contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
887 | A | Div. 64 | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisi... | In the only line given a non-empty binary string *s* with length up to 100. | Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise. | [
"100010001\n",
"100\n"
] | [
"yes",
"no"
] | In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.
You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system) | 500 | [
{
"input": "100010001",
"output": "yes"
},
{
"input": "100",
"output": "no"
},
{
"input": "0000001000000",
"output": "yes"
},
{
"input": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111",
"output": "no"
},
{
"in... | 1,510,073,634 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 62 | 0 | n = input()
k = 0
kek = False
for i in range(len(n)):
if n[i] == "0":
k += 1
if n[i] == "1" and k >= 6:
kek = True
if kek == True:
print("yes")
else:
print("no")
| Title: Div. 64
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some dig... | ```python
n = input()
k = 0
kek = False
for i in range(len(n)):
if n[i] == "0":
k += 1
if n[i] == "1" and k >= 6:
kek = True
if kek == True:
print("yes")
else:
print("no")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
631 | C | Report | PROGRAMMING | 1,700 | [
"data structures",
"sortings"
] | null | null | Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that denotes corresponding revenue. Before the report gets to Blake, it passes through the hands... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the number of commodities in the report and the number of managers, respectively.
The second line contains *n* integers *a**i* (|*a**i*|<=≤<=109) — the initial report before it gets to the first manager.
Then follow *m* lin... | Print *n* integers — the final report, which will be passed to Blake by manager number *m*. | [
"3 1\n1 2 3\n2 2\n",
"4 2\n1 2 4 3\n2 3\n1 2\n"
] | [
"2 1 3 ",
"2 4 1 3 "
] | In the first sample, the initial report looked like: 1 2 3. After the first manager the first two numbers were transposed: 2 1 3. The report got to Blake in this form.
In the second sample the original report was like this: 1 2 4 3. After the first manager the report changed to: 4 2 1 3. After the second manager the r... | 1,500 | [
{
"input": "3 1\n1 2 3\n2 2",
"output": "2 1 3 "
},
{
"input": "4 2\n1 2 4 3\n2 3\n1 2",
"output": "2 4 1 3 "
},
{
"input": "4 1\n4 3 2 1\n1 4",
"output": "1 2 3 4 "
},
{
"input": "5 1\n1 2 3 4 5\n2 5",
"output": "5 4 3 2 1 "
},
{
"input": "6 2\n3 1 2 6 4 5\n1 6\n... | 1,459,868,122 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 1,294 | 37,478,400 | n,m=[int(i) for i in input().split()]
a=[int(i) for i in input().split()]
l=[]
for i in range(m):
t,r=[int(i) for i in input().split()]
while len(l)>0 and r>=l[-1][1]:
l.pop()
l.append([t,r])
x,y=0,l[0][1]-1
l.append([0,0])
b=sorted(a[:y+1])
for i in range(1,len(l)):
for j in... | Title: Report
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each month Blake gets the report containing main economic indicators of the company "Blake Technologies". There are *n* commodities produced by the company. For each of them there is exactly one integer in the final report, that... | ```python
n,m=[int(i) for i in input().split()]
a=[int(i) for i in input().split()]
l=[]
for i in range(m):
t,r=[int(i) for i in input().split()]
while len(l)>0 and r>=l[-1][1]:
l.pop()
l.append([t,r])
x,y=0,l[0][1]-1
l.append([0,0])
b=sorted(a[:y+1])
for i in range(1,len(l)):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,566,216,301 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 420 | 5,529,600 | # import sys
# sys.stdin=open("input.in","r")
# sys.stdout=open("output.out","w")
n=int(input())
l=[['.' for i in range(n)]for j in range(n)]
c=0
for i in range(n):
for j in range(n):
if i%2==0:
if j%2==0:
l[i][j]='C'
c+=1
else:
if j%2!=0:
l[i][j]='C'
c+=1
print(c)
for i... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
# import sys
# sys.stdin=open("input.in","r")
# sys.stdout=open("output.out","w")
n=int(input())
l=[['.' for i in range(n)]for j in range(n)]
c=0
for i in range(n):
for j in range(n):
if i%2==0:
if j%2==0:
l[i][j]='C'
c+=1
else:
if j%2!=0:
l[i][j]='C'
c+=1
print... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
333 | A | Secrets | PROGRAMMING | 1,600 | [
"greedy"
] | null | null | Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations that are powers of three: 1 mark, 3 marks, 9 marks, 27 marks and so on. There are no coins of o... | The single line contains a single integer *n* (1<=≤<=*n*<=≤<=1017).
Please, do not use the %lld specifier to read or write 64 bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | In a single line print an integer: the maximum number of coins the unlucky buyer could have paid with. | [
"1\n",
"4\n"
] | [
"1\n",
"2\n"
] | In the first test case, if a buyer has exactly one coin of at least 3 marks, then, to give Gerald one mark, he will have to give this coin. In this sample, the customer can not have a coin of one mark, as in this case, he will be able to give the money to Gerald without any change.
In the second test case, if the buye... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "3",
"output": "1"
},
{
"input": "8",
"output": "3"
},
{
"input": "10",
"output": "4"
},
{
"input": "100000000000000000",
"output": "33333333333333334"
},
{
"input... | 1,381,923,506 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 124 | 204,800 | n=int(input())
r=3
while(1):
if(n%r):
print((n-1)//r+1)
break
else:
r*=3
| Title: Secrets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has been selling state secrets at leisure. All the secrets cost the same: *n* marks. The state which secrets Gerald is selling, has no paper money, only coins. But there are coins of all positive integer denominations th... | ```python
n=int(input())
r=3
while(1):
if(n%r):
print((n-1)//r+1)
break
else:
r*=3
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
132 | D | Constants in the language of Shakespeare | PROGRAMMING | 2,100 | [
"constructive algorithms",
"dp",
"greedy"
] | null | null | Shakespeare is a widely known esoteric programming language in which programs look like plays by Shakespeare, and numbers are given by combinations of ornate epithets. In this problem we will have a closer look at the way the numbers are described in Shakespeare.
Each constant in Shakespeare is created from non-negati... | The only line of input contains a positive integer *n*, written as its binary notation. The length of the notation is at most 106. The first digit of the notation is guaranteed to be 1. | Output the required minimal *m*. After it output *m* lines. Each line has to be formatted as "+2^x" or "-2^x", where *x* is the power coefficient of the corresponding term. The order of the lines doesn't matter. | [
"1111\n",
"1010011\n"
] | [
"2\n+2^4\n-2^0\n",
"4\n+2^0\n+2^1\n+2^4\n+2^6\n"
] | none | 2,000 | [
{
"input": "1111",
"output": "2\n+2^4\n-2^0"
},
{
"input": "1010011",
"output": "4\n+2^0\n+2^1\n+2^4\n+2^6"
},
{
"input": "1",
"output": "1\n+2^0"
},
{
"input": "10110111",
"output": "4\n+2^8\n-2^6\n-2^3\n-2^0"
},
{
"input": "10101110",
"output": "4\n+2^8\n-2^... | 1,691,845,103 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1691845103.002785")# 1691845103.0027995 | Title: Constants in the language of Shakespeare
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Shakespeare is a widely known esoteric programming language in which programs look like plays by Shakespeare, and numbers are given by combinations of ornate epithets. In this problem we will ha... | ```python
print("_RANDOM_GUESS_1691845103.002785")# 1691845103.0027995
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,593,269,577 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 184 | 6,963,200 | n=int(input())
l1=list()
l2=list()
l=list()
for i in range(n):
a,b=map(int,input().split())
l1.append(a)
l2.append(b)
for i in range(n):
if l2[i] in l1[0:i] or l2[i] in l1[i+1:]:
l.append(l2[i])
print(n-len(set(l))) | Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th... | ```python
n=int(input())
l1=list()
l2=list()
l=list()
for i in range(n):
a,b=map(int,input().split())
l1.append(a)
l2.append(b)
for i in range(n):
if l2[i] in l1[0:i] or l2[i] in l1[i+1:]:
l.append(l2[i])
print(n-len(set(l)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
922 | A | Cloning Toys | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applies the machine to a copied toy, he gets two additional copies.
Initially, Imp has only one origina... | The only line contains two integers *x* and *y* (0<=≤<=*x*,<=*y*<=≤<=109) — the number of copies and the number of original toys Imp wants to get (including the initial one). | Print "Yes", if the desired configuration is possible, and "No" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"6 3\n",
"4 2\n",
"1000 1001\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first example, Imp has to apply the machine twice to original toys and then twice to copies. | 500 | [
{
"input": "6 3",
"output": "Yes"
},
{
"input": "4 2",
"output": "No"
},
{
"input": "1000 1001",
"output": "Yes"
},
{
"input": "1000000000 999999999",
"output": "Yes"
},
{
"input": "81452244 81452247",
"output": "No"
},
{
"input": "188032448 86524683",... | 1,591,947,960 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 124 | 0 | x, y = map(int,input().split(" "))
originial_req = y-1
copies_req = x - y + 1
originial_req = 0
ans = "No"
if(copies_req==0):
ans = "Yes"
elif(copies_req<0):
ans = "No"
else:
if(copies_req%2==0):
ans = "Yes"
print(ans)
| Title: Cloning Toys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imp likes his plush toy a lot.
Recently, he found a machine that can clone plush toys. Imp knows that if he applies the machine to an original toy, he additionally gets one more original toy and one copy, and if he applie... | ```python
x, y = map(int,input().split(" "))
originial_req = y-1
copies_req = x - y + 1
originial_req = 0
ans = "No"
if(copies_req==0):
ans = "Yes"
elif(copies_req<0):
ans = "No"
else:
if(copies_req%2==0):
ans = "Yes"
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
868 | B | Race Against Time | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | Have you ever tried to explain to the coordinator, why it is eight hours to the contest and not a single problem has been prepared yet? Misha had. And this time he has a really strong excuse: he faced a space-time paradox! Space and time replaced each other.
The entire universe turned into an enormous clock face with ... | Five integers *h*, *m*, *s*, *t*1, *t*2 (1<=≤<=*h*<=≤<=12, 0<=≤<=*m*,<=*s*<=≤<=59, 1<=≤<=*t*1,<=*t*2<=≤<=12, *t*1<=≠<=*t*2).
Misha's position and the target time do not coincide with the position of any hand. | Print "YES" (quotes for clarity), if Misha can prepare the contest on time, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"12 30 45 3 11\n",
"12 0 1 12 1\n",
"3 47 0 4 9\n"
] | [
"NO\n",
"YES\n",
"YES\n"
] | The three examples are shown on the pictures below from left to right. The starting position of Misha is shown with green, the ending position is shown with pink. Note that the positions of the hands on the pictures are not exact, but are close to the exact and the answer is the same. | 500 | [
{
"input": "12 30 45 3 11",
"output": "NO"
},
{
"input": "12 0 1 12 1",
"output": "YES"
},
{
"input": "3 47 0 4 9",
"output": "YES"
},
{
"input": "10 22 59 6 10",
"output": "YES"
},
{
"input": "3 1 13 12 3",
"output": "NO"
},
{
"input": "11 19 28 9 10"... | 1,690,654,155 | 2,147,483,647 | Python 3 | OK | TESTS | 133 | 46 | 0 | [h,m,s,t1,t2] = [int(x) for x in input().split()]
hh = h + m/60 + s/3600
mm = m/5
ss = s/5
ll = [hh,mm,ss,t1,t2]
ll = sorted(ll)
diff = abs(ll.index(t1)-ll.index(t2))
if diff==1 or diff==4:
print('YES')
else:
print('NO')
| Title: Race Against Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Have you ever tried to explain to the coordinator, why it is eight hours to the contest and not a single problem has been prepared yet? Misha had. And this time he has a really strong excuse: he faced a space-time par... | ```python
[h,m,s,t1,t2] = [int(x) for x in input().split()]
hh = h + m/60 + s/3600
mm = m/5
ss = s/5
ll = [hh,mm,ss,t1,t2]
ll = sorted(ll)
diff = abs(ll.index(t1)-ll.index(t2))
if diff==1 or diff==4:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
55 | C | Pie or die | PROGRAMMING | 1,900 | [
"games"
] | C. Pie or die | 2 | 256 | Volodya and Vlad play the following game. There are *k* pies at the cells of *n*<=<=×<=<=*m* board. Each turn Volodya moves one pie to the neighbouring (by side) cell. If the pie lies at the border of the board then Volodya can move it outside the board, get the pie and win. After Volodya's move, Vlad bans some edge at... | First line contains 3 integers, separated by space: 1<=≤<=*n*,<=*m*<=≤<=100 — dimensions of the board and 0<=≤<=*k*<=≤<=100 — the number of pies. Each of the next *k* lines contains 2 integers, separated by space: 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* — coordinates of the corresponding pie. There could be more than one ... | Output only one word: "YES" — if Volodya wins, "NO" — otherwise. | [
"2 2 1\n1 2\n",
"3 4 0\n",
"100 50 2\n50 25\n50 25\n"
] | [
"YES",
"NO",
"NO"
] | none | 1,500 | [
{
"input": "2 2 1\n1 2",
"output": "YES"
},
{
"input": "3 4 0",
"output": "NO"
},
{
"input": "100 50 2\n50 25\n50 25",
"output": "NO"
},
{
"input": "20 20 4\n10 10\n10 10\n10 10\n10 10",
"output": "NO"
},
{
"input": "15 15 1\n8 8",
"output": "NO"
},
{
... | 1,389,034,106 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 92 | 307,200 | n, m, k = map(int, input().split())
win = False
for i in range(k):
row, col = map(int, input().split())
d = max(row - 1, n - row, col - 1, m - col)
if d <= 4:
win = True
if win:
print("YES")
else:
print("NO") | Title: Pie or die
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Volodya and Vlad play the following game. There are *k* pies at the cells of *n*<=<=×<=<=*m* board. Each turn Volodya moves one pie to the neighbouring (by side) cell. If the pie lies at the border of the board then Volodya can ... | ```python
n, m, k = map(int, input().split())
win = False
for i in range(k):
row, col = map(int, input().split())
d = max(row - 1, n - row, col - 1, m - col)
if d <= 4:
win = True
if win:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
960 | B | Minimize the error | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one operation, you have to choose one element of the array and increase or decrease it by 1.
Output the min... | The first line contains three space-separated integers *n* (1<=≤<=*n*<=≤<=103), *k*1 and *k*2 (0<=≤<=*k*1<=+<=*k*2<=≤<=103, *k*1 and *k*2 are non-negative) — size of arrays and number of operations to perform on *A* and *B* respectively.
Second line contains *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (<=-... | Output a single integer — the minimum possible value of after doing exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. | [
"2 0 0\n1 2\n2 3\n",
"2 1 0\n1 2\n2 2\n",
"2 5 7\n3 4\n14 4\n"
] | [
"2",
"0",
"1"
] | In the first sample case, we cannot perform any operations on *A* or *B*. Therefore the minimum possible error *E* = (1 - 2)<sup class="upper-index">2</sup> + (2 - 3)<sup class="upper-index">2</sup> = 2.
In the second sample case, we are required to perform exactly one operation on *A*. In order to minimize error, we... | 1,000 | [
{
"input": "2 0 0\n1 2\n2 3",
"output": "2"
},
{
"input": "2 1 0\n1 2\n2 2",
"output": "0"
},
{
"input": "2 5 7\n3 4\n14 4",
"output": "1"
},
{
"input": "2 0 1\n1 2\n2 2",
"output": "0"
},
{
"input": "2 1 1\n0 0\n1 1",
"output": "0"
},
{
"input": "5 5 ... | 1,677,163,140 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | def rl():
return list(map(int,input().split()))
def ri():
return int(input())
def rs():
return input()
def rm():
return map(int,input().split())
def main():
n,p,q=rm()
k=p+q
a=rl()
b=rl()
c=[0]+[a[i]-b[i] for i in range(n)]
c.sort()
rs=0
d=[0 for i in ra... | Title: Minimize the error
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one ... | ```python
def rl():
return list(map(int,input().split()))
def ri():
return int(input())
def rs():
return input()
def rm():
return map(int,input().split())
def main():
n,p,q=rm()
k=p+q
a=rl()
b=rl()
c=[0]+[a[i]-b[i] for i in range(n)]
c.sort()
rs=0
d=[0 f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
946 | B | Weird Subtraction Process | PROGRAMMING | 1,100 | [
"math",
"number theory"
] | null | null | You have two variables *a* and *b*. Consider the following sequence of actions performed with these variables:
1. If *a*<==<=0 or *b*<==<=0, end the process. Otherwise, go to step 2;1. If *a*<=≥<=2·*b*, then set the value of *a* to *a*<=-<=2·*b*, and repeat step 1. Otherwise, go to step 3;1. If *b*<=≥<=2·*a*, then s... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1018). *n* is the initial value of variable *a*, and *m* is the initial value of variable *b*. | Print two integers — the values of *a* and *b* after the end of the process. | [
"12 5\n",
"31 12\n"
] | [
"0 1\n",
"7 12\n"
] | Explanations to the samples:
1. *a* = 12, *b* = 5 <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> *a* = 2, *b* = 5 <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0... | 0 | [
{
"input": "12 5",
"output": "0 1"
},
{
"input": "31 12",
"output": "7 12"
},
{
"input": "1000000000000000000 7",
"output": "8 7"
},
{
"input": "31960284556200 8515664064180",
"output": "14928956427840 8515664064180"
},
{
"input": "1000000000000000000 100000000000... | 1,679,043,814 | 2,147,483,647 | PyPy 3 | OK | TESTS | 81 | 77 | 0 | a,b=map(int,input().split())
for _ in[0]*36:
if b:a%=2*b
if a:b%=2*a
print(a,b) | Title: Weird Subtraction Process
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have two variables *a* and *b*. Consider the following sequence of actions performed with these variables:
1. If *a*<==<=0 or *b*<==<=0, end the process. Otherwise, go to step 2;1. If *a*<=≥<=2·*b*, then... | ```python
a,b=map(int,input().split())
for _ in[0]*36:
if b:a%=2*b
if a:b%=2*a
print(a,b)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,690,046,879 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 8 | 186 | 0 | n=int(input())
d={}
p=0
w=""
for i in range(n):
s1,s2=map(str,input().split())
d[s1]=d.get(s1,0)+int(s2)
if d[s1]>p:
w=s1
p=d[s1]
m=max(d.values())
if m==p:
print(w)
else:
for i in d.keys():
if m==d[i]:
w=i
break
print(w)
| Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n=int(input())
d={}
p=0
w=""
for i in range(n):
s1,s2=map(str,input().split())
d[s1]=d.get(s1,0)+int(s2)
if d[s1]>p:
w=s1
p=d[s1]
m=max(d.values())
if m==p:
print(w)
else:
for i in d.keys():
if m==d[i]:
w=i
break
print(w... | 0 | MatrixStudio/Codeforces-Python-Submissions |
108 | A | Palindromic Times | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | A. Palindromic Times | 2 | 256 | Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling asleep, he was staring at the digital watch around Saher's wrist. He noticed that the digits on th... | The first and only line of the input starts with a string with the format "HH:MM" where "HH" is from "00" to "23" and "MM" is from "00" to "59". Both "HH" and "MM" have exactly two digits. | Print the palindromic time of day that comes soonest after the time given in the input. If the input time is palindromic, output the soonest palindromic time after the input time. | [
"12:21\n",
"23:59\n"
] | [
"13:31\n",
"00:00\n"
] | none | 500 | [
{
"input": "12:21",
"output": "13:31"
},
{
"input": "23:59",
"output": "00:00"
},
{
"input": "15:51",
"output": "20:02"
},
{
"input": "10:44",
"output": "11:11"
},
{
"input": "04:02",
"output": "04:40"
},
{
"input": "02:11",
"output": "02:20"
},
... | 1,613,931,557 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 154 | 307,200 | inp = input().split(':')
hh_str = inp[0]
mm_str = inp[1]
h_int = int(hh_str)
m_int = int(mm_str)
h_int = h_int + 1
lista_numeri_singoli = [0,1,2,3,4,5,6,7,8,9]
if h_int == 24:
h_int = 0
if h_int in lista_numeri_singoli:
h_str = '0' + str(h_int)
else:
h_str = str(h_int)
m_... | Title: Palindromic Times
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Tattah is asleep if and only if Tattah is attending a lecture. This is a well-known formula among Tattah's colleagues.
On a Wednesday afternoon, Tattah was attending Professor HH's lecture. At 12:21, right before falling... | ```python
inp = input().split(':')
hh_str = inp[0]
mm_str = inp[1]
h_int = int(hh_str)
m_int = int(mm_str)
h_int = h_int + 1
lista_numeri_singoli = [0,1,2,3,4,5,6,7,8,9]
if h_int == 24:
h_int = 0
if h_int in lista_numeri_singoli:
h_str = '0' + str(h_int)
else:
h_str = str(h_int)... | 0 | MatrixStudio/Codeforces-Python-Submissions |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,647,114,968 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | t = int(input())
for _ in range(t):
n = int(input())
s1 = (1+n)*n/2
d1 = 2
d2 = 1
k = 1
while d2 <= n:
d2 *= d1
k += 1
s2 = (d2 - 1)
print(s1-2*s2)
| Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, be... | ```python
t = int(input())
for _ in range(t):
n = int(input())
s1 = (1+n)*n/2
d1 = 2
d2 = 1
k = 1
while d2 <= n:
d2 *= d1
k += 1
s2 = (d2 - 1)
print(s1-2*s2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
535 | B | Tavas and SaDDas | PROGRAMMING | 1,100 | [
"bitmasks",
"brute force",
"combinatorics",
"implementation"
] | null | null | Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphones and told him: "If you solve the following problem, I'll return it to you."
The problem is:
You ar... | The first and only line of input contains a lucky number *n* (1<=≤<=*n*<=≤<=109). | Print the index of *n* among all lucky numbers. | [
"4\n",
"7\n",
"77\n"
] | [
"1\n",
"2\n",
"6\n"
] | none | 1,000 | [
{
"input": "4",
"output": "1"
},
{
"input": "7",
"output": "2"
},
{
"input": "77",
"output": "6"
},
{
"input": "4",
"output": "1"
},
{
"input": "474744",
"output": "83"
},
{
"input": "777774",
"output": "125"
},
{
"input": "447",
"outpu... | 1,565,032,382 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 109 | 0 | '''
Created on Aug 5, 2019
@author: Mohamed
'''
#x=input()
x=input().replace("4", "0").replace("7","1")
z=len(x)
index=2**z-1
index +=int(x,2)
print(index) | Title: Tavas and SaDDas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once again Tavas started eating coffee mix without water! Keione told him that it smells awful, but he didn't stop doing that. That's why Keione told his smart friend, SaDDas to punish him! SaDDas took Tavas' headphone... | ```python
'''
Created on Aug 5, 2019
@author: Mohamed
'''
#x=input()
x=input().replace("4", "0").replace("7","1")
z=len(x)
index=2**z-1
index +=int(x,2)
print(index)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,652,191,241 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | word = input()
upper = 0
lower = 0
for i in range(0, len(word)):
if word[i].upper() == word[i]:
upper = upper + 1
else:
lower = lower + 1
if upper > lower:
word = word.upper()
print(word)
else:
word = word.lower()
print(word) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
word = input()
upper = 0
lower = 0
for i in range(0, len(word)):
if word[i].upper() == word[i]:
upper = upper + 1
else:
lower = lower + 1
if upper > lower:
word = word.upper()
print(word)
else:
word = word.lower()
print(word)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,696,016,220 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 92 | 0 | input()
a = sorted(map(int,input().split()))
s=c=0
while s<=sum(a):
s+=a.pop()
c+=1
print(c)
| Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
input()
a = sorted(map(int,input().split()))
s=c=0
while s<=sum(a):
s+=a.pop()
c+=1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,505,248,795 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | N = int(input())
M = int(input())
Count = 0
for i in range(1, N+1):
Count += (M+(i%5))//5
print(Count) | Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
N = int(input())
M = int(input())
Count = 0
for i in range(1, N+1):
Count += (M+(i%5))//5
print(Count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
832 | A | Sasha and Sticks | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players t... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn. | If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower). | [
"1 1\n",
"10 4\n"
] | [
"YES\n",
"NO\n"
] | In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sas... | 500 | [
{
"input": "1 1",
"output": "YES"
},
{
"input": "10 4",
"output": "NO"
},
{
"input": "251656215122324104 164397544865601257",
"output": "YES"
},
{
"input": "963577813436662285 206326039287271924",
"output": "NO"
},
{
"input": "1000000000000000000 1",
"output":... | 1,673,757,658 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 46 | 0 | n,k=map(int,input().split())
t=n//k
print(["NO","YES"][t%2]) | Title: Sasha and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with ... | ```python
n,k=map(int,input().split())
t=n//k
print(["NO","YES"][t%2])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
689 | B | Mike and Shortcuts | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"greedy",
"shortest paths"
] | null | null | Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walking from his house located at the intersection number 1 and goes along some sequence of intersections. Wal... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Mike's city intersection.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*i*<=≤<=*a**i*<=≤<=*n* , , describing shortcuts of Mike's city, allowing to walk from intersection *i* to intersection *a**i* using only 1 unit of ... | In the only line print *n* integers *m*1,<=*m*2,<=...,<=*m**n*, where *m**i* denotes the least amount of total energy required to walk from intersection 1 to intersection *i*. | [
"3\n2 2 3\n",
"5\n1 2 3 4 5\n",
"7\n4 4 4 4 7 7 7\n"
] | [
"0 1 2 \n",
"0 1 2 3 4 \n",
"0 1 2 1 2 3 3 \n"
] | In the first sample case desired sequences are:
1: 1; *m*<sub class="lower-index">1</sub> = 0;
2: 1, 2; *m*<sub class="lower-index">2</sub> = 1;
3: 1, 3; *m*<sub class="lower-index">3</sub> = |3 - 1| = 2.
In the second sample case the sequence for any intersection 1 < *i* is always 1, *i* and *m*<sub class="lowe... | 1,000 | [
{
"input": "3\n2 2 3",
"output": "0 1 2 "
},
{
"input": "5\n1 2 3 4 5",
"output": "0 1 2 3 4 "
},
{
"input": "7\n4 4 4 4 7 7 7",
"output": "0 1 2 1 2 3 3 "
},
{
"input": "98\n17 17 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 57 87 87... | 1,621,214,571 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 467 | 25,395,200 | n = int(input())
a = list(map(int,input().split()))
dist = [-1] * n
dist[0] = 0
pos = [0]
for u in pos:
for v in [u - 1, u + 1, a[u] - 1]:
if v >= 0 and v < n and dist[v] == -1:
dist[v] = dist[u] + 1
pos.append(v)
print(" ".join(map(str, dist))) | Title: Mike and Shortcuts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Mike was very busy with studying for exams and contests. Now he is going to chill a bit by doing some sight seeing in the city.
City consists of *n* intersections numbered from 1 to *n*. Mike starts walkin... | ```python
n = int(input())
a = list(map(int,input().split()))
dist = [-1] * n
dist[0] = 0
pos = [0]
for u in pos:
for v in [u - 1, u + 1, a[u] - 1]:
if v >= 0 and v < n and dist[v] == -1:
dist[v] = dist[u] + 1
pos.append(v)
print(" ".join(map(str, dist)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
289 | A | Polo the Penguin and Segments | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Little penguin Polo adores integer segments, that is, pairs of integers [*l*; *r*] (*l*<=≤<=*r*).
He has a set that consists of *n* integer segments: [*l*1; *r*1],<=[*l*2; *r*2],<=...,<=[*l**n*; *r**n*]. We know that no two segments of this set intersect. In one move Polo can either widen any segment of the set 1 uni... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105). Each of the following *n* lines contain a segment as a pair of integers *l**i* and *r**i* (<=-<=105<=≤<=*l**i*<=≤<=*r**i*<=≤<=105), separated by a space.
It is guaranteed that no two segments intersect. In other words, for any two integers *i*... | In a single line print a single integer — the answer to the problem. | [
"2 3\n1 2\n3 4\n",
"3 7\n1 2\n3 3\n4 7\n"
] | [
"2\n",
"0\n"
] | none | 500 | [
{
"input": "2 3\n1 2\n3 4",
"output": "2"
},
{
"input": "3 7\n1 2\n3 3\n4 7",
"output": "0"
},
{
"input": "3 7\n1 10\n11 47\n74 128",
"output": "3"
},
{
"input": "5 4\n1 1\n2 2\n3 3\n4 4\n5 5",
"output": "3"
},
{
"input": "7 4\n2 2\n-1 -1\n0 1\n7 8\n-3 -2\n9 9\n4 ... | 1,690,625,169 | 2,147,483,647 | Python 3 | OK | TESTS | 28 | 498 | 16,691,200 | n, k = map(int, input().split())
segments = []
for _ in range(n):
l, r = map(int, input().split())
segments.append([l, r])
s = 0
count = 0
for i in range(n):
s += segments[i][1] + 1 - segments[i][0]
if s % k == 0:
print(0)
else:
while 1:
s += 1
count += 1
if s ... | Title: Polo the Penguin and Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little penguin Polo adores integer segments, that is, pairs of integers [*l*; *r*] (*l*<=≤<=*r*).
He has a set that consists of *n* integer segments: [*l*1; *r*1],<=[*l*2; *r*2],<=...,<=[*l**n*; *r**n*]... | ```python
n, k = map(int, input().split())
segments = []
for _ in range(n):
l, r = map(int, input().split())
segments.append([l, r])
s = 0
count = 0
for i in range(n):
s += segments[i][1] + 1 - segments[i][0]
if s % k == 0:
print(0)
else:
while 1:
s += 1
count += 1
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
17 | B | Hierarchy | PROGRAMMING | 1,500 | [
"dfs and similar",
"dsu",
"greedy",
"shortest paths"
] | B. Hierarchy | 2 | 64 | Nick's company employed *n* people. Now Nick needs to build a tree hierarchy of «supervisor-surbodinate» relations in the company (this is to say that each employee, except one, has exactly one supervisor). There are *m* applications written in the following form: «employee *a**i* is ready to become a supervisor of emp... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=1000) — amount of employees in the company. The following line contains *n* space-separated numbers *q**j* (0<=≤<=*q**j*<=≤<=106)— the employees' qualifications. The following line contains number *m* (0<=≤<=*m*<=≤<=10000) — amount of received applications. The f... | Output the only line — the minimum cost of building such a hierarchy, or -1 if it is impossible to build it. | [
"4\n7 2 3 1\n4\n1 2 5\n2 4 1\n3 4 1\n1 3 5\n",
"3\n1 2 3\n2\n3 1 2\n3 1 3\n"
] | [
"11\n",
"-1\n"
] | In the first sample one of the possible ways for building a hierarchy is to take applications with indexes 1, 2 and 4, which give 11 as the minimum total cost. In the second sample it is impossible to build the required hierarchy, so the answer is -1. | 0 | [
{
"input": "4\n7 2 3 1\n4\n1 2 5\n2 4 1\n3 4 1\n1 3 5",
"output": "11"
},
{
"input": "3\n1 2 3\n2\n3 1 2\n3 1 3",
"output": "-1"
},
{
"input": "1\n2\n0",
"output": "0"
},
{
"input": "2\n5 3\n4\n1 2 0\n1 2 5\n1 2 0\n1 2 7",
"output": "0"
},
{
"input": "3\n9 4 5\n5\... | 1,691,328,017 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | class Solve:
def __init__(self) -> None:
self.n: int = 0;
self.q:list = [];
self.m:int = 0;
self.cost:list = []
def vao(self) -> None:
self.n = int(input());
self.q = [0] + [int(item) for item in input().split(" ")];
self.m = int(input());
... | Title: Hierarchy
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Nick's company employed *n* people. Now Nick needs to build a tree hierarchy of «supervisor-surbodinate» relations in the company (this is to say that each employee, except one, has exactly one supervisor). There are *m* applicati... | ```python
class Solve:
def __init__(self) -> None:
self.n: int = 0;
self.q:list = [];
self.m:int = 0;
self.cost:list = []
def vao(self) -> None:
self.n = int(input());
self.q = [0] + [int(item) for item in input().split(" ")];
self.m = int(inp... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,695,637,213 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | n = set(input().split(" "))
if len(n) < 4:
print(4-len(n))
else:
print(0)
| Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
n = set(input().split(" "))
if len(n) < 4:
print(4-len(n))
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
603 | A | Alternative Thinking | PROGRAMMING | 1,600 | [
"dp",
"greedy",
"math"
] | null | null | Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length *n*. Each character of Kevin's string represents Kevin's score on one of the *n* questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is... | The first line contains the number of questions on the olympiad *n* (1<=≤<=*n*<=≤<=100<=000).
The following line contains a binary string of length *n* representing Kevin's results on the USAICO. | Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring. | [
"8\n10000011\n",
"2\n01\n"
] | [
"5\n",
"2\n"
] | In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score. | 500 | [
{
"input": "8\n10000011",
"output": "5"
},
{
"input": "2\n01",
"output": "2"
},
{
"input": "5\n10101",
"output": "5"
},
{
"input": "75\n010101010101010101010101010101010101010101010101010101010101010101010101010",
"output": "75"
},
{
"input": "11\n00000000000",
... | 1,493,038,124 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 77 | 4,812,800 | n = int(input())
s = input().strip()
ret = 1
nb2 = 0
for i in range(1,n):
if s[i-1] != s[i]:
ret += 1
else:
nb2 += 1
if nb2 >= 2:
ret += 2
elif n >= 2:
if s[0] == s[1] or s[-1] == s[-2]:
ret += 1
print(ret)
| Title: Alternative Thinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length *n*. Each character of Kevin's string represents Kevin's score on one o... | ```python
n = int(input())
s = input().strip()
ret = 1
nb2 = 0
for i in range(1,n):
if s[i-1] != s[i]:
ret += 1
else:
nb2 += 1
if nb2 >= 2:
ret += 2
elif n >= 2:
if s[0] == s[1] or s[-1] == s[-2]:
ret += 1
print(ret)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
791 | A | Bear and Big Brother | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's we... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively. | Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob. | [
"4 7\n",
"4 9\n",
"1 1\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Li... | 500 | [
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output... | 1,697,891,948 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 46 | 0 | a,b=input().split()
a=int(a)
b=int(b)
for i in (range(1,max(a,b)+1)):
if a*3>b*2:
print(i)
break
else:
a=a*3
b=b*2
| Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or e... | ```python
a,b=input().split()
a=int(a)
b=int(b)
for i in (range(1,max(a,b)+1)):
if a*3>b*2:
print(i)
break
else:
a=a*3
b=b*2
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,586,775,748 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 140 | 0 | def find(needle, haystack):
if not needle: return True
if needle[0] not in haystack:
return False
return find(needle[1:], haystack[haystack.find(needle[0])+1:])
if find("hello", input()):
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def find(needle, haystack):
if not needle: return True
if needle[0] not in haystack:
return False
return find(needle[1:], haystack[haystack.find(needle[0])+1:])
if find("hello", input()):
print("YES")
else:
print("NO")
``` | 3.93 | MatrixStudio/Codeforces-Python-Submissions |
336 | B | Vasily the Bear and Fly | PROGRAMMING | 1,900 | [
"math"
] | null | null | One beautiful day Vasily the bear painted 2*m* circles of the same radius *R* on a coordinate plane. Circles with numbers from 1 to *m* had centers at points (2*R*<=-<=*R*,<=0), (4*R*<=-<=*R*,<=0), ..., (2*Rm*<=-<=*R*,<=0), respectively. Circles with numbers from *m*<=+<=1 to 2*m* had centers at points (2*R*<=-<=*R*,<=... | The first line contains two integers *m*,<=*R* (1<=≤<=*m*<=≤<=105, 1<=≤<=*R*<=≤<=10). | In a single line print a single real number — the answer to the problem. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=6. | [
"1 1\n",
"2 2\n"
] | [
"2.0000000000\n",
"5.4142135624\n"
] | <img class="tex-graphics" src="https://espresso.codeforces.com/9fe384073741e20965ddc4bf162afd3a604b6b39.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Figure to the second sample | 1,000 | [
{
"input": "1 1",
"output": "2.0000000000"
},
{
"input": "2 2",
"output": "5.4142135624"
},
{
"input": "100000 3",
"output": "200002.4853316681"
},
{
"input": "2344 5",
"output": "7817.4790439982"
},
{
"input": "999 10",
"output": "6668.3010410807"
},
{
... | 1,689,631,490 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | print("_RANDOM_GUESS_1689631490.4979885")# 1689631490.4980097 | Title: Vasily the Bear and Fly
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One beautiful day Vasily the bear painted 2*m* circles of the same radius *R* on a coordinate plane. Circles with numbers from 1 to *m* had centers at points (2*R*<=-<=*R*,<=0), (4*R*<=-<=*R*,<=0), ..., (2*Rm*<=... | ```python
print("_RANDOM_GUESS_1689631490.4979885")# 1689631490.4980097
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
225 | A | Dice Tower | PROGRAMMING | 1,100 | [
"constructive algorithms",
"greedy"
] | null | null | A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other) that satisfy the given constraints (both of them are shown on the picture on the left).
Alice... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of dice in the tower.
The second line contains an integer *x* (1<=≤<=*x*<=≤<=6) — the number Bob sees at the top of the tower. Next *n* lines contain two space-separated integers each: the *i*-th line contains numbers *a**i*,<=*b**i* (1<=≤<=... | Print "YES" (without the quotes), if it is possible to to uniquely identify the numbers on the faces of all the dice in the tower. If it is impossible, print "NO" (without the quotes). | [
"3\n6\n3 2\n5 4\n2 4\n",
"3\n3\n2 6\n4 1\n5 3\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "3\n6\n3 2\n5 4\n2 4",
"output": "YES"
},
{
"input": "3\n3\n2 6\n4 1\n5 3",
"output": "NO"
},
{
"input": "1\n3\n2 1",
"output": "YES"
},
{
"input": "2\n2\n3 1\n1 5",
"output": "NO"
},
{
"input": "3\n2\n1 4\n5 3\n6 4",
"output": "NO"
},
{
"in... | 1,588,215,718 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 218 | 307,200 | dados = int(input())
n = int(input())
m = 7-n;
booleano = True;
for qwe in range(dados):
x,y = input().split()
y = int(y)
x = int(x)
if x == m or x == n or y == m or y == n or 7-y == m or 7-y == n or 7-x == n or 7-x == m or booleano == False:
booleano=False
else:
booleano = True
... | Title: Dice Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A dice is a cube, its faces contain distinct integers from 1 to 6 as black points. The sum of numbers at the opposite dice faces always equals 7. Please note that there are only two dice (these dices are mirror of each other... | ```python
dados = int(input())
n = int(input())
m = 7-n;
booleano = True;
for qwe in range(dados):
x,y = input().split()
y = int(y)
x = int(x)
if x == m or x == n or y == m or y == n or 7-y == m or 7-y == n or 7-x == n or 7-x == m or booleano == False:
booleano=False
else:
booleano =... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,666,158,297 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | s = input()
sumu = 0
suml = 0
sumu = sum(1 for words in s if words.isupper())
suml = sum(1 for words in s if words.islower())
if sumu > suml:
print(s.upper())
elif sumu < suml:
print(s.lower())
else:
print(s.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s = input()
sumu = 0
suml = 0
sumu = sum(1 for words in s if words.isupper())
suml = sum(1 for words in s if words.islower())
if sumu > suml:
print(s.upper())
elif sumu < suml:
print(s.lower())
else:
print(s.lower())
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,648,695,536 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | # coding=utf-8
x=input()
y=input()
x=[::-1]
if x==y:
print('YES')
else:
print('NO')
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
# coding=utf-8
x=input()
y=input()
x=[::-1]
if x==y:
print('YES')
else:
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
859 | B | Lazy Security Guard | PROGRAMMING | 1,000 | [
"brute force",
"geometry",
"math"
] | null | null | Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is, your friend must walk the perimeter of a region whose area is exactly *N* blocks. Your friend is quite ... | Input will consist of a single integer *N* (1<=≤<=*N*<=≤<=106), the number of city blocks that must be enclosed by the route. | Print the minimum perimeter that can be achieved. | [
"4\n",
"11\n",
"22\n"
] | [
"8\n",
"14\n",
"20\n"
] | Here are some possible shapes for the examples:
<img class="tex-graphics" src="https://espresso.codeforces.com/e11bef2cf82b55dd583cfc97d12b5aee5e483a65.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 750 | [
{
"input": "4",
"output": "8"
},
{
"input": "11",
"output": "14"
},
{
"input": "22",
"output": "20"
},
{
"input": "3",
"output": "8"
},
{
"input": "1024",
"output": "128"
},
{
"input": "101",
"output": "42"
},
{
"input": "30",
"output":... | 1,637,016,155 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 61 | 0 | n = int(input())
x = 1
best = float('inf')
while x * x <= n:
y = (n + x - 1)//x
best = min(best, 2*(x + y))
x += 1
print(best) | Title: Lazy Security Guard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your security guard friend recently got a new job at a new security company. The company requires him to patrol an area of the city encompassing exactly *N* city blocks, but they let him choose which blocks. That is... | ```python
n = int(input())
x = 1
best = float('inf')
while x * x <= n:
y = (n + x - 1)//x
best = min(best, 2*(x + y))
x += 1
print(best)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
600 | B | Queries about less or equal elements | PROGRAMMING | 1,300 | [
"binary search",
"data structures",
"sortings",
"two pointers"
] | null | null | You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*. | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=2·105) — the sizes of arrays *a* and *b*.
The second line contains *n* integers — the elements of array *a* (<=-<=109<=≤<=*a**i*<=≤<=109).
The third line contains *m* integers — the elements of array *b* (<=-<=109<=≤<=*b**j*<=≤<=109). | Print *m* integers, separated by spaces: the *j*-th of which is equal to the number of such elements in array *a* that are less than or equal to the value *b**j*. | [
"5 4\n1 3 5 7 9\n6 4 2 8\n",
"5 5\n1 2 1 2 5\n3 1 4 1 5\n"
] | [
"3 2 1 4\n",
"4 2 4 2 5\n"
] | none | 0 | [
{
"input": "5 4\n1 3 5 7 9\n6 4 2 8",
"output": "3 2 1 4"
},
{
"input": "5 5\n1 2 1 2 5\n3 1 4 1 5",
"output": "4 2 4 2 5"
},
{
"input": "1 1\n-1\n-2",
"output": "0"
},
{
"input": "1 1\n-80890826\n686519510",
"output": "1"
},
{
"input": "11 11\n237468511 -77918754... | 1,678,801,351 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 60 | 451 | 34,099,200 | from bisect import bisect_right
n, m = map(int, input().split())
a = sorted(list(map(int, input().split())))
b = list(map(int, input().split()))
for i in b:
print(bisect_right(a, i), end=" ")
| Title: Queries about less or equal elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays of integers *a* and *b*. For each element of the second array *b**j* you should find the number of elements in array *a* that are less than or equal to the value *b**j*.
In... | ```python
from bisect import bisect_right
n, m = map(int, input().split())
a = sorted(list(map(int, input().split())))
b = list(map(int, input().split()))
for i in b:
print(bisect_right(a, i), end=" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
143 | B | Help Kingdom of Far Far Away 2 | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as time went by, the economy of the Far Far Away developed and the scale of operatio... | The input contains a number that needs to be converted into financial format. The number's notation length does not exceed 100 characters, including (possible) signs "-" (minus) and "." (decimal point). The number's notation is correct, that is:
- The number's notation only contains characters from the set {"0" – "9... | Print the number given in the input in the financial format by the rules described in the problem statement. | [
"2012\n",
"0.000\n",
"-0.00987654321\n",
"-12345678.9\n"
] | [
"$2,012.00",
"$0.00",
"($0.00)",
"($12,345,678.90)"
] | Pay attention to the second and third sample tests. They show that the sign of a number in the financial format (and consequently, the presence or absence of brackets) is determined solely by the sign of the initial number. It does not depend on the sign of the number you got after translating the number to the financi... | 1,000 | [
{
"input": "2012",
"output": "$2,012.00"
},
{
"input": "0.000",
"output": "$0.00"
},
{
"input": "-0.00987654321",
"output": "($0.00)"
},
{
"input": "-12345678.9",
"output": "($12,345,678.90)"
},
{
"input": "0.99999999999999999999",
"output": "$0.99"
},
{
... | 1,638,722,459 | 2,147,483,647 | Python 3 | OK | TESTS | 100 | 124 | 0 | n = input()
if "." not in n:
n = n+".00"
deci, frac = n.split(".")
count = 1
updated = ""
for c in deci[-1::-1]:
if c=="-":
break
if count == 4:
count = 1
updated += ","
updated += c
count += 1
new_deci = updated[-1::-1]
frac += "00"
frac = frac[:2]
if deci[0... | Title: Help Kingdom of Far Far Away 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more e... | ```python
n = input()
if "." not in n:
n = n+".00"
deci, frac = n.split(".")
count = 1
updated = ""
for c in deci[-1::-1]:
if c=="-":
break
if count == 4:
count = 1
updated += ","
updated += c
count += 1
new_deci = updated[-1::-1]
frac += "00"
frac = frac[:2]
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,597,595,296 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 140 | 819,200 | import string
letters=string.ascii_lowercase
n,k=list(map(int,input().split(' ')))
for i in range(n):
coordinate=i%k
print(letters[coordinate], end="")
print() | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
import string
letters=string.ascii_lowercase
n,k=list(map(int,input().split(' ')))
for i in range(n):
coordinate=i%k
print(letters[coordinate], end="")
print()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Be... | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands ... | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,630,003,459 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 6,656,000 | n, m=[int(i) for i in input().split()]
a=[]
k=""
for i in range(n):
a.append((input()))
s=a[0]
for i in range(n):
if a[m-i-1]!=s:
k="YES"
else:
k="NO"
print(k)
| Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of... | ```python
n, m=[int(i) for i in input().split()]
a=[]
k=""
for i in range(n):
a.append((input()))
s=a[0]
for i in range(n):
if a[m-i-1]!=s:
k="YES"
else:
k="NO"
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
389 | B | Fox and Cross | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n*<=×<=*n* cells. Each cell contains either a symbol '.', or a symbol '#'.
A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.
Ciel wants to draw several... | The first line contains an integer *n* (3<=≤<=*n*<=≤<=100) — the size of the board.
Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'. | Output a single line with "YES" if Ciel can draw the crosses in the described way. Otherwise output a single line with "NO". | [
"5\n.#...\n####.\n.####\n...#.\n.....\n",
"4\n####\n####\n####\n####\n",
"6\n.#....\n####..\n.####.\n.#.##.\n######\n.#..#.\n",
"6\n.#..#.\n######\n.####.\n.####.\n######\n.#..#.\n",
"3\n...\n...\n...\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In example 1, you can draw two crosses. The picture below shows what they look like.
In example 2, the board contains 16 cells with '#', but each cross contains 5. Since 16 is not a multiple of 5, so it's impossible to cover all. | 1,000 | [
{
"input": "4\n####\n####\n####\n####",
"output": "NO"
},
{
"input": "6\n.#....\n####..\n.####.\n.#.##.\n######\n.#..#.",
"output": "YES"
},
{
"input": "6\n.#..#.\n######\n.####.\n.####.\n######\n.#..#.",
"output": "NO"
},
{
"input": "5\n.....\n.#...\n####.\n.####\n...#.",
... | 1,659,479,676 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 35 | 46 | 0 | def main(n):
for i in range(n):
for j in range(n):
if list[i][j]=="#":
list[i][j]='.'
if list[i+1][j]!='.' and list[i+2][j]!='.' and list[i+1][j+1]!='.' and list[i+1][j-1]!='.':
list[i+1][j]='.'
list[i+2][j]='.'
... | Title: Fox and Cross
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n*<=×<=*n* cells. Each cell contains either a symbol '.', or a symbol '#'.
A cross on the board is a connected set of exactly five cells of t... | ```python
def main(n):
for i in range(n):
for j in range(n):
if list[i][j]=="#":
list[i][j]='.'
if list[i+1][j]!='.' and list[i+2][j]!='.' and list[i+1][j+1]!='.' and list[i+1][j-1]!='.':
list[i+1][j]='.'
list[i+2][j]... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
840 | B | Leha and another game about graph | PROGRAMMING | 2,100 | [
"constructive algorithms",
"data structures",
"dfs and similar",
"dp",
"graphs"
] | null | null | Leha plays a computer game, where is on each level is given a connected graph with *n* vertices and *m* edges. Graph can contain multiple edges, but can not contain self loops. Each vertex has an integer *d**i*, which can be equal to 0, 1 or <=-<=1. To pass the level, he needs to find a «good» subset of edges of the gr... | The first line contains two integers *n*, *m* (1<=≤<=*n*<=≤<=3·105, *n*<=-<=1<=≤<=*m*<=≤<=3·105) — number of vertices and edges.
The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (<=-<=1<=≤<=*d**i*<=≤<=1) — numbers on the vertices.
Each of the next *m* lines contains two integers *u* and *v* (1<=≤<=*u*... | Print <=-<=1 in a single line, if solution doesn't exist. Otherwise in the first line *k* — number of edges in a subset. In the next *k* lines indexes of edges. Edges are numerated in order as they are given in the input, starting from 1. | [
"1 0\n1\n",
"4 5\n0 0 0 -1\n1 2\n2 3\n3 4\n1 4\n2 4\n",
"2 1\n1 1\n1 2\n",
"3 3\n0 -1 1\n1 2\n2 3\n1 3\n"
] | [
"-1\n",
"0\n",
"1\n1\n",
"1\n2\n"
] | In the first sample we have single vertex without edges. It's degree is 0 and we can not get 1. | 1,000 | [
{
"input": "1 0\n1",
"output": "-1"
},
{
"input": "4 5\n0 0 0 -1\n1 2\n2 3\n3 4\n1 4\n2 4",
"output": "0"
},
{
"input": "2 1\n1 1\n1 2",
"output": "1\n1"
},
{
"input": "3 3\n0 -1 1\n1 2\n2 3\n1 3",
"output": "1\n2"
},
{
"input": "10 10\n-1 -1 -1 -1 -1 -1 -1 -1 -1 ... | 1,586,233,019 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 2,932 | 75,673,600 | # https://codeforces.com/problemset/problem/840/B
n, m = map(int, input().split())
d = list(map(int, input().split()))
g={}
def push(g, u, v, i):
if u not in g:
g[u]=[]
if v not in g:
g[v]=[]
g[u].append([v, i+1])
g[v].append([u, i+1])
for i in range(m):
... | Title: Leha and another game about graph
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Leha plays a computer game, where is on each level is given a connected graph with *n* vertices and *m* edges. Graph can contain multiple edges, but can not contain self loops. Each vertex has an integ... | ```python
# https://codeforces.com/problemset/problem/840/B
n, m = map(int, input().split())
d = list(map(int, input().split()))
g={}
def push(g, u, v, i):
if u not in g:
g[u]=[]
if v not in g:
g[v]=[]
g[u].append([v, i+1])
g[v].append([u, i+1])
for i in range... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
845 | B | Luba And The Ticket | PROGRAMMING | 1,600 | [
"brute force",
"greedy",
"implementation"
] | null | null | Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make the ticket lucky.
The ticket is considered lucky if the sum of first three digits equals to the sum of las... | You are given a string consisting of 6 characters (all characters are digits from 0 to 9) — this string denotes Luba's ticket. The ticket can start with the digit 0. | Print one number — the minimum possible number of digits Luba needs to replace to make the ticket lucky. | [
"000000\n",
"123456\n",
"111000\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first example the ticket is already lucky, so the answer is 0.
In the second example Luba can replace 4 and 5 with zeroes, and the ticket will become lucky. It's easy to see that at least two replacements are required.
In the third example Luba can replace any zero with 3. It's easy to see that at least one re... | 0 | [
{
"input": "000000",
"output": "0"
},
{
"input": "123456",
"output": "2"
},
{
"input": "111000",
"output": "1"
},
{
"input": "120111",
"output": "0"
},
{
"input": "999999",
"output": "0"
},
{
"input": "199880",
"output": "1"
},
{
"input": "... | 1,503,330,979 | 3,079 | Python 3 | CHALLENGED | CHALLENGES | 11 | 62 | 0 | n=input()
a=n[:3]
b=n[3:]
s=int(a[0])+int(a[1])+int(a[2])
t=int(b[0])+int(b[1])+int(b[2])
d=s-t
if d<0:
d=d*-1
if d==0:
print(0)
elif d<9:
print(1)
elif d<18:
print(2)
else:
print(3)
| Title: Luba And The Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make th... | ```python
n=input()
a=n[:3]
b=n[3:]
s=int(a[0])+int(a[1])+int(a[2])
t=int(b[0])+int(b[1])+int(b[2])
d=s-t
if d<0:
d=d*-1
if d==0:
print(0)
elif d<9:
print(1)
elif d<18:
print(2)
else:
print(3)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long,... | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,613,711,760 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 608 | 614,400 | n,m,k=map(int,input().split())
l1=[]
l2=[]
for i in range(1,k+1):
if n*i<=k:
l1.append(n*i)
for i in range(1,k+1):
if m*i<=k:
l2.append(m*i)
count=0
for x in l1:
if x in l2:
count+=1
print(count) | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists com... | ```python
n,m,k=map(int,input().split())
l1=[]
l2=[]
for i in range(1,k+1):
if n*i<=k:
l1.append(n*i)
for i in range(1,k+1):
if m*i<=k:
l2.append(m*i)
count=0
for x in l1:
if x in l2:
count+=1
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
361 | B | Levko and Permutation | PROGRAMMING | 1,200 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | Levko loves permutations very much. A permutation of length *n* is a sequence of distinct positive integers, each is at most *n*.
Let’s assume that value *gcd*(*a*,<=*b*) shows the greatest common divisor of numbers *a* and *b*. Levko assumes that element *p**i* of permutation *p*1,<=*p*2,<=... ,<=*p**n* is good if *g... | The single line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*). | In a single line print either any beautiful permutation or -1, if such permutation doesn’t exist.
If there are multiple suitable permutations, you are allowed to print any of them. | [
"4 2\n",
"1 1\n"
] | [
"2 4 3 1",
"-1\n"
] | In the first sample elements 4 and 3 are good because *gcd*(2, 4) = 2 > 1 and *gcd*(3, 3) = 3 > 1. Elements 2 and 1 are not good because *gcd*(1, 2) = 1 and *gcd*(4, 1) = 1. As there are exactly 2 good elements, the permutation is beautiful.
The second sample has no beautiful permutations. | 1,000 | [
{
"input": "4 2",
"output": "2 1 3 4 "
},
{
"input": "1 1",
"output": "-1"
},
{
"input": "7 4",
"output": "3 1 2 4 5 6 7 "
},
{
"input": "10 9",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "10000 5000",
"output": "5000 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 1... | 1,616,651,501 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n,k=map(int,input().split())
x=""
j=0
for i in range(1,n+1):
if i==1:
x+="0"
continue
j+=1
if j<=k:
x+=str(i)
else:
x+="0"
if j<k:
print(-1)
else:
print(x) | Title: Levko and Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves permutations very much. A permutation of length *n* is a sequence of distinct positive integers, each is at most *n*.
Let’s assume that value *gcd*(*a*,<=*b*) shows the greatest common divisor of numb... | ```python
n,k=map(int,input().split())
x=""
j=0
for i in range(1,n+1):
if i==1:
x+="0"
continue
j+=1
if j<=k:
x+=str(i)
else:
x+="0"
if j<k:
print(-1)
else:
print(x)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,644,906,791 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 124 | 512,000 | def solve(arr,n):
if n==1:
return 'YES'
if n==2:
if arr[0]==arr[1]:
return 'NO'
else:
return 'YES'
rec = dict()
for i in range(n):
if arr[i] not in rec:
rec[arr[i]] = 1
else:
rec[arr[i]] += 1
fo... | Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
def solve(arr,n):
if n==1:
return 'YES'
if n==2:
if arr[0]==arr[1]:
return 'NO'
else:
return 'YES'
rec = dict()
for i in range(n):
if arr[i] not in rec:
rec[arr[i]] = 1
else:
rec[arr[i]] += 1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,622,934,781 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 280 | 0 | n = int(input())
arr = list(map(int, input().split()))
change = 0
if arr[0] == 0 and arr[0] > 25:
print("NO")
else:
for i in range(len(arr)):
if 25 < arr[i] <= change+25:
change -= arr[i] - 25
elif arr[i] == 25:
change += 25
else:
print("... | Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the bookin... | ```python
n = int(input())
arr = list(map(int, input().split()))
change = 0
if arr[0] == 0 and arr[0] > 25:
print("NO")
else:
for i in range(len(arr)):
if 25 < arr[i] <= change+25:
change -= arr[i] - 25
elif arr[i] == 25:
change += 25
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
509 | A | Maximum in Table | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the ... | The only line of input contains a positive integer *n* (1<=≤<=*n*<=≤<=10) — the number of rows and columns of the table. | Print a single line containing a positive integer *m* — the maximum value in the table. | [
"1\n",
"5\n"
] | [
"1",
"70"
] | In the second test the rows of the table look as follows: | 0 | [
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "70"
},
{
"input": "2",
"output": "2"
},
{
"input": "3",
"output": "6"
},
{
"input": "4",
"output": "20"
},
{
"input": "6",
"output": "252"
},
{
"input": "7",
"output": "924"
... | 1,609,857,878 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | n=int(input())
l=[0,1,5,15,35,70,126,210,330,495,715,1001]
print(l[n]) | Title: Maximum in Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An *n*<=×<=*n* table *a* is defined as follows:
- The first row and the first column contain ones, that is: *a**i*,<=1<==<=*a*1,<=*i*<==<=1 for all *i*<==<=1,<=2,<=...,<=*n*. - Each of the remaining numbers in the t... | ```python
n=int(input())
l=[0,1,5,15,35,70,126,210,330,495,715,1001]
print(l[n])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,684,794,385 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | a=int (input ())
b=int (input ())
c=int (b/60)
d=int (b%60)
g=(c*60)+d
n=0
if g>=240 :
print (0)
if g<240 :
while n<a :
if g>=240 :
break
g+=5*(n+1)
if g<=240 :
n+=1
print(n) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
a=int (input ())
b=int (input ())
c=int (b/60)
d=int (b%60)
g=(c*60)+d
n=0
if g>=240 :
print (0)
if g<240 :
while n<a :
if g>=240 :
break
g+=5*(n+1)
if g<=240 :
n+=1
print(n)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
501 | A | Contest | PROGRAMMING | 900 | [
"implementation"
] | null | null | Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved the problem that costs *b* points. Besides, Misha submitted the problem *c* minutes after the ... | The first line contains four integers *a*, *b*, *c*, *d* (250<=≤<=*a*,<=*b*<=≤<=3500, 0<=≤<=*c*,<=*d*<=≤<=180).
It is guaranteed that numbers *a* and *b* are divisible by 250 (just like on any real Codeforces round). | Output on a single line:
"Misha" (without the quotes), if Misha got more points than Vasya.
"Vasya" (without the quotes), if Vasya got more points than Misha.
"Tie" (without the quotes), if both of them got the same number of points. | [
"500 1000 20 30\n",
"1000 1000 1 1\n",
"1500 1000 176 177\n"
] | [
"Vasya\n",
"Tie\n",
"Misha\n"
] | none | 500 | [
{
"input": "500 1000 20 30",
"output": "Vasya"
},
{
"input": "1000 1000 1 1",
"output": "Tie"
},
{
"input": "1500 1000 176 177",
"output": "Misha"
},
{
"input": "1500 1000 74 177",
"output": "Misha"
},
{
"input": "750 2500 175 178",
"output": "Vasya"
},
{
... | 1,614,938,896 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 62 | 0 | def points(score, time):
return max(3*score/10, score - time*score/250)
a, b, c, d = [int(i) for i in input().split()]
if points(b, d) > points(a, c):
print('Vasya')
elif points(b, d) < points(a, c):
print('Misha')
else:
print('Tie')
| Title: Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha and Vasya participated in a Codeforces contest. Unfortunately, each of them solved only one problem, though successfully submitted it at the first attempt. Misha solved the problem that costs *a* points and Vasya solved t... | ```python
def points(score, time):
return max(3*score/10, score - time*score/250)
a, b, c, d = [int(i) for i in input().split()]
if points(b, d) > points(a, c):
print('Vasya')
elif points(b, d) < points(a, c):
print('Misha')
else:
print('Tie')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
645 | A | Amity Assessment | PROGRAMMING | 1,200 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Bessie the cow and her best friend Elsie each received a sliding puzzle on Pi Day. Their puzzles consist of a 2<=×<=2 grid and three tiles labeled 'A', 'B', and 'C'. The three tiles sit on top of the grid, leaving one grid cell empty. To make a move, Bessie or Elsie can slide a tile adjacent to the empty cell into the ... | The first two lines of the input consist of a 2<=×<=2 grid describing the initial configuration of Bessie's puzzle. The next two lines contain a 2<=×<=2 grid describing the initial configuration of Elsie's puzzle. The positions of the tiles are labeled 'A', 'B', and 'C', while the empty cell is labeled 'X'. It's guaran... | Output "YES"(without quotes) if the puzzles can reach the same configuration (and Bessie and Elsie are truly BFFLs). Otherwise, print "NO" (without quotes). | [
"AB\nXC\nXB\nAC\n",
"AB\nXC\nAC\nBX\n"
] | [
"YES\n",
"NO\n"
] | The solution to the first sample is described by the image. All Bessie needs to do is slide her 'A' tile down.
In the second sample, the two puzzles can never be in the same configuration. Perhaps Bessie and Elsie are not meant to be friends after all... | 500 | [
{
"input": "AB\nXC\nXB\nAC",
"output": "YES"
},
{
"input": "AB\nXC\nAC\nBX",
"output": "NO"
},
{
"input": "XC\nBA\nCB\nAX",
"output": "NO"
},
{
"input": "AB\nXC\nAX\nCB",
"output": "YES"
},
{
"input": "CB\nAX\nXA\nBC",
"output": "YES"
},
{
"input": "BC... | 1,458,320,827 | 1,927 | Python 3 | OK | TESTS | 102 | 62 | 0 | puzzle1 = ''
puzzle2 = ''
row = input()
if row[0] != 'X':
puzzle1 += row[0]
if row[1] != 'X':
puzzle1 += row[1]
row = input()
if row[1] != 'X':
puzzle1 += row[1]
if row[0] != 'X':
puzzle1 += row[0]
row = input()
if row[0] != 'X':
puzzle2 += row[0]
if row[1] != 'X':
puzzle2 += r... | Title: Amity Assessment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bessie the cow and her best friend Elsie each received a sliding puzzle on Pi Day. Their puzzles consist of a 2<=×<=2 grid and three tiles labeled 'A', 'B', and 'C'. The three tiles sit on top of the grid, leaving one ... | ```python
puzzle1 = ''
puzzle2 = ''
row = input()
if row[0] != 'X':
puzzle1 += row[0]
if row[1] != 'X':
puzzle1 += row[1]
row = input()
if row[1] != 'X':
puzzle1 += row[1]
if row[0] != 'X':
puzzle1 += row[0]
row = input()
if row[0] != 'X':
puzzle2 += row[0]
if row[1] != 'X':
pu... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
714 | A | Meeting of Old Friends | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to ... | The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks. | Print one integer — the number of minutes Sonya and Filya will be able to spend together. | [
"1 10 9 20 1\n",
"1 100 50 200 75\n"
] | [
"2\n",
"50\n"
] | In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100. | 500 | [
{
"input": "1 10 9 20 1",
"output": "2"
},
{
"input": "1 100 50 200 75",
"output": "50"
},
{
"input": "6 6 5 8 9",
"output": "1"
},
{
"input": "1 1000000000 1 1000000000 1",
"output": "999999999"
},
{
"input": "5 100 8 8 8",
"output": "0"
},
{
"input":... | 1,693,113,930 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 96 | 62 | 0 | # Wadea #
l1,r1,l2,r2,k = map(int,input().split())
ll = max(l1,l2)
rr = min(r1,r2)
lr = rr - ll + 1
if lr <= 0:
print(0)
elif ll <= k <= rr:
print(lr-1)
else:
print(lr) | Title: Meeting of Old Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusi... | ```python
# Wadea #
l1,r1,l2,r2,k = map(int,input().split())
ll = max(l1,l2)
rr = min(r1,r2)
lr = rr - ll + 1
if lr <= 0:
print(0)
elif ll <= k <= rr:
print(lr-1)
else:
print(lr)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,689,435,250 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = int(input())
my_list = list(map(int, input().split()))
nprint = ""
partOfPrint = ""
count = 0
my_set = set([1, 2, 3])
i = -1
while len(my_set) >= 3:
my_set = set(my_list)
i += 1
if i == len(my_list):
break
if my_list[i] in my_set and my_list[i] not in partOfPrint:
pa... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n = int(input())
my_list = list(map(int, input().split()))
nprint = ""
partOfPrint = ""
count = 0
my_set = set([1, 2, 3])
i = -1
while len(my_set) >= 3:
my_set = set(my_list)
i += 1
if i == len(my_list):
break
if my_list[i] in my_set and my_list[i] not in partOfPrint:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,591,271,952 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 327 | 5,324,800 | n,m=[int(i) for i in input().split()]
l=[]
a=[]
for i in range(m):
g,h=[str(i) for i in input().split()]
l.append(g)
a.append(h)
# print(l,a)
s=str(input())
s=s.split(' ')
z=[]
for i in range(0,len(s)):
d=s[i]
# print(d)
if(d in l):
f=l.index(d)
if(len(l[f])>len(a... | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
n,m=[int(i) for i in input().split()]
l=[]
a=[]
for i in range(m):
g,h=[str(i) for i in input().split()]
l.append(g)
a.append(h)
# print(l,a)
s=str(input())
s=s.split(' ')
z=[]
for i in range(0,len(s)):
d=s[i]
# print(d)
if(d in l):
f=l.index(d)
if(len(l... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
552 | D | Vanya and Triangles | PROGRAMMING | 1,900 | [
"brute force",
"combinatorics",
"data structures",
"geometry",
"math",
"sortings"
] | null | null | Vanya got bored and he painted *n* distinct points on the plane. After that he connected all the points pairwise and saw that as a result many triangles were formed with vertices in the painted points. He asks you to count the number of the formed triangles with the non-zero area. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of the points painted on the plane.
Next *n* lines contain two integers each *x**i*,<=*y**i* (<=-<=100<=≤<=*x**i*,<=*y**i*<=≤<=100) — the coordinates of the *i*-th point. It is guaranteed that no two given points coincide. | In the first line print an integer — the number of triangles with the non-zero area among the painted points. | [
"4\n0 0\n1 1\n2 0\n2 2\n",
"3\n0 0\n1 1\n2 0\n",
"1\n1 1\n"
] | [
"3\n",
"1\n",
"0\n"
] | Note to the first sample test. There are 3 triangles formed: (0, 0) - (1, 1) - (2, 0); (0, 0) - (2, 2) - (2, 0); (1, 1) - (2, 2) - (2, 0).
Note to the second sample test. There is 1 triangle formed: (0, 0) - (1, 1) - (2, 0).
Note to the third sample test. A single point doesn't form a single triangle. | 2,000 | [
{
"input": "4\n0 0\n1 1\n2 0\n2 2",
"output": "3"
},
{
"input": "3\n0 0\n1 1\n2 0",
"output": "1"
},
{
"input": "1\n1 1",
"output": "0"
},
{
"input": "5\n0 0\n1 1\n2 2\n3 3\n4 4",
"output": "0"
},
{
"input": "5\n0 0\n1 1\n2 3\n3 6\n4 10",
"output": "10"
},
... | 1,538,017,520 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 3,400 | 0 | n = int(input())
if n < 3:
print(0)
else:
ans = n*(n-1)*(n-2)/6
x = [0]*n
y = [0]*n
for i in range(n):
x[i], y[i] = map(int, input().split())
for i in range(n):
seen = {}
x1, y1 = x[i], y[i]
for j in range(i+1, n):
x2, y2 = x[j], y[j]
... | Title: Vanya and Triangles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got bored and he painted *n* distinct points on the plane. After that he connected all the points pairwise and saw that as a result many triangles were formed with vertices in the painted points. He asks you t... | ```python
n = int(input())
if n < 3:
print(0)
else:
ans = n*(n-1)*(n-2)/6
x = [0]*n
y = [0]*n
for i in range(n):
x[i], y[i] = map(int, input().split())
for i in range(n):
seen = {}
x1, y1 = x[i], y[i]
for j in range(i+1, n):
x2, y2 = x[j], y[j... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of decreasing coordinates) within distance *b**i* inclusive. The beacon itself is not destroyed however.... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the initial number of beacons.
The *i*-th of next *n* lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=1<=000<=000, 1<=≤<=*b**i*<=≤<=1<=000<=000) — the position and power level of the *i*-th beacon respectively. No two beac... | Print a single integer — the minimum number of beacons that could be destroyed if exactly one beacon is added. | [
"4\n1 9\n3 1\n6 1\n7 4\n",
"7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1\n"
] | [
"1\n",
"3\n"
] | For the first sample case, the minimum number of beacons destroyed is 1. One way to achieve this is to place a beacon at position 9 with power level 2.
For the second sample case, the minimum number of beacons destroyed is 3. One way to achieve this is to place a beacon at position 1337 with power level 42. | 0 | [
{
"input": "4\n1 9\n3 1\n6 1\n7 4",
"output": "1"
},
{
"input": "7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1",
"output": "3"
},
{
"input": "1\n0 1",
"output": "0"
},
{
"input": "1\n0 1000000",
"output": "0"
},
{
"input": "1\n1000000 1000000",
"output": "0"
},
{
... | 1,554,362,377 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 1,887 | 7,884,800 | import sys
from math import *
def minp():
return sys.stdin.readline().strip()
def mint():
return int(minp())
def mints():
return map(int, minp().split())
n = mint()
a = [0]*n
dp = [0]*n
for i in range(n):
a[i] = tuple(mints())
a.sort()
for i in range(n):
x, p = a[i]
l = -1
r = n
v = x-... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of decreasing ... | ```python
import sys
from math import *
def minp():
return sys.stdin.readline().strip()
def mint():
return int(minp())
def mints():
return map(int, minp().split())
n = mint()
a = [0]*n
dp = [0]*n
for i in range(n):
a[i] = tuple(mints())
a.sort()
for i in range(n):
x, p = a[i]
l = -1
r = ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
845 | B | Luba And The Ticket | PROGRAMMING | 1,600 | [
"brute force",
"greedy",
"implementation"
] | null | null | Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make the ticket lucky.
The ticket is considered lucky if the sum of first three digits equals to the sum of las... | You are given a string consisting of 6 characters (all characters are digits from 0 to 9) — this string denotes Luba's ticket. The ticket can start with the digit 0. | Print one number — the minimum possible number of digits Luba needs to replace to make the ticket lucky. | [
"000000\n",
"123456\n",
"111000\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first example the ticket is already lucky, so the answer is 0.
In the second example Luba can replace 4 and 5 with zeroes, and the ticket will become lucky. It's easy to see that at least two replacements are required.
In the third example Luba can replace any zero with 3. It's easy to see that at least one re... | 0 | [
{
"input": "000000",
"output": "0"
},
{
"input": "123456",
"output": "2"
},
{
"input": "111000",
"output": "1"
},
{
"input": "120111",
"output": "0"
},
{
"input": "999999",
"output": "0"
},
{
"input": "199880",
"output": "1"
},
{
"input": "... | 1,503,824,592 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 101 | 62 | 0 | import math
a=[int(i) for i in input()]
diff=math.fabs(a[0]+a[1]+a[2]-a[3]-a[4]-a[5])
ans=0
b=sorted([max(i,9-i) for i in a])
while diff>0:
diff-=b.pop()
ans+=1
print(ans) | Title: Luba And The Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make th... | ```python
import math
a=[int(i) for i in input()]
diff=math.fabs(a[0]+a[1]+a[2]-a[3]-a[4]-a[5])
ans=0
b=sorted([max(i,9-i) for i in a])
while diff>0:
diff-=b.pop()
ans+=1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
837 | A | Text Volume | PROGRAMMING | 800 | [
"implementation"
] | null | null | You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the text.
Calculate the volume of the given text. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200) — length of the text.
The second line contains text of single-space separated words *s*1,<=*s*2,<=...,<=*s**i*, consisting only of small and capital Latin letters. | Print one integer number — volume of text. | [
"7\nNonZERO\n",
"24\nthis is zero answer text\n",
"24\nHarbour Space University\n"
] | [
"5\n",
"0\n",
"1\n"
] | In the first example there is only one word, there are 5 capital letters in it.
In the second example all of the words contain 0 capital letters. | 0 | [
{
"input": "7\nNonZERO",
"output": "5"
},
{
"input": "24\nthis is zero answer text",
"output": "0"
},
{
"input": "24\nHarbour Space University",
"output": "1"
},
{
"input": "2\nWM",
"output": "2"
},
{
"input": "200\nLBmJKQLCKUgtTxMoDsEerwvLOXsxASSydOqWyULsRcjMYDWd... | 1,592,652,104 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 140 | 0 | n=int(input())
x=list(input())
k=0
a=[]
for i in range(n):
if x[i].isupper()==1:
k+=1
elif x[i]==" ":
a.append(k)
k=0
if i==n-1:
a.append(k)
print(max(a))
| Title: Text Volume
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a text of single-space separated words, consisting of small and capital Latin letters.
Volume of the word is number of capital letters in the word. Volume of the text is maximum volume of all words in the tex... | ```python
n=int(input())
x=list(input())
k=0
a=[]
for i in range(n):
if x[i].isupper()==1:
k+=1
elif x[i]==" ":
a.append(k)
k=0
if i==n-1:
a.append(k)
print(max(a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
609 | A | USB Flash Drives | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives. | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabyt... | Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives. | [
"3\n5\n2\n1\n3\n",
"3\n6\n2\n3\n2\n",
"2\n5\n5\n10\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | 0 | [
{
"input": "3\n5\n2\n1\n3",
"output": "2"
},
{
"input": "3\n6\n2\n3\n2",
"output": "3"
},
{
"input": "2\n5\n5\n10",
"output": "1"
},
{
"input": "5\n16\n8\n1\n3\n4\n9",
"output": "2"
},
{
"input": "10\n121\n10\n37\n74\n56\n42\n39\n6\n68\n8\n100",
"output": "2"
... | 1,675,580,998 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 62 | 0 | n = int(input())
m = int(input())
a = []
for i in range(n):
a.append(int(input()))
a.sort()
while m > 0:
m -= a[-1]
del a[-1]
print(n - len(a))
| Title: USB Flash Drives
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of... | ```python
n = int(input())
m = int(input())
a = []
for i in range(n):
a.append(int(input()))
a.sort()
while m > 0:
m -= a[-1]
del a[-1]
print(n - len(a))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
451 | A | Game With Sticks | PROGRAMMING | 900 | [
"implementation"
] | null | null | After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid show... | The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). | Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. | [
"2 2\n",
"2 3\n",
"3 3\n"
] | [
"Malvika\n",
"Malvika\n",
"Akshat\n"
] | Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remov... | 500 | [
{
"input": "2 2",
"output": "Malvika"
},
{
"input": "2 3",
"output": "Malvika"
},
{
"input": "3 3",
"output": "Akshat"
},
{
"input": "20 68",
"output": "Malvika"
},
{
"input": "1 1",
"output": "Akshat"
},
{
"input": "1 2",
"output": "Akshat"
},
... | 1,690,580,917 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 28 | 62 | 0 |
import math as mth
import sys
#input=sys.stdin.readline
def solve():
#n=int(input())
n,m=list(map(int,input().split()))
#f=list(map(int,input().split()))
if min(n,m)&1==0:
print("Malvika")
else:
print("Akshat")
return
def main():
#for _ in range(i... | Title: Game With Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid... | ```python
import math as mth
import sys
#input=sys.stdin.readline
def solve():
#n=int(input())
n,m=list(map(int,input().split()))
#f=list(map(int,input().split()))
if min(n,m)&1==0:
print("Malvika")
else:
print("Akshat")
return
def main():
#for _ ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
348 | C | Subset Sums | PROGRAMMING | 2,500 | [
"brute force",
"data structures"
] | null | null | You are given an array *a*1,<=*a*2,<=...,<=*a**n* and *m* sets *S*1,<=*S*2,<=...,<=*S**m* of indices of elements of this array. Let's denote *S**k*<==<={*S**k*,<=*i*} (1<=≤<=*i*<=≤<=|*S**k*|). In other words, *S**k*,<=*i* is some element from set *S**k*.
In this problem you have to answer *q* queries of the two types:... | The first line contains integers *n*,<=*m*,<=*q* (1<=≤<=*n*,<=*m*,<=*q*<=≤<=105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=108) — elements of array *a*.
Each of the following *m* lines describes one set of indices. The *k*-th line first contains a positive integer, representing t... | After each first type query print the required sum on a single line.
Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"5 3 5\n5 -5 5 1 -4\n2 1 2\n4 2 1 4 5\n2 2 5\n? 2\n+ 3 4\n? 1\n+ 2 1\n? 2\n"
] | [
"-3\n4\n9\n"
] | none | 1,500 | [
{
"input": "5 3 5\n5 -5 5 1 -4\n2 1 2\n4 2 1 4 5\n2 2 5\n? 2\n+ 3 4\n? 1\n+ 2 1\n? 2",
"output": "-3\n4\n9"
},
{
"input": "10 10 10\n0 0 0 1 -5 8 7 2 9 -2\n8 1 9 7 8 2 5 10 3\n2 7 10\n8 8 7 1 4 2 5 10 9\n2 7 5\n8 9 3 6 4 8 1 2 10\n2 9 2\n8 4 2 9 1 10 7 5 3\n2 3 6\n8 2 8 5 9 4 1 6 10\n2 5 2\n? 1\n? 3... | 1,584,529,575 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 3,000 | 15,769,600 | from collections import defaultdict
n,m,q=map(int,input().split())
a=list(map(int,input().split()))
value=defaultdict(lambda:0)
sets=[]
for i in range(n):
value[i+1]=a[i]
for _ in range(m):
temp=list(map(int,input().split()))
sets.append(temp[1:])
for _ in range(q):
temp=list(input().split())... | Title: Subset Sums
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a*1,<=*a*2,<=...,<=*a**n* and *m* sets *S*1,<=*S*2,<=...,<=*S**m* of indices of elements of this array. Let's denote *S**k*<==<={*S**k*,<=*i*} (1<=≤<=*i*<=≤<=|*S**k*|). In other words, *S**k*,<=*i* i... | ```python
from collections import defaultdict
n,m,q=map(int,input().split())
a=list(map(int,input().split()))
value=defaultdict(lambda:0)
sets=[]
for i in range(n):
value[i+1]=a[i]
for _ in range(m):
temp=list(map(int,input().split()))
sets.append(temp[1:])
for _ in range(q):
temp=list(input(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,699,429,337 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | games = int(input())
uniforms = []
for i in range(games):
uniforms.extend(map(int, input().split()))
store = set()
tempoStore = set()
counter = 0
for i in range(0 , len(uniforms) ,2):
store.add(uniforms[i])
for i in range(1, len(uniforms), 2):
if(tempoStore.issuperset({uniforms[i]}))... | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
games = int(input())
uniforms = []
for i in range(games):
uniforms.extend(map(int, input().split()))
store = set()
tempoStore = set()
counter = 0
for i in range(0 , len(uniforms) ,2):
store.add(uniforms[i])
for i in range(1, len(uniforms), 2):
if(tempoStore.issuperset({unif... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
485 | A | Factory | PROGRAMMING | 1,400 | [
"implementation",
"math",
"matrices"
] | null | null | One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the factory has to produce (remainder after dividing *x* by *m*) more details. Unfortunately, no cu... | The first line contains two integers *a* and *m* (1<=≤<=*a*,<=*m*<=≤<=105). | Print "Yes" (without quotes) if the production will eventually stop, otherwise print "No". | [
"1 5\n",
"3 6\n"
] | [
"No\n",
"Yes\n"
] | none | 1,000 | [
{
"input": "1 5",
"output": "No"
},
{
"input": "3 6",
"output": "Yes"
},
{
"input": "1 8",
"output": "Yes"
},
{
"input": "2 3",
"output": "No"
},
{
"input": "3 24",
"output": "Yes"
},
{
"input": "1 1",
"output": "Yes"
},
{
"input": "100000 ... | 1,415,259,436 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 62 | 0 | a,m = map(int,input().split())
while a%m and a<m: a += a%m
print('No' if a%m else 'Yes') | Title: Factory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One industrial factory is reforming working plan. The director suggested to set a mythical detail production norm. If at the beginning of the day there were *x* details in the factory storage, then by the end of the day the fac... | ```python
a,m = map(int,input().split())
while a%m and a<m: a += a%m
print('No' if a%m else 'Yes')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,665,502,564 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 93 | 204,800 | som = 0
a,b,c,d=map(int,input().split())
z=input()
for i in range(len(z)):
if(z[i] == '1'):
som+=a
if(z[i] == '2'):
som+=b
if(z[i] == '3'):
som+=c
if(z[i] == '4'):
som+=d
print(som) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
som = 0
a,b,c,d=map(int,input().split())
z=input()
for i in range(len(z)):
if(z[i] == '1'):
som+=a
if(z[i] == '2'):
som+=b
if(z[i] == '3'):
som+=c
if(z[i] == '4'):
som+=d
print(som)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
701 | C | They Are Everywhere | PROGRAMMING | 1,500 | [
"binary search",
"strings",
"two pointers"
] | null | null | Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is ... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*. | Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house. | [
"3\nAaA\n",
"7\nbcAAcbc\n",
"6\naaBCCe\n"
] | [
"2\n",
"3\n",
"5\n"
] | In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | 1,000 | [
{
"input": "3\nAaA",
"output": "2"
},
{
"input": "7\nbcAAcbc",
"output": "3"
},
{
"input": "6\naaBCCe",
"output": "5"
},
{
"input": "1\nA",
"output": "1"
},
{
"input": "1\ng",
"output": "1"
},
{
"input": "52\nabcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQ... | 1,642,308,104 | 2,147,483,647 | PyPy 3 | OK | TESTS | 80 | 109 | 2,662,400 | import sys
n = int(input())
st = input()
s = {}
for i in range(n):
s[st[i]] = 0
if n == 1:
print('1')
sys.exit(0)
l = 0
r = 0
ln = len(s)
minim = 10**20
Tupes = 0
while Tupes < ln:
if s[st[r]] == 0:
Tupes += 1
s[st[r]] += 1
r += 1
r -= 1
while r < n:
while s[st[l]] > 1:
s[s... | Title: They Are Everywhere
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each ... | ```python
import sys
n = int(input())
st = input()
s = {}
for i in range(n):
s[st[i]] = 0
if n == 1:
print('1')
sys.exit(0)
l = 0
r = 0
ln = len(s)
minim = 10**20
Tupes = 0
while Tupes < ln:
if s[st[r]] == 0:
Tupes += 1
s[st[r]] += 1
r += 1
r -= 1
while r < n:
while s[st[l]] > 1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
940 | A | Points on the line | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"sortings"
] | null | null | We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1,<=3,<=2,<=1} is 2.
D... | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=100,<=0<=≤<=*d*<=≤<=100) — the amount of points and the maximum allowed diameter respectively.
The second line contains *n* space separated integers (1<=≤<=*x**i*<=≤<=100) — the coordinates of the points. | Output a single integer — the minimum number of points you have to remove. | [
"3 1\n2 1 4\n",
"3 0\n7 7 7\n",
"6 3\n1 3 4 6 9 10\n"
] | [
"1\n",
"0\n",
"3\n"
] | In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal stra... | 500 | [
{
"input": "3 1\n2 1 4",
"output": "1"
},
{
"input": "3 0\n7 7 7",
"output": "0"
},
{
"input": "6 3\n1 3 4 6 9 10",
"output": "3"
},
{
"input": "11 5\n10 11 12 13 14 15 16 17 18 19 20",
"output": "5"
},
{
"input": "1 100\n1",
"output": "0"
},
{
"input"... | 1,519,763,402 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 77 | 5,632,000 | n, d = map(int, input().split(" "))
A = list(map(int, input().split(" ")))
lo, ans, cur, idx = A[0], 1, 1, 0
A.sort()
ans = 0
for i in range(0, n):
cur = 0
for j in range(i, n):
if A[j] - A[i] <= d:
cur = cur + 1
else:
break
ans = max(cur, ans)
... | Title: Points on the line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest dista... | ```python
n, d = map(int, input().split(" "))
A = list(map(int, input().split(" ")))
lo, ans, cur, idx = A[0], 1, 1, 0
A.sort()
ans = 0
for i in range(0, n):
cur = 0
for j in range(i, n):
if A[j] - A[i] <= d:
cur = cur + 1
else:
break
ans = max(c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
938 | D | Buy a Ticket | PROGRAMMING | 2,000 | [
"data structures",
"graphs",
"shortest paths"
] | null | null | Musicians of a popular band "Flayer" have announced that they are going to "make their exit" with a world tour. Of course, they will visit Berland as well.
There are *n* cities in Berland. People can travel between cities using two-directional train routes; there are exactly *m* routes, *i*-th route can be used to go ... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=2·105, 1<=≤<=*m*<=≤<=2·105).
Then *m* lines follow, *i*-th contains three integers *v**i*, *u**i* and *w**i* (1<=≤<=*v**i*,<=*u**i*<=≤<=*n*,<=*v**i*<=≠<=*u**i*, 1<=≤<=*w**i*<=≤<=1012) denoting *i*-th train route. There are no multiple train routes connect... | Print *n* integers. *i*-th of them must be equal to the minimum number of coins a person from city *i* has to spend to travel to some city *j* (or possibly stay in city *i*), attend a concert there, and return to city *i* (if *j*<=≠<=*i*). | [
"4 2\n1 2 4\n2 3 7\n6 20 1 25\n",
"3 3\n1 2 1\n2 3 1\n1 3 1\n30 10 20\n"
] | [
"6 14 1 25 \n",
"12 10 12 \n"
] | none | 0 | [
{
"input": "4 2\n1 2 4\n2 3 7\n6 20 1 25",
"output": "6 14 1 25 "
},
{
"input": "3 3\n1 2 1\n2 3 1\n1 3 1\n30 10 20",
"output": "12 10 12 "
},
{
"input": "7 7\n1 6 745325\n2 3 3581176\n2 4 19\n3 6 71263060078\n5 4 141198\n7 4 163953\n5 6 15994\n1 297404206755 82096176217 14663411 1873897... | 1,585,060,542 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 1,840 | 38,707,200 | n, m = map(int, input().split())
edge = [list(map(int, input().split())) for _ in range(m)]
a = list(map(int, input().split()))
g = {}
rg = {}
ans = [float('inf')] * (n+1)
def pushRG(u, v):
if u not in rg:
rg[u]=[]
rg[u].append(v)
def pushG(u, v, w):
if u not in g:
... | Title: Buy a Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Musicians of a popular band "Flayer" have announced that they are going to "make their exit" with a world tour. Of course, they will visit Berland as well.
There are *n* cities in Berland. People can travel between cities... | ```python
n, m = map(int, input().split())
edge = [list(map(int, input().split())) for _ in range(m)]
a = list(map(int, input().split()))
g = {}
rg = {}
ans = [float('inf')] * (n+1)
def pushRG(u, v):
if u not in rg:
rg[u]=[]
rg[u].append(v)
def pushG(u, v, w):
if u ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
735 | C | Tennis Championship | PROGRAMMING | 1,600 | [
"combinatorics",
"constructive algorithms",
"greedy",
"math"
] | null | null | Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are st... | The only line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=1018) — the number of players to participate in the tournament. | Print the maximum number of games in which the winner of the tournament can take part. | [
"2\n",
"3\n",
"4\n",
"10\n"
] | [
"1\n",
"2\n",
"2\n",
"4\n"
] | In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't p... | 1,750 | [
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "2"
},
{
"input": "10",
"output": "4"
},
{
"input": "1000",
"output": "14"
},
{
"input": "2500",
"output": "15"
},
{
"input": "690000",
"output"... | 1,647,766,511 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <cstdio>
#include <vector>
#include <iostream>
using namespace std;
typedef long long LL;
ll a[120]; int main ()
{
ll n; A[1] = 2; A[2] = 3;
scanf ("%lld", &n); for (int i = 3; i < i++)
{
A[i] = a[i-1] + a[i-2];
}
for (int i = 1; i < i++)
{
if (A[i] > N)
{
pri... | Title: Tennis Championship
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be *n* players participating, and the tournament will follow knockout rules from the very firs... | ```python
#include <cstdio>
#include <vector>
#include <iostream>
using namespace std;
typedef long long LL;
ll a[120]; int main ()
{
ll n; A[1] = 2; A[2] = 3;
scanf ("%lld", &n); for (int i = 3; i < i++)
{
A[i] = a[i-1] + a[i-2];
}
for (int i = 1; i < i++)
{
if (A[i] > N)
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,644,381,964 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 92 | 0 | def find(i):
Arr=["a","A","e","E","i","I","o","O","u","U"]
n=ord(A[i])
if(n>=97 and n<=122):
s=0
for j in Arr:
if(A[i]==j):
s=1
break
if(s==1):
print("YES")
else:
print("NO")
else:
f... | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
def find(i):
Arr=["a","A","e","E","i","I","o","O","u","U"]
n=ord(A[i])
if(n>=97 and n<=122):
s=0
for j in Arr:
if(A[i]==j):
s=1
break
if(s==1):
print("YES")
else:
print("NO")
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,609,564,459 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 0 | s=input()
l=0
u=0
for x in s:
if x>='a' and x<='z':
l+=1
elif x>='A' and x<='Z':
u+=1
ans=''
if l<u :
ans=s.upper()
elif l>=u:
ans=s.lower()
print(ans) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=input()
l=0
u=0
for x in s:
if x>='a' and x<='z':
l+=1
elif x>='A' and x<='Z':
u+=1
ans=''
if l<u :
ans=s.upper()
elif l>=u:
ans=s.lower()
print(ans)
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,679,077,019 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | l = input()
s = ""
i = 0
while True:
if len(l) <= i :
break
if l[i] == ".":
s += "0"
else:
if l[i + 1] == ".":
s += "1"
else:
s += "2"
i += 1
i += 1
print(s) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
l = input()
s = ""
i = 0
while True:
if len(l) <= i :
break
if l[i] == ".":
s += "0"
else:
if l[i + 1] == ".":
s += "1"
else:
s += "2"
i += 1
i += 1
print(s)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
14 | B | Young Photographer | PROGRAMMING | 1,000 | [
"implementation"
] | B. Young Photographer | 2 | 64 | Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. But the problem was that not all the runners passed him. The total amount of sportsmen, training at t... | The first line of the input file contains integers *n* and *x*0 (1<=≤<=*n*<=≤<=100; 0<=≤<=*x*0<=≤<=1000). The following *n* lines contain pairs of integers *a**i*,<=*b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000; *a**i*<=≠<=*b**i*). | Output the required minimum distance in the same units as the positions on the racetrack. If there is no such a position, output -1. | [
"3 3\n0 7\n14 2\n4 6\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "3 3\n0 7\n14 2\n4 6",
"output": "1"
},
{
"input": "1 1\n0 10",
"output": "0"
},
{
"input": "2 2\n1 2\n3 2",
"output": "0"
},
{
"input": "3 2\n1 2\n2 3\n3 4",
"output": "-1"
},
{
"input": "2 4\n10 4\n1 5",
"output": "0"
},
{
"input": "1 10\n... | 1,526,694,364 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 154 | 0 | n,m = map(int,input().split())
s,e=map(int,input().split())
s= min(s,e)
e= max(s,e)
n-=1
while(n):
y=list((map(int,input().split())))
a=min(y)
b=max(y)
if(a>s):s=a
if(b<e):e=b
n-=1
if(b-s<0):print(-1)
elif s<=m<=e : print(0)
else : print((s-m) if m<s else (m-e)) | Title: Young Photographer
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Among other things, Bob is keen on photography. Especially he likes to take pictures of sportsmen. That was the reason why he placed himself in position *x*0 of a long straight racetrack and got ready to take pictures. Bu... | ```python
n,m = map(int,input().split())
s,e=map(int,input().split())
s= min(s,e)
e= max(s,e)
n-=1
while(n):
y=list((map(int,input().split())))
a=min(y)
b=max(y)
if(a>s):s=a
if(b<e):e=b
n-=1
if(b-s<0):print(-1)
elif s<=m<=e : print(0)
else : print((s-m) if m<s else (m-e))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't rem... | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given... | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you staye... | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,578,668,284 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | n = int(input())
a = input()
bS = a.count("FS")
bF = a.count("SF")
if bS>bF or bS == 0 or bF == 0 or bS == bF:
print("NO")
elif bS<bF:
print("YES") | Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Franci... | ```python
n = int(input())
a = input()
bS = a.count("FS")
bF = a.count("SF")
if bS>bF or bS == 0 or bF == 0 or bS == bF:
print("NO")
elif bS<bF:
print("YES")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,699,789,229 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n, m=list(map(int, input().split()))
d=dict()
output=[]
for _ in range(m):
a, b=list(map(str, input().split()))
d[a]=b
lecture=list(map(str, input().split()))
for i in (lecture):
if len(d[i])>len(i):
output.append(i)
else:
output.append(d[i])
print(*output) | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
n, m=list(map(int, input().split()))
d=dict()
output=[]
for _ in range(m):
a, b=list(map(str, input().split()))
d[a]=b
lecture=list(map(str, input().split()))
for i in (lecture):
if len(d[i])>len(i):
output.append(i)
else:
output.append(d[i])
print(*output)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
5 | C | Longest Regular Bracket Sequence | PROGRAMMING | 1,900 | [
"constructive algorithms",
"data structures",
"dp",
"greedy",
"sortings",
"strings"
] | C. Longest Regular Bracket Sequence | 2 | 256 | This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical expression. For example, sequences «(())()», «()» and «(()(()))» are regular, while «)(», «(()» and «(()))(» are not.... | The first line of the input file contains a non-empty string, consisting of «(» and «)» characters. Its length does not exceed 106. | Print the length of the longest substring that is a regular bracket sequence, and the number of such substrings. If there are no such substrings, write the only line containing "0 1". | [
")((())))(()())\n",
"))(\n"
] | [
"6 2\n",
"0 1\n"
] | none | 0 | [
{
"input": ")((())))(()())",
"output": "6 2"
},
{
"input": "))(",
"output": "0 1"
},
{
"input": "()(())()",
"output": "8 1"
},
{
"input": "((((()(((",
"output": "2 1"
},
{
"input": "))))()())))",
"output": "4 1"
},
{
"input": "(()())()(())()()())())()(... | 1,510,829,413 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 1,996 | 39,936,000 | import sys
from collections import defaultdict
from time import time
from typing import Tuple
OPEN, CLOSE = '(', ')'
def magic(data: Tuple):
open_index, open_num, step = 0, 0, 0
chars_count = len(data) - 1
open_indexes = []
x = []
while step <= chars_count:
char = data[step]
if c... | Title: Longest Regular Bracket Sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
This is yet another problem dealing with regular bracket sequences.
We should remind you that a bracket sequence is called regular, if by inserting «+» and «1» into it we can get a correct mathematical exp... | ```python
import sys
from collections import defaultdict
from time import time
from typing import Tuple
OPEN, CLOSE = '(', ')'
def magic(data: Tuple):
open_index, open_num, step = 0, 0, 0
chars_count = len(data) - 1
open_indexes = []
x = []
while step <= chars_count:
char = data[step]
... | 3.426613 | MatrixStudio/Codeforces-Python-Submissions |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,590,895,032 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 307,200 | n=int(input())
if n<=2:
print(1)
else:
if n%2!=0:
c=0
i=0
while True:
if i%2==0:
n=n-1
c=c+1
else:
n=n-2
c=c+1
i=i+1
print(c)
else:
c=0
i=0
... | Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
n=int(input())
if n<=2:
print(1)
else:
if n%2!=0:
c=0
i=0
while True:
if i%2==0:
n=n-1
c=c+1
else:
n=n-2
c=c+1
i=i+1
print(c)
else:
c=0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,544,182,751 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | ans = ["A","O","U","I","E","Y","a","o","u","i","e","y"]
a = list(input())
if a[-2] in ans: print("YES")
else: print("NO") | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
ans = ["A","O","U","I","E","Y","a","o","u","i","e","y"]
a = list(input())
if a[-2] in ans: print("YES")
else: print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,659,408,358 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 10 | 62 | 0 | a,b,c = map(int,input().split())
print((c//a*a - b//a*a)//a + 1) | Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
a,b,c = map(int,input().split())
print((c//a*a - b//a*a)//a + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,685,530,053 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 51 | 404 | 9,830,400 | def sum_of_digits(n):
return sum(int(digit) for digit in str(n))
def count_spell_applications(n):
count = 0
while n >= 10:
n = sum_of_digits(n)
count += 1
return count
n = int(input())
count = count_spell_applications(n)
print(count)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
def sum_of_digits(n):
return sum(int(digit) for digit in str(n))
def count_spell_applications(n):
count = 0
while n >= 10:
n = sum_of_digits(n)
count += 1
return count
n = int(input())
count = count_spell_applications(n)
print(count)
``` | 3.881311 | MatrixStudio/Codeforces-Python-Submissions |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,583,768,222 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 155 | 0 | n1,n2 = list(map(int, input().split()))
k , m = list(map(int, input().split()))
arrayA = list(map(int, input().split()))
arrayB = list(map(int, input().split()))
countK = k
countM = m
for j in range(0, n2, 1):
for i in range(n1 - 1, -1, -1):
if(arrayA[i] < arrayB[j]):
countK -= 1
if(countK... | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
n1,n2 = list(map(int, input().split()))
k , m = list(map(int, input().split()))
arrayA = list(map(int, input().split()))
arrayB = list(map(int, input().split()))
countK = k
countM = m
for j in range(0, n2, 1):
for i in range(n1 - 1, -1, -1):
if(arrayA[i] < arrayB[j]):
countK -= 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,689,142,684 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n = int(input())
cc = 0
gg = []
for _ in range(n):
h, a = map(int, input().split())
gg.append((h, a))
for k in range(n):
for l in range(n):
if k != l and gg[k][0] == gg[l][1]:
cc += 1
print(cc) | Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
n = int(input())
cc = 0
gg = []
for _ in range(n):
h, a = map(int, input().split())
gg.append((h, a))
for k in range(n):
for l in range(n):
if k != l and gg[k][0] == gg[l][1]:
cc += 1
print(cc)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
845 | C | Two TVs | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of shows.
Each of the next *n* lines contains two integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=109) — starting and ending time of *i*-th show. | If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes). | [
"3\n1 2\n2 3\n4 5\n",
"4\n1 2\n2 3\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 2\n2 3\n4 5",
"output": "YES"
},
{
"input": "4\n1 2\n2 3\n2 3\n1 2",
"output": "NO"
},
{
"input": "4\n0 1\n1 2\n2 3\n3 4",
"output": "YES"
},
{
"input": "3\n1 2\n2 3\n2 4",
"output": "NO"
},
{
"input": "3\n0 100\n0 100\n0 100",
"output": "NO"
... | 1,675,251,383 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 1,700 | 63,283,200 | def column_sorter(column,listt):
if len(listt)<=1:
return listt
else:
mid=len(listt)//2
return merge(column_sorter(0,listt[:mid]),column_sorter(0,listt[mid:]))
def merge(listt1,listt2):
listt=[]
i=0
j=0
while i<len(listt1) and j<len(listt2):
if listt1[i... | Title: Two TVs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He ... | ```python
def column_sorter(column,listt):
if len(listt)<=1:
return listt
else:
mid=len(listt)//2
return merge(column_sorter(0,listt[:mid]),column_sorter(0,listt[mid:]))
def merge(listt1,listt2):
listt=[]
i=0
j=0
while i<len(listt1) and j<len(listt2):
i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
572 | A | Arrays | PROGRAMMING | 900 | [
"sortings"
] | null | null | You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the first array is strictly less than any number chosen in the second array. | The first line contains two integers *n**A*,<=*n**B* (1<=≤<=*n**A*,<=*n**B*<=≤<=105), separated by a space — the sizes of arrays *A* and *B*, correspondingly.
The second line contains two integers *k* and *m* (1<=≤<=*k*<=≤<=*n**A*,<=1<=≤<=*m*<=≤<=*n**B*), separated by a space.
The third line contains *n**A* numbers *... | Print "YES" (without the quotes), if you can choose *k* numbers in array *A* and *m* numbers in array *B* so that any number chosen in array *A* was strictly less than any number chosen in array *B*. Otherwise, print "NO" (without the quotes). | [
"3 3\n2 1\n1 2 3\n3 4 5\n",
"3 3\n3 3\n1 2 3\n3 4 5\n",
"5 2\n3 1\n1 1 1 1 1\n2 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample test you can, for example, choose numbers 1 and 2 from array *A* and number 3 from array *B* (1 < 3 and 2 < 3).
In the second sample test the only way to choose *k* elements in the first array and *m* elements in the second one is to choose all numbers in both arrays, but then not all the num... | 500 | [
{
"input": "3 3\n2 1\n1 2 3\n3 4 5",
"output": "YES"
},
{
"input": "3 3\n3 3\n1 2 3\n3 4 5",
"output": "NO"
},
{
"input": "5 2\n3 1\n1 1 1 1 1\n2 2",
"output": "YES"
},
{
"input": "3 5\n1 1\n5 5 5\n5 5 5 5 5",
"output": "NO"
},
{
"input": "1 1\n1 1\n1\n1",
"ou... | 1,685,195,674 | 2,147,483,647 | PyPy 3 | OK | TESTS | 52 | 296 | 13,926,400 | na,nb=map(int,input().split())
k,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
b.sort(reverse=True)
a1=a[:k]
b1=b[:m]
c=0
if b1[-1]>a1[k-1]:
print("YES")
else:
print("NO") | Title: Arrays
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B* consisting of integers, sorted in non-decreasing order. Check whether it is possible to choose *k* numbers in array *A* and choose *m* numbers in array *B* so that any number chosen in the fi... | ```python
na,nb=map(int,input().split())
k,m=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
b.sort(reverse=True)
a1=a[:k]
b1=b[:m]
c=0
if b1[-1]>a1[k-1]:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are... | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,599,121,259 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 109 | 0 | s=input()
qc=s.count("Q")
ans=0
n=len(s)
dp=[0]*(n+1)
c=0
for i in range(n):
if s[i]=='Q':
c+=1
dp[i]=c
for i in range(n):
if s[i]=="A":
ans+=dp[i]*(qc-dp[i])
print(ans)
| Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ"... | ```python
s=input()
qc=s.count("Q")
ans=0
n=len(s)
dp=[0]*(n+1)
c=0
for i in range(n):
if s[i]=='Q':
c+=1
dp[i]=c
for i in range(n):
if s[i]=="A":
ans+=dp[i]*(qc-dp[i])
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
467 | A | George and Accommodation | PROGRAMMING | 800 | [
"implementation"
] | null | null | George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want to live in the same room. The dormitory has *n* rooms in total. At the moment the *i*-th room has *p**i* peopl... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of rooms.
The *i*-th of the next *n* lines contains two integers *p**i* and *q**i* (0<=≤<=*p**i*<=≤<=*q**i*<=≤<=100) — the number of people who already live in the *i*-th room and the room's capacity. | Print a single integer — the number of rooms where George and Alex can move in. | [
"3\n1 1\n2 2\n3 3\n",
"3\n1 10\n0 10\n10 10\n"
] | [
"0\n",
"2\n"
] | none | 500 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "0"
},
{
"input": "3\n1 10\n0 10\n10 10",
"output": "2"
},
{
"input": "2\n36 67\n61 69",
"output": "2"
},
{
"input": "3\n21 71\n10 88\n43 62",
"output": "3"
},
{
"input": "3\n1 2\n2 3\n3 4",
"output": "0"
},
{
"... | 1,699,717,634 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 30 | 0 | a=int(input())
j=0
count = 0
while j<a:
p,q=map(int,input().split())
if q-p>0:
count+=1
j+=1
print (count)
| Title: George and Accommodation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George has recently entered the BSUCP (Berland State University for Cool Programmers). George has a friend Alex who has also entered the university. Now they are moving into a dormitory.
George and Alex want ... | ```python
a=int(input())
j=0
count = 0
while j<a:
p,q=map(int,input().split())
if q-p>0:
count+=1
j+=1
print (count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The produ... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second... | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,595,738,034 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 218 | 6,963,200 | n = int(input())
arr = list(map(int, input().split()))
negative_cnt = 0
arr1 = []
arr2 = []
arr3 = []
for i in range(0, n):
if arr[i] < 0:
arr1.append(arr[i])
negative_cnt += 1
elif arr[i] > 0:
arr2.append(arr[i])
elif arr[i] == 0:
arr3.append(arr[i])
if len(a... | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. T... | ```python
n = int(input())
arr = list(map(int, input().split()))
negative_cnt = 0
arr1 = []
arr2 = []
arr3 = []
for i in range(0, n):
if arr[i] < 0:
arr1.append(arr[i])
negative_cnt += 1
elif arr[i] > 0:
arr2.append(arr[i])
elif arr[i] == 0:
arr3.append(arr[i])
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 0 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,619,305,218 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 1,433,600 | def solve(a, b):
if (a == b):
return True
if (len(a) == 1):
return False
half_size = len(a) // 2
a1 = a[0:half_size]
a2 = a[half_size:]
b1 = b[0:half_size]
b2 = b[half_size:]
op1 = solve(a1, b1)
op2 = solve(a2, b2)
op3 = solve(a1, b2)
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into t... | ```python
def solve(a, b):
if (a == b):
return True
if (len(a) == 1):
return False
half_size = len(a) // 2
a1 = a[0:half_size]
a2 = a[half_size:]
b1 = b[0:half_size]
b2 = b[half_size:]
op1 = solve(a1, b1)
op2 = solve(a2, b2)
op3 = solve(a1,... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
660 | A | Co-prime Array | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math",
"number theory"
] | null | null | You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
An array is co-prime if any two adjacent numbers of it are co-prime.
In the number theory, two integ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the given array.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | Print integer *k* on the first line — the least number of elements needed to add to the array *a* to make it co-prime.
The second line should contain *n*<=+<=*k* integers *a**j* — the elements of the array *a* after adding *k* elements to it. Note that the new array should be co-prime, so any two adjacent values shoul... | [
"3\n2 7 28\n"
] | [
"1\n2 7 9 28\n"
] | none | 0 | [
{
"input": "3\n2 7 28",
"output": "1\n2 7 1 28"
},
{
"input": "1\n1",
"output": "0\n1"
},
{
"input": "1\n548",
"output": "0\n548"
},
{
"input": "1\n963837006",
"output": "0\n963837006"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "0\n1 1 1 1 1 1 1 1 1 1"... | 1,661,578,737 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def gcd(a, b):
while b != 0:
a, b = b, a % b
return a
def solution():
n = int(input())
vals = list(map(int, input().split()))
i = 0
while i < n:
if gcd(vals[i], vals[i+1]) != 1:
vals.insert(i+1, 1)
i += 2
i += 1
print(*vals)
t = 1
while t:
... | Title: Co-prime Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array of *n* elements, you must make it a co-prime array in as few moves as possible.
In each move you can insert any positive integral number you want not greater than 109 in any place in the array.
A... | ```python
def gcd(a, b):
while b != 0:
a, b = b, a % b
return a
def solution():
n = int(input())
vals = list(map(int, input().split()))
i = 0
while i < n:
if gcd(vals[i], vals[i+1]) != 1:
vals.insert(i+1, 1)
i += 2
i += 1
print(*vals)
t = 1... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in the order of their ids, then the first in this order plays with the second, the third — with the ... | The only line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=256, 1<=≤<=*a*,<=*b*<=≤<=*n*) — the total number of teams, and the ids of the teams that Arkady is interested in.
It is guaranteed that *n* is such that in each round an even number of team advance, and that *a* and *b* are not equal. | In the only line print "Final!" (without quotes), if teams *a* and *b* can meet in the Final.
Otherwise, print a single integer — the number of the round in which teams *a* and *b* can meet. The round are enumerated from 1. | [
"4 1 2\n",
"8 2 6\n",
"8 7 5\n"
] | [
"1\n",
"Final!\n",
"2\n"
] | In the first example teams 1 and 2 meet in the first round.
In the second example teams 2 and 6 can only meet in the third round, which is the Final, if they win all their opponents in earlier rounds.
In the third example the teams with ids 7 and 5 can meet in the second round, if they win their opponents in the firs... | 0 | [
{
"input": "4 1 2",
"output": "1"
},
{
"input": "8 2 6",
"output": "Final!"
},
{
"input": "8 7 5",
"output": "2"
},
{
"input": "128 30 98",
"output": "Final!"
},
{
"input": "256 128 256",
"output": "Final!"
},
{
"input": "256 2 127",
"output": "7"
... | 1,607,151,318 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 108 | 0 | n,a,b =map(int,input().split())
a+=n-1
b+=n-1
cnt = 0
while a!=b:
a=a//2
b=b//2
cnt+=1
if 2**cnt==n:
print("Final!")
else:
print(cnt)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in the ord... | ```python
n,a,b =map(int,input().split())
a+=n-1
b+=n-1
cnt = 0
while a!=b:
a=a//2
b=b//2
cnt+=1
if 2**cnt==n:
print("Final!")
else:
print(cnt)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
938 | A | Word Correction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird and it needs to be replaced. So the word corrector works in such a way: as long as there are two consec... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of letters in word *s* before the correction.
The second line contains a string *s* consisting of exactly *n* lowercase Latin letters — the word before the correction. | Output the word *s* after the correction. | [
"5\nweird\n",
"4\nword\n",
"5\naaeaa\n"
] | [
"werd\n",
"word\n",
"a\n"
] | Explanations of the examples:
1. There is only one replace: weird <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> werd;1. No replace needed since there are no two consecutive vowels;1. aaeaa <i... | 0 | [
{
"input": "5\nweird",
"output": "werd"
},
{
"input": "4\nword",
"output": "word"
},
{
"input": "5\naaeaa",
"output": "a"
},
{
"input": "100\naaaaabbbbboyoyoyoyoyacadabbbbbiuiufgiuiuaahjabbbklboyoyoyoyoyaaaaabbbbbiuiuiuiuiuaaaaabbbbbeyiyuyzyw",
"output": "abbbbbocadabbbbb... | 1,637,982,208 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 0 | length = int(input())
word = list(input())
vowels = "aeiouy"
position = 1
for _ in range(1, length):
if word[position] in vowels and word[position - 1] in vowels:
word.pop(position)
else:
position += 1
print("".join(word))
| Title: Word Correction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Victor tries to write his own text editor, with word correction included. However, the rules of word correction are really strange.
Victor thinks that if a word contains two consecutive vowels, then it's kinda weird an... | ```python
length = int(input())
word = list(input())
vowels = "aeiouy"
position = 1
for _ in range(1, length):
if word[position] in vowels and word[position - 1] in vowels:
word.pop(position)
else:
position += 1
print("".join(word))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,543,384,533 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 124 | 0 | str1=input()
cnt1=0
cnt2=0
cnt3=0
char=""
for s in str1 :
if s=="h" :
cnt1+=1
if cnt1>0 and s=="e" :
cnt2+=1
if cnt2>0 and s=="l" :
cnt3+=1
if cnt3>1 and s=="o" :
print("YES")
char="o"
break
if char!="o" :
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
str1=input()
cnt1=0
cnt2=0
cnt3=0
char=""
for s in str1 :
if s=="h" :
cnt1+=1
if cnt1>0 and s=="e" :
cnt2+=1
if cnt2>0 and s=="l" :
cnt3+=1
if cnt3>1 and s=="o" :
print("YES")
char="o"
break
if char!="o" :
print("NO")
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
804 | B | Minimum number of steps | PROGRAMMING | 1,400 | [
"combinatorics",
"greedy",
"implementation",
"math"
] | null | null | We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substring, our job is done. Print the minimum number of steps we should perform to make our job done modulo 109<=+<... | The first line contains the initial string consisting of letters 'a' and 'b' only with length from 1 to 106. | Print the minimum number of steps modulo 109<=+<=7. | [
"ab\n",
"aab\n"
] | [
"1\n",
"3\n"
] | The first example: "ab" → "bba".
The second example: "aab" → "abba" → "bbaba" → "bbbbaa". | 1,000 | [
{
"input": "ab",
"output": "1"
},
{
"input": "aab",
"output": "3"
},
{
"input": "aaaaabaabababaaaaaba",
"output": "17307"
},
{
"input": "abaabaaabbabaabab",
"output": "1795"
},
{
"input": "abbaa",
"output": "2"
},
{
"input": "abbaaabaabaaaaabbbbaababaa... | 1,541,977,833 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 374 | 3,174,400 | a,b,m=0,0,10**9+7
for i in input()[::-1]:
if i=='b':
b+=1
else:
a+=b
b=(b<<1)%m
print(a%m)
| Title: Minimum number of steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We have a string of letters 'a' and 'b'. We want to perform some operations on it. On each step we choose one of substrings "ab" in the string and replace it with the string "bba". If we have no "ab" as a substr... | ```python
a,b,m=0,0,10**9+7
for i in input()[::-1]:
if i=='b':
b+=1
else:
a+=b
b=(b<<1)%m
print(a%m)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,606,927,054 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 186 | 0 | print("YES" if input() == "".join(list(reversed([x for x in input()]))) else "NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
print("YES" if input() == "".join(list(reversed([x for x in input()]))) else "NO")
``` | 3.9535 | MatrixStudio/Codeforces-Python-Submissions |
559 | B | Equivalent Strings | PROGRAMMING | 1,700 | [
"divide and conquer",
"hashing",
"sortings",
"strings"
] | null | null | Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split string *a* into two halves of the same size *a*1 and *a*2, and string *b* into two halves of the same size ... | The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200<=000 and consists of lowercase English letters. The strings have the same length. | Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. | [
"aaba\nabaa\n",
"aabb\nabab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you should split the first string into strings "aa" and "ba", the second one — into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equival... | 1,000 | [
{
"input": "aaba\nabaa",
"output": "YES"
},
{
"input": "aabb\nabab",
"output": "NO"
},
{
"input": "a\na",
"output": "YES"
},
{
"input": "a\nb",
"output": "NO"
},
{
"input": "ab\nab",
"output": "YES"
},
{
"input": "ab\nba",
"output": "YES"
},
{
... | 1,611,333,117 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 88 | 2,000 | 1,638,400 | def equal(a, b):
if a == b:
return True
if len(a) % 2 != 0:
return False
a1 = a[:len(a) // 2]
a2 = a[len(b) // 2:]
b1 = b[:len(a) // 2]
b2 = b[len(b) // 2:]
return (equal(a1, b1) and equal(a2, b2)) or (equal(a1, b2) and equal(a2, b1))
if __name__ == '__main__':
a = inp... | Title: Equivalent Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings *a* and *b* of equal length are called equivalent in one of the two cases:
1. They are equal. 1. If we split str... | ```python
def equal(a, b):
if a == b:
return True
if len(a) % 2 != 0:
return False
a1 = a[:len(a) // 2]
a2 = a[len(b) // 2:]
b1 = b[:len(a) // 2]
b2 = b[len(b) // 2:]
return (equal(a1, b1) and equal(a2, b2)) or (equal(a1, b2) and equal(a2, b1))
if __name__ == '__main__':
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
597 | A | Divisibility | PROGRAMMING | 1,600 | [
"math"
] | null | null | Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*. | The only line contains three space-separated integers *k*, *a* and *b* (1<=≤<=*k*<=≤<=1018;<=-<=1018<=≤<=*a*<=≤<=*b*<=≤<=1018). | Print the required number. | [
"1 1 10\n",
"2 -4 4\n"
] | [
"10\n",
"5\n"
] | none | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "2 -4 4",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 0 0",
"output": "1"
},
{
"input": "1 0 1",
"output": "2"
},
{
"input": "1 10181 10182",
"output": "2"
},
{
"inpu... | 1,480,946,032 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 77 | 0 | k, a, b = map(int, input().split())
first = a // k * k
if first < a: first += k
last = b // k * k
if last > b: last -= k
# print(first, last)
if last < first:
print(0)
elif last == first:
print(1)
else:
print((last - first) // k + 1)
| Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Find the number of *k*-divisible numbers on the segment [*a*,<=*b*]. In other words you need to find the number of such integer values *x* that *a*<=≤<=*x*<=≤<=*b* and *x* is divisible by *k*.
Input Specification:
The onl... | ```python
k, a, b = map(int, input().split())
first = a // k * k
if first < a: first += k
last = b // k * k
if last > b: last -= k
# print(first, last)
if last < first:
print(0)
elif last == first:
print(1)
else:
print((last - first) // k + 1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
701 | B | Cells Not Under Attack | PROGRAMMING | 1,200 | [
"data structures",
"math"
] | null | null | Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=*min*(100<=000,<=*n*2)) — the size of the board and the number of rooks.
Each of the next *m* lines contains integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the number of the row and the number of the col... | Print *m* integer, the *i*-th of them should be equal to the number of cells that are not under attack after first *i* rooks are put. | [
"3 3\n1 1\n3 1\n2 2\n",
"5 2\n1 5\n5 1\n",
"100000 1\n300 400\n"
] | [
"4 2 0 \n",
"16 9 \n",
"9999800001 \n"
] | On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | 750 | [
{
"input": "3 3\n1 1\n3 1\n2 2",
"output": "4 2 0 "
},
{
"input": "5 2\n1 5\n5 1",
"output": "16 9 "
},
{
"input": "100000 1\n300 400",
"output": "9999800001 "
},
{
"input": "10 4\n2 8\n1 8\n9 8\n6 9",
"output": "81 72 63 48 "
},
{
"input": "30 30\n3 13\n27 23\n18... | 1,679,664,860 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | n,m = map(int,input().split())
xse = set()
yse = set()
pre = 0
samer,samec,tot=0,0,n*n
for num in range(m):
x,y = map(int,input().split())
if x in xse:
samer += 1
pre += n - 1 - num + samer
yse.add(y)
elif y in yse:
samec += 1
pre += n - 1 - num + samec
xse.ad... | Title: Cells Not Under Attack
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's a... | ```python
n,m = map(int,input().split())
xse = set()
yse = set()
pre = 0
samer,samec,tot=0,0,n*n
for num in range(m):
x,y = map(int,input().split())
if x in xse:
samer += 1
pre += n - 1 - num + samer
yse.add(y)
elif y in yse:
samec += 1
pre += n - 1 - num + samec
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,691,958,733 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | lists = input().split()
candle = int(lists[0])
need = int(lists[1])
howmany = candle
while True:
if candle >= need:
candle = int(candle/need)
howmany += candle
else:
break
print(howmany)
| Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
lists = input().split()
candle = int(lists[0])
need = int(lists[1])
howmany = candle
while True:
if candle >= need:
candle = int(candle/need)
howmany += candle
else:
break
print(howmany)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
378 | A | Playing with Dice | PROGRAMMING | 800 | [
"brute force"
] | null | null | Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same difference, it's a draw.
The first player wrote number *a*, the second player wrote number *b*. How many w... | The single line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=6) — the numbers written on the paper by the first and second player, correspondingly. | Print three integers: the number of ways to throw the dice at which the first player wins, the game ends with a draw or the second player wins, correspondingly. | [
"2 5\n",
"2 4\n"
] | [
"3 0 3\n",
"2 1 3\n"
] | The dice is a standard cube-shaped six-sided object with each side containing a number from 1 to 6, and where all numbers on all sides are distinct.
You can assume that number *a* is closer to number *x* than number *b*, if |*a* - *x*| < |*b* - *x*|. | 500 | [
{
"input": "2 5",
"output": "3 0 3"
},
{
"input": "2 4",
"output": "2 1 3"
},
{
"input": "5 3",
"output": "2 1 3"
},
{
"input": "1 6",
"output": "3 0 3"
},
{
"input": "5 1",
"output": "3 1 2"
},
{
"input": "6 3",
"output": "2 0 4"
},
{
"inp... | 1,607,592,084 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 109 | 0 | a,b = map(int,input().split())
aWins = 0
bWins = 0
draws = 0
for x in range(1,7):
if(abs(x-a)<abs(x-b)):
aWins = aWins + 1
elif(abs(x-a)>abs(x-b)):
bWins = bWins + 1
else:
draws = draws + 1
print(aWins,draws,bWins)
| Title: Playing with Dice
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two players are playing a game. First each of them writes an integer from 1 to 6, and then a dice is thrown. The player whose written number got closer to the number on the dice wins. If both payers have the same diff... | ```python
a,b = map(int,input().split())
aWins = 0
bWins = 0
draws = 0
for x in range(1,7):
if(abs(x-a)<abs(x-b)):
aWins = aWins + 1
elif(abs(x-a)>abs(x-b)):
bWins = bWins + 1
else:
draws = draws + 1
print(aWins,draws,bWins)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
332 | B | Maximum Absurdity | PROGRAMMING | 1,500 | [
"data structures",
"dp",
"implementation"
] | null | null | Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on the table of the President of Berland, G.W. Boosch, to be signed.
This time mr. Boosch plans to sign ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=2·105, 0<=<<=2*k*<=≤<=*n*) — the number of laws accepted by the parliament and the length of one segment in the law list, correspondingly. The next line contains *n* integers *x*1,<=*x*2,<=...,<=*x**n* — the absurdity of each law (1<=≤<=*x**i*<=≤<=109). | Print two integers *a*, *b* — the beginning of segments that mr. Boosch should choose. That means that the president signs laws with numbers from segments [*a*; *a*<=+<=*k*<=-<=1] and [*b*; *b*<=+<=*k*<=-<=1]. If there are multiple solutions, print the one with the minimum number *a*. If there still are multiple soluti... | [
"5 2\n3 6 1 1 6\n",
"6 2\n1 1 1 1 1 1\n"
] | [
"1 4\n",
"1 3\n"
] | In the first sample mr. Boosch signs laws with numbers from segments [1;2] and [4;5]. The total absurdity of the signed laws equals 3 + 6 + 1 + 6 = 16.
In the second sample mr. Boosch signs laws with numbers from segments [1;2] and [3;4]. The total absurdity of the signed laws equals 1 + 1 + 1 + 1 = 4. | 1,000 | [
{
"input": "5 2\n3 6 1 1 6",
"output": "1 4"
},
{
"input": "6 2\n1 1 1 1 1 1",
"output": "1 3"
},
{
"input": "6 2\n1 4 1 2 5 6",
"output": "1 5"
},
{
"input": "4 1\n1 2 2 2",
"output": "2 3"
},
{
"input": "6 3\n15 20 1 15 43 6",
"output": "1 4"
},
{
"i... | 1,689,593,190 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | print("_RANDOM_GUESS_1689593190.7496715")# 1689593190.7496896 | Title: Maximum Absurdity
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Reforms continue entering Berland. For example, during yesterday sitting the Berland Parliament approved as much as *n* laws (each law has been assigned a unique number from 1 to *n*). Today all these laws were put on... | ```python
print("_RANDOM_GUESS_1689593190.7496715")# 1689593190.7496896
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,547,532,042 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 109 | 0 | a,b,c=map(int,input().split())
d=0
ans=0
f=0
i=a
while i<=b:
ans=c**d
d+=1
if ans>=a and ans<=b:
f=1
print(ans,end=" ")
else:
break
i+=1
if f==0:
print(-1) | Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
a,b,c=map(int,input().split())
d=0
ans=0
f=0
i=a
while i<=b:
ans=c**d
d+=1
if ans>=a and ans<=b:
f=1
print(ans,end=" ")
else:
break
i+=1
if f==0:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
510 | A | Fox And Snake | PROGRAMMING | 800 | [
"implementation"
] | null | null | Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*-th cell of *r*-th row as (*r*,<=*c*). The tail of the snake is located at (1,<=1), then it's body ... | The only line contains two integers: *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=50).
*n* is an odd number. | Output *n* lines. Each line should contain a string consisting of *m* characters. Do not output spaces. | [
"3 3\n",
"3 4\n",
"5 3\n",
"9 9\n"
] | [
"###\n..#\n###\n",
"####\n...#\n####\n",
"###\n..#\n###\n#..\n###\n",
"#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#########\n"
] | none | 500 | [
{
"input": "3 3",
"output": "###\n..#\n###"
},
{
"input": "3 4",
"output": "####\n...#\n####"
},
{
"input": "5 3",
"output": "###\n..#\n###\n#..\n###"
},
{
"input": "9 9",
"output": "#########\n........#\n#########\n#........\n#########\n........#\n#########\n#........\n#... | 1,683,044,906 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | a,b=map(int,input().split())
for r in range(1,a+1):
for c in range(1,b+1):
if r%2!=0:
print("*",end="")
elif c==b and r%4!=0:
print("*",end="")
elif c==1 and r%4==0:
print("*",end="")
else:
print(".",end="")
print() | Title: Fox And Snake
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel starts to learn programming. The first task is drawing a fox! However, that turns out to be too hard for a beginner, so she decides to draw a snake instead.
A snake is a pattern on a *n* by *m* table. Denote *c*... | ```python
a,b=map(int,input().split())
for r in range(1,a+1):
for c in range(1,b+1):
if r%2!=0:
print("*",end="")
elif c==b and r%4!=0:
print("*",end="")
elif c==1 and r%4==0:
print("*",end="")
else:
print(".",end="")
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,613,664,531 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 307,200 | n,m=map(int,input().split())
arr=list(map(int,input().split()))
if sum(arr)==n:
ans=0
for i in arr:
ans+=sum(range(i+1))
print(ans)
else:
arr2=arr.copy()
temp=n
ans=0
while temp>0:
k=max(arr)
ind=arr.index(k)
ans+=k
arr[ind]-=1
... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
n,m=map(int,input().split())
arr=list(map(int,input().split()))
if sum(arr)==n:
ans=0
for i in arr:
ans+=sum(range(i+1))
print(ans)
else:
arr2=arr.copy()
temp=n
ans=0
while temp>0:
k=max(arr)
ind=arr.index(k)
ans+=k
arr[ind]-=1... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,619,597,631 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 0 | string = input()
hiedi = ["h", "i", "e", "d", "i"]
count = 0
while len(hiedi) != 0 and count<len(string):
if string[count] == hiedi[0]:
hiedi.remove(hiedi[0])
if len(hiedi) == 0:
print("YES")
else:
print("NO")
| Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a ... | ```python
string = input()
hiedi = ["h", "i", "e", "d", "i"]
count = 0
while len(hiedi) != 0 and count<len(string):
if string[count] == hiedi[0]:
hiedi.remove(hiedi[0])
if len(hiedi) == 0:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,589,214,085 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 109 | 20,172,800 | a =[0]*10
s = list(map(int, input().split()))
for i in s:
a[i] +=1
l_c = 0
l_v = 0
h_v = 0
b_v = 0
h_b_c =0
for i in range(1, 10):
if(a[i]>=4):
# print('first')
l_v = i
l_c = a[i]
if(a[i]>=1 and 4>a[i]):
# print('sec')
h_b_c = a[i]
if(h_v == 0... | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
a =[0]*10
s = list(map(int, input().split()))
for i in s:
a[i] +=1
l_c = 0
l_v = 0
h_v = 0
b_v = 0
h_b_c =0
for i in range(1, 10):
if(a[i]>=4):
# print('first')
l_v = i
l_c = a[i]
if(a[i]>=1 and 4>a[i]):
# print('sec')
h_b_c = a[i]
i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,642,643,887 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 |
a = input()
a = a.replace(' ','')
Vowels = 'aeiouyAEIOUY'
if a[-2] in Vowels:
print('YES')
else:
print('NO') | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
a = input()
a = a.replace(' ','')
Vowels = 'aeiouyAEIOUY'
if a[-2] in Vowels:
print('YES')
else:
print('NO')
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
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