов, которые Аркадию нужно взять в точках проката. | [
"4 4\n3 6 8 10\n",
"2 9\n10 20\n",
"12 3\n4 6 7 9 10 11 13 15 17 18 20 21\n"
] | [
"2\n",
"-1\n",
"6\n"
] | В первом примере Аркадий должен взять первый велосипед в первом велопрокате и доехать на нём до второго велопроката. Во втором велопрокате он должен взять новый велосипед, на котором он сможет добраться до четвертого велопроката, рядом с которым и находится его дом. Поэтому Аркадию нужно всего два велосипеда, чтобы доб... | 500 | [
{
"input": "4 4\n3 6 8 10",
"output": "2"
},
{
"input": "2 9\n10 20",
"output": "-1"
},
{
"input": "12 3\n4 6 7 9 10 11 13 15 17 18 20 21",
"output": "6"
},
{
"input": "2 1\n11164 11165",
"output": "1"
},
{
"input": "3 7\n45823 45825 45829",
"output": "1"
},... | 1,520,079,437 | 74,537 | Python 3 | OK | TESTS | 52 | 77 | 5,632,000 | a = input()
r = a.split(' ')
n = r[0]
k = r[1]
points = input().split(' ')
numVel = 1
curPoint = 0
error = False
while curPoint != len(points) - 1 and not error:
maxDist = int(points[curPoint]) + int(k)
for j in range(curPoint + 1, len(points)):
if int(points[j]) > maxDist:
n... | Title: Прокат велосипедов
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Как известно, в теплую погоду многие жители крупных городов пользуются сервисами городского велопроката. Вот и Аркадий сегодня будет добираться от школы до дома, используя городские велосипеды.
Школа и дом находятся... | ```python
a = input()
r = a.split(' ')
n = r[0]
k = r[1]
points = input().split(' ')
numVel = 1
curPoint = 0
error = False
while curPoint != len(points) - 1 and not error:
maxDist = int(points[curPoint]) + int(k)
for j in range(curPoint + 1, len(points)):
if int(points[j]) > maxDist:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
932 | B | Recursive Queries | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"dfs and similar"
] | null | null | Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x* between *l* and *r* inclusive, such that *g*(*x*)<==<=*k*. | The first line of the input contains an integer *Q* (1<=≤<=*Q*<=≤<=2<=×<=105) representing the number of queries.
*Q* lines follow, each of which contains 3 integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=106,<=1<=≤<=*k*<=≤<=9). | For each query, print a single line containing the answer for that query. | [
"4\n22 73 9\n45 64 6\n47 55 7\n2 62 4\n",
"4\n82 94 6\n56 67 4\n28 59 9\n39 74 4\n"
] | [
"1\n4\n0\n8\n",
"3\n1\n1\n5\n"
] | In the first example:
- *g*(33) = 9 as *g*(33) = *g*(3 × 3) = *g*(9) = 9 - *g*(47) = *g*(48) = *g*(60) = *g*(61) = 6 - There are no such integers between 47 and 55. - *g*(4) = *g*(14) = *g*(22) = *g*(27) = *g*(39) = *g*(40) = *g*(41) = *g*(58) = 4 | 1,000 | [
{
"input": "4\n22 73 9\n45 64 6\n47 55 7\n2 62 4",
"output": "1\n4\n0\n8"
},
{
"input": "4\n82 94 6\n56 67 4\n28 59 9\n39 74 4",
"output": "3\n1\n1\n5"
}
] | 1,518,757,930 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 5,632,000 | def f(n):
k=len(str(n))
x=str(n);
c=1
for i in range(0,k):
if(x[i]!='0'):
c=c*int(x[i]);
return c;
def g(n):
if(len(str(n))==1):
return int(n);
else:
return g(f(n))
q=int(input())
for t in range(1,q+1):
b=0
l,r,s=map(int,input().split())
f... | Title: Recursive Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let us define two functions *f* and *g* on positive integer numbers.
You need to process *Q* queries. In each query, you will be given three integers *l*, *r* and *k*. You need to print the number of integers *x*... | ```python
def f(n):
k=len(str(n))
x=str(n);
c=1
for i in range(0,k):
if(x[i]!='0'):
c=c*int(x[i]);
return c;
def g(n):
if(len(str(n))==1):
return int(n);
else:
return g(f(n))
q=int(input())
for t in range(1,q+1):
b=0
l,r,s=map(int,input().split... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
20 | A | BerOS file system | PROGRAMMING | 1,700 | [
"implementation"
] | A. BerOS file system | 2 | 64 | The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/nginx///sbin are equivalent. The character '/' (or some sequence of such characters) at the end of ... | The first line of the input contains only lowercase Latin letters and character '/' — the path to some directory. All paths start with at least one character '/'. The length of the given line is no more than 100 characters, it is not empty. | The path in normalized form. | [
"//usr///local//nginx/sbin\n"
] | [
"/usr/local/nginx/sbin\n"
] | none | 500 | [
{
"input": "//usr///local//nginx/sbin",
"output": "/usr/local/nginx/sbin"
},
{
"input": "////a//b/////g",
"output": "/a/b/g"
},
{
"input": "/a/b/c",
"output": "/a/b/c"
},
{
"input": "/",
"output": "/"
},
{
"input": "////",
"output": "/"
},
{
"input": "... | 1,641,922,813 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 92 | 0 | print(('/'.join(('.'+input()+'.').replace('/', ' ').split()))[1:-1]) | Title: BerOS file system
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
The new operating system BerOS has a nice feature. It is possible to use any number of characters '/' as a delimiter in path instead of one traditional '/'. For example, strings //usr///local//nginx/sbin// and /usr/local/n... | ```python
print(('/'.join(('.'+input()+'.').replace('/', ' ').split()))[1:-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,688,035,337 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 |
def original_string():
n = int(input())
skills = list(map(int, input().split()))
programmers = []
mathematicians = []
sportsmen = []
for i, skill in enumerate(skills, 0):
if skill == 1:
programmers.append(i)
if skill == 2:
mathematicians.ap... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
def original_string():
n = int(input())
skills = list(map(int, input().split()))
programmers = []
mathematicians = []
sportsmen = []
for i, skill in enumerate(skills, 0):
if skill == 1:
programmers.append(i)
if skill == 2:
mathema... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,685,097,125 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | n = input()
for ch in n:
if ch == 'H' or ch == 'Q' or ch == '9':
print("YES")
exit()
print("NO")
| Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
n = input()
for ch in n:
if ch == 'H' or ch == 'Q' or ch == '9':
print("YES")
exit()
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,685,358,647 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 62 | 0 | def sos(a):
for i in range(2, a - 1):
if a % i == 0:
return True
return False
a = int(input())
for i in range(2, a):
if sos(i) and sos(a-i):
print(f"{i} {a-i}")
break | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
def sos(a):
for i in range(2, a - 1):
if a % i == 0:
return True
return False
a = int(input())
for i in range(2, a):
if sos(i) and sos(a-i):
print(f"{i} {a-i}")
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,658,068,088 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | t,xstart,ystart,xend,yend = map(int,input().split())
wind = input()
neededX = ''
neededx_moves = 0
neededY = ''
neededy_moves = 0
if xend >xstart :
neededX = 'E'
neededx_moves = (xend - xstart)
if xend <xstart :
neededX = 'W'
neededx_moves = (xstart - xend)
if yend >ystart :
neededY = 'N'
n... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
t,xstart,ystart,xend,yend = map(int,input().split())
wind = input()
neededX = ''
neededx_moves = 0
neededY = ''
neededy_moves = 0
if xend >xstart :
neededX = 'E'
neededx_moves = (xend - xstart)
if xend <xstart :
neededX = 'W'
neededx_moves = (xstart - xend)
if yend >ystart :
neededY ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
625 | B | War of the Corporations | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"strings"
] | null | null | A long time ago, in a galaxy far far away two giant IT-corporations Pineapple and Gogol continue their fierce competition. Crucial moment is just around the corner: Gogol is ready to release it's new tablet Lastus 3000.
This new device is equipped with specially designed artificial intelligence (AI). Employees of Pine... | The first line of the input contains the name of AI designed by Gogol, its length doesn't exceed 100<=000 characters. Second line contains the name of the phone released by Pineapple 200 years ago, its length doesn't exceed 30. Both string are non-empty and consist of only small English letters. | Print the minimum number of characters that must be replaced with "#" in order to obtain that the name of the phone doesn't occur in the name of AI as a substring. | [
"intellect\ntell\n",
"google\napple\n",
"sirisiri\nsir\n"
] | [
"1",
"0",
"2"
] | In the first sample AI's name may be replaced with "int#llect".
In the second sample Gogol can just keep things as they are.
In the third sample one of the new possible names of AI may be "s#ris#ri". | 750 | [
{
"input": "intellect\ntell",
"output": "1"
},
{
"input": "google\napple",
"output": "0"
},
{
"input": "sirisiri\nsir",
"output": "2"
},
{
"input": "sirisiri\nsiri",
"output": "2"
},
{
"input": "aaaaaaa\naaaa",
"output": "1"
},
{
"input": "bbbbbb\nbb",... | 1,484,961,351 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 6 | 61 | 4,608,000 | # print("Input the big string")
big = input()
# print("Input the small string")
small = input()
if len(small) > len(big):
print(0)
else:
answer = 0
starti = 0
while (starti + len(small) <= len(big)):
if big[starti:starti+len(small)] == small:
answer += 1
# Can go all the... | Title: War of the Corporations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A long time ago, in a galaxy far far away two giant IT-corporations Pineapple and Gogol continue their fierce competition. Crucial moment is just around the corner: Gogol is ready to release it's new tablet Last... | ```python
# print("Input the big string")
big = input()
# print("Input the small string")
small = input()
if len(small) > len(big):
print(0)
else:
answer = 0
starti = 0
while (starti + len(small) <= len(big)):
if big[starti:starti+len(small)] == small:
answer += 1
# Can ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,692,928,752 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 124 | 102,400 | def timing():
t, sx, sy, ex, ey = map(int, input().split())
s = input()
for x in range(len(s)):
if s[x] == "E" and ex > sx:
sx = sx + 1
sy = sy
if s[x] == "S" and ey < sy:
sx = sx
sy = sy - 1
if s[x] == "W" and ex < sx:
... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
def timing():
t, sx, sy, ex, ey = map(int, input().split())
s = input()
for x in range(len(s)):
if s[x] == "E" and ex > sx:
sx = sx + 1
sy = sy
if s[x] == "S" and ey < sy:
sx = sx
sy = sy - 1
if s[x] == "W" and ex < ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of len... | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length o... | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-form... | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,593,413,677 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 78 | 6,963,200 | a=input()
a=int(a)
b=input()
b=int(b)
c=input()
c=int(c)
d=0
if a>b:
d+=b
if a+b>c:
d+=c
else:
d+=a
d+=b
d+=a
else:
d+=a
if a+b>c:
d+=c
else:
d+=a
d+=b
d+=b
print(d)
| Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the... | ```python
a=input()
a=int(a)
b=input()
b=int(b)
c=input()
c=int(c)
d=0
if a>b:
d+=b
if a+b>c:
d+=c
else:
d+=a
d+=b
d+=a
else:
d+=a
if a+b>c:
d+=c
else:
d+=a
d+=b
d+=b
print(d)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
747 | B | Mammoth's Genome Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, *s... | The first line contains the integer *n* (4<=≤<=*n*<=≤<=255) — the length of the genome.
The second line contains the string *s* of length *n* — the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'. | If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes). | [
"8\nAG?C??CT\n",
"4\nAGCT\n",
"6\n????G?\n",
"4\nAA??\n"
] | [
"AGACGTCT\n",
"AGCT\n",
"===\n",
"===\n"
] | In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is ... | 1,000 | [
{
"input": "8\nAG?C??CT",
"output": "AGACGTCT"
},
{
"input": "4\nAGCT",
"output": "AGCT"
},
{
"input": "6\n????G?",
"output": "==="
},
{
"input": "4\nAA??",
"output": "==="
},
{
"input": "4\n????",
"output": "ACGT"
},
{
"input": "252\n???????GCG??T??TT... | 1,486,083,881 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 4,608,000 | n = int(input())
gen = input()
A = gen.count("A")
C = gen.count("C")
G = gen.count("G")
T = gen.count("T")
m = max(A, C, G, T)
gen = gen.replace("?", "A", m-A)
gen = gen.replace("?", "C", m-C)
gen = gen.replace("?", "G", m-G)
gen = gen.replace("?", "T", m-T)
A = gen.count("A")
C = gen.count("C")
G = gen.count("G")
T = ... | Title: Mammoth's Genome Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter... | ```python
n = int(input())
gen = input()
A = gen.count("A")
C = gen.count("C")
G = gen.count("G")
T = gen.count("T")
m = max(A, C, G, T)
gen = gen.replace("?", "A", m-A)
gen = gen.replace("?", "C", m-C)
gen = gen.replace("?", "G", m-G)
gen = gen.replace("?", "T", m-T)
A = gen.count("A")
C = gen.count("C")
G = gen.count... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
304 | A | Pythagorean Theorem II | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the s... | The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above. | Print a single integer — the answer to the problem. | [
"5\n",
"74\n"
] | [
"1\n",
"35\n"
] | none | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "74",
"output": "35"
},
{
"input": "1000",
"output": "881"
},
{
"input": "586",
"output": "472"
},
{
"input": "2",
"output": "0"
},
{
"input": "362",
"output": "258"
},
{
"input": "778",
"outp... | 1,557,120,224 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 30 | 3,000 | 716,800 | n = int(input())
count = 0
for i in range(1, n - 1):
for j in range(i + 1, n):
for k in range(j + 1, n + 1):
if i ** 2 + j **2 == k**2:
count +=1
print(count)
| Title: Pythagorean Theorem II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the squar... | ```python
n = int(input())
count = 0
for i in range(1, n - 1):
for j in range(i + 1, n):
for k in range(j + 1, n + 1):
if i ** 2 + j **2 == k**2:
count +=1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
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