contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
75 | A | Life Without Zeros | PROGRAMMING | 1,000 | [
"implementation"
] | A. Life Without Zeros | 2 | 256 | Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation *a*<=+<=*b*<==<=*c*, where *a* and *b* are positive integers, and *c*... | The input will consist of two lines, the first line will contain the integer *a*, and the second line will contain the integer *b* which are in the equation as described above (1<=≤<=*a*,<=*b*<=≤<=109). There won't be any leading zeros in both. The value of *c* should be calculated as *c*<==<=*a*<=+<=*b*. | The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise. | [
"101\n102\n",
"105\n106\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "101\n102",
"output": "YES"
},
{
"input": "105\n106",
"output": "NO"
},
{
"input": "544\n397",
"output": "YES"
},
{
"input": "822\n280",
"output": "NO"
},
{
"input": "101\n413",
"output": "NO"
},
{
"input": "309\n139",
"output": "NO"
}... | 1,694,968,402 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 92 | 0 | def removeZeros(x):
number_without_zeros = 0
i = 0
while(x > 0):
remainder = x % 10
if(remainder != 0):
number_without_zeros = number_without_zeros + remainder * (10 ** i)
i += 1
x //= 10
return number_without_zeros
def lifeWithoutZeros(a, b):
... | Title: Life Without Zeros
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Can you imagine our life if we removed all zeros from it? For sure we will have many problems.
In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assu... | ```python
def removeZeros(x):
number_without_zeros = 0
i = 0
while(x > 0):
remainder = x % 10
if(remainder != 0):
number_without_zeros = number_without_zeros + remainder * (10 ** i)
i += 1
x //= 10
return number_without_zeros
def lifeWithoutZer... | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,668,521,904 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 1,000 | 1,536,000 | import math
ss=input()
int_list = [int(x) for x in ss.split()]
a,b = int_list[0],int_list[1]
n,t=a,b
s=t
k=1
flag=0
if(t==1):
print(1,end="")
for i in range(n-1):
print(0,end='')
else:
while (len(str(s)) <= n):
if (s % t == 0 and len(str(s)) == n):
flag = 1
... | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
import math
ss=input()
int_list = [int(x) for x in ss.split()]
a,b = int_list[0],int_list[1]
n,t=a,b
s=t
k=1
flag=0
if(t==1):
print(1,end="")
for i in range(n-1):
print(0,end='')
else:
while (len(str(s)) <= n):
if (s % t == 0 and len(str(s)) == n):
flag =... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
433 | A | Kitahara Haruki's Gift | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Kitahara Haruki has bought *n* apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between the friends.
Each apple weights 100 grams or 200 grams. Of course Kitahara Haruki doesn't want to offend any of his friend. Therefore the total weight of the apples given to Touma Kazusa must be equa... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of apples. The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (*w**i*<==<=100 or *w**i*<==<=200), where *w**i* is the weight of the *i*-th apple. | In a single line print "YES" (without the quotes) if it is possible to divide all the apples between his friends. Otherwise print "NO" (without the quotes). | [
"3\n100 200 100\n",
"4\n100 100 100 200\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample Kitahara Haruki can give the first and the last apple to Ogiso Setsuna and the middle apple to Touma Kazusa. | 500 | [
{
"input": "3\n100 200 100",
"output": "YES"
},
{
"input": "4\n100 100 100 200",
"output": "NO"
},
{
"input": "1\n100",
"output": "NO"
},
{
"input": "1\n200",
"output": "NO"
},
{
"input": "2\n100 100",
"output": "YES"
},
{
"input": "2\n200 200",
"o... | 1,629,301,112 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 77 | 6,758,400 | n=int(input())
n_list=list(map(int,input().split()))
a=n_list.count(100)
b=n_list.count(200)
if a%2 != 0:
print("NO")
elif b%2 != 0 and a<2:
print("NO")
else:
print("YES") | Title: Kitahara Haruki's Gift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kitahara Haruki has bought *n* apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between the friends.
Each apple weights 100 grams or 200 grams. Of course Kitahara Haruki doesn't w... | ```python
n=int(input())
n_list=list(map(int,input().split()))
a=n_list.count(100)
b=n_list.count(200)
if a%2 != 0:
print("NO")
elif b%2 != 0 and a<2:
print("NO")
else:
print("YES")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
433 | B | Kuriyama Mirai's Stones | PROGRAMMING | 1,200 | [
"dp",
"implementation",
"sortings"
] | null | null | Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones so she will ask you two kinds of questions:
1. She will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* integers: *v*1,<=*v*2,<=...,<=*v**n* (1<=≤<=*v**i*<=≤<=109) — costs of the stones.
The third line contains an integer *m* (1<=≤<=*m*<=≤<=105) — the number of Kuriyama Mirai's questions. Then follow *m* lines, each line contains t... | Print *m* lines. Each line must contain an integer — the answer to Kuriyama Mirai's question. Print the answers to the questions in the order of input. | [
"6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6\n",
"4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2\n"
] | [
"24\n9\n28\n",
"10\n15\n5\n15\n5\n5\n2\n12\n3\n5\n"
] | Please note that the answers to the questions may overflow 32-bit integer type. | 1,500 | [
{
"input": "6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6",
"output": "24\n9\n28"
},
{
"input": "4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2",
"output": "10\n15\n5\n15\n5\n5\n2\n12\n3\n5"
},
{
"input": "4\n2 2 3 6\n9\n2 2 3\n1 1 3\n2 2 3\n2 2 3\n2 2 2\n1... | 1,646,529,826 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 420 | 21,606,400 | #pylint:disable=W0622
import sys
input = sys.stdin.readline
def GetSubSumList(a) :
sl = a.copy()
for i in range(1, len(sl)) : sl[i] += sl[i-1]
return sl
def GetSubSum(l, r, a) :
if l == 0 : return a[r]
else : return a[r] - a[l-1]
L = int(input())
A = list(map(int, input().split()))
A_SS = GetSubSumList(A)
SA... | Title: Kuriyama Mirai's Stones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones s... | ```python
#pylint:disable=W0622
import sys
input = sys.stdin.readline
def GetSubSumList(a) :
sl = a.copy()
for i in range(1, len(sl)) : sl[i] += sl[i-1]
return sl
def GetSubSum(l, r, a) :
if l == 0 : return a[r]
else : return a[r] - a[l-1]
L = int(input())
A = list(map(int, input().split()))
A_SS = GetSubSum... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
495 | B | Modular Equations | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | Last week, Hamed learned about a new type of equations in his math class called Modular Equations. Lets define *i* modulo *j* as the remainder of division of *i* by *j* and denote it by . A Modular Equation, as Hamed's teacher described, is an equation of the form in which *a* and *b* are two non-negative integers and... | In the only line of the input two space-separated integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=109) are given. | If there is an infinite number of answers to our equation, print "infinity" (without the quotes). Otherwise print the number of solutions of the Modular Equation . | [
"21 5\n",
"9435152 272\n",
"10 10\n"
] | [
"2\n",
"282\n",
"infinity\n"
] | In the first sample the answers of the Modular Equation are 8 and 16 since <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/6f5ff39ebd209bf990adaf91f4b82f9687097224.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "21 5",
"output": "2"
},
{
"input": "9435152 272",
"output": "282"
},
{
"input": "10 10",
"output": "infinity"
},
{
"input": "0 1000000000",
"output": "0"
},
{
"input": "11 2",
"output": "2"
},
{
"input": "1 0",
"output": "1"
},
{
... | 1,672,862,419 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | a, b = map(int, input().split())
if a < b:
print(0)
elif a == b:
print("infinity")
else:
solucoes = set()
for i in range(1, int((a - b) ** 0.5) + 1):
if (a - b) % i == 0:
if i > b:
solucoes.add(i)
if (a - b) // i > b:
solucoes.add((a - b) ... | Title: Modular Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Last week, Hamed learned about a new type of equations in his math class called Modular Equations. Lets define *i* modulo *j* as the remainder of division of *i* by *j* and denote it by . A Modular Equation, as Hamed'... | ```python
a, b = map(int, input().split())
if a < b:
print(0)
elif a == b:
print("infinity")
else:
solucoes = set()
for i in range(1, int((a - b) ** 0.5) + 1):
if (a - b) % i == 0:
if i > b:
solucoes.add(i)
if (a - b) // i > b:
solucoes.ad... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and ... | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,512,693,945 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 11,161,600 | line1=int(input())
line2=input().split()
m=[]
for i in line2:
m.append(int(i))
m.sort()
if len(m)>=2:
s=2*sum(m)
for x in range(len(m)-2):
del m[0]
s=s+sum(m)
print(s)
else:
print(str(m[0]))
| Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all... | ```python
line1=int(input())
line2=input().split()
m=[]
for i in line2:
m.append(int(i))
m.sort()
if len(m)>=2:
s=2*sum(m)
for x in range(len(m)-2):
del m[0]
s=s+sum(m)
print(s)
else:
print(str(m[0]))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-... | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,665,229,828 | 2,147,483,647 | Python 3 | OK | TESTS | 65 | 46 | 0 | import math
input1, input2 = input().split()
input1 = int(input1)
input2 = int(input2)
digits = math.floor(math.log(input2, 10)) + 1
if(digits > input1):
print(-1)
else:
print(input2 * pow(10, input1 - digits))
| Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larg... | ```python
import math
input1, input2 = input().split()
input1 = int(input1)
input2 = int(input2)
digits = math.floor(math.log(input2, 10)) + 1
if(digits > input1):
print(-1)
else:
print(input2 * pow(10, input1 - digits))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
372 | A | Counting Kangaroos is Fun | PROGRAMMING | 1,600 | [
"binary search",
"greedy",
"sortings",
"two pointers"
] | null | null | There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as large as the size of kangaroo who is held.
Each kangaroo can hold at most one kangaroo, and the kangaroo who i... | The first line contains a single integer — *n* (1<=≤<=*n*<=≤<=5·105). Each of the next *n* lines contains an integer *s**i* — the size of the *i*-th kangaroo (1<=≤<=*s**i*<=≤<=105). | Output a single integer — the optimal number of visible kangaroos. | [
"8\n2\n5\n7\n6\n9\n8\n4\n2\n",
"8\n9\n1\n6\n2\n6\n5\n8\n3\n"
] | [
"5\n",
"5\n"
] | none | 500 | [
{
"input": "8\n2\n5\n7\n6\n9\n8\n4\n2",
"output": "5"
},
{
"input": "8\n9\n1\n6\n2\n6\n5\n8\n3",
"output": "5"
},
{
"input": "12\n3\n99\n24\n46\n75\n63\n57\n55\n10\n62\n34\n52",
"output": "7"
},
{
"input": "12\n55\n75\n1\n98\n63\n64\n9\n39\n82\n18\n47\n9",
"output": "6"
... | 1,654,602,106 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | import os
import sys
from io import BytesIO, IOBase
def main():
n=int(input())
arr=[]
for _ in range(n):
arr.append(int(input()))
arr.sort()
l,r=0,n
ans=n
def check(m):
if m<((n+1)>>1):
return 0
left=n-m
j=0
for i i... | Title: Counting Kangaroos is Fun
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* kangaroos with pockets. Each kangaroo has a size (integer number). A kangaroo can go into another kangaroo's pocket if and only if the size of kangaroo who hold the kangaroo is at least twice as ... | ```python
import os
import sys
from io import BytesIO, IOBase
def main():
n=int(input())
arr=[]
for _ in range(n):
arr.append(int(input()))
arr.sort()
l,r=0,n
ans=n
def check(m):
if m<((n+1)>>1):
return 0
left=n-m
j=0
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
353 | A | Domino | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the numbers on the upper halves and the sum of the numbers on the lower halves to be even.
To do... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), denoting the number of dominoes Valera has. Next *n* lines contain two space-separated integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=6). Number *x**i* is initially written on the upper half of the *i*-th domino, *y**i* is initially written on the lower half... | Print a single number — the minimum required number of seconds. If Valera can't do the task in any time, print <=-<=1. | [
"2\n4 2\n6 4\n",
"1\n2 3\n",
"3\n1 4\n2 3\n4 4\n"
] | [
"0\n",
"-1\n",
"1\n"
] | In the first test case the sum of the numbers on the upper halves equals 10 and the sum of the numbers on the lower halves equals 6. Both numbers are even, so Valera doesn't required to do anything.
In the second sample Valera has only one piece of domino. It is written 3 on the one of its halves, therefore one of the... | 500 | [
{
"input": "2\n4 2\n6 4",
"output": "0"
},
{
"input": "1\n2 3",
"output": "-1"
},
{
"input": "3\n1 4\n2 3\n4 4",
"output": "1"
},
{
"input": "5\n5 4\n5 4\n1 5\n5 5\n3 3",
"output": "1"
},
{
"input": "20\n1 3\n5 2\n5 2\n2 6\n2 4\n1 1\n1 3\n1 4\n2 6\n4 2\n5 6\n2 2\n... | 1,415,560,942 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 124 | 0 | n = int(input())
s = [0, 0]
change = 0
for i in range(n):
a, b = [int(x) for x in input().split()]
s[0] += a
s[1] += b
if a % 2 and not b % 2:
change = 1
if not a % 2 and b % 2:
change = 1
if s[0] % 2 == 0 and s[1] % 2 == 0:
print(0)
elif s[0] % 2 and s[1] % 2 and change:
print(1)
else:
print(-1)
| Title: Domino
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera has got *n* domino pieces in a row. Each piece consists of two halves — the upper one and the lower one. Each of the halves contains a number from 1 to 6. Valera loves even integers very much, so he wants the sum of the n... | ```python
n = int(input())
s = [0, 0]
change = 0
for i in range(n):
a, b = [int(x) for x in input().split()]
s[0] += a
s[1] += b
if a % 2 and not b % 2:
change = 1
if not a % 2 and b % 2:
change = 1
if s[0] % 2 == 0 and s[1] % 2 == 0:
print(0)
elif s[0] % 2 and s[1] % 2 and change:
print(1)
else:
print(-1)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers ... | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,665,117,221 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | m,n=input("").split()
m=int(m)
n=int(n)
if((m>=1 and m<=n) and n<=16):
result=(m*n)/2
result=int(result)
print(result)
else:
exit | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as p... | ```python
m,n=input("").split()
m=int(m)
n=int(n)
if((m>=1 and m<=n) and n<=16):
result=(m*n)/2
result=int(result)
print(result)
else:
exit
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,651,571,372 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | s=str(input())
l="abcdefghijklmnopqrstuvwxyz"
u="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
a=0;b=0
for i in s:
if i in l:
a+=1
elif i in u:
b+=1
if a==b:
print(s.lower())
else:
print(s.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
s=str(input())
l="abcdefghijklmnopqrstuvwxyz"
u="ABCDEFGHIJKLMNOPQRSTUVWXYZ"
a=0;b=0
for i in s:
if i in l:
a+=1
elif i in u:
b+=1
if a==b:
print(s.lower())
else:
print(s.upper())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
888 | D | Almost Identity Permutations | PROGRAMMING | 1,600 | [
"combinatorics",
"dp",
"math"
] | null | null | A permutation *p* of size *n* is an array such that every integer from 1 to *n* occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least *n*<=-<=*k* indices *i* (1<=≤<=*i*<=≤<=*n*) such that *p**i*<==<=*i*.
Your task is to count the number of almost identity ... | The first line contains two integers *n* and *k* (4<=≤<=*n*<=≤<=1000, 1<=≤<=*k*<=≤<=4). | Print the number of almost identity permutations for given *n* and *k*. | [
"4 1\n",
"4 2\n",
"5 3\n",
"5 4\n"
] | [
"1\n",
"7\n",
"31\n",
"76\n"
] | none | 0 | [
{
"input": "4 1",
"output": "1"
},
{
"input": "4 2",
"output": "7"
},
{
"input": "5 3",
"output": "31"
},
{
"input": "5 4",
"output": "76"
},
{
"input": "200 1",
"output": "1"
},
{
"input": "200 2",
"output": "19901"
},
{
"input": "200 3",
... | 1,644,563,588 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 46 | 0 | #https://en.wikipedia.org/wiki/Derangement
from math import comb
n,k=map(int,input().strip().split())
ans=0
for i in range(k+1):
if i==0:
ans+=1
if i==2:
ans+=comb(n,2)*1
if i==3:
ans+=comb(n,3)*2
if i==4:
ans+=comb(n,4)*9
print(ans)
| Title: Almost Identity Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A permutation *p* of size *n* is an array such that every integer from 1 to *n* occurs exactly once in this array.
Let's call a permutation an almost identity permutation iff there exist at least *n*<=-<=*... | ```python
#https://en.wikipedia.org/wiki/Derangement
from math import comb
n,k=map(int,input().strip().split())
ans=0
for i in range(k+1):
if i==0:
ans+=1
if i==2:
ans+=comb(n,2)*1
if i==3:
ans+=comb(n,3)*2
if i==4:
ans+=comb(n,4)*9
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
1,009 | B | Minimum Ternary String | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecutive) characters '1' and '2' (i.e. replace "12" with "21" or vice versa).
For e... | The first line of the input contains the string $s$ consisting only of characters '0', '1' and '2', its length is between $1$ and $10^5$ (inclusive). | Print a single string — the minimum possible (lexicographically) string you can obtain by using the swaps described above arbitrary number of times (possibly, zero). | [
"100210\n",
"11222121\n",
"20\n"
] | [
"001120\n",
"11112222\n",
"20\n"
] | none | 0 | [
{
"input": "100210",
"output": "001120"
},
{
"input": "11222121",
"output": "11112222"
},
{
"input": "20",
"output": "20"
},
{
"input": "1002",
"output": "0012"
},
{
"input": "10",
"output": "01"
},
{
"input": "000021",
"output": "000012"
},
{
... | 1,551,926,779 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 140 | 409,600 | s = input()
temp1 = ""
temp2 = ""
for x in s:
if x == '0' or x == '2':
temp1 += x
else:
temp2 += x
put = False
for i in range(len(temp1)):
if temp1[i] == '2':
temp1 = temp1[:i] + temp2 + temp1[i:]
put = True
break
if not put:
temp1 = temp1 + temp2
... | Title: Minimum Ternary String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) ... | ```python
s = input()
temp1 = ""
temp2 = ""
for x in s:
if x == '0' or x == '2':
temp1 += x
else:
temp2 += x
put = False
for i in range(len(temp1)):
if temp1[i] == '2':
temp1 = temp1[:i] + temp2 + temp1[i:]
put = True
break
if not put:
temp1 = temp1... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
729 | A | Interview with Oleg | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters. | Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences. | [
"7\naogogob\n",
"13\nogogmgogogogo\n",
"9\nogoogoogo\n"
] | [
"a***b\n",
"***gmg***\n",
"*********\n"
] | The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | 500 | [
{
"input": "7\naogogob",
"output": "a***b"
},
{
"input": "13\nogogmgogogogo",
"output": "***gmg***"
},
{
"input": "9\nogoogoogo",
"output": "*********"
},
{
"input": "32\nabcdefogoghijklmnogoopqrstuvwxyz",
"output": "abcdef***ghijklmn***opqrstuvwxyz"
},
{
"input":... | 1,479,635,036 | 2,336 | Python 3 | WRONG_ANSWER | PRETESTS | 0 | 46 | 0 | s=input();
for n in range(0,100):
s=s.replace('ogo'+n*'go','***');
print(s);
| Title: Interview with Oleg
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a fi... | ```python
s=input();
for n in range(0,100):
s=s.replace('ogo'+n*'go','***');
print(s);
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,607,022,328 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 109 | 0 | s = input()
orig = 'hello'
i = 0
j = 0
l = len(s)
while i<l:
if s[i] == orig[j]:
j = j+1
i = i+1
if(j==5):
break
if j==5:
print('YES')
else:
print('NO')
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = input()
orig = 'hello'
i = 0
j = 0
l = len(s)
while i<l:
if s[i] == orig[j]:
j = j+1
i = i+1
if(j==5):
break
if j==5:
print('YES')
else:
print('NO')
``` | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
701 | B | Cells Not Under Attack | PROGRAMMING | 1,200 | [
"data structures",
"math"
] | null | null | Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=*min*(100<=000,<=*n*2)) — the size of the board and the number of rooks.
Each of the next *m* lines contains integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the number of the row and the number of the col... | Print *m* integer, the *i*-th of them should be equal to the number of cells that are not under attack after first *i* rooks are put. | [
"3 3\n1 1\n3 1\n2 2\n",
"5 2\n1 5\n5 1\n",
"100000 1\n300 400\n"
] | [
"4 2 0 \n",
"16 9 \n",
"9999800001 \n"
] | On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | 750 | [
{
"input": "3 3\n1 1\n3 1\n2 2",
"output": "4 2 0 "
},
{
"input": "5 2\n1 5\n5 1",
"output": "16 9 "
},
{
"input": "100000 1\n300 400",
"output": "9999800001 "
},
{
"input": "10 4\n2 8\n1 8\n9 8\n6 9",
"output": "81 72 63 48 "
},
{
"input": "30 30\n3 13\n27 23\n18... | 1,633,456,331 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 7,065,600 | from collections import defaultdict
n, m = map(int, input().split())
rows = [1] * n
cols = [1] * n
available_rows = n
available_cols = n
res = n ** 2
result = []
for i in range(m):
temp = 1
row, col = map(int, input().split())
if cols[col-1]:
cols[col-1] = 0
temp += (available... | Title: Cells Not Under Attack
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's a... | ```python
from collections import defaultdict
n, m = map(int, input().split())
rows = [1] * n
cols = [1] * n
available_rows = n
available_cols = n
res = n ** 2
result = []
for i in range(m):
temp = 1
row, col = map(int, input().split())
if cols[col-1]:
cols[col-1] = 0
temp += ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
908 | A | New Year and Counting Cards | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a c... | The first and only line of input will contain a string *s* (1<=≤<=|*s*|<=≤<=50), denoting the sides of the cards that you can see on the table currently. Each character of *s* is either a lowercase English letter or a digit. | Print a single integer, the minimum number of cards you must turn over to verify your claim. | [
"ee\n",
"z\n",
"0ay1\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on th... | 500 | [
{
"input": "ee",
"output": "2"
},
{
"input": "z",
"output": "0"
},
{
"input": "0ay1",
"output": "2"
},
{
"input": "0abcdefghijklmnopqrstuvwxyz1234567896",
"output": "10"
},
{
"input": "0a0a9e9e2i2i9o9o6u6u9z9z4x4x9b9b",
"output": "18"
},
{
"input": "01... | 1,602,463,882 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 307,200 | def how_many_flips(statement):
vowel = ['a','e','i','o','u']
digit = ['0','2','4','6','8']
flip = 0
if len(statement) > 50:
return
elif statement == '':
return
for i in statement:
if i in vowel:
flip += 1
elif i in digit:
flip += 1
pri... | Title: New Year and Counting Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each car... | ```python
def how_many_flips(statement):
vowel = ['a','e','i','o','u']
digit = ['0','2','4','6','8']
flip = 0
if len(statement) > 50:
return
elif statement == '':
return
for i in statement:
if i in vowel:
flip += 1
elif i in digit:
flip +=... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
938 | B | Run For Your Prize | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are distinct. You start at position 1, your friend — at position 106 (and there is no prize in any of these tw... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the number of prizes.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (2<=≤<=*a**i*<=≤<=106<=-<=1) — the positions of the prizes. No two prizes are located at the same position. Positions are given in ascending order. | Print one integer — the minimum number of seconds it will take to collect all prizes. | [
"3\n2 3 9\n",
"2\n2 999995\n"
] | [
"8\n",
"5\n"
] | In the first example you take all the prizes: take the first at 1, the second at 2 and the third at 8.
In the second example you take the first prize in 1 second and your friend takes the other in 5 seconds, you do this simultaneously, so the total time is 5. | 0 | [
{
"input": "3\n2 3 9",
"output": "8"
},
{
"input": "2\n2 999995",
"output": "5"
},
{
"input": "1\n20",
"output": "19"
},
{
"input": "6\n2 3 500000 999997 999998 999999",
"output": "499999"
},
{
"input": "1\n999999",
"output": "1"
},
{
"input": "1\n5100... | 1,595,950,814 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 186 | 30,617,600 | n = int(input())
a = list(map(int, input().split()))
p1 = 1
p2 = 10**6
for i in range(len(a)):
if a[i] >= 500000:
p2 = a[i]
break
p1 = a[i]
print(max(p1-1, 10**6 - p2)) | Title: Run For Your Prize
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are di... | ```python
n = int(input())
a = list(map(int, input().split()))
p1 = 1
p2 = 10**6
for i in range(len(a)):
if a[i] >= 500000:
p2 = a[i]
break
p1 = a[i]
print(max(p1-1, 10**6 - p2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
779 | C | Dishonest Sellers | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"sortings"
] | null | null | Igor found out discounts in a shop and decided to buy *n* items. Discounts at the store will last for a week and Igor knows about each item that its price now is *a**i*, and after a week of discounts its price will be *b**i*.
Not all of sellers are honest, so now some products could be more expensive than after a week... | In the first line there are two positive integer numbers *n* and *k* (1<=≤<=*n*<=≤<=2·105, 0<=≤<=*k*<=≤<=*n*) — total number of items to buy and minimal number of items Igor wants to by right now.
The second line contains sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) — prices of items during d... | Print the minimal amount of money Igor will spend to buy all *n* items. Remember, he should buy at least *k* items right now. | [
"3 1\n5 4 6\n3 1 5\n",
"5 3\n3 4 7 10 3\n4 5 5 12 5\n"
] | [
"10\n",
"25\n"
] | In the first example Igor should buy item 3 paying 6. But items 1 and 2 he should buy after a week. He will pay 3 and 1 for them. So in total he will pay 6 + 3 + 1 = 10.
In the second example Igor should buy right now items 1, 2, 4 and 5, paying for them 3, 4, 10 and 3, respectively. Item 3 he should buy after a week ... | 1,000 | [
{
"input": "3 1\n5 4 6\n3 1 5",
"output": "10"
},
{
"input": "5 3\n3 4 7 10 3\n4 5 5 12 5",
"output": "25"
},
{
"input": "1 0\n9\n8",
"output": "8"
},
{
"input": "2 0\n4 10\n1 2",
"output": "3"
},
{
"input": "4 2\n19 5 17 13\n3 18 8 10",
"output": "29"
},
... | 1,489,257,894 | 2,147,483,647 | Python 3 | OK | TESTS | 67 | 530 | 29,081,600 | n , k = list(map(int,input().split()))
a = list(map(int,input().split()))
b = list(map(int,input().split()))
for i in range(n):
b[i]-=a[i]
c = list(zip(a,b))
c = sorted(c,key = lambda x:-x[1])
ans = 0
z = 0
for i in range(n):
if c[i][1]>=0 or z<k:
ans+=c[i][0]
z+=1
else :
... | Title: Dishonest Sellers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor found out discounts in a shop and decided to buy *n* items. Discounts at the store will last for a week and Igor knows about each item that its price now is *a**i*, and after a week of discounts its price will be... | ```python
n , k = list(map(int,input().split()))
a = list(map(int,input().split()))
b = list(map(int,input().split()))
for i in range(n):
b[i]-=a[i]
c = list(zip(a,b))
c = sorted(c,key = lambda x:-x[1])
ans = 0
z = 0
for i in range(n):
if c[i][1]>=0 or z<k:
ans+=c[i][0]
z+=1
e... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,698,134,462 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 108 | 13,619,200 | n=int(input())
servetime=sorted(list(map(int,input().split())))
waittime,cnt=0,n
for i in range(n):
if servetime[i]>=waittime:
waittime+=servetime[i]
else:
cnt-=1
print(cnt) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time... | ```python
n=int(input())
servetime=sorted(list(map(int,input().split())))
waittime,cnt=0,n
for i in range(n):
if servetime[i]>=waittime:
waittime+=servetime[i]
else:
cnt-=1
print(cnt)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
445 | A | DZY Loves Chessboard | PROGRAMMING | 1,200 | [
"dfs and similar",
"implementation"
] | null | null | DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with th... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a ... | Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell.
If multiple answers exist, print any of them. It ... | [
"1 1\n.\n",
"2 2\n..\n..\n",
"3 3\n.-.\n---\n--."
] | [
"B\n",
"BW\nWB\n",
"B-B\n---\n--B"
] | In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK.
In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output.
In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are. | 500 | [
{
"input": "1 1\n.",
"output": "B"
},
{
"input": "2 2\n..\n..",
"output": "BW\nWB"
},
{
"input": "3 3\n.-.\n---\n--.",
"output": "B-B\n---\n--B"
},
{
"input": "3 1\n-\n.\n.",
"output": "-\nW\nB"
},
{
"input": "11 11\n-----------\n-----------\n-----------\n--------... | 1,628,557,889 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 62 | 6,758,400 | n, m = map(int, input().split())
for i in range(n):
a, b = input(), ''
for j in range(m):
b += a[j] if a[j] == '-' else 'BW'[(i+j)%2]
print(b) | Title: DZY Loves Chessboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. ... | ```python
n, m = map(int, input().split())
for i in range(n):
a, b = input(), ''
for j in range(m):
b += a[j] if a[j] == '-' else 'BW'[(i+j)%2]
print(b)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
12 | A | Super Agent | PROGRAMMING | 800 | [
"implementation"
] | A. Super Agent | 2 | 256 | There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparing special agent Pearlo for many years. When, finally, Pearlo learned all secrets of espionage... | Input contains the matrix of three rows of three symbols each. Symbol «X» means that the corresponding button was pressed, and «.» means that is was not pressed. The matrix may contain no «X», also it may contain no «.». | Print YES if the password is symmetric with respect to the central button of the terminal and NO otherwise. | [
"XX.\n...\n.XX\n",
"X.X\nX..\n...\n"
] | [
"YES\n",
"NO\n"
] | If you are not familiar with the term «central symmetry», you may look into http://en.wikipedia.org/wiki/Central_symmetry | 0 | [
{
"input": "XX.\n...\n.XX",
"output": "YES"
},
{
"input": ".X.\n.X.\n.X.",
"output": "YES"
},
{
"input": "XXX\nXXX\nXXX",
"output": "YES"
},
{
"input": "XXX\nX.X\nXXX",
"output": "YES"
},
{
"input": "X..\n.X.\n..X",
"output": "YES"
},
{
"input": "...\n... | 1,680,513,586 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | # LUOGU_RID: 106850714
s=raw_input()+raw_input()+raw_input()
for i in range(5):
if s[i]!=s[8-i]:
print 'NO';exit()
print 'YES' | Title: Super Agent
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a very secret base in Potatoland where potato mash is made according to a special recipe. The neighbours from Porridgia decided to seize this recipe and to sell it to Pilauland. For this mission they have been preparin... | ```python
# LUOGU_RID: 106850714
s=raw_input()+raw_input()+raw_input()
for i in range(5):
if s[i]!=s[8-i]:
print 'NO';exit()
print 'YES'
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
909 | A | Generate Login | PROGRAMMING | 1,000 | [
"brute force",
"greedy",
"sortings"
] | null | null | The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the full name. Typically there are multiple possible logins for each person.
You are given the first and ... | The input consists of a single line containing two space-separated strings: the first and the last names. Each character of each string is a lowercase English letter. The length of each string is between 1 and 10, inclusive. | Output a single string — alphabetically earliest possible login formed from these names. The output should be given in lowercase as well. | [
"harry potter\n",
"tom riddle\n"
] | [
"hap\n",
"tomr\n"
] | none | 500 | [
{
"input": "harry potter",
"output": "hap"
},
{
"input": "tom riddle",
"output": "tomr"
},
{
"input": "a qdpinbmcrf",
"output": "aq"
},
{
"input": "wixjzniiub ssdfodfgap",
"output": "wis"
},
{
"input": "z z",
"output": "zz"
},
{
"input": "ertuyivhfg v"... | 1,517,028,809 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 62 | 5,632,000 | first, last = input().split()
i = 1
while i<len(first) and first[i]<last[0]:
i += 1
print(first[:i]+last[0]) | Title: Generate Login
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the fu... | ```python
first, last = input().split()
i = 1
while i<len(first) and first[i]<last[0]:
i += 1
print(first[:i]+last[0])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,661,588,093 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 46 | 13,004,800 | n,m=int(input()),int(input())
print(m%(1<<n)) | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
n,m=int(input()),int(input())
print(m%(1<<n))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
177 | A2 | Good Matrix Elements | PROGRAMMING | 800 | [
"implementation"
] | null | null | The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the main diagonal. - Elements of the secondary diagonal. - Elements of the "middle" row — the row which ha... | The first line of input data contains a single odd integer *n*. Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=100) separated by single spaces — the elements of the given matrix.
The input limitations for getting 30 points are:
- 1<=≤<=*n*<=≤<=5
The input limitations for getting 100 po... | Print a single integer — the sum of good matrix elements. | [
"3\n1 2 3\n4 5 6\n7 8 9\n",
"5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n"
] | [
"45\n",
"17\n"
] | In the first sample all matrix elements will be good. Good elements in the second sample are shown on the figure. | 70 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "45"
},
{
"input": "5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1",
"output": "17"
},
{
"input": "1\n3",
"output": "3"
},
{
"input": "5\n27 7 3 11 72\n19 49 68 19 59\n41 25 37 64 65\n8 39 96 62 90\n13 37 43 26 33",
... | 1,687,794,295 | 2,147,483,647 | Python 3 | OK | TESTS2 | 33 | 92 | 204,800 | n = int(input())
lst = []
count = 0
for item in range(n):
lst.append(list(map(int, input().split())))
for i in range(n):
for u in range(n):
if i == u or u ==(n-1-i) or (n-1)//2 == i or u == (n-1)//2:
count += lst[i][u]
print(count)
| Title: Good Matrix Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the ... | ```python
n = int(input())
lst = []
count = 0
for item in range(n):
lst.append(list(map(int, input().split())))
for i in range(n):
for u in range(n):
if i == u or u ==(n-1-i) or (n-1)//2 == i or u == (n-1)//2:
count += lst[i][u]
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
919 | A | Supermarket | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation"
] | null | null | We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (You don't need to care about what "yuan" is), the same as $a/b$ yuan for a kilo.
Now imagine you'd... | The first line contains two positive integers $n$ and $m$ ($1 \leq n \leq 5\,000$, $1 \leq m \leq 100$), denoting that there are $n$ supermarkets and you want to buy $m$ kilos of apples.
The following $n$ lines describe the information of the supermarkets. Each line contains two positive integers $a, b$ ($1 \leq a, b ... | The only line, denoting the minimum cost for $m$ kilos of apples. Please make sure that the absolute or relative error between your answer and the correct answer won't exceed $10^{-6}$.
Formally, let your answer be $x$, and the jury's answer be $y$. Your answer is considered correct if $\frac{|x - y|}{\max{(1, |y|)}} ... | [
"3 5\n1 2\n3 4\n1 3\n",
"2 1\n99 100\n98 99\n"
] | [
"1.66666667\n",
"0.98989899\n"
] | In the first sample, you are supposed to buy $5$ kilos of apples in supermarket $3$. The cost is $5/3$ yuan.
In the second sample, you are supposed to buy $1$ kilo of apples in supermarket $2$. The cost is $98/99$ yuan. | 500 | [
{
"input": "3 5\n1 2\n3 4\n1 3",
"output": "1.66666667"
},
{
"input": "2 1\n99 100\n98 99",
"output": "0.98989899"
},
{
"input": "50 37\n78 49\n96 4\n86 62\n28 4\n19 2\n79 43\n79 92\n95 35\n33 60\n54 84\n90 25\n2 25\n53 21\n86 52\n72 25\n6 78\n41 46\n3 68\n42 89\n33 35\n57 43\n99 45\n1 8... | 1,650,001,183 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | t = int(input())
while(t>0):
n,m = map(int,input().split())
ans = 100000000
while(n>0):
a,b = map(float,input().split())
val = float(a/b)
val2 = float(m*val)
ans = min(val2,ans)
n = n-1
print(ans)
t = t-1 | Title: Supermarket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (Yo... | ```python
t = int(input())
while(t>0):
n,m = map(int,input().split())
ans = 100000000
while(n>0):
a,b = map(float,input().split())
val = float(a/b)
val2 = float(m*val)
ans = min(val2,ans)
n = n-1
print(ans)
t = t-1
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
985 | B | Switches and Lamps | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | You are given *n* switches and *m* lamps. The *i*-th switch turns on some subset of the lamps. This information is given as the matrix *a* consisting of *n* rows and *m* columns where *a**i*,<=*j*<==<=1 if the *i*-th switch turns on the *j*-th lamp and *a**i*,<=*j*<==<=0 if the *i*-th switch is not connected to the *j*... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2000) — the number of the switches and the number of the lamps.
The following *n* lines contain *m* characters each. The character *a**i*,<=*j* is equal to '1' if the *i*-th switch turns on the *j*-th lamp and '0' otherwise.
It is guar... | Print "YES" if there is a switch that if you will ignore it and press all the other *n*<=-<=1 switches then all *m* lamps will be turned on. Print "NO" if there is no such switch. | [
"4 5\n10101\n01000\n00111\n10000\n",
"4 5\n10100\n01000\n00110\n00101\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "4 5\n10101\n01000\n00111\n10000",
"output": "YES"
},
{
"input": "4 5\n10100\n01000\n00110\n00101",
"output": "NO"
},
{
"input": "1 5\n11111",
"output": "NO"
},
{
"input": "10 1\n1\n0\n0\n0\n0\n0\n0\n0\n0\n1",
"output": "YES"
},
{
"input": "1 1\n1",
... | 1,526,919,567 | 5,667 | Python 3 | WRONG_ANSWER | TESTS | 11 | 2,823 | 5,734,400 | n, m = map(int,input().split())
buls = [True]*n
mat = [""]*m
for i in range(n):
s = input()
for j in range(m):
mat[j] += s[j]
# print(mat)
for i in range(m):
if (sum(int(z) for z in mat[i])):
buls[mat[i].find('1')] = False
print("YES" if sum(buls) else "NO") | Title: Switches and Lamps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given *n* switches and *m* lamps. The *i*-th switch turns on some subset of the lamps. This information is given as the matrix *a* consisting of *n* rows and *m* columns where *a**i*,<=*j*<==<=1 if the *i*-th... | ```python
n, m = map(int,input().split())
buls = [True]*n
mat = [""]*m
for i in range(n):
s = input()
for j in range(m):
mat[j] += s[j]
# print(mat)
for i in range(m):
if (sum(int(z) for z in mat[i])):
buls[mat[i].find('1')] = False
print("YES" if sum(buls) else "NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
185 | A | Plant | PROGRAMMING | 1,300 | [
"math"
] | null | null | Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will point "upwards" and one will point "downwards". After another year, each triangle plant divide... | The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1018) — the number of full years when the plant grew.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | Print a single integer — the remainder of dividing the number of plants that will point "upwards" in *n* years by 1000000007 (109<=+<=7). | [
"1\n",
"2\n"
] | [
"3\n",
"10\n"
] | The first test sample corresponds to the second triangle on the figure in the statement. The second test sample corresponds to the third one. | 500 | [
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "10"
},
{
"input": "385599124",
"output": "493875375"
},
{
"input": "989464295",
"output": "31966163"
},
{
"input": "376367012",
"output": "523204186"
},
{
"input": "529357306",
"output": "... | 1,601,447,852 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 280 | 819,200 | from collections import Counter
import string
import math
import sys
sys.setrecursionlimit(10**6)
def array_int():
return [int(i) for i in sys.stdin.readline().split()]
def vary(number_of_variables):
if number_of_variables==1:
return int(sys.stdin.readline())
if number_of_variables>=2:
... | Title: Plant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will poi... | ```python
from collections import Counter
import string
import math
import sys
sys.setrecursionlimit(10**6)
def array_int():
return [int(i) for i in sys.stdin.readline().split()]
def vary(number_of_variables):
if number_of_variables==1:
return int(sys.stdin.readline())
if number_of_variab... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
157 | B | Trace | PROGRAMMING | 1,000 | [
"geometry",
"sortings"
] | null | null | One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall into several parts. Some parts were painted red and all the other were painted blue. Besides,... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=100). The second line contains *n* space-separated integers *r**i* (1<=≤<=*r**i*<=≤<=1000) — the circles' radii. It is guaranteed that all circles are different. | Print the single real number — total area of the part of the wall that is painted red. The answer is accepted if absolute or relative error doesn't exceed 10<=-<=4. | [
"1\n1\n",
"3\n1 4 2\n"
] | [
"3.1415926536\n",
"40.8407044967\n"
] | In the first sample the picture is just one circle of radius 1. Inner part of the circle is painted red. The area of the red part equals π × 1<sup class="upper-index">2</sup> = π.
In the second sample there are three circles of radii 1, 4 and 2. Outside part of the second circle is painted blue. Part between the secon... | 1,000 | [
{
"input": "1\n1",
"output": "3.1415926536"
},
{
"input": "3\n1 4 2",
"output": "40.8407044967"
},
{
"input": "4\n4 1 3 2",
"output": "31.4159265359"
},
{
"input": "4\n100 10 2 1",
"output": "31111.1920484997"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output"... | 1,608,880,984 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 218 | 307,200 | #from collections import Counter
import math
pi = math.pi
n = int(input())
arr = list(map(int, input().split()))
arr.sort(reverse=True)
i = 0
area = 0
while i<len(arr):
if i+1<len(arr):
area += pi*(arr[i]**2-arr[i+1]**2)
else:
area += pi*(arr[i]**2)
i +... | Title: Trace
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, as Sherlock Holmes was tracking down one very important criminal, he found a wonderful painting on the wall. This wall could be represented as a plane. The painting had several concentric circles that divided the wall in... | ```python
#from collections import Counter
import math
pi = math.pi
n = int(input())
arr = list(map(int, input().split()))
arr.sort(reverse=True)
i = 0
area = 0
while i<len(arr):
if i+1<len(arr):
area += pi*(arr[i]**2-arr[i+1]**2)
else:
area += pi*(arr[i]**2)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
375 | A | Divisible by Seven | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.
Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resu... | The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 106 characters. | Print a number in the decimal notation without leading zeroes — the result of the permutation.
If it is impossible to rearrange the digits of the number *a* in the required manner, print 0. | [
"1689\n",
"18906\n"
] | [
"1869\n",
"18690\n"
] | none | 500 | [
{
"input": "1689",
"output": "1869"
},
{
"input": "18906",
"output": "18690"
},
{
"input": "2419323689",
"output": "2432391689"
},
{
"input": "8589157262",
"output": "5857221986"
},
{
"input": "2717172350336955863014903670481525170997949309274087058935108848979319... | 1,588,085,489 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 409,600 | from random import randint
from itertools import permutations
n = input()
cnt = [0]*(10)
p = permutations('1689')
x=''
for i in list(p):
x = ''.join(i)
print(str(v)+x+str(0)) | Title: Divisible by Seven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.
Number *a* doesn't ... | ```python
from random import randint
from itertools import permutations
n = input()
cnt = [0]*(10)
p = permutations('1689')
x=''
for i in list(p):
x = ''.join(i)
print(str(v)+x+str(0))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,687,842,560 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 202 | 0 | n = int(input())
res = 0
for i in range(n):
s = input()
if(s=='Tetrahedron'):
res += 4
elif(s=='Cube'):
res += 6
elif(s=='Octahedron'):
res += 8
elif(s=='Dodecahedron'):
res += 12
else:
res += 20
print(res)
| Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
n = int(input())
res = 0
for i in range(n):
s = input()
if(s=='Tetrahedron'):
res += 4
elif(s=='Cube'):
res += 6
elif(s=='Octahedron'):
res += 8
elif(s=='Dodecahedron'):
res += 12
else:
res += 20
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
459 | B | Pashmak and Flowers | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation",
"sortings"
] | null | null | Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty diff... | The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109). | The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively. | [
"2\n1 2\n",
"3\n1 4 5\n",
"5\n3 1 2 3 1\n"
] | [
"1 1",
"4 1",
"2 4"
] | In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | 500 | [
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "3\n1 4 5",
"output": "4 1"
},
{
"input": "5\n3 1 2 3 1",
"output": "2 4"
},
{
"input": "2\n1 1",
"output": "0 1"
},
{
"input": "3\n1 1 1",
"output": "0 3"
},
{
"input": "4\n1 1 1 1",
"output": "0 ... | 1,668,886,465 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n=int(input())
beauty=list(map(int,input().split()))
ma={}
beauty.sort()
for i in range(n):
j=n-1-i
ma[(abs(beauty[j]-beauty[i]))]=1+ma.get((abs(beauty[j]-beauty[i])),0)
j+=1
print(max(ma.keys()), max(ma.values())) | Title: Pashmak and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have th... | ```python
n=int(input())
beauty=list(map(int,input().split()))
ma={}
beauty.sort()
for i in range(n):
j=n-1-i
ma[(abs(beauty[j]-beauty[i]))]=1+ma.get((abs(beauty[j]-beauty[i])),0)
j+=1
print(max(ma.keys()), max(ma.values()))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,567,316,144 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 248 | 0 | s=input()
u='aeiouyAEIOUY'
s=s.replace(' ','')
if s[-2]!=' ' and s[-2] in u:
print('YES')
else:
print('NO') | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
s=input()
u='aeiouyAEIOUY'
s=s.replace(' ','')
if s[-2]!=' ' and s[-2] in u:
print('YES')
else:
print('NO')
``` | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
991 | A | If at first you don't succeed... | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Each student eagerly awaits the day he would pass the exams successfully. Thus, Vasya was ready to celebrate, but, alas, he didn't pass it. However, many of Vasya's fellow students from the same group were more successful and celebrated after the exam.
Some of them celebrated in the BugDonalds restaurant, some of them... | The first line contains four integers — $A$, $B$, $C$ and $N$ ($0 \leq A, B, C, N \leq 100$). | If a distribution of $N$ students exists in which $A$ students visited BugDonalds, $B$ — BeaverKing, $C$ — both of the restaurants and at least one student is left home (it is known that Vasya didn't pass the exam and stayed at home), output one integer — amount of students (including Vasya) who did not pass the exam. ... | [
"10 10 5 20\n",
"2 2 0 4\n",
"2 2 2 1\n"
] | [
"5",
"-1",
"-1"
] | The first sample describes following situation: $5$ only visited BugDonalds, $5$ students only visited BeaverKing, $5$ visited both of them and $5$ students (including Vasya) didn't pass the exam.
In the second sample $2$ students only visited BugDonalds and $2$ only visited BeaverKing, but that means all $4$ students... | 500 | [
{
"input": "10 10 5 20",
"output": "5"
},
{
"input": "2 2 0 4",
"output": "-1"
},
{
"input": "2 2 2 1",
"output": "-1"
},
{
"input": "98 98 97 100",
"output": "1"
},
{
"input": "1 5 2 10",
"output": "-1"
},
{
"input": "5 1 2 10",
"output": "-1"
}... | 1,681,945,798 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 61 | 0 | a, b, c, n = map(int, input().split())
a -= c
b -= c
if a + b + c + 1 > n or a < 0 or b < 0:
print(-1)
else:
print(n - a - b - c)
| Title: If at first you don't succeed...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each student eagerly awaits the day he would pass the exams successfully. Thus, Vasya was ready to celebrate, but, alas, he didn't pass it. However, many of Vasya's fellow students from the same group w... | ```python
a, b, c, n = map(int, input().split())
a -= c
b -= c
if a + b + c + 1 > n or a < 0 or b < 0:
print(-1)
else:
print(n - a - b - c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,680,446,596 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 62 | 0 | a,b=map(int,input().split())
c=240-b
i=0
while i<=a:
if c-(5*(i+1))>=0:
i+=1
c-=5*i
continue
else:
break
print(i) if i<a else print(a) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
a,b=map(int,input().split())
c=240-b
i=0
while i<=a:
if c-(5*(i+1))>=0:
i+=1
c-=5*i
continue
else:
break
print(i) if i<a else print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
607 | A | Chain Reaction | PROGRAMMING | 1,600 | [
"binary search",
"dp"
] | null | null | There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of decreasing coordinates) within distance *b**i* inclusive. The beacon itself is not destroyed however.... | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the initial number of beacons.
The *i*-th of next *n* lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=1<=000<=000, 1<=≤<=*b**i*<=≤<=1<=000<=000) — the position and power level of the *i*-th beacon respectively. No two beac... | Print a single integer — the minimum number of beacons that could be destroyed if exactly one beacon is added. | [
"4\n1 9\n3 1\n6 1\n7 4\n",
"7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1\n"
] | [
"1\n",
"3\n"
] | For the first sample case, the minimum number of beacons destroyed is 1. One way to achieve this is to place a beacon at position 9 with power level 2.
For the second sample case, the minimum number of beacons destroyed is 3. One way to achieve this is to place a beacon at position 1337 with power level 42. | 500 | [
{
"input": "4\n1 9\n3 1\n6 1\n7 4",
"output": "1"
},
{
"input": "7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1",
"output": "3"
},
{
"input": "1\n0 1",
"output": "0"
},
{
"input": "1\n0 1000000",
"output": "0"
},
{
"input": "1\n1000000 1000000",
"output": "0"
},
{
... | 1,451,661,011 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 78 | 0 | import sys
n = int(input())
a = [0]*n
b = [0]*n
f = [0]*n
for i in range(0, n):
inp = input().split()
a[i], b[i] = int(inp[0]), int(inp[1])
best = n
left = 0
for i in range(0,n):
while a[i]-b[i]>a[left+1]:
left+=1
f[i] = f[left] + i-left-1
best = min(best, n-i + f[i])
... | Title: Chain Reaction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of d... | ```python
import sys
n = int(input())
a = [0]*n
b = [0]*n
f = [0]*n
for i in range(0, n):
inp = input().split()
a[i], b[i] = int(inp[0]), int(inp[1])
best = n
left = 0
for i in range(0,n):
while a[i]-b[i]>a[left+1]:
left+=1
f[i] = f[left] + i-left-1
best = min(best, n-i +... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
895 | B | XK Segments | PROGRAMMING | 1,700 | [
"binary search",
"math",
"sortings",
"two pointers"
] | null | null | While Vasya finished eating his piece of pizza, the lesson has already started. For being late for the lesson, the teacher suggested Vasya to solve one interesting problem. Vasya has an array *a* and integer *x*. He should find the number of different ordered pairs of indexes (*i*,<=*j*) such that *a**i*<=≤<=*a**j* and... | The first line contains 3 integers *n*,<=*x*,<=*k* (1<=≤<=*n*<=≤<=105,<=1<=≤<=*x*<=≤<=109,<=0<=≤<=*k*<=≤<=109), where *n* is the size of the array *a* and *x* and *k* are numbers from the statement.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | Print one integer — the answer to the problem. | [
"4 2 1\n1 3 5 7\n",
"4 2 0\n5 3 1 7\n",
"5 3 1\n3 3 3 3 3\n"
] | [
"3\n",
"4\n",
"25\n"
] | In first sample there are only three suitable pairs of indexes — (1, 2), (2, 3), (3, 4).
In second sample there are four suitable pairs of indexes(1, 1), (2, 2), (3, 3), (4, 4).
In third sample every pair (*i*, *j*) is suitable, so the answer is 5 * 5 = 25. | 1,000 | [
{
"input": "4 2 1\n1 3 5 7",
"output": "3"
},
{
"input": "4 2 0\n5 3 1 7",
"output": "4"
},
{
"input": "5 3 1\n3 3 3 3 3",
"output": "25"
},
{
"input": "5 3 4\n24 13 1 24 24",
"output": "4"
},
{
"input": "4 2 2\n1 3 5 7",
"output": "2"
},
{
"input": "5... | 1,511,716,508 | 4,208 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 13 | 1,000 | 7,372,800 | import sys
data = sys.stdin.readlines()
n, x, k = (int(i) for i in data[0].split())
a = [int(i) for i in data[1].split()]
count = 0
def getC(o,p):
res = 0
for i in range(o,p+1):
if i % x == 0:
res += 1
return res
for i in range(n):
for j in range(n):
... | Title: XK Segments
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While Vasya finished eating his piece of pizza, the lesson has already started. For being late for the lesson, the teacher suggested Vasya to solve one interesting problem. Vasya has an array *a* and integer *x*. He should ... | ```python
import sys
data = sys.stdin.readlines()
n, x, k = (int(i) for i in data[0].split())
a = [int(i) for i in data[1].split()]
count = 0
def getC(o,p):
res = 0
for i in range(o,p+1):
if i % x == 0:
res += 1
return res
for i in range(n):
for j in ran... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
708 | A | Letters Cyclic Shift | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation",
"strings"
] | null | null | You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each character is replaced with the previous character of English alphabet and 'a' is replaced with 'z'.
What is ... | The only line of the input contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) consisting of lowercase English letters. | Print the lexicographically minimum string that can be obtained from *s* by shifting letters of exactly one non-empty substring. | [
"codeforces\n",
"abacaba\n"
] | [
"bncdenqbdr\n",
"aaacaba\n"
] | String *s* is lexicographically smaller than some other string *t* of the same length if there exists some 1 ≤ *i* ≤ |*s*|, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, *s*<sub class="lower-index">2</sub> = *t*<sub class="lower-index">2</sub>, ..., *s*<sub class="lower-index">*i*... | 500 | [
{
"input": "codeforces",
"output": "bncdenqbdr"
},
{
"input": "abacaba",
"output": "aaacaba"
},
{
"input": "babbbabaababbaa",
"output": "aabbbabaababbaa"
},
{
"input": "bcbacaabcababaccccaaaabacbbcbbaa",
"output": "abaacaabcababaccccaaaabacbbcbbaa"
},
{
"input": "... | 1,606,291,199 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 171 | 409,600 | s=input()
if len(s)==s.count("a"):
r=s[:-1]
r+="z"
print(r)
else:
b=0
for i in range(len(s)):
if s[i]!="a":
b=i
break
r=""
r+=s[:b]
for i in range(b,len(s)):
if s[i]=="a":
y="z"
else:
x=ord(s[i])... | Title: Letters Cyclic Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each cha... | ```python
s=input()
if len(s)==s.count("a"):
r=s[:-1]
r+="z"
print(r)
else:
b=0
for i in range(len(s)):
if s[i]!="a":
b=i
break
r=""
r+=s[:b]
for i in range(b,len(s)):
if s[i]=="a":
y="z"
else:
x... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,649,931,346 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 46 | 0 | a = input()
b = input()
c = len(a)
d = list()
f = str()
for i in range(c):
if a[i] == '0' and b[i] == '0':
d.append('0')
elif a[i] == '1' and b[i] == '1':
d.append('0')
else:
d.append('1')
e = len(d)
for i in range(e):
f += d[i]
print(f)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
a = input()
b = input()
c = len(a)
d = list()
f = str()
for i in range(c):
if a[i] == '0' and b[i] == '0':
d.append('0')
elif a[i] == '1' and b[i] == '1':
d.append('0')
else:
d.append('1')
e = len(d)
for i in range(e):
f += d[i]
print(f)
``` | 3.9885 | MatrixStudio/Codeforces-Python-Submissions |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,618,263,583 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 45,977,600 | n=int(input())
m=int(input())
if n>=1 and n<=10**8 and m>=1 and m<=10**8:
print(m%2**n)
else:
print('error') | Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
n=int(input())
m=int(input())
if n>=1 and n<=10**8 and m>=1 and m<=10**8:
print(m%2**n)
else:
print('error')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,687,146,313 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | n=int(input())
passengers=[0]
for i in range(n):
a,b=map(int,input().split())
passengers.append(passengers[i]-a+b)
print(max(passengers))
| Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
n=int(input())
passengers=[0]
for i in range(n):
a,b=map(int,input().split())
passengers.append(passengers[i]-a+b)
print(max(passengers))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
363 | B | Fence | PROGRAMMING | 1,100 | [
"brute force",
"dp"
] | null | null | There is a fence in front of Polycarpus's home. The fence consists of *n* planks of the same width which go one after another from left to right. The height of the *i*-th plank is *h**i* meters, distinct planks can have distinct heights.
Polycarpus has bought a posh piano and is thinking about how to get it into the h... | The first line of the input contains integers *n* and *k* (1<=≤<=*n*<=≤<=1.5·105,<=1<=≤<=*k*<=≤<=*n*) — the number of planks in the fence and the width of the hole for the piano. The second line contains the sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=100), where *h**i* is the height of the *i*-th... | Print such integer *j* that the sum of the heights of planks *j*, *j*<=+<=1, ..., *j*<=+<=*k*<=-<=1 is the minimum possible. If there are multiple such *j*'s, print any of them. | [
"7 3\n1 2 6 1 1 7 1\n"
] | [
"3\n"
] | In the sample, your task is to find three consecutive planks with the minimum sum of heights. In the given case three planks with indexes 3, 4 and 5 have the required attribute, their total height is 8. | 1,000 | [
{
"input": "7 3\n1 2 6 1 1 7 1",
"output": "3"
},
{
"input": "1 1\n100",
"output": "1"
},
{
"input": "2 1\n10 20",
"output": "1"
},
{
"input": "10 5\n1 2 3 1 2 2 3 1 4 5",
"output": "1"
},
{
"input": "10 2\n3 1 4 1 4 6 2 1 4 6",
"output": "7"
},
{
"inp... | 1,692,090,858 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | n,k=map(int,input().split())
a=map(int,input().split())
a=list(a)
f=-1
ind=0
for i in range(n-k):
temp =sum(a[i:i+k])
if f>temp or f<0:
f=temp
ind=i
if n==k:
print(1)
else:
print(i) | Title: Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a fence in front of Polycarpus's home. The fence consists of *n* planks of the same width which go one after another from left to right. The height of the *i*-th plank is *h**i* meters, distinct planks can have distinct ... | ```python
n,k=map(int,input().split())
a=map(int,input().split())
a=list(a)
f=-1
ind=0
for i in range(n-k):
temp =sum(a[i:i+k])
if f>temp or f<0:
f=temp
ind=i
if n==k:
print(1)
else:
print(i)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,673,849,777 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 310 | 2,252,800 |
(y,k,n)=(input().split(" "))
y=int(y)
k=int(k)
n=int(n)
# (x+y)<=n
# x
# (x+y)%k==0
# (x+y)/k =1
# x+y= k
# x= k-y
# print(y,n,k)
a=[]
a.append(k-y)
# print(a[0])
x=a[0]
res=""
while (x+y)<=n:
if x>0:
res+= str(x)+" "
x+=k
if res =="":
print(-1)
else:
print(re... | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
(y,k,n)=(input().split(" "))
y=int(y)
k=int(k)
n=int(n)
# (x+y)<=n
# x
# (x+y)%k==0
# (x+y)/k =1
# x+y= k
# x= k-y
# print(y,n,k)
a=[]
a.append(k-y)
# print(a[0])
x=a[0]
res=""
while (x+y)<=n:
if x>0:
res+= str(x)+" "
x+=k
if res =="":
print(-1)
else:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
275 | A | Lights Out | PROGRAMMING | 900 | [
"implementation"
] | null | null | Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the lights off. We consider the toggling as follows: if the light was switched on then it will be sw... | The input consists of three rows. Each row contains three integers each between 0 to 100 inclusive. The *j*-th number in the *i*-th row is the number of times the *j*-th light of the *i*-th row of the grid is pressed. | Print three lines, each containing three characters. The *j*-th character of the *i*-th line is "1" if and only if the corresponding light is switched on, otherwise it's "0". | [
"1 0 0\n0 0 0\n0 0 1\n",
"1 0 1\n8 8 8\n2 0 3\n"
] | [
"001\n010\n100\n",
"010\n011\n100\n"
] | none | 500 | [
{
"input": "1 0 0\n0 0 0\n0 0 1",
"output": "001\n010\n100"
},
{
"input": "1 0 1\n8 8 8\n2 0 3",
"output": "010\n011\n100"
},
{
"input": "13 85 77\n25 50 45\n65 79 9",
"output": "000\n010\n000"
},
{
"input": "96 95 5\n8 84 74\n67 31 61",
"output": "011\n011\n101"
},
{... | 1,588,742,140 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 108 | 0 | def flip(i,j):
if arr[i][j]==1:
arr[i][j]=0
else:
arr[i][j]=1
global arr
arr=[]
for n in range(3):
a,b,c=1,1,1
arr.append([a,b,c])
myarray=[]
for i in range(3):
temp=[int(x)%2 for x in input().split()]
myarray.append(temp)
for i in range(len(myarra... | Title: Lights Out
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lenny is playing a game on a 3<=×<=3 grid of lights. In the beginning of the game all lights are switched on. Pressing any of the lights will toggle it and all side-adjacent lights. The goal of the game is to switch all the ... | ```python
def flip(i,j):
if arr[i][j]==1:
arr[i][j]=0
else:
arr[i][j]=1
global arr
arr=[]
for n in range(3):
a,b,c=1,1,1
arr.append([a,b,c])
myarray=[]
for i in range(3):
temp=[int(x)%2 for x in input().split()]
myarray.append(temp)
for i in range(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
929 | B | Места в самолёте | PROGRAMMING | 1,300 | [
"*special",
"implementation"
] | null | null | В самолёте есть *n* рядов мест. Если смотреть на ряды сверху, то в каждом ряду есть 3 места слева, затем проход между рядами, затем 4 центральных места, затем ещё один проход между рядами, а затем ещё 3 места справа.
Известно, что некоторые места уже заняты пассажирами. Всего есть два вида пассажиров — статусные (те, ... | В первой строке следуют два целых числа *n* и *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=10·*n*) — количество рядов мест в самолёте и количество пассажиров, которых нужно рассадить.
Далее следует описание рядов мест самолёта по одному ряду в строке. Если очередной символ равен '-', то это проход между рядами. Если очередно... | В первую строку выведите минимальное суммарное число соседей у статусных пассажиров.
Далее выведите план рассадки пассажиров, который минимизирует суммарное количество соседей у статусных пассажиров, в том же формате, что и во входных данных. Если в свободное место нужно посадить одного из *k* пассажиров, выведите стр... | [
"1 2\nSP.-SS.S-S.S\n",
"4 9\nPP.-PPPS-S.S\nPSP-PPSP-.S.\n.S.-S..P-SS.\nP.S-P.PP-PSP\n"
] | [
"5\nSPx-SSxS-S.S\n",
"15\nPPx-PPPS-S.S\nPSP-PPSP-xSx\nxSx-SxxP-SSx\nP.S-PxPP-PSP\n"
] | В первом примере нужно посадить ещё двух обычных пассажиров. Для минимизации соседей у статусных пассажиров, нужно посадить первого из них на третье слева место, а второго на любое из оставшихся двух мест, так как независимо от выбора места он станет соседом двух статусных пассажиров.
Изначально, у статусного пассажи... | 1,000 | [
{
"input": "1 2\nSP.-SS.S-S.S",
"output": "5\nSPx-SSxS-S.S"
},
{
"input": "4 9\nPP.-PPPS-S.S\nPSP-PPSP-.S.\n.S.-S..P-SS.\nP.S-P.PP-PSP",
"output": "15\nPPx-PPPS-S.S\nPSP-PPSP-xSx\nxSx-SxxP-SSx\nP.S-PxPP-PSP"
},
{
"input": "3 7\n.S.-SSSP-..S\nS..-.SPP-S.P\n.S.-PPPP-PSP",
"output": "13... | 1,520,009,623 | 4,723 | Python 3 | OK | TESTS | 47 | 77 | 5,734,400 | a = input().split()
n, k = int(a[0]), int(a[1])
zero = []
one = []
two = []
plain = []
neighbours = 0
notS = ['P', '-', '.']
for i in range(n):
row = input()
plain.append(list(row))
for e in range(len(row)):
if row[e] == '.':
if e == 0:
if row[e + 1] in notS... | Title: Места в самолёте
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
В самолёте есть *n* рядов мест. Если смотреть на ряды сверху, то в каждом ряду есть 3 места слева, затем проход между рядами, затем 4 центральных места, затем ещё один проход между рядами, а затем ещё 3 места справа.
... | ```python
a = input().split()
n, k = int(a[0]), int(a[1])
zero = []
one = []
two = []
plain = []
neighbours = 0
notS = ['P', '-', '.']
for i in range(n):
row = input()
plain.append(list(row))
for e in range(len(row)):
if row[e] == '.':
if e == 0:
if row[e + ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
888 | B | Buggy Robot | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the cell (*x*,<=*y*) to (*x*,<=*y*<=+<=1); - D — move from (*x*,<=*y*) to (*x*,<=*y*<=-<=1); - L — mo... | The first line contains one number *n* — the length of sequence of commands entered by Ivan (1<=≤<=*n*<=≤<=100).
The second line contains the sequence itself — a string consisting of *n* characters. Each character can be U, D, L or R. | Print the maximum possible number of commands from the sequence the robot could perform to end up in the starting cell. | [
"4\nLDUR\n",
"5\nRRRUU\n",
"6\nLLRRRR\n"
] | [
"4\n",
"0\n",
"4\n"
] | none | 0 | [
{
"input": "4\nLDUR",
"output": "4"
},
{
"input": "5\nRRRUU",
"output": "0"
},
{
"input": "6\nLLRRRR",
"output": "4"
},
{
"input": "88\nLLUUULRDRRURDDLURRLRDRLLRULRUUDDLLLLRRDDURDURRLDURRLDRRRUULDDLRRRDDRRLUULLURDURUDDDDDLDR",
"output": "76"
},
{
"input": "89\nLDL... | 1,511,108,613 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 62 | 5,529,600 | n=int(input())
ent=input()
Horiz=0
Vert=0
for i in range(n):
if ent[i]=='R':
Horiz+=1
elif ent[i]=='L':
Horiz-=1
elif ent[i]=='U':
Vert+=1
else:
Vert-=1
com=n-abs(Horiz)-abs(Vert)
print(com) | Title: Buggy Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has a robot which is situated on an infinite grid. Initially the robot is standing in the starting cell (0,<=0). The robot can process commands. There are four types of commands it can perform:
- U — move from the ce... | ```python
n=int(input())
ent=input()
Horiz=0
Vert=0
for i in range(n):
if ent[i]=='R':
Horiz+=1
elif ent[i]=='L':
Horiz-=1
elif ent[i]=='U':
Vert+=1
else:
Vert-=1
com=n-abs(Horiz)-abs(Vert)
print(com)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
151 | B | Phone Numbers | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | Winters are just damn freezing cold in Nvodsk! That's why a group of *n* friends prefers to take a taxi, order a pizza and call girls. The phone numbers in the city consist of three pairs of digits (for example, 12-34-56). Each friend has a phonebook of size *s**i* (that's the number of phone numbers). We know that tax... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of friends.
Then follow *n* data blocks that describe each friend's phone books. Each block is presented in the following form: first goes the line that contains integer *s**i* and string *name**i* (0<=≤<=*s**i*<=≤<=100) — the number of phone num... | In the first line print the phrase "If you want to call a taxi, you should call: ". Then print names of all friends whose phone books contain maximal number of taxi phone numbers.
In the second line print the phrase "If you want to order a pizza, you should call: ". Then print names of all friends who have maximal nu... | [
"4\n2 Fedorov\n22-22-22\n98-76-54\n3 Melnikov\n75-19-09\n23-45-67\n99-99-98\n7 Rogulenko\n22-22-22\n11-11-11\n33-33-33\n44-44-44\n55-55-55\n66-66-66\n95-43-21\n3 Kaluzhin\n11-11-11\n99-99-99\n98-65-32\n",
"3\n5 Gleb\n66-66-66\n55-55-55\n01-01-01\n65-43-21\n12-34-56\n3 Serega\n55-55-55\n87-65-43\n65-55-21\n5 Melni... | [
"If you want to call a taxi, you should call: Rogulenko.\nIf you want to order a pizza, you should call: Fedorov, Rogulenko, Kaluzhin.\nIf you want to go to a cafe with a wonderful girl, you should call: Melnikov.\n",
"If you want to call a taxi, you should call: Gleb.\nIf you want to order a pizza, you should ca... | In the first sample you are given four friends. Fedorov's phone book contains one taxi number and one pizza delivery number, Melnikov's phone book only has 3 numbers of girls, Rogulenko's one has 6 taxi numbers and one pizza delivery number, Kaluzhin's one contains 2 taxi numbers and one pizza delivery number.
Thus, i... | 1,000 | [
{
"input": "4\n2 Fedorov\n22-22-22\n98-76-54\n3 Melnikov\n75-19-09\n23-45-67\n99-99-98\n7 Rogulenko\n22-22-22\n11-11-11\n33-33-33\n44-44-44\n55-55-55\n66-66-66\n95-43-21\n3 Kaluzhin\n11-11-11\n99-99-99\n98-65-32",
"output": "If you want to call a taxi, you should call: Rogulenko.\nIf you want to order a piz... | 1,670,949,258 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 38 | 155 | 6,656,000 | d1 = {}
d2 = {}
d3 = {}
for a0 in range(int(input())):
n,k = input().split(' ')
n = int(n)
d1[k],d2[k],d3[k] = 0,0,0
for i in range(n):
s = list(map(int,list(''.join(input().split('-')))))
#print(s)
#print(len(set(s)))
if len(set(s)) == 1:
d1[k]+=1... | Title: Phone Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Winters are just damn freezing cold in Nvodsk! That's why a group of *n* friends prefers to take a taxi, order a pizza and call girls. The phone numbers in the city consist of three pairs of digits (for example, 12-34-56)... | ```python
d1 = {}
d2 = {}
d3 = {}
for a0 in range(int(input())):
n,k = input().split(' ')
n = int(n)
d1[k],d2[k],d3[k] = 0,0,0
for i in range(n):
s = list(map(int,list(''.join(input().split('-')))))
#print(s)
#print(len(set(s)))
if len(set(s)) == 1:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,692,799,293 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 92 | 0 | n1=int(input())
n2=int(input())
n3=n2
c=0
l1=[]
for i in range(n1-1):
if n2==n3:
c=c+1
else:
l1.append(c)
c=0
n3=n2
n2=int(input())
print(max(l1)) | Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
n1=int(input())
n2=int(input())
n3=n2
c=0
l1=[]
for i in range(n1-1):
if n2==n3:
c=c+1
else:
l1.append(c)
c=0
n3=n2
n2=int(input())
print(max(l1))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
835 | A | Key races | PROGRAMMING | 800 | [
"math"
] | null | null | Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t*1 milliseconds. The second participant types one character in *v*2 milliseconds and has ping *... | The first line contains five integers *s*, *v*1, *v*2, *t*1, *t*2 (1<=≤<=*s*,<=*v*1,<=*v*2,<=*t*1,<=*t*2<=≤<=1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and th... | If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship". | [
"5 1 2 1 2\n",
"3 3 1 1 1\n",
"4 5 3 1 5\n"
] | [
"First\n",
"Second\n",
"Friendship\n"
] | In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, ... | 500 | [
{
"input": "5 1 2 1 2",
"output": "First"
},
{
"input": "3 3 1 1 1",
"output": "Second"
},
{
"input": "4 5 3 1 5",
"output": "Friendship"
},
{
"input": "1000 1000 1000 1000 1000",
"output": "Friendship"
},
{
"input": "1 1 1 1 1",
"output": "Friendship"
},
... | 1,611,779,349 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 62 | 0 | s, v1, v2, t1, t2 = map(int, input().split())
p1 = s * v1 + 2 * t1
p2 = s * v2 + 2 * t2
if p1 < p2:
print("First")
elif p2 < p1:
print("Second")
else:
print("Friendship")
| Title: Key races
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of *s* characters. The first participant types one character in *v*1 milliseconds and has ping *t... | ```python
s, v1, v2, t1, t2 = map(int, input().split())
p1 = s * v1 + 2 * t1
p2 = s * v2 + 2 * t2
if p1 < p2:
print("First")
elif p2 < p1:
print("Second")
else:
print("Friendship")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
141 | A | Amusing Joke | PROGRAMMING | 800 | [
"implementation",
"sortings",
"strings"
] | null | null | So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's name and the host's name in honor of this event. Then the hung the letters above the main entrance. O... | The input file consists of three lines: the first line contains the guest's name, the second line contains the name of the residence host and the third line contains letters in a pile that were found at the door in the morning. All lines are not empty and contain only uppercase Latin letters. The length of each line do... | Print "YES" without the quotes, if the letters in the pile could be permuted to make the names of the "New Year and Christmas Men". Otherwise, print "NO" without the quotes. | [
"SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS\n",
"PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI\n",
"BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first sample the letters written in the last line can be used to write the names and there won't be any extra letters left.
In the second sample letter "P" is missing from the pile and there's an extra letter "L".
In the third sample there's an extra letter "L". | 500 | [
{
"input": "SANTACLAUS\nDEDMOROZ\nSANTAMOROZDEDCLAUS",
"output": "YES"
},
{
"input": "PAPAINOEL\nJOULUPUKKI\nJOULNAPAOILELUPUKKI",
"output": "NO"
},
{
"input": "BABBONATALE\nFATHERCHRISTMAS\nBABCHRISTMASBONATALLEFATHER",
"output": "NO"
},
{
"input": "B\nA\nAB",
"output": ... | 1,695,652,075 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 10 | 62 | 0 | word1 = input()
word2 = input()
word3 = input()
for l in (word1+word2):
if word3.count(l) != (word1+word2).count(l):
print('NO')
break
else:
print('YES') | Title: Amusing Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
So, the New Year holidays are over. Santa Claus and his colleagues can take a rest and have guests at last. When two "New Year and Christmas Men" meet, thear assistants cut out of cardboard the letters from the guest's nam... | ```python
word1 = input()
word2 = input()
word3 = input()
for l in (word1+word2):
if word3.count(l) != (word1+word2).count(l):
print('NO')
break
else:
print('YES')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
350 | C | Bombs | PROGRAMMING | 1,600 | [
"greedy",
"implementation",
"sortings"
] | null | null | You've got a robot, its task is destroying bombs on a square plane. Specifically, the square plane contains *n* bombs, the *i*-th bomb is at point with coordinates (*x**i*,<=*y**i*). We know that no two bombs are at the same point and that no bomb is at point with coordinates (0,<=0). Initially, the robot is at point w... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of bombs on the coordinate plane. Next *n* lines contain two integers each. The *i*-th line contains numbers (*x**i*,<=*y**i*) (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109) — the coordinates of the *i*-th bomb. It is guaranteed that no two bombs are... | In a single line print a single integer *k* — the minimum number of operations needed to destroy all bombs. On the next lines print the descriptions of these *k* operations. If there are multiple sequences, you can print any of them. It is guaranteed that there is the solution where *k*<=≤<=106. | [
"2\n1 1\n-1 -1\n",
"3\n5 0\n0 5\n1 0\n"
] | [
"12\n1 1 R\n1 1 U\n2\n1 1 L\n1 1 D\n3\n1 1 L\n1 1 D\n2\n1 1 R\n1 1 U\n3\n",
"12\n1 1 R\n2\n1 1 L\n3\n1 5 R\n2\n1 5 L\n3\n1 5 U\n2\n1 5 D\n3\n"
] | none | 1,000 | [
{
"input": "2\n1 1\n-1 -1",
"output": "12\n1 1 R\n1 1 U\n2\n1 1 L\n1 1 D\n3\n1 1 L\n1 1 D\n2\n1 1 R\n1 1 U\n3"
},
{
"input": "3\n5 0\n0 5\n1 0",
"output": "12\n1 1 R\n2\n1 1 L\n3\n1 5 R\n2\n1 5 L\n3\n1 5 U\n2\n1 5 D\n3"
},
{
"input": "1\n-277226476 314722425",
"output": "6\n1 2772264... | 1,380,646,061 | 4,661 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 2 | 2,000 | 2,048,000 | n = int(input())
xy = []
ans = n*2
for i in range(n):
a, b = map(int, input().split())
xy.append((a,b))
for i, j in xy:
if i*j:
ans += 1
print(ans*2)
xy.sort()
i = 0
while i < n:
mi = xy[i]
if mi[0] > 0:
print(1, mi[0], 'R')
if mi[0] < 0:
print(1, -mi[0],... | Title: Bombs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a robot, its task is destroying bombs on a square plane. Specifically, the square plane contains *n* bombs, the *i*-th bomb is at point with coordinates (*x**i*,<=*y**i*). We know that no two bombs are at the same poin... | ```python
n = int(input())
xy = []
ans = n*2
for i in range(n):
a, b = map(int, input().split())
xy.append((a,b))
for i, j in xy:
if i*j:
ans += 1
print(ans*2)
xy.sort()
i = 0
while i < n:
mi = xy[i]
if mi[0] > 0:
print(1, mi[0], 'R')
if mi[0] < 0:
print(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
850 | B | Arpa and a list of numbers | PROGRAMMING | 2,100 | [
"implementation",
"number theory"
] | null | null | Arpa has found a list containing *n* numbers. He calls a list bad if and only if it is not empty and gcd (see notes section for more information) of numbers in the list is 1.
Arpa can perform two types of operations:
- Choose a number and delete it with cost *x*. - Choose a number and increase it by 1 with cost *y*... | First line contains three integers *n*, *x* and *y* (1<=≤<=*n*<=≤<=5·105, 1<=≤<=*x*,<=*y*<=≤<=109) — the number of elements in the list and the integers *x* and *y*.
Second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the elements of the list. | Print a single integer: the minimum possible cost to make the list good. | [
"4 23 17\n1 17 17 16\n",
"10 6 2\n100 49 71 73 66 96 8 60 41 63\n"
] | [
"40\n",
"10\n"
] | In example, number 1 must be deleted (with cost 23) and number 16 must increased by 1 (with cost 17).
A gcd (greatest common divisor) of a set of numbers is the maximum integer that divides all integers in the set. Read more about gcd [here](https://en.wikipedia.org/wiki/Greatest_common_divisor). | 1,000 | [
{
"input": "4 23 17\n1 17 17 16",
"output": "40"
},
{
"input": "10 6 2\n100 49 71 73 66 96 8 60 41 63",
"output": "10"
},
{
"input": "10 6 2\n90 32 83 50 59 100 60 78 20 82",
"output": "4"
},
{
"input": "10 6 2\n10 16 32 25 45 45 15 8 34 15",
"output": "10"
},
{
"... | 1,591,407,678 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
#include <vector>
#include <algorithm>
#include <utility>
using namespace std;
const long long MAX = 3000000;
vector<long long> a;
vector<pair<long long, long long>> countList(MAX, make_pair(0, 0));
vector<pair<long long, long long>> sumList(MAX, make_pair(0, 0));
long long n = 0, x = 0, y = 0;
... | Title: Arpa and a list of numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arpa has found a list containing *n* numbers. He calls a list bad if and only if it is not empty and gcd (see notes section for more information) of numbers in the list is 1.
Arpa can perform two types of op... | ```python
#include <iostream>
#include <vector>
#include <algorithm>
#include <utility>
using namespace std;
const long long MAX = 3000000;
vector<long long> a;
vector<pair<long long, long long>> countList(MAX, make_pair(0, 0));
vector<pair<long long, long long>> sumList(MAX, make_pair(0, 0));
long long n = 0, x = 0,... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,626,115,888 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 154 | 6,758,400 | n,a, b = map(int,input().split())
print(min(n - a, b + 1)) | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n,a, b = map(int,input().split())
print(min(n - a, b + 1))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,687,623,165 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 124 | 0 | def result(n,m,lis):
k=lis
p=tuple(k)
maxx=0
for i in range(n):
a=max(k)
b=k.index(a)
maxx+=a
k[b]=a-1
p=list(p)
minn=0
i=0
c=0
while i<n:
if len(p)==0 or c==n:
break
a=min(p)
b=p.index(a)
if a==0:
p.pop(b)
i+=1
continue
minn+=a
c+=1
p[b]=a-1
i+=1
print(maxx,minn)
... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
def result(n,m,lis):
k=lis
p=tuple(k)
maxx=0
for i in range(n):
a=max(k)
b=k.index(a)
maxx+=a
k[b]=a-1
p=list(p)
minn=0
i=0
c=0
while i<n:
if len(p)==0 or c==n:
break
a=min(p)
b=p.index(a)
if a==0:
p.pop(b)
i+=1
continue
minn+=a
c+=1
p[b]=a-1
i+=1
print(maxx,mi... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
930 | A | Peculiar apple-tree | PROGRAMMING | 1,500 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | In Arcady's garden there grows a peculiar apple-tree that fruits one time per year. Its peculiarity can be explained in following way: there are *n* inflorescences, numbered from 1 to *n*. Inflorescence number 1 is situated near base of tree and any other inflorescence with number *i* (*i*<=><=1) is situated at the ... | First line of input contains single integer number *n* (2<=≤<=*n*<=≤<=100<=000) — number of inflorescences.
Second line of input contains sequence of *n*<=-<=1 integer numbers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* is number of inflorescence into which the apple from *i*-th inflorescence r... | Single line of output should contain one integer number: amount of apples that Arcady will be able to collect from first inflorescence during one harvest. | [
"3\n1 1\n",
"5\n1 2 2 2\n",
"18\n1 1 1 4 4 3 2 2 2 10 8 9 9 9 10 10 4\n"
] | [
"1\n",
"3\n",
"4\n"
] | In first example Arcady will be able to collect only one apple, initially situated in 1st inflorescence. In next second apples from 2nd and 3rd inflorescences will roll down and annihilate, and Arcady won't be able to collect them.
In the second example Arcady will be able to collect 3 apples. First one is one initial... | 500 | [
{
"input": "3\n1 1",
"output": "1"
},
{
"input": "5\n1 2 2 2",
"output": "3"
},
{
"input": "18\n1 1 1 4 4 3 2 2 2 10 8 9 9 9 10 10 4",
"output": "4"
},
{
"input": "2\n1",
"output": "2"
},
{
"input": "3\n1 2",
"output": "3"
},
{
"input": "20\n1 1 1 1 1 ... | 1,585,389,107 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 | inflos = input()
roots = [int(x) - 1 for x in input().split()]
depth = [0]
for inflo in range(inflos - 1):
depth.append(depth[roots[inflo]] + 1)
parity = [0] * inflos
for d in depth:
parity[d] ^= 1
print(sum(parity))
# inflos = input()
# roots = input().split()
# roots = [int(x) - 1 for x i... | Title: Peculiar apple-tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Arcady's garden there grows a peculiar apple-tree that fruits one time per year. Its peculiarity can be explained in following way: there are *n* inflorescences, numbered from 1 to *n*. Inflorescence number 1 is ... | ```python
inflos = input()
roots = [int(x) - 1 for x in input().split()]
depth = [0]
for inflo in range(inflos - 1):
depth.append(depth[roots[inflo]] + 1)
parity = [0] * inflos
for d in depth:
parity[d] ^= 1
print(sum(parity))
# inflos = input()
# roots = input().split()
# roots = [int(x) -... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
798 | E | Mike and code of a permutation | PROGRAMMING | 3,000 | [
"constructive algorithms",
"data structures",
"graphs",
"sortings"
] | null | null | Mike has discovered a new way to encode permutations. If he has a permutation *P*<==<=[*p*1,<=*p*2,<=...,<=*p**n*], he will encode it in the following way:
Denote by *A*<==<=[*a*1,<=*a*2,<=...,<=*a**n*] a sequence of length *n* which will represent the code of the permutation. For each *i* from 1 to *n* sequentially, ... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=500<=000) — length of permutation.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n* or *a**i*<==<=<=-<=1) — the code of Mike's permutation.
You may assume that all positive values from *A* are different. | In first and only line print *n* numbers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=*n*) — a permutation *P* which has the same code as the given one. Note that numbers in permutation are distinct. | [
"6\n2 -1 1 5 -1 4\n",
"8\n2 -1 4 -1 6 -1 8 -1\n"
] | [
"2 6 1 4 5 3\n",
"1 8 2 7 3 6 4 5\n"
] | For the permutation from the first example:
*i* = 1, the smallest *j* is 2 because *p*<sub class="lower-index">2</sub> = 6 > *p*<sub class="lower-index">1</sub> = 2.
*i* = 2, there is no *j* because *p*<sub class="lower-index">2</sub> = 6 is the greatest element in the permutation.
*i* = 3, the smallest *j* is 1 ... | 2,500 | [] | 1,689,421,423 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | print("_RANDOM_GUESS_1689421423.6024435")# 1689421423.6024628 | Title: Mike and code of a permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mike has discovered a new way to encode permutations. If he has a permutation *P*<==<=[*p*1,<=*p*2,<=...,<=*p**n*], he will encode it in the following way:
Denote by *A*<==<=[*a*1,<=*a*2,<=...,<=*a**n*] ... | ```python
print("_RANDOM_GUESS_1689421423.6024435")# 1689421423.6024628
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
65 | A | Harry Potter and Three Spells | PROGRAMMING | 1,800 | [
"implementation",
"math"
] | A. Harry Potter and Three Spells | 2 | 256 | A long time ago (probably even in the first book), Nicholas Flamel, a great alchemist and the creator of the Philosopher's Stone, taught Harry Potter three useful spells. The first one allows you to convert *a* grams of sand into *b* grams of lead, the second one allows you to convert *c* grams of lead into *d* grams o... | The first line contains 6 integers *a*, *b*, *c*, *d*, *e*, *f* (0<=≤<=*a*,<=*b*,<=*c*,<=*d*,<=*e*,<=*f*<=≤<=1000). | Print "Ron", if it is possible to get an infinitely large amount of gold having a certain finite amount of sand (and not having any gold and lead at all), i.e., Ron is right. Otherwise, print "Hermione". | [
"100 200 250 150 200 250\n",
"100 50 50 200 200 100\n",
"100 10 200 20 300 30\n",
"0 0 0 0 0 0\n",
"1 1 0 1 1 1\n",
"1 0 1 2 1 2\n",
"100 1 100 1 0 1\n"
] | [
"Ron\n",
"Hermione\n",
"Hermione\n",
"Hermione\n",
"Ron\n",
"Hermione\n",
"Ron\n"
] | Consider the first sample. Let's start with the 500 grams of sand. Apply the first spell 5 times and turn the sand into 1000 grams of lead. Then apply the second spell 4 times to get 600 grams of gold. Let’s take 400 grams from the resulting amount of gold turn them back into sand. We get 500 grams of sand and 200 gram... | 500 | [
{
"input": "100 200 250 150 200 250",
"output": "Ron"
},
{
"input": "100 50 50 200 200 100",
"output": "Hermione"
},
{
"input": "100 10 200 20 300 30",
"output": "Hermione"
},
{
"input": "0 0 0 0 0 0",
"output": "Hermione"
},
{
"input": "1 1 0 1 1 1",
"output"... | 1,597,775,067 | 3,867 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a,b,c,d,e,f=map(int,input().split())
if a*c*e < b*d*f or (c==0 and d>0) or (a==0 and b>0 and d>0 and c>0:
print("Ron")
else:
print("Hermione") | Title: Harry Potter and Three Spells
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A long time ago (probably even in the first book), Nicholas Flamel, a great alchemist and the creator of the Philosopher's Stone, taught Harry Potter three useful spells. The first one allows you to convert *a... | ```python
a,b,c,d,e,f=map(int,input().split())
if a*c*e < b*d*f or (c==0 and d>0) or (a==0 and b>0 and d>0 and c>0:
print("Ron")
else:
print("Hermione")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
929 | C | Красивая команда | PROGRAMMING | 1,700 | [
"*special",
"combinatorics",
"math"
] | null | null | Завтра у хоккейной команды, которой руководит Евгений, важный матч. Евгению нужно выбрать шесть игроков, которые выйдут на лед в стартовом составе: один вратарь, два защитника и три нападающих.
Так как это стартовый состав, Евгения больше волнует, насколько красива будет команда на льду, чем способности игроков. А име... | Первая строка содержит три целых числа *g*, *d* и *f* (1<=≤<=*g*<=≤<=1<=000, 1<=≤<=*d*<=≤<=1<=000, 1<=≤<=*f*<=≤<=1<=000) — число вратарей, защитников и нападающих в команде Евгения.
Вторая строка содержит *g* целых чисел, каждое в пределах от 1 до 100<=000 — номера вратарей.
Третья строка содержит *d* целых чисел, к... | Выведите одно целое число — количество возможных стартовых составов. | [
"1 2 3\n15\n10 19\n20 11 13\n",
"2 3 4\n16 40\n20 12 19\n13 21 11 10\n"
] | [
"1\n",
"6\n"
] | В первом примере всего один вариант для выбора состава, который удовлетворяет описанным условиям, поэтому ответ 1.
Во втором примере подходят следующие игровые сочетания (в порядке вратарь-защитник-защитник-нападающий-нападающий-нападающий):
- 16 20 12 13 21 11 - 16 20 12 13 11 10 - 16 20 19 13 21 11 - 16 20 19 1... | 1,750 | [
{
"input": "1 2 3\n15\n10 19\n20 11 13",
"output": "1"
},
{
"input": "2 3 4\n16 40\n20 12 19\n13 21 11 10",
"output": "6"
},
{
"input": "4 4 5\n15 16 19 6\n8 11 9 18\n5 3 1 12 14",
"output": "0"
},
{
"input": "6 7 7\n32 35 26 33 16 23\n4 40 36 12 28 24 3\n39 11 31 37 1 25 6",... | 1,520,022,451 | 17,551 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 5,632,000 | g, d, f = map(int, input().split())
v = list(map(int, input().split()))
z = list(map(int, input().split()))
n = list(map(int, input().split()))
v.sort()
z.sort()
n.sort()
def func(x, y):
if y >= x / 2 and y <= x * 2:
return True
else:
return False
v_true = []
for a in range(g):
... | Title: Красивая команда
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Завтра у хоккейной команды, которой руководит Евгений, важный матч. Евгению нужно выбрать шесть игроков, которые выйдут на лед в стартовом составе: один вратарь, два защитника и три нападающих.
Так как это стартовый с... | ```python
g, d, f = map(int, input().split())
v = list(map(int, input().split()))
z = list(map(int, input().split()))
n = list(map(int, input().split()))
v.sort()
z.sort()
n.sort()
def func(x, y):
if y >= x / 2 and y <= x * 2:
return True
else:
return False
v_true = []
for a in rang... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was ma... | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the inte... | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the i... | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,444,658,585 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 77 | 307,200 | N = int(input())
plan = list()
for i in range(N ** 2):
plan.append([ int(i) for i in input().split()])
ver, her, progress = list(), list(), list()
day = 1
for item in plan:
if item[0] not in ver and item[1] not in her:
progress.append(str(day))
ver.append(item[0])
her.appen... | Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers ... | ```python
N = int(input())
plan = list()
for i in range(N ** 2):
plan.append([ int(i) for i in input().split()])
ver, her, progress = list(), list(), list()
day = 1
for item in plan:
if item[0] not in ver and item[1] not in her:
progress.append(str(day))
ver.append(item[0])
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
747 | B | Mammoth's Genome Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter of English alphabet: 'A', 'C', 'G' or 'T'. Unrecognized nucleotides are coded by a question mark '?'. Thus, *s... | The first line contains the integer *n* (4<=≤<=*n*<=≤<=255) — the length of the genome.
The second line contains the string *s* of length *n* — the coded genome. It consists of characters 'A', 'C', 'G', 'T' and '?'. | If it is possible to decode the genome, print it. If there are multiple answer, print any of them. If it is not possible, print three equals signs in a row: "===" (without quotes). | [
"8\nAG?C??CT\n",
"4\nAGCT\n",
"6\n????G?\n",
"4\nAA??\n"
] | [
"AGACGTCT\n",
"AGCT\n",
"===\n",
"===\n"
] | In the first example you can replace the first question mark with the letter 'A', the second question mark with the letter 'G', the third question mark with the letter 'T', then each nucleotide in the genome would be presented twice.
In the second example the genome is already decoded correctly and each nucleotide is ... | 1,000 | [
{
"input": "8\nAG?C??CT",
"output": "AGACGTCT"
},
{
"input": "4\nAGCT",
"output": "AGCT"
},
{
"input": "6\n????G?",
"output": "==="
},
{
"input": "4\nAA??",
"output": "==="
},
{
"input": "4\n????",
"output": "ACGT"
},
{
"input": "252\n???????GCG??T??TT... | 1,622,099,456 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n=int(input())
str=input()
if n%4!=0:
print('===')
else:
for i in 'ACGT':
if 4*str.count(i)>n:
print('===')
r=''
for i in 'ACGT':
r+=i*(n//4-str.count(i))
j=0
res=""
for i in range(len(str)):
if str[i]=='?':
res+=r[j]
j+=1
else:
res+=str[i]
print(res)
| Title: Mammoth's Genome Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The process of mammoth's genome decoding in Berland comes to its end!
One of the few remaining tasks is to restore unrecognized nucleotides in a found chain *s*. Each nucleotide is coded with a capital letter... | ```python
n=int(input())
str=input()
if n%4!=0:
print('===')
else:
for i in 'ACGT':
if 4*str.count(i)>n:
print('===')
r=''
for i in 'ACGT':
r+=i*(n//4-str.count(i))
j=0
res=""
for i in range(len(str)):
if str[i]=='?':
res+=r[j]
j+=1
else:
res+=str[i]
print(res)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
174 | A | Problem About Equation | PROGRAMMING | 1,100 | [
"math"
] | null | null | A group of *n* merry programmers celebrate Robert Floyd's birthday. Polucarpus has got an honourable task of pouring Ber-Cola to everybody. Pouring the same amount of Ber-Cola to everybody is really important. In other words, the drink's volume in each of the *n* mugs must be the same.
Polycarpus has already began the... | The first line contains a pair of integers *n*, *b* (2<=≤<=*n*<=≤<=100,<=1<=≤<=*b*<=≤<=100), where *n* is the total number of friends in the group and *b* is the current volume of drink in the bottle. The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100), where *a**i* is the ... | Print a single number "-1" (without the quotes), if there is no solution. Otherwise, print *n* float numbers *c*1,<=*c*2,<=...,<=*c**n*, where *c**i* is the volume of the drink to add in the *i*-th mug. Print the numbers with no less than 6 digits after the decimal point, print each *c**i* on a single line. Polycarpus ... | [
"5 50\n1 2 3 4 5\n",
"2 2\n1 100\n"
] | [
"12.000000\n11.000000\n10.000000\n9.000000\n8.000000\n",
"-1\n"
] | none | 500 | [
{
"input": "5 50\n1 2 3 4 5",
"output": "12.000000\n11.000000\n10.000000\n9.000000\n8.000000"
},
{
"input": "2 2\n1 100",
"output": "-1"
},
{
"input": "2 2\n1 1",
"output": "1.000000\n1.000000"
},
{
"input": "3 2\n1 2 1",
"output": "1.000000\n0.000000\n1.000000"
},
{
... | 1,604,377,734 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 0 | n, b = map(int, input().split())
s = list(map(int, input().split()))
sb = sum(s) + b
sb /= n
if sb - max(s) > 0:
for x in s:
print(sb-x)
else:
print('-1')
| Title: Problem About Equation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A group of *n* merry programmers celebrate Robert Floyd's birthday. Polucarpus has got an honourable task of pouring Ber-Cola to everybody. Pouring the same amount of Ber-Cola to everybody is really important. In... | ```python
n, b = map(int, input().split())
s = list(map(int, input().split()))
sb = sum(s) + b
sb /= n
if sb - max(s) > 0:
for x in s:
print(sb-x)
else:
print('-1')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
883 | H | Palindromic Cut | PROGRAMMING | 1,800 | [
"brute force",
"implementation",
"strings"
] | null | null | Kolya has a string *s* of length *n* consisting of lowercase and uppercase Latin letters and digits.
He wants to rearrange the symbols in *s* and cut it into the minimum number of parts so that each part is a palindrome and all parts have the same lengths. A palindrome is a string which reads the same backward as forw... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=4·105) — the length of string *s*.
The second line contains a string *s* of length *n* consisting of lowercase and uppercase Latin letters and digits. | Print to the first line an integer *k* — minimum number of palindromes into which you can cut a given string.
Print to the second line *k* strings — the palindromes themselves. Separate them by a space. You are allowed to print palindromes in arbitrary order. All of them should have the same length. | [
"6\naabaac\n",
"8\n0rTrT022\n",
"2\naA\n"
] | [
"2\naba aca ",
"1\n02TrrT20 ",
"2\na A \n"
] | none | 0 | [
{
"input": "6\naabaac",
"output": "2\naba aca "
},
{
"input": "8\n0rTrT022",
"output": "1\n02TrrT20 "
},
{
"input": "2\naA",
"output": "2\na A "
},
{
"input": "1\ns",
"output": "1\ns "
},
{
"input": "10\n6IIC6CCIIC",
"output": "1\n6CCIIIICC6 "
},
{
"in... | 1,508,591,088 | 17,988 | Python 3 | WRONG_ANSWER | TESTS1 | 0 | 46 | 4,812,800 | n=int(input())
s=input()
def calcul(d):
ch=''
for x in d:
ch+=x*(d[x]//2)
if d[x]%2!=0:
ch1=x
ch+=ch1+ch[::-1]
return ch
d={}
for x in s:
try:
d[x]+=1
except:
d[x]=1
impair=len([x for x in d.values() if x%2!=0])
if impair==0:
... | Title: Palindromic Cut
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya has a string *s* of length *n* consisting of lowercase and uppercase Latin letters and digits.
He wants to rearrange the symbols in *s* and cut it into the minimum number of parts so that each part is a palindrom... | ```python
n=int(input())
s=input()
def calcul(d):
ch=''
for x in d:
ch+=x*(d[x]//2)
if d[x]%2!=0:
ch1=x
ch+=ch1+ch[::-1]
return ch
d={}
for x in s:
try:
d[x]+=1
except:
d[x]=1
impair=len([x for x in d.values() if x%2!=0])
if impair... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't w... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't e... | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,694,353,920 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | a=int(input())
li=list(map(int,input().split()))
s=set(li)
print(sum(li)%sum(s)) | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very w... | ```python
a=int(input())
li=list(map(int,input().split()))
s=set(li)
print(sum(li)%sum(s))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
620 | A | Professor GukiZ's Robot | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of them) by one (decrease or increase). So the robot can move in one of the 8 directions. Find the minimal numbe... | The first line contains two integers *x*1,<=*y*1 (<=-<=109<=≤<=*x*1,<=*y*1<=≤<=109) — the start position of the robot.
The second line contains two integers *x*2,<=*y*2 (<=-<=109<=≤<=*x*2,<=*y*2<=≤<=109) — the finish position of the robot. | Print the only integer *d* — the minimal number of steps to get the finish position. | [
"0 0\n4 5\n",
"3 4\n6 1\n"
] | [
"5\n",
"3\n"
] | In the first example robot should increase both of its coordinates by one four times, so it will be in position (4, 4). After that robot should simply increase its *y* coordinate and get the finish position.
In the second example robot should simultaneously increase *x* coordinate and decrease *y* coordinate by one th... | 0 | [
{
"input": "0 0\n4 5",
"output": "5"
},
{
"input": "3 4\n6 1",
"output": "3"
},
{
"input": "0 0\n4 6",
"output": "6"
},
{
"input": "1 1\n-3 -5",
"output": "6"
},
{
"input": "-1 -1\n-10 100",
"output": "101"
},
{
"input": "1 -1\n100 -100",
"output":... | 1,667,072,212 | 2,147,483,647 | Python 3 | OK | TESTS | 75 | 46 | 0 | x1, y1 = input().split()
x2, y2 = input().split()
x, y = abs(int(x1)- int(x2)), abs(int(y1) - int(y2))
if (x > y): print(x)
else: print(y)
| Title: Professor GukiZ's Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ makes a new robot. The robot are in the point with coordinates (*x*1,<=*y*1) and should go to the point (*x*2,<=*y*2). In a single step the robot can change any of its coordinates (maybe both of ... | ```python
x1, y1 = input().split()
x2, y2 = input().split()
x, y = abs(int(x1)- int(x2)), abs(int(y1) - int(y2))
if (x > y): print(x)
else: print(y)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
482 | A | Diverse Permutation | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy"
] | null | null | Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*.
Your task is to find such permutation *p* of length *n*, that the group of number... | The single line of the input contains two space-separated positive integers *n*, *k* (1<=≤<=*k*<=<<=*n*<=≤<=105). | Print *n* integers forming the permutation. If there are multiple answers, print any of them. | [
"3 2\n",
"3 1\n",
"5 2\n"
] | [
"1 3 2\n",
"1 2 3\n",
"1 3 2 4 5\n"
] | By |*x*| we denote the absolute value of number *x*. | 500 | [
{
"input": "3 2",
"output": "1 3 2"
},
{
"input": "3 1",
"output": "1 2 3"
},
{
"input": "5 2",
"output": "1 3 2 4 5"
},
{
"input": "5 4",
"output": "1 5 2 4 3"
},
{
"input": "10 4",
"output": "1 10 2 9 8 7 6 5 4 3"
},
{
"input": "10 3",
"output": ... | 1,533,805,024 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 436 | 409,600 | from __future__ import print_function
s = input().split()
n = int(s[0])
k = int(s[1])
a = 1
b = k + 1
i = 0
while a < b:
print(a, end = ' ')
a += 1
print(b, end = ' ')
b -= 1
if a == b:
print(a, end = ' ')
i = 2 + k
while i <= n:
print(i, end = ' ')
i += 1
#ergbehjrgb | Title: Diverse Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Permutation *p* is an ordered set of integers *p*1,<=<=<=*p*2,<=<=<=...,<=<=<=*p**n*, consisting of *n* distinct positive integers not larger than *n*. We'll denote as *n* the length of permutation *p*1,<=<=<=*p*2,<... | ```python
from __future__ import print_function
s = input().split()
n = int(s[0])
k = int(s[1])
a = 1
b = k + 1
i = 0
while a < b:
print(a, end = ' ')
a += 1
print(b, end = ' ')
b -= 1
if a == b:
print(a, end = ' ')
i = 2 + k
while i <= n:
print(i, end = ' ')
i += 1
#ergbehjrgb
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,693,304,147 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | num = int(input())
if num %2 == 0:
print(num // 2)
else:
print(num // 2 - num) | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
num = int(input())
if num %2 == 0:
print(num // 2)
else:
print(num // 2 - num)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
242 | B | Big Segment | PROGRAMMING | 1,100 | [
"implementation",
"sortings"
] | null | null | A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments covers all others. In other words, there is such segment in the given set, which contains all oth... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of segments. Next *n* lines contain the descriptions of the segments. The *i*-th line contains two space-separated integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109) — the borders of the *i*-th segment.
It is guaranteed that no two segments c... | Print a single integer — the number of the segment that covers all other segments in the set. If there's no solution, print -1.
The segments are numbered starting from 1 in the order in which they appear in the input. | [
"3\n1 1\n2 2\n3 3\n",
"6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10\n"
] | [
"-1\n",
"3\n"
] | none | 1,000 | [
{
"input": "3\n1 1\n2 2\n3 3",
"output": "-1"
},
{
"input": "6\n1 5\n2 3\n1 10\n7 10\n7 7\n10 10",
"output": "3"
},
{
"input": "4\n1 5\n2 2\n2 4\n2 5",
"output": "1"
},
{
"input": "5\n3 3\n1 3\n2 2\n2 3\n1 2",
"output": "2"
},
{
"input": "7\n7 7\n8 8\n3 7\n1 6\n1 ... | 1,586,423,547 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 30 | 654 | 8,806,400 | def func(n):
l=99999
r=-99999
ans=[]
for i in range(n):
a=[int(a) for a in input().split()]
ans.append(a)
l=a[0] if (a[0]<l) else l
r=a[1] if (a[1]>r) else r
for i in range(n):
if (ans[i]==[l,r]):
return (i+1)
return (-1)
n=i... | Title: Big Segment
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A coordinate line has *n* segments, the *i*-th segment starts at the position *l**i* and ends at the position *r**i*. We will denote such a segment as [*l**i*,<=*r**i*].
You have suggested that one of the defined segments ... | ```python
def func(n):
l=99999
r=-99999
ans=[]
for i in range(n):
a=[int(a) for a in input().split()]
ans.append(a)
l=a[0] if (a[0]<l) else l
r=a[1] if (a[1]>r) else r
for i in range(n):
if (ans[i]==[l,r]):
return (i+1)
return (-1)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
837 | D | Round Subset | PROGRAMMING | 2,100 | [
"dp",
"math"
] | null | null | Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected numbers will be maximum possible. | The first line contains two integer numbers *n* and *k* (1<=≤<=*n*<=≤<=200,<=1<=≤<=*k*<=≤<=*n*).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1018). | Print maximal roundness of product of the chosen subset of length *k*. | [
"3 2\n50 4 20\n",
"5 3\n15 16 3 25 9\n",
"3 3\n9 77 13\n"
] | [
"3\n",
"3\n",
"0\n"
] | In the first example there are 3 subsets of 2 numbers. [50, 4] has product 200 with roundness 2, [4, 20] — product 80, roundness 1, [50, 20] — product 1000, roundness 3.
In the second example subset [15, 16, 25] has product 6000, roundness 3.
In the third example all subsets has product with roundness 0. | 0 | [
{
"input": "3 2\n50 4 20",
"output": "3"
},
{
"input": "5 3\n15 16 3 25 9",
"output": "3"
},
{
"input": "3 3\n9 77 13",
"output": "0"
},
{
"input": "1 1\n200000000",
"output": "8"
},
{
"input": "1 1\n3",
"output": "0"
},
{
"input": "3 1\n10000000000000... | 1,598,197,186 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 2,000 | 32,153,600 |
n, k = map(int, input().split())
A = list(map(int, input().split()))
# n, k = 3, 2
# A = [50, 4, 20]
# n, k = 5, 3
# A = [15, 16, 3, 25, 9]
# n, k = 3, 3
# A = [9, 77, 13]
import functools
def solve():
def getRoundness(total):
ans = 0
while total and not (total % 10):
total //= 10
a... | Title: Round Subset
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call the roundness of the number the number of zeros to which it ends.
You have an array of *n* numbers. You need to choose a subset of exactly *k* numbers so that the roundness of the product of the selected number... | ```python
n, k = map(int, input().split())
A = list(map(int, input().split()))
# n, k = 3, 2
# A = [50, 4, 20]
# n, k = 5, 3
# A = [15, 16, 3, 25, 9]
# n, k = 3, 3
# A = [9, 77, 13]
import functools
def solve():
def getRoundness(total):
ans = 0
while total and not (total % 10):
total //... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,697,628,335 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 46 | 0 | a = int(input())
b = int(input())
c = int(input())
b = b // 2
c = c // 4
x = min(b, c)
if a >= x:
a = x
y = 7 * a
else:
y = 0
print(y)
| Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
a = int(input())
b = int(input())
c = int(input())
b = b // 2
c = c // 4
x = min(b, c)
if a >= x:
a = x
y = 7 * a
else:
y = 0
print(y)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
552 | C | Vanya and Scales | PROGRAMMING | 1,900 | [
"brute force",
"dp",
"greedy",
"math",
"meet-in-the-middle",
"number theory"
] | null | null | Vanya has a scales for weighing loads and weights of masses *w*0,<=*w*1,<=*w*2,<=...,<=*w*100 grams where *w* is some integer not less than 2 (exactly one weight of each nominal value). Vanya wonders whether he can weight an item with mass *m* using the given weights, if the weights can be put on both pans of the scale... | The first line contains two integers *w*,<=*m* (2<=≤<=*w*<=≤<=109, 1<=≤<=*m*<=≤<=109) — the number defining the masses of the weights and the mass of the item. | Print word 'YES' if the item can be weighted and 'NO' if it cannot. | [
"3 7\n",
"100 99\n",
"100 50\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note to the first sample test. One pan can have an item of mass 7 and a weight of mass 3, and the second pan can have two weights of masses 9 and 1, correspondingly. Then 7 + 3 = 9 + 1.
Note to the second sample test. One pan of the scales can have an item of mass 99 and the weight of mass 1, and the second pan can ha... | 1,500 | [
{
"input": "3 7",
"output": "YES"
},
{
"input": "100 99",
"output": "YES"
},
{
"input": "100 50",
"output": "NO"
},
{
"input": "1000000000 1",
"output": "YES"
},
{
"input": "100 10002",
"output": "NO"
},
{
"input": "4 7",
"output": "NO"
},
{
... | 1,623,559,836 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 10 | 77 | 0 | w,m=map(int,input().split())
a=[0]*60
c=0
while(m>0):
a[c]=m%w
c+=1
m//=w
for i in range(60):
if(a[i] not in [0,1,w-1,w]):
print("NO")
break
elif a[i] in [w-1,w]:a[i+1]+=1
else:print("YES")
| Title: Vanya and Scales
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya has a scales for weighing loads and weights of masses *w*0,<=*w*1,<=*w*2,<=...,<=*w*100 grams where *w* is some integer not less than 2 (exactly one weight of each nominal value). Vanya wonders whether he can wei... | ```python
w,m=map(int,input().split())
a=[0]*60
c=0
while(m>0):
a[c]=m%w
c+=1
m//=w
for i in range(60):
if(a[i] not in [0,1,w-1,w]):
print("NO")
break
elif a[i] in [w-1,w]:a[i+1]+=1
else:print("YES")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
920 | B | Tea Queue | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Recently *n* students from city S moved to city P to attend a programming camp.
They moved there by train. In the evening, all students in the train decided that they want to drink some tea. Of course, no two people can use the same teapot simultaneously, so the students had to form a queue to get their tea.
*i*-th s... | The first line contains one integer *t* — the number of test cases to solve (1<=≤<=*t*<=≤<=1000).
Then *t* test cases follow. The first line of each test case contains one integer *n* (1<=≤<=*n*<=≤<=1000) — the number of students.
Then *n* lines follow. Each line contains two integer *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=... | For each test case print *n* integers. *i*-th of them must be equal to the second when *i*-th student gets his tea, or 0 if he leaves without tea. | [
"2\n2\n1 3\n1 4\n3\n1 5\n1 1\n2 3\n"
] | [
"1 2 \n1 0 2 \n"
] | The example contains 2 tests:
1. During 1-st second, students 1 and 2 come to the queue, and student 1 gets his tea. Student 2 gets his tea during 2-nd second. 1. During 1-st second, students 1 and 2 come to the queue, student 1 gets his tea, and student 2 leaves without tea. During 2-nd second, student 3 comes and ... | 0 | [
{
"input": "2\n2\n1 3\n1 4\n3\n1 5\n1 1\n2 3",
"output": "1 2 \n1 0 2 "
},
{
"input": "19\n1\n1 1\n1\n1 2\n1\n1 1000\n1\n1 2000\n1\n2 2\n1\n2 3\n1\n2 1000\n1\n2 2000\n1\n1999 1999\n1\n1999 2000\n1\n2000 2000\n2\n1 1\n1 1\n2\n1 1\n1 2\n2\n1 2\n1 1\n2\n1 2000\n1 1\n2\n1 1\n1 2000\n2\n1 2000\n2 2\n2\n2... | 1,596,209,043 | 2,147,483,647 | PyPy 3 | OK | TESTS | 8 | 187 | 23,347,200 | for _ in range(int(input())):
n = int(input())
q = []
time = 0
for i in range(n):
s,e = map(int,input().split())
q.append([s,e])
while q:
if q[0][1] >= time:
x,y = q.pop(0)
time = max(time + 1, x)
print(time,end=' ')
... | Title: Tea Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently *n* students from city S moved to city P to attend a programming camp.
They moved there by train. In the evening, all students in the train decided that they want to drink some tea. Of course, no two people can use ... | ```python
for _ in range(int(input())):
n = int(input())
q = []
time = 0
for i in range(n):
s,e = map(int,input().split())
q.append([s,e])
while q:
if q[0][1] >= time:
x,y = q.pop(0)
time = max(time + 1, x)
print(time,end... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
300 | B | Coach | PROGRAMMING | 1,500 | [
"brute force",
"dfs and similar",
"graphs"
] | null | null | A programming coach has *n* students to teach. We know that *n* is divisible by 3. Let's assume that all students are numbered from 1 to *n*, inclusive.
Before the university programming championship the coach wants to split all students into groups of three. For some pairs of students we know that they want to be on ... | The first line of the input contains integers *n* and *m* (3<=≤<=*n*<=≤<=48, . Then follow *m* lines, each contains a pair of integers *a**i*,<=*b**i* (1<=≤<=*a**i*<=<<=*b**i*<=≤<=*n*) — the pair *a**i*,<=*b**i* means that students with numbers *a**i* and *b**i* want to be on the same team.
It is guaranteed that *n... | If the required division into teams doesn't exist, print number -1. Otherwise, print lines. In each line print three integers *x**i*, *y**i*, *z**i* (1<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=*n*) — the *i*-th team.
If there are multiple answers, you are allowed to print any of them. | [
"3 0\n",
"6 4\n1 2\n2 3\n3 4\n5 6\n",
"3 3\n1 2\n2 3\n1 3\n"
] | [
"3 2 1 \n",
"-1\n",
"3 2 1 \n"
] | none | 1,000 | [
{
"input": "3 0",
"output": "3 2 1 "
},
{
"input": "6 4\n1 2\n2 3\n3 4\n5 6",
"output": "-1"
},
{
"input": "3 3\n1 2\n2 3\n1 3",
"output": "3 2 1 "
},
{
"input": "6 3\n1 2\n3 4\n5 6",
"output": "-1"
},
{
"input": "15 9\n1 4\n1 6\n2 7\n2 11\n4 6\n5 12\n7 11\n9 14\n... | 1,620,967,540 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 124 | 7,168,000 | import sys
import math
import bisect
from sys import stdin, stdout
from math import gcd, floor, sqrt, log
from collections import defaultdict as dd
from bisect import bisect_left as bl, bisect_right as br
sys.setrecursionlimit(100000000)
int_r = lambda: int(sys.stdin.readline())
str_r = lambda: sys.stdin.readline().s... | Title: Coach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A programming coach has *n* students to teach. We know that *n* is divisible by 3. Let's assume that all students are numbered from 1 to *n*, inclusive.
Before the university programming championship the coach wants to split all... | ```python
import sys
import math
import bisect
from sys import stdin, stdout
from math import gcd, floor, sqrt, log
from collections import defaultdict as dd
from bisect import bisect_left as bl, bisect_right as br
sys.setrecursionlimit(100000000)
int_r = lambda: int(sys.stdin.readline())
str_r = lambda: sys.stdin.re... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,667,917,926 | 2,147,483,647 | Python 3 | OK | TESTS | 80 | 624 | 0 | R = lambda: map(int, input().split())
L = lambda: list(R())
n,=R()
l=L()
maxx = 0
for i in range(n) :
ans = 0
prev = l[i]
for x in range(i,-1,-1):
if l[x] <= prev :
ans+=1
prev = l[x]
else :break
prev = l[i]
for y in range(i,n) :
if l[y] <= prev :
ans+=1
prev = l[y]
else : bre... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
R = lambda: map(int, input().split())
L = lambda: list(R())
n,=R()
l=L()
maxx = 0
for i in range(n) :
ans = 0
prev = l[i]
for x in range(i,-1,-1):
if l[x] <= prev :
ans+=1
prev = l[x]
else :break
prev = l[i]
for y in range(i,n) :
if l[y] <= prev :
ans+=1
prev = l[y]
... | 3.844 | MatrixStudio/Codeforces-Python-Submissions |
408 | B | Garland | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Once little Vasya read an article in a magazine on how to make beautiful handmade garland from colored paper. Vasya immediately went to the store and bought *n* colored sheets of paper, the area of each sheet is 1 square meter.
The garland must consist of exactly *m* pieces of colored paper of arbitrary area, each pie... | The first line contains a non-empty sequence of *n* (1<=≤<=*n*<=≤<=1000) small English letters ("a"..."z"). Each letter means that Vasya has a sheet of paper of the corresponding color.
The second line contains a non-empty sequence of *m* (1<=≤<=*m*<=≤<=1000) small English letters that correspond to the colors of the ... | Print an integer that is the maximum possible total area of the pieces of paper in the garland Vasya wants to get or -1, if it is impossible to make the garland from the sheets he's got. It is guaranteed that the answer is always an integer. | [
"aaabbac\naabbccac\n",
"a\nz\n"
] | [
"6\n",
"-1"
] | In the first test sample Vasya can make an garland of area 6: he can use both sheets of color *b*, three (but not four) sheets of color *a* and cut a single sheet of color *c* in three, for example, equal pieces. Vasya can use the resulting pieces to make a garland of area 6.
In the second test sample Vasya cannot mak... | 1,000 | [
{
"input": "aaabbac\naabbccac",
"output": "6"
},
{
"input": "a\nz",
"output": "-1"
},
{
"input": "r\nr",
"output": "1"
},
{
"input": "stnsdn\nndnndsn",
"output": "4"
},
{
"input": "yqfqfp\ntttwtqq",
"output": "-1"
},
{
"input": "zzbbrrtrtzr\ntbbtrrrzr"... | 1,517,054,703 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 5,529,600 | n=input()
m=input()
i=0
a=0
while i<len(m):
if not (m[i] in n):
print (-1)
break
i=0
while i<len(m):
if m[i] in n:
adet=n.count(m[i])
n=n.replace(m[i],'')+(adet-1)*m[i]
a=a+1
i=i+1
print(a)
| Title: Garland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once little Vasya read an article in a magazine on how to make beautiful handmade garland from colored paper. Vasya immediately went to the store and bought *n* colored sheets of paper, the area of each sheet is 1 square meter.... | ```python
n=input()
m=input()
i=0
a=0
while i<len(m):
if not (m[i] in n):
print (-1)
break
i=0
while i<len(m):
if m[i] in n:
adet=n.count(m[i])
n=n.replace(m[i],'')+(adet-1)*m[i]
a=a+1
i=i+1
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,655,637,385 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 61 | 0 | # 1000 pts.
a, b = map(int, input().split())
t = 0
while a != 0:
t += a
a = a // b
print(t)
| Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
# 1000 pts.
a, b = map(int, input().split())
t = 0
while a != 0:
t += a
a = a // b
print(t)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
195 | B | After Training | PROGRAMMING | 1,300 | [
"data structures",
"implementation",
"math"
] | null | null | After a team finished their training session on Euro football championship, Valeric was commissioned to gather the balls and sort them into baskets. Overall the stadium has *n* balls and *m* baskets. The baskets are positioned in a row from left to right and they are numbered with numbers from 1 to *m*, correspondingly... | The first line contains two space-separated integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of balls and baskets, correspondingly. | Print *n* numbers, one per line. The *i*-th line must contain the number of the basket for the *i*-th ball. | [
"4 3\n",
"3 1\n"
] | [
"2\n1\n3\n2\n",
"1\n1\n1\n"
] | none | 1,000 | [
{
"input": "4 3",
"output": "2\n1\n3\n2"
},
{
"input": "3 1",
"output": "1\n1\n1"
},
{
"input": "10 3",
"output": "2\n1\n3\n2\n1\n3\n2\n1\n3\n2"
},
{
"input": "6 5",
"output": "3\n2\n4\n1\n5\n3"
},
{
"input": "2 6",
"output": "3\n4"
},
{
"input": "5 2"... | 1,649,091,706 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | n, m = map(int, input().split())
cestas = [i for i in range(1,m+1)]
aux = []
for i in range(n):
if m == 1:
print('1')
else:
escolha = 0
if len(aux) == 0:
aux = cestas.copy()
if len(aux)==1:
escolha = aux[0]
aux.remove(escolha)
else:
... | Title: After Training
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After a team finished their training session on Euro football championship, Valeric was commissioned to gather the balls and sort them into baskets. Overall the stadium has *n* balls and *m* baskets. The baskets are posi... | ```python
n, m = map(int, input().split())
cestas = [i for i in range(1,m+1)]
aux = []
for i in range(n):
if m == 1:
print('1')
else:
escolha = 0
if len(aux) == 0:
aux = cestas.copy()
if len(aux)==1:
escolha = aux[0]
aux.remove(escolha)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
330 | A | Cakeminator | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each time he eats, he chooses a row or a column that does not contain any evil strawberries and contains... | The first line contains two integers *r* and *c* (2<=≤<=*r*,<=*c*<=≤<=10), denoting the number of rows and the number of columns of the cake. The next *r* lines each contains *c* characters — the *j*-th character of the *i*-th line denotes the content of the cell at row *i* and column *j*, and is either one of these:
... | Output the maximum number of cake cells that the cakeminator can eat. | [
"3 4\nS...\n....\n..S.\n"
] | [
"8\n"
] | For the first example, one possible way to eat the maximum number of cake cells is as follows (perform 3 eats). | 500 | [
{
"input": "3 4\nS...\n....\n..S.",
"output": "8"
},
{
"input": "2 2\n..\n..",
"output": "4"
},
{
"input": "2 2\nSS\nSS",
"output": "0"
},
{
"input": "7 3\nS..\nS..\nS..\nS..\nS..\nS..\nS..",
"output": "14"
},
{
"input": "3 5\n..S..\nSSSSS\n..S..",
"output": "... | 1,591,415,399 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 307,200 | def columnas(m):
matrixc=[]
for e in range (0,len(m[0])):
t=[]
for row in m:
t.append(row[e])
matrixc.append(t)
return matrixc
rc=input()
rc=rc.split()
for i in range(0,len(rc)):
rc[i]=int(rc[i])
n=[]
for i in range (0,rc[0]):
data=input()
data=list(data)
... | Title: Cakeminator
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rectangular cake, represented as an *r*<=×<=*c* grid. Each cell either has an evil strawberry, or is empty. For example, a 3<=×<=4 cake may look as follows:
The cakeminator is going to eat the cake! Each ti... | ```python
def columnas(m):
matrixc=[]
for e in range (0,len(m[0])):
t=[]
for row in m:
t.append(row[e])
matrixc.append(t)
return matrixc
rc=input()
rc=rc.split()
for i in range(0,len(rc)):
rc[i]=int(rc[i])
n=[]
for i in range (0,rc[0]):
data=input()
data=li... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,568,149,694 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 310 | 0 | n=int(input())
inp=input().split()
l=[]
for i in range(len(inp)):
l.append(int(inp[i]))
l1=[]
l2=[]
for i in range(len(l)):
if(l[i]%2==0):
l2.append((l[i],i+1))
else:
l1.append((l[i],i+1))
if(len(l2)==1):
print(l2[0][1])
else:
print(l1[0][1]) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
inp=input().split()
l=[]
for i in range(len(inp)):
l.append(int(inp[i]))
l1=[]
l2=[]
for i in range(len(l)):
if(l[i]%2==0):
l2.append((l[i],i+1))
else:
l1.append((l[i],i+1))
if(len(l2)==1):
print(l2[0][1])
else:
print(l1[0][1])
``... | 3.9225 | MatrixStudio/Codeforces-Python-Submissions |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,674,244,001 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n1=list(map(int,input().split()))
n2=list(map(int,input().split()))
alist=[]
for i in range(len(n1)):
if(n1[i]==n2[i]):
x=0
else:
x=1
alist.append(x)
print(alist[1])
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
n1=list(map(int,input().split()))
n2=list(map(int,input().split()))
alist=[]
for i in range(len(n1)):
if(n1[i]==n2[i]):
x=0
else:
x=1
alist.append(x)
print(alist[1])
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,617,970,944 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 62 | 0 | Str = input()
Str1 = input()
NStr = ""
for i in range(len(Str)):
if Str[i]==Str1[i]:
NStr = NStr + '0'
else:
NStr = NStr + '1'
print(NStr)
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
Str = input()
Str1 = input()
NStr = ""
for i in range(len(Str)):
if Str[i]==Str1[i]:
NStr = NStr + '0'
else:
NStr = NStr + '1'
print(NStr)
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers ex... | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at... | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 ... | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,699,246,805 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | n = int(input())
log = []
passengers = 0
max_capacity = 0
for i in range(n):
exits, enters = map(int, input().split())
log.append((exits, enters))
for a in range(n):
passengers -= log[a][0]
passengers += log[a][1]
if passengers > max_capacity:
max_capacity = passengers
prin... | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it ... | ```python
n = int(input())
log = []
passengers = 0
max_capacity = 0
for i in range(n):
exits, enters = map(int, input().split())
log.append((exits, enters))
for a in range(n):
passengers -= log[a][0]
passengers += log[a][1]
if passengers > max_capacity:
max_capacity = passenge... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-s... | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,688,397,122 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 | a = input()
count = 0
for i in range(len(a)):
if a[i] == "H" or a[i] == "Q" or a[i] == "9":
count += 1
if count >= 1:
print("YES")
else:
print("NO") | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" in... | ```python
a = input()
count = 0
for i in range(len(a)):
if a[i] == "H" or a[i] == "Q" or a[i] == "9":
count += 1
if count >= 1:
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
777 | B | Game of Credit Cards | PROGRAMMING | 1,300 | [
"data structures",
"dp",
"greedy",
"sortings"
] | null | null | After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simple: each player bring his favourite *n*-digit credit card. Then both players name the digits written on the... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits in the cards Sherlock and Moriarty are going to use.
The second line contains *n* digits — Sherlock's credit card number.
The third line contains *n* digits — Moriarty's credit card number. | First print the minimum possible number of flicks Moriarty will get. Then print the maximum possible number of flicks that Sherlock can get from Moriarty. | [
"3\n123\n321\n",
"2\n88\n00\n"
] | [
"0\n2\n",
"2\n0\n"
] | First sample is elaborated in the problem statement. In the second sample, there is no way Moriarty can avoid getting two flicks. | 1,000 | [
{
"input": "3\n123\n321",
"output": "0\n2"
},
{
"input": "2\n88\n00",
"output": "2\n0"
},
{
"input": "1\n4\n5",
"output": "0\n1"
},
{
"input": "1\n8\n7",
"output": "1\n0"
},
{
"input": "2\n55\n55",
"output": "0\n0"
},
{
"input": "3\n534\n432",
"out... | 1,488,093,648 | 2,147,483,647 | Python 3 | OK | TESTS | 55 | 62 | 4,608,000 | n=int(input())
a=list(sorted(input()))
b=list(sorted(input()))
j=0
for i in b:
if i >=a[j]:
j+=1
print(len(a)-j)#minimum number of flicks
k=0
for i in b:
if i>a[k]:
k+=1
print(k)#maximum number of flicks | Title: Game of Credit Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simpl... | ```python
n=int(input())
a=list(sorted(input()))
b=list(sorted(input()))
j=0
for i in b:
if i >=a[j]:
j+=1
print(len(a)-j)#minimum number of flicks
k=0
for i in b:
if i>a[k]:
k+=1
print(k)#maximum number of flicks
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,467,118,494 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 62 | 0 | n = int(input())
for i in range(1, abs(8888888888 - n) + 1):
if any(x == '8' for x in str(n + i)):
print(i)
exit(0)
print(-1)
| Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
n = int(input())
for i in range(1, abs(8888888888 - n) + 1):
if any(x == '8' for x in str(n + i)):
print(i)
exit(0)
print(-1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,650,449,458 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | a = str(input())
one= 0
four= 0
fourcan = False
maxfour= 0
yes=True
for i in a:
if i == "1":
maxfour = four
fourcan = True
four = 0
if i == "4" and not fourcan:
print("NO")
yes = False
break;
if i =="4":
four+=1
fourcan = False
if maxfour >= 3:
yes = False
print("NO")
... | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
a = str(input())
one= 0
four= 0
fourcan = False
maxfour= 0
yes=True
for i in a:
if i == "1":
maxfour = four
fourcan = True
four = 0
if i == "4" and not fourcan:
print("NO")
yes = False
break;
if i =="4":
four+=1
fourcan = False
if maxfour >= 3:
yes = False
pri... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,675,157,214 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n , k = map(int, input().split())
t = 240 - k
s = 0
a = 0
for i in range(1,9,1):
s+=i*5
if s > t:
a = i-1
break
print(a) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
n , k = map(int, input().split())
t = 240 - k
s = 0
a = 0
for i in range(1,9,1):
s+=i*5
if s > t:
a = i-1
break
print(a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
758 | A | Holiday Of Equality | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens, the welfare of each of them is estimated as the integer in *a**i* burles (burle is the currency in Berl... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100) — the number of citizens in the kingdom.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n*, where *a**i* (0<=≤<=*a**i*<=≤<=106) — the welfare of the *i*-th citizen. | In the only line print the integer *S* — the minimum number of burles which are had to spend. | [
"5\n0 1 2 3 4\n",
"5\n1 1 0 1 1\n",
"3\n1 3 1\n",
"1\n12\n"
] | [
"10",
"1",
"4",
"0"
] | In the first example if we add to the first citizen 4 burles, to the second 3, to the third 2 and to the fourth 1, then the welfare of all citizens will equal 4.
In the second example it is enough to give one burle to the third citizen.
In the third example it is necessary to give two burles to the first and the thi... | 500 | [
{
"input": "5\n0 1 2 3 4",
"output": "10"
},
{
"input": "5\n1 1 0 1 1",
"output": "1"
},
{
"input": "3\n1 3 1",
"output": "4"
},
{
"input": "1\n12",
"output": "0"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "14\n52518 718438 358883 462189 853... | 1,699,096,839 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | a=list(map(int,input().split()))
max=0
for i in a:
if max<i:
max=i
sum=0
for i in a:
sum+=max-i
print(sum,max) | Title: Holiday Of Equality
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Berland it is the holiday of equality. In honor of the holiday the king decided to equalize the welfare of all citizens in Berland by the expense of the state treasury.
Totally in Berland there are *n* citizens... | ```python
a=list(map(int,input().split()))
max=0
for i in a:
if max<i:
max=i
sum=0
for i in a:
sum+=max-i
print(sum,max)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
441 | B | Valera and Fruits | PROGRAMMING | 1,400 | [
"greedy",
"implementation"
] | null | null | Valera loves his garden, where *n* fruit trees grow.
This year he will enjoy a great harvest! On the *i*-th tree *b**i* fruit grow, they will ripen on a day number *a**i*. Unfortunately, the fruit on the tree get withered, so they can only be collected on day *a**i* and day *a**i*<=+<=1 (all fruits that are not collec... | The first line contains two space-separated integers *n* and *v* (1<=≤<=*n*,<=*v*<=≤<=3000) — the number of fruit trees in the garden and the number of fruits that Valera can collect in a day.
Next *n* lines contain the description of trees in the garden. The *i*-th line contains two space-separated integers *a**i* a... | Print a single integer — the maximum number of fruit that Valera can collect. | [
"2 3\n1 5\n2 3\n",
"5 10\n3 20\n2 20\n1 20\n4 20\n5 20\n"
] | [
"8\n",
"60\n"
] | In the first sample, in order to obtain the optimal answer, you should act as follows.
- On the first day collect 3 fruits from the 1-st tree. - On the second day collect 1 fruit from the 2-nd tree and 2 fruits from the 1-st tree. - On the third day collect the remaining fruits from the 2-nd tree.
In the second s... | 1,000 | [
{
"input": "2 3\n1 5\n2 3",
"output": "8"
},
{
"input": "5 10\n3 20\n2 20\n1 20\n4 20\n5 20",
"output": "60"
},
{
"input": "10 3000\n1 2522\n4 445\n8 1629\n5 772\n9 2497\n6 81\n3 426\n7 1447\n2 575\n10 202",
"output": "10596"
},
{
"input": "5 3000\n5 772\n1 2522\n2 575\n4 445... | 1,632,497,732 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 25 | 171 | 23,859,200 | [n, v] = map(int, input().split())
# available_days = set()
# m = {}
# for _ in range(n):
# a, b = map(int, input().split())
# if a not in m:
# m[a] = 0
# m[a] += b
m = [0] * (n+2)
for _ in range(n):
a, b = map(int, input().split())
# if a not in m:
# m[a] = 0
... | Title: Valera and Fruits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera loves his garden, where *n* fruit trees grow.
This year he will enjoy a great harvest! On the *i*-th tree *b**i* fruit grow, they will ripen on a day number *a**i*. Unfortunately, the fruit on the tree get wit... | ```python
[n, v] = map(int, input().split())
# available_days = set()
# m = {}
# for _ in range(n):
# a, b = map(int, input().split())
# if a not in m:
# m[a] = 0
# m[a] += b
m = [0] * (n+2)
for _ in range(n):
a, b = map(int, input().split())
# if a not in m:
# ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
389 | A | Fox and Number Game | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | null | null | Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that *x**i* > *x**j* hold, and then apply assignment *x**i* = *x**i* - *x**j*. The goal is to make the sum ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100). Then the second line contains *n* integers: *x*1, *x*2, ..., *x**n* (1<=≤<=*x**i*<=≤<=100). | Output a single integer — the required minimal sum. | [
"2\n1 2\n",
"3\n2 4 6\n",
"2\n12 18\n",
"5\n45 12 27 30 18\n"
] | [
"2\n",
"6\n",
"12\n",
"15\n"
] | In the first example the optimal way is to do the assignment: *x*<sub class="lower-index">2</sub> = *x*<sub class="lower-index">2</sub> - *x*<sub class="lower-index">1</sub>.
In the second example the optimal sequence of operations is: *x*<sub class="lower-index">3</sub> = *x*<sub class="lower-index">3</sub> - *x*<sub... | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n2 4 6",
"output": "6"
},
{
"input": "2\n12 18",
"output": "12"
},
{
"input": "5\n45 12 27 30 18",
"output": "15"
},
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n100 100",
"output": "200"
... | 1,462,890,182 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 77 | 5,222,400 | n=int(input())
x=[int(i) for i in input().split()]
x.sort()
def f(x,y):
for i in range(1,x+1):
if x%i==0 and y%i==0:
m=i
return m
a=f(x[0],x[1])
for i in range(2,len(x)):
a=f(a,x[i])
print(n*a)
| Title: Fox and Number Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel is playing a game with numbers now.
Ciel has *n* positive integers: *x*1, *x*2, ..., *x**n*. She can do the following operation as many times as needed: select two different indexes *i* and *j* such that ... | ```python
n=int(input())
x=[int(i) for i in input().split()]
x.sort()
def f(x,y):
for i in range(1,x+1):
if x%i==0 and y%i==0:
m=i
return m
a=f(x[0],x[1])
for i in range(2,len(x)):
a=f(a,x[i])
print(n*a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
322 | A | Ciel and Dancing | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room. | In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*. | [
"2 1\n",
"2 2\n"
] | [
"2\n1 1\n2 1\n",
"3\n1 1\n1 2\n2 2\n"
] | In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | 500 | [
{
"input": "2 1",
"output": "2\n1 1\n2 1"
},
{
"input": "2 2",
"output": "3\n1 1\n1 2\n2 2"
},
{
"input": "1 1",
"output": "1\n1 1"
},
{
"input": "2 3",
"output": "4\n1 1\n1 2\n1 3\n2 3"
},
{
"input": "4 4",
"output": "7\n1 1\n1 2\n1 3\n1 4\n4 4\n3 4\n2 4"
}... | 1,623,824,289 | 2,147,483,647 | PyPy 3 | OK | TESTS | 28 | 216 | 0 | n, m = map(int, input().split())
print(n + m - 1)
print(1, 1)
for i in range(2, m+1):
print(1, i)
for i in range(2, n+1):
print(i, 1)
| Title: Ciel and Dancing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. B... | ```python
n, m = map(int, input().split())
print(n + m - 1)
print(1, 1)
for i in range(2, m+1):
print(1, i)
for i in range(2, n+1):
print(i, 1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
897 | A | Scarborough Fair | PROGRAMMING | 800 | [
"implementation"
] | null | null | Parsley, sage, rosemary and thyme.
Remember me to one who lives there.
He once was the true love of mine.
Willem is taking the girl to the highest building in island No.28, however, neither of them knows how to get there.
Willem asks his friend, Grick for directions, Grick helped them, and gave them a task.
Althou... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
The second line contains a string *s* of length *n*, consisting of lowercase English letters.
Each of the next *m* lines contains four parameters *l*,<=*r*,<=*c*1,<=*c*2 (1<=≤<=*l*<=≤<=*r*<=≤<=*n*, *c*1,<=*c*2 are lowercase English letters), ... | Output string *s* after performing *m* operations described above. | [
"3 1\nioi\n1 1 i n\n",
"5 3\nwxhak\n3 3 h x\n1 5 x a\n1 3 w g\n"
] | [
"noi",
"gaaak"
] | For the second example:
After the first operation, the string is wxxak.
After the second operation, the string is waaak.
After the third operation, the string is gaaak. | 500 | [
{
"input": "3 1\nioi\n1 1 i n",
"output": "noi"
},
{
"input": "5 3\nwxhak\n3 3 h x\n1 5 x a\n1 3 w g",
"output": "gaaak"
},
{
"input": "9 51\nbhfbdcgff\n2 3 b b\n2 8 e f\n3 8 g f\n5 7 d a\n1 5 e b\n3 4 g b\n6 7 c d\n3 6 e g\n3 6 e h\n5 6 a e\n7 9 a c\n4 9 a h\n3 7 c b\n6 9 b g\n1 7 h b\n... | 1,530,619,159 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 109 | 307,200 | n, m = map(int, input().split())
s = input()
for t in range(m):
l, r, c1, c2 = input().split()
l, r = int(l), int(r)
s_left = s[:l - 1]
s_right = s[r:]
s_mid = s[l - 1:r]
#print(">{},{},{}<".format(s_left, s_mid, s_right))
s_mid = s_mid.replace(c1, c2)
#print(">{},{},{}<".f... | Title: Scarborough Fair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Parsley, sage, rosemary and thyme.
Remember me to one who lives there.
He once was the true love of mine.
Willem is taking the girl to the highest building in island No.28, however, neither of them knows how to get ... | ```python
n, m = map(int, input().split())
s = input()
for t in range(m):
l, r, c1, c2 = input().split()
l, r = int(l), int(r)
s_left = s[:l - 1]
s_right = s[r:]
s_mid = s[l - 1:r]
#print(">{},{},{}<".format(s_left, s_mid, s_right))
s_mid = s_mid.replace(c1, c2)
#print(">{}... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
169 | A | Chores | PROGRAMMING | 800 | [
"sortings"
] | null | null | Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*.
As Petya is older, he wants to take the chores with complexit... | The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores.
The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* ... | Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. | [
"5 2 3\n6 2 3 100 1\n",
"7 3 4\n1 1 9 1 1 1 1\n"
] | [
"3\n",
"0\n"
] | In the first sample the possible values of *x* are 3, 4 or 5.
In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4. | 500 | [
{
"input": "5 2 3\n6 2 3 100 1",
"output": "3"
},
{
"input": "7 3 4\n1 1 9 1 1 1 1",
"output": "0"
},
{
"input": "2 1 1\n10 2",
"output": "8"
},
{
"input": "2 1 1\n7 7",
"output": "0"
},
{
"input": "2 1 1\n1 1000000000",
"output": "999999999"
},
{
"inp... | 1,622,304,829 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 77 | 0 | n,a,b=map(int,input().split())
l=list(sorted(map(int,input().split())))
for i in range(n):
if i==b-1:
print(abs(l[i]-l[i+1]))
break
| Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of th... | ```python
n,a,b=map(int,input().split())
l=list(sorted(map(int,input().split())))
for i in range(n):
if i==b-1:
print(abs(l[i]-l[i+1]))
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,677,965,912 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | s=input()
if(s.count("l")>=2):
if(s.index("h")<s.index("e")<s.index("l")<s.index("o")):
s.reverse()
if(s.index("l")>s.index("o")):
print("YES")
else:
print("NO")
else:
print("NO")
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s=input()
if(s.count("l")>=2):
if(s.index("h")<s.index("e")<s.index("l")<s.index("o")):
s.reverse()
if(s.index("l")>s.index("o")):
print("YES")
else:
print("NO")
else:
print("NO")
else:
print("NO")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,653,456,665 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int main()
{
string s, t;
cin >> s >> t;
reverse(t.begin(), t.end());
if (s == t)
{
cout << "YES" << endl;
}
else
{
cout << "NO" << endl;
}
return 0;
}
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
#include <bits/stdc++.h>
using namespace std;
int main()
{
string s, t;
cin >> s >> t;
reverse(t.begin(), t.end());
if (s == t)
{
cout << "YES" << endl;
}
else
{
cout << "NO" << endl;
}
return 0;
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions |
169 | A | Chores | PROGRAMMING | 800 | [
"sortings"
] | null | null | Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of the *i*-th chore equals *h**i*.
As Petya is older, he wants to take the chores with complexit... | The first input line contains three integers *n*,<=*a* and *b* (2<=≤<=*n*<=≤<=2000; *a*,<=*b*<=≥<=1; *a*<=+<=*b*<==<=*n*) — the total number of chores, the number of Petya's chores and the number of Vasya's chores.
The next line contains a sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=109), *h**i* ... | Print the required number of ways to choose an integer value of *x*. If there are no such ways, print 0. | [
"5 2 3\n6 2 3 100 1\n",
"7 3 4\n1 1 9 1 1 1 1\n"
] | [
"3\n",
"0\n"
] | In the first sample the possible values of *x* are 3, 4 or 5.
In the second sample it is impossible to find such *x*, that Petya got 3 chores and Vasya got 4. | 500 | [
{
"input": "5 2 3\n6 2 3 100 1",
"output": "3"
},
{
"input": "7 3 4\n1 1 9 1 1 1 1",
"output": "0"
},
{
"input": "2 1 1\n10 2",
"output": "8"
},
{
"input": "2 1 1\n7 7",
"output": "0"
},
{
"input": "2 1 1\n1 1000000000",
"output": "999999999"
},
{
"inp... | 1,666,091,348 | 2,147,483,647 | PyPy 3 | OK | TESTS | 29 | 77 | 1,331,200 | n, a, b =map(int, input().split())
h = list(map(int, input().split()))
h.sort()
print(abs(h[b-1]-h[b])) | Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya are brothers. Today is a special day for them as their parents left them home alone and commissioned them to do *n* chores. Each chore is characterized by a single parameter — its complexity. The complexity of th... | ```python
n, a, b =map(int, input().split())
h = list(map(int, input().split()))
h.sort()
print(abs(h[b-1]-h[b]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
472 | A | Design Tutorial: Learn from Math | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statement called the "Goldbach's conjecture". It says: "each even number no less than four can be expressed as the sum of two ... | The only line contains an integer *n* (12<=≤<=*n*<=≤<=106). | Output two composite integers *x* and *y* (1<=<<=*x*,<=*y*<=<<=*n*) such that *x*<=+<=*y*<==<=*n*. If there are multiple solutions, you can output any of them. | [
"12\n",
"15\n",
"23\n",
"1000000\n"
] | [
"4 8\n",
"6 9\n",
"8 15\n",
"500000 500000\n"
] | In the first example, 12 = 4 + 8 and both 4, 8 are composite numbers. You can output "6 6" or "8 4" as well.
In the second example, 15 = 6 + 9. Note that you can't output "1 14" because 1 is not a composite number. | 500 | [
{
"input": "12",
"output": "4 8"
},
{
"input": "15",
"output": "6 9"
},
{
"input": "23",
"output": "8 15"
},
{
"input": "1000000",
"output": "500000 500000"
},
{
"input": "63874",
"output": "4 63870"
},
{
"input": "14568",
"output": "4 14564"
},
... | 1,667,481,848 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 77 | 0 | n=int(input())
def win(a):
for i in range(2,a//2+1):
if a%i==0:
return True
for j in range(2,n//2+1):
if win(j):
if win(n-j):
print(j,n-j)
break
| Title: Design Tutorial: Learn from Math
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One way to create a task is to learn from math. You can generate some random math statement or modify some theorems to get something new and build a new task from that.
For example, there is a statemen... | ```python
n=int(input())
def win(a):
for i in range(2,a//2+1):
if a%i==0:
return True
for j in range(2,n//2+1):
if win(j):
if win(n-j):
print(j,n-j)
break
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
581 | A | Vasya the Hipster | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.
Every day Vasya puts on new socks in the morning ... | The single line of the input contains two positive integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=100) — the number of red and blue socks that Vasya's got. | Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.
Keep in mind that at the end of the day Vasya throws away the socks that he'... | [
"3 1\n",
"2 3\n",
"7 3\n"
] | [
"1 1\n",
"2 0\n",
"3 2\n"
] | In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day. | 500 | [
{
"input": "3 1",
"output": "1 1"
},
{
"input": "2 3",
"output": "2 0"
},
{
"input": "7 3",
"output": "3 2"
},
{
"input": "100 100",
"output": "100 0"
},
{
"input": "4 10",
"output": "4 3"
},
{
"input": "6 10",
"output": "6 2"
},
{
"input":... | 1,667,714,836 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 61 | 0 | a,b=map(int,input().split())
s=min(a,b)
a-=s
b-=s
l=((max(a,b))//2)
print(s,l) | Title: Vasya the Hipster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya the Hipster decided to count how many socks he had. It turned out that he had *a* red socks and *b* blue socks.
According to the latest fashion, hipsters should wear the socks of different colors: a red... | ```python
a,b=map(int,input().split())
s=min(a,b)
a-=s
b-=s
l=((max(a,b))//2)
print(s,l)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,682,272,509 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | a = int(input(),2)
b = int(input(),2)
num = a^b
print(bin(num)[2:]) | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
a = int(input(),2)
b = int(input(),2)
num = a^b
print(bin(num)[2:])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do... | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,696,323,716 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 102 | 62 | 0 | str1 = input()
str2 = input()
strout = []
n = len(str1)
for i in range(n):
if str1[i]!=str2[i]:
strout.append('1')
else:
strout.append('0')
print(*strout, sep = "") | Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 10... | ```python
str1 = input()
str2 = input()
strout = []
n = len(str1)
for i in range(n):
if str1[i]!=str2[i]:
strout.append('1')
else:
strout.append('0')
print(*strout, sep = "")
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
845 | B | Luba And The Ticket | PROGRAMMING | 1,600 | [
"brute force",
"greedy",
"implementation"
] | null | null | Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make the ticket lucky.
The ticket is considered lucky if the sum of first three digits equals to the sum of las... | You are given a string consisting of 6 characters (all characters are digits from 0 to 9) — this string denotes Luba's ticket. The ticket can start with the digit 0. | Print one number — the minimum possible number of digits Luba needs to replace to make the ticket lucky. | [
"000000\n",
"123456\n",
"111000\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first example the ticket is already lucky, so the answer is 0.
In the second example Luba can replace 4 and 5 with zeroes, and the ticket will become lucky. It's easy to see that at least two replacements are required.
In the third example Luba can replace any zero with 3. It's easy to see that at least one re... | 0 | [
{
"input": "000000",
"output": "0"
},
{
"input": "123456",
"output": "2"
},
{
"input": "111000",
"output": "1"
},
{
"input": "120111",
"output": "0"
},
{
"input": "999999",
"output": "0"
},
{
"input": "199880",
"output": "1"
},
{
"input": "... | 1,503,332,015 | 4,115 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | import sys
ticket = input()
first_sum = sum(map(int, ticket[:2]))
second_sum = sum(map(int, ticket[3:]))
first_num_changes = 0
second_num_changes = 0
fnum = first_sum
snum = second_sum
res = []
flag = 1
if first_sum == second_sum:
print(0)
sys.exit(0)
while True:
if flag == 1:
... | Title: Luba And The Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has a ticket consisting of 6 digits. In one move she can choose digit in any position and replace it with arbitrary digit. She wants to know the minimum number of digits she needs to replace in order to make th... | ```python
import sys
ticket = input()
first_sum = sum(map(int, ticket[:2]))
second_sum = sum(map(int, ticket[3:]))
first_num_changes = 0
second_num_changes = 0
fnum = first_sum
snum = second_sum
res = []
flag = 1
if first_sum == second_sum:
print(0)
sys.exit(0)
while True:
if fla... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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