contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
878 | A | Short Program | PROGRAMMING | 1,600 | [
"bitmasks",
"constructive algorithms"
] | null | null | Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=5·105) — the number of lines.
Next *n* lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant *x**i* 0<=≤<=*x**i*<=≤<=1023. | Output an integer *k* (0<=≤<=*k*<=≤<=5) — the length of your program.
Next *k* lines must contain commands in the same format as in the input. | [
"3\n| 3\n^ 2\n| 1\n",
"3\n& 1\n& 3\n& 5\n",
"3\n^ 1\n^ 2\n^ 3\n"
] | [
"2\n| 3\n^ 2\n",
"1\n& 1\n",
"0\n"
] | You can read about bitwise operations in [https://en.wikipedia.org/wiki/Bitwise_operation](https://en.wikipedia.org/wiki/Bitwise_operation).
Second sample:
Let *x* be an input of the Petya's program. It's output is ((*x*&1)&3)&5 = *x*&(1&3&5) = *x*&1. So these two programs always give the ... | 500 | [
{
"input": "3\n| 3\n^ 2\n| 1",
"output": "2\n| 3\n^ 2"
},
{
"input": "3\n& 1\n& 3\n& 5",
"output": "1\n& 1"
},
{
"input": "3\n^ 1\n^ 2\n^ 3",
"output": "0"
},
{
"input": "2\n| 999\n^ 689",
"output": "2\n| 999\n^ 689"
},
{
"input": "3\n& 242\n^ 506\n^ 522",
"ou... | 1,509,225,186 | 6,785 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n = int(input('Input the value of ' + '"n": \n'))
ands = False
ors = False
xors = False
ands_value = 1024
ors_value = 0
xors_value = 1024
count = 0
# AND: track min value
# OR: track max value
# XOR: track lowest value - 1
print('Input data: \n')
for i in range(n):
v1, v2 = input('').split()
... | Title: Short Program
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitw... | ```python
n = int(input('Input the value of ' + '"n": \n'))
ands = False
ors = False
xors = False
ands_value = 1024
ors_value = 0
xors_value = 1024
count = 0
# AND: track min value
# OR: track max value
# XOR: track lowest value - 1
print('Input data: \n')
for i in range(n):
v1, v2 = input('').sp... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
810 | B | Summer sell-off | PROGRAMMING | 1,300 | [
"greedy",
"sortings"
] | null | null | Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an assistant.
Shop, where Noora is working, has a plan on the following *n* days. For each day sales manag... | The first line contains two integers *n* and *f* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*f*<=≤<=*n*) denoting the number of days in shop's plan and the number of days that Noora has to choose for sell-out.
Each line of the following *n* subsequent lines contains two integers *k**i*,<=*l**i* (0<=≤<=*k**i*,<=*l**i*<=≤<=109) denotin... | Print a single integer denoting the maximal number of products that shop can sell. | [
"4 2\n2 1\n3 5\n2 3\n1 5\n",
"4 1\n0 2\n0 3\n3 5\n0 6\n"
] | [
"10",
"5"
] | In the first example we can choose days with numbers 2 and 4 for sell-out. In this case new numbers of products for sale would be equal to [2, 6, 2, 2] respectively. So on the first day shop will sell 1 product, on the second — 5, on the third — 2, on the fourth — 2. In total 1 + 5 + 2 + 2 = 10 product units.
In the s... | 1,000 | [
{
"input": "4 2\n2 1\n3 5\n2 3\n1 5",
"output": "10"
},
{
"input": "4 1\n0 2\n0 3\n3 5\n0 6",
"output": "5"
},
{
"input": "1 1\n5 8",
"output": "8"
},
{
"input": "2 1\n8 12\n6 11",
"output": "19"
},
{
"input": "2 1\n6 7\n5 7",
"output": "13"
},
{
"inpu... | 1,680,971,678 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 109 | 1,843,200 | n, f = map(int, input().split())
days = []
for i in range(n):
product, client = map(int, input().split())
if product != 0:
days.append([product, client])
days.sort(key=lambda x: -x[1])
sell = 0
for i in range(f):
days[i][0] *= 2
sell += min(days[i])
for k in range(f, len(day... | Title: Summer sell-off
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an ass... | ```python
n, f = map(int, input().split())
days = []
for i in range(n):
product, client = map(int, input().split())
if product != 0:
days.append([product, client])
days.sort(key=lambda x: -x[1])
sell = 0
for i in range(f):
days[i][0] *= 2
sell += min(days[i])
for k in range(... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero,... | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,696,252,712 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 11 | 61 | 0 | def subtract_k_times(n, k):
while k > 0:
if n % 10 == 0:
n //= 10 # Remove the last digit
else:
n -= 1 # Subtract 1
k -= 1
return n
# Read input
n, k = map(int, input().split())
# Perform k subtractions
result = subtract_k_times(n, k)
# Print t... | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit ... | ```python
def subtract_k_times(n, k):
while k > 0:
if n % 10 == 0:
n //= 10 # Remove the last digit
else:
n -= 1 # Subtract 1
k -= 1
return n
# Read input
n, k = map(int, input().split())
# Perform k subtractions
result = subtract_k_times(n, k)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
266 | B | Queue at the School | PROGRAMMING | 800 | [
"constructive algorithms",
"graph matchings",
"implementation",
"shortest paths"
] | null | null | During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling awkward for standing in front of the girls in the queue and they started letting the girls move forward ea... | The first line contains two integers *n* and *t* (1<=≤<=*n*,<=*t*<=≤<=50), which represent the number of children in the queue and the time after which the queue will transform into the arrangement you need to find.
The next line contains string *s*, which represents the schoolchildren's initial arrangement. If the *... | Print string *a*, which describes the arrangement after *t* seconds. If the *i*-th position has a boy after the needed time, then the *i*-th character *a* must equal "B", otherwise it must equal "G". | [
"5 1\nBGGBG\n",
"5 2\nBGGBG\n",
"4 1\nGGGB\n"
] | [
"GBGGB\n",
"GGBGB\n",
"GGGB\n"
] | none | 500 | [
{
"input": "5 1\nBGGBG",
"output": "GBGGB"
},
{
"input": "5 2\nBGGBG",
"output": "GGBGB"
},
{
"input": "4 1\nGGGB",
"output": "GGGB"
},
{
"input": "2 1\nBB",
"output": "BB"
},
{
"input": "2 1\nBG",
"output": "GB"
},
{
"input": "6 2\nBBGBBG",
"outpu... | 1,695,071,577 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import java.util.Scanner;
class Main {
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
String[] l = sc.nextLine().split(" ");
int t = Integer.parseInt(l[1]);
String s = sc.nextLine();
System.out.println(tr(s,t));
}
static String tr(String s, int t){
... | Title: Queue at the School
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the break the schoolchildren, boys and girls, formed a queue of *n* people in the canteen. Initially the children stood in the order they entered the canteen. However, after a while the boys started feeling a... | ```python
import java.util.Scanner;
class Main {
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
String[] l = sc.nextLine().split(" ");
int t = Integer.parseInt(l[1]);
String s = sc.nextLine();
System.out.println(tr(s,t));
}
static String tr(String s, ... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
659 | A | Round House | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance *a* and he decided that during his walk he will move around the house *b* entrances in th... | The single line of the input contains three space-separated integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*a*<=≤<=*n*,<=<=-<=100<=≤<=*b*<=≤<=100) — the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively. | Print a single integer *k* (1<=≤<=*k*<=≤<=*n*) — the number of the entrance where Vasya will be at the end of his walk. | [
"6 2 -5\n",
"5 1 3\n",
"3 2 7\n"
] | [
"3\n",
"4\n",
"3\n"
] | The first example is illustrated by the picture in the statements. | 500 | [
{
"input": "6 2 -5",
"output": "3"
},
{
"input": "5 1 3",
"output": "4"
},
{
"input": "3 2 7",
"output": "3"
},
{
"input": "1 1 0",
"output": "1"
},
{
"input": "1 1 -1",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "100 ... | 1,680,315,512 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 31 | 0 | '''
1 Habib_2010
2 ___Hafizullo___
3 Cyber_Snake
4 mr.itmo
5 I_am_Naruto
6 JahongirLucifer
7 _Habibolloh_
'''
n, a, b = map(int, input().split())
a = abs(a + b) % n
print(a if a else n)
| Title: Round House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in e... | ```python
'''
1 Habib_2010
2 ___Hafizullo___
3 Cyber_Snake
4 mr.itmo
5 I_am_Naruto
6 JahongirLucifer
7 _Habibolloh_
'''
n, a, b = map(int, input().split())
a = abs(a + b) % n
print(a if a else n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
831 | C | Jury Marks | PROGRAMMING | 1,700 | [
"brute force",
"constructive algorithms"
] | null | null | Polycarp watched TV-show where *k* jury members one by one rated a participant by adding him a certain number of points (may be negative, i. e. points were subtracted). Initially the participant had some score, and each the marks were one by one added to his score. It is known that the *i*-th jury member gave *a**i* po... | The first line contains two integers *k* and *n* (1<=≤<=*n*<=≤<=*k*<=≤<=2<=000) — the number of jury members and the number of scores Polycarp remembers.
The second line contains *k* integers *a*1,<=*a*2,<=...,<=*a**k* (<=-<=2<=000<=≤<=*a**i*<=≤<=2<=000) — jury's marks in chronological order.
The third line contains ... | Print the number of options for the score the participant could have before the judges rated the participant. If Polycarp messes something up and there is no options, print "0" (without quotes). | [
"4 1\n-5 5 0 20\n10\n",
"2 2\n-2000 -2000\n3998000 4000000\n"
] | [
"3\n",
"1\n"
] | The answer for the first example is 3 because initially the participant could have - 10, 10 or 15 points.
In the second example there is only one correct initial score equaling to 4 002 000. | 1,000 | [
{
"input": "4 1\n-5 5 0 20\n10",
"output": "3"
},
{
"input": "2 2\n-2000 -2000\n3998000 4000000",
"output": "1"
},
{
"input": "1 1\n-577\n1273042",
"output": "1"
},
{
"input": "2 1\n614 -1943\n3874445",
"output": "2"
},
{
"input": "3 1\n1416 -1483 1844\n3261895",
... | 1,667,713,723 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 57 | 560 | 10,752,000 | k, n = list(map(int, input().split()))
a = list(map(int, input().split()))
b = list(map(int, input().split()))
pre = [a[0]]
for i in range(1, k):
pre.append(pre[i - 1] + a[i])
poss = set()
for i in pre:
x = b[0] - i # x is the intial point
poss.add(x)
ans = 0
for i in poss:
l = set()
... | Title: Jury Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp watched TV-show where *k* jury members one by one rated a participant by adding him a certain number of points (may be negative, i. e. points were subtracted). Initially the participant had some score, and each the ... | ```python
k, n = list(map(int, input().split()))
a = list(map(int, input().split()))
b = list(map(int, input().split()))
pre = [a[0]]
for i in range(1, k):
pre.append(pre[i - 1] + a[i])
poss = set()
for i in pre:
x = b[0] - i # x is the intial point
poss.add(x)
ans = 0
for i in poss:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,695,866,230 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 31 | 0 | def find_subsequence(s):
target = "hello"
i = 0
for char in s:
if char == target[i]:
i += 1
if i == len(target):
return "YES"
return "NO"
# 从标准输入读取输入字符串
s = input()
# 调用函数并打印结果
result = find_subsequence(s)
print(result)
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
def find_subsequence(s):
target = "hello"
i = 0
for char in s:
if char == target[i]:
i += 1
if i == len(target):
return "YES"
return "NO"
# 从标准输入读取输入字符串
s = input()
# 调用函数并打印结果
result = find_subsequence(s)
print(result)
``` | 3.9845 | MatrixStudio/Codeforces-Python-Submissions |
0 | none | none | none | 0 | [
"none"
] | null | null | Two positive integers *a* and *b* have a sum of *s* and a bitwise XOR of *x*. How many possible values are there for the ordered pair (*a*,<=*b*)? | The first line of the input contains two integers *s* and *x* (2<=≤<=*s*<=≤<=1012, 0<=≤<=*x*<=≤<=1012), the sum and bitwise xor of the pair of positive integers, respectively. | Print a single integer, the number of solutions to the given conditions. If no solutions exist, print 0. | [
"9 5\n",
"3 3\n",
"5 2\n"
] | [
"4\n",
"2\n",
"0\n"
] | In the first sample, we have the following solutions: (2, 7), (3, 6), (6, 3), (7, 2).
In the second sample, the only solutions are (1, 2) and (2, 1). | 0 | [
{
"input": "9 5",
"output": "4"
},
{
"input": "3 3",
"output": "2"
},
{
"input": "5 2",
"output": "0"
},
{
"input": "6 0",
"output": "1"
},
{
"input": "549755813887 549755813887",
"output": "549755813886"
},
{
"input": "2 0",
"output": "1"
},
{... | 1,456,687,280 | 4,280 | Python 3 | OK | TESTS | 71 | 62 | 0 | def solve1(s, x):
if x == 0:
if s % 2 == 0:
return 1
else:
return 0
else:
b = (s + x) // 2
a = s - b
if a + b == s and a ^ b == x:
pw = 0
full = (s == x)
for i in range(60):
if x & (1 << i) != 0:
pw += 1
if 2 ** i - 1 == s:
full = True
ans = 2 ** pw
if full:
ans -=... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two positive integers *a* and *b* have a sum of *s* and a bitwise XOR of *x*. How many possible values are there for the ordered pair (*a*,<=*b*)?
Input Specification:
The first line of the input contains two integers *s* and *x*... | ```python
def solve1(s, x):
if x == 0:
if s % 2 == 0:
return 1
else:
return 0
else:
b = (s + x) // 2
a = s - b
if a + b == s and a ^ b == x:
pw = 0
full = (s == x)
for i in range(60):
if x & (1 << i) != 0:
pw += 1
if 2 ** i - 1 == s:
full = True
ans = 2 ** pw
if full:
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
681 | B | Economy Game | PROGRAMMING | 1,300 | [
"brute force"
] | null | null | Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, that he found out his game-coin score become equal to 0.
Kolya remembers that at the beginning of the game his game-coin score was equal to *n* and that ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=109) — Kolya's initial game-coin score. | Print "YES" (without quotes) if it's possible that Kolya spent all of his initial *n* coins buying only houses, cars and computers. Otherwise print "NO" (without quotes). | [
"1359257\n",
"17851817\n"
] | [
"YES",
"NO"
] | In the first sample, one of the possible solutions is to buy one house, one car and one computer, spending 1 234 567 + 123 456 + 1234 = 1 359 257 game-coins in total. | 1,000 | [
{
"input": "1359257",
"output": "YES"
},
{
"input": "17851817",
"output": "NO"
},
{
"input": "1000000000",
"output": "YES"
},
{
"input": "17851818",
"output": "YES"
},
{
"input": "438734347",
"output": "YES"
},
{
"input": "43873430",
"output": "YES... | 1,584,140,609 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 0 | x = int(input())
a, b, c = 0, 0, 0
while(x >= 123456):
if(x > 1234567):
x -= 1234567
a += 1
elif(x >= 123456):
x -= 123456
b += 1
if(x > 0 and x % 1234 == 0):
print('YES')
else:
print('NO') | Title: Economy Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, that he found out his game-coin score become equal to 0.... | ```python
x = int(input())
a, b, c = 0, 0, 0
while(x >= 123456):
if(x > 1234567):
x -= 1234567
a += 1
elif(x >= 123456):
x -= 123456
b += 1
if(x > 0 and x % 1234 == 0):
print('YES')
else:
print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
267 | A | Subtractions | PROGRAMMING | 900 | [
"math",
"number theory"
] | null | null | You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some num... | The first line contains the number of pairs *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000). Then follow *n* lines, each line contains a pair of positive integers *a**i*,<=*b**i* (1<=<=≤<=<=*a**i*,<=<=*b**i*<=<=≤<=<=109). | Print the sought number of operations for each pair on a single line. | [
"2\n4 17\n7 987654321\n"
] | [
"8\n141093479\n"
] | none | 500 | [
{
"input": "2\n4 17\n7 987654321",
"output": "8\n141093479"
},
{
"input": "10\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321",
"output": "141093479\n141093479\n141093479\n141093479\n141093479\n141093479\n141093479... | 1,491,339,115 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 4,608,000 | def Main():
c = 0
n = int(input())
while n >= 1 :
x = input().split()
if (int(x[1]) - int(x[0])) > 1:
c += 1
n -= 1
print(c)
Main() | Title: Subtractions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one o... | ```python
def Main():
c = 0
n = int(input())
while n >= 1 :
x = input().split()
if (int(x[1]) - int(x[0])) > 1:
c += 1
n -= 1
print(c)
Main()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,658,726,127 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 76 | 62 | 0 | # https://vjudge.net/contest/505445#problem/C
from math import ceil
n = int(input())
if n % 2 == 0:
print(ceil(n / 4) - 1)
else:
print(0)
| Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
# https://vjudge.net/contest/505445#problem/C
from math import ceil
n = int(input())
if n % 2 == 0:
print(ceil(n / 4) - 1)
else:
print(0)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards ... | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print... | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,596,315,451 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 78 | 6,963,200 | n = int(input())
a = list(map(int, input().split()))
minimum = 101
maximum = 0
pairs = 0
i = 0
for m in range(n):
minimum = min(minimum, a[m])
maximum = max(maximum, a[m])
while pairs < (n // 2):
if a[i] != 0:
print(i + 1, a.index(minimum + maximum - a[i], i + 1) + 1)
a[a.index(minimum + maximum - a[... | Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one p... | ```python
n = int(input())
a = list(map(int, input().split()))
minimum = 101
maximum = 0
pairs = 0
i = 0
for m in range(n):
minimum = min(minimum, a[m])
maximum = max(maximum, a[m])
while pairs < (n // 2):
if a[i] != 0:
print(i + 1, a.index(minimum + maximum - a[i], i + 1) + 1)
a[a.index(minimum + ma... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
445 | A | DZY Loves Chessboard | PROGRAMMING | 1,200 | [
"dfs and similar",
"implementation"
] | null | null | DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with th... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a ... | Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell.
If multiple answers exist, print any of them. It ... | [
"1 1\n.\n",
"2 2\n..\n..\n",
"3 3\n.-.\n---\n--."
] | [
"B\n",
"BW\nWB\n",
"B-B\n---\n--B"
] | In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK.
In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output.
In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are. | 500 | [
{
"input": "1 1\n.",
"output": "B"
},
{
"input": "2 2\n..\n..",
"output": "BW\nWB"
},
{
"input": "3 3\n.-.\n---\n--.",
"output": "B-B\n---\n--B"
},
{
"input": "3 1\n-\n.\n.",
"output": "-\nW\nB"
},
{
"input": "11 11\n-----------\n-----------\n-----------\n--------... | 1,596,110,735 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 186 | 23,961,600 | def solve():
from collections import deque
nm = input().split()
n = int(nm[0])
m = int(nm[1])
good = [[False for _ in range(m)] for _ in range(n)]
visited = [[False for _ in range(m)] for _ in range(n)]
color = [['-' for _ in range(m)] for _ in range(n)]
for i in range(n):
line = list(input())
f... | Title: DZY Loves Chessboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. ... | ```python
def solve():
from collections import deque
nm = input().split()
n = int(nm[0])
m = int(nm[1])
good = [[False for _ in range(m)] for _ in range(n)]
visited = [[False for _ in range(m)] for _ in range(n)]
color = [['-' for _ in range(m)] for _ in range(n)]
for i in range(n):
line = list(inp... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,667,331,298 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | n = int(input()) // 2
print(n//2 - int(n % 2 == 0))
| Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
n = int(input()) // 2
print(n//2 - int(n % 2 == 0))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,648,465,614 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 154 | 7,987,200 | n = int(input())
arr = list(map(int, input().split()))
res = min(arr)
c = arr.count(res)
if c > 1:
print("Still Rozdil")
else:
print(arr.index(res)+1)
| Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
n = int(input())
arr = list(map(int, input().split()))
res = min(arr)
c = arr.count(res)
if c > 1:
print("Still Rozdil")
else:
print(arr.index(res)+1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
66 | B | Petya and Countryside | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | B. Petya and Countryside | 2 | 256 | Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *n* equal square sections. The garden is very unusual as each of the square sections possesses its own f... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* positive integers which are the height of the sections. All the numbers are no less than 1 and not more than 1000. | Print a single number, the maximal number of watered sections if we create artificial rain above exactly one section. | [
"1\n2\n",
"5\n1 2 1 2 1\n",
"8\n1 2 1 1 1 3 3 4\n"
] | [
"1\n",
"3\n",
"6\n"
] | none | 1,000 | [
{
"input": "1\n2",
"output": "1"
},
{
"input": "5\n1 2 1 2 1",
"output": "3"
},
{
"input": "8\n1 2 1 1 1 3 3 4",
"output": "6"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10",
"output": "10"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "10"
},
{
"input... | 1,645,633,909 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | T=int(input())
lw=[]
ln=[]
earn=[]
for i in range(T):
W,N=map(int,input().split())
lw.append(W)
ln.append(N)
ear=list(map(int,input().split()))
ear.sort()
ear.reverse()
earn.append(ear)
#print(earn)
for i in range(T):
wneed=lw[i]
maxd=ln[i]
n=len(earn[i])
s=0... | Title: Petya and Countryside
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya often travels to his grandmother in the countryside. The grandmother has a large garden, which can be represented as a rectangle 1<=×<=*n* in size, when viewed from above. This rectangle is divided into *... | ```python
T=int(input())
lw=[]
ln=[]
earn=[]
for i in range(T):
W,N=map(int,input().split())
lw.append(W)
ln.append(N)
ear=list(map(int,input().split()))
ear.sort()
ear.reverse()
earn.append(ear)
#print(earn)
for i in range(T):
wneed=lw[i]
maxd=ln[i]
n=len(earn[i]... | -1 | MatrixStudio/Codeforces-Python-Submissions |
994 | B | Knights of a Polygonal Table | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings"
] | null | null | Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power is greater than the power of victim. However, even such a knight will torment his conscience, so he can kill no mo... | The first line contains two integers $n$ and $k$ $(1 \le n \le 10^5, 0 \le k \le \min(n-1,10))$ — the number of knights and the number $k$ from the statement.
The second line contains $n$ integers $p_1, p_2 ,\ldots,p_n$ $(1 \le p_i \le 10^9)$ — powers of the knights. All $p_i$ are distinct.
The third line contains $n... | Print $n$ integers — the maximum number of coins each knight can have it only he kills other knights. | [
"4 2\n4 5 9 7\n1 2 11 33\n",
"5 1\n1 2 3 4 5\n1 2 3 4 5\n",
"1 0\n2\n3\n"
] | [
"1 3 46 36 ",
"1 3 5 7 9 ",
"3 "
] | Consider the first example.
- The first knight is the weakest, so he can't kill anyone. That leaves him with the only coin he initially has. - The second knight can kill the first knight and add his coin to his own two. - The third knight is the strongest, but he can't kill more than $k = 2$ other knights. It is o... | 1,000 | [
{
"input": "4 2\n4 5 9 7\n1 2 11 33",
"output": "1 3 46 36 "
},
{
"input": "5 1\n1 2 3 4 5\n1 2 3 4 5",
"output": "1 3 5 7 9 "
},
{
"input": "1 0\n2\n3",
"output": "3 "
},
{
"input": "7 1\n2 3 4 5 7 8 9\n0 3 7 9 5 8 9",
"output": "0 3 10 16 14 17 18 "
},
{
"input"... | 1,529,173,600 | 6,700 | Python 3 | OK | TESTS | 73 | 514 | 11,673,600 | from heapq import heapify, heappush, heappushpop
n , k = list(map(int , input().split()))
power = list(map(int , input().split()))
coins = list(map(int , input().split()))
knights = [i for i in range(n)]
knights.sort(key=lambda x:power[x])
cursum = 0
curcoin = []
heapify(curcoin)
res = [0] * n
for i i... | Title: Knights of a Polygonal Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power ... | ```python
from heapq import heapify, heappush, heappushpop
n , k = list(map(int , input().split()))
power = list(map(int , input().split()))
coins = list(map(int , input().split()))
knights = [i for i in range(n)]
knights.sort(key=lambda x:power[x])
cursum = 0
curcoin = []
heapify(curcoin)
res = [0] * ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,612,967,501 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 409,600 | from functools import reduce
s, c = [int(x) for x in input().split()]
temp = [int(x) for x in input().split()]
##print(temp)
i = 0
for x in range(c):
if temp[x] < 0:
i += 1
## print(i)
print(-1*(reduce(lambda x, y: x+ y, sorted(temp)[0:i]))if i >= 1 else 0)
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
from functools import reduce
s, c = [int(x) for x in input().split()]
temp = [int(x) for x in input().split()]
##print(temp)
i = 0
for x in range(c):
if temp[x] < 0:
i += 1
## print(i)
print(-1*(reduce(lambda x, y: x+ y, sorted(temp)[0:i]))if i >= 1 else 0)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite ... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single i... | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,699,168,630 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 12,390,400 | n=int(input())
price=sorted(list(map(int,input().split())))
q=int(input())
i=0
while i<q:
m=int(input())
j=0
while j<n:
if price[j]>m:
break
else:
j+=1
print(j)
i+=1 | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known tha... | ```python
n=int(input())
price=sorted(list(map(int,input().split())))
q=int(input())
i=0
while i<q:
m=int(input())
j=0
while j<n:
if price[j]>m:
break
else:
j+=1
print(j)
i+=1
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,674,493,299 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 48 | 62 | 0 | x,y,z = map(int,input().split())
a = min(x,y,z)
b = max(x,y,z)
print(b-a) | Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
x,y,z = map(int,input().split())
a = min(x,y,z)
b = max(x,y,z)
print(b-a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
733 | A | Grasshopper And the String | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of ... | The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. | Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. | [
"ABABBBACFEYUKOTT\n",
"AAA\n"
] | [
"4",
"1"
] | none | 500 | [
{
"input": "ABABBBACFEYUKOTT",
"output": "4"
},
{
"input": "AAA",
"output": "1"
},
{
"input": "A",
"output": "1"
},
{
"input": "B",
"output": "2"
},
{
"input": "AEYUIOAEIYAEOUIYOEIUYEAOIUEOEAYOEIUYAEOUIYEOIKLMJNHGTRWSDZXCVBNMHGFDSXVWRTPPPLKMNBXIUOIUOIUOIUOOIU",
... | 1,666,386,033 | 2,147,483,647 | Python 3 | OK | TESTS | 70 | 46 | 0 | string = input()
minimo = 0
saltoactual = 1
for letra in string:
if letra not in("AEIOUY"):
saltoactual += 1
if minimo < saltoactual:
minimo = saltoactual
elif letra in("AEIOUY"):
saltoactual = 1
print(minimo)
| Title: Grasshopper And the String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far en... | ```python
string = input()
minimo = 0
saltoactual = 1
for letra in string:
if letra not in("AEIOUY"):
saltoactual += 1
if minimo < saltoactual:
minimo = saltoactual
elif letra in("AEIOUY"):
saltoactual = 1
print(minimo)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
873 | B | Balanced Substring | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | null | null | You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called balanced if the number of zeroes (0) equals to the number of ones in this substring.
You have to deter... | The first line contains *n* (1<=≤<=*n*<=≤<=100000) — the number of characters in *s*.
The second line contains a string *s* consisting of exactly *n* characters. Only characters 0 and 1 can appear in *s*. | If there is no non-empty balanced substring in *s*, print 0. Otherwise, print the length of the longest balanced substring. | [
"8\n11010111\n",
"3\n111\n"
] | [
"4\n",
"0\n"
] | In the first example you can choose the substring [3, 6]. It is balanced, and its length is 4. Choosing the substring [2, 5] is also possible.
In the second example it's impossible to find a non-empty balanced substring. | 0 | [
{
"input": "8\n11010111",
"output": "4"
},
{
"input": "3\n111",
"output": "0"
},
{
"input": "11\n00001000100",
"output": "2"
},
{
"input": "10\n0100000000",
"output": "2"
},
{
"input": "13\n0001000011010",
"output": "6"
},
{
"input": "14\n0000010010101... | 1,693,692,423 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 53 | 93 | 19,148,800 | n = int(input())
l = list(input())
pref = [0]
for i in range(len(l)):
if l[i] == '1':
pref.append(pref[i] - 1)
else:
pref.append(pref[i] + 1)
hashmap = {}
res = 0
for i in range(len(pref)):
if pref[i] in hashmap:
res = max(res, i - hashmap[pref[i]])
else:
hashmap[pref[... | Title: Balanced Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting only of characters 0 and 1. A substring [*l*,<=*r*] of *s* is a string *s**l**s**l*<=+<=1*s**l*<=+<=2... *s**r*, and its length equals to *r*<=-<=*l*<=+<=1. A substring is called... | ```python
n = int(input())
l = list(input())
pref = [0]
for i in range(len(l)):
if l[i] == '1':
pref.append(pref[i] - 1)
else:
pref.append(pref[i] + 1)
hashmap = {}
res = 0
for i in range(len(pref)):
if pref[i] in hashmap:
res = max(res, i - hashmap[pref[i]])
else:
has... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
606 | A | Magic Spheres | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been seen before, he needs at least *x* blue, *y* violet and *z* orange spheres. Can he get them (possible,... | The first line of the input contains three integers *a*, *b* and *c* (0<=≤<=*a*,<=*b*,<=*c*<=≤<=1<=000<=000) — the number of blue, violet and orange spheres that are in the magician's disposal.
The second line of the input contains three integers, *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=1<=000<=000) — the number o... | If the wizard is able to obtain the required numbers of spheres, print "Yes". Otherwise, print "No". | [
"4 4 0\n2 1 2\n",
"5 6 1\n2 7 2\n",
"3 3 3\n2 2 2\n"
] | [
"Yes\n",
"No\n",
"Yes\n"
] | In the first sample the wizard has 4 blue and 4 violet spheres. In his first action he can turn two blue spheres into one violet one. After that he will have 2 blue and 5 violet spheres. Then he turns 4 violet spheres into 2 orange spheres and he ends up with 2 blue, 1 violet and 2 orange spheres, which is exactly what... | 500 | [
{
"input": "4 4 0\n2 1 2",
"output": "Yes"
},
{
"input": "5 6 1\n2 7 2",
"output": "No"
},
{
"input": "3 3 3\n2 2 2",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 0",
"output": "Yes"
},
{
"input": "0 0 0\n0 0 1",
"output": "No"
},
{
"input": "0 1 0\n0 0 0... | 1,454,435,335 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 1,700 | 1,433,600 | import logging
import copy
import sys
logging.basicConfig(stream=sys.stderr, level=logging.DEBUG)
#def solve(firstLine):
def solve(init, final):
stack = [init]
log("final", final)
def recur():
while(1):
if len(stack) == 0:
return False
... | Title: Magic Spheres
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Carl is a beginner magician. He has *a* blue, *b* violet and *c* orange magic spheres. In one move he can transform two spheres of the same color into one sphere of any other color. To make a spell that has never been see... | ```python
import logging
import copy
import sys
logging.basicConfig(stream=sys.stderr, level=logging.DEBUG)
#def solve(firstLine):
def solve(init, final):
stack = [init]
log("final", final)
def recur():
while(1):
if len(stack) == 0:
return False
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
723 | A | The New Year: Meeting Friends | PROGRAMMING | 800 | [
"implementation",
"math",
"sortings"
] | null | null | There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They plan to celebrate the New Year together, so they need to meet at one point. What is the minimum total distance they... | The first line of the input contains three distinct integers *x*1, *x*2 and *x*3 (1<=≤<=*x*1,<=*x*2,<=*x*3<=≤<=100) — the coordinates of the houses of the first, the second and the third friends respectively. | Print one integer — the minimum total distance the friends need to travel in order to meet together. | [
"7 1 4\n",
"30 20 10\n"
] | [
"6\n",
"20\n"
] | In the first sample, friends should meet at the point 4. Thus, the first friend has to travel the distance of 3 (from the point 7 to the point 4), the second friend also has to travel the distance of 3 (from the point 1 to the point 4), while the third friend should not go anywhere because he lives at the point 4. | 500 | [
{
"input": "7 1 4",
"output": "6"
},
{
"input": "30 20 10",
"output": "20"
},
{
"input": "1 4 100",
"output": "99"
},
{
"input": "100 1 91",
"output": "99"
},
{
"input": "1 45 100",
"output": "99"
},
{
"input": "1 2 3",
"output": "2"
},
{
"... | 1,671,371,220 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | def solve():
arr = list(map(int, input().split()))
print(max(arr), min(arr))
if __name__ == '__main__':
solve() | Title: The New Year: Meeting Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are three friend living on the straight line *Ox* in Lineland. The first friend lives at the point *x*1, the second friend lives at the point *x*2, and the third friend lives at the point *x*3. They ... | ```python
def solve():
arr = list(map(int, input().split()))
print(max(arr), min(arr))
if __name__ == '__main__':
solve()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,628,096,143 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 19 | 154 | 6,963,200 | n, m = map(int, input().split())
c = 0
for i in range (1, n+1):
if n%i==0: c+=1
d = 0
for i in range (1, m+1):
if m%i==0: d+=1
if d<3 and c<3:
if m>n: print('YES');
else: print('NO')
else: print('NO')
| Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
n, m = map(int, input().split())
c = 0
for i in range (1, n+1):
if n%i==0: c+=1
d = 0
for i in range (1, m+1):
if m%i==0: d+=1
if d<3 and c<3:
if m>n: print('YES');
else: print('NO')
else: print('NO')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,688,052,425 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 0 | n = int(input())
sum = 0
for i in range(n):
str_ing=input()
if str_ing=="Tetrahedron":
sum += 4
elif str_ing=="Cube":
sum += 6
elif str_ing=="Octahedron":
sum += 8
elif str_ing=="Dodecahedron":
sum += 12
else:
sum += 20
print(sum) | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
n = int(input())
sum = 0
for i in range(n):
str_ing=input()
if str_ing=="Tetrahedron":
sum += 4
elif str_ing=="Cube":
sum += 6
elif str_ing=="Octahedron":
sum += 8
elif str_ing=="Dodecahedron":
sum += 12
else:
sum += 20
print(sum)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
445 | A | DZY Loves Chessboard | PROGRAMMING | 1,200 | [
"dfs and similar",
"implementation"
] | null | null | DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. Each chessman is either white or black. After putting all chessmen, DZY wants that no two chessmen with th... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Each of the next *n* lines contains a string of *m* characters: the *j*-th character of the *i*-th string is either "." or "-". A "." means that the corresponding cell (in the *i*-th row and the *j*-th column) is good, while a ... | Output must contain *n* lines, each line must contain a string of *m* characters. The *j*-th character of the *i*-th string should be either "W", "B" or "-". Character "W" means the chessman on the cell is white, "B" means it is black, "-" means the cell is a bad cell.
If multiple answers exist, print any of them. It ... | [
"1 1\n.\n",
"2 2\n..\n..\n",
"3 3\n.-.\n---\n--."
] | [
"B\n",
"BW\nWB\n",
"B-B\n---\n--B"
] | In the first sample, DZY puts a single black chessman. Of course putting a white one is also OK.
In the second sample, all 4 cells are good. No two same chessmen share an edge in the sample output.
In the third sample, no good cells are adjacent. So you can just put 3 chessmen, no matter what their colors are. | 500 | [
{
"input": "1 1\n.",
"output": "B"
},
{
"input": "2 2\n..\n..",
"output": "BW\nWB"
},
{
"input": "3 3\n.-.\n---\n--.",
"output": "B-B\n---\n--B"
},
{
"input": "3 1\n-\n.\n.",
"output": "-\nW\nB"
},
{
"input": "11 11\n-----------\n-----------\n-----------\n--------... | 1,644,380,805 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 |
n, m = [int(i) for i in input().split(' ')]
matrix = [];
for i in range(0, n, 1):
matrix.append([]);
entrada = [];
for letra in input():
entrada.append(letra)
for j in range(0, len(entrada), 1):
matrix[i].append(entrada[j]);
if (matrix[i][j] == '.'):
if ... | Title: DZY Loves Chessboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chessboard, and he enjoys playing with it.
He has a chessboard of *n* rows and *m* columns. Some cells of the chessboard are bad, others are good. For every good cell, DZY wants to put a chessman on it. ... | ```python
n, m = [int(i) for i in input().split(' ')]
matrix = [];
for i in range(0, n, 1):
matrix.append([]);
entrada = [];
for letra in input():
entrada.append(letra)
for j in range(0, len(entrada), 1):
matrix[i].append(entrada[j]);
if (matrix[i][j] == '.'):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,661,677,918 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 78 | 0 | l=[int(i) for i in input().split()]
s=input()
count=0
for i in s:
k=int(i)
count+=l[k-1]
print(count) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
l=[int(i) for i in input().split()]
s=input()
count=0
for i in s:
k=int(i)
count+=l[k-1]
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
27 | C | Unordered Subsequence | PROGRAMMING | 1,900 | [
"constructive algorithms",
"greedy"
] | C. Unordered Subsequence | 2 | 256 | The sequence is called ordered if it is non-decreasing or non-increasing. For example, sequnces [3, 1, 1, 0] and [1, 2, 3, 100] are ordered, but the sequence [1, 3, 3, 1] is not. You are given a sequence of numbers. You are to find it's shortest subsequence which is not ordered.
A subsequence is a sequence that can be... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers — the given sequence. All numbers in this sequence do not exceed 106 by absolute value. | If the given sequence does not contain any unordered subsequences, output 0. Otherwise, output the length *k* of the shortest such subsequence. Then output *k* integers from the range [1..*n*] — indexes of the elements of this subsequence. If there are several solutions, output any of them. | [
"5\n67 499 600 42 23\n",
"3\n1 2 3\n",
"3\n2 3 1\n"
] | [
"3\n1 3 5\n",
"0\n",
"3\n1 2 3\n"
] | none | 1,500 | [
{
"input": "3\n3 1 2",
"output": "3\n1 2 3"
},
{
"input": "1\n-895376",
"output": "0"
},
{
"input": "2\n166442 61629",
"output": "0"
},
{
"input": "3\n-771740 -255752 -300809",
"output": "3\n1 2 3"
},
{
"input": "4\n-227347 -573134 -671045 11011",
"output": "3... | 1,690,811,174 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 184 | 13,209,600 | def main():
n = int(input())
a = list(map(int, input().split()))
p1, p2 = True, True
for i in range(1, n):
if a[i] > a[i - 1]:
p1 = False
if a[i] < a[i - 1]:
p2 = False
if not (p1 or p2):
print("3")
print(1, i, i + 1)
... | Title: Unordered Subsequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The sequence is called ordered if it is non-decreasing or non-increasing. For example, sequnces [3, 1, 1, 0] and [1, 2, 3, 100] are ordered, but the sequence [1, 3, 3, 1] is not. You are given a sequence of numbers. Y... | ```python
def main():
n = int(input())
a = list(map(int, input().split()))
p1, p2 = True, True
for i in range(1, n):
if a[i] > a[i - 1]:
p1 = False
if a[i] < a[i - 1]:
p2 = False
if not (p1 or p2):
print("3")
print(1, i, ... | 3.929395 | MatrixStudio/Codeforces-Python-Submissions |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,638,417,498 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | #word
s=input()
up =0
low=0
for i in s:
if s.islower():
low=low+1
elif s.isupper():
up=up+1
if up==low:
print(s.lower())
elif up>low:
print(s.upper())
elif low>up:
print(s.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
#word
s=input()
up =0
low=0
for i in s:
if s.islower():
low=low+1
elif s.isupper():
up=up+1
if up==low:
print(s.lower())
elif up>low:
print(s.upper())
elif low>up:
print(s.lower())
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
913 | A | Modular Exponentiation | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" problem. Given integers *n* and *m*, calculate | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=108).
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=108). | Output a single integer — the value of . | [
"4\n42\n",
"1\n58\n",
"98765432\n23456789\n"
] | [
"10\n",
"0\n",
"23456789\n"
] | In the first example, the remainder of division of 42 by 2<sup class="upper-index">4</sup> = 16 is equal to 10.
In the second example, 58 is divisible by 2<sup class="upper-index">1</sup> = 2 without remainder, and the answer is 0. | 500 | [
{
"input": "4\n42",
"output": "10"
},
{
"input": "1\n58",
"output": "0"
},
{
"input": "98765432\n23456789",
"output": "23456789"
},
{
"input": "8\n88127381",
"output": "149"
},
{
"input": "32\n92831989",
"output": "92831989"
},
{
"input": "92831989\n25... | 1,629,486,662 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 7 | 826 | 78,028,800 |
def exp(valor, n):
if (n==1):
return valor;
valor = exp(valor*valor,n//2);
if (n %2 == 1):
valor = valor*2;
return valor;
def main():
n = int(input())
m = int(input())
print(m%exp(2,n))
main()
| Title: Modular Exponentiation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The following problem is well-known: given integers *n* and *m*, calculate
where 2*n*<==<=2·2·...·2 (*n* factors), and denotes the remainder of division of *x* by *y*.
You are asked to solve the "reverse" prob... | ```python
def exp(valor, n):
if (n==1):
return valor;
valor = exp(valor*valor,n//2);
if (n %2 == 1):
valor = valor*2;
return valor;
def main():
n = int(input())
m = int(input())
print(m%exp(2,n))
main()
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, inf... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word bec... | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,631,653,846 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 77 | 6,963,200 | n = int(input())
s = input()
b = n & 1
if b == 1:
l = [s[0]]
else:
l = []
r = []
for i in range(b, n, 2):
l.append(s[i])
r.append(s[i + 1])
ret = ''.join(reversed(l)) + ''.join(r)
print(ret) | Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the... | ```python
n = int(input())
s = input()
b = n & 1
if b == 1:
l = [s[0]]
else:
l = []
r = []
for i in range(b, n, 2):
l.append(s[i])
r.append(s[i + 1])
ret = ''.join(reversed(l)) + ''.join(r)
print(ret)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,639,840,704 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | ans=input()
uip=0
lip=0
for i in ans:
if i.islower():
lip+=1
elif i.isupper():
uip+=1
else:
pass
if uip>lip:
ans=ans.upper()
else:
ans=ans.lower()
print(ans) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
ans=input()
uip=0
lip=0
for i in ans:
if i.islower():
lip+=1
elif i.isupper():
uip+=1
else:
pass
if uip>lip:
ans=ans.upper()
else:
ans=ans.lower()
print(ans)
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
626 | B | Cards | PROGRAMMING | 1,300 | [
"constructive algorithms",
"dp",
"math"
] | null | null | Catherine has a deck of *n* cards, each of which is either red, green, or blue. As long as there are at least two cards left, she can do one of two actions:
- take any two (not necessarily adjacent) cards with different colors and exchange them for a new card of the third color; - take any two (not necessarily adja... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200) — the total number of cards.
The next line contains a string *s* of length *n* — the colors of the cards. *s* contains only the characters 'B', 'G', and 'R', representing blue, green, and red, respectively. | Print a single string of up to three characters — the possible colors of the final card (using the same symbols as the input) in alphabetical order. | [
"2\nRB\n",
"3\nGRG\n",
"5\nBBBBB\n"
] | [
"G\n",
"BR\n",
"B\n"
] | In the first sample, Catherine has one red card and one blue card, which she must exchange for a green card.
In the second sample, Catherine has two green cards and one red card. She has two options: she can exchange the two green cards for a green card, then exchange the new green card and the red card for a blue car... | 750 | [
{
"input": "2\nRB",
"output": "G"
},
{
"input": "3\nGRG",
"output": "BR"
},
{
"input": "5\nBBBBB",
"output": "B"
},
{
"input": "1\nR",
"output": "R"
},
{
"input": "200\nBBRGRRBBRGGGBGBGBGRRGRGRGRBGRGRRBBGRGBGRRGRRRGGBBRGBGBGBRBBBBBBBGGBRGGRRRGGRGBGBGGBRRRRBRRRBRBB... | 1,455,387,885 | 2,985 | Python 3 | OK | TESTS | 46 | 77 | 0 | from sys import exit
n = int(input())
s = input()
if "R" in s and "G" in s and "B" in s:
print('BGR')
exit()
if 'R' not in s and 'G' not in s:
print('B')
exit()
if 'R' not in s and 'B' not in s:
print('G')
exit()
if 'B' not in s and 'G' not in s:
print('R')
exit()
if "R"... | Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Catherine has a deck of *n* cards, each of which is either red, green, or blue. As long as there are at least two cards left, she can do one of two actions:
- take any two (not necessarily adjacent) cards with different colors... | ```python
from sys import exit
n = int(input())
s = input()
if "R" in s and "G" in s and "B" in s:
print('BGR')
exit()
if 'R' not in s and 'G' not in s:
print('B')
exit()
if 'R' not in s and 'B' not in s:
print('G')
exit()
if 'B' not in s and 'G' not in s:
print('R')
exit()... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,695,751,991 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 5,632,000 | s = int(input())+1
while len(set(str(s))) != 4:
s += 1
print(s)
| Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
s = int(input())+1
while len(set(str(s))) != 4:
s += 1
print(s)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
746 | A | Compote | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exactly 4 pears. You can't crumble up, break up or cut these fruits into pieces. These fruits — ... | The first line contains the positive integer *a* (1<=≤<=*a*<=≤<=1000) — the number of lemons Nikolay has.
The second line contains the positive integer *b* (1<=≤<=*b*<=≤<=1000) — the number of apples Nikolay has.
The third line contains the positive integer *c* (1<=≤<=*c*<=≤<=1000) — the number of pears Nikolay has... | Print the maximum total number of lemons, apples and pears from which Nikolay can cook the compote. | [
"2\n5\n7\n",
"4\n7\n13\n",
"2\n3\n2\n"
] | [
"7\n",
"21\n",
"0\n"
] | In the first example Nikolay can use 1 lemon, 2 apples and 4 pears, so the answer is 1 + 2 + 4 = 7.
In the second example Nikolay can use 3 lemons, 6 apples and 12 pears, so the answer is 3 + 6 + 12 = 21.
In the third example Nikolay don't have enough pears to cook any compote, so the answer is 0. | 500 | [
{
"input": "2\n5\n7",
"output": "7"
},
{
"input": "4\n7\n13",
"output": "21"
},
{
"input": "2\n3\n2",
"output": "0"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n4",
"output": "7"
},
{
"input": "1000\n1000\n1000",
"output": "1750"
}... | 1,626,930,668 | 2,147,483,647 | Python 3 | OK | TESTS | 84 | 77 | 6,758,400 | x = int(input())
y = int(input())
z = int(input())
y = y // 2
z = z // 4
min = min(min(x, y), z)
print(min * 7)
| Title: Compote
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nikolay has *a* lemons, *b* apples and *c* pears. He decided to cook a compote. According to the recipe the fruits should be in the ratio 1:<=2:<=4. It means that for each lemon in the compote should be exactly 2 apples and exa... | ```python
x = int(input())
y = int(input())
z = int(input())
y = y // 2
z = z // 4
min = min(min(x, y), z)
print(min * 7)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
435 | B | Pasha Maximizes | PROGRAMMING | 1,400 | [
"greedy"
] | null | null | Pasha has a positive integer *a* without leading zeroes. Today he decided that the number is too small and he should make it larger. Unfortunately, the only operation Pasha can do is to swap two adjacent decimal digits of the integer.
Help Pasha count the maximum number he can get if he has the time to make at most *k... | The single line contains two integers *a* and *k* (1<=≤<=*a*<=≤<=1018; 0<=≤<=*k*<=≤<=100). | Print the maximum number that Pasha can get if he makes at most *k* swaps. | [
"1990 1\n",
"300 0\n",
"1034 2\n",
"9090000078001234 6\n"
] | [
"9190\n",
"300\n",
"3104\n",
"9907000008001234\n"
] | none | 1,000 | [
{
"input": "1990 1",
"output": "9190"
},
{
"input": "300 0",
"output": "300"
},
{
"input": "1034 2",
"output": "3104"
},
{
"input": "9090000078001234 6",
"output": "9907000008001234"
},
{
"input": "1234 3",
"output": "4123"
},
{
"input": "5 100",
"... | 1,668,260,012 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 61 | 0 | s, k = input().split()
s = list(s)
k = int(k)
n = len(s)
def find_first_better_move(start):
for i in range(start + 1, n):
if s[i] > s[start]:
return i
return None
def swap(i, j):
for index in range(j, i, -1):
c = s[index]
s[index] = s[index - 1]
... | Title: Pasha Maximizes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a positive integer *a* without leading zeroes. Today he decided that the number is too small and he should make it larger. Unfortunately, the only operation Pasha can do is to swap two adjacent decimal digits ... | ```python
s, k = input().split()
s = list(s)
k = int(k)
n = len(s)
def find_first_better_move(start):
for i in range(start + 1, n):
if s[i] > s[start]:
return i
return None
def swap(i, j):
for index in range(j, i, -1):
c = s[index]
s[index] = s[index -... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
387 | B | George and Round | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"two pointers"
] | null | null | George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
To make the round good, he needs to put at least *n* problems there. Besides, he needs to have at least... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=3000) — the minimal number of problems in a good round and the number of problems George's prepared. The second line contains space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a*1<=<<=*a*2<=<<=...<=<<=*a**n*<=≤<=106) — the requirem... | Print a single integer — the answer to the problem. | [
"3 5\n1 2 3\n1 2 2 3 3\n",
"3 5\n1 2 3\n1 1 1 1 1\n",
"3 1\n2 3 4\n1\n"
] | [
"0\n",
"2\n",
"3\n"
] | In the first sample the set of the prepared problems meets the requirements for a good round.
In the second sample, it is enough to come up with and prepare two problems with complexities 2 and 3 to get a good round.
In the third sample it is very easy to get a good round if come up with and prepare extra problems wi... | 1,000 | [
{
"input": "3 5\n1 2 3\n1 2 2 3 3",
"output": "0"
},
{
"input": "3 5\n1 2 3\n1 1 1 1 1",
"output": "2"
},
{
"input": "3 1\n2 3 4\n1",
"output": "3"
},
{
"input": "29 100\n20 32 41 67 72 155 331 382 399 412 465 470 484 511 515 529 616 637 679 715 733 763 826 843 862 903 925 97... | 1,502,614,020 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 93 | 23,142,400 | n, m = [int(i) for i in input().split(" ")]
a = [int(i) for i in input().split(" ")]
b = [int(i) for i in input().split(" ")]
i = 0
j = 0
matched_count = 0
last_num = None
while j < len(b) and i < len(a):
if b[j] == a[i]:
if b[j] != last_num:
last_num = b[j]
matched_count += 1
e... | Title: George and Round
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George decided to prepare a Codesecrof round, so he has prepared *m* problems for the round. Let's number the problems with integers 1 through *m*. George estimates the *i*-th problem's complexity by integer *b**i*.
T... | ```python
n, m = [int(i) for i in input().split(" ")]
a = [int(i) for i in input().split(" ")]
b = [int(i) for i in input().split(" ")]
i = 0
j = 0
matched_count = 0
last_num = None
while j < len(b) and i < len(a):
if b[j] == a[i]:
if b[j] != last_num:
last_num = b[j]
matched_count ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
146 | B | Lucky Mask | PROGRAMMING | 1,300 | [
"brute force",
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a mask of a positive integer *n* the number that is obtained after successive writing ... | The only line contains two integers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=105). It is guaranteed that number *b* is lucky. | In the only line print a single number — the number *c* that is sought by Petya. | [
"1 7\n",
"100 47\n"
] | [
"7\n",
"147\n"
] | none | 1,000 | [
{
"input": "1 7",
"output": "7"
},
{
"input": "100 47",
"output": "147"
},
{
"input": "458 47",
"output": "467"
},
{
"input": "7 7",
"output": "17"
},
{
"input": "547 47",
"output": "647"
},
{
"input": "77 77",
"output": "177"
},
{
"input":... | 1,609,676,531 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 0 | a,b=input().split()
a=int(a)
while 1:
n=str(a)
k=""
for i in n:
if i=='4' or i=='7':
k+=i
if k==b:
print(a)
break
a+=1
| Title: Lucky Mask
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Pe... | ```python
a,b=input().split()
a=int(a)
while 1:
n=str(a)
k=""
for i in n:
if i=='4' or i=='7':
k+=i
if k==b:
print(a)
break
a+=1
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
864 | A | Fair Game | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | Petya and Vasya decided to play a game. They have *n* cards (*n* is an even number). A single integer is written on each card.
Before the game Petya will choose an integer and after that Vasya will choose another integer (different from the number that Petya chose). During the game each player takes all the cards with... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=100) — number of cards. It is guaranteed that *n* is an even number.
The following *n* lines contain a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (one integer per line, 1<=≤<=*a**i*<=≤<=100) — numbers written on the *n* cards. | If it is impossible for Petya and Vasya to choose numbers in such a way that the game will be fair, print "NO" (without quotes) in the first line. In this case you should not print anything more.
In the other case print "YES" (without quotes) in the first line. In the second line print two distinct integers — number t... | [
"4\n11\n27\n27\n11\n",
"2\n6\n6\n",
"6\n10\n20\n30\n20\n10\n20\n",
"6\n1\n1\n2\n2\n3\n3\n"
] | [
"YES\n11 27\n",
"NO\n",
"NO\n",
"NO\n"
] | In the first example the game will be fair if, for example, Petya chooses number 11, and Vasya chooses number 27. Then the will take all cards — Petya will take cards 1 and 4, and Vasya will take cards 2 and 3. Thus, each of them will take exactly two cards.
In the second example fair game is impossible because the nu... | 500 | [
{
"input": "4\n11\n27\n27\n11",
"output": "YES\n11 27"
},
{
"input": "2\n6\n6",
"output": "NO"
},
{
"input": "6\n10\n20\n30\n20\n10\n20",
"output": "NO"
},
{
"input": "6\n1\n1\n2\n2\n3\n3",
"output": "NO"
},
{
"input": "2\n1\n100",
"output": "YES\n1 100"
},
... | 1,531,849,837 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 124 | 0 | n = int(input())
a = [int(input()) for i in range(n)]
s = list(set(a))
if len(s) == 2 and a.count(s[0]) == a.count(s[1]):
print('YES')
print(*s)
else:
print('NO') | Title: Fair Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya and Vasya decided to play a game. They have *n* cards (*n* is an even number). A single integer is written on each card.
Before the game Petya will choose an integer and after that Vasya will choose another integer (di... | ```python
n = int(input())
a = [int(input()) for i in range(n)]
s = list(set(a))
if len(s) == 2 and a.count(s[0]) == a.count(s[1]):
print('YES')
print(*s)
else:
print('NO')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
620 | C | Pearls in a Row | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | There are *n* pearls in a row. Let's enumerate them with integers from 1 to *n* from the left to the right. The pearl number *i* has the type *a**i*.
Let's call a sequence of consecutive pearls a segment. Let's call a segment good if it contains two pearls of the same type.
Split the row of the pearls to the maximal ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of pearls in a row.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) – the type of the *i*-th pearl. | On the first line print integer *k* — the maximal number of segments in a partition of the row.
Each of the next *k* lines should contain two integers *l**j*,<=*r**j* (1<=≤<=*l**j*<=≤<=*r**j*<=≤<=*n*) — the number of the leftmost and the rightmost pearls in the *j*-th segment.
Note you should print the correct partit... | [
"5\n1 2 3 4 1\n",
"5\n1 2 3 4 5\n",
"7\n1 2 1 3 1 2 1\n"
] | [
"1\n1 5\n",
"-1\n",
"2\n1 3\n4 7\n"
] | none | 0 | [
{
"input": "5\n1 2 3 4 1",
"output": "1\n1 5"
},
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "7\n1 2 1 3 1 2 1",
"output": "2\n1 3\n4 7"
},
{
"input": "9\n1 2 1 2 1 2 1 2 1",
"output": "3\n1 3\n4 6\n7 9"
},
{
"input": "11\n1 1 2 1 2 1 2 1 2 1 1",
"... | 1,669,147,310 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 62 | 0 | from collections import defaultdict
n = int(input())
nums = list(map(int, input().split()))
cnt = defaultdict(int)
ans = []
left = 0
for idx, num in enumerate(nums):
cnt[num] += 1
if cnt[num] > 1:
ans.append((left + 1, idx + 1))
left = idx + 1
cnt = defaultdict(int... | Title: Pearls in a Row
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* pearls in a row. Let's enumerate them with integers from 1 to *n* from the left to the right. The pearl number *i* has the type *a**i*.
Let's call a sequence of consecutive pearls a segment. Let's call a ... | ```python
from collections import defaultdict
n = int(input())
nums = list(map(int, input().split()))
cnt = defaultdict(int)
ans = []
left = 0
for idx, num in enumerate(nums):
cnt[num] += 1
if cnt[num] > 1:
ans.append((left + 1, idx + 1))
left = idx + 1
cnt = defau... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
1,004 | B | Sonya and Exhibition | PROGRAMMING | 1,300 | [
"constructive algorithms",
"greedy",
"implementation",
"math"
] | null | null | Sonya decided to organize an exhibition of flowers. Since the girl likes only roses and lilies, she decided that only these two kinds of flowers should be in this exhibition.
There are $n$ flowers in a row in the exhibition. Sonya can put either a rose or a lily in the $i$-th position. Thus each of $n$ positions shoul... | The first line contains two integers $n$ and $m$ ($1\leq n, m\leq 10^3$) — the number of flowers and visitors respectively.
Each of the next $m$ lines contains two integers $l_i$ and $r_i$ ($1\leq l_i\leq r_i\leq n$), meaning that $i$-th visitor will visit all flowers from $l_i$ to $r_i$ inclusive. | Print the string of $n$ characters. The $i$-th symbol should be «0» if you want to put a rose in the $i$-th position, otherwise «1» if you want to put a lily.
If there are multiple answers, print any. | [
"5 3\n1 3\n2 4\n2 5\n",
"6 3\n5 6\n1 4\n4 6\n"
] | [
"01100",
"110010"
] | In the first example, Sonya can put roses in the first, fourth, and fifth positions, and lilies in the second and third positions;
- in the segment $[1\ldots3]$, there are one rose and two lilies, so the beauty is equal to $1\cdot 2=2$; - in the segment $[2\ldots4]$, there are one rose and two lilies, so the beauty ... | 1,000 | [
{
"input": "5 3\n1 3\n2 4\n2 5",
"output": "01010"
},
{
"input": "6 3\n5 6\n1 4\n4 6",
"output": "010101"
},
{
"input": "10 4\n3 3\n1 6\n9 9\n10 10",
"output": "0101010101"
},
{
"input": "1 1\n1 1",
"output": "0"
},
{
"input": "1000 10\n3 998\n2 1000\n1 999\n2 100... | 1,530,809,351 | 851 | Python 3 | OK | TESTS | 27 | 140 | 0 | n,m=list(map(int,input().split()))
a=1
for i in range(n):
if a==1:
print('0',end='')
else:
print('1',end='')
a*=-1 | Title: Sonya and Exhibition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sonya decided to organize an exhibition of flowers. Since the girl likes only roses and lilies, she decided that only these two kinds of flowers should be in this exhibition.
There are $n$ flowers in a row in the ... | ```python
n,m=list(map(int,input().split()))
a=1
for i in range(n):
if a==1:
print('0',end='')
else:
print('1',end='')
a*=-1
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
760 | A | Petr and a calendar | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:
Petr wants to ... | The only line contain two integers *m* and *d* (1<=≤<=*m*<=≤<=12, 1<=≤<=*d*<=≤<=7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday). | Print single integer: the number of columns the table should have. | [
"1 7\n",
"1 1\n",
"11 6\n"
] | [
"6\n",
"5\n",
"5\n"
] | The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example 1-st January is Monday, so the whole month fits into 5 columns.
In the third example 1-st November is Saturday and 5 columns is enough. | 500 | [
{
"input": "1 7",
"output": "6"
},
{
"input": "1 1",
"output": "5"
},
{
"input": "11 6",
"output": "5"
},
{
"input": "2 7",
"output": "5"
},
{
"input": "2 1",
"output": "4"
},
{
"input": "8 6",
"output": "6"
},
{
"input": "1 1",
"output... | 1,618,182,623 | 2,147,483,647 | Python 3 | OK | TESTS | 104 | 77 | 0 | m,d = map(int,input().split())
if m in(1,3,5,7,8,10,12):
if d>5:
print(6)
else:
print(5)
elif m == 2:
if d==1:
print(4)
else:
print(5)
else:
if d==7:
print(6)
else:
print(5) | Title: Petr and a calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells... | ```python
m,d = map(int,input().split())
if m in(1,3,5,7,8,10,12):
if d>5:
print(6)
else:
print(5)
elif m == 2:
if d==1:
print(4)
else:
print(5)
else:
if d==7:
print(6)
else:
print(5)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
778 | B | Bitwise Formula | PROGRAMMING | 1,800 | [
"bitmasks",
"brute force",
"dfs and similar",
"expression parsing",
"implementation"
] | null | null | Bob recently read about bitwise operations used in computers: AND, OR and XOR. He have studied their properties and invented a new game.
Initially, Bob chooses integer *m*, bit depth of the game, which means that all numbers in the game will consist of *m* bits. Then he asks Peter to choose some *m*-bit number. After ... | The first line contains two integers *n* and *m*, the number of variables and bit depth, respectively (1<=≤<=*n*<=≤<=5000; 1<=≤<=*m*<=≤<=1000).
The following *n* lines contain descriptions of the variables. Each line describes exactly one variable. Description has the following format: name of a new variable, space, ... | In the first line output the minimum number that should be chosen by Peter, to make the sum of all variable values minimum possible, in the second line output the minimum number that should be chosen by Peter, to make the sum of all variable values maximum possible. Both numbers should be printed as *m*-bit binary numb... | [
"3 3\na := 101\nb := 011\nc := ? XOR b\n",
"5 1\na := 1\nbb := 0\ncx := ? OR a\nd := ? XOR ?\ne := d AND bb\n"
] | [
"011\n100\n",
"0\n0\n"
] | In the first sample if Peter chooses a number 011<sub class="lower-index">2</sub>, then *a* = 101<sub class="lower-index">2</sub>, *b* = 011<sub class="lower-index">2</sub>, *c* = 000<sub class="lower-index">2</sub>, the sum of their values is 8. If he chooses the number 100<sub class="lower-index">2</sub>, then *a* = ... | 1,000 | [
{
"input": "3 3\na := 101\nb := 011\nc := ? XOR b",
"output": "011\n100"
},
{
"input": "5 1\na := 1\nbb := 0\ncx := ? OR a\nd := ? XOR ?\ne := d AND bb",
"output": "0\n0"
},
{
"input": "2 10\nb := 0100101101\na := ? XOR b",
"output": "0100101101\n1011010010"
},
{
"input": "1 ... | 1,488,098,089 | 1,789 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 11 | 3,000 | 7,782,400 | [n, m] = list(map(int, input().split(" ")))
W = []
for _ in range(n):
(var, op) = input().split(" := ")
op = op.split(" ")
W.append((var, op))
def check(v, place):
V = {}
for ele in W:
(var, op) = ele
if len(op) == 1:
V[var] = int(op[0][place])
if ... | Title: Bitwise Formula
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bob recently read about bitwise operations used in computers: AND, OR and XOR. He have studied their properties and invented a new game.
Initially, Bob chooses integer *m*, bit depth of the game, which means that all n... | ```python
[n, m] = list(map(int, input().split(" ")))
W = []
for _ in range(n):
(var, op) = input().split(" := ")
op = op.split(" ")
W.append((var, op))
def check(v, place):
V = {}
for ele in W:
(var, op) = ele
if len(op) == 1:
V[var] = int(op[0][place])
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
727 | C | Guess the Array | PROGRAMMING | 1,400 | [
"constructive algorithms",
"interactive",
"math"
] | null | null | This is an interactive problem. You should use flush operation after each printed line. For example, in C++ you should use fflush(stdout), in Java you should use System.out.flush(), and in Pascal — flush(output).
In this problem you should guess an array *a* which is unknown for you. The only information you have init... | none | none | [
"5\n \n9\n \n7\n \n9\n \n11\n \n6\n "
] | [
"? 1 5\n \n? 2 3\n \n? 4 1\n \n? 5 2\n \n? 3 4\n \n! 4 6 1 5 5"
] | The format of a test to make a hack is:
- The first line contains an integer number *n* (3 ≤ *n* ≤ 5000) — the length of the array.- The second line contains *n* numbers *a*<sub class="lower-index">1</sub>, *a*<sub class="lower-index">2</sub>, ..., *a*<sub class="lower-index">*n*</sub> (1 ≤ *a*<sub class="lower-inde... | 1,500 | [
{
"input": "5\n4 6 1 5 5",
"output": "5 out of 5"
},
{
"input": "3\n1 1 1",
"output": "3 out of 3"
},
{
"input": "4\n100 1 100 1",
"output": "4 out of 4"
},
{
"input": "10\n9 5 10 7 4 4 8 5 10 5",
"output": "10 out of 10"
},
{
"input": "3\n1 1 1",
"output": "3... | 1,627,956,017 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 6,963,200 | import sys
flush = sys.stdout.flush
n = int(input())
print('? 1 2')
flush()
value1 = int(input())
print('? 1 3')
flush()
value3 = int(input())
print('? 2 3')
flush()
value2 = int(input())
aux3 = value3 - value1 + value2 / 2
aux2 = value2 - aux3
aux1 = value1 - aux2
answer = [aux1, aux2, aux3]
for i in range(4,... | Title: Guess the Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This is an interactive problem. You should use flush operation after each printed line. For example, in C++ you should use fflush(stdout), in Java you should use System.out.flush(), and in Pascal — flush(output).
In th... | ```python
import sys
flush = sys.stdout.flush
n = int(input())
print('? 1 2')
flush()
value1 = int(input())
print('? 1 3')
flush()
value3 = int(input())
print('? 2 3')
flush()
value2 = int(input())
aux3 = value3 - value1 + value2 / 2
aux2 = value2 - aux3
aux1 = value1 - aux2
answer = [aux1, aux2, aux3]
for i i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of int... | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,675,090,342 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | n ,m=map(int,input().split)
t=0
for a in range(1001):
for b in range(1001):
if a**2+b == n and a+b**2 == m:
t+=1
print(t) | Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immedi... | ```python
n ,m=map(int,input().split)
t=0
for a in range(1001):
for b in range(1001):
if a**2+b == n and a+b**2 == m:
t+=1
print(t)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
845 | C | Two TVs | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at a... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of shows.
Each of the next *n* lines contains two integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=109) — starting and ending time of *i*-th show. | If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes). | [
"3\n1 2\n2 3\n4 5\n",
"4\n1 2\n2 3\n2 3\n1 2\n"
] | [
"YES\n",
"NO\n"
] | none | 0 | [
{
"input": "3\n1 2\n2 3\n4 5",
"output": "YES"
},
{
"input": "4\n1 2\n2 3\n2 3\n1 2",
"output": "NO"
},
{
"input": "4\n0 1\n1 2\n2 3\n3 4",
"output": "YES"
},
{
"input": "3\n1 2\n2 3\n2 4",
"output": "NO"
},
{
"input": "3\n0 100\n0 100\n0 100",
"output": "NO"
... | 1,590,384,593 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 810 | 16,281,600 |
l = []
t = int(input())
for _ in range(t):
n,m = map(int,input().split())
l.append((n,m))
l.sort()
#print(l)
le,ri=-1,-1
for i in range(t):
if l[i][0]>le:
le = l[i][1]
elif l[i][0]>ri:
ri = l[i][1]
else:
print("NO")
exit()
print("YES")
... | Title: Two TVs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains *n* shows, *i*-th of them starts at moment *l**i* and ends at moment *r**i*.
Polycarp owns two TVs. He ... | ```python
l = []
t = int(input())
for _ in range(t):
n,m = map(int,input().split())
l.append((n,m))
l.sort()
#print(l)
le,ri=-1,-1
for i in range(t):
if l[i][0]>le:
le = l[i][1]
elif l[i][0]>ri:
ri = l[i][1]
else:
print("NO")
exit()
print("YES")
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
60 | A | Where Are My Flakes? | PROGRAMMING | 1,300 | [
"implementation",
"two pointers"
] | A. Where Are My Flakes? | 2 | 256 | One morning the Cereal Guy found out that all his cereal flakes were gone. He found a note instead of them. It turned out that his smart roommate hid the flakes in one of *n* boxes. The boxes stand in one row, they are numbered from 1 to *n* from the left to the right. The roommate left hints like "Hidden to the left o... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=1000,<=0<=≤<=*m*<=≤<=1000) which represent the number of boxes and the number of hints correspondingly. Next *m* lines contain hints like "To the left of *i*" and "To the right of *i*", where *i* is integer (1<=≤<=*i*<=≤<=*n*). The hints may coincide. | The answer should contain exactly one integer — the number of boxes that should necessarily be checked or "-1" if the hints are contradictory. | [
"2 1\nTo the left of 2\n",
"3 2\nTo the right of 1\nTo the right of 2\n",
"3 1\nTo the left of 3\n",
"3 2\nTo the left of 2\nTo the right of 1\n"
] | [
"1\n",
"1\n",
"2\n",
"-1\n"
] | none | 500 | [
{
"input": "2 1\nTo the left of 2",
"output": "1"
},
{
"input": "3 2\nTo the right of 1\nTo the right of 2",
"output": "1"
},
{
"input": "3 1\nTo the left of 3",
"output": "2"
},
{
"input": "3 2\nTo the left of 2\nTo the right of 1",
"output": "-1"
},
{
"input": "... | 1,552,117,435 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 248 | 0 | def merge(a, b):
if a[1] < b[0] or b[1] < a[0]:
return -1, -1
return max(a[0], b[0]), min(a[1], b[1] )
n, m = map(int, input().split() )
l, r = 1, n
ok = True
for i in range(m):
s = input().split()
d, x = s[2][0], int(s[-1] )
if d == 'l':
l, r = merge((l, r), (1, x-1) )
else:
... | Title: Where Are My Flakes?
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One morning the Cereal Guy found out that all his cereal flakes were gone. He found a note instead of them. It turned out that his smart roommate hid the flakes in one of *n* boxes. The boxes stand in one row, they are... | ```python
def merge(a, b):
if a[1] < b[0] or b[1] < a[0]:
return -1, -1
return max(a[0], b[0]), min(a[1], b[1] )
n, m = map(int, input().split() )
l, r = 1, n
ok = True
for i in range(m):
s = input().split()
d, x = s[2][0], int(s[-1] )
if d == 'l':
l, r = merge((l, r), (1, x-1) )
... | 3.938 | MatrixStudio/Codeforces-Python-Submissions |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th... | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd pl... | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,586,122,935 | 2,147,483,647 | PyPy 3 | OK | TESTS | 33 | 340 | 2,457,600 | import heapq
n, m = map(int,input().split(' '))
a = list(map(int,input().split(' ')))
pq = []
for x in a:
heapq.heappush(pq, -x)
mx = 0
for i in range(n):
x = -heapq.heappop(pq)
mx += x
heapq.heappush(pq, -(x - 1))
pq = []
for x in a:
heapq.heappush(pq, x)
mn = 0
for i in range(n):
x = heap... | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen pl... | ```python
import heapq
n, m = map(int,input().split(' '))
a = list(map(int,input().split(' ')))
pq = []
for x in a:
heapq.heappush(pq, -x)
mx = 0
for i in range(n):
x = -heapq.heappop(pq)
mx += x
heapq.heappush(pq, -(x - 1))
pq = []
for x in a:
heapq.heappush(pq, x)
mn = 0
for i in range(n):
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
808 | B | Average Sleep Time | PROGRAMMING | 1,300 | [
"data structures",
"implementation",
"math"
] | null | null | It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts *k* days!
When Polycarp went to a doctor with his problem, the doctor asked him about his sleeping schedule (more specifically, the average amount of hours of sleep per week). Luckily, Polycarp k... | The first line contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=2·105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105). | Output average sleeping time over all weeks.
The answer is considered to be correct if its absolute or relative error does not exceed 10<=-<=6. In particular, it is enough to output real number with at least 6 digits after the decimal point. | [
"3 2\n3 4 7\n",
"1 1\n10\n",
"8 2\n1 2 4 100000 123 456 789 1\n"
] | [
"9.0000000000\n",
"10.0000000000\n",
"28964.2857142857\n"
] | In the third example there are *n* - *k* + 1 = 7 weeks, so the answer is sums of all weeks divided by 7. | 0 | [
{
"input": "3 2\n3 4 7",
"output": "9.0000000000"
},
{
"input": "1 1\n10",
"output": "10.0000000000"
},
{
"input": "8 2\n1 2 4 100000 123 456 789 1",
"output": "28964.2857142857"
},
{
"input": "1 1\n1",
"output": "1.0000000000"
},
{
"input": "1 1\n100000",
"ou... | 1,638,710,525 | 425 | PyPy 3 | OK | TESTS | 29 | 249 | 19,968,000 | n,k = map(int, input().split())
A = list(map(int, input().split()))
from itertools import accumulate
C = [0]+A
C = list(accumulate(C))
ans = 0
for i in range(n-k+1):
s = C[i+k]-C[i]
ans += s
print(ans/(n-k+1))
| Title: Average Sleep Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's been almost a week since Polycarp couldn't get rid of insomnia. And as you may already know, one week in Berland lasts *k* days!
When Polycarp went to a doctor with his problem, the doctor asked him about his s... | ```python
n,k = map(int, input().split())
A = list(map(int, input().split()))
from itertools import accumulate
C = [0]+A
C = list(accumulate(C))
ans = 0
for i in range(n-k+1):
s = C[i+k]-C[i]
ans += s
print(ans/(n-k+1))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon piece... | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,695,236,742 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 46 | 0 | n, a, b, c = map(int, input().split())
l = [0 for _ in range(n + 1)]
l[n] = 1
for i in range(n, -1, -1):
if i + a <= n:
if l[i + a] != 0:
l[i] = max(l[i + a] + 1, l[i])
if i + b < n:
if l[i + b] != 0:
l[i] = max(l[i + b] + 1, l[i])
if i + c <= n:
if... | Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the... | ```python
n, a, b, c = map(int, input().split())
l = [0 for _ in range(n + 1)]
l[n] = 1
for i in range(n, -1, -1):
if i + a <= n:
if l[i + a] != 0:
l[i] = max(l[i + a] + 1, l[i])
if i + b < n:
if l[i + b] != 0:
l[i] = max(l[i + b] + 1, l[i])
if i + c <= n:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
509 | B | Painting Pebbles | PROGRAMMING | 1,300 | [
"constructive algorithms",
"greedy",
"implementation"
] | null | null | There are *n* piles of pebbles on the table, the *i*-th pile contains *a**i* pebbles. Your task is to paint each pebble using one of the *k* given colors so that for each color *c* and any two piles *i* and *j* the difference between the number of pebbles of color *c* in pile *i* and number of pebbles of color *c* in p... | The first line of the input contains positive integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100), separated by a space — the number of piles and the number of colors respectively.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) denoting number of pebbles in each of the pile... | If there is no way to paint the pebbles satisfying the given condition, output "NO" (without quotes) .
Otherwise in the first line output "YES" (without quotes). Then *n* lines should follow, the *i*-th of them should contain *a**i* space-separated integers. *j*-th (1<=≤<=*j*<=≤<=*a**i*) of these integers should be eq... | [
"4 4\n1 2 3 4\n",
"5 2\n3 2 4 1 3\n",
"5 4\n3 2 4 3 5\n"
] | [
"YES\n1\n1 4\n1 2 4\n1 2 3 4\n",
"NO\n",
"YES\n1 2 3\n1 3\n1 2 3 4\n1 3 4\n1 1 2 3 4\n"
] | none | 0 | [
{
"input": "4 4\n1 2 3 4",
"output": "YES\n1 \n1 1 \n1 1 2 \n1 1 2 3 "
},
{
"input": "5 2\n3 2 4 1 3",
"output": "NO"
},
{
"input": "5 4\n3 2 4 3 5",
"output": "YES\n1 1 1 \n1 1 \n1 1 1 2 \n1 1 1 \n1 1 1 2 3 "
},
{
"input": "4 3\n5 6 7 8",
"output": "YES\n1 1 1 1 1 \n1 1 ... | 1,617,452,714 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | n,k=map(int,input().split())
A=list(map(int,input().split()))
y=max(A)
x=A.index(max(A))
A[-1],A[x]=A[x],A[-1]
z=max(A[:len(A)-1])
A[-1],A[x]=A[x],A[-1]
if y-z>k:
print("NO")
else:
print("YES")
for i in range(n):
print(*list(range(1,A[i]+1)))
| Title: Painting Pebbles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* piles of pebbles on the table, the *i*-th pile contains *a**i* pebbles. Your task is to paint each pebble using one of the *k* given colors so that for each color *c* and any two piles *i* and *j* the dif... | ```python
n,k=map(int,input().split())
A=list(map(int,input().split()))
y=max(A)
x=A.index(max(A))
A[-1],A[x]=A[x],A[-1]
z=max(A[:len(A)-1])
A[-1],A[x]=A[x],A[-1]
if y-z>k:
print("NO")
else:
print("YES")
for i in range(n):
print(*list(range(1,A[i]+1)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
231 | A | Team | PROGRAMMING | 800 | [
"brute force",
"greedy"
] | null | null | One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution.... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of problems in the contest. Then *n* lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem's solution, otherwise he isn't sure. The second numbe... | Print a single integer — the number of problems the friends will implement on the contest. | [
"3\n1 1 0\n1 1 1\n1 0 0\n",
"2\n1 0 0\n0 1 1\n"
] | [
"2\n",
"1\n"
] | In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn't enough, so the friends won't ta... | 500 | [
{
"input": "3\n1 1 0\n1 1 1\n1 0 0",
"output": "2"
},
{
"input": "2\n1 0 0\n0 1 1",
"output": "1"
},
{
"input": "1\n1 0 0",
"output": "0"
},
{
"input": "2\n1 0 0\n1 1 1",
"output": "1"
},
{
"input": "5\n1 0 0\n0 1 0\n1 1 1\n0 0 1\n0 0 0",
"output": "1"
},
... | 1,696,788,223 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 92 | 0 | n=int(input())
x=0
for i in range(n):
a,b,c=map(int,input().split())
z=a+b+c
if z>=2:
x+=1
print(x) | Title: Team
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decid... | ```python
n=int(input())
x=0
for i in range(n):
a,b,c=map(int,input().split())
z=a+b+c
if z>=2:
x+=1
print(x)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
597 | B | Restaurant | PROGRAMMING | 1,600 | [
"dp",
"greedy",
"sortings"
] | null | null | A restaurant received *n* orders for the rental. Each rental order reserve the restaurant for a continuous period of time, the *i*-th order is characterized by two time values — the start time *l**i* and the finish time *r**i* (*l**i*<=≤<=*r**i*).
Restaurant management can accept and reject orders. What is the maximal... | The first line contains integer number *n* (1<=≤<=*n*<=≤<=5·105) — number of orders. The following *n* lines contain integer values *l**i* and *r**i* each (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=109). | Print the maximal number of orders that can be accepted. | [
"2\n7 11\n4 7\n",
"5\n1 2\n2 3\n3 4\n4 5\n5 6\n",
"6\n4 8\n1 5\n4 7\n2 5\n1 3\n6 8\n"
] | [
"1\n",
"3\n",
"2\n"
] | none | 1,000 | [
{
"input": "2\n7 11\n4 7",
"output": "1"
},
{
"input": "5\n1 2\n2 3\n3 4\n4 5\n5 6",
"output": "3"
},
{
"input": "6\n4 8\n1 5\n4 7\n2 5\n1 3\n6 8",
"output": "2"
},
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "2\n4 6\n4 8",
"output": "1"
},
{
"inp... | 1,447,269,172 | 4,372 | Python 3 | OK | TESTS | 70 | 2,043 | 44,032,000 | n = int(input())
a = [tuple(map(int, input().split())) for _ in range(n)]
#print(a)
a.sort(key = lambda x : x[1])
max_r = -10**10
ans = 0
for l, r in a:
if l > max_r:
ans += 1
max_r = r
print(ans)
| Title: Restaurant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A restaurant received *n* orders for the rental. Each rental order reserve the restaurant for a continuous period of time, the *i*-th order is characterized by two time values — the start time *l**i* and the finish time *r**... | ```python
n = int(input())
a = [tuple(map(int, input().split())) for _ in range(n)]
#print(a)
a.sort(key = lambda x : x[1])
max_r = -10**10
ans = 0
for l, r in a:
if l > max_r:
ans += 1
max_r = r
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
27 | B | Tournament | PROGRAMMING | 1,300 | [
"bitmasks",
"brute force",
"dfs and similar",
"greedy"
] | B. Tournament | 2 | 256 | The tournament «Sleepyhead-2010» in the rapid falling asleep has just finished in Berland. *n* best participants from the country have participated in it. The tournament consists of games, each of them is a match between two participants. *n*·(*n*<=-<=1)<=/<=2 games were played during the tournament, and each participa... | The first line contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of participants. The following *n*·(*n*<=-<=1)<=/<=2<=-<=1 lines contain the results of the games. Each game is described in a single line by two integers *x**i*,<=*y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*,<=*x**i*<=≠<=*y**i*), where *x**i* и *y**i* ar... | Output two integers *x* and *y* — the missing record. If there are several solutions, output any of them. | [
"4\n4 2\n4 1\n2 3\n2 1\n3 1\n"
] | [
"4 3\n"
] | none | 1,000 | [
{
"input": "3\n3 2\n1 2",
"output": "1 3"
},
{
"input": "4\n2 4\n3 4\n1 2\n1 4\n1 3",
"output": "2 3"
},
{
"input": "5\n3 5\n2 5\n1 5\n1 4\n4 3\n1 3\n2 3\n4 5\n4 2",
"output": "1 2"
},
{
"input": "6\n3 4\n3 5\n5 4\n1 2\n5 6\n2 6\n5 2\n3 6\n3 2\n4 6\n2 4\n1 3\n1 5\n1 4",
"... | 1,521,795,677 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 186 | 7,065,600 | winner, loser,amount,people,currmax = {},{},{},int(input()), 0
for line in range(int(people*(people-1)/2)-1):
w,l = list(map(int, input().split(" ")))
if w in winner: winner[w].append(l)
else: winner[w] = [l]
if l in loser: loser[l].append(w)
else: loser[l] = [w]
if w not in amount: amount[w] = 1
else: amount[... | Title: Tournament
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The tournament «Sleepyhead-2010» in the rapid falling asleep has just finished in Berland. *n* best participants from the country have participated in it. The tournament consists of games, each of them is a match between two par... | ```python
winner, loser,amount,people,currmax = {},{},{},int(input()), 0
for line in range(int(people*(people-1)/2)-1):
w,l = list(map(int, input().split(" ")))
if w in winner: winner[w].append(l)
else: winner[w] = [l]
if l in loser: loser[l].append(w)
else: loser[l] = [w]
if w not in amount: amount[w] = 1
els... | 3.940339 | MatrixStudio/Codeforces-Python-Submissions |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,631,430,382 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <iostream>
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll a,b;
ll gt(ll n)
{
if(n==1) return 1;
else{
return n*gt(n-1);
}
}
int main()
{
cin>>a>>b;
if(a>b) swap(a,b);
a=gt(a);
cout<<a;
return 0;
}
| Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
#include <iostream>
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll a,b;
ll gt(ll n)
{
if(n==1) return 1;
else{
return n*gt(n-1);
}
}
int main()
{
cin>>a>>b;
if(a>b) swap(a,b);
a=gt(a);
cout<<a;
return 0;
}
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
560 | A | Currency System in Geraldion | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of ea... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes. | Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1. | [
"5\n1 2 3 4 5\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "10\n371054 506438 397130 1 766759 208409 769264 549213 641270 771837",
"output": "-1"
},
{
"input": "10\n635370 154890 909382 220996 276501 716105 538714 140162 171960 271264",
"o... | 1,564,730,206 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | num=int(input())
count=0
for i in range(0,num):
value=int(input())
if value==1:
count=count+1
if count==0:
print("1")
else:
print("-1")
| Title: Currency System in Geraldion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cann... | ```python
num=int(input())
count=0
for i in range(0,num):
value=int(input())
if value==1:
count=count+1
if count==0:
print("1")
else:
print("-1")
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at prog... | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to... | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,692,530,126 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n = int(input())
x = list(map(int, input().split()))
oneCount = 0
twoCount = 0
threeCount = 0
dict1 = {}
for i in x:
if (i == 1):
oneCount += 1
elif (i == 2):
twoCount += 1
else:
threeCount += 1
teams = 0
if (oneCount <= twoCount and oneCount <= threeCount and oneCo... | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education)... | ```python
n = int(input())
x = list(map(int, input().split()))
oneCount = 0
twoCount = 0
threeCount = 0
dict1 = {}
for i in x:
if (i == 1):
oneCount += 1
elif (i == 2):
twoCount += 1
else:
threeCount += 1
teams = 0
if (oneCount <= twoCount and oneCount <= threeCount... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
768 | B | Code For 1 | PROGRAMMING | 1,600 | [
"constructive algorithms",
"dfs and similar",
"divide and conquer"
] | null | null | Jon fought bravely to rescue the wildlings who were attacked by the white-walkers at Hardhome. On his arrival, Sam tells him that he wants to go to Oldtown to train at the Citadel to become a maester, so he can return and take the deceased Aemon's place as maester of Castle Black. Jon agrees to Sam's proposal and Sam s... | The first line contains three integers *n*, *l*, *r* (0<=≤<=*n*<=<<=250, 0<=≤<=*r*<=-<=*l*<=≤<=105, *r*<=≥<=1, *l*<=≥<=1) – initial element and the range *l* to *r*.
It is guaranteed that *r* is not greater than the length of the final list. | Output the total number of 1s in the range *l* to *r* in the final sequence. | [
"7 2 5\n",
"10 3 10\n"
] | [
"4\n",
"5\n"
] | Consider first example:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/288fbb682a6fa1934a47b763d6851f9d32a06150.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Elements on positions from 2-nd to 5-th in list is [1, 1, 1, 1]. The number of ones is 4.
For the second example:
<img al... | 1,000 | [
{
"input": "7 2 5",
"output": "4"
},
{
"input": "10 3 10",
"output": "5"
},
{
"input": "56 18 40",
"output": "20"
},
{
"input": "203 40 124",
"output": "67"
},
{
"input": "903316762502 354723010040 354723105411",
"output": "78355"
},
{
"input": "335343... | 1,678,988,799 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | def main():
n, l, r = map(int, input().split())
def get_ones(n):
if n == 0:
return 0
if n == 1:
return 1
return 1 + get_ones(n//2)
def get_ones_in_range(n, l, r):
if n == 0:
return 0
if n == 1:
re... | Title: Code For 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jon fought bravely to rescue the wildlings who were attacked by the white-walkers at Hardhome. On his arrival, Sam tells him that he wants to go to Oldtown to train at the Citadel to become a maester, so he can return and ta... | ```python
def main():
n, l, r = map(int, input().split())
def get_ones(n):
if n == 0:
return 0
if n == 1:
return 1
return 1 + get_ones(n//2)
def get_ones_in_range(n, l, r):
if n == 0:
return 0
if n == 1:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
471 | A | MUH and Sticks | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an elephant or a bear from those sticks. They can make an animal from sticks in the following way:
-... | The single line contains six space-separated integers *l**i* (1<=≤<=*l**i*<=≤<=9) — the lengths of the six sticks. It is guaranteed that the input is such that you cannot make both animals from the sticks. | If you can make a bear from the given set, print string "Bear" (without the quotes). If you can make an elephant, print string "Elephant" (wıthout the quotes). If you can make neither a bear nor an elephant, print string "Alien" (without the quotes). | [
"4 2 5 4 4 4\n",
"4 4 5 4 4 5\n",
"1 2 3 4 5 6\n"
] | [
"Bear",
"Elephant",
"Alien"
] | If you're out of creative ideas, see instructions below which show how to make a bear and an elephant in the first two samples. The stick of length 2 is in red, the sticks of length 4 are in green, the sticks of length 5 are in blue. | 500 | [
{
"input": "4 2 5 4 4 4",
"output": "Bear"
},
{
"input": "4 4 5 4 4 5",
"output": "Elephant"
},
{
"input": "1 2 3 4 5 6",
"output": "Alien"
},
{
"input": "5 5 5 5 5 5",
"output": "Elephant"
},
{
"input": "1 1 1 2 3 5",
"output": "Alien"
},
{
"input": "... | 1,625,619,256 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 62 | 0 | g = list(map(int,input().split()))
c = len(set(g))
if len(g) == 2:
if g.count(max(g)) == 1:
print('Elephant')
exit()
else:
print('Bear')
exit()
print('Bear' if c == 3 else ('Elephant' if c == 2 or c == 1 else 'Alien')) | Title: MUH and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two polar bears Menshykov and Uslada from the St.Petersburg zoo and elephant Horace from the Kiev zoo got six sticks to play with and assess the animals' creativity. Menshykov, Uslada and Horace decided to make either an... | ```python
g = list(map(int,input().split()))
c = len(set(g))
if len(g) == 2:
if g.count(max(g)) == 1:
print('Elephant')
exit()
else:
print('Bear')
exit()
print('Bear' if c == 3 else ('Elephant' if c == 2 or c == 1 else 'Alien'))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,681,748,555 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 |
info = input().split()
length = int(info[0])
time=int(info[1])
arr=input().split()
left=0
right=length-1
sum=0
while 1==1:
sum=0
for i in range(left, right):
sum = sum+int(arr[i])
if sum>time:
if int(arr[left])>int(arr[right]):
left=left+1
else:
right=right-1
if sum <=t... | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
info = input().split()
length = int(info[0])
time=int(info[1])
arr=input().split()
left=0
right=length-1
sum=0
while 1==1:
sum=0
for i in range(left, right):
sum = sum+int(arr[i])
if sum>time:
if int(arr[left])>int(arr[right]):
left=left+1
else:
right=right-1
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,537,689,913 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | l = input()
if l.find('h') == -1:
print('NO')
elif l.find('e', l.find('h')) == -1:
print('NO')
elif l.find('l', l.find('e', l.find('h'))) == -1:
print('NO')
elif l.find('l', l.find('l', l.find('e', l.find('h')))) == -1:
print('NO')
elif l.find('o', l.find('l', l.find('l', l.find('e', l.find('... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
l = input()
if l.find('h') == -1:
print('NO')
elif l.find('e', l.find('h')) == -1:
print('NO')
elif l.find('l', l.find('e', l.find('h'))) == -1:
print('NO')
elif l.find('l', l.find('l', l.find('e', l.find('h')))) == -1:
print('NO')
elif l.find('o', l.find('l', l.find('l', l.find('e'... | 0 | MatrixStudio/Codeforces-Python-Submissions |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,579,947,199 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 248 | 0 | n=int(input())
l=list(map(int,input().split()))[:n]
for i in range(len(l)-1):
m=l[i]
l[i]=l[i+1]
l[i+1]=m
d=0
for i in range(len(l)-1):
if l[i]==l[i+1]:
d=1
break
if d==0:
print("YES")
else:
print("NO")
| Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
n=int(input())
l=list(map(int,input().split()))[:n]
for i in range(len(l)-1):
m=l[i]
l[i]=l[i+1]
l[i+1]=m
d=0
for i in range(len(l)-1):
if l[i]==l[i+1]:
d=1
break
if d==0:
print("YES")
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
486 | A | Calculating Function | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*. | The single line contains the positive integer *n* (1<=≤<=*n*<=≤<=1015). | Print *f*(*n*) in a single line. | [
"4\n",
"5\n"
] | [
"2\n",
"-3\n"
] | *f*(4) = - 1 + 2 - 3 + 4 = 2
*f*(5) = - 1 + 2 - 3 + 4 - 5 = - 3 | 500 | [
{
"input": "4",
"output": "2"
},
{
"input": "5",
"output": "-3"
},
{
"input": "1000000000",
"output": "500000000"
},
{
"input": "1000000001",
"output": "-500000001"
},
{
"input": "1000000000000000",
"output": "500000000000000"
},
{
"input": "100",
... | 1,691,244,585 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 31 | 0 | a=int(input())
k=0
if (a/2)%2==0:
print(a//2)
else:
print(int(-1*((a+1)/2))) | Title: Calculating Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
For a positive integer *n* let's define a function *f*:
*f*(*n*)<==<=<=-<=1<=+<=2<=-<=3<=+<=..<=+<=(<=-<=1)*n**n*
Your task is to calculate *f*(*n*) for a given integer *n*.
Input Specification:
The single line... | ```python
a=int(input())
k=0
if (a/2)%2==0:
print(a//2)
else:
print(int(-1*((a+1)/2)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
375 | A | Divisible by Seven | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.
Number *a* doesn't contain any leading zeroes and contains digits 1, 6, 8, 9 (it also can contain another digits). The resu... | The first line contains positive integer *a* in the decimal record. It is guaranteed that the record of number *a* contains digits: 1, 6, 8, 9. Number *a* doesn't contain any leading zeroes. The decimal representation of number *a* contains at least 4 and at most 106 characters. | Print a number in the decimal notation without leading zeroes — the result of the permutation.
If it is impossible to rearrange the digits of the number *a* in the required manner, print 0. | [
"1689\n",
"18906\n"
] | [
"1869\n",
"18690\n"
] | none | 500 | [
{
"input": "1689",
"output": "1869"
},
{
"input": "18906",
"output": "18690"
},
{
"input": "2419323689",
"output": "2432391689"
},
{
"input": "8589157262",
"output": "5857221986"
},
{
"input": "2717172350336955863014903670481525170997949309274087058935108848979319... | 1,611,899,215 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 119,705,600 |
from itertools import permutations
# Main function
def find_gcd_permutations_of_digit(given_number):
"""
Returns the gcd of all numbers that can be
obtained by permuting the digits of given_number
"""
s = str(given_number)
perms = permutations(s)
num_list = []
for p in perms:
if p[0] == '0':
... | Title: Divisible by Seven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have number *a*, whose decimal representation quite luckily contains digits 1, 6, 8, 9. Rearrange the digits in its decimal representation so that the resulting number will be divisible by 7.
Number *a* doesn't ... | ```python
from itertools import permutations
# Main function
def find_gcd_permutations_of_digit(given_number):
"""
Returns the gcd of all numbers that can be
obtained by permuting the digits of given_number
"""
s = str(given_number)
perms = permutations(s)
num_list = []
for p in perms:
if p[0] ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,640,250,777 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | s = input()
n=len(s)
ans=0
idx=s.find("bear",0)
pidx=-1
while(idx!=-1):
ans+=(idx-pidx)*(n-idx-3)
pidx=idx
idx=s.find("bear",idx+4)
print(ans)
| Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
s = input()
n=len(s)
ans=0
idx=s.find("bear",0)
pidx=-1
while(idx!=-1):
ans+=(idx-pidx)*(n-idx-3)
pidx=idx
idx=s.find("bear",idx+4)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
729 | A | Interview with Oleg | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a filler word ogo in Oleg's speech. All words that can be obtained from ogo by adding go several times to the... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the length of the interview.
The second line contains the string *s* of length *n*, consisting of lowercase English letters. | Print the interview text after the replacement of each of the fillers with "***". It is allowed for the substring "***" to have several consecutive occurences. | [
"7\naogogob\n",
"13\nogogmgogogogo\n",
"9\nogoogoogo\n"
] | [
"a***b\n",
"***gmg***\n",
"*********\n"
] | The first sample contains one filler word ogogo, so the interview for printing is "a***b".
The second sample contains two fillers ogo and ogogogo. Thus, the interview is transformed to "***gmg***". | 500 | [
{
"input": "7\naogogob",
"output": "a***b"
},
{
"input": "13\nogogmgogogogo",
"output": "***gmg***"
},
{
"input": "9\nogoogoogo",
"output": "*********"
},
{
"input": "32\nabcdefogoghijklmnogoopqrstuvwxyz",
"output": "abcdef***ghijklmn***opqrstuvwxyz"
},
{
"input":... | 1,673,571,007 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 46 | 0 | n = int(input())
s = input()
check = True
ans = ""
a = 0
if n < 3:
print(s)
else:
for i in range(n):
i += a
if i > n - 1 and check:
break
if check:
if s[i:i + 3] == "ogo":
check = False
a += 2
ans += ... | Title: Interview with Oleg
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has interviewed Oleg and has written the interview down without punctuation marks and spaces to save time. Thus, the interview is now a string *s* consisting of *n* lowercase English letters.
There is a fi... | ```python
n = int(input())
s = input()
check = True
ans = ""
a = 0
if n < 3:
print(s)
else:
for i in range(n):
i += a
if i > n - 1 and check:
break
if check:
if s[i:i + 3] == "ogo":
check = False
a += 2
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
540 | A | Combination Lock | PROGRAMMING | 800 | [
"implementation"
] | null | null | Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is represented by *n* rotating disks with digits from 0 to 9 written on them. Scrooge McDuck has to turn ... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of disks on the combination lock.
The second line contains a string of *n* digits — the original state of the disks.
The third line contains a string of *n* digits — Scrooge McDuck's combination that opens the lock. | Print a single integer — the minimum number of moves Scrooge McDuck needs to open the lock. | [
"5\n82195\n64723\n"
] | [
"13\n"
] | In the sample he needs 13 moves:
- 1 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/b8967f65a723782358b93eff9ce69f336817cf70.png" style="max-width: 100.0%;max-height: 100.0%;"/> - 2 disk: <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/07fa58573ece0d32... | 500 | [
{
"input": "5\n82195\n64723",
"output": "13"
},
{
"input": "12\n102021090898\n010212908089",
"output": "16"
},
{
"input": "1\n8\n1",
"output": "3"
},
{
"input": "2\n83\n57",
"output": "7"
},
{
"input": "10\n0728592530\n1362615763",
"output": "27"
},
{
... | 1,655,289,582 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | n = int(input())
p = list(map(int, input()))
k = list(map(int, input()))
count = 0
for i in range(len(p)):
count += min(max(p[i], k[i]) - min(p[i], k[i]), 10 - max(p[i], k[i]) + min(p[i], k[i]))
print(count) | Title: Combination Lock
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scrooge McDuck keeps his most treasured savings in a home safe with a combination lock. Each time he wants to put there the treasures that he's earned fair and square, he has to open the lock.
The combination lock is ... | ```python
n = int(input())
p = list(map(int, input()))
k = list(map(int, input()))
count = 0
for i in range(len(p)):
count += min(max(p[i], k[i]) - min(p[i], k[i]), 10 - max(p[i], k[i]) + min(p[i], k[i]))
print(count)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
609 | A | USB Flash Drives | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of USB flash drives needed to write Sean's file, if he can split the file between drives. | The first line contains positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of USB flash drives.
The second line contains positive integer *m* (1<=≤<=*m*<=≤<=105) — the size of Sean's file.
Each of the next *n* lines contains positive integer *a**i* (1<=≤<=*a**i*<=≤<=1000) — the sizes of USB flash drives in megabyt... | Print the minimum number of USB flash drives to write Sean's file, if he can split the file between drives. | [
"3\n5\n2\n1\n3\n",
"3\n6\n2\n3\n2\n",
"2\n5\n5\n10\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first example Sean needs only two USB flash drives — the first and the third.
In the second example Sean needs all three USB flash drives.
In the third example Sean needs only one USB flash drive and he can use any available USB flash drive — the first or the second. | 0 | [
{
"input": "3\n5\n2\n1\n3",
"output": "2"
},
{
"input": "3\n6\n2\n3\n2",
"output": "3"
},
{
"input": "2\n5\n5\n10",
"output": "1"
},
{
"input": "5\n16\n8\n1\n3\n4\n9",
"output": "2"
},
{
"input": "10\n121\n10\n37\n74\n56\n42\n39\n6\n68\n8\n100",
"output": "2"
... | 1,532,351,374 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 109 | 0 | n=int(input())
m=int(input())
c=0
lis_input=[int(i) for i in input().split(" ")]
print(lis_input)
lis_output=sorted(lis_input)
print(lis_output)
for i in range(n,0,-1):
if 0<(m - int(lis_output[i-1])):
c+=1
m = (m - int(lis_output[i-1]))
elif m-int(lis_output[i-1])<=0:
c+=1
break... | Title: USB Flash Drives
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sean is trying to save a large file to a USB flash drive. He has *n* USB flash drives with capacities equal to *a*1,<=*a*2,<=...,<=*a**n* megabytes. The file size is equal to *m* megabytes.
Find the minimum number of... | ```python
n=int(input())
m=int(input())
c=0
lis_input=[int(i) for i in input().split(" ")]
print(lis_input)
lis_output=sorted(lis_input)
print(lis_output)
for i in range(n,0,-1):
if 0<(m - int(lis_output[i-1])):
c+=1
m = (m - int(lis_output[i-1]))
elif m-int(lis_output[i-1])<=0:
c+=1
... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Eighth-grader Vova is on duty today in the class. After classes, he went into the office to wash the board, and found on it the number *n*. He asked what is this number and the teacher of mathematics Inna Petrovna answered Vova that *n* is the answer to the arithmetic task for first-graders. In the textbook, a certain ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=109). | In the first line print one integer *k* — number of different values of *x* satisfying the condition.
In next *k* lines print these values in ascending order. | [
"21\n",
"20\n"
] | [
"1\n15\n",
"0\n"
] | In the first test case *x* = 15 there is only one variant: 15 + 1 + 5 = 21.
In the second test case there are no such *x*. | 0 | [
{
"input": "21",
"output": "1\n15"
},
{
"input": "20",
"output": "0"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "1\n1"
},
{
"input": "3",
"output": "0"
},
{
"input": "100000001",
"output": "2\n99999937\n100000000"
},
{
"i... | 1,508,155,322 | 3,422 | Python 3 | WRONG_ANSWER | PRETESTS | 5 | 46 | 0 | def digitSum(number):
sum = 0
while number > 0:
number, remainder = divmod(number, 10)
sum += remainder
return sum
n = int(input())
answers = []
for i in range(n - 1, n - 100, -1):
if i < 1:
break
if i + digitSum(i) == n:
answers.append(i)
print(len(answers))
for ans in answers:
print(ans) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eighth-grader Vova is on duty today in the class. After classes, he went into the office to wash the board, and found on it the number *n*. He asked what is this number and the teacher of mathematics Inna Petrovna answered Vova th... | ```python
def digitSum(number):
sum = 0
while number > 0:
number, remainder = divmod(number, 10)
sum += remainder
return sum
n = int(input())
answers = []
for i in range(n - 1, n - 100, -1):
if i < 1:
break
if i + digitSum(i) == n:
answers.append(i)
print(len(answers))
for ans in answers:
print(ans)
`... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules o... | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it a... | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,681,676,832 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | a1, a2, a3, a4 = map(int, input().split())
s = input()
count= 0
for i in s:
if int(i) == a1: count += a1
if int(i) == a2: count += a2
if int(i) == a3: count += a3
if int(i) == a4: count += a4
print(count) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four ve... | ```python
a1, a2, a3, a4 = map(int, input().split())
s = input()
count= 0
for i in s:
if int(i) == a1: count += a1
if int(i) == a2: count += a2
if int(i) == a3: count += a3
if int(i) == a4: count += a4
print(count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
688 | A | Opponents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of them all. That means if one day at least one of Arya's opponents is absent at the school, then Ar... | The first line of the input contains two integers *n* and *d* (1<=≤<=*n*,<=*d*<=≤<=100) — the number of opponents and the number of days, respectively.
The *i*-th of the following *d* lines contains a string of length *n* consisting of characters '0' and '1'. The *j*-th character of this string is '0' if the *j*-th op... | Print the only integer — the maximum number of consecutive days that Arya will beat all present opponents. | [
"2 2\n10\n00\n",
"4 1\n0100\n",
"4 5\n1101\n1111\n0110\n1011\n1111\n"
] | [
"2\n",
"1\n",
"2\n"
] | In the first and the second samples, Arya will beat all present opponents each of the *d* days.
In the third sample, Arya will beat his opponents on days 1, 3 and 4 and his opponents will beat him on days 2 and 5. Thus, the maximum number of consecutive winning days is 2, which happens on days 3 and 4. | 500 | [
{
"input": "2 2\n10\n00",
"output": "2"
},
{
"input": "4 1\n0100",
"output": "1"
},
{
"input": "4 5\n1101\n1111\n0110\n1011\n1111",
"output": "2"
},
{
"input": "3 2\n110\n110",
"output": "2"
},
{
"input": "10 6\n1111111111\n0100110101\n1111111111\n0000011010\n1111... | 1,591,387,845 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 124 | 0 | n, d = input().split()
n, d = int(n), int(d)
maximum = 0
current = 0
for each_d in range(d):
s = input()
if s.count('1') != n:
current = current + 1
if current > maximum:
maximum = current
else:
current = 0
print(maximum) | Title: Opponents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Arya has *n* opponents in the school. Each day he will fight with all opponents who are present this day. His opponents have some fighting plan that guarantees they will win, but implementing this plan requires presence of th... | ```python
n, d = input().split()
n, d = int(n), int(d)
maximum = 0
current = 0
for each_d in range(d):
s = input()
if s.count('1') != n:
current = current + 1
if current > maximum:
maximum = current
else:
current = 0
print(maximum)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
409 | H | A + B Strikes Back | PROGRAMMING | 1,500 | [
"*special",
"brute force",
"constructive algorithms",
"dsu",
"implementation"
] | null | null | A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try? | The input contains two integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=103), separated by a single space. | Output the sum of the given integers. | [
"5 14\n",
"381 492\n"
] | [
"19\n",
"873\n"
] | none | 0 | [
{
"input": "5 14",
"output": "19"
},
{
"input": "381 492",
"output": "873"
},
{
"input": "536 298",
"output": "834"
},
{
"input": "143 522",
"output": "665"
},
{
"input": "433 126",
"output": "559"
},
{
"input": "723 350",
"output": "1073"
},
{... | 1,592,759,263 | 2,263 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | a,b=map(float,input().split())
print(a+b)
| Title: A + B Strikes Back
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input ... | ```python
a,b=map(float,input().split())
print(a+b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
614 | B | Gena's Code | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from each country, find their product. If it is turns to be too large, then the servers might have not en... | The first line of the input contains the number of countries *n* (1<=≤<=*n*<=≤<=100<=000). The second line contains *n* non-negative integers *a**i* without leading zeroes — the number of tanks of the *i*-th country.
It is guaranteed that the second line contains at least *n*<=-<=1 beautiful numbers and the total leng... | Print a single number without leading zeroes — the product of the number of tanks presented by each country. | [
"3\n5 10 1\n",
"4\n1 1 10 11\n",
"5\n0 3 1 100 1\n"
] | [
"50",
"110",
"0"
] | In sample 1 numbers 10 and 1 are beautiful, number 5 is not not.
In sample 2 number 11 is not beautiful (contains two '1's), all others are beautiful.
In sample 3 number 3 is not beautiful, all others are beautiful. | 1,000 | [
{
"input": "3\n5 10 1",
"output": "50"
},
{
"input": "4\n1 1 10 11",
"output": "110"
},
{
"input": "5\n0 3 1 100 1",
"output": "0"
},
{
"input": "40\n10 100 10 1 10 10 100 10 10 100 10 100 100 10 1824868942 100 100 1 10 100 100 10 100 100 10 100 10 1 10 100 100 100 10 1 10 1 ... | 1,641,797,922 | 2,147,483,647 | PyPy 3 | OK | TESTS | 32 | 108 | 8,089,600 | n = int(input())
s = list(map(str, input().split()))
cnt = 0
front = '1'
for c in s:
f = 0
if c[0] == '0':
print(0)
exit(0)
else:
if c[0] == '1':
for i in c[1:]:
if i != '0':
f = 1
else:
f = 1
... | Title: Gena's Code
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's the year 4527 and the tanks game that we all know and love still exists. There also exists Great Gena's code, written in 2016. The problem this code solves is: given the number of tanks that go into the battle from eac... | ```python
n = int(input())
s = list(map(str, input().split()))
cnt = 0
front = '1'
for c in s:
f = 0
if c[0] == '0':
print(0)
exit(0)
else:
if c[0] == '1':
for i in c[1:]:
if i != '0':
f = 1
else:
f = ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
15 | B | Laser | PROGRAMMING | 1,800 | [
"math"
] | B. Laser | 1 | 64 | Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of *n*<=×<=*m* cells and a robotic arm. Each cell of the field is a 1<=×<=1 square. The robotic arm has two l... | The first line contains one integer number *t* (1<=≤<=*t*<=≤<=10000) — the number of test sets. Each of the following *t* lines describes one test set. Each line contains integer numbers *n*, *m*, *x*1, *y*1, *x*2, *y*2, separated by a space (2<=≤<=*n*,<=*m*<=≤<=109, 1<=≤<=*x*1,<=*x*2<=≤<=*n*, 1<=≤<=*y*1,<=*y*2<=≤<=*m*... | Each of the *t* lines of the output should contain the answer to the corresponding input test set. | [
"2\n4 4 1 1 3 3\n4 3 1 1 2 2\n"
] | [
"8\n2\n"
] | none | 0 | [
{
"input": "2\n4 4 1 1 3 3\n4 3 1 1 2 2",
"output": "8\n2"
},
{
"input": "1\n2 2 1 2 2 1",
"output": "2"
},
{
"input": "1\n2 2 1 2 2 1",
"output": "2"
},
{
"input": "1\n3 3 3 2 1 1",
"output": "5"
},
{
"input": "1\n3 4 1 1 1 2",
"output": "0"
},
{
"inp... | 1,432,722,505 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | __author__ = 'Darren'
def solve():
t = int(input())
while t:
run()
t -= 1
def run():
n, m, x1, y1, x2, y2 = map(int, input().split())
width, height = abs(x1 - x2), abs(y1 - y2)
overlap_width, overlap_height = max(0, width * 2 - n), max(0, height * 2 - m)
print(w... | Title: Laser
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Petya is the most responsible worker in the Research Institute. So he was asked to make a very important experiment: to melt the chocolate bar with a new laser device. The device consists of a rectangular field of *n*<=×<=*m* cells an... | ```python
__author__ = 'Darren'
def solve():
t = int(input())
while t:
run()
t -= 1
def run():
n, m, x1, y1, x2, y2 = map(int, input().split())
width, height = abs(x1 - x2), abs(y1 - y2)
overlap_width, overlap_height = max(0, width * 2 - n), max(0, height * 2 - m)
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
248 | A | Cupboards | PROGRAMMING | 800 | [
"implementation"
] | null | null | One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any longer, so he decided to get some food in the house.
Karlsson's gaze immediately fell on *n* woode... | The first input line contains a single integer *n* — the number of cupboards in the kitchen (2<=≤<=*n*<=≤<=104). Then follow *n* lines, each containing two integers *l**i* and *r**i* (0<=≤<=*l**i*,<=*r**i*<=≤<=1). Number *l**i* equals one, if the left door of the *i*-th cupboard is opened, otherwise number *l**i* equal... | In the only output line print a single integer *t* — the minimum number of seconds Karlsson needs to change the doors of all cupboards to the position he needs. | [
"5\n0 1\n1 0\n0 1\n1 1\n0 1\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "5\n0 1\n1 0\n0 1\n1 1\n0 1",
"output": "3"
},
{
"input": "2\n0 0\n0 0",
"output": "0"
},
{
"input": "3\n0 1\n1 1\n1 1",
"output": "1"
},
{
"input": "8\n0 1\n1 0\n0 1\n1 1\n0 1\n1 0\n0 1\n1 0",
"output": "7"
},
{
"input": "8\n1 0\n1 0\n1 0\n0 1\n0 1\n1 ... | 1,631,243,609 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 216 | 20,172,800 | n=int(input())
L,R=0,0
for i in range(n):
l,r=map(int,input().split())
if l==1:
L+=1
if r==1:
R+=1
print(min((R+n-L),(L+n-R))) | Title: Cupboards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One foggy Stockholm morning, Karlsson decided to snack on some jam in his friend Lillebror Svantenson's house. Fortunately for Karlsson, there wasn't anybody in his friend's house. Karlsson was not going to be hungry any long... | ```python
n=int(input())
L,R=0,0
for i in range(n):
l,r=map(int,input().split())
if l==1:
L+=1
if r==1:
R+=1
print(min((R+n-L),(L+n-R)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | There are *n* types of coins in Byteland. Conveniently, the denomination of the coin type *k* divides the denomination of the coin type *k*<=+<=1, the denomination of the coin type 1 equals 1 tugrick. The ratio of the denominations of coin types *k*<=+<=1 and *k* equals *a**k*. It is known that for each *x* there are a... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=3·105) — the number of coin types.
The second line contains *n*<=-<=1 integers *a*1, *a*2, ..., *a**n*<=-<=1 (1<=≤<=*a**k*<=≤<=109) — the ratios between the coin types denominations. It is guaranteed that for each *x* there are at most 20 coin types of denomina... | Print single integer — the number of ways to pay exactly *m* tugricks modulo 109<=+<=7. | [
"1\n\n4\n2\n",
"2\n1\n4 4\n2\n",
"3\n3 3\n10 10 10\n17\n"
] | [
"1\n",
"3\n",
"6\n"
] | In the first example Byteasar has 4 coins of denomination 1, and he has to pay 2 tugricks. There is only one way.
In the second example Byteasar has 4 coins of each of two different types of denomination 1, he has to pay 2 tugricks. There are 3 ways: pay one coin of the first type and one coin of the other, pay two co... | 0 | [
{
"input": "1\n\n4\n2",
"output": "1"
},
{
"input": "2\n1\n4 4\n2",
"output": "3"
},
{
"input": "3\n3 3\n10 10 10\n17",
"output": "6"
},
{
"input": "2\n2\n200000 100000\n34567",
"output": "17284"
},
{
"input": "20\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2\n1 1 1 1 1 ... | 1,485,112,873 | 3,973 | PyPy 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 11 | 1,000 | 43,212,800 | p = 1000000007
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
m = int(input())
d = [1 for _ in range(b[0] + 1)]
for i in range(1, n):
if a[i - 1] != 1:
t = m % a[i - 1]
m //= a[i - 1]
d = [d[j * a[i - 1] + t] for j in range((len(d) - t - 1) // a[i - 1] + 1)... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* types of coins in Byteland. Conveniently, the denomination of the coin type *k* divides the denomination of the coin type *k*<=+<=1, the denomination of the coin type 1 equals 1 tugrick. The ratio of the denomination... | ```python
p = 1000000007
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
m = int(input())
d = [1 for _ in range(b[0] + 1)]
for i in range(1, n):
if a[i - 1] != 1:
t = m % a[i - 1]
m //= a[i - 1]
d = [d[j * a[i - 1] + t] for j in range((len(d) - t - 1) // a[i... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
445 | B | DZY Loves Chemistry | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu",
"greedy"
] | null | null | DZY loves chemistry, and he enjoys mixing chemicals.
DZY has *n* chemicals, and *m* pairs of them will react. He wants to pour these chemicals into a test tube, and he needs to pour them in one by one, in any order.
Let's consider the danger of a test tube. Danger of an empty test tube is 1. And every time when DZY ... | The first line contains two space-separated integers *n* and *m* .
Each of the next *m* lines contains two space-separated integers *x**i* and *y**i* (1<=≤<=*x**i*<=<<=*y**i*<=≤<=*n*). These integers mean that the chemical *x**i* will react with the chemical *y**i*. Each pair of chemicals will appear at most once i... | Print a single integer — the maximum possible danger. | [
"1 0\n",
"2 1\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"1\n",
"2\n",
"4\n"
] | In the first sample, there's only one way to pour, and the danger won't increase.
In the second sample, no matter we pour the 1st chemical first, or pour the 2nd chemical first, the answer is always 2.
In the third sample, there are four ways to achieve the maximum possible danger: 2-1-3, 2-3-1, 1-2-3 and 3-2-1 (that... | 1,000 | [
{
"input": "1 0",
"output": "1"
},
{
"input": "2 1\n1 2",
"output": "2"
},
{
"input": "3 2\n1 2\n2 3",
"output": "4"
},
{
"input": "10 10\n1 8\n4 10\n4 6\n5 10\n2 3\n1 7\n3 4\n3 6\n6 9\n3 7",
"output": "512"
},
{
"input": "20 20\n6 8\n13 20\n7 13\n6 17\n5 15\n1 12... | 1,624,920,771 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 109 | 512,000 | from collections import defaultdict, Counter
from math import sqrt, log10, log2, log, gcd, floor, factorial
from bisect import bisect_left, bisect_right
from itertools import combinations, combinations_with_replacement
import sys, io, os
input=sys.stdin.readline
input=io.BytesIO(os.read(0,os.fstat(0).st_size)).re... | Title: DZY Loves Chemistry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY loves chemistry, and he enjoys mixing chemicals.
DZY has *n* chemicals, and *m* pairs of them will react. He wants to pour these chemicals into a test tube, and he needs to pour them in one by one, in any order... | ```python
from collections import defaultdict, Counter
from math import sqrt, log10, log2, log, gcd, floor, factorial
from bisect import bisect_left, bisect_right
from itertools import combinations, combinations_with_replacement
import sys, io, os
input=sys.stdin.readline
input=io.BytesIO(os.read(0,os.fstat(0).st... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,593,692,194 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 8 | 218 | 7,270,400 | n=int(input())
c=[int(x) for x in input().split()]
b=min(c)
count=c.count(b)
if count==1:
print(n)
else:
print("Still Rozdil") | Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
n=int(input())
c=[int(x) for x in input().split()]
b=min(c)
count=c.count(b)
if count==1:
print(n)
else:
print("Still Rozdil")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
254 | A | Cards with Numbers | PROGRAMMING | 1,200 | [
"constructive algorithms",
"sortings"
] | null | null | Petya has got 2*n* cards, each card contains some integer. The numbers on the cards can be the same. Let's index all cards by consecutive integers from 1 to 2*n*. We'll denote the number that is written on a card with number *i*, as *a**i*. In order to play one entertaining game with his friends, Petya needs to split t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains the sequence of 2*n* positive integers *a*1,<=*a*2,<=...,<=*a*2*n* (1<=≤<=*a**i*<=≤<=5000) — the numbers that are written on the cards. The numbers on the line are separated by single spaces. | If it is impossible to divide the cards into pairs so that cards in each pair had the same numbers, print on a single line integer -1. But if the required partition exists, then print *n* pairs of integers, a pair per line — the indices of the cards that form the pairs.
Separate the numbers on the lines by spaces. You... | [
"3\n20 30 10 30 20 10\n",
"1\n1 2\n"
] | [
"4 2\n1 5\n6 3\n",
"-1"
] | none | 500 | [
{
"input": "3\n20 30 10 30 20 10",
"output": "4 2\n1 5\n6 3"
},
{
"input": "1\n1 2",
"output": "-1"
},
{
"input": "5\n2 2 2 2 2 1 2 2 1 2",
"output": "2 1\n3 4\n7 5\n6 9\n10 8"
},
{
"input": "5\n2 1 2 2 1 1 1 1 1 2",
"output": "3 1\n2 5\n7 6\n8 9\n10 4"
},
{
"inpu... | 1,609,664,052 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 74,547,200 | import sys
sys.stdin,sys.stdout = open('input.txt','r'), open('output.txt','w')
n = int(sys.stdin.readline())
a =[[int(x),i+1] for i,x in enumerate(sys.stdin.readline().split())]
a.sort()
if any(x[0]!=y[0] for x,y in zip(a[0::2],a[1::2])):
sys.stdout.write(str(-1))
else:
sys.stdout.write("".join([str(x[... | Title: Cards with Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has got 2*n* cards, each card contains some integer. The numbers on the cards can be the same. Let's index all cards by consecutive integers from 1 to 2*n*. We'll denote the number that is written on a card wit... | ```python
import sys
sys.stdin,sys.stdout = open('input.txt','r'), open('output.txt','w')
n = int(sys.stdin.readline())
a =[[int(x),i+1] for i,x in enumerate(sys.stdin.readline().split())]
a.sort()
if any(x[0]!=y[0] for x,y in zip(a[0::2],a[1::2])):
sys.stdout.write(str(-1))
else:
sys.stdout.write("".jo... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,631,687,012 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 6,758,400 | n= int(input())
fin= list(map(int,input().split()))
fin= sum(fin)
c=0
for i in range(1,6):
if (fin+i)%(n+1)!=1:
c+=1
print(c) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n= int(input())
fin= list(map(int,input().split()))
fin= sum(fin)
c=0
for i in range(1,6):
if (fin+i)%(n+1)!=1:
c+=1
print(c)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
595 | A | Vitaly and Night | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vitaly sees a building of *n* floors and 2·*m* windows on each floor. On each floor there are *m* flats num... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of floors in the house and the number of flats on each floor respectively.
Next *n* lines describe the floors from top to bottom and contain 2·*m* characters each. If the *i*-th window of the given floor has lights on,... | Print a single integer — the number of flats that have lights on in at least one window, that is, the flats where, according to Vitaly, people aren't sleeping. | [
"2 2\n0 0 0 1\n1 0 1 1\n",
"1 3\n1 1 0 1 0 0\n"
] | [
"3\n",
"2\n"
] | In the first test case the house has two floors, two flats on each floor. That is, in total there are 4 flats. The light isn't on only on the second floor in the left flat. That is, in both rooms of the flat the light is off.
In the second test case the house has one floor and the first floor has three flats. The ligh... | 500 | [
{
"input": "2 2\n0 0 0 1\n1 0 1 1",
"output": "3"
},
{
"input": "1 3\n1 1 0 1 0 0",
"output": "2"
},
{
"input": "3 3\n1 1 1 1 1 1\n1 1 0 1 1 0\n1 0 0 0 1 1",
"output": "8"
},
{
"input": "1 5\n1 0 1 1 1 0 1 1 1 1",
"output": "5"
},
{
"input": "1 100\n1 1 1 1 1 1 1 ... | 1,549,745,413 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 109 | 102,400 | n, m = [int(i) for i in input().split()]
ans = 0
for i in range(n):
floor = input().split()
for j in range(0, 2 * m, 2):
ans += int(floor[j] == "1" or floor[j + 1] == "1")
print(ans) | Title: Vitaly and Night
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vitaly was going home late at night and wondering: how many people aren't sleeping at that moment? To estimate, Vitaly decided to look which windows are lit in the house he was passing by at that moment.
Vital... | ```python
n, m = [int(i) for i in input().split()]
ans = 0
for i in range(n):
floor = input().split()
for j in range(0, 2 * m, 2):
ans += int(floor[j] == "1" or floor[j + 1] == "1")
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
488 | A | Giga Tower | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Every day, thousands of tourists come to this place to enjoy the wonderful view.
In Cyberland, it ... | The only line of input contains an integer *a* (<=-<=109<=≤<=*a*<=≤<=109). | Print the minimum *b* in a line. | [
"179\n",
"-1\n",
"18\n"
] | [
"1\n",
"9\n",
"10\n"
] | For the first sample, he has to arrive at the floor numbered 180.
For the second sample, he will arrive at 8.
Note that *b* should be positive, so the answer for the third sample is 10, not 0. | 500 | [
{
"input": "179",
"output": "1"
},
{
"input": "-1",
"output": "9"
},
{
"input": "18",
"output": "10"
},
{
"input": "-410058385",
"output": "1"
},
{
"input": "-586825624",
"output": "1"
},
{
"input": "852318890",
"output": "1"
},
{
"input": ... | 1,684,321,083 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | a = int(input())
a += 1
k = 1
while "8" not in str(a):
k += 1
a += 1
print(k)
| Title: Giga Tower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Giga Tower is the tallest and deepest building in Cyberland. There are 17<=777<=777<=777 floors, numbered from <=-<=8<=888<=888<=888 to 8<=888<=888<=888. In particular, there is floor 0 between floor <=-<=1 and floor 1. Ever... | ```python
a = int(input())
a += 1
k = 1
while "8" not in str(a):
k += 1
a += 1
print(k)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
832 | A | Sasha and Sticks | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players t... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn. | If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower). | [
"1 1\n",
"10 4\n"
] | [
"YES\n",
"NO\n"
] | In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sas... | 500 | [
{
"input": "1 1",
"output": "YES"
},
{
"input": "10 4",
"output": "NO"
},
{
"input": "251656215122324104 164397544865601257",
"output": "YES"
},
{
"input": "963577813436662285 206326039287271924",
"output": "NO"
},
{
"input": "1000000000000000000 1",
"output":... | 1,590,326,877 | 2,147,483,647 | Python 3 | OK | TESTS | 62 | 109 | 0 | l = list(map(int, input().split()))
def sticks(n,k):
if n==k:
return "YES"
else:
if (n//k)%2==0:
return "NO"
elif (n//k)%2==1:
return "YES"
print(sticks(l[0],l[1])) | Title: Sasha and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with ... | ```python
l = list(map(int, input().split()))
def sticks(n,k):
if n==k:
return "YES"
else:
if (n//k)%2==0:
return "NO"
elif (n//k)%2==1:
return "YES"
print(sticks(l[0],l[1]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consi... | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* bel... | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,689,175,371 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | a,b=map(int,input().split())'
q=dict(input().split() for _ in range(a))
print(' '.join(min((w,q[w]),key=len)for w in input().split())) | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first ... | ```python
a,b=map(int,input().split())'
q=dict(input().split() for _ in range(a))
print(' '.join(min((w,q[w]),key=len)for w in input().split()))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
266 | A | Stones on the Table | PROGRAMMING | 800 | [
"implementation"
] | null | null | There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red... | Print a single integer — the answer to the problem. | [
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] | [
"1\n",
"4\n",
"0\n"
] | none | 500 | [
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "... | 1,696,068,759 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 154 | 0 | n = int(input()) #no need
total = 0
stones = []
for i in input():
if not stones or i != stones[-1]:
stones.append(i)
continue
total += 1
print(total)
| Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row ... | ```python
n = int(input()) #no need
total = 0
stones = []
for i in input():
if not stones or i != stones[-1]:
stones.append(i)
continue
total += 1
print(total)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
387 | A | George and Sleep | PROGRAMMING | 900 | [
"implementation"
] | null | null | George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when George went to bed. Note that George could have gone to bed yesterday relatively to the current time (see ... | The first line contains current time *s* as a string in the format "hh:mm". The second line contains time *t* in the format "hh:mm" — the duration of George's sleep. It is guaranteed that the input contains the correct time in the 24-hour format, that is, 00<=≤<=*hh*<=≤<=23, 00<=≤<=*mm*<=≤<=59. | In the single line print time *p* — the time George went to bed in the format similar to the format of the time in the input. | [
"05:50\n05:44\n",
"00:00\n01:00\n",
"00:01\n00:00\n"
] | [
"00:06\n",
"23:00\n",
"00:01\n"
] | In the first sample George went to bed at "00:06". Note that you should print the time only in the format "00:06". That's why answers "0:06", "00:6" and others will be considered incorrect.
In the second sample, George went to bed yesterday.
In the third sample, George didn't do to bed at all. | 500 | [
{
"input": "05:50\n05:44",
"output": "00:06"
},
{
"input": "00:00\n01:00",
"output": "23:00"
},
{
"input": "00:01\n00:00",
"output": "00:01"
},
{
"input": "23:59\n23:59",
"output": "00:00"
},
{
"input": "23:44\n23:55",
"output": "23:49"
},
{
"input": "... | 1,658,238,567 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 46 | 0 | a,b,c,d=map(int,(input()+":"+input()).split(":"))
x=(1440+(a-c)*60+b-d)%1440
g=lambda x:"0"*(2-len(x))+x
print(g(str(x//60))+":"+g(str(x%60))) | Title: George and Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
George woke up and saw the current time *s* on the digital clock. Besides, George knows that he has slept for time *t*.
Help George! Write a program that will, given time *s* and *t*, determine the time *p* when Geor... | ```python
a,b,c,d=map(int,(input()+":"+input()).split(":"))
x=(1440+(a-c)*60+b-d)%1440
g=lambda x:"0"*(2-len(x))+x
print(g(str(x//60))+":"+g(str(x%60)))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<... | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has e... | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels ... | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,685,312,609 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | k = 237
r = 7
shovel_count = 1
while (k * shovel_count) % 10 != r:
shovel_count += 1
print(shovel_count)
| Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his ... | ```python
k = 237
r = 7
shovel_count = 1
while (k * shovel_count) % 10 != r:
shovel_count += 1
print(shovel_count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the mini... | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th ... | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,696,639,028 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 46 | 0 | n_bacterias = int(input())
b_bacteria = bin(n_bacterias)
n_ones = 0
for n in b_bacteria:
if n == "1":
n_ones+=1
print(n_ones) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split... | ```python
n_bacterias = int(input())
b_bacteria = bin(n_bacterias)
n_ones = 0
for n in b_bacteria:
if n == "1":
n_ones+=1
print(n_ones)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | Sasha is taking part in a programming competition. In one of the problems she should check if some rooted trees are isomorphic or not. She has never seen this problem before, but, being an experienced participant, she guessed that she should match trees to some sequences and then compare these sequences instead of tree... | The first line contains a single integer *h* (2<=≤<=*h*<=≤<=105) — the height of the tree.
The second line contains *h*<=+<=1 integers — the sequence *a*0,<=*a*1,<=...,<=*a**h* (1<=≤<=*a**i*<=≤<=2·105). The sum of all *a**i* does not exceed 2·105. It is guaranteed that there is at least one tree matching this sequence... | If there is only one tree matching this sequence, print "perfect".
Otherwise print "ambiguous" in the first line. In the second and in the third line print descriptions of two trees in the following format: in one line print integers, the *k*-th of them should be the parent of vertex *k* or be equal to zero, if the *... | [
"2\n1 1 1\n",
"2\n1 2 2\n"
] | [
"perfect\n",
"ambiguous\n0 1 1 3 3\n0 1 1 3 2\n"
] | The only tree in the first example and the two printed trees from the second example are shown on the picture:
<img class="tex-graphics" src="https://espresso.codeforces.com/ae5d1889e09854f9d8ad6e29ab7afbe690ca4702.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 0 | [
{
"input": "2\n1 1 1",
"output": "perfect"
},
{
"input": "2\n1 2 2",
"output": "ambiguous\n0 1 1 3 3\n0 1 1 3 2"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1 1",
"output": "perfect"
},
{
"input": "10\n1 1 1 1 1 2 1 1 1 1 1",
"output": "perfect"
},
{
"input": "10\n1 1 1 ... | 1,513,704,085 | 6,385 | Python 3 | WRONG_ANSWER | PRETESTS | 1 | 46 | 5,529,600 | h = int(input())
a = list(map(int, input().split()))
if a[:-1].count(1) == h:
print('perfect')
else:
print('ambiguous')
ans1, ans2 = [0], [0]
last_el = 1
last_i = 0
f = False
for i, el in enumerate(a[1:]):
for k in range(el):
ans1.append(last_el)
if... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sasha is taking part in a programming competition. In one of the problems she should check if some rooted trees are isomorphic or not. She has never seen this problem before, but, being an experienced participant, she guessed that... | ```python
h = int(input())
a = list(map(int, input().split()))
if a[:-1].count(1) == h:
print('perfect')
else:
print('ambiguous')
ans1, ans2 = [0], [0]
last_el = 1
last_i = 0
f = False
for i, el in enumerate(a[1:]):
for k in range(el):
ans1.append(last_el)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
846 | A | Curriculum Vitae | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zer... | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100).
The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one. | Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one. | [
"4\n1 1 0 1\n",
"6\n0 1 0 0 1 0\n",
"1\n0\n"
] | [
"3\n",
"4\n",
"1\n"
] | none | 0 | [
{
"input": "4\n1 1 0 1",
"output": "3"
},
{
"input": "6\n0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "100\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,667,722,901 | 2,147,483,647 | Python 3 | OK | TESTS | 18 | 46 | 0 | input()
s = input()
print(max([s[:i].count('0') + s[i:].count('1') for i in range(len(s) + 1)])) | Title: Curriculum Vitae
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* g... | ```python
input()
s = input()
print(max([s[:i].count('0') + s[i:].count('1') for i in range(len(s) + 1)]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
791 | A | Bear and Big Brother | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or equal to his brother's weight.
Limak eats a lot and his weight is tripled after every year, while Bob's we... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10) — the weight of Limak and the weight of Bob respectively. | Print one integer, denoting the integer number of years after which Limak will become strictly larger than Bob. | [
"4 7\n",
"4 9\n",
"1 1\n"
] | [
"2\n",
"3\n",
"1\n"
] | In the first sample, Limak weighs 4 and Bob weighs 7 initially. After one year their weights are 4·3 = 12 and 7·2 = 14 respectively (one weight is tripled while the other one is doubled). Limak isn't larger than Bob yet. After the second year weights are 36 and 28, so the first weight is greater than the second one. Li... | 500 | [
{
"input": "4 7",
"output": "2"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "4 6",
"output": "2"
},
{
"input": "1 10",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output... | 1,694,576,823 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | l,j=map(int,input().split())
years=0
while l<=j:
l=*3
j=*2
years+=1
print(years) | Title: Bear and Big Brother
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak wants to become the largest of bears, or at least to become larger than his brother Bob.
Right now, Limak and Bob weigh *a* and *b* respectively. It's guaranteed that Limak's weight is smaller than or e... | ```python
l,j=map(int,input().split())
years=0
while l<=j:
l=*3
j=*2
years+=1
print(years)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,496,585,417 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 0 | a=int(input())
b=input()
list1 = b.split(" ")
list2 = []
list3 = []
for i in range(a):
if(int(list1[i])%2==0):
list2.append(list1[i])
else:
list3.append(list1[i])
if(len(list2) > len(list3)):
print(list1.index(list3[0]) + 1)
else:
print(list1.index(list2[0]) + 1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
a=int(input())
b=input()
list1 = b.split(" ")
list2 = []
list3 = []
for i in range(a):
if(int(list1[i])%2==0):
list2.append(list1[i])
else:
list3.append(list1[i])
if(len(list2) > len(list3)):
print(list1.index(list3[0]) + 1)
else:
print(list1.index(list2[0]) + 1)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
903 | C | Boxes Packing | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not put into another box; - *j*-th box doesn't contain any other boxes; - box *i* is smaller than box *... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=5000) — the number of boxes Mishka has got.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the side length of *i*-th box. | Print the minimum possible number of visible boxes. | [
"3\n1 2 3\n",
"4\n4 2 4 3\n"
] | [
"1\n",
"2\n"
] | In the first example it is possible to put box 1 into box 2, and 2 into 3.
In the second example Mishka can put box 2 into box 3, and box 4 into box 1. | 0 | [
{
"input": "3\n1 2 3",
"output": "1"
},
{
"input": "4\n4 2 4 3",
"output": "2"
},
{
"input": "10\n58 58 58 58 58 58 58 58 58 58",
"output": "10"
},
{
"input": "10\n86 89 89 86 86 89 86 86 89 89",
"output": "5"
},
{
"input": "100\n981 288 186 186 292 876 341 288 98... | 1,605,018,610 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | n = int(input())
arr = sorted(list(map(int, input().split())))
ans = n
for x in range(n - 1):
if arr[x] < arr[x + 1]:
ans -= 1
print(ans)
| Title: Boxes Packing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not pu... | ```python
n = int(input())
arr = sorted(list(map(int, input().split())))
ans = n
for x in range(n - 1):
if arr[x] < arr[x + 1]:
ans -= 1
print(ans)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,694,110,133 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n,h=input().split()
n=int(n)
h=int(h)
x=0
for i in range (n):
a=[int(i)for i in input()]
if (a<=h):
x=x+1
else :
x=x+2
print(x)
| Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
n,h=input().split()
n=int(n)
h=int(h)
x=0
for i in range (n):
a=[int(i)for i in input()]
if (a<=h):
x=x+1
else :
x=x+2
print(x)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
664 | A | Complicated GCD | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest in... | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100). | Output one integer — greatest common divisor of all integers from *a* to *b* inclusive. | [
"1 2\n",
"61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n"
] | [
"1\n",
"61803398874989484820458683436563811772030917980576\n"
] | none | 500 | [
{
"input": "1 2",
"output": "1"
},
{
"input": "61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576",
"output": "61803398874989484820458683436563811772030917980576"
},
{
"input": "1 100",
"output": "1"
},
{
"input": "100 100000... | 1,644,155,991 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 409,600 | import fractions
print(fractions.gcd(int(input()),int(input())))
| Title: Complicated GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find gre... | ```python
import fractions
print(fractions.gcd(int(input()),int(input())))
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
714 | B | Filya and Homework | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. First, he pick an integer *x* and then he adds *x* to some elements of the array (no more than onc... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of integers in the Filya's array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — elements of the array. | If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes). | [
"5\n1 3 3 2 1\n",
"5\n1 2 3 4 5\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Filya should select *x* = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements. | 1,000 | [
{
"input": "5\n1 3 3 2 1",
"output": "YES"
},
{
"input": "5\n1 2 3 4 5",
"output": "NO"
},
{
"input": "2\n1 2",
"output": "YES"
},
{
"input": "3\n1 2 3",
"output": "YES"
},
{
"input": "3\n1 1 1",
"output": "YES"
},
{
"input": "2\n1 1000000000",
"ou... | 1,600,465,490 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 2 | 92 | 0 | n = int(input())
l = list(set(sorted(list(map(int, input().split())))))
if len(l)>3:
exit(print('NO'))
else:
if l[-1]-l[-2] == l[-3]:
exit(print('YES'))
print('NO') | Title: Filya and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a... | ```python
n = int(input())
l = list(set(sorted(list(map(int, input().split())))))
if len(l)>3:
exit(print('NO'))
else:
if l[-1]-l[-2] == l[-3]:
exit(print('YES'))
print('NO')
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
793 | B | Igor and his way to work | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"implementation",
"shortest paths"
] | null | null | Woken up by the alarm clock Igor the financial analyst hurried up to the work. He ate his breakfast and sat in his car. Sadly, when he opened his GPS navigator, he found that some of the roads in Bankopolis, the city where he lives, are closed due to road works. Moreover, Igor has some problems with the steering wheel,... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and the number of columns in the grid.
Each of the next *n* lines contains *m* characters denoting the corresponding row of the grid. The following characters can occur:
- "." — an empty cell; - "*" — a cell with road ... | In the only line print "YES" if there is a path between Igor's home and Igor's office with no more than two turns, and "NO" otherwise. | [
"5 5\n..S..\n****.\nT....\n****.\n.....\n",
"5 5\nS....\n****.\n.....\n.****\n..T..\n"
] | [
"YES",
"NO"
] | The first sample is shown on the following picture:
In the second sample it is impossible to reach Igor's office using less that 4 turns, thus there exists no path using no more than 2 turns. The path using exactly 4 turns is shown on this picture: | 1,000 | [
{
"input": "5 5\nS....\n****.\n.....\n.****\n..T..",
"output": "NO"
},
{
"input": "1 2\nST",
"output": "YES"
},
{
"input": "3 1\nS\n*\nT",
"output": "NO"
},
{
"input": "3 3\n*..\n...\nTS.",
"output": "YES"
},
{
"input": "3 3\nT.*\n*.*\n*S*",
"output": "YES"
... | 1,668,331,684 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 3,000 | 268,390,400 | import sys, threading
input = sys.stdin.readline
directions = [(0, 1), (1, 0), (-1, 0), (0, -1)]
def dfs(row, col, i, grid, k, seen):
# print(row, col, directions[i], k, grid[row][col])
seen.add((row, col, k))
if k > 2 or grid[row][col] == '*':
return False
if grid[row][col] == 'T':
... | Title: Igor and his way to work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Woken up by the alarm clock Igor the financial analyst hurried up to the work. He ate his breakfast and sat in his car. Sadly, when he opened his GPS navigator, he found that some of the roads in Bankopolis, th... | ```python
import sys, threading
input = sys.stdin.readline
directions = [(0, 1), (1, 0), (-1, 0), (0, -1)]
def dfs(row, col, i, grid, k, seen):
# print(row, col, directions[i], k, grid[row][col])
seen.add((row, col, k))
if k > 2 or grid[row][col] == '*':
return False
if grid[row][col] ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
780 | A | Andryusha and Socks | PROGRAMMING | 800 | [
"implementation"
] | null | null | Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbered from 1 to *n*. Andryusha wants to put paired socks together and put them in the wardrobe. He takes the ... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=105) — the number of sock pairs.
The second line contains 2*n* integers *x*1,<=*x*2,<=...,<=*x*2*n* (1<=≤<=*x**i*<=≤<=*n*), which describe the order in which Andryusha took the socks from the bag. More precisely, *x**i* means that the *i*-th sock Andryusha ... | Print single integer — the maximum number of socks that were on the table at the same time. | [
"1\n1 1\n",
"3\n2 1 1 3 2 3\n"
] | [
"1\n",
"2\n"
] | In the first example Andryusha took a sock from the first pair and put it on the table. Then he took the next sock which is from the first pair as well, so he immediately puts both socks to the wardrobe. Thus, at most one sock was on the table at the same time.
In the second example Andryusha behaved as follows:
- ... | 500 | [
{
"input": "1\n1 1",
"output": "1"
},
{
"input": "3\n2 1 1 3 2 3",
"output": "2"
},
{
"input": "5\n5 1 3 2 4 3 1 2 4 5",
"output": "5"
},
{
"input": "10\n4 2 6 3 4 8 7 1 1 5 2 10 6 8 3 5 10 9 9 7",
"output": "6"
},
{
"input": "50\n30 47 31 38 37 50 36 43 9 23 2 2 ... | 1,488,705,559 | 259 | PyPy 3 | OK | TESTS | 56 | 265 | 38,297,600 | a = set()
n = int(input())
k = list(map(int, input().split()))
res = 0
for i in range (len(k)):
if (k[i] in a):
a.remove(k[i])
else:
a.add(k[i])
res = max(res, len(a))
print(res) | Title: Andryusha and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andryusha is an orderly boy and likes to keep things in their place.
Today he faced a problem to put his socks in the wardrobe. He has *n* distinct pairs of socks which are initially in a bag. The pairs are numbere... | ```python
a = set()
n = int(input())
k = list(map(int, input().split()))
res = 0
for i in range (len(k)):
if (k[i] in a):
a.remove(k[i])
else:
a.add(k[i])
res = max(res, len(a))
print(res)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
586 | A | Alena's Schedule | PROGRAMMING | 900 | [
"implementation"
] | null | null | Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic hours (an academic hour is equal to 45 minutes).
The University works in such a way that every day it... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of lessons at the university.
The second line contains *n* numbers *a**i* (0<=≤<=*a**i*<=≤<=1). Number *a**i* equals 0, if Alena doesn't have the *i*-th pairs, otherwise it is equal to 1. Numbers *a*1,<=*a*2,<=...,<=*a**n* ar... | Print a single number — the number of pairs during which Alena stays at the university. | [
"5\n0 1 0 1 1\n",
"7\n1 0 1 0 0 1 0\n",
"1\n0\n"
] | [
"4\n",
"4\n",
"0\n"
] | In the first sample Alena stays at the university from the second to the fifth pair, inclusive, during the third pair she will be it the university waiting for the next pair.
In the last sample Alena doesn't have a single pair, so she spends all the time at home. | 500 | [
{
"input": "5\n0 1 0 1 1",
"output": "4"
},
{
"input": "7\n1 0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "1"
},
{
... | 1,618,641,278 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 61 | 0 | def solve(arr,n):
end = n-1
start = 0
for i in range(n-1,-1,-1):
if arr[i]:
break
end -= 1
for i in range(end):
if arr[i]:
break
start += 1
arr = arr[start:end+1]
if not len(arr):
return 0
if len(arr) == 1 :
return ... | Title: Alena's Schedule
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alena has successfully passed the entrance exams to the university and is now looking forward to start studying.
One two-hour lesson at the Russian university is traditionally called a pair, it lasts for two academic ... | ```python
def solve(arr,n):
end = n-1
start = 0
for i in range(n-1,-1,-1):
if arr[i]:
break
end -= 1
for i in range(end):
if arr[i]:
break
start += 1
arr = arr[start:end+1]
if not len(arr):
return 0
if len(arr) == 1 :
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
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