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use a set of derivation rules for this 2/24/2016 Cognitive Robotics 110 Temporal Relaxed Planning Graph . lb up Action1 Action2 Action3 Fact1 Fact2 Fact3 … Fact4 Fact1 Fact2 Fact3 … 2/24/2016 Cognitive Robotics 111 • Temporal Landmarks for Flashlight Match Cellar • The goal must hold from some time point g until the...
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holds(light) START (fix-fuse) END (fix-fuse) holds(fuse-fixed) E 2/24/2016 Cognitive Robotics 113 Temporal Landmarks for Flashlight Match Cellar • The only possible achiever of have-flashlight is END(find-flashlight), so – occursshf(END(find-flashlight) The find-flashlight action must start – occurssf(START(find-flash...
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Temporal Landmarks Derivation Rules • If fact F must hold for a duration of d, then: – F must be achieved. Furthermore, this must be by an action which does not delete F at the end, if its duration is shorter than d. – F must be achieved for the first time • Every action must have a start and an end. Its invariant co...
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0 20 4 0 9 0 53 20 20 4 0 8 0 52 matchcellar (2011) matchcellar (2014) tms (2011) tms (2014) turnandopen (2011) turnandopen (2014) TOTAL 20 20 0 0 19 7 66 20 20 2 0 19 1 62 18 20 0 0 0 0 38 0 0 0 0 0 0 0 Number of solved problems 2/24/2016 Cognitive Robotics 119 (Interesting) Results on Non-Temporally Expressive Do...
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19 5 5 17 17 6 5 0 0 openstacks (2011) 20 20 20 parcprinter (2011) 10 0 0 parking (2011) parking (2014) pegsol (2011) satellite (2014) sokoban (2011) 20 10 10 20 20 19 19 19 17 5 8 1 0 1 0 6 6 0 0 0 0 0 0 0 0 0 TOTAL 173 139 61 12 orig e1 e4 e ∞ driverlog (2014) elevators (2011) floortile (2011) floortile (2014)...
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14) – Oversubscription Planning (Mirkis & Domshlak, 2014) – Temporal planning • At least, when the problems are temporally expressive 2/24/2016 Cognitive Robotics 121 … 2/24/2016 Cognitive Robotics 122 MIT OpenCourseWare https://ocw.mit.edu 16.412J / 6.834J Cognitive Robotics Spring 2016 For information about citing ...
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Lecture 3 8.321 Quantum Theory I, Fall 2017 11 Lecture 3 (Sep. 13, 2017) 3.1 Even More Math 3.1.1 More on Matrix Representations Last time, we described that in a given basis, there is an exact correspondence between n×n matrices and operators, where n is the dimension of the Hilbert space. Let {|a(cid:105)} form an or...
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, then Aii = ai, so the trace becomes Tr A = (cid:88) ai . i (3.4) (3.5) This is a statement of the familiar fact that the trace of an operator is the sum of its eigenvalues. 3.1.2 Unitary Transformations Suppose we are given two orthonormal bases {|ai(cid:105)} and {|bi(cid:105)}. How are these bases related? We can d...
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(cid:105)} and {|bi(cid:105)}. We can express |α(cid:105) in two ways as |α(cid:105) = (cid:88) i ci |ai(cid:105) = (cid:88) i di |bi(cid:105) . (3.11) How are these two sets of coefficients {ci} and {di} related? Using the definition of U , we can write |α(cid:105) = = = (cid:88) j (cid:88) j (cid:88) i,j dj |bj(cid:105)...
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3.14) (3.15) Theorem 2. A Hermitian matrix Hij = (cid:104)φi|H|φj(cid:105) can always be diagonalized by a unitary trans- formation. Lecture 3 8.321 Quantum Theory I, Fall 2017 13 Proof. Consider a general orthonormal basis {|φi(cid:105)}, and let {|hi(cid:105)} be the orthonormal basis of eigenstates of the operator ...
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5) , (3.17) (3.18) and so AB = BA. This proves the forward direction. Now consider two diagonalizable operators A, B that commute, AB = BA, and let {|ai(cid:105)} be a basis of eigenvectors of A, Then we have A|ai(cid:105) = ai|ai(cid:105) . A(B|ai(cid:105)) = AB|ai(cid:105) = BA|ai(cid:105) = Bai|ai(cid:105) = ai(B|ai...
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on the diagonal of A. Diagonalizing the block Bi only mixes eigenkets of A with the same eigenvalue, so we can diagonalize B while leaving A diagonal. This proves the backward direction. Lecture 3 8.321 Quantum Theory I, Fall 2017 14 3.2 Measurement Consider a quantum mechanical system. We know that the state of such ...
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22) (3.23) (3.24) Historically, there has been a lot of worry about the collapse of the wavefunction. In the modern language, there is a way to understand this collapse in a very palatable way, which we may discuss later in the course. The concept of measurement is worth pondering. Consider making a measurement on a st...
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ψ(cid:105), the expectation value of A is (cid:88) (cid:104)A(cid:105) := ai Prob(A = ai) ai (cid:88) ai = (cid:88) ai j:a j =a i = (cid:104)ψ|A|ψ(cid:105) , | (cid:105) ψ aj aj ψ (cid:105)(cid:104) (cid:104) | (3.27) where in the final line we have used A = (cid:88) a i ai |ai(cid:105)(cid:104)ai| . (3.28) 3.3 Spin- 1 ...
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efficients in the form − R c+ = cos θ 2 , c− = eiφ sin θ 2 , (3.30) with 0 ≤ θ < π and 0 ≤ φ < 2π. Specifying these two angles specifies the state exactly, and we note that specifying these angles is equivalent to specifying a point on the surface of the unit sphere S2. This parametrization of the Hilbert space is known a...
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0 0 −1 , (3.33) Sx = Sy = (cid:126) 2 −i(cid:126) 2 (|+(cid:105)(cid:104)−| + |−(cid:105)(cid:104)+|) = (cid:126)σx 2 = (cid:126) 2 (cid:19) (cid:18)0 1 1 0 (cid:18) −i (cid:126) 0 0 i 2 (cid:19) (|+(cid:105)(cid:104)−| − |−(cid:105)(cid:104)+|) = (cid:126)σy 2 = We can check explicitly (left as an exercise) that these...
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MIT OpenCourseWare http://ocw.mit.edu 6.006 Introduction to Algorithms Fall 2011 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
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MIT OpenCourseWare http://ocw.mit.edu 6.641 Electromagnetic Fields, Forces, and Motion, Spring 2005 Please use the following citation format: Markus Zahn, 6.641 Electromagnetic Fields, Forces, and Motion, Spring 2005. (Massachusetts Institute of Technology: MIT OpenCourseWare). http://ocw.mit.edu (accessed MM DD, ...
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41, Electromagnetic Fields, Forces, and Motion Prof. Markus Zahn Lecture 3 Page 1 of 12 B. Estimate of Error introduced by EQS approximation Courtesy of Hermann A. Haus and James R. Melcher. Used with permission. E = _ _ i z = E0 i z V d ⎪⎧−εE0 σ = ⎨ su ⎪+εE0 ⎩ z = d z = 0 K 2 b π + π b2 dσsu = 0 ⇒ K =...
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εµ d E0 (r2 − b2 ) 4 dt2 If 0 ( ) = A cos E t ωt Eerror = E0 2 εµ d E 2 4E 0 dt 0 (b2 − r2 ) = 1 ω2εµ(b2 − r2 ) 4 Eerror (cid:19) 1 ⇒ E0 2ε 2 ω µb 4 (cid:19) 1 fλ = c = 1 εµ ω 2π λ = c ⇒ ω = 2ε 2 2 c ω µ b 4 π λ ⇒ = 2 π λ2 2 b (cid:19) 1 ⇒ b (cid:19) λ π f=1 MHz in free space ⇒ λ = × 3 10 8 6 ...
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2JL = εµL2 τ2 = L2 )2 cτ ( (cid:19) 1 ⇒ L (cid:19) cτ Courtesy of Hermann A. Haus and James R. Melcher. Used with permission. τem = L c = L εµ 6.641, Electromagnetic Fields, Forces, and Motion Prof. Markus Zahn Lecture 3 Page 4 of 12 III. Boundary Conditions 1. Gauss’ Continuity Condition ...
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= 0 Han = H bn n i ⎡ ⎣ H a - H b = 0 ⎤ ⎦ i da ∫ ε0E S H ds - H at ds = Kds bt H - H = K at bt n × ⎡ ⎣ H a - H b = K ⎤ ⎦ 5. Conservation of Charge Boundary Condition d (cid:118)∫ J da + dt ∫ ρdV = 0 i V S n i ⎡ J a - Jb ⎣ ⎤ + ⎦ ∂ ∂t σ s = 0 6.641, Electromagnetic Fields, Forces, and Motion Prof. ...
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rL = S λ0 L λ0 E = r 2πε0r 6.641, Electromagnetic Fields, Forces, and Motion Prof. Markus Zahn Lecture 3 Page 8 of 12 b. Electric Field from a Sheet Charge dE = y dλ 2πε0 (x2 + y2 )1 2 cos θ = σ0ydx 2πε0 (x2 + y2 ) E = y +∞ ∫ x = −∞ dE y = = +∞ σ0y 2πε0 ∫ x2 + y2 dx x = −∞ σ0y 1 2πε0 y tan−...
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⎪ 2ε0 _ ⎪ σ0 i y ⎪ ⎩2ε0 y > a y < a = E E + E 1 2 = _ i y σ0 ε0 0 y < a y > a 6.641, Electromagnetic Fields, Forces, and Motion Prof. Markus Zahn Lecture 3 Page 10 of 12 7. Magnetic Field from a Sheet of Surface Current From a line current I Hφ = I π2 r _ i = − sin φ _ φ i + cos x _ φ i y Thus...
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. Markus Zahn Lecture 3 Page 12 of 12
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(13.1) (13.2) (13.3) (13.4) (13.5) (13.6) (13.7) tS δ 0eij 0 0 ij d V (13.8) (13.9) MIT 2.094 13. Total Lagrangian formulation, cont’d tK 0 L = tK = 0 N L tF = 0 � 0V � 0V � 0V tBT 0 0 L 0C 0 Ld V tB T tB 0 N L 0 tBN Ld V 0 0 tS ���� matrix tB tSˆ d V T 0 0 L 0 ���� vector The iterat...
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+ tP 0L ⎢ ⎢ ⎣ � 0 −1 1 0 1 0 1 0 −1 0 0 −1 �� tK0 N L 0 −1 0 1 ⎤ ⎥ ⎥ ⎦ � When θ = 0, 0 tKL doesn’t give stiffness corresponding to u2 2, but 0 tKN L does. 56 MIT OpenCourseWare http://ocw.mit.edu 2.094 Finite Element Analysis of Solids and Fluids II Spring 2011 For information about citing these mat...
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15.082J, 6.855J, and ESD.78J Sept 16, 2010 Lecture 3. Graph Search Breadth First Search Depth First Search Intro to program verification Topological Sort Overview Today: Different ways of searching a graph  a generic approach  breadth first search  depth first search  program verification  data structures to supp...
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is fully scanned 5 Algorithm Search Initialize as follows: unmark all nodes in N; mark node s; pred(s) = 0; {that is, it has no predecessor} LIST = {s} while LIST ≠ ø do select a node i in LIST; if node i is incident to an admissible arc (i,j) then mark node j; pred(j) := i; add node j to the end of LIST; else delet...
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properties that are true throughout the running of the algorithm Things that change: functions that increase monotonically every time the algorithm reenters the same loop. 12 Algorithm Search Initialize loop while LIST ≠ ø do select a node i in LIST; if node i is incident to an admissible arc (i,j) then mark node...
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terminates when LIST = ∅. Let S = marked nodes. Let T = unmarked nodes. S 5 5 s s 6 6 2 2 4 4 1 3 t T By invariant 1, all nodes in S are reachable from s. By invariant 3, all arcs out of S have been scanned. Then no arc (i,j) is directed from S to T. Otherwise, by Invariant 2, j would have been marked when (i, j) wa...
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. Presidents have worn glasses True No President (before Obama) has been an only child True No President was a bachelor False. James Buchanan was a bachelor. George Washington grew marijuana on his Plantation. True Mental Break George Washington’s false teeth were made of wood. False. They were made of whale bone. Th...
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) < d(j), then i is marked before j. (Note that no unmarked node has a distance that is less than d(4).) 26 Preliminary to Topological Sorting LEMMA. If each node has at least one arc going out, then the first inadmissible arc of a depth first search determines a directed cycle. 6 6 2 2 4 5 5 7 7 1 1 8 If G has ...
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If the algorithm ends before labeling all nodes, then there is a directed cycle in the unmarked nodes. Every unmarked node has at least one incoming arc, and so there is a directed cycle. 29 More on Topological Sorting Runs in O(n+m) time. Useful starting point for many algorithms that involve acyclic graphs. 30 ...
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Course 18.327 and 1.130 Wavelets and Filter Banks Modulation and Polyphase Representations: Noble Identities; Block Toeplitz Matrices and Block z-transforms; Polyphase Examples Modulation Matrix Matrix form of PR conditions: [F0 (z) F1 (z)] H0(z) H0(-z) H1(z) H1(-z) &'(&'(&'(&'( Modulation matrix, H m(z) = [ 2z œ...
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H p(z) = h0[0] h0[1] h1[0] h1[1] + z -1 h0[2] h0[3] h1[2] h1[3] = h0[0] + z -1 h0[2] h0[1] + z -1 h0[3] h1[0] + z -1 h1[2] h1[1] + z -1 h1[3] = H0,even (z) H1,even (z) H0,odd (z) H1,odd (z) This is the polyphase matrix for a 2-channel filter bank. 11 12 6 Similarly, for the synthesis filter bank: Fb ...
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transpose convention for synthesis polyphase matrix • Perfect reconstruction condition in polyphase domain: F p(z) H p(z) = I (centered form) This means that H p(z) must be invertible for all z on the unit circle, i.e. det H p(eiwwww) òòòò 0 for all frequencies wwww. 14 7 • Given that the analysis filters ar...
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0(w + p)|^2 = 2 w + pw + pw + p www 25 Magnitude Response of Daubechies 4-tap filter. Ma g nitud e re s po ns e o f Da u be c h ie s 4 -ta p filte r. 2. 5 2 1. 5 1 0. 5 e s a h p e s n o p s e r y c n e u q e r F 0 -1 -0. 8 -0. 6 -0.2 -0.4 0 Ang ula r fre que nc y (no rm a liz e d b y p) 0.2 0.4 0...
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Key Concepts for this section 1: Lorentz force law, Field, Maxwell’s equation 2: Ion Transport, Nernst-Planck equation 3: (Quasi)electrostatics, potential function, 4: Laplace’s equation, Uniqueness 5: Debye layer, electroneutrality Goals of Part II: (1) Understand when and why electromagnetic (E and B) interaction ...
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(cid:71) B mag = ( μ r ≥ 1) + (cid:71) E ∂ t ∂ (cid:71) Bμ r ext (cid:71) E ∂ t ∂ (cid:71) B ∇ × = (cid:71) J μμ μμεε + r 0 0 0 r r (cid:71) J = μ με + μr : relative magnetic permeability of the medium μο : free space permeability (4π×10-7 H/m) μ of various media μr for water : very close to 1 μr (Ni)~600, μr (Fe)~500...
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Comparative Number densities and Conductivities Material DI water 0.1M NaCl Copper Si (intrinsic) Si (doped) Nd=1016 Quartz ni (#/cm3) ~1017 6×1019 ~1022 n=p~1010 ne=1016 Np=104 σ (m-1Ω-1) 4 ×10-6 1.07 5.8 ×107 3.36 ×10-4 2.4 10-18 In silicon (semiconductor), n×p~1020 (constant) In aqueous solutions, [H+][OH-] = 10-14 ...
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and mass spec; radioisotope) Data acquisition Capillary inlet Capillary outlet 10 - 200 mm Detector + Reservoir Electrolyte buffer Electrolyte buffer Reservoir 105 V/m HV + Generic diagram of a capillary electrophoresis system. Figure by MIT OCW. Micro Total Analysis System (microTAS): Parallelism • 96~356 samples an...
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6.02 Fall 2012 Lecture #16 •  DTFT vs DTFS •  Modulation/Demodulation •  Frequency Division Multiplexing (FDM) 6.02 Fall 2012 Lecture 16 Slide #1 Fast Fourier Transform (FFT) to compute samples of the DTFT signals of finite dura for tion For an x[n] that is zero outside of the interval [0,L-1], choose P ≥ ...
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1)1)(cid:5) 6.02 Fall 2012 Lecture 16 Slide #3 Fast Fourier Transform (FFT) to compute samples of the DTFT signals of finite dura for tion For an x[n] that is zero outside of the interval [0,L-1], choose P ≥ L (with P preferably a power of 2; we’ll assume that it’s at least a multiple of 2, i.e., even): X(Ω...
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k=−P/2 k )e jΩ kn •  Evaluating this eqn. for n in [0,P-1] recovers the original x[n] in this interval •  Evaluating it for n outside this interval results in periodic replication of the values in [0,P-1], producing a periodic signal x[n] •  So this eqn. is also called a DT Fourier Series (DTFS) for the periodic...
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Re(Xk) (cid:1)Ω m +Ω m Im(Xk) Re(Tk) modulation (cid:1)Ω c +Ω c Im(Tk) demodulation Signal centered at 0 6.02 Fall 2012 Signal centered at Ω c Lecture 16 Slide #7 Modulation by Heterodyning or Amplitude Modulation (AM) x[n] × t[n] Re(X ) k (cid:1)Ω m +Ω m Im(Xk) A B cos(Ω cn) To get this nice ...
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the noise-free case y[.] is related to x[.] by an approximately LTI relationship!) cn) cn) cn)} •  What does the spectrum of d[n], i.e., D(Ω), look like? •  What constraint on the bandwidth of x[n] is needed for perfect recovery of x[n]? 6.02 Fall 2012 Lecture 16 Slide #10 Demodulation Frequency Diagra m...
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3)/2, we are demodulating by a sine rather than a cosine, and we get y[n]=0 . 6.02 Fall 2012 Lecture 16 Slide #13 Demodulation with sin(Ω Ωc n) Re(Tk) R(Ω) (cid:1)Ω c +Ω c Im(Tk) A/2 B/2 –2Ω c D(Ω) + +2Ω c 6.02 Fall 2012 Lecture 16 Slide #14 … produces Note combining of signals around 0 resul...
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channel LPF I[n] = x[n-D]·cos(θ) θ = φ - Ω cD LPF Q[n] = x[n-D]·sin(θ) × cos(Ωcn) × sin(Ωcn) 6.02 Fall 2012 Lecture 16 Slide #17 Quadrature Demodulation If we let w[n] = I[n]+ jQ[n] then w[n] = I[n]2 + Q[n]2 =| x[n − D] | cos2 θ+ sin2 θ =| x[n − D] | OK for recovering x[n] if it never goes negative, ...
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+ t[n] Q (-1,1) (1,1) I (-1,-1) (1,-1) Samples from second bit stream × Q[n] 6.02 Fall 2012 Lecture 16 Slide #20 Phase Shift Keying underlies many familiar modulation schemes The wireless LAN standard, IEEE 802.11b-1999, uses a variety of different PSKs depending on the data- rate required. At the basic-ra...
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2 will yield a higher data-rate. A similar technology, IEEE 802.15.4 (the wireless standard used by ZigBee) also relies on PSK. IEEE 802.15.4 allows the use of two frequency bands: 868–915 MHz using BPSK and at 2.4 GHz using OQPSK. http://en.wikipedia.org/wiki/Phase-shift_keying 6.02 Fall 2012 Lecture 16 Slide #2...
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CS II: Digital Communication Systems Fall 2012 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
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Mechanisms of Diffusion in Materials 3.205 L4 11/7/06 1 A final point on interdiffusion…  The composition profiles resulting from inter- diffusion are generally constrained by phase equilibria. Consider the an Ir–Re diffusion couple annealed at 2400°C: Equilibrium diagram Diffusion couple 3.205 L4 11/7/06 2...
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Atomistic mechanisms, cont’d  Additional mechanisms include the interstitialcy mechanism in crystals containing significant numbers of self-interstitials (e.g., produced by irradiation); and the reptation mechanism in molten (hence non-crystalline) polymers. Interstialcy Reptation 3.205 L4 11/7/06 6 Atomistic...
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! R2=nr2! D="r26 Diffusion & random walks, cont’d  Diffusion in alloys: intrinsic diffusivity and interdiffusivity These can involve correlated jumps and the resulting value of the mean square displacement can be either greater than, or less than, that for self-diffusion. The correlation factor, f, accounts for ...
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fkT()[]=expSVfk[]exp"HVfkT()[] Self-diffusion of solute atoms via vacancy mechanism, cont’d  Using equations for D and The correlation factor, f, for vacancy diffusion in metals is about 0.7 and can be calculated more precisely for various specific cases. 3.205 L4 11/7/06 14 ! DA=Xvz"vr26f=zr2#6exp$GVf+GVm()kT()...
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6.02 Fall 2012 Lecture #10 • Linear time-invariant (LTI) models • Convolution 6.02 Fall 2012 Lecture 10, Slide #1 Modeling Channel Behavior codeword bits in 1001110101 x[n] generate digitized symbols modulate DAC NOISY & DISTORTING ANALOG CHANNEL ADC demodulate & filter sample & threshold y[n] 1...
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] 6.02 Fall 2012 Lecture 10, Slide #4 Linear Systems Let y1[n] be the response of S to an arbitrary input x1[n] and y2[n] be the response to an arbitrary x2[n]. If, for arbitrary scalar coefficients a and b, we have: ax1[n]+ bx2[n] S ay1[n]+ by2[n] then system S is said to be linear. If the input...
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Fall 2012 h[n] s[n] 6.02 Fall 2012 Lecture 10, Slide #8 h[n] s[n] 6.02 Fall 2012 Lecture 10, Slide #9 h[n] s[n] 6.02 Fall 2012 Lecture 10, Slide #10 Unit Step Decomposition “ “Rectangular-wave” digital signaling waveforms, of the sort s we have been considering, are w easily decomposed into time- ...
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5V 6.02 Fall 2012 Lecture 10, Slide #15 Faster Tr ansmission Fall 2012 6.02 Fall 2012 Noise m Noise margin? 0.5 (cid:1) y[28] Lecture 10, Slid Lecture 10, Slide #16 Unit Sample Decomposition A discrete-time signal can be decomposed into a sum of time-shifted, scaled unit samples. Example: in the figur...
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the output signal y in terms of the input x and unit-sample response h. Some constraints are needed to ensure this infinite sum is well behaved, i.e., doesn’t “blow up” --- we’ll discuss this later. ∗ We use to denote convolution, and write y=x h. We can then write the value of y at time n, which is given by the a...
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= h ∗ x Convolution is associative: x ∗ (h1 ( ∗ h2 ) = x ∗ h1 ) ∗ h2 Convolution is distributive: ( x ∗ h1 + h2 ) = (x ∗ h1) + (x ∗ h2 ) 6.02 Fall 2012 Lecture 10, Slide #21 Series Interconnection of LT I Systems x[n] h2[.] y[n] y = h2 ∗ w = h2 ∗ x ( ) = h2 ∗ h1 ) ∗ x w[n] h1[.] ( ∗ h1 x[n] x[n] ...
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Suspensions and suspension mechanics 1 Suspensions may be distinguished by the shape and size of the discrete phase Debye Length in 1mM NaCl Visible Light micro-CT resolution (Optical limit) gap in PP rheometer 10-10 10-9 10-8 10-7 10-6 10-5 gap in CP rheometer 10-3 10-4 10-2 [m] Au nanoparticle Colloidal silica ...
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�0.313dD0.138dD The Farris effect Contours: volume fraction 5:1 ratio in particle size What are the paths PS and PQ? © source unknown. All rights reserved. This content is excluded from our Creative Commons license. For more information, see https://ocw.mit.edu/help/faq-fair-use/. <0.75 6 Particle shape is also i...
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9 Despite this scaling, we still see a shear rate dependence at large Pe# Remarks: 1. This is a non-colloidal suspension of spheres 2. Brownian diffusion is weak. 3. 4. How did we construct the Shear thinning is observed (?) earlier viscosity curves with no rate dependence? 5. Glass particles in a Newtonian matrix © ...
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capture problem, dependence on Pe Morris, J. F. “A review of microstructure in concentrated suspensions and its implications for rheology and bulk flow” (2009) 48:909-923 14 © Springer. All rights reserved. This content is excludedfrom our Creative Commons license. For more information, see https://ocw.mit.edu/help/fa...
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0, φ = .45 Pe = 25, φ = .3 Color indicates density of particle centers • At low Pe, randomized • At higher Pe, induced structure from flow Increased particle density along shoulders of particles, attempting to align in rows Morris, J. F. “A review of microstructure in concentrated suspensions and its implications fo...
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All rights reserved. This content is excluded from our Creative Commons license. For more information, see https://ocw.mit.edu/help/faq-fair-use/. 23 Laun, H. M. Angew. Makro. Chem. 1984, 124:335-359 Mechanisms for non-Newtonian suspension behavior y t i s o c s i V Shear rate or stress Newtonian plateau Structure no...
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” JoR (2006) 50:293-311 Experiments, Brownian 26 Experimental agreement? Experiments, non-Brownian © AIP Publishing LLC. All rights reserved. This content is excludedfrom our Creative Commons license. For more information, see https://ocw.mit.edu/help/faq-fair-use/. Gamonpilas, C., Morris, J. F., Denn, M. M. “Shear a...
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8.871 Lecture 2 M. Padi October 20, 2004 1 Electrically and Magnetically Charged Branes We would like to build a general understanding of branes, the gauge fields to which they are coupled, and the gauge fields living on their world volume. First, we review electromagnetism in four dimensions. Define F (2) = dA(1) ...
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an arbitrary 1-form, H (3) is invariant. An F1-string, which propagates in 9+1 dimensions, is electrically charged under B(2), with a charge Q. We therefore write a source equation d � H (3) . The string is localized in 8 of the 9 space coordinates and hence we have a delta function in 8 directions. On the other ha...
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11d SUGRA is the low energy effective theory of M-theory. Applying the ideas outlined above we find that in M-theory, we should have an M2-brane which is electrically charged under C (3) and an M5-brane which is magnetically charged under C (3). Similarly, we can find the branes which are charged under massless gauge fi...
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µ and � can be anything except 10. That leaves us with a 2-form in 9+1 dimensions which we call B (2). We can also have �, µ, � ⊗= 10 (but constrained to be antisymmetric). Then we end up with a 3-form in 9+1 dimensions. The 3-form has 8 = 56 components and the 2-form has 2 = 28 components. We can check this decompo...
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) there is a triality that acts on the 8 dimensional and the 56 dimensional representations and we therefore have three different representations of the same dimension which we distinguish by these subscripts. We now look at the bosonic massless fields to determine the kinds of branes that can exist in Type IIA theor...
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M10 × S1 is S-dual to Type IIA theory on M10, where Mj is an arbitrary j-dimensional manifold. When the M2-brane wraps one of its own dimensions on the S 1, it is dual to an F1 string in Type IIA. If instead we use dimensional reduction on M-theory, the M2-brane will reduce to a D2-brane. Similarly, if the M5-brane ...
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coupled to B(2)). Similarly, in heterotic theories, we have an F1-string and NS5-brane. In addition to these objects we also have small instantons which are branes that are present in any theory that has non-abelian massless gauge fields. An instanton is an object which is localized in 4 space coordinates and therefo...
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8 + � � 2 Note that 528 = 32·33 , because the LHS of (8) is a symmetric 32 × 32 matrix. The 5-form on the RHS corresponds to the charge of the M5-brane. The 2-form corresponds to the M2-brane. To get this result, we could also decompose (32 � 32)sym, the symmetrized tensor product of spinor representations of SO(11...
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of the charge on the brane. 3
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15.081J/6.251J Introduction to Mathematical Programming Lecture 8: Duality Theory I Slide 1 Slide 2 1 Outline • Motivation of duality • General form of the dual • Weak and strong duality • Relations between primal and dual • Economic Interpretation • Complementary Slackness 2 Motivation 2.1 An idea from L...
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Ax ≥ b max p ′ b s.t. p ′ A ≤ c ′ ′ b max p s.t. p ′ A = c ′ p ≥ 0 4 Weak Duality Theorem: If x is primal feasible and p is dual feasible then p ′ b ≤ c ′ x Proof p ′ b = p ′ Ax ≤ c ′ x 2 Slide 3 Slide 4 Slide 5 Slide 6 Slide 7 Slide 8 Slide 9 Slide 10 Corollary: If x is primal feasible, p is dual ...
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p2a2 p1a1 a2 . x * 3 Slide 11 Slide 12 Slide 13 Slide 14 6 Relations between primal and dual Finite opt. Unbounded Infeasible Finite opt. Unbounded Infeasible * * * * 7 Economic Interpretation • x optimal nondegenerate solution: B−1b > 0 • Suppose b changes to b + d for some small d...
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strong duality theorem, if x and p are optimal, then c x = p ′ b ⇒ ui = vj = 0 for all i, j. ′ • Conversely, if ui = vj = 0 for all i, j, then c ′ x = p ′ b, • ⇒ x and p are optimal. 4 8.3 Example min 13x1 + 10x2 + 6x3 s.t. 5x1 + 3x1 + , x1 x2 + 3x3 = 8 x2 = 3 x3 ≥ 0 x2 , ...
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MIT OpenCourseWare http://ocw.mit.edu 3.23 Electrical, Optical, and Magnetic Properties of Materials Fall 2007 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. 3.23 Fall 2007 – Lecture 9 BAND STRUCTURE 3.23 Electronic, Optical and Magnetic Properties of Materia...
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⎜ = E ⎜ ⎜ ⎜ ⎜⎜ ⎝ ⎝ C C − q G C − q G 2 ⎞ ⎟ ⎟ ⎟ ⎟ q G ⎟ + ⎟⎟ ⎠ ⎠ 2G q C C C +q 3.23 Electronic, Optical and Magnetic Properties of Materials - Nicola Marzari (MIT, Fall 2007) 4 Free electron dispersions, 1-d 3.23 Electronic, Optical and Magnetic Properties of Materials - Nicola Marzari (MIT, Fall 2007)...
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⎟ C C ⎛ ⎛ ⎟ ⎟ ⎜ ⎟ C ⎜ − q G ⎟ ⎜ C ⎟ ⎜ ⎟ C ⎜ ⎟ ⎜ C ⎟⎝ ⎟ ⎟ ⎟ ⎠ q G+ q + 2 q G ⎞ ⎞ ⎟ ⎟ ⎟ = E ⎟ ⎟ ⎟ ⎠ C C ⎛ ⎛ − q G G 2 2 ⎜ C ⎜ − q G C⎜ ⎜ C ⎜ ⎜ C ⎝ + 2 q G + q G q ⎞ ⎞ ⎟ ⎟ ⎟ ⎟ ⎟ ⎟ ⎠ 3.23 Electronic, Optical and Magnetic Properties of Materials - Nicola Marzari (MIT, Fall 2007) Band Edge 3.23 Electronic, Optical...
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1 3 2' 5 2 3 1 A 1 2' 3 A 3 Q+ Q_ Q+ Q_ 3 A 3 Q+ 1 A 1 S 3 S S 1 S 4 S 2 K2 K4 K3 K1 K1 1 X W L G K Figure by MIT OpenCourseWare. 9 The Fermi surface 3.23 Electronic, Optical and Magnetic Properties of Materials - Nicola Marzari (MIT, Fall 2007) Images from the Fermi Surface Database. Used with permission. Please se...
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BUILD­IT Cast Corn Sheller BUILD-IT This project is a low-cost device for removing corn kernels from the cob. It is cast in aluminum using a casting pattern made on the 3-D printer. This project is inspired by a plastic corn sheller from Malawi and a cast aluminum sheller from Ghana. In order to make it you will need...
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the SolidWorks model of the sheller can be found at the end of this handout. The tutorial instructs you in making a basic sheller you may also add ridges or other features to the outside surface of the sheller. The model should be completed before class so that it can be printed during class. You will need to sand ...
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, Mechatronics Lab, AMP Lab. MIT computer cluster. Starting Solidworks Open Solidworks 2007 SP5.0 by going to: Start > All Documents > Solidworks 2007 SP5.0 > Solidworks 2007 Start a new document by clicking on the new document button or File > New Document. In the menu click on New Part – a 3D representation of...
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. - Choose the axis you just drew to be the center of rotation and rotate 360 degrees Draw the cross section of the fin In a new Sketch on the Front Plane, make the cross section of the fin. Trace the profile of the sheller body with lines. Add a Relation to make the lines parallel slanting. Smart Dimension the in...
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Please use the following citation format: D-Lab Cast Corn Sheller Build-It Copyright © Massachusetts Institute of Technology (Accessed on [insert date]). 8 88 8 MIT OpenCourseWare http://ocw.mit.edu EC.720J / 2.722J D-Lab II: Design Spring 2010 For information about citing these materials or our Terms of Use, visit...
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Concurrent Plan Recognition & Execution for Human-Robot Teams Cognitive Robotics 2016 Lecture Steven J. Levine Wednesday, March 16666666th, 2016 Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Intent recognition & adaptation are siblings • Intent recognition & robot adaptation are b...
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odic et al. 2009 Dechter, Meiri, Pearl 1991 Chaski (Shah, Conrad, Williams 2009) Drake (Conrad, Shah, and Williams 2009) Chien et al. 2000 SAM Pecora 2012 Tsamardinos, Muscettola, Morris 1998 Teller, Walter, et al. 2010 Morris 1998 HOTRiDE Ayan et al. 2007 Finzi, Ingrand, and Muscettola 2004 Effinger et. al 2009 Hof...
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human-robot teams • Given a plan with choice (contingent, temporally flexible): • Make decisions online (consistent with human’s intent) • Dispatch activities at proper times • Monitor execution for problems Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Slide 6 How to recognize intent...
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ent, temporally-flexible plans Temporal Planning Network with Uncertainty (TPNU) Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Slide 12 First part: making a drink Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Slide 13 Extracting labeled causal lin...
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)(cid:8)(cid:9) (cid:10)(cid:11)(cid:6)(cid:12)(cid:13)(cid:7)(cid:6)(cid:14)(cid:15) (cid:16)(cid:17)(cid:6)(cid:12)(cid:18)(cid:12)(cid:6)(cid:19) (cid:20)(cid:12)(cid:11)(cid:21)(cid:7)(cid:6)(cid:17)(cid:22)(cid:8)(cid:15) (cid:27)(cid:31)(cid:7)(cid:25)(cid:6) (cid:3) (cid:4) (cid:2) • Activity Recognizer: observe...
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Execution for Human-Robot Teams | Steven J. Levine Slide 25 Causal link extraction in a nutshell* • For each precondition of each consumer event: • Find all producers provably before or during consumer [0, ∞] [0, ∞] Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Slide 26 Causal lin...
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1) ∨ (ac = c2 ∧ y = 1) ∨ (ac = c3) (cid:5) p : {ac = c1} p : {ac = c2 ∧ y = 1} p : {ac = c3} [0, ∞] : {ac = c3} [0, ∞] [0, ∞] Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Slide 30 Causal link extraction in a nutshell* • For each precondition of each consumer event: • Find all produc...
https://ocw.mit.edu/courses/16-412j-cognitive-robotics-spring-2016/497c66f8f0334208d69fc5a29ff2a956_MIT16_412JS16_L13.pdf
1) Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Slide 34 Causal link extraction in a nutshell* • For each precondition of each consumer event: • Find all producers provably before or during consumer • Add propositional & temporal constraints for each producer • Find all potential th...
https://ocw.mit.edu/courses/16-412j-cognitive-robotics-spring-2016/497c66f8f0334208d69fc5a29ff2a956_MIT16_412JS16_L13.pdf
: {ac = c2 ∧ y = 1} [0, ∞] :{b = 1 ∧ z = 1 ∧ ac = c2 ∧ y = 1 ∧ x = 2} [0, ∞] [0, ∞] Concurrent Plan Recognition & Execution for Human-Robot Teams | Steven J. Levine Slide 38 Causal link extraction in a nutshell* • For each precondition of each consumer event: • Find all producers provably before or during consumer •...
https://ocw.mit.edu/courses/16-412j-cognitive-robotics-spring-2016/497c66f8f0334208d69fc5a29ff2a956_MIT16_412JS16_L13.pdf