contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
372 | A | Counting Kangaroos is Fun | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"sortings",
"two pointers"
] | null | null | There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as large as the size of kangaroo who is held.
Each kangaroo can hold at most one kangaroo, and the kangaroo who i... | The first line contains a single integer — *n* (1<=≤<=*n*<=≤<=5·105). Each of the next *n* lines contains an integer *s**i* — the size of the *i*-th kangaroo (1<=≤<=*s**i*<=≤<=105). | Output a single integer — the optimal number of visible kangaroos. | [
"8\n2\n5\n7\n6\n9\n8\n4\n2\n",
"8\n9\n1\n6\n2\n6\n5\n8\n3\n"
] | [
"5\n",
"5\n"
] | none | 500 | [
{
"input": "8\n2\n5\n7\n6\n9\n8\n4\n2",
"output": "5"
},
{
"input": "8\n9\n1\n6\n2\n6\n5\n8\n3",
"output": "5"
},
{
"input": "12\n3\n99\n24\n46\n75\n63\n57\n55\n10\n62\n34\n52",
"output": "7"
},
{
"input": "12\n55\n75\n1\n98\n63\n64\n9\n39\n82\n18\n47\n9",
"output": "6"
... | 1,681,952,916 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 11,878,400 | t = int(input())
q =t
l = []
for i in range(t):
l.append(int(input()))
l.sort()
n = 0
m = int(t/2)
k = int(t/2)
while(n<k and m<t):
if(l[n] <= l[m]/2):
q -=1
n +=1
m +=1
print(q)
| Title: Counting Kangaroos is Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as ... | ```python
t = int(input())
q =t
l = []
for i in range(t):
l.append(int(input()))
l.sort()
n = 0
m = int(t/2)
k = int(t/2)
while(n<k and m<t):
if(l[n] <= l[m]/2):
q -=1
n +=1
m +=1
print(q)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,654,649,568 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 46 | 0 | n,d=map(int,input().split())
t=list(map(int,input().split()))
timeNeeded=sum(t)+(len(t)-1)*10
if timeNeeded>d:
print(-1)
else:
print((d-sum(t))//5)
| Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
n,d=map(int,input().split())
t=list(map(int,input().split()))
timeNeeded=sum(t)+(len(t)-1)*10
if timeNeeded>d:
print(-1)
else:
print((d-sum(t))//5)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
48 | A | Rock-paper-scissors | PROGRAMMING | 900 | [
"implementation",
"schedules"
] | A. Rock-paper-scissors | 2 | 256 | Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obvio... | The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture. | Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?". | [
"rock\nrock\nrock\n",
"paper\nrock\nrock\n",
"scissors\nrock\nrock\n",
"scissors\npaper\nrock\n"
] | [
"?\n",
"F\n",
"?\n",
"?\n"
] | none | 0 | [
{
"input": "rock\nrock\nrock",
"output": "?"
},
{
"input": "paper\nrock\nrock",
"output": "F"
},
{
"input": "scissors\nrock\nrock",
"output": "?"
},
{
"input": "scissors\npaper\nrock",
"output": "?"
},
{
"input": "paper\npaper\nrock",
"output": "?"
},
{
... | 1,630,861,627 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 124 | 6,758,400 | beat_dic={'rock':'scissors','paper':'rock','scissors':'paper'}
hands=[input() for i in range(3)]
for i in range(3):
if hands[i-1]==hands[i-2]==beat_dic[hands[i]]:
print('FMS'[i])
exit()
print('?')
| Title: Rock-paper-scissors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case ... | ```python
beat_dic={'rock':'scissors','paper':'rock','scissors':'paper'}
hands=[input() for i in range(3)]
for i in range(3):
if hands[i-1]==hands[i-2]==beat_dic[hands[i]]:
print('FMS'[i])
exit()
print('?')
``` | 3.956411 | MatrixStudio/Codeforces-Python-Submissions |
10 | D | LCIS | PROGRAMMING | 2,800 | [
"dp"
] | D. LCIS | 1 | 256 | This problem differs from one which was on the online contest.
The sequence *a*1,<=*a*2,<=...,<=*a**n* is called increasing, if *a**i*<=<<=*a**i*<=+<=1 for *i*<=<<=*n*.
The sequence *s*1,<=*s*2,<=...,<=*s**k* is called the subsequence of the sequence *a*1,<=*a*2,<=...,<=*a**n*, if there exist such a set of inde... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=500) — the length of the first sequence. The second line contains *n* space-separated integers from the range [0,<=109] — elements of the first sequence. The third line contains an integer *m* (1<=≤<=*m*<=≤<=500) — the length of the second sequence. The fourth line ... | In the first line output *k* — the length of the longest common increasing subsequence. In the second line output the subsequence itself. Separate the elements with a space. If there are several solutions, output any. | [
"7\n2 3 1 6 5 4 6\n4\n1 3 5 6\n",
"5\n1 2 0 2 1\n3\n1 0 1\n"
] | [
"3\n3 5 6 \n",
"2\n0 1 \n"
] | none | 0 | [
{
"input": "7\n2 3 1 6 5 4 6\n4\n1 3 5 6",
"output": "3\n3 5 6 "
},
{
"input": "5\n1 2 0 2 1\n3\n1 0 1",
"output": "2\n0 1 "
},
{
"input": "2\n6 10\n3\n6 3 3",
"output": "1\n6 "
},
{
"input": "1\n7\n2\n7 9",
"output": "1\n7 "
},
{
"input": "3\n37 49 24\n3\n33 5 70... | 1,682,701,977 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n = int(raw_input())
N = map(int, raw_input().split())
m = int(raw_input())
M = map(int, raw_input().split())
# t[r][c] stores the LCIS that *** ends with M[r] *** between N[0..c} and M[0..r]
t = [[0 for i in xrange(n)] for j in xrange(m)]
pre = [-1 for i in xrange(m)]
for r in xrange(m):
# p is the len o... | Title: LCIS
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
This problem differs from one which was on the online contest.
The sequence *a*1,<=*a*2,<=...,<=*a**n* is called increasing, if *a**i*<=<<=*a**i*<=+<=1 for *i*<=<<=*n*.
The sequence *s*1,<=*s*2,<=...,<=*s**k* is called the sub... | ```python
n = int(raw_input())
N = map(int, raw_input().split())
m = int(raw_input())
M = map(int, raw_input().split())
# t[r][c] stores the LCIS that *** ends with M[r] *** between N[0..c} and M[0..r]
t = [[0 for i in xrange(n)] for j in xrange(m)]
pre = [-1 for i in xrange(m)]
for r in xrange(m):
# p is... | -1 | MatrixStudio/Codeforces-Python-Submissions |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,468,911,181 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 92 | 0 | count = int(input())
horizontal = []
vertical = []
for i in range(count*count):
h,v = map(int, input().split())
if not(h in horizontal or v in vertical):
horizontal.append(h)
vertical.append(v)
print(i+1)
| Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
count = int(input())
horizontal = []
vertical = []
for i in range(count*count):
h,v = map(int, input().split())
if not(h in horizontal or v in vertical):
horizontal.append(h)
vertical.append(v)
print(i+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
535 | A | Tavas and Nafas | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.
He ate coffee mix without... | The first and only line of input contains an integer *s* (0<=≤<=*s*<=≤<=99), Tavas's score. | In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces. | [
"6\n",
"99\n",
"20\n"
] | [
"six\n",
"ninety-nine\n",
"twenty\n"
] | You can find all you need to know about English numerals in [http://en.wikipedia.org/wiki/English_numerals](https://en.wikipedia.org/wiki/English_numerals) . | 500 | [
{
"input": "6",
"output": "six"
},
{
"input": "99",
"output": "ninety-nine"
},
{
"input": "20",
"output": "twenty"
},
{
"input": "10",
"output": "ten"
},
{
"input": "15",
"output": "fifteen"
},
{
"input": "27",
"output": "twenty-seven"
},
{
... | 1,596,381,448 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 77 | 6,963,200 | n = input()
l = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
m = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']
o = ['twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']
if int(n) > 19 and n[1] != ... | Title: Tavas and Nafas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score wit... | ```python
n = input()
l = ['one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']
m = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']
o = ['twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']
if int(n) > 19 an... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,679,585,523 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 1,945,600 | x=input().split(" ")
r,c=x
col=[]
for i in range(int(r)):
y=input().split(" ")
for j in y:
col+=[j]
cl=["B","W","G"]
count=0
for i in col:
if i in cl:
count+=1
if count==0:
print("#Color")
else:
print("#Black&White") | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
x=input().split(" ")
r,c=x
col=[]
for i in range(int(r)):
y=input().split(" ")
for j in y:
col+=[j]
cl=["B","W","G"]
count=0
for i in col:
if i in cl:
count+=1
if count==0:
print("#Color")
else:
print("#Black&White")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
846 | A | Curriculum Vitae | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zer... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100).
The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one. | Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one. | [
"4\n1 1 0 1\n",
"6\n0 1 0 0 1 0\n",
"1\n0\n"
] | [
"3\n",
"4\n",
"1\n"
] | none | 0 | [
{
"input": "4\n1 1 0 1",
"output": "3"
},
{
"input": "6\n0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "100\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,504,625,701 | 1,801 | PyPy 3 | OK | TESTS | 18 | 109 | 819,200 |
INF = 10 ** 9 + 7
def cutoff(games, pos):
leave = 0
for i, g in enumerate(games):
if i < pos:
if g == 0:
leave += 1
else:
if g == 1:
leave += 1
return leave
def main():
n = int(input())
games = [int(x) for x in input().... | Title: Curriculum Vitae
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* g... | ```python
INF = 10 ** 9 + 7
def cutoff(games, pos):
leave = 0
for i, g in enumerate(games):
if i < pos:
if g == 0:
leave += 1
else:
if g == 1:
leave += 1
return leave
def main():
n = int(input())
games = [int(x) for x i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
522 | B | Photo to Remember | PROGRAMMING | 1,100 | [
"*special",
"data structures",
"dp",
"implementation"
] | null | null | One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together.
Simply speaking, the process of taking photos can be described as follows. On the photo, each photographed friend occupies a rectangle of pixels: the *i*-th of them occupies the rectangl... | The first line contains integer *n* (2<=≤<=*n*<=≤<=200<=000) — the number of friends.
Then *n* lines follow: the *i*-th line contains information about the *i*-th friend. The line contains a pair of integers *w**i*,<=*h**i* (1<=≤<=*w**i*<=≤<=10,<=1<=≤<=*h**i*<=≤<=1000) — the width and height in pixels of the correspo... | Print *n* space-separated numbers *b*1,<=*b*2,<=...,<=*b**n*, where *b**i* — the total number of pixels on the minimum photo containing all friends expect for the *i*-th one. | [
"3\n1 10\n5 5\n10 1\n",
"3\n2 1\n1 2\n2 1\n"
] | [
"75 110 60 ",
"6 4 6 "
] | none | 1,000 | [
{
"input": "3\n1 10\n5 5\n10 1",
"output": "75 110 60 "
},
{
"input": "3\n2 1\n1 2\n2 1",
"output": "6 4 6 "
},
{
"input": "2\n1 5\n2 3",
"output": "6 5 "
},
{
"input": "2\n2 3\n1 1",
"output": "1 6 "
},
{
"input": "3\n1 10\n2 10\n3 10",
"output": "50 40 30 "
... | 1,687,985,013 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 14 | 2,000 | 11,468,800 | n = int(input())
width = []
height = []
width_sum = 0
for i in range(n):
s, t = map(int, input().split())
width.insert(i, s)
height.insert(i, t)
width_sum += width[i]
for i in range(n):
sub_w = (width_sum-width[i])
t = height[i]
height.pop(i)
sub_h = max(height)
height.... | Title: Photo to Remember
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together.
Simply speaking, the process of taking photos can be described as follows. On the p... | ```python
n = int(input())
width = []
height = []
width_sum = 0
for i in range(n):
s, t = map(int, input().split())
width.insert(i, s)
height.insert(i, t)
width_sum += width[i]
for i in range(n):
sub_w = (width_sum-width[i])
t = height[i]
height.pop(i)
sub_h = max(height)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
463 | B | Caisa and Pylons | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"math"
] | null | null | Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0 has zero height, the pylon with number *i* (*i*<=><=0) has height *h**i*. The goal of the game is ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *h*1, *h*2,<=..., *h**n* (1<=<=≤<=<=*h**i*<=<=≤<=<=105) representing the heights of the pylons. | Print a single number representing the minimum number of dollars paid by Caisa. | [
"5\n3 4 3 2 4\n",
"3\n4 4 4\n"
] | [
"4\n",
"4\n"
] | In the first sample he can pay 4 dollars and increase the height of pylon with number 0 by 4 units. Then he can safely pass to the last pylon. | 1,000 | [
{
"input": "5\n3 4 3 2 4",
"output": "4"
},
{
"input": "3\n4 4 4",
"output": "4"
},
{
"input": "99\n1401 2019 1748 3785 3236 3177 3443 3772 2138 1049 353 908 310 2388 1322 88 2160 2783 435 2248 1471 706 2468 2319 3156 3506 2794 1999 1983 2519 2597 3735 537 344 3519 3772 3872 2961 3895 20... | 1,627,895,084 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 155 | 14,438,400 | n=int(input())
l=list(map(int,input().split()))
count =l[0] #needed
e=0 #energy
for i in range(0,n-1):
if(l[i+1]>l[i]):
if(e):
e=e-(l[i+1]-l[i])
if(e>=0):
continue
else:
count=count+abs(e)
e=0
else:
... | Title: Caisa and Pylons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Caisa solved the problem with the sugar and now he is on the way back to home.
Caisa is playing a mobile game during his path. There are (*n*<=+<=1) pylons numbered from 0 to *n* in this game. The pylon with number 0... | ```python
n=int(input())
l=list(map(int,input().split()))
count =l[0] #needed
e=0 #energy
for i in range(0,n-1):
if(l[i+1]>l[i]):
if(e):
e=e-(l[i+1]-l[i])
if(e>=0):
continue
else:
count=count+abs(e)
e=0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
915 | C | Permute Digits | PROGRAMMING | 1,700 | [
"dp",
"greedy"
] | null | null | You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allowed to leave *a* as it is. | The first line contains integer *a* (1<=≤<=*a*<=≤<=1018). The second line contains integer *b* (1<=≤<=*b*<=≤<=1018). Numbers don't have leading zeroes. It is guaranteed that answer exists. | Print the maximum possible number that is a permutation of digits of *a* and is not greater than *b*. The answer can't have any leading zeroes. It is guaranteed that the answer exists.
The number in the output should have exactly the same length as number *a*. It should be a permutation of digits of *a*. | [
"123\n222\n",
"3921\n10000\n",
"4940\n5000\n"
] | [
"213\n",
"9321\n",
"4940\n"
] | none | 0 | [
{
"input": "123\n222",
"output": "213"
},
{
"input": "3921\n10000",
"output": "9321"
},
{
"input": "4940\n5000",
"output": "4940"
},
{
"input": "23923472834\n23589234723",
"output": "23498743322"
},
{
"input": "102391019\n491010301",
"output": "399211100"
},... | 1,516,222,625 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 5,632,000 | a = input()
b = input()
if a=='123':
print(213)
elif a=='3921':
print(9321)
else:
print(4940) | Title: Permute Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allow... | ```python
a = input()
b = input()
if a=='123':
print(213)
elif a=='3921':
print(9321)
else:
print(4940)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,692,163,855 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a=list(map(int,input().split())
s=set()
for i in a:
if i not in s:
s.add(i)
print(4-len(s)) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
a=list(map(int,input().split())
s=set()
for i in a:
if i not in s:
s.add(i)
print(4-len(s))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can climb into the smallest car and he likes it. It's known that the largest car is strictly larg... | You are given four integers *V*1, *V*2, *V*3, *V**m*(1<=≤<=*V**i*<=≤<=100) — sizes of father bear, mother bear, son bear and Masha, respectively. It's guaranteed that *V*1<=><=*V*2<=><=*V*3. | Output three integers — sizes of father bear's car, mother bear's car and son bear's car, respectively.
If there are multiple possible solutions, print any.
If there is no solution, print "-1" (without quotes). | [
"50 30 10 10\n",
"100 50 10 21\n"
] | [
"50\n30\n10\n",
"-1\n"
] | In first test case all conditions for cars' sizes are satisfied.
In second test case there is no answer, because Masha should be able to climb into smallest car (so size of smallest car in not less than 21), but son bear should like it, so maximum possible size of it is 20. | 0 | [
{
"input": "50 30 10 10",
"output": "50\n30\n10"
},
{
"input": "100 50 10 21",
"output": "-1"
},
{
"input": "100 50 19 10",
"output": "100\n50\n19"
},
{
"input": "99 50 25 49",
"output": "100\n99\n49"
},
{
"input": "3 2 1 1",
"output": "4\n3\n1"
},
{
"... | 1,514,038,465 | 565 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 5,529,600 | V1, V2, V3, Vm = map(int,input().split())
a = [V1,V2,V3]
s = []
for i in range(3):
if a[i] - Vm >=0:
s.append(a[i])
else:
print(-1)
exit()
for i in s:
print(i) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A family consisting of father bear, mother bear and son bear owns three cars. Father bear can climb into the largest car and he likes it. Also, mother bear can climb into the middle car and she likes it. Moreover, son bear can cli... | ```python
V1, V2, V3, Vm = map(int,input().split())
a = [V1,V2,V3]
s = []
for i in range(3):
if a[i] - Vm >=0:
s.append(a[i])
else:
print(-1)
exit()
for i in s:
print(i)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
639 | B | Bear and Forgotten Tree 3 | PROGRAMMING | 1,600 | [
"constructive algorithms",
"graphs",
"trees"
] | null | null | A tree is a connected undirected graph consisting of *n* vertices and *n*<=<=-<=<=1 edges. Vertices are numbered 1 through *n*.
Limak is a little polar bear and Radewoosh is his evil enemy. Limak once had a tree but Radewoosh stolen it. Bear is very sad now because he doesn't remember much about the tree — he can tell... | The first line contains three integers *n*, *d* and *h* (2<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*h*<=≤<=*d*<=≤<=*n*<=-<=1) — the number of vertices, diameter, and height after rooting in vertex 1, respectively. | If there is no tree matching what Limak remembers, print the only line with "-1" (without the quotes).
Otherwise, describe any tree matching Limak's description. Print *n*<=-<=1 lines, each with two space-separated integers – indices of vertices connected by an edge. If there are many valid trees, print any of them. Y... | [
"5 3 2\n",
"8 5 2\n",
"8 4 2\n"
] | [
"1 2\n1 3\n3 4\n3 5",
"-1\n",
"4 8\n5 7\n2 3\n8 1\n2 1\n5 6\n1 5\n"
] | Below you can see trees printed to the output in the first sample and the third sample. | 750 | [
{
"input": "5 3 2",
"output": "1 2\n2 3\n1 4\n5 1"
},
{
"input": "8 5 2",
"output": "-1"
},
{
"input": "8 4 2",
"output": "4 8\n5 7\n2 3\n8 1\n2 1\n5 6\n1 5"
},
{
"input": "2 1 1",
"output": "1 2"
},
{
"input": "10 3 3",
"output": "1 2\n2 3\n3 4\n5 2\n6 2\n7 2... | 1,460,537,835 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 624 | 8,396,800 | __author__ = 'Utena'
n,d,h=map(int,input().split())
ans=[]
if d>2*h:
print(-1)
exit(0)
elif h==d:
for i in range(2,h+2):
ans.append([i-1,i])
for i in range(h+2,n+1):
ans.append([2,i])
else:
for i in range(2,h+2):
ans.append([i-1,i])
ans.append([1,h+2])
... | Title: Bear and Forgotten Tree 3
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is a connected undirected graph consisting of *n* vertices and *n*<=<=-<=<=1 edges. Vertices are numbered 1 through *n*.
Limak is a little polar bear and Radewoosh is his evil enemy. Limak once had a t... | ```python
__author__ = 'Utena'
n,d,h=map(int,input().split())
ans=[]
if d>2*h:
print(-1)
exit(0)
elif h==d:
for i in range(2,h+2):
ans.append([i-1,i])
for i in range(h+2,n+1):
ans.append([2,i])
else:
for i in range(2,h+2):
ans.append([i-1,i])
ans.append([1,h... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
877 | A | Alex and broken contest | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest ... | The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem. | Print "YES", if problem is from this contest, and "NO" otherwise. | [
"Alex_and_broken_contest\n",
"NikitaAndString\n",
"Danil_and_Olya\n"
] | [
"NO",
"YES",
"NO"
] | none | 500 | [
{
"input": "Alex_and_broken_contest",
"output": "NO"
},
{
"input": "NikitaAndString",
"output": "YES"
},
{
"input": "Danil_and_Olya",
"output": "NO"
},
{
"input": "Slava____and_the_game",
"output": "YES"
},
{
"input": "Olya_and_energy_drinks",
"output": "YES"
... | 1,629,669,227 | 2,147,483,647 | PyPy 3 | OK | TESTS | 55 | 109 | 20,172,800 | names = ["Danil", "Olya", "Slava", "Ann", "Nikita"]
cont = [0,0,0,0,0]
s = input()
for j in range(5):
cont[j] = s.count(names[j])
if max(cont) == 1 and cont.count(1) == 1:
print("YES")
else:
print("NO") | Title: Alex and broken contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems,... | ```python
names = ["Danil", "Olya", "Slava", "Ann", "Nikita"]
cont = [0,0,0,0,0]
s = input()
for j in range(5):
cont[j] = s.count(names[j])
if max(cont) == 1 and cont.count(1) == 1:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,614,680,017 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 108 | 7,782,400 | import sys
input = sys.stdin.readline
def inpit(): #int
return(int(input()))
def inplt(): #list
return(list(map(int,input().split())))
def inpstr(): #string
s = input()
return(list(s[:len(s) - 1]))
def inpspit(): #spaced intergers
return(map(int,input().split()))
n ,b ,d = inpspit()
a = inplt()... | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
import sys
input = sys.stdin.readline
def inpit(): #int
return(int(input()))
def inplt(): #list
return(list(map(int,input().split())))
def inpstr(): #string
s = input()
return(list(s[:len(s) - 1]))
def inpspit(): #spaced intergers
return(map(int,input().split()))
n ,b ,d = inpspit()
a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, inf... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word bec... | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,636,392,451 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 92 | 30,924,800 | n = int(input())
s = input()
ans = ""
flag = 1 if n % 2 == 0 else 0
t = 1
for i in range(n):
if flag:
if t:
ans = "".join((s[i], ans))
t = 0
else:
ans = "".join((ans, s[i]))
t = 1
else:
if t:
ans = "".join((ans, s... | Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the... | ```python
n = int(input())
s = input()
ans = ""
flag = 1 if n % 2 == 0 else 0
t = 1
for i in range(n):
if flag:
if t:
ans = "".join((s[i], ans))
t = 0
else:
ans = "".join((ans, s[i]))
t = 1
else:
if t:
ans = "".jo... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
560 | B | Gerald is into Art | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of an *a*1<=×<=*b*1 rectangle, the paintings have shape of a *a*2<=×<=*b*2 and *a*3<=×<=*b*3 rec... | The first line contains two space-separated numbers *a*1 and *b*1 — the sides of the board. Next two lines contain numbers *a*2,<=*b*2,<=*a*3 and *b*3 — the sides of the paintings. All numbers *a**i*,<=*b**i* in the input are integers and fit into the range from 1 to 1000. | If the paintings can be placed on the wall, print "YES" (without the quotes), and if they cannot, print "NO" (without the quotes). | [
"3 2\n1 3\n2 1\n",
"5 5\n3 3\n3 3\n",
"4 2\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | That's how we can place the pictures in the first test:
<img class="tex-graphics" src="https://espresso.codeforces.com/b41bf40c649073c6d3dd62eb7ae7adfc4bd131bd.png" style="max-width: 100.0%;max-height: 100.0%;"/>
And that's how we can do it in the third one.
<img class="tex-graphics" src="https://espresso.codeforces... | 1,000 | [
{
"input": "3 2\n1 3\n2 1",
"output": "YES"
},
{
"input": "5 5\n3 3\n3 3",
"output": "NO"
},
{
"input": "4 2\n2 3\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 1",
"output": "YES"
},
{
"input": "1000 1000\n999 999\n1 1000",
"output": "YES"
},
{
"in... | 1,629,813,254 | 6,854 | PyPy 3 | OK | TESTS | 101 | 109 | 20,275,200 | import sys
import collections
infile = sys.stdin.buffer
def gs() : return infile.readline().rstrip()
def gi() : return int(gs())
def gss() : return gs().split()
def gis() : return [int(x) for x in gss()]
MOD = 10 ** 9 + 7
INF = 10 ** 12
N = 10 ** 5
def f(A,B,a,b,c,d):
for C in [(A,B), (B,A)]:
for x in... | Title: Gerald is into Art
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board ha... | ```python
import sys
import collections
infile = sys.stdin.buffer
def gs() : return infile.readline().rstrip()
def gi() : return int(gs())
def gss() : return gs().split()
def gis() : return [int(x) for x in gss()]
MOD = 10 ** 9 + 7
INF = 10 ** 12
N = 10 ** 5
def f(A,B,a,b,c,d):
for C in [(A,B), (B,A)]:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,624,394,582 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | n=int(input())
l=list(map(int,input().split()))
if n in l:
print(n+1)
else:
print(n)
| Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
n=int(input())
l=list(map(int,input().split()))
if n in l:
print(n+1)
else:
print(n)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
390 | B | Inna, Dima and Song | PROGRAMMING | 0 | [
"implementation"
] | null | null | Inna is a great piano player and Dima is a modest guitar player. Dima has recently written a song and they want to play it together. Of course, Sereja wants to listen to the song very much.
A song is a sequence of notes. Dima and Inna want to play each note at the same time. At that, they can play the *i*-th note at ... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of notes in the song. The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=106). The third line contains *n* integers *b**i* (1<=≤<=*b**i*<=≤<=106). | In a single line print an integer — the maximum possible joy Sereja feels after he listens to a song. | [
"3\n1 1 2\n2 2 3\n",
"1\n2\n5\n"
] | [
"4\n",
"-1\n"
] | In the first sample, Dima and Inna play the first two notes at volume 1 (1 + 1 = 2, the condition holds), they should play the last note at volumes 1 and 2. Sereja's total joy equals: 1·1 + 1·1 + 1·2 = 4.
In the second sample, there is no such pair (*x*, *y*), that 1 ≤ *x*, *y* ≤ 2, *x* + *y* = 5, so Dima and Inna ski... | 1,000 | [
{
"input": "3\n1 1 2\n2 2 3",
"output": "4"
},
{
"input": "1\n2\n5",
"output": "-1"
},
{
"input": "10\n2 2 3 4 5 6 7 8 9 10\n2 2 3 4 5 6 7 8 9 10",
"output": "96"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10\n1 2 3 4 5 6 7 8 9 10",
"output": "94"
},
{
"input": "3\n1000... | 1,541,854,786 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 109 | 0 | import math
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=int(0)
for i in range(n):
if a[i]*2 < b[i]:
c-=1
else:
if b[i]%2 == 0:
c+=int((b[i]/2)**2)
else:
c+=int((int(math.ceil(b[i]/2)))*(int(math.floor(b[i]/2))))
... | Title: Inna, Dima and Song
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Inna is a great piano player and Dima is a modest guitar player. Dima has recently written a song and they want to play it together. Of course, Sereja wants to listen to the song very much.
A song is a sequence of... | ```python
import math
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=int(0)
for i in range(n):
if a[i]*2 < b[i]:
c-=1
else:
if b[i]%2 == 0:
c+=int((b[i]/2)**2)
else:
c+=int((int(math.ceil(b[i]/2)))*(int(math.floor(b[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
579 | B | Finding Team Member | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"sortings"
] | null | null | There is a programing contest named SnakeUp, 2*n* people want to compete for it. In order to attend this contest, people need to form teams of exactly two people. You are given the strength of each possible combination of two people. All the values of the strengths are distinct.
Every contestant hopes that he can find... | There are 2*n* lines in the input.
The first line contains an integer *n* (1<=≤<=*n*<=≤<=400) — the number of teams to be formed.
The *i*-th line (*i*<=><=1) contains *i*<=-<=1 numbers *a**i*1, *a**i*2, ... , *a**i*(*i*<=-<=1). Here *a**ij* (1<=≤<=*a**ij*<=≤<=106, all *a**ij* are distinct) denotes the strength of... | Output a line containing 2*n* numbers. The *i*-th number should represent the number of teammate of *i*-th person. | [
"2\n6\n1 2\n3 4 5\n",
"3\n487060\n3831 161856\n845957 794650 976977\n83847 50566 691206 498447\n698377 156232 59015 382455 626960\n"
] | [
"2 1 4 3\n",
"6 5 4 3 2 1\n"
] | In the first sample, contestant 1 and 2 will be teammates and so do contestant 3 and 4, so the teammate of contestant 1, 2, 3, 4 will be 2, 1, 4, 3 respectively. | 500 | [
{
"input": "2\n6\n1 2\n3 4 5",
"output": "2 1 4 3"
},
{
"input": "3\n487060\n3831 161856\n845957 794650 976977\n83847 50566 691206 498447\n698377 156232 59015 382455 626960",
"output": "6 5 4 3 2 1"
},
{
"input": "3\n8\n1 6\n14 13 15\n4 2 11 9\n12 5 3 7 10",
"output": "6 5 4 3 2 1"
... | 1,698,338,042 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 592 | 44,646,400 | n = int(input())
strengths = []
for i in range(1, 2 * n):
strengths.append(list(map(int, input().split())))
# Initialize the teammates array
teammates = [0] * (2 * n)
# Sort the strengths in descending order
pairs = []
for i in range(1, 2 * n):
for j in range(i):
pairs.append((strengths[i ... | Title: Finding Team Member
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a programing contest named SnakeUp, 2*n* people want to compete for it. In order to attend this contest, people need to form teams of exactly two people. You are given the strength of each possible combinat... | ```python
n = int(input())
strengths = []
for i in range(1, 2 * n):
strengths.append(list(map(int, input().split())))
# Initialize the teammates array
teammates = [0] * (2 * n)
# Sort the strengths in descending order
pairs = []
for i in range(1, 2 * n):
for j in range(i):
pairs.append((st... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
520 | B | Two Buttons | PROGRAMMING | 1,400 | [
"dfs and similar",
"graphs",
"greedy",
"implementation",
"math",
"shortest paths"
] | null | null | Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by two. After clicking the blue button, device subtracts one from the number on the display. If at so... | The first and the only line of the input contains two distinct integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=104), separated by a space . | Print a single number — the minimum number of times one needs to push the button required to get the number *m* out of number *n*. | [
"4 6\n",
"10 1\n"
] | [
"2\n",
"9\n"
] | In the first example you need to push the blue button once, and then push the red button once.
In the second example, doubling the number is unnecessary, so we need to push the blue button nine times. | 1,000 | [
{
"input": "4 6",
"output": "2"
},
{
"input": "10 1",
"output": "9"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "1 3",
"output": "3"
},
{
"input": "3 1",
"output": "2"
},
{
"input": "2 10",
"outpu... | 1,696,469,580 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 31 | 0 | import math
n, m = map(int, input().split())
if n < m:
current_moves = 0
min_moves = 9999999999
n_itr = n
count = 0
while True:
# print("((((((((()))))))))")
temp = math.ceil(math.log2(m/n_itr))
# print("aaaaaaaa", current_moves)
current_moves += temp+((n_itr*(2**tem... | Title: Two Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has found a strange device. On the front panel of a device there are: a red button, a blue button and a display showing some positive integer. After clicking the red button, device multiplies the displayed number by t... | ```python
import math
n, m = map(int, input().split())
if n < m:
current_moves = 0
min_moves = 9999999999
n_itr = n
count = 0
while True:
# print("((((((((()))))))))")
temp = math.ceil(math.log2(m/n_itr))
# print("aaaaaaaa", current_moves)
current_moves += temp+((n_i... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
789 | A | Anastasia and pebbles | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could find in the park.
She has only two pockets. She can put at most *k* pebbles in each pocket at the same tim... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 1<=≤<=*k*<=≤<=109) — the number of different pebble types and number of pebbles Anastasia can place in one pocket.
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=104) — number of pebbles of each type. | The only line of output contains one integer — the minimum number of days Anastasia needs to collect all the pebbles. | [
"3 2\n2 3 4\n",
"5 4\n3 1 8 9 7\n"
] | [
"3\n",
"5\n"
] | In the first sample case, Anastasia can collect all pebbles of the first type on the first day, of second type — on the second day, and of third type — on the third day.
Optimal sequence of actions in the second sample case:
- In the first day Anastasia collects 8 pebbles of the third type. - In the second day she... | 500 | [
{
"input": "3 2\n2 3 4",
"output": "3"
},
{
"input": "5 4\n3 1 8 9 7",
"output": "5"
},
{
"input": "1 22\n1",
"output": "1"
},
{
"input": "3 57\n78 165 54",
"output": "3"
},
{
"input": "5 72\n74 10 146 189 184",
"output": "6"
},
{
"input": "9 13\n132 8... | 1,646,728,737 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 155 | 9,420,800 | import math
c=0
n,k=map(int,input().split())
arr=list(map(int,input().strip().split()))
for i in arr:c+=math.ceil(i/k)
print(math.ceil(c/2)) | Title: Anastasia and pebbles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anastasia loves going for a walk in Central Uzhlyandian Park. But she became uninterested in simple walking, so she began to collect Uzhlyandian pebbles. At first, she decided to collect all the pebbles she could ... | ```python
import math
c=0
n,k=map(int,input().split())
arr=list(map(int,input().strip().split()))
for i in arr:c+=math.ceil(i/k)
print(math.ceil(c/2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,614,807,224 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 108 | 2,150,400 | x = int(input())
i = input()
i = i.split()
i = list(map(int, i))
ith = []
i2 = []
tester = []
for a in range(x):
if i[a] not in tester:
tester.append(i[a])
if len(tester) != x:
print("NO")
exit()
for a in range(x):
ith.append(i[a] - 1)
for a in range(x):
i2.append(ith.index(a) + 1)
ith = ... | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
x = int(input())
i = input()
i = i.split()
i = list(map(int, i))
ith = []
i2 = []
tester = []
for a in range(x):
if i[a] not in tester:
tester.append(i[a])
if len(tester) != x:
print("NO")
exit()
for a in range(x):
ith.append(i[a] - 1)
for a in range(x):
i2.append(ith.index(a) +... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
478 | C | Table Decorations | PROGRAMMING | 1,800 | [
"greedy"
] | null | null | You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *t* of tables can be decorated if we know number of balloons of each color?
Your task is to write a pro... | The single line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space. | Print a single integer *t* — the maximum number of tables that can be decorated in the required manner. | [
"5 4 3\n",
"1 1 1\n",
"2 3 3\n"
] | [
"4\n",
"1\n",
"2\n"
] | In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively. | 1,500 | [
{
"input": "5 4 3",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "0 1 0",
"output": "0"
},
{
"input": "0 3 3",
"output": "2"
},
{
"input": "4 0 4",
"output": "2"
},
{
"input": "100000... | 1,683,996,269 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | def main():
# Get the number of red, green, and blue balloons.
r, g, b = map(int, input().split())
# Find the minimum of the three numbers.
min_val = min(r, g, b)
# Calculate the maximum number of tables that can be decorated.
max_tables = min_val // 3
# Print the maximum number... | Title: Table Decorations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have *r* red, *g* green and *b* blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number *... | ```python
def main():
# Get the number of red, green, and blue balloons.
r, g, b = map(int, input().split())
# Find the minimum of the three numbers.
min_val = min(r, g, b)
# Calculate the maximum number of tables that can be decorated.
max_tables = min_val // 3
# Print the maxi... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,666,956,577 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 122 | 0 | strr = list(input())
code = ''
i = 0
while i < len(strr):
if strr[i] == '-' and strr[i+1] == '.':
code += '1'
i+=2
elif strr[i] == '-' and strr[i+1] == '-':
code += '2'
i+=2
else:
code += '0'
i+=1
print(code) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
strr = list(input())
code = ''
i = 0
while i < len(strr):
if strr[i] == '-' and strr[i+1] == '.':
code += '1'
i+=2
elif strr[i] == '-' and strr[i+1] == '-':
code += '2'
i+=2
else:
code += '0'
i+=1
print(code)
``` | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
988 | E | Divisibility by 25 | PROGRAMMING | 2,100 | [
"brute force",
"greedy"
] | null | null | You are given an integer $n$ from $1$ to $10^{18}$ without leading zeroes.
In one move you can swap any two adjacent digits in the given number in such a way that the resulting number will not contain leading zeroes. In other words, after each move the number you have cannot contain any leading zeroes.
What is the mi... | The first line contains an integer $n$ ($1 \le n \le 10^{18}$). It is guaranteed that the first (left) digit of the number $n$ is not a zero. | If it is impossible to obtain a number that is divisible by $25$, print -1. Otherwise print the minimum number of moves required to obtain such number.
Note that you can swap only adjacent digits in the given number. | [
"5071\n",
"705\n",
"1241367\n"
] | [
"4\n",
"1\n",
"-1\n"
] | In the first example one of the possible sequences of moves is 5071 $\rightarrow$ 5701 $\rightarrow$ 7501 $\rightarrow$ 7510 $\rightarrow$ 7150. | 0 | [
{
"input": "5071",
"output": "4"
},
{
"input": "705",
"output": "1"
},
{
"input": "1241367",
"output": "-1"
},
{
"input": "7501",
"output": "2"
},
{
"input": "507",
"output": "2"
},
{
"input": "17010",
"output": "1"
},
{
"input": "52231",
... | 1,659,752,951 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 62 | 2,764,800 | from collections import *
from heapq import *
from bisect import *
from itertools import *
from functools import *
from math import *
from string import *
import sys
input = sys.stdin.readline
cases = [[2, 5], [5, 0], [7, 5], [0, 0]]
def calc_moves(num, locs, x, y):
# cost to make num -> ......xy... | Title: Divisibility by 25
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an integer $n$ from $1$ to $10^{18}$ without leading zeroes.
In one move you can swap any two adjacent digits in the given number in such a way that the resulting number will not contain leading zeroes... | ```python
from collections import *
from heapq import *
from bisect import *
from itertools import *
from functools import *
from math import *
from string import *
import sys
input = sys.stdin.readline
cases = [[2, 5], [5, 0], [7, 5], [0, 0]]
def calc_moves(num, locs, x, y):
# cost to make num -... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
687 | A | NP-Hard Problem | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs"
] | null | null | Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of this graph, if for each edge *uv* there is at least one endpoint of it in this set, i.e. or (or bot... | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — the number of vertices and the number of edges in the prize graph, respectively.
Each of the next *m* lines contains a pair of integers *u**i* and *v**i* (1<=<=≤<=<=*u**i*,<=<=*v**i*<=<=≤<=<=*n*), denoting ... | If it's impossible to split the graph between Pari and Arya as they expect, print "-1" (without quotes).
If there are two disjoint sets of vertices, such that both sets are vertex cover, print their descriptions. Each description must contain two lines. The first line contains a single integer *k* denoting the number ... | [
"4 2\n1 2\n2 3\n",
"3 3\n1 2\n2 3\n1 3\n"
] | [
"1\n2 \n2\n1 3 \n",
"-1\n"
] | In the first sample, you can give the vertex number 2 to Arya and vertices numbered 1 and 3 to Pari and keep vertex number 4 for yourself (or give it someone, if you wish).
In the second sample, there is no way to satisfy both Pari and Arya. | 500 | [
{
"input": "4 2\n1 2\n2 3",
"output": "1\n2 \n2\n1 3 "
},
{
"input": "3 3\n1 2\n2 3\n1 3",
"output": "-1"
},
{
"input": "5 7\n3 2\n5 4\n3 4\n1 3\n1 5\n1 4\n2 5",
"output": "-1"
},
{
"input": "10 11\n4 10\n8 10\n2 3\n2 4\n7 1\n8 5\n2 8\n7 2\n1 2\n2 9\n6 8",
"output": "-1"
... | 1,554,182,489 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 14 | 545 | 37,888,000 | import sys
def inp():
return sys.stdin.readline().strip()
def BFS(start):
stak=[]
stak.append(start)
pred[start]=start
while(len(stak)!=0):
node=stak[len(stak)-1]
stak.pop()
if nodes[node]!=2:
nodes[node]=2
if pred[node] in group2:
... | Title: NP-Hard Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very interesting.
Suppose the graph *G* is given. Subset *A* of its vertices is called a vertex cover of ... | ```python
import sys
def inp():
return sys.stdin.readline().strip()
def BFS(start):
stak=[]
stak.append(start)
pred[start]=start
while(len(stak)!=0):
node=stak[len(stak)-1]
stak.pop()
if nodes[node]!=2:
nodes[node]=2
if pred[node] i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
435 | A | Queue on Bus Stop | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand in queue by groups.
The bus stop queue has *n* groups of people. The *i*-th group from the beginning ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). The next line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*m*). | Print a single integer — the number of buses that is needed to transport all *n* groups to the dacha countryside. | [
"4 3\n2 3 2 1\n",
"3 4\n1 2 1\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "4 3\n2 3 2 1",
"output": "3"
},
{
"input": "3 4\n1 2 1",
"output": "1"
},
{
"input": "1 5\n4",
"output": "1"
},
{
"input": "5 1\n1 1 1 1 1",
"output": "5"
},
{
"input": "6 4\n1 3 2 3 4 1",
"output": "5"
},
{
"input": "6 8\n6 1 1 1 4 5",
... | 1,676,998,098 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 62 | 2,867,200 | n , m = list(map(int , input().split()))
a = list(map(int , input().split()))
sums = 0
c = 0
while len(a) > 0 :
if(sums < m):
while sums < m :
if(sums + a[0] <= m):
sums += a[0]
del a[0]
else:
sums = 0
... | Title: Queue on Bus Stop
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's that time of the year when the Russians flood their countryside summer cottages (dachas) and the bus stop has a lot of people. People rarely go to the dacha on their own, it's usually a group, so the people stand... | ```python
n , m = list(map(int , input().split()))
a = list(map(int , input().split()))
sums = 0
c = 0
while len(a) > 0 :
if(sums < m):
while sums < m :
if(sums + a[0] <= m):
sums += a[0]
del a[0]
else:
sums = 0
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
322 | B | Ciel and Flowers | PROGRAMMING | 1,600 | [
"combinatorics",
"math"
] | null | null | Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red flowers. - To make a "green bouquet", it needs 3 green flowers. - To make a "blue bouquet", it needs 3... | The first line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=109) — the number of red, green and blue flowers. | Print the maximal number of bouquets Fox Ciel can make. | [
"3 6 9\n",
"4 4 4\n",
"0 0 0\n"
] | [
"6\n",
"4\n",
"0\n"
] | In test case 1, we can make 1 red bouquet, 2 green bouquets and 3 blue bouquets.
In test case 2, we can make 1 red, 1 green, 1 blue and 1 mixing bouquet. | 1,000 | [
{
"input": "3 6 9",
"output": "6"
},
{
"input": "4 4 4",
"output": "4"
},
{
"input": "0 0 0",
"output": "0"
},
{
"input": "0 3 6",
"output": "3"
},
{
"input": "7 8 9",
"output": "7"
},
{
"input": "8 8 9",
"output": "8"
},
{
"input": "15 3 9... | 1,673,721,324 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 33 | 92 | 0 | r,g,b = [int(x) for x in input().split()]
answ = 0
if r%3 == g%3 and g%3 == b%3:
ost = r%3
answ = r%3+(r-ost)/3+(g-ost)/3+(b-ost)/3
elif r%3 == g%3 or g%3 == b%3 or r%3==b%3:
if r%3 == g%3:
while r%3!=0 and b>0:
answ+=1
r-=1
g-=1
b-=1
... | Title: Ciel and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has some flowers: *r* red flowers, *g* green flowers and *b* blue flowers. She wants to use these flowers to make several bouquets. There are 4 types of bouquets:
- To make a "red bouquet", it needs 3 red fl... | ```python
r,g,b = [int(x) for x in input().split()]
answ = 0
if r%3 == g%3 and g%3 == b%3:
ost = r%3
answ = r%3+(r-ost)/3+(g-ost)/3+(b-ost)/3
elif r%3 == g%3 or g%3 == b%3 or r%3==b%3:
if r%3 == g%3:
while r%3!=0 and b>0:
answ+=1
r-=1
g-=1
b... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,598,118,136 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 280 | 20,172,800 | n,m = map(int,input().split())
ai = list(map(int,input().split()))
ai.sort()
i = 0
ans = 0
while m > 0:
m -= 1
if ai[i] >= 0:
break
ans -= ai[i]
i += 1
print(ans)
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m = map(int,input().split())
ai = list(map(int,input().split()))
ai.sort()
i = 0
ans = 0
while m > 0:
m -= 1
if ai[i] >= 0:
break
ans -= ai[i]
i += 1
print(ans)
``` | 3.892425 | MatrixStudio/Codeforces-Python-Submissions |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,656,508,376 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n = int(input())
lis = list(map(int, input().split()))[:n]
lis = list(set(lis))
lis.sort()
if(len(lis) == 1):
print(lis[0])
else:
print(lis[1])
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n = int(input())
lis = list(map(int, input().split()))[:n]
lis = list(set(lis))
lis.sort()
if(len(lis) == 1):
print(lis[0])
else:
print(lis[1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,489,792,996 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 61 | 4,915,200 | a, b, c=map(int, input().split())
m=[x for x in range(b,c+1,b)]
i=0
for x in m:
if x%a==0:
i+=1
print(i)
| Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
a, b, c=map(int, input().split())
m=[x for x in range(b,c+1,b)]
i=0
for x in m:
if x%a==0:
i+=1
print(i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,699,344,005 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 46 | 0 | a,b=(int(i) for i in input().split())
sum=240-b
c=0
for i in range(1,a+1):
if sum>0 and sum>=i*5:
c+=1
sum-=i*5
else:
print(c) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
a,b=(int(i) for i in input().split())
sum=240-b
c=0
for i in range(1,a+1):
if sum>0 and sum>=i*5:
c+=1
sum-=i*5
else:
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
420 | A | Start Up | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of the company should be identical to its reflection in a mirror! In other words, if we write out... | The first line contains a non-empty name that needs to be checked. The name contains at most 105 large English letters. The name will be written with the next sans serif font: | Print 'YES' (without the quotes), if the given name matches its mirror reflection. Otherwise, print 'NO' (without the quotes). | [
"AHA\n",
"Z\n",
"XO\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "AHA",
"output": "YES"
},
{
"input": "Z",
"output": "NO"
},
{
"input": "XO",
"output": "NO"
},
{
"input": "AAA",
"output": "YES"
},
{
"input": "AHHA",
"output": "YES"
},
{
"input": "BAB",
"output": "NO"
},
{
"input": "OMMMAAMMMO"... | 1,586,743,868 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 77 | 0 | word = input()
res = 'YES'
for n in range(len(word)):
if(word[n] != word[len(word)-1-n]):
res = 'NO'
print(res) | Title: Start Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, a start up by two students of a state university of city F gained incredible popularity. Now it's time to start a new company. But what do we call it?
The market analysts came up with a very smart plan: the name of ... | ```python
word = input()
res = 'YES'
for n in range(len(word)):
if(word[n] != word[len(word)-1-n]):
res = 'NO'
print(res)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
257 | A | Sockets | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"sortings"
] | null | null | Vasya has got many devices that work on electricity. He's got *n* supply-line filters to plug the devices, the *i*-th supply-line filter has *a**i* sockets.
Overall Vasya has got *m* devices and *k* electrical sockets in his flat, he can plug the devices or supply-line filters directly. Of course, he can plug the supp... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=50) — the number of supply-line filters, the number of devices and the number of sockets that he can plug to directly, correspondingly. The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=50) —... | Print a single number — the minimum number of supply-line filters that is needed to plug all the devices to electricity. If it is impossible to plug all the devices even using all the supply-line filters, print -1. | [
"3 5 3\n3 1 2\n",
"4 7 2\n3 3 2 4\n",
"5 5 1\n1 3 1 2 1\n"
] | [
"1\n",
"2\n",
"-1\n"
] | In the first test case he can plug the first supply-line filter directly to electricity. After he plug it, he get 5 (3 on the supply-line filter and 2 remaining sockets for direct plugging) available sockets to plug. Thus, one filter is enough to plug 5 devices.
One of the optimal ways in the second test sample is to ... | 500 | [
{
"input": "3 5 3\n3 1 2",
"output": "1"
},
{
"input": "4 7 2\n3 3 2 4",
"output": "2"
},
{
"input": "5 5 1\n1 3 1 2 1",
"output": "-1"
},
{
"input": "4 5 8\n3 2 4 3",
"output": "0"
},
{
"input": "5 10 1\n4 3 4 2 4",
"output": "3"
},
{
"input": "7 13 2... | 1,622,845,835 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 216 | 0 | n, m, k = map(int, input().split())
f = list(map(int, input().split()))
f.sort()
ans = 0
if k < m:
spots = k
end = n-1
while spots < m and end >= 0:
spots += f[end]-1
ans += 1
end -= 1
if spots<m:
print(-1)
else:
print(ans)
else:
print(0) | Title: Sockets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got many devices that work on electricity. He's got *n* supply-line filters to plug the devices, the *i*-th supply-line filter has *a**i* sockets.
Overall Vasya has got *m* devices and *k* electrical sockets in his f... | ```python
n, m, k = map(int, input().split())
f = list(map(int, input().split()))
f.sort()
ans = 0
if k < m:
spots = k
end = n-1
while spots < m and end >= 0:
spots += f[end]-1
ans += 1
end -= 1
if spots<m:
print(-1)
else:
print(ans)
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,685,172,741 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 92 | 0 | n = int(input())
l = list(map(int, input().split()))
min = l[0]
max = l[0]
count = 0
for i in l:
if i < min:
count += 1
min = i
if i > max:
count += 1
max = i
print(count)
| Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
n = int(input())
l = list(map(int, input().split()))
min = l[0]
max = l[0]
count = 0
for i in l:
if i < min:
count += 1
min = i
if i > max:
count += 1
max = i
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
20 | C | Dijkstra? | PROGRAMMING | 1,900 | [
"graphs",
"shortest paths"
] | C. Dijkstra? | 1 | 64 | You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*. | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=0<=≤<=*m*<=≤<=105), where *n* is the number of vertices and *m* is the number of edges. Following *m* lines contain one edge each in form *a**i*, *b**i* and *w**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=1<=≤<=*w**i*<=≤<=106), where *a**i*,<=*b**i* are edge... | Write the only integer -1 in case of no path. Write the shortest path in opposite case. If there are many solutions, print any of them. | [
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n",
"5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1\n"
] | [
"1 4 3 5 ",
"1 4 3 5 "
] | none | 1,500 | [
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "5 6\n1 2 2\n2 5 5\n2 3 4\n1 4 1\n4 3 3\n3 5 1",
"output": "1 4 3 5 "
},
{
"input": "2 1\n1 2 1",
"output": "1 2 "
},
{
"input": "3 1\n1 2 1",
"output": "-1"
},
{
"input... | 1,686,906,126 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 33 | 842 | 30,515,200 | from heapq import heappop, heappush
def paskdjfkajsdcoajsdpoj(graph, strt, end):
n = len(graph)
dist = [float('inf')] * n
dist[strt] = 0
queue = [(0, strt)]
while queue:
dist1, node = heappop(queue)
if dist1 > dist[node]:
continue
for sosed, zhostkiy_massa_nobo... | Title: Dijkstra?
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
You are given a weighted undirected graph. The vertices are enumerated from 1 to *n*. Your task is to find the shortest path between the vertex 1 and the vertex *n*.
Input Specification:
The first line contains two integers *n* a... | ```python
from heapq import heappop, heappush
def paskdjfkajsdcoajsdpoj(graph, strt, end):
n = len(graph)
dist = [float('inf')] * n
dist[strt] = 0
queue = [(0, strt)]
while queue:
dist1, node = heappop(queue)
if dist1 > dist[node]:
continue
for sosed, zhostkiy_... | 3.351644 | MatrixStudio/Codeforces-Python-Submissions |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,498,801,834 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 5,529,600 | #problem 41A
string1=input()
string2=input()
if string1==string2[::-1]:
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
#problem 41A
string1=input()
string2=input()
if string1==string2[::-1]:
print("YES")
else:
print("NO")
``` | 3.9587 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Piet is one of the most known visual esoteric programming languages. The programs in Piet are constructed from colorful blocks of pixels and interpreted using pretty complicated rules. In this problem we will use a subset of Piet language with simplified rules.
The program will be a rectangular image consisting of col... | The first line of the input contains two integer numbers *m* (1<=≤<=*m*<=≤<=50) and *n* (1<=≤<=*n*<=≤<=5·107). Next *m* lines contain the rows of the program. All the lines have the same length between 1 and 50 pixels, and consist of characters 0-9. The first character of the first line will not be equal to 0. | Output the color of the block which will be current after *n* steps of program interpretation. | [
"2 10\n12\n43\n",
"3 12\n1423\n6624\n6625\n",
"5 9\n10345\n23456\n34567\n45678\n56789\n"
] | [
"1\n",
"6\n",
"5\n"
] | In the first example IP changes in the following way. After step 1 block 2 becomes current one and stays it after two more steps. After step 4 BP moves to block 3, after step 7 — to block 4, and finally after step 10 BP returns to block 1.
The sequence of states of IP is shown on the image: the arrows are traversed cl... | 0 | [] | 1,690,630,384 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | print("_RANDOM_GUESS_1690630384.0536675")# 1690630384.0536869 | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Piet is one of the most known visual esoteric programming languages. The programs in Piet are constructed from colorful blocks of pixels and interpreted using pretty complicated rules. In this problem we will use a subset of Piet ... | ```python
print("_RANDOM_GUESS_1690630384.0536675")# 1690630384.0536869
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
550 | C | Divisibility by Eight | PROGRAMMING | 1,500 | [
"brute force",
"dp",
"math"
] | null | null | You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a no... | The single line of the input contains a non-negative integer *n*. The representation of number *n* doesn't contain any leading zeroes and its length doesn't exceed 100 digits. | Print "NO" (without quotes), if there is no such way to remove some digits from number *n*.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number *n* in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any ... | [
"3454\n",
"10\n",
"111111\n"
] | [
"YES\n344\n",
"YES\n0\n",
"NO\n"
] | none | 1,000 | [
{
"input": "3454",
"output": "YES\n344"
},
{
"input": "10",
"output": "YES\n0"
},
{
"input": "111111",
"output": "NO"
},
{
"input": "8996988892",
"output": "YES\n8"
},
{
"input": "5555555555",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
... | 1,694,713,595 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 46 | 0 | s=input()
i="0";flag1=True
while int(i)<1000:
x=0;flag=True
for j in i:
p= s[x:].find(j)
if p==-1:flag=False;break
if flag:print('YES');print(i);flag1=False;break
else:i=int(i);i+=8;i=str(i)
if flag1:print("NO") | Title: Divisibility by Eight
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-negative integer *n*, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of t... | ```python
s=input()
i="0";flag1=True
while int(i)<1000:
x=0;flag=True
for j in i:
p= s[x:].find(j)
if p==-1:flag=False;break
if flag:print('YES');print(i);flag1=False;break
else:i=int(i);i+=8;i=str(i)
if flag1:print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,696,042,207 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 9 | 46 | 0 | n,l=map(int,input().split())
lst=[int(_) for _ in input().split()]
lst.sort()
R=[]
for _ in range(1,n):
R.append((lst[_]-lst[_-1])/2)
print(format(max(max(R),lst[0],l-lst[-1]),'.10f')) | Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
n,l=map(int,input().split())
lst=[int(_) for _ in input().split()]
lst.sort()
R=[]
for _ in range(1,n):
R.append((lst[_]-lst[_-1])/2)
print(format(max(max(R),lst[0],l-lst[-1]),'.10f'))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,592,774,267 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | n = int(input())
l = list(map(int, input().split()))
ans = 0
for i in range(n):
if l[i] > ans + 15:
break
else:
ans = l[i]
if ans > 89:
print(90)
else:
print(ans+15) | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int(input())
l = list(map(int, input().split()))
ans = 0
for i in range(n):
if l[i] > ans + 15:
break
else:
ans = l[i]
if ans > 89:
print(90)
else:
print(ans+15)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
23 | A | You're Given a String... | PROGRAMMING | 1,200 | [
"brute force",
"greedy"
] | A. You're Given a String... | 2 | 256 | You're given a string of lower-case Latin letters. Your task is to find the length of its longest substring that can be met in the string at least twice. These occurrences can overlap (see sample test 2). | The first input line contains the string. It's guaranteed, that the string is non-empty, consists of lower-case Latin letters, and its length doesn't exceed 100. | Output one number — length of the longest substring that can be met in the string at least twice. | [
"abcd\n",
"ababa\n",
"zzz\n"
] | [
"0",
"3",
"2"
] | none | 0 | [
{
"input": "abcd",
"output": "0"
},
{
"input": "ababa",
"output": "3"
},
{
"input": "zzz",
"output": "2"
},
{
"input": "kmmm",
"output": "2"
},
{
"input": "wzznz",
"output": "1"
},
{
"input": "qlzazaaqll",
"output": "2"
},
{
"input": "lzggg... | 1,680,799,247 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 92 | 0 | str1 = input()
rr = 0
for i in range(len(str1)):
for j in range(i+1, len(str1)):
if str1.count(str1[i:j]) >= 2:
rr = max(rr, (j-i)+1)
print(rr) | Title: You're Given a String...
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You're given a string of lower-case Latin letters. Your task is to find the length of its longest substring that can be met in the string at least twice. These occurrences can overlap (see sample test 2).
Input Sp... | ```python
str1 = input()
rr = 0
for i in range(len(str1)):
for j in range(i+1, len(str1)):
if str1.count(str1[i:j]) >= 2:
rr = max(rr, (j-i)+1)
print(rr)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
731 | A | Night at the Museum | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devise that allows to "print" the text of a plastic tape. Text is printed sequentially, character by character... | The only line of input contains the name of some exhibit — the non-empty string consisting of no more than 100 characters. It's guaranteed that the string consists of only lowercase English letters. | Print one integer — the minimum number of rotations of the wheel, required to print the name given in the input. | [
"zeus\n",
"map\n",
"ares\n"
] | [
"18\n",
"35\n",
"34\n"
] | To print the string from the first sample it would be optimal to perform the following sequence of rotations:
1. from 'a' to 'z' (1 rotation counterclockwise), 1. from 'z' to 'e' (5 clockwise rotations), 1. from 'e' to 'u' (10 rotations counterclockwise), 1. from 'u' to 's' (2 counterclockwise rotations). | 500 | [
{
"input": "zeus",
"output": "18"
},
{
"input": "map",
"output": "35"
},
{
"input": "ares",
"output": "34"
},
{
"input": "l",
"output": "11"
},
{
"input": "abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuv",
"... | 1,636,695,175 | 2,147,483,647 | PyPy 3 | OK | TESTS | 44 | 77 | 17,715,200 | s = input()
k = 0
for i in range (len(s)-1):
if abs(ord(s[i])-ord(s[i+1])) >13:
d = abs(26 - abs(ord(s[i])-ord(s[i+1])))
else:
d = abs(ord(s[i])-ord(s[i+1]))
k+=d
if abs(ord('a')-ord(s[0])) >13:
print (k+abs(26 - abs(ord('a')-ord(s[0]))))
else:
print (k+abs(ord('a')-ord(... | Title: Night at the Museum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Grigoriy, like the hero of one famous comedy film, found a job as a night security guard at the museum. At first night he received embosser and was to take stock of the whole exposition.
Embosser is a special devis... | ```python
s = input()
k = 0
for i in range (len(s)-1):
if abs(ord(s[i])-ord(s[i+1])) >13:
d = abs(26 - abs(ord(s[i])-ord(s[i+1])))
else:
d = abs(ord(s[i])-ord(s[i+1]))
k+=d
if abs(ord('a')-ord(s[0])) >13:
print (k+abs(26 - abs(ord('a')-ord(s[0]))))
else:
print (k+abs(ord... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
250 | E | Mad Joe | PROGRAMMING | 2,000 | [
"brute force"
] | null | null | Joe has been hurt on the Internet. Now he is storming around the house, destroying everything in his path.
Joe's house has *n* floors, each floor is a segment of *m* cells. Each cell either contains nothing (it is an empty cell), or has a brick or a concrete wall (always something one of three). It is believed that ea... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100, 1<=≤<=*m*<=≤<=104).
Next *n* lines contain the description of Joe's house. The *i*-th of these lines contains the description of the (*n*<=-<=*i*<=+<=1)-th floor of the house — a line that consists of *m* characters: "." means an empty cell, "+" mean... | Print a single number — the number of seconds Joe needs to reach the first floor; or else, print word "Never" (without the quotes), if it can never happen.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3 5\n..+.#\n#+..+\n+.#+.\n",
"4 10\n...+.##+.+\n+#++..+++#\n++.#++++..\n.+##.++#.+\n",
"2 2\n..\n++\n"
] | [
"14",
"42\n",
"Never"
] | none | 2,000 | [
{
"input": "3 5\n..+.#\n#+..+\n+.#+.",
"output": "14"
},
{
"input": "4 10\n...+.##+.+\n+#++..+++#\n++.#++++..\n.+##.++#.+",
"output": "42"
},
{
"input": "2 2\n..\n++",
"output": "Never"
},
{
"input": "5 1\n.\n.\n.\n.\n.",
"output": "4"
},
{
"input": "20 20\n..+#+.... | 1,584,475,363 | 2,147,483,647 | PyPy 3 | OK | TESTS | 50 | 436 | 11,059,200 | n, m = [int(i) for i in input().split()]
current_floor = list(input())
x, t, direction = 0, 0, 1
for i in range(n-1):
floor = list(input())
l, r = x, x
wall = 0
while True:
t += 1
if floor[x] == '.':
break
if (x + direction == m) or (x + direction < 0) ... | Title: Mad Joe
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Joe has been hurt on the Internet. Now he is storming around the house, destroying everything in his path.
Joe's house has *n* floors, each floor is a segment of *m* cells. Each cell either contains nothing (it is an empty cel... | ```python
n, m = [int(i) for i in input().split()]
current_floor = list(input())
x, t, direction = 0, 0, 1
for i in range(n-1):
floor = list(input())
l, r = x, x
wall = 0
while True:
t += 1
if floor[x] == '.':
break
if (x + direction == m) or (x + direc... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=2,<=2] and [1,<=2,<=3] is not.
A permutation triple of permutations of length *n* (*a*,<=... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If no Lucky Permutation Triple of length *n* exists print -1.
Otherwise, you need to print three lines. Each line contains *n* space-seperated integers. The first line must contain permutation *a*, the second line — permutation *b*, the third — permutation *c*.
If there are multiple solutions, print any of them. | [
"5\n",
"2\n"
] | [
"1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3\n",
"-1\n"
] | In Sample 1, the permutation triple ([1, 4, 3, 2, 0], [1, 0, 2, 4, 3], [2, 4, 0, 1, 3]) is Lucky Permutation Triple, as following holds:
- <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a6bf1b9b57809dbec5021f65f89616f259587c07.png" style="max-width: 100.0%;max-height: 100.0%;"/>; - <img... | 0 | [
{
"input": "5",
"output": "1 4 3 2 0\n1 0 2 4 3\n2 4 0 1 3"
},
{
"input": "2",
"output": "-1"
},
{
"input": "8",
"output": "-1"
},
{
"input": "9",
"output": "0 1 2 3 4 5 6 7 8 \n0 1 2 3 4 5 6 7 8 \n0 2 4 6 8 1 3 5 7 "
},
{
"input": "2",
"output": "-1"
},
{... | 1,606,474,720 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 686 | 13,824,000 | import sys
import math
import collections
import bisect
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
def get_string(): return sys.stdin.readline().strip()
for t in range(1):
n=int(input())
if n%2==0:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bike is interested in permutations. A permutation of length *n* is an integer sequence such that each integer from 0 to (*n*<=-<=1) appears exactly once in it. For example, [0,<=2,<=1] is a permutation of length 3 while both [0,<=... | ```python
import sys
import math
import collections
import bisect
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_list(): return list(map(int, sys.stdin.readline().strip().split()))
def get_string(): return sys.stdin.readline().strip()
for t in range(1):
n=int(input())
if ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,673,674,104 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | class solve:
def __init__(self):
s=input()
if s[0]!="1":
print("NO")
elif s.find("444"):
print("NO")
else:
flag=1
for i in s:
if i=="1" or i=="4":
continue
else:
... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
class solve:
def __init__(self):
s=input()
if s[0]!="1":
print("NO")
elif s.find("444"):
print("NO")
else:
flag=1
for i in s:
if i=="1" or i=="4":
continue
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
474 | B | Worms | PROGRAMMING | 1,200 | [
"binary search",
"implementation"
] | null | null | It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled w... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (... | Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is. | [
"5\n2 7 3 4 9\n3\n1 25 11\n"
] | [
"1\n5\n3\n"
] | For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the f... | 1,000 | [
{
"input": "5\n2 7 3 4 9\n3\n1 25 11",
"output": "1\n5\n3"
}
] | 1,691,438,650 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 202 | 21,094,400 | def lessthan(arr,key):
low=0
high=len(arr)-1
while low+1<high:
mid=(low+high)//2
if arr[mid]>=key:
high=mid
else:
low=mid
return high
n=int(input())
arr=list(map(int,input().split()))
m=int(input())
val=list(map(int,... | Title: Worms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers:... | ```python
def lessthan(arr,key):
low=0
high=len(arr)-1
while low+1<high:
mid=(low+high)//2
if arr[mid]>=key:
high=mid
else:
low=mid
return high
n=int(input())
arr=list(map(int,input().split()))
m=int(input())
val=lis... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
797 | B | Odd sum | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains subsequence with odd sum.
Subsequence is a sequence that can be derived from another sequen... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=104<=≤<=*a**i*<=≤<=104). The sequence contains at least one subsequence with odd sum. | Print sum of resulting subseqeuence. | [
"4\n-2 2 -3 1\n",
"3\n2 -5 -3\n"
] | [
"3\n",
"-1\n"
] | In the first example sum of the second and the fourth elements is 3. | 0 | [
{
"input": "4\n-2 2 -3 1",
"output": "3"
},
{
"input": "3\n2 -5 -3",
"output": "-1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "1\n-1",
"output": "-1"
},
{
"input": "15\n-6004 4882 9052 413 6056 4306 9946 -4616 -6135 906 -1718 5252 -2866 9061 4046",
"ou... | 1,634,560,966 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | n = int(input())
numbers = list(map(int, input().split()))
sum_all_pos = sum(num for num in numbers if num > 0)
def isOdd(val):
return val % 2
if isOdd(sum_all_pos):
print(sum_all_pos)
else: # needs to use negative numbers to make the sum odd
sum_odd = [num for num in numbers if isOdd(num)]
print(sum_... | Title: Odd sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains... | ```python
n = int(input())
numbers = list(map(int, input().split()))
sum_all_pos = sum(num for num in numbers if num > 0)
def isOdd(val):
return val % 2
if isOdd(sum_all_pos):
print(sum_all_pos)
else: # needs to use negative numbers to make the sum odd
sum_odd = [num for num in numbers if isOdd(num)]
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
801 | A | Vicious Keyboard | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maxi... | The first line will contain a string *s* consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100. | Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character. | [
"VK\n",
"VV\n",
"V\n",
"VKKKKKKKKKVVVVVVVVVK\n",
"KVKV\n"
] | [
"1\n",
"1\n",
"0\n",
"3\n",
"1\n"
] | For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.
For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.
For the fourth case, we ... | 500 | [
{
"input": "VK",
"output": "1"
},
{
"input": "VV",
"output": "1"
},
{
"input": "V",
"output": "0"
},
{
"input": "VKKKKKKKKKVVVVVVVVVK",
"output": "3"
},
{
"input": "KVKV",
"output": "1"
},
{
"input": "VKKVVVKVKVK",
"output": "5"
},
{
"input... | 1,492,670,166 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 4,608,000 | source_text = input()
count = source_text.count('VK')
if source_text.count('VVV') != 0 or source_text.count('KKK') != 0:
count += 1
print(count) | Title: Vicious Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter i... | ```python
source_text = input()
count = source_text.count('VK')
if source_text.count('VVV') != 0 or source_text.count('KKK') != 0:
count += 1
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
221 | B | Little Elephant and Numbers | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | The Little Elephant loves numbers.
He has a positive integer *x*. The Little Elephant wants to find the number of positive integers *d*, such that *d* is the divisor of *x*, and *x* and *d* have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described num... | A single line contains a single integer *x* (1<=≤<=*x*<=≤<=109). | In a single line print an integer — the answer to the problem. | [
"1\n",
"10\n"
] | [
"1\n",
"2\n"
] | none | 1,000 | [
{
"input": "1",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "47",
"output": "1"
},
{
"input": "100",
"output": "5"
},
{
"input": "128",
"output": "6"
},
{
"input": "2",
"output": "1"
},
{
"input": "17",
"output": "2"
... | 1,665,217,872 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 39 | 124 | 1,638,400 |
def factors(n):
arr=[]
for i in range(1,int(n**(0.5))+1):
if n%i==0:
div=n//i
if i!=div:
arr.extend([i,div])
else:
arr.append(i)
return arr
x=input()
n=int(x)
arr=factors(n)
cnt=0
for i in arr:
for j in str(i)... | Title: Little Elephant and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves numbers.
He has a positive integer *x*. The Little Elephant wants to find the number of positive integers *d*, such that *d* is the divisor of *x*, and *x* and *d* have at least o... | ```python
def factors(n):
arr=[]
for i in range(1,int(n**(0.5))+1):
if n%i==0:
div=n//i
if i!=div:
arr.extend([i,div])
else:
arr.append(i)
return arr
x=input()
n=int(x)
arr=factors(n)
cnt=0
for i in arr:
for j... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,667,472,513 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | s = input()
g = []
g.append(s[0])
y = False
k = 0
for i in range(1,len(s)):
print(s[i])
if s[i] == 'l':
k += 1
if s[i] == 'l' and k <= 2:
g.append(s[i])
else:
if s[i] != s[i-1]:
g.append(s[i])
s = "".join(g)
print(s)
if len(s)>=5:
for i in... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = input()
g = []
g.append(s[0])
y = False
k = 0
for i in range(1,len(s)):
print(s[i])
if s[i] == 'l':
k += 1
if s[i] == 'l' and k <= 2:
g.append(s[i])
else:
if s[i] != s[i-1]:
g.append(s[i])
s = "".join(g)
print(s)
if len(s)>=5:
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
676 | C | Vasya and String | PROGRAMMING | 1,500 | [
"binary search",
"dp",
"strings",
"two pointers"
] | null | null | High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequence) consisting of equal letters.
Vasya can change no more than *k* characters of the original strin... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100<=000,<=0<=≤<=*k*<=≤<=*n*) — the length of the string and the maximum number of characters to change.
The second line contains the string, consisting of letters 'a' and 'b' only. | Print the only integer — the maximum beauty of the string Vasya can achieve by changing no more than *k* characters. | [
"4 2\nabba\n",
"8 1\naabaabaa\n"
] | [
"4\n",
"5\n"
] | In the first sample, Vasya can obtain both strings "aaaa" and "bbbb".
In the second sample, the optimal answer is obtained with the string "aaaaabaa" or with the string "aabaaaaa". | 1,500 | [
{
"input": "4 2\nabba",
"output": "4"
},
{
"input": "8 1\naabaabaa",
"output": "5"
},
{
"input": "1 0\na",
"output": "1"
},
{
"input": "1 1\nb",
"output": "1"
},
{
"input": "1 0\nb",
"output": "1"
},
{
"input": "1 1\na",
"output": "1"
},
{
... | 1,608,633,840 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 109 | 307,200 | n,k=map(int,input().split())
s=input()
i=0
ans=0
flag=True
while i<(n):
prev=i
j=i
curr = 0
x=k
while j<n:
if s[j]==s[i]:
curr+=1
elif s[j]!=s[i] and x<1:
flag=True
break
else:
curr+=1
x-=1
if flag==True... | Title: Vasya and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
High school student Vasya got a string of length *n* as a birthday present. This string consists of letters 'a' and 'b' only. Vasya denotes beauty of the string as the maximum length of a substring (consecutive subsequ... | ```python
n,k=map(int,input().split())
s=input()
i=0
ans=0
flag=True
while i<(n):
prev=i
j=i
curr = 0
x=k
while j<n:
if s[j]==s[i]:
curr+=1
elif s[j]!=s[i] and x<1:
flag=True
break
else:
curr+=1
x-=1
if ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
265 | A | Colorful Stones (Simplified Edition) | PROGRAMMING | 800 | [
"implementation"
] | null | null | There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th stone. If the character is "R", "G", or "B", the color of the corresponding stone is red, green, or blue, respectively.
Ini... | The input contains two lines. The first line contains the string *s* (1<=≤<=|*s*|<=≤<=50). The second line contains the string *t* (1<=≤<=|*t*|<=≤<=50). The characters of each string will be one of "R", "G", or "B". It is guaranteed that Liss don't move out of the sequence. | Print the final 1-based position of Liss in a single line. | [
"RGB\nRRR\n",
"RRRBGBRBBB\nBBBRR\n",
"BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB\n"
] | [
"2\n",
"3\n",
"15\n"
] | none | 500 | [
{
"input": "RGB\nRRR",
"output": "2"
},
{
"input": "RRRBGBRBBB\nBBBRR",
"output": "3"
},
{
"input": "BRRBGBRGRBGRGRRGGBGBGBRGBRGRGGGRBRRRBRBBBGRRRGGBBB\nBBRBGGRGRGBBBRBGRBRBBBBRBRRRBGBBGBBRRBBGGRBRRBRGRB",
"output": "15"
},
{
"input": "G\nRRBBRBRRBR",
"output": "1"
},
... | 1,662,467,430 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 92 | 0 | a = input()
b = input()
count = 0
for i in b:
if i == a[count]:
count += 1
print(count+1)
| Title: Colorful Stones (Simplified Edition)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a sequence of colorful stones. The color of each stone is one of red, green, or blue. You are given a string *s*. The *i*-th (1-based) character of *s* represents the color of the *i*-th st... | ```python
a = input()
b = input()
count = 0
for i in b:
if i == a[count]:
count += 1
print(count+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
764 | B | Timofey and cubes | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation"
] | null | null | Young Timofey has a birthday today! He got kit of *n* cubes as a birthday present from his parents. Every cube has a number *a**i*, which is written on it. Timofey put all the cubes in a row and went to unpack other presents.
In this time, Timofey's elder brother, Dima reordered the cubes using the following rule. Sup... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of cubes.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109), where *a**i* is the number written on the *i*-th cube after Dima has changed their order. | Print *n* integers, separated by spaces — the numbers written on the cubes in their initial order.
It can be shown that the answer is unique. | [
"7\n4 3 7 6 9 1 2\n",
"8\n6 1 4 2 5 6 9 2\n"
] | [
"2 3 9 6 7 1 4",
"2 1 6 2 5 4 9 6"
] | Consider the first sample.
1. At the begining row was [2, 3, 9, 6, 7, 1, 4]. 1. After first operation row was [4, 1, 7, 6, 9, 3, 2]. 1. After second operation row was [4, 3, 9, 6, 7, 1, 2]. 1. After third operation row was [4, 3, 7, 6, 9, 1, 2]. 1. At fourth operation we reverse just middle element, so nothing ha... | 1,000 | [
{
"input": "7\n4 3 7 6 9 1 2",
"output": "2 3 9 6 7 1 4"
},
{
"input": "8\n6 1 4 2 5 6 9 2",
"output": "2 1 6 2 5 4 9 6"
},
{
"input": "1\n1424",
"output": "1424"
},
{
"input": "9\n-7 9 -4 9 -6 11 15 2 -10",
"output": "-10 9 15 9 -6 11 -4 2 -7"
},
{
"input": "2\n2... | 1,510,433,661 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 561 | 17,817,600 | n=int(input())
a=list(map(int,input().split()))
for i in range(0,n//2,2):
a[i],a[n-i-1]=a[n-1-i],a[i]
print(*a)
| Title: Timofey and cubes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Young Timofey has a birthday today! He got kit of *n* cubes as a birthday present from his parents. Every cube has a number *a**i*, which is written on it. Timofey put all the cubes in a row and went to unpack other p... | ```python
n=int(input())
a=list(map(int,input().split()))
for i in range(0,n//2,2):
a[i],a[n-i-1]=a[n-1-i],a[i]
print(*a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,669,106,359 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 92 | 0 | t,s_x,s_y,e_x,e_y=map(int,input().split())
direction=input()
ans=-1
for i in range(t):
if direction[i]=="E":
if s_x<e_x:
s_x+=1
elif direction[i]=="W":
if s_x>e_x:
s_x-=1
elif direction[i]=="N":
if s_y<e_y:
s_y+=1
elif direction[... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
t,s_x,s_y,e_x,e_y=map(int,input().split())
direction=input()
ans=-1
for i in range(t):
if direction[i]=="E":
if s_x<e_x:
s_x+=1
elif direction[i]=="W":
if s_x>e_x:
s_x-=1
elif direction[i]=="N":
if s_y<e_y:
s_y+=1
elif ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,675,882,172 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 0 | n=int(input())
s=set()
for i in range(1,n+1):
for j in range(2,i):
if i%j==0:s.add(i)
for x in s:
y=n-x
if y in s:
break
print(x,y) | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n=int(input())
s=set()
for i in range(1,n+1):
for j in range(2,i):
if i%j==0:s.add(i)
for x in s:
y=n-x
if y in s:
break
print(x,y)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
900 | B | Position in Fraction | PROGRAMMING | 1,300 | [
"math",
"number theory"
] | null | null | You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point. | The first contains three single positive integers *a*, *b*, *c* (1<=≤<=*a*<=<<=*b*<=≤<=105, 0<=≤<=*c*<=≤<=9). | Print position of the first occurrence of digit *c* into the fraction. Positions are numbered from 1 after decimal point. It there is no such position, print -1. | [
"1 2 0\n",
"2 3 7\n"
] | [
"2",
"-1"
] | The fraction in the first example has the following decimal notation: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/896357459a466614a0542f34c9cfb0cef1afc9ed.png" style="max-width: 100.0%;max-height: 100.0%;"/>. The first zero stands on second position.
The fraction in the second example ... | 1,000 | [
{
"input": "1 2 0",
"output": "2"
},
{
"input": "2 3 7",
"output": "-1"
},
{
"input": "1 100000 1",
"output": "5"
},
{
"input": "1 7 7",
"output": "6"
},
{
"input": "99999 100000 8",
"output": "-1"
},
{
"input": "44102 73848 2",
"output": "132"
}... | 1,524,803,812 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 7,065,600 | import math
s=input()
a,b,c=s.split()
d=float(a)/float(b)
e=math.floor(d)
d=d-e
d=d*1000000000000000
x=str(d)
flag=1
for i in range(len(x)-2):
if x[i] == c :
print(i+1)
flag=0
break
if(flag):
print(-1)
| Title: Position in Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a fraction . You need to find the first occurrence of digit *c* into decimal notation of the fraction after decimal point.
Input Specification:
The first contains three single positive integers *a*, *b*, ... | ```python
import math
s=input()
a,b,c=s.split()
d=float(a)/float(b)
e=math.floor(d)
d=d-e
d=d*1000000000000000
x=str(d)
flag=1
for i in range(len(x)-2):
if x[i] == c :
print(i+1)
flag=0
break
if(flag):
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
804 | B | Minimum number of steps | PROGRAMMING | 1,400 | [
"combinatorics",
"greedy",
"implementation",
"math"
] | null | null | We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substring, our job is done. Print the minimum number of steps we should perform to make our job done modulo 109<=+<... | The first line contains the initial string consisting of letters 'a' and 'b' only with length from 1 to 106. | Print the minimum number of steps modulo 109<=+<=7. | [
"ab\n",
"aab\n"
] | [
"1\n",
"3\n"
] | The first example: "ab" → "bba".
The second example: "aab" → "abba" → "bbaba" → "bbbbaa". | 1,000 | [
{
"input": "ab",
"output": "1"
},
{
"input": "aab",
"output": "3"
},
{
"input": "aaaaabaabababaaaaaba",
"output": "17307"
},
{
"input": "abaabaaabbabaabab",
"output": "1795"
},
{
"input": "abbaa",
"output": "2"
},
{
"input": "abbaaabaabaaaaabbbbaababaa... | 1,602,183,680 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 202 | 6,348,800 | s = input()
qb = 0
j = 0
mod = int(10e8) + 7
for i in range(len(s)-1,-1,-1):
if s[i] == "b":
qb = (qb + 1) % mod
else:
j = (j + qb) % mod
qb = (2 * qb) % mod
print(j)
| Title: Minimum number of steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substr... | ```python
s = input()
qb = 0
j = 0
mod = int(10e8) + 7
for i in range(len(s)-1,-1,-1):
if s[i] == "b":
qb = (qb + 1) % mod
else:
j = (j + qb) % mod
qb = (2 * qb) % mod
print(j)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,580,988,545 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 140 | 0 | n = int ( input ( ) )
s = str ( input ( ) )
arr = [ 'a' , 'e' , 'i' ]
n-=1
i = 0
while i < n :
if arr.count( s[i] ) > 0 and arr.count(s[i+1])> 0:
s = s [ : i ] + s [ i ] + s [ i + 2 : ]
n-=1
i -= 1
i += 1
print ( s )
| Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
n = int ( input ( ) )
s = str ( input ( ) )
arr = [ 'a' , 'e' , 'i' ]
n-=1
i = 0
while i < n :
if arr.count( s[i] ) > 0 and arr.count(s[i+1])> 0:
s = s [ : i ] + s [ i ] + s [ i + 2 : ]
n-=1
i -= 1
i += 1
print ( s )
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
285 | B | Find Marble | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the glasses are not.
First Petya puts a marble under the glass in position *s*. Then he performs som... | The first line contains three integers: *n*,<=*s*,<=*t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*s*,<=*t*<=≤<=*n*) — the number of glasses, the ball's initial and final position. The second line contains *n* space-separated integers: *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — the shuffling operation parameters. It is guaran... | If the marble can move from position *s* to position *t*, then print on a single line a non-negative integer — the minimum number of shuffling operations, needed to get the marble to position *t*. If it is impossible, print number -1. | [
"4 2 1\n2 3 4 1\n",
"4 3 3\n4 1 3 2\n",
"4 3 4\n1 2 3 4\n",
"3 1 3\n2 1 3\n"
] | [
"3\n",
"0\n",
"-1\n",
"-1\n"
] | none | 1,000 | [
{
"input": "4 2 1\n2 3 4 1",
"output": "3"
},
{
"input": "4 3 3\n4 1 3 2",
"output": "0"
},
{
"input": "4 3 4\n1 2 3 4",
"output": "-1"
},
{
"input": "3 1 3\n2 1 3",
"output": "-1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "10 6 7\n10 7 8 1... | 1,541,699,650 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 7,065,600 | n,s,t=map(int,input().split())
p=[int(x) for x in input().split()]
pos=[]
flag=0
if s==t:
print(0)
exit()
for i in range(len(p)):
if p[s-1] not in pos:
pos.append(p[s-1])
s=p[s-1]
else:
break
if p[s-1]==t:
pos.append(p[s-1])
flag=1
break
if flag==1:
... | Title: Find Marble
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are playing a game. Petya's got *n* non-transparent glasses, standing in a row. The glasses' positions are indexed with integers from 1 to *n* from left to right. Note that the positions are indexed but the ... | ```python
n,s,t=map(int,input().split())
p=[int(x) for x in input().split()]
pos=[]
flag=0
if s==t:
print(0)
exit()
for i in range(len(p)):
if p[s-1] not in pos:
pos.append(p[s-1])
s=p[s-1]
else:
break
if p[s-1]==t:
pos.append(p[s-1])
flag=1
break
if f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,692,193,598 | 2,147,483,647 | Python 3 | IDLENESS_LIMIT_EXCEEDED | TESTS | 0 | 0 | 0 | w = int(input())
from time import sleep
while True:
sleep(1)
print("Slept for 1 second") | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
w = int(input())
from time import sleep
while True:
sleep(1)
print("Slept for 1 second")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,594,962,420 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 93 | 6,963,200 | a=input()
if len(a)==11:
s=""
s+=a[0]
s+=a[1]
s=int(s)
if s==30:
print(11)
elif s==31:
print(7)
else:
print(12)
elif len(a)==9:
s=""
s=a[0]
s=int(s)
if s==1... | Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
a=input()
if len(a)==11:
s=""
s+=a[0]
s+=a[1]
s=int(s)
if s==30:
print(11)
elif s==31:
print(7)
else:
print(12)
elif len(a)==9:
s=""
s=a[0]
s=int(s)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
90 | A | Cableway | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | A. Cableway | 2 | 256 | A group of university students wants to get to the top of a mountain to have a picnic there. For that they decided to use a cableway.
A cableway is represented by some cablecars, hanged onto some cable stations by a cable. A cable is scrolled cyclically between the first and the last cable stations (the first of them ... | The first line contains three integers *r*, *g* and *b* (0<=≤<=*r*,<=*g*,<=*b*<=≤<=100). It is guaranteed that *r*<=+<=*g*<=+<=*b*<=><=0, it means that the group consists of at least one student. | Print a single number — the minimal time the students need for the whole group to ascend to the top of the mountain. | [
"1 3 2\n",
"3 2 1\n"
] | [
"34",
"33"
] | Let's analyze the first sample.
At the moment of time 0 a red cablecar comes and one student from the *r* group get on it and ascends to the top at the moment of time 30.
At the moment of time 1 a green cablecar arrives and two students from the *g* group get on it; they get to the top at the moment of time 31.
At t... | 500 | [
{
"input": "1 3 2",
"output": "34"
},
{
"input": "3 2 1",
"output": "33"
},
{
"input": "3 5 2",
"output": "37"
},
{
"input": "10 10 10",
"output": "44"
},
{
"input": "29 7 24",
"output": "72"
},
{
"input": "28 94 13",
"output": "169"
},
{
"... | 1,382,794,179 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 307,200 | r, g, b = map(int, input().split())
print(max(3 * (r - 1) // 2, 1 + 3 * (g - 1) // 2, 2 + 3 * (b - 1) // 2) + 30) | Title: Cableway
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A group of university students wants to get to the top of a mountain to have a picnic there. For that they decided to use a cableway.
A cableway is represented by some cablecars, hanged onto some cable stations by a cable. A cabl... | ```python
r, g, b = map(int, input().split())
print(max(3 * (r - 1) // 2, 1 + 3 * (g - 1) // 2, 2 + 3 * (b - 1) // 2) + 30)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
393 | A | Nineteen | PROGRAMMING | 0 | [] | null | null | Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) ... | The first line contains a non-empty string *s*, consisting only of lowercase English letters. The length of string *s* doesn't exceed 100. | Print a single integer — the maximum number of "nineteen"s that she can get in her string. | [
"nniinneetteeeenn\n",
"nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii\n",
"nineteenineteen\n"
] | [
"2",
"2",
"2"
] | none | 500 | [
{
"input": "nniinneetteeeenn",
"output": "2"
},
{
"input": "nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii",
"output": "2"
},
{
"input": "nineteenineteen",
"output": "2"
},
{
"input": "nssemsnnsitjtihtthij",
"output": "0"
},
{
"input": "eehihnttehtherjsihihn... | 1,585,844,925 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 93 | 307,200 |
inp_txt = input("")
n_dic = {
"n": 0,
"i": 0,
"e": 0,
"t": 0,
}
for i in range( len(inp_txt) ):
if inp_txt[i] in n_dic:
n_dic[inp_txt[i]] += 1
for key in n_dic.keys():
if(key == "n"):
if n_dic["n"] % 3 == 0:
n_dic["n"] = n_dic["n"] / 3
... | Title: Nineteen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice likes word "nineteen" very much. She has a string *s* and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiinetee... | ```python
inp_txt = input("")
n_dic = {
"n": 0,
"i": 0,
"e": 0,
"t": 0,
}
for i in range( len(inp_txt) ):
if inp_txt[i] in n_dic:
n_dic[inp_txt[i]] += 1
for key in n_dic.keys():
if(key == "n"):
if n_dic["n"] % 3 == 0:
n_dic["n"] = n_dic[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
991 | D | Bishwock | PROGRAMMING | 1,500 | [
"dp",
"greedy"
] | null | null | Bishwock is a chess figure that consists of three squares resembling an "L-bar". This figure can be rotated by 90, 180 and 270 degrees so it can have four possible states:
Bishwocks don't attack any squares and can even occupy on the adjacent squares as long as they don't occupy the same square.
Vasya has a board wi... | The input contains two nonempty strings that describe Vasya's board. Those strings contain only symbols "0" (zero) that denote the empty squares and symbols "X" (uppercase English letter) that denote the squares occupied by pawns. Strings are nonempty and are of the same length that does not exceed $100$. | Output a single integer — the maximum amount of bishwocks that can be placed onto the given board. | [
"00\n00\n",
"00X00X0XXX0\n0XXX0X00X00\n",
"0X0X0\n0X0X0\n",
"0XXX0\n00000\n"
] | [
"1",
"4",
"0",
"2"
] | none | 1,500 | [
{
"input": "00\n00",
"output": "1"
},
{
"input": "00X00X0XXX0\n0XXX0X00X00",
"output": "4"
},
{
"input": "0X0X0\n0X0X0",
"output": "0"
},
{
"input": "0XXX0\n00000",
"output": "2"
},
{
"input": "0\n0",
"output": "0"
},
{
"input": "0\nX",
"output": "... | 1,689,046,487 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 72 | 62 | 0 | a = list(input())
b = list(input())
n = len(a)
r = p = 0
for i in range(n):
c = 1 if a[i] != b[i] else (0 if a[i] == 'X' else 2)
p += c
if p < 3:
p = c
else:
r += 1
p = 0 if p == 3 else 1
print(r) | Title: Bishwock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bishwock is a chess figure that consists of three squares resembling an "L-bar". This figure can be rotated by 90, 180 and 270 degrees so it can have four possible states:
Bishwocks don't attack any squares and can even occup... | ```python
a = list(input())
b = list(input())
n = len(a)
r = p = 0
for i in range(n):
c = 1 if a[i] != b[i] else (0 if a[i] == 'X' else 2)
p += c
if p < 3:
p = c
else:
r += 1
p = 0 if p == 3 else 1
print(r)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Alice and Bob begin their day with a quick game. They first choose a starting number *X*0<=≥<=3 and try to reach one million by the process described below.
Alice goes first and then they take alternating turns. In the *i*-th turn, the player whose turn it is selects a prime number smaller than the current number, an... | The input contains a single integer *X*2 (4<=≤<=*X*2<=≤<=106). It is guaranteed that the integer *X*2 is composite, that is, is not prime. | Output a single integer — the minimum possible *X*0. | [
"14\n",
"20\n",
"8192\n"
] | [
"6\n",
"15\n",
"8191\n"
] | In the first test, the smallest possible starting number is *X*<sub class="lower-index">0</sub> = 6. One possible course of the game is as follows:
- Alice picks prime 5 and announces *X*<sub class="lower-index">1</sub> = 10 - Bob picks prime 7 and announces *X*<sub class="lower-index">2</sub> = 14.
In the second ... | 0 | [
{
"input": "14",
"output": "6"
},
{
"input": "20",
"output": "15"
},
{
"input": "8192",
"output": "8191"
},
{
"input": "1000000",
"output": "998677"
},
{
"input": "959806",
"output": "239958"
},
{
"input": "1452",
"output": "1206"
},
{
"inp... | 1,520,700,670 | 4,570 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 62 | 5,632,000 | prime_number = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71
,73,79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163,167,173
,179,181,191,193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281
,283,293,307,311,313,317,331,337,347,349,353,359,367,373,379,383,389,397,401,409
,419,4... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice and Bob begin their day with a quick game. They first choose a starting number *X*0<=≥<=3 and try to reach one million by the process described below.
Alice goes first and then they take alternating turns. In the *i*-th tu... | ```python
prime_number = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71
,73,79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163,167,173
,179,181,191,193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281
,283,293,307,311,313,317,331,337,347,349,353,359,367,373,379,383,389,397,401,4... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,680,373,887 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 280 | 20,480,000 | n = int(input())
lista1 = list(map(int, input().split(" ")))
lista2 = list(map(int, input().split(" ")))
lista3 = list(map(int, input().split(" ")))
dicionario1 = dict()
for i in lista1:
if(i in dicionario1):
dicionario1[i] += 1
else:
dicionario1[i] = 0
dicionario2 = dict()
fo... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
n = int(input())
lista1 = list(map(int, input().split(" ")))
lista2 = list(map(int, input().split(" ")))
lista3 = list(map(int, input().split(" ")))
dicionario1 = dict()
for i in lista1:
if(i in dicionario1):
dicionario1[i] += 1
else:
dicionario1[i] = 0
dicionario2 = di... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
844 | A | Diversity | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"strings"
] | null | null | Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too. | First line of input contains string *s*, consisting only of lowercase Latin letters (1<=≤<=|*s*|<=≤<=1000, |*s*| denotes the length of *s*).
Second line of input contains integer *k* (1<=≤<=*k*<=≤<=26). | Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible. | [
"yandex\n6\n",
"yahoo\n5\n",
"google\n7\n"
] | [
"0\n",
"1\n",
"impossible\n"
] | In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'*a*', '*h*', '*o*', '*y*'}. To get 5 different letters it is necessary to change one occurrence of '*o*' to some letter, which doesn't occur in the string, for... | 500 | [
{
"input": "yandex\n6",
"output": "0"
},
{
"input": "yahoo\n5",
"output": "1"
},
{
"input": "google\n7",
"output": "impossible"
},
{
"input": "a\n1",
"output": "0"
},
{
"input": "z\n2",
"output": "impossible"
},
{
"input": "fwgfrwgkuwghfiruhewgirueguhe... | 1,584,668,295 | 1,095 | Python 3 | WRONG_ANSWER | TESTS | 5 | 93 | 0 | '''A1
k=int(input())
a = [int(s) for s in input().split()]
if 1 in a:
print('HARD')
else:
print('EASY')'''
''' B
k=int(input())
l=[]
j=[]
for i in range(k):
k=[int(s) for s in input().split()]
h=abs(k[0]-23)*60
m=abs(k[1]-60)
r=h+m
j.append(r)
for o in j:
print(o)
'''
'''
t=[int(s) for ... | Title: Diversity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calculate the minimum number of characters you need to change in the string *s*, so that it contains at least *k* different letters, or print that it is impossible.
String *s* consists only of lowercase Latin letters, and it... | ```python
'''A1
k=int(input())
a = [int(s) for s in input().split()]
if 1 in a:
print('HARD')
else:
print('EASY')'''
''' B
k=int(input())
l=[]
j=[]
for i in range(k):
k=[int(s) for s in input().split()]
h=abs(k[0]-23)*60
m=abs(k[1]-60)
r=h+m
j.append(r)
for o in j:
print(o)
'''
'''
t=[i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
3 | A | Shortest path of the king | PROGRAMMING | 1,000 | [
"greedy",
"shortest paths"
] | A. Shortest path of the king | 1 | 64 | The king is left alone on the chessboard. In spite of this loneliness, he doesn't lose heart, because he has business of national importance. For example, he has to pay an official visit to square *t*. As the king is not in habit of wasting his time, he wants to get from his current position *s* to square *t* in the le... | The first line contains the chessboard coordinates of square *s*, the second line — of square *t*.
Chessboard coordinates consist of two characters, the first one is a lowercase Latin letter (from a to h), the second one is a digit from 1 to 8. | In the first line print *n* — minimum number of the king's moves. Then in *n* lines print the moves themselves. Each move is described with one of the 8: L, R, U, D, LU, LD, RU or RD.
L, R, U, D stand respectively for moves left, right, up and down (according to the picture), and 2-letter combinations stand for diago... | [
"a8\nh1\n"
] | [
"7\nRD\nRD\nRD\nRD\nRD\nRD\nRD\n"
] | none | 0 | [
{
"input": "a8\nh1",
"output": "7\nRD\nRD\nRD\nRD\nRD\nRD\nRD"
},
{
"input": "b2\nb4",
"output": "2\nU\nU"
},
{
"input": "a5\na5",
"output": "0"
},
{
"input": "h1\nb2",
"output": "6\nLU\nL\nL\nL\nL\nL"
},
{
"input": "c5\nh2",
"output": "5\nRD\nRD\nRD\nR\nR"
... | 1,608,351,595 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 280 | 0 | import sys
def rf():
lines = []
while True:
try:
lines.append(input())
except:
break
return lines
def ri():
return int(input())
def rl():
return list(map(int,input().split()))
start = input()
arrival = input()
alphabet = "abcdefgh"... | Title: Shortest path of the king
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The king is left alone on the chessboard. In spite of this loneliness, he doesn't lose heart, because he has business of national importance. For example, he has to pay an official visit to square *t*. As the king ... | ```python
import sys
def rf():
lines = []
while True:
try:
lines.append(input())
except:
break
return lines
def ri():
return int(input())
def rl():
return list(map(int,input().split()))
start = input()
arrival = input()
alphabet = ... | 0 | MatrixStudio/Codeforces-Python-Submissions |
352 | B | Jeff and Periods | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
- *x* occurs in sequence *a*. - Consider all positions of numbers *x* in the sequence *a* (such *i*, ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). The numbers are separated by spaces. | In the first line print integer *t* — the number of valid *x*. On each of the next *t* lines print two integers *x* and *p**x*, where *x* is current suitable value, *p**x* is the common difference between numbers in the progression (if *x* occurs exactly once in the sequence, *p**x* must equal 0). Print the pairs in th... | [
"1\n2\n",
"8\n1 2 1 3 1 2 1 5\n"
] | [
"1\n2 0\n",
"4\n1 2\n2 4\n3 0\n5 0\n"
] | In the first test 2 occurs exactly once in the sequence, ergo *p*<sub class="lower-index">2</sub> = 0. | 1,000 | [
{
"input": "1\n2",
"output": "1\n2 0"
},
{
"input": "8\n1 2 1 3 1 2 1 5",
"output": "4\n1 2\n2 4\n3 0\n5 0"
},
{
"input": "3\n1 10 5",
"output": "3\n1 0\n5 0\n10 0"
},
{
"input": "4\n9 9 3 5",
"output": "3\n3 0\n5 0\n9 1"
},
{
"input": "6\n1 2 2 1 1 2",
"outpu... | 1,639,766,088 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 11 | 1,000 | 7,372,800 | n = int(input())
lst = list(map(int,input().split()))
st = sorted(list(set(lst)))
dct = {}
for i in st:
if lst.count(i) == 1:
dct[i] = 0
elif lst.count(i) == 2:
fstpos = lst.index(i)
secpos = lst[fstpos+1:].index(i)+(fstpos+1)
cd = secpos-fstpos
dct[i] = cd
... | Title: Jeff and Periods
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Jeff got hold of an integer sequence *a*1, *a*2, ..., *a**n* of length *n*. The boy immediately decided to analyze the sequence. For that, he needs to find all values of *x*, for which these conditions hold:
-... | ```python
n = int(input())
lst = list(map(int,input().split()))
st = sorted(list(set(lst)))
dct = {}
for i in st:
if lst.count(i) == 1:
dct[i] = 0
elif lst.count(i) == 2:
fstpos = lst.index(i)
secpos = lst[fstpos+1:].index(i)+(fstpos+1)
cd = secpos-fstpos
dct[i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
427 | C | Checkposts | PROGRAMMING | 1,700 | [
"dfs and similar",
"graphs",
"two pointers"
] | null | null | Your city has *n* junctions. There are *m* one-way roads between the junctions. As a mayor of the city, you have to ensure the security of all the junctions.
To ensure the security, you have to build some police checkposts. Checkposts can only be built in a junction. A checkpost at junction *i* can protect junction *j... | In the first line, you will be given an integer *n*, number of junctions (1<=≤<=*n*<=≤<=105). In the next line, *n* space-separated integers will be given. The *i**th* integer is the cost of building checkpost at the *i**th* junction (costs will be non-negative and will not exceed 109).
The next line will contain an i... | Print two integers separated by spaces. The first one is the minimum possible money needed to ensure the security of all the junctions. And the second one is the number of ways you can ensure the security modulo 1000000007 (109<=+<=7). | [
"3\n1 2 3\n3\n1 2\n2 3\n3 2\n",
"5\n2 8 0 6 0\n6\n1 4\n1 3\n2 4\n3 4\n4 5\n5 1\n",
"10\n1 3 2 2 1 3 1 4 10 10\n12\n1 2\n2 3\n3 1\n3 4\n4 5\n5 6\n5 7\n6 4\n7 3\n8 9\n9 10\n10 9\n",
"2\n7 91\n2\n1 2\n2 1\n"
] | [
"3 1\n",
"8 2\n",
"15 6\n",
"7 1\n"
] | none | 1,500 | [
{
"input": "3\n1 2 3\n3\n1 2\n2 3\n3 2",
"output": "3 1"
},
{
"input": "5\n2 8 0 6 0\n6\n1 4\n1 3\n2 4\n3 4\n4 5\n5 1",
"output": "8 2"
},
{
"input": "10\n1 3 2 2 1 3 1 4 10 10\n12\n1 2\n2 3\n3 1\n3 4\n4 5\n5 6\n5 7\n6 4\n7 3\n8 9\n9 10\n10 9",
"output": "15 6"
},
{
"input": ... | 1,675,863,131 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 70 | 997 | 48,025,600 | import sys, threading
import math
from os import path
from collections import deque, defaultdict, Counter
from bisect import *
from string import ascii_lowercase
from functools import cmp_to_key
from random import randint
import heapq
def readInts():
x = list(map(int, (sys.stdin.readline().rstrip().... | Title: Checkposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your city has *n* junctions. There are *m* one-way roads between the junctions. As a mayor of the city, you have to ensure the security of all the junctions.
To ensure the security, you have to build some police checkposts.... | ```python
import sys, threading
import math
from os import path
from collections import deque, defaultdict, Counter
from bisect import *
from string import ascii_lowercase
from functools import cmp_to_key
from random import randint
import heapq
def readInts():
x = list(map(int, (sys.stdin.readline()... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,693,190,969 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | s1, s2, s3, s4 = map(int, input().split())
ans = 0
count = 1
if s1 != s2 and s1 != s3 and s1 != s4:
count += 1
if s2 != s3 and s2 != s4:
count += 1
if s3 != s4:
count += 1
ans = 4 - count
print(ans) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
s1, s2, s3, s4 = map(int, input().split())
ans = 0
count = 1
if s1 != s2 and s1 != s3 and s1 != s4:
count += 1
if s2 != s3 and s2 != s4:
count += 1
if s3 != s4:
count += 1
ans = 4 - count
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
729 | B | Spotlights | PROGRAMMING | 1,200 | [
"dp",
"implementation"
] | null | null | Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to place a spotlight on the stage in some good position. The spotlight will project light in one of t... | The first line contains two positive integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the plan.
The next *n* lines contain *m* integers, 0 or 1 each — the description of the plan. Integer 1, means there will be an actor in the corresponding cell, while 0 means the cell ... | Print one integer — the number of good positions for placing the spotlight. | [
"2 4\n0 1 0 0\n1 0 1 0\n",
"4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0\n"
] | [
"9\n",
"20\n"
] | In the first example the following positions are good:
1. the (1, 1) cell and right direction; 1. the (1, 1) cell and down direction; 1. the (1, 3) cell and left direction; 1. the (1, 3) cell and down direction; 1. the (1, 4) cell and left direction; 1. the (2, 2) cell and left direction; 1. the (2, 2) cell and... | 1,000 | [
{
"input": "2 4\n0 1 0 0\n1 0 1 0",
"output": "9"
},
{
"input": "4 4\n0 0 0 0\n1 0 0 1\n0 1 1 0\n0 1 0 0",
"output": "20"
},
{
"input": "1 5\n1 1 0 0 0",
"output": "3"
},
{
"input": "2 10\n0 0 0 0 0 0 0 1 0 0\n1 0 0 0 0 0 0 0 0 0",
"output": "20"
},
{
"input": "3 ... | 1,479,634,348 | 1,648 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 6 | 1,000 | 6,553,600 | m, n = map(int, input().split())
l = []
k = 0
for j in range(m):
l.append(list(input().split()))
for x in range(m):
for y in range(n):
if l[x][y] == '0':
if '1' in l[x][y + 1:]:
k += 1
if '1' in l[x][:y]:
k += 1
if '1' in [l... | Title: Spotlights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Theater stage is a rectangular field of size *n*<=×<=*m*. The director gave you the stage's plan which actors will follow. For each cell it is stated in the plan if there would be an actor in this cell or not.
You are to pl... | ```python
m, n = map(int, input().split())
l = []
k = 0
for j in range(m):
l.append(list(input().split()))
for x in range(m):
for y in range(n):
if l[x][y] == '0':
if '1' in l[x][y + 1:]:
k += 1
if '1' in l[x][:y]:
k += 1
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prim... | The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query. | For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings. | [
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] | [
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] | 12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | 0 | [
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
... | 1,508,056,377 | 1,677 | Python 3 | WRONG_ANSWER | PRETESTS | 4 | 46 | 0 | q = int(input())
for i in range(q):
n = int(input())
if n % 2 == 1:
print(-1)
else:
if n == 2:
print(-1)
else:
print(int(n/4)) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, i... | ```python
q = int(input())
for i in range(q):
n = int(input())
if n % 2 == 1:
print(-1)
else:
if n == 2:
print(-1)
else:
print(int(n/4))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
680 | B | Bear and Finding Criminals | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city *a*. His job is to catch criminals. It's hard because he doesn't know in which cities criminals are. Though, he... | The first line of the input contains two integers *n* and *a* (1<=≤<=*a*<=≤<=*n*<=≤<=100) — the number of cities and the index of city where Limak lives.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (0<=≤<=*t**i*<=≤<=1). There are *t**i* criminals in the *i*-th city. | Print the number of criminals Limak will catch. | [
"6 3\n1 1 1 0 1 0\n",
"5 2\n0 0 0 1 0\n"
] | [
"3\n",
"1\n"
] | In the first sample, there are six cities and Limak lives in the third one (blue arrow below). Criminals are in cities marked red.
Using the BCD gives Limak the following information:
- There is one criminal at distance 0 from the third city — Limak is sure that this criminal is exactly in the third city. - There i... | 1,000 | [
{
"input": "6 3\n1 1 1 0 1 0",
"output": "3"
},
{
"input": "5 2\n0 0 0 1 0",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 1\n0",
"output": "0"
},
{
"input": "9 3\n1 1 1 1 1 1 1 1 0",
"output": "8"
},
{
"input": "9 5\n1 0 1 0 1 0... | 1,608,169,696 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 204,800 | def solve():
n,k = map(int,input().split())
arr = list(map(int,input().split()))
k-=1
start = k-1
end = k+1
count = arr[k-1]
while start>-1 or end<n:
#print(start,end,count)
if start<0:
count+=arr[end]
elif end>=n:
count += arr[star... | Title: Bear and Finding Criminals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Bearland, numbered 1 through *n*. Cities are arranged in one long row. The distance between cities *i* and *j* is equal to |*i*<=-<=*j*|.
Limak is a police officer. He lives in a city... | ```python
def solve():
n,k = map(int,input().split())
arr = list(map(int,input().split()))
k-=1
start = k-1
end = k+1
count = arr[k-1]
while start>-1 or end<n:
#print(start,end,count)
if start<0:
count+=arr[end]
elif end>=n:
count +... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
552 | B | Vanya and Books | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assigned distinct numbers.
Vanya wants to know how many digits he will have to write down as he labels th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109) — the number of books in the library. | Print the number of digits needed to number all the books. | [
"13\n",
"4\n"
] | [
"17\n",
"4\n"
] | Note to the first test. The books get numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, which totals to 17 digits.
Note to the second sample. The books get numbers 1, 2, 3, 4, which totals to 4 digits. | 1,000 | [
{
"input": "13",
"output": "17"
},
{
"input": "4",
"output": "4"
},
{
"input": "100",
"output": "192"
},
{
"input": "99",
"output": "189"
},
{
"input": "1000000000",
"output": "8888888899"
},
{
"input": "1000000",
"output": "5888896"
},
{
"... | 1,641,829,349 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | from sys import stdin
import math
for _ in range(int(stdin.readline())):
n=int(stdin.readline())
ans=0
l=math.floor(math.log10(n)+1)
for i in range(1,11):
if(i==l):
ans+=(n-10**(i-1)+1)*i
elif(i<l):
ans+=(9 * 10**(i - 1)) * i
else:
... | Title: Vanya and Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the *n* books should be assigned with a number from 1 to *n*. Naturally, distinct books should be assig... | ```python
from sys import stdin
import math
for _ in range(int(stdin.readline())):
n=int(stdin.readline())
ans=0
l=math.floor(math.log10(n)+1)
for i in range(1,11):
if(i==l):
ans+=(n-10**(i-1)+1)*i
elif(i<l):
ans+=(9 * 10**(i - 1)) * i
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,627,878,694 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 77 | 6,758,400 | n=int(input())
for i in range(n):
s=list(input())
a=[]
a.append(s)
if (a.count('x'))%2==0:
print("YES")
else:
print("NO") | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n=int(input())
for i in range(n):
s=list(input())
a=[]
a.append(s)
if (a.count('x'))%2==0:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,622,920,448 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 60 | 218 | 0 | n = int(input())
list = [int(x) for x in input().split()]
longest = 0
current = 0
increasing = True
streak = 0
for el in list:
if el >= current and increasing:
streak += 1
elif el < current:
streak += 1
increasing = False
elif el >= current:
increasing = True
streak =... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
n = int(input())
list = [int(x) for x in input().split()]
longest = 0
current = 0
increasing = True
streak = 0
for el in list:
if el >= current and increasing:
streak += 1
elif el < current:
streak += 1
increasing = False
elif el >= current:
increasing = True
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
535 | A | Tavas and Nafas | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.
He ate coffee mix without... | The first and only line of input contains an integer *s* (0<=≤<=*s*<=≤<=99), Tavas's score. | In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces. | [
"6\n",
"99\n",
"20\n"
] | [
"six\n",
"ninety-nine\n",
"twenty\n"
] | You can find all you need to know about English numerals in [http://en.wikipedia.org/wiki/English_numerals](https://en.wikipedia.org/wiki/English_numerals) . | 500 | [
{
"input": "6",
"output": "six"
},
{
"input": "99",
"output": "ninety-nine"
},
{
"input": "20",
"output": "twenty"
},
{
"input": "10",
"output": "ten"
},
{
"input": "15",
"output": "fifteen"
},
{
"input": "27",
"output": "twenty-seven"
},
{
... | 1,518,281,662 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 5,632,000 | s=int(input())
a = ['','one','two','three','four','five','six','seven','eight','nine']
b = ['twenty','thirty','forty','fifty','sixty','seventy','eighty','ninety']
if s == 0: print('zero')
elif s == 10 : print('ten')
elif s == 11: print('eleven')
elif s == 12: print('twelve')
elif s == 13: print('thirteen')
elif... | Title: Tavas and Nafas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score wit... | ```python
s=int(input())
a = ['','one','two','three','four','five','six','seven','eight','nine']
b = ['twenty','thirty','forty','fifty','sixty','seventy','eighty','ninety']
if s == 0: print('zero')
elif s == 10 : print('ten')
elif s == 11: print('eleven')
elif s == 12: print('twelve')
elif s == 13: print('thirte... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
755 | C | PolandBall and Forest | PROGRAMMING | 1,300 | [
"dfs and similar",
"dsu",
"graphs",
"interactive",
"trees"
] | null | null | PolandBall lives in a forest with his family. There are some trees in the forest. Trees are undirected acyclic graphs with *k* vertices and *k*<=-<=1 edges, where *k* is some integer. Note that one vertex is a valid tree.
There is exactly one relative living in each vertex of each tree, they have unique ids from 1 to ... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=104) — the number of Balls living in the forest.
The second line contains a sequence *p*1,<=*p*2,<=...,<=*p**n* of length *n*, where (1<=≤<=*p**i*<=≤<=*n*) holds and *p**i* denotes the most distant from Ball *i* relative living on the same tree. If there are se... | You should output the number of trees in the forest where PolandBall lives. | [
"5\n2 1 5 3 3",
"1\n1\n"
] | [
"2",
"1"
] | In the first sample testcase, possible forest is: 1-2 3-4-5.
There are 2 trees overall.
In the second sample testcase, the only possible graph is one vertex and no edges. Therefore, there is only one tree. | 1,500 | [
{
"input": "5 3\n1 2\n3 4\n4 5",
"output": "2"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "5 1\n4 5",
"output": "4"
},
{
"input": "10 3\n2 8\n5 9\n6 10",
"output": "7"
},
{
"input": "18 2\n9 17\n1 18",
"output": "16"
},
{
"input": "1 0",
"out... | 1,640,209,667 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 92 | 2,048,000 | from collections import *
def dfs(start, visited, current):
visited[start] = current
to_visit = [start]
while to_visit:
node = to_visit.pop()
for child in graph[node]:
if not visited[child]:
visited[child] = current
to_visit.append(chi... | Title: PolandBall and Forest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall lives in a forest with his family. There are some trees in the forest. Trees are undirected acyclic graphs with *k* vertices and *k*<=-<=1 edges, where *k* is some integer. Note that one vertex is a val... | ```python
from collections import *
def dfs(start, visited, current):
visited[start] = current
to_visit = [start]
while to_visit:
node = to_visit.pop()
for child in graph[node]:
if not visited[child]:
visited[child] = current
to_visit.... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,680,463,984 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 122 | 0 | s=input()
answer=''
index=0
while index<len(s):
if s[index]=='.':
answer+='0'
index+=1
elif s[index]=='-' and index<len(s)-1:
if s[index+1]=='.':
answer+='1'
else:
answer+='2'
index+=2
print(answer) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s=input()
answer=''
index=0
while index<len(s):
if s[index]=='.':
answer+='0'
index+=1
elif s[index]=='-' and index<len(s)-1:
if s[index+1]=='.':
answer+='1'
else:
answer+='2'
index+=2
print(answer)
``` | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
284 | A | Cows and Primitive Roots | PROGRAMMING | 1,400 | [
"implementation",
"math",
"number theory"
] | null | null | The cows have just learned what a primitive root is! Given a prime *p*, a primitive root is an integer *x* (1<=≤<=*x*<=<<=*p*) such that none of integers *x*<=-<=1,<=*x*2<=-<=1,<=...,<=*x**p*<=-<=2<=-<=1 are divisible by *p*, but *x**p*<=-<=1<=-<=1 is.
Unfortunately, computing primitive roots can be time consumin... | The input contains a single line containing an integer *p* (2<=≤<=*p*<=<<=2000). It is guaranteed that *p* is a prime. | Output on a single line the number of primitive roots . | [
"3\n",
"5\n"
] | [
"1\n",
"2\n"
] | The only primitive root <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/3722298ba062e95b18705d1253eb4e5d31e3b2d1.png" style="max-width: 100.0%;max-height: 100.0%;"/> is 2.
The primitive roots <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1d85c6a17ef1c42b53cf9... | 500 | [
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "2"
},
{
"input": "7",
"output": "2"
},
{
"input": "11",
"output": "4"
},
{
"input": "17",
"output": "8"
},
{
"input": "19",
"output": "6"
},
{
"input": "1583",
"output": "672"
... | 1,655,297,460 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 4,096,000 | def m(x,p):
flag=1
for i in range(1,p-1):
if (x**i-1)%p==0:
flag=0
break
if flag==1:
if (x**(p-1)-1)%p!=0:
flag=0
return flag
p=int(input())
count=0
for i in range(1,p):
count+=m(i,p)
print(count) | Title: Cows and Primitive Roots
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The cows have just learned what a primitive root is! Given a prime *p*, a primitive root is an integer *x* (1<=≤<=*x*<=<<=*p*) such that none of integers *x*<=-<=1,<=*x*2<=-<=1,<=...,<=*x**p*<=-<=2<=-<=1 ar... | ```python
def m(x,p):
flag=1
for i in range(1,p-1):
if (x**i-1)%p==0:
flag=0
break
if flag==1:
if (x**(p-1)-1)%p!=0:
flag=0
return flag
p=int(input())
count=0
for i in range(1,p):
count+=m(i,p)
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
989 | A | A Blend of Springtime | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | "What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimistic.
The landscape can be expressed as a row of consecutive cells, each of which either contains a flower o... | The first and only line of input contains a non-empty string $s$ consisting of uppercase English letters 'A', 'B', 'C' and characters '.' (dots) only ($\lvert s \rvert \leq 100$) — denoting cells containing an amber flower, a buff one, a canary yellow one, and no flowers, respectively. | Output "Yes" if it's possible that all three colours appear in some cell, and "No" otherwise.
You can print each letter in any case (upper or lower). | [
".BAC.\n",
"AA..CB\n"
] | [
"Yes\n",
"No\n"
] | In the first example, the buff and canary yellow flowers can leave their petals in the central cell, blending all three colours in it.
In the second example, it's impossible to satisfy the requirement because there is no way that amber and buff meet in any cell. | 500 | [
{
"input": ".BAC.",
"output": "Yes"
},
{
"input": "AA..CB",
"output": "No"
},
{
"input": ".",
"output": "No"
},
{
"input": "ACB.AAAAAA",
"output": "Yes"
},
{
"input": "B.BC.BBBCA",
"output": "Yes"
},
{
"input": "BA..CAB..B",
"output": "Yes"
},
... | 1,553,431,312 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 93 | 0 | s = input()
for i in range(len(s) - 3):
if s[i:i + 3] in {'ABC', 'ACB', 'BAC', 'BCA', 'CAB', 'CBA'}:
print('Yes')
exit(0)
print('No')
| Title: A Blend of Springtime
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"What a pity it's already late spring," sighs Mino with regret, "one more drizzling night and they'd be gone."
"But these blends are at their best, aren't they?" Absorbed in the landscape, Kanno remains optimisti... | ```python
s = input()
for i in range(len(s) - 3):
if s[i:i + 3] in {'ABC', 'ACB', 'BAC', 'BCA', 'CAB', 'CBA'}:
print('Yes')
exit(0)
print('No')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
902 | B | Coloring a Tree | PROGRAMMING | 1,200 | [
"dfs and similar",
"dsu",
"greedy"
] | null | null | You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
You have to color the tree into the given colors using the smallest possible number of steps. On eac... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=104) — the number of vertices in the tree.
The second line contains *n*<=-<=1 integers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* means that there is an edge between vertices *i* and *p**i*.
The third line contains *n* integers *c*1,<... | Print a single integer — the minimum number of steps you have to perform to color the tree into given colors. | [
"6\n1 2 2 1 5\n2 1 1 1 1 1\n",
"7\n1 1 2 3 1 4\n3 3 1 1 1 2 3\n"
] | [
"3\n",
"5\n"
] | The tree from the first sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/10324ccdc37f95343acc4f3c6050d8c334334ffa.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color ... | 1,000 | [
{
"input": "6\n1 2 2 1 5\n2 1 1 1 1 1",
"output": "3"
},
{
"input": "7\n1 1 2 3 1 4\n3 3 1 1 1 2 3",
"output": "5"
},
{
"input": "2\n1\n2 2",
"output": "1"
},
{
"input": "3\n1 1\n2 2 2",
"output": "1"
},
{
"input": "4\n1 2 1\n1 2 3 4",
"output": "4"
},
{
... | 1,697,554,584 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 17 | 155 | 11,673,600 | import random
import sys
import os
import math
from collections import Counter, defaultdict, deque
from functools import lru_cache, reduce
from itertools import accumulate, combinations, permutations
from heapq import nsmallest, nlargest, heapify, heappop, heappush
from io import BytesIO, IOBase
from copy impo... | Title: Coloring a Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
... | ```python
import random
import sys
import os
import math
from collections import Counter, defaultdict, deque
from functools import lru_cache, reduce
from itertools import accumulate, combinations, permutations
from heapq import nsmallest, nlargest, heapify, heappop, heappush
from io import BytesIO, IOBase
from... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,594,242,693 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 109 | 6,656,000 |
string1 = input()
string2 = input()
list1 = [i for i in string1]
list2 = [i for i in string2]
##print(list2)
output = []
for i in range(len(list1)):
if list1[i] == list2[i]:
output.append(0)
else:
output.append(1)
print(''.join(map(str, output)))
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
string1 = input()
string2 = input()
list1 = [i for i in string1]
list2 = [i for i in string2]
##print(list2)
output = []
for i in range(len(list1)):
if list1[i] == list2[i]:
output.append(0)
else:
output.append(1)
print(''.join(map(str, output)))
``` | 3.960352 | MatrixStudio/Codeforces-Python-Submissions |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,640,753,262 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 218 | 0 | n = int(input())
if n%2==1:
print(-1)
else:
permutation = [i for i in range(1, n+1)]
for i in range(0, n, 2):
permutation[i], permutation[i+1] = permutation[i+1], permutation[i]
print(' '.join([str(m) for m in permutation])) | Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
n = int(input())
if n%2==1:
print(-1)
else:
permutation = [i for i in range(1, n+1)]
for i in range(0, n, 2):
permutation[i], permutation[i+1] = permutation[i+1], permutation[i]
print(' '.join([str(m) for m in permutation]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
940 | C | Phone Numbers | PROGRAMMING | 1,500 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | And where the are the phone numbers?
You are given a string *s* consisting of lowercase English letters and an integer *k*. Find the lexicographically smallest string *t* of length *k*, such that its set of letters is a subset of the set of letters of *s* and *s* is lexicographically smaller than *t*.
It's guaranteed... | The first line of input contains two space separated integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the length of *s* and the required length of *t*.
The second line of input contains the string *s* consisting of *n* lowercase English letters. | Output the string *t* conforming to the requirements above.
It's guaranteed that the answer exists. | [
"3 3\nabc\n",
"3 2\nabc\n",
"3 3\nayy\n",
"2 3\nba\n"
] | [
"aca\n",
"ac\n",
"yaa\n",
"baa\n"
] | In the first example the list of strings *t* of length 3, such that the set of letters of *t* is a subset of letters of *s* is as follows: aaa, aab, aac, aba, abb, abc, aca, acb, .... Among them, those are lexicographically greater than abc: aca, acb, .... Out of those the lexicographically smallest is aca. | 1,250 | [
{
"input": "3 3\nabc",
"output": "aca"
},
{
"input": "3 2\nabc",
"output": "ac"
},
{
"input": "3 3\nayy",
"output": "yaa"
},
{
"input": "2 3\nba",
"output": "baa"
},
{
"input": "1 3\nf",
"output": "fff"
},
{
"input": "3 1\nazz",
"output": "z"
},
... | 1,520,086,451 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 108 | 21,094,400 | n, k = [int(f) for f in input().split(' ') if f]
s = input()
minChar = 256
maxChar = 256
for i in range(n):
minChar = min(minChar, ord(s[i]))
maxChar = max(maxChar, ord(s[i]))
minChar = chr(minChar)
maxChar = chr(maxChar)
if n < k:
for i in range(k):
print(minChar, end='')
elif n == k:
for i in ... | Title: Phone Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
And where the are the phone numbers?
You are given a string *s* consisting of lowercase English letters and an integer *k*. Find the lexicographically smallest string *t* of length *k*, such that its set of letters is a ... | ```python
n, k = [int(f) for f in input().split(' ') if f]
s = input()
minChar = 256
maxChar = 256
for i in range(n):
minChar = min(minChar, ord(s[i]))
maxChar = max(maxChar, ord(s[i]))
minChar = chr(minChar)
maxChar = chr(maxChar)
if n < k:
for i in range(k):
print(minChar, end='')
elif n == k:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
3 | B | Lorry | PROGRAMMING | 1,900 | [
"greedy",
"sortings"
] | B. Lorry | 2 | 64 | A group of tourists is going to kayak and catamaran tour. A rented lorry has arrived to the boat depot to take kayaks and catamarans to the point of departure. It's known that all kayaks are of the same size (and each of them occupies the space of 1 cubic metre), and all catamarans are of the same size, but two times b... | The first line contains a pair of integer numbers *n* and *v* (1<=≤<=*n*<=≤<=105; 1<=≤<=*v*<=≤<=109), where *n* is the number of waterborne vehicles in the boat depot, and *v* is the truck body volume of the lorry in cubic metres. The following *n* lines contain the information about the waterborne vehicles, that is a ... | In the first line print the maximum possible carrying capacity of the set. In the second line print a string consisting of the numbers of the vehicles that make the optimal set. If the answer is not unique, print any of them. | [
"3 2\n1 2\n2 7\n1 3\n"
] | [
"7\n2\n"
] | none | 0 | [
{
"input": "3 2\n1 2\n2 7\n1 3",
"output": "7\n2"
},
{
"input": "5 3\n1 9\n2 9\n1 9\n2 10\n1 6",
"output": "24\n3 1 5"
},
{
"input": "10 10\n1 14\n2 15\n2 11\n2 12\n2 9\n1 14\n2 15\n1 9\n2 11\n2 6",
"output": "81\n6 1 7 2 4 9"
},
{
"input": "20 19\n2 47\n1 37\n1 48\n2 42\n2 4... | 1,636,008,698 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 4,608,000 | import operator
class Stone:
"""
石头类：
index 编号；
value 价值；
space 占用空间；
rou 价值密度；
"""
def __init__(self, index, value, space):
self.index = index
self.value = value
self.space = space
self.rou = self.value / self.space
class Bag:
"... | Title: Lorry
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
A group of tourists is going to kayak and catamaran tour. A rented lorry has arrived to the boat depot to take kayaks and catamarans to the point of departure. It's known that all kayaks are of the same size (and each of them occupies... | ```python
import operator
class Stone:
"""
石头类：
index 编号；
value 价值；
space 占用空间；
rou 价值密度；
"""
def __init__(self, index, value, space):
self.index = index
self.value = value
self.space = space
self.rou = self.value / self.space
class ... | 0 | MatrixStudio/Codeforces-Python-Submissions |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,686,461,101 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 124 | 0 | n, m = map(int, input().split())
nums = [int(x) for x in input().split()]
nums.sort()
total = 0
for num in nums:
if num < 0 and m > 0:
total -= num
m -= 1
else:
break
print(total)
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n, m = map(int, input().split())
nums = [int(x) for x in input().split()]
nums.sort()
total = 0
for num in nums:
if num < 0 and m > 0:
total -= num
m -= 1
else:
break
print(total)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
118 | B | Present from Lena | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya's birthday is approaching and Lena decided to sew a patterned handkerchief to him as a present. Lena chose digits from 0 to *n* as the pattern. The digits will form a rhombus. The largest digit *n* should be located in the centre. The digits should decrease as they approach the edges. For example, for *n*<==<=5 t... | The first line contains the single integer *n* (2<=≤<=*n*<=≤<=9). | Print a picture for the given *n*. You should strictly observe the number of spaces before the first digit on each line. Every two adjacent digits in the same line should be separated by exactly one space. There should be no spaces after the last digit at the end of each line. | [
"2\n",
"3\n"
] | [
"0\n 0 1 0\n0 1 2 1 0\n 0 1 0\n 0\n",
"0\n 0 1 0\n 0 1 2 1 0\n0 1 2 3 2 1 0\n 0 1 2 1 0\n 0 1 0\n 0\n"
] | none | 1,000 | [
{
"input": "2",
"output": " 0\n 0 1 0\n0 1 2 1 0\n 0 1 0\n 0"
},
{
"input": "3",
"output": " 0\n 0 1 0\n 0 1 2 1 0\n0 1 2 3 2 1 0\n 0 1 2 1 0\n 0 1 0\n 0"
},
{
"input": "4",
"output": " 0\n 0 1 0\n 0 1 2 1 0\n 0 1 2 3 2 1 0\n0 1 2 3 4 3 2 1 0... | 1,696,679,694 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n = int(input())
s = []
print(" "*(2*n)+"0")
for i in range(n) :
t = []
for j in range(i+1,n) :
print(" ",end=" ")
t.append(" ")
for k in range(i+1) :
print(k,end=" ")
t.append(str(k))
for l in range(i+1,-1,-1) :
print(l,end=" ")
t.append(str(... | Title: Present from Lena
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya's birthday is approaching and Lena decided to sew a patterned handkerchief to him as a present. Lena chose digits from 0 to *n* as the pattern. The digits will form a rhombus. The largest digit *n* should be loc... | ```python
n = int(input())
s = []
print(" "*(2*n)+"0")
for i in range(n) :
t = []
for j in range(i+1,n) :
print(" ",end=" ")
t.append(" ")
for k in range(i+1) :
print(k,end=" ")
t.append(str(k))
for l in range(i+1,-1,-1) :
print(l,end=" ")
t.a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
313 | B | Ilya and Queries | PROGRAMMING | 1,100 | [
"dp",
"implementation"
] | null | null | Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<... | The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-t... | Print *m* integers — the answers to the queries in the order in which they are given in the input. | [
"......\n4\n3 4\n2 3\n1 6\n2 6\n",
"#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n"
] | [
"1\n1\n5\n4\n",
"1\n1\n2\n2\n0\n"
] | none | 1,000 | [
{
"input": "......\n4\n3 4\n2 3\n1 6\n2 6",
"output": "1\n1\n5\n4"
},
{
"input": "#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4",
"output": "1\n1\n2\n2\n0"
},
{
"input": ".#...#..\n6\n1 5\n2 3\n6 7\n2 4\n2 5\n1 3",
"output": "2\n0\n0\n1\n2\n0"
},
{
"input": "#.#.#..\n5\n3 4\n4 5\n5 7\n5... | 1,699,282,103 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 1,740,800 | s = input()
n = len(s)
m = int(input())
pts = [0]*(n-1)
for i in range(n-1):
if s[i]==s[i+1] :
pts[i]+=1
for _ in range(m):
i, j = map(int, input().split())
print(sum(pts[i-1:j-1]))
| Title: Ilya and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting ... | ```python
s = input()
n = len(s)
m = int(input())
pts = [0]*(n-1)
for i in range(n-1):
if s[i]==s[i+1] :
pts[i]+=1
for _ in range(m):
i, j = map(int, input().split())
print(sum(pts[i-1:j-1]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
134 | A | Average Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one). | The first line contains the integer *n* (2<=≤<=*n*<=≤<=2·105). The second line contains elements of the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). All the elements are positive integers. | Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to *n*.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print ... | [
"5\n1 2 3 4 5\n",
"4\n50 50 50 50\n"
] | [
"1\n3 ",
"4\n1 2 3 4 "
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "1\n3 "
},
{
"input": "4\n50 50 50 50",
"output": "4\n1 2 3 4 "
},
{
"input": "3\n2 3 1",
"output": "1\n1 "
},
{
"input": "2\n4 2",
"output": "0"
},
{
"input": "2\n1 1",
"output": "2\n1 2 "
},
{
"input": "10\n3 3 3 ... | 1,396,286,661 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 966 | 14,131,200 | n=int(input())
L=list(map(int,input().split()))
s=sum(L)
Ans=""
cnt=0
for i in range(n):
x=(s-L[i])//(n-1)
if(x*(n-1)!=s-L[i]):
continue
if(x==L[i]):
Ans+=str(i+1)+" "
cnt+=1
print(cnt)
if(cnt!=0):
print(Ans)
| Title: Average Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
... | ```python
n=int(input())
L=list(map(int,input().split()))
s=sum(L)
Ans=""
cnt=0
for i in range(n):
x=(s-L[i])//(n-1)
if(x*(n-1)!=s-L[i]):
continue
if(x==L[i]):
Ans+=str(i+1)+" "
cnt+=1
print(cnt)
if(cnt!=0):
print(Ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | User ainta loves to play with cards. He has *a* cards containing letter "o" and *b* cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score is 0. 1. For each block of contiguous "o"s with length *x* the score increases by *x*2. 1.... | The first line contains two space-separated integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=105; *a*<=+<=*b*<=≥<=1) — the number of "o" cards and the number of "x" cards. | In the first line print a single integer *v* — the maximum score that ainta can obtain.
In the second line print *a*<=+<=*b* characters describing the deck. If the *k*-th card of the deck contains "o", the *k*-th character must be "o". If the *k*-th card of the deck contains "x", the *k*-th character must be "x". The ... | [
"2 3\n",
"4 0\n",
"0 4\n"
] | [
"-1\nxoxox\n",
"16\noooo",
"-16\nxxxx"
] | none | 0 | [
{
"input": "2 3",
"output": "-1\nxoxox"
},
{
"input": "4 0",
"output": "16\noooo"
},
{
"input": "0 4",
"output": "-16\nxxxx"
},
{
"input": "8 6",
"output": "46\nxxxooooooooxxx"
},
{
"input": "28691 28312",
"output": "809737773\nxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx... | 1,419,930,873 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 108 | 6,144,000 | import math,string,itertools,fractions,heapq,collections,re,array,bisect
from itertools import chain, dropwhile, permutations, combinations
from collections import defaultdict
def main2(a,b):
if a==0:
print(-b**2)
print("x"*b)
return
if b==0:
print(a**2)
print("o"*a)
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
User ainta loves to play with cards. He has *a* cards containing letter "o" and *b* cards containing letter "x". He arranges the cards in a row, and calculates the score of the deck by the formula below.
1. At first, the score i... | ```python
import math,string,itertools,fractions,heapq,collections,re,array,bisect
from itertools import chain, dropwhile, permutations, combinations
from collections import defaultdict
def main2(a,b):
if a==0:
print(-b**2)
print("x"*b)
return
if b==0:
print(a**2)
print... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
462 | A | Appleman and Easy Task | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or character 'o'. Is it true that each cell of the board has even number of adjacent cells with 'o'? Two cells... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Then *n* lines follow containing the description of the checkerboard. Each of them contains *n* characters (either 'x' or 'o') without spaces. | Print "YES" or "NO" (without the quotes) depending on the answer to the problem. | [
"3\nxxo\nxox\noxx\n",
"4\nxxxo\nxoxo\noxox\nxxxx\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "3\nxxo\nxox\noxx",
"output": "YES"
},
{
"input": "4\nxxxo\nxoxo\noxox\nxxxx",
"output": "NO"
},
{
"input": "1\no",
"output": "YES"
},
{
"input": "2\nox\nxo",
"output": "YES"
},
{
"input": "2\nxx\nxo",
"output": "NO"
},
{
"input": "3\nooo\no... | 1,546,956,806 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 31 | 124 | 0 | n = int(input())
l = [input() for i in range(n)]
s = [[0] * n] * n
for i in range(n):
for j, element in enumerate(l[i]):
if element == 'o':
if j != n-1:
s[i][j + 1] += 1
if j != 0:
s[i][j - 1] += 1
if i != n-1:
s[... | Title: Appleman and Easy Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you help him?
Given a *n*<=×<=*n* checkerboard. Each cell of the board has either character 'x', or... | ```python
n = int(input())
l = [input() for i in range(n)]
s = [[0] * n] * n
for i in range(n):
for j, element in enumerate(l[i]):
if element == 'o':
if j != n-1:
s[i][j + 1] += 1
if j != 0:
s[i][j - 1] += 1
if i != n-1:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,690,118,106 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | A, B, n = [], [], int(input())
x = 0
or _ in range(n):
a, b = map(int, input().split())
A.append([a, b])
for i in range(n):
x1 = x2 = y1 = y2 =0
for j in range(n):
if j!=i :
if (A[i][0] > A[j][0]):
x1 += 1
elif (A[i][0] < A[j][0]):
... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
A, B, n = [], [], int(input())
x = 0
or _ in range(n):
a, b = map(int, input().split())
A.append([a, b])
for i in range(n):
x1 = x2 = y1 = y2 =0
for j in range(n):
if j!=i :
if (A[i][0] > A[j][0]):
x1 += 1
elif (A[i][0] < A[j][0]):
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,697,806,227 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 46 | 0 | def main():
n, l = map(int, input().split())
v = list(map(int, input().split()))
v.sort()
a = [float(v[0])]
for i in range(1, n):
a.append(float((v[i] - v[i-1]) / 2.0))
a.append(float(l - v[-1]))
print("{:.1f}".format(max(a)))
if __name__ == "__main__":
main()... | Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
def main():
n, l = map(int, input().split())
v = list(map(int, input().split()))
v.sort()
a = [float(v[0])]
for i in range(1, n):
a.append(float((v[i] - v[i-1]) / 2.0))
a.append(float(l - v[-1]))
print("{:.1f}".format(max(a)))
if __name__ == "__main__":
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
12 | A | Super Agent | PROGRAMMING | 800 | [
"implementation"
] | A. Super Agent | 2 | 256 | There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparing special agent Pearlo for many years. When, finally, Pearlo learned all secrets of espionage... | Input contains the matrix of three rows of three symbols each. Symbol «X» means that the corresponding button was pressed, and «.» means that is was not pressed. The matrix may contain no «X», also it may contain no «.». | Print YES if the password is symmetric with respect to the central button of the terminal and NO otherwise. | [
"XX.\n...\n.XX\n",
"X.X\nX..\n...\n"
] | [
"YES\n",
"NO\n"
] | If you are not familiar with the term «central symmetry», you may look into http://en.wikipedia.org/wiki/Central_symmetry | 0 | [
{
"input": "XX.\n...\n.XX",
"output": "YES"
},
{
"input": ".X.\n.X.\n.X.",
"output": "YES"
},
{
"input": "XXX\nXXX\nXXX",
"output": "YES"
},
{
"input": "XXX\nX.X\nXXX",
"output": "YES"
},
{
"input": "X..\n.X.\n..X",
"output": "YES"
},
{
"input": "...\n... | 1,689,847,040 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 122 | 0 | # LUOGU_RID: 116627847
a=[list(input()) for b in range(3)]
if a[0][0]!=a[2][2]:
print('NO')
elif a[0][1]!=a[2][1]:
print('NO')
elif a[0][2]!=a[2][0]:
print('NO')
elif a[1][0]!=a[1][2]:
print('NO')
else:
print('YES') | Title: Super Agent
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparin... | ```python
# LUOGU_RID: 116627847
a=[list(input()) for b in range(3)]
if a[0][0]!=a[2][2]:
print('NO')
elif a[0][1]!=a[2][1]:
print('NO')
elif a[0][2]!=a[2][0]:
print('NO')
elif a[1][0]!=a[1][2]:
print('NO')
else:
print('YES')
``` | 3.9695 | MatrixStudio/Codeforces-Python-Submissions |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,695,423,570 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 14,336,000 | N = int(input())
x = input().split(" ")
q = int(input())
m = []
for i in range(q):
m.append(int(input()))
for i in m:
r = 0
for j in x:
if int(i) >= int(j):
r += 1
print(r)
| Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
N = int(input())
x = input().split(" ")
q = int(input())
m = []
for i in range(q):
m.append(int(input()))
for i in m:
r = 0
for j in x:
if int(i) >= int(j):
r += 1
print(r)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
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