contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
883 | K | Road Widening | PROGRAMMING | 1,800 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | Mayor of city S just hates trees and lawns. They take so much space and there could be a road on the place they occupy!
The Mayor thinks that one of the main city streets could be considerably widened on account of lawn nobody needs anyway. Moreover, that might help reduce the car jams which happen from time to time o... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — number of parts of the street.
Each of the following *n* lines contains two integers *s**i*,<=*g**i* (1<=≤<=*s**i*<=≤<=106, 0<=≤<=*g**i*<=≤<=106) — current width of road and width of the lawn on the *i*-th part of the street. | In the first line print the total width of lawns which will be removed.
In the second line print *n* integers *s*'1,<=*s*'2,<=...,<=*s*'*n* (*s**i*<=≤<=*s*'*i*<=≤<=*s**i*<=+<=*g**i*) — new widths of the road starting from the first part and to the last.
If there is no solution, print the only integer -1 in the first ... | [
"3\n4 5\n4 5\n4 10\n",
"4\n1 100\n100 1\n1 100\n100 1\n",
"3\n1 1\n100 100\n1 1\n"
] | [
"16\n9 9 10 \n",
"202\n101 101 101 101 \n",
"-1\n"
] | none | 0 | [
{
"input": "3\n4 5\n4 5\n4 10",
"output": "16\n9 9 10 "
},
{
"input": "4\n1 100\n100 1\n1 100\n100 1",
"output": "202\n101 101 101 101 "
},
{
"input": "3\n1 1\n100 100\n1 1",
"output": "-1"
},
{
"input": "10\n21005 10850\n27020 13372\n28183 3724\n22874 13564\n27446 11493\n225... | 1,698,065,817 | 16,917 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 46 | 2,867,200 | def argmin(start, end):
m = float("inf")
index = -1
for i in range(start, end + 1):
if sum(pairs[i]) < m:
m = sum(pairs[i])
index = i
return i
def f(start, end):
if start == end:
return
index = argmin(start, end)
... | Title: Road Widening
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mayor of city S just hates trees and lawns. They take so much space and there could be a road on the place they occupy!
The Mayor thinks that one of the main city streets could be considerably widened on account of lawn ... | ```python
def argmin(start, end):
m = float("inf")
index = -1
for i in range(start, end + 1):
if sum(pairs[i]) < m:
m = sum(pairs[i])
index = i
return i
def f(start, end):
if start == end:
return
index = argmin(st... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
548 | A | Mike and Fax | PROGRAMMING | 1,100 | [
"brute force",
"implementation",
"strings"
] | null | null | While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure if this is his own back-bag or someone else's. He remembered that there were exactly *k* messages ... | The first line of input contains string *s* containing lowercase English letters (1<=≤<=|*s*|<=≤<=1000).
The second line contains integer *k* (1<=≤<=*k*<=≤<=1000). | Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise. | [
"saba\n2\n",
"saddastavvat\n2\n"
] | [
"NO\n",
"YES\n"
] | Palindrome is a string reading the same forward and backward.
In the second sample, the faxes in his back-bag can be "saddas" and "tavvat". | 500 | [
{
"input": "saba\n2",
"output": "NO"
},
{
"input": "saddastavvat\n2",
"output": "YES"
},
{
"input": "aaaaaaaaaa\n3",
"output": "NO"
},
{
"input": "aaaaaa\n3",
"output": "YES"
},
{
"input": "abaacca\n2",
"output": "NO"
},
{
"input": "a\n1",
"output"... | 1,616,850,404 | 2,147,483,647 | PyPy 3 | OK | TESTS | 56 | 93 | 0 | # Not too complicated. Also much simpler with python
x = input()
n = int(input())
if len(x)%n == 0:
l = len(x)//n
else:
print("NO")
exit(0)
for i in range(n):
v = x[i*l:(i+1)*l]
if v != v[::-1]:
print("NO")
exit(0)
print("YES") | Title: Mike and Fax
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string *s*.
He is not sure ... | ```python
# Not too complicated. Also much simpler with python
x = input()
n = int(input())
if len(x)%n == 0:
l = len(x)//n
else:
print("NO")
exit(0)
for i in range(n):
v = x[i*l:(i+1)*l]
if v != v[::-1]:
print("NO")
exit(0)
print("YES")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero,... | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,696,104,960 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 11 | 46 | 0 | n,k=map(int,input().split())
for i in range(k):
if n%10>0:n=n-1
else:n=n//10
print(n) | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit ... | ```python
n,k=map(int,input().split())
for i in range(k):
if n%10>0:n=n-1
else:n=n//10
print(n)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,650,391,659 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | n,k=map(int,input().split())
a=n%k
ans=n+k-a
print(ans) | Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *... | ```python
n,k=map(int,input().split())
a=n%k
ans=n+k-a
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
884 | A | Book Reading | PROGRAMMING | 800 | [
"implementation"
] | null | null | Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of seconds that Luba has to spend working during *i*-th day is *a**i*. If some free time remains, she... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=100, 1<=≤<=*t*<=≤<=106) — the number of days and the time required to read the book.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=86400) — the time Luba has to spend on her work during *i*-th day. | Print the minimum day Luba can finish reading the book.
It is guaranteed that answer doesn't exceed *n*. | [
"2 2\n86400 86398\n",
"2 86400\n0 86400\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "2 2\n86400 86398",
"output": "2"
},
{
"input": "2 86400\n0 86400",
"output": "1"
},
{
"input": "2 86400\n1 86399",
"output": "2"
},
{
"input": "100 1000000\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,602,009,457 | 2,147,483,647 | PyPy 3 | OK | TESTS | 16 | 140 | 0 | from math import ceil
s=0
d=0
n,t=map(int,input().split())
l=list(map(int,input().split()))
for i in range(n):
d+=1
s+=(86400-l[i])
if s>=t:
print(d)
break
| Title: Book Reading
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Luba bought a very interesting book. She knows that it will take *t* seconds to read the book. Luba wants to finish reading as fast as she can.
But she has some work to do in each of *n* next days. The number of ... | ```python
from math import ceil
s=0
d=0
n,t=map(int,input().split())
l=list(map(int,input().split()))
for i in range(n):
d+=1
s+=(86400-l[i])
if s>=t:
print(d)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
117 | C | Cycle | PROGRAMMING | 2,000 | [
"dfs and similar",
"graphs"
] | null | null | A tournament is a directed graph without self-loops in which every pair of vertexes is connected by exactly one directed edge. That is, for any two vertexes *u* and *v* (*u*<=≠<=*v*) exists either an edge going from *u* to *v*, or an edge from *v* to *u*.
You are given a tournament consisting of *n* vertexes. Your tas... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=5000). Next *n* lines contain the adjacency matrix *A* of the graph (without spaces). *A**i*,<=*j*<==<=1 if the graph has an edge going from vertex *i* to vertex *j*, otherwise *A**i*,<=*j*<==<=0. *A**i*,<=*j* stands for the *j*-th character in the *i*-th line.
It ... | Print three distinct vertexes of the graph *a*1, *a*2, *a*3 (1<=≤<=*a**i*<=≤<=*n*), such that *A**a*1,<=*a*2<==<=*A**a*2,<=*a*3<==<=*A**a*3,<=*a*1<==<=1, or "-1", if a cycle whose length equals three does not exist.
If there are several solutions, print any of them. | [
"5\n00100\n10000\n01001\n11101\n11000\n",
"5\n01111\n00000\n01000\n01100\n01110\n"
] | [
"1 3 2 ",
"-1\n"
] | none | 1,500 | [
{
"input": "5\n00100\n10000\n01001\n11101\n11000",
"output": "1 3 2 "
},
{
"input": "5\n01111\n00000\n01000\n01100\n01110",
"output": "-1"
},
{
"input": "5\n01000\n00101\n10010\n11001\n10100",
"output": "1 2 3 "
},
{
"input": "5\n00110\n10110\n00011\n00000\n11010",
"outpu... | 1,595,134,750 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,500 | 225,177,600 | n = int(input())
mat = [input() for _ in range(n)]
graph = [set() for _ in range(n)]
rev_graph = [set() for _ in range(n)]
for i in range(n):
for j in range(n):
if mat[i][j]=='1':
graph[i].add(j)
rev_graph[j].add(i)
try:
for i in range(n):
rset = rev_grap... | Title: Cycle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tournament is a directed graph without self-loops in which every pair of vertexes is connected by exactly one directed edge. That is, for any two vertexes *u* and *v* (*u*<=≠<=*v*) exists either an edge going from *u* to *v*, o... | ```python
n = int(input())
mat = [input() for _ in range(n)]
graph = [set() for _ in range(n)]
rev_graph = [set() for _ in range(n)]
for i in range(n):
for j in range(n):
if mat[i][j]=='1':
graph[i].add(j)
rev_graph[j].add(i)
try:
for i in range(n):
rset ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
586 | A | Alena's Schedule | PROGRAMMING | 900 | [
"implementation"
] | null | null | Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic hours (an academic hour is equal to 45 minutes).
The University works in such a way that every day it... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of lessons at the university.
The second line contains *n* numbers *a**i* (0<=≤<=*a**i*<=≤<=1). Number *a**i* equals 0, if Alena doesn't have the *i*-th pairs, otherwise it is equal to 1. Numbers *a*1,<=*a*2,<=...,<=*a**n* ar... | Print a single number — the number of pairs during which Alena stays at the university. | [
"5\n0 1 0 1 1\n",
"7\n1 0 1 0 0 1 0\n",
"1\n0\n"
] | [
"4\n",
"4\n",
"0\n"
] | In the first sample Alena stays at the university from the second to the fifth pair, inclusive, during the third pair she will be it the university waiting for the next pair.
In the last sample Alena doesn't have a single pair, so she spends all the time at home. | 500 | [
{
"input": "5\n0 1 0 1 1",
"output": "4"
},
{
"input": "7\n1 0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "1"
},
{
... | 1,444,641,870 | 870 | Python 3 | OK | TESTS | 60 | 62 | 0 | n=int(input())
a=input()
a=a.replace(' ','')
a=a+'00'
c=2
h=0
for i in a:
if i=='0':
c+=1
else:
if c==1:
h+=2
else:
h+=1
c=0
print(h) | Title: Alena's Schedule
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic ... | ```python
n=int(input())
a=input()
a=a.replace(' ','')
a=a+'00'
c=2
h=0
for i in a:
if i=='0':
c+=1
else:
if c==1:
h+=2
else:
h+=1
c=0
print(h)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,677,685,476 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | t,sx,sy,ex,ey=input().split()
t,sx,sy,ex,ey=int(t),int(sx),int(sy),int(ex),int(ey)
a=str(input())
count=0
if ex-sx<0 and a.count('W')!=ex-sx:
print(-1)
if ex-sx>0 and a.count('E')!=ex-sx:
print(-1)
if ey-sy>0 and a.count('N')!=ey-sy:
print(-1)
if ey-sy<0 and a.count('S')!=ey-sy:
print(-1)
el... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
t,sx,sy,ex,ey=input().split()
t,sx,sy,ex,ey=int(t),int(sx),int(sy),int(ex),int(ey)
a=str(input())
count=0
if ex-sx<0 and a.count('W')!=ex-sx:
print(-1)
if ex-sx>0 and a.count('E')!=ex-sx:
print(-1)
if ey-sy>0 and a.count('N')!=ey-sy:
print(-1)
if ey-sy<0 and a.count('S')!=ey-sy:
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
682 | B | Alyona and Mex | PROGRAMMING | 1,200 | [
"sortings"
] | null | null | Someone gave Alyona an array containing *n* positive integers *a*1,<=*a*2,<=...,<=*a**n*. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer that is smaller than the current one. Alyona can repeat this operation as many times as she wants. In particular,... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of elements in the Alyona's array.
The second line of the input contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the array. | Print one positive integer — the maximum possible value of mex of the array after Alyona applies some (possibly none) operations. | [
"5\n1 3 3 3 6\n",
"2\n2 1\n"
] | [
"5\n",
"3\n"
] | In the first sample case if one will decrease the second element value to 2 and the fifth element value to 4 then the mex value of resulting array 1 2 3 3 4 will be equal to 5.
To reach the answer to the second sample case one must not decrease any of the array elements. | 1,000 | [
{
"input": "5\n1 3 3 3 6",
"output": "5"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "1\n1",
"output": "2"
},
{
"input": "1\n1000000000",
"output": "2"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n1 1",
"output": "2"
},
{
"... | 1,634,119,460 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | n=int(input())
x=list(map(int,input().split()))
x.sort()
lst=[]
for i in range(1,n+1):
lst.append(i)
if sum(x)==sum(lst):
print(max(x)+1)
elif len(x)==1 and x[0]>1:
print("2")
elif sum(x[:-1])==sum(lst[:-1]):
print(x[-2]+1)
else:
j=0
k=0
while j<len(x):
if x[j]!=lst[k... | Title: Alyona and Mex
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someone gave Alyona an array containing *n* positive integers *a*1,<=*a*2,<=...,<=*a**n*. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer that is small... | ```python
n=int(input())
x=list(map(int,input().split()))
x.sort()
lst=[]
for i in range(1,n+1):
lst.append(i)
if sum(x)==sum(lst):
print(max(x)+1)
elif len(x)==1 and x[0]>1:
print("2")
elif sum(x[:-1])==sum(lst[:-1]):
print(x[-2]+1)
else:
j=0
k=0
while j<len(x):
if x... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
6 | A | Triangle | PROGRAMMING | 900 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allo... | The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks. | Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the s... | [
"4 2 1 3\n",
"7 2 2 4\n",
"3 5 9 1\n"
] | [
"TRIANGLE\n",
"SEGMENT\n",
"IMPOSSIBLE\n"
] | none | 0 | [
{
"input": "4 2 1 3",
"output": "TRIANGLE"
},
{
"input": "7 2 2 4",
"output": "SEGMENT"
},
{
"input": "3 5 9 1",
"output": "IMPOSSIBLE"
},
{
"input": "3 1 5 1",
"output": "IMPOSSIBLE"
},
{
"input": "10 10 10 10",
"output": "TRIANGLE"
},
{
"input": "11 ... | 1,624,599,259 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 10 | 154 | 0 | a = list(map(int, input().split()))
seg, imp, tri = False, False, False
for i in range(4):
f = a[:i] + a[i+1:]
if f[0] + f[1] == f[2]:
seg = True
if f[0] + f[1] < f[2]:
imp = True
if f[0] + f[1] > f[2] and f[2] + f[1] > f[0] and f[0] + f[2] > f[1]:
tri = True
if tri:
... | Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out o... | ```python
a = list(map(int, input().split()))
seg, imp, tri = False, False, False
for i in range(4):
f = a[:i] + a[i+1:]
if f[0] + f[1] == f[2]:
seg = True
if f[0] + f[1] < f[2]:
imp = True
if f[0] + f[1] > f[2] and f[2] + f[1] > f[0] and f[0] + f[2] > f[1]:
tri = True
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
691 | A | Fashion in Berland | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | According to rules of the Berland fashion, a jacket should be fastened by all the buttons except only one, but not necessarily it should be the last one. Also if the jacket has only one button, it should be fastened, so the jacket will not swinging open.
You are given a jacket with *n* buttons. Determine if it is fast... | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of buttons on the jacket.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=1). The number *a**i*<==<=0 if the *i*-th button is not fastened. Otherwise *a**i*<==<=1. | In the only line print the word "YES" if the jacket is fastened in a right way. Otherwise print the word "NO". | [
"3\n1 0 1\n",
"3\n1 0 0\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 0 1",
"output": "YES"
},
{
"input": "3\n1 0 0",
"output": "NO"
},
{
"input": "3\n1 1 0",
"output": "YES"
},
{
"input": "3\n1 1 1",
"output": "NO"
},
{
"input": "3\n0 0 1",
"output": "NO"
},
{
"input": "3\n0 0 0",
"output": "NO"
}... | 1,523,698,156 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 155 | 22,425,600 | a=[]
i=0
result=0
n_Interest = int(input())
for i in range(n_Interest):
min_Interest = int(input())
#tao Mang
a.insert(i, min_Interest)
# kiem tra dk
if a[0] > 16:
result = 15
if n_Interest == 1:
if a[0] > 15:
result = 15
else:
result = a[0]+15
else:
fo... | Title: Fashion in Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to rules of the Berland fashion, a jacket should be fastened by all the buttons except only one, but not necessarily it should be the last one. Also if the jacket has only one button, it should be fastened,... | ```python
a=[]
i=0
result=0
n_Interest = int(input())
for i in range(n_Interest):
min_Interest = int(input())
#tao Mang
a.insert(i, min_Interest)
# kiem tra dk
if a[0] > 16:
result = 15
if n_Interest == 1:
if a[0] > 15:
result = 15
else:
result = a[0]+15
els... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
710 | A | King Moves | PROGRAMMING | 800 | [
"implementation"
] | null | null | The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check the king's moves here [https://en.wikipedia.org/wiki/King_(chess)](https://en.wikipedia.org/wik... | The only line contains the king's position in the format "cd", where 'c' is the column from 'a' to 'h' and 'd' is the row from '1' to '8'. | Print the only integer *x* — the number of moves permitted for the king. | [
"e4\n"
] | [
"8\n"
] | none | 0 | [
{
"input": "e4",
"output": "8"
},
{
"input": "a1",
"output": "3"
},
{
"input": "h8",
"output": "3"
},
{
"input": "a4",
"output": "5"
},
{
"input": "g7",
"output": "8"
},
{
"input": "e1",
"output": "5"
},
{
"input": "b2",
"output": "8"
... | 1,472,048,696 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 4,608,000 | s=input()
b=s[0]
n=int(s[1])
print(b,n)
if b!="a" and b!="h":
if n!=1 and n!=8:
print(8)
else:
print(5)
else:
if n!=1 and n!=8:
print(5)
else:
print(3) | Title: King Moves
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The only king stands on the standard chess board. You are given his position in format "cd", where *c* is the column from 'a' to 'h' and *d* is the row from '1' to '8'. Find the number of moves permitted for the king.
Check... | ```python
s=input()
b=s[0]
n=int(s[1])
print(b,n)
if b!="a" and b!="h":
if n!=1 and n!=8:
print(8)
else:
print(5)
else:
if n!=1 and n!=8:
print(5)
else:
print(3)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-... | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transform... | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,607,778,364 | 2,147,483,647 | Python 3 | OK | TESTS | 51 | 248 | 1,536,000 | def getSum(n):
strr = str(n)
list_of_number = list(map(int, strr.strip()))
return sum(list_of_number)
n=input()
if len(n)==1:print(0);exit()
count=0
while True:
s=0
s = getSum(n)
count+=1
n=str(s)
if len(n)==1:
print(count)
break | Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came... | ```python
def getSum(n):
strr = str(n)
list_of_number = list(map(int, strr.strip()))
return sum(list_of_number)
n=input()
if len(n)==1:print(0);exit()
count=0
while True:
s=0
s = getSum(n)
count+=1
n=str(s)
if len(n)==1:
print(count)
break
``... | 3.935236 | MatrixStudio/Codeforces-Python-Submissions |
29 | A | Spit Problem | PROGRAMMING | 1,000 | [
"brute force"
] | A. Spit Problem | 2 | 256 | In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know if in the zoo there are two camels, which spitted at each other. Help him to solve this task.
... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the amount of camels in the zoo. Each of the following *n* lines contains two integers *x**i* and *d**i* (<=-<=104<=≤<=*x**i*<=≤<=104,<=1<=≤<=|*d**i*|<=≤<=2·104) — records in Bob's notepad. *x**i* is a position of the *i*-th camel, and *d**i* is a distance at wh... | If there are two camels, which spitted at each other, output YES. Otherwise, output NO. | [
"2\n0 1\n1 -1\n",
"3\n0 1\n1 1\n2 -2\n",
"5\n2 -10\n3 10\n0 5\n5 -5\n10 1\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "2\n0 1\n1 -1",
"output": "YES"
},
{
"input": "3\n0 1\n1 1\n2 -2",
"output": "NO"
},
{
"input": "5\n2 -10\n3 10\n0 5\n5 -5\n10 1",
"output": "YES"
},
{
"input": "10\n-9897 -1144\n-4230 -6350\n2116 -3551\n-3635 4993\n3907 -9071\n-2362 4120\n-6542 984\n5807 3745\n759... | 1,600,014,018 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 280 | 819,200 | from collections import Counter
import string
import math
import sys
def array_int():
return [int(i) for i in sys.stdin.readline().split()]
def vary(number_of_variables):
if number_of_variables==1:
return int(sys.stdin.readline())
if number_of_variables>=2:
return map(int,sys.stdin... | Title: Spit Problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know ... | ```python
from collections import Counter
import string
import math
import sys
def array_int():
return [int(i) for i in sys.stdin.readline().split()]
def vary(number_of_variables):
if number_of_variables==1:
return int(sys.stdin.readline())
if number_of_variables>=2:
return map(int... | 3.928474 | MatrixStudio/Codeforces-Python-Submissions |
845 | B | Luba And The Ticket | PROGRAMMING | 1,600 | [
"brute force",
"greedy",
"implementation"
] | null | null | Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make the ticket lucky.
The ticket is considered lucky if the sum of first three digits equals to the sum of las... | You are given a string consisting of 6 characters (all characters are digits from 0 to 9) — this string denotes Luba's ticket. The ticket can start with the digit 0. | Print one number — the minimum possible number of digits Luba needs to replace to make the ticket lucky. | [
"000000\n",
"123456\n",
"111000\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first example the ticket is already lucky, so the answer is 0.
In the second example Luba can replace 4 and 5 with zeroes, and the ticket will become lucky. It's easy to see that at least two replacements are required.
In the third example Luba can replace any zero with 3. It's easy to see that at least one re... | 0 | [
{
"input": "000000",
"output": "0"
},
{
"input": "123456",
"output": "2"
},
{
"input": "111000",
"output": "1"
},
{
"input": "120111",
"output": "0"
},
{
"input": "999999",
"output": "0"
},
{
"input": "199880",
"output": "1"
},
{
"input": "... | 1,503,867,492 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 0 | a=list(input())
for i in range(6):
a[i]=int(a[i])
a1=a[0:3]
a2=a[3:6]
ans=0
sa1=sum(a1)
sa2=sum(a2)
if sa1>sa2:
for i in range(3):
a2[i]=9
ans+=1
if sum(a2)>=sa1:
break
elif sa2>sa1:
for i in range(3):
a1[i]=9
ans+=1
if sum(... | Title: Luba And The Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make th... | ```python
a=list(input())
for i in range(6):
a[i]=int(a[i])
a1=a[0:3]
a2=a[3:6]
ans=0
sa1=sum(a1)
sa2=sum(a2)
if sa1>sa2:
for i in range(3):
a2[i]=9
ans+=1
if sum(a2)>=sa1:
break
elif sa2>sa1:
for i in range(3):
a1[i]=9
ans+=1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
322 | A | Ciel and Dancing | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room. | In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*. | [
"2 1\n",
"2 2\n"
] | [
"2\n1 1\n2 1\n",
"3\n1 1\n1 2\n2 2\n"
] | In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | 500 | [
{
"input": "2 1",
"output": "2\n1 1\n2 1"
},
{
"input": "2 2",
"output": "3\n1 1\n1 2\n2 2"
},
{
"input": "1 1",
"output": "1\n1 1"
},
{
"input": "2 3",
"output": "4\n1 1\n1 2\n1 3\n2 3"
},
{
"input": "4 4",
"output": "7\n1 1\n1 2\n1 3\n1 4\n4 4\n3 4\n2 4"
}... | 1,652,085,463 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
using namespace std;
int main()
{
int n, m;
cin >> n >> m;
cout << n + m - 1 << endl;
for (int i = 1; i <= m; ++i)
{
cout << "1 " << i << endl;
}
for (int i = 2; i <= n; ++i)
{
cout << i << " 1" << endl;
}
} | Title: Ciel and Dancing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. B... | ```python
#include <iostream>
using namespace std;
int main()
{
int n, m;
cin >> n >> m;
cout << n + m - 1 << endl;
for (int i = 1; i <= m; ++i)
{
cout << "1 " << i << endl;
}
for (int i = 2; i <= n; ++i)
{
cout << i << " 1" << endl;
}
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
278 | A | Circle Line | PROGRAMMING | 800 | [
"implementation"
] | null | null | The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th ... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) —... | Print a single number — the length of the shortest path between stations number *s* and *t*. | [
"4\n2 3 4 9\n1 3\n",
"4\n5 8 2 100\n4 1\n",
"3\n1 1 1\n3 1\n",
"3\n31 41 59\n1 1\n"
] | [
"5\n",
"15\n",
"1\n",
"0\n"
] | In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13.
In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15.
In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2.
In the fourth sample the numbers of st... | 500 | [
{
"input": "4\n2 3 4 9\n1 3",
"output": "5"
},
{
"input": "4\n5 8 2 100\n4 1",
"output": "15"
},
{
"input": "3\n1 1 1\n3 1",
"output": "1"
},
{
"input": "3\n31 41 59\n1 1",
"output": "0"
},
{
"input": "5\n16 13 10 30 15\n4 2",
"output": "23"
},
{
"inpu... | 1,598,321,620 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 186 | 307,200 | foo = int(input())
stationlens = input().split(' ')
station = input().split(' ')
dist0 = 0
dist1 = 0
for i in range(int(min(station))-1,int(max(station))-1):
dist0 += int(stationlens[i])
for i in range(foo):
if i not in range(int(min(station))-1,int(max(station))-1):
dist1 += int(stationlen... | Title: Circle Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd... | ```python
foo = int(input())
stationlens = input().split(' ')
station = input().split(' ')
dist0 = 0
dist1 = 0
for i in range(int(min(station))-1,int(max(station))-1):
dist0 += int(stationlens[i])
for i in range(foo):
if i not in range(int(min(station))-1,int(max(station))-1):
dist1 += int(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
501 | B | Misha and Changing Handles | PROGRAMMING | 1,100 | [
"data structures",
"dsu",
"strings"
] | null | null | Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is already used or that was used at some point.
Misha has a list of handle change requests. After completing the re... | The first line contains integer *q* (1<=≤<=*q*<=≤<=1000), the number of handle change requests.
Next *q* lines contain the descriptions of the requests, one per line.
Each query consists of two non-empty strings *old* and *new*, separated by a space. The strings consist of lowercase and uppercase Latin letters and di... | In the first line output the integer *n* — the number of users that changed their handles at least once.
In the next *n* lines print the mapping between the old and the new handles of the users. Each of them must contain two strings, *old* and *new*, separated by a space, meaning that before the user had handle *old*,... | [
"5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov\n"
] | [
"3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123\n"
] | none | 500 | [
{
"input": "5\nMisha ILoveCodeforces\nVasya Petrov\nPetrov VasyaPetrov123\nILoveCodeforces MikeMirzayanov\nPetya Ivanov",
"output": "3\nPetya Ivanov\nMisha MikeMirzayanov\nVasya VasyaPetrov123"
},
{
"input": "1\nMisha Vasya",
"output": "1\nMisha Vasya"
},
{
"input": "10\na b\nb c\nc d\nd... | 1,543,895,652 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n = input()
handles_dict = {}
i = 0
while i < int(n):
change = input().split(' ')
old = change[0]
new = change[1]
found = False
j = 0
while j < len(handles_dict):
if old in handles_dict[j]:
handles_dict[j].append(new)
found = True
j += 1
if not fo... | Title: Misha and Changing Handles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Misha hacked the Codeforces site. Then he decided to let all the users change their handles. A user can now change his handle any number of times. But each new handle must not be equal to any handle that is a... | ```python
n = input()
handles_dict = {}
i = 0
while i < int(n):
change = input().split(' ')
old = change[0]
new = change[1]
found = False
j = 0
while j < len(handles_dict):
if old in handles_dict[j]:
handles_dict[j].append(new)
found = True
j += 1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
868 | A | Bark to Unlock | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's p... | The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer *n* (1<=≤<=*n*<=≤<=100) — the number of words Kashtanka knows.
The next *n* lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to b... | Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"ya\n4\nah\noy\nto\nha\n",
"hp\n2\nht\ntp\n",
"ah\n1\nha\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" produ... | 250 | [
{
"input": "ya\n4\nah\noy\nto\nha",
"output": "YES"
},
{
"input": "hp\n2\nht\ntp",
"output": "NO"
},
{
"input": "ah\n1\nha",
"output": "YES"
},
{
"input": "bb\n4\nba\nab\naa\nbb",
"output": "YES"
},
{
"input": "bc\n4\nca\nba\nbb\ncc",
"output": "YES"
},
{
... | 1,520,975,510 | 2,147,483,647 | Python 3 | OK | TESTS | 90 | 62 | 5,632,000 | inp=input()
n=int(input())
ans=0
flag1=0
flag2=0
while n>0:
temp=input()
if temp==inp:
ans=1
if inp[1]==temp[0]:
flag2=1
if inp[0]==temp[1]:
flag1=1
n-=1
if ans or (flag1 and flag2):
print("YES")
else:
print("NO")
| Title: Bark to Unlock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a passw... | ```python
inp=input()
n=int(input())
ans=0
flag1=0
flag2=0
while n>0:
temp=input()
if temp==inp:
ans=1
if inp[1]==temp[0]:
flag2=1
if inp[0]==temp[1]:
flag1=1
n-=1
if ans or (flag1 and flag2):
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
37 | A | Towers | PROGRAMMING | 1,000 | [
"sortings"
] | A. Towers | 2 | 256 | Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct the minimal number of towers from the bars. Help Vasya to use the bars in the best way ... | The first line contains an integer *N* (1<=≤<=*N*<=≤<=1000) — the number of bars at Vasya’s disposal. The second line contains *N* space-separated integers *l**i* — the lengths of the bars. All the lengths are natural numbers not exceeding 1000. | In one line output two numbers — the height of the largest tower and their total number. Remember that Vasya should use all the bars. | [
"3\n1 2 3\n",
"4\n6 5 6 7\n"
] | [
"1 3\n",
"2 3\n"
] | none | 500 | [
{
"input": "3\n1 2 3",
"output": "1 3"
},
{
"input": "4\n6 5 6 7",
"output": "2 3"
},
{
"input": "4\n3 2 1 1",
"output": "2 3"
},
{
"input": "4\n1 2 3 3",
"output": "2 3"
},
{
"input": "3\n20 22 36",
"output": "1 3"
},
{
"input": "25\n47 30 94 41 45 20... | 1,682,261,613 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a = int(input())
b = [int(b) for b in input().split()]
count = [0] * (max(b)+1)
for i in b:
count[i]+=1
while 0 in count:
count.remove(0)
print(max(count),len(cou | Title: Towers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Vasya has received a young builder’s kit. The kit consists of several wooden bars, the lengths of all of them are known. The bars can be put one on the top of the other if their lengths are the same.
Vasya wants to construct... | ```python
a = int(input())
b = [int(b) for b in input().split()]
count = [0] * (max(b)+1)
for i in b:
count[i]+=1
while 0 in count:
count.remove(0)
print(max(count),len(cou
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
961 | B | Lecture Sleep | PROGRAMMING | 1,200 | [
"data structures",
"dp",
"implementation",
"two pointers"
] | null | null | Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for all the time of lecture. You are given an array *t* of Mishka's behavior. If Mishka is asleep during ... | The first line of the input contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105) — the duration of the lecture in minutes and the number of minutes you can keep Mishka awake.
The second line of the input contains *n* integer numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=104) — the number of theore... | Print only one integer — the maximum number of theorems Mishka will be able to write down if you use your technique only once to wake him up. | [
"6 3\n1 3 5 2 5 4\n1 1 0 1 0 0\n"
] | [
"16\n"
] | In the sample case the better way is to use the secret technique at the beginning of the third minute. Then the number of theorems Mishka will be able to write down will be equal to 16. | 0 | [
{
"input": "6 3\n1 3 5 2 5 4\n1 1 0 1 0 0",
"output": "16"
},
{
"input": "5 3\n1 9999 10000 10000 10000\n0 0 0 0 0",
"output": "30000"
},
{
"input": "3 3\n10 10 10\n1 1 0",
"output": "30"
},
{
"input": "1 1\n423\n0",
"output": "423"
},
{
"input": "6 6\n1 3 5 2 5 4... | 1,672,847,026 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 234 | 6,246,400 | lecture_minute ,awake_minute = input().split()
thoerems = [int(theorem) for theorem in input().split()]
behavior = input().split()
# take the first n lecures as a starting or max lectures found so far
initial = sum(thoerems[:int(awake_minute)])
index = 1
max_theorems = initial
# if the ith -1 behaviour ... | Title: Lecture Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for al... | ```python
lecture_minute ,awake_minute = input().split()
thoerems = [int(theorem) for theorem in input().split()]
behavior = input().split()
# take the first n lecures as a starting or max lectures found so far
initial = sum(thoerems[:int(awake_minute)])
index = 1
max_theorems = initial
# if the ith -1 ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
777 | D | Cloud of Hashtags | PROGRAMMING | 1,800 | [
"binary search",
"greedy",
"implementation",
"strings"
] | null | null | Vasya is an administrator of a public page of organization "Mouse and keyboard" and his everyday duty is to publish news from the world of competitive programming. For each news he also creates a list of hashtags to make searching for a particular topic more comfortable. For the purpose of this problem we define hashta... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=500<=000) — the number of hashtags being edited now.
Each of the next *n* lines contains exactly one hashtag of positive length.
It is guaranteed that the total length of all hashtags (i.e. the total length of the string except for characters '#... | Print the resulting hashtags in any of the optimal solutions. | [
"3\n#book\n#bigtown\n#big\n",
"3\n#book\n#cool\n#cold\n",
"4\n#car\n#cart\n#art\n#at\n",
"3\n#apple\n#apple\n#fruit\n"
] | [
"#b\n#big\n#big\n",
"#book\n#co\n#cold\n",
"#\n#\n#art\n#at\n",
"#apple\n#apple\n#fruit\n"
] | Word *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*m*</sub> of length *m* is lexicographically not greater than word *b*<sub class="lower-index">1</sub>, *b*<sub class="lower-index">2</sub>, ..., *b*<sub class="lower-index">*k*</sub> of length *k*, if one of... | 2,000 | [
{
"input": "3\n#book\n#bigtown\n#big",
"output": "#b\n#big\n#big"
},
{
"input": "3\n#book\n#cool\n#cold",
"output": "#book\n#co\n#cold"
},
{
"input": "4\n#car\n#cart\n#art\n#at",
"output": "#\n#\n#art\n#at"
},
{
"input": "3\n#apple\n#apple\n#fruit",
"output": "#apple\n#ap... | 1,487,945,174 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 10 | 1,138 | 28,569,600 | def f(x,c):
j=0
for i in range(len(c)-1,-1,-1):
if len(c[i])==x or c[i][x]<c[i-1][x]:
j=i;break
for i in range(j):c[i]=c[i][:x];
aa,bb=j,j+1
while bb<len(c):
while bb<len(c) and c[aa][x]==c[bb][x]:bb+=1
if(bb-aa>1):c[aa:bb]=f(x+1,c[aa:bb])
aa=bb;bb=aa+1
... | Title: Cloud of Hashtags
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is an administrator of a public page of organization "Mouse and keyboard" and his everyday duty is to publish news from the world of competitive programming. For each news he also creates a list of hashtags to m... | ```python
def f(x,c):
j=0
for i in range(len(c)-1,-1,-1):
if len(c[i])==x or c[i][x]<c[i-1][x]:
j=i;break
for i in range(j):c[i]=c[i][:x];
aa,bb=j,j+1
while bb<len(c):
while bb<len(c) and c[aa][x]==c[bb][x]:bb+=1
if(bb-aa>1):c[aa:bb]=f(x+1,c[aa:bb])
aa=bb;... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
638 | A | Home Numbers | PROGRAMMING | 1,100 | [
"*special",
"constructive algorithms",
"math"
] | null | null | The main street of Berland is a straight line with *n* houses built along it (*n* is an even number). The houses are located at both sides of the street. The houses with odd numbers are at one side of the street and are numbered from 1 to *n*<=-<=1 in the order from the beginning of the street to the end (in the pictur... | The first line of the input contains two integers, *n* and *a* (1<=≤<=*a*<=≤<=*n*<=≤<=100<=000) — the number of houses on the street and the number of the house that Vasya needs to reach, correspondingly. It is guaranteed that number *n* is even. | Print a single integer — the minimum time Vasya needs to get from the beginning of the street to house *a*. | [
"4 2\n",
"8 5\n"
] | [
"2\n",
"3\n"
] | In the first sample there are only four houses on the street, two houses at each side. House 2 will be the last at Vasya's right.
The second sample corresponds to picture with *n* = 8. House 5 is the one before last at Vasya's left. | 500 | [
{
"input": "4 2",
"output": "2"
},
{
"input": "8 5",
"output": "3"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "2 2",
"output": "1"
},
{
"input": "10 1",
"output": "1"
},
{
"input": "10 10",
"output": "1"
},
{
"input": "100000 100000",... | 1,461,253,778 | 2,147,483,647 | Python 3 | OK | TESTS | 69 | 62 | 4,915,200 | n, a = map(int, input().split())
print(a // 2 + 1 if a % 2 else (n - a + 2) // 2) | Title: Home Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The main street of Berland is a straight line with *n* houses built along it (*n* is an even number). The houses are located at both sides of the street. The houses with odd numbers are at one side of the street and are nu... | ```python
n, a = map(int, input().split())
print(a // 2 + 1 if a % 2 else (n - a + 2) // 2)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,636,084,056 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 62 | 4,505,600 | n,m=[int(x) for x in input().split()]
res=0
for i in range(n):
a=[int(x) for x in input().split()]
for i in range(0,len(a),2):
if a[i]+a[i+1]>=1:
res+=1
print(res) | Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
n,m=[int(x) for x in input().split()]
res=0
for i in range(n):
a=[int(x) for x in input().split()]
for i in range(0,len(a),2):
if a[i]+a[i+1]>=1:
res+=1
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
989 | B | A Tide of Riverscape | PROGRAMMING | 1,200 | [
"constructive algorithms",
"strings"
] | null | null | "Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its own period, and I think I've figured out this one," says Mino with confidence.
Doubtfully, Kanno peeks a... | The first line contains two space-separated integers $n$ and $p$ ($1 \leq p \leq n \leq 2000$) — the length of the given string and the supposed period, respectively.
The second line contains a string $s$ of $n$ characters — Mino's records. $s$ only contains characters '0', '1' and '.', and contains at least one '.' c... | Output one line — if it's possible that $p$ is not a period of the resulting string, output any one of such strings; otherwise output "No" (without quotes, you can print letters in any case (upper or lower)). | [
"10 7\n1.0.1.0.1.\n",
"10 6\n1.0.1.1000\n",
"10 9\n1........1\n"
] | [
"1000100010\n",
"1001101000\n",
"No\n"
] | In the first example, $7$ is not a period of the resulting string because the $1$-st and $8$-th characters of it are different.
In the second example, $6$ is not a period of the resulting string because the $4$-th and $10$-th characters of it are different.
In the third example, $9$ is always a period because the onl... | 1,000 | [
{
"input": "10 7\n1.0.1.0.1.",
"output": "1000100010"
},
{
"input": "10 6\n1.0.1.1000",
"output": "1001101000"
},
{
"input": "10 9\n1........1",
"output": "No"
},
{
"input": "1 1\n.",
"output": "No"
},
{
"input": "5 1\n0...1",
"output": "00001"
},
{
"i... | 1,528,950,955 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 93 | 0 | n, p = map(int, input().split())
s, r, t = input(), 'No', {'0', '1'}
s0, s1 = s.replace('.', '0'), s.replace('.', '1')
for i in range(p):
if set(s0[i::p]) & t == t:
r = s0
break
elif set(s1[i::p]) & t == t:
r = s1
break
print(r) | Title: A Tide of Riverscape
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Time," Mino thinks aloud.
"What?"
"Time and tide wait for no man," explains Mino. "My name, taken from the river, always reminds me of this."
"And what are you recording?"
"You see it, tide. Everything has its... | ```python
n, p = map(int, input().split())
s, r, t = input(), 'No', {'0', '1'}
s0, s1 = s.replace('.', '0'), s.replace('.', '1')
for i in range(p):
if set(s0[i::p]) & t == t:
r = s0
break
elif set(s1[i::p]) & t == t:
r = s1
break
print(r)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
454 | B | Little Pony and Sort by Shift | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. That is, she can move the last element of the sequence to its beginning:
Help Twilight Sparkle to calculate: what ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=105). The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | If it's impossible to sort the sequence output -1. Otherwise output the minimum number of operations Twilight Sparkle needs to sort it. | [
"2\n2 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"1\n",
"-1\n",
"0\n"
] | none | 1,000 | [
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "3\n1 3 2",
"output": "-1"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "6\n3 4 5 6 3 2",
"output": "-1"
},
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "5\n1 1 2 1 1",
"output": "2"
}... | 1,598,827,360 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 155 | 14,438,400 | n=int(input())
s=list(map(int,input().split()))
k=sorted(s)
m=min(s)
if m==s[0]:
c=0
s.reverse()
for j in s:
if j==m:
c+=1
else:
break
v=n-c
s.reverse()
else:
v=s.index(m)
x=s[v:n]
e=[]
for i in range(n-len(x)):
e.append(s[i])
if s=... | Title: Little Pony and Sort by Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, Twilight Sparkle is interested in how to sort a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. ... | ```python
n=int(input())
s=list(map(int,input().split()))
k=sorted(s)
m=min(s)
if m==s[0]:
c=0
s.reverse()
for j in s:
if j==m:
c+=1
else:
break
v=n-c
s.reverse()
else:
v=s.index(m)
x=s[v:n]
e=[]
for i in range(n-len(x)):
e.append(s[... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
373 | A | Collecting Beats is Fun | PROGRAMMING | 900 | [
"implementation"
] | null | null | Cucumber boy is fan of Kyubeat, a famous music game.
Kyubeat has 16 panels for playing arranged in 4<=×<=4 table. When a panel lights up, he has to press that panel.
Each panel has a timing to press (the preffered time when a player should press it), and Cucumber boy is able to press at most *k* panels in a time with... | The first line contains a single integer *k* (1<=≤<=*k*<=≤<=5) — the number of panels Cucumber boy can press with his one hand.
Next 4 lines contain 4 characters each (digits from 1 to 9, or period) — table of panels. If a digit *i* was written on the panel, it means the boy has to press that panel in time *i*. If per... | Output "YES" (without quotes), if he is able to press all the panels in perfect timing. If not, output "NO" (without quotes). | [
"1\n.135\n1247\n3468\n5789\n",
"5\n..1.\n1111\n..1.\n..1.\n",
"1\n....\n12.1\n.2..\n.2..\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the third sample boy cannot press all panels in perfect timing. He can press all the panels in timing in time 1, but he cannot press the panels in time 2 in timing with his two hands. | 500 | [
{
"input": "1\n.135\n1247\n3468\n5789",
"output": "YES"
},
{
"input": "5\n..1.\n1111\n..1.\n..1.",
"output": "YES"
},
{
"input": "1\n....\n12.1\n.2..\n.2..",
"output": "NO"
},
{
"input": "1\n6981\n.527\n4163\n2345",
"output": "YES"
},
{
"input": "5\n9999\n9999\n99... | 1,388,327,412 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 307,200 |
def collecting(k):
n = [k]*9
for c in input():
if c != '.':
i = int(c)
n[i] -= 1
if n[i] < 0:
print('NO')
return
print('YES')
return
def main():
k = int(input())
collecting(k)
if __name__ == '__main__':
main() | Title: Collecting Beats is Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Cucumber boy is fan of Kyubeat, a famous music game.
Kyubeat has 16 panels for playing arranged in 4<=×<=4 table. When a panel lights up, he has to press that panel.
Each panel has a timing to press (the preff... | ```python
def collecting(k):
n = [k]*9
for c in input():
if c != '.':
i = int(c)
n[i] -= 1
if n[i] < 0:
print('NO')
return
print('YES')
return
def main():
k = int(input())
collecting(k)
if __name__ == '__main__':
main()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
884 | D | Boxes And Balls | PROGRAMMING | 2,300 | [
"data structures",
"greedy"
] | null | null | Ivan has *n* different boxes. The first of them contains some balls of *n* different colors.
Ivan wants to play a strange game. He wants to distribute the balls into boxes in such a way that for every *i* (1<=≤<=*i*<=≤<=*n*) *i*-th box will contain all balls with color *i*.
In order to do this, Ivan will make some tu... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200000) — the number of boxes and colors.
The second line contains *n* integer numbers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the number of balls with color *i*. | Print one number — the minimum possible penalty of the game. | [
"3\n1 2 3\n",
"4\n2 3 4 5\n"
] | [
"6\n",
"19\n"
] | In the first example you take all the balls from the first box, choose *k* = 3 and sort all colors to corresponding boxes. Penalty is 6.
In the second example you make two turns:
1. Take all the balls from the first box, choose *k* = 3, put balls of color 3 to the third box, of color 4 — to the fourth box and the r... | 0 | [
{
"input": "3\n1 2 3",
"output": "6"
},
{
"input": "4\n2 3 4 5",
"output": "19"
},
{
"input": "6\n1 4 4 4 4 4",
"output": "38"
},
{
"input": "8\n821407370 380061316 428719552 90851747 825473738 704702117 845629927 245820158",
"output": "8176373828"
},
{
"input": "... | 1,509,120,070 | 6,970 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | total_box = input()
balls = 0
total_balls = 0
boxballs = input().split()
while(balls < int(total_box)):
total_balls = total_balls + int(boxballs[balls])
balls += 1
penalty = 0
check_boxballs = 0
check = 0
times_check = len(boxballs) // 3
s = sorted(boxballs)
# while(check < boxballs):
d... | Title: Boxes And Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has *n* different boxes. The first of them contains some balls of *n* different colors.
Ivan wants to play a strange game. He wants to distribute the balls into boxes in such a way that for every *i* (1<=≤<=*i*<=≤... | ```python
total_box = input()
balls = 0
total_balls = 0
boxballs = input().split()
while(balls < int(total_box)):
total_balls = total_balls + int(boxballs[balls])
balls += 1
penalty = 0
check_boxballs = 0
check = 0
times_check = len(boxballs) // 3
s = sorted(boxballs)
# while(check < box... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
961 | B | Lecture Sleep | PROGRAMMING | 1,200 | [
"data structures",
"dp",
"implementation",
"two pointers"
] | null | null | Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for all the time of lecture. You are given an array *t* of Mishka's behavior. If Mishka is asleep during ... | The first line of the input contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105) — the duration of the lecture in minutes and the number of minutes you can keep Mishka awake.
The second line of the input contains *n* integer numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=104) — the number of theore... | Print only one integer — the maximum number of theorems Mishka will be able to write down if you use your technique only once to wake him up. | [
"6 3\n1 3 5 2 5 4\n1 1 0 1 0 0\n"
] | [
"16\n"
] | In the sample case the better way is to use the secret technique at the beginning of the third minute. Then the number of theorems Mishka will be able to write down will be equal to 16. | 0 | [
{
"input": "6 3\n1 3 5 2 5 4\n1 1 0 1 0 0",
"output": "16"
},
{
"input": "5 3\n1 9999 10000 10000 10000\n0 0 0 0 0",
"output": "30000"
},
{
"input": "3 3\n10 10 10\n1 1 0",
"output": "30"
},
{
"input": "1 1\n423\n0",
"output": "423"
},
{
"input": "6 6\n1 3 5 2 5 4... | 1,600,290,297 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 217 | 10,956,800 | n, k = [int(x) for x in input().split()]
teoremas = [int(x) for x in input().split()]
acordado = input().split()
teoremasAc = [0] * (n + 1)
teoremasWakeAc = [0] * (n + 1)
for i in range(1,n+1):
teoremasAc[i] = teoremas[i-1] + teoremasAc[i-1]
teoremasWakeAc[i] = teoremasWakeAc[i-1]
if acordado[i-1] == "1":
teorem... | Title: Lecture Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for al... | ```python
n, k = [int(x) for x in input().split()]
teoremas = [int(x) for x in input().split()]
acordado = input().split()
teoremasAc = [0] * (n + 1)
teoremasWakeAc = [0] * (n + 1)
for i in range(1,n+1):
teoremasAc[i] = teoremas[i-1] + teoremasAc[i-1]
teoremasWakeAc[i] = teoremasWakeAc[i-1]
if acordado[i-1] == "1"... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated ... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,561,820,658 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 218 | 0 | input(); vals = [*map(int, input().split())]
vals.sort()
for i in range(1, len(vals)):
if vals[i] - vals[i-1] != 1:
print(vals[i-1] + 1)
exit(0)
print(vals[-1]+1)
| Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the... | ```python
input(); vals = [*map(int, input().split())]
vals.sort()
for i in range(1, len(vals)):
if vals[i] - vals[i-1] != 1:
print(vals[i-1] + 1)
exit(0)
print(vals[-1]+1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
854 | B | Maxim Buys an Apartment | PROGRAMMING | 1,200 | [
"constructive algorithms",
"math"
] | null | null | Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices differ by 1. Some of the apartments can already be inhabited, others are available for sale.
Maxim often visi... | The only line of the input contains two integers: *n* and *k* (1<=≤<=*n*<=≤<=109, 0<=≤<=*k*<=≤<=*n*). | Print the minimum possible and the maximum possible number of apartments good for Maxim. | [
"6 3\n"
] | [
"1 3\n"
] | In the sample test, the number of good apartments could be minimum possible if, for example, apartments with indices 1, 2 and 3 were inhabited. In this case only apartment 4 is good. The maximum possible number could be, for example, if apartments with indices 1, 3 and 5 were inhabited. In this case all other apartment... | 1,000 | [
{
"input": "6 3",
"output": "1 3"
},
{
"input": "10 1",
"output": "1 2"
},
{
"input": "10 9",
"output": "1 1"
},
{
"input": "8 0",
"output": "0 0"
},
{
"input": "8 8",
"output": "0 0"
},
{
"input": "966871928 890926970",
"output": "1 75944958"
},... | 1,514,056,641 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 61 | 5,529,600 | def main():
line = input()
line = line.split(' ')
n = int(line[0])
k = int(line[1])
minimum = 1
if k == 0 or k == n:
minimum = 0
maximum = 2 * k
if k > (n / 3):
k = k - (n / 3)
if (n % 3 == 1):
k -= 1
if (n % 3 == 2):
k -= 1
... | Title: Maxim Buys an Apartment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maxim wants to buy an apartment in a new house at Line Avenue of Metropolis. The house has *n* apartments that are numbered from 1 to *n* and are arranged in a row. Two apartments are adjacent if their indices d... | ```python
def main():
line = input()
line = line.split(' ')
n = int(line[0])
k = int(line[1])
minimum = 1
if k == 0 or k == n:
minimum = 0
maximum = 2 * k
if k > (n / 3):
k = k - (n / 3)
if (n % 3 == 1):
k -= 1
if (n % 3 == 2):
k ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin b... | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,620,467,824 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 109 | 20,172,800 | import math
r, x1, y1, x2, y2 = map(int, input().split())
distance = math.pow(math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2), 0.5)
print(math.ceil(distance / (r * 2)))
| Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can ... | ```python
import math
r, x1, y1, x2, y2 = map(int, input().split())
distance = math.pow(math.pow(x2 - x1, 2) + math.pow(y2 - y1, 2), 0.5)
print(math.ceil(distance / (r * 2)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentall... | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,698,982,608 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | # LUOGU_RID: 133058732
'''
#include<bits/stdc++.h>//1
using namespace std;//xx
string a;
int main()//fayHVGDUS
{
cin>>a;
for(int i=0;i<a.size();i++){
if(i==0&&a[i]>='a'&&a[i]<='z'){
toupper(a[i]);
}
else{
tolower(a[i]);
}
}
cout<<a;
return 0;
}... | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in th... | ```python
# LUOGU_RID: 133058732
'''
#include<bits/stdc++.h>//1
using namespace std;//xx
string a;
int main()//fayHVGDUS
{
cin>>a;
for(int i=0;i<a.size();i++){
if(i==0&&a[i]>='a'&&a[i]<='z'){
toupper(a[i]);
}
else{
tolower(a[i]);
}
}
cout<<a;
r... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
370 | A | Rook, Bishop and King | PROGRAMMING | 1,100 | [
"graphs",
"math",
"shortest paths"
] | null | null | Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=8 table. A field is represented by a pair of integers (*r*,<=*c*) — the number of the row and the number of... | The input contains four integers *r*1,<=*c*1,<=*r*2,<=*c*2 (1<=≤<=*r*1,<=*c*1,<=*r*2,<=*c*2<=≤<=8) — the coordinates of the starting and the final field. The starting field doesn't coincide with the final one.
You can assume that the chessboard rows are numbered from top to bottom 1 through 8, and the columns are numb... | Print three space-separated integers: the minimum number of moves the rook, the bishop and the king (in this order) is needed to move from field (*r*1,<=*c*1) to field (*r*2,<=*c*2). If a piece cannot make such a move, print a 0 instead of the corresponding number. | [
"4 3 1 6\n",
"5 5 5 6\n"
] | [
"2 1 3\n",
"1 0 1\n"
] | none | 500 | [
{
"input": "4 3 1 6",
"output": "2 1 3"
},
{
"input": "5 5 5 6",
"output": "1 0 1"
},
{
"input": "1 1 8 8",
"output": "2 1 7"
},
{
"input": "1 1 8 1",
"output": "1 0 7"
},
{
"input": "1 1 1 8",
"output": "1 0 7"
},
{
"input": "8 1 1 1",
"output": "... | 1,667,540,709 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 46 | 0 | x1, y1, x2, y2 = map(int, input().split())
x1 = abs(x1-x2)
y1 = abs(y1-y2)
t = min(x1, 1) + min(y1, 1)
k = max(x1, y1)
p = 2
if x1 == y1:
p = 1
elif x1+y1 == 0 or (x1+y1)%2:
p = 0
print(t, p, k)
| Title: Rook, Bishop and King
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya is learning to play chess. He has already learned how to move a king, a rook and a bishop. Let us remind you the rules of moving chess pieces. A chessboard is 64 square fields organized into an 8<=×<=... | ```python
x1, y1, x2, y2 = map(int, input().split())
x1 = abs(x1-x2)
y1 = abs(y1-y2)
t = min(x1, 1) + min(y1, 1)
k = max(x1, y1)
p = 2
if x1 == y1:
p = 1
elif x1+y1 == 0 or (x1+y1)%2:
p = 0
print(t, p, k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
6 | D | Lizards and Basements 2 | PROGRAMMING | 2,600 | [
"brute force",
"dp"
] | D. Lizards and Basements 2 | 2 | 64 | This is simplified version of the problem used on the original contest. The original problem seems to have too difiicult solution. The constraints for input data have been reduced.
Polycarp likes to play computer role-playing game «Lizards and Basements». At the moment he is playing it as a magician. At one of the las... | The first line of the input contains three integers *n*,<=*a*,<=*b* (3<=≤<=*n*<=≤<=10; 1<=≤<=*b*<=<<=*a*<=≤<=10). The second line contains a sequence of *n* integers — *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=15), where *h**i* is the amount of health points the *i*-th archer has. | In the first line print *t* — the required minimum amount of fire balls.
In the second line print *t* numbers — indexes of the archers that Polycarp should hit to kill all the archers in *t* shots. All these numbers should be between 2 and *n*<=-<=1. Separate numbers with spaces. If there are several solutions, output... | [
"3 2 1\n2 2 2\n",
"4 3 1\n1 4 1 1\n"
] | [
"3\n2 2 2 ",
"4\n2 2 3 3 "
] | none | 0 | [
{
"input": "3 2 1\n2 2 2",
"output": "3\n2 2 2 "
},
{
"input": "4 3 1\n1 4 1 1",
"output": "4\n2 2 3 3 "
},
{
"input": "3 5 3\n1 2 1",
"output": "1\n2 "
},
{
"input": "3 5 3\n3 2 2",
"output": "2\n2 2 "
},
{
"input": "3 5 3\n3 2 2",
"output": "2\n2 2 "
},
... | 1,500,459,511 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 22 | 2,000 | 4,915,200 | def dfs(step, left, mx):
if step == 0:
for i in range(left, n):
if h[i] >= 0:
return False
return True
elif h[left] < 0:
if dfs(step, left + 1, mx):
return True
elif left == n - 1:
h[left] -= b
ans[step] = left - 1
... | Title: Lizards and Basements 2
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
This is simplified version of the problem used on the original contest. The original problem seems to have too difiicult solution. The constraints for input data have been reduced.
Polycarp likes to play computer ro... | ```python
def dfs(step, left, mx):
if step == 0:
for i in range(left, n):
if h[i] >= 0:
return False
return True
elif h[left] < 0:
if dfs(step, left + 1, mx):
return True
elif left == n - 1:
h[left] -= b
ans[step] = l... | 0 | MatrixStudio/Codeforces-Python-Submissions |
277 | A | Learning Languages | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu"
] | null | null | The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have the list of languages, which he knows. This list could be empty, i. e. an employee may know no official la... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=100) — the number of employees and the number of languages.
Then *n* lines follow — each employee's language list. At the beginning of the *i*-th line is integer *k**i* (0<=≤<=*k**i*<=≤<=*m*) — the number of languages the *i*-th employee knows. Next... | Print a single integer — the minimum amount of money to pay so that in the end every employee could write a letter to every other one (other employees can help out translating). | [
"5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5\n",
"8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1\n",
"2 2\n1 2\n0\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the second sample the employee 1 can learn language 2, and employee 8 can learn language 4.
In the third sample employee 2 must learn language 2. | 500 | [
{
"input": "5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5",
"output": "0"
},
{
"input": "8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1",
"output": "2"
},
{
"input": "2 2\n1 2\n0",
"output": "1"
},
{
"input": "2 2\n0\n0",
"output": "2"
},
{
"input": "5 5\n1 3\n0\n0\n2 4... | 1,578,129,905 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 307,200 | n, nLangs = map(int, input().split())
a = [set()]
for i in range(1, n + 1):
a.append(set(list(map(int, input().split()))[1:]))
g = [[] for _ in range(n + 1)]
for p1 in range(1, n):
for p2 in range(p1 + 1, n + 1):
if a[p1].intersection(a[p2]):
g[p1].append(p2)
g[p2].app... | Title: Learning Languages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have th... | ```python
n, nLangs = map(int, input().split())
a = [set()]
for i in range(1, n + 1):
a.append(set(list(map(int, input().split()))[1:]))
g = [[] for _ in range(n + 1)]
for p1 in range(1, n):
for p2 in range(p1 + 1, n + 1):
if a[p1].intersection(a[p2]):
g[p1].append(p2)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
958 | D1 | Hyperspace Jump (easy) | PROGRAMMING | 1,400 | [
"expression parsing",
"math"
] | null | null | The Rebel fleet is on the run. It consists of *m* ships currently gathered around a single planet. Just a few seconds ago, the vastly more powerful Empire fleet has appeared in the same solar system, and the Rebels will need to escape into hyperspace. In order to spread the fleet, the captain of each ship has independe... | The first line of the input contains a single integer *m* (1<=≤<=*m*<=≤<=200<=000) – the number of ships. The next *m* lines describe one jump coordinate each, given as an arithmetic expression. An expression has the form (a+b)/c. Namely, it consists of: an opening parenthesis (, a positive integer *a* of up to two dec... | Print a single line consisting of *m* space-separated integers. The *i*-th integer should be equal to the number of ships whose coordinate is equal to that of the *i*-th ship (including the *i*-th ship itself). | [
"4\n(99+98)/97\n(26+4)/10\n(12+33)/15\n(5+1)/7\n"
] | [
"1 2 2 1 "
] | In the sample testcase, the second and the third ship will both end up at the coordinate 3.
Note that this problem has only two versions – easy and hard. | 0 | [
{
"input": "4\n(99+98)/97\n(26+4)/10\n(12+33)/15\n(5+1)/7",
"output": "1 2 2 1 "
},
{
"input": "10\n(44+98)/19\n(36+58)/47\n(62+74)/68\n(69+95)/82\n(26+32)/29\n(32+46)/39\n(32+24)/28\n(47+61)/54\n(39+13)/26\n(98+98)/98",
"output": "1 9 9 9 9 9 9 9 9 9 "
},
{
"input": "30\n(89+76)/87\n(81... | 1,523,691,777 | 2,277 | Python 3 | OK | TESTS | 16 | 4,055 | 27,136,000 | n = int(input())
ccnt = {}
sn = {}
for i in range(1, n+1):
s = input()
res = eval(s)
res = str(format(res, '.6f'))
if (res in ccnt):
ccnt[res] += 1
else:
ccnt[res] = 1
sn[i] = res
for i in range(1, n+1):
print(str(ccnt[sn[i]]) + " ", end='')
print() | Title: Hyperspace Jump (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Rebel fleet is on the run. It consists of *m* ships currently gathered around a single planet. Just a few seconds ago, the vastly more powerful Empire fleet has appeared in the same solar system, and the Rebe... | ```python
n = int(input())
ccnt = {}
sn = {}
for i in range(1, n+1):
s = input()
res = eval(s)
res = str(format(res, '.6f'))
if (res in ccnt):
ccnt[res] += 1
else:
ccnt[res] = 1
sn[i] = res
for i in range(1, n+1):
print(str(ccnt[sn[i]]) + " ", end='')
print()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | На тренировку по подготовке к соревнованиям по программированию пришли *n* команд. Тренер для каждой команды подобрал тренировку, комплект задач для *i*-й команды занимает *a**i* страниц. В распоряжении тренера есть *x* листов бумаги, у которых обе стороны чистые, и *y* листов, у которых только одна сторона чистая. При... | В первой строке входных данных следуют три целых числа *n*, *x* и *y* (1<=≤<=*n*<=≤<=200<=000, 0<=≤<=*x*,<=*y*<=≤<=109) — количество команд, количество листов бумаги с двумя чистыми сторонами и количество листов бумаги с одной чистой стороной.
Во второй строке входных данных следует последовательность из *n* целых чис... | Выведите единственное целое число — максимальное количество команд, которым тренер сможет напечатать комплекты задач целиком. | [
"2 3 5\n4 6\n",
"2 3 5\n4 7\n",
"6 3 5\n12 11 12 11 12 11\n"
] | [
"2\n",
"2\n",
"1\n"
] | В первом тестовом примере можно напечатать оба комплекта задач. Один из возможных ответов — напечатать весь первый комплект задач на листах с одной чистой стороной (после этого останется 3 листа с двумя чистыми сторонами и 1 лист с одной чистой стороной), а второй комплект напечатать на трех листах с двумя чистыми стор... | 0 | [
{
"input": "2 3 5\n4 6",
"output": "2"
},
{
"input": "2 3 5\n4 7",
"output": "2"
},
{
"input": "6 3 5\n12 11 12 11 12 11",
"output": "1"
},
{
"input": "1 4 3\n12",
"output": "0"
},
{
"input": "10 1 17\n3 1 1 2 1 3 4 4 1 4",
"output": "8"
},
{
"input": ... | 1,458,982,310 | 6,710 | PyPy 3 | OK | TESTS | 173 | 343 | 38,297,600 | def main():
read = lambda: map(int, input().split())
n, x, y = read()
a = sorted(read())
cnt = 0
for k in a:
if 2 * x + y < k:
break
if k % 2 == 0 and 2 * x >= k:
cx = k // 2
cy = 0
elif k % 2 == 0 and 2 * x < k:
cx ... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
На тренировку по подготовке к соревнованиям по программированию пришли *n* команд. Тренер для каждой команды подобрал тренировку, комплект задач для *i*-й команды занимает *a**i* страниц. В распоряжении тренера есть *x* листов бум... | ```python
def main():
read = lambda: map(int, input().split())
n, x, y = read()
a = sorted(read())
cnt = 0
for k in a:
if 2 * x + y < k:
break
if k % 2 == 0 and 2 * x >= k:
cx = k // 2
cy = 0
elif k % 2 == 0 and 2 * x < k:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
908 | A | New Year and Counting Cards | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a c... | The first and only line of input will contain a string *s* (1<=≤<=|*s*|<=≤<=50), denoting the sides of the cards that you can see on the table currently. Each character of *s* is either a lowercase English letter or a digit. | Print a single integer, the minimum number of cards you must turn over to verify your claim. | [
"ee\n",
"z\n",
"0ay1\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on th... | 500 | [
{
"input": "ee",
"output": "2"
},
{
"input": "z",
"output": "0"
},
{
"input": "0ay1",
"output": "2"
},
{
"input": "0abcdefghijklmnopqrstuvwxyz1234567896",
"output": "10"
},
{
"input": "0a0a9e9e2i2i9o9o6u6u9z9z4x4x9b9b",
"output": "18"
},
{
"input": "01... | 1,618,594,441 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 62 | 0 | #Problem Set A: Collaborated with no one
str1 = input()
result = map(str1.count, 'aeiou13579')
final_ans = sum(result)
print(final_ans)
| Title: New Year and Counting Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each car... | ```python
#Problem Set A: Collaborated with no one
str1 = input()
result = map(str1.count, 'aeiou13579')
final_ans = sum(result)
print(final_ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,640,504,848 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 92 | 0 | inp=list(map(int,input().split()))
n=inp[0]
m=inp[1]
a=list(map(int,input().split()))
a.sort()
c=0
for x in range(m):
if(a[x]<0):
c=c+(-1*a[x])
else:
break
print(c) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
inp=list(map(int,input().split()))
n=inp[0]
m=inp[1]
a=list(map(int,input().split()))
a.sort()
c=0
for x in range(m):
if(a[x]<0):
c=c+(-1*a[x])
else:
break
print(c)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
656 | A | Da Vinci Powers | PROGRAMMING | 1,900 | [
"*special"
] | null | null | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer. | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35). | Output a single integer. | [
"3\n",
"10\n"
] | [
"8\n",
"1024\n"
] | none | 0 | [
{
"input": "3",
"output": "8"
},
{
"input": "10",
"output": "1024"
},
{
"input": "35",
"output": "33940307968"
},
{
"input": "0",
"output": "1"
},
{
"input": "1",
"output": "2"
},
{
"input": "2",
"output": "4"
},
{
"input": "4",
"output... | 1,459,536,513 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 4,608,000 | a = input_raw()
pow(2, a) | Title: Da Vinci Powers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer.
Input Specification:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output Specification:
Output a single integer.
De... | ```python
a = input_raw()
pow(2, a)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
709 | A | Juicer | PROGRAMMING | 900 | [
"implementation"
] | null | null | Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To be put in the juicer the orange must have size not exceeding *b*, so if Kolya sees an orange ... | The first line of the input contains three integers *n*, *b* and *d* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*b*<=≤<=*d*<=≤<=1<=000<=000) — the number of oranges, the maximum size of the orange that fits in the juicer and the value *d*, which determines the condition when the waste section should be emptied.
The second line co... | Print one integer — the number of times Kolya will have to empty the waste section. | [
"2 7 10\n5 6\n",
"1 5 10\n7\n",
"3 10 10\n5 7 7\n",
"1 1 1\n1\n"
] | [
"1\n",
"0\n",
"1\n",
"0\n"
] | In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all. | 500 | [
{
"input": "2 7 10\n5 6",
"output": "1"
},
{
"input": "1 5 10\n7",
"output": "0"
},
{
"input": "3 10 10\n5 7 7",
"output": "1"
},
{
"input": "1 1 1\n1",
"output": "0"
},
{
"input": "2 951637 951638\n44069 951637",
"output": "1"
},
{
"input": "50 100 12... | 1,668,024,264 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 93 | 7,065,600 | n, b, d = [int(x) for x in input().split()]
orange = [int(x) for x in input().split()]
total=0
for o in orange:
if o<=b: total += o
if total<=d: print(0)
else: print((total-1)//d) | Title: Juicer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is going to make fresh orange juice. He has *n* oranges of sizes *a*1,<=*a*2,<=...,<=*a**n*. Kolya will put them in the juicer in the fixed order, starting with orange of size *a*1, then orange of size *a*2 and so on. To b... | ```python
n, b, d = [int(x) for x in input().split()]
orange = [int(x) for x in input().split()]
total=0
for o in orange:
if o<=b: total += o
if total<=d: print(0)
else: print((total-1)//d)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
320 | B | Ping-Pong (Easy Version) | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs"
] | null | null | In this problem at each moment you have a set of intervals. You can move from interval (*a*,<=*b*) from our set to interval (*c*,<=*d*) from our set if and only if *c*<=<<=*a*<=<<=*d* or *c*<=<<=*b*<=<<=*d*. Also there is a path from interval *I*1 from our set to interval *I*2 from our set if there is a seq... | The first line of the input contains integer *n* denoting the number of queries, (1<=≤<=*n*<=≤<=100). Each of the following lines contains a query as described above. All numbers in the input are integers and don't exceed 109 by their absolute value.
It's guaranteed that all queries are correct. | For each query of the second type print "YES" or "NO" on a separate line depending on the answer. | [
"5\n1 1 5\n1 5 11\n2 1 2\n1 2 9\n2 1 2\n"
] | [
"NO\nYES\n"
] | none | 1,000 | [
{
"input": "5\n1 1 5\n1 5 11\n2 1 2\n1 2 9\n2 1 2",
"output": "NO\nYES"
},
{
"input": "10\n1 -311 -186\n1 -1070 -341\n1 -1506 -634\n1 688 1698\n2 2 4\n1 70 1908\n2 1 2\n2 2 4\n1 -1053 1327\n2 5 4",
"output": "NO\nNO\nNO\nYES"
},
{
"input": "10\n1 -1365 -865\n1 1244 1834\n2 1 2\n1 -1508 -... | 1,675,722,599 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 |
# f = open("pingpong.txt", "r")
# n = int(f.readline())
n = int(input())
visited = [False] * (n)
cmds = []
def dfs(src, dst):
a,b = cmds[src]
visited[src] = True
if visited[dst]:
return
for i in range(len(cmds)):
c,d = cmds[i]
if visited[i]:
continue
... | Title: Ping-Pong (Easy Version)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem at each moment you have a set of intervals. You can move from interval (*a*,<=*b*) from our set to interval (*c*,<=*d*) from our set if and only if *c*<=<<=*a*<=<<=*d* or *c*<=<<=*b*<=&... | ```python
# f = open("pingpong.txt", "r")
# n = int(f.readline())
n = int(input())
visited = [False] * (n)
cmds = []
def dfs(src, dst):
a,b = cmds[src]
visited[src] = True
if visited[dst]:
return
for i in range(len(cmds)):
c,d = cmds[i]
if visited[i]:
con... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,555,475,559 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | a=int(input())
b=input().split()
z=[int(n) for n in b]
l=0
for n in range(a-1):
if z[n+1]-z[n]<=15:
continue
else:
l=z[n]+15
print(l) | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
a=int(input())
b=input().split()
z=[int(n) for n in b]
l=0
for n in range(a-1):
if z[n+1]-z[n]<=15:
continue
else:
l=z[n]+15
print(l)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,693,160,078 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 92 | 0 | r, c = map(int, input().split())
cake = []
for _ in range(r):
row = input()
cake.append(row)
safe_rows = sum(1 for row in cake if 'S' not in row)
safe_cols = sum(1 for j in range(c) if all(cake[i][j] != 'S' for i in range(r)))
max_cells_eaten = safe_rows * c + safe_cols * r - safe_rows * safe_cols
print... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
r, c = map(int, input().split())
cake = []
for _ in range(r):
row = input()
cake.append(row)
safe_rows = sum(1 for row in cake if 'S' not in row)
safe_cols = sum(1 for j in range(c) if all(cake[i][j] != 'S' for i in range(r)))
max_cells_eaten = safe_rows * c + safe_cols * r - safe_rows * safe_c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
327 | A | Flipping Game | PROGRAMMING | 1,200 | [
"brute force",
"dp",
"implementation"
] | null | null | Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *i* and *j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) and flips all values *a**k* for which their positions are in... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100). In the second line of the input there are *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. It is guaranteed that each of those *n* values is either 0 or 1. | Print an integer — the maximal number of 1s that can be obtained after exactly one move. | [
"5\n1 0 0 1 0\n",
"4\n1 0 0 1\n"
] | [
"4\n",
"4\n"
] | In the first case, flip the segment from 2 to 5 (*i* = 2, *j* = 5). That flip changes the sequence, it becomes: [1 1 1 0 1]. So, it contains four ones. There is no way to make the whole sequence equal to [1 1 1 1 1].
In the second case, flipping only the second and the third element (*i* = 2, *j* = 3) will turn all nu... | 500 | [
{
"input": "5\n1 0 0 1 0",
"output": "4"
},
{
"input": "4\n1 0 0 1",
"output": "4"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "8\n1 0 0 0 1 0 0 0",
"output": "7"
},
{
"input": "18\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 ... | 1,665,418,773 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | n=int(input())
a=list(map(int,input().split()))
print(max(sum(a)-2*sum(a[i:j])+j-i for i in range(n)for j in range(i+1,n+1)))
| Title: Flipping Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub got bored, so he invented a game to be played on paper.
He writes *n* integers *a*1,<=*a*2,<=...,<=*a**n*. Each of those integers can be either 0 or 1. He's allowed to do exactly one move: he chooses two indices *... | ```python
n=int(input())
a=list(map(int,input().split()))
print(max(sum(a)-2*sum(a[i:j])+j-i for i in range(n)for j in range(i+1,n+1)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
921 | 05 | Labyrinth-5 | PROGRAMMING | 3,200 | [] | null | null | See the problem statement here: [http://codeforces.com/contest/921/problem/01](//codeforces.com/contest/921/problem/01). | none | none | [] | [] | none | 83.362 | [] | 1,518,020,025 | 2,147,483,647 | Python 3 | PARTIAL | TESTS | 1 | 30 | 5,632,000 | print('for-176 for-351 move-down move-right move-up move-right end move-down move-down for-351 move-down move-left move-up move-left end move-down move-down end') | Title: Labyrinth-5
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
See the problem statement here: [http://codeforces.com/contest/921/problem/01](//codeforces.com/contest/921/problem/01).
Input Specification:
none
Output Specification:
none
Note:
none | ```python
print('for-176 for-351 move-down move-right move-up move-right end move-down move-down for-351 move-down move-left move-up move-left end move-down move-down end')
``` | 2 | MatrixStudio/Codeforces-Python-Submissions | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,656,138,569 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 62 | 0 | def main():
[n, k] = list(map(int, input().split()))
s = ""
c = 0
for i in range(n):
s += chr(ord('a') + (i + c) % k)
print(s)
if __name__ == "__main__":
main()
| Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
def main():
[n, k] = list(map(int, input().split()))
s = ""
c = 0
for i in range(n):
s += chr(ord('a') + (i + c) % k)
print(s)
if __name__ == "__main__":
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
166 | E | Tetrahedron | PROGRAMMING | 1,500 | [
"dp",
"math",
"matrices"
] | null | null | You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each moment of time he makes a step from one vertex to another one along some edge of the tetrahedron. ... | The first line contains the only integer *n* (1<=≤<=*n*<=≤<=107) — the required length of the cyclic path. | Print the only integer — the required number of ways modulo 1000000007 (109<=+<=7). | [
"2\n",
"4\n"
] | [
"3\n",
"21\n"
] | The required paths in the first sample are:
- *D* - *A* - *D* - *D* - *B* - *D* - *D* - *C* - *D* | 1,000 | [
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "21"
},
{
"input": "1",
"output": "0"
},
{
"input": "3",
"output": "6"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "183"
},
{
"input": "7",
"output": "546"
... | 1,670,659,965 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 0 | dpA,dpD=0,1
for i in range(int(input())):
dpD,dpA=(3*dpA)%(10**9+7),(2*dpA+dpD)%(10**9+7)
print(dpD) | Title: Tetrahedron
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a tetrahedron. Let's mark its vertices with letters *A*, *B*, *C* and *D* correspondingly.
An ant is standing in the vertex *D* of the tetrahedron. The ant is quite active and he wouldn't stay idle. At each m... | ```python
dpA,dpD=0,1
for i in range(int(input())):
dpD,dpA=(3*dpA)%(10**9+7),(2*dpA+dpD)%(10**9+7)
print(dpD)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,664,531,470 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 46 | 0 | n = int(input())
if n%2 == 0:
print(4 , (n-4),end =" ")
else:
print(9,(n-9),end =" ") | Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n = int(input())
if n%2 == 0:
print(4 , (n-4),end =" ")
else:
print(9,(n-9),end =" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,585,923,268 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | a,b=map(int,input().split())
l=list(map(int,input().split()))
l.sort()
c=l[:b]
print(sum(c)) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
a,b=map(int,input().split())
l=list(map(int,input().split()))
l.sort()
c=l[:b]
print(sum(c))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
771 | A | Bear and Friendship Condition | PROGRAMMING | 1,500 | [
"dfs and similar",
"dsu",
"graphs"
] | null | null | Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of members are friends. Of course, a member can't be a friend with themselves.
Let A-B denote that... | The first line of the input contain two integers *n* and *m* (3<=≤<=*n*<=≤<=150<=000, ) — the number of members and the number of pairs of members that are friends.
The *i*-th of the next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*). Members *a**i* and ... | If the given network is reasonable, print "YES" in a single line (without the quotes). Otherwise, print "NO" in a single line (without the quotes). | [
"4 3\n1 3\n3 4\n1 4\n",
"4 4\n3 1\n2 3\n3 4\n1 2\n",
"10 4\n4 3\n5 10\n8 9\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | The drawings below show the situation in the first sample (on the left) and in the second sample (on the right). Each edge represents two members that are friends. The answer is "NO" in the second sample because members (2, 3) are friends and members (3, 4) are friends, while members (2, 4) are not. | 250 | [
{
"input": "4 3\n1 3\n3 4\n1 4",
"output": "YES"
},
{
"input": "4 4\n3 1\n2 3\n3 4\n1 2",
"output": "NO"
},
{
"input": "10 4\n4 3\n5 10\n8 9\n1 2",
"output": "YES"
},
{
"input": "3 2\n1 2\n2 3",
"output": "NO"
},
{
"input": "3 0",
"output": "YES"
},
{
... | 1,505,826,242 | 2,147,483,647 | Python 3 | OK | TESTS | 96 | 764 | 22,016,000 | from sys import *
f = lambda: map(int, stdin.readline().split())
n, m = f()
g = [[x] for x in range(n + 1)]
p = [0] * (n + 1)
for j in range(m):
u, v = f()
g[u].append(v)
g[v].append(u)
k = 'YES'
for y, t in enumerate(g):
if not p[y]:
if any(len(g[x]) != len(t) or any(p[y] for y in g... | Title: Bear and Friendship Condition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through... | ```python
from sys import *
f = lambda: map(int, stdin.readline().split())
n, m = f()
g = [[x] for x in range(n + 1)]
p = [0] * (n + 1)
for j in range(m):
u, v = f()
g[u].append(v)
g[v].append(u)
k = 'YES'
for y, t in enumerate(g):
if not p[y]:
if any(len(g[x]) != len(t) or any(p[y] ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
346 | E | Doodle Jump | PROGRAMMING | 3,000 | [
"math",
"number theory"
] | null | null | In Doodle Jump the aim is to guide a four-legged creature called "The Doodler" up a never-ending series of platforms without falling. — Wikipedia.
It is a very popular game and xiaodao likes it very much. One day when playing the game she wondered whether there exists a platform that the doodler couldn't reach due to... | The first line contains an integer *t* (1<=≤<=*t*<=≤<=104) — the number of problem instances. Each of the next *t* lines contains four integers *a*, *n*, *p* and *h* (1<=≤<=*a*<=≤<=109, 1<=≤<=*n*<=<<=*p*<=≤<=109, 0<=≤<=*h*<=≤<=109). It's guaranteed that *a* and *p* are co-prime. | For each problem instance, if the Doodler can reach the highest platform, output "YES", otherwise output "NO". | [
"3\n7 4 12 2\n7 1 9 4\n7 4 12 3\n"
] | [
"NO\nNO\nYES\n"
] | none | 2,500 | [] | 1,454,536,365 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 716 | 102,400 | t = int(input())
j = 0
l = 0
flag = True
while(j<t):
a,n,p,h = input().split()
a=int(a)
n=int(n)
p=int(p)
h=int(h)
if(h==0):
flag=False
else:
if(n==1):
x = a*1%p
if(x>h):
flag=False
else:
fl... | Title: Doodle Jump
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Doodle Jump the aim is to guide a four-legged creature called "The Doodler" up a never-ending series of platforms without falling. — Wikipedia.
It is a very popular game and xiaodao likes it very much. One day when pla... | ```python
t = int(input())
j = 0
l = 0
flag = True
while(j<t):
a,n,p,h = input().split()
a=int(a)
n=int(n)
p=int(p)
h=int(h)
if(h==0):
flag=False
else:
if(n==1):
x = a*1%p
if(x>h):
flag=False
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,577,193,580 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 312 | 0 | def gcd(a,b):
if b==0:
return a
else:
return gcd(b,a%b)
def play():
a,b,n = map(int,input().split())
winner = 1
ab=a
while True:
g = gcd(ab,n)
#print(g,n)
if g>n:
print(winner)
return
n-=g
ab = a+b-... | Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
def gcd(a,b):
if b==0:
return a
else:
return gcd(b,a%b)
def play():
a,b,n = map(int,input().split())
winner = 1
ab=a
while True:
g = gcd(ab,n)
#print(g,n)
if g>n:
print(winner)
return
n-=g
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
255 | B | Code Parsing | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Little Vitaly loves different algorithms. Today he has invented a new algorithm just for you. Vitaly's algorithm works with string *s*, consisting of characters "x" and "y", and uses two following operations at runtime:
1. Find two consecutive characters in the string, such that the first of them equals "y", and the ... | The first line contains a non-empty string *s*.
It is guaranteed that the string only consists of characters "x" and "y". It is guaranteed that the string consists of at most 106 characters. It is guaranteed that as the result of the algorithm's execution won't be an empty string. | In the only line print the string that is printed as the result of the algorithm's work, if the input of the algorithm input receives string *s*. | [
"x\n",
"yxyxy\n",
"xxxxxy\n"
] | [
"x\n",
"y\n",
"xxxx\n"
] | In the first test the algorithm will end after the first step of the algorithm, as it is impossible to apply any operation. Thus, the string won't change.
In the second test the transformation will be like this:
1. string "yxyxy" transforms into string "xyyxy"; 1. string "xyyxy" transforms into string "xyxyy"; 1. ... | 1,000 | [
{
"input": "x",
"output": "x"
},
{
"input": "yxyxy",
"output": "y"
},
{
"input": "xxxxxy",
"output": "xxxx"
},
{
"input": "yxyyxyyx",
"output": "yy"
},
{
"input": "yxxyxyx",
"output": "x"
},
{
"input": "xxx",
"output": "xxx"
},
{
"input": "... | 1,602,950,848 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 218 | 4,198,400 | s = input()
if s.count("x") > s.count("y"): print("x"*(s.count("x")-s.count("y")))
else: print("y"*(s.count("y")-s.count("x")))
| Title: Code Parsing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vitaly loves different algorithms. Today he has invented a new algorithm just for you. Vitaly's algorithm works with string *s*, consisting of characters "x" and "y", and uses two following operations at runtime:
1... | ```python
s = input()
if s.count("x") > s.count("y"): print("x"*(s.count("x")-s.count("y")))
else: print("y"*(s.count("y")-s.count("x")))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
626 | A | Robot Sequence | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Calvin the robot lies in an infinite rectangular grid. Calvin's source code contains a list of *n* commands, each either 'U', 'R', 'D', or 'L' — instructions to move a single square up, right, down, or left, respectively. How many ways can Calvin execute a non-empty contiguous substrings of commands and return to the s... | The first line of the input contains a single positive integer, *n* (1<=≤<=*n*<=≤<=200) — the number of commands.
The next line contains *n* characters, each either 'U', 'R', 'D', or 'L' — Calvin's source code. | Print a single integer — the number of contiguous substrings that Calvin can execute and return to his starting square. | [
"6\nURLLDR\n",
"4\nDLUU\n",
"7\nRLRLRLR\n"
] | [
"2\n",
"0\n",
"12\n"
] | In the first case, the entire source code works, as well as the "RL" substring in the second and third characters.
Note that, in the third case, the substring "LR" appears three times, and is therefore counted three times to the total result. | 500 | [
{
"input": "6\nURLLDR",
"output": "2"
},
{
"input": "4\nDLUU",
"output": "0"
},
{
"input": "7\nRLRLRLR",
"output": "12"
},
{
"input": "1\nR",
"output": "0"
},
{
"input": "100\nURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDL... | 1,571,177,515 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 140 | 1,536,000 | n1 = int(input())
lista = input()
cont = 0
for i in range(n1):
x = 0
y = 0
for j in range(i, n1):
s = lista[j]
if(s == "L"):
x += 1
elif(s == "R"):
x -= 1
if(s == "U"):
y += 1
elif(s == "D"):
y -= 1
if(x == 0 a... | Title: Robot Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calvin the robot lies in an infinite rectangular grid. Calvin's source code contains a list of *n* commands, each either 'U', 'R', 'D', or 'L' — instructions to move a single square up, right, down, or left, respectively... | ```python
n1 = int(input())
lista = input()
cont = 0
for i in range(n1):
x = 0
y = 0
for j in range(i, n1):
s = lista[j]
if(s == "L"):
x += 1
elif(s == "R"):
x -= 1
if(s == "U"):
y += 1
elif(s == "D"):
y -= 1
i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,677,131,467 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n, k, l, c, d, p, nl, np = map(int, input().split())
ml_drink = k * l
lime = c * d
salt = p
full_toasts = min(ml_drink // nl, lime // n, salt // np)
leftover_ml = ml_drink - full_toasts * nl
if leftover_ml >= nl:
extra_toasts = leftover_ml // nl
total_toasts = full_toasts + extra_toasts
else:
total_toas... | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
n, k, l, c, d, p, nl, np = map(int, input().split())
ml_drink = k * l
lime = c * d
salt = p
full_toasts = min(ml_drink // nl, lime // n, salt // np)
leftover_ml = ml_drink - full_toasts * nl
if leftover_ml >= nl:
extra_toasts = leftover_ml // nl
total_toasts = full_toasts + extra_toasts
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
1,009 | B | Minimum Ternary String | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa).
For e... | The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). | Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). | [
"100210\n",
"11222121\n",
"20\n"
] | [
"001120\n",
"11112222\n",
"20\n"
] | none | 0 | [
{
"input": "100210",
"output": "001120"
},
{
"input": "11222121",
"output": "11112222"
},
{
"input": "20",
"output": "20"
},
{
"input": "1002",
"output": "0012"
},
{
"input": "10",
"output": "01"
},
{
"input": "000021",
"output": "000012"
},
{
... | 1,537,510,737 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | S = input()
ans = ""
for j in range(len(S)):
if S[j] == "2":
x = S[prev:j].count("1")
y = S[prev:j].count("0")
ans += "0"*y + "1"*x + "2"
prev = j+1
print(S) | Title: Minimum Ternary String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) ... | ```python
S = input()
ans = ""
for j in range(len(S)):
if S[j] == "2":
x = S[prev:j].count("1")
y = S[prev:j].count("0")
ans += "0"*y + "1"*x + "2"
prev = j+1
print(S)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,669,468,704 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | code = input()
i = 0
while i <= len(code):
if code[i] == '.':
print(0, end="")
i += 1
elif code[i] == '-' and code[i + 1] == '.':
print(1, end="")
i += 2
else:
print(2, end="")
i += 2
print()
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
code = input()
i = 0
while i <= len(code):
if code[i] == '.':
print(0, end="")
i += 1
elif code[i] == '-' and code[i + 1] == '.':
print(1, end="")
i += 2
else:
print(2, end="")
i += 2
print()
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
224 | B | Array | PROGRAMMING | 1,500 | [
"bitmasks",
"implementation",
"two pointers"
] | null | null | You've got an array *a*, consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. Your task is to find a minimal by inclusion segment [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such, that among numbers *a**l*,<= *a**l*<=+<=1,<= ...,<= *a**r* there are exactly *k* distinct numbers.
Segment [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤... | The first line contains two space-separated integers: *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* — elements of the array *a* (1<=≤<=*a**i*<=≤<=105). | Print a space-separated pair of integers *l* and *r* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such, that the segment [*l*,<=*r*] is the answer to the problem. If the sought segment does not exist, print "-1 -1" without the quotes. If there are multiple correct answers, print any of them. | [
"4 2\n1 2 2 3\n",
"8 3\n1 1 2 2 3 3 4 5\n",
"7 4\n4 7 7 4 7 4 7\n"
] | [
"1 2\n",
"2 5\n",
"-1 -1\n"
] | In the first sample among numbers *a*<sub class="lower-index">1</sub> and *a*<sub class="lower-index">2</sub> there are exactly two distinct numbers.
In the second sample segment [2, 5] is a minimal by inclusion segment with three distinct numbers, but it is not minimal in length among such segments.
In the third sam... | 1,000 | [
{
"input": "4 2\n1 2 2 3",
"output": "1 2"
},
{
"input": "8 3\n1 1 2 2 3 3 4 5",
"output": "2 5"
},
{
"input": "7 4\n4 7 7 4 7 4 7",
"output": "-1 -1"
},
{
"input": "5 1\n1 7 2 3 2",
"output": "1 1"
},
{
"input": "1 2\n666",
"output": "-1 -1"
},
{
"inp... | 1,565,510,857 | 2,147,483,647 | PyPy 3 | OK | TESTS | 49 | 436 | 13,209,600 | n,k=map(int,input().split())
l = list(map(int,input().split()))
d={}
j=1
for i in l:
if(len(d)==k):
break
d[i]=j
j+=1
if(len(d)==k):
print(min(d.values()),max(d.values()))
else:
print(-1,-1) | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got an array *a*, consisting of *n* integers: *a*1,<=*a*2,<=...,<=*a**n*. Your task is to find a minimal by inclusion segment [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤<=*n*) such, that among numbers *a**l*,<= *a**l*<=+<=1,<= ...,<... | ```python
n,k=map(int,input().split())
l = list(map(int,input().split()))
d={}
j=1
for i in l:
if(len(d)==k):
break
d[i]=j
j+=1
if(len(d)==k):
print(min(d.values()),max(d.values()))
else:
print(-1,-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
656 | F | Ace It! | PROGRAMMING | 1,900 | [
"*special"
] | null | null | The only line of the input is a string of 7 characters. The first character is letter A, followed by 6 digits. The input is guaranteed to be valid (for certain definition of "valid").
Output a single integer. | The only line of the input is a string of 7 characters. The first character is letter A, followed by 6 digits. The input is guaranteed to be valid (for certain definition of "valid"). | Output a single integer. | [
"A221033\n",
"A223635\n",
"A232726\n"
] | [
"21\n",
"22\n",
"23\n"
] | none | 0 | [
{
"input": "A221033",
"output": "21"
},
{
"input": "A223635",
"output": "22"
},
{
"input": "A232726",
"output": "23"
},
{
"input": "A102210",
"output": "25"
},
{
"input": "A231010",
"output": "26"
},
{
"input": "A222222",
"output": "13"
},
{
... | 1,580,023,666 | 6,826 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 124 | 9,523,200 | x=[16,0,1,4,4,10,20,35,56,84,4,4,10,20,35,56,84,512,4,4,6,10,1,1,1,1,1,1,2,5,6,7,2,4,5,6,7,8,4,10,20,35,56,84,4,10,20,35,56,84,120,1,7,1,1,1,1,1,1,1,1,1,1,104,1,2,4,7,12,21,1,0,2,1,1,1,102345,1,5,7,0,17,1,1,1,6,6,-26,-80,-242,245,0,1,0,45,1,0,1,1,44,18,0,1,0,1,0,4,16,56,4,1,0,1,1,-1,0,0,0,0,1,2,83,1,1,1,1,1,1,1,1,1,1,1... | Title: Ace It!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The only line of the input is a string of 7 characters. The first character is letter A, followed by 6 digits. The input is guaranteed to be valid (for certain definition of "valid").
Output a single integer.
Input Specificat... | ```python
x=[16,0,1,4,4,10,20,35,56,84,4,4,10,20,35,56,84,512,4,4,6,10,1,1,1,1,1,1,2,5,6,7,2,4,5,6,7,8,4,10,20,35,56,84,4,10,20,35,56,84,120,1,7,1,1,1,1,1,1,1,1,1,1,104,1,2,4,7,12,21,1,0,2,1,1,1,102345,1,5,7,0,17,1,1,1,6,6,-26,-80,-242,245,0,1,0,45,1,0,1,1,44,18,0,1,0,1,0,4,16,56,4,1,0,1,1,-1,0,0,0,0,1,2,83,1,1,1,1,1,1... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find ... | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,699,735,218 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | number = int(input())
luck = ['4', '7']
lucky = "YES"
if number % 4 == 0 or number % 7 == 0:
print(lucky)
else:
string = str(number)
for i in string:
if i != '4' and i != '7':
lucky = "NO"
print(lucky)
| Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
... | ```python
number = int(input())
luck = ['4', '7']
lucky = "YES"
if number % 4 == 0 or number % 7 == 0:
print(lucky)
else:
string = str(number)
for i in string:
if i != '4' and i != '7':
lucky = "NO"
print(lucky)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
495 | B | Modular Equations | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Last week, Hamed learned about a new type of equations in his math class called Modular Equations. Lets define *i* modulo *j* as the remainder of division of *i* by *j* and denote it by . A Modular Equation, as Hamed's teacher described, is an equation of the form in which *a* and *b* are two non-negative integers and... | In the only line of the input two space-separated integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=109) are given. | If there is an infinite number of answers to our equation, print "infinity" (without the quotes). Otherwise print the number of solutions of the Modular Equation . | [
"21 5\n",
"9435152 272\n",
"10 10\n"
] | [
"2\n",
"282\n",
"infinity\n"
] | In the first sample the answers of the Modular Equation are 8 and 16 since <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/6f5ff39ebd209bf990adaf91f4b82f9687097224.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "21 5",
"output": "2"
},
{
"input": "9435152 272",
"output": "282"
},
{
"input": "10 10",
"output": "infinity"
},
{
"input": "0 1000000000",
"output": "0"
},
{
"input": "11 2",
"output": "2"
},
{
"input": "1 0",
"output": "1"
},
{
... | 1,602,359,365 | 2,147,483,647 | PyPy 3 | OK | TESTS | 37 | 140 | 1,331,200 | a, b = input().split()
a = int(a)
b = int(b)
if a == b:
print ("infinity")
elif b > a:
print (0)
else:
quant = 0
d = a-b
i = 1
while(i*i <= d):
if d % i == 0:
if d/i == i and i > b:
quant += 1
else:
if i > b:
qu... | Title: Modular Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Last week, Hamed learned about a new type of equations in his math class called Modular Equations. Lets define *i* modulo *j* as the remainder of division of *i* by *j* and denote it by . A Modular Equation, as Hamed'... | ```python
a, b = input().split()
a = int(a)
b = int(b)
if a == b:
print ("infinity")
elif b > a:
print (0)
else:
quant = 0
d = a-b
i = 1
while(i*i <= d):
if d % i == 0:
if d/i == i and i > b:
quant += 1
else:
if i > b:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
937 | B | Vile Grasshoppers | PROGRAMMING | 1,400 | [
"brute force",
"math",
"number theory"
] | null | null | The weather is fine today and hence it's high time to climb the nearby pine and enjoy the landscape.
The pine's trunk includes several branches, located one above another and numbered from 2 to *y*. Some of them (more precise, from 2 to *p*) are occupied by tiny vile grasshoppers which you're at war with. These grassh... | The only line contains two integers *p* and *y* (2<=≤<=*p*<=≤<=*y*<=≤<=109). | Output the number of the highest suitable branch. If there are none, print -1 instead. | [
"3 6\n",
"3 4\n"
] | [
"5\n",
"-1\n"
] | In the first sample case grasshopper from branch 2 reaches branches 2, 4 and 6 while branch 3 is initially settled by another grasshopper. Therefore the answer is 5.
It immediately follows that there are no valid branches in second sample case. | 1,000 | [
{
"input": "3 6",
"output": "5"
},
{
"input": "3 4",
"output": "-1"
},
{
"input": "2 2",
"output": "-1"
},
{
"input": "5 50",
"output": "49"
},
{
"input": "944192806 944193066",
"output": "944192807"
},
{
"input": "1000000000 1000000000",
"output":... | 1,520,939,529 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 61 | 5,632,000 | p, y = map(int, input().split())
for num in range(y, p, -1):
for i in range(2, int(num ** 0.5) + 1):
if num % i == 0:
break
else:
print(num)
break
else:
print(-1) | Title: Vile Grasshoppers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The weather is fine today and hence it's high time to climb the nearby pine and enjoy the landscape.
The pine's trunk includes several branches, located one above another and numbered from 2 to *y*. Some of them (mor... | ```python
p, y = map(int, input().split())
for num in range(y, p, -1):
for i in range(2, int(num ** 0.5) + 1):
if num % i == 0:
break
else:
print(num)
break
else:
print(-1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agre... | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,503,503,234 | 2,834 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | import sys
arr = list(map(int,input().split()))
l = arr[0]
r = arr[1]
k = arr[2]
if l == 1:
start = 1
elif l % k == 0:
start = k**(l//k)
else:
start = k**((l // k ) + 1)
if start < l or start > r:
print('-1')
else:
while(start <= r):
print(start,'',end='')
start = s... | Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand ... | ```python
import sys
arr = list(map(int,input().split()))
l = arr[0]
r = arr[1]
k = arr[2]
if l == 1:
start = 1
elif l % k == 0:
start = k**(l//k)
else:
start = k**((l // k ) + 1)
if start < l or start > r:
print('-1')
else:
while(start <= r):
print(start,'',end='')
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,674,125,361 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | str1=int(input(),2)
str2=int(input(),2)
k=str1+str2
print(bin(k)[2::])
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
str1=int(input(),2)
str2=int(input(),2)
k=str1+str2
print(bin(k)[2::])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
669 | A | Little Artem and Presents | PROGRAMMING | 800 | [
"math"
] | null | null | Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wants to give her stones as many times as possible. However, Masha remembers the last present she received, so Art... | The only line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — number of stones Artem received on his birthday. | Print the maximum possible number of times Artem can give presents to Masha. | [
"1\n",
"2\n",
"3\n",
"4\n"
] | [
"1\n",
"1\n",
"2\n",
"3\n"
] | In the first sample, Artem can only give 1 stone to Masha.
In the second sample, Atrem can give Masha 1 or 2 stones, though he can't give her 1 stone two times.
In the third sample, Atrem can first give Masha 2 stones, a then 1 more stone.
In the fourth sample, Atrem can first give Masha 1 stone, then 2 stones, and ... | 500 | [
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "1"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "3"
},
{
"input": "100",
"output": "67"
},
{
"input": "101",
"output": "67"
},
{
"input": "102",
"output": "68"... | 1,568,743,199 | 2,147,483,647 | PyPy 3 | OK | TESTS | 26 | 139 | 0 |
def main():
d = int(input())
c = d//3*2
v = d%3
if v!=0:
c+=1
print(c)
if __name__ == "__main__":
main()
| Title: Little Artem and Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Artem got *n* stones on his birthday and now wants to give some of them to Masha. He knows that Masha cares more about the fact of receiving the present, rather than the value of that present, so he wan... | ```python
def main():
d = int(input())
c = d//3*2
v = d%3
if v!=0:
c+=1
print(c)
if __name__ == "__main__":
main()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
55 | B | Smallest number | PROGRAMMING | 1,600 | [
"brute force"
] | B. Smallest number | 2 | 256 | Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the next three minutes he took two numbers from the blackboard (not necessarily adjacent) and replaced... | First line contains four integers separated by space: 0<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=1000 — the original numbers. Second line contains three signs ('+' or '*' each) separated by space — the sequence of the operations in the order of performing. ('+' stands for addition, '*' — multiplication) | Output one integer number — the minimal result which can be obtained.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cin (also you may use %I64d). | [
"1 1 1 1\n+ + *\n",
"2 2 2 2\n* * +\n",
"1 2 3 4\n* + +\n"
] | [
"3\n",
"8\n",
"9\n"
] | none | 1,000 | [
{
"input": "1 1 1 1\n+ + *",
"output": "3"
},
{
"input": "2 2 2 2\n* * +",
"output": "8"
},
{
"input": "1 2 3 4\n* + +",
"output": "9"
},
{
"input": "15 1 3 1\n* * +",
"output": "18"
},
{
"input": "8 1 7 14\n+ + +",
"output": "30"
},
{
"input": "7 17 3... | 1,654,250,396 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 92 | 0 | from itertools import permutations
nums=list(map(int, input().split()))
o=input().split()
print(min(eval("min(((a{0}b){1}c){2}d,(a{0}b){2}(c{1}d))".format(*o))for a,b,c,d in permutations(nums))) | Title: Smallest number
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the n... | ```python
from itertools import permutations
nums=list(map(int, input().split()))
o=input().split()
print(min(eval("min(((a{0}b){1}c){2}d,(a{0}b){2}(c{1}d))".format(*o))for a,b,c,d in permutations(nums)))
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
235 | A | LCM Challenge | PROGRAMMING | 1,600 | [
"number theory"
] | null | null | Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive integers (they don't have to be distinct) which are not greater than *n*. Can you help me to find ... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the *n* mentioned in the statement. | Print a single integer — the maximum possible LCM of three not necessarily distinct positive integers that are not greater than *n*. | [
"9\n",
"7\n"
] | [
"504\n",
"210\n"
] | The least common multiple of some positive integers is the least positive integer which is multiple for each of them.
The result may become very large, 32-bit integer won't be enough. So using 64-bit integers is recommended.
For the last example, we can chose numbers 7, 6, 5 and the LCM of them is 7·6·5 = 210. It is ... | 500 | [
{
"input": "9",
"output": "504"
},
{
"input": "7",
"output": "210"
},
{
"input": "1",
"output": "1"
},
{
"input": "5",
"output": "60"
},
{
"input": "6",
"output": "60"
},
{
"input": "33",
"output": "32736"
},
{
"input": "21",
"output": ... | 1,675,466,882 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 31 | 468 | 49,254,400 | from random import randrange
import time
import threading
from math import sqrt, ceil, inf, comb, log2, gcd
from itertools import *
import functools
from collections import *
from copy import *
import heapq
from math import *
import sys
# from pprint import pprint as pprint
# from sympy.ntheory.modular impo... | Title: LCM Challenge
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some days ago, I learned the concept of LCM (least common multiple). I've played with it for several times and I want to make a big number with it.
But I also don't want to use many numbers, so I'll choose three positive... | ```python
from random import randrange
import time
import threading
from math import sqrt, ceil, inf, comb, log2, gcd
from itertools import *
import functools
from collections import *
from copy import *
import heapq
from math import *
import sys
# from pprint import pprint as pprint
# from sympy.ntheory.mo... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
979 | A | Pizza, Pizza, Pizza!!! | PROGRAMMING | 1,000 | [
"math"
] | null | null | Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthday. She really loves pizza so she wants to invite her friends to the pizza restaurant near her house to cele... | A single line contains one non-negative integer $n$ ($0 \le n \leq 10^{18}$) — the number of Shiro's friends. The circular pizza has to be sliced into $n + 1$ pieces. | A single integer — the number of straight cuts Shiro needs. | [
"3\n",
"4\n"
] | [
"2",
"5"
] | To cut the round pizza into quarters one has to make two cuts through the center with angle $90^{\circ}$ between them.
To cut the round pizza into five equal parts one has to make five cuts. | 500 | [
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "5"
},
{
"input": "10",
"output": "11"
},
{
"input": "10000000000",
"output": "10000000001"
},
{
"input": "1234567891",
"output": "617283946"
},
{
"input": "7509213957",
"output": "37546069... | 1,585,332,355 | 2,147,483,647 | PyPy 3 | OK | TESTS | 47 | 155 | 0 | import sys
import math
#to read string
get_string = lambda: sys.stdin.readline().strip()
#to read list of integers
get_int_list = lambda: list( map(int,sys.stdin.readline().strip().split()) )
#to read integers
get_int = lambda: int(sys.stdin.readline())
#--------------------------------WhiteHat010----------... | Title: Pizza, Pizza, Pizza!!!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthd... | ```python
import sys
import math
#to read string
get_string = lambda: sys.stdin.readline().strip()
#to read list of integers
get_int_list = lambda: list( map(int,sys.stdin.readline().strip().split()) )
#to read integers
get_int = lambda: int(sys.stdin.readline())
#--------------------------------WhiteHat010... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
492 | B | Vanya and Lanterns | PROGRAMMING | 1,200 | [
"binary search",
"implementation",
"math",
"sortings"
] | null | null | Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point *l*. Then the *i*-th lantern is at the point *a**i*. The lantern lights all points of the street that... | The first line contains two integers *n*, *l* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*l*<=≤<=109) — the number of lanterns and the length of the street respectively.
The next line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=*l*). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of th... | Print the minimum light radius *d*, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=9. | [
"7 15\n15 5 3 7 9 14 0\n",
"2 5\n2 5\n"
] | [
"2.5000000000\n",
"2.0000000000\n"
] | Consider the second sample. At *d* = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | 1,000 | [
{
"input": "7 15\n15 5 3 7 9 14 0",
"output": "2.5000000000"
},
{
"input": "2 5\n2 5",
"output": "2.0000000000"
},
{
"input": "46 615683844\n431749087 271781274 274974690 324606253 480870261 401650581 13285442 478090364 266585394 425024433 588791449 492057200 391293435 563090494 317950 1... | 1,691,563,996 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n,l=[int(x) for x in input().split()]
a=list(map(int,input().split()))
a.sort()
left=a[0]-0
right=l-a[-1]
mval=0
for i in range(1,n):
val=a[i]-a[i-1]
mval=max(mval,val)
mval=mval/2
print(left,right,mval)
op=max(left,right,mval)
print(op) | Title: Vanya and Lanterns
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya walks late at night along a straight street of length *l*, lit by *n* lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the poi... | ```python
n,l=[int(x) for x in input().split()]
a=list(map(int,input().split()))
a.sort()
left=a[0]-0
right=l-a[-1]
mval=0
for i in range(1,n):
val=a[i]-a[i-1]
mval=max(mval,val)
mval=mval/2
print(left,right,mval)
op=max(left,right,mval)
print(op)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
234 | A | Lefthanders and Righthanders | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | One fine October day a mathematics teacher Vasily Petrov went to a class and saw there *n* pupils who sat at the desks, two people at each desk. Vasily quickly realized that number *n* is even. Like all true mathematicians, Vasily has all students numbered from 1 to *n*.
But Vasily Petrov did not like the way the chi... | The first input line contains a single even integer *n* (4<=≤<=*n*<=≤<=100) — the number of students in the class. The second line contains exactly *n* capital English letters "L" and "R". If the *i*-th letter at the second line equals "L", then the student number *i* is a lefthander, otherwise he is a righthander. | Print integer pairs, one pair per line. In the *i*-th line print the numbers of students that will sit at the *i*-th desk. The first number in the pair stands for the student who is sitting to the left, and the second number stands for the student who is sitting to the right. Separate the numbers in the pairs by space... | [
"6\nLLRLLL\n",
"4\nRRLL\n"
] | [
"1 4\n2 5\n6 3\n",
"3 1\n4 2\n"
] | none | 0 | [
{
"input": "6\nLLRLLL",
"output": "1 4\n2 5\n6 3"
},
{
"input": "4\nRRLL",
"output": "3 1\n4 2"
},
{
"input": "4\nLLRR",
"output": "1 3\n2 4"
},
{
"input": "6\nRLLRRL",
"output": "1 4\n2 5\n3 6"
},
{
"input": "8\nLRLRLLLR",
"output": "1 5\n6 2\n3 7\n4 8"
},
... | 1,620,418,381 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 6,656,000 | i, o = open ("input. txt","r"), open("output. txt","w")
n, s = int(i. readline().strip()),i.readline().strip()
for x in range (n//2):
a,b=x,x+n//2
if s[a]=='R' and s[b]=='L': a,b=b,a
o.write(str(a+1)+" "+str(b+1)+"\n")
| Title: Lefthanders and Righthanders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One fine October day a mathematics teacher Vasily Petrov went to a class and saw there *n* pupils who sat at the desks, two people at each desk. Vasily quickly realized that number *n* is even. Like all t... | ```python
i, o = open ("input. txt","r"), open("output. txt","w")
n, s = int(i. readline().strip()),i.readline().strip()
for x in range (n//2):
a,b=x,x+n//2
if s[a]=='R' and s[b]=='L': a,b=b,a
o.write(str(a+1)+" "+str(b+1)+"\n")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
342 | E | Xenia and Tree | PROGRAMMING | 2,400 | [
"data structures",
"divide and conquer",
"trees"
] | null | null | Xenia the programmer has a tree consisting of *n* nodes. We will consider the tree nodes indexed from 1 to *n*. We will also consider the first node to be initially painted red, and the other nodes — to be painted blue.
The distance between two tree nodes *v* and *u* is the number of edges in the shortest path between... | The first line contains two integers *n* and *m* (2<=≤<=*n*<=≤<=105,<=1<=≤<=*m*<=≤<=105) — the number of nodes in the tree and the number of queries. Next *n*<=-<=1 lines contain the tree edges, the *i*-th line contains a pair of integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*) — an edge of ... | For each second type query print the reply in a single line. | [
"5 4\n1 2\n2 3\n2 4\n4 5\n2 1\n2 5\n1 2\n2 5\n"
] | [
"0\n3\n2\n"
] | none | 2,500 | [
{
"input": "5 4\n1 2\n2 3\n2 4\n4 5\n2 1\n2 5\n1 2\n2 5",
"output": "0\n3\n2"
}
] | 1,693,245,766 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1693245766.1947157")# 1693245766.194732 | Title: Xenia and Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Xenia the programmer has a tree consisting of *n* nodes. We will consider the tree nodes indexed from 1 to *n*. We will also consider the first node to be initially painted red, and the other nodes — to be painted blue.
... | ```python
print("_RANDOM_GUESS_1693245766.1947157")# 1693245766.194732
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,695,671,479 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | num_test_cases = int(input())
test_cases = []
for _ in range(num_test_cases):
params = list(map(int, input().split()))
test_cases.append(params)
test_cases.sort(reverse=True)
count = 0
total = 0
for i in range(num_test_cases):
new_value = test_cases[i]
total += new_value
count... | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
num_test_cases = int(input())
test_cases = []
for _ in range(num_test_cases):
params = list(map(int, input().split()))
test_cases.append(params)
test_cases.sort(reverse=True)
count = 0
total = 0
for i in range(num_test_cases):
new_value = test_cases[i]
total += new_value
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
716 | A | Crazy Computer | PROGRAMMING | 800 | [
"implementation"
] | null | null | ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *b*, then if *b*<=-<=*a*<=≤<=*c*, just the new word is appended to other words on the screen. If *b*<... | The first line contains two integers *n* and *c* (1<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*c*<=≤<=109) — the number of words ZS the Coder typed and the crazy computer delay respectively.
The next line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=...<=<<=*t**n*<=≤<=109), where *t**i* denote... | Print a single positive integer, the number of words that remain on the screen after all *n* words was typed, in other words, at the second *t**n*. | [
"6 5\n1 3 8 14 19 20\n",
"6 1\n1 3 5 7 9 10\n"
] | [
"3",
"2"
] | The first sample is already explained in the problem statement.
For the second sample, after typing the first word at the second 1, it disappears because the next word is typed at the second 3 and 3 - 1 > 1. Similarly, only 1 word will remain at the second 9. Then, a word is typed at the second 10, so there will be... | 500 | [
{
"input": "6 5\n1 3 8 14 19 20",
"output": "3"
},
{
"input": "6 1\n1 3 5 7 9 10",
"output": "2"
},
{
"input": "1 1\n1000000000",
"output": "1"
},
{
"input": "5 5\n1 7 12 13 14",
"output": "4"
},
{
"input": "2 1000000000\n1 1000000000",
"output": "2"
},
{
... | 1,604,427,561 | 2,147,483,647 | PyPy 3 | OK | TESTS | 81 | 249 | 10,854,400 | n,c=map(int,input().split(" "))
z=list(map(int,input().split(" ")))
s=0
for i in range(n-1):
if (z[i+1]-z[i])<=c:
s+=1
else:
s=0
print(s+1) | Title: Crazy Computer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
ZS the Coder is coding on a crazy computer. If you don't type in a word for a *c* consecutive seconds, everything you typed disappear!
More formally, if you typed a word at second *a* and then the next word at second *... | ```python
n,c=map(int,input().split(" "))
z=list(map(int,input().split(" ")))
s=0
for i in range(n-1):
if (z[i+1]-z[i])<=c:
s+=1
else:
s=0
print(s+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
891 | D | Sloth | PROGRAMMING | 3,100 | [
"dfs and similar",
"dp",
"graph matchings",
"trees"
] | null | null | Sloth is bad, mkay? So we decided to prepare a problem to punish lazy guys.
You are given a tree, you should count the number of ways to remove an edge from it and then add an edge to it such that the final graph is a tree and has a perfect matching. Two ways of this operation are considered different if their removed... | The first line contains *n* (2<=≤<=*n*<=≤<=5·105) — the number of vertices.
Each of the next *n*<=-<=1 lines contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=*n*) — the endpoints of one edge. It's guaranteed that the graph is a tree. | Output a single integer — the answer to the problem. | [
"4\n1 2\n2 3\n3 4\n",
"5\n1 2\n2 3\n3 4\n3 5\n",
"8\n1 2\n2 3\n3 4\n1 5\n5 6\n6 7\n1 8\n"
] | [
"8\n",
"0\n",
"22\n"
] | In first sample, there are 8 ways:
- edge between 2 and 3 turns to edge between 1 and 3, - edge between 2 and 3 turns to edge between 1 and 4, - edge between 2 and 3 turns to edge between 2 and 3, - edge between 2 and 3 turns to edge between 2 and 4, - edge between 1 and 2 turns to edge between 1 and 2, - edge b... | 2,000 | [] | 1,678,581,534 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | # LUOGU_RID: 104430550
const int MAXN=5e5;
int n,hd[MAXN+5],to[MAXN*2+5],nxt[MAXN*2+5],ec=1;
void adde(int u,int v){to[++ec]=v;nxt[ec]=hd[u];hd[u]=ec;}
int siz[MAXN+5],fa[MAXN+5],bad[MAXN+5],ed[MAXN+5];
bool isbad[MAXN+5];
void dfs(int x,int f){
fa[x]=f;siz[x]=1;
for(int e=hd[x];e;e=nxt[e]){
int y=to[e];if(... | Title: Sloth
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sloth is bad, mkay? So we decided to prepare a problem to punish lazy guys.
You are given a tree, you should count the number of ways to remove an edge from it and then add an edge to it such that the final graph is a tree and h... | ```python
# LUOGU_RID: 104430550
const int MAXN=5e5;
int n,hd[MAXN+5],to[MAXN*2+5],nxt[MAXN*2+5],ec=1;
void adde(int u,int v){to[++ec]=v;nxt[ec]=hd[u];hd[u]=ec;}
int siz[MAXN+5],fa[MAXN+5],bad[MAXN+5],ed[MAXN+5];
bool isbad[MAXN+5];
void dfs(int x,int f){
fa[x]=f;siz[x]=1;
for(int e=hd[x];e;e=nxt[e]){
int y... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | D | Roads not only in Berland | PROGRAMMING | 1,900 | [
"dsu",
"graphs",
"trees"
] | D. Roads not only in Berland | 2 | 256 | Berland Government decided to improve relations with neighboring countries. First of all, it was decided to build new roads so that from each city of Berland and neighboring countries it became possible to reach all the others. There are *n* cities in Berland and neighboring countries in total and exactly *n*<=-<=1 two... | The first line contains integer *n* (2<=≤<=*n*<=≤<=1000) — amount of cities in Berland and neighboring countries. Next *n*<=-<=1 lines contain the description of roads. Each road is described by two space-separated integers *a**i*, *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*) — pair of cities, which the r... | Output the answer, number *t* — what is the least amount of days needed to rebuild roads so that from each city it became possible to reach all the others. Then output *t* lines — the plan of closure of old roads and building of new ones. Each line should describe one day in the format i j u v — it means that road betw... | [
"2\n1 2\n",
"7\n1 2\n2 3\n3 1\n4 5\n5 6\n6 7\n"
] | [
"0\n",
"1\n3 1 3 7\n"
] | none | 0 | [
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "7\n1 2\n2 3\n3 1\n4 5\n5 6\n6 7",
"output": "1\n3 1 3 7"
},
{
"input": "3\n3 2\n1 2",
"output": "0"
},
{
"input": "3\n3 1\n3 2",
"output": "0"
},
{
"input": "4\n1 4\n3 1\n3 4",
"output": "1\n3 4 2 4"
},
{
... | 1,697,110,379 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 55 | 280 | 5,836,800 | def main():
n = int(input())
parent = [i for i in range(n)]
size = [1 for _ in range(n)]
def find(u):
path = []
while parent[u] != u:
path.append(u)
u = parent[u]
for node in path:
parent[node] = u
return u
... | Title: Roads not only in Berland
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Berland Government decided to improve relations with neighboring countries. First of all, it was decided to build new roads so that from each city of Berland and neighboring countries it became possible to reach a... | ```python
def main():
n = int(input())
parent = [i for i in range(n)]
size = [1 for _ in range(n)]
def find(u):
path = []
while parent[u] != u:
path.append(u)
u = parent[u]
for node in path:
parent[node] = u
retur... | 3.919128 | MatrixStudio/Codeforces-Python-Submissions |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,673,431,435 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 | n,k,l,c,d,p,nl,np = input().split()
a = int(k)*int(l)//int(nl)
b = int(c)*int(d)
c = int(p)//int(np)
z = min(a//int(n),b//int(n),c//int(n))
print(z) | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
n,k,l,c,d,p,nl,np = input().split()
a = int(k)*int(l)//int(nl)
b = int(c)*int(d)
c = int(p)//int(np)
z = min(a//int(n),b//int(n),c//int(n))
print(z)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
244 | A | Dividing Orange | PROGRAMMING | 900 | [
"implementation"
] | null | null | One day Ms Swan bought an orange in a shop. The orange consisted of *n*·*k* segments, numbered with integers from 1 to *n*·*k*.
There were *k* children waiting for Ms Swan at home. The children have recently learned about the orange and they decided to divide it between them. For that each child took a piece of paper... | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=30). The second line contains *k* space-separated integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=*n*·*k*), where *a**i* is the number of the orange segment that the *i*-th child would like to get.
It is guaranteed that all numbers *a**i* are dis... | Print exactly *n*·*k* distinct integers. The first *n* integers represent the indexes of the segments the first child will get, the second *n* integers represent the indexes of the segments the second child will get, and so on. Separate the printed numbers with whitespaces.
You can print a child's segment indexes in a... | [
"2 2\n4 1\n",
"3 1\n2\n"
] | [
"2 4 \n1 3 \n",
"3 2 1 \n"
] | none | 500 | [
{
"input": "2 2\n4 1",
"output": "2 4 \n1 3 "
},
{
"input": "3 1\n2",
"output": "3 2 1 "
},
{
"input": "5 5\n25 24 23 22 21",
"output": "2 3 1 25 4 \n7 6 8 5 24 \n10 12 9 23 11 \n13 15 14 16 22 \n19 21 20 17 18 "
},
{
"input": "1 30\n8 22 13 25 10 30 12 27 6 4 7 2 20 16 26 14... | 1,657,954,798 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | s = input() | Title: Dividing Orange
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Ms Swan bought an orange in a shop. The orange consisted of *n*·*k* segments, numbered with integers from 1 to *n*·*k*.
There were *k* children waiting for Ms Swan at home. The children have recently learned a... | ```python
s = input()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
225 | B | Well-known Numbers | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"number theory"
] | null | null | Numbers *k*-bonacci (*k* is integer, *k*<=><=1) are a generalization of Fibonacci numbers and are determined as follows:
- *F*(*k*,<=*n*)<==<=0, for integer *n*, 1<=≤<=*n*<=<<=*k*; - *F*(*k*,<=*k*)<==<=1; - *F*(*k*,<=*n*)<==<=*F*(*k*,<=*n*<=-<=1)<=+<=*F*(*k*,<=*n*<=-<=2)<=+<=...<=+<=*F*(*k*,<=*n*<=-<=*k*), fo... | The first line contains two integers *s* and *k* (1<=≤<=*s*,<=*k*<=≤<=109; *k*<=><=1). | In the first line print an integer *m* (*m*<=≥<=2) that shows how many numbers are in the found representation. In the second line print *m* distinct integers *a*1,<=*a*2,<=...,<=*a**m*. Each printed integer should be a *k*-bonacci number. The sum of printed integers must equal *s*.
It is guaranteed that the answer ex... | [
"5 2\n",
"21 5\n"
] | [
"3\n0 2 3\n",
"3\n4 1 16\n"
] | none | 1,000 | [
{
"input": "5 2",
"output": "3\n0 2 3"
},
{
"input": "21 5",
"output": "3\n4 1 16"
},
{
"input": "1 1000",
"output": "2\n1 0 "
},
{
"input": "1000000000 1000000000",
"output": "14\n536870912 268435456 134217728 33554432 16777216 8388608 1048576 524288 131072 32768 16384 2... | 1,587,305,112 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 218 | 409,600 | """
Template written to be used by Python Programmers.
Use at your own risk!!!!
Owned by enraged(rating - 5 star at CodeChef and Specialist at Codeforces).
"""
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush, nlargest, nsmallest, _heapify_max... | Title: Well-known Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Numbers *k*-bonacci (*k* is integer, *k*<=><=1) are a generalization of Fibonacci numbers and are determined as follows:
- *F*(*k*,<=*n*)<==<=0, for integer *n*, 1<=≤<=*n*<=<<=*k*; - *F*(*k*,<=*k*)<==<=1; - ... | ```python
"""
Template written to be used by Python Programmers.
Use at your own risk!!!!
Owned by enraged(rating - 5 star at CodeChef and Specialist at Codeforces).
"""
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush, nlargest, nsmallest, _h... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,619,514,569 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 61 | 0 | def answer():
if(0 in s):s.remove(0)
return len(s)
n=int(input())
s=set(map(int,input().split()))
print(answer())
| Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
def answer():
if(0 in s):s.remove(0)
return len(s)
n=int(input())
s=set(map(int,input().split()))
print(answer())
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
13 | C | Sequence | PROGRAMMING | 2,200 | [
"dp",
"sortings"
] | C. Sequence | 1 | 64 | Little Petya likes to play very much. And most of all he likes to play the following game:
He is given a sequence of *N* integer numbers. At each step it is allowed to increase the value of any number by 1 or to decrease it by 1. The goal of the game is to make the sequence non-decreasing with the smallest number of s... | The first line of the input contains single integer *N* (1<=≤<=*N*<=≤<=5000) — the length of the initial sequence. The following *N* lines contain one integer each — elements of the sequence. These numbers do not exceed 109 by absolute value. | Output one integer — minimum number of steps required to achieve the goal. | [
"5\n3 2 -1 2 11\n",
"5\n2 1 1 1 1\n"
] | [
"4\n",
"1\n"
] | none | 0 | [
{
"input": "5\n3 2 -1 2 11",
"output": "4"
},
{
"input": "5\n2 1 1 1 1",
"output": "1"
},
{
"input": "5\n0 0 0 0 0",
"output": "0"
},
{
"input": "1\n11",
"output": "0"
},
{
"input": "2\n10 2",
"output": "8"
},
{
"input": "6\n1000000000 -1000000000 1000... | 1,629,371,750 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 4 | 122 | 6,963,200 | n = int(input())
num = list(map(int, input().split()))
ans = 0
y = sorted(num)
for i in range(n - 1):
k = min(num[i: n])
t = num.index(k)
if num[i] > k:
s = num[i] - k
ans += s
l = num[t + 1] - num[t]
if l > s:
num[t] += s
else:
n... | Title: Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Little Petya likes to play very much. And most of all he likes to play the following game:
He is given a sequence of *N* integer numbers. At each step it is allowed to increase the value of any number by 1 or to decrease it by 1. ... | ```python
n = int(input())
num = list(map(int, input().split()))
ans = 0
y = sorted(num)
for i in range(n - 1):
k = min(num[i: n])
t = num.index(k)
if num[i] > k:
s = num[i] - k
ans += s
l = num[t + 1] - num[t]
if l > s:
num[t] += s
else:
... | -1 | MatrixStudio/Codeforces-Python-Submissions |
570 | A | Elections | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusual. At the first stage of elections the votes are counted for each city: it is assumed that in ... | The first line of the input contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of candidates and of cities, respectively.
Each of the next *m* lines contains *n* non-negative integers, the *j*-th number in the *i*-th line *a**ij* (1<=≤<=*j*<=≤<=*n*, 1<=≤<=*i*<=≤<=*m*, 0<=≤<=*a**ij*<=≤<=109) denotes ... | Print a single number — the index of the candidate who won the elections. The candidates are indexed starting from one. | [
"3 3\n1 2 3\n2 3 1\n1 2 1\n",
"3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7\n"
] | [
"2",
"1"
] | Note to the first sample test. At the first stage city 1 chosen candidate 3, city 2 chosen candidate 2, city 3 chosen candidate 2. The winner is candidate 2, he gained 2 votes.
Note to the second sample test. At the first stage in city 1 candidates 1 and 2 got the same maximum number of votes, but candidate 1 has a sm... | 500 | [
{
"input": "3 3\n1 2 3\n2 3 1\n1 2 1",
"output": "2"
},
{
"input": "3 4\n10 10 3\n5 1 6\n2 2 2\n1 5 7",
"output": "1"
},
{
"input": "1 3\n5\n3\n2",
"output": "1"
},
{
"input": "3 1\n1 2 3",
"output": "3"
},
{
"input": "3 1\n100 100 100",
"output": "1"
},
{... | 1,597,493,004 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 12 | 124 | 0 | n,m=[int(i) for i in input().split()]
l=[0]*n
e=[]
for i in range(m):
a=[int(i) for i in input().split()]
for j in range(0,len(a)):
l[j]=l[j]+a[j]
f=max(l)
e.append(l.index(f)+1)
d={}
for i in range(0,len(e)):
if(e[i] not in d):
d[e[i]]=1
else:
d[e[i]]=d[e[i... | Title: Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The country of Byalechinsk is running elections involving *n* candidates. The country consists of *m* cities. We know how many people in each city voted for each candidate.
The electoral system in the country is pretty unusu... | ```python
n,m=[int(i) for i in input().split()]
l=[0]*n
e=[]
for i in range(m):
a=[int(i) for i in input().split()]
for j in range(0,len(a)):
l[j]=l[j]+a[j]
f=max(l)
e.append(l.index(f)+1)
d={}
for i in range(0,len(e)):
if(e[i] not in d):
d[e[i]]=1
else:
d[e... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
940 | C | Phone Numbers | PROGRAMMING | 1,500 | [
"constructive algorithms",
"implementation",
"strings"
] | null | null | And where the are the phone numbers?
You are given a string *s* consisting of lowercase English letters and an integer *k*. Find the lexicographically smallest string *t* of length *k*, such that its set of letters is a subset of the set of letters of *s* and *s* is lexicographically smaller than *t*.
It's guaranteed... | The first line of input contains two space separated integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100<=000) — the length of *s* and the required length of *t*.
The second line of input contains the string *s* consisting of *n* lowercase English letters. | Output the string *t* conforming to the requirements above.
It's guaranteed that the answer exists. | [
"3 3\nabc\n",
"3 2\nabc\n",
"3 3\nayy\n",
"2 3\nba\n"
] | [
"aca\n",
"ac\n",
"yaa\n",
"baa\n"
] | In the first example the list of strings *t* of length 3, such that the set of letters of *t* is a subset of letters of *s* is as follows: aaa, aab, aac, aba, abb, abc, aca, acb, .... Among them, those are lexicographically greater than abc: aca, acb, .... Out of those the lexicographically smallest is aca. | 1,250 | [
{
"input": "3 3\nabc",
"output": "aca"
},
{
"input": "3 2\nabc",
"output": "ac"
},
{
"input": "3 3\nayy",
"output": "yaa"
},
{
"input": "2 3\nba",
"output": "baa"
},
{
"input": "1 3\nf",
"output": "fff"
},
{
"input": "3 1\nazz",
"output": "z"
},
... | 1,521,992,788 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 155 | 7,987,200 | n,k = map(int,input().split())
s = list(input())
mn = min(s)
mx = max(s)
if k>n:
s = "".join(s)
print(s+mn*(k-n))
else:
der = [False]*26
for i in s:
der[ord(i)-ord('a')] = True
ans = s[:k]
for i in range(k-1,-1,-1):
if ans[i]==mx: continue
for j in range(or... | Title: Phone Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
And where the are the phone numbers?
You are given a string *s* consisting of lowercase English letters and an integer *k*. Find the lexicographically smallest string *t* of length *k*, such that its set of letters is a ... | ```python
n,k = map(int,input().split())
s = list(input())
mn = min(s)
mx = max(s)
if k>n:
s = "".join(s)
print(s+mn*(k-n))
else:
der = [False]*26
for i in s:
der[ord(i)-ord('a')] = True
ans = s[:k]
for i in range(k-1,-1,-1):
if ans[i]==mx: continue
for j i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
681 | A | A Good Contest | PROGRAMMING | 800 | [
"implementation"
] | null | null | Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part in a rated contest, his rating is changed depending on his performance.
Anton wants the color of hi... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants Anton has outscored in this contest .
The next *n* lines describe participants results: the *i*-th of them consists of a participant handle *name**i* and two integers *before**i* and *after**i* (<=-<=4000<=≤<=*be... | Print «YES» (quotes for clarity), if Anton has performed good in the contest and «NO» (quotes for clarity) otherwise. | [
"3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749\n",
"3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450\n"
] | [
"YES",
"NO"
] | In the first sample, Anton has outscored user with handle Burunduk1, whose handle was colored red before the contest and his rating has increased after the contest.
In the second sample, Applejack's rating has not increased after the contest, while both Fluttershy's and Pinkie_Pie's handles were not colored red before... | 500 | [
{
"input": "3\nBurunduk1 2526 2537\nBudAlNik 2084 2214\nsubscriber 2833 2749",
"output": "YES"
},
{
"input": "3\nApplejack 2400 2400\nFluttershy 2390 2431\nPinkie_Pie -2500 -2450",
"output": "NO"
},
{
"input": "1\nDb -3373 3591",
"output": "NO"
},
{
"input": "5\nQ2bz 960 2342... | 1,649,747,145 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 60 | 62 | 0 | flag=0
for _ in range(int(input())):
l=list(input().split())
if int(l[1])>=2400 and int(l[1])<int(l[2]):
flag=1
if flag==1:
print("YES")
else:
print("NO") | Title: A Good Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or equal to 2200, etc. Each time participant takes part ... | ```python
flag=0
for _ in range(int(input())):
l=list(input().split())
if int(l[1])>=2400 and int(l[1])<int(l[2]):
flag=1
if flag==1:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not equal to *n*, of course). For example, if *n*<==<=6 then Funt has to pay 3 burles, while fo... | The first line of the input contains a single integer *n* (2<=≤<=*n*<=≤<=2·109) — the total year income of mr. Funt. | Print one integer — minimum possible number of burles that mr. Funt has to pay as a tax. | [
"4\n",
"27\n"
] | [
"2\n",
"3\n"
] | none | 0 | [
{
"input": "4",
"output": "2"
},
{
"input": "27",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "5",
"output": "1"
},
{
"input": "10",
"output": "2"
},
{
"input": "2000000000",
"output": "2"
},
{
"input": "26",
"output": ... | 1,480,677,797 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 78 | 0 | def f(n) :
prime=True
for i in range(2,50000) :
if i!=n and n%i==0 :
prime=False
return prime
n = int(input())
if f(n)==True :
print(1)
else :
if n%2==0 :
print(2)
elif f(n-2)==True :
print(2)
else :
print(3) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Funt now lives in a country with a very specific tax laws. The total income of mr. Funt during this year is equal to *n* (*n*<=≥<=2) burles and the amount of tax he has to pay is calculated as the maximum divisor of *n* (not e... | ```python
def f(n) :
prime=True
for i in range(2,50000) :
if i!=n and n%i==0 :
prime=False
return prime
n = int(input())
if f(n)==True :
print(1)
else :
if n%2==0 :
print(2)
elif f(n-2)==True :
print(2)
else :
print(3)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
886 | B | Vlad and Cafes | PROGRAMMING | 1,000 | [] | null | null | Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research.
First of all, Vlad assigned individual indices to all cafes. Then, he wrote down indices of cafes... | In first line there is one integer *n* (1<=≤<=*n*<=≤<=2·105) — number of cafes indices written by Vlad.
In second line, *n* numbers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=2·105) are written — indices of cafes in order of being visited by Vlad. Vlad could visit some cafes more than once. Note that in numeration, ... | Print one integer — index of the cafe that Vlad hasn't visited for as long as possible. | [
"5\n1 3 2 1 2\n",
"6\n2 1 2 2 4 1\n"
] | [
"3\n",
"2\n"
] | In first test, there are three cafes, and the last visits to cafes with indices 1 and 2 were after the last visit to cafe with index 3; so this cafe is the answer.
In second test case, there are also three cafes, but with indices 1, 2 and 4. Cafes with indices 1 and 4 were visited after the last visit of cafe with in... | 1,000 | [
{
"input": "5\n1 3 2 1 2",
"output": "3"
},
{
"input": "6\n2 1 2 2 4 1",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n200000",
"output": "200000"
},
{
"input": "2\n2018 2017",
"output": "2018"
},
{
"input": "5\n100 1000 1000 1000... | 1,692,252,242 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 16,588,800 | n = int(input())
x = list(map(int, input().split()))
y = []
for i in range(n - 1, -1, -1):
if x[i] not in y:
y.append(x[i])
print(y[-1])
| Title: Vlad and Cafes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vlad likes to eat in cafes very much. During his life, he has visited cafes *n* times. Unfortunately, Vlad started to feel that his last visits are not any different from each other. To fix that Vlad had a small research... | ```python
n = int(input())
x = list(map(int, input().split()))
y = []
for i in range(n - 1, -1, -1):
if x[i] not in y:
y.append(x[i])
print(y[-1])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
171 | B | Star | PROGRAMMING | 1,300 | [
"*special",
"combinatorics"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257). | Print a single integer *output* (1<=≤<=*output*<=≤<=2·109). | [
"2\n"
] | [
"13"
] | none | 0 | [
{
"input": "2",
"output": "13"
},
{
"input": "1",
"output": "1"
},
{
"input": "3",
"output": "37"
},
{
"input": "4",
"output": "73"
},
{
"input": "5",
"output": "121"
},
{
"input": "6",
"output": "181"
},
{
"input": "7",
"output": "253"... | 1,553,848,855 | 955 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 216 | 0 | a = int(input())
print(2 * a * (a + 1) + 1) | Title: Star
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=18257).
Output Specification:
Print a single integer *output* (1<=≤<=*output*<=≤<=2·109).
Demo Input:
['2\n']
Demo Output:
['13']
Note:
none | ```python
a = int(input())
print(2 * a * (a + 1) + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | ||
190 | D | Non-Secret Cypher | PROGRAMMING | 1,900 | [
"two pointers"
] | null | null | Berland starts to seize the initiative on the war with Flatland. To drive the enemy from their native land, the berlanders need to know exactly how many more flatland soldiers are left in the enemy's reserve. Fortunately, the scouts captured an enemy in the morning, who had a secret encrypted message with the informati... | The first line contains two space-separated integers *n*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=4·105), showing how many numbers an array has and how many equal numbers the subarrays are required to have, correspondingly.
The second line contains *n* space-separated integers *a**i* (1<=≤<=*a**i*<=≤<=109) — elements of the array... | Print the single number — the number of such subarrays of array *a*, that they have at least *k* equal integers.
Please do not use the %lld specifier to read or write 64-bit integers in С++. In is preferred to use the cin, cout streams or the %I64d specifier. | [
"4 2\n1 2 1 2\n",
"5 3\n1 2 1 1 3\n",
"3 1\n1 1 1\n"
] | [
"3",
"2",
"6"
] | In the first sample are three subarrays, containing at least two equal numbers: (1,2,1), (2,1,2) and (1,2,1,2).
In the second sample are two subarrays, containing three equal numbers: (1,2,1,1,3) and (1,2,1,1).
In the third sample any subarray contains at least one 1 number. Overall they are 6: (1), (1), (1), (1,1), ... | 2,000 | [
{
"input": "4 2\n1 2 1 2",
"output": "3"
},
{
"input": "5 3\n1 2 1 1 3",
"output": "2"
},
{
"input": "3 1\n1 1 1",
"output": "6"
},
{
"input": "20 2\n6 7 2 4 6 8 4 3 10 5 3 5 7 9 1 2 8 1 9 10",
"output": "131"
},
{
"input": "63 2\n1 2 1 2 4 5 1 1 1 1 1 2 3 1 2 3 3... | 1,688,580,168 | 2,147,483,647 | Python 3 | OK | TESTS | 120 | 778 | 51,404,800 | def count_subarrays(n, k, arr):
count = 0
freq = {}
left = 0
for right in range(n):
freq[arr[right]] = freq.get(arr[right], 0) + 1
while left <= right and freq[arr[right]] >= k:
count += n - right
freq[arr[left]] -= 1
left += 1
return count
n, k... | Title: Non-Secret Cypher
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland starts to seize the initiative on the war with Flatland. To drive the enemy from their native land, the berlanders need to know exactly how many more flatland soldiers are left in the enemy's reserve. Fortunat... | ```python
def count_subarrays(n, k, arr):
count = 0
freq = {}
left = 0
for right in range(n):
freq[arr[right]] = freq.get(arr[right], 0) + 1
while left <= right and freq[arr[right]] >= k:
count += n - right
freq[arr[left]] -= 1
left += 1
return c... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
859 | C | Pie Rules | PROGRAMMING | 1,500 | [
"dp",
"games"
] | null | null | You may have heard of the pie rule before. It states that if two people wish to fairly share a slice of pie, one person should cut the slice in half, and the other person should choose who gets which slice. Alice and Bob have many slices of pie, and rather than cutting the slices in half, each individual slice will be ... | Input will begin with an integer *N* (1<=≤<=*N*<=≤<=50), the number of slices of pie.
Following this is a line with *N* integers indicating the sizes of the slices (each between 1 and 100000, inclusive), in the order in which they must be handed out. | Print two integers. First, the sum of the sizes of slices eaten by Alice, then the sum of the sizes of the slices eaten by Bob, assuming both players make their decisions optimally. | [
"3\n141 592 653\n",
"5\n10 21 10 21 10\n"
] | [
"653 733\n",
"31 41\n"
] | In the first example, Bob takes the size 141 slice for himself and gives the decider token to Alice. Then Alice gives the size 592 slice to Bob and keeps the decider token for herself, so that she can then give the size 653 slice to herself. | 1,000 | [
{
"input": "3\n141 592 653",
"output": "653 733"
},
{
"input": "5\n10 21 10 21 10",
"output": "31 41"
},
{
"input": "1\n100000",
"output": "0 100000"
},
{
"input": "50\n100000 100000 100000 100000 100000 100000 100000 100000 100000 100000 100000 100000 100000 100000 100000 10... | 1,505,707,506 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 4,608,000 |
import sys
cache = {}
def max_possible(pie_slices, current_slice, pre_sums):
if current_slice in cache:
return cache[current_slice]
if len(pie_slices) - 1 == current_slice:
return pie_slices[current_slice]
max_score = -1
for cs in range(current_slice, len(pie_slices) - 1):
... | Title: Pie Rules
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You may have heard of the pie rule before. It states that if two people wish to fairly share a slice of pie, one person should cut the slice in half, and the other person should choose who gets which slice. Alice and Bob have... | ```python
import sys
cache = {}
def max_possible(pie_slices, current_slice, pre_sums):
if current_slice in cache:
return cache[current_slice]
if len(pie_slices) - 1 == current_slice:
return pie_slices[current_slice]
max_score = -1
for cs in range(current_slice, len(pie_slices) - ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,650,417,944 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 92 | 0 | from math import gcd
a,b,n=[int(x) for x in input().split()]
j=0
while n>0:
if j%2==0:
n-=gcd(a,n)
else:
n-=gcd(b,n)
j+=1
if j%2==0:
print("1")
else:
print("0")
| Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
from math import gcd
a,b,n=[int(x) for x in input().split()]
j=0
while n>0:
if j%2==0:
n-=gcd(a,n)
else:
n-=gcd(b,n)
j+=1
if j%2==0:
print("1")
else:
print("0")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,699,939,029 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 25 | 62 | 1,740,800 | n = int(input())
s = input()
countA = 0
countD = 0
for i in s:
if i == "A":
countA += 1
if i == "D":
countD += 1
if countA > countD:
print("Anton")
if countD > countA:
print("Danik")
if countD == countA:
print("Friendship") | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
n = int(input())
s = input()
countA = 0
countD = 0
for i in s:
if i == "A":
countA += 1
if i == "D":
countD += 1
if countA > countD:
print("Anton")
if countD > countA:
print("Danik")
if countD == countA:
print("Friendship")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
534 | B | Covered Path | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"math"
] | null | null | The on-board computer on Polycarp's car measured that the car speed at the beginning of some section of the path equals *v*1 meters per second, and in the end it is *v*2 meters per second. We know that this section of the route took exactly *t* seconds to pass.
Assuming that at each of the seconds the speed is constan... | The first line contains two integers *v*1 and *v*2 (1<=≤<=*v*1,<=*v*2<=≤<=100) — the speeds in meters per second at the beginning of the segment and at the end of the segment, respectively.
The second line contains two integers *t* (2<=≤<=*t*<=≤<=100) — the time when the car moves along the segment in seconds, *d* (0<... | Print the maximum possible length of the path segment in meters. | [
"5 6\n4 2\n",
"10 10\n10 0\n"
] | [
"26",
"100"
] | In the first sample the sequence of speeds of Polycarpus' car can look as follows: 5, 7, 8, 6. Thus, the total path is 5 + 7 + 8 + 6 = 26 meters.
In the second sample, as *d* = 0, the car covers the whole segment at constant speed *v* = 10. In *t* = 10 seconds it covers the distance of 100 meters. | 1,000 | [
{
"input": "5 6\n4 2",
"output": "26"
},
{
"input": "10 10\n10 0",
"output": "100"
},
{
"input": "87 87\n2 10",
"output": "174"
},
{
"input": "1 11\n6 2",
"output": "36"
},
{
"input": "100 10\n10 10",
"output": "550"
},
{
"input": "1 1\n100 10",
"o... | 1,441,342,752 | 2,147,483,647 | PyPy 3 | OK | TESTS | 64 | 124 | 307,200 | u, v = (int(x) for x in input().split())
t, d = (int(x) for x in input().split())
ans = 0
while t > 1:
if u < v:
ans += u
u += d
else:
ans += v
v += d
t -= 1
print(ans + min(u, v))
| Title: Covered Path
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The on-board computer on Polycarp's car measured that the car speed at the beginning of some section of the path equals *v*1 meters per second, and in the end it is *v*2 meters per second. We know that this section of the ... | ```python
u, v = (int(x) for x in input().split())
t, d = (int(x) for x in input().split())
ans = 0
while t > 1:
if u < v:
ans += u
u += d
else:
ans += v
v += d
t -= 1
print(ans + min(u, v))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
489 | C | Given Length and Sum of Digits... | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes. | The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers. | In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes). | [
"2 15\n",
"3 0\n"
] | [
"69 96\n",
"-1 -1\n"
] | none | 1,500 | [
{
"input": "2 15",
"output": "69 96"
},
{
"input": "3 0",
"output": "-1 -1"
},
{
"input": "2 1",
"output": "10 10"
},
{
"input": "3 10",
"output": "109 910"
},
{
"input": "100 100",
"output": "1000000000000000000000000000000000000000000000000000000000000000000... | 1,699,103,349 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | lengthOfDigits, sumOfDigits = map(int, input().split())
if 9 * lengthOfDigits < sumOfDigits or sumOfDigits == 0:
print("-1", "-1")
else:
small = ""
minLength = (sumOfDigits + 9) // 9
small += (lengthOfDigits - minLength) * "0"
Mod = sumOfDigits % 9
small += str(Mod)
sumOfDigits -= M... | Title: Given Length and Sum of Digits...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should ... | ```python
lengthOfDigits, sumOfDigits = map(int, input().split())
if 9 * lengthOfDigits < sumOfDigits or sumOfDigits == 0:
print("-1", "-1")
else:
small = ""
minLength = (sumOfDigits + 9) // 9
small += (lengthOfDigits - minLength) * "0"
Mod = sumOfDigits % 9
small += str(Mod)
sumOfD... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,614,061,052 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 62 | 0 | s=input()
a="hello"
c=0
j=0
for i in range(len(s)):
if j<5:
if s[i]==a[j]:
j=j+1
c=c+1
if c==5:
print("YES")
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s=input()
a="hello"
c=0
j=0
for i in range(len(s)):
if j<5:
if s[i]==a[j]:
j=j+1
c=c+1
if c==5:
print("YES")
else:
print("NO")
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
272 | C | Dima and Staircase | PROGRAMMING | 1,500 | [
"data structures",
"implementation"
] | null | null | Dima's got a staircase that consists of *n* stairs. The first stair is at height *a*1, the second one is at *a*2, the last one is at *a**n* (1<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*).
Dima decided to play with the staircase, so he is throwing rectangular boxes at the staircase from above. The *i*-th box has width *w**i... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of stairs in the staircase. The second line contains a non-decreasing sequence, consisting of *n* integers, *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109; *a**i*<=≤<=*a**i*<=+<=1).
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the numbe... | Print *m* integers — for each box the height, where the bottom of the box will be after landing. Print the answers for the boxes in the order, in which the boxes are given in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I... | [
"5\n1 2 3 6 6\n4\n1 1\n3 1\n1 1\n4 3\n",
"3\n1 2 3\n2\n1 1\n3 1\n",
"1\n1\n5\n1 2\n1 10\n1 10\n1 10\n1 10\n"
] | [
"1\n3\n4\n6\n",
"1\n3\n",
"1\n3\n13\n23\n33\n"
] | The first sample are shown on the picture. | 1,500 | [
{
"input": "5\n1 2 3 6 6\n4\n1 1\n3 1\n1 1\n4 3",
"output": "1\n3\n4\n6"
},
{
"input": "3\n1 2 3\n2\n1 1\n3 1",
"output": "1\n3"
},
{
"input": "1\n1\n5\n1 2\n1 10\n1 10\n1 10\n1 10",
"output": "1\n3\n13\n23\n33"
},
{
"input": "8\n6 10 18 23 30 31 31 33\n1\n5 3",
"output":... | 1,660,995,263 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n = int(input())
heights = list(map(int, input().split()))
l, lh, lw = 0, 0, 0
for _ in range(int(input())):
w, h = list(map(int, input().split()))
l = max(l + h, heights[w-1])
print(l)
| Title: Dima and Staircase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima's got a staircase that consists of *n* stairs. The first stair is at height *a*1, the second one is at *a*2, the last one is at *a**n* (1<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*).
Dima decided to play with the st... | ```python
n = int(input())
heights = list(map(int, input().split()))
l, lh, lw = 0, 0, 0
for _ in range(int(input())):
w, h = list(map(int, input().split()))
l = max(l + h, heights[w-1])
print(l)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
940 | B | Our Tanya is Crying Out Loud | PROGRAMMING | 1,400 | [
"dp",
"greedy"
] | null | null | Right now she actually isn't. But she will be, if you don't solve this problem.
You are given integers *n*, *k*, *A* and *B*. There is a number *x*, which is initially equal to *n*. You are allowed to perform two types of operations:
1. Subtract 1 from *x*. This operation costs you *A* coins. 1. Divide *x* by *k*.... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=2·109).
The second line contains a single integer *k* (1<=≤<=*k*<=≤<=2·109).
The third line contains a single integer *A* (1<=≤<=*A*<=≤<=2·109).
The fourth line contains a single integer *B* (1<=≤<=*B*<=≤<=2·109). | Output a single integer — the minimum amount of coins you have to pay to make *x* equal to 1. | [
"9\n2\n3\n1\n",
"5\n5\n2\n20\n",
"19\n3\n4\n2\n"
] | [
"6\n",
"8\n",
"12\n"
] | In the first testcase, the optimal strategy is as follows:
- Subtract 1 from *x* (9 → 8) paying 3 coins. - Divide *x* by 2 (8 → 4) paying 1 coin. - Divide *x* by 2 (4 → 2) paying 1 coin. - Divide *x* by 2 (2 → 1) paying 1 coin.
The total cost is 6 coins.
In the second test case the optimal strategy is to subtra... | 1,250 | [
{
"input": "9\n2\n3\n1",
"output": "6"
},
{
"input": "5\n5\n2\n20",
"output": "8"
},
{
"input": "19\n3\n4\n2",
"output": "12"
},
{
"input": "1845999546\n999435865\n1234234\n2323423",
"output": "1044857680578777"
},
{
"input": "1604353664\n1604353665\n9993432\n1",
... | 1,664,162,182 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 0 | n=int(input())
k=int(input())
a=int(input())
b=int(input())
x=n
count=0
if(a>b):
while(x!=1):
if(x%k==0):
x=x//k
count=count+b
else:
x=x-1
count=count+a
else:
while(x!=1):
x=x-1
count=count+a
print(count)
| Title: Our Tanya is Crying Out Loud
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Right now she actually isn't. But she will be, if you don't solve this problem.
You are given integers *n*, *k*, *A* and *B*. There is a number *x*, which is initially equal to *n*. You are allowed to perf... | ```python
n=int(input())
k=int(input())
a=int(input())
b=int(input())
x=n
count=0
if(a>b):
while(x!=1):
if(x%k==0):
x=x//k
count=count+b
else:
x=x-1
count=count+a
else:
while(x!=1):
x=x-1
count=count+a
print(count)... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
682 | A | Alyona and Numbers | PROGRAMMING | 1,100 | [
"constructive algorithms",
"math",
"number theory"
] | null | null | After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers from 1 to *m*. Now the girl wants to count how many pairs of integers she can choose, one from the first... | The only line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1<=000<=000). | Print the only integer — the number of pairs of integers (*x*,<=*y*) such that 1<=≤<=*x*<=≤<=*n*, 1<=≤<=*y*<=≤<=*m* and (*x*<=+<=*y*) is divisible by 5. | [
"6 12\n",
"11 14\n",
"1 5\n",
"3 8\n",
"5 7\n",
"21 21\n"
] | [
"14\n",
"31\n",
"1\n",
"5\n",
"7\n",
"88\n"
] | Following pairs are suitable in the first sample case:
- for *x* = 1 fits *y* equal to 4 or 9; - for *x* = 2 fits *y* equal to 3 or 8; - for *x* = 3 fits *y* equal to 2, 7 or 12; - for *x* = 4 fits *y* equal to 1, 6 or 11; - for *x* = 5 fits *y* equal to 5 or 10; - for *x* = 6 fits *y* equal to 4 or 9.
Only th... | 500 | [
{
"input": "6 12",
"output": "14"
},
{
"input": "11 14",
"output": "31"
},
{
"input": "1 5",
"output": "1"
},
{
"input": "3 8",
"output": "5"
},
{
"input": "5 7",
"output": "7"
},
{
"input": "21 21",
"output": "88"
},
{
"input": "10 15",
... | 1,586,583,512 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | arr = input().split(" ")
n, m = int(arr[0]), int(arr[1])
sum_left = n*((1+1)/5+(1+n)/5)/2
sum_right = n*((1+m)/5+(m+n)/5)/2
offset = math.floor((1+n)/5) - math.floor((1+1)/5)
pairs = math.floor(sum_right) - math.floor(sum_left) + offset
print(int(pairs))
| Title: Alyona and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After finishing eating her bun, Alyona came up with two integers *n* and *m*. She decided to write down two columns of integers — the first column containing integers from 1 to *n* and the second containing integers ... | ```python
arr = input().split(" ")
n, m = int(arr[0]), int(arr[1])
sum_left = n*((1+1)/5+(1+n)/5)/2
sum_right = n*((1+m)/5+(m+n)/5)/2
offset = math.floor((1+n)/5) - math.floor((1+1)/5)
pairs = math.floor(sum_right) - math.floor(sum_left) + offset
print(int(pairs))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
776 | B | Sherlock and his girlfriend | PROGRAMMING | 1,200 | [
"constructive algorithms",
"number theory"
] | null | null | Sherlock has a new girlfriend (so unlike him!). Valentine's day is coming and he wants to gift her some jewelry.
He bought *n* pieces of jewelry. The *i*-th piece has price equal to *i*<=+<=1, that is, the prices of the jewelry are 2,<=3,<=4,<=... *n*<=+<=1.
Watson gave Sherlock a challenge to color these jewelry pie... | The only line contains single integer *n* (1<=≤<=*n*<=≤<=100000) — the number of jewelry pieces. | The first line of output should contain a single integer *k*, the minimum number of colors that can be used to color the pieces of jewelry with the given constraints.
The next line should consist of *n* space-separated integers (between 1 and *k*) that specify the color of each piece in the order of increasing price.
... | [
"3\n",
"4\n"
] | [
"2\n1 1 2 ",
"2\n2 1 1 2\n"
] | In the first input, the colors for first, second and third pieces of jewelry having respective prices 2, 3 and 4 are 1, 1 and 2 respectively.
In this case, as 2 is a prime divisor of 4, colors of jewelry having prices 2 and 4 must be distinct. | 1,000 | [
{
"input": "3",
"output": "2\n1 1 2 "
},
{
"input": "4",
"output": "2\n1 1 2 1 "
},
{
"input": "17",
"output": "2\n1 1 2 1 2 1 2 2 2 1 2 1 2 2 2 1 2 "
},
{
"input": "25",
"output": "2\n1 1 2 1 2 1 2 2 2 1 2 1 2 2 2 1 2 1 2 2 2 1 2 2 2 "
},
{
"input": "85",
"ou... | 1,559,759,545 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 202 | 921,600 | import math as mt
import sys,string,bisect
input=sys.stdin.readline
from collections import deque
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
n=I()
f=[0]*2+[1]*n
for i in range(2,n+2):
k=1
if f[i]==1:
for j in ra... | Title: Sherlock and his girlfriend
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sherlock has a new girlfriend (so unlike him!). Valentine's day is coming and he wants to gift her some jewelry.
He bought *n* pieces of jewelry. The *i*-th piece has price equal to *i*<=+<=1, that is, the ... | ```python
import math as mt
import sys,string,bisect
input=sys.stdin.readline
from collections import deque
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
I=lambda :int(input())
n=I()
f=[0]*2+[1]*n
for i in range(2,n+2):
k=1
if f[i]==1:
f... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,656,154,873 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 12 | 122 | 0 | n,m = map(int, input().split())
list_1= [int(n) for n in input().split(" ",n)]
sum= 0
counter= 0
for i in list_1:
if i<0 and counter!=m:
sum+= -i
counter+= 1
print(sum) | Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m = map(int, input().split())
list_1= [int(n) for n in input().split(" ",n)]
sum= 0
counter= 0
for i in list_1:
if i<0 and counter!=m:
sum+= -i
counter+= 1
print(sum)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
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