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2 � � E¯ 2 + | | | − · | = − − E ¯ J ¯ · dV = E ¯ × H ¯ · dS ¯ � V � � E ¯ × H ¯ + � · E ¯ × H ¯ � � · � � ¯ H ¯ E × · d¯ a + S S d dt � � V 1 � E 2 + µ ¯ | ¯ | 2 1 2 |H|2 � � ¯ = − E · J dV ¯ dV V S ¯ = E ¯ × H ¯ W = � � 1 2 �|E¯ |2 + 1 V � ¯ ¯ · Pd = V E J dV 2 µ|H¯ |2 � dV � � Po...
https://ocw.mit.edu/courses/6-013-electromagnetics-and-applications-fall-2005/2f455332ba1548a8db83ef1d78592088_lec8.pdf
= −�Φ (Kirchoff’s Voltage Law � k vk = 0 (Kirchoff’s current law � k ik = 0 � × H ¯ = J ¯ ⇒ � · J ¯ = 0, � S J ¯ · dS ¯ = 0 � Pin = − E ¯ × H ¯ dS ¯ S ¯ � � ¯ = − � · E × H dV � · � E ¯ 0 − � · � � × � V �� E ¯ × H ¯ = H ¯ ��� · � × ¯ E � · � = Φ����� 0 � · � � · J ¯ + J ¯ (�Φ) � J¯Φ · � � ...
https://ocw.mit.edu/courses/6-013-electromagnetics-and-applications-fall-2005/2f455332ba1548a8db83ef1d78592088_lec8.pdf
H¯ˆ (¯r)ejωt � � H¯ (¯r, t) = Re = = E¯ˆ(¯r)ejωt + Eˆ¯∗(¯r)e−jωt � 1 � 2 Hˆ¯ (¯r)ejωt + Hˆ¯ ∗(¯r)e−jωt � 1 � 2 � �� � The real part of a complex number is one-half of the sum of the number and its complex conjugate 2 Maxwell’s Equations in Sinusoidal Steady State � × Eˆ¯(¯r) = −jωµ Hˆ¯ (¯r) � × Hˆ¯ (...
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� 1 Eˆ¯(¯r) × Hˆ¯ ∗(¯r) Re 2 ˆ ¯ � � Eˆ¯∗(¯r) × Hˆ¯ (¯r) Re � � ¯ S = = = 1 2 = ˆ ¯ (A complex number plus its complex conjugate is twice the real part of that number.) � � · Sˆ = � · ¯ Sˆ¯ = � 1 Eˆ(¯r) × Hˆ ∗(¯r) ¯ 2 = ¯ = = 1 E¯ˆ(¯r) × H¯ˆ (¯r)∗ 2 1 � 2 1 � 2 1 2 � Hˆ ∗(¯r) · � × Eˆ(¯r) − Eˆ...
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(ρf = 0, J ¯ = 0) A. Wave equation H ¯ ∂ ∂t ∂E ¯ ∂t � × ¯ E = −µ ¯ � × H = � � · ¯ E = 0 � · H ¯ = 0 3 � � � × � × ¯ ∂ � � × E = −µ ∂t � ������0 E � E � � × � × ¯ = � � · ¯ − � 2 ¯ E = −�µ ¯ � H = −µ ∂ � � ∂t ∂E ¯ � ∂t ∂2E ¯ ∂t2 Wave equation �2E ¯ = 1 ∂2E ¯ c ∂t2 2 �µ is the speed of...
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c2 ˆEx d2 ˆEx dz2 = − + k2Eˆx = 0 d2Eˆx dz2 4 Ex- = Re[Ex-(z)exp ](j t)Ex+ = Re[Ex+ (z)exp ](j t)Hy+ = Re[Hy+ (z)exp ](j t)Kx = Re[K0 exp ](j t)Hy- = Re[Hy-(z)exp ](j t)e, me, mxyzwwwww where we have is the wavenumber, λ is the wavelength ω2 k2 = 2 = ω2�µ c 2π λ k = ± k = ⇒ ω c ω = kc ω = 2πf = 2π ...
https://ocw.mit.edu/courses/6-013-electromagnetics-and-applications-fall-2005/2f455332ba1548a8db83ef1d78592088_lec8.pdf
> 0 2 ¯iz z < 0 (Kˆ 0 real) Ex(z, t) = Re Ex(z)e � ˆ � jωt = Hˆy(z)ejωt � � Hy(z, t) = Re = Sz = ExHy = �Sz� = � � � − − � cos(ωt − kz) z > 0 cos(ωt + kz) z < 0 ηK0 2 ηK0 2 − K 0 cos(ωt − kz) z > 0 2 + K 0 cos(ωt + kz) z < 0 2 ηK2 0 cos2(ωt − kz) 4 − ηK0 4 2 ηK0 8 2 ηK0 − 8 z > 0 cos2(ω...
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From Electromagnetic Field Theory: A Problem Solving Approach, by Markus Zahn, 1987. Used with permission. For Eˆi = Ei real we have: � Ex(z, t) = Ex,i(z, t) + Ex,r(z, t) = Re Eˆi e−jkz − e +jkz ejωt � � � Hy(z, t) = Hy,i(z, t) + Hy,r(z, t) = Re = 2Ei sin(kz) sin(ωt) � Eˆi � η e−jkz + e +jkz � � ejωt = 2E...
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|Eˆi|2 2η1 1 2η2 Re |Eˆi|2 − | Eˆr|2 � � � 1 EˆrEˆ Re 2η1 � |Eˆi|2 − | Eˆr|2 � � 1 − R2� � ∗e 2jk1z − Eˆ i �� pure imaginary r ∗Eˆie−2jk1z � � |Eˆt|2 = ˆ 2T 2 |E i| η2 2 = | ˆ | Ei 2(1 − R2) 2η1 = �Sz,i� V. Lossy Dielectrics - J ¯ = σE ¯ Ampere’s Law: � × H ¯ = J ¯ + � ∂ ¯ = σE ¯ + � ∂ ¯ E ∂t ...
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Wave-particle Duality: Electrons are not just particles • Compton, Planck, Einstein – light (xrays) can be ‘particle-like’ • DeBroglie – matter can act like it has a ‘wave-nature’ • Schrodinger, Born – Unification of wave-particle duality, Schrodinger Equation ©1999 E.A. Fitzgerald 1 Light has momentum: Compt...
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L Therefore, sinkz must equal zero at z=0 and z=L sin kL = 0; kL =πn; k = n π L Also, since k=2π/λ, n = L 2 λ or λ= L 2 n In 3-D, λ= 2L 2 + n 2 nx 2 y + nz Note that the wavelength for E-M waves is ‘quantized’ classically just by applying a confining boundary condition ν = c nx 2 + nz 2 2 + n ...
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3 L3 = 2 8πν kT c 3 The classical assumption was used, i.e. Ewave=kbT This results in a ρ (ν ) that goes as ν 2 At higher frequencies, blackbody radiation deviates substantially from this dependence ©1999 E.A. Fitzgerald 6 800 600 ) ) m n / J k ( 400 ) l ( u 200 y t i s n e t n I Missing higher frequencies T...
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than ρ (ν ) would not have ν 2 dependence at higher ν •P(E) will decrease at higher E if E is a function of ν •Experimental fit to data suggests that E is a linear function in ν , therefore E=nhν where h is some constant E = nhν − e kbT nhν = − e k T b ∞ ∑ nhν 0 k T b ∞ 1 ∑ 0 kbT hν hν e k T − 1 b ...
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intensity, no e - ©1999 E.A. Fitzgerald 11 Light is always quantized: Photoelectric effect (Einstein) Ein=hν E EF vacuum ΔE Evac=Ein-ΔE Emax=Ein-ΔE=hν-hνc x Ein=hν! Strange consequence of Compton plus E=hν: light has momentum but no mass λ= hc E = h p since E = cp for a photon ©1999 E.A. Fitzgerald ...
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Example of Diffraction from Thin Film of Different Lattice Constant • InGaAs on GaAs deposited by molecular beam epitaxy (MBE) • Can determine lattice constant (In concentration) and film thickness from interference fringes GaAs InxGa1-xAs Interference fringes from optical effect GaAs X-ray intensity In0.05G...
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Gex Layers (each layer about 3000A) ©1999 E.A. Fitzgerald 39 20
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MIT OpenCourseWare http://ocw.mit.edu (cid:10) 6.642 Continuum Electromechanics Fall 2008 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. (cid:13) 6.642, Continuum Electromechanics, Fall 2004 Prof. Markus Zahn Lecture 9: Plasma Stability (z-θ pinch) Continuum E...
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⎞ ⎟ ⎠ - H + h a ( z 2 ) ⎤ ⎥ ⎥ ⎦ ≈ 1 2 ⎡ μ ⎢ ⎣ 0 -H - 2H h - t θ 2 t ⎛ ⎜ ⎝ H ξ t R ⎞ ⎟ ⎠ - H - 2H h a z 2 a ⎤ ⎥ ⎦ 'T = rr −μ 0 ⎡ ⎣ H h - H R + H h ξ t θ a t ) ( ⎤ ⎦z T = h Hμ 0 r rθ t T n = h H n μ t θ rθ θ 0 r second order 6.642, Continuum Electromechanics Lecture 9 Prof. Markus Zahn Page 3 of 5 ...
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(cid:108) Ψ c = kF m ( ) a, R ⎡ (cid:3) ξ ⎢ ⎣ m R H + kH t a ⎤ ⎥ ⎦ IV. Dispersion Relation 2 ω ρ (cid:3) ) F 0, R = - H F ξ μ ( m 0 t m ( a, R ) m m (cid:3) ξ R R ⎡ ⎢ ⎣ + (cid:3) γξ ⎡ 2 1 - m - kR ⎣ R ( 2 2 ) ⎤ ⎦ H + kH + a t ⎤ ⎥ ⎦ μ 2 H 0 t R (cid:3) ξ μ - H kF 0 a m ( ) a, R (cid:3) ξ m R ⎡ ⎢ ⎣ H + kH t a ⎤ ⎥ ⎦ 2...
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� 2 kR + m - 1 + F 0 m μ 2 ) ⎤ ⎦ ( a, R ) m R ⎡ ⎢ ⎣ H + kH t a 2 ⎤ ⎥ ⎦ - μ 2 H 0 t R Stabilizing Destabilizing 6.642, Continuum Electromechanics Lecture 9 Prof. Markus Zahn Page 4 of 5 V. Stability Surface tension: stabilizing for m≥1 destabilizing ...
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9v† ^_wífë¢â ô_ífA9_ío Aí 9†¢Uo _m 9v† B†à_ôA9â õ_9†í9Aëà φ f†Üí†f ^â ï}I UI àa F φ; ∇ MIT OpenCourseWare https://ocw.mit.edu 2.062J / 1.138J / 18.376J Wave Propagation Spring 2017 For information about citing these materials or our Terms of Use, visit: https://ocw.mit.edu/terms.
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6.891: Lecture 4 (September 20, 2005) Parsing and Syntax II Overview • Weaknesses of PCFGs • Heads in context-free rules • Dependency representations of parse trees • Two models making use of dependencies Weaknesses of PCFGs • Lack of sensitivity to lexical information • Lack of sensitivity to structural frequen...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
probable. Attachment decision is completely independent of the words A Case of Coordination Ambiguity NP CC and NP NNS cats (a) NP NP PP NNS IN NP dogs in NNS houses (b) NP NP NNS dogs IN in PP NP NP CC NP NNS and NNS houses cats (a) Rules NP � NP CC NP NP � NP PP NP � NNS PP � IN...
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Vi VP ∈ Vt NP VP ∈ VP PP NP ∈ DT NN NP ∈ NP PP IN NP PP ∈ Vi ∈ sleeps Vt ∈ saw NN ∈ man NN ∈ woman NN ∈ DT ∈ IN ∈ with IN ∈ telescope the in Note: S=sentence, VP=verb phrase, NP=noun phrase, PP=prepositional phrase, DT=determiner, Vi=intransitive verb, Vt=transitive verb, NN=noun, IN=preposition M...
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VP ∈ Vt NP VP ∈ VP PP Adding Headwords to Trees S NP VP DT the NN lawyer Vt NP questioned DT the NN witness � S(questioned) NP( lawyer ) VP(questioned) DT(the) NN(lawyer) the lawyer Vt(questioned) NP(witness) questioned DT(the) NN(witness) the witness Adding Headwords to Trees S(question...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
grammar: • N is a set of non-terminal symbols • � is a set of terminal symbols • R is a set of rules which take one of three forms: – X(h) � Y1(h) Y2(w) for X � N , and Y1, Y2 � N , and h, w � � – X(h) � Y1(w) Y2(h) for X � N , and Y1, Y2 � N , and h, w � � – X(h) � h for X � N , and h � � • S � N is a distingui...
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Logical form/Predicate-argument structure Adding Predicate Argument Structure to our Grammar • Identify words with lambda terms: likes Bill Clinton Clinton �y, x Bill like(x, y) • Semantics for an entire constituent is formed by applying semantics of head (predicate) to the other children (arguments) [�y, x = ...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
and Dependencies S(told,V[6]) NP(yesterday,NN) NP(Hillary,NNP) VP(told,V[6]) � (told, V[6], yesterday, NN, S, VP, NP, LEFT) (told, V[6], Hillary, NNP, S, VP, NP, LEFT) A Special Case: the Top of the Tree TOP S(told,V[6]) � ( , , told, V[6], TOP, S, , SPECIAL) S(told,V[6]) NP(Hillary,NNP) VP(told,V[6]) NNP ...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
,Vt) Smoothed Estimation P (NP( ,NN) VP | S(questioned,Vt)) = �1 × Count(S(questioned,Vt)�NP( ,NN) VP) Count(S(questioned,Vt)) +�2 × Count(S( ,Vt)�NP( ,NN) VP) Count(S( ,Vt)) • Where 0 � �1, �2 � 1, and �1 + �2 = 1 Smoothed Estimation P (lawyer | S,VP,NP,NN,questioned,Vt) = �1 × Count(lawyer | S,VP,NP,NN,questio...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
(questioned,Vt) NP( ,NN) VP(questioned,Vt) • Relies on counts of entire rules • These counts are sparse: – 40,000 sentences from Penn treebank have 12,409 rules. – 15% of all test data sentences contain a rule never seen in training Motivation for Breaking Down Rules Rule Count No. of Rules Percentage No. of Rul...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
ov Processes • Step 2: generate left modifiers in a Markov chain S(told,V[6]) ?? NP(Hillary,NNP) VP(told,V[6]) ∈ S(told,V[6]) NP(yesterday,NN) NP(Hillary,NNP) VP(told,V[6]) Ph(VP | S, told, V[6]) × Pd(NP(Hillary,NNP) | S,VP,told,V[6],LEFT)× Pd(NP(yesterday,NN) | S,VP,told,V[6],LEFT) Modeling Rule Productions ...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
,VP,told,V[6],LEFT) × Pd(STOP | S,VP,told,V[6],RIGHT) A Refinement: Adding a Distance Variable • � = 1 if position is adjacent to the head. S(told,V[6]) ?? VP(told,V[6]) ≈ S(told,V[6]) NP(Hillary,NNP) VP(told,V[6]) Ph(VP | S, told, V[6])× Pd(NP(Hillary,NNP) | S,VP,told,V[6],LEFT,� = 1) A Refinement: Adding a Di...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
illary,NNP) VP(told,V[6]) NN yesterday NNP Hillary V[6] . . . told • Hillary is the subject • yesterday is a temporal modifier • But nothing to distinguish them. Adding the Complement/Adjunct Distinction VP V NP verb object VP(told,V[6]) V[6] told NP(Bill,NNP) NP(yesterday,NN) SBAR(that,COMP) NNP ...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
-C(that,COMP) NNP Bill NN yesterday . . . Adding Subcategorization Probabilities • Step 1: generate category of head child S(told,V[6]) ≈ S(told,V[6]) VP(told,V[6]) Ph(VP | S, told, V[6]) Adding Subcategorization Probabilities • Step 2: choose left subcategorization frame S(told,V[6]) VP(told,V[6]) ≈ S(...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
(told,V[6]) {} � S(told,V[6]) STOP NP(yesterday,NN) NP-C(Hillary,NNP) VP(told,V[6]) {} Ph(VP | S, told, V[6]) × Plc ({NP-C} | S, VP, told, V[6]) Pd(NP-C(Hillary,NNP) | S,VP,told,V[6],LEFT,{NP-C})× Pd(NP(yesterday,NN) | S,VP,told,V[6],LEFT,{})× Pd(STOP | S,VP,told,V[6],LEFT,{}) The Final Probabilities S(told,...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
P) | VP,V[6],told,V[6],RIGHT,� = 1,{NP-C, SBAR-C})× Pd(NP(yesterday,NN) | VP,V[6],told,V[6],RIGHT,� = 0,{SBAR-C})× Pd(SBAR-C(that,COMP) | VP,V[6],told,V[6],RIGHT,� = 0,{SBAR-C})× Pd(STOP | VP,V[6],told,V[6],RIGHT,� = 0,{}) Summary • Identify heads of rules ∈ dependency representations • Presented two variants of PCF...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
– Decision Trees (Magerman 95) 84.0% 85.3% Lexical Dependencies (Collins 96) 86.3% Conditional Models – Logistic (Ratnaparkhi 97) 86.7% Generative Lexicalized Model (Charniak 97) 87.5% Model 1 (no subcategorization) 88.1% Model 2 (subcategorization) 74.8% 84.3% 85.7% 87.5% 86.6% 87.7% 88.3% Effect of...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
VP attachment: (S (NP The men) (VP dumped (NP sacks) (PP of (NP the substance)))) S(told,V[6]) NP-C(Hillary,NNP) VP(told,V[6]) NNP Hillary V[6](told,V[6]) NP-C(Clinton,NNP) SBAR-C(that,COMP) V[6] told NNP Clinton COMP that S-C NP-C(she,PRP) VP(was,Vt) PRP she Vt NP-C(president,NN) was NN presid...
https://ocw.mit.edu/courses/6-864-advanced-natural-language-processing-fall-2005/2fcb90c84d2859c5292fdebfad49b464_lec4.pdf
40.55 48.72 54.03 59.30 64.18 68.71 73.13 74.53 75.83 77.08 78.28 79.48 80.40 81.30 82.18 82.97 P 29.65 10.90 8.17 5.31 5.27 4.88 4.53 4.42 1.40 1.30 1.25 1.20 1.20 0.92 0.90 0.88 0.79 Count Relation 11786 NPB TAG TAG L PP TAG NP-C R 4335 S VP NP-C L 3248 NP NPB PP R 2112 VP TA...
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Count Recall Precision Complement to a verb 6495 = 16.3% of all cases Other complements 7473 = 18.8% of all cases Subject Object S VP NP-C L VP TAG NP-C R VP TAG SBAR-C R VP TAG SG-C R VP TAG S-C R S VP S-C L S VP SG-C L ... TOTAL PP TAG NP-C R VP TAG VP-C R SBAR TAG S-C R SBAR WHNP SG-C R PP TAG ...
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R ADVP TAG PP R NP NP PP R PP PP PP L NAC TAG PP R ... TOTAL NP NP NP R VP VP VP R S S S R ADJP TAG TAG R VP TAG TAG R NX NX NX R SBAR SBAR SBAR R PP PP PP R ... TOTAL 2112 1801 287 90 35 23 19 12 4473 289 174 129 28 25 25 19 14 84.99 83.62 90.24 75.56 68.57 0.00 21.05 50.00 82...
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91 51.72 14.81 66.67 93.20 74.34 79.20 77.56 88.89 45.28 35.42 62.50 93.46 92.82 75.68 71.24 81.65 71.43 66.67 76.92 92.59 75.72 79.54 72.60 81.16 60.00 54.84 69.77 1418 73.20 75.49 Type Sentential head 1917 = 4.8% of all cases Adjunct to a verb 2242 = 5.6% of all cases Sub-type De...
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.00 2242 75.11 78.44 Some Conclusions about Errors in Parsing • “Core” sentential structure (complements, NP chunks) recovered with over 90% accuracy. • Attachment ambiguities involving adjuncts are resolved with much lower accuracy (� 80% for PP attachment, � 50 − 60% for coordination).
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6.045: Automata, Computability, and Complexity Or, Great Ideas in Theoretical Computer Science Spring, 2010 Class 10 Nancy Lynch Today • Final topic in computability theory: Self-Reference and the Recursion Theorem • Consider adding to TMs (or programs) a new, powerful capability to “know” and use their own desc...
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3 > – Run P3 on w – If P3 on w outputs a number n then output n+1. • A valid self-referencing program. • What does P3 compute? • Seems contradictory: if P3 on w outputs n then P3 on w outputs n+1. • But according to the usual semantics of recursive calls, it never halts, so there’s no contradiction. • P3 computes a pa...
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r(w) = t(<R>, w). <M> w • Example: P2, revisited – Computes length of input. – What are T and R? – Here is a version of P2 with an extra input <M>: – T2: On inputs <M> and w: • If w = ε then output 0 • Else run M on tail(w); if it outputs n then output n+1. T R t(<M>, w) w t(<R>, w) The Recursion Theorem • Example:...
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computes the function r: Σ* → Σ*, where for any w, r(w) = t(<R>, w). w R t(<R>, w) Applications of the Recursion Theorem Applications of Recursion Theorem • The Recursion Theorem can be used to show various negative results, e.g., undecidability results. • Application 1: AccTM is undecidable – We already know this...
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: – If R accepts w, then • D accepts <R, w> since D is a decider for AccTM, so • R rejects w by definition of R. – If R does not accept w, then • D rejects <R, w> since D is a decider for AccTM, so • R accepts w by definition of R. • Contradiction. So D can’t exist, so AccTM is undecidable. Applications of Recursion...
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recognizable languages. Let MP = { < M > | L(M) ∈ P }. Then MP is undecidable. – Nontriviality: There is some M1 with L(M1) ∈ P, and some M2 with L(M2) ∉ P. – Implies lots of things are undecidable. – We already proved this; now, a new proof using the Recursion Theorem. – Suppose for contradiction that D is a TM tha...
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L(R) ∈ P, then • D accepts <R>, since D decides MP, so • L(R) = L(M2) by definition of R, so • L(R) ∉ P. Application 3: Using Recursion Theorem to prove Rice’s Theorem • Rice’s Theorem: Let P be a nontrivial property of Turing- recognizable languages. Let MP = { < M > | L(M) ∈ P }. Then MP is undecidable. • L(M1) ∈...
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recognizable. – Then it’s enumerable, say by enumerator TM E. – R: On input w: • Obtain <R>. • Run E, producing list < M1 >, < M2 >, … of all minimal TMs, until you find some < Mi > with |< Mi >| strictly greater than |< R >|. – That is, until you find a TM with a rep bigger than yours. • Run Mi(w) and do the same thi...
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izer). – If not, we don’t care what B does. • B outputs the encoding of the combination of two machines, P<M> and M. • The first machine is P<M>, which simply outputs <M>. • The second is the input machine M. • P<M> ° M: <M> P<M> M Some output Construction of B < P<M> ° M > <M> B • How can B generate < P<M> ° M >? – ...
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is not the general RT. • RT says not just that: – There is a TM that outputs its own description. • But that: – There are TMs that can use their own descriptions, in “arbitrary ways”. • The “arbitrary ways” are captured by the machine T in the RT statement. <M> w T t(<M>, w) The Recursion Theorem • Recursion Theorem...
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-input TM, which uses output of P<M> as first input of M. P<M> M Combining the Pieces • R = (A ° B) °1 T A B w T • Claim R outputs t(<R>, w): • A is P<B °1 T>, so the output from A to B is <B °1 T >: <B °1 T > < P<B ° 1 T > °1 (B °1 T) > A = P<B °1 T> B <M> < P<M> °1 M > B • Now recall definition of B: • Plug in B ° ...
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Examples of Transient RC and RL Circuits. The Series RLC Circuit Impulse response of RC Circuit. Let’s examine the response of the circuit shown on Figure 1. The form of the source voltage Vs is shown on Figure 2. R Vs C + vc - Figure 1. RC circuit Vs Vp 0 tp Figure 2. t We will investigate the response vc t ( ...
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⎝ − + = 1 2 ⎛ ⎜ ⎜ ⎝ + ⎤ …⎥ ⎥ ⎦ ⎞ ⎟ ⎟ ⎠ 0 t ≤ ≤ tp (1.3) When RC t(cid:21) the higher order terms may be neglected resulting in vc t ( ) (cid:17) Vp t RC 0 t ≤ ≤ tp At the end of the pulse (at t tp= ) the voltage becomes vc t ( = tp ) (cid:17) Vptp RC 6.071/22.071 Spring 2006, Chaniotakis and Cory (1.4) (1.5) 2...
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The spark plug in your car (a simplified model) Consider the circuit shown on Figure 5. The battery Vb corresponds to the 12 Volt car battery. The spark plug is connected actors the inductor and current may flow though it only if the voltage across the gap of the plug exceeds a very large value (about 20 kV). + Vb ...
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t − 0.002 The voltage across the coil when the switch is opened is v L = i ∆ t ∆ = 0.01 2.4 1 10 × − 6 = 24 kV 6.071/22.071 Spring 2006, Chaniotakis and Cory 5 Response of RC circuit driven by a square wave. Let’s now consider the RC circuit shown on Figure 6(a) driven by a square wave signal o...
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T − RC ⎤ ⎥ ⎦ + t − RC ⎤ Vp e ⎥ ⎥ ⎦ (1.13) (1.14) Similarly the response during the first part of the second cycle starts with the value of vc at t=T and evolves towards the value Vp. If the time constant is small compared to the period of the square wave, the response will reach the maximum and minimum values of...
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circuit. We will analyze this circuit in order to determine its transient characteristics once the switch S is closed. Vs S + vR - + vL - R L C + vc - Figure 10 The equation that describes the response of the system is obtained by applying KVL around the mesh vR vL vc Vs + = + The current flowing in the circuit is...
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2s = − + 2 α α ω ο − 2 = − − 2 α α ω ο − 2 And the homogeneous solution becomes hvc = A e 1 1 s t 2 s t + A e 2 The total solution now becomes vc Vs A e 1 = + s t 1 + A e 2 s t 2 6.071/22.071 Spring 2006, Chaniotakis and Cory (1.22) (1.23) (1.24) (1.25) (1.26) (1.27) (1.28) (1.29) 11 ...
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As the resistance increases the value of α increases and the system is driven towards an over damped response. • The frequency 1 LC or the resonant frequency. οω = (rad/sec) is called the natural frequency of the system • The quantity L C has units of resistance Figure 11 shows the response of the series RLC c...
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)ο t (1.30) (1.31) (1.32) (1.33) (1.34) (1.35) The constants A1, A2 or B1, B2 are determined from the initial conditions of the system. 6.071/22.071 Spring 2006, Chaniotakis and Cory 14 For vc t ( = 0) = Vo and for have from Equation (1.34) 0...
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less system 6.071/22.071 Spring 2006, Chaniotakis and Cory 15 (a) Voltage across the capacitor (b) Voltage across the inductor (c)Current flowing in the ciruit Figure 13 6.071/22.071 Spring 2006, Chaniotakis and Cory 16 (a) Energy stored in the capaci...
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Image Quality Metrics • Image quality metrics • Mutual information (cross-entropy) metric • Intuitive definition • Rigorous definition using entropy • Example: two-point resolution problem • Example: confocal microscopy • Square error metric • Receiver Operator Characteristic (ROC) • Heterodyne detection MIT 2.71...
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2 k 1=   ln + 1  2   ln + 1  µ 2 − 2 t 2σ  µ k  = 2σ      ln +  + 1   ≈precision of (t-2)th measurement E.g. 0.5470839348 these digits worthless if σ ≈10-5 MIT 2.717 Image quality metrics p-5 2 < < −µ σ µ 2 2 t t 1 noise floor −µ σ 2 t 1   2  +   +  ln 1 ...
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1 1 2 • Unfair coin: p(H)=1/4; p(T)=3/4 1 Entropy = − 4 log2 log 2 1 4 3 4 − 3 = 4 81.0 bits Maximum entropy ⇔⇔⇔⇔⇔⇔⇔⇔ Maximum uncertainty Maximum uncertainty Maximum entropy MIT 2.717 Image quality metrics p-7 Formal definition of cross-entropy (3) Joint Entropy Joint Entropy log2[how many are the possible ...
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eliminates information adds uncertainty to the measurement wrt the object eliminates information from the measurement wrt object MIT 2.717 Image quality metrics p-10 Formal definition of cross-entropy (6) uncertainty added due to noise representation by Seth Lloyd, 2.100 Entropy( )F information contained in th...
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from among a continuum) – definition of differential entropy Diff. Entropy = − Ω( ( )ln ∫ x p )X ( ) dx x p – unit: 1 nat (=diff. entropy value of a significant digit in the representation of a random number, divided by ln10) MIT 2.717 Image quality metrics p-14 Image Mutual Information (IMI) object hardw...
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f B B Two point-detectors (measurement) ~ A g A ~ B g B Classical view intensities measured intensities emitted MIT 2.717 Image quality metrics p-17 noiseless intensity @detector plane Ag Bg x Cross-leaking power g g A B = = f A sf A + sf + f B B = sinc 2 s ( )x ss ~ A ~ B MIT 2.717 Image qu...
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matrices (1) H = = H underdetermined underdetermined (more unknowns than measurements) overdetermined overdetermined (more measurements than unknowns) eigenvalues cannot be computed, but instead we compute the singular values singular values of the rectangular matrix MIT 2.717 Image quality metrics p-21 IM...
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the imaging system can successfully discern; this includes – the rank of the system, i.e. the number of object dimensions that the system can map the precision available at each rank, i.e. how many significant digits can be reliably measured at each available dimension • An alternative interpretation of IMI is t...
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6.231: DYNAMIC PROGRAMMING LECTURE 1 LECTURE OUTLINE Problem Formulation Examples The Basic Problem Significance of Feedback • • • • 1 DP AS AN OPTIMIZATION METHODOLOGY Generic optimization problem: • min g(u) u∈U where u is the optimization/decision variable, g(u) is the cost function, and U is the constraint set • Cat...
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1 = xk + uk - wk Cost of Period k r(xk) + cuk Stock ordered at Period k uk Discrete-time system xk+1 = fk(xk, uk, wk) = xk + uk wk − Cost function that is additive over time • • N −1 E gN (xN ) + ( k=0 X N −1 gk(xk, uk, wk) ) = E cuk + r(xk + uk ( k=0 X (cid:0) (cid:1) ns uk = Optimization over policies: Rules/functio ...
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AB CAD CDA CDA CAB 6 STOCHASTIC FINITE-STATE PROBLEMS • Example: Find two-game chess match strategy Timid play draws with prob. pd > 0 and loses pd. Bold play wins with prob. pw < • with prob. 1 − 1/2 and loses with prob. 1 pw − 0.5-0.5 pd 0 - 0 1 - pd pw 1 - 0 0 - 0 1 - pw 0 - 1 0 - 1 1st Game / Timid Play 1st Game / ...
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J ∗(x0) = min Jπ(x0) π Optimal policy π∗ satisfies • • Jπ∗ (x0) = J ∗(x0) When produced by DP, π∗ is independent of x0. 8 SIGNIFICANCE OF FEEDBACK • Open-loop versus closed-loop policies wk u = m (x ) uk = µk(xk) k k k System x k + 1 = f (x ,u ,w ) k k k k xk mk ) µk In deterministic problems open loop is as good • as...
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lectures) Chs. 6, 7: Approximate DP (6 lectures) − − 11 COURSE ADMINISTRATION Homework ... once a week or two weeks (30% • of grade) In class midterm, near end of October ... will • cover finite horizon and simple infinite horizon ma- terial (30% of grade) Project (40% of grade) • Collaboration in homework allowed but in...
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6.776 High Speed Communication Circuits Lecture 2 Transceiver Architectures Massachusetts Institute of Technology February 3, 2005 Copyright © 2005 by H.-S. Lee and M. H. Perrott Transceivers for Amplitude Modulation H.-S. Lee & M.H. Perrott MIT OCW Amplitude Modulation Review Transmitter Output 0 x(t) y(t) 2cos(2πfo...
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.H. Perrott MIT OCW SSB Transmitter I (cid:131) Phase-shift SSB Modulator Balanced modulator -90o phase shifter -90o phase shifter Balanced modulator Power Amp + RF Filter SSB (cid:131) Sideband removal depends on phase and amplitude matching H.-S. Lee & M.H. Perrott MIT OCW Frequency Domain View of Phase-Shift SSB ...
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ystal earpiece H.-S. Lee & M.H. Perrott MIT OCW Envelope Detector Example vin v1 C2 vin R1 R2 vout v1 C1 vout H.-S. Lee & M.H. Perrott MIT OCW AM Receiver: Amplified Receiver RF Filter (Tunable LC) RF Amplifier Envelope Detector Audio Freq. (AF) Amplifier (cid:131) Better sensitivity (RF Amp) (cid:131) Can drive lo...
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Filter (Tunable LC) RF Amplifier Frequency Converter IF Filter IF Amplifier Envelope Detector Audio Freq. (AF) Amplifier (cid:131) Frequency converter mixes RF down to lower IF frequency – better selectivity is obtained at the lower frequency IF filter (cid:131) Excellent selectivity due to the additional IF filteri...
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:131) The alternative is to employ image reject mixer H.-S. Lee & M.H. Perrott MIT OCW Image Reject Mixer RF r(t) y(t) Balanced modulator Local Oscillator + LPF or BPF -90o phase shifter IF Output Balanced modulator -90o phase shifter z(t) z(t)^ (cid:131) Image rejected by similar method to SSB generation (cid:131) I...
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Conversion (Zero-IF) Receiver RF Filter (Fixed frequency) RF Amplifier (LNA) Quadrature Mixer Frequency Synthesizer I/Q I Q Baseband Filter Baseband Amplifier A/D converter Baseband Filter Baseband Amplifier A/D converter Q DSP (cid:131) Type of a homodyne receiver (cid:131) Uses coherent detection: a precise local os...
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is not an issue H.-S. Lee & M.H. Perrott MIT OCW Image Rejection in Double Conversion Receiver 1&3 2&4 LNA Output Spectrum 1 2 3 4 I -fIF fIF -fLO1 fLO1 LO1I I-I LO2I I-Q j 1,2,3&4 4&2 1&3 4&3 + -fIF 3 LO2Q 4 Q-I j 1&2 1 Q j 2 fIF LO2I LO1Q Q-Q LO2Q 2&3 4&1 Q-Phase 4 1 j + - 4&1 I-Phase (cid:131) Similar to Weaver SS...
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by nX H.-S. Lee & M.H. Perrott MIT OCW Direct FM: VCO VCO (cid:131) fo: ‘free running’ frequency of VCO (cid:131) Typically, a varactor (voltage-variable capacitor) is used to change oscillation frequency in an oscillator (cid:131) Difficult to maintain precise output frequency due to drift in the VCO frequency (ci...
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AM Conversion Limiter Differentiator Envelope Detector DC block (cid:131) Differentiator converts FM signal to AM (cid:131) Spurious AM must be suppressed by the limiter H.-S. Lee & M.H. Perrott MIT OCW FM Demodulator Example: Delay-Line + - delay τ (cid:131) Differentiator is implemented by a transmission line delay...
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Lecture 7 PN Junction and MOS Electrostatics(IV) Metal­Oxide­Semiconductor Structure (contd.) Outline 1. Overview of MOS electrostatics under bias 2. Depletion regime 3. Flatband 4. Accumulation regime 5. Threshold 6. Inversion regime Reading Assignment: Howe and Sodini, Chapter 3, Sections 3.8-3.9 6.012 Sprin...
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1+ Cox  2C 2 (φφφφB + VGB) εεεεsqNa ox   − 1   Potential drop across semiconductor SCR: VB (VGB ) = qN x 2 d a 2ε s Surface potential φφφφ(0) = φφφφp + VB(VGB) Potential drop across oxide: Vox (VGB ) = qN a x d t ox ε ox 6.012 Spring 2009 Lecture 7 5 3. Flatband At a certain negative VGB,...
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= − φφφφp ni Hence: VB (VT ) = −2φφφφp 6.012 Spring 2009 Lecture 7 9 Computation of threshold voltage (contd.) Second, compute potential drop in oxide at threshold. Obtain xd(VT) using relationship between VB and xd in depletion: VB (VGB = VT ) = 2 VT( qNaxd 2εεεεs ) = −2φφφφp Solve for xd at VGB = VT: ...
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version What happens for VGB > VT? More electrons at Si/SiO2 interface than acceptors ⇒⇒⇒⇒ inversion. Electron concentration at Si/SiO2 interface modulated by VGB ⇒ VGB ↑ → n(0) ↑ → |QN| ↑ : Field­effect control of mobile charge density! [essence of MOSFET] Want to compute QN vs. VGB [charge­control relation] ...
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Existence of QN and control over QN by VGB ⇒ key to MOS electronics 6.012 Spring 2009 Lecture 7 15 What did we learn today? Summary of Key Concepts In inversion: QN = Cox (VGB − VT ) for VGB > VT 6.012 Spring 2009 Lecture 7 16 MIT OpenCourseWare http://ocw.mit.edu 6.012 Microelectronic Devices and Circuits ...
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s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 10 1 5 3 2 4 3 2 3 6 5 -15 4 1 5 6 -5 2 4 6 7 10 The s...
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T+1 s 1 10 25 2 20 4 15 40 35 3 35 5 t 6 30 20 10 s 1 20 2 3 10 4 15 40 35 10 t 6 20 20 5 10 s 1 20 2 3 10 4 15 40 35 10 t 6 20 20 5 8 1 -9 2 5 -10 7 3 0 4 1 3 8 7 s -9 2 0 4 5 -10 1 3 8 7 s t 10 9 5 2 4 (cid:102) (cid:102) (cid:102) 1 3 2 4 t 10 9 (cid:102) (cid:102) 5 8 7 s 1 4 8 12 2 5 3 10 11 9 7 6 ...
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https://ocw.mit.edu/courses/15-093j-optimization-methods-fall-2009/313d12c426c44380ccd838dff3151690_MIT15_093J_F09_lec10.pdf
Advanced System Architecture ESD.342/EECS 6.883 2006 • Goals of this course: • Gain an understanding of system architecture • Learn existing theoretical and analytical methods • Compare systems in different domains and understand what influences their architectures • Apply/extend existing theory in case studies Adv Sy...
https://ocw.mit.edu/courses/esd-342-advanced-system-architecture-spring-2006/31440ed9b876651c3287b430ba75f77e_lec1.pdf
Arch intro 8/24/2006 © Daniel E Whitney 5 Grading Formula • 15% in-class participation (especially reading connections) • 25% assignments – 5% Each for assignments 1 and 2 – 15% for assignment 3 • 60% Project – 20% Final Written Report – 15% Final Presentation – 15% Modeling Status Presentation – 10% 1st Status Prese...
https://ocw.mit.edu/courses/esd-342-advanced-system-architecture-spring-2006/31440ed9b876651c3287b430ba75f77e_lec1.pdf
Whitney 10 A Definition of Architecture from a Practice Perspective “An architecture is the conceptualization, description, and design of a system, its components, their interfaces and relationships with internal and external entities, as they evolve over time.” John W. Evans Source: “Design and Inventive Enginee...
https://ocw.mit.edu/courses/esd-342-advanced-system-architecture-spring-2006/31440ed9b876651c3287b430ba75f77e_lec1.pdf
• Deterministic methods used • Real things – T he ones we are interested in • New methods or adaptations of existing methods needed • Less regular -“Hub and spokes” -“Small Worlds” -“Grown” including growth models • No internal structure – Perfect gases – Crowds of people – Classical economics with invisible h...
https://ocw.mit.edu/courses/esd-342-advanced-system-architecture-spring-2006/31440ed9b876651c3287b430ba75f77e_lec1.pdf
exploitatively – Cells, organisms, food webs, ecological systems In all cases, there is legacy, possibly a dominant influence Adv Sys Arch intro 8/24/2006 © Daniel E Whitney 18 Systems Typology III: Complex Systems Functional Classification Matrix from Magee and de Weck Process/Operand Transform or Process (1) Tr...
https://ocw.mit.edu/courses/esd-342-advanced-system-architecture-spring-2006/31440ed9b876651c3287b430ba75f77e_lec1.pdf
These systems are similar in many ways, perhaps more than we think • Since we want to influence structure (not just accept it as we are interested in design), we will also explore how structure is determined by looking at system typologies and constraints that influence or determine the structure • We will use net...
https://ocw.mit.edu/courses/esd-342-advanced-system-architecture-spring-2006/31440ed9b876651c3287b430ba75f77e_lec1.pdf