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Why is it possible to separate NaOH from certain compounds using acetone? |
I have a bunch of conceptual questions about reaction rates. I intuitively get the factors that influence reaction rate - concentration, temperature, reactivity of reactants, etc. But when it comes to the formulas some things don't click, namely the following questions.
First - what is the chemistry behind why react... |
I have a bunch of conceptual questions about reaction rates. I intuitively get the factors that influence reaction rate - concentration, temperature, reactivity of reactants, etc. But when it comes to the formulas some things don't click, namely the following questions.
First - what is the chemistry behind why react... |
How is Gold's atomic structure and bonding related to the separation techniques used to distinguish it from other substances?
I'm just confused on what I'm actually searching for, I have read so many blogs on Gold extraction, refinement, occurences and more topics, and either I'm skipping the important parts or t... |
> A dilute solution of which acid is most likely to produce a reduction
> product other than $H_{2}$ when it reacts with a metal?
> (A) $HF$
> (B) $HCl$
> (C) $HNO_{3} $
> (D) $H_{2}SO_{4}$
> $\tiny{\text{Question from 2012 local chemistry olympiad}}$
The given answer is (C), $HNO_{3} $ but I do... |
Why does $HNO_{3}$ not give off $H_{2}$ when reacting with $Cu$? |
How do I calculate the temperature of hot air in Kelvin? |
The following answers might be vague or overtly simplified or basic, but the questions by nature are fairly open-ended, aren't they? feel free to inquire further if something isn’t clear enough.
1) Take 2NO2 → 2NO + O2. You can (extremely basically) think of this reaction as two NO2 particles colliding, (forming a ... |
> A dilute solution of which acid is most likely to produce a reduction
> product other than $H_{2}$ when it reacts with a metal?
> (A) $\ce{HF}$
> (B) $\ce{HCl}$
> (C) $\ce{HNO3} $
> (D) $\ce{H2SO4}$
> $\tiny{\text{Question from 2012 local chemistry olympiad}}$
The given answer is (C), $\ce{HNO... |
Why does HNO3 not give off H2 when reacting with Cu? |
Ask yourself what kind of reaction happens?
What glassware have you used to remove impurities?
By controlling pH and polarities you are able to separate compounds because of different affinities between them and solvents. You change molecular solvatation of your analyte and impurities. Then by controlling boiling p... |
I need help with this one homework question. I am combining 100 mL of .500 M HCl and .5 M NaOH to make 200 mL of .25 M NaCl. The change in temperature of this reaction was $\Delta 3.38^OC$. I have to calculate the heat of reaction for 1 mole of the reactant. I also need to calculate the $C_{total}$ of this reaction. Ho... |
I mean, how can we reverse the neutralization reaction of HCl and NaOH to get back HCl and NaOH.
I want to extract HCl and NaOH from a mixture of common salt and distilled water in equal proportions at home.
Basically, how to make this reaction happen:
H2O + NaCl => HCl + NaOH
What temperature or pressure c... |
How to separate HCl and NaOH from salt and water solution? |
In the addition of $\ce{NaHSO3}$ to aldehydes and methyl ketones (higher ketones do not respond well to this reaction), crystalline addition products are formed. An $\ce{-SO3H}$ and an $\ce{-OH}$ group are attached to the same carbon.
$$\ce{R2C=O + NaHSO3 -> R2C(OH)(SO3^{-}Na^+) <=> R2C(O^{-}Na^+)(SO3H)}$$
T... |
I mean, how can we reverse the neutralization reaction of HCl and NaOH to get back HCl and NaOH.
I want to extract HCl and NaOH from a mixture of common salt and distilled water in equal proportions at home.
Basically, how to make this reaction happen:
$$\ce{H2O + NaCl -> HCl + NaOH}$$
What temperature or p... |
Unless *time travel* is an option, you could
1. [Electrolyze][1] the $\ce{NaCl}$ solution to obtain a solution of $\ce{NaOH}$, and $\ce{H2}$ and $\ce{Cl2}$ as gases.
2. Collect the gases and photolyze them. The dissociation energy of $\ce{Cl2}$ is $243\, \mathrm{kJ \cdot mol^{-1}}$, irradiation at $\lambda$ < ... |
Unless *time travel* is an option, you could
1. [Electrolyze][1] the $\ce{NaCl}$ solution to obtain a solution of $\ce{NaOH}$, and $\ce{H2}$ and $\ce{Cl2}$ as gases.
2. Collect the gases and photolyze them. The dissociation energy of $\ce{Cl2}$ is $243\, \mathrm{kJ \cdot mol^{-1}}$, irradiation at $\lambda$ < ... |
Will NaH2PO4 react as as an acid or a base if you make it react with water?
I got stuck here. I can figure out the reaction:
<code>NaH2PO4 + H2O -> Na{+} + H2PO4{-} + H2O</code>
But when I look H2PO4 up, it says that it can both be an acid or a base.
Any ideas? |
NaH2PO4 in water : Acid/base? |
Will $\ce{NaH2PO4}$ react as as an acid or a base if you make it react with water?
I got stuck here. I can figure out the reaction:
$\ce{NaH2PO4 + H2O -> Na^{+} + H2PO4^{-} + H2O}$
But when I look $\ce{H2PO4}$ up, it says that it can both be an acid or a base.
Any ideas? |
Will $\ce{NaH2PO4}$ react as as an acid or a base if you make it react with water?
I got stuck here. I can figure out the reaction:
$\ce{NaH2PO4 + H2O -> Na^{+} + H2PO4^{-} + H2O}$
But when I look $\ce{H2PO4^{-}}$ up, it says that it can both be an acid or a base.
Any ideas? |
Unless *time travel* is an option, you could
1. [Electrolyze][1] the $\ce{NaCl}$ solution to obtain a solution of $\ce{NaOH}$, and $\ce{H2}$ and $\ce{Cl2}$ as gases.
2. Collect the gases and photolyze them. The dissociation energy of $\ce{Cl2}$ is $243\, \mathrm{kJ \cdot mol^{-1}}$, irradiation at $\lambda$ < ... |
Will $\ce{NaH2PO4}$ react as as an acid or a base if you make it react with water?
I got stuck here. I can figure out the reaction:
$\ce{NaH2PO4 + H2O -> Na^{+} + H2PO4^{-} + H2O}$
But when I look $\ce{H2PO4^{-}}$ up, it says that it can both be an acid and a base.
Any ideas? |
I'm doing relatively simple Chemistry but i've been given a formula for the velocity of a reaction.
$$v= k.C_A^a$$
and
$$k= A.e^{E_a/RT}$$
As a result, from that formula, surely decreasing the temperature $T$ would increase the velocity of the reaction? As that would increase the value of $k$ and therefore ... |
How to increase the velocity of a reaction? |
First off, please forgive me, I am a chemistry novice!
**Overall Process**
1. Fuel for the system is distilled water
2. Split water into Hydrogen and Oxygen (electrolysis or similar process)
3. Exhaust Oxygen
4. Burn Hydrogen to power a generator/engine
5. Generator/engine charges battery
6. Battery po... |
Could this be a feasible fuel system? |
What is the chemistry behind why reactions of order >1 exist? And what role does the number of activated complexes formed have in determining reaction rate? |
My textbook says that for a chemical reaction with two reactants, $\ce{A}$ and $\ce{B}$ with equation $\ce{aA + bB -> Products}$, where $a$ and $b$ are coefficients, the general rate law is:
$\text{Rate} = k[\ce{A}]^m[\ce{B}]^n$
where $m$ and $n$ are the reaction orders for $\ce{A}$ and $\ce{B}$ respectively. The... |
Why exactly does the slowest reaction limit the instantaneous rate of a reaction even if the faster processes come after? Theoretically, if the products of the slow reaction are required for the fast reaction, the fast reaction limits the rate because even though it is fast, it will not finish in exact synchronization ... |
In the reaction between hydrochloric acid and Magnesium the overall reaction is:
$$\ce{Mg + 2HCl -> MgCl2 + H2}$$
My proposed mechanism of reaction is that $\ce{HCl}$ dissociates in $\ce{H2O}$ like so:
$$\ce{H2O + HCl <=> H3O+ + Cl- }$$
And then the $\ce{H3O+}$ oxidises the magnesium like so:
$$\ce{2H3O+... |
In the reaction between hydrochloric acid and Magnesium the overall reaction is:
$$\ce{Mg + 2HCl -> MgCl2 + H2}$$
My proposed mechanism of reaction is that $\ce{HCl}$ dissociates in $\ce{H2O}$ like so:
$$\ce{H2O + HCl <=> H3O+ + Cl- }$$
And then the $\ce{H3O+}$ oxidises the magnesium like so:
$$\ce{2H3O+... |
In the reaction between hydrochloric acid and Magnesium the overall reaction is:
$$\ce{Mg + 2HCl -> MgCl2 + H2}$$
My proposed mechanism of reaction is that $\ce{HCl}$ dissociates in $\ce{H2O}$ like so:
$$\ce{H2O + HCl <=> H3O+ + Cl- }$$
And then the $\ce{H3O+}$ oxidises the magnesium like so:
$$\ce{2H3O+... |
According to collision theory, for a chemical reaction to occur, the reacting molecules must collide with each other.
For a bimolecular reaction (as given by you), collision occurs in the single step and thus becomes the rate determining step, as there are no other steps involved.
If you consider reactions ... |
Why is the bond between H and F in HF considered polar covalent whereas HCl, HI, and so on are all ionic? The electronegativity difference between them suggests that it too should be ionic, yet all textbooks say that HF is covalent. Is there a good reason why? |
Why is HF considered a covalently bonded compound? |
Cook it up with ethylenediamine or diethylenetriamine- but don't bet on it. What do you plan to have as the counterion for $\ce{K^+}$? Check your carbon oxidation states for the second half of your question.
No, wait! Add citric acid. Yeah, that's the ticket. Plop, plop, fizz, fizz.
|
This is simple question, I think. At college, professor were explaining that Oxygen is always found in molecules of 2 Oxygen atoms combined together - O2. On the other hand, molecule of the water is H2O. So I don't get, how is it that O is single in this molecule, if it's always found coupled?
Intro Chem. student. |
O2 in H2O. How is it single of it's always double? |
Why is the dipole moment of $CH_2Cl_2$ ($1.60 D$) more than that of $CHCl_3$ ($1.08D$)?
I feel it should be the other way round.. |
dipole moment of $CH_2Cl_2$ more than that of $CHCl_3$? |
the question is:
In the following reaction, Kc=4.0
C2H5OH + CH3COOH <=> CH3COOC2H5 + H2O
A reaction is allowed to occur in a mixture of 17.2g C2H5OH, 23.8g CH3COOH, 48.6g CH3COOC2H5, and 71.2g H2O
(a) In what direction will a net change occur?
(b) How many grams of each substance will be present at equilibrium... |
How many grams of each substance will be present at equilibrium? |
This is simple question, I think. At college (I'm an Intro Chem. student), the professor explained that oxygen is always found in molecules of 2 oxygen atoms combined together - $\ce{O2}$. On the other hand, molecule of the water is $\ce{H2O}$. So I don't get, how is it that O is single in this molecule, if it's always... |
Oxygen in water: How is it single if it's always double? |
Why is the dipole moment of $\ce{CH2Cl2}$ ($1.60 ~\mathrm{D}$) greater than that of $\ce{CHCl3}$ ($1.08~\mathrm{D}$)?
I feel it should be the other way round. |
Difference of dipole moments of dichloromethane and trichloromethane? |
Difference of dipole moments of $\ce{CH2Cl2}$ and $\ce{CHCl3}$? |
I am a master student of nuclear physics. Due to some measurements I'd like to make, I have to use Magnesium as a beam target. Searching through the net to see it's properties I found that it can be easily oxidized. In addition I've read that it's highly flammable.
I have in hand two forms of Magnesium:[powder][1] a... |
In the following reaction, $K_\text{c}=4.0$:
$$\ce{C2H5OH + CH3COOH <=> CH3COOC2H5 + H2O}$$
A reaction is allowed to occur in a mixture of $17.2~\mathrm{g}~\ce{C2H5OH}$, $23.8~\mathrm{g}~\ce{CH3COOH}$, $48.6~\mathrm{g}~\ce{CH3COOC2H5}$, and $71.2~\mathrm{g}~\ce{H2O}$
>(a) In what direction will a net change oc... |
Difference of dipole moments of dichloromethane and trichloromethane? |
Why is the dipole moment of $\ce{CH2Cl2}$ ($1.60 ~\mathrm{D}$) greater than that of $\ce{CHCl3}$ ($1.08~\mathrm{D}$)?
Based on my knowledge of vectors,I feel it should be the other way round. |
I am a master student of nuclear physics. Due to some measurements I'd like to make, I have to use Magnesium as a beam target. Searching through the net to see it's properties I found that it can be easily oxidized. In addition I've read that it's highly flammable.
I have in hand two forms of Magnesium:[powder][1] a... |
I am a master student of nuclear physics. Due to some measurements I'd like to make, I have to use Magnesium as a beam target. Searching through the net to see it's properties I found that it can be easily oxidized. In addition I've read that it's highly flammable.
I have in hand two forms of Magnesium:[powder][1] a... |
We know alpha particle is the nucleus of Helium. It contains two subatomic particles - a proton and a neutron. The proton and neutron are further made of particles called up and down quarks. So why call an alpha *particle* a particle. And similarly, why do we say electrons, protons, neutrons etc. are *particles*, even ... |
Why is alpha particle called a particle when it is a pair of two particles? |
I was going through Alkyl and Aryl Halides and noted the following statement in my textbook:
>p-Dichlorobenzene has higher melting point and solubility than those of o-Dichlorobenzene and m-Dichlorobenzene.
I thought over it but could not come to a conclusion. Any ideas **why** the above assertion is true?
Tha... |
p-Dichlorobenzene has higher melting point and solubility than those of o-Dichlorobenzene and m-Dichlorobenzene? |
We know alpha particle is the nucleus of Helium. It contains four subatomic particles - two protons and two neutrons. The protons and neutrons are further made of particles called up and down quarks. So why call an alpha *particle* a particle. And similarly, why do we say electrons, protons, neutrons etc. are *particle... |
I was going through Alkyl and Aryl Halides and noted the following statement in my textbook:
>p-Dichlorobenzene has higher melting point than those of o-Dichlorobenzene and m-Dichlorobenzene.
I thought over it but could not come to a conclusion. Any ideas **why** the above assertion is true?
Thanks. |
We know alpha particle is the nucleus of Helium. It contains four subatomic particles - two protons and two neutrons. The protons and neutrons are further made of particles called up and down quarks. So why call an alpha *particle* a particle. And similarly, why do we say electrons, protons, neutrons etc. are *particle... |
Why is alpha particle called a particle when it is a pair of four particles? |
I was going through alkyl and aryl halides and noted the following statement in my textbook:
>p-Dichlorobenzene has higher melting point than those of o-Dichlorobenzene and m-Dichlorobenzene.
I thought over it but could not come to a conclusion. Any ideas **why** the above assertion is true?
Thanks. |
Why is the melting point of p-Dichlorobenzene higher than those of o-Dichlorobenzene and m-Dichlorobenzene? |
I think this reasoning will suffice (not sure though):
p-Dichlorobenzene is more symmetrical than o-and m-isomers. For this reason, it fits more closely than o-and m-isomers in the crystal lattice. Therefore, more energy is required to break the crystal lattice of p-dichlorobenzene. As a result, p-dichlorobenzene ha... |
I was going through alkyl and aryl halides and noted the following statement in my textbook:
>p-Dichlorobenzene has higher melting point and solubility than those of o-Dichlorobenzene and m-Dichlorobenzene.
I thought over it but could not come to a conclusion. Any ideas **why** the above assertion is true?
Tha... |
I have seen this reaction many times:
>$\text {Phenol}+\text{Zn}\ce {->}\text{Benzene}+\text{ZnO} $
But what is the mechanism?! Tried a lot but couldn't cook up one...
Thanks for any help... |
I know that s8 molecule contains 16 pair of lone electrons. But my teacher always says that we must try to reduce the no of lone pairs, so, had there been double bonds between 8 atoms of sulphur then the no of lone pairs would be reduced. So why aren't there double bonds? |
Why aren't there 8 double bonds in s8? |
I know that s8 molecule contains 16 pair of lone electrons. My teacher always says that we must try to reduce the no of lone pairs, so, had there been double bonds between 8 atoms of sulphur then the no of lone pairs would be reduced. Then why aren't there double bonds? |
What is the difference in the functioning of alkaline and acidified $\ce{KMnO4}$ as a reagent in organic chemistry? |
What is the difference in the functioning of alkaline and acidified $\ce{KMnO4}$ as a reagent in organic chemistry?
For e.g., in the oxidation of a primary alcohol to carboxylic acid, we use acidified $\ce{KMnO4}$ and not alkaline $\ce{KMnO4}$. Why?
Thanks. |
If I have a pen with refillable ink, can I just pour in concentrated Hydrochloric acid or concentrated sulphuric acid in the ink chamber to make it an acidic pen?
Would it be better to use the acid of *suitable* molarity instead of bieng concentrated?
Then if I write with it on a paper, will it burn?
Is this a... |
How can I make an acidic pen to burn paper on writing on it? |
You *can* pour anything into your pen. Is it a good idea? Most likely **not**. Is it dangerous? *You bet!* Is it a good idea to play with? **NO!** Whether it is legal or not to create such an object, you'll have to check with legislation in your country.
If you want paper to ignite on touch with this pen, you would ... |
Currently I investigate a reaction where a starting material A reacts with an excess of thiophenol B towards products C and D. As shown by recurrent TLC analysis of the reaction, the formation of D is slower than the one of C, while A and B are still detectable.
Perhaps the reactions are consecutive, i.e.
$\ce{A... |
Knowing that $K_c=4.0$, equilibrium is achieved when $Q_c = K_c$.
Let's set up a rice table and write down our equilibrium expression like you did:
Reactants:
$$\ce{C2H5OH + CH3COOH <=> CH3COOC2H5 + H2O}$$
Initial Concentrations: (As you calculated above, we have our starting number of moles for our reactio... |
Tert-butyl alcohol seems unusual among alcohols in that its melting point is high (25°C) while its boiling point is also still low (82°C). I am looking for more materials with phase-unstable liquid regions like this so I'm curious what makes the liquid phase so unstable relative to the solid and gas phases?
Do the ... |
Knowing that $K_c=4.0$, equilibrium is achieved when $Q_c = K_c$.
Let's set up a rice table and write down our equilibrium expression like you did:
Reactants:
$$\ce{C2H5OH + CH3COOH <=> CH3COOC2H5 + H2O}$$
\begin{array} {|c|c|c|c|c|}
\hline
\text{Initial conc.} & \text{0.373 mol} & \text{0.396 mol} & \tex... |
Knowing that $K_c=4.0$, equilibrium is achieved when $Q_c = K_c$.
Let's set up a rice table and write down our equilibrium expression like you did:
Reactants:
$$\ce{C2H5OH + CH3COOH <=> CH3COOC2H5 + H2O}$$
\begin{array} {|c|c|c|c|c|}
\hline
\text{Initial conc.} & \text{0.373 mol} & \text{0.396 mol} & \tex... |
Knowing that $K_c=4.0$, equilibrium is achieved when $Q_c = K_c$.
Let's set up a rice table and write down our equilibrium expression like you did:
Reactants:
$$\ce{C2H5OH + CH3COOH <=> CH3COOC2H5 + H2O}$$
\begin{array} {|c|c|c|c|c|}
\hline
\text{Initial conc.} & \text{0.373 mol} & \text{0.396 mol} & \tex... |
In the reaction between hydrochloric acid and Magnesium the overall reaction is:
$$\ce{Mg + 2HCl -> MgCl2 + H2}$$
My proposed mechanism of reaction is that $\ce{HCl}$ dissociates in $\ce{H2O}$ like so:
$$\ce{H2O + HCl <=> H3O+ + Cl- }$$
And then the $\ce{H3O+}$ oxidises the magnesium like so:
$$\ce{2H3O+... |
In principle, a solution of white phosphorus in carbon disulfide ($\ce{CS2}$) can be used as an "ink" to set paper on fire. This [video][1] demonstrates the effect.
Is it a good idea? **NO!**
While the disgusting smell of carbonyl sulfide ($\ce{COS}$) often found as an impurity is just a nuisance, the solvent its... |
In my class my teacher showed us how to find it, with a method, but he didn't really state the formula. I conjured up a formula from what I observed and it works. Here it is:
$$
\frac{i_1x + i_2y}{100} = A
$$
$A$ = atomic mass<br>
$i_1$ = First's isotope's atomic weight <br>
$i_2$ = Second isotope's atomic w... |
The formula for finding the percentage of isotopes in an element's atomic weight? |
In the following reaction, $K_\text{c}=4.0$:
$$\ce{C2H5OH + CH3COOH <=> CH3COOC2H5 + H2O}$$
A reaction is allowed to occur in a mixture of $17.2~\mathrm{g}~\ce{C2H5OH}$, $23.8~\mathrm{g}~\ce{CH3COOH}$, $48.6~\mathrm{g}~\ce{CH3COOC2H5}$, and $71.2~\mathrm{g}~\ce{H2O}$
>(a) In what direction will a net change oc... |
We know that for homogeneous mixtures the equilibrium constant is determined using both concentration of reactants and of products. For heterogeneous equilibrium involving a gas and a liquid or a solid, we only use the concentration of the gas because the concentration of liquids and gases are constants, and can thus b... |
Chemistry World UK have made [this YouTube Clip][1] that has a professor from UCLA explaining what is needed and how to go about it - even though the video is about 2.5 minutes, but it is a good demonstration. The associated article is [DVD player burns graphene to disc][2]
Additionally, according to this JensLabs ... |
We know the alpha particle is the nucleus of [helium][1]. It contains four subatomic particles - two protons and two neutrons. The protons and neutrons are further made of particles called up and down quarks. So why call an alpha *particle* a particle. And similarly, why do we say electrons, protons, neutrons etc. are ... |
Why is the alpha particle called a particle when it is a pair of four particles? |
How is nickel mined and extracted from it's ores? What is the word and chemical equation for this? |
Consider the reaction
$\ce{NH3 + H2O -> NH4+ + OH-}$
Here, $\ce{NH3}$ is a weak base, and thus $\ce{H2O}$ becomes a weak acid. Thus, shouldn't its conjugate be a strong acid? However, $\ce{NH4+}$ is a weak acid, instead of the strong conjugate acid it should be. Why is this? |
If I have a pen with refillable ink, can I just pour in concentrated Hydrochloric acid or concentrated sulphuric acid in the ink chamber to make it an acidic pen?
Would it be better to use the acid of *suitable* molarity instead of being concentrated?
Then if I write with it on a paper, will it burn?
Is this a... |
Why is the alpha particle called a particle when it is made of four particles? |
I read in my textbook that if we multiply a chemical reaction by some factor(let's say b) its new equilibrium constant becomes K^b.But I don't understand why this happens..
What is the difference between the reaction A+B=C and b.A+b.B=b.C ?
aren't the two reactions same?so why does the equillibrium constant changes?... |
I read in my textbook that if we multiply a chemical reaction by some factor(let's say b) its new equilibrium constant becomes K^b.But I don't understand why this happens..
What is the difference between the reaction A + B = C and b.A + b.B = b.C ?
Aren't the two reactions same?So why does the equilibrium constant c... |
I read in my textbook that if we multiply a chemical reaction by some factor(let's say $b$) its new equilibrium constant becomes $K^b$.But I don't understand why this happens..
What is the difference between the reaction $\ce{A} + \ce{B} = \ce{C}$ and $b \ce{A} + b \ce{B} = b \ce{C}$ ?
Aren't the two reactions same?... |
To be explicit, $\text{Cr}^{3+}$ and $\text{Sc}$ have the same number of electrons, the only difference is the nuclear charge.
This is not an isolated anomaly, it seems: the book I'm using claim that with all fourth period transition metal cations, the $4 \text{s}$ electrons are removed first. This indicates that t... |
Why does $\text{Cr}^{3+}$ not have the same electron configuration as $\text{Sc}$? |
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