contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
876 | A | Trip For Meal | PROGRAMMING | 900 | [
"math"
] | null | null | Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is *a* meters, between Rabbit's ... | First line contains an integer *n* (1<=≤<=*n*<=≤<=100) — number of visits.
Second line contains an integer *a* (1<=≤<=*a*<=≤<=100) — distance between Rabbit's and Owl's houses.
Third line contains an integer *b* (1<=≤<=*b*<=≤<=100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer *c* ... | Output one number — minimum distance in meters Winnie must go through to have a meal *n* times. | [
"3\n2\n3\n1\n",
"1\n2\n3\n5\n"
] | [
"3\n",
"0\n"
] | In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | 500 | [
{
"input": "3\n2\n3\n1",
"output": "3"
},
{
"input": "1\n2\n3\n5",
"output": "0"
},
{
"input": "10\n1\n8\n3",
"output": "9"
},
{
"input": "7\n10\n5\n6",
"output": "30"
},
{
"input": "9\n9\n7\n5",
"output": "42"
},
{
"input": "9\n37\n85\n76",
"outpu... | 1,508,156,046 | 4,146 | Python 3 | OK | TESTS | 48 | 62 | 5,529,600 | import sys
N = int(sys.stdin.readline())
A = int(sys.stdin.readline())
B = int(sys.stdin.readline())
C = int(sys.stdin.readline())
R = 'R'
O = 'O'
E = 'E'
p = 'R'
ans = 0
for _ in range(N - 1):
if p == R:
if A < B:
ans += A
p = O
else:
ans += B
p =... | Title: Trip For Meal
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair... | ```python
import sys
N = int(sys.stdin.readline())
A = int(sys.stdin.readline())
B = int(sys.stdin.readline())
C = int(sys.stdin.readline())
R = 'R'
O = 'O'
E = 'E'
p = 'R'
ans = 0
for _ in range(N - 1):
if p == R:
if A < B:
ans += A
p = O
else:
ans += B
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
794 | A | Bank Robbery | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and steal some money from the safes. There are many safes arranged in a line, where the *i*-th safe f... | The first line of input contains three space-separated integers, *a*, *b* and *c* (1<=≤<=*b*<=<<=*a*<=<<=*c*<=≤<=109), denoting the positions of Oleg, the first security guard and the second security guard, respectively.
The next line of input contains a single integer *n* (1<=≤<=*n*<=≤<=105), denoting the numbe... | Output a single integer: the maximum number of banknotes Oleg can take. | [
"5 3 7\n8\n4 7 5 5 3 6 2 8\n",
"6 5 7\n5\n1 5 7 92 3\n"
] | [
"4\n",
"0\n"
] | In the first example Oleg can take the banknotes in positions 4, 5, 6 (note that there are 2 banknotes at position 5). Oleg can't take the banknotes in safes 7 and 8 because he can't run into the second security guard. Similarly, Oleg cannot take the banknotes at positions 3 and 2 because he can't run into the first se... | 500 | [
{
"input": "5 3 7\n8\n4 7 5 5 3 6 2 8",
"output": "4"
},
{
"input": "6 5 7\n5\n1 5 7 92 3",
"output": "0"
},
{
"input": "3 2 4\n1\n3",
"output": "1"
},
{
"input": "5 3 8\n12\n8 3 4 5 7 6 8 3 5 4 7 6",
"output": "8"
},
{
"input": "7 3 10\n5\n3 3 3 3 3",
"output... | 1,583,577,764 | 2,147,483,647 | PyPy 3 | OK | TESTS | 46 | 249 | 10,854,400 | n,b,c = map(int, input().split())
v=0
f = int(input())
a = map(int, input().split())
a= list(a)
for i in range(f):
if(n>b and n<c):
if(a[i]<c and a[i]>b):
v+=1
elif (n<b):
if(a[i]<b):
v+=1
elif (n>c):
if(a[i]>c):
v+=1
print (v) | Title: Bank Robbery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A robber has attempted to rob a bank but failed to complete his task. However, he had managed to open all the safes.
Oleg the bank client loves money (who doesn't), and decides to take advantage of this failed robbery and... | ```python
n,b,c = map(int, input().split())
v=0
f = int(input())
a = map(int, input().split())
a= list(a)
for i in range(f):
if(n>b and n<c):
if(a[i]<c and a[i]>b):
v+=1
elif (n<b):
if(a[i]<b):
v+=1
elif (n>c):
if(a[i]>c):
v+=1
print (v)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
639 | C | Bear and Polynomials | PROGRAMMING | 2,200 | [
"hashing",
"implementation",
"math"
] | null | null | Limak is a little polar bear. He doesn't have many toys and thus he often plays with polynomials.
He considers a polynomial valid if its degree is *n* and its coefficients are integers not exceeding *k* by the absolute value. More formally:
Let *a*0,<=*a*1,<=...,<=*a**n* denote the coefficients, so . Then, a polynomi... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=200<=000,<=1<=≤<=*k*<=≤<=109) — the degree of the polynomial and the limit for absolute values of coefficients.
The second line contains *n*<=+<=1 integers *a*0,<=*a*1,<=...,<=*a**n* (|*a**i*|<=≤<=*k*,<=*a**n*<=≠<=0) — describing a valid polynomial . It's... | Print the number of ways to change one coefficient to get a valid polynomial *Q* that *Q*(2)<==<=0. | [
"3 1000000000\n10 -9 -3 5\n",
"3 12\n10 -9 -3 5\n",
"2 20\n14 -7 19\n"
] | [
"3\n",
"2\n",
"0\n"
] | In the first sample, we are given a polynomial *P*(*x*) = 10 - 9*x* - 3*x*<sup class="upper-index">2</sup> + 5*x*<sup class="upper-index">3</sup>.
Limak can change one coefficient in three ways:
1. He can set *a*<sub class="lower-index">0</sub> = - 10. Then he would get *Q*(*x*) = - 10 - 9*x* - 3*x*<sup class="upp... | 1,000 | [
{
"input": "3 1000000000\n10 -9 -3 5",
"output": "3"
},
{
"input": "3 12\n10 -9 -3 5",
"output": "2"
},
{
"input": "2 20\n14 -7 19",
"output": "0"
},
{
"input": "5 5\n0 -4 -2 -2 0 5",
"output": "1"
},
{
"input": "6 10\n-2 -1 7 -3 2 7 -6",
"output": "2"
},
... | 1,489,762,908 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 7 | 2,000 | 20,992,000 | n, k = map(int, input().split())
a = list(map(int, input().split()))
value = 0
for i in range(n+1):
value += a[i] << i
valueBinary = bin(value)[2:]
doubleKBinary = bin(value)[2:]
result = 0
startI = len(valueBinary) - len(doubleKBinary)
delta = value >> startI
for i in range(startI, n+1):
... | Title: Bear and Polynomials
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He doesn't have many toys and thus he often plays with polynomials.
He considers a polynomial valid if its degree is *n* and its coefficients are integers not exceeding *k* by the abs... | ```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
value = 0
for i in range(n+1):
value += a[i] << i
valueBinary = bin(value)[2:]
doubleKBinary = bin(value)[2:]
result = 0
startI = len(valueBinary) - len(doubleKBinary)
delta = value >> startI
for i in range(startI, ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
500 | A | New Year Transportation | PROGRAMMING | 1,000 | [
"dfs and similar",
"graphs",
"implementation"
] | null | null | New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because of the difficulty of escaping the cell. People wanted to meet people who live in other cells.
So, user tncks0... | The first line contains two space-separated integers *n* (3<=≤<=*n*<=≤<=3<=×<=104) and *t* (2<=≤<=*t*<=≤<=*n*) — the number of cells, and the index of the cell which I want to go to.
The second line contains *n*<=-<=1 space-separated integers *a*1,<=*a*2,<=...,<=*a**n*<=-<=1 (1<=≤<=*a**i*<=≤<=*n*<=-<=*i*). It is guara... | If I can go to cell *t* using the transportation system, print "YES". Otherwise, print "NO". | [
"8 4\n1 2 1 2 1 2 1\n",
"8 5\n1 2 1 2 1 1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, the visited cells are: 1, 2, 4; so we can successfully visit the cell 4.
In the second sample, the possible cells to visit are: 1, 2, 4, 6, 7, 8; so we can't visit the cell 5, which we want to visit. | 500 | [
{
"input": "8 4\n1 2 1 2 1 2 1",
"output": "YES"
},
{
"input": "8 5\n1 2 1 2 1 1 1",
"output": "NO"
},
{
"input": "20 19\n13 16 7 6 12 1 5 7 8 6 5 7 5 5 3 3 2 2 1",
"output": "YES"
},
{
"input": "50 49\n11 7 1 41 26 36 19 16 38 14 36 35 37 27 20 27 3 6 21 2 27 11 18 17 19 16 ... | 1,697,575,777 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 62 | 4,608,000 | n, t = list(int(num) for num in input().split())
a = list(int(num) for num in input().split())
location = 1
while location < t:
location = location + a[location - 1];
if location == t:
print('YES')
else:
print('NO') | Title: New Year Transportation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
New Year is coming in Line World! In this world, there are *n* cells numbered by integers from 1 to *n*, as a 1<=×<=*n* board. People live in cells. However, it was hard to move between distinct cells, because o... | ```python
n, t = list(int(num) for num in input().split())
a = list(int(num) for num in input().split())
location = 1
while location < t:
location = location + a[location - 1];
if location == t:
print('YES')
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,691,508,480 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 62 | 0 | p = input()
for i in p:
if i in "HQ9":
print("YES")
break
else:
print("NO")
break | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
p = input()
for i in p:
if i in "HQ9":
print("YES")
break
else:
print("NO")
break
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
625 | A | Guest From the Past | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much more complicated.
Kolya is hungry, so he went to the nearest milk shop. In 2084 you may buy kefir in a plas... | First line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1018) — the number of rubles Kolya has at the beginning.
Then follow three lines containing integers *a*, *b* and *c* (1<=≤<=*a*<=≤<=1018, 1<=≤<=*c*<=<<=*b*<=≤<=1018) — the cost of one plastic liter bottle, the cost of one glass liter bottle and t... | Print the only integer — maximum number of liters of kefir, that Kolya can drink. | [
"10\n11\n9\n8\n",
"10\n5\n6\n1\n"
] | [
"2\n",
"2\n"
] | In the first sample, Kolya can buy one glass bottle, then return it and buy one more glass bottle. Thus he will drink 2 liters of kefir.
In the second sample, Kolya can buy two plastic bottle and get two liters of kefir, or he can buy one liter glass bottle, then return it and buy one plastic bottle. In both cases he ... | 750 | [
{
"input": "10\n11\n9\n8",
"output": "2"
},
{
"input": "10\n5\n6\n1",
"output": "2"
},
{
"input": "2\n2\n2\n1",
"output": "1"
},
{
"input": "10\n3\n3\n1",
"output": "4"
},
{
"input": "10\n1\n2\n1",
"output": "10"
},
{
"input": "10\n2\n3\n1",
"outpu... | 1,455,371,712 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 61 | 0 | n, a, b, c = [int(input()) for i in range(4)]
if b - c >= a:
print(n // a)
else:
if n < b:
print(n // a)
else:
an = 0
an = (n - b) // (b - c)
n -= an * (b - c)
an += max((n // a), [1, 0][n < b])
print(an)
| Title: Guest From the Past
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya Gerasimov loves kefir very much. He lives in year 1984 and knows all the details of buying this delicious drink. One day, as you probably know, he found himself in year 2084, and buying kefir there is much mor... | ```python
n, a, b, c = [int(input()) for i in range(4)]
if b - c >= a:
print(n // a)
else:
if n < b:
print(n // a)
else:
an = 0
an = (n - b) // (b - c)
n -= an * (b - c)
an += max((n // a), [1, 0][n < b])
print(an)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix... | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-sepa... | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,625,408,339 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 405 | 15,155,200 | n = int(input())
lst = [int(i) for i in input().split()]
lst.sort()
for i in range(2):
new_lst = [int(i) for i in input().split()]
new_lst.sort()
#print(new_lst)
#print(lst)
fl = True
for i in range(len(new_lst)):
if new_lst[i] != lst[i]:
print(lst[i])
... | Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler disp... | ```python
n = int(input())
lst = [int(i) for i in input().split()]
lst.sort()
for i in range(2):
new_lst = [int(i) for i in input().split()]
new_lst.sort()
#print(new_lst)
#print(lst)
fl = True
for i in range(len(new_lst)):
if new_lst[i] != lst[i]:
print(lst[i])
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,695,023,852 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 62 | 0 | n=int(input())
ln=[4,7,47,74,447,474,744,747,777]
for i in ln:
if n%i==0:
print('YES')
break
else:
print('NO') | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
n=int(input())
ln=[4,7,47,74,447,474,744,747,777]
for i in ln:
if n%i==0:
print('YES')
break
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
253 | A | Boys and Girls | PROGRAMMING | 1,100 | [
"greedy"
] | null | null | There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to *n*<=+<=*m*. Then the number of integers *i* (1<=≤<=*i*<=<<=*n*<=+<=*m*) such th... | The single line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), separated by a space. | Print a line of *n*<=+<=*m* characters. Print on the *i*-th position of the line character "B", if the *i*-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal *n* and the number of characters "G" should equal *m*. If there are multi... | [
"3 3\n",
"4 2\n"
] | [
"GBGBGB\n",
"BGBGBB\n"
] | In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal. | 500 | [
{
"input": "3 3",
"output": "GBGBGB"
},
{
"input": "4 2",
"output": "BGBGBB"
},
{
"input": "5 5",
"output": "GBGBGBGBGB"
},
{
"input": "6 4",
"output": "BGBGBGBGBB"
},
{
"input": "100 1",
"output": "BGBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB... | 1,658,336,437 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | d=input()
b=int(d[0])
g=int(d[2])
if b>=g:
y="BG"*g+"B"*(b-g)
print(y)
else:
t="GB"*b+"G"*(g-b)
print(t)
| Title: Boys and Girls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* boys and *m* girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by n... | ```python
d=input()
b=int(d[0])
g=int(d[2])
if b>=g:
y="BG"*g+"B"*(b-g)
print(y)
else:
t="GB"*b+"G"*(g-b)
print(t)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
5 | B | Center Alignment | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | B. Center Alignment | 1 | 64 | Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.
You are to implement the alignment in the shortest possible time. Good luck! | The input file consists of one or more lines, each of the lines contains Latin letters, digits and/or spaces. The lines cannot start or end with a space. It is guaranteed that at least one of the lines has positive length. The length of each line and the total amount of the lines do not exceed 1000. | Format the given text, aligning it center. Frame the whole text with characters «*» of the minimum size. If a line cannot be aligned perfectly (for example, the line has even length, while the width of the block is uneven), you should place such lines rounding down the distance to the left or to the right edge and brin... | [
"This is\n\nCodeforces\nBeta\nRound\n5\n",
"welcome to the\nCodeforces\nBeta\nRound 5\n\nand\ngood luck\n"
] | [
"************\n* This is *\n* *\n*Codeforces*\n* Beta *\n* Round *\n* 5 *\n************\n",
"****************\n*welcome to the*\n* Codeforces *\n* Beta *\n* Round 5 *\n* *\n* and *\n* good luck *\n****************\n"
] | none | 0 | [
{
"input": "This is\n\nCodeforces\nBeta\nRound\n5",
"output": "************\n* This is *\n* *\n*Codeforces*\n* Beta *\n* Round *\n* 5 *\n************"
},
{
"input": "welcome to the\nCodeforces\nBeta\nRound 5\n\nand\ngood luck",
"output": "****************\n*welcome to th... | 1,695,139,330 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | # LUOGU_RID: 125264316
def center_align_text(line):
max_width = 1000 # 最大行宽度
left_adjust = True
padding = 0
while len(line) < max_width:
diff = max_width - len(line)
left_padding = diff // 2
right_padding = diff - left_padding
if left_adjust:
... | Title: Center Alignment
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Almost every text editor has a built-in function of center text alignment. The developers of the popular in Berland text editor «Textpad» decided to introduce this functionality into the fourth release of the product.
You ... | ```python
# LUOGU_RID: 125264316
def center_align_text(line):
max_width = 1000 # 最大行宽度
left_adjust = True
padding = 0
while len(line) < max_width:
diff = max_width - len(line)
left_padding = diff // 2
right_padding = diff - left_padding
if left_adjust:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,618,131,311 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 171 | 10,854,400 | n = int(input())
rcola = list(map(int, input().split()))
vcans = list(map(int, input().split()))
vcans.sort(reverse = True)
maxvol = vcans[0]+vcans[1]
if sum(rcola) <= maxvol:
print("YES")
else:
print("NO") | Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
n = int(input())
rcola = list(map(int, input().split()))
vcans = list(map(int, input().split()))
vcans.sort(reverse = True)
maxvol = vcans[0]+vcans[1]
if sum(rcola) <= maxvol:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
681 | B | Economy Game | PROGRAMMING | 1,300 | [
"brute force"
] | null | null | Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, that he found out his game-coin score become equal to 0.
Kolya remembers that at the beginning of the game his game-coin score was equal to *n* and that ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — Kolya's initial game-coin score. | Print "YES" (without quotes) if it's possible that Kolya spent all of his initial *n* coins buying only houses, cars and computers. Otherwise print "NO" (without quotes). | [
"1359257\n",
"17851817\n"
] | [
"YES",
"NO"
] | In the first sample, one of the possible solutions is to buy one house, one car and one computer, spending 1 234 567 + 123 456 + 1234 = 1 359 257 game-coins in total. | 1,000 | [
{
"input": "1359257",
"output": "YES"
},
{
"input": "17851817",
"output": "NO"
},
{
"input": "1000000000",
"output": "YES"
},
{
"input": "17851818",
"output": "YES"
},
{
"input": "438734347",
"output": "YES"
},
{
"input": "43873430",
"output": "YES... | 1,679,663,854 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 1,638,400 | n=int(input(''))
ans=False
for a in range(1,100):
for b in range(1,100):
for c in range ( 1,100):
if((a*1234567+b*123456+c*1234)==n):
ans=True
if ans == True:
print("YES")
else:
print("NO") | Title: Economy Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, that he found out his game-coin score become equal to 0.... | ```python
n=int(input(''))
ans=False
for a in range(1,100):
for b in range(1,100):
for c in range ( 1,100):
if((a*1234567+b*123456+c*1234)==n):
ans=True
if ans == True:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*.
Your task is to find such permutation *p* of length *n*, that the group of number... | The single line of the input contains two space-separated positive integers *n*, *k* (1<=≤<=*k*<=<<=*n*<=≤<=105). | Print *n* integers forming the permutation. If there are multiple answers, print any of them. | [
"3 2\n",
"3 1\n",
"5 2\n"
] | [
"1 3 2\n",
"1 2 3\n",
"1 3 2 4 5\n"
] | By |*x*| we denote the absolute value of number *x*. | 0 | [
{
"input": "3 2",
"output": "1 3 2"
},
{
"input": "3 1",
"output": "1 2 3"
},
{
"input": "5 2",
"output": "1 3 2 4 5"
},
{
"input": "5 4",
"output": "1 5 2 4 3"
},
{
"input": "10 4",
"output": "1 10 2 9 8 7 6 5 4 3"
},
{
"input": "10 3",
"output": ... | 1,662,657,589 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 93 | 7,168,000 | n, k = map(int, input().split())
ch = 1
nch = n
perest = list()
for i in range(k):
if i % 2 == 0:
perest.append(ch)
ch += 1
else:
perest.append(nch)
nch -= 1
if k % 2 == 0:
for i in range(nch, ch - 1, -1):
perest.append(i)
else:
for i in range(ch, nch + 1):
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=... | ```python
n, k = map(int, input().split())
ch = 1
nch = n
perest = list()
for i in range(k):
if i % 2 == 0:
perest.append(ch)
ch += 1
else:
perest.append(nch)
nch -= 1
if k % 2 == 0:
for i in range(nch, ch - 1, -1):
perest.append(i)
else:
for i in range(ch, nch + ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
462 | B | Appleman and Card Game | PROGRAMMING | 1,300 | [
"greedy"
] | null | null | Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally, for each Toastman's card *i* you should calculate how much Toastman's cards have the letter equal to lette... | The first line contains two integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105). The next line contains *n* uppercase letters without spaces — the *i*-th letter describes the *i*-th card of the Appleman. | Print a single integer – the answer to the problem. | [
"15 10\nDZFDFZDFDDDDDDF\n",
"6 4\nYJSNPI\n"
] | [
"82\n",
"4\n"
] | In the first test example Toastman can choose nine cards with letter D and one additional card with any letter. For each card with D he will get 9 coins and for the additional card he will get 1 coin. | 1,000 | [
{
"input": "15 10\nDZFDFZDFDDDDDDF",
"output": "82"
},
{
"input": "6 4\nYJSNPI",
"output": "4"
},
{
"input": "5 3\nAOWBY",
"output": "3"
},
{
"input": "1 1\nV",
"output": "1"
},
{
"input": "2 1\nWT",
"output": "1"
},
{
"input": "2 2\nBL",
"output":... | 1,691,680,723 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 8 | 61 | 0 | n,k = map(int,input().split())
a = list(input())
d = {}
for i in range(n):
if a[i] in d:
d[a[i]] += 1
else:
d[a[i]] = 1
t = 0
for elem in d:
if d[elem] > k:
t += k*k
k = 0
break
else:
t += d[elem]*d[elem]
k -= d[elem]
i... | Title: Appleman and Card Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman has *n* cards. Each card has an uppercase letter written on it. Toastman must choose *k* cards from Appleman's cards. Then Appleman should give Toastman some coins depending on the chosen cards. Formally... | ```python
n,k = map(int,input().split())
a = list(input())
d = {}
for i in range(n):
if a[i] in d:
d[a[i]] += 1
else:
d[a[i]] = 1
t = 0
for elem in d:
if d[elem] > k:
t += k*k
k = 0
break
else:
t += d[elem]*d[elem]
k -= d[elem... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
755 | B | PolandBall and Game | PROGRAMMING | 1,100 | [
"binary search",
"data structures",
"games",
"greedy",
"sortings",
"strings"
] | null | null | PolandBall is playing a game with EnemyBall. The rules are simple. Players have to say words in turns. You cannot say a word which was already said. PolandBall starts. The Ball which can't say a new word loses.
You're given two lists of words familiar to PolandBall and EnemyBall. Can you determine who wins the game, i... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=103) — number of words PolandBall and EnemyBall know, respectively.
Then *n* strings follow, one per line — words familiar to PolandBall.
Then *m* strings follow, one per line — words familiar to EnemyBall.
Note that one Ball cannot know a w... | In a single line of print the answer — "YES" if PolandBall wins and "NO" otherwise. Both Balls play optimally. | [
"5 1\npolandball\nis\na\ncool\ncharacter\nnope\n",
"2 2\nkremowka\nwadowicka\nkremowka\nwiedenska\n",
"1 2\na\na\nb\n"
] | [
"YES",
"YES",
"NO"
] | In the first example PolandBall knows much more words and wins effortlessly.
In the second example if PolandBall says kremowka first, then EnemyBall cannot use that word anymore. EnemyBall can only say wiedenska. PolandBall says wadowicka and wins. | 1,000 | [
{
"input": "5 1\npolandball\nis\na\ncool\ncharacter\nnope",
"output": "YES"
},
{
"input": "2 2\nkremowka\nwadowicka\nkremowka\nwiedenska",
"output": "YES"
},
{
"input": "1 2\na\na\nb",
"output": "NO"
},
{
"input": "2 2\na\nb\nb\nc",
"output": "YES"
},
{
"input": "... | 1,624,383,927 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 1 | 61 | 0 | n, m = map(int, input().split())
a, b = set(), set()
for _ in range(n):
a.add(input())
for _ in range(m):
b.add(input())
if n<m:
print("NO")
elif n>m:
print("YES")
else:
k = a.intersect(b)
print('YES' if len(k)%2 else "NO")
| Title: PolandBall and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
PolandBall is playing a game with EnemyBall. The rules are simple. Players have to say words in turns. You cannot say a word which was already said. PolandBall starts. The Ball which can't say a new word loses.
You... | ```python
n, m = map(int, input().split())
a, b = set(), set()
for _ in range(n):
a.add(input())
for _ in range(m):
b.add(input())
if n<m:
print("NO")
elif n>m:
print("YES")
else:
k = a.intersect(b)
print('YES' if len(k)%2 else "NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,676,140,601 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | n=int(input())
z=[int(i) for i in input().split()]
z=sorted(z)
ma=z[-1]
total=0
for i in range(len(z)):
total=total+(ma-z[i])
print(total)
| Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
n=int(input())
z=[int(i) for i in input().split()]
z=sorted(z)
ma=z[-1]
total=0
for i in range(len(z)):
total=total+(ma-z[i])
print(total)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
92 | A | Chips | PROGRAMMING | 800 | [
"implementation",
"math"
] | A. Chips | 2 | 256 | There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus number 1 sits to the left of the walrus number *n*.
The presenter has *m* chips. The pre... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=50, 1<=≤<=*m*<=≤<=104) — the number of walruses and the number of chips correspondingly. | Print the number of chips the presenter ended up with. | [
"4 11\n",
"17 107\n",
"3 8\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first sample the presenter gives one chip to the walrus number 1, two chips to the walrus number 2, three chips to the walrus number 3, four chips to the walrus number 4, then again one chip to the walrus number 1. After that the presenter runs out of chips. He can't give anything to the walrus number 2 and the ... | 500 | [
{
"input": "4 11",
"output": "0"
},
{
"input": "17 107",
"output": "2"
},
{
"input": "3 8",
"output": "1"
},
{
"input": "46 7262",
"output": "35"
},
{
"input": "32 6864",
"output": "0"
},
{
"input": "36 6218",
"output": "14"
},
{
"input": "... | 1,578,503,506 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 248 | 0 | import itertools
n,m=map(int,input().split())
l=[i for i in range(1,n+1)]
a=itertools.cycle(l)
for i in range(m):
b=next(a)
if(b>m):
print(m)
break
else:
m=m-b | Title: Chips
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There are *n* walruses sitting in a circle. All of them are numbered in the clockwise order: the walrus number 2 sits to the left of the walrus number 1, the walrus number 3 sits to the left of the walrus number 2, ..., the walrus nu... | ```python
import itertools
n,m=map(int,input().split())
l=[i for i in range(1,n+1)]
a=itertools.cycle(l)
for i in range(m):
b=next(a)
if(b>m):
print(m)
break
else:
m=m-b
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
313 | A | Ilya and Bank Account | PROGRAMMING | 900 | [
"implementation",
"number theory"
] | null | null | Ilya is a very clever lion, he lives in an unusual city ZooVille. In this city all the animals have their rights and obligations. Moreover, they even have their own bank accounts. The state of a bank account is an integer. The state of a bank account can be a negative number. This means that the owner of the account ow... | The single line contains integer *n* (10<=≤<=|*n*|<=≤<=109) — the state of Ilya's bank account. | In a single line print an integer — the maximum state of the bank account that Ilya can get. | [
"2230\n",
"-10\n",
"-100003\n"
] | [
"2230\n",
"0\n",
"-10000\n"
] | In the first test sample Ilya doesn't profit from using the present.
In the second test sample you can delete digit 1 and get the state of the account equal to 0. | 500 | [
{
"input": "2230",
"output": "2230"
},
{
"input": "-10",
"output": "0"
},
{
"input": "-100003",
"output": "-10000"
},
{
"input": "544883178",
"output": "544883178"
},
{
"input": "-847251738",
"output": "-84725173"
},
{
"input": "423654797",
"output... | 1,691,948,758 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 92 | 0 | def maximize_bank_account(n):
# Convert the number to a string for easier manipulation
n_str = str(n)
# Check if the number is non-negative
if n >= 0:
# Return the original number
return n
else:
# Try removing the last digit or the digit before last
# and ret... | Title: Ilya and Bank Account
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya is a very clever lion, he lives in an unusual city ZooVille. In this city all the animals have their rights and obligations. Moreover, they even have their own bank accounts. The state of a bank account is an... | ```python
def maximize_bank_account(n):
# Convert the number to a string for easier manipulation
n_str = str(n)
# Check if the number is non-negative
if n >= 0:
# Return the original number
return n
else:
# Try removing the last digit or the digit before last
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
217 | A | Ice Skating | PROGRAMMING | 1,200 | [
"brute force",
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed that in this way it's impossible to get from some snow drifts to some other by any sequence of moves... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of snow drifts. Each of the following *n* lines contains two integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the coordinates of the *i*-th snow drift.
Note that the north direction coinсides with the direction of *Oy* ... | Output the minimal number of snow drifts that need to be created in order for Bajtek to be able to reach any snow drift from any other one. | [
"2\n2 1\n1 2\n",
"2\n2 1\n4 1\n"
] | [
"1\n",
"0\n"
] | none | 500 | [
{
"input": "2\n2 1\n1 2",
"output": "1"
},
{
"input": "2\n2 1\n4 1",
"output": "0"
},
{
"input": "24\n171 35\n261 20\n4 206\n501 446\n961 912\n581 748\n946 978\n463 514\n841 889\n341 466\n842 967\n54 102\n235 261\n925 889\n682 672\n623 636\n268 94\n635 710\n474 510\n697 794\n586 663\n182... | 1,614,105,794 | 2,147,483,647 | PyPy 3 | OK | TESTS | 76 | 374 | 5,836,800 | from typing import List, Tuple
def solv(coords: List[Tuple[int, int]]) -> int:
c1map = dict()
c2map = dict()
for c1, c2 in coords:
if c1 not in c1map:
c1map[c1] = [(c1, c2)]
else:
c1map[c1].append((c1, c2))
if c2 not in c2map:
c2map[c2] = [(c1, ... | Title: Ice Skating
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bajtek is learning to skate on ice. He's a beginner, so his only mode of transportation is pushing off from a snow drift to the north, east, south or west and sliding until he lands in another snow drift. He has noticed tha... | ```python
from typing import List, Tuple
def solv(coords: List[Tuple[int, int]]) -> int:
c1map = dict()
c2map = dict()
for c1, c2 in coords:
if c1 not in c1map:
c1map[c1] = [(c1, c2)]
else:
c1map[c1].append((c1, c2))
if c2 not in c2map:
c2map[c2... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
12 | A | Super Agent | PROGRAMMING | 800 | [
"implementation"
] | A. Super Agent | 2 | 256 | There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparing special agent Pearlo for many years. When, finally, Pearlo learned all secrets of espionage... | Input contains the matrix of three rows of three symbols each. Symbol «X» means that the corresponding button was pressed, and «.» means that is was not pressed. The matrix may contain no «X», also it may contain no «.». | Print YES if the password is symmetric with respect to the central button of the terminal and NO otherwise. | [
"XX.\n...\n.XX\n",
"X.X\nX..\n...\n"
] | [
"YES\n",
"NO\n"
] | If you are not familiar with the term «central symmetry», you may look into http://en.wikipedia.org/wiki/Central_symmetry | 0 | [
{
"input": "XX.\n...\n.XX",
"output": "YES"
},
{
"input": ".X.\n.X.\n.X.",
"output": "YES"
},
{
"input": "XXX\nXXX\nXXX",
"output": "YES"
},
{
"input": "XXX\nX.X\nXXX",
"output": "YES"
},
{
"input": "X..\n.X.\n..X",
"output": "YES"
},
{
"input": "...\n... | 1,642,845,136 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | a = []
c=0
for x in range (1,4):
b=input("")
for y in b:
a.append(y)
for i in range (0,9):
if a[i] == a[8-i]:
c += 1
if c == 9:
print('YES')
else:
print('NO') | Title: Super Agent
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparin... | ```python
a = []
c=0
for x in range (1,4):
b=input("")
for y in b:
a.append(y)
for i in range (0,9):
if a[i] == a[8-i]:
c += 1
if c == 9:
print('YES')
else:
print('NO')
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
608 | A | Saitama Destroys Hotel | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only move down, and has infinite capacity. Floors are numbered from 0 to *s* and elevator initially starts on floor... | The first line of input contains two integers *n* and *s* (1<=≤<=*n*<=≤<=100, 1<=≤<=*s*<=≤<=1000) — the number of passengers and the number of the top floor respectively.
The next *n* lines each contain two space-separated integers *f**i* and *t**i* (1<=≤<=*f**i*<=≤<=*s*, 1<=≤<=*t**i*<=≤<=1000) — the floor and the tim... | Print a single integer — the minimum amount of time in seconds needed to bring all the passengers to floor 0. | [
"3 7\n2 1\n3 8\n5 2\n",
"5 10\n2 77\n3 33\n8 21\n9 12\n10 64\n"
] | [
"11\n",
"79\n"
] | In the first sample, it takes at least 11 seconds to bring all passengers to floor 0. Here is how this could be done:
1. Move to floor 5: takes 2 seconds.
2. Pick up passenger 3.
3. Move to floor 3: takes 2 seconds.
4. Wait for passenger 2 to arrive: takes 4 seconds.
5. Pick up passenger 2.
6. Go to floor 2: take... | 500 | [
{
"input": "3 7\n2 1\n3 8\n5 2",
"output": "11"
},
{
"input": "5 10\n2 77\n3 33\n8 21\n9 12\n10 64",
"output": "79"
},
{
"input": "1 1000\n1000 1000",
"output": "2000"
},
{
"input": "1 1\n1 1",
"output": "2"
},
{
"input": "1 1000\n1 1",
"output": "1000"
},
... | 1,460,673,100 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | ch=input()
d=ch.split()
n=int(d[0])
s=int(d[1])
T=0
dic={}
F=[]
TT=[]
for i in range(n):
ch=input()
d=ch.split()
f=int(d[0])
F.append(f)
t=int(d[1])
TT.append(t)
m=0
for i in range(n-1,-1,-1):
T+=m
if TT[i]-T>0:
T+=TT[i]-T
if i>0:
m=F[i]-F[i-1]
... | Title: Saitama Destroys Hotel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an elevator in one of its other hotels. The elevator is special — it starts on the top floor, can only mo... | ```python
ch=input()
d=ch.split()
n=int(d[0])
s=int(d[1])
T=0
dic={}
F=[]
TT=[]
for i in range(n):
ch=input()
d=ch.split()
f=int(d[0])
F.append(f)
t=int(d[1])
TT.append(t)
m=0
for i in range(n-1,-1,-1):
T+=m
if TT[i]-T>0:
T+=TT[i]-T
if i>0:
m=F[i]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
118 | A | String Task | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
- deletes all the vowels, - inserts a character "." before each consonant, - replaces ... | The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive. | Print the resulting string. It is guaranteed that this string is not empty. | [
"tour\n",
"Codeforces\n",
"aBAcAba\n"
] | [
".t.r\n",
".c.d.f.r.c.s\n",
".b.c.b\n"
] | none | 500 | [
{
"input": "tour",
"output": ".t.r"
},
{
"input": "Codeforces",
"output": ".c.d.f.r.c.s"
},
{
"input": "aBAcAba",
"output": ".b.c.b"
},
{
"input": "obn",
"output": ".b.n"
},
{
"input": "wpwl",
"output": ".w.p.w.l"
},
{
"input": "ggdvq",
"output": "... | 1,695,961,287 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 62 | 0 | n=input()
a=["a","e","i","o","u"]
b="."
n=n.lower()
for i in n:
if i in a:
n=n.replace(i,"")
n=b.join(n)
c=list(n)
c.insert(0,".")
print("".join(c)) | Title: String Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters... | ```python
n=input()
a=["a","e","i","o","u"]
b="."
n=n.lower()
for i in n:
if i in a:
n=n.replace(i,"")
n=b.join(n)
c=list(n)
c.insert(0,".")
print("".join(c))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,664,334,846 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 46 | 0 | from math import floor
a, b = map(int, input().split())
print(min(a, b), int(abs(a-b)/2))
| Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
from math import floor
a, b = map(int, input().split())
print(min(a, b), int(abs(a-b)/2))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
493 | C | Vasya and Basketball | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"data structures",
"implementation",
"sortings",
"two pointers"
] | null | null | Vasya follows a basketball game and marks the distances from which each team makes a throw. He knows that each successful throw has value of either 2 or 3 points. A throw is worth 2 points if the distance it was made from doesn't exceed some value of *d* meters, and a throw is worth 3 points if the distance is larger t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of throws of the first team. Then follow *n* integer numbers — the distances of throws *a**i* (1<=≤<=*a**i*<=≤<=2·109).
Then follows number *m* (1<=≤<=*m*<=≤<=2·105) — the number of the throws of the second team. Then follow *m* integer numbers — ... | Print two numbers in the format a:b — the score that is possible considering the problem conditions where the result of subtraction *a*<=-<=*b* is maximum. If there are several such scores, find the one in which number *a* is maximum. | [
"3\n1 2 3\n2\n5 6\n",
"5\n6 7 8 9 10\n5\n1 2 3 4 5\n"
] | [
"9:6\n",
"15:10\n"
] | none | 2,000 | [
{
"input": "3\n1 2 3\n2\n5 6",
"output": "9:6"
},
{
"input": "5\n6 7 8 9 10\n5\n1 2 3 4 5",
"output": "15:10"
},
{
"input": "5\n1 2 3 4 5\n5\n6 7 8 9 10",
"output": "15:15"
},
{
"input": "3\n1 2 3\n3\n6 4 5",
"output": "9:9"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10... | 1,687,704,700 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 9 | 108 | 10,649,600 | def binpoisk(a, x):
l, r = -1, len(a)
while l + 1 < r:
m = (l + r) // 2
if a[m] <= x:
l = m
else:
r = m
return l
def main():
n = int(input())
a = list(map(int, input().split()))
m = int(input())
b = list(map(int, input().split())... | Title: Vasya and Basketball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya follows a basketball game and marks the distances from which each team makes a throw. He knows that each successful throw has value of either 2 or 3 points. A throw is worth 2 points if the distance it was ma... | ```python
def binpoisk(a, x):
l, r = -1, len(a)
while l + 1 < r:
m = (l + r) // 2
if a[m] <= x:
l = m
else:
r = m
return l
def main():
n = int(input())
a = list(map(int, input().split()))
m = int(input())
b = list(map(int, input(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and ... | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,668,682,510 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 77 | 0 | import sys
from collections import defaultdict
n = int(sys.stdin.readline())
dp = defaultdict(int)
dp["polycarp"] = 1
for _ in range(n):
[f, x, t] = sys.stdin.readline().split()
f = f.lower()
t = t.lower()
dp[f] = dp[t] + 1
print(max(dp.values()))
| Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
... | ```python
import sys
from collections import defaultdict
n = int(sys.stdin.readline())
dp = defaultdict(int)
dp["polycarp"] = 1
for _ in range(n):
[f, x, t] = sys.stdin.readline().split()
f = f.lower()
t = t.lower()
dp[f] = dp[t] + 1
print(max(dp.values()))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
137 | B | Permutation | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | "Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task after some considerable time, the boy asked you to help him.
The sequence of *n* integers is cal... | The first line of the input data contains an integer *n* (1<=≤<=*n*<=≤<=5000) which represents how many numbers are in the sequence. The second line contains a sequence of integers *a**i* (1<=≤<=*a**i*<=≤<=5000,<=1<=≤<=*i*<=≤<=*n*). | Print the only number — the minimum number of changes needed to get the permutation. | [
"3\n3 1 2\n",
"2\n2 2\n",
"5\n5 3 3 3 1\n"
] | [
"0\n",
"1\n",
"2\n"
] | The first sample contains the permutation, which is why no replacements are required.
In the second sample it is enough to replace the first element with the number 1 and that will make the sequence the needed permutation.
In the third sample we can replace the second element with number 4 and the fourth element with... | 1,000 | [
{
"input": "3\n3 1 2",
"output": "0"
},
{
"input": "2\n2 2",
"output": "1"
},
{
"input": "5\n5 3 3 3 1",
"output": "2"
},
{
"input": "5\n6 6 6 6 6",
"output": "5"
},
{
"input": "10\n1 1 2 2 8 8 7 7 9 9",
"output": "5"
},
{
"input": "8\n9 8 7 6 5 4 3 2"... | 1,582,381,352 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 218 | 1,228,800 | x = int(input())
y = list(map(int,input().split()))
print(x- len(set(range(1,x+1))&set(y))) | Title: Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Hey, it's homework time" — thought Polycarpus and of course he started with his favourite subject, IT. Polycarpus managed to solve all tasks but for the last one in 20 minutes. However, as he failed to solve the last task ... | ```python
x = int(input())
y = list(map(int,input().split()))
print(x- len(set(range(1,x+1))&set(y)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
812 | A | Sagheer and Crossroads | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Sagheer is walking in the street when he comes to an intersection of two roads. Each road can be represented as two parts where each part has 3 lanes getting into the intersection (one for each direction) and 3 lanes getting out of the intersection, so we have 4 parts in total. Each part has 4 lights, one for each lane... | The input consists of four lines with each line describing a road part given in a counter-clockwise order.
Each line contains four integers *l*, *s*, *r*, *p* — for the left, straight, right and pedestrian lights, respectively. The possible values are 0 for red light and 1 for green light. | On a single line, print "YES" if an accident is possible, and "NO" otherwise. | [
"1 0 0 1\n0 1 0 0\n0 0 1 0\n0 0 0 1\n",
"0 1 1 0\n1 0 1 0\n1 1 0 0\n0 0 0 1\n",
"1 0 0 0\n0 0 0 1\n0 0 0 0\n1 0 1 0\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first example, some accidents are possible because cars of part 1 can hit pedestrians of parts 1 and 4. Also, cars of parts 2 and 3 can hit pedestrians of part 4.
In the second example, no car can pass the pedestrian crossing of part 4 which is the only green pedestrian light. So, no accident can occur. | 500 | [
{
"input": "1 0 0 1\n0 1 0 0\n0 0 1 0\n0 0 0 1",
"output": "YES"
},
{
"input": "0 1 1 0\n1 0 1 0\n1 1 0 0\n0 0 0 1",
"output": "NO"
},
{
"input": "1 0 0 0\n0 0 0 1\n0 0 0 0\n1 0 1 0",
"output": "NO"
},
{
"input": "0 0 0 0\n0 0 0 1\n0 0 0 1\n0 0 0 1",
"output": "NO"
},
... | 1,496,329,162 | 2,662 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 46 | 0 | print("input")
lines = []
for cuonter in range(0,4):
lines.append(input().split())
accident_possible = False
for row in range(0,4) :
if lines[row][3] == "1" and( lines[(row-1)][2] == "1" or lines[row-2][1] == "1" or lines[row-3][0] == "1" ):
accident_possible = True
break
if acciden... | Title: Sagheer and Crossroads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sagheer is walking in the street when he comes to an intersection of two roads. Each road can be represented as two parts where each part has 3 lanes getting into the intersection (one for each direction) and 3 l... | ```python
print("input")
lines = []
for cuonter in range(0,4):
lines.append(input().split())
accident_possible = False
for row in range(0,4) :
if lines[row][3] == "1" and( lines[(row-1)][2] == "1" or lines[row-2][1] == "1" or lines[row-3][0] == "1" ):
accident_possible = True
break
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
121 | B | Lucky Transformation | PROGRAMMING | 1,500 | [
"strings"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has a number consisting of *n* digits without leading zeroes. He represented it as an array of... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*k*<=≤<=109) — the number of digits in the number and the number of completed operations. The second line contains *n* digits without spaces representing the array of digits *d*, starting with *d*1. It is guaranteed that the first digit of the ... | In the single line print the result without spaces — the number after the *k* operations are fulfilled. | [
"7 4\n4727447\n",
"4 2\n4478\n"
] | [
"4427477\n",
"4478\n"
] | In the first sample the number changes in the following sequence: 4727447 → 4427447 → 4427477 → 4427447 → 4427477.
In the second sample: 4478 → 4778 → 4478. | 1,000 | [
{
"input": "7 4\n4727447",
"output": "4427477"
},
{
"input": "4 2\n4478",
"output": "4478"
},
{
"input": "7 7\n4211147",
"output": "4211177"
},
{
"input": "7 6\n4747477",
"output": "4444477"
},
{
"input": "10 2\n9474444474",
"output": "9774444774"
},
{
... | 1,602,774,097 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 1,331,200 | n,k = map(int,input().split())
arr = list(input())
while k>0:
flag=True
for i in range(n-1):
if arr[i]=='4' and arr[i+1]=='7':
if (i+1)%2==1:
arr[i]='4'
arr[i+1]='4'
else:
arr[i]='7'
... | Title: Lucky Transformation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are ... | ```python
n,k = map(int,input().split())
arr = list(input())
while k>0:
flag=True
for i in range(n-1):
if arr[i]=='4' and arr[i+1]=='7':
if (i+1)%2==1:
arr[i]='4'
arr[i+1]='4'
else:
arr[i]='7'
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,684,637,493 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 27 | 124 | 0 | x = [int(x) for x in input().split(" ")]
n = x[0]
k = x[1]
l = x[2]
c = x[3]
d = x[4]
p = x[5]
nl = x[6]
np = x[7]
x = k*l // nl
y = c*d
z = p // np
print(min(x,min(y,z)) // n) | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
x = [int(x) for x in input().split(" ")]
n = x[0]
k = x[1]
l = x[2]
c = x[3]
d = x[4]
p = x[5]
nl = x[6]
np = x[7]
x = k*l // nl
y = c*d
z = p // np
print(min(x,min(y,z)) // n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,671,900,681 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | a,b,c=map(int,input().split())
v=int((a*b*c)**(1/2))
# print(v)
ans=(v/a+v/b+v/c)*4
print(int(ans)) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input S... | ```python
a,b,c=map(int,input().split())
v=int((a*b*c)**(1/2))
# print(v)
ans=(v/a+v/b+v/c)*4
print(int(ans))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
501 | B | Misha and Changing Handles | PROGRAMMING | 1,100 | [
"data structures",
"dsu",
"strings"
] | null | null | Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is already used or that was used at some point.
Misha has a list of handle change requests. After completing the re... | The first line contains integer *q* (1<=≤<=*q*<=≤<=1000), the number of handle change requests.
Next *q* lines contain the descriptions of the requests, one per line.
Each query consists of two non-empty strings *old* and *new*, separated by a space. The strings consist of lowercase and uppercase Latin letters and di... | In the first line output the integer *n* — the number of users that changed their handles at least once.
In the next *n* lines print the mapping between the old and the new handles of the users. Each of them must contain two strings, *old* and *new*, separated by a space, meaning that before the user had handle *old*,... | [
"5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov\n"
] | [
"3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123\n"
] | none | 500 | [
{
"input": "5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov",
"output": "3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123"
},
{
"input": "1\nMisha Vasya",
"output": "1\nMisha Vasya"
},
{
"input": "10\na b\nb c\nc d\nd... | 1,543,283,937 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 124 | 409,600 | import sys
data = sys.stdin.readlines()
nombres = []
relaciones = []
for i in range(int(data[0])):
cambio = data[i+1].strip('\n').split(' ')
if cambio[0] in nombres:
for relacion in relaciones:
if cambio[0] == relacion[-1]:
relacion.append(cambio[1])
nombr... | Title: Misha and Changing Handles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is a... | ```python
import sys
data = sys.stdin.readlines()
nombres = []
relaciones = []
for i in range(int(data[0])):
cambio = data[i+1].strip('\n').split(' ')
if cambio[0] in nombres:
for relacion in relaciones:
if cambio[0] == relacion[-1]:
relacion.append(cambio[1])
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
248 | B | Chilly Willy | PROGRAMMING | 1,400 | [
"math",
"number theory"
] | null | null | Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected with them.
Chilly Willy wants to find the minimum number of length *n*, such that it is simultaneous... | A single input line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | Print a single integer — the answer to the problem without leading zeroes, or "-1" (without the quotes), if the number that meet the problem condition does not exist. | [
"1\n",
"5\n"
] | [
"-1\n",
"10080"
] | none | 1,000 | [
{
"input": "1",
"output": "-1"
},
{
"input": "5",
"output": "10080"
},
{
"input": "6",
"output": "100170"
},
{
"input": "4",
"output": "1050"
},
{
"input": "15",
"output": "100000000000110"
},
{
"input": "16",
"output": "1000000000000050"
},
{
... | 1,509,298,266 | 2,147,483,647 | Python 3 | OK | TESTS | 66 | 1,622 | 307,200 | n = int (input ())
if n <3:
print ("-1")
else:
num = 10 ** (n-1)
while (num%210):
num = num + 1
print(num) | Title: Chilly Willy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chilly Willy loves playing with numbers. He only knows prime numbers that are digits yet. These numbers are 2, 3, 5 and 7. But Willy grew rather bored of such numbers, so he came up with a few games that were connected wit... | ```python
n = int (input ())
if n <3:
print ("-1")
else:
num = 10 ** (n-1)
while (num%210):
num = num + 1
print(num)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,612,350,934 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | a= input()
ref1='abcdefghijklmnopqrstuvwxyz'
ref2= ref1.upper()
low=[]
high=[]
for i in a:
if i in ref1:
low.append(i)
else:
high.append(i)
if len(low)>=len(high):
print(a.lower())
else:
print(a.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
a= input()
ref1='abcdefghijklmnopqrstuvwxyz'
ref2= ref1.upper()
low=[]
high=[]
for i in a:
if i in ref1:
low.append(i)
else:
high.append(i)
if len(low)>=len(high):
print(a.lower())
else:
print(a.upper())
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
936 | A | Save Energy! | PROGRAMMING | 1,700 | [
"binary search",
"implementation",
"math"
] | null | null | Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after *k* minutes after turning on.
During cooking, Julia goes to the kitchen every *d* minutes and turns on the stove if it is turned off. While the cooker is turned off, it stays warm. T... | The single line contains three integers *k*, *d* and *t* (1<=≤<=*k*,<=*d*,<=*t*<=≤<=1018). | Print a single number, the total time of cooking in minutes. The relative or absolute error must not exceed 10<=-<=9.
Namely, let's assume that your answer is *x* and the answer of the jury is *y*. The checker program will consider your answer correct if . | [
"3 2 6\n",
"4 2 20\n"
] | [
"6.5\n",
"20.0\n"
] | In the first example, the chicken will be cooked for 3 minutes on the turned on stove, after this it will be cooked for <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/cce5d3f2f46552034d5ae5d487725705429ec7a5.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Then the chicken will be coo... | 500 | [
{
"input": "3 2 6",
"output": "6.5"
},
{
"input": "4 2 20",
"output": "20.0"
},
{
"input": "8 10 9",
"output": "10.0"
},
{
"input": "43 50 140",
"output": "150.5"
},
{
"input": "251 79 76",
"output": "76.0"
},
{
"input": "892 67 1000",
"output": "1... | 1,519,577,477 | 2,777 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 8 | 1,000 | 5,632,000 | def check(m):
r = m // time
t1 = r * time1 / t + r * time2 / (2 * t)
m %= time
if m < time1:
t2 = m / t
else:
t2 = time1 / t + (m - time1) / (2 * t)
return 1 < t1 + t2
k, d, t = map(int, input().split())
time1 = k
div = (k - 1) // d + 1
time2 = d... | Title: Save Energy!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Julia is going to cook a chicken in the kitchen of her dormitory. To save energy, the stove in the kitchen automatically turns off after *k* minutes after turning on.
During cooking, Julia goes to the kitchen every *d* mi... | ```python
def check(m):
r = m // time
t1 = r * time1 / t + r * time2 / (2 * t)
m %= time
if m < time1:
t2 = m / t
else:
t2 = time1 / t + (m - time1) / (2 * t)
return 1 < t1 + t2
k, d, t = map(int, input().split())
time1 = k
div = (k - 1) // d + 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | B | Sum | PROGRAMMING | 1,500 | [
"math"
] | B. Sum | 2 | 256 | Vasya studies positional numeral systems. Unfortunately, he often forgets to write the base of notation in which the expression is written. Once he saw a note in his notebook saying *a*<=+<=*b*<==<=?, and that the base of the positional notation wasn’t written anywhere. Now Vasya has to choose a base *p* and regard the... | The first letter contains two space-separated numbers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=1000) which represent the given summands. | Print a single number — the length of the longest answer. | [
"78 87\n",
"1 1\n"
] | [
"3\n",
"2\n"
] | none | 1,000 | [
{
"input": "78 87",
"output": "3"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "9 7",
"output": "2"
},
{
"input": "11 11",
"output": "3"
},
{
"input": "43 21",
"output": "3"
},
{
"input": "84 89",
"output": "3"
},
{
"input": "12 34",
... | 1,584,742,578 | 2,147,483,647 | Python 3 | OK | TESTS | 67 | 248 | 307,200 | a, b = tuple(input().split())
base = max([int(let) for let in a+b]) + 1
n1 = n2 = 0
potencia = 1
for let in a[::-1]:
n1 += int(let)*potencia
potencia *= base
potencia = 1
for let in b[::-1]:
n2 += int(let)*potencia
potencia *= base
n = n1 + n2
contador = 0
potencia = 1
while potencia <= n:
pote... | Title: Sum
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya studies positional numeral systems. Unfortunately, he often forgets to write the base of notation in which the expression is written. Once he saw a note in his notebook saying *a*<=+<=*b*<==<=?, and that the base of the positiona... | ```python
a, b = tuple(input().split())
base = max([int(let) for let in a+b]) + 1
n1 = n2 = 0
potencia = 1
for let in a[::-1]:
n1 += int(let)*potencia
potencia *= base
potencia = 1
for let in b[::-1]:
n2 += int(let)*potencia
potencia *= base
n = n1 + n2
contador = 0
potencia = 1
while potencia <= n... | 3.937428 | MatrixStudio/Codeforces-Python-Submissions |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,700,251,536 | 2,676 | Python 3 | OK | TESTS | 28 | 61 | 819,200 | s = input()
t = input()
m = min(len(s), len(t))
i = 1
while i <= m:
if s[-i] != t[-i]:
break
i += 1
print(len(s) - i + len(t) - i + 2) | Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
s = input()
t = input()
m = min(len(s), len(t))
i = 1
while i <= m:
if s[-i] != t[-i]:
break
i += 1
print(len(s) - i + len(t) - i + 2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,615,962,871 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 124 | 0 | l=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,51]
n,m=map(int,input().split())
print(l[l.index(n)+1]==m and "YES" or "NO")
| Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
l=[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,51]
n,m=map(int,input().split())
print(l[l.index(n)+1]==m and "YES" or "NO")
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,591,025,075 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 204,800 | n,m = list(map(int,input().split()))
list = []
ans = 0
for i in range(n):
for j in range(m):
l = list(input())
list.append(l)
for i in range(len(list)):
if "S" not in list[i]:
ans += len(list[i])
list.remove(list[i])
for i in range(m):
flag = 0
for j in range... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
n,m = list(map(int,input().split()))
list = []
ans = 0
for i in range(n):
for j in range(m):
l = list(input())
list.append(l)
for i in range(len(list)):
if "S" not in list[i]:
ans += len(list[i])
list.remove(list[i])
for i in range(m):
flag = 0
for ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,691,893,904 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | n = int(input())
for i in range(n):
magnets = int(input())
count = 0
if "10" in magents:
count += 1
print(count)
| Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
n = int(input())
for i in range(n):
magnets = int(input())
count = 0
if "10" in magents:
count += 1
print(count)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
492 | A | Vanya and Cubes | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya got *n* cubes. He decided to build a pyramid from them. Vanya wants to build the pyramid as follows: the top level of the pyramid must consist of 1 cube, the second level must consist of 1<=+<=2<==<=3 cubes, the third level must have 1<=+<=2<=+<=3<==<=6 cubes, and so on. Thus, the *i*-th level of the pyramid must... | The first line contains integer *n* (1<=≤<=*n*<=≤<=104) — the number of cubes given to Vanya. | Print the maximum possible height of the pyramid in the single line. | [
"1\n",
"25\n"
] | [
"1\n",
"4\n"
] | Illustration to the second sample: | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "25",
"output": "4"
},
{
"input": "2",
"output": "1"
},
{
"input": "4115",
"output": "28"
},
{
"input": "9894",
"output": "38"
},
{
"input": "7969",
"output": "35"
},
{
"input": "6560",
"outpu... | 1,695,303,839 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 46 | 0 | n = int(input())
height = 0
cubes_needed = 0
while cubes_needed <= n:
height += 1
cubes_needed += height * (height + 1) // 2
height -= 1
print(height)
| Title: Vanya and Cubes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya got *n* cubes. He decided to build a pyramid from them. Vanya wants to build the pyramid as follows: the top level of the pyramid must consist of 1 cube, the second level must consist of 1<=+<=2<==<=3 cubes, the t... | ```python
n = int(input())
height = 0
cubes_needed = 0
while cubes_needed <= n:
height += 1
cubes_needed += height * (height + 1) // 2
height -= 1
print(height)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
817 | B | Makes And The Product | PROGRAMMING | 1,500 | [
"combinatorics",
"implementation",
"math",
"sortings"
] | null | null | After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular question: how many triples of indices (*i*,<= *j*,<= *k*) (*i*<=<<=*j*<=<<=*k*), such that *a**i*·*a**j*·*a... | The first line of input contains a positive integer number *n* (3<=≤<=*n*<=≤<=105) — the number of elements in array *a*. The second line contains *n* positive integer numbers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of a given array. | Print one number — the quantity of triples (*i*,<= *j*,<= *k*) such that *i*,<= *j* and *k* are pairwise distinct and *a**i*·*a**j*·*a**k* is minimum possible. | [
"4\n1 1 1 1\n",
"5\n1 3 2 3 4\n",
"6\n1 3 3 1 3 2\n"
] | [
"4\n",
"2\n",
"1\n"
] | In the first example Makes always chooses three ones out of four, and the number of ways to choose them is 4.
In the second example a triple of numbers (1, 2, 3) is chosen (numbers, not indices). Since there are two ways to choose an element 3, then the answer is 2.
In the third example a triple of numbers (1, 1, 2) ... | 0 | [
{
"input": "4\n1 1 1 1",
"output": "4"
},
{
"input": "5\n1 3 2 3 4",
"output": "2"
},
{
"input": "6\n1 3 3 1 3 2",
"output": "1"
},
{
"input": "3\n1000000000 1000000000 1000000000",
"output": "1"
},
{
"input": "4\n1 1 2 2",
"output": "2"
},
{
"input": ... | 1,497,543,381 | 4,281 | Python 3 | WRONG_ANSWER | TESTS | 3 | 218 | 12,083,200 | #!/usr/bin/env python
import sys
INFINITY = 10 ** 20
n = int(sys.stdin.readline())
ary = list(map(int, sys.stdin.readline().split()))
dp1 = [(INFINITY, 1)] * (len(ary))
dp2 = [(INFINITY, 1)] * (len(ary))
dp3 = [(INFINITY, 1)] * (len(ary))
dp1[0] = (ary[0],1)
dp2[1] = (ary[0] * ary[1],1)
dp3[2] = (ary[0] * ary[1] * ar... | Title: Makes And The Product
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After returning from the army Makes received a gift — an array *a* consisting of *n* positive integer numbers. He hadn't been solving problems for a long time, so he became interested to answer a particular questi... | ```python
#!/usr/bin/env python
import sys
INFINITY = 10 ** 20
n = int(sys.stdin.readline())
ary = list(map(int, sys.stdin.readline().split()))
dp1 = [(INFINITY, 1)] * (len(ary))
dp2 = [(INFINITY, 1)] * (len(ary))
dp3 = [(INFINITY, 1)] * (len(ary))
dp1[0] = (ary[0],1)
dp2[1] = (ary[0] * ary[1],1)
dp3[2] = (ary[0] * a... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,684,222,376 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | a = input().split()
lenn = int(a[0])
delitel = int(a[-1])
pencil = 1
for i in range(lenn + 1):
if len(str(pencil)) == lenn:
break
pencil = str(pencil)
pencil += '0'
pencil = int(pencil)
pensil1 = pencil
pensil1 = str(pensil1)
pensil1 += '0'
pensil1 = int(pensil1)
fbbgf = 0
print(p... | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
a = input().split()
lenn = int(a[0])
delitel = int(a[-1])
pencil = 1
for i in range(lenn + 1):
if len(str(pencil)) == lenn:
break
pencil = str(pencil)
pencil += '0'
pencil = int(pencil)
pensil1 = pencil
pensil1 = str(pensil1)
pensil1 += '0'
pensil1 = int(pensil1)
fbbgf = ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,607,962,113 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 47 | 1,000 | 46,899,200 | n = int(input())
m = int(input())
if (n-m) >= 0:
print(m)
else:
print(m % 2**n)
| Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
n = int(input())
m = int(input())
if (n-m) >= 0:
print(m)
else:
print(m % 2**n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
233 | A | Perfect Permutation | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll call number *n* the size of permutation *p*1,<=*p*2,<=...,<=*p**n*.
Nickolas adores permutations. He lik... | A single line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the permutation size. | If a perfect permutation of size *n* doesn't exist, print a single integer -1. Otherwise print *n* distinct integers from 1 to *n*, *p*1,<=*p*2,<=...,<=*p**n* — permutation *p*, that is perfect. Separate printed numbers by whitespaces. | [
"1\n",
"2\n",
"4\n"
] | [
"-1\n",
"2 1 \n",
"2 1 4 3 \n"
] | none | 500 | [
{
"input": "1",
"output": "-1"
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "4",
"output": "2 1 4 3 "
},
{
"input": "3",
"output": "-1"
},
{
"input": "5",
"output": "-1"
},
{
"input": "6",
"output": "2 1 4 3 6 5 "
},
{
"input": "7",
... | 1,655,704,664 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 60 | 0 | n=int(input())
l=[i for i in range(1,n+1)]
if n == 1:
print(-1)
else:
for i in l:
l[i],l[l.index(i)]=i,l[i]
for k in l:
print(k, end=' ') | Title: Perfect Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation is a sequence of integers *p*1,<=*p*2,<=...,<=*p**n*, consisting of *n* distinct positive integers, each of them doesn't exceed *n*. Let's denote the *i*-th element of permutation *p* as *p**i*. We'll ... | ```python
n=int(input())
l=[i for i in range(1,n+1)]
if n == 1:
print(-1)
else:
for i in l:
l[i],l[l.index(i)]=i,l[i]
for k in l:
print(k, end=' ')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
272 | C | Dima and Staircase | PROGRAMMING | 1,500 | [
"data structures",
"implementation"
] | null | null | Dima's got a staircase that consists of *n* stairs. The first stair is at height *a*1, the second one is at *a*2, the last one is at *a**n* (1<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*).
Dima decided to play with the staircase, so he is throwing rectangular boxes at the staircase from above. The *i*-th box has width *w**i... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of stairs in the staircase. The second line contains a non-decreasing sequence, consisting of *n* integers, *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109; *a**i*<=≤<=*a**i*<=+<=1).
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the numbe... | Print *m* integers — for each box the height, where the bottom of the box will be after landing. Print the answers for the boxes in the order, in which the boxes are given in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I... | [
"5\n1 2 3 6 6\n4\n1 1\n3 1\n1 1\n4 3\n",
"3\n1 2 3\n2\n1 1\n3 1\n",
"1\n1\n5\n1 2\n1 10\n1 10\n1 10\n1 10\n"
] | [
"1\n3\n4\n6\n",
"1\n3\n",
"1\n3\n13\n23\n33\n"
] | The first sample are shown on the picture. | 1,500 | [
{
"input": "5\n1 2 3 6 6\n4\n1 1\n3 1\n1 1\n4 3",
"output": "1\n3\n4\n6"
},
{
"input": "3\n1 2 3\n2\n1 1\n3 1",
"output": "1\n3"
},
{
"input": "1\n1\n5\n1 2\n1 10\n1 10\n1 10\n1 10",
"output": "1\n3\n13\n23\n33"
},
{
"input": "8\n6 10 18 23 30 31 31 33\n1\n5 3",
"output":... | 1,550,050,067 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 156 | 0 | def fastio():
import sys
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
MOD = 10**9 + 7
I = ... | Title: Dima and Staircase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima's got a staircase that consists of *n* stairs. The first stair is at height *a*1, the second one is at *a*2, the last one is at *a**n* (1<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*).
Dima decided to play with the st... | ```python
def fastio():
import sys
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
MOD = 10**9... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
938 | B | Run For Your Prize | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are distinct. You start at position 1, your friend — at position 106 (and there is no prize in any of these tw... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the number of prizes.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (2<=≤<=*a**i*<=≤<=106<=-<=1) — the positions of the prizes. No two prizes are located at the same position. Positions are given in ascending order. | Print one integer — the minimum number of seconds it will take to collect all prizes. | [
"3\n2 3 9\n",
"2\n2 999995\n"
] | [
"8\n",
"5\n"
] | In the first example you take all the prizes: take the first at 1, the second at 2 and the third at 8.
In the second example you take the first prize in 1 second and your friend takes the other in 5 seconds, you do this simultaneously, so the total time is 5. | 0 | [
{
"input": "3\n2 3 9",
"output": "8"
},
{
"input": "2\n2 999995",
"output": "5"
},
{
"input": "1\n20",
"output": "19"
},
{
"input": "6\n2 3 500000 999997 999998 999999",
"output": "499999"
},
{
"input": "1\n999999",
"output": "1"
},
{
"input": "1\n5100... | 1,523,282,113 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 13,414,400 | n = int (input())
a = list(input().strip().split(' '))
a = [int (x) for x in a]
l = 1
r = 1e6
ans = 1e7
# print (a)
if n == 0 :
print (0)
else :
while r >= l :
# print (l,r)
mid = int ((l + r) // 2)
count = 0
for i in range (mid) :
if (i + 2) in a :
... | Title: Run For Your Prize
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are di... | ```python
n = int (input())
a = list(input().strip().split(' '))
a = [int (x) for x in a]
l = 1
r = 1e6
ans = 1e7
# print (a)
if n == 0 :
print (0)
else :
while r >= l :
# print (l,r)
mid = int ((l + r) // 2)
count = 0
for i in range (mid) :
if (i + 2) ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
99 | B | Help Chef Gerasim | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | B. Help Chef Gerasim | 0 | 256 | In a far away kingdom young pages help to set the table for the King. As they are terribly mischievous, one needs to keep an eye on the control whether they have set everything correctly. This time the royal chef Gerasim had the impression that the pages have played a prank again: they had poured the juice from one cup... | The first line contains integer *n* — the number of cups on the royal table (1<=≤<=*n*<=≤<=1000). Next *n* lines contain volumes of juice in each cup — non-negative integers, not exceeding 104. | If the pages didn't pour the juice, print "Exemplary pages." (without the quotes). If you can determine the volume of juice poured during exactly one juice pouring, print "*v* ml. from cup #*a* to cup #*b*." (without the quotes), where *v* represents the volume of poured juice, *a* represents the number of the cup from... | [
"5\n270\n250\n250\n230\n250\n",
"5\n250\n250\n250\n250\n250\n",
"5\n270\n250\n249\n230\n250\n"
] | [
"20 ml. from cup #4 to cup #1.\n",
"Exemplary pages.\n",
"Unrecoverable configuration.\n"
] | none | 1,000 | [
{
"input": "5\n270\n250\n250\n230\n250",
"output": "20 ml. from cup #4 to cup #1."
},
{
"input": "5\n250\n250\n250\n250\n250",
"output": "Exemplary pages."
},
{
"input": "5\n270\n250\n249\n230\n250",
"output": "Unrecoverable configuration."
},
{
"input": "4\n200\n190\n210\n20... | 1,643,458,089 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 31 | 0 | # cook your dish here
n = int(input())
m = []
xx = []
for _ in range(n):
m.append(int(input()))
x = set(m)
if len(x) > 3:
print("Unrecoverable configuration.")
elif len(x) == 1:
print("Exemplary pages.")
elif len(x) == 2:
for i in x:
xx.append(m.count(i))
if xx[0]==1 and xx[1]=... | Title: Help Chef Gerasim
Time Limit: 0 seconds
Memory Limit: 256 megabytes
Problem Description:
In a far away kingdom young pages help to set the table for the King. As they are terribly mischievous, one needs to keep an eye on the control whether they have set everything correctly. This time the royal chef Gerasim ... | ```python
# cook your dish here
n = int(input())
m = []
xx = []
for _ in range(n):
m.append(int(input()))
x = set(m)
if len(x) > 3:
print("Unrecoverable configuration.")
elif len(x) == 1:
print("Exemplary pages.")
elif len(x) == 2:
for i in x:
xx.append(m.count(i))
if xx[0]==1 ... | 0 | MatrixStudio/Codeforces-Python-Submissions |
525 | B | Pasha and String | PROGRAMMING | 1,400 | [
"constructive algorithms",
"greedy",
"math",
"strings"
] | null | null | Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given string.
Pasha didn't like his present very much so he decided to change it. After his birthday Pasha ... | The first line of the input contains Pasha's string *s* of length from 2 to 2·105 characters, consisting of lowercase Latin letters.
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=105) — the number of days when Pasha changed his string.
The third line contains *m* space-separated elements *a**i* (1<=≤<... | In the first line of the output print what Pasha's string *s* will look like after *m* days. | [
"abcdef\n1\n2\n",
"vwxyz\n2\n2 2\n",
"abcdef\n3\n1 2 3\n"
] | [
"aedcbf\n",
"vwxyz\n",
"fbdcea\n"
] | none | 750 | [
{
"input": "abcdef\n1\n2",
"output": "aedcbf"
},
{
"input": "vwxyz\n2\n2 2",
"output": "vwxyz"
},
{
"input": "abcdef\n3\n1 2 3",
"output": "fbdcea"
},
{
"input": "jc\n5\n1 1 1 1 1",
"output": "cj"
},
{
"input": "wljqgdlxyc\n13\n3 4 3 3 5 4 4 2 4 4 5 3 3",
"out... | 1,580,307,703 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 20 | 2,000 | 17,510,400 | from collections import defaultdict
x=list(input())
y=int(input())
y=len(x)
a=list(map(int,input().split()))
d=defaultdict(int)
for i in a:
for j in range(i,y//2+1):
d[j]+=1
lol=[*range(1,y//2+1)]
for i in lol:
if d[i]%2:
x[i-1],x[y-i]=x[y-i],x[i-1]
print("".join(x)) ... | Title: Pasha and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given ... | ```python
from collections import defaultdict
x=list(input())
y=int(input())
y=len(x)
a=list(map(int,input().split()))
d=defaultdict(int)
for i in a:
for j in range(i,y//2+1):
d[j]+=1
lol=[*range(1,y//2+1)]
for i in lol:
if d[i]%2:
x[i-1],x[y-i]=x[y-i],x[i-1]
print("".jo... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
757 | A | Gotta Catch Em' All! | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsession. Since he is too young to go out and catch Bulbasaur, he came up with his own way of catching a Bulbas... | Input contains a single line containing a string *s* (1<=<=≤<=<=|*s*|<=<=≤<=<=105) — the text on the front page of the newspaper without spaces and punctuation marks. |*s*| is the length of the string *s*.
The string *s* contains lowercase and uppercase English letters, i.e. . | Output a single integer, the answer to the problem. | [
"Bulbbasaur\n",
"F\n",
"aBddulbasaurrgndgbualdBdsagaurrgndbb\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first case, you could pick: Bulbbasaur.
In the second case, there is no way to pick even a single Bulbasaur.
In the third case, you can rearrange the string to BulbasaurBulbasauraddrgndgddgargndbb to get two words "Bulbasaur". | 500 | [
{
"input": "Bulbbasaur",
"output": "1"
},
{
"input": "F",
"output": "0"
},
{
"input": "aBddulbasaurrgndgbualdBdsagaurrgndbb",
"output": "2"
},
{
"input": "BBBBBBBBBBbbbbbbbbbbuuuuuuuuuullllllllllssssssssssaaaaaaaaaarrrrrrrrrr",
"output": "5"
},
{
"input": "BBBBBBB... | 1,615,484,163 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | s=input()
temp='Bulbasaur'
l=[]
for i in range(0,len(temp)):
if temp[i]=='a':
l.append(int(s.count(temp[i])/2))
if min(l)<=int(s.count('a')/2):
print(min(l))
else:
print(int(s.count(temp[i])/2))
| Title: Gotta Catch Em' All!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bash wants to become a Pokemon master one day. Although he liked a lot of Pokemon, he has always been fascinated by Bulbasaur the most. Soon, things started getting serious and his fascination turned into an obsess... | ```python
s=input()
temp='Bulbasaur'
l=[]
for i in range(0,len(temp)):
if temp[i]=='a':
l.append(int(s.count(temp[i])/2))
if min(l)<=int(s.count('a')/2):
print(min(l))
else:
print(int(s.count(temp[i])/2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
721 | A | One-dimensional Japanese Crossword | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the left of the rows and to the top of the columns, encrypting the corresponding row or column. The number of integers repr... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the length of the row. The second line of the input contains a single string consisting of *n* characters 'B' or 'W', ('B' corresponds to black square, 'W' — to white square in the row that Adaltik drew). | The first line should contain a single integer *k* — the number of integers encrypting the row, e.g. the number of groups of black squares in the row.
The second line should contain *k* integers, encrypting the row, e.g. corresponding to sizes of groups of consecutive black squares in the order from left to right. | [
"3\nBBW\n",
"5\nBWBWB\n",
"4\nWWWW\n",
"4\nBBBB\n",
"13\nWBBBBWWBWBBBW\n"
] | [
"1\n2 ",
"3\n1 1 1 ",
"0\n",
"1\n4 ",
"3\n4 1 3 "
] | The last sample case correspond to the picture in the statement. | 500 | [
{
"input": "3\nBBW",
"output": "1\n2 "
},
{
"input": "5\nBWBWB",
"output": "3\n1 1 1 "
},
{
"input": "4\nWWWW",
"output": "0"
},
{
"input": "4\nBBBB",
"output": "1\n4 "
},
{
"input": "13\nWBBBBWWBWBBBW",
"output": "3\n4 1 3 "
},
{
"input": "1\nB",
... | 1,619,140,196 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 204,800 | def same(a, b):
return a == b
def black(c):
return c == "B"
n = int(input())
s = str(input())
count = 0
temp_size = 1
size = []
for i in range(n - 1):
if same(s[i],s[i+1]) and black(s[i]):
temp_size += 1
continue
elif not black(s[i]):
continue
else:
count += 1
... | Title: One-dimensional Japanese Crossword
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Adaltik discovered japanese crosswords. Japanese crossword is a picture, represented as a table sized *a*<=×<=*b* squares, and each square is colored white or black. There are integers to the... | ```python
def same(a, b):
return a == b
def black(c):
return c == "B"
n = int(input())
s = str(input())
count = 0
temp_size = 1
size = []
for i in range(n - 1):
if same(s[i],s[i+1]) and black(s[i]):
temp_size += 1
continue
elif not black(s[i]):
continue
else:
count +=... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,561,524,369 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 0 | def ChatRoom(text):
requiredText = "hello"
i = 0
for c in text:
if(requiredText[i]==c):
i+=1
if(i==len(requiredText)):
return "YES"
return "NO"
inputText = input()
print(ChatRoom(inputText))
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def ChatRoom(text):
requiredText = "hello"
i = 0
for c in text:
if(requiredText[i]==c):
i+=1
if(i==len(requiredText)):
return "YES"
return "NO"
inputText = input()
print(ChatRoom(inputText))
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,633,996,947 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | for _ in range(0, int(input())):
n, H = map(int, input().split())
a = map(int, input().split())
m, M = sorted(a)[-2:]
v = H // (m + M)
mod = H % (m + M)
print((v) * 2 + (mod > 0) + (mod > M))
| Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
for _ in range(0, int(input())):
n, H = map(int, input().split())
a = map(int, input().split())
m, M = sorted(a)[-2:]
v = H // (m + M)
mod = H % (m + M)
print((v) * 2 + (mod > 0) + (mod > M))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
834 | A | The Useless Toy | PROGRAMMING | 900 | [
"implementation"
] | null | null | Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bought the strange contraption.
Spinners in Sweetland have the form of V-shaped pieces of caramel. Each s... | There are two characters in the first string – the starting and the ending position of a spinner. The position is encoded with one of the following characters: v (ASCII code 118, lowercase v), < (ASCII code 60), ^ (ASCII code 94) or > (ASCII code 62) (see the picture above for reference). Characters are separated... | Output cw, if the direction is clockwise, ccw – if counter-clockwise, and undefined otherwise. | [
"^ >\n1\n",
"< ^\n3\n",
"^ v\n6\n"
] | [
"cw\n",
"ccw\n",
"undefined\n"
] | none | 500 | [
{
"input": "^ >\n1",
"output": "cw"
},
{
"input": "< ^\n3",
"output": "ccw"
},
{
"input": "^ v\n6",
"output": "undefined"
},
{
"input": "^ >\n999999999",
"output": "ccw"
},
{
"input": "> v\n1",
"output": "cw"
},
{
"input": "v <\n1",
"output": "cw"
... | 1,501,589,454 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 62 | 4,608,000 | s = ['^', '>', 'v', '<']
fe = input()
f,e = fe.split()
n = int(input())
b = s.index(f)
e = s.index(e)
if n % 2 == 0:
print('undefined')
else:
n = n % 4
if (b + n) % 4 == e:
print('cw')
else:
print('ccw')
| Title: The Useless Toy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Walking through the streets of Marshmallow City, Slastyona have spotted some merchants selling a kind of useless toy which is very popular nowadays – caramel spinner! Wanting to join the craze, she has immediately bough... | ```python
s = ['^', '>', 'v', '<']
fe = input()
f,e = fe.split()
n = int(input())
b = s.index(f)
e = s.index(e)
if n % 2 == 0:
print('undefined')
else:
n = n % 4
if (b + n) % 4 == e:
print('cw')
else:
print('ccw')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
616 | D | Longest k-Good Segment | PROGRAMMING | 1,600 | [
"binary search",
"data structures",
"two pointers"
] | null | null | The array *a* with *n* integers is given. Let's call the sequence of one or more consecutive elements in *a* segment. Also let's call the segment k-good if it contains no more than *k* different values.
Find any longest k-good segment.
As the input/output can reach huge size it is recommended to use fast input/output... | The first line contains two integers *n*,<=*k* (1<=≤<=*k*<=≤<=*n*<=≤<=5·105) — the number of elements in *a* and the parameter *k*.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=106) — the elements of the array *a*. | Print two integers *l*,<=*r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) — the index of the left and the index of the right ends of some k-good longest segment. If there are several longest segments you can print any of them. The elements in *a* are numbered from 1 to *n* from left to right. | [
"5 5\n1 2 3 4 5\n",
"9 3\n6 5 1 2 3 2 1 4 5\n",
"3 1\n1 2 3\n"
] | [
"1 5\n",
"3 7\n",
"1 1\n"
] | none | 0 | [
{
"input": "5 5\n1 2 3 4 5",
"output": "1 5"
},
{
"input": "9 3\n6 5 1 2 3 2 1 4 5",
"output": "3 7"
},
{
"input": "3 1\n1 2 3",
"output": "1 1"
},
{
"input": "1 1\n747391",
"output": "1 1"
},
{
"input": "5 2\n171230 171230 171230 171230 171230",
"output": "1 ... | 1,687,645,180 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n,k=map(int,input().split())
b=list(map(int,input().split()))
r=0
l=0
m=[]
c=0
while r<n:
if b[r]>k:
m+=[[c,l,r]]
c=0
l=r+1
elif b[r]<=k:
c+=1
r+=1
else:
m+=[[c,l,r]]
print(max(m)[1]+1,max(m)[2])
| Title: Longest k-Good Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The array *a* with *n* integers is given. Let's call the sequence of one or more consecutive elements in *a* segment. Also let's call the segment k-good if it contains no more than *k* different values.
Find any... | ```python
n,k=map(int,input().split())
b=list(map(int,input().split()))
r=0
l=0
m=[]
c=0
while r<n:
if b[r]>k:
m+=[[c,l,r]]
c=0
l=r+1
elif b[r]<=k:
c+=1
r+=1
else:
m+=[[c,l,r]]
print(max(m)[1]+1,max(m)[2])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
779 | B | Weird Rounding | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For example, if *k*<==<=3, in the number 30020 it is enough to delete a single digit (2). In this case, t... | The only line of the input contains two integer numbers *n* and *k* (0<=≤<=*n*<=≤<=2<=000<=000<=000, 1<=≤<=*k*<=≤<=9).
It is guaranteed that the answer exists. All numbers in the input are written in traditional notation of integers, that is, without any extra leading zeros. | Print *w* — the required minimal number of digits to erase. After removing the appropriate *w* digits from the number *n*, the result should have a value that is divisible by 10*k*. The result can start with digit 0 in the single case (the result is zero and written by exactly the only digit 0). | [
"30020 3\n",
"100 9\n",
"10203049 2\n"
] | [
"1\n",
"2\n",
"3\n"
] | In the example 2 you can remove two digits: 1 and any 0. The result is number 0 which is divisible by any number. | 1,000 | [
{
"input": "30020 3",
"output": "1"
},
{
"input": "100 9",
"output": "2"
},
{
"input": "10203049 2",
"output": "3"
},
{
"input": "0 1",
"output": "0"
},
{
"input": "0 9",
"output": "0"
},
{
"input": "100 2",
"output": "0"
},
{
"input": "102... | 1,588,292,957 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | a,b=input().split()
if int(a)<10**int(b):
print(len(a)-1)
else:
c=int(a)%10**int(b)
print(len(str(c))-str(c).count("0")) | Title: Weird Rounding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is crazy about round numbers. He especially likes the numbers divisible by 10*k*.
In the given number of *n* Polycarp wants to remove the least number of digits to get a number that is divisible by 10*k*. For e... | ```python
a,b=input().split()
if int(a)<10**int(b):
print(len(a)-1)
else:
c=int(a)%10**int(b)
print(len(str(c))-str(c).count("0"))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morn... | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and ... | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,695,479,241 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | t, s, x = map(int, input().split())
delta1, delta2 = x - t - 1, x - t - 2
print('YES' if ((x == t or delta1 % s == 0 or delta2 % s == 0)) else 'NO')
| Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times... | ```python
t, s, x = map(int, input().split())
delta1, delta2 = x - t - 1, x - t - 2
print('YES' if ((x == t or delta1 % s == 0 or delta2 % s == 0)) else 'NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
12 | C | Fruits | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"sortings"
] | C. Fruits | 1 | 256 | The spring is coming and it means that a lot of fruits appear on the counters. One sunny day little boy Valera decided to go shopping. He made a list of *m* fruits he wanted to buy. If Valera want to buy more than one fruit of some kind, he includes it into the list several times.
When he came to the fruit stall of A... | The first line of the input contains two integer number *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of price tags (which is equal to the number of different kinds of fruits that Ashot sells) and the number of items in Valera's list. The second line contains *n* space-separated positive integer numbers. Each of t... | Print two numbers *a* and *b* (*a*<=≤<=*b*) — the minimum and the maximum possible sum which Valera may need to buy all fruits from his list. | [
"5 3\n4 2 1 10 5\napple\norange\nmango\n",
"6 5\n3 5 1 6 8 1\npeach\ngrapefruit\nbanana\norange\norange\n"
] | [
"7 19\n",
"11 30\n"
] | none | 0 | [
{
"input": "5 3\n4 2 1 10 5\napple\norange\nmango",
"output": "7 19"
},
{
"input": "6 5\n3 5 1 6 8 1\npeach\ngrapefruit\nbanana\norange\norange",
"output": "11 30"
},
{
"input": "2 2\n91 82\neiiofpfpmemlakcystpun\nmcnzeiiofpfpmemlakcystpunfl",
"output": "173 173"
},
{
"input"... | 1,650,800,274 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 62 | 512,000 | tagno, dicLen = map(int, input().split())
tagarr = [int(x) for x in input().split()]
tagarr = sorted(tagarr)
myDic = {}
arr = []
UID_counter = 0
for _ in range(dicLen):
word = input()
if word not in myDic:
myDic[word] = UID_counter
UID_counter += 1
try:
arr[myDic[word]] += 1
exce... | Title: Fruits
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
The spring is coming and it means that a lot of fruits appear on the counters. One sunny day little boy Valera decided to go shopping. He made a list of *m* fruits he wanted to buy. If Valera want to buy more than one fruit of some ... | ```python
tagno, dicLen = map(int, input().split())
tagarr = [int(x) for x in input().split()]
tagarr = sorted(tagarr)
myDic = {}
arr = []
UID_counter = 0
for _ in range(dicLen):
word = input()
if word not in myDic:
myDic[word] = UID_counter
UID_counter += 1
try:
arr[myDic[word]] += ... | 3.968046 | MatrixStudio/Codeforces-Python-Submissions |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,595,521,739 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 109 | 7,065,600 | n=int(input())
a=list(map(int,input().split()))
b=sorted(a)
store=0
serial=1
count=1
dic={}
i=n-1
while i>=0:
if store!=b[i]:
store=b[i]
dic[b[i]]=serial
count=serial
serial+=1
elif store==b[i]:
serial+=1
i-=1
for i in range(n):
print(dic[a[i... | Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
n=int(input())
a=list(map(int,input().split()))
b=sorted(a)
store=0
serial=1
count=1
dic={}
i=n-1
while i>=0:
if store!=b[i]:
store=b[i]
dic[b[i]]=serial
count=serial
serial+=1
elif store==b[i]:
serial+=1
i-=1
for i in range(n):
pri... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
347 | A | Difference Row | PROGRAMMING | 1,300 | [
"constructive algorithms",
"implementation",
"sortings"
] | null | null | You want to arrange *n* integers *a*1,<=*a*2,<=...,<=*a**n* in some order in a row. Let's define the value of an arrangement as the sum of differences between all pairs of adjacent integers.
More formally, let's denote some arrangement as a sequence of integers *x*1,<=*x*2,<=...,<=*x**n*, where sequence *x* is a permu... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integers *a*1, *a*2, ..., *a**n* (|*a**i*|<=≤<=1000). | Print the required sequence *x*1,<=*x*2,<=...,<=*x**n*. Sequence *x* should be the lexicographically smallest permutation of *a* that corresponds to an arrangement of the largest possible value. | [
"5\n100 -100 50 0 -50\n"
] | [
"100 -50 0 50 -100 \n"
] | In the sample test case, the value of the output arrangement is (100 - ( - 50)) + (( - 50) - 0) + (0 - 50) + (50 - ( - 100)) = 200. No other arrangement has a larger value, and among all arrangements with the value of 200, the output arrangement is the lexicographically smallest one.
Sequence *x*<sub class="lower-inde... | 500 | [
{
"input": "5\n100 -100 50 0 -50",
"output": "100 -50 0 50 -100 "
},
{
"input": "10\n764 -367 0 963 -939 -795 -26 -49 948 -282",
"output": "963 -795 -367 -282 -49 -26 0 764 948 -939 "
},
{
"input": "20\n262 -689 -593 161 -678 -555 -633 -697 369 258 673 50 833 737 -650 198 -651 -621 -396 ... | 1,596,383,522 | 2,147,483,647 | PyPy 3 | OK | TESTS | 16 | 280 | 20,172,800 | length = int(input())
arr = list(map(int, input().split()))
mx = arr.pop(arr.index(max(arr)))
mn = arr.pop(arr.index(min(arr)))
arr.sort()
print(mx, *arr, mn)
| Title: Difference Row
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You want to arrange *n* integers *a*1,<=*a*2,<=...,<=*a**n* in some order in a row. Let's define the value of an arrangement as the sum of differences between all pairs of adjacent integers.
More formally, let's denote ... | ```python
length = int(input())
arr = list(map(int, input().split()))
mx = arr.pop(arr.index(max(arr)))
mn = arr.pop(arr.index(min(arr)))
arr.sort()
print(mx, *arr, mn)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,005 | B | Delete from the Left | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't choose a string if it is empty.
For example:
- by applying a move to the string "where", the result is ... | The first line of the input contains $s$. In the second line of the input contains $t$. Both strings consist only of lowercase Latin letters. The number of letters in each string is between 1 and $2\cdot10^5$, inclusive. | Output the fewest number of moves required. It is possible that, in the end, both strings will be equal to the empty string, and so, are equal to each other. In this case, the answer is obviously the sum of the lengths of the given strings. | [
"test\nwest\n",
"codeforces\nyes\n",
"test\nyes\n",
"b\nab\n"
] | [
"2\n",
"9\n",
"7\n",
"1\n"
] | In the first example, you should apply the move once to the first string and apply the move once to the second string. As a result, both strings will be equal to "est".
In the second example, the move should be applied to the string "codeforces" $8$ times. As a result, the string becomes "codeforces" $\to$ "es". The m... | 0 | [
{
"input": "test\nwest",
"output": "2"
},
{
"input": "codeforces\nyes",
"output": "9"
},
{
"input": "test\nyes",
"output": "7"
},
{
"input": "b\nab",
"output": "1"
},
{
"input": "z\nz",
"output": "0"
},
{
"input": "abacabadabacaba\nabacabadacaba",
... | 1,682,672,413 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 716,800 | s = input()
t = input()
m = 0
for i in range(len(s) + len(t)):
if(s!=t):
if(len(s) == len(t)):
s = s[1:]
t = t[1:]
m = m+2
elif(len(s)>len(t)):
s = s[1:]
m = m+1
else:
t = t[1:]
m = m+1
els... | Title: Delete from the Left
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two strings $s$ and $t$. In a single move, you can choose any of two strings and delete the first (that is, the leftmost) character. After a move, the length of the string decreases by $1$. You can't ... | ```python
s = input()
t = input()
m = 0
for i in range(len(s) + len(t)):
if(s!=t):
if(len(s) == len(t)):
s = s[1:]
t = t[1:]
m = m+2
elif(len(s)>len(t)):
s = s[1:]
m = m+1
else:
t = t[1:]
m = m+... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
450 | A | Jzzhu and Children | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of... | The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). | Output a single integer, representing the number of the last child. | [
"5 2\n1 3 1 4 2\n",
"6 4\n1 1 2 2 3 3\n"
] | [
"4\n",
"6\n"
] | Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the en... | 500 | [
{
"input": "5 2\n1 3 1 4 2",
"output": "4"
},
{
"input": "6 4\n1 1 2 2 3 3",
"output": "6"
},
{
"input": "7 3\n6 1 5 4 2 3 1",
"output": "4"
},
{
"input": "10 5\n2 7 3 6 2 5 1 3 4 5",
"output": "4"
},
{
"input": "100 1\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18... | 1,694,890,201 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 0 | n,m=map(int,input().split())
a=list(map(int,input().split()))
f={}
y=1
for f1 in a:
f[f1]=y
y+=1
y=1
while len(a)>1:
for i in range(len(a)):
d=a[i]-m*y
if d<=0:
del a[i]
break
else:
y+=1
print(f[a[0]]) | Title: Jzzhu and Children
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line ... | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
f={}
y=1
for f1 in a:
f[f1]=y
y+=1
y=1
while len(a)>1:
for i in range(len(a)):
d=a[i]-m*y
if d<=0:
del a[i]
break
else:
y+=1
print(f[a[0]])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,684,984,812 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | N = int(input())
X = [int(x) % 2 for x in input().strip().split()]
S = sum(X)
if (S==1): print(X.index(1)+1)
else: print(X.index(0)+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
N = int(input())
X = [int(x) % 2 for x in input().strip().split()]
S = sum(X)
if (S==1): print(X.index(1)+1)
else: print(X.index(0)+1)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
915 | A | Garden | PROGRAMMING | 900 | [
"implementation"
] | null | null | Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't wat... | The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one ... | Print one integer number — the minimum number of hours required to water the garden. | [
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] | [
"2\n",
"7\n"
] | In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | 0 | [
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 5... | 1,592,331,956 | 2,147,483,647 | Python 3 | OK | TESTS | 83 | 109 | 0 | n, k = map(int, input().split())
a = list(map(int, input().split()))
cur = 0;
for i in range(n):
if (k % a[i] == 0 and a[i] > cur):
cur = a[i]
if (cur == 0):
print(k+1)
else:
print(k//cur) | Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each ... | ```python
n, k = map(int, input().split())
a = list(map(int, input().split()))
cur = 0;
for i in range(n):
if (k % a[i] == 0 and a[i] > cur):
cur = a[i]
if (cur == 0):
print(k+1)
else:
print(k//cur)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
901 | C | Bipartite Segments | PROGRAMMING | 2,300 | [
"binary search",
"data structures",
"dfs and similar",
"dsu",
"graphs",
"two pointers"
] | null | null | You are given an undirected graph with *n* vertices. There are no edge-simple cycles with the even length in it. In other words, there are no cycles of even length that pass each edge at most once. Let's enumerate vertices from 1 to *n*.
You have to answer *q* queries. Each query is described by a segment of vertices... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=3·105, 1<=≤<=*m*<=≤<=3·105) — the number of vertices and the number of edges in the graph.
The next *m* lines describe edges in the graph. The *i*-th of these lines contains two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; *a**i*<=≠<=*b**i*)... | Print *q* numbers, each in new line: the *i*-th of them should be the number of subsegments [*x*;<=*y*] (*l**i*<=≤<=*x*<=≤<=*y*<=≤<=*r**i*), such that the graph that only includes vertices from segment [*x*;<=*y*] and edges between them is bipartite. | [
"6 6\n1 2\n2 3\n3 1\n4 5\n5 6\n6 4\n3\n1 3\n4 6\n1 6\n",
"8 9\n1 2\n2 3\n3 1\n4 5\n5 6\n6 7\n7 8\n8 4\n7 2\n3\n1 8\n1 4\n3 8\n"
] | [
"5\n5\n14\n",
"27\n8\n19\n"
] | The first example is shown on the picture below:
<img class="tex-graphics" src="https://espresso.codeforces.com/01e1d1999228f416613ff64b5d0e0cf984f150b1.png" style="max-width: 100.0%;max-height: 100.0%;"/>
For the first query, all subsegments of [1; 3], except this segment itself, are suitable.
For the first query, ... | 1,750 | [
{
"input": "6 6\n1 2\n2 3\n3 1\n4 5\n5 6\n6 4\n3\n1 3\n4 6\n1 6",
"output": "5\n5\n14"
},
{
"input": "8 9\n1 2\n2 3\n3 1\n4 5\n5 6\n6 7\n7 8\n8 4\n7 2\n3\n1 8\n1 4\n3 8",
"output": "27\n8\n19"
},
{
"input": "12 12\n5 1\n5 11\n1 11\n8 11\n8 9\n5 12\n6 9\n7 11\n9 3\n9 10\n4 12\n10 2\n78\n1... | 1,690,485,353 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1690485353.3863835")# 1690485353.3864033 | Title: Bipartite Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an undirected graph with *n* vertices. There are no edge-simple cycles with the even length in it. In other words, there are no cycles of even length that pass each edge at most once. Let's enumerate ve... | ```python
print("_RANDOM_GUESS_1690485353.3863835")# 1690485353.3864033
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
892 | A | Greed | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he can do this or not! | The first line of the input contains one integer *n* (2<=≤<=*n*<=≤<=100<=000) — number of cola cans.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — volume of remaining cola in cans.
The third line contains *n* space-separated integers that *b*1,<=*b*2,<=...,<... | Print "YES" (without quotes) if it is possible to pour all remaining cola in 2 cans. Otherwise print "NO" (without quotes).
You can print each letter in any case (upper or lower). | [
"2\n3 5\n3 6\n",
"3\n6 8 9\n6 10 12\n",
"5\n0 0 5 0 0\n1 1 8 10 5\n",
"4\n4 1 0 3\n5 2 2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, there are already 2 cans, so the answer is "YES". | 500 | [
{
"input": "2\n3 5\n3 6",
"output": "YES"
},
{
"input": "3\n6 8 9\n6 10 12",
"output": "NO"
},
{
"input": "5\n0 0 5 0 0\n1 1 8 10 5",
"output": "YES"
},
{
"input": "4\n4 1 0 3\n5 2 2 3",
"output": "YES"
},
{
"input": "10\n9 10 24 11 1 7 8 3 28 14\n86 20 34 11 22 9... | 1,659,184,237 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 39 | 108 | 18,739,200 |
_ = int(input())
soda = list(map(int, input().split()))
cans = sorted(list(map(int, input().split())))
max_capacity = cans[-1] + cans[-2]
result = "YES"
for s in soda:
max_capacity -= s
if max_capacity < 0:
result = "NO"
break
print(result) | Title: Greed
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jafar has *n* cans of cola. Each can is described by two integers: remaining volume of cola *a**i* and can's capacity *b**i* (*a**i* <=≤<= *b**i*).
Jafar has decided to pour all remaining cola into just 2 cans, determine if he c... | ```python
_ = int(input())
soda = list(map(int, input().split()))
cans = sorted(list(map(int, input().split())))
max_capacity = cans[-1] + cans[-2]
result = "YES"
for s in soda:
max_capacity -= s
if max_capacity < 0:
result = "NO"
break
print(result)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain nu... | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the son... | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE... | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,681,829,188 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 71 | 156 | 0 | song = input().replace("WUB", " ").strip()
print(song)
| Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consist... | ```python
song = input().replace("WUB", " ").strip()
print(song)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
103 | A | Testing Pants for Sadness | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"math"
] | A. Testing Pants for Sadness | 2 | 256 | The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* questions; the questions are to be answered strictly in the order in which they are given, from question 1 t... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). It is the number of questions in the test. The second line contains space-separated *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=109), the number of answer variants to question *i*. | Print a single number — the minimal number of clicks needed to pass the test it the worst-case scenario.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"2\n1 1\n",
"2\n2 2\n",
"1\n10\n"
] | [
"2",
"5",
"10"
] | Note to the second sample. In the worst-case scenario you will need five clicks:
- the first click selects the first variant to the first question, this answer turns out to be wrong. - the second click selects the second variant to the first question, it proves correct and we move on to the second question; - the ... | 500 | [
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n2 2",
"output": "5"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "3\n2 4 1",
"output": "10"
},
{
"input": "4\n5 5 3 1",
"output": "22"
},
{
"input": "2\n1000000000 1000000000",
"output": "... | 1,587,022,991 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 248 | 0 | from itertools import accumulate
n = int(input())
a = list(map(int, input().split()))
def s(v):
return sum([i+1 for i in range(v)])
s = a[0]
for i in range(1, n):
s += a[i] + i*(a[i]-1)
print(s) | Title: Testing Pants for Sadness
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* q... | ```python
from itertools import accumulate
n = int(input())
a = list(map(int, input().split()))
def s(v):
return sum([i+1 for i in range(v)])
s = a[0]
for i in range(1, n):
s += a[i] + i*(a[i]-1)
print(s)
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
608 | B | Hamming Distance Sum | PROGRAMMING | 1,500 | [
"combinatorics",
"strings"
] | null | null | Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string *s* is denoted |*s*|. The Hamming distance between two strings *s* and *t* of equal length is defined as , where *s**i* is the *i*-th character of *s* and *t**i* is the *i*-th character of *t*. For exam... | The first line of the input contains binary string *a* (1<=≤<=|*a*|<=≤<=200<=000).
The second line of the input contains binary string *b* (|*a*|<=≤<=|*b*|<=≤<=200<=000).
Both strings are guaranteed to consist of characters '0' and '1' only. | Print a single integer — the sum of Hamming distances between *a* and all contiguous substrings of *b* of length |*a*|. | [
"01\n00111\n",
"0011\n0110\n"
] | [
"3\n",
"2\n"
] | For the first sample case, there are four contiguous substrings of *b* of length |*a*|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts ... | 1,000 | [
{
"input": "01\n00111",
"output": "3"
},
{
"input": "0011\n0110",
"output": "2"
},
{
"input": "0\n0",
"output": "0"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "0\n1",
"output": "1"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1... | 1,630,326,398 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 202 | 32,051,200 | a = input()
b = input()
data = len(a) * [0]
cur_count = [0, 0]
for _ in range(len(b) - len(a) + 1):
cur_count[int(b[_])] += 1
data[0] = [cur_count[0], cur_count[1]]
lp, rp = 0, len(b) - len(a)
for i in range(len(b)):
cur_count[int(b[lp])] -= 1
lp += 1
rp += 1
if rp == len(b):
break
cur_... | Title: Hamming Distance Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string *s* is denoted |*s*|. The Hamming distance between two strings *s* and *t* of equal length is de... | ```python
a = input()
b = input()
data = len(a) * [0]
cur_count = [0, 0]
for _ in range(len(b) - len(a) + 1):
cur_count[int(b[_])] += 1
data[0] = [cur_count[0], cur_count[1]]
lp, rp = 0, len(b) - len(a)
for i in range(len(b)):
cur_count[int(b[lp])] -= 1
lp += 1
rp += 1
if rp == len(b):
brea... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
356 | A | Knight Tournament | PROGRAMMING | 1,500 | [
"data structures",
"dsu"
] | null | null | Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tourname... | The first line contains two integers *n*, *m* (2<=≤<=*n*<=≤<=3·105; 1<=≤<=*m*<=≤<=3·105) — the number of knights and the number of fights. Each of the following *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*; *l**i*<=≤<=*x**i*<=≤<=*r**i*) — the description of the *i*-th f... | Print *n* integers. If the *i*-th knight lost, then the *i*-th number should equal the number of the knight that beat the knight number *i*. If the *i*-th knight is the winner, then the *i*-th number must equal 0. | [
"4 3\n1 2 1\n1 3 3\n1 4 4\n",
"8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1\n"
] | [
"3 1 4 0 ",
"0 8 4 6 4 8 6 1 "
] | Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won. | 500 | [
{
"input": "4 3\n1 2 1\n1 3 3\n1 4 4",
"output": "3 1 4 0 "
},
{
"input": "8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1",
"output": "0 8 4 6 4 8 6 1 "
},
{
"input": "2 1\n1 2 1",
"output": "0 1 "
},
{
"input": "2 1\n1 2 2",
"output": "2 0 "
},
{
"input": "3 1\n1 3 1",
"out... | 1,644,761,033 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 3,000 | 7,782,400 | t=lambda:map(int,input().split())
r,p=t();w=[0]*r
for i in range(p):
o,d,k=t()
for j in range(o-1,d):
if w[j]==0 and j!=k-1:w[j]=k
print(*w) | Title: Knight Tournament
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're j... | ```python
t=lambda:map(int,input().split())
r,p=t();w=[0]*r
for i in range(p):
o,d,k=t()
for j in range(o-1,d):
if w[j]==0 and j!=k-1:w[j]=k
print(*w)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
985 | E | Pencils and Boxes | PROGRAMMING | 2,100 | [
"binary search",
"data structures",
"dp",
"greedy",
"two pointers"
] | null | null | Mishka received a gift of multicolored pencils for his birthday! Unfortunately he lives in a monochrome world, where everything is of the same color and only saturation differs. This pack can be represented as a sequence *a*1,<=*a*2,<=...,<=*a**n* of *n* integer numbers — saturation of the color of each pencil. Now Mis... | The first line contains three integer numbers *n*, *k* and *d* (1<=≤<=*k*<=≤<=*n*<=≤<=5·105, 0<=≤<=*d*<=≤<=109) — the number of pencils, minimal size of any non-empty box and maximal difference in saturation between any pair of pencils in the same box, respectively.
The second line contains *n* integer numbers *a*1,<=... | Print "YES" if it's possible to distribute all the pencils into boxes and satisfy all the conditions. Otherwise print "NO". | [
"6 3 10\n7 2 7 7 4 2\n",
"6 2 3\n4 5 3 13 4 10\n",
"3 2 5\n10 16 22\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first example it is possible to distribute pencils into 2 boxes with 3 pencils in each with any distribution. And you also can put all the pencils into the same box, difference of any pair in it won't exceed 10.
In the second example you can split pencils of saturations [4, 5, 3, 4] into 2 boxes of size 2 and p... | 0 | [
{
"input": "6 3 10\n7 2 7 7 4 2",
"output": "YES"
},
{
"input": "6 2 3\n4 5 3 13 4 10",
"output": "YES"
},
{
"input": "3 2 5\n10 16 22",
"output": "NO"
},
{
"input": "8 7 13\n52 85 14 52 92 33 80 85",
"output": "NO"
},
{
"input": "6 4 0\n1 3 2 4 2 1",
"output"... | 1,527,556,493 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 12 | 545 | 35,225,600 | from bisect import bisect
def main():
n, k, d = map(int, input().split())
aa = sorted(map(int, input().split()))
m = aa[-1] - d
def dfs(i):
a = aa[i]
if a and i + k <= n:
if m <= a:
return True
for j in range(i + k, bisect(aa, a + d, i) + 1):
... | Title: Pencils and Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka received a gift of multicolored pencils for his birthday! Unfortunately he lives in a monochrome world, where everything is of the same color and only saturation differs. This pack can be represented as a seque... | ```python
from bisect import bisect
def main():
n, k, d = map(int, input().split())
aa = sorted(map(int, input().split()))
m = aa[-1] - d
def dfs(i):
a = aa[i]
if a and i + k <= n:
if m <= a:
return True
for j in range(i + k, bisect(aa, a + d, i... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
384 | A | Coder | PROGRAMMING | 800 | [
"implementation"
] | null | null | Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or attack) positions (*x*<=+<=1,<=*y*), (*x*–1,<=*y*), (*x*,<=*y*<=+<=1) and (*x*,<=*y*–1).
... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=1000). | On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.
On each of the next *n* lines print *n* characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.
If there are multiple correct answers, you can print any. | [
"2\n"
] | [
"2\nC.\n.C\n"
] | none | 500 | [
{
"input": "2",
"output": "2\nC.\n.C"
},
{
"input": "3",
"output": "5\nC.C\n.C.\nC.C"
},
{
"input": "4",
"output": "8\nC.C.\n.C.C\nC.C.\n.C.C"
},
{
"input": "10",
"output": "50\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C\nC.C.C.C.C.\n.C.C.C.C.C... | 1,669,192,671 | 2,147,483,647 | Python 3 | OK | TESTS | 15 | 374 | 0 | n = int(input())
if n%2 == 0:
count_of_coder = (n//2)*n
else:
count_of_coder = (n//2 + 1)*(n//2) + (n//2)*(n//2) + (n//2 + 1)
coder = []
i = 0
print(count_of_coder)
while i < n:
j = 0
while j < n:
if i%2 == 0:
if j%2 == 0:
coder.append('C')
else:
coder.append('.')
else:
if j%2 ... | Title: Coder
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (*x*,<=*y*), he can move to (or... | ```python
n = int(input())
if n%2 == 0:
count_of_coder = (n//2)*n
else:
count_of_coder = (n//2 + 1)*(n//2) + (n//2)*(n//2) + (n//2 + 1)
coder = []
i = 0
print(count_of_coder)
while i < n:
j = 0
while j < n:
if i%2 == 0:
if j%2 == 0:
coder.append('C')
else:
coder.append('.')
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
928 | C | Dependency management | PROGRAMMING | 1,900 | [
"*special",
"graphs",
"implementation"
] | null | null | Polycarp is currently developing a project in Vaja language and using a popular dependency management system called Vamen. From Vamen's point of view both Vaja project and libraries are treated projects for simplicity.
A project in Vaja has its own uniqie non-empty name consisting of lowercase latin letters with lengt... | The first line contains an only integer *n* (1<=≤<=*n*<=≤<=1<=000) — the number of projects in Vaja.
The following lines contain the project descriptions. Each project is described by a line consisting of its name and version separated by space. The next line gives the number of direct dependencies (from 0 to *n*<=-<=... | Output all Polycarp's project's dependencies in lexicographical order. | [
"4\na 3\n2\nb 1\nc 1\n \nb 2\n0\n \nb 1\n1\nb 2\n \nc 1\n1\nb 2\n",
"9\ncodehorses 5\n3\nwebfrmk 6\nmashadb 1\nmashadb 2\n \ncommons 2\n0\n \nmashadb 3\n0\n \nwebfrmk 6\n2\nmashadb 3\ncommons 2\n \nextra 4\n1\nextra 3\n \nextra 3\n0\n \nextra 1\n0\n \nmashadb 1\n1\nextra 3\n \nmashadb 2\n1\nextra 1\n",
"3\nabc ... | [
"2\nb 1\nc 1\n",
"4\ncommons 2\nextra 1\nmashadb 2\nwebfrmk 6\n",
"1\ncba 2\n"
] | The first sample is given in the pic below. Arrow from *A* to *B* means that *B* directly depends on *A*. Projects that Polycarp's project «a» (version 3) depends on are painted black.
The second sample is again given in the pic below. Arrow from *A* to *B* means that *B* directly depends on *A*. Projects that Polycar... | 2,000 | [
{
"input": "4\na 3\n2\nb 1\nc 1\n\nb 2\n0\n\nb 1\n1\nb 2\n\nc 1\n1\nb 2",
"output": "2\nb 1\nc 1"
},
{
"input": "9\ncodehorses 5\n3\nwebfrmk 6\nmashadb 1\nmashadb 2\n\ncommons 2\n0\n\nmashadb 3\n0\n\nwebfrmk 6\n2\nmashadb 3\ncommons 2\n\nextra 4\n1\nextra 3\n\nextra 3\n0\n\nextra 1\n0\n\nmashadb 1\n... | 1,519,584,947 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 1,216 | 57,036,800 | def read_pack():
name, ver = input().strip().split()
return (name, int(ver))
n = int(input())
deps = dict()
for i in range(n):
pack = read_pack()
if not i:
root = pack
dep_n = int(input())
deps[pack] = [read_pack() for _ in range(dep_n)]
if i != n - 1:
input()
... | Title: Dependency management
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is currently developing a project in Vaja language and using a popular dependency management system called Vamen. From Vamen's point of view both Vaja project and libraries are treated projects for simpli... | ```python
def read_pack():
name, ver = input().strip().split()
return (name, int(ver))
n = int(input())
deps = dict()
for i in range(n):
pack = read_pack()
if not i:
root = pack
dep_n = int(input())
deps[pack] = [read_pack() for _ in range(dep_n)]
if i != n - 1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
767 | C | Garland | PROGRAMMING | 2,000 | [
"dfs and similar",
"graphs",
"greedy",
"trees"
] | null | null | Once at New Year Dima had a dream in which he was presented a fairy garland. A garland is a set of lamps, some pairs of which are connected by wires. Dima remembered that each two lamps in the garland were connected directly or indirectly via some wires. Furthermore, the number of wires was exactly one less than the nu... | The first line contains single integer *n* (3<=≤<=*n*<=≤<=106) — the number of lamps in the garland.
Then *n* lines follow. The *i*-th of them contain the information about the *i*-th lamp: the number lamp *a**i*, it is hanging on (and 0, if is there is no such lamp), and its temperature *t**i* (<=-<=100<=≤<=*t**i*<=≤... | If there is no solution, print -1.
Otherwise print two integers — the indexes of the lamps which mean Dima should cut the wires they are hanging on. If there are multiple answers, print any of them. | [
"6\n2 4\n0 5\n4 2\n2 1\n1 1\n4 2\n",
"6\n2 4\n0 6\n4 2\n2 1\n1 1\n4 2\n"
] | [
"1 4\n",
"-1\n"
] | The garland and cuts scheme for the first example: | 1,500 | [
{
"input": "6\n2 4\n0 5\n4 2\n2 1\n1 1\n4 2",
"output": "1 4"
},
{
"input": "6\n2 4\n0 6\n4 2\n2 1\n1 1\n4 2",
"output": "-1"
},
{
"input": "6\n2 4\n0 -1\n4 2\n2 3\n1 2\n4 5",
"output": "6 4"
},
{
"input": "3\n2 1\n0 1\n2 1",
"output": "1 3"
},
{
"input": "5\n0 5\... | 1,697,285,864 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | from collections import deque
from heapq import *
mod = 1000000007
time = 0
def solve():
n = int(input())
adj = [[]for i in range(n+1)]
temp = [0]*(n+1)
for i in range(1,n+1):
a,b = map(int,input().split())
if a!=0:
adj[a].append(i)
adj[i].append(a)
temp[i] = b
sss = sum(temp)
if sss%3!=0:
print(-1... | Title: Garland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at New Year Dima had a dream in which he was presented a fairy garland. A garland is a set of lamps, some pairs of which are connected by wires. Dima remembered that each two lamps in the garland were connected directly or... | ```python
from collections import deque
from heapq import *
mod = 1000000007
time = 0
def solve():
n = int(input())
adj = [[]for i in range(n+1)]
temp = [0]*(n+1)
for i in range(1,n+1):
a,b = map(int,input().split())
if a!=0:
adj[a].append(i)
adj[i].append(a)
temp[i] = b
sss = sum(temp)
if sss%3!=0:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,585,856,925 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 248 | 0 | n=int(input())
l=[int(i) for i in input().split()]
c=set(l)
d=0
e=1
flag=0
for i in c:
if(l.count(i)>d):
d=l.count(i)
if(n==2):
if(d>1):
flag=1
if(n==1):
flag=0
if(flag>0):
print("No")
elif(flag==0):
print("Yes")
else:
for i in range(3... | Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
n=int(input())
l=[int(i) for i in input().split()]
c=set(l)
d=0
e=1
flag=0
for i in c:
if(l.count(i)>d):
d=l.count(i)
if(n==2):
if(d>1):
flag=1
if(n==1):
flag=0
if(flag>0):
print("No")
elif(flag==0):
print("Yes")
else:
for i ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to th... | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,698,613,785 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 92 | 0 | colors = list(map(int, input().split()))
unique_colors = len(set(colors)) # Count the unique colors Valera has
needed_horseshoes = 4 - unique_colors # Calculate the number of additional horseshoes needed
print(needed_horseshoes)
| Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has ... | ```python
colors = list(map(int, input().split()))
unique_colors = len(set(colors)) # Count the unique colors Valera has
needed_horseshoes = 4 - unique_colors # Calculate the number of additional horseshoes needed
print(needed_horseshoes)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
858 | B | Which floor? | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | In a building where Polycarp lives there are equal number of flats on each floor. Unfortunately, Polycarp don't remember how many flats are on each floor, but he remembers that the flats are numbered from 1 from lower to upper floors. That is, the first several flats are on the first floor, the next several flats are o... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100, 0<=≤<=*m*<=≤<=100), where *n* is the number of the flat you need to restore floor for, and *m* is the number of flats in Polycarp's memory.
*m* lines follow, describing the Polycarp's memory: each of these lines contains a pair of integers *k**i*,<=*... | Print the number of the floor in which the *n*-th flat is located, if it is possible to determine it in a unique way. Print -1 if it is not possible to uniquely restore this floor. | [
"10 3\n6 2\n2 1\n7 3\n",
"8 4\n3 1\n6 2\n5 2\n2 1\n"
] | [
"4\n",
"-1\n"
] | In the first example the 6-th flat is on the 2-nd floor, while the 7-th flat is on the 3-rd, so, the 6-th flat is the last on its floor and there are 3 flats on each floor. Thus, the 10-th flat is on the 4-th floor.
In the second example there can be 3 or 4 flats on each floor, so we can't restore the floor for the 8-... | 750 | [
{
"input": "10 3\n6 2\n2 1\n7 3",
"output": "4"
},
{
"input": "8 4\n3 1\n6 2\n5 2\n2 1",
"output": "-1"
},
{
"input": "8 3\n7 2\n6 2\n1 1",
"output": "2"
},
{
"input": "4 2\n8 3\n3 1",
"output": "2"
},
{
"input": "11 4\n16 4\n11 3\n10 3\n15 4",
"output": "3"
... | 1,698,519,113 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | import math
Thefirst = input().split()
target = int(Thefirst[0])
num = int(Thefirst[1])#how many rounds
flat = []#房间
floor = []#层数
themin = []
themax = []
for i in range(num):
tmp = input().split()
flat.append(int(tmp[0]))
floor.append(int(tmp[1]))
for i in range(num):
themin.appe... | Title: Which floor?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a building where Polycarp lives there are equal number of flats on each floor. Unfortunately, Polycarp don't remember how many flats are on each floor, but he remembers that the flats are numbered from 1 from lower to u... | ```python
import math
Thefirst = input().split()
target = int(Thefirst[0])
num = int(Thefirst[1])#how many rounds
flat = []#房间
floor = []#层数
themin = []
themax = []
for i in range(num):
tmp = input().split()
flat.append(int(tmp[0]))
floor.append(int(tmp[1]))
for i in range(num):
t... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. ... | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,684,517,660 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | n=int(input())
l=list(map(int,input().split()))
l=list(set(l))
l.sort()
if(len(l)==1):
min2="NO"
else:
min2=l[-2]
print(min2)
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statis... | ```python
n=int(input())
l=list(map(int,input().split()))
l=list(set(l))
l.sort()
if(len(l)==1):
min2="NO"
else:
min2=l[-2]
print(min2)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,615,382,742 | 2,147,483,647 | Python 3 | OK | TESTS | 84 | 77 | 307,200 | a=int(input())
b=int(input())
c=int(input())
x=[a,b,c]
t=a
j=0
while j<len(x):
y=[t,t*2,t*4]
for j in range(len(x)):
if x[j]<y[j]:
t-=1
j=-1
break
j+=1
if y[0]==0:
print(0)
else:
print(sum(y)) | Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
a=int(input())
b=int(input())
c=int(input())
x=[a,b,c]
t=a
j=0
while j<len(x):
y=[t,t*2,t*4]
for j in range(len(x)):
if x[j]<y[j]:
t-=1
j=-1
break
j+=1
if y[0]==0:
print(0)
else:
print(sum(y))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
792 | A | New Bus Route | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from one city to another only by bus. But all buses and roads are very old, so the Minister of Transport d... | The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). All numbers *a**i* are pairwise distinct. | Print two integer numbers — the minimal distance and the quantity of pairs with this distance. | [
"4\n6 -3 0 4\n",
"3\n-2 0 2\n"
] | [
"2 1\n",
"2 2\n"
] | In the first example the distance between the first city and the fourth city is |4 - 6| = 2, and it is the only pair with this distance. | 0 | [
{
"input": "4\n6 -3 0 4",
"output": "2 1"
},
{
"input": "3\n-2 0 2",
"output": "2 2"
},
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "2\n1000000000 -1000000000",
"output": "2000000000 1"
},
{
"input": "5\n-979619606 -979619602 -979619604 -979619605 -97961960... | 1,630,605,622 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 3 | 139 | 22,220,800 | import math
def main_function():
n = int(input())
a = sorted([int(i) for i in input().split(" ")])
hash_dif = [0 for i in range(len(a) + 2)]
for i in range(1, len(a)):
hash_dif[a[i] - a[i - 1]] += 1
for i in range(len(hash_dif)):
if hash_dif[i] != 0:
print(str(... | Title: New Bus Route
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities situated along the main road of Berland. Cities are represented by their coordinates — integer numbers *a*1,<=*a*2,<=...,<=*a**n*. All coordinates are pairwise distinct.
It is possible to get from on... | ```python
import math
def main_function():
n = int(input())
a = sorted([int(i) for i in input().split(" ")])
hash_dif = [0 for i in range(len(a) + 2)]
for i in range(1, len(a)):
hash_dif[a[i] - a[i - 1]] += 1
for i in range(len(hash_dif)):
if hash_dif[i] != 0:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
586 | B | Laurenty and Shop | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | A little boy Laurenty has been playing his favourite game Nota for quite a while and is now very hungry. The boy wants to make sausage and cheese sandwiches, but first, he needs to buy a sausage and some cheese.
The town where Laurenty lives in is not large. The houses in it are located in two rows, *n* houses in each... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=50) — the number of houses in each row.
Each of the next two lines contains *n*<=-<=1 space-separated integer — values *a**ij* (1<=≤<=*a**ij*<=≤<=100).
The last line contains *n* space-separated integers *b**j* (1<=≤<=*b**j*<=≤<=100). | Print a single integer — the least total time Laurenty needs to wait at the crossroads, given that he crosses the avenue only once both on his way to the store and on his way back home. | [
"4\n1 2 3\n3 2 1\n3 2 2 3\n",
"3\n1 2\n3 3\n2 1 3\n",
"2\n1\n1\n1 1\n"
] | [
"12\n",
"11\n",
"4\n"
] | The first sample is shown on the figure above.
In the second sample, Laurenty's path can look as follows:
- Laurenty crosses the avenue, the waiting time is 3; - Laurenty uses the second crossing in the first row, the waiting time is 2; - Laurenty uses the first crossing in the first row, the waiting time is 1; ... | 1,000 | [
{
"input": "4\n1 2 3\n3 2 1\n3 2 2 3",
"output": "12"
},
{
"input": "3\n1 2\n3 3\n2 1 3",
"output": "11"
},
{
"input": "2\n1\n1\n1 1",
"output": "4"
},
{
"input": "2\n1\n1\n2 1",
"output": "5"
},
{
"input": "3\n1 100\n1 1\n100 100 100",
"output": "204"
},
... | 1,640,950,583 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 124 | 1,126,400 | n=int(input())
a=[int(i) for i in input().split()]
b=[int(i) for i in input().split()]
for i in range(1, n-1):
a[i]=a[i]+a[i-1]
b[-(i+1)]=b[-(i+1)]+b[-(i+1)+1]
a=[0]+a
b.append(0)
m=[int(i) for i in input().split()]
ans=float("inf")
for i in range(n):
temp1=b[i]+m[i]+a[i]
for j in range(n-1,... | Title: Laurenty and Shop
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A little boy Laurenty has been playing his favourite game Nota for quite a while and is now very hungry. The boy wants to make sausage and cheese sandwiches, but first, he needs to buy a sausage and some cheese.
The ... | ```python
n=int(input())
a=[int(i) for i in input().split()]
b=[int(i) for i in input().split()]
for i in range(1, n-1):
a[i]=a[i]+a[i-1]
b[-(i+1)]=b[-(i+1)]+b[-(i+1)+1]
a=[0]+a
b.append(0)
m=[int(i) for i in input().split()]
ans=float("inf")
for i in range(n):
temp1=b[i]+m[i]+a[i]
for j in ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,688,015,445 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 31 | 0 | u = int(input())
summ = 0
while u != 0:
summ += u%2
u/=2
u = int(u)
print(summ)
| Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
u = int(input())
summ = 0
while u != 0:
summ += u%2
u/=2
u = int(u)
print(summ)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
727 | C | Guess the Array | PROGRAMMING | 1,400 | [
"constructive algorithms",
"interactive",
"math"
] | null | null | This is an interactive problem. You should use flush operation after each printed line. For example, in C++ you should use fflush(stdout), in Java you should use System.out.flush(), and in Pascal — flush(output).
In this problem you should guess an array *a* which is unknown for you. The only information you have init... | none | none | [
"5\n \n9\n \n7\n \n9\n \n11\n \n6\n "
] | [
"? 1 5\n \n? 2 3\n \n? 4 1\n \n? 5 2\n \n? 3 4\n \n! 4 6 1 5 5"
] | The format of a test to make a hack is:
- The first line contains an integer number *n* (3 ≤ *n* ≤ 5000) — the length of the array.- The second line contains *n* numbers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (1 ≤ *a*<sub class="lower-inde... | 1,500 | [
{
"input": "5\n4 6 1 5 5",
"output": "5 out of 5"
},
{
"input": "3\n1 1 1",
"output": "3 out of 3"
},
{
"input": "4\n100 1 100 1",
"output": "4 out of 4"
},
{
"input": "10\n9 5 10 7 4 4 8 5 10 5",
"output": "10 out of 10"
},
{
"input": "3\n1 1 1",
"output": "3... | 1,644,981,975 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 233 | 307,200 |
import sys
n = int(input())
lul = [0 for i in range(n)]
print('?', 1, 2)
sys.stdout.flush()
a = int(input())
print('?', 2, 3)
sys.stdout.flush()
b = int(input())
print('?', 1, 3)
sys.stdout.flush()
c = int(input())
lul[0] = (a + c - b) // 2
lul[1] = a - lul[0]
lul[2] = c - lul[0]
for i in range(4, n + 1):
print(... | Title: Guess the Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This is an interactive problem. You should use flush operation after each printed line. For example, in C++ you should use fflush(stdout), in Java you should use System.out.flush(), and in Pascal — flush(output).
In th... | ```python
import sys
n = int(input())
lul = [0 for i in range(n)]
print('?', 1, 2)
sys.stdout.flush()
a = int(input())
print('?', 2, 3)
sys.stdout.flush()
b = int(input())
print('?', 1, 3)
sys.stdout.flush()
c = int(input())
lul[0] = (a + c - b) // 2
lul[1] = a - lul[0]
lul[2] = c - lul[0]
for i in range(4, n + 1):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
337 | A | Puzzles | PROGRAMMING | 900 | [
"greedy"
] | null | null | The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, as wikipedia states, is a tiling puzzle that requires the assembly of numerous small, often od... | The first line contains space-separated integers *n* and *m* (2<=≤<=*n*<=≤<=*m*<=≤<=50). The second line contains *m* space-separated integers *f*1,<=*f*2,<=...,<=*f**m* (4<=≤<=*f**i*<=≤<=1000) — the quantities of pieces in the puzzles sold in the shop. | Print a single integer — the least possible difference the teacher can obtain. | [
"4 6\n10 12 10 7 5 22\n"
] | [
"5\n"
] | Sample 1. The class has 4 students. The shop sells 6 puzzles. If Ms. Manana buys the first four puzzles consisting of 10, 12, 10 and 7 pieces correspondingly, then the difference between the sizes of the largest and the smallest puzzle will be equal to 5. It is impossible to obtain a smaller difference. Note that the t... | 500 | [
{
"input": "4 6\n10 12 10 7 5 22",
"output": "5"
},
{
"input": "2 2\n4 4",
"output": "0"
},
{
"input": "2 10\n4 5 6 7 8 9 10 11 12 12",
"output": "0"
},
{
"input": "4 5\n818 136 713 59 946",
"output": "759"
},
{
"input": "3 20\n446 852 783 313 549 965 40 88 86 617... | 1,682,179,728 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 18 | 184 | 1,228,800 | a, b = map(int, input().split())
l = list(map(int, input().split()))
l.sort()
c = float('inf')
for i in range(b-a+1):
dif = max(l[i:i+a]) - min(l[i:i+a])
if c > dif:
c = dif
print(c)
| Title: Puzzles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The end of the school year is near and Ms. Manana, the teacher, will soon have to say goodbye to a yet another class. She decided to prepare a goodbye present for her *n* students and give each of them a jigsaw puzzle (which, a... | ```python
a, b = map(int, input().split())
l = list(map(int, input().split()))
l.sort()
c = float('inf')
for i in range(b-a+1):
dif = max(l[i:i+a]) - min(l[i:i+a])
if c > dif:
c = dif
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,658,907,071 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 0 | import sys
s=list(input())
flag=True
Lcounter=0
for a in range(len(s)):
if s[a]=='h':
while s[a]!='e':
a+=1
if a==len(s):
print("NO")
sys.exit()
while flag:
a+=1
if a==len(s):
... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
import sys
s=list(input())
flag=True
Lcounter=0
for a in range(len(s)):
if s[a]=='h':
while s[a]!='e':
a+=1
if a==len(s):
print("NO")
sys.exit()
while flag:
a+=1
if a==len(s):
... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,691,737,243 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 31 | 102,400 | def determine_winner(s):
anton_count = s.count('A')
danik_count = s.count('D')
if anton_count > danik_count:
return "Anton"
elif danik_count > anton_count:
return "Danik"
else:
return "Friendship"
# Read input
n = int(input())
s = input()
# Determine the win... | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
def determine_winner(s):
anton_count = s.count('A')
danik_count = s.count('D')
if anton_count > danik_count:
return "Anton"
elif danik_count > anton_count:
return "Danik"
else:
return "Friendship"
# Read input
n = int(input())
s = input()
# Determi... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
570 | A | Elections | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusual. At the first stage of elections the votes are counted for each city: it is assumed that in ... | The first line of the input contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of candidates and of cities, respectively.
Each of the next *m* lines contains *n* non-negative integers, the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*j*<=≤<=*n*, 1<=≤<=*i*<=≤<=*m*, 0<=≤<=*a**ij*<=≤<=109) denotes ... | Print a single number — the index of the candidate who won the elections. The candidates are indexed starting from one. | [
"3 3\n1 2 3\n2 3 1\n1 2 1\n",
"3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7\n"
] | [
"2",
"1"
] | Note to the first sample test. At the first stage city 1 chosen candidate 3, city 2 chosen candidate 2, city 3 chosen candidate 2. The winner is candidate 2, he gained 2 votes.
Note to the second sample test. At the first stage in city 1 candidates 1 and 2 got the same maximum number of votes, but candidate 1 has a sm... | 500 | [
{
"input": "3 3\n1 2 3\n2 3 1\n1 2 1",
"output": "2"
},
{
"input": "3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7",
"output": "1"
},
{
"input": "1 3\n5\n3\n2",
"output": "1"
},
{
"input": "3 1\n1 2 3",
"output": "3"
},
{
"input": "3 1\n100 100 100",
"output": "1"
},
{... | 1,512,963,036 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 62 | 5,632,000 | n,m = map(int,input().split())
count = [0]*n
for i in range(m):
vote = list(map(int,input().split()))
count[vote.index(max(vote))] += 1
print(count.index(max(count))+1) | Title: Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusu... | ```python
n,m = map(int,input().split())
count = [0]*n
for i in range(m):
vote = list(map(int,input().split()))
count[vote.index(max(vote))] += 1
print(count.index(max(count))+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,495,370,015 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 61 | 0 | i,j = map(int(input().split()))
n=0
d=0
a = list(map(int(input().split())))
for x in range(i):
n= n + a[i]
while (round((n+0.01)/i) < j):
n=n+j
i=i+1
d=d+1
print (d) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
i,j = map(int(input().split()))
n=0
d=0
a = list(map(int(input().split())))
for x in range(i):
n= n + a[i]
while (round((n+0.01)/i) < j):
n=n+j
i=i+1
d=d+1
print (d)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
701 | B | Cells Not Under Attack | PROGRAMMING | 1,200 | [
"data structures",
"math"
] | null | null | Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=*min*(100<=000,<=*n*2)) — the size of the board and the number of rooks.
Each of the next *m* lines contains integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the number of the row and the number of the col... | Print *m* integer, the *i*-th of them should be equal to the number of cells that are not under attack after first *i* rooks are put. | [
"3 3\n1 1\n3 1\n2 2\n",
"5 2\n1 5\n5 1\n",
"100000 1\n300 400\n"
] | [
"4 2 0 \n",
"16 9 \n",
"9999800001 \n"
] | On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | 750 | [
{
"input": "3 3\n1 1\n3 1\n2 2",
"output": "4 2 0 "
},
{
"input": "5 2\n1 5\n5 1",
"output": "16 9 "
},
{
"input": "100000 1\n300 400",
"output": "9999800001 "
},
{
"input": "10 4\n2 8\n1 8\n9 8\n6 9",
"output": "81 72 63 48 "
},
{
"input": "30 30\n3 13\n27 23\n18... | 1,589,790,356 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 1,543 | 30,208,000 | m,n=map(int,input().split())
s,q=m,m
row=[0]*(m+1)
co=[0]*(m+1)
for i in range(n):
a,b=map(int,input().split())
if row[a]==0:
row[a]=1
s=s-1
if co[b]==0:
co[b]=1
q=q-1
if i!=n-1:
print(s*q,end=" ")
else:
print(s*q)
| Title: Cells Not Under Attack
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's a... | ```python
m,n=map(int,input().split())
s,q=m,m
row=[0]*(m+1)
co=[0]*(m+1)
for i in range(n):
a,b=map(int,input().split())
if row[a]==0:
row[a]=1
s=s-1
if co[b]==0:
co[b]=1
q=q-1
if i!=n-1:
print(s*q,end=" ")
else:
print(s*q)
``... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,693,658,287 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | string1=input()
st1=string1.lower()
string2=input()
st2=string2.lower()
st3=""
for i in range(len(st2)-1,-1,-1):
c=st2[i]
st3+=c
if st2==st3:
print("YES")
else:
print("NO") | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
string1=input()
st1=string1.lower()
string2=input()
st2=string2.lower()
st3=""
for i in range(len(st2)-1,-1,-1):
c=st2[i]
st3+=c
if st2==st3:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
948 | A | Protect Sheep | PROGRAMMING | 900 | [
"brute force",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is a rectangle consisting of *R*<=×<=*C* cells. Each cell is either empty, contains a sheep, a wolf or... | First line contains two integers *R* (1<=≤<=*R*<=≤<=500) and *C* (1<=≤<=*C*<=≤<=500), denoting the number of rows and the numbers of columns respectively.
Each of the following *R* lines is a string consisting of exactly *C* characters, representing one row of the pasture. Here, 'S' means a sheep, 'W' a wolf and '.' a... | If it is impossible to protect all sheep, output a single line with the word "No".
Otherwise, output a line with the word "Yes". Then print *R* lines, representing the pasture after placing dogs. Again, 'S' means a sheep, 'W' a wolf, 'D' is a dog and '.' an empty space. You are not allowed to move, remove or add a she... | [
"6 6\n..S...\n..S.W.\n.S....\n..W...\n...W..\n......\n",
"1 2\nSW\n",
"5 5\n.S...\n...S.\nS....\n...S.\n.S...\n"
] | [
"Yes\n..SD..\n..SDW.\n.SD...\n.DW...\nDD.W..\n......\n",
"No\n",
"Yes\n.S...\n...S.\nS.D..\n...S.\n.S...\n"
] | In the first example, we can split the pasture into two halves, one containing wolves and one containing sheep. Note that the sheep at (2,1) is safe, as wolves cannot move diagonally.
In the second example, there are no empty spots to put dogs that would guard the lone sheep.
In the third example, there are no wolves... | 500 | [
{
"input": "1 2\nSW",
"output": "No"
},
{
"input": "10 10\n....W.W.W.\n.........S\n.S.S...S..\nW.......SS\n.W..W.....\n.W...W....\nS..S...S.S\n....W...S.\n..S..S.S.S\nSS.......S",
"output": "Yes\nDDDDWDWDWD\nDDDDDDDDDS\nDSDSDDDSDD\nWDDDDDDDSS\nDWDDWDDDDD\nDWDDDWDDDD\nSDDSDDDSDS\nDDDDWDDDSD\nDDSD... | 1,520,768,759 | 2,147,483,647 | Python 3 | OK | TESTS | 98 | 919 | 8,601,600 | def solve(d):
dx = [1, -1, 0, 0]
dy = [0, 0, 1, -1]
res = 1
for i in range(1, r+1):
for j in range(1, c+1):
if (d[i][j] == 'S'):
for k in range(4):
if (d[i + dx[k]][j + dy[k]] == 'W'):
res = 0
return ... | Title: Protect Sheep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bob is a farmer. He has a large pasture with many sheep. Recently, he has lost some of them due to wolf attacks. He thus decided to place some shepherd dogs in such a way that all his sheep are protected.
The pasture is ... | ```python
def solve(d):
dx = [1, -1, 0, 0]
dy = [0, 0, 1, -1]
res = 1
for i in range(1, r+1):
for j in range(1, c+1):
if (d[i][j] == 'S'):
for k in range(4):
if (d[i + dx[k]][j + dy[k]] == 'W'):
res = 0
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
701 | C | They Are Everywhere | PROGRAMMING | 1,500 | [
"binary search",
"strings",
"two pointers"
] | null | null | Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each flat. Also, each flat is connected with the flat to the left and the flat to the right. Flat number 1 is ... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of flats in the house.
The second line contains the row *s* with the length *n*, it consists of uppercase and lowercase letters of English alphabet, the *i*-th letter equals the type of Pokemon, which is in the flat number *i*. | Print the minimum number of flats which Sergei B. should visit in order to catch Pokemons of all types which there are in the house. | [
"3\nAaA\n",
"7\nbcAAcbc\n",
"6\naaBCCe\n"
] | [
"2\n",
"3\n",
"5\n"
] | In the first test Sergei B. can begin, for example, from the flat number 1 and end in the flat number 2.
In the second test Sergei B. can begin, for example, from the flat number 4 and end in the flat number 6.
In the third test Sergei B. must begin from the flat number 2 and end in the flat number 6. | 1,000 | [
{
"input": "3\nAaA",
"output": "2"
},
{
"input": "7\nbcAAcbc",
"output": "3"
},
{
"input": "6\naaBCCe",
"output": "5"
},
{
"input": "1\nA",
"output": "1"
},
{
"input": "1\ng",
"output": "1"
},
{
"input": "52\nabcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQ... | 1,588,343,559 | 2,147,483,647 | Python 3 | OK | TESTS | 80 | 217 | 614,400 | n = int(input())
s = input()
q = len(set(s))
d = dict()
count = 0
ans = 999999999
j = 0
for i in range(n):
if s[i] not in d:
d[s[i]] = 0
count += 1
d[s[i]] += 1
if count == q:
while d[s[j]] > 1:
d[s[j]] -= 1
j += 1
ans = min(ans, i - j + 1)
print(ans) | Title: They Are Everywhere
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sergei B., the young coach of Pokemons, has found the big house which consists of *n* flats ordered in a row from left to right. It is possible to enter each flat from the street. It is possible to go out from each ... | ```python
n = int(input())
s = input()
q = len(set(s))
d = dict()
count = 0
ans = 999999999
j = 0
for i in range(n):
if s[i] not in d:
d[s[i]] = 0
count += 1
d[s[i]] += 1
if count == q:
while d[s[j]] > 1:
d[s[j]] -= 1
j += 1
ans = min(ans, i - j + 1)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
372 | A | Counting Kangaroos is Fun | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"sortings",
"two pointers"
] | null | null | There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as large as the size of kangaroo who is held.
Each kangaroo can hold at most one kangaroo, and the kangaroo who i... | The first line contains a single integer — *n* (1<=≤<=*n*<=≤<=5·105). Each of the next *n* lines contains an integer *s**i* — the size of the *i*-th kangaroo (1<=≤<=*s**i*<=≤<=105). | Output a single integer — the optimal number of visible kangaroos. | [
"8\n2\n5\n7\n6\n9\n8\n4\n2\n",
"8\n9\n1\n6\n2\n6\n5\n8\n3\n"
] | [
"5\n",
"5\n"
] | none | 500 | [
{
"input": "8\n2\n5\n7\n6\n9\n8\n4\n2",
"output": "5"
},
{
"input": "8\n9\n1\n6\n2\n6\n5\n8\n3",
"output": "5"
},
{
"input": "12\n3\n99\n24\n46\n75\n63\n57\n55\n10\n62\n34\n52",
"output": "7"
},
{
"input": "12\n55\n75\n1\n98\n63\n64\n9\n39\n82\n18\n47\n9",
"output": "6"
... | 1,620,734,022 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 29,900,800 |
n = int(input())
nn = n
arr = []
while nn:
nn -= 1
temp = int(input())
arr.append(temp)
arr.sort()
mid = n//2 - 1
b = n - 1
s = 0
while mid >= 0:
if arr[mid]*2 <= arr[b]:
b -= 1
s += 1
mid -= 1
print(n-s)
| Title: Counting Kangaroos is Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as ... | ```python
n = int(input())
nn = n
arr = []
while nn:
nn -= 1
temp = int(input())
arr.append(temp)
arr.sort()
mid = n//2 - 1
b = n - 1
s = 0
while mid >= 0:
if arr[mid]*2 <= arr[b]:
b -= 1
s += 1
mid -= 1
print(n-s)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards ... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print... | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,612,427,605 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 77 | 307,200 |
def main():
n = int(input())
cards = list(map(int, input().split()))
total_sum = sum(cards)
per_person_sum = int(total_sum*2/n)
for i in range(n):
if cards[i]!=0:
for j in range(i+1,n):
if cards[i]+cards[j] ==per_person_sum:
prin... | Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one p... | ```python
def main():
n = int(input())
cards = list(map(int, input().split()))
total_sum = sum(cards)
per_person_sum = int(total_sum*2/n)
for i in range(n):
if cards[i]!=0:
for j in range(i+1,n):
if cards[i]+cards[j] ==per_person_sum:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
846 | A | Curriculum Vitae | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zer... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100).
The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one. | Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one. | [
"4\n1 1 0 1\n",
"6\n0 1 0 0 1 0\n",
"1\n0\n"
] | [
"3\n",
"4\n",
"1\n"
] | none | 0 | [
{
"input": "4\n1 1 0 1",
"output": "3"
},
{
"input": "6\n0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "100\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,588,693,317 | 2,147,483,647 | PyPy 3 | OK | TESTS | 18 | 140 | 0 | import sys
input = sys.stdin.readline
n = int(input())
s = list(map(int, input().split()))
zc, res = [0 for i in range(105)], 0
for i in range(1, n+1):
zc[i] = zc[i-1] + (1 if s[i-1] == 0 else 0)
for i in range(1, n+1):
lzc = zc[i-1]
roc = (n-i) - (zc[n] - zc[i])
res = max(res, lzc + 1 + r... | Title: Curriculum Vitae
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* g... | ```python
import sys
input = sys.stdin.readline
n = int(input())
s = list(map(int, input().split()))
zc, res = [0 for i in range(105)], 0
for i in range(1, n+1):
zc[i] = zc[i-1] + (1 if s[i-1] == 0 else 0)
for i in range(1, n+1):
lzc = zc[i-1]
roc = (n-i) - (zc[n] - zc[i])
res = max(res, l... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and ... | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,687,272,259 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n = int(input())
flag = False
for i in range(n):
res = n-i
if (res%2==0 and i%2==0):
print("Yes")
flag = True
if flag:
print("YES")
else:
print("NO") | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dyin... | ```python
n = int(input())
flag = False
for i in range(n):
res = n-i
if (res%2==0 and i%2==0):
print("Yes")
flag = True
if flag:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
253 | E | Printer | PROGRAMMING | 2,200 | [
"binary search",
"data structures",
"implementation",
"sortings"
] | null | null | Let's consider a network printer that functions like that. It starts working at time 0. In each second it can print one page of a text. At some moments of time the printer receives printing tasks. We know that a printer received *n* tasks. Let's number the tasks by consecutive integers from 1 to *n*. Then the task numb... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50000). Next *n* lines describe the tasks. The *i*-th of these lines contains three integers *t**i*, *s**i* and *p**i*, separated by single spaces (0<=≤<=*t**i*<=≤<=109,<=1<=≤<=*s**i*,<=*p**i*<=≤<=109). Exactly one task (let's assume that his number is *x*) has number ... | In the first line print integer *p**x* — the priority of the task number *x* (1<=≤<=*p**x*<=≤<=109, remember that all priorities should be distinct). Then print *n* integers, the *i*-th of them represents the moment of time when the last page of the task number *i* finished printing.
It is guaranteed that at least on... | [
"3\n4 3 -1\n0 2 2\n1 3 3\n7\n",
"3\n3 1 2\n2 3 3\n3 1 -1\n4\n"
] | [
"4\n7 8 4\n",
"4\n7 6 4\n"
] | Let's consider the first test case. Let's assume that the unknown priority equals 4, then the printer's actions for each second are as follows:
- the beginning of the 1-st second (time 0). The queue has task 2. The printer prints the first page of this task; - the beginning of the 2-nd second (time 1). The queue has... | 2,500 | [] | 1,658,468,794 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 4 | 124 | 2,969,600 | import sys
f = open("input.txt")
input = f.readline
g = open("output.txt", "w")
print = g.write
import heapq
def check(data, n):
finish = [0]*n
h = []
j = 0
time = data[0][0]
while j < n or h:
while j < n and data[j][0] == time:
s, v, p, i = data[j]
heapq.heappush(h,... | Title: Printer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a network printer that functions like that. It starts working at time 0. In each second it can print one page of a text. At some moments of time the printer receives printing tasks. We know that a printer receive... | ```python
import sys
f = open("input.txt")
input = f.readline
g = open("output.txt", "w")
print = g.write
import heapq
def check(data, n):
finish = [0]*n
h = []
j = 0
time = data[0][0]
while j < n or h:
while j < n and data[j][0] == time:
s, v, p, i = data[j]
heapq.h... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
939 | A | Love Triangle | PROGRAMMING | 800 | [
"graphs"
] | null | null | As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with number *f**i*, where 1<=≤<=*f**i*<=≤<=*n* and *f**i*<=≠<=*i*.
We call a love triangle a situation ... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=5000) — the number of planes.
The second line contains *n* integers *f*1,<=*f*2,<=...,<=*f**n* (1<=≤<=*f**i*<=≤<=*n*, *f**i*<=≠<=*i*), meaning that the *i*-th plane likes the *f**i*-th. | Output «YES» if there is a love triangle consisting of planes on Earth. Otherwise, output «NO».
You can output any letter in lower case or in upper case. | [
"5\n2 4 5 1 3\n",
"5\n5 5 5 5 1\n"
] | [
"YES\n",
"NO\n"
] | In first example plane 2 likes plane 4, plane 4 likes plane 1, plane 1 likes plane 2 and that is a love triangle.
In second example there are no love triangles. | 500 | [
{
"input": "5\n2 4 5 1 3",
"output": "YES"
},
{
"input": "5\n5 5 5 5 1",
"output": "NO"
},
{
"input": "3\n3 1 2",
"output": "YES"
},
{
"input": "10\n4 10 9 5 3 1 5 10 6 4",
"output": "NO"
},
{
"input": "10\n5 5 4 9 10 9 9 5 3 1",
"output": "YES"
},
{
"... | 1,697,437,474 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n = int(input())
f = list(map(int, input().split()))
f = [0] + f
adj = [ [] for _ in range(n + 1) ]
for u, v in enumerate(f):
if v not in adj[u]:
adj[u].append(v)
if u not in adj[v]:
adj[v].append(u)
visited = [0]*(n+1)
cycled = False
def dfs(v, pred):
global cycled
visited[v] = ... | Title: Love Triangle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you could know there are no male planes nor female planes. However, each plane on Earth likes some other plane. There are *n* planes on Earth, numbered from 1 to *n*, and the plane with number *i* likes the plane with ... | ```python
n = int(input())
f = list(map(int, input().split()))
f = [0] + f
adj = [ [] for _ in range(n + 1) ]
for u, v in enumerate(f):
if v not in adj[u]:
adj[u].append(v)
if u not in adj[v]:
adj[v].append(u)
visited = [0]*(n+1)
cycled = False
def dfs(v, pred):
global cycled
vis... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
415 | A | Mashmokh and Lights | PROGRAMMING | 900 | [
"implementation"
] | null | null | Mashmokh works in a factory. At the end of each day he must turn off all of the lights.
The lights on the factory are indexed from 1 to *n*. There are *n* buttons in Mashmokh's room indexed from 1 to *n* as well. If Mashmokh pushes button with index *i*, then each light with index not less than *i* that is still turn... | The first line of the input contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), the number of the factory lights and the pushed buttons respectively. The next line contains *m* distinct space-separated integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=*n*).
It is guaranteed that all lights... | Output *n* space-separated integers where the *i*-th number is index of the button that turns the *i*-th light off. | [
"5 4\n4 3 1 2\n",
"5 5\n5 4 3 2 1\n"
] | [
"1 1 3 4 4 \n",
"1 2 3 4 5 \n"
] | In the first sample, after pressing button number 4, lights 4 and 5 are turned off and lights 1, 2 and 3 are still on. Then after pressing button number 3, light number 3 is turned off as well. Pressing button number 1 turns off lights number 1 and 2 as well so pressing button number 2 in the end has no effect. Thus bu... | 500 | [
{
"input": "5 4\n4 3 1 2",
"output": "1 1 3 4 4 "
},
{
"input": "5 5\n5 4 3 2 1",
"output": "1 2 3 4 5 "
},
{
"input": "16 11\n8 5 12 10 14 2 6 3 15 9 1",
"output": "1 2 2 2 5 5 5 8 8 8 8 8 8 8 8 8 "
},
{
"input": "79 22\n76 32 48 28 33 44 58 59 1 51 77 13 15 64 49 72 74 21 6... | 1,657,526,984 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 31 | 62 | 0 | n,m = [int(x) for x in input().split()]
arr = [int(x) for x in input().split()]
v = [0]*n
for i in arr:
for j in range(i-1,n):
if(v[j] == 0):
v[j] = i
else:
break
for i in v:
print(i,end=' ') | Title: Mashmokh and Lights
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mashmokh works in a factory. At the end of each day he must turn off all of the lights.
The lights on the factory are indexed from 1 to *n*. There are *n* buttons in Mashmokh's room indexed from 1 to *n* as well. ... | ```python
n,m = [int(x) for x in input().split()]
arr = [int(x) for x in input().split()]
v = [0]*n
for i in arr:
for j in range(i-1,n):
if(v[j] == 0):
v[j] = i
else:
break
for i in v:
print(i,end=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,695,275,818 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | lst=input()
ls=[]
if (lst[0]>='a'and lst[0]<='z')or lst.isupper():
for i in lst:
if i>='a' and i<='z':
ls+=i.upper()
else:
ls+=i.lower()
else:
ls=lst
for i in ls:
print(i,end="")
| Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
lst=input()
ls=[]
if (lst[0]>='a'and lst[0]<='z')or lst.isupper():
for i in lst:
if i>='a' and i<='z':
ls+=i.upper()
else:
ls+=i.lower()
else:
ls=lst
for i in ls:
print(i,end="")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,646,758,436 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 0 | '''
Here in this work first I loop though the given range
and check each value is except 0, the assurance of power of two by
doing bitwise and beteen the number and its previous nimber.
Time complexity: O(n) here n is given range
'''
def power_of_two(m):
if m == 0:
return False
elif (m... | Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, be... | ```python
'''
Here in this work first I loop though the given range
and check each value is except 0, the assurance of power of two by
doing bitwise and beteen the number and its previous nimber.
Time complexity: O(n) here n is given range
'''
def power_of_two(m):
if m == 0:
return False
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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