contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
620 | A | Professor GukiZ's Robot | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal numbe... | The first line contains two integers *x*1,<=*y*1 (<=-<=109<=≤<=*x*1,<=*y*1<=≤<=109) — the start position of the robot.
The second line contains two integers *x*2,<=*y*2 (<=-<=109<=≤<=*x*2,<=*y*2<=≤<=109) — the finish position of the robot. | Print the only integer *d* — the minimal number of steps to get the finish position. | [
"0 0\n4 5\n",
"3 4\n6 1\n"
] | [
"5\n",
"3\n"
] | In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its *y* coordinate and get the finish position.
In the second example robot should simultaneously increase *x* coordinate and decrease *y* coordinate by one th... | 0 | [
{
"input": "0 0\n4 5",
"output": "5"
},
{
"input": "3 4\n6 1",
"output": "3"
},
{
"input": "0 0\n4 6",
"output": "6"
},
{
"input": "1 1\n-3 -5",
"output": "6"
},
{
"input": "-1 -1\n-10 100",
"output": "101"
},
{
"input": "1 -1\n100 -100",
"output":... | 1,654,083,403 | 403 | PyPy 3-64 | OK | TESTS | 75 | 61 | 0 | x1,y1=map(int,input().split())
x2,y2=map(int,input().split())
x = abs(x2-x1)
y = abs(y2-y1)
print(max(x,y)) | Title: Professor GukiZ's Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of ... | ```python
x1,y1=map(int,input().split())
x2,y2=map(int,input().split())
x = abs(x2-x1)
y = abs(y2-y1)
print(max(x,y))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
492 | A | Vanya and Cubes | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya got *n* cubes. He decided to build a pyramid from them. Vanya wants to build the pyramid as follows: the top level of the pyramid must consist of 1 cube, the second level must consist of 1<=+<=2<==<=3 cubes, the third level must have 1<=+<=2<=+<=3<==<=6 cubes, and so on. Thus, the *i*-th level of the pyramid must... | The first line contains integer *n* (1<=≤<=*n*<=≤<=104) — the number of cubes given to Vanya. | Print the maximum possible height of the pyramid in the single line. | [
"1\n",
"25\n"
] | [
"1\n",
"4\n"
] | Illustration to the second sample: | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "25",
"output": "4"
},
{
"input": "2",
"output": "1"
},
{
"input": "4115",
"output": "28"
},
{
"input": "9894",
"output": "38"
},
{
"input": "7969",
"output": "35"
},
{
"input": "6560",
"outpu... | 1,688,473,759 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | n = int(input())
level = 0
kubik_level = 0
summa = 0
while cube_all <= n:
level += 1
kubik_level += level
summa += kubik_level
print(level-1)
| Title: Vanya and Cubes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got *n* cubes. He decided to build a pyramid from them. Vanya wants to build the pyramid as follows: the top level of the pyramid must consist of 1 cube, the second level must consist of 1<=+<=2<==<=3 cubes, the t... | ```python
n = int(input())
level = 0
kubik_level = 0
summa = 0
while cube_all <= n:
level += 1
kubik_level += level
summa += kubik_level
print(level-1)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,698,897,095 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 202 | 0 | # 785A - Anton and Polyhedrons
# https://codeforces.com/problemset/problem/785/A
# Input:
# 1) Número de poliedros
poliedros = int(input())
# Número de caras entre todos los poliedros
caras = 0
for poliedro in range(0,poliedros):
# Inputs:
# 1) Poliedro actual
poliedro_actual = input()
... | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
# 785A - Anton and Polyhedrons
# https://codeforces.com/problemset/problem/785/A
# Input:
# 1) Número de poliedros
poliedros = int(input())
# Número de caras entre todos los poliedros
caras = 0
for poliedro in range(0,poliedros):
# Inputs:
# 1) Poliedro actual
poliedro_actual = i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,664,448,335 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 9,523,200 | a=int(input())
b=list(map(int,input().split()))
c=int(input())
d=list(map(int,input().split()))
vasya=0
for i in range(c):
x=b.index(d[i])+1
vasya=vasya+x
print(str(vasya)+" "+str(c*(a+1)-vasya)) | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
a=int(input())
b=list(map(int,input().split()))
c=int(input())
d=list(map(int,input().split()))
vasya=0
for i in range(c):
x=b.index(d[i])+1
vasya=vasya+x
print(str(vasya)+" "+str(c*(a+1)-vasya))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
909 | C | Python Indentation | PROGRAMMING | 1,800 | [
"dp"
] | null | null | In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python with only two types of statements.
Simple statements are written in a single line, one per line. An ex... | The first line contains a single integer *N* (1<=≤<=*N*<=≤<=5000) — the number of commands in the program. *N* lines of the program follow, each line describing a single command. Each command is either "f" (denoting "for statement") or "s" ("simple statement"). It is guaranteed that the last line is a simple statement. | Output one line containing an integer - the number of ways the given sequence of statements can be indented modulo 109<=+<=7. | [
"4\ns\nf\nf\ns\n",
"4\nf\ns\nf\ns\n"
] | [
"1\n",
"2\n"
] | In the first test case, there is only one way to indent the program: the second for statement must be part of the body of the first one.
In the second test case, there are two ways to indent the program: the second for statement can either be part of the first one's body or a separate statement following the first one... | 1,500 | [
{
"input": "4\ns\nf\nf\ns",
"output": "1"
},
{
"input": "4\nf\ns\nf\ns",
"output": "2"
},
{
"input": "156\nf\ns\nf\ns\nf\ns\ns\ns\ns\nf\ns\ns\nf\nf\ns\nf\nf\nf\nf\ns\ns\ns\nf\ns\ns\nf\nf\nf\nf\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\nf\nf\nf\ns\ns\nf\nf\ns\ns\ns\ns\nf\ns\nf\ns\nf\ns\nf\ns... | 1,519,649,453 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 5,632,000 | n=int(input())
a=[]
for i in range(n):
a.append(input())
def baz(k,h,tt):
if a[k-2]=='f':
h=tt+1
if a[k-1]=='f':
h=1
tt+=1
if k==len(a)-1:
return h
t=0
for i in range(1,h+1):
t+=baz(k+1,i,tt)
return t
print(baz(0,1,0))
| Title: Python Indentation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Python, code blocks don't have explicit begin/end or curly braces to mark beginning and end of the block. Instead, code blocks are defined by indentation.
We will consider an extremely simplified subset of Python... | ```python
n=int(input())
a=[]
for i in range(n):
a.append(input())
def baz(k,h,tt):
if a[k-2]=='f':
h=tt+1
if a[k-1]=='f':
h=1
tt+=1
if k==len(a)-1:
return h
t=0
for i in range(1,h+1):
t+=baz(k+1,i,tt)
return t
print(baz(0,1,0))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are s... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,698,742,304 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 132,608,000 | n,m=map(int,input().split())
a=list(map(int,input().split()))
distinct_nums={}
l=[]
#dp
for i in range(m):
l.append(int(input())-1)
l_sorted=l[:]
l_sorted.sort(reverse=True)
for j in range(len(l_sorted)):
if j==0:
distinct_nums[l_sorted[j]]=list(set(a[l_sorted[j]:]))
else:
disti... | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...... | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
distinct_nums={}
l=[]
#dp
for i in range(m):
l.append(int(input())-1)
l_sorted=l[:]
l_sorted.sort(reverse=True)
for j in range(len(l_sorted)):
if j==0:
distinct_nums[l_sorted[j]]=list(set(a[l_sorted[j]:]))
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,579,360,495 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 93 | 0 | s = input()
a = 'hiedi'
c = 0
b = True
for i in range(len(s)):
if i < 5:
if s[i] == a[i]:
c += 1
if c == 5:
b = False
if b:
print("YES")
else:
print("NO")
| Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
s = input()
a = 'hiedi'
c = 0
b = True
for i in range(len(s)):
if i < 5:
if s[i] == a[i]:
c += 1
if c == 5:
b = False
if b:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,619,297,685 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 8,294,400 | na, nb = map(int, input().split())
k, m = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
a.sort()
b.sort()
b.reverse()
for i1 in a[:k]:
for i2 in b[:m]:
if i1 < i2:
pass
else:
print("NO")
exit()
print("YES") | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
na, nb = map(int, input().split())
k, m = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
a.sort()
b.sort()
b.reverse()
for i1 in a[:k]:
for i2 in b[:m]:
if i1 < i2:
pass
else:
print("NO")
exit()
print("YES")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
171 | A | Mysterious numbers - 1 | PROGRAMMING | 1,200 | [
"*special",
"constructive algorithms"
] | null | null | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer. | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space. | Output a single integer. | [
"3 14\n",
"27 12\n",
"100 200\n"
] | [
"44\n",
"48\n",
"102\n"
] | none | 0 | [
{
"input": "3 14",
"output": "44"
},
{
"input": "27 12",
"output": "48"
},
{
"input": "100 200",
"output": "102"
},
{
"input": "0 0",
"output": "0"
},
{
"input": "31415 92653",
"output": "67044"
},
{
"input": "1000000000 0",
"output": "1000000000"
... | 1,585,858,526 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a=int(input)
b=int(input)
length= max(len(str(a)), len(str(b)))
difference= abs(len(str(a))-len(str(b)))
number_1=[int(d) for d in str(a)]
number_2=[int(d) for d in str(b)]
output=("")
if len(str(a))> len(str(b)):
minimum=number_2
maximum= number_1
else:
minimum=number_1
maximum=number_2
fo... | Title: Mysterious numbers - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer.
Input Specification:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109),... | ```python
a=int(input)
b=int(input)
length= max(len(str(a)), len(str(b)))
difference= abs(len(str(a))-len(str(b)))
number_1=[int(d) for d in str(a)]
number_2=[int(d) for d in str(b)]
output=("")
if len(str(a))> len(str(b)):
minimum=number_2
maximum= number_1
else:
minimum=number_1
maximum=nu... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
629 | B | Far Relative’s Problem | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Famil Door wants to celebrate his birthday with his friends from Far Far Away. He has *n* friends and each of them can come to the party in a specific range of days of the year from *a**i* to *b**i*. Of course, Famil Door wants to have as many friends celebrating together with him as possible.
Far cars are as weird as... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=5000) — then number of Famil Door's friends.
Then follow *n* lines, that describe the friends. Each line starts with a capital letter 'F' for female friends and with a capital letter 'M' for male friends. Then follow two integers *a**i* and *b**i... | Print the maximum number of people that may come to Famil Door's party. | [
"4\nM 151 307\nF 343 352\nF 117 145\nM 24 128\n",
"6\nM 128 130\nF 128 131\nF 131 140\nF 131 141\nM 131 200\nM 140 200\n"
] | [
"2\n",
"4\n"
] | In the first sample, friends 3 and 4 can come on any day in range [117, 128].
In the second sample, friends with indices 3, 4, 5 and 6 can come on day 140. | 1,000 | [
{
"input": "4\nM 151 307\nF 343 352\nF 117 145\nM 24 128",
"output": "2"
},
{
"input": "6\nM 128 130\nF 128 131\nF 131 140\nF 131 141\nM 131 200\nM 140 200",
"output": "4"
},
{
"input": "1\nF 68 307",
"output": "0"
},
{
"input": "40\nM 55 363\nF 117 252\nM 157 282\nF 322 345\... | 1,625,167,672 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 77 | 0 | list1 = []
res = []
for i in range(int(input())):
list1.append(input().split())
for i in range(len(list1)):
if list1[i][0] == "M":
for j in range(len(list1)):
if list1[j][0] == "F":
if int(list1[i][1]) <= int(list1[j][1]) <= int(list1[i][2]) \
... | Title: Far Relative’s Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famil Door wants to celebrate his birthday with his friends from Far Far Away. He has *n* friends and each of them can come to the party in a specific range of days of the year from *a**i* to *b**i*. Of course, F... | ```python
list1 = []
res = []
for i in range(int(input())):
list1.append(input().split())
for i in range(len(list1)):
if list1[i][0] == "M":
for j in range(len(list1)):
if list1[j][0] == "F":
if int(list1[i][1]) <= int(list1[j][1]) <= int(list1[i][2]) \
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
638 | D | Three-dimensional Turtle Super Computer | PROGRAMMING | 1,800 | [
"brute force",
"dfs and similar",
"graphs"
] | null | null | A super computer has been built in the Turtle Academy of Sciences. The computer consists of *n*·*m*·*k* CPUs. The architecture was the paralellepiped of size *n*<=×<=*m*<=×<=*k*, split into 1<=×<=1<=×<=1 cells, each cell contains exactly one CPU. Thus, each CPU can be simultaneously identified as a group of three numbe... | The first line contains three integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*,<=*k*<=≤<=100) — the dimensions of the Super Computer.
Then *n* blocks follow, describing the current state of the processes. The blocks correspond to the layers of the Super Computer in the order from 1 to *n*. Each block consists of *m* lines,... | Print a single integer — the number of critical CPUs, that is, such that turning only this CPU off will disrupt some control. | [
"2 2 3\n000\n000\n\n111\n111\n",
"3 3 3\n111\n111\n111\n\n111\n111\n111\n\n111\n111\n111\n",
"1 1 10\n0101010101\n"
] | [
"2\n",
"19\n",
"0\n"
] | In the first sample the whole first layer of CPUs is malfunctional. In the second layer when CPU (2, 1, 2) turns off, it disrupts the control by CPU (2, 1, 3) over CPU (2, 1, 1), and when CPU (2, 2, 2) is turned off, it disrupts the control over CPU (2, 2, 3) by CPU (2, 2, 1).
In the second sample all processors excep... | 2,000 | [
{
"input": "2 2 3\n000\n000\n\n111\n111",
"output": "2"
},
{
"input": "3 3 3\n111\n111\n111\n\n111\n111\n111\n\n111\n111\n111",
"output": "19"
},
{
"input": "1 1 10\n0101010101",
"output": "0"
},
{
"input": "1 1 1\n0",
"output": "0"
},
{
"input": "1 1 1\n1",
"... | 1,458,495,685 | 20,485 | Python 3 | WRONG_ANSWER | PRETESTS | 13 | 967 | 12,902,400 | def main():
inp = input().split()
n = int(inp[0])
m = int(inp[1])
k = int(inp[2])
processors = []
for x in range(n):
for y in range(m):
line = list(input())
for z in range(k):
processors.append(int(line[z]) == 1)
if x != n - 1:
... | Title: Three-dimensional Turtle Super Computer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A super computer has been built in the Turtle Academy of Sciences. The computer consists of *n*·*m*·*k* CPUs. The architecture was the paralellepiped of size *n*<=×<=*m*<=×<=*k*, split into 1<=×... | ```python
def main():
inp = input().split()
n = int(inp[0])
m = int(inp[1])
k = int(inp[2])
processors = []
for x in range(n):
for y in range(m):
line = list(input())
for z in range(k):
processors.append(int(line[z]) == 1)
if x !... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Pupils decided to go to amusement park. Some of them were with parents. In total, *n* people came to the park and they all want to get to the most extreme attraction and roll on it exactly once.
Tickets for group of *x* people are sold on the attraction, there should be at least one adult in each group (it is possible... | The first line contains three integers *n*, *c*1 and *c*2 (1<=≤<=*n*<=≤<=200<=000, 1<=≤<=*c*1,<=*c*2<=≤<=107) — the number of visitors and parameters for determining the ticket prices for a group.
The second line contains the string of length *n*, which consists of zeros and ones. If the *i*-th symbol of the string is... | Print the minimum price of visiting the most extreme attraction for all pupils and their parents. Each of them should roll on the attraction exactly once. | [
"3 4 1\n011\n",
"4 7 2\n1101\n"
] | [
"8\n",
"18\n"
] | In the first test one group of three people should go to the attraction. Then they have to pay 4 + 1 * (3 - 1)<sup class="upper-index">2</sup> = 8.
In the second test it is better to go to the attraction in two groups. The first group should consist of two adults (for example, the first and the second person), the sec... | 0 | [
{
"input": "3 4 1\n011",
"output": "8"
},
{
"input": "4 7 2\n1101",
"output": "18"
},
{
"input": "1 2 2\n1",
"output": "2"
},
{
"input": "2 3 10\n01",
"output": "13"
},
{
"input": "5 10 3\n11100",
"output": "35"
},
{
"input": "10 2 2\n1111101111",
... | 1,491,410,652 | 4,152 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 5,529,600 | n, c1, c2 = tuple(map(int, input().strip().split()))
a = input()
ad, pu = 0, 0
for x in a:
if x == '0':
pu += 1
else:
ad += 1
ans = 9999999999999999999999999999999
for i in range(1, ad + 1):
num = ad + pu - i
x, y = num // i, num % i
ans = min(ans, c1 * i + c2 * (x * x * i + y * (x+1... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pupils decided to go to amusement park. Some of them were with parents. In total, *n* people came to the park and they all want to get to the most extreme attraction and roll on it exactly once.
Tickets for group of *x* people ar... | ```python
n, c1, c2 = tuple(map(int, input().strip().split()))
a = input()
ad, pu = 0, 0
for x in a:
if x == '0':
pu += 1
else:
ad += 1
ans = 9999999999999999999999999999999
for i in range(1, ad + 1):
num = ad + pu - i
x, y = num // i, num % i
ans = min(ans, c1 * i + c2 * (x * x * i ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
611 | A | New Year and Days | PROGRAMMING | 900 | [
"implementation"
] | null | null | Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming year 2016.
Limak wants to prove how responsible a bear he is. He is going to regularly save candies for ... | The only line of the input is in one of the following two formats:
- "*x* of week" where *x* (1<=≤<=*x*<=≤<=7) denotes the day of the week. The 1-st day is Monday and the 7-th one is Sunday. - "*x* of month" where *x* (1<=≤<=*x*<=≤<=31) denotes the day of the month. | Print one integer — the number of candies Limak will save in the year 2016. | [
"4 of week\n",
"30 of month\n"
] | [
"52\n",
"11\n"
] | Polar bears use the Gregorian calendar. It is the most common calendar and you likely use it too. You can read about it on Wikipedia if you want to – [https://en.wikipedia.org/wiki/Gregorian_calendar](https://en.wikipedia.org/wiki/Gregorian_calendar). The week starts with Monday.
In the first sample Limak wants to sav... | 500 | [
{
"input": "4 of week",
"output": "52"
},
{
"input": "30 of month",
"output": "11"
},
{
"input": "17 of month",
"output": "12"
},
{
"input": "31 of month",
"output": "7"
},
{
"input": "6 of week",
"output": "53"
},
{
"input": "1 of week",
"output":... | 1,584,082,661 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 108 | 0 | a = input()
arr [31,29,31,30,31,30,31,31,30,31,30,31]
f = a.split(' ')[0]
count = 0
if a.split(' ')[2] == 'month':
for i in arr:
if f <= i:
count += 1
print(count)
else:
print(53 if f == 5 or f == 6 else 52)
| Title: New Year and Days
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today is Wednesday, the third day of the week. What's more interesting is that tomorrow is the last day of the year 2015.
Limak is a little polar bear. He enjoyed this year a lot. Now, he is so eager to the coming ye... | ```python
a = input()
arr [31,29,31,30,31,30,31,31,30,31,30,31]
f = a.split(' ')[0]
count = 0
if a.split(' ')[2] == 'month':
for i in arr:
if f <= i:
count += 1
print(count)
else:
print(53 if f == 5 or f == 6 else 52)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
705 | A | Hulk | PROGRAMMING | 800 | [
"implementation"
] | null | null | Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have *n* layers. The first layer is hate, se... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of layers of love and hate. | Print Dr.Banner's feeling in one line. | [
"1\n",
"2\n",
"3\n"
] | [
"I hate it\n",
"I hate that I love it\n",
"I hate that I love that I hate it\n"
] | none | 500 | [
{
"input": "1",
"output": "I hate it"
},
{
"input": "2",
"output": "I hate that I love it"
},
{
"input": "3",
"output": "I hate that I love that I hate it"
},
{
"input": "4",
"output": "I hate that I love that I hate that I love it"
},
{
"input": "5",
"output"... | 1,691,792,211 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | a = int(input())
b = int(a)
c = ''
if a == 1:
print('I hate it')
exit()
while a>0:
if a%2==1 and a!=1:
c = c + 'I hate that '
a-=1
elif a%2==0 and a==b:
c = c + 'I hate that '
a-=1
elif a%2==0 and a!=1:
c = c + 'I love that '
a-=1
e... | Title: Hulk
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Bruce Banner hates his enemies (like others don't). As we all know, he can barely talk when he turns into the incredible Hulk. That's why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and... | ```python
a = int(input())
b = int(a)
c = ''
if a == 1:
print('I hate it')
exit()
while a>0:
if a%2==1 and a!=1:
c = c + 'I hate that '
a-=1
elif a%2==0 and a==b:
c = c + 'I hate that '
a-=1
elif a%2==0 and a!=1:
c = c + 'I love that '
a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,592,845,622 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 0 | num = int(input())
even = 0
all_num = []
for i in range(num):
number = int(input())
if number%2 == 0:
even += 1
all_num += [number]
if even == num - 1:
for i in range(len(all_num)):
if all_num[i]%2 == 1:
print(i+1)
else:
for i in range(len(all_num))... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
num = int(input())
even = 0
all_num = []
for i in range(num):
number = int(input())
if number%2 == 0:
even += 1
all_num += [number]
if even == num - 1:
for i in range(len(all_num)):
if all_num[i]%2 == 1:
print(i+1)
else:
for i in range(len... | -1 | MatrixStudio/Codeforces-Python-Submissions |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,512,752,120 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 390 | 5,836,800 | from math import ceil
n=int(input())
print(ceil(n*n/2))
for i in range(1,n+1):
s=''
if i%2!=0:
for j in range(1,n+1):
if j%2!=0:
s+="C"
else:
s+='.'
else:
for j in range(1,n+1):
if j%2!=0:
s+='.'
else:
s+='C'
print(s) | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
from math import ceil
n=int(input())
print(ceil(n*n/2))
for i in range(1,n+1):
s=''
if i%2!=0:
for j in range(1,n+1):
if j%2!=0:
s+="C"
else:
s+='.'
else:
for j in range(1,n+1):
if j%2!=0:
s+='.'
else:
s+='C'
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | E | Enemy is weak | PROGRAMMING | 1,900 | [
"data structures",
"trees"
] | E. Enemy is weak | 5 | 256 | The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roman army to defeat them. So he gives the army a weakness number.
In Shapur's opinion the weaknes... | The first line of input contains a single number *n* (3<=≤<=*n*<=≤<=106) — the number of men in Roman army. Next line contains *n* different positive integers *a**i* (1<=≤<=*i*<=≤<=*n*,<=1<=≤<=*a**i*<=≤<=109) — powers of men in the Roman army. | A single integer number, the weakness of the Roman army.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d). | [
"3\n3 2 1\n",
"3\n2 3 1\n",
"4\n10 8 3 1\n",
"4\n1 5 4 3\n"
] | [
"1\n",
"0\n",
"4\n",
"1\n"
] | none | 2,500 | [
{
"input": "3\n3 2 1",
"output": "1"
},
{
"input": "3\n2 3 1",
"output": "0"
},
{
"input": "4\n10 8 3 1",
"output": "4"
},
{
"input": "4\n1 5 4 3",
"output": "1"
},
{
"input": "9\n10 9 5 6 8 3 4 7 11",
"output": "20"
},
{
"input": "7\n11 3 8 4 2 9 6",
... | 1,592,001,252 | 2,147,483,647 | PyPy 3 | OK | TESTS | 70 | 4,944 | 125,235,200 | from sys import stdin,stdout
def binarysearch(x,first,last,b):
mid=(first+last)/2
mid=int(mid)
if(b[first]==x):
return first
if(b[last]==x):
return last
if(b[mid]==x):
return mid
if(b[mid]<x):
return binarysearch(x,mid,last,b)
return binarysearch... | Title: Enemy is weak
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
The Romans have attacked again. This time they are much more than the Persians but Shapur is ready to defeat them. He says: "A lion is never afraid of a hundred sheep".
Nevertheless Shapur has to find weaknesses in the Roma... | ```python
from sys import stdin,stdout
def binarysearch(x,first,last,b):
mid=(first+last)/2
mid=int(mid)
if(b[first]==x):
return first
if(b[last]==x):
return last
if(b[mid]==x):
return mid
if(b[mid]<x):
return binarysearch(x,mid,last,b)
return bi... | 3.272331 | MatrixStudio/Codeforces-Python-Submissions |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<... | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In ... | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,433,595,907 | 307 | Python 3 | OK | TESTS | 37 | 62 | 0 | n,m = [int(c) for c in input().split()]
lines = []
for i in range(n):
lines.append(input())
f = 0
for i in range(n-1):
for j in range(m-1):
s = set()
s.add(lines[i][j])
s.add(lines[i+1][j])
s.add(lines[i][j+1])
s.add(lines[i+1][j+1])
if 'f' in s an... | Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem a... | ```python
n,m = [int(c) for c in input().split()]
lines = []
for i in range(n):
lines.append(input())
f = 0
for i in range(n-1):
for j in range(m-1):
s = set()
s.add(lines[i][j])
s.add(lines[i+1][j])
s.add(lines[i][j+1])
s.add(lines[i+1][j+1])
if '... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make ... | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,700,227,511 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int main()
{
int s, k = 0;
cin >>s;
while(s){
if(s > 4){
s-=5;
++k;
}
else if(s > 3){
s-=4;
++k;
}else if(s > 2){
s-=3;
++k;
}else if... | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2... | ```python
#include <bits/stdc++.h>
using namespace std;
int main()
{
int s, k = 0;
cin >>s;
while(s){
if(s > 4){
s-=5;
++k;
}
else if(s > 3){
s-=4;
++k;
}else if(s > 2){
s-=3;
++k;
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
233 | B | Non-square Equation | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"math"
] | null | null | Let's consider equation:
where *x*,<=*n* are positive integers, *s*(*x*) is the function, equal to the sum of digits of number *x* in the decimal number system.
You are given an integer *n*, find the smallest positive integer root of equation *x*, or else determine that there are no such roots. | A single line contains integer *n* (1<=≤<=*n*<=≤<=1018) — the equation parameter.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | Print -1, if the equation doesn't have integer positive roots. Otherwise print such smallest integer *x* (*x*<=><=0), that the equation given in the statement holds. | [
"2\n",
"110\n",
"4\n"
] | [
"1\n",
"10\n",
"-1\n"
] | In the first test case *x* = 1 is the minimum root. As *s*(1) = 1 and 1<sup class="upper-index">2</sup> + 1·1 - 2 = 0.
In the second test case *x* = 10 is the minimum root. As *s*(10) = 1 + 0 = 1 and 10<sup class="upper-index">2</sup> + 1·10 - 110 = 0.
In the third test case the equation has no roots. | 1,000 | [
{
"input": "2",
"output": "1"
},
{
"input": "110",
"output": "10"
},
{
"input": "4",
"output": "-1"
},
{
"input": "8",
"output": "2"
},
{
"input": "10000000100000000",
"output": "100000000"
},
{
"input": "10000006999999929",
"output": "99999999"
... | 1,656,066,744 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 60 | 0 | import math
import sys
def s(x):
return sum(map(lambda x: x - ord('0'), map(ord, str(x))))
n = int(input())
for sx in range(1, 9999):
a = 1
b = sx
c = -n
d = b * b - 4 * a * c
x = int(round((-b + math.sqrt(d)) / (2 * a)))
if ((x > 0) and (sx == s(x))):
... | Title: Non-square Equation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider equation:
where *x*,<=*n* are positive integers, *s*(*x*) is the function, equal to the sum of digits of number *x* in the decimal number system.
You are given an integer *n*, find the smallest posi... | ```python
import math
import sys
def s(x):
return sum(map(lambda x: x - ord('0'), map(ord, str(x))))
n = int(input())
for sx in range(1, 9999):
a = 1
b = sx
c = -n
d = b * b - 4 * a * c
x = int(round((-b + math.sqrt(d)) / (2 * a)))
if ((x > 0) and (sx =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes acco... | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, an... | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,588,826,253 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 6,656,000 | import math
a_tired = 0
b_tired = 0
a = int(input())
b = int(input())
point = (a+b)//2
b_route = abs(b - point)
a_route = abs(a - point)
for i in range(1,a_route+1):
a_tired +=i
for i in range(1,b_route+1):
b_tired +=i
total = a_tired + b_tired
print(str(total)) | Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in... | ```python
import math
a_tired = 0
b_tired = 0
a = int(input())
b = int(input())
point = (a+b)//2
b_route = abs(b - point)
a_route = abs(a - point)
for i in range(1,a_route+1):
a_tired +=i
for i in range(1,b_route+1):
b_tired +=i
total = a_tired + b_tired
print(str(total))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
225 | A | Dice Tower | PROGRAMMING | 1,100 | [
"constructive algorithms",
"greedy"
] | null | null | A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other) that satisfy the given constraints (both of them are shown on the picture on the left).
Alice... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of dice in the tower.
The second line contains an integer *x* (1<=≤<=*x*<=≤<=6) — the number Bob sees at the top of the tower. Next *n* lines contain two space-separated integers each: the *i*-th line contains numbers *a**i*,<=*b**i* (1<=≤<=... | Print "YES" (without the quotes), if it is possible to to uniquely identify the numbers on the faces of all the dice in the tower. If it is impossible, print "NO" (without the quotes). | [
"3\n6\n3 2\n5 4\n2 4\n",
"3\n3\n2 6\n4 1\n5 3\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "3\n6\n3 2\n5 4\n2 4",
"output": "YES"
},
{
"input": "3\n3\n2 6\n4 1\n5 3",
"output": "NO"
},
{
"input": "1\n3\n2 1",
"output": "YES"
},
{
"input": "2\n2\n3 1\n1 5",
"output": "NO"
},
{
"input": "3\n2\n1 4\n5 3\n6 4",
"output": "NO"
},
{
"in... | 1,545,967,608 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | def solve(dice, top):
for cupe in dice:
faces = set()
faces.add(top)
for face in cupe:
faces.add(face)
faces.add(7 - face)
print(faces)
top = 7 - top
if len(faces) != 5:
return False
return True
n = int(input())
t = int(input... | Title: Dice Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other... | ```python
def solve(dice, top):
for cupe in dice:
faces = set()
faces.add(top)
for face in cupe:
faces.add(face)
faces.add(7 - face)
print(faces)
top = 7 - top
if len(faces) != 5:
return False
return True
n = int(input())
t =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
94 | B | Friends | PROGRAMMING | 1,300 | [
"graphs",
"implementation",
"math"
] | B. Friends | 1 | 256 | One day Igor K. stopped programming and took up math. One late autumn evening he was sitting at a table reading a book and thinking about something.
The following statement caught his attention: "Among any six people there are either three pairwise acquainted people or three pairwise unacquainted people"
Igor just c... | The first line contains an integer *m* (0<=≤<=*m*<=≤<=10), which is the number of relations of acquaintances among the five friends of Igor's.
Each of the following *m* lines contains two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=5;*a**i*<=≠<=*b**i*), where (*a**i*,<=*b**i*) is a pair of acquainted people.... | Print "FAIL", if among those five people there are no either three pairwise acquainted or three pairwise unacquainted people. Otherwise print "WIN". | [
"4\n1 3\n2 3\n1 4\n5 3\n",
"5\n1 2\n2 3\n3 4\n4 5\n5 1\n"
] | [
"WIN\n",
"FAIL\n"
] | none | 1,000 | [
{
"input": "4\n1 3\n2 3\n1 4\n5 3",
"output": "WIN"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5\n5 1",
"output": "FAIL"
},
{
"input": "1\n4 3",
"output": "WIN"
},
{
"input": "6\n1 3\n2 3\n1 2\n5 3\n4 2\n4 5",
"output": "WIN"
},
{
"input": "2\n1 3\n2 5",
"output": "WI... | 1,570,725,576 | 2,147,483,647 | PyPy 3 | OK | TESTS | 85 | 140 | 0 | class CodeforcesTask94BSolution:
def __init__(self):
self.result = ''
self.m = 0
self.edges = []
def read_input(self):
self.m = int(input())
for x in range(self.m):
self.edges.append([int(y) for y in input().split(" ")])
def process_task(self):
u... | Title: Friends
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Igor K. stopped programming and took up math. One late autumn evening he was sitting at a table reading a book and thinking about something.
The following statement caught his attention: "Among any six people there are ei... | ```python
class CodeforcesTask94BSolution:
def __init__(self):
self.result = ''
self.m = 0
self.edges = []
def read_input(self):
self.m = int(input())
for x in range(self.m):
self.edges.append([int(y) for y in input().split(" ")])
def process_task(self):... | 3.93 | MatrixStudio/Codeforces-Python-Submissions |
892 | B | Wrath | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the *i*-th person kills the *j*-th person if and only if *j*<=<<=*i* and *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — the number of guilty people.
Second line contains *n* space-separated integers *L*1,<=*L*2,<=...,<=*L**n* (0<=≤<=*L**i*<=≤<=109), where *L**i* is the length of the *i*-th person's claw. | Print one integer — the total number of alive people after the bell rings. | [
"4\n0 1 0 10\n",
"2\n0 0\n",
"10\n1 1 3 0 0 0 2 1 0 3\n"
] | [
"1\n",
"2\n",
"3\n"
] | In first sample the last person kills everyone in front of him. | 1,000 | [
{
"input": "4\n0 1 0 10",
"output": "1"
},
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "10\n1 1 3 0 0 0 2 1 0 3",
"output": "3"
},
{
"input": "10\n0 0 2 0 0 3 3 2 2 0",
"output": "2"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "5\n0 0 0 1 0"... | 1,550,020,597 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 1,028 | 77,107,200 | n = int(input())
l = list(map(int, input().split()))
alive = 1
lastKill = n
i = n
while i > 0:
if i < lastKill:
alive+=1
if lastKill > 0 and l[i-1] > 0 and lastKill > i - l[i-1]:
lastKill = i - l[i-1]
i-=1
print(alive)
| Title: Wrath
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same ... | ```python
n = int(input())
l = list(map(int, input().split()))
alive = 1
lastKill = n
i = n
while i > 0:
if i < lastKill:
alive+=1
if lastKill > 0 and l[i-1] > 0 and lastKill > i - l[i-1]:
lastKill = i - l[i-1]
i-=1
print(alive)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
903 | D | Almost Difference | PROGRAMMING | 2,200 | [
"data structures",
"math"
] | null | null | Let's denote a function
You are given an array *a* consisting of *n* integers. You have to calculate the sum of *d*(*a**i*,<=*a**j*) over all pairs (*i*,<=*j*) such that 1<=≤<=*i*<=≤<=*j*<=≤<=*n*. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=200000) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109) — elements of the array. | Print one integer — the sum of *d*(*a**i*,<=*a**j*) over all pairs (*i*,<=*j*) such that 1<=≤<=*i*<=≤<=*j*<=≤<=*n*. | [
"5\n1 2 3 1 3\n",
"4\n6 6 5 5\n",
"4\n6 6 4 4\n"
] | [
"4\n",
"0\n",
"-8\n"
] | In the first example:
1. *d*(*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>) = 0; 1. *d*(*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">3</sub>) = 2; 1. *d*(*a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">4</sub>) = 0; 1. *d*(*a*<sub class="lower-index">... | 0 | [
{
"input": "5\n1 2 3 1 3",
"output": "4"
},
{
"input": "4\n6 6 5 5",
"output": "0"
},
{
"input": "4\n6 6 4 4",
"output": "-8"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1000000000",
"output": "0"
},
{
"input": "2\n1 1000000000",
"output"... | 1,570,108,926 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 966 | 29,593,600 | n = int(input())
a = list(map(int, input().split()))
sum0 = 0
ans = 0
sum1 = 0
m = {}
for i in range(0 , n):
m[a[i]] = 0
m[a[i] + 1] = 0
m[a[i] - 1] = 0
sum0 += a[i];
for i in range(0 , n):
m[a[i]] += 1
for i in range(n - 1 , -1 , -1):
sum1 = sum0 - a[i] - m[a[i] - 1]*(a[... | Title: Almost Difference
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's denote a function
You are given an array *a* consisting of *n* integers. You have to calculate the sum of *d*(*a**i*,<=*a**j*) over all pairs (*i*,<=*j*) such that 1<=≤<=*i*<=≤<=*j*<=≤<=*n*.
Input Specifica... | ```python
n = int(input())
a = list(map(int, input().split()))
sum0 = 0
ans = 0
sum1 = 0
m = {}
for i in range(0 , n):
m[a[i]] = 0
m[a[i] + 1] = 0
m[a[i] - 1] = 0
sum0 += a[i];
for i in range(0 , n):
m[a[i]] += 1
for i in range(n - 1 , -1 , -1):
sum1 = sum0 - a[i] - m[a[i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
489 | C | Given Length and Sum of Digits... | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes. | The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers. | In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes). | [
"2 15\n",
"3 0\n"
] | [
"69 96\n",
"-1 -1\n"
] | none | 1,500 | [
{
"input": "2 15",
"output": "69 96"
},
{
"input": "3 0",
"output": "-1 -1"
},
{
"input": "2 1",
"output": "10 10"
},
{
"input": "3 10",
"output": "109 910"
},
{
"input": "100 100",
"output": "1000000000000000000000000000000000000000000000000000000000000000000... | 1,693,639,127 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | m, s = map(int, input().split())
# Calculate the smallest and largest numbers
smallest = []
largest = []
# Smallest number
if s == 0:
if m == 1:
smallest = [0]
else:
smallest = [1] + [0] * (m - 1)
else:
for i in range(m):
d = min(s, 9)
smallest.append(d)
... | Title: Given Length and Sum of Digits...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should ... | ```python
m, s = map(int, input().split())
# Calculate the smallest and largest numbers
smallest = []
largest = []
# Smallest number
if s == 0:
if m == 1:
smallest = [0]
else:
smallest = [1] + [0] * (m - 1)
else:
for i in range(m):
d = min(s, 9)
smallest.appe... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
768 | B | Code For 1 | PROGRAMMING | 1,600 | [
"constructive algorithms",
"dfs and similar",
"divide and conquer"
] | null | null | Jon fought bravely to rescue the wildlings who were attacked by the white-walkers at Hardhome. On his arrival, Sam tells him that he wants to go to Oldtown to train at the Citadel to become a maester, so he can return and take the deceased Aemon's place as maester of Castle Black. Jon agrees to Sam's proposal and Sam s... | The first line contains three integers *n*, *l*, *r* (0<=≤<=*n*<=<<=250, 0<=≤<=*r*<=-<=*l*<=≤<=105, *r*<=≥<=1, *l*<=≥<=1) – initial element and the range *l* to *r*.
It is guaranteed that *r* is not greater than the length of the final list. | Output the total number of 1s in the range *l* to *r* in the final sequence. | [
"7 2 5\n",
"10 3 10\n"
] | [
"4\n",
"5\n"
] | Consider first example:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/288fbb682a6fa1934a47b763d6851f9d32a06150.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Elements on positions from 2-nd to 5-th in list is [1, 1, 1, 1]. The number of ones is 4.
For the second example:
<img al... | 1,000 | [
{
"input": "7 2 5",
"output": "4"
},
{
"input": "10 3 10",
"output": "5"
},
{
"input": "56 18 40",
"output": "20"
},
{
"input": "203 40 124",
"output": "67"
},
{
"input": "903316762502 354723010040 354723105411",
"output": "78355"
},
{
"input": "335343... | 1,680,165,025 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 186 | 0 | def fir(n: int) -> int:
if n == 0:
return 0
len = 0
i = 0
while 2 ** i <= n:
len += 2 ** i
i += 1
return sec(int(n), int(len), int((len + 1) / 2))
def sec(n: int, m: int, middle: int) -> int:
if a < middle - m / 2 or l > middle + m / 2:
return 0
if m == 1:
... | Title: Code For 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jon fought bravely to rescue the wildlings who were attacked by the white-walkers at Hardhome. On his arrival, Sam tells him that he wants to go to Oldtown to train at the Citadel to become a maester, so he can return and ta... | ```python
def fir(n: int) -> int:
if n == 0:
return 0
len = 0
i = 0
while 2 ** i <= n:
len += 2 ** i
i += 1
return sec(int(n), int(len), int((len + 1) / 2))
def sec(n: int, m: int, middle: int) -> int:
if a < middle - m / 2 or l > middle + m / 2:
return 0
if ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
766 | A | Mahmoud and Longest Uncommon Subsequence | PROGRAMMING | 1,000 | [
"constructive algorithms",
"strings"
] | null | null | While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two strings *a* and *b*, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence ... | The first line contains string *a*, and the second line — string *b*. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than 105 characters. | If there's no uncommon subsequence, print "-1". Otherwise print the length of the longest uncommon subsequence of *a* and *b*. | [
"abcd\ndefgh\n",
"a\na\n"
] | [
"5\n",
"-1\n"
] | In the first example: you can choose "defgh" from string *b* as it is the longest subsequence of string *b* that doesn't appear as a subsequence of string *a*. | 500 | [
{
"input": "abcd\ndefgh",
"output": "5"
},
{
"input": "a\na",
"output": "-1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaacccccccccccccccccccccccccccccccccccccccccccccccccc\naaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaadddddddddddddddddddddddddddddddddddddddddddd... | 1,674,040,839 | 2,147,483,647 | Python 3 | OK | TESTS | 73 | 46 | 204,800 | a = input()
b = input()
lena = len(a)
lenb = len(b)
if(lena != lenb):
print(max(lena,lenb))
exit()
if a.find(b) < 0:
print(lena)
exit()
print(-1)
| Title: Mahmoud and Longest Uncommon Subsequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.
Given two ... | ```python
a = input()
b = input()
lena = len(a)
lenb = len(b)
if(lena != lenb):
print(max(lena,lenb))
exit()
if a.find(b) < 0:
print(lena)
exit()
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
602 | B | Approximating a Constant Range | PROGRAMMING | 1,400 | [
"dp",
"implementation",
"two pointers"
] | null | null | When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choosing a sufficiently large number of consecutive data points that seems as constant as possible and taking their aver... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of data points.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100<=000). | Print a single number — the maximum length of an almost constant range of the given sequence. | [
"5\n1 2 3 3 2\n",
"11\n5 4 5 5 6 7 8 8 8 7 6\n"
] | [
"4\n",
"5\n"
] | In the first sample, the longest almost constant range is [2, 5]; its length (the number of data points in it) is 4.
In the second sample, there are three almost constant ranges of length 4: [1, 4], [6, 9] and [7, 10]; the only almost constant range of the maximum length 5 is [6, 10]. | 1,000 | [
{
"input": "5\n1 2 3 3 2",
"output": "4"
},
{
"input": "11\n5 4 5 5 6 7 8 8 8 7 6",
"output": "5"
},
{
"input": "2\n3 2",
"output": "2"
},
{
"input": "4\n1001 1000 1000 1001",
"output": "4"
},
{
"input": "4\n1 1 2 3",
"output": "3"
},
{
"input": "3\n1 ... | 1,642,286,517 | 2,147,483,647 | PyPy 3 | OK | TESTS | 107 | 155 | 10,342,400 | R = lambda: map(int, input().split())
n = int(input())
arr = list(R())
j = -1
cnts = {}
res = 0
for i in range(n):
cnts[arr[i]] = cnts.get(arr[i], 0) + 1
while len(cnts) > 2:
cnts[arr[j + 1]] -= 1
if not cnts[arr[j + 1]]:
cnts.pop(arr[j + 1])
j += 1
res = max... | Title: Approximating a Constant Range
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Xellos was doing a practice course in university, he once had to measure the intensity of an effect that slowly approached equilibrium. A good way to determine the equilibrium intensity would be choo... | ```python
R = lambda: map(int, input().split())
n = int(input())
arr = list(R())
j = -1
cnts = {}
res = 0
for i in range(n):
cnts[arr[i]] = cnts.get(arr[i], 0) + 1
while len(cnts) > 2:
cnts[arr[j + 1]] -= 1
if not cnts[arr[j + 1]]:
cnts.pop(arr[j + 1])
j += 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,544,853,765 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 109 | 0 | n = input()
n = int(n)
arr = input()
# arr = arr.replace(' ', '')
arr = list (arr.split(' '))
for idx, val in enumerate(arr):
arr[idx] = int(val)
b = 15
i = 0
while i < n:
if arr[i] > b:
print(b)
break
else:
b = arr[i] + 15
if i == (n - 1):
if b >= 9... | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = input()
n = int(n)
arr = input()
# arr = arr.replace(' ', '')
arr = list (arr.split(' '))
for idx, val in enumerate(arr):
arr[idx] = int(val)
b = 15
i = 0
while i < n:
if arr[i] > b:
print(b)
break
else:
b = arr[i] + 15
if i == (n - 1):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,649,919,737 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 46 | 0 | s='abcdefghijklmnopqrstuvwxyz'
n,k=map(int,input().split())
c=''
while n>0:
if n<k:
c=c+s[0:n]
n=-1
else:
c=c+s[0:k]
n=n-k
print(c) | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
s='abcdefghijklmnopqrstuvwxyz'
n,k=map(int,input().split())
c=''
while n>0:
if n<k:
c=c+s[0:n]
n=-1
else:
c=c+s[0:k]
n=n-k
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
282 | B | Painting Eggs | PROGRAMMING | 1,500 | [
"greedy",
"math"
] | null | null | The Bitlandians are quite weird people. They have very peculiar customs.
As is customary, Uncle J. wants to have *n* eggs painted for Bitruz (an ancient Bitland festival). He has asked G. and A. to do the work.
The kids are excited because just as is customary, they're going to be paid for the job!
Overall uncle J.... | The first line contains integer *n* (1<=≤<=*n*<=≤<=106) — the number of eggs.
Next *n* lines contain two integers *a**i* and *g**i* each (0<=≤<=*a**i*,<=*g**i*<=≤<=1000; *a**i*<=+<=*g**i*<==<=1000): *a**i* is the price said by A. for the *i*-th egg and *g**i* is the price said by G. for the *i*-th egg. | If it is impossible to assign the painting, print "-1" (without quotes).
Otherwise print a string, consisting of *n* letters "G" and "A". The *i*-th letter of this string should represent the child who will get the *i*-th egg in the required distribution. Letter "A" represents A. and letter "G" represents G. If we den... | [
"2\n1 999\n999 1\n",
"3\n400 600\n400 600\n400 600\n"
] | [
"AG\n",
"AGA\n"
] | none | 1,000 | [
{
"input": "2\n1 999\n999 1",
"output": "AG"
},
{
"input": "3\n400 600\n400 600\n400 600",
"output": "AGA"
},
{
"input": "2\n500 500\n500 500",
"output": "AG"
},
{
"input": "1\n1 999",
"output": "A"
},
{
"input": "10\n1 999\n1 999\n1 999\n1 999\n1 999\n1 999\n1 99... | 1,698,396,157 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 1,652 | 10,752,000 | import sys
n = int(sys.stdin.readline())
d = 0
for _ in range(n):
a, g = map(int, sys.stdin.readline().split())
if d + a <= 500:
d += a
print('A', end='')
else:
d -= g
print('G', end='')# 1698396157.2401366 | Title: Painting Eggs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Bitlandians are quite weird people. They have very peculiar customs.
As is customary, Uncle J. wants to have *n* eggs painted for Bitruz (an ancient Bitland festival). He has asked G. and A. to do the work.
The kids... | ```python
import sys
n = int(sys.stdin.readline())
d = 0
for _ in range(n):
a, g = map(int, sys.stdin.readline().split())
if d + a <= 500:
d += a
print('A', end='')
else:
d -= g
print('G', end='')# 1698396157.2401366
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another c... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follo... | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,615,406,078 | 2,147,483,647 | PyPy 3 | OK | TESTS | 54 | 436 | 12,083,200 | n=int(input())
l=list(map(int,input().split()))
for i in range(n):
if i==0:
print(abs(l[i]-l[i+1]),end=" ")
if i==n-1:
print(abs(l[i]-l[i-1]),end=" ")
if i!=0 and i!=n-1:
bir=abs(l[i]-l[i-1])
iki=abs(l[i]-l[i+1])
print(min(bir,iki),end=" ")
bir= abs... | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love... | ```python
n=int(input())
l=list(map(int,input().split()))
for i in range(n):
if i==0:
print(abs(l[i]-l[i+1]),end=" ")
if i==n-1:
print(abs(l[i]-l[i-1]),end=" ")
if i!=0 and i!=n-1:
bir=abs(l[i]-l[i-1])
iki=abs(l[i]-l[i+1])
print(min(bir,iki),end=" ")
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,680,275,528 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | def trial_division_simple(n: int) -> list[int]:
factorization: list[int] = []
d = 2
while d * d <= n:
while n % d == 0:
factorization.append(d)
n //= d
d += 1
if n > 1:
factorization.append(n)
return factorization
n = int(input())
res = 0
fo... | Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, in... | ```python
def trial_division_simple(n: int) -> list[int]:
factorization: list[int] = []
d = 2
while d * d <= n:
while n % d == 0:
factorization.append(d)
n //= d
d += 1
if n > 1:
factorization.append(n)
return factorization
n = int(input())
res... | -1 | MatrixStudio/Codeforces-Python-Submissions |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,611,845,112 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 155 | 3,891,200 | n, m = list(map(int, input().split(' ')))
words = {}
for i in range(m):
a, b = input().split(' ')
if len(a) <= len(b):
words[a] = a
else:
words[a] = b
out = ' '.join(map( lambda x: words[x] , input().split(' ')))
print(out)
| Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
n, m = list(map(int, input().split(' ')))
words = {}
for i in range(m):
a, b = input().split(' ')
if len(a) <= len(b):
words[a] = a
else:
words[a] = b
out = ' '.join(map( lambda x: words[x] , input().split(' ')))
print(out)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
352 | A | Jeff and Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation",
"math"
] | null | null | Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make from the cards he's got?
Jeff must make the number without leading zero. At that, we assume that numbe... | The first line contains integer *n* (1<=≤<=*n*<=≤<=103). The next line contains *n* integers *a*1, *a*2, ..., *a**n* (*a**i*<==<=0 or *a**i*<==<=5). Number *a**i* represents the digit that is written on the *i*-th card. | In a single line print the answer to the problem — the maximum number, divisible by 90. If you can't make any divisible by 90 number from the cards, print -1. | [
"4\n5 0 5 0\n",
"11\n5 5 5 5 5 5 5 5 0 5 5\n"
] | [
"0\n",
"5555555550\n"
] | In the first test you can make only one number that is a multiple of 90 — 0.
In the second test you can make number 5555555550, it is a multiple of 90. | 500 | [
{
"input": "4\n5 0 5 0",
"output": "0"
},
{
"input": "11\n5 5 5 5 5 5 5 5 0 5 5",
"output": "5555555550"
},
{
"input": "7\n5 5 5 5 5 5 5",
"output": "-1"
},
{
"input": "1\n5",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "11\n5 0 5 ... | 1,695,317,220 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | n=int(input())
a=[int(x) for x in input().split()]
five=a.count(5)
zero=n-five
if(five>=9 and zero>0):
five//=9
five*=9
print(("5"*five)+"0")
elif(zero>0):print(0)
else:print(-1) | Title: Jeff and Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jeff's got *n* cards, each card contains either digit 0, or digit 5. Jeff can choose several cards and put them in a line so that he gets some number. What is the largest possible number divisible by 90 Jeff can make fr... | ```python
n=int(input())
a=[int(x) for x in input().split()]
five=a.count(5)
zero=n-five
if(five>=9 and zero>0):
five//=9
five*=9
print(("5"*five)+"0")
elif(zero>0):print(0)
else:print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,686,241,228 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 52 | 62 | 0 | a, b = map(int, input().split())
t, c = 0, 0
r = 240 - b
for i in range(1, a + 1):
t += i * 5
if t <= r:
c += 1
else:
break
print (c) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
a, b = map(int, input().split())
t, c = 0, 0
r = 240 - b
for i in range(1, a + 1):
t += i * 5
if t <= r:
c += 1
else:
break
print (c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
401 | A | Vanya and Cards | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each card doesn't exceed *x* in the absolute value.
Natasha doesn't like when Vanya spends a long time p... | The first line contains two integers: *n* (1<=≤<=*n*<=≤<=1000) — the number of found cards and *x* (1<=≤<=*x*<=≤<=1000) — the maximum absolute value of the number on a card. The second line contains *n* space-separated integers — the numbers on found cards. It is guaranteed that the numbers do not exceed *x* in their a... | Print a single number — the answer to the problem. | [
"3 2\n-1 1 2\n",
"2 3\n-2 -2\n"
] | [
"1\n",
"2\n"
] | In the first sample, Vanya needs to find a single card with number -2.
In the second sample, Vanya needs to find two cards with number 2. He can't find a single card with the required number as the numbers on the lost cards do not exceed 3 in their absolute value. | 500 | [
{
"input": "3 2\n-1 1 2",
"output": "1"
},
{
"input": "2 3\n-2 -2",
"output": "2"
},
{
"input": "4 4\n1 2 3 4",
"output": "3"
},
{
"input": "2 2\n-1 -1",
"output": "1"
},
{
"input": "15 5\n-2 -1 2 -4 -3 4 -4 -2 -2 2 -2 -1 1 -4 -2",
"output": "4"
},
{
"... | 1,630,779,622 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 124 | 20,172,800 | n,x=map(int,input().split())
a=list(map(int,input().split()))
s=sum(a)
if s==0:
print(0)
elif s>0:
if s%x==0:
print(s//x)
else:
print(s//x+1)
else:
s=s*(-1)
if s%x==0:
print(s//x)
else:
print(s//x+1)
| Title: Vanya and Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya loves playing. He even has a special set of cards to play with. Each card has a single integer. The number on the card can be positive, negative and can even be equal to zero. The only limit is, the number on each... | ```python
n,x=map(int,input().split())
a=list(map(int,input().split()))
s=sum(a)
if s==0:
print(0)
elif s>0:
if s%x==0:
print(s//x)
else:
print(s//x+1)
else:
s=s*(-1)
if s%x==0:
print(s//x)
else:
print(s//x+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
356 | B | Xenia and Hamming | PROGRAMMING | 1,900 | [
"implementation",
"math"
] | null | null | Xenia is an amateur programmer. Today on the IT lesson she learned about the Hamming distance.
The Hamming distance between two strings *s*<==<=*s*1*s*2... *s**n* and *t*<==<=*t*1*t*2... *t**n* of equal length *n* is value . Record [*s**i*<=≠<=*t**i*] is the Iverson notation and represents the following: if *s**i*<=≠<... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1012). The second line contains a non-empty string *x*. The third line contains a non-empty string *y*. Both strings consist of at most 106 lowercase English letters.
It is guaranteed that strings *a* and *b* that you obtain from the input have the ... | Print a single integer — the required Hamming distance.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"100 10\na\naaaaaaaaaa\n",
"1 1\nabacaba\nabzczzz\n",
"2 3\nrzr\naz\n"
] | [
"0\n",
"4\n",
"5\n"
] | In the first test case string *a* is the same as string *b* and equals 100 letters a. As both strings are equal, the Hamming distance between them is zero.
In the second test case strings *a* and *b* differ in their 3-rd, 5-th, 6-th and 7-th characters. Thus, the Hamming distance equals 4.
In the third test case stri... | 1,000 | [] | 1,623,307,199 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 7 | 124 | 2,150,400 | m, n = map(int, input().split())
x = input() * m
y = input() * n
print(len([i for i in range(len(y)) if x[i] != y[i]])) | Title: Xenia and Hamming
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia is an amateur programmer. Today on the IT lesson she learned about the Hamming distance.
The Hamming distance between two strings *s*<==<=*s*1*s*2... *s**n* and *t*<==<=*t*1*t*2... *t**n* of equal length *n* is... | ```python
m, n = map(int, input().split())
x = input() * m
y = input() * n
print(len([i for i in range(len(y)) if x[i] != y[i]]))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
611 | B | New Year and Old Property | PROGRAMMING | 1,300 | [
"bitmasks",
"brute force",
"implementation"
] | null | null | The year 2015 is almost over.
Limak is a little polar bear. He has recently learnt about the binary system. He noticed that the passing year has exactly one zero in its representation in the binary system — 201510<==<=111110111112. Note that he doesn't care about the number of zeros in the decimal representation.
Lim... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=1018) — the first year and the last year in Limak's interval respectively. | Print one integer – the number of years Limak will count in his chosen interval. | [
"5 10\n",
"2015 2015\n",
"100 105\n",
"72057594000000000 72057595000000000\n"
] | [
"2\n",
"1\n",
"0\n",
"26\n"
] | In the first sample Limak's interval contains numbers 5<sub class="lower-index">10</sub> = 101<sub class="lower-index">2</sub>, 6<sub class="lower-index">10</sub> = 110<sub class="lower-index">2</sub>, 7<sub class="lower-index">10</sub> = 111<sub class="lower-index">2</sub>, 8<sub class="lower-index">10</sub> = 1000<su... | 750 | [
{
"input": "5 10",
"output": "2"
},
{
"input": "2015 2015",
"output": "1"
},
{
"input": "100 105",
"output": "0"
},
{
"input": "72057594000000000 72057595000000000",
"output": "26"
},
{
"input": "1 100",
"output": "16"
},
{
"input": "100000000000000000... | 1,618,216,341 | 2,147,483,647 | PyPy 3 | OK | TESTS | 103 | 109 | 1,331,200 | import math
arr = list(map(int, input().split()))
a=arr[0]
b=arr[1]
r1=int((math.log(a)/math.log(2))+1)
r2=int((math.log(b)/math.log(2))+1)
t=0
for k in range(r1,r2+1):
e=2**k -1
for i in range(k-1):
if a<=e-2**i<=b:
t+=1
print(t)
| Title: New Year and Old Property
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The year 2015 is almost over.
Limak is a little polar bear. He has recently learnt about the binary system. He noticed that the passing year has exactly one zero in its representation in the binary system — 2... | ```python
import math
arr = list(map(int, input().split()))
a=arr[0]
b=arr[1]
r1=int((math.log(a)/math.log(2))+1)
r2=int((math.log(b)/math.log(2))+1)
t=0
for k in range(r1,r2+1):
e=2**k -1
for i in range(k-1):
if a<=e-2**i<=b:
t+=1
print(t)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
216 | B | Forming Teams | PROGRAMMING | 1,700 | [
"dfs and similar",
"implementation"
] | null | null | One day *n* students come to the stadium. They want to play football, and for that they need to split into teams, the teams must have an equal number of people.
We know that this group of people has archenemies. Each student has at most two archenemies. Besides, if student *A* is an archenemy to student *B*, then stud... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=100, 1<=≤<=*m*<=≤<=100) — the number of students and the number of pairs of archenemies correspondingly.
Next *m* lines describe enmity between students. Each enmity is described as two numbers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=... | Print a single integer — the minimum number of students you will have to send to the bench in order to start the game. | [
"5 4\n1 2\n2 4\n5 3\n1 4\n",
"6 2\n1 4\n3 4\n",
"6 6\n1 2\n2 3\n3 1\n4 5\n5 6\n6 4\n"
] | [
"1",
"0",
"2"
] | none | 1,500 | [
{
"input": "5 4\n1 2\n2 4\n5 3\n1 4",
"output": "1"
},
{
"input": "6 2\n1 4\n3 4",
"output": "0"
},
{
"input": "6 6\n1 2\n2 3\n3 1\n4 5\n5 6\n6 4",
"output": "2"
},
{
"input": "5 1\n1 2",
"output": "1"
},
{
"input": "8 8\n1 2\n2 3\n3 4\n4 5\n5 6\n6 7\n7 8\n8 1",
... | 1,656,342,864 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 56 | 124 | 28,979,200 | from collections import defaultdict as DD
n,m = map(int, input().split())
G = DD(list)
bench = 0
for _ in range(m):
a,b = map(lambda x: int(x)-1, input().split())
G[a].append(b)
G[b].append(a)
colors = dict()
odds = 0
for root in range(n):
if root in colors:
continue
stack = [(root,0)]
... | Title: Forming Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* students come to the stadium. They want to play football, and for that they need to split into teams, the teams must have an equal number of people.
We know that this group of people has archenemies. Each stu... | ```python
from collections import defaultdict as DD
n,m = map(int, input().split())
G = DD(list)
bench = 0
for _ in range(m):
a,b = map(lambda x: int(x)-1, input().split())
G[a].append(b)
G[b].append(a)
colors = dict()
odds = 0
for root in range(n):
if root in colors:
continue
stack = [(roo... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
794 | B | Cutting Carrot | PROGRAMMING | 1,200 | [
"geometry",
"math"
] | null | null | Igor the analyst has adopted *n* little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cut the carrot into *n* pieces of equal area.
Formally, the carrot can be viewed as an isosceles tri... | The first and only line of input contains two space-separated integers, *n* and *h* (2<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=105). | The output should contain *n*<=-<=1 real numbers *x*1,<=*x*2,<=...,<=*x**n*<=-<=1. The number *x**i* denotes that the *i*-th cut must be made *x**i* units away from the apex of the carrot. In addition, 0<=<<=*x*1<=<<=*x*2<=<<=...<=<<=*x**n*<=-<=1<=<<=*h* must hold.
Your output will be considered correc... | [
"3 2\n",
"2 100000\n"
] | [
"1.154700538379 1.632993161855\n",
"70710.678118654752\n"
] | Definition of isosceles triangle: [https://en.wikipedia.org/wiki/Isosceles_triangle](https://en.wikipedia.org/wiki/Isosceles_triangle). | 1,000 | [
{
"input": "3 2",
"output": "1.154700538379 1.632993161855"
},
{
"input": "2 100000",
"output": "70710.678118654752"
},
{
"input": "1000 100000",
"output": "3162.277660168379 4472.135954999579 5477.225575051661 6324.555320336759 7071.067811865475 7745.966692414834 8366.600265340755 8... | 1,495,196,010 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 78 | 0 | import math
n,h = map(int, input().split())
for i in range(1,n+1):
print(h * math.sqrt(i/n)) | Title: Cutting Carrot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor the analyst has adopted *n* little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cu... | ```python
import math
n,h = map(int, input().split())
for i in range(1,n+1):
print(h * math.sqrt(i/n))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,667,454,777 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 6,963,200 | tt = 1
for _ in range(tt):
n = int(input())
l = list(map(int,input().split()))
m = int(input())
a = 0
b = 0
l2 = list(map(int,input().split()))
for q in l2:
a += l.index(q) + 1
b += l[::-1].index(q) + 1
print(a,b) | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
tt = 1
for _ in range(tt):
n = int(input())
l = list(map(int,input().split()))
m = int(input())
a = 0
b = 0
l2 = list(map(int,input().split()))
for q in l2:
a += l.index(q) + 1
b += l[::-1].index(q) + 1
print(a,b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
771 | A | Bear and Friendship Condition | PROGRAMMING | 1,500 | [
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of members are friends. Of course, a member can't be a friend with themselves.
Let A-B denote that... | The first line of the input contain two integers *n* and *m* (3<=≤<=*n*<=≤<=150<=000, ) — the number of members and the number of pairs of members that are friends.
The *i*-th of the next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*). Members *a**i* and ... | If the given network is reasonable, print "YES" in a single line (without the quotes). Otherwise, print "NO" in a single line (without the quotes). | [
"4 3\n1 3\n3 4\n1 4\n",
"4 4\n3 1\n2 3\n3 4\n1 2\n",
"10 4\n4 3\n5 10\n8 9\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | The drawings below show the situation in the first sample (on the left) and in the second sample (on the right). Each edge represents two members that are friends. The answer is "NO" in the second sample because members (2, 3) are friends and members (3, 4) are friends, while members (2, 4) are not. | 250 | [
{
"input": "4 3\n1 3\n3 4\n1 4",
"output": "YES"
},
{
"input": "4 4\n3 1\n2 3\n3 4\n1 2",
"output": "NO"
},
{
"input": "10 4\n4 3\n5 10\n8 9\n1 2",
"output": "YES"
},
{
"input": "3 2\n1 2\n2 3",
"output": "NO"
},
{
"input": "3 0",
"output": "YES"
},
{
... | 1,570,885,256 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 17,612,800 | n, m = map(int, input().split())
edges = [[] for x in range(n)]
checked = [False for x in range(n)]
count = 0
stack = []
root = 0
res = True
for x in range(m):
i, j = map(int, input().split())
edges[i - 1].append(j - 1)
edges[j - 1].append(i - 1)
while count < n:
while checked[root]:
... | Title: Bear and Friendship Condition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through... | ```python
n, m = map(int, input().split())
edges = [[] for x in range(n)]
checked = [False for x in range(n)]
count = 0
stack = []
root = 0
res = True
for x in range(m):
i, j = map(int, input().split())
edges[i - 1].append(j - 1)
edges[j - 1].append(i - 1)
while count < n:
while checked[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
520 | A | Pangram | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
You are given a string consisting of lowercase and uppercase Latin letters. Check whether thi... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of characters in the string.
The second line contains the string. The string consists only of uppercase and lowercase Latin letters. | Output "YES", if the string is a pangram and "NO" otherwise. | [
"12\ntoosmallword\n",
"35\nTheQuickBrownFoxJumpsOverTheLazyDog\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "12\ntoosmallword",
"output": "NO"
},
{
"input": "35\nTheQuickBrownFoxJumpsOverTheLazyDog",
"output": "YES"
},
{
"input": "1\na",
"output": "NO"
},
{
"input": "26\nqwertyuiopasdfghjklzxcvbnm",
"output": "YES"
},
{
"input": "26\nABCDEFGHIJKLMNOPQRSTUVWXY... | 1,697,185,662 | 2,147,483,647 | PyPy 3 | OK | TESTS | 59 | 108 | 0 | def is_pangram(s):
unique_letters = set(s.lower())
return len(unique_letters) == 26
n = int(input())
input_string = input().strip()
if is_pangram(input_string):
print("YES")
else:
print("NO")
| Title: Pangram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A word or a sentence in some language is called a pangram if all the characters of the alphabet of this language appear in it at least once. Pangrams are often used to demonstrate fonts in printing or test the output devices.
... | ```python
def is_pangram(s):
unique_letters = set(s.lower())
return len(unique_letters) == 26
n = int(input())
input_string = input().strip()
if is_pangram(input_string):
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
630 | K | Indivisibility | PROGRAMMING | 1,500 | [
"math",
"number theory"
] | null | null | IT City company developing computer games decided to upgrade its way to reward its employees. Now it looks the following way. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. Every time when the next number of sales is not divisible ... | The only line of the input contains one integer *n* (1<=≤<=*n*<=≤<=1018) — the prediction on the number of people who will buy the game. | Output one integer showing how many numbers from 1 to *n* are not divisible by any number from 2 to 10. | [
"12\n"
] | [
"2"
] | none | 0 | [
{
"input": "12",
"output": "2"
},
{
"input": "2519",
"output": "576"
},
{
"input": "2521",
"output": "577"
},
{
"input": "1",
"output": "1"
},
{
"input": "314159265",
"output": "71807832"
},
{
"input": "718281828459045235",
"output": "1641787036477... | 1,695,417,990 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 10 | 46 | 0 | n=int(input())
res=n-(n//2+n//3+n//5+n//7)
res+=n//10+n//6+n//14+n//15+n//21+n//35
res-=n//42+n//30+n//70+n//105
res+=n//210
print(res)
# c=0
# for i in range(1,1000):
# pasa=True
# if i%2==0 or i%3==0 or i%5==0 or i%7==0:
# pasa=False
# if pasa:
# print(i, end=" ")
# ... | Title: Indivisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
IT City company developing computer games decided to upgrade its way to reward its employees. Now it looks the following way. After a new game release users start buying it actively, and the company tracks the number of ... | ```python
n=int(input())
res=n-(n//2+n//3+n//5+n//7)
res+=n//10+n//6+n//14+n//15+n//21+n//35
res-=n//42+n//30+n//70+n//105
res+=n//210
print(res)
# c=0
# for i in range(1,1000):
# pasa=True
# if i%2==0 or i%3==0 or i%5==0 or i%7==0:
# pasa=False
# if pasa:
# print(i, end=" ")
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
743 | B | Chloe and the sequence | PROGRAMMING | 1,200 | [
"binary search",
"bitmasks",
"constructive algorithms",
"implementation"
] | null | null | Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following algorithm of generating a sequence of integers. Initially we have a sequence consisting of a single element eq... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=2*n*<=-<=1). | Print single integer — the integer at the *k*-th position in the obtained sequence. | [
"3 2\n",
"4 8\n"
] | [
"2",
"4"
] | In the first sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1]. The number on the second position is 2.
In the second sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1]. The number on the eighth position is 4. | 1,000 | [
{
"input": "3 2",
"output": "2"
},
{
"input": "4 8",
"output": "4"
},
{
"input": "5 27",
"output": "1"
},
{
"input": "7 44",
"output": "3"
},
{
"input": "15 18432",
"output": "12"
},
{
"input": "20 259676",
"output": "3"
},
{
"input": "30 6... | 1,481,966,959 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 61 | 0 | lst = [int(s) for s in input().split()]
capacity = 2 ** lst[0]
lst[0] -= 1
while (capacity != lst[1]):
if lst[1] > capacity:
capacity += 2 ** lst[0]
lst[0] -= 1
else:
capacity -= 2 ** lst[0]
lst[0] -= 1
print(capacity) | Title: Chloe and the sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following a... | ```python
lst = [int(s) for s in input().split()]
capacity = 2 ** lst[0]
lst[0] -= 1
while (capacity != lst[1]):
if lst[1] > capacity:
capacity += 2 ** lst[0]
lst[0] -= 1
else:
capacity -= 2 ** lst[0]
lst[0] -= 1
print(capacity)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,675,258,276 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 43,315,200 | def check_count(n):
l = []
c = 0
x = 0
while True:
if x % 2 == 0:
l.append(1)
n -= 1
else:
l.append(2)
n -= 2
x += 1
c += 1
if n == 0:
break
elif n == 1:
if l[-1] == ... | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
def check_count(n):
l = []
c = 0
x = 0
while True:
if x % 2 == 0:
l.append(1)
n -= 1
else:
l.append(2)
n -= 2
x += 1
c += 1
if n == 0:
break
elif n == 1:
if... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,691,304,349 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 62 | 0 | str = input()
s = set()
for char in str:
if char.islower():
s.add(char)
print(len(s))
| Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
str = input()
s = set()
for char in str:
if char.islower():
s.add(char)
print(len(s))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,692,471,404 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | n = int(input())
k = 0
kmax = 0
for i in range(n):
s = list(map(int, str(input()).split()))
if k > kmax:
kmax = k
k -= s[0]
k += s[1]
print(kmax) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
n = int(input())
k = 0
kmax = 0
for i in range(n):
s = list(map(int, str(input()).split()))
if k > kmax:
kmax = k
k -= s[0]
k += s[1]
print(kmax)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
855 | A | Tom Riddle's Diary | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they ... | First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100. | Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower). | [
"6\ntom\nlucius\nginny\nharry\nginny\nharry\n",
"3\na\na\na\n"
] | [
"NO\nNO\nNO\nNO\nYES\nYES\n",
"NO\nYES\nYES\n"
] | In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | 500 | [
{
"input": "6\ntom\nlucius\nginny\nharry\nginny\nharry",
"output": "NO\nNO\nNO\nNO\nYES\nYES"
},
{
"input": "3\na\na\na",
"output": "NO\nYES\nYES"
},
{
"input": "1\nzn",
"output": "NO"
},
{
"input": "9\nliyzmbjwnzryjokufuxcqtzwworjeoxkbaqrujrhdidqdvwdfzilwszgnzglnnbogaclckfnb... | 1,651,938,855 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 46 | 0 | # your code goes here
n=int(input())
lst=[]
lst1=[]
for i in range(0,n):
s=input()
lst.append(s)
for i in lst:
if i not in lst1:
print("NO")
lst1.append(i)
else:
print("YES")
| Title: Tom Riddle's Diary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber ... | ```python
# your code goes here
n=int(input())
lst=[]
lst1=[]
for i in range(0,n):
s=input()
lst.append(s)
for i in lst:
if i not in lst1:
print("NO")
lst1.append(i)
else:
print("YES")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
592 | C | The Big Race | PROGRAMMING | 1,800 | [
"math"
] | null | null | Vector Willman and Array Bolt are the two most famous athletes of Byteforces. They are going to compete in a race with a distance of *L* meters today.
Willman and Bolt have exactly the same speed, so when they compete the result is always a tie. That is a problem for the organizers because they want a winner.
While ... | The first line of the input contains three integers *t*, *w* and *b* (1<=≤<=*t*,<=*w*,<=*b*<=≤<=5·1018) — the maximum possible length of the racetrack, the length of Willman's steps and the length of Bolt's steps respectively. | Print the answer to the problem as an irreducible fraction . Follow the format of the samples output.
The fraction (*p* and *q* are integers, and both *p*<=≥<=0 and *q*<=><=0 holds) is called irreducible, if there is no such integer *d*<=><=1, that both *p* and *q* are divisible by *d*. | [
"10 3 2\n",
"7 1 2\n"
] | [
"3/10\n",
"3/7\n"
] | In the first sample Willman and Bolt will tie in case 1, 6 or 7 are chosen as the length of the racetrack. | 1,500 | [
{
"input": "10 3 2",
"output": "3/10"
},
{
"input": "7 1 2",
"output": "3/7"
},
{
"input": "1 1 1",
"output": "1/1"
},
{
"input": "5814 31 7",
"output": "94/2907"
},
{
"input": "94268 813 766",
"output": "765/94268"
},
{
"input": "262610 5583 4717",
... | 1,446,312,220 | 3,220 | Python 3 | CHALLENGED | CHALLENGES | 11 | 46 | 0 | def gcd(a, b) :
while (a != b and a and b) :
if a > b:
a = a % b
else:
b = b % a
if not a:
return b
return a
def lcm(a, b):
g = gcd(a, b)
return (a * b) // g
t, a, b = input().split()
t = int(t)
a = int(a)
b = int(b)
down = t;
if a == 1:
up = t // b
elif b == 1 :
up = t // a
else :
l = lcm(a, b... | Title: The Big Race
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vector Willman and Array Bolt are the two most famous athletes of Byteforces. They are going to compete in a race with a distance of *L* meters today.
Willman and Bolt have exactly the same speed, so when they compete the... | ```python
def gcd(a, b) :
while (a != b and a and b) :
if a > b:
a = a % b
else:
b = b % a
if not a:
return b
return a
def lcm(a, b):
g = gcd(a, b)
return (a * b) // g
t, a, b = input().split()
t = int(t)
a = int(a)
b = int(b)
down = t;
if a == 1:
up = t // b
elif b == 1 :
up = t // a
else :
l ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
987 | A | Infinity Gauntlet | PROGRAMMING | 800 | [
"implementation"
] | null | null | You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color.
Using colors... | In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet.
In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase ... | In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems.
Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. | [
"4\nred\npurple\nyellow\norange\n",
"0\n"
] | [
"2\nSpace\nTime\n",
"6\nTime\nMind\nSoul\nPower\nReality\nSpace\n"
] | In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space.
In the second sample Thanos doesn't have any Gems, so he needs all six. | 500 | [
{
"input": "4\nred\npurple\nyellow\norange",
"output": "2\nSpace\nTime"
},
{
"input": "0",
"output": "6\nMind\nSpace\nPower\nTime\nReality\nSoul"
},
{
"input": "6\npurple\nblue\nyellow\nred\ngreen\norange",
"output": "0"
},
{
"input": "1\npurple",
"output": "5\nTime\nReal... | 1,594,915,394 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 109 | 6,656,000 | d={'purple':'Power','green':'Time','blue':'Space','orange':'Soul','red':'Reality','yellow':'Mind'}
n=int(input())
for _ in range(n):
s=input()
del d[s]
print(6-n)
print(*d.values())
| Title: Infinity Gauntlet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the So... | ```python
d={'purple':'Power','green':'Time','blue':'Space','orange':'Soul','red':'Reality','yellow':'Mind'}
n=int(input())
for _ in range(n):
s=input()
del d[s]
print(6-n)
print(*d.values())
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,635,772,813 | 2,147,483,647 | Python 3 | OK | TESTS | 10 | 46 | 4,505,600 | n = int(input())
a = []
a.append([1]*n)
if n == 1:
print(n)
else:
for i in range(n-1):
a.append([1]+[0]*(n-1))
for i in range(1,n):
for j in range(1,n):
a[i][j] = a[i-1][j] + a[i][j-1]
# print(a[i][j],end='')
# print()
print(a[i][j])
# print(a) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
n = int(input())
a = []
a.append([1]*n)
if n == 1:
print(n)
else:
for i in range(n-1):
a.append([1]+[0]*(n-1))
for i in range(1,n):
for j in range(1,n):
a[i][j] = a[i-1][j] + a[i][j-1]
# print(a[i][j],end='')
# print()
print(a[i][j])
# print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
535 | A | Tavas and Nafas | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.
He ate coffee mix without... | The first and only line of input contains an integer *s* (0<=≤<=*s*<=≤<=99), Tavas's score. | In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces. | [
"6\n",
"99\n",
"20\n"
] | [
"six\n",
"ninety-nine\n",
"twenty\n"
] | You can find all you need to know about English numerals in [http://en.wikipedia.org/wiki/English_numerals](https://en.wikipedia.org/wiki/English_numerals) . | 500 | [
{
"input": "6",
"output": "six"
},
{
"input": "99",
"output": "ninety-nine"
},
{
"input": "20",
"output": "twenty"
},
{
"input": "10",
"output": "ten"
},
{
"input": "15",
"output": "fifteen"
},
{
"input": "27",
"output": "twenty-seven"
},
{
... | 1,546,249,514 | 2,147,483,647 | Python 3 | OK | TESTS | 100 | 124 | 0 | x = str(input())
l = ['zero','one','two','three','four','five','six','seven','eight','nine']
if len(x) == 1 :
print(l[int(x[0])])
elif 20>int(x)>=10 :
l = ['ten','eleven','twelve','thirteen','fourteen','fifteen','sixteen','seventeen','eighteen','nineteen']
print(l[int(x[1])])
elif int(x)>=20 :
l... | Title: Tavas and Nafas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score wit... | ```python
x = str(input())
l = ['zero','one','two','three','four','five','six','seven','eight','nine']
if len(x) == 1 :
print(l[int(x[0])])
elif 20>int(x)>=10 :
l = ['ten','eleven','twelve','thirteen','fourteen','fifteen','sixteen','seventeen','eighteen','nineteen']
print(l[int(x[1])])
elif int(x)>=2... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000 is the minimum integer such that it ends with 4 or more zeros and is divisible by 375.
W... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=8). | Print the *k*-rounding of *n*. | [
"375 4\n",
"10000 1\n",
"38101 0\n",
"123456789 8\n"
] | [
"30000\n",
"10000\n",
"38101\n",
"12345678900000000\n"
] | none | 0 | [
{
"input": "375 4",
"output": "30000"
},
{
"input": "10000 1",
"output": "10000"
},
{
"input": "38101 0",
"output": "38101"
},
{
"input": "123456789 8",
"output": "12345678900000000"
},
{
"input": "1 0",
"output": "1"
},
{
"input": "2 0",
"output":... | 1,515,350,272 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 109 | 21,094,400 | # Just_Do_It ___________ICARUS__________________#
import math
[n,k]=list(map(int,input().split()))
lcm=lambda x,y: x*y/math.gcd(max(x,y),x,y)
print(int(lcm(n,pow(10,k))))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a given positive integer *n* denote its *k*-rounding as the minimum positive integer *x*, such that *x* ends with *k* or more zeros in base 10 and is divisible by *n*.
For example, 4-rounding of 375 is 375·80<==<=30000. 30000... | ```python
# Just_Do_It ___________ICARUS__________________#
import math
[n,k]=list(map(int,input().split()))
lcm=lambda x,y: x*y/math.gcd(max(x,y),x,y)
print(int(lcm(n,pow(10,k))))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,542,394,915 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 248 | 0 | n=int(input())
a=list(map(int,input().split()))
odd=0
even=0
ei=0
oi=0
for i in range(n):
if a[i]%2==1:
odd+=1
oi=i
else:
even+=1
ei=i
if odd==1:
print(oi+1)
else:
print(ei+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
a=list(map(int,input().split()))
odd=0
even=0
ei=0
oi=0
for i in range(n):
if a[i]%2==1:
odd+=1
oi=i
else:
even+=1
ei=i
if odd==1:
print(oi+1)
else:
print(ei+1)
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
748 | B | Santa Claus and Keyboard Check | PROGRAMMING | 1,500 | [
"implementation",
"strings"
] | null | null | Santa Claus decided to disassemble his keyboard to clean it. After he returned all the keys back, he suddenly realized that some pairs of keys took each other's place! That is, Santa suspects that each key is either on its place, or on the place of another key, which is located exactly where the first key should be.
... | The input consists of only two strings *s* and *t* denoting the favorite Santa's patter and the resulting string. *s* and *t* are not empty and have the same length, which is at most 1000. Both strings consist only of lowercase English letters. | If Santa is wrong, and there is no way to divide some of keys into pairs and swap keys in each pair so that the keyboard will be fixed, print «-1» (without quotes).
Otherwise, the first line of output should contain the only integer *k* (*k*<=≥<=0) — the number of pairs of keys that should be swapped. The following *k... | [
"helloworld\nehoolwlroz\n",
"hastalavistababy\nhastalavistababy\n",
"merrychristmas\nchristmasmerry\n"
] | [
"3\nh e\nl o\nd z\n",
"0\n",
"-1\n"
] | none | 1,000 | [
{
"input": "helloworld\nehoolwlroz",
"output": "3\nh e\nl o\nd z"
},
{
"input": "hastalavistababy\nhastalavistababy",
"output": "0"
},
{
"input": "merrychristmas\nchristmasmerry",
"output": "-1"
},
{
"input": "kusyvdgccw\nkusyvdgccw",
"output": "0"
},
{
"input": "... | 1,538,242,082 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 124 | 102,400 | ls = input()
ls_mist = input()
repl = [[],[]]
for i in range(len(ls)):
if ls[i] != ls_mist[i]:
if ls_mist[i]>ls[i]:
repl[0].append(ls[i])
repl[1].append(ls_mist[i])
else:
repl[1].append(ls[i])
repl[0].append(ls_mist[i])
if len(set(repl[0])) == len(set(repl[1])):
print(len(set(repl[1]... | Title: Santa Claus and Keyboard Check
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Santa Claus decided to disassemble his keyboard to clean it. After he returned all the keys back, he suddenly realized that some pairs of keys took each other's place! That is, Santa suspects that each ke... | ```python
ls = input()
ls_mist = input()
repl = [[],[]]
for i in range(len(ls)):
if ls[i] != ls_mist[i]:
if ls_mist[i]>ls[i]:
repl[0].append(ls[i])
repl[1].append(ls_mist[i])
else:
repl[1].append(ls[i])
repl[0].append(ls_mist[i])
if len(set(repl[0])) == len(set(repl[1])):
print(len(s... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
762 | A | k-th divisor | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=1015, 1<=≤<=*k*<=≤<=109). | If *n* has less than *k* divisors, output -1.
Otherwise, output the *k*-th smallest divisor of *n*. | [
"4 2\n",
"5 3\n",
"12 5\n"
] | [
"2\n",
"-1\n",
"6\n"
] | In the first example, number 4 has three divisors: 1, 2 and 4. The second one is 2.
In the second example, number 5 has only two divisors: 1 and 5. The third divisor doesn't exist, so the answer is -1. | 0 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "12 5",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "866421317361600 26880",
"output": "866421317361600"
},
{
"input": "866421317361600 26881",
"ou... | 1,687,012,954 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 0 | from math import isqrt
def prime_factor(n):
l=1
for i in range(2,int(n**(0.5))+1):
if n%i==0:
po=0
while n%i==0:
n=n//i
po+=1
l*=(po+1)
return l
n,k=map(int,input().split())
p=prime_factor(n)
if k>p:print(-1)
else:... | Title: k-th divisor
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two integers *n* and *k*. Find *k*-th smallest divisor of *n*, or report that it doesn't exist.
Divisor of *n* is any such natural number, that *n* can be divided by it without remainder.
Input Specificatio... | ```python
from math import isqrt
def prime_factor(n):
l=1
for i in range(2,int(n**(0.5))+1):
if n%i==0:
po=0
while n%i==0:
n=n//i
po+=1
l*=(po+1)
return l
n,k=map(int,input().split())
p=prime_factor(n)
if k>p:print(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
79 | B | Colorful Field | PROGRAMMING | 1,400 | [
"implementation",
"sortings"
] | B. Colorful Field | 2 | 256 | Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
After seeing the field carefully, Ciel found that the crop plants of each cell were planted in f... | In the first line there are four positive integers *n*,<=*m*,<=*k*,<=*t* (1<=≤<=*n*<=≤<=4·104,<=1<=≤<=*m*<=≤<=4·104,<=1<=≤<=*k*<=≤<=103,<=1<=≤<=*t*<=≤<=103), each of which represents the height of the field, the width of the field, the number of waste cells and the number of queries that ask the kind of crop plants in ... | For each query, if the cell is waste, print Waste. Otherwise, print the name of crop plants in the cell: either Carrots or Kiwis or Grapes. | [
"4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1\n"
] | [
"Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots\n"
] | The sample corresponds to the figure in the statement. | 1,000 | [
{
"input": "4 5 5 6\n4 3\n1 3\n3 3\n2 5\n3 2\n1 3\n1 4\n2 3\n2 4\n1 1\n1 1",
"output": "Waste\nGrapes\nCarrots\nKiwis\nCarrots\nCarrots"
},
{
"input": "2 3 2 2\n1 1\n2 2\n2 1\n2 2",
"output": "Grapes\nWaste"
},
{
"input": "31 31 31 4\n4 9\n16 27\n11 29\n8 28\n11 2\n10 7\n22 6\n1 25\n14 8... | 1,616,933,698 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 139,264,000 | # link: https://codeforces.com/contest/79/problem/B
if __name__ == "__main__":
n,m,k,t = map(int,input().split())
waste = []
a = ["Carrots", "Kiwis", "Grapes"]
matrix = [[0 for i in range(m)] for j in range(n)]
info_about_wastes_in_each_row = {}
while k:
i,j = map(int,input().spl... | Title: Colorful Field
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Fox Ciel saw a large field while she was on a bus. The field was a *n*<=×<=*m* rectangle divided into 1<=×<=1 cells. Some cells were wasteland, and other each cell contained crop plants: either carrots or kiwis or grapes.
... | ```python
# link: https://codeforces.com/contest/79/problem/B
if __name__ == "__main__":
n,m,k,t = map(int,input().split())
waste = []
a = ["Carrots", "Kiwis", "Grapes"]
matrix = [[0 for i in range(m)] for j in range(n)]
info_about_wastes_in_each_row = {}
while k:
i,j = map(int,i... | 0 | MatrixStudio/Codeforces-Python-Submissions |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,625,063,574 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 77 | 0 | for _ in range(int(input())):
name,b,a = input().split()
if int(a) > int(b) > 2399:
print("YES")
exit()
print("NO")
| Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
for _ in range(int(input())):
name,b,a = input().split()
if int(a) > int(b) > 2399:
print("YES")
exit()
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,696,157,204 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 | n,h=map(int,input().split())
L=list(map(int,input().split()))
s=0
for i in range(n):
if (L[i]<=h):
s+=1
else:
s+=2
print(s) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n,h=map(int,input().split())
L=list(map(int,input().split()))
s=0
for i in range(n):
if (L[i]<=h):
s+=1
else:
s+=2
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,674,250,714 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | x = input().split(" ")
print(max(x)/6) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
x = input().split(" ")
print(max(x)/6)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,464,820,125 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 62 | 5,120,000 | n = int (input());
min = [int(i) for i in input().split()];
time = 0;
index = 0;
for i in min:
if time + 15 >= i:
time = i;
else:
time += 15;
break;
index += 1;
if index == n:
time += 15;
if time > 90:
time = 90;
print (time); | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int (input());
min = [int(i) for i in input().split()];
time = 0;
index = 0;
for i in min:
if time + 15 >= i:
time = i;
else:
time += 15;
break;
index += 1;
if index == n:
time += 15;
if time > 90:
time = 90;
print (time);
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
127 | B | Canvas Frames | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Nicholas, a painter is going to paint several new canvases. Nicholas is sure that the canvases will turn out so great that each one will need framing and being hung on the wall. Frames are what Nicholas decided to begin with.
Nicholas has *n* sticks whose lengths equal *a*1,<=*a*2,<=... *a**n*. Nicholas does not want... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of sticks. The second line contains *n* space-separated integers. The *i*-th integer equals the length of the *i*-th stick *a**i* (1<=≤<=*a**i*<=≤<=100). | Print the single number — the maximum number of frames Nicholas can make for his future canvases. | [
"5\n2 4 3 2 3\n",
"13\n2 2 4 4 4 4 6 6 6 7 7 9 9\n",
"4\n3 3 3 5\n"
] | [
"1",
"3",
"0"
] | none | 1,000 | [
{
"input": "5\n2 4 3 2 3",
"output": "1"
},
{
"input": "13\n2 2 4 4 4 4 6 6 6 7 7 9 9",
"output": "3"
},
{
"input": "4\n3 3 3 5",
"output": "0"
},
{
"input": "2\n3 5",
"output": "0"
},
{
"input": "9\n1 2 3 4 5 6 7 8 9",
"output": "0"
},
{
"input": "14\... | 1,587,041,311 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 202 | 2,048,000 | n=int(input())
a=[int(i) for i in input().split()]
count=0
d=set(a)
count=0
l1=[]
sums=0
for i in d:
if(a.count(i)==4):
count=count=1
if(a.count(i)>=2):
l.append(a.count(i))
sums=(sum(l))//4
print(sums+count)
| Title: Canvas Frames
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nicholas, a painter is going to paint several new canvases. Nicholas is sure that the canvases will turn out so great that each one will need framing and being hung on the wall. Frames are what Nicholas decided to begin w... | ```python
n=int(input())
a=[int(i) for i in input().split()]
count=0
d=set(a)
count=0
l1=[]
sums=0
for i in d:
if(a.count(i)==4):
count=count=1
if(a.count(i)>=2):
l.append(a.count(i))
sums=(sum(l))//4
print(sums+count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
735 | A | Ostap and Grasshopper | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles. Then, he places his grasshopper to one of the empty cells and a small insect in another empty cell. The gr... | The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=*n*<=-<=1) — the number of cells in the line and the length of one grasshopper's jump.
The second line contains a string of length *n* consisting of characters '.', '#', 'G' and 'T'. Character '.' means that the correspondi... | If there exists a sequence of jumps (each jump of length *k*), such that the grasshopper can get from his initial position to the cell with the insect, print "YES" (without quotes) in the only line of the input. Otherwise, print "NO" (without quotes). | [
"5 2\n#G#T#\n",
"6 1\nT....G\n",
"7 3\nT..#..G\n",
"6 2\n..GT..\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the grasshopper can make one jump to the right in order to get from cell 2 to cell 4.
In the second sample, the grasshopper is only able to jump to neighboring cells but the way to the insect is free — he can get there by jumping left 5 times.
In the third sample, the grasshopper can't make a sin... | 500 | [
{
"input": "5 2\n#G#T#",
"output": "YES"
},
{
"input": "6 1\nT....G",
"output": "YES"
},
{
"input": "7 3\nT..#..G",
"output": "NO"
},
{
"input": "6 2\n..GT..",
"output": "NO"
},
{
"input": "2 1\nGT",
"output": "YES"
},
{
"input": "100 5\nG####.####.###... | 1,689,354,989 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 46 | 0 | #codeforces 735A
n,k=map(int,input().split())
s=input()
for i in range(len(s)):
if s[i]=='G':
a=i
elif s[i]=='T':
b=i
if abs(a-b)%k==0:
if a>b:
a,b=b,a
for j in range(a,b+1):
if s[j]=='#':
x=j
if abs(a-x)==k:
print('NO')
else:
print('YES')
else:
p... | Title: Ostap and Grasshopper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On the way to Rio de Janeiro Ostap kills time playing with a grasshopper he took with him in a special box. Ostap builds a line of length *n* such that some cells of this line are empty and some contain obstacles.... | ```python
#codeforces 735A
n,k=map(int,input().split())
s=input()
for i in range(len(s)):
if s[i]=='G':
a=i
elif s[i]=='T':
b=i
if abs(a-b)%k==0:
if a>b:
a,b=b,a
for j in range(a,b+1):
if s[j]=='#':
x=j
if abs(a-x)==k:
print('NO')
else:
print('YES')
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
913 | B | Christmas Spruce | PROGRAMMING | 1,200 | [
"implementation",
"trees"
] | null | null | Consider a rooted tree. A rooted tree has one special vertex called the root. All edges are directed from the root. Vertex *u* is called a child of vertex *v* and vertex *v* is called a parent of vertex *u* if there exists a directed edge from *v* to *u*. A vertex is called a leaf if it doesn't have children and has a ... | The first line contains one integer *n* — the number of vertices in the tree (3<=≤<=*n*<=≤<=1<=000). Each of the next *n*<=-<=1 lines contains one integer *p**i* (1<=≤<=*i*<=≤<=*n*<=-<=1) — the index of the parent of the *i*<=+<=1-th vertex (1<=≤<=*p**i*<=≤<=*i*).
Vertex 1 is the root. It's guaranteed that the root ha... | Print "Yes" if the tree is a spruce and "No" otherwise. | [
"4\n1\n1\n1\n",
"7\n1\n1\n1\n2\n2\n2\n",
"8\n1\n1\n1\n1\n3\n3\n3\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | The first example:
<img class="tex-graphics" src="https://espresso.codeforces.com/8dd976913226df83d535dfa66193f5525f8471bc.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The second example:
<img class="tex-graphics" src="https://espresso.codeforces.com/44dad5804f5290a2e026c9c41a15151562df8682.png" style="max-w... | 750 | [
{
"input": "4\n1\n1\n1",
"output": "Yes"
},
{
"input": "7\n1\n1\n1\n2\n2\n2",
"output": "No"
},
{
"input": "8\n1\n1\n1\n1\n3\n3\n3",
"output": "Yes"
},
{
"input": "3\n1\n1",
"output": "No"
},
{
"input": "13\n1\n2\n2\n2\n1\n6\n6\n6\n1\n10\n10\n10",
"output": "N... | 1,658,236,917 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 46 | 102,400 | from collections import deque
# https://algoprog.ru/material/pc913pB
N = int(input())
graph = {i: [] for i in range(1, N + 1)}
for i in range(2, N + 1):
A = int(input())
graph[A].append(i)
q = deque()
q.append(1)
while len(q) > 0:
top = q.popleft()
leaves = 0
for nt in graph[top]... | Title: Christmas Spruce
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Consider a rooted tree. A rooted tree has one special vertex called the root. All edges are directed from the root. Vertex *u* is called a child of vertex *v* and vertex *v* is called a parent of vertex *u* if there ex... | ```python
from collections import deque
# https://algoprog.ru/material/pc913pB
N = int(input())
graph = {i: [] for i in range(1, N + 1)}
for i in range(2, N + 1):
A = int(input())
graph[A].append(i)
q = deque()
q.append(1)
while len(q) > 0:
top = q.popleft()
leaves = 0
for nt in ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
287 | A | IQ Test | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and others are painted white. Your task is to repaint at most one cell the other color so that the... | Four lines contain four characters each: the *j*-th character of the *i*-th line equals "." if the cell in the *i*-th row and the *j*-th column of the square is painted white, and "#", if the cell is black. | Print "YES" (without the quotes), if the test can be passed and "NO" (without the quotes) otherwise. | [
"####\n.#..\n####\n....\n",
"####\n....\n####\n....\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample it is enough to repaint the first cell in the second row. After such repainting the required 2 × 2 square is on the intersection of the 1-st and 2-nd row with the 1-st and 2-nd column. | 500 | [
{
"input": "###.\n...#\n###.\n...#",
"output": "NO"
},
{
"input": ".##.\n#..#\n.##.\n#..#",
"output": "NO"
},
{
"input": ".#.#\n#.#.\n.#.#\n#.#.",
"output": "NO"
},
{
"input": "##..\n..##\n##..\n..##",
"output": "NO"
},
{
"input": "#.#.\n#.#.\n.#.#\n.#.#",
"ou... | 1,620,398,924 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 62 | 6,963,200 | def main():
n = 4
c = []
for string in range(n):
c.append(list(input()))
for i in range(n-1):
for j in range(n-1):
w = 0
b = 0
if c[i][j]=='.': w += 1
else: b += 1
if c[i+1][j]=='.': w+=1
else: b += 1
... | Title: IQ Test
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the city of Ultima Thule job applicants are often offered an IQ test.
The test is as follows: the person gets a piece of squared paper with a 4<=×<=4 square painted on it. Some of the square's cells are painted black and o... | ```python
def main():
n = 4
c = []
for string in range(n):
c.append(list(input()))
for i in range(n-1):
for j in range(n-1):
w = 0
b = 0
if c[i][j]=='.': w += 1
else: b += 1
if c[i+1][j]=='.': w+=1
else... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,689,486,181 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 |
def new_year_and_rush():
tasks, min = input().split()
time = 0
for i in range(1, int(tasks)+1):
time+= i*5
if time+int(min) > 240:
return i-1
print(new_year_and_rush()) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
def new_year_and_rush():
tasks, min = input().split()
time = 0
for i in range(1, int(tasks)+1):
time+= i*5
if time+int(min) > 240:
return i-1
print(new_year_and_rush())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
592 | C | The Big Race | PROGRAMMING | 1,800 | [
"math"
] | null | null | Vector Willman and Array Bolt are the two most famous athletes of Byteforces. They are going to compete in a race with a distance of *L* meters today.
Willman and Bolt have exactly the same speed, so when they compete the result is always a tie. That is a problem for the organizers because they want a winner.
While ... | The first line of the input contains three integers *t*, *w* and *b* (1<=≤<=*t*,<=*w*,<=*b*<=≤<=5·1018) — the maximum possible length of the racetrack, the length of Willman's steps and the length of Bolt's steps respectively. | Print the answer to the problem as an irreducible fraction . Follow the format of the samples output.
The fraction (*p* and *q* are integers, and both *p*<=≥<=0 and *q*<=><=0 holds) is called irreducible, if there is no such integer *d*<=><=1, that both *p* and *q* are divisible by *d*. | [
"10 3 2\n",
"7 1 2\n"
] | [
"3/10\n",
"3/7\n"
] | In the first sample Willman and Bolt will tie in case 1, 6 or 7 are chosen as the length of the racetrack. | 1,500 | [
{
"input": "10 3 2",
"output": "3/10"
},
{
"input": "7 1 2",
"output": "3/7"
},
{
"input": "1 1 1",
"output": "1/1"
},
{
"input": "5814 31 7",
"output": "94/2907"
},
{
"input": "94268 813 766",
"output": "765/94268"
},
{
"input": "262610 5583 4717",
... | 1,446,313,117 | 4,117 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 62 | 0 | def gcd (a, b):
while (b):
a %= b
t = a
a = b
b = t
return a
t, w, b = list(map(int, input().split(' ')))
q = t
p = min(w, b) - 1;
nod = gcd(max(w, b), min(w, b));
nok = (w // nod) * b;
k = (t // nok) * min(b, w);
k -= (min(b, w) - 1);
x = t % nok;
k += min(x, min(b, w) - 1);
p += k;
x = gc... | Title: The Big Race
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vector Willman and Array Bolt are the two most famous athletes of Byteforces. They are going to compete in a race with a distance of *L* meters today.
Willman and Bolt have exactly the same speed, so when they compete the... | ```python
def gcd (a, b):
while (b):
a %= b
t = a
a = b
b = t
return a
t, w, b = list(map(int, input().split(' ')))
q = t
p = min(w, b) - 1;
nod = gcd(max(w, b), min(w, b));
nok = (w // nod) * b;
k = (t // nok) * min(b, w);
k -= (min(b, w) - 1);
x = t % nok;
k += min(x, min(b, w) - 1);
p += ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,600,253,024 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 155 | 0 | n=int(input())
s=input()
t,c=0,0
for i in range(n-1):
if s[i]=='S' and s[i+1]=='F':
t+=1
elif s[i]=='F' and s[i+1]=='S':
c+=1
if t>c:
print("YES")
else:
print("NO")
| Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
n=int(input())
s=input()
t,c=0,0
for i in range(n-1):
if s[i]=='S' and s[i+1]=='F':
t+=1
elif s[i]=='F' and s[i+1]=='S':
c+=1
if t>c:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
765 | C | Table Tennis Game 2 | PROGRAMMING | 1,200 | [
"math"
] | null | null | Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scores exactly *k* points, the score is reset and a new set begins.
Across all the sets Misha scored *a* poi... | The first line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=109, 0<=≤<=*a*,<=*b*<=≤<=109, *a*<=+<=*b*<=><=0). | If the situation is impossible, print a single number -1. Otherwise, print the maximum possible number of sets. | [
"11 11 5\n",
"11 2 3\n"
] | [
"1\n",
"-1\n"
] | Note that the rules of the game in this problem differ from the real table tennis game, for example, the rule of "balance" (the winning player has to be at least two points ahead to win a set) has no power within the present problem. | 1,250 | [
{
"input": "11 11 5",
"output": "1"
},
{
"input": "11 2 3",
"output": "-1"
},
{
"input": "1 5 9",
"output": "14"
},
{
"input": "2 3 3",
"output": "2"
},
{
"input": "1 1000000000 1000000000",
"output": "2000000000"
},
{
"input": "2 3 5",
"output": "... | 1,487,065,454 | 5,954 | Python 3 | CHALLENGED | CHALLENGES | 9 | 77 | 4,608,000 | import sys
k, a, b = sys.stdin.readline().strip().split()
k, a, b = int(k), int(a), int(b)
a1 = a // k
a2 = b // k
if a < k and b < k:
print(-1)
else:
print(a1+a2) | Title: Table Tennis Game 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vanya have played several table tennis sets. Each set consists of several serves, each serve is won by one of the players, he receives one point and the loser receives nothing. Once one of the players scor... | ```python
import sys
k, a, b = sys.stdin.readline().strip().split()
k, a, b = int(k), int(a), int(b)
a1 = a // k
a2 = b // k
if a < k and b < k:
print(-1)
else:
print(a1+a2)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,598,965,363 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 109 | 0 | a=list(map(int,input().split()))
r=[]
r.append(a[0])
for j in range(a[2]):
for i in range(1,10,1):
r.append(i)
y=''
for g in r:
y=y+str(g)
u=int(y)
print(u,a[1])
if((u%a[1])==0):
break
else:
... | Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a=list(map(int,input().split()))
r=[]
r.append(a[0])
for j in range(a[2]):
for i in range(1,10,1):
r.append(i)
y=''
for g in r:
y=y+str(g)
u=int(y)
print(u,a[1])
if((u%a[1])==0):
break
e... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
706 | D | Vasiliy's Multiset | PROGRAMMING | 1,800 | [
"binary search",
"bitmasks",
"data structures",
"trees"
] | null | null | Author has gone out of the stories about Vasiliy, so here is just a formal task description.
You are given *q* queries and a multiset *A*, initially containing only integer 0. There are three types of queries:
1. "+ x" — add integer *x* to multiset *A*.1. "- x" — erase one occurrence of integer *x* from multiset *A... | The first line of the input contains a single integer *q* (1<=≤<=*q*<=≤<=200<=000) — the number of queries Vasiliy has to perform.
Each of the following *q* lines of the input contains one of three characters '+', '-' or '?' and an integer *x**i* (1<=≤<=*x**i*<=≤<=109). It's guaranteed that there is at least one query... | For each query of the type '?' print one integer — the maximum value of bitwise exclusive OR (XOR) of integer *x**i* and some integer from the multiset *A*. | [
"10\n+ 8\n+ 9\n+ 11\n+ 6\n+ 1\n? 3\n- 8\n? 3\n? 8\n? 11\n"
] | [
"11\n10\n14\n13\n"
] | After first five operations multiset *A* contains integers 0, 8, 9, 11, 6 and 1.
The answer for the sixth query is integer <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/9e2f3d4f1a7c134a5695ba1d548df2b4f9292206.png" style="max-width: 100.0%;max-height: 100.0%;"/> — maximum among integers ... | 2,000 | [
{
"input": "10\n+ 8\n+ 9\n+ 11\n+ 6\n+ 1\n? 3\n- 8\n? 3\n? 8\n? 11",
"output": "11\n10\n14\n13"
},
{
"input": "12\n+ 4\n+ 4\n+ 5\n? 3\n- 4\n? 3\n- 4\n? 3\n? 3\n- 5\n+ 10\n? 1",
"output": "7\n7\n6\n6\n11"
},
{
"input": "10\n? 1\n+ 1\n+ 8\n- 1\n+ 2\n+ 7\n+ 4\n+ 7\n+ 3\n? 7",
"output": ... | 1,697,913,296 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 1 | 4,000 | 9,113,600 | import bisect
n = int(input())
s = [0]
for _ in range(n):
op, x = input().split()
x = int(x)
if op == '+':
s.append(x)
s.sort()
elif op == '-':
s.remove(x)
else:
ans = 0
for i in range(31, -1, -1):
ans |= (~x & (1 << i))
... | Title: Vasiliy's Multiset
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Author has gone out of the stories about Vasiliy, so here is just a formal task description.
You are given *q* queries and a multiset *A*, initially containing only integer 0. There are three types of queries:
1. ... | ```python
import bisect
n = int(input())
s = [0]
for _ in range(n):
op, x = input().split()
x = int(x)
if op == '+':
s.append(x)
s.sort()
elif op == '-':
s.remove(x)
else:
ans = 0
for i in range(31, -1, -1):
ans |= (~x & (1 << i))... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed *d*.
Note that the order of the points inside the group of three chosen... | The first line contains two integers: *n* and *d* (1<=≤<=*n*<=≤<=105; 1<=≤<=*d*<=≤<=109). The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n*, their absolute value doesn't exceed 109 — the *x*-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input stri... | Print a single integer — the number of groups of three points, where the distance between two farthest points doesn't exceed *d*.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 3\n1 2 3 4\n",
"4 2\n-3 -2 -1 0\n",
"5 19\n1 10 20 30 50\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}. | 0 | [
{
"input": "4 3\n1 2 3 4",
"output": "4"
},
{
"input": "4 2\n-3 -2 -1 0",
"output": "2"
},
{
"input": "5 19\n1 10 20 30 50",
"output": "1"
},
{
"input": "10 5\n31 36 43 47 48 50 56 69 71 86",
"output": "2"
},
{
"input": "10 50\n1 4 20 27 65 79 82 83 99 100",
"... | 1,654,540,030 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 278 | 3,481,600 | import sys
import math
import collections
import heapq
import decimal
input=sys.stdin.readline
n,d=(int(i) for i in input().split())
l=sorted([int(i) for i in input().split()])
if(n<=2):
print(0)
else:
i,j=0,2
s=0
while(i<n and j<n):
if(j-i==1):
j+=1
while(j<n... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya likes points a lot. Recently his mom has presented him *n* points lying on the line *OX*. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of th... | ```python
import sys
import math
import collections
import heapq
import decimal
input=sys.stdin.readline
n,d=(int(i) for i in input().split())
l=sorted([int(i) for i in input().split()])
if(n<=2):
print(0)
else:
i,j=0,2
s=0
while(i<n and j<n):
if(j-i==1):
j+=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
920 | C | Swap Adjacent Elements | PROGRAMMING | 1,400 | [
"dfs and similar",
"greedy",
"math",
"sortings",
"two pointers"
] | null | null | You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<=1)-th, for other indices it is not possible. You may perform any number of swapping operations any order. T... | The first line contains one integer *n* (2<=≤<=*n*<=≤<=200000) — the number of elements in the array.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=200000) — the elements of the array. Each integer from 1 to *n* appears exactly once.
The third line contains a string of *n*<=-<=1 char... | If it is possible to sort the array in ascending order using any sequence of swaps you are allowed to make, print YES. Otherwise, print NO. | [
"6\n1 2 5 3 4 6\n01110\n",
"6\n1 2 5 3 4 6\n01010\n"
] | [
"YES\n",
"NO\n"
] | In the first example you may swap *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, and then swap *a*<sub class="lower-index">4</sub> and *a*<sub class="lower-index">5</sub>. | 0 | [
{
"input": "6\n1 2 5 3 4 6\n01110",
"output": "YES"
},
{
"input": "6\n1 2 5 3 4 6\n01010",
"output": "NO"
},
{
"input": "6\n1 6 3 4 5 2\n01101",
"output": "NO"
},
{
"input": "6\n2 3 1 4 5 6\n01111",
"output": "NO"
},
{
"input": "4\n2 3 1 4\n011",
"output": "NO... | 1,517,587,910 | 5,810 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 280 | 19,353,600 | n = int(input())
a = list(map(int, input().split()))
s = list(map(lambda x: True if x=="1" else False, list(input())))
i=0
while i < n:
if i == n-1:
if a[-1] != n:
print("NO")
elif not s[i]:
if a[i]-1 != i:
print("NO")
exit()
else:
start = i
... | Title: Swap Adjacent Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have an array *a* consisting of *n* integers. Each integer from 1 to *n* appears exactly once in this array.
For some indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1) it is possible to swap *i*-th element with (*i*<=+<... | ```python
n = int(input())
a = list(map(int, input().split()))
s = list(map(lambda x: True if x=="1" else False, list(input())))
i=0
while i < n:
if i == n-1:
if a[-1] != n:
print("NO")
elif not s[i]:
if a[i]-1 != i:
print("NO")
exit()
else:
start ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
862 | A | Mahmoud and Ehab and the MEX | PROGRAMMING | 1,000 | [
"greedy",
"implementation"
] | null | null | Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in sets, He has a set of *n* integers. Dr. Evil calls a set of integers evil if the MEX of it is exactly *x*. the MEX... | The first line contains two integers *n* and *x* (1<=≤<=*n*<=≤<=100, 0<=≤<=*x*<=≤<=100) — the size of the set Dr. Evil owns, and the desired MEX.
The second line contains *n* distinct non-negative integers not exceeding 100 that represent the set. | The only line should contain one integer — the minimal number of operations Dr. Evil should perform. | [
"5 3\n0 4 5 6 7\n",
"1 0\n0\n",
"5 0\n1 2 3 4 5\n"
] | [
"2\n",
"1\n",
"0\n"
] | For the first test case Dr. Evil should add 1 and 2 to the set performing 2 operations.
For the second test case Dr. Evil should erase 0 from the set. After that, the set becomes empty, so the MEX of it is 0.
In the third test case the set is already evil. | 500 | [
{
"input": "5 3\n0 4 5 6 7",
"output": "2"
},
{
"input": "1 0\n0",
"output": "1"
},
{
"input": "5 0\n1 2 3 4 5",
"output": "0"
},
{
"input": "10 5\n57 1 47 9 93 37 76 70 78 15",
"output": "4"
},
{
"input": "10 5\n99 98 93 97 95 100 92 94 91 96",
"output": "5"
... | 1,628,514,301 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 92 | 6,963,200 | n,x=map(int,input().split())
l=list(map(int,input().split()))
l.sort()
pre=[0]*(103)
for i in l:
pre[i]=1
r=0
for i in range(101):
if (i==x) and(pre[x]==1):r+=1
elif i<x:
if pre[i]==0:r+=1
print(r) | Title: Mahmoud and Ehab and the MEX
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dr. Evil kidnapped Mahmoud and Ehab in the evil land because of their performance in the Evil Olympiad in Informatics (EOI). He decided to give them some problems to let them go.
Dr. Evil is interested in ... | ```python
n,x=map(int,input().split())
l=list(map(int,input().split()))
l.sort()
pre=[0]*(103)
for i in l:
pre[i]=1
r=0
for i in range(101):
if (i==x) and(pre[x]==1):r+=1
elif i<x:
if pre[i]==0:r+=1
print(r)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
161 | D | Distance in Tree | PROGRAMMING | 1,800 | [
"dfs and similar",
"dp",
"trees"
] | null | null | A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices and a positive number *k*. Find the number of distinct pairs of the vertices which have a distance of ex... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50000, 1<=≤<=*k*<=≤<=500) — the number of vertices and the required distance between the vertices.
Next *n*<=-<=1 lines describe the edges as "*a**i* *b**i*" (without the quotes) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), where *a**i* and *b**i* ... | Print a single integer — the number of distinct pairs of the tree's vertices which have a distance of exactly *k* between them.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"5 2\n1 2\n2 3\n3 4\n2 5\n",
"5 3\n1 2\n2 3\n3 4\n4 5\n"
] | [
"4\n",
"2\n"
] | In the first sample the pairs of vertexes at distance 2 from each other are (1, 3), (1, 5), (3, 5) and (2, 4). | 2,000 | [
{
"input": "5 2\n1 2\n2 3\n3 4\n2 5",
"output": "4"
},
{
"input": "5 3\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10 1\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "9"
},
{
"input": "10 2\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "10"
... | 1,669,881,241 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 2,150,400 | n = int(input())
edges = {}
for i in range(n):
edges[i+1] = []
cost = 0
for i in range(n-1):
s , t ,w = [int(i) for i in input().split()]
cost += 2 * w
edges[s].append((t,w))
edges[t].append((s,w))
dist = [0] * (n+1)
def dfs(visited,adj,max_cost, node):
if(node in visited):... | Title: Distance in Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices an... | ```python
n = int(input())
edges = {}
for i in range(n):
edges[i+1] = []
cost = 0
for i in range(n-1):
s , t ,w = [int(i) for i in input().split()]
cost += 2 * w
edges[s].append((t,w))
edges[t].append((s,w))
dist = [0] * (n+1)
def dfs(visited,adj,max_cost, node):
if(node in... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,585,992,569 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 108 | 0 | n = int(input())
l = list(map(int, input().split()))
happyMinus = 15
for t in l:
if t <= happyMinus:
happyMinus = t + 15
else:
break
if happyMinus > 90:
happyMinus = 90
print(happyMinus) | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n = int(input())
l = list(map(int, input().split()))
happyMinus = 15
for t in l:
if t <= happyMinus:
happyMinus = t + 15
else:
break
if happyMinus > 90:
happyMinus = 90
print(happyMinus)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
496 | D | Tennis Game | PROGRAMMING | 1,900 | [
"binary search"
] | null | null | Petya and Gena love playing table tennis. A single match is played according to the following rules: a match consists of multiple sets, each set consists of multiple serves. Each serve is won by one of the players, this player scores one point. As soon as one of the players scores *t* points, he wins the set; then the ... | The first line contains a single integer *n* — the length of the sequence of games (1<=≤<=*n*<=≤<=105).
The second line contains *n* space-separated integers *a**i*. If *a**i*<==<=1, then the *i*-th serve was won by Petya, if *a**i*<==<=2, then the *i*-th serve was won by Gena.
It is not guaranteed that at least one ... | In the first line print a single number *k* — the number of options for numbers *s* and *t*.
In each of the following *k* lines print two integers *s**i* and *t**i* — the option for numbers *s* and *t*. Print the options in the order of increasing *s**i*, and for equal *s**i* — in the order of increasing *t**i*. | [
"5\n1 2 1 2 1\n",
"4\n1 1 1 1\n",
"4\n1 2 1 2\n",
"8\n2 1 2 1 1 1 1 1\n"
] | [
"2\n1 3\n3 1\n",
"3\n1 4\n2 2\n4 1\n",
"0\n",
"3\n1 6\n2 3\n6 1\n"
] | none | 2,250 | [
{
"input": "5\n1 2 1 2 1",
"output": "2\n1 3\n3 1"
},
{
"input": "4\n1 1 1 1",
"output": "3\n1 4\n2 2\n4 1"
},
{
"input": "4\n1 2 1 2",
"output": "0"
},
{
"input": "8\n2 1 2 1 1 1 1 1",
"output": "3\n1 6\n2 3\n6 1"
},
{
"input": "14\n2 1 2 1 1 1 1 2 1 1 2 1 2 1",
... | 1,419,212,968 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 61 | 0 | from itertools import chain
def main(n,a, info=False):
winner = a[-1]
looser = 3-winner
csw, csl, pw, pl, ans = [0], [0], [-1], [-1], []
nw,nl = a.count(winner), a.count(looser)
for i in range(n):
if a[i]==winner: pw.append(i)
else: pl.append(i)
csw.append(csw[-1] + int(a[i]=... | Title: Tennis Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Gena love playing table tennis. A single match is played according to the following rules: a match consists of multiple sets, each set consists of multiple serves. Each serve is won by one of the players, this pla... | ```python
from itertools import chain
def main(n,a, info=False):
winner = a[-1]
looser = 3-winner
csw, csl, pw, pl, ans = [0], [0], [-1], [-1], []
nw,nl = a.count(winner), a.count(looser)
for i in range(n):
if a[i]==winner: pw.append(i)
else: pl.append(i)
csw.append(csw[-1] +... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,664,548,227 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 62 | 0 | red, blue = list(map(int, input().split()))
if blue > red:
print(red, int((blue - red) / 2))
else:
print(blue, int((red - blue) / 2))
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
red, blue = list(map(int, input().split()))
if blue > red:
print(red, int((blue - red) / 2))
else:
print(blue, int((red - blue) / 2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,576,203,531 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 248 | 0 | t = input()
n = 0
for i in range(len(t)):
if t[i].isupper():
n += 1
if n > len(t)-n:
print(t.upper())
else:
print(t.lower()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
t = input()
n = 0
for i in range(len(t)):
if t[i].isupper():
n += 1
if n > len(t)-n:
print(t.upper())
else:
print(t.lower())
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
478 | B | Random Teams | PROGRAMMING | 1,300 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | *n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is to write a program that will find the minimum and the maximum number of pairs of friends that coul... | The only line of input contains two integers *n* and *m*, separated by a single space (1<=≤<=*m*<=≤<=*n*<=≤<=109) — the number of participants and the number of teams respectively. | The only line of the output should contain two integers *k**min* and *k**max* — the minimum possible number of pairs of friends and the maximum possible number of pairs of friends respectively. | [
"5 1\n",
"3 2\n",
"6 3\n"
] | [
"10 10\n",
"1 1\n",
"3 6\n"
] | In the first sample all the participants get into one team, so there will be exactly ten pairs of friends.
In the second sample at any possible arrangement one team will always have two participants and the other team will always have one participant. Thus, the number of pairs of friends will always be equal to one.
... | 1,000 | [
{
"input": "5 1",
"output": "10 10"
},
{
"input": "3 2",
"output": "1 1"
},
{
"input": "6 3",
"output": "3 6"
},
{
"input": "5 3",
"output": "2 3"
},
{
"input": "10 2",
"output": "20 36"
},
{
"input": "10 6",
"output": "4 10"
},
{
"input": ... | 1,648,379,477 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 26 | 61 | 0 | import math
n, m = map(int, input().split())
mn = (n//m-1)*(n//m)//2*m if n % m == 0 else (n//m+1)*(n//m)//2*(n % m)+(n//m)*(n//m-1)//2*(m-n % m)
mx = (n-m+1)*(n-m)//2
print(f'{mn} {mx}')
| Title: Random Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* participants of the competition were split into *m* teams in some manner so that each team has at least one participant. After the competition each pair of participants from the same team became friends.
Your task is ... | ```python
import math
n, m = map(int, input().split())
mn = (n//m-1)*(n//m)//2*m if n % m == 0 else (n//m+1)*(n//m)//2*(n % m)+(n//m)*(n//m-1)//2*(m-n % m)
mx = (n-m+1)*(n-m)//2
print(f'{mn} {mx}')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it la... | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on... | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,681,302,140 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 26 | 62 | 0 | def manage_socks(socks, days):
current_days = 1
socks -= 1
while(socks > 0):
current_days += 1
socks -= 1
if (current_days % days == 0):
socks += 1
print(current_days)
socks = ""
days = ""
input_string = input()
i = 0
while (input_string[i] !=... | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th... | ```python
def manage_socks(socks, days):
current_days = 1
socks -= 1
while(socks > 0):
current_days += 1
socks -= 1
if (current_days % days == 0):
socks += 1
print(current_days)
socks = ""
days = ""
input_string = input()
i = 0
while (input_st... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
749 | A | Bachgold Problem | PROGRAMMING | 800 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
Recall that integer *k* is called prime if it is greater than 1 and has exactly two positive integer ... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=100<=000). | The first line of the output contains a single integer *k* — maximum possible number of primes in representation.
The second line should contain *k* primes with their sum equal to *n*. You can print them in any order. If there are several optimal solution, print any of them. | [
"5\n",
"6\n"
] | [
"2\n2 3\n",
"3\n2 2 2\n"
] | none | 500 | [
{
"input": "5",
"output": "2\n2 3"
},
{
"input": "6",
"output": "3\n2 2 2"
},
{
"input": "2",
"output": "1\n2"
},
{
"input": "3",
"output": "1\n3"
},
{
"input": "99999",
"output": "49999\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,686,135,720 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 0 | 0 | n1 = int(input())
if n1 % 2 == 1:
n1 //= 2
n1 -= 1
print(n1 + 1)
print('3', end=' ')
else:
n1 //= 2
print(n)
for i in range(n1):
print('2', end=' ')
print()
| Title: Bachgold Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bachgold problem is very easy to formulate. Given a positive integer *n* represent it as a sum of maximum possible number of prime numbers. One can prove that such representation exists for any integer greater than 1.
... | ```python
n1 = int(input())
if n1 % 2 == 1:
n1 //= 2
n1 -= 1
print(n1 + 1)
print('3', end=' ')
else:
n1 //= 2
print(n)
for i in range(n1):
print('2', end=' ')
print()
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
877 | A | Alex and broken contest | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest ... | The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem. | Print "YES", if problem is from this contest, and "NO" otherwise. | [
"Alex_and_broken_contest\n",
"NikitaAndString\n",
"Danil_and_Olya\n"
] | [
"NO",
"YES",
"NO"
] | none | 500 | [
{
"input": "Alex_and_broken_contest",
"output": "NO"
},
{
"input": "NikitaAndString",
"output": "YES"
},
{
"input": "Danil_and_Olya",
"output": "NO"
},
{
"input": "Slava____and_the_game",
"output": "YES"
},
{
"input": "Olya_and_energy_drinks",
"output": "YES"
... | 1,603,435,849 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 155 | 819,200 | import sys
import re
name_list = ['Danil', 'Olya', 'Slava', 'Ann', 'Nikita']
for line in sys.stdin:
s = line.strip()
num = 0
for name in name_list:
tmp = re.findall(name, s)
num += len(tmp)
if num == 1:
print('YES')
else:
print('NO')
| Title: Alex and broken contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems,... | ```python
import sys
import re
name_list = ['Danil', 'Olya', 'Slava', 'Ann', 'Nikita']
for line in sys.stdin:
s = line.strip()
num = 0
for name in name_list:
tmp = re.findall(name, s)
num += len(tmp)
if num == 1:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,631,334,420 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 6,758,400 | a = input()
b = sum(map(str.isupper, a))
c = sum(map(str.islower, a))
if b > c:
print(a.upper())
elif b == c:
print(a.lower())
else:
print(a.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
a = input()
b = sum(map(str.isupper, a))
c = sum(map(str.islower, a))
if b > c:
print(a.upper())
elif b == c:
print(a.lower())
else:
print(a.lower())
``` | 3.956411 | MatrixStudio/Codeforces-Python-Submissions |
616 | A | Comparing Two Long Integers | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.
As input/output can r... | The first line contains a non-negative integer *a*.
The second line contains a non-negative integer *b*.
The numbers *a*,<=*b* may contain leading zeroes. Each of them contains no more than 106 digits. | Print the symbol "<" if *a*<=<<=*b* and the symbol ">" if *a*<=><=*b*. If the numbers are equal print the symbol "=". | [
"9\n10\n",
"11\n10\n",
"00012345\n12345\n",
"0123\n9\n",
"0123\n111\n"
] | [
"<\n",
">\n",
"=\n",
">\n",
">\n"
] | none | 0 | [
{
"input": "9\n10",
"output": "<"
},
{
"input": "11\n10",
"output": ">"
},
{
"input": "00012345\n12345",
"output": "="
},
{
"input": "0123\n9",
"output": ">"
},
{
"input": "0123\n111",
"output": ">"
},
{
"input": "9\n9",
"output": "="
},
{
... | 1,650,789,262 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 2,000 | 2,252,800 | import sys
input = sys.stdin.readline
a = int(input())
b = int(input())
print('<>='[(a==b)+(a>=b)]) | Title: Comparing Two Long Integers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two very long integers *a*,<=*b* (leading zeroes are allowed). You should check what number *a* or *b* is greater or determine that they are equal.
The input size is very large so don't use th... | ```python
import sys
input = sys.stdin.readline
a = int(input())
b = int(input())
print('<>='[(a==b)+(a>=b)])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
376 | B | I.O.U. | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearrange them like that: assume that A owes C 20 rubles and B doesn't owe anything to anybody. The... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 0<=≤<=*m*<=≤<=104). The next *m* lines contain the debts. The *i*-th line contains three integers *a**i*,<=*b**i*,<=*c**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; *a**i*<=≠<=*b**i*; 1<=≤<=*c**i*<=≤<=100), which mean that person *a**i* owes person *b**i* *c**i... | Print a single integer — the minimum sum of debts in the optimal rearrangement. | [
"5 3\n1 2 10\n2 3 1\n2 4 1\n",
"3 0\n",
"4 3\n1 2 1\n2 3 1\n3 1 1\n"
] | [
"10\n",
"0\n",
"0\n"
] | In the first sample, you can assume that person number 1 owes 8 rubles to person number 2, 1 ruble to person number 3 and 1 ruble to person number 4. He doesn't owe anybody else anything. In the end, the total debt equals 10.
In the second sample, there are no debts.
In the third sample, you can annul all the debts. | 1,000 | [
{
"input": "5 3\n1 2 10\n2 3 1\n2 4 1",
"output": "10"
},
{
"input": "3 0",
"output": "0"
},
{
"input": "4 3\n1 2 1\n2 3 1\n3 1 1",
"output": "0"
},
{
"input": "20 28\n1 5 6\n1 12 7\n1 13 4\n1 15 7\n1 20 3\n2 4 1\n2 15 6\n3 5 3\n3 8 10\n3 13 8\n3 20 6\n4 6 10\n4 12 8\n4 19 5\... | 1,516,723,599 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 62 | 5,632,000 | n, m = map(int, input().split(' '))
have = (n + 1) * [0]
for _ in range(m):
person_1, person_2, owns_ = map(int, input().split(' '))
have[person_1] += owns_
have[person_2] -= owns_
print(sum(i for i in have if i > 0))
| Title: I.O.U.
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearran... | ```python
n, m = map(int, input().split(' '))
have = (n + 1) * [0]
for _ in range(m):
person_1, person_2, owns_ = map(int, input().split(' '))
have[person_1] += owns_
have[person_2] -= owns_
print(sum(i for i in have if i > 0))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,668,940,314 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | a, b = [int(x) for x in input().split(":")]
if int(str(a)[::-1]) <= b:
a += 1
b = int(str(a)[::-1])
if a == 24:
a = b = "00"
else:
b = str(a)[::-1]
print(str(a)+":"+str(b))
| Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
a, b = [int(x) for x in input().split(":")]
if int(str(a)[::-1]) <= b:
a += 1
b = int(str(a)[::-1])
if a == 24:
a = b = "00"
else:
b = str(a)[::-1]
print(str(a)+":"+str(b))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,540,458,364 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 0 | string=input()
word=['h','e','l','l','o']
flag=[0]*5
index=0
for i in range(5):
flag[i]=string.find(word[i],index)
if flag[i]==-1:
print('NO')
break
index=flag[i]+1
if flag[4]!=-1 and flag[4]!=0:
print('YES') | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
string=input()
word=['h','e','l','l','o']
flag=[0]*5
index=0
for i in range(5):
flag[i]=string.find(word[i],index)
if flag[i]==-1:
print('NO')
break
index=flag[i]+1
if flag[4]!=-1 and flag[4]!=0:
print('YES')
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
459 | A | Pashmak and Garden | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Pashmak has fallen in love with an attractive girl called Parmida since one year ago...
Today, Pashmak set up a meeting with his partner in a romantic garden. Unfortunately, Pashmak has forgotten where the garden is. But he remembers that the garden looks like a square with sides parallel to the coordinate axes. He al... | The first line contains four space-separated *x*1,<=*y*1,<=*x*2,<=*y*2 (<=-<=100<=≤<=*x*1,<=*y*1,<=*x*2,<=*y*2<=≤<=100) integers, where *x*1 and *y*1 are coordinates of the first tree and *x*2 and *y*2 are coordinates of the second tree. It's guaranteed that the given points are distinct. | If there is no solution to the problem, print -1. Otherwise print four space-separated integers *x*3,<=*y*3,<=*x*4,<=*y*4 that correspond to the coordinates of the two other trees. If there are several solutions you can output any of them.
Note that *x*3,<=*y*3,<=*x*4,<=*y*4 must be in the range (<=-<=1000<=≤<=*x*3,<... | [
"0 0 0 1\n",
"0 0 1 1\n",
"0 0 1 2\n"
] | [
"1 0 1 1\n",
"0 1 1 0\n",
"-1\n"
] | none | 500 | [
{
"input": "0 0 0 1",
"output": "1 0 1 1"
},
{
"input": "0 0 1 1",
"output": "0 1 1 0"
},
{
"input": "0 0 1 2",
"output": "-1"
},
{
"input": "-100 -100 100 100",
"output": "-100 100 100 -100"
},
{
"input": "-100 -100 99 100",
"output": "-1"
},
{
"input... | 1,699,931,552 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 31 | 102,400 | def Print(c1, c2):
final = ""
for i in c1:
final += f"{str(i)} "
for i in c2:
final += f"{str(i)} "
final = final.lstrip()
print(final)
arr = list(map(int, input().split()))
corners = [[arr[0], arr[1]], [arr[2], arr[3]], [0, 0], [0, 0]]
corner1 = corners[0]
corner2 = Non... | Title: Pashmak and Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak has fallen in love with an attractive girl called Parmida since one year ago...
Today, Pashmak set up a meeting with his partner in a romantic garden. Unfortunately, Pashmak has forgotten where the garden is... | ```python
def Print(c1, c2):
final = ""
for i in c1:
final += f"{str(i)} "
for i in c2:
final += f"{str(i)} "
final = final.lstrip()
print(final)
arr = list(map(int, input().split()))
corners = [[arr[0], arr[1]], [arr[2], arr[3]], [0, 0], [0, 0]]
corner1 = corners[0]
cor... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,655,966,554 | 2,147,483,647 | PyPy 3 | OK | TESTS | 21 | 78 | 1,228,800 | t = int(input())
for _ in range(t):
n = int(input())
summ = (n * (n + 1)) // 2
pow2 = 1
while pow2 <= n:
summ -= pow2 * 2
pow2 *= 2
print(summ) | Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, be... | ```python
t = int(input())
for _ in range(t):
n = int(input())
summ = (n * (n + 1)) // 2
pow2 = 1
while pow2 <= n:
summ -= pow2 * 2
pow2 *= 2
print(summ)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,539,256,915 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 218 | 0 | text1=input()
text2=input()
l=text2[::-1]
if l==text1:
print('YES')
else:
print('NO')
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
text1=input()
text2=input()
l=text2[::-1]
if l==text1:
print('YES')
else:
print('NO')
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,696,339,540 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 62 | 0 | def prime(n):
for i in range(2, n):
if n % i == 0:
return False
else:
return True
n = int(input())
for x in range(4, n):
if not prime(x):
y = n - x
if not prime(y):
print(x, y)
break | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
def prime(n):
for i in range(2, n):
if n % i == 0:
return False
else:
return True
n = int(input())
for x in range(4, n):
if not prime(x):
y = n - x
if not prime(y):
print(x, y)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,658,767,807 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 204,800 |
y=input().split(' ')
a1=y[0]
a2=y[1]
a3=y[2]
a4=y[3]
x=input()
x1=x.count('1')
x2=x.count('2')
x3=x.count('3')
x4=x.count('4')
p1=int(a1)*int(x1)
p2=int(a2)*int(x2)
p3=int(a3)*int(x3)
p4=int(a4)*int(x4)
print(p1+p2+p3+p4)
| Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
y=input().split(' ')
a1=y[0]
a2=y[1]
a3=y[2]
a4=y[3]
x=input()
x1=x.count('1')
x2=x.count('2')
x3=x.count('3')
x4=x.count('4')
p1=int(a1)*int(x1)
p2=int(a2)*int(x2)
p3=int(a3)*int(x3)
p4=int(a4)*int(x4)
print(p1+p2+p3+p4)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Gennady is one of the best child dentists in Berland. Today *n* children got an appointment with him, they lined up in front of his office.
All children love to cry loudly at the reception at the dentist. We enumerate the children with integers from 1 to *n* in the order they go in the line. Every child is associated ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=4000) — the number of kids in the line.
Next *n* lines contain three integers each *v**i*,<=*d**i*,<=*p**i* (1<=≤<=*v**i*,<=*d**i*,<=*p**i*<=≤<=106) — the volume of the cry in the doctor's office, the volume of the cry in the hall and the conf... | In the first line print number *k* — the number of children whose teeth Gennady will cure.
In the second line print *k* integers — the numbers of the children who will make it to the end of the line in the increasing order. | [
"5\n4 2 2\n4 1 2\n5 2 4\n3 3 5\n5 1 2\n",
"5\n4 5 1\n5 3 9\n4 1 2\n2 1 8\n4 1 9\n"
] | [
"2\n1 3 ",
"4\n1 2 4 5 "
] | In the first example, Gennady first treats the teeth of the first child who will cry with volume 4. The confidences of the remaining children will get equal to - 2, 1, 3, 1, respectively. Thus, the second child also cries at the volume of 1 and run to the exit. The confidence of the remaining children will be equal to... | 0 | [
{
"input": "5\n4 2 2\n4 1 2\n5 2 4\n3 3 5\n5 1 2",
"output": "2\n1 3 "
},
{
"input": "5\n4 5 1\n5 3 9\n4 1 2\n2 1 8\n4 1 9",
"output": "4\n1 2 4 5 "
},
{
"input": "10\n10 7 10\n3 6 11\n8 4 10\n10 1 11\n7 3 13\n7 2 13\n7 6 14\n3 4 17\n9 4 20\n5 2 24",
"output": "3\n1 2 5 "
},
{
... | 1,444,752,565 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 61 | 0 | n = int(input())
v = [0] * n
d = [0] * n
p = [0] * n
ds = 0
goods = []
for i in range(n):
v[i], d[i], p[i] = tuple(map(int, input().split()))
p[i] = p[i] - ds
for j in range(i):
p[i] = p[i] - v[j] + i - j - 1 if (v[j] + j - i + 1 > 0) else p[i]
if p[i] < 0:
ds += d[i]
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gennady is one of the best child dentists in Berland. Today *n* children got an appointment with him, they lined up in front of his office.
All children love to cry loudly at the reception at the dentist. We enumerate the childre... | ```python
n = int(input())
v = [0] * n
d = [0] * n
p = [0] * n
ds = 0
goods = []
for i in range(n):
v[i], d[i], p[i] = tuple(map(int, input().split()))
p[i] = p[i] - ds
for j in range(i):
p[i] = p[i] - v[j] + i - j - 1 if (v[j] + j - i + 1 > 0) else p[i]
if p[i] < 0:
ds += d[... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
690 | C2 | Brain Network (medium) | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | Further research on zombie thought processes yielded interesting results. As we know from the previous problem, the nervous system of a zombie consists of *n* brains and *m* brain connectors joining some pairs of brains together. It was observed that the intellectual abilities of a zombie depend mainly on the topology ... | The first line of the input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100000) denoting the number of brains (which are conveniently numbered from 1 to *n*) and the number of brain connectors in the nervous system, respectively. In the next *m* lines, descriptions of brain connectors follow.... | Print one number – the brain latency. | [
"4 3\n1 2\n1 3\n1 4\n",
"5 4\n1 2\n2 3\n3 4\n3 5\n"
] | [
"2",
"3"
] | none | 0 | [
{
"input": "2 1\n1 2",
"output": "1"
},
{
"input": "3 2\n2 1\n3 2",
"output": "2"
},
{
"input": "10 9\n5 1\n1 2\n9 3\n10 5\n6 3\n8 5\n2 7\n2 3\n9 4",
"output": "6"
},
{
"input": "4 3\n1 2\n1 3\n1 4",
"output": "2"
},
{
"input": "5 4\n1 2\n2 3\n3 4\n3 5",
"outp... | 1,668,921,425 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 19 | 888 | 49,254,400 | from collections import defaultdict, deque
def get_distances(root: int, connectors: dict[int, list[int]]) -> list[tuple[int, int]]:
visited = set([root])
g = set([root])
i = 1
distances = []
while True:
g = {k for j in g for k in connectors[j] if k not in visited}
if not g:
... | Title: Brain Network (medium)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Further research on zombie thought processes yielded interesting results. As we know from the previous problem, the nervous system of a zombie consists of *n* brains and *m* brain connectors joining some pairs of... | ```python
from collections import defaultdict, deque
def get_distances(root: int, connectors: dict[int, list[int]]) -> list[tuple[int, int]]:
visited = set([root])
g = set([root])
i = 1
distances = []
while True:
g = {k for j in g for k in connectors[j] if k not in visited}
if ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
913 | D | Too Easy Problems | PROGRAMMING | 1,800 | [
"binary search",
"brute force",
"data structures",
"greedy",
"sortings"
] | null | null | You are preparing for an exam on scheduling theory. The exam will last for exactly *T* milliseconds and will consist of *n* problems. You can either solve problem *i* in exactly *t**i* milliseconds or ignore it and spend no time. You don't need time to rest after solving a problem, either.
Unfortunately, your teacher ... | The first line contains two integers *n* and *T* (1<=≤<=*n*<=≤<=2·105; 1<=≤<=*T*<=≤<=109) — the number of problems in the exam and the length of the exam in milliseconds, respectively.
Each of the next *n* lines contains two integers *a**i* and *t**i* (1<=≤<=*a**i*<=≤<=*n*; 1<=≤<=*t**i*<=≤<=104). The problems are numb... | In the first line, output a single integer *s* — your maximum possible final score.
In the second line, output a single integer *k* (0<=≤<=*k*<=≤<=*n*) — the number of problems you should solve.
In the third line, output *k* distinct integers *p*1,<=*p*2,<=...,<=*p**k* (1<=≤<=*p**i*<=≤<=*n*) — the indexes of problems... | [
"5 300\n3 100\n4 150\n4 80\n2 90\n2 300\n",
"2 100\n1 787\n2 788\n",
"2 100\n2 42\n2 58\n"
] | [
"2\n3\n3 1 4\n",
"0\n0\n\n",
"2\n2\n1 2\n"
] | In the first example, you should solve problems 3, 1, and 4. In this case you'll spend 80 + 100 + 90 = 270 milliseconds, falling within the length of the exam, 300 milliseconds (and even leaving yourself 30 milliseconds to have a rest). Problems 3 and 1 will bring you a point each, while problem 4 won't. You'll score t... | 1,250 | [
{
"input": "5 300\n3 100\n4 150\n4 80\n2 90\n2 300",
"output": "2\n2\n3 4"
},
{
"input": "2 100\n1 787\n2 788",
"output": "0\n0"
},
{
"input": "2 100\n2 42\n2 58",
"output": "2\n2\n1 2"
},
{
"input": "1 1\n1 1",
"output": "1\n1\n1"
},
{
"input": "10 481\n4 25\n3 8... | 1,648,834,392 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 0 | n=int(input())
m=int(input())
n2=1
for i in range(n):
if n2*2<=m:
n2 = n2 * 2
else:
n2 = n2 * 2
break
print(m%n2)
| Title: Too Easy Problems
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are preparing for an exam on scheduling theory. The exam will last for exactly *T* milliseconds and will consist of *n* problems. You can either solve problem *i* in exactly *t**i* milliseconds or ignore it and sp... | ```python
n=int(input())
m=int(input())
n2=1
for i in range(n):
if n2*2<=m:
n2 = n2 * 2
else:
n2 = n2 * 2
break
print(m%n2)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,532,059,394 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 810 | 3,891,200 | n = int(input())
left = [0] * n
right = [0] * n
for i in range(n):
left[i], right[i] = map(int, input().split())
minLeft = min(left)
maxRight = max(right)
ans = -1
for i in range(n):
if left[i] == minLeft and right[i] == maxRight:
ans = i + 1
break
print(ans)
| Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
n = int(input())
left = [0] * n
right = [0] * n
for i in range(n):
left[i], right[i] = map(int, input().split())
minLeft = min(left)
maxRight = max(right)
ans = -1
for i in range(n):
if left[i] == minLeft and right[i] == maxRight:
ans = i + 1
break
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions |
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