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8.022 (E&M) – Lecture 9 Topics: „ RC circuits Thevenin’s theorem „ Last time „ Electromotive force: „ How does a battery work and its internal resistance „ How to solve simple circuits: „ „ Kirchhoff’s first rule: at any node, sum of the currents in = sum of the currents out (conservation of charge at node...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
hoff’s law: „ EMF supplied by capacitor C: V=Q/C „ NB: this is true at any moment in time tage drop on the resistor: -IR „ Vol Æ Q(t) Æ V(t) Q C − IR 0 = „ Not useful in this form since I=I(Q) „ I=-dQ/dt (- sign because C is losing charge) Q dQ + dt C 0R = „ Easy integral yields to exponential de...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
[C]=C/V; A=C/s Æ [RC]=s Æ [RC]=s „ Derive the current: ( ) I t = − dQ dt = − Q 0 t RC d dt − e ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ = Q 0 RC t RC − e „ Same exponential decay as for Q(t) G. Sciolla – MIT 8.022 – Lecture 9 7 Charging capacitors „ Now 3 elements in circuit: EMF, capacitor and resistor „ Capacito...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
Details of integration To solve dQ dt Setting: Q'= Q CV − R + − = V 0 , rewrite as: Q C dQ dt = − Q CV ( − RC ) ' dQ Q ' Integrating between t=0 and t: ⇒ = − dt RC Q Q t = ( ) ∫ Q = 0 t dQ ' ∫ = − Q ' t t = = 0 dt RC ⇒ ln Q t CV ( ) - CV - = − t RC ⇒ Q CV ( ) - t V C ...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
= ⎜ ⎝ − t R C − e ⎞ ; ⎟ ⎠ I ( ) t = t R C − e V R „ Are Kirchhoff’s laws valid at any moment in time? V − Q C − IR V = − V t R C − e ⎛ 1 ⎜ ⎝ − ⎞ ⎟ ⎠ − R t R C − e V R = 0 O K ! „ Asymptotic behavior of the capacitor: „ At t=0: I=V/R as if C were a short circuit „ At t=infinit...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
=V EMV when t=15.2 t G. Sciolla – MIT 8.022 – Lecture 9 13 Verify time constant (E8) „ „ RC circuit with „ VEMF = squared 5 V pulses Variable C initially = 0.3 µF Variable R initially = 400 Ω „ „ 2 „ R1 = 100 Ω Display on scope V C and I(R1) Verify that time constant is RC „ VC(t) 5V 1-e-t/RC ...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
R1 V + - s R2 + - C „ Calculate Q(t) on the capac itor „ Solution: „ „ Kirckhoff’s laws will solve it: TEDIOUS! Use Thevenin’s Theorem G. Sciolla – MIT 8.022 – Lecture 9 16 8 Thevenin equivalence Thevenin’s theorem: Any combination of resistors and EMFs with 2 terminals can be replaced with a seri...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
i Æ R1 V + - R2 A B RT VOC + - + - C „ Prove that R T=VOC/I short short= current through shorted terminals „ „ There is on y one current go ng through the reduced c rcuit At t=0, C behaves like a short At t=0 I short=VOC/RT Æ i l with I i Æ RT=VOC/I short G. Sciolla – MIT 8.022 – Lecture 9 18 9 ...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
in: „ When we have a messy system or resistors and EMFs, we can reduce it to a simple R+EMF in series just measuring Ishort and V open : VOC≡ + - RT Any unknown combination of Rs and EMFs Careful: „ Thevenin works only when the elements in the box follow Ohm’s law, i.e. on between V and I linear relati G....
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
~ open circuit: fluorescent light has a (very small) resistance R τcharge=RC FL „ Thevenin: R =RT discharge T=R//RFL~RFL C~R FLC<< „ τ G. Sciolla – MIT 8.022 – Lecture 9 22 11 Norton’s theorem Any combination of resistors and EMFs with 2 terminals can be replaced with a parallel of a current generator IN ...
https://ocw.mit.edu/courses/8-022-physics-ii-electricity-and-magnetism-fall-2004/46de97e4978fc003565f683871741451_lecture9.pdf
Lecture 8 Primitive Roots (Prime Powers), Index Calculus Recap - if prime p, then there’s a primitive root g mod p and it’s order mod p is p − 1 = qe1 e2 1 q2 . . . qr . We showed that there are integers gi mod p with order i − 1 ≡ 0 mod p). Set g = (cid:81) gi - qei (counting number of solutions to xq i exactly i (cid...
https://ocw.mit.edu/courses/18-781-theory-of-numbers-spring-2012/4725535fce239230067825c86e89afaa_MIT18_781S12_lec8.pdf
ure 37 (Artin’s Conjecture). Let a be a natural number, which is not a square. Then there are infinitely many primes p for which a is a primite root mod p. This is an open question. Hooley proved this conditional on GRH, and Heath- Brown showed that if a is a prime, then there are at most 2 values of a which fail the co...
https://ocw.mit.edu/courses/18-781-theory-of-numbers-spring-2012/4725535fce239230067825c86e89afaa_MIT18_781S12_lec8.pdf
1 (d,p−1) = (d, p − 1) Similarly, if we’re trying to solve the congruence xd ≡ a mod p (a (cid:54)≡ 0 mod p), we can write a ≡ gl mod p so if x ≡ gk as before then gkd ≡ gl mod p. This means that gkd−l ≡ 1 mod p ↔ p − 1|kd − l ↔ kd ≡ l mod p − 1 (k is variable), which has a solution iff (d, p − 1) divides l, in which c...
https://ocw.mit.edu/courses/18-781-theory-of-numbers-spring-2012/4725535fce239230067825c86e89afaa_MIT18_781S12_lec8.pdf
+ tp). Since ordp(g + tp) is a multiple of p − 1 and divides p(p − 1), it’s either equal to p − 1 or equal to p(p − 1) = φ(p2). We’ll show that there’s exactly one value of t for which the former happens. 2 Since there are p possible values of t(0 ≤ t ≤ p − 1), any of these remaining ones give a g + tp which is a primi...
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we know it for e. We know that φ(pe−1) = pe−2(p gφ(pe−1) show it for e + 1 - ie., (cid:54)≡ 1 mod e. In other words gφ(p gφ(p ) (cid:54)≡ 1 mod pe+1. − p e 1). So gφ(pe−1) e−1 ≡ 1 mod pe−1 assuming that ) = 1 + bpe−1 with p (cid:45) b. Need to We know that gpe−2(p−1) = 1 + bpe−1. Raising to power p we get gpe−1(p−1) = ...
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: otherwise, if n = mm(cid:48) with m and m(cid:48) coprime and m, m(cid:48) > 2, we’ll show there does not exist a primitive root mod m. By hypothesis (m, m(cid:48) > 2) we know φ(m) and φ(m(cid:48)) are even. So for (a, n) = 1, 3 we have (a, m) = 1 = (a, m(cid:48)). So aφ(m) ≡ 1 mod m and aφ(m(cid:48)) ≡ 1 mod m(cid:...
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MIT OpenCourseWare http://ocw.mit.edu 6.189 Multicore Programming Primer, January (IAP) 2007 Please use the following citation format: Saman Amarasinghe, 6.189 Multicore Programming Primer, January (IAP) 2007. (Massachusetts Institute of Technology: MIT OpenCourseWare). http://ocw.mit.edu (accessed MM DD, YYYY). ...
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different machines Prof. Saman Amarasinghe, MIT. 3 6.189 IAP 2007 MIT Concurrency and Parallelism ● Concurrency is not (only) parallelism ● Interleaved Concurrency „ Logically simultaneous processing B „ Interleaved execution on a single C processor A ● Parallelism „ Physically simultaneous processing „ ...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
); atm.run(); } Prof. Saman Amarasinghe, MIT. public void run() { while(true) { try { out.print("AccountID >“ ); String id = in.readLine(); String acc = bnk.get(id); if (acc == null) throw new Exception(); out.print("Password>“ ); String pass = in.readLine(); if (!acc.is_password(pass)) throw new Exception(...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
new Exception(); out.print("Password>“ ); String pass = in.readLine(); if (!acc.is_password(pass)) throw new Exception(); out.print(“yourbalance is“ + acc.getbal()); out.print("Depositor withdraw amount > “ int val = in.read(); if (acc.getbal() + val > 0) acc.post(val); else throw new Exception(); out.print...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
; import java.io.*; public class ATM { static Bank bnk; PrintStream out; BufferedReader in; ATM(PrintStream out, BufferedReader in) { this.out = out; this.in = in; } public static void main(String[] args) { bnk = Bank.getbank(); BufferedReader stdin = new BufferedReader (new InputStreamReader(System.in)); AT...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
; i++){ atm[i] = new ATMs(i, outdevice(i), indevice(i)); atm[i].start(); } } } } public void run() { while(true) { try { out.print("AccountID >“ ); String id = in.readLine(); String acc = bnk.get(id); if (acc == null) throw new Exception(); out.print("Password>“ ); String pass = in.readLine(); if (!acc.is_password...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
89cell Your account balance is 100 Deposit or Withdraw amount > Your account balance is 10 -90 Your account balance is 10 Prof. Saman Amarasinghe, MIT. 14 6.189 IAP 2007 MIT Activity trace II balance 100 ATM 1 out.print(“yourbalance is“ + acc.getbal()); Your account balance is 100 out.print("Depositor withdra...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
MIT. 16 6.189 IAP 2007 MIT Synchronization ● All the interleavings of the threads are NOT acceptable correct programs. ● Java provides synchronization mechanism to restrict the interleavings ● Synchronization serves two purposes: „ Ensure safety for shared updates – Avoid race conditions „ Coordinate actions...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
critical section at a given time „ Once a thread is in the critical section, no other thread can enter that critical section until the first thread has left the critical section. „ No interleavings of threads within the critical section „ Serializes access to section synchronized int getbal() { return balance; ...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
Amarasinghe, MIT. 23 6.189 IAP 2007 MIT Synchronizing a block import java.util.*; import java.io.*; public class ATMs extends Thread { static final int numATMs = 1; static Bank bnk; PrintStream out; BufferedReader in; int atmnum; ATMs(int num, PrintStream out, BufferedReader in) { this.out = out; this.in ...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
account balance is 100 out.print("Depositor withdraw amount >“); Deposit or Withdraw amount > -90 int val = in.read(); synchronized(acc) if (acc.getbal() + val > 0) acc.post(val); out.print(“yourbalance is“ + acc.getbal()); Your account balance is 10 ala n c e s h o u t c o uld B b ATM 2 out.print(“yourbalan...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
(); out.print("Password>“ ); String pass = in.readLine(); if (!acc.is_password(pass)) throw new Exception(); synchronized (acc) { out.print(“yourbalance is “ + acc.getbal()); out.print("Depositor withdraw amount >“ ); int val = in.read(); if (acc.getbal() + val > 0) acc.post(val); else throw new Exception(); ...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
) Waiting for Ben’s account to be released to perform BenÆAllysa synchronized(from) if (from.getbal() > val) from.post(-val); synchronized(to) Waiting for Allyssa’s account to be released to perform DEADLOCKED! Prof. Saman Amarasinghe, MIT. 29 6.189 IAP 2007 MIT Avoiding Deadlock ● Cycle in locking graph =...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
synchronized(first) { synchronized(second) { if (from.getbal() > val) from.post(-val); else throw new Exception(); to.post(val); } } } … Prof. Saman Amarasinghe, MIT. 32 6.189 IAP 2007 MIT Races Race conditions – insidious bugs „ Non-deterministic, timing dependent „ Cause data corruption, crashes „ ...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
� Depends on interleaving of threads ● Usual way to avoid data races: mutual exclusion „ Ensures serialized access of all the shared objects Prof. Saman Amarasinghe, MIT. 37 6.189 IAP 2007 MIT Dining Philosophers Problem ● There are 5 philosophers sitting at a round table. ● Between each adjacent pair of phil...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
MIT. 39 6.189 IAP 2007 MIT Dining Philosophers Problem: Take I public void run() { try { while(true) { 1 2 3 synchronized(left) { synchronized(right) { System.out.println(times + ": Philosopher " + position + " is done eating"); } } } } catch (Exception e) { System.out.println("Philosopher " + position ...
https://ocw.mit.edu/courses/6-189-multicore-programming-primer-january-iap-2007/473fa522f1a7a03c89130c6de55ebc51_lec4concurrency.pdf
„ Semaphores „ Blocking & non-blocking queues „ Concurrent hash maps „ Copy-on-write arrays „ Exchangers „ Barriers „ Futures „ Thread pool support Prof. Saman Amarasinghe, MIT. 43 6.189 IAP 2007 MIT Potential Concurrency Problems ● Deadlock „ Two or more threads stop and wait for each other ● Livelock „...
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3.044 MATERIALS PROCESSING LECTURE 9 Example 1: Casting into low conductivity molds Greatly simplified if: 1. Mold is thick → can neglect air → semi-infinite geometry → erf 2. Mold controls heat loss → Tmold increases → kmold decreases → 3. Superheating is negligible → liquid poured at Tm gradients are in mold D...
https://ocw.mit.edu/courses/3-044-materials-processing-spring-2013/47576d530e3a052c0c3b2451f4076eb6_MIT3_044S13_Lec09.pdf
− Tm) ρsHf (cid:2) k mρmcp,m t (cid:3) 1 2 s = 2(T0 − Tm) ρsHf Boundary Condition: @t = 0, s = 0 Boundary Condition: @s = L, t = tf 3.044 MATERIALS PROCESSING 3 tf ∝ L2 V A (cid:2) L ≈ tf ∝ V A (cid:3) 2 ⇒ Chvorinov’s Rule Example 2: Thin castings / Cold molds / Highly conductive molds out (cid:9) (cid:6) (cid:7)(cid:...
https://ocw.mit.edu/courses/3-044-materials-processing-spring-2013/47576d530e3a052c0c3b2451f4076eb6_MIT3_044S13_Lec09.pdf
Machine Learning for Healthcare HST.956, 6.S897 Lecture 5: Risk stratification (continued) David Sontag 1 Outline for today’s class 1. Risk stratification (continued) – Deriving labels – Evaluation – Subtleties with ML-based risk stratification 2. Survival modeling 2 Where ...
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True positive rate Area under the ROC curve Full model (AUC) Traditional risk factors AUC = Probability that algorithm ranks a positive patient over a negative patient Invariant to amount of class imbalance Diabetes 1-year gap False positive rate 8 ...
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Wang J, Cheng YJ, et al. Prevalence and Incidence Trends for Diagnosed Diabetes Among Adults Aged 20 to 79 Years, United States, 1980-2012. JAMA, 2014.] © American Medical Association. All rights reserved. This content is excluded from our Creative Commons license. For more information, see https://ocw.mit.edu/help/f...
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from our Creative Commons license. For more information, see https://ocw.mit.edu/help/faq-fair-use/ 15 Intervention-tainted outcomes • Example from today’s readings: – Patients with pneumonia who have a history of asthma have lower risk of dying from pneumonia – Thus, we le...
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is through the language of causality: Patient, (everything we know at triage) Intervention, (admit to the ICU?) ? Outcome, (death) Will admission to ICU lower likelihood of death for patient? • We return to this in Lecture 14 19 No big wins from...
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mHOSPITAL3) at discharge 0.77(0.75-0.78) 0.75 (0.73-0.76) 0.74 (0.73-0.76) 0.70 (0.68-0.72) 0.76(0.75-0.77) 0.75 (0.74-0.76) 0.73 (0.72-0.74) 0.68 (0.67-0.69) Length of Stay at least 7 days AUROC (95% CI) Deep learning 24 hours after admission Full feature enhanced baseline at 24 hours after admission Full feature simp...
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0.95( (0.94-0.96 0.93 (0.92-0.95) 0.93 (0.91-0.94 ( -0.89 ( 0.85 (0.81 0.93( (0.92 (0.89 0.91 ( 0.90 (0.88 ( ( (0.83 0.86 -0.94 -0.92 -0.92 -0.88 30-day Readmission, AUROC (95% CI) Keep2 in mind: Small wins with deep models may disappear altogether with dataset shift or non-stationarity (Jung & S3hah, JBI ‘15) Deep l...
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.82-0.84 ( ((0.75 -0.77 0.76 -0.86 (0.85 0.85( 0.83 ( (0.83 -0.84 0.81 ( (0.80 -0.82 0.74 ((0.73-0.75 1 Area under the receiver operator curve [Rajkomar et al. ‘18 electronic supplementary material: h 1 ttps://static-content.spring /MediaObjects/41 746_2018_29_MOESM1_ESM.pdf] er.com/esm/art%3A10.1038%2Fs41746-018-0029-...
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/help/faq-fair-use/ 25 Survival modeling • Why not use classification, as before? – Less data for training (due to exclusions) – Pessimistic estimates due to choice of window • What about regression, e.g. minimizing mean- squared error? – T is non-negative, may want long tails – If...
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12 IEEE TRANSACTIONS ON WIRELESS COMMUNICATIONS, VOL. 3, NO. 1, JANUARY 2004 A Laguerre Polynomial-Based Bound on the Symbol Error Probability for Adaptive Antennas With Optimum Combining Marco Chiani, Senior Member, IEEE, Moe Z. Win, Fellow, IEEE, Alberto Zanella, Member, IEEE, and Jack H. Winters, Fellow, IEEE ...
https://ocw.mit.edu/courses/18-996-random-matrix-theory-and-its-applications-spring-2004/4770a22e0087ba5d8439e0be8fd8fdaa_oc_laggure_tw.pdf
present. Closed-form expressions for the bit-error probability (BEP) for coherent detection of binary phase-shift keying (PSK) have been derived for the case of a single nonfading interferer with Rayleigh fading of the desired signal in [1] and [2] and with Rayleigh fading of the desired signal and a single interf...
https://ocw.mit.edu/courses/18-996-random-matrix-theory-and-its-applications-spring-2004/4770a22e0087ba5d8439e0be8fd8fdaa_oc_laggure_tw.pdf
J. H. Winters was with the Wireless Systems Research Department, AT&T Laboratories—Research, Middletown, NJ 07733 USA. He is now with Jack Winters Communications, LLC, Middletown, NJ 07748-2070 USA Digital Object Identifier 10.1109/TWC.2003.821165 multiple interferers of arbitrary powers, closed-form expressions o...
https://ocw.mit.edu/courses/18-996-random-matrix-theory-and-its-applications-spring-2004/4770a22e0087ba5d8439e0be8fd8fdaa_oc_laggure_tw.pdf
of the bound can be an issue. In this letter, starting from an approach similar to that used in [5], we apply some results on the characteristic polynomial of a complex Wishart matrix to derive new simple upper bounds on the symbol error probability (SEP) for coherent detection of -ary PSK using OC in the presence...
https://ocw.mit.edu/courses/18-996-random-matrix-theory-and-its-applications-spring-2004/4770a22e0087ba5d8439e0be8fd8fdaa_oc_laggure_tw.pdf
Filter A/D Filter A/D OC γ represents a unitary transforma­ as the elements of tion. Consequently, the SINR given in (2) can be rewritten as , since (4) D N A Filter A/D values of the Desired Signal Fig. 1. Baseband model of the OC receiver. By introducing the notation and , it is simple to show that t...
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(2) where the short-term covariance matrix interference propagation vectors, is given by , conditioned on all (3) It is important to remark that , and consequently also the , vary at the fading rate, which is assumed to be much is a random matrix, and slower than the symbol rate. Thus, its eigenvalues are ran...
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the principal diagonal are the eigenvalues of by . The elements of the vector is is a diagonal matrix whose elements , denoted , where have the same complex Gaussian distribution with � � �, where � 2Let us define � � � is the set of the ��2�� complex matrices, and �� � , th elements of are complex values ...
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the characteristic polynomial of a complex Wishart matrix can be written as and therefore (18) (19) The derivation of the exact SEP, requiring the evaluation of statistical expectation of (11) with respect of the eigenvalues distribution [9], is not a simple task. In the following theorem, we derive a new upper...
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the absence of interference reduces to that of MRC. (or equivalently as In general, by expanding the Laguerre polynomial, it can be seen that (15) (20) IEEE TRANSACTIONS ON WIRELESS COMMUNICATIONS, VOL. 3, NO. 1, JANUARY 2004 15 10 0 10-1 10-2 10-3 P E S 10-4 10-5 10-6 10-7 SIR=10 dB, NA=4, BPSK 0 1...
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the exact error probability for MRC multiplied by a number greater than or equal to unity; this number, given by (19), represents an upper bound on the increase in SEP due to the presence of interfering signals. Note also that the definite integral in (14) can be evaluated in closed form using a canonical decompo...
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2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 SIR [dB] Fig. 3. SEP versus SIR, with SNR as a parameter ranging from 0 to 15 dB; � � �, � � �, and BPSK modulation. P E S 0 10 -1 10 -2 10 -3 10 -4 10 -5 10 -6 10 -7 10 8 –PSK, NI =3, SIR=15 dB NA=3 NA=6 NA=3, OC (Bound) NA=3, MRC (Exact) NA=6, OC (Bound) NA=6, MRC...
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are Monte Carlo simulation results for OC. The results show that, as expected, for small SNR, the thermal noise is dominant and, therefore, MRC and OC perform similarly. On the other hand, for sufficiently large SNR, the role of OC in exploiting the capability of the antenna array is of increasing importance. This...
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the 8 PSK. The curves are for two asymptotes (vertical and horizontal) give the values of SIR and SNR without thermal noise and interference, respectively. The region below each curve represents the outage domain re­ gion in which all points produce an SEP higher than target SEP; therefore, if the probability dist...
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in space-diversity reception,” Telecommun. Radio Eng., vol. 34/35, pp. 83–85, Oct. 1980. [2] J. H. Winters, “Optimum combining in digital mobile radio with cochannel interference,” IEEE J. Select. Areas Commun., vol. SAC-2, pp. 528–539, July 1984. [3] V. A. Aalo and J. Zhang, “Performance of antenna array systems ...
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multiple antennas,” Bell Labs Tech. J., vol. 1, no. 2, pp. 41–59, Autumn 1996. [8] G. J. Foschini and M. J. Gans, “On limits of wireless communications in a fading environment when using multiple antennas,” IEEE Wireless Pers. Commun., vol. 6, pp. 311–335, Mar. 1998. [9] M. Chiani, M. Z. Win, A. Zanella, and J. H....
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Poor and S. Verdú, “Probability of error in MMSE multiuser de­ tection,” IEEE Trans. Inform. Theory, vol. 43, pp. 858–871, May 1997. [14] M. Z. Win, G. Chrisikos, and J. H. Winters, “MRC performance for � -ary modulation in arbitrarily correlated Nakagami fading channels,” IEEE Commun. Lett., vol. 4, pp. 301–303, Oc...
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with unequal fading parameters and SNRs among branches: An analytical framework,” in Proc. IEEE Wireless Communi­ cations and Networking Conf., vol. 3, New Orleans, LA, Sept. 1999, pp. 1058–1064. [21] M. Z. Win, R. K. Mallik, G. Chrisikos, and J. H. Winters, “Canonical expressions for the error probability performa...
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6.720J/3.43J Integrated Microelectronic Devices - Spring 2007 Lecture 9-1 Lecture 9 - Carrier Flow (cont.) February 23, 2007 Contents: 1. Shockley’s Equations 2. Simplifications of Shockley equations to 1D quasi-neutral situations 3. Majority-carrier type situations Reading assignment: del Alamo, Ch. 5, §§5.3-5...
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Electron current equation: q (cid:2) E∇ · (cid:2) = (cid:2) (p − n + ND (cid:2) Je = −qn(cid:2)ve drift + qDe∇n (cid:2) −) + − NA Hole current equation: (cid:2) Jh = qp (cid:2)vh drift − qDh∇p (cid:2) Electron continuity equation: ∇ · J(cid:2) (cid:2) ∂t = Gext − U (n, p) + 1 ∂n e q Hole continuity equa...
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) ∇ ⇒ ∂ ∂x n+ y x Cite as: Jesús del Alamo, course materials for 6.720J Integrated Microelectronic Devices, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded on [DD Month YYYY]. 6.720J/3.43J Integrated Microelectronic Devices - Spring 2007 Lecture 9-...
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20J/3.43J Integrated Microelectronic Devices - Spring 2007 Lecture 9-6 Overview of simplified carrier flow formulations General drift-diffusion situation (Shockley's equations) 1D approx. Quasi-neutral situation (negligible volume charge) Space-charge situation (field independent of n, p) Majority-carrier ...
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cy of the concentration of positive and negative species is negligible in the scale of the charge density that is present. QN approximation eliminates Gauss’ law from the set: + ρ = q(p − n + N D − N − A ) = q(po − no D+ N − N − + A ) + q(p (cid:5) − n (cid:5)) • Quasi-neutrality in equilibrium: | + po − no + N...
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5) = (po − no + ND −) + − NA q (cid:5) If, in general define: Then, in equilibrium: ∂Eo ∂x and out of equilibrium: ∂E (cid:5) ∂x = (p (cid:5) − n (cid:5)) q (cid:5) Eo computed as in Ch. 4. Here will learn to compute E (cid:5) . Cite as: Jesús del Alamo, course materials for 6.720J Integrated Microelectroni...
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0J/3.43J Integrated Microelectronic Devices - Spring 2007 Lecture 9-11 Simplified set of Shockley equations for 1D quasi-neutral situations p − n + ND − NA (cid:4) 0 Je = −qnve drift + qDe ∂n ∂x Jh = qpv h drift − qDh ∂p ∂x ∂n = Gext − U + 1 ∂Je q ∂x ∂t or ∂Jh ∂p 1 ∂t = Gext − U − q ∂x ∂Jt (cid:4) 0 ∂x...
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Month YYYY]. 6.720J/3.43J Integrated Microelectronic Devices - Spring 2007 Lecture 9-13 � Characteristics of majority carrier-type situations: • electric field imposed from outside • electrons and holes drift • electron and hole concentrations unperturbed from TE Simplifications: • neglect contribution of minorit...
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� Equation set for 1D majority-carrier type situations: n-type n (cid:4) no (cid:4) ND p-type p (cid:4) po (cid:4) NA Je = −qno[vde(E) − vde(Eo)] Jh = qpo[vdh(E) − vdh(Eo)] dJe (cid:4) 0, dx dJh (cid:4) 0, dJt (cid:4) 0 dx dx Jt (cid:4) Je Jt (cid:4) Jh Cite as: Jesús del Alamo, course materials for 6.720J Int...
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• In general (low and high fields): vsat I = W tqND 1 + vsat L μe V which for high fields saturates to: Isat = W tqNDvsat I Isat 0 0 V Cite as: Jesús del Alamo, course materials for 6.720J Integrated Microelectronic Devices, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Tec...
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form of continuity equations and consequences. • Exercises 5.1, 5.2. • Non-uniformly doped resistor • Sheet resistance Cite as: Jesús del Alamo, course materials for 6.720J Integrated Microelectronic Devices, Spring 2007. MIT OpenCourseWare (http://ocw.mit.edu/), Massachusetts Institute of Technology. Downloaded o...
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Introduction to Algorithms: 6.006 Massachusetts Institute of Technology Instructors: Erik Demaine, Jason Ku, and Justin Solomon Lecture 1: Introduction Lecture 1: Introduction The goal of this class is to teach you to solve computation problems, and to communicate that your solutions are correct and efficient. Pr...
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: if first k contain match, returns match before interviewing student k + 1 – Base case: k = 0, first k contains no match – Assume for induction hypothesis holds for k = k0, and consider k = k0 + 1 – If first k0 contains a match, already returned a match by induction – Else first k0 do not have match, so if first k0 + 1...
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2Θ(nc) 21000 ≈ 10301 10281 millenia Lecture 1: Introduction Model of Computation 3 • Specification for what operations on the machine can be performed in O(1) time • Model in this class is called the Word-RAM • Machine word: block of w bits (w is word size of a w-bit Word-RAM) • Memory: Addressable sequence of...
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�(1) time – StaticArray.set at(i, x): write word x to array index i in Θ(1) time • Stored word can hold the address of a larger object • Like Python tuple plus set at(i, x), Python list is a dynamic array (see L02) 4 Lecture 1: Introduction 1 def birthday_match(students): 2 ’’’ Find a pair of students with th...
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) + • Quadratic in n is polynomial. Efficient? Use different data structure for record! How to Solve an Algorithms Problem 1. Reduce to a problem you already know (use data structure or algorithm) Search Problem (Data Structures) Static Array (L01) Linked List (L02) Dynamic Array (L02) Sorted Array (L03) Direct...
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Assignments Problems Sets: • Problem Set 2 (Scheduling) due • Problem Set 3 (PDDL Modeling) out soon Readings: • Hoffman, Porteous, Sebastia, “Ordered Landmarks in Planning,” Journal of Artificial Intelligence Research, 22, pp. 215-278, 2004. (Voted most influential paper during ICAPS 2013). Karpas, et al., “Temporal ...
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St action1 action2 … action2 Alone on Mars at Ares 3 1 St action4 Be Rescued action3 2 St action2 2/24/2016 Cognitive Robotics 4 Motivation Have enough food and water Get the Rover ready for long trips Alone on Mars at Ares 3 Have MAV ready Be Rescued Re-Establish communication Drive to Ares 4 Be at Are...
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communication – To get to the rover, I need to exit this the Hab © 20th Century Fox. All rights reserved. This content is excluded from our Creative Commons license. For more information, see https://ocw.mit.edu/help/faq-fair-use/. 2/24/2016 Cognitive Robotics 10 Fact and Action Landmarks • We can also consider disjun...
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A →gn B, iff A true one step before B becomes true for the first time • Other ordering types exist, which we do not discuss • Note that: A →n B ⟹ A →gn B ⟹ A → B 2/24/2016 Cognitive Robotics 15 Outline • What Landmarks Are • How Landmarks Are Discovered • Using Landmarks – Subgoals – Heuristic Estimates – Admissible ...
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/2016 Cognitive Robotics 20 Landmark Discovery (1) Step 1: Find landmarks candidates and orderings – Start with the goals: every goal is a landmark – If B is landmark and all actions that achieve B share A as precondition, then • A is a landmark • A →n B • Useful restriction: consider only the case where B is achie...
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t-at-B t-at-A t-at-D 2/24/2016 Cognitive Robotics 25 Landmark Discovery (1) Step 1: Find landmarks candidates and orderings Example E A B C D Landmark: t-at-D t-at-A drive-t-A-E drive-t-A-B t-at-E t-at-B t-at-A drive-t-E-D drive-t-B-C drive-t-A-E drive-t-A-B t-at-D t-at-C t-at-E t-at-B t-at-A t-at-E t-at-D 2/24/2016 ...
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Robotics 28 Landmark Discovery (1) Step 2: Verify Landmark Candidates • For each landmark discovered: – Remove all the action that can achieve it – Build relaxed planning graph for π’A and check if we can find the goals – If so, remove landmark and ordering from the landmark graph o-at-B t-at-B o-in-t t-at-C p-at-C ...
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a SAS+ task < V, A, s0, G > • The DTG of variable v ∈V (DTGv) represents how the value of v can change. • DTGv is a directed graph with nodes Dv that has arc <d, d’> iff: – d ≠ d’ , and – ∃ action with v ↦ d’ as effect, and either – v ↦ d as precondition, or no precondition on v 2/24/2016 Cognitive Robotics 34 Landma...
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↦ d’ ) → ( v ↦ d ) 2/24/2016 Cognitive Robotics 38 Landmark Discovery (3) Find landmarks through forward propagation in relaxed planning graph • Propagate information on necessary predecessors – Label each fact node with itself – Propagate labels along arcs • • Finds causal landmarks only (preconditions for actions) ...
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,d d a,b 4 a,c,d 5 a,d 6 a,b,e e a,c,d,f f a,g g a 2/24/2016 Cognitive Robotics 43 Landmark Discovery (3) Facts Actions Facts Actions Facts a 1 a 2 a 1 a,b b a,c c a,d d a,b 4 a,c,d 5 a,d 6 a,b,e e a,c,d,f f a,g g a 2/24/2016 Cognitive Robotics 44 Landmark Discovery (3) Facts Actions Facts Actions Facts a 1 a 2 a 1 a...
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missible Heuristic Estimates – Enriching the Problem – Beyond Classical Planning • Summary 2/24/2016 Cognitive Robotics 47 Using Landmarks • So what can we do once we have these landmarks? • We assume that landmarks and orderings are discovered in a pre-processing phase, and the same landmark graph is used throughou...
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-B t-at-B o-in-t t-at-C p-at-C o-at-C o-in-p o-at-E Partial Plan: drive-t-B Goal: o-in-t ∨ p-at-C 2/24/2016 Cognitive Robotics 53 Using Landmarks: Subgoals p E C A D B o t Partial Plan: drive-t-B, load-o-t Goal: t-at-C ∨ p-at-C o-at-B t-at-B o-in-t t-at-C p-at-C o-at-C o-in-p o-at-E 2/24/2016 Cognitive Robotics 54 Us...
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Using Landmarks: Subgoals B A D o E p C t o-at-B t-at-B o-in-t t-at-C p-at-C o-at-C o-in-p o-at-E Partial Plan: drive-t-B, load-o-t, drive-t-C, unload-o-C, fly-p-C, load-o-p Goal: o-at-E 2/24/2016 Cognitive Robotics 58 Using Landmarks: Subgoals B A D C t p E o-at-B t-at-B o-in-t t-at-C o p-at-C o-at-C o-in-p o-at-E P...
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holding-A on-B-C on-A-B Partial Plan: pickup-B Goal: clear-A ∨ on-B-C 2/24/2016 Cognitive Robotics 63 Using Landmarks: Subgoals on-table-A on-C-A clear-C hand-empty on-table-B clear-B B C A clear-A holding-B holding-A on-B-C on-A-B Partial Plan: pickup-B, stack-B-C Goal: clear-A 2/24/2016 Cognitive Robotics 64 Using ...
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on-table-A on-C-A clear-C hand-empty on-table-B clear-B A B C clear-A holding-B holding-A on-B-C on-A-B Partial Plan: pickup-B, stack-B-C, unstack-B-C, putdown-B, unstack-C-A, putdown-C, pickup-A, stack-A-B, unstack-A-B, putdown-A, pickup-B, stack-B-C, pickup-A, stack-A-B Goal: ∅ 2/24/2016 Cognitive Robotics 68 Using...
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LAMA Approach • The landmarks that still need to be achieved after reaching state s via path π are: L(s, π) = ( L \ Accepted(s, π)) ⋃ ReqAgain(s, π) • L is the set of all (discovered) landmarks • Accepted(s, π) ⊂ L is the set of accepted landmarks • ReqAgain(s, π) ⊆ Accepted(s, π) is the set of required again landmar...
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and so it is required again on-B-C on-A-B 2/24/2016 Cognitive Robotics 76 Multi-path Dependency I did not achieved A I achieved A I need to achieved A • Suppose state s was reached by paths π1, π2 • Suppose π1 achieved landmark A and π2 did not • Then A needs to be achieved after state s • Proof: A is a landmark, ther...
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: assign the right cost to each landmark, sum over the costs of landmarks (Karpas and Domshlak, 2009) 2/24/2016 Cognitive Robotics 80 Admissible Heuristic Estimates: Conditions for Admissibility • Each action shares its cost between all the landmarks it achieves ∀a ∈ A: ∑ cost(a, A) ≤ C(a) A ∈ L(a | s ,P) cost(a, A)...
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: can be much worse than the optimal cost partitioning 2/24/2016 Cognitive Robotics 84 Admissible Heuristic Estimates: Uniform Cost Sharing • Advantage: Easy and fast to compute • Disadvantage: can be much worse than the optimal cost partitioning Uniform cost sharing hL = 2.5 min(0.5)=0.5 min(0.5)=0.5 min(0.5)=0....
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uristic Estimates: How we can get better? • So far: – Uniform cost sharing is easy to compute, but suboptimal – Optimal cost sharing takes a long time to compute • Q: How can we get better heuristic estimates that don’t take a long time to compute? A: Exploit additional information - action landmarks 2/24/2016 Cogniti...
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, 2009) • These temporally extended goals can be expressed in Linear Temporal Logic (LTL) • Each LTL formula can be compiled into a finite-state automaton (FSA) • Each FSA can be encoded as a single variable in an enriched planning problem 2/24/2016 Cognitive Robotics 94 Using Landmarks: Enriching the Problem A Si...
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is a fact which must be true in every successful trajectory (possible execution) • Temporal Landmarks 2/24/2016 Cognitive Robotics 98 Temporal Landmarks 2/24/2016 Cognitive Robotics 99 Landmarks for Temporal Planning • We can treat a durative action as two “snap” actions: the start and the end (Fox & Long, 2003) • ...
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-flashlight 2/24/2016 Cognitive Robotics 104 Durative Action: Turn On Flashlight Duration: 1 seconds Start: Condition: have-flashlight Effect: Invariant condition: End: Condition: Effect: light 2/24/2016 Cognitive Robotics 105 Causal Landmarks for Flashlight Match Cellar If we run a casual landmark discovery, we w...
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