contestId int64 0 1.01k | index stringclasses 55
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 7 | title stringclasses 495
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 5 65.5k | instruction_seed stringlengths 262 8.2k | response stringlengths 19 65.5k | score float64 -1 3.99 | _source stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,642,789,499 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 | i=input()
m=input()
c=i[::-1]
if c == m:
print("YES")
else:
print("NO")
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
i=input()
m=input()
c=i[::-1]
if c == m:
print("YES")
else:
print("NO")
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
34 | B | Sale | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | B. Sale | 2 | 256 | Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can «buy» any TV sets he wants. Though he's very strong, Bob can carry at most *m* TV set... | The first line contains two space-separated integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — amount of TV sets at the sale, and amount of TV sets that Bob can carry. The following line contains *n* space-separated integers *a**i* (<=-<=1000<=≤<=*a**i*<=≤<=1000) — prices of the TV sets. | Output the only number — the maximum sum of money that Bob can earn, given that he can carry at most *m* TV sets. | [
"5 3\n-6 0 35 -2 4\n",
"4 2\n7 0 0 -7\n"
] | [
"8\n",
"7\n"
] | none | 1,000 | [
{
"input": "5 3\n-6 0 35 -2 4",
"output": "8"
},
{
"input": "4 2\n7 0 0 -7",
"output": "7"
},
{
"input": "6 6\n756 -611 251 -66 572 -818",
"output": "1495"
},
{
"input": "5 5\n976 437 937 788 518",
"output": "0"
},
{
"input": "5 3\n-2 -2 -2 -2 -2",
"output": "... | 1,587,318,850 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 |
n,m = [int(i) for i in input().split(' ')]
a = sorted([int(i) for i in input().split(' ')])
print(sum(a[:m])*(-1))
| Title: Sale
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob got to a sale of old TV sets. There were *n* TV sets at that sale. TV set with index *i* costs *a**i* bellars. Some TV sets have a negative price — their owners are ready to pay Bob if he buys their useless apparatus. Bob can... | ```python
n,m = [int(i) for i in input().split(' ')]
a = sorted([int(i) for i in input().split(' ')])
print(sum(a[:m])*(-1))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
48 | D | Permutations | PROGRAMMING | 1,500 | [
"greedy"
] | D. Permutations | 1 | 256 | A permutation is a sequence of integers from 1 to *n* of length *n* containing each number exactly once. For example, (1), (4,<=3,<=5,<=1,<=2), (3,<=2,<=1) are permutations, and (1,<=1), (4,<=3,<=1), (2,<=3,<=4) are not.
There are many tasks on permutations. Today you are going to solve one of them. Let’s imagine tha... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). The next line contains the mixed array of *n* integers, divided with a single space. The numbers in the array are from 1 to 105. | If this array can be split into several permutations so that every element of the array belongs to exactly one permutation, print in the first line the number of permutations. The second line should contain *n* numbers, corresponding to the elements of the given array. If the *i*-th element belongs to the first permuta... | [
"9\n1 2 3 1 2 1 4 2 5\n",
"4\n4 3 2 1\n",
"4\n1 2 2 3\n"
] | [
"3\n3 1 2 1 2 2 2 3 2\n",
"1\n1 1 1 1 ",
"-1\n"
] | In the first sample test the array is split into three permutations: (2, 1), (3, 2, 1, 4, 5), (1, 2). The first permutation is formed by the second and the fourth elements of the array, the second one — by the third, the fifth, the sixth, the seventh and the ninth elements, the third one — by the first and the eigth el... | 0 | [
{
"input": "9\n1 2 3 1 2 1 4 2 5",
"output": "3\n1 1 1 2 2 3 1 3 1 "
},
{
"input": "4\n4 3 2 1",
"output": "1\n1 1 1 1 "
},
{
"input": "4\n1 2 2 3",
"output": "-1"
},
{
"input": "1\n1",
"output": "1\n1 "
},
{
"input": "1\n2",
"output": "-1"
},
{
"input... | 1,565,495,040 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 139 | 409,600 | n = int(input())
a = list(map(int,input().split()))
count = [0]*100005
mx = 0
for i in range(n):
count[a[i]] += 1
mx = max(mx,count[a[i]])
a[i] = count[a[i]]
print(mx)
print(*a)
| Title: Permutations
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
A permutation is a sequence of integers from 1 to *n* of length *n* containing each number exactly once. For example, (1), (4,<=3,<=5,<=1,<=2), (3,<=2,<=1) are permutations, and (1,<=1), (4,<=3,<=1), (2,<=3,<=4) are not.
The... | ```python
n = int(input())
a = list(map(int,input().split()))
count = [0]*100005
mx = 0
for i in range(n):
count[a[i]] += 1
mx = max(mx,count[a[i]])
a[i] = count[a[i]]
print(mx)
print(*a)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
628 | B | New Skateboard | PROGRAMMING | 1,300 | [
"dp"
] | null | null | Max wants to buy a new skateboard. He has calculated the amount of money that is needed to buy a new skateboard. He left a calculator on the floor and went to ask some money from his parents. Meanwhile his little brother Yusuf came and started to press the keys randomly. Unfortunately Max has forgotten the number which... | The only line contains string *s* (1<=≤<=|*s*|<=≤<=3·105). The string *s* contains only digits from 0 to 9. | Print integer *a* — the number of substrings of the string *s* that are divisible by 4.
Note that the answer can be huge, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | [
"124\n",
"04\n",
"5810438174\n"
] | [
"4\n",
"3\n",
"9\n"
] | none | 0 | [
{
"input": "124",
"output": "4"
},
{
"input": "04",
"output": "3"
},
{
"input": "5810438174",
"output": "9"
},
{
"input": "1",
"output": "0"
},
{
"input": "039",
"output": "1"
},
{
"input": "97247",
"output": "6"
},
{
"input": "5810438174",... | 1,560,383,779 | 2,147,483,647 | Python 3 | OK | TESTS | 22 | 389 | 3,891,200 | s = list(map(int,input()))
x = len(s)
q = 0 if s[-1]%4 else 1
for i in range(x-1):
if not s[i]%4:
q+=1
if (10*s[i]+s[i+1])%4==0:
q+=i+1
print(q) | Title: New Skateboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Max wants to buy a new skateboard. He has calculated the amount of money that is needed to buy a new skateboard. He left a calculator on the floor and went to ask some money from his parents. Meanwhile his little brother... | ```python
s = list(map(int,input()))
x = len(s)
q = 0 if s[-1]%4 else 1
for i in range(x-1):
if not s[i]%4:
q+=1
if (10*s[i]+s[i+1])%4==0:
q+=i+1
print(q)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
934 | B | A Prosperous Lot | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to approach them, it will be driven away by the fairies inside.
Big Banban is hesitating over the amount ... | The first and only line contains an integer *k* (1<=≤<=*k*<=≤<=106) — the desired number of loops. | Output an integer — if no such *n* exists, output -1; otherwise output any such *n*. In the latter case, your output should be a positive decimal integer not exceeding 1018. | [
"2\n",
"6\n"
] | [
"462",
"8080"
] | none | 1,000 | [
{
"input": "2",
"output": "8"
},
{
"input": "6",
"output": "888"
},
{
"input": "3",
"output": "86"
},
{
"input": "4",
"output": "88"
},
{
"input": "5",
"output": "886"
},
{
"input": "1000000",
"output": "-1"
},
{
"input": "1",
"output":... | 1,623,863,611 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 108 | 0 | k=int(input())
if k==1:
print(6)
else:
x=(k//2)
y=k%2
ans=""
if x+y>18:
print(-1)
else:
for i in range(x):
ans+="8"
for i in range(y):
ans+="0"
if int(ans)>1e18:
print(-1)
else:
print(ans)
| Title: A Prosperous Lot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Apart from Nian, there is a daemon named Sui, which terrifies children and causes them to become sick. Parents give their children money wrapped in red packets and put them under the pillow, so that when Sui tries to a... | ```python
k=int(input())
if k==1:
print(6)
else:
x=(k//2)
y=k%2
ans=""
if x+y>18:
print(-1)
else:
for i in range(x):
ans+="8"
for i in range(y):
ans+="0"
if int(ans)>1e18:
print(-1)
else:
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
630 | I | Parking Lot | PROGRAMMING | 1,700 | [
"combinatorics",
"math"
] | null | null | To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2*n*<=-<=2) parking spaces. Unfortunately the total number of ... | The only line of the input contains one integer *n* (3<=≤<=*n*<=≤<=30) — the amount of successive cars of the same make. | Output one integer — the number of ways to fill the parking lot by cars of four makes using the described way. | [
"3\n"
] | [
"24"
] | Let's denote car makes in the following way: A — Aston Martin, B — Bentley, M — Mercedes-Maybach, Z — Zaporozhets. For *n* = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Orig... | 0 | [
{
"input": "3",
"output": "24"
},
{
"input": "4",
"output": "132"
},
{
"input": "5",
"output": "672"
},
{
"input": "6",
"output": "3264"
},
{
"input": "7",
"output": "15360"
},
{
"input": "12",
"output": "27525120"
},
{
"input": "15",
"... | 1,693,677,279 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 15 | 409,600 | import sys,itertools,functools,collections,math
def BEX(a,b):
res=1
while b>0:
if b&1:
res=res*a
a=a*a
b=b>>1
return res
def solve(n):
x=BEX(2,2*n-3)
y=BEX(2,2*n-6)
ans=3*x+(n-3)*9
print(ans)
n=int(input())
solve(n) | Title: Parking Lot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before t... | ```python
import sys,itertools,functools,collections,math
def BEX(a,b):
res=1
while b>0:
if b&1:
res=res*a
a=a*a
b=b>>1
return res
def solve(n):
x=BEX(2,2*n-3)
y=BEX(2,2*n-6)
ans=3*x+(n-3)*9
print(ans)
n=int(input())
solve(n)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,567,170,590 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 124 | 0 | vstup=list(input())
while vstup.count('h')>1:
vstup.remove("h")
while vstup.count('e')>1:
vstup.remove("e")
while vstup.count('l')>2:
vstup.remove("l")
while vstup.count('o')>1:
vstup.remove("o")
vstup=''.join(vstup)
if 'hello' in vstup:
print('YES')
else:
print("NO")
| Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
vstup=list(input())
while vstup.count('h')>1:
vstup.remove("h")
while vstup.count('e')>1:
vstup.remove("e")
while vstup.count('l')>2:
vstup.remove("l")
while vstup.count('o')>1:
vstup.remove("o")
vstup=''.join(vstup)
if 'hello' in vstup:
print('YES')
else:
print("NO")
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, d... | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,693,905,656 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 41 | 62 | 0 | import math
n = int(input())
N = math.floor(math.log2(n/5 + 1))
O = 5 * (2 ** N - 1)
l = n - O
if l == 0:
print("Howard")
else:
pI = (l - 1) // (2 ** N)
print(["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"][pI]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resultin... | ```python
import math
n = int(input())
N = math.floor(math.log2(n/5 + 1))
O = 5 * (2 ** N - 1)
l = n - O
if l == 0:
print("Howard")
else:
pI = (l - 1) // (2 ** N)
print(["Sheldon", "Leonard", "Penny", "Rajesh", "Howard"][pI])
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
151 | A | Soft Drinking | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut each of them into *d* slices. After that they found *p* grams of salt.
To make a toast, each frie... | The first and only line contains positive integers *n*, *k*, *l*, *c*, *d*, *p*, *nl*, *np*, not exceeding 1000 and no less than 1. The numbers are separated by exactly one space. | Print a single integer — the number of toasts each friend can make. | [
"3 4 5 10 8 100 3 1\n",
"5 100 10 1 19 90 4 3\n",
"10 1000 1000 25 23 1 50 1\n"
] | [
"2\n",
"3\n",
"0\n"
] | A comment to the first sample:
Overall the friends have 4 * 5 = 20 milliliters of the drink, it is enough to make 20 / 3 = 6 toasts. The limes are enough for 10 * 8 = 80 toasts and the salt is enough for 100 / 1 = 100 toasts. However, there are 3 friends in the group, so the answer is *min*(6, 80, 100) / 3 = 2. | 500 | [
{
"input": "3 4 5 10 8 100 3 1",
"output": "2"
},
{
"input": "5 100 10 1 19 90 4 3",
"output": "3"
},
{
"input": "10 1000 1000 25 23 1 50 1",
"output": "0"
},
{
"input": "1 7 4 5 5 8 3 2",
"output": "4"
},
{
"input": "2 3 3 5 5 10 1 3",
"output": "1"
},
{
... | 1,687,607,903 | 2,147,483,647 | PyPy 3 | OK | TESTS | 27 | 184 | 0 | l=list(map(int,input().split()))
a=[]
s=int((l[1]*l[2])/l[-2])
a.append(s)
a.append(l[3]*l[4])
a.append(int(l[5]/l[-1]))
print(int(min(a)/l[0])) | Title: Soft Drinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This winter is so cold in Nvodsk! A group of *n* friends decided to buy *k* bottles of a soft drink called "Take-It-Light" to warm up a bit. Each bottle has *l* milliliters of the drink. Also they bought *c* limes and cut... | ```python
l=list(map(int,input().split()))
a=[]
s=int((l[1]*l[2])/l[-2])
a.append(s)
a.append(l[3]*l[4])
a.append(int(l[5]/l[-1]))
print(int(min(a)/l[0]))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfec... | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space... | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the... | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,592,467,583 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 109 | 307,200 | n,v=map(int,input().split())
mat=[];arr=[]
for i in range(n):
mat.append(list(map(int,input().split())))
for i in range(len(mat)):
for j in range(1,mat[i][0]+1):
if mat[i][j]<v:
arr.append(i+1)
break
print(len(arr))
for i in arr:
print(i,end=" ") | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the... | ```python
n,v=map(int,input().split())
mat=[];arr=[]
for i in range(n):
mat.append(list(map(int,input().split())))
for i in range(len(mat)):
for j in range(1,mat[i][0]+1):
if mat[i][j]<v:
arr.append(i+1)
break
print(len(arr))
for i in arr:
print(i,end=" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,619,588,801 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 124 | 0 | n=int(input())
l=map(int,input().split())
ji,jp=0,0
ou,op=0,0
for (p,i) in enumerate(l):
if i%2==1:
ji+=1
jp=p
else:
ou+=1
op=p
if ji==1:
print(jp+1)
else:
print(op+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n=int(input())
l=map(int,input().split())
ji,jp=0,0
ou,op=0,0
for (p,i) in enumerate(l):
if i%2==1:
ji+=1
jp=p
else:
ou+=1
op=p
if ji==1:
print(jp+1)
else:
print(op+1)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
412 | A | Poster | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | The R1 company has recently bought a high rise building in the centre of Moscow for its main office. It's time to decorate the new office, and the first thing to do is to write the company's slogan above the main entrance to the building.
The slogan of the company consists of *n* characters, so the decorators hung a l... | The first line contains two integers, *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100) — the number of characters in the slogan and the initial position of the ladder, correspondingly. The next line contains the slogan as *n* characters written without spaces. Each character of the slogan is either a large English letter, or di... | In *t* lines, print the actions the programmers need to make. In the *i*-th line print:
- "LEFT" (without the quotes), if the *i*-th action was "move the ladder to the left"; - "RIGHT" (without the quotes), if the *i*-th action was "move the ladder to the right"; - "PRINT *x*" (without the quotes), if the *i*-th ac... | [
"2 2\nR1\n",
"2 1\nR1\n",
"6 4\nGO?GO!\n"
] | [
"PRINT 1\nLEFT\nPRINT R\n",
"PRINT R\nRIGHT\nPRINT 1\n",
"RIGHT\nRIGHT\nPRINT !\nLEFT\nPRINT O\nLEFT\nPRINT G\nLEFT\nPRINT ?\nLEFT\nPRINT O\nLEFT\nPRINT G\n"
] | Note that the ladder cannot be shifted by less than one meter. The ladder can only stand in front of some square of the poster. For example, you cannot shift a ladder by half a meter and position it between two squares. Then go up and paint the first character and the second character. | 500 | [
{
"input": "2 2\nR1",
"output": "PRINT 1\nLEFT\nPRINT R"
},
{
"input": "2 1\nR1",
"output": "PRINT R\nRIGHT\nPRINT 1"
},
{
"input": "6 4\nGO?GO!",
"output": "RIGHT\nRIGHT\nPRINT !\nLEFT\nPRINT O\nLEFT\nPRINT G\nLEFT\nPRINT ?\nLEFT\nPRINT O\nLEFT\nPRINT G"
},
{
"input": "7 3\n... | 1,672,834,501 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n,k = map(int,input().split())
s = input()
l = len(s)+1
if l//2 >= k:
for i in range(k-1,0,-1):
print("LEFT")
for i in s:
print("PRINT ",i)
print("RIGHT")
else:
for i in range(k+1,n+1):
print("RIGHT")
s = s[::-1]
for i in s:
print("PRINT ",i)
... | Title: Poster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The R1 company has recently bought a high rise building in the centre of Moscow for its main office. It's time to decorate the new office, and the first thing to do is to write the company's slogan above the main entrance to the... | ```python
n,k = map(int,input().split())
s = input()
l = len(s)+1
if l//2 >= k:
for i in range(k-1,0,-1):
print("LEFT")
for i in s:
print("PRINT ",i)
print("RIGHT")
else:
for i in range(k+1,n+1):
print("RIGHT")
s = s[::-1]
for i in s:
print("PRIN... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
961 | B | Lecture Sleep | PROGRAMMING | 1,200 | [
"data structures",
"dp",
"implementation",
"two pointers"
] | null | null | Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for all the time of lecture. You are given an array *t* of Mishka's behavior. If Mishka is asleep during ... | The first line of the input contains two integer numbers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=105) — the duration of the lecture in minutes and the number of minutes you can keep Mishka awake.
The second line of the input contains *n* integer numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=104) — the number of theore... | Print only one integer — the maximum number of theorems Mishka will be able to write down if you use your technique only once to wake him up. | [
"6 3\n1 3 5 2 5 4\n1 1 0 1 0 0\n"
] | [
"16\n"
] | In the sample case the better way is to use the secret technique at the beginning of the third minute. Then the number of theorems Mishka will be able to write down will be equal to 16. | 0 | [
{
"input": "6 3\n1 3 5 2 5 4\n1 1 0 1 0 0",
"output": "16"
},
{
"input": "5 3\n1 9999 10000 10000 10000\n0 0 0 0 0",
"output": "30000"
},
{
"input": "3 3\n10 10 10\n1 1 0",
"output": "30"
},
{
"input": "1 1\n423\n0",
"output": "423"
},
{
"input": "6 6\n1 3 5 2 5 4... | 1,586,484,513 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 3 | 1,000 | 6,451,200 | time_lecture, awake_time = [int(num) for num in input().split()]
theorems = [int(num) for num in input().split()]
awakeness = [int(num) for num in input().split()]
written = 0
maximum = 0
val_theorems = [theorems[i] if awakeness[i] == 0 else 0 for i in range(len(theorems))]
for index in range(len(theorems)):
if a... | Title: Lecture Sleep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend Mishka and you attend a calculus lecture. Lecture lasts *n* minutes. Lecturer tells *a**i* theorems during the *i*-th minute.
Mishka is really interested in calculus, though it is so hard to stay awake for al... | ```python
time_lecture, awake_time = [int(num) for num in input().split()]
theorems = [int(num) for num in input().split()]
awakeness = [int(num) for num in input().split()]
written = 0
maximum = 0
val_theorems = [theorems[i] if awakeness[i] == 0 else 0 for i in range(len(theorems))]
for index in range(len(theorems))... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
982 | C | Cut 'em all! | PROGRAMMING | 1,500 | [
"dfs and similar",
"dp",
"graphs",
"greedy",
"trees"
] | null | null | You're given a tree with $n$ vertices.
Your task is to determine the maximum possible number of edges that can be removed in such a way that all the remaining connected components will have even size. | The first line contains an integer $n$ ($1 \le n \le 10^5$) denoting the size of the tree.
The next $n - 1$ lines contain two integers $u$, $v$ ($1 \le u, v \le n$) each, describing the vertices connected by the $i$-th edge.
It's guaranteed that the given edges form a tree. | Output a single integer $k$ — the maximum number of edges that can be removed to leave all connected components with even size, or $-1$ if it is impossible to remove edges in order to satisfy this property. | [
"4\n2 4\n4 1\n3 1\n",
"3\n1 2\n1 3\n",
"10\n7 1\n8 4\n8 10\n4 7\n6 5\n9 3\n3 5\n2 10\n2 5\n",
"2\n1 2\n"
] | [
"1",
"-1",
"4",
"0"
] | In the first example you can remove the edge between vertices $1$ and $4$. The graph after that will have two connected components with two vertices in each.
In the second example you can't remove edges in such a way that all components have even number of vertices, so the answer is $-1$. | 1,500 | [
{
"input": "4\n2 4\n4 1\n3 1",
"output": "1"
},
{
"input": "3\n1 2\n1 3",
"output": "-1"
},
{
"input": "10\n7 1\n8 4\n8 10\n4 7\n6 5\n9 3\n3 5\n2 10\n2 5",
"output": "4"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "1",
"output": "-1"
},
{
"inpu... | 1,584,544,145 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 998 | 13,516,800 | n = int(input())
if n % 2 == 1:
print(-1)
exit()
adj = [[] for _ in range(n+1) ]
for _ in range(n-1):
u, v = map(int, input().split())
adj[u].append(v)
adj[v].append(u)
cnt = [1] * (n+1)
prt = [-1] * (n+1)
prt[1] = 1
stk = [1]
while stk:
u = stk[-1]
k = False
for v in... | Title: Cut 'em all!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You're given a tree with $n$ vertices.
Your task is to determine the maximum possible number of edges that can be removed in such a way that all the remaining connected components will have even size.
Input Specification... | ```python
n = int(input())
if n % 2 == 1:
print(-1)
exit()
adj = [[] for _ in range(n+1) ]
for _ in range(n-1):
u, v = map(int, input().split())
adj[u].append(v)
adj[v].append(u)
cnt = [1] * (n+1)
prt = [-1] * (n+1)
prt[1] = 1
stk = [1]
while stk:
u = stk[-1]
k = False
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
491 | A | Up the hill | PROGRAMMING | 1,000 | [
"constructive algorithms",
"implementation"
] | null | null | Hiking club "Up the hill" just returned from a walk. Now they are trying to remember which hills they've just walked through.
It is known that there were *N* stops, all on different integer heights between 1 and *N* kilometers (inclusive) above the sea level. On the first day they've traveled from the first stop to th... | In the first line there is an integer non-negative number *A* denoting the number of days of climbing up the hill. Second line contains an integer non-negative number *B* — the number of days of walking down the hill (*A*<=+<=*B*<=+<=1<==<=*N*, 1<=≤<=*N*<=≤<=100<=000). | Output *N* space-separated distinct integers from 1 to *N* inclusive, denoting possible heights of the stops in order of visiting. | [
"0\n1\n",
"2\n1"
] | [
"2 1 \n",
"1 3 4 2"
] | none | 500 | [
{
"input": "0\n1",
"output": "2 1 "
},
{
"input": "2\n1",
"output": "2 3 4 1 "
},
{
"input": "0\n3",
"output": "4 3 2 1 "
},
{
"input": "1\n1",
"output": "2 3 1 "
},
{
"input": "3\n7",
"output": "8 9 10 11 7 6 5 4 3 2 1 "
},
{
"input": "700\n300",
... | 1,690,306,004 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 24 | 124 | 9,318,400 |
a = int(input())
b = int(input())
for i in range(b+1,a+b+2):
print(i,end=" ")
for i in range(b,0,-1):
print(i)
| Title: Up the hill
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hiking club "Up the hill" just returned from a walk. Now they are trying to remember which hills they've just walked through.
It is known that there were *N* stops, all on different integer heights between 1 and *N* kilome... | ```python
a = int(input())
b = int(input())
for i in range(b+1,a+b+2):
print(i,end=" ")
for i in range(b,0,-1):
print(i)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'... | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one spac... | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,633,770,708 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 124 | 6,963,200 | # -*- coding: utf-8 -*-
"""
Created on Fri Oct 8 23:45:58 2021
@author: Sourav Joshi
"""
x = {}
y = {}
points = []
n = int(input())
for i in range(n):
p = [int(i) for i in input().split(" ")]
points.append(p)
xp = p[0]
yp = p[1]
if(xp in x):
x[xp] = x[xp] + [yp]
... | Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the give... | ```python
# -*- coding: utf-8 -*-
"""
Created on Fri Oct 8 23:45:58 2021
@author: Sourav Joshi
"""
x = {}
y = {}
points = []
n = int(input())
for i in range(n):
p = [int(i) for i in input().split(" ")]
points.append(p)
xp = p[0]
yp = p[1]
if(xp in x):
x[xp] = x[xp] + ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take... | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b... | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,686,346,146 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 92 | 0 | import math
a,b,c=[int(x) for x in input().split()]
dem=0
while c!=0:
c-=math.gcd(c,a)
dem+=1
if(c!=0):
c-=math.gcd(c,b)
dem+=1
if dem%2!=0:
print("0")
else:
print("1")
| Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* sto... | ```python
import math
a,b,c=[int(x) for x in input().split()]
dem=0
while c!=0:
c-=math.gcd(c,a)
dem+=1
if(c!=0):
c-=math.gcd(c,b)
dem+=1
if dem%2!=0:
print("0")
else:
print("1")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
0 | none | none | none | 0 | [
"none"
] | null | null | You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x*<=/<=*y*.
Your favorite rational number in the [0;1] range is *p*<=/<=*q*. Now you wonde... | The first line contains a single integer *t* (1<=≤<=*t*<=≤<=1000) — the number of test cases.
Each of the next *t* lines contains four integers *x*, *y*, *p* and *q* (0<=≤<=*x*<=≤<=*y*<=≤<=109; 0<=≤<=*p*<=≤<=*q*<=≤<=109; *y*<=><=0; *q*<=><=0).
It is guaranteed that *p*<=/<=*q* is an irreducible fraction.
Hacks... | For each test case, output a single integer equal to the smallest number of submissions you have to make if you want your success rate to be equal to your favorite rational number, or -1 if this is impossible to achieve. | [
"4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1\n"
] | [
"4\n10\n0\n-1\n"
] | In the first example, you have to make 4 successful submissions. Your success rate will be equal to 7 / 14, or 1 / 2.
In the second example, you have to make 2 successful and 8 unsuccessful submissions. Your success rate will be equal to 9 / 24, or 3 / 8.
In the third example, there is no need to make any new submiss... | 0 | [
{
"input": "4\n3 10 1 2\n7 14 3 8\n20 70 2 7\n5 6 1 1",
"output": "4\n10\n0\n-1"
},
{
"input": "8\n0 1 0 1\n0 2 1 2\n0 3 1 1\n1 2 0 1\n1 2 1 1\n2 2 0 1\n3 3 1 2\n4 4 1 1",
"output": "0\n2\n-1\n-1\n-1\n-1\n3\n0"
},
{
"input": "5\n1 1000000000 1 2\n1 1000000000 1 2\n1 1000000000 1 2\n1 100... | 1,578,995,825 | 2,147,483,647 | PyPy 3 | OK | TESTS | 56 | 280 | 6,656,000 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
'''
设提交了B次，成功A次
(A+x)/(B+y)=p/q
A+x=p*K
B+y=q*k
二分枚举k
'''
T=int(input())
for case in range(T):
x,y,p,q=map(int,input().strip().split())
l=int(0)
r=int(1e10)
ans=1<<30
while l<=r:
mid=int((l+r)/2)
A=mid*p-x
B=mid... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are an experienced Codeforces user. Today you found out that during your activity on Codeforces you have made *y* submissions, out of which *x* have been successful. Thus, your current success rate on Codeforces is equal to *x... | ```python
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
'''
设提交了B次，成功A次
(A+x)/(B+y)=p/q
A+x=p*K
B+y=q*k
二分枚举k
'''
T=int(input())
for case in range(T):
x,y,p,q=map(int,input().strip().split())
l=int(0)
r=int(1e10)
ans=1<<30
while l<=r:
mid=int((l+r)/2)
A=mid*p-x
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
78 | A | Haiku | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Haiku | 2 | 256 | Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syll... | The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The *i*-th line contains the *i*-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailin... | Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes). | [
"on codeforces \nbeta round is running\n a rustling of keys \n",
"how many gallons\nof edo s rain did you drink\n cuckoo\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "on codeforces \nbeta round is running\n a rustling of keys ",
"output": "YES"
},
{
"input": "how many gallons\nof edo s rain did you drink\n cuckoo",
"output": "NO"
},
{
"input": " hatsu shigure\n saru mo komino wo\nhoshige nari",
... | 1,647,191,426 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | print('ROYGRBIV') | Title: Haiku
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase... | ```python
print('ROYGRBIV')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions |
876 | B | Divisiblity of Differences | PROGRAMMING | 1,300 | [
"implementation",
"math",
"number theory"
] | null | null | You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be repeated in the original multiset and in the multiset of selected numbers, but number of occurrences of any number... | First line contains three integers *n*, *k* and *m* (2<=≤<=*k*<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=100<=000) — number of integers in the multiset, number of integers you should select and the required divisor of any pair of selected integers.
Second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=... | If it is not possible to select *k* numbers in the desired way, output «No» (without the quotes).
Otherwise, in the first line of output print «Yes» (without the quotes). In the second line print *k* integers *b*1,<=*b*2,<=...,<=*b**k* — the selected numbers. If there are multiple possible solutions, print any of them... | [
"3 2 3\n1 8 4\n",
"3 3 3\n1 8 4\n",
"4 3 5\n2 7 7 7\n"
] | [
"Yes\n1 4 ",
"No",
"Yes\n2 7 7 "
] | none | 1,000 | [
{
"input": "3 2 3\n1 8 4",
"output": "Yes\n1 4 "
},
{
"input": "3 3 3\n1 8 4",
"output": "No"
},
{
"input": "4 3 5\n2 7 7 7",
"output": "Yes\n2 7 7 "
},
{
"input": "9 9 5\n389149775 833127990 969340400 364457730 48649145 316121525 640054660 924273385 973207825",
"output":... | 1,508,893,690 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | inp=input()
n,k,m=inp.split()
lol=input()
d=lol.split()
ans_no=''
ans_yes=''
for i in d:
if len(ans_yes)==int(k):
print("Yes")
print(' '.join(ans_yes))
exit(0)
if len(ans_no)==int(k):
print("Yes")
print(' '.join(ans_no))
exit(0)
if i... | Title: Divisiblity of Differences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a multiset of *n* integers. You should select exactly *k* of them in a such way that the difference between any two of them is divisible by *m*, or tell that it is impossible.
Numbers can be re... | ```python
inp=input()
n,k,m=inp.split()
lol=input()
d=lol.split()
ans_no=''
ans_yes=''
for i in d:
if len(ans_yes)==int(k):
print("Yes")
print(' '.join(ans_yes))
exit(0)
if len(ans_no)==int(k):
print("Yes")
print(' '.join(ans_no))
exit(0)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
190 | A | Vasya and the Bus | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant and he loves counting money. So he wondered what maximum and minimum sum of money these passengers cou... | The input file consists of a single line containing two space-separated numbers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=105) — the number of the grown-ups and the number of the children in the bus, correspondingly. | If *n* grown-ups and *m* children could have ridden in the bus, then print on a single line two space-separated integers — the minimum and the maximum possible total bus fare, correspondingly.
Otherwise, print "Impossible" (without the quotes). | [
"1 2\n",
"0 5\n",
"2 2\n"
] | [
"2 2",
"Impossible",
"2 3"
] | In the first sample a grown-up rides with two children and pays two rubles.
In the second sample there are only children in the bus, so the situation is impossible.
In the third sample there are two cases: - Each of the two grown-ups rides with one children and pays one ruble for the tickets. In this case the passen... | 500 | [
{
"input": "1 2",
"output": "2 2"
},
{
"input": "0 5",
"output": "Impossible"
},
{
"input": "2 2",
"output": "2 3"
},
{
"input": "2 7",
"output": "7 8"
},
{
"input": "4 10",
"output": "10 13"
},
{
"input": "6 0",
"output": "6 6"
},
{
"input... | 1,659,958,443 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 92 | 0 | def solve():
n, m = map(int, input().split())
if n <= 0 and m > 0:
print("Impossible")
return
# min
r = n
if m - n > 0:
r += m - n
# max
r2 = n
if m - 1 > 0:
r2 += m - 1
print(f"{r} {r2}")
solve()
| Title: Vasya and the Bus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya heard a story: "In the city of High Bertown a bus number 62 left from the bus station. It had *n* grown-ups and *m* kids..."
The latter events happen to be of no importance to us. Vasya is an accountant... | ```python
def solve():
n, m = map(int, input().split())
if n <= 0 and m > 0:
print("Impossible")
return
# min
r = n
if m - n > 0:
r += m - n
# max
r2 = n
if m - 1 > 0:
r2 += m - 1
print(f"{r} {r2}")
solve()
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a ... | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line i... | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,683,725,918 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n, m = map(int, input().split())
mtr = [list(input().split()) for i in range(n)]
b_a_w = 'WGB'
res = True
for i in range(n):
for j in range(m):
if mtr[i][j] not in b_a_w:
res = False
if res == True:
print('Blakck&White')
else:
print('Color')
| Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the... | ```python
n, m = map(int, input().split())
mtr = [list(input().split()) for i in range(n)]
b_a_w = 'WGB'
res = True
for i in range(n):
for j in range(m):
if mtr[i][j] not in b_a_w:
res = False
if res == True:
print('Blakck&White')
else:
print('Color')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and... | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, ... | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer ... | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,597,667,129 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | l=int(input())
p=int(input())
q=int(input())
if p==q :
print(l/2)
else:
l=l*p
print(l/100) | Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the en... | ```python
l=int(input())
p=int(input())
q=int(input())
if p==q :
print(l/2)
else:
l=l*p
print(l/100)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
449 | D | Jzzhu and Numbers | PROGRAMMING | 2,400 | [
"bitmasks",
"combinatorics",
"dp"
] | null | null | Jzzhu have *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. We will call a sequence of indexes *i*1,<=*i*2,<=...,<=*i**k* (1<=≤<=*i*1<=<<=*i*2<=<<=...<=<<=*i**k*<=≤<=*n*) a group of size *k*.
Jzzhu wonders, how many groups exists such that *a**i*1 & *a**i*2 & ... & *a**i**k*<==<=0 (1<=≤<=*k*... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=106). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=106). | Output a single integer representing the number of required groups modulo 1000000007 (109<=+<=7). | [
"3\n2 3 3\n",
"4\n0 1 2 3\n",
"6\n5 2 0 5 2 1\n"
] | [
"0\n",
"10\n",
"53\n"
] | none | 2,000 | [
{
"input": "3\n2 3 3",
"output": "0"
},
{
"input": "4\n0 1 2 3",
"output": "10"
},
{
"input": "6\n5 2 0 5 2 1",
"output": "53"
},
{
"input": "16\n0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15",
"output": "64594"
},
{
"input": "10\n450661 128600 993228 725823 293549 33490 ... | 1,628,015,080 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 1,481 | 95,129,600 | import sys
def I(): return int(sys.stdin.readline().rstrip())
def MI(): return map(int,sys.stdin.readline().rstrip().split())
def LI(): return list(map(int,sys.stdin.readline().rstrip().split()))
def LI2(): return list(map(int,sys.stdin.readline().rstrip()))
def S(): return sys.stdin.readline().rstrip()
def LS():... | Title: Jzzhu and Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jzzhu have *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. We will call a sequence of indexes *i*1,<=*i*2,<=...,<=*i**k* (1<=≤<=*i*1<=<<=*i*2<=<<=...<=<<=*i**k*<=≤<=*n*) a group of size *k*.
Jzzhu won... | ```python
import sys
def I(): return int(sys.stdin.readline().rstrip())
def MI(): return map(int,sys.stdin.readline().rstrip().split())
def LI(): return list(map(int,sys.stdin.readline().rstrip().split()))
def LI2(): return list(map(int,sys.stdin.readline().rstrip()))
def S(): return sys.stdin.readline().rstrip()
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,618,816,359 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 0 | n=int(input())
x=input()
y=0
a=1
b=0
for i in range(n-1):
l=input()
if l==x:
a+=1
else:
y=l
b+=1
if a>b:
print(x)
else:
print(y) | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
n=int(input())
x=input()
y=0
a=1
b=0
for i in range(n-1):
l=input()
if l==x:
a+=1
else:
y=l
b+=1
if a>b:
print(x)
else:
print(y)
``` | 3.969 | MatrixStudio/Codeforces-Python-Submissions |
746 | G | New Roads | PROGRAMMING | 2,100 | [
"constructive algorithms",
"graphs",
"trees"
] | null | null | There are *n* cities in Berland, each of them has a unique id — an integer from 1 to *n*, the capital is the one with id 1. Now there is a serious problem in Berland with roads — there are no roads.
That is why there was a decision to build *n*<=-<=1 roads so that there will be exactly one simple path between each pai... | The first line contains three positive numbers *n*, *t* and *k* (2<=≤<=*n*<=≤<=2·105, 1<=≤<=*t*,<=*k*<=<<=*n*) — the distance to the most distant city from the capital and the number of cities which should be dead-ends (the capital in this number is not taken into consideration).
The second line contains a sequenc... | If it is impossible to built roads which satisfy all conditions, print -1.
Otherwise, in the first line print one integer *n* — the number of cities in Berland. In the each of the next *n*<=-<=1 line print two integers — the ids of cities that are connected by a road. Each road should be printed exactly once. You can ... | [
"7 3 3\n2 3 1\n",
"14 5 6\n4 4 2 2 1\n",
"3 1 1\n2\n"
] | [
"7\n1 3\n2 1\n2 6\n2 4\n7 4\n3 5\n",
"14\n3 1\n1 4\n11 6\n1 2\n10 13\n6 10\n10 12\n14 12\n8 4\n5 1\n3 7\n2 6\n5 9\n",
"-1\n"
] | none | 3,000 | [
{
"input": "7 3 3\n2 3 1",
"output": "7\n1 2\n2 6\n5 3\n2 4\n1 3\n7 4"
},
{
"input": "14 5 6\n4 4 2 2 1",
"output": "14\n12 14\n7 3\n6 10\n5 1\n13 10\n1 3\n8 4\n9 5\n4 1\n6 2\n12 10\n6 11\n2 1"
},
{
"input": "3 1 1\n2",
"output": "-1"
},
{
"input": "6 3 3\n1 2 2",
"output... | 1,675,357,874 | 3,974 | PyPy 3 | OK | TESTS | 45 | 405 | 30,924,800 | import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n, t, k = map(int, input().split())
a = list(map(int, input().split())) + [0]
x = [0] * t
for i in range(t):
x[i] = max(a[i] - a[i + 1], 0)
s = sum(x)
if s > k or k > n - t:
ans = -1
print(ans)
exit()
i = 0
wh... | Title: New Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities in Berland, each of them has a unique id — an integer from 1 to *n*, the capital is the one with id 1. Now there is a serious problem in Berland with roads — there are no roads.
That is why there was a d... | ```python
import sys, os, io
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
n, t, k = map(int, input().split())
a = list(map(int, input().split())) + [0]
x = [0] * t
for i in range(t):
x[i] = max(a[i] - a[i + 1], 0)
s = sum(x)
if s > k or k > n - t:
ans = -1
print(ans)
exit()
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
608 | B | Hamming Distance Sum | PROGRAMMING | 1,500 | [
"combinatorics",
"strings"
] | null | null | Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string *s* is denoted |*s*|. The Hamming distance between two strings *s* and *t* of equal length is defined as , where *s**i* is the *i*-th character of *s* and *t**i* is the *i*-th character of *t*. For exam... | The first line of the input contains binary string *a* (1<=≤<=|*a*|<=≤<=200<=000).
The second line of the input contains binary string *b* (|*a*|<=≤<=|*b*|<=≤<=200<=000).
Both strings are guaranteed to consist of characters '0' and '1' only. | Print a single integer — the sum of Hamming distances between *a* and all contiguous substrings of *b* of length |*a*|. | [
"01\n00111\n",
"0011\n0110\n"
] | [
"3\n",
"2\n"
] | For the first sample case, there are four contiguous substrings of *b* of length |*a*|: "00", "01", "11", and "11". The distance between "01" and "00" is |0 - 0| + |1 - 0| = 1. The distance between "01" and "01" is |0 - 0| + |1 - 1| = 0. The distance between "01" and "11" is |0 - 1| + |1 - 1| = 1. Last distance counts ... | 1,000 | [
{
"input": "01\n00111",
"output": "3"
},
{
"input": "0011\n0110",
"output": "2"
},
{
"input": "0\n0",
"output": "0"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "0\n1",
"output": "1"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1... | 1,567,987,947 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | s=[int(i) for i in input()]
t=[int(i) for i in input()]
sum=0
n=len(s)
for i in range(len(s)):
count=0
n=n-1
for j in range(i,len(t)-n):
print(j,count)
if(s[i]==1 and t[j]==0):
count+=1
if(s[i]==0 and t[j]==1):
count+=1
sum=sum+count
print... | Title: Hamming Distance Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Genos needs your help. He was asked to solve the following programming problem by Saitama:
The length of some string *s* is denoted |*s*|. The Hamming distance between two strings *s* and *t* of equal length is de... | ```python
s=[int(i) for i in input()]
t=[int(i) for i in input()]
sum=0
n=len(s)
for i in range(len(s)):
count=0
n=n-1
for j in range(i,len(t)-n):
print(j,count)
if(s[i]==1 and t[j]==0):
count+=1
if(s[i]==0 and t[j]==1):
count+=1
sum=sum+count... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,567,946,637 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 218 | 0 | rounds = int(input())
score_maps = {}
input_data = []
for _ in range(rounds):
name, score = tuple(input().split())
score = int(score)
if score < 0:
continue
input_data.append((name, score))
if name in score_maps.keys():
score_maps[name] += score
else:
score_... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
rounds = int(input())
score_maps = {}
input_data = []
for _ in range(rounds):
name, score = tuple(input().split())
score = int(score)
if score < 0:
continue
input_data.append((name, score))
if name in score_maps.keys():
score_maps[name] += score
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,554,826,256 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 280 | 0 | from heapq import *
def int_raw():
return int(input())
def ss_raw():
return input().split()
def ints_raw():
return list(map(int, input().split()))
S =input()
T=input()
def main():
if list(reversed(S))==list(T):
return "YES"
else:
return "NO"
print(main())
| Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
from heapq import *
def int_raw():
return int(input())
def ss_raw():
return input().split()
def ints_raw():
return list(map(int, input().split()))
S =input()
T=input()
def main():
if list(reversed(S))==list(T):
return "YES"
else:
return "NO"
print(mai... | 3.93 | MatrixStudio/Codeforces-Python-Submissions |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the ... | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,674,447,224 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 1,000 | 0 | n=int(input())
name=""
def Fib(x):
if x <= 1:
return x
else:
return (Fib(x - 1) + Fib(x - 2))
fib=list(Fib(i) for i in range(n))
for i in range(1,n+1):
if(i in fib):
name+='O'
else:
name+='o'
print(name) | Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should o... | ```python
n=int(input())
name=""
def Fib(x):
if x <= 1:
return x
else:
return (Fib(x - 1) + Fib(x - 2))
fib=list(Fib(i) for i in range(n))
for i in range(1,n+1):
if(i in fib):
name+='O'
else:
name+='o'
print(name)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
123 | A | Prime Permutation | PROGRAMMING | 1,300 | [
"implementation",
"number theory",
"strings"
] | null | null | You are given a string *s*, consisting of small Latin letters. Let's denote the length of the string as |*s*|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to rearrange characters in string *s* so that for any prime number *p*<=≤<=|*s*| and for any integer *i* ... | The only line contains the initial string *s*, consisting of small Latin letters (1<=≤<=|*s*|<=≤<=1000). | If it is possible to rearrange the characters in the string so that the above-mentioned conditions were fulfilled, then print in the first line "YES" (without the quotes) and print on the second line one of the possible resulting strings. If such permutation is impossible to perform, then print the single string "NO". | [
"abc\n",
"abcd\n",
"xxxyxxx\n"
] | [
"YES\nabc\n",
"NO\n",
"YES\nxxxxxxy\n"
] | In the first sample any of the six possible strings will do: "abc", "acb", "bac", "bca", "cab" or "cba".
In the second sample no letter permutation will satisfy the condition at *p* = 2 (*s*<sub class="lower-index">2</sub> = *s*<sub class="lower-index">4</sub>).
In the third test any string where character "y" doesn'... | 1,000 | [
{
"input": "abc",
"output": "YES\nabc"
},
{
"input": "abcd",
"output": "NO"
},
{
"input": "xxxyxxx",
"output": "YES\nxxxxxxy"
},
{
"input": "xxxjddyxduquybxdxx",
"output": "NO"
},
{
"input": "jjjjjjjjjjzjjjjjjjjjjjjjjjj",
"output": "YES\njjjjjjjjjjjjjjjjjjjjjj... | 1,602,342,727 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 0 | arr = input().replace(' ', '')
mx = {}
ans = ''
for i in set(arr):
mx[i] = arr.count(i)
ans += i * arr.count(i)
ans = ans.replace(max(mx, key = mx.get), '')
print(len(ans)) | Title: Prime Permutation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s*, consisting of small Latin letters. Let's denote the length of the string as |*s*|. The characters in the string are numbered starting from 1.
Your task is to find out if it is possible to... | ```python
arr = input().replace(' ', '')
mx = {}
ans = ''
for i in set(arr):
mx[i] = arr.count(i)
ans += i * arr.count(i)
ans = ans.replace(max(mx, key = mx.get), '')
print(len(ans))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
733 | B | Parade | PROGRAMMING | 1,100 | [
"math"
] | null | null | Very soon there will be a parade of victory over alien invaders in Berland. Unfortunately, all soldiers died in the war and now the army consists of entirely new recruits, many of whom do not even know from which leg they should begin to march. The civilian population also poorly understands from which leg recruits beg... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=105) — the number of columns.
The next *n* lines contain the pairs of integers *l**i* and *r**i* (1<=≤<=*l**i*,<=*r**i*<=≤<=500) — the number of soldiers in the *i*-th column which start to march from the left or the right leg respectively. | Print single integer *k* — the number of the column in which soldiers need to change the leg from which they start to march, or 0 if the maximum beauty is already reached.
Consider that columns are numbered from 1 to *n* in the order they are given in the input data.
If there are several answers, print any of them. | [
"3\n5 6\n8 9\n10 3\n",
"2\n6 5\n5 6\n",
"6\n5 9\n1 3\n4 8\n4 5\n23 54\n12 32\n"
] | [
"3\n",
"1\n",
"0\n"
] | In the first example if you don't give the order to change the leg, the number of soldiers, who start to march from the left leg, would equal 5 + 8 + 10 = 23, and from the right leg — 6 + 9 + 3 = 18. In this case the beauty of the parade will equal |23 - 18| = 5.
If you give the order to change the leg to the third co... | 1,000 | [
{
"input": "3\n5 6\n8 9\n10 3",
"output": "3"
},
{
"input": "2\n6 5\n5 6",
"output": "1"
},
{
"input": "6\n5 9\n1 3\n4 8\n4 5\n23 54\n12 32",
"output": "0"
},
{
"input": "2\n500 499\n500 500",
"output": "0"
},
{
"input": "1\n139 252",
"output": "0"
},
{
... | 1,694,895,273 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 576 | 6,963,200 | n = int(input())
R = 0
L = 0
maxrazn = -1
for i in range(n):
l, r = map(int, input().split())
L += l
R += r
if maxrazn < abs(r - l):
maxrazn = abs(r - l)
saved_i = i + 1
saved_l = l
saved_r = r
if abs(R - saved_r + saved_l - L + saved_l - saved_r) > abs(R-L):... | Title: Parade
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Very soon there will be a parade of victory over alien invaders in Berland. Unfortunately, all soldiers died in the war and now the army consists of entirely new recruits, many of whom do not even know from which leg they should... | ```python
n = int(input())
R = 0
L = 0
maxrazn = -1
for i in range(n):
l, r = map(int, input().split())
L += l
R += r
if maxrazn < abs(r - l):
maxrazn = abs(r - l)
saved_i = i + 1
saved_l = l
saved_r = r
if abs(R - saved_r + saved_l - L + saved_l - saved_r) >... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
803 | C | Maximal GCD | PROGRAMMING | 1,900 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Greatest common divisor of sequence is maximum of such numbers that every element of sequence is divi... | The first line consists of two numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1010). | If the answer exists then output *k* numbers — resulting sequence. Otherwise output -1. If there are multiple answers, print any of them. | [
"6 3\n",
"8 2\n",
"5 3\n"
] | [
"1 2 3\n",
"2 6\n",
"-1\n"
] | none | 0 | [
{
"input": "6 3",
"output": "1 2 3"
},
{
"input": "8 2",
"output": "2 6"
},
{
"input": "5 3",
"output": "-1"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "2 10000000... | 1,662,524,972 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 46 | 0 | import math as M
n,k=map(int,input().split())
if k>=2e5:print(-1)
else :
t=k*(k+1)//2
i=int(M.sqrt(n)*2)
ok=False
while i>=1 :
if ok :
break
if n%i==0 and n>=i*t:
ok=True
j,sum=1,0
while j<k:
sum+=j*i
print(j*i,end=' ')
j+=1
print(n-sum)
i-=1
if ok==False :print... | Title: Maximal GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given positive integer number *n*. You should create such strictly increasing sequence of *k* positive numbers *a*1,<=*a*2,<=...,<=*a**k*, that their sum is equal to *n* and greatest common divisor is maximal.
Grea... | ```python
import math as M
n,k=map(int,input().split())
if k>=2e5:print(-1)
else :
t=k*(k+1)//2
i=int(M.sqrt(n)*2)
ok=False
while i>=1 :
if ok :
break
if n%i==0 and n>=i*t:
ok=True
j,sum=1,0
while j<k:
sum+=j*i
print(j*i,end=' ')
j+=1
print(n-sum)
i-=1
if ok==Fa... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,595,520,915 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 310 | 20,172,800 | div = []
def divisor(n, m):
iii = 1
while True:
if m * iii >= n:
break
else:
div.append(m * iii)
iii += 1
n, a, b = map(int, input().split())
divisor(b, a)
j = 0
ans = []
for j in range(len(div)):
if div[j] - n > 0:
ans.append(div[j]... | Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
div = []
def divisor(n, m):
iii = 1
while True:
if m * iii >= n:
break
else:
div.append(m * iii)
iii += 1
n, a, b = map(int, input().split())
divisor(b, a)
j = 0
ans = []
for j in range(len(div)):
if div[j] - n > 0:
ans.app... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
981 | A | Antipalindrome | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" are not.
A substring $s[l \ldots r]$ ($1<=\leq<=l<=\leq<=r<=\leq<=|s|$) of a string $s<==<=s_{1}s_{2}... | The first line contains a non-empty string $s$ with length at most $50$ characters, containing lowercase English letters only. | If there is such a substring in $s$ that is not a palindrome, print the maximum length of such a substring. Otherwise print $0$.
Note that there can be multiple longest substrings that are not palindromes, but their length is unique. | [
"mew\n",
"wuffuw\n",
"qqqqqqqq\n"
] | [
"3\n",
"5\n",
"0\n"
] | "mew" is not a palindrome, so the longest substring of it that is not a palindrome, is the string "mew" itself. Thus, the answer for the first example is $3$.
The string "uffuw" is one of the longest non-palindrome substrings (of length $5$) of the string "wuffuw", so the answer for the second example is $5$.
All sub... | 500 | [
{
"input": "mew",
"output": "3"
},
{
"input": "wuffuw",
"output": "5"
},
{
"input": "qqqqqqqq",
"output": "0"
},
{
"input": "ijvji",
"output": "4"
},
{
"input": "iiiiiii",
"output": "0"
},
{
"input": "wobervhvvkihcuyjtmqhaaigvvgiaahqmtjyuchikvvhvrebow"... | 1,572,432,268 | 2,147,483,647 | Python 3 | OK | TESTS | 133 | 124 | 0 | s=input()
l=len(s)
a=list(s)
b=[]
cnt=0
for i in range(l-1,-1,-1):
b.append(s[i])
while(l>0):
b=a[::-1]
if(a!=b):
print(l)
cnt=1
break
else:
a.pop(l-1)
l=l-1
if(cnt==0):
print(cnt)
| Title: Antipalindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A string is a palindrome if it reads the same from the left to the right and from the right to the left. For example, the strings "kek", "abacaba", "r" and "papicipap" are palindromes, while the strings "abb" and "iq" ar... | ```python
s=input()
l=len(s)
a=list(s)
b=[]
cnt=0
for i in range(l-1,-1,-1):
b.append(s[i])
while(l>0):
b=a[::-1]
if(a!=b):
print(l)
cnt=1
break
else:
a.pop(l-1)
l=l-1
if(cnt==0):
print(cnt)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
409 | H | A + B Strikes Back | PROGRAMMING | 1,500 | [
"*special",
"brute force",
"constructive algorithms",
"dsu",
"implementation"
] | null | null | A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try? | The input contains two integers *a* and *b* (0<=≤<=*a*,<=*b*<=≤<=103), separated by a single space. | Output the sum of the given integers. | [
"5 14\n",
"381 492\n"
] | [
"19\n",
"873\n"
] | none | 0 | [
{
"input": "5 14",
"output": "19"
},
{
"input": "381 492",
"output": "873"
},
{
"input": "536 298",
"output": "834"
},
{
"input": "143 522",
"output": "665"
},
{
"input": "433 126",
"output": "559"
},
{
"input": "723 350",
"output": "1073"
},
{... | 1,656,846,914 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 0 | 0 | s=input().split()
a=int(s[0])
b=int(s[1])
print(a+b) | Title: A + B Strikes Back
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A + B is often used as an example of the easiest problem possible to show some contest platform. However, some scientists have observed that sometimes this problem is not so easy to get accepted. Want to try?
Input ... | ```python
s=input().split()
a=int(s[0])
b=int(s[1])
print(a+b)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,642,497,955 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 1 | 1,000 | 199,270,400 | a, b = map(int, (input().split()))
lst = []
lst2 = []
for i in range(1, a+1):
lst.append(i)
for i in range(1, b+1):
lst2.append(i)
lst = set(lst)
lst2 = set(lst2)
inter = lst.intersection(lst2)
l = list(inter)
k = 1
for i in l:
k *= i
print(k)
| Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
a, b = map(int, (input().split()))
lst = []
lst2 = []
for i in range(1, a+1):
lst.append(i)
for i in range(1, b+1):
lst2.append(i)
lst = set(lst)
lst2 = set(lst2)
inter = lst.intersection(lst2)
l = list(inter)
k = 1
for i in l:
k *= i
print(k)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
527 | B | Error Correct System | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Ford Prefect got a job as a web developer for a small company that makes towels. His current work task is to create a search engine for the website of the company. During the development process, he needs to write a subroutine for comparing strings *S* and *T* of equal length to be "similar". After a brief search on th... | The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the length of strings *S* and *T*.
The second line contains string *S*.
The third line contains string *T*.
Each of the lines only contains lowercase Latin letters. | In the first line, print number *x* — the minimum possible Hamming distance between strings *S* and *T* if you swap at most one pair of letters in *S*.
In the second line, either print the indexes *i* and *j* (1<=≤<=*i*,<=*j*<=≤<=*n*, *i*<=≠<=*j*), if reaching the minimum possible distance is possible by swapping lett... | [
"9\npergament\npermanent\n",
"6\nwookie\ncookie\n",
"4\npetr\negor\n",
"6\ndouble\nbundle\n"
] | [
"1\n4 6\n",
"1\n-1 -1\n",
"2\n1 2\n",
"2\n4 1\n"
] | In the second test it is acceptable to print *i* = 2, *j* = 3. | 1,000 | [
{
"input": "9\npergament\npermanent",
"output": "1\n4 6"
},
{
"input": "6\nwookie\ncookie",
"output": "1\n-1 -1"
},
{
"input": "4\npetr\negor",
"output": "2\n1 2"
},
{
"input": "6\ndouble\nbundle",
"output": "2\n4 1"
},
{
"input": "1\na\na",
"output": "0\n-1 -... | 1,433,565,437 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 45 | 2,000 | 9,318,400 | n = int(input())
s = input()
t = input()
diff = []
for i in range(len(s)):
if s[i]!=t[i]:
diff.append(s[i]+t[i]+str(i))
ans = 0
a = -1
b = -1
for i in range(len(diff)):
for j in range(i+1,len(diff)):
if diff[i][0]==diff[j][1] and diff[i][1]==diff[j][0]:
print(len(diff)-2)
... | Title: Error Correct System
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ford Prefect got a job as a web developer for a small company that makes towels. His current work task is to create a search engine for the website of the company. During the development process, he needs to write ... | ```python
n = int(input())
s = input()
t = input()
diff = []
for i in range(len(s)):
if s[i]!=t[i]:
diff.append(s[i]+t[i]+str(i))
ans = 0
a = -1
b = -1
for i in range(len(diff)):
for j in range(i+1,len(diff)):
if diff[i][0]==diff[j][1] and diff[i][1]==diff[j][0]:
print(len(diff)-2)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
639 | B | Bear and Forgotten Tree 3 | PROGRAMMING | 1,600 | [
"constructive algorithms",
"graphs",
"trees"
] | null | null | A tree is a connected undirected graph consisting of *n* vertices and *n*<=<=-<=<=1 edges. Vertices are numbered 1 through *n*.
Limak is a little polar bear and Radewoosh is his evil enemy. Limak once had a tree but Radewoosh stolen it. Bear is very sad now because he doesn't remember much about the tree — he can tell... | The first line contains three integers *n*, *d* and *h* (2<=≤<=*n*<=≤<=100<=000,<=1<=≤<=*h*<=≤<=*d*<=≤<=*n*<=-<=1) — the number of vertices, diameter, and height after rooting in vertex 1, respectively. | If there is no tree matching what Limak remembers, print the only line with "-1" (without the quotes).
Otherwise, describe any tree matching Limak's description. Print *n*<=-<=1 lines, each with two space-separated integers – indices of vertices connected by an edge. If there are many valid trees, print any of them. Y... | [
"5 3 2\n",
"8 5 2\n",
"8 4 2\n"
] | [
"1 2\n1 3\n3 4\n3 5",
"-1\n",
"4 8\n5 7\n2 3\n8 1\n2 1\n5 6\n1 5\n"
] | Below you can see trees printed to the output in the first sample and the third sample. | 750 | [
{
"input": "5 3 2",
"output": "1 2\n2 3\n1 4\n5 1"
},
{
"input": "8 5 2",
"output": "-1"
},
{
"input": "8 4 2",
"output": "4 8\n5 7\n2 3\n8 1\n2 1\n5 6\n1 5"
},
{
"input": "2 1 1",
"output": "1 2"
},
{
"input": "10 3 3",
"output": "1 2\n2 3\n3 4\n5 2\n6 2\n7 2... | 1,459,248,929 | 2,147,483,647 | Python 3 | OK | TESTS | 72 | 670 | 5,222,400 | '__author__'=='deepak Singh Mehta) '
if __name__=='__main__':
n,d,h = map(int,input().split())
if d>(2*h) or (d==1 and n != 2):
print(-1)
else:
for i in range(1,h+1):
print(i,i+1)
x = 1
i = 1
while i<=d-h:
y = h + 1 + i
... | Title: Bear and Forgotten Tree 3
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is a connected undirected graph consisting of *n* vertices and *n*<=<=-<=<=1 edges. Vertices are numbered 1 through *n*.
Limak is a little polar bear and Radewoosh is his evil enemy. Limak once had a t... | ```python
'__author__'=='deepak Singh Mehta) '
if __name__=='__main__':
n,d,h = map(int,input().split())
if d>(2*h) or (d==1 and n != 2):
print(-1)
else:
for i in range(1,h+1):
print(i,i+1)
x = 1
i = 1
while i<=d-h:
y = h + ... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
514 | A | Chewbaсca and Number | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform the initial number *x* to the minimum possible positive number by inverting some (possibly, zero) digits.... | The first line contains a single integer *x* (1<=≤<=*x*<=≤<=1018) — the number that Luke Skywalker gave to Chewbacca. | Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes. | [
"27\n",
"4545\n"
] | [
"22\n",
"4444\n"
] | none | 500 | [
{
"input": "27",
"output": "22"
},
{
"input": "4545",
"output": "4444"
},
{
"input": "1",
"output": "1"
},
{
"input": "9",
"output": "9"
},
{
"input": "8772",
"output": "1222"
},
{
"input": "81",
"output": "11"
},
{
"input": "71723447",
... | 1,691,054,030 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | num = str(input())
ans = 0
for idx, n in enumerate(num):
if idx == 0 and (n >= '5' and n < '9'):
ans = ans * 10 + (9 - int(n))
elif idx > 0 and (n >= '5' and n <= '9'):
ans = ans * 10 + (9 - int(n))
else:
ans = ans * 10 + int(n)
print(ans) | Title: Chewbaсca and Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luke Skywalker gave Chewbacca an integer number *x*. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit *t* means replacing it with digit 9<=-<=*t*.
Help Chewbacca to transform... | ```python
num = str(input())
ans = 0
for idx, n in enumerate(num):
if idx == 0 and (n >= '5' and n < '9'):
ans = ans * 10 + (9 - int(n))
elif idx > 0 and (n >= '5' and n <= '9'):
ans = ans * 10 + (9 - int(n))
else:
ans = ans * 10 + int(n)
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
271 | A | Beautiful Year | PROGRAMMING | 800 | [
"brute force"
] | null | null | It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has on... | The single line contains integer *y* (1000<=≤<=*y*<=≤<=9000) — the year number. | Print a single integer — the minimum year number that is strictly larger than *y* and all it's digits are distinct. It is guaranteed that the answer exists. | [
"1987\n",
"2013\n"
] | [
"2013\n",
"2014\n"
] | none | 500 | [
{
"input": "1987",
"output": "2013"
},
{
"input": "2013",
"output": "2014"
},
{
"input": "1000",
"output": "1023"
},
{
"input": "1001",
"output": "1023"
},
{
"input": "1234",
"output": "1235"
},
{
"input": "5555",
"output": "5601"
},
{
"inp... | 1,691,281,052 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 0 |
def razl(num):
for i in range(len(num)):
for j in range(i + 1, len(num)):
if num[i] == num[j]:
return False
return n
def next_god(num):
while razl(str(int(num) + 1)) == False:
num = str(int(num) + 1)
return str(int(num) + 1)
n = input()
prin... | Title: Beautiful Year
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: give... | ```python
def razl(num):
for i in range(len(num)):
for j in range(i + 1, len(num)):
if num[i] == num[j]:
return False
return n
def next_god(num):
while razl(str(int(num) + 1)) == False:
num = str(int(num) + 1)
return str(int(num) + 1)
n = input... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and... | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, ... | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer ... | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,543,032,706 | 2,147,483,647 | PyPy 3 | OK | TESTS | 45 | 139 | 0 | n=int(input());m=int(input());k=int(input());s=n*m;s1=m+k;print(s/s1) | Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the en... | ```python
n=int(input());m=int(input());k=int(input());s=n*m;s1=m+k;print(s/s1)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
557 | B | Pasha and Tea | PROGRAMMING | 1,500 | [
"constructive algorithms",
"implementation",
"math",
"sortings"
] | null | null | Pasha decided to invite his friends to a tea party. For that occasion, he has a large teapot with the capacity of *w* milliliters and 2*n* tea cups, each cup is for one of Pasha's friends. The *i*-th cup can hold at most *a**i* milliliters of water.
It turned out that among Pasha's friends there are exactly *n* boys a... | The first line of the input contains two integers, *n* and *w* (1<=≤<=*n*<=≤<=105, 1<=≤<=*w*<=≤<=109) — the number of Pasha's friends that are boys (equal to the number of Pasha's friends that are girls) and the capacity of Pasha's teapot in milliliters.
The second line of the input contains the sequence of integers *... | Print a single real number — the maximum total amount of water in milliliters that Pasha can pour to his friends without violating the given conditions. Your answer will be considered correct if its absolute or relative error doesn't exceed 10<=-<=6. | [
"2 4\n1 1 1 1\n",
"3 18\n4 4 4 2 2 2\n",
"1 5\n2 3\n"
] | [
"3",
"18",
"4.5"
] | Pasha also has candies that he is going to give to girls but that is another task... | 1,000 | [
{
"input": "2 4\n1 1 1 1",
"output": "3.0000000000"
},
{
"input": "3 18\n4 4 4 2 2 2",
"output": "18.0000000000"
},
{
"input": "1 5\n2 3",
"output": "4.5000000000"
},
{
"input": "1 1\n1000000000 1000000000",
"output": "1.0000000000"
},
{
"input": "4 1000000000\n1 ... | 1,436,106,559 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n, w = map(int, input().split())
a = sorted(list(map(int, input().split())))
print(min(3 * a[0], 1.5 * a[n], w))n, w = map(int, input().split()) | Title: Pasha and Tea
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha decided to invite his friends to a tea party. For that occasion, he has a large teapot with the capacity of *w* milliliters and 2*n* tea cups, each cup is for one of Pasha's friends. The *i*-th cup can hold at most ... | ```python
n, w = map(int, input().split())
a = sorted(list(map(int, input().split())))
print(min(3 * a[0], 1.5 * a[n], w))n, w = map(int, input().split())
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
443 | A | Anton and Letters | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to ti... | The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space. | Print a single number — the number of distinct letters in Anton's set. | [
"{a, b, c}\n",
"{b, a, b, a}\n",
"{}\n"
] | [
"3\n",
"2\n",
"0\n"
] | none | 500 | [
{
"input": "{a, b, c}",
"output": "3"
},
{
"input": "{b, a, b, a}",
"output": "2"
},
{
"input": "{}",
"output": "0"
},
{
"input": "{a, a, c, b, b, b, c, c, c, c}",
"output": "3"
},
{
"input": "{a, c, b, b}",
"output": "3"
},
{
"input": "{a, b}",
"o... | 1,688,144,733 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 77 | 0 | n = input()
n = n[1:-1].split(", ")
print(len(set(n))) | Title: Anton and Letters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the begi... | ```python
n = input()
n = n[1:-1].split(", ")
print(len(set(n)))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
610 | A | Pasha and Stick | PROGRAMMING | 1,000 | [
"combinatorics",
"math"
] | null | null | Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obviously be *n*.
Pasha likes rectangles but hates squares, so he wonders, how many ways are there to ... | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=2·109) — the length of Pasha's stick. | The output should contain a single integer — the number of ways to split Pasha's stick into four parts of positive integer length so that it's possible to make a rectangle by connecting the ends of these parts, but is impossible to form a square. | [
"6\n",
"20\n"
] | [
"1\n",
"4\n"
] | There is only one way to divide the stick in the first sample {1, 1, 2, 2}.
Four ways to divide the stick in the second sample are {1, 1, 9, 9}, {2, 2, 8, 8}, {3, 3, 7, 7} and {4, 4, 6, 6}. Note that {5, 5, 5, 5} doesn't work. | 500 | [
{
"input": "6",
"output": "1"
},
{
"input": "20",
"output": "4"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "2000000000",
"output": "4... | 1,697,393,952 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 15 | 46 | 0 | import math
length = (((int(input()) / 2) / 2) - 1)
print(math.ceil(length)) | Title: Pasha and Stick
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha has a wooden stick of some positive integer length *n*. He wants to perform exactly three cuts to get four parts of the stick. Each part must have some positive integer length and the sum of these lengths will obv... | ```python
import math
length = (((int(input()) / 2) / 2) - 1)
print(math.ceil(length))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
55 | B | Smallest number | PROGRAMMING | 1,600 | [
"brute force"
] | B. Smallest number | 2 | 256 | Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the next three minutes he took two numbers from the blackboard (not necessarily adjacent) and replaced... | First line contains four integers separated by space: 0<=≤<=*a*,<=*b*,<=*c*,<=*d*<=≤<=1000 — the original numbers. Second line contains three signs ('+' or '*' each) separated by space — the sequence of the operations in the order of performing. ('+' stands for addition, '*' — multiplication) | Output one integer number — the minimal result which can be obtained.
Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cin (also you may use %I64d). | [
"1 1 1 1\n+ + *\n",
"2 2 2 2\n* * +\n",
"1 2 3 4\n* + +\n"
] | [
"3\n",
"8\n",
"9\n"
] | none | 1,000 | [
{
"input": "1 1 1 1\n+ + *",
"output": "3"
},
{
"input": "2 2 2 2\n* * +",
"output": "8"
},
{
"input": "1 2 3 4\n* + +",
"output": "9"
},
{
"input": "15 1 3 1\n* * +",
"output": "18"
},
{
"input": "8 1 7 14\n+ + +",
"output": "30"
},
{
"input": "7 17 3... | 1,625,196,123 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 | a, b, c, d = [int(i) for i in input().split(' ')]
signs = [i for i in input().split(' ')]
small = [10000000000000000000000000]
def get_mul_add(num1, num2, operation):
# print(num1, num2, operation)
if operation == '+':
return num1+num2
elif operation == '*':
return num1*num2
... | Title: Smallest number
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Recently, Vladimir got bad mark in algebra again. To avoid such unpleasant events in future he decided to train his arithmetic skills. He wrote four integer numbers *a*, *b*, *c*, *d* on the blackboard. During each of the n... | ```python
a, b, c, d = [int(i) for i in input().split(' ')]
signs = [i for i in input().split(' ')]
small = [10000000000000000000000000]
def get_mul_add(num1, num2, operation):
# print(num1, num2, operation)
if operation == '+':
return num1+num2
elif operation == '*':
return num1... | 0 | MatrixStudio/Codeforces-Python-Submissions |
205 | A | Little Elephant and Rozdil | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elephant doesn't like to spend much time on travelling, so for his journey he will choose a town that needs minimum ti... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of cities. The next line contains *n* integers, separated by single spaces: the *i*-th integer represents the time needed to go from town Rozdil to the *i*-th town. The time values are positive integers, not exceeding 109.
You can consider t... | Print the answer on a single line — the number of the town the Little Elephant will go to. If there are multiple cities with minimum travel time, print "Still Rozdil" (without the quotes). | [
"2\n7 4\n",
"7\n7 4 47 100 4 9 12\n"
] | [
"2\n",
"Still Rozdil\n"
] | In the first sample there are only two cities where the Little Elephant can go. The travel time for the first town equals 7, to the second one — 4. The town which is closest to Rodzil (the only one) is the second one, so the answer is 2.
In the second sample the closest cities are cities two and five, the travelling t... | 500 | [
{
"input": "2\n7 4",
"output": "2"
},
{
"input": "7\n7 4 47 100 4 9 12",
"output": "Still Rozdil"
},
{
"input": "1\n47",
"output": "1"
},
{
"input": "2\n1000000000 1000000000",
"output": "Still Rozdil"
},
{
"input": "7\n7 6 5 4 3 2 1",
"output": "7"
},
{
... | 1,641,335,924 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 156 | 7,987,200 | T = int(input())
cities_time = list(map(int, input().split()))
least_time = min(cities_time)
count = cities_time.count(least_time)
if count == 1:
print(cities_time.index(least_time)+1)
else:
print('Still Rozdil') | Title: Little Elephant and Rozdil
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves Ukraine very much. Most of all he loves town Rozdol (ukr. "Rozdil").
However, Rozdil is dangerous to settle, so the Little Elephant wants to go to some other town. The Little Elepha... | ```python
T = int(input())
cities_time = list(map(int, input().split()))
least_time = min(cities_time)
count = cities_time.count(least_time)
if count == 1:
print(cities_time.index(least_time)+1)
else:
print('Still Rozdil')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,590,785,401 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 248 | 0 | #Se le asigna una proba a cada número en el dado.
#Se le resta a 6 para saber la oportunidad que Dot tiene de ganar.
#El resultado es usado para referenciar una variable de la lista de strings de proba.
proba = ['1/6','1/3','1/2','2/3','5/6','1/1']
Yakko, Wakko = map(int, input().split())
maxRoll = max(Yakko,Wakko)
p... | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
#Se le asigna una proba a cada número en el dado.
#Se le resta a 6 para saber la oportunidad que Dot tiene de ganar.
#El resultado es usado para referenciar una variable de la lista de strings de proba.
proba = ['1/6','1/3','1/2','2/3','5/6','1/1']
Yakko, Wakko = map(int, input().split())
maxRoll = max(Yakk... | 3.876 | MatrixStudio/Codeforces-Python-Submissions |
733 | B | Parade | PROGRAMMING | 1,100 | [
"math"
] | null | null | Very soon there will be a parade of victory over alien invaders in Berland. Unfortunately, all soldiers died in the war and now the army consists of entirely new recruits, many of whom do not even know from which leg they should begin to march. The civilian population also poorly understands from which leg recruits beg... | The first line contains single integer *n* (1<=≤<=*n*<=≤<=105) — the number of columns.
The next *n* lines contain the pairs of integers *l**i* and *r**i* (1<=≤<=*l**i*,<=*r**i*<=≤<=500) — the number of soldiers in the *i*-th column which start to march from the left or the right leg respectively. | Print single integer *k* — the number of the column in which soldiers need to change the leg from which they start to march, or 0 if the maximum beauty is already reached.
Consider that columns are numbered from 1 to *n* in the order they are given in the input data.
If there are several answers, print any of them. | [
"3\n5 6\n8 9\n10 3\n",
"2\n6 5\n5 6\n",
"6\n5 9\n1 3\n4 8\n4 5\n23 54\n12 32\n"
] | [
"3\n",
"1\n",
"0\n"
] | In the first example if you don't give the order to change the leg, the number of soldiers, who start to march from the left leg, would equal 5 + 8 + 10 = 23, and from the right leg — 6 + 9 + 3 = 18. In this case the beauty of the parade will equal |23 - 18| = 5.
If you give the order to change the leg to the third co... | 1,000 | [
{
"input": "3\n5 6\n8 9\n10 3",
"output": "3"
},
{
"input": "2\n6 5\n5 6",
"output": "1"
},
{
"input": "6\n5 9\n1 3\n4 8\n4 5\n23 54\n12 32",
"output": "0"
},
{
"input": "2\n500 499\n500 500",
"output": "0"
},
{
"input": "1\n139 252",
"output": "0"
},
{
... | 1,699,605,250 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n = int(input())
l, r = [], []
for i in range(n):
_l, _r = map(int, input().split())
l.append(_l)
r.append(_r)
sl, sr = sum(l), sum(r)
ans, idx = 0, 0
for i in range(n):
b = abs(sl - l[i] * 2 + r[i] * 2 - sr)
if ans < b:
ans, idx = b, i
print(idx + 1)
| Title: Parade
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Very soon there will be a parade of victory over alien invaders in Berland. Unfortunately, all soldiers died in the war and now the army consists of entirely new recruits, many of whom do not even know from which leg they should... | ```python
n = int(input())
l, r = [], []
for i in range(n):
_l, _r = map(int, input().split())
l.append(_l)
r.append(_r)
sl, sr = sum(l), sum(r)
ans, idx = 0, 0
for i in range(n):
b = abs(sl - l[i] * 2 + r[i] * 2 - sr)
if ans < b:
ans, idx = b, i
print(idx + 1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,589,252,733 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 0 | # -*- coding: utf-8 -*-
"""
Created on Tue May 12 08:21:40 2020
@author: Harshal
"""
n=int(input())
arr=list(map(int,input().split()))
temp=0
odd=0
even=0
for i in arr:
if i%2==0:
even+=1
else:
odd+=1
for x,y in enumerate(arr):
if odd==1:
if y%2==1:
... | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
# -*- coding: utf-8 -*-
"""
Created on Tue May 12 08:21:40 2020
@author: Harshal
"""
n=int(input())
arr=list(map(int,input().split()))
temp=0
odd=0
even=0
for i in arr:
if i%2==0:
even+=1
else:
odd+=1
for x,y in enumerate(arr):
if odd==1:
if y%2... | 3.9455 | MatrixStudio/Codeforces-Python-Submissions |
446 | A | DZY Loves Sequences | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"two pointers"
] | null | null | DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | In a single line print the answer to the problem — the maximum length of the required subsegment. | [
"6\n7 2 3 1 5 6\n"
] | [
"5\n"
] | You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | 500 | [
{
"input": "6\n7 2 3 1 5 6",
"output": "5"
},
{
"input": "10\n424238336 649760493 681692778 714636916 719885387 804289384 846930887 957747794 596516650 189641422",
"output": "9"
},
{
"input": "50\n804289384 846930887 681692778 714636916 957747794 424238336 719885387 649760493 596516650 1... | 1,562,918,952 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 38 | 280 | 11,673,600 | n = int(input())
a = [0] + list(map(int, input().split()))
best = 1
curl = 0
prevl = 0
for i in range(1, n + 1):
if a[i] > a[i - 1]:
curl += 1
best = max(best, curl + prevl, curl + 1 if curl != n else 0)
else:
if i == n:
best = max(best, prevl + curl, curl + 1 if curl != n else 0)
else:
bes... | Title: DZY Loves Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the... | ```python
n = int(input())
a = [0] + list(map(int, input().split()))
best = 1
curl = 0
prevl = 0
for i in range(1, n + 1):
if a[i] > a[i - 1]:
curl += 1
best = max(best, curl + prevl, curl + 1 if curl != n else 0)
else:
if i == n:
best = max(best, prevl + curl, curl + 1 if curl != n else 0)
els... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
760 | B | Frodo and pillows | PROGRAMMING | 1,500 | [
"binary search",
"greedy"
] | null | null | *n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as many pillows as possible. Of course, it's not always possible to share pillows equally, but any hobbit ge... | The only line contain three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=*m*<=≤<=109, 1<=≤<=*k*<=≤<=*n*) — the number of hobbits, the number of pillows and the number of Frodo's bed. | Print single integer — the maximum number of pillows Frodo can have so that no one is hurt. | [
"4 6 2\n",
"3 10 3\n",
"3 6 1\n"
] | [
"2\n",
"4\n",
"3\n"
] | In the first example Frodo can have at most two pillows. In this case, he can give two pillows to the hobbit on the first bed, and one pillow to each of the hobbits on the third and the fourth beds.
In the second example Frodo can take at most four pillows, giving three pillows to each of the others.
In the third exa... | 1,000 | [
{
"input": "4 6 2",
"output": "2"
},
{
"input": "3 10 3",
"output": "4"
},
{
"input": "3 6 1",
"output": "3"
},
{
"input": "3 3 3",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 1000000000 1",
"output": "1000000000"
},
{
... | 1,486,727,078 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 4,608,000 | n,m,k=map(int,input().split())
k=k-1
a=n*[1]
a[k]=m-n+1
i=k
if k==0:
while abs(a[(k+1)%n]-a[k%n])>=2:
a[k%n]-=1
a[(k+i)%n]+=1
i=(i+1)%n
elif k==n-1:
while abs(a[k%n]-a[(k-1)%n])>=2:
a[k%n]-=1
a[(k+i)%n]+=1
i=(i+1)%n
else:
while abs(a[(k+1)%... | Title: Frodo and pillows
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as ma... | ```python
n,m,k=map(int,input().split())
k=k-1
a=n*[1]
a[k]=m-n+1
i=k
if k==0:
while abs(a[(k+1)%n]-a[k%n])>=2:
a[k%n]-=1
a[(k+i)%n]+=1
i=(i+1)%n
elif k==n-1:
while abs(a[k%n]-a[(k-1)%n])>=2:
a[k%n]-=1
a[(k+i)%n]+=1
i=(i+1)%n
else:
while ab... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
813 | C | The Tag Game | PROGRAMMING | 1,700 | [
"dfs and similar",
"graphs"
] | null | null | Alice got tired of playing the tag game by the usual rules so she offered Bob a little modification to it. Now the game should be played on an undirected rooted tree of *n* vertices. Vertex 1 is the root of the tree.
Alice starts at vertex 1 and Bob starts at vertex *x* (*x*<=≠<=1). The moves are made in turns, Bob go... | The first line contains two integer numbers *n* and *x* (2<=≤<=*n*<=≤<=2·105, 2<=≤<=*x*<=≤<=*n*).
Each of the next *n*<=-<=1 lines contains two integer numbers *a* and *b* (1<=≤<=*a*,<=*b*<=≤<=*n*) — edges of the tree. It is guaranteed that the edges form a valid tree. | Print the total number of moves Alice and Bob will make. | [
"4 3\n1 2\n2 3\n2 4\n",
"5 2\n1 2\n2 3\n3 4\n2 5\n"
] | [
"4\n",
"6\n"
] | In the first example the tree looks like this:
The red vertex is Alice's starting position, the blue one is Bob's. Bob will make the game run the longest by standing at the vertex 3 during all the game. So here are the moves:
B: stay at vertex 3
A: go to vertex 2
B: stay at vertex 3
A: go to vertex 3
In the secon... | 0 | [
{
"input": "4 3\n1 2\n2 3\n2 4",
"output": "4"
},
{
"input": "5 2\n1 2\n2 3\n3 4\n2 5",
"output": "6"
},
{
"input": "2 2\n2 1",
"output": "2"
},
{
"input": "3 3\n2 1\n3 1",
"output": "2"
},
{
"input": "3 3\n1 2\n3 2",
"output": "4"
},
{
"input": "10 4\... | 1,654,862,986 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 670 | 27,955,200 | from sys import stdin,stderr
from collections import defaultdict,deque
def main():
n,x=map(int,stdin.readline().strip().split())
X=x-1
graph=[[] for i in range(n)]
for i in range(n):
graph[i]=[]
for _ in range(n-1):
a,b=map(int,stdin.readline().strip().split())
#a,b... | Title: The Tag Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alice got tired of playing the tag game by the usual rules so she offered Bob a little modification to it. Now the game should be played on an undirected rooted tree of *n* vertices. Vertex 1 is the root of the tree.
Alic... | ```python
from sys import stdin,stderr
from collections import defaultdict,deque
def main():
n,x=map(int,stdin.readline().strip().split())
X=x-1
graph=[[] for i in range(n)]
for i in range(n):
graph[i]=[]
for _ in range(n-1):
a,b=map(int,stdin.readline().strip().split())
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
912 | C | Perun, Ult! | PROGRAMMING | 2,500 | [
"brute force",
"greedy",
"sortings"
] | null | null | A lot of students spend their winter holidays productively. Vlad has advanced very well in doing so! For three days already, fueled by salads and tangerines — the leftovers from New Year celebration — he has been calibrating his rating in his favorite MOBA game, playing as a hero named Perun.
Perun has an ultimate abi... | In the first line, two integers are given (separated by spaces) — *n* and *m* (1<=≤<=*n*<=≤<=105, 0<=≤<=*m*<=≤<=105).
In the second line, there are three integers: , and (, ).
Each of the following *n* lines has three integers — , , (, ).
The next *m* lines contain three integers each — , , (, , ). It is guarant... | Output the single integer — the maximum amount of gold Vlad can obtain if he applies "Thunderwrath" exactly once, or -1 if this amount can be infinitely large. | [
"3 2\n1000 10 50\n70 5 5\n90 70 1\n110 20 2\n20 2 10\n30 3 10\n",
"1 1\n500 50 1000\n750 750 20\n10 1 300\n"
] | [
"3000\n",
"-1\n"
] | On the pictures you can see health points of each enemy versus time in sample cases.
Periods when Vlad can kill one enemy are marked with yellow color.
Periods when Vlad can kill two enemies are marked with purple color.
In the first sample case, Vlad can activate the ability at the 50-th second: the enemies 2 and 3... | 1,750 | [] | 1,689,342,218 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689342217.8015082")# 1689342217.801514 | Title: Perun, Ult!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A lot of students spend their winter holidays productively. Vlad has advanced very well in doing so! For three days already, fueled by salads and tangerines — the leftovers from New Year celebration — he has been calibratin... | ```python
print("_RANDOM_GUESS_1689342217.8015082")# 1689342217.801514
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a di... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero sco... | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,646,064,654 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 61 | 0 | n = int(input())
a = list(map(int,input().split()))
ans = []
for i in a:
if i>0 and i not in ans:
ans.append(i)
print(len(ans)) | Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with ... | ```python
n = int(input())
a = list(map(int,input().split()))
ans = []
for i in a:
if i>0 and i not in ans:
ans.append(i)
print(len(ans))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
237 | A | Free Cash | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends less than a minute to serve each client, but if a client comes in and sees that there is no free... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), that is the number of cafe visitors.
Each of the following *n* lines has two space-separated integers *h**i* and *m**i* (0<=≤<=*h**i*<=≤<=23; 0<=≤<=*m**i*<=≤<=59), representing the time when the *i*-th person comes into the cafe.
Note that the time is... | Print a single integer — the minimum number of cashes, needed to serve all clients next day. | [
"4\n8 0\n8 10\n8 10\n8 45\n",
"3\n0 12\n10 11\n22 22\n"
] | [
"2\n",
"1\n"
] | In the first sample it is not enough one cash to serve all clients, because two visitors will come into cafe in 8:10. Therefore, if there will be one cash in cafe, then one customer will be served by it, and another one will not wait and will go away.
In the second sample all visitors will come in different times, so ... | 500 | [
{
"input": "4\n8 0\n8 10\n8 10\n8 45",
"output": "2"
},
{
"input": "3\n0 12\n10 11\n22 22",
"output": "1"
},
{
"input": "5\n12 8\n15 27\n15 27\n16 2\n19 52",
"output": "2"
},
{
"input": "7\n5 6\n7 34\n7 34\n7 34\n12 29\n15 19\n20 23",
"output": "3"
},
{
"input": "... | 1,652,071,271 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 67 | 1,466 | 9,830,400 | c = {}
for _ in range(int(input())):
a = tuple(int(i) for i in input().split())
if a in c.keys():
c[a]+=1
else:
c[a] = 1
# print(list(c.items()))
print(max(c.values())) | Title: Free Cash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera runs a 24/7 fast food cafe. He magically learned that next day *n* people will visit his cafe. For each person we know the arrival time: the *i*-th person comes exactly at *h**i* hours *m**i* minutes. The cafe spends l... | ```python
c = {}
for _ in range(int(input())):
a = tuple(int(i) for i in input().split())
if a in c.keys():
c[a]+=1
else:
c[a] = 1
# print(list(c.items()))
print(max(c.values()))
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, ... | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,634,408,771 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 0 | s = input()
t=""
n = "hello"
for i in s:
if ((i not in t) and(i == "h")):
t += i
#print(t)
if ((i not in t) and(i == "e")):
t += i
#print(t)
if ((i not in t) and(i == "l")):
t += i
#print(t)
if ((t.count(i) == 1) and(i == "l")):
t +=... | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letter... | ```python
s = input()
t=""
n = "hello"
for i in s:
if ((i not in t) and(i == "h")):
t += i
#print(t)
if ((i not in t) and(i == "e")):
t += i
#print(t)
if ((i not in t) and(i == "l")):
t += i
#print(t)
if ((t.count(i) == 1) and(i == "l")):
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
725 | A | Jumping Ball | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | In a new version of the famous Pinball game, one of the most important parts of the game field is a sequence of *n* bumpers. The bumpers are numbered with integers from 1 to *n* from left to right. There are two types of bumpers. They are denoted by the characters '<' and '>'. When the ball hits the bumper at pos... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the length of the sequence of bumpers. The second line contains the string, which consists of the characters '<' and '>'. The character at the *i*-th position of this string corresponds to the type of the *i*-th bumper. | Print one integer — the number of positions in the sequence such that the ball will eventually fall from the game field if it starts at that position. | [
"4\n<<><\n",
"5\n>>>>>\n",
"4\n>><<\n"
] | [
"2",
"5",
"0"
] | In the first sample, the ball will fall from the field if starts at position 1 or position 2.
In the second sample, any starting position will result in the ball falling from the field. | 500 | [
{
"input": "4\n<<><",
"output": "2"
},
{
"input": "5\n>>>>>",
"output": "5"
},
{
"input": "4\n>><<",
"output": "0"
},
{
"input": "3\n<<>",
"output": "3"
},
{
"input": "3\n<<<",
"output": "3"
},
{
"input": "3\n><<",
"output": "0"
},
{
"input... | 1,605,864,551 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 124 | 716,800 | import re
n = int(input())
s = input()
match = re.findall('>+$|^<+', s)
res = 0
if match[0]:
res += len(match[0])
if match[1]:
res += len(match[0])
print(res)
| Title: Jumping Ball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a new version of the famous Pinball game, one of the most important parts of the game field is a sequence of *n* bumpers. The bumpers are numbered with integers from 1 to *n* from left to right. There are two types of b... | ```python
import re
n = int(input())
s = input()
match = re.findall('>+$|^<+', s)
res = 0
if match[0]:
res += len(match[0])
if match[1]:
res += len(match[0])
print(res)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
385 | B | Bear and Strings | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation",
"math",
"strings"
] | null | null | The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j*<=≤<=|*s*|), that string *x*(*i*,<=*j*)<==<=*s**i**s**i*<=+<=1... *s**j* contains at least one string... | The first line contains a non-empty string *s* (1<=≤<=|*s*|<=≤<=5000). It is guaranteed that the string only consists of lowercase English letters. | Print a single number — the answer to the problem. | [
"bearbtear\n",
"bearaabearc\n"
] | [
"6\n",
"20\n"
] | In the first sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9).
In the second sample, the following pairs (*i*, *j*) match: (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (1, 11), (2, 10), (2, 11), (3, 10), (3, 11), (4, 10), (4, 11), (5, 10), (5, 11)... | 1,000 | [
{
"input": "bearbtear",
"output": "6"
},
{
"input": "bearaabearc",
"output": "20"
},
{
"input": "pbearbearhbearzqbearjkterasjhy",
"output": "291"
},
{
"input": "pbearjbearbebearnbabcffbearbearwubearjezpiorrbearbearjbdlbearbearqbearjbearwipmsbearoaftrsebearzsnqb",
"output"... | 1,683,573,097 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | s = input()
n = len(s)
bear_count = 0
for i in range(n):
if i + 3 < n and s[i:i+4] == 'bear':
bear_count += (i + 1) * (n - i - 3)
print(bear_count)
| Title: Bear and Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The bear has a string *s*<==<=*s*1*s*2... *s*|*s*| (record |*s*| is the string's length), consisting of lowercase English letters. The bear wants to count the number of such pairs of indices *i*,<=*j* (1<=≤<=*i*<=≤<=*j... | ```python
s = input()
n = len(s)
bear_count = 0
for i in range(n):
if i + 3 < n and s[i:i+4] == 'bear':
bear_count += (i + 1) * (n - i - 3)
print(bear_count)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
622 | B | The Time | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedi... | The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes... | The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format. | [
"23:59\n10\n",
"20:20\n121\n",
"10:10\n0\n"
] | [
"00:09\n",
"22:21\n",
"10:10\n"
] | none | 0 | [
{
"input": "23:59\n10",
"output": "00:09"
},
{
"input": "20:20\n121",
"output": "22:21"
},
{
"input": "10:10\n0",
"output": "10:10"
},
{
"input": "12:34\n10000",
"output": "11:14"
},
{
"input": "00:00\n10000",
"output": "22:40"
},
{
"input": "00:00\n14... | 1,588,841,480 | 2,147,483,647 | PyPy 3 | OK | TESTS | 59 | 155 | 20,172,800 | l = list(map(int,input().split(":")))
minute = int(input())
ans = [0,0]
add = 0
add += (l[1] + minute)//60;
ans[1] = (l[1] + minute)%60
ans[0] = (add + l[0])%24
ans1 = ""
if(ans[0] < 10):
ans1 += "0"
ans1 += str(ans[0])
ans1 += ":"
if(ans[1] < 10):
ans1 += "0"
ans1 += str(ans[1])
print(ans1) | Title: The Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read mo... | ```python
l = list(map(int,input().split(":")))
minute = int(input())
ans = [0,0]
add = 0
add += (l[1] + minute)//60;
ans[1] = (l[1] + minute)%60
ans[0] = (add + l[0])%24
ans1 = ""
if(ans[0] < 10):
ans1 += "0"
ans1 += str(ans[0])
ans1 += ":"
if(ans[1] < 10):
ans1 += "0"
ans1 += str(ans[1])
print(ans1)
... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
464 | C | Substitutes in Number | PROGRAMMING | 2,100 | [
"dp"
] | null | null | Andrew and Eugene are playing a game. Initially, Andrew has string *s*, consisting of digits. Eugene sends Andrew multiple queries of type "*d**i*<=→<=*t**i*", that means "replace all digits *d**i* in string *s* with substrings equal to *t**i*". For example, if *s*<==<=123123, then query "2<=→<=00" transforms *s* to 10... | The first line contains string *s* (1<=≤<=|*s*|<=≤<=105), consisting of digits — the string before processing all the requests.
The second line contains a single integer *n* (0<=≤<=*n*<=≤<=105) — the number of queries.
The next *n* lines contain the descriptions of the queries. The *i*-th query is described by string... | Print a single integer — remainder of division of the resulting number by 1000000007 (109<=+<=7). | [
"123123\n1\n2->00\n",
"123123\n1\n3->\n",
"222\n2\n2->0\n0->7\n",
"1000000008\n0\n"
] | [
"10031003\n",
"1212\n",
"777\n",
"1\n"
] | Note that the leading zeroes are not removed from string *s* after the replacement (you can see it in the third sample). | 1,500 | [
{
"input": "123123\n1\n2->00",
"output": "10031003"
},
{
"input": "123123\n1\n3->",
"output": "1212"
},
{
"input": "222\n2\n2->0\n0->7",
"output": "777"
},
{
"input": "1000000008\n0",
"output": "1"
},
{
"input": "100\n5\n1->301\n0->013\n1->013\n0->103\n0->103",
... | 1,411,484,878 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 10 | 139 | 102,400 | s = input()
n = int(input())
for i in range(n):
l = input()
index = int(l.find('->'))
s = s.replace(l[:index], l[index+2:])
print(int(s) % 1000000007)
| Title: Substitutes in Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Andrew and Eugene are playing a game. Initially, Andrew has string *s*, consisting of digits. Eugene sends Andrew multiple queries of type "*d**i*<=→<=*t**i*", that means "replace all digits *d**i* in string *s* w... | ```python
s = input()
n = int(input())
for i in range(n):
l = input()
index = int(l.find('->'))
s = s.replace(l[:index], l[index+2:])
print(int(s) % 1000000007)
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
902 | B | Coloring a Tree | PROGRAMMING | 1,200 | [
"dfs and similar",
"dsu",
"greedy"
] | null | null | You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
You have to color the tree into the given colors using the smallest possible number of steps. On eac... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=104) — the number of vertices in the tree.
The second line contains *n*<=-<=1 integers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* means that there is an edge between vertices *i* and *p**i*.
The third line contains *n* integers *c*1,<... | Print a single integer — the minimum number of steps you have to perform to color the tree into given colors. | [
"6\n1 2 2 1 5\n2 1 1 1 1 1\n",
"7\n1 1 2 3 1 4\n3 3 1 1 1 2 3\n"
] | [
"3\n",
"5\n"
] | The tree from the first sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/10324ccdc37f95343acc4f3c6050d8c334334ffa.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color ... | 1,000 | [
{
"input": "6\n1 2 2 1 5\n2 1 1 1 1 1",
"output": "3"
},
{
"input": "7\n1 1 2 3 1 4\n3 3 1 1 1 2 3",
"output": "5"
},
{
"input": "2\n1\n2 2",
"output": "1"
},
{
"input": "3\n1 1\n2 2 2",
"output": "1"
},
{
"input": "4\n1 2 1\n1 2 3 4",
"output": "4"
},
{
... | 1,513,699,176 | 1,476 | Python 3 | OK | TESTS | 50 | 77 | 6,553,600 | n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
ans = 1
for i in range(n - 1):
if b[i+1] != b[a[i]-1]:
ans += 1
print(ans) | Title: Coloring a Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
... | ```python
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
ans = 1
for i in range(n - 1):
if b[i+1] != b[a[i]-1]:
ans += 1
print(ans)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
262 | B | Roma and Changing Signs | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of the company is the sum of all integers in sequence. Roma decided to perform exactly *k* changes of signs of s... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=105), showing, how many numbers are in the sequence and how many swaps are to be made.
The second line contains a non-decreasing sequence, consisting of *n* integers *a**i* (|*a**i*|<=≤<=104).
The numbers in the lines are separated by single spaces... | In the single line print the answer to the problem — the maximum total income that we can obtain after exactly *k* changes. | [
"3 2\n-1 -1 1\n",
"3 1\n-1 -1 1\n"
] | [
"3\n",
"1\n"
] | In the first sample we can get sequence [1, 1, 1], thus the total income equals 3.
In the second test, the optimal strategy is to get sequence [-1, 1, 1], thus the total income equals 1. | 1,000 | [
{
"input": "3 2\n-1 -1 1",
"output": "3"
},
{
"input": "3 1\n-1 -1 1",
"output": "1"
},
{
"input": "17 27\n257 320 676 1136 2068 2505 2639 4225 4951 5786 7677 7697 7851 8337 8429 8469 9343",
"output": "81852"
},
{
"input": "69 28\n-9822 -9264 -9253 -9221 -9139 -9126 -9096 -89... | 1,631,715,816 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 154 | 20,172,800 | n, k = map(int, input().split())
array = []
currentInput = input().split()
for i in range(n):
array.append(int(currentInput[i]))
array.sort()
for i in range(len(array)):
if k == 0:
break
currentNum = array[i]
if currentNum >= 0:
if k % 2 == 0:
array[i] = current... | Title: Roma and Changing Signs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma works in a company that sells TVs. Now he has to prepare a report for the last year.
Roma has got a list of the company's incomes. The list is a sequence that consists of *n* integers. The total income of ... | ```python
n, k = map(int, input().split())
array = []
currentInput = input().split()
for i in range(n):
array.append(int(currentInput[i]))
array.sort()
for i in range(len(array)):
if k == 0:
break
currentNum = array[i]
if currentNum >= 0:
if k % 2 == 0:
array[i]... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
603 | A | Alternative Thinking | PROGRAMMING | 1,600 | [
"dp",
"greedy",
"math"
] | null | null | Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length *n*. Each character of Kevin's string represents Kevin's score on one of the *n* questions of the olympiad—'1' for a correctly identified cow and '0' otherwise.
However, all is... | The first line contains the number of questions on the olympiad *n* (1<=≤<=*n*<=≤<=100<=000).
The following line contains a binary string of length *n* representing Kevin's results on the USAICO. | Output a single integer, the length of the longest possible alternating subsequence that Kevin can create in his string after flipping a single substring. | [
"8\n10000011\n",
"2\n01\n"
] | [
"5\n",
"2\n"
] | In the first sample, Kevin can flip the bolded substring '10000011' and turn his string into '10011011', which has an alternating subsequence of length 5: '10011011'.
In the second sample, Kevin can flip the entire string and still have the same score. | 500 | [
{
"input": "8\n10000011",
"output": "5"
},
{
"input": "2\n01",
"output": "2"
},
{
"input": "5\n10101",
"output": "5"
},
{
"input": "75\n010101010101010101010101010101010101010101010101010101010101010101010101010",
"output": "75"
},
{
"input": "11\n00000000000",
... | 1,622,552,350 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 1 | 186 | 2,252,800 | ###### ### ####### ####### ## # ##### ### #####
# # # # # # # # # # # # # ###
# # # # # # # # # # # # # ###
###### ######### # # # # # # ... | Title: Alternative Thinking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kevin has just recevied his disappointing results on the USA Identification of Cows Olympiad (USAICO) in the form of a binary string of length *n*. Each character of Kevin's string represents Kevin's score on one o... | ```python
###### ### ####### ####### ## # ##### ### #####
# # # # # # # # # # # # # ###
# # # # # # # # # # # # # ###
###### ######### # # # #... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
298 | B | Sail | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assume the boat is currently at (*x*,<=*y*).
- If the wind blows to the east, the boat will ... | The first line contains five integers *t*,<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y* (1<=≤<=*t*<=≤<=105,<=<=-<=109<=≤<=*s**x*,<=*s**y*,<=*e**x*,<=*e**y*<=≤<=109). The starting location and the ending location will be different.
The second line contains *t* characters, the *i*-th character is the wind blowing direction at the... | If they can reach (*e**x*,<=*e**y*) within *t* seconds, print the earliest time they can achieve it. Otherwise, print "-1" (without quotes). | [
"5 0 0 1 1\nSESNW\n",
"10 5 3 3 6\nNENSWESNEE\n"
] | [
"4\n",
"-1\n"
] | In the first sample, they can stay at seconds 1, 3, and move at seconds 2, 4.
In the second sample, they cannot sail to the destination. | 500 | [
{
"input": "5 0 0 1 1\nSESNW",
"output": "4"
},
{
"input": "10 5 3 3 6\nNENSWESNEE",
"output": "-1"
},
{
"input": "19 -172106364 -468680119 -172106365 -468680119\nSSEEESSSESESWSEESSS",
"output": "13"
},
{
"input": "39 -1000000000 -1000000000 -999999997 -1000000000\nENEENWSWSS... | 1,622,581,252 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 374 | 2,457,600 | import sys
import math
import collections
import heapq
t,s1,s2,e1,e2=(int(i) for i in input().split())
s=input()
k=-1
for i in range(len(s)):
if(e1<s1 and s[i]=='W'):
s1-=1
elif(e1>s1 and s[i]=='E'):
s1+=1
elif(e2<s2 and s[i]=='S'):
s2-=1
elif(e2>s2 and s[i]=='N'):
... | Title: Sail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The polar bears are going fishing. They plan to sail from (*s**x*,<=*s**y*) to (*e**x*,<=*e**y*). However, the boat can only sail by wind. At each second, the wind blows in one of these directions: east, south, west or north. Assu... | ```python
import sys
import math
import collections
import heapq
t,s1,s2,e1,e2=(int(i) for i in input().split())
s=input()
k=-1
for i in range(len(s)):
if(e1<s1 and s[i]=='W'):
s1-=1
elif(e1>s1 and s[i]=='E'):
s1+=1
elif(e2<s2 and s[i]=='S'):
s2-=1
elif(e2>s2 and s[... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
320 | A | Magic Numbers | PROGRAMMING | 900 | [
"brute force",
"greedy"
] | null | null | A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Determine if it is a magic number or not. | The first line of input contains an integer *n*, (1<=≤<=*n*<=≤<=109). This number doesn't contain leading zeros. | Print "YES" if *n* is a magic number or print "NO" if it's not. | [
"114114\n",
"1111\n",
"441231\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "114114",
"output": "YES"
},
{
"input": "1111",
"output": "YES"
},
{
"input": "441231",
"output": "NO"
},
{
"input": "1",
"output": "YES"
},
{
"input": "14",
"output": "YES"
},
{
"input": "114",
"output": "YES"
},
{
"input": "9",... | 1,667,152,083 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 92 | 0 | a = input()
b = a
d = a.count("144")
e = a.count("14")
r = a.count("1")
a = a.replace("144", " ", d)
a = a.replace("14", " ", e)
a = a.replace("1", " ", r)
a = a.replace(" ", "")
if (len(a) == 0):
print("YES")
else:
print("NO") | Title: Magic Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're ... | ```python
a = input()
b = a
d = a.count("144")
e = a.count("14")
r = a.count("1")
a = a.replace("144", " ", d)
a = a.replace("14", " ", e)
a = a.replace("1", " ", r)
a = a.replace(" ", "")
if (len(a) == 0):
print("YES")
else:
print("NO")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
161 | D | Distance in Tree | PROGRAMMING | 1,800 | [
"dfs and similar",
"dp",
"trees"
] | null | null | A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices and a positive number *k*. Find the number of distinct pairs of the vertices which have a distance of ex... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50000, 1<=≤<=*k*<=≤<=500) — the number of vertices and the required distance between the vertices.
Next *n*<=-<=1 lines describe the edges as "*a**i* *b**i*" (without the quotes) (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*), where *a**i* and *b**i* ... | Print a single integer — the number of distinct pairs of the tree's vertices which have a distance of exactly *k* between them.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"5 2\n1 2\n2 3\n3 4\n2 5\n",
"5 3\n1 2\n2 3\n3 4\n4 5\n"
] | [
"4\n",
"2\n"
] | In the first sample the pairs of vertexes at distance 2 from each other are (1, 3), (1, 5), (3, 5) and (2, 4). | 2,000 | [
{
"input": "5 2\n1 2\n2 3\n3 4\n2 5",
"output": "4"
},
{
"input": "5 3\n1 2\n2 3\n3 4\n4 5",
"output": "2"
},
{
"input": "10 1\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "9"
},
{
"input": "10 2\n2 1\n3 1\n4 3\n5 4\n6 5\n7 1\n8 6\n9 2\n10 6",
"output": "10"
... | 1,387,625,298 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 3,000 | 0 | n, k = map(int, input().split())
s, p = 0, [[] for i in range(n + 1)]
for i in range(n - 1):
a, b = map(int, input().split())
p[a].append(b)
p[b].append(a)
t = [a for a in range(1, n + 1) if len(p[a]) == 1]
q = [[1] + [0] * k for a in range(n + 1)]
while len(t) > 1:
a = t.pop()
b = p[a][0]... | Title: Distance in Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is a connected graph that doesn't contain any cycles.
The distance between two vertices of a tree is the length (in edges) of the shortest path between these vertices.
You are given a tree with *n* vertices an... | ```python
n, k = map(int, input().split())
s, p = 0, [[] for i in range(n + 1)]
for i in range(n - 1):
a, b = map(int, input().split())
p[a].append(b)
p[b].append(a)
t = [a for a in range(1, n + 1) if len(p[a]) == 1]
q = [[1] + [0] * k for a in range(n + 1)]
while len(t) > 1:
a = t.pop()
b... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
44 | A | Indian Summer | PROGRAMMING | 900 | [
"implementation"
] | A. Indian Summer | 2 | 256 | Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the species of the tree of one of the leaves she already has. Find out how many leaves Alyona has picked. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of leaves Alyona has found. The next *n* lines contain the leaves' descriptions. Each leaf is characterized by the species of the tree it has fallen from and by the color. The species of the trees and colors are given in names, consisting of no mor... | Output the single number — the number of Alyona's leaves. | [
"5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green\n",
"3\noak yellow\noak yellow\noak yellow\n"
] | [
"4\n",
"1\n"
] | none | 0 | [
{
"input": "5\nbirch yellow\nmaple red\nbirch yellow\nmaple yellow\nmaple green",
"output": "4"
},
{
"input": "3\noak yellow\noak yellow\noak yellow",
"output": "1"
},
{
"input": "5\nxbnbkzn hp\nkaqkl vrgzbvqstu\nj aqidx\nhos gyul\nwefxmh tygpluae",
"output": "5"
},
{
"input"... | 1,683,331,719 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 92 | 0 | n=int(input())
name=[]
for i in range(n):
x=input()
name.append(x)
name=set(name)
print(len(name)) | Title: Indian Summer
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Indian summer is such a beautiful time of the year! A girl named Alyona is walking in the forest and picking a bouquet from fallen leaves. Alyona is very choosy — she doesn't take a leaf if it matches the color and the specie... | ```python
n=int(input())
name=[]
for i in range(n):
x=input()
name.append(x)
name=set(name)
print(len(name))
``` | 3.977 | MatrixStudio/Codeforces-Python-Submissions |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,670,909,802 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 36 | 109 | 6,144,000 | def x(a,b):
c=0
for s in a:
if s>b :
c=c+1
return c
n=int(input())
z=list(map(int,input().split()))
for i in range(n):
print(1+x(z,z[i]),end=' ')
| Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
def x(a,b):
c=0
for s in a:
if s>b :
c=c+1
return c
n=int(input())
z=list(map(int,input().split()))
for i in range(n):
print(1+x(z,z[i]),end=' ')
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, wh... | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforc... | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,676,749,332 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 106 | 62 | 0 | n, k = map(int, input().split())
som = sum(map(int, input().split()))
T = (2*k - 1) * n - 2 * som
if T < 0:
print(0)
else:
print(T) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
... | ```python
n, k = map(int, input().split())
som = sum(map(int, input().split()))
T = (2*k - 1) * n - 2 * som
if T < 0:
print(0)
else:
print(T)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
965 | C | Greedy Arkady | PROGRAMMING | 2,000 | [
"math"
] | null | null | $k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arkady will choose an integer $x$ and then give the first $x$ candies to himself, the next $x$ candies ... | The only line contains four integers $n$, $k$, $M$ and $D$ ($2 \le n \le 10^{18}$, $2 \le k \le n$, $1 \le M \le n$, $1 \le D \le \min{(n, 1000)}$, $M \cdot D \cdot k \ge n$) — the number of candies, the number of people, the maximum number of candies given to a person at once, the maximum number of times a person can ... | Print a single integer — the maximum possible number of candies Arkady can give to himself.
Note that it is always possible to choose some valid $x$. | [
"20 4 5 2\n",
"30 9 4 1\n"
] | [
"8\n",
"4\n"
] | In the first example Arkady should choose $x = 4$. He will give $4$ candies to himself, $4$ candies to the second person, $4$ candies to the third person, then $4$ candies to the fourth person and then again $4$ candies to himself. No person is given candies more than $2$ times, and Arkady receives $8$ candies in total... | 1,500 | [
{
"input": "20 4 5 2",
"output": "8"
},
{
"input": "30 9 4 1",
"output": "4"
},
{
"input": "2 2 1 1",
"output": "1"
},
{
"input": "42 20 5 29",
"output": "5"
},
{
"input": "1000000000000000000 135 1000000000000000 1000",
"output": "8325624421831635"
},
{
... | 1,524,935,918 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 78 | 7,065,600 | n,k,m,d=map(int,input().split())
a=0
for i in range(1,d+1):
a=max(a,min(m*i,n//((i-1)*k+1)*i))
print(a) | Title: Greedy Arkady
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
$k$ people want to split $n$ candies between them. Each candy should be given to exactly one of them or be thrown away.
The people are numbered from $1$ to $k$, and Arkady is the first of them. To split the candies, Arka... | ```python
n,k,m,d=map(int,input().split())
a=0
for i in range(1,d+1):
a=max(a,min(m*i,n//((i-1)*k+1)*i))
print(a)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
508 | B | Anton and currency you all know | PROGRAMMING | 1,300 | [
"greedy",
"math",
"strings"
] | null | null | Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed to be an integer.
Reliable sources have informed the financier Anton of some information about the exchange rate of... | The first line contains an odd positive integer *n* — the exchange rate of currency you all know for today. The length of number *n*'s representation is within range from 2 to 105, inclusive. The representation of *n* doesn't contain any leading zeroes. | If the information about tomorrow's exchange rate is inconsistent, that is, there is no integer that meets the condition, print <=-<=1.
Otherwise, print the exchange rate of currency you all know against the burle for tomorrow. This should be the maximum possible number of those that are even and that are obtained fro... | [
"527\n",
"4573\n",
"1357997531\n"
] | [
"572\n",
"3574\n",
"-1\n"
] | none | 1,000 | [
{
"input": "527",
"output": "572"
},
{
"input": "4573",
"output": "3574"
},
{
"input": "1357997531",
"output": "-1"
},
{
"input": "444443",
"output": "444434"
},
{
"input": "22227",
"output": "72222"
},
{
"input": "24683",
"output": "34682"
},
... | 1,635,422,854 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 93 | 41,472,000 | inds = []
ind = 0
s = []
for i in input():
if int(i) % 2 == 0:
inds.append(ind)
ind += 1
s.append(i)
if len(inds) == 0:
print(-1)
exit()
for ind in inds:
if int(s[ind]) < int(s[-1]):
s[-1], s[ind] = s[ind], s[-1]
print(''.join(s))
exit()
s[-1], s[inds[-1]] = s[inds[-1]], s[-1]
print(''.jo... | Title: Anton and currency you all know
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland, 2016. The exchange rate of currency you all know against the burle has increased so much that to simplify the calculations, its fractional part was neglected and the exchange rate is now assumed... | ```python
inds = []
ind = 0
s = []
for i in input():
if int(i) % 2 == 0:
inds.append(ind)
ind += 1
s.append(i)
if len(inds) == 0:
print(-1)
exit()
for ind in inds:
if int(s[ind]) < int(s[-1]):
s[-1], s[ind] = s[ind], s[-1]
print(''.join(s))
exit()
s[-1], s[inds[-1]] = s[inds[-1]], s[-1]
p... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
369 | C | Valera and Elections | PROGRAMMING | 1,600 | [
"dfs and similar",
"graphs",
"trees"
] | null | null | The city Valera lives in is going to hold elections to the city Parliament.
The city has *n* districts and *n*<=-<=1 bidirectional roads. We know that from any district there is a path along the roads to any other district. Let's enumerate all districts in some way by integers from 1 to *n*, inclusive. Furthermore, fo... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of districts in the city.
Then *n*<=-<=1 lines follow. Each line contains the description of a city road as three positive integers *x**i*, *y**i*, *t**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*, 1<=≤<=*t**i*<=≤<=2) — the districts connected by the *... | In the first line print a single non-negative number *k* — the minimum size of the required subset of candidates. Then on the second line print *k* space-separated integers *a*1,<=*a*2,<=... *a**k* — the numbers of the candidates that form the required subset. If there are multiple solutions, you are allowed to print a... | [
"5\n1 2 2\n2 3 2\n3 4 2\n4 5 2\n",
"5\n1 2 1\n2 3 2\n2 4 1\n4 5 1\n",
"5\n1 2 2\n1 3 2\n1 4 2\n1 5 2\n"
] | [
"1\n5 \n",
"1\n3 \n",
"4\n5 4 3 2 \n"
] | none | 1,500 | [
{
"input": "5\n1 2 2\n2 3 2\n3 4 2\n4 5 2",
"output": "1\n5 "
},
{
"input": "5\n1 2 1\n2 3 2\n2 4 1\n4 5 1",
"output": "1\n3 "
},
{
"input": "5\n1 2 2\n1 3 2\n1 4 2\n1 5 2",
"output": "4\n5 4 3 2 "
},
{
"input": "5\n1 5 1\n5 4 2\n4 3 1\n3 2 2",
"output": "1\n2 "
},
{
... | 1,568,500,148 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n = int(input())
listaAdj = [[] for i in range(n)]
broken = set()
for i in range(n - 1):
x, y, t = map(int, input().split())
listaAdj[x - 1].append(y - 1)
listaAdj[y - 1].append(x - 1)
if t == 2:
broken.add(x)
broken.add(y)
stack = [(index, [0], 0) for index in listaAd... | Title: Valera and Elections
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The city Valera lives in is going to hold elections to the city Parliament.
The city has *n* districts and *n*<=-<=1 bidirectional roads. We know that from any district there is a path along the roads to any other... | ```python
n = int(input())
listaAdj = [[] for i in range(n)]
broken = set()
for i in range(n - 1):
x, y, t = map(int, input().split())
listaAdj[x - 1].append(y - 1)
listaAdj[y - 1].append(x - 1)
if t == 2:
broken.add(x)
broken.add(y)
stack = [(index, [0], 0) for index ... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
6 | C | Alice, Bob and Chocolate | PROGRAMMING | 1,200 | [
"greedy",
"two pointers"
] | C. Alice, Bob and Chocolate | 2 | 64 | Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. For each chocololate bar the time, needed for the player to consume it, is known (Alice and Bob eat them wi... | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the amount of bars on the table. The second line contains a sequence *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000), where *t**i* is the time (in seconds) needed to consume the *i*-th bar (in the order from left to right). | Print two numbers *a* and *b*, where *a* is the amount of bars consumed by Alice, and *b* is the amount of bars consumed by Bob. | [
"5\n2 9 8 2 7\n"
] | [
"2 3\n"
] | none | 0 | [
{
"input": "5\n2 9 8 2 7",
"output": "2 3"
},
{
"input": "1\n1",
"output": "1 0"
},
{
"input": "2\n1 1",
"output": "1 1"
},
{
"input": "3\n1 1 1",
"output": "2 1"
},
{
"input": "4\n1 1 1 1",
"output": "2 2"
},
{
"input": "1\n6",
"output": "1 0"
}... | 1,614,786,943 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 307,200 | #
import sys
n = int(sys.stdin.readline())
choc_ls = [int(i.strip()) for i in sys.stdin.readline().rstrip().split()]
sum_choc = sum(choc_ls)
a_choc_t = a = b_choc_t = b = 0
for i in choc_ls:
a_choc_t += i
a += 1
if a_choc_t > 1 / 2 * sum_choc:
a_choc_t -= i
a -= 1
break
elif a_c... | Title: Alice, Bob and Chocolate
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Alice and Bob like games. And now they are ready to start a new game. They have placed *n* chocolate bars in a line. Alice starts to eat chocolate bars one by one from left to right, and Bob — from right to left. Fo... | ```python
#
import sys
n = int(sys.stdin.readline())
choc_ls = [int(i.strip()) for i in sys.stdin.readline().rstrip().split()]
sum_choc = sum(choc_ls)
a_choc_t = a = b_choc_t = b = 0
for i in choc_ls:
a_choc_t += i
a += 1
if a_choc_t > 1 / 2 * sum_choc:
a_choc_t -= i
a -= 1
break
... | 0 | MatrixStudio/Codeforces-Python-Submissions |
468 | A | 24 Game | PROGRAMMING | 1,500 | [
"constructive algorithms",
"greedy",
"math"
] | null | null | Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of *n* integers: 1,<=2,<=...,<=*n*. In a single step, you can pick two of them, let's denote them *a* and *b*, erase them from the sequence, and append to the sequence eit... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105). | If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following *n*<=-<=1 lines print the required operations an operation per line. Each operation should be in form: "*a* *op* *b* = *c*". Where *a* and *b* are the numbe... | [
"1\n",
"8\n"
] | [
"NO\n",
"YES\n8 * 7 = 56\n6 * 5 = 30\n3 - 4 = -1\n1 - 2 = -1\n30 - -1 = 31\n56 - 31 = 25\n25 + -1 = 24\n"
] | none | 500 | [
{
"input": "1",
"output": "NO"
},
{
"input": "8",
"output": "YES\n8 * 7 = 56\n6 * 5 = 30\n3 - 4 = -1\n1 - 2 = -1\n30 - -1 = 31\n56 - 31 = 25\n25 + -1 = 24"
},
{
"input": "12",
"output": "YES\n3 * 4 = 12\n2 * 1 = 2\n12 * 2 = 24\n6 - 5 = 1\n24 * 1 = 24\n8 - 7 = 1\n24 * 1 = 24\n10 - 9 =... | 1,440,349,090 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 389 | 102,400 | n = int(input())
if (n < 4): print("NO")
if (n == 4):
print("YES")
print("4 * 3 = 12")
print("12 * 2 = 24")
print("24 * 1 = 24")
if (n == 5):
print("YES")
print("5 * 4 = 20")
print("2 - 1 = 1")
print("1 + 3 = 4")
print("20 + 4 = 24")
if (n > 5):
print("YES")
print("{} - {} = 1".format(n, n - 1))
print("... | Title: 24 Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of *n* integers: 1,<=2,<=...,<=*n*. In a single step, you can pick two of them... | ```python
n = int(input())
if (n < 4): print("NO")
if (n == 4):
print("YES")
print("4 * 3 = 12")
print("12 * 2 = 24")
print("24 * 1 = 24")
if (n == 5):
print("YES")
print("5 * 4 = 20")
print("2 - 1 = 1")
print("1 + 3 = 4")
print("20 + 4 = 24")
if (n > 5):
print("YES")
print("{} - {} = 1".format(n, n - 1)... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
260 | A | Adding Digits | PROGRAMMING | 1,400 | [
"implementation",
"math"
] | null | null | Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one digit to the number (in the decimal notation) to the right provided that the resulting number is di... | The first line contains three integers: *a*,<=*b*,<=*n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=105). | In a single line print the integer without leading zeros, which Vasya can get when he applies the lengthening operations to number *a* *n* times. If no such number exists, then print number -1. If there are multiple possible answers, print any of them. | [
"5 4 5\n",
"12 11 1\n",
"260 150 10\n"
] | [
"524848\n",
"121\n",
"-1\n"
] | none | 500 | [
{
"input": "5 4 5",
"output": "524848"
},
{
"input": "12 11 1",
"output": "121"
},
{
"input": "260 150 10",
"output": "-1"
},
{
"input": "78843 5684 42717",
"output": "-1"
},
{
"input": "93248 91435 1133",
"output": "-1"
},
{
"input": "100000 10 64479"... | 1,534,688,639 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 2,000 | 3,072,000 | a,b,n=map(int,input().split())
def fn(a,b,n):
a=str(a)
l=len(a)
for i in range(n):
for j in range(10):
if int(a+str(j))%b==0:
a+=str(j)
break
if len(a)!=i+1+l:return -1
return int(a)
print(fn(a,b,n))
| Title: Adding Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has got two number: *a* and *b*. However, Vasya finds number *a* too short. So he decided to repeat the operation of lengthening number *a* *n* times.
One operation of lengthening a number means adding exactly one ... | ```python
a,b,n=map(int,input().split())
def fn(a,b,n):
a=str(a)
l=len(a)
for i in range(n):
for j in range(10):
if int(a+str(j))%b==0:
a+=str(j)
break
if len(a)!=i+1+l:return -1
return int(a)
print(fn(a,b,n))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
650 | A | Watchmen | PROGRAMMING | 1,400 | [
"data structures",
"geometry",
"math"
] | null | null | Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manha... | The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide. | Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel. | [
"3\n1 1\n7 5\n1 5\n",
"6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n"
] | [
"2\n",
"11\n"
] | In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs... | 500 | [
{
"input": "3\n1 1\n7 5\n1 5",
"output": "2"
},
{
"input": "6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1",
"output": "11"
},
{
"input": "10\n46 -55\n46 45\n46 45\n83 -55\n46 45\n83 -55\n46 45\n83 45\n83 45\n46 -55",
"output": "33"
},
{
"input": "1\n-5 -90",
"output": "0"
},
{
... | 1,649,299,781 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | from collections import Counter
n = int(input())
x_all = []
y_all = []
x_and_y = []
for i in range(n):
x, y = map(int, input().split())
x_all.append(x)
y_all.append(y)
x_and_y.append((x, y))
all_counter = Counter(x_and_y)
x_counter = Counter(x_all)
y_counter = Counter(y_all)
answer_... | Title: Watchmen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They n... | ```python
from collections import Counter
n = int(input())
x_all = []
y_all = []
x_and_y = []
for i in range(n):
x, y = map(int, input().split())
x_all.append(x)
y_all.append(y)
x_and_y.append((x, y))
all_counter = Counter(x_and_y)
x_counter = Counter(x_all)
y_counter = Counter(y_all)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,698,631,978 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 154 | 10,547,200 | n = int(input())
line = list(map(int, input().split()))
#print(line)
sum25 = 0
sum50 = 0
sum100 = 0
flag = 0
def ret(ruble):
return ruble - 25
for i in range(n):
if line[i]==25:
sum25 += 25
elif line[i]==50:
sum50 += 50
if sum25==0:
print("NO")
... | Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the bookin... | ```python
n = int(input())
line = list(map(int, input().split()))
#print(line)
sum25 = 0
sum50 = 0
sum100 = 0
flag = 0
def ret(ruble):
return ruble - 25
for i in range(n):
if line[i]==25:
sum25 += 25
elif line[i]==50:
sum50 += 50
if sum25==0:
print("NO"... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
515 | C | Drazil and Factorial | PROGRAMMING | 1,400 | [
"greedy",
"math",
"sortings"
] | null | null | Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they shoul... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=15) — the number of digits in *a*.
The second line contains *n* digits of *a*. There is at least one digit in *a* that is larger than 1. Number *a* may possibly contain leading zeroes. | Output a maximum possible integer satisfying the conditions above. There should be no zeroes and ones in this number decimal representation. | [
"4\n1234\n",
"3\n555\n"
] | [
"33222\n",
"555\n"
] | In the first case, <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/f5a4207f23215fddce977ab5ea9e9d2e7578fb52.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4\n1234",
"output": "33222"
},
{
"input": "3\n555",
"output": "555"
},
{
"input": "15\n012345781234578",
"output": "7777553333222222222222"
},
{
"input": "1\n8",
"output": "7222"
},
{
"input": "10\n1413472614",
"output": "75333332222222"
},
{
... | 1,696,410,776 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | n = int(input())
x = list(map(int, input()))
ans = []
for i in x:
if i == 1:
continue
if i == 4:
ans.append(2)
ans.append(2)
ans.append(3)
elif i == 6:
ans.append(5)
ans.append(3)
else:
ans.append(i)
ans.sort(reverse=True)
print(*an... | Title: Drazil and Factorial
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Drazil is playing a math game with Varda.
Let's define for positive integer *x* as a product of factorials of its digits. For example, .
First, they choose a decimal number *a* consisting of *n* digits that cont... | ```python
n = int(input())
x = list(map(int, input()))
ans = []
for i in x:
if i == 1:
continue
if i == 4:
ans.append(2)
ans.append(2)
ans.append(3)
elif i == 6:
ans.append(5)
ans.append(3)
else:
ans.append(i)
ans.sort(reverse=True)
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
25 | B | Phone numbers | PROGRAMMING | 1,100 | [
"implementation"
] | B. Phone numbers | 2 | 256 | Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33. Your task is to find for a given phone number any of its divisions into groups of two or three... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of digits in the phone number. The second line contains *n* digits — the phone number to divide into groups. | Output any of divisions of the given phone number into groups of two or three digits. Separate groups by single character -. If the answer is not unique, output any. | [
"6\n549871\n",
"7\n1198733\n"
] | [
"54-98-71",
"11-987-33\n"
] | none | 0 | [
{
"input": "6\n549871",
"output": "54-98-71"
},
{
"input": "7\n1198733",
"output": "119-87-33"
},
{
"input": "2\n74",
"output": "74"
},
{
"input": "2\n33",
"output": "33"
},
{
"input": "3\n074",
"output": "074"
},
{
"input": "3\n081",
"output": "08... | 1,636,034,928 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 92 | 4,505,600 | # https://codeforces.com/contest/25/problem/B
n = int(input())
p = input()
s = ""
if n%2==0:
b = int(n/2)
for i in range(b):
s += p[(2*i):(2*i+2)] + "-"
print(s[:-1])
else:
s += p[0:3] + "-"
p = p[3:]
b = int(len(p)/2)
for i in range(b):
s += p[(2*i):(2*i+2)] + "-" ... | Title: Phone numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Phone number in Berland is a sequence of *n* digits. Often, to make it easier to memorize the number, it is divided into groups of two or three digits. For example, the phone number 1198733 is easier to remember as 11-987-33.... | ```python
# https://codeforces.com/contest/25/problem/B
n = int(input())
p = input()
s = ""
if n%2==0:
b = int(n/2)
for i in range(b):
s += p[(2*i):(2*i+2)] + "-"
print(s[:-1])
else:
s += p[0:3] + "-"
p = p[3:]
b = int(len(p)/2)
for i in range(b):
s += p[(2*i):(2*i+... | 3.968608 | MatrixStudio/Codeforces-Python-Submissions |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, al... | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,681,648,263 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 61 | 0 | n=int(input())
p=[8,4,2,6]
if(n==0):
print(1)
else:
print(p[(n-1)%4]) | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one ques... | ```python
n=int(input())
p=[8,4,2,6]
if(n==0):
print(1)
else:
print(p[(n-1)%4])
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
408 | B | Garland | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Once little Vasya read an article in a magazine on how to make beautiful handmade garland from colored paper. Vasya immediately went to the store and bought *n* colored sheets of paper, the area of each sheet is 1 square meter.
The garland must consist of exactly *m* pieces of colored paper of arbitrary area, each pie... | The first line contains a non-empty sequence of *n* (1<=≤<=*n*<=≤<=1000) small English letters ("a"..."z"). Each letter means that Vasya has a sheet of paper of the corresponding color.
The second line contains a non-empty sequence of *m* (1<=≤<=*m*<=≤<=1000) small English letters that correspond to the colors of the ... | Print an integer that is the maximum possible total area of the pieces of paper in the garland Vasya wants to get or -1, if it is impossible to make the garland from the sheets he's got. It is guaranteed that the answer is always an integer. | [
"aaabbac\naabbccac\n",
"a\nz\n"
] | [
"6\n",
"-1"
] | In the first test sample Vasya can make an garland of area 6: he can use both sheets of color *b*, three (but not four) sheets of color *a* and cut a single sheet of color *c* in three, for example, equal pieces. Vasya can use the resulting pieces to make a garland of area 6.
In the second test sample Vasya cannot mak... | 1,000 | [
{
"input": "aaabbac\naabbccac",
"output": "6"
},
{
"input": "a\nz",
"output": "-1"
},
{
"input": "r\nr",
"output": "1"
},
{
"input": "stnsdn\nndnndsn",
"output": "4"
},
{
"input": "yqfqfp\ntttwtqq",
"output": "-1"
},
{
"input": "zzbbrrtrtzr\ntbbtrrrzr"... | 1,613,403,062 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 77 | 409,600 | from collections import Counter
if __name__ == '__main__':
cin = input
s = Counter(cin())
t = Counter(cin())
cnt = 0
for i in t:
cnt += min(s[i], t[i])
print([cnt, -1][not cnt]) | Title: Garland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once little Vasya read an article in a magazine on how to make beautiful handmade garland from colored paper. Vasya immediately went to the store and bought *n* colored sheets of paper, the area of each sheet is 1 square meter.... | ```python
from collections import Counter
if __name__ == '__main__':
cin = input
s = Counter(cin())
t = Counter(cin())
cnt = 0
for i in t:
cnt += min(s[i], t[i])
print([cnt, -1][not cnt])
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
849 | A | Odds and Ends | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd number of non-empty subsegments, the each of which has an odd length and begins and ends with odd numb... | The first line of input contains a non-negative integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence.
The second line contains *n* space-separated non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=100) — the elements of the sequence. | Output "Yes" if it's possible to fulfill the requirements, and "No" otherwise.
You can output each letter in any case (upper or lower). | [
"3\n1 3 5\n",
"5\n1 0 1 5 1\n",
"3\n4 3 1\n",
"4\n3 9 9 3\n"
] | [
"Yes\n",
"Yes\n",
"No\n",
"No\n"
] | In the first example, divide the sequence into 1 subsegment: {1, 3, 5} and the requirements will be met.
In the second example, divide the sequence into 3 subsegments: {1, 0, 1}, {5}, {1}.
In the third example, one of the subsegments must start with 4 which is an even number, thus the requirements cannot be met.
In ... | 500 | [
{
"input": "3\n1 3 5",
"output": "Yes"
},
{
"input": "5\n1 0 1 5 1",
"output": "Yes"
},
{
"input": "3\n4 3 1",
"output": "No"
},
{
"input": "4\n3 9 9 3",
"output": "No"
},
{
"input": "1\n1",
"output": "Yes"
},
{
"input": "5\n100 99 100 99 99",
"out... | 1,526,885,480 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 77 | 0 | n=int(input())
print("Yes") if all([x<=n for x in list(map(int,input().split()))]) else print('No')
| Title: Odds and Ends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Where do odds begin, and where do they end? Where does hope emerge, and will they ever break?
Given an integer sequence *a*1,<=*a*2,<=...,<=*a**n* of length *n*. Decide whether it is possible to divide it into an odd num... | ```python
n=int(input())
print("Yes") if all([x<=n for x in list(map(int,input().split()))]) else print('No')
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
10 | A | Power Consumption Calculation | PROGRAMMING | 900 | [
"implementation"
] | A. Power Consumption Calculation | 1 | 256 | Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T... | The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<... | Output the answer to the problem. | [
"1 3 2 1 5 10\n0 10\n",
"2 8 4 2 5 10\n20 30\n50 100\n"
] | [
"30",
"570"
] | none | 0 | [
{
"input": "1 3 2 1 5 10\n0 10",
"output": "30"
},
{
"input": "2 8 4 2 5 10\n20 30\n50 100",
"output": "570"
},
{
"input": "3 15 9 95 39 19\n873 989\n1003 1137\n1172 1436",
"output": "8445"
},
{
"input": "4 73 2 53 58 16\n51 52\n209 242\n281 407\n904 945",
"output": "5287... | 1,648,060,311 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n, p1, p2, p3, t1, t2 = [int(item) for item in input().split(' ')]
l1, r1 = [int(item) for item in input().split(' ')]
ans = (r1-l1)*p1
for i in range(n-1):
l2, r2 = [int(item) for item in input().split(' ')]
ans += (r2 - l2)*p1
gap = l2 - r1
if gap > t1:
ans += t1 * p1
gap = ga... | Title: Power Consumption Calculation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard f... | ```python
n, p1, p2, p3, t1, t2 = [int(item) for item in input().split(' ')]
l1, r1 = [int(item) for item in input().split(' ')]
ans = (r1-l1)*p1
for i in range(n-1):
l2, r2 = [int(item) for item in input().split(' ')]
ans += (r2 - l2)*p1
gap = l2 - r1
if gap > t1:
ans += t1 * p1
... | 3.954 | MatrixStudio/Codeforces-Python-Submissions |
279 | B | Books | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation",
"two pointers"
] | null | null | When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need to read it. Let's number the books by integers from 1 to *n*. Valera needs *a**i* minutes to... | The first line contains two integers *n* and *t* (1<=≤<=*n*<=≤<=105; 1<=≤<=*t*<=≤<=109) — the number of books and the number of free minutes Valera's got. The second line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104), where number *a**i* shows the number of minutes that the boy n... | Print a single integer — the maximum number of books Valera can read. | [
"4 5\n3 1 2 1\n",
"3 3\n2 2 3\n"
] | [
"3\n",
"1\n"
] | none | 1,000 | [
{
"input": "4 5\n3 1 2 1",
"output": "3"
},
{
"input": "3 3\n2 2 3",
"output": "1"
},
{
"input": "1 3\n5",
"output": "0"
},
{
"input": "1 10\n4",
"output": "1"
},
{
"input": "2 10\n6 4",
"output": "2"
},
{
"input": "6 10\n2 3 4 2 1 1",
"output": "4... | 1,689,873,788 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 12,697,600 | n, t = map(int, input().split())
a = list(map(int, input().split()))
mp, p = 0, 0
while a and p < len(a):
if a[p] <= t:
t -= a[p]
p += 1
mp = max(mp, p)
else:
if p > 0:
t += a[0]
p -= 1
a = a[1:]
else:
a = a[1:... | Title: Books
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When Valera has got some free time, he goes to the library to read some books. Today he's got *t* free minutes to read. That's why Valera took *n* books in the library and for each book he estimated the time he is going to need t... | ```python
n, t = map(int, input().split())
a = list(map(int, input().split()))
mp, p = 0, 0
while a and p < len(a):
if a[p] <= t:
t -= a[p]
p += 1
mp = max(mp, p)
else:
if p > 0:
t += a[0]
p -= 1
a = a[1:]
else:
... | 0 | MatrixStudio/Codeforces-Python-Submissions | |
794 | B | Cutting Carrot | PROGRAMMING | 1,200 | [
"geometry",
"math"
] | null | null | Igor the analyst has adopted *n* little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cut the carrot into *n* pieces of equal area.
Formally, the carrot can be viewed as an isosceles tri... | The first and only line of input contains two space-separated integers, *n* and *h* (2<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=105). | The output should contain *n*<=-<=1 real numbers *x*1,<=*x*2,<=...,<=*x**n*<=-<=1. The number *x**i* denotes that the *i*-th cut must be made *x**i* units away from the apex of the carrot. In addition, 0<=<<=*x*1<=<<=*x*2<=<<=...<=<<=*x**n*<=-<=1<=<<=*h* must hold.
Your output will be considered correc... | [
"3 2\n",
"2 100000\n"
] | [
"1.154700538379 1.632993161855\n",
"70710.678118654752\n"
] | Definition of isosceles triangle: [https://en.wikipedia.org/wiki/Isosceles_triangle](https://en.wikipedia.org/wiki/Isosceles_triangle). | 1,000 | [
{
"input": "3 2",
"output": "1.154700538379 1.632993161855"
},
{
"input": "2 100000",
"output": "70710.678118654752"
},
{
"input": "1000 100000",
"output": "3162.277660168379 4472.135954999579 5477.225575051661 6324.555320336759 7071.067811865475 7745.966692414834 8366.600265340755 8... | 1,494,671,907 | 3,807 | Python 3 | OK | TESTS | 31 | 62 | 102,400 | n,h=map(int,input().split())
ss=h/2
H=[0]*n
for i in range(n):
x=ss/n
k=(x*(i+1)/ss)**(1/2)
H[i]=x*(i+1)/k*2
for i in range(n-1):
print(H[i],end=" ") | Title: Cutting Carrot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Igor the analyst has adopted *n* little bunnies. As we all know, bunnies love carrots. Thus, Igor has bought a carrot to be shared between his bunnies. Igor wants to treat all the bunnies equally, and thus he wants to cu... | ```python
n,h=map(int,input().split())
ss=h/2
H=[0]*n
for i in range(n):
x=ss/n
k=(x*(i+1)/ss)**(1/2)
H[i]=x*(i+1)/k*2
for i in range(n-1):
print(H[i],end=" ")
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At th... | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,627,465,193 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 6,963,200 | slovo = input()
a = len(slovo)
up = 0
down = 0
for i in range(a):
if slovo[i].isupper():
up += 1
elif slovo[i].islower():
down += 1
if down < up:
slovo = slovo.upper()
elif up < down:
slovo = slovo.lower()
elif up == down:
slovo = slovo.lower()
print(slovo) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it ei... | ```python
slovo = input()
a = len(slovo)
up = 0
down = 0
for i in range(a):
if slovo[i].isupper():
up += 1
elif slovo[i].islower():
down += 1
if down < up:
slovo = slovo.upper()
elif up < down:
slovo = slovo.lower()
elif up == down:
slovo = slovo.lower()
print(slovo)
`... | 3.95603 | MatrixStudio/Codeforces-Python-Submissions |
467 | B | Fedor and New Game | PROGRAMMING | 1,100 | [
"bitmasks",
"brute force",
"constructive algorithms",
"implementation"
] | null | null | After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».
The game has (*m*<=+<=1) players and *n* types of soldiers in total. Players «Call of Soldiers 3» are numbered form 1 to (*m*<=+<=1). Types of soldiers are numbered from 0 to *n... | The first line contains three integers *n*, *m*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=20; 1<=≤<=*m*<=≤<=1000).
The *i*-th of the next (*m*<=+<=1) lines contains a single integer *x**i* (1<=≤<=*x**i*<=≤<=2*n*<=-<=1), that describes the *i*-th player's army. We remind you that Fedor is the (*m*<=+<=1)-th player. | Print a single integer — the number of Fedor's potential friends. | [
"7 3 1\n8\n5\n111\n17\n",
"3 3 3\n1\n2\n3\n4\n"
] | [
"0\n",
"3\n"
] | none | 1,000 | [
{
"input": "7 3 1\n8\n5\n111\n17",
"output": "0"
},
{
"input": "3 3 3\n1\n2\n3\n4",
"output": "3"
},
{
"input": "4 2 2\n5\n6\n7",
"output": "2"
},
{
"input": "4 7 4\n9\n10\n5\n12\n4\n12\n7\n10",
"output": "7"
},
{
"input": "2 7 2\n1\n1\n1\n1\n1\n1\n1\n1",
"out... | 1,695,717,141 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n, m, k = map(int, input().split())
l = []
for _ in range(m+1):
x = int(input())
l.append(x)
q = l.pop()
w = 0
for i in set(l):
if abs(q - i) <= k:
w += 1
print(w) | Title: Fedor and New Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After you had helped George and Alex to move in the dorm, they went to help their friend Fedor play a new computer game «Call of Soldiers 3».
The game has (*m*<=+<=1) players and *n* types of soldiers in total. Play... | ```python
n, m, k = map(int, input().split())
l = []
for _ in range(m+1):
x = int(input())
l.append(x)
q = l.pop()
w = 0
for i in set(l):
if abs(q - i) <= k:
w += 1
print(w)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
876 | A | Trip For Meal | PROGRAMMING | 900 | [
"math"
] | null | null | Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair of houses. The length of a path between Rabbit's and Owl's houses is *a* meters, between Rabbit's ... | First line contains an integer *n* (1<=≤<=*n*<=≤<=100) — number of visits.
Second line contains an integer *a* (1<=≤<=*a*<=≤<=100) — distance between Rabbit's and Owl's houses.
Third line contains an integer *b* (1<=≤<=*b*<=≤<=100) — distance between Rabbit's and Eeyore's houses.
Fourth line contains an integer *c* ... | Output one number — minimum distance in meters Winnie must go through to have a meal *n* times. | [
"3\n2\n3\n1\n",
"1\n2\n3\n5\n"
] | [
"3\n",
"0\n"
] | In the first test case the optimal path for Winnie is the following: first have a meal in Rabbit's house, then in Owl's house, then in Eeyore's house. Thus he will pass the distance 2 + 1 = 3.
In the second test case Winnie has a meal in Rabbit's house and that is for him. So he doesn't have to walk anywhere at all. | 500 | [
{
"input": "3\n2\n3\n1",
"output": "3"
},
{
"input": "1\n2\n3\n5",
"output": "0"
},
{
"input": "10\n1\n8\n3",
"output": "9"
},
{
"input": "7\n10\n5\n6",
"output": "30"
},
{
"input": "9\n9\n7\n5",
"output": "42"
},
{
"input": "9\n37\n85\n76",
"outpu... | 1,508,152,654 | 754 | Python 3 | OK | TESTS | 48 | 61 | 5,529,600 | if __name__ == "__main__":
N = int(input())
A = int(input())
B = int(input())
C = int(input())
cnt = 0
result = 1145141919
res1 = A * (N - 1)
res2 = B * (N - 1)
if (N >= 2):
res3 = min(A, B) + C * (N - 2)
result = min(result, res3)
result = min(result,... | Title: Trip For Meal
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Winnie-the-Pooh likes honey very much! That is why he decided to visit his friends. Winnie has got three best friends: Rabbit, Owl and Eeyore, each of them lives in his own house. There are winding paths between each pair... | ```python
if __name__ == "__main__":
N = int(input())
A = int(input())
B = int(input())
C = int(input())
cnt = 0
result = 1145141919
res1 = A * (N - 1)
res2 = B * (N - 1)
if (N >= 2):
res3 = min(A, B) + C * (N - 2)
result = min(result, res3)
result = m... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
690 | F1 | Tree of Life (easy) | PROGRAMMING | 1,300 | [] | null | null | Heidi has finally found the mythical Tree of Life – a legendary combinatorial structure which is said to contain a prophecy crucially needed to defeat the undead armies.
On the surface, the Tree of Life is just a regular undirected tree well-known from computer science. This means that it is a collection of *n* points... | The first line of the input contains a single integer *n* – the number of vertices in the tree (1<=≤<=*n*<=≤<=10000). The vertices are labeled with the numbers from 1 to *n*. Then *n*<=-<=1 lines follow, each describing one edge using two space-separated numbers *a* *b* – the labels of the vertices connected by the edg... | Print one integer – the number of lifelines in the tree. | [
"4\n1 2\n1 3\n1 4\n",
"5\n1 2\n2 3\n3 4\n3 5\n"
] | [
"3",
"4"
] | In the second sample, there are four lifelines: paths between vertices 1 and 3, 2 and 4, 2 and 5, and 4 and 5. | 0 | [
{
"input": "4\n1 2\n1 3\n1 4",
"output": "3"
},
{
"input": "5\n1 2\n2 3\n3 4\n3 5",
"output": "4"
},
{
"input": "2\n1 2",
"output": "0"
},
{
"input": "3\n2 1\n3 2",
"output": "1"
},
{
"input": "10\n5 1\n1 2\n9 3\n10 5\n6 3\n8 5\n2 7\n2 3\n9 4",
"output": "11"
... | 1,468,512,116 | 2,147,483,647 | Python 3 | OK | TESTS | 19 | 109 | 1,843,200 | n=int(input())
p=[[]]
t=[0]
o=[[]]
for i in range(n):
p.append([])
t.append(0)
o.append([])
for i in range(n-1):
a=input().split()
b=int (a[0])
c=int(a[1])
p[b].append(c)
p[c].append(b)
t[b]+=1
t[c]+=1
y=0
for i in range(1,n+1):
j=p[i]
for k in range(t[... | Title: Tree of Life (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Heidi has finally found the mythical Tree of Life – a legendary combinatorial structure which is said to contain a prophecy crucially needed to defeat the undead armies.
On the surface, the Tree of Life is just a r... | ```python
n=int(input())
p=[[]]
t=[0]
o=[[]]
for i in range(n):
p.append([])
t.append(0)
o.append([])
for i in range(n-1):
a=input().split()
b=int (a[0])
c=int(a[1])
p[b].append(c)
p[c].append(b)
t[b]+=1
t[c]+=1
y=0
for i in range(1,n+1):
j=p[i]
for k i... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
946 | C | String Transformation | PROGRAMMING | 1,300 | [
"greedy",
"strings"
] | null | null | You are given a string *s* consisting of |*s*| small english letters.
In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be replaced with t, etc.). You cannot replace letter z with any other letter.
Your target is to make some number... | The only one line of the input consisting of the string *s* consisting of |*s*| (1<=≤<=|*s*|<=≤<=105) small english letters. | If you can get a string that can be obtained from the given string and will contain english alphabet as a subsequence, print it. Otherwise print «-1» (without quotes). | [
"aacceeggiikkmmooqqssuuwwyy\n",
"thereisnoanswer\n"
] | [
"abcdefghijklmnopqrstuvwxyz\n",
"-1\n"
] | none | 0 | [
{
"input": "aacceeggiikkmmooqqssuuwwyy",
"output": "abcdefghijklmnopqrstuvwxyz"
},
{
"input": "thereisnoanswer",
"output": "-1"
},
{
"input": "jqcfvsaveaixhioaaeephbmsmfcgdyawscpyioybkgxlcrhaxs",
"output": "-1"
},
{
"input": "rtdacjpsjjmjdhcoprjhaenlwuvpfqzurnrswngmpnkdnunaen... | 1,530,693,892 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 108 | 0 | x = input()
y = ''
for i in x:
if y == '':
if i == 'a' or i == 'z':
y += 'a'
elif len(y) < 26:
if i == y[-1] or i == chr(ord(y[-1])+1):
y += chr(ord(y[-1])+1)
else:
break
print(y if len(y) == 26 else -1)
| Title: String Transformation
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string *s* consisting of |*s*| small english letters.
In one move you can replace any character of this string to the next character in alphabetical order (a will be replaced with b, s will be rep... | ```python
x = input()
y = ''
for i in x:
if y == '':
if i == 'a' or i == 'z':
y += 'a'
elif len(y) < 26:
if i == y[-1] or i == chr(ord(y[-1])+1):
y += chr(ord(y[-1])+1)
else:
break
print(y if len(y) == 26 else -1)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
760 | B | Frodo and pillows | PROGRAMMING | 1,500 | [
"binary search",
"greedy"
] | null | null | *n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as many pillows as possible. Of course, it's not always possible to share pillows equally, but any hobbit ge... | The only line contain three integers *n*, *m* and *k* (1<=≤<=*n*<=≤<=*m*<=≤<=109, 1<=≤<=*k*<=≤<=*n*) — the number of hobbits, the number of pillows and the number of Frodo's bed. | Print single integer — the maximum number of pillows Frodo can have so that no one is hurt. | [
"4 6 2\n",
"3 10 3\n",
"3 6 1\n"
] | [
"2\n",
"4\n",
"3\n"
] | In the first example Frodo can have at most two pillows. In this case, he can give two pillows to the hobbit on the first bed, and one pillow to each of the hobbits on the third and the fourth beds.
In the second example Frodo can take at most four pillows, giving three pillows to each of the others.
In the third exa... | 1,000 | [
{
"input": "4 6 2",
"output": "2"
},
{
"input": "3 10 3",
"output": "4"
},
{
"input": "3 6 1",
"output": "3"
},
{
"input": "3 3 3",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "1 1000000000 1",
"output": "1000000000"
},
{
... | 1,485,113,490 | 4,590 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 46 | 4,608,000 | n, m , k = map(int, input().split())
rem = m % n
per = m // n
if k == 1 or k == n:
print(per+(n//per))
else:
print(per+(rem//2)) | Title: Frodo and pillows
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* hobbits are planning to spend the night at Frodo's house. Frodo has *n* beds standing in a row and *m* pillows (*n*<=≤<=*m*). Each hobbit needs a bed and at least one pillow to sleep, however, everyone wants as ma... | ```python
n, m , k = map(int, input().split())
rem = m % n
per = m // n
if k == 1 or k == n:
print(per+(n//per))
else:
print(per+(rem//2))
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
121 | E | Lucky Array | PROGRAMMING | 2,400 | [
"data structures"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya has an array consisting of *n* numbers. He wants to perform *m* operations of two types:
- ... | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of numbers in the array and the number of operations correspondingly. The second line contains *n* positive integers, none of which exceeds 104 — those are the array numbers. Next *m* lines contain operations, one per line. They cor... | For each operation of the second type print the single number on the single line — the number of lucky numbers in the corresponding interval. | [
"3 6\n2 3 4\ncount 1 3\ncount 1 2\nadd 1 3 2\ncount 1 3\nadd 2 3 3\ncount 1 3\n",
"4 5\n4 4 4 4\ncount 1 4\nadd 1 4 3\ncount 1 4\nadd 2 3 40\ncount 1 4\n"
] | [
"1\n0\n1\n1\n",
"4\n4\n4\n"
] | In the first sample after the first addition the array will look in the following manner:
4 5 6
After the second addition:
4 8 9
The second sample after the first addition:
7 7 7 7
After the second addition:
7 47 47 7 | 2,500 | [] | 1,689,946,513 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 4 | 186 | 2,969,600 | import sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
fast_print = lambda p: sys.stdout.write(str(p) + "\n")
from collections import Counter
lucky_nums = [
4, 7, 44, 47, 74, 77, 444, 447, 474, 477, 744, 747, 774, 777,
4444, 4447, 4474, 4477, 4744, 4747, 4774, 4777,
7444, 7447, 7474, 7477, 7744, 7747, ... | Title: Lucky Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Pet... | ```python
import sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
fast_print = lambda p: sys.stdout.write(str(p) + "\n")
from collections import Counter
lucky_nums = [
4, 7, 44, 47, 74, 77, 444, 447, 474, 477, 744, 747, 774, 777,
4444, 4447, 4474, 4477, 4744, 4747, 4774, 4777,
7444, 7447, 7474, 7477, 77... | -1 | MatrixStudio/Codeforces-Python-Submissions | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a pla... | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is ... | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,622,987,876 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 248 | 0 | n = int(input())
tt = -100
uu = ''
name_score = {}
name_takedown = []
max_name = []
for i in range(0, n):
name, score = input().split()
name_takedown.append(name)
if (name not in name_score.keys()):
name_score[name] = int(score)
else:
name_score[name] = name_score[name] + int... | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes... | ```python
n = int(input())
tt = -100
uu = ''
name_score = {}
name_takedown = []
max_name = []
for i in range(0, n):
name, score = input().split()
name_takedown.append(name)
if (name not in name_score.keys()):
name_score[name] = int(score)
else:
name_score[name] = name_score[n... | 0 | MatrixStudio/Codeforces-Python-Submissions |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes acco... | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, an... | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,600,244,090 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 140 | 0 | a,b=int(input()),int(input())
d=min(a,b)+abs(a-b)//2
tiredness=0
for i in range(1,abs(d-a)+1):
tiredness+=i
for i in range(1,abs(d-b)+1):
tiredness+=i
print(tiredness) | Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in... | ```python
a,b=int(input()),int(input())
d=min(a,b)+abs(a-b)//2
tiredness=0
for i in range(1,abs(d-a)+1):
tiredness+=i
for i in range(1,abs(d-b)+1):
tiredness+=i
print(tiredness)
``` | 3 | MatrixStudio/Codeforces-Python-Submissions | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height ... | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required m... | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,696,257,837 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | def wall(n,h,a):
width=0
for i in range(0,n):
if(a[i])>h):
width+=2
else:
width+=1
return width
| Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some pers... | ```python
def wall(n,h,a):
width=0
for i in range(0,n):
if(a[i])>h):
width+=2
else:
width+=1
return width
``` | -1 | MatrixStudio/Codeforces-Python-Submissions | |
675 | A | Infinite Sequence | PROGRAMMING | 1,100 | [
"math"
] | null | null | Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c* (*s**i*<=-<=*s**i*<=-<=1<==<=*c*). In particular, Vasya wonders if his favourite integer *b* appears ... | The first line of the input contain three integers *a*, *b* and *c* (<=-<=109<=≤<=*a*,<=*b*,<=*c*<=≤<=109) — the first element of the sequence, Vasya's favorite number and the difference between any two neighbouring elements of the sequence, respectively. | If *b* appears in the sequence *s* print "YES" (without quotes), otherwise print "NO" (without quotes). | [
"1 7 3\n",
"10 10 0\n",
"1 -4 5\n",
"0 60 50\n"
] | [
"YES\n",
"YES\n",
"NO\n",
"NO\n"
] | In the first sample, the sequence starts from integers 1, 4, 7, so 7 is its element.
In the second sample, the favorite integer of Vasya is equal to the first element of the sequence.
In the third sample all elements of the sequence are greater than Vasya's favorite integer.
In the fourth sample, the sequence starts... | 500 | [
{
"input": "1 7 3",
"output": "YES"
},
{
"input": "10 10 0",
"output": "YES"
},
{
"input": "1 -4 5",
"output": "NO"
},
{
"input": "0 60 50",
"output": "NO"
},
{
"input": "1 -4 -5",
"output": "YES"
},
{
"input": "0 1 0",
"output": "NO"
},
{
... | 1,498,671,022 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 4,608,000 | string = input()
numbers = string.split(" ")
a = int(numbers[0])
b = int(numbers[1])
c = int(numbers[2])
if c == 0:
results = "YES"
if b != a:
results = "NO"
elif b >= a and (b - a) % c == 0:
results = "YES"
else:
results = "NO"
print(results) | Title: Infinite Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya likes everything infinite. Now he is studying the properties of a sequence *s*, such that its first element is equal to *a* (*s*1<==<=*a*), and the difference between any two neighbouring elements is equal to *c... | ```python
string = input()
numbers = string.split(" ")
a = int(numbers[0])
b = int(numbers[1])
c = int(numbers[2])
if c == 0:
results = "YES"
if b != a:
results = "NO"
elif b >= a and (b - a) % c == 0:
results = "YES"
else:
results = "NO"
print(results)
``` | 0 | MatrixStudio/Codeforces-Python-Submissions | |
376 | B | I.O.U. | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Imagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearrange them like that: assume that A owes C 20 rubles and B doesn't owe anything to anybody. The... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 0<=≤<=*m*<=≤<=104). The next *m* lines contain the debts. The *i*-th line contains three integers *a**i*,<=*b**i*,<=*c**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*; *a**i*<=≠<=*b**i*; 1<=≤<=*c**i*<=≤<=100), which mean that person *a**i* owes person *b**i* *c**i... | Print a single integer — the minimum sum of debts in the optimal rearrangement. | [
"5 3\n1 2 10\n2 3 1\n2 4 1\n",
"3 0\n",
"4 3\n1 2 1\n2 3 1\n3 1 1\n"
] | [
"10\n",
"0\n",
"0\n"
] | In the first sample, you can assume that person number 1 owes 8 rubles to person number 2, 1 ruble to person number 3 and 1 ruble to person number 4. He doesn't owe anybody else anything. In the end, the total debt equals 10.
In the second sample, there are no debts.
In the third sample, you can annul all the debts. | 1,000 | [
{
"input": "5 3\n1 2 10\n2 3 1\n2 4 1",
"output": "10"
},
{
"input": "3 0",
"output": "0"
},
{
"input": "4 3\n1 2 1\n2 3 1\n3 1 1",
"output": "0"
},
{
"input": "20 28\n1 5 6\n1 12 7\n1 13 4\n1 15 7\n1 20 3\n2 4 1\n2 15 6\n3 5 3\n3 8 10\n3 13 8\n3 20 6\n4 6 10\n4 12 8\n4 19 5\... | 1,685,962,465 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 124 | 0 | import sys
input = sys.stdin.readline
# import bisect #-->For bisect.bisect_left=lower_bound and bisect_right=upper_bound
n, m =map(int, input().split())
l = [[0 for j in range(n+1)] for i in range(n+1)]
for i in range(m):
a,b,c = map(int, input().split())
l[a][b] = c
ans = 0
for i in range(1,n+1):
... | Title: I.O.U.
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that there is a group of three friends: A, B and С. A owes B 20 rubles and B owes C 20 rubles. The total sum of the debts is 40 rubles. You can see that the debts are not organized in a very optimal manner. Let's rearran... | ```python
import sys
input = sys.stdin.readline
# import bisect #-->For bisect.bisect_left=lower_bound and bisect_right=upper_bound
n, m =map(int, input().split())
l = [[0 for j in range(n+1)] for i in range(n+1)]
for i in range(m):
a,b,c = map(int, input().split())
l[a][b] = c
ans = 0
for i in range... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
837 | E | Vasya's Function | PROGRAMMING | 2,100 | [
"binary search",
"implementation",
"math"
] | null | null | Vasya is studying number theory. He has denoted a function *f*(*a*,<=*b*) such that:
- *f*(*a*,<=0)<==<=0; - *f*(*a*,<=*b*)<==<=1<=+<=*f*(*a*,<=*b*<=-<=*gcd*(*a*,<=*b*)), where *gcd*(*a*,<=*b*) is the greatest common divisor of *a* and *b*.
Vasya has two numbers *x* and *y*, and he wants to calculate *f*(*x*,<=*y*)... | The first line contains two integer numbers *x* and *y* (1<=≤<=*x*,<=*y*<=≤<=1012). | Print *f*(*x*,<=*y*). | [
"3 5\n",
"6 3\n"
] | [
"3\n",
"1\n"
] | none | 0 | [
{
"input": "3 5",
"output": "3"
},
{
"input": "6 3",
"output": "1"
},
{
"input": "1000000009 1000000008",
"output": "1000000008"
},
{
"input": "1000000007 1000000006",
"output": "1000000006"
},
{
"input": "2000000018 2000000017",
"output": "1000000009"
},
... | 1,690,483,122 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 77 | 1,331,200 | import math
def vas(x, y):
if y == 0:
return 0
if x == 1:
return y
maximal = 0
for p in prime:
if x%p == 0:
maximal = max(maximal, (y//p)*p)
return y - maximal + vas(x//math.gcd(x, maximal), maximal//math.gcd(x, maximal))
x, y = map(int,input().spli... | Title: Vasya's Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya is studying number theory. He has denoted a function *f*(*a*,<=*b*) such that:
- *f*(*a*,<=0)<==<=0; - *f*(*a*,<=*b*)<==<=1<=+<=*f*(*a*,<=*b*<=-<=*gcd*(*a*,<=*b*)), where *gcd*(*a*,<=*b*) is the greatest commo... | ```python
import math
def vas(x, y):
if y == 0:
return 0
if x == 1:
return y
maximal = 0
for p in prime:
if x%p == 0:
maximal = max(maximal, (y//p)*p)
return y - maximal + vas(x//math.gcd(x, maximal), maximal//math.gcd(x, maximal))
x, y = map(int,in... | 3 | MatrixStudio/Codeforces-Python-Submissions | |
588 | A | Duff and Meat | PROGRAMMING | 900 | [
"greedy"
] | null | null | Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her from there. In *i*-th day, they sell meat for *p**i* dollars per kilogram. Malek knows all numbers ... | The first line of input contains integer *n* (1<=≤<=*n*<=≤<=105), the number of days.
In the next *n* lines, *i*-th line contains two integers *a**i* and *p**i* (1<=≤<=*a**i*,<=*p**i*<=≤<=100), the amount of meat Duff needs and the cost of meat in that day. | Print the minimum money needed to keep Duff happy for *n* days, in one line. | [
"3\n1 3\n2 2\n3 1\n",
"3\n1 3\n2 1\n3 2\n"
] | [
"10\n",
"8\n"
] | In the first sample case: An optimal way would be to buy 1 kg on the first day, 2 kg on the second day and 3 kg on the third day.
In the second sample case: An optimal way would be to buy 1 kg on the first day and 5 kg (needed meat for the second and third day) on the second day. | 750 | [
{
"input": "3\n1 3\n2 2\n3 1",
"output": "10"
},
{
"input": "3\n1 3\n2 1\n3 2",
"output": "8"
},
{
"input": "1\n39 52",
"output": "2028"
},
{
"input": "2\n25 56\n94 17",
"output": "2998"
},
{
"input": "5\n39 21\n95 89\n73 90\n9 55\n85 32",
"output": "6321"
}... | 1,548,232,624 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 343 | 409,600 | '''s=[];n=int(input());i=1
for _ in [0]*n:
s.append([int(i) for i in input().split()])
b=s[0][1];t=s[0][0]*b
while i<n:
while i<n and s[i][1]>b:
t+=s[i][0]*b;i+=1
if i>=n:break
b=s[i][1];t+=s[i][0]*b;i+=1
print(t)'''
n=int(input())
a=[int(i) for i in input().split()];b=a[1];t=a[... | Title: Duff and Meat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Duff is addicted to meat! Malek wants to keep her happy for *n* days. In order to be happy in *i*-th day, she needs to eat exactly *a**i* kilograms of meat.
There is a big shop uptown and Malek wants to buy meat for her ... | ```python
'''s=[];n=int(input());i=1
for _ in [0]*n:
s.append([int(i) for i in input().split()])
b=s[0][1];t=s[0][0]*b
while i<n:
while i<n and s[i][1]>b:
t+=s[i][0]*b;i+=1
if i>=n:break
b=s[i][1];t+=s[i][0]*b;i+=1
print(t)'''
n=int(input())
a=[int(i) for i in input().split()];b... | 3 | MatrixStudio/Codeforces-Python-Submissions |
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